context listlengths 1 1 | gen_kwargs dict | repeat_idx int64 0 4 | request_idx int64 0 510 | task_name stringclasses 6
values | metadata dict | model_outputs stringlengths 9 33.7k |
|---|---|---|---|---|---|---|
[
{
"content": "Problem: Among the 900 residents of Aimeville, there are 195 who own a diamond ring, 367 who own a set of golf clubs, and 562 who own a garden spade. In addition, each of the 900 residents owns a bag of candy hearts. There are 437 residents who own exactly two of these things, and 234 residents wh... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 0 | AIME24 | {
"expected_answer": "73",
"problem_id": "aime24-0",
"reference_solution": "Let $w,x,y,z$ denote the number of residents who own 1,2,3 and 4 of these items, respectively. We know $w+x+y+z=900$ , since there are 900 residents in total. This simplifies to $w+z=229$ , since we know $x=437$ and $y=234$ . Now, w... | To solve this problem, we will use the principle of inclusion-exclusion. Let's denote the following:
- \( D \) as the set of residents who own a diamond ring,
- \( G \) as the set of residents who own a set of golf clubs,
- \( S \) as the set of residents who own a garden spade,
- \( C \) as the set of residents who o... |
[
{
"content": "Problem: A list of positive integers has the following properties: $\\bullet$ The sum of the items in the list is $30$ . $\\bullet$ The unique mode of the list is $9$ . $\\bullet$ The median of the list is a positive integer that does not appear in the list itself. Find the sum of the squares... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 1 | AIME24 | {
"expected_answer": "236",
"problem_id": "aime24-1",
"reference_solution": "The third condition implies that the list's size must be an even number, as if it were an odd number, the median of the list would surely appear in the list itself. Therefore, we can casework on what even numbers work. Say the size is 2.... | To solve the problem, we need to find a list of positive integers that satisfies the given conditions and then compute the sum of the squares of all the items in the list.
The conditions are:
1. The sum of the items in the list is 30.
2. The unique mode of the list is 9.
3. The median of the list is a positive integer... |
[
{
"content": "Problem: Find the number of ways to place a digit in each cell of a 2x3 grid so that the sum of the two numbers formed by reading left to right is $999$ , and the sum of the three numbers formed by reading top to bottom is $99$ . The grid below is an example of such an arrangement because $8+99... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 2 | AIME24 | {
"expected_answer": "45",
"problem_id": "aime24-2",
"reference_solution": "Consider this table: $\\begin{array}{|c|c|c|} \\hline a & b & c \\\\ \\hline d & e & f\\\\ \\hline \\end{array}$ We note that $c+f = 9$ , because $c+f \\leq 18$ , meaning it never achieves a unit's digit sum of $9$ otherwise. Since no... | To solve the problem, we need to find the number of ways to place a digit in each cell of a 2x3 grid such that the sum of the two numbers formed by reading left to right is 999, and the sum of the three numbers formed by reading top to bottom is 99.
Let's denote the digits in the grid as follows:
\[
\begin{array}{|c|c... |
[
{
"content": "Problem: Let $x,y$ and $z$ be positive real numbers that satisfy the following system of equations:\n \\[\\log_2\\left({x \\over yz}\\right) = {1 \\over 2}\\] \\[\\log_2\\left({y \\over xz}\\right) = {1 \\over 3}\\] \\[\\log_2\\left({z \\over xy}\\right) = {1 \\over 4}\\] \nThen the value of... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 3 | AIME24 | {
"expected_answer": "33",
"problem_id": "aime24-3",
"reference_solution": "Denote $\\log_2(x) = a$ , $\\log_2(y) = b$ , and $\\log_2(z) = c$ . Then, we have:\n $a-b-c = \\frac{1}{2}$ \n $-a+b-c = \\frac{1}{3}$ \n $-a-b+c = \\frac{1}{4}$ Now, we can solve to get $a = \\frac{-7}{24}, b = \\frac{-9}{24}, c = \\... | To solve the given system of equations, we start by rewriting each equation in exponential form. The given equations are:
\[
\log_2\left(\frac{x}{yz}\right) = \frac{1}{2}
\]
\[
\log_2\left(\frac{y}{xz}\right) = \frac{1}{3}
\]
\[
\log_2\left(\frac{z}{xy}\right) = \frac{1}{4}
\]
Rewriting these in exponential form, we ... |
[
{
"content": "Problem: Let ABCDEF be a convex equilateral hexagon in which all pairs of opposite sides are parallel. The triangle whose sides are extensions of segments AB, CD, and EF has side lengths 200, 240, and 300. Find the side length of the hexagon.\nMark your solution with \\boxed\nAnswer:",
"role":... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 4 | AIME24 | {
"expected_answer": "80",
"problem_id": "aime24-4",
"reference_solution": "Draw a good diagram!\nLet $AF \\cap BC$ , $BC \\cap DE$ , and $AF \\cap DE$ be K, L, and M, respectively. Let $KL=200, KM=300, ML=240$ . Notice that all smaller triangles formed are all similar to the larger $(200,240,300)$ triangl... | Given that \(ABCDEF\) is a convex equilateral hexagon with all pairs of opposite sides being parallel, we can infer that the hexagon can be divided into two congruent parallelograms by drawing lines connecting opposite vertices. This means that the hexagon can be thought of as a "stretched" or "compressed" version of a... |
[
{
"content": "Problem: Alice chooses a set $A$ of positive integers. Then Bob lists all finite nonempty sets $B$ of positive integers with the property that the maximum element of $B$ belongs to $A$ . Bob's list has 2024 sets. Find the sum of the elements of A.\nMark your solution with \\boxed\nAnswer:",... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 5 | AIME24 | {
"expected_answer": "55",
"problem_id": "aime24-5",
"reference_solution": "Let $k$ be one of the elements in Alices set $A$ of positive integers. The number of sets that Bob lists with the property that their maximum element is k is $2^{k-1}$ , since every positive integer less than k can be in the set or o... | To solve the problem, we need to understand the relationship between the set \( A \) and the sets \( B \) that Bob lists. Bob lists all finite nonempty sets \( B \) of positive integers such that the maximum element of \( B \) belongs to \( A \). Let's denote the elements of \( A \) as \( a_1, a_2, \ldots, a_n \) where... |
[
{
"content": "Problem: Let $N$ be the greatest four-digit positive integer with the property that whenever one of its digits is changed to $1$ , the resulting number is divisible by $7$ . Let $Q$ and $R$ be the quotient and remainder, respectively, when $N$ is divided by $1000$ . Find $Q+R$ .\nMark ... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 6 | AIME24 | {
"expected_answer": "699",
"problem_id": "aime24-6",
"reference_solution": "We note that by changing a digit to $1$ for the number $\\overline{abcd}$ , we are subtracting the number by either $1000(a-1)$ , $100(b-1)$ , $10(c-1)$ , or $d-1$ . Thus, $1000a + 100b + 10c + d \\equiv 1000(a-1) \\equiv 100(b-1... | To solve the problem, we need to find the greatest four-digit positive integer \( N \) such that changing any one of its digits to 1 results in a number divisible by 7. Let's denote \( N \) as \( \overline{abcd} \), where \( a, b, c, \) and \( d \) are its digits. The number \( N \) can be expressed as \( 1000a + 100b ... |
[
{
"content": "Problem: Torus $T$ is the surface produced by revolving a circle with radius $3$ around an axis in the plane of the circle that is a distance $6$ from the center of the circle (so like a donut). Let $S$ be a sphere with a radius $11$ . When $T$ rests on the inside of $S$ , it is intern... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 7 | AIME24 | {
"expected_answer": "127",
"problem_id": "aime24-7",
"reference_solution": "First, let's consider a section $\\mathcal{P}$ of the solids, along the axis.\nBy some 3D-Geomerty thinking, we can simply know that the axis crosses the sphere center. So, that is saying, the $\\mathcal{P}$ we took crosses one of th... | To solve the problem, we need to understand the geometry of the torus and the sphere and how they interact when the torus is both internally and externally tangent to the sphere.
First, let's recall the dimensions of the torus. The torus \( T \) is formed by revolving a circle with radius \( 3 \) around an axis that i... |
[
{
"content": "Problem: There is a collection of $25$ indistinguishable white chips and $25$ indistinguishable black chips. Find the number of ways to place some of these chips in the $25$ unit cells of a $5\\times5$ grid such that: each cell contains at most one chip all chips in the same row and all ch... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 8 | AIME24 | {
"expected_answer": "902",
"problem_id": "aime24-8",
"reference_solution": "The problem says \"some\", so not all cells must be occupied.\nWe start by doing casework on the column on the left. There can be 5,4,3,2, or 1 black chip. The same goes for white chips, so we will multiply by 2 at the end. There is $1$... | To solve this problem, we need to carefully analyze the conditions given and determine how to place the chips in the grid. The conditions are:
1. Each cell contains at most one chip.
2. All chips in the same row and all chips in the same column have the same color.
3. Any additional chip placed on the grid would viola... |
[
{
"content": "Problem: Let $\\triangle ABC$ have circumcenter $O$ and incenter $I$ with $\\overline{IA}\\perp\\overline{OI}$ , circumradius $13$ , and inradius $6$ . Find $AB\\cdot AC$ .\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 9 | AIME24 | {
"expected_answer": "468",
"problem_id": "aime24-9",
"reference_solution": "By Euler's formula $OI^{2}=R(R-2r)$ , we have $OI^{2}=13(13-12)=13$ . Thus, by the Pythagorean theorem, $AI^{2}=13^{2}-13=156$ . Let $AI\\cap(ABC)=M$ ; notice $\\triangle AOM$ is isosceles and $\\overline{OI}\\perp\\overline{AM}$ ... | Given that \(\triangle ABC\) has circumcenter \(O\) and incenter \(I\), and \(\overline{IA} \perp \overline{OI}\), with circumradius \(R = 13\) and inradius \(r = 6\), we need to find \(AB \cdot AC\).
First, recall that the distance \(OI\) between the circumcenter and the incenter of a triangle is given by the formula... |
[
{
"content": "Problem: Find the number of triples of nonnegative integers $(a,b,c)$ satisfying $a + b + c = 300$ and\n \\[a^2b + a^2c + b^2a + b^2c + c^2a + c^2b = 6,000,000.\\]\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 10 | AIME24 | {
"expected_answer": "601",
"problem_id": "aime24-10",
"reference_solution": "$ab(a+b)+bc(b+c)+ac(a+c)=300(ab+bc+ac)-3abc=6000000, 100(ab+bc+ac)-abc=2000000$ Note that \n $(100-a)(100-b)(100-c)=1000000-10000(a+b+c)+100(ab+bc+ac)-abc=0$ . Thus, $a/b/c=100$ . There are $201$ cases for each but we need to subtrac... | To solve the given problem, we start by analyzing the given equations:
\[ a + b + c = 300 \]
\[ a^2b + a^2c + b^2a + b^2c + c^2a + c^2b = 6,000,000. \]
First, let's consider the symmetry and possible values for \(a, b,\) and \(c\). We will explore the possibility that two of the variables are equal. Assume \(a = b\). ... |
[
{
"content": "Problem: Let \\(O=(0,0)\\), \\(A=\\left(\\tfrac{1}{2},0\\right)\\), and \\(B=\\left(0,\\tfrac{\\sqrt{3}}{2}\\right)\\) be points in the coordinate plane. Let \\(\\mathcal{F}\\) be the family of segments \\(\\overline{PQ}\\) of unit length lying in the first quadrant with \\(P\\) on the \\(x\\)-axi... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 11 | AIME24 | {
"expected_answer": "23",
"problem_id": "aime24-11",
"reference_solution": "Begin by finding the equation of the line $\\overline{AB}$ : $y= -\\sqrt{3}x+\\frac{\\sqrt{3}}{2}$ Now, consider the general equation of all lines that belong to $\\mathcal{F}$ . Let $P$ be located at $(a,0)$ and $Q$ be located... | To solve the problem, we start by understanding the geometry of the situation. The points \(O=(0,0)\), \(A=\left(\frac{1}{2},0\right)\), and \(B=\left(0,\frac{\sqrt{3}}{2}\right)\) form a right triangle with \(O\) as the right angle. The segment \(\overline{AB}\) is the hypotenuse of this right triangle. The length of ... |
[
{
"content": "Problem: Let $\\omega\\neq 1$ be a 13th root of unity. Find the remainder when\n \\[\\prod_{k=0}^{12}(2-2\\omega^k+\\omega^{2k})\\] \nis divided by 1000.\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 12 | AIME24 | {
"expected_answer": "321",
"problem_id": "aime24-12",
"reference_solution": "\\[\\prod_{k=0}^{12} \\left(2- 2\\omega^k + \\omega^{2k}\\right) = \\prod_{k=0}^{12} \\left((1 - \\omega^k)^2 + 1\\right) = \\prod_{k=0}^{12} \\left((1 + i) - \\omega^k)((1 - i) - \\omega^k\\right)\\] Now, we consider the polynomial $x... | To solve the given problem, we start by noting that \(\omega\) is a 13th root of unity, which means \(\omega^{13} = 1\) and \(\omega \neq 1\). The polynomial whose roots are the 13th roots of unity is \(x^{13} - 1 = 0\). Excluding the root \(x = 1\), the polynomial whose roots are the other 12 roots of unity is given b... |
[
{
"content": "Problem: Let \\(b\\ge 2\\) be an integer. Call a positive integer \\(n\\) \\(b\\text-\\textit{eautiful}\\) if it has exactly two digits when expressed in base \\(b\\) and these two digits sum to \\(\\sqrt n\\). For example, \\(81\\) is \\(13\\text-\\textit{eautiful}\\) because \\(81 = \\underlin... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 13 | AIME24 | {
"expected_answer": "211",
"problem_id": "aime24-13",
"reference_solution": "We write the base- $b$ two-digit integer as $\\left( xy \\right)_b$ .\nThus, this number satisfies\n \\[ \\left( x + y \\right)^2 = b x + y \\] \nwith $x \\in \\left\\{ 1, 2, \\cdots , b-1 \\right\\}$ and $y \\in \\left\\{ 0, 1, \\... | To solve the problem, we need to find the smallest base \(b\) for which there are more than ten \(b\)-beautiful integers. A positive integer \(n\) is \(b\)-beautiful if it has exactly two digits when expressed in base \(b\) and these two digits sum to \(\sqrt{n}\).
1. **Expression of \(n\) in base \(b\):**
Any two-... |
[
{
"content": "Problem: Find the number of rectangles that can be formed inside a fixed regular dodecagon ( $12$ -gon) where each side of the rectangle lies on either a side or a diagonal of the dodecagon. The diagram below shows three of those rectangles. [asy] unitsize(0.6 inch); for(int i=0; i<360; i+=30) { d... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 14 | AIME24 | {
"expected_answer": "315",
"problem_id": "aime24-14",
"reference_solution": "By Furaken There are two kinds of such rectangles: those whose sides are parallel to some edges of the regular 12-gon (Case 1), and those whose sides are not (Case 2). For Case 1, WLOG assume that the rectangle's sides are horizontal an... | To find the number of rectangles that can be formed inside a fixed regular dodecagon (12-gon) where each side of the rectangle lies on either a side or a diagonal of the dodecagon, we need to consider the properties and symmetries of the dodecagon.
A rectangle is defined by choosing two pairs of parallel lines. In the... |
[
{
"content": "Problem: Every morning Aya goes for a $9$ -kilometer-long walk and stops at a coffee shop afterwards. When she walks at a constant speed of $s$ kilometers per hour, the walk takes her 4 hours, including $t$ minutes spent in the coffee shop. When she walks $s+2$ kilometers per hour, the walk... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 15 | AIME24 | {
"expected_answer": "204",
"problem_id": "aime24-15",
"reference_solution": "$\\frac{9}{s} + t = 4$ in hours and $\\frac{9}{s+2} + t = 2.4$ in hours. Subtracting the second equation from the first, we get, $\\frac{9}{s} - \\frac{9}{s+2} = 1.6$ Multiplying by $(s)(s+2)$ , we get $9s+18-9s=18=1.6s^{2} + 3.2s$ ... | To solve the problem, we start by setting up equations based on the information given.
First, we know that the distance Aya walks is 9 kilometers. When she walks at a speed of \( s \) kilometers per hour, the time taken for the walk, excluding the coffee shop stop, is \( \frac{9}{s} \) hours. Including the \( t \) min... |
[
{
"content": "Problem: There exist real numbers $x$ and $y$ , both greater than 1, such that $\\log_x\\left(y^x\\right)=\\log_y\\left(x^{4y}\\right)=10$ . Find $xy$ .\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 16 | AIME24 | {
"expected_answer": "25",
"problem_id": "aime24-16",
"reference_solution": "By properties of logarithms, we can simplify the given equation to $x\\log_xy=4y\\log_yx=10$ . Let us break this into two separate equations: \\[x\\log_xy=10\\] \n \\[4y\\log_yx=10.\\] \nWe multiply the two equations to get: \n \\[4xy\\... | Given the equations \(\log_x(y^x) = 10\) and \(\log_y(x^{4y}) = 10\), we need to find the value of \(xy\).
First, consider the equation \(\log_x(y^x) = 10\). Using the logarithm power rule, we can rewrite this as:
\[
x \log_x(y) = 10 \implies \log_x(y) = \frac{10}{x}
\]
This can be rewritten in exponential form as:
\[... |
[
{
"content": "Problem: Alice and Bob play the following game. A stack of $n$ tokens lies before them. The players take turns with Alice going first. On each turn, the player removes either $1$ token or $4$ tokens from the stack. Whoever removes the last token wins. Find the number of positive integers $n... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 17 | AIME24 | {
"expected_answer": "809",
"problem_id": "aime24-17",
"reference_solution": "Let's first try some experimentation. Alice obviously wins if there is one coin. She will just take it and win. If there are 2 remaining, then Alice will take one and then Bob will take one, so Bob wins. If there are $3$ , Alice will t... | To solve this problem, we need to analyze the game based on the number of tokens $n$ and determine under what conditions Bob can guarantee a win. The key to this problem is recognizing the pattern of winning and losing positions. A winning position is one from which the player whose turn it is can force a win with opti... |
[
{
"content": "Problem: Jen enters a lottery by picking $4$ distinct numbers from $S=\\{1,2,3,\\cdots,9,10\\}.$ $4$ numbers are randomly chosen from $S.$ She wins a prize if at least two of her numbers were $2$ of the randomly chosen numbers, and wins the grand prize if all four of her numbers were the... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 18 | AIME24 | {
"expected_answer": "116",
"problem_id": "aime24-18",
"reference_solution": "This is a conditional probability problem. Bayes' Theorem states that \n \\[P(A|B)=\\dfrac{P(B|A)\\cdot P(A)}{P(B)}\\] in other words, the probability of $A$ given $B$ is equal to the probability of $B$ given $A$ times the proba... | To solve the problem, we need to calculate the probability of Jen winning the grand prize given that she won a prize. This involves understanding the total number of ways she can win a prize and the number of ways she can win the grand prize.
First, let's determine the total number of ways to choose 4 numbers from the... |
[
{
"content": "Problem: Rectangles $ABCD$ and $EFGH$ are drawn such that $D,E,C,F$ are collinear. Also, $A,D,H,G$ all lie on a circle. If $BC=16$ , $AB=107$ , $FG=17$ , and $EF=184$ , what is the length of $CE$ ? [asy] import graph; unitsize(0.1cm); pair A = (0,0);pair B = (70,0);pair C = (70,16);pai... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 19 | AIME24 | {
"expected_answer": "104",
"problem_id": "aime24-19",
"reference_solution": "We use simple geometry to solve this problem. [asy] import graph; unitsize(0.1cm); pair A = (0,0);pair B = (107,0);pair C = (107,16);pair D = (0,16);pair E = (3,16);pair F = (187,16);pair G = (187,33);pair H = (3,33); label(\"$A$\", A,... | To solve the problem, we need to find the length of \(CE\). Given the rectangles \(ABCD\) and \(EFGH\) with \(BC=16\), \(AB=107\), \(FG=17\), and \(EF=184\), and knowing that \(D, E, C, F\) are collinear and \(A, D, H, G\) lie on a circle, we can use the properties of cyclic quadrilaterals and similar triangles.
First... |
[
{
"content": "Problem: Consider the paths of length $16$ that follow the lines from the lower left corner to the upper right corner on an $8\\times 8$ grid. Find the number of such paths that change direction exactly four times, as in the examples shown below. [asy] size(10cm); usepackage(\"tikz\");label(\"... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 20 | AIME24 | {
"expected_answer": "294",
"problem_id": "aime24-20",
"reference_solution": "We divide the path into eight “ $R$ ” movements and eight “ $U$ ” movements. Five sections of alternative $RURUR$ or $URURU$ are necessary in order to make four “turns.” We use the first case and multiply by $2$ . <br/>\nFor $U$ ,... | To solve the problem of finding the number of paths of length 16 that change direction exactly four times on an $8 \times 8$ grid, we need to carefully analyze the structure of such paths.
A path from the lower left corner $(0,0)$ to the upper right corner $(8,8)$ consists of 8 right (R) moves and 8 up (U) moves. A ch... |
[
{
"content": "Problem: Find the largest possible real part of \\[(75+117i)z+\\frac{96+144i}{z}\\] where $z$ is a complex number with $|z|=4$ .\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 21 | AIME24 | {
"expected_answer": "540",
"problem_id": "aime24-21",
"reference_solution": "Let $z=a+bi$ such that $a^2+b^2=4^2=16$ . The expression becomes: \\[(75+117i)(a+bi)+\\dfrac{96+144i}{a+bi}.\\] Call this complex number $w$ . We simplify this expression. \\begin{align*}\nw&=(75+117i)(a+bi)+\\dfrac{96+144i}{a+bi} \... | To find the largest possible real part of the expression \((75+117i)z + \frac{96+144i}{z}\) where \(z\) is a complex number with \(|z| = 4\), we start by letting \(z = 4e^{i\theta}\). Then, we have \(\frac{1}{z} = \frac{1}{4}e^{-i\theta}\).
The expression becomes:
\[
(75+117i)z + \frac{96+144i}{z} = (75+117i)4e^{i\the... |
[
{
"content": "Problem: Eight circles of radius $34$ are sequentially tangent, and two of the circles are tangent to $AB$ and $BC$ of triangle $ABC$ , respectively. $2024$ circles of radius $1$ can be arranged in the same manner. The inradius of triangle $ABC$ can be expressed as $\\frac{m}{n}$ , w... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 22 | AIME24 | {
"expected_answer": "197",
"problem_id": "aime24-22",
"reference_solution": "Draw an altitude from both end circles of the diagram with the circles of radius one, and call the lengths you get drawing the altitudes of the circles down to $BC$ $a$ and $b$ . Now we have the length of side $BC$ of being $(2)... | To solve the problem, we need to understand the arrangement of the circles and their relation to the inradius of triangle \(ABC\). Let's denote the inradius of triangle \(ABC\) by \(r\).
First, consider the arrangement of the eight circles of radius 34. Since these circles are tangent to each other and to the sides \(... |
[
{
"content": "Problem: Let $A$ , $B$ , $C$ , and $D$ be points on the hyperbola $\\frac{x^2}{20}- \\frac{y^2}{24} = 1$ such that $ABCD$ is a rhombus whose diagonals intersect at the origin. Find the greatest real number that is less than $BD^2$ for all such rhombi.\nMark your solution with \\boxed\nA... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 23 | AIME24 | {
"expected_answer": "480",
"problem_id": "aime24-23",
"reference_solution": "A quadrilateral is a rhombus if and only if its two diagonals bisect each other and are perpendicular to each other. The first condition is automatically satisfied because of the hyperbola's symmetry about the origin. To satisfy the sec... | Given the hyperbola \(\frac{x^2}{20} - \frac{y^2}{24} = 1\) and a rhombus \(ABCD\) whose diagonals intersect at the origin, we need to find the greatest real number less than \(BD^2\) for all such rhombi.
Since the diagonals of the rhombus intersect at the origin and are perpendicular to each other, the vertices of th... |
[
{
"content": "Problem: Let $ABC$ be a triangle inscribed in circle $\\omega$ . Let the tangents to $\\omega$ at $B$ and $C$ intersect at point $D$ , and let $\\overline{AD}$ intersect $\\omega$ at $P$ . If $AB=5$ , $BC=9$ , and $AC=10$ , $AP$ can be written as the form $\\frac{m}{n}$ , wher... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 24 | AIME24 | {
"expected_answer": "113",
"problem_id": "aime24-24",
"reference_solution": "From the tangency condition we have $\\let\\angle BCD = \\let\\angle CBD = \\let\\angle A$ . With LoC we have $\\cos(A) = \\frac{25+100-81}{2*5*10} = \\frac{11}{25}$ and $\\cos(B) = \\frac{81+25-100}{2*9*5} = \\frac{1}{15}$ . Then, ... | To solve the problem, we will use properties of the power of a point and the concept of harmonic division in geometry. The given triangle \(ABC\) is inscribed in a circle \(\omega\), and we are given that the tangents to \(\omega\) at \(B\) and \(C\) intersect at point \(D\). The line \(AD\) intersects \(\omega\) again... |
[
{
"content": "Problem: Each vertex of a regular octagon is independently colored either red or blue with equal probability. The probability that the octagon can then be rotated so that all of the blue vertices end up at positions where there were originally red vertices is $\\tfrac{m}{n}$ , where $m$ and $n... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 25 | AIME24 | {
"expected_answer": "371",
"problem_id": "aime24-25",
"reference_solution": "Notice that the question's condition mandates all blues to go to reds, but reds do not necessarily have to go to blue. Let us do casework on how many blues there are. If there are no blues whatsoever, there is only one case. This case i... | To solve this problem, we need to understand the conditions under which a regular octagon can be rotated such that all blue vertices end up at positions where there were originally red vertices. This means that if we rotate the octagon, the set of blue vertices must map to the set of red vertices, and vice versa. Let's... |
[
{
"content": "Problem: Define $f(x)=|| x|-\\tfrac{1}{2}|$ and $g(x)=|| x|-\\tfrac{1}{4}|$ . Find the number of intersections of the graphs of \\[y=4 g(f(\\sin (2 \\pi x))) \\quad\\text{ and }\\quad x=4 g(f(\\cos (3 \\pi y))).\\]\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 26 | AIME24 | {
"expected_answer": "385",
"problem_id": "aime24-26",
"reference_solution": "If we graph $4g(f(x))$ , we see it forms a sawtooth graph that oscillates between $0$ and $1$ (for values of $x$ between $-1$ and $1$ , which is true because the arguments are between $-1$ and $1$ ). Thus by precariously dr... | To solve the problem, we need to understand the behavior of the functions \( f(x) \) and \( g(x) \), and then analyze the given equations.
First, let's define the functions more clearly:
\[ f(x) = \left| |x| - \frac{1}{2} \right| \]
\[ g(x) = \left| |x| - \frac{1}{4} \right| \]
We need to find the number of intersect... |
[
{
"content": "Problem: Let $p$ be the least prime number for which there exists a positive integer $n$ such that $n^{4}+1$ is divisible by $p^{2}$ . Find the least positive integer $m$ such that $m^{4}+1$ is divisible by $p^{2}$ .\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 27 | AIME24 | {
"expected_answer": "110",
"problem_id": "aime24-27",
"reference_solution": "If \\(p=2\\), then \\(4\\mid n^4+1\\) for some integer \\(n\\). But \\(\\left(n^2\\right)^2\\equiv0\\) or \\(1\\pmod4\\), so it is impossible. Thus \\(p\\) is an odd prime. For integer \\(n\\) such that \\(p^2\\mid n^4+1\\), we have \\(... | To solve the problem, we need to find the least prime number \( p \) such that there exists a positive integer \( n \) for which \( n^4 + 1 \) is divisible by \( p^2 \). Then, we need to find the least positive integer \( m \) such that \( m^4 + 1 \) is divisible by \( p^2 \).
First, we note that \( n^4 + 1 \equiv 0 \... |
[
{
"content": "Problem: Let $ABCD$ be a tetrahedron such that $AB=CD= \\sqrt{41}$ , $AC=BD= \\sqrt{80}$ , and $BC=AD= \\sqrt{89}$ . There exists a point $I$ inside the tetrahedron such that the distances from $I$ to each of the faces of the tetrahedron are all equal. This distance can be written in the ... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 28 | AIME24 | {
"expected_answer": "104",
"problem_id": "aime24-28",
"reference_solution": "Notice that \\(41=4^2+5^2\\), \\(89=5^2+8^2\\), and \\(80=8^2+4^2\\), let \\(A~(0,0,0)\\), \\(B~(4,5,0)\\), \\(C~(0,5,8)\\), and \\(D~(4,0,8)\\). Then the plane \\(BCD\\) has a normal\n\\begin{equation*}\n\\mathbf n:=\\frac14\\overright... | To solve the problem, we need to find the distance from the point \( I \) (which is the incenter of the tetrahedron) to each of the faces of the tetrahedron \(ABCD\). This distance is known as the inradius of the tetrahedron.
First, we calculate the volume of the tetrahedron. We can use the Cayley-Menger determinant f... |
[
{
"content": "Problem: Let $\\mathcal{B}$ be the set of rectangular boxes with surface area $54$ and volume $23$ . Let $r$ be the radius of the smallest sphere that can contain each of the rectangular boxes that are elements of $\\mathcal{B}$ . The value of $r^2$ can be written as $\\frac{p}{q}$ , wh... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 0,
"temperature": 0.7
} | 0 | 29 | AIME24 | {
"expected_answer": "721",
"problem_id": "aime24-29",
"reference_solution": "Observe that the \"worst\" possible box is one of the maximum possible length. \nBy symmetry, the height and the width are the same in this antioptimal box. (If the height and width weren't the same, the extra difference between them co... | To solve the problem, we start by letting the dimensions of the rectangular box be \(a\), \(b\), and \(c\). The surface area of the box is given by:
\[
2(ab + bc + ca) = 54 \implies ab + bc + ca = 27.
\]
The volume of the box is given by:
\[
abc = 23.
\]
The radius \(r\) of the smallest sphere that can contain the rect... |
[
{
"content": "Problem: Among the 900 residents of Aimeville, there are 195 who own a diamond ring, 367 who own a set of golf clubs, and 562 who own a garden spade. In addition, each of the 900 residents owns a bag of candy hearts. There are 437 residents who own exactly two of these things, and 234 residents wh... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 0 | AIME24 | {
"expected_answer": "73",
"problem_id": "aime24-0",
"reference_solution": "Let $w,x,y,z$ denote the number of residents who own 1,2,3 and 4 of these items, respectively. We know $w+x+y+z=900$ , since there are 900 residents in total. This simplifies to $w+z=229$ , since we know $x=437$ and $y=234$ . Now, w... | To find the number of residents of Aimeville who own all four items, we can use the principle of inclusion-exclusion. Let's denote the sets of residents owning diamond rings, sets of golf clubs, garden spades, and bags of candy hearts as \(D\), \(G\), \(S\), and \(C\) respectively. We are given the following:
- \(|D| ... |
[
{
"content": "Problem: A list of positive integers has the following properties: $\\bullet$ The sum of the items in the list is $30$ . $\\bullet$ The unique mode of the list is $9$ . $\\bullet$ The median of the list is a positive integer that does not appear in the list itself. Find the sum of the squares... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 1 | AIME24 | {
"expected_answer": "236",
"problem_id": "aime24-1",
"reference_solution": "The third condition implies that the list's size must be an even number, as if it were an odd number, the median of the list would surely appear in the list itself. Therefore, we can casework on what even numbers work. Say the size is 2.... | To find a list of positive integers that satisfies the given conditions, we need to analyze each condition carefully.
1. **Sum of the items in the list is 30.**
2. **The unique mode of the list is 9.**
3. **The median of the list is a positive integer that does not appear in the list itself.**
### Step 1: Understandi... |
[
{
"content": "Problem: Find the number of ways to place a digit in each cell of a 2x3 grid so that the sum of the two numbers formed by reading left to right is $999$ , and the sum of the three numbers formed by reading top to bottom is $99$ . The grid below is an example of such an arrangement because $8+99... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 2 | AIME24 | {
"expected_answer": "45",
"problem_id": "aime24-2",
"reference_solution": "Consider this table: $\\begin{array}{|c|c|c|} \\hline a & b & c \\\\ \\hline d & e & f\\\\ \\hline \\end{array}$ We note that $c+f = 9$ , because $c+f \\leq 18$ , meaning it never achieves a unit's digit sum of $9$ otherwise. Since no... | To solve this problem, we need to find a way to place digits in a 2x3 grid such that the sum of the two numbers formed by reading left to right is 999, and the sum of the three numbers formed by reading top to bottom is 99. Let's denote the digits in the grid as follows:
\[
\begin{array}{|c|c|c|}
\hline
a & b & c \\
\... |
[
{
"content": "Problem: Let $x,y$ and $z$ be positive real numbers that satisfy the following system of equations:\n \\[\\log_2\\left({x \\over yz}\\right) = {1 \\over 2}\\] \\[\\log_2\\left({y \\over xz}\\right) = {1 \\over 3}\\] \\[\\log_2\\left({z \\over xy}\\right) = {1 \\over 4}\\] \nThen the value of... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 3 | AIME24 | {
"expected_answer": "33",
"problem_id": "aime24-3",
"reference_solution": "Denote $\\log_2(x) = a$ , $\\log_2(y) = b$ , and $\\log_2(z) = c$ . Then, we have:\n $a-b-c = \\frac{1}{2}$ \n $-a+b-c = \\frac{1}{3}$ \n $-a-b+c = \\frac{1}{4}$ Now, we can solve to get $a = \\frac{-7}{24}, b = \\frac{-9}{24}, c = \\... | To solve the given system of equations involving logarithms, we first rewrite the equations in a more manageable form. The given equations are:
\[
\log_2\left(\frac{x}{yz}\right) = \frac{1}{2}
\]
\[
\log_2\left(\frac{y}{xz}\right) = \frac{1}{3}
\]
\[
\log_2\left(\frac{z}{xy}\right) = \frac{1}{4}
\]
We can rewrite the... |
[
{
"content": "Problem: Let ABCDEF be a convex equilateral hexagon in which all pairs of opposite sides are parallel. The triangle whose sides are extensions of segments AB, CD, and EF has side lengths 200, 240, and 300. Find the side length of the hexagon.\nMark your solution with \\boxed\nAnswer:",
"role":... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 4 | AIME24 | {
"expected_answer": "80",
"problem_id": "aime24-4",
"reference_solution": "Draw a good diagram!\nLet $AF \\cap BC$ , $BC \\cap DE$ , and $AF \\cap DE$ be K, L, and M, respectively. Let $KL=200, KM=300, ML=240$ . Notice that all smaller triangles formed are all similar to the larger $(200,240,300)$ triangl... | Given that ABCDEF is a convex equilateral hexagon with all pairs of opposite sides being parallel, we can deduce that the hexagon can be split into two congruent trapezoids by drawing a line through the midpoints of the opposite sides. This property implies that the hexagon is symmetric and can be thought of as a "stre... |
[
{
"content": "Problem: Alice chooses a set $A$ of positive integers. Then Bob lists all finite nonempty sets $B$ of positive integers with the property that the maximum element of $B$ belongs to $A$ . Bob's list has 2024 sets. Find the sum of the elements of A.\nMark your solution with \\boxed\nAnswer:",... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 5 | AIME24 | {
"expected_answer": "55",
"problem_id": "aime24-5",
"reference_solution": "Let $k$ be one of the elements in Alices set $A$ of positive integers. The number of sets that Bob lists with the property that their maximum element is k is $2^{k-1}$ , since every positive integer less than k can be in the set or o... | To solve this problem, we need to understand how Bob's list of sets \( B \) is formed based on the set \( A \) chosen by Alice. Each set \( B \) in Bob's list is a nonempty set of positive integers whose maximum element is in \( A \). Let's denote the elements of \( A \) as \( a_1, a_2, \ldots, a_n \) where \( a_1 < a_... |
[
{
"content": "Problem: Let $N$ be the greatest four-digit positive integer with the property that whenever one of its digits is changed to $1$ , the resulting number is divisible by $7$ . Let $Q$ and $R$ be the quotient and remainder, respectively, when $N$ is divided by $1000$ . Find $Q+R$ .\nMark ... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 6 | AIME24 | {
"expected_answer": "699",
"problem_id": "aime24-6",
"reference_solution": "We note that by changing a digit to $1$ for the number $\\overline{abcd}$ , we are subtracting the number by either $1000(a-1)$ , $100(b-1)$ , $10(c-1)$ , or $d-1$ . Thus, $1000a + 100b + 10c + d \\equiv 1000(a-1) \\equiv 100(b-1... | To find the greatest four-digit positive integer \( N \) such that changing any one of its digits to \( 1 \) results in a number divisible by \( 7 \), we will denote \( N \) as \( \overline{abcd} \), where \( a, b, c, \) and \( d \) are its digits. We need to ensure that the numbers \( \overline{1bcd} \), \( \overline{... |
[
{
"content": "Problem: Torus $T$ is the surface produced by revolving a circle with radius $3$ around an axis in the plane of the circle that is a distance $6$ from the center of the circle (so like a donut). Let $S$ be a sphere with a radius $11$ . When $T$ rests on the inside of $S$ , it is intern... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 7 | AIME24 | {
"expected_answer": "127",
"problem_id": "aime24-7",
"reference_solution": "First, let's consider a section $\\mathcal{P}$ of the solids, along the axis.\nBy some 3D-Geomerty thinking, we can simply know that the axis crosses the sphere center. So, that is saying, the $\\mathcal{P}$ we took crosses one of th... | To solve this problem, we need to understand the geometry of the torus \( T \) and the sphere \( S \) and how they interact when the torus is internally and externally tangent to the sphere.
1. **Torus Geometry**:
- The torus is generated by revolving a circle with radius \( 3 \) around an axis that is \( 6 \) unit... |
[
{
"content": "Problem: There is a collection of $25$ indistinguishable white chips and $25$ indistinguishable black chips. Find the number of ways to place some of these chips in the $25$ unit cells of a $5\\times5$ grid such that: each cell contains at most one chip all chips in the same row and all ch... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 8 | AIME24 | {
"expected_answer": "902",
"problem_id": "aime24-8",
"reference_solution": "The problem says \"some\", so not all cells must be occupied.\nWe start by doing casework on the column on the left. There can be 5,4,3,2, or 1 black chip. The same goes for white chips, so we will multiply by 2 at the end. There is $1$... | To solve this problem, we need to place some of the chips in the $5 \times 5$ grid such that each row and each column contains chips of the same color and no additional chip can be added without violating the conditions. This means each row and each column must contain either all white chips or all black chips, and we ... |
[
{
"content": "Problem: Let $\\triangle ABC$ have circumcenter $O$ and incenter $I$ with $\\overline{IA}\\perp\\overline{OI}$ , circumradius $13$ , and inradius $6$ . Find $AB\\cdot AC$ .\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 9 | AIME24 | {
"expected_answer": "468",
"problem_id": "aime24-9",
"reference_solution": "By Euler's formula $OI^{2}=R(R-2r)$ , we have $OI^{2}=13(13-12)=13$ . Thus, by the Pythagorean theorem, $AI^{2}=13^{2}-13=156$ . Let $AI\\cap(ABC)=M$ ; notice $\\triangle AOM$ is isosceles and $\\overline{OI}\\perp\\overline{AM}$ ... | Given that \(\triangle ABC\) has circumcenter \(O\), incenter \(I\), and \(\overline{IA} \perp \overline{OI}\), with circumradius \(R = 13\) and inradius \(r = 6\), we aim to find the product \(AB \cdot AC\).
Since \(\overline{IA} \perp \overline{OI}\), we can use the fact that in a triangle, the line joining the ince... |
[
{
"content": "Problem: Find the number of triples of nonnegative integers $(a,b,c)$ satisfying $a + b + c = 300$ and\n \\[a^2b + a^2c + b^2a + b^2c + c^2a + c^2b = 6,000,000.\\]\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 10 | AIME24 | {
"expected_answer": "601",
"problem_id": "aime24-10",
"reference_solution": "$ab(a+b)+bc(b+c)+ac(a+c)=300(ab+bc+ac)-3abc=6000000, 100(ab+bc+ac)-abc=2000000$ Note that \n $(100-a)(100-b)(100-c)=1000000-10000(a+b+c)+100(ab+bc+ac)-abc=0$ . Thus, $a/b/c=100$ . There are $201$ cases for each but we need to subtrac... | To find the number of triples of nonnegative integers \((a, b, c)\) satisfying the equations \(a + b + c = 300\) and \(a^2b + a^2c + b^2a + b^2c + c^2a + c^2b = 6,000,000\), we will analyze the second equation in detail.
First, let's rewrite the second equation:
\[a^2b + a^2c + b^2a + b^2c + c^2a + c^2b = 6,000,000.\]... |
[
{
"content": "Problem: Let \\(O=(0,0)\\), \\(A=\\left(\\tfrac{1}{2},0\\right)\\), and \\(B=\\left(0,\\tfrac{\\sqrt{3}}{2}\\right)\\) be points in the coordinate plane. Let \\(\\mathcal{F}\\) be the family of segments \\(\\overline{PQ}\\) of unit length lying in the first quadrant with \\(P\\) on the \\(x\\)-axi... | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 11 | AIME24 | {
"expected_answer": "23",
"problem_id": "aime24-11",
"reference_solution": "Begin by finding the equation of the line $\\overline{AB}$ : $y= -\\sqrt{3}x+\\frac{\\sqrt{3}}{2}$ Now, consider the general equation of all lines that belong to $\\mathcal{F}$ . Let $P$ be located at $(a,0)$ and $Q$ be located... | To find the unique point \(C\) on \(\overline{AB}\) that does not belong to any segment from \(\mathcal{F}\) other than \(\overline{AB}\), we first need to understand the nature of the segments in \(\mathcal{F}\). These segments are unit length segments with one endpoint on the \(x\)-axis and the other on the \(y\)-axi... |
[
{
"content": "Problem: Let $\\omega\\neq 1$ be a 13th root of unity. Find the remainder when\n \\[\\prod_{k=0}^{12}(2-2\\omega^k+\\omega^{2k})\\] \nis divided by 1000.\nMark your solution with \\boxed\nAnswer:",
"role": "user"
}
] | {
"do_sample": false,
"max_new_tokens": 32768,
"seed": 1,
"temperature": 0.7
} | 1 | 12 | AIME24 | {
"expected_answer": "321",
"problem_id": "aime24-12",
"reference_solution": "\\[\\prod_{k=0}^{12} \\left(2- 2\\omega^k + \\omega^{2k}\\right) = \\prod_{k=0}^{12} \\left((1 - \\omega^k)^2 + 1\\right) = \\prod_{k=0}^{12} \\left((1 + i) - \\omega^k)((1 - i) - \\omega^k\\right)\\] Now, we consider the polynomial $x... | To find the remainder when \(\prod_{k=0}^{12}(2-2\omega^k+\omega^{2k})\) is divided by 1000, we first need to understand the properties of the 13th roots of unity. Let \(\omega = e^{2\pi i / 13}\) be a primitive 13th root of unity. The 13th roots of unity are the solutions to the equation \(x^{13} - 1 = 0\), which can ... |
End of preview. Expand in Data Studio
YAML Metadata Warning:empty or missing yaml metadata in repo card
Check out the documentation for more information.
mlfoundations-dev/Qwen2.5-32B-Instruct_1744001655_eval_0981
Precomputed model outputs for evaluation.
Evaluation Results
Summary
| Metric | AIME24 | AIME25 | AMC23 | MATH500 | GPQADiamond | LiveCodeBench |
|---|---|---|---|---|---|---|
| Accuracy | 16.7 | 12.0 | 62.0 | 79.4 | 41.2 | 49.3 |
AIME24
- Average Accuracy: 16.67% ± 2.11%
- Number of Runs: 5
| Run | Accuracy | Questions Solved | Total Questions |
|---|---|---|---|
| 1 | 13.33% | 4 | 30 |
| 2 | 16.67% | 5 | 30 |
| 3 | 20.00% | 6 | 30 |
| 4 | 23.33% | 7 | 30 |
| 5 | 10.00% | 3 | 30 |
AIME25
- Average Accuracy: 12.00% ± 1.52%
- Number of Runs: 5
| Run | Accuracy | Questions Solved | Total Questions |
|---|---|---|---|
| 1 | 13.33% | 4 | 30 |
| 2 | 6.67% | 2 | 30 |
| 3 | 10.00% | 3 | 30 |
| 4 | 16.67% | 5 | 30 |
| 5 | 13.33% | 4 | 30 |
AMC23
- Average Accuracy: 62.00% ± 3.27%
- Number of Runs: 5
| Run | Accuracy | Questions Solved | Total Questions |
|---|---|---|---|
| 1 | 50.00% | 20 | 40 |
| 2 | 62.50% | 25 | 40 |
| 3 | 65.00% | 26 | 40 |
| 4 | 72.50% | 29 | 40 |
| 5 | 60.00% | 24 | 40 |
MATH500
- Accuracy: 79.40%
Accuracy Questions Solved Total Questions 79.40% 397 500
GPQADiamond
- Average Accuracy: 41.25% ± 0.84%
- Number of Runs: 3
| Run | Accuracy | Questions Solved | Total Questions |
|---|---|---|---|
| 1 | 41.41% | 82 | 198 |
| 2 | 39.39% | 78 | 198 |
| 3 | 42.93% | 85 | 198 |
LiveCodeBench
- Average Accuracy: 49.32% ± 0.97%
- Number of Runs: 3
| Run | Accuracy | Questions Solved | Total Questions |
|---|---|---|---|
| 1 | 51.08% | 261 | 511 |
| 2 | 47.75% | 244 | 511 |
| 3 | 49.12% | 251 | 511 |
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