Datasets:
logged_at_unix_ns int64 | session_id string | rank int64 | generation_batch int64 | rollout_index int64 | prompt string | gold_answer string | q_m float64 | completion string | completion_chars int64 | ends_after_post_confidence bool | parsed_pre_confidence float64 | parsed_answer string | parsed_post_confidence float64 | schema_fields_ok dict | missing_schema_fields list | schema_tag_order list | schema_order_ok bool | format_field_penalty float64 | format_order_penalty float64 | rewards dict | arm string | model_id string | run_id string | reward_format float64 | reward_accuracy float64 | reward_pre float64 | reward_post float64 | reward_total float64 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 0 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 9 | 0.282311 | <pre_confidence>1.0</pre_confidence>
<thinking>Here's the step-by-step solution:
1. **Determine how many apples Greg and Sarah each get.**
The total number of apples is 18, and they are splitting them evenly between Greg and Sarah. Since the problem states "Greg and Sarah have 18 apples that they are going to split... | 5,275 | false | 1 | null | null | {
"pre_confidence": true,
"thinking": false,
"answer": false,
"post_confidence": false
} | [
"thinking",
"answer",
"post_confidence"
] | [
"pre_confidence",
"thinking"
] | true | 0.75 | 0 | {
"format": 0.25,
"accuracy": 0,
"pre": 0,
"post": 0,
"total": 0.25
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 0.25 | 0 | 0 | 0 | 0.25 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 1 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 9 | 0.282311 | <pre_confidence>1.0</pre_confidence>
<thinking>Here's the step-by-step thought process:
1. **Determine the number of apples each person gets:**
* Greg and Sarah have 18 apples to split evenly.
* Apples Greg gets = $18 / 2 = 9$ apples.
2. **Determine how many apples Susan has:**
* Susan has twice as many appl... | 5,308 | false | 1 | null | null | {
"pre_confidence": true,
"thinking": false,
"answer": false,
"post_confidence": false
} | [
"thinking",
"answer",
"post_confidence"
] | [
"pre_confidence",
"thinking"
] | true | 0.75 | 0 | {
"format": 0.25,
"accuracy": 0,
"pre": 0,
"post": 0,
"total": 0.25
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 0.25 | 0 | 0 | 0 | 0.25 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 2 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 9 | 0.282311 | <pre_confidence>1.0</pre_confidence>
<thinking>Here's the step-by-step solution:
1. **Determine how many apples Greg and Sarah each get:**
They have 18 apples to split evenly between Greg and Sarah.
Greg's share = $18 / 2 = 9$ apples.
2. **Determine how many apples Susan has:**
Susan has twice as many apples... | 4,467 | true | 1 | 40 | 1 | {
"pre_confidence": true,
"thinking": true,
"answer": true,
"post_confidence": true
} | [] | [
"pre_confidence",
"thinking",
"answer",
"post_confidence"
] | true | 0 | 0 | {
"format": 1,
"accuracy": 0,
"pre": 0,
"post": 0,
"total": 1
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 1 | 0 | 0 | 0 | 1 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 3 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 9 | 0.282311 | <pre_confidence>1.0</pre_confidence>
<thinking>Here is the step-by-step solution:
1. **Determine how many apples Greg and Sarah split evenly:**
The total number of apples is 18.
Since they are splitting them evenly, each person (Greg and Sarah) gets $18 / 2 = 9$ apples.
So, Greg will end up with 9 apples.
2.... | 4,397 | true | 1 | 40 | 1 | {
"pre_confidence": true,
"thinking": true,
"answer": true,
"post_confidence": true
} | [] | [
"pre_confidence",
"thinking",
"answer",
"post_confidence"
] | true | 0 | 0 | {
"format": 1,
"accuracy": 0,
"pre": 0,
"post": 0,
"total": 1
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 1 | 0 | 0 | 0 | 1 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 4 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 13 | 0.285605 | <pre_confidence>1.0</pre_confidence>
<thinking>The problem asks for the value of $n$ such that the sum of consecutive odd integers $e$, where $e = 2k - 1$ and $k$ is a multiple of 3, from $k=1$ to $n$, equals 597.
1. Identify the values of $k$: $k$ must be a multiple of 3. So, $k$ takes the values $3, 6, 9, 12, \dots$... | 3,279 | false | 1 | null | null | {
"pre_confidence": true,
"thinking": false,
"answer": false,
"post_confidence": false
} | [
"thinking",
"answer",
"post_confidence"
] | [
"pre_confidence",
"thinking"
] | true | 0.75 | 0 | {
"format": 0.25,
"accuracy": 0,
"pre": 0,
"post": 0,
"total": 0.25
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 0.25 | 0 | 0 | 0 | 0.25 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 5 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 13 | 0.285605 | <pre_confidence>1.0</pre_confidence>
<thinking>The problem asks for the value of $n$ such that the sum of consecutive odd integers $e$, where $e = 2k - 1$ and $k$ is a multiple of 3, from $k=1$ up to some limit related to $n$, equals 597.
First, let's identify the values of $k$ that are multiples of 3. These are $k = ... | 3,549 | false | 1 | null | null | {
"pre_confidence": true,
"thinking": false,
"answer": false,
"post_confidence": false
} | [
"thinking",
"answer",
"post_confidence"
] | [
"pre_confidence",
"thinking"
] | true | 0.75 | 0 | {
"format": 0.25,
"accuracy": 0,
"pre": 0,
"post": 0,
"total": 0.25
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 0.25 | 0 | 0 | 0 | 0.25 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 6 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 13 | 0.285605 | <pre_confidence>1.0</pre_confidence>
<thinking>The problem asks for the value of $n$ such that the sum of a specific set of consecutive odd integers equals 597.
The consecutive odd integers are defined by $e = 2k - 1$, where $k$ is a multiple of 3.
So, $k$ can be written as $k = 3m$ for some positive integer $m$ (sinc... | 3,642 | false | 1 | null | null | {
"pre_confidence": true,
"thinking": false,
"answer": false,
"post_confidence": false
} | [
"thinking",
"answer",
"post_confidence"
] | [
"pre_confidence",
"thinking"
] | true | 0.75 | 0 | {
"format": 0.25,
"accuracy": 0,
"pre": 0,
"post": 0,
"total": 0.25
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 0.25 | 0 | 0 | 0 | 0.25 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 7 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 13 | 0.285605 | <pre_confidence>1.0</pre_confidence>
<thinking>The problem asks for the value of $n$ such that the sum of a specific sequence of consecutive odd integers equals 597.
1. **Identify the sequence of odd integers ($e$):**
The odd integers are defined by $e = 2k - 1$, where $k$ is a multiple of 3.
So, $k$ can be writ... | 3,688 | false | 1 | null | null | {
"pre_confidence": true,
"thinking": false,
"answer": false,
"post_confidence": false
} | [
"thinking",
"answer",
"post_confidence"
] | [
"pre_confidence",
"thinking"
] | true | 0.75 | 0 | {
"format": 0.25,
"accuracy": 0,
"pre": 0,
"post": 0,
"total": 0.25
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 0.25 | 0 | 0 | 0 | 0.25 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 8 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 5 | 0.28258 | <pre_confidence>1.0</pre_confidence>
<thinking>The problem involves an arithmetic sequence $\{a_n\}$ with a common difference $d \neq 0$.
The general term of an arithmetic sequence is $a_n = a_1 + (n-1)d$.
We are given the condition: $a_{3}+a_{9}=a_{10}-a_{8}$.
Express the terms using the general formula:
$a_3 = a_1 ... | 1,273 | true | 1 | 5 | 1 | {
"pre_confidence": true,
"thinking": true,
"answer": true,
"post_confidence": true
} | [] | [
"pre_confidence",
"thinking",
"answer",
"post_confidence"
] | true | 0 | 0 | {
"format": 1,
"accuracy": 1,
"pre": 1,
"post": 1,
"total": 4
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 1 | 1 | 1 | 1 | 4 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 9 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 5 | 0.28258 | <pre_confidence>1.0</pre_confidence>
<thinking>The problem asks for the index $n$ such that $a_n = 0$, given an arithmetic sequence $\{a_n\}$ with a common difference $d \neq 0$, and the condition $a_{3}+a_{9}=a_{10}-a_{8}$.
The formula for the $n$-th term of an arithmetic sequence is $a_n = a_1 + (n-1)d$.
Let's expr... | 1,300 | true | 1 | 5 | 1 | {
"pre_confidence": true,
"thinking": true,
"answer": true,
"post_confidence": true
} | [] | [
"pre_confidence",
"thinking",
"answer",
"post_confidence"
] | true | 0 | 0 | {
"format": 1,
"accuracy": 1,
"pre": 1,
"post": 1,
"total": 4
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 1 | 1 | 1 | 1 | 4 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 10 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 5 | 0.28258 | <pre_confidence>1.0</pre_confidence>
<thinking>The problem involves an arithmetic sequence $\{a_n\}$ with a common difference $d \neq 0$.
The general term of an arithmetic sequence is given by $a_n = a_1 + (n-1)d$, where $a_1$ is the first term.
We are given the condition: $a_{3} + a_{9} = a_{10} - a_{8}$.
Let's expr... | 1,880 | true | 1 | 5 | 1 | {
"pre_confidence": true,
"thinking": true,
"answer": true,
"post_confidence": true
} | [] | [
"pre_confidence",
"thinking",
"answer",
"post_confidence"
] | true | 0 | 0 | {
"format": 1,
"accuracy": 1,
"pre": 1,
"post": 1,
"total": 4
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 1 | 1 | 1 | 1 | 4 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 11 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 5 | 0.28258 | <pre_confidence>1.0</pre_confidence>
<thinking>The problem involves an arithmetic sequence $\{a_n\}$ with a common difference $d \neq 0$.
The general term of an arithmetic sequence is given by $a_n = a_1 + (n-1)d$, where $a_1$ is the first term.
The given condition is $a_{3}+a_{9}=a_{10}-a_{8}$.
Let's express these t... | 1,481 | true | 1 | 5 | 1 | {
"pre_confidence": true,
"thinking": true,
"answer": true,
"post_confidence": true
} | [] | [
"pre_confidence",
"thinking",
"answer",
"post_confidence"
] | true | 0 | 0 | {
"format": 1,
"accuracy": 1,
"pre": 1,
"post": 1,
"total": 4
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 1 | 1 | 1 | 1 | 4 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 12 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 18 | 0.285605 | <pre_confidence>1.0</pre_confidence>
<thinking>The problem involves an arithmetic sequence $\{a_n\}$.
Let $a_1$ be the first term and $d$ be the common difference.
The $n$-th term of an arithmetic sequence is given by $a_n = a_1 + (n-1)d$.
We are given the condition: $a_3 + a_7 = 4$.
Express $a_3$ and $a_7$ in terms ... | 1,582 | true | 1 | 18 | 1 | {
"pre_confidence": true,
"thinking": true,
"answer": true,
"post_confidence": true
} | [] | [
"pre_confidence",
"thinking",
"answer",
"post_confidence"
] | true | 0 | 0 | {
"format": 1,
"accuracy": 1,
"pre": 1,
"post": 1,
"total": 4
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 1 | 1 | 1 | 1 | 4 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 13 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 18 | 0.285605 | <pre_confidence>1.0</pre_confidence>
<thinking>The problem asks for the sum of the first 9 terms ($S_9$) of an arithmetic sequence $\{a_n\}$, given that $a_3 + a_7 = 4$.
1. **Recall the formula for the $n$-th term of an arithmetic sequence:**
$a_n = a_1 + (n-1)d$, where $a_1$ is the first term and $d$ is the comm... | 1,741 | true | 1 | 18 | 1 | {
"pre_confidence": true,
"thinking": true,
"answer": true,
"post_confidence": true
} | [] | [
"pre_confidence",
"thinking",
"answer",
"post_confidence"
] | true | 0 | 0 | {
"format": 1,
"accuracy": 1,
"pre": 1,
"post": 1,
"total": 4
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 1 | 1 | 1 | 1 | 4 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 14 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 18 | 0.285605 | <pre_confidence>1.0</pre_confidence>
<thinking>The problem involves an arithmetic sequence $\{a_n\}$.
The general form of an arithmetic sequence is $a_n = a_1 + (n-1)d$, where $a_1$ is the first term and $d$ is the common difference.
We are given the condition: $a_3 + a_7 = 4$.
Express $a_3$ and $a_7$ in terms of $a_... | 1,804 | true | 1 | 18 | 1 | {
"pre_confidence": true,
"thinking": true,
"answer": true,
"post_confidence": true
} | [] | [
"pre_confidence",
"thinking",
"answer",
"post_confidence"
] | true | 0 | 0 | {
"format": 1,
"accuracy": 1,
"pre": 1,
"post": 1,
"total": 4
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 1 | 1 | 1 | 1 | 4 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 15 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 18 | 0.285605 | <pre_confidence>1.0</pre_confidence>
<thinking>The problem asks for the sum of the first 9 terms ($S_9$) of an arithmetic sequence $\{a_n\}$, given the condition $a_3 + a_7 = 4$.
1. **Define the terms of an arithmetic sequence:**
Let $a_1$ be the first term and $d$ be the common difference.
The $n$-th term is... | 1,939 | true | 1 | 18 | 1 | {
"pre_confidence": true,
"thinking": true,
"answer": true,
"post_confidence": true
} | [] | [
"pre_confidence",
"thinking",
"answer",
"post_confidence"
] | true | 0 | 0 | {
"format": 1,
"accuracy": 1,
"pre": 1,
"post": 1,
"total": 4
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 1 | 1 | 1 | 1 | 4 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 16 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 29 | 0.282311 | <pre_confidence>1.0</pre_confidence>
<thinking>1. Start with the initial amount of money Jesse received: $50.
2. Calculate the cost of the novel: $7.
3. Calculate the amount spent on lunch. The problem states she spent twice as much as the novel cost, so lunch cost = $7 * 2 = $14.
4. Calculate the total amount spent: T... | 542 | true | 1 | $29 | 1 | {
"pre_confidence": true,
"thinking": true,
"answer": true,
"post_confidence": true
} | [] | [
"pre_confidence",
"thinking",
"answer",
"post_confidence"
] | true | 0 | 0 | {
"format": 1,
"accuracy": 0,
"pre": 0,
"post": 0,
"total": 1
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 1 | 0 | 0 | 0 | 1 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 17 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 29 | 0.282311 | <pre_confidence>1.0</pre_confidence>
<thinking>1. Start with the initial amount of money Jesse has: $50.
2. Calculate the cost of the novel: $7.
3. Calculate the amount spent on lunch. The problem states she spent twice as much as the novel cost.
Lunch cost = 2 * Novel cost = 2 * $7 = $14.
4. Calculate the total amo... | 589 | true | 1 | $29 | 1 | {
"pre_confidence": true,
"thinking": true,
"answer": true,
"post_confidence": true
} | [] | [
"pre_confidence",
"thinking",
"answer",
"post_confidence"
] | true | 0 | 0 | {
"format": 1,
"accuracy": 0,
"pre": 0,
"post": 0,
"total": 1
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 1 | 0 | 0 | 0 | 1 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 18 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 29 | 0.282311 | <pre_confidence>1.0</pre_confidence>
<thinking>Here's the step-by-step calculation:
1. **Starting amount:** Jesse started with $50.
2. **Cost of the novel:** The novel cost $7.
3. **Money spent on the novel:** $7.
4. **Cost of lunch:** Jesse spent twice as much as the novel cost. Cost of lunch = $7 * 2 = $14.
5. **Tota... | 556 | true | 1 | $29 | 1 | {
"pre_confidence": true,
"thinking": true,
"answer": true,
"post_confidence": true
} | [] | [
"pre_confidence",
"thinking",
"answer",
"post_confidence"
] | true | 0 | 0 | {
"format": 1,
"accuracy": 0,
"pre": 0,
"post": 0,
"total": 1
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 1 | 0 | 0 | 0 | 1 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 19 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 29 | 0.282311 | <pre_confidence>1.0</pre_confidence>
<thinking>1. **Initial amount:** Jesse starts with $50.
2. **Cost of the novel:** The novel costs $7. This cost is spent.
Remaining money after buying the novel: $50 - $7 = $43.
3. **Cost of lunch:** She spent twice as much as the novel cost her.
Cost of lunch = 2 * $7 = $14.
... | 670 | true | 1 | $29 | 1 | {
"pre_confidence": true,
"thinking": true,
"answer": true,
"post_confidence": true
} | [] | [
"pre_confidence",
"thinking",
"answer",
"post_confidence"
] | true | 0 | 0 | {
"format": 1,
"accuracy": 0,
"pre": 0,
"post": 0,
"total": 1
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 1 | 0 | 0 | 0 | 1 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 20 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 0 | 0.284051 | <pre_confidence>1.0</pre_confidence>
<thinking>Let the given expression be $E$.
$$E = 8^{10k + \alpha} + 6^{10k - \alpha} - 7^{10k - \alpha} - 2^{10k + \alpha}$$
We need to find $E \pmod{11}$.
First, we simplify the bases modulo 11:
$8 \equiv -3 \pmod{11}$
$6 \equiv 6 \pmod{11}$
$7 \equiv 7 \pmod{11}$
$2 \equiv 2 \pmo... | 3,403 | false | 1 | null | null | {
"pre_confidence": true,
"thinking": false,
"answer": false,
"post_confidence": false
} | [
"thinking",
"answer",
"post_confidence"
] | [
"pre_confidence",
"thinking"
] | true | 0.75 | 0 | {
"format": 0.25,
"accuracy": 0,
"pre": 0,
"post": 0,
"total": 0.25
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 0.25 | 0 | 0 | 0 | 0.25 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 21 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 0 | 0.284051 | <pre_confidence>1.0</pre_confidence>
<thinking>Let the given expression be $E$.
\[ E = 8^{10k + \alpha} + 6^{10k - \alpha} - 7^{10k - \alpha} - 2^{10k + \alpha} \]
We need to find $E \pmod{11}$.
First, let's simplify the bases modulo 11:
$8 \equiv -3 \pmod{11}$
$6 \equiv 6 \pmod{11}$
$7 \equiv 7 \pmod{11}$
$2 \equiv 2... | 2,892 | true | 1 | 0 | 1 | {
"pre_confidence": true,
"thinking": true,
"answer": true,
"post_confidence": true
} | [] | [
"pre_confidence",
"thinking",
"answer",
"post_confidence"
] | true | 0 | 0 | {
"format": 1,
"accuracy": 1,
"pre": 0.4375,
"post": 1,
"total": 3.4375
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 1 | 1 | 0.4375 | 1 | 3.4375 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 22 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 0 | 0.284051 | <pre_confidence>1.0</pre_confidence>
<thinking>Let the given expression be $E$.
\[ E = 8^{10k + \alpha} + 6^{10k - \alpha} - 7^{10k - \alpha} - 2^{10k + \alpha} \]
We need to find $E \pmod{11}$.
First, let's reduce the bases modulo 11:
$8 \equiv -3 \pmod{11}$
$6 \equiv 6 \pmod{11}$
$7 \equiv 7 \pmod{11}$
$2 \equiv 2 \... | 3,339 | false | 1 | null | null | {
"pre_confidence": true,
"thinking": false,
"answer": false,
"post_confidence": false
} | [
"thinking",
"answer",
"post_confidence"
] | [
"pre_confidence",
"thinking"
] | true | 0.75 | 0 | {
"format": 0.25,
"accuracy": 0,
"pre": 0,
"post": 0,
"total": 0.25
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 0.25 | 0 | 0 | 0 | 0.25 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 23 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 0 | 0.284051 | <pre_confidence>1.0</pre_confidence>
<thinking>Let the given expression be $E$.
\[ E = 8^{10k + \alpha} + 6^{10k - \alpha} - 7^{10k - \alpha} - 2^{10k + \alpha} \]
We need to find $E \pmod{11}$.
We can rewrite the terms using the base 11 residues.
Note that $8 \equiv -3 \pmod{11}$, $6 \equiv 6 \pmod{11}$, $7 \equiv 7 ... | 3,208 | false | 1 | null | null | {
"pre_confidence": true,
"thinking": false,
"answer": false,
"post_confidence": false
} | [
"thinking",
"answer",
"post_confidence"
] | [
"pre_confidence",
"thinking"
] | true | 0.75 | 0 | {
"format": 0.25,
"accuracy": 0,
"pre": 0,
"post": 0,
"total": 0.25
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 0.25 | 0 | 0 | 0 | 0.25 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 24 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 11 | 0.284051 | <pre_confidence>0.95</pre_confidence>
<thinking>Here's a step-by-step thought process to solve the problem:
1. **Understand the Goal:** The objective is to find the *maximum number of sections* that can remain *uncovered*.
2. **Analyze the Given Information:**
* Total length of the corridor ($L_{corridor}$): ... | 5,477 | false | 0.95 | null | null | {
"pre_confidence": true,
"thinking": false,
"answer": false,
"post_confidence": false
} | [
"thinking",
"answer",
"post_confidence"
] | [
"pre_confidence",
"thinking"
] | true | 0.75 | 0 | {
"format": 0.25,
"accuracy": 0,
"pre": 0,
"post": 0,
"total": 0.25
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 0.25 | 0 | 0 | 0 | 0.25 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 25 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 11 | 0.284051 | <pre_confidence>0.95</pre_confidence>
<thinking>Here's a step-by-step thought process to solve the problem:
1. **Understand the Goal:** The objective is to find the *maximum number of sections that can remain uncovered*.
2. **Analyze the Given Information:**
* Total length of the corridor: $L_{corridor} = 100... | 5,171 | true | 0.95 | 19 | 0.85 | {
"pre_confidence": true,
"thinking": true,
"answer": true,
"post_confidence": true
} | [] | [
"pre_confidence",
"thinking",
"answer",
"post_confidence"
] | true | 0 | 0 | {
"format": 1,
"accuracy": 0,
"pre": 0.09750000000000003,
"post": 0.2775000000000001,
"total": 1.3750000000000002
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 1 | 0 | 0.0975 | 0.2775 | 1.375 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 26 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 11 | 0.284051 | <pre_confidence>0.8</pre_confidence>
<thinking>Here's a step-by-step thought process to solve the problem:
1. **Analyze the given information:**
* Total length to pave: $L_{total} = 1000$ meters.
* Number of carpets available: $N_{carpets} = 20$.
* Corridor length: $L_{corridor} = 100$ meters.
*... | 5,421 | false | 0.8 | null | null | {
"pre_confidence": true,
"thinking": false,
"answer": false,
"post_confidence": false
} | [
"thinking",
"answer",
"post_confidence"
] | [
"pre_confidence",
"thinking"
] | true | 0.75 | 0 | {
"format": 0.25,
"accuracy": 0,
"pre": 0,
"post": 0,
"total": 0.25
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 0.25 | 0 | 0 | 0 | 0.25 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 27 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 11 | 0.284051 | <pre_confidence>0.95</pre_confidence>
<thinking>Here's a step-by-step thought process to solve the problem:
1. **Understand the Goal:** The objective is to find the *maximum number of sections that can remain uncovered* when paving 1000 meters of length using 20 rectangular carpets in a 100-meter long corridor, assum... | 5,268 | false | 0.95 | null | null | {
"pre_confidence": true,
"thinking": false,
"answer": false,
"post_confidence": false
} | [
"thinking",
"answer",
"post_confidence"
] | [
"pre_confidence",
"thinking"
] | true | 0.75 | 0 | {
"format": 0.25,
"accuracy": 0,
"pre": 0,
"post": 0,
"total": 0.25
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 0.25 | 0 | 0 | 0 | 0.25 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 28 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 90 | 0.285605 | <pre_confidence>0.95</pre_confidence>
<thinking>1. **Analyze the given information:**
* We have an equilateral triangle ABC. Let the side length be $s$.
* A circle has its center at vertex C and passes through the other two vertices, A and B.
* The radius of this circle is $R = CA = CB$.
* Sinc... | 5,064 | false | 0.95 | null | null | {
"pre_confidence": true,
"thinking": false,
"answer": false,
"post_confidence": false
} | [
"thinking",
"answer",
"post_confidence"
] | [
"pre_confidence",
"thinking"
] | true | 0.75 | 0 | {
"format": 0.25,
"accuracy": 0,
"pre": 0,
"post": 0,
"total": 0.25
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 0.25 | 0 | 0 | 0 | 0.25 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 29 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 90 | 0.285605 | <pre_confidence>0.95</pre_confidence>
<thinking>1. **Analyze the given information:**
* We have an equilateral triangle ABC. Let the side length be $s$.
* A circle has its center at vertex C.
* The radius of the circle is $R = 10$ inches.
* The circle passes through the other two vertices, A an... | 4,397 | false | 0.95 | null | null | {
"pre_confidence": true,
"thinking": false,
"answer": false,
"post_confidence": false
} | [
"thinking",
"answer",
"post_confidence"
] | [
"pre_confidence",
"thinking"
] | true | 0.75 | 0 | {
"format": 0.25,
"accuracy": 0,
"pre": 0,
"post": 0,
"total": 0.25
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 0.25 | 0 | 0 | 0 | 0.25 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 30 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 90 | 0.285605 | <pre_confidence>0.7</pre_confidence>
<thinking>Here's a step-by-step thought process to solve the problem:
1. **Understand the Geometry:**
* We have an equilateral triangle ABC. Let the side length be $s$.
* A circle is defined: Radius $R=10$, Center $C$.
* The circle passes through the other two ve... | 4,495 | false | 0.7 | null | null | {
"pre_confidence": true,
"thinking": false,
"answer": false,
"post_confidence": false
} | [
"thinking",
"answer",
"post_confidence"
] | [
"pre_confidence",
"thinking"
] | true | 0.75 | 0 | {
"format": 0.25,
"accuracy": 0,
"pre": 0,
"post": 0,
"total": 0.25
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 0.25 | 0 | 0 | 0 | 0.25 |
1,789,183,543,941,526,500 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 0 | 31 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | 90 | 0.285605 | <pre_confidence>0.95</pre_confidence>
<thinking>1. **Analyze the given information:**
* We have an equilateral triangle ABC. Let the side length be $s$.
* A circle has its center at vertex C and has a radius $R=10$ inches.
* This circle passes through the other two vertices, A and B.
* This statement im... | 4,264 | false | 0.95 | null | null | {
"pre_confidence": true,
"thinking": false,
"answer": false,
"post_confidence": false
} | [
"thinking",
"answer",
"post_confidence"
] | [
"pre_confidence",
"thinking"
] | true | 0.75 | 0 | {
"format": 0.25,
"accuracy": 0,
"pre": 0,
"post": 0,
"total": 0.25
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 0.25 | 0 | 0 | 0 | 0.25 |
1,789,183,672,122,757,000 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 1 | 0 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | -3 | 0.276947 | <pre_confidence>1.0</pre_confidence>
<thinking>
Let the geometric sequence be $\{a_n\}$ with the first term $a_1$ and the common ratio $r$.
The formula for the $n$-th term of a geometric sequence is $a_n = a_1 r^{n-1}$.
We are given:
1) $a_3 = -1$
Using the formula: $a_3 = a_1 r^{3-1} = a_1 r^2 = -1$ (Equation 1)
2) ... | 2,427 | true | 1 | -3 | 1 | {
"pre_confidence": true,
"thinking": true,
"answer": true,
"post_confidence": true
} | [] | [
"pre_confidence",
"thinking",
"answer",
"post_confidence"
] | true | 0 | 0 | {
"format": 1,
"accuracy": 1,
"pre": 0.75,
"post": 1,
"total": 3.75
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 1 | 1 | 0.75 | 1 | 3.75 |
1,789,183,672,122,757,000 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 1 | 1 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | -3 | 0.276947 | <pre_confidence>1.0</pre_confidence>
<thinking>
Let the geometric sequence be $\{a_n\}$ with the first term $a_1$ and the common ratio $r$. The formula for the $n$-th term of a geometric sequence is $a_n = a_1 \cdot r^{n-1}$.
We are given:
1. $a_3 = -1$
2. $a_7 = -9$
Using the formula:
1. $a_3 = a_1 \cdot r^{3-1} = a... | 3,297 | false | 1 | null | null | {
"pre_confidence": true,
"thinking": false,
"answer": false,
"post_confidence": false
} | [
"thinking",
"answer",
"post_confidence"
] | [
"pre_confidence",
"thinking"
] | true | 0.75 | 0 | {
"format": 0.25,
"accuracy": 0,
"pre": 0,
"post": 0,
"total": 0.25
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 0.25 | 0 | 0 | 0 | 0.25 |
1,789,183,672,122,757,000 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 1 | 2 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | -3 | 0.276947 | <pre_confidence>1.0</pre_confidence>
<thinking>The problem involves a geometric sequence $\{a_n\}$.
The general form of a geometric sequence is $a_n = a_1 \cdot r^{n-1}$, where $a_1$ is the first term and $r$ is the common ratio.
We are given:
1. $a_3 = -1$
2. $a_7 = -9$
Using the general formula:
1. $a_3 = a_1 \cdot... | 2,341 | true | 1 | -3 | 1 | {
"pre_confidence": true,
"thinking": true,
"answer": true,
"post_confidence": true
} | [] | [
"pre_confidence",
"thinking",
"answer",
"post_confidence"
] | true | 0 | 0 | {
"format": 1,
"accuracy": 1,
"pre": 0.75,
"post": 1,
"total": 3.75
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 1 | 1 | 0.75 | 1 | 3.75 |
1,789,183,672,122,757,000 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 1 | 3 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | -3 | 0.276947 | <pre_confidence>1.0</pre_confidence>
<thinking>Let the geometric sequence be denoted by $\{a_n\}$, with the first term $a_1$ and the common ratio $r$. The formula for the $n$-th term of a geometric sequence is $a_n = a_1 \cdot r^{n-1}$.
We are given:
1. $a_3 = -1$
2. $a_7 = -9$
Using the formula:
1. $a_3 = a_1 \cdot ... | 3,187 | false | 1 | null | null | {
"pre_confidence": true,
"thinking": false,
"answer": false,
"post_confidence": false
} | [
"thinking",
"answer",
"post_confidence"
] | [
"pre_confidence",
"thinking"
] | true | 0.75 | 0 | {
"format": 0.25,
"accuracy": 0,
"pre": 0,
"post": 0,
"total": 0.25
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 0.25 | 0 | 0 | 0 | 0.25 |
1,789,183,672,122,757,000 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 1 | 4 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | -8 | 0.28258 | <pre_confidence>1.0</pre_confidence>
<thinking>The given equation is $\sin \alpha - \cos \alpha = -\frac{\sqrt{5}}{2}$.
We want to find the value of $\tan \alpha + \frac{1}{\tan \alpha}$.
Recall that $\tan \alpha + \frac{1}{\tan \alpha} = \tan \alpha + \cot \alpha = \frac{\sin \alpha}{\cos \alpha} + \frac{\cos \alpha}{... | 1,641 | true | 1 | -8 | 1 | {
"pre_confidence": true,
"thinking": true,
"answer": true,
"post_confidence": true
} | [] | [
"pre_confidence",
"thinking",
"answer",
"post_confidence"
] | true | 0 | 0 | {
"format": 1,
"accuracy": 1,
"pre": 0.9375,
"post": 1,
"total": 3.9375
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 1 | 1 | 0.9375 | 1 | 3.9375 |
1,789,183,672,122,757,000 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 1 | 5 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | -8 | 0.28258 | <pre_confidence>1.0</pre_confidence>
<thinking>The given equation is $\sin \alpha - \cos \alpha = -\frac{\sqrt{5}}{2}$.
We want to find the value of $\tan \alpha + \frac{1}{\tan \alpha}$.
First, let's manipulate the given equation. We can rewrite the left side using the R-formula for $a\sin x + b\cos x$.
$\sin \alpha ... | 2,786 | true | 1 | -8 | 1 | {
"pre_confidence": true,
"thinking": true,
"answer": true,
"post_confidence": true
} | [] | [
"pre_confidence",
"thinking",
"answer",
"post_confidence"
] | true | 0 | 0 | {
"format": 1,
"accuracy": 1,
"pre": 0.9375,
"post": 1,
"total": 3.9375
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 1 | 1 | 0.9375 | 1 | 3.9375 |
1,789,183,672,122,757,000 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 1 | 6 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | -8 | 0.28258 | <pre_confidence>1.0</pre_confidence>
<thinking>The given equation is $\sin \alpha - \cos \alpha = -\frac{\sqrt{5}}{2}$.
We want to find the value of $\tan \alpha + \frac{1}{\tan \alpha}$.
We know that $\tan \alpha + \frac{1}{\tan \alpha} = \frac{\sin \alpha}{\cos \alpha} + \frac{\cos \alpha}{\sin \alpha} = \frac{\sin^2... | 2,224 | true | 1 | -8 | 1 | {
"pre_confidence": true,
"thinking": true,
"answer": true,
"post_confidence": true
} | [] | [
"pre_confidence",
"thinking",
"answer",
"post_confidence"
] | true | 0 | 0 | {
"format": 1,
"accuracy": 1,
"pre": 0.9375,
"post": 1,
"total": 3.9375
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 1 | 1 | 0.9375 | 1 | 3.9375 |
1,789,183,672,122,757,000 | 1ae314a77ffe4ec1a764c48096cefe38 | 0 | 1 | 7 | Solve the math problem below.
Respond with exactly these four fields, once each, in this order, and nothing else:
<pre_confidence>p</pre_confidence>
<thinking>...</thinking>
<answer>...</answer>
<post_confidence>p</post_confidence>
- <pre_confidence>: your probability of solving this problem correctly, a number in [0,... | -8 | 0.28258 | <pre_confidence>1.0</pre_confidence>
<thinking>The given equation is $\sin \alpha - \cos \alpha = -\frac{\sqrt{5}}{2}$.
We want to find the value of $\tan \alpha + \frac{1}{\tan \alpha}$.
We know that $\tan \alpha + \frac{1}{\tan \alpha} = \frac{\sin \alpha}{\cos \alpha} + \frac{\cos \alpha}{\sin \alpha} = \frac{\sin^2... | 3,709 | false | 1 | null | null | {
"pre_confidence": true,
"thinking": false,
"answer": false,
"post_confidence": false
} | [
"thinking",
"answer",
"post_confidence"
] | [
"pre_confidence",
"thinking"
] | true | 0.75 | 0 | {
"format": 0.25,
"accuracy": 0,
"pre": 0,
"post": 0,
"total": 0.25
} | caliber | google/gemma-4-E2B-it | gemma4-e2b-caliber-grpo-newprompt-1500-joint | 0.25 | 0 | 0 | 0 | 0.25 |
End of preview. Expand in Data Studio
CALIBER Extension — Gemma4-E2B GRPO Rollouts
Training rollouts from matched GRPO arms on google/gemma-4-E2B-it
(new-prompt template, non-thinking, full bf16, max completion 1500, 150 steps).
Subsets
| subset | arm | τ | prior | rows | mean reward_total | accuracy | full schema |
|---|---|---|---|---|---|---|---|
caliber |
vanilla CALIBER | 0.0 | — | 1600 | 2.298 | 0.514 | 0.664 |
mink |
Min-K% prior | 1.0 | mink_0.2 | 4800 | 2.506 | 0.520 | 0.680 |
minkpp |
Min-K++% prior | 1.0 | minkpp_0.2 | 4800 | 2.637 | 0.541 | 0.726 |
Load:
from datasets import load_dataset
caliber = load_dataset("dmnsh/caliber-extension-gemma4-e2b-grpo-rollouts", "caliber")
mink = load_dataset("dmnsh/caliber-extension-gemma4-e2b-grpo-rollouts", "mink")
minkpp = load_dataset("dmnsh/caliber-extension-gemma4-e2b-grpo-rollouts", "minkpp")
Fields
Each row is one generation completion with parsed CALIBER fields, format penalties,
and component rewards (format, accuracy, pre, post, total), plus q_m
(memorization prior / target used in the prompt for τ>0 arms).
Notes
- Expected rows for a full 150-step run with batch=8, grad_accum=4, num_generations=4
is 4800. The
calibersubset currently has 1600 rows (likely partial rollout logging during that arm). - Source configs live in the
caliber-extensionbranchfeat/parkiv-gemma4-e2b-grpounderintegrations/parkiv/configs/.
- Downloads last month
- 44