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EN_B00000_S02991_W000004
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.4029, "duration": 5.483, "id": "EN_B00000_S02991_W000004", "language": "en", "speaker": "EN_B00000_S02991", "text": " So calculate the current flowing through each resistor using Kirchhoff's rules.", "wav": "EN_B00000/EN_B00000_S02991/mp3/EN_B00000_S02991_W000004.mp3" }
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[ -0.8987013101577759, -0.22672396898269653, 1.9211511611938477, -1.4871796369552612, 0.7605034708976746, 0.20792561769485474, -0.1941205859184265, -0.3008018732070923, -1.4412271976470947, 2.339266777038574, -1.293412685394287, 0.40878841280937195, -0.6280036568641663, -0.2685675024986267, ...
EN_B00000_S02991_W000005
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.3819, "duration": 19.898, "id": "EN_B00000_S02991_W000005", "language": "en", "speaker": "EN_B00000_S02991", "text": " So let's say that the current that's flown through the first resistor, we're going to call it I1, and the current flown through the second resistor, let's call it I2, and the ...
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[ -0.4672284424304962, -0.45827627182006836, 2.0619254112243652, -2.257753610610962, 0.9054716229438782, 0.2655148506164551, -0.18513613939285278, 0.19730007648468018, -1.2906901836395264, 1.4464147090911865, -1.5687106847763062, 0.38419556617736816, -0.7660748958587646, 0.45189982652664185,...
EN_B00000_S02991_W000006
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.3139, "duration": 19.253, "id": "EN_B00000_S02991_W000006", "language": "en", "speaker": "EN_B00000_S02991", "text": " So notice that we have a current I1 which flows into the junction, and I2 leaves the junction, I3 also leaves it to go this way. Now according to this junction rule, the curre...
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EN_B00000_S02991_W000007
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.2773, "duration": 4.431, "id": "EN_B00000_S02991_W000007", "language": "en", "speaker": "EN_B00000_S02991", "text": " leaves the junction. So the only current that's entering the junction is I1.", "wav": "EN_B00000/EN_B00000_S02991/mp3/EN_B00000_S02991_W000007.mp3" }
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EN_B00000_S02991_W000008
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.3828, "duration": 12.275, "id": "EN_B00000_S02991_W000008", "language": "en", "speaker": "EN_B00000_S02991", "text": " The other two currents are leaving the junction, so I1 has to equal the sum of I2 plus I3. So that's one equation that we have so far. We're going to use it later.", "wav": ...
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EN_B00000_S02991_W000009
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.3579, "duration": 4.278, "id": "EN_B00000_S02991_W000009", "language": "en", "speaker": "EN_B00000_S02991", "text": " Now the next thing that we need to talk about is Kirchhoff's voltage law.", "wav": "EN_B00000/EN_B00000_S02991/mp3/EN_B00000_S02991_W000009.mp3" }
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EN_B00000_S02991_W000010
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.1291, "duration": 3.124, "id": "EN_B00000_S02991_W000010", "language": "en", "speaker": "EN_B00000_S02991", "text": " Which is important when using the loop rule.", "wav": "EN_B00000/EN_B00000_S02991/mp3/EN_B00000_S02991_W000010.mp3" }
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EN_B00000_S02991_W000011
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.4029, "duration": 10.526, "id": "EN_B00000_S02991_W000011", "language": "en", "speaker": "EN_B00000_S02991", "text": " So that law states that the sum of all the voltages around a loop or around a closed circle must add to zero. Now, when going around a loop, you need to determine", "wav": "...
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EN_B00000_S02991_W000012
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.304, "duration": 24.55, "id": "EN_B00000_S02991_W000012", "language": "en", "speaker": "EN_B00000_S02991", "text": " Which elements will create a positive voltage contribution to the circuit, and which one will create a voltage drop, or a negative contribution to the voltage of the circuit. So...
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EN_B00000_S02991_W000013
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.3135, "duration": 8.506, "id": "EN_B00000_S02991_W000013", "language": "en", "speaker": "EN_B00000_S02991", "text": " To let's say a high potential, if you're traveling in that direction, then the voltage is increasing, so there should be a voltage lift.", "wav": "EN_B00000/EN_B00000_S02991/...
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EN_B00000_S02991_W000014
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.1952, "duration": 3.243, "id": "EN_B00000_S02991_W000014", "language": "en", "speaker": "EN_B00000_S02991", "text": " Now here's a question for you. Let's say the current is flowing in this direction.", "wav": "EN_B00000/EN_B00000_S02991/mp3/EN_B00000_S02991_W000014.mp3" }
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EN_B00000_S02991_W000015
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.403, "duration": 5.093, "id": "EN_B00000_S02991_W000015", "language": "en", "speaker": "EN_B00000_S02991", "text": " Will this be associated with a positive voltage or a negative voltage?", "wav": "EN_B00000/EN_B00000_S02991/mp3/EN_B00000_S02991_W000015.mp3" }
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EN_B00000_S02991_W000016
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.4362, "duration": 4.906, "id": "EN_B00000_S02991_W000016", "language": "en", "speaker": "EN_B00000_S02991", "text": " Now keep in mind, current flows from high potential to low potential.", "wav": "EN_B00000/EN_B00000_S02991/mp3/EN_B00000_S02991_W000016.mp3" }
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EN_B00000_S02991_W000017
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.3308, "duration": 7.419, "id": "EN_B00000_S02991_W000017", "language": "en", "speaker": "EN_B00000_S02991", "text": " So we're going in this direction. We're going from a positive to negative. So therefore, this will be associated with a voltage drop.", "wav": "EN_B00000/EN_B00000_S02991/mp3...
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EN_B00000_S02991_W000018
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.3885, "duration": 8.7, "id": "EN_B00000_S02991_W000018", "language": "en", "speaker": "EN_B00000_S02991", "text": " So when using the loop rule, if you're going in a direction of the current, that's associated with a voltage drop. Now, if you're going opposite to the direction of the current,"...
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EN_B00000_S02991_W000019
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.2522, "duration": 18.625, "id": "EN_B00000_S02991_W000019", "language": "en", "speaker": "EN_B00000_S02991", "text": " Then you're traveling from a low potential to a high potential, which is what we have in this situation. So that's going to be associated with an increase in voltage or voltag...
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EN_B00000_S02991_W000020
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.3321, "duration": 5.62, "id": "EN_B00000_S02991_W000020", "language": "en", "speaker": "EN_B00000_S02991", "text": " So if you're traveling towards a negative sign, you should be associated with a voltage drop. If you're traveling towards", "wav": "EN_B00000/EN_B00000_S02991/mp3/EN_B00000_S0...
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EN_B00000_S02991_W000021
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.3579, "duration": 8.608, "id": "EN_B00000_S02991_W000021", "language": "en", "speaker": "EN_B00000_S02991", "text": " Let's say a positive sign. We're going in that direction. That should be associated with a positive voltage or voltage lift.", "wav": "EN_B00000/EN_B00000_S02991/mp3/EN_B0000...
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EN_B00000_S02991_W000022
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.3506, "duration": 3.532, "id": "EN_B00000_S02991_W000022", "language": "en", "speaker": "EN_B00000_S02991", "text": " So now let's say if you have a resistor,", "wav": "EN_B00000/EN_B00000_S02991/mp3/EN_B00000_S02991_W000022.mp3" }
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EN_B00000_S02991_W000023
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{ "dnsmos": 3.2633, "duration": 6.74, "id": "EN_B00000_S02991_W000023", "language": "en", "speaker": "EN_B00000_S02991", "text": " And this part is positive and this part is negative. So if you're traveling in this direction using the loop rule.", "wav": "EN_B00000/EN_B00000_S02991/mp3/EN_B00000_S02991_W0...
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EN_B00000_S02991_W000024
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{ "dnsmos": 3.3064, "duration": 7.029, "id": "EN_B00000_S02991_W000024", "language": "en", "speaker": "EN_B00000_S02991", "text": " Should you apply a positive voltage contribution or negative voltage in the voltage law equation?", "wav": "EN_B00000/EN_B00000_S02991/mp3/EN_B00000_S02991_W000024.mp3" }
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EN_B00000_S02991_W000025
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{ "dnsmos": 3.3239, "duration": 11.341, "id": "EN_B00000_S02991_W000025", "language": "en", "speaker": "EN_B00000_S02991", "text": " Now we know that current flows from high potential to low potential. So notice that we're going against the current and we're traveling towards the positive side. So this is g...
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EN_B00000_S02991_W000026
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.3002, "duration": 4.482, "id": "EN_B00000_S02991_W000026", "language": "en", "speaker": "EN_B00000_S02991", "text": " Now let's say if we have a resistor and the current is flowing in this direction.", "wav": "EN_B00000/EN_B00000_S02991/mp3/EN_B00000_S02991_W000026.mp3" }
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EN_B00000_S02991_W000027
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.3497, "duration": 6.57, "id": "EN_B00000_S02991_W000027", "language": "en", "speaker": "EN_B00000_S02991", "text": " And using the loop rule, we're traveling in this direction. Will this be associated with a voltage drop or a voltage lift?", "wav": "EN_B00000/EN_B00000_S02991/mp3/EN_B00000_S...
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EN_B00000_S02991_W000028
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{ "dnsmos": 3.3294, "duration": 3.684, "id": "EN_B00000_S02991_W000028", "language": "en", "speaker": "EN_B00000_S02991", "text": " Now we know that current flows from positive to negative.", "wav": "EN_B00000/EN_B00000_S02991/mp3/EN_B00000_S02991_W000028.mp3" }
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EN_B00000_S02991_W000029
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.3384, "duration": 4.975, "id": "EN_B00000_S02991_W000029", "language": "en", "speaker": "EN_B00000_S02991", "text": " So we're traveling towards a low potential. So this will be associated with a voltage drop.", "wav": "EN_B00000/EN_B00000_S02991/mp3/EN_B00000_S02991_W000029.mp3" }
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EN_B00000_S02991_W000030
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.3633, "duration": 8.88, "id": "EN_B00000_S02991_W000030", "language": "en", "speaker": "EN_B00000_S02991", "text": " Now let's focus on a battery. So let's say this is positive and this is negative. And I'm going to draw another battery in this direction.", "wav": "EN_B00000/EN_B00000_S02991...
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EN_B00000_S02991_W000031
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.3007, "duration": 3.65, "id": "EN_B00000_S02991_W000031", "language": "en", "speaker": "EN_B00000_S02991", "text": " So let's say if we're using the loop rule and we're going in this direction.", "wav": "EN_B00000/EN_B00000_S02991/mp3/EN_B00000_S02991_W000031.mp3" }
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EN_B00000_S02991_W000032
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.2823, "duration": 7.86, "id": "EN_B00000_S02991_W000032", "language": "en", "speaker": "EN_B00000_S02991", "text": " Should we apply a positive voltage or a negative voltage in the voltage law equation? Is this a voltage lift or a voltage drop?", "wav": "EN_B00000/EN_B00000_S02991/mp3/EN_B00...
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EN_B00000_S02991_W000033
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.3072, "duration": 5.009, "id": "EN_B00000_S02991_W000033", "language": "en", "speaker": "EN_B00000_S02991", "text": " Now we're going towards the positive sign. So this is going to be associated with a voltage lift.", "wav": "EN_B00000/EN_B00000_S02991/mp3/EN_B00000_S02991_W000033.mp3" }
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EN_B00000_S02991_W000034
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.2845, "duration": 3.922, "id": "EN_B00000_S02991_W000034", "language": "en", "speaker": "EN_B00000_S02991", "text": " Now what if we're going in this direction using the loop rule?", "wav": "EN_B00000/EN_B00000_S02991/mp3/EN_B00000_S02991_W000034.mp3" }
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EN_B00000_S02991_W000035
/proj/MR_dataset/mtk53678/downloads/00e15b7f13b78e2cd1bd81f798aac965245694df3ac74f926a3805752920ddee
{ "dnsmos": 3.394, "duration": 11.018, "id": "EN_B00000_S02991_W000035", "language": "en", "speaker": "EN_B00000_S02991", "text": " So notice that we're going towards the negative sign and so that should be associated with a voltage drop. So hopefully that makes sense and understanding this will be very use...
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