thinking stringlengths 42 849 | answer stringlengths 3 23 | content stringlengths 46 872 |
|---|---|---|
<think>Explanation :
Let the height of the building be h. Initially, he was at an angle of 450. tan 45 = h/distance between car and tower. h = distance between car and tower (since tan 45 = 1).
Now, after 10 minutes, it travelled a certain distance, and angle changed to 600.
tan 60 = h/x x = h/√3
So, in 10 minutes, it ... | A)5(√3 + 1) | <think>Explanation :
Let the height of the building be h. Initially, he was at an angle of 450. tan 45 = h/distance between car and tower. h = distance between car and tower (since tan 45 = 1).
Now, after 10 minutes, it travelled a certain distance, and angle changed to 600.
tan 60 = h/x x = h/√3
So, in 10 minutes, it ... |
<think>Let x be the original price of the item
Discounted price = 0.78x
Payment made by the customer after using the $20 coupon = 0.78x - 20
0.78x - 20 = x/2 + 1.9
x = 78.20
Answer: E</think>
| E)$78.20 | <think>Let x be the original price of the item
Discounted price = 0.78x
Payment made by the customer after using the $20 coupon = 0.78x - 20
0.78x - 20 = x/2 + 1.9
x = 78.20
Answer: E</think>
E)$78.20 |
<think>9=3*3
12=3*4
The number should definitely have these factors 3*3*4
36 is the number that has these factors
So, 36 is the multiple of X
Answer is A</think>
| A)36 | <think>9=3*3
12=3*4
The number should definitely have these factors 3*3*4
36 is the number that has these factors
So, 36 is the multiple of X
Answer is A</think>
A)36 |
<think>The probability that stock A does not increase is 0.44, and the probability that stock B does not increase is 0.26. Now, how can the probability that both do not increase be more than individual probability of not increasing for each? So the probability that both do not increase can not be more than 0.26. Basica... | B)0.26 | <think>The probability that stock A does not increase is 0.44, and the probability that stock B does not increase is 0.26. Now, how can the probability that both do not increase be more than individual probability of not increasing for each? So the probability that both do not increase can not be more than 0.26. Basica... |
<think>Cost Price = Selling Price / (100+Profit%) × 100 => 360 / (100+20) × 100 => 360 / 120 × 100 = Rs.300
Option B</think>
| B)300 | <think>Cost Price = Selling Price / (100+Profit%) × 100 => 360 / (100+20) × 100 => 360 / 120 × 100 = Rs.300
Option B</think>
B)300 |
<think>We know that there are 20 black marbles in the bag and this number represent 1/20 th of the number of all marbles in the bag, thus there are total Q of 20*20=400 marbles.
Answer: D.</think>
| D)400 | <think>We know that there are 20 black marbles in the bag and this number represent 1/20 th of the number of all marbles in the bag, thus there are total Q of 20*20=400 marbles.
Answer: D.</think>
D)400 |
<think>Out of 26 alphabets two distinct letters can be chosen in 26P2 ways. Coming to the numbers part, there are 10 ways to choose the first digit and similarly, there are another 10 ways to choose the second digit. Hence, there are in total 10X10 = 100 ways.
Combined with letters there are 6P2 X 100 ways = 65000 ways... | D)65000 | <think>Out of 26 alphabets two distinct letters can be chosen in 26P2 ways. Coming to the numbers part, there are 10 ways to choose the first digit and similarly, there are another 10 ways to choose the second digit. Hence, there are in total 10X10 = 100 ways.
Combined with letters there are 6P2 X 100 ways = 65000 ways... |
<think>Distance to destination = 100 X 10 = 1000 miles.
Distance remaining when it starts to rain = 1000 - 250 = 750 miles.
Speed for remaining distance = 75 miles / hour.
Time taken to cover remaining distance = 750 / 75 = 10 hours.
Total duration of the journey = 2.5 + 10 = 12.5 hours.
The correct option is C.</think... | C)12.5 | <think>Distance to destination = 100 X 10 = 1000 miles.
Distance remaining when it starts to rain = 1000 - 250 = 750 miles.
Speed for remaining distance = 75 miles / hour.
Time taken to cover remaining distance = 750 / 75 = 10 hours.
Total duration of the journey = 2.5 + 10 = 12.5 hours.
The correct option is C.</think... |
<think>To maximize the number of students who did neither, we should minimize the number of students who debated or attended the prom.
Let's assume that all 35% of students who debated also attended the prom.
Then 35% did both, 10% only attended prom, and 55% did neither.
0.55*200 = 110
The answer is E.</think>
| E)110 | <think>To maximize the number of students who did neither, we should minimize the number of students who debated or attended the prom.
Let's assume that all 35% of students who debated also attended the prom.
Then 35% did both, 10% only attended prom, and 55% did neither.
0.55*200 = 110
The answer is E.</think>
E)11... |
<think>10% of 250 = 25.
Total salary required = 1000
Earning from single sale = 25
# of sales = 1000/25 =40
So 40 sales
D is the correct choice</think>
| D)40 | <think>10% of 250 = 25.
Total salary required = 1000
Earning from single sale = 25
# of sales = 1000/25 =40
So 40 sales
D is the correct choice</think>
D)40 |
<think>450*12(x-110)=626400
where x is a selling cost of one item
x-110, is a profit from one item
450 - number of items produced and sold per month
12 - is a number of month in a year
Simplifying the equation will lead to x-110=116, then x = 230
B</think>
| B)230 | <think>450*12(x-110)=626400
where x is a selling cost of one item
x-110, is a profit from one item
450 - number of items produced and sold per month
12 - is a number of month in a year
Simplifying the equation will lead to x-110=116, then x = 230
B</think>
B)230 |
<think>We're told that 10% of staplers in a factory are defective.
X = Total staplers
0.1X = defective staplers
0.9X = normal staplers
Next, we're told that 2% of the normal staplers were rejected by mistake and that this = 72 staplers.
0.9X(0.02) = 72
0.018X = 72
18X = 72,000
X = 4,000
Final Answer:
A</think>
| A)4,000 | <think>We're told that 10% of staplers in a factory are defective.
X = Total staplers
0.1X = defective staplers
0.9X = normal staplers
Next, we're told that 2% of the normal staplers were rejected by mistake and that this = 72 staplers.
0.9X(0.02) = 72
0.018X = 72
18X = 72,000
X = 4,000
Final Answer:
A</think>
A)4,0... |
<think>A's speed = 3 yo-yos every 18 minutes
B's speed = 2 yo-yos every 18 minutes
A + B's speed = 3 + 2 = 5 yo-yos every 18 minutes
both together will finish 10 yo-yos in 36 minutes
correct option is C</think>
| C)36 minutes | <think>A's speed = 3 yo-yos every 18 minutes
B's speed = 2 yo-yos every 18 minutes
A + B's speed = 3 + 2 = 5 yo-yos every 18 minutes
both together will finish 10 yo-yos in 36 minutes
correct option is C</think>
C)36 minutes |
<think>45 - 30 = 15
ANSWER : D</think>
| D)15 | <think>45 - 30 = 15
ANSWER : D</think>
D)15 |
<think>There are seven positions to be filled.
The first position can be filled using any of the 7 letters contained in PROBLEM.
The second position can be filled by the remaining 6 letters as the letters should not repeat.
The third position can be filled by the remaining 5 letters only and so on.
758
Therefore, the t... | C)7! | <think>There are seven positions to be filled.
The first position can be filled using any of the 7 letters contained in PROBLEM.
The second position can be filled by the remaining 6 letters as the letters should not repeat.
The third position can be filled by the remaining 5 letters only and so on.
758
Therefore, the t... |
<think>P(A/B) = P (A n B)/P(B)
Here, P (A n B) = 0.16
P(A/B) = 0.16/0.8 = 0.2
A</think>
| A)0.2 | <think>P(A/B) = P (A n B)/P(B)
Here, P (A n B) = 0.16
P(A/B) = 0.16/0.8 = 0.2
A</think>
A)0.2 |
<think>Let total number of steps in the elevator be n and let the speed be e
Elevator covered n-20 steps in 10 mins
(n-20)/e=10.................1
Elevator covered n-10 steps in 20 mins
(n-10)/e=20......................2
From (1) and (2)
n=30
e=1 step/min
Hence (A) is correct answer.</think>
| A)1 step/minute | <think>Let total number of steps in the elevator be n and let the speed be e
Elevator covered n-20 steps in 10 mins
(n-20)/e=10.................1
Elevator covered n-10 steps in 20 mins
(n-10)/e=20......................2
From (1) and (2)
n=30
e=1 step/min
Hence (A) is correct answer.</think>
A)1 step/minute |
<think>42×12+20×10 /12+10=504+200/22=704/22=32
Answer D</think>
| D)32 | <think>42×12+20×10 /12+10=504+200/22=704/22=32
Answer D</think>
D)32 |
<think>Highest: H
Lowest: L
Number of students in the class: Z
Number of students in the class excluding the highest and lowest : Z-2
Average of Highest and Lowest: (H + L)/2=X => H+L=2X
Average of Entire Class : (H+L+Others)/Z=Y => Others= ZY-2X
Average of the others in the class: (ZY-2X)/(Z-2)
Answer: D</think>
| D)(zy – 2x)/(z -2) | <think>Highest: H
Lowest: L
Number of students in the class: Z
Number of students in the class excluding the highest and lowest : Z-2
Average of Highest and Lowest: (H + L)/2=X => H+L=2X
Average of Entire Class : (H+L+Others)/Z=Y => Others= ZY-2X
Average of the others in the class: (ZY-2X)/(Z-2)
Answer: D</think>
D)... |
<think>(? × 19 - 17)/(169 - 156) = 6
=> ? × 19 - 17 = 13 × 6 = 76
=> ? × 19 = 78 + 17 = 95
? = 95/19 = 5
Answer: Option C</think>
| C)5 | <think>(? × 19 - 17)/(169 - 156) = 6
=> ? × 19 - 17 = 13 × 6 = 76
=> ? × 19 = 78 + 17 = 95
? = 95/19 = 5
Answer: Option C</think>
C)5 |
<think>Profit on one bag: 100*1.25= 125
Number of bags sold = 3000/125 = 24
Answer is C.</think>
| C)24 | <think>Profit on one bag: 100*1.25= 125
Number of bags sold = 3000/125 = 24
Answer is C.</think>
C)24 |
<think>Lets say Alex has worked for x hrs., and Jacob has worked for y hrs. So, number of toys prepared by Alex is x/7, and Jacob is y/9. Since total number of toys prepared by both of them is 35.
=> x/7 + y/9 = 35.
=> 9x + 7y = (35)(63)
=> 7y = (35)(63) - 9x
=> y = (5)(63) - (9/7)x
=> y = 315 - (9/7)x
=> x is to be a ... | A)15 | <think>Lets say Alex has worked for x hrs., and Jacob has worked for y hrs. So, number of toys prepared by Alex is x/7, and Jacob is y/9. Since total number of toys prepared by both of them is 35.
=> x/7 + y/9 = 35.
=> 9x + 7y = (35)(63)
=> 7y = (35)(63) - 9x
=> y = (5)(63) - (9/7)x
=> y = 315 - (9/7)x
=> x is to be a ... |
<think>Imagine starting out with 100 ml of 50% milk tea.
In step 1, 15% of the tea is replaced with milk. Thus, 85% of the original tea remains. Since this is done twice, we have a concentration of 50x0.85x0.85% (=36.125%) of tea solution.
Finally, 10% of this solution is replaced with milk again. So, the final concent... | E)32.51% | <think>Imagine starting out with 100 ml of 50% milk tea.
In step 1, 15% of the tea is replaced with milk. Thus, 85% of the original tea remains. Since this is done twice, we have a concentration of 50x0.85x0.85% (=36.125%) of tea solution.
Finally, 10% of this solution is replaced with milk again. So, the final concent... |
<think>LCM of 16,10,8 = 80
the largest 4 digit number divisible by 80 = 9920
The smallest 4 digit number divisible by 80 = 1040
So, required difference = 9920-1040= 8880
ANSWER:A</think>
| A)8880 | <think>LCM of 16,10,8 = 80
the largest 4 digit number divisible by 80 = 9920
The smallest 4 digit number divisible by 80 = 1040
So, required difference = 9920-1040= 8880
ANSWER:A</think>
A)8880 |
<think>15 mph - 4 mph= 11 mph
11 mph x (21/60)= 3.85 miles
Answer D</think>
| D)3.85 miles | <think>15 mph - 4 mph= 11 mph
11 mph x (21/60)= 3.85 miles
Answer D</think>
D)3.85 miles |
<think>Let the cost be A. Then the selling price is A+0.4*A.
So the profit is 0.4 * A.
0.4*A=20 ---> A=50.
So the selling price is 50+20=70.
The answer is (D).</think>
| D)$70.00 | <think>Let the cost be A. Then the selling price is A+0.4*A.
So the profit is 0.4 * A.
0.4*A=20 ---> A=50.
So the selling price is 50+20=70.
The answer is (D).</think>
D)$70.00 |
<think>We need to calculate the total amount to be paid by him after 4 years, so it will be Principal + simple interest.
So,
=>500+500∗6∗4 /100=>Rs.620
Option C</think>
| C)620 | <think>We need to calculate the total amount to be paid by him after 4 years, so it will be Principal + simple interest.
So,
=>500+500∗6∗4 /100=>Rs.620
Option C</think>
C)620 |
<think>99 is generated
We don't know what the square root of 99 is because we would need a calculator, but we know the square root of 100 is 10, so the square root of 99 has to be less than 10.
ANSWER:A</think>
| A)(99,10) | <think>99 is generated
We don't know what the square root of 99 is because we would need a calculator, but we know the square root of 100 is 10, so the square root of 99 has to be less than 10.
ANSWER:A</think>
A)(99,10) |
<think>Let 'x' be the distance and 'y' be the speed of the forward journey. Then, we have 6v=d and 4(v+12)=d
=> v=d/6 and v=d/4 - 12
=> d/6 = d/4 - 12
=> d/12 = 12
=> d=144
Answer: B</think>
| B)144km | <think>Let 'x' be the distance and 'y' be the speed of the forward journey. Then, we have 6v=d and 4(v+12)=d
=> v=d/6 and v=d/4 - 12
=> d/6 = d/4 - 12
=> d/12 = 12
=> d=144
Answer: B</think>
B)144km |
<think>Half of 2 is 1. =>2+58=60-> 1+58=59
Answer A</think>
| A)A)59 | <think>Half of 2 is 1. =>2+58=60-> 1+58=59
Answer A</think>
A)A)59 |
<think>wholesale cost = 100;
original price = 100*1.6 = 160;
actual price = 160*0.8 = 128.
Answer: B.</think>
| B)28% | <think>wholesale cost = 100;
original price = 100*1.6 = 160;
actual price = 160*0.8 = 128.
Answer: B.</think>
B)28% |
<think>Here we are given a ratio: 1/4 inch on the map = 10 miles, so 1 inch on the map = 40 miles. If the map-distance between the towns is 20 inches, then the actual distance must be 20 x 40 = 800
Answer: A.</think>
| A)800 | <think>Here we are given a ratio: 1/4 inch on the map = 10 miles, so 1 inch on the map = 40 miles. If the map-distance between the towns is 20 inches, then the actual distance must be 20 x 40 = 800
Answer: A.</think>
A)800 |
<think>Let the sheet be folded along its breadth and its perimeter = 48cm
Therefore, (l/2 + b) = 48 ... (i)
Now, let the sheet be folded along its length, and the perimeter = 66cm
(l + b/2)= 66 …... (ii)
Solving (i) and (ii), we get,
l = 56cm, b = 20cm
Area = l*b
Area = 1120 cm2
ANSWER IS B</think>
| B)1120 | <think>Let the sheet be folded along its breadth and its perimeter = 48cm
Therefore, (l/2 + b) = 48 ... (i)
Now, let the sheet be folded along its length, and the perimeter = 66cm
(l + b/2)= 66 …... (ii)
Solving (i) and (ii), we get,
l = 56cm, b = 20cm
Area = l*b
Area = 1120 cm2
ANSWER IS B</think>
B)1120 |
<think>The bus from M to N can be selected in 3 ways. The bus from N to O can be selected in 4 ways. The bus from O to P can be selected in 1 way. The bus from P to Q can be selected in 3 ways. So, by the General Counting Principle, one can travel from M to Q in 3*4*1*3= 36 ways
Answer B</think>
| B)36 | <think>The bus from M to N can be selected in 3 ways. The bus from N to O can be selected in 4 ways. The bus from O to P can be selected in 1 way. The bus from P to Q can be selected in 3 ways. So, by the General Counting Principle, one can travel from M to Q in 3*4*1*3= 36 ways
Answer B</think>
B)36 |
<think>In an inscribed rectangle in a sphere, we will have a line joining the opposite vertices as the diameter.
According to the Pythagoras theorem, sides 3, 4 give diagonal as 5 ==> with 5 and 15, we get 5sqrt(10).
5sqrt(10) or 15.8113 is the diameter of the sphere.
answer = B</think>
| B) 15.8113 | <think>In an inscribed rectangle in a sphere, we will have a line joining the opposite vertices as the diameter.
According to the Pythagoras theorem, sides 3, 4 give diagonal as 5 ==> with 5 and 15, we get 5sqrt(10).
5sqrt(10) or 15.8113 is the diameter of the sphere.
answer = B</think>
B) 15.8113 |
<think>3s,5e,3n,2w
5-2=3e
3-3=0
3km
ANSWER:A</think>
| A)3km | <think>3s,5e,3n,2w
5-2=3e
3-3=0
3km
ANSWER:A</think>
A)3km |
<think>If he increases the discount by 2%, then his profit is 15 less. Let the marked price be X.
.02x = 15
x = 750 marked price
ANSWER:D</think>
| D)Rs. 750 | <think>If he increases the discount by 2%, then his profit is 15 less. Let the marked price be X.
.02x = 15
x = 750 marked price
ANSWER:D</think>
D)Rs. 750 |
<think>According to the question,
=> [7/8 - 7/18 ]x = 770
=> 7*10*x /18*8 = 770
=> x = 11*18*8
=> 1584.
Answer : A</think>
| A)1584 | <think>According to the question,
=> [7/8 - 7/18 ]x = 770
=> 7*10*x /18*8 = 770
=> x = 11*18*8
=> 1584.
Answer : A</think>
A)1584 |
<think>Let S be the total monthly salary and x be the monthly sales, hence
S = 500 + 5% * x
Find sales x so that S = 1500, hence
1500 = 500 + 5% * x = 500 + 0.05 x
Solve for x
x = (1500 - 500) / 0.05 = $20000
Answer D</think>
| D)$20000 | <think>Let S be the total monthly salary and x be the monthly sales, hence
S = 500 + 5% * x
Find sales x so that S = 1500, hence
1500 = 500 + 5% * x = 500 + 0.05 x
Solve for x
x = (1500 - 500) / 0.05 = $20000
Answer D</think>
D)$20000 |
<think>Let the each side of the square is x km
average speed of plane is y km/hr
(x/200)+(x/400)+(x/600)+(x/800) = 4x/y
25x/2400 = 4x/y
y= 384 km/hr
Answer is A</think>
| A)384 | <think>Let the each side of the square is x km
average speed of plane is y km/hr
(x/200)+(x/400)+(x/600)+(x/800) = 4x/y
25x/2400 = 4x/y
y= 384 km/hr
Answer is A</think>
A)384 |
<think>Total cost=100
number of sharp=18
cost of white=cost of brown+1
100/18=5.5...-(1)
also 100%18=10...-(2)
as cost of white is 1 more than that of brown
from 1 int. value will be 5
now remainder is 10 so 10 sharp. will be of cost (5+1)
=> 10*(5+1)+8*5
=>10*6+8*5
=60+40
100
white=10
brown=8
ANSWER:A</think>
| A)10,8 | <think>Total cost=100
number of sharp=18
cost of white=cost of brown+1
100/18=5.5...-(1)
also 100%18=10...-(2)
as cost of white is 1 more than that of brown
from 1 int. value will be 5
now remainder is 10 so 10 sharp. will be of cost (5+1)
=> 10*(5+1)+8*5
=>10*6+8*5
=60+40
100
white=10
brown=8
ANSWER:A</think>
A)10,... |
<think>Since hose A can fill the pool in 8 hours, then in 2 + 3 = 5 hours it will fill 5/8th of the pool. Thus the remaining 3/8th is filled by hose B in 3 hours. This means that hose B,working alone, to fill the entire pool will need 3*8/3 = 8 hours.
Answer: A.</think>
| A)8 | <think>Since hose A can fill the pool in 8 hours, then in 2 + 3 = 5 hours it will fill 5/8th of the pool. Thus the remaining 3/8th is filled by hose B in 3 hours. This means that hose B,working alone, to fill the entire pool will need 3*8/3 = 8 hours.
Answer: A.</think>
A)8 |
<think>reduction = 120 – 96 = 24
∴ Reduction percent = (24/120)×100% =20%
Answer:C</think>
| C)20% | <think>reduction = 120 – 96 = 24
∴ Reduction percent = (24/120)×100% =20%
Answer:C</think>
C)20% |
<think>Let the number be x
10x +1 = 3(100,000 + x)
=> x = 42857.</think>
| A)42857 | <think>Let the number be x
10x +1 = 3(100,000 + x)
=> x = 42857.</think>
A)42857 |
<think>Assume there are total of 100 students. 24 students are members of both clubs. We are told that:20% of members of the swim team are not members of the chess club, thus if S is a # of members of the swim team then 0.2S is # of members of only the swim teem:
24+0.2S=S --> S=30.
Answer: B.</think>
| B)30% | <think>Assume there are total of 100 students. 24 students are members of both clubs. We are told that:20% of members of the swim team are not members of the chess club, thus if S is a # of members of the swim team then 0.2S is # of members of only the swim teem:
24+0.2S=S --> S=30.
Answer: B.</think>
B)30% |
<think>The % change in population of city in two years time is 1.05*1.05 = 1.1025 = 10.25%
Therefore, after 2 years the population of the city will be 1.1025 * 78000 = 85995
ANSWER B</think>
| B)85995 | <think>The % change in population of city in two years time is 1.05*1.05 = 1.1025 = 10.25%
Therefore, after 2 years the population of the city will be 1.1025 * 78000 = 85995
ANSWER B</think>
B)85995 |
<think>Time they will meet = total distance/ relative speed= 50/12+13 = 50/25 = 2
Answer is E</think>
| E) 2 | <think>Time they will meet = total distance/ relative speed= 50/12+13 = 50/25 = 2
Answer is E</think>
E) 2 |
<think>Servant’s commission amount
= 6000 – 1500 = 4500
i.e.,15% = 4500
or,100% = 4500⁄15 × 100 = 30000
Answer A</think>
| A)30000 | <think>Servant’s commission amount
= 6000 – 1500 = 4500
i.e.,15% = 4500
or,100% = 4500⁄15 × 100 = 30000
Answer A</think>
A)30000 |
<think>Instead of paying monthly 360/12 = 30Rs, the man pays 31.50Rs. Therefore, the interest rate is 1.5/30 = 0.5/10 = 5/100 = 5%.
Answer D</think>
| D)5% | <think>Instead of paying monthly 360/12 = 30Rs, the man pays 31.50Rs. Therefore, the interest rate is 1.5/30 = 0.5/10 = 5/100 = 5%.
Answer D</think>
D)5% |
<think>If initial price is Rs 100 and reduced price is Rs 70.
Then, to make it 100 again, price should increase by 100*30/70= 300/7 % or 42.86% approx
ANSWER:B</think>
| B)42.86% | <think>If initial price is Rs 100 and reduced price is Rs 70.
Then, to make it 100 again, price should increase by 100*30/70= 300/7 % or 42.86% approx
ANSWER:B</think>
B)42.86% |
<think>25 paise + 50 paise + 100 paise = 175 paise and Rs. 700 = 70,000 paise
70,000/175 = 400</think>
| C)400 | <think>25 paise + 50 paise + 100 paise = 175 paise and Rs. 700 = 70,000 paise
70,000/175 = 400</think>
C)400 |
<think>87 1/2% of P = 3500
⇒ {(175/2) x P} / 100 = 3500
∵ P = (3500 x 2 x 100) / 175 = 4000
Correct Option: C</think>
| C)Rs. 4000 | <think>87 1/2% of P = 3500
⇒ {(175/2) x P} / 100 = 3500
∵ P = (3500 x 2 x 100) / 175 = 4000
Correct Option: C</think>
C)Rs. 4000 |
<think>Five dozen = 5 x 12 = 60
⇒ No of toys can be kept in 1 box = 60
∴ No of toys can be kept in 98 boxes = 60 x 98 = 5880
∴ 29400 toys can be lifted by = 29400 / 5880 = 5 tempos
Option: B</think>
| B)5 | <think>Five dozen = 5 x 12 = 60
⇒ No of toys can be kept in 1 box = 60
∴ No of toys can be kept in 98 boxes = 60 x 98 = 5880
∴ 29400 toys can be lifted by = 29400 / 5880 = 5 tempos
Option: B</think>
B)5 |
<think>Required number of ways = 10C2 = 10*9/2 = 45
Answer is A</think>
| A)45 | <think>Required number of ways = 10C2 = 10*9/2 = 45
Answer is A</think>
A)45 |
<think>let x is amount of work to be done to paint one house.
So Brown's one day work is x/6, black's can do x/8 work in
one day and blue is x/12.
Total houses is 3, so tatal work to be done is 3x.
3x= 8*(x/6) + 6*(x/8) + y*(x/12)
finally y = 11.
blue will complete the remaining work in 11 days.
ANSWER:D</think>
| D)11 | <think>let x is amount of work to be done to paint one house.
So Brown's one day work is x/6, black's can do x/8 work in
one day and blue is x/12.
Total houses is 3, so tatal work to be done is 3x.
3x= 8*(x/6) + 6*(x/8) + y*(x/12)
finally y = 11.
blue will complete the remaining work in 11 days.
ANSWER:D</think>
D)1... |
<think>We have to find the LCM:
17 is a prime number which means the LCM of 16 and 17 has to be 16*17=272
Correct answer is A.</think>
| A)272 minutes | <think>We have to find the LCM:
17 is a prime number which means the LCM of 16 and 17 has to be 16*17=272
Correct answer is A.</think>
A)272 minutes |
<think>Volume of Big Cube considering it is not hollow = L3 = 5*5*5 = 125 cm3
Size of hollow cube (considering 1 cm thickness on two faces of large cube = 5 - 2 = 3cm
Volume of hollow cube = 3*3*3 = 27 cm3
So Total Volume filled up by smaller cubes = Volume of Larger Cube - Volume of hollow cube
= 125 - 27
= 98 cm3
Vol... | A)438 | <think>Volume of Big Cube considering it is not hollow = L3 = 5*5*5 = 125 cm3
Size of hollow cube (considering 1 cm thickness on two faces of large cube = 5 - 2 = 3cm
Volume of hollow cube = 3*3*3 = 27 cm3
So Total Volume filled up by smaller cubes = Volume of Larger Cube - Volume of hollow cube
= 125 - 27
= 98 cm3
Vol... |
<think>If 10% of chocolates are cocoa flavored, then 90% are vanilla flavored.
90% of 90% are squashed, i.e. 81% are squashed.
Vanilla flavored and non squashed= 90-81= 9%
D is the answer</think>
| D)9% | <think>If 10% of chocolates are cocoa flavored, then 90% are vanilla flavored.
90% of 90% are squashed, i.e. 81% are squashed.
Vanilla flavored and non squashed= 90-81= 9%
D is the answer</think>
D)9% |
<think>frog jumps 3 m up day & falls back 2 m down at night
so,frog will be 3-2=1 m up in a day.
Thus, in 27 days it will be 27 m up
on 28 th day it will be at top i.e 27+3 = 30 m & will not fall down.
ANSWER:D</think>
| D)28 days | <think>frog jumps 3 m up day & falls back 2 m down at night
so,frog will be 3-2=1 m up in a day.
Thus, in 27 days it will be 27 m up
on 28 th day it will be at top i.e 27+3 = 30 m & will not fall down.
ANSWER:D</think>
D)28 days |
<think>perfect square:- 1,4,9,16,25,36
sum=square*10=10,40,90,160,250,360
sum of 4 odd consecutive numbers is multiple of 4
so the only number left are 40,160,360
sum/4=40/4=10 is not possible
sum/4=360/4=90 is not possible
sum/4=160/4=40 is the only option available i.e 41
ANSWER:C</think>
| C)41 | <think>perfect square:- 1,4,9,16,25,36
sum=square*10=10,40,90,160,250,360
sum of 4 odd consecutive numbers is multiple of 4
so the only number left are 40,160,360
sum/4=40/4=10 is not possible
sum/4=360/4=90 is not possible
sum/4=160/4=40 is the only option available i.e 41
ANSWER:C</think>
C)41 |
<think>Let x is total no. of students
8x/100+4x/5+10x/100+20=x
By solving this
x=1000
ANSWER:E</think>
| E)1000 | <think>Let x is total no. of students
8x/100+4x/5+10x/100+20=x
By solving this
x=1000
ANSWER:E</think>
E)1000 |
<think>R - Q = R - T
Q = T.
Also R + T = 50; R + Q = 50
So, (R - Q) cannot be determined.
Answer:D</think>
| D)Cannot be determined | <think>R - Q = R - T
Q = T.
Also R + T = 50; R + Q = 50
So, (R - Q) cannot be determined.
Answer:D</think>
D)Cannot be determined |
<think>Subtract the fee for te first quarter mile $8.50 - $3.50 = $5
Calculate how many extra additional quarter miles---$5/10 cents => 50 quarter miles => 12.5 miles
Total distance is 12.5 miles + 1/4 (first quarter mile)
12.75 miles
Answer: B</think>
| B)12.75 miles | <think>Subtract the fee for te first quarter mile $8.50 - $3.50 = $5
Calculate how many extra additional quarter miles---$5/10 cents => 50 quarter miles => 12.5 miles
Total distance is 12.5 miles + 1/4 (first quarter mile)
12.75 miles
Answer: B</think>
B)12.75 miles |
<think>Let total number of matches = x
then, total runs 54*x
total runs before final = 51*(x-1)
runs in the final match
54*x - 51*(x-1) = 78
x= 9
ANSWER:C</think>
| C)9 | <think>Let total number of matches = x
then, total runs 54*x
total runs before final = 51*(x-1)
runs in the final match
54*x - 51*(x-1) = 78
x= 9
ANSWER:C</think>
C)9 |
<think>The question asks for the smallest value of n, such that (n + nC2) = 10 (n represents the number of letters. In this equation, n by itself is for single-letter codes and nC2 is for two-letter codes).
At this point, you'd need to pick numbers, since there's really no easy way to solve nC2 = (10 – n) without a cal... | D)10 | <think>The question asks for the smallest value of n, such that (n + nC2) = 10 (n represents the number of letters. In this equation, n by itself is for single-letter codes and nC2 is for two-letter codes).
At this point, you'd need to pick numbers, since there's really no easy way to solve nC2 = (10 – n) without a cal... |
<think>Let its breadth be = x m.
So length will be = (4x+1) m.
Now,
x * (4x+1) = 150
or, 4x^2+x-150 = 0
or, (4x+25)(x-6) = 0
Either 4x = -25 or x = 6
As breadth can not take negetive value so x = 6
So its length is 4*6+1 = 25
So perimeter will be 2*(25+6)=62 mLet its breadth be = x m.
So length will be = (4x+1) m.
Now,... | C)62 m | <think>Let its breadth be = x m.
So length will be = (4x+1) m.
Now,
x * (4x+1) = 150
or, 4x^2+x-150 = 0
or, (4x+25)(x-6) = 0
Either 4x = -25 or x = 6
As breadth can not take negetive value so x = 6
So its length is 4*6+1 = 25
So perimeter will be 2*(25+6)=62 mLet its breadth be = x m.
So length will be = (4x+1) m.
Now,... |
<think>100% / 8% = 12.5
12.5 grams of the health food provides 12.5(8%) = 100% of the vitamin A requirement and more than 100% of the vitamin E requirement.
The answer is C.</think>
| C)12.5 | <think>100% / 8% = 12.5
12.5 grams of the health food provides 12.5(8%) = 100% of the vitamin A requirement and more than 100% of the vitamin E requirement.
The answer is C.</think>
C)12.5 |
<think>20 large cakes will require the equivalent of 10 helpers working for one hour. 700 small cakes will require the equivalent of 20 helpers working for one hour. This means if only one hour were available we would need 30 helpers. But since three hours are available we can use 10 helpers.
B</think>
| B)10 | <think>20 large cakes will require the equivalent of 10 helpers working for one hour. 700 small cakes will require the equivalent of 20 helpers working for one hour. This means if only one hour were available we would need 30 helpers. But since three hours are available we can use 10 helpers.
B</think>
B)10 |
<think>Since SR + RT = 22 = ST, then R is somewhere between S and T.
Since ST is 22, then SU is 11 because U is the midpoint of ST.
Since SR < SU, then R is somewhere between S and U.
Then SR + RU = SU.
5 + RU = 11
RU = 6
The answer is A.</think>
| A)6 | <think>Since SR + RT = 22 = ST, then R is somewhere between S and T.
Since ST is 22, then SU is 11 because U is the midpoint of ST.
Since SR < SU, then R is somewhere between S and U.
Then SR + RU = SU.
5 + RU = 11
RU = 6
The answer is A.</think>
A)6 |
<think>6P = 2R
3R = 5B
2B = ?P
Thus, P : R : B = 18 : 6 : 12
P : B = 18 : 12
= 3 : 2
Thus P = 3
Answer : C</think>
| C)3 | <think>6P = 2R
3R = 5B
2B = ?P
Thus, P : R : B = 18 : 6 : 12
P : B = 18 : 12
= 3 : 2
Thus P = 3
Answer : C</think>
C)3 |
<think>Suppose every item is priced at $100. On 20% discount, the price will become $80. Now he must add $20 to each item for original price which is 25% of $80.</think>
| C)25% | <think>Suppose every item is priced at $100. On 20% discount, the price will become $80. Now he must add $20 to each item for original price which is 25% of $80.</think>
C)25% |
<think>Let the train fare between the two places for one person be Rs.t
Bus fare between the two places for two persons Rs.4/3 t
=> 6/2 (4/3 t) + 8(t) = 1512
=> 12t = 1512 => t = 126.
Answer:A</think>
| A)126 | <think>Let the train fare between the two places for one person be Rs.t
Bus fare between the two places for two persons Rs.4/3 t
=> 6/2 (4/3 t) + 8(t) = 1512
=> 12t = 1512 => t = 126.
Answer:A</think>
A)126 |
<think>Perimeter = 2(8 cm) + 2(3 cm) = 16 cm + 6 cm = 22 cm
answer:B.</think>
| B)22cm | <think>Perimeter = 2(8 cm) + 2(3 cm) = 16 cm + 6 cm = 22 cm
answer:B.</think>
B)22cm |
<think>We have to arrange 6 books. The number of permutations is 6*5*4*3*2*1= 720
Answer : B</think>
| B)720 | <think>We have to arrange 6 books. The number of permutations is 6*5*4*3*2*1= 720
Answer : B</think>
B)720 |
<think>Number of pickets = x
Size of pickets = 1/2
length of pickets = 1/2x
If there are x pickets, it implies that there are x -1 spaces between the picket
Length of space = 6
total number of length = 1/2 x + 6(x-1) in inches
total length in feet =( 1/2 x + 6(x-1))/12
Simplify to get (13X-12)/24
ANSWER:E</think>
| E)(13x-12)/24 | <think>Number of pickets = x
Size of pickets = 1/2
length of pickets = 1/2x
If there are x pickets, it implies that there are x -1 spaces between the picket
Length of space = 6
total number of length = 1/2 x + 6(x-1) in inches
total length in feet =( 1/2 x + 6(x-1))/12
Simplify to get (13X-12)/24
ANSWER:E</think>
E)... |
<think>Let the speed of the ship = m miles/hr. and plane took 't' hours to meet the ship
Then, m×t is the distance ship traveled after plane started
So we have, mt + 180 = 10mt
⇒ 9mt = 180
⇒ mt = 20
Hence distance = 180 + 20 = 200 miles
Answer:C</think>
| C)200 | <think>Let the speed of the ship = m miles/hr. and plane took 't' hours to meet the ship
Then, m×t is the distance ship traveled after plane started
So we have, mt + 180 = 10mt
⇒ 9mt = 180
⇒ mt = 20
Hence distance = 180 + 20 = 200 miles
Answer:C</think>
C)200 |
<think>Let N = the total number of deer in the forest.
During the first year, the percent of deer in the entire population with tags was: 300/N
20/500 is the percent of deer caught during the second year that had tags. Since this sample percent matches the percent for the entire population (i.e., the total number of ta... | E)7500 | <think>Let N = the total number of deer in the forest.
During the first year, the percent of deer in the entire population with tags was: 300/N
20/500 is the percent of deer caught during the second year that had tags. Since this sample percent matches the percent for the entire population (i.e., the total number of ta... |
<think>For each 10 min interval, if man comes in first 2 min, he'll catch the 1st train, if he comes in next 8 min, he'll catch the 2nd train.
Hence, for harbor line = (2/10) = 0.2 and for main line 0.8.
Answer:B</think>
| B)0.8 | <think>For each 10 min interval, if man comes in first 2 min, he'll catch the 1st train, if he comes in next 8 min, he'll catch the 2nd train.
Hence, for harbor line = (2/10) = 0.2 and for main line 0.8.
Answer:B</think>
B)0.8 |
<think>The new average is 14.8 tons.
On average, the ten trucks are 2.6 tons below the average for a total weighting of 26 tons.
Therefore, the added truck must be 14.8 + 26 = 40.8 tons
The answer is A.</think>
| A)40.8 | <think>The new average is 14.8 tons.
On average, the ten trucks are 2.6 tons below the average for a total weighting of 26 tons.
Therefore, the added truck must be 14.8 + 26 = 40.8 tons
The answer is A.</think>
A)40.8 |
<think>Population now - 100;
Population one year from now - 110;
Population two years from now - 121;
Since the population two years from now (121) is exactly double the population one year ago then the population one year ago was 121/2=60.5.
Now, the question asks about the population increase over the last year, so f... | D)65% | <think>Population now - 100;
Population one year from now - 110;
Population two years from now - 121;
Since the population two years from now (121) is exactly double the population one year ago then the population one year ago was 121/2=60.5.
Now, the question asks about the population increase over the last year, so f... |
<think>Suppose Arun has $X and Sajal has $Y. then,
2(x-30)= y+30 => 2x-y =90 …(i)
and x +10 =3(y-10) => x-3y = - 40 …(ii)
Solving (i) and (ii), we get x =62 and y =34.
Arun has $62 and Sajal has $34.
Answer B.</think>
| B)62, 34 | <think>Suppose Arun has $X and Sajal has $Y. then,
2(x-30)= y+30 => 2x-y =90 …(i)
and x +10 =3(y-10) => x-3y = - 40 …(ii)
Solving (i) and (ii), we get x =62 and y =34.
Arun has $62 and Sajal has $34.
Answer B.</think>
B)62, 34 |
<think>Area = length x width. Divide area by width to find the missing side.
3000 ÷100 = 30
The other side is 30 feet.
Correct answer A</think>
| A)30 feet | <think>Area = length x width. Divide area by width to find the missing side.
3000 ÷100 = 30
The other side is 30 feet.
Correct answer A</think>
A)30 feet |
<think>GCF*LCM = product of 2 numbers
11*7700 = product of 2 numbers
other number = 11*7700/350 = 242
Answer is A</think>
| A)242 | <think>GCF*LCM = product of 2 numbers
11*7700 = product of 2 numbers
other number = 11*7700/350 = 242
Answer is A</think>
A)242 |
<think>Let x be the length of one side of the original square.
The area of the rectangle is x(x-4)=140.
x=14.
The perimeter of the square was 4*14=56 feet.
The answer is A.</think>
| A)56 | <think>Let x be the length of one side of the original square.
The area of the rectangle is x(x-4)=140.
x=14.
The perimeter of the square was 4*14=56 feet.
The answer is A.</think>
A)56 |
<think>Length of ribbon originally = 30 cm
Let the original length be 5x and reduced length be 3x.
But 5x = 30 cm
x = 30/5 cm = 6 cm
Therefore, reduced length = 3 cm
= 3 × 6 cm = 18 cm
Answer:A</think>
| A)18 | <think>Length of ribbon originally = 30 cm
Let the original length be 5x and reduced length be 3x.
But 5x = 30 cm
x = 30/5 cm = 6 cm
Therefore, reduced length = 3 cm
= 3 × 6 cm = 18 cm
Answer:A</think>
A)18 |
<think>From the given data,
abc – cba + 396c = 990
100a + 10b + c – (100c + 10b + a) + 396c = 990
99a – 99c + 396c = 990
Observe that each term is divisible by 99. So on dividing the above expression by 99, we get
a – c + 4c = 10
a + 3c = 10
For c = 1, a = 7
c = 2, a = 4
c = 3, a = 1
'b' can take any value from 0 to 9
... | A)20 | <think>From the given data,
abc – cba + 396c = 990
100a + 10b + c – (100c + 10b + a) + 396c = 990
99a – 99c + 396c = 990
Observe that each term is divisible by 99. So on dividing the above expression by 99, we get
a – c + 4c = 10
a + 3c = 10
For c = 1, a = 7
c = 2, a = 4
c = 3, a = 1
'b' can take any value from 0 to 9
... |
<think>20% means 1/5 and 28% means 7/25,taking the lcm of the denominators 5 and 25 we get 25,the least multiple of 25 which is greater than 501 is 525. So, answer is none
ANSWER:E</think>
| E)none of these | <think>20% means 1/5 and 28% means 7/25,taking the lcm of the denominators 5 and 25 we get 25,the least multiple of 25 which is greater than 501 is 525. So, answer is none
ANSWER:E</think>
E)none of these |
<think>Raj’s age today = 17 decades,
Hence, 5 decades back, he must be 12 years old.
Rahim must be 36 years old, Because (3×12).
5 years back Rahim must be 41 years old today. Because (36+5).</think>
| B)41 | <think>Raj’s age today = 17 decades,
Hence, 5 decades back, he must be 12 years old.
Rahim must be 36 years old, Because (3×12).
5 years back Rahim must be 41 years old today. Because (36+5).</think>
B)41 |
<think>Area of the field grazed = [22/7*14*14]sq.ft. = 616 sq.ft.
Number of days taken to graze the field = 616/10 days
=> 61 days
ANSWER:B</think>
| B)61 days | <think>Area of the field grazed = [22/7*14*14]sq.ft. = 616 sq.ft.
Number of days taken to graze the field = 616/10 days
=> 61 days
ANSWER:B</think>
B)61 days |
<think>S.P.=(100+gain%100∗C.P)
So, C.P. = (100/110∗25.75)
When S.P. = 25.75 then
Profit=25.75−25=Re.0.75
Profit%=0.75/25∗100=3%
Answer is B</think>
| B)3% Profit | <think>S.P.=(100+gain%100∗C.P)
So, C.P. = (100/110∗25.75)
When S.P. = 25.75 then
Profit=25.75−25=Re.0.75
Profit%=0.75/25∗100=3%
Answer is B</think>
B)3% Profit |
<think>Total ways in which 3 children can be arranged on 3 chairs = 3*2*1 = 6
But in half cases Susan will be left of Tim and in other half of cases Tim will be on left of Susan
i.e. Desired cases in which Susan is on the left of Tim = (1/2)*6 = 3
B</think>
| B)3 | <think>Total ways in which 3 children can be arranged on 3 chairs = 3*2*1 = 6
But in half cases Susan will be left of Tim and in other half of cases Tim will be on left of Susan
i.e. Desired cases in which Susan is on the left of Tim = (1/2)*6 = 3
B</think>
B)3 |
<think>Let the fixed amount be Rs. X and the cost of each unit be Rs. Y.
Then, 540y + x = 1800 …. And 620y + x = 2040
On subtracting (i) from (ii), we get 80y = 240 -> y = 3
Putting y = 3 in (i) we get :
540 * 3 + x = 1800 x = (1800-1620) = 180
. : Fixed charges = Rs.180, Charge per unit = Rs.3.
Total charges for consu... | B)Rs.1680 | <think>Let the fixed amount be Rs. X and the cost of each unit be Rs. Y.
Then, 540y + x = 1800 …. And 620y + x = 2040
On subtracting (i) from (ii), we get 80y = 240 -> y = 3
Putting y = 3 in (i) we get :
540 * 3 + x = 1800 x = (1800-1620) = 180
. : Fixed charges = Rs.180, Charge per unit = Rs.3.
Total charges for consu... |
<think>If ball A makes 2 rotations in 26 minutes, it makes 1 rotation in 13 minutes. If ball B makes 5 rotations in 35 minutes, it makes 1 rotation in 7 minutes.
The two balls start rotating now and makes several rotations before they are at the SAME starting points. Ball A would have done a WHOLE number X of rotations... | A)1 hour and 31 minutes | <think>If ball A makes 2 rotations in 26 minutes, it makes 1 rotation in 13 minutes. If ball B makes 5 rotations in 35 minutes, it makes 1 rotation in 7 minutes.
The two balls start rotating now and makes several rotations before they are at the SAME starting points. Ball A would have done a WHOLE number X of rotations... |
<think>Total Books = 45
Hard Cover = 30
Non hardcover = 15
Fiction = 20
Non-Fiction = 25
Maximum number of Hardcover fiction will be 20( Assuming All the Fiction Books are Hard Cover )
Hence, the correct answer will be (D)</think>
| D)20 | <think>Total Books = 45
Hard Cover = 30
Non hardcover = 15
Fiction = 20
Non-Fiction = 25
Maximum number of Hardcover fiction will be 20( Assuming All the Fiction Books are Hard Cover )
Hence, the correct answer will be (D)</think>
D)20 |
<think>Number of paper bought on monday = x
# of paper bought on sunday = 2x
Total cost = 210 = 6*x(rest of the day cost)+8*x (sunday cost)
14x = 210
x = 15
Ans A</think>
| A)15 | <think>Number of paper bought on monday = x
# of paper bought on sunday = 2x
Total cost = 210 = 6*x(rest of the day cost)+8*x (sunday cost)
14x = 210
x = 15
Ans A</think>
A)15 |
<think>Let the number of persons be x. Then,
96/x-4-96/x=4 => x=12
So, required number =x-4=8.
Answer is A</think>
| A)8 | <think>Let the number of persons be x. Then,
96/x-4-96/x=4 => x=12
So, required number =x-4=8.
Answer is A</think>
A)8 |
<think>Perimeter of rectangle = 2 (27 + 17) cm
= 88cm
Perimeter of square of side x cm = 4x
Therefore, perimeter of rectangle = Perimeter of Square
88 cm = 4x
x = 22
Therefore, each side of square = 22 cm
ANSWER : OPTION C</think>
| C)22 | <think>Perimeter of rectangle = 2 (27 + 17) cm
= 88cm
Perimeter of square of side x cm = 4x
Therefore, perimeter of rectangle = Perimeter of Square
88 cm = 4x
x = 22
Therefore, each side of square = 22 cm
ANSWER : OPTION C</think>
C)22 |
<think>If each nephew got Rs x, then
2x+16x+25x = 8600
x= 200
Each daughter got 4*200 = Rs 800
ANSWER:E</think>
| E)Rs 800 | <think>If each nephew got Rs x, then
2x+16x+25x = 8600
x= 200
Each daughter got 4*200 = Rs 800
ANSWER:E</think>
E)Rs 800 |
<think>It is given that Meenu weighs 29 Kgs plus half of her own weight.
It means that 29 Kgs is the other half. So she weighs 58 Kgs.
Solving mathematically, let's assume that her weight is A Kgs.
A = 29 + A/2
2 × A = 58 + A
A = 58 Kgs.
Answer:D</think>
| D)58 | <think>It is given that Meenu weighs 29 Kgs plus half of her own weight.
It means that 29 Kgs is the other half. So she weighs 58 Kgs.
Solving mathematically, let's assume that her weight is A Kgs.
A = 29 + A/2
2 × A = 58 + A
A = 58 Kgs.
Answer:D</think>
D)58 |
<think>Tablet 1 will be taken in 0 min.
Tablet 2 will be taken in 15 min.
Tablet 3 will be taken in 30 min.
Tablet 4 will be taken in 45 min.
Tablet 5 will be taken in 60 min.</think>
| E)60 Min | <think>Tablet 1 will be taken in 0 min.
Tablet 2 will be taken in 15 min.
Tablet 3 will be taken in 30 min.
Tablet 4 will be taken in 45 min.
Tablet 5 will be taken in 60 min.</think>
E)60 Min |
End of preview. Expand in Data Studio
README.md exists but content is empty.
- Downloads last month
- 18