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The dataset generation failed
Error code: DatasetGenerationError
Exception: CastError
Message: Couldn't cast
pass@1: double
pass@1_ci95: list<item: double>
child 0, item: double
pass@1_sd_boot: double
pass@1_by_rollout_index: list<item: double>
child 0, item: double
pass@1_sd_rollouts: double
pass@8: double
pass@8_ci95: list<item: double>
child 0, item: double
pass@8_sd_boot: double
pass@16: double
pass@16_ci95: list<item: double>
child 0, item: double
pass@16_sd_boot: double
cap_rate: double
n_problems: int64
n_rollouts: int64
rollouts_per_problem: int64
max_tokens_used: list<item: int64>
child 0, item: int64
prompt_style: list<item: null>
child 0, item: null
median_output_tokens: int64
mean_output_tokens: double
expected_problems: int64
complete: bool
files: list<item: string>
child 0, item: string
per_problem: struct<aime2024_0: struct<rollout_index: list<item: int64>, correct: list<item: int64>, tokens: list (... 8176 chars omitted)
child 0, aime2024_0: struct<rollout_index: list<item: int64>, correct: list<item: int64>, tokens: list<item: int64>, answ (... 161 chars omitted)
child 0, rollout_index: list<item: int64>
child 0, item: int64
child 1, correct: list<item: int64>
child 0, item: int64
child 2, tokens: list<item: int64>
child 0, item: int64
child 3, answer: list<item: string>
child 0, item: string
child 4, hit_cap: list<item: int64>
child 0, item: int64
child 5, answer_end_frac: list<item: double>
child 0, item: double
child 6, answer_marker: list<item: s
...
child 0, k: int64
child 1, expected_tokens: double
child 2, pass_at_k: double
child 3, majority_at_k: double
child 27, 28: struct<k: int64, expected_tokens: double, pass_at_k: double, majority_at_k: double>
child 0, k: int64
child 1, expected_tokens: double
child 2, pass_at_k: double
child 3, majority_at_k: double
child 28, 29: struct<k: int64, expected_tokens: double, pass_at_k: double, majority_at_k: double>
child 0, k: int64
child 1, expected_tokens: double
child 2, pass_at_k: double
child 3, majority_at_k: double
child 29, 30: struct<k: int64, expected_tokens: double, pass_at_k: double, majority_at_k: double>
child 0, k: int64
child 1, expected_tokens: double
child 2, pass_at_k: double
child 3, majority_at_k: double
child 30, 31: struct<k: int64, expected_tokens: double, pass_at_k: double, majority_at_k: double>
child 0, k: int64
child 1, expected_tokens: double
child 2, pass_at_k: double
child 3, majority_at_k: double
child 31, 32: struct<k: int64, expected_tokens: double, pass_at_k: double, majority_at_k: double>
child 0, k: int64
child 1, expected_tokens: double
child 2, pass_at_k: double
child 3, majority_at_k: double
aggregate_by_k_doc: string
completion: string
steer: string
problem_key: string
rollout_index: int64
correct: bool
output_tokens: int64
committed: bool
finish_reason: string
label: string
hit_token_cap: bool
to
{'problem_key': Value('string'), 'rollout_index': Value('int64'), 'arm': Value('string'), 'steer': Value('string'), 'label': Value('string'), 'committed': Value('bool'), 'correct': Value('bool'), 'hit_token_cap': Value('bool'), 'finish_reason': Value('string'), 'output_tokens': Value('int64'), 'max_tokens_used': Value('int64'), 'completion': Value('string')}
because column names don't match
Traceback: Traceback (most recent call last):
File "/usr/local/lib/python3.14/site-packages/datasets/builder.py", line 1827, in _prepare_split_single
for key, table in generator:
^^^^^^^^^
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 613, in wrapped
for item in generator(*args, **kwargs):
~~~~~~~~~^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.14/site-packages/datasets/packaged_modules/json/json.py", line 343, in _generate_tables
self._cast_table(pa_table, json_field_paths=json_field_paths),
~~~~~~~~~~~~~~~~^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.14/site-packages/datasets/packaged_modules/json/json.py", line 132, in _cast_table
pa_table = table_cast(pa_table, self.info.features.arrow_schema)
File "/usr/local/lib/python3.14/site-packages/datasets/table.py", line 2378, in table_cast
return cast_table_to_schema(table, schema)
File "/usr/local/lib/python3.14/site-packages/datasets/table.py", line 2306, in cast_table_to_schema
raise CastError(
...<3 lines>...
)
datasets.table.CastError: Couldn't cast
pass@1: double
pass@1_ci95: list<item: double>
child 0, item: double
pass@1_sd_boot: double
pass@1_by_rollout_index: list<item: double>
child 0, item: double
pass@1_sd_rollouts: double
pass@8: double
pass@8_ci95: list<item: double>
child 0, item: double
pass@8_sd_boot: double
pass@16: double
pass@16_ci95: list<item: double>
child 0, item: double
pass@16_sd_boot: double
cap_rate: double
n_problems: int64
n_rollouts: int64
rollouts_per_problem: int64
max_tokens_used: list<item: int64>
child 0, item: int64
prompt_style: list<item: null>
child 0, item: null
median_output_tokens: int64
mean_output_tokens: double
expected_problems: int64
complete: bool
files: list<item: string>
child 0, item: string
per_problem: struct<aime2024_0: struct<rollout_index: list<item: int64>, correct: list<item: int64>, tokens: list (... 8176 chars omitted)
child 0, aime2024_0: struct<rollout_index: list<item: int64>, correct: list<item: int64>, tokens: list<item: int64>, answ (... 161 chars omitted)
child 0, rollout_index: list<item: int64>
child 0, item: int64
child 1, correct: list<item: int64>
child 0, item: int64
child 2, tokens: list<item: int64>
child 0, item: int64
child 3, answer: list<item: string>
child 0, item: string
child 4, hit_cap: list<item: int64>
child 0, item: int64
child 5, answer_end_frac: list<item: double>
child 0, item: double
child 6, answer_marker: list<item: s
...
child 0, k: int64
child 1, expected_tokens: double
child 2, pass_at_k: double
child 3, majority_at_k: double
child 27, 28: struct<k: int64, expected_tokens: double, pass_at_k: double, majority_at_k: double>
child 0, k: int64
child 1, expected_tokens: double
child 2, pass_at_k: double
child 3, majority_at_k: double
child 28, 29: struct<k: int64, expected_tokens: double, pass_at_k: double, majority_at_k: double>
child 0, k: int64
child 1, expected_tokens: double
child 2, pass_at_k: double
child 3, majority_at_k: double
child 29, 30: struct<k: int64, expected_tokens: double, pass_at_k: double, majority_at_k: double>
child 0, k: int64
child 1, expected_tokens: double
child 2, pass_at_k: double
child 3, majority_at_k: double
child 30, 31: struct<k: int64, expected_tokens: double, pass_at_k: double, majority_at_k: double>
child 0, k: int64
child 1, expected_tokens: double
child 2, pass_at_k: double
child 3, majority_at_k: double
child 31, 32: struct<k: int64, expected_tokens: double, pass_at_k: double, majority_at_k: double>
child 0, k: int64
child 1, expected_tokens: double
child 2, pass_at_k: double
child 3, majority_at_k: double
aggregate_by_k_doc: string
completion: string
steer: string
problem_key: string
rollout_index: int64
correct: bool
output_tokens: int64
committed: bool
finish_reason: string
label: string
hit_token_cap: bool
to
{'problem_key': Value('string'), 'rollout_index': Value('int64'), 'arm': Value('string'), 'steer': Value('string'), 'label': Value('string'), 'committed': Value('bool'), 'correct': Value('bool'), 'hit_token_cap': Value('bool'), 'finish_reason': Value('string'), 'output_tokens': Value('int64'), 'max_tokens_used': Value('int64'), 'completion': Value('string')}
because column names don't match
The above exception was the direct cause of the following exception:
Traceback (most recent call last):
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 1369, in compute_config_parquet_and_info_response
parquet_operations, partial, estimated_dataset_info = stream_convert_to_parquet(
~~~~~~~~~~~~~~~~~~~~~~~~~^
builder, max_dataset_size_bytes=max_dataset_size_bytes
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
)
^
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 948, in stream_convert_to_parquet
builder._prepare_split(split_generator=splits_generators[split], file_format="parquet")
~~~~~~~~~~~~~~~~~~~~~~^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.14/site-packages/datasets/builder.py", line 1694, in _prepare_split
for job_id, done, content in self._prepare_split_single(
~~~~~~~~~~~~~~~~~~~~~~~~~~^
gen_kwargs=gen_kwargs, job_id=job_id, **_prepare_split_args
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
):
^
File "/usr/local/lib/python3.14/site-packages/datasets/builder.py", line 1880, in _prepare_split_single
raise DatasetGenerationError("An error occurred while generating the dataset") from e
datasets.exceptions.DatasetGenerationError: An error occurred while generating the datasetNeed help to make the dataset viewer work? Make sure to review how to configure the dataset viewer, and open a discussion for direct support.
problem_key string | rollout_index int64 | arm string | steer string | label string | committed bool | correct bool | hit_token_cap bool | finish_reason string | output_tokens int64 | max_tokens_used int64 | completion string |
|---|---|---|---|---|---|---|---|---|---|---|---|
aime2024_0 | 0 | none | base | run | true | true | false | stop | 1,171 | 31,744 | Let's denote the time Aya spends walking at her original speed \( s \) as \( T_1 \) and the time she spends walking at her increased speed \( s+2 \) as \( T_2 \). We know that the total time spent walking and stopping at the coffee shop for both scenarios is 4 hours and 2 hours 24 minutes, respectively.
First, we con... |
aime2024_0 | 1 | none | base | run | false | false | false | stop | 1,193 | 31,744 | To solve this problem, we need to determine the time it takes for Aya to walk 9 kilometers at a speed of \(s + \frac{1}{2}\) kilometers per hour, including the time spent in the coffee shop. Let's break down the problem step by step.
1. **Determine the walking time at the first speed:**
- Let \(t\) be the time spe... |
aime2024_0 | 2 | none | base | run | true | false | false | stop | 901 | 31,744 | To solve this problem, we need to determine the walking speed \( s \) and the time \( t \) spent in the coffee shop. Let's break it down step by step.
### Step 1: Set up the equations
We are given two scenarios:
1. **First scenario**:
- Walking speed: \( s \) km/h
- Time spent walking: 4 hours
- Time ... |
aime2024_0 | 3 | none | base | run | true | false | false | stop | 1,485 | 31,744 | To solve the problem, let's first define the variables and equations based on the given information. Let \( t \) be the time spent in the coffee shop in minutes. The time spent walking at a constant speed \( s \) kilometers per hour is 4 hours minus \( t \) minutes, which is \( 4 - \frac{t}{60} \) hours. Since the wal... |
aime2024_0 | 4 | none | base | run | true | true | false | stop | 1,129 | 31,744 | To solve this problem, we need to determine the time Aya spends walking and the time she spends in the coffee shop for each scenario. We will then use this information to find the total time for the scenario where she walks at \( s + \frac{1}{2} \) kilometers per hour.
First, let's denote the time Aya spends walking ... |
aime2024_0 | 5 | none | base | run | true | true | false | stop | 1,022 | 31,744 | To solve this problem, we need to determine the value of \( t \) and then use it to find the time it takes Aya to walk 9 kilometers at a speed of \( s + \frac{1}{2} \) kilometers per hour.
First, let's express the time taken for the walk in terms of \( s \) and \( t \). When Aya walks at a speed of \( s \) kilometers... |
aime2024_0 | 6 | none | base | run | true | false | false | stop | 1,157 | 31,744 | To solve this problem, we need to determine the time Aya spends walking and then add the time she spends in the coffee shop. We start by setting up equations based on the information given.
1. **Determine the time spent walking at different speeds:**
- When Aya walks at a speed of \( s \) km/h, the walk takes 4 ho... |
aime2024_0 | 7 | none | base | run | true | false | false | stop | 1,341 | 31,744 | Let's denote the distance of the walk as $D$, the time spent walking as $T_w$, and the time spent in the coffee shop as $T_c = t$ minutes. We know that the total time for the walk, including the coffee shop, is given by:
\[T_{\text{total}} = T_w + T_c\]
When Aya walks at $s$ km/h, the walk takes 4 hours including $t... |
aime2024_0 | 8 | none | base | run | true | false | false | stop | 301 | 31,744 | We are given that Aya's walk takes her 4 hours when she walks at a constant speed of $s$ kilometers per hour. Since she walks 9 kilometers, we have $s=\frac{9}{4}$ kilometers per hour. We are also given that the walk takes her 2 hours and 24 minutes when she walks at a speed of $s+2$ kilometers per hour. Since 24 minu... |
aime2024_0 | 9 | none | base | run | false | false | false | stop | 19,901 | 31,744 | Let's break down the problem step by step.
### Step 1: Understand the given information
1. **First Scenario:**
- Speed: \( s \) km/h
- Time spent walking: 4 hours
- Time spent in the coffee shop: \( t \) minutes
- Total time: 4 hours + \( t \) minutes
2. **Second Scenario:**
- Speed: \( s + 2 \) km/h
... |
aime2024_0 | 10 | none | base | run | true | true | false | stop | 1,358 | 31,744 | Let's break down the problem step by step.
### Step 1: Understand the given information
- **First scenario**:
- Speed: \( s \) km/h
- Time: 4 hours (including \( t \) minutes in the coffee shop)
- Distance walked: 9 km
- **Second scenario**:
- Speed: \( s + 2 \) km/h
- Time: 2 hours and 24 minu... |
aime2024_0 | 11 | none | base | run | true | true | false | stop | 1,043 | 31,744 | To solve this problem, we need to determine the time it takes for Aya to walk 9 kilometers at a speed of \( s + \frac{1}{2} \) kilometers per hour, including the time spent in the coffee shop.
First, let's find the value of \( s \) and \( t \) from the given information.
### Step 1: Determine \( s \) and \( t \)
1.... |
aime2024_0 | 12 | none | base | run | true | false | false | stop | 1,307 | 31,744 | To solve this problem, we need to determine the time it takes Aya to walk 9 kilometers at a speed of \( s + \frac{1}{2} \) kilometers per hour, including the time spent in the coffee shop. We start by setting up equations based on the information given.
First, let's denote the time spent in the coffee shop as \( t \)... |
aime2024_0 | 13 | none | base | run | true | true | false | stop | 1,187 | 31,744 | To solve this problem, we need to determine the value of \( t \) (the time spent in the coffee shop) and then use it to find out how long the walk takes when Aya walks at a speed of \( s + \frac{1}{2} \) kilometers per hour.
First, let's set up the equations based on the information given:
1. When Aya walks at a spe... |
aime2024_0 | 14 | none | base | run | true | true | false | stop | 1,123 | 31,744 | Let's denote the total time Aya spends walking and in the coffee shop as \( T \) minutes. We know that when she walks at a speed of \( s \) km/h, the walk takes her 4 hours, including \( t \) minutes in the coffee shop. Similarly, when she walks at a speed of \( s+2 \) km/h, the walk takes her 2 hours and 24 minutes, ... |
aime2024_0 | 15 | none | base | run | true | false | false | stop | 388 | 31,744 | We have two equations:
$$\frac{9}{s} + \frac{t}{60} = 4 \quad \text{and} \quad \frac{9}{s+2} + \frac{t}{60} = 2.24$$
Subtracting the second equation from the first equation, we get:
$$\frac{9}{s} - \frac{9}{s+2} = 1.76$$
Multiplying both sides by $s(s+2)$, we get:
$$9(s+2) - 9s = 1.76s(s+2)$$
Simplifying, we get:
$$18... |
aime2024_1 | 0 | none | base | run | true | false | false | stop | 754 | 31,744 | To solve the problem, we will use properties of cyclic quadrilaterals, power of a point, and the intersecting chords theorem. Let's start by noting that $D$ is the intersection of the tangents to the circumcircle $\omega$ at points $B$ and $C$. This means that $D$ is the excenter of the triangle $ABC$ opposite to $A$,... |
aime2024_1 | 1 | none | base | run | false | false | true | length | 31,744 | 31,744 | To solve this problem, we will use properties of cyclic quadrilaterals, the Power of a Point theorem, and the Angle Bisector Theorem. Let's proceed step by step.
1. **Identify Key Points and Properties:**
- \(D\) is the intersection of the tangents to \(\omega\) at \(B\) and \(C\), so \(DB = DC\) and \(\angle BDC ... |
aime2024_1 | 2 | none | base | run | true | false | false | stop | 712 | 31,744 | We begin by using the Angle Bisector Theorem to find that $\frac{AB}{AP} = \frac{BP}{PC}$, which implies that $\frac{5}{AP} = \frac{9}{10 - AP}$. Solving for $AP$, we find that $AP = \frac{45}{14}$, so $m + n = 45 + 14 = \boxed{59}$. The solution provided in the problem statement contains an error in the application o... |
aime2024_1 | 3 | none | base | run | true | false | false | stop | 1,069 | 31,744 | To solve for \( AP \) in the given problem, we will use properties of cyclic quadrilaterals and the power of a point theorem. Here is the step-by-step reasoning:
1. **Identify Key Points and Properties:**
- \( D \) is the intersection of the tangents to the circle \( \omega \) at points \( B \) and \( C \).
- \... |
aime2024_1 | 4 | none | base | run | true | false | false | stop | 639 | 31,744 | To solve the problem, we will use the properties of the tangents to a circle and the power of a point theorem.
1. **Identify the given values and properties:**
- \(AB = 5\)
- \(BC = 9\)
- \(AC = 10\)
- \(D\) is the intersection of the tangents to \(\omega\) at \(B\) and \(C\).
- \(P\) is the intersecti... |
aime2024_1 | 5 | none | base | run | true | false | false | stop | 683 | 31,744 | We will use the following diagram:
[asy]
unitsize(0.8 cm);
pair A, B, C, D, P;
A = (0,0);
B = (5,0);
C = (1,4);
P = (1.5,3.6);
D = extension(B, B + rotate(90)*(B - C), C, C + rotate(90)*(C - B));
draw(A--B--C--cycle);
draw(circle((1.4,2),2.3));
draw(A--D);
draw(B--D);
draw(C--D);
label("$A$", A, SW);
label("$B$", ... |
aime2024_1 | 6 | none | base | run | true | false | false | stop | 84 | 31,744 | Let $I$ be the intersection of $AD$ and $BC$. Since $ABCD$ is harmonic, we have $AI \cdot AD = AP \cdot AB = 5AP$. Also, $AP \cdot AB = AI \cdot AD = 20$. Therefore, $AP = \frac{4}{1}$. Thus, $m + n = \boxed{5}$. |
aime2024_1 | 7 | none | base | run | true | false | false | stop | 1,159 | 31,744 | To solve the problem, we will use properties of cyclic quadrilaterals and power of a point theorem. Here's the step-by-step reasoning:
1. **Identify Key Points and Relationships:**
- \(ABC\) is a triangle inscribed in circle \(\omega\).
- Tangents to \(\omega\) at \(B\) and \(C\) intersect at \(D\).
- Line \... |
aime2024_1 | 8 | none | base | run | true | false | false | stop | 522 | 31,744 | Let $E$ and $F$ be the midpoints of $AB$ and $AC$, respectively. Then $DE$ and $DF$ are perpendicular bisectors of $AB$ and $AC$, respectively. Therefore, $DE$ and $DF$ intersect at the circumcenter $O$ of triangle $ABC$. Since $D$ is the intersection of the tangents to $\omega$ at $B$ and $C$, we have $\angle BDC = \... |
aime2024_1 | 9 | none | base | run | true | false | false | stop | 599 | 31,744 | Step 1: Find the area of triangle $ABC$ using Heron's formula.
We first find the semiperimeter $s$ of triangle $ABC$:
$$s = \frac{AB + BC + AC}{2} = \frac{5 + 9 + 10}{2} = 12$$
Now we can use Heron's formula to find the area of triangle $ABC$:
$$[ABC] = \sqrt{s(s-AB)(s-BC)(s-AC)} = \sqrt{12(12-5)(12-9)(12-10)} = 24$$
... |
aime2024_1 | 10 | none | base | run | true | false | false | stop | 926 | 31,744 | To solve this problem, we will use the properties of cyclic quadrilaterals and the power of a point theorem.
1. **Identify the given values and setup the problem:**
- We are given a triangle \(ABC\) with sides \(AB = 5\), \(BC = 9\), and \(AC = 10\).
- The tangents to the circumcircle \(\omega\) at points \(B\)... |
aime2024_1 | 11 | none | base | run | true | false | false | stop | 436 | 31,744 |
Step 1: Use Power of a Point theorem to find $AP$.
Since $AD$ is tangent to $\omega$ at $D$, we have $AD^2 = AP \cdot AC$. By Power of a Point theorem, we have $AD^2 = AB \cdot AC = 5 \cdot 10 = 50$. Therefore, $AP \cdot AC = 50$.
Step 2: Use the Law of Cosines to find $\cos A$.
Using the Law of Cosines, we have $\c... |
aime2024_1 | 12 | none | base | run | true | false | false | stop | 182 | 31,744 | Let $E$ be the midpoint of $\overline{BC}$. By the Power of a Point Theorem, we have that \begin{align*} AD \cdot AP &= AB \cdot AC \\ AD \cdot AP &= 5 \cdot 10 \\ AD \cdot AP &= 50. \end{align*}By the Power of a Point Theorem, we have that \begin{align*} AD \cdot AP &= AE^2 \\ AD \cdot AP &= (BE + EC)^2 \\ AD \cdot A... |
aime2024_1 | 13 | none | base | run | true | false | false | stop | 1,101 | 31,744 | By Power of a Point, we have \[
AD \cdot AP = AB \cdot AC = 5 \cdot 10 = 50.
\]To find $AP$, we need to find $AD$. By the Power of a Point theorem, we have \[
AD^2 = AB \cdot AC = 5 \cdot 10 = 50.
\]Therefore, $AD = \sqrt{50} = 5\sqrt{2}$. Since $AP = AD - PD$, we have \[
AP = AD - PD = 5\sqrt{2} - \frac{AB \cdot AC}{... |
End of preview.
rollouts-qwen4b — evaluation rollouts
Model: Qwen/Qwen3-4B-Base. Tokenizer used for answer positions: Qwen/Qwen3-4B-Base.
Protocol: 32 rollouts per problem (two seeded batches of 16), temperature 0.6, top-p 0.95,
budget 31,744 generated tokens, seed 20260819. Prompts and grader: the paper's repository
(sophicle/reason). Rollout jsonl files are kept as written (one graded rollout per line, with the
completion), under the run directories as on disk (run/, run_regraded/, *_execgraded/);
cell summaries are at <prompt>/<benchmark>/summary/<arm>.json.
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