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The dataset generation failed
Error code: DatasetGenerationError
Exception: CastError
Message: Couldn't cast
pass@1: double
pass@1_ci95: list<item: double>
child 0, item: double
pass@1_sd_boot: double
pass@1_by_rollout_index: list<item: double>
child 0, item: double
pass@1_sd_rollouts: double
pass@8: double
pass@8_ci95: list<item: double>
child 0, item: double
pass@8_sd_boot: double
pass@16: double
pass@16_ci95: list<item: double>
child 0, item: double
pass@16_sd_boot: double
cap_rate: double
n_problems: int64
n_rollouts: int64
rollouts_per_problem: int64
max_tokens_used: list<item: int64>
child 0, item: int64
prompt_style: list<item: null>
child 0, item: null
median_output_tokens: int64
mean_output_tokens: double
expected_problems: int64
complete: bool
files: list<item: string>
child 0, item: string
per_problem: struct<aime2024_0: struct<rollout_index: list<item: int64>, correct: list<item: int64>, tokens: list (... 8176 chars omitted)
child 0, aime2024_0: struct<rollout_index: list<item: int64>, correct: list<item: int64>, tokens: list<item: int64>, answ (... 161 chars omitted)
child 0, rollout_index: list<item: int64>
child 0, item: int64
child 1, correct: list<item: int64>
child 0, item: int64
child 2, tokens: list<item: int64>
child 0, item: int64
child 3, answer: list<item: string>
child 0, item: string
child 4, hit_cap: list<item: int64>
child 0, item: int64
child 5, answer_end_frac: list<item: double>
child 0, item: double
child 6, answer_marker: list<item: s
...
child 0, k: int64
child 1, expected_tokens: double
child 2, pass_at_k: double
child 3, majority_at_k: double
child 27, 28: struct<k: int64, expected_tokens: double, pass_at_k: double, majority_at_k: double>
child 0, k: int64
child 1, expected_tokens: double
child 2, pass_at_k: double
child 3, majority_at_k: double
child 28, 29: struct<k: int64, expected_tokens: double, pass_at_k: double, majority_at_k: double>
child 0, k: int64
child 1, expected_tokens: double
child 2, pass_at_k: double
child 3, majority_at_k: double
child 29, 30: struct<k: int64, expected_tokens: double, pass_at_k: double, majority_at_k: double>
child 0, k: int64
child 1, expected_tokens: double
child 2, pass_at_k: double
child 3, majority_at_k: double
child 30, 31: struct<k: int64, expected_tokens: double, pass_at_k: double, majority_at_k: double>
child 0, k: int64
child 1, expected_tokens: double
child 2, pass_at_k: double
child 3, majority_at_k: double
child 31, 32: struct<k: int64, expected_tokens: double, pass_at_k: double, majority_at_k: double>
child 0, k: int64
child 1, expected_tokens: double
child 2, pass_at_k: double
child 3, majority_at_k: double
aggregate_by_k_doc: string
rollout_index: int64
correct: bool
completion: string
label: string
problem_key: string
committed: bool
output_tokens: int64
hit_token_cap: bool
finish_reason: string
steer: string
to
{'problem_key': Value('string'), 'rollout_index': Value('int64'), 'arm': Value('string'), 'steer': Value('string'), 'label': Value('string'), 'committed': Value('bool'), 'correct': Value('bool'), 'hit_token_cap': Value('bool'), 'finish_reason': Value('string'), 'output_tokens': Value('int64'), 'max_tokens_used': Value('int64'), 'completion': Value('string')}
because column names don't match
Traceback: Traceback (most recent call last):
File "/usr/local/lib/python3.14/site-packages/datasets/builder.py", line 1827, in _prepare_split_single
for key, table in generator:
^^^^^^^^^
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 613, in wrapped
for item in generator(*args, **kwargs):
~~~~~~~~~^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.14/site-packages/datasets/packaged_modules/json/json.py", line 343, in _generate_tables
self._cast_table(pa_table, json_field_paths=json_field_paths),
~~~~~~~~~~~~~~~~^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.14/site-packages/datasets/packaged_modules/json/json.py", line 132, in _cast_table
pa_table = table_cast(pa_table, self.info.features.arrow_schema)
File "/usr/local/lib/python3.14/site-packages/datasets/table.py", line 2378, in table_cast
return cast_table_to_schema(table, schema)
File "/usr/local/lib/python3.14/site-packages/datasets/table.py", line 2306, in cast_table_to_schema
raise CastError(
...<3 lines>...
)
datasets.table.CastError: Couldn't cast
pass@1: double
pass@1_ci95: list<item: double>
child 0, item: double
pass@1_sd_boot: double
pass@1_by_rollout_index: list<item: double>
child 0, item: double
pass@1_sd_rollouts: double
pass@8: double
pass@8_ci95: list<item: double>
child 0, item: double
pass@8_sd_boot: double
pass@16: double
pass@16_ci95: list<item: double>
child 0, item: double
pass@16_sd_boot: double
cap_rate: double
n_problems: int64
n_rollouts: int64
rollouts_per_problem: int64
max_tokens_used: list<item: int64>
child 0, item: int64
prompt_style: list<item: null>
child 0, item: null
median_output_tokens: int64
mean_output_tokens: double
expected_problems: int64
complete: bool
files: list<item: string>
child 0, item: string
per_problem: struct<aime2024_0: struct<rollout_index: list<item: int64>, correct: list<item: int64>, tokens: list (... 8176 chars omitted)
child 0, aime2024_0: struct<rollout_index: list<item: int64>, correct: list<item: int64>, tokens: list<item: int64>, answ (... 161 chars omitted)
child 0, rollout_index: list<item: int64>
child 0, item: int64
child 1, correct: list<item: int64>
child 0, item: int64
child 2, tokens: list<item: int64>
child 0, item: int64
child 3, answer: list<item: string>
child 0, item: string
child 4, hit_cap: list<item: int64>
child 0, item: int64
child 5, answer_end_frac: list<item: double>
child 0, item: double
child 6, answer_marker: list<item: s
...
child 0, k: int64
child 1, expected_tokens: double
child 2, pass_at_k: double
child 3, majority_at_k: double
child 27, 28: struct<k: int64, expected_tokens: double, pass_at_k: double, majority_at_k: double>
child 0, k: int64
child 1, expected_tokens: double
child 2, pass_at_k: double
child 3, majority_at_k: double
child 28, 29: struct<k: int64, expected_tokens: double, pass_at_k: double, majority_at_k: double>
child 0, k: int64
child 1, expected_tokens: double
child 2, pass_at_k: double
child 3, majority_at_k: double
child 29, 30: struct<k: int64, expected_tokens: double, pass_at_k: double, majority_at_k: double>
child 0, k: int64
child 1, expected_tokens: double
child 2, pass_at_k: double
child 3, majority_at_k: double
child 30, 31: struct<k: int64, expected_tokens: double, pass_at_k: double, majority_at_k: double>
child 0, k: int64
child 1, expected_tokens: double
child 2, pass_at_k: double
child 3, majority_at_k: double
child 31, 32: struct<k: int64, expected_tokens: double, pass_at_k: double, majority_at_k: double>
child 0, k: int64
child 1, expected_tokens: double
child 2, pass_at_k: double
child 3, majority_at_k: double
aggregate_by_k_doc: string
rollout_index: int64
correct: bool
completion: string
label: string
problem_key: string
committed: bool
output_tokens: int64
hit_token_cap: bool
finish_reason: string
steer: string
to
{'problem_key': Value('string'), 'rollout_index': Value('int64'), 'arm': Value('string'), 'steer': Value('string'), 'label': Value('string'), 'committed': Value('bool'), 'correct': Value('bool'), 'hit_token_cap': Value('bool'), 'finish_reason': Value('string'), 'output_tokens': Value('int64'), 'max_tokens_used': Value('int64'), 'completion': Value('string')}
because column names don't match
The above exception was the direct cause of the following exception:
Traceback (most recent call last):
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 1369, in compute_config_parquet_and_info_response
parquet_operations, partial, estimated_dataset_info = stream_convert_to_parquet(
~~~~~~~~~~~~~~~~~~~~~~~~~^
builder, max_dataset_size_bytes=max_dataset_size_bytes
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
)
^
File "/src/services/worker/src/worker/job_runners/config/parquet_and_info.py", line 948, in stream_convert_to_parquet
builder._prepare_split(split_generator=splits_generators[split], file_format="parquet")
~~~~~~~~~~~~~~~~~~~~~~^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
File "/usr/local/lib/python3.14/site-packages/datasets/builder.py", line 1694, in _prepare_split
for job_id, done, content in self._prepare_split_single(
~~~~~~~~~~~~~~~~~~~~~~~~~~^
gen_kwargs=gen_kwargs, job_id=job_id, **_prepare_split_args
^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^^
):
^
File "/usr/local/lib/python3.14/site-packages/datasets/builder.py", line 1880, in _prepare_split_single
raise DatasetGenerationError("An error occurred while generating the dataset") from e
datasets.exceptions.DatasetGenerationError: An error occurred while generating the datasetNeed help to make the dataset viewer work? Make sure to review how to configure the dataset viewer, and open a discussion for direct support.
problem_key string | rollout_index int64 | arm string | steer string | label string | committed bool | correct bool | hit_token_cap bool | finish_reason string | output_tokens int64 | max_tokens_used int64 | completion string |
|---|---|---|---|---|---|---|---|---|---|---|---|
aime2024_0 | 0 | none | base | run | false | false | false | stop | 2 | 7,168 | |
aime2024_0 | 1 | none | base | run | false | false | false | stop | 2 | 7,168 | |
aime2024_0 | 2 | none | base | run | false | false | false | stop | 487 | 7,168 | To find the number of minutes the walk takes Aya, including the $t$ minutes spent in the coffee shop, we need to determine the value of $t$ first.
Let's find the value of $t$ by setting up two equations based on the given information:
1. When Aya walks at a constant speed of $s$ kilometers per hour, the walk takes h... |
aime2024_0 | 3 | none | base | run | true | false | false | stop | 696 | 7,168 | The problem asks for the number of minutes the walk takes Aya when she walks at a speed of $s+\frac{1}{2}$ kilometers per hour, including the time spent in the coffee shop.
Let the distance of the walk be $d$ kilometers.
Let the time taken to walk $d$ kilometers at a constant speed of $s$ kilometers per hour be $t$ ho... |
aime2024_0 | 4 | none | base | run | false | false | false | stop | 4 | 7,168 | $8$ |
aime2024_0 | 5 | none | base | run | true | false | false | stop | 556 | 7,168 | Let $s$ be the speed in kilometers per hour, and let $t$ be the time in minutes that Aya spends in the coffee shop. We are given the following information:
1. When Aya walks at a speed of $s$ kilometers per hour, the walk takes her 4 hours, including $t$ minutes spent in the coffee shop. This means that the distance ... |
aime2024_0 | 6 | none | base | run | true | false | false | stop | 415 | 7,168 | Let $t$ be the number of minutes spent in the coffee shop. The total time for the walk is $4$ hours and $t$ minutes when walking at a constant speed of $s$ kilometers per hour. This is equal to $4+\frac{t}{60}$ hours. The total time for the walk is $2$ hours and $24$ minutes when walking at a constant speed of $s+2$ k... |
aime2024_0 | 7 | none | base | run | false | false | false | stop | 319 | 7,168 | We are given that Aya walks at a constant speed of $s$ kilometers per hour and the walk takes her 4 hours, including $t$ minutes spent in the coffee shop. This means that the distance she walks is $4s$ kilometers and the total time is $4+\frac{t}{60}$ hours. Therefore, we have the equation $4s=4(4+\frac{t}{60})$. Simp... |
aime2024_0 | 8 | none | base | run | false | false | false | stop | 5 | 7,168 | $6t$ |
aime2024_0 | 9 | none | base | run | true | false | false | stop | 261 | 7,168 | Let $x$ be the number of minutes that Aya spends in the coffee shop. Then, the number of hours that Aya spends walking is given by $\frac{9}{s} - \frac{x}{60}$ for $s = 9$ and $\frac{9}{s+2} - \frac{x}{60}$ for $s = 9+2$. We are given that these expressions are equal, so we can set them equal to each other and solve f... |
aime2024_0 | 10 | none | base | run | true | false | false | stop | 530 | 7,168 | We will solve the problem by using the given information and setting up equations based on the time taken for the walk and the time spent in the coffee shop.
Let $t$ be the number of minutes Aya spends in the coffee shop. We need to find the total time for the walk, including the time spent in the coffee shop.
First... |
aime2024_0 | 11 | none | base | run | false | false | true | length | 7,168 | 7,168 | The distance of the walk is $9$ kilometers. The walk takes 4 hours at a speed of $s$ kilometers per hour, including $t$ minutes spent in the coffee shop. Therefore, $s=9/4=2.25$ kilometers per hour. The walk takes 2 hours and 24 minutes at a speed of $s+2=4.25$ kilometers per hour, including $t$ minutes spent in the c... |
aime2024_0 | 12 | none | base | run | false | false | false | stop | 422 | 7,168 | 1. Find $s$ and $t$.
2. Find the walk time at $s+\frac{1}{2}$ km/h.
3. Find the walk time including $t$ minutes.
4. Add the time spent in the coffee shop.
1. We have $9=s\cdot 4+t$ and $9=(s+2)\cdot 2+24+t$.
2. From the first equation, $s=\frac{9-24}{4}=-3$.
3. From the second equation, $s+2=\frac{9-24}{2-2}=-3$.
4. ... |
aime2024_0 | 13 | none | base | run | true | false | false | stop | 328 | 7,168 | First, we convert the given times into hours. When Aya walks at a constant speed of $s$ kilometers per hour, the walk takes her $4$ hours, including $t$ minutes spent in the coffee shop. Since there are $60$ minutes in an hour, we have $t = 60(4 - \frac{t}{60}) = 240 - t$ minutes. When Aya walks at a constant speed of... |
aime2024_0 | 14 | none | base | run | false | false | false | stop | 37 | 7,168 | $8$ hours, 24 minutes
Reason: The walk takes 8 hours, 24 minutes when walking $s+\frac{1}{2}$ kilometers per hour. |
aime2024_0 | 15 | none | base | run | true | false | false | stop | 206 | 7,168 | We know that $t$ is an integer. Then, by the first condition, $s$ is an integer. We also know that $t$ is a multiple of 15. We can write $t=15k$ for some integer $k$.
Substituting this into the second condition, we get $s+2=3(15k-1)$, which implies $s=45k-5$.
Substituting this into the first condition, we get $s=2(15k... |
aime2024_1 | 0 | none | base | run | false | false | false | stop | 260 | 7,168 | We know that the tangents to a circle at two points are perpendicular. So, $\angle ABD = 90^{\circ}$ and $\angle ACD = 90^{\circ}$. Also, $\angle APB = \angle ABD$ and $\angle APC = \angle ACD$. Since $\angle APB + \angle APC = \angle BAC$, we have $\angle APB = \angle BAC$ and $\angle APC = \angle BAC$. Therefore, $\... |
aime2024_1 | 1 | none | base | run | false | false | false | stop | 4 | 7,168 | $9$ |
aime2024_1 | 2 | none | base | run | true | false | false | stop | 186 | 7,168 | The tangent to a circle at a point is perpendicular to the radius at that point. Therefore, $\angle ABP = \angle CBP = 90^\circ$. Since $\angle ABC = \angle APB + \angle CBP$, $\angle ABC = \angle APB + 90^\circ$. Since $\angle APB + \angle ABC = 180^\circ$, $\angle APB = 90^\circ$. Therefore, $\triangle APB$ is a rig... |
aime2024_1 | 3 | none | base | run | false | false | true | length | 7,168 | 7,168 | The problem gives us a triangle $ABC$ inscribed in a circle $\omega$. The tangents to $\omega$ at $B$ and $C$ intersect at point $D$. The line $AD$ intersects $\omega$ at point $P$. We are given that $AB=5$, $BC=9$, and $AC=10$, and we are asked to find the length of $AP$ as a fraction $\frac{m}{n}$, where $m$ and $n$... |
aime2024_1 | 4 | none | base | run | true | false | false | stop | 339 | 7,168 |
We begin by noting that since $\overline{AD}$ is tangent to $\omega$ at $B$, we have that $\overline{DB} \perp \overline{AD}$. Also, since $\overline{AD}$ is tangent to $\omega$ at $C$, we have that $\overline{CD} \perp \overline{AD}$. Hence $\overline{DB} \parallel \overline{CD}$.
Now let $\omega$ be the circumc... |
aime2024_1 | 5 | none | base | run | true | false | false | stop | 505 | 7,168 |
Let $\omega$ be the circle with center $O$ and radius $r$. We know that $AB=5$, $BC=9$, and $AC=10$. We are given that $AD$ is the tangent to $\omega$ at $B$, and $\overline{AD}$ intersects $\omega$ at $P$. We are asked to find $AP$.
Since $AD$ is the tangent to $\omega$ at $B$, we know that $AB^2 = OB^2 - r^2$ (Py... |
aime2024_1 | 6 | none | base | run | true | false | false | stop | 298 | 7,168 | Let $\omega$ be the circle with center $O$ and radius $r$. Since $AB = 5$, $BC = 9$, and $AC = 10$, we have $AB + BC = 14$, so $r = \frac{1}{2}(AB + BC) = \frac{1}{2}(14) = 7$. We can find the coordinates of $O$ by noting that $O$ is the midpoint of the chord $BC$, so $O = (0, 0)$, and $O = (0, 7)$. Since $AB = 5$, we... |
aime2024_1 | 7 | none | base | run | false | false | false | stop | 4,039 | 7,168 | Let $O$ be the center of $\omega$. Then $\angle AOB=\angle AOC=90^{\circ}$. We have $AP=BP$ and $CP$. Let $\angle PAB=\angle PBA=\alpha$ and $\angle PCA=\angle PCB=\beta$. Then $\angle BAP=90^\circ-\alpha$ and $\angle CAP=90^\circ-\beta$. So $\angle AOP=90^\circ-\alpha-\beta$. Since $\angle AOB=\angle AOC=90^\circ$, w... |
aime2024_1 | 8 | none | base | run | true | false | false | stop | 694 | 7,168 | $m+n=31$
### Backward Chain
Our final goal is to determine the value of $m + n$ where $AP = \frac{m}{n}$, with $m$ and $n$ coprime. To reach this, we need to know the exact length of $AP$.
**Immediate Sub-goal:** Find the length of $AP$.
To do this, we need the coordinates of $A$, $P$, and the circle’s equation. ... |
aime2024_1 | 9 | none | base | run | true | false | false | stop | 690 | 7,168 | We start by drawing a diagram and computing some relevant lengths. Let $O$ denote the center of $\omega$, and let $O'$ denote the center of the circle with diameter $\overline{BC}$. We note that $\overline{O'B} = \overline{OC'} = \frac{1}{2} BC = \frac{9}{2}$, and we have $\overline{O'B} \perp \overline{O'C'}$ and $\o... |
aime2024_1 | 10 | none | base | run | true | false | false | stop | 194 | 7,168 | Let $O$ be the center of $\omega$. Since $\overline{AD}$ is tangent to $\omega$, $\overline{AD}$ is perpendicular to $\overline{OP}$, and $OD = OP$.
We can use Ptolemy's theorem to find that $BP \cdot CD = AB \cdot CD + BC \cdot AD$. Since $\overline{AD}$ is tangent to $\omega$, we can conclude that $AD = \frac{AB \c... |
aime2024_1 | 11 | none | base | run | false | false | true | length | 7,168 | 7,168 | The problem asks for the length of the segment $AP$ where $P$ is the intersection of the line $AD$ with the circle $\omega$.
First, let's find the length of the tangent segment $BD$. We can use the formula for the length of a tangent segment to a circle given the length of the chord $BC$ and the distance from the cen... |
aime2024_1 | 12 | none | base | run | false | false | true | length | 7,168 | 7,168 | Let $M$ be the midpoint of $BC$. We want to show that $AM$ is perpendicular to $AD$.
We know that $AM$ is the angle bisector of $\angle BAC$. Therefore, $AM$ is the perpendicular bisector of $BC$.
Since $AM$ is the perpendicular bisector of $BC$, $AM$ is also the angle bisector of $\angle BAC$.
Therefore, $AM$ is the ... |
aime2024_1 | 13 | none | base | run | true | false | false | stop | 495 | 7,168 | Let's first find the length of the tangent from $A$ to $\omega$. Let $E$ be the point of tangency, and let $O$ be the center of $\omega$. Then, $OE$ is perpendicular to $AB$, so $OE = \frac{AB^2}{2} = \frac{25}{2}$.
Now, since $\triangle ADE$ is a right triangle, we have $\angle ADE = 90^\circ$. Therefore, $\angle AE... |
aime2024_1 | 14 | none | base | run | false | false | false | stop | 320 | 7,168 | Let $O$ be the center of the circle $\omega$. Then $OP$ is a radius of the circle, and $O$ is the midpoint of $AP$.
We are given that $AB = 5$, $BC = 9$, and $AC = 10$. Let $O = (0,0)$. Let $P = (p,0)$ be the midpoint of $AP$.
We have $OP^2 = p^2 + 0^2 = p^2$ and $AP^2 = (p-0)^2 + (0-0)^2 = p^2$. Thus, $OP^2 = AP^2$... |
aime2024_1 | 15 | none | base | run | false | false | true | length | 7,168 | 7,168 | 1. Draw triangle $ABC$ with $AB=5$, $BC=9$, $AC=10$.
2. Draw tangents to $\omega$ at $B$ and $C$.
3. Let $D$ be the intersection of tangents at $B$ and $C$.
4. Let $\overline{AD}$ intersect $\omega$ at $P$.
5. $\overline{AB}$ and $\overline{AC}$ are tangents to $\omega$ at $B$ and $C$ respectively, so $\overline{AB} \... |
aime2024_2 | 0 | none | base | run | false | false | true | length | 7,168 | 7,168 | Let $f(n)$ denote the probability that the octagon can be rotated so that all of the blue vertices end up at positions where there were originally red vertices. We want to find $f(8)$, the probability that the octagon can be rotated so that all of the blue vertices end up at positions where there were originally red v... |
aime2024_2 | 1 | none | base | run | true | false | false | stop | 45 | 7,168 | The key observation is that there are two possible rotations that map blue vertices to red vertices, so the probability is $\boxed{\dfrac{2}{8}}$. The final answer is $2+8=10$. |
aime2024_2 | 2 | none | base | run | true | false | false | stop | 47 | 7,168 | The probability that the octagon can be rotated so that all blue vertices end up in red positions is $\boxed{1}$, so the answer is $1+1=\boxed{2}$.
The answer is: 2 |
End of preview.
rollouts-mt-question-okay — evaluation rollouts
Model: amil-sophie-kevin/olmo3-7b-mt-question_okay — Olmo-3-7B mid-trained 10B tokens from
stage-1 step 4769 on the question mix (chicken_all plus every paragraph-initial Question:
renamed Okay,, so Okay opens a question and never a trace). Protocol: 32 rollouts per problem
(two seeded batches of 16), temperature 0.6, top-p 0.95, budget 7,168 generated tokens (8,192
context), seed 20260819, full problem set of each benchmark. Prompts and grader: the paper's
repository (sophicle/reason). Rollouts generated with vLLM 0.29.0 (the pinned 0.27.1 has no
wheel for the partner cluster's architecture); the MATH-500 gate matched the 0.27.1 references
within +0.007. HumanEval is execution-graded (run_execgraded/). Rollout jsonl files are kept
as written under <prompt>/<benchmark>/run/; cell summaries (with aggregate_by_k) are at
<prompt>/<benchmark>/summary/<arm>.json — note summaries for HumanEval live under
<prompt>/humaneval_execgraded/summary/.
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