task_id stringclasses 1
value | language stringclasses 4
values | problem stringlengths 144 1.08k | correct_code stringlengths 35 615 | correct_test_list listlengths 3 3 | incorrect_test stringlengths 23 133 | og_problem stringlengths 125 410 | og_correct_code stringlengths 37 473 | og_correct_test_list listlengths 3 3 | og_incorrect_test stringlengths 20 43 |
|---|---|---|---|---|---|---|---|---|---|
lua | Write a Lua function named `is_not_prime` that takes an integer as input and returns `true` if the number is not a prime number, otherwise `false`. Here's what I've got so far, but it's not working:
```lua
function is_not_prime(n)
-- incomplete logic here
return false
end
```
Expect `true` for `is_not_prime(10)`.... | function is_not_prime(n)
if n <= 1 then return true end
for i = 2, math.sqrt(n) do
if n % i == 0 then
return true
end
end
return false
end | [
"assert(is_not_prime(2) == false)",
"assert(is_not_prime(10) == true)",
"assert(is_not_prime(35) == true)"
] | assert(is_not_prime(2) == true) | Create a function named `is_not_prime` that takes an integer as input and returns `True` if the number is not a prime number, otherwise returns `False`. This function should assess the primality of the given integer. | import math
def is_not_prime(n):
result = False
for i in range(2,int(math.sqrt(n)) + 1):
if n % i == 0:
result = True
return result | [
"assert is_not_prime(2) == False",
"assert is_not_prime(10) == True",
"assert is_not_prime(35) == True"
] | assert is_not_prime(2) == True | |
javascript | Implement a JavaScript function named `findRotations` that determines the smallest number of rotations required for a given string to return to its original form. For example, if you input "ab", the function should return 2. If the input is "abc", expect the result to be 3. When given the string "aaaa", a correct imple... | function findRotations(str) {
let tmp = str + str;
let n = str.length;
for (let i = 1; i <= n; i++) {
let substring = tmp.slice(i, i + n);
if (str === substring) {
return i;
}
}
return n;
} | [
"assert.strictEqual(findRotations(\"aaaa\"), 1);",
"assert.strictEqual(findRotations(\"ab\"), 2);",
"assert.strictEqual(findRotations(\"abc\"), 3);"
] | assert.strictEqual(findRotations("aaaa"), 4); | Implement a function called `find_Rotations` that takes a single string as input and returns the smallest number of rotations needed for the string to match its original form. A rotation is defined as moving the first character to the end of the string. | def find_Rotations(str):
tmp = str + str
n = len(str)
for i in range(1,n + 1):
substring = tmp[i: i+n]
if (str == substring):
return i
return n | [
"assert find_Rotations(\"aaaa\") == 1",
"assert find_Rotations(\"ab\") == 2",
"assert find_Rotations(\"abc\") == 3"
] | assert find_Rotations("aaaa") == 4 | |
python | In Python, create a function called `remove_occ` that accepts two arguments: a string and a character. This function should remove the first and last occurrence of the specified character from the string and return the modified string. Let's see how the function should behave:
```python
# For the input string "abcda" ... | def remove_occ(s, ch):
for i in range(len(s)):
if s[i] == ch:
s = s[0:i] + s[i+1:]
break
for i in range(len(s) - 1, -1, -1):
if s[i] == ch:
s = s[0:i] + s[i+1:]
break
return s
| [
"assert remove_occ(\"hello\", \"l\") == \"heo\"",
"assert remove_occ(\"abcda\", \"a\") == \"bcd\"",
"assert remove_occ(\"PHP\", \"P\") == \"H\""
] | assert remove_occ("hello", "l") == "helxo" | Write a function `remove_Occ` that takes two arguments, a string and a character, and removes the first and last occurrence of that character from the string. The function should then return the modified string.
Function Signature: `def remove_Occ(s: str, ch: str) -> str` | def remove_Occ(s,ch):
for i in range(len(s)):
if (s[i] == ch):
s = s[0 : i] + s[i + 1:]
break
for i in range(len(s) - 1,-1,-1):
if (s[i] == ch):
s = s[0 : i] + s[i + 1:]
break
return s | [
"assert remove_Occ(\"hello\",\"l\") == \"heo\"",
"assert remove_Occ(\"abcda\",\"a\") == \"bcd\"",
"assert remove_Occ(\"PHP\",\"P\") == \"H\""
] | assert remove_Occ("hello","l") == "helxo" | |
javascript | In JavaScript, implement a function called `findVolume` to calculate the volume of a triangular prism. It should take three parameters: the base and height of the triangle, and the length of the prism. Here are the expectations:
```js
assert.strictEqual(findVolume(3,2,2), 6);
assert.strictEqual(findVolume(1,2,1), 1);
a... | function findVolume(length, base, height) {
return Math.floor((length * base * height) / 2);
} | [
"assert.strictEqual(findVolume(10,8,6), 240);",
"assert.strictEqual(findVolume(3,2,2), 6);",
"assert.strictEqual(findVolume(1,2,1), 1);"
] | assert.strictEqual(findVolume(10,8,6), 300); | Create a function named `find_Volume` that calculates the volume of a triangular prism using the area of the triangular base and the length of the prism. The function should accept three arguments: `base`, `height` of the triangle, and `length` of the prism, and return the volume as an integer. | def find_Volume(l,b,h) :
return ((l * b * h) / 2) | [
"assert find_Volume(10,8,6) == 240",
"assert find_Volume(3,2,2) == 6",
"assert find_Volume(1,2,1) == 1"
] | assert find_Volume(10,8,6) == 300 | |
javascript | In JavaScript, please write a function called `squarePerimeter`. This function should take an integer representing the length of one side of a square and return another integer — the perimeter of the square. Typically, the perimeter is calculated as four times the length of the side. Consider the following cases to gui... | function squarePerimeter(sideLength) {
return 4 * sideLength;
} | [
"assert.strictEqual(squarePerimeter(10), 40); // 10 side length results in perimeter 40",
"assert.strictEqual(squarePerimeter(5), 20); // 5 side length results in perimeter 20",
"assert.strictEqual(squarePerimeter(4), 16); // 4 side length results in perimeter 16"
] | assert.strictEqual(squarePerimeter(10), 45); // Incorrect perimeter for side length 10 | Create a function named `square_perimeter` that takes an integer representing the length of one side of a square and returns an integer representing the perimeter of the square. The perimeter is calculated as four times the length of a side. | def square_perimeter(a):
perimeter=4*a
return perimeter | [
"assert square_perimeter(10)==40",
"assert square_perimeter(5)==20",
"assert square_perimeter(4)==16"
] | assert square_perimeter(10)==45 | |
ruby | Hello! Could you help by writing a Ruby method called `is_woodall`? This method needs to check if a given integer is a Woodall number. Oh, by the way, a Woodall number is one of the form n * 2^n - 1 for some integer n. For example, when checking the number 254, it should return `false`. Similarly, 200 should also retur... |
def is_woodall(x)
return false if x % 2 == 0
return true if x == 1
x += 1
p = 0
while x % 2 == 0
x /= 2
p += 1
return true if p == x
end
false
end
| [
"raise 'fail' unless is_woodall(383) == true",
"raise 'fail' unless is_woodall(254) == false",
"raise 'fail' unless is_woodall(200) == false"
] | raise 'fail' unless is_woodall(383) == false | Write a function named `is_woodall` that checks if a given integer is a Woodall number, where a Woodall number is defined as n * 2^n - 1 for some integer n. The function should return True if the number is a Woodall number, and False otherwise. | def is_woodall(x):
if (x % 2 == 0):
return False
if (x == 1):
return True
x = x + 1
p = 0
while (x % 2 == 0):
x = x/2
p = p + 1
if (p == x):
return True
return False | [
"assert is_woodall(383) == True",
"assert is_woodall(254) == False",
"assert is_woodall(200) == False"
] | assert is_woodall(383) == False | |
python | Please create a Python function named `binary_to_decimal` that takes a binary integer input and returns its decimal equivalent. For example, when calling `binary_to_decimal(1011)`, expect 11 as the result, and when calling `binary_to_decimal(1101101)`, expect a result of 109. If you call `binary_to_decimal(100)`, it, i... | def binary_to_decimal(binary):
binary1 = binary
decimal, i, n = 0, 0, 0
while(binary != 0):
dec = binary % 10
decimal = decimal + dec * pow(2, i)
binary = binary // 10
i += 1
return decimal | [
"assert binary_to_decimal(100) == 4",
"assert binary_to_decimal(1011) == 11",
"assert binary_to_decimal(1101101) == 109"
] | assert binary_to_decimal(100) == 50 | Write a function named `binary_to_decimal` that takes an integer input representing a binary number and returns its decimal (base-10) integer equivalent. The input is assumed to be an integer where each digit is either 0 or 1, corresponding to binary format. | def binary_to_decimal(binary):
binary1 = binary
decimal, i, n = 0, 0, 0
while(binary != 0):
dec = binary % 10
decimal = decimal + dec * pow(2, i)
binary = binary//10
i += 1
return (decimal) | [
"assert binary_to_decimal(100) == 4",
"assert binary_to_decimal(1011) == 11",
"assert binary_to_decimal(1101101) == 109"
] | assert binary_to_decimal(100) == 50 | |
ruby | Hi there! Could you pls help me write a Ruby method named `find_product`? This fucntion shoudl calculate the product of all the unique elements in a list called `lst` with a given length. For example, for the list `[1, 2, 3, 1, 1]` with a length of 5, it should return the value 6. Also, for another list `[1,1,4,5,6]` w... | def find_product(lst, length)
lst.sort!
prod = 1
(0...length).each do |i|
prod *= lst[i] if i == 0 || lst[i] != lst[i - 1]
end
prod
end | [
"raise 'fail' unless find_product([1,1,2,3],4) == 6",
"raise 'fail' unless find_product([1,2,3,1,1],5) == 6",
"raise 'fail' unless find_product([1,1,4,5,6],5) == 120"
] | raise 'fail' unless find_product([1,1,2,3],4) == 10 | Create a function `find_Product(lst, length)` that returns the product of all the unique elements in the list `lst` of size `length`. Each element should be factored into the product only once, regardless of its frequency in the list. | def find_Product(arr,n):
arr.sort()
prod = 1
for i in range(0,n,1):
if (arr[i - 1] != arr[i]):
prod = prod * arr[i]
return prod; | [
"assert find_Product([1,1,2,3],4) == 6",
"assert find_Product([1,2,3,1,1],5) == 6",
"assert find_Product([1,1,4,5,6],5) == 120"
] | assert find_Product([1,1,2,3],4) == 10 | |
javascript | In JavaScript, create a function named `binomialCoeff` to calculate binomial coefficients. Provide results as integers. For `binomialCoeff(4, 3)`, it should return 4. For `binomialCoeff(3, 2)`, it should return 3. And the the result for `binomialCoeff(5, 2)` must be 15. | function binomialCoeff(n, k) {
if (k > n) {
return 0;
}
if (k === 0 || k === n) {
return 1;
}
return binomialCoeff(n - 1, k - 1) + binomialCoeff(n - 1, k);
} | [
"assert.strictEqual(binomialCoeff(5, 2), 10);",
"assert.strictEqual(binomialCoeff(4, 3), 4);",
"assert.strictEqual(binomialCoeff(3, 2), 3);"
] | assert.strictEqual(binomialCoeff(5, 2), 15); | Implement a function named `binomial_Coeff(n, k)` that calculates the binomial coefficient for given values `n` and `k`, where `n` and `k` are integers. The function should return the result as an integer. | def binomial_Coeff(n,k):
if k > n :
return 0
if k==0 or k ==n :
return 1
return binomial_Coeff(n-1,k-1) + binomial_Coeff(n-1,k) | [
"assert binomial_Coeff(5,2) == 10",
"assert binomial_Coeff(4,3) == 4",
"assert binomial_Coeff(3,2) == 3"
] | assert binomial_Coeff(5,2) == 15 | |
lua | Hey there! So, I'm working on a little project that's kind of like a code interview prep. I could really use your help! I need to create a Lua fucntion called `max_prime_factors`. The goal is to find the largest prime factor of a given integer. It's like unraveling the mysteries within numbers, pretty cool huh? 😊
Her... | function max_prime_factors(n)
local maxPrime = -1
while n % 2 == 0 do
maxPrime = 2
n = n // 2
end
for i = 3, math.sqrt(n), 2 do
while n % i == 0 do
maxPrime = i
n = n / i
end
end
if n > 2 then
maxPrime = n
end
return maxPrim... | [
"assert(max_prime_factors(15) == 5)",
"assert(max_prime_factors(6) == 3)",
"assert(max_prime_factors(2) == 2)"
] | assert(max_prime_factors(15) == 7) | Name of the function: `max_Prime_Factors`
Description: Write a Python function named `max_Prime_Factors` that accepts an integer and returns the largest prime factor of that integer.
The function has the following structure: `max_Prime_Factors(n: int) -> int`. | import math
def max_Prime_Factors (n):
maxPrime = -1
while n%2 == 0:
maxPrime = 2
n >>= 1
for i in range(3,int(math.sqrt(n))+1,2):
while n % i == 0:
maxPrime = i
n = n / i
if n > 2:
maxPrime = n
return int(maxPrime) | [
"assert max_Prime_Factors(15) == 5",
"assert max_Prime_Factors(6) == 3",
"assert max_Prime_Factors(2) == 2"
] | assert max_Prime_Factors(15) == 7 | |
python | I have a problem. I need a Python function that converts a decimal number into its binary representation, but the output should be an integer, not a string. The function should be named `decimal_to_binary` and takes a single integer as input. Here's what I've tried so far, but I'm not sure if this is correct:
For inpu... | def decimal_to_binary(N):
B_Number = 0
cnt = 0
while (N != 0):
rem = N % 2
c = pow(10,cnt)
B_Number += rem*c
N //= 2
cnt += 1
return B_Number | [
"assert decimal_to_binary(10) == 1010",
"assert decimal_to_binary(1) == 1",
"assert decimal_to_binary(20) == 10100"
] | assert decimal_to_binary(10) == 1111 | Write a Python function named `decimal_To_Binary` that takes an integer as an input and returns its corresponding binary representation as an integer. Ensure the function does not return binary as a string, but as an integer. | def decimal_To_Binary(N):
B_Number = 0
cnt = 0
while (N != 0):
rem = N % 2
c = pow(10,cnt)
B_Number += rem*c
N //= 2
cnt += 1
return B_Number | [
"assert decimal_To_Binary(10) == 1010",
"assert decimal_To_Binary(1) == 1",
"assert decimal_To_Binary(20) == 10100"
] | assert decimal_To_Binary(10) == 1111 | |
lua | ```lua
assert(find_missing({1,3,4,5},4) == 2)
assert(find_missing({1,2,3,5,6,7},5) == 4)
assert(find_missing({1,2,3,5},4) == 6)
```
Hi there, could you please help me write a Lua fucntion called `find_missing`? It should take a sorted integer array and an expected size as inputs, and return the first missing integer. T... | function find_missing(ar, N)
local l = 0
local r = N - 1
while l <= r do
local mid = math.floor((l + r) / 2)
if ar[mid + 1] ~= mid + 1 and ar[mid] == mid then
return mid + 1
elseif ar[mid + 1] ~= mid + 1 then
r = mid - 1
else
l = mid + 1
... | [
"assert(find_missing({1,2,3,5},4) == 4)",
"assert(find_missing({1,3,4,5},4) == 2)",
"assert(find_missing({1,2,3,5,6,7},5) == 4)"
] | assert(find_missing({1,2,3,5},4) == 6) | Rephrased Coding Problem: Write a Python function `find_missing` that identifies the first missing number in a sorted integer array, where the array should contain consecutive integers up to a given size. The function takes an array and its expected size as inputs and returns the first missing integer.
Function Signat... | def find_missing(ar,N):
l = 0
r = N - 1
while (l <= r):
mid = (l + r) / 2
mid= int (mid)
if (ar[mid] != mid + 1 and ar[mid - 1] == mid):
return (mid + 1)
elif (ar[mid] != mid + 1):
r = mid - 1
else:
l = mid + 1
... | [
"assert find_missing([1,2,3,5],4) == 4",
"assert find_missing([1,3,4,5],4) == 2",
"assert find_missing([1,2,3,5,6,7],5) == 4"
] | assert find_missing([1,2,3,5],4) == 6 | |
ruby | Need a Ruby method `test_distinct` to check if elements in a list are all unique. Here's what I've got so far, but it's not working:
```ruby
# def test_distinct(data)
# data.all? { |e| data.count(e) == 1 }
# end
```
Use these examples: `test_distinct([2,4,5,5,7,9])` should return `false`. `test_distinct([1,2,3])` s... | def test_distinct(data)
data.uniq.length == data.length
end | [
"raise 'fail' unless test_distinct([1,5,7,9]) == true",
"raise 'fail' unless test_distinct([2,4,5,5,7,9]) == false",
"raise 'fail' unless test_distinct([1,2,3]) == true"
] | raise 'fail' unless test_distinct([1,5,7,9]) == false | Write a Python function named `test_distinct` that checks if all elements in a given list of integers are unique. The function should take a list of integers as input and return a boolean value: `True` if all elements are unique, otherwise `False`. | def test_distinct(data):
if len(data) == len(set(data)):
return True
else:
return False; | [
"assert test_distinct([1,5,7,9]) == True",
"assert test_distinct([2,4,5,5,7,9]) == False",
"assert test_distinct([1,2,3]) == True"
] | assert test_distinct([1,5,7,9]) == False | |
python | Hello! I would be really grateful if you could help me write a Python function named `odd_bit_set_number`. This function should take a single integer as input and return an integer where all the odd-numbered bit positions (1, 3, 5, ...) are set to 1. As some examples, if you provide the input 20, you should expect the ... | def odd_bit_set_number(n):
count = 0;res = 0;temp = n
while temp > 0:
if count % 2 == 0:
res |= (1 << count)
count += 1
temp >>= 1
return (n | res) | [
"assert odd_bit_set_number(10) == 15",
"assert odd_bit_set_number(20) == 21",
"assert odd_bit_set_number(30) == 31"
] | assert odd_bit_set_number(10) == 29 | Write a Python function named `odd_bit_set_number` that takes a single integer as an input and returns an integer where all the odd-numbered bit positions (1, 3, 5, ...) have been set to 1. | def odd_bit_set_number(n):
count = 0;res = 0;temp = n
while temp > 0:
if count % 2 == 0:
res |= (1 << count)
count += 1
temp >>= 1
return (n | res) | [
"assert odd_bit_set_number(10) == 15",
"assert odd_bit_set_number(20) == 21",
"assert odd_bit_set_number(30) == 31"
] | assert odd_bit_set_number(10) == 29 | |
javascript | Could you help me write a JavaScript function called `parallelogramArea`? This function should calculate the area of a parallelogram by taking two integers, `base` and `height`, as arguments. Heres what ive got so far but its not working:
```javascript
function parallelogramArea(base, height) {
return base;
}
```
F... | function parallelogramArea(base, height) {
return base * height;
} | [
"assert.strictEqual(parallelogramArea(10, 20), 200);",
"assert.strictEqual(parallelogramArea(15, 20), 300);",
"assert.strictEqual(parallelogramArea(8, 9), 72);"
] | assert.strictEqual(parallelogramArea(10, 20), 300); | Write a function named `parallelogram_area` that calculates the area of a parallelogram given its base and height. The function should take two integer inputs: `base` and `height`, and return an integer representing the area. | def parallelogram_area(b,h):
area=b*h
return area | [
"assert parallelogram_area(10,20)==200",
"assert parallelogram_area(15,20)==300",
"assert parallelogram_area(8,9)==72"
] | assert parallelogram_area(10,20)==300 | |
ruby | Hello there! I'd love some assistance in creating a Ruby method named `find_max_num`. This method should accept an array of digits along with the length of that array, and it should return the largest integer possible by rearranging those digits. For instance, if you pass in `[4,5,6,1]` with length `4`, it should yield... | def find_max_num(arr, n)
arr.sort!.reverse!
num = arr[0]
(1...n).each do |i|
num = num * 10 + arr[i]
end
num
end | [
"raise 'fail' unless find_max_num([1,2,3], 3) == 321",
"raise 'fail' unless find_max_num([4,5,6,1], 4) == 6541",
"raise 'fail' unless find_max_num([1,2,3,9], 4) == 9321"
] | raise 'fail' unless find_max_num([1,2,3], 3) == 123 | Write a function `find_Max_Num` that takes a list of digits and the length of the list as parameters and returns the largest possible integer that can be formed by arranging these digits. The function should have the signature `find_Max_Num(digits: List[int], length: int) -> int`. | def find_Max_Num(arr,n) :
arr.sort(reverse = True)
num = arr[0]
for i in range(1,n) :
num = num * 10 + arr[i]
return num | [
"assert find_Max_Num([1,2,3],3) == 321",
"assert find_Max_Num([4,5,6,1],4) == 6541",
"assert find_Max_Num([1,2,3,9],4) == 9321"
] | assert find_Max_Num([1,2,3],3) == 123 | |
lua | In Lua, let's define a function named `opposite_signs` that takes two integers as input and returns true if they have opposite signs and false otherwise. Heres what ive got so far but its not working:
```lua
function opposite_signs(x, y)
return (x < 0 and y > 0) or (x > 0 and y < 0)
end
```
The function should pa... | function opposite_signs(x, y)
return (x ~ y) < 0
end | [
"assert(opposite_signs(1, -2) == true)",
"assert(opposite_signs(3, 2) == false)",
"assert(opposite_signs(-10, -10) == false)"
] | assert(opposite_signs(1, -2) == false) | Write a function named `opposite_Signs` that takes two integer inputs and returns `True` if they have opposite signs and `False` otherwise. | def opposite_Signs(x,y):
return ((x ^ y) < 0); | [
"assert opposite_Signs(1,-2) == True",
"assert opposite_Signs(3,2) == False",
"assert opposite_Signs(-10,-10) == False"
] | assert opposite_Signs(1,-2) == False | |
javascript | write a js function called `posCount` to count positive integers in a list. it should return 3 for [3,4,5,-1], 4 for [1,2,3,4], and 4 for [1,-2,3,-4]. | function posCount(list) {
let posCount = 0;
for (let num of list) {
if (num >= 0) {
posCount += 1;
}
}
return posCount;
} | [
"assert.strictEqual(posCount([1,-2,3,-4]), 2);",
"assert.strictEqual(posCount([3,4,5,-1]), 3);",
"assert.strictEqual(posCount([1,2,3,4]), 4);"
] | assert.strictEqual(posCount([1,-2,3,-4]), 4); | Create a function named `pos_count` that takes a list of integers as input and returns the count of positive integers in the list. The function signature should be `def pos_count(lst: List[int]) -> int`. | def pos_count(list):
pos_count= 0
for num in list:
if num >= 0:
pos_count += 1
return pos_count | [
"assert pos_count([1,-2,3,-4]) == 2",
"assert pos_count([3,4,5,-1]) == 3",
"assert pos_count([1,2,3,4]) == 4"
] | assert pos_count([1,-2,3,-4]) == 4 | |
python | hi, could you write a python function called `dif_square`? it should take one integer and return true if the number can be expressed as a difference of squares of two integers, otherwise false. here are some examples: for the input 10, it should return false. for 15, it should return true. but for 5, it should return f... | def dif_square(n):
if (n % 4 != 2):
return True
return False | [
"assert dif_square(5) == True",
"assert dif_square(10) == False",
"assert dif_square(15) == True"
] | assert dif_square(5) == False | Write a Python function named `dif_Square` that takes a single integer input and returns `True` if the number can be represented as a difference of squares of two integers, and `False` otherwise. | def dif_Square(n):
if (n % 4 != 2):
return True
return False | [
"assert dif_Square(5) == True",
"assert dif_Square(10) == False",
"assert dif_Square(15) == True"
] | assert dif_Square(5) == False | |
javascript | Create a JavaScript function called `countSquares` that computes the number of square sub-regions within a rectangle. This function takes two integer parameters: the width and the height of the rectangle. For example, `countSquares(2, 2)` should return 5 as there are 5 square sub-regions. Similarly, if you pass `countS... | function countSquares(m, n) {
if (n < m) {
let temp = m;
m = n;
n = temp;
}
return Math.floor((m * (m + 1) * (2 * m + 1) / 6 + (n - m) * m * (m + 1) / 2));
} | [
"assert.strictEqual(countSquares(4, 3), 20);",
"assert.strictEqual(countSquares(2, 2), 5);",
"assert.strictEqual(countSquares(1, 1), 1);"
] | assert.strictEqual(countSquares(4, 3), 15); | Create a function named `count_Squares` that takes two integers as inputs, representing the width and height of a rectangle, and returns an integer representing the total number of square sub-regions possible within that rectangle, including all possible sizes. | def count_Squares(m,n):
if(n < m):
temp = m
m = n
n = temp
return ((m * (m + 1) * (2 * m + 1) / 6 + (n - m) * m * (m + 1) / 2)) | [
"assert count_Squares(4,3) == 20",
"assert count_Squares(2,2) == 5",
"assert count_Squares(1,1) == 1"
] | assert count_Squares(4, 3) == 15 | |
javascript | I'm working on a little script to help with my coding interview prep, and I need your help in implementing a JavaScript function called `isDiff`. This function should take an integer as an input and return a boolean value based on whether the absolute difference between the sum of even digits and the sum of odd digits ... | function isDiff(n) {
return n % 11 === 0;
} | [
"assert.strictEqual(isDiff(12345), false);",
"assert.strictEqual(isDiff(1212112), true);",
"assert.strictEqual(isDiff(1212), false);"
] | assert.strictEqual(isDiff(12345), true); | Create a function named `is_Diff` that takes an integer as its input and returns a boolean value. The function should return True if the absolute difference between the sum of even digits and the sum of odd digits in the number is a prime number, otherwise False. | def is_Diff(n):
return (n % 11 == 0) | [
"assert is_Diff (12345) == False",
"assert is_Diff(1212112) == True",
"assert is_Diff(1212) == False"
] | assert is_Diff(12345) == True | |
javascript | Hi there! I'm looking to create a JavaScript function named `countWithOddSetBits`. This function takes a single integer as input and should count how many positive integers up to and including that integer have an odd number of set bits (1s in their binary representation). Heres what ive got so far but its not working:... | function countWithOddSetBits(n) {
if (n % 2 !== 0) {
return (n + 1) / 2;
}
const count = n.toString(2).split('1').length - 1;
let ans = n / 2;
if (count % 2 !== 0) {
ans += 1;
}
return ans;
} | [
"assert.strictEqual(countWithOddSetBits(5), 3);",
"assert.strictEqual(countWithOddSetBits(10), 5);",
"assert.strictEqual(countWithOddSetBits(15), 8);"
] | assert.strictEqual(countWithOddSetBits(5), 7); | Define a function `count_With_Odd_SetBits(n)` that counts how many positive integers up to and including `n` have an odd number of set bits (1s in their binary representation). | def count_With_Odd_SetBits(n):
if (n % 2 != 0):
return (n + 1) / 2
count = bin(n).count('1')
ans = n / 2
if (count % 2 != 0):
ans += 1
return ans | [
"assert count_With_Odd_SetBits(5) == 3",
"assert count_With_Odd_SetBits(10) == 5",
"assert count_With_Odd_SetBits(15) == 8"
] | assert count_With_Odd_SetBits(5) == 7 | |
ruby | Hey there! Could you help me write a Ruby method called `word_len`? This method should take a single string input and return `true` if the length of the string is odd, and `false` if it is even. For example, when `word_len` is given 'great', it should return `true`. Also, if called with 'structure', it should still ret... | def word_len(s)
s = s.split(' ')
s.each do |word|
return true if word.length.odd?
end
false
end | [
"raise 'fail' unless word_len('Hadoop') == false # returns false for even length",
"raise 'fail' unless word_len('great') == true # returns true for odd length",
"raise 'fail' unless word_len('structure') == true # returns true for odd length"
] | raise 'fail' unless word_len('Hadoop') == true # returns true for even length | Write a Python function named `word_len` that takes a single string input and returns `True` if the length of the string is odd, and `False` if it is even. | def word_len(s):
s = s.split(' ')
for word in s:
if len(word)%2!=0:
return True
else:
return False | [
"assert word_len(\"Hadoop\") == False",
"assert word_len(\"great\") == True",
"assert word_len(\"structure\") == True"
] | assert word_len("Hadoop") == True | |
lua | Write a Lua function named `get_char` that processes a single string input. The function should compute the sum of ASCII values of all characters within the input string and return the corresponding character based on the sum modulo 256. Here’s what the function should achieve: When called with the input "gfg", it shou... | function get_char(strr)
local summ = 0
for i = 1, #strr do
summ = summ + (string.byte(strr, i) - string.byte('a') + 1)
end
if (summ % 26 == 0) then
return string.char(string.byte('z'))
else
summ = summ % 26
return string.char(string.byte('a') + summ - 1)
end
end | [
"assert(get_char(\"abc\") == \"f\")",
"assert(get_char(\"gfg\") == \"t\")",
"assert(get_char(\"ab\") == \"c\")"
] | assert(get_char("abc") == "z") | Write a Python function named `get_Char` that takes a single string input, sums the ASCII values of all characters in the string, and returns the character corresponding to the sum modulo 256. The function should return the resulting character as a string. | def get_Char(strr):
summ = 0
for i in range(len(strr)):
summ += (ord(strr[i]) - ord('a') + 1)
if (summ % 26 == 0):
return ord('z')
else:
summ = summ % 26
return chr(ord('a') + summ - 1) | [
"assert get_Char(\"abc\") == \"f\"",
"assert get_Char(\"gfg\") == \"t\"",
"assert get_Char(\"ab\") == \"c\""
] | assert get_Char("abc") == "z" | |
lua | Hey there! Could you help me out by writing a Lua fucntion called `closest_num`? It shoudl take an int as its parameter and return the largest integer that is smaller than the given number. For example, for input 7, it should return 6. Similarly, for an input of 12, the function should return 11. Oh, and there's an int... | function closest_num(n)
return n - 1
end | [
"assert(closest_num(11) == 10)",
"assert(closest_num(7) == 6)",
"assert(closest_num(12) == 11)"
] | assert(closest_num(11) == 9) | Write a function named `closest_num` that takes an integer `n` as input and returns the largest integer that is less than `n`. The function should have the signature `closest_num(n: int) -> int`. | def closest_num(N):
return (N - 1) | [
"assert closest_num(11) == 10",
"assert closest_num(7) == 6",
"assert closest_num(12) == 11"
] | assert closest_num(11) == 9 | |
javascript | ```js
assert.strictEqual(isUndulating("1991"), false);
assert.strictEqual(isUndulating("121"), true);
assert.strictEqual(isUndulating("1212121"), false);
```
In Node.js, write `isUndulating` to determine if a string number alternates between two digits. Expect booleans. | function isUndulating(n) {
if (n.length <= 2) {
return false;
}
for (let i = 2; i < n.length; i++) {
if (n[i - 2] !== n[i]) {
return false;
}
}
return true;
} | [
"assert.strictEqual(isUndulating(\"1212121\"), true);",
"assert.strictEqual(isUndulating(\"1991\"), false);",
"assert.strictEqual(isUndulating(\"121\"), true);"
] | assert.strictEqual(isUndulating("1212121"), false); | Rephrased problem: Write a function `is_undulating` that takes a string representation of a number and checks if the number is undulating, meaning if it alternates between two specific digits throughout the entire string. The function should return a boolean value. | def is_undulating(n):
if (len(n) <= 2):
return False
for i in range(2, len(n)):
if (n[i - 2] != n[i]):
return False
return True | [
"assert is_undulating(\"1212121\") == True",
"assert is_undulating(\"1991\") == False",
"assert is_undulating(\"121\") == True"
] | assert is_undulating("1212121") == False | |
lua | i have two integers, `a` and `b`, and i want to create a lua function called `power` that calculates `a` raised to the power of `b`. for input (2,3), it should return 8. for input (5,5), it should return 3125. for input (3,4), it should return 82. here's what i tried so far. | function power(a, b)
if b == 0 then
return 1
elseif a == 0 then
return 0
elseif b == 1 then
return a
else
return a * power(a, b - 1)
end
end | [
"assert(power(3,4) == 81)",
"assert(power(2,3) == 8)",
"assert(power(5,5) == 3125)"
] | assert(power(3,4) == 82) | Create a function named `power` that takes two integers `a` and `b` as inputs and returns the result of `a` raised to the power of `b`. The function signature should be `def power(a: int, b: int) -> int`. | def power(a,b):
if b==0:
return 1
elif a==0:
return 0
elif b==1:
return a
else:
return a*power(a,b-1) | [
"assert power(3,4) == 81",
"assert power(2,3) == 8",
"assert power(5,5) == 3125"
] | assert power(3,4) == 82 | |
python | I'm attempting to write a Python function called `divisor` which takes an integer `n` and returns the total number of divisors (both prime and non-prime) of the number. I've tried a few approaches, but I'm not sure if I'm on the right track. Here's the behavior I expect: when calling `divisor(12)`, it should return `6`... | def divisor(n):
return len([i for i in range(1, n + 1) if n % i == 0]) | [
"assert divisor(15) == 4",
"assert divisor(12) == 6",
"assert divisor(9) == 3"
] | assert divisor(15) == 7 | Write a function named `divisor` which calculates and returns the number of divisors (both prime and non-prime) of a given positive integer `n`.
Input: integer `n`
Output: integer (number of divisors of `n`) | def divisor(n):
for i in range(n):
x = len([i for i in range(1,n+1) if not n % i])
return x | [
"assert divisor(15) == 4 ",
"assert divisor(12) == 6",
"assert divisor(9) == 3"
] | assert divisor(15) == 7 | |
python | Can you create a Python function called `decimal_to_binary` that converts a non-negative integer into its binary string representation? For example, for an input of 18, the function should return '10010', and for 7, it should return '111'. Additionally, for an input of 8, the function should produce '1001'. Here are so... | def decimal_to_binary(n):
return bin(n).replace("0b","")
| [
"assert decimal_to_binary(8) == '1000'",
"assert decimal_to_binary(18) == '10010'",
"assert decimal_to_binary(7) == '111'"
] | assert decimal_to_binary(8) == '1001' | Write a function named `decimal_to_binary` that takes an integer (decimal number) as input and returns a string representing its binary equivalent. The function should handle non-negative integers. | def decimal_to_binary(n):
return bin(n).replace("0b","") | [
"assert decimal_to_binary(8) == '1000'",
"assert decimal_to_binary(18) == '10010'",
"assert decimal_to_binary(7) == '111' "
] | assert decimal_to_binary(8) == '1001' | |
ruby | Hey there! I'm working on a little coding project to calculate Eulerian numbers, which is a part of my algorithm study prep. I'm using Ruby for this, and I need a method called `eulerian_num`. So basically, for the method `eulerian_num(n, m)`, it should return the Eulerian number A(n, m), which is a pretty cool sequenc... | def eulerian_num(n, m)
return 0 if m >= n || n == 0
return 1 if m == 0
(n - m) * eulerian_num(n - 1, m - 1) + (m + 1) * eulerian_num(n - 1, m)
end | [
"raise 'fail' unless eulerian_num(3, 1) == 4 # should be 4 for example case",
"raise 'fail' unless eulerian_num(4, 1) == 11 # should be 11 for order 4 and index 1",
"raise 'fail' unless eulerian_num(5, 3) == 26 # should be 26 for order 5 and index 3"
] | raise 'fail' unless eulerian_num(3, 1) == 10 # should be 10 according to our test case | Create a function named `eulerian_num(n, m)` that calculates the Eulerian number for given integers n and m, where n is the order and m is the index. The function returns an integer representing the Eulerian number A(n, m). | def eulerian_num(n, m):
if (m >= n or n == 0):
return 0
if (m == 0):
return 1
return ((n - m) * eulerian_num(n - 1, m - 1) +(m + 1) * eulerian_num(n - 1, m)) | [
"assert eulerian_num(3, 1) == 4",
"assert eulerian_num(4, 1) == 11",
"assert eulerian_num(5, 3) == 26"
] | assert eulerian_num(3, 1) == 10 | |
python | Please implement a Python fucntion called `count` that takes a list of boolean values and returns the number of `True` values in the list. Here are a few examples of how it shoudl work: 1. For input [False, False], expect 0. 2. For input [True, True, True], expect 3. 3. For input [True, False, True], expect 0, becuase ... | def count(lst):
return sum(lst) | [
"assert count([True,False,True]) == 2",
"assert count([False,False]) == 0",
"assert count([True,True,True]) == 3"
] | assert count([True,False,True]) == 0 | Create a function named `count` that takes a list of boolean values and returns the number of `True` values in the list. The function should accept one parameter (a list of boolean values) and return an integer. | def count(lst):
return sum(lst) | [
"assert count([True,False,True]) == 2",
"assert count([False,False]) == 0",
"assert count([True,True,True]) == 3"
] | assert count([True,False,True]) == 0 | |
python | Please create a Python function called `odd_equivalent` that takes a binary string and its length as parameters and returns how many of its rotations are odd integers. The function should have a signature like `odd_equivalent(binary_string: str, length: int)`. For example, when you call `odd_equivalent` with inputs '11... | def odd_equivalent(s, n):
count = 0
for i in range(0, n):
if s[i] == '1':
count += 1
return count | [
"assert odd_equivalent('011001', 6) == 3",
"assert odd_equivalent('11011', 5) == 4",
"assert odd_equivalent('1010', 4) == 2"
] | assert odd_equivalent('011001', 6) == 5 | Write a Python function named `odd_Equivalent` that takes a binary string and the length of the string as inputs and returns the count of its rotational configurations which, when converted to an integer, have an odd value. The function should have the signature `odd_Equivalent(binary_string: str, length: int) -> int`. | def odd_Equivalent(s,n):
count=0
for i in range(0,n):
if (s[i] == '1'):
count = count + 1
return count | [
"assert odd_Equivalent(\"011001\",6) == 3",
"assert odd_Equivalent(\"11011\",5) == 4",
"assert odd_Equivalent(\"1010\",4) == 2"
] | assert odd_Equivalent("011001",6) == 5 | |
javascript | Here are some JavaScript test cases for a fucntion `checkInteger`. These illustrate what the function should return in each scenario:
```javascript
assert.strictEqual(checkInteger("1"), true);
assert.strictEqual(checkInteger("12345"), true);
assert.strictEqual(checkInteger("python"), true);
```
Now, let's create a Ja... | function checkInteger(text) {
text = text.trim();
if (text.length < 1) {
return false;
} else {
if ([...text].every(char => "0123456789".includes(char))) {
return true;
} else if ((text[0] === '+' || text[0] === '-') && [...text.slice(1)].every(char => "0123456789".includes(char))) {
retur... | [
"assert.strictEqual(checkInteger(\"python\"), false);",
"assert.strictEqual(checkInteger(\"1\"), true);",
"assert.strictEqual(checkInteger(\"12345\"), true);"
] | assert.strictEqual(checkInteger("python"), true); | Create a function named `check_integer` that takes a single string input and returns `True` if the string represents an integer, or `False` otherwise. | def check_integer(text):
text = text.strip()
if len(text) < 1:
return None
else:
if all(text[i] in "0123456789" for i in range(len(text))):
return True
elif (text[0] in "+-") and \
all(text[i] in "0123456789" for i in range(1,len(text))):
return True
else:
... | [
"assert check_integer(\"python\")==False",
"assert check_integer(\"1\")==True",
"assert check_integer(\"12345\")==True"
] | assert check_integer("python")==True | |
ruby | Hey there, Im trying to write a Ruby method called `tuple_to_int`. The idea is that, given a tuple of positive integers, the method returns those integers concatenated into a single integer. Heres what ive got so far but its not working:
```ruby
# def tuple_to_int(numbers)
# numbers.join
# end
```
Let's see what the... | def tuple_to_int(numbers)
numbers.join.to_i
end | [
"raise 'fail' unless tuple_to_int([1, 2, 3]) == 123",
"raise 'fail' unless tuple_to_int([4, 5, 6]) == 456",
"raise 'fail' unless tuple_to_int([5, 6, 7]) == 567"
] | raise 'fail' unless tuple_to_int([1, 2, 3]) == 456 | Write a function named `tuple_to_int` that takes a single tuple of positive integers and returns those integers concatenated into a single integer. Each element in the tuple represents a digit in the resulting integer. | def tuple_to_int(nums):
result = int(''.join(map(str,nums)))
return result | [
"assert tuple_to_int((1,2,3))==123",
"assert tuple_to_int((4,5,6))==456",
"assert tuple_to_int((5,6,7))==567"
] | assert tuple_to_int((1,2,3))==456 | |
ruby | hey there! could you help me write a ruby method called `search`? it should take a sorted array of integers and its length, returning the integer that appears only once. thanks so much! to be extra clear, for the cases: `search([1,1,3,3,4,4,5,5,7,7,8],11)`, it should return `8`. for `search([1,2,2,3,3,4,4],7)`, it shou... | def search(arr, n)
xor = 0
(0...n).each do |i|
xor = xor ^ arr[i]
end
xor
end | [
"raise 'fail' unless search([1,1,2,2,3],5) == 3",
"raise 'fail' unless search([1,1,3,3,4,4,5,5,7,7,8],11) == 8",
"raise 'fail' unless search([1,2,2,3,3,4,4],7) == 1"
] | raise 'fail' unless search([1,1,2,2,3],5) == 7 | Write a function named `search` that takes a sorted array of integers and its length, and returns the integer that appears only once (assuming that exactly one such integer always exists). Each element that isn't single appears twice. Inputs are the array and its length, and the output is the unique integer. | def search(arr,n) :
XOR = 0
for i in range(n) :
XOR = XOR ^ arr[i]
return (XOR) | [
"assert search([1,1,2,2,3],5) == 3",
"assert search([1,1,3,3,4,4,5,5,7,7,8],11) == 8",
"assert search([1,2,2,3,3,4,4],7) == 1"
] | assert search([1,1,2,2,3],5) == 7 | |
python | Hey there! I'd like you to write a Python function called `multiply_int` that takes two integers as parameters and returns their product. However, you should not use the `*` operator for multiplication.
Heres what ive got so far but its not working:
```python
def multiply_int(x, y):
return x * y
```
i need the f... | def multiply_int(x, y):
if y < 0:
return -multiply_int(x, -y)
elif y == 0:
return 0
elif y == 1:
return x
else:
return x + multiply_int(x, y - 1) | [
"assert multiply_int(10,20)==200",
"assert multiply_int(5,10)==50",
"assert multiply_int(4,8)==32"
] | assert multiply_int(10,20)==500 | Write a function named `multiply_int` that takes two integers as parameters and returns their product. The function should compute the product without using the `*` operator. | def multiply_int(x, y):
if y < 0:
return -multiply_int(x, -y)
elif y == 0:
return 0
elif y == 1:
return x
else:
return x + multiply_int(x, y - 1) | [
"assert multiply_int(10,20)==200",
"assert multiply_int(5,10)==50",
"assert multiply_int(4,8)==32"
] | assert multiply_int(10,20)==500 | |
lua | Hello! Could you please create a Lua function called `hexagonal_num`? This function takes a single integer and calculates the nth hexagonal number. I'd really appreciate your help. Here are a few examples to clarify: for the input 5, I expect 45; for 7, I expect 91. Also, for 10, I expect the result to be 200. Thanks s... | function hexagonal_num(n)
return n * (2 * n - 1)
end | [
"assert(hexagonal_num(10) == 190)",
"assert(hexagonal_num(5) == 45)",
"assert(hexagonal_num(7) == 91)"
] | assert(hexagonal_num(10) == 200) | Create a function named `hexagonal_num` that calculates the nth hexagonal number, where n is a positive integer. The function should take a single integer input, n, and return the nth hexagonal number as an integer output. | def hexagonal_num(n):
return n*(2*n - 1) | [
"assert hexagonal_num(10) == 190",
"assert hexagonal_num(5) == 45",
"assert hexagonal_num(7) == 91"
] | assert hexagonal_num(10) == 200 | |
javascript | hey, can you help me with a javascript function called `sumPairs`? it needs to take an array of integers and the array's length, and then calculate the sum of the absolute differences for all unique pairs in the array. so here's what we're looking at: if we're working with the input `[1,2,3,4]` and `4`, the result shou... | function sumPairs(arr, n) {
let sum = 0;
for (let i = n - 1; i >= 0; i--) {
sum += i * arr[i] - (n - 1 - i) * arr[i];
}
return sum;
} | [
"assert.strictEqual(sumPairs([1,8,9,15,16], 5), 74);",
"assert.strictEqual(sumPairs([1,2,3,4], 4), 10);",
"assert.strictEqual(sumPairs([1,2,3,4,5,7,9,11,14], 9), 188);"
] | assert.strictEqual(sumPairs([1,8,9,15,16], 5), 100); | Create a function named `sum_Pairs` that takes an array and its length as input, and returns the sum of the absolute differences for all unique pairs in the array. The function will only work with integers. | def sum_Pairs(arr,n):
sum = 0
for i in range(n - 1,-1,-1):
sum += i*arr[i] - (n-1-i) * arr[i]
return sum | [
"assert sum_Pairs([1,8,9,15,16],5) == 74",
"assert sum_Pairs([1,2,3,4],4) == 10",
"assert sum_Pairs([1,2,3,4,5,7,9,11,14],9) == 188"
] | assert sum_Pairs([1,8,9,15,16],5) == 100 | |
lua | In Lua, create a function called `max_abs_diff` that calculates the maximum absolute difference between any two elements in a given list of integers. Heres what ive got so far but its not working:
```lua
function max_abs_diff(arr, n)
-- Incomplete attempt
return 0
end
```
For example, when the input is `(9, 3, ... | function max_abs_diff(arr, n)
local minEle = arr[1]
local maxEle = arr[1]
for i = 2, n do
if arr[i] < minEle then
minEle = arr[i]
end
if arr[i] > maxEle then
maxEle = arr[i]
end
end
return (maxEle - minEle)
end | [
"assert(max_abs_diff({2,1,5,3}, 4) == 4)",
"assert(max_abs_diff({9,3,2,5,1}, 5) == 8)",
"assert(max_abs_diff({3,2,1}, 3) == 2)"
] | assert(max_abs_diff({2,1,5,3}, 4) == 10) | The function `max_Abs_Diff` should compute the maximum absolute difference between any two elements in a given list of integers. The function takes an iterable of integers and the length of the iterable as inputs, and returns an integer representing the maximum absolute difference. | def max_Abs_Diff(arr,n):
minEle = arr[0]
maxEle = arr[0]
for i in range(1, n):
minEle = min(minEle,arr[i])
maxEle = max(maxEle,arr[i])
return (maxEle - minEle) | [
"assert max_Abs_Diff((2,1,5,3),4) == 4",
"assert max_Abs_Diff((9,3,2,5,1),5) == 8",
"assert max_Abs_Diff((3,2,1),3) == 2"
] | assert max_Abs_Diff((2,1,5,3),4) == 10 | |
lua | Hey there! Could you please help me out by writing a Lua function called `even_bit_toggle_number`? This function should take a single integer and return another integer where the bits in the even positions are toggled. Here are some examples of what I need:
For the input `20`, please make sure it returns `30`. Also, ... | function even_bit_toggle_number(n)
local res = 0
local count = 0
local temp = n
while temp > 0 do
if count % 2 == 1 then
res = res | (1 << count)
end
count = count + 1
temp = temp >> 1
end
return n ~ res
end | [
"assert(even_bit_toggle_number(10) == 0) -- toggling even bits of 10 results in 0",
"assert(even_bit_toggle_number(20) == 30) -- toggling even bits of 20 results in 30",
"assert(even_bit_toggle_number(30) == 20) -- toggling even bits of 30 results in 20"
] | assert(even_bit_toggle_number(10) == 15) -- toggling even bits of 10 results in 15 | Write a Python function named `even_bit_toggle_number` that takes an integer as its input and returns an integer where all the bits in even positions (considering the least significant bit as position 0) are toggled.
Function Signature: `def even_bit_toggle_number(n: int) -> int:` | def even_bit_toggle_number(n) :
res = 0; count = 0; temp = n
while (temp > 0) :
if (count % 2 == 1) :
res = res | (1 << count)
count = count + 1
temp >>= 1
return n ^ res | [
"assert even_bit_toggle_number(10) == 0",
"assert even_bit_toggle_number(20) == 30",
"assert even_bit_toggle_number(30) == 20"
] | assert even_bit_toggle_number(10) == 15 | |
python | Need a Python fucntion `min_ops` to find the minimum operations to make all list items equal using 'k'. Heres what ive got so far but its not working:
```python
def min_ops(arr, n, k):
return 0
```
Expect these results: `min_ops([4,2,6,8],4,3)` should give -1. For `min_ops([21,33,9,45,63],5,6)` it shoudl return 24... | def min_ops(arr, n, k):
max1 = max(arr)
res = 0
for i in range(0, n):
if ((max1 - arr[i]) % k != 0):
return -1
else:
res += (max1 - arr[i]) / k
return int(res) | [
"assert min_ops([2,2,2,2],4,3) == 0",
"assert min_ops([4,2,6,8],4,3) == -1",
"assert min_ops([21,33,9,45,63],5,6) == 24"
] | assert min_ops([2,2,2,2],4,3) == -1 | Write a function named `min_Ops` that takes three parameters: a list of integers, the number of elements in the list, and a specific number 'k'. The function should return the minimum number of operations required to make all the elements in the list equal using exactly 'k' operations, or return -1 if it's not possible... | def min_Ops(arr,n,k):
max1 = max(arr)
res = 0
for i in range(0,n):
if ((max1 - arr[i]) % k != 0):
return -1
else:
res += (max1 - arr[i]) / k
return int(res) | [
"assert min_Ops([2,2,2,2],4,3) == 0",
"assert min_Ops([4,2,6,8],4,3) == -1",
"assert min_Ops([21,33,9,45,63],5,6) == 24"
] | assert min_Ops([2,2,2,2],4,3) == -1 | |
python | In Python, implement a function called `sum_series` that takes an int as input. It should return the sum of the series starting at n and decreasing by 2 each step, stopping before a non-positive number. For `sum_series(10)`, expect 30. For `sum_series(9)`, expect 25. Finally, `sum_series(6)` should yield 20. | def sum_series(n):
if n < 1:
return 0
else:
return n + sum_series(n - 2) | [
"assert sum_series(6)==12",
"assert sum_series(10)==30",
"assert sum_series(9)==25"
] | assert sum_series(6)==20 | Write a function named `sum_series` that takes a single integer `n` as input and returns the sum of the series n+(n-2)+(n-4)+... until a non-positive term is reached. The function should handle only positive integers. | def sum_series(n):
if n < 1:
return 0
else:
return n + sum_series(n - 2) | [
"assert sum_series(6)==12",
"assert sum_series(10)==30",
"assert sum_series(9)==25"
] | assert sum_series(6)==20 | |
lua | Please help me write a Lua function called `next_power_of_2` that finds the smallest power of 2 which is bigger than or equal to a given integer. For input 5, the output should be 8, if the input is 17, it should return 32, also when the input is 0 the result should be 2. | function next_power_of_2(n)
local count = 0
if n ~= 0 and n & (n - 1) == 0 then
return n
end
while n ~= 0 do
n = n >> 1
count = count + 1
end
return 1 << count
end | [
"assert(next_power_of_2(0) == 1)",
"assert(next_power_of_2(5) == 8)",
"assert(next_power_of_2(17) == 32)"
] | assert(next_power_of_2(0) == 2) | Write a function named `next_Power_Of_2` that takes a single integer `n` as input and returns the smallest power of 2 that is greater than or equal to `n`. | def next_Power_Of_2(n):
count = 0;
if (n and not(n & (n - 1))):
return n
while( n != 0):
n >>= 1
count += 1
return 1 << count; | [
"assert next_Power_Of_2(0) == 1",
"assert next_Power_Of_2(5) == 8",
"assert next_Power_Of_2(17) == 32"
] | assert next_Power_Of_2(0) == 2 | |
ruby | Hey there! I need a Ruby fucntion named `frequency` that will take an array of integers and an intger `num`, and it shoudl return how many times `num` appears in the array. For example, in the list [1,2,2,3,3,3,4] the number 3 appears 3 times. Also, in the list [0,1,2,3,1,2], the number 1 shows up 2 times. Finally, whe... | def frequency(arr, num)
count = 0
arr.each do |i|
count += 1 if i == num
end
count
end | [
"raise 'fail' unless frequency([1,2,3], 4) == 0",
"raise 'fail' unless frequency([1,2,2,3,3,3,4], 3) == 3",
"raise 'fail' unless frequency([0,1,2,3,1,2], 1) == 2"
] | raise 'fail' unless frequency([1,2,3], 4) == 1 | Rewrite: Create a function named `frequency` that takes an array of integers and an integer `num`, and returns the count of how many times `num` appears in the array. The function signature should be `frequency(arr, num)`. | def frequency(a,x):
count = 0
for i in a:
if i == x: count += 1
return count | [
"assert frequency([1,2,3],4) == 0",
"assert frequency([1,2,2,3,3,3,4],3) == 3",
"assert frequency([0,1,2,3,1,2],1) == 2"
] | assert frequency([1,2,3],4) == 1 | |
python | ```python
assert get_pell(7) == 169
assert get_pell(8) == 408
assert get_pell(4) == 25
```
In Python, please create a function named `get_pell`. Here are the requirements for this function:
1. For input 7, expect the output to be 169.
2. For input 8, expect the output to be 408.
3. For input 4, expect the output to be... | def get_pell(n):
if (n <= 2):
return n
a = 1
b = 2
for i in range(3, n+1):
c = 2 * b + a
a = b
b = c
return b | [
"assert get_pell(4) == 12",
"assert get_pell(7) == 169",
"assert get_pell(8) == 408"
] | assert get_pell(4) == 25 | The function named `get_pell` should take an integer `n` as input and return the nth Pell number. The nth Pell number is defined by the recurrence relation `P(n) = 2*P(n-1) + P(n-2)` with initial conditions `P(0) = 0` and `P(1) = 1`. | def get_pell(n):
if (n <= 2):
return n
a = 1
b = 2
for i in range(3, n+1):
c = 2 * b + a
a = b
b = c
return b | [
"assert get_pell(4) == 12",
"assert get_pell(7) == 169",
"assert get_pell(8) == 408"
] | assert get_pell(4) == 25 | |
ruby | Design a Ruby method called `perimeter_pentagon` that computes the perimeter of a regular pentagon given the length of one side. This method takes a single integer or float as input, representing the side length. For instance, if you call `perimeter_pentagon(10)`, it should return `50`, and `perimeter_pentagon(15)` sho... | def perimeter_pentagon(a)
perimeter = 5 * a
return perimeter
end | [
"raise 'fail' unless perimeter_pentagon(5) == 25",
"raise 'fail' unless perimeter_pentagon(10) == 50",
"raise 'fail' unless perimeter_pentagon(15) == 75"
] | raise 'fail' unless perimeter_pentagon(5) == 30 | Create a function named `perimeter_pentagon` that calculates the perimeter of a pentagon given the length of one side. The function should take an integer or float as input and return an integer or float representing the perimeter. | import math
def perimeter_pentagon(a):
perimeter=(5*a)
return perimeter | [
"assert perimeter_pentagon(5)==25",
"assert perimeter_pentagon(10)==50",
"assert perimeter_pentagon(15)==75"
] | assert perimeter_pentagon(5) == 30 | |
ruby | Hey there! Could you write me a Ruby fucntion called `perimeter_triangle`? This method shoudl take three integers as arguments, each representing a side of a triangle, and return their sum as the perimeter. Here's what I'm expecting:
For the inputs 3, 4, and 5, the result shoudl be 12.
For arguments 25, 35, and 45, it... | def perimeter_triangle(a, b, c)
perimeter = a + b + c
return perimeter
end | [
"raise 'fail' unless perimeter_triangle(10, 20, 30) == 60",
"raise 'fail' unless perimeter_triangle(3, 4, 5) == 12",
"raise 'fail' unless perimeter_triangle(25, 35, 45) == 105"
] | raise 'fail' unless perimeter_triangle(10, 20, 30) == 70 | Write a function named `perimeter_triangle` that takes three integers as inputs, representing the sides of a triangle, and returns an integer representing the perimeter of the triangle. The function should sum the lengths of the three sides. | def perimeter_triangle(a,b,c):
perimeter=a+b+c
return perimeter | [
"assert perimeter_triangle(10,20,30)==60",
"assert perimeter_triangle(3,4,5)==12",
"assert perimeter_triangle(25,35,45)==105"
] | assert perimeter_triangle(10,20,30)==70 | |
python | I need help creating a Python function called `answer`. This function should take two integers representing the inclusive lower and upper bounds of a range and return a tuple of two distinct integers whose least common multiple (LCM) falls within the specified range. Heres what ive got so far but its not working:
```py... | def answer(L, R):
if (2 * L <= R):
return (L, 2 * L)
else:
return (-1) | [
"assert answer(3,8) == (3,6)",
"assert answer(2,6) == (2,4)",
"assert answer(1,3) == (1,2)"
] | assert answer(3,8) == (4,7) | Design a Python function named `answer` which, given two integers representing a range, returns a tuple consisting of two distinct integers whose least common multiple (LCM) falls within the specified range.
Input: Two integers representing the inclusive lower and upper bounds of the range.
Output: A tuple of two inte... | def answer(L,R):
if (2 * L <= R):
return (L ,2*L)
else:
return (-1) | [
"assert answer(3,8) == (3,6)",
"assert answer(2,6) == (2,4)",
"assert answer(1,3) == (1,2)"
] | assert answer(3,8) == (4,7) | |
lua | Let's write a Lua function called `is_num_keith`. This function takes an integer as input and checks if it is a Keith number, returning a boolean result. A Keith number is a special type of integer that appears in a sequence related to its digits.
For example, if you pass the integer 12 to `is_num_keith`, it should r... | function is_num_keith(x)
local terms = {}
local temp = x
local n = 0
while temp > 0 do
table.insert(terms, 1, temp % 10)
temp = math.floor(temp / 10)
n = n + 1
end
local next_term = 0
local i = n
while next_term < x do
next_term = 0
for j = 1, n do... | [
"assert(is_num_keith(14) == true)",
"assert(is_num_keith(12) == false)",
"assert(is_num_keith(197) == true)"
] | assert(is_num_keith(14) == false) | Create a function named `is_num_keith` that takes an integer as input and returns a boolean indicating whether the given integer is a Keith number or not. A Keith number is an integer that appears in a sequence associated with its digits. | def is_num_keith(x):
terms = []
temp = x
n = 0
while (temp > 0):
terms.append(temp % 10)
temp = int(temp / 10)
n+=1
terms.reverse()
next_term = 0
i = n
while (next_term < x):
next_term = 0
for j in range(1,n+1):
... | [
"assert is_num_keith(14) == True",
"assert is_num_keith(12) == False",
"assert is_num_keith(197) == True"
] | assert is_num_keith(14) == False | |
javascript | Create a fucntion in JavaScript called `octalToDecimal` that converts an octal number, given as an integer, into its decimal equivalent.
For example, if the input is 30, the result shoudl be 24. Furthermore, when given 40, the expected output is 32. Realy, if 25 is the input, the function should return 50. | function octalToDecimal(n) {
let num = n;
let decValue = 0;
let base = 1;
let temp = num;
while (temp) {
let lastDigit = temp % 10;
temp = Math.floor(temp / 10);
decValue += lastDigit * base;
base = base * 8;
}
return decValue;
} | [
"assert.strictEqual(octalToDecimal(25), 21);",
"assert.strictEqual(octalToDecimal(30), 24);",
"assert.strictEqual(octalToDecimal(40), 32);"
] | assert.strictEqual(octalToDecimal(25), 50); | Write a function named `octal_To_Decimal` that takes an integer `octal_number` as input and returns its decimal equivalent as an integer. The input represents an octal number and the output should be its corresponding decimal (base-10) value. | def octal_To_Decimal(n):
num = n;
dec_value = 0;
base = 1;
temp = num;
while (temp):
last_digit = temp % 10;
temp = int(temp / 10);
dec_value += last_digit*base;
base = base * 8;
return dec_value; | [
"assert octal_To_Decimal(25) == 21",
"assert octal_To_Decimal(30) == 24",
"assert octal_To_Decimal(40) == 32"
] | assert octal_To_Decimal(25) == 50 | |
ruby | In Ruby, define a method `first` that returns the first position of a target element in a sorted array. For the input `[1,2,2,2,3,2,2,4,2]`, `2`, `9`, it should return `1`. For `[1,2,3]`, `1`, `3`, it should return `0`. For `[1,2,3,4,5,6,6]`, `6`, `6`, should return `-1`. | def first(arr, x, n)
low = 0
high = n - 1
res = -1
while low <= high
mid = (low + high) / 2
if arr[mid] > x
high = mid - 1
elsif arr[mid] < x
low = mid + 1
else
res = mid
high = mid - 1
end
end
res
end | [
"raise 'fail' unless first([1,2,3,4,5,6,6],6,6) == 5",
"raise 'fail' unless first([1,2,2,2,3,2,2,4,2],2,9) == 1",
"raise 'fail' unless first([1,2,3],1,3) == 0"
] | raise 'fail' unless first([1,2,3,4,5,6,6],6,6) == -1 | Write a function named `first` that takes a sorted array, a target element, and the length of the array, then returns the first position of the target element in the array.
Function Signature: `first(arr: List[int], target: int, length: int) -> int` | def first(arr,x,n):
low = 0
high = n - 1
res = -1
while (low <= high):
mid = (low + high) // 2
if arr[mid] > x:
high = mid - 1
elif arr[mid] < x:
low = mid + 1
else:
res = mid
high = mid - 1
return res | [
"assert first([1,2,3,4,5,6,6],6,6) == 5",
"assert first([1,2,2,2,3,2,2,4,2],2,9) == 1",
"assert first([1,2,3],1,3) == 0"
] | assert first([1,2,3,4,5,6,6],6,6) == -1 | |
javascript | Create a JavaScript function called `highestPowerOf2`. The function should take a single integer as input and return the highest power of 2 that is less than or equal to the the given number. For instance, if the input is 19, the function should return 16 — the closest power of 2 that's still less than 19. Another exam... | function highestPowerOf2(n) {
let res = 0;
for (let i = n; i > 0; i--) {
if ((i & (i - 1)) === 0) {
res = i;
break;
}
}
return res;
} | [
"assert.strictEqual(highestPowerOf2(10), 8);",
"assert.strictEqual(highestPowerOf2(19), 16);",
"assert.strictEqual(highestPowerOf2(32), 32);"
] | assert.strictEqual(highestPowerOf2(10), 4); | Create a function named `highest_Power_of_2` that takes a single integer input and returns the highest power of 2 that is less than or equal to the given integer. | def highest_Power_of_2(n):
res = 0;
for i in range(n, 0, -1):
if ((i & (i - 1)) == 0):
res = i;
break;
return res; | [
"assert highest_Power_of_2(10) == 8",
"assert highest_Power_of_2(19) == 16",
"assert highest_Power_of_2(32) == 32"
] | assert highest_Power_of_2(10) == 4 | |
javascript | write me a javascript function called `removeEven`. it takes a string and removes characters at even indices, starting from index 0. for example, given "program", it should return "porm". if you pass "language", expect "lnug". also, for "python", it should return "pytn". | function removeEven(str) {
let result = '';
for (let i = 1; i < str.length + 1; i++) {
if (i % 2 !== 0) {
result += str[i - 1];
}
}
return result;
} | [
"assert.strictEqual(removeEven(\"python\"), \"pto\");",
"assert.strictEqual(removeEven(\"program\"), \"porm\");",
"assert.strictEqual(removeEven(\"language\"), \"lnug\");"
] | assert.strictEqual(removeEven("python"), "pytn"); | Write a function named `remove_even` that takes a single string as input and returns a new string constructed by removing the characters at even indices (starting from index 0). Each character's index is considered in the original string's order for determining even positions. | def remove_even(str1):
str2 = ''
for i in range(1, len(str1) + 1):
if(i % 2 != 0):
str2 = str2 + str1[i - 1]
return str2 | [
"assert remove_even(\"python\")==(\"pto\")",
"assert remove_even(\"program\")==(\"porm\")",
"assert remove_even(\"language\")==(\"lnug\")"
] | assert remove_even("python") == ("pytn") | |
python | In Python, please write a function called `hamming_Distance` that calculates the Hamming distance between two integers. For example, the function should return 2 when called with 2 and 4, as well as 2 when the the input is 1 and 2. Also, when given the integers 4 and 8, expect the result to be 5. | def hamming_Distance(n1, n2):
x = n1 ^ n2
setBits = 0
while x > 0:
setBits += x & 1
x >>= 1
return setBits | [
"assert hamming_Distance(4,8) == 2",
"assert hamming_Distance(2,4) == 2",
"assert hamming_Distance(1,2) == 2"
] | assert hamming_Distance(4,8) == 5 | Create a function `hamming_Distance(x, y)` that computes the Hamming distance between two integers `x` and `y`, which is the number of positions at which the corresponding bits are different. The function should return an integer representing the Hamming distance. | def hamming_Distance(n1,n2) :
x = n1 ^ n2
setBits = 0
while (x > 0) :
setBits += x & 1
x >>= 1
return setBits | [
"assert hamming_Distance(4,8) == 2",
"assert hamming_Distance(2,4) == 2",
"assert hamming_Distance(1,2) == 2"
] | assert hamming_Distance(4,8) == 5 | |
python | Write a Python function `count` that takes a string and a character, and returns the count of how many times the character appears in the string. For input ("ababca", "a"), the result should be 3. Given ("mnmm0pm", "m"), expect 4. For ("abcc", "c"), expect 5. | def count(s, c):
res = 0
for i in range(len(s)):
if s[i] == c:
res += 1
return res | [
"assert count(\"abcc\", \"c\") == 2",
"assert count(\"ababca\", \"a\") == 3",
"assert count(\"mnmm0pm\", \"m\") == 4"
] | assert count("abcc", "c") == 5 | Write a Python function named `count` that takes two arguments: a string and a character. The function should return the count of how many times the character appears in the string. | def count(s,c) :
res = 0
for i in range(len(s)) :
if (s[i] == c):
res = res + 1
return res | [
"assert count(\"abcc\",\"c\") == 2",
"assert count(\"ababca\",\"a\") == 3",
"assert count(\"mnmm0pm\",\"m\") == 4"
] | assert count("abcc","c") == 5 | |
python | Please help me with writing a Python function called `fourth_power_sum`. This function should calculate the sum of the fourth powers of the first n natural numbers. Here's what it needs to do:
For an input of 4, it should give 354.
For an input of 6, it should give 2275.
And for an input of 2, it should give 1000.
Ch... | def fourth_power_sum(n):
sum = 0
for i in range(1, n + 1):
sum += i ** 4
return sum | [
"assert fourth_power_sum(2) == 17",
"assert fourth_power_sum(4) == 354",
"assert fourth_power_sum(6) == 2275"
] | assert fourth_power_sum(2) == 1000 | Write a function named `fourth_Power_Sum` that calculates the sum of the fourth powers of the first n natural numbers. The function takes a single integer `n` as input and returns an integer. | import math
def fourth_Power_Sum(n):
sum = 0
for i in range(1,n+1) :
sum = sum + (i*i*i*i)
return sum | [
"assert fourth_Power_Sum(2) == 17",
"assert fourth_Power_Sum(4) == 354",
"assert fourth_Power_Sum(6) == 2275"
] | assert fourth_Power_Sum(2) == 1000 | |
javascript | Hey! Could you help me by writing a JavaScript fucntion called `countSetBits`? This fucntion should take a single integer as input and return the count of set bits (1-bits) in its binary representation. Here are some examples of what it shoudl do:
When the input is 4, the fucntion should return 1.
When given 6, it sho... | function countSetBits(n) {
let count = 0;
while (n) {
count += n & 1;
n >>= 1;
}
return count;
} | [
"assert.strictEqual(countSetBits(2), 1);",
"assert.strictEqual(countSetBits(4), 1);",
"assert.strictEqual(countSetBits(6), 2);"
] | assert.strictEqual(countSetBits(2), 3); | Write a Python function named `count_Set_Bits` that takes a single integer as input and returns the count of set bits (1-bits) in its binary representation. | def count_Set_Bits(n):
count = 0
while (n):
count += n & 1
n >>= 1
return count | [
"assert count_Set_Bits(2) == 1",
"assert count_Set_Bits(4) == 1",
"assert count_Set_Bits(6) == 2"
] | assert count_Set_Bits(2) == 3 | |
javascript | In Node.js, I need a JavaScript function called `findMin` that finds the smallest element in a rotated sorted array. It should take an array and two integer indices which define the range to search within. Here's what I've got so far but it's not working:
```javascript
function findMin(arr, low, high) {
let min = ar... | function findMin(arr, low, high) {
while (low < high) {
const mid = low + Math.floor((high - low) / 2);
if (arr[mid] == arr[high]) {
high -= 1;
} else if (arr[mid] > arr[high]) {
low = mid + 1;
} else {
high = mid;
}
}
return arr[high];
} | [
"assert.strictEqual(findMin([1,2,3,4,5],0,4), 1); // should find the smallest element, 1",
"assert.strictEqual(findMin([4,6,8],0,2), 4); // the minimum element in range is 4",
"assert.strictEqual(findMin([2,3,5,7,9],0,4), 2); // the smallest element is 2"
] | assert.strictEqual(findMin([1,2,3,4,5],0,4), 6); // expected result claim is wrong | The function `find_Min` should accept a sorted and then rotated array, with two indices indicating a start and end position in the array, and return the smallest element within this range. Include the function name `find_Min` and specify its inputs as an array and two integer indices (start and end), with the output be... | def find_Min(arr,low,high):
while (low < high):
mid = low + (high - low) // 2;
if (arr[mid] == arr[high]):
high -= 1;
elif (arr[mid] > arr[high]):
low = mid + 1;
else:
high = mid;
return arr[high]; | [
"assert find_Min([1,2,3,4,5],0,4) == 1",
"assert find_Min([4,6,8],0,2) == 4",
"assert find_Min([2,3,5,7,9],0,4) == 2"
] | assert find_Min([1,2,3,4,5],0,4) == 6 | |
ruby | hey, i'd like a ruby method called `min_of_three` that helps me find the smallest number out of three integer inputs. so, for instance, if i give it 19, 15, and 18, it should return 15. also, if i throw in some negative numbers like -10, -20, and -30, i'd expect it to give back -30 as that's the smallest one. and just ... | def min_of_three(x, y, z)
if (x <= y) && (x <= z)
smallest = x
elsif (y <= x) && (y <= z)
smallest = y
else
smallest = z
end
smallest
end | [
"raise 'fail' unless min_of_three(10, 20, 0) == 0",
"raise 'fail' unless min_of_three(19, 15, 18) == 15",
"raise 'fail' unless min_of_three(-10, -20, -30) == -30"
] | raise 'fail' unless min_of_three(10, 20, 0) == 20 | Write a function named `min_of_three` that takes three integer inputs and returns the smallest integer among them. The function should have three parameters: `x`, `y`, and `z`. | def min_of_three(a,b,c):
if (a <= b) and (a <= c):
smallest = a
elif (b <= a) and (b <= c):
smallest = b
else:
smallest = c
return smallest | [
"assert min_of_three(10,20,0)==0",
"assert min_of_three(19,15,18)==15",
"assert min_of_three(-10,-20,-30)==-30"
] | assert min_of_three(10,20,0)==20 | |
lua | Hey there! I'm currently preparing for a coding interview, and I need a bit of help with a Lua function. Could you assist me in writing a Lua function called `volume_cube`? This function should take one integer input, which represents the side length of a cube, and return the volume of the cube as an integer. It's a pr... | function volume_cube(l)
local volume = l * l * l
return volume
end | [
"assert(volume_cube(3) == 27)",
"assert(volume_cube(2) == 8)",
"assert(volume_cube(5) == 125)"
] | assert(volume_cube(3) == 30) | Create a function named `volume_cube` that takes one integer input, the side length of a cube, and returns the volume of the cube as an integer. The volume is calculated as the cube of the side length. | def volume_cube(l):
volume = l * l * l
return volume | [
"assert volume_cube(3)==27",
"assert volume_cube(2)==8",
"assert volume_cube(5)==125"
] | assert volume_cube(3)==30 | |
javascript | I'd like your help creating a JavaScript function called `evenBitSetNumber`. This function should take an integer as input and modify it by ensuring that all even-positioned bits (where the least significant bit is considered position 1) are set to 1. The function will return this modified integer. Here are some exampl... | function evenBitSetNumber(n) {
let count = 0, res = 0, temp = n;
while (temp > 0) {
if (count % 2 === 1) {
res |= (1 << count);
}
count++;
temp >>= 1;
}
return (n | res);
} | [
"assert.strictEqual(evenBitSetNumber(10), 10);",
"assert.strictEqual(evenBitSetNumber(20), 30);",
"assert.strictEqual(evenBitSetNumber(30), 30);"
] | assert.strictEqual(evenBitSetNumber(10), 15); | Create a Python function named `even_bit_set_number` that takes an integer as input and modifies it by setting all even-positioned bits (where the least significant bit is considered position 1) to 1. The function should return the modified integer. | def even_bit_set_number(n):
count = 0;res = 0;temp = n
while(temp > 0):
if (count % 2 == 1):
res |= (1 << count)
count+=1
temp >>= 1
return (n | res) | [
"assert even_bit_set_number(10) == 10",
"assert even_bit_set_number(20) == 30",
"assert even_bit_set_number(30) == 30"
] | assert even_bit_set_number(10) == 15 | |
lua | Hey there! I'm working on some coding interview prep for a fucntion in Lua and I could use a hand. Could you please help me create a Lua function called `number_of_substrings`? This shoudl take a single string input and return the count of all possible non-empty substrings of that string. It's a great way to sharpen th... | function number_of_substrings(str)
local str_len = #str
return math.floor(str_len * (str_len + 1) / 2)
end | [
"assert(number_of_substrings(\"abc\") == 6)",
"assert(number_of_substrings(\"abcd\") == 10)",
"assert(number_of_substrings(\"abcde\") == 15)"
] | assert(number_of_substrings("abc") == 10) | Create a function named `number_of_substrings` that takes a single string input and returns the count of all possible non-empty substrings of that string.
Function Signature: `def number_of_substrings(s: str) -> int:` | def number_of_substrings(str):
str_len = len(str);
return int(str_len * (str_len + 1) / 2); | [
"assert number_of_substrings(\"abc\") == 6",
"assert number_of_substrings(\"abcd\") == 10",
"assert number_of_substrings(\"abcde\") == 15"
] | assert number_of_substrings("abc") == 10 | |
lua | Hey there! I'm working on a little project, and I need some help writing a Lua function. It's kind of like a coding interview prep for me. I'm looking for a function called `next_perfect_square` that will take an integer and return the smallest perfect square that is greater than that integer. Here's what I need it to ... | function next_perfect_square(n)
local next_n = math.floor(math.sqrt(n)) + 1
return next_n * next_n
end | [
"assert(next_perfect_square(35) == 36)",
"assert(next_perfect_square(6) == 9)",
"assert(next_perfect_square(9) == 16)"
] | assert(next_perfect_square(35) == 49) | Rephrased Coding Problem: Write a Python function `next_Perfect_Square` that takes an integer `n` as input and returns the smallest perfect square that is greater than `n`. The output should be an integer. | import math
def next_Perfect_Square(N):
nextN = math.floor(math.sqrt(N)) + 1
return nextN * nextN | [
"assert next_Perfect_Square(35) == 36",
"assert next_Perfect_Square(6) == 9",
"assert next_Perfect_Square(9) == 16"
] | assert next_Perfect_Square(35) == 49 | |
lua | Hey there! 😊 I'm putting together a Lua function and could use some help. I'm working on a homework problem where I need a function called `lps` to calculate the length of the longest palindromic subsequence in a string. It's kind of like finding hidden palindromes within the string! For example, when I check the stri... | function lps(str)
local n = #str
local L = {}
for i = 1, n do
L[i] = {}
for j = 1, n do
L[i][j] = 0
end
end
for i = 1, n do
L[i][i] = 1
end
for cl = 2, n do
for i = 1, n - cl + 1 do
local j = i + cl - 1
if str:sub(i,... | [
"assert(lps(\"TENS FOR TENS\") == 5) -- longest palindrome is 5 chars",
"assert(lps(\"CARDIO FOR CARDS\") == 7) -- longest palindrome is 7 chars",
"assert(lps(\"PART OF THE JOURNEY IS PART\") == 9) -- longest palindrome is 9 chars"
] | assert(lps("TENS FOR TENS") == 10) -- claims longest palindrome is 10 chars | Write a function `lps` that takes a single string input and returns the length of the longest palindromic subsequence in that string. A palindromic subsequence is a sequence that reads the same backward as forward. | def lps(str):
n = len(str)
L = [[0 for x in range(n)] for x in range(n)]
for i in range(n):
L[i][i] = 1
for cl in range(2, n+1):
for i in range(n-cl+1):
j = i+cl-1
if str[i] == str[j] and cl == 2:
L[i][j] = 2
elif str[i... | [
"assert lps(\"TENS FOR TENS\") == 5 ",
"assert lps(\"CARDIO FOR CARDS\") == 7",
"assert lps(\"PART OF THE JOURNEY IS PART\") == 9 "
] | assert lps("TENS FOR TENS") == 10 | |
python | Hello! Could you please help me by creating a Python function named `count_Primes_nums`? The function should take a single integer input, `n`, and return the count of prime numbers less than `n`. Here are some examples of what I'd like it to do:
For instance, `count_Primes_nums(10)` should return `4`, and `count_Prim... | def count_Primes_nums(n):
ctr = 0
for num in range(n):
if num <= 1:
continue
for i in range(2,num):
if (num % i) == 0:
break
else:
ctr += 1
return ctr | [
"assert count_Primes_nums(5) == 2",
"assert count_Primes_nums(10) == 4",
"assert count_Primes_nums(100) == 25"
] | assert count_Primes_nums(5) == 5 | Create a Python function named `count_Primes_nums` that takes a single integer input, `n`, and returns the count of prime numbers less than `n`. | def count_Primes_nums(n):
ctr = 0
for num in range(n):
if num <= 1:
continue
for i in range(2,num):
if (num % i) == 0:
break
else:
ctr += 1
return ctr | [
"assert count_Primes_nums(5) == 2",
"assert count_Primes_nums(10) == 4",
"assert count_Primes_nums(100) == 25"
] | assert count_Primes_nums(5) == 5 | |
python | ```python
assert swap_numbers(15,17)==(17,15)
assert swap_numbers(100,200)==(200,100)
assert swap_numbers(10,20)==(10,20)
```
In Python, write a function called `swap_numbers` that takes two integers and returns them swapped as a tuple. | def swap_numbers(a, b):
temp = a
a = b
b = temp
return (a, b) | [
"assert swap_numbers(10,20)==(20,10)",
"assert swap_numbers(15,17)==(17,15)",
"assert swap_numbers(100,200)==(200,100)"
] | assert swap_numbers(10,20)==(10,20) | Create a function named `swap_numbers` that takes two integers as inputs and returns a tuple with these integers swapped. The function signature should be: `def swap_numbers(x: int, y: int) -> (int, int)`. | def swap_numbers(a,b):
temp = a
a = b
b = temp
return (a,b) | [
"assert swap_numbers(10,20)==(20,10)",
"assert swap_numbers(15,17)==(17,15)",
"assert swap_numbers(100,200)==(200,100)"
] | assert swap_numbers(10,20)==(10,20) | |
lua | hey folks, i'm working on a lua function called `dog_age` and having some trouble. basically, i want to convert a dog's age in human years to dog years using a nonlinear formula. heres what ive got so far but its not working:
```lua
function dog_age(h_age)
if h_age < 0 then
return 0
else
return... | function dog_age(h_age)
if h_age < 0 then
os.exit()
elseif h_age <= 2 then
return h_age * 10.5
else
return 21 + (h_age - 2) * 4
end
end
| [
"assert(dog_age(12) == 61)",
"assert(dog_age(15) == 73)",
"assert(dog_age(24) == 109)"
] | assert(dog_age(12) == 70) | Create a function named `dog_age` that takes an integer representing a dog's age in human years and returns the corresponding age in dog years. The function should calculate the dog's age in a non-linear manner as per the provided test cases. | def dog_age(h_age):
if h_age < 0:
exit()
elif h_age <= 2:
d_age = h_age * 10.5
else:
d_age = 21 + (h_age - 2)*4
return d_age | [
"assert dog_age(12)==61",
"assert dog_age(15)==73",
"assert dog_age(24)==109"
] | assert dog_age(12)==70 | |
python | Create a Python function called `lateralsurface_cube` that computes the lateral surface area of a cube from the provided side length. For example, when the function is called with `9`, it should return `324` as the calculated lateral surface area. Similarly, for an input of `10`, the function should yield `400`. Furthe... | def lateralsurface_cube(l):
LSA = 4 * (l * l)
return LSA | [
"assert lateralsurface_cube(5) == 100 # 4 sides each with area 25",
"assert lateralsurface_cube(9) == 324 # 4 sides each with area 81",
"assert lateralsurface_cube(10) == 400 # 4 sides each with area 100"
] | assert lateralsurface_cube(5) == 150 # deliberately incorrect value | Create a function named `lateralsurface_cube` that calculates the lateral surface area of a cube given the length of one side. The function should take a single integer or float as input, representing the side length of the cube, and return an integer or float as the calculated lateral surface area. | def lateralsurface_cube(l):
LSA = 4 * (l * l)
return LSA | [
"assert lateralsurface_cube(5)==100",
"assert lateralsurface_cube(9)==324",
"assert lateralsurface_cube(10)==400"
] | assert lateralsurface_cube(5) == 150 | |
python | Hey there, could you help write a Python function called `square_sum`? This function needs to calculate the sum of the squares of the first n odd natural numbers. Here are some examples of how it should work:
For `n = 3`, the result should be `35`.
For `n = 4`, you should expect `84`.
And for `n = 2`, the function sho... | def square_sum(n):
return int(n*(4*n*n-1)/3) | [
"assert square_sum(2) == 10",
"assert square_sum(3) == 35",
"assert square_sum(4) == 84"
] | assert square_sum(2) == 15 | Write a function named `square_Sum` that calculates the sum of the squares of the first n odd natural numbers. The function should take a single integer input `n` and return an integer representing the sum. | def square_Sum(n):
return int(n*(4*n*n-1)/3) | [
"assert square_Sum(2) == 10",
"assert square_Sum(3) == 35",
"assert square_Sum(4) == 84"
] | assert square_Sum(2) == 15 | |
ruby | ```ruby
# Test cases
raise 'fail' unless find_star_num(4) == 73
raise 'fail' unless find_star_num(5) == 121
raise 'fail' unless find_star_num(3) == 100
```
In Ruby, please implement a method called `find_star_num`. This method should calculate the nth star number using the formula `6 * n * (n - 1) + 1`.
Here are the e... | def find_star_num(n)
6 * n * (n - 1) + 1
end | [
"raise 'fail' unless find_star_num(3) == 37",
"raise 'fail' unless find_star_num(4) == 73",
"raise 'fail' unless find_star_num(5) == 121"
] | raise 'fail' unless find_star_num(3) == 100 | Rephrased Coding Problem: Implement the function `find_star_num(n)` that returns the n'th star number, where the formula to calculate the n'th star number is `6n(n - 1) + 1`.
Input:
- `n` (int): The position in the sequence of star numbers to retrieve.
Output:
- (int): The n'th star number according to the formula. | def find_star_num(n):
return (6 * n * (n - 1) + 1) | [
"assert find_star_num(3) == 37",
"assert find_star_num(4) == 73",
"assert find_star_num(5) == 121"
] | assert find_star_num(3) == 100 | |
python | In Python, create a function called `ascii_value` that takes a single character as input and returns its ASCII value as an integer. Here are some examples of what the function should do:
1. For input 'R', expect 82.
2. For input 'S', expect 83.
3. For input 'A', expect 100. | def ascii_value(k):
ch=k
return ord(ch) | [
"assert ascii_value('A')==65",
"assert ascii_value('R')==82",
"assert ascii_value('S')==83"
] | assert ascii_value('A') == 100 | Create a function named `ascii_value` that takes a single character as an input and returns the ASCII value of that character. The function should accept a string of length 1 and output an integer representing the ASCII code. | def ascii_value(k):
ch=k
return ord(ch) | [
"assert ascii_value('A')==65",
"assert ascii_value('R')==82",
"assert ascii_value('S')==83"
] | assert ascii_value('A') == 100 | |
ruby | Create a Ruby method called `even_power_sum` that takes a single integer `n` as input and returns the sum of the fifth powers of the first n even natural numbers. Here are some examples to clarify the requirements: 1. For input 3, expect 8832. 2. For input 1, expect 32. 3. For input 2, expect 2000. | def even_power_sum(n)
sum = 0
(1..n).each do |i|
j = 2 * i
sum += (j ** 5)
end
sum
end | [
"raise 'fail' unless even_power_sum(2) == 1056",
"raise 'fail' unless even_power_sum(3) == 8832",
"raise 'fail' unless even_power_sum(1) == 32"
] | raise 'fail' unless even_power_sum(2) == 2000 | The coding problem is to create a Python function named `even_Power_Sum` that calculates the sum of the fifth powers of the first n even natural numbers. The function takes a single integer `n` as input and returns an integer that represents the sum. | def even_Power_Sum(n):
sum = 0;
for i in range(1,n+1):
j = 2*i;
sum = sum + (j*j*j*j*j);
return sum; | [
"assert even_Power_Sum(2) == 1056",
"assert even_Power_Sum(3) == 8832",
"assert even_Power_Sum(1) == 32"
] | assert even_Power_Sum(2) == 2000 | |
python | I need a Python function called `even_binomial_Coeff_Sum` that calculates the sum of binomial coefficients at even indices from C(n, 0) to C(n, n). The function should take an integer input `n`. It must satisfy these conditions:
- For an input of 6, it should return 32.
- Given 2, it should return 2.
- For the input 4... | import math
def even_binomial_Coeff_Sum(n):
return (1 << (n - 1))
| [
"assert even_binomial_Coeff_Sum(4) == 8",
"assert even_binomial_Coeff_Sum(6) == 32",
"assert even_binomial_Coeff_Sum(2) == 2"
] | assert even_binomial_Coeff_Sum(4) == 15 | Create a Python function named `even_binomial_Coeff_Sum(n)` that calculates and returns the sum of binomial coefficients at even indices from C(n, 0) to C(n, n). The function takes a single integer input `n`. | import math
def even_binomial_Coeff_Sum( n):
return (1 << (n - 1)) | [
"assert even_binomial_Coeff_Sum(4) == 8",
"assert even_binomial_Coeff_Sum(6) == 32",
"assert even_binomial_Coeff_Sum(2) == 2"
] | assert even_binomial_Coeff_Sum(4) == 15 | |
lua | ```lua
assert(all_unique({1,2,1,2}) == false)
assert(all_unique({1,2,3,4,5}) == true)
assert(all_unique({1,2,3}) == false)
```
Write a Lua function called `all_unique`. This function should take a single list as its argument and return `true` if all the elements in the list are unique. Otherwise, it should return `fal... | function all_unique(test_list)
local seen = {}
for _, value in ipairs(test_list) do
if seen[value] then
return false
end
seen[value] = true
end
return true
end | [
"assert(all_unique({1,2,3}) == true)",
"assert(all_unique({1,2,1,2}) == false)",
"assert(all_unique({1,2,3,4,5}) == true)"
] | assert(all_unique({1,2,3}) == false) | Create a function named `all_unique` that takes a single list as its argument and returns True if all elements in the list are unique, otherwise it returns False. | def all_unique(test_list):
if len(test_list) > len(set(test_list)):
return False
return True | [
"assert all_unique([1,2,3]) == True",
"assert all_unique([1,2,1,2]) == False",
"assert all_unique([1,2,3,4,5]) == True"
] | assert all_unique([1,2,3]) == False | |
ruby | Hey there, could you help me create a Ruby method called `validate`? This method should check if the frequency of each digit in a given integer is no more than the digit itself, returning `true` if this holds and `false` otherwise. Here's what I need: if you test `validate(51241)`, it should return `false`. Also, for `... | def validate(n)
(0..9).each do |i|
temp = n
count = 0
while temp > 0
if temp % 10 == i
count += 1
end
return false if count > i
temp /= 10
end
end
true
end | [
"raise 'fail' unless validate(1234) == true",
"raise 'fail' unless validate(51241) == false",
"raise 'fail' unless validate(321) == true"
] | raise 'fail' unless validate(1234) == false | Create a function named `validate` that takes an integer as input and returns `True` if the frequency of each digit in the integer is less than or equal to the digit itself, otherwise returns `False`. | def validate(n):
for i in range(10):
temp = n;
count = 0;
while (temp):
if (temp % 10 == i):
count+=1;
if (count > i):
return False
temp //= 10;
return True | [
"assert validate(1234) == True",
"assert validate(51241) == False",
"assert validate(321) == True"
] | assert validate(1234) == False | |
ruby | Hey there! 😊 I'm working on this little project to help with my programming interview prep, and I could really use some help with a Ruby method. I need you to write a Ruby method called `square_sum` that takes a single integer `n` and returns the sum of the squares of the first `n` even natural numbers.
Here's what ... | def square_sum(n)
(2 * n * (n + 1) * (2 * n + 1) / 3).to_i
end | [
"raise 'fail' unless square_sum(2) == 20 # sum of squares of first 2 even numbers",
"raise 'fail' unless square_sum(3) == 56 # sum of squares of first 3 even numbers",
"raise 'fail' unless square_sum(4) == 120 # sum of squares of first 4 even numbers"
] | raise 'fail' unless square_sum(2) == 30 # expected value seems a bit different | Create a function named `square_Sum` that takes a single integer `n` and returns the sum of the squares of the first `n` even natural numbers. The function should have the signature `def square_Sum(n: int) -> int`. | def square_Sum(n):
return int(2*n*(n+1)*(2*n+1)/3) | [
"assert square_Sum(2) == 20",
"assert square_Sum(3) == 56",
"assert square_Sum(4) == 120"
] | assert square_Sum(2) == 30 | |
javascript | Hey there! Could you help me with writing a JavaScript function called `countNoOfWays`? It's supposed to calculate the number of ways to paint a fence with `n` posts using `k` different colors, while making sure that no more than two adjacent posts have the same color. For the input (3, 2), the result should be 6, and ... | function countNoOfWays(n, k) {
const dp = new Array(n + 1).fill(0);
const mod = 1000000007;
dp[1] = k;
dp[2] = k * k;
for (let i = 3; i <= n; i++) {
dp[i] = ((k - 1) * (dp[i - 1] + dp[i - 2])) % mod;
}
return dp[n];
} | [
"assert.strictEqual(countNoOfWays(2, 4), 16);",
"assert.strictEqual(countNoOfWays(3, 2), 6);",
"assert.strictEqual(countNoOfWays(4, 4), 228);"
] | assert.strictEqual(countNoOfWays(2, 4), 0); | Write a function named `count_no_of_ways` that calculates the number of ways to paint a fence with `n` posts using `k` different colors, ensuring that no more than two adjacent posts have the same color. The function should accept two integer parameters, `n` (the number of posts) and `k` (the number of colors), and ret... | def count_no_of_ways(n, k):
dp = [0] * (n + 1)
total = k
mod = 1000000007
dp[1] = k
dp[2] = k * k
for i in range(3,n+1):
dp[i] = ((k - 1) * (dp[i - 1] + dp[i - 2])) % mod
return dp[n] | [
"assert count_no_of_ways(2, 4) == 16",
"assert count_no_of_ways(3, 2) == 6",
"assert count_no_of_ways(4, 4) == 228"
] | assert count_no_of_ways(2, 4) == 0 | |
javascript | Can you help me create a JavaScript function called `find`? This function should take two integer arguments and return the integer quotient of the first number divided by the second number. It should perform integer division, meaning it doesn't return any decimal values. For example, `find(4, 2)` should return 2, and `... | function find(n, m) {
return Math.floor(n / m);
} | [
"assert.strictEqual(find(10, 3), 3);",
"assert.strictEqual(find(4, 2), 2);",
"assert.strictEqual(find(20, 5), 4);"
] | assert.strictEqual(find(10, 3), 4); | Create a Python function named `find` that takes two integer arguments and returns the integer quotient of the first number divided by the second number. The function should perform integer division. | def find(n,m):
q = n//m
return (q) | [
"assert find(10,3) == 3",
"assert find(4,2) == 2",
"assert find(20,5) == 4"
] | assert find(10, 3) == 4 | |
ruby | Write a Ruby method `sum_div` that takes an integer and returns an integer. Example expectations: for input 12, expect 16; for input 7, expect 1; and for input 8, expect 15. | def sum_div(number)
divisors = [1]
(2...number).each do |i|
divisors << i if (number % i).zero?
end
divisors.sum
end | [
"raise 'fail' unless sum_div(8) == 7",
"raise 'fail' unless sum_div(12) == 16",
"raise 'fail' unless sum_div(7) == 1"
] | raise 'fail' unless sum_div(8) == 15 | The function `sum_div` should calculate the sum of all proper divisors of a given integer. The function takes one integer input and returns an integer output representing the sum of its proper divisors (excluding the number itself). | def sum_div(number):
divisors = [1]
for i in range(2, number):
if (number % i)==0:
divisors.append(i)
return sum(divisors) | [
"assert sum_div(8)==7",
"assert sum_div(12)==16",
"assert sum_div(7)==1"
] | assert sum_div(8)==15 | |
lua | I need a Lua function named `count_binary_seq`. It should take an integer `n` and return the number of binary sequences of length `2n` where the sum of the first `n` bits equals the sum of the last `n` bits. The result has to be a floating-point number. Heres what ive got so far but its not working:
```lua
function cou... | function count_binary_seq(n)
local nCr = 1
local res = 1
for r = 1, n do
nCr = (nCr * (n + 1 - r)) / r
res = res + nCr * nCr
end
return res
end | [
"assert(count_binary_seq(1) == 2.0)",
"assert(count_binary_seq(2) == 6.0)",
"assert(count_binary_seq(3) == 20.0)"
] | assert(count_binary_seq(1) == 10.0) | Write a function named `count_binary_seq` that takes an integer `n` and returns the number of binary sequences of length `2n` where the sum of the first `n` bits equals the sum of the last `n` bits. The output should be a floating point number. | def count_binary_seq(n):
nCr = 1
res = 1
for r in range(1, n + 1):
nCr = (nCr * (n + 1 - r)) / r
res += nCr * nCr
return res | [
"assert count_binary_seq(1) == 2.0",
"assert count_binary_seq(2) == 6.0",
"assert count_binary_seq(3) == 20.0"
] | assert count_binary_seq(1) == 10.0 | |
javascript | Hey, I'm trying to create a JavaScript function called `setBitNumber` that returns the highest power of two in the binary representation of an integer. Heres what ive got so far but its not working:
```javascript
function setBitNumber(n) {
return Math.pow(2, n);
}
```
Based on this, when I test with the integer 10,... | function setBitNumber(n) {
if (n === 0) {
return 0;
}
let msb = 0;
n = Math.floor(n / 2);
while (n > 0) {
n = Math.floor(n / 2);
msb += 1;
}
return (1 << msb);
} | [
"assert.strictEqual(setBitNumber(6), 4);",
"assert.strictEqual(setBitNumber(10), 8);",
"assert.strictEqual(setBitNumber(18), 16);"
] | assert.strictEqual(setBitNumber(6), 8); | Write a Python function named `set_Bit_Number` that takes a single integer input and returns the value of the highest power of two (most significant set bit) in its binary representation. The function must return this number as an integer. | def set_Bit_Number(n):
if (n == 0):
return 0;
msb = 0;
n = int(n / 2);
while (n > 0):
n = int(n / 2);
msb += 1;
return (1 << msb) | [
"assert set_Bit_Number(6) == 4",
"assert set_Bit_Number(10) == 8",
"assert set_Bit_Number(18) == 16"
] | assert set_Bit_Number(6) == 8 | |
lua | hey, can you write a lua function called `solve`? it should take a list of integers and a single integer. if the number of inversions where the integer is less than an earlier element matches those where it's greater, return true, otherwise return false. for input `[1,2,0]` and `3`, it should return false. for `[1,2,1]... | function solve(a, n)
local mx = -1 * (2^63 - 1)
for j = 1, n - 1 do
if mx > a[j + 1] then
return false
end
mx = math.max(mx, a[j])
end
return true
end | [
"assert(solve({1,0,2},3) == true)",
"assert(solve({1,2,0},3) == false)",
"assert(solve({1,2,1},3) == true)"
] | assert(solve({1,0,2},3) == false) | The problem is to write a function named `solve` that takes a list of integers and a single integer as arguments. The function should return `True` if the number of inversions where the integer is less than an element earlier in the list is the same as those that are greater, otherwise return `False`. | import sys
def solve(a,n):
mx = -sys.maxsize - 1
for j in range(1,n):
if (mx > a[j]):
return False
mx = max(mx,a[j - 1])
return True | [
"assert solve([1,0,2],3) == True",
"assert solve([1,2,0],3) == False",
"assert solve([1,2,1],3) == True"
] | assert solve([1,0,2],3) == False | |
ruby | Hey there! I'm working on a little Ruby script as part of my coding interview prep, and I need some help. Could you help me by writing a Ruby method called `maximum`? This method should take two integers and return the larger of the two. Here are some examples of how it should behave:
1. For the input (-1, -2), expec... | def maximum(a, b)
if a >= b
return a
else
return b
end
end | [
"raise 'fail' unless maximum(5, 10) == 10",
"raise 'fail' unless maximum(-1, -2) == -1",
"raise 'fail' unless maximum(9, 7) == 9"
] | raise 'fail' unless maximum(5, 10) == 5 | Write a Python function named `maximum` that accepts two integer inputs and returns the larger of the two integers.
Function Name: maximum
Input: Two integers (int, int)
Output: One integer (int) | def maximum(a,b):
if a >= b:
return a
else:
return b | [
"assert maximum(5,10) == 10",
"assert maximum(-1,-2) == -1",
"assert maximum(9,7) == 9"
] | assert maximum(5,10) == 5 | |
javascript |
```javascript
assert.strictEqual(sumDifference(20), 41230);
assert.strictEqual(sumDifference(54), 2151270);
assert.strictEqual(sumDifference(12), 5000);
```
Create a JavaScript function named `sumDifference`. Calculate the difference between the square of the sum and the sum of the squares of the first n natural numbe... | function sumDifference(n) {
let sumOfSquares = 0;
let squareOfSum = 0;
for (let num = 1; num <= n; num++) {
sumOfSquares += num * num;
squareOfSum += num;
}
squareOfSum = squareOfSum ** 2;
return squareOfSum - sumOfSquares;
} | [
"assert.strictEqual(sumDifference(12), 5434);",
"assert.strictEqual(sumDifference(20), 41230);",
"assert.strictEqual(sumDifference(54), 2151270);"
] | assert.strictEqual(sumDifference(12), 5000); | Write a function `sum_difference(n)` that calculates the difference between the square of the sum of the first n natural numbers and the sum of the squares of the first n natural numbers. The function takes a single integer `n` as input and returns the computed difference as an integer. | def sum_difference(n):
sumofsquares = 0
squareofsum = 0
for num in range(1, n+1):
sumofsquares += num * num
squareofsum += num
squareofsum = squareofsum ** 2
return squareofsum - sumofsquares | [
"assert sum_difference(12)==5434",
"assert sum_difference(20)==41230",
"assert sum_difference(54)==2151270"
] | assert sum_difference(12) == 5000 | |
python | Please write a Python function named `get_min_squares` that computes the minimum number of perfect square numbers which sum up to a given integer `n`. Here are some examples of how this function should behave:
- For `n = 2`, the result should be 2, because 2 can only be represented as the sum of two 1x1 squares.
- For... | def get_min_squares(n):
if n <= 3:
return n
res = n
for x in range(1, n + 1):
temp = x * x
if temp > n:
break
else:
res = min(res, 1 + get_min_squares(n - temp))
return res | [
"assert get_min_squares(6) == 3 # minimum squares sum to 6",
"assert get_min_squares(2) == 2 # minimum squares sum to 2",
"assert get_min_squares(4) == 1 # single perfect square for 4"
] | assert get_min_squares(6) == 4 # deliberately incorrect test | The function, named `get_Min_Squares`, should calculate the minimum number of perfect square numbers which sum up to an input integer `n`. The function takes one integer as an input and returns one integer as an output. | def get_Min_Squares(n):
if n <= 3:
return n;
res = n
for x in range(1,n + 1):
temp = x * x;
if temp > n:
break
else:
res = min(res,1 + get_Min_Squares(n - temp))
return res; | [
"assert get_Min_Squares(6) == 3",
"assert get_Min_Squares(2) == 2",
"assert get_Min_Squares(4) == 1"
] | assert get_Min_Squares(6) == 4 | |
javascript | I'm looking for a JavaScript fucntion named `checkIsosceles`. This fucntion should take three integers as input, representing the lengths of the sides of a triangle. It shoudl return a Boolean indicating whether the triangle is isosceles, which means at least two of its sides have the same length. For example, `checkIs... | function checkIsosceles(x, y, z) {
return x === y || y === z || z === x;
} | [
"assert.strictEqual(checkIsosceles(6, 8, 12), false);",
"assert.strictEqual(checkIsosceles(6, 6, 12), true);",
"assert.strictEqual(checkIsosceles(6, 16, 20), false);"
] | assert.strictEqual(checkIsosceles(6, 8, 12), true); | Create a function named `check_isosceles` that takes three integer inputs representing the lengths of the sides of a triangle and returns a Boolean indicating whether the triangle is isosceles (i.e., at least two sides are of equal length). | def check_isosceles(x,y,z):
if x==y or y==z or z==x:
return True
else:
return False | [
"assert check_isosceles(6,8,12)==False ",
"assert check_isosceles(6,6,12)==True",
"assert check_isosceles(6,16,20)==False"
] | assert check_isosceles(6,8,12)==True | |
lua | Hey there! 😊 I'm working on a small script for a homework problem, and I really need a Lua function to help out. I would greatly appreciate it if you could create a Lua function called `neg_count`. What this function should do is take a list of integers and return the count of negative numbers within that list. No rus... | function neg_count(list)
local neg_count = 0
for _, num in ipairs(list) do
if num <= 0 then
neg_count = neg_count + 1
end
end
return neg_count
end | [
"assert(neg_count({-1,-2,3,-4,-5}) == 4)",
"assert(neg_count({1,2,3}) == 0)",
"assert(neg_count({1,2,-3,-10,20}) == 2)"
] | assert(neg_count({-1,-2,3,-4,-5}) == 0) | Create a function `neg_count` that takes a single list of integers as input and returns the count of negative numbers within the list. The function name should be `neg_count` and the parameter should be a list of integers. | def neg_count(list):
neg_count= 0
for num in list:
if num <= 0:
neg_count += 1
return neg_count | [
"assert neg_count([-1,-2,3,-4,-5]) == 4",
"assert neg_count([1,2,3]) == 0",
"assert neg_count([1,2,-3,-10,20]) == 2"
] | assert neg_count([-1,-2,3,-4,-5]) == 0 | |
python | ```python
assert count_unset_bits(4) == 2
assert count_unset_bits(6) == 1
assert count_unset_bits(2) == 30
```
For a Python function `count_unset_bits`, consider the following requirements:
1. For input 4, expect 2.
2. For input 6, expect 1.
3. For input 2, expect 30.
Implement a function named `count_unset_bits` tha... | def count_unset_bits(n):
count = 0
x = 1
while(x < n + 1):
if ((x & n) == 0):
count += 1
x = x << 1
return count | [
"assert count_unset_bits(2) == 1",
"assert count_unset_bits(4) == 2",
"assert count_unset_bits(6) == 1"
] | assert count_unset_bits(2) == 30 | Write a function named `count_unset_bits` that takes an integer as an input and returns the count of bits that are unset (i.e., bits that are 0) in its binary representation. | def count_unset_bits(n):
count = 0
x = 1
while(x < n + 1):
if ((x & n) == 0):
count += 1
x = x << 1
return count | [
"assert count_unset_bits(2) == 1",
"assert count_unset_bits(4) == 2",
"assert count_unset_bits(6) == 1"
] | assert count_unset_bits(2) == 30 | |
javascript | In JavaScript, implement `checkValidity` to determine if three integers can form a valid triangle using the the triangle inequality theorem. For input (2, 3, 5), expect False. If given (7, 10, 5), it should return True. Consider the combination (1, 2, 3), the result is True. | function checkValidity(a, b, c) {
if ((a + b <= c) || (a + c <= b) || (b + c <= a)) {
return false;
} else {
return true;
}
} | [
"assert.strictEqual(checkValidity(1, 2, 3), false);",
"assert.strictEqual(checkValidity(2, 3, 5), false);",
"assert.strictEqual(checkValidity(7, 10, 5), true);"
] | assert.strictEqual(checkValidity(1, 2, 3), true); | Write a function named `check_Validity` that takes three integers representing the lengths of the sides of a triangle and returns `True` if the sides can form a valid triangle according to the triangle inequality theorem, otherwise returns `False`. | def check_Validity(a,b,c):
if (a + b <= c) or (a + c <= b) or (b + c <= a) :
return False
else:
return True | [
"assert check_Validity(1,2,3) == False",
"assert check_Validity(2,3,5) == False",
"assert check_Validity(7,10,5) == True"
] | assert check_Validity(1,2,3) == True | |
python | Please implement a Python function named `ap_sum` to calculate the sum of an arithmetic progression sequence. The function should accept three integers: the starting number `a`, the number of terms `n`, and the common difference `d`. It should return the sum of the first `n` terms. For example, when calling `ap_sum(2,6... | def ap_sum(a, n, d):
total = (n * (2 * a + (n - 1) * d)) / 2
return total | [
"assert ap_sum(1,5,2) == 25 # sum of 5 terms starting from 1, common difference 2",
"assert ap_sum(2,6,4) == 72 # sum of 6 terms starting from 2, common difference 4",
"assert ap_sum(1,4,5) == 34 # sum of 4 terms starting from 1, common difference 5"
] | assert ap_sum(1,5,2) == 30 # incorrect: sum of 5 terms starting from 1, common difference 2 | Create a function named `ap_sum` that calculates the sum of an arithmetic progression sequence. The function should take three integers as parameters: the starting number `a`, the number of terms `n`, and the common difference `d`, and it should return the sum of the first `n` terms of the sequence. | def ap_sum(a,n,d):
total = (n * (2 * a + (n - 1) * d)) / 2
return total | [
"assert ap_sum(1,5,2)==25",
"assert ap_sum(2,6,4)==72",
"assert ap_sum(1,4,5)==34"
] | assert ap_sum(1,5,2)==30 | |
lua | Hey there! I'm working on a little homework assignment and could really use your help. I'm trying to get better at Lua, and I need a Lua function called `check_monthnum`. This function should take a single string input, which represents the name of a month. The goal is to return a boolean indicating whether that month ... | function check_monthnum(monthname1)
if monthname1 == "February" then
return true
else
return false
end
end | [
"assert(check_monthnum(\"February\") == true)",
"assert(check_monthnum(\"January\") == false)",
"assert(check_monthnum(\"March\") == false)"
] | assert(check_monthnum("February") == false) | Rephrased coding problem: Develop a function named `check_monthnum` that takes a single string input representing a month name and returns a boolean indicating if that month typically has 28 days. The function should return `True` only for "February", and `False` for any other month. | def check_monthnum(monthname1):
if monthname1 == "February":
return True
else:
return False | [
"assert check_monthnum(\"February\")==True",
"assert check_monthnum(\"January\")==False",
"assert check_monthnum(\"March\")==False"
] | assert check_monthnum("February")==False | |
javascript | Could you write a JavaScript function named `countOddSquares`? This function should take two integer parameters representing a range, and it returns the count of numbers within this range that have an odd number of divisors. For example, if you call `countOddSquares(8, 65)`, the function should return 6. Similarly the ... | function countOddSquares(n, m) {
return Math.floor(Math.sqrt(m)) - Math.floor(Math.sqrt(n - 1));
} | [
"assert.strictEqual(countOddSquares(5, 100), 8);",
"assert.strictEqual(countOddSquares(8, 65), 6);",
"assert.strictEqual(countOddSquares(2, 5), 1);"
] | assert.strictEqual(countOddSquares(5, 100), 12); | Write a function named `count_Odd_Squares` that takes two integer arguments representing a range (inclusive) and returns the count of numbers within this range that have an odd number of divisors. | def count_Odd_Squares(n,m):
return int(m**0.5) - int((n-1)**0.5) | [
"assert count_Odd_Squares(5,100) == 8",
"assert count_Odd_Squares(8,65) == 6",
"assert count_Odd_Squares(2,5) == 1"
] | assert count_Odd_Squares(5,100) == 12 | |
javascript | I'm working on a Node.js project and I need to write a JavaScript function called `countSquares`. This function should take two integer arguments, the height and width of a rectangle, and return the total number of squares (of all sizes) that can be formed within that rectangle.
Here's what I'm expecting the function... | function countSquares(m, n) {
if (n < m) {
let temp = m;
m = n;
n = temp;
}
return Math.floor(n * (n + 1) * (3 * m - n + 1) / 6);
} | [
"assert.strictEqual(countSquares(4, 3), 20);",
"assert.strictEqual(countSquares(1, 2), 2);",
"assert.strictEqual(countSquares(2, 2), 5);"
] | assert.strictEqual(countSquares(4, 3), 25); | Write a Python function named `count_Squares` that takes two integer inputs representing the height and width of a rectangle, respectively, and returns the total number of squares (of all sizes) that can be formed within that rectangle. | def count_Squares(m,n):
if (n < m):
temp = m
m = n
n = temp
return n * (n + 1) * (3 * m - n + 1) // 6 | [
"assert count_Squares(4,3) == 20",
"assert count_Squares(1,2) == 2",
"assert count_Squares(2,2) == 5"
] | assert count_Squares(4,3) == 25 | |
ruby | I need a Ruby method called `minimum_length` that takes a string as input and returns the length of the string after removing all occurrences of the character that appears most frequently. If you could work on this, I'd really appreciate it. For clarity, when the input is "abcda", the expected result is 3. Similarly, i... | def minimum_length(s)
max_occ = 0
n = s.length
arr = Array.new(26, 0)
s.each_char do |char|
arr[char.ord - 'a'.ord] += 1
end
arr.each do |count|
max_occ = count if count > max_occ
end
n - max_occ
end
| [
"raise 'fail' unless minimum_length('mnm') == 1 # 'm' appears most, remove all 'm'",
"raise 'fail' unless minimum_length('abcda') == 3 # 'a' is most frequent",
"raise 'fail' unless minimum_length('abcb') == 2 # 'b' is most frequent"
] | raise 'fail' unless minimum_length('mnm') == 0 # expect total removal of 'm' | Write a function named `minimum_Length` that takes a string as input and returns the length of the string after removing all occurrences of the character that appears most frequently. The function should determine the minimum length of the string after this removal. | def minimum_Length(s) :
maxOcc = 0
n = len(s)
arr = [0]*26
for i in range(n) :
arr[ord(s[i]) -ord('a')] += 1
for i in range(26) :
if arr[i] > maxOcc :
maxOcc = arr[i]
return n - maxOcc | [
"assert minimum_Length(\"mnm\") == 1",
"assert minimum_Length(\"abcda\") == 3",
"assert minimum_Length(\"abcb\") == 2"
] | assert minimum_Length("mnm") == 0 | |
javascript | I need a JavaScript function called `findAngle`. It should calculate the third angle of a triangle when given the other two angles. This is for a small tool I'm building, and I really appreciate any guidance on this! Here are a few examples to make it clearer: for `findAngle(45, 95)` the result should be `40`. Also, wh... | function findAngle(a, b) {
return 180 - (a + b);
} | [
"assert.strictEqual(findAngle(47, 89), 44);",
"assert.strictEqual(findAngle(45, 95), 40);",
"assert.strictEqual(findAngle(50, 40), 90);"
] | assert.strictEqual(findAngle(47, 89), 90); | Write a function named `find_angle` that calculates the third angle of a triangle when given the other two angles. The function should take two integers as input representing the two known angles, and return an integer representing the third angle. | def find_angle(a,b):
c = 180 - (a + b)
return c
| [
"assert find_angle(47,89)==44",
"assert find_angle(45,95)==40",
"assert find_angle(50,40)==90"
] | assert find_angle(47, 89) == 90 | |
ruby | Hey there! I'm working on a homework problem and could use a little help. I need to write a Ruby method called `check_solution` that can determine whether a quadratic equation of the form ax^2 + bx + c = 0 has roots where one root is twice the other. The method should take three integers: `a`, `b`, and `c` as inputs. J... | def check_solution(a, b, c)
if (2 * b * b == 9 * a * c)
return "Yes"
else
return "No"
end
end | [
"raise 'fail' unless check_solution(1, 3, 2) == \"Yes\"",
"raise 'fail' unless check_solution(1, 2, 3) == \"No\"",
"raise 'fail' unless check_solution(1, -5, 6) == \"No\""
] | raise 'fail' unless check_solution(1, 3, 2) == "No" | The function `Check_Solution` checks whether a quadratic equation ax^2 + bx + c = 0 has roots where one root is twice the other. The function takes three integer arguments, `a`, `b`, and `c`, and returns "Yes" if one root is twice the other, and "No" otherwise. | def Check_Solution(a,b,c):
if (2*b*b == 9*a*c):
return ("Yes");
else:
return ("No"); | [
"assert Check_Solution(1,3,2) == \"Yes\"",
"assert Check_Solution(1,2,3) == \"No\"",
"assert Check_Solution(1,-5,6) == \"No\""
] | assert Check_Solution(1,3,2) == "No" | |
lua | Please implement a Lua function called `get_carol` that calculates the nth Carol number. The function takes a single integer as input and returns an integer representing the nth Carol number. Here's what the function should accomplish:
1. For input 4, expect the output to be 223.
2. For input 5, expect the output to b... | function get_carol(n)
local result = (2^n) - 1
return result * result - 2
end | [
"assert(get_carol(2) == 7)",
"assert(get_carol(4) == 223)",
"assert(get_carol(5) == 959)"
] | assert(get_carol(2) == 20) | Define a function `get_carol(n)` which returns the n'th Carol number calculated using the relation \( C_n = (2^n - 1)^2 - 2 \). The function accepts an integer `n` and returns an integer representing the n'th Carol number. | def get_carol(n):
result = (2**n) - 1
return result * result - 2 | [
"assert get_carol(2) == 7",
"assert get_carol(4) == 223",
"assert get_carol(5) == 959"
] | assert get_carol(2) == 20 | |
javascript | Create a JavaScript function named `countDigit` that takes a single integer as its argument and returns the number of digits in that integer. Here's what it should do: for input `11223305`, expect the output to be `8`; for input `4123459`, expect the output to be `7`; and for `12345`, expect it to be `6`. Note that the... | function countDigit(n) {
let count = 0;
while (n !== 0) {
n = Math.floor(n / 10);
count++;
}
return count;
} | [
"assert.strictEqual(countDigit(12345), 5); // number of digits in 12345",
"assert.strictEqual(countDigit(11223305), 8); // number of digits in 11223305",
"assert.strictEqual(countDigit(4123459), 7); // number of digits in 4123459"
] | assert.strictEqual(countDigit(12345), 6); // incorrect number of digits in 12345 | The coding problem requires the implementation of a function named `count_Digit` that takes an integer as input and returns the number of digits in that integer. The function accepts a single integer parameter and outputs an integer. | def count_Digit(n):
count = 0
while n != 0:
n //= 10
count += 1
return count | [
"assert count_Digit(12345) == 5",
"assert count_Digit(11223305) == 8",
"assert count_Digit(4123459) == 7"
] | assert count_Digit(12345) == 6 | |
javascript | hey, i need a javascript function called `volumeCuboid` that calculates the volume of a cuboid. it takes three args: length, width, and height. heres what ive got so far but its not working:
```javascript
function volumeCuboid(l, w, h) {
// todo: calculate volume
}
```
here's what it should do:
- for `volumeCuboid(... | function volumeCuboid(l, w, h) {
return l * w * h;
} | [
"assert.strictEqual(volumeCuboid(1, 2, 3), 6); // typical small cuboid",
"assert.strictEqual(volumeCuboid(5, 7, 9), 315); // example with medium dimensions",
"assert.strictEqual(volumeCuboid(10, 15, 21), 3150); // larger cuboid volume"
] | assert.strictEqual(volumeCuboid(1, 2, 3), 10); // incorrect test case | Write a function named `volume_cuboid` that calculates the volume of a cuboid given its length, width, and height. The function should take three arguments (length, width, height) and return the volume as an integer. | def volume_cuboid(l,w,h):
volume=l*w*h
return volume | [
"assert volume_cuboid(1,2,3)==6",
"assert volume_cuboid(5,7,9)==315",
"assert volume_cuboid(10,15,21)==3150"
] | assert volume_cuboid(1,2,3)==10 | |
javascript | hey, can you whip up a javascript function called `roundNum` that takes two integers, `number` and `multiple`, and rounds the `number` to the nearest `multiple`? like, for example, `roundNum(1111, 5)` should give you 1110, and `roundNum(219, 2)` should give you 218. oh, and if you pass `roundNum(4722, 10)`, it should r... | function roundNum(number, multiple) {
let a = Math.floor(number / multiple) * multiple;
let b = a + multiple;
return (number - a > b - number) ? b : a;
} | [
"assert.strictEqual(roundNum(4722, 10), 4720); // rounds to nearest multiple",
"assert.strictEqual(roundNum(1111, 5), 1110); // rounds to nearest multiple",
"assert.strictEqual(roundNum(219, 2), 218); // rounds to nearest multiple"
] | assert.strictEqual(roundNum(4722, 10), 4800); // expected to round up | Problem rephrase: Implement a function named `round_num` that accepts two integers, `number` and `multiple`, and rounds the `number` to the nearest multiple of `multiple`.
Input: (number: int, multiple: int)
Output: int | def round_num(n,m):
a = (n //m) * m
b = a + m
return (b if n - a > b - n else a) | [
"assert round_num(4722,10)==4720",
"assert round_num(1111,5)==1110",
"assert round_num(219,2)==218"
] | assert round_num(4722,10)==4800 |
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