id stringclasses 8
values | split stringclasses 1
value | topic stringclasses 3
values | concept_id stringclasses 8
values | prereqs listlengths 0 2 | rung stringclasses 3
values | difficulty stringclasses 3
values | problem dict | ground_truth dict | attempts listlengths 1 1 | feedback listlengths 1 1 | solution dict | provenance dict |
|---|---|---|---|---|---|---|---|---|---|---|---|---|
physics-v1-E1-R3-4bdc0d81 | train | E | E1 | [
"N3"
] | R3 | medium | {
"template_id": "E1-R3-work-at-angle",
"params": {
"force_N": {
"value": 50,
"unit": "N"
},
"distance_m": {
"value": 10,
"unit": "m"
},
"angle_deg": {
"value": 30,
"unit": "°"
}
},
"text": "A child pulls a sled 10 m across level snow in a playground u... | {
"answer": 433,
"unit": "J",
"tolerance_rel": 0.01
} | [
{
"misconception_id": "MC17",
"text": "I think the work is just the force times the distance because the angle doesn't matter. So, 50 N times 10 m equals 500 J.",
"final_answer": 500
}
] | [
{
"for_attempt": 0,
"text": "Do you think the angle of the rope doesn't affect the work done? Consider how the direction of the force relates to the direction of the motion."
}
] | {
"steps": [
"Find the component of the force that acts in the direction of motion: 50 N × cos(30°) = 50 N × 0.866 = 43.3 N",
"Calculate the work done by multiplying the force component by the distance: 43.3 N × 10 m = 433 J"
],
"final_answer": 433
} | {
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"template_version": "0.1.0-spec",
"seed": 3,
"gen_attempt": 0,
"checks": {
"V2": "pass",
"V3": "pass",
"V4": "pass",
"V5": "pass",
"V6": "pass",
"V9": "pass",
"V10": "pass",
"V7": "pass"
},
"human_review": {
"rev... |
physics-v1-E2-R3-3da3077d | train | E | E2 | [
"E1"
] | R3 | medium | {
"template_id": "E2-R3-kinetic-energy",
"params": {
"mass_kg": {
"value": 1200,
"unit": "kg"
},
"speed_m_s": {
"value": 20,
"unit": "m/s"
}
},
"text": "An object with a mass of 1200 kg is moving at a speed of 20 m/s on a construction site. Calculate the kinetic energy of... | {
"answer": 240000,
"unit": "J",
"tolerance_rel": 0.01
} | [
{
"misconception_id": "MC14",
"text": "To find the kinetic energy, I use the formula that I thought was correct, KE = ½·m·v. So, I take the mass, which is 1200 kg, and the speed, which is 20 m/s, and calculate: KE = ½ × 1200 × 20 = 12000 J.",
"final_answer": 12000
}
] | [
{
"for_attempt": 0,
"text": "Why did you use velocity alone to calculate the kinetic energy? Does the energy double if the speed doubles?"
}
] | {
"steps": [
"Kinetic energy formula: KE = ½·m·v²",
"Plugging in the values: KE = ½ × 1200 kg × (20 m/s)²",
"Calculating the speed squared: (20 m/s)² = 400 m²/s²",
"Calculating the kinetic energy: KE = ½ × 1200 × 400 = 240000 J",
"The kinetic energy of the object is 240000 J."
],
"final_answer... | {
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"template_version": "0.1.0-spec",
"seed": 4,
"gen_attempt": 0,
"checks": {
"V2": "pass",
"V3": "pass",
"V4": "pass",
"V5": "pass",
"V6": "pass",
"V9": "pass",
"V10": "pass",
"V7": "pass"
},
"human_review": {
"rev... |
physics-v1-E5-R4-213f7ba0 | train | E | E5 | [
"E4",
"N6"
] | R4 | hard | {
"template_id": "E5-R4-slide-with-friction",
"params": {
"height_m": {
"value": 4,
"unit": "m"
},
"angle_deg": {
"value": 45,
"unit": "°"
},
"mu_k": {
"value": 0.30000000000000004,
"unit": ""
}
},
"text": "A skier starts from rest at the top of a ski ... | {
"answer": 7.41,
"unit": "m/s",
"tolerance_rel": 0.01
} | [
{
"misconception_id": "MC16",
"text": "I used the principle of conservation of energy, assuming no friction affects the skier's speed. The potential energy at the top, 4 m × 9.8 m/s², equals the kinetic energy at the bottom, 0.5 × v². Solving for v, I get 8.85 m/s.",
"final_answer": 8.85
}
] | [
{
"for_attempt": 0,
"text": "How does friction affect the skier's speed on the ramp, and how does this impact the conservation of mechanical energy?"
}
] | {
"steps": [
"The ramp length is calculated as 5.66 m, and the work done by friction per kg is 11.8 J.",
"Initial potential energy is 4 m × 9.8 m/s² = 39.2 J/kg.",
"Work done by friction = 11.8 J/kg, subtract from initial potential energy to get final kinetic energy: 39.2 J/kg - 11.8 J/kg = 27.4 J/kg.",
... | {
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"template_version": "0.1.0-spec",
"seed": 3,
"gen_attempt": 0,
"checks": {
"V2": "pass",
"V3": "pass",
"V4": "pass",
"V5": "pass",
"V6": "pass",
"V9": "pass",
"V10": "pass",
"V7": "pass"
},
"human_review": {
"rev... |
physics-v1-K1-R3-48c8f309 | train | K | K1 | [] | R3 | medium | {
"template_id": "K1-R3-out-and-back",
"params": {
"east_m": {
"value": 800,
"unit": "m"
},
"west_m": {
"value": 350,
"unit": "m"
}
},
"text": "A person walks 800 m due east in a warehouse, then turns around and walks 350 m due west. What is the magnitude of the person's ... | {
"answer": 450,
"unit": "m",
"tolerance_rel": 0.01
} | [
{
"misconception_id": "MC04",
"text": "I walked 800 m east and then 350 m west. To find the displacement, I think I just need to add these distances together because that's the total distance I traveled. So, the displacement should be 800 m + 350 m = 1150 m.",
"final_answer": 1150
}
] | [
{
"for_attempt": 0,
"text": "Is the displacement the same as the total distance traveled? Consider how the direction of movement affects the displacement."
}
] | {
"steps": [
"The person walks 800 m east, then 350 m west.",
"To find the displacement, subtract the distance walked west from the distance walked east.",
"800 m - 350 m = 450 m",
"This means the person's displacement is 450 m east."
],
"final_answer": 450
} | {
"generator": "mlx-community/Qwen2.5-32B-Instruct-4bit",
"template_version": "0.1.0-spec",
"seed": 1,
"gen_attempt": 0,
"checks": {
"V2": "pass",
"V3": "pass",
"V4": "pass",
"V5": "pass",
"V6": "pass",
"V9": "pass",
"V10": "pass",
"V7": "pass"
},
"human_review": {
"rev... |
physics-v1-K6-R1-22e5357f | train | K | K6 | [
"K5"
] | R1 | easy | {
"template_id": "K6-R1-drop-two-masses",
"params": {},
"text": "A marble and a steel shot put are dropped at the same moment from a height of 10 m. Ignore air resistance. Which statement is correct?",
"options": [
"A) A steel shot put hits the ground first.",
"B) They hit the ground at the same time.",... | {
"answer": "B",
"unit": null,
"tolerance_rel": 0
} | [
{
"misconception_id": "MC01",
"text": "Since the steel shot put is much heavier than the marble, it should fall faster and hit the ground first. Therefore, the answer is A.",
"final_answer": "A"
}
] | [
{
"for_attempt": 0,
"text": "If heavier objects fall faster, how would you explain two pieces of paper of different weights falling at the same speed in a vacuum?"
}
] | {
"steps": [
"In a vacuum, all objects fall at the same rate regardless of their mass.",
"Since air resistance is ignored, the marble and the steel shot put will fall at the same rate and hit the ground at the same time.",
"The correct answer is B."
],
"final_answer": "B"
} | {
"generator": "mlx-community/Qwen2.5-32B-Instruct-4bit",
"template_version": "0.1.0-spec",
"seed": 1,
"gen_attempt": 1,
"checks": {
"V2": "pass",
"V3": "pass",
"V4": "pass",
"V5": "pass",
"V6": "pass",
"V9": "pass",
"V10": "pass",
"V7": "pass"
},
"human_review": {
"rev... |
physics-v1-K7-R1-13b3e76d | train | K | K7 | [
"K6"
] | R1 | easy | {
"template_id": "K7-R1-drop-vs-launch",
"params": {},
"text": "From a height of 5.0 m, one ball is dropped while an identical ball is launched horizontally at 3 m/s at the same instant. Ignore air resistance. Which statement is correct?",
"options": [
"A) The launched ball lands first, because it is moving... | {
"answer": "C",
"unit": null,
"tolerance_rel": 0
} | [
{
"misconception_id": "MC13",
"text": "I think the launched ball will land first because it's moving faster horizontally. Since it's moving faster, it should hit the ground sooner than the ball that is just dropped straight down. So, I choose A.",
"final_answer": "A"
}
] | [
{
"for_attempt": 0,
"text": "Does the horizontal speed affect how quickly the ball falls vertically? Consider the motion of the balls in the vertical direction alone."
}
] | {
"steps": [
"Both balls experience the same gravitational acceleration in the vertical direction, regardless of their horizontal speed.",
"The time it takes for each ball to fall 5.0 m is determined solely by the vertical motion.",
"Since both balls fall the same distance under the same acceleration, the... | {
"generator": "mlx-community/Qwen2.5-32B-Instruct-4bit",
"template_version": "0.1.0-spec",
"seed": 2,
"gen_attempt": 2,
"checks": {
"V2": "pass",
"V3": "pass",
"V4": "pass",
"V5": "pass",
"V6": "pass",
"V9": "pass",
"V10": "pass",
"V7": "pass"
},
"human_review": {
"rev... |
physics-v1-N4-R1-5553fe5d | train | N | N4 | [
"N1"
] | R1 | easy | {
"template_id": "N4-R1-collision-forces",
"params": {},
"text": "A truck collides head-on with a small car. During the collision, how do the forces they exert on each other compare?",
"options": [
"A) Only a truck exerts a force; a small car just gets pushed.",
"B) A truck exerts a larger force on a sm... | {
"answer": "C",
"unit": null,
"tolerance_rel": 0
} | [
{
"misconception_id": "MC09",
"text": "I think the truck exerts a larger force on the small car because it's bigger and heavier. The small car just gets pushed, so the force it exerts is not as important. Therefore, I choose A.",
"final_answer": "A"
}
] | [
{
"for_attempt": 0,
"text": "If the truck exerts a larger force, shouldn't the small car move much more than the truck? How would both objects affect each other's motion in the collision?"
}
] | {
"steps": [
"According to Newton's Third Law, for every action, there is an equal and opposite reaction.",
"This means that the force the truck exerts on the small car is equal in size and opposite in direction to the force the small car exerts on the truck.",
"The correct answer is C."
],
"final_ans... | {
"generator": "mlx-community/Qwen2.5-32B-Instruct-4bit",
"template_version": "0.1.0-spec",
"seed": 3,
"gen_attempt": 0,
"checks": {
"V2": "pass",
"V3": "pass",
"V4": "pass",
"V5": "pass",
"V6": "pass",
"V9": "pass",
"V10": "pass",
"V7": "pass"
},
"human_review": {
"rev... |
physics-v1-N5-R3-2f67b1dc | train | N | N5 | [
"N3"
] | R3 | medium | {
"template_id": "N5-R3-weight",
"params": {
"mass_kg": {
"value": 12,
"unit": "kg"
}
},
"text": "A factory has a piece of machinery with a mass of 12 kg placed on the Earth's surface. Calculate the weight of this machinery in newtons, given g = 9.8 m/s².",
"options": null
} | {
"answer": 118,
"unit": "N",
"tolerance_rel": 0.01
} | [
{
"misconception_id": "MC18",
"text": "To find the weight of the machinery, I simply use the mass which is given as 12 kg. Since weight is the same as mass, the weight of the machinery is 12 N.",
"final_answer": 12
}
] | [
{
"for_attempt": 0,
"text": "Consider the difference between mass and weight. How does gravity play a role in calculating weight?"
}
] | {
"steps": [
"The weight of an object is given by the mass multiplied by the gravitational acceleration.",
"So, weight = 12 kg × 9.8 m/s²",
"Therefore, weight = 118 N"
],
"final_answer": 118
} | {
"generator": "mlx-community/Qwen2.5-32B-Instruct-4bit",
"template_version": "0.1.0-spec",
"seed": 1,
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"V3": "pass",
"V4": "pass",
"V5": "pass",
"V6": "pass",
"V9": "pass",
"V10": "pass",
"V7": "pass"
},
"human_review": {
"rev... |
Learning Paths in Intro Mechanics: free sample
Creative Data Lab · 8 of 45 records from batch-001
Learning paths through introductory mechanics. Each record is a problem, one or two realistic wrong attempts tagged with a documented misconception, Socratic tutor feedback, and a correct worked solution.
This is a free sample so you can check the schema and quality. The full dataset is creativedatalab/physics-v1 (US$149 per organization, instant access after purchase at creative-data-lab-production.up.railway.app).
Load it
from datasets import load_dataset
records = load_dataset("creativedatalab/physics-v1-sample", "master") # full records (default)
sft = load_dataset("creativedatalab/physics-v1-sample", "sft") # problem -> worked solution
tutor = load_dataset("creativedatalab/physics-v1-sample", "tutor") # problem + wrong attempt -> guiding question
preference = load_dataset("creativedatalab/physics-v1-sample", "preference") # chosen / rejected pairs
steps = load_dataset("creativedatalab/physics-v1-sample", "step_labels") # per-step labels, first error marked
Files
| File | Sample rows | Full dataset |
|---|---|---|
master/records.jsonl |
8 | 45 |
exports/sft.jsonl |
8 | 45 |
exports/tutor.jsonl |
8 | 49 |
exports/preference.jsonl |
8 | 49 |
exports/step_labels.jsonl |
16 | 94 |
How it was made
- Ground truth is computed by code. Every problem comes from a parameterised template; the correct answer and each misconception's wrong answer are computed with sympy, never by a language model.
- Text is written by an open-weight model:
mlx-community/Qwen2.5-32B-Instruct-4bit(Apache 2.0), which writes problem wording, student attempts, feedback and solution steps around the computed values. - Every record passed automated checks: answer matches truth within 1%; each wrong attempt lands exactly on its misconception's predicted answer; feedback does not leak the answer; all arithmetic in the text recomputes; no LaTeX or formatting debris; no duplicate problems.
- Human review: 0 of 53 records reviewed so far.
Batch yield: 53 of 56 problems kept (45 on the first try).
Coverage
| Topic | Records |
|---|---|
| E Work and energy | 10 |
| K Kinematics | 15 |
| N Newton's laws | 20 |
| Rung | Records |
|---|---|
| R1 Intuition | 11 |
| R2 Definition | 4 |
| R3 One step | 24 |
| R4 Multi step | 6 |
| Concept | Records |
|---|---|
| E1 Work by a force | 4 |
| E2 Kinetic energy / work–energy theorem | 4 |
| E5 Energy with friction | 2 |
| K1 Displacement vs. distance | 4 |
| K6 Free fall | 7 |
| K7 Projectile motion | 4 |
| N4 Third law (interaction pairs) | 4 |
| N5 Weight | 4 |
| N6 Friction (static and kinetic) | 4 |
| N7 Inclined planes | 4 |
| N8 Tension and pulleys (Atwood) | 4 |
| Misconception | Records |
|---|---|
| MC01 Heavier objects fall faster | 3 |
| MC02 Motion requires a force in its direction | 4 |
| MC03 Zero velocity means zero acceleration | 4 |
| MC04 Distance equals displacement | 4 |
| MC09 Bigger object exerts bigger force | 4 |
| MC10 Normal force always equals mg | 4 |
| MC11 Static friction always equals μs·N | 4 |
| MC13 Horizontal speed changes fall time | 4 |
| MC14 Kinetic energy is linear in speed | 4 |
| MC16 Mechanical energy conserved despite friction | 2 |
| MC17 Perpendicular forces do work | 4 |
| MC18 Mass and weight are the same | 4 |
| MC19 Rope tension equals hanging weight | 4 |
Record schema (master)
id, split, topic, concept_id, prereqs, rung (R1 intuition → R5 transfer), difficulty,
problem (template, params, text, options), ground_truth (answer, unit, tolerance), attempts
(misconception_id, text, final_answer), feedback, solution (steps, final_answer), provenance
(generator, template version, seed, check results, human review).
Step labels: how to read them
Correct solutions are labelled +1 at every step. For misconception attempts, the first step that reaches the
misconception's wrong answer, and every step after it, are labelled -1. Earlier steps are null: they are not
verified either way.
Limitations
- Sample batch: 11 of 22 planned concepts, 45 training records.
- Multiple-choice stems are template-written, so wording repeats across records of the same template.
- Physics is checked by code; pedagogy (realism of attempts, quality of feedback) relies on human review.
License
Problems are original, generated from in-house templates. Dataset license: per client agreement.
License
Sample: Creative Data Lab Dataset License, evaluation use. The full dataset carries the same license for training and evaluation inside one organization.
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