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0 | From the image calculate the rate of depreciation | d | As per the Straight Line Method SLM
Capitalized cost Original cost = Purchase price + expenses to be capitalized
Depreciable amount = Capitalized cost − Residual value
Annual depreciation ₹ = Depreciable amount ÷ Useful life
Rate of depreciation % p.a. = Annual depreciation ÷ Capitalized cost × 100
... | M1: 20%, M2: 10%, M3: 8%, M4: 28% | M1: 20%, M2: 10%, M3: 18%, M4: 18% | M1: 10%, M2: 15%, M3: 10%, M4: 18% | M1: 10%, M2: 15%, M3: 18%, M4: 8% | english | tough | Foundamental Accounts | Finance | |
1 | From the image, calculate the cash & discount | a | Ledger Postings T-accounts
Arun A/c
Cr side:
Dec 5 — By Cash … ₹2,000
Rajesh A/c
Cr side:
Dec 14 — By Cash ₹950; By Discount Allowed ₹50 … ₹1,000
Dec 26 — By Cash ₹1,900; By Discount Allowed ₹100 … ₹2,000
Total credited to Rajesh = ₹3,000
Sanjay A/c
Dr side:
Dec 7 — To Cash ₹2,900
Dec 7 — To Discount Recei... | Closing Cash Balance Balance c/d = ₹7,300
Total Discount Allowed Dr column = ₹150
Total Discount Received Cr column = ₹200 | Closing Cash Balance Balance c/d = ₹7,100
Total Discount Allowed Dr column = ₹100
Total Discount Received Cr column = ₹200 | Closing Cash Balance Balance c/d = ₹6,100
Total Discount Allowed Dr column = ₹150
Total Discount Received Cr column = ₹220 | "Closing Cash Balance Balance c/d = ₹7,700
Total Discount Allowed Dr column = ₹400
Total Discount Received Cr column = ₹200 | english | tough | Basic Statistics | null | |
2 | From the image find out Balances brought down 1 May 2023
Cash Balance and Bank Balance? | b | ### Three-Column Cash Book Cash, Bank & Discount — April 2023
* Balances brought down to next month included *
**Important treatment used as per the question line items :**
* **Apr 24 cheque from Patel** is treated as **cheque in hand Cash column **, because **Apr 26** separately says “Deposited Patel’s cheq... | Cash Balance b/d = ₹7,000
Bank Balance b/d = ₹1,980 | Cash Balance b/d = ₹7,580
Bank Balance b/d = ₹5,980 | Cash Balance b/d = ₹,6580
Bank Balance b/d = ₹5,80 | Cash Balance b/d = ₹5,580
Bank Balance b/d = ₹6,980 | english | moderate | Basic Statistics | null | |
3 | complete solution: Three-Column Cash Book Cash, Bank & Discount | b | A Discount totals
Apr 6: Discount allowed to Sridhara = ₹200 → Discount Allowed Dr. = ₹200
Apr 7: Discount allowed by Ramvilas = ₹65 → Discount Received Cr. = ₹65
B Cash balance ₹7,870
Cash receipts
Opening cash Apr 1 = ₹385
Capital introduced in cash Apr 4 : 10,000 total, 6,000 in bank ⇒ cash par... | Cash in hand = ₹17,870
Bank balance = Dr. ₹90,150
Discount Allowed = Dr. ₹200
| Cash in hand = ₹17,870
Bank balance = Dr. ₹10,150
Discount Allowed = Dr. ₹300
| Cash in hand = ₹7,870
Bank balance = Dr. ₹12,150
Discount Allowed = Dr. ₹200
| Cash in hand = ₹15,870
Bank balance = Dr. ₹10,150
Discount Allowed = Dr. ₹300
| english | moderate | Basic Statistics | null | |
4 | What is the ratio of the number of students pased
from University A in year 20007 and the number 5.
students passed from University B in year 2004 | b | Required ratio = 50: 35 = 10: 7 | 7:10 | 10:07 | 4:05 | 5:04 | english | moderate | Basic Statistics | null | |
5 | The number of students from University B in the year
2008 is approximately what percentage of the total
number of students passed from University A ovet the
years? | b | Required percentage = 50/225 X 100
= 22.22% ~ 22% approximately | 20 | 22 | 28 | 30 | english | moderate | Basic Statistics | null | |
6 | What is the ratio between the number of students
passed in the years 2007, 2008 and 2005 from University A? | b | Required ratio = 50: 30:30 = 5:3:3 | 3:05:05 | 5:03:03 | 5:03:02 | 5:02:02 | english | moderate | Basic Statistics | null | |
7 | What is the difference between the total number of
students passed from both the universities together in
2007 and the total number of students passed from
both the universities together in 2005? | a | Total number of students passed in 207
= 110 in thousands
Total number of students passed in 2005 = 40
in thousands
Required difference = 110 - 40 = 70 in thusand | 70,000 | 80,000 | 8,50,000 | 90,000 | english | moderate | Basic Statistics | null | |
8 | If Section-II in College B's 2nd year class and Section-1
in College D's 30 year class have the same number of
students, then the ratio of the number of students in
Section-ll in College B's 20d year class to that of Section-Ill in College D's 5 ' year class is ____ | d | The Section I of 3^ Year has 20% of 180 students =
36 = College B's 2» Year's Section I students. as
given that both are equal in number.
D's 5th Year - Section III students = 35% of 180
= 63
Thus, ATQ, the required ratio = 36: 63 = 4:7 | 2:04 | 5:07 | 5:06 | 4:07 | english | moderate | Basic Statistics | null | |
9 | What is the total number of students in Section-I of all
classes in College D? | b | We can take individual calculation for Section I
of individual class, but as each class has 180 stu-
dents. So, we can combine all the percentages
and calculate with 180 to get the combined fig-
ure as done below:
1 Year - Section 1 = 30 + 50 + 20 + 45 + 35
% of 180 = 180% of 180 = 324 | 320 | 324 | 250 | 252 | english | moderate | Basic Statistics | null | |
10 | The number of students in Section-Ill of 4th year class
in College D is _% of the total number students in
College A. | c | From the Table, Total No. of students in College
A = 450
No. of students in Section III of 4h Year of
College D = 20% of 180 = 36
Thus, required p e r c e n t a g e = 36 / 4 5 0 X 1 0 0 = 8. | 5 | 6 | 8 | 10 | english | moderate | Basic Statistics | null | |
11 | If 20% of the students in College A move to College D
and are equally distributed in each class, then what is
the number of students in Section-II of College E's 3rd
year class? | d | All colleges work independently, so any such
movement of students will alter the students of
A and D only, and will not have any impact on E. | 36 | 45 | 72 | cannot be determined | english | moderate | Basic Statistics | null | |
12 | What is the difference between the number of students in College C and in Section-IlI across all classes in College D? | a | The total number of students in Sections III of
all classes = 35 + 25 + 25 + 20 + 35 % of 180
= 140% of 180 = 252
The number of students in College C = 1080
given Thus, the difference = 1080 - 252 = 828 | 828 | 830 | 838 | 756 | english | moderate | Basic Statistics | null | |
13 | For which of the following years, the percentage rise/
fall in production from the previous year is the maxi-
mum for Company Y? | a | Percentage change rise/fall in the production of Company Y in comparison to the previous year for different years is:
For 2017 =[ 35-25 /25 x100]% = 40%
For 2018 = [ 35-35 /35 x100]% = 0%
For 2019 = [ 40 - 35 /35 X100]%=14.29%
For 2020 = [ 50-40 /40 x100] % = 25% | 2017 | 2018 | 2019 | 2020 | english | moderate | Financial Math | null | |
14 | What is the ratio of the average production of Com-
pany X over the period 2018-20 to the average pro-
duction of Company Y over the same period? | c | Average production of Company X over the
period 2018-20
= [1/3 x 25+50+40 ] = 115/3 lakhs tons. Average production of Company X over the
period 2018-20
= [1/3 x 35+50+40 ] = 125/3 lakhs tons. thus the required = 115/3 / 125/3 = 23:25 | 1:01 | 15:17 | 23:25 | 27:29:00 | english | moderate | Financial Math | null | |
15 | The average production for 5 years was maximum for which company | null | Average production in lakh tons in 5 years
for the three companies is:
For Company X
[ 1/3 x 30+45+25+50+40 ]= 190/5 = 38
For Company Y
[ 1/3 x 25+35+355+40+50 ]= 180/5 = 37
For Company Z
[ 1/3 x 35+40+45+35+35 ]= 190/5 = 38
Thus, average production of five 5 is maximum
for both the Companies X and Z | X | Y | Z | both X and Z | english | moderate | Financial Math | null | |
16 | In which year was the percentage of production
of Company Z to the production of Company Y the maximum? | a | The percentages of production of Company
Z to the production of Company Z for various
years are: For 2016 = 35/25 x 100 % = 140%
For 2017 = 40/35 x 100 % = 114.29%
For 2018 = 45/35 x 100 % = 128.57%
For 2019 = 35/40 X 100 % = 87.5%
For 2020 = 35/50 x 100 % = 70% | 2016 | 2017 | 2018 | 2019 | english | moderate | Financial Math | null | |
17 | What is the percentage increase in the production of
Company Y from 2016 to 2019? | d | Percentage increase in the production of
Company Y from 2016 to 2019: = 40-25 / 25 x100% = 60% | 30% | 45% | 50% | 60% | english | moderate | Financial Math | null | |
18 | What is the total number of items of type C produced
in the year 2020 and 2021 together? | b | The No. of items of C type produced in 2020 and
2021 = 17% of 48600 + 8% of 62500
= 8262 + 5000 = 13262 | 12482 | 13262 | 14786 | 15200 | english | moderate | Financial Math | null | |
19 | The number of items of type B produced in 2020 is
approximately _ % of the number of items of type B
produced in 2021. | d | : Number of type B items produced in 2020 =
18% of 48600 = 8748. Number of type B items produced in 2021 = 15% of 62500 = 9375
As comparison is with 2021, that will be taken as base.
Thus, desired answer = 9375 8748 X 100 = 93.31 =
approx 93% | 84 | 87 | 90 | 93 | english | moderate | Financial Math | null | |
20 | What is the ratio of the number of items of type D produced in 2020 to the number of items of type F produced in 2021? | c | Items of D Type in 2020
Items of F Type in 2021
20% of 48600 = 9720 24% of 62500 = 15000
972 : 1500
324 : 500
81 : 125 | 13:17 | 83 : 116 | 81 : 125 | 103 : 147 | english | moderate | Financial Math | null | |
21 | What is the total number of items of type A, B and C
produced by the company in 2020 and 2021 together? | a | Total Number of items by Company A, B and C in 2020
= 17 + 18 + 17 % of 48600 + 18 + 15 + 8 % of 62500
= 52% of 48600 + 41% of 62500 = 25272 + 25625 = 50897 | 50894 | 51164 | 52324 | 48542 | english | moderate | Financial Math | null | |
22 | The number of items of type E produced in the year
2021 is__% more than the number of items of type C produced in 2021. | d | Note that we don't need to do calculation with
62500, that is total of production of 2021.
The total is to assumed to be 100, and calcula-
tions to be done accordingly.
As they belong to the same year 2021, the %age
difference between E and C = 18 - 8 = 10
No. of items of type C in 2021 = 8
As the comparison is ... | 105 | 75 | 60 | 125 | english | moderate | Financial Math | null | |
23 | How many companies have shown production below
their average production in 2012-2013, but have
showed above the average production in 2013-14? | c | Average sales of company:
Honda = 6 + 14 + 21 = 13.66
GM = 12 + 18 + 18 = 16
Maruti = 5 + 9 + 15 = 9.66
Hindustan Morors = 16 + 9 + 12 = 12.33
Hyundai=8+ 14+72=9.66 | one | two | three | four | english | moderate | Financial Math | null | |
24 | The ratio of Hindustan Motors production in 2013-
2014 to Honda's production in 2012-2013 is | b | The required ratio is 9/6 = 1.5. | 0.66 | 1.5 | 2 | None of these | english | moderate | Financial Math | null | |
25 | For how many companies has there been no decrease in production in any year from the previous year? | c | By visual inspection, we can say that Honda,
GM and Maruti have not shown a decrease. | one | two | three | four | english | moderate | Financial Math | null | |
26 | Which of the following companies has shown consistent growth during the period? | d | By simple observation, we can say that d is
the right answer. | Maruti | Honda | Hindustan Motars | Both a and c | english | moderate | Financial Math | null | |
27 | Which of the following companies have shown high-
est and lowest growth rates? | b | By simple observation, we can say that b is
the right answer. | Honda and Hundai | Honda and Maruti | GM and Hundai | GM and Maruti | english | moderate | Financial Math | null | |
28 | What is the average of marks obtained by Aman for all subjects? | b | Average marks = 100 + 80 + 80 + 70 + 80 + 40 /6 = 75 | 72 | 75 | 80 | 85 | english | moderate | Basic Statistics | null | |
29 | What is the approximate percentage of marks
obtained by Ayush? | a | Percentage marks = [ 90 + 50 + 90+60+70 + 80 / 150 + 130 + 120 + 100 + 100 + 100 ]x100 = 62.8% | 62.8 | 72.5 | 75 | 74 | english | moderate | Basic Statistics | null | |
30 | What is the average of marks obtained by all candidates in Physics? | b | Average marks in Physics = 90+80+70+80+85+65+50 /7 =74.28 | 62.85 | 74.28 | 78.52 | None of these | english | moderate | Basic Statistics | null | |
31 | Who among the following has obtained the highest aggregate marks? | d | Aggregate marks: Ayush, 440; Aman, 450;
Sajal, 450; and Muskan, 465 | Ayush | Aman | Sajal | Muskan | english | moderate | Basic Statistics | null | |
32 | Who among the following has secured the highest
percentage marks in Physics, Chemistry and Maths? | b | As the denominator is same for the calculation of percentage of marks in all the cases, there is no need to calculate the percentage figures. Simply, the aggregate marks of three subects will provide the answer:
Ayush, 230; Aman, 260; Rohit, 225; and
Muskan, 230. | Ayush | Aman | Rohit | Muskan | english | moderate | Basic Statistics | null | |
33 | What is the percentage of candidates who qualifted
during 2007 for all states combined? | c | Percentage of candidates qualified = 5820 = [ 780 + 750 + 960 + 850 + 1560 /5200 + 7500 + 6400 + 8100 + 7800] x 100 = 14% | 12.00% | 14.00% | 15.00% | None of these | english | moderate | Basic Statistics | null | |
34 | What is the average percentage of candidates who
qualified from State M for all the years? | c | Percentage of candidates qualified =
Number of candidates qualified/ Number of candidates appeared X100
= [ 780 + 1170 + 1200 + 1320 + 1350 / 5200 + 7800 + 8000 + 8800 + 9000 ]x100 = 15%
If we look at all the figures for individual years, we can see that the result has been consistent at 15% for all these year... | 12% | 14% | 15% | 16% | english | moderate | Basic Statistics | null | |
35 | What is the average number of candidates who
appeared from State Q during the given years? | b | Average number of candidates appeared
8100 + 9000 + 9200 + 10,000+10,000 /5=9,260 | 8660 | 9260 | 9560 | 9660 | english | moderate | Basic Statistics | null | |
36 | What is the average number of candidates who qualified from the State N during the given years? | b | Average = 750+850 +860+920 + 880 /5=852 | 702 | 852 | 762 | 902 | english | moderate | Basic Statistics | null | |
37 | What is the percentage increase in candidates who appeared between 2007 and 2011? | b | Total number of candidates in 2007
= 35,000 as calculated in Question 25
Total number of candidates in 2011
= 9000 + 8800 + 10,000 + 10,000 + 11,200
= 49,000
Increase = 49,000 - 35,000 = 14,000
Percentage increase = 14,000/35,000 X 100=40 % | 35.00% | 40.00% | 45.00% | 50.00% | english | moderate | Basic Statistics | null | |
38 | In rural areas, which of the following sizes of the
households is the highest in number? | d | From the graph, we see that the line for
rural peaks at about 4-5.
Hence, the best answer is 4. | 15 | 2 | 3 | 4 | english | easy | Basic Statistics | null | |
39 | In urban areas, among the households of different
sizes, what is the percentage of households of size 5
or less? | b | Explanation: The total n u m b e r of households ≤5 is
17 + 14 + 12 + 15 + 14 = 72. | 13 | 72 | 36 | 87 | english | easy | Basic Statistics | null | |
40 | In rural areas, per 100 households, there were 31
households of size | c | Total up the values for rural area for the size 3 or less to get the answer | 3 or above | 3, 4 and 5 | 3 or less | 4 or less | english | easy | Basic Statistics | null | |
41 | As the urban population of towns increases, the average household size | d | As the population size increases, we see
that household sizes are 4.75, 4.50 and 4.70. Hence,
the values are fluctuating. | increse | decresse | remains constants | Fluctuates | english | easy | Basic Statistics | null | |
42 | Which of the following statements is true?
a On the average, there are more persons per family
in urban areas than in rural areas.
b In rural areas. 350 of the households are of that
size 7 and above.
c In urban areas, the average size of the household
is the least for towns.
d In urban areas, there ... | b | Only statement b can be inferred from the given graphs. | On the average, there are more persons per family
in urban areas than in rural areas. | In rural areas. 350 of the households are of that size 7 and above. | In urban areas, the average size of the household
is the least for towns | In urban areas, there are 460 persons on an average per 100 households. | english | easy | Basic Statistics | null | |
43 | What is the average profit earned by the company
over the years? | c | Total profit earned over 5 years = 25 + 35 +
22.5 + 30 + 37.5 = 150 lakhs
Average profit = 150/5 = Rs. 30 lakhs | Rs. 26 lakhs | Rs. 28 lakhs | Rs. 30 lakhs | Rs. 32 lakhs | english | moderate | Financial Math | null | |
44 | If the expenditure of the company in 2009 was
Rs. 28 lakhs, then what was the revenue of the company
in that year? | a | Revenue in 2009 = Profit + Expenditure
= 65.5 lakhs | Rs. 65.5 lakhs | Rs. 72.5 lakhs | Rs. 75 lakhs | None of these | english | moderate | Financial Math | null | |
45 | What is the approximate percentage increase in the
profit of the company in 2008 in comparison to the
previous year? | b | Ans: b Percentage increase = 30 - 23 /23 X 100
= 30.43 ~ 30% | 28 | 30 | 36 | 40 | english | moderate | Financial Math | null | |
46 | What is the ratio of profit earned by the company in
2005 to the profit earned in 2009? | b | The required ratio = 25: 37.5 = 2: 3 | 1:03 | 2:03 | 3:05 | 1:02 | english | moderate | Financial Math | null | |
47 | If the revenue of the company in 2007 was RS. 45 lakhs,
then what was the expenditure of the company in
that year? | b | Expenditure in 2007 = 45 - 22.5 = Rs. 22.5
lakhs | Rs. 20.5 lakhs | Rs. 22.5 lakhs | Rs. 24.5 lakhs | Rs. 25.5 lakhs | english | moderate | Financial Math | null | |
48 | What would be the gross profit? | d | Net Purchases
Purchases 2,55,000 − Returns 13,250 = 2,41,750
Trading A/c includes these direct items:
Opening stock = 2,00,000
Net purchases = 2,41,750
Wages = 1,00,000
Carriage = 5,000
Coal & coke = 25,000
Gas & water = 1,500 treated as direct
Factory lighting = 2,500
Total Trading debit
= 2,00,000 + 2,41... | 89,250 | 2,89,000 | 1,89,250 | 2,89,250 | english | moderate | Financial Math | null | |
49 | What is the difference between the total production of
the two companies in the given years? | c | Total production of Company X from 2007
to 2012 in thousands = 119 + 99 + 141 + 78 +
120 + 159 = 716
Total production of Company Y from 2007 to
2012 in thousands = 139 + 120 + 100 + 128 +
107 + 148 = 742
Difference = 742 - 716 thousands = 26,000 | 19,000 | 22,000 | 26,000 | 28,000 | english | moderate | Financial Math | null | |
50 | What would be the total credit? | b | Given Data Year ending 31 March 2024
Opening Stock 1-4-2023
₹2,40,000
Purchases
Cash purchases = ₹2,08,000
Credit purchases = ₹6,08,000
Total Purchases = ₹8,16,000
Less: Purchase returns = ₹8,000
➡️ Net Purchases = ₹8,08,000
Sales
Cash sales = ₹3,50,000
Credit sales = ₹6,00,000
Total Sales = ₹9,50,000
... | 20,73,000 | 10,73,000 | 10,7,000 | 20,83,000 | english | moderate | Financial Math | null | |
51 | In which of the following years was the diference
between the productions of Companies X and Y the
maximum? | d | The differences between the productions of
Companies X and Y in various years are as fol
lows all figures in thousands :
For 2007 139 - 119 = 20
For 2008 120 X 99 = 21
For 2009 141 - 100 = 41
For 2010 128 - 78 = 50
For 2011 120 - 107 = 13
For 2012 159 - 148 = 11
Hence, the maximum differenc... | 2007 | 2008 | 2009 | 2010 | english | moderate | Financial Math | null | |
52 | The production of Company Y in 2010 was approximately what percentage of the production of Company X in the same year? | b | As the comparison is with Company X, its
production figure will appear as denominator.
Required percentage = 1,28,000/78,000 x
100 = 164% | 173 | 164 | 132 | 97 | english | moderate | Financial Math | null | |
53 | If total expenditure during a year is 765 lakhs, then
what are the expenses on cultural events in lakhs ? | c | 5% of Rs. 65 lakhs = Rs. 3.25 lakhs | 1.67 | 2.65 | 3.25 | 4.25 | english | moderate | Financial Math | null | |
54 | What is the approximate angle extended by staff sala-
ries at the centre in degrees ? | b | Angle extended by staff salaries at the centre = 38 X 3.6 = 137° | 132 | 137 | 142 | 145 | english | moderate | Financial Math | null | |
55 | The total of which of the following heads is equal to
salary expenses? | b | Maintenance + transportation + sports = 38% | Miscellaneous, transportation and cultural events | Maintenance, transportation and sports | Maintenance, publicity and miscellaneous | None of the above | english | moderate | Financial Math | null | |
56 | If the teachers' salaries are increased by 20%, then
what will be the new angle extended at the centre in
degrees ? | d | No separate data is given for teachers' sal-
ary. Hence, it cannot be determined. So, new
angle extended may not be determined. | 45.6 | 43.6 | 56 | Cannot be determined | english | moderate | Basic Statistics | null | |
57 | What is the angle extended at the centre by a combination of miscellaneous and cultural events expenses
at the centre in degrees ? | null | Total of miscelleneous and cultural percentages = 15 + 5 = 20%. Hence, angle extended
by them at the centre = 20 / 100x 360 = 72°. | 65 | 72 | 78 | 84 | english | moderate | Basic Statistics | null | |
58 | If the publisher has to pay 761,200 as the printing cost
for production of a certain quantity of books, then
what will be the amount of royalty to be paid for these
books? | c | The ratio between printing cost and royalty
= 20 : 15 or 4 : 3.
Let royalty be denoted by R.
Then 4: 3 = 61,200 : R
RX 4 = 61,200 X 3
R = 61,200 x 3 /4 = Rs. 45,900 | Rs. 22,950 | Rs. 45,000 | Rs. 45,900 | Rs. 48,900 | english | moderate | Financial Math | null | |
59 | If the cost price of the book is ?150, then what is the
combined printing and binding cost for a single copy
of the book? | a | Total printing and binding cost = 20 + 20 = 40%
Printing and binding cost = 40% of cost price
= 40% of 150 = Rs. 60 | Rs. 60 | Rs. 75 | Rs. 80 | Rs. 72 | english | moderate | Financial Math | null | |
60 | What is the central angle of t he sector corresponding
to the expenditure incurred on royalty? | b | Central angle corresponding to royalty
= 15% of 360 º = 15/100 X 360 = 54° | 48° | 54° | 60° | 72° | english | moderate | Financial Math | null | |
61 | What is the difference between promotion and
printing cost if we assume that total cost is Rs. 200? | b | Difference in percentage terms = 20 - 10 = 10%
Then, 10% of Rs. 200 = Rs. 20 | Rs. 10 | Rs. 20 | Rs. 30 | Rs. 24 | english | moderate | Financial Math | null | |
62 | If 1000 copies are published and the transportation
cost on them amounts to 15,000, then what should
be the selling price per book so that the publisher can
earn a profit of 20%? | c | To calculate the selling price of a single book, we need to total the cost. Let us calculate that first.
Transportation cost per book = 15,000/1000 = Rs. 15
As transportation cost is 10% of total cost, thus
Rs. 15 = 10% of total cost
Total cost of printing a copy = 15 X 100/10 = Rs. 150
Now selling price = total c... | Rs. 150 | Rs. 160 | Rs. 180 | Rs. 200 | english | moderate | Financial Math | null | |
63 | Considering all the four years together, what is the average number of boys who appered from school E? | c | For 2019
Number of Boys = 75% of Total students
Number of Girls = 25% of Total students
Difference = 75% of TS - 25% of TS = 280
50% of Total Students = 280
Total Students = 2 8 0 x - 100 = 560
Number of boys = 75% of 560 = 420
Similarly for 2020
Number of boys and girls is 60% and 40% that
come by 100 - 60 ... | 424 | 434 | 438 | 455 | english | moderate | Basic Statistics | null | |
64 | What is the total number of girls who appeared in the
examination from all the six schools in 2020? | c | In School A
Difference = 70% - 30% = 40%
40% of Total Students = 75
Total students = 75 X 100/40 = 187.5
No. of Girls = 30% of 187.5 = 56.25 = 56 apprx.
Similarly, in School B
Percentage of Boys = 48
Percentage of Girls = 100 - 48 = 52
Difference = 5 2 - 48 = 4
4% of Total students = 18
Total students = 18... | 1364 | 1386 | 1280 | 1414 | english | moderate | Basic Statistics | null | |
65 | What is the difference between the total numbers of
students appearing from School B in 2020 and that in
2022? | a | Total No. of Students already calculated in 2nd
question = 450
For Year 2022
Difference = 60 - 40 = 20%
20% of Total students = 90
Total students = 90 X 100 = 450
Thus, overall difference = 450 - 450 = 0 | 0 | 17 | 29 | 35 | english | moderate | Basic Statistics | null | |
66 | What is the ratio of the number of boys who appeared
from School C in 2019 to the number of girls who
appeared from school E in 2021? | d | Given data for 2019 School C
Boys = 44%, Girls = 100 - 44 = 56%
Difference Boys - Girls = 56 - 44 % of Total = 60
12% of Total students = 60
Total students = 60 X 100- = 500
No. of Boys = 44% of 500 = 220
Given d a t a for 2021 School E
Now, No. of Boys = 70%
Girls = 100 - 70 = 30%
Difference = 70 -... | 5:04 | 8:07 | 9:08 | 10:09 | english | moderate | Basic Statistics | null | |
67 | In the year 2019, number of students appearing from
School F is __% more than the number of students
appearing from School C: | d | For Year 2019 School F
Number of Boys = 44%, Number of Girls
= 100 - 44 = 56%
Difference = 56 - 44 = 12%
12% of Total = 90
Total students = 90 X 100/12 = 750
For the Year 2019 School C
Number of Boys = 44%
Number of Girls = 100 - 44 = 56%
Difference = 56 - 44 = 12%
12% of Total students = 60
Total stud... | 40 | 66.66 | 20 | 50 | english | moderate | Basic Statistics | null | |
68 | Which city reported the highest number of positive cases? | b | City 1: 30 + 15 + 35 + 10 = 90
City 2: 35 + 10 + 30 + 10 = 85
City 3: 15 + 5 + 15 + 5 = 40
City 4: 10 + 5 + 5 + 15 = 35
Therefore, City 1 reported the highest number
of positive cases. | city 2 | city 1 | city 4 | city 3 | english | moderate | Basic Statistics | null | |
69 | What is the percentage of positive cases in City 2
across all hospitals? Round to two decimal places | b | Total Tests in City 2 = 100 + 50 + 100 + 50
= 300
Total Positive Cases in City 2 = 35 A + 10 B
+ 30 C + 10 D = 85
Percentage of Positive Cases in City 2
= 85/300 X 100 = 28.33% | 17.50% | 28.33% | 35.42% | 41.67% | english | moderate | Basic Statistics | null | |
70 | What is the ratio of positive cases in City 1 and City 3? | a | From the table, we can see:
City 1 had a total of 30 + 15 + 35 + 10 = 90 positive cases.
City 3 had a total of 15 + 5 + 15 + 5 = 40 positive cases.
Thus, the answer is 90: 40 or 9:4 | 9:04 | 6:05 | 9:05 | 11:04 | english | moderate | Basic Statistics | null | |
71 | What is the percentage of positive cases in City 4? | b | Total Tests in City 4 = 100 + 50 + 100 + 50
= 300 tests
Positive Cases in City 4 = 10 + 5 + 5 + 15
= 35 cases
Percentage of Positive Cases =
Positive Cases / Total Tests X 100
Percentage = 35/300 X 100 = 11.67% | 16 | 12 | 14 | 15 | english | moderate | Basic Statistics | null | |
72 | Which hospital has reported maximum number of
positive cases ? | a | Look at the positive cases at each hospital :
Hospital A: 30 + 35 + 15 + 10 = 90
Hospital B: 15 + 10 + 5 + 5 = 35
Hospital C: 35 + 30 + 15 + 5 = 85
Hospital D: 10 + 10 + 5 + 15 = 40
Therefore, Hospital A has reported the maxi-
mum number of positive cases | Hospital A | Hospital D | Hospital B | Hospital C | english | moderate | Basic Statistics | null | |
73 | If the ratio of literate males to illiterate males of City
'D' is 11: 7. Then what is the difference between the
number of literate males and number of illiterate
males of City 'D'? | d | Females in City D = 100 - 45 + 25
= 100 - 70 = 30%
30% of total = 3600
Total in City D = 3600/30 X 100 = 12000
Males in City D = 45% of 12000 = 45 X 12000/100 = 5400
Ratio of Literate Males to Illiterate Males = 11: 7
Literates = 11/18X 5400 = 3300
Other = 5400 - 3300 = 2100
Difference = 3300 - 2100 = 1200 | 900 | 1050 | 800 | 1200 | english | moderate | Basic Statistics | null | |
74 | Population of City 'C' is what percent less than the
population of City 'B'? | c | Total Population of City C PC
If 50% is 8000, then PC = 8000 x 2 = 16000
Total Population of City B PB
If 15% of City B is 3000, then PB =3000/15%
= 20000
Percentage Difference Calculation
Difference between PB and PC = 20000 - 16000 = 4000.
Percentage Difference = 4000/20000X 100 = 20% | 30.00% | 25% | 20% | 17.50% | english | moderate | Basic Statistics | null | |
75 | If the population of City E is anticipated to doubles by
the year 2035, but the ratio remains same, then what
will be total of populations of females and transgenders in that year? | d | ATQ, Number of Transgenders = [100 - 38 + 32 ]% of Total Population of E = 4200,
Population of E = 4200 X 100/30 = 14000
Total Population in 2035 = 2 X 14000 = 28000
As the ratio remains the same, the total of
females and transgenders in 2035 = 32 + 30 % of 28,000
= 62% of 28000 = 17,360 | 16600 | 18360 | 17200 | 17360 | english | moderate | Basic Statistics | null | |
76 | Female population in City 'C' is how much percent
less than the sum of male and transgender population
of City 'D'? | b | Calculate Female Population of City C
Total population of City C = 16000 as calculated in a previous question
Female percentage in City C = 35%
Female population in City C = 0.35 X 16000 = 5600.
Calculate Male and Transgender Population in City D
Total population of City D = 12000
from previous calculations ... | 25% | 33 x 1/3% | 50% | 66 x 2/3 % | english | moderate | Basic Statistics | null | |
77 | Male population of City 'E' is how much more than
female population of City 'A'? | d | Total Population of City E = 4200/[100 - 38 + 32 ] %
4200/30 x 100 =14,000
Male Population of City E = 38% of 14000
= 5320
For City A
Total Population of City A = 2000/[100 - 45 + 30 ] %
2000/25 x 100 =8,000
Female Population of City A = 30% of 8000
= 2400
Required Difference = 5320 - 2400 = 2920 | 2900 | 2840 | 2980 | 2920 | english | moderate | Basic Statistics | null | |
78 | What is the average population of State B for all the
years together in lakhs ? | c | Average population of State B for all years:Data for State B: 3.2 2002 , 3.6 2003 , 3.4 2004 , 3.8 2005 , 4.1 2006 , 4.4 2007 .Calculation: Sum = 3.2 + 3.6 + 3.4 + 3.8 + 4.1 + 4.4 = 22.5 lakhs.Average: 22.5 / 6 = 3.75 text lakhs . | 3.5 | 3.6 | 3.75 | 3.8 | english | moderate | Basic Statistics | null | |
79 | What is the percentage increase in population of State
A between 2002 and 2003? | c | Data: 4.5 2002 to 4.8 2003 .Calculation: 4.8 - 4.5 /4.5 X 100 = 0.3 /4.5 X 100 = 6.67 % . | 5 | 5.25 | 6.67 | 7.5 | english | moderate | Basic Statistics | null | |
80 | What was the difference between combined popu-
lations of all the three states for the years 2004 and
2005? | c | 1. Combined Population for 2004The populations for states A, B, and C in 2004 in lakhs are:State A: 5.2State B: 3.4State C: 5.8Total for 2004: 5.2 + 3.4 + 5.8 = 14.4lakhs 2. Combined Population for 2005The populations for states A, B, and C in 2005 in lakhs are:State A: 5.4State B: 3.8State C: 6.3Total for 2005: ... | 90,000 | 100000 | 110000 | None of the above | english | moderate | Basic Statistics | null | |
81 | What was the average population of al the three
states in 2006 in lakhs ? | b | Data: 5.8 A + 4.1 B + 6.6 C = 16.5 lakhs.Average: 16.5 / 3 = 5.5 text lakhs . | 5.5 | 5.8 | 6.1 | 6.3 | english | moderate | Basic Statistics | null | |
82 | What is the ratio between combined populations of all
the three states in 2004 and 2005? | c | Totals: 14.4 2004 and 15.5 2005 .Ratio: 14.4 : 15.5 , which simplifies to 144 : 155 . | 155 : 144 | 144 : 155 | 144 : 165 | 165 : 144 | english | moderate | Basic Statistics | null | |
83 | The number of students who appeared from School
E in 2004 is approximately what percentage of the
total number of students who appeared from all the school together in that year | c | Total in 2004: 650 + 760 + 820 + 800 + 780 = 3810 .Calculation: 780 /3810 X 100 = approx 20.47 % . | 16% | 18% | 20% | 25% | english | moderate | Basic Statistics | null | |
84 | What is the average number of students who appeared
from School B for all the years | b | Data: 760 + 740 + 820 + 880 + 840 = 4040 .Average: 4040 / 5 = 808 . | 676 | 787 | 808 | 818 | english | moderate | Basic Statistics | null | |
85 | The number of students who appeared in 2006 from
School A is what per cent of the total number of students who appeared from School A for al the years together | a | Total for School A: 650 + 700 + 800 + 750 + 850 = 3750 .Calculation: 800 /3750 X 100 = approx 21.33 % . | 25.25 | 21.33 | 22.45 | 23.45 | english | moderate | Basic Statistics | null | |
86 | What is the ratio between the total number of students who appeared in 2004 and 2005 from Schools C and D, respectively | a | 1. Identify Values from the TableBased on the table "Number of candidates who appeared from five schools":School C:Appeared in 2004: 820Appeared in 2005: 860School D:Appeared in 2004: 800Appeared in 2005: 7802. Calculate Total for Each SchoolNext, we sum the 2004 and 2005 values for each school:Total for School C: 820 ... | 84 : 79 | 79 :84 | 84 : 89 | 89 : 84 | english | moderate | Basic Statistics | null | |
87 | What is the average number of students who appeared
from the given schools in 2007 | c | null | 825 | 836 | 845 | 863 | english | moderate | Basic Statistics | null | |
88 | What is the difference between the number of gradu-
ates and the number of postgraduates in town C | d | Data: 15,150 text Grads - 10,500 text Postgrads = 4,650 . | 4500 | 4600 | 4650 | 4560 | english | moderate | Basic Statistics | null | |
89 | What is the average number of postgraduates in all
the towns together | b | Total Postgrads: 8,000 + 18,000 + 10,500 + 16,250 + 20,000 + 18,450 = 91,200 .Average: 91,200 / 6 = 15,200 . | 15000 | 15500 | 16250 | 15200 | english | moderate | Basic Statistics | null | |
90 | What is the ratio of the number of graduates from
towns A and B together to the number of postgraduates from towns A and E together | c | Grads A+B: 10,200 + 25,250 = 35,450 .Postgrads A+E: 8,000 + 20,000 = 28,000 .Ratio: 35,450 : 28,000 = 709 : 560 | 709 : 580 | 709 : 560 | 560 : 709 | None of these | english | moderate | Basic Statistics | null | |
91 | What is the total number of graduates and postgraduates in towns A, D and F together? | b | Town A: 10,200 + 8,000 = 18,200 .Town D: 20,200 + 16,250 = 36,450 .Town F: 16,500 + 18,450 = 34,950 .Total: 18,200 + 36,450 + 34,950 = 89,600 . | 85800 | 88600 | 89600 | 90600 | english | moderate | Basic Statistics | null | |
92 | The number of graduates in town F is approximately
what percentage of the number of postgraduates in
the same town? | b | Calculation: 16,500 /18,450 X 100 = approx 89.43 % . | 84 | 89 | 92 | 95 | english | moderate | Basic Statistics | null | |
93 | For how many years, the exports are at least 10%
higher than the imports? | a | 2004: 40 > 35 X1.1 (38.5) rightarrow Yes.2005: 65 > 60 X1.1 (66) rightarrow No.2007: 55 > 50 X1.1 (55) rightarrow Yes.Result: 2 years (2004, 2007). | 1 | 2 | 3 | 4 | english | moderate | Financial Math | null | |
94 | In which year have the exports shown the highes
growth in percentage terms in comparison to the preceding year? | b | 2005: 65-40 / 40 = 62.5 % rightarrow Highest. | 2005 | 2006 | 2007 | 2008 | english | moderate | Financial Math | null | |
95 | What are the average exports in billion 2 for the period 2004-2009? | b | Sum: 40+65+70+55+85+80 = 395 .Average: 395 / 6 = 65.83 billion ₹. | 60.35 | 65.83 | 70.2 | 75.36 | english | moderate | Financial Math | null | |
96 | By how much percentage are the total exports higher
than total imports from 2004 to 2009? | b | Data: 35 (2004) to 75 (2009).Calculation: 75-35 / 35 X100 = approx 114.29 % . | 4.15 | 5.33 | 6.33 | 7.58 | english | moderate | Financial Math | null | |
97 | What is the percentage increase in imports between
the years 2004 and 2009? | a | Imports: 35 (2004) to 75 (2009).Calculation: 75 - 35 / 35 X100 = approx 114.29 % . | 110 | 114 | 125 | 135 | english | moderate | Financial Math | null | |
98 | What is the ratio of the total enrolment of State B for
years 2010 and 2011 to the total enrolment of State D
for both the years combined? | c | Enrolment in 2010: 75 thousandEnrolment in 2011: 65 thousandTotal for State B: 75 + 65 = 140 . Enrolment in 2010: 85 thousandEnrolment in 2011: 95 thousandTotal for State D: 85 + 95 = 180 thousand 3. Calculate the RatioRatio formula: Total State B : Total State DCalculation: 140 : 180Simplification: Dividing both side... | 7:09 | 4:05 | 3:05 | 2:03 | english | moderate | Basic Statistics | null | |
99 | What is the percentage of total enrolment of State C
in comparison to enrolment of State E for years 2010
and 2011? | b | State C: 95+115=210.
State E: 75+95=170.
Calculation:
170
210
×100.
Final Answer: | 73 | 126 | 137 | 145 | english | moderate | Basic Statistics | null |
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