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If 25% of diesel engine cars in State 'C' are Air-Condi-
tioned (AC), then what is the number of diesel engine
cars which are non-AC in State 'C? | d | From above MCQ, No. of diesel cars in State C =
448 - 168 = 280
Thus, No. of non-AC Diesel cars = (100 - 25)%
of 280 = 75% of 280 = 210 | 150 | 90 | 190 | 210 | English | moderate | Generic math | Finance | |
What is the difference between the total number of
cars in State 'C' and the number of petrol engine cars
in State 'B'? | d | Total No. of Cars in State C = 448
Total No. of Petrol cars in State B = 392 - 140
= 252
Difference = 448 - 252 = 196. | 212 | 224 | 204 | 196 | English | moderate | Generic math | null | |
What is the sum of petrol engine cars in all the states
together? | b | This has been directly calculated in the table | 710 | 712 | 714 | 716 | English | moderate | Generic math | null | |
What is the sum of students passing from University B
in 2003, 2005 and 2006 together? | b | Required number of students = (30 + 10 +40) thousands = 80,000 | 75,000 | 80,000 | 88,000 | 90,000 | English | moderate | Generic math | null | |
What is the ratio of the number of students pased
from University A in year 20007 and the number 5.
students passed from University B in year 2004 | b | Required ratio = 50: 35 = 10: 7 | 7:10 | 10:07 | 4:05 | 5:04 | English | moderate | Generic math | null | |
The number of students from University B in the year
2008 is approximately what percentage of the total
number of students passed from University A ovet the
years? | b | Required percentage = 50/225 √ó 100
= 22.22% ~ 22% approximately | 20 | 22 | 28 | 30 | English | moderate | Generic math | null | |
What is the ratio between the number of students
passed in the years 2007, 2008 and 2005 from University A? | b | Required ratio = 50: 30:30 = 5:3:3 | 3:05:05 | 5:03:03 | 5:03:02 | 5:02:02 | English | moderate | Generic math | null | |
What is the difference between the total number of
students passed from both the universities together in
2007 and the total number of students passed from
both the universities together in 2005? | a | Total number of students passed in 207
= 110 (in thousands)
Total number of students passed in 2005 = 40
(in thousands)
Required difference = 110 - 40 = 70 (in thusand) | 70,000 | 80,000 | 8,50,000 | 90,000 | English | moderate | Generic math | null | |
If Section-II in College B's 2nd year class and Section-1
in College D's 30 year class have the same number of
students, then the ratio of the number of students in
Section-ll in College B's 20d year class to that of Sec-
tion-Ill in College D's 5 ' year class is ____ | d | The Section I of 3^ Year has 20% of 180 students =
36 = College B's 2» Year's Section I students. (as
given that both are equal in number.)
D's 5th Year - Section III students = 35% of 180
= 63
Thus, ATQ, the required ratio = 36: 63 = 4:7 | 2:04 | 5:07 | 5:06 | 4:07 | English | moderate | Generic math | null | |
What is the total number of students in Section-I of all
classes in College D? | b | We can take individual calculation for Section I
of individual class, but as each class has 180 stu-
dents. So, we can combine all the percentages
and calculate with 180 to get the combined fig-
ure as done below:
1 Year - Section 1 = (30 + 50 + 20 + 45 + 35)
% of 180 = 180% of 180 = 324 | 320 | 324 | 250 | 252 | English | moderate | Generic math | null | |
The number of students in Section-Ill of 4th year class
in College D is _% of the total number students in
College A. | c | From the Table, Total No. of students in College
A = 450
No. of students in Section III of 4h Year of
College D = 20% of 180 = 36
Thus, required p e r c e n t a g e = 36 / 4 5 0 √ó 1 0 0 = 8. | 5 | 6 | 8 | 10 | English | moderate | Generic math | null | |
If 20% of the students in College A move to College D
and are equally distributed in each class, then what is
the number of students in Section-II of College E's 3rd
year class? | d | All colleges work independently, so any such
movement of students will alter the students of
A and D only, and will not have any impact on E. | 36 | 45 | 72 | cannot be determined | English | moderate | Generic math | null | |
What is the difference between the number of students in College C and in Section-IlI across all classes in College D? | a | The total number of students in Sections III of
all classes = (35 + 25 + 25 + 20 + 35)% of 180
= 140% of 180 = 252
The number of students in College C = 1080
(given) Thus, the difference = 1080 - 252 = 828 | 828 | 830 | 838 | 756 | English | moderate | Generic math | null | |
For which of the following years, the percentage rise/
fall in production from the previous year is the maxi-
mum for Company Y? | a | Percentage change (rise/fall) in the production of Company Y in comparison to the previous year for different years is:
For 2017 =[((35-25)/25 )x100]% = 40%
For 2018 = [((35-35)/35 )x100]% = 0%
For 2019 = [((40 - 35)/35)√ó100]%=14.29%
For 2020 = [((50-40)/40)x100] % = 25% | 2017 | 2018 | 2019 | 2020 | English | moderate | Basic Finance | null | |
What is the ratio of the average production of Com-
pany X over the period 2018-20 to the average pro-
duction of Company Y over the same period? | c | Average production of Company X over the
period 2018-20
= [1/3 x (25+50+40)] = (115/3) lakhs tons. Average production of Company X over the
period 2018-20
= [1/3 x (35+50+40)] = (125/3) lakhs tons. thus the required = (115/3) /(125/3) = 23:25 | 1:01 | 15:17 | 23:25 | 27:29:00 | English | moderate | Basic Finance | null | |
The average production for 5 years was maximum for which company | null | Average production (in lakh tons) in 5 years
for the three companies is:
For Company X
[ 1/3 x (30+45+25+50+40)]= 190/5 = 38
For Company Y
[ 1/3 x (25+35+355+40+50)]= 180/5 = 37
For Company Z
[ 1/3 x (35+40+45+35+35)]= 190/5 = 38
Thus, average production of five 5 is maximum
for both the Companies X and Z | X | Y | Z | both X and Z | English | moderate | Basic Finance | null | |
In which year was the percentage of production
of Company Z to the production of Company Y the maximum? | a | The percentages of production of Company
Z to the production of Company Z for various
years are: For 2016 = ( 35/25 x 100 ) % = 140%
For 2017 = (40/35 x 100)% = 114.29%
For 2018 = (45/35 x 100)% = 128.57%
For 2019 = (35/40 √ó 100)% = 87.5%
For 2020 = (35/50 x 100)% = 70% | 2016 | 2017 | 2018 | 2019 | English | moderate | Basic Finance | null | |
What is the percentage increase in the production of
Company Y from 2016 to 2019? | d | Percentage increase in the production of
Company Y from 2016 to 2019: = ((40-25)/ 25) x100% = 60% | 30% | 45% | 50% | 60% | English | moderate | Basic Finance | null | |
What is the total number of items of type C produced
in the year 2020 and 2021 together? | b | The No. of items of C type produced in 2020 and
2021 = 17% of 48600 + 8% of 62500
= 8262 + 5000 = 13262 | 12482 | 13262 | 14786 | 15200 | English | moderate | Basic Finance | null | |
The number of items of type B produced in 2020 is
approximately _ % of the number of items of type B
produced in 2021. | d | : Number of type B items produced in 2020 =
18% of 48600 = 8748. Number of type B items produced in 2021 = 15% of 62500 = 9375
As comparison is with 2021, that will be taken as base.
Thus, desired answer = 9375 8748 √ó 100 = 93.31 =
approx 93% | 84 | 87 | 90 | 93 | English | moderate | Basic Finance | null | |
What is the ratio of the number of items of type D produced in 2020 to the number of items of type F produced in 2021? | c | Items of D Type in 2020
Items of F Type in 2021
20% of 48600 = 9720 24% of 62500 = 15000
972 : 1500
324 : 500
81 : 125 | 13:17 | 83 : 116 | 81 : 125 | 103 : 147 | English | moderate | Basic Finance | null | |
What is the total number of items of type A, B and C
produced by the company in 2020 and 2021 together? | a | Total Number of items by Company A, B and C in 2020
= (17 + 18 + 17)% of 48600 + (18 + 15 + 8)% of 62500
= 52% of 48600 + 41% of 62500 = 25272 + 25625 = 50897 | 50894 | 51164 | 52324 | 48542 | English | moderate | Basic Finance | null | |
The number of items of type E produced in the year
2021 is__% more than the number of items of type C produced in 2021. | d | Note that we don't need to do calculation with
62500, that is total of production of 2021.
The total is to assumed to be 100, and calcula-
tions to be done accordingly.
As they belong to the same year 2021, the %age
difference between E and C = 18 - 8 = 10
No. of items of type C in 2021 = 8
As the comparison is with C,... | 105 | 75 | 60 | 125 | English | moderate | Basic Finance | null | |
How many companies have shown production below
their average production in 2012-2013, but have
showed above the average production in 2013-14? | c | Average sales of company:
Honda = (6 + 14 + 21) = 13.66
GM = (12 + 18 + 18) = 16
Maruti = (5 + 9 + 15) = 9.66
Hindustan Morors = (16 + 9 + 12) = 12.33
Hyundai=8+ 14+72=9.66 | one | two | three | four | English | moderate | Basic Finance | null | |
The ratio of Hindustan Motors production in 2013-
2014 to Honda's production in 2012-2013 is | b | The required ratio is (9/6) = 1.5. | 0.66 | 1.5 | 2 | None of these | English | moderate | Basic Finance | null | |
For how many companies has there been no decrease in production in any year from the previous year? | c | By visual inspection, we can say that Honda,
GM and Maruti have not shown a decrease. | one | two | three | four | English | moderate | Basic Finance | null | |
Which of the following companies has shown consistent growth during the period? | d | By simple observation, we can say that (d) is
the right answer. | Maruti | Honda | Hindustan Motars | Both a and c | English | moderate | Basic Finance | null | |
Which of the following companies have shown high-
est and lowest growth rates? | b | By simple observation, we can say that (b) is
the right answer. | Honda and Hundai | Honda and Maruti | GM and Hundai | GM and Maruti | English | moderate | Basic Finance | null | |
What is the average of marks obtained by Aman for all subjects? | b | Average marks = (100 + 80 + 80 + 70 + 80 + 40)/6 = 75 | 72 | 75 | 80 | 85 | English | moderate | Generic math | null | |
What is the approximate percentage of marks
obtained by Ayush? | a | Percentage marks = [(90 + 50 + 90+60+70 + 80)/(150 + 130 + 120 + 100 + 100 + 100)]x100 = 62.8% | 62.8 | 72.5 | 75 | 74 | English | moderate | Generic math | null | |
What is the average of marks obtained by all candidates in Physics? | b | Average marks in Physics =(90+80+70+80+85+65+50)/7 =74.28 | 62.85 | 74.28 | 78.52 | None of these | English | moderate | Generic math | null | |
Who among the following has obtained the highest aggregate marks? | d | Aggregate marks: Ayush, 440; Aman, 450;
Sajal, 450; and Muskan, 465 | Ayush | Aman | Sajal | Muskan | English | moderate | Generic math | null | |
Who among the following has secured the highest
percentage marks in Physics, Chemistry and Maths? | b | As the denominator is same for the calculation of percentage of marks in all the cases, there is no need to calculate the percentage figures. Simply, the aggregate marks of three subects will provide the answer:
Ayush, 230; Aman, 260; Rohit, 225; and
Muskan, 230. | Ayush | Aman | Rohit | Muskan | English | moderate | Generic math | null | |
What is the percentage of candidates who qualifted
during 2007 for all states combined? | c | Percentage of candidates qualified = 5820 = [(780 + 750 + 960 + 850 + 1560)/5200 + 7500 + 6400 + 8100 + 7800] x 100 = 14% | 12.00% | 14.00% | 15.00% | None of these | English | moderate | Generic math | null | |
What is the average percentage of candidates who
qualified from State M for all the years? | c | Percentage of candidates qualified =
(Number of candidates qualified/ Number of candidates appeared) √ó100
= [(780 + 1170 + 1200 + 1320 + 1350 )/(5200 + 7800 + 8000 + 8800 + 9000)]x100 = 15%
If we look at all the figures for individual years, we can see that the result has been consistent at 15% for all these years. | 12% | 14% | 15% | 16% | English | moderate | Generic math | null | |
What is the average number of candidates who
appeared from State Q during the given years? | b | Average number of candidates appeared
(8100 + 9000 + 9200 + 10,000+10,000)/5=9,260 | 8660 | 9260 | 9560 | 9660 | English | moderate | Generic math | null | |
What is the average number of candidates who qualified from the State N during the given years? | b | Average = (750+850 +860+920 + 880 )/5=852 | 702 | 852 | 762 | 902 | English | moderate | Generic math | null | |
What is the percentage increase in candidates who appeared between 2007 and 2011? | b | Total number of candidates in 2007
= 35,000 (as calculated in Question 25)
Total number of candidates in 2011
= 9000 + 8800 + 10,000 + 10,000 + 11,200
= 49,000
Increase = 49,000 - 35,000 = 14,000
Percentage increase = 14,000/35,000 √ó 100=40 % | 35.00% | 40.00% | 45.00% | 50.00% | English | moderate | Generic math | null | |
In rural areas, which of the following sizes of the
households is the highest in number? | d | From the graph, we see that the line for
rural peaks at about 4-5.
Hence, the best answer is 4. | 15 | 2 | 3 | 4 | English | easy | GK | null | |
In urban areas, among the households of different
sizes, what is the percentage of households of size 5
or less? | b | Explanation: The total n u m b e r of households ≤5 is
17 + 14 + 12 + 15 + 14 = 72. | 13 | 72 | 36 | 87 | English | easy | GK | null | |
In rural areas, per 100 households, there were 31
households of size | c | Total up the values for rural area for the size 3 or less to get the answer | 3 or above | 3, 4 and 5 | 3 or less | 4 or less | English | easy | GK | null | |
As the urban population of towns increases, the average household size | d | As the population size increases, we see
that household sizes are 4.75, 4.50 and 4.70. Hence,
the values are fluctuating. | increse | decresse | remains constants | Fluctuates | English | easy | GK | null | |
Which of the following statements is true?
(a) On the average, there are more persons per family
in urban areas than in rural areas.
(b) In rural areas. 350 of the households are of that
size 7 and above.
(c) In urban areas, the average size of the household
is the least for towns.
(d) In urban areas, there are 460 per... | b | Only statement (b) can be inferred from the given graphs. | On the average, there are more persons per family
in urban areas than in rural areas. | In rural areas. 350 of the households are of that size 7 and above. | In urban areas, the average size of the household
is the least for towns | In urban areas, there are 460 persons on an average per 100 households. | English | easy | GK | null | |
What is the average profit earned by the company
over the years? | c | Total profit earned over 5 years = (25 + 35 +
22.5 + 30 + 37.5) = 150 lakhs
Average profit = 150/5 = Rs. 30 lakhs | Rs. 26 lakhs | Rs. 28 lakhs | Rs. 30 lakhs | Rs. 32 lakhs | English | moderate | Core Finance | null | |
If the expenditure of the company in 2009 was
Rs. 28 lakhs, then what was the revenue of the company
in that year? | a | Revenue in 2009 = Profit + Expenditure
= 65.5 lakhs | Rs. 65.5 lakhs | Rs. 72.5 lakhs | Rs. 75 lakhs | None of these | English | moderate | Core Finance | null | |
What is the approximate percentage increase in the
profit of the company in 2008 in comparison to the
previous year? | b | Ans: (b) Percentage increase = (30 - 23)/23 √ó 100
= 30.43 ~ 30% | 28 | 30 | 36 | 40 | English | moderate | Core Finance | null | |
What is the ratio of profit earned by the company in
2005 to the profit earned in 2009? | b | The required ratio = 25: 37.5 = 2: 3 | 1:03 | 2:03 | 3:05 | 1:02 | English | moderate | Core Finance | null | |
If the revenue of the company in 2007 was RS. 45 lakhs,
then what was the expenditure of the company in
that year? | b | Expenditure in 2007 = 45 - 22.5 = Rs. 22.5
lakhs | Rs. 20.5 lakhs | Rs. 22.5 lakhs | Rs. 24.5 lakhs | Rs. 25.5 lakhs | English | moderate | Core Finance | null | |
What is the difference between the number of vehi-
cles manufactured by Company Y in 2010 and 2011? | d | Difference = 1,28,000 - 1,07,000 = 21,000 | 50,000 | 42,000 | 33,000 | 21,000 | English | moderate | Basic Finance | null | |
What is the difference between the total production of
the two companies in the given years? | c | Total production of Company X from 2007
to 2012 (in thousands) = 119 + 99 + 141 + 78 +
120 + 159 = 716
Total production of Company Y from 2007 to
2012 (in thousands) = 139 + 120 + 100 + 128 +
107 + 148 = 742
Difference = (742 - 716) thousands = 26,000 | 19,000 | 22,000 | 26,000 | 28,000 | English | moderate | Basic Finance | null | |
What is the average numbers of vehicles manufactured by Company X over the given period? | b | Average number of vehicles manufactured
by Company X = (119 + 99 + 141 + 78 + 107 +
159)/6 = 1,17.166 (in thousands) = 1,17,166 | 1,19,333 | 1,17,166 | 1,12,778 | 1,11,223 | English | moderate | Basic Finance | null | |
In which of the following years was the diference
between the productions of Companies X and Y the
maximum? | d | The differences between the productions of
Companies X and Y in various years are as fol
lows (all figures in thousands):
For 2007 (139 - 119) = 20
For 2008 (120 √ó 99) = 21
For 2009 (141 - 100) = 41
For 2010 (128 - 78) = 50
For 2011 (120 - 107) = 13
For 2012 (159 - 148) = 11
Hence, the maximum difference was in 2010 | 2007 | 2008 | 2009 | 2010 | English | moderate | Basic Finance | null | |
The production of Company Y in 2010 was approximately what percentage of the production of Company X in the same year? | b | As the comparison is with Company X, its
production figure will appear as denominator.
Required percentage = (1,28,000/78,000) x
100 = 164% | 173 | 164 | 132 | 97 | English | moderate | Basic Finance | null | |
If total expenditure during a year is 765 lakhs, then
what are the expenses on cultural events (in lakhs)? | c | 5% of Rs. 65 lakhs = Rs. 3.25 lakhs | 1.67 | 2.65 | 3.25 | 4.25 | English | moderate | Basic Finance | null | |
What is the approximate angle extended by staff sala-
ries at the centre (in degrees)? | b | Angle extended by staff salaries at the centre = 38 × 3.6 = 137° | 132 | 137 | 142 | 145 | English | moderate | Basic Finance | null | |
The total of which of the following heads is equal to
salary expenses? | b | Maintenance + transportation + sports = 38% | Miscellaneous, transportation and cultural events | Maintenance, transportation and sports | Maintenance, publicity and miscellaneous | None of the above | English | moderate | Basic Finance | null | |
If the teachers' salaries are increased by 20%, then
what will be the new angle extended at the centre (in
degrees)? | d | No separate data is given for teachers' sal-
ary. Hence, it cannot be determined. So, new
angle extended may not be determined. | 45.6 | 43.6 | 56 | Cannot be determined | English | moderate | Generic math | null | |
What is the angle extended at the centre by a combination of miscellaneous and cultural events expenses
at the centre (in degrees)? | null | Total of miscelleneous and cultural percentages = 15 + 5 = 20%. Hence, angle extended
by them at the centre = 20 / 100x 360 = 72°. | 65 | 72 | 78 | 84 | English | moderate | Generic math | null | |
If the publisher has to pay 761,200 as the printing cost
for production of a certain quantity of books, then
what will be the amount of royalty to be paid for these
books? | c | The ratio between printing cost and royalty
= 20 : 15 or 4 : 3.
Let royalty be denoted by R.
Then 4: 3 = 61,200 : R
R√ó 4 = 61,200 √ó 3
R = (61,200 x 3)/4 = Rs. 45,900 | Rs. 22,950 | Rs. 45,000 | Rs. 45,900 | Rs. 48,900 | English | moderate | Basic Finance | null | |
If the cost price of the book is ?150, then what is the
combined printing and binding cost for a single copy
of the book? | a | Total printing and binding cost = 20 + 20 = 40%
Printing and binding cost = 40% of cost price
= 40% of 150 = Rs. 60 | Rs. 60 | Rs. 75 | Rs. 80 | Rs. 72 | English | moderate | Basic Finance | null | |
What is the central angle of t he sector corresponding
to the expenditure incurred on royalty? | b | Central angle corresponding to royalty
= (15% of 360)º = 15/100 × 360 = 54° | 48° | 54° | 60° | 72° | English | moderate | Basic Finance | null | |
What is the difference between promotion and
printing cost if we assume that total cost is Rs. 200? | b | Difference in percentage terms = 20 - 10 = 10%
Then, 10% of Rs. 200 = Rs. 20 | Rs. 10 | Rs. 20 | Rs. 30 | Rs. 24 | English | moderate | Basic Finance | null | |
If 1000 copies are published and the transportation
cost on them amounts to {15,000, then what should
be the selling price per book so that the publisher can
earn a profit of 20%? | c | To calculate the selling price of a single book, we need to total the cost. Let us calculate that first.
Transportation cost per book = 15,000/1000 = Rs. 15
As transportation cost is 10% of total cost, thus
Rs. 15 = 10% of total cost
Total cost of printing a copy = 15 √ó 100/10 = Rs. 150
Now selling price = total cost ... | Rs. 150 | Rs. 160 | Rs. 180 | Rs. 200 | English | moderate | Basic Finance | null | |
Considering all the four years together, what is the average number of boys who appered from school E? | c | For 2019
Number of Boys = 75% of Total students
Number of Girls = 25% of Total students
Difference = 75% of TS - 25% of TS = 280
50% of Total Students = 280
Total Students = 2 8 0 x - 100 = 560
Number of boys = 75% of 560 = 420
Similarly for 2020
Number of boys and girls is 60% and 40% (that
come by 100 - 60)
Differenc... | 424 | 434 | 438 | 455 | English | moderate | Generic math | null | |
What is the total number of girls who appeared in the
examination from all the six schools in 2020? | c | In School A
Difference = 70% - 30% = 40%
40% of Total Students = 75
Total students = 75 √ó 100/40 = 187.5
No. of Girls = 30% of 187.5 = 56.25 = 56 (apprx.)
Similarly, in School B
Percentage of Boys = 48
Percentage of Girls = 100 - 48 = 52
Difference = 5 2 - 48 = 4
4% of Total students = 18
Total students = 18 √ó 100/4 ... | 1364 | 1386 | 1280 | 1414 | English | moderate | Generic math | null | |
What is the difference between the total numbers of
students appearing from School B in 2020 and that in
2022? | a | Total No. of Students (already calculated in 2nd
question) = 450
For Year 2022
Difference = 60 - 40 = 20%
20% of Total students = 90
Total students = 90 √ó 100 = 450
Thus, overall difference = 450 - 450 = 0 | 0 | 17 | 29 | 35 | English | moderate | Generic math | null | |
What is the ratio of the number of boys who appeared
from School C in 2019 to the number of girls who
appeared from school E in 2021? | d | Given data for 2019 (School C)
Boys = 44%, Girls = 100 - 44 = 56%
Difference (Boys - Girls) = (56 - 44)% of Total = 60
12% of Total students = 60
Total students = 60 √ó 100- = 500
No. of Boys = 44% of 500 = 220
Given d a t a for 2021 (School E)
Now, No. of Boys = 70%
Girls = 100 - 70 = 30%
Difference = 70 - 30 = 40%
40... | 5:04 | 8:07 | 9:08 | 10:09 | English | moderate | Generic math | null | |
In the year 2019, number of students appearing from
School F is __% more than the number of students
appearing from School C: | d | For Year 2019 (School F)
Number of Boys = 44%, Number of Girls
= 100 - 44 = 56%
Difference = 56 - 44 = 12%
12% of Total = 90
Total students = 90 √ó 100/12 = 750
For the Year 2019 (School C)
Number of Boys = 44%
Number of Girls = 100 - 44 = 56%
Difference = 56 - 44 = 12%
12% of Total students = 60
Total students = 60 √ó... | 40 | 66.66 | 20 | 50 | English | moderate | Generic math | null | |
Which city reported the highest number of positive cases? | b | City 1: 30 + 15 + 35 + 10 = 90
City 2: 35 + 10 + 30 + 10 = 85
City 3: 15 + 5 + 15 + 5 = 40
City 4: 10 + 5 + 5 + 15 = 35
Therefore, City 1 reported the highest number
of positive cases. | city 2 | city 1 | city 4 | city 3 | English | moderate | Generic math | null | |
What is the percentage of positive cases in City 2
across all hospitals? (Round to two decimal places) | b | Total Tests in City 2 = 100 + 50 + 100 + 50
= 300
Total Positive Cases in City 2 = 35 (A) + 10 (B)
+ 30 (C) + 10 (D) = 85
Percentage of Positive Cases in City 2
= 85/300 √ó 100 = 28.33% | 17.50% | 28.33% | 35.42% | 41.67% | English | moderate | Generic math | null | |
What is the ratio of positive cases in City 1 and City 3? | a | From the table, we can see:
City 1 had a total of 30 + 15 + 35 + 10 = 90 positive cases.
City 3 had a total of 15 + 5 + 15 + 5 = 40 positive cases.
Thus, the answer is 90: 40 or 9:4 | 9:04 | 6:05 | 9:05 | 11:04 | English | moderate | Generic math | null | |
What is the percentage of positive cases in City 4? | b | Total Tests in City 4 = 100 + 50 + 100 + 50
= 300 tests
Positive Cases in City 4 = 10 + 5 + 5 + 15
= 35 cases
Percentage of Positive Cases =
(Positive Cases / Total Tests) √ó 100
Percentage = (35/300) √ó 100 = 11.67% | 16 | 12 | 14 | 15 | English | moderate | Generic math | null | |
Which hospital has reported maximum number of
positive cases ? | a | Look at the positive cases at each hospital :
Hospital A: 30 + 35 + 15 + 10 = 90
Hospital B: 15 + 10 + 5 + 5 = 35
Hospital C: 35 + 30 + 15 + 5 = 85
Hospital D: 10 + 10 + 5 + 15 = 40
Therefore, Hospital A has reported the maxi-
mum number of positive cases | Hospital A | Hospital D | Hospital B | Hospital C | English | moderate | Generic math | null | |
If the ratio of literate males to illiterate males of City
'D' is 11: 7. Then what is the difference between the
number of literate males and number of illiterate
males of City 'D'? | d | Females in City D = 100 - (45 + 25)
= 100 - 70 = 30%
30% of total = 3600
Total in City D = 3600/30 √ó 100 = 12000
Males in City D = 45% of 12000 = 45 √ó 12000/100 = 5400
Ratio of Literate Males to Illiterate Males = 11: 7
Literates = 11/18√ó 5400 = 3300
Other = 5400 - 3300 = 2100
Difference = 3300 - 2100 = 1200 | 900 | 1050 | 800 | 1200 | English | moderate | Generic math | null | |
Population of City 'C' is what percent less than the
population of City 'B'? | c | Total Population of City C (PC)
If 50% is 8000, then PC = 8000 x 2 = 16000
Total Population of City B (PB)
If 15% of City B is 3000, then PB =3000/15%
= 20000
Percentage Difference Calculation
Difference between PB and PC = 20000 - 16000 = 4000.
Percentage Difference = 4000/20000√ó 100 = 20% | 30.00% | 25% | 20% | 17.50% | English | moderate | Generic math | null | |
If the population of City E is anticipated to doubles by
the year 2035, but the ratio remains same, then what
will be total of populations of females and transgenders in that year? | d | ATQ, Number of Transgenders = [100 -(38 + 32)]% of Total Population of E = 4200,
Population of E = 4200 √ó 100/30 = 14000
Total Population in 2035 = 2 √ó 14000 = 28000
As the ratio remains the same, the total of
females and transgenders in 2035 = (32 + 30)% of 28,000
= 62% of 28000 = 17,360 | 16600 | 18360 | 17200 | 17360 | English | moderate | Generic math | null | |
Female population in City 'C' is how much percent
less than the sum of male and transgender population
of City 'D'? | b | Calculate Female Population of City C
Total population of City C = 16000 (as calculated in a previous question)
Female percentage in City C = 35%
Female population in City C = 0.35 √ó 16000 = 5600.
Calculate Male and Transgender Population in City D
Total population of City D = 12000
(from previous calculations).
Male ... | 25% | 33 x 1/3% | 50% | 66 x 2/3 % | English | moderate | Generic math | null | |
Male population of City 'E' is how much more than
female population of City 'A'? | d | Total Population of City E = 4200/[100 - (38 + 32)] %
4200/30 x 100 =14,000
Male Population of City E = 38% of 14000
= 5320
For City A
Total Population of City A = 2000/[100 - (45 + 30)] %
2000/25 x 100 =8,000
Female Population of City A = 30% of 8000
= 2400
Required Difference = 5320 - 2400 = 2920 | 2900 | 2840 | 2980 | 2920 | English | moderate | Generic math | null | |
What is the average population of State B for all the
years together (in lakhs)? | c | null | 3.5 | 3.6 | 3.75 | 3.8 | English | moderate | Generic math | null | |
What is the percentage increase in population of State
A between 2002 and 2003? | c | null | 5 | 5.25 | 6.67 | 7.5 | English | moderate | Generic math | null | |
What was the difference between combined popu-
lations of all the three states for the years 2004 and
2005? | a | null | 90,000 | 100000 | 110000 | None of the above | English | moderate | Generic math | null | |
What was the average population of al the three
states in 2006 (in lakhs)? | b | null | 5.5 | 5.8 | 6.1 | 6.3 | English | moderate | Generic math | null | |
What is the ratio between combined populations of all
the three states in 2004 and 2005? | c | null | 155 : 144 | 144 : 155 | 144 : 165 | 165 : 144 | English | moderate | Generic math | null | |
The number of students who appeared from School
E in 2004 is approximately what percentage of the
total number of students who appeared from all the school together in that year | c | null | 16% | 18% | 20% | 25% | English | moderate | Generic math | null | |
What is the average number of students who appeared
from School B for all the years | b | null | 676 | 787 | 808 | 818 | English | moderate | Generic math | null | |
The number of students who appeared in 2006 from
School A is what per cent of the total number of students who appeared from School A for al the years together | a | null | 25.25 | 21.33 | 22.45 | 23.45 | English | moderate | Generic math | null | |
What is the ratio between the total number of students who appeared in 2004 and 2005 from Schools C and D, respectively | b | null | 84 : 79 | 79 :84 | 84 : 89 | 89 : 84 | English | moderate | Generic math | null | |
What is the average number of students who appeared
from the given schools in 2007 | c | null | 825 | 836 | 845 | 863 | English | moderate | Generic math | null | |
What is the difference between the number of gradu-
ates and the number of postgraduates in town C | d | null | 4500 | 4600 | 4650 | 4560 | English | moderate | Generic math | null | |
What is the average number of postgraduates in all
the towns together | b | null | 15000 | 15500 | 16250 | 15200 | English | moderate | Generic math | null | |
What is the ratio of the number of graduates from
towns A and B together to the number of postgraduates from towns A and E together | c | null | 709 : 580 | 709 : 560 | 560 : 709 | None of these | English | moderate | Generic math | null | |
What is the total number of graduates and postgraduates in towns A, D and F together? | b | null | 85800 | 88600 | 89600 | 90600 | English | moderate | Generic math | null | |
The number of graduates in town F is approximately
what percentage of the number of postgraduates in
the same town? | b | null | 84 | 89 | 92 | 95 | English | moderate | Generic math | null | |
For how many years, the exports are at least 10%
higher than the imports? | a | null | 1 | 2 | 3 | 4 | English | moderate | Basic Finance | null | |
In which year have the exports shown the highes
growth in percentage terms in comparison to the preceding year? | b | null | 2005 | 2006 | 2007 | 2008 | English | moderate | Basic Finance | null | |
What are the average exports (in billion 2) for the period 2004-2009? | b | null | 60.35 | 65.83 | 70.2 | 75.36 | English | moderate | Basic Finance | null | |
By how much percentage are the total exports higher
than total imports from 2004 to 2009? | b | null | 4.15 | 5.33 | 6.33 | 7.58 | English | moderate | Basic Finance | null | |
What is the percentage increase in imports between
the years 2004 and 2009? | a | null | 110 | 114 | 125 | 135 | English | moderate | Basic Finance | null | |
What is the ratio of the total enrolment of State B for
years 2010 and 2011 to the total enrolment of State D
for both the years combined? | c | null | 7:09 | 4:05 | 3:05 | 2:03 | English | moderate | Generic math | null | |
What is the percentage of total enrolment of State C
in comparison to enrolment of State E for years 2010
and 2011? | b | null | 73 | 126 | 137 | 145 | English | moderate | Generic math | null |
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