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Question: Assuming that functions $f(x, y, z), U(x, y, z), V(x, y, z)$, and $W(x, y, z)$ have continuous second-order partial derivatives, i.e. the order of differentiation is not important. Given a scalar field $f(x, y, z)$. Prove that the gradient of field $f$ is an irrotational vector field.
Step-by-Step Answer: Scalar field $f(x, y, z)$. Prove that gradient of field $f(i, e, \nabla f)$ is irrotational, or $\nabla \times(\nabla f)=0$ Proof: $$ \nabla f=\left(f_{x}, f_{y}, f_{z}\right), \text { where } f_{x}=\frac{\partial f}{\partial x}, f_{y}=\frac{\partial f}{\partial y}, f_{z}=\frac{\partial f}{\partia...
$\nabla \times(\nabla f)=0$ or $\nabla f$ is irrotational
Scalar field $f(x, y, z)$. Prove that gradient of field $f(i, e, \nabla f)$ is irrotational, or $\nabla \times(\nabla f)=0$ Proof: $$ \nabla f=\left(f_{x}, f_{y}, f_{z}\right), \text { where } f_{x}=\frac{\partial f}{\partial x}, f_{y}=\frac{\partial f}{\partial y}, f_{z}=\frac{\partial f}{\partial z} $$ \[ \nabla \tim...
Question: Determine $\operatorname{grad} \phi=\nabla \phi$ for the following scalar fields $\phi(x, y, z)=e^{6 x y^3 z} \ln \left(4 x y^7 z^8\right)$
Step-by-Step Answer: $$ \begin{aligned} & \text { b) } \phi(x, y, z)=e^{6 x y^{3} z} \ln \left(4 x y^{7} z^{8}\right) \\ & \nabla \phi=\phi_{x} \cdot \hat{i}+\phi_{y} \hat{j}+\phi_{z} \hat{k}, \end{aligned} $$ where $\phi_{x}=\frac{\partial \phi}{\partial x}=\left(e^{6 x y^{3} z}\right)_{x}^{\prime} \cdot \ln \left(4 x...
$\phi_{z} =6 x y^{3} \cdot e^{6 x y^{3} z} \cdot \ln \left(4 x y^{7} z^{8}\right)+\frac{8 e^{6 x y^{3} z}}{z}$
$$ \begin{aligned} & \text { b) } \phi(x, y, z)=e^{6 x y^{3} z} \ln \left(4 x y^{7} z^{8}\right) \\ & \nabla \phi=\phi_{x} \cdot \hat{i}+\phi_{y} \hat{j}+\phi_{z} \hat{k}, \end{aligned} $$ where $\phi_{x}=\frac{\partial \phi}{\partial x}=\left(e^{6 x y^{3} z}\right)_{x}^{\prime} \cdot \ln \left(4 x y^{7} z^{8}\right)+e...
Question: Calculate the Fourier transform of the two-sided exponential pulse given by \[ f(t) = \begin{cases} e^{at}, & \text{if } t \leq 0 \\ e^{-at}, & \text{if } t > 0 \end{cases}, \quad a > 0 \]
Step-by-Step Answer: Fourice Transform:\\ \begin{tikzpicture} \begin{axis}[ axis lines=middle, xlabel={$t$}, ylabel={$f(t)$}, xtick=\empty, ytick={1}, ymin=-0.1, ymax=1.5, xmin=-3, xmax=3, samples=200, domain=-3:3, width=12cm, height=8cm, every a...
$\frac{2 a}{a^{2}+\omega^{2}}$
Fourice Transform:\\ \begin{tikzpicture} \begin{axis}[ axis lines=middle, xlabel={$t$}, ylabel={$f(t)$}, xtick=\empty, ytick={1}, ymin=-0.1, ymax=1.5, xmin=-3, xmax=3, samples=200, domain=-3:3, width=12cm, height=8cm, every axis x label/.style={a...
Question: Consider finding the root of $f(x)=x^2-3$. Let the tolerance tol $=0.01$ and start with the interval $[1,2]$, solve the equation using the Bisection method.
Step-by-Step Answer: Consider finding the root of $f(x)=x^{2}-3$. Let the tolerance fol $=0.01$ and start with the interval $[1,2]$, solve the equation using the Bisection method. \section*{Solution:} \begin{center} \begin{tabular}{|l|l|l|l|l|l|l|l|} \hline $x_{1}$ & $x_{2}$ & $f\left(x_{1}\right)$ & $f\left(x_{2}\rig...
$1.7344$
Consider finding the root of $f(x)=x^{2}-3$. Let the tolerance fol $=0.01$ and start with the interval $[1,2]$, solve the equation using the Bisection method. \section*{Solution:} \begin{center} \begin{tabular}{|l|l|l|l|l|l|l|l|} \hline $x_{1}$ & $x_{2}$ & $f\left(x_{1}\right)$ & $f\left(x_{2}\right)$ & $x_{3}=\left(x...
Question: Given two vectors $\vec{u}=\hat{\imath}+2 \hat{\jmath}+3 \hat{k}$ and $\vec{v}=4 \hat{\imath}+5 \hat{\jmath}+\widehat{6 k}$, compute: The vector projection of $\vec{v}$ onto $\vec{u}$
Step-by-Step Answer: $$ \begin{aligned} & \vec{u}=\hat{i}+2 \hat{j}+3 \hat{k}=(1,2,3) \\ & \vec{v}=4 \hat{i}+5 \hat{j}+6 \hat{k}=(4,5,6) \end{aligned} $$ \begin{tikzpicture}[scale=2,>=stealth] % Define points \coordinate (O) at (0,0); \coordinate (U) at (2,0); \coordinate (V) at (1,1.5); \coordinate (P) at (1...
$\frac{16}{7}(1,2,3)$
$$ \begin{aligned} & \vec{u}=\hat{i}+2 \hat{j}+3 \hat{k}=(1,2,3) \\ & \vec{v}=4 \hat{i}+5 \hat{j}+6 \hat{k}=(4,5,6) \end{aligned} $$ \begin{tikzpicture}[scale=2,>=stealth] % Define points \coordinate (O) at (0,0); \coordinate (U) at (2,0); \coordinate (V) at (1,1.5); \coordinate (P) at (1,0); % Vectors \d...
Question: Given a vector field $\vec{F}(x, y, z)=(2 x y+z) \hat{\imath}+x^2 \hat{\jmath}+x \hat{k}$. Evaluate $\int_C \vec{F} \cdot d \vec{r}$, where C is a line segment $\vec{r}(t)$ from point $P(1,-1,2)$ to $Q(2,2,3)$.
Step-by-Step Answer: $$ \left.\left.\begin{array}{rl} \int_{c} \vec{F} \cdot d \vec{r} & =\phi\left(r\left(t_{2}\right)\right)-\phi\left(r\left(t_{1}\right)\right)=\phi(\text { at point } Q)-\phi(\text { at point } P) \\ & =\phi(2,2,3)-\phi(1,-1,2) \end{array}\right)\left(2^{2} \cdot 2+2 \cdot 3\right)-\left(1^{2} \c...
$13$
$$ \left.\left.\begin{array}{rl} \int_{c} \vec{F} \cdot d \vec{r} & =\phi\left(r\left(t_{2}\right)\right)-\phi\left(r\left(t_{1}\right)\right)=\phi(\text { at point } Q)-\phi(\text { at point } P) \\ & =\phi(2,2,3)-\phi(1,-1,2) \end{array}\right)\left(2^{2} \cdot 2+2 \cdot 3\right)-\left(1^{2} \cdot(-1)+1.2\right)\righ...
Question: Using the Laplace transform table, determine the Laplace transform of the following functions:$f(t)=3 t^{2}+\sin (2 t)$
Step-by-Step Answer: Laplace transform table $$ \begin{aligned} & \text { a) } f(t)=3 t^{2}+\sin (2 t) \\ & L\left\{3 t^{2}+\sin (2 t)\right\}=L\left\{3 t^{2}\right\}+L\{\sin (2 t)\} \\ & \left\{\begin{array}{l} 3 t^{2} \longrightarrow 3 \cdot \frac{2!}{s^{2+2}}=\frac{6}{s^{3}} \\ \sin (2 t) \rightarrow \frac{2}{s^{2}...
$\frac{6}{s^{3}}+\frac{2}{s^{2}+4}\right$
Laplace transform table $$ \begin{aligned} & \text { a) } f(t)=3 t^{2}+\sin (2 t) \\ & L\left\{3 t^{2}+\sin (2 t)\right\}=L\left\{3 t^{2}\right\}+L\{\sin (2 t)\} \\ & \left\{\begin{array}{l} 3 t^{2} \longrightarrow 3 \cdot \frac{2!}{s^{2+2}}=\frac{6}{s^{3}} \\ \sin (2 t) \rightarrow \frac{2}{s^{2}+2^{2}}=\frac{2}{s^{2}...
Question: Using the Laplace transform table, find the inverse Laplace transform of the following functions: $F(s)=\frac{s+2}{(s+2)^{2}+9}$
Step-by-Step Answer: $\mathbb{L}^{-1}\left\{\frac{s+2}{(s+2)^{2}+9}\right\}$ For calculating $L^{-1}\left\{\frac{s+2}{(s+2)^{2}+9}\right\}$, we use $\cos (a t) \leftrightarrow \frac{s}{s^{2}+a^{2}}$ and $e^{\text {sot }} f(t) \leftrightarrow F\left(s-s_{0}\right)$, i.e., $L^{-1}\left\{\frac{s}{s^{2}+\underset{a}{2} \ti...
$L^{-1}\left\{\frac{s+2}{(s+2)^{2}+9}\right\}=e^{-2 t} \cdot \cos (3 t)$
$\mathbb{L}^{-1}\left\{\frac{s+2}{(s+2)^{2}+9}\right\}$ For calculating $L^{-1}\left\{\frac{s+2}{(s+2)^{2}+9}\right\}$, we use $\cos (a t) \leftrightarrow \frac{s}{s^{2}+a^{2}}$ and $e^{\text {sot }} f(t) \leftrightarrow F\left(s-s_{0}\right)$, i.e., $L^{-1}\left\{\frac{s}{s^{2}+\underset{a}{2} \tilde{g}_{i}}\right\} ...
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