task_id stringlengths 9 15 | bucket stringclasses 3
values | split stringclasses 2
values | sample int64 0 3 | content stringlengths 0 1.08k | reasoning stringlengths 100 16.9k | tokens int64 55 4.1k | ms float64 1.2k 76.5k | ok bool 2
classes |
|---|---|---|---|---|---|---|---|---|
gsm8k-0001 | reasoning | train | 0 | The trip costs $300, and the school covers half of it:
\[
\frac{1}{2} \times 300 = 150
\]
So John still needs to pay $150.
He already has $50, so the amount he is missing is:
\[
150 - 50 = 100
\]
Final answer: 100 | We need answer a math word problem. Need produce final with work and end 'Final answer: <number>'. Problem: John raising money for school trip. School covers half cost. Trip costs $300. School covers half = $150. Remaining cost for John = $150. He has $50. Missing = $150 - $50 = $100. Need show work. End exact Final an... | 214 | 4,669 | true |
gsm8k-0001 | reasoning | train | 1 | The trip costs $300. The school covers half the cost:
$300 ÷ 2 = $150
So John still needs to raise:
$300 − $150 = $150
John has $50, so the money he is missing is:
$150 − $50 = $100
Final answer: 100 | We need answer math word problem. Need solve: trip costs 300. School covers half cost = 150. John needs remaining half = 150. He has 50, missing 100. Show work and final answer: <number>. Need final with "Final answer: 100". Ensure only? User says show work, end answer. We can concise.
| 178 | 3,355 | true |
gsm8k-0001 | reasoning | train | 2 | The trip costs $300. The school covers half of the cost:
$300 ÷ 2 = $150
So John still needs to raise $150.
He already has $50, so the amount he is missing is:
$150 - $50 = $100
Final answer: 100 | We need answer arithmetic word problem. Need show work and end with Final answer: <number>. Let's parse: John raising money. School covers half cost. Trip costs $300. School covers half = $150. Remaining cost to be raised = $150. John has $50. Missing = 150-50=100. Need final answer: 100 maybe with dollar? User says en... | 216 | 4,050.5 | true |
gsm8k-0001 | reasoning | train | 3 | The trip costs $300.
The school covers half the cost:
\[
\frac{300}{2} = 150
\]
So John still needs:
\[
300 - 150 = 150
\]
John already has $50, so the amount he is missing is:
\[
150 - 50 = 100
\]
Final answer: 100 | We need answer simple math. User asks solve showing work, end with Final answer: <number>. Need ensure final only? System says precise, answer task. We can show work. Compute: trip cost $300, school covers half = $150. John missing amount = cost - school cover - John has = 300-150-50=100. Or amount needed total after s... | 221 | 4,136.2 | true |
gsm8k-0002 | reasoning | train | 0 | Claire earns 1 badge per month, so in 1 year (12 months):
- Claire: \(1 \times 12 = 12\) badges
Amber takes twice as long to earn a badge, so she earns half as many:
- Amber: \(\frac{12}{2} = 6\) badges
Wendy earns three times as many badges as Claire:
- Wendy: \(3 \times 12 = 36\) badges
Difference between Wendy... | We need solve word problem. Let's reason carefully.
Claire earns 1 badge every month. In 1 year = 12 months, Claire earns 12 badges.
It takes Amber twice as long to earn a badge than Claire. Claire rate: 1 badge per month. Twice as long means Amber's time per badge = 2 months, so rate = 1 badge per 2 months = 6 badges... | 327 | 6,423.6 | true |
gsm8k-0002 | reasoning | train | 1 | Claire earns **1 badge per month**.
In **1 year** (12 months):
- **Claire:** \(1 \times 12 = 12\) badges
- **Amber:** It takes Amber twice as long as Claire to earn a badge, so she earns \( \frac{1}{2} \) badge per month.
\[
12 \times \frac{1}{2} = 6
\]
- **Wendy:** She earns three times as many badges as C... | We need answer simple word problem. Need solve: Claire earns 1 badge every month. Amber takes twice as long to earn a badge than Claire. If Claire 1 per month, Amber's rate 1 badge per 2 months = 0.5/month. In 1 year 12 months, Amber earns 6 badges. Wendy earns three times amount of badges as Claire in same time frame.... | 325 | 6,051.8 | true |
gsm8k-0002 | reasoning | train | 2 | Claire earns 1 badge every month.
In 1 year (12 months):
- Claire earns: 12 × 1 = 12 badges
Amber takes twice as long to earn a badge as Claire.
- Claire takes 1 month per badge
- Amber takes 2 months per badge
- In 12 months, Amber earns: 12 ÷ 2 = 6 badges
Wendy earns three times as many badges as Claire in the sam... | We need answer user's math word problem. done. Need show work and end with Final answer: <number>. Let's solve carefully.
Claire earns 1 girl scout badge every month. So in 1 year = 12 months, Claire earns 12 badges.
It takes Amber twice as long to earn a badge than Claire. Claire takes 1 month per badge. Amber takes... | 352 | 6,529.2 | true |
gsm8k-0002 | reasoning | train | 3 | Claire earns:
- 1 badge every month
- In 1 year (12 months): \(1 \times 12 = 12\) badges
Amber takes twice as long as Claire to earn a badge:
- Amber earns 1 badge every 2 months
- In 12 months: \(12 \div 2 = 6\) badges
Wendy earns three times as many badges as Claire:
- Claire earns 1 badge per month, so Wendy ea... | We need solve math word problem. Need provide work and final answer. Let's analyze carefully.
Claire earns 1 badge per month.
It takes Amber twice as long to earn a badge than Claire. So Amber earns 1 badge every 2 months. In 1 year (12 months), Amber earns 12/2 = 6 badges.
Wendy earns three times amount of badges as ... | 336 | 6,236.1 | true |
gsm8k-0003 | reasoning | train | 0 | Grace weighs 125 pounds.
Alex weighs 2 pounds less than 4 times Grace’s weight:
\[
4 \times 125 - 2 = 500 - 2 = 498
\]
So Alex weighs 498 pounds.
Their combined weight is:
\[
125 + 498 = 623
\]
Final answer: 623 | We need answer math word problem. Compute. Grace 125. Alex weighs 2 pounds less than 4 times what Grace weighs. 4*125=500, less 2 =498. Combined 125+498=623. Need show work, end Final answer: 623. Ensure exact final.
| 178 | 3,685.2 | true |
gsm8k-0003 | reasoning | train | 1 | Grace weighs 125 pounds.
Alex weighs 2 pounds less than 4 times Grace’s weight:
4 × 125 = 500
500 − 2 = 498
So Alex weighs 498 pounds.
Combined weight:
125 + 498 = 623
Final answer: 623 | We need answer arithmetic. Need solve: Grace 125. Alex weighs 2 pounds less than 4 times what Grace weighs. 4*125=500; 2 less = 498. Combined=125+498=623. Need show work and end Final answer: 623.
| 162 | 3,082.2 | true |
gsm8k-0003 | reasoning | train | 2 | Grace weighs 125 pounds.
Alex weighs 2 pounds less than 4 times Grace’s weight:
\[
4 \times 125 = 500
\]
\[
500 - 2 = 498
\]
So Alex weighs 498 pounds.
Their combined weight is:
\[
125 + 498 = 623
\]
Final answer: 623 | We need answer user math word problem. Need show work and end Final answer: <number>. Compute: Grace 125. Alex weighs 2 pounds less than 4 times what Grace weighs. 4*125=500. 2 less =498. Combined =125+498=623. Need final with Final answer: 623. Ensure only? They ask solve showing work. We can provide concise.
| 204 | 3,832.7 | true |
gsm8k-0003 | reasoning | train | 3 | Grace weighs 125 pounds.
Alex weighs 2 pounds less than 4 times Grace’s weight:
4 × 125 = 500
500 − 2 = 498
So Alex weighs 498 pounds.
Their combined weight is:
125 + 498 = 623
Final answer: 623 | We need answer simple arithmetic. Need provide final answer. Let's solve: Grace 125. Alex weighs 2 pounds less than 4 times Grace = 4*125 - 2 = 500 - 2 = 498. Combined = 125 + 498 = 623. Need show work and end with Final answer: 623.
| 176 | 3,330.1 | true |
gsm8k-0004 | reasoning | train | 0 | Josh worked out for 8 weeks.
- Base workout time: 4 hours per week
- Exceptions:
- 2 consecutive weeks at 5 hours: \(2 \times 5 = 10\)
- 1 week at 6 hours: \(6\)
Remaining weeks: \(8 - 3 = 5\) weeks at 4 hours each:
\[
5 \times 4 = 20
\]
Total hours:
\[
10 + 6 + 20 = 36
\]
Final answer: 36 | We need answer math word problem. Need solve. Let's parse carefully.
"After tracking his workout routine for 8 weeks, Josh discovered that he had spent 4 hours working out every week except on some occasions. At one point, he spent 5 hours each for two consecutive weeks. Another time, he spent 6 hours in one week. Wha... | 415 | 8,183.5 | true |
gsm8k-0004 | reasoning | train | 1 | He would have spent 4 hours per week for 8 weeks:
\[
8 \times 4 = 32
\]
But there were exceptions:
- Two consecutive weeks at 5 hours each:
\[
5 + 5 = 10
\]
Instead of 4 hours each for those 2 weeks, which would be:
\[
4 + 4 = 8
\]
So these two weeks add:
\[
10 - 8 = 2
\]
- One week at 6 hours instead of 4 hou... | We need answer math word problem. Need solve carefully. Let's parse: "After tracking his workout routine for 8 weeks, Josh discovered that he had spent 4 hours working out every week except on some occasions. At one point, he spent 5 hours each for two consecutive weeks. Another time, he spent 6 hours in one week. What... | 618 | 11,660.3 | true |
gsm8k-0004 | reasoning | train | 2 | He tracked workouts for 8 weeks, and his usual amount was 4 hours per week.
Exceptions:
- Two consecutive weeks: 5 hours each
\[
2 \times 5 = 10
\]
- One week: 6 hours
\[
1 \times 6 = 6
\]
The remaining weeks were the usual 4 hours:
\[
8 - 2 - 1 = 5
\]
Hours for the remaining weeks:
\[
5 \times 4... | We need answer problem. Need parse carefully. We have to solve: "After tracking his workout routine for 8 weeks, Josh discovered that he had spent 4 hours working out every week except on some occasions. At one point, he spent 5 hours each for two consecutive weeks. Another time, he spent 6 hours in one week. What is t... | 520 | 9,793.3 | true |
gsm8k-0004 | reasoning | train | 3 | He worked out for 4 hours in most weeks.
There are 8 weeks total. If every week were 4 hours:
\[
8 \times 4 = 32 \text{ hours}
\]
For the two consecutive weeks with 5 hours each, each week is 1 hour more than 4 hours:
\[
2 \times 1 = 2 \text{ extra hours}
\]
For the one week with 6 hours, it is 2 hours more than 4... | We need answer math word problem. Need solve carefully. Let's parse problem.
"After tracking his workout routine for 8 weeks, Josh discovered that he had spent 4 hours working out every week except on some occasions. At one point, he spent 5 hours each for two consecutive weeks. Another time, he spent 6 hours in one w... | 696 | 13,011.3 | true |
gsm8k-0005 | reasoning | test | 0 | Let the number of tennis balls Rory retrieved in the second set be \(s\).
- First set: \(s + 4\)
- Third set: \(\frac{s}{2}\)
- Total: \(19\)
Set up the equation:
\[
(s + 4) + s + \frac{s}{2} = 19
\]
Combine terms:
\[
2s + \frac{s}{2} + 4 = 19
\]
\[
\frac{5s}{2} + 4 = 19
\]
Subtract 4 from both sides:
\[
\frac{... | We need answer math problem. Need solve: first set had four more than second: F = S + 4. Third half of second: T = S/2. Total 19: S+4 + S + S/2 = 19 => 2.5S+4=19 => 2.5S=15 => S=6. First=10. Show work. End with Final answer: 10.
| 326 | 6,580.7 | true |
gsm8k-0005 | reasoning | test | 1 | Let the number of balls retrieved in the second set be \(x\).
- First set: \(x + 4\)
- Third set: \(\frac{x}{2}\)
Total:
\[
(x + 4) + x + \frac{x}{2} = 19
\]
Combine terms:
\[
2x + 4 + \frac{x}{2} = 19
\]
\[
\frac{5x}{2} + 4 = 19
\]
\[
\frac{5x}{2} = 15
\]
\[
5x = 30
\]
\[
x = 6
\]
So he retrieved 6 balls in the se... | We need answer math word problem. Need solve and show work, end Final answer: <number>.
Let's parse: Rory retrieving tennis balls from court after match. In first of three sets, had to retrieve four more balls than in second set. In third, half as many balls as in second. Total 19. How many in first?
Let second = x. ... | 500 | 9,265.1 | true |
gsm8k-0005 | reasoning | test | 2 | Let the number of tennis balls retrieved in the second set be \(x\).
- First set: \(x + 4\)
- Third set: \(\frac{x}{2}\)
Total tennis balls:
\[
(x + 4) + x + \frac{x}{2} = 19
\]
Combine terms:
\[
\frac{5x}{2} + 4 = 19
\]
Subtract 4:
\[
\frac{5x}{2} = 15
\]
Multiply by 2:
\[
5x = 30
\]
Divide by 5:
\[
x = 6
\... | We need answer simple word problem. Need solve. Let's analyze: Let second set = x. First = x+4. Third = x/2. Total 19: x + x+4 + x/2 = 19 => 2.5x +4=19 => 2.5x=15 => x=6. First=10. Check third=3 total 19. Final answer: 10. Need show work and end exact Final answer: <number>. Probably just 10. Ensure only? User asks sol... | 330 | 6,130.8 | true |
gsm8k-0005 | reasoning | test | 3 | Let the number of tennis balls Rory retrieved in the second set be \(x\).
- First set: \(x + 4\)
- Second set: \(x\)
- Third set: \(\frac{x}{2}\)
Total balls:
\[
(x + 4) + x + \frac{x}{2} = 19
\]
Combine like terms:
\[
2x + \frac{x}{2} + 4 = 19
\]
\[
\frac{5x}{2} + 4 = 19
\]
Subtract 4:
\[
\frac{5x}{2} = 15
\]
... | We need answer math word problem. Done. Need solve. Let second set = x. First = x+4. Third = x/2. Sum = x + (x+4) + x/2 = 19. Combine: 2.5x+4=19 => 2.5x=15 => x=6. First=10. Need show work, end Final answer: 10. Ensure final only? User asked solve showing work. final answer. We'll produce concise.
| 331 | 6,147.2 | true |
gsm8k-0006 | reasoning | test | 0 | The trousers cost $30.
- Mother gave: $6
- Father gave twice as much as the mother: 2 × $6 = $12
Total given by parents: $6 + $12 = $18
Adam’s contribution from savings: $30 - $18 = $12
Final answer: 12 | We need answer user's simple math word problem. Need solve showing work and end with Final answer: <number>. Need think: Adam bought trousers for $30. Mother gave $6, father gave twice as much as mother? "twice as much" likely twice as much as mother gave = $12. Total contributed parents = 18. Need savings = 30 - 18 = ... | 197 | 4,036.2 | true |
gsm8k-0006 | reasoning | test | 1 | The trousers cost $30.
His mother gave him $6.
His father gave him twice as much, so:
$6 \times 2 = 12$
Money given by his parents:
$6 + 12 = 18$
Money Adam had to contribute from his savings:
$30 - 18 = 12$
Final answer: 12 | We need answer math problem. Need produce final with work and Final answer: <number>. Let's solve: trousers cost $30. Mother gave $6. Father gave twice as much: twice mother? "His mother gave him $6 for this purpose, and his father gave him twice as much." likely twice as much as mother = $12. Total from parents = 18. ... | 198 | 3,738.4 | true |
gsm8k-0006 | reasoning | test | 2 | The trousers cost $30.
His mother gave him $6.
His father gave him twice as much, so $2 × $6 = $12.
Together his parents gave him:
$6 + $12 = $18
So Adam had to pay the rest from his savings:
$30 − $18 = $12
Final answer: 12 | We need answer arithmetic word problem. User asks solve showing work, end with Final answer: <number>. Need final only likely include work and final. Let's solve: trousers $30. Mother gave $6. Father gave twice as much (twice as much as mother?) $12. Total from parents =18. Adam savings =30-18=12. Need Final answer: 12... | 184 | 3,467 | true |
gsm8k-0006 | reasoning | test | 3 | The trousers cost $30.
Adam’s mother gave him $6.
His father gave him twice as much, so:
\[
2 \times 6 = 12
\]
Together, his parents gave him:
\[
6 + 12 = 18
\]
So Adam had to contribute:
\[
30 - 18 = 12
\]
Final answer: 12 | We need answer simple math. Let's solve: trousers $30. Mother gave $6. Father gave twice as much as mother? "twice as much" likely twice mother's $6 = $12. Contributions: 6+12=18. Savings: 30-18=12. Need show work and end Final answer: 12.
| 179 | 3,374.7 | true |
gsm8k-0007 | reasoning | train | 0 | He produces a total of 50,000 bars each month, assumed to be over 4 weeks.
- First week: 8,000 bars
- Second week: half as much as the first week
\[
8000 \div 2 = 4000
\]
- Third week: three times as much as the first week
\[
8000 \times 3 = 24000
\]
Total produced in the first three weeks:
\[
8000... | We need answer user's problem. Need solve. Let's parse carefully.
Problem: Boris produces 50,000 bars each month. He produces 8,000 bars first week. Second week half as much as first week. Third week three times as much as first week. How much does he produce the fourth week?
Need infer fourth week production given m... | 415 | 8,055.5 | true |
gsm8k-0007 | reasoning | train | 1 | The factory produces **50,000 bars per month**.
- First week: **8,000 bars**
- Second week: half of first week = 8,000 ÷ 2 = **4,000 bars**
- Third week: three times first week = 3 × 8,000 = **24,000 bars**
Total produced in the first three weeks:
8,000 + 4,000 + 24,000 = **36,000 bars**
Fourth week production:
50... | We need answer simple arithmetic. Need solve showing work, end Final answer: <number>. Need think if trick: 50,000 bars each month. First week 8,000. Second half as much as first: 4,000. Third three times first: 24,000. Month total 50,000. Fourth week = 50,000 - (8,000+4,000+24,000)=50,000-36,000=14,000. Need ensure no... | 345 | 6,425.9 | true |
gsm8k-0007 | reasoning | train | 2 | Boris produces 50,000 bars in a month, which we’ll assume is 4 weeks.
- First week: 8,000 bars
- Second week: half of first week = 8,000 ÷ 2 = 4,000 bars
- Third week: three times the first week = 3 × 8,000 = 24,000 bars
Total produced in the first three weeks:
8,000 + 4,000 + 24,000 = 36,000 bars
So the fourth wee... | We need answer simple arithmetic. Need show work and final answer format. Problem: total 50,000 per month? Produces 50,000 bars each month. First week 8000. Second half = 4000. Third three times first = 24000. Fourth week = total - sum first three = 50000 - (8000+4000+24000)=14000. Need ensure if month 4 weeks? implied... | 307 | 5,709.1 | true |
gsm8k-0007 | reasoning | train | 3 | First week: 8,000 bars
Second week: half of first week = 8,000 ÷ 2 = 4,000 bars
Third week: three times first week = 3 × 8,000 = 24,000 bars
Total for first three weeks:
8,000 + 4,000 + 24,000 = 36,000 bars
He produces 50,000 bars each month, so the fourth week:
50,000 − 36,000 = 14,000 bars
Final answ... | We need answer simple arithmetic word problem. We need solve. Boris produces 50,000 bars each month. First week 8,000. Second week half as much as first = 4,000. Third week three times first = 24,000. Fourth week presumably remaining to meet monthly total: 50,000 - (8,000+4,000+24,000)=50,000-36,000=14,000. Need show w... | 337 | 6,277.9 | true |
gsm8k-0008 | reasoning | test | 0 | He went to physical therapy 6 weeks.
Each week, he went 2 times, and each session was 2 hours:
\(6 \times 2 \times 2 = 24\) total hours
Each hour cost $125:
\(24 \times 125 = 3000\)
Final answer: 3000 | We need answer arithmetic. Need show work and final answer format. Problem: 6 weeks, each week twice for 2 hours. Sessions cost $125 per hour. Total hours = 6*2*2=24 hours. Cost = 24*125 = 3000. Need final answer: 3000 probably with dollar? Prompt says End answer with 'Final answer: <number>'. So number maybe 3000. Ens... | 196 | 4,163 | true |
gsm8k-0008 | reasoning | test | 1 | John went to physical therapy for 6 weeks.
Each week, he went 2 times, and each session lasted 2 hours:
\[
6 \text{ weeks} \times 2 \text{ sessions per week} \times 2 \text{ hours per session} = 24 \text{ hours}
\]
The cost is $125 per hour:
\[
24 \text{ hours} \times \$125 = \$3{,}000
\]
Final answer: 3000 | We need answer user's math problem. Need show work. Need compute: 6 weeks, each week twice for 2 hours each. Total hours = 6*2*2=24 hours. Cost per hour $125. Total=24*125=3000. Need final answer format 'Final answer: <number>' probably just number 3000? They ask show work. End with Final answer: <number>. Could be Fin... | 248 | 4,855.1 | true |
gsm8k-0008 | reasoning | test | 2 | John went to physical therapy for 6 weeks.
He went 2 times per week, and each session was 2 hours:
Total hours = 6 weeks × 2 sessions/week × 2 hours/session
Total hours = 24 hours
Each hour cost $125:
Total cost = 24 hours × $125/hour
Total cost = $3,000
Final answer: 3000 | We need answer arithmetic. We did. Need compute: 6 weeks, 2 visits per week, 2 hours each session. Total hours = 6*2*2 = 24 hours. Cost per hour $125 => 24*125 = 3000. Show work, final answer with Final answer: 3000. Ensure only final? User asks solve showing work. We can include concise. End exact.
| 197 | 3,865.6 | true |
gsm8k-0008 | reasoning | test | 3 | John went to physical therapy for 6 weeks.
Each week, he went twice for 2 hours:
- 2 sessions per week × 2 hours = 4 hours per week
Over 6 weeks:
- 4 hours per week × 6 weeks = 24 hours total
Each hour costs $125:
- 24 hours × $125 per hour = $3,000
Final answer: 3000 | We need answer user's math word problem. Need show work, end with Final answer: <number>. Compute: 6 weeks, twice per week = 12 sessions, each 2 hours = 24 hours, $125 per hour => 24*125=3000. Need final exactly maybe Final answer: 3000. Ensure no extra after? Could include work and then final line.
| 196 | 3,750 | true |
gsm8k-0009 | reasoning | test | 0 | On Saturday, Sunny sold:
- Gingerbread: 10 boxes
- Apple pie: 4 fewer boxes than on Sunday
On Sunday, he sold 15 boxes of apple pie, so on Saturday he sold:
\[
15 - 4 = 11
\]
boxes of apple pie.
On Sunday, he sold 5 more boxes of gingerbread than on Saturday:
\[
10 + 5 = 15
\]
boxes of gingerbread.
Now calcul... | We need answer math problem. Let's parse carefully.
Problem: Sunny is selling gingerbread and apple pie. On Saturday, he sold 10 boxes of gingerbread and 4 fewer boxes of apple pie, than on Sunday. On Sunday, he sold 5 more boxes of gingerbread than on Saturday and 15 boxes of apple pie. If gingerbread cost $6 and app... | 596 | 11,376 | true |
gsm8k-0009 | reasoning | test | 1 | On Saturday, Sunny sold:
- Gingerbread: 10 boxes
- Apple pie: 4 fewer than Sunday = 15 − 4 = 11 boxes
Saturday earnings:
- Gingerbread: 10 × $6 = $60
- Apple pie: 11 × $15 = $165
- Saturday total: $60 + $165 = $225
On Sunday, Sunny sold:
- Gingerbread: 5 more than Saturday = 10 + 5 = 15 boxes
- Apple pie: 15 boxes
S... | We need answer math problem. Let's solve carefully.
Problem: "Sunny is selling gingerbread and apple pie for a fundraiser. On Saturday, he sold 10 boxes of gingerbread and 4 fewer boxes of apple pie, than on Sunday. On Sunday, he sold 5 more boxes of gingerbread than on Saturday and 15 boxes of apple pie. If the ginge... | 600 | 11,134 | true |
gsm8k-0009 | reasoning | test | 2 | Saturday:
- Gingerbread: 10 boxes
- Apple pie: 15 − 4 = 11 boxes
Saturday earnings:
- Gingerbread: 10 × $6 = $60
- Apple pie: 11 × $15 = $165
- Total: $60 + $165 = $225
Sunday:
- Gingerbread: 10 + 5 = 15 boxes
- Apple pie: 15 boxes
Sunday earnings:
- Gingerbread: 15 × $6 = $90
- Apple pie: 15 × $15 = $225
- Total: $... | We need answer math problem. Need solve.
Let's parse carefully.
"Sunny is selling gingerbread and apple pie for a fundraiser. On Saturday, he sold 10 boxes of gingerbread and 4 fewer boxes of apple pie, than on Sunday. On Sunday, he sold 5 more boxes of gingerbread than on Saturday and 15 boxes of apple pie. If the g... | 525 | 9,685.1 | true |
gsm8k-0009 | reasoning | test | 3 | Saturday:
- Gingerbread: 10 boxes
- Apple pie: 4 fewer than Sunday’s 15 boxes = 15 − 4 = 11 boxes
Sunday:
- Gingerbread: 5 more than Saturday’s 10 boxes = 10 + 5 = 15 boxes
- Apple pie: 15 boxes
Earnings:
- Gingerbread: (10 + 15) × $6 = 25 × $6 = $150
- Apple pie: (11 + 15) × $15 = 26 × $15 = $390
Total earned:
$150... | We need answer math word problem. Need solve carefully. Let's parse: "Sunny is selling gingerbread and apple pie for a fundraiser. On Saturday, he sold 10 boxes of gingerbread and 4 fewer boxes of apple pie, than on Sunday. On Sunday, he sold 5 more boxes of gingerbread than on Saturday and 15 boxes of apple pie. If th... | 507 | 9,346.2 | true |
gsm8k-0010 | reasoning | train | 0 | Greg and his 3 younger siblings make a total of 4 people.
\[
\$20 \div 4 = \$5
\]
Each of them got $5.
Final answer: 5 | We need answer simple math. We did. Need final answer only? User asks solve showing work, end with Final answer: <number>. We can provide concise. Greg plus 3 younger siblings = 4 people total. $20 /4 = $5. End exactly.
| 106 | 2,364.1 | true |
gsm8k-0010 | reasoning | train | 1 | There are Greg and his 3 younger siblings, so there are:
3 + 1 = 4 people
They split $20 equally:
20 ÷ 4 = 5
Each person got $5.
Final answer: 5 | We need answer simple word problem. User asks: While walking down street with his 3 younger siblings, Greg found $20. To be fair, split equally. How much each? Show work. End with Final answer: <number>. Need consider total people: Greg + 3 siblings = 4. 20/4=5. Final answer: 5. Need maybe include $ maybe number? They ... | 158 | 2,942.8 | true |
gsm8k-0010 | reasoning | train | 2 | There are 4 people total: Greg and his 3 younger siblings.
\[
20 \div 4 = 5
\]
Each of them got $5.
Final answer: 5 | We need answer math problem. Need show work. Problem: Greg with 3 younger siblings, total people? Greg + 3 siblings = 4. Found $20. Split equally among them. 20/4=5. End with Final answer: 5. Need likely include dollar? They ask number. 'Final answer: <number>' maybe 5. Let's craft concise with work.
| 132 | 2,630.7 | true |
gsm8k-0010 | reasoning | train | 3 | Greg has 3 younger siblings, so there are:
1 + 3 = 4 people
Split $20 equally:
$20 ÷ 4 = $5
Final answer: 5 | We need answer simple math. We need final answer with Final answer: <number>. Need show work. Let's analyze: Greg + 3 younger siblings = 4 people total. $20 split equally: 20/4=5. Final answer: 5? They ask how much money did each of them get? Include dollars maybe $5. But requested final answer: <number>, probably 5. W... | 151 | 2,812 | true |
gsm8k-0011 | reasoning | train | 0 | Each whale has 40 gallons of blood.
Each shark has three times as much blood as a whale:
40 × 3 = 120 gallons per shark
Ten sharks have:
120 × 10 = 1,200 gallons
Final answer: 1200 | We need answer user. Need solve simple word problem. Need final with Final answer: <number>. Let's reason: whale blood 40 gallons. shark has three times as much as whale = 120 gallons per shark. Ten sharks = 120*10=1200. Show work. End exact.
| 141 | 3,072.9 | true |
gsm8k-0011 | reasoning | train | 1 | Each whale has 40 gallons of blood.
A shark has three times as much blood as a whale:
40 × 3 = 120 gallons per shark.
Ten sharks have:
120 × 10 = 1,200 gallons.
Final answer: 1200 | We need answer simple math. Need solve showing work end final answer. Let's compute: whale 40 gallons. shark three times as much: 3*40=120 gallons per shark. Ten sharks: 10*120=1200 gallons. Need final format 'Final answer: <number>'. Ensure no extra after? End answer with that.
| 153 | 2,859.9 | true |
gsm8k-0011 | reasoning | train | 2 | Each whale has 40 gallons of blood.
A shark has three times as much blood as a whale:
40 × 3 = 120 gallons per shark
Ten sharks have:
120 × 10 = 1200 gallons
Final answer: 1200 | We need answer a simple arithmetic word problem. Need solve showing work and end with Final answer: <number>. Need ensure final answer. Let's reason: Whale 40 gallons. Shark three times whale = 120 gallons per shark. Ten sharks = 1200 gallons. End with Final answer: 1200. Provide concise work.
| 145 | 2,702.6 | true |
gsm8k-0011 | reasoning | train | 3 | A whale has 40 gallons of blood.
A shark has three times as much blood as a whale:
\[
40 \times 3 = 120
\]
So, one shark has 120 gallons of blood.
For ten sharks:
\[
120 \times 10 = 1200
\]
Final answer: 1200 | We need answer simple arithmetic. Done. Need produce final with work and Final answer: <number>. Let's compute: whale 40 gallons. Shark = 3*40=120 gallons. Ten sharks = 10*120=1200 gallons. Need show work. Ensure final exact.
| 160 | 2,974.9 | true |
gsm8k-0012 | reasoning | train | 0 | Joey starts with 214 points and scores 26 points:
214 + 26 = 240
Marcy starts with 225 points and scores 10 points:
225 + 10 = 235
Now, to find how many points Joey is winning by:
240 − 235 = 5
Final answer: 5 | We need answer simple arithmetic. Need final with Final answer: <number>. Let's reason: Joey before 214, scores 26 => 240. Marcy 225 scores 10 => 235. Joey winning by 240-235=5. Need show work. End exactly? "Final answer: 5". Ensure no extra after maybe okay.
| 181 | 3,747.9 | true |
gsm8k-0012 | reasoning | train | 1 | Joey’s score after scoring 26 points:
214 + 26 = 240
Marcy’s score after scoring 10 points:
225 + 10 = 235
Now find the difference:
240 - 235 = 5
So Joey is winning by 5 points.
Final answer: 5 | We need answer simple math. We need show work and end with Final answer: <number>. Compute: Joey 214 + 26 = 240. Marcy 225 + 10 = 235. Difference 5. Need final exact.
| 147 | 2,826.8 | true |
gsm8k-0012 | reasoning | train | 2 | Joey’s score after scoring 26 points:
\[
214 + 26 = 240
\]
Marcy’s score after scoring 10 points:
\[
225 + 10 = 235
\]
The difference is:
\[
240 - 235 = 5
\]
Final answer: 5 | We need answer simple math. Need solve show work, final answer. Let's compute: Joey 214+26=240. Marcy 225+10=235. Joey winning by 240-235=5. Need final with Final answer: 5. Ensure maybe no extra? They requested solve showing work. We can provide concise.
| 175 | 3,249 | true |
gsm8k-0012 | reasoning | train | 3 | Joey’s new score:
214 + 26 = 240
Marcy’s new score:
225 + 10 = 235
Difference:
240 - 235 = 5
Final answer: 5 | We need answer simple arithmetic. Let's solve: Joey before 214, scores 26 => 240. Marcy 225 scores 10 => 235. Joey winning by 240-235=5. Need show work and final answer format. Final: 5.
| 134 | 2,551.9 | true |
gsm8k-0013 | reasoning | train | 0 | Melissa is paid $15 per day for 3 days:
\[
15 \times 3 = 45
\]
She pays $3 for parking each day for 3 days:
\[
3 \times 3 = 9
\]
Her pay after expenses is:
\[
45 - 9 = 36
\]
She works 6 hours each day for 3 days:
\[
6 \times 3 = 18
\]
Her hourly pay after expenses is:
\[
36 \div 18 = 2
\]
Final answer: 2 | We need answer arithmetic word problem. Need solve carefully.
Problem: Melissa jury duty. She spends 6 hours a day for 3 days listening to court case. Paid $15 per day but also has to pay $3 for parking each day. How much jury pay does she make per hour after expenses?
Compute total gross pay = 15*3 = 45. Parking exp... | 310 | 6,105.7 | true |
gsm8k-0013 | reasoning | train | 1 | Melissa works 6 hours per day for 3 days:
\[
6 \times 3 = 18 \text{ hours}
\]
She is paid $15 per day, but pays $3 for parking each day:
\[
15 - 3 = 12 \text{ dollars per day after expenses}
\]
Over 3 days, her total pay after expenses is:
\[
12 \times 3 = 36 \text{ dollars}
\]
Now divide the total pay after expe... | We need answer simple arithmetic. Need solve: Melissa jury duty 6 hours/day for 3 days. Paid $15 per day. Pays $3 parking each day. How much jury pay per hour after expenses? Daily pay $15, parking $3 => net per day $12. Total net $36. Total hours 18. Hourly = 36/18 = $2. Could also per hour after expenses daily net 12... | 268 | 5,036.4 | true |
gsm8k-0013 | reasoning | train | 2 | Melissa works 6 hours per day for 3 days:
6 × 3 = 18 hours
She earns $15 per day for 3 days:
15 × 3 = $45
She pays $3 per day for parking for 3 days:
3 × 3 = $9
Her pay after expenses is:
$45 − $9 = $36
Her hourly pay after expenses is:
$36 ÷ 18 = $2
Final answer: 2 | We need answer simple math. Need solve showing work, end with Final answer: <number>. Let's compute: Melissa 6 hours/day for 3 days = 18 hours total. Paid $15 per day for 3 days = $45 gross. Parking $3 each day for 3 days = $9 expenses. Net = 45 - 9 = 36. Per hour = 36 / 18 = $2 per hour. Need show work. Final answer: ... | 252 | 4,733.1 | true |
gsm8k-0013 | reasoning | train | 3 | Melissa works 6 hours a day for 3 days, so total hours:
6 × 3 = 18 hours
Her gross jury pay:
$15/day × 3 days = $45
Her parking expenses:
$3/day × 3 days = $9
Her total pay after expenses:
$45 − $9 = $36
Her pay per hour after expenses:
$36 ÷ 18 hours = $2 per hour
Final answer: 2 | We need answer math word problem. Let's solve carefully.
Melissa spends 6 hours a day for 3 days. Paid $15 per day. Pay $3 for parking each day. Need how much jury pay does she make per hour after expenses.
Interpretation: total pay per day 15, total expense per day 3, net per day 12. Over 3 days gross 45, expenses 9... | 293 | 5,620.1 | true |
gsm8k-0014 | reasoning | test | 0 | Ann is 9 years old. Her brother is twice her age:
9 × 2 = 18
In 3 years, her brother will be:
18 + 3 = 21
Final answer: 21 | We need answer simple arithmetic. Need solve: Ann 9, brother twice her age => 18. In 3 years brother will be 21. Need show work and end Final answer: 21. Ensure final exactly maybe with number.
| 107 | 2,558.5 | true |
gsm8k-0014 | reasoning | test | 1 | Ann is 9 years old. Her brother is twice her age:
9 × 2 = 18
In 3 years, her brother will be:
18 + 3 = 21
Final answer: 21 | We need answer simple math. Need show work and end with Final answer: <number>. Let's think: Ann 9, brother twice her age = 18. In 3 years brother = 21. Final answer: 21.
| 107 | 2,017 | true |
gsm8k-0014 | reasoning | test | 2 | Ann is 9 years old.
Her brother is twice her age:
\(9 \times 2 = 18\) years old.
In 3 years, her brother will be:
\(18 + 3 = 21\) years old.
Final answer: 21 | We need answer simple math. Done. Need final with work and Final answer: number. Compute: Ann 9, brother twice age = 18. In 3 years = 21. Ensure format.
| 111 | 2,076.1 | true |
gsm8k-0014 | reasoning | test | 3 | Ann is 9 years old.
Her brother is twice her age:
2 × 9 = 18 years old.
In 3 years, her brother will be:
18 + 3 = 21 years old.
Final answer: 21 | We need answer simple math. Need show work and end Final answer: <number>. Need final only maybe. Let's craft concise.
| 89 | 1,679.1 | true |
gsm8k-0015 | reasoning | test | 0 | Add the birds from each day:
- Days 1 and 2: 50 birds
- Day 3: 0 birds
- Days 4 and 5: 120 birds
- Day 6: 20 birds
- Day 7: 90 birds
Total birds:
50 + 0 + 120 + 20 + 90 = 280 birds
Average per day over 7 days:
280 ÷ 7 = 40
Final answer: 40 | We need answer user's math problem. Need show work, end with Final answer: <number>. Problem: Mack counts birds over next week. Days one and two total 50. Day three none (0). Days four and five saw 120. Day six 20. Day seven 90. Average per day over week? Total = 50 + 0 + 120 + 20 + 90 = 280. Over 7 days. 280/7=40. Nee... | 284 | 5,775.3 | true |
gsm8k-0015 | reasoning | test | 1 | Mack counted birds over 7 days.
Total birds:
- Days 1 and 2: 50 birds
- Day 3: 0 birds
- Days 4 and 5: 120 birds
- Day 6: 20 birds
- Day 7: 90 birds
Total = 50 + 0 + 120 + 20 + 90 = 280 birds
Average per day = total birds ÷ number of days = 280 ÷ 7 = 40
Final answer: 40 | We need answer simple word problem. We need produce final answer with work and end exact 'Final answer: <number>'. Let's compute: days total: day1+day2=50, day3=0, day4+day5=120, day6=20, day7=90. Total=50+0+120+20+90=280. Average over 7 days = 280/7=40. Need show work. Ensure final line exactly Final answer: 40.
| 252 | 4,744.5 | true |
gsm8k-0015 | reasoning | test | 2 | Total birds seen:
- Days 1 and 2: 50
- Day 3: 0
- Days 4 and 5: 120
- Day 6: 20
- Day 7: 90
Add them:
50 + 0 + 120 + 20 + 90 = 280 birds
There are 7 days in a week, so the average is:
280 ÷ 7 = 40
Final answer: 40 | We need answer simple arithmetic. Compute total birds over week: days one and two total 50. day three 0. days four and five total 120. day six 20, day seven 90. Total = 50+0+120+20+90 = 280. Average per day over 7 days = 280/7 = 40. Need show work and final answer: 40. Ensure final answer format.
| 228 | 4,309.2 | true |
gsm8k-0015 | reasoning | test | 3 | The total number of birds Mack saw over the week is:
\[
50 + 0 + 120 + 20 + 90 = 280
\]
He counted birds over 7 days, so the daily average is:
\[
\frac{280}{7} = 40
\]
Final answer: 40 | We need answer user asks simple arithmetic. Need produce final with work and end with Final answer: <number>. Need be precise. Let's compute: days: day1+day2 total 50, day3 0, day4+day5 120, day6 20, day7 90. Total = 50+0+120+20+90 = 280. Average over 7 days = 280/7=40. End with Final answer: 40.
| 203 | 3,814.2 | true |
gsm8k-0016 | reasoning | train | 0 | Kelly has:
- 5 quarters = \(5 \times 25 = 125\) cents
- 2 dimes = \(2 \times 10 = 20\) cents
Total money:
\[
125 + 20 = 145
\]
Cost of the pop:
\[
145 - 55 = 90
\]
Final answer: 90 | We need answer arithmetic. Compute: 5 quarters = 125 cents. 2 dimes = 20. Total 145. Buy 55. Left 90. Need show work and end Final answer: 90.
| 153 | 3,243.7 | true |
gsm8k-0016 | reasoning | train | 1 | Kelly has 5 quarters:
\[
5 \times 25 = 125 \text{ cents}
\]
She has 2 dimes:
\[
2 \times 10 = 20 \text{ cents}
\]
Total money she has:
\[
125 + 20 = 145 \text{ cents}
\]
The pop costs 55 cents, so the amount left is:
\[
145 - 55 = 90 \text{ cents}
\]
Final answer: 90 | We need answer simple arithmetic. Need solve showing work end with Final answer: <number>. Let's compute: 5 quarters = 5*25=125 cents. 2 dimes=20 cents. Total=145. Pop 55. Left=90. Need final answer: 90. Ensure format exactly? "End your answer with 'Final answer: <number>'." We can include work then final.
| 228 | 4,334.8 | true |
gsm8k-0016 | reasoning | train | 2 | 5 quarters = 5 × 25 = 125 cents
2 dimes = 2 × 10 = 20 cents
Total money Kelly has:
125 + 20 = 145 cents
She spends 55 cents:
145 − 55 = 90 cents
Final answer: 90 | We need answer simple arithmetic. Need compute: 5 quarters = 125 cents. 2 dimes = 20 cents. Total 145 cents. Subtract 55 = 90 cents. Need show work. End with Final answer: <number>.
| 141 | 2,773.3 | true |
gsm8k-0016 | reasoning | train | 3 | Kelly has 5 quarters, so:
5 × 25 cents = 125 cents
She also has 2 dimes, so:
2 × 10 cents = 20 cents
Total money:
125 + 20 = 145 cents
Cost of the pop is 55 cents, so money left:
145 − 55 = 90 cents
Final answer: 90 | We need answer user: math word problem. We did. Need solve and show work. Problem: Kelly has 5 quarters and 2 dimes. Pop 55 cents. How many cents left? Quarters 5*25=125, dimes 2*10=20 total 145. minus 55 = 90. End with Final answer: 90. Need concise but show work. Ensure final exactly maybe line.
| 201 | 3,818.2 | true |
gsm8k-0017 | reasoning | train | 0 | She needs 5 crayons.
Cost = 5 × $2 = $10
Change = $20 − $10 = $10
Final answer: 10 | We need answer user: "Violetta wants to buy new crayons. She needs them in 5 different colors and prepared $20 for this purchase. One crayon costs $2. How much change will she get?
Solve the problem, showing your work. End your answer with 'Final answer: <number>'."
Simple arithmetic. She needs 5 different colors lik... | 224 | 4,516.2 | true |
gsm8k-0017 | reasoning | train | 1 | Violetta needs 5 crayons, one of each color.
Cost per crayon: $2
Total cost: 5 × $2 = $10
She has $20, so her change is:
$20 − $10 = $10
Final answer: 10 | We need answer math word problem. We need produce final with work and final answer. Simple: 5 colors, one crayon costs $2. She needs crayons in 5 different colors likely 5 crayons. Total 5*2=10. Prepared 20. Change = 20-10=10. End with Final answer: 10.
| 150 | 2,866.4 | true |
gsm8k-0017 | reasoning | train | 2 | Violetta needs 5 crayons, one for each color.
Cost:
5 crayons × $2 each = $10
Change:
$20 − $10 = $10
Final answer: 10 | We need answer simple arithmetic. Need solve: needs 5 different colors, prepared $20. One crayon costs $2. How much change? Need maybe buy one crayon in each of 5 colors => 5 crayons. Cost 5*2=10. Change 20-10=10. Need show work, end Final answer: <number>. Final answer: 10 maybe with dollar sign? They say <number>, li... | 172 | 3,250.9 | true |
gsm8k-0017 | reasoning | train | 3 | Violetta needs 5 crayons, one of each color.
Cost of crayons:
5 × $2 = $10
Change from $20:
$20 − $10 = $10
Final answer: 10 | We need answer user's math problem. Need produce final with work and end with Final answer: <number>. Problem: Violetta wants to buy crayons. Needs them in 5 different colors and prepared $20 for this purchase. One crayon costs $2. How much change will she get?
Interpretation ambiguous: "She needs them in 5 different ... | 430 | 7,958.3 | true |
gsm8k-0018 | reasoning | train | 0 | The Kennel house has:
- 3 German Shepherds, each consuming 5 kilograms per day:
\[
3 \times 5 = 15 \text{ kg/day}
\]
- 2 Bulldogs, each consuming 3 kilograms per day:
\[
2 \times 3 = 6 \text{ kg/day}
\]
Total daily dog food needed:
\[
15 + 6 = 21 \text{ kg/day}
\]
In a week (7 days):
\[
21 \times 7 = 14... | We need answer simple math. Done. Need show work and end with Final answer: number. Let's compute: 3 German Shepherds *5 kg/day=15. 2 Bulldogs*3=6. Total daily=21 kg. Week 7 days =>147 kg. Need final answer: 147 likely no unit? User says number. Could include 147. Ensure end exact.
| 247 | 4,976.9 | true |
gsm8k-0018 | reasoning | train | 1 | 3 German Shepherds consume \(3 \times 5 = 15\) kg per day.
2 Bulldogs consume \(2 \times 3 = 6\) kg per day.
Total daily consumption is \(15 + 6 = 21\) kg.
In one week (7 days): \(21 \times 7 = 147\) kg.
Final answer: 147 | We need answer user asks math word problem. Need solve showing work and end with Final answer: <number>. Let's compute: 3 German Shepherds *5 kg/day =15 kg/day. 2 Bulldogs *3=6 kg/day. total daily=21 kg/day. week=7 days =>147 kg. Need final answer format exactly? "Final answer: 147". Ensure no extra after? They say End... | 212 | 4,046.9 | true |
gsm8k-0018 | reasoning | train | 2 | There are 3 German Shepherds and 2 Bulldogs.
Daily food needed:
- German Shepherds: \(3 \times 5 = 15\) kg per day
- Bulldogs: \(2 \times 3 = 6\) kg per day
Total per day:
\[
15 + 6 = 21 \text{ kg}
\]
In one week (7 days):
\[
21 \times 7 = 147
\]
Final answer: 147 | We need answer arithmetic. Need compute. 3 German Shepherds *5 kg/day =15. 2 Bulldogs*3=6. Total daily=21. Week 7 days =147 kg. Need show work, final answer: 147.
| 176 | 3,411.9 | true |
gsm8k-0018 | reasoning | train | 3 | 3 German Shepherds × 5 kg/day = 15 kg/day
2 Bulldogs × 3 kg/day = 6 kg/day
Total daily food = 15 + 6 = 21 kg/day
Total weekly food = 21 kg/day × 7 days = 147 kg
Final answer: 147 | We need answer arithmetic word problem. Compute: 3 German Shepherds *5 kg/day =15. 2 Bulldogs*3=6. Total daily=21 kg/day. Week 7 days: 21*7=147. Need show work, end with Final answer: <number>. Ensure final only? User asks solve showing work. We can include explanation. Final line exact.
| 163 | 3,184 | true |
gsm8k-0019 | reasoning | train | 0 | Julie started with $500.
She spent 20% of $500 on clothes:
\[
0.20 \times 500 = 100
\]
Money remaining after buying clothes:
\[
500 - 100 = 400
\]
She then spent 25% of the remaining $400 on CDs:
\[
0.25 \times 400 = 100
\]
Money remaining after buying CDs:
\[
400 - 100 = 300
\]
Final answer: 300 | We need answer math. Let's solve: Start 500. Spent 20% on clothes = 100. Remaining 400. Spent 25% of remaining on CDs = 100. Remaining 300. Need show work and final answer format. Simple.
| 215 | 4,366 | true |
gsm8k-0019 | reasoning | train | 1 | Julie started with $500.
She spent 20% on clothes:
20% of $500 = $100
Remaining money:
$500 - $100 = $400
She then spent 25% of the remaining $400 on CDs:
25% of $400 = $100
Money left:
$400 - $100 = $300
Final answer: 300 | We need answer user: Julie had $500. She spent 20% of it on clothes and then 25% of remaining money on CDs. How much left? Show work, end with Final answer: <number>.
Compute: initial 500. Clothes 20% = 100, remaining 400. CDs 25% of remaining = 100, remaining 300. Final answer: 300.
Need output only? User says solve... | 245 | 4,599.5 | true |
gsm8k-0019 | reasoning | train | 2 | Julie started with $500.
She spent 20% on clothes:
\[
0.20 \times 500 = 100
\]
Money remaining:
\[
500 - 100 = 400
\]
Then she spent 25% of the remaining money on CDs:
\[
0.25 \times 400 = 100
\]
Money left:
\[
400 - 100 = 300
\]
Final answer: 300 | We need answer a simple math word problem. Need show work and end with Final answer: <number>. Compute: Julie $500. Spent 20% on clothes: 0.2*500=100, remaining 400. Then spent 25% of remaining on CDs: 0.25*400=100, remaining 300. Final answer: 300. Need likely include dollars? They ask End answer with 'Final answer: <... | 266 | 5,009.9 | true |
gsm8k-0019 | reasoning | train | 3 | Julie started with $500.
She spent 20% on clothes:
\[
20\% \text{ of } 500 = 0.20 \times 500 = 100
\]
Money remaining after clothes:
\[
500 - 100 = 400
\]
Then she spent 25% of the remaining money on CDs:
\[
25\% \text{ of } 400 = 0.25 \times 400 = 100
\]
Money left:
\[
400 - 100 = 300
\]
Final answer: 300 | We need answer arithmetic. Let's solve: 500 - 20% = 500*0.8=400. 25% of remaining on CDs = 100. Left 300. Need show work and final answer with exact format.
| 228 | 4,272 | true |
gsm8k-0020 | reasoning | test | 0 | The first child is 6 feet tall, which is:
6 × 12 = 72 inches
The second child is 2 inches taller:
72 + 2 = 74 inches
The third child is 5 inches shorter than the second:
74 − 5 = 69 inches
The fourth child is 3 inches taller than the third:
69 + 3 = 72 inches
Final answer: 72 | We need answer arithmetic. Need final only? User asks solve showing work end final answer: <number>. We can provide concise. Compute: first 6 ft =72 inches. second two inches taller =74. third 5 inches shorter than second =69. fourth 3 inches taller than third =72. Final answer: 72. Ensure format.
| 180 | 3,744.9 | true |
gsm8k-0020 | reasoning | test | 1 | The first child is 6 feet tall:
\(6 \times 12 = 72\) inches
The second child is 2 inches taller:
\(72 + 2 = 74\) inches
The third child is 5 inches shorter than the second child:
\(74 - 5 = 69\) inches
The fourth child is 3 inches taller than the third child:
\(69 + 3 = 72\) inches
Final answer: 72 | We need answer arithmetic. Let's solve: first 6 feet =72 inches. second two inches taller:74. third 5 inches shorter than second:69. fourth three inches taller than third:72. Need show work and final answer. Ensure final answer: <number>. Could be just 72.
| 179 | 3,459.4 | true |
gsm8k-0020 | reasoning | test | 2 | First child: 6 feet = 72 inches.
Second child: 72 + 2 = 74 inches.
Third child: 74 - 5 = 69 inches.
Fourth child: 69 + 3 = 72 inches.
Final answer: 72 | We need answer simple arithmetic. Need solve: first 6 feet = 72 inches. second two inches taller = 74. third 5 shorter = 69. fourth 3 taller = 72 inches. End Final answer: 72. Need show work. Ensure final exact.
| 134 | 2,643.3 | true |
gsm8k-0020 | reasoning | test | 3 | The first child is 6 feet tall.
Since 1 foot = 12 inches:
\[
6 \text{ feet} = 6 \times 12 = 72 \text{ inches}
\]
The second child is 2 inches taller than the first child:
\[
72 + 2 = 74 \text{ inches}
\]
The third child is 5 inches shorter than the second child:
\[
74 - 5 = 69 \text{ inches}
\]
The fourth child ... | We need answer simple arithmetic. Need solve: first 6 ft tall = 72 inches. second two inches taller than first: 74 inches. third 5 inches shorter than second: 69 inches. fourth three inches taller than third: 72 inches. Need show work and end final answer: <number>. Need be careful: first child is 6 feet tall. Convert ... | 280 | 5,162.1 | true |
gsm8k-0021 | reasoning | train | 0 | Eve originally had 20 pomelos.
She is left with \( \frac{1}{4} \) of the original amount:
\[
\frac{1}{4} \times 20 = 5
\]
So she has 5 pomelos left.
The number she gave away is:
\[
20 - 5 = 15
\]
Final answer: 15 | We need answer arithmetic. Need show work, end with Final answer: number. Problem: Eve had 20 pomelos. After giving friend some, left with 1/4 of originally had. 1/4 of 20 =5 left. Gave away 20-5=15. Need final format. Ensure final only? User says solve showing work. End with 'Final answer: <number>'. Can include work ... | 190 | 3,947.7 | true |
gsm8k-0021 | reasoning | train | 1 | Eve originally had 20 pomelos.
She is left with \( \frac{1}{4} \) of the original amount:
\[
\frac{1}{4} \times 20 = 5
\]
So she has 5 pomelos left.
The number she gave away is:
\[
20 - 5 = 15
\]
Final answer: 15 | We need answer simple math. Need solve. Eve had 20 pomelos. Left with 1/4 of originally had = 20*1/4 =5. Give away 20-5=15. Need show work and end with Final answer: 15. Ensure exact phrase.
| 160 | 3,062.5 | true |
gsm8k-0021 | reasoning | train | 2 | Eve originally had 20 pomelos.
She is left with \( \frac{1}{4} \) of what she originally had:
\[
\frac{1}{4} \times 20 = 5
\]
So the number she gave away is:
\[
20 - 5 = 15
\]
Final answer: 15 | We need answer a simple arithmetic word problem. User asks solve showing work and end with Final answer: <number>. We need output final likely with work. Need think: Eve had 20. Left with 1/4 of originally = 5. Gave away = 20 - 5 = 15. Need final answer: 15. Ensure end exact? "End your answer with 'Final answer: <numbe... | 191 | 3,591.5 | true |
gsm8k-0021 | reasoning | train | 3 | Eve originally had 20 pomelos.
She is left with 1/4 of the original amount:
\[
\frac{1}{4} \times 20 = 5
\]
So Eve gave away:
\[
20 - 5 = 15
\]
Final answer: 15 | We need answer simple word problem. We did. Need solve. Eve had 20. Left with 1/4 of original = 5. Gave away 20-5=15. Need show work and end with Final answer: 15. Ensure exact format.
| 137 | 2,612 | true |
gsm8k-0022 | reasoning | train | 0 | Peter exercised for:
- Sunday: 23 minutes
- Monday: 16 minutes
Combined for Sunday and Monday:
23 + 16 = 39 minutes
On Tuesday, he wants to exercise for twice that amount:
39 × 2 = 78 minutes
Final answer: 78 | We need answer simple arithmetic. Need include work and final answer exact format. Compute Sunday 23 + Monday 16 = 39. Twice = 78. Need final: Final answer: 78. Ensure maybe show work.
| 125 | 2,750.5 | true |
gsm8k-0022 | reasoning | train | 1 | Sunday exercise: 23 minutes
Monday exercise: 16 minutes
Combined Sunday and Monday:
23 + 16 = 39 minutes
Peter wants to exercise twice that amount on Tuesday:
39 × 2 = 78 minutes
Final answer: 78 | We need answer simple math. Done. Need show work and final answer with number. Let's craft concise.
| 88 | 1,676.2 | true |
gsm8k-0022 | reasoning | train | 2 | Sunday: 23 minutes
Monday: 16 minutes
Combined time on Monday and Sunday:
23 + 16 = 39 minutes
Tuesday should be twice that combined amount:
2 × 39 = 78 minutes
Final answer: 78 | We need answer simple math. We did. Now solve. Problem: Tuesday = twice amount Monday + Sunday combined. Sunday 23, Monday 16. Combined 39. Twice = 78. Need show work, end with Final answer: 78. Ensure exact final phrase.
| 126 | 2,365.7 | true |
gsm8k-0022 | reasoning | train | 3 | Sunday: 23 minutes
Monday: 16 minutes
Combined Sunday and Monday:
23 + 16 = 39 minutes
Peter wants to exercise for twice that amount on Tuesday:
2 × 39 = 78 minutes
Final answer: 78 | We need answer arithmetic word problem. Need show work, final answer. Compute Sunday + Monday = 23+16=39. Twice that =78. Tuesday needs 78 minutes. Provide concise.
| 110 | 2,068.7 | true |
gsm8k-0023 | reasoning | train | 0 | The total cost is $60, and there are 10 classes total.
If Manny misses \(x\) classes, he will attend \(10 - x\) classes.
For the parents to keep signing him up, the cost per attended class must be at most $10:
\[
\frac{60}{10-x} \le 10
\]
Multiply both sides by \(10 - x\):
\[
60 \le 10(10 - x)
\]
Divide by 10:
\... | We need answer math word problem. Need solve. Let's parse: Manny signed up for Karate classes for $60. His parents tell him that if his classes end up costing more than $10 per class, then they won't sign him up again. If there are 10 total classes, how many can he miss before they don't sign him up again?
We need car... | 737 | 13,920.7 | true |
gsm8k-0023 | reasoning | train | 1 | Manny pays a total of $60 for the class package.
If he misses some classes, the cost per class he actually attends is:
\[
\text{cost per attended class} = \frac{60}{\text{number of classes attended}}
\]
His parents will not sign him up again if the cost per class is **more than $10**.
So we need:
\[
\frac{60}{\tex... | We need answer simple arithmetic. Need solve. Manny signed up for $60 for karate classes. Parents: if classes end up costing more than $10 per class, they won't sign again. If 10 total classes, how many can he miss before they don't sign again?
Interpretation: total cost $60. If he misses some, the cost per class base... | 537 | 9,986.8 | true |
gsm8k-0023 | reasoning | train | 2 | He paid $60 total.
Let \(m\) be the number of classes he misses. Then the number of classes he actually attends is:
\[
10 - m
\]
The cost per class he attends is:
\[
\frac{60}{10-m}
\]
His parents will not sign him up again if the cost is more than $10 per class, so we need:
\[
\frac{60}{10-m} \le 10
\]
Multiply... | We need answer user's math word problem. We did. Need solve. Let's parse: Manny signed up for Karate classes for $60. Parents tell him if his classes end up costing more than $10 per class, then they won't sign him up again. If there are 10 total classes, how many can he miss before they don't sign him up again?
Need ... | 724 | 13,391.9 | true |
gsm8k-0023 | reasoning | train | 3 | Manny pays $60 total for 10 classes.
If he misses some classes, the effective cost per attended class is:
\[
\frac{60}{\text{classes attended}}
\]
His parents won’t sign him up again if the cost is **more than** $10 per class. So the number of classes he attends must satisfy:
\[
\frac{60}{\text{classes attended}} \... | We need answer a math word problem. User asks: Manny signed up for Karate classes for $60. Parents tell him if classes end up costing more than $10 per class, then they won't sign him up again. If there are 10 total classes, how many can he miss before they don't sign him up again? Solve, show work, end with Final answ... | 642 | 11,849.4 | true |
gsm8k-0024 | reasoning | train | 0 | Josie's farm produces:
- Grapes per year: \(10 \text{ acres} \times 5 \text{ tons/acre} = 50 \text{ tons}\)
- Barrels of wine per year: \(50 \text{ tons} \times 2 \text{ barrels/ton} = 100 \text{ barrels}\)
Final answer: 100 | We need answer simple arithmetic. Need provide final answer. Compute: 10 acres * 5 tons/acre/year = 50 tons/year. 50 tons * 2 barrels/ton = 100 barrels. Show work. End with Final answer: 100. Ensure only? User asks solve showing work. final.
| 165 | 3,450.4 | true |
gsm8k-0024 | reasoning | train | 1 | Josie has 10 acres, and each acre produces 5 tons of grapes per year:
10 acres × 5 tons/acre = 50 tons of grapes per year.
Each ton of grapes makes 2 barrels of wine:
50 tons × 2 barrels/ton = 100 barrels of wine per year.
Final answer: 100 | We need answer arithmetic. Compute: 10 acres * 5 tons/acre = 50 tons. 50 tons * 2 barrels/ton = 100 barrels. Need show work and end with Final answer: <number>. Ensure final exact.
| 141 | 2,748.5 | true |
gsm8k-0024 | reasoning | train | 2 | 10 acres × 5 tons per acre = 50 tons of grapes per year
50 tons × 2 barrels per ton = 100 barrels of wine per year
Final answer: 100 | We need answer simple arithmetic. Need final with 'Final answer: <number>'. User asks show work. Let's compute: 10 acres * 5 tons/acre = 50 tons. 50 tons * 2 barrels/ton = 100 barrels. Need final answer: 100. Ensure exact format. Could include concise work.
| 126 | 2,357.9 | true |
gsm8k-0024 | reasoning | train | 3 | Josie’s farm is 10 acres.
Each acre produces 5 tons of grapes per year:
\[
10 \times 5 = 50 \text{ tons of grapes per year}
\]
Each ton of grapes makes 2 barrels of wine:
\[
50 \times 2 = 100 \text{ barrels of wine per year}
\]
Final answer: 100 | We need answer arithmetic. Need solve: 10 acres, 5 tons/acre/year => 50 tons/year. Each ton makes 2 barrels => 100 barrels/year. Show work. End with Final answer: 100. Ensure exact format maybe 'Final answer: 100'.
| 163 | 3,029.4 | true |
gsm8k-0025 | reasoning | train | 0 | Each tire costs **25 cents**, or **$0.25**.
- 5 bicycles: \(5 \times 2 = 10\) tires
- 3 tricycles: \(3 \times 3 = 9\) tires
- 1 unicycle: \(1 \times 1 = 1\) tire
Total tires inflated:
\[
10 + 9 + 1 = 20
\]
Total money made:
\[
20 \times 0.25 = 5
\]
Final answer: 5 | We need answer math word problem. We did. Need solve. Let's parse: each tire costs 25 cents to inflate. First day: 5 people on bicycles came by to get both tires inflated. A bicycle has 2 tires, so 10 tires * $0.25 = $2.50. 3 people came by to get all their tricycle tires inflated. Tricycle has 3 tires each, total 9 ti... | 358 | 7,027.4 | true |
gsm8k-0025 | reasoning | train | 1 | Each tire costs $0.25.
- 5 people on bicycles: \(5 \times 2 = 10\) tires
- 3 people on tricycles: \(3 \times 3 = 9\) tires
- 1 person on a unicycle: \(1 \times 1 = 1\) tire
Total tires inflated:
\[
10 + 9 + 1 = 20
\]
Total money made:
\[
20 \times 0.25 = 5
\]
Final answer: 5 | We need answer math word problem. Need solve. Let's parse:
Shawnda charges by tire. Each tire costs 25 cents to inflate.
First day: 5 people on bicycles came by to get both tires inflated. Bicycles have 2 tires each -> 5*2=10 tires.
3 people came by to get all their tricycle tires inflated. Tricycle has 3 tires -> 3*3=... | 360 | 6,752.6 | true |
gsm8k-0025 | reasoning | train | 2 | Each tire costs 25 cents, or $0.25.
- 5 bicycles: each has 2 tires
\(5 \times 2 = 10\) tires
\(10 \times 0.25 = 2.50\) dollars
- 3 tricycles: each has 3 tires
\(3 \times 3 = 9\) tires
\(9 \times 0.25 = 2.25\) dollars
- 1 unicycle: 1 tire
\(1 \times 0.25 = 0.25\) dollars
Total:
\[
2.50 + 2.25 + 0... | We need answer math problem. We have to show work and end final answer. Need compute. Bike tires: 5 people bicycles got both tires inflated: each bicycle 2 tires, each 0.25 => 5*2*0.25=2.5. Tricycles: 3 people got all tricycle tires inflated. Tricycle has 3 tires. 3 people *3 tires*0.25 = 2.25. Unicycle: 1 person on un... | 351 | 6,521.3 | true |
gsm8k-0025 | reasoning | train | 3 | Each tire costs 25 cents.
- 5 bicycles × 2 tires = 10 tires
- 3 tricycles × 3 tires = 9 tires
- 1 unicycle × 1 tire = 1 tire
Total tires inflated = 10 + 9 + 1 = 20 tires
Money made = 20 × $0.25 = $5
Final answer: 5 | We need answer user's math word problem. Need solve showing work, end with Final answer: <number>. Let's analyze carefully.
Problem: Each tire costs 25 cents to inflate. First day, 5 people on bicycles came by to get both tires inflated. 3 people came by to get all their tricycle tires inflated. Finally, one person ac... | 312 | 5,814.8 | true |
End of preview. Expand in Data Studio
Decision heads: self-verification by readout, not a second model
A correctness verdict is already linearly readable from a language model's own hidden state. A closed-form head (ridge + Platt, about 66 KB) over the last-prompt-token hidden state matches or beats purpose-trained judges, and runs inside the inference engine as a sidecar. This dataset is the results record for that study.
Canonical source, with the scripts and the full record:
Start with CONCLUSION.md, then WHITEPAPER-OUTLINE.md, PLAN.md, PRIOR-ART.md, and
the per-model reports.
Headline results
- Readout beats asking in words. Scion-35B-A3B catches 23/28 of its own errors from the head versus 7/28 prompted, at zero false rejects; frozen judge bench AUC 0.999 (prompted 0.903) and 0.9988 on another model's answers.
- Survives trained low-bit, not post-hoc quant. Scion (2-bit ternary MoE) 0.999; Ternary-Bonsai-2-27B (2-bit ternary dense) 0.988; post-hoc quantised bodies collapse (Clef QAT 0.712, h128 0.648) and heads do not transfer across bodies or prompt formats.
- Selection is the efficiency lever. Head-gated sequential sampling reaches best-of-3 accuracy at roughly half the pool cost. Majority plus head override ("veto") adds +7/199 on Scion and +5/199 on Bonsai, pooled 14 fixes / 2 breaks over 398 held-out tasks, exact p=.004, with no extra generation.
- The model's own answer-slot margin, p(A) minus p(B), is a strong zero-training readout (AUC 0.880 Scion / 0.858 Bonsai) and is not dominated by the fitted head.
- Negative result, kept. Mid-generation early cancellation does not pay off: even a perfect predictor saves only 21 to 34 percent of tokens, and realistic operating points save 10 to 19 percent while falsely cancelling 3 to 15 percent of correct samples. The monitor is an end-of-trace verifier, not an early exit.
What is here
CONCLUSION.md,WHITEPAPER-OUTLINE.md,PLAN.md,PRIOR-ART.md,COMPARISON.md,MONITOR-FIX.md: write-up, plan, literature scan, and the corrected monitor record.SCION-HEAD-REPORT.md,SCION-COMMUNITY-REPORT.md,BONSAI-HEAD-REPORT.md,BONSAI-COMMUNITY-REPORT.md: per-model before/after and community-benchmark arms.PORT-REPORT.md: the Strata-engine port (cross-engine transfer, the 176B FlashNext community arms, the 176B and 35B-q36 heads, and the engine/API serving path for the readout).*.json: every result the numbers come from (probes, readouts, attribution audits, veto, cancel simulation, selection frontiers).judge-bench.jsonl+judge-bench.manifest.json: the frozen 378-item judge benchmark and its sha256 manifest.- Exported heads:
scion-35b-a3b-decision-head.json,bonsai-2-27b-decision-head.json,scion-176b-a6b-decision-head.json,scion-176b-a6b-community-head.json,scion-35b-a3b-decision-head-q36.json, and the in-domain heads. run-*.sh: the session chains that produced the runs.samples/*.jsonl: the per-sample generations behind the arms (task id, bucket, split, sample index, content, reasoning, token count, wall time, correctness), wired into the Viewer as named configs. The frozen bench is the default config; the run pools are the rest. These are regenerable from the run directories.
Not included: the multi-GB hidden-state dumps and .npz state caches. They are regenerable,
and the JSONs beside them carry the numbers.
Models referenced
- SkyIsNotGreen/Scion-35B-A3B (2.61 bpw ternary MoE)
- prism-ml/Ternary-Bonsai-2-27B-gguf
- Qwen3.5 0.8B / 4B and Qwen3 1.7B (reference probes), Qwen3.8-27B (monitor)
Status and caveats
Internal, unreviewed numbers. One task family (candidate-answer verification) and one generator per body. Held-out sets are 199 and 398 tasks. The negative results are included deliberately. The frozen bench is derived from GSM8K, MATH and HumanEval through programmatic checkers; check those sources' terms before redistribution.
License: MIT, matching the source repository.
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