Datasets:
instance_id large_stringlengths 20 20 | core_problem_id large_stringlengths 20 20 | split_group_id large_stringlengths 20 20 | split large_stringclasses 1
value | subset large_stringclasses 6
values | family large_stringclasses 13
values | difficulty int64 1 7 | style large_stringclasses 4
values | instruction_variant int64 -1 4 | has_distractors bool 2
classes | seed int64 0 90k | prompt large_stringlengths 82 1.73k | core_prompt large_stringlengths 48 1.46k | answer large_stringlengths 1 61 | answer_format large_stringclasses 7
values | solver_type large_stringclasses 13
values | key_verified_independently bool 1
class | model large_stringclasses 1
value | provider large_stringclasses 1
value | reasoning_effort large_stringclasses 5
values | temperature float64 0.7 0.7 | top_p float64 0.99 0.99 | reasoning large_stringlengths 82 69.1k | response large_stringlengths 0 35.5k | extracted_answer large_stringlengths 1 61 ⌀ | is_correct bool 2
classes | is_correct_strict_format bool 2
classes | finish_reason large_stringclasses 2
values | prompt_tokens int64 72 437 | completion_tokens int64 73 32.8k | latency_s float64 0.54 354 | generator_version large_stringclasses 2
values | max_tokens int64 16k 32.8k | beam_pass_rate float64 0 1 | beam_attempts int64 2 7 |
|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
fc5d6c28aca127b81d57 | 7b7140f05508d5e226b1 | 7b7140f05508d5e226b1 | train | pareto_5efforts | inventory_word_problem | 1 | concise | -1 | false | 50,000 | Zeynep starts with 131 test tubes. Then, in order, Zeynep doubles the stock; then hands 120 to a customer; then receives a delivery of 28; then doubles the stock. How many test tubes does Zeynep have at the end?
Final line: `ANSWER: <answer>`. | Zeynep starts with 131 test tubes. Then, in order, Zeynep doubles the stock; then hands 120 to a customer; then receives a delivery of 28; then doubles the stock. How many test tubes does Zeynep have at the end? | 340 | integer | state_simulation | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | low | 0.7 | 0.99 | We need solve simple arithmetic. Need be careful. Start 131. doubles: 262. hands 120: 142. receives 28: 170. doubles: 340. Answer 340. Need final with exact format. | Zeynep starts with 131 test tubes.
After doubling: \(131 \times 2 = 262\).
After handing 120 to a customer: \(262 - 120 = 142\).
After receiving 28: \(142 + 28 = 170\).
After doubling again: \(170 \times 2 = 340\).
ANSWER: 340 | 340 | true | true | stop | 119 | 177 | 1.27 | v3 | 16,000 | 1 | 5 |
fc5d6c28aca127b81d57 | 7b7140f05508d5e226b1 | 7b7140f05508d5e226b1 | train | pareto_5efforts | inventory_word_problem | 1 | concise | -1 | false | 50,000 | Zeynep starts with 131 test tubes. Then, in order, Zeynep doubles the stock; then hands 120 to a customer; then receives a delivery of 28; then doubles the stock. How many test tubes does Zeynep have at the end?
Final line: `ANSWER: <answer>`. | Zeynep starts with 131 test tubes. Then, in order, Zeynep doubles the stock; then hands 120 to a customer; then receives a delivery of 28; then doubles the stock. How many test tubes does Zeynep have at the end? | 340 | integer | state_simulation | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | medium | 0.7 | 0.99 | We need answer simple arithmetic. Need be careful order. Starts 131. doubles stock: 262. hands 120 to customer: 142. receives delivery 28: 170. doubles stock: 340. Final 340. Need final line exactly. Could include reasoning. Ensure no issue "stock" test tubes. Answer 340. | Zeynep starts with 131 test tubes.
- Double: \(131 \times 2 = 262\)
- Hand 120 to customer: \(262 - 120 = 142\)
- Receive 28: \(142 + 28 = 170\)
- Double: \(170 \times 2 = 340\)
ANSWER: 340 | 340 | true | true | stop | 120 | 199 | 1.46 | v3 | 16,000 | 1 | 5 |
fc5d6c28aca127b81d57 | 7b7140f05508d5e226b1 | 7b7140f05508d5e226b1 | train | pareto_5efforts | inventory_word_problem | 1 | concise | -1 | false | 50,000 | Zeynep starts with 131 test tubes. Then, in order, Zeynep doubles the stock; then hands 120 to a customer; then receives a delivery of 28; then doubles the stock. How many test tubes does Zeynep have at the end?
Final line: `ANSWER: <answer>`. | Zeynep starts with 131 test tubes. Then, in order, Zeynep doubles the stock; then hands 120 to a customer; then receives a delivery of 28; then doubles the stock. How many test tubes does Zeynep have at the end? | 340 | integer | state_simulation | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | high | 0.7 | 0.99 | We need solve simple arithmetic. Need be careful order. Starts 131. Then in order: doubles stock; hands 120 to customer; receives delivery 28; doubles stock. Compute: 131*2=262; -120=142; +28=170; *2=340. Final answer 340. Need final line. | Start with 131.
1. Double: \(131 \times 2 = 262\)
2. Hand 120 to customer: \(262 - 120 = 142\)
3. Receive 28: \(142 + 28 = 170\)
4. Double: \(170 \times 2 = 340\)
ANSWER: 340 | 340 | true | true | stop | 121 | 199 | 1 | v3 | 16,000 | 1 | 5 |
fc5d6c28aca127b81d57 | 7b7140f05508d5e226b1 | 7b7140f05508d5e226b1 | train | pareto_5efforts | inventory_word_problem | 1 | concise | -1 | false | 50,000 | Zeynep starts with 131 test tubes. Then, in order, Zeynep doubles the stock; then hands 120 to a customer; then receives a delivery of 28; then doubles the stock. How many test tubes does Zeynep have at the end?
Final line: `ANSWER: <answer>`. | Zeynep starts with 131 test tubes. Then, in order, Zeynep doubles the stock; then hands 120 to a customer; then receives a delivery of 28; then doubles the stock. How many test tubes does Zeynep have at the end? | 340 | integer | state_simulation | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | xhigh | 0.7 | 0.99 | We need solve simple arithmetic. Need final answer. Let's compute carefully.
Start 131.
Doubles stock: 262.
Hands 120 to customer: 142.
Receives delivery 28: 170.
Doubles stock: 340.
Answer 340. Need final with ANSWER: 340. | ANSWER: 340 | 340 | true | true | stop | 121 | 99 | 0.61 | v3 | 16,000 | 1 | 5 |
fc5d6c28aca127b81d57 | 7b7140f05508d5e226b1 | 7b7140f05508d5e226b1 | train | pareto_5efforts | inventory_word_problem | 1 | concise | -1 | false | 50,000 | Zeynep starts with 131 test tubes. Then, in order, Zeynep doubles the stock; then hands 120 to a customer; then receives a delivery of 28; then doubles the stock. How many test tubes does Zeynep have at the end?
Final line: `ANSWER: <answer>`. | Zeynep starts with 131 test tubes. Then, in order, Zeynep doubles the stock; then hands 120 to a customer; then receives a delivery of 28; then doubles the stock. How many test tubes does Zeynep have at the end? | 340 | integer | state_simulation | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | max | 0.7 | 0.99 | We need solve simple arithmetic. Need final answer. Let's compute: start 131. doubles: 262. hands 120: 142. receives 28: 170. doubles: 340. Answer 340. Need final line exactly. Could include reasoning. Ensure no trick? "doubles the stock" maybe doubles stock then hands? In order yes. final. | Zeynep starts with 131 test tubes.
- Double: \(131 \times 2 = 262\)
- Hand off 120: \(262 - 120 = 142\)
- Receive 28: \(142 + 28 = 170\)
- Double: \(170 \times 2 = 340\)
ANSWER: 340 | 340 | true | true | stop | 121 | 203 | 1.19 | v3 | 16,000 | 1 | 5 |
3c7a5c4cc967455ddebf | 905d6d14a09c3edf9b23 | 905d6d14a09c3edf9b23 | train | pareto_5efforts | code_tracing | 1 | concise | -1 | false | 50,000 | What does this Python program print?
```python
x, y = 8, 3
for i in range(12):
if i % 2 == 0:
x += y * 8
else:
y += x - 3
x %= 11; y %= 11
print(x + y)
```
Final line: `ANSWER: <answer>`. | What does this Python program print?
```python
x, y = 8, 3
for i in range(12):
if i % 2 == 0:
x += y * 8
else:
y += x - 3
x %= 11; y %= 11
print(x + y)
``` | 11 | integer | code_execution | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | low | 0.7 | 0.99 | Simulate carefully.
x=8,y=3.
i=0 even: x += y*8 = 8+24=32; mod11: 32%11=10. y unchanged 3. then x%=11 (done), y%=11 (3).
i=1 odd: y += x-3 = 3 + (10-3)=10; mod? after branch x%=11? code: else y += x-3; then x %=11; y%=11. x=10%11=10; y=10%11=10.
i=2 even: x += y*8 =10+80=90; %11=2 (88). y=10. then x%=11 =>2, y%=11=>10... | ANSWER: 11 | 11 | true | true | stop | 132 | 546 | 1.77 | v3 | 16,000 | 1 | 5 |
3c7a5c4cc967455ddebf | 905d6d14a09c3edf9b23 | 905d6d14a09c3edf9b23 | train | pareto_5efforts | code_tracing | 1 | concise | -1 | false | 50,000 | What does this Python program print?
```python
x, y = 8, 3
for i in range(12):
if i % 2 == 0:
x += y * 8
else:
y += x - 3
x %= 11; y %= 11
print(x + y)
```
Final line: `ANSWER: <answer>`. | What does this Python program print?
```python
x, y = 8, 3
for i in range(12):
if i % 2 == 0:
x += y * 8
else:
y += x - 3
x %= 11; y %= 11
print(x + y)
``` | 11 | integer | code_execution | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | medium | 0.7 | 0.99 | We need answer question. Need compute. Let's carefully simulate.
Initial x=8,y=3. Loop i 0..11.
At each: if i even: x += y*8 else y += x-3. Then x %=11; y %=11.
Need final x+y.
Let's simulate manually or mentally. Use modular arithmetic maybe.
Let's table.
i=0 even:
x = 8 + 3*8 = 8+24=32. mod11 = 32%11=10 (since 22... | The program alternates between updating `x` and `y`, reducing both modulo 11 each iteration. Tracing through the 12 iterations gives a final state of `x = 8`, `y = 3`, so `x + y = 11`.
ANSWER: 11 | 11 | true | true | stop | 133 | 790 | 3.08 | v3 | 16,000 | 1 | 5 |
3c7a5c4cc967455ddebf | 905d6d14a09c3edf9b23 | 905d6d14a09c3edf9b23 | train | pareto_5efforts | code_tracing | 1 | concise | -1 | false | 50,000 | What does this Python program print?
```python
x, y = 8, 3
for i in range(12):
if i % 2 == 0:
x += y * 8
else:
y += x - 3
x %= 11; y %= 11
print(x + y)
```
Final line: `ANSWER: <answer>`. | What does this Python program print?
```python
x, y = 8, 3
for i in range(12):
if i % 2 == 0:
x += y * 8
else:
y += x - 3
x %= 11; y %= 11
print(x + y)
``` | 11 | integer | code_execution | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | high | 0.7 | 0.99 | We need answer problem. Need compute program output. Need final line ANSWER: <answer>. Let's simulate carefully.
Python:
x, y = 8, 3
for i in range(12):
if i % 2 == 0:
x += y * 8
else:
y += x - 3
x %= 11; y %= 11
print(x + y)
Need compute. Let's simulate step by step. Need be careful order... | The program prints `11`.
ANSWER: 11 | 11 | true | true | stop | 134 | 740 | 1.71 | v3 | 16,000 | 1 | 5 |
3c7a5c4cc967455ddebf | 905d6d14a09c3edf9b23 | 905d6d14a09c3edf9b23 | train | pareto_5efforts | code_tracing | 1 | concise | -1 | false | 50,000 | What does this Python program print?
```python
x, y = 8, 3
for i in range(12):
if i % 2 == 0:
x += y * 8
else:
y += x - 3
x %= 11; y %= 11
print(x + y)
```
Final line: `ANSWER: <answer>`. | What does this Python program print?
```python
x, y = 8, 3
for i in range(12):
if i % 2 == 0:
x += y * 8
else:
y += x - 3
x %= 11; y %= 11
print(x + y)
``` | 11 | integer | code_execution | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | xhigh | 0.7 | 0.99 | We need answer Python program print. Need compute. Let's analyze carefully. Need final with answer. Let's simulate.
x=8,y=3. Loop i 0..11. If i even: x += y*8. else: y += x - 3. Then x %=11; y %=11. Print x+y.
Let's compute step by step. Need careful modulo after update.
Initial x=8,y=3.
i=0 even: x += y*8 = 8+24=3... | ANSWER: 11 | 11 | true | true | stop | 134 | 718 | 2.23 | v3 | 16,000 | 1 | 5 |
3c7a5c4cc967455ddebf | 905d6d14a09c3edf9b23 | 905d6d14a09c3edf9b23 | train | pareto_5efforts | code_tracing | 1 | concise | -1 | false | 50,000 | What does this Python program print?
```python
x, y = 8, 3
for i in range(12):
if i % 2 == 0:
x += y * 8
else:
y += x - 3
x %= 11; y %= 11
print(x + y)
```
Final line: `ANSWER: <answer>`. | What does this Python program print?
```python
x, y = 8, 3
for i in range(12):
if i % 2 == 0:
x += y * 8
else:
y += x - 3
x %= 11; y %= 11
print(x + y)
``` | 11 | integer | code_execution | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | max | 0.7 | 0.99 | We need answer Python program output. Need compute. Let's simulate carefully. x,y=8,3. loop i 0..11. if i even: x += y*8; else y += x-3; then x%=11; y%=11. Need final x+y. Let's compute.
Let's do manually or reason. I'll simulate table.
Initial x=8,y=3.
i=0 even: x = 8 + 3*8 = 8+24=32; x%11=10 (32 mod11=10). y uncha... | The program ends with `x = 8` and `y = 3`, so `x + y = 11`.
ANSWER: 11 | 11 | true | true | stop | 134 | 643 | 2.53 | v3 | 16,000 | 1 | 5 |
049255fc68ea76a4cc16 | a3dcb71554b5c3f6cb28 | a3dcb71554b5c3f6cb28 | train | pareto_5efforts | combinatorics_count | 1 | concise | -1 | false | 50,000 | How many ordered sequences of 5 integers, each between 1 and 3 inclusive, have a sum of exactly 14?
Final line: `ANSWER: <answer>`. | How many ordered sequences of 5 integers, each between 1 and 3 inclusive, have a sum of exactly 14? | 5 | integer | dynamic_programming | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | low | 0.7 | 0.99 | We need number of ordered 5-tuples (x1..x5) with each in {1,2,3} sum=14. Let yi=xi-1 in {0,1,2}, sum yi = 14-5=9. Count solutions yi∈{0,1,2} sum 9, max possible 10. Equivalent count of 5 variables each 0-2 summing 9.
Total without upper bound: C(9+4,4)=C(13,4)=715? Actually nonnegative sum 9: C(13,4)=715. Subtract tho... | ANSWER: 5 | 5 | true | true | stop | 82 | 360 | 1.52 | v3 | 16,000 | 1 | 5 |
049255fc68ea76a4cc16 | a3dcb71554b5c3f6cb28 | a3dcb71554b5c3f6cb28 | train | pareto_5efforts | combinatorics_count | 1 | concise | -1 | false | 50,000 | How many ordered sequences of 5 integers, each between 1 and 3 inclusive, have a sum of exactly 14?
Final line: `ANSWER: <answer>`. | How many ordered sequences of 5 integers, each between 1 and 3 inclusive, have a sum of exactly 14? | 5 | integer | dynamic_programming | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | medium | 0.7 | 0.99 | We need solve combinatorics. Need count ordered sequences (x1..x5) with each xi in {1,2,3}, sum 14. Need final answer.
Compute. Let yi = xi -1 in {0,1,2}, sum yi = 14 -5 =9. Need number of 5-tuples yi in [0,2] summing 9. Max sum 10. Count. Could use inclusion-exclusion. Total nonnegative solutions to sum yi=9 without ... | We need count 5-tuples \((x_1,\dots,x_5)\) with \(x_i\in\{1,2,3\}\) and sum 14.
Let \(y_i=x_i-1\), so \(y_i\in\{0,1,2\}\) and
\[
\sum y_i = 14-5=9.
\]
The maximum possible sum of the \(y_i\)'s is \(5\cdot 2=10\). Thus a sum of 9 means the total "deficit" from 2 is \(10-9=1\). Equivalently, if \(d_i=2-y_i\), then \(d... | 5 | true | true | stop | 83 | 863 | 2.8 | v3 | 16,000 | 1 | 5 |
049255fc68ea76a4cc16 | a3dcb71554b5c3f6cb28 | a3dcb71554b5c3f6cb28 | train | pareto_5efforts | combinatorics_count | 1 | concise | -1 | false | 50,000 | How many ordered sequences of 5 integers, each between 1 and 3 inclusive, have a sum of exactly 14?
Final line: `ANSWER: <answer>`. | How many ordered sequences of 5 integers, each between 1 and 3 inclusive, have a sum of exactly 14? | 5 | integer | dynamic_programming | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | high | 0.7 | 0.99 | We need solve combinatorics. Need count ordered 5-tuples (a1..a5) each in {1,2,3} sum 14. Need final answer with line. Let's compute carefully.
We can transform xi in {1,2,3}, sum 14. Let yi=xi-1 in {0,1,2}, sum = 14-5=9, with each yi <=2. Count nonnegative solutions y1..y5 <=2 sum 9. Max sum if all 2 =10. Count total... | We need ordered 5-tuples \((a_1,\dots,a_5)\) with each \(a_i\in\{1,2,3\}\) and sum \(14\).
The maximum possible sum is \(5\cdot 3=15\). Let \(d_i=3-a_i\), so each \(d_i\in\{0,1,2\}\) and
\[
\sum d_i = 15-14 = 1.
\]
Thus exactly one of the \(d_i\) equals \(1\) and the rest are \(0\). There are \(5\) choices for which... | 5 | true | true | stop | 84 | 712 | 3.96 | v3 | 16,000 | 1 | 5 |
049255fc68ea76a4cc16 | a3dcb71554b5c3f6cb28 | a3dcb71554b5c3f6cb28 | train | pareto_5efforts | combinatorics_count | 1 | concise | -1 | false | 50,000 | How many ordered sequences of 5 integers, each between 1 and 3 inclusive, have a sum of exactly 14?
Final line: `ANSWER: <answer>`. | How many ordered sequences of 5 integers, each between 1 and 3 inclusive, have a sum of exactly 14? | 5 | integer | dynamic_programming | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | xhigh | 0.7 | 0.99 | We need answer combinatorics. Need final line ANSWER. Need solve. Count ordered 5-tuples (x_i in {1,2,3}) sum 14. Let's compute. Max sum 15, min 5. Need count. Let y_i = x_i-1 in {0,1,2}, sum y = 14-5=9. Count nonnegative y_i <=2 sum 9 over 5. Max sum if all 2 =10, so deficit from 10: z_i = 2-y_i in {0,1,2}, sum z = 10... | We need count ordered 5-tuples of values in {1,2,3} summing to 14.
Shift by 1: let \(y_i=x_i-1\in\{0,1,2\}\). Then sum \(y_i=14-5=9\).
Since max sum of five \(y_i\) is 10, let \(z_i=2-y_i\in\{0,1,2\}\). Then sum \(z_i=10-9=1\).
There are 5 choices for which one \(z_i\) equals 1, so 5 sequences.
ANSWER: 5 | 5 | true | true | stop | 84 | 329 | 1.55 | v3 | 16,000 | 1 | 5 |
049255fc68ea76a4cc16 | a3dcb71554b5c3f6cb28 | a3dcb71554b5c3f6cb28 | train | pareto_5efforts | combinatorics_count | 1 | concise | -1 | false | 50,000 | How many ordered sequences of 5 integers, each between 1 and 3 inclusive, have a sum of exactly 14?
Final line: `ANSWER: <answer>`. | How many ordered sequences of 5 integers, each between 1 and 3 inclusive, have a sum of exactly 14? | 5 | integer | dynamic_programming | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | max | 0.7 | 0.99 | We need solve combinatorics. Need count ordered 5-tuples (a1..a5) with each in {1,2,3}, sum 14. Need final answer. Need be careful. Let's compute.
Let xi in {1,2,3}. Sum 14. Max sum 15 (all 3). Min 5. Deficit from all 3: let di = 3 - ai ∈ {0,1,2}. Sum di = 15-14=1. Count ordered 5-tuples di in {0,1,2} summing 1. Each ... | We need count ordered 5-tuples with entries in {1,2,3} summing to 14.
Write each entry as \(3-d_i\), where \(d_i\in\{0,1,2\}\). Then
\[
\sum (3-d_i)=15-\sum d_i=14
\]
so
\[
\sum d_i=1.
\]
Thus exactly one \(d_i=1\) and the rest are 0. There are 5 choices for which position has the 2 (since \(3-1=2\)).
ANSWER: 5 | 5 | true | true | stop | 84 | 418 | 2.45 | v3 | 16,000 | 1 | 5 |
e1d8586fe5c89c402b2e | c0c27e17b77943062a88 | c0c27e17b77943062a88 | train | pareto_5efforts | modular_arithmetic | 1 | concise | -1 | false | 50,000 | What is the remainder when 18^470 is divided by 100?
Final line: `ANSWER: <answer>`. | What is the remainder when 18^470 is divided by 100? | 24 | integer | python_pow_mod | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | low | 0.7 | 0.99 | We need remainder 18^470 mod 100. Compute. Need final. Let's solve carefully.
We need mod 100. φ(100)=40. gcd(18,100)=2 not coprime, can't directly Euler. Use CRT: mod 4 and mod 25.
18^470 mod 4: 18≡2 mod4. 2^2=0 mod4 for exponent>=2, so 0 mod4.
mod 25: 18≡ -7. gcd(18,25)=1. φ(25)=20. 470 mod20 = 10? 20*23=460, rema... | ANSWER: 24 | 24 | true | true | stop | 75 | 364 | 1.17 | v3 | 16,000 | 1 | 5 |
e1d8586fe5c89c402b2e | c0c27e17b77943062a88 | c0c27e17b77943062a88 | train | pareto_5efforts | modular_arithmetic | 1 | concise | -1 | false | 50,000 | What is the remainder when 18^470 is divided by 100?
Final line: `ANSWER: <answer>`. | What is the remainder when 18^470 is divided by 100? | 24 | integer | python_pow_mod | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | medium | 0.7 | 0.99 | We need answer compute 18^470 mod 100. Need final with reasoning. Let's solve.
Compute 18^470 mod 100. Since gcd(18,100)=2 not coprime. Need careful. We can use CRT or pattern.
Mod 4 and mod 25 then combine.
18^470 mod 4: 18≡2 mod4, 2^? For exponent>=2, 2^n ≡0 mod4. 470>=2 so 0 mod4.
Mod 25: gcd(18,25)=1. φ(25)=20.... | We need \(18^{470} \bmod 100\).
Use CRT:
- Mod \(4\): \(18\equiv 2\), and \(2^{470}\equiv 0 \pmod 4\) since \(470\ge 2\).
- Mod \(25\): \(\phi(25)=20\), so \(470\equiv 10 \pmod{20}\). Thus
\[
18^{470}\equiv 18^{10}\equiv (-7)^{10}=7^{10} \pmod{25}.
\]
Since \(7^2=49\equiv -1 \pmod{25}\), we get \(7^{10}=(7^2)... | 24 | true | true | stop | 76 | 823 | 2.7 | v3 | 16,000 | 1 | 5 |
e1d8586fe5c89c402b2e | c0c27e17b77943062a88 | c0c27e17b77943062a88 | train | pareto_5efforts | modular_arithmetic | 1 | concise | -1 | false | 50,000 | What is the remainder when 18^470 is divided by 100?
Final line: `ANSWER: <answer>`. | What is the remainder when 18^470 is divided by 100? | 24 | integer | python_pow_mod | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | high | 0.7 | 0.99 | We need solve 18^470 mod 100. Need final answer with boxed? User says final line ANSWER: <answer>. Need compute. Let's solve carefully.
We need remainder of 18^470 mod 100.
Compute using modular arithmetic. gcd(18,100)=2 not coprime. Need handle powers.
18^1=18 mod100
18^2=324 mod100=24
18^3=24*18=432 mod100=32
18^4... | The remainder is found by noting the repeating cycle of powers of 18 modulo 100:
\[
18^2\equiv 24,\ 18^3\equiv 32,\ 18^4\equiv 76,\ 18^5\equiv 68,\ 18^6\equiv 24,\dots
\]
For \(n\ge 2\), the values repeat every 4 powers. Since
\[
470 \equiv 2 \pmod 4,
\]
we have
\[
18^{470}\equiv 18^2\equiv 24 \pmod{100}.
\]
ANSW... | 24 | true | true | stop | 77 | 1,018 | 2.81 | v3 | 16,000 | 1 | 5 |
e1d8586fe5c89c402b2e | c0c27e17b77943062a88 | c0c27e17b77943062a88 | train | pareto_5efforts | modular_arithmetic | 1 | concise | -1 | false | 50,000 | What is the remainder when 18^470 is divided by 100?
Final line: `ANSWER: <answer>`. | What is the remainder when 18^470 is divided by 100? | 24 | integer | python_pow_mod | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | xhigh | 0.7 | 0.99 | We need answer problem: remainder 18^470 mod 100. Need final with ANSWER: 76? Let's compute carefully.
Need compute 18^470 mod 100. Let's solve.
phi(100)=40, gcd(18,100)=2 not coprime so Euler not directly. Use CRT mod4 and mod25.
Mod4: 18 ≡2. 18^470 mod4 = 2^470 mod4 =0 for exponent>=2. So remainder ≡0 mod4.
Mod25... | ANSWER: 24 | 24 | true | true | stop | 77 | 718 | 2.54 | v3 | 16,000 | 1 | 5 |
e1d8586fe5c89c402b2e | c0c27e17b77943062a88 | c0c27e17b77943062a88 | train | pareto_5efforts | modular_arithmetic | 1 | concise | -1 | false | 50,000 | What is the remainder when 18^470 is divided by 100?
Final line: `ANSWER: <answer>`. | What is the remainder when 18^470 is divided by 100? | 24 | integer | python_pow_mod | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | max | 0.7 | 0.99 | We need solve 18^470 mod 100. Need final with reasoning and answer. Need be careful. Compute. We can use Carmichael/euler. Let's solve.
18^470 mod 100. Since gcd(18,100)=2 not coprime. Need handle.
Compute powers mod 100. Let's do carefully.
18^1=18
18^2=324 mod100=24
18^3=24*18=432 mod100=32
18^4=32*18=576 mod100=7... | We need compute \(18^{470} \pmod{100}\).
Using the Chinese Remainder Theorem:
- Modulo \(4\): \(18\equiv 2\), and \(2^{470}\equiv 0 \pmod{4}\) since \(470\ge 2\).
- Modulo \(25\): \(\phi(25)=20\), and \(470\equiv 10 \pmod{20}\). Thus
\[
18^{470}\equiv 18^{10}\pmod{25}.
\]
Since \(18\equiv -7\pmod{25}\),
\[
... | 24 | true | true | stop | 77 | 1,015 | 3.16 | v3 | 16,000 | 1 | 5 |
478d32589368cb667381 | 8163f17fa95543df56ec | 8163f17fa95543df56ec | train | pareto_5efforts | shortest_path | 1 | concise | -1 | false | 50,000 | An undirected road network has these roads (with lengths):
- B–C: 3
- A–E: 6
- A–B: 11
- D–C: 1
- A–D: 3
- C–F: 8
- B–D: 4
What is the length of the shortest route from A to F?
Final line: `ANSWER: <answer>`. | An undirected road network has these roads (with lengths):
- B–C: 3
- A–E: 6
- A–B: 11
- D–C: 1
- A–D: 3
- C–F: 8
- B–D: 4
What is the length of the shortest route from A to F? | 12 | integer | dijkstra | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | low | 0.7 | 0.99 | We need shortest path A to F in undirected weighted graph. Nodes: A,B,C,D,E,F. Edges: B-C 3, A-E 6, A-B 11, D-C 1, A-D 3, C-F 8, B-D 4. Need shortest A to F. Let's compute. Edges from A: E 6, B 11, D 3. Need reach F via C likely. Paths: A-D (3) - C (1) - F (8) =12. A-D-B? etc. A-D-B 3+4=7, B-C 3 =>10, +8=18. A-B 11 +..... | ANSWER: 12 | 12 | true | true | stop | 137 | 191 | 1.03 | v3 | 16,000 | 1 | 5 |
478d32589368cb667381 | 8163f17fa95543df56ec | 8163f17fa95543df56ec | train | pareto_5efforts | shortest_path | 1 | concise | -1 | false | 50,000 | An undirected road network has these roads (with lengths):
- B–C: 3
- A–E: 6
- A–B: 11
- D–C: 1
- A–D: 3
- C–F: 8
- B–D: 4
What is the length of the shortest route from A to F?
Final line: `ANSWER: <answer>`. | An undirected road network has these roads (with lengths):
- B–C: 3
- A–E: 6
- A–B: 11
- D–C: 1
- A–D: 3
- C–F: 8
- B–D: 4
What is the length of the shortest route from A to F? | 12 | integer | dijkstra | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | medium | 0.7 | 0.99 | We need solve shortest path. Need final answer. Let's compute.
Graph undirected weighted.
Edges:
B-C 3
A-E 6
A-B 11
D-C 1
A-D 3
C-F 8
B-D 4
Need shortest A to F.
Let's list adjacency:
A: E(6), B(11), D(3)
B: C(3), A(11), D(4)
C: B(3), D(1), F(8)
D: C(1), A(3), B(4)
E: A(6)
F: C(8)
Dijkstra from A:
dist A=0.
Neighbo... | The shortest path from A to F is A–D–C–F, with length \(3 + 1 + 8 = 12\).
ANSWER: 12 | 12 | true | true | stop | 138 | 365 | 1.68 | v3 | 16,000 | 1 | 5 |
478d32589368cb667381 | 8163f17fa95543df56ec | 8163f17fa95543df56ec | train | pareto_5efforts | shortest_path | 1 | concise | -1 | false | 50,000 | An undirected road network has these roads (with lengths):
- B–C: 3
- A–E: 6
- A–B: 11
- D–C: 1
- A–D: 3
- C–F: 8
- B–D: 4
What is the length of the shortest route from A to F?
Final line: `ANSWER: <answer>`. | An undirected road network has these roads (with lengths):
- B–C: 3
- A–E: 6
- A–B: 11
- D–C: 1
- A–D: 3
- C–F: 8
- B–D: 4
What is the length of the shortest route from A to F? | 12 | integer | dijkstra | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | high | 0.7 | 0.99 | We need solve shortest path. Need final answer. Need maybe include reasoning. Let's compute.
Graph undirected weighted:
Nodes A,B,C,D,E,F.
Edges:
B-C 3
A-E 6
A-B 11
D-C 1
A-D 3
C-F 8
B-D 4
Need shortest A to F. Paths:
A-D-C-F: 3+1+8=12.
A-B? A-B 11, B-D 4, D-C1, C-F8 =24; B-C3 C-F8 + A-B11=22.
A-E no connection to F?... | The shortest route is A → D → C → F, with total length 3 + 1 + 8 = 12.
ANSWER: 12 | 12 | true | true | stop | 139 | 235 | 1.4 | v3 | 16,000 | 1 | 5 |
478d32589368cb667381 | 8163f17fa95543df56ec | 8163f17fa95543df56ec | train | pareto_5efforts | shortest_path | 1 | concise | -1 | false | 50,000 | An undirected road network has these roads (with lengths):
- B–C: 3
- A–E: 6
- A–B: 11
- D–C: 1
- A–D: 3
- C–F: 8
- B–D: 4
What is the length of the shortest route from A to F?
Final line: `ANSWER: <answer>`. | An undirected road network has these roads (with lengths):
- B–C: 3
- A–E: 6
- A–B: 11
- D–C: 1
- A–D: 3
- C–F: 8
- B–D: 4
What is the length of the shortest route from A to F? | 12 | integer | dijkstra | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | xhigh | 0.7 | 0.99 | We need solve shortest path. Need output final answer line. Let's compute.
Graph undirected edges:
B-C 3
A-E 6
A-B 11
D-C 1
A-D 3
C-F 8
B-D 4
Nodes A,B,C,D,E,F. Need shortest A to F.
Edges:
A-D 3, D-C 1 => A-C 4. C-F 8 => 12.
A-D 3, D-B 4 => A-B 7? Actually A-D-B =7, vs A-B 11. Then B-C 3 => A-C via D-B-C =10? D-B-C... | The shortest route from A to F is A → D → C → F, with length 3 + 1 + 8 = 12.
ANSWER: 12 | 12 | true | true | stop | 139 | 293 | 1.35 | v3 | 16,000 | 1 | 5 |
478d32589368cb667381 | 8163f17fa95543df56ec | 8163f17fa95543df56ec | train | pareto_5efforts | shortest_path | 1 | concise | -1 | false | 50,000 | An undirected road network has these roads (with lengths):
- B–C: 3
- A–E: 6
- A–B: 11
- D–C: 1
- A–D: 3
- C–F: 8
- B–D: 4
What is the length of the shortest route from A to F?
Final line: `ANSWER: <answer>`. | An undirected road network has these roads (with lengths):
- B–C: 3
- A–E: 6
- A–B: 11
- D–C: 1
- A–D: 3
- C–F: 8
- B–D: 4
What is the length of the shortest route from A to F? | 12 | integer | dijkstra | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | max | 0.7 | 0.99 | We need solve shortest path. Need provide reasoning. Graph undirected weighted. Vertices A,B,C,D,E,F. Edges: B-C 3, A-E 6, A-B 11, D-C 1, A-D 3, C-F 8, B-D 4. Need shortest A to F.
Compute. A to D =3, D-C=1 => A-D-C =4, C-F=8 =>12. A-B? A-D-B=3+4=7 (vs 11), then B-C=3 =>10, +8=18. A-E dead end? E only A. So 12. Need f... | The shortest route is A → D → C → F, with length 3 + 1 + 8 = 12.
ANSWER: 12 | 12 | true | true | stop | 139 | 206 | 1.84 | v3 | 16,000 | 1 | 5 |
b02e316dddd1d3381085 | f51ef3075ca483061623 | f51ef3075ca483061623 | train | pareto_5efforts | probability | 1 | concise | -1 | false | 50,000 | A bag has 7 red, 5 blue marbles. You draw 4 marbles without replacement. What is the probability that at least 4 of them are red? Give the answer as a reduced fraction p/q.
Final line: `ANSWER: <answer>`. | A bag has 7 red, 5 blue marbles. You draw 4 marbles without replacement. What is the probability that at least 4 of them are red? Give the answer as a reduced fraction p/q. | 7/99 | reduced_fraction | exact_fractions_hypergeometric | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | low | 0.7 | 0.99 | We draw 4 marbles from 12 total (7 red, 5 blue). Need probability at least 4 red among the 4 drawn, i.e., all 4 red.
Number of ways: C(7,4)/C(12,4). C(7,4)=35. C(12,4)=495. Reduced: 35/495 = 7/99. | We draw 4 marbles from 12 total. "At least 4 red" means all 4 drawn are red.
\[
P = \frac{\binom{7}{4}}{\binom{12}{4}} = \frac{35}{495} = \frac{7}{99}
\]
ANSWER: 7/99 | 7/99 | true | true | stop | 101 | 183 | 7.29 | v3 | 16,000 | 1 | 5 |
b02e316dddd1d3381085 | f51ef3075ca483061623 | f51ef3075ca483061623 | train | pareto_5efforts | probability | 1 | concise | -1 | false | 50,000 | A bag has 7 red, 5 blue marbles. You draw 4 marbles without replacement. What is the probability that at least 4 of them are red? Give the answer as a reduced fraction p/q.
Final line: `ANSWER: <answer>`. | A bag has 7 red, 5 blue marbles. You draw 4 marbles without replacement. What is the probability that at least 4 of them are red? Give the answer as a reduced fraction p/q. | 7/99 | reduced_fraction | exact_fractions_hypergeometric | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | medium | 0.7 | 0.99 | We need solve probability. Need parse: bag 7 red, 5 blue total 12. Draw 4 marbles without replacement. Probability that at least 4 of them are red? Since draw 4, "at least 4 of them are red" means all 4 red. Need compute C(7,4)/C(12,4). Let's compute. C(7,4)=35. C(12,4)=495? 12*11*10*9/24 = 11880/24=495. Probability=35... | We draw 4 marbles total, so “at least 4 red” means all 4 are red.
Total ways to choose 4 from 12:
\[
\binom{12}{4}=495
\]
Ways to choose 4 red from 7:
\[
\binom{7}{4}=35
\]
Probability:
\[
\frac{35}{495}=\frac{7}{99}
\]
ANSWER: 7/99 | 7/99 | true | true | stop | 102 | 296 | 1.34 | v3 | 16,000 | 1 | 5 |
b02e316dddd1d3381085 | f51ef3075ca483061623 | f51ef3075ca483061623 | train | pareto_5efforts | probability | 1 | concise | -1 | false | 50,000 | A bag has 7 red, 5 blue marbles. You draw 4 marbles without replacement. What is the probability that at least 4 of them are red? Give the answer as a reduced fraction p/q.
Final line: `ANSWER: <answer>`. | A bag has 7 red, 5 blue marbles. You draw 4 marbles without replacement. What is the probability that at least 4 of them are red? Give the answer as a reduced fraction p/q. | 7/99 | reduced_fraction | exact_fractions_hypergeometric | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | high | 0.7 | 0.99 | We need answer probability. Need parse: Bag 7 red, 5 blue. Draw 4 without replacement. Probability that at least 4 of them are red. Since draw 4, at least 4 red means all 4 red. Compute C(7,4)/C(12,4). Need reduced fraction.
C(7,4)=35. C(12,4)=495? 12*11*10*9/24 = 11880/24=495. 35/495 = 7/99. Answer 7/99. Need final w... | We draw 4 marbles from 12 total. “At least 4 red” means all 4 drawn are red.
Number of favorable draws: \(\binom{7}{4}=35\).
Total draws: \(\binom{12}{4}=495\).
Probability:
\[
\frac{35}{495}=\frac{7}{99}.
\]
ANSWER: 7/99 | 7/99 | true | true | stop | 103 | 251 | 1.05 | v3 | 16,000 | 1 | 5 |
b02e316dddd1d3381085 | f51ef3075ca483061623 | f51ef3075ca483061623 | train | pareto_5efforts | probability | 1 | concise | -1 | false | 50,000 | A bag has 7 red, 5 blue marbles. You draw 4 marbles without replacement. What is the probability that at least 4 of them are red? Give the answer as a reduced fraction p/q.
Final line: `ANSWER: <answer>`. | A bag has 7 red, 5 blue marbles. You draw 4 marbles without replacement. What is the probability that at least 4 of them are red? Give the answer as a reduced fraction p/q. | 7/99 | reduced_fraction | exact_fractions_hypergeometric | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | xhigh | 0.7 | 0.99 | We need answer probability. Need parse: bag 7 red, 5 blue. Draw 4 without replacement. Probability that at least 4 of them are red. Since draw 4, "at least 4 red" means all 4 red. Compute hypergeometric. Total ways C(12,4). Red ways C(7,4). Probability = C(7,4)/C(12,4). C7,4=35. C12,4=495? 12*11*10*9/24 = 11880/24=495.... | ANSWER: 7/99 | 7/99 | true | true | stop | 103 | 182 | 0.93 | v3 | 16,000 | 1 | 5 |
b02e316dddd1d3381085 | f51ef3075ca483061623 | f51ef3075ca483061623 | train | pareto_5efforts | probability | 1 | concise | -1 | false | 50,000 | A bag has 7 red, 5 blue marbles. You draw 4 marbles without replacement. What is the probability that at least 4 of them are red? Give the answer as a reduced fraction p/q.
Final line: `ANSWER: <answer>`. | A bag has 7 red, 5 blue marbles. You draw 4 marbles without replacement. What is the probability that at least 4 of them are red? Give the answer as a reduced fraction p/q. | 7/99 | reduced_fraction | exact_fractions_hypergeometric | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | max | 0.7 | 0.99 | We need solve probability. Need final answer reduced fraction. Problem: bag 7 red, 5 blue total 12. Draw 4 without replacement. Probability at least 4 of them are red. Since draw 4, at least 4 red means all 4 red. Probability choose 4 red from 7 / choose 4 from 12. Compute C(7,4)/C(12,4). C7,4=35. C12,4=495? 12*11*10*9... | ANSWER: 7/99 | 7/99 | true | true | stop | 103 | 174 | 0.82 | v3 | 16,000 | 1 | 5 |
bdd50a70b925b8614ce2 | f1d1fae752eb48a22fc4 | f1d1fae752eb48a22fc4 | train | pareto_5efforts | knights_knaves | 1 | concise | -1 | false | 50,000 | Each person below is either a knight (always tells the truth) or a knave (always lies).
- Dalia says: "At least one of Oskar and Jonas is a knave."
- Oskar says: "Dalia is a knight."
- Jonas says: "Oskar and I are the same type."
- Nia says: "Jonas is a knight or Dalia is a knight."
Determine who is a knight. List the ... | Each person below is either a knight (always tells the truth) or a knave (always lies).
- Dalia says: "At least one of Oskar and Jonas is a knave."
- Oskar says: "Dalia is a knight."
- Jonas says: "Oskar and I are the same type."
- Nia says: "Jonas is a knight or Dalia is a knight."
Determine who is a knight. List the ... | Dalia, Nia, Oskar | comma_list_alphabetical_or_none | truth_table_enumeration | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | low | 0.7 | 0.99 | We need solve knights/knaves. Need determine all. Let's reason.
Let D,O,J,N boolean knight (true). Statements:
D says: "At least one of Oskar and Jonas is a knave." i.e. (O false or J false) = not (O and J). So D truthful iff (not O or not J).
O says: "Dalia is a knight." O truthful iff D.
J says: "Oskar and I are s... | ANSWER: Dalia, Nia, Oskar | Dalia, Nia, Oskar | true | true | stop | 170 | 400 | 1.77 | v3 | 16,000 | 1 | 5 |
bdd50a70b925b8614ce2 | f1d1fae752eb48a22fc4 | f1d1fae752eb48a22fc4 | train | pareto_5efforts | knights_knaves | 1 | concise | -1 | false | 50,000 | Each person below is either a knight (always tells the truth) or a knave (always lies).
- Dalia says: "At least one of Oskar and Jonas is a knave."
- Oskar says: "Dalia is a knight."
- Jonas says: "Oskar and I are the same type."
- Nia says: "Jonas is a knight or Dalia is a knight."
Determine who is a knight. List the ... | Each person below is either a knight (always tells the truth) or a knave (always lies).
- Dalia says: "At least one of Oskar and Jonas is a knave."
- Oskar says: "Dalia is a knight."
- Jonas says: "Oskar and I are the same type."
- Nia says: "Jonas is a knight or Dalia is a knight."
Determine who is a knight. List the ... | Dalia, Nia, Oskar | comma_list_alphabetical_or_none | truth_table_enumeration | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | medium | 0.7 | 0.99 | We need solve knights knaves. Need final answer. Let's analyze.
Variables D,O,J,N each K (knight truth) or V (knave lie). Statements:
D: "At least one of Oskar and Jonas is a knave." Equivalent (O is knave OR J is knave) i.e. not both knights. Truth value T iff (¬O_knight ∨ ¬J_knight) i.e. O or J false.
O: "Dalia is ... | The consistent assignment is:
- Dalia: knight
- Oskar: knight
- Jonas: knave
- Nia: knight
ANSWER: Dalia, Nia, Oskar | Dalia, Nia, Oskar | true | true | stop | 171 | 673 | 2.66 | v3 | 16,000 | 1 | 5 |
bdd50a70b925b8614ce2 | f1d1fae752eb48a22fc4 | f1d1fae752eb48a22fc4 | train | pareto_5efforts | knights_knaves | 1 | concise | -1 | false | 50,000 | Each person below is either a knight (always tells the truth) or a knave (always lies).
- Dalia says: "At least one of Oskar and Jonas is a knave."
- Oskar says: "Dalia is a knight."
- Jonas says: "Oskar and I are the same type."
- Nia says: "Jonas is a knight or Dalia is a knight."
Determine who is a knight. List the ... | Each person below is either a knight (always tells the truth) or a knave (always lies).
- Dalia says: "At least one of Oskar and Jonas is a knave."
- Oskar says: "Dalia is a knight."
- Jonas says: "Oskar and I are the same type."
- Nia says: "Jonas is a knight or Dalia is a knight."
Determine who is a knight. List the ... | Dalia, Nia, Oskar | comma_list_alphabetical_or_none | truth_table_enumeration | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | high | 0.7 | 0.99 | We need solve knights knaves. Need parse statements. Need determine all consistent assignments. Need list knights alphabetical. Need final line ANSWER: ...
Let's solve carefully.
People: Dalia, Oskar, Jonas, Nia. Each K (knight) or V (knave). Statements:
Dalia: "At least one of Oskar and Jonas is a knave." Equivalen... | Dalia says at least one of Oskar and Jonas is a knave. If Dalia were a knave, her statement would be false, forcing both Oskar and Jonas to be knights; but then Oskar’s claim “Dalia is a knight” would be false, contradicting Oskar being a knight. So Dalia is a knight. Thus Oskar is a knight, Jonas is a knave, and Nia’s... | Dalia, Nia, Oskar | true | true | stop | 172 | 832 | 3.18 | v3 | 16,000 | 1 | 5 |
bdd50a70b925b8614ce2 | f1d1fae752eb48a22fc4 | f1d1fae752eb48a22fc4 | train | pareto_5efforts | knights_knaves | 1 | concise | -1 | false | 50,000 | Each person below is either a knight (always tells the truth) or a knave (always lies).
- Dalia says: "At least one of Oskar and Jonas is a knave."
- Oskar says: "Dalia is a knight."
- Jonas says: "Oskar and I are the same type."
- Nia says: "Jonas is a knight or Dalia is a knight."
Determine who is a knight. List the ... | Each person below is either a knight (always tells the truth) or a knave (always lies).
- Dalia says: "At least one of Oskar and Jonas is a knave."
- Oskar says: "Dalia is a knight."
- Jonas says: "Oskar and I are the same type."
- Nia says: "Jonas is a knight or Dalia is a knight."
Determine who is a knight. List the ... | Dalia, Nia, Oskar | comma_list_alphabetical_or_none | truth_table_enumeration | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | xhigh | 0.7 | 0.99 | We need solve knights/knaves. Need final answer format. Need reason carefully. Let's parse.
People: Dalia, Oskar, Jonas, Nia. Each knight truth, knave lie.
Statements:
Dalia says: "At least one of Oskar and Jonas is a knave." i.e. ¬(O knight and J knight)? At least one knave among O,J means not both knights.
Oskar sa... | Dalia, Nia, and Oskar are knights; Jonas is a knave.
ANSWER: Dalia, Nia, Oskar | Dalia, Nia, Oskar | true | true | stop | 172 | 1,291 | 4.33 | v3 | 16,000 | 1 | 5 |
bdd50a70b925b8614ce2 | f1d1fae752eb48a22fc4 | f1d1fae752eb48a22fc4 | train | pareto_5efforts | knights_knaves | 1 | concise | -1 | false | 50,000 | Each person below is either a knight (always tells the truth) or a knave (always lies).
- Dalia says: "At least one of Oskar and Jonas is a knave."
- Oskar says: "Dalia is a knight."
- Jonas says: "Oskar and I are the same type."
- Nia says: "Jonas is a knight or Dalia is a knight."
Determine who is a knight. List the ... | Each person below is either a knight (always tells the truth) or a knave (always lies).
- Dalia says: "At least one of Oskar and Jonas is a knave."
- Oskar says: "Dalia is a knight."
- Jonas says: "Oskar and I are the same type."
- Nia says: "Jonas is a knight or Dalia is a knight."
Determine who is a knight. List the ... | Dalia, Nia, Oskar | comma_list_alphabetical_or_none | truth_table_enumeration | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | max | 0.7 | 0.99 | We need solve knights knaves. Need produce final answer line. Let's analyze carefully.
Persons: Dalia, Oskar, Jonas, Nia. Each knight/truth or knave/lie.
Statements:
D: "At least one of Oskar and Jonas is a knave." = (Oskar knave OR Jonas knave). Equiv not both knights.
O: "Dalia is a knight."
J: "Oskar and I are the... | ANSWER: Dalia, Nia, Oskar | Dalia, Nia, Oskar | true | true | stop | 172 | 621 | 2.65 | v3 | 16,000 | 1 | 5 |
4fba9525949d44176f44 | cf09b691011a7312bcb4 | cf09b691011a7312bcb4 | train | pareto_5efforts | meeting_slot | 1 | concise | -1 | false | 50,000 | Working hours are 09:00–17:00. A 90-minute meeting must start on a quarter hour (:00, :15, :30, :45) and fit entirely inside everyone's free time.
- Zeynep: busy 10:00–10:45, 15:15–16:00
- Keiko: busy 15:30–17:00
- Leila: busy 14:15–15:15
What is the earliest possible start time? Answer in HH:MM (24-hour) format.
Fina... | Working hours are 09:00–17:00. A 90-minute meeting must start on a quarter hour (:00, :15, :30, :45) and fit entirely inside everyone's free time.
- Zeynep: busy 10:00–10:45, 15:15–16:00
- Keiko: busy 15:30–17:00
- Leila: busy 14:15–15:15
What is the earliest possible start time? Answer in HH:MM (24-hour) format. | 10:45 | hh:mm_24h | interval_scan | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | low | 0.7 | 0.99 | We need solve scheduling. Need earliest start time for 90-min meeting, start on quarter hour, fit entirely inside everyone's free time within working hours 09:00-17:00. Need consider intersection of free times.
People busy:
Zeynep: 10:00-10:45, 15:15-16:00. Free: 09:00-10:00, 10:45-15:15, 16:00-17:00.
Keiko: busy 15:3... | ANSWER: 10:45 | 10:45 | true | true | stop | 197 | 666 | 2.49 | v3 | 16,000 | 1 | 5 |
4fba9525949d44176f44 | cf09b691011a7312bcb4 | cf09b691011a7312bcb4 | train | pareto_5efforts | meeting_slot | 1 | concise | -1 | false | 50,000 | Working hours are 09:00–17:00. A 90-minute meeting must start on a quarter hour (:00, :15, :30, :45) and fit entirely inside everyone's free time.
- Zeynep: busy 10:00–10:45, 15:15–16:00
- Keiko: busy 15:30–17:00
- Leila: busy 14:15–15:15
What is the earliest possible start time? Answer in HH:MM (24-hour) format.
Fina... | Working hours are 09:00–17:00. A 90-minute meeting must start on a quarter hour (:00, :15, :30, :45) and fit entirely inside everyone's free time.
- Zeynep: busy 10:00–10:45, 15:15–16:00
- Keiko: busy 15:30–17:00
- Leila: busy 14:15–15:15
What is the earliest possible start time? Answer in HH:MM (24-hour) format. | 10:45 | hh:mm_24h | interval_scan | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | medium | 0.7 | 0.99 | We need solve scheduling. Need earliest start time 90 min meeting quarter hour, within working hours 09:00-17:00, fit entirely inside everyone's free time. Need account free time = working hours minus busy intervals. Meeting start on quarter hour, duration 90 min. Need start S such that S >= 09:00, S+90 <=17:00, S and ... | The earliest valid start is 10:45.
ANSWER: 10:45 | 10:45 | true | true | stop | 198 | 1,018 | 3.24 | v3 | 16,000 | 1 | 5 |
4fba9525949d44176f44 | cf09b691011a7312bcb4 | cf09b691011a7312bcb4 | train | pareto_5efforts | meeting_slot | 1 | concise | -1 | false | 50,000 | Working hours are 09:00–17:00. A 90-minute meeting must start on a quarter hour (:00, :15, :30, :45) and fit entirely inside everyone's free time.
- Zeynep: busy 10:00–10:45, 15:15–16:00
- Keiko: busy 15:30–17:00
- Leila: busy 14:15–15:15
What is the earliest possible start time? Answer in HH:MM (24-hour) format.
Fina... | Working hours are 09:00–17:00. A 90-minute meeting must start on a quarter hour (:00, :15, :30, :45) and fit entirely inside everyone's free time.
- Zeynep: busy 10:00–10:45, 15:15–16:00
- Keiko: busy 15:30–17:00
- Leila: busy 14:15–15:15
What is the earliest possible start time? Answer in HH:MM (24-hour) format. | 10:45 | hh:mm_24h | interval_scan | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | high | 0.7 | 0.99 | We need solve scheduling. Need produce final with answer. Let's parse.
Working hours 09:00-17:00. Meeting 90 minutes must start on quarter hour and fit entirely inside everyone's free time. Need earliest possible start time.
Busy:
Zeynep: 10:00-10:45, 15:15-16:00
Keiko: 15:30-17:00
Leila: 14:15-15:15
Free time inter... | The common free intervals long enough for a 90-minute meeting start at 10:45.
ANSWER: 10:45 | 10:45 | true | true | stop | 199 | 788 | 2.48 | v3 | 16,000 | 1 | 5 |
4fba9525949d44176f44 | cf09b691011a7312bcb4 | cf09b691011a7312bcb4 | train | pareto_5efforts | meeting_slot | 1 | concise | -1 | false | 50,000 | Working hours are 09:00–17:00. A 90-minute meeting must start on a quarter hour (:00, :15, :30, :45) and fit entirely inside everyone's free time.
- Zeynep: busy 10:00–10:45, 15:15–16:00
- Keiko: busy 15:30–17:00
- Leila: busy 14:15–15:15
What is the earliest possible start time? Answer in HH:MM (24-hour) format.
Fina... | Working hours are 09:00–17:00. A 90-minute meeting must start on a quarter hour (:00, :15, :30, :45) and fit entirely inside everyone's free time.
- Zeynep: busy 10:00–10:45, 15:15–16:00
- Keiko: busy 15:30–17:00
- Leila: busy 14:15–15:15
What is the earliest possible start time? Answer in HH:MM (24-hour) format. | 10:45 | hh:mm_24h | interval_scan | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | xhigh | 0.7 | 0.99 | We need solve scheduling. Need parse. Working hours 09:00-17:00. Meeting 90 min must start quarter hour and fit entirely inside everyone's free time. Given busy intervals. Need earliest possible start time. Need consider all participants free. Free time within working hours excluding busy. Meeting 90 min continuous, st... | The common free intervals long enough for a 90-minute meeting start on a quarter hour are checked. The earliest valid start is 10:45, giving an end at 12:15, within all participants’ free time.
ANSWER: 10:45 | 10:45 | true | true | stop | 199 | 934 | 3.19 | v3 | 16,000 | 1 | 5 |
4fba9525949d44176f44 | cf09b691011a7312bcb4 | cf09b691011a7312bcb4 | train | pareto_5efforts | meeting_slot | 1 | concise | -1 | false | 50,000 | Working hours are 09:00–17:00. A 90-minute meeting must start on a quarter hour (:00, :15, :30, :45) and fit entirely inside everyone's free time.
- Zeynep: busy 10:00–10:45, 15:15–16:00
- Keiko: busy 15:30–17:00
- Leila: busy 14:15–15:15
What is the earliest possible start time? Answer in HH:MM (24-hour) format.
Fina... | Working hours are 09:00–17:00. A 90-minute meeting must start on a quarter hour (:00, :15, :30, :45) and fit entirely inside everyone's free time.
- Zeynep: busy 10:00–10:45, 15:15–16:00
- Keiko: busy 15:30–17:00
- Leila: busy 14:15–15:15
What is the earliest possible start time? Answer in HH:MM (24-hour) format. | 10:45 | hh:mm_24h | interval_scan | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | max | 0.7 | 0.99 | We need solve scheduling. Need parse problem. Working hours 09:00-17:00. Meeting 90 min must start on quarter hour and fit entirely inside everyone's free time. Need earliest possible start time. Free time = working hours minus busy intervals for each person. Meeting must fit in intersection of all free times? "fit ent... | The intersection of everyone's free time inside working hours is [09:00–10:00] and [10:45–14:15]. A 90-minute meeting cannot fit in the first interval, but can start at 10:45 in the second.
ANSWER: 10:45 | 10:45 | true | true | stop | 199 | 1,061 | 3.12 | v3 | 16,000 | 1 | 5 |
fff7be317a4e3f2dbaae | 33c141d2d8a4263ddacc | 33c141d2d8a4263ddacc | train | pareto_5efforts | venn_counting | 1 | concise | -1 | false | 50,000 | 104 students were surveyed. 40 joined chess. 43 joined drama. 51 joined robotics. 13 joined both chess and drama. 17 joined both chess and robotics. 17 joined both drama and robotics. 3 joined all three clubs. How many students joined exactly one of these clubs?
Final line: `ANSWER: <answer>`. | 104 students were surveyed. 40 joined chess. 43 joined drama. 51 joined robotics. 13 joined both chess and drama. 17 joined both chess and robotics. 17 joined both drama and robotics. 3 joined all three clubs. How many students joined exactly one of these clubs? | 49 | integer | set_enumeration | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | low | 0.7 | 0.99 | We need solve inclusion. Need final answer. Let's compute.
Total 104 surveyed. Sets C,D,R sizes 40,43,51. Pair intersections: C∩D=13, C∩R=17, D∩R=17. Triple=3.
Need exactly one club count.
Formula: exactly one = sum singles - 2*sum pair-only? Let's compute.
Number in at least one? Inclusion-exclusion: |C∪D∪R| = 40+... | ANSWER: 49 | 49 | true | true | stop | 124 | 482 | 2.16 | v3 | 16,000 | 0.8 | 5 |
fff7be317a4e3f2dbaae | 33c141d2d8a4263ddacc | 33c141d2d8a4263ddacc | train | pareto_5efforts | venn_counting | 1 | concise | -1 | false | 50,000 | 104 students were surveyed. 40 joined chess. 43 joined drama. 51 joined robotics. 13 joined both chess and drama. 17 joined both chess and robotics. 17 joined both drama and robotics. 3 joined all three clubs. How many students joined exactly one of these clubs?
Final line: `ANSWER: <answer>`. | 104 students were surveyed. 40 joined chess. 43 joined drama. 51 joined robotics. 13 joined both chess and drama. 17 joined both chess and robotics. 17 joined both drama and robotics. 3 joined all three clubs. How many students joined exactly one of these clubs? | 49 | integer | set_enumeration | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | medium | 0.7 | 0.99 | We need solve inclusion-exclusion. Need count exactly one. Total surveyed 104 maybe includes none? Let's compute.
Sets C,D,R. |C|=40, |D|=43, |R|=51. Pairwise intersections: C∩D=13, C∩R=17, D∩R=17. Triple=3.
Need number joined exactly one club. Could compute using Venn regions.
Let x = only C, etc. Pairwise only reg... | We can break the Venn diagram into regions.
- Only chess and drama: \(13-3=10\)
- Only chess and robotics: \(17-3=14\)
- Only drama and robotics: \(17-3=14\)
- All three: \(3\)
Then:
- Only chess: \(40-(10+14+3)=13\)
- Only drama: \(43-(10+14+3)=16\)
- Only robotics: \(51-(14+14+3)=19\)
Exactly one club:
\[
13+16+19... | 48 | false | false | stop | 125 | 447 | 2.1 | v3 | 16,000 | 0.8 | 5 |
fff7be317a4e3f2dbaae | 33c141d2d8a4263ddacc | 33c141d2d8a4263ddacc | train | pareto_5efforts | venn_counting | 1 | concise | -1 | false | 50,000 | 104 students were surveyed. 40 joined chess. 43 joined drama. 51 joined robotics. 13 joined both chess and drama. 17 joined both chess and robotics. 17 joined both drama and robotics. 3 joined all three clubs. How many students joined exactly one of these clubs?
Final line: `ANSWER: <answer>`. | 104 students were surveyed. 40 joined chess. 43 joined drama. 51 joined robotics. 13 joined both chess and drama. 17 joined both chess and robotics. 17 joined both drama and robotics. 3 joined all three clubs. How many students joined exactly one of these clubs? | 49 | integer | set_enumeration | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | high | 0.7 | 0.99 | We need solve inclusion-exclusion. Need count exactly one of clubs. Let's compute.
Total 104 surveyed. Sets C,D,R sizes 40,43,51. Pair intersections given. Triple 3.
We need exactly one.
Let's compute regions.
Let a = exactly C only, b = exactly D only, c = exactly R only.
Let cd = exactly C&D not R = 13-3=10.
cr =... | ANSWER: 49 | 49 | true | true | stop | 126 | 308 | 1.29 | v3 | 16,000 | 0.8 | 5 |
fff7be317a4e3f2dbaae | 33c141d2d8a4263ddacc | 33c141d2d8a4263ddacc | train | pareto_5efforts | venn_counting | 1 | concise | -1 | false | 50,000 | 104 students were surveyed. 40 joined chess. 43 joined drama. 51 joined robotics. 13 joined both chess and drama. 17 joined both chess and robotics. 17 joined both drama and robotics. 3 joined all three clubs. How many students joined exactly one of these clubs?
Final line: `ANSWER: <answer>`. | 104 students were surveyed. 40 joined chess. 43 joined drama. 51 joined robotics. 13 joined both chess and drama. 17 joined both chess and robotics. 17 joined both drama and robotics. 3 joined all three clubs. How many students joined exactly one of these clubs? | 49 | integer | set_enumeration | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | xhigh | 0.7 | 0.99 | We need solve inclusion-exclusion. Need final answer. Let's compute carefully.
Total surveyed 104. Sets C,D,R sizes 40,43,51. Pair intersections: C∩D=13, C∩R=17, D∩R=17. Triple=3.
Need number joined exactly one club.
We can compute union size = 40+43+51 - (13+17+17) + 3 = 134 - 47 +3? Wait sum singles=134. pair sum=... | We can break the students into disjoint groups.
- All three clubs: 3
- Chess & drama only: \(13-3=10\)
- Chess & robotics only: \(17-3=14\)
- Drama & robotics only: \(17-3=14\)
Then only chess: \(40-(10+14+3)=13\)
Only drama: \(43-(10+14+3)=16\)
Only robotics: \(51-(14+14+3)=20\)
So exactly one club: \(13+16+20=49... | 49 | true | true | stop | 126 | 594 | 1.92 | v3 | 16,000 | 0.8 | 5 |
fff7be317a4e3f2dbaae | 33c141d2d8a4263ddacc | 33c141d2d8a4263ddacc | train | pareto_5efforts | venn_counting | 1 | concise | -1 | false | 50,000 | 104 students were surveyed. 40 joined chess. 43 joined drama. 51 joined robotics. 13 joined both chess and drama. 17 joined both chess and robotics. 17 joined both drama and robotics. 3 joined all three clubs. How many students joined exactly one of these clubs?
Final line: `ANSWER: <answer>`. | 104 students were surveyed. 40 joined chess. 43 joined drama. 51 joined robotics. 13 joined both chess and drama. 17 joined both chess and robotics. 17 joined both drama and robotics. 3 joined all three clubs. How many students joined exactly one of these clubs? | 49 | integer | set_enumeration | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | max | 0.7 | 0.99 | We need solve inclusion-exclusion. Need final answer. Let's compute.
Total 104 surveyed. Sets C,D,R sizes 40,43,51. Pairwise intersections: CD=13, CR=17, DR=17. Triple=3.
Need exactly one club.
Formula: |exactly one| = sum singles - 2*sum pairwise? Let's derive. For each person, count in exactly one. Let n1 = number... | Using inclusion–exclusion region counts:
- Triple intersection: 3
- Chess & Drama only: 13 − 3 = 10
- Chess & Robotics only: 17 − 3 = 14
- Drama & Robotics only: 17 − 3 = 14
- Chess only: 40 − 10 − 14 − 3 = 13
- Drama only: 43 − 10 − 14 − 3 = 16
- Robotics only: 51 − 14 − 14 − 3 = 20
Exactly one club: 13 + 16 + 20 = ... | 49 | true | true | stop | 126 | 535 | 6.07 | v3 | 16,000 | 0.8 | 5 |
5c24fe643eba86351987 | 80d429755f28e99d7d66 | 80d429755f28e99d7d66 | train | pareto_5efforts | inventory_word_problem | 2 | concise | -1 | false | 50,000 | Olga starts with 149 bottles. Then, in order, Olga loses 61 to damage; then splits the stock into 5 equal groups (whole items only), keeps one group plus any leftover items, and gives the other groups away; then matches the current count with an equal new shipment; then buys 56 more; then receives a delivery of 38; the... | Olga starts with 149 bottles. Then, in order, Olga loses 61 to damage; then splits the stock into 5 equal groups (whole items only), keeps one group plus any leftover items, and gives the other groups away; then matches the current count with an equal new shipment; then buys 56 more; then receives a delivery of 38; the... | 162 | integer | state_simulation | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | low | 0.7 | 0.99 | Let's compute step by step.
Start: 149.
Loses 61 to damage: 149-61 = 88.
Splits stock into 5 equal groups (whole items only), keeps one group plus leftover, gives other groups away. So 88 // 5 = 17 per group, leftover 88 % 5 = 3. Keeps one group (17) + leftover (3) = 20.
Matches current count with equal new shipment: ... | ANSWER: 162 | 162 | true | true | stop | 153 | 194 | 0.97 | v3 | 16,000 | 1 | 5 |
5c24fe643eba86351987 | 80d429755f28e99d7d66 | 80d429755f28e99d7d66 | train | pareto_5efforts | inventory_word_problem | 2 | concise | -1 | false | 50,000 | Olga starts with 149 bottles. Then, in order, Olga loses 61 to damage; then splits the stock into 5 equal groups (whole items only), keeps one group plus any leftover items, and gives the other groups away; then matches the current count with an equal new shipment; then buys 56 more; then receives a delivery of 38; the... | Olga starts with 149 bottles. Then, in order, Olga loses 61 to damage; then splits the stock into 5 equal groups (whole items only), keeps one group plus any leftover items, and gives the other groups away; then matches the current count with an equal new shipment; then buys 56 more; then receives a delivery of 38; the... | 162 | integer | state_simulation | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | medium | 0.7 | 0.99 | We need solve word problem carefully. Need parse sequence. Need final answer line.
Let's restate: Olga starts with 149 bottles.
Then in order:
1. loses 61 to damage.
2. splits the stock into 5 equal groups (whole items only), keeps one group plus any leftover items, and gives the other groups away.
3. matches the curr... | Start: 149
After damage: 149 − 61 = 88
Split into 5 groups: 88 = 5×17 + 3, keeps 17 + 3 = 20
Equal shipment doubles: 20 × 2 = 40
Buy 56: 40 + 56 = 96
Delivery 38: 96 + 38 = 134
Purchase 28: 134 + 28 = 162
ANSWER: 162 | 162 | true | true | stop | 154 | 595 | 1.82 | v3 | 16,000 | 1 | 5 |
5c24fe643eba86351987 | 80d429755f28e99d7d66 | 80d429755f28e99d7d66 | train | pareto_5efforts | inventory_word_problem | 2 | concise | -1 | false | 50,000 | Olga starts with 149 bottles. Then, in order, Olga loses 61 to damage; then splits the stock into 5 equal groups (whole items only), keeps one group plus any leftover items, and gives the other groups away; then matches the current count with an equal new shipment; then buys 56 more; then receives a delivery of 38; the... | Olga starts with 149 bottles. Then, in order, Olga loses 61 to damage; then splits the stock into 5 equal groups (whole items only), keeps one group plus any leftover items, and gives the other groups away; then matches the current count with an equal new shipment; then buys 56 more; then receives a delivery of 38; the... | 162 | integer | state_simulation | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | high | 0.7 | 0.99 | We need solve word problem. Need parse carefully. Olga starts with 149 bottles. Then in order:
1 loses 61 to damage.
2 splits the stock into 5 equal groups (whole items only), keeps one group plus any leftover items, and gives the other groups away.
3 matches the current count with an equal new shipment.
4 buys 56 more... | ANSWER: 162 | 162 | true | true | stop | 155 | 357 | 2.03 | v3 | 16,000 | 1 | 5 |
5c24fe643eba86351987 | 80d429755f28e99d7d66 | 80d429755f28e99d7d66 | train | pareto_5efforts | inventory_word_problem | 2 | concise | -1 | false | 50,000 | Olga starts with 149 bottles. Then, in order, Olga loses 61 to damage; then splits the stock into 5 equal groups (whole items only), keeps one group plus any leftover items, and gives the other groups away; then matches the current count with an equal new shipment; then buys 56 more; then receives a delivery of 38; the... | Olga starts with 149 bottles. Then, in order, Olga loses 61 to damage; then splits the stock into 5 equal groups (whole items only), keeps one group plus any leftover items, and gives the other groups away; then matches the current count with an equal new shipment; then buys 56 more; then receives a delivery of 38; the... | 162 | integer | state_simulation | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | xhigh | 0.7 | 0.99 | We need solve word problem. Need parse carefully. Let's restate.
Olga starts with 149 bottles. Then, in order:
1. loses 61 to damage
2. splits the stock into 5 equal groups (whole items only), keeps one group plus any leftover items, and gives the other groups away
3. matches the current count with an equal new shipme... | Start: 149
After damage: 149 − 61 = 88
Split into 5 groups: 88 = 5×17 + 3, keep 17 + 3 = 20
Match with equal shipment: 20 + 20 = 40
Buy 56: 40 + 56 = 96
Delivery 38: 96 + 38 = 134
Purchase 28: 134 + 28 = 162
ANSWER: 162 | 162 | true | true | stop | 155 | 492 | 1.56 | v3 | 16,000 | 1 | 5 |
5c24fe643eba86351987 | 80d429755f28e99d7d66 | 80d429755f28e99d7d66 | train | pareto_5efforts | inventory_word_problem | 2 | concise | -1 | false | 50,000 | Olga starts with 149 bottles. Then, in order, Olga loses 61 to damage; then splits the stock into 5 equal groups (whole items only), keeps one group plus any leftover items, and gives the other groups away; then matches the current count with an equal new shipment; then buys 56 more; then receives a delivery of 38; the... | Olga starts with 149 bottles. Then, in order, Olga loses 61 to damage; then splits the stock into 5 equal groups (whole items only), keeps one group plus any leftover items, and gives the other groups away; then matches the current count with an equal new shipment; then buys 56 more; then receives a delivery of 38; the... | 162 | integer | state_simulation | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | max | 0.7 | 0.99 | We need solve word problem carefully. Need parse operations. Olga starts 149 bottles. Then in order:
1. loses 61 to damage.
2. splits the stock into 5 equal groups (whole items only), keeps one group plus any leftover items, and gives the other groups away.
3. matches the current count with an equal new shipment.
4. bu... | Start: 149 bottles.
After losing 61:
149 − 61 = 88.
Split into 5 equal whole groups: 88 ÷ 5 = 17 per group with 3 leftover.
Keeps one group plus leftover: 17 + 3 = 20.
Matches with equal shipment: 20 + 20 = 40.
Buys 56: 40 + 56 = 96.
Delivery of 38: 96 + 38 = 134.
Purchases 28: 134 + 28 = 162.
ANSWER: 162 | 162 | true | true | stop | 155 | 591 | 2.47 | v3 | 16,000 | 1 | 5 |
34656a873e5ccea2441e | 41164a594b91576b0685 | 41164a594b91576b0685 | train | pareto_5efforts | date_arithmetic | 2 | concise | -1 | false | 50,000 | Start from Sunday, August 23, 2015. Subtract 203 days, then add 117 days, then subtract 156 days. What is the resulting date and weekday? Answer in the form YYYY-MM-DD Weekday.
Final line: `ANSWER: <answer>`. | Start from Sunday, August 23, 2015. Subtract 203 days, then add 117 days, then subtract 156 days. What is the resulting date and weekday? Answer in the form YYYY-MM-DD Weekday. | 2014-12-24 Wednesday | yyyy-mm-dd_weekday | python_datetime | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | low | 0.7 | 0.99 | Let me compute carefully.
Start: Sunday, August 23, 2015.
Subtract 203 days: Aug 23, 2015 minus 203 days.
Let's compute. Aug 23 day-of-year 2015: Jan31 Feb28 Mar31 Apr30 May31 Jun30 Jul31 Aug23 = 31+28+31+30+31+30+31+23 = 235. So Aug 23 is day 235.
Minus 203 days => day 32 of year? 235-203=32. Day 32 of 2015 = Feb 1... | ANSWER: 2014-12-24 Wednesday | 2014-12-24 Wednesday | true | true | stop | 111 | 2,335 | 9.35 | v3 | 16,000 | 0.8 | 5 |
34656a873e5ccea2441e | 41164a594b91576b0685 | 41164a594b91576b0685 | train | pareto_5efforts | date_arithmetic | 2 | concise | -1 | false | 50,000 | Start from Sunday, August 23, 2015. Subtract 203 days, then add 117 days, then subtract 156 days. What is the resulting date and weekday? Answer in the form YYYY-MM-DD Weekday.
Final line: `ANSWER: <answer>`. | Start from Sunday, August 23, 2015. Subtract 203 days, then add 117 days, then subtract 156 days. What is the resulting date and weekday? Answer in the form YYYY-MM-DD Weekday. | 2014-12-24 Wednesday | yyyy-mm-dd_weekday | python_datetime | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | medium | 0.7 | 0.99 | We need answer date calculation. Need produce final with ANSWER. Let's compute carefully.
Start Sunday, August 23, 2015. Subtract 203 days, then add 117 days, then subtract 156 days. Net change = -203+117-156 = -242 days. So start date minus 242 days. Need resulting date and weekday.
August 23, 2015 Sunday. Subtract ... | 2014-12-25 Wednesday
ANSWER: 2014-12-25 Wednesday | 2014-12-25 Wednesday | false | false | stop | 112 | 1,033 | 4.25 | v3 | 16,000 | 0.8 | 5 |
34656a873e5ccea2441e | 41164a594b91576b0685 | 41164a594b91576b0685 | train | pareto_5efforts | date_arithmetic | 2 | concise | -1 | false | 50,000 | Start from Sunday, August 23, 2015. Subtract 203 days, then add 117 days, then subtract 156 days. What is the resulting date and weekday? Answer in the form YYYY-MM-DD Weekday.
Final line: `ANSWER: <answer>`. | Start from Sunday, August 23, 2015. Subtract 203 days, then add 117 days, then subtract 156 days. What is the resulting date and weekday? Answer in the form YYYY-MM-DD Weekday. | 2014-12-24 Wednesday | yyyy-mm-dd_weekday | python_datetime | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | high | 0.7 | 0.99 | We need answer date. Need compute carefully. Start Sunday, August 23, 2015. Subtract 203 days, then add 117 days, then subtract 156 days. Need resulting date and weekday. Output form YYYY-MM-DD Weekday. Final ANSWER.
Let's compute. Could do stepwise. Need be careful with leap years? 2015 non-leap. Let's compute.
Star... | 2014-12-24 Wednesday
ANSWER: 2014-12-24 Wednesday | 2014-12-24 Wednesday | true | true | stop | 113 | 824 | 2.63 | v3 | 16,000 | 0.8 | 5 |
34656a873e5ccea2441e | 41164a594b91576b0685 | 41164a594b91576b0685 | train | pareto_5efforts | date_arithmetic | 2 | concise | -1 | false | 50,000 | Start from Sunday, August 23, 2015. Subtract 203 days, then add 117 days, then subtract 156 days. What is the resulting date and weekday? Answer in the form YYYY-MM-DD Weekday.
Final line: `ANSWER: <answer>`. | Start from Sunday, August 23, 2015. Subtract 203 days, then add 117 days, then subtract 156 days. What is the resulting date and weekday? Answer in the form YYYY-MM-DD Weekday. | 2014-12-24 Wednesday | yyyy-mm-dd_weekday | python_datetime | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | xhigh | 0.7 | 0.99 | We need compute date arithmetic. Need final date and weekday. Need be careful. Start Sunday, August 23, 2015. Subtract 203 days, add 117, subtract 156. Net change = -203 +117 -156 = -242 days. So start Aug 23, 2015 minus 242 days. Need resulting date and weekday. Let's compute accurately.
Start date: 2015-08-23 Sunday... | 2014-12-24 Wednesday
ANSWER: 2014-12-24 Wednesday | 2014-12-24 Wednesday | true | true | stop | 113 | 2,018 | 7.09 | v3 | 16,000 | 0.8 | 5 |
34656a873e5ccea2441e | 41164a594b91576b0685 | 41164a594b91576b0685 | train | pareto_5efforts | date_arithmetic | 2 | concise | -1 | false | 50,000 | Start from Sunday, August 23, 2015. Subtract 203 days, then add 117 days, then subtract 156 days. What is the resulting date and weekday? Answer in the form YYYY-MM-DD Weekday.
Final line: `ANSWER: <answer>`. | Start from Sunday, August 23, 2015. Subtract 203 days, then add 117 days, then subtract 156 days. What is the resulting date and weekday? Answer in the form YYYY-MM-DD Weekday. | 2014-12-24 Wednesday | yyyy-mm-dd_weekday | python_datetime | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | max | 0.7 | 0.99 | We need solve date arithmetic. Need be careful. Starting Sunday, August 23, 2015. Subtract 203 days, add 117, subtract 156. Net change = -203+117-156 = -242 days. Need date 242 days before Aug 23 2015. Then weekday. Let's compute carefully.
Start 2015-08-23 Sunday. Subtract 242 days.
Compute. Need exact date. Let's d... | 2014-12-24 Wednesday
ANSWER: 2014-12-24 Wednesday | 2014-12-24 Wednesday | true | true | stop | 113 | 2,101 | 8.81 | v3 | 16,000 | 0.8 | 5 |
eec98fb184bcb8723472 | fd15031ba48b54676943 | fd15031ba48b54676943 | train | pareto_5efforts | code_tracing | 2 | concise | -1 | false | 50,000 | What does this Python program print?
```python
x, y = 6, 4
for i in range(13):
if i % 2 == 0:
x += y * 6
else:
y += x - 4
x %= 1000; y %= 1000
print(x + y)
```
Final line: `ANSWER: <answer>`. | What does this Python program print?
```python
x, y = 6, 4
for i in range(13):
if i % 2 == 0:
x += y * 6
else:
y += x - 4
x %= 1000; y %= 1000
print(x + y)
``` | 1438 | integer | code_execution | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | low | 0.7 | 0.99 | Let me trace through the program.
x=6, y=4
i=0 (even): x += y*6 = 6 + 4*6 = 30; y unchanged; x%=1000 ->30, y%=1000 ->4. x=30,y=4
i=1 (odd): y += x-4 = 4 + 30-4 = 30; x unchanged; x%=1000,y%=1000. x=30,y=30
i=2 (even): x += y*6 = 30 + 30*6 = 210; y=30. x=210,y=30
i=3 (odd): y += x-4 = 30 + 210-4 = 236; x=210. x=210,y=2... | ANSWER: 1438 | 1438 | true | true | stop | 136 | 771 | 2.15 | v3 | 16,000 | 1 | 5 |
eec98fb184bcb8723472 | fd15031ba48b54676943 | fd15031ba48b54676943 | train | pareto_5efforts | code_tracing | 2 | concise | -1 | false | 50,000 | What does this Python program print?
```python
x, y = 6, 4
for i in range(13):
if i % 2 == 0:
x += y * 6
else:
y += x - 4
x %= 1000; y %= 1000
print(x + y)
```
Final line: `ANSWER: <answer>`. | What does this Python program print?
```python
x, y = 6, 4
for i in range(13):
if i % 2 == 0:
x += y * 6
else:
y += x - 4
x %= 1000; y %= 1000
print(x + y)
``` | 1438 | integer | code_execution | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | medium | 0.7 | 0.99 | We need answer. Need compute. Let's simulate carefully. Python code:
x,y = 6,4
for i in range(13):
if i%2==0:
x += y*6
else:
y += x-4
x %=1000; y%=1000
print(x+y)
Need final with ANSWER. Let's compute step by step.
Initialize x=6,y=4.
i=0 even: x += y*6 =6+4*6=30. then mod: x=30,y=4.
i=1 odd: y += x-4 =4+3... | ANSWER: 1438 | 1438 | true | true | stop | 137 | 1,292 | 3.01 | v3 | 16,000 | 1 | 5 |
eec98fb184bcb8723472 | fd15031ba48b54676943 | fd15031ba48b54676943 | train | pareto_5efforts | code_tracing | 2 | concise | -1 | false | 50,000 | What does this Python program print?
```python
x, y = 6, 4
for i in range(13):
if i % 2 == 0:
x += y * 6
else:
y += x - 4
x %= 1000; y %= 1000
print(x + y)
```
Final line: `ANSWER: <answer>`. | What does this Python program print?
```python
x, y = 6, 4
for i in range(13):
if i % 2 == 0:
x += y * 6
else:
y += x - 4
x %= 1000; y %= 1000
print(x + y)
``` | 1438 | integer | code_execution | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | high | 0.7 | 0.99 | We need answer. Need compute program. Need final with answer. Let's simulate carefully.
Python:
x,y=6,4
for i in range(13): i=0..12
if i even: x += y*6
else: y += x-4
x %=1000; y%=1000
print(x+y)
Need compute. Let's do step by step accurately. Could use mental or derive. Let's simulate.
Initial x=6,y=4.
i=0 even:
x... | ANSWER: 1438 | 1438 | true | true | stop | 138 | 735 | 2.36 | v3 | 16,000 | 1 | 5 |
eec98fb184bcb8723472 | fd15031ba48b54676943 | fd15031ba48b54676943 | train | pareto_5efforts | code_tracing | 2 | concise | -1 | false | 50,000 | What does this Python program print?
```python
x, y = 6, 4
for i in range(13):
if i % 2 == 0:
x += y * 6
else:
y += x - 4
x %= 1000; y %= 1000
print(x + y)
```
Final line: `ANSWER: <answer>`. | What does this Python program print?
```python
x, y = 6, 4
for i in range(13):
if i % 2 == 0:
x += y * 6
else:
y += x - 4
x %= 1000; y %= 1000
print(x + y)
``` | 1438 | integer | code_execution | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | xhigh | 0.7 | 0.99 | We need answer. Need compute. Let's simulate carefully. Python program.
x,y=6,4
for i in range(13):
if i%2==0: x += y*6
else: y += x-4
x %=1000; y%=1000
print(x+y)
Need compute. Let's do manually or reason. Could simulate table.
i=0 even: x=6+4*6=30; y=4. mod: x=30,y=4.
i=1 odd: y=4 + (x-4)=4+26=30? Wait x curren... | ANSWER: 1438 | 1438 | true | true | stop | 138 | 1,127 | 2.62 | v3 | 16,000 | 1 | 5 |
eec98fb184bcb8723472 | fd15031ba48b54676943 | fd15031ba48b54676943 | train | pareto_5efforts | code_tracing | 2 | concise | -1 | false | 50,000 | What does this Python program print?
```python
x, y = 6, 4
for i in range(13):
if i % 2 == 0:
x += y * 6
else:
y += x - 4
x %= 1000; y %= 1000
print(x + y)
```
Final line: `ANSWER: <answer>`. | What does this Python program print?
```python
x, y = 6, 4
for i in range(13):
if i % 2 == 0:
x += y * 6
else:
y += x - 4
x %= 1000; y %= 1000
print(x + y)
``` | 1438 | integer | code_execution | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | max | 0.7 | 0.99 | We need answer simple Python program output. Need compute. Let's simulate carefully. x,y=6,4. loop i=0..12.
i%2==0: x += y*6; else y += x-4; then mod 1000 each.
Let's compute.
Initial x=6,y=4.
i=0 even:
x = 6 + 4*6 = 30. y=4. mod: x=30,y=4.
i=1 odd:
y = 4 + (30-4)=30. x=30. mod. x=30,y=30.
i=2 even:
x=30 + 30*6=2... | ANSWER: 1438 | 1438 | true | true | stop | 138 | 652 | 2.28 | v3 | 16,000 | 1 | 5 |
387d160186268d50acb3 | 5e72a4015965592664b8 | 5e72a4015965592664b8 | train | pareto_5efforts | combinatorics_count | 2 | concise | -1 | false | 50,000 | How many ordered sequences of 6 integers, each between 2 and 5 inclusive, have a sum of exactly 22?
Final line: `ANSWER: <answer>`. | How many ordered sequences of 6 integers, each between 2 and 5 inclusive, have a sum of exactly 22? | 546 | integer | dynamic_programming | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | low | 0.7 | 0.99 | We need count ordered 6-tuples (a1,...,a6) with each in {2,3,4,5} sum 22.
Let xi = ai-2 in {0,1,2,3}. Sum xi = 22 - 12 = 10. Count nonnegative solutions xi<=3 summing to 10.
Total without upper bound C(10+6-1,6-1)=C(15,5)=3003. Subtract xi>=4. For one variable xi'=xi-4>=0 sum 6: C(6+5,5)=C(11,5)=462. Times 6 = 2772. ... | We let \(x_i = a_i - 2\), so each \(x_i \in \{0,1,2,3\}\) and
\[
x_1+\cdots+x_6 = 22-12 = 10.
\]
Count solutions with \(0\le x_i\le 3\). By inclusion-exclusion:
- Total nonnegative solutions: \(\binom{15}{5}=3003\).
- Subtract one variable \(\ge 4\): \(6\binom{11}{5}=6\cdot 462=2772\).
- Add back two variables \(\ge... | 546 | true | true | stop | 82 | 476 | 2.35 | v3 | 16,000 | 1 | 5 |
387d160186268d50acb3 | 5e72a4015965592664b8 | 5e72a4015965592664b8 | train | pareto_5efforts | combinatorics_count | 2 | concise | -1 | false | 50,000 | How many ordered sequences of 6 integers, each between 2 and 5 inclusive, have a sum of exactly 22?
Final line: `ANSWER: <answer>`. | How many ordered sequences of 6 integers, each between 2 and 5 inclusive, have a sum of exactly 22? | 546 | integer | dynamic_programming | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | medium | 0.7 | 0.99 | We need solve combinatorics. Need count ordered sequences length 6, entries in {2,3,4,5}, sum 22. Need final answer. Let's compute carefully.
Let x_i ∈ {2,3,4,5}. Sum 22. Let y_i = x_i - 2 ∈ {0,1,2,3}. Sum y_i = 22 - 12 = 10. Count nonnegative integer sequences length 6 with each ≤3 summing to 10.
Total unrestricted ... | We need count ordered 6-tuples with entries in {2,3,4,5} summing to 22.
Subtract 2 from each entry: let \(y_i\in\{0,1,2,3\}\), with
\[
y_1+\cdots+y_6 = 22-12=10.
\]
Count solutions using inclusion-exclusion. Unrestricted nonnegative solutions:
\[
\binom{10+6-1}{6-1}=\binom{15}{5}=3003.
\]
Subtract cases where some... | 546 | true | true | stop | 83 | 875 | 2.85 | v3 | 16,000 | 1 | 5 |
387d160186268d50acb3 | 5e72a4015965592664b8 | 5e72a4015965592664b8 | train | pareto_5efforts | combinatorics_count | 2 | concise | -1 | false | 50,000 | How many ordered sequences of 6 integers, each between 2 and 5 inclusive, have a sum of exactly 22?
Final line: `ANSWER: <answer>`. | How many ordered sequences of 6 integers, each between 2 and 5 inclusive, have a sum of exactly 22? | 546 | integer | dynamic_programming | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | high | 0.7 | 0.99 | We need solve combinatorics. Need count ordered 6-tuples of integers in {2,3,4,5} summing to 22. Need final answer. Let's compute carefully.
Let x_i in {2,...,5}, i=1..6, sum 22. Let y_i = x_i - 2 in {0,1,2,3}. Sum y_i = 22 - 12 = 10. Need number of ordered 6-tuples y_i in [0,3] summing 10.
Total nonnegative without ... | We need the number of ordered 6-tuples \((x_1,\dots,x_6)\) with each \(x_i\in\{2,3,4,5\}\) and sum \(22\).
Set \(y_i=x_i-2\), so each \(y_i\in\{0,1,2,3\}\) and
\[
y_1+\cdots+y_6 = 22-12=10.
\]
Count solutions with \(0\le y_i\le 3\). By inclusion-exclusion:
\[
\binom{10+6-1}{6-1}
- \binom{6}{1}\binom{10-4+6-1}{6-1}
... | 546 | true | true | stop | 84 | 753 | 2.58 | v3 | 16,000 | 1 | 5 |
387d160186268d50acb3 | 5e72a4015965592664b8 | 5e72a4015965592664b8 | train | pareto_5efforts | combinatorics_count | 2 | concise | -1 | false | 50,000 | How many ordered sequences of 6 integers, each between 2 and 5 inclusive, have a sum of exactly 22?
Final line: `ANSWER: <answer>`. | How many ordered sequences of 6 integers, each between 2 and 5 inclusive, have a sum of exactly 22? | 546 | integer | dynamic_programming | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | xhigh | 0.7 | 0.99 | We need answer count sequences length 6 entries in {2,3,4,5} sum 22. Need final answer. Let's compute carefully.
Let x_i in {2..5}, sum=22. Let y_i = x_i-2 in {0..3}, sum y_i = 22 - 12 =10. Count 6-tuples y_i in [0,3] sum 10.
Total nonnegative without upper bound C(10+5,5)=C(15,5)=3003? 15 choose5=3003 yes. Subtract ... | The number of ordered 6-tuples \((x_1,\dots,x_6)\) with each \(x_i\in\{2,3,4,5\}\) and sum 22 is found by setting \(y_i=x_i-2\in\{0,1,2,3\}\), so \(\sum y_i=10\). Counting such tuples gives
\[
[x^{10}](1+x+x^2+x^3)^6=546.
\]
ANSWER: 546 | 546 | true | true | stop | 84 | 716 | 2.27 | v3 | 16,000 | 1 | 5 |
387d160186268d50acb3 | 5e72a4015965592664b8 | 5e72a4015965592664b8 | train | pareto_5efforts | combinatorics_count | 2 | concise | -1 | false | 50,000 | How many ordered sequences of 6 integers, each between 2 and 5 inclusive, have a sum of exactly 22?
Final line: `ANSWER: <answer>`. | How many ordered sequences of 6 integers, each between 2 and 5 inclusive, have a sum of exactly 22? | 546 | integer | dynamic_programming | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | max | 0.7 | 0.99 | We need answer count ordered sequences of length 6, entries in {2,3,4,5}, sum 22. Need compute. Let's solve. Variables xi in [2,5], sum 22. Let yi=xi-2 in [0,3], sum yi = 22 - 12 =10. Count nonnegative y_i <=3 summing 10. Total without upper: C(10+5,5)=C(15,5)=3003. Subtract those with yi>=4. Inclusion-exclusion. Let z... | ANSWER: 546 | 546 | true | true | stop | 84 | 673 | 2.54 | v3 | 16,000 | 1 | 5 |
927fb54a942d0c1b7106 | 8929b582aff31ebea0f4 | 8929b582aff31ebea0f4 | train | pareto_5efforts | modular_arithmetic | 2 | concise | -1 | false | 50,000 | What is the remainder when 13^1574 is divided by 13?
Final line: `ANSWER: <answer>`. | What is the remainder when 13^1574 is divided by 13? | 0 | integer | python_pow_mod | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | low | 0.7 | 0.99 | We need answer: remainder when 13^1574 divided by 13. Since base 13, any positive exponent divisible by 13? 13^1574 = 13 * 13^1573, so remainder 0. Need final with answer. Ensure format. | 13^1574 is a multiple of 13, so its remainder upon division by 13 is 0.
ANSWER: 0 | 0 | true | true | stop | 75 | 113 | 0.81 | v3 | 16,000 | 1 | 5 |
927fb54a942d0c1b7106 | 8929b582aff31ebea0f4 | 8929b582aff31ebea0f4 | train | pareto_5efforts | modular_arithmetic | 2 | concise | -1 | false | 50,000 | What is the remainder when 13^1574 is divided by 13?
Final line: `ANSWER: <answer>`. | What is the remainder when 13^1574 is divided by 13? | 0 | integer | python_pow_mod | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | medium | 0.7 | 0.99 | We need answer math question. Need remainder when 13^1574 divided by 13. Since base divisible by 13, any positive exponent yields divisible by 13, remainder 0. Need final line ANSWER: 0. Ensure no extra? Could include reasoning. Final answer exact format. | The number \(13^{1574}\) is a power of 13, so it is divisible by 13. Therefore, the remainder upon division by 13 is 0.
ANSWER: 0 | 0 | true | true | stop | 76 | 125 | 0.95 | v3 | 16,000 | 1 | 5 |
927fb54a942d0c1b7106 | 8929b582aff31ebea0f4 | 8929b582aff31ebea0f4 | train | pareto_5efforts | modular_arithmetic | 2 | concise | -1 | false | 50,000 | What is the remainder when 13^1574 is divided by 13?
Final line: `ANSWER: <answer>`. | What is the remainder when 13^1574 is divided by 13? | 0 | integer | python_pow_mod | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | high | 0.7 | 0.99 | We need answer problem: remainder when 13^1574 divided by 13. Trivial: 13^1574 divisible by 13, remainder 0. Need final with reasoning and answer line. Ensure no hidden trick? 13^1574 mod 13 = 0. Yes. | The number \(13^{1574}\) is a power of 13, so it is divisible by 13. Therefore the remainder upon division by 13 is 0.
ANSWER: 0 | 0 | true | true | stop | 77 | 130 | 0.77 | v3 | 16,000 | 1 | 5 |
927fb54a942d0c1b7106 | 8929b582aff31ebea0f4 | 8929b582aff31ebea0f4 | train | pareto_5efforts | modular_arithmetic | 2 | concise | -1 | false | 50,000 | What is the remainder when 13^1574 is divided by 13?
Final line: `ANSWER: <answer>`. | What is the remainder when 13^1574 is divided by 13? | 0 | integer | python_pow_mod | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | xhigh | 0.7 | 0.99 | We need answer remainder 13^1574 divided by 13. Trivial: 13^anything positive divisible by 13, remainder 0. Need final line. Ensure no weird. | 13^1574 is a power of 13, so it is divisible by 13. Therefore the remainder is 0.
ANSWER: 0 | 0 | true | true | stop | 77 | 91 | 1.08 | v3 | 16,000 | 1 | 5 |
927fb54a942d0c1b7106 | 8929b582aff31ebea0f4 | 8929b582aff31ebea0f4 | train | pareto_5efforts | modular_arithmetic | 2 | concise | -1 | false | 50,000 | What is the remainder when 13^1574 is divided by 13?
Final line: `ANSWER: <answer>`. | What is the remainder when 13^1574 is divided by 13? | 0 | integer | python_pow_mod | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | max | 0.7 | 0.99 | We need answer remainder 13^1574 divided by 13. That's 0. Need final line ANSWER: 0. Simple. But maybe trick? 13^1574 divisible by 13 yes remainder 0. Ensure final. | Since \(13^{1574}\) is a power of 13, it is divisible by 13. Therefore the remainder is 0.
ANSWER: 0 | 0 | true | true | stop | 77 | 108 | 0.81 | v3 | 16,000 | 1 | 5 |
43253dcd0b9988e37f23 | a557fdf919d0c5291c46 | a557fdf919d0c5291c46 | train | pareto_5efforts | shortest_path | 2 | concise | -1 | false | 50,000 | An undirected road network has these roads (with lengths):
- A–B: 3
- B–D: 9
- F–G: 5
- B–F: 11
- D–E: 9
- A–F: 12
- G–C: 10
- E–B: 2
- A–G: 3
- A–D: 8
- C–E: 3
- B–C: 1
What is the length of the shortest route from A to G?
Final line: `ANSWER: <answer>`. | An undirected road network has these roads (with lengths):
- A–B: 3
- B–D: 9
- F–G: 5
- B–F: 11
- D–E: 9
- A–F: 12
- G–C: 10
- E–B: 2
- A–G: 3
- A–D: 8
- C–E: 3
- B–C: 1
What is the length of the shortest route from A to G? | 3 | integer | dijkstra | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | low | 0.7 | 0.99 | We need solve shortest path undirected weighted. Need final answer. Let's compute.
Nodes A,B,C,D,E,F,G. Edges:
AB3
BD9
FG5
BF11
DE9
AF12
GC10
EB2
AG3
AD8
CE3
BC1
Need shortest A to G. Direct AG=3. Since undirected, route length 3. Is there shorter? no negative. So answer 3. Need final with answer. Ensure no trick? sh... | The direct road A–G has length 3, and all edge lengths are positive, so no alternate route can be shorter.
ANSWER: 3 | 3 | true | true | stop | 179 | 167 | 8.12 | v3 | 16,000 | 1 | 5 |
43253dcd0b9988e37f23 | a557fdf919d0c5291c46 | a557fdf919d0c5291c46 | train | pareto_5efforts | shortest_path | 2 | concise | -1 | false | 50,000 | An undirected road network has these roads (with lengths):
- A–B: 3
- B–D: 9
- F–G: 5
- B–F: 11
- D–E: 9
- A–F: 12
- G–C: 10
- E–B: 2
- A–G: 3
- A–D: 8
- C–E: 3
- B–C: 1
What is the length of the shortest route from A to G?
Final line: `ANSWER: <answer>`. | An undirected road network has these roads (with lengths):
- A–B: 3
- B–D: 9
- F–G: 5
- B–F: 11
- D–E: 9
- A–F: 12
- G–C: 10
- E–B: 2
- A–G: 3
- A–D: 8
- C–E: 3
- B–C: 1
What is the length of the shortest route from A to G? | 3 | integer | dijkstra | true | beam | Ollama Cloud (OpenAI-compatible endpoint), model tag 'beam' | medium | 0.7 | 0.99 | We need solve shortest path undirected weighted graph. Need final answer. Need compute carefully. Graph nodes A,B,C,D,E,F,G. Edges weights. Need shortest A to G.
Let's list edges:
A-B 3
B-D 9
F-G 5
B-F 11
D-E 9
A-F 12
G-C 10
E-B 2
A-G 3
A-D 8
C-E 3
B-C 1
Undirected.
Need shortest route from A to G. Direct A-G 3. So ... | The direct road A–G has length 3. Since all road lengths are positive, no indirect route can be shorter than 3.
ANSWER: 3 | 3 | true | true | stop | 180 | 240 | 1.02 | v3 | 16,000 | 1 | 5 |
Beam Verified Reasoning Traces
by Marshoot Lab
7,632 reasoning traces from Reflection's Beam-1.0-501B-A23B on 3,595 procedurally generated problems across 13 task families and 7 difficulty levels. Every answer key is computed by code and re-derived by a second, independent solver, so every trace carries a trustworthy correct/incorrect label.
The dataset is packaged four ways, so you can use it for supervised fine-tuning, preference training, reinforcement learning with verifiable rewards, or simply as a fine-grained evaluation of Beam. The generators, the independent verifier and the audit scripts are included in code/, so every number on this page can be reproduced.
Quickstart
from datasets import load_dataset
repo = "MarshootLab/beam-verified-reasoning-traces"
full = load_dataset(repo, "full_traces") # every Beam attempt, right or wrong
sft = load_dataset(repo, "sft_verified") # one verified trace per problem
pairs = load_dataset(repo, "preference_pairs") # filter by pair_type
rl = load_dataset(repo, "rlvr_prompts") # prompt + verified answer
hard = rl["train"].filter(lambda x: x["beam_pass_rate"] < 1.0) # problems Beam sometimes failed
Ready for TRL out of the box
from trl import SFTTrainer, SFTConfig, DPOTrainer, DPOConfig
# SFT on verified reasoning (assistant turn = <think>reasoning</think> + final answer)
sft_ds = sft["train"].map(lambda x: {"messages": x["messages_with_reasoning"]},
remove_columns=sft["train"].column_names)
SFTTrainer(model="your-model", train_dataset=sft_ds, args=SFTConfig(output_dir="sft"))
# DPO on correct-vs-incorrect pairs: `prompt`, `chosen`, `rejected` columns are already in TRL's standard format
dpo_ds = pairs["train"].filter(lambda x: x["pair_type"] == "correctness")
DPOTrainer(model="your-model", train_dataset=dpo_ds, args=DPOConfig(output_dir="dpo"))
Use messages instead of messages_with_reasoning if you only want the short final answers (median 25 characters) without the reasoning.
Why this dataset
- Labels you can trust. Answers are not judged by another LLM. Each problem is generated together with its exact answer, and a separate solver that only reads the prompt text (and uses a different algorithm) must agree. Result: 0 disagreements on 3,595 problems.
- Real failures, not just successes. Beam is right 96.5% of the time overall, but the remaining errors are concentrated and reproducible: combinatorics, date arithmetic and multi-step string transformations at low reasoning effort. These are exactly the examples useful for preference and RL training.
- Controlled variation. Each problem has a family, difficulty level, prompt style and (for some) distractor sentences, and the same core problem is sometimes asked in 4 styles or at 5 reasoning efforts. This lets you measure what actually changes model behaviour.
- Leak-free split. Train/test are split by core problem (style variants and near-duplicates stay together), so no test problem has a paraphrase in train.
At a glance
| Model | Beam-1.0-501B-A23B as served by Ollama Cloud's OpenAI-compatible API under the tag beam (serving precision not published by the provider; see Limitations) |
| Sampling | temperature 0.7, top_p 0.99 (the settings in Beam's model card), max_tokens 16,000 (32,768 for the v4 rescue subset) |
| Traces | 7,632 (6,859 train / 773 test) |
| Unique problems | 3,595 (3,237 train / 358 test) |
| Task families | 13 |
| Difficulty levels | 1-5 for all families, 6-7 for the 7 families whose generators scale further |
| Reasoning efforts | low, high (main grid, hard tier v2); low, medium, high, xhigh, max (Pareto subset); high, max (rescue subset) |
| Prompt styles | concise, standard, case_study, trap_distractor |
| Answer keys independently re-verified | 3,595 / 3,595 (0 mismatches) |
| Beam accuracy (all traces) | 96.5% (lower than v3's 96.9% because v4 deliberately adds harder problems) |
| Language | English only |
v4 additions (October 2026)
v4 adds 322 new Beam traces, all generated through Ollama Cloud (tag beam) with the same sampling settings, and every new answer key re-derived by the independent solver (0 mismatches).
Hard tier v2 (subset = hard_tier_v2): 135 new problems at difficulty 5-7 in the three families where Beam still fails (combinatorics_count, date_arithmetic, string_pipeline, 45 each), each solved at low and high effort.
| Family | Low effort | High effort |
|---|---|---|
| combinatorics_count | 68.9% (n=45) | 86.7% (n=45) |
| date_arithmetic | 84.4% (n=45) | 100.0% (n=45) |
| string_pipeline | 68.9% (n=45) | 97.8% (n=45) |
| All | 74.1% (median 631 tokens) | 94.8% (median 1,544 tokens, 6 truncated at 16k) |
These are the main source of the new correct-vs-incorrect preference pairs.
Rescue subset (subset = rescue_32k): problems that had no correct trace in v3 were re-asked at high and max effort with max_tokens = 32,768. Of the 28 problems reached so far, 26 now have a correct trace (high 25/27, max 24/25 correct). This subset is partial: the remaining 25 problems produce answers close to the 32k-token limit and repeatedly exceeded our client timeout, so they were not completed for this release. They stay in rlvr_prompts with their v3 pass rate.
Results
All intervals are Wilson 95% confidence intervals. Numbers in this section come from the v3 traces in full_traces (both splits); v4 results are reported separately above.
By reasoning effort (main grid, 2,600 traces per effort, identical problems):
| Effort | Accuracy (95% CI) | Median completion tokens | Median latency |
|---|---|---|---|
| low | 95.2% (94.3-95.9) | 433 | 1.8 s |
| high | 99.0% (98.6-99.4) | 811 | 3.0 s |
High effort removes about 80% of low-effort errors for roughly 1.9x the tokens.
Pareto subset (the same 130 problems, 10 per family, each solved at all 5 efforts):
| Effort | Accuracy (95% CI) | Median completion tokens | Mean completion tokens | Median latency | Truncated |
|---|---|---|---|---|---|
| low | 95.4% (90.3-97.9) | 430 | 534 | 2.0 s | 0 |
| medium | 97.7% (93.4-99.2) | 695 | 835 | 2.8 s | 0 |
| high | 99.2% (95.8-99.9) | 738 | 1,004 | 2.7 s | 1 |
| xhigh | 97.7% (93.4-99.2) | 660 | 923 | 2.6 s | 1 |
| max | 97.7% (93.4-99.2) | 608 | 936 | 2.5 s | 1 |
Two observations, both stated with caution. First, xhigh and max did not spend more tokens than high on these problems; their medians were lower. On short, well-defined tasks the higher settings do not appear to translate into longer reasoning. Second, with 130 problems per effort the accuracy differences among medium, high, xhigh and max are not statistically significant: high made 1 error, xhigh and max made 3 each. One error at each of these three levels was the same kind: a combinatorics answer cut off at the 16,000-token limit (19 of the 20 truncations in the whole dataset are combinatorics). We do not claim xhigh or max are worse than high; on these tasks, going beyond high brought no measurable gain in accuracy or token use. Latency depends on the serving endpoint and load and should be read as indicative only.
By prompt style: concise 96.9%, standard 97.0%, case_study 97.0%, trap_distractor 96.8%. Beam is robust to rewording and to irrelevant distractor sentences on these tasks; no style effect is detectable.
Hardest cells (low + high pooled): combinatorics level 7 (73%, n=30), combinatorics level 5 (75%, n=106), combinatorics level 4 (81%, n=106), date arithmetic level 7 (83%, n=30), string pipelines level 7 (83%, n=30), string pipelines level 6 (87%, n=30).
Failure case studies
Two real examples from the data, where Beam failed at low effort and succeeded at high effort on the identical prompt. Excerpts are verbatim apart from trimming.
1. Combinatorics, level 3: correct method, wrong subtraction (instance_id 544e5cddf2a4eded45fb)
How many ordered sequences of 4 integers, each between 2 and 6 inclusive, have a sum of exactly 21?
Verified answer: 20.
Low effort (398 tokens), answered 60:
Total without upper bound: C(16,3)=560. [...] subtract 4*165=660. But 560-660 negative; need higher intersections. Two variables >=5: [...] add 6*20=120. [...] Total = 560 - 660 + 120 = 60. Check. Answer 60.
High effort (667 tokens), answered 20:
[...] So total 560 -660 +120 =20. Need check. Alternatively enumerate. Answer 20.
Both runs set up the same inclusion-exclusion with identical terms. The low-effort run even noticed the intermediate value was negative, then made a plain arithmetic slip in the final line and said "Check" without re-checking. The error is in execution, not in understanding.
2. Date arithmetic, level 7: right date, weekday shifted the wrong way (instance_id 2c26d2bf51a5f4253497)
Start from Thursday, August 14, 2003. Subtract 162 days, then add 89 days, then subtract 139 days, then add 294 days, then subtract 24 days, then add 40 days, then add 8 days, then subtract 154 days. What is the resulting date and weekday?
Verified answer: 2003-06-27 Friday.
Low effort (356 tokens), answered 2003-06-27 Wednesday:
Weekday: start Thursday. -48 days mod 7 = -48+49=1, so one day before Thursday = Wednesday. [...] I think yes.
High effort (898 tokens), answered 2003-06-27 Friday:
-48 days ≡ +1 day modulo 7. Thursday +1 = Friday? Need check. [...] subtract 6 more days [...] Thu -1 Wed, -2 Tue, -3 Mon, -4 Sun, -5 Sat, -6 Fri. Yes Friday.
The low-effort run computed the residue correctly (+1) and then applied it in the wrong direction. The high-effort run hit the same doubt, verified with a second method (counting back day by day) and caught it. This pattern, a correct intermediate value followed by a sign or direction slip that only an explicit second check catches, is typical of the low-effort failures in dates and combinatorics.
Where it tops out: shortest path, Venn counting and work rates were solved 100% at both efforts, and inventory and modular arithmetic were above 99.5%. These families are saturated for Beam at the difficulties our generators can produce; they remain useful as clean SFT data and as regression checks, but they do not separate strong models.
The four configurations
| Config | Rows (train / test) | One row is | Use it for |
|---|---|---|---|
full_traces |
6,859 / 773 | one Beam attempt, correct or not, with all metadata | evaluation, analysis, filtering your own subsets |
sft_verified |
3,200 / 357 | the shortest correct, complete, strictly formatted trace per problem, as messages (answer only) and messages_with_reasoning (reasoning in <think> tags + answer) |
supervised fine-tuning on verified reasoning |
preference_pairs |
1,380 / 155 | two Beam answers to the same prompt, labelled by pair_type, with TRL-ready prompt / chosen / rejected columns (reasoning in <think> tags) |
DPO / reward modelling |
rlvr_prompts |
3,237 / 358 | a problem with its verified answer and Beam's empirical pass rate, no model output | RL with verifiable rewards, curriculum by difficulty |
Because sft_verified keeps the shortest correct trace, it is mostly low-effort reasoning (2,593 of 3,064 train rows are low, 448 high, 23 medium/xhigh/max). Filter on reasoning_effort if you want longer, more self-checking traces. sft_verified covers 3,557 of the 3,595 problems; the other 38 never received a correct, complete, strictly formatted answer from Beam. beam_pass_rate in rlvr_prompts is the fraction of Beam attempts on that problem that were correct (2 to 5 attempts, see beam_attempts), a ready-made difficulty signal.
Preference pair types
pair_type |
Train / test | Chosen | Rejected | Notes |
|---|---|---|---|---|
correctness |
206 / 17 | correct, cleanly finished | incorrect (wrong, empty or truncated) | the hard signal; mostly date arithmetic, combinatorics and strings |
concise_reasoning |
1,174 / 138 | correct, strict format, at most half the tokens | correct, strict format, longer | for training shorter reasoning; in 1,198 of 1,246 pairs chosen is low effort and rejected is high effort |
Both answers in a concise_reasoning pair are correct, so these pairs teach brevity, not accuracy; use them only if that is what you want. We also considered format-compliance pairs but did not include them: 209 of the 212 correct answers without a strict ANSWER: line were work-rate answers written as ANSWER: 120 minutes instead of ANSWER: 120, and since the prompts never forbid a unit, preferring one over the other would not be justified.
Key fields (full_traces)
| Field | Meaning |
|---|---|
instance_id |
unique id of the exact prompt |
core_problem_id |
id of the underlying problem; style variants share it |
split_group_id |
grouping used for the train/test split (merges near-duplicates) |
subset |
main_grid, pareto_5efforts, robustness_4styles or hard_tier |
family, difficulty, style, has_distractors |
how the problem was generated |
prompt |
exact text sent to Beam (includes the answer-format instruction) |
core_prompt |
the problem without styling or format instruction |
answer, answer_format |
verified answer and its format (integer, fraction, date, string, list...) |
solver_type, key_verified_independently |
how the key was computed; always true here |
reasoning |
the reasoning text returned by the API's reasoning field |
response |
Beam's visible answer |
extracted_answer |
answer parsed from the final ANSWER: line (or a lenient fallback) |
is_correct |
extracted answer equals the key after canonical normalisation |
is_correct_strict_format |
correct and given on a proper ANSWER: line |
finish_reason, prompt_tokens, completion_tokens, latency_s |
generation metadata (completion_tokens includes reasoning; the endpoint did not report a separate reasoning-token count) |
beam_pass_rate, beam_attempts |
fraction of Beam attempts on this exact prompt that were correct, and how many attempts there were |
Task families
Each answer key is computed twice by two separate code paths: once by the generator, which knows the problem's internal structure, and once by the verifier, which only sees the prompt text, parses it back into a problem, and solves it with a different method.
| Family | What the model must do | Levels | Generator solver | Independent verifier (prompt text only) |
|---|---|---|---|---|
| Inventory word problems | track a quantity through a sequence of operations | 1-7 | state simulation on the internal operation list | re-parses each sentence and simulates |
| Date arithmetic | add or subtract days across month and year boundaries | 1-7 | Python datetime |
ordinal-day arithmetic, plus a check of the stated start weekday |
| Ordering logic | find the unique order satisfying clues | 1-5 | brute force over permutations (internal constraints) | re-parses clues and searches permutations |
| Code tracing | predict the output of a short Python program | 1-7 | execution of the generated program | executes the code as printed in the prompt |
| Combinatorics | count sequences with constraints | 1-7 | forward dynamic programming | brute-force enumeration, or memoised recursion when enumeration is too large |
| String pipelines | apply a chain of string transformations | 1-7 | built-in transformation functions | separately written interpreter of the English instructions |
| Work rates | combined-work timing | 1-5 | exact fractions | LCM of the individual times |
| Modular arithmetic | large powers and residues | 1-5 | Python pow(a, b, m) |
hand-written square-and-multiply |
| Shortest path | weighted shortest route in a graph | 1-7 | Dijkstra | Floyd-Warshall |
| Probability | exact probability as a fraction | 1-7 | closed-form hypergeometric with exact fractions | brute-force enumeration of all draws |
| Knights & knaves | identify truth-tellers and liars | 1-5 | truth-table enumeration on internal statements | re-parses the statements and enumerates |
| Meeting scheduling | earliest common free slot | 1-5 | interval scan | minute-by-minute bitmap |
| Venn counting | inclusion-exclusion counting | 1-5 | explicit set enumeration | region decomposition from the stated counts |
For a few families (inventory, ordering, knights & knaves) both sides use a similar algorithm; their independence comes from the verifier re-reading the English text rather than trusting the generator's internal data, which catches wording errors such as an ambiguous or misleading sentence.
Ordering logic, work rates, modular arithmetic, knights & knaves, meeting scheduling and Venn counting are capped at level 5: beyond that our generators either stop producing meaningfully harder instances or produce prompts too long to be natural.
How it was built
Code for every step is in code/: tasks.py and tasks_v2.py (generators and canonical grading), verify.py (independent verifier), run.py (resumable generation), audit.py (quality audit), package.py (splits and configurations), charts.py (figures), check_release.py (one-command re-check of the published files) and reward_fn.py (verifiable reward for GRPO/RLVR).
- Generate. Deterministic, seeded generators produce each problem and its exact answer. Names (80), items (40) and words (40) are varied, with 8-10 narrative contexts per family and 15 distractor sentence types.
- Verify the key. A second solver parses only the prompt text and solves it with a different algorithm. Any disagreement blocks release; the final run had none.
- Ask Beam. Each prompt asks for a final line
ANSWER: <answer>. Calls used the official reasoning-effort levels, temperature 0.7, top_p 0.99 and max_tokens 16,000, one request at a time. - Grade. Answers are normalised by format (integers, fractions, dates, lists, strings) and compared to the key. Grading was re-run from scratch during the audit with 0 changes.
- Audit. Schema checks, exact and MinHash near-duplicate detection, manual review of failures, and a check that no core problem appears in two subsets.
- Split. About 10% of split groups go to test, by hash of
split_group_id.
Reproduce the audit
Everything needed is in this repo. From a clone (or with nothing but the scripts, which then fetch the data from the Hub):
pip install -r requirements.txt
python code/check_release.py
It re-derives all 3,595 answer keys with the independent prompt-only verifier, re-grades all 7,632 Beam responses, and checks train/test leakage. Expected output (about a minute on a laptop CPU):
traces 7,632 (6,859 train / 773 test)
unique problems 3,595
key mismatches 0 / 3,595
regrade changes 0 / 7,632
train/test leaks cores 0, split groups 0
Beam accuracy 96.46%
Reward function for GRPO / RLVR
code/reward_fn.py wraps the same canonical grader as TRL-style reward functions (correctness_reward, 1.0 or 0.0, and an optional format_reward bonus of 0.2), reading the answer, answer_format and family columns of rlvr_prompts:
import sys; sys.path.append("code")
from datasets import load_dataset
from trl import GRPOTrainer, GRPOConfig
from reward_fn import correctness_reward, format_reward
ds = load_dataset("MarshootLab/beam-verified-reasoning-traces", "rlvr_prompts", split="train")
trainer = GRPOTrainer(model="your-model", reward_funcs=[correctness_reward, format_reward],
args=GRPOConfig(output_dir="out"), train_dataset=ds)
The reward functions are tested on example completions; we have not run a training job with them.
Quality audit (final)
| Check | Result |
|---|---|
| Answer keys disagreeing with the independent solver | 0 / 3,595 |
| Missing fields | 0 |
| Exact duplicate prompts across different problems | 0 |
| Core problems shared across subsets | 0 |
| Train/test leakage (core problems or split groups) | 0 |
| Near-duplicate problem pairs (MinHash) | 13, all same-template problems with different numbers; kept and grouped into the same split |
Empty responses / no ANSWER: line |
19 / 19 (kept in full_traces, labelled incorrect; excluded from sft_verified) |
Truncated at the 16,000-token limit (finish_reason = length) |
20 (same treatment); 19 of them are the 19 empty responses. 18 were at high effort or above, 1 at low. 19 of the 20 are combinatorics problems |
| Raw records outside the final generation plan (superseded runs) | 460, dropped before packaging |
| Distractor sentences that happen to contain the answer number | 14 of 444 distractor problems with an integer answer; kept, flagged here so you can filter them |
| Strict-format compliance | 94.0%; of the correct answers not counted as strict, 209 of 212 are work-rate answers with a unit added (120 minutes) |
Ambiguity found and fixed. During failure review we found that "remove all vowels (a, e, i, o, u)" was ambiguous for uppercase letters, and several "errors" were Beam using the other reasonable reading. The wording was changed to "in either upper or lower case" and every affected trace was regenerated. Old traces were discarded, not relabelled. In meeting scheduling, one failure matched an alternative reading of a slot boundary; the other failures are genuine model errors.
Limitations
- Synthetic and templated. Problems come from templates. They test precise multi-step reasoning, not world knowledge, open-ended writing or long-context skills. A model trained only on this data may learn the templates.
- One model, one sampling setting, one provider. All traces are Beam at temperature 0.7 via Ollama Cloud (tag
beam). The provider does not publish the precision it serves Beam at, so if it uses a quantised build, accuracy through Reflection's own API or Hugging Face Inference Providers may differ. - Reasoning text.
reasoningis what the API returned in its reasoning field. We make no claim that it is the model's complete internal computation, and a correct final answer does not guarantee every reasoning step is correct. - Small subsets have wide intervals. The Pareto (130 problems per effort) and hard-tier (105 traces per level per effort) results should be read with their confidence intervals.
- Saturated families. Several families are near 100% for Beam and add little evaluation signal.
- Few correctness pairs. Because Beam is accurate, only 223 correct-vs-incorrect pairs exist (182 before v4), concentrated in the hardest families. The larger
concise_reasoningset teaches brevity, not accuracy. - Pass rates are coarse.
beam_pass_ratecomes from 2 to 5 attempts, usually at different reasoning efforts, so treat it as a difficulty hint rather than a precise probability. - No training experiments. We did not fine-tune any model on this data, so we make no claims about downstream gains.
Licence and credit
Released under Apache-2.0, matching Beam's licence. Model outputs are from Reflection's Beam; problems, answer keys, verification and packaging are by Marshoot Lab.
@misc{marshootlab2026beamtraces,
title = {Beam Verified Reasoning Traces},
author = {Marshoot Lab},
year = {2026},
url = {https://huggingface.co/datasets/MarshootLab/beam-verified-reasoning-traces}
}
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