Document ID: chunk:federal_register_of_legislation:F2016C00867:body:0:p19
Version: federal_register_of_legislation:F2016C00867
Segment Type: other
Provision Reference: 
Character Range: 55449–59076

this annex.
2.4.2.2.2.              In the direction specified in paragraph 2.3.3.2. of this annex.
2.4.2.2.3.              In the direction specified in paragraph 2.3.3.3. of this annex.
2.4.2.2.4.              In the direction specified in paragraph 2.3.3.4. of this annex.
2.4.2.2.5.              In the direction specified in paragraph 2.3.3.5. of this annex.
2.4.2.2.6.              In the direction specified in paragraph 2.3.3.6. of this annex.
2.4.3.                              If at any point in time the pulse exceeds 36 g and the test requirements are fulfilled, the test shall be considered valid.
2.4.4.                              Ensure that the door did not open and close during the test.

Figure 4-1
Inertial loading - Sample calculation

Given:
Door latch system subjected to a 30g deceleration
Average Push-Button Spring Output Force = 0.459kgf
Pawl Spring Output Torque = 0.0459kgf m
a = 30g (m/s2)
F = ma = m*30g = m*294.2

M1 = 0.0163kg                                                                       d1 = 31.50mm
M2 = 0.0227kg                                                                       d2 = 10.67mm
M3 = 0.0122kg                                                                       d3 = 4.83mm
M4 = 0.0422kg                                                                       d4 = 31.50mm
                                                                                    d5 = 37.59mm
                                                                                    d6 = 1.90mm
                                                                                                    denotes the cg of component

F1  = M1 x a - Average load on knob spring = (0.0163kg x 30g) - 0.459kgf = 0.03kgf

F2  = M2 x a = 0.0227kg x 30g = 0.681kgf

F3  = M3/2 x a = 0.0122kg/2 x 30g = 0.183kgf

Σ Mo  = F1 x d1 + F2 x d2 - F3 x d3
  = 0.03 x 31.5 + 0.681 x 10.67 - 0.183 x 4.83
  = 7.33kgf mm

F5  = Mo/d4 = 7.33/31.5 = 0.2328kgf

F6  = M4 x a = 0.0422kg x 30g = 1.266kgf

Σ Mo  = Pawl spring output torque- (F5 d5 + F6 d6)/1000
 = 0.0459 - (0.2328 x 37.59 + 1.266 x 1.9)/1000
 = 0.0347kgf m

Table 4-1
Acceleration pulse corridor

Upper Bound  Lower Bound
Point        Time (ms)    Acceleration  Point  Time (ms)  Acceleration
                          (g)                             (g)
A            0            6             E      5          0
B            20           36            F      25         30
C            60           36            G      55         30
D            100          0             H      70         0

Figure 4-2
Acceleration pulse

Figure 4-3
Vehicle coordinate reference system for inertial testing

 X = longitudinal direction
 Y = transversal direction
 Z = vertical direction

Annex 5

Hinge test procedure
          1. Purpose
These tests are conducted to determine the ability of the vehicle hinge system to withstand test loads:
(a) In the longitudinal and transversal directions and, in addition;
(b) For doors that open in a vertical direction, vertical vehicle direction.
2.                                          Test procedure
2.1.                                    Multiple hinge system
2.1.1.                              Longitudinal load test
2.1.1.1.                        Equipment
2.1.1.1.1.              Tensile testing fixture.
2.1.1.1.2.              A typical static test fixture is illustrated in Figure 5-1.
2.1.1.2.                        Procedure
2.1.1.2.1.              Attach the hinge system to the mounting provision of the test fixture. Hinge attitude must simulate vehicle position (door fully closed)