question stringlengths 49 545 | sql stringlengths 25 2.39k | rewritten_sql stringlengths 32 4.76k | hardness stringclasses 4
values | TestSuiteEval evaluation bool 2
classes | db_id stringclasses 1
value |
|---|---|---|---|---|---|
List the states that have more than 100 active establishments. For each of these states, show the count of active establishments and order the results from the state with the most to the fewest. | SELECT T1.state, COUNT(T1.basic_cnpj) AS number_of_active_establishments
FROM establishment AS T1
JOIN registration_status AS T2
ON T1.registration_status_code = T2.code
WHERE
T2.description = 'ACTIVE'
GROUP BY
T1.state
HAVING
COUNT(T1.basic_cnpj) > 100
ORDER BY
number_of_active_establishments DESC; | SELECT establishment.state, COUNT(establishment.basic_cnpj)
FROM establishment
JOIN registration_status
ON establishment.registration_status_code = registration_status.code
WHERE
registration_status.description = 'ATIVA'
GROUP BY
establishment.state
HAVING
COUNT(establishment.basic_cnpj) > 100
ORDER BY
COUNT(... | extra | true | sqliteEN-sample |
What are the names of all companies with a company size described as 'MICRO COMPANY'? | SELECT T1.name
FROM company AS T1
INNER JOIN company_size AS T2
ON T1.company_size_code = T2.code
WHERE
T2.description = 'MICRO COMPANY'; | SELECT company.name FROM company JOIN company_size ON company.company_size_code = company_size.code WHERE company_size.description = 'MICRO EMPRESA' | medium | true | sqliteEN-sample |
For each state, what are the top 3 company sizes that have the highest average number of 'Administrator' qualified partners? For this analysis, only consider companies that started their activities after 2010 and currently have an 'Active' registration status. Your result should display the state, the company size desc... | WITH FilteredCompanies AS (
-- First, select companies that are active and started after 2010
SELECT
e.basic_cnpj,
e.state,
c.company_size_code
FROM establishment AS e
JOIN company AS c
ON e.basic_cnpj = c.basic_cnpj
JOIN registration_status AS rs
ON e.registration_status_code = rs.code
... | SELECT
T3.state,
company_size.description,
T3.avg_admin_partners_value
FROM (
SELECT
T2.state,
T2.company_size_code,
T2.avg_admin_partners_value,
RANK() OVER (PARTITION BY T2.state ORDER BY T2.avg_admin_partners_value DESC) rank_value
FROM (
SELECT
establishment.state,
company.... | extra | true | sqliteEN-sample |
What is the average capital for each legal nature? List the top 5 legal natures with the highest average capital. | SELECT T2.description, AVG(T1.capital) AS average_capital
FROM company AS T1
JOIN legal_nature AS T2
ON T1.legal_nature_code = T2.code
GROUP BY T2.description
ORDER BY average_capital DESC
LIMIT 5; | SELECT legal_nature.description, AVG(company.capital) FROM company JOIN legal_nature ON company.legal_nature_code = legal_nature.code GROUP BY legal_nature.description ORDER BY AVG(company.capital) DESC LIMIT 5 | extra | true | sqliteEN-sample |
What are the names of the top 5 largest companies (by capital) that have 'ACTIVE' registration status? Also, show their capital and registration status description. | SELECT
c.name,
c.capital,
rs.description
FROM company AS c
JOIN establishment AS e
ON c.basic_cnpj = e.basic_cnpj
JOIN registration_status AS rs
ON e.registration_status_code = rs.code
WHERE
rs.description = 'ACTIVE'
ORDER BY
c.capital DESC
LIMIT 5; | SELECT
company.name,
company.capital,
registration_status.description
FROM company
JOIN establishment
ON company.basic_cnpj = establishment.basic_cnpj
JOIN registration_status
ON establishment.registration_status_code = registration_status.code
WHERE
registration_status.description = 'ATIVA'
ORDER BY
comp... | extra | true | sqliteEN-sample |
What are the top 5 most capitalized legal natures for companies with an 'Active' registration status? Show the legal nature description and the total capital for each. | SELECT
T2.description,
SUM(T1.capital) AS total_capital
FROM company AS T1
INNER JOIN legal_nature AS T2
ON T1.legal_nature_code = T2.code
INNER JOIN establishment AS T3
ON T1.basic_cnpj = T3.basic_cnpj
INNER JOIN registration_status AS T4
ON T3.registration_status_code = T4.code
WHERE
T4.description = 'ATI... | SELECT legal_nature.description, SUM(company.capital) FROM company INNER JOIN legal_nature ON company.legal_nature_code = legal_nature.code INNER JOIN establishment ON company.basic_cnpj = establishment.basic_cnpj INNER JOIN registration_status ON establishment.registration_status_code = registration_status.code WHERE ... | extra | true | sqliteEN-sample |
What is the count of active establishments for each type of legal nature? Show the legal nature's description and the corresponding count, sorted in descending order of the count. | SELECT T3.description, COUNT(T1.basic_cnpj) AS establishment_count
FROM establishment AS T1
INNER JOIN company AS T2
ON T1.basic_cnpj = T2.basic_cnpj
INNER JOIN legal_nature AS T3
ON T2.legal_nature_code = T3.code
INNER JOIN registration_status AS T4
ON T1.registration_status_code = T4.code
WHERE
T4.description... | SELECT legal_nature.description, COUNT(establishment.basic_cnpj)
FROM establishment
INNER JOIN company
ON establishment.basic_cnpj = company.basic_cnpj
INNER JOIN legal_nature
ON company.legal_nature_code = legal_nature.code
INNER JOIN registration_status
ON establishment.registration_status_code = registration_s... | extra | true | sqliteEN-sample |
List the names of all companies that have at least one partner in the age range of '61-70 years old'. | SELECT DISTINCT T1.name
FROM company AS T1
JOIN partner AS T2
ON T1.basic_cnpj = T2.basic_cnpj
JOIN age_range AS T3
ON T2.age_range_code = T3.code
WHERE
T3.description = '61-70 years old'; | SELECT DISTINCT company.name FROM company JOIN partner ON company.basic_cnpj = partner.basic_cnpj JOIN age_range ON partner.age_range_code = age_range.code WHERE age_range.description = '61 a 70 anos' | hard | true | sqliteEN-sample |
What are the names and legal natures of companies with a capital greater than 5,000,000 that have an active registration status and are located in the state 'SP'? | SELECT T1.name, T3.description
FROM company AS T1
INNER JOIN establishment AS T2
ON T1.basic_cnpj = T2.basic_cnpj
INNER JOIN legal_nature AS T3
ON T1.legal_nature_code = T3.code
INNER JOIN registration_status AS T4
ON T2.registration_status_code = T4.code
WHERE
T1.capital > 5000000 AND T2.state = 'SP' AND T4.de... | SELECT company.name, legal_nature.description FROM company INNER JOIN establishment ON company.basic_cnpj = establishment.basic_cnpj INNER JOIN legal_nature ON company.legal_nature_code = legal_nature.code INNER JOIN registration_status ON establishment.registration_status_code = registration_status.code WHERE company.... | extra | true | sqliteEN-sample |
What are the names of all companies with a capital greater than 50000? | SELECT name FROM company WHERE capital > 50000; | SELECT company.name FROM company WHERE company.capital > 50000 | easy | true | sqliteEN-sample |
List the names of companies whose capital is greater than the average capital for their primary business activity (CNAE). These companies must also have at least one foreign partner (country code not equal to 105) and a group of partners with at least three different qualification types. For each company, display its n... | SELECT
company.name,
cnae.name,
company.capital,
T1.media_capital -- Referência ao alias da subconsulta
FROM company
JOIN establishment
ON company.basic_cnpj = establishment.basic_cnpj
JOIN (
SELECT
establishment.primary_cnae_code, -- Adicionado para permitir o JOIN
AVG(company.capital) AS media_cap... | SELECT
company.name,
cnae.name,
company.capital,
T1.AVG(company.capital)
FROM company
JOIN establishment
ON company.basic_cnpj = establishment.basic_cnpj
JOIN (
SELECT
establishment.primary_cnae_code,
AVG(company.capital)
FROM establishment
JOIN company
ON establishment.basic_cnpj = company.... | extra | false | sqliteEN-sample |
For each primary business activity (CNAE), identify the top company based on capital. Then, for that top company, determine the most common qualification among its partners. Provide the name of the business activity, the name and capital of the top company, and the most common partner qualification description for that... | WITH RankedCompaniesByCnae AS (
SELECT
c.name AS company_name,
c.capital,
e.primary_cnae_code,
c.basic_cnpj,
ROW_NUMBER() OVER(PARTITION BY e.primary_cnae_code ORDER BY c.capital DESC) as rn
FROM company c
JOIN establishment e
ON c.basic_cnpj = e.basic_cnpj
WHERE
e.primary_cnae_code ... | SELECT
cnae.name,
company.name,
company.capital,
(
SELECT
qualification.description
FROM partner
JOIN qualification
ON partner.partner_qualification_code = qualification.code
WHERE
partner.basic_cnpj = company.basic_cnpj
GROUP BY
partner.basic_cnpj,
qualificatio... | extra | false | sqliteEN-sample |
List the names of all establishments along with the name of their city. | SELECT T1.name, T2.name FROM establishment AS T1 INNER JOIN city AS T2 ON T1.city_code = T2.code; | SELECT establishment.name, city.name FROM establishment INNER JOIN city ON establishment.city_code = city.code | medium | true | sqliteEN-sample |
For each company size, what is the average capital? List only the company size categories with more than 10 companies, and order the result by the average capital in descending order. | SELECT T2.description, AVG(T1.capital) AS average_capital
FROM company AS T1
JOIN company_size AS T2
ON T1.company_size_code = T2.code
GROUP BY
T2.description
HAVING
COUNT(T1.basic_cnpj) > 10
ORDER BY
average_capital DESC; | SELECT company_size.description, AVG(company.capital)
FROM company
JOIN company_size
ON company.company_size_code = company_size.code
GROUP BY
company_size.description
HAVING
COUNT(company.basic_cnpj) > 10
ORDER BY
AVG(company.capital) DESC; | hard | true | sqliteEN-sample |
What are the names and capital of companies that are classified as 'LARGE' and whose main establishment is in the state of 'SP'? | SELECT
T1.name,
T1.capital
FROM company AS T1
INNER JOIN establishment AS T2
ON T1.basic_cnpj = T2.basic_cnpj
INNER JOIN company_size AS T3
ON T1.company_size_code = T3.code
WHERE
T3.description = 'DEMAIS' AND T2.state = 'SP'; | SELECT
company.name,
company.capital
FROM company
INNER JOIN establishment
ON company.basic_cnpj = establishment.basic_cnpj
INNER JOIN company_size
ON company.company_size_code = company_size.code
WHERE
company_size.description = 'LARGE' AND establishment.state = 'SP'; | hard | true | sqliteEN-sample |
List the states that contain more than 50 companies classified as 'MICRO EMPRESA'. For these states, show the state name, the total count of these micro-companies, and their average capital. Only consider companies that have opted for 'SIMPLES' taxation and have an 'ACTIVE' registration status. Order the results by the... | SELECT
e.state,
COUNT(c.basic_cnpj) AS number_of_micro_companies,
AVG(c.capital) AS average_capital
FROM company AS c
JOIN establishment AS e
ON c.basic_cnpj = e.basic_cnpj
JOIN company_size AS cs
ON c.company_size_code = cs.code
JOIN taxation AS t
ON c.basic_cnpj = t.basic_cnpj
JOIN registration_status AS ... | SELECT
establishment.state,
COUNT(company.basic_cnpj),
AVG(company.capital)
FROM company
JOIN establishment
ON company.basic_cnpj = establishment.basic_cnpj
JOIN company_size
ON company.company_size_code = company_size.code
JOIN taxation
ON company.basic_cnpj = taxation.basic_cnpj
JOIN registration_status
... | extra | true | sqliteEN-sample |
For each primary economic activity (CNAE), what is the average capital of companies established after 2015 that have at least one partner with the qualification of 'Administrator'? Only include economic activities with more than three such companies, and list them in descending order of their average capital. | SELECT
c.name AS cnae_name,
AVG(co.capital) AS average_capital
FROM company AS co
JOIN establishment AS e
ON co.basic_cnpj = e.basic_cnpj
JOIN cnae AS c
ON e.primary_cnae_code = c.code
WHERE
e.start_activity_date > '2015-12-31' AND e.basic_cnpj IN (SELECT DISTINCT
p.basic_cnpj
FROM partner AS p
JOIN q... | SELECT cnae.name, AVG(company.capital) FROM company JOIN establishment ON company.basic_cnpj = establishment.basic_cnpj JOIN cnae ON establishment.primary_cnae_code = cnae.code WHERE establishment.start_activity_date > '2015-12-31' AND establishment.basic_cnpj IN (SELECT DISTINCT partner.basic_cnpj FROM partner JOIN qu... | extra | true | sqliteEN-sample |
What are the names of all the registered countries? | SELECT name FROM country; | SELECT country.name FROM country; | easy | true | sqliteEN-sample |
What are the names of companies that opted for and were later excluded from 'Simples' taxation, have a capital greater than 5 million, and have at least two partners from a country other than Brazil? For these companies, display their name, state, and the count of their foreign partners, ordered by capital in descendin... | WITH CompanyTaxation AS (
SELECT
T1.basic_cnpj,
T1.name,
T1.capital,
T2.state
FROM company AS T1
INNER JOIN establishment AS T2
ON T1.basic_cnpj = T2.basic_cnpj
INNER JOIN taxation AS T3
ON T1.basic_cnpj = T3.basic_cnpj
WHERE
T1.capital > 5000000 AND T3.simples_taxation_option_date... | SELECT
company.name,
establishment.state,
COUNT(partner.basic_cnpj)
FROM company
INNER JOIN establishment
ON company.basic_cnpj = establishment.basic_cnpj
INNER JOIN taxation
ON company.basic_cnpj = taxation.basic_cnpj
INNER JOIN partner
ON company.basic_cnpj = partner.basic_cnpj
INNER JOIN country
ON par... | extra | false | sqliteEN-sample |
List the names of all companies along with their size description. | SELECT T1.name, T2.description FROM company AS T1 JOIN company_size AS T2 ON T1.company_size_code = T2.code | SELECT company.name, company_size.description FROM company JOIN company_size ON company.company_size_code = company_size.code | medium | true | sqliteEN-sample |
What are the names of all companies and their corresponding size descriptions? | SELECT T1.name, T2.description
FROM company AS T1
JOIN company_size AS T2
ON T1.company_size_code = T2.code; | SELECT company.name, company_size.description FROM company JOIN company_size ON company.company_size_code = company_size.code | medium | true | sqliteEN-sample |
For the three most common legal natures among companies with a capital greater than 1,000,000, calculate the average number of partners per company size. Only include main establishments (where `main_or_branch` is 'MAIN') that started their activities after 2010 in this calculation. List the legal nature, the company s... | WITH TopLegalNatures AS (
SELECT
legal_nature_code
FROM company
WHERE
capital > 1000000
GROUP BY
legal_nature_code
ORDER BY
COUNT(*) DESC
LIMIT 3
), RelevantCompaniesPartnerCount AS (
SELECT
p.basic_cnpj,
COUNT(p.cpf_or_cnpj) AS NumberOfPartners
FROM partner AS p
JOIN establish... | SELECT
legal_nature.description,
company_size.description,
AVG((
SELECT
COUNT(partner.cpf_or_cnpj)
FROM partner
JOIN establishment
ON partner.basic_cnpj = establishment.basic_cnpj
WHERE
establishment.main_or_branch = 'MAIN' AND establishment.start_activity_date > '2010-12-31'
... | extra | false | sqliteEN-sample |
List the top 5 cities with the highest number of establishments that started their activities on or after January 1st, 2021. Provide the city name and the count of establishments. | SELECT T2.name, COUNT(T1.basic_cnpj) AS establishment_count
FROM establishment AS T1
JOIN city AS T2
ON T1.city_code = T2.code
WHERE T1.start_activity_date >= '2021-01-01'
GROUP BY T2.name
ORDER BY establishment_count DESC
LIMIT 5; | SELECT city.name, COUNT(establishment.basic_cnpj) FROM establishment JOIN city ON establishment.city_code = city.code WHERE establishment.start_activity_date >= '2021-01-01' GROUP BY city.name ORDER BY COUNT(establishment.basic_cnpj) DESC LIMIT 5 | extra | true | sqliteEN-sample |
What are the names of companies, along with their primary activity (CNAE name) and the reason for their registration status, for all establishments located in the state of 'SP'? | SELECT
c.name AS company_name,
cn.name AS primary_activity,
rsr.description AS registration_status_reason
FROM company AS c
JOIN establishment AS e
ON c.basic_cnpj = e.basic_cnpj
JOIN cnae AS cn
ON e.primary_cnae_code = cn.code
JOIN registration_status_reason AS rsr
ON e.registration_status_reason_code = rs... | SELECT
company.name,
cnae.name,
registration_status_reason.description
FROM company
JOIN establishment
ON company.basic_cnpj = establishment.basic_cnpj
JOIN cnae
ON establishment.primary_cnae_code = cnae.code
JOIN registration_status_reason
ON establishment.registration_status_reason_code = registration_sta... | extra | true | sqliteEN-sample |
For each state, identify the most common primary economic activity (CNAE) by counting the number of establishments. List the state, the name of that top Cnae, the number of establishments associated with it, and the total capital of all companies sharing that primary activity in that state. Only consider establishments... | WITH StateCnaeRank AS (
SELECT
e.state,
cn.name AS cnae_name,
COUNT(e.basic_cnpj) AS establishment_count,
SUM(c.capital) AS total_capital,
RANK() OVER (PARTITION BY e.state ORDER BY COUNT(e.basic_cnpj) DESC) as rnk
FROM
establishment AS e
JOIN
company ... | SELECT
establishment.state,
cnae.name,
COUNT(establishment.basic_cnpj),
SUM(company.capital)
FROM establishment
JOIN company
ON establishment.basic_cnpj = company.basic_cnpj
JOIN cnae
ON establishment.primary_cnae_code = cnae.code
JOIN registration_status
ON establishment.registration_status_code = regist... | extra | false | sqliteEN-sample |
For each distinct legal nature, find the company with the highest social capital that is opted into the 'Simples' taxation scheme and was established in the state of 'SP'. For each of these top companies, provide the legal nature's description, the company's name, its capital, and the name of the partner who is qualifi... | WITH RankedCompanies AS (
SELECT
c.basic_cnpj,
c.name AS company_name,
c.capital,
c.legal_nature_code,
e.state,
RANK() OVER (PARTITION BY c.legal_nature_code ORDER BY c.capital DESC) AS rnk
FROM company c
JOIN establishment e ON c.basic_cnpj = e.basic_cnpj
JOIN taxation t ON c.basic_cnpj... | SELECT
legal_nature.description,
company.name,
company.capital,
partner.name
FROM company
JOIN establishment ON company.basic_cnpj = establishment.basic_cnpj
JOIN taxation ON company.basic_cnpj = taxation.basic_cnpj
JOIN legal_nature ON company.legal_nature_code = legal_nature.code
JOIN partner ON company.basic... | extra | true | sqliteEN-sample |
List the top 5 states by total company capital for establishments that are designated as the main branch and started their activities on or after January 1st, 2020. For each of these top states, identify the most common primary business activity (CNAE name) among these establishments and show the count of establishment... | WITH MainEstablishments AS (
SELECT
e.state,
e.primary_cnae_code,
c.capital
FROM establishment e
JOIN company c ON e.basic_cnpj = c.basic_cnpj
WHERE
e.main_or_branch = '1' AND e.start_activity_date >= '2020-01-01'
),
TopStates AS (
SELECT
state,
SUM(ca... | SELECT
T1.state,
T1.total_capital,
cnae.name,
T2.cnae_count
FROM (
SELECT
establishment.state,
SUM(company.capital) AS total_capital
FROM establishment
JOIN company
ON establishment.basic_cnpj = company.basic_cnpj
WHERE
establishment.main_or_branch = '1' AND establishment.start_activity_... | extra | true | sqliteEN-sample |
List the names of companies that have a capital greater than the average capital for their respective size category. For each of these companies, also show its size, its capital, and the calculated average capital for its size. Only include companies where at least one of its partners has the same qualification as the ... | WITH AvgCapitalPerSize AS (
SELECT
cs.code AS size_code,
AVG(c.capital) AS avg_capital_for_size
FROM company AS c
JOIN company_size AS cs
ON c.company_size_code = cs.code
GROUP BY
cs.code
)
SELECT
c.name AS company_name,
cs.description AS company_size,
c.capital,
ac.avg_capital_for_size
... | SELECT
company.name,
company_size.description,
company.capital,
(
SELECT
AVG(company.capital)
FROM company
WHERE
company.company_size_code = company.company_size_code
)
FROM company
JOIN company_size
ON company.company_size_code = company_size.code
WHERE
company.capital > (
SEL... | extra | false | sqliteEN-sample |
List the top 3 highest-capital companies for each primary business activity (CNAE) category that has more than 10 active companies. For each of these top companies, display the CNAE name, the company's name, its capital, its rank within that category, and the name of a partner who is qualified as an 'Administrator'. An... | WITH ActiveCompanyCNAE AS (
-- Step 1: Identify active companies and count how many active companies belong to each primary CNAE.
SELECT
c.basic_cnpj,
c.name AS company_name,
c.capital,
e.primary_cnae_code,
COUNT(c.basic_cnpj) OVER (PARTITION BY e.primary_cnae_code) AS companies_in_cnae
FROM c... | SELECT
cnae.name,
sub2.name,
sub2.capital,
sub2.capital_rank_value,
partner.name
FROM (
SELECT
sub1.basic_cnpj,
sub1.name,
sub1.capital,
sub1.primary_cnae_code,
RANK() OVER (PARTITION BY sub1.primary_cnae_code ORDER BY sub1.capital DESC) AS capital_rank_value
FROM (
SELECT
co... | extra | true | sqliteEN-sample |
What are the names of the top 5 primary economic activities (CNAE) with the most establishments, and how many establishments does each have? | SELECT T2.name, COUNT(T1.basic_cnpj) AS establishment_count
FROM establishment AS T1
JOIN cnae AS T2
ON T1.primary_cnae_code = T2.code
GROUP BY
T2.name
ORDER BY
establishment_count DESC
LIMIT 5; | SELECT cnae.name, COUNT(establishment.basic_cnpj) FROM establishment JOIN cnae ON establishment.primary_cnae_code = cnae.code GROUP BY cnae.name ORDER BY COUNT(establishment.basic_cnpj) DESC LIMIT 5 | extra | true | sqliteEN-sample |
What are the top 5 most common primary business activities (CNAE) for establishments, and how many establishments are registered under each? | SELECT
T2.name,
COUNT(T1.basic_cnpj) AS number_of_establishments
FROM establishment AS T1
INNER JOIN cnae AS T2
ON T1.primary_cnae_code = T2.code
GROUP BY
T2.name
ORDER BY
number_of_establishments DESC
LIMIT 5; | SELECT cnae.name, COUNT(establishment.basic_cnpj) FROM establishment INNER JOIN cnae ON establishment.primary_cnae_code = cnae.code GROUP BY cnae.name ORDER BY COUNT(establishment.basic_cnpj) DESC LIMIT 5 | extra | true | sqliteEN-sample |
For each partner qualification, what is the total number of partners and the average capital of the companies they are part of? List only those qualifications with 10 or more partners, and order the result by the number of partners in descending order. | SELECT
T3.description,
COUNT(T1.basic_cnpj) AS num_partners,
AVG(T2.capital) AS avg_capital
FROM partner AS T1
INNER JOIN company AS T2
ON T1.basic_cnpj = T2.basic_cnpj
INNER JOIN qualification AS T3
ON T1.partner_qualification_code = T3.code
GROUP BY
T3.description
HAVING
COUNT(T1.basic_cnpj) >= 10
ORDER... | SELECT
qualification.description,
COUNT(partner.basic_cnpj),
AVG(company.capital)
FROM partner
INNER JOIN company
ON partner.basic_cnpj = company.basic_cnpj
INNER JOIN qualification
ON partner.partner_qualification_code = qualification.code
GROUP BY
qualification.description
HAVING
COUNT(partner.basic_cnp... | extra | true | sqliteEN-sample |
Identify the top 3 states with the highest proportion of companies that have ever opted for 'Simples' taxation. For each of these top states, determine the primary business activity (CNAE name) with the largest total capital sum from currently 'Active' companies. Display the state, the calculated proportion of 'Simples... | WITH StateProportions AS (
-- First, calculate the proportion of companies with 'Simples' taxation for each state
SELECT
e.state,
CAST(SUM(CASE WHEN t.option_for_simples_taxation = 'Y' THEN 1 ELSE 0 END) AS REAL) / COUNT(t.basic_cnpj) AS simples_proportion
FROM establishment AS e
JOIN taxation AS t
... | SELECT
StateProportions.state,
StateProportions.simples_proportion,
RankedCnaeByCapital.cnae_name,
RankedCnaeByCapital.total_capital
FROM
(
SELECT
establishment.state,
CAST(SUM(CASE WHEN taxation.option_for_simples_taxation = 'Y' THEN 1 ELSE 0 END) AS REAL) / COUNT(taxation.basic_cnpj) simples... | extra | true | sqliteEN-sample |
What are the names of the top 10 companies with the highest capital? | SELECT name, capital
FROM company
ORDER BY capital DESC
LIMIT 10; | SELECT company.name, company.capital FROM company ORDER BY company.capital DESC LIMIT 10 | medium | true | sqliteEN-sample |
For each legal business structure that has over 1,000 actively registered companies, identify two specific companies: the one with the highest declared capital and the one that was most recently founded. The final result should display the description of the legal structure, the name and capital of the top-capital comp... | WITH ActiveCompanies AS (
-- Pre-filter and join main tables for active companies
SELECT
c.basic_cnpj,
c.name AS company_name,
c.capital,
e.start_activity_date,
c.legal_nature_code,
ln.description AS legal_nature_description
FROM company c
JOIN establishme... | SELECT
legal_nature.description,
(
SELECT company.name
FROM company
JOIN establishment ON company.basic_cnpj = establishment.basic_cnpj
JOIN registration_status ON establishment.registration_status_code = registration_status.code
WHERE registration_status.description = 'ATIVA'
AND company.legal_... | extra | false | sqliteEN-sample |
What is the number of companies and their average capital for each company size description? Please order the results by the number of companies in descending order. | SELECT T2.description, COUNT(T1.basic_cnpj) AS company_count, AVG(T1.capital) AS average_capital
FROM company AS T1
JOIN company_size AS T2
ON T1.company_size_code = T2.code
GROUP BY T2.description
ORDER BY company_count DESC; | SELECT company_size.description, COUNT(company.basic_cnpj), AVG(company.capital) FROM company JOIN company_size ON company.company_size_code = company_size.code GROUP BY company_size.description ORDER BY COUNT(company.basic_cnpj) DESC | hard | true | sqliteEN-sample |
List the names of all partners who are associated with a company described as a 'MICRO COMPANY' in size. | SELECT T1.name FROM partner AS T1 INNER JOIN company AS T2 ON T1.basic_cnpj = T2.basic_cnpj INNER JOIN company_size AS T3 ON T2.company_size_code = T3.code WHERE T3.description = 'MICRO COMPANY' | SELECT partner.name FROM partner INNER JOIN company ON partner.basic_cnpj = company.basic_cnpj INNER JOIN company_size ON company.company_size_code = company_size.code WHERE company_size.description = 'MICRO COMPANY' | hard | true | sqliteEN-sample |
For each year since 2010, identify the most common legal nature for companies that were established in the city of 'SAO PAULO', have opted for 'SIMPLES' taxation, and have at least one partner with the qualification 'Administrator'. Display the establishment year, the description of the most common legal nature, and th... | WITH CompanyCountsPerNature AS (
-- Step 1: Count companies for each year and legal nature that meet all criteria
SELECT
STRFTIME('%Y', T1.start_activity_date) AS establishment_year,
T3.description AS legal_nature,
COUNT(T1.basic_cnpj) AS num_companies
FROM establishment AS T1
INNER JOIN company AS ... | SELECT
STRFTIME('%Y', establishment.start_activity_date),
legal_nature.description,
COUNT(establishment.basic_cnpj)
FROM establishment
INNER JOIN company
ON establishment.basic_cnpj = company.basic_cnpj
INNER JOIN legal_nature
ON company.legal_nature_code = legal_nature.code
INNER JOIN city
ON establishment... | extra | true | sqliteEN-sample |
List the top 5 legal natures based on the number of associated companies that are classified as 'LARGE'. Provide the legal nature description and the count of such companies for each. | SELECT T2.description, COUNT(*) AS company_count
FROM company AS T1
JOIN legal_nature AS T2
ON T1.legal_nature_code = T2.code
JOIN company_size AS T3
ON T1.company_size_code = T3.code
WHERE
T3.description = 'LARGE'
GROUP BY
T2.description
ORDER BY
company_count DESC
LIMIT 5; | SELECT legal_nature.description, COUNT(*) FROM company JOIN legal_nature ON company.legal_nature_code = legal_nature.code JOIN company_size ON company.company_size_code = company_size.code WHERE company_size.description = 'LARGE' GROUP BY legal_nature.description ORDER BY COUNT(*) DESC LIMIT 5 | extra | true | sqliteEN-sample |
For each state, identify the primary economic activity (CNAE) with the highest number of main establishments. For that top activity in each state, calculate the total number of associated companies and their average capital. List the state, the name of the top economic activity, the count of companies, and their averag... | WITH RankedActivities AS (
SELECT
state,
primary_cnae_code,
RANK() OVER (PARTITION BY state ORDER BY COUNT(*) DESC) as rnk
FROM establishment
WHERE main_or_branch = '1'
GROUP BY state, primary_cnae_code
),
TopActivities AS (
SELECT
state,
primary_cnae_code
FROM RankedActivities
WHERE r... | SELECT
establishment.state,
cnae.name,
COUNT(company.basic_cnpj),
AVG(company.capital)
FROM establishment
INNER JOIN cnae
ON establishment.primary_cnae_code = cnae.code
INNER JOIN company
ON establishment.basic_cnpj = company.basic_cnpj
WHERE establishment.main_or_branch = '1'
AND (establishment.state, es... | extra | false | sqliteEN-sample |
For each company size classification, determine which primary business activity (CNAE) boasts the highest average number of partners over the age of 50. Your analysis should be restricted to companies that are currently active, opted for 'SIMPLES' taxation, were founded after 2015, and have a share capital of at least ... | WITH CompanyPartnerCounts AS (
-- First, for each company meeting the criteria, count how many partners are over 50
SELECT
c.company_size_code,
e.primary_cnae_code,
COUNT(p.cpf_or_cnpj) AS older_partner_count
FROM company AS c
JOIN establishment AS e
ON c.basic_cnpj = e.basic_cnpj
JOIN taxatio... | SELECT
company_size.description,
cnae.name,
AVG(CAST(COUNT(partner.cpf_or_cnpj) AS REAL))
FROM (
SELECT
company.company_size_code,
establishment.primary_cnae_code,
AVG(CAST(COUNT(partner.cpf_or_cnpj) AS REAL)),
ROW_NUMBER() OVER (PARTITION BY company.company_size_code ORDER BY AVG(CAST(COUNT(par... | extra | true | sqliteEN-sample |
What is the average capital for companies of each size, considering only those with an 'ATIVA' (active) registration status? | SELECT T2.description, AVG(T1.capital)
FROM company AS T1
INNER JOIN company_size AS T2
ON T1.company_size_code = T2.code
INNER JOIN establishment AS T3
ON T1.basic_cnpj = T3.basic_cnpj
INNER JOIN registration_status AS T4
ON T3.registration_status_code = T4.code
WHERE
T4.description = 'ATIVA'
GROUP BY
T2.des... | SELECT company_size.description, AVG(company.capital)
FROM company
INNER JOIN company_size
ON company.company_size_code = company_size.code
INNER JOIN establishment
ON company.basic_cnpj = establishment.basic_cnpj
INNER JOIN registration_status
ON establishment.registration_status_code = registration_status.code
... | extra | true | sqliteEN-sample |
List the names of all companies, along with their primary CNAE (National Classification of Economic Activities) descriptions, that opted for 'SIMPLES' taxation and started their activities after 2015. | SELECT
c.name AS company_name,
cn.name AS primary_cnae_description
FROM company AS c
JOIN establishment AS e
ON c.basic_cnpj = e.basic_cnpj
JOIN taxation AS t
ON c.basic_cnpj = t.basic_cnpj
JOIN cnae AS cn
ON e.primary_cnae_code = cn.code
WHERE
t.option_for_simples_taxation = 'S' AND e.start_activity_date >... | SELECT company.name, cnae.name FROM company JOIN establishment ON company.basic_cnpj = establishment.basic_cnpj JOIN taxation ON company.basic_cnpj = taxation.basic_cnpj JOIN cnae ON establishment.primary_cnae_code = cnae.code WHERE taxation.option_for_simples_taxation = 'S' AND establishment.start_activity_date > '201... | extra | true | sqliteEN-sample |
What are the top 5 states with the highest number of active business establishments? Provide the state and the count of active establishments for each. | SELECT T1.state, COUNT(*) AS number_of_establishments
FROM establishment AS T1
JOIN registration_status AS T2
ON T1.registration_status_code = T2.code
WHERE
T2.description = 'ATIVA'
GROUP BY
T1.state
ORDER BY
number_of_establishments DESC
LIMIT 5; | SELECT establishment.state, COUNT(*)
FROM establishment
JOIN registration_status
ON establishment.registration_status_code = registration_status.code
WHERE
registration_status.description = 'ATIVA'
GROUP BY
establishment.state
ORDER BY
COUNT(*) DESC
LIMIT 5 | extra | true | sqliteEN-sample |
For each company that has partners with the 'Administrator' qualification, list the company's name and the total count of these partners. | SELECT T1.name, COUNT(*) AS administrator_count
FROM company AS T1
INNER JOIN partner AS T2
ON T1.basic_cnpj = T2.basic_cnpj
INNER JOIN qualification AS T3
ON T2.partner_qualification_code = T3.code
WHERE
T3.description = 'Administrator'
GROUP BY
T1.name; | SELECT company.name, COUNT(*)
FROM company
INNER JOIN partner
ON company.basic_cnpj = partner.basic_cnpj
INNER JOIN qualification
ON partner.partner_qualification_code = qualification.code
WHERE
qualification.description = 'Administrator'
GROUP BY
company.name | extra | true | sqliteEN-sample |
For each state, identify the year with the highest number of newly registered main establishments (headquarters). Then, for each of these peak years, display the state, the peak year itself, the count of new headquarters established in that year, and the name of the most common primary business activity (CNAE) for thos... | WITH EstablishmentCounts AS (
SELECT
state,
CAST(strftime('%Y', start_activity_date) AS INTEGER) AS year_of_activity,
COUNT(basic_cnpj) AS establishment_count
FROM establishment
WHERE
main_or_branch = '1'
GROUP BY
state,
year_of_activity
), RankedYears AS (
SELECT
state,
year_o... | SELECT
T3.state,
T3.year_of_activity,
T3.establishment_count,
cnae.name
FROM (
SELECT
T2.state,
T2.year_of_activity year_of_activity,
T2.establishment_count establishment_count
FROM (
SELECT
T1.state,
T1.year_of_activity,
T1.establishment_count,
RANK() OVER (PARTITION... | extra | true | sqliteEN-sample |
What are the top 3 primary economic activities (by name) for companies classified as 'MICRO COMPANY' that have opted for 'Simples' taxation and have at least one partner whose legal representative is qualified as 'Administrator'? | SELECT T3.name, COUNT(*) AS number_of_companies
FROM establishment AS T1
INNER JOIN company AS T2
ON T1.basic_cnpj = T2.basic_cnpj
INNER JOIN cnae AS T3
ON T1.primary_cnae_code = T3.code
INNER JOIN company_size AS T4
ON T2.company_size_code = T4.code
INNER JOIN taxation AS T5
ON T1.basic_cnpj = T5.basic_cnpj
WH... | SELECT cnae.name, COUNT(*)
FROM establishment
INNER JOIN company
ON establishment.basic_cnpj = company.basic_cnpj
INNER JOIN cnae
ON establishment.primary_cnae_code = cnae.code
INNER JOIN company_size
ON company.company_size_code = company_size.code
INNER JOIN taxation
ON establishment.basic_cnpj = taxation.bas... | extra | true | sqliteEN-sample |
What are the names of companies that are classified as 'LARGE', have a capital of over 1,000,000, and are located in the state of 'SP'? | SELECT
T1.name
FROM company AS T1
INNER JOIN company_size AS T2
ON T1.company_size_code = T2.code
INNER JOIN establishment AS T3
ON T1.basic_cnpj = T3.basic_cnpj
WHERE
T2.description = 'GRANDE' AND T1.capital > 1000000 AND T3.state = 'SP'; | SELECT
company.name
FROM company
INNER JOIN company_size
ON company.company_size_code = company_size.code
INNER JOIN establishment
ON company.basic_cnpj = establishment.basic_cnpj
WHERE
company_size.description = 'GRANDE' AND company.capital > 1000000 AND establishment.state = 'SP' | hard | true | sqliteEN-sample |
What are the top 5 legal natures with the highest average company capital? List the legal nature description and their average capital. | SELECT T2.description, AVG(T1.capital) AS average_capital
FROM company AS T1
JOIN legal_nature AS T2
ON T1.legal_nature_code = T2.code
GROUP BY T2.description
ORDER BY average_capital DESC
LIMIT 5; | SELECT legal_nature.description, AVG(company.capital) FROM company JOIN legal_nature ON company.legal_nature_code = legal_nature.code GROUP BY legal_nature.description ORDER BY AVG(company.capital) DESC LIMIT 5 | extra | true | sqliteEN-sample |
What are the names and capital of the top 5 companies with the company size described as 'MICRO COMPANY', ordered by their capital in descending order? | SELECT T1.name, T1.capital
FROM company AS T1
INNER JOIN company_size AS T2
ON T1.company_size_code = T2.code
WHERE
T2.description = 'MICRO COMPANY'
ORDER BY
T1.capital DESC
LIMIT 5; | SELECT company.name, company.capital FROM company JOIN company_size ON company.company_size_code = company_size.code WHERE company_size.description = 'MICRO COMPANY' ORDER BY company.capital DESC LIMIT 5 | extra | true | sqliteEN-sample |
What are the top 5 most common partner qualifications, along with the count of partners for each qualification? | SELECT T2.description, COUNT(T1.basic_cnpj) AS number_of_partners
FROM partner AS T1
JOIN qualification AS T2
ON T1.partner_qualification_code = T2.code
GROUP BY T2.description
ORDER BY number_of_partners DESC
LIMIT 5; | SELECT qualification.description, COUNT(partner.basic_cnpj)
FROM partner
JOIN qualification
ON partner.partner_qualification_code = qualification.code
GROUP BY qualification.description
ORDER BY COUNT(partner.basic_cnpj) DESC
LIMIT 5 | extra | true | sqliteEN-sample |
What is the average registered capital for each company size? List the company size description along with the corresponding average capital, and sort the results from the highest average capital to the lowest. | SELECT
cs.description,
AVG(c.capital) AS average_capital
FROM company AS c
JOIN company_size AS cs
ON c.company_size_code = cs.code
GROUP BY
cs.description
ORDER BY
average_capital DESC; | SELECT
company_size.description,
AVG(company.capital)
FROM company
JOIN company_size
ON company.company_size_code = company_size.code
GROUP BY
company_size.description
ORDER BY
AVG(company.capital) DESC | hard | true | sqliteEN-sample |
For each legal nature, count the number of companies with an 'Active' registration status. List the description of each legal nature and its corresponding count, ordered from most to least frequent. | SELECT T3.description, COUNT(T1.basic_cnpj) AS count_of_companies
FROM company AS T1
JOIN establishment AS T2
ON T1.basic_cnpj = T2.basic_cnpj
JOIN legal_nature AS T3
ON T1.legal_nature_code = T3.code
JOIN registration_status AS T4
ON T2.registration_status_code = T4.code
WHERE
T4.description = 'ATIVA'
GROUP BY... | SELECT legal_nature.description, COUNT(company.basic_cnpj) FROM company JOIN establishment ON company.basic_cnpj = establishment.basic_cnpj JOIN legal_nature ON company.legal_nature_code = legal_nature.code JOIN registration_status ON establishment.registration_status_code = registration_status.code WHERE registration_... | extra | true | sqliteEN-sample |
Count the number of companies for each company size description. Display the company size description and its corresponding count, ordered from the highest count to the lowest. | SELECT T2.description, COUNT(T1.basic_cnpj) AS company_count
FROM company AS T1
JOIN company_size AS T2
ON T1.company_size_code = T2.code
GROUP BY T2.description
ORDER BY company_count DESC; | SELECT company_size.description, COUNT(company.basic_cnpj) FROM company JOIN company_size ON company.company_size_code = company_size.code GROUP BY company_size.description ORDER BY COUNT(company.basic_cnpj) DESC | hard | true | sqliteEN-sample |
What are the names of all the companies and their respective capital? | SELECT name, capital FROM company; | SELECT company.name, company.capital FROM company | medium | true | sqliteEN-sample |
For companies that opted for 'SIMPLES' taxation after 2010 and are currently 'Active', identify the top 5 primary economic activities (CNAE) that have the highest average number of partners from the '21 to 30 years old' age range. For each of these activities, show the CNAE name, the average number of young partners, a... | WITH FilteredCompanies AS (
SELECT
t.basic_cnpj
FROM
taxation AS t
JOIN
establishment AS e ON t.basic_cnpj = e.basic_cnpj
JOIN
registration_status AS rs ON e.registration_status_code = rs.code
WHERE
t.option_for_simples_taxation = 'S'
AND t.simples_tax... | SELECT
cnae.name,
AVG(COALESCE((SELECT COUNT(partner.cpf_or_cnpj) FROM partner JOIN age_range ON partner.age_range_code = age_range.code WHERE age_range.description = '21 to 30 years' AND partner.basic_cnpj = establishment.basic_cnpj GROUP BY partner.basic_cnpj), 0)),
SUM(company.capital)
FROM
establish... | extra | true | sqliteEN-sample |
Identify the primary business activities (by CNAE name) for companies located in the state of 'SP'. From this group, calculate the average company capital, but only consider companies that satisfy two conditions: they must have at least one partner with the qualification 'SOCIO-ADMINISTRADOR', and they must also have a... | SELECT
T3.name AS primary_activity_name,
AVG(T1.capital) AS average_capital
FROM company AS T1
INNER JOIN establishment AS T2
ON T1.basic_cnpj = T2.basic_cnpj
INNER JOIN cnae AS T3
ON T2.primary_cnae_code = T3.code
WHERE
T2.state = 'SP' AND T1.basic_cnpj IN (SELECT
T1.basic_cnpj
FROM partner AS T1
INN... | SELECT
cnae.name,
AVG(company.capital)
FROM company
INNER JOIN establishment
ON company.basic_cnpj = establishment.basic_cnpj
INNER JOIN cnae
ON establishment.primary_cnae_code = cnae.code
WHERE
establishment.state = 'SP' AND company.basic_cnpj IN (
SELECT
partner.basic_cnpj
FROM partner
INNER JOIN ... | extra | false | sqliteEN-sample |
Show me the names of all companies and their size descriptions. | SELECT T1.name , T2.description FROM company AS T1 JOIN company_size AS T2 ON T1.company_size_code = T2.code | SELECT company.name , company_size.description FROM company JOIN company_size ON company.company_size_code = company_size.code | medium | true | sqliteEN-sample |
How many partners are there for each company that is classified as 'MICRO EMPRESA'? List the company name and its partner count, ordered by the partner count in descending order. | SELECT
T1.name,
COUNT(T3.cpf_or_cnpj)
FROM company AS T1
JOIN company_size AS T2
ON T1.company_size_code = T2.code
JOIN partner AS T3
ON T1.basic_cnpj = T3.basic_cnpj
WHERE
T2.description = 'MICRO EMPRESA'
GROUP BY
T1.name
ORDER BY
COUNT(T3.cpf_or_cnpj) DESC; | SELECT
company.name,
COUNT(partner.cpf_or_cnpj)
FROM company
JOIN company_size
ON company.company_size_code = company_size.code
JOIN partner
ON company.basic_cnpj = partner.basic_cnpj
WHERE
company_size.description = 'MICRO EMPRESA'
GROUP BY
company.name
ORDER BY
COUNT(partner.cpf_or_cnpj) DESC | extra | true | sqliteEN-sample |
For each company size category, identify the most common partner qualification. Then, for this most common qualification, count the number of distinct companies of that size that have at least one partner with that qualification. Display the company size, the most frequent partner qualification, and the corresponding c... | WITH PartnerQualificationFrequency AS (
-- Step 1: Count the occurrences of each partner qualification within each company size.
SELECT
c.company_size_code,
p.partner_qualification_code,
COUNT(*) AS qualification_count
FROM company c
JOIN partner p ON c.basic_cnpj = p.basic_cnpj
... | SELECT
company_size.description,
qualification.description,
COUNT(DISTINCT company.basic_cnpj)
FROM company
JOIN partner
ON company.basic_cnpj = partner.basic_cnpj
JOIN (
SELECT
RankedQualifications.company_size_code,
RankedQualifications.partner_qualification_code
FROM (
SELECT
PartnerQua... | extra | true | sqliteEN-sample |
What is the total number of establishments for each company size, considering only those with an 'ACTIVE' registration status? List the company size description and the count, ordered from most to least numerous. | SELECT
cs.description,
COUNT(e.basic_cnpj) AS number_of_establishments
FROM establishment AS e
JOIN company AS c
ON e.basic_cnpj = c.basic_cnpj
JOIN company_size AS cs
ON c.company_size_code = cs.code
JOIN registration_status AS rs
ON e.registration_status_code = rs.code
WHERE
rs.description = 'ACTIVE'
GROU... | SELECT
company_size.description,
COUNT(establishment.basic_cnpj)
FROM establishment
JOIN company
ON establishment.basic_cnpj = company.basic_cnpj
JOIN company_size
ON company.company_size_code = company_size.code
JOIN registration_status
ON establishment.registration_status_code = registration_status.code
WHE... | extra | true | sqliteEN-sample |
Identify the top 3 primary business activities (by company count) for businesses that meet all the following criteria: are classified as a 'MICRO COMPANY', have opted for 'SIMPLES' taxation, are currently active, and have at least one partner with a qualification of 'Administrator' whose age is over 50. For each of the... | WITH QualifiedCompanies AS (
SELECT
p.basic_cnpj
FROM partner AS p
JOIN qualification AS q
ON p.partner_qualification_code = q.code
JOIN age_range AS a
ON p.age_range_code = a.code
WHERE
q.description = 'Administrator' AND a.code >= 6 -- Assuming age range codes are ordered, and 6 corresponds ... | SELECT
cnae.name,
COUNT(company.basic_cnpj),
AVG(company.capital)
FROM company
JOIN establishment
ON company.basic_cnpj = establishment.basic_cnpj
JOIN cnae
ON establishment.primary_cnae_code = cnae.code
JOIN company_size
ON company.company_size_code = company_size.code
JOIN taxation
ON company.basic_cnpj... | extra | true | sqliteEN-sample |
Count the number of companies for each legal nature that have opted for 'SIMPLES' taxation. Return the legal nature description and the corresponding count, ordered by the count in descending order. | SELECT T3.description, COUNT(*) AS count
FROM taxation AS T1
JOIN company AS T2
ON T1.basic_cnpj = T2.basic_cnpj
JOIN legal_nature AS T3
ON T2.legal_nature_code = T3.code
WHERE
T1.option_for_simples_taxation = 'S'
GROUP BY
T3.description
ORDER BY
count DESC; | SELECT legal_nature.description, COUNT(*)
FROM taxation
JOIN company
ON taxation.basic_cnpj = company.basic_cnpj
JOIN legal_nature
ON company.legal_nature_code = legal_nature.code
WHERE
taxation.option_for_simples_taxation = 'S'
GROUP BY
legal_nature.description
ORDER BY
COUNT(*) DESC | extra | true | sqliteEN-sample |
Of all companies that have opted for 'Simples' taxation and include at least one partner aged 61 or over, which three states have the highest average company capital? For these top three states, provide the state, its average company capital, the total count of such companies, and the description of the most frequently... | WITH QualifyingCompanies AS (
-- First, identify all companies that meet the base criteria: 'Simples' taxation and an elderly partner.
SELECT
e.basic_cnpj,
e.state,
c.capital
FROM establishment AS e
JOIN taxation AS t
ON e.basic_cnpj = t.basic_cnpj
JOIN company AS c
ON e.basic_cnpj = c.bas... | SELECT
(
SELECT
establishment.state
FROM establishment
JOIN taxation
ON establishment.basic_cnpj = taxation.basic_cnpj
JOIN company
ON establishment.basic_cnpj = company.basic_cnpj
WHERE
taxation.option_for_simples_taxation = 'S' AND EXISTS (
SELECT
1
... | extra | true | sqliteEN-sample |
For companies that are currently active, have opted for SIMPLES taxation, and have at least one partner with the 'Sócio-Administrador' (Managing Partner) qualification, what are their primary business activities (CNAE)? List each activity name along with the total count of companies and their average capital, but only ... | WITH QualifiedCompanies AS (
SELECT DISTINCT T1.basic_cnpj
FROM partner AS T1
INNER JOIN qualification AS T2
ON T1.partner_qualification_code = T2.code
INNER JOIN establishment AS T3
ON T1.basic_cnpj = T3.basic_cnpj
INNER JOIN registration_status AS T4
ON T3.registration_status_code = T4.code
IN... | SELECT
cnae.name,
COUNT(company.basic_cnpj),
AVG(company.capital)
FROM company
INNER JOIN establishment
ON company.basic_cnpj = establishment.basic_cnpj
INNER JOIN cnae
ON establishment.primary_cnae_code = cnae.code
WHERE
company.basic_cnpj IN (
SELECT DISTINCT partner.basic_cnpj
FROM partner
IN... | extra | true | sqliteEN-sample |
List the name, capital, and count of qualifying partners for all 'LARGE' companies that have not opted for 'Simples' taxation. A partner qualifies if their legal representative's qualification is 'Director'. Only include companies that have more than one such qualifying partner. | WITH QualifiedPartners AS (
SELECT
p.basic_cnpj,
COUNT(p.cpf_or_cnpj) AS director_rep_count
FROM partner AS p
JOIN qualification AS q
ON p.legal_representative_qualification_code = q.code
WHERE
q.description = 'Diretor'
GROUP BY
p.basic_cnpj
HAVING
COUNT(p.cpf_or_cnpj) > 1
)
SELECT
... | SELECT
company.name,
company.capital,
(
SELECT
COUNT(partner.cpf_or_cnpj)
FROM partner
JOIN qualification
ON partner.legal_representative_qualification_code = qualification.code
WHERE
qualification.description = 'Diretor' AND partner.basic_cnpj = company.basic_cnpj
GROUP BY
... | extra | false | sqliteEN-sample |
For each company size category, count the total number of associated partners. Display the company size description along with the partner count, ordering the results from the size with the most partners to the least. | SELECT
cs.description,
COUNT(p.basic_cnpj) AS partner_count
FROM partner AS p
JOIN company AS c
ON p.basic_cnpj = c.basic_cnpj
JOIN company_size AS cs
ON c.company_size_code = cs.code
GROUP BY
cs.description
ORDER BY
partner_count DESC; | SELECT
company_size.description,
COUNT(partner.basic_cnpj)
FROM partner
JOIN company
ON partner.basic_cnpj = company.basic_cnpj
JOIN company_size
ON company.company_size_code = company_size.code
GROUP BY
company_size.description
ORDER BY
COUNT(partner.basic_cnpj) DESC | extra | true | sqliteEN-sample |
List the names of all companies and their corresponding partners, specifically for partners who are in the '51 to 60 years old' age range. | SELECT
c.name AS company_name,
p.name AS partner_name
FROM company AS c
JOIN partner AS p
ON c.basic_cnpj = p.basic_cnpj
JOIN age_range AS ar
ON p.age_range_code = ar.code
WHERE
ar.description = '51 to 60 years old'; | SELECT
company.name,
partner.name
FROM company
JOIN partner
ON company.basic_cnpj = partner.basic_cnpj
JOIN age_range
ON partner.age_range_code = age_range.code
WHERE
age_range.description = '51 to 60 years old'; | hard | true | sqliteEN-sample |
What are the top 3 cities with the highest average company capital, considering only companies that have at least one managing partner ('SOCIO-ADMINISTRADOR') who is between 61 and 70 years old? | SELECT T3.name, AVG(T1.capital) AS average_capital
FROM company AS T1
INNER JOIN establishment AS T2 ON T1.basic_cnpj = T2.basic_cnpj
INNER JOIN city AS T3 ON T2.city_code = T3.code
WHERE EXISTS (
SELECT 1
FROM partner AS p
INNER JOIN qualification AS q ON p.partner_qualification_code = q.code
INNER JOIN age_ra... | SELECT city.name, AVG(company.capital) FROM company INNER JOIN establishment ON company.basic_cnpj = establishment.basic_cnpj INNER JOIN city ON establishment.city_code = city.code WHERE EXISTS ( SELECT 1 FROM partner INNER JOIN qualification ON partner.partner_qualification_code = qualification.code INNER JOIN age_ran... | extra | false | sqliteEN-sample |
What are the names and capital of all 'LARGE' companies with a capital greater than 50,000,000? Also, show the description of their legal nature. | SELECT T1.name, T1.capital, T3.description
FROM company AS T1
INNER JOIN company_size AS T2
ON T1.company_size_code = T2.code
INNER JOIN legal_nature AS T3
ON T1.legal_nature_code = T3.code
WHERE
T2.description = 'LARGE' AND T1.capital > 50000000; | SELECT company.name, company.capital, legal_nature.description
FROM company
INNER JOIN company_size
ON company.company_size_code = company_size.code
INNER JOIN legal_nature
ON company.legal_nature_code = legal_nature.code
WHERE
company_size.description = 'LARGE' AND company.capital > 50000000 | hard | true | sqliteEN-sample |
For each company legal nature, identify the most common qualification among its partners. Display the legal nature, the most common qualification, and the number of partners with that qualification, considering only companies with a capital greater than zero. | WITH QualificationCounts AS (
SELECT
ln.description AS legal_nature_description,
q.description AS qualification_description,
COUNT(p.basic_cnpj) AS qualification_count,
RANK() OVER (PARTITION BY ln.description ORDER BY COUNT(p.basic_cnpj) DESC) as rnk
FROM partner AS p
JOIN company AS c
ON p.b... | SELECT
T1.1,
T1.2,
T1.3
FROM (
SELECT
legal_nature.description,
qualification.description,
COUNT(partner.basic_cnpj),
RANK() OVER (PARTITION BY legal_nature.description ORDER BY COUNT(partner.basic_cnpj) DESC)
FROM partner
JOIN company
ON partner.basic_cnpj = company.basic_cnpj
JOIN le... | extra | true | sqliteEN-sample |
What are the names and capitals of all companies? | SELECT name, capital FROM company; | SELECT company.name, company.capital FROM company | medium | true | sqliteEN-sample |
For companies established after 2010 that have opted for SIMPLES taxation and include at least one 'Legal Entity' as a partner, calculate the average company capital for each company size. Only include company sizes that contain more than 5 such companies. Additionally, for these filtered company sizes, provide the tot... | WITH EligibleCompanies AS (
-- First, select the companies that meet the initial criteria: date, taxation, and having a legal entity partner
SELECT
c.basic_cnpj,
c.capital,
c.company_size_code
FROM
company c
JOIN
establishment e ON c.basic_cnpj = e.basic_cnpj
... | SELECT
company_size.description,
AVG(company.capital),
COUNT(company.basic_cnpj),
SUM(COALESCE(
(SELECT
COUNT(partner.cpf_or_cnpj)
FROM
partner
JOIN
qualification ON partner.partner_qualification_code = qualification.code
WHERE
qualification.description = 'Qualified Administrator'
AND partner.basic_cnpj = company.basic... | extra | true | sqliteEN-sample |
List the legal nature, total capital, and the count of unique individual partners for each legal nature that has at least 10 'ACTIVE' companies with a capital over 1,000,000 in the state of 'SP'. The total capital should reflect the sum from these qualifying companies, and the partner count should only include partners... | WITH ValidCompanies AS (
SELECT
c.basic_cnpj,
c.capital,
c.legal_nature_code
FROM company AS c
JOIN establishment AS e
ON c.basic_cnpj = e.basic_cnpj
JOIN registration_status AS rs
ON e.registration_status_code = rs.code
WHERE
e.state = 'SP' AND rs.description = 'ACTIVE' AND c.capital ... | SELECT
legal_nature.description,
(
SELECT
SUM(company.capital)
FROM company
JOIN establishment
ON company.basic_cnpj = establishment.basic_cnpj
JOIN registration_status
ON establishment.registration_status_code = registration_status.code
WHERE
establishment.state = 'SP' A... | extra | true | sqliteEN-sample |
For companies classified as 'Sociedade Empresária Limitada', whose primary activity is 'Desenvolvimento de programas de computador sob encomenda', and which initially opted for 'SIMPLES' taxation but were later excluded, what are the top 3 most common qualifications for their partners that are legal entities, consideri... | WITH AvgCapital AS (
SELECT
AVG(c.capital) AS average_capital
FROM company AS c
INNER JOIN legal_nature AS ln
ON c.legal_nature_code = ln.code
WHERE
ln.description = 'Sociedade Empresária Limitada'
), FilteredCompanies AS (
SELECT
c.basic_cnpj
FROM company AS c
INNER JOIN establishment AS ... | SELECT
qualification.description,
COUNT(partner.basic_cnpj)
FROM partner
INNER JOIN company
ON partner.basic_cnpj = company.basic_cnpj
INNER JOIN establishment
ON company.basic_cnpj = establishment.basic_cnpj
INNER JOIN taxation
ON company.basic_cnpj = taxation.basic_cnpj
INNER JOIN cnae
ON establishment.pr... | extra | false | sqliteEN-sample |
What is the number of companies, the average capital, and the count of distinct partner qualification types for each legal nature? Show only legal natures that are associated with companies not classified as 'MICRO EMPRESA', have more than 10 associated companies, and have an average company capital exceeding 500,000. ... | SELECT
ln.description AS legal_nature,
COUNT(DISTINCT c.basic_cnpj) AS num_companies,
AVG(c.capital) AS avg_capital,
COUNT(DISTINCT p.partner_qualification_code) AS distinct_partner_qualifications
FROM company AS c
JOIN legal_nature AS ln
ON c.legal_nature_code = ln.code
JOIN company_size AS cs
ON c.company... | SELECT
legal_nature.description,
COUNT(DISTINCT company.basic_cnpj),
AVG(company.capital),
COUNT(DISTINCT partner.partner_qualification_code)
FROM company
JOIN legal_nature
ON company.legal_nature_code = legal_nature.code
JOIN company_size
ON company.company_size_code = company_size.code
LEFT JOIN partner
... | extra | false | sqliteEN-sample |
What are the names of all companies that have at least one partner with the qualification of 'Administrator'? | SELECT DISTINCT T1.name
FROM company AS T1
INNER JOIN partner AS T2
ON T1.basic_cnpj = T2.basic_cnpj
INNER JOIN qualification AS T3
ON T2.partner_qualification_code = T3.code
WHERE
T3.description = 'Administrator'; | SELECT DISTINCT company.name FROM company INNER JOIN partner ON company.basic_cnpj = partner.basic_cnpj INNER JOIN qualification ON partner.partner_qualification_code = qualification.code WHERE qualification.description = 'Administrator' | hard | true | sqliteEN-sample |
What are the names of companies and their corresponding partners, for all partners who are qualified as 'Socio-Administrador' and are between 41 and 50 years old? | SELECT T2.name, T1.name FROM partner AS T1 INNER JOIN company AS T2 ON T1.basic_cnpj = T2.basic_cnpj INNER JOIN qualification AS T3 ON T1.partner_qualification_code = T3.code INNER JOIN age_range AS T4 ON T1.age_range_code = T4.code WHERE T3.description = 'Socio-Administrador' AND T4.description = 'Entre 41 e 50 anos' | SELECT company.name, partner.name FROM partner INNER JOIN company ON partner.basic_cnpj = company.basic_cnpj INNER JOIN qualification ON partner.partner_qualification_code = qualification.code INNER JOIN age_range ON partner.age_range_code = age_range.code WHERE qualification.description = 'Socio-Administrador' AND age... | extra | true | sqliteEN-sample |
What are the top 5 cities with the most companies classified as 'PORTE GRANDE' (Large Size)? | SELECT T4.name, COUNT(*) AS company_count
FROM company AS T1
JOIN company_size AS T2
ON T1.company_size_code = T2.code
JOIN establishment AS T3
ON T1.basic_cnpj = T3.basic_cnpj
JOIN city AS T4
ON T3.city_code = T4.code
WHERE
T2.description = 'PORTE GRANDE'
GROUP BY
T4.name
ORDER BY
company_count DESC
LIMIT ... | SELECT
city.name,
COUNT(*)
FROM
company
JOIN
company_size ON company.company_size_code = company_size.code
JOIN
establishment ON company.basic_cnpj = establishment.basic_cnpj
JOIN
city ON establishment.city_code = city.code
WHERE
company_size.description = 'PORTE GRANDE'
GROUP BY
city.name
ORDER BY
CO... | extra | true | sqliteEN-sample |
List the top 5 cities with the highest number of registered establishments. Show the city name and the corresponding count of establishments. | SELECT T2.name, COUNT(T1.basic_cnpj) AS number_of_establishments
FROM establishment AS T1
INNER JOIN city AS T2
ON T1.city_code = T2.code
GROUP BY
T2.name
ORDER BY
number_of_establishments DESC
LIMIT 5; | SELECT city.name, COUNT(establishment.basic_cnpj) FROM establishment INNER JOIN city ON establishment.city_code = city.code GROUP BY city.name ORDER BY COUNT(establishment.basic_cnpj) DESC LIMIT 5 | extra | true | sqliteEN-sample |
What are the names of all the companies listed in the database? | SELECT name FROM company; | SELECT company.name FROM company | easy | true | sqliteEN-sample |
For each state, determine the primary business activity (CNAE) that boasts the highest average capital among its associated companies. Then, for this top-performing CNAE in each state, identify the single earliest established company. Your result should show the state, the name of the CNAE, the company's name, its esta... | WITH StateCnaeAvgCapital AS (
-- Step 1: Calculate the average capital for each primary business activity (CNAE) within each state.
-- We only consider active companies (status code 2) with positive capital.
SELECT
e.state,
e.primary_cnae_code,
AVG(c.capital) AS avg_capital
FROM establishment AS e
... | SELECT
T3.state,
cnae.name,
T3.company_name,
T3.start_activity_date,
T3.capital
FROM (
SELECT
establishment.state,
company.name company_name,
company.capital,
establishment.start_activity_date,
establishment.primary_cnae_code,
ROW_NUMBER() OVER (PARTITION BY establishment.state ORDER... | extra | true | sqliteEN-sample |
For each distinct legal nature category, find the single company with the highest capital. For each of these top companies, display their legal nature, name, capital amount, the name of their primary economic activity (CNAE), their state, and the total count of their partners who hold the 'Sócio-Administrador' qualific... | WITH RankedCompanies AS (
SELECT
c.basic_cnpj,
c.name AS company_name,
c.capital,
ln.description AS legal_nature,
e.state,
e.primary_cnae_code,
RANK() OVER (PARTITION BY ln.code ORDER BY c.capital DESC) as capital_rank
FROM company AS c
JOIN legal_nature AS ln
ON c.legal_nature_cod... | SELECT
legal_nature.description,
company.name,
company.capital,
cnae.name,
establishment.state,
COALESCE((
SELECT
COUNT(partner.basic_cnpj)
FROM partner
JOIN qualification
ON partner.partner_qualification_code = qualification.code
WHERE
qualification.description = 'Sócio-Ad... | extra | true | sqliteEN-sample |
For companies established after 2018 that have at least one foreign-domiciled partner, identify the top 5 primary business activities (CNAE names) with the highest average company capital. For each of these activities, show the activity name, the calculated average capital, the number of distinct companies belonging to... | WITH ForeignPartnerCounts AS (
SELECT
T1.basic_cnpj,
COUNT(*) AS num_foreign_partners
FROM partner AS T1
JOIN country AS T2
ON T1.country_code = T2.code
WHERE
T2.name != 'BRASIL'
GROUP BY
T1.basic_cnpj
)
SELECT
T4.name AS primary_activity,
AVG(T3.capital) AS average_capital,
COUNT(DI... | SELECT
cnae.name,
AVG(company.capital),
COUNT(DISTINCT establishment.basic_cnpj),
SUM(
(
SELECT
COUNT(*)
FROM partner
JOIN country
ON partner.country_code = country.code
WHERE
country.name != 'BRASIL' AND partner.basic_cnpj = establishment.basic_cnpj
)
)... | extra | false | sqliteEN-sample |
Identify the top 3 primary economic activities (by CNAE name) with the highest number of 'Active' companies that have at least one partner who is a foreign national. For each of these three activities, show the count of such qualifying companies, their total combined capital, and the count of their unique foreign partn... | WITH ForeignPartnerCompanies AS (
SELECT DISTINCT
e.basic_cnpj,
e.primary_cnae_code
FROM establishment AS e
JOIN registration_status AS rs
ON e.registration_status_code = rs.code
JOIN partner AS p
ON e.basic_cnpj = p.basic_cnpj
JOIN country AS co
ON p.country_code = co.code
WHERE
rs.... | SELECT
cnae.name,
COUNT(DISTINCT establishment.basic_cnpj),
SUM(company.capital),
COUNT(DISTINCT partner.cpf_or_cnpj)
FROM establishment
JOIN registration_status
ON establishment.registration_status_code = registration_status.code
JOIN partner
ON establishment.basic_cnpj = partner.basic_cnpj
JOIN country
... | extra | true | sqliteEN-sample |
List the names of all companies and the descriptions of their respective sizes. | SELECT T1.name, T2.description
FROM company AS T1
JOIN company_size AS T2
ON T1.company_size_code = T2.code; | SELECT company.name, company_size.description FROM company JOIN company_size ON company.company_size_code = company_size.code | medium | true | sqliteEN-sample |
For companies that are located in the city of 'CURITIBA', list the top 3 primary business activities (CNAE) based on the number of establishments, along with the count for each. | SELECT T3.name, COUNT(T1.basic_cnpj) AS number_of_establishments
FROM establishment AS T1
JOIN city AS T2
ON T1.city_code = T2.code
JOIN cnae AS T3
ON T1.primary_cnae_code = T3.code
WHERE T2.name = 'CURITIBA'
GROUP BY T3.name
ORDER BY number_of_establishments DESC
LIMIT 3; | SELECT cnae.name, COUNT(establishment.basic_cnpj)
FROM establishment
JOIN city
ON establishment.city_code = city.code
JOIN cnae
ON establishment.primary_cnae_code = cnae.code
WHERE city.name = 'CURITIBA'
GROUP BY cnae.name
ORDER BY COUNT(establishment.basic_cnpj) DESC
LIMIT 3 | extra | true | sqliteEN-sample |
What are the names of all companies and the description of their respective legal nature? | SELECT T1.name, T2.description
FROM company AS T1
INNER JOIN legal_nature AS T2
ON T1.legal_nature_code = T2.code; | SELECT company.name, legal_nature.description FROM company INNER JOIN legal_nature ON company.legal_nature_code = legal_nature.code | medium | true | sqliteEN-sample |
Among companies that are main establishments, currently active, and opted for the 'SIMPLES' taxation scheme, find the one with the highest capital in each state. For these top companies, list the state, company name, capital, primary CNAE description, the total count of partners who act as legal representatives for som... | WITH PartnerQualificationRank AS (
SELECT
p.basic_cnpj,
q.description AS qualification_description,
ROW_NUMBER() OVER (PARTITION BY p.basic_cnpj ORDER BY COUNT(*) DESC, q.description ASC) AS rn
FROM partner AS p
JOIN qualification AS q
ON p.partner_qualification_code = q.code
GROUP BY
p.basi... | SELECT
T2.state,
T2.name,
T2.capital,
cnae.name,
SUM(CASE WHEN partner.legal_representative_cpf IS NOT NULL THEN 1 ELSE 0 END),
T1.description
FROM (
SELECT
company.basic_cnpj,
company.name,
company.capital,
establishment.state,
establishment.primary_cnae_code,
RANK() OVER (PARTITI... | extra | true | sqliteEN-sample |
For each primary business activity (CNAE), find the company with the highest capital. List the name of the business activity, the name of the top company, and its capital amount. | WITH RankedCompanies AS (
SELECT
c.name AS company_name,
c.capital,
cn.name AS cnae_name,
ROW_NUMBER() OVER (PARTITION BY cn.code ORDER BY c.capital DESC) as rn
FROM company AS c
JOIN establishment AS e
ON c.basic_cnpj = e.basic_cnpj
JOIN cnae AS cn
ON e.primary_cnae_code = cn.code
WHE... | SELECT
cnae.name,
company.name,
company.capital
FROM company
JOIN establishment
ON company.basic_cnpj = establishment.basic_cnpj
JOIN cnae
ON establishment.primary_cnae_code = cnae.code
WHERE company.capital IS NOT NULL
AND (cnae.code, company.capital) IN (
SELECT
cnae.code,
MAX(company.capi... | extra | false | sqliteEN-sample |
What are the names of all the companies registered? | SELECT name FROM company; | SELECT company.name FROM company | easy | true | sqliteEN-sample |
For each state, identify the top 3 primary industries (CNAE) with the highest number of active establishments. For each of these ranked industries, display the state, the industry name, the count of active establishments, and the percentage of those establishments that belong to companies classified as 'MICRO EMPRESA'. | WITH EstablishmentCounts AS (
SELECT
e.state,
e.primary_cnae_code,
COUNT(e.basic_cnpj) AS active_establishment_count,
SUM(CASE WHEN cs.description = 'MICRO EMPRESA' THEN 1 ELSE 0 END) AS micro_empresa_count
FROM
establishment e
JOIN
registration_status rs ON e... | SELECT
T1.state,
cnae.name,
T1.active_establishment_count,
ROUND( ( T1.micro_empresa_count * 100.0 / T1.active_establishment_count ) , 2)
FROM (
SELECT
establishment.state,
establishment.primary_cnae_code,
COUNT(establishment.basic_cnpj) active_establishment_count,
SUM(CASE WHEN company_size.d... | extra | true | sqliteEN-sample |
For each distinct legal nature, identify the most common qualification for a partner's legal representative, but only under a specific set of conditions: the company must have an active registration status, its establishment must be a main branch ('MATRIZ'), it must have opted for SIMPLES taxation, and the partner in q... | WITH RepresentativeQualificationCounts AS (
-- First, join all necessary tables and filter for the specific conditions to count qualifications per legal nature.
SELECT
ln.description AS legal_nature,
q.description AS representative_qualification,
COUNT(p.legal_representative_cpf) AS qual... | SELECT
legal_nature.description,
qualification.description,
COUNT(partner.legal_representative_cpf)
FROM company
JOIN establishment
ON company.basic_cnpj = establishment.basic_cnpj
JOIN partner
ON company.basic_cnpj = partner.basic_cnpj
JOIN taxation
ON company.basic_cnpj = taxation.basic_cnpj
JOIN le... | extra | true | sqliteEN-sample |
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