app.py

import os
import gradio as gr
from openai import OpenAI

# ================= 🔐 安全隐藏区域 =================
# 核心：只读取变量名，绝不在这里写死任何真实的 URL 或 KEY
FREE_LLM_API_URL = os.getenv("FREE_LLM_API_URL")
FREE_LLM_API_KEY = os.getenv("FREE_LLM_API_KEY")

# 启动前做个基础的安全检查（在容器日志中提示，但不会暴露具体内容）
if not FREE_LLM_API_URL or not FREE_LLM_API_KEY:
    print("⚠️ 警告: 环境变量 FREE_LLM_API_URL 或 FREE_LLM_API_KEY 未配置，API 链接可能会失败！")
# ==================================================

# 初始化 OpenAI 客户端（桥接 FreeLLMAPI）
client = OpenAI(
    base_url=FREE_LLM_API_URL,
    api_key=FREE_LLM_API_KEY
)

def predict(message, history):
    # 再次确保密匙存在才执行
    if not client.api_key or not client.base_url:
        yield "❌ 系统未配置 API 密钥，请在平台后台设置 Environment Variables / Secrets。"
        return

    history_openai = []
    for human, ai in history:
        history_openai.append({"role": "user", "content": human})
        history_openai.append({"role": "assistant", "content": ai})
    history_openai.append({"role": "user", "content": message})
    
    try:
        response = client.chat.completions.create(
            model="gemini",
            messages=history_openai,
            stream=True 
        )
        
        partial_message = ""
        for chunk in response:
            if chunk.choices[0].delta.content:
                partial_message = partial_message + chunk.choices[0].delta.content
                yield partial_message
                
    except Exception as e:
        # 安全提示：报错时模糊处理，防止由于报错信息太详细而泄露了敏感的 URL
        yield f"⚠️ 接口连接失败，请检查后台配置。"

# Gradio 界面
demo = gr.ChatInterface(
    fn=predict, 
    title="AI 自动化助手",
    textbox=gr.Textbox(placeholder="请输入内容...", container=False, scale=7)
)

if __name__ == "__main__":
    server_name = os.getenv("GRADIO_SERVER_NAME", "0.0.0.0")
    server_port = int(os.getenv("GRADIO_SERVER_PORT", 7860))
    demo.queue().launch(server_name=server_name, server_port=server_port)