Patent Document

BACKGROUND 
       [0001]    The invention relates to systems and methods for determining the speed of a driven wheel. Specifically, the invention determines the speed of a driven wheel using the speed of a drive shaft and the speed of a second driven wheel, and compensates for timing factors. 
         [0002]    Vehicle systems, such as electronic stability control systems, require knowledge of the speed of each of the wheels of the vehicle. The speed of the wheels needs to be accurately determined in near real time (e.g., every 5 milliseconds). To achieve this, many modern vehicles use wheel speed sensors on each wheel with the sensors hard-wired to the control system or linked via a communication bus. 
       SUMMARY 
       [0003]    In one embodiment, the invention provides a controller. The controller includes a processor and a non-transitory computer readable medium. The processor is configured to receive the speed of a first driven wheel from a wheel speed sensor and the speed of a drive shaft from a drive shaft sensor. The non-transistory computer readable medium includes program instructions executed by the processor for determining a speed of a second driven wheel based on a plurality of detected speeds of the first driven wheel and detected speeds of the drive shaft over time. 
         [0004]    In another embodiment the invention provides a method of determining a speed of a first wheel of a vehicle. The vehicle includes a controller, a differential, a second driven wheel, and a drive shaft. The first and second wheels are driven by the drive shaft. The method includes detecting a speed of the second driven wheel, the second driven wheel driven by the differential, detecting a speed of the drive shaft, the drive shaft driving the differential, transmitting the speed of the second driven wheel to the controller, transmitting the speed of the drive shaft to the controller, compensating for delays in transmission of the speed of the second driven wheel and the drive shaft, compensating for differences in when the speed of the second driven wheel is detected and when the speed of the drive shaft is detected, and determining a speed of the first wheel, using the speed of the second driven wheel, the speed of the drive shaft, and the compensating acts, the first wheel driven by the differential. 
         [0005]    Other aspects of the invention will become apparent by consideration of the detailed description and accompanying drawings. 
     
    
     
       BRIEF DESCRIPTION OF THE DRAWINGS 
         [0006]      FIG. 1  is a block diagram of a vehicle. 
           [0007]      FIG. 2  is a chart showing an actual wheel speed and communication and computation delays. 
           [0008]      FIG. 3  is a chart showing the impact of different update intervals for a plurality of speed sensors on a calculation of a wheel speed. 
           [0009]      FIGS. 4A and 4B  are a schematic of an acceleration model for determining a wheel speed. 
           [0010]      FIG. 5  is an exploded view of an open differential showing various torque transfer values. 
       
    
    
     DETAILED DESCRIPTION 
       [0011]    Before any embodiments of the invention are explained in detail, it is to be understood that the invention is not limited in its application to the details of construction and the arrangement of components set forth in the following description or illustrated in the following drawings. The invention is capable of other embodiments and of being practiced or of being carried out in various ways. 
         [0012]      FIG. 1  shows a block diagram of a vehicle  100 . The vehicle  100  includes a right front wheel  105 , a left front wheel  110 , a right rear wheel  115 , a left rear wheel  120 , an engine  125 , a transmission  130 , a drive shaft  135 , a drive shaft sensor  140 , a differential  145 , a right rear axle  150 , a left rear axle  155 , a right front wheel speed sensor  160 , a left front wheel speed sensor  165 , and a right rear wheel speed sensor  170 . The vehicle  100  also includes a controller  175  (e.g., an electronic stability controller (ESC)) and a communication network  180  (e.g., a controller area network (CAN) bus). In some embodiments, the controller  175  and/or other modules include a processor (e.g., a microprocessor, microcontroller, ASIC, DSP, etc.) and memory (e.g., flash, ROM, RAM, EEPROM, etc.; i.e., a non-transitory computer readable medium), which can be internal to the processor, external to the processor, or both. The processor executes program code stored in the memory. Portions of the invention can be implemented in hardware or software or a combination of both. 
         [0013]    The wheel speed sensors  160 ,  165 , and  170  detect the speed of their respective wheels and communicate that speed to the controller  175 . The speed can be communicated via the communication network  180  or directly (e.g., an analog signal, a PWM signal, etc.). Similarly, the drive shaft speed sensor  140  detects the speed of the drive shaft  135  and communicates that speed to the controller  175 . The differential  145  is driven by the drive shaft  135  and divides the torque between the left and right rear wheels  120  and  115  such that the wheels can turn at different rates. The sum of the speeds of the left and right rear wheels  120  and  115  is two times the speed of the drive shaft  135  (assuming a one to one gear ratio). The controller  175  estimates the speed of one of the driven wheels  115  and  120  as described below (for the description below, the controller  175  estimates the speed of the left rear wheel  120 ). 
         [0014]    The speed of the left rear wheel  120  can be approximated using equation 1 below. Solving for L, the determined speed of the left rear wheel, provides equation 2 below: 
         [0000]        T =( L+R )/2  (eq. 1)
 
         [0000]        L= 2 T−R   (eq. 2)
       where T is the measured speed of the drive shaft  135 , and R is the measured speed of the right rear wheel  115 .       
 
         [0016]    Determining the speed of the left rear wheel  120  using these equations is generally accurate enough for use with anti-lock braking systems which update approximately every 50 msec. However, an ESC system updates approximately every 5 msec. If the measured speeds of the right rear wheel  115  and/or the drive shaft  135  are communicated to the controller  175  via a communications network  180 , the controller  175  receives the measured speeds after a delay exceeding the ESC update time. For example,  FIG. 2  shows delays that were measured in a system using a CAN bus. The CAN bus had a worst case delay in providing the speed information to the controller  175  of 15 msec. In addition, the controller  175  requires time to process the data it receives. In this case, up to an additional 11 msec. The total delay reached 26 msec. A delay of 26 msec is more than five times the update time for the ESC system. 
         [0017]    The error between actual speed of a wheel and the calculated wheel speed (e.g., due to the delays above) can be further exacerbated by differences in the update speeds of the different sensors. For example,  FIG. 3  shows the deviation of the calculated speed of a left rear wheel  120  where the right rear wheel speed sensor updates every 5 msec and the drive shaft speed sensor  140  updates every 7 msec. 
         [0018]    To improve the performance of the system, more accurate determination of the wheel speed is needed. By taking into account past conditions (versus using only the latest readings), models can be developed to accurately estimate wheel speed. 
         [0019]    For an open differential, the speed of a driven left wheel is defined by 
         [0000]        L ( k )=2 T ( k )− R ( k )
 
         [0000]    where:
       k is the control loop cycle,   L(k) is the calculated speed of the left driven wheel at cycle k,   T(k) is the measured transmission output speed at cycle k, and   R(k) is the measured speed of the right driven wheel at cycle k.       
 
         [0024]    Considering errors along with delays in the inputs for T and R, L(k) becomes L(k)=F(T(k), T(k−1) . . . R(k), R(k−1) . . . L(k), L(k−1) . . . other vehicle states) where:
       F is a function of a plurality of input variables.       
 
         [0026]    The invention uses models to estimate the function F. Three methods or models are used: acceleration, Taylor Series, and drivetrain modeling. The acceleration method uses the acceleration of the left driven wheel to estimate the speed of the left driven wheel at cycle k. The following equation is used to perform the estimation: 
         [0000]        L ( k )= L ( k− 1)+ L ′( k− 1)( dt )
 
         [0000]    where:
       L′ is the first derivative of L, and   dt is the cycle time.       
 
         [0029]    The calculations can be smoothed using a weighted average of several past cycles or a filtered value. Empirical vehicle data can also be used to limit a change in the estimated speed of the wheel to an absolute change. Acceleration can also be modeled as discussed below in relation to a drivetrain model.  FIGS. 4A and 4B  show a schematic of an acceleration model  100 . A sensed speed of a right wheel  105  and a sensed speed of a driveshaft  110  are input into the model. As discussed above, the wheel speed sensor xxx and the driveshaft speed sensor xxx update their outputs at different time intervals (e.g., 5 msec for the wheel speed sensor xxx and 7 msec for the driveshaft speed sensor xxx). By using various multipliers  115 , adder/subtractors  120 , and delays  125 , the model  100  is able to compensate for the differences in signal updates. A switch  130  connects a correct signal to an output  135 . The model  100  includes a three additional outputs  140 ,  145 , and  150  for testing purposes. 
         [0030]    A Taylor Series is a representation of a function as an infinite sum of terms calculated from the values of its derivatives at a single point. A Taylor Series for modeling the speed of a left driven wheel takes the form: 
         [0000]        L ( k )= L ( k− 1)+ L ′( k− 1)( dt )/1!+ L ″( k− 1)( dt ) 2 /2!
 
         [0000]    where:
       L′ and L″ are derivatives of L, and   dt is the cycle time.       
 
         [0033]    Again, the calculations can be smoothed using a weighted average of several past cycles or a filtered value. Empirical vehicle data can also be used to limit a change in the estimated speed of the wheel to an absolute change. 
         [0034]    L(k) can also be estimated using various vehicle states including applied brake torque, friction co-efficient, and load on a wheel among others. The vehicle states can be calculated using a drivetrain model. 
         [0035]    An example drivetrain model includes models of the (1) engine and torque converter pump assembly, (2) torque converter turbine and transmission input shaft, (3) transmission output shaft and drive shaft, (4) ring gear of the open differential, (5) torque transfer from the engine to the differential, (6) drive axle torque, and (7) total drive dynamics. 
         [0036]    An engine and torque converter pump assembly model calculates the available torque converter pump output using engine combustion torque. Neglecting the elastic and friction term, the equation of motion can be simplified as: 
         [0000]        T   p   =T   e   −J   e ω e   (eq. 1)
 
         [0000]    where:
       T p  is the torque output at the pump assembly,   T e  is the engine torque resulting from combustion,   J e  is the moment of inertia of the engine crankshaft, flywheel and torque converter pump assembly, and   ω e  is the angular acceleration of the engine crankshaft, flywheel and torque converter pump assembly. In the software, the engine acceleration can be calculated from the engine speed.       
 
         [0041]    Note: elastic, friction, and damping are neglected in the equations. 
         [0042]    A torque converter turbine and transmission input shaft model calculates the available torque at transmission input shaft using: 
         [0000]        T   I   =T   p ƒ(1/ v )− J   I ω I   (eq. 2)
 
         [0000]    where:
       T I  is the torque output at the transmission input shaft,   ω I  is the angular acceleration of the transmission input shaft,   v is the speed ratio for the automatic transmission and is defined as,
           ω I =ω e /v (Note: The above relation is not true for the angular acceleration of the torque converter.),   
           G(1/v) is the torque converter multiplication factor as a function of 1/v, and   J I  is the moment of inertia of the turbine and transmission input shaft.       
 
         [0049]    A transmission output shaft and drive shaft model calculates the available torque at drive shaft from: 
         [0000]        T   d   =T   I   G   tj   −J   d ω d   (eq. 3)
 
         [0000]    where:
       T d  is the available torque at the drive shaft pinion gear,   G tj  is the transmission gear ratio at jth gear,   J d  is the moment of inertia of the drive shaft (include transmission output shaft and its gear set), and   ω d  is the angular acceleration of the transmission output shaft.       
 
         [0054]    The angular acceleration has the following relation: 
         [0000]      ω d =ω I   /G   tj   (eq. 3a)
 
         [0055]    The ring gear of the open differential model calculates the available torque at open differential ring gear using: 
         [0000]        T   rg   =T   d   G   A   −J   rg ω rg   (eq. 4)
 
         [0000]    where:
       T rg  is the available torque at the ring gear (also referred to as Cardan torque).   G A  is the axle ratio,   J rg  is the ring gear assembly moment of inertia, and   ω rg  is the angular acceleration of the ring gear (also referred to as Cardan acceleration).       
 
         [0060]    The speed relation among ring gear, drive shaft and wheel speed is: 
         [0000]      ω rg =ω d   /G   A =(ω AR +ω AL )/2  (eq. 4a)
 
         [0000]    where:
       ω AR  is right driven axle acceleration, and   ω AL  is left driven axle acceleration.       
 
         [0063]      FIG. 5  shows the location of the torque transfer variables in an open differential. 
         [0064]    A torque transfer from engine to differential model calculates the available torque at the ring gear. The available torque at the ring gear can be described by engine combustion torque, engine rotational acceleration, and wheel rotational acceleration (a known variable). 
         [0065]    Substituting torque equations (1), (2) and (3) into equation (4), results in: 
         [0000]        T   rg   ={[T   e   −J   e ω e )ƒ(1/ v )− J   I ω I   ]G   tj   −J   d ω d   }G   A   −J   rg ω rg   (eq. 5)
 
         [0066]    Substituting speed equation (3a) and (4a) into equation 5 and simplifying it results in: 
         [0000]        T   rg =ƒ(1/ v ) G   tj   G   A   T   e −ƒ(1/ v ) G   tj   G   A   J   e ω e   −G   tj   2   G   A   2   J   I (ω AR +ω AL )/2− G   A   2   J   d (ω AR +ω AL )/2− J   rg (ω AR +ω AL )/2  (eq. 5a)
 
         [0000]    where:
       ƒ(1/v)G tj G A T e  is the engine torque amplified by the torque converter, transmission, and axle,   ƒ(1/v)G tj G A J e ω e  is the torque loss due to engine acceleration,   G tj   2 G A   2 J I (ω AR +ω AL )/2 is the torque loss due to transmission input shaft acceleration,   G A   2 J d (ω AR +ω AL )/2 is the torque loss due to transmission output shaft acceleration, and   J rg (ω AR +ω AL )/2 is the torque loss due to ring gear acceleration.       
 
         [0072]    A drive axle torque model calculates the drive axle torque for each drive axle. For an open differential, each drive axle torque is approximately half of the ring gear torque when neglecting torque lost at the spider or similar gear. 
         [0000]        T   AR   ˜T   rg /2˜ TR   R   whl   +T   bR   +J   A ω AR   (eq. 6)
 
         [0000]        T   AL   ˜T   rg /2˜ F   TL   R   whl   +T   bL   +J   A ω AL   (eq. 6a)
 
         [0000]    where:
       T AR  is the right drive axle torque,   T AL  is the left drive axle torque,   T bR  is the right brake torque,   T bL  is the left brake torque,   J A  is the moment of inertia of a single axle and wheel, and   R whl  is the wheel radius.       
 
         [0079]    A total drive dynamics model calculates the available torque at the differential ring gear (Kardan torque): 
         [0000]      G(1/v)GtjGATe−G(11/v)FtjGAJeωe−G tj   2 G A   2 J I (ω AR +ω AL )/2−G A   2 J d (ω AR +ω AL )/2−J rg (ω AR ω AL )/2
 
         [0080]    While the torque consumed at the axle is: 
         [0000]      F TL R whl +T bL +J A ω AL +F TR R whl +T bR +J A ω AR  
 
       Where: 
       [0000]    
       
         
           
             F TL R whl  is drive torque at the left wheel, 
             T bL  is brake torque at the left wheel, 
             J A ω AL  is inertia torque at the left wheel, 
             F TR R whl  is drive torque at the right wheel, 
             T bR  is brake torque at the right wheel, and 
             J A ω AR  is inertia torque at the right wheel. 
           
         
       
     
         [0087]    Simplifying the total drive dynamics model results in: 
         [0000]      [ƒ(1/ v ) G   tj   G   A   ]T   e −[ƒ(1/ v ) G   tj   G   A   ]J   e ω e   −J   A (ω AR +ω AL )˜( F   TL   +F   TR )R whl   +T   bL   +T   bR  
 
         [0000]    where:
       [ƒ(1/v)G tj G A ] is a drivetrain torque multiplication factor,   T e  is engine torque,   J e ω e  is engine acceleration,   (ω AR +ω AL ) is kardan acceleration,   [ƒ(1/v)G tj G A ]T e  is engine torque amplified by the torque converter, transmission and axle,   [ƒ(1/v)G tj G A ]J e ω e  is inertia torque loss at the engine assembly,   J A (ω AR +ω AL ) is inertia torque loss at the wheel assembly,   [ƒ(1/v)G tj G A ]J e ω e −J A (ω AR +ω AL ) is excess torque,   (F TL +F TR )R whl  is total drive torque,   T bL  is brake torque at the left wheel, and   T bR  is brake torque at the right wheel.       
 
         [0099]    Another model of the drivetrain can be represented by a linear system of the form: 
         [0000]        x   1   =Ax+Bu   (eq. 6a)
 
         [0000]      y=Cx (eq. 6b) 
         [0000]    where:
       x is one or more vehicle states (including the relevant wheel speed),   u is one or more system inputs, and   y is one or more measurable vehicle output states that are dependent on x.       
 
         [0103]    A closed loop observer (eqs.  7   a  and  7   b  below) can be constructed to estimate the states of x. The observer estimates the state of x faster than the system operates, allowing any errors to converge to zero. By feeding errors back into the observed and actual vehicle outputs, the system corrects, driving the error to zero. Thus: 
         [0000]      x 2   =Ax   3   +BuL ( y−y   1 )  (eq. 7a)
 
         [0000]      y 1 =Cx 3   (eq. 7b)
 
         [0000]    where:
       x 2  is the estimated vehicle states (from the drivetrain model), and   y 1  is the observer vehicle outputs.       
 
         [0106]    Combining equations  6   a  and  6   b  with  7   a  and  7   b  results in: 
         [0000]        x   1   −x   2   =A ( x−x   3 )− L ( y−y   1 )
 
         [0000]        y−y   1   =C ( x−x   3 ) 
         [0107]    The resulting error between observed and actual vehicle states (including wheel speed) is: 
         [0000]        e =( A−LC ) e   1    
         [0000]    
       
      
       y−y 
       1 
       =Ce 
       1  
      
     
         [0108]    Because these equations have no inputs, (A−LC) can be designed to be solved for any speed. Therefore, (A−LC) is designed to decay the error to zero for initial conditions. The vector L can be obtained and used in the observer (eq. 7a) to solve for the wheel speed. 
         [0109]    The use of the above models enables a speed of a driven wheel to be predicted accurately. This allows a wheel speed sensor to be eliminated saving costs while improving the performance of systems that use the wheel speed. 
         [0110]    Various features and advantages of the invention are set forth in the following claims.

Technology Category: 7