lucyknada/maldv_Loqwqtus2.5-32B-Instruct-exl2

exl2 quant (measurement.json in main branch)

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check revisions for quants

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GGUF iMat

Loqwqtus 2.5 32B Instruct

Loqwqtus 2.5 32B Instruct is a normalized denoised fourier interpolation of the following models:

output_base_model: "Qwen/QwQ-32B"
output_dtype: "bfloat16"
finetune_merge:
  - { "model": "Qwen/Qwen2.5-32B-Instruct", "base": "Qwen/Qwen2.5-32B", "alpha": 1.0 }
  - { "model": "huihui-ai/QwQ-32B-abliterated", "base": "Qwen/QwQ-32B", "alpha": 0.9 }
  - { "model": "prithivMLmods/Sombrero-QwQ-32B-Elite10-Fixed", "base": "Qwen/QwQ-32B", "alpha": 0.5 }
  - { "model": "EVA-UNIT-01/EVA-Qwen2.5-32B-v0.2", "base": "Qwen/Qwen2.5-32B", "alpha": 0.5 }
  - { "model": "Sao10K/32B-Qwen2.5-Kunou-v1", "base": "Qwen/Qwen2.5-32B-Instruct", "alpha": 0.9 }
  - { "model": "zetasepic/Qwen2.5-32B-Instruct-abliterated-v2", "base": "Qwen/Qwen2.5-32B-Instruct", "alpha": 0.75 }
  - { "model": "Saxo/Linkbricks-Horizon-AI-Avengers-V1-32B", "base": "Qwen/Qwen2.5-32B-Instruct", "alpha": 0.5 }

In other words, all of these models get warped and interpolated in signal space, and then jammed back on top of the base model.

What is this?

This is my first attempt to create a thinker model, in the style of the Qwentile series.

Is it good?

It is a huge overthinker, but it nailed the "If you have one bucket that holds two gallons and another bucket that holds five gallons, how do you fill one of the buckets with exactly 4 gallons?" problem; discovering two solutions and picking the most efficient one.

The following was from a IQ4 NL test:

<think>
Okay, so I need to figure out how to get exactly 4 gallons using a 2-gallon and a 5-gallon bucket. Hmm, let me think. Maybe I should start by filling one of the buckets and then transferring water between them? Let me try to outline the steps.

First, maybe fill the 5-gallon bucket completely. Then pour water from the 5-gallon into the 2-gallon until the 2-gallon is full. That should leave me with 3 gallons in the 5-gallon bucket because 5 minus 2 is 3. Then, I can empty the 2-gallon bucket. Now, I have 3 gallons in the 5-gallon and 0 in the 2-gallon. 

Next, pour the remaining 3 gallons from the 5-gallon into the 2-gallon bucket. The 2-gallon can only take 2 gallons, so after pouring, the 2-gallon will be full, and there will be 1 gallon left in the 5-gallon. Now, empty the 2-gallon again. Now the 2-gallon is empty, and the 5-gallon has 1 gallon. 

Then, pour the 1 gallon from the 5-gallon into the 2-gallon. Now the 2-gallon has 1 gallon, and the 5-gallon is empty. Then fill the 5-gallon completely again. Now, we have 5 gallons in the 5-gallon and 1 gallon in the 2-gallon. 

Now, transfer water from the 5-gallon to the 2-gallon until the 2-gallon is full. Since the 2-gallon already has 1 gallon, it can only take 1 more gallon. So pouring 1 gallon from the 5-gallon into the 2-gallon leaves the 5-gallon with 4 gallons (5 -1 =4). 

That's exactly what we wanted! So the steps are:

1. Fill the 5-gallon bucket.
2. Pour from 5 into 2 until 2 is full (leaves 3 in 5).
3. Empty 2.
4. Pour the remaining 3 from 5 into 2 (now 2 has 2, leaving 1 in 5).
5. Empty 2 again.
6. Pour the 1 from 5 into 2 (so 2 has 1, 5 empty).
7. Fill 5 again.
8. Pour from 5 into 2 until 2 is full (needs 1 more, so 5 gives 1, leaving 4 in 5).

So the 5-gallon bucket now has exactly 4 gallons. Let me check each step again to make sure I didn't make a mistake.

Alternatively, maybe there's a quicker way. Let me see. If I start by filling the 2-gallon first and do something else... Hmm. Let me try that approach.

Start by filling the 2-gallon and pour it into the 5. Then fill the 2 again and pour into the 5 again. The 5 can hold 5 gallons, so after first pour, it has 2, then another 2 makes 4. Oh! Wait, that's simpler.

Wait, if you fill the 2, pour into 5 (now 5 has 2). Then fill 2 again and pour into 5 again. Since 5 can only take 3 more, so after pouring 2 into it, you have 2 + 2 =4. Wait, but the 5-gallon can take up to 5, so adding another 2 would fill it to 4? Wait no, 2+2 is 4, so that's exactly 4 in the 5-gallon. Wait, that seems easier. 

So, is that the case? Let me verify step by step:

1. Fill the 2-gallon bucket.
2. Pour it into the 5-gallon. Now, 5 has 2, 2 has 0.
3. Fill the 2-gallon again.
4. Pour into the 5-gallon until 5 is full. Since 5 can take only 3 more gallons (since it has 2 already), so pouring 3 gallons from the 2 would leave 2 - 3 = negative, which can't be. Wait, so maybe this approach doesn't work? Wait, the 2-gallon has 2, and the 5 has 2. If you pour from the 2 into the 5, the 5 can take 3 more. But since the 2 has only 2, you can pour all 2 into the 5, making 5 have 4, and the 2 is empty. So then that would be 4 in the 5-gallon bucket. Wait, that's even simpler! So the steps would be:

1. Fill 2 into 5 twice. 

Wait, but the first pour from 2 to 5 gives 2, then filling 2 again and pouring into 5 again gives total 4 in the 5, since the second pour would be 2 more. But 5 can take 5, so adding 2 twice would make 4. So that's actually the same as the second approach. 

Wait, so why did I think of the longer method first? Maybe I confused the steps. Let me check again. 

So the first method I thought of was by first filling the 5, pouring into 2, leaving 3, then transferring, etc. But actually the second approach is simpler. 

Wait, but is there a catch here? Because in the second approach, if you pour the 2 into the 5 twice, you can get 4. But let's make sure:

Start with empty buckets. 

Step 1: Fill 2-gallon. (2:2, 5:0)

Step 2: Pour into 5. (2:0, 5:2)

Step 3: Fill 2 again. (2:2, 5:2)

Step 4: Pour into 5 again. 5 can take up to 5, so adding 2 more would make 4. So pouring all 2 into 5 gives (2:0, 5:4). 

That's exactly 4 in the 5-gallon. So that's the solution. Wait, that seems straightforward. 

Hmm, so maybe the first method I thought of was overcomplicating it. But why did I think of that first? Maybe because sometimes you have to do that when the numbers are different. 

Wait, but in this case, since 2 + 2 =4, which is less than 5, you can just pour twice. 

Is there a reason this wouldn't work? Let me check again. 

Yes, if the 5-gallon is empty, you can pour the 2 into it twice, but only if you have enough capacity. Since 2*2=4 which is less than 5, that's okay. 

So in that case, the answer is much simpler. So why did I think of the longer method first? Maybe because in other puzzles where the target is higher than the small bucket's capacity, you need to do the pour and fill steps. 

But in this case, it's possible to do it in fewer steps. 

So the correct answer is: Fill the 2-gallon bucket twice into the 5-gallon, resulting in 4 gallons. 

Wait, but let me confirm once more. 

Alternatively, maybe the problem requires you to end up with the 4 gallons in the 5-gallon bucket, which is exactly what this does. 

So that must be the solution. 

Therefore, the steps are:

1. Fill the 2-gallon bucket.

2. Pour it into the 5-gallon.

3. Fill the 2-gallon again.

4. Pour from the 2-gallon into the 5-gallon until the 5-gallon is full. Since the 5 already has 2, adding 2 more would make it 4, so you pour all 2 into it, resulting in 4 in the 5-gallon. 

Yes, that works. 

Therefore, this is the correct solution. Maybe I overcomplicated it at first, but this seems straightforward. 

Alternatively, another way: if you want 4 in the 2-gallon bucket? But since it's only 2 gallons, that's impossible. So the 4 must be in the 5. 

Hence, the answer is as above. 

So the steps are:

- Fill the 2-gallon twice into the 5-gallon, resulting in 4 gallons in the 5.

I think that's the correct answer.
</think>

To measure exactly 4 gallons using a 2-gallon and a 5-gallon bucket, follow these steps:

1. **Fill the 2-gallon bucket completely.**  
   (2-gallon: 2, 5-gallon: 0)

2. **Pour the water from the 2-gallon into the 5-gallon bucket.**  
   (2-gallon: 0, 5-gallon: 2)

3. **Fill the 2-gallon bucket again.**  
   (2-gallon: 2, 5-gallon: 2)

4. **Pour water from the 2-gallon into the 5-gallon until the 5-gallon is full.**  
   Since the 5-gallon already has 2 gallons, it can only take **3 more gallons**. However, the 2-gallon only has 2 gallons, so you pour all of it into the 5-gallon. This results in:  
   (2-gallon: 0, 5-gallon: **4**)

You now have **exactly 4 gallons** in the 5-gallon bucket. 

**Final Answer:**  
Fill the 2-gallon bucket twice into the 5-gallon bucket, leaving **4 gallons** in the 5-gallon bucket.

Censored

This model is lightly censored by default, but can be easily overridden by tweaking the system prompt.

Citation

If you find our work helpful, feel free to give us a cite.

@misc{loqwqtus2.5-32b-instruct,
    title = {Loqwqtus 2.5 32B Instruct},
    url = {https://huggingface.co/maldv/Loqwqtus2.5-32B-Instruct},
    author = {Praxis Maldevide},
    month = {March},
    year = {2025}
}