query_id
int64
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1.03k
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20 values
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stringlengths
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stringlengths
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difficulty
stringclasses
4 values
0
concert_singer
[ "singer" ]
How many singers do we have?
SELECT count(*) FROM singer
easy
1
concert_singer
[ "singer" ]
What is the total number of singers?
SELECT count(*) FROM singer
easy
2
concert_singer
[ "singer" ]
Show name, country, age for all singers ordered by age from the oldest to the youngest.
SELECT name , country , age FROM singer ORDER BY age DESC
medium
3
concert_singer
[ "singer" ]
What are the names, countries, and ages for every singer in descending order of age?
SELECT name , country , age FROM singer ORDER BY age DESC
medium
4
concert_singer
[ "singer" ]
What is the average, minimum, and maximum age of all singers from France?
SELECT avg(age) , min(age) , max(age) FROM singer WHERE country = 'France'
medium
5
concert_singer
[ "singer" ]
What is the average, minimum, and maximum age for all French singers?
SELECT avg(age) , min(age) , max(age) FROM singer WHERE country = 'France'
medium
6
concert_singer
[ "singer" ]
Show the name and the release year of the song by the youngest singer.
SELECT song_name , song_release_year FROM singer ORDER BY age LIMIT 1
medium
7
concert_singer
[ "singer" ]
What are the names and release years for all the songs of the youngest singer?
SELECT song_name , song_release_year FROM singer ORDER BY age LIMIT 1
medium
8
concert_singer
[ "singer" ]
What are all distinct countries where singers above age 20 are from?
SELECT DISTINCT country FROM singer WHERE age > 20
easy
9
concert_singer
[ "singer" ]
What are the different countries with singers above age 20?
SELECT DISTINCT country FROM singer WHERE age > 20
easy
10
concert_singer
[ "singer" ]
Show all countries and the number of singers in each country.
SELECT country , count(*) FROM singer GROUP BY country
medium
11
concert_singer
[ "singer" ]
How many singers are from each country?
SELECT country , count(*) FROM singer GROUP BY country
medium
12
concert_singer
[ "singer" ]
List all song names by singers above the average age.
SELECT song_name FROM singer WHERE age > (SELECT avg(age) FROM singer)
hard
13
concert_singer
[ "singer" ]
What are all the song names by singers who are older than average?
SELECT song_name FROM singer WHERE age > (SELECT avg(age) FROM singer)
hard
14
concert_singer
[ "stadium" ]
Show location and name for all stadiums with a capacity between 5000 and 10000.
SELECT LOCATION , name FROM stadium WHERE capacity BETWEEN 5000 AND 10000
medium
15
concert_singer
[ "stadium" ]
What are the locations and names of all stations with capacity between 5000 and 10000?
SELECT LOCATION , name FROM stadium WHERE capacity BETWEEN 5000 AND 10000
medium
16
concert_singer
[ "stadium" ]
What is the maximum capacity and the average of all stadiums ?
select max(capacity), average from stadium
medium
17
concert_singer
[ "stadium" ]
What is the average and maximum capacities for all stadiums ?
select avg(capacity) , max(capacity) from stadium
medium
18
concert_singer
[ "stadium" ]
What is the name and capacity for the stadium with highest average attendance?
SELECT name , capacity FROM stadium ORDER BY average DESC LIMIT 1
medium
19
concert_singer
[ "stadium" ]
What is the name and capacity for the stadium with the highest average attendance?
SELECT name , capacity FROM stadium ORDER BY average DESC LIMIT 1
medium
20
concert_singer
[ "concert" ]
How many concerts are there in year 2014 or 2015?
SELECT count(*) FROM concert WHERE YEAR = 2014 OR YEAR = 2015
medium
21
concert_singer
[ "concert" ]
How many concerts occurred in 2014 or 2015?
SELECT count(*) FROM concert WHERE YEAR = 2014 OR YEAR = 2015
medium
22
concert_singer
[ "stadium", "concert" ]
Show the stadium name and the number of concerts in each stadium.
SELECT T2.name , count(*) FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id GROUP BY T1.stadium_id
medium
23
concert_singer
[ "stadium", "concert" ]
For each stadium, how many concerts play there?
SELECT T2.name , count(*) FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id GROUP BY T1.stadium_id
medium
24
concert_singer
[ "stadium", "concert" ]
Show the stadium name and capacity with most number of concerts in year 2014 or after.
SELECT T2.name , T2.capacity FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.year >= 2014 GROUP BY T2.stadium_id ORDER BY count(*) DESC LIMIT 1
extra
25
concert_singer
[ "stadium", "concert" ]
What is the name and capacity of the stadium with the most concerts after 2013 ?
select t2.name , t2.capacity from concert as t1 join stadium as t2 on t1.stadium_id = t2.stadium_id where t1.year > 2013 group by t2.stadium_id order by count(*) desc limit 1
extra
26
concert_singer
[ "concert" ]
Which year has most number of concerts?
SELECT YEAR FROM concert GROUP BY YEAR ORDER BY count(*) DESC LIMIT 1
hard
27
concert_singer
[ "concert" ]
What is the year that had the most concerts?
SELECT YEAR FROM concert GROUP BY YEAR ORDER BY count(*) DESC LIMIT 1
hard
28
concert_singer
[ "stadium", "concert" ]
Show the stadium names without any concert.
SELECT name FROM stadium WHERE stadium_id NOT IN (SELECT stadium_id FROM concert)
hard
29
concert_singer
[ "stadium", "concert" ]
What are the names of the stadiums without any concerts?
SELECT name FROM stadium WHERE stadium_id NOT IN (SELECT stadium_id FROM concert)
hard
30
concert_singer
[ "singer" ]
Show countries where a singer above age 40 and a singer below 30 are from.
SELECT country FROM singer WHERE age > 40 INTERSECT SELECT country FROM singer WHERE age < 30
hard
31
concert_singer
[ "stadium", "concert" ]
Show names for all stadiums except for stadiums having a concert in year 2014.
SELECT name FROM stadium EXCEPT SELECT T2.name FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.year = 2014
hard
32
concert_singer
[ "stadium", "concert" ]
What are the names of all stadiums that did not have a concert in 2014?
SELECT name FROM stadium EXCEPT SELECT T2.name FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.year = 2014
hard
33
concert_singer
[ "concert", "singer_in_concert" ]
Show the name and theme for all concerts and the number of singers in each concert.
SELECT T2.concert_name , T2.theme , count(*) FROM singer_in_concert AS T1 JOIN concert AS T2 ON T1.concert_id = T2.concert_id GROUP BY T2.concert_id
medium
34
concert_singer
[ "concert", "singer_in_concert" ]
What are the names , themes , and number of singers for every concert ?
select t2.concert_name , t2.theme , count(*) from singer_in_concert as t1 join concert as t2 on t1.concert_id = t2.concert_id group by t2.concert_id
medium
35
concert_singer
[ "singer", "singer_in_concert" ]
List singer names and number of concerts for each singer.
SELECT T2.name , count(*) FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id GROUP BY T2.singer_id
medium
36
concert_singer
[ "singer", "singer_in_concert" ]
What are the names of the singers and number of concerts for each person?
SELECT T2.name , count(*) FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id GROUP BY T2.singer_id
medium
37
concert_singer
[ "singer", "concert", "singer_in_concert" ]
List all singer names in concerts in year 2014.
SELECT T2.name FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id JOIN concert AS T3 ON T1.concert_id = T3.concert_id WHERE T3.year = 2014
hard
38
concert_singer
[ "singer", "concert", "singer_in_concert" ]
What are the names of the singers who performed in a concert in 2014?
SELECT T2.name FROM singer_in_concert AS T1 JOIN singer AS T2 ON T1.singer_id = T2.singer_id JOIN concert AS T3 ON T1.concert_id = T3.concert_id WHERE T3.year = 2014
hard
39
concert_singer
[ "singer" ]
what is the name and nation of the singer who have a song having 'Hey' in its name?
SELECT name , country FROM singer WHERE song_name LIKE '%Hey%'
medium
40
concert_singer
[ "singer" ]
What is the name and country of origin of every singer who has a song with the word 'Hey' in its title?
SELECT name , country FROM singer WHERE song_name LIKE '%Hey%'
medium
41
concert_singer
[ "stadium", "concert" ]
Find the name and location of the stadiums which some concerts happened in the years of both 2014 and 2015.
SELECT T2.name , T2.location FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.Year = 2014 INTERSECT SELECT T2.name , T2.location FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.Year = 2015
extra
42
concert_singer
[ "stadium", "concert" ]
What are the names and locations of the stadiums that had concerts that occurred in both 2014 and 2015?
SELECT T2.name , T2.location FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.Year = 2014 INTERSECT SELECT T2.name , T2.location FROM concert AS T1 JOIN stadium AS T2 ON T1.stadium_id = T2.stadium_id WHERE T1.Year = 2015
extra
43
concert_singer
[ "stadium", "concert" ]
Find the number of concerts happened in the stadium with the highest capacity .
select count(*) from concert where stadium_id = (select stadium_id from stadium order by capacity desc limit 1)
hard
44
concert_singer
[ "stadium", "concert" ]
What are the number of concerts that occurred in the stadium with the largest capacity ?
select count(*) from concert where stadium_id = (select stadium_id from stadium order by capacity desc limit 1)
hard
45
pets_1
[ "pets" ]
Find the number of pets whose weight is heavier than 10.
SELECT count(*) FROM pets WHERE weight > 10
easy
46
pets_1
[ "pets" ]
How many pets have a greater weight than 10?
SELECT count(*) FROM pets WHERE weight > 10
easy
47
pets_1
[ "pets" ]
Find the weight of the youngest dog.
SELECT weight FROM pets ORDER BY pet_age LIMIT 1
medium
48
pets_1
[ "pets" ]
How much does the youngest dog weigh?
SELECT weight FROM pets ORDER BY pet_age LIMIT 1
medium
49
pets_1
[ "pets" ]
Find the maximum weight for each type of pet. List the maximum weight and pet type.
SELECT max(weight) , petType FROM pets GROUP BY petType
medium
50
pets_1
[ "pets" ]
List the maximum weight and type for each type of pet.
SELECT max(weight) , petType FROM pets GROUP BY petType
medium
51
pets_1
[ "has_pet", "student" ]
Find number of pets owned by students who are older than 20.
SELECT count(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.age > 20
medium
52
pets_1
[ "has_pet", "student" ]
How many pets are owned by students that have an age greater than 20?
SELECT count(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.age > 20
medium
53
pets_1
[ "has_pet", "pets", "student" ]
Find the number of dog pets that are raised by female students (with sex F).
SELECT count(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T2.petid = T3.petid WHERE T1.sex = 'F' AND T3.pettype = 'dog'
hard
54
pets_1
[ "has_pet", "pets", "student" ]
How many dog pets are raised by female students?
SELECT count(*) FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T2.petid = T3.petid WHERE T1.sex = 'F' AND T3.pettype = 'dog'
hard
55
pets_1
[ "pets" ]
Find the number of distinct type of pets.
SELECT count(DISTINCT pettype) FROM pets
easy
56
pets_1
[ "pets" ]
How many different types of pet are there?
SELECT count(DISTINCT pettype) FROM pets
easy
57
pets_1
[ "has_pet", "pets", "student" ]
Find the first name of students who have cat or dog pet.
SELECT DISTINCT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' OR T3.pettype = 'dog'
extra
58
pets_1
[ "has_pet", "pets", "student" ]
What are the first names of every student who has a cat or dog as a pet?
SELECT DISTINCT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' OR T3.pettype = 'dog'
extra
59
pets_1
[ "has_pet", "pets", "student" ]
Find the first name of students who have both cat and dog pets .
select t1.fname from student as t1 join has_pet as t2 on t1.stuid = t2.stuid join pets as t3 on t3.petid = t2.petid where t3.pettype = 'cat' intersect select t1.fname from student as t1 join has_pet as t2 on t1.stuid = t2.stuid join pets as t3 on t3.petid = t2.petid where t3.pettype = 'dog'
extra
60
pets_1
[ "has_pet", "pets", "student" ]
What are the students' first names who have both cats and dogs as pets?
SELECT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat' INTERSECT SELECT T1.Fname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'dog'
extra
61
pets_1
[ "has_pet", "pets", "student" ]
Find the major and age of students who do not have a cat pet.
SELECT major , age FROM student WHERE stuid NOT IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat')
extra
62
pets_1
[ "has_pet", "pets", "student" ]
What major is every student who does not own a cat as a pet, and also how old are they?
SELECT major , age FROM student WHERE stuid NOT IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat')
extra
63
pets_1
[ "has_pet", "pets", "student" ]
Find the id of students who do not have a cat pet.
SELECT stuid FROM student EXCEPT SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat'
hard
64
pets_1
[ "has_pet", "pets", "student" ]
What are the ids of the students who do not own cats as pets?
SELECT stuid FROM student EXCEPT SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat'
hard
65
pets_1
[ "has_pet", "pets", "student" ]
Find the first name and age of students who have a dog but do not have a cat as a pet.
SELECT T1.fname , T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'dog' AND T1.stuid NOT IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat')
extra
66
pets_1
[ "has_pet", "pets", "student" ]
What is the first name of every student who has a dog but does not have a cat?
SELECT T1.fname , T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'dog' AND T1.stuid NOT IN (SELECT T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pettype = 'cat')
extra
67
pets_1
[ "pets" ]
Find the type and weight of the youngest pet.
SELECT pettype , weight FROM pets ORDER BY pet_age LIMIT 1
medium
68
pets_1
[ "pets" ]
What type of pet is the youngest animal, and how much does it weigh?
SELECT pettype , weight FROM pets ORDER BY pet_age LIMIT 1
medium
69
pets_1
[ "pets" ]
Find the id and weight of all pets whose age is older than 1.
SELECT petid , weight FROM pets WHERE pet_age > 1
medium
70
pets_1
[ "pets" ]
What is the id and weight of every pet who is older than 1?
SELECT petid , weight FROM pets WHERE pet_age > 1
medium
71
pets_1
[ "pets" ]
Find the average and maximum age for each type of pet.
SELECT avg(pet_age) , max(pet_age) , pettype FROM pets GROUP BY pettype
medium
72
pets_1
[ "pets" ]
What is the average and maximum age for each pet type?
SELECT avg(pet_age) , max(pet_age) , pettype FROM pets GROUP BY pettype
medium
73
pets_1
[ "pets" ]
Find the average weight for each pet type.
SELECT avg(weight) , pettype FROM pets GROUP BY pettype
medium
74
pets_1
[ "pets" ]
What is the average weight for each type of pet?
SELECT avg(weight) , pettype FROM pets GROUP BY pettype
medium
75
pets_1
[ "has_pet", "student" ]
Find the first name and age of students who have a pet.
SELECT DISTINCT T1.fname , T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid
medium
76
pets_1
[ "has_pet", "student" ]
What are the different first names and ages of the students who do have pets?
SELECT DISTINCT T1.fname , T1.age FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid
medium
77
pets_1
[ "has_pet", "student" ]
Find the id of the pet owned by student whose last name is ‘Smith’.
SELECT T2.petid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.Lname = 'Smith'
medium
78
pets_1
[ "has_pet", "student" ]
What is the id of the pet owned by the student whose last name is 'Smith'?
SELECT T2.petid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid WHERE T1.Lname = 'Smith'
medium
79
pets_1
[ "has_pet", "student" ]
Find the number of pets for each student who has any pet and student id.
SELECT count(*) , T1.stuid FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid GROUP BY T1.stuid
medium
80
pets_1
[ "has_pet", "student" ]
For students who have pets , how many pets does each student have ? list their ids instead of names .
select count(*) , t1.stuid from student as t1 join has_pet as t2 on t1.stuid = t2.stuid group by t1.stuid
medium
81
pets_1
[ "has_pet", "student" ]
Find the first name and gender of student who have more than one pet.
SELECT T1.fname , T1.sex FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid GROUP BY T1.stuid HAVING count(*) > 1
medium
82
pets_1
[ "has_pet", "student" ]
What is the first name and gender of the all the students who have more than one pet?
SELECT T1.fname , T1.sex FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid GROUP BY T1.stuid HAVING count(*) > 1
medium
83
pets_1
[ "has_pet", "pets", "student" ]
Find the last name of the student who has a cat that is age 3.
SELECT T1.lname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pet_age = 3 AND T3.pettype = 'cat'
hard
84
pets_1
[ "has_pet", "pets", "student" ]
What is the last name of the student who has a cat that is 3 years old?
SELECT T1.lname FROM student AS T1 JOIN has_pet AS T2 ON T1.stuid = T2.stuid JOIN pets AS T3 ON T3.petid = T2.petid WHERE T3.pet_age = 3 AND T3.pettype = 'cat'
hard
85
pets_1
[ "has_pet", "student" ]
Find the average age of students who do not have any pet .
select avg(age) from student where stuid not in (select stuid from has_pet)
extra
86
pets_1
[ "has_pet", "student" ]
What is the average age for all students who do not own any pets ?
select avg(age) from student where stuid not in (select stuid from has_pet)
extra
87
car_1
[ "CONTINENTS" ]
How many continents are there?
SELECT count(*) FROM CONTINENTS;
easy
88
car_1
[ "CONTINENTS" ]
What is the number of continents?
SELECT count(*) FROM CONTINENTS;
easy
89
car_1
[ "COUNTRIES", "CONTINENTS" ]
How many countries does each continent have? List the continent id, continent name and the number of countries.
SELECT T1.ContId , T1.Continent , count(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId = T2.Continent GROUP BY T1.ContId;
medium
90
car_1
[ "COUNTRIES", "CONTINENTS" ]
For each continent, list its id, name, and how many countries it has?
SELECT T1.ContId , T1.Continent , count(*) FROM CONTINENTS AS T1 JOIN COUNTRIES AS T2 ON T1.ContId = T2.Continent GROUP BY T1.ContId;
medium
91
car_1
[ "COUNTRIES" ]
How many countries are listed?
SELECT count(*) FROM COUNTRIES;
easy
92
car_1
[ "COUNTRIES" ]
How many countries exist?
SELECT count(*) FROM COUNTRIES;
easy
93
car_1
[ "MODEL_LIST", "CAR_MAKERS" ]
How many models does each car maker produce? List maker full name, id and the number.
SELECT T1.FullName , T1.Id , count(*) FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id;
medium
94
car_1
[ "MODEL_LIST", "CAR_MAKERS" ]
What is the full name of each car maker, along with its id and how many models it produces?
SELECT T1.FullName , T1.Id , count(*) FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker GROUP BY T1.Id;
medium
95
car_1
[ "CARS_DATA", "CAR_NAMES" ]
Which model of the car has the minimum horsepower?
SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id ORDER BY T2.horsepower ASC LIMIT 1;
hard
96
car_1
[ "CARS_DATA", "CAR_NAMES" ]
What is the model of the car with the smallest amount of horsepower?
SELECT T1.Model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id ORDER BY T2.horsepower ASC LIMIT 1;
hard
97
car_1
[ "CAR_NAMES", "CARS_DATA" ]
Find the model of the car whose weight is below the average weight.
SELECT T1.model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.Weight < (SELECT avg(Weight) FROM CARS_DATA)
extra
98
car_1
[ "CAR_NAMES", "CARS_DATA" ]
What is the model for the car with a weight smaller than the average?
SELECT T1.model FROM CAR_NAMES AS T1 JOIN CARS_DATA AS T2 ON T1.MakeId = T2.Id WHERE T2.Weight < (SELECT avg(Weight) FROM CARS_DATA)
extra
99
car_1
[ "CAR_NAMES", "MODEL_LIST", "CAR_MAKERS", "CARS_DATA" ]
Find the name of the makers that produced some cars in the year of 1970?
SELECT DISTINCT T1.Maker FROM CAR_MAKERS AS T1 JOIN MODEL_LIST AS T2 ON T1.Id = T2.Maker JOIN CAR_NAMES AS T3 ON T2.model = T3.model JOIN CARS_DATA AS T4 ON T3.MakeId = T4.id WHERE T4.year = '1970';
extra

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