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var_a = 9 var_b = 6 var_c = var_a * var_b var_d = 5 var_e = var_c + var_d print(int(var_e))

59

59

9 6 [OP_MUL] 5 [OP_ADD]

var_a = 9 var_b = 6 var_c = var_a * var_b var_d = 5 var_e = var_c + var_d print(int(var_e))

9 6 [OP_MUL] 5 [OP_ADD]

For the natural number A, the quotient of A divided by 9 is 6 and the remainder is 5. What is the value of A?

자연수 A에 대해 9로 나눈 몫은 6, 나머지는 5입니다. A의 값은 무엇일까요?

Correspondence

var_a = 1 var_b = 80 var_c = 1 var_d = var_b - var_c var_e = 1 list_a = [i for i in range(var_a, var_d + 1, var_e)] var_f = 9 list_b = [] var_f = int(var_f) for i in list_a: i = int(i) if i % var_f == 0: list_b.append(i) list_b = [float(i) for i in list_b] var_g = sum(list_b) print(int(var_g))

324

324

1 80 1 [OP_SUB] 1 [OP_LIST_ARANGE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_SUM]

var_a = 1 var_b = 80 var_c = 1 var_d = var_b - var_c var_e = 1 list_a = [i for i in range(var_a, var_d + 1, var_e)] var_f = 9 list_b = [] var_f = int(var_f) for i in list_a: i = int(i) if i % var_f == 0: list_b.append(i) list_b = [float(i) for i in list_b] var_g = sum(list_b) print(int(var_g))

1 80 1 [OP_SUB] 1 [OP_LIST_ARANGE] 9 [OP_LIST_DIVISIBLE] [OP_LIST_SUM]

Find the sum of all multiples of 9 that are less than 80.

80보다 작은 수 중에서 9의 배수의 총합을 구하시오.

Arithmetic calculation

var_a = 1 var_b = 6 var_c = 8 list_a= [] if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_d = 3 list_b = [str(i) for i in list_a] list_b = list(itertools.permutations(list_b, var_d)) list_b = [''.join(num_list) for num_list in list_b] list_b = [str_num for str_num in list_b if str_num[0] != '0'] list_b = [float(i) for i in list_b] var_e = 2 list_c=list_b.copy() list_c.sort() var_f = list_c[var_e-1] var_g = 3 list_d=list_b.copy() list_d.sort() var_h = list_d[var_g-1] var_i = var_f + var_h print(int(var_i))

804

804

[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MIN] 3 [OP_LIST_MIN] [OP_ADD]

var_a = 1 var_b = 6 var_c = 8 list_a= [] if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_d = 3 list_b = [str(i) for i in list_a] list_b = list(itertools.permutations(list_b, var_d)) list_b = [''.join(num_list) for num_list in list_b] list_b = [str_num for str_num in list_b if str_num[0] != '0'] list_b = [float(i) for i in list_b] var_e = 2 list_c=list_b.copy() list_c.sort() var_f = list_c[var_e-1] var_g = 3 list_d=list_b.copy() list_d.sort() var_h = list_d[var_g-1] var_i = var_f + var_h print(int(var_i))

[OP_LIST_SOL] 1 6 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 2 [OP_LIST_MIN] 3 [OP_LIST_MIN] [OP_ADD]

Dongju selects a piece of paper with a number written on it, and wants to make a three-digit number by placing the first selected number in the hundreds place, the second selected in the tens place, and the third selected in the units place. If the numbers written on each paper was 1, 6, and 8, respectively, find the sum of the second smallest and third smallest three-digit numbers that Dongju can make. However, you cannot select the same numbered paper multiple times.

동주는 숫자가 적힌 쪽지를 뽑아, 처음 뽑은 것을 백의 자리, 두 번째는 십의 자리, 세 번째는 일의 자리로 하여 세 자리수를 만들고자 한다. 쪽지는 1, 6, 8이 있을 때, 동주가 만들 수 있는 두 번째로 작은 수와 세 번째로 작은 세 자리수의 합을 구하시오. 단, 같은 쪽지를 여러 번 뽑을 수 없다.

Possibility

var_a = 1 var_b = 2 var_c = 6 var_d = 8 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_e = 4 list_b = [str(i) for i in list_a] list_b = list(itertools.permutations(list_b, var_e)) list_b = [''.join(num_list) for num_list in list_b] list_b = [str_num for str_num in list_b if str_num[0] != '0'] list_b = [float(i) for i in list_b] var_f = 2 list_c=list_b.copy() list_c.sort() var_g = list_c[-var_f] var_h = 3 list_d=list_b.copy() list_d.sort() var_i = list_d[var_h-1] var_j = var_g + var_i print(int(var_j))

10240

10240

[OP_LIST_SOL] 1 2 6 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]

var_a = 1 var_b = 2 var_c = 6 var_d = 8 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_e = 4 list_b = [str(i) for i in list_a] list_b = list(itertools.permutations(list_b, var_e)) list_b = [''.join(num_list) for num_list in list_b] list_b = [str_num for str_num in list_b if str_num[0] != '0'] list_b = [float(i) for i in list_b] var_f = 2 list_c=list_b.copy() list_c.sort() var_g = list_c[-var_f] var_h = 3 list_d=list_b.copy() list_d.sort() var_i = list_d[var_h-1] var_j = var_g + var_i print(int(var_j))

[OP_LIST_SOL] 1 2 6 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 2 [OP_LIST_MAX] 3 [OP_LIST_MIN] [OP_ADD]

Among the numbers that you can make using all of the numbers 1, 2, 6, and 8 once each, find the sum of the second largest four-digit number and the third smallest four-digit number.

숫자 1, 2, 6, 8을 한 번씩 모두 사용하여 두 번째로 큰 네 자리 수와 세 번째로 작은 네 자리수의 합을 구하시오.

Possibility

var_a = 10 var_b = 10 var_c = 3 var_d = var_b - var_c var_e = var_a * var_d var_f = 2 var_g = var_e / var_f print(int(var_g))

35

35

10 10 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]

var_a = 10 var_b = 10 var_c = 3 var_d = var_b - var_c var_e = var_a * var_d var_f = 2 var_g = var_e / var_f print(int(var_g))

10 10 3 [OP_SUB] [OP_MUL] 2 [OP_DIV]

How many diagonals can you draw in a decagon?

십각형 내에 그릴 수 있는 대각선의 개수는?

Geometry

var_a = 12 var_b = 2 var_c = var_a * var_b print(int(var_c))

24

24

12 2 [OP_MUL]

var_a = 12 var_b = 2 var_c = var_a * var_b print(int(var_c))

12 2 [OP_MUL]

The length of one span of Jinseo is about 12 centimeters (cm). When Jinseo measured the length of the shorter side of the bookshelf, it was about two spans. How many centimeters (cm) is the short side of the bookshelf?

진서의 한 뼘의 길이는 약 12센티미터(㎝)입니다. 진서가 책꽂이의 짧은 쪽의 길이를 재었더니 뼘으로 2번이었습니다. 책꽂이의 짧은 쪽의 길이는 약 몇 센티미터(㎝)입니까?

Arithmetic calculation

var_a = 2 var_b = 0 var_c = 3 var_d = 5 var_e = 8 list_a= [] if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_f = 4 list_b = [str(i) for i in list_a] list_b = list(itertools.permutations(list_b, var_f)) list_b = [''.join(num_list) for num_list in list_b] list_b = [str_num for str_num in list_b if str_num[0] != '0'] list_b = [float(i) for i in list_b] var_g = 1 list_c=list_b.copy() list_c.sort() var_h = list_c[-var_g] var_i = 1 list_d=list_b.copy() list_d.sort() var_j = list_d[var_i-1] var_k = var_h - var_j print(int(var_k))

6497

6497

[OP_LIST_SOL] 2 0 3 5 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]

var_a = 2 var_b = 0 var_c = 3 var_d = 5 var_e = 8 list_a= [] if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_f = 4 list_b = [str(i) for i in list_a] list_b = list(itertools.permutations(list_b, var_f)) list_b = [''.join(num_list) for num_list in list_b] list_b = [str_num for str_num in list_b if str_num[0] != '0'] list_b = [float(i) for i in list_b] var_g = 1 list_c=list_b.copy() list_c.sort() var_h = list_c[-var_g] var_i = 1 list_d=list_b.copy() list_d.sort() var_j = list_d[var_i-1] var_k = var_h - var_j print(int(var_k))

[OP_LIST_SOL] 2 0 3 5 8 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_SUB]

What is the difference between the largest number and the smallest number that can be made by selecting four from the number magnets 2, 0, 3, 5, and 8 and arranging them in a row to form a four-digit number?

숫자 자석 2, 0, 3, 5, 8중 4개를 골라 일렬로 배열하여 네 자리 수를 만들 때, 만들 수 있는 수 중 가장 큰 수와 가장 작은 수의 차는 얼마인가?

Possibility

var_a = 41 var_b = 3 var_c = var_a + var_b var_d = 4 var_e = var_c - var_d var_f = 4 var_g = var_e / var_f var_h = 2 var_i = var_g ** var_h var_j = 3 var_k = var_i + var_j print(int(var_k))

103

103

41 3 [OP_ADD] 4 [OP_SUB] 4 [OP_DIV] 2 [OP_POW] 3 [OP_ADD]

var_a = 41 var_b = 3 var_c = var_a + var_b var_d = 4 var_e = var_c - var_d var_f = 4 var_g = var_e / var_f var_h = 2 var_i = var_g ** var_h var_j = 3 var_k = var_i + var_j print(int(var_k))

41 3 [OP_ADD] 4 [OP_SUB] 4 [OP_DIV] 2 [OP_POW] 3 [OP_ADD]

Jiho's classmates are standing on the playground. When the students made a big square by matching the front, back, left, and right spacing, there were 3 people left. It is said that 44 more students are needed to increase each horizontal and vertical side of the square by 2 columns. How many students are in Jiho's class?

지호네 반 학생들이 운동장에 서 있습니다. 학생들이 앞,뒤,좌,우 간격을 맞춰서서 큰 정사각형을 만들었더니 3명이 남았습니다. 만든 정사각형의 가로 한 변과 세로 한 변을 2열씩 늘리려면 41명이 더 필요하다고 합니다. 지호네 반 학생은 모두 몇 명입니까?

Geometry

var_a = 6 var_b = 10 var_c = var_a * var_b var_d = 15 var_e = var_c - var_d print(int(var_e))

45

45

6 10 [OP_MUL] 15 [OP_SUB]

var_a = 6 var_b = 10 var_c = var_a * var_b var_d = 15 var_e = var_c - var_d print(int(var_e))

6 10 [OP_MUL] 15 [OP_SUB]

A number divided by 10 is 6. Yoongi got the result by subtracting 15 from a certain number. What is the result he got?

10으로 어떤 수를 나누었더니 6이 됩니다. 윤기는 어떤 수에서 15를 빼 결과를 얻었습니다. 윤기가 얻은 값은?

Correspondence

var_a = 'A85-2B=364' var_b = 'A' ans_dict = dict() var_a = var_a.replace('×','*') var_a = var_a.replace('x','*') var_a = var_a.replace('÷','/') variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a): if v in variable_candi: ans_dict[v] = 1 candi = list(itertools.product('0123456789', repeat=len(ans_dict))) for c in candi: temp = var_a for i, (k, _) in enumerate(ans_dict.items()): temp = temp.replace(k, str(c[i])) term_list = [] op_list = [] temp_c = '' for tc in temp: if tc not in '+-*/=><().': temp_c += tc else: op_list.append(tc) term_list.append(temp_c) temp_c = '' term_list.append(temp_c) new_eq = '' for i in range(len(op_list)): new_eq += str(int(term_list[i]))+op_list[i] new_eq += str(int(term_list[-1])) if len(new_eq) == len(var_a): new_eq=new_eq.replace('=', '==') new_eq=new_eq.replace('>==', '>=') new_eq=new_eq.replace('<==', '<=') eval_result = False try: eval_result = eval(new_eq) except: pass if eval_result: for i, (k, _) in enumerate(ans_dict.items()): ans_dict[k] = int(c[i]) var_c = ans_dict[var_b] print(int(var_c))

3

3

A85-2B=364 A [OP_DIGIT_UNK_SOLVER]

var_a = 'A85-2B=364' var_b = 'A' ans_dict = dict() var_a = var_a.replace('×','*') var_a = var_a.replace('x','*') var_a = var_a.replace('÷','/') variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a): if v in variable_candi: ans_dict[v] = 1 candi = list(itertools.product('0123456789', repeat=len(ans_dict))) for c in candi: temp = var_a for i, (k, _) in enumerate(ans_dict.items()): temp = temp.replace(k, str(c[i])) term_list = [] op_list = [] temp_c = '' for tc in temp: if tc not in '+-*/=><().': temp_c += tc else: op_list.append(tc) term_list.append(temp_c) temp_c = '' term_list.append(temp_c) new_eq = '' for i in range(len(op_list)): new_eq += str(int(term_list[i]))+op_list[i] new_eq += str(int(term_list[-1])) if len(new_eq) == len(var_a): new_eq=new_eq.replace('=', '==') new_eq=new_eq.replace('>==', '>=') new_eq=new_eq.replace('<==', '<=') eval_result = False try: eval_result = eval(new_eq) except: pass if eval_result: for i, (k, _) in enumerate(ans_dict.items()): ans_dict[k] = int(c[i]) var_c = ans_dict[var_b] print(int(var_c))

A85-2B=364 A [OP_DIGIT_UNK_SOLVER]

A85-2B=364. How much is A?

A85-2B=364입니다. A는 얼마인가요?

Correspondence

var_a = 13 var_b = 28 var_c = 13 var_d = var_b - var_c var_e = 2 var_f = var_d * var_e var_g = var_a + var_f var_h = 2 var_i = 1 var_j = var_h - var_i var_k = var_g / var_j var_l = 28 var_m = var_k - var_l print(int(var_m))

15

15

13 28 13 [OP_SUB] 2 [OP_MUL] [OP_ADD] 2 1 [OP_SUB] [OP_DIV] 28 [OP_SUB]

var_a = 13 var_b = 28 var_c = 13 var_d = var_b - var_c var_e = 2 var_f = var_d * var_e var_g = var_a + var_f var_h = 2 var_i = 1 var_j = var_h - var_i var_k = var_g / var_j var_l = 28 var_m = var_k - var_l print(int(var_m))

13 28 13 [OP_SUB] 2 [OP_MUL] [OP_ADD] 2 1 [OP_SUB] [OP_DIV] 28 [OP_SUB]

This year, the age difference between Minsu and his mother is 28 years old, and after 13 years, the age of his mother will be twice that of Minsu. Find the age of Minsu this year.

올해 민수와 어머니의 나이의 차는 28살이고, 13년 후에는 어머니의 나이가 민수의 나이의 2배가 된다고 한다. 올해 민수의 나이를 구하시오.

Arithmetic calculation

var_a = 43 var_b = 59 var_c = var_a + var_b var_d = 46 var_e = var_c - var_d print(int(var_e))

56

56

43 59 [OP_ADD] 46 [OP_SUB]

var_a = 43 var_b = 59 var_c = var_a + var_b var_d = 46 var_e = var_c - var_d print(int(var_e))

43 59 [OP_ADD] 46 [OP_SUB]

You wanted to subtract 46 from a number, but you accidentally subtract 59 and get 43. How much do you get from the correct calculation?

46을 어떤 수에서 빼야 하는데 실수로 59를 뺐더니 43이 나왔습니다. 바르게 계산한 결과를 구하여라.

Correspondence

var_a = '정희' var_b = '철수' var_c = '은수' var_d = '민준' list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_e = len(list_a) var_f = len(list_a) var_g = 1 var_e = int(var_e) var_f = int(var_f) for i, elem in enumerate(range(var_f)): var_g = var_g * (var_e-i) var_h = '은수' list_b= [] if "/" in str(var_h): var_h = eval(str(var_h)) list_b.append(var_h) list_b.reverse() list_c = list(set(list_a) - set(list_b)) var_i = len(list_c) var_j = len(list_c) var_k = 1 var_i = int(var_i) var_j = int(var_j) for i, elem in enumerate(range(var_j)): var_k = var_k * (var_i-i) var_l = '은수' var_m = '민준' list_d= [] if "/" in str(var_m): var_m = eval(str(var_m)) list_d.append(var_m) if "/" in str(var_l): var_l = eval(str(var_l)) list_d.append(var_l) list_d.reverse() var_n = len(list_d) var_o = len(list_d) var_p = 1 var_n = int(var_n) var_o = int(var_o) for i, elem in enumerate(range(var_o)): var_p = var_p * (var_n-i) var_q = var_k * var_p var_r = var_g - var_q print(int(var_r))

12

12

[OP_LIST_SOL] 정희 철수 은수 민준 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] 은수 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] 은수 민준 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL] [OP_SUB]

var_a = 'Jeonghee' var_b = 'Cheolsu' var_c = 'Eunsu' var_d = 'Minjun' list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_e = len(list_a) var_f = len(list_a) var_g = 1 var_e = int(var_e) var_f = int(var_f) for i, elem in enumerate(range(var_f)): var_g = var_g * (var_e-i) var_h = 'Eunsu' list_b= [] if "/" in str(var_h): var_h = eval(str(var_h)) list_b.append(var_h) list_b.reverse() list_c = list(set(list_a) - set(list_b)) var_i = len(list_c) var_j = len(list_c) var_k = 1 var_i = int(var_i) var_j = int(var_j) for i, elem in enumerate(range(var_j)): var_k = var_k * (var_i-i) var_l = 'Eunsu' var_m = 'Minjun' list_d= [] if "/" in str(var_m): var_m = eval(str(var_m)) list_d.append(var_m) if "/" in str(var_l): var_l = eval(str(var_l)) list_d.append(var_l) list_d.reverse() var_n = len(list_d) var_o = len(list_d) var_p = 1 var_n = int(var_n) var_o = int(var_o) for i, elem in enumerate(range(var_o)): var_p = var_p * (var_n-i) var_q = var_k * var_p var_r = var_g - var_q print(int(var_r))

[OP_LIST_SOL] Jeonghee Cheolsu Eunsu Minjun [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] Eunsu [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_LIST_SOL] Eunsu Minjun [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM] [OP_MUL] [OP_SUB]

Jeonghee, Cheolsu, Eunsu, and Minjun went to the cinema to watch a horror movie. If Eunsu and Minjun, who can't watch horror movies, don't sit next to each other, find the number of cases in which four people sit in a row. (However, there are four seats and all are attached.)

정희, 철수, 은수, 민준 4명이 공포영화를 보러 영화관에 갔다. 이때, 공포영화를 잘 못보는 은수와 민준은 이웃하여 앉지 않는다고 할 때, 네 명이 한 줄로 앉는 경우의 수를 구하시오. (단, 좌석은 네 좌석이며 모두 붙어있다.)

Possibility

var_a = 2 var_b = 2 var_c = var_a * var_b print(int(var_c))

4

4

2 2 [OP_MUL]

var_a = 2 var_b = 2 var_c = var_a * var_b print(int(var_c))

2 2 [OP_MUL]

Three caterpillars came across a forked road. Each caterpillar must choose the path between left and right. Find the number of ways the last caterpillar chooses the left path.

애벌레 3마리가 양갈래 길을 마주했습니다. 각 애벌레는 왼쪽 길과 오른쪽 길 중 하나를 골라야 합니다. 마지막 애벌레가 왼쪽 길을 선택하는 경우의 수를 구하시오.

Possibility

var_a = 7 var_b = 1 var_c = 0 list_a= [] if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_d = len(list_a) list_b = [str(i) for i in list_a] list_b = list(itertools.permutations(list_b, var_d)) list_b = [''.join(num_list) for num_list in list_b] list_b = [str_num for str_num in list_b if str_num[0] != '0'] list_b = [float(i) for i in list_b] var_e = 1 list_c=list_b.copy() list_c.sort() var_f = list_c[-var_e] print(int(var_f))

710

710

[OP_LIST_SOL] 7 1 0 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]

var_a = 7 var_b = 1 var_c = 0 list_a= [] if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_d = len(list_a) list_b = [str(i) for i in list_a] list_b = list(itertools.permutations(list_b, var_d)) list_b = [''.join(num_list) for num_list in list_b] list_b = [str_num for str_num in list_b if str_num[0] != '0'] list_b = [float(i) for i in list_b] var_e = 1 list_c=list_b.copy() list_c.sort() var_f = list_c[-var_e] print(int(var_f))

[OP_LIST_SOL] 7 1 0 [OP_LIST_EOL] [OP_LIST_LEN] [OP_LIST_GET_PERM] 1 [OP_LIST_MAX]

The owner of the snack shop said that for a special occasion, he would give out cookies equal to the three-digit number made by using 1, 7, and 0 all at least once. What number should Haneul make to receive the most sweets?

과자 가게의 사장님이 행사로, 1, 7, 0을 모두 한 번씩 사용해서 만든 세 자리 숫자 만큼 과자를 준다고 했습니다. 하늘이는 어떤 수를 만들어야 과자를 가장 많이 받을 수 있을까요?

Possibility

var_a = 5 var_b = 1 var_c = var_a - var_b print(int(var_c))

4

4

5 1 [OP_SUB]

var_a = 5 var_b = 1 var_c = var_a - var_b print(int(var_c))

5 1 [OP_SUB]

Jungkook is the 5th place. Find the number of people who crossed the finish line faster than Jungkook.

정국이가 5등입니다. 정국이보다 결승선을 빨리 통과한 사람의 수를 구하세요.

Comparison

var_a = 12 var_b = 12 var_c = 4 var_d = var_b + var_c var_e = var_a + var_d var_f = 10 var_g = var_e * var_f var_h = 2 var_i = var_g / var_h print(int(var_i))

140

140

12 12 4 [OP_ADD] [OP_ADD] 10 [OP_MUL] 2 [OP_DIV]

var_a = 12 var_b = 12 var_c = 4 var_d = var_b + var_c var_e = var_a + var_d var_f = 10 var_g = var_e * var_f var_h = 2 var_i = var_g / var_h print(int(var_i))

12 12 4 [OP_ADD] [OP_ADD] 10 [OP_MUL] 2 [OP_DIV]

A parallelogram was cut to form a trapezoid, the lower side being 4 centimeters (cm) longer than the upper side. If the upper side is 12 centimeters (cm) and the height is 10 centimeters (cm), how much is the area of this trapezoid?

어떤 평행사변형을 잘라서 사다리꼴 모양을 만들었는데, 아랫변의 길이가 윗변보다 4센티미터(㎝) 더 길다. 윗변의 길이가 12센티미터(㎝)이고, 높이가 10센티미터(㎝)라면, 이 사다리꼴의 넓이는 몇입니까?

Geometry

var_a = 1 var_b = 3 var_c = 5 var_d = 7 var_e = 9 list_a= [] if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_f = 3 list_b = [str(i) for i in list_a] list_b = list(itertools.product(list_b, repeat=var_f)) list_b = [''.join(num_list) for num_list in list_b] list_b = [str_num for str_num in list_b if str_num[0] != '0'] list_b = [float(i) for i in list_b] var_g = 500 list_c = [] for i in list_b: if i < var_g: list_c.append(i) var_h = 2 list_d=list_c.copy() list_d.sort() var_i = list_d[-var_h] print(int(var_i))

397

397

[OP_LIST_SOL] 1 3 5 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 500 [OP_LIST_LESS] 2 [OP_LIST_MAX]

var_a = 1 var_b = 3 var_c = 5 var_d = 7 var_e = 9 list_a= [] if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_f = 3 list_b = [str(i) for i in list_a] list_b = list(itertools.product(list_b, repeat=var_f)) list_b = [''.join(num_list) for num_list in list_b] list_b = [str_num for str_num in list_b if str_num[0] != '0'] list_b = [float(i) for i in list_b] var_g = 500 list_c = [] for i in list_b: if i < var_g: list_c.append(i) var_h = 2 list_d=list_c.copy() list_d.sort() var_i = list_d[-var_h] print(int(var_i))

[OP_LIST_SOL] 1 3 5 7 9 [OP_LIST_EOL] 3 [OP_LIST_GET_PRODUCT] 500 [OP_LIST_LESS] 2 [OP_LIST_MAX]

There are five cards of numbers 1, 3, 5, 7, and 9. What is the second largest number less than 500 of the three-digit natural numbers that can be created using this card? (However, a card can be used repeatedly.)

1, 3, 5, 7, 9 다섯 장의 숫자카드가 있다. 이 카드를 사용하여 만들 수 있는 3자리 자연수 중 500미만인 수 중 2번째로 큰 값은 얼마인지 구하시오. (단, 카드는 중복사용 가능하다.)

Possibility

var_a = 'A' var_b = 'B' list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 6 var_d = 9 var_e = var_c + var_d var_f = 8 var_g = 8 var_h = var_f + var_g list_b= [] if "/" in str(var_h): var_h = eval(str(var_h)) list_b.append(var_h) if "/" in str(var_e): var_e = eval(str(var_e)) list_b.append(var_e) list_b.reverse() var_i = 1 list_c=list_b.copy() list_c.sort() var_j = list_c[-var_i] var_k = list_b.index(var_j)+1 var_l = list_a[var_k-1] print(var_l)

B

B

[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 6 9 [OP_ADD] 8 8 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]

var_a = 'A' var_b = 'B' list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 6 var_d = 9 var_e = var_c + var_d var_f = 8 var_g = 8 var_h = var_f + var_g list_b= [] if "/" in str(var_h): var_h = eval(str(var_h)) list_b.append(var_h) if "/" in str(var_e): var_e = eval(str(var_e)) list_b.append(var_e) list_b.reverse() var_i = 1 list_c=list_b.copy() list_c.sort() var_j = list_c[-var_i] var_k = list_b.index(var_j)+1 var_l = list_a[var_k-1] print(var_l)

[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 6 9 [OP_ADD] 8 8 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]

Farm A has a rectangular shape measuring 6 kilometers (km) by 9 kilometers (km), and Farm B has a square shape measuring 8 kilometers (km) by 8 km by 8 kilometers (km). The owners of both farms want to build a fence around the perimeter of the farm by putting together wooden planks of the same length. Which farm needs more planks?

A 농장은 가로 6킬로미터(㎞), 세로 9킬로미터(㎞)인 직사각형 모양이고, B 농장은 가로 8킬로미터(㎞), 세로 8킬로미터(㎞)인 정사각형 모양입니다. 두 농장의 주인 모두 같은 길이의 나무판자를 여러 개를 이어 붙여서 농장 둘레를 따라 울타리를 설치하려고 합니다. 어느 농장이 나무판자를 더 많이 필요로 합니까?

Geometry

var_a = 158760 var_b = 140 var_c = var_a / var_b print(int(var_c))

1134

1134

158760 140 [OP_DIV]

var_a = 158760 var_b = 140 var_c = var_a / var_b print(int(var_c))

158760 140 [OP_DIV]

The exchange rate refers to the rate at which one country's currency is exchanged for another country's currency. Soojeong came back from a trip to the U.S. and exchanged the remaining 140 dollars for 158,760 won in Korean money at the bank today. What is the exchange rate of the Korean Won to the US Dollar today?

환율은 자기나라 돈과 다른나라 돈의 교환 비율을 말합니다. 수정이는 미국 여행을 다녀와서 남은 돈 140달러를 오늘 은행에 가서 우리나라 돈 158760원으로 교환 하였습니다. 오늘 미국 돈 달러에 대한 우리나라 돈 원의 환율은 얼마입니까?

Arithmetic calculation

var_a = '지안' var_b = '도윤' var_c = '시우' list_a= [] if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_d = 3 var_e = 5 var_f = 2 list_b= [] if "/" in str(var_f): var_f = eval(str(var_f)) list_b.append(var_f) if "/" in str(var_e): var_e = eval(str(var_e)) list_b.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_b.append(var_d) list_b.reverse() var_g = 2 list_c=list_b.copy() list_c.sort() var_h = list_c[-var_g] var_i = list_b.index(var_h)+1 var_j = list_a[var_i-1] print(var_j)

지안

Jian

[OP_LIST_SOL] 지안 도윤 시우 [OP_LIST_EOL] [OP_LIST_SOL] 3 5 2 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]

var_a = '지안' var_b = '도윤' var_c = '시우' list_a= [] if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_d = 3 var_e = 5 var_f = 2 list_b= [] if "/" in str(var_f): var_f = eval(str(var_f)) list_b.append(var_f) if "/" in str(var_e): var_e = eval(str(var_e)) list_b.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_b.append(var_d) list_b.reverse() var_g = 2 list_c=list_b.copy() list_c.sort() var_h = list_c[-var_g] var_i = list_b.index(var_h)+1 var_j = list_a[var_i-1] print(var_j)

[OP_LIST_SOL] 지안 도윤 시우 [OP_LIST_EOL] [OP_LIST_SOL] 3 5 2 [OP_LIST_EOL] 2 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]

Jian has 3 notebooks in his bag, Doyun has 5 notebooks in his bag, and Siu has 2 notebooks in his bag. Who has the second most notebooks?

지안이 가방에는 공책이 3권, 도윤이 가방에는 공책이 5권, 시우 가방에는 공책이 2권있습니다. 공책이 2번째로 많은 사람은 누구인가요?

Comparison

var_a = 82.04 var_b = 28 var_c = var_a / var_b print('{:.2f}'.format(round(var_c+1e-10,2)))

2.93

2.93

82.04 28 [OP_DIV]

var_a = 82.04 var_b = 28 var_c = var_a / var_b print('{:.2f}'.format(round(var_c+1e-10,2)))

82.04 28 [OP_DIV]

Seungyeon is wrapping the box with ribbon tape. If 28 identical boxes are wrapped with the ribbon tape that is 82.04 meters (m) long and there should be no tape left after wrapping, how many meters (m) of ribbon tape are needed to wrap one box?

승연이는 리본 테이프로 상자를 포장하고 있다. 전체 길이가 82.04미터(m)인 리본 테이프로 똑같은 상자 28개를 포장하고 남은 테이프가 없다고 할 때 한 상자를 포장하는데 몇 미터(m)의 리본테이프를 사용해야하는가?

Correspondence

var_a = '지민' var_b = '윤기' var_c = '태형' var_d = '남준' list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_e = '지민' var_f = '태형' var_g = '>' var_h = '지민' var_i = '남준' var_j = '<' var_k = '윤기' var_l = '남준' var_m = '>' list_b= [] if "/" in str(var_m): var_m = eval(str(var_m)) list_b.append(var_m) if "/" in str(var_l): var_l = eval(str(var_l)) list_b.append(var_l) if "/" in str(var_k): var_k = eval(str(var_k)) list_b.append(var_k) if "/" in str(var_j): var_j = eval(str(var_j)) list_b.append(var_j) if "/" in str(var_i): var_i = eval(str(var_i)) list_b.append(var_i) if "/" in str(var_h): var_h = eval(str(var_h)) list_b.append(var_h) if "/" in str(var_g): var_g = eval(str(var_g)) list_b.append(var_g) if "/" in str(var_f): var_f = eval(str(var_f)) list_b.append(var_f) if "/" in str(var_e): var_e = eval(str(var_e)) list_b.append(var_e) list_b.reverse() global item_name_index_dict items_name_list = list_a.copy() conditions = [] condition_list = list_b.copy() temp_stack = [] for index_, cond_ in enumerate(map(str, condition_list)): if cond_ in ("<", ">", "="): operand_right = temp_stack.pop() operand_left = temp_stack.pop() if cond_ == "=": cond_ = "==" conditions.append(f"{operand_left} {cond_} {operand_right}") else: if not cond_.isdigit(): cond_ = "{" + cond_ + "}" temp_stack.append(cond_) item_name_index_dict = {} for perm in itertools.permutations(range(1, len(items_name_list) + 1)): item_name_index_dict = dict(zip(items_name_list, perm)) formatted_conditions = \ [condition.format_map(item_name_index_dict) for condition in conditions] if all(map(eval, formatted_conditions)): break list_c = list(item_name_index_dict.keys()) list_c.sort(key=item_name_index_dict.get, reverse=True) var_n = len(list_c) var_o = list_c[var_n-1] print(var_o)

태형

Taehyung

[OP_LIST_SOL] 지민 윤기 태형 남준 [OP_LIST_EOL] [OP_LIST_SOL] 지민 태형 > 지민 남준 < 윤기 남준 > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]

var_a = 'Jimin' var_b = 'Yoongi' var_c = 'Taehyung' var_d = 'Namjoon' list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_e = 'Jimin' var_f = 'Taehyung' var_g = '>' var_h = 'Jimin' var_i = 'Namjoon' var_j = '<' var_k = 'Yoongi' var_l = 'Namjoon' var_m = '>' list_b= [] if "/" in str(var_m): var_m = eval(str(var_m)) list_b.append(var_m) if "/" in str(var_l): var_l = eval(str(var_l)) list_b.append(var_l) if "/" in str(var_k): var_k = eval(str(var_k)) list_b.append(var_k) if "/" in str(var_j): var_j = eval(str(var_j)) list_b.append(var_j) if "/" in str(var_i): var_i = eval(str(var_i)) list_b.append(var_i) if "/" in str(var_h): var_h = eval(str(var_h)) list_b.append(var_h) if "/" in str(var_g): var_g = eval(str(var_g)) list_b.append(var_g) if "/" in str(var_f): var_f = eval(str(var_f)) list_b.append(var_f) if "/" in str(var_e): var_e = eval(str(var_e)) list_b.append(var_e) list_b.reverse() global item_name_index_dict items_name_list = list_a.copy() conditions = [] condition_list = list_b.copy() temp_stack = [] for index_, cond_ in enumerate(map(str, condition_list)): if cond_ in ("<", ">", "="): operand_right = temp_stack.pop() operand_left = temp_stack.pop() if cond_ == "=": cond_ = "==" conditions.append(f"{operand_left} {cond_} {operand_right}") else: if not cond_.isdigit(): cond_ = "{" + cond_ + "}" temp_stack.append(cond_) item_name_index_dict = {} for perm in itertools.permutations(range(1, len(items_name_list) + 1)): item_name_index_dict = dict(zip(items_name_list, perm)) formatted_conditions = \ [condition.format_map(item_name_index_dict) for condition in conditions] if all(map(eval, formatted_conditions)): break list_c = list(item_name_index_dict.keys()) list_c.sort(key=item_name_index_dict.get, reverse=True) var_n = len(list_c) var_o = list_c[var_n-1] print(var_o)

[OP_LIST_SOL] Jimin Yoongi Taehyung Namjoon [OP_LIST_EOL] [OP_LIST_SOL] Jimin Taehyung > Jimin Namjoon < Yoongi Namjoon > [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] [OP_LIST_LEN] [OP_LIST_GET]

The four students, Jimin, Yoongi, Taehyung, and Namjoon, are of different ages. Yoongi is older than Namjoon, and Jimin is older than Taehyung but younger than Namjoon. Who is the youngest among the 4 people?

네 학생 지민, 윤기, 태형, 남준이의 나이는 모두 다릅니다. 윤기가 남준이 보다 나이가 많고, 지민이는 태형이보다 나이가 많지만 남준이보다는 적습니다. 4사람 중 가장 어린 사람은 누구입니까?

Comparison

var_a = 3 var_b = 12 var_c = var_a * var_b var_d = 24 var_e = var_c * var_d print(int(var_e))

864

864

3 12 [OP_MUL] 24 [OP_MUL]

var_a = 3 var_b = 12 var_c = var_a * var_b var_d = 24 var_e = var_c * var_d print(int(var_e))

3 12 [OP_MUL] 24 [OP_MUL]

A country has a total of 3 islands. Each island has 12 ships, and each ship has 24 crew members. Find the number of crew members working on all the islands in this country.

어느 나라에 총 3개의 섬이 있습니다. 각 섬에는 12척의 배를 가지고 있고, 각 배마다 일하는 선원의 수는 24명으로 같습니다. 이 나라의 모든 섬에서 일하고 있는 선원의 수를 구하시오.

Comparison

var_a = 1 var_b = 10 var_c = 1 var_d = var_b - var_c var_e = 1 list_a = [i for i in range(var_a, var_d + 1, var_e)] var_f = 3 list_b = [str(i) for i in list_a] list_b = list(itertools.permutations(list_b, var_f)) list_b = [''.join(num_list) for num_list in list_b] list_b = [str_num for str_num in list_b if str_num[0] != '0'] list_b = [float(i) for i in list_b] list_c=[] for i in list_b: var_g = 0 i = int(i) while i//10 > 0: var_g = var_g + i%10 i = i//10 var_g = var_g + i%10 list_c.append(var_g) var_h = 14 list_d = [] for i in list_c: if i <= var_h: list_d.append(i) var_i = 14 list_e = [] for i in list_d: if i >= var_i: list_e.append(i) var_j = len(list_e) print(int(var_j))

48

48

1 10 1 [OP_SUB] 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 14 [OP_LIST_LESS_EQUAL] 14 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]

var_a = 1 var_b = 10 var_c = 1 var_d = var_b - var_c var_e = 1 list_a = [i for i in range(var_a, var_d + 1, var_e)] var_f = 3 list_b = [str(i) for i in list_a] list_b = list(itertools.permutations(list_b, var_f)) list_b = [''.join(num_list) for num_list in list_b] list_b = [str_num for str_num in list_b if str_num[0] != '0'] list_b = [float(i) for i in list_b] list_c=[] for i in list_b: var_g = 0 i = int(i) while i//10 > 0: var_g = var_g + i%10 i = i//10 var_g = var_g + i%10 list_c.append(var_g) var_h = 14 list_d = [] for i in list_c: if i <= var_h: list_d.append(i) var_i = 14 list_e = [] for i in list_d: if i >= var_i: list_e.append(i) var_j = len(list_e) print(int(var_j))

1 10 1 [OP_SUB] 1 [OP_LIST_ARANGE] 3 [OP_LIST_GET_PERM] [OP_LIST_NUM2SUM] 14 [OP_LIST_LESS_EQUAL] 14 [OP_LIST_MORE_EQUAL] [OP_LIST_LEN]

We want to simultaneously draw three different numbers from among the natural numbers less than 10. Find the number of ways in which the sum of three numbers is 14.

10보다 작은 자연수 중에서 서로 다른 세 수를 동시에 뽑으려고 합니다. 세 수의 합이 14인 경우의 수를 구하시오.

Possibility

var_a = 5 var_b = 11 var_c = var_a * var_b var_d = 43 var_e = var_c - var_d var_f = 5 var_g = 1 var_h = var_f - var_g var_i = var_e / var_h print(int(var_i))

3

3

5 11 [OP_MUL] 43 [OP_SUB] 5 1 [OP_SUB] [OP_DIV]

var_a = 5 var_b = 11 var_c = var_a * var_b var_d = 43 var_e = var_c - var_d var_f = 5 var_g = 1 var_h = var_f - var_g var_i = var_e / var_h print(int(var_i))

5 11 [OP_MUL] 43 [OP_SUB] 5 1 [OP_SUB] [OP_DIV]

My mother is 43 years old this year. A few years ago, her age was five times her daughter's age, who is 11 years old this year. Find how many years ago it was.

올해 어머니는 43살입니다. 몇 년 전에는 현재 11살인 딸의 나이에 5를 곱하면 어머니의 나이였습니다. 몇 년 전인지 구하시오.

Arithmetic calculation

var_a = 9 var_b = 4 var_c = var_a * var_b var_d = 7 var_e = var_c * var_d print(int(var_e))

252

252

9 4 [OP_MUL] 7 [OP_MUL]

var_a = 9 var_b = 4 var_c = var_a * var_b var_d = 7 var_e = var_c * var_d print(int(var_e))

9 4 [OP_MUL] 7 [OP_MUL]

Yuran wants to buy a gift box that is 9 centimeters (cm) wide, 4 centimeters (cm) long, and 7 centimeters (cm) high. What is the volume in cubic centimeters (cm) of the gift box Yuran is buying?

유란이는 가로가 9센티미터(㎝), 세로가 4센티미터(㎝), 높이가 7센티미터(㎝)인 선물 상자를 사려고 합니다. 유란이가 사려고 하는 선물 상자의 부피는 몇 세제곱센티미터(㎤)입니까?

Geometry

var_a = '정국' var_b = '지민' var_c = '석진' var_d = '태형' var_e = '남준' list_a= [] if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_f = '정국' var_g = '지민' var_h = '>' var_i = '석진' var_j = '지민' var_k = '<' var_l = '남준' var_m = '석진' var_n = '<' var_o = '정국' var_p = '태형' var_q = '<' list_b= [] if "/" in str(var_q): var_q = eval(str(var_q)) list_b.append(var_q) if "/" in str(var_p): var_p = eval(str(var_p)) list_b.append(var_p) if "/" in str(var_o): var_o = eval(str(var_o)) list_b.append(var_o) if "/" in str(var_n): var_n = eval(str(var_n)) list_b.append(var_n) if "/" in str(var_m): var_m = eval(str(var_m)) list_b.append(var_m) if "/" in str(var_l): var_l = eval(str(var_l)) list_b.append(var_l) if "/" in str(var_k): var_k = eval(str(var_k)) list_b.append(var_k) if "/" in str(var_j): var_j = eval(str(var_j)) list_b.append(var_j) if "/" in str(var_i): var_i = eval(str(var_i)) list_b.append(var_i) if "/" in str(var_h): var_h = eval(str(var_h)) list_b.append(var_h) if "/" in str(var_g): var_g = eval(str(var_g)) list_b.append(var_g) if "/" in str(var_f): var_f = eval(str(var_f)) list_b.append(var_f) list_b.reverse() global item_name_index_dict items_name_list = list_a.copy() conditions = [] condition_list = list_b.copy() temp_stack = [] for index_, cond_ in enumerate(map(str, condition_list)): if cond_ in ("<", ">", "="): operand_right = temp_stack.pop() operand_left = temp_stack.pop() if cond_ == "=": cond_ = "==" conditions.append(f"{operand_left} {cond_} {operand_right}") else: if not cond_.isdigit(): cond_ = "{" + cond_ + "}" temp_stack.append(cond_) item_name_index_dict = {} for perm in itertools.permutations(range(1, len(items_name_list) + 1)): item_name_index_dict = dict(zip(items_name_list, perm)) formatted_conditions = \ [condition.format_map(item_name_index_dict) for condition in conditions] if all(map(eval, formatted_conditions)): break list_c = list(item_name_index_dict.keys()) list_c.sort(key=item_name_index_dict.get, reverse=True) var_r = 1 var_s = list_c[var_r-1] print(var_s)

태형

Taehyung

[OP_LIST_SOL] 정국 지민 석진 태형 남준 [OP_LIST_EOL] [OP_LIST_SOL] 정국 지민 > 석진 지민 < 남준 석진 < 정국 태형 < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]

var_a = 'Jungkook' var_b = 'Jimin' var_c = 'Seokjin' var_d = 'Taehyung' var_e = 'Namjoon' list_a= [] if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_f = 'Jungkook' var_g = 'Jimin' var_h = '>' var_i = 'Seokjin' var_j = 'Jimin' var_k = '<' var_l = 'Namjoon' var_m = 'Seokjin' var_n = '<' var_o = 'Jungkook' var_p = 'Taehyung' var_q = '<' list_b= [] if "/" in str(var_q): var_q = eval(str(var_q)) list_b.append(var_q) if "/" in str(var_p): var_p = eval(str(var_p)) list_b.append(var_p) if "/" in str(var_o): var_o = eval(str(var_o)) list_b.append(var_o) if "/" in str(var_n): var_n = eval(str(var_n)) list_b.append(var_n) if "/" in str(var_m): var_m = eval(str(var_m)) list_b.append(var_m) if "/" in str(var_l): var_l = eval(str(var_l)) list_b.append(var_l) if "/" in str(var_k): var_k = eval(str(var_k)) list_b.append(var_k) if "/" in str(var_j): var_j = eval(str(var_j)) list_b.append(var_j) if "/" in str(var_i): var_i = eval(str(var_i)) list_b.append(var_i) if "/" in str(var_h): var_h = eval(str(var_h)) list_b.append(var_h) if "/" in str(var_g): var_g = eval(str(var_g)) list_b.append(var_g) if "/" in str(var_f): var_f = eval(str(var_f)) list_b.append(var_f) list_b.reverse() global item_name_index_dict items_name_list = list_a.copy() conditions = [] condition_list = list_b.copy() temp_stack = [] for index_, cond_ in enumerate(map(str, condition_list)): if cond_ in ("<", ">", "="): operand_right = temp_stack.pop() operand_left = temp_stack.pop() if cond_ == "=": cond_ = "==" conditions.append(f"{operand_left} {cond_} {operand_right}") else: if not cond_.isdigit(): cond_ = "{" + cond_ + "}" temp_stack.append(cond_) item_name_index_dict = {} for perm in itertools.permutations(range(1, len(items_name_list) + 1)): item_name_index_dict = dict(zip(items_name_list, perm)) formatted_conditions = \ [condition.format_map(item_name_index_dict) for condition in conditions] if all(map(eval, formatted_conditions)): break list_c = list(item_name_index_dict.keys()) list_c.sort(key=item_name_index_dict.get, reverse=True) var_r = 1 var_s = list_c[var_r-1] print(var_s)

[OP_LIST_SOL] Jungkook Jimin Seokjin Taehyung Namjoon [OP_LIST_EOL] [OP_LIST_SOL] Jungkook Jimin > Seokjin Jimin < Namjoon Seokjin < Jungkook Taehyung < [OP_LIST_EOL] [OP_LIST_COND_MAX_MIN] 1 [OP_LIST_GET]

Jungkook, Jimin, Seokjin, Taehyung, and Namjoon are standing side by side. Jungkook is standing next to Jimin's right side, and Seokjin is standing next to Jimin's left side. Also, Namjoon is standing to the left of Seokjin, and Jungkook is standing to the left of Taehyung. Who's standing on the furthest right?

정국, 지민, 석진, 태형, 남준이가 나란히 서 있습니다. 정국이는 지민이의 오른쪽 옆에 나란히 서 있고, 석진이는 지민이의 왼쪽 옆에 서 있습니다. 또 남준이는 석진이의 왼쪽 옆에 서 있고, 태형이의 왼쪽 옆에는 정국이가 서 있습니다. 가장 오른쪽에 서 있는 사람은 누구입니까?

Comparison

var_a = 458.64 var_b = 14 var_c = var_a / var_b var_d = 17 var_e = var_c % var_d var_f = 2 var_g = round(float(var_e)+1e-10, var_f) print('{:.2f}'.format(round(var_g+1e-10,2)))

15.76

15.76

458.64 14 [OP_DIV] 17 [OP_MOD] 2 [OP_ROUND]

var_a = 458.64 var_b = 14 var_c = var_a / var_b var_d = 17 var_e = var_c % var_d var_f = 2 var_g = round(float(var_e)+1e-10, var_f) print('{:.2f}'.format(round(var_g+1e-10,2)))

458.64 14 [OP_DIV] 17 [OP_MOD] 2 [OP_ROUND]

When a number is multiplied by 14, it is 458.64. When a number is divided by 17, round the remainder to two decimal places.

어떤 수에 14를 곱하였더니 458.64가 되었습니다. 어떤 수를 17로 나누었을 때의 나머지를 반올림하여 소수 둘째 자리까지 나타내시오.

Correspondence

var_a = 215 var_b = 0.32 var_c = var_a * var_b print('{:.2f}'.format(round(var_c+1e-10,2)))

68.80

68.8

215 0.32 [OP_MUL]

var_a = 215 var_b = 0.32 var_c = var_a * var_b print('{:.2f}'.format(round(var_c+1e-10,2)))

215 0.32 [OP_MUL]

Hyunggyu jumps rope 215 times every day. If Taewoo jumps 0.32 times the number of rope jumps made by Hyeonggyu, how many times does Taewoo jump rope a day?

형규는 매일 줄넘기 215회를 넘습니다. 태우는 형규가 하는 줄넘기 횟수의 0.32배를 넘는다면 태우의 하루 줄넘기 횟수는 몇 회입니까?

Arithmetic calculation

var_a = '9A-B4=34' var_b = 'B' ans_dict = dict() var_a = var_a.replace('×','*') var_a = var_a.replace('x','*') var_a = var_a.replace('÷','/') variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a): if v in variable_candi: ans_dict[v] = 1 candi = list(itertools.product('0123456789', repeat=len(ans_dict))) for c in candi: temp = var_a for i, (k, _) in enumerate(ans_dict.items()): temp = temp.replace(k, str(c[i])) term_list = [] op_list = [] temp_c = '' for tc in temp: if tc not in '+-*/=><().': temp_c += tc else: op_list.append(tc) term_list.append(temp_c) temp_c = '' term_list.append(temp_c) new_eq = '' for i in range(len(op_list)): new_eq += str(int(term_list[i]))+op_list[i] new_eq += str(int(term_list[-1])) if len(new_eq) == len(var_a): new_eq=new_eq.replace('=', '==') new_eq=new_eq.replace('>==', '>=') new_eq=new_eq.replace('<==', '<=') eval_result = False try: eval_result = eval(new_eq) except: pass if eval_result: for i, (k, _) in enumerate(ans_dict.items()): ans_dict[k] = int(c[i]) var_c = ans_dict[var_b] print(int(var_c))

6

6

9A-B4=34 B [OP_DIGIT_UNK_SOLVER]

var_a = '9A-B4=34' var_b = 'B' ans_dict = dict() var_a = var_a.replace('×','*') var_a = var_a.replace('x','*') var_a = var_a.replace('÷','/') variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a): if v in variable_candi: ans_dict[v] = 1 candi = list(itertools.product('0123456789', repeat=len(ans_dict))) for c in candi: temp = var_a for i, (k, _) in enumerate(ans_dict.items()): temp = temp.replace(k, str(c[i])) term_list = [] op_list = [] temp_c = '' for tc in temp: if tc not in '+-*/=><().': temp_c += tc else: op_list.append(tc) term_list.append(temp_c) temp_c = '' term_list.append(temp_c) new_eq = '' for i in range(len(op_list)): new_eq += str(int(term_list[i]))+op_list[i] new_eq += str(int(term_list[-1])) if len(new_eq) == len(var_a): new_eq=new_eq.replace('=', '==') new_eq=new_eq.replace('>==', '>=') new_eq=new_eq.replace('<==', '<=') eval_result = False try: eval_result = eval(new_eq) except: pass if eval_result: for i, (k, _) in enumerate(ans_dict.items()): ans_dict[k] = int(c[i]) var_c = ans_dict[var_b] print(int(var_c))

9A-B4=34 B [OP_DIGIT_UNK_SOLVER]

There are two different numbers A and B. Find B from the two-digit subtraction equation, 9A-B4=34.

서로 다른 두 수 A, B가 있습니다. 두 자리 수끼리의 뺄셈식 9A-B4=34에서 B를 구하시오.

Correspondence

var_a = 1 var_b = 3 var_c = 6 var_d = 7 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_e = 3 list_b = [str(i) for i in list_a] list_b = list(itertools.permutations(list_b, var_e)) list_b = [''.join(num_list) for num_list in list_b] list_b = [str_num for str_num in list_b if str_num[0] != '0'] list_b = [float(i) for i in list_b] var_f = len(list_b) print(int(var_f))

24

24

[OP_LIST_SOL] 1 3 6 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]

var_a = 1 var_b = 3 var_c = 6 var_d = 7 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_e = 3 list_b = [str(i) for i in list_a] list_b = list(itertools.permutations(list_b, var_e)) list_b = [''.join(num_list) for num_list in list_b] list_b = [str_num for str_num in list_b if str_num[0] != '0'] list_b = [float(i) for i in list_b] var_f = len(list_b) print(int(var_f))

[OP_LIST_SOL] 1 3 6 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] [OP_LIST_LEN]

How many three-digit numbers can you make from three different numbers of the numbers 1, 3, 6, and 7?

1, 3, 6, 7 중에서 서로 다른 숫자 3개를 사용하여 만들 수 있는 세 자리 수는 모두 몇 개입니까?

Possibility

var_a = 30 var_b = 15 var_c = var_a * var_b var_d = 15 var_e = 1 var_f = var_d - var_e var_g = 2 var_h = var_f * var_g var_i = var_c - var_h print(int(var_i))

422

422

30 15 [OP_MUL] 15 1 [OP_SUB] 2 [OP_MUL] [OP_SUB]

var_a = 30 var_b = 15 var_c = var_a * var_b var_d = 15 var_e = 1 var_f = var_d - var_e var_g = 2 var_h = var_f * var_g var_i = var_c - var_h print(int(var_i))

30 15 [OP_MUL] 15 1 [OP_SUB] 2 [OP_MUL] [OP_SUB]

There are pieces of ribbon each of which is 30 centimeters (cm) long. I tied 15 pieces of ribbon to each other to make a long piece of ribbon. If 2 centimeters (cm) of a piece of ribbon is used to tie the ribbon, what is the length of the piece of ribbon made?

길이가 30센티미터(㎝)인 리본이 있습니다. 리본 15개를 묶어서 긴 리본을 하나 만들었습니다. 리본을 묶는데 2센티미터(㎝)가 사용된다고 할 때, 만든 리본의 길이는 얼마입니까?

Arithmetic calculation

var_a = '32×A×A×A=42592' var_b = 'A' ans_dict = dict() var_a = var_a.replace('×','*') var_a = var_a.replace('x','*') var_a = var_a.replace('÷','/') variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a): if v in variable_candi: ans_dict[v] = 0 candidate_num = [i for i in range(51)] candi = list(itertools.product(candidate_num, repeat=len(ans_dict))) for c in candi: temp = var_a for i, (k, _) in enumerate(ans_dict.items()): temp = temp.replace(k, str(c[i])) term_list = [] op_list = [] temp_c = '' for tc in temp: if tc not in '+-*/=><().': temp_c += tc else: op_list.append(tc) term_list.append(temp_c) temp_c = '' term_list.append(temp_c) new_eq = '' for i in range(len(op_list)): if term_list[i] == '': new_eq += str(term_list[i])+op_list[i] else: new_eq += str(int(term_list[i]))+op_list[i] new_eq += str(int(term_list[-1])) new_eq=new_eq.replace('=', '==') new_eq=new_eq.replace('>==', '>=') new_eq=new_eq.replace('<==', '<=') eval_result = False try: if '=' in new_eq and '>' not in new_eq and '<' not in new_eq: new_eq=new_eq.replace('==','=') new_eq=new_eq.replace('>','') new_eq=new_eq.replace('<','') new_eq=new_eq.split('=') for i in range(len(new_eq)-1): eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1])) if not eval_result: break else: eval_result = eval(new_eq) except: eval_result = False pass if eval_result: for i, (k, _) in enumerate(ans_dict.items()): ans_dict[k] = int(c[i]) var_c = ans_dict[var_b] print(int(var_c))

11

11

32×A×A×A=42592 A [OP_NUM_UNK_SOLVER]

var_a = '32×A×A×A=42592' var_b = 'A' ans_dict = dict() var_a = var_a.replace('×','*') var_a = var_a.replace('x','*') var_a = var_a.replace('÷','/') variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a): if v in variable_candi: ans_dict[v] = 0 candidate_num = [i for i in range(51)] candi = list(itertools.product(candidate_num, repeat=len(ans_dict))) for c in candi: temp = var_a for i, (k, _) in enumerate(ans_dict.items()): temp = temp.replace(k, str(c[i])) term_list = [] op_list = [] temp_c = '' for tc in temp: if tc not in '+-*/=><().': temp_c += tc else: op_list.append(tc) term_list.append(temp_c) temp_c = '' term_list.append(temp_c) new_eq = '' for i in range(len(op_list)): if term_list[i] == '': new_eq += str(term_list[i])+op_list[i] else: new_eq += str(int(term_list[i]))+op_list[i] new_eq += str(int(term_list[-1])) new_eq=new_eq.replace('=', '==') new_eq=new_eq.replace('>==', '>=') new_eq=new_eq.replace('<==', '<=') eval_result = False try: if '=' in new_eq and '>' not in new_eq and '<' not in new_eq: new_eq=new_eq.replace('==','=') new_eq=new_eq.replace('>','') new_eq=new_eq.replace('<','') new_eq=new_eq.split('=') for i in range(len(new_eq)-1): eval_result = math.isclose(eval(new_eq[i]), eval(new_eq[i+1])) if not eval_result: break else: eval_result = eval(new_eq) except: eval_result = False pass if eval_result: for i, (k, _) in enumerate(ans_dict.items()): ans_dict[k] = int(c[i]) var_c = ans_dict[var_b] print(int(var_c))

32×A×A×A=42592 A [OP_NUM_UNK_SOLVER]

Find A that satisfies 32×A×A×A=42592

32×A×A×A=42592를 만족하는 A를 구하시오

Correspondence

var_a = 10 var_b = 30 var_c = 60 var_d = var_b / var_c var_e = var_a * var_d var_f = 15 var_g = 10 var_h = var_f - var_g var_i = var_e / var_h print(int(var_i))

1

1

10 30 60 [OP_DIV] [OP_MUL] 15 10 [OP_SUB] [OP_DIV]

var_a = 10 var_b = 30 var_c = 60 var_d = var_b / var_c var_e = var_a * var_d var_f = 15 var_g = 10 var_h = var_f - var_g var_i = var_e / var_h print(int(var_i))

10 30 60 [OP_DIV] [OP_MUL] 15 10 [OP_SUB] [OP_DIV]

A pink rabbit and a white rabbit is running a race. The pink rabbit ran at a speed of 15 kilometers per hour (km), and the white rabbit ran at a speed of 10 kilometers per hour (km), arriving 30 minutes later than the pink rabbit. Find the time it took for the pink rabbit to arrive.

분홍 토끼와 하양 토끼가 경주를 한다. 분홍 토끼는 시속 15킬로미터(㎞)의 속도로 달렸고, 하양 토끼는 시속 10킬로미터(㎞)의 속도로 달렸는데 분홍 토끼보다 30분 늦게 도착했다. 분홍 토끼가 도착할때 까지 걸린 시간을 구하시오.

Arithmetic calculation

var_a = 300 var_b = 60 var_c = 2 var_d = var_b * var_c var_e = var_a - var_d print(int(var_e))

180

180

300 60 2 [OP_MUL] [OP_SUB]

var_a = 300 var_b = 60 var_c = 2 var_d = var_b * var_c var_e = var_a - var_d print(int(var_e))

300 60 2 [OP_MUL] [OP_SUB]

Taehyung is trying to get to his grandmother's house, which is 300 kilometers (km) away on a motorcycle at 60 kilometers (km) per hour. Find how far Taehyung needs to go when 2 hours have passed since he left.

태형이는 시속 60킬로미터(㎞)의 오토바이를 타고 300킬로미터(㎞) 떨어진 할머니댁에 가려고 합니다. 태형이가 출발한 지 2시간이 지났을 때 더 가야할 거리는 얼마인지 구하세요.

Arithmetic calculation

var_a = 45 var_b = 5 var_c = var_a // var_b print(int(var_c))

9

9

45 5 [OP_FDIV]

var_a = 45 var_b = 5 var_c = var_a // var_b print(int(var_c))

45 5 [OP_FDIV]

Taehyung has 45 candies. If he plans to give 5 candies to his friends, how many friends can get candies in maximum?

태형이는 사탕 45개를 가지고 있습니다. 친구들에게 사탕을 5개씩 나누어 주면 몇 명의 친구들에게 나누어 줄 수 있습니까?

Arithmetic calculation

var_a = 1 var_b = 3 var_c = 5 var_d = 6 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_e = 4 list_b = [str(i) for i in list_a] list_b = list(itertools.permutations(list_b, var_e)) list_b = [''.join(num_list) for num_list in list_b] list_b = [str_num for str_num in list_b if str_num[0] != '0'] list_b = [float(i) for i in list_b] var_f = 4 list_c = [] var_f = int(var_f) for i in list_b: i = int(i) if i % var_f == 0: list_c.append(i) var_g = len(list_c) print(int(var_g))

6

6

[OP_LIST_SOL] 1 3 5 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]

var_a = 1 var_b = 3 var_c = 5 var_d = 6 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_e = 4 list_b = [str(i) for i in list_a] list_b = list(itertools.permutations(list_b, var_e)) list_b = [''.join(num_list) for num_list in list_b] list_b = [str_num for str_num in list_b if str_num[0] != '0'] list_b = [float(i) for i in list_b] var_f = 4 list_c = [] var_f = int(var_f) for i in list_b: i = int(i) if i % var_f == 0: list_c.append(i) var_g = len(list_c) print(int(var_g))

[OP_LIST_SOL] 1 3 5 6 [OP_LIST_EOL] 4 [OP_LIST_GET_PERM] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]

How many multiples of 4 are there among the four-digit numbers made using the number cards 1, 3, 5, and 6 once?

숫자 카드 1, 3, 5, 6을 한 번씩 사용하여 만들 수 있는 네 자리 수 중 4의 배수는 모두 몇 개인가?

Possibility

var_a = '쥐' var_b = '소' var_c = '호랑이' var_d = '토끼' var_e = '용' var_f = '뱀' list_a= [] if "/" in str(var_f): var_f = eval(str(var_f)) list_a.append(var_f) if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_g = '쥐' list_b= [] if "/" in str(var_g): var_g = eval(str(var_g)) list_b.append(var_g) list_b.reverse() list_c = list(set(list_a) - set(list_b)) var_h = '뱀' list_d= [] if "/" in str(var_h): var_h = eval(str(var_h)) list_d.append(var_h) list_d.reverse() list_e = list(set(list_c) - set(list_d)) var_i = len(list_e) var_j = len(list_e) var_k = 1 var_i = int(var_i) var_j = int(var_j) for i, elem in enumerate(range(var_j)): var_k = var_k * (var_i-i) print(int(var_k))

24

24

[OP_LIST_SOL] 쥐 소 호랑이 토끼 용 뱀 [OP_LIST_EOL] [OP_LIST_SOL] 쥐 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_SOL] 뱀 [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]

var_a = 'Rat' var_b = 'Cow' var_c = 'Tiger' var_d = 'Rabbit' var_e = 'Dragon' var_f = 'Snake' list_a= [] if "/" in str(var_f): var_f = eval(str(var_f)) list_a.append(var_f) if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_g = 'Rat' list_b= [] if "/" in str(var_g): var_g = eval(str(var_g)) list_b.append(var_g) list_b.reverse() list_c = list(set(list_a) - set(list_b)) var_h = 'Snake' list_d= [] if "/" in str(var_h): var_h = eval(str(var_h)) list_d.append(var_h) list_d.reverse() list_e = list(set(list_c) - set(list_d)) var_i = len(list_e) var_j = len(list_e) var_k = 1 var_i = int(var_i) var_j = int(var_j) for i, elem in enumerate(range(var_j)): var_k = var_k * (var_i-i) print(int(var_k))

[OP_LIST_SOL] Rat Cow Tiger Rabbit Dragon Snake [OP_LIST_EOL] [OP_LIST_SOL] Rat [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_SOL] Snake [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]

Among Rat, Cow, Tiger, Rabbit, Dragon, and Snake, find the number of cases in which the rat is placed at the very front, the snake at the very back, and the rest are placed in one line.

쥐, 소, 호랑이, 토끼, 용, 뱀 중 쥐의 위치는 맨 앞에, 뱀의 위치는 맨 뒤에 세워놓은 뒤 나머지를 한 줄로 세우는 경우의 수를 구하시오.

Possibility

var_a = 0.14 var_b = 93.6 var_c = var_a * var_b var_d = 2 var_e = 30 var_f = 60 var_g = var_e / var_f var_h = var_d + var_g var_i = var_c * var_h print('{:.2f}'.format(round(var_i+1e-10,2)))

32.76

32.76

0.14 93.6 [OP_MUL] 2 30 60 [OP_DIV] [OP_ADD] [OP_MUL]

var_a = 0.14 var_b = 93.6 var_c = var_a * var_b var_d = 2 var_e = 30 var_f = 60 var_g = var_e / var_f var_h = var_d + var_g var_i = var_c * var_h print('{:.2f}'.format(round(var_i+1e-10,2)))

0.14 93.6 [OP_MUL] 2 30 60 [OP_DIV] [OP_ADD] [OP_MUL]

A car that requires 0.14 liters (l) of gasoline to run 1 kilometer (km) ran for 2 hours and 30 minutes at 93.6 kilometers (km) per hour. How many liters of gasoline did it use?

1킬로미터(㎞)를 달리는 데 휘발유 0.14리터(L)가 필요한 자동차로 1시간에 93.6킬로미터(㎞)씩 2시간 30분 동안 달렸습니다. 사용한 휘발유는 모두 몇 리터(L)일까요?

Arithmetic calculation

var_a = 5 var_b = 1 var_c = 1 var_d = var_b + var_c var_e = 1 var_f = var_d + var_e var_g = 1 var_h = var_f + var_g var_i = 1 var_j = var_h + var_i var_k = 1 var_a = int(var_a) var_j = int(var_j) for i, elem in enumerate(range(var_j)): var_k = var_k * (var_a-i) print(int(var_k))

120

120

5 1 1 [OP_ADD] 1 [OP_ADD] 1 [OP_ADD] 1 [OP_ADD] [OP_PERM]

var_a = 5 var_b = 1 var_c = 1 var_d = var_b + var_c var_e = 1 var_f = var_d + var_e var_g = 1 var_h = var_f + var_g var_i = 1 var_j = var_h + var_i var_k = 1 var_a = int(var_a) var_j = int(var_j) for i, elem in enumerate(range(var_j)): var_k = var_k * (var_a-i) print(int(var_k))

5 1 1 [OP_ADD] 1 [OP_ADD] 1 [OP_ADD] 1 [OP_ADD] [OP_PERM]

There are 5 different people. Everyone wanted to be an executive, so you decided to have 1 chairman, 1 vice-president, 1 secretary, 1 secretary, and 1 manager. Find the possible number of cases for assigning the position.

5명의 서로 다른 사람이 있다. 모두가 임원을 하고 싶어해서 회장 1명, 부회장 1명, 총무 1명, 서기 1명, 관리부장 1명을 하기로 했다. 이렇게 5명을 뽑을 때 경우의 수를 구하여라.

Possibility

var_a = '3+6AB=691' var_b = 'B' ans_dict = dict() var_a = var_a.replace('×','*') var_a = var_a.replace('x','*') var_a = var_a.replace('÷','/') variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a): if v in variable_candi: ans_dict[v] = 1 candi = list(itertools.product('0123456789', repeat=len(ans_dict))) for c in candi: temp = var_a for i, (k, _) in enumerate(ans_dict.items()): temp = temp.replace(k, str(c[i])) term_list = [] op_list = [] temp_c = '' for tc in temp: if tc not in '+-*/=><().': temp_c += tc else: op_list.append(tc) term_list.append(temp_c) temp_c = '' term_list.append(temp_c) new_eq = '' for i in range(len(op_list)): new_eq += str(int(term_list[i]))+op_list[i] new_eq += str(int(term_list[-1])) if len(new_eq) == len(var_a): new_eq=new_eq.replace('=', '==') new_eq=new_eq.replace('>==', '>=') new_eq=new_eq.replace('<==', '<=') eval_result = False try: eval_result = eval(new_eq) except: pass if eval_result: for i, (k, _) in enumerate(ans_dict.items()): ans_dict[k] = int(c[i]) var_c = ans_dict[var_b] print(int(var_c))

8

8

3+6AB=691 B [OP_DIGIT_UNK_SOLVER]

var_a = '3+6AB=691' var_b = 'B' ans_dict = dict() var_a = var_a.replace('×','*') var_a = var_a.replace('x','*') var_a = var_a.replace('÷','/') variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a): if v in variable_candi: ans_dict[v] = 1 candi = list(itertools.product('0123456789', repeat=len(ans_dict))) for c in candi: temp = var_a for i, (k, _) in enumerate(ans_dict.items()): temp = temp.replace(k, str(c[i])) term_list = [] op_list = [] temp_c = '' for tc in temp: if tc not in '+-*/=><().': temp_c += tc else: op_list.append(tc) term_list.append(temp_c) temp_c = '' term_list.append(temp_c) new_eq = '' for i in range(len(op_list)): new_eq += str(int(term_list[i]))+op_list[i] new_eq += str(int(term_list[-1])) if len(new_eq) == len(var_a): new_eq=new_eq.replace('=', '==') new_eq=new_eq.replace('>==', '>=') new_eq=new_eq.replace('<==', '<=') eval_result = False try: eval_result = eval(new_eq) except: pass if eval_result: for i, (k, _) in enumerate(ans_dict.items()): ans_dict[k] = int(c[i]) var_c = ans_dict[var_b] print(int(var_c))

3+6AB=691 B [OP_DIGIT_UNK_SOLVER]

When 3+6AB=691, what number should go in B?

3+6AB=691일 때, B에 들어가야 하는 숫자는 무엇인가요?

Correspondence

var_a = 2 var_b = 4 var_c = var_a + var_b var_d = 1 var_e = 1 var_c = int(var_c) var_d = int(var_d) for i, elem in enumerate(range(var_d)): var_e = var_e * (var_c-i) for i, elem in enumerate(range(var_d)): var_e = var_e / (i+1) print(int(var_e))

6

6

2 4 [OP_ADD] 1 [OP_COMB]

var_a = 2 var_b = 4 var_c = var_a + var_b var_d = 1 var_e = 1 var_c = int(var_c) var_d = int(var_d) for i, elem in enumerate(range(var_d)): var_e = var_e * (var_c-i) for i, elem in enumerate(range(var_d)): var_e = var_e / (i+1) print(int(var_e))

2 4 [OP_ADD] 1 [OP_COMB]

There are two types of Korean language workbooks and four types of math workbooks. When choosing one book among them, in how many cases can you choose Korean workbook or math workbook?

국어문제집이 2가지 종류, 수학문제집이 4가지 종류가 있다. 이 중에서 한 권을 선택할 때, 국어문제집 또는 수학문제집을 선택하는 경우의 수는?

Possibility

var_a = 21.12 var_b = 6 var_c = var_a / var_b print('{:.2f}'.format(round(var_c+1e-10,2)))

3.52

3.52

21.12 6 [OP_DIV]

var_a = 21.12 var_b = 6 var_c = var_a / var_b print('{:.2f}'.format(round(var_c+1e-10,2)))

21.12 6 [OP_DIV]

A regular hexagon with an area of 21.12 square centimeters (cm2) is divided into six pieces. If the cut pieces have the same shape and size, find the area of one piece in square centimeters (cm2).

넓이가 21.12제곱센티미터(㎠)인 정육각형을 여섯 조각으로 나누었습니다. 잘린 조각들의 모양과 크기가 같을 때, 한 조각의 넓이는 몇 제곱센티미터(㎠)일지 구하시오.

Geometry

var_a = 713 var_b = 928 var_c = 713 var_d = var_b - var_c var_e = var_a - var_d print(int(var_e))

498

498

713 928 713 [OP_SUB] [OP_SUB]

var_a = 713 var_b = 928 var_c = 713 var_d = var_b - var_c var_e = var_a - var_d print(int(var_e))

713 928 713 [OP_SUB] [OP_SUB]

There are a total of 928 baduk stones and 713 of them are colored white. Find the difference between the number of white stones and black stones.

바둑알이 모두 928개가 있고 흰 바둑알이 713개 있다. 흰 바둑알과 검은 바둑알의 개수는 몇 개가 차이나는지 구하시오.

Correspondence

var_a = 0 var_b = 3 var_c = 4 var_d = 6 var_e = 8 list_a= [] if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_f = 2 list_b = [str(i) for i in list_a] list_b = list(itertools.permutations(list_b, var_f)) list_b = [''.join(num_list) for num_list in list_b] list_b = [str_num for str_num in list_b if str_num[0] != '0'] list_b = [float(i) for i in list_b] var_g = 1 list_c=list_b.copy() list_c.sort() var_h = list_c[var_g-1] var_i = 7 var_j = var_h - var_i print(int(var_j))

23

23

[OP_LIST_SOL] 0 3 4 6 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 7 [OP_SUB]

var_a = 0 var_b = 3 var_c = 4 var_d = 6 var_e = 8 list_a= [] if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_f = 2 list_b = [str(i) for i in list_a] list_b = list(itertools.permutations(list_b, var_f)) list_b = [''.join(num_list) for num_list in list_b] list_b = [str_num for str_num in list_b if str_num[0] != '0'] list_b = [float(i) for i in list_b] var_g = 1 list_c=list_b.copy() list_c.sort() var_h = list_c[var_g-1] var_i = 7 var_j = var_h - var_i print(int(var_j))

[OP_LIST_SOL] 0 3 4 6 8 [OP_LIST_EOL] 2 [OP_LIST_GET_PERM] 1 [OP_LIST_MIN] 7 [OP_SUB]

The smallest two-digit number that can be formed by two of 0, 3, 4, 6, and 8 is subtracted by a certain number and it became 7. Find the number.

0, 3, 4, 6, 8을 한 번씩만 사용하여 만든 가장 작은 두 자리 수에서 어떤 수를 뺐더니 7이 됩니다. 어떤 수는 몇인지 구하시오.

Possibility

var_a = 98 var_b = 7 var_c = var_a / var_b print(int(var_c))

14

14

98 7 [OP_DIV]

var_a = 98 var_b = 7 var_c = var_a / var_b print(int(var_c))

98 7 [OP_DIV]

When you multiply a number by 7, it becomes 98. What is that number?

어떤 수에 7을 곱하였더니 98이 되었습니다. 어떤 수는 얼마입니까?

Correspondence

var_a = 10 var_b = 11 var_c = 12 list_a= [] if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_d = 1 list_b=list_a.copy() list_b.sort() var_e = list_b[var_d-1] var_f = 2 list_c=list_a.copy() list_c.sort() var_g = list_c[var_f-1] var_h = var_e - var_g var_i = abs(var_h) print(int(var_i))

1

1

[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_SUB] [OP_ABS]

var_a = 10 var_b = 11 var_c = 12 list_a= [] if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_d = 1 list_b=list_a.copy() list_b.sort() var_e = list_b[var_d-1] var_f = 2 list_c=list_a.copy() list_c.sort() var_g = list_c[var_f-1] var_h = var_e - var_g var_i = abs(var_h) print(int(var_i))

[OP_LIST_SOL] 10 11 12 [OP_LIST_EOL] 1 [OP_LIST_MIN] 2 [OP_LIST_MIN] [OP_SUB] [OP_ABS]

There are three numbers 10, 11, and 12. What is the difference between the smallest number and the second smallest number?

3개의 수 10, 11, 12가 있습니다. 그 중에서 가장 작은 수와 2번째로 작은 수의 차는 얼마입니까?

Arithmetic calculation

var_a = 42 var_b = 42 var_c = var_a + var_b var_d = 48 var_e = var_c - var_d print(int(var_e))

36

36

42 42 [OP_ADD] 48 [OP_SUB]

var_a = 42 var_b = 42 var_c = var_a + var_b var_d = 48 var_e = var_c - var_d print(int(var_e))

42 42 [OP_ADD] 48 [OP_SUB]

There are 42 chickens and 48 ducks on the farm, and there are as many geese as there are chickens. How many ducks are fewer than the number of chickens and geese combined?

농장에 닭은 42마리, 오리는 48마리 있고, 거위는 닭의 수와 같습니다. 오리는 닭과 거위를 합한 것보다 몇 마리 더 적게 있습니까?

Arithmetic calculation

var_a = 0.1 var_b = 6 var_c = var_a * var_b var_d = 0.12 var_e = var_c / var_d print(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))

5

5

1/10 6 [OP_MUL] 3/25 [OP_DIV]

var_a = 0.1 var_b = 6 var_c = var_a * var_b var_d = 0.12 var_e = var_c / var_d print(int(eval('{:.2f}'.format(round(var_e+1e-10,2)))))

1/10 6 [OP_MUL] 3/25 [OP_DIV]

When a number is divided by 6, it becomes 1/10. What is the value of the number divided by 3/25?

어떤 수는 6으로 나눴을때 1/10이 된다. 이때 어떤 수를 3/25로 나눈다면 얼마가 되는가?

Correspondence

var_a = 8 var_b = 2 var_c = 2 var_d = var_b * var_c var_e = var_a / var_d var_f = 2 var_g = var_e ** var_f print(int(var_g))

4

4

8 2 2 [OP_MUL] [OP_DIV] 2 [OP_POW]

var_a = 8 var_b = 2 var_c = 2 var_d = var_b * var_c var_e = var_a / var_d var_f = 2 var_g = var_e ** var_f print(int(var_g))

8 2 2 [OP_MUL] [OP_DIV] 2 [OP_POW]

You want to place tissue paper with a radius of 2 centimeters (cm) inside a square box with a side length of 8 centimeters (cm) without overlapping. How many toilet papers can be put on one floor?

반지름의 길이가 2센티미터(㎝)인 휴지를 한 변의 길이가 8센티미터(㎝)인 정사각형 상자 안에 겹치지 않게 넣으려고 합니다. 한 층에휴지는 모두 몇 개 넣을 수 있습니까?

Geometry

var_a = 'A3B-41=591' var_b = 'A' ans_dict = dict() var_a = var_a.replace('×','*') var_a = var_a.replace('x','*') var_a = var_a.replace('÷','/') variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a): if v in variable_candi: ans_dict[v] = 1 candi = list(itertools.product('0123456789', repeat=len(ans_dict))) for c in candi: temp = var_a for i, (k, _) in enumerate(ans_dict.items()): temp = temp.replace(k, str(c[i])) term_list = [] op_list = [] temp_c = '' for tc in temp: if tc not in '+-*/=><().': temp_c += tc else: op_list.append(tc) term_list.append(temp_c) temp_c = '' term_list.append(temp_c) new_eq = '' for i in range(len(op_list)): new_eq += str(int(term_list[i]))+op_list[i] new_eq += str(int(term_list[-1])) if len(new_eq) == len(var_a): new_eq=new_eq.replace('=', '==') new_eq=new_eq.replace('>==', '>=') new_eq=new_eq.replace('<==', '<=') eval_result = False try: eval_result = eval(new_eq) except: pass if eval_result: for i, (k, _) in enumerate(ans_dict.items()): ans_dict[k] = int(c[i]) var_c = ans_dict[var_b] print(int(var_c))

6

6

A3B-41=591 A [OP_DIGIT_UNK_SOLVER]

var_a = 'A3B-41=591' var_b = 'A' ans_dict = dict() var_a = var_a.replace('×','*') var_a = var_a.replace('x','*') var_a = var_a.replace('÷','/') variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a): if v in variable_candi: ans_dict[v] = 1 candi = list(itertools.product('0123456789', repeat=len(ans_dict))) for c in candi: temp = var_a for i, (k, _) in enumerate(ans_dict.items()): temp = temp.replace(k, str(c[i])) term_list = [] op_list = [] temp_c = '' for tc in temp: if tc not in '+-*/=><().': temp_c += tc else: op_list.append(tc) term_list.append(temp_c) temp_c = '' term_list.append(temp_c) new_eq = '' for i in range(len(op_list)): new_eq += str(int(term_list[i]))+op_list[i] new_eq += str(int(term_list[-1])) if len(new_eq) == len(var_a): new_eq=new_eq.replace('=', '==') new_eq=new_eq.replace('>==', '>=') new_eq=new_eq.replace('<==', '<=') eval_result = False try: eval_result = eval(new_eq) except: pass if eval_result: for i, (k, _) in enumerate(ans_dict.items()): ans_dict[k] = int(c[i]) var_c = ans_dict[var_b] print(int(var_c))

A3B-41=591 A [OP_DIGIT_UNK_SOLVER]

A3B-41=591. How much is A?

A3B-41=591입니다. A는 얼마인가요?

Correspondence

var_a = 10 var_b = 99 var_c = 1 list_a = [i for i in range(var_a, var_b + 1, var_c)] var_d = 3 list_b = [] var_d = int(var_d) for i in list_a: i = int(i) if i % var_d == 0: list_b.append(i) var_e = 5 list_c = [] var_e = int(var_e) for i in list_b: i = int(i) if i % var_e == 0: list_c.append(i) var_f = 1 list_d=list_c.copy() list_d.sort() var_g = list_d[var_f-1] print(int(var_g))

15

15

10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]

var_a = 10 var_b = 99 var_c = 1 list_a = [i for i in range(var_a, var_b + 1, var_c)] var_d = 3 list_b = [] var_d = int(var_d) for i in list_a: i = int(i) if i % var_d == 0: list_b.append(i) var_e = 5 list_c = [] var_e = int(var_e) for i in list_b: i = int(i) if i % var_e == 0: list_c.append(i) var_f = 1 list_d=list_c.copy() list_d.sort() var_g = list_d[var_f-1] print(int(var_g))

10 99 1 [OP_LIST_ARANGE] 3 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] 1 [OP_LIST_MIN]

What is the smallest two-digit number that is a multiple of 3 and a multiple of 5 at the same time?

3의 배수이면서 5의 배수인 수 중 가장 작은 두 자리 수는?

Arithmetic calculation

var_a = 25 var_b = 32 var_c = var_a + var_b var_d = 23 var_e = var_c - var_d print(int(var_e))

34

34

25 32 [OP_ADD] 23 [OP_SUB]

var_a = 25 var_b = 32 var_c = var_a + var_b var_d = 23 var_e = var_c - var_d print(int(var_e))

25 32 [OP_ADD] 23 [OP_SUB]

I should have subtracted 23, but I mistakenly subtracted 32 from some number and got 25. How much do you get when calculated correctly?

23을 뺐어야하는데 잘못하여 32를 어떤 수에서 뺐더니 25가 나왔습니다. 바르게 계산하면 얼마입니까?

Correspondence

var_a = 1.77 var_b = 3 var_c = var_a / var_b print('{:.2f}'.format(round(var_c+1e-10,2)))

0.59

0.59

1.77 3 [OP_DIV]

var_a = 1.77 var_b = 3 var_c = var_a / var_b print('{:.2f}'.format(round(var_c+1e-10,2)))

1.77 3 [OP_DIV]

The rectangular shape of the ttakji's area is 1.77 square centimeters (cm2). If the width of this ttakji is 3 centimeters (cm), how many centimeters (cm) will the length be?

직사각형 모양의 딱지의 넓이는 1.77제곱센티미터(㎠)입니다. 이 딱지의 가로의 길이는 3센티미터(㎝)일 때, 세로의 길이는 몇 센티미터(㎝) 일까요?

Geometry

var_a = 1 var_b = 3 var_c = 4 var_d = 7 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_e = 3 list_b = [str(i) for i in list_a] list_b = list(itertools.permutations(list_b, var_e)) list_b = [''.join(num_list) for num_list in list_b] list_b = [str_num for str_num in list_b if str_num[0] != '0'] list_b = [float(i) for i in list_b] var_f = 10 var_g = 3 list_c = [] var_f = int(var_f) var_g = int(var_g) for i in list_b: i = int(i) if (i//var_f)%10 == var_g: list_c.append(i) var_h = 1 list_d=list_c.copy() list_d.sort() var_i = list_d[-var_h] var_j = 3 list_e=list_c.copy() list_e.sort() var_k = list_e[-var_j] var_l = var_i + var_k print(int(var_l))

1171

1171

[OP_LIST_SOL] 1 3 4 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 3 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD]

var_a = 1 var_b = 3 var_c = 4 var_d = 7 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_e = 3 list_b = [str(i) for i in list_a] list_b = list(itertools.permutations(list_b, var_e)) list_b = [''.join(num_list) for num_list in list_b] list_b = [str_num for str_num in list_b if str_num[0] != '0'] list_b = [float(i) for i in list_b] var_f = 10 var_g = 3 list_c = [] var_f = int(var_f) var_g = int(var_g) for i in list_b: i = int(i) if (i//var_f)%10 == var_g: list_c.append(i) var_h = 1 list_d=list_c.copy() list_d.sort() var_i = list_d[-var_h] var_j = 3 list_e=list_c.copy() list_e.sort() var_k = list_e[-var_j] var_l = var_i + var_k print(int(var_l))

[OP_LIST_SOL] 1 3 4 7 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 10 3 [OP_LIST_SEARCH_FIXED_DIGIT] 1 [OP_LIST_MAX] 3 [OP_LIST_MAX] [OP_ADD]

Find the sum of the largest number and the third largest number when selecting three of 1, 3, 4, and 7 to form a three-digit number with 3 in the tens place.

1, 3, 4, 7 중 세 개를 뽑아 십의 자리가 3인 세 자리 수를 만들 때, 가장 큰 수와 세 번째로 큰 수의 합을 구하시오.

Possibility

var_a = 10 var_b = 11 var_c = 12 var_d = 13 var_e = 14 list_a= [] if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_f = 1 list_b=list_a.copy() list_b.sort() var_g = list_b[-var_f] var_h = 2 list_c=list_a.copy() list_c.sort() var_i = list_c[var_h-1] var_j = var_g + var_i print(int(var_j))

25

25

[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]

var_a = 10 var_b = 11 var_c = 12 var_d = 13 var_e = 14 list_a= [] if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_f = 1 list_b=list_a.copy() list_b.sort() var_g = list_b[-var_f] var_h = 2 list_c=list_a.copy() list_c.sort() var_i = list_c[var_h-1] var_j = var_g + var_i print(int(var_j))

[OP_LIST_SOL] 10 11 12 13 14 [OP_LIST_EOL] 1 [OP_LIST_MAX] 2 [OP_LIST_MIN] [OP_ADD]

You have five numbers 10, 11, 12, 13, and 14. What is the sum of the largest number and the second smallest number?

5개의 수 10, 11, 12, 13, 14가 있습니다. 그 중에서 가장 큰 수와 2번째로 작은 수의 합은 얼마입니까?

Arithmetic calculation

var_a = 14.23 var_b = 4.7 var_c = var_a / var_b var_d = 2 var_e = round(float(var_c)+1e-10, var_d) print('{:.2f}'.format(round(var_e+1e-10,2)))

3.03

3.03

14.23 4.7 [OP_DIV] 2 [OP_ROUND]

var_a = 14.23 var_b = 4.7 var_c = var_a / var_b var_d = 2 var_e = round(float(var_c)+1e-10, var_d) print('{:.2f}'.format(round(var_e+1e-10,2)))

14.23 4.7 [OP_DIV] 2 [OP_ROUND]

When 14.23 is divided by 4.7, find the value to two decimal places.

14.23을 4.7로 나누었을 때 값을 소수 둘째 자리까지 구하시오.

Arithmetic calculation

var_a = 100 var_b = 999 var_c = 1 list_a = [i for i in range(var_a, var_b + 1, var_c)] var_d = 4 list_b = [] var_d = int(var_d) for i in list_a: i = int(i) if i % var_d == 0: list_b.append(i) var_e = 5 list_c = [] var_e = int(var_e) for i in list_b: i = int(i) if i % var_e == 0: list_c.append(i) var_f = len(list_c) print(int(var_f))

45

45

100 999 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]

var_a = 100 var_b = 999 var_c = 1 list_a = [i for i in range(var_a, var_b + 1, var_c)] var_d = 4 list_b = [] var_d = int(var_d) for i in list_a: i = int(i) if i % var_d == 0: list_b.append(i) var_e = 5 list_c = [] var_e = int(var_e) for i in list_b: i = int(i) if i % var_e == 0: list_c.append(i) var_f = len(list_c) print(int(var_f))

100 999 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]

How many three-digit numbers are divisible by the two numbers - 4 and 5?

2개의 수 4, 5로 나누어 떨어질 수 있는 세 자리 수는 모두 몇 개 있습니까?

Arithmetic calculation

var_a = '어제' var_b = '오늘' list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 135 var_d = 12 var_e = 10 var_f = var_d * var_e var_g = 7 var_h = var_f + var_g list_b= [] if "/" in str(var_h): var_h = eval(str(var_h)) list_b.append(var_h) if "/" in str(var_c): var_c = eval(str(var_c)) list_b.append(var_c) list_b.reverse() var_i = 1 list_c=list_b.copy() list_c.sort() var_j = list_c[-var_i] var_k = list_b.index(var_j)+1 var_l = list_a[var_k-1] print(var_l)

어제

yesterday

[OP_LIST_SOL] 어제 오늘 [OP_LIST_EOL] [OP_LIST_SOL] 135 12 10 [OP_MUL] 7 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]

var_a = 'yesterday' var_b = 'today' list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 135 var_d = 12 var_e = 10 var_f = var_d * var_e var_g = 7 var_h = var_f + var_g list_b= [] if "/" in str(var_h): var_h = eval(str(var_h)) list_b.append(var_h) if "/" in str(var_c): var_c = eval(str(var_c)) list_b.append(var_c) list_b.reverse() var_i = 1 list_c=list_b.copy() list_c.sort() var_j = list_c[-var_i] var_k = list_b.index(var_j)+1 var_l = list_a[var_k-1] print(var_l)

[OP_LIST_SOL] yesterday today [OP_LIST_EOL] [OP_LIST_SOL] 135 12 10 [OP_MUL] 7 [OP_ADD] [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]

It rained 135 millimeters (mm) yesterday and 12 centimeters (cm) 7 millimeters (mm) today. Find the answer on which day it rained more between yesterday and today.

비가 어제는 135 밀리미터(㎜) 내렸고 오늘은 12 센티미터(㎝) 7 밀리미터(㎜) 내렸습니다. 어제와 오늘 중 비가 더 많이 내린 날은 언제인지 답을 구해 보세요.

Comparison

var_a = 18 var_b = 2 var_c = var_a / var_b var_d = 4 var_e = var_c - var_d print(int(var_e))

5

5

18 2 [OP_DIV] 4 [OP_SUB]

var_a = 18 var_b = 2 var_c = var_a / var_b var_d = 4 var_e = var_c - var_d print(int(var_e))

18 2 [OP_DIV] 4 [OP_SUB]

When you multiply a number by 2, you get 18. What is the value of this number when you subtract 4?

어떤 수에 2를 곱했더니 18이 되었습니다. 어떤 수에서 4를 빼면 얼마입니까?

Correspondence

var_a = 200 var_b = 8 var_c = 5 var_d = var_b * var_c var_e = var_a / var_d print(int(var_e))

5

5

200 8 5 [OP_MUL] [OP_DIV]

var_a = 200 var_b = 8 var_c = 5 var_d = var_b * var_c var_e = var_a / var_d print(int(var_e))

200 8 5 [OP_MUL] [OP_DIV]

It is said that it takes an hour to make 8 toys from one machine. How many hours would it take to make 200 toys using 5 machines?

하나의 기계에서 8개의 장난감을 만드는 데 1시간이 걸린다고 합니다. 200개의 장난감을 만들기 위해 5개의 기계를 사용한다면 총 몇 시간이 걸리는지 구하시오.

Arithmetic calculation

var_a = 96 var_b = 6 var_c = var_a / var_b var_d = 8 var_e = var_c / var_d print(int(var_e))

2

2

96 6 [OP_DIV] 8 [OP_DIV]

var_a = 96 var_b = 6 var_c = var_a / var_b var_d = 8 var_e = var_c / var_d print(int(var_e))

96 6 [OP_DIV] 8 [OP_DIV]

I have to divide a number by 8, but I accidentally multiply a number by 6 is 96. What is the correct calculation result?

어떤 수에 8을 나눠야 할 것을 잘못하여 6을 곱한 결과는 96이 되었습니다. 바르게 계산한 결과는 얼마인가요?

Correspondence

var_a = 16 var_b = 1 var_c = var_a - var_b print(int(var_c))

15

15

16 1 [OP_SUB]

var_a = 16 var_b = 1 var_c = var_a - var_b print(int(var_c))

16 1 [OP_SUB]

16 teams are about to have a soccer match. Two teams have a game to eliminate the losing team, while only the winning team is allowed to proceed to the next game, and the team who won the last game wins the match. Find the total number of games.

16개 팀이 축구 시합을 하려고 합니다. 두 팀씩 경기를 하여 패배한 팀은 탈락하고 승리한 팀만 다음 경기를 할 수 있으며, 마지막에 승리한 팀이 우승합니다. 경기의 총 횟수를 구하시오.

Possibility

var_a = 45 var_b = 1 var_c = var_a - var_b var_d = 11 var_e = var_c / var_d print(int(var_e))

4

4

45 1 [OP_SUB] 11 [OP_DIV]

var_a = 45 var_b = 1 var_c = var_a - var_b var_d = 11 var_e = var_c / var_d print(int(var_e))

45 1 [OP_SUB] 11 [OP_DIV]

Multiplying a number by 11 and adding 1 equals 45. Find the number.

어떤 수에 11을 곱한 뒤 1을 더하면 45이다. 어떤 수를 구하시오.

Correspondence

var_a = 5 var_b = 4 var_c = var_a + var_b var_d = 3 var_e = 5 var_f = var_d + var_e var_g = var_c * var_f print(int(var_g))

72

72

5 4 [OP_ADD] 3 5 [OP_ADD] [OP_MUL]

var_a = 5 var_b = 4 var_c = var_a + var_b var_d = 3 var_e = 5 var_f = var_d + var_e var_g = var_c * var_f print(int(var_g))

5 4 [OP_ADD] 3 5 [OP_ADD] [OP_MUL]

There are 5 types of hot coffee and 4 types of cold coffee in the cafe, and there are 3 types of cookies and 5 types of muffins. Find the number of cases where you order 1 coffee and 1 bread each.

카페에 커피는 뜨거운 커피 5종류, 차가운 커피 4종류가 있고 빵은 쿠키가 3종류, 머핀이 5종류가 있다. 커피와 빵을 각각 1개식 주문하는 경우의 수를 구하시오.

Possibility

var_a = 18 var_b = 10 var_c = var_a * var_b var_d = 10 var_e = 2 var_f = var_d * var_e var_g = 2 var_h = 18 var_i = var_g * var_h var_j = var_f + var_i var_k = 2 var_l = var_j * var_k var_m = var_c + var_l print(int(var_m))

292

292

18 10 [OP_MUL] 10 2 [OP_MUL] 2 18 [OP_MUL] [OP_ADD] 2 [OP_MUL] [OP_ADD]

var_a = 18 var_b = 10 var_c = var_a * var_b var_d = 10 var_e = 2 var_f = var_d * var_e var_g = 2 var_h = 18 var_i = var_g * var_h var_j = var_f + var_i var_k = 2 var_l = var_j * var_k var_m = var_c + var_l print(int(var_m))

18 10 [OP_MUL] 10 2 [OP_MUL] 2 18 [OP_MUL] [OP_ADD] 2 [OP_MUL] [OP_ADD]

A cuboid box is 18 centimeters (cm) long, 10 centimeters (cm) wide, and 2 centimeters (cm) high. How many square centimeters (cm2) will be covered to paint the entire inside of this uncovered box?

어떤 직육면체 모양의 상자는 가로가 18센티미터(㎝), 세로가 10센티미터(㎝), 높이가 2센티미터(㎝)이다. 이 뚜껑이 없는 상자의 안쪽 전체를 색칠하려면 몇 제곱센티미터(㎠)를 칠해야 하는가?

Geometry

var_a = 3 var_b = 4 var_c = var_a * var_b print(int(var_c))

12

12

3 4 [OP_MUL]

var_a = 3 var_b = 4 var_c = var_a * var_b print(int(var_c))

3 4 [OP_MUL]

You can go to the academy from school in 3 ways, and from the academy to the playground in 4 ways. In total, how many ways are there to get from school to the playground passing the academy?

학교가 끝난 후 학원까지 3가지의 방법으로 갈 수 있고, 학원에서 놀이터까지 4가지의 방법으로 갈 수 있습니다. 학교에서 학원을 거쳐 놀이터로 가는 방법은 총 몇 가지입니까?

Possibility

var_a = 25 var_b = 9 var_c = var_a * var_b var_d = 7 var_e = var_c + var_d var_f = 9 var_g = var_e * var_f print(int(var_g))

2088

2088

25 9 [OP_MUL] 7 [OP_ADD] 9 [OP_MUL]

var_a = 25 var_b = 9 var_c = var_a * var_b var_d = 7 var_e = var_c + var_d var_f = 9 var_g = var_e * var_f print(int(var_g))

25 9 [OP_MUL] 7 [OP_ADD] 9 [OP_MUL]

There is a number that is a multiple of 9. The quotient of a number divided by 9 is then divided again by 9, and the quotient is 25 and the remainder is 7. Find the number.

9의 배수인 어떤 수가 있다. 어떤 수를 9로 나눈 몫을 다시 9로 나누었더니 몫이 25이고 나머지가 7이었습니다. 어떤 수를 구하시오.

Correspondence

var_a = '태형' var_b = '민주' var_c = '상민' var_d = '윤정' var_e = '유정' list_a= [] if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_f = 1 var_g = list_a[var_f-1] print(var_g)

태형

Taehyung

[OP_LIST_SOL] 태형 민주 상민 윤정 유정 [OP_LIST_EOL] 1 [OP_LIST_GET]

var_a = 'Taehyung' var_b = 'Minju' var_c = 'Sangmin' var_d = 'Yoonjung' var_e = 'Yoojung' list_a= [] if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_f = 1 var_g = list_a[var_f-1] print(var_g)

[OP_LIST_SOL] Taehyung Minju Sangmin Yoonjung Yoojung [OP_LIST_EOL] 1 [OP_LIST_GET]

As a result of the Korean language test in the school, Taehyung, Minju, Sangmin, Yoonjung, and Yoojung received the highest score in that order. Who got the highest score?

학교에서 한국어 시험을 본 결과 태형, 민주, 상민, 윤정, 유정이 순으로 높은 점수를 받았다. 누가 가장 높은 점수를 얻었습니까?

Comparison

var_a = 9 var_b = 1 var_c = var_a - var_b var_d = 1 var_e = var_c + var_d print(int(var_e))

9

9

9 1 [OP_SUB] 1 [OP_ADD]

var_a = 9 var_b = 1 var_c = var_a - var_b var_d = 1 var_e = var_c + var_d print(int(var_e))

9 1 [OP_SUB] 1 [OP_ADD]

There are 9 people standing in a line from shortest to tallest. Consider Hoseok is the shortest. Then what place does Hoseok take when the line is in order from tallest to shortest?

키가 작은 사람부터 순서대로 9명이 한 줄로 서 있습니다. 호석이가 가장 키가 작습니다. 키가 큰 사람부터 순서대로 다시 줄을 서면 호석이는 앞에서부터 몇 번째에 서게 됩니까?

Comparison

var_a = 9 var_b = 4 var_c = var_a * var_b print(int(var_c))

36

36

9 4 [OP_MUL]

var_a = 9 var_b = 4 var_c = var_a * var_b print(int(var_c))

9 4 [OP_MUL]

What is the sum of the lengths of the four sides of a square with a side of 9 centimeters (cm), in cm (cm)?

한 변이 9센티미터(㎝)인 정사각형의 네 변의 길이의 합은 몇 센티미터(㎝)입니까?

Geometry

var_a = 12 var_b = 8 var_c = var_a * var_b print(int(var_c))

96

96

12 8 [OP_MUL]

var_a = 12 var_b = 8 var_c = var_a * var_b print(int(var_c))

12 8 [OP_MUL]

Find the perimeter of a regular octagon with a side length of 12 meters (m), in meters (m).

한 변의 길이가 12미터(m)인 정팔각형의 둘레는 몇 미터(m)인지 구해 보시오.

Geometry

var_a = 1000 var_b = 1 var_c = var_a * var_b var_d = 100 var_e = 16 var_f = var_d * var_e var_g = var_c + var_f var_h = 10 var_i = 28 var_j = var_h * var_i var_k = var_g + var_j var_l = 355 var_m = 245 var_n = 3 var_o = var_m * var_n var_p = var_l + var_o var_q = var_k - var_p print(int(var_q))

1790

1790

1000 1 [OP_MUL] 100 16 [OP_MUL] [OP_ADD] 10 28 [OP_MUL] [OP_ADD] 355 245 3 [OP_MUL] [OP_ADD] [OP_SUB]

var_a = 1000 var_b = 1 var_c = var_a * var_b var_d = 100 var_e = 16 var_f = var_d * var_e var_g = var_c + var_f var_h = 10 var_i = 28 var_j = var_h * var_i var_k = var_g + var_j var_l = 355 var_m = 245 var_n = 3 var_o = var_m * var_n var_p = var_l + var_o var_q = var_k - var_p print(int(var_q))

1000 1 [OP_MUL] 100 16 [OP_MUL] [OP_ADD] 10 28 [OP_MUL] [OP_ADD] 355 245 3 [OP_MUL] [OP_ADD] [OP_SUB]

A is a number comprised of 1 group of 1000, 16 groups of 100, and 28 groups of 10. B is calculated as 3 jumps from 355 with an interval of 245. Find the value of A-B.

A는 1000개씩 묶음이 1개, 100개씩 묶음이 16개, 10개씩 묶음이 28개인 수입니다. B는 355에서 245씩 커지게 3번 뛰어서 센 수입니다. A-B의 값을 구하시오.

Correspondence

var_a = 1650 var_b = 1650 var_c = 1250 var_d = var_b - var_c var_e = 1 var_f = var_d * var_e var_g = 0.3333333333333333 var_h = var_f / var_g var_i = var_a - var_h print(int(var_i))

450

450

1650 1650 1250 [OP_SUB] 1 [OP_MUL] 1/3 [OP_DIV] [OP_SUB]

var_a = 1650 var_b = 1650 var_c = 1250 var_d = var_b - var_c var_e = 1 var_f = var_d * var_e var_g = 0.3333333333333333 var_h = var_f / var_g var_i = var_a - var_h print(int(var_i))

1650 1650 1250 [OP_SUB] 1 [OP_MUL] 1/3 [OP_DIV] [OP_SUB]

A full bottle of milk weighs 1650 grams (g). After drinking 1/3 of the milk, I weighed the bottle again, which was 1250 grams (g). How many grams (g) does the bottle alone weigh?

우유가 가득 담긴 병의 무게는 1650그램(g)입니다. 이 중 우유의 1/3을 마신 후 병의 무게를 다시 재어 보니 1250그램(g)입니다. 병만의 무게는 몇 그램(g)입니까?

Arithmetic calculation

var_a = 1 var_b = 100 var_c = 1 var_d = var_b - var_c var_e = 2 var_f = var_d * var_e var_g = 1 var_h = var_f + var_g var_i = 2 list_a = [i for i in range(var_a, var_h + 1, var_i)] list_a = [float(i) for i in list_a] var_j = sum(list_a) print(int(var_j))

10000

10000

1 100 1 [OP_SUB] 2 [OP_MUL] 1 [OP_ADD] 2 [OP_LIST_ARANGE] [OP_LIST_SUM]

var_a = 1 var_b = 100 var_c = 1 var_d = var_b - var_c var_e = 2 var_f = var_d * var_e var_g = 1 var_h = var_f + var_g var_i = 2 list_a = [i for i in range(var_a, var_h + 1, var_i)] list_a = [float(i) for i in list_a] var_j = sum(list_a) print(int(var_j))

1 100 1 [OP_SUB] 2 [OP_MUL] 1 [OP_ADD] 2 [OP_LIST_ARANGE] [OP_LIST_SUM]

Find the sum of 100 consecutive odd numbers from 1.

1부터 연속하는 홀수 100개의 합을 구하시오

Arithmetic calculation

var_a = 7 var_b = 8 var_c = 9 var_d = 10 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_e = 2 list_b = [] var_e = int(var_e) for i in list_a: i = int(i) if i % var_e == 0: list_b.append(i) list_c = list(set(list_a) - set(list_b)) var_f = 3 list_d = [] var_f = int(var_f) for i in list_c: i = int(i) if i % var_f == 0: list_d.append(i) list_e = list(set(list_c) - set(list_d)) var_g = 10 list_f = [] for i in list_e: if i < var_g: list_f.append(i) var_h = 1 var_i = list_f[var_h-1] print(int(var_i))

7

7

[OP_LIST_SOL] 7 8 9 10 [OP_LIST_EOL] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] 3 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] 10 [OP_LIST_LESS] 1 [OP_LIST_GET]

var_a = 7 var_b = 8 var_c = 9 var_d = 10 list_a= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_e = 2 list_b = [] var_e = int(var_e) for i in list_a: i = int(i) if i % var_e == 0: list_b.append(i) list_c = list(set(list_a) - set(list_b)) var_f = 3 list_d = [] var_f = int(var_f) for i in list_c: i = int(i) if i % var_f == 0: list_d.append(i) list_e = list(set(list_c) - set(list_d)) var_g = 10 list_f = [] for i in list_e: if i < var_g: list_f.append(i) var_h = 1 var_i = list_f[var_h-1] print(int(var_i))

[OP_LIST_SOL] 7 8 9 10 [OP_LIST_EOL] 2 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] 3 [OP_LIST_DIVISIBLE] [OP_SET_DIFFERENCE] 10 [OP_LIST_LESS] 1 [OP_LIST_GET]

A number is less than 10 and is not a multiple of 2 or 3. Which number is it out of 7, 8, 9, or 10?

어떤 수는 10보다 작고, 2의 배수나 3의 배수가 아닙니다. 7, 8, 9, 10 중 어떤 수를 구하시오.

Correspondence

var_a = 2 var_b = 4 var_c = 3 list_a= [] if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_d = 3 list_b = [str(i) for i in list_a] list_b = list(itertools.permutations(list_b, var_d)) list_b = [''.join(num_list) for num_list in list_b] list_b = [str_num for str_num in list_b if str_num[0] != '0'] list_b = [float(i) for i in list_b] var_e = 340 list_c = [] for i in list_b: if i < var_e: list_c.append(i) var_f = len(list_c) print(int(var_f))

3

3

[OP_LIST_SOL] 2 4 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 340 [OP_LIST_LESS] [OP_LIST_LEN]

var_a = 2 var_b = 4 var_c = 3 list_a= [] if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_d = 3 list_b = [str(i) for i in list_a] list_b = list(itertools.permutations(list_b, var_d)) list_b = [''.join(num_list) for num_list in list_b] list_b = [str_num for str_num in list_b if str_num[0] != '0'] list_b = [float(i) for i in list_b] var_e = 340 list_c = [] for i in list_b: if i < var_e: list_c.append(i) var_f = len(list_c) print(int(var_f))

[OP_LIST_SOL] 2 4 3 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 340 [OP_LIST_LESS] [OP_LIST_LEN]

The dice are rolled and the dots 2, 4, and 3 come out. How many three-digit numbers formed by using all the digits once are less than 340?

주사위를 던져 나온 숫자가 2, 4, 3입니다. 나온 숫자를 한 번씩 모두 사용하여 만든 세 자리 수 중 340보다 작은 수는 모두 몇 개입니까?

Possibility

var_a = 600 var_b = 800 var_c = 2 list_a = [i for i in range(var_a, var_b + 1, var_c)] list_b=[] for i in list_a: var_d = 0 i = int(i) while i//10 > 0: var_d = var_d + i%10 i = i//10 var_d = var_d + i%10 list_b.append(var_d) list_b = [float(i) for i in list_b] var_e = sum(list_b) print(int(var_e))

1508

1508

600 800 2 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] [OP_LIST_SUM]

var_a = 600 var_b = 800 var_c = 2 list_a = [i for i in range(var_a, var_b + 1, var_c)] list_b=[] for i in list_a: var_d = 0 i = int(i) while i//10 > 0: var_d = var_d + i%10 i = i//10 var_d = var_d + i%10 list_b.append(var_d) list_b = [float(i) for i in list_b] var_e = sum(list_b) print(int(var_e))

600 800 2 [OP_LIST_ARANGE] [OP_LIST_NUM2SUM] [OP_LIST_SUM]

Find the sum of the digits of the even numbers from 600 to 800.

600부터 800까지의 짝수들의 각 자리의 숫자를 더하면 얼마인지 구하여라.

Arithmetic calculation

var_a = 12 var_b = 7 var_c = var_a * var_b var_d = 5 var_e = var_c + var_d var_f = 8 var_g = var_e % var_f print(int(var_g))

1

1

12 7 [OP_MUL] 5 [OP_ADD] 8 [OP_MOD]

var_a = 12 var_b = 7 var_c = var_a * var_b var_d = 5 var_e = var_c + var_d var_f = 8 var_g = var_e % var_f print(int(var_g))

12 7 [OP_MUL] 5 [OP_ADD] 8 [OP_MOD]

Seoyoon's teacher bought her class pizzas. There were 7 students in Seoyoon's class, and each student took 12 pieces, leaving 5 pieces. At this moment, Seoyoon's neighboring classmate came in to play, so it is decided to distribute the pizza again to 8 people including Seoyoon's friend. Find the number of remaining pizza slices at this time.

서윤이네 반 선생님께서 피자를 사주셨다. 서윤이네 반 학생은 모두 7명인데 한 명당 12조각씩 가지고 5조각이 남았다. 이때 서윤이의 옆 반 친구가 놀러와 서윤이의 친구를 포함해서 8명에게 다시 나눠주기로 하였다. 이때 남는 피자 조각의 개수는 몇 조각인지 구하시오.

Correspondence

var_a = '정국' var_b = '지민' list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 3 var_d = 5 list_b= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_b.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_b.append(var_c) list_b.reverse() var_e = 1 list_c=list_b.copy() list_c.sort() var_f = list_c[-var_e] var_g = list_b.index(var_f)+1 var_h = list_a[var_g-1] print(var_h)

지민

Jimin

[OP_LIST_SOL] 정국 지민 [OP_LIST_EOL] [OP_LIST_SOL] 3 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]

var_a = 'Jungkook' var_b = 'Jimin' list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 3 var_d = 5 list_b= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_b.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_b.append(var_c) list_b.reverse() var_e = 1 list_c=list_b.copy() list_c.sort() var_f = list_c[-var_e] var_g = list_b.index(var_f)+1 var_h = list_a[var_g-1] print(var_h)

[OP_LIST_SOL] Jungkook Jimin [OP_LIST_EOL] [OP_LIST_SOL] 3 5 [OP_LIST_EOL] 1 [OP_LIST_MAX] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]

JungKook and Jimin walked up the stairs to the third floor. Jimin took the elevator from the 3rd floor to the 5th floor. Who has risen higher, Jung Kook or Jimin?

정국이와 지민이는 계단을 걸어서 3층까지 올라갔습니다. 지민이는 3층에서 엘리베이터를 타고 5층까지 올라갔습니다. 정국이와 지민이 중 더 높이 올라간 사람은 누구입니까?

Comparison

var_a = 348 var_b = 173 var_c = var_a + var_b var_d = 299 var_e = var_c + var_d print(int(var_e))

820

820

348 173 [OP_ADD] 299 [OP_ADD]

var_a = 348 var_b = 173 var_c = var_a + var_b var_d = 299 var_e = var_c + var_d print(int(var_e))

348 173 [OP_ADD] 299 [OP_ADD]

A is 348 and A is less than B by 173. C is greater than B by 299. Find C.

A는 348입니다. A는 B보다 173만큼 작습니다. C는 B보다 299만큼 큽니다. C를 구하시오.

Correspondence

var_a = 16 var_b = 11 var_c = var_a + var_b var_d = 20 var_e = var_c - var_d var_f = 2 var_g = var_e - var_f print(int(var_g))

5

5

16 11 [OP_ADD] 20 [OP_SUB] 2 [OP_SUB]

var_a = 16 var_b = 11 var_c = var_a + var_b var_d = 20 var_e = var_c - var_d var_f = 2 var_g = var_e - var_f print(int(var_g))

16 11 [OP_ADD] 20 [OP_SUB] 2 [OP_SUB]

20 cars of different colors are parked in a row. The black car is 16th from the right, and the white car is 11th from the left. How many cars are between the black and white cars?

각각의 색이 다른 자동차 20대가 한 줄로 주차되어 있습니다. 검은색 자동차는 오른쪽에서 16번째에 있고, 흰색 자동차는 왼쪽에서 11번째에 있습니다. 검은색 자동차와 흰색 자동차 사이에 있는 자동차는 몇 대입니까?

Comparison

var_a = 69 var_b = 5 var_c = var_a - var_b var_d = 86 var_e = 6 var_f = var_d - var_e var_g = math.gcd(int(var_f), int(var_c)) print(int(var_g))

16

16

69 5 [OP_SUB] 86 6 [OP_SUB] [OP_GCD]

var_a = 69 var_b = 5 var_c = var_a - var_b var_d = 86 var_e = 6 var_f = var_d - var_e var_g = math.gcd(int(var_f), int(var_c)) print(int(var_g))

69 5 [OP_SUB] 86 6 [OP_SUB] [OP_GCD]

The number of students in Class 1 is 69 and the number of students in Class 2 is 86. When I asked the students in Class 1 and Class 2 to form groups, there were 5 students left in Class 1 and 6 students in Class 2. Find the maximum number of people in a group.

1반 학생들의 수는 69명이고 2반 학생들의 수는 86명이다. 1반과 2반 학생들에게 몇 명씩 조를 짜라고 하였더니 1반에서는 5명이 남고 2반에는 6명이 남았다. 한 조에 최대 몇 명이 모일 수 있는지 구하시오.

Correspondence

var_a = 25 var_b = 25 var_c = 6 var_d = var_b - var_c var_e = 30 var_f = 1 var_g = var_e - var_f var_h = var_d * var_g var_i = var_a + var_h print(int(var_i))

576

576

25 25 6 [OP_SUB] 30 1 [OP_SUB] [OP_MUL] [OP_ADD]

var_a = 25 var_b = 25 var_c = 6 var_d = var_b - var_c var_e = 30 var_f = 1 var_g = var_e - var_f var_h = var_d * var_g var_i = var_a + var_h print(int(var_i))

25 25 6 [OP_SUB] 30 1 [OP_SUB] [OP_MUL] [OP_ADD]

Thirty sheets of 25 centimeters (cm) long paper strips were overlapped by 6 centimeters (cm) each and made a long line. Find the total length in centimeters (cm) of the 30 strips of paper glued together.

길이가 25센티미터(㎝)인 종이띠 30장을 6센티미터(㎝)씩 겹쳐서 한 줄로 길게 이어 붙였습니다. 30장을 이어 붙인 종이띠의 전체 길이는 몇 센티미터(㎝)인지 구해 보시오.

Arithmetic calculation

var_a = '632-5AB=41' var_b = 'A' ans_dict = dict() var_a = var_a.replace('×','*') var_a = var_a.replace('x','*') var_a = var_a.replace('÷','/') variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a): if v in variable_candi: ans_dict[v] = 1 candi = list(itertools.product('0123456789', repeat=len(ans_dict))) for c in candi: temp = var_a for i, (k, _) in enumerate(ans_dict.items()): temp = temp.replace(k, str(c[i])) term_list = [] op_list = [] temp_c = '' for tc in temp: if tc not in '+-*/=><().': temp_c += tc else: op_list.append(tc) term_list.append(temp_c) temp_c = '' term_list.append(temp_c) new_eq = '' for i in range(len(op_list)): new_eq += str(int(term_list[i]))+op_list[i] new_eq += str(int(term_list[-1])) if len(new_eq) == len(var_a): new_eq=new_eq.replace('=', '==') new_eq=new_eq.replace('>==', '>=') new_eq=new_eq.replace('<==', '<=') eval_result = False try: eval_result = eval(new_eq) except: pass if eval_result: for i, (k, _) in enumerate(ans_dict.items()): ans_dict[k] = int(c[i]) var_c = ans_dict[var_b] print(int(var_c))

9

9

632-5AB=41 A [OP_DIGIT_UNK_SOLVER]

var_a = '632-5AB=41' var_b = 'A' ans_dict = dict() var_a = var_a.replace('×','*') var_a = var_a.replace('x','*') var_a = var_a.replace('÷','/') variable_candi = set(['A', 'B', 'C', 'D', 'E', 'F', 'G', 'H', 'I', 'J', 'K', 'L', 'M', 'N', 'O', 'P', 'Q', 'R', 'S', 'T', 'U', 'V', 'W', 'X', 'Y', 'Z']) for v in set(var_a): if v in variable_candi: ans_dict[v] = 1 candi = list(itertools.product('0123456789', repeat=len(ans_dict))) for c in candi: temp = var_a for i, (k, _) in enumerate(ans_dict.items()): temp = temp.replace(k, str(c[i])) term_list = [] op_list = [] temp_c = '' for tc in temp: if tc not in '+-*/=><().': temp_c += tc else: op_list.append(tc) term_list.append(temp_c) temp_c = '' term_list.append(temp_c) new_eq = '' for i in range(len(op_list)): new_eq += str(int(term_list[i]))+op_list[i] new_eq += str(int(term_list[-1])) if len(new_eq) == len(var_a): new_eq=new_eq.replace('=', '==') new_eq=new_eq.replace('>==', '>=') new_eq=new_eq.replace('<==', '<=') eval_result = False try: eval_result = eval(new_eq) except: pass if eval_result: for i, (k, _) in enumerate(ans_dict.items()): ans_dict[k] = int(c[i]) var_c = ans_dict[var_b] print(int(var_c))

632-5AB=41 A [OP_DIGIT_UNK_SOLVER]

What number must go into A to make 632-5AB=41?

632-5AB=41이 성립하기 위해 A에 들어가야 하는 숫자는 무엇인가요?

Correspondence

var_a = 'A' var_b = 'B' list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 10 var_d = 3 var_e = var_c * var_d var_f = 7 var_g = var_e + var_f var_h = 40 var_i = 1 var_j = var_h - var_i list_b= [] if "/" in str(var_j): var_j = eval(str(var_j)) list_b.append(var_j) if "/" in str(var_g): var_g = eval(str(var_g)) list_b.append(var_g) list_b.reverse() var_k = 1 list_c=list_b.copy() list_c.sort() var_l = list_c[var_k-1] var_m = list_b.index(var_l)+1 var_n = list_a[var_m-1] print(var_n)

A

A

[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 10 3 [OP_MUL] 7 [OP_ADD] 40 1 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]

var_a = 'A' var_b = 'B' list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 10 var_d = 3 var_e = var_c * var_d var_f = 7 var_g = var_e + var_f var_h = 40 var_i = 1 var_j = var_h - var_i list_b= [] if "/" in str(var_j): var_j = eval(str(var_j)) list_b.append(var_j) if "/" in str(var_g): var_g = eval(str(var_g)) list_b.append(var_g) list_b.reverse() var_k = 1 list_c=list_b.copy() list_c.sort() var_l = list_c[var_k-1] var_m = list_b.index(var_l)+1 var_n = list_a[var_m-1] print(var_n)

[OP_LIST_SOL] A B [OP_LIST_EOL] [OP_LIST_SOL] 10 3 [OP_MUL] 7 [OP_ADD] 40 1 [OP_SUB] [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]

A is 3 groups of 10 and 7 individual units, and B is the number obtained by subtracting 1 from 40. Which is smaller, A or B?

A는 10개씩 3묶음과 낱개가 7개이고, B는 40에서 1을 뺀 수입니다. A, B 중 작은 수는 무엇입니까?

Comparison

var_a = 9 var_b = 16 var_c = var_a * var_b var_d = 0.5 var_e = var_c ** var_d print(int(var_e))

12

12

9 16 [OP_MUL] 1/2 [OP_POW]

var_a = 9 var_b = 16 var_c = var_a * var_b var_d = 0.5 var_e = var_c ** var_d print(int(var_e))

9 16 [OP_MUL] 1/2 [OP_POW]

A rectangle-shaped notebook and a square-shaped notebook have the same area. If the lengths of the two sides of the notebook are 9 centimeters (cm) and 16 centimeters (cm), respectively. How many centimeters (cm) are the length of one side of the notebook?

직사각형 모양의 공책과 정사각형 모양의 수첩의 넓이는 같습니다. 공책의 두 변의 길이가 각각 9센티미터(㎝), 16센티미터(㎝)일 때, 수첩의 한 변의 길이는 몇 센티미터(㎝)인지 구하시오.

Geometry

var_a = 40 var_b = 2 var_c = var_a / var_b var_d = 8 var_e = var_c - var_d print(int(var_e))

12

12

40 2 [OP_DIV] 8 [OP_SUB]

var_a = 40 var_b = 2 var_c = var_a / var_b var_d = 8 var_e = var_c - var_d print(int(var_e))

40 2 [OP_DIV] 8 [OP_SUB]

You have a rectangle with a perimeter of 40 centimeters (cm). If the width of this rectangle is 8 centimeters (cm), how many centimeters (cm) is the length?

둘레가 40센티미터(㎝)인 직사각형이 있습니다. 이 직사각형의 가로 길이가 8센티미터(㎝)일 때 세로는 몇 센티미터(㎝)입니까?

Geometry

var_a = 1 var_b = 30 var_c = 1 var_d = var_b - var_c var_e = 1 list_a = [i for i in range(var_a, var_d + 1, var_e)] var_f = 4 list_b = [] var_f = int(var_f) for i in list_a: i = int(i) if i % var_f == 0: list_b.append(i) var_g = len(list_b) print(int(var_g))

7

7

1 30 1 [OP_SUB] 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]

var_a = 1 var_b = 30 var_c = 1 var_d = var_b - var_c var_e = 1 list_a = [i for i in range(var_a, var_d + 1, var_e)] var_f = 4 list_b = [] var_f = int(var_f) for i in list_a: i = int(i) if i % var_f == 0: list_b.append(i) var_g = len(list_b) print(int(var_g))

1 30 1 [OP_SUB] 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]

Find how many multiples of 4 are less than 30.

30보다 작은 4의 배수는 모두 몇 개인지 구하세요.

Possibility

var_a = 23 var_b = 9 var_c = var_a - var_b print(int(var_c))

14

14

23 9 [OP_SUB]

var_a = 23 var_b = 9 var_c = var_a - var_b print(int(var_c))

23 9 [OP_SUB]

There are 9 dogs and 23 cats. How many more cats are there than dogs?

개가 9마리, 고양이가 23마리 있습니다. 고양이는 개보다 몇 마리 더 많습니까?

Arithmetic calculation

var_a = 45 var_b = 21 var_c = var_a - var_b var_d = 18 var_e = var_c + var_d print(int(var_e))

42

42

45 21 [OP_SUB] 18 [OP_ADD]

var_a = 45 var_b = 21 var_c = var_a - var_b var_d = 18 var_e = var_c + var_d print(int(var_e))

45 21 [OP_SUB] 18 [OP_ADD]

There are 45 apples. There are 21 fewer pears than apples. How many tangerines are there if there are 18 fewer pears than tangerines?

사과가 45개 있습니다. 배는 사과보다 21개 적습니다. 배가 귤보다 18개 더 적다면 귤은 몇 개입니까?

Arithmetic calculation

var_a = 'A' var_b = 'B' var_c = 'C' var_d = 'D' var_e = 'E' list_a= [] if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_f = 'A' var_g = 'B' var_h = 'C' list_b= [] if "/" in str(var_h): var_h = eval(str(var_h)) list_b.append(var_h) if "/" in str(var_g): var_g = eval(str(var_g)) list_b.append(var_g) if "/" in str(var_f): var_f = eval(str(var_f)) list_b.append(var_f) list_b.reverse() list_c = list(set(list_a) - set(list_b)) var_i = len(list_c) var_j = len(list_c) var_k = 1 var_i = int(var_i) var_j = int(var_j) for i, elem in enumerate(range(var_j)): var_k = var_k * (var_i-i) print(int(var_k))

2

2

[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]

var_a = 'A' var_b = 'B' var_c = 'C' var_d = 'D' var_e = 'E' list_a= [] if "/" in str(var_e): var_e = eval(str(var_e)) list_a.append(var_e) if "/" in str(var_d): var_d = eval(str(var_d)) list_a.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_f = 'A' var_g = 'B' var_h = 'C' list_b= [] if "/" in str(var_h): var_h = eval(str(var_h)) list_b.append(var_h) if "/" in str(var_g): var_g = eval(str(var_g)) list_b.append(var_g) if "/" in str(var_f): var_f = eval(str(var_f)) list_b.append(var_f) list_b.reverse() list_c = list(set(list_a) - set(list_b)) var_i = len(list_c) var_j = len(list_c) var_k = 1 var_i = int(var_i) var_j = int(var_j) for i, elem in enumerate(range(var_j)): var_k = var_k * (var_i-i) print(int(var_k))

[OP_LIST_SOL] A B C D E [OP_LIST_EOL] [OP_LIST_SOL] A B C [OP_LIST_EOL] [OP_SET_DIFFERENCE] [OP_LIST_LEN] [OP_LIST_LEN] [OP_PERM]

You want to put 5 different books A, B, C, D, and E on a bookshelf. When A, B, and C are placed on the left side in such order, find the number of ways to place books on the bookshelf.

서로 다른 책 A, B, C, D, E 5권을 책꽂이에 꽂으려고 한다. A, B, C를 차례로 왼쪽에 꽂을 때, 책을 책꽂이에 꽂는 경우의 수를 구하시오.

Possibility

var_a = '윤기' var_b = '정국' list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 7 var_d = 6 list_b= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_b.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_b.append(var_c) list_b.reverse() var_e = 1 list_c=list_b.copy() list_c.sort() var_f = list_c[var_e-1] var_g = list_b.index(var_f)+1 var_h = list_a[var_g-1] print(var_h)

정국

Jungkook

[OP_LIST_SOL] 윤기 정국 [OP_LIST_EOL] [OP_LIST_SOL] 7 6 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]

var_a = 'Yoongi' var_b = 'Jungkook' list_a= [] if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_c = 7 var_d = 6 list_b= [] if "/" in str(var_d): var_d = eval(str(var_d)) list_b.append(var_d) if "/" in str(var_c): var_c = eval(str(var_c)) list_b.append(var_c) list_b.reverse() var_e = 1 list_c=list_b.copy() list_c.sort() var_f = list_c[var_e-1] var_g = list_b.index(var_f)+1 var_h = list_a[var_g-1] print(var_h)

[OP_LIST_SOL] Yoongi Jungkook [OP_LIST_EOL] [OP_LIST_SOL] 7 6 [OP_LIST_EOL] 1 [OP_LIST_MIN] [OP_LIST_INDEX] [OP_LIST_POP] [OP_LIST_GET]

Two students, Yoongi and Jungkook, have numbers 7 and 6, respectively. Whose number is smaller?

두 명의 학생 윤기, 정국은 각각 7, 6만큼의 숫자를 가지고 있습니다. 누구의 수가 더 작습니까?

Comparison

var_a = 10 var_b = 21 var_c = var_a * var_b var_d = 1 var_e = 8 var_f = var_d * var_e var_g = var_c + var_f var_h = 0.1 var_i = 5 var_j = var_h * var_i var_k = var_g + var_j var_l = 0.01 var_m = 34 var_n = var_l * var_m var_o = var_k + var_n print('{:.2f}'.format(round(var_o+1e-10,2)))

218.84

218.84

10 21 [OP_MUL] 1 8 [OP_MUL] [OP_ADD] 0.1 5 [OP_MUL] [OP_ADD] 0.01 34 [OP_MUL] [OP_ADD]

var_a = 10 var_b = 21 var_c = var_a * var_b var_d = 1 var_e = 8 var_f = var_d * var_e var_g = var_c + var_f var_h = 0.1 var_i = 5 var_j = var_h * var_i var_k = var_g + var_j var_l = 0.01 var_m = 34 var_n = var_l * var_m var_o = var_k + var_n print('{:.2f}'.format(round(var_o+1e-10,2)))

10 21 [OP_MUL] 1 8 [OP_MUL] [OP_ADD] 0.1 5 [OP_MUL] [OP_ADD] 0.01 34 [OP_MUL] [OP_ADD]

10's are 21, 1's are 8, 0.1's are 5, and 0.01's are 34 in a certain number. How much is this number?

10 이 21 개, 1 이 8 개, 0.1 이 5 개, 0.01 이 34 개인 수는 얼마입니까?

Arithmetic calculation

var_a = 6 var_b = 3 var_c = 8 list_a= [] if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_d = 3 list_b = [str(i) for i in list_a] list_b = list(itertools.permutations(list_b, var_d)) list_b = [''.join(num_list) for num_list in list_b] list_b = [str_num for str_num in list_b if str_num[0] != '0'] list_b = [float(i) for i in list_b] var_e = 1 list_c=list_b.copy() list_c.sort() var_f = list_c[-var_e] var_g = 1 list_d=list_b.copy() list_d.sort() var_h = list_d[var_g-1] var_i = var_f + var_h print(int(var_i))

1231

1231

[OP_LIST_SOL] 6 3 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]

var_a = 6 var_b = 3 var_c = 8 list_a= [] if "/" in str(var_c): var_c = eval(str(var_c)) list_a.append(var_c) if "/" in str(var_b): var_b = eval(str(var_b)) list_a.append(var_b) if "/" in str(var_a): var_a = eval(str(var_a)) list_a.append(var_a) list_a.reverse() var_d = 3 list_b = [str(i) for i in list_a] list_b = list(itertools.permutations(list_b, var_d)) list_b = [''.join(num_list) for num_list in list_b] list_b = [str_num for str_num in list_b if str_num[0] != '0'] list_b = [float(i) for i in list_b] var_e = 1 list_c=list_b.copy() list_c.sort() var_f = list_c[-var_e] var_g = 1 list_d=list_b.copy() list_d.sort() var_h = list_d[var_g-1] var_i = var_f + var_h print(int(var_i))

[OP_LIST_SOL] 6 3 8 [OP_LIST_EOL] 3 [OP_LIST_GET_PERM] 1 [OP_LIST_MAX] 1 [OP_LIST_MIN] [OP_ADD]

Given 3 number cards with 6, 3, and 8 written on them, find the sum of the largest and smallest three-digit numbers that can be formed by using each card only once.

6, 3, 8이 각각 적힌 숫자 카드 3장이 있을 때, 각 카드를 딱 한 번씩만 사용하여 만들 수 있는 세 자리 수 중에서 가장 큰 수와 가장 작은 수의 합을 구하시오.

Possibility

var_a = 100 var_b = 999 var_c = 1 list_a = [i for i in range(var_a, var_b + 1, var_c)] var_d = 4 list_b = [] var_d = int(var_d) for i in list_a: i = int(i) if i % var_d == 0: list_b.append(i) var_e = 5 list_c = [] var_e = int(var_e) for i in list_b: i = int(i) if i % var_e == 0: list_c.append(i) var_f = len(list_c) print(int(var_f))

45

45

100 999 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]

var_a = 100 var_b = 999 var_c = 1 list_a = [i for i in range(var_a, var_b + 1, var_c)] var_d = 4 list_b = [] var_d = int(var_d) for i in list_a: i = int(i) if i % var_d == 0: list_b.append(i) var_e = 5 list_c = [] var_e = int(var_e) for i in list_b: i = int(i) if i % var_e == 0: list_c.append(i) var_f = len(list_c) print(int(var_f))

100 999 1 [OP_LIST_ARANGE] 4 [OP_LIST_DIVISIBLE] 5 [OP_LIST_DIVISIBLE] [OP_LIST_LEN]

How many three-digit numbers are common multiples of 4 and 5?

세 자리 수 중 4와 5의 공배수는 모두 몇 개 입니까?

Arithmetic calculation

var_a = 1 var_b = 60 var_c = var_a * var_b var_d = 30 var_e = var_c / var_d var_f = 180 var_g = var_e * var_f print(int(var_g))

360

360

1 60 [OP_MUL] 30 [OP_DIV] 180 [OP_MUL]

var_a = 1 var_b = 60 var_c = var_a * var_b var_d = 30 var_e = var_c / var_d var_f = 180 var_g = var_e * var_f print(int(var_g))

1 60 [OP_MUL] 30 [OP_DIV] 180 [OP_MUL]

Yewon ran at a speed of 180 meters (m) in 30 seconds. How many meters (m) did Yewon run in 1 minute?

예원이는 30초에 180미터(m)를 달리는 빠르기로 달렸다. 1분 동안 예원이가 달린 거리는 몇 미터(m)인가?

Arithmetic calculation

var_a = 4 var_b = 5 var_c = var_a * var_b var_d = 10 var_e = var_c - var_d var_f = 3 var_g = var_e * var_f var_h = 18 var_i = var_g - var_h print(int(var_i))

12

12

4 5 [OP_MUL] 10 [OP_SUB] 3 [OP_MUL] 18 [OP_SUB]

var_a = 4 var_b = 5 var_c = var_a * var_b var_d = 10 var_e = var_c - var_d var_f = 3 var_g = var_e * var_f var_h = 18 var_i = var_g - var_h print(int(var_i))

4 5 [OP_MUL] 10 [OP_SUB] 3 [OP_MUL] 18 [OP_SUB]

There is a number that is divisible by 5 and the resulting quotient is 4. Subtract 10 from that particular number, and then multiply by 3, and then subtract 18. What is the answer?

5로 나누어떨어지고 5로 나눈 몫이 4인 어떤 수가 있다. 어떤 수에서 10을 빼고 3을 곱한 후 18을 뺀 값을 구하세요.

Correspondence

var_a = 1.5 var_b = 2.3333333333333335 var_c = var_a + var_b var_d = 2.3333333333333335 var_e = var_c + var_d print('{:.2f}'.format(round(var_e+1e-10,2)))

6.17

6.17

3/2 7/3 [OP_ADD] 7/3 [OP_ADD]

var_a = 1.5 var_b = 2.3333333333333335 var_c = var_a + var_b var_d = 2.3333333333333335 var_e = var_c + var_d print('{:.2f}'.format(round(var_e+1e-10,2)))

3/2 7/3 [OP_ADD] 7/3 [OP_ADD]

Subtracting 7/3 from a number equals 3/2. What is the result if you add 7/3 to that number?

어떤 수에서 7/3을 빼면 3/2이다. 어떤 수에서 7/3을 더하면 얼마인지 구하시오.

Correspondence