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You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:How many heads of the departments are older than 56 ?, schema:CREATE TABLE IF NOT EXISTS "department" ("Department_ID" int,"Name" text,"Creation" text,"Ranking" int,"Budget_in_Billions" real,"Num_Employees" real,PRIMARY KEY ("Department_ID")); CREATE TABLE IF NOT EXISTS "head" ("head_ID" int,"name" text,"born_state" text,"age" real,PRIMARY KEY ("head_ID")); CREATE TABLE IF NOT EXISTS "management" ("department_ID" int,"head_ID" int,"temporary_acting" text,PRIMARY KEY ("Department_ID","head_ID"),FOREIGN KEY ("Department_ID") REFERENCES `department`("Department_ID"),FOREIGN KEY ("head_ID") REFERENCES `head`("head_ID"));

SELECT count(*) FROM head WHERE age > 56

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:List the name, born state and age of the heads of departments ordered by age., schema:CREATE TABLE IF NOT EXISTS "department" ("Department_ID" int,"Name" text,"Creation" text,"Ranking" int,"Budget_in_Billions" real,"Num_Employees" real,PRIMARY KEY ("Department_ID")); CREATE TABLE IF NOT EXISTS "head" ("head_ID" int,"name" text,"born_state" text,"age" real,PRIMARY KEY ("head_ID")); CREATE TABLE IF NOT EXISTS "management" ("department_ID" int,"head_ID" int,"temporary_acting" text,PRIMARY KEY ("Department_ID","head_ID"),FOREIGN KEY ("Department_ID") REFERENCES `department`("Department_ID"),FOREIGN KEY ("head_ID") REFERENCES `head`("head_ID"));

SELECT name , born_state , age FROM head ORDER BY age

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:List the creation year, name and budget of each department., schema:CREATE TABLE IF NOT EXISTS "department" ("Department_ID" int,"Name" text,"Creation" text,"Ranking" int,"Budget_in_Billions" real,"Num_Employees" real,PRIMARY KEY ("Department_ID")); CREATE TABLE IF NOT EXISTS "head" ("head_ID" int,"name" text,"born_state" text,"age" real,PRIMARY KEY ("head_ID")); CREATE TABLE IF NOT EXISTS "management" ("department_ID" int,"head_ID" int,"temporary_acting" text,PRIMARY KEY ("Department_ID","head_ID"),FOREIGN KEY ("Department_ID") REFERENCES `department`("Department_ID"),FOREIGN KEY ("head_ID") REFERENCES `head`("head_ID"));

SELECT creation , name , budget_in_billions FROM department

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the maximum and minimum budget of the departments?, schema:CREATE TABLE IF NOT EXISTS "department" ("Department_ID" int,"Name" text,"Creation" text,"Ranking" int,"Budget_in_Billions" real,"Num_Employees" real,PRIMARY KEY ("Department_ID")); CREATE TABLE IF NOT EXISTS "head" ("head_ID" int,"name" text,"born_state" text,"age" real,PRIMARY KEY ("head_ID")); CREATE TABLE IF NOT EXISTS "management" ("department_ID" int,"head_ID" int,"temporary_acting" text,PRIMARY KEY ("Department_ID","head_ID"),FOREIGN KEY ("Department_ID") REFERENCES `department`("Department_ID"),FOREIGN KEY ("head_ID") REFERENCES `head`("head_ID"));

SELECT max(budget_in_billions) , min(budget_in_billions) FROM department

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the average number of employees of the departments whose rank is between 10 and 15?, schema:CREATE TABLE IF NOT EXISTS "department" ("Department_ID" int,"Name" text,"Creation" text,"Ranking" int,"Budget_in_Billions" real,"Num_Employees" real,PRIMARY KEY ("Department_ID")); CREATE TABLE IF NOT EXISTS "head" ("head_ID" int,"name" text,"born_state" text,"age" real,PRIMARY KEY ("head_ID")); CREATE TABLE IF NOT EXISTS "management" ("department_ID" int,"head_ID" int,"temporary_acting" text,PRIMARY KEY ("Department_ID","head_ID"),FOREIGN KEY ("Department_ID") REFERENCES `department`("Department_ID"),FOREIGN KEY ("head_ID") REFERENCES `head`("head_ID"));

SELECT avg(num_employees) FROM department WHERE ranking BETWEEN 10 AND 15

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the names of the heads who are born outside the California state?, schema:CREATE TABLE IF NOT EXISTS "department" ("Department_ID" int,"Name" text,"Creation" text,"Ranking" int,"Budget_in_Billions" real,"Num_Employees" real,PRIMARY KEY ("Department_ID")); CREATE TABLE IF NOT EXISTS "head" ("head_ID" int,"name" text,"born_state" text,"age" real,PRIMARY KEY ("head_ID")); CREATE TABLE IF NOT EXISTS "management" ("department_ID" int,"head_ID" int,"temporary_acting" text,PRIMARY KEY ("Department_ID","head_ID"),FOREIGN KEY ("Department_ID") REFERENCES `department`("Department_ID"),FOREIGN KEY ("head_ID") REFERENCES `head`("head_ID"));

SELECT name FROM head WHERE born_state != 'California'

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the distinct creation years of the departments managed by a secretary born in state 'Alabama'?, schema:CREATE TABLE IF NOT EXISTS "department" ("Department_ID" int,"Name" text,"Creation" text,"Ranking" int,"Budget_in_Billions" real,"Num_Employees" real,PRIMARY KEY ("Department_ID")); CREATE TABLE IF NOT EXISTS "head" ("head_ID" int,"name" text,"born_state" text,"age" real,PRIMARY KEY ("head_ID")); CREATE TABLE IF NOT EXISTS "management" ("department_ID" int,"head_ID" int,"temporary_acting" text,PRIMARY KEY ("Department_ID","head_ID"),FOREIGN KEY ("Department_ID") REFERENCES `department`("Department_ID"),FOREIGN KEY ("head_ID") REFERENCES `head`("head_ID"));

SELECT DISTINCT T1.creation FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T3.born_state = 'Alabama'

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the names of the states where at least 3 heads were born?, schema:CREATE TABLE IF NOT EXISTS "department" ("Department_ID" int,"Name" text,"Creation" text,"Ranking" int,"Budget_in_Billions" real,"Num_Employees" real,PRIMARY KEY ("Department_ID")); CREATE TABLE IF NOT EXISTS "head" ("head_ID" int,"name" text,"born_state" text,"age" real,PRIMARY KEY ("head_ID")); CREATE TABLE IF NOT EXISTS "management" ("department_ID" int,"head_ID" int,"temporary_acting" text,PRIMARY KEY ("Department_ID","head_ID"),FOREIGN KEY ("Department_ID") REFERENCES `department`("Department_ID"),FOREIGN KEY ("head_ID") REFERENCES `head`("head_ID"));

SELECT born_state FROM head GROUP BY born_state HAVING count(*) >= 3

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:In which year were most departments established?, schema:CREATE TABLE IF NOT EXISTS "department" ("Department_ID" int,"Name" text,"Creation" text,"Ranking" int,"Budget_in_Billions" real,"Num_Employees" real,PRIMARY KEY ("Department_ID")); CREATE TABLE IF NOT EXISTS "head" ("head_ID" int,"name" text,"born_state" text,"age" real,PRIMARY KEY ("head_ID")); CREATE TABLE IF NOT EXISTS "management" ("department_ID" int,"head_ID" int,"temporary_acting" text,PRIMARY KEY ("Department_ID","head_ID"),FOREIGN KEY ("Department_ID") REFERENCES `department`("Department_ID"),FOREIGN KEY ("head_ID") REFERENCES `head`("head_ID"));

SELECT creation FROM department GROUP BY creation ORDER BY count(*) DESC LIMIT 1

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Show the name and number of employees for the departments managed by heads whose temporary acting value is 'Yes'?, schema:CREATE TABLE IF NOT EXISTS "department" ("Department_ID" int,"Name" text,"Creation" text,"Ranking" int,"Budget_in_Billions" real,"Num_Employees" real,PRIMARY KEY ("Department_ID")); CREATE TABLE IF NOT EXISTS "head" ("head_ID" int,"name" text,"born_state" text,"age" real,PRIMARY KEY ("head_ID")); CREATE TABLE IF NOT EXISTS "management" ("department_ID" int,"head_ID" int,"temporary_acting" text,PRIMARY KEY ("Department_ID","head_ID"),FOREIGN KEY ("Department_ID") REFERENCES `department`("Department_ID"),FOREIGN KEY ("head_ID") REFERENCES `head`("head_ID"));

SELECT T1.name , T1.num_employees FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id WHERE T2.temporary_acting = 'Yes'

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:How many acting statuses are there?, schema:CREATE TABLE IF NOT EXISTS "department" ("Department_ID" int,"Name" text,"Creation" text,"Ranking" int,"Budget_in_Billions" real,"Num_Employees" real,PRIMARY KEY ("Department_ID")); CREATE TABLE IF NOT EXISTS "head" ("head_ID" int,"name" text,"born_state" text,"age" real,PRIMARY KEY ("head_ID")); CREATE TABLE IF NOT EXISTS "management" ("department_ID" int,"head_ID" int,"temporary_acting" text,PRIMARY KEY ("Department_ID","head_ID"),FOREIGN KEY ("Department_ID") REFERENCES `department`("Department_ID"),FOREIGN KEY ("head_ID") REFERENCES `head`("head_ID"));

SELECT count(DISTINCT temporary_acting) FROM management

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:How many departments are led by heads who are not mentioned?, schema:CREATE TABLE IF NOT EXISTS "department" ("Department_ID" int,"Name" text,"Creation" text,"Ranking" int,"Budget_in_Billions" real,"Num_Employees" real,PRIMARY KEY ("Department_ID")); CREATE TABLE IF NOT EXISTS "head" ("head_ID" int,"name" text,"born_state" text,"age" real,PRIMARY KEY ("head_ID")); CREATE TABLE IF NOT EXISTS "management" ("department_ID" int,"head_ID" int,"temporary_acting" text,PRIMARY KEY ("Department_ID","head_ID"),FOREIGN KEY ("Department_ID") REFERENCES `department`("Department_ID"),FOREIGN KEY ("head_ID") REFERENCES `head`("head_ID"));

SELECT count(*) FROM department WHERE department_id NOT IN (SELECT department_id FROM management);

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the distinct ages of the heads who are acting?, schema:CREATE TABLE IF NOT EXISTS "department" ("Department_ID" int,"Name" text,"Creation" text,"Ranking" int,"Budget_in_Billions" real,"Num_Employees" real,PRIMARY KEY ("Department_ID")); CREATE TABLE IF NOT EXISTS "head" ("head_ID" int,"name" text,"born_state" text,"age" real,PRIMARY KEY ("head_ID")); CREATE TABLE IF NOT EXISTS "management" ("department_ID" int,"head_ID" int,"temporary_acting" text,PRIMARY KEY ("Department_ID","head_ID"),FOREIGN KEY ("Department_ID") REFERENCES `department`("Department_ID"),FOREIGN KEY ("head_ID") REFERENCES `head`("head_ID"));

SELECT DISTINCT T1.age FROM management AS T2 JOIN head AS T1 ON T1.head_id = T2.head_id WHERE T2.temporary_acting = 'Yes'

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:List the states where both the secretary of 'Treasury' department and the secretary of 'Homeland Security' were born., schema:CREATE TABLE IF NOT EXISTS "department" ("Department_ID" int,"Name" text,"Creation" text,"Ranking" int,"Budget_in_Billions" real,"Num_Employees" real,PRIMARY KEY ("Department_ID")); CREATE TABLE IF NOT EXISTS "head" ("head_ID" int,"name" text,"born_state" text,"age" real,PRIMARY KEY ("head_ID")); CREATE TABLE IF NOT EXISTS "management" ("department_ID" int,"head_ID" int,"temporary_acting" text,PRIMARY KEY ("Department_ID","head_ID"),FOREIGN KEY ("Department_ID") REFERENCES `department`("Department_ID"),FOREIGN KEY ("head_ID") REFERENCES `head`("head_ID"));

SELECT T3.born_state FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T1.name = 'Treasury' INTERSECT SELECT T3.born_state FROM department AS T1 JOIN management AS T2 ON T1.department_id = T2.department_id JOIN head AS T3 ON T2.head_id = T3.head_id WHERE T1.name = 'Homeland Security'

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Which department has more than 1 head at a time? List the id, name and the number of heads., schema:CREATE TABLE IF NOT EXISTS "department" ("Department_ID" int,"Name" text,"Creation" text,"Ranking" int,"Budget_in_Billions" real,"Num_Employees" real,PRIMARY KEY ("Department_ID")); CREATE TABLE IF NOT EXISTS "head" ("head_ID" int,"name" text,"born_state" text,"age" real,PRIMARY KEY ("head_ID")); CREATE TABLE IF NOT EXISTS "management" ("department_ID" int,"head_ID" int,"temporary_acting" text,PRIMARY KEY ("Department_ID","head_ID"),FOREIGN KEY ("Department_ID") REFERENCES `department`("Department_ID"),FOREIGN KEY ("head_ID") REFERENCES `head`("head_ID"));

SELECT T1.department_id , T1.name , count(*) FROM management AS T2 JOIN department AS T1 ON T1.department_id = T2.department_id GROUP BY T1.department_id HAVING count(*) > 1

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Which head's name has the substring 'Ha'? List the id and name., schema:CREATE TABLE IF NOT EXISTS "department" ("Department_ID" int,"Name" text,"Creation" text,"Ranking" int,"Budget_in_Billions" real,"Num_Employees" real,PRIMARY KEY ("Department_ID")); CREATE TABLE IF NOT EXISTS "head" ("head_ID" int,"name" text,"born_state" text,"age" real,PRIMARY KEY ("head_ID")); CREATE TABLE IF NOT EXISTS "management" ("department_ID" int,"head_ID" int,"temporary_acting" text,PRIMARY KEY ("Department_ID","head_ID"),FOREIGN KEY ("Department_ID") REFERENCES `department`("Department_ID"),FOREIGN KEY ("head_ID") REFERENCES `head`("head_ID"));

SELECT head_id , name FROM head WHERE name LIKE '%Ha%'

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:How many farms are there?, schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT count(*) FROM farm

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Count the number of farms., schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT count(*) FROM farm

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:List the total number of horses on farms in ascending order., schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT Total_Horses FROM farm ORDER BY Total_Horses ASC

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the total horses record for each farm, sorted ascending?, schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT Total_Horses FROM farm ORDER BY Total_Horses ASC

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the hosts of competitions whose theme is not "Aliens"?, schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT Hosts FROM farm_competition WHERE Theme != 'Aliens'

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Return the hosts of competitions for which the theme is not Aliens?, schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT Hosts FROM farm_competition WHERE Theme != 'Aliens'

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the themes of farm competitions sorted by year in ascending order?, schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT Theme FROM farm_competition ORDER BY YEAR ASC

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Return the themes of farm competitions, sorted by year ascending., schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT Theme FROM farm_competition ORDER BY YEAR ASC

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the average number of working horses of farms with more than 5000 total number of horses?, schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT avg(Working_Horses) FROM farm WHERE Total_Horses > 5000

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Give the average number of working horses on farms with more than 5000 total horses., schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT avg(Working_Horses) FROM farm WHERE Total_Horses > 5000

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the maximum and minimum number of cows across all farms., schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT max(Cows) , min(Cows) FROM farm

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Return the maximum and minimum number of cows across all farms., schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT max(Cows) , min(Cows) FROM farm

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:How many different statuses do cities have?, schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT count(DISTINCT Status) FROM city

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Count the number of different statuses., schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT count(DISTINCT Status) FROM city

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:List official names of cities in descending order of population., schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT Official_Name FROM city ORDER BY Population DESC

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the official names of cities, ordered descending by population?, schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT Official_Name FROM city ORDER BY Population DESC

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:List the official name and status of the city with the largest population., schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT Official_Name , Status FROM city ORDER BY Population DESC LIMIT 1

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the official name and status of the city with the most residents?, schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT Official_Name , Status FROM city ORDER BY Population DESC LIMIT 1

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Show the years and the official names of the host cities of competitions., schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT T2.Year , T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Give the years and official names of the cities of each competition., schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT T2.Year , T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Show the official names of the cities that have hosted more than one competition., schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID HAVING COUNT(*) > 1

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the official names of cities that have hosted more than one competition?, schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT T1.Official_Name FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID HAVING COUNT(*) > 1

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Show the status of the city that has hosted the greatest number of competitions., schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT T1.Status FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID ORDER BY COUNT(*) DESC LIMIT 1

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the status of the city that has hosted the most competitions?, schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT T1.Status FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID GROUP BY T2.Host_city_ID ORDER BY COUNT(*) DESC LIMIT 1

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Please show the themes of competitions with host cities having populations larger than 1000., schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT T2.Theme FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID WHERE T1.Population > 1000

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the themes of competitions that have corresponding host cities with more than 1000 residents?, schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT T2.Theme FROM city AS T1 JOIN farm_competition AS T2 ON T1.City_ID = T2.Host_city_ID WHERE T1.Population > 1000

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Please show the different statuses of cities and the average population of cities with each status., schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT Status , avg(Population) FROM city GROUP BY Status

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the statuses and average populations of each city?, schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT Status , avg(Population) FROM city GROUP BY Status

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Please show the different statuses, ordered by the number of cities that have each., schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) ASC

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Return the different statuses of cities, ascending by frequency., schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) ASC

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:List the most common type of Status across cities., schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) DESC LIMIT 1

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the most common status across all cities?, schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT Status FROM city GROUP BY Status ORDER BY COUNT(*) DESC LIMIT 1

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:List the official names of cities that have not held any competition., schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT Official_Name FROM city WHERE City_ID NOT IN (SELECT Host_city_ID FROM farm_competition)

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the official names of cities that have not hosted a farm competition?, schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT Official_Name FROM city WHERE City_ID NOT IN (SELECT Host_city_ID FROM farm_competition)

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Show the status shared by cities with population bigger than 1500 and smaller than 500., schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT Status FROM city WHERE Population > 1500 INTERSECT SELECT Status FROM city WHERE Population < 500

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Which statuses correspond to both cities that have a population over 1500 and cities that have a population lower than 500?, schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT Status FROM city WHERE Population > 1500 INTERSECT SELECT Status FROM city WHERE Population < 500

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Find the official names of cities with population bigger than 1500 or smaller than 500., schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT Official_Name FROM city WHERE Population > 1500 OR Population < 500

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the official names of cities that have population over 1500 or less than 500?, schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT Official_Name FROM city WHERE Population > 1500 OR Population < 500

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Show the census ranking of cities whose status are not "Village"., schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT Census_Ranking FROM city WHERE Status != "Village"

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the census rankings of cities that do not have the status "Village"?, schema:CREATE TABLE "city" ("City_ID" int,"Official_Name" text,"Status" text,"Area_km_2" real,"Population" real,"Census_Ranking" text,PRIMARY KEY ("City_ID")); CREATE TABLE "farm" ("Farm_ID" int,"Year" int,"Total_Horses" real,"Working_Horses" real,"Total_Cattle" real,"Oxen" real,"Bulls" real,"Cows" real,"Pigs" real,"Sheep_and_Goats" real,PRIMARY KEY ("Farm_ID")); CREATE TABLE "farm_competition" ("Competition_ID" int,"Year" int,"Theme" text,"Host_city_ID" int,"Hosts" text,PRIMARY KEY ("Competition_ID"),FOREIGN KEY (`Host_city_ID`) REFERENCES `city`(`City_ID`)); CREATE TABLE "competition_record" ("Competition_ID" int,"Farm_ID" int,"Rank" int,PRIMARY KEY ("Competition_ID","Farm_ID"),FOREIGN KEY (`Competition_ID`) REFERENCES `farm_competition`(`Competition_ID`),FOREIGN KEY (`Farm_ID`) REFERENCES `farm`(`Farm_ID`));

SELECT Census_Ranking FROM city WHERE Status != "Village"

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:which course has most number of registered students?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT T1.course_name FROM courses AS T1 JOIN student_course_registrations AS T2 ON T1.course_id = T2.course_Id GROUP BY T1.course_id ORDER BY count(*) DESC LIMIT 1

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the name of the course with the most registered students?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT T1.course_name FROM courses AS T1 JOIN student_course_registrations AS T2 ON T1.course_id = T2.course_Id GROUP BY T1.course_id ORDER BY count(*) DESC LIMIT 1

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:what is id of students who registered some courses but the least number of courses in these students?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT student_id FROM student_course_registrations GROUP BY student_id ORDER BY count(*) LIMIT 1

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the ids of the students who registered for some courses but had the least number of courses for all students?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT student_id FROM student_course_registrations GROUP BY student_id ORDER BY count(*) LIMIT 1

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:what are the first name and last name of all candidates?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT T2.first_name , T2.last_name FROM candidates AS T1 JOIN people AS T2 ON T1.candidate_id = T2.person_id

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the first and last names of all the candidates?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT T2.first_name , T2.last_name FROM candidates AS T1 JOIN people AS T2 ON T1.candidate_id = T2.person_id

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:List the id of students who never attends courses?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT student_id FROM students WHERE student_id NOT IN (SELECT student_id FROM student_course_attendance)

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the ids of every student who has never attended a course?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT student_id FROM students WHERE student_id NOT IN (SELECT student_id FROM student_course_attendance)

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:List the id of students who attended some courses?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT student_id FROM student_course_attendance

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the ids of all students who have attended at least one course?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT student_id FROM student_course_attendance

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the ids of all students for courses and what are the names of those courses?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT T1.student_id , T2.course_name FROM student_course_registrations AS T1 JOIN courses AS T2 ON T1.course_id = T2.course_id

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is detail of the student who most recently registered course?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT T2.student_details FROM student_course_registrations AS T1 JOIN students AS T2 ON T1.student_id = T2.student_id ORDER BY T1.registration_date DESC LIMIT 1

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What details do we have on the students who registered for courses most recently?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT T2.student_details FROM student_course_registrations AS T1 JOIN students AS T2 ON T1.student_id = T2.student_id ORDER BY T1.registration_date DESC LIMIT 1

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:How many students attend course English?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT count(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T1.course_name = "English"

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:How many students are attending English courses?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT count(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T1.course_name = "English"

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:How many courses do the student whose id is 171 attend?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT count(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T2.student_id = 171

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:How many courses does the student with id 171 actually attend?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT count(*) FROM courses AS T1 JOIN student_course_attendance AS T2 ON T1.course_id = T2.course_id WHERE T2.student_id = 171

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Find id of the candidate whose email is stanley.monahan@example.org?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT T2.candidate_id FROM people AS T1 JOIN candidates AS T2 ON T1.person_id = T2.candidate_id WHERE T1.email_address = "stanley.monahan@example.org"

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the id of the candidate whose email is stanley.monahan@example.org?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT T2.candidate_id FROM people AS T1 JOIN candidates AS T2 ON T1.person_id = T2.candidate_id WHERE T1.email_address = "stanley.monahan@example.org"

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Find id of the candidate who most recently accessed the course?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT candidate_id FROM candidate_assessments ORDER BY assessment_date DESC LIMIT 1

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the id of the candidate who most recently accessed the course?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT candidate_id FROM candidate_assessments ORDER BY assessment_date DESC LIMIT 1

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is detail of the student who registered the most number of courses?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT T1.student_details FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY count(*) DESC LIMIT 1

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the details of the student who registered for the most number of courses?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT T1.student_details FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id ORDER BY count(*) DESC LIMIT 1

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:List the id of students who registered some courses and the number of their registered courses?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT T1.student_id , count(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:For every student who is registered for some course, how many courses are they registered for?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT T1.student_id , count(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id GROUP BY T1.student_id

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:How many registed students do each course have? List course name and the number of their registered students?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT T3.course_name , count(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id JOIN courses AS T3 ON T2.course_id = T3.course_id GROUP BY T2.course_id

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:For each course id, how many students are registered and what are the course names?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT T3.course_name , count(*) FROM students AS T1 JOIN student_course_registrations AS T2 ON T1.student_id = T2.student_id JOIN courses AS T3 ON T2.course_id = T3.course_id GROUP BY T2.course_id

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Find id of candidates whose assessment code is "Pass"?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT candidate_id FROM candidate_assessments WHERE asessment_outcome_code = "Pass"

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the ids of the candidates that have an outcome code of Pass?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT candidate_id FROM candidate_assessments WHERE asessment_outcome_code = "Pass"

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Find the cell mobile number of the candidates whose assessment code is "Fail"?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT T3.cell_mobile_number FROM candidates AS T1 JOIN candidate_assessments AS T2 ON T1.candidate_id = T2.candidate_id JOIN people AS T3 ON T1.candidate_id = T3.person_id WHERE T2.asessment_outcome_code = "Fail"

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the cell phone numbers of the candidates that received an assessment code of "Fail"?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT T3.cell_mobile_number FROM candidates AS T1 JOIN candidate_assessments AS T2 ON T1.candidate_id = T2.candidate_id JOIN people AS T3 ON T1.candidate_id = T3.person_id WHERE T2.asessment_outcome_code = "Fail"

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the id of students who registered course 301?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT student_id FROM student_course_attendance WHERE course_id = 301

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the ids of the students who registered for course 301?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT student_id FROM student_course_attendance WHERE course_id = 301

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What is the id of the student who most recently registered course 301?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT student_id FROM student_course_attendance WHERE course_id = 301 ORDER BY date_of_attendance DESC LIMIT 1

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the ids of the students who registered for course 301 most recently?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT student_id FROM student_course_attendance WHERE course_id = 301 ORDER BY date_of_attendance DESC LIMIT 1

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Find distinct cities of addresses of people?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the different cities where people live?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:Find distinct cities of address of students?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id JOIN students AS T3 ON T2.person_id = T3.student_id

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the different cities where students live?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT DISTINCT T1.city FROM addresses AS T1 JOIN people_addresses AS T2 ON T1.address_id = T2.address_id JOIN students AS T3 ON T2.person_id = T3.student_id

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:List the names of courses in alphabetical order?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT course_name FROM courses ORDER BY course_name

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the names of the courses in alphabetical order?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT course_name FROM courses ORDER BY course_name

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:List the first names of people in alphabetical order?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT first_name FROM people ORDER BY first_name

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the first names of the people in alphabetical order?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT first_name FROM people ORDER BY first_name

You are an excellent developer. Please make an SQL query based on the instructions and the provided schema.Instruction:What are the id of students who registered courses or attended courses?, schema:CREATE TABLE Addresses (address_id INTEGER NOT NULL,line_1 VARCHAR(80),line_2 VARCHAR(80),city VARCHAR(50),zip_postcode CHAR(20),state_province_county VARCHAR(50),country VARCHAR(50),PRIMARY KEY (address_id)); CREATE TABLE People (person_id INTEGER NOT NULL,first_name VARCHAR(255),middle_name VARCHAR(255),last_name VARCHAR(255),cell_mobile_number VARCHAR(40),email_address VARCHAR(40),login_name VARCHAR(40),password VARCHAR(40),PRIMARY KEY (person_id)); CREATE TABLE Students (student_id INTEGER NOT NULL,student_details VARCHAR(255),PRIMARY KEY (student_id),FOREIGN KEY (student_id) REFERENCES People (person_id)); CREATE TABLE Courses (course_id VARCHAR(100) NOT NULL,course_name VARCHAR(120),course_description VARCHAR(255),other_details VARCHAR(255),PRIMARY KEY (course_id)); CREATE TABLE People_Addresses (person_address_id INTEGER NOT NULL,person_id INTEGER NOT NULL,address_id INTEGER NOT NULL,date_from DATETIME,date_to DATETIME,PRIMARY KEY (person_address_id),FOREIGN KEY (person_id) REFERENCES People (person_id),FOREIGN KEY (address_id) REFERENCES Addresses (address_id)); CREATE TABLE Student_Course_Registrations (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,registration_date DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id) REFERENCES Students (student_id),FOREIGN KEY (course_id) REFERENCES Courses (course_id)); CREATE TABLE Student_Course_Attendance (student_id INTEGER NOT NULL,course_id INTEGER NOT NULL,date_of_attendance DATETIME NOT NULL,PRIMARY KEY (student_id, course_id),FOREIGN KEY (student_id, course_id) REFERENCES Student_Course_Registrations (student_id,course_id)); CREATE TABLE Candidates (candidate_id INTEGER NOT NULL ,candidate_details VARCHAR(255),PRIMARY KEY (candidate_id),FOREIGN KEY (candidate_id) REFERENCES People (person_id)); CREATE TABLE Candidate_Assessments (candidate_id INTEGER NOT NULL,qualification CHAR(15) NOT NULL,assessment_date DATETIME NOT NULL,asessment_outcome_code CHAR(15) NOT NULL,PRIMARY KEY (candidate_id, qualification),FOREIGN KEY (candidate_id) REFERENCES Candidates (candidate_id));

SELECT student_id FROM student_course_registrations UNION SELECT student_id FROM student_course_attendance