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Most A Level students can't answer this GCSE question - can you? #gcsephysics #alevelphysics | 70% of A-level students couldn't answer this question even though it was just based on GCSE knowledge. I've just published a video on YouTube where I work through the solution to this and that means you don't want to be one of that group, you want to be in that top 30%. |
Angular Velocity Definition - A Level Physics | Angular velocity is defined as the rate of change of angle for an object moving in a circular path. |
Antiparticle Definition - A Level Physics | An antiparticle is a particle with an equal rest mass but offers it charge, barion number or lepton number. |
Avogadro's Constant Definition - A Level Physics | Avogadre's constant is defined as a number of atoms in 12 grams of carbon 12. |
Binding Energy Definition - A Level Physics | The binding energy of a nucleus is the energy released when the nucleons come together to form the nucleus. |
Electric Field Definition - A Level Physics | An electric field is a region where charged particles experience a force. |
Electric Field Lines Definition - A Level Physics | Electric field lines show the direction of a force on a positive charge. |
Internal Energy Definition - A Level Physics | The internal energy of a gas is defined as the sum of the kinetic and potential energies of all the molecules in that system. |
Isotopes Definition - A Level Physics | Isotopes are atoms with the same number of protons but a different number of neutrons. |
Radian Definition - A Level Physics | The radian is defined as the angle when the arc length is equal to the radius. |
Radioisotope Definition - A Level Physics | A radio isotope is a material with nuclei which are unstable. |
Specific Heat Capacity Definition - A Level Physics | Specific heat capacity is defined as the energy required to increase the temperature of 1 kilogram of a substance by 1 Kelvin. |
Simple Harmonic Motion Definition - A Level Physics | Simple harmonic motion can be defined as when the acceleration of an oscillator is directly proportional to the displacement from its equilibrium position, but the acceleration is in the opposite direction to its displacement. |
Specific Latent Heat of Fusion Definition - A Level Physics | The specific latent heat of fusion is to find as the energy required to change one kilogram of material from the solid state into the liquid state without change in temperature. |
Thermal Equilibrium Definition - A Level Physics | Thermal equilibrium is the state in which there's no net flow of thermal energy between the objects involved. |
Electric Field Strength Definition - A Level Physics | Electric field strength is the fourth per unit charge on a positive charge. |
Electric Potential Definition - A Level Physics | Electric potential is the work done per unit charge and bringing a positive charge from infinity to that point. |
Faraday's Law Definition - A Level Physics | Faraday's law of electromagnetic induction states that the EMF is directly proportional to the rate of change of magnetic flux linkage. |
Gravitational Field Definition - A Level Physics | A gravitational field is a region where a particle with mass experiences a force. |
Gravitational Field Lines Definition - A Level Physics | Gravitational field lines show the direction of force on a mass. |
Gravitational Field Strength Definition - A Level Physics | Gravitational field strength is the force per unit mass on an object. |
Gravitational Potential Definition - A Level Physics | Gravitational potential at a point is a work done bringing a unit mass from infinity to that point. |
Lenz's Law Definition - A Level Physics | Lens is law, states as the direction of the induced EMF, is such that it will try to oppose the change that is producing it. |
Newtons Law Of Gravitation Definition - A Level Physics | Newton's law of gravitation states that the force between two point masses is directly proportional to the product of the two masses and inversely proportional to the square of the separation between them. |
A Level Physics Units | Now, if you've been working through this daily workout book every day in A Level Physics, then you should now be really confident and familiar with all of the constants used in many exam questions. And this means that you can work that little bit quicker when it comes to any exams. So today, on the 7th of May, I've got a table for you to complete. We've got the constants, we then have the symbols, we have their values, and of course, their units. Now, you should be really familiar with all of those by the end of Year 12. You can of course check in your data and formula book, but if you know them off by heart, it means you're going to be a lot quicker when it comes to doing any physics questions. |
A Level Physics | If you are currently revising A-level physics, do let me know in the comments below, which results as you're finding particularly useful, just so we can share it with a wider community of students who are in exactly the same position as you are. |
Revision Activities for A Level Physics | If you're doing A-level physics and you want to get your best possible mark in your exam, then you should be using this book here. This is a daily workout. This one book three also has information about your exams. So for example, in addition to all the questions, there are also activities for you to ever go at that are tried and tested to allow people like you to remember as much as possible and therefore get the highest grades in any exams that you have coming up. |
A Level Physics Derivations | If you have A-level physics exams coming up then you know it is essential to remember some of the key derivations. I have four of these organised in one page over my website, A-levelphysicsonline.com and for each one of these I not only have a video solution where explain how to do it. I also have a downloadable sheet that has everything on one side of paper so you can remember this as you're preparing for your exam system. |
Base Units for Joules - A Level Physics #Shorts | Now for this A level physics revision we're going to be showing that the base units for joules are kilograms meter squared seconds to the minus two. Now I'm going to start with an equation that says a kinetic energy is equal to a half times the mass times the velocity squared. Now for mass that has the base unit of the kilogram. Velocity is measured in meters per second but this is all squared and the half here is a unitless quantity. So we can also write this by multiplying at the bracket as kilograms times meters squared times seconds to the minus two. So this is the derived unit, the dual, expressed in its base units of kilograms meter squared second to the minus two. |
Calculate the Combined Resistance - A Level Physics #Shorts | So if we want to calculate the combined resistance of a 30 ohm and 50 ohm resistor, we can use this method, but there is an easier way. We can also say that the combined resistance, when you have two resistors in parallel, is equal to their product over their sum. And in this case, the product of 30 times 50 is going to be equal to 1,500. And that's divided by the sum, which is 30 plus 50, which is 80. If I work that out on my calculator, this also gives me an answer of 18.75, which is what we had before. So in this case, using product over sum, when we've got resistors in parallel, and it's two resistors in parallel, this gives us a combined resistance equal to 19 ohms. |
Calculate the Intensity - A Level Physics #Shorts | Light from a 60 watt bulb shines onto a surface with a radius of three meters. Now to calculate the intensity, that's going to be equal to the power divided by the area. And because it's a circular area, that's going to be equal to pi r squared. So that means if to calculate the intensity, it's going to be equal to the power, which was 60 watts. So 60 joules of energy are transferred every second. And the area is going to be equal to pi times 3.0 squared. So I'm just going to wet that out on my calculator. And this just gives me an answer to two significant figures of 2.1 watts per square meter. |
Calculate the Critical Angle - A Level Physics #Shorts | If you have light traveling from an optically dense to a less dense medium, then there's going to be a certain angle at which none of that light escapes. This angle is theta c, the critical angle, and at this critical angle, all of that light is going to travel along the surface. If the angle of incidence was even bigger, then we then get total internal reflection occurring. Now we can say that sine theta c is equal to 1 divided by n. So here, to work at the size of that critical angle, it's just sine to the minus 1 of 1 divided by the refractive index of diamond, which in this case is 2.42. So in this case, for diamond, the critical angle is equal to 24.4 degrees. |
Calculate the Half-life - A Level Physics #Shorts | calculate the half-life of a radioactive sample that has a decay constant of 1.1 times 10 to the minus 2 per second. Now for this we're going to use the equation that says a half-life, t a half, is equal to the natural log of 2 divided by the decay constant. That's an equation that you will be given for your exam. So that means a half-life is just going to be equal to the natural log of 2 divided by 1.1 times 10 to the minus 2. We can put that into our calculator and then just calculate this. And that gives us a half-life of about 63 seconds. So quite a short half-life, which is why it has quite a high decay constant. |
Calculate the Wavelength of Laser Light - A Level Physics #Shorts | We can use the diffraction grating to work out the wavelength of light. This one has 600 lines per millimeter, producing a first order maximum at 24 degrees. We're going to use the equation that says D sine theta is equal to N lambda, and here N is equal to 1 because that's our first order maximum. So when we work out the value for the wavelength, that's going to be equal to D, and this is the space between the gratings, and we can work that out as because there are 600 lines per millimeter. There are going to be 600,000 lines per meter, so that's why I've got one over 600,000. We're going to multiply that by sine theta, which is 24. If we work this out, this is equal to 6.78 times 10 to the minus 7 meters, or 678 nanometers, which is in the red part of the spectrum. |
Calculate the Acceleration - A Level Physics #Shorts | Here we need to calculate the acceleration of the tip of the blade of a wind turbine, which is 45 meters in radius and also traveling at 20 meters per second. So here we can say the acceleration is equal to V squared over R. So that's going to be equal to our value of 20 squared, divided by the radius and because it's a 45 meter long blade, that's equal to 45. So then we've got 20 squared over 45. which equals 8.9 meters per second squared. |
Calculate the Fringe Spacing - A Level Physics #Shorts | So standard practicalists using a double slit and a laser. We want to work out the fringe spacing and W is equal to lambda D over S. Now it depends on which exam board you're doing. This is the way the AQA presented. I think they use different letters for OCR. Whatever it is, it's exactly the same physics. So here that fringe spacing is going to be the wavelength. And it's given it as 532 nanometers. So that's times 10 to the minus 9. The distance to the screen is 2.5 meters. And here the slit separation, which is often printed or given to you when you actually have that double slit, is equal to 0.02 millimeters. So I'm going to multiply that by 10 to the minus 3 to convert it to meters. And when you do that, we find that in this case the fringes are a distance of 0.067 meters apart. |
Objects on an Inclined Plane - A Level #Shorts | So when we have an object on an inclined plane like me on the slope, there are three forces that we can consider. Acting vertically down, we have my weight. At 90 degrees to the surface, we have the normal contact force. And then in this acting of the slope, we have friction. And it's really useful sometimes to split the weight into the components of its force along the slope and at 90 degrees to the slope. |
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