Abstract:
Oral fluid for drug testing has several advantages over other specimens: (1) It may be collected noninvasively and under direct supervision; (2) its drug concentration reflects blood-drug concentrations; and (3) it can be processed by conventional drug screening and confirmation methods. This technology provides a system that measures the quantity of a drug (without needing a priori knowledge of the drug) in an oral fluid specimen and translates this level to a blood plasma drug concentration. The method first measures the concentration of a drug in an oral fluid sample. Next, a processor calculates the blood plasma concentration from the measured oral fluid drug concentration. Finally, this blood plasma drug level is utilized to calculate a total body drug concentration.

Description:
CROSS-REFERENCE TO RELATED PATENT APPLICATIONS 
       [0001]    The present application claims priority to U.S. Provisional Patent Application Ser. No. 61/815,205, filed Apr. 23, 2013, the disclosure of which is incorporated herein by reference as if set out in full. 
     
    
     FIELD OF THE INVENTION 
       [0002]    The technology of the present application relates generally to correlating the quantitative measurement of drugs in oral fluid to total body drug concentrations and more specifically uses the quantitative measurement of drug concentration in the oral fluid specimens and determines the blood equivalent plasma drug concentration using pharmacokinetic calculations. From this blood equivalent plasma drug concentration, the total body drug concentration, and the assessment of the drug dose required to produce this concentration, is determinable. 
       BACKGROUND 
       [0003]    Historically, urine has been utilized as the primary specimen for the detection of drug use in standard toxicology protocols and drug monitoring programs. The monitoring ensures compliance with treatment regimens and assess potential drug abuse. In both scenarios, the analysis of urine samples primarily targets the metabolite(s) of drugs in the body. Detection of these compounds is facilitated by the relatively high concentration of analyte present in the urine specimen in addition to a reasonably long detection window. However, urine drug testing is limited by the fact that results solely indicate past exposure to the detected compounds. Urine is not an acceptable matrix for determining impairment or pharmacological effects, or to estimate dose compliance based on drug concentrations. Currently, blood is the preferred specimen for assessing impairment based on biologically active drug levels in an individual or determinations as to the minimum dose consumed to produce the corresponding concentrations in the body. 
         [0004]    As explained, urine cannot provide a satisfactory sample for analysis to determine impairment, pharmacological effects, or dose compliance. Thus, against this background, improved systems and methods to determine body drug concentration from an oral fluid are desirable. 
       SUMMARY 
       [0005]    This Summary is provided to introduce a selection of concepts in a simplified form that are further described below in the Detailed Description. This Summary, and the foregoing Background, is not intended to identify key aspects or essential aspects of the claimed subject matter. Moreover, this Summary is not intended for use as an aid in determining the scope of the claimed subject matter. 
         [0006]    The technology of the present application describes a system, which provides an interpretative measure to assess plasma drug levels from an oral fluid drug test and correlate the dose to the calculated plasma level. In addition to determining the blood equivalent plasma concentration of one or more drugs, this method has application to infer potential pharmacological effects, dose compliance, or drug impairment from an oral fluid drug test (that can be collected onsite). The results generated from this technology may aid in the interpretation of oral fluid drug concentrations as a means to determine if the oral fluid drug level is consistent with a dosage consumed or what effects (impairment or otherwise) may be seen in an individual with a specific drug amount in the body. Using a noninvasive, volumetric oral fluid collection device that also measures pH at the time of collection, an adequate sample can be rapidly obtained. A processor uses the measured oral fluid drug concentration and pharmacokinetic variables to provide a plasma drug level and a minimum dosage required to obtain a corresponding oral fluid drug concentration equivalent. 
         [0007]    These and other aspects of the present system and method will be apparent after consideration of the Detailed Description and Figures herein. 
     
    
     
       DRAWINGS 
         [0008]    The technology of the present application will be further explained with reference to the drawing figures reference below, wherein like structures may be referred to by like numerals throughout the several views thereof. 
           [0009]      FIG. 1  illustrates a methodology for collecting a volume of oral fluid and measuring the pH of the oral fluid at the time of collection consistent with the technology of the present application. 
           [0010]      FIG. 2  illustrates an exemplary system using the oral fluid to determine body drug concentration consistent with the technology of the present application. 
           [0011]      FIG. 3  is an exemplary algorithm to calculate oral fluid/plasma ratio for acidic drugs consistent with the technology of the present application. 
           [0012]      FIG. 4  is an exemplary algorithm to calculate oral fluid/plasma ratio for basic drugs consistent with the technology of the present application. 
           [0013]      FIG. 5  is an exemplary algorithm to calculate total body concentration of the drug from the plasma concentration consistent with the technology of the present application. 
           [0014]      FIG. 6  is an exemplary collection device consistent with the technology of the present application. 
       
    
    
       [0015]    While the above-identified drawing figures set forth one or more exemplary embodiments, other embodiments of the present invention are also contemplated, as noted throughout. The technology of the present application is described by way of representative examples and should not be construed as limiting. Numerous other modifications and embodiments within the spirit and scope of the technology of the present application are incorporated herein. 
       DETAILED DESCRIPTION 
       [0016]    The technology of the present application will now be described more fully below with reference to the accompanying figures, which form a part hereof and show, by way of illustration, specific exemplary embodiments. These embodiments are disclosed in sufficient detail to enable those skilled in the art to practice the technology of the present application. However, embodiments may be implemented in many different forms and should not be construed as being limited to the embodiments set forth herein. The following detailed description is, therefore, not to be taken in a limiting sense. 
         [0017]    The technology of the present application is described with specific reference to using an oral fluid sample to determine total body drug concentration. However, the technology described herein may be used for other applications where oral fluid, perspiration, or the like may be used to determine concentrations of chemicals, organisms, or the like in blood plasma. Additionally, various embodiments of the technology may omit, substitute, or add components as appropriate. Methods of using the technology are disclosed herein, but the methods may be performed in an order different than that described, and various steps may be added, omitted, or combined. Finally, the technology of the present application will be described with relation to exemplary embodiments. The word “exemplary” is used herein to mean “serving as an example, instance, or illustration.” Any embodiment described herein as “exemplary” is not necessarily to be construed as preferred or advantageous over other embodiments. Additionally, unless specifically identified otherwise, all embodiments described herein should be considered exemplary. 
         [0018]    As described above, urine has been the specimen of choice for drug testing purposes. The use of urine as a method of drug monitoring comes with certain disadvantages. For example, urine collection tends to be more invasive or embarrassing (particularly for observed collection) and samples are susceptible to adulteration (dilution, oxidants etc.) or substitution. Furthermore, drug concentrations in urine are only illustrative of past drug use. Analytical results cannot be used for determining levels of impairment or to assess the dosage taken, due to the fact that urinary drug concentrations do not directly reflect blood levels in the body. 
         [0019]    An alternate specimen type with the potential to allow for total drug in the body determinations without the need to draw a blood sample is oral fluid. Oral fluid, sometimes called mixed saliva, comes from three major and multiple minor salivary glands. Oral fluid may comprise the mixed saliva from multiple glands and other constituents in the mouth including plasma electrolytes (K+, Na+, Cl— Bicarbonate), enzymes, and DNA. Oral fluid is a filtrate of the blood. Thus, it has been determined that oral fluid drug concentrations show predictable ratios as compared to plasma drug concentrations. The predictable plasma: oral fluid drug concentration ratios in addition to pharmacokinetic information allow for the calculation of the minimum dose taken that is required to produce an oral fluid drug concentration. Thus, measurement of an oral fluid drug level will allow for the determination of the corresponding plasma blood equivalent plasma drug concentration and subsequently, the minimum dose required to produce this amount and if the concentration corresponds to the expected steady state level of the drug in the blood based on provided dosing regimen. 
         [0020]    Oral fluid has the advantage of being very simple to collect and difficult to adulterate. Collections are not invasive and can be easily observed to ensure the validity of the sample. Drug incorporation into oral fluid occurs rapidly after ingestion, allowing for detection of very recent drug use. Because the drug in oral fluid reflects that which is in the plasma, the parent drug is more commonly detected as compared to urine, which tends to have higher concentration of metabolites. Thus, for drugs where metabolites are detectible in urine for long periods after abstinence (e.g. THC), measurement in oral fluid allows for detection of the parent drug that reflects more recent drug use. Furthermore, correlation of drug concentrations in oral fluid and plasma allow for the establishment of concentration ratios. This correlation will serve to predict the amount of drug in the body and ultimately lead to the determination of the minimum amount of drug a patient has taken to achieve the measured oral fluid concentration. Thus providing the capability of calculating the minimum original dose of drug (taken or administered) from the concentration in oral fluid. The concentration of a drug in the oral fluid along with knowledge of several pharmacokinetic properties of the drug, including, but not limited to, pKa, volume of distribution, absorption constant, elimination constant, and bioavailability together with information relating to pH of the saliva, and elapsed time between dosage and specimen collection allow the prediction of plasma concentration, body concentration, and minimum dose. This information allows for assessment of compliance with a drug regimen. Additionally, it may provide information about the amount of biologically active drug in the body. 
       Oral Fluid Specimen Collection  
       [0021]    With reference now to  FIG. 1 , an exemplary methodology  100  for collecting oral fluid will be described. First, the donor (sometimes referred to as subject, patient, person, or the like) is positioned to allow retrieval of the oral fluid sample, step  102 . Next, an oral fluid collection device is placed in the donor&#39;s mouth, step  104 . The collection device in one exemplary embodiment may be an absorbent swab placed under the tongue. One particularly useful collection device that has been developed is shown and described in  FIG. 6 . In this exemplary embodiment, the oral fluid collection device collects about 1 mL of neat oral fluid from the donor. Generally, the term about or approximately in the present application means within an acceptable tolerance, such as, for example, ±10% or the like. Volumetric collection is required for quantitative analysis when analyzed from a buffer solution. Oral fluid may be absorbed by the collection device by allowing saliva to move up the stem of a collection device via capillary action, step  106 . When a sufficient amount of oral fluid is collected, the collection device provides indicia that the required collection amount has been collected, step  108 . The indicia indicating the required volume is collected may be by a color change on a collection adequacy indicator or the like. Alternatively, an alpha/numeric display may be provided or an audio alert, such as a beep. Determining salivary pH is completed next or substantially at the same time as the required volume is collected, step  110 . The pH of the oral fluid may be determined by a pH sensitive pigment or by other means including, for example, a sensor or the like. The pH indicia may be combined or separate from the indicia for volume and may include the same or different indicators. For example, the volume of the sample may be provided by a color strip whereas the pH may be provided by an audio. The collection device may be provided with a display that displays both the volume and the pH in certain embodiments. The pH will then be recorded or otherwise maintained for later use, step  112 . In this exemplary embodiment, the donor will provide a sample by placing the collector swab under his or her tongue until the indicator changes color. The swab is then placed in 3 mL of oral fluid extraction buffer that promotes stabilization of the drug, preventing bacterial growth, and facilitates efficient extraction of the drugs and/or metabolites from the adsorbent swab, as is further explained below, step  114 . Specimens may be aliquoted for analysis, and any remaining sample may be transferred to long-term storage at, for example, a storage temperature of between about −20 to about 0° C. The collected oral fluid may be referred to as a sample or a specimen interchangeably herein. 
       The System 
       [0022]    With reference now to  FIG. 2 , a system  200  for determining total body drug concentration from the collected oral fluid sample is described. The system  200  includes a collection device  202 , capable of the features described above. The collection device  202  provides a sample to drug concentration analysis engine  204 . The drug concentration analysis engine detects types and concentrations of drugs even without a priori knowledge of the drugs. The drug concentration analysis engine  204  may receive the required sample from collection device  202  via, for example, a pipette transfer, or the sample collection device may be releasably attached to the drug concentration analysis engine  204  to place the collection device  202  sample reservoir in fluid communication with the drug concentration analysis engine  204 . In one exemplary embodiment, the drug concentration analysis engine  204  may detect drug concentration using a liquid chromatography-mass spectrometry processor. In this case, the drug concentration analysis engine  204  includes a solid phase extraction module  206  and an identification module  208 . Once the identification module  208  identifies the drug and the concentration of the drug in the oral fluid, the information is provided to a data analysis engine  210  along with information regarding the chemistry of the oral fluid, with particular regard for the pH of the sample. The data analysis engine  210  comprises processor modules to calculate the blood equivalent plasma blood concentration and the total body concentration of the identified drugs. The total body concentration equivalent of the drugs may be used in numerous applications, some of which may be referenced herein. Other applications, however, are within the spirit and scope of the technology of the present application. 
       Specimen Preparation 
       [0023]    Specimens may undergo a sample preparation step in advance of providing the sample to the drug concentration analysis engine, which involves extracting the analyte(s) of interest from biological matrices. This process serves to eliminate any biological material that could potentially affect analytical results. Samples are first treated to disrupt any drug matrix interactions (protein binding, conjugation) and then adjusted to a specific pH with a buffer. Analytes are then extracted from the remaining matrix using solid phase extraction module  206 , which may be comprised of cartridges that are mixed-mode cationic exchange columns. This technique uses the specific binding of ionized drug molecules to the extraction cartridge packing material resulting in strong analyte retention within the column. A series of aqueous and organic wash steps may be used to assist in removing unwanted compounds and matrix components from the sample. Target analytes are then eluted from the solid phase extraction module  206 , collected, and analyzed by identification module  208  that may be, for example, a liquid chromatography tandem mass spectrometry (LC/MS-MS) device, although other analysis devices are possible. 
       Drug Quantitation by Liquid Chromatography Tandem Mass Spectrometry (LC/MS-MS) 
       [0024]    In this exemplary embodiment, the specimens are analyzed by the identification module  208  that is a LC/MS-MS device, which allows for accurate and precise analyte identification and quantitation. This analytical technique uses a chromatographic system to separate all of the sample components into discrete peaks and sequentially identifies each compound through mass spectral identification. The chromatographic system is composed of a stationary phase of hydrophobic character (for example, octadecylsilane) and a mobile phase of varying polarity (for example, methanol, water). Specimens are injected into the chromatograph and pumped through the system by flow of the mobile phase. Separation is brought about by differential interactions with the stationary phase based on physical and chemical properties of the individual analytes. The end result is a separation of all of the sample components into discrete bands. As each component elutes from the liquid chromatograph it enters the mass spectrometer. The mass spectrometer is able to first determine an analytes specific molecular weight, called a precursor ion, and subsequently fragment the precursor ion into smaller fragments called product ions. The precursor ion and generated product ions are a specific marker of every analyte of interest. No two compounds will generate completely identical mass spectra. This allows for the identification module  208  to conclusively identify specimen components. Additionally, when specimens are analyzed alongside a series of standards of known concentration, a calibration curve can be generated and quantitative values of identified drugs can be determined. 
       Data Analysis  
       [0025]    The identification module  208  outputs data obtained from the analysis of oral fluid relating to the drug and the drug concentration in the oral fluid. Oral fluid specimens may be used to determine blood equivalent plasma drug concentration and ultimately correlate the derived blood equivalent plasma drug concentration to the minimum dosage of a drug required to produce the measured drug level.  FIGS. 3-5  provide algorithms implemented by the data analysis module  210  to automatically correlate the drug concentration in the sample to the blood equivalent plasma drug concentration. When using these equations, plasma pH is assumed to be constant at 7.4 and drug protein binding is assumed to be negligible in the saliva. Therefore, a value of 1 is used for fs. The binding of drugs to plasma proteins varies from drug to drug. However, it remains fairly consistent between individuals. Normally, saliva pH may vary from 6 to 8. If the pH is measured at the time of sample collection, one can modify this variable in the equation and thus derive the blood equivalent plasma drug concentration of a drug given its saliva drug concentration. The percentage of drug and/or metabolite transferred from blood to saliva is primarily dependent on salivary pH. For basic drugs, as the salivary pH decreases, a greater concentration of drug will be ionized, and the oral fluid drug concentration will increase. Minor changes in salivary pH may result in significant changes in the saliva/plasma ratio (S/P ratio). Much of the pharmacokinetic and pharmacodynamic research reported on therapeutic and abused drugs has been based on plasma drug concentrations. Because the S/P ratio can be shown to be predictable using mathematical models, the databases on plasma pharmacokinetic, physiological, and behavioral data may be used to support interpretation of saliva drug concentrations. Mathematical models provide S/P concentration ratios for acidic and basic drugs and the following pharmacokinetic formulas are used to convert the oral fluid drug level to the plasma drug level: 
         [0026]    Determination of plasma drug concentrations (solving for P) based on oral fluid analysis (acidic drugs) 
         [0000]    
       
         
           
             
               S 
                
               
                 / 
               
                
               P 
             
             = 
             
               
                 1 
                 + 
                 
                   
                     10 
                     
                       ( 
                       
                         pHs 
                         - 
                         pKa 
                       
                       ) 
                     
                   
                   × 
                   fp 
                 
               
               
                 1 
                 + 
                 
                   
                     10 
                     
                       ( 
                       
                         pHp 
                         - 
                         pKa 
                       
                       ) 
                     
                   
                   × 
                   fs 
                 
               
             
           
         
       
     
         [0027]    Determination of plasma drug concentrations (solving for P) based on oral fluid analysis (basic drugs) 
         [0000]    
       
         
           
             
               S 
                
               
                 / 
               
                
               P 
             
             = 
             
               
                 1 
                 + 
                 
                   
                     10 
                     
                       ( 
                       
                         pKa 
                         - 
                         pHs 
                       
                       ) 
                     
                   
                   × 
                   fp 
                 
               
               
                 1 
                 + 
                 
                   
                     10 
                     
                       ( 
                       
                         pKa 
                         - 
                         pHp 
                       
                       ) 
                     
                   
                   × 
                   fs 
                 
               
             
           
         
       
     
         [0028]    Where: 
         [0029]    S=Saliva drug concentration 
         [0030]    P=Plasma drug concentration 
         [0031]    pHs=pH of saliva (to be determined at the time of collection) 
         [0032]    pHp=pH of plasma (assumed to be 7.4) 
         [0033]    pKa=Dissociation constant of a drug (referenced in literature) 
         [0034]    fp=Free fraction of drug in plasma (referenced in literature) 
         [0035]    fs=Free fraction of drug in saliva (negligible; assumed to be 1) 
         [0036]    Once a plasma concentration has been established then the following calculation can be performed: 
         [0037]    Determination of minimum dosage consumed based on plasma drug concentrations 
         [0000]    
       
         
           
             
               D 
               o 
             
             = 
             
               
                 
                   V 
                   d 
                 
                  
                 
                   C 
                    
                   
                     ( 
                     
                       
                         K 
                         a 
                       
                       - 
                       
                         
                           K 
                           e 
                         
                          
                         l 
                       
                     
                     ) 
                   
                 
               
               
                 FKa 
                  
                 
                   ( 
                   
                     
                        
                       
                         - 
                         Kelt 
                       
                     
                     - 
                     
                        
                       
                         - 
                         Kat 
                       
                     
                   
                   ) 
                 
               
             
           
         
       
     
         [0038]    Where: 
         [0039]    Do=Original dosage taken 
         [0040]    Vd=Volume of distribution of drug (referenced in literature) times the kg body weight of donor 
         [0041]    C=Plasma drug concentration 
         [0042]    Ka=Absorption constant of drug (referenced in literature) 
         [0043]    Kel=Elimination constant of drug (referenced in literature) 
         [0044]    F=Bioavailability of drug (referenced in literature) 
         [0045]    t=Elapsed time between dosage and specimen collection 
         [0046]    Using oral fluid-concentrations to determine dosing has at least two advantages: assessing impairment due to bioactive levels of drugs in a forensic setting and the ability to assess compliance with prescribed dosing regimens for clinical treatment without the necessity of drawing blood. 
         [0047]    As described above, the pH of the sample is determined and recorded at the time of oral fluid collection. The data analysis engine  210  uses the pH to determine a processing algorithm based on whether the target analyte is acidic or basic (see  FIGS. 3 and 4 ). The fixed variables, such as percentage of plasma protein binding and drug pKa are stored in a memory associated with the data analysis engine  210 . Using these data, in addition to saliva drug concentration, the data analysis engine  210  calculates blood equivalent plasma concentration. 
         [0048]    As shown in  FIG. 5 , which is the third formula mentioned above, the minimum dosage required to produce a corresponding plasma concentration is determinable. The basis for this formula is derived from the volume of distribution (Vd) of the drug, which is simply defined as a ratio of the amount of drug in the body to the equivalent drug concentration in plasma. The Vd describes the extent of distribution of drug into target tissues when equilibrium has been established between blood and tissue, before elimination has begun. Based on the physical and chemical properties of the drug, Vd can be influenced by many factors such as the extent of plasma protein binding, lipophilicity, molecular size, and state of ionization. With knowledge of the time interval between last dosage taken and sample collection, as well as plasma drug concentrations, an estimate of minimum dose can be made. Similarly, comparison of the plasma concentration to the known and established steady state concentration of that drug in plasma will provide interpretive information about the dosing of the drug in a person. 
         [0049]    As mentioned above, the technology of the present application uses a collection of oral fluid, or saliva, to obtain the information necessary to calculate blood equivalent plasma drug concentration.  FIG. 6  shows an exemplary collection and transport device  600 . The collection and transport device  600  includes a collection portion  602  and a transport portion  604 . The transport portion  604  includes a housing  606  having an opening  608  to allow the collection portion  602  to be inserted into the transport portion  604  subsequent to collecting the sample of oral fluid. The housing  606 , as shown, may be a simple test tube or the like. The transport portion  604  has a generally hollow interior  610  that contains a measure of buffer solution  612  (as described above). A topper  614 , which may be a cap or plug, is removably secured to the opening  608  of the transport portion  604 . The topper  614  prevents the buffer solution  612  from leaking from the hollow interior  610 . The topper  614  is removed such that the collection portion  602  may be inserted into the hollow interior  610  subsequent to the collection of the oral fluid. Once the collection portion  602  is inserted into the transport portion  604 , the topper  614  is secured to the opening  608 . The topper  614  may be secured to the opening  608  using a friction fit, as shown, threads, a snap fit, or the like. 
         [0050]    The collection portion  602  includes an absorbent swab  616  at a first end  618  of the collection portion  602 . The absorbent swab  616  may be any type of absorbent material, such as a cotton swab, filter paper, a porous fabric material, etc. The absorbent swab  616  is coupled to a handle  620  extending from the absorbent swab towards a second end  622  of the collection portion  602 . An indicator  624  is coupled to the handle  620  towards the second end  622  of the collection portion  602 . The indicator  624  may have a first indicator  626  and a second indicator  628 . The first indicator  626  may be designed to indicate the collection of a particular volume of oral fluid, such by changing color when 1 ml of oral fluid is collected by the absorbent  616 . When a sufficient amount of oral fluid is collected, the oral fluid travels along the handle  620 , via a fluid conduit  630 , which may be a wick or a capillary tube, to the first indicator  626  whereby the oral fluid causes, in one exemplary embodiment, the first indicator  626  to change color indicating an acceptable level of fluid has been collected. The second indicator  628  also is in fluid communication with the absorbent  616 , such as via the same fluid conduit  630  or a second fluid conduit  632 . The second indicator  628  may indicate the pH of the oral fluid by, for example, a color code or the like. Notice, while shown as a completely separate second fluid conduit  632 , the fluid conduits  630  and  632  may be merged in part and separated in part forming, for example, a Y-shape to provide oral fluid to both indicators, but using a common conduit from the absorbent  616  until a branching to provide two separate fluid streams to the indicators  626  and  628 . Moreover, while the indicators are shown and described as indicators that change color, the indicators could be electronic displays, audio, or the like instead of a color strip. 
         [0051]    The technology of the present application was applied in several exemplary embodiments as outlined below. The exemplary embodiments relate to specific patients, donors, or people, and specific drugs, metabolites, and the like. However, the examples are provided to exemplify the technology presented herein and are not to be considered limiting. To technology of using oral fluids to determine blood equivalent plasma drug concentrations was tested against actual blood plasma tests as will be explained below. 
       Donor Calculations 
       [0052]    Each donor&#39;s drug clearance rate is determined by multiplying the drugs clearance rate (referenced in literature) by the donor&#39;s weight (provided). 
         [0000]    
       
         
           
             
               
                 
                   
                       
                   
                    
                   
                     
                       Determination 
                        
                       
                           
                       
                        
                       of 
                        
                       
                           
                       
                        
                       donor 
                        
                       
                           
                       
                        
                       
                         clearance 
                         . 
                         
                           
 
                         
                          
                         Donor 
                       
                        
                       
                           
                       
                        
                       Clearance 
                        
                       
                           
                       
                        
                       
                         ( 
                         
                           L 
                            
                           
                             / 
                           
                            
                           hr 
                         
                         ) 
                       
                     
                     = 
                     
                       Drug 
                        
                       
                           
                       
                        
                       Clearance 
                        
                       
                           
                       
                        
                       
                         ( 
                         
                           L 
                           × 
                           
                             hr 
                             
                               - 
                               1 
                             
                           
                           × 
                           
                             kg 
                             
                               - 
                               1 
                             
                           
                         
                         ) 
                       
                       × 
                       Donor 
                        
                       
                           
                       
                        
                       Weight 
                        
                       
                           
                       
                        
                       
                         
                           ( 
                           kg 
                           ) 
                         
                         . 
                       
                     
                   
                 
               
               
                 
                   Eq 
                   . 
                   
                       
                   
                    
                   1 
                 
               
             
           
         
       
     
         [0053]    Likewise, each donor&#39;s volume of distribution (DV d ) is calculated by multiplying the drug volume of distribution (V d ) (referenced in literature) by the donor&#39;s weight (provided). 
         [0000]    
       
         
           
             
               
                 
                   
                     Determination 
                      
                     
                         
                     
                      
                     of 
                      
                     
                         
                     
                      
                     donor 
                      
                     
                         
                     
                      
                     volume 
                      
                     
                         
                     
                      
                     of 
                      
                     
                         
                     
                      
                     
                       distribution 
                       . 
                       
                         
 
                       
                        
                       
                         
                           DV 
                           d 
                         
                          
                         
                           ( 
                           L 
                           ) 
                         
                       
                     
                   
                   = 
                   
                     
                       
                         V 
                         d 
                       
                        
                       
                         ( 
                         L 
                         ) 
                       
                     
                     × 
                     Donor 
                      
                     
                         
                     
                      
                     Weight 
                      
                     
                         
                     
                      
                     
                       
                         ( 
                         kg 
                         ) 
                       
                       . 
                     
                   
                 
               
               
                 
                   Eq 
                   . 
                   
                       
                   
                    
                   2 
                 
               
             
           
         
       
     
         [0054]    Each donor&#39;s steady state drug concentration range is calculated by determining the steady state maximum drug concentration (C ss  max) and the steady state minimum drug concentration (C ss  min) by the following formulas: 
         [0000]    
       
         
           
             
               
                 
                   
                     
                       Determination 
                        
                       
                           
                       
                        
                       of 
                        
                       
                           
                       
                        
                       steady 
                        
                       
                           
                       
                        
                       state 
                        
                       
                           
                       
                        
                       maximum 
                        
                       
                           
                       
                        
                       plasma 
                        
                       
                           
                       
                        
                       drug 
                        
                       
                           
                       
                        
                       
                         concentration 
                         . 
                         
                           
 
                         
                          
                         
                             
                         
                          
                         
                           C 
                           ss 
                         
                       
                        
                       max 
                     
                     = 
                     
                       
                         
                           F 
                           × 
                           
                             dose 
                             / 
                             1 
                           
                         
                         - 
                         
                            
                           
                             - 
                             kt 
                           
                         
                       
                       
                         DV 
                         d 
                       
                     
                   
                    
                   
                     
 
                   
                    
                   
                       
                   
                    
                   
                     
                       
                         C 
                         ss 
                       
                        
                       max 
                     
                     = 
                     
                       Steady 
                        
                       
                           
                       
                        
                       state 
                        
                       
                           
                       
                        
                       maximum 
                        
                       
                           
                       
                        
                       concentration 
                        
                       
                           
                       
                        
                       
                         ( 
                         
                           ng 
                            
                           
                             / 
                           
                            
                           mL 
                         
                         ) 
                       
                     
                   
                    
                   
                     
 
                   
                    
                   
                       
                   
                    
                   
                     F 
                     = 
                     
                       Fractional 
                        
                       
                           
                       
                        
                       bioavailability 
                     
                   
                    
                   
                     
 
                   
                    
                   
                       
                   
                    
                   
                     k 
                     = 
                     
                       Fractional 
                        
                       
                           
                       
                        
                       rate 
                        
                       
                           
                       
                        
                       constant 
                        
                       
                           
                       
                        
                       
                         ( 
                         
                           drug 
                            
                           
                               
                           
                            
                           
                             clearance 
                             / 
                             
                               V 
                               d 
                             
                           
                         
                         ) 
                       
                     
                   
                    
                   
                     
 
                   
                    
                   
                       
                   
                    
                   
                     t 
                     = 
                     
                       Dose 
                        
                       
                           
                       
                        
                       frequency 
                        
                       
                           
                       
                        
                       
                         ( 
                         hr 
                         ) 
                       
                     
                   
                    
                   
                     
 
                   
                    
                   
                       
                   
                    
                   
                     
                       DV 
                       d 
                     
                     = 
                     
                       Donor 
                        
                       
                           
                       
                        
                       volume 
                        
                       
                           
                       
                        
                       of 
                        
                       
                           
                       
                        
                       distribution 
                        
                       
                           
                       
                        
                       
                         
                           ( 
                           
                             reference 
                              
                             
                                 
                             
                              
                             
                               Eq 
                               . 
                               
                                   
                               
                                
                               2 
                             
                           
                           ) 
                         
                         . 
                       
                     
                   
                 
               
               
                 
                   Eq 
                   . 
                   
                       
                   
                    
                   3 
                 
               
             
             
               
                 
                   
                     
                       Determination 
                        
                       
                           
                       
                        
                       of 
                        
                       
                           
                       
                        
                       steady 
                        
                       
                           
                       
                        
                       state 
                        
                       
                           
                       
                        
                       minimum 
                        
                       
                           
                       
                        
                       plasma 
                        
                       
                           
                       
                        
                       drug 
                        
                       
                           
                       
                        
                       
                         concentration 
                         . 
                         
                           
 
                         
                          
                         
                             
                         
                          
                         
                           C 
                           ss 
                         
                       
                        
                       min 
                     
                     = 
                     
                       
                         C 
                         ss 
                       
                        
                       max 
                       × 
                       
                          
                         
                           - 
                           kt 
                         
                       
                     
                   
                    
                   
                     
 
                   
                    
                   
                       
                   
                    
                   
                     
                       
                         C 
                         ss 
                       
                        
                       min 
                     
                     = 
                     
                       Steady 
                        
                       
                           
                       
                        
                       state 
                        
                       
                           
                       
                        
                       minimum 
                        
                       
                           
                       
                        
                       concentration 
                        
                       
                           
                       
                        
                       
                         ( 
                         
                           ng 
                            
                           
                             / 
                           
                            
                           mL 
                         
                         ) 
                       
                     
                   
                    
                   
                     
 
                   
                    
                   
                       
                   
                    
                   
                     k 
                     = 
                     
                       Fractional 
                        
                       
                           
                       
                        
                       rate 
                        
                       
                           
                       
                        
                       constant 
                        
                       
                           
                       
                        
                       
                         ( 
                         
                           drug 
                            
                           
                               
                           
                            
                           
                             clearnace 
                             / 
                             
                               V 
                               d 
                             
                           
                         
                         ) 
                       
                     
                   
                    
                   
                     
 
                   
                    
                   
                       
                   
                    
                   
                     t 
                     = 
                     
                       Dose 
                        
                       
                           
                       
                        
                       frequency 
                        
                       
                           
                       
                        
                       
                         ( 
                         hr 
                         ) 
                       
                     
                   
                 
               
               
                 
                   Eq 
                   . 
                   
                       
                   
                    
                   4 
                 
               
             
           
         
       
     
       Calculated Values 
       [0055]    Each donor provides simultaneous serum and oral fluid samples. The measured serum drug concentration is the LC-MS/MS response ratio of drug to internal standard determined from the individual&#39;s provided serum sample. The measured oral fluid drug concentration ratio is the LC-MS/MS response ratio of drug to internal standard determined from the individual&#39;s provided oral fluid sample. The oral fluid plasma equivalent is derived from the individual&#39;s measured oral fluid drug concentration, salivary pH, as well as various drug parameters referenced in literature. 
         [0000]    
       
         
           
             
               
                 
                   
                     
                       Determination 
                        
                       
                           
                       
                        
                       of 
                        
                       
                           
                       
                        
                       plasma 
                        
                       
                           
                       
                        
                       drug 
                        
                       
                           
                       
                        
                       concentration 
                        
                       
                           
                       
                        
                       based 
                        
                       
                           
                       
                        
                       on 
                        
                       
                           
                       
                        
                       oral 
                        
                       
                           
                       
                        
                       fluid 
                        
                       
                           
                       
                        
                       analysis 
                        
                       
                           
                       
                        
                       for 
                        
                       
                           
                       
                        
                       acidic 
                        
                       
                           
                       
                        
                       
                         drugs 
                         . 
                         
                             
                         
                          
                         
                           
 
                         
                          
                         
                             
                         
                          
                         S 
                       
                        
                       
                         / 
                       
                        
                       P 
                     
                     = 
                     
                       
                         1 
                         + 
                         
                           
                             10 
                             
                               ( 
                               
                                 pHs 
                                 - 
                                 pKa 
                               
                               ) 
                             
                           
                           × 
                           fp 
                         
                       
                       
                         1 
                         + 
                         
                           
                             10 
                             
                               ( 
                               
                                 pHp 
                                 - 
                                 pKa 
                               
                               ) 
                             
                           
                           × 
                           fs 
                         
                       
                     
                   
                    
                   
                     
 
                   
                    
                   
                     S 
                     = 
                     
                       Saliva 
                        
                       
                           
                       
                        
                       drug 
                        
                       
                           
                       
                        
                       concentration 
                        
                       
                           
                       
                        
                       
                         ( 
                         
                           ng 
                            
                           
                             / 
                           
                            
                           mL 
                         
                         ) 
                       
                     
                   
                    
                   
                     
 
                   
                    
                   
                     P 
                     = 
                     
                       Plasma 
                        
                       
                           
                       
                        
                       drug 
                        
                       
                           
                       
                        
                       concentration 
                        
                       
                           
                       
                        
                       
                         ( 
                         
                           ng 
                            
                           
                             / 
                           
                            
                           mL 
                         
                         ) 
                       
                     
                   
                    
                   
                     
 
                   
                    
                   
                     
                       pH 
                       s 
                     
                     = 
                     
                         
                     
                      
                     
                       pH 
                        
                       
                           
                       
                        
                       of 
                        
                       
                           
                       
                        
                       saliva 
                        
                       
                           
                       
                        
                       
                         ( 
                         
                           to 
                            
                           
                               
                           
                            
                           be 
                            
                           
                               
                           
                            
                           determined 
                            
                           
                               
                           
                            
                           at 
                            
                           
                               
                           
                            
                           the 
                            
                           
                               
                           
                            
                           time 
                            
                           
                               
                           
                            
                           of 
                            
                           
                               
                           
                            
                           collection 
                         
                         ) 
                       
                     
                   
                    
                   
                     
 
                   
                    
                   
                     
                       pH 
                       p 
                     
                     = 
                     
                       
                         pH 
                          
                         
                             
                         
                          
                         of 
                          
                         
                             
                         
                          
                         plasma 
                          
                         
                             
                         
                          
                         
                           ( 
                           
                             assumed 
                              
                             
                                 
                             
                              
                             to 
                              
                             
                                 
                             
                              
                             be 
                              
                             
                                 
                             
                              
                             7.4 
                           
                           ) 
                         
                          
                         
                           
 
                         
                          
                         pKa 
                       
                       = 
                       
                           
                       
                        
                       
                         
                           
                             Dissociat 
                              
                             ion 
                           
                            
                           
                               
                           
                            
                           constant 
                            
                           
                               
                           
                            
                           of 
                            
                           
                               
                           
                            
                           a 
                            
                           
                               
                           
                            
                           drug 
                            
                           
                               
                           
                            
                           
                             ( 
                             
                               referenced 
                                
                               
                                   
                               
                                
                               in 
                                
                               
                                   
                               
                                
                               literature 
                             
                             ) 
                           
                            
                           
                             
 
                           
                            
                           fp 
                         
                         = 
                         
                           
                             Free 
                              
                             
                                 
                             
                              
                             fraction 
                              
                             
                                 
                             
                              
                             of 
                              
                             
                                 
                             
                              
                             drug 
                              
                             
                                 
                             
                              
                             in 
                              
                             
                                 
                             
                              
                             plasma 
                              
                             
                                 
                             
                              
                             
                               ( 
                               
                                 referenced 
                                  
                                 
                                     
                                 
                                  
                                 in 
                                  
                                 
                                     
                                 
                                  
                                 literature 
                               
                               ) 
                             
                              
                             
                               
 
                             
                              
                             fs 
                           
                           = 
                           
                             Free 
                              
                             
                                 
                             
                              
                             fraction 
                              
                             
                                 
                             
                              
                             of 
                              
                             
                                 
                             
                              
                             drug 
                              
                             
                                 
                             
                              
                             in 
                              
                             
                                 
                             
                              
                             saliva 
                              
                             
                                 
                             
                              
                             
                               ( 
                               
                                 negligible 
                                  
                                 
                                     
                                 
                                  
                                 
                                   
                                       
                                   
                                   ; 
                                 
                                  
                                 
                                     
                                 
                                  
                                 assumed 
                                  
                                 
                                     
                                 
                                  
                                 to 
                                  
                                 
                                     
                                 
                                  
                                 be 
                                  
                                 
                                     
                                 
                                  
                                 1 
                               
                               ) 
                             
                           
                         
                       
                     
                   
                 
               
               
                 
                   Eq 
                   . 
                   
                       
                   
                    
                   5 
                 
               
             
             
               
                 
                   
                     
                       
                         Determination 
                          
                         
                             
                         
                          
                         of 
                          
                         
                             
                         
                          
                         plasma 
                          
                         
                             
                         
                          
                         drug 
                          
                         
                             
                         
                          
                         concentration 
                          
                         
                             
                         
                          
                         based 
                          
                         
                             
                         
                          
                         on 
                          
                         
                             
                         
                          
                         oral 
                          
                         
                             
                         
                          
                         fluid 
                          
                         
                             
                         
                          
                         analysis 
                          
                         
                             
                         
                          
                         for 
                          
                         
                             
                         
                          
                         basic 
                          
                         
                             
                         
                          
                         
                           drugs 
                           . 
                           
                             
 
                           
                            
                           
                               
                           
                            
                           S 
                         
                          
                         
                           / 
                         
                          
                         P 
                       
                       = 
                       
                         
                           1 
                           + 
                           
                             
                               10 
                               
                                 ( 
                                 
                                   pKa 
                                   - 
                                   pHs 
                                 
                                 ) 
                               
                             
                             × 
                             fp 
                           
                         
                         
                           1 
                           + 
                           
                             
                               10 
                               
                                 ( 
                                 
                                   pKa 
                                   - 
                                   pHp 
                                 
                                 ) 
                               
                             
                             × 
                             fs 
                           
                         
                       
                     
                      
                     
                       
 
                     
                      
                     
                       S 
                       = 
                       
                         Saliva 
                          
                         
                             
                         
                          
                         drug 
                          
                         
                             
                         
                          
                         concentration 
                          
                         
                             
                         
                          
                         
                           ( 
                           
                             ng 
                              
                             
                               / 
                             
                              
                             mL 
                           
                           ) 
                         
                       
                     
                      
                     
                       
 
                     
                      
                     
                       P 
                       = 
                       
                         Plasma 
                          
                         
                             
                         
                          
                         drug 
                          
                         
                             
                         
                          
                         concentration 
                          
                         
                             
                         
                          
                         
                           ( 
                           
                             ng 
                              
                             
                               / 
                             
                              
                             mL 
                           
                           ) 
                         
                       
                     
                      
                     
                       
 
                     
                      
                     
                       
                         pH 
                         s 
                       
                       = 
                       
                           
                       
                        
                       
                         pH 
                          
                         
                             
                         
                          
                         of 
                          
                         
                           
                               
                           
                            
                           
                               
                           
                         
                          
                         saliva 
                          
                         
                             
                         
                          
                         
                           ( 
                           
                             to 
                              
                             
                                 
                             
                              
                             be 
                              
                             
                                 
                             
                              
                             determined 
                              
                             
                                 
                             
                              
                             at 
                              
                             
                                 
                             
                              
                             the 
                              
                             
                                 
                             
                              
                             time 
                              
                             
                                 
                             
                              
                             of 
                              
                             
                                 
                             
                              
                             collection 
                           
                           ) 
                         
                       
                     
                      
                     
                       
 
                     
                      
                     
                       
                         pH 
                         p 
                       
                       = 
                       
                         pH 
                          
                         
                             
                         
                          
                         of 
                          
                         
                             
                         
                          
                         plasma 
                          
                         
                             
                         
                          
                         
                           ( 
                           
                             assumed 
                              
                             
                                 
                             
                              
                             to 
                              
                             
                                 
                             
                              
                             be 
                              
                             
                                 
                             
                              
                             7.4 
                           
                           ) 
                         
                       
                     
                      
                     
                       
 
                     
                      
                     
                       pKa 
                       = 
                       
                           
                       
                        
                       
                         
                           Dissociat 
                            
                           ion 
                         
                          
                         
                             
                         
                          
                         constant 
                          
                         
                             
                         
                          
                         of 
                          
                         
                             
                         
                          
                         a 
                          
                         
                             
                         
                          
                         drug 
                          
                         
                             
                         
                          
                         
                           ( 
                           
                             referenced 
                              
                             
                                 
                             
                              
                             in 
                              
                             
                                 
                             
                              
                             literature 
                           
                           ) 
                         
                       
                     
                      
                     
                       
 
                     
                      
                     
                       fp 
                       = 
                       
                         
                           Free 
                            
                           
                               
                           
                            
                           fraction 
                            
                           
                               
                           
                            
                           of 
                            
                           
                               
                           
                            
                           drug 
                            
                           
                               
                           
                            
                           in 
                            
                           
                               
                           
                            
                           plasma 
                            
                           
                               
                           
                            
                           
                             ( 
                             
                               referenced 
                                
                               
                                   
                               
                                
                               in 
                                
                               
                                   
                               
                                
                               literature 
                             
                             ) 
                           
                            
                           
                             
 
                           
                            
                           fs 
                         
                         = 
                         
                           Free 
                            
                           
                               
                           
                            
                           fraction 
                            
                           
                               
                           
                            
                           of 
                            
                           
                               
                           
                            
                           drug 
                            
                           
                               
                           
                            
                           in 
                            
                           
                               
                           
                            
                           saliva 
                            
                           
                               
                           
                            
                           
                             ( 
                             
                               negligible 
                                
                               
                                 
                                     
                                 
                                  
                                 
                                     
                                 
                               
                                
                               
                                 ; 
                               
                                
                               
                                   
                               
                                
                               assumed 
                                
                               
                                   
                               
                                
                               to 
                                
                               
                                   
                               
                                
                               be 
                                
                               
                                   
                               
                                
                               1 
                             
                             ) 
                           
                         
                       
                     
                   
                    
                   
                     
 
                   
                 
               
               
                 
                   Eq 
                   . 
                   
                       
                   
                    
                   6 
                 
               
             
           
         
       
     
         [0056]    Once the S/P ratio for a drug is calculated using Eq. 5 or Eq. 6, oral fluid plasma equivalent is determined by multiplying the calculated S/P by the measured oral fluid drug concentration determined by LC/MS-MS quantitation, ultimately eliminating the necessity of directly analyzing blood samples to determine donor compliance. 
         [0000]    
       
         
           
             
               
                 
                   
                     Determination 
                      
                     
                         
                     
                      
                     of 
                      
                     
                         
                     
                      
                     calculated 
                      
                     
                         
                     
                      
                     plasma 
                      
                     
                         
                     
                      
                     drug 
                      
                     
                         
                     
                      
                     
                       concentration 
                       . 
                       
                         
 
                       
                        
                       Oral 
                     
                      
                     
                         
                     
                      
                     fluid 
                      
                     
                         
                     
                      
                     plasma 
                      
                     
                         
                     
                      
                     equivalent 
                      
                     
                         
                     
                      
                     
                       ( 
                       
                         ng 
                          
                         
                           / 
                         
                          
                         mL 
                       
                       ) 
                     
                   
                   = 
                   
                     
                       
                         Measured 
                          
                         
                             
                         
                          
                         oral 
                          
                         
                             
                         
                          
                         fluid 
                          
                         
                             
                         
                          
                         drug 
                          
                         
                             
                         
                          
                         concentration 
                          
                         
                             
                         
                          
                         
                           ( 
                           
                             ng 
                              
                             
                               / 
                             
                              
                             mL 
                           
                           ) 
                         
                       
                        
                       
                           
                       
                     
                     
                       Calculated 
                        
                       
                           
                       
                        
                       S 
                        
                       
                         / 
                       
                        
                       P 
                     
                   
                 
               
               
                 
                   Eq 
                   . 
                   
                       
                   
                    
                   8 
                 
               
             
           
         
       
     
       Determination of Compliance 
       [0057]    The steady state concentration ranges calculated by Eq. 3 and Eq. 4 provide a drug concentration range unique to each donor. This range is the guideline to determining an individual&#39;s compliance with the dosing regimen provided. Both the LC/MS-MS quantitated plasma drug concentration and the oral fluid plasma equivalent determined by Eq. 8 are compared to the steady state range determined. The measured plasma drug concentration can fall within the range, fall above the range, or fall below the range, providing clues to donor compliance. Similarly, the oral fluid plasma equivalent can fall within the range, fall above the range, or fall below the range. There is an agreement in compliance if the measured and the oral fluid plasma equivalent drug concentrations either both fall within the range, both fall above the range, or both fall below the range. These calculations apply to a wide range of therapeutic drugs. The following examples illustrate the application of the equations above in a proof of concept study. 
       Example Calculations Supporting Equations Above in Proof of Concept Study 
     Hydrocodone Example Calculation 
       [0058]      
         [0000]    
       
         
               
             
               
               
               
             
           
               
                 TABLE 1 
               
               
                   
               
               
                 Hydrocodone pharmacokinetic parameters. 
               
               
                 Hydrocodone 
               
               
                   
               
             
             
               
                   
               
             
          
           
               
                   
                 Clearance (L × hr −1  × kg −1 ) 
                 0.529 
               
               
                   
                 Volume of Distribution (L/kg) 
                 4.0 
               
               
                   
                 Fractional Bioavailability 
                 0.7 
               
               
                   
                 Fractional Rate Constant (hr −1 ); “k” 
                 0.132 
               
               
                   
                 Unbound Fraction (fp) 
                 0.68 
               
               
                   
                 pKa 
                 8.9 
               
               
                   
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
               
               
             
               
               
               
               
               
             
           
               
                 TABLE 2 
               
             
             
               
                   
               
               
                 Donor information. 
               
             
          
           
               
                   
                   
                   
                 Dosing Frequency 
                   
               
               
                 Donor 
                 Salivary pH (pHs) 
                 Dose (mg) 
                 (hr) 
                 Weight (kg) 
               
               
                   
               
             
          
           
               
                 0409 
                 6 
                 5 
                 6 
                 67.646 
               
               
                 0704 
                 6.6 
                 10 
                 12 
                 147.55 
               
               
                 0897 
                 7 
                 10 
                 4 
                 83.99 
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
             
           
               
                 TABLE 3 
               
             
             
               
                   
               
               
                 Donor calculations. 
               
             
          
           
               
                   
                 Donor Clearance (L/hr) 
                   
               
               
                   
                 Donor Clearance (L/hr) = 
                 DV d  (L) 
               
               
                   
                 Drug Clearance (L × hr −1  × kg −1 ) × 
                 DV d  (L) = V d  (L) × Donor 
               
               
                 Donor 
                 Donor Weight (kg) 
                 Weight (kg) 
               
               
                   
               
               
                 0409 
                 = 0.529 × 67.646 
                 = 4.0 × 67.646 
               
               
                   
                 = 35.785 L/hr 
                 = 270.5 L 
               
               
                 0704 
                 = 0.529 × 147.55 
                 = 4.0 × 147.55 
               
               
                   
                 = 78.054 L/hr 
                 = 590.2 L 
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
             
           
               
                 TABLE 4 
               
             
             
               
                   
               
               
                 Calculated steady state maximum plasma hydrocodone concentration. 
               
               
                 
                   
                     
                       
                         
                           
                             C 
                             ss 
                           
                            
                           max 
                         
                         = 
                         
                           
                             
                               F 
                               × 
                               
                                 dose 
                                 / 
                                 1 
                               
                             
                             - 
                             
                               e 
                               
                                 - 
                                 kt 
                               
                             
                           
                           
                             DV 
                             d 
                           
                         
                       
                     
                   
                 
               
               
                   
               
             
          
           
               
                 Donor 0409 
                 Donor 0704 
                 Donor 0897 
               
               
                   
               
               
                 
                   
                     
                       
                         = 
                         
                           
                             
                               
                                 0.7 
                                 × 
                                 
                                   5 
                                   / 
                                   1 
                                 
                               
                               - 
                               
                                 e 
                                 
                                   - 
                                   
                                     ( 
                                     
                                       0.132 
                                       × 
                                       6 
                                     
                                     ) 
                                   
                                 
                               
                             
                             270.5 
                           
                            
                           
                             
 
                           
                           = 
                           
                             23.6 
                              
                             
                                 
                             
                              
                             ng 
                              
                             
                               / 
                             
                              
                             mL 
                           
                         
                       
                     
                   
                 
                 
                   
                     
                       
                         = 
                         
                           
                             
                               
                                 0.7 
                                 × 
                                 
                                   10 
                                   / 
                                   1 
                                 
                               
                               - 
                               
                                 e 
                                 
                                   - 
                                   
                                     ( 
                                     
                                       0.132 
                                       × 
                                       12 
                                     
                                     ) 
                                   
                                 
                               
                             
                             590.2 
                           
                            
                           
                             
 
                           
                           = 
                           
                             14.9 
                              
                             
                                 
                             
                              
                             ng 
                              
                             
                               / 
                             
                              
                             mL 
                           
                         
                       
                     
                   
                 
                 
                   
                     
                       
                         = 
                         
                           
                             
                               
                                 0.7 
                                 × 
                                 
                                   10 
                                   / 
                                   1 
                                 
                               
                               - 
                               
                                 e 
                                 
                                   - 
                                   
                                     ( 
                                     
                                       0.132 
                                       × 
                                       4 
                                     
                                     ) 
                                   
                                 
                               
                             
                             335.9 
                           
                            
                           
                             
 
                           
                           = 
                           
                             50.7 
                              
                             
                                 
                             
                              
                             ng 
                              
                             
                               / 
                             
                              
                             mL 
                           
                         
                       
                     
                   
                 
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
             
           
               
                 TABLE 5 
               
             
             
               
                   
               
               
                 Calculated steady state minimum plasma hydrocodone concentration. 
               
               
                 C ss  min = C ss  max × e −kt   
               
             
          
           
               
                 Donor 0409 
                 Donor 0704 
                 Donor 0897 
               
               
                   
               
               
                 = 23.6 × e −(0.132×6)   
                 = 14.9 × e −(0.132×12)   
                 = 50.7 × e −(0.132×4)   
               
               
                 = 10.7 ng/mL 
                 = 3.0 ng/mL 
                 = 29.9 ng/mL 
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
             
           
               
                 TABLE 6 
               
             
             
               
                   
               
               
                 Calculated saliva to plasma hydrocodone concentration ratio calculation. 
               
               
                 
                   
                     
                       
                         
                           S 
                           / 
                           P 
                         
                         = 
                         
                           
                             1 
                             + 
                             
                               
                                 10 
                                 
                                   ( 
                                   
                                     pKa 
                                     - 
                                     pHs 
                                   
                                   ) 
                                 
                               
                               × 
                               fp 
                             
                           
                           
                             1 
                             + 
                             
                               
                                 10 
                                 
                                   ( 
                                   
                                     pKa 
                                     - 
                                     pHp 
                                   
                                   ) 
                                 
                               
                               × 
                               fs 
                             
                           
                         
                       
                     
                   
                 
               
               
                   
               
             
          
           
               
                 Donor 0409 
                 Donor 0704 
                 Donor 0897 
               
               
                   
               
               
                 
                   
                     
                       
                         = 
                         
                           
                             
                               1 
                               + 
                               
                                 
                                   10 
                                   
                                     ( 
                                     
                                       8.9 
                                       - 
                                       6 
                                     
                                     ) 
                                   
                                 
                                 × 
                                 0.68 
                               
                             
                             
                               1 
                               + 
                               
                                 
                                   10 
                                   
                                     ( 
                                     
                                       8.9 
                                       - 
                                       7.4 
                                     
                                     ) 
                                   
                                 
                                 × 
                                 1 
                               
                             
                           
                            
                           
                             
 
                           
                           = 
                           16.5 
                         
                       
                     
                   
                 
                 
                   
                     
                       
                         = 
                         
                           
                             
                               1 
                               + 
                               
                                 
                                   10 
                                   
                                     ( 
                                     
                                       8.9 
                                       - 
                                       6 
                                     
                                     ) 
                                   
                                 
                                 × 
                                 0.68 
                               
                             
                             
                               1 
                               + 
                               
                                 
                                   10 
                                   
                                     ( 
                                     
                                       8.9 
                                       - 
                                       7.4 
                                     
                                     ) 
                                   
                                 
                                 × 
                                 1 
                               
                             
                           
                            
                           
                             
 
                           
                           = 
                           4.1 
                         
                       
                     
                   
                 
                 
                   
                     
                       
                         = 
                         
                           
                             
                               1 
                               + 
                               
                                 
                                   10 
                                   
                                     ( 
                                     
                                       8.9 
                                       - 
                                       7 
                                     
                                     ) 
                                   
                                 
                                 × 
                                 0.68 
                               
                             
                             
                               1 
                               + 
                               
                                 
                                   10 
                                   
                                     ( 
                                     
                                       8.9 
                                       - 
                                       7.4 
                                     
                                     ) 
                                   
                                 
                                 × 
                                 1 
                               
                             
                           
                            
                           
                             
 
                           
                           = 
                           1.6 
                         
                       
                     
                   
                 
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
             
               
               
               
             
           
               
                 TABLE 7 
               
             
             
               
                   
               
               
                 Hydrocodone LC-MS/MS quantitation. 
               
             
          
           
               
                   
                 Measured Saliva 
                   
               
               
                   
                 Hydrocodone Concentration 
                 Measured Plasma Hydrocodone 
               
               
                 Donor 
                 (ng/mL) 
                 Concentration (ng/mL) 
               
               
                   
               
             
          
           
               
                 0409 
                 341.2 
                 19.8 
               
               
                 0704 
                 252.7 
                 44.6 
               
               
                 0897 
                 17.1 
                 11.6 
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
             
           
               
                 TABLE 8 
               
             
             
               
                   
               
               
                 Oral fluid plasma equivalent calculation. 
               
               
                 
                   
                     
                       
                         
                           
                             
                               
                                 Oral 
                                  
                                 
                                     
                                 
                                  
                                 fluid 
                                  
                                 
                                     
                                 
                                  
                                 plasma 
                               
                             
                           
                           
                             
                               
                                 equivalent 
                                  
                                 
                                     
                                 
                                  
                                 
                                   ( 
                                   
                                     ng 
                                      
                                     
                                       / 
                                     
                                      
                                     mL 
                                   
                                   ) 
                                 
                               
                             
                           
                         
                         = 
                         
                           
                             
                               
                                 
                                   Measured 
                                    
                                   
                                       
                                   
                                    
                                   oral 
                                    
                                   
                                       
                                   
                                    
                                   fluid 
                                 
                               
                             
                             
                               
                                 
                                   drug 
                                    
                                   
                                       
                                   
                                    
                                   concentration 
                                    
                                   
                                       
                                   
                                    
                                   
                                     ( 
                                     
                                       ng 
                                        
                                       
                                         / 
                                       
                                        
                                       mL 
                                     
                                     ) 
                                   
                                 
                               
                             
                           
                           
                             Calculated 
                              
                             
                                 
                             
                              
                             S 
                              
                             
                               / 
                             
                              
                             P 
                           
                         
                       
                     
                   
                 
               
               
                   
               
             
          
           
               
                 Donor 0409 
                 Donor 0704 
                 Donor 0897 
               
               
                   
               
               
                 
                   
                     
                       
                         = 
                         
                           
                             341.2 
                             16.5 
                           
                            
                           
                             
 
                           
                           = 
                           
                             20.5 
                              
                             
                                 
                             
                              
                             ng 
                              
                             
                               / 
                             
                              
                             mL 
                           
                         
                       
                     
                   
                 
                 
                   
                     
                       
                         = 
                         
                           
                             252.7 
                             4.1 
                           
                            
                           
                             
 
                           
                           = 
                           
                             60.5 
                              
                             
                                 
                             
                              
                             ng 
                              
                             
                               / 
                             
                              
                             mL 
                           
                         
                       
                     
                   
                 
                 
                   
                     
                       
                         = 
                         
                           
                             17.1 
                             1.6 
                           
                            
                           
                             
 
                           
                           = 
                           
                             10.6 
                              
                             
                                 
                             
                              
                             ng 
                              
                             
                               / 
                             
                              
                             mL 
                           
                         
                       
                     
                   
                 
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
               
               
               
               
               
             
               
               
               
               
               
               
               
               
             
           
               
                 TABLE 9 
               
             
             
               
                   
               
               
                 Compliance analysis. 
               
             
          
           
               
                   
                   
                   
                 Meas- 
                   
                 Hydro- 
                   
                   
               
               
                   
                   
                   
                 ured 
                   
                 codone 
                   
                   
               
               
                   
                   
                   
                 Hydro- 
                   
                 Oral  
                   
                   
               
               
                   
                   
                   
                 codone 
                   
                 Fluid 
                   
                 Agree- 
               
               
                   
                   
                   
                 Plasma 
                   
                 Plasma 
                   
                 ment 
               
               
                   
                   
                   
                 Concen- 
                   
                 Equiv- 
                   
                 in 
               
               
                   
                 C ss  max 
                 C ss  min 
                 tration 
                 Com- 
                 alent 
                 Com- 
                 Com- 
               
               
                 Donor  
                 (ng/mL) 
                 (ng/mL) 
                 (ng/mL) 
                 pliance  
                 (ng/mL) 
                 pliance  
                 pliance 
               
               
                   
               
             
          
           
               
                 0409 
                 23.6 
                 10.7 
                 19.8 
                 Within 
                 20.5 
                 Within 
                 Agree 
               
               
                 0704 
                 14.9 
                 5.6 
                 44.6 
                 Above 
                 60.5 
                 Above 
                 Agree 
               
               
                 0897 
                 50.7 
                 29.9 
                 11.6 
                 Below 
                 10.1 
                 Below 
                 Agree 
               
               
                   
               
             
          
         
       
       
      
      
      
     
         [0059]    *Expected steady state plasma drug range is calculated based on dosing regimen provided by donor. Maximum steady state concentrations may fall outside therapeutic ranges and approach and/or exceed toxic ranges due to drug tolerance. 
       Example Calculations Supporting Equations Above in Proof of Concept Study 
     Oxycodone Example Calculation 
       [0060]      
         [0000]    
       
         
               
             
               
               
               
             
           
               
                 TABLE 10 
               
               
                   
               
               
                 Oxycodone pharmacokinetic parameters. 
               
               
                 Oxycodone 
               
               
                   
               
             
             
               
                   
               
             
          
           
               
                   
                 Clearance (L × hr −1  × kg −1 ) 
                 0.744 
               
               
                   
                 Volume of Distribution (L/kg) 
                 2.0 
               
               
                   
                 Fractional Bioavailability 
                 0.735 
               
               
                   
                 Fractional Rate Constant (hr −1 ); “k” 
                 0.372 
               
               
                   
                 Unbound Fraction (fp) 
                 0.55 
               
               
                   
                 pKa 
                 8.5 
               
               
                   
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
               
               
             
               
               
               
               
               
             
           
               
                 TABLE 11 
               
             
             
               
                   
               
               
                 Donor information. 
               
             
          
           
               
                   
                 Salivary  
                   
                 Dosing  
                   
               
               
                 Donor 
                 pH (pHs) 
                 Dose (mg) 
                 Frequency (hr) 
                 Weight (kg) 
               
               
                   
               
             
          
           
               
                 0182 
                 5.5 
                 5 
                 6 
                 68.554 
               
               
                 0602 
                 5.5 
                 5 
                 12 
                 163.44 
               
               
                 0383 
                 5.8 
                 10 
                 4 
                 68.10 
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
             
           
               
                 TABLE 12 
               
             
             
               
                   
               
               
                 Donor calculations. 
               
             
          
           
               
                   
                 Donor Clearance (L/hr) 
                   
               
               
                   
                 Donor Clearance (L/hr) = 
                 DV d  (L) 
               
               
                   
                 Drug Clearance (L × hr −1  × kg −1 ) × 
                 DV d  (L) = V d  (L) × Donor 
               
               
                 Donor 
                 Donor Weight (kg) 
                 Weight (kg) 
               
               
                   
               
               
                 0182 
                 = 0.744 × 68.554 
                 = 2.0 × 68.554 
               
               
                   
                 = 51.004 L/hr 
                 = 137.1 L 
               
               
                 0602 
                 = 0.744 × 163.44 
                 = 2.0 × 163.44 
               
               
                   
                 = 121.599 L/hr 
                 = 326.8 L 
               
               
                 0383 
                 = 0.744 × 68.10 
                 = 2.0 × 68.10 
               
               
                   
                 = 50.600 L/hr 
                 = 136.2 L 
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
             
           
               
                 TABLE 13 
               
             
             
               
                   
               
               
                 Calculated steady state maximum plasma oxycodone concentration. 
               
               
                 
                   
                     
                       
                         
                           
                             C 
                             ss 
                           
                            
                           max 
                         
                         = 
                         
                           
                             
                               F 
                               × 
                               
                                 dose 
                                 / 
                                 1 
                               
                             
                             - 
                             
                               e 
                               
                                 - 
                                 kt 
                               
                             
                           
                           
                             DV 
                             d 
                           
                         
                       
                     
                   
                 
               
               
                   
               
             
          
           
               
                 Donor 0182 
                 Donor 0602 
                 Donor 0383 
               
               
                   
               
               
                 
                   
                     
                       
                         = 
                         
                           
                             
                               
                                 0.735 
                                 × 
                                 
                                   10 
                                   / 
                                   1 
                                 
                               
                               - 
                               
                                 e 
                                 
                                   - 
                                   
                                     ( 
                                     
                                       0.372 
                                       × 
                                       6 
                                     
                                     ) 
                                   
                                 
                               
                             
                             137.1 
                           
                            
                           
                             
 
                           
                           = 
                           
                             30.0 
                              
                             
                                 
                             
                              
                             ng 
                              
                             
                               / 
                             
                              
                             mL 
                           
                         
                       
                     
                   
                 
                 
                   
                     
                       
                         = 
                         
                           
                             
                               
                                 0.735 
                                 × 
                                 
                                   5 
                                   / 
                                   1 
                                 
                               
                               - 
                               
                                 e 
                                 
                                   - 
                                   
                                     ( 
                                     
                                       0.372 
                                       × 
                                       12 
                                     
                                     ) 
                                   
                                 
                               
                             
                             326.8 
                           
                            
                           
                             
 
                           
                           = 
                           
                             11.3 
                              
                             
                                 
                             
                              
                             ng 
                              
                             
                               / 
                             
                              
                             mL 
                           
                         
                       
                     
                   
                 
                 
                   
                     
                       
                         = 
                         
                           
                             
                               
                                 0.735 
                                 × 
                                 
                                   5 
                                   / 
                                   1 
                                 
                               
                               - 
                               
                                 e 
                                 
                                   - 
                                   
                                     ( 
                                     
                                       0.372 
                                       × 
                                       4 
                                     
                                     ) 
                                   
                                 
                               
                             
                             136.2 
                           
                            
                           
                             
 
                           
                           = 
                           
                             69.7 
                              
                             
                                 
                             
                              
                             ng 
                              
                             
                               / 
                             
                              
                             mL 
                           
                         
                       
                     
                   
                 
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
             
           
               
                 TABLE 14 
               
             
             
               
                   
               
               
                 Calculated steady state minimum plasma oxycodone concentration. 
               
               
                 C ss  min = C ss  max × e −kt   
               
             
          
           
               
                 Donor 0182 
                 Donor 0602 
                 Donor 0383 
               
               
                   
               
               
                 = 30.0 × e −(0.372×6)   
                 = 11.3 × e −(0.372×12)   
                 = 69.7 × e −(0.372×4)   
               
               
                 = 3.2 ng/mL 
                 = 0.1 ng/mL 
                 = 15.7 ng/mL 
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
             
           
               
                 TABLE 15 
               
             
             
               
                   
               
               
                 Calculated saliva to plasma oxycodone concentration ratio calculation. 
               
               
                 
                   
                     
                       
                         
                           S 
                            
                           
                             / 
                           
                            
                           P 
                         
                         = 
                         
                           
                             1 
                             + 
                             
                               
                                 10 
                                 
                                   ( 
                                   
                                     pKa 
                                     - 
                                     pHs 
                                   
                                   ) 
                                 
                               
                               × 
                               fp 
                             
                           
                           
                             1 
                             + 
                             
                               
                                 10 
                                 
                                   ( 
                                   
                                     pKa 
                                     - 
                                     pHp 
                                   
                                   ) 
                                 
                               
                               × 
                               fs 
                             
                           
                         
                       
                     
                   
                 
               
               
                   
               
             
          
           
               
                 Donor 0182 
                 Donor 0602 
                 Donor 0383 
               
               
                   
               
               
                 
                   
                     
                       
                         = 
                         
                           
                             
                               1 
                               + 
                               
                                 
                                   10 
                                   
                                     ( 
                                     
                                       8.5 
                                       - 
                                       5.5 
                                     
                                     ) 
                                   
                                 
                                 × 
                                 0.55 
                               
                             
                             
                               1 
                               + 
                               
                                 
                                   10 
                                   
                                     ( 
                                     
                                       8.5 
                                       - 
                                       7.4 
                                     
                                     ) 
                                   
                                 
                                 × 
                                 1 
                               
                             
                           
                            
                           
                             
 
                           
                           = 
                           40.5 
                         
                       
                     
                   
                 
                 
                   
                     
                       
                         = 
                         
                           
                             
                               1 
                               + 
                               
                                 
                                   10 
                                   
                                     ( 
                                     
                                       8.5 
                                       - 
                                       5.5 
                                     
                                     ) 
                                   
                                 
                                 × 
                                 0.55 
                               
                             
                             
                               1 
                               + 
                               
                                 
                                   10 
                                   
                                     ( 
                                     
                                       8.5 
                                       - 
                                       7.4 
                                     
                                     ) 
                                   
                                 
                                 × 
                                 1 
                               
                             
                           
                            
                           
                             
 
                           
                           = 
                           40.5 
                         
                       
                     
                   
                 
                 
                   
                     
                       
                         = 
                         
                           
                             
                               1 
                               + 
                               
                                 
                                   10 
                                   
                                     ( 
                                     
                                       8.5 
                                       - 
                                       5.8 
                                     
                                     ) 
                                   
                                 
                                 × 
                                 0.55 
                               
                             
                             
                               1 
                               + 
                               
                                 
                                   10 
                                   
                                     ( 
                                     
                                       8.5 
                                       - 
                                       7.4 
                                     
                                     ) 
                                   
                                 
                                 × 
                                 1 
                               
                             
                           
                            
                           
                             
 
                           
                           = 
                           20.3 
                         
                       
                     
                   
                 
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
             
               
               
               
             
           
               
                 TABLE 16 
               
             
             
               
                   
               
               
                 Oxycodone LC-MS/MS quantitation. 
               
             
          
           
               
                   
                 Measured Saliva Oxycodone  
                 Measured Plasma Oxycodone 
               
               
                 Donor 
                 Concentration (ng/mL) 
                 Concentration (ng/mL) 
               
               
                   
               
             
          
           
               
                 0182 
                 306.4 
                 7.9 
               
               
                 0602 
                 978.2 
                 16.7 
               
               
                 0383 
                 230.2 
                 8.4 
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
             
           
               
                 TABLE 17 
               
             
             
               
                   
               
               
                 Oral fluid plasma equivalent calculation. 
               
               
                 
                   
                     
                       
                         
                           
                             
                               
                                 Oral 
                                  
                                 
                                     
                                 
                                  
                                 fluid 
                                  
                                 
                                     
                                 
                                  
                                 plasma 
                               
                             
                           
                           
                             
                               
                                 equivalent 
                                  
                                 
                                     
                                 
                                  
                                 
                                   ( 
                                   
                                     ng 
                                      
                                     
                                       / 
                                     
                                      
                                     mL 
                                   
                                   ) 
                                 
                               
                             
                           
                         
                         = 
                         
                           
                             
                               
                                 
                                   
                                     Measured 
                                      
                                     
                                         
                                     
                                      
                                     oral 
                                      
                                     
                                         
                                     
                                      
                                     fluid 
                                   
                                    
                                   
                                       
                                   
                                 
                               
                             
                             
                               
                                 
                                   drug 
                                    
                                   
                                       
                                   
                                    
                                   
                                     c 
                                      
                                     oncentration 
                                   
                                    
                                   
                                       
                                   
                                    
                                   
                                     ( 
                                     
                                       ng 
                                        
                                       
                                         / 
                                       
                                        
                                       mL 
                                     
                                     ) 
                                   
                                 
                               
                             
                           
                           
                             Calculated 
                              
                             
                                 
                             
                              
                             S 
                              
                             
                               / 
                             
                              
                             P 
                           
                         
                       
                     
                   
                 
               
               
                   
               
             
          
           
               
                 Donor 0182 
                 Donor 0602 
                 Donor 0383 
               
               
                   
               
               
                 
                   
                     
                       
                         = 
                         
                           
                             306.4 
                             40.5 
                           
                            
                           
                             
 
                           
                           = 
                           
                             7.5 
                              
                             
                                 
                             
                              
                             ng 
                              
                             
                               / 
                             
                              
                             mL 
                           
                         
                       
                     
                   
                 
                 
                   
                     
                       
                         = 
                         
                           
                             978.2 
                             40.5 
                           
                            
                           
                             
 
                           
                           = 
                           
                             24.1 
                              
                             
                                 
                             
                              
                             ng 
                              
                             
                               / 
                             
                              
                             mL 
                           
                         
                       
                     
                   
                 
                 
                   
                     
                       
                         = 
                         
                           
                             230.2 
                             20.3 
                           
                            
                           
                             
 
                           
                           = 
                           
                             11.3 
                              
                             
                                 
                             
                              
                             ng 
                              
                             
                               / 
                             
                              
                             mL 
                           
                         
                       
                     
                   
                 
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
               
               
               
               
               
             
               
               
               
               
               
               
               
               
             
           
               
                 TABLE 18 
               
             
             
               
                   
               
               
                 Compliance analysis. 
               
             
          
           
               
                   
                   
                   
                 Meas- 
                   
                 Oxy- 
                   
                   
               
               
                   
                   
                   
                 ured 
                   
                 codone 
                   
                   
               
               
                   
                   
                   
                 Oxy- 
                   
                 Oral  
                   
                   
               
               
                   
                   
                   
                 codone 
                   
                 Fluid 
                   
                 Agree- 
               
               
                   
                   
                   
                 Plasma 
                   
                 Plasma 
                   
                 ment 
               
               
                   
                   
                   
                 Concen- 
                   
                 Equiv- 
                   
                 in 
               
               
                   
                 C ss  max 
                 C ss  min 
                 tration 
                 Com- 
                 alent 
                 Com- 
                 Com- 
               
               
                 Donor  
                 (ng/mL) 
                 (ng/mL) 
                 (ng/mL) 
                 pliance  
                 (ng/mL) 
                 pliance  
                 pliance 
               
               
                   
               
             
          
           
               
                 0182 
                 30.0 
                 3.2 
                 7.9 
                 Within 
                 7.5 
                 Within 
                 Agree 
               
               
                 0602 
                 11.3 
                 0.1 
                 16.7 
                 Above 
                 24.1 
                 Above 
                 Agree 
               
               
                 0383 
                 69.7 
                 15.7 
                 8.4 
                 Below 
                 11.3 
                 Below 
                 Agree 
               
               
                   
               
             
          
         
       
       
      
      
      
     
         [0061]    *Expected steady state plasma drug range is calculated based on dosing regimen provided by donor. Maximum steady state concentrations may fall outside therapeutic ranges and approach and/or exceed toxic ranges due to drug tolerance. 
       Example of Drug Supporting Equations Above in Proof of Concept Study 
     Tramadol Example Calculation 
       [0062]      
         [0000]    
       
         
               
             
               
               
               
             
           
               
                 TABLE 19 
               
               
                   
               
               
                 Tramadol pharmacokinetic parameters. 
               
               
                 Tramadol 
               
               
                   
               
             
             
               
                   
               
             
          
           
               
                   
                 Clearance (L × hr −1  × kg −1 ) 
                 0.480 
               
               
                   
                 Volume of Distribution (L/kg) 
                 2.7 
               
               
                   
                 Fractional Bioavailability 
                 0.725 
               
               
                   
                 Fractional Rate Constant (hr −1 ); “k” 
                 0.178 
               
               
                   
                 Unbound Fraction (fp) 
                 0.80 
               
               
                   
                 pKa 
                 9.4 
               
               
                   
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
               
               
             
               
               
               
               
               
             
           
               
                 TABLE 20 
               
             
             
               
                   
               
               
                 Donor information. 
               
             
          
           
               
                   
                 Salivary  
                   
                 Dosing  
                   
               
               
                 Donor 
                 pH (pHs) 
                 Dose (mg) 
                 Frequency (hr) 
                 Weight (kg) 
               
               
                   
               
             
          
           
               
                 0673 
                 6.8 
                 50 
                 6 
                 105.782 
               
               
                 0604 
                 5.5 
                 50 
                 8 
                 81.720 
               
               
                 0442 
                 5.8 
                 100 
                 8 
                 89.890 
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
             
           
               
                 TABLE 21 
               
             
             
               
                   
               
               
                 Donor calculations. 
               
             
          
           
               
                   
                 Donor Clearance (L/hr) 
                   
               
               
                   
                 Donor Clearance (L/hr) = 
                 DV d  (L) 
               
               
                   
                 Drug Clearance (L × hr −1  × kg −1 ) × 
                 DV d  (L) = V d  (L) × Donor 
               
               
                 Donor 
                 Donor Weight (kg) 
                 Weight (kg) 
               
               
                   
               
               
                 0673 
                 = 0.480 × 105.782 
                 = 2.7 × 105.782 
               
               
                   
                 = 50.775 L/hr 
                 = 285.6 L 
               
               
                 0604 
                 = 0.480 × 81.72 
                 = 2.7 × 81.720 
               
               
                   
                 = 39.226 L/hr 
                 = 220.6 L 
               
               
                 0442 
                 = 0.480 × 89.89 
                 = 2.7 × 89.890 
               
               
                   
                 = 43.148 L/hr 
                 = 242.7 L 
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
             
           
               
                 TABLE 22 
               
             
             
               
                   
               
               
                 Calculated steady state maximum plasma tramadol concentration. 
               
               
                 
                   
                     
                       
                         
                           
                             C 
                             ss 
                           
                            
                           max 
                         
                         = 
                         
                           
                             
                               F 
                               × 
                               
                                 dose 
                                 / 
                                 1 
                               
                             
                             - 
                             
                               e 
                               
                                 - 
                                 kt 
                               
                             
                           
                           
                             DV 
                             d 
                           
                         
                       
                     
                   
                 
               
               
                   
               
             
          
           
               
                 Donor 0673 
                 Donor 0604 
                 Donor 0442 
               
               
                   
               
               
                 
                   
                     
                       
                         = 
                         
                           
                             
                               
                                 0.725 
                                 × 
                                 
                                   50 
                                   / 
                                   1 
                                 
                               
                               - 
                               
                                 e 
                                 
                                   - 
                                   
                                     ( 
                                     
                                       0.178 
                                       × 
                                       6 
                                     
                                     ) 
                                   
                                 
                               
                             
                             285.6 
                           
                            
                           
                             
 
                           
                           = 
                           
                             193.3 
                              
                             
                                 
                             
                              
                             ng 
                              
                             
                               / 
                             
                              
                             mL 
                           
                         
                       
                     
                   
                 
                 
                   
                     
                       
                         = 
                         
                           
                             
                               
                                 0.725 
                                 × 
                                 
                                   50 
                                   / 
                                   1 
                                 
                               
                               - 
                               
                                 e 
                                 
                                   - 
                                   
                                     ( 
                                     
                                       0.178 
                                       × 
                                       8 
                                     
                                     ) 
                                   
                                 
                               
                             
                             220.6 
                           
                            
                           
                             
 
                           
                           = 
                           
                             216.6 
                              
                             
                                 
                             
                              
                             ng 
                              
                             
                               / 
                             
                              
                             mL 
                           
                         
                       
                     
                   
                 
                 
                   
                     
                       
                         = 
                         
                           
                             
                               
                                 0.725 
                                 × 
                                 
                                   100 
                                   / 
                                   1 
                                 
                               
                               - 
                               
                                 e 
                                 
                                   - 
                                   
                                     ( 
                                     
                                       0.178 
                                       × 
                                       8 
                                     
                                     ) 
                                   
                                 
                               
                             
                             242.7 
                           
                            
                           
                             
 
                           
                           = 
                           
                             393.4 
                              
                             
                                 
                             
                              
                             
                               ng 
                               / 
                               mL 
                             
                           
                         
                       
                     
                   
                 
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
             
           
               
                 TABLE 23 
               
             
             
               
                   
               
               
                 Calculated steady state minimum plasma tramadol concentration. 
               
               
                 C ss  min = C ss  max × e −kt   
               
             
          
           
               
                 Donor 0673 
                 Donor 0604 
                 Donor 0442 
               
               
                   
               
               
                 = 193.387 × e −(0.178×6)   
                 = 216.387 × e −(0.178×8)   
                 = 393.430 × 
               
               
                   
                   
                 e −(0.178×8)   
               
               
                 = 66.4 ng/mL 
                 = 52.0 ng/mL 
                 = 94.7 ng/mL 
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
             
           
               
                 TABLE 24 
               
             
             
               
                   
               
               
                 Calculated saliva to plasma tramadol concentration ratio calculation. 
               
               
                 
                   
                     
                       
                         
                           S 
                            
                           
                             / 
                           
                            
                           P 
                         
                         = 
                         
                           
                             1 
                             + 
                             
                               
                                 10 
                                 
                                   ( 
                                   
                                     pKa 
                                     - 
                                     pHs 
                                   
                                   ) 
                                 
                               
                               × 
                               fp 
                             
                           
                           
                             1 
                             + 
                             
                               
                                 10 
                                 
                                   ( 
                                   
                                     pKa 
                                     - 
                                     pHp 
                                   
                                   ) 
                                 
                               
                               × 
                               fs 
                             
                           
                         
                       
                     
                   
                 
               
               
                   
               
             
          
           
               
                 Donor 0673 
                 Donor 0604 
                 Donor 0442 
               
               
                   
               
               
                 
                   
                     
                       
                         = 
                         
                           
                             
                               1 
                               + 
                               
                                 
                                   10 
                                   
                                     ( 
                                     
                                       9.4 
                                       - 
                                       6.8 
                                     
                                     ) 
                                   
                                 
                                 × 
                                 0.80 
                               
                             
                             
                               1 
                               + 
                               
                                 
                                   10 
                                   
                                     ( 
                                     
                                       9.4 
                                       - 
                                       7.4 
                                     
                                     ) 
                                   
                                 
                                 × 
                                 1 
                               
                             
                           
                            
                           
                             
 
                           
                           = 
                           3.1 
                         
                       
                     
                   
                 
                 
                   
                     
                       
                         = 
                         
                           
                             
                               1 
                               + 
                               
                                 
                                   10 
                                   
                                     ( 
                                     
                                       9.4 
                                       - 
                                       5.5 
                                     
                                     ) 
                                   
                                 
                                 × 
                                 0.80 
                               
                             
                             
                               1 
                               + 
                               
                                 
                                   10 
                                   
                                     ( 
                                     
                                       9.4 
                                       - 
                                       7.4 
                                     
                                     ) 
                                   
                                 
                                 × 
                                 1 
                               
                             
                           
                            
                           
                             
 
                           
                           = 
                           62.9 
                         
                       
                     
                   
                 
                 
                   
                     
                       
                         = 
                         
                           
                             
                               1 
                               + 
                               
                                 
                                   10 
                                   
                                     ( 
                                     
                                       9.4 
                                       - 
                                       5.8 
                                     
                                     ) 
                                   
                                 
                                 × 
                                 0.80 
                               
                             
                             
                               1 
                               + 
                               
                                 
                                   10 
                                   
                                     ( 
                                     
                                       9.4 
                                       - 
                                       7.4 
                                     
                                     ) 
                                   
                                 
                                 × 
                                 1 
                               
                             
                           
                            
                           
                             
 
                           
                           = 
                           31.5 
                         
                       
                     
                   
                 
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
             
               
               
               
             
           
               
                 TABLE 25 
               
             
             
               
                   
               
               
                 Tramadol LC-MS/MS quantitation. 
               
             
          
           
               
                   
                 Measured Saliva Tramadol  
                 Measured Plasma Tramadol 
               
               
                 Donor 
                 Concentration (ng/mL) 
                 Concentration (ng/mL) 
               
               
                   
               
             
          
           
               
                 0673 
                 375.6 
                 104.1 
               
               
                 0604 
                 29926.5 
                 376.6 
               
               
                 0442 
                 1302.5 
                 70.4 
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
             
           
               
                 TABLE 26 
               
             
             
               
                   
               
               
                 Oral fluid plasma equivalent calculation. 
               
               
                 
                   
                     
                       
                         
                           
                             
                               
                                 
                                   Oral 
                                    
                                   
                                       
                                   
                                    
                                   fluid 
                                    
                                   
                                       
                                   
                                    
                                   plasma 
                                 
                                  
                                 
                                     
                                 
                               
                             
                           
                           
                             
                               
                                 equivalent 
                                  
                                 
                                     
                                 
                                  
                                 
                                   ( 
                                   
                                     ng 
                                      
                                     
                                       / 
                                     
                                      
                                     mL 
                                   
                                   ) 
                                 
                               
                             
                           
                         
                         = 
                         
                           
                             
                               
                                 
                                   Measured 
                                    
                                   
                                       
                                   
                                    
                                   oral 
                                    
                                   
                                       
                                   
                                    
                                   fluid 
                                 
                               
                             
                             
                               
                                 
                                   drug 
                                    
                                   
                                       
                                   
                                    
                                   concentration 
                                    
                                   
                                       
                                   
                                    
                                   
                                     ( 
                                     
                                       ng 
                                        
                                       
                                         / 
                                       
                                        
                                       mL 
                                     
                                     ) 
                                   
                                 
                               
                             
                           
                           
                             Calculated 
                              
                             
                                 
                             
                              
                             S 
                              
                             
                               / 
                             
                              
                             P 
                           
                         
                       
                     
                   
                 
               
               
                   
               
             
          
           
               
                 Donor 0673 
                 Donor 0604 
                 Donor 0442 
               
               
                   
               
               
                 
                   
                     
                       
                         = 
                         
                           
                             375.6 
                             3.1 
                           
                            
                           
                             
 
                           
                           = 
                           
                             118.7 
                              
                             
                                 
                             
                              
                             ng 
                              
                             
                               / 
                             
                              
                             mL 
                           
                         
                       
                     
                   
                 
                 
                   
                     
                       
                         = 
                         
                           
                             29926.5 
                             62.9 
                           
                            
                           
                             
 
                           
                           = 
                           
                             475.5 
                              
                             
                                 
                             
                              
                             ng 
                              
                             
                               / 
                             
                              
                             mL 
                           
                         
                       
                     
                   
                 
                 
                   
                     
                       
                         = 
                         
                           
                             1302.5 
                             31.5 
                           
                            
                           
                             
 
                           
                           = 
                           
                             41.2 
                              
                             
                                 
                             
                              
                             ng 
                              
                             
                               / 
                             
                              
                             mL 
                           
                         
                       
                     
                   
                 
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
               
               
               
               
               
             
               
               
               
               
               
               
               
               
             
           
               
                 TABLE 27 
               
             
             
               
                   
               
               
                 Compliance analysis. 
               
             
          
           
               
                   
                   
                   
                 Meas- 
                   
                 Tram- 
                   
                   
               
               
                   
                   
                   
                 ured 
                   
                 adol 
                   
                   
               
               
                   
                   
                   
                 Tram- 
                   
                 Oral  
                   
                   
               
               
                   
                   
                   
                 adol 
                   
                 Fluid 
                   
                 Agree- 
               
               
                   
                   
                   
                 Plasma 
                   
                 Plasma 
                   
                 ment 
               
               
                   
                   
                   
                 Concen- 
                   
                 Equiv- 
                   
                 in 
               
               
                   
                 C ss  max 
                 C ss  min 
                 tration 
                 Com- 
                 alent 
                 Com- 
                 Com- 
               
               
                 Donor  
                 (ng/mL) 
                 (ng/mL) 
                 (ng/mL) 
                 pliance  
                 (ng/mL) 
                 pliance  
                 pliance 
               
               
                   
               
             
          
           
               
                 0673 
                 193.3 
                 66.4 
                 104.1 
                 Within 
                 118.7 
                 Within 
                 Agree 
               
               
                 0604 
                 216.3 
                 52.0 
                 376.6 
                 Above 
                 475.5 
                 Above 
                 Agree 
               
               
                 0442 
                 393.4 
                 94.7 
                 70.4 
                 Below 
                 41.2 
                 Below 
                 Agree 
               
               
                   
               
             
          
         
       
       
      
      
      
     
         [0063]    *Expected steady state plasma drug range is calculated based on dosing regimen provided by donor. Maximum steady state concentrations may fall outside therapeutic ranges and approach and/or exceed toxic ranges due to drug tolerance. 
       Determination of Minimum Dosage Consumed Based on Oral Fluid Plasma Equivalent 
       [0064]    Once oral fluid plasma equivalent is calculated based on the quantitated oral fluid drug concentration by Eq.  8 , assessment of the minimum dosage of a drug required to produce a corresponding oral fluid drug concentration is calculated. 
         [0000]    
       
         
           
             
               
                 
                   
                     
                       Determination 
                        
                       
                           
                       
                        
                       of 
                        
                       
                           
                       
                        
                       minimum 
                        
                       
                           
                       
                        
                       dosage 
                        
                       
                           
                       
                        
                       consumed 
                        
                       
                           
                       
                        
                       based 
                        
                       
                           
                       
                        
                       on 
                        
                       
                           
                       
                        
                       oral 
                        
                       
                           
                       
                        
                       fluid 
                        
                       
                           
                       
                        
                       plasma 
                        
                       
                           
                       
                        
                       
                         equivalent 
                         . 
                         
                           
 
                         
                          
                         
                             
                         
                          
                         
                           D 
                           o 
                         
                       
                     
                     = 
                     
                       
                         [ 
                         
                           
                             ( 
                             
                               DV 
                               d 
                             
                             ) 
                           
                           × 
                           C 
                           × 
                           
                             ( 
                             
                               
                                 K 
                                 a 
                               
                               - 
                               
                                 K 
                                 el 
                               
                             
                             ) 
                           
                         
                         ] 
                       
                       
                         F 
                         × 
                         
                           
                             K 
                             a 
                           
                            
                           
                             ( 
                             
                               
                                  
                                 
                                   
                                     - 
                                     Kel 
                                   
                                   × 
                                   t 
                                 
                               
                               - 
                               
                                  
                                 
                                   
                                     - 
                                     Ka 
                                   
                                   × 
                                   t 
                                 
                               
                             
                             ) 
                           
                         
                       
                     
                   
                    
                   
                     
 
                   
                    
                   
                     
                       D 
                       0 
                     
                     = 
                     
                       Original 
                        
                       
                           
                       
                        
                       dose 
                        
                       
                           
                       
                        
                       taken 
                        
                       
                           
                       
                        
                       
                         ( 
                         mg 
                         ) 
                       
                     
                   
                    
                   
                     
 
                   
                    
                   
                     
                       DV 
                       d 
                     
                     = 
                     
                         
                     
                      
                     
                       Volume 
                        
                       
                           
                       
                        
                       of 
                        
                       
                           
                       
                        
                       distribution 
                        
                       
                           
                       
                        
                       of 
                        
                       
                           
                       
                        
                       donor 
                        
                       
                           
                       
                        
                       
                         ( 
                         mL 
                         ) 
                       
                        
                       
                           
                       
                        
                       
                         ( 
                         
                           reference 
                            
                           
                               
                           
                            
                           
                             Eq 
                             . 
                             
                                 
                             
                              
                             2 
                           
                         
                         ) 
                       
                     
                   
                    
                   
                     
 
                   
                    
                   
                     C 
                     = 
                     
                       
                         Plasma 
                          
                         
                             
                         
                          
                         drug 
                          
                         
                             
                         
                          
                         concentration 
                          
                         
                             
                         
                          
                         
                           ( 
                           
                             mg 
                              
                             
                               / 
                             
                              
                             mL 
                           
                           ) 
                         
                          
                         
                           
 
                         
                          
                         
                           K 
                           a 
                         
                       
                       = 
                       
                         
                           Absorption 
                            
                           
                               
                           
                            
                           constant 
                            
                           
                               
                           
                            
                           of 
                            
                           
                               
                           
                            
                           drug 
                            
                           
                               
                           
                            
                           
                             ( 
                             
                               referenced 
                                
                               
                                   
                               
                                
                               in 
                                
                               
                                   
                               
                                
                               literature 
                             
                             ) 
                           
                            
                           
                              
                           
                            
                           
                             K 
                             el 
                           
                         
                         = 
                         
                             
                         
                          
                         
                           Elimination 
                            
                           
                               
                           
                            
                           constant 
                            
                           
                               
                           
                            
                           of 
                            
                           
                               
                           
                            
                           drug 
                         
                       
                     
                   
                    
                   
                       
                   
                    
                   
                     
 
                   
                    
                   
                       
                   
                    
                   
                     ( 
                     
                       referenced 
                        
                       
                           
                       
                        
                       in 
                        
                       
                           
                       
                        
                       literature 
                     
                     ) 
                   
                    
                   
                      
                   
                    
                   
                     F 
                     = 
                     
                       Fractional 
                        
                       
                           
                       
                        
                       bioavailability 
                        
                       
                           
                       
                        
                       of 
                        
                       
                           
                       
                        
                       drug 
                        
                       
                           
                       
                        
                       
                         ( 
                         
                           referenced 
                            
                           
                               
                           
                            
                           in 
                            
                           
                               
                           
                            
                           literature 
                         
                         ) 
                       
                     
                   
                    
                   
                     
 
                   
                    
                   
                     t 
                     = 
                     
                       Elapsed 
                        
                       
                           
                       
                        
                       time 
                        
                       
                           
                       
                        
                       between 
                        
                       
                           
                       
                        
                       dosage 
                        
                       
                           
                       
                        
                       and 
                        
                       
                           
                       
                        
                       specimen 
                        
                       
                           
                       
                        
                       collection 
                        
                       
                           
                       
                        
                       
                         ( 
                         hr 
                         ) 
                       
                     
                   
                 
               
               
                 
                   Eq 
                   . 
                   
                       
                   
                    
                   9 
                 
               
             
           
         
       
     
       Example Supporting Minimum Dose Consumed Calculation Above in Proof of Concept Study 
     Oxycodone Example Calculation 
       [0065]      
         [0000]    
       
         
               
             
               
               
               
             
           
               
                 TABLE 28 
               
               
                   
               
               
                 Oxycodone pharmacokinetic parameters. 
               
               
                 Oxycodone 
               
               
                   
               
             
             
               
                   
               
             
          
           
               
                   
                 Volume of Distribution (mL/kg) 
                 2000 
               
               
                   
                 K a  (hr −1 ) 
                 3.5 
               
               
                   
                 K el  (hr −1 ) 
                 0.174 
               
               
                   
                 Fractional Bioavailability 
                 0.735 
               
               
                   
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
             
           
               
                 TABLE 29 
               
               
                   
               
               
                 Donor information. 
               
               
                 Donor 0565 
               
               
                   
               
             
             
               
                   
               
             
          
           
               
                   
                 Salivary pH (pH S ) 
                 6.4 
               
               
                   
                 Weight (kg) 
                 118.040 
               
               
                   
                 Measured Oral Fluid  
                 217.1 
               
               
                   
                 Concentration (ng/mL) 
               
               
                   
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
               
               
               
               
             
           
               
                 TABLE 30 
               
             
             
               
                   
               
               
                 Donor compliance analysis. 
               
             
          
           
               
                   
                   
                 Measured 
                   
                 Oral  
                   
                   
               
               
                   
                   
                 Oxycodone 
                   
                 Fluid 
                   
                 Agree- 
               
               
                   
                   
                 Plasma 
                   
                 Plasma 
                   
                 ment 
               
               
                   
                   
                 Concen- 
                   
                 Equiv- 
                   
                 in 
               
               
                 C ss  max 
                 C ss  min 
                 tration 
                 Com- 
                 alent 
                 Com- 
                 Com- 
               
               
                 (ng/mL) 
                 (ng/mL) 
                 (ng/mL) 
                 pliance  
                 (ng/mL) 
                 pliance  
                 pliance 
               
               
                   
               
               
                 32.8 
                 1.6 
                 33.7 
                 Above 
                 42.0 
                 Above 
                 Agree 
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
             
           
               
                 TABLE 31 
               
               
                   
               
               
                 Parameters for determination of minimum dosage  
               
               
                 consumed based on measured plasma drug concentration. 
               
               
                 Donor 0565 
               
               
                   
               
             
             
               
                   
               
             
          
           
               
                   
                 Measured Plasma Concentration (ng/mL) 
                 33.7 
               
               
                   
                 Time Last Dose Taken 
                 13:00 
               
               
                   
                 Time of Blood Collection 
                 14:23 
               
               
                   
                 Time Elapsed Between Last Dose  
                 1.383 
               
               
                   
                 Taken and Blood Collection (hr) 
                   
               
               
                   
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
             
           
               
                 TABLE 32 
               
               
                   
               
               
                 Determination of minimum dosage consumed  
               
               
                 based on calculated plasma drug concentration. 
               
               
                 Donor 0565 
               
               
                   
               
             
             
               
                   
               
             
          
           
               
                 Calculated Plasma Concentration (ng/mL)  
                 42.0 ng/mL (reference Eq. 8) 
               
               
                 Time Last Dose Taken 
                 13:00 
               
               
                 Time of Oral Fluid Collection 
                 14:20 
               
               
                 Time Elapsed Between Last Dose  
                 1.333 
               
               
                 Taken and Oral Fluid Collection (hr) 
                   
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
             
           
               
                 TABLE 33 
               
             
             
               
                   
               
               
                 Determination of minimum dosage consumed based on plasma drug concentration. 
               
             
          
           
               
                 Measured Plasma Concentration 
                 Oral Fluid Plasma Equivalent 
               
               
                   
               
               
                 
                   
                     
                       
                         
                           D 
                           o 
                         
                         = 
                         
                           
                             [ 
                             
                               
                                 ( 
                                 
                                   DV 
                                   d 
                                 
                                 ) 
                               
                               × 
                               C 
                               × 
                               
                                 ( 
                                 
                                   
                                     K 
                                     a 
                                   
                                   - 
                                   
                                     K 
                                     el 
                                   
                                 
                                 ) 
                               
                             
                             ] 
                           
                           
                             F 
                             × 
                             
                               
                                 K 
                                 a 
                               
                                
                               
                                 ( 
                                 
                                   
                                     e 
                                     
                                       
                                         - 
                                         Kel 
                                       
                                       × 
                                       t 
                                     
                                   
                                   - 
                                   
                                     e 
                                     
                                       
                                         - 
                                         Ka 
                                       
                                       × 
                                       t 
                                     
                                   
                                 
                                 ) 
                               
                             
                           
                         
                       
                     
                   
                 
                 
                   
                     
                       
                         
                           D 
                           o 
                         
                         = 
                         
                           
                             [ 
                             
                               
                                 ( 
                                 
                                   DV 
                                   d 
                                 
                                 ) 
                               
                               × 
                               C 
                               × 
                               
                                 ( 
                                 
                                   
                                     K 
                                     a 
                                   
                                   - 
                                   
                                     K 
                                     el 
                                   
                                 
                                 ) 
                               
                             
                             ] 
                           
                           
                             F 
                             × 
                             
                               
                                 K 
                                 a 
                               
                                
                               
                                 ( 
                                 
                                   
                                     e 
                                     
                                       
                                         - 
                                         Kel 
                                       
                                       × 
                                       t 
                                     
                                   
                                   - 
                                   
                                     e 
                                     
                                       
                                         - 
                                         Ka 
                                       
                                       × 
                                       t 
                                     
                                   
                                 
                                 ) 
                               
                             
                           
                         
                       
                     
                   
                 
               
               
                   
               
               
                 
                   
                     
                       
                         = 
                         
                           
                             
                               
                                 
                                   
                                     [ 
                                     
                                       
                                         ( 
                                         
                                           2000 
                                            
                                           
                                               
                                           
                                            
                                           mL 
                                            
                                           
                                             / 
                                           
                                            
                                           kg 
                                           × 
                                           118.040 
                                            
                                           
                                               
                                           
                                            
                                           kg 
                                         
                                         ) 
                                       
                                       × 
                                     
                                   
                                 
                               
                               
                                 
                                   
                                     
                                       
                                         ( 
                                         
                                           33.7 
                                            
                                           
                                               
                                           
                                            
                                           ng 
                                            
                                           
                                             / 
                                           
                                            
                                           mL 
                                           × 
                                           1 
                                           × 
                                           
                                             10 
                                             
                                               - 
                                               6 
                                             
                                           
                                            
                                           ng 
                                         
                                         ) 
                                       
                                       × 
                                       
                                         ( 
                                         
                                           3.5 
                                           - 
                                           0.174 
                                         
                                         ) 
                                       
                                     
                                     ] 
                                   
                                 
                               
                             
                             
                               0.735 
                               × 
                               3.5 
                                
                               
                                 ( 
                                 
                                   
                                     e 
                                     
                                       
                                         - 
                                         0.174 
                                       
                                       × 
                                       1.383 
                                     
                                   
                                   - 
                                   
                                     e 
                                     
                                       
                                         - 
                                         3.5 
                                       
                                       × 
                                       1.383 
                                     
                                   
                                 
                                 ) 
                               
                             
                           
                            
                           
                             
 
                           
                           = 
                           
                             13.2 
                              
                             
                                 
                             
                              
                             mg 
                           
                         
                       
                     
                   
                 
                 
                   
                     
                       
                         = 
                         
                           
                             
                               
                                 
                                   
                                     [ 
                                     
                                       
                                         ( 
                                         
                                           2000 
                                            
                                           
                                               
                                           
                                            
                                           mL 
                                            
                                           
                                             / 
                                           
                                            
                                           kg 
                                           × 
                                           118.040 
                                            
                                           
                                               
                                           
                                            
                                           kg 
                                         
                                         ) 
                                       
                                       × 
                                     
                                   
                                 
                               
                               
                                 
                                   
                                     
                                       
                                         ( 
                                         
                                           42.0 
                                            
                                           
                                               
                                           
                                            
                                           ng 
                                            
                                           
                                             / 
                                           
                                            
                                           mL 
                                           × 
                                           1 
                                           × 
                                           
                                             10 
                                             
                                               - 
                                               6 
                                             
                                           
                                            
                                           ng 
                                         
                                         ) 
                                       
                                       × 
                                       
                                         ( 
                                         
                                           3.5 
                                           - 
                                           0.174 
                                         
                                         ) 
                                       
                                     
                                     ] 
                                   
                                 
                               
                             
                             
                               0.735 
                               × 
                               3.5 
                                
                               
                                 ( 
                                 
                                   
                                     e 
                                     
                                       
                                         - 
                                         0.174 
                                       
                                       × 
                                       1.383 
                                     
                                   
                                   - 
                                   
                                     e 
                                     
                                       
                                         - 
                                         3.5 
                                       
                                       × 
                                       1.383 
                                     
                                   
                                 
                                 ) 
                               
                             
                           
                            
                           
                             
 
                           
                           = 
                           
                             16.3 
                              
                             
                                 
                             
                              
                             mg 
                           
                         
                       
                     
                   
                 
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
               
               
               
             
           
               
                 TABLE 34 
               
             
             
               
                   
               
               
                 Comparison to dosage provided by donor. 
               
             
          
           
               
                   
                 Minimum  
                   
                 Minimum  
                   
                   
               
               
                   
                 Dosage 
                   
                 Dosage 
                   
                   
               
               
                   
                 Consumed  
                   
                 Consumed  
                   
                   
               
               
                   
                 Based on 
                   
                 Based on 
                   
                   
               
               
                 Dose 
                 Measured  
                   
                 Oral Fluid  
                   
                   
               
               
                 Taken 
                 Plasma 
                   
                 Plasma  
                   
                 Agreement  
               
               
                 Provided 
                 Concen- 
                 Com- 
                 Equivalent  
                 Com- 
                 in 
               
               
                 (mg) 
                 tration (mg) 
                 pliance 
                 (mg) 
                 pliance 
                 Compliance 
               
               
                   
               
               
                 10 
                 13.2 
                 Above 
                 16.3 
                 Above 
                 Agree 
               
               
                   
               
             
          
         
       
     
       Example Supporting Minimum Dose Consumed Calculation Above in Proof of Concept Study 
     Hydrocodone Example Calculation 
       [0066]      
         [0000]    
       
         
               
             
               
               
               
             
           
               
                 TABLE 35 
               
               
                   
               
               
                 Hydrocodone pharmacokinetic parameters. 
               
               
                 Hydrocodone 
               
               
                   
               
             
             
               
                   
               
             
          
           
               
                   
                 Volume of Distribution (mL/kg) 
                 4000 
               
               
                   
                 K a  (hr −1 ) 
                 2.8 
               
               
                   
                 K el  (hr −1 ) 
                 0.141 
               
               
                   
                 Fractional Bioavailability 
                 0.7 
               
               
                   
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
             
           
               
                 TABLE 36 
               
               
                   
               
               
                 Donor information. 
               
               
                 Donor 0476 
               
               
                   
               
             
             
               
                   
               
             
          
           
               
                   
                 Salivary pH (pH S ) 
                 7.2 
               
               
                   
                 Weight (kg) 
                 84.898 
               
               
                   
                 Measured Oral Fluid Concentration (ng/mL) 
                 4.5 
               
               
                   
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
               
               
               
               
             
           
               
                 TABLE 37 
               
             
             
               
                   
               
               
                 Donor compliance analysis. 
               
             
          
           
               
                   
                   
                 Measured 
                   
                 Oral  
                   
                   
               
               
                   
                   
                 Oxycodone 
                   
                 Fluid 
                   
                 Agree- 
               
               
                   
                   
                 Plasma 
                   
                 Plasma 
                   
                 ment 
               
               
                   
                   
                 Concen- 
                   
                 Equiv- 
                   
                 in 
               
               
                 C ss  max 
                 C ss  min 
                 tration 
                 Com- 
                 alent 
                 Com- 
                 Com- 
               
               
                 (ng/mL) 
                 (ng/mL) 
                 (ng/mL) 
                 pliance  
                 (ng/mL) 
                 pliance  
                 pliance 
               
               
                   
               
               
                 23.7 
                 8.2 
                 3.2 
                 Below 
                 4.5 
                 Below 
                 Agree 
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
             
           
               
                 TABLE 38 
               
               
                   
               
               
                 Parameters for determination of minimum dosage  
               
               
                 consumed based on measured plasma drug concentration. 
               
               
                 Donor 0476 
               
               
                   
               
             
             
               
                   
               
             
          
           
               
                   
                 Measured Plasma Concentration (ng/mL) 
                 3.2 
               
               
                   
                 Time Last Dose Taken 
                 07:00 
               
               
                   
                 Time of Blood Collection 
                 13:03 
               
               
                   
                 Time Elapsed Between Last Dose  
                 6.050 
               
               
                   
                 Taken and Blood Collection (hr) 
                   
               
               
                   
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
             
           
               
                 TABLE 39 
               
               
                   
               
               
                 Determination of minimum dosage consumed  
               
               
                 based on oral fluid plasma equivalent. 
               
               
                 Donor 0476 
               
               
                   
               
             
             
               
                   
               
             
          
           
               
                 Oral Fluid Plasma Equivalent (ng/mL) 
                 4.5 ng/mL (reference Eq. 8) 
               
               
                 Time Last Dose Taken 
                 07:00 
               
               
                 Time of Oral Fluid Collection 
                 12:50 
               
               
                 Time Elapsed Between Last Dose  
                 5.833 
               
               
                 Taken and Oral Fluid Collection (hr) 
                   
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
             
           
               
                 TABLE 40 
               
             
             
               
                   
               
               
                 Determination of minimum dosage consumed based on plasma drug concentration. 
               
             
          
           
               
                 Measured Plasma Concentration 
                 Oral Fluid Plasma Equivalent 
               
               
                   
               
               
                 
                   
                     
                       
                         
                           D 
                           o 
                         
                         = 
                         
                           
                             [ 
                             
                               
                                 ( 
                                 
                                   DV 
                                   d 
                                 
                                 ) 
                               
                               × 
                               C 
                               × 
                               
                                 ( 
                                 
                                   
                                     K 
                                     a 
                                   
                                   - 
                                   
                                     K 
                                     el 
                                   
                                 
                                 ) 
                               
                             
                             ] 
                           
                           
                             F 
                             × 
                             
                               
                                 K 
                                 a 
                               
                                
                               
                                 ( 
                                 
                                   
                                     e 
                                     
                                       
                                         - 
                                         Kel 
                                       
                                       × 
                                       t 
                                     
                                   
                                   - 
                                   
                                     e 
                                     
                                       
                                         - 
                                         Ka 
                                       
                                       × 
                                       t 
                                     
                                   
                                 
                                 ) 
                               
                             
                           
                         
                       
                     
                   
                 
                 
                   
                     
                       
                         
                           D 
                           o 
                         
                         = 
                         
                           
                             [ 
                             
                               
                                 ( 
                                 
                                   DV 
                                   d 
                                 
                                 ) 
                               
                               × 
                               C 
                               × 
                               
                                 ( 
                                 
                                   
                                     K 
                                     a 
                                   
                                   - 
                                   
                                     K 
                                     el 
                                   
                                 
                                 ) 
                               
                             
                             ] 
                           
                           
                             F 
                             × 
                             
                               
                                 K 
                                 a 
                               
                                
                               
                                 ( 
                                 
                                   
                                     e 
                                     
                                       
                                         - 
                                         Kel 
                                       
                                       × 
                                       t 
                                     
                                   
                                   - 
                                   
                                     e 
                                     
                                       
                                         - 
                                         Ka 
                                       
                                       × 
                                       t 
                                     
                                   
                                 
                                 ) 
                               
                             
                           
                         
                       
                     
                   
                 
               
               
                   
               
               
                 
                   
                     
                       
                         = 
                         
                           
                             
                               
                                 
                                   
                                     [ 
                                     
                                       
                                         ( 
                                         
                                           4000 
                                            
                                           
                                               
                                           
                                            
                                           mL 
                                            
                                           
                                             / 
                                           
                                            
                                           kg 
                                           × 
                                           84.898 
                                            
                                           
                                               
                                           
                                            
                                           kg 
                                         
                                         ) 
                                       
                                       × 
                                       
                                         ( 
                                         
                                           3.2 
                                            
                                           
                                               
                                           
                                            
                                           ng 
                                            
                                           
                                             / 
                                           
                                            
                                           mL 
                                           × 
                                         
                                          
                                         
                                             
                                         
                                       
                                     
                                   
                                 
                               
                               
                                 
                                   
                                     
                                       
                                         
                                           1 
                                           × 
                                           
                                             10 
                                             
                                               - 
                                               6 
                                             
                                           
                                            
                                           ng 
                                         
                                         ) 
                                       
                                       × 
                                       
                                         ( 
                                         
                                           2.8 
                                           - 
                                           0.141 
                                         
                                         ) 
                                       
                                     
                                     ] 
                                   
                                 
                               
                             
                             
                               0.7 
                               × 
                               2.8 
                                
                               
                                 ( 
                                 
                                   
                                     e 
                                     
                                       
                                         - 
                                         0.141 
                                       
                                       × 
                                       6.050 
                                     
                                   
                                   - 
                                   
                                     e 
                                     
                                       
                                         - 
                                         2.8 
                                       
                                       × 
                                       6.050 
                                     
                                   
                                 
                                 ) 
                               
                             
                           
                            
                           
                             
 
                           
                           = 
                           
                             3.5 
                              
                             
                                 
                             
                              
                             mg 
                           
                         
                       
                     
                   
                 
                 
                   
                     
                       
                         = 
                         
                           
                             
                               
                                 
                                   
                                     [ 
                                     
                                       
                                         ( 
                                         
                                           4000 
                                            
                                           
                                               
                                           
                                            
                                           mL 
                                            
                                           
                                             / 
                                           
                                            
                                           kg 
                                           × 
                                           84.898 
                                            
                                           
                                               
                                           
                                            
                                           kg 
                                         
                                         ) 
                                       
                                       × 
                                       
                                         ( 
                                         
                                           4.5 
                                            
                                           
                                               
                                           
                                            
                                           ng 
                                            
                                           
                                             / 
                                           
                                            
                                           mL 
                                           × 
                                         
                                          
                                         
                                             
                                         
                                       
                                     
                                   
                                 
                               
                               
                                 
                                   
                                     
                                       
                                         
                                           1 
                                           × 
                                           
                                             10 
                                             
                                               - 
                                               6 
                                             
                                           
                                            
                                           ng 
                                         
                                         ) 
                                       
                                       × 
                                       
                                         ( 
                                         
                                           2.8 
                                           - 
                                           0.141 
                                         
                                         ) 
                                       
                                     
                                     ] 
                                   
                                 
                               
                             
                             
                               0.7 
                               × 
                               2.8 
                                
                               
                                 ( 
                                 
                                   
                                     e 
                                     
                                       
                                         - 
                                         0.141 
                                       
                                       × 
                                       5.833 
                                     
                                   
                                   - 
                                   
                                     e 
                                     
                                       
                                         - 
                                         2.8 
                                       
                                       × 
                                       5.833 
                                     
                                   
                                 
                                 ) 
                               
                             
                           
                            
                           
                             
 
                           
                           = 
                           
                             4.4 
                              
                             
                                 
                             
                              
                             mg 
                           
                         
                       
                     
                   
                 
               
               
                   
               
             
          
         
       
     
         [0000]    
       
         
               
             
               
               
               
               
               
               
             
           
               
                 TABLE 41 
               
             
             
               
                   
               
               
                 Comparison to dosage provided by donor. 
               
             
          
           
               
                   
                 Minimum  
                   
                 Minimum  
                   
                   
               
               
                   
                 Dosage 
                   
                 Dosage 
                   
                   
               
               
                   
                 Consumed  
                   
                 Consumed  
                   
                   
               
               
                   
                 Based on 
                   
                 Based on 
                   
                   
               
               
                 Dose  
                 Measured  
                   
                 Oral Fluid 
                   
                   
               
               
                 Taken 
                 Plasma 
                   
                 Plasma  
                   
                 Agreement 
               
               
                 Provided 
                 Concen- 
                 Com- 
                 Equivalent  
                 Com- 
                 in 
               
               
                 (mg) 
                 tration (mg) 
                 pliance 
                 (mg) 
                 pliance 
                 Compliance 
               
               
                   
               
               
                 7.5 
                 3.5 
                 Below 
                 4.4 
                 Below 
                 Agree 
               
               
                   
               
             
          
         
       
     
         [0067]    Although the technology has been described in language that is specific to certain structures and materials, it is to be understood that the invention defined in the appended claims is not necessarily limited to the specific structures and materials described. Rather, the specific aspects are described as forms of implementing the claimed invention. Because many embodiments of the invention can be practiced without departing from the spirit and scope of the invention, the invention resides in the claims hereinafter appended. Unless otherwise indicated, all numbers or expressions, such as those expressing dimensions, physical characteristics, etc. used in the specification (other than the claims) are understood as modified in all instances by the term “approximately.” At the very least, and not as an attempt to limit the application of the doctrine of equivalents to the claims, each numerical parameter recited in the specification or claims which is modified by the term “approximately” should at least be construed in light of the number of recited significant digits and by applying ordinary rounding techniques. Moreover, all ranges disclosed herein are to be understood to encompass and provide support for claims that recite any and all subranges or any and all individual values subsumed therein. For example, a stated range of 1 to 10 should be considered to include and provide support for claims that recite any and all subranges or individual values that are between and/or inclusive of the minimum value of 1 and the maximum value of 10; that is, all subranges beginning with a minimum value of 1 or more and ending with a maximum value of 10 or less (e.g., 5.5 to 10, 2.34 to 3.56, and so forth) or any values from 1 to 10 (e.g., 3, 5.8, 9.9994, and so forth).