MU-NLPC/calcformer-t5-large
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math_qa__nwoNskhwavrdQAqt | The banker's gain of a certain sum due 3 years hence at 10% per annum is Rs. 36. What is the present worth ? Pick one:
A) rs . 400 B) rs . 300 C) rs . 500 D) rs . 350 E) none of these | <gadget id="calculator">36 * 100</gadget>
<output>3_600</output>
<gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">3_600 / 30</gadget>
<output>120</output>
<gadget id="calculator">100 * 120</gadget>
<output>12_000</output>
<gadget id="calculator">12_000 / 30</gadget>
<output>400</output>
<result>A</result> | A | 400 | The banker's gain of a certain sum due 3 years hence at 10% per annum is Rs. 36. What is the present worth ? | {
"A": "rs . 400",
"B": "rs . 300",
"C": "rs . 500",
"D": "rs . 350",
"E": "none of these"
} | divide(multiply(const_100, divide(multiply(36, const_100), multiply(3, 10))), multiply(3, 10)) | multiply(n2,const_100)|multiply(n0,n1)|divide(#0,#1)|multiply(#2,const_100)|divide(#3,#1)| | "explanation : t = 3 years r = 10 % td = ( bg × 100 ) / tr = ( 36 × 100 ) / ( 3 × 10 ) = 12 × 10 = rs . 120 td = ( pw × tr ) / 100 ⇒ 120 = ( pw × 3 × 10 ) / 100 ⇒ 1200 = pw × 3 pw = 1200 / 3 = rs . 400 answer : option a" | gain |
math_qa__sglkXZvNvCAEnqmm | Sophia finished 2/3 of a book. She calculated that she finished 90 more pages than she has yet to read. How long is her book? Answers.
A) 229 B) 270 C) 877 D) 266 E) 281 | <gadget id="calculator">2 / 3</gadget>
<output>2/3 = around 0.666667</output>
<gadget id="calculator">1 - (2/3)</gadget>
<output>1/3 = around 0.333333</output>
<gadget id="calculator">90 / (1/3)</gadget>
<output>270</output>
<result>B</result> | B | 270 | Sophia finished 2/3 of a book. She calculated that she finished 90 more pages than she has yet to read. How long is her book? | {
"A": "229",
"B": "270",
"C": "877",
"D": "266",
"E": "281"
} | divide(90, subtract(const_1, divide(2, 3))) | divide(n0,n1)|subtract(const_1,#0)|divide(n2,#1) | let xx be the total number of pages in the book , then she finished 23 ⋅ x 23 ⋅ x pages . then she has x − 23 ⋅ x = 13 ⋅ xx − 23 ⋅ x = 13 ⋅ x pages left . 23 ⋅ x − 13 ⋅ x = 9023 ⋅ x − 13 ⋅ x = 90 13 ⋅ x = 9013 ⋅ x = 90 x = 270 x = 270 so the book is 270 pages long . answer : b | general |
math_qa__G6aLBpX2cm4yc9bJ | 120 is what percent of 50 ? Choose the correct choice from the following options.
A) 5 % B) 240 % C) 50 % D) 2 % E) 500 % | <gadget id="calculator">120 / 50</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">(12/5) * 100</gadget>
<output>240</output>
<result>B</result> | B | 240 | 120 is what percent of 50 ? | {
"A": "5 %",
"B": "240 %",
"C": "50 %",
"D": "2 %",
"E": "500 %"
} | multiply(divide(120, 50), const_100) | divide(n0,n1)|multiply(#0,const_100)| | "50 * x = 120 - - > x = 2.4 - - > 2.4 expressed as percent is 240 % . answer : b ." | gain |
math_qa__ZMnHyfYaWveL6nzN | there are 10 girls and 20 boys in a classroom. what is the ratio of girls to boys? Pick.
A) 1 / 2 B) 1 / 3 C) 1 / 5 D) 10 / 30 E) 2 / 5 | <gadget id="calculator">10 / 20</gadget>
<output>1/2 = around 0.5</output>
<result>A</result> | A | 0.5 | there are 10 girls and 20 boys in a classroom. what is the ratio of girls to boys? | {
"A": "1 / 2",
"B": "1 / 3",
"C": "1 / 5",
"D": "10 / 30",
"E": "2 / 5"
} | divide(10, 20) | divide(n0,n1) | if girls is 10 and boys is 20 , then 10 / 20 . so ratio of girls to boys is = 10 / 20 = 1 / 2 answer : a | other |
math_qa__RXWCzgkVWmA98hLs | An empty fuel tank with a capacity of 218 gallons was filled partially with fuel A and then to capacity with fuel B. Fuel A contains 12% ethanol by volume and fuel B contains 16% ethanol by volume. If the full fuel tank contains 30 gallons of ethanol, how many gallons of fuel A were added? Choose the correct choice from the following options
A) 122
B) 150
C) 100
D) 80
E) 50 | <gadget id="calculator">16 / 100</gadget>
<output>4/25 = around 0.16</output>
<gadget id="calculator">218 * (4/25)</gadget>
<output>872/25 = around 34.88</output>
<gadget id="calculator">(872/25) - 30</gadget>
<output>122/25 = around 4.88</output>
<gadget id="calculator">12 / 100</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">(4/25) - (3/25)</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">(122/25) / (1/25)</gadget>
<output>122</output>
<result>A</result> | A | 122 | An empty fuel tank with a capacity of 218 gallons was filled partially with fuel A and then to capacity with fuel B. Fuel A contains 12% ethanol by volume and fuel B contains 16% ethanol by volume. If the full fuel tank contains 30 gallons of ethanol, how many gallons of fuel A were added? | {
"A": "122",
"B": "150",
"C": "100",
"D": "80",
"E": "50"
} | divide(subtract(multiply(218, divide(16, const_100)), 30), subtract(divide(16, const_100), divide(12, const_100))) | divide(n2,const_100)|divide(n1,const_100)|multiply(n0,#0)|subtract(#0,#1)|subtract(#2,n3)|divide(#4,#3)| | "say there are a gallons of fuel a in the tank , then there would be 218 - a gallons of fuel b . the amount of ethanol in a gallons of fuel a is 0.12 a ; the amount of ethanol in 218 - a gallons of fuel b is 0.16 ( 218 - a ) ; since the total amount of ethanol is 30 gallons then 0.12 a + 0.16 ( 218 - a ) = 30 - - > a = 122 . answer : a ." | gain |
math_qa__M9KorSSZUpJ49RbY | 6 workers should finish a job in 8 days. After 3 days came 4 workers join them. How many days M do they need to finish the same job? Options
A) 3
B) 4
C) 5
D) 6
E) 7 | <gadget id="calculator">6 * 8</gadget>
<output>48</output>
<gadget id="calculator">3 * 6</gadget>
<output>18</output>
<gadget id="calculator">48 - 18</gadget>
<output>30</output>
<gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">30 / 10</gadget>
<output>3</output>
<result>A</result> | A | 3 | 6 workers should finish a job in 8 days. After 3 days came 4 workers join them. How many days M do they need to finish the same job? | {
"A": "3",
"B": "4",
"C": "5",
"D": "6",
"E": "7"
} | divide(subtract(multiply(6, 8), multiply(3, 6)), add(6, 4)) | add(n0,n3)|multiply(n0,n1)|multiply(n0,n2)|subtract(#1,#2)|divide(#3,#0)| | "let rate of one worker be r = > ( 6 * r ) * 8 = 1 ( rate * time = work ) = > r = 1 / 48 = > work remaining after 3 days 1 - ( 3 * 6 ) / 48 = 30 / 48 after 4 ppl joined in ( ( 6 + 4 ) * time ) / 48 = 30 / 48 time m = 3 days to finish the task imo a" | physics |
math_qa__MN0QtgV87Hvvx2b6 | J is 25% less than P and 20% less than T. T is q% less than P. What is the value of q? Choose the most appropriate option:
A) 93.5
B) 90
C) 6.75
D) 6.25
E) 2 | <gadget id="calculator">25 * 25</gadget>
<output>625</output>
<gadget id="calculator">625 / 100</gadget>
<output>25/4 = around 6.25</output>
<result>D</result> | D | 6.25 | J is 25% less than P and 20% less than T. T is q% less than P. What is the value of q? | {
"A": "93.5",
"B": "90",
"C": "6.75",
"D": "6.25",
"E": "2"
} | divide(multiply(25, 25), const_100) | multiply(n0,n0)|divide(#0,const_100)| | "usually we can solve every question of this type by choosing appropriate value of the variable and deriving the value of other related variables . let , p = 400 then j = ( 75 / 100 ) * 400 = 300 also j = ( 80 / 100 ) * t i . e . t = 300 * 100 / 80 = 375 and t = [ 1 - ( q / 100 ) ] * p i . e . 100 - q = 100 * t / p = 100 * 375 / 400 = 93.75 i . e . q = 6.25 answer : option d" | gain |
math_qa__ZZ6gBssM1qCf3P4e | A student was asked to find 4/5 of a number. But the student divided the number by 4/5, thus the student got 36 more than the correct answer. Find the number. Pick one
A) 60 B) 70 C) 80 D) 90 E) 100 | <gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">36 * (4/5)</gadget>
<output>144/5 = around 28.8</output>
<gadget id="calculator">(144/5) * (4/5)</gadget>
<output>576/25 = around 23.04</output>
<gadget id="calculator">(4/5) * (4/5)</gadget>
<output>16/25 = around 0.64</output>
<gadget id="calculator">1 - (16/25)</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">(576/25) / (9/25)</gadget>
<output>64</output>
<gadget id="calculator">64 / (4/5)</gadget>
<output>80</output>
<result>C</result> | C | 80 | A student was asked to find 4/5 of a number. But the student divided the number by 4/5, thus the student got 36 more than the correct answer. Find the number. | {
"A": "60",
"B": "70",
"C": "80",
"D": "90",
"E": "100"
} | divide(divide(multiply(multiply(36, divide(4, 5)), divide(4, 5)), subtract(const_1, multiply(divide(4, 5), divide(4, 5)))), divide(4, 5)) | divide(n0,n1)|multiply(n4,#0)|multiply(#0,#0)|multiply(#0,#1)|subtract(const_1,#2)|divide(#3,#4)|divide(#5,#0)| | "let the number be x . ( 5 / 4 ) * x = ( 4 / 5 ) * x + 36 25 x = 16 x + 720 9 x = 720 x = 80 the answer is c ." | general |
math_qa__azRm2dmwlE6pg8FQ | A vessel of capacity 2 litre has 30% of alcohol and another vessel of capacity 6 litre had 40% alcohol. The total liquid of 8 litre was poured out in a vessel of capacity 10 litre and thus the rest part of the vessel was filled with the water. What is the new concentration of Mixture?
Choose the correct choice:
A) 30 % . B) 71 % . C) 49 % . D) 29 % . E) 51 % . | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) * 2</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 6</gadget>
<output>12/5 = around 2.4</output>
<gadget id="calculator">(3/5) + (12/5)</gadget>
<output>3</output>
<gadget id="calculator">3 / 10</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(3/10) * 100</gadget>
<output>30</output>
<result>A</result> | A | 30 | A vessel of capacity 2 litre has 30% of alcohol and another vessel of capacity 6 litre had 40% alcohol. The total liquid of 8 litre was poured out in a vessel of capacity 10 litre and thus the rest part of the vessel was filled with the water. What is the new concentration of Mixture? | {
"A": "30 % .",
"B": "71 % .",
"C": "49 % .",
"D": "29 % .",
"E": "51 % ."
} | multiply(divide(add(multiply(divide(30, const_100), 2), multiply(divide(40, const_100), 6)), 10), const_100) | divide(n1,const_100)|divide(n3,const_100)|multiply(n0,#0)|multiply(n2,#1)|add(#2,#3)|divide(#4,n5)|multiply(#5,const_100)| | "30 % of 2 litres = 0.6 litres 40 % of 6 litres = 2.4 litres therefore , total quantity of alcohol is 3.0 litres . this mixture is in a 10 litre vessel . hence , the concentration of alcohol in this 10 litre vessel is 30 % answer : a" | general |
math_qa__VoFBf6tU582vXceL | The total of 324 of 20 paise and 25 paise make a sum of Rs. 70. The no of 20 paise coins is Choose the correct choice from the following answers
A) 238 B) 277 C) 220 D) 200 E) 288 | <gadget id="calculator">324 * 25</gadget>
<output>8_100</output>
<gadget id="calculator">70 * 100</gadget>
<output>7_000</output>
<gadget id="calculator">8_100 - 7_000</gadget>
<output>1_100</output>
<gadget id="calculator">25 - 20</gadget>
<output>5</output>
<gadget id="calculator">1_100 / 5</gadget>
<output>220</output>
<result>C</result> | C | 220 | The total of 324 of 20 paise and 25 paise make a sum of Rs. 70. The no of 20 paise coins is | {
"A": "238",
"B": "277",
"C": "220",
"D": "200",
"E": "288"
} | divide(subtract(multiply(324, 25), multiply(70, const_100)), subtract(25, 20)) | multiply(n0,n2)|multiply(n3,const_100)|subtract(n2,n1)|subtract(#0,#1)|divide(#3,#2)| | "explanation : let the number of 20 paise coins be x . then the no of 25 paise coins = ( 324 - x ) . 0.20 * ( x ) + 0.25 ( 324 - x ) = 70 = > x = 220 . . answer : c ) 220" | general |
math_qa__J8TF4ZXfDHbKQRM4 | What is the number of integers from 1 to 1100 (inclusive) that are divisible by neither 11 nor by 35?
Choose the correct option: A) 884 B) 890 C) 892 D) 910 E) 945 | <gadget id="calculator">1_100 / 11</gadget>
<output>100</output>
<gadget id="calculator">1_100 / 35</gadget>
<output>220/7 = around 31.428571</output>
<gadget id="calculator">100 + (220/7)</gadget>
<output>920/7 = around 131.428571</output>
<gadget id="calculator">11 * 35</gadget>
<output>385</output>
<gadget id="calculator">1_100 / 385</gadget>
<output>20/7 = around 2.857143</output>
<gadget id="calculator">(920/7) - (20/7)</gadget>
<output>900/7 = around 128.571429</output>
<gadget id="calculator">1_100 - (900/7)</gadget>
<output>6_800/7 = around 971.428571</output>
<result>E</result> | E | 945 | What is the number of integers from 1 to 1100 (inclusive) that are divisible by neither 11 nor by 35? | {
"A": "884",
"B": "890",
"C": "892",
"D": "910",
"E": "945"
} | subtract(1100, subtract(add(divide(1100, 11), divide(1100, 35)), divide(1100, multiply(11, 35)))) | divide(n1,n2)|divide(n1,n3)|multiply(n2,n3)|add(#0,#1)|divide(n1,#2)|subtract(#3,#4)|subtract(n1,#5)| | "normally , i would use the method used by bunuel . it ' s the most accurate . but if you are looking for a speedy solution , you can use another method which will sometimes give you an estimate . looking at the options ( most of them are spread out ) , i wont mind trying it . ( mind you , the method is accurate here since the numbers start from 1 . ) in 1000 consecutive numbers , number of multiples of 11 = 1000 / 11 = 90 ( ignore decimals ) in 1000 consecutive numbers , number of multiples of 35 = 1000 / 35 = 28 number of multiples of 11 * 35 i . e . 385 = 1000 / 385 = 2 number of integers from 1 to 1000 that are divisible by neither 11 nor by 35 = 1000 - ( 90 + 28 - 2 ) { using the concept of sets here ) = 945 think : why did i say the method is approximate in some cases ? think what happens if the given range is 11 to 1010 both inclusive ( again 1000 numbers ) what is the number of multiples in this case ? e" | other |
math_qa__QX1CijS4aTss3CTT | Arun makes a popular brand of ice cream in a rectangular shaped bar 6cm long, 5cm wide and 2cm thick. To cut costs, the company had decided to reduce the volume of the bar by 19%. The thickness will remain same, but the length and width will be decreased by some percentage. The new width will be, Choices:
A) 33 B) 87 C) 99 D) 367 E) 72 | <gadget id="calculator">6 * 5</gadget>
<output>30</output>
<gadget id="calculator">30 * 2</gadget>
<output>60</output>
<gadget id="calculator">60 / 2</gadget>
<output>30</output>
<gadget id="calculator">30 + 3</gadget>
<output>33</output>
<result>A</result> | A | 33 | Arun makes a popular brand of ice cream in a rectangular shaped bar 6cm long, 5cm wide and 2cm thick. To cut costs, the company had decided to reduce the volume of the bar by 19%. The thickness will remain same, but the length and width will be decreased by some percentage. The new width will be, | {
"A": "33",
"B": "87",
"C": "99",
"D": "367",
"E": "72"
} | add(divide(multiply(multiply(6, 5), 2), 2), const_3) | multiply(n0,n1)|multiply(n2,#0)|divide(#1,n2)|add(#2,const_3) | answer : a | gain |
math_qa__S0qAy4c6TBY0iaC7 | Mark bought a set of 6 flower pots of different sizes at a total cost of $8.25. Each pot cost 0.1 more than the next one below it in size. What was the cost, in dollars, of the largest pot? Answers
A) $ 1.62
B) $ 1.85
C) $ 2.00
D) $ 2.15
E) $ 2.30 | <gadget id="calculator">6 - 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 6</gadget>
<output>30</output>
<gadget id="calculator">30 / 2</gadget>
<output>15</output>
<gadget id="calculator">15 * 0.1</gadget>
<output>1.5</output>
<gadget id="calculator">8.25 - 1.5</gadget>
<output>6.75</output>
<gadget id="calculator">6.75 / 6</gadget>
<output>1.125</output>
<gadget id="calculator">5 * 0.1</gadget>
<output>0.5</output>
<gadget id="calculator">1.125 + 0.5</gadget>
<output>1.625</output>
<result>A</result> | A | 1.62 | Mark bought a set of 6 flower pots of different sizes at a total cost of $8.25. Each pot cost 0.1 more than the next one below it in size. What was the cost, in dollars, of the largest pot? | {
"A": "$ 1.62",
"B": "$ 1.85",
"C": "$ 2.00",
"D": "$ 2.15",
"E": "$ 2.30"
} | add(divide(subtract(8.25, multiply(divide(multiply(subtract(6, const_1), 6), const_2), 0.1)), 6), multiply(subtract(6, const_1), 0.1)) | subtract(n0,const_1)|multiply(n0,#0)|multiply(n2,#0)|divide(#1,const_2)|multiply(n2,#3)|subtract(n1,#4)|divide(#5,n0)|add(#6,#2)| | "this question can be solved with a handful of different algebra approaches ( as has been shown in the various posts ) . since the question asks for the price of the largest pot , and the answers are prices , we can test the answers . we ' re told that there are 6 pots and that each pot costs 25 cents more than the next . the total price of the pots is $ 8.25 . we ' re asked for the price of the largest ( most expensive ) pot . since the total price is $ 8.25 ( a 10 - cent increment ) and the the difference in sequential prices of the pots is 10 cents , the largest pot probably has a price that is a 10 - cent increment . from the answer choices , i would then test answer a first if . . . . the largest pot = $ 1.625 1.125 1.225 1.325 1.425 1.525 1.625 total = $ 8.25 so this must be the answer . a" | general |
math_qa__QZcprOWnGG1CPqgU | The profit obtained by selling an article for Rs. 57 is the same as the loss obtained by selling it for Rs. 43. What is the cost price of the article?
Choose the correct choice from the following answers:
A) rs . 40
B) rs . 50
C) rs . 49
D) rs . 59
E) none of these | <gadget id="calculator">57 + 43</gadget>
<output>100</output>
<gadget id="calculator">100 / 2</gadget>
<output>50</output>
<result>B</result> | B | 50 | The profit obtained by selling an article for Rs. 57 is the same as the loss obtained by selling it for Rs. 43. What is the cost price of the article? | {
"A": "rs . 40",
"B": "rs . 50",
"C": "rs . 49",
"D": "rs . 59",
"E": "none of these"
} | divide(add(57, 43), const_2) | add(n0,n1)|divide(#0,const_2)| | "s . p 1 - c . p = c . p – s . p 2 57 - c . p = c . p - 43 2 c . p = 57 + 43 ; c . p = 100 / 2 = 50 answer : b" | gain |
math_qa__eXnXtp9ePQzY4aKw | In 2008, the profits of Company N were 8 percent of revenues. In 2009, the revenues of Company N fell by 20 percent, but profits were 15 percent of revenues. The profits in 2009 were what percent of the profits in 2008? Choose the correct choice:
A) 150 % B) 105 % C) 120 % D) 124.2 % E) 138 % | <gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">1 - (1/5)</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">15 * (4/5)</gadget>
<output>12</output>
<gadget id="calculator">12 / 8</gadget>
<output>3/2 = around 1.5</output>
<gadget id="calculator">(3/2) * 100</gadget>
<output>150</output>
<result>A</result> | A | 150 | In 2008, the profits of Company N were 8 percent of revenues. In 2009, the revenues of Company N fell by 20 percent, but profits were 15 percent of revenues. The profits in 2009 were what percent of the profits in 2008? | {
"A": "150 %",
"B": "105 %",
"C": "120 %",
"D": "124.2 %",
"E": "138 %"
} | multiply(divide(multiply(15, subtract(const_1, divide(20, const_100))), 8), const_100) | divide(n3,const_100)|subtract(const_1,#0)|multiply(n4,#1)|divide(#2,n1)|multiply(#3,const_100)| | "the profit 0 f 2009 interms of 2008 = 0.8 * 15 / 8 * 100 = 150 % a" | gain |
math_qa__rd6Vcm79EksYZbgA | A garrison of 2000 men has provisions for 54 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 20 days more. What is the reinforcement? Select: A) 1778 B) 1682 C) 9178 D) 1900 E) 1782 | <gadget id="calculator">2_000 * 54</gadget>
<output>108_000</output>
<gadget id="calculator">2_000 * 15</gadget>
<output>30_000</output>
<gadget id="calculator">108_000 - 30_000</gadget>
<output>78_000</output>
<gadget id="calculator">78_000 / 20</gadget>
<output>3_900</output>
<gadget id="calculator">3_900 - 2_000</gadget>
<output>1_900</output>
<result>D</result> | D | 1,900 | A garrison of 2000 men has provisions for 54 days. At the end of 15 days, a reinforcement arrives, and it is now found that the provisions will last only for 20 days more. What is the reinforcement? | {
"A": "1778",
"B": "1682",
"C": "9178",
"D": "1900",
"E": "1782"
} | subtract(divide(subtract(multiply(2000, 54), multiply(2000, 15)), 20), 2000) | multiply(n0,n1)|multiply(n0,n2)|subtract(#0,#1)|divide(#2,n3)|subtract(#3,n0)| | "2000 - - - - 54 2000 - - - - 39 x - - - - - 20 x * 20 = 2000 * 39 x = 3900 2000 - - - - - - - 1900 answer : d" | physics |
math_qa__AWZWHAwG1rQYPNIq | If a bicyclist in motion increases his speed by 30 percent and then increases this speed by 10 percent, what percent of the original speed is the total increase in speed?
Choose the correct choice from the following:
A) 10 %
B) 40 %
C) 43 %
D) 64 %
E) 140 % | <gadget id="calculator">100 + 30</gadget>
<output>130</output>
<gadget id="calculator">10 / 100</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">130 * (1/10)</gadget>
<output>13</output>
<gadget id="calculator">130 + 13</gadget>
<output>143</output>
<gadget id="calculator">143 - 100</gadget>
<output>43</output>
<result>C</result> | C | 43 | If a bicyclist in motion increases his speed by 30 percent and then increases this speed by 10 percent, what percent of the original speed is the total increase in speed? | {
"A": "10 %",
"B": "40 %",
"C": "43 %",
"D": "64 %",
"E": "140 %"
} | subtract(add(add(const_100, 30), multiply(add(const_100, 30), divide(10, const_100))), const_100) | add(n0,const_100)|divide(n1,const_100)|multiply(#0,#1)|add(#0,#2)|subtract(#3,const_100) | let the sped be 100 an increase of 30 % the speed now is 130 a further increase of 10 % on 130 = 13 total increase = 43 on 100 = 43 % c | general |
math_qa__r3iHEwLtSwhzDKLm | What is the greatest number that divides 263, 935 and 1383 leaving a remainder of 7 in each case ? Choices.
A) 30
B) 31
C) 32
D) 35
E) 37 | <gadget id="calculator">1_383 - 7</gadget>
<output>1_376</output>
<gadget id="calculator">935 - 7</gadget>
<output>928</output>
<gadget id="calculator">1_376 - 928</gadget>
<output>448</output>
<gadget id="calculator">263 - 7</gadget>
<output>256</output>
<gadget id="calculator">448 - 256</gadget>
<output>192</output>
<gadget id="calculator">192 / 3</gadget>
<output>64</output>
<gadget id="calculator">64 / 2</gadget>
<output>32</output>
<result>C</result> | C | 32 | What is the greatest number that divides 263, 935 and 1383 leaving a remainder of 7 in each case ? | {
"A": "30",
"B": "31",
"C": "32",
"D": "35",
"E": "37"
} | divide(divide(subtract(subtract(subtract(1383, 7), subtract(935, 7)), subtract(263, 7)), const_3), const_2) | subtract(n2,n3)|subtract(n1,n3)|subtract(n0,n3)|subtract(#0,#1)|subtract(#3,#2)|divide(#4,const_3)|divide(#5,const_2) | answer the required greatest number is the hcf of 263 - 7 , 935 - 7 , 1383 - 7 i . e . 256 , 928 and 1376 hcf = 32 correct option : c | general |
math_qa__39V95Ke2HRJ8iBvw | How many seconds will a 900 meter long train moving with a speed of 63 km/hr take to cross a man walking with a speed of 3 km/hr in the direction of the train ?
Choose the correct choice from the following.
A) 48 B) 36 C) 54 D) 11 E) 18 | <gadget id="calculator">63 - 3</gadget>
<output>60</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">60 * (5/18)</gadget>
<output>50/3 = around 16.666667</output>
<gadget id="calculator">900 / (50/3)</gadget>
<output>54</output>
<result>C</result> | C | 54 | How many seconds will a 900 meter long train moving with a speed of 63 km/hr take to cross a man walking with a speed of 3 km/hr in the direction of the train ? | {
"A": "48",
"B": "36",
"C": "54",
"D": "11",
"E": "18"
} | divide(900, multiply(subtract(63, 3), const_0_2778)) | subtract(n1,n2)|multiply(#0,const_0_2778)|divide(n0,#1)| | "explanation : here distance d = 900 mts speed s = 63 - 3 = 60 kmph = 60 x 5 / 18 m / s time t = = 54 sec . answer : c" | physics |
math_qa__DA5Ky6qHt8ZENnpZ | Find the average of all the numbers between 6 and 38 which are divisible by 4. Choose the correct answer
A) 18 B) 22 C) 20 D) 30 E) 28 | <gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">38 - 4</gadget>
<output>34</output>
<gadget id="calculator">10 + 34</gadget>
<output>44</output>
<gadget id="calculator">44 / 2</gadget>
<output>22</output>
<result>B</result> | B | 22 | Find the average of all the numbers between 6 and 38 which are divisible by 4. | {
"A": "18",
"B": "22",
"C": "20",
"D": "30",
"E": "28"
} | divide(add(add(6, const_4), subtract(38, const_4)), const_2) | add(n0,const_4)|subtract(n1,const_4)|add(#0,#1)|divide(#2,const_2)| | "solution average = ( ( 8 + 12 + 16 + 20 + 24 + 28 + 32 + 36 ) / 8 ) = 186 / 7 = 22 answer b" | general |
math_qa__CdTyZoS6bLbtf8fP | If the cost price is 96% of sp then what is the profit % Choose the correct choice from the following answers:
A) 4.07 % B) 4 % C) 4.7 % D) 4.17 % E) 4.27 % | <gadget id="calculator">100 - 96</gadget>
<output>4</output>
<gadget id="calculator">4 / 96</gadget>
<output>1/24 = around 0.041667</output>
<gadget id="calculator">(1/24) * 100</gadget>
<output>25/6 = around 4.166667</output>
<result>D</result> | D | 4.17 | If the cost price is 96% of sp then what is the profit % | {
"A": "4.07 %",
"B": "4 %",
"C": "4.7 %",
"D": "4.17 %",
"E": "4.27 %"
} | multiply(divide(subtract(const_100, 96), 96), const_100) | subtract(const_100,n0)|divide(#0,n0)|multiply(#1,const_100)| | "sol . sp = rs 100 : then cp = rs 96 : profit = rs 4 . profit = { ( 4 / 96 ) * 100 } % = 4.17 % answer is d ." | gain |
math_qa__aDjg1NxTelmaqfub | A car gets 27 miles to the gallon. If it is modified to use a solar panel, it will use only 75 percent as much fuel as it does now. If the fuel tank holds 14 gallons, how many more miles will the car be able to travel, per full tank of fuel, after it has been modified?
Answers
A) 120 B) 126 C) 132 D) 138 E) 144 | <gadget id="calculator">27 / 75</gadget>
<output>9/25 = around 0.36</output>
<gadget id="calculator">(9/25) * 100</gadget>
<output>36</output>
<gadget id="calculator">36 * 14</gadget>
<output>504</output>
<gadget id="calculator">27 * 14</gadget>
<output>378</output>
<gadget id="calculator">504 - 378</gadget>
<output>126</output>
<result>B</result> | B | 126 | A car gets 27 miles to the gallon. If it is modified to use a solar panel, it will use only 75 percent as much fuel as it does now. If the fuel tank holds 14 gallons, how many more miles will the car be able to travel, per full tank of fuel, after it has been modified? | {
"A": "120",
"B": "126",
"C": "132",
"D": "138",
"E": "144"
} | subtract(multiply(multiply(divide(27, 75), const_100), 14), multiply(27, 14)) | divide(n0,n1)|multiply(n0,n2)|multiply(#0,const_100)|multiply(n2,#2)|subtract(#3,#1)| | "originally , the distance the car could go on a full tank was 14 * 27 = 378 miles . after it has been modified , the car can go 27 / 0.75 = 36 miles per gallon . on a full tank , the car can go 14 * 36 = 504 miles , thus 126 miles more . the answer is b ." | physics |
math_qa__W4FtJqTop8MdGh2A | A fort had provision of food for 150 men for 45 days. After 10 days, 25 men left the fort. The number of days for which the remaining food will last, is: Choose the correct choice: A) 34 B) 387 C) 42 D) 28 E) 71 | <gadget id="calculator">25 + 10</gadget>
<output>35</output>
<gadget id="calculator">150 * 35</gadget>
<output>5_250</output>
<gadget id="calculator">150 - 25</gadget>
<output>125</output>
<gadget id="calculator">5_250 / 125</gadget>
<output>42</output>
<result>C</result> | C | 42 | A fort had provision of food for 150 men for 45 days. After 10 days, 25 men left the fort. The number of days for which the remaining food will last, is: | {
"A": "34",
"B": "387",
"C": "42",
"D": "28",
"E": "71"
} | divide(multiply(150, add(25, 10)), subtract(150, 25)) | add(n2,n3)|subtract(n0,n3)|multiply(n0,#0)|divide(#2,#1)| | "explanation : after 10 days : 150 men had food for 35 days . suppose 125 men had food for x days . now , less men , more days ( indirect proportion ) { \ color { blue } \ therefore } 125 : 150 : : 35 : x { \ color { blue } \ rightarrow } 125 x x = 150 x 35 { \ color { blue } \ rightarrow x = \ frac { 150 \ times 35 } { 125 } } { \ color { blue } \ rightarrow } x = 42 . answer : c ) 42" | physics |
math_qa__dGzLFxe0g9PeGHxl | A person lent a certain sum of money at 4% per annum at simple interest and in 8 years the interest amounted to Rs.306 less than the sum lent. What was the sum lent? Choose one.
A) 228 B) 278 C) 289 D) 500 E) 450 | <gadget id="calculator">4 * 8</gadget>
<output>32</output>
<gadget id="calculator">32 / 100</gadget>
<output>8/25 = around 0.32</output>
<gadget id="calculator">1 - (8/25)</gadget>
<output>17/25 = around 0.68</output>
<gadget id="calculator">306 / (17/25)</gadget>
<output>450</output>
<result>E</result> | E | 450 | A person lent a certain sum of money at 4% per annum at simple interest and in 8 years the interest amounted to Rs.306 less than the sum lent. What was the sum lent? | {
"A": "228",
"B": "278",
"C": "289",
"D": "500",
"E": "450"
} | divide(306, subtract(const_1, divide(multiply(4, 8), const_100))) | multiply(n0,n1)|divide(#0,const_100)|subtract(const_1,#1)|divide(n2,#2)| | "p - 306 = ( p * 4 * 8 ) / 100 p = 450 answer : e" | gain |
math_qa__9uOtAaxxuShvIxtg | A man has some hens and cows. If the number of heads be 50 and the number of feet equals 144, then the number of hens will be Select.
A) 22 B) 24 C) 26 D) 20 E) 28 | <gadget id="calculator">50 * 4</gadget>
<output>200</output>
<gadget id="calculator">200 - 144</gadget>
<output>56</output>
<gadget id="calculator">56 / 2</gadget>
<output>28</output>
<result>E</result> | E | 28 | A man has some hens and cows. If the number of heads be 50 and the number of feet equals 144, then the number of hens will be | {
"A": "22",
"B": "24",
"C": "26",
"D": "20",
"E": "28"
} | divide(subtract(multiply(50, const_4), 144), const_2) | multiply(n0,const_4)|subtract(#0,n1)|divide(#1,const_2)| | "explanation : let number of hens = h and number of cows = c number of heads = 50 = > h + c = 48 - - - ( equation 1 ) number of feet = 144 = > 2 h + 4 c = 144 = > h + 2 c = 72 - - - ( equation 2 ) ( equation 2 ) - ( equation 1 ) gives 2 c - c = 72 - 50 = > c = 22 substituting the value of c in equation 1 , we get h + 22 = 50 = > h = 50 - 22 = 28 i . e . , number of hens = 28 answer : e" | general |
math_qa__Ke66bopWn7ZOtBwU | Because he’s taxed by his home planet, Mork pays a tax rate of 40% on his income, while Mindy pays a rate of only 30% on hers. If Mindy earned 3 times as much as Mork did, what was their combined tax rate? Choose the correct choice from the following:
A) 32.5 % B) 34 % C) 35 % D) 36 % E) 37.5 % | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">3 * (3/10)</gadget>
<output>9/10 = around 0.9</output>
<gadget id="calculator">(2/5) + (9/10)</gadget>
<output>13/10 = around 1.3</output>
<gadget id="calculator">1 + 3</gadget>
<output>4</output>
<gadget id="calculator">(13/10) / 4</gadget>
<output>13/40 = around 0.325</output>
<gadget id="calculator">100 * (13/40)</gadget>
<output>65/2 = around 32.5</output>
<result>A</result> | A | 32.5 | Because he’s taxed by his home planet, Mork pays a tax rate of 40% on his income, while Mindy pays a rate of only 30% on hers. If Mindy earned 3 times as much as Mork did, what was their combined tax rate? | {
"A": "32.5 %",
"B": "34 %",
"C": "35 %",
"D": "36 %",
"E": "37.5 %"
} | multiply(const_100, divide(add(divide(40, const_100), multiply(3, divide(30, const_100))), add(const_1, 3))) | add(n2,const_1)|divide(n0,const_100)|divide(n1,const_100)|multiply(n2,#2)|add(#1,#3)|divide(#4,#0)|multiply(#5,const_100)| | "say morks income is - 100 so tax paid will be 40 say mindy ' s income is 3 * 100 = 300 so tax paid is 30 % * 300 = 90 total tax paid = 40 + 90 = 130 . combined tax % will be 130 / 100 + 300 = 32.5 % answer : a" | gain |
math_qa__PySEEP8fbeZPdshv | A car travels at a speed of 65 miles per hour. How far will it travel in 6 hours?
Pick one:
A) 125 miles B) 225 miles C) 390 miles D) 425 miles E) 525 miles | <gadget id="calculator">65 * 6</gadget>
<output>390</output>
<result>C</result> | C | 390 | A car travels at a speed of 65 miles per hour. How far will it travel in 6 hours? | {
"A": "125 miles",
"B": "225 miles",
"C": "390 miles",
"D": "425 miles",
"E": "525 miles"
} | multiply(65, 6) | multiply(n0,n1)| | "during each hour , the car travels 65 miles . for 6 hours it will travel 65 + 65 + 65 + 65 + 65 + 65 = 6 × 65 = 390 miles correct answer is c ) 390 miles" | physics |
math_qa__pOcOZtaDbkrsfJQO | In a family 13 people eat only vegetarian, 7 people eat only non veg., 8 people eat both veg and non veg.. How many people eat veg in the family? Choose the correct option: A) 20 B) 11 C) 9 D) 31 E) 21 | <gadget id="calculator">13 + 8</gadget>
<output>21</output>
<result>E</result> | E | 21 | In a family 13 people eat only vegetarian, 7 people eat only non veg., 8 people eat both veg and non veg.. How many people eat veg in the family? | {
"A": "20",
"B": "11",
"C": "9",
"D": "31",
"E": "21"
} | add(13, 8) | add(n0,n2)| | "total people eat veg = only veg + both veg and non veg total = 13 + 8 = 21 answer = e" | other |
math_qa__tWTq6iAiC64AhIx7 | If p/q =4/5, then the value of 11/7 + {(2q - p) / (2q + p)} is ?
Options: A) 3 / 7 B) 34 C) 1 D) 2 E) 3 | <gadget id="calculator">11 / 7</gadget>
<output>11/7 = around 1.571429</output>
<gadget id="calculator">4 / 5</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">2 - (4/5)</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">2 + (4/5)</gadget>
<output>14/5 = around 2.8</output>
<gadget id="calculator">(6/5) / (14/5)</gadget>
<output>3/7 = around 0.428571</output>
<gadget id="calculator">(11/7) + (3/7)</gadget>
<output>2</output>
<result>D</result> | D | 2 | If p/q =4/5, then the value of 11/7 + {(2q - p) / (2q + p)} is ? | {
"A": "3 / 7",
"B": "34",
"C": "1",
"D": "2",
"E": "3"
} | add(divide(11, 7), divide(subtract(2, divide(4, 5)), add(2, divide(4, 5)))) | divide(n2,n3)|divide(n0,n1)|add(n4,#1)|subtract(n4,#1)|divide(#3,#2)|add(#0,#4) | answer given exp . = 11 / 7 + { ( 2 q - p ) / ( 2 q + p ) } dividing numerator as well as denominator by q , exp = 11 / 7 + { 2 - p / q ) / ( 2 + p / q ) } = 11 / 7 + { ( 2 - 4 / 5 ) / ( 2 + 4 / 5 ) } = 11 / 7 + 6 / 14 = 11 / 7 + 3 / 7 = 14 / 7 = 2 correct option : d | general |
math_qa__O2RgOdqQRJoj829k | A big container is 40% full with water. If 14 liters of water is added, the container becomes 3/4 full. What is the capacity of the big container in liters? Choose the correct option:
A) 32
B) 36
C) 40
D) 44
E) 48 | <gadget id="calculator">3 / 4</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(3/4) - (2/5)</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">14 / (7/20)</gadget>
<output>40</output>
<result>C</result> | C | 40 | A big container is 40% full with water. If 14 liters of water is added, the container becomes 3/4 full. What is the capacity of the big container in liters? | {
"A": "32",
"B": "36",
"C": "40",
"D": "44",
"E": "48"
} | divide(14, subtract(divide(3, 4), divide(40, const_100))) | divide(n2,n3)|divide(n0,const_100)|subtract(#0,#1)|divide(n1,#2) | 14 liters is 35 % of the capacity c . 14 = 0.35 c c = 14 / 0.35 = 40 liters . the answer is c . | general |
math_qa__8WhKD9MGTGq6sDpf | The ratio of the arithmetic mean of two numbers to one of the numbers is 5:8. What is the ratio of the smaller number to the larger number? Select:
A) 1 : 8 B) 1 : 6 C) 1 : 5 D) 1 : 4 E) 1 : 3 | <gadget id="calculator">5 / 8</gadget>
<output>5/8 = around 0.625</output>
<gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(5/8) - (1/2)</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 2</gadget>
<output>1/4 = around 0.25</output>
<result>D</result> | D | 0.25 | The ratio of the arithmetic mean of two numbers to one of the numbers is 5:8. What is the ratio of the smaller number to the larger number? | {
"A": "1 : 8",
"B": "1 : 6",
"C": "1 : 5",
"D": "1 : 4",
"E": "1 : 3"
} | multiply(subtract(divide(5, 8), divide(const_1, const_2)), const_2) | divide(n0,n1)|divide(const_1,const_2)|subtract(#0,#1)|multiply(#2,const_2)| | "for two numbers , the arithmetic mean is the middle of the two numbers . the ratio of the mean to the larger number is 5 : 8 , thus the smaller number must have a ratio of 2 . the ratio of the smaller number to the larger number is 2 : 8 = 1 : 4 . the answer is d ." | other |
math_qa__hulrzelTay4MV8Pj | The salaries of A, B, and C are in the ratio of 1 : 2 : 3. The salary of B and C together is Rs. 6000. By what percent is the salary of C more than that of A? Options:
A) 209 %
B) 200 %
C) 290 %
D) 600 %
E) 100 % | <gadget id="calculator">2 + 3</gadget>
<output>5</output>
<gadget id="calculator">6_000 / 5</gadget>
<output>1_200</output>
<gadget id="calculator">3 * 1_200</gadget>
<output>3_600</output>
<gadget id="calculator">3_600 / 1_200</gadget>
<output>3</output>
<gadget id="calculator">3 - 1</gadget>
<output>2</output>
<gadget id="calculator">2 * 100</gadget>
<output>200</output>
<result>B</result> | B | 200 | The salaries of A, B, and C are in the ratio of 1 : 2 : 3. The salary of B and C together is Rs. 6000. By what percent is the salary of C more than that of A? | {
"A": "209 %",
"B": "200 %",
"C": "290 %",
"D": "600 %",
"E": "100 %"
} | multiply(subtract(divide(multiply(3, divide(6000, add(2, 3))), divide(6000, add(2, 3))), const_1), const_100) | add(n1,n2)|divide(n3,#0)|multiply(n2,#1)|divide(#2,#1)|subtract(#3,const_1)|multiply(#4,const_100) | explanation : let the salaries of a , b , c be x , 2 x and 3 x respectively . then , 2 x + 3 x = 6000 = > x = 1200 . a ' s salary = rs . 1200 , b ' s salary = rs . 2400 , and cs salary rs . 3600 . excess of c ' s salary over a ' s = [ ( 2400 / 1200 ) x 100 ] = 200 % . answer : b ) 200 % | other |
math_qa__vPt0rIMtUh4F4fqr | Vinoth can complete a painting work in 20 days. Prakash can do the same work in 25 days. They start the work together but Vinoth quit after 3 days of work. How many days are required to complete the remaining painting work by Prakash. Answers: A) 15.25 days B) 16.25 days C) 17.25 days D) 18.25 days E) 19.25 days | <gadget id="calculator">1 / 25</gadget>
<output>1/25 = around 0.04</output>
<gadget id="calculator">3 * (1/25)</gadget>
<output>3/25 = around 0.12</output>
<gadget id="calculator">1 - (3/25)</gadget>
<output>22/25 = around 0.88</output>
<gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">(22/25) / (1/20)</gadget>
<output>88/5 = around 17.6</output>
<result>D</result> | D | 18.25 | Vinoth can complete a painting work in 20 days. Prakash can do the same work in 25 days. They start the work together but Vinoth quit after 3 days of work. How many days are required to complete the remaining painting work by Prakash. | {
"A": "15.25 days",
"B": "16.25 days",
"C": "17.25 days",
"D": "18.25 days",
"E": "19.25 days"
} | divide(subtract(const_1, multiply(3, divide(const_1, 25))), divide(const_1, 20)) | divide(const_1,n1)|divide(const_1,n0)|multiply(n2,#0)|subtract(const_1,#2)|divide(#3,#1) | vinoth can complete the painting work in one day is 1 / 20 prakash can complete the same work in one day is 1 / 25 both of them can complete the work in 1 / 20 + days = 9 / 100 ( 1 / 20 + 1 / 25 ) they must have completed in three days = 9 / 100 * 3 = 27 / 100 remaining work to be done is by prakash = 1 - 27 / 100 = 73 / 100 for one work , prakash can do in 25 days for 73 / 100 work , he can do in 73 / 100 * 25 = 73 / 4 days or 18.25 days answer : d | physics |
math_qa__11ogiziPPUNjYPRh | The total cost of a vacation was divided among 3 people. If the total cost of the vacation had been divided equally among 5 people, the cost per person would have been $50 less. What was the total cost cost of the vacation? Choose one.
A) $ 200 B) $ 375 C) $ 400 D) $ 500 E) $ 600 | <gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">5 - 3</gadget>
<output>2</output>
<gadget id="calculator">50 / 2</gadget>
<output>25</output>
<gadget id="calculator">15 * 25</gadget>
<output>375</output>
<result>B</result> | B | 375 | The total cost of a vacation was divided among 3 people. If the total cost of the vacation had been divided equally among 5 people, the cost per person would have been $50 less. What was the total cost cost of the vacation? | {
"A": "$ 200",
"B": "$ 375",
"C": "$ 400",
"D": "$ 500",
"E": "$ 600"
} | multiply(multiply(5, 3), divide(50, subtract(5, 3))) | multiply(n0,n1)|subtract(n1,n0)|divide(n2,#1)|multiply(#2,#0) | c for cost . p price per person . c = 3 * p c = 5 * p - 250 substituting the value of p from the first equation onto the second we get p = 125 . plugging in the value of p in the first equation , we get c = 375 . which leads us to answer choice b | general |
math_qa__HeyUPxSanvwTNym3 | How many ounces of a 60% salt solution must be added to 30 ounces of a 20 percent salt solution so that the resulting mixture is 40% salt? Select the correct option:
A) 16.67
B) 30
C) 50
D) 60.33
E) 70 | <gadget id="calculator">40 / 100</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(2/5) * 30</gadget>
<output>12</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(1/5) * 30</gadget>
<output>6</output>
<gadget id="calculator">12 - 6</gadget>
<output>6</output>
<gadget id="calculator">(2/5) - (1/5)</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">6 / (1/5)</gadget>
<output>30</output>
<result>B</result> | B | 30 | How many ounces of a 60% salt solution must be added to 30 ounces of a 20 percent salt solution so that the resulting mixture is 40% salt? | {
"A": "16.67",
"B": "30",
"C": "50",
"D": "60.33",
"E": "70"
} | divide(subtract(multiply(divide(40, const_100), 30), multiply(divide(20, const_100), 30)), subtract(divide(40, const_100), divide(20, const_100))) | divide(n3,const_100)|divide(n2,const_100)|multiply(n1,#0)|multiply(n1,#1)|subtract(#0,#1)|subtract(#2,#3)|divide(#5,#4)| | "let x = ounces of 60 % salt solution to be added . 2 * 30 + . 6 x = . 4 ( 30 + x ) x = 30 answer b" | gain |
math_qa__QXAvpMpNSy5Ah04g | If 20% of A is the same as 30% of B, then A : B is : Choose the correct choice from the following choices: A) 5 : 4 B) 5 : 3 C) 4 : 3 D) 3 : 2 E) 1 : 3 | <gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">20 / 100</gadget>
<output>1/5 = around 0.2</output>
<gadget id="calculator">(3/10) / (1/5)</gadget>
<output>3/2 = around 1.5</output>
<result>D</result> | D | 1.5 | If 20% of A is the same as 30% of B, then A : B is : | {
"A": "5 : 4",
"B": "5 : 3",
"C": "4 : 3",
"D": "3 : 2",
"E": "1 : 3"
} | divide(divide(30, const_100), divide(20, const_100)) | divide(n1,const_100)|divide(n0,const_100)|divide(#0,#1)| | "expl : 20 % of a i = 30 % of b = 20 a / 100 = 30 b / 100 = 3 / 2 = 3 : 2 answer : d" | gain |
math_qa__65LqUPusbLsdBriY | Working alone at its constant rate, machine A produces x boxes in 10 minutes and working alone at its constant rate, machine B produces 2x boxes in 5 minutes. How many minutes does it take machines A and B, working simultaneously at their respective constant rates, to produce 10x boxes? Choose the correct option:
A) 13 minutes B) 14 minutes C) 15 minutes D) 16 minutes E) 20 minutes | <gadget id="calculator">10 * 10</gadget>
<output>100</output>
<gadget id="calculator">10 / 10</gadget>
<output>1</output>
<gadget id="calculator">2 * 10</gadget>
<output>20</output>
<gadget id="calculator">20 / 5</gadget>
<output>4</output>
<gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">100 / 5</gadget>
<output>20</output>
<result>E</result> | E | 20 | Working alone at its constant rate, machine A produces x boxes in 10 minutes and working alone at its constant rate, machine B produces 2x boxes in 5 minutes. How many minutes does it take machines A and B, working simultaneously at their respective constant rates, to produce 10x boxes? | {
"A": "13 minutes",
"B": "14 minutes",
"C": "15 minutes",
"D": "16 minutes",
"E": "20 minutes"
} | divide(multiply(10, 10), add(speed(10, 10), speed(multiply(2, 10), 5))) | multiply(n0,n3)|multiply(n0,n1)|speed(n0,n0)|speed(#1,n2)|add(#2,#3)|divide(#0,#4)| | "rate = work / time given rate of machine a = x / 10 min machine b produces 2 x boxes in 5 min hence , machine b produces 4 x boxes in 10 min . rate of machine b = 4 x / 10 we need tofind the combined time that machines a and b , working simultaneouslytakeat their respective constant rates let ' s first find the combined rate of machine a and b rate of machine a = x / 10 min + rate of machine b = 4 x / 10 = 5 x / 10 now combine time = combine work needs to be done / combine rate = 10 x / 5 x * 10 = 6 min ans : e" | physics |
math_qa__EMwDvn2eD4I0GmiS | If y > 0, (1y)/20 + (3y)/10 is what percent of y? Choose the correct choice from the following choices.
A) 35 % B) 50 % C) 60 % D) 70 % E) 80 % | <gadget id="calculator">1 / 20</gadget>
<output>1/20 = around 0.05</output>
<gadget id="calculator">3 / 10</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">(1/20) + (3/10)</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">100 * (7/20)</gadget>
<output>35</output>
<result>A</result> | A | 35 | If y > 0, (1y)/20 + (3y)/10 is what percent of y? | {
"A": "35 %",
"B": "50 %",
"C": "60 %",
"D": "70 %",
"E": "80 %"
} | multiply(const_100, add(divide(1, 20), divide(3, 10))) | divide(n1,n2)|divide(n3,n4)|add(#0,#1)|multiply(#2,const_100)| | "can be reduced to y / 20 + 3 y / 10 = 7 y / 20 = 35 % a" | general |
math_qa__Bq5IBEXt2EGIEAOk | A certain college's enrollment at the beginning of 1992 was 20 percent greater than it was at the beginning of 1991, and its enrollment at the beginning of 1993 was 5 percent greater than it was at the beginning of 1992. The college's enrollment at the beginning of 1993 was what percent greater than its enrollment at the beginning of 1991 ? Answers:
A) 17.5 % B) 26 % C) 30 % D) 35 % E) 38 % | <gadget id="calculator">100 + 20</gadget>
<output>120</output>
<gadget id="calculator">100 + 5</gadget>
<output>105</output>
<gadget id="calculator">105 / 100</gadget>
<output>21/20 = around 1.05</output>
<gadget id="calculator">120 * (21/20)</gadget>
<output>126</output>
<gadget id="calculator">126 - 100</gadget>
<output>26</output>
<result>B</result> | B | 26 | A certain college's enrollment at the beginning of 1992 was 20 percent greater than it was at the beginning of 1991, and its enrollment at the beginning of 1993 was 5 percent greater than it was at the beginning of 1992. The college's enrollment at the beginning of 1993 was what percent greater than its enrollment at the beginning of 1991 ? | {
"A": "17.5 %",
"B": "26 %",
"C": "30 %",
"D": "35 %",
"E": "38 %"
} | subtract(multiply(add(const_100, 20), divide(add(const_100, 5), const_100)), const_100) | add(n1,const_100)|add(n4,const_100)|divide(#1,const_100)|multiply(#0,#2)|subtract(#3,const_100)| | "suppose enrollment in 1991 was 100 then enrollment in 1992 will be 120 and enrollment in 1993 will be 120 * 1.05 = 126 increase in 1993 from 1991 = 126 - 100 = 26 answer : b" | gain |
math_qa__AJlBEAExKCHe4DaX | An electric pump can fill a tank in 10 hours. Because of a leak in the tank, it took 20 hours to fill the tank. If the tank is full, how much time will the leak take to empty it? Answers.
A) 10 hours B) 12 hours C) 20 hours D) 5 hours E) 15 hours | <gadget id="calculator">20 / 1</gadget>
<output>20</output>
<result>C</result> | C | 20 | An electric pump can fill a tank in 10 hours. Because of a leak in the tank, it took 20 hours to fill the tank. If the tank is full, how much time will the leak take to empty it? | {
"A": "10 hours",
"B": "12 hours",
"C": "20 hours",
"D": "5 hours",
"E": "15 hours"
} | divide(20, const_1) | divide(n1,const_1)| | "work done by the leak in 1 hour = 1 / 10 - 1 / 20 = 1 / 20 the leak will empty the tank in 20 hours answer is c" | physics |
math_qa__W9kZ0TTvHocI9P85 | For every even positive integer m, f(m) represents the product of all even integers from 2 to m, inclusive. For example, f(12)=2x4x6x8x10x12. What is the greatest prime factor of f(36)? Choices.
A) 2 B) 5 C) 11 D) 17 E) 23 | <gadget id="calculator">36 / 2</gadget>
<output>18</output>
<gadget id="calculator">18 - 1</gadget>
<output>17</output>
<result>D</result> | D | 17 | For every even positive integer m, f(m) represents the product of all even integers from 2 to m, inclusive. For example, f(12)=2x4x6x8x10x12. What is the greatest prime factor of f(36)? | {
"A": "2",
"B": "5",
"C": "11",
"D": "17",
"E": "23"
} | subtract(divide(36, 2), const_1) | divide(n8,n0)|subtract(#0,const_1)| | "f ( 36 ) = 2 * 4 * 6 * 8 * 10 * 12 * 14 * 16 * 18 * 20 * 22 * 24 * 26 * 28 * 30 * 32 * 34 * 36 the greatest prime factor in this list is 17 . the answer is d ." | general |
math_qa__c8mdZgzidBZuJbAJ | Pipe A can fill a tank in 10 hours. Due to a leak at the bottom, it takes 15 hours for the pipe A to fill the tank. In what time can the leak alone empty the full tank? Choose the correct answer:
A) 76
B) 84
C) 56
D) 75
E) 30 | <gadget id="calculator">15 * 10</gadget>
<output>150</output>
<gadget id="calculator">15 - 10</gadget>
<output>5</output>
<gadget id="calculator">150 / 5</gadget>
<output>30</output>
<result>E</result> | E | 30 | Pipe A can fill a tank in 10 hours. Due to a leak at the bottom, it takes 15 hours for the pipe A to fill the tank. In what time can the leak alone empty the full tank? | {
"A": "76",
"B": "84",
"C": "56",
"D": "75",
"E": "30"
} | divide(multiply(15, 10), subtract(15, 10)) | multiply(n0,n1)|subtract(n1,n0)|divide(#0,#1) | let the leak can empty the full tank in x hours 1 / 10 - 1 / x = 1 / 15 = > 1 / x = 1 / 10 - 1 / 15 = ( 3 - 2 ) / 30 = 1 / 30 = > x = 30 . answer : e | physics |
math_qa__DIUwZNclNJ3DqlxU | The average age of 19 persons in a office is 15 years. Out of these, the average age of 5 of them is 14 years and that of the other 9 persons is 16 years. The age of the 15th person is? Choose the correct choice from the following answers: A) 9 B) 71 C) 85 D) 92 E) 90 | <gadget id="calculator">19 * 15</gadget>
<output>285</output>
<gadget id="calculator">5 * 14</gadget>
<output>70</output>
<gadget id="calculator">285 - 70</gadget>
<output>215</output>
<gadget id="calculator">9 * 16</gadget>
<output>144</output>
<gadget id="calculator">215 - 144</gadget>
<output>71</output>
<result>B</result> | B | 71 | The average age of 19 persons in a office is 15 years. Out of these, the average age of 5 of them is 14 years and that of the other 9 persons is 16 years. The age of the 15th person is? | {
"A": "9",
"B": "71",
"C": "85",
"D": "92",
"E": "90"
} | subtract(subtract(multiply(19, 15), multiply(5, 14)), multiply(9, 16)) | multiply(n0,n1)|multiply(n2,n3)|multiply(n4,n5)|subtract(#0,#1)|subtract(#3,#2)| | "age of the 15 th student = 19 * 15 - ( 14 * 5 + 16 * 9 ) = 285 - 214 = 71 years answer is b" | general |
math_qa__XTNskG7lMeTQaybr | A pet store regularly sells pet food at a discount of 10 percent to 30 percent from the manufacturer’s suggested retail price. If during a sale, the store discounts an additional 20 percent from the discount price, what would be the lowest possible price of a container of pet food that had a manufacturer’s suggested retail price o f $ 40.00? Answers
A) $ 10.00 B) $ 11.20 C) $ 22.40 D) $ 16.00 E) $ 18.00 | <gadget id="calculator">100 - 20</gadget>
<output>80</output>
<gadget id="calculator">80 / 100</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">100 - 30</gadget>
<output>70</output>
<gadget id="calculator">70 / 100</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">(7/10) * 40</gadget>
<output>28</output>
<gadget id="calculator">(4/5) * 28</gadget>
<output>112/5 = around 22.4</output>
<result>C</result> | C | 22.4 | A pet store regularly sells pet food at a discount of 10 percent to 30 percent from the manufacturer’s suggested retail price. If during a sale, the store discounts an additional 20 percent from the discount price, what would be the lowest possible price of a container of pet food that had a manufacturer’s suggested retail price o f $ 40.00? | {
"A": "$ 10.00",
"B": "$ 11.20",
"C": "$ 22.40",
"D": "$ 16.00",
"E": "$ 18.00"
} | multiply(divide(subtract(const_100, 20), const_100), multiply(divide(subtract(const_100, 30), const_100), 40.00)) | subtract(const_100,n2)|subtract(const_100,n1)|divide(#0,const_100)|divide(#1,const_100)|multiply(n3,#3)|multiply(#2,#4)| | "for retail price = $ 40 first maximum discounted price = 40 - 30 % of 40 = 40 - 12 = 28 price after additional discount of 20 % = 28 - 20 % of 28 = 28 - 5.6 = 22.4 answer : option c" | gain |
math_qa__IPaecZ7rNDmrUIuN | The perimeter of an equilateral triangle is 60. If one of the sides of the equilateral triangle is the side of an isosceles triangle of perimeter 45, then how long is the base of isosceles triangle? Pick one
A) 5 units
B) 10 units
C) 15 units
D) 20 units
E) 25 units | <gadget id="calculator">60 / 3</gadget>
<output>20</output>
<gadget id="calculator">45 - 20</gadget>
<output>25</output>
<gadget id="calculator">25 - 20</gadget>
<output>5</output>
<result>A</result> | A | 5 | The perimeter of an equilateral triangle is 60. If one of the sides of the equilateral triangle is the side of an isosceles triangle of perimeter 45, then how long is the base of isosceles triangle? | {
"A": "5 units",
"B": "10 units",
"C": "15 units",
"D": "20 units",
"E": "25 units"
} | subtract(subtract(45, divide(60, const_3)), divide(60, const_3)) | divide(n0,const_3)|subtract(n1,#0)|subtract(#1,#0)| | "the base of the isosceles triangle is 45 - 20 - 20 = 5 units the answer is a ." | geometry |
math_qa__uCEe47uW00U9xI6S | A small table has a length of 12 inches and a breadth of b inches. Cubes are placed on the surface of the table so as to cover the entire surface. The maximum side of such cubes is found to be 4 inches. Also, a few such tables are arranged to form a square. The minimum length of side possible for such a square is 80 inches. Find b. Choose the correct choice from the following options
A) 8 B) 16 C) 24 D) 32 E) 48 | <gadget id="calculator">80 / 4</gadget>
<output>20</output>
<gadget id="calculator">20 ** 2</gadget>
<output>400</output>
<gadget id="calculator">12 ** 2</gadget>
<output>144</output>
<gadget id="calculator">400 - 144</gadget>
<output>256</output>
<gadget id="calculator">256 ** (1/2)</gadget>
<output>16</output>
<result>B</result> | B | 16 | A small table has a length of 12 inches and a breadth of b inches. Cubes are placed on the surface of the table so as to cover the entire surface. The maximum side of such cubes is found to be 4 inches. Also, a few such tables are arranged to form a square. The minimum length of side possible for such a square is 80 inches. Find b. | {
"A": "8",
"B": "16",
"C": "24",
"D": "32",
"E": "48"
} | sqrt(subtract(power(divide(80, 4), const_2), power(12, const_2))) | divide(n2,n1)|power(n0,const_2)|power(#0,const_2)|subtract(#2,#1)|sqrt(#3) | from the info that the maximum sides of the cubes is 4 , we know that the gcf of 12 ( = 2 ^ 2 * 3 ) andbis 4 ( = 2 ^ 2 ) , sob = 2 ^ x , where x > = 2 . from the second premise , we know that the lcm of 12 ( 2 ^ 2 * 3 ) andbis 80 ( 2 ^ 4 * 5 ) , sob = 2 ^ 4 or 2 ^ 4 * 5 ( 16 or 80 ) . combining 2 premises shows the answer is b ( 16 ) . | geometry |
math_qa__3PdUgyPWwEhqPwe2 | Calculate the ratio between x and y if 25% of x equal to 40% of y? Pick one
A) 5 : 8
B) 5 : 9
C) 5 : 7
D) 5 : 6
E) 5 : 4 | <gadget id="calculator">25 / 40</gadget>
<output>5/8 = around 0.625</output>
<result>A</result> | A | 0.625 | Calculate the ratio between x and y if 25% of x equal to 40% of y? | {
"A": "5 : 8",
"B": "5 : 9",
"C": "5 : 7",
"D": "5 : 6",
"E": "5 : 4"
} | divide(25, 40) | divide(n0,n1)| | "explanation : 25 x = 40 y x : y = 25 : 40 = 5 : 8 answer : a" | general |
math_qa__Td5lL1JoqpPS9svq | If √10 = 3.16, find the value of If √5/2 Pick one: A) 1.3 B) 1.58 C) 2.03 D) 2.15 E) 3.15 | <gadget id="calculator">5 / 2</gadget>
<output>5/2 = around 2.5</output>
<gadget id="calculator">(5/2) ** (1/2)</gadget>
<output>sqrt(10)/2 = around 1.581139</output>
<result>B</result> | B | 1.58 | If √10 = 3.16, find the value of If √5/2 | {
"A": "1.3",
"B": "1.58",
"C": "2.03",
"D": "2.15",
"E": "3.15"
} | sqrt(divide(5, 2)) | divide(n2,n3)|sqrt(#0) | explanation : √ ( 5 / 2 ) = √ ( 5 × 2 / 2 × 2 ) = √ ( 10 ) / 2 = 3.16 / 2 = 1.58 answer : b | general |
math_qa__ZSb7TG53QXMVHogw | 30 men can do a work in 40 days. When should 12 men leave the work so that the entire work is completed in 40 days after they leave the work? Choose the correct choice from the following answers
A) 18 days B) 10 days C) 55 days D) 44 days E) 22 days | <gadget id="calculator">30 * 40</gadget>
<output>1_200</output>
<gadget id="calculator">40 * 12</gadget>
<output>480</output>
<gadget id="calculator">1_200 - 480</gadget>
<output>720</output>
<gadget id="calculator">720 / 40</gadget>
<output>18</output>
<result>A</result> | A | 18 | 30 men can do a work in 40 days. When should 12 men leave the work so that the entire work is completed in 40 days after they leave the work? | {
"A": "18 days",
"B": "10 days",
"C": "55 days",
"D": "44 days",
"E": "22 days"
} | divide(subtract(multiply(30, 40), multiply(40, 12)), 40) | multiply(n0,n1)|multiply(n1,n2)|subtract(#0,#1)|divide(#2,n1)| | "total work to be done = 30 * 40 = 1200 let 12 men leave the work after ' p ' days , so that the remaining work is completed in 40 days after they leave the work . 40 p + ( 12 * 40 ) = 1200 40 p = 720 = > p = 18 days answer : a" | physics |
math_qa__xVmgffBC3PhJrkoC | Carrie likes to buy t-shirts at the local clothing store. They cost $9.65 each. One day, she bought 12 t-shirts. How much money did she spend? Choose the most appropriate option: A) $ 115.8 B) $ 248.75 C) $ 200 D) $ 171.6 E) $ 190 | <gadget id="calculator">12 * 9.65</gadget>
<output>115.8</output>
<gadget id="calculator">floor(115.8)</gadget>
<output>115</output>
<result>A</result> | A | 115.8 | Carrie likes to buy t-shirts at the local clothing store. They cost $9.65 each. One day, she bought 12 t-shirts. How much money did she spend? | {
"A": "$ 115.8",
"B": "$ 248.75",
"C": "$ 200",
"D": "$ 171.6",
"E": "$ 190"
} | floor(multiply(12, 9.65)) | multiply(n0,n1)|floor(#0)| | $ 9.65 * 12 = $ 115.8 . answer is a . | general |
math_qa__ds7cXN4HMjWaigWa | Kanul spent $3000 in buying raw materials, $1000 in buying machinery and 30% of the total amount he had as cash with him. What was the total amount? Choose the correct choice from the following answers.
A) $ 5825.16 B) $ 5725.26 C) $ 5714.28 D) $ 5912.52 E) $ 5614.46 | <gadget id="calculator">3_000 + 1_000</gadget>
<output>4_000</output>
<gadget id="calculator">30 / 100</gadget>
<output>3/10 = around 0.3</output>
<gadget id="calculator">1 - (3/10)</gadget>
<output>7/10 = around 0.7</output>
<gadget id="calculator">4_000 / (7/10)</gadget>
<output>40_000/7 = around 5_714.285714</output>
<result>C</result> | C | 5,714.28 | Kanul spent $3000 in buying raw materials, $1000 in buying machinery and 30% of the total amount he had as cash with him. What was the total amount? | {
"A": "$ 5825.16",
"B": "$ 5725.26",
"C": "$ 5714.28",
"D": "$ 5912.52",
"E": "$ 5614.46"
} | divide(add(3000, 1000), subtract(const_1, divide(30, const_100))) | add(n0,n1)|divide(n2,const_100)|subtract(const_1,#1)|divide(#0,#2)| | "let the total amount be x then , ( 100 - 30 ) % of x = 3000 + 1000 70 % of x = 4000 70 x / 100 = 4000 x = $ 40000 / 7 x = $ 5714.28 answer is c" | gain |
math_qa__imAFy6MS6Mdy8e7V | Two trains 110 meters and 200 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet? Choose one: A) 4.85 B) 7.69 C) 6.85 D) 5.85 E) 6.15 | <gadget id="calculator">110 + 200</gadget>
<output>310</output>
<gadget id="calculator">80 + 65</gadget>
<output>145</output>
<gadget id="calculator">10 / 36</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">145 * (5/18)</gadget>
<output>725/18 = around 40.277778</output>
<gadget id="calculator">310 / (725/18)</gadget>
<output>1_116/145 = around 7.696552</output>
<result>B</result> | B | 7.69 | Two trains 110 meters and 200 meters in length respectively are running in opposite directions, one at the rate of 80 km and the other at the rate of 65 kmph. In what time will they be completely clear of each other from the moment they meet? | {
"A": "4.85",
"B": "7.69",
"C": "6.85",
"D": "5.85",
"E": "6.15"
} | divide(add(110, 200), multiply(add(80, 65), const_0_2778)) | add(n0,n1)|add(n2,n3)|multiply(#1,const_0_2778)|divide(#0,#2)| | "t = ( 110 + 200 ) / ( 80 + 65 ) * 18 / 5 t = 7.69 answer : b" | physics |
math_qa__IKf75M1Qu3ub7LQt | How many 1/10s are there in 37 1/2? Choose the correct choice from the following answers: A) 375 B) 475 C) 500 D) 670 E) 700 | <gadget id="calculator">1 / 2</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">37 + (1/2)</gadget>
<output>75/2 = around 37.5</output>
<gadget id="calculator">1 / 10</gadget>
<output>1/10 = around 0.1</output>
<gadget id="calculator">(75/2) / (1/10)</gadget>
<output>375</output>
<result>A</result> | A | 375 | How many 1/10s are there in 37 1/2? | {
"A": "375",
"B": "475",
"C": "500",
"D": "670",
"E": "700"
} | divide(add(37, divide(1, 2)), divide(1, 10)) | divide(n0,n4)|divide(n0,n1)|add(n2,#0)|divide(#2,#1)| | "required number = ( 75 / 2 ) / ( 1 / 10 ) = ( 75 / 2 x 10 / 1 ) = 375 . answer : a" | general |
math_qa__jo1TrqlLe41XuRxw | A circle graph shows how the MegaTech corporation allocates its Research and Development budget: 12% microphotonics; 24% home electronics; 15% food additives; 29% genetically modified microorganisms; 8% industrial lubricants; and the remainder for basic astrophysics. If the arc of each sector of the graph is proportional to the percentage of the budget it represents, how many degrees of the circle are used to represent basic astrophysics research? Choices
A) 43 ° B) 10 ° C) 18 ° D) 36 ° E) 52 ° | <gadget id="calculator">12 + 24</gadget>
<output>36</output>
<gadget id="calculator">36 + 15</gadget>
<output>51</output>
<gadget id="calculator">51 + 29</gadget>
<output>80</output>
<gadget id="calculator">80 + 8</gadget>
<output>88</output>
<gadget id="calculator">100 - 88</gadget>
<output>12</output>
<gadget id="calculator">3_600 / 10</gadget>
<output>360</output>
<gadget id="calculator">12 * 360</gadget>
<output>4_320</output>
<gadget id="calculator">4_320 / 100</gadget>
<output>216/5 = around 43.2</output>
<result>A</result> | A | 43 | A circle graph shows how the MegaTech corporation allocates its Research and Development budget: 12% microphotonics; 24% home electronics; 15% food additives; 29% genetically modified microorganisms; 8% industrial lubricants; and the remainder for basic astrophysics. If the arc of each sector of the graph is proportional to the percentage of the budget it represents, how many degrees of the circle are used to represent basic astrophysics research? | {
"A": "43 °",
"B": "10 °",
"C": "18 °",
"D": "36 °",
"E": "52 °"
} | divide(multiply(subtract(const_100, add(add(add(add(12, 24), 15), 29), 8)), divide(const_3600, const_10)), const_100) | add(n0,n1)|divide(const_3600,const_10)|add(n2,#0)|add(n3,#2)|add(n4,#3)|subtract(const_100,#4)|multiply(#1,#5)|divide(#6,const_100)| | "here all percentage when summed we need to get 100 % . as per data 12 + 24 + 15 + 29 + 8 = 88 % . so remaining 12 % is the balance for the astrophysics . since this is a circle all percentage must be equal to 360 degrees . 100 % - - - - 360 degrees then 12 % will be 43 degrees . . imo option a ." | gain |
math_qa__3CMpYZ30xeMG6mrY | In a box of 8 pens, a total of 3 are defective. If a customer buys 2 pens selected at random from the box, what is the probability that neither pen will be defective?
Choose the correct choice from the following
A) 2 / 10
B) 3 / 11
C) 4 / 13
D) 5 / 14
E) 6 / 17 | <gadget id="calculator">8 - 3</gadget>
<output>5</output>
<gadget id="calculator">5 / 8</gadget>
<output>5/8 = around 0.625</output>
<gadget id="calculator">5 - 1</gadget>
<output>4</output>
<gadget id="calculator">8 - 1</gadget>
<output>7</output>
<gadget id="calculator">4 / 7</gadget>
<output>4/7 = around 0.571429</output>
<gadget id="calculator">(5/8) * (4/7)</gadget>
<output>5/14 = around 0.357143</output>
<result>D</result> | D | 0.357143 | In a box of 8 pens, a total of 3 are defective. If a customer buys 2 pens selected at random from the box, what is the probability that neither pen will be defective? | {
"A": "2 / 10",
"B": "3 / 11",
"C": "4 / 13",
"D": "5 / 14",
"E": "6 / 17"
} | multiply(divide(subtract(8, 3), 8), divide(subtract(subtract(8, 3), const_1), subtract(8, const_1))) | subtract(n0,n1)|subtract(n0,const_1)|divide(#0,n0)|subtract(#0,const_1)|divide(#3,#1)|multiply(#2,#4)| | "p ( neither pen is defective ) = 5 / 8 * 4 / 7 = 5 / 14 the answer is d ." | general |
math_qa__O6CLLh4ibH5t5oHt | In filling a room with gas 100 m * 10 m * 10 m the volumes of gas will be? Choose the correct choice from the following options: A) 100 cu . m B) 1000 cu . m C) 10000 cu . m D) 100000 cu . m E) 10000000 cu . m | <gadget id="calculator">100 * 10 * 10</gadget>
<output>10_000</output>
<result>C</result> | C | 10,000 | In filling a room with gas 100 m * 10 m * 10 m the volumes of gas will be? | {
"A": "100 cu . m",
"B": "1000 cu . m",
"C": "10000 cu . m",
"D": "100000 cu . m",
"E": "10000000 cu . m"
} | volume_rectangular_prism(100, 10, 10) | volume_rectangular_prism(n0,n1,n1) | 100 * 10 * 10 = 10000 answer : c | physics |
math_qa__GLDbOiWhGag0mBV3 | A right triangle is inscribed in a circle. The legs of the triangle have lengths 6 and 8. What is the diameter of the circle? Choose the correct option.
A) 8 B) 8 π C) 9 √ 3 D) 10 E) 12 | <gadget id="calculator">6 ** 2</gadget>
<output>36</output>
<gadget id="calculator">8 ** 2</gadget>
<output>64</output>
<gadget id="calculator">36 + 64</gadget>
<output>100</output>
<gadget id="calculator">100 ** (1/2)</gadget>
<output>10</output>
<result>D</result> | D | 10 | A right triangle is inscribed in a circle. The legs of the triangle have lengths 6 and 8. What is the diameter of the circle? | {
"A": "8",
"B": "8 π",
"C": "9 √ 3",
"D": "10",
"E": "12"
} | sqrt(add(power(6, const_2), power(8, const_2))) | power(n0,const_2)|power(n1,const_2)|add(#0,#1)|sqrt(#2) | property of a right triangle inscribed in a circle is that when an angle is made from diameter of the circle , it is a right triangle . or if a right triangle is made inscribed in a circle , its its longest side is the diameter of the circle . hence diameter = ( 6 ^ 2 + 8 ^ 2 ) ^ 1 / 2 = 10 d is the answer | geometry |
math_qa__RKxonRAIrYOHPX8k | If k is an integer and 0.0010101 x 10^k is greater than 10, what is the least possible value of k? Choose the correct answer.
A) 2 B) 3 C) 4 D) 5 E) 6 | <gadget id="calculator">10 / 0.00101</gadget>
<output>9_900.990099</output>
<gadget id="calculator">log(9_900.990099)</gadget>
<output>9.20039</output>
<gadget id="calculator">log(10)</gadget>
<output>log(10) = around 2.302585</output>
<gadget id="calculator">9.20039 / log(10)</gadget>
<output>9.20039/log(10) = around 3.995679</output>
<result>C</result> | C | 4 | If k is an integer and 0.0010101 x 10^k is greater than 10, what is the least possible value of k? | {
"A": "2",
"B": "3",
"C": "4",
"D": "5",
"E": "6"
} | divide(log(divide(10, 0.0010101)), log(10)) | divide(n2,n0)|log(n1)|log(#0)|divide(#2,#1)| | "0.0010101 * 10 ^ k > 10 we need to move the decimal point to the right 4 places to get 10.101 this is equivalent to multiplying by 10 ^ 4 . the answer is c ." | general |
math_qa__t7TklXFobxCrtkKe | If a and b are positive integers and (3^a)^b = 3^3, what is the value of 3^a*3^b? Choose the correct choice from the following choices.
A) 3 B) 9 C) 81 D) 27 E) 243 | <gadget id="calculator">3 ** 3</gadget>
<output>27</output>
<gadget id="calculator">27 * 3</gadget>
<output>81</output>
<result>C</result> | C | 81 | If a and b are positive integers and (3^a)^b = 3^3, what is the value of 3^a*3^b? | {
"A": "3",
"B": "9",
"C": "81",
"D": "27",
"E": "243"
} | multiply(power(3, 3), 3) | power(n0,n0)|multiply(n0,#0) | 3 ^ ab = 3 ^ 3 therefore ab = 3 either a = 1 or 3 or b = 3 or 1 therefore 3 ^ a * 3 ^ b = 3 ^ ( a + b ) = 3 ^ 4 = 81 c | general |
math_qa__zdGMl9Rcnxeu7tmB | A gardener is going to plant 2 red rosebushes and 2 white rosebushes. If the gardener is to select each of the bushes at random, one at a time, and plant them in a row, what is the probability that the 2 rosebushes in the middle of the row will be the red rosebushes? Select.
A) 1 / 12 B) 1 / 6 C) 1 / 5 D) 1 / 3 E) ½ | <gadget id="calculator">2 + 2</gadget>
<output>4</output>
<gadget id="calculator">binomial(4, 2)</gadget>
<output>6</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<result>B</result> | B | 0.166667 | A gardener is going to plant 2 red rosebushes and 2 white rosebushes. If the gardener is to select each of the bushes at random, one at a time, and plant them in a row, what is the probability that the 2 rosebushes in the middle of the row will be the red rosebushes? | {
"A": "1 / 12",
"B": "1 / 6",
"C": "1 / 5",
"D": "1 / 3",
"E": "½"
} | divide(const_1, choose(add(2, 2), 2)) | add(n0,n0)|choose(#0,n0)|divide(const_1,#1) | we are asked to find the probability of one particular pattern : wrrw . total # of ways a gardener can plant these four bushes is the # of permutations of 4 letters wwrr , out of which 2 w ' s and 2 r ' s are identical , so 4 ! / 2 ! 2 ! = 6 ; so p = 1 / 6 answer : b . | probability |
math_qa__zGApHSYZhVBGGLHF | What will be the LCM of 8, 24, 36 and 54 Choose the correct choice from the following: A) 54 B) 108 C) 216 D) 432 E) none of these | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">4 * 2</gadget>
<output>8</output>
<gadget id="calculator">8 * 3</gadget>
<output>24</output>
<gadget id="calculator">24 * 3</gadget>
<output>72</output>
<gadget id="calculator">72 * 3</gadget>
<output>216</output>
<result>C</result> | C | 216 | What will be the LCM of 8, 24, 36 and 54 | {
"A": "54",
"B": "108",
"C": "216",
"D": "432",
"E": "none of these"
} | multiply(multiply(multiply(multiply(multiply(const_2, const_2), const_2), const_3), const_3), const_3) | multiply(const_2,const_2)|multiply(#0,const_2)|multiply(#1,const_3)|multiply(#2,const_3)|multiply(#3,const_3) | explanation : lcm of 8 - 24 - 36 - 54 will be 2 * 2 * 2 * 3 * 3 * 3 = 216 answer : option c | physics |
math_qa__yQGCwBpdcy3eA3p9 | A number exceeds by 35 from its 3/8 part. Then the number is? Choose one:
A) 56
B) 35
C) 39
D) 40
E) 45 | <gadget id="calculator">35 * 8</gadget>
<output>280</output>
<gadget id="calculator">8 - 3</gadget>
<output>5</output>
<gadget id="calculator">280 / 5</gadget>
<output>56</output>
<result>A</result> | A | 56 | A number exceeds by 35 from its 3/8 part. Then the number is? | {
"A": "56",
"B": "35",
"C": "39",
"D": "40",
"E": "45"
} | divide(multiply(35, 8), subtract(8, 3)) | multiply(n0,n2)|subtract(n2,n1)|divide(#0,#1)| | "x – 3 / 8 x = 35 x = 56 answer : a" | general |
math_qa__8LfBMXVnmVY0T3Z0 | If 0.75: x :: 5:6, then x is equal to:
Pick:
A) 1.12
B) 1.16
C) 1.2
D) 0.9
E) none of these | <gadget id="calculator">0.75 * 6</gadget>
<output>4.5</output>
<gadget id="calculator">4.5 / 5</gadget>
<output>0.9</output>
<result>D</result> | D | 0.9 | If 0.75: x :: 5:6, then x is equal to: | {
"A": "1.12",
"B": "1.16",
"C": "1.2",
"D": "0.9",
"E": "none of these"
} | divide(multiply(0.75, 6), 5) | multiply(n0,n2)|divide(#0,n1)| | "explanation : ( x * 5 ) = ( 0.75 * 6 ) x = 4.5 / 5 = 0.9 answer : d" | general |
math_qa__AJHKsuISJdSeVjRO | Two trains of equal lengths take 10 sec and 14 sec respectively to cross a telegraph post. If the length of each train be 120 m, in what time will they cross other travelling in opposite direction? Choose the correct choice from the following:
A) 10 B) 12 C) 13 D) 11.7 E) 15 | <gadget id="calculator">120 * 2</gadget>
<output>240</output>
<gadget id="calculator">120 / 14</gadget>
<output>60/7 = around 8.571429</output>
<gadget id="calculator">120 / 10</gadget>
<output>12</output>
<gadget id="calculator">(60/7) + 12</gadget>
<output>144/7 = around 20.571429</output>
<gadget id="calculator">240 / (144/7)</gadget>
<output>35/3 = around 11.666667</output>
<result>D</result> | D | 11.7 | Two trains of equal lengths take 10 sec and 14 sec respectively to cross a telegraph post. If the length of each train be 120 m, in what time will they cross other travelling in opposite direction? | {
"A": "10",
"B": "12",
"C": "13",
"D": "11.7",
"E": "15"
} | divide(multiply(120, const_2), add(speed(120, 14), speed(120, 10))) | multiply(n2,const_2)|speed(n2,n1)|speed(n2,n0)|add(#1,#2)|divide(#0,#3)| | "speed of the first train = 120 / 10 = 12 m / sec . speed of the second train = 120 / 14 = 8.6 m / sec . relative speed = 12 + 8.6 = 20.6 m / sec . required time = ( 120 + 120 ) / 20.6 = 11.7 sec . answer : option d" | physics |
math_qa__nQJVI9hMrzBx3m8t | Four equal circles are described about the four corners of a square so that each touches two of the others. If a side of the square is 14 cm, then the area enclosed between the circumferences of the circles is : Choose the correct answer.
A) 24 cm 2 B) 42 cm 2 C) 154 cm 2 D) 196 cm 2 E) none of these | <gadget id="calculator">14 ** 2</gadget>
<output>196</output>
<gadget id="calculator">14 / 2</gadget>
<output>7</output>
<gadget id="calculator">pi * (7 ** 2)</gadget>
<output>49*pi = around 153.93804</output>
<gadget id="calculator">196 - (49*pi)</gadget>
<output>196 - 49*pi = around 42.06196</output>
<result>B</result> | B | 42 | Four equal circles are described about the four corners of a square so that each touches two of the others. If a side of the square is 14 cm, then the area enclosed between the circumferences of the circles is : | {
"A": "24 cm 2",
"B": "42 cm 2",
"C": "154 cm 2",
"D": "196 cm 2",
"E": "none of these"
} | subtract(square_area(14), circle_area(divide(14, const_2))) | divide(n0,const_2)|square_area(n0)|circle_area(#0)|subtract(#1,#2) | the shaded area gives the required region . area of the shaded region = area of the square – area of four quadrants of the circles = ( 14 ) 2 - 4 × 1 ⁄ 4 π ( 7 ) 2 = 196 - 22 ⁄ 7 × 49 = 196 - 154 = 42 cm 2 answer b | geometry |
math_qa__F31NOyYoebTq8eGS | If the annual increase in the population of a town is 10% and the present number of people is 10000, what will the population be in 2 years? Pick one:
A) 12100
B) 15240
C) 12456
D) 11452
E) 10002 | <gadget id="calculator">10 + 100</gadget>
<output>110</output>
<gadget id="calculator">110 / 100</gadget>
<output>11/10 = around 1.1</output>
<gadget id="calculator">(11/10) * 10_000</gadget>
<output>11_000</output>
<gadget id="calculator">11_000 * (11/10)</gadget>
<output>12_100</output>
<result>A</result> | A | 12,100 | If the annual increase in the population of a town is 10% and the present number of people is 10000, what will the population be in 2 years? | {
"A": "12100",
"B": "15240",
"C": "12456",
"D": "11452",
"E": "10002"
} | multiply(multiply(divide(add(10, const_100), const_100), 10000), divide(add(10, const_100), const_100)) | add(n0,const_100)|divide(#0,const_100)|multiply(n1,#1)|multiply(#1,#2)| | "the required population is = 10000 ( 1 + 10 / 100 ) ^ 2 = 10000 * 11 / 10 * 11 / 10 = 12100 answer is a" | gain |
math_qa__GawQL30K7HTDU7H2 | A certain company’s profit in 1996 was 15 percent greater than its profit in 1995, and its profit in 1997 was 35 percent greater than its profit in 1996. The company’s profit in 1997 was what percent greater than its profit in 1995?
Select the correct option.
A) 5 % B) 18 % C) 33 % D) 35 % E) 55.25 % | <gadget id="calculator">35 / 100</gadget>
<output>7/20 = around 0.35</output>
<gadget id="calculator">(7/20) + 1</gadget>
<output>27/20 = around 1.35</output>
<gadget id="calculator">15 / 100</gadget>
<output>3/20 = around 0.15</output>
<gadget id="calculator">1 + (3/20)</gadget>
<output>23/20 = around 1.15</output>
<gadget id="calculator">(27/20) * (23/20)</gadget>
<output>621/400 = around 1.5525</output>
<gadget id="calculator">(621/400) - 1</gadget>
<output>221/400 = around 0.5525</output>
<gadget id="calculator">(221/400) * 100</gadget>
<output>221/4 = around 55.25</output>
<result>E</result> | E | 55.25 | A certain company’s profit in 1996 was 15 percent greater than its profit in 1995, and its profit in 1997 was 35 percent greater than its profit in 1996. The company’s profit in 1997 was what percent greater than its profit in 1995? | {
"A": "5 %",
"B": "18 %",
"C": "33 %",
"D": "35 %",
"E": "55.25 %"
} | multiply(subtract(multiply(add(divide(35, const_100), const_1), add(const_1, divide(15, const_100))), const_1), const_100) | divide(n4,const_100)|divide(n1,const_100)|add(#0,const_1)|add(#1,const_1)|multiply(#2,#3)|subtract(#4,const_1)|multiply(#5,const_100)| | "profit in 1995 - 100 profit in 1996 - 115 % increae profit in 1997 in comparison to 1995 = 15 + 115 * 35 % = 55.25 correct option : e" | gain |
math_qa__YldU5LnYiJ34aP6i | A, B and C started a partnership business by investing Rs.12000, Rs.16000, Rs.20000 respectively. At the end of the year , the profit were distributed among them. If C's share of profit is 36000, What is the total profit?
Choose the correct choice: A) 70000 B) 60000 C) 86400 D) 90000 E) 50000 | <gadget id="calculator">12_000 / 20_000</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">(3/5) * 36_000</gadget>
<output>21_600</output>
<gadget id="calculator">16_000 / 20_000</gadget>
<output>4/5 = around 0.8</output>
<gadget id="calculator">(4/5) * 36_000</gadget>
<output>28_800</output>
<gadget id="calculator">21_600 + 28_800</gadget>
<output>50_400</output>
<gadget id="calculator">50_400 + 36_000</gadget>
<output>86_400</output>
<result>C</result> | C | 86,400 | A, B and C started a partnership business by investing Rs.12000, Rs.16000, Rs.20000 respectively. At the end of the year , the profit were distributed among them. If C's share of profit is 36000, What is the total profit? | {
"A": "70000",
"B": "60000",
"C": "86400",
"D": "90000",
"E": "50000"
} | add(add(multiply(divide(12000, 20000), 36000), multiply(divide(16000, 20000), 36000)), 36000) | divide(n0,n2)|divide(n1,n2)|multiply(n3,#0)|multiply(n3,#1)|add(#2,#3)|add(n3,#4)| | "a : b : c = 12000 : 16000 : 20000 = 3 : 4 : 5 let total profit = p then p ã — 5 / 12 = 36000 p = ( 36000 ã — 12 ) / 5 = 86400 answer is c ." | gain |
math_qa__jXazXuknw8ccK9AY | Sarah operated her lemonade stand Monday through Friday over a two week period and made a total profit of 450 dollars. On hot days she sold cups of lemonade for a price that was 25 percent higher than the regular days. Each cup she sold had a total cost of 75 cents and Sarah did not incur any other costs. If every day she sold exactly 32 cups and 3 of the days were hot, then what was the price of 1 cup on a hot day? Choose the correct option:
A) $ 1.50 B) $ 1.88 C) $ 2.25 D) $ 2.50 E) $ 3.25 | <gadget id="calculator">75 / 100</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">32 * (3/4)</gadget>
<output>24</output>
<gadget id="calculator">4 + 1</gadget>
<output>5</output>
<gadget id="calculator">5 * 2</gadget>
<output>10</output>
<gadget id="calculator">24 * 10</gadget>
<output>240</output>
<gadget id="calculator">240 + 450</gadget>
<output>690</output>
<gadget id="calculator">10 - 3</gadget>
<output>7</output>
<gadget id="calculator">7 * 32</gadget>
<output>224</output>
<gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">125 / 100</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(5/4) * 3</gadget>
<output>15/4 = around 3.75</output>
<gadget id="calculator">(15/4) * 32</gadget>
<output>120</output>
<gadget id="calculator">224 + 120</gadget>
<output>344</output>
<gadget id="calculator">690 / 344</gadget>
<output>345/172 = around 2.005814</output>
<gadget id="calculator">(345/172) * (5/4)</gadget>
<output>1_725/688 = around 2.507267</output>
<result>D</result> | D | 2.5 | Sarah operated her lemonade stand Monday through Friday over a two week period and made a total profit of 450 dollars. On hot days she sold cups of lemonade for a price that was 25 percent higher than the regular days. Each cup she sold had a total cost of 75 cents and Sarah did not incur any other costs. If every day she sold exactly 32 cups and 3 of the days were hot, then what was the price of 1 cup on a hot day? | {
"A": "$ 1.50",
"B": "$ 1.88",
"C": "$ 2.25",
"D": "$ 2.50",
"E": "$ 3.25"
} | multiply(divide(add(multiply(multiply(32, divide(75, const_100)), multiply(add(const_4, const_1), const_2)), 450), add(multiply(subtract(multiply(add(const_4, const_1), const_2), 3), 32), multiply(multiply(divide(add(const_100, 25), const_100), 3), 32))), divide(add(const_100, 25), const_100)) | add(const_1,const_4)|add(n1,const_100)|divide(n2,const_100)|divide(#1,const_100)|multiply(n3,#2)|multiply(#0,const_2)|multiply(#4,#5)|multiply(n4,#3)|subtract(#5,n4)|add(n0,#6)|multiply(n3,#8)|multiply(n3,#7)|add(#10,#11)|divide(#9,#12)|multiply(#13,#3) | 7 regular days - - > sales = 7 * 32 * x = 224 x ; 3 hot days - - > sales = 3 * 32 * ( 1.25 x ) = 120 x ; total sales = 224 x + 120 x = 344 x . total cost = 10 * 32 * 0.75 = 240 . profit = 344 x - 240 = 450 - - > x = 2 . 1.25 x = ~ 2.50 . answer : d . | gain |
math_qa__udXPjrPA7yzuL7M6 | At Sandi’s Pet Shop, 25 cups of bird seed are used every 5 days to feed 15 parakeets. How many cups of bird seed would be required to feed 14 parakeets for 7 days?
Select the correct option.
A) 40.5 B) 32.34 C) 6.23 D) 9 E) 15 | <gadget id="calculator">14 * 25</gadget>
<output>350</output>
<gadget id="calculator">350 * 7</gadget>
<output>2_450</output>
<gadget id="calculator">5 * 15</gadget>
<output>75</output>
<gadget id="calculator">2_450 / 75</gadget>
<output>98/3 = around 32.666667</output>
<result>B</result> | B | 32.34 | At Sandi’s Pet Shop, 25 cups of bird seed are used every 5 days to feed 15 parakeets. How many cups of bird seed would be required to feed 14 parakeets for 7 days? | {
"A": "40.5",
"B": "32.34",
"C": "6.23",
"D": "9",
"E": "15"
} | divide(multiply(multiply(14, 25), 7), multiply(5, 15)) | multiply(n0,n3)|multiply(n1,n2)|multiply(n4,#0)|divide(#2,#1) | let ' s go step - by - step . 25 cups are used over a 5 day period , which means 5 cups a day . this feeds 15 parakeets , which means each parakeet needs 1 / 3 of a cup every day . for 14 parakeets , we need 14 * 1 / 3 cups = 4.62 cups a day . over 7 days , we need 32.34 cups . choice b . | physics |
math_qa__QBBwaCcgy2kP0pIU | There are 2 available positions and 50 candidates, one half of whom are democrats and another half are republicans. If it was decided that the positions would be filled at random, then what is the probability E that the both positions will be taken by members of just one party?
Select the correct option:
A) 1 / 25 B) 12 / 49 C) 1 / 4 D) 24 / 49 E) 1 / 2 | <gadget id="calculator">50 / 2</gadget>
<output>25</output>
<gadget id="calculator">25 - 1</gadget>
<output>24</output>
<gadget id="calculator">50 - 1</gadget>
<output>49</output>
<gadget id="calculator">24 / 49</gadget>
<output>24/49 = around 0.489796</output>
<gadget id="calculator">25 / 50</gadget>
<output>1/2 = around 0.5</output>
<gadget id="calculator">(24/49) * (1/2)</gadget>
<output>12/49 = around 0.244898</output>
<gadget id="calculator">(12/49) * 2</gadget>
<output>24/49 = around 0.489796</output>
<result>D</result> | D | 0.489796 | There are 2 available positions and 50 candidates, one half of whom are democrats and another half are republicans. If it was decided that the positions would be filled at random, then what is the probability E that the both positions will be taken by members of just one party? | {
"A": "1 / 25",
"B": "12 / 49",
"C": "1 / 4",
"D": "24 / 49",
"E": "1 / 2"
} | multiply(multiply(divide(subtract(divide(50, const_2), const_1), subtract(50, const_1)), divide(divide(50, const_2), 50)), 2) | divide(n1,const_2)|subtract(n1,const_1)|divide(#0,n1)|subtract(#0,const_1)|divide(#3,#1)|multiply(#4,#2)|multiply(n0,#5) | e probability of one party having both spots : ( 1 / 2 ) * ( 24 / 49 ) = 12 / 49 ( 1 / 2 ) or ( 25 / 50 ) because it does not matter which party or which person gets the first spot . ( 24 / 49 ) because after one person from a particular party is chosen , there are 24 members of the same party left out of 49 total candidates . since this result can happen for both parties , ( 12 / 49 ) + ( 12 / 49 ) = ( 24 / 49 ) answer : d | other |
math_qa__CQMBo9Wa7BI3uhst | Sonika deposited Rs.8000 which amounted to Rs.11200 after 3 years at simple interest. Had the interest been 2% more. She would get how much? Choose the correct answer:
A) 9680 B) 2277 C) 11680 D) 12068 E) 1212 | <gadget id="calculator">2 / 100</gadget>
<output>1/50 = around 0.02</output>
<gadget id="calculator">11_200 - 8_000</gadget>
<output>3_200</output>
<gadget id="calculator">3_200 / 3</gadget>
<output>3_200/3 = around 1_066.666667</output>
<gadget id="calculator">(3_200/3) / 8_000</gadget>
<output>2/15 = around 0.133333</output>
<gadget id="calculator">(1/50) + (2/15)</gadget>
<output>23/150 = around 0.153333</output>
<gadget id="calculator">(23/150) * 8_000</gadget>
<output>3_680/3 = around 1_226.666667</output>
<gadget id="calculator">(3_680/3) * 3</gadget>
<output>3_680</output>
<gadget id="calculator">3_680 + 8_000</gadget>
<output>11_680</output>
<result>C</result> | C | 11,680 | Sonika deposited Rs.8000 which amounted to Rs.11200 after 3 years at simple interest. Had the interest been 2% more. She would get how much? | {
"A": "9680",
"B": "2277",
"C": "11680",
"D": "12068",
"E": "1212"
} | add(multiply(multiply(add(divide(2, const_100), divide(divide(subtract(11200, 8000), 3), 8000)), 8000), 3), 8000) | divide(n3,const_100)|subtract(n1,n0)|divide(#1,n2)|divide(#2,n0)|add(#0,#3)|multiply(n0,#4)|multiply(n2,#5)|add(n0,#6)| | "( 8000 * 3 * 2 ) / 100 = 480 11200 - - - - - - - - 11680 answer : c" | gain |
math_qa__SvdbnoiLtUzkv8Fe | A manufacturer sells a pair of glasses to a wholesale dealer at a profit of 18%. The wholesaler sells the same to retailer at a profit of 20%. The retailer in turn sells them to a customer for Rs. 30.09, there by earning a profit of 25%. The cost price for the manufacturer is: Choose the most appropriate option.
A) rs . 15 B) rs . 16 C) rs . 17 D) rs . 18 E) rs . 19 | <gadget id="calculator">1 + 2</gadget>
<output>3</output>
<gadget id="calculator">20 / 2</gadget>
<output>10</output>
<gadget id="calculator">3 * 10</gadget>
<output>30</output>
<gadget id="calculator">3 * 3</gadget>
<output>9</output>
<gadget id="calculator">9 / 100</gadget>
<output>9/100 = around 0.09</output>
<gadget id="calculator">30 + (9/100)</gadget>
<output>3_009/100 = around 30.09</output>
<gadget id="calculator">100 + 25</gadget>
<output>125</output>
<gadget id="calculator">125 / 100</gadget>
<output>5/4 = around 1.25</output>
<gadget id="calculator">(3_009/100) / (5/4)</gadget>
<output>3_009/125 = around 24.072</output>
<gadget id="calculator">20 + 100</gadget>
<output>120</output>
<gadget id="calculator">120 / 100</gadget>
<output>6/5 = around 1.2</output>
<gadget id="calculator">(3_009/125) / (6/5)</gadget>
<output>1_003/50 = around 20.06</output>
<gadget id="calculator">100 + 18</gadget>
<output>118</output>
<gadget id="calculator">118 / 100</gadget>
<output>59/50 = around 1.18</output>
<gadget id="calculator">(1_003/50) / (59/50)</gadget>
<output>17</output>
<result>C</result> | C | 17 | A manufacturer sells a pair of glasses to a wholesale dealer at a profit of 18%. The wholesaler sells the same to retailer at a profit of 20%. The retailer in turn sells them to a customer for Rs. 30.09, there by earning a profit of 25%. The cost price for the manufacturer is: | {
"A": "rs . 15",
"B": "rs . 16",
"C": "rs . 17",
"D": "rs . 18",
"E": "rs . 19"
} | divide(divide(divide(add(multiply(add(const_1, const_2), divide(20, const_2)), divide(multiply(const_3, const_3), const_100)), divide(add(const_100, 25), const_100)), divide(add(20, const_100), const_100)), divide(add(const_100, 18), const_100)) | add(const_1,const_2)|add(n3,const_100)|add(n1,const_100)|add(n0,const_100)|divide(n1,const_2)|multiply(const_3,const_3)|divide(#5,const_100)|divide(#1,const_100)|divide(#2,const_100)|divide(#3,const_100)|multiply(#0,#4)|add(#6,#10)|divide(#11,#7)|divide(#12,#8)|divide(#13,#9) | let the cost price for the manufacturer be rs . x . then , 125 % of 120 % of 118 % of x = 30.09 . 125 / 100 * 120 / 100 * 118 / 100 * x = 3009 / 100 177 / 100 x = 3009 / 100 = > x = 17 answer : c | gain |
math_qa__AZzbYtmA6eUXmUlf | How long will a boy take to run round a square field of side 40 meters, if he runs at the rate of 12km/hr? Choose the most appropriate option.
A) 52 sec
B) 48 sec
C) 60 sec
D) 25 sec
E) 39 sec | <gadget id="calculator">40 * 4</gadget>
<output>160</output>
<gadget id="calculator">1_000 / 3_600</gadget>
<output>5/18 = around 0.277778</output>
<gadget id="calculator">12 * (5/18)</gadget>
<output>10/3 = around 3.333333</output>
<gadget id="calculator">160 / (10/3)</gadget>
<output>48</output>
<result>B</result> | B | 48 | How long will a boy take to run round a square field of side 40 meters, if he runs at the rate of 12km/hr? | {
"A": "52 sec",
"B": "48 sec",
"C": "60 sec",
"D": "25 sec",
"E": "39 sec"
} | divide(multiply(40, const_4), multiply(12, divide(const_1000, const_3600))) | divide(const_1000,const_3600)|multiply(n0,const_4)|multiply(n1,#0)|divide(#1,#2) | speed = 12 km / hr = 12 * 5 / 18 = 10 / 3 m / sec distance = 40 * 4 = 160 m time taken = 160 * 3 / 10 = 48 sec answer is b | gain |
math_qa__XnMiLXvKtRu7ezJi | The sum of the first 50 positive even integers is 2550. What is the sum of the even integers from 602 to 700 inclusive?
Select the correct option: A) 24,550 B) 28,550 C) 32,550 D) 36,550 E) 40,550 | <gadget id="calculator">700 + 602</gadget>
<output>1_302</output>
<gadget id="calculator">1_302 / 2</gadget>
<output>651</output>
<gadget id="calculator">700 - 602</gadget>
<output>98</output>
<gadget id="calculator">98 / 2</gadget>
<output>49</output>
<gadget id="calculator">49 + 1</gadget>
<output>50</output>
<gadget id="calculator">651 * 50</gadget>
<output>32_550</output>
<result>C</result> | C | 32,550 | The sum of the first 50 positive even integers is 2550. What is the sum of the even integers from 602 to 700 inclusive? | {
"A": "24,550",
"B": "28,550",
"C": "32,550",
"D": "36,550",
"E": "40,550"
} | multiply(divide(add(700, 602), const_2), add(divide(subtract(700, 602), const_2), const_1)) | add(n2,n3)|subtract(n3,n2)|divide(#1,const_2)|divide(#0,const_2)|add(#2,const_1)|multiply(#4,#3)| | "2 + 4 + 6 + 8 + . . . + 100 = 2550 602 + 604 + . . . + 700 = 50 ( 600 ) + ( 2 + 4 + . . . + 100 ) = 30,000 + 2550 = 32,550 the answer is c ." | general |
math_qa__xukisZiy6xfmuckr | The average runs scored by a batsman in 10 matches is 40. In the next 10 matches the batsman scored an average of 30 runs. Find his average in all the 20 matches? Choose the correct choice from the following options.
A) 31 B) 35 C) 88 D) 13 E) 12 | <gadget id="calculator">40 * 10</gadget>
<output>400</output>
<gadget id="calculator">30 * 10</gadget>
<output>300</output>
<gadget id="calculator">400 + 300</gadget>
<output>700</output>
<gadget id="calculator">10 + 10</gadget>
<output>20</output>
<gadget id="calculator">700 / 20</gadget>
<output>35</output>
<result>B</result> | B | 35 | The average runs scored by a batsman in 10 matches is 40. In the next 10 matches the batsman scored an average of 30 runs. Find his average in all the 20 matches? | {
"A": "31",
"B": "35",
"C": "88",
"D": "13",
"E": "12"
} | divide(add(multiply(40, 10), multiply(30, 10)), add(10, 10)) | add(n0,n2)|multiply(n0,n1)|multiply(n2,n3)|add(#1,#2)|divide(#3,#0)| | "total score of the batsman in 10 matches = 400 . total score of the batsman in the next 10 matches = 300 . total score of the batsman in the 20 matches = 700 . average score of the batsman = 700 / 20 = 35 . answer : b" | general |
math_qa__ROOwdqUMkk6GxxAg | There are 300 giraffes at a large zoo. The number of giraffes is 3 times the number of all the other animals combined. How many more giraffes are there than non giraffes animals at the zoo? Select the correct option:
A) 400 B) 360 C) 300 D) 290 E) 200 | <gadget id="calculator">300 / 3</gadget>
<output>100</output>
<gadget id="calculator">100 / 10</gadget>
<output>10</output>
<gadget id="calculator">300 - 10</gadget>
<output>290</output>
<result>D</result> | D | 290 | There are 300 giraffes at a large zoo. The number of giraffes is 3 times the number of all the other animals combined. How many more giraffes are there than non giraffes animals at the zoo? | {
"A": "400",
"B": "360",
"C": "300",
"D": "290",
"E": "200"
} | subtract(300, divide(divide(300, 3), const_10)) | divide(n0,n1)|divide(#0,const_10)|subtract(n0,#1) | answer is d . total giraffes = 300 = 3 * other animals ( x ) or x = 10 . so , difference in giraffes and x = 300 - 10 = 290 . | general |
math_qa__Kx8tnnoGziILjjny | Bucket A is 1/4 full of sand, and Bucket B, which has one-half the capacity of Bucket A, is 3/8 full of sand. Jana pours the contents of Bucket B into Bucket A. Bucket A is now filled to what fraction of its capacity? Choose the correct choice from the following options.
A) 3 / 8
B) 7 / 16
C) 1 / 2
D) 5 / 8
E) 7 / 8 | <gadget id="calculator">4 + 3</gadget>
<output>7</output>
<gadget id="calculator">8 * 2</gadget>
<output>16</output>
<gadget id="calculator">7 / 16</gadget>
<output>7/16 = around 0.4375</output>
<result>B</result> | B | 0.4375 | Bucket A is 1/4 full of sand, and Bucket B, which has one-half the capacity of Bucket A, is 3/8 full of sand. Jana pours the contents of Bucket B into Bucket A. Bucket A is now filled to what fraction of its capacity? | {
"A": "3 / 8",
"B": "7 / 16",
"C": "1 / 2",
"D": "5 / 8",
"E": "7 / 8"
} | divide(add(4, 3), multiply(8, const_2)) | add(n1,n2)|multiply(n3,const_2)|divide(#0,#1) | let capapcity of a = x sand = x / 4 capacity of b = x / 2 sand = 3 x / 16 a total = x / 4 + 3 x / 16 = 7 x / 16 answer : b | general |
math_qa__ZSG7K9hbHQvNmlWw | If n is an integer, f(n) = f(n-1) - n and f(4)=15. What is the value of f(6)? Choose the correct choice:
A) 4 B) 0 C) 1 D) 2 E) 24 | <gadget id="calculator">1 + 4</gadget>
<output>5</output>
<gadget id="calculator">15 - 5</gadget>
<output>10</output>
<gadget id="calculator">10 - 6</gadget>
<output>4</output>
<result>A</result> | A | 4 | If n is an integer, f(n) = f(n-1) - n and f(4)=15. What is the value of f(6)? | {
"A": "4",
"B": "0",
"C": "1",
"D": "2",
"E": "24"
} | subtract(subtract(15, add(1, 4)), 6) | add(n0,n1)|subtract(n2,#0)|subtract(#1,n3) | since f ( n ) = f ( n - 1 ) - n then : f ( 6 ) = f ( 5 ) - 6 and f ( 5 ) = f ( 4 ) - 5 . as given that f ( 4 ) = 15 then f ( 5 ) = 15 - 5 = 10 - - > substitute the value of f ( 5 ) back into the first equation : f ( 6 ) = f ( 5 ) - 6 = 10 - 6 = 4 . answer : a . questions on funtions to practice : | general |
math_qa__oNC6UBZy93xmPbMJ | Andy solves problems 78 to 125 inclusive in a Math exercise. How many problems does he solve? Answers:
A) 53 B) 52 C) 51 D) 50 E) 48 | <gadget id="calculator">125 - 78</gadget>
<output>47</output>
<gadget id="calculator">47 + 1</gadget>
<output>48</output>
<result>E</result> | E | 48 | Andy solves problems 78 to 125 inclusive in a Math exercise. How many problems does he solve? | {
"A": "53",
"B": "52",
"C": "51",
"D": "50",
"E": "48"
} | add(subtract(125, 78), const_1) | subtract(n1,n0)|add(#0,const_1)| | "125 - 78 + 1 = 48 ' e ' is the answer" | general |
math_qa__AGxdOB450lG5r1al | A fair 2 sided coin is flipped 3 times. What is the probability that tails will be the result at least twice, but not more than 3 times? Select the correct option: A) 5 / 8 B) 3 / 4 C) 3 / 8 D) 7 / 4 E) 5 / 6 | <gadget id="calculator">2 ** 3</gadget>
<output>8</output>
<gadget id="calculator">1 / 8</gadget>
<output>1/8 = around 0.125</output>
<gadget id="calculator">(1/8) * 3</gadget>
<output>3/8 = around 0.375</output>
<gadget id="calculator">(1/8) + (1/8)</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">(3/8) + (1/4)</gadget>
<output>5/8 = around 0.625</output>
<gadget id="calculator">1 - (5/8)</gadget>
<output>3/8 = around 0.375</output>
<result>C</result> | C | 0.375 | A fair 2 sided coin is flipped 3 times. What is the probability that tails will be the result at least twice, but not more than 3 times? | {
"A": "5 / 8",
"B": "3 / 4",
"C": "3 / 8",
"D": "7 / 4",
"E": "5 / 6"
} | subtract(const_1, add(multiply(inverse(power(2, 3)), 3), add(inverse(power(2, 3)), inverse(power(2, 3))))) | power(n0,n1)|inverse(#0)|add(#1,#1)|multiply(n1,#1)|add(#2,#3)|subtract(const_1,#4)| | "at least twice , but not more than 3 timesmeans exactly 2 times , 3 times the probability of getting exactly k results out of n flips is nck / 2 ^ n 3 c 2 / 2 ^ 3 = 3 / 8 option : c" | general |
math_qa__VdUIsRRwHx6jX1Fz | 3/5 of all married couples have more than one child. 2/5 of all married couples have more than 3 children. What fraction of all married couples have 2 or 3 children? Choose the correct choice from the following options:
A) 1 / 5
B) 1 / 4
C) 7 / 20
D) 3 / 5
E) it can not be determined from the given information . | <gadget id="calculator">3 / 5</gadget>
<output>3/5 = around 0.6</output>
<gadget id="calculator">2 / 5</gadget>
<output>2/5 = around 0.4</output>
<gadget id="calculator">(3/5) - (2/5)</gadget>
<output>1/5 = around 0.2</output>
<result>A</result> | A | 0.2 | 3/5 of all married couples have more than one child. 2/5 of all married couples have more than 3 children. What fraction of all married couples have 2 or 3 children? | {
"A": "1 / 5",
"B": "1 / 4",
"C": "7 / 20",
"D": "3 / 5",
"E": "it can not be determined from the given information ."
} | subtract(divide(3, 5), divide(2, 5)) | divide(n0,n1)|divide(n2,n1)|subtract(#0,#1) | plug in simple numbers . take 100 couples for example . 3 / 5 of 100 couples have more than one child = 60 couples . 2 / 5 of 100 couples have more than 3 kids = 40 couples . this implies that 40 couples are a subset of 60 couples and the complement of 60 couples within those 100 couples , which equals 20 couples have either one or no kids at all . we need to find couples that have 2 or 3 kids , so essentially , it is 60 - 40 = 20 . fraction will be 20 / 100 = 1 / 5 . option a | general |
math_qa__bwfV0soV2BqhBLDH | One pump drains one-half of a pond in 2 hours, and then a second pump starts draining the pond. The two pumps working together finish emptying the pond in one-half hour. How long would it take the second pump to drain the pond if it had to do the job alone? Choose the correct choice from the following options:
A) 1.3 hour B) 1.2 hour C) 3 hours D) 5 hours E) 6 hours | <gadget id="calculator">2 * 2</gadget>
<output>4</output>
<gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 - (1/4)</gadget>
<output>3/4 = around 0.75</output>
<gadget id="calculator">1 / (3/4)</gadget>
<output>4/3 = around 1.333333</output>
<result>A</result> | A | 1.3 | One pump drains one-half of a pond in 2 hours, and then a second pump starts draining the pond. The two pumps working together finish emptying the pond in one-half hour. How long would it take the second pump to drain the pond if it had to do the job alone? | {
"A": "1.3 hour",
"B": "1.2 hour",
"C": "3 hours",
"D": "5 hours",
"E": "6 hours"
} | divide(const_1, subtract(const_1, divide(const_1, multiply(2, const_2)))) | multiply(n0,const_2)|divide(const_1,#0)|subtract(const_1,#1)|divide(const_1,#2)| | "the tricky part here , i believed is one half hour = 1 / 2 . then everything would be easy . we have the 1 st pump working rate / hour = 1 / 2 : 2 = 1 / 4 working rate of 2 pumps : 1 / 2 : 1 / 2 = 1 . working rate of 2 nd pump : 1 - 1 / 4 = 3 / 4 - - > time taken for the 2 nd pump to finish : 1 : 3 / 4 = 4 / 3 = 1.3 hours . a" | physics |
math_qa__vVCaYoNgk9sMGDKf | If 2^2n + 2^2n + 2^2n + 2^2n = 4^18, then n = Pick one.
A) 3 B) 6 C) 17 D) 23 E) 24 | <gadget id="calculator">18 * 2</gadget>
<output>36</output>
<gadget id="calculator">36 - 2</gadget>
<output>34</output>
<gadget id="calculator">34 / 2</gadget>
<output>17</output>
<result>C</result> | C | 17 | If 2^2n + 2^2n + 2^2n + 2^2n = 4^18, then n = | {
"A": "3",
"B": "6",
"C": "17",
"D": "23",
"E": "24"
} | divide(subtract(multiply(18, 2), 2), 2) | multiply(n0,n9)|subtract(#0,n0)|divide(#1,n0)| | "2 ^ 2 n + 2 ^ 2 n + 2 ^ 2 n + 2 ^ 2 n = 4 ^ 18 = > 4 x 2 ^ 2 n = 4 ^ 24 = 2 ^ 36 = > 2 ^ 2 x 2 ^ 2 n = 2 ^ 36 = > 2 ^ ( 2 n + 2 ) = 2 ^ 36 = > 2 n + 2 = 36 = > n = 17 so . answer will be c ." | general |
math_qa__8teUZ997o21DQ9cD | A fair price shopkeeper takes 10% profit on his goods. He lost 40% goods during theft. His loss percent is: Answers
A) 72 %
B) 42 %
C) 34 %
D) 12 %
E) 22 % | <gadget id="calculator">100 + 10</gadget>
<output>110</output>
<gadget id="calculator">110 * 40</gadget>
<output>4_400</output>
<gadget id="calculator">4_400 / 100</gadget>
<output>44</output>
<gadget id="calculator">110 - 44</gadget>
<output>66</output>
<gadget id="calculator">100 - 66</gadget>
<output>34</output>
<result>C</result> | C | 34 | A fair price shopkeeper takes 10% profit on his goods. He lost 40% goods during theft. His loss percent is: | {
"A": "72 %",
"B": "42 %",
"C": "34 %",
"D": "12 %",
"E": "22 %"
} | subtract(const_100, subtract(add(const_100, 10), divide(multiply(add(const_100, 10), 40), const_100))) | add(n0,const_100)|multiply(n1,#0)|divide(#1,const_100)|subtract(#0,#2)|subtract(const_100,#3) | explanation : suppose he has 100 items . let c . p . of each item be re . 1 . total cost = rs . 100 . number of items left after theft = 60 . s . p . of each item = rs . 1.10 total sale = 1.10 * 60 = rs . 66 hence , loss % = 34 / 100 * 100 = 34 % answer : c | gain |
math_qa__q6EIUMgUaFKCYs5x | Two assembly line inspectors, smithy and glen, inspect widgets as they come off the assembly line. If smithy inspects every fifth widget, starting with the fifth, and glen inspects every third, starting with the third, how many of the 98 widgets produced in the first hour of operation are not inspected by either inspector? Choose the correct option: A) 50 B) 53 C) 55 D) 60 E) 65 | <gadget id="calculator">10 / 2</gadget>
<output>5</output>
<gadget id="calculator">98 / 5</gadget>
<output>98/5 = around 19.6</output>
<gadget id="calculator">98 / 3</gadget>
<output>98/3 = around 32.666667</output>
<gadget id="calculator">(98/5) + (98/3)</gadget>
<output>784/15 = around 52.266667</output>
<gadget id="calculator">5 * 3</gadget>
<output>15</output>
<gadget id="calculator">98 / 15</gadget>
<output>98/15 = around 6.533333</output>
<gadget id="calculator">(784/15) - (98/15)</gadget>
<output>686/15 = around 45.733333</output>
<gadget id="calculator">98 - (686/15)</gadget>
<output>784/15 = around 52.266667</output>
<result>B</result> | B | 53 | Two assembly line inspectors, smithy and glen, inspect widgets as they come off the assembly line. If smithy inspects every fifth widget, starting with the fifth, and glen inspects every third, starting with the third, how many of the 98 widgets produced in the first hour of operation are not inspected by either inspector? | {
"A": "50",
"B": "53",
"C": "55",
"D": "60",
"E": "65"
} | subtract(98, subtract(add(divide(98, divide(const_10, const_2)), divide(98, const_3)), divide(98, multiply(divide(const_10, const_2), const_3)))) | divide(const_10,const_2)|divide(n0,const_3)|divide(n0,#0)|multiply(#0,const_3)|add(#2,#1)|divide(n0,#3)|subtract(#4,#5)|subtract(n0,#6) | widgets inspected by smithy : ( ( 95 - 5 ) / 5 ) + 1 = 18 + 1 = 19 widgets inspected by glen : ( ( 96 - 3 ) / 3 ) + 1 = 31 + 1 = 32 widgets inspected by both : ( ( 90 - 15 ) + 1 = 6 total : 19 + 32 - 6 = 45 hence , widgets not inspected : 98 - 45 = 53 option b | other |
math_qa__4KxsKSe1TbTtOGZL | The speed of a car is 120 km in the first hour and 70 km in the second hour. What is the average speed of the car? Pick:
A) 72 kmph
B) 75 kmph
C) 95 kmph
D) 80 kmph
E) 82 kmph | <gadget id="calculator">120 + 70</gadget>
<output>190</output>
<gadget id="calculator">190 / 2</gadget>
<output>95</output>
<result>C</result> | C | 95 | The speed of a car is 120 km in the first hour and 70 km in the second hour. What is the average speed of the car? | {
"A": "72 kmph",
"B": "75 kmph",
"C": "95 kmph",
"D": "80 kmph",
"E": "82 kmph"
} | divide(add(120, 70), const_2) | add(n0,n1)|divide(#0,const_2)| | "s = ( 120 + 70 ) / 2 = 95 kmph answer : c" | physics |
math_qa__zrRcagjX12zn8ThX | In a class of 60 children, 30% children can speak only English, 20 % Hindi and English both and the rest of the children can speak only Hindi. How many children can speak Hindi?
Choose one:
A) 42 B) 36 C) 30 D) 48 E) none of these | <gadget id="calculator">60 - 30</gadget>
<output>30</output>
<gadget id="calculator">20 * 60</gadget>
<output>1_200</output>
<gadget id="calculator">1_200 / 100</gadget>
<output>12</output>
<gadget id="calculator">30 + 12</gadget>
<output>42</output>
<result>A</result> | A | 42 | In a class of 60 children, 30% children can speak only English, 20 % Hindi and English both and the rest of the children can speak only Hindi. How many children can speak Hindi? | {
"A": "42",
"B": "36",
"C": "30",
"D": "48",
"E": "none of these"
} | add(subtract(60, 30), divide(multiply(20, 60), const_100)) | multiply(n0,n2)|subtract(n0,n1)|divide(#0,const_100)|add(#2,#1) | number of students who speak only english = 30 % of 60 = 18 ∵ number of students who speak hindi and english = 20 % of 60 = 12 ∵ number of students who speak only hindi = ( 60 – 30 = ) 30 ∵ no . of students who speak hindi = 30 + 12 = 42 answer a | other |
math_qa__ycV4iW4i2BB15LZp | 25% of a number is more than 20% of 650 by 190. Find the number? Choose the correct answer.
A) 288
B) 278
C) 800
D) 267
E) 1280 | <gadget id="calculator">650 * 20</gadget>
<output>13_000</output>
<gadget id="calculator">13_000 / 100</gadget>
<output>130</output>
<gadget id="calculator">130 + 190</gadget>
<output>320</output>
<gadget id="calculator">320 * 100</gadget>
<output>32_000</output>
<gadget id="calculator">32_000 / 25</gadget>
<output>1_280</output>
<result>E</result> | E | 1,280 | 25% of a number is more than 20% of 650 by 190. Find the number? | {
"A": "288",
"B": "278",
"C": "800",
"D": "267",
"E": "1280"
} | divide(multiply(add(divide(multiply(650, 20), const_100), 190), const_100), 25) | multiply(n1,n2)|divide(#0,const_100)|add(n3,#1)|multiply(#2,const_100)|divide(#3,n0)| | "( 25 / 100 ) * x â € “ ( 20 / 100 ) * 650 = 190 1 / 4 x = 320 x = 1280 answer : e" | gain |
math_qa__1QfPYidxvyg1dm0W | George's car calls for 8 ounces of oil for each cylinder used. His car's engine has 6 cylinders. If 16 ounces of oil has already been put into the engine used, then how many additional ounces of oil are needed?
Select.
A) 16 B) 48 C) 64 D) 32 E) 8 | <gadget id="calculator">8 * 6</gadget>
<output>48</output>
<gadget id="calculator">48 - 16</gadget>
<output>32</output>
<result>D</result> | D | 32 | George's car calls for 8 ounces of oil for each cylinder used. His car's engine has 6 cylinders. If 16 ounces of oil has already been put into the engine used, then how many additional ounces of oil are needed? | {
"A": "16",
"B": "48",
"C": "64",
"D": "32",
"E": "8"
} | subtract(multiply(8, 6), 16) | multiply(n0,n1)|subtract(#0,n2) | number of ounces per cylinder 8 number of cylinders 6 ounces needed 48 ounces used 16 answer d | geometry |
math_qa__54sBK3I1wbBqVOLu | A car traveled 35% of the way from Town X to Town Y at an average speed of 35 mph. The car traveled at an average speed of v mph for the remaining part of the trip. The average speed for the entire trip was 50 mph. What is v in mph?
Choose the correct choice from the following options:
A) 45 B) 65 C) 55 D) 75 E) 85 | <gadget id="calculator">100 - 35</gadget>
<output>65</output>
<gadget id="calculator">35 / 35</gadget>
<output>1</output>
<gadget id="calculator">65 / 1</gadget>
<output>65</output>
<result>B</result> | B | 65 | A car traveled 35% of the way from Town X to Town Y at an average speed of 35 mph. The car traveled at an average speed of v mph for the remaining part of the trip. The average speed for the entire trip was 50 mph. What is v in mph? | {
"A": "45",
"B": "65",
"C": "55",
"D": "75",
"E": "85"
} | divide(subtract(const_100, 35), divide(35, 35)) | divide(n0,n0)|subtract(const_100,n0)|divide(#1,#0)| | "assume total distance = 100 miles time taken for 35 miles = 35 / 35 = 1 hour time taken for the rest of the 65 miles = 65 / v hours . average speed = 50 therefore the total time needed = 2 hours . 2 = 1 + 65 / v hence v = 65 mph answer : b" | general |
math_qa__56ij5Rfft7lut3Pw | If the compound interest on a certain sum of money for 2 years at 10% per annum be Rs. 993, what would be the simple interest? Choose the correct choice from the following choices
A) rs . 600 B) rs . 890 C) rs . 895 D) rs . 900 E) none | <gadget id="calculator">3 * 100</gadget>
<output>300</output>
<gadget id="calculator">300 * 10</gadget>
<output>3_000</output>
<gadget id="calculator">3_000 * 10</gadget>
<output>30_000</output>
<gadget id="calculator">30_000 * 2</gadget>
<output>60_000</output>
<gadget id="calculator">60_000 / 100</gadget>
<output>600</output>
<result>A</result> | A | 600 | If the compound interest on a certain sum of money for 2 years at 10% per annum be Rs. 993, what would be the simple interest? | {
"A": "rs . 600",
"B": "rs . 890",
"C": "rs . 895",
"D": "rs . 900",
"E": "none"
} | divide(multiply(multiply(multiply(multiply(const_3.0, const_100), 10), 10), 2), const_100) | multiply(const_3.0,const_100)|multiply(n1,#0)|multiply(n1,#1)|multiply(n0,#2)|divide(#3,const_100)| | "let p = principal a - amount we have a = p ( 1 + r / 100 ) 3 and ci = a - p atq 993 = p ( 1 + r / 100 ) 3 - p ? p = 3000 / - now si @ 10 % on 3000 / - for 2 yrs = ( 3000 x 10 x 2 ) / 100 = 600 / - answer : a ." | gain |
math_qa__lKhLqsQzm1bBeMig | Hammers and wrenches are manufactured at a uniform weight per hammer and a uniform weight per wrench. If the total weight of two hammers and two wrenches is one-third that of 8 hammers and 5 wrenches, then the total weight of one wrench is how many times that of one hammer? Choose the most appropriate option
A) 1 / 2 B) 2 / 3 C) 1 D) 3 / 2 E) 2 | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">8 - 6</gadget>
<output>2</output>
<gadget id="calculator">6 - 5</gadget>
<output>1</output>
<gadget id="calculator">2 / 1</gadget>
<output>2</output>
<result>E</result> | E | 2 | Hammers and wrenches are manufactured at a uniform weight per hammer and a uniform weight per wrench. If the total weight of two hammers and two wrenches is one-third that of 8 hammers and 5 wrenches, then the total weight of one wrench is how many times that of one hammer? | {
"A": "1 / 2",
"B": "2 / 3",
"C": "1",
"D": "3 / 2",
"E": "2"
} | divide(subtract(8, multiply(const_3, const_2)), subtract(multiply(const_3, const_2), 5)) | multiply(const_2,const_3)|subtract(n0,#0)|subtract(#0,n1)|divide(#1,#2) | x be the weight of a hammer and y be the weight of a wrench . ( 2 x + 2 y ) = 1 / 3 * ( 8 x + 5 y ) 3 ( 2 x + 2 y ) = ( 8 x + 5 y ) 6 x + 6 y = 8 x + 5 y y = 2 x ans - e | general |
math_qa__epu72kpRpcN4Bhxe | The total circumference of two circles is 49. If the first circle has a circumference that is exactly twice the circumference of the second circle, then what is the approximate sum of their two radii? Choose the correct choice from the following choices:
A) 7.8 B) 6.0 C) 6.7 D) 9.7 E) 18.0 | <gadget id="calculator">49 / 3</gadget>
<output>49/3 = around 16.333333</output>
<gadget id="calculator">(49/3) / 3</gadget>
<output>49/9 = around 5.444444</output>
<gadget id="calculator">(49/3) * 2</gadget>
<output>98/3 = around 32.666667</output>
<gadget id="calculator">(98/3) / 3</gadget>
<output>98/9 = around 10.888889</output>
<gadget id="calculator">(49/9) + (98/9)</gadget>
<output>49/3 = around 16.333333</output>
<gadget id="calculator">(49/3) / 2</gadget>
<output>49/6 = around 8.166667</output>
<result>A</result> | A | 7.8 | The total circumference of two circles is 49. If the first circle has a circumference that is exactly twice the circumference of the second circle, then what is the approximate sum of their two radii? | {
"A": "7.8",
"B": "6.0",
"C": "6.7",
"D": "9.7",
"E": "18.0"
} | divide(add(divide(divide(49, const_3), const_3), divide(multiply(divide(49, const_3), const_2), const_3)), const_2) | divide(n0,const_3)|divide(#0,const_3)|multiply(#0,const_2)|divide(#2,const_3)|add(#1,#3)|divide(#4,const_2)| | "let r = radius of smaller circle . let r = radius of larger circle therefore : 2 π r + 2 π r = 49 where 2 r = r thus : 2 π r + 4 π r = 49 6 π r = 49 r = approx 2.6 π r + 2 r π = 49 3 π r = 49 r = approx 5.2 r + r = approx 7.8 answer : a" | general |
math_qa__TDGJYTVaqkETTIS6 | A certain pair of used shoes can be repaired for $10.50 and will last for 1 year. A pair of the same kind of shoes can be purchased new for $30.00 and will last for 2 years. The average cost per year of the new shoes is what percent greater than the cost of repairing the used shoes?
Choose one:
A) 42.85 B) 44 C) 48 D) 38 E) 40 | <gadget id="calculator">10.5 * 2</gadget>
<output>21</output>
<gadget id="calculator">30 - 21</gadget>
<output>9</output>
<gadget id="calculator">9 / 21</gadget>
<output>3/7 = around 0.428571</output>
<gadget id="calculator">100 * (3/7)</gadget>
<output>300/7 = around 42.857143</output>
<result>A</result> | A | 42.85 | A certain pair of used shoes can be repaired for $10.50 and will last for 1 year. A pair of the same kind of shoes can be purchased new for $30.00 and will last for 2 years. The average cost per year of the new shoes is what percent greater than the cost of repairing the used shoes? | {
"A": "42.85",
"B": "44",
"C": "48",
"D": "38",
"E": "40"
} | multiply(const_100, divide(subtract(30.00, multiply(10.50, 2)), multiply(10.50, 2))) | multiply(n0,n3)|subtract(n2,#0)|divide(#1,#0)|multiply(#2,const_100)| | "1 ) cost of repairing = 10.5 ( for one year ) , therefore for 2 years it would be $ 21 . 2 ) cost of new pair which will last for 2 years is $ 30.00 percentage change formula = ( final value - initial value ) / ( initial value ) * 100 . in this case the final value would be the price of new shoe initial value would be the cost of repairing the old shoe . i . e ( 30 - 21 ) / ( 21 ) * 100 = 42.85 % . ans is a" | general |
math_qa__t8d53q5xGqGPQcAd | A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 6 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled?
Choose the correct option
A) 17.5
B) 7.4
C) 7.9
D) 12.0
E) 7.1 | <gadget id="calculator">1 / 4</gadget>
<output>1/4 = around 0.25</output>
<gadget id="calculator">1 / 6</gadget>
<output>1/6 = around 0.166667</output>
<gadget id="calculator">(1/4) - (1/6)</gadget>
<output>1/12 = around 0.083333</output>
<gadget id="calculator">1 / (1/12)</gadget>
<output>12</output>
<result>D</result> | D | 12 | A cistern can be filled by a tap in 4 hours while it can be emptied by another tap in 6 hours. If both the taps are opened simultaneously, then after how much time will the cistern get filled? | {
"A": "17.5",
"B": "7.4",
"C": "7.9",
"D": "12.0",
"E": "7.1"
} | divide(const_1, subtract(divide(const_1, 4), divide(const_1, 6))) | divide(const_1,n0)|divide(const_1,n1)|subtract(#0,#1)|divide(const_1,#2)| | "net part filled in 1 hour = ( 1 / 4 - 1 / 6 ) = 1 / 12 the cistern will be filled in 12 / 1 hrs i . e . , 12 hrs . answer : d" | physics |
math_qa__ek1gxmuP1CpwEoIp | A runs twice as fast as B and gives B a start of 42m.How long should the racecourse be so that A and B might reach in the same time?
Choose the correct choice from the following: A) 75 m . B) 80 m . C) 84 m . D) 100 m . E) none of the above | <gadget id="calculator">42 * 2</gadget>
<output>84</output>
<result>C</result> | C | 84 | A runs twice as fast as B and gives B a start of 42m.How long should the racecourse be so that A and B might reach in the same time? | {
"A": "75 m .",
"B": "80 m .",
"C": "84 m .",
"D": "100 m .",
"E": "none of the above"
} | multiply(42, const_2) | multiply(n0,const_2)| | "ratio of speeds of a and b is 2 : 1 b is 42 m away from a but we know that a covers 1 meter ( 2 - 1 ) more in every second than b the time taken for a to cover 42 m is 42 / 1 = 42 m so the total time taken by a and b to reach = 2 * 42 = 84 m answer : c" | physics |
math_qa__Xxl7G26rU03efSM6 | In a certain town, the ratio of NY Yankees fans to NY Mets fans is 3:2, and the ratio of NY Mets fans to Boston Red Sox fans is 4:5. If there are 330 baseball fans in the town, each of whom is a fan of exactly one of those three teams, how many NY Mets fans are there in this town? Choose the correct choice from the following options:
A) 72
B) 88
C) 95
D) 120
E) 135 | <gadget id="calculator">3 * 2</gadget>
<output>6</output>
<gadget id="calculator">6 + 4</gadget>
<output>10</output>
<gadget id="calculator">10 + 5</gadget>
<output>15</output>
<gadget id="calculator">330 / 15</gadget>
<output>22</output>
<gadget id="calculator">22 * 4</gadget>
<output>88</output>
<result>B</result> | B | 88 | In a certain town, the ratio of NY Yankees fans to NY Mets fans is 3:2, and the ratio of NY Mets fans to Boston Red Sox fans is 4:5. If there are 330 baseball fans in the town, each of whom is a fan of exactly one of those three teams, how many NY Mets fans are there in this town? | {
"A": "72",
"B": "88",
"C": "95",
"D": "120",
"E": "135"
} | multiply(divide(330, add(add(multiply(3, 2), 4), 5)), 4) | multiply(n0,n1)|add(n2,#0)|add(n3,#1)|divide(n4,#2)|multiply(n2,#3)| | "the ratio of yankees : mets : red sox = 6 : 4 : 5 the mets fans are 4 / 15 of the population . ( 4 / 15 ) * 330 = 88 the answer is b ." | other |
math_qa__m9uSrWL0f3CdqfGE | What is the area of square field whose side of length 13 m? Choose the correct choice from the following:
A) 169
B) 196
C) 266
D) 288
E) 261 | <gadget id="calculator">13 ** 2</gadget>
<output>169</output>
<result>A</result> | A | 169 | What is the area of square field whose side of length 13 m? | {
"A": "169",
"B": "196",
"C": "266",
"D": "288",
"E": "261"
} | square_area(13) | square_area(n0)| | "13 * 13 = 169 sq m answer : a" | geometry |
math_qa__VEvVEtbego4xMtWk | In what time a sum of money double itself at 2% per annum simple interest? Pick:
A) 60 % B) 58 % C) 55 % D) 40 % E) 50 % | <gadget id="calculator">100 * 100</gadget>
<output>10_000</output>
<gadget id="calculator">2 * 100</gadget>
<output>200</output>
<gadget id="calculator">10_000 / 200</gadget>
<output>50</output>
<result>E</result> | E | 50 | In what time a sum of money double itself at 2% per annum simple interest? | {
"A": "60 %",
"B": "58 %",
"C": "55 %",
"D": "40 %",
"E": "50 %"
} | divide(multiply(const_100, const_100), multiply(2, const_100)) | multiply(const_100,const_100)|multiply(n0,const_100)|divide(#0,#1) | p = ( p * 2 * r ) / 100 r = 50 % answer : e | gain |
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Dataset Card for Calc-math_qa
Summary
This dataset is an instance of math_qa dataset, converted to a simple HTML-like language that can be easily parsed (e.g. by BeautifulSoup). The data contains 3 types of tags:
- gadget: A tag whose content is intended to be evaluated by calling an external tool (sympy-based calculator in this case)
- output: An output of the external tool
- result: The final answer of the mathematical problem (correct option)
Supported Tasks
The dataset is intended for training Chain-of-Thought reasoning models able to use external tools to enhance the factuality of their responses. This dataset presents in-context scenarios where models can outsource the computations in the reasoning chain to a calculator.
Construction Process
We took the original math_qa dataset, parsed the nested formulas, linearized them into a sequence (chain) of operations, and replaced all advanced
function calls (such as circle_area) with explicit elementary operations. We evaluate all the steps in each example and filter out examples if their
evaluation does not match the answer selected as correct in the data with a 5% tolerance, with about 26k examples remaining. The sequence of steps is then saved in HTML-like language
in the chain column.
We also perform in-dataset and cross-dataset data-leak detection within Calc-X collection. Specifically for MathQA, we found that majority of validation and test examples are near-duplicates of some example in the train set, and that all validation and test examples likely originate from the Aqua-RAT train split. We do not recommend to original validation and test splits of the MathQA dataset.
You can read more information about this process in our Calc-X paper.
Data splits
In our default configuration, test and validation splits are removed and we recommend using MathQA for training only. You can load it using:
datasets.load_dataset("MU-NLPC/calc-math_qa")
If you want to use the original dataset splits, you can load it using:
datasets.load_dataset("MU-NLPC/calc-math_qa", "original-splits")
Atributes
- id - id of the example
- question - the description of a mathematical problem in natural language, and includes the options to be selected from
- chain - solution in the form of step-by-step calculations encoded in simple html-like language. computed from
annotated_formulacolumn - result - the correct option
- result_float - the result converted to a float
- question_without_options - same as
question, but does not contain the options - options - dictionary of options to choose from, one is correct, keys are "A".."E"
- annotated_formula - human-annotated nested expression that (approximately) evaluates to the selected correct answer
- linear_formula - same as
annotated_formula, but linearized by original math_qa authors - rationale - human-annotated free-text reasoning that leads to the correct answer
- category - category of the math problem
Attributes id, question, chain, and result are present in all datasets in Calc-X collection.
Sources
Related work
This dataset was created as a part of a larger effort in training models capable of using a calculator during inference, which we call Calcformers. We have released a collection of datasets on solving math problems with calculator interactions on HuggingFace called Calc-X collection. You can find the models we trained in the Calcformers collection. You can read more in our paper Calc-X and Calcformers.
Licence
Apache 2.0, consistently with the original dataset.
Cite
If you use this version of dataset in research, please cite the original MathQA paper, and Calc-X paper as follows:
@inproceedings{kadlcik-etal-2023-soft,
title = "Calc-X and Calcformers: Empowering Arithmetical Chain-of-Thought through Interaction with Symbolic Systems",
author = "Marek Kadlčík and Michal Štefánik and Ondřej Sotolář and Vlastimil Martinek",
booktitle = "Proceedings of the The 2023 Conference on Empirical Methods in Natural Language Processing: Main track",
month = dec,
year = "2023",
address = "Singapore, Singapore",
publisher = "Association for Computational Linguistics",
url = "https://arxiv.org/abs/2305.15017",
}
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