Hugging Face's logo

Spaces:
justest
/
GPT-Academic-with-B3n-AI
Runtime error

App Files Community
GPT-Academic-with-B3n-AI
File size: 5,672 Bytes 
c533201
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
 
sample = """
[1]: https://baike.baidu.com/item/%E8%B4%A8%E8%83%BD%E6%96%B9%E7%A8%8B/1884527 "质能方程（质能方程式）_百度百科"
[2]: https://www.zhihu.com/question/348249281 "如何理解质能方程 E＝mc²？ - 知乎"
[3]: https://zhuanlan.zhihu.com/p/32597385 "质能方程的推导与理解 - 知乎 - 知乎专栏"

你好，这是必应。质能方程是描述质量与能量之间的当量关系的方程[^1^][1]。用tex格式，质能方程可以写成$$E=mc^2$$，其中$E$是能量，$m$是质量，$c$是光速[^2^][2] [^3^][3]。
"""
import re

def preprocess_newbing_out(s):
    pattern = r'\^(\d+)\^' # 匹配^数字^
    pattern2 = r'\[(\d+)\]' # 匹配^数字^
    sub = lambda m: '\['+m.group(1)+'\]' # 将匹配到的数字作为替换值
    result = re.sub(pattern, sub, s) # 替换操作
    if '[1]' in result:
        result += '<br/><hr style="border-top: dotted 1px #44ac5c;"><br/><small>' + "<br/>".join([re.sub(pattern2, sub, r) for r in result.split('\n') if r.startswith('[')]) + '</small>'
    return result


def close_up_code_segment_during_stream(gpt_reply):
    """
    在gpt输出代码的中途（输出了前面的```，但还没输出完后面的```），补上后面的```

    Args:
        gpt_reply (str): GPT模型返回的回复字符串。

    Returns:
        str: 返回一个新的字符串，将输出代码片段的“后面的```”补上。

    """
    if '```' not in gpt_reply:
        return gpt_reply
    if gpt_reply.endswith('```'):
        return gpt_reply

    # 排除了以上两个情况，我们
    segments = gpt_reply.split('```')
    n_mark = len(segments) - 1
    if n_mark % 2 == 1:
        # print('输出代码片段中！')
        return gpt_reply+'\n```'
    else:
        return gpt_reply
    
import markdown
from latex2mathml.converter import convert as tex2mathml
from functools import wraps, lru_cache
def markdown_convertion(txt):
    """
    将Markdown格式的文本转换为HTML格式。如果包含数学公式，则先将公式转换为HTML格式。
    """
    pre = '<div class="markdown-body">'
    suf = '</div>'
    if txt.startswith(pre) and txt.endswith(suf):
        # print('警告，输入了已经经过转化的字符串，二次转化可能出问题')
        return txt # 已经被转化过，不需要再次转化
    
    markdown_extension_configs = {
        'mdx_math': {
            'enable_dollar_delimiter': True,
            'use_gitlab_delimiters': False,
        },
    }
    find_equation_pattern = r'<script type="math/tex(?:.*?)>(.*?)</script>'

    def tex2mathml_catch_exception(content, *args, **kwargs):
        try:
            content = tex2mathml(content, *args, **kwargs)
        except:
            content = content
        return content

    def replace_math_no_render(match):
        content = match.group(1)
        if 'mode=display' in match.group(0):
            content = content.replace('\n', '</br>')
            return f"<font color=\"#00FF00\">$$</font><font color=\"#FF00FF\">{content}</font><font color=\"#00FF00\">$$</font>"
        else:
            return f"<font color=\"#00FF00\">$</font><font color=\"#FF00FF\">{content}</font><font color=\"#00FF00\">$</font>"

    def replace_math_render(match):
        content = match.group(1)
        if 'mode=display' in match.group(0):
            if '\\begin{aligned}' in content:
                content = content.replace('\\begin{aligned}', '\\begin{array}')
                content = content.replace('\\end{aligned}', '\\end{array}')
                content = content.replace('&', ' ')
            content = tex2mathml_catch_exception(content, display="block")
            return content
        else:
            return tex2mathml_catch_exception(content)

    def markdown_bug_hunt(content):
        """
        解决一个mdx_math的bug（单$包裹begin命令时多余<script>）
        """
        content = content.replace('<script type="math/tex">\n<script type="math/tex; mode=display">', '<script type="math/tex; mode=display">')
        content = content.replace('</script>\n</script>', '</script>')
        return content


    if ('$' in txt) and ('```' not in txt):  # 有$标识的公式符号，且没有代码段```的标识
        # convert everything to html format
        split = markdown.markdown(text='---')
        convert_stage_1 = markdown.markdown(text=txt, extensions=['mdx_math', 'fenced_code', 'tables', 'sane_lists'], extension_configs=markdown_extension_configs)
        convert_stage_1 = markdown_bug_hunt(convert_stage_1)
        # re.DOTALL: Make the '.' special character match any character at all, including a newline; without this flag, '.' will match anything except a newline. Corresponds to the inline flag (?s).
        # 1. convert to easy-to-copy tex (do not render math)
        convert_stage_2_1, n = re.subn(find_equation_pattern, replace_math_no_render, convert_stage_1, flags=re.DOTALL)
        # 2. convert to rendered equation
        convert_stage_2_2, n = re.subn(find_equation_pattern, replace_math_render, convert_stage_1, flags=re.DOTALL)
        # cat them together
        return pre + convert_stage_2_1 + f'{split}' + convert_stage_2_2 + suf
    else:
        return pre + markdown.markdown(txt, extensions=['fenced_code', 'codehilite', 'tables', 'sane_lists']) + suf


sample = preprocess_newbing_out(sample)
sample = close_up_code_segment_during_stream(sample)
sample = markdown_convertion(sample)
with open('tmp.html', 'w', encoding='utf8') as f:
    f.write("""

<head>
    <title>My Website</title>
    <link rel="stylesheet" type="text/css" href="style.css">
</head>

    """)
    f.write(sample)