Datasets:

Task Categories: text2text-generation
Languages: en
Multilinguality: monolingual
Size Categories: n<1K
Licenses: mit
Language Creators: expert-generated
Annotations Creators: expert-generated
Source Datasets: original
Dataset Preview Go to dataset viewer
task_id (string)prompt (string)canonical_solution (string)test (string)entry_point (string)
HumanEval/0
from typing import List def has_close_elements(numbers: List[float], threshold: float) -> bool: """ Check if in given list of numbers, are any two numbers closer to each other than given threshold. >>> has_close_elements([1.0, 2.0, 3.0], 0.5) False >>> has_close_elements([1.0, 2.8, 3.0, 4.0, 5.0, 2.0], 0.3) True """
for idx, elem in enumerate(numbers): for idx2, elem2 in enumerate(numbers): if idx != idx2: distance = abs(elem - elem2) if distance < threshold: return True return False
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.3) == True assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2], 0.05) == False assert candidate([1.0, 2.0, 5.9, 4.0, 5.0], 0.95) == True assert candidate([1.0, 2.0, 5.9, 4.0, 5.0], 0.8) == False assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.0], 0.1) == True assert candidate([1.1, 2.2, 3.1, 4.1, 5.1], 1.0) == True assert candidate([1.1, 2.2, 3.1, 4.1, 5.1], 0.5) == False
has_close_elements
HumanEval/1
from typing import List def separate_paren_groups(paren_string: str) -> List[str]: """ Input to this function is a string containing multiple groups of nested parentheses. Your goal is to separate those group into separate strings and return the list of those. Separate groups are balanced (each open brace is properly closed) and not nested within each other Ignore any spaces in the input string. >>> separate_paren_groups('( ) (( )) (( )( ))') ['()', '(())', '(()())'] """
result = [] current_string = [] current_depth = 0 for c in paren_string: if c == '(': current_depth += 1 current_string.append(c) elif c == ')': current_depth -= 1 current_string.append(c) if current_depth == 0: result.append(''.join(current_string)) current_string.clear() return result
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('(()()) ((())) () ((())()())') == [ '(()())', '((()))', '()', '((())()())' ] assert candidate('() (()) ((())) (((())))') == [ '()', '(())', '((()))', '(((())))' ] assert candidate('(()(())((())))') == [ '(()(())((())))' ] assert candidate('( ) (( )) (( )( ))') == ['()', '(())', '(()())']
separate_paren_groups
HumanEval/2
def truncate_number(number: float) -> float: """ Given a positive floating point number, it can be decomposed into and integer part (largest integer smaller than given number) and decimals (leftover part always smaller than 1). Return the decimal part of the number. >>> truncate_number(3.5) 0.5 """
return number % 1.0
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate(3.5) == 0.5 assert abs(candidate(1.33) - 0.33) < 1e-6 assert abs(candidate(123.456) - 0.456) < 1e-6
truncate_number
HumanEval/3
from typing import List def below_zero(operations: List[int]) -> bool: """ You're given a list of deposit and withdrawal operations on a bank account that starts with zero balance. Your task is to detect if at any point the balance of account fallls below zero, and at that point function should return True. Otherwise it should return False. >>> below_zero([1, 2, 3]) False >>> below_zero([1, 2, -4, 5]) True """
balance = 0 for op in operations: balance += op if balance < 0: return True return False
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([]) == False assert candidate([1, 2, -3, 1, 2, -3]) == False assert candidate([1, 2, -4, 5, 6]) == True assert candidate([1, -1, 2, -2, 5, -5, 4, -4]) == False assert candidate([1, -1, 2, -2, 5, -5, 4, -5]) == True assert candidate([1, -2, 2, -2, 5, -5, 4, -4]) == True
below_zero
HumanEval/4
from typing import List def mean_absolute_deviation(numbers: List[float]) -> float: """ For a given list of input numbers, calculate Mean Absolute Deviation around the mean of this dataset. Mean Absolute Deviation is the average absolute difference between each element and a centerpoint (mean in this case): MAD = average | x - x_mean | >>> mean_absolute_deviation([1.0, 2.0, 3.0, 4.0]) 1.0 """
mean = sum(numbers) / len(numbers) return sum(abs(x - mean) for x in numbers) / len(numbers)
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert abs(candidate([1.0, 2.0, 3.0]) - 2.0/3.0) < 1e-6 assert abs(candidate([1.0, 2.0, 3.0, 4.0]) - 1.0) < 1e-6 assert abs(candidate([1.0, 2.0, 3.0, 4.0, 5.0]) - 6.0/5.0) < 1e-6
mean_absolute_deviation
HumanEval/5
from typing import List def intersperse(numbers: List[int], delimeter: int) -> List[int]: """ Insert a number 'delimeter' between every two consecutive elements of input list `numbers' >>> intersperse([], 4) [] >>> intersperse([1, 2, 3], 4) [1, 4, 2, 4, 3] """
if not numbers: return [] result = [] for n in numbers[:-1]: result.append(n) result.append(delimeter) result.append(numbers[-1]) return result
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([], 7) == [] assert candidate([5, 6, 3, 2], 8) == [5, 8, 6, 8, 3, 8, 2] assert candidate([2, 2, 2], 2) == [2, 2, 2, 2, 2]
intersperse
HumanEval/6
from typing import List def parse_nested_parens(paren_string: str) -> List[int]: """ Input to this function is a string represented multiple groups for nested parentheses separated by spaces. For each of the group, output the deepest level of nesting of parentheses. E.g. (()()) has maximum two levels of nesting while ((())) has three. >>> parse_nested_parens('(()()) ((())) () ((())()())') [2, 3, 1, 3] """
def parse_paren_group(s): depth = 0 max_depth = 0 for c in s: if c == '(': depth += 1 max_depth = max(depth, max_depth) else: depth -= 1 return max_depth return [parse_paren_group(x) for x in paren_string.split(' ') if x]
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('(()()) ((())) () ((())()())') == [2, 3, 1, 3] assert candidate('() (()) ((())) (((())))') == [1, 2, 3, 4] assert candidate('(()(())((())))') == [4]
parse_nested_parens
HumanEval/7
from typing import List def filter_by_substring(strings: List[str], substring: str) -> List[str]: """ Filter an input list of strings only for ones that contain given substring >>> filter_by_substring([], 'a') [] >>> filter_by_substring(['abc', 'bacd', 'cde', 'array'], 'a') ['abc', 'bacd', 'array'] """
return [x for x in strings if substring in x]
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([], 'john') == [] assert candidate(['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx') == ['xxx', 'xxxAAA', 'xxx'] assert candidate(['xxx', 'asd', 'aaaxxy', 'john doe', 'xxxAAA', 'xxx'], 'xx') == ['xxx', 'aaaxxy', 'xxxAAA', 'xxx'] assert candidate(['grunt', 'trumpet', 'prune', 'gruesome'], 'run') == ['grunt', 'prune']
filter_by_substring
HumanEval/8
from typing import List, Tuple def sum_product(numbers: List[int]) -> Tuple[int, int]: """ For a given list of integers, return a tuple consisting of a sum and a product of all the integers in a list. Empty sum should be equal to 0 and empty product should be equal to 1. >>> sum_product([]) (0, 1) >>> sum_product([1, 2, 3, 4]) (10, 24) """
sum_value = 0 prod_value = 1 for n in numbers: sum_value += n prod_value *= n return sum_value, prod_value
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([]) == (0, 1) assert candidate([1, 1, 1]) == (3, 1) assert candidate([100, 0]) == (100, 0) assert candidate([3, 5, 7]) == (3 + 5 + 7, 3 * 5 * 7) assert candidate([10]) == (10, 10)
sum_product
HumanEval/9
from typing import List, Tuple def rolling_max(numbers: List[int]) -> List[int]: """ From a given list of integers, generate a list of rolling maximum element found until given moment in the sequence. >>> rolling_max([1, 2, 3, 2, 3, 4, 2]) [1, 2, 3, 3, 3, 4, 4] """
running_max = None result = [] for n in numbers: if running_max is None: running_max = n else: running_max = max(running_max, n) result.append(running_max) return result
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([]) == [] assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4] assert candidate([4, 3, 2, 1]) == [4, 4, 4, 4] assert candidate([3, 2, 3, 100, 3]) == [3, 3, 3, 100, 100]
rolling_max
HumanEval/10
def is_palindrome(string: str) -> bool: """ Test if given string is a palindrome """ return string == string[::-1] def make_palindrome(string: str) -> str: """ Find the shortest palindrome that begins with a supplied string. Algorithm idea is simple: - Find the longest postfix of supplied string that is a palindrome. - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix. >>> make_palindrome('') '' >>> make_palindrome('cat') 'catac' >>> make_palindrome('cata') 'catac' """
if not string: return '' beginning_of_suffix = 0 while not is_palindrome(string[beginning_of_suffix:]): beginning_of_suffix += 1 return string + string[:beginning_of_suffix][::-1]
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('') == '' assert candidate('x') == 'x' assert candidate('xyz') == 'xyzyx' assert candidate('xyx') == 'xyx' assert candidate('jerry') == 'jerryrrej'
make_palindrome
HumanEval/11
from typing import List def string_xor(a: str, b: str) -> str: """ Input are two strings a and b consisting only of 1s and 0s. Perform binary XOR on these inputs and return result also as a string. >>> string_xor('010', '110') '100' """
def xor(i, j): if i == j: return '0' else: return '1' return ''.join(xor(x, y) for x, y in zip(a, b))
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('111000', '101010') == '010010' assert candidate('1', '1') == '0' assert candidate('0101', '0000') == '0101'
string_xor
HumanEval/12
from typing import List, Optional def longest(strings: List[str]) -> Optional[str]: """ Out of list of strings, return the longest one. Return the first one in case of multiple strings of the same length. Return None in case the input list is empty. >>> longest([]) >>> longest(['a', 'b', 'c']) 'a' >>> longest(['a', 'bb', 'ccc']) 'ccc' """
if not strings: return None maxlen = max(len(x) for x in strings) for s in strings: if len(s) == maxlen: return s
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([]) == None assert candidate(['x', 'y', 'z']) == 'x' assert candidate(['x', 'yyy', 'zzzz', 'www', 'kkkk', 'abc']) == 'zzzz'
longest
HumanEval/13
def greatest_common_divisor(a: int, b: int) -> int: """ Return a greatest common divisor of two integers a and b >>> greatest_common_divisor(3, 5) 1 >>> greatest_common_divisor(25, 15) 5 """
while b: a, b = b, a % b return a
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate(3, 7) == 1 assert candidate(10, 15) == 5 assert candidate(49, 14) == 7 assert candidate(144, 60) == 12
greatest_common_divisor
HumanEval/14
from typing import List def all_prefixes(string: str) -> List[str]: """ Return list of all prefixes from shortest to longest of the input string >>> all_prefixes('abc') ['a', 'ab', 'abc'] """
result = [] for i in range(len(string)): result.append(string[:i+1]) return result
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('') == [] assert candidate('asdfgh') == ['a', 'as', 'asd', 'asdf', 'asdfg', 'asdfgh'] assert candidate('WWW') == ['W', 'WW', 'WWW']
all_prefixes
HumanEval/15
def string_sequence(n: int) -> str: """ Return a string containing space-delimited numbers starting from 0 upto n inclusive. >>> string_sequence(0) '0' >>> string_sequence(5) '0 1 2 3 4 5' """
return ' '.join([str(x) for x in range(n + 1)])
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate(0) == '0' assert candidate(3) == '0 1 2 3' assert candidate(10) == '0 1 2 3 4 5 6 7 8 9 10'
string_sequence
HumanEval/16
def count_distinct_characters(string: str) -> int: """ Given a string, find out how many distinct characters (regardless of case) does it consist of >>> count_distinct_characters('xyzXYZ') 3 >>> count_distinct_characters('Jerry') 4 """
return len(set(string.lower()))
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('') == 0 assert candidate('abcde') == 5 assert candidate('abcde' + 'cade' + 'CADE') == 5 assert candidate('aaaaAAAAaaaa') == 1 assert candidate('Jerry jERRY JeRRRY') == 5
count_distinct_characters
HumanEval/17
from typing import List def parse_music(music_string: str) -> List[int]: """ Input to this function is a string representing musical notes in a special ASCII format. Your task is to parse this string and return list of integers corresponding to how many beats does each not last. Here is a legend: 'o' - whole note, lasts four beats 'o|' - half note, lasts two beats '.|' - quater note, lasts one beat >>> parse_music('o o| .| o| o| .| .| .| .| o o') [4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4] """
note_map = {'o': 4, 'o|': 2, '.|': 1} return [note_map[x] for x in music_string.split(' ') if x]
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('') == [] assert candidate('o o o o') == [4, 4, 4, 4] assert candidate('.| .| .| .|') == [1, 1, 1, 1] assert candidate('o| o| .| .| o o o o') == [2, 2, 1, 1, 4, 4, 4, 4] assert candidate('o| .| o| .| o o| o o|') == [2, 1, 2, 1, 4, 2, 4, 2]
parse_music
HumanEval/18
def how_many_times(string: str, substring: str) -> int: """ Find how many times a given substring can be found in the original string. Count overlaping cases. >>> how_many_times('', 'a') 0 >>> how_many_times('aaa', 'a') 3 >>> how_many_times('aaaa', 'aa') 3 """
times = 0 for i in range(len(string) - len(substring) + 1): if string[i:i+len(substring)] == substring: times += 1 return times
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('', 'x') == 0 assert candidate('xyxyxyx', 'x') == 4 assert candidate('cacacacac', 'cac') == 4 assert candidate('john doe', 'john') == 1
how_many_times
HumanEval/19
from typing import List def sort_numbers(numbers: str) -> str: """ Input is a space-delimited string of numberals from 'zero' to 'nine'. Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'. Return the string with numbers sorted from smallest to largest >>> sort_numbers('three one five') 'one three five' """
value_map = { 'zero': 0, 'one': 1, 'two': 2, 'three': 3, 'four': 4, 'five': 5, 'six': 6, 'seven': 7, 'eight': 8, 'nine': 9 } return ' '.join(sorted([x for x in numbers.split(' ') if x], key=lambda x: value_map[x]))
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('') == '' assert candidate('three') == 'three' assert candidate('three five nine') == 'three five nine' assert candidate('five zero four seven nine eight') == 'zero four five seven eight nine' assert candidate('six five four three two one zero') == 'zero one two three four five six'
sort_numbers
HumanEval/20
from typing import List, Tuple def find_closest_elements(numbers: List[float]) -> Tuple[float, float]: """ From a supplied list of numbers (of length at least two) select and return two that are the closest to each other and return them in order (smaller number, larger number). >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) (2.0, 2.2) >>> find_closest_elements([1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) (2.0, 2.0) """
closest_pair = None distance = None for idx, elem in enumerate(numbers): for idx2, elem2 in enumerate(numbers): if idx != idx2: if distance is None: distance = abs(elem - elem2) closest_pair = tuple(sorted([elem, elem2])) else: new_distance = abs(elem - elem2) if new_distance < distance: distance = new_distance closest_pair = tuple(sorted([elem, elem2])) return closest_pair
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([1.0, 2.0, 3.9, 4.0, 5.0, 2.2]) == (3.9, 4.0) assert candidate([1.0, 2.0, 5.9, 4.0, 5.0]) == (5.0, 5.9) assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.2]) == (2.0, 2.2) assert candidate([1.0, 2.0, 3.0, 4.0, 5.0, 2.0]) == (2.0, 2.0) assert candidate([1.1, 2.2, 3.1, 4.1, 5.1]) == (2.2, 3.1)
find_closest_elements
HumanEval/21
from typing import List def rescale_to_unit(numbers: List[float]) -> List[float]: """ Given list of numbers (of at least two elements), apply a linear transform to that list, such that the smallest number will become 0 and the largest will become 1 >>> rescale_to_unit([1.0, 2.0, 3.0, 4.0, 5.0]) [0.0, 0.25, 0.5, 0.75, 1.0] """
min_number = min(numbers) max_number = max(numbers) return [(x - min_number) / (max_number - min_number) for x in numbers]
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([2.0, 49.9]) == [0.0, 1.0] assert candidate([100.0, 49.9]) == [1.0, 0.0] assert candidate([1.0, 2.0, 3.0, 4.0, 5.0]) == [0.0, 0.25, 0.5, 0.75, 1.0] assert candidate([2.0, 1.0, 5.0, 3.0, 4.0]) == [0.25, 0.0, 1.0, 0.5, 0.75] assert candidate([12.0, 11.0, 15.0, 13.0, 14.0]) == [0.25, 0.0, 1.0, 0.5, 0.75]
rescale_to_unit
HumanEval/22
from typing import List, Any def filter_integers(values: List[Any]) -> List[int]: """ Filter given list of any python values only for integers >>> filter_integers(['a', 3.14, 5]) [5] >>> filter_integers([1, 2, 3, 'abc', {}, []]) [1, 2, 3] """
return [x for x in values if isinstance(x, int)]
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([]) == [] assert candidate([4, {}, [], 23.2, 9, 'adasd']) == [4, 9] assert candidate([3, 'c', 3, 3, 'a', 'b']) == [3, 3, 3]
filter_integers
HumanEval/23
def strlen(string: str) -> int: """ Return length of given string >>> strlen('') 0 >>> strlen('abc') 3 """
return len(string)
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('') == 0 assert candidate('x') == 1 assert candidate('asdasnakj') == 9
strlen
HumanEval/24
def largest_divisor(n: int) -> int: """ For a given number n, find the largest number that divides n evenly, smaller than n >>> largest_divisor(15) 5 """
for i in reversed(range(n)): if n % i == 0: return i
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate(3) == 1 assert candidate(7) == 1 assert candidate(10) == 5 assert candidate(100) == 50 assert candidate(49) == 7
largest_divisor
HumanEval/25
from typing import List def factorize(n: int) -> List[int]: """ Return list of prime factors of given integer in the order from smallest to largest. Each of the factors should be listed number of times corresponding to how many times it appeares in factorization. Input number should be equal to the product of all factors >>> factorize(8) [2, 2, 2] >>> factorize(25) [5, 5] >>> factorize(70) [2, 5, 7] """
import math fact = [] i = 2 while i <= int(math.sqrt(n) + 1): if n % i == 0: fact.append(i) n //= i else: i += 1 if n > 1: fact.append(n) return fact
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate(2) == [2] assert candidate(4) == [2, 2] assert candidate(8) == [2, 2, 2] assert candidate(3 * 19) == [3, 19] assert candidate(3 * 19 * 3 * 19) == [3, 3, 19, 19] assert candidate(3 * 19 * 3 * 19 * 3 * 19) == [3, 3, 3, 19, 19, 19] assert candidate(3 * 19 * 19 * 19) == [3, 19, 19, 19] assert candidate(3 * 2 * 3) == [2, 3, 3]
factorize
HumanEval/26
from typing import List def remove_duplicates(numbers: List[int]) -> List[int]: """ From a list of integers, remove all elements that occur more than once. Keep order of elements left the same as in the input. >>> remove_duplicates([1, 2, 3, 2, 4]) [1, 3, 4] """
import collections c = collections.Counter(numbers) return [n for n in numbers if c[n] <= 1]
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([]) == [] assert candidate([1, 2, 3, 4]) == [1, 2, 3, 4] assert candidate([1, 2, 3, 2, 4, 3, 5]) == [1, 4, 5]
remove_duplicates
HumanEval/27
def flip_case(string: str) -> str: """ For a given string, flip lowercase characters to uppercase and uppercase to lowercase. >>> flip_case('Hello') 'hELLO' """
return string.swapcase()
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate('') == '' assert candidate('Hello!') == 'hELLO!' assert candidate('These violent delights have violent ends') == 'tHESE VIOLENT DELIGHTS HAVE VIOLENT ENDS'
flip_case
HumanEval/28
from typing import List def concatenate(strings: List[str]) -> str: """ Concatenate list of strings into a single string >>> concatenate([]) '' >>> concatenate(['a', 'b', 'c']) 'abc' """
return ''.join(strings)
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([]) == '' assert candidate(['x', 'y', 'z']) == 'xyz' assert candidate(['x', 'y', 'z', 'w', 'k']) == 'xyzwk'
concatenate
HumanEval/29
from typing import List def filter_by_prefix(strings: List[str], prefix: str) -> List[str]: """ Filter an input list of strings only for ones that start with a given prefix. >>> filter_by_prefix([], 'a') [] >>> filter_by_prefix(['abc', 'bcd', 'cde', 'array'], 'a') ['abc', 'array'] """
return [x for x in strings if x.startswith(prefix)]
METADATA = { 'author': 'jt', 'dataset': 'test' } def check(candidate): assert candidate([], 'john') == [] assert candidate(['xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'], 'xxx') == ['xxx', 'xxxAAA', 'xxx']
filter_by_prefix
HumanEval/30
def get_positive(l: list): """Return only positive numbers in the list. >>> get_positive([-1, 2, -4, 5, 6]) [2, 5, 6] >>> get_positive([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) [5, 3, 2, 3, 9, 123, 1] """
return [e for e in l if e > 0]
METADATA = {} def check(candidate): assert candidate([-1, -2, 4, 5, 6]) == [4, 5, 6] assert candidate([5, 3, -5, 2, 3, 3, 9, 0, 123, 1, -10]) == [5, 3, 2, 3, 3, 9, 123, 1] assert candidate([-1, -2]) == [] assert candidate([]) == []
get_positive
HumanEval/31
def is_prime(n): """Return true if a given number is prime, and false otherwise. >>> is_prime(6) False >>> is_prime(101) True >>> is_prime(11) True >>> is_prime(13441) True >>> is_prime(61) True >>> is_prime(4) False >>> is_prime(1) False """
if n < 2: return False for k in range(2, n - 1): if n % k == 0: return False return True
METADATA = {} def check(candidate): assert candidate(6) == False assert candidate(101) == True assert candidate(11) == True assert candidate(13441) == True assert candidate(61) == True assert candidate(4) == False assert candidate(1) == False assert candidate(5) == True assert candidate(11) == True assert candidate(17) == True assert candidate(5 * 17) == False assert candidate(11 * 7) == False assert candidate(13441 * 19) == False
is_prime
HumanEval/32
import math def poly(xs: list, x: float): """ Evaluates polynomial with coefficients xs at point x. return xs[0] + xs[1] * x + xs[1] * x^2 + .... xs[n] * x^n """ return sum([coeff * math.pow(x, i) for i, coeff in enumerate(xs)]) def find_zero(xs: list): """ xs are coefficients of a polynomial. find_zero find x such that poly(x) = 0. find_zero returns only only zero point, even if there are many. Moreover, find_zero only takes list xs having even number of coefficients and largest non zero coefficient as it guarantees a solution. >>> round(find_zero([1, 2]), 2) # f(x) = 1 + 2x -0.5 >>> round(find_zero([-6, 11, -6, 1]), 2) # (x - 1) * (x - 2) * (x - 3) = -6 + 11x - 6x^2 + x^3 1.0 """
begin, end = -1., 1. while poly(xs, begin) * poly(xs, end) > 0: begin *= 2.0 end *= 2.0 while end - begin > 1e-10: center = (begin + end) / 2.0 if poly(xs, center) * poly(xs, begin) > 0: begin = center else: end = center return begin
METADATA = {} def check(candidate): import math import random rng = random.Random(42) import copy for _ in range(100): ncoeff = 2 * rng.randint(1, 4) coeffs = [] for _ in range(ncoeff): coeff = rng.randint(-10, 10) if coeff == 0: coeff = 1 coeffs.append(coeff) solution = candidate(copy.deepcopy(coeffs)) assert math.fabs(poly(coeffs, solution)) < 1e-4
find_zero
HumanEval/33
def sort_third(l: list): """This function takes a list l and returns a list l' such that l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal to the values of the corresponding indicies of l, but sorted. >>> sort_third([1, 2, 3]) [1, 2, 3] >>> sort_third([5, 6, 3, 4, 8, 9, 2]) [2, 6, 3, 4, 8, 9, 5] """
l = list(l) l[::3] = sorted(l[::3]) return l
METADATA = {} def check(candidate): assert tuple(candidate([1, 2, 3])) == tuple(sort_third([1, 2, 3])) assert tuple(candidate([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) == tuple(sort_third([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) assert tuple(candidate([5, 8, -12, 4, 23, 2, 3, 11, 12, -10])) == tuple(sort_third([5, 8, -12, 4, 23, 2, 3, 11, 12, -10])) assert tuple(candidate([5, 6, 3, 4, 8, 9, 2])) == tuple([2, 6, 3, 4, 8, 9, 5]) assert tuple(candidate([5, 8, 3, 4, 6, 9, 2])) == tuple([2, 8, 3, 4, 6, 9, 5]) assert tuple(candidate([5, 6, 9, 4, 8, 3, 2])) == tuple([2, 6, 9, 4, 8, 3, 5]) assert tuple(candidate([5, 6, 3, 4, 8, 9, 2, 1])) == tuple([2, 6, 3, 4, 8, 9, 5, 1])
sort_third
HumanEval/34
def unique(l: list): """Return sorted unique elements in a list >>> unique([5, 3, 5, 2, 3, 3, 9, 0, 123]) [0, 2, 3, 5, 9, 123] """
return sorted(list(set(l)))
METADATA = {} def check(candidate): assert candidate([5, 3, 5, 2, 3, 3, 9, 0, 123]) == [0, 2, 3, 5, 9, 123]
unique
HumanEval/35
def max_element(l: list): """Return maximum element in the list. >>> max_element([1, 2, 3]) 3 >>> max_element([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10]) 123 """
m = l[0] for e in l: if e > m: m = e return m
METADATA = {} def check(candidate): assert candidate([1, 2, 3]) == 3 assert candidate([5, 3, -5, 2, -3, 3, 9, 0, 124, 1, -10]) == 124
max_element
HumanEval/36
def fizz_buzz(n: int): """Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13. >>> fizz_buzz(50) 0 >>> fizz_buzz(78) 2 >>> fizz_buzz(79) 3 """
ns = [] for i in range(n): if i % 11 == 0 or i % 13 == 0: ns.append(i) s = ''.join(list(map(str, ns))) ans = 0 for c in s: ans += (c == '7') return ans
METADATA = {} def check(candidate): assert candidate(50) == 0 assert candidate(78) == 2 assert candidate(79) == 3 assert candidate(100) == 3 assert candidate(200) == 6 assert candidate(4000) == 192 assert candidate(10000) == 639 assert candidate(100000) == 8026
fizz_buzz
HumanEval/37
def sort_even(l: list): """This function takes a list l and returns a list l' such that l' is identical to l in the odd indicies, while its values at the even indicies are equal to the values of the even indicies of l, but sorted. >>> sort_even([1, 2, 3]) [1, 2, 3] >>> sort_even([5, 6, 3, 4]) [3, 6, 5, 4] """
evens = l[::2] odds = l[1::2] evens.sort() ans = [] for e, o in zip(evens, odds): ans.extend([e, o]) if len(evens) > len(odds): ans.append(evens[-1]) return ans
METADATA = {} def check(candidate): assert tuple(candidate([1, 2, 3])) == tuple([1, 2, 3]) assert tuple(candidate([5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10])) == tuple([-10, 3, -5, 2, -3, 3, 5, 0, 9, 1, 123]) assert tuple(candidate([5, 8, -12, 4, 23, 2, 3, 11, 12, -10])) == tuple([-12, 8, 3, 4, 5, 2, 12, 11, 23, -10])
sort_even
HumanEval/38
def encode_cyclic(s: str): """ returns encoded string by cycling groups of three characters. """ # split string to groups. Each of length 3. groups = [s[(3 * i):min((3 * i + 3), len(s))] for i in range((len(s) + 2) // 3)] # cycle elements in each group. Unless group has fewer elements than 3. groups = [(group[1:] + group[0]) if len(group) == 3 else group for group in groups] return "".join(groups) def decode_cyclic(s: str): """ takes as input string encoded with encode_cyclic function. Returns decoded string. """
return encode_cyclic(encode_cyclic(s))
METADATA = {} def check(candidate): from random import randint, choice import string letters = string.ascii_lowercase for _ in range(100): str = ''.join(choice(letters) for i in range(randint(10, 20))) encoded_str = encode_cyclic(str) assert candidate(encoded_str) == str
decode_cyclic
HumanEval/39
def prime_fib(n: int): """ prime_fib returns n-th number that is a Fibonacci number and it's also prime. >>> prime_fib(1) 2 >>> prime_fib(2) 3 >>> prime_fib(3) 5 >>> prime_fib(4) 13 >>> prime_fib(5) 89 """
import math def is_prime(p): if p < 2: return False for k in range(2, min(int(math.sqrt(p)) + 1, p - 1)): if p % k == 0: return False return True f = [0, 1] while True: f.append(f[-1] + f[-2]) if is_prime(f[-1]): n -= 1 if n == 0: return f[-1]
METADATA = {} def check(candidate): assert candidate(1) == 2 assert candidate(2) == 3 assert candidate(3) == 5 assert candidate(4) == 13 assert candidate(5) == 89 assert candidate(6) == 233 assert candidate(7) == 1597 assert candidate(8) == 28657 assert candidate(9) == 514229 assert candidate(10) == 433494437
prime_fib
HumanEval/40
def triples_sum_to_zero(l: list): """ triples_sum_to_zero takes a list of integers as an input. it returns True if there are three distinct elements in the list that sum to zero, and False otherwise. >>> triples_sum_to_zero([1, 3, 5, 0]) False >>> triples_sum_to_zero([1, 3, -2, 1]) True >>> triples_sum_to_zero([1, 2, 3, 7]) False >>> triples_sum_to_zero([2, 4, -5, 3, 9, 7]) True >>> triples_sum_to_zero([1]) False """
for i in range(len(l)): for j in range(i + 1, len(l)): for k in range(j + 1, len(l)): if l[i] + l[j] + l[k] == 0: return True return False
METADATA = {} def check(candidate): assert candidate([1, 3, 5, 0]) == False assert candidate([1, 3, 5, -1]) == False assert candidate([1, 3, -2, 1]) == True assert candidate([1, 2, 3, 7]) == False assert candidate([1, 2, 5, 7]) == False assert candidate([2, 4, -5, 3, 9, 7]) == True assert candidate([1]) == False assert candidate([1, 3, 5, -100]) == False assert candidate([100, 3, 5, -100]) == False
triples_sum_to_zero
HumanEval/41
def car_race_collision(n: int): """ Imagine a road that's a perfectly straight infinitely long line. n cars are driving left to right; simultaneously, a different set of n cars are driving right to left. The two sets of cars start out being very far from each other. All cars move in the same speed. Two cars are said to collide when a car that's moving left to right hits a car that's moving right to left. However, the cars are infinitely sturdy and strong; as a result, they continue moving in their trajectory as if they did not collide. This function outputs the number of such collisions. """
return n**2
METADATA = {} def check(candidate): assert candidate(2) == 4 assert candidate(3) == 9 assert candidate(4) == 16 assert candidate(8) == 64 assert candidate(10) == 100
car_race_collision
HumanEval/42
def incr_list(l: list): """Return list with elements incremented by 1. >>> incr_list([1, 2, 3]) [2, 3, 4] >>> incr_list([5, 3, 5, 2, 3, 3, 9, 0, 123]) [6, 4, 6, 3, 4, 4, 10, 1, 124] """
return [(e + 1) for e in l]
METADATA = {} def check(candidate): assert candidate([]) == [] assert candidate([3, 2, 1]) == [4, 3, 2] assert candidate([5, 2, 5, 2, 3, 3, 9, 0, 123]) == [6, 3, 6, 3, 4, 4, 10, 1, 124]
incr_list
HumanEval/43
def pairs_sum_to_zero(l): """ pairs_sum_to_zero takes a list of integers as an input. it returns True if there are two distinct elements in the list that sum to zero, and False otherwise. >>> pairs_sum_to_zero([1, 3, 5, 0]) False >>> pairs_sum_to_zero([1, 3, -2, 1]) False >>> pairs_sum_to_zero([1, 2, 3, 7]) False >>> pairs_sum_to_zero([2, 4, -5, 3, 5, 7]) True >>> pairs_sum_to_zero([1]) False """
for i, l1 in enumerate(l): for j in range(i + 1, len(l)): if l1 + l[j] == 0: return True return False
METADATA = {} def check(candidate): assert candidate([1, 3, 5, 0]) == False assert candidate([1, 3, -2, 1]) == False assert candidate([1, 2, 3, 7]) == False assert candidate([2, 4, -5, 3, 5, 7]) == True assert candidate([1]) == False assert candidate([-3, 9, -1, 3, 2, 30]) == True assert candidate([-3, 9, -1, 3, 2, 31]) == True assert candidate([-3, 9, -1, 4, 2, 30]) == False assert candidate([-3, 9, -1, 4, 2, 31]) == False
pairs_sum_to_zero
HumanEval/44
def change_base(x: int, base: int): """Change numerical base of input number x to base. return string representation after the conversion. base numbers are less than 10. >>> change_base(8, 3) '22' >>> change_base(8, 2) '1000' >>> change_base(7, 2) '111' """
ret = "" while x > 0: ret = str(x % base) + ret x //= base return ret
METADATA = {} def check(candidate): assert candidate(8, 3) == "22" assert candidate(9, 3) == "100" assert candidate(234, 2) == "11101010" assert candidate(16, 2) == "10000" assert candidate(8, 2) == "1000" assert candidate(7, 2) == "111" for x in range(2, 8): assert candidate(x, x + 1) == str(x)
change_base
HumanEval/45
def triangle_area(a, h): """Given length of a side and high return area for a triangle. >>> triangle_area(5, 3) 7.5 """
return a * h / 2.0
METADATA = {} def check(candidate): assert candidate(5, 3) == 7.5 assert candidate(2, 2) == 2.0 assert candidate(10, 8) == 40.0
triangle_area
HumanEval/46
def fib4(n: int): """The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows: fib4(0) -> 0 fib4(1) -> 0 fib4(2) -> 2 fib4(3) -> 0 fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4). Please write a function to efficiently compute the n-th element of the fib4 number sequence. Do not use recursion. >>> fib4(5) 4 >>> fib4(6) 8 >>> fib4(7) 14 """
results = [0, 0, 2, 0] if n < 4: return results[n] for _ in range(4, n + 1): results.append(results[-1] + results[-2] + results[-3] + results[-4]) results.pop(0) return results[-1]
METADATA = {} def check(candidate): assert candidate(5) == 4 assert candidate(8) == 28 assert candidate(10) == 104 assert candidate(12) == 386
fib4
HumanEval/47
def median(l: list): """Return median of elements in the list l. >>> median([3, 1, 2, 4, 5]) 3 >>> median([-10, 4, 6, 1000, 10, 20]) 15.0 """
l = sorted(l) if len(l) % 2 == 1: return l[len(l) // 2] else: return (l[len(l) // 2 - 1] + l[len(l) // 2]) / 2.0
METADATA = {} def check(candidate): assert candidate([3, 1, 2, 4, 5]) == 3 assert candidate([-10, 4, 6, 1000, 10, 20]) == 8.0 assert candidate([5]) == 5 assert candidate([6, 5]) == 5.5 assert candidate([8, 1, 3, 9, 9, 2, 7]) == 7
median
HumanEval/48
def is_palindrome(text: str): """ Checks if given string is a palindrome >>> is_palindrome('') True >>> is_palindrome('aba') True >>> is_palindrome('aaaaa') True >>> is_palindrome('zbcd') False """
for i in range(len(text)): if text[i] != text[len(text) - 1 - i]: return False return True
METADATA = {} def check(candidate): assert candidate('') == True assert candidate('aba') == True assert candidate('aaaaa') == True assert candidate('zbcd') == False assert candidate('xywyx') == True assert candidate('xywyz') == False assert candidate('xywzx') == False
is_palindrome
HumanEval/49
def modp(n: int, p: int): """Return 2^n modulo p (be aware of numerics). >>> modp(3, 5) 3 >>> modp(1101, 101) 2 >>> modp(0, 101) 1 >>> modp(3, 11) 8 >>> modp(100, 101) 1 """
ret = 1 for i in range(n): ret = (2 * ret) % p return ret
METADATA = {} def check(candidate): assert candidate(3, 5) == 3 assert candidate(1101, 101) == 2 assert candidate(0, 101) == 1 assert candidate(3, 11) == 8 assert candidate(100, 101) == 1 assert candidate(30, 5) == 4 assert candidate(31, 5) == 3
modp
HumanEval/50
def encode_shift(s: str): """ returns encoded string by shifting every character by 5 in the alphabet. """ return "".join([chr(((ord(ch) + 5 - ord("a")) % 26) + ord("a")) for ch in s]) def decode_shift(s: str): """ takes as input string encoded with encode_shift function. Returns decoded string. """
return "".join([chr(((ord(ch) - 5 - ord("a")) % 26) + ord("a")) for ch in s])
METADATA = {} def check(candidate): from random import randint, choice import copy import string letters = string.ascii_lowercase for _ in range(100): str = ''.join(choice(letters) for i in range(randint(10, 20))) encoded_str = encode_shift(str) assert candidate(copy.deepcopy(encoded_str)) == str
decode_shift
HumanEval/51
def remove_vowels(text): """ remove_vowels is a function that takes string and returns string without vowels. >>> remove_vowels('') '' >>> remove_vowels("abcdef\nghijklm") 'bcdf\nghjklm' >>> remove_vowels('abcdef') 'bcdf' >>> remove_vowels('aaaaa') '' >>> remove_vowels('aaBAA') 'B' >>> remove_vowels('zbcd') 'zbcd' """
return "".join([s for s in text if s.lower() not in ["a", "e", "i", "o", "u"]])
METADATA = {} def check(candidate): assert candidate('') == '' assert candidate("abcdef\nghijklm") == 'bcdf\nghjklm' assert candidate('fedcba') == 'fdcb' assert candidate('eeeee') == '' assert candidate('acBAA') == 'cB' assert candidate('EcBOO') == 'cB' assert candidate('ybcd') == 'ybcd'
remove_vowels
HumanEval/52
def below_threshold(l: list, t: int): """Return True if all numbers in the list l are below threshold t. >>> below_threshold([1, 2, 4, 10], 100) True >>> below_threshold([1, 20, 4, 10], 5) False """
for e in l: if e >= t: return False return True
METADATA = {} def check(candidate): assert candidate([1, 2, 4, 10], 100) assert not candidate([1, 20, 4, 10], 5) assert candidate([1, 20, 4, 10], 21) assert candidate([1, 20, 4, 10], 22) assert candidate([1, 8, 4, 10], 11) assert not candidate([1, 8, 4, 10], 10)
below_threshold
HumanEval/53
def add(x: int, y: int): """Add two numbers x and y >>> add(2, 3) 5 >>> add(5, 7) 12 """
return x + y
METADATA = {} def check(candidate): import random assert candidate(0, 1) == 1 assert candidate(1, 0) == 1 assert candidate(2, 3) == 5 assert candidate(5, 7) == 12 assert candidate(7, 5) == 12 for i in range(100): x, y = random.randint(0, 1000), random.randint(0, 1000) assert candidate(x, y) == x + y
add
HumanEval/54
def same_chars(s0: str, s1: str): """ Check if two words have the same characters. >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc') True >>> same_chars('abcd', 'dddddddabc') True >>> same_chars('dddddddabc', 'abcd') True >>> same_chars('eabcd', 'dddddddabc') False >>> same_chars('abcd', 'dddddddabce') False >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc') False """
return set(s0) == set(s1)
METADATA = {} def check(candidate): assert candidate('eabcdzzzz', 'dddzzzzzzzddeddabc') == True assert candidate('abcd', 'dddddddabc') == True assert candidate('dddddddabc', 'abcd') == True assert candidate('eabcd', 'dddddddabc') == False assert candidate('abcd', 'dddddddabcf') == False assert candidate('eabcdzzzz', 'dddzzzzzzzddddabc') == False assert candidate('aabb', 'aaccc') == False
same_chars
HumanEval/55
def fib(n: int): """Return n-th Fibonacci number. >>> fib(10) 55 >>> fib(1) 1 >>> fib(8) 21 """
if n == 0: return 0 if n == 1: return 1 return fib(n - 1) + fib(n - 2)
METADATA = {} def check(candidate): assert candidate(10) == 55 assert candidate(1) == 1 assert candidate(8) == 21 assert candidate(11) == 89 assert candidate(12) == 144
fib
HumanEval/56
def correct_bracketing(brackets: str): """ brackets is a string of "<" and ">". return True if every opening bracket has a corresponding closing bracket. >>> correct_bracketing("<") False >>> correct_bracketing("<>") True >>> correct_bracketing("<<><>>") True >>> correct_bracketing("><<>") False """
depth = 0 for b in brackets: if b == "<": depth += 1 else: depth -= 1 if depth < 0: return False return depth == 0
METADATA = {} def check(candidate): assert candidate("<>") assert candidate("<<><>>") assert candidate("<><><<><>><>") assert candidate("<><><<<><><>><>><<><><<>>>") assert not candidate("<<<><>>>>") assert not candidate("><<>") assert not candidate("<") assert not candidate("<<<<") assert not candidate(">") assert not candidate("<<>") assert not candidate("<><><<><>><>><<>") assert not candidate("<><><<><>><>>><>")
correct_bracketing
HumanEval/57
def monotonic(l: list): """Return True is list elements are monotonically increasing or decreasing. >>> monotonic([1, 2, 4, 20]) True >>> monotonic([1, 20, 4, 10]) False >>> monotonic([4, 1, 0, -10]) True """
if l == sorted(l) or l == sorted(l, reverse=True): return True return False
METADATA = {} def check(candidate): assert candidate([1, 2, 4, 10]) == True assert candidate([1, 2, 4, 20]) == True assert candidate([1, 20, 4, 10]) == False assert candidate([4, 1, 0, -10]) == True assert candidate([4, 1, 1, 0]) == True assert candidate([1, 2, 3, 2, 5, 60]) == False assert candidate([1, 2, 3, 4, 5, 60]) == True assert candidate([9, 9, 9, 9]) == True
monotonic
HumanEval/58
def common(l1: list, l2: list): """Return sorted unique common elements for two lists. >>> common([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) [1, 5, 653] >>> common([5, 3, 2, 8], [3, 2]) [2, 3] """
ret = set() for e1 in l1: for e2 in l2: if e1 == e2: ret.add(e1) return sorted(list(ret))
METADATA = {} def check(candidate): assert candidate([1, 4, 3, 34, 653, 2, 5], [5, 7, 1, 5, 9, 653, 121]) == [1, 5, 653] assert candidate([5, 3, 2, 8], [3, 2]) == [2, 3] assert candidate([4, 3, 2, 8], [3, 2, 4]) == [2, 3, 4] assert candidate([4, 3, 2, 8], []) == []
common
HumanEval/59
def largest_prime_factor(n: int): """Return the largest prime factor of n. Assume n > 1 and is not a prime. >>> largest_prime_factor(13195) 29 >>> largest_prime_factor(2048) 2 """
def is_prime(k): if k < 2: return False for i in range(2, k - 1): if k % i == 0: return False return True largest = 1 for j in range(2, n + 1): if n % j == 0 and is_prime(j): largest = max(largest, j) return largest
METADATA = {} def check(candidate): assert candidate(15) == 5 assert candidate(27) == 3 assert candidate(63) == 7 assert candidate(330) == 11 assert candidate(13195) == 29
largest_prime_factor
HumanEval/60
def sum_to_n(n: int): """sum_to_n is a function that sums numbers from 1 to n. >>> sum_to_n(30) 465 >>> sum_to_n(100) 5050 >>> sum_to_n(5) 15 >>> sum_to_n(10) 55 >>> sum_to_n(1) 1 """
return sum(range(n + 1))
METADATA = {} def check(candidate): assert candidate(1) == 1 assert candidate(6) == 21 assert candidate(11) == 66 assert candidate(30) == 465 assert candidate(100) == 5050
sum_to_n
HumanEval/61
def correct_bracketing(brackets: str): """ brackets is a string of "(" and ")". return True if every opening bracket has a corresponding closing bracket. >>> correct_bracketing("(") False >>> correct_bracketing("()") True >>> correct_bracketing("(()())") True >>> correct_bracketing(")(()") False """
depth = 0 for b in brackets: if b == "(": depth += 1 else: depth -= 1 if depth < 0: return False return depth == 0
METADATA = {} def check(candidate): assert candidate("()") assert candidate("(()())") assert candidate("()()(()())()") assert candidate("()()((()()())())(()()(()))") assert not candidate("((()())))") assert not candidate(")(()") assert not candidate("(") assert not candidate("((((") assert not candidate(")") assert not candidate("(()") assert not candidate("()()(()())())(()") assert not candidate("()()(()())()))()")
correct_bracketing
HumanEval/62
def derivative(xs: list): """ xs represent coefficients of a polynomial. xs[0] + xs[1] * x + xs[2] * x^2 + .... Return derivative of this polynomial in the same form. >>> derivative([3, 1, 2, 4, 5]) [1, 4, 12, 20] >>> derivative([1, 2, 3]) [2, 6] """
return [(i * x) for i, x in enumerate(xs)][1:]
METADATA = {} def check(candidate): assert candidate([3, 1, 2, 4, 5]) == [1, 4, 12, 20] assert candidate([1, 2, 3]) == [2, 6] assert candidate([3, 2, 1]) == [2, 2] assert candidate([3, 2, 1, 0, 4]) == [2, 2, 0, 16] assert candidate([1]) == []
derivative
HumanEval/63
def fibfib(n: int): """The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows: fibfib(0) == 0 fibfib(1) == 0 fibfib(2) == 1 fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3). Please write a function to efficiently compute the n-th element of the fibfib number sequence. >>> fibfib(1) 0 >>> fibfib(5) 4 >>> fibfib(8) 24 """
if n == 0: return 0 if n == 1: return 0 if n == 2: return 1 return fibfib(n - 1) + fibfib(n - 2) + fibfib(n - 3)
METADATA = {} def check(candidate): assert candidate(2) == 1 assert candidate(1) == 0 assert candidate(5) == 4 assert candidate(8) == 24 assert candidate(10) == 81 assert candidate(12) == 274 assert candidate(14) == 927
fibfib
HumanEval/64
FIX = """ Add more test cases. """ def vowels_count(s): """Write a function vowels_count which takes a string representing a word as input and returns the number of vowels in the string. Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a vowel, but only when it is at the end of the given word. Example: >>> vowels_count("abcde") 2 >>> vowels_count("ACEDY") 3 """
vowels = "aeiouAEIOU" n_vowels = sum(c in vowels for c in s) if s[-1] == 'y' or s[-1] == 'Y': n_vowels += 1 return n_vowels
def check(candidate): # Check some simple cases assert candidate("abcde") == 2, "Test 1" assert candidate("Alone") == 3, "Test 2" assert candidate("key") == 2, "Test 3" assert candidate("bye") == 1, "Test 4" assert candidate("keY") == 2, "Test 5" assert candidate("bYe") == 1, "Test 6" assert candidate("ACEDY") == 3, "Test 7" # Check some edge cases that are easy to work out by hand. assert True, "This prints if this assert fails 2 (also good for debugging!)"
vowels_count
HumanEval/65
def circular_shift(x, shift): """Circular shift the digits of the integer x, shift the digits right by shift and return the result as a string. If shift > number of digits, return digits reversed. >>> circular_shift(12, 1) "21" >>> circular_shift(12, 2) "12" """
s = str(x) if shift > len(s): return s[::-1] else: return s[len(s) - shift:] + s[:len(s) - shift]
def check(candidate): # Check some simple cases assert candidate(100, 2) == "001" assert candidate(12, 2) == "12" assert candidate(97, 8) == "79" assert candidate(12, 1) == "21", "This prints if this assert fails 1 (good for debugging!)" # Check some edge cases that are easy to work out by hand. assert candidate(11, 101) == "11", "This prints if this assert fails 2 (also good for debugging!)"
circular_shift
HumanEval/66
def digitSum(s): """Task Write a function that takes a string as input and returns the sum of the upper characters only' ASCII codes. Examples: digitSum("") => 0 digitSum("abAB") => 131 digitSum("abcCd") => 67 digitSum("helloE") => 69 digitSum("woArBld") => 131 digitSum("aAaaaXa") => 153 """
if s == "": return 0 return sum(ord(char) if char.isupper() else 0 for char in s)
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate("") == 0, "Error" assert candidate("abAB") == 131, "Error" assert candidate("abcCd") == 67, "Error" assert candidate("helloE") == 69, "Error" assert candidate("woArBld") == 131, "Error" assert candidate("aAaaaXa") == 153, "Error" # Check some edge cases that are easy to work out by hand. assert True, "This prints if this assert fails 2 (also good for debugging!)" assert candidate(" How are yOu?") == 151, "Error" assert candidate("You arE Very Smart") == 327, "Error"
digitSum
HumanEval/67
def fruit_distribution(s,n): """ In this task, you will be given a string that represents a number of apples and oranges that are distributed in a basket of fruit this basket contains apples, oranges, and mango fruits. Given the string that represents the total number of the oranges and apples and an integer that represent the total number of the fruits in the basket return the number of the mango fruits in the basket. for examble: fruit_distribution("5 apples and 6 oranges", 19) ->19 - 5 - 6 = 8 fruit_distribution("0 apples and 1 oranges",3) -> 3 - 0 - 1 = 2 fruit_distribution("2 apples and 3 oranges", 100) -> 100 - 2 - 3 = 95 fruit_distribution("100 apples and 1 oranges",120) -> 120 - 100 - 1 = 19 """
lis = list() for i in s.split(' '): if i.isdigit(): lis.append(int(i)) return n - sum(lis)
def check(candidate): # Check some simple cases assert candidate("5 apples and 6 oranges",19) == 8 assert candidate("5 apples and 6 oranges",21) == 10 assert candidate("0 apples and 1 oranges",3) == 2 assert candidate("1 apples and 0 oranges",3) == 2 assert candidate("2 apples and 3 oranges",100) == 95 assert candidate("2 apples and 3 oranges",5) == 0 assert candidate("1 apples and 100 oranges",120) == 19
fruit_distribution
HumanEval/68
def pluck(arr): """ "Given an array representing a branch of a tree that has non-negative integer nodes your task is to pluck one of the nodes and return it. The plucked node should be the node with the smallest even value. If multiple nodes with the same smallest even value are found return the node that has smallest index. The plucked node should be returned in a list, [ smalest_value, its index ], If there are no even values or the given array is empty, return []. Example 1: Input: [4,2,3] Output: [2, 1] Explanation: 2 has the smallest even value, and 2 has the smallest index. Example 2: Input: [1,2,3] Output: [2, 1] Explanation: 2 has the smallest even value, and 2 has the smallest index. Example 3: Input: [] Output: [] Example 4: Input: [5, 0, 3, 0, 4, 2] Output: [0, 1] Explanation: 0 is the smallest value, but there are two zeros, so we will choose the first zero, which has the smallest index. Constraints: * 1 <= nodes.length <= 10000 * 0 <= node.value """
if(len(arr) == 0): return [] evens = list(filter(lambda x: x%2 == 0, arr)) if(evens == []): return [] return [min(evens), arr.index(min(evens))]
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate([4,2,3]) == [2, 1], "Error" assert candidate([1,2,3]) == [2, 1], "Error" assert candidate([]) == [], "Error" assert candidate([5, 0, 3, 0, 4, 2]) == [0, 1], "Error" # Check some edge cases that are easy to work out by hand. assert True, "This prints if this assert fails 2 (also good for debugging!)" assert candidate([1, 2, 3, 0, 5, 3]) == [0, 3], "Error" assert candidate([5, 4, 8, 4 ,8]) == [4, 1], "Error" assert candidate([7, 6, 7, 1]) == [6, 1], "Error" assert candidate([7, 9, 7, 1]) == [], "Error"
pluck
HumanEval/69
def search(lst): ''' You are given a non-empty list of positive integers. Return the greatest integer that is greater than zero, and has a frequency greater than or equal to the value of the integer itself. The frequency of an integer is the number of times it appears in the list. If no such a value exist, return -1. Examples: search([4, 1, 2, 2, 3, 1]) == 2 search([1, 2, 2, 3, 3, 3, 4, 4, 4]) == 3 search([5, 5, 4, 4, 4]) == -1 '''
frq = [0] * (max(lst) + 1) for i in lst: frq[i] += 1; ans = -1 for i in range(1, len(frq)): if frq[i] >= i: ans = i return ans
def check(candidate): # manually generated tests assert candidate([5, 5, 5, 5, 1]) == 1 assert candidate([4, 1, 4, 1, 4, 4]) == 4 assert candidate([3, 3]) == -1 assert candidate([8, 8, 8, 8, 8, 8, 8, 8]) == 8 assert candidate([2, 3, 3, 2, 2]) == 2 # automatically generated tests assert candidate([2, 7, 8, 8, 4, 8, 7, 3, 9, 6, 5, 10, 4, 3, 6, 7, 1, 7, 4, 10, 8, 1]) == 1 assert candidate([3, 2, 8, 2]) == 2 assert candidate([6, 7, 1, 8, 8, 10, 5, 8, 5, 3, 10]) == 1 assert candidate([8, 8, 3, 6, 5, 6, 4]) == -1 assert candidate([6, 9, 6, 7, 1, 4, 7, 1, 8, 8, 9, 8, 10, 10, 8, 4, 10, 4, 10, 1, 2, 9, 5, 7, 9]) == 1 assert candidate([1, 9, 10, 1, 3]) == 1 assert candidate([6, 9, 7, 5, 8, 7, 5, 3, 7, 5, 10, 10, 3, 6, 10, 2, 8, 6, 5, 4, 9, 5, 3, 10]) == 5 assert candidate([1]) == 1 assert candidate([8, 8, 10, 6, 4, 3, 5, 8, 2, 4, 2, 8, 4, 6, 10, 4, 2, 1, 10, 2, 1, 1, 5]) == 4 assert candidate([2, 10, 4, 8, 2, 10, 5, 1, 2, 9, 5, 5, 6, 3, 8, 6, 4, 10]) == 2 assert candidate([1, 6, 10, 1, 6, 9, 10, 8, 6, 8, 7, 3]) == 1 assert candidate([9, 2, 4, 1, 5, 1, 5, 2, 5, 7, 7, 7, 3, 10, 1, 5, 4, 2, 8, 4, 1, 9, 10, 7, 10, 2, 8, 10, 9, 4]) == 4 assert candidate([2, 6, 4, 2, 8, 7, 5, 6, 4, 10, 4, 6, 3, 7, 8, 8, 3, 1, 4, 2, 2, 10, 7]) == 4 assert candidate([9, 8, 6, 10, 2, 6, 10, 2, 7, 8, 10, 3, 8, 2, 6, 2, 3, 1]) == 2 assert candidate([5, 5, 3, 9, 5, 6, 3, 2, 8, 5, 6, 10, 10, 6, 8, 4, 10, 7, 7, 10, 8]) == -1 assert candidate([10]) == -1 assert candidate([9, 7, 7, 2, 4, 7, 2, 10, 9, 7, 5, 7, 2]) == 2 assert candidate([5, 4, 10, 2, 1, 1, 10, 3, 6, 1, 8]) == 1 assert candidate([7, 9, 9, 9, 3, 4, 1, 5, 9, 1, 2, 1, 1, 10, 7, 5, 6, 7, 6, 7, 7, 6]) == 1 assert candidate([3, 10, 10, 9, 2]) == -1
search
HumanEval/70
def strange_sort_list(lst): ''' Given list of integers, return list in strange order. Strange sorting, is when you start with the minimum value, then maximum of the remaining integers, then minimum and so on. Examples: strange_sort_list([1, 2, 3, 4]) == [1, 4, 2, 3] strange_sort_list([5, 5, 5, 5]) == [5, 5, 5, 5] strange_sort_list([]) == [] '''
res, switch = [], True while lst: res.append(min(lst) if switch else max(lst)) lst.remove(res[-1]) switch = not switch return res
def check(candidate): # Check some simple cases assert candidate([1, 2, 3, 4]) == [1, 4, 2, 3] assert candidate([5, 6, 7, 8, 9]) == [5, 9, 6, 8, 7] assert candidate([1, 2, 3, 4, 5]) == [1, 5, 2, 4, 3] assert candidate([5, 6, 7, 8, 9, 1]) == [1, 9, 5, 8, 6, 7] assert candidate([5, 5, 5, 5]) == [5, 5, 5, 5] assert candidate([]) == [] assert candidate([1,2,3,4,5,6,7,8]) == [1, 8, 2, 7, 3, 6, 4, 5] assert candidate([0,2,2,2,5,5,-5,-5]) == [-5, 5, -5, 5, 0, 2, 2, 2] assert candidate([111111]) == [111111] # Check some edge cases that are easy to work out by hand. assert True
strange_sort_list
HumanEval/71
def triangle_area(a, b, c): ''' Given the lengths of the three sides of a triangle. Return the area of the triangle rounded to 2 decimal points if the three sides form a valid triangle. Otherwise return -1 Three sides make a valid triangle when the sum of any two sides is greater than the third side. Example: triangle_area(3, 4, 5) == 6.00 triangle_area(1, 2, 10) == -1 '''
if a + b <= c or a + c <= b or b + c <= a: return -1 s = (a + b + c)/2 area = (s * (s - a) * (s - b) * (s - c)) ** 0.5 area = round(area, 2) return area
def check(candidate): # Check some simple cases assert candidate(3, 4, 5) == 6.00, "This prints if this assert fails 1 (good for debugging!)" assert candidate(1, 2, 10) == -1 assert candidate(4, 8, 5) == 8.18 assert candidate(2, 2, 2) == 1.73 assert candidate(1, 2, 3) == -1 assert candidate(10, 5, 7) == 16.25 assert candidate(2, 6, 3) == -1 # Check some edge cases that are easy to work out by hand. assert candidate(1, 1, 1) == 0.43, "This prints if this assert fails 2 (also good for debugging!)" assert candidate(2, 2, 10) == -1
triangle_area
HumanEval/72
def will_it_fly(q,w): ''' Write a function that returns True if the object q will fly, and False otherwise. The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w. Example: will_it_fly([1, 2], 5) ➞ False # 1+2 is less than the maximum possible weight, but it's unbalanced. will_it_fly([3, 2, 3], 1) ➞ False # it's balanced, but 3+2+3 is more than the maximum possible weight. will_it_fly([3, 2, 3], 9) ➞ True # 3+2+3 is less than the maximum possible weight, and it's balanced. will_it_fly([3], 5) ➞ True # 3 is less than the maximum possible weight, and it's balanced. '''
if sum(q) > w: return False i, j = 0, len(q)-1 while i<j: if q[i] != q[j]: return False i+=1 j-=1 return True
def check(candidate): # Check some simple cases assert candidate([3, 2, 3], 9) is True assert candidate([1, 2], 5) is False assert candidate([3], 5) is True assert candidate([3, 2, 3], 1) is False # Check some edge cases that are easy to work out by hand. assert candidate([1, 2, 3], 6) is False assert candidate([5], 5) is True
will_it_fly
HumanEval/73
def smallest_change(arr): """ Given an array arr of integers, find the minimum number of elements that need to be changed to make the array palindromic. A palindromic array is an array that is read the same backwards and forwards. In one change, you can change one element to any other element. For example: smallest_change([1,2,3,5,4,7,9,6]) == 4 smallest_change([1, 2, 3, 4, 3, 2, 2]) == 1 smallest_change([1, 2, 3, 2, 1]) == 0 """
ans = 0 for i in range(len(arr) // 2): if arr[i] != arr[len(arr) - i - 1]: ans += 1 return ans
def check(candidate): # Check some simple cases assert candidate([1,2,3,5,4,7,9,6]) == 4 assert candidate([1, 2, 3, 4, 3, 2, 2]) == 1 assert candidate([1, 4, 2]) == 1 assert candidate([1, 4, 4, 2]) == 1 # Check some edge cases that are easy to work out by hand. assert candidate([1, 2, 3, 2, 1]) == 0 assert candidate([3, 1, 1, 3]) == 0 assert candidate([1]) == 0 assert candidate([0, 1]) == 1
smallest_change
HumanEval/74
def total_match(lst1, lst2): ''' Write a function that accepts two lists of strings and returns the list that has total number of chars in the all strings of the list less than the other list. if the two lists have the same number of chars, return the first list. Examples total_match([], []) ➞ [] total_match(['hi', 'admin'], ['hI', 'Hi']) ➞ ['hI', 'Hi'] total_match(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) ➞ ['hi', 'admin'] total_match(['hi', 'admin'], ['hI', 'hi', 'hi']) ➞ ['hI', 'hi', 'hi'] total_match(['4'], ['1', '2', '3', '4', '5']) ➞ ['4'] '''
l1 = 0 for st in lst1: l1 += len(st) l2 = 0 for st in lst2: l2 += len(st) if l1 <= l2: return lst1 else: return lst2
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate([], []) == [] assert candidate(['hi', 'admin'], ['hi', 'hi']) == ['hi', 'hi'] assert candidate(['hi', 'admin'], ['hi', 'hi', 'admin', 'project']) == ['hi', 'admin'] assert candidate(['4'], ['1', '2', '3', '4', '5']) == ['4'] assert candidate(['hi', 'admin'], ['hI', 'Hi']) == ['hI', 'Hi'] assert candidate(['hi', 'admin'], ['hI', 'hi', 'hi']) == ['hI', 'hi', 'hi'] assert candidate(['hi', 'admin'], ['hI', 'hi', 'hii']) == ['hi', 'admin'] # Check some edge cases that are easy to work out by hand. assert True, "This prints if this assert fails 2 (also good for debugging!)" assert candidate([], ['this']) == [] assert candidate(['this'], []) == []
total_match
HumanEval/75
def is_multiply_prime(a): """Write a function that returns true if the given number is the multiplication of 3 prime numbers and false otherwise. Knowing that (a) is less then 100. Example: is_multiply_prime(30) == True 30 = 2 * 3 * 5 """
def is_prime(n): for j in range(2,n): if n%j == 0: return False return True for i in range(2,101): if not is_prime(i): continue for j in range(2,101): if not is_prime(j): continue for k in range(2,101): if not is_prime(k): continue if i*j*k == a: return True return False
def check(candidate): assert candidate(5) == False assert candidate(30) == True assert candidate(8) == True assert candidate(10) == False assert candidate(125) == True assert candidate(3 * 5 * 7) == True assert candidate(3 * 6 * 7) == False assert candidate(9 * 9 * 9) == False assert candidate(11 * 9 * 9) == False assert candidate(11 * 13 * 7) == True
is_multiply_prime
HumanEval/76
def is_simple_power(x, n): """Your task is to write a function that returns true if a number x is a simple power of n and false in other cases. x is a simple power of n if n**int=x For example: is_simple_power(1, 4) => true is_simple_power(2, 2) => true is_simple_power(8, 2) => true is_simple_power(3, 2) => false is_simple_power(3, 1) => false is_simple_power(5, 3) => false """
if (n == 1): return (x == 1) power = 1 while (power < x): power = power * n return (power == x)
def check(candidate): # Check some simple cases assert candidate(16, 2)== True, "This prints if this assert fails 1 (good for debugging!)" assert candidate(143214, 16)== False, "This prints if this assert fails 1 (good for debugging!)" assert candidate(4, 2)==True, "This prints if this assert fails 1 (good for debugging!)" assert candidate(9, 3)==True, "This prints if this assert fails 1 (good for debugging!)" assert candidate(16, 4)==True, "This prints if this assert fails 1 (good for debugging!)" assert candidate(24, 2)==False, "This prints if this assert fails 1 (good for debugging!)" assert candidate(128, 4)==False, "This prints if this assert fails 1 (good for debugging!)" assert candidate(12, 6)==False, "This prints if this assert fails 1 (good for debugging!)" # Check some edge cases that are easy to work out by hand. assert candidate(1, 1)==True, "This prints if this assert fails 2 (also good for debugging!)" assert candidate(1, 12)==True, "This prints if this assert fails 2 (also good for debugging!)"
is_simple_power
HumanEval/77
def iscube(a): ''' Write a function that takes an integer a and returns True if this ingeger is a cube of some integer number. Note: you may assume the input is always valid. Examples: iscube(1) ==> True iscube(2) ==> False iscube(-1) ==> True iscube(64) ==> True iscube(0) ==> True iscube(180) ==> False '''
a = abs(a) return int(round(a ** (1. / 3))) ** 3 == a
def check(candidate): # Check some simple cases assert candidate(1) == True, "First test error: " + str(candidate(1)) assert candidate(2) == False, "Second test error: " + str(candidate(2)) assert candidate(-1) == True, "Third test error: " + str(candidate(-1)) assert candidate(64) == True, "Fourth test error: " + str(candidate(64)) assert candidate(180) == False, "Fifth test error: " + str(candidate(180)) assert candidate(1000) == True, "Sixth test error: " + str(candidate(1000)) # Check some edge cases that are easy to work out by hand. assert candidate(0) == True, "1st edge test error: " + str(candidate(0)) assert candidate(1729) == False, "2nd edge test error: " + str(candidate(1728))
iscube
HumanEval/78
def hex_key(num): """You have been tasked to write a function that receives a hexadecimal number as a string and counts the number of hexadecimal digits that are primes (prime number, or a prime, is a natural number greater than 1 that is not a product of two smaller natural numbers). Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F. Prime numbers are 2, 3, 5, 7, 11, 13, 17,... So you have to determine a number of the following digits: 2, 3, 5, 7, B (=decimal 11), D (=decimal 13). Note: you may assume the input is always correct or empty string, and symbols A,B,C,D,E,F are always uppercase. Examples: For num = "AB" the output should be 1. For num = "1077E" the output should be 2. For num = "ABED1A33" the output should be 4. For num = "123456789ABCDEF0" the output should be 6. For num = "2020" the output should be 2. """
primes = ('2', '3', '5', '7', 'B', 'D') total = 0 for i in range(0, len(num)): if num[i] in primes: total += 1 return total
def check(candidate): # Check some simple cases assert candidate("AB") == 1, "First test error: " + str(candidate("AB")) assert candidate("1077E") == 2, "Second test error: " + str(candidate("1077E")) assert candidate("ABED1A33") == 4, "Third test error: " + str(candidate("ABED1A33")) assert candidate("2020") == 2, "Fourth test error: " + str(candidate("2020")) assert candidate("123456789ABCDEF0") == 6, "Fifth test error: " + str(candidate("123456789ABCDEF0")) assert candidate("112233445566778899AABBCCDDEEFF00") == 12, "Sixth test error: " + str(candidate("112233445566778899AABBCCDDEEFF00")) # Check some edge cases that are easy to work out by hand. assert candidate([]) == 0
hex_key
HumanEval/79
def decimal_to_binary(decimal): """You will be given a number in decimal form and your task is to convert it to binary format. The function should return a string, with each character representing a binary number. Each character in the string will be '0' or '1'. There will be an extra couple of characters 'db' at the beginning and at the end of the string. The extra characters are there to help with the format. Examples: decimal_to_binary(15) # returns "db1111db" decimal_to_binary(32) # returns "db100000db" """
return "db" + bin(decimal)[2:] + "db"
def check(candidate): # Check some simple cases assert candidate(0) == "db0db" assert candidate(32) == "db100000db" assert candidate(103) == "db1100111db" assert candidate(15) == "db1111db", "This prints if this assert fails 1 (good for debugging!)" # Check some edge cases that are easy to work out by hand. assert True, "This prints if this assert fails 2 (also good for debugging!)"
decimal_to_binary
HumanEval/80
def is_happy(s): """You are given a string s. Your task is to check if the string is happy or not. A string is happy if its length is at least 3 and every 3 consecutive letters are distinct For example: is_happy(a) => False is_happy(aa) => False is_happy(abcd) => True is_happy(aabb) => False is_happy(adb) => True is_happy(xyy) => False """
if len(s) < 3: return False for i in range(len(s) - 2): if s[i] == s[i+1] or s[i+1] == s[i+2] or s[i] == s[i+2]: return False return True
def check(candidate): # Check some simple cases assert candidate("a") == False , "a" assert candidate("aa") == False , "aa" assert candidate("abcd") == True , "abcd" assert candidate("aabb") == False , "aabb" assert candidate("adb") == True , "adb" assert candidate("xyy") == False , "xyy" assert candidate("iopaxpoi") == True , "iopaxpoi" assert candidate("iopaxioi") == False , "iopaxioi"
is_happy
HumanEval/81
def numerical_letter_grade(grades): """It is the last week of the semester and the teacher has to give the grades to students. The teacher has been making her own algorithm for grading. The only problem is, she has lost the code she used for grading. She has given you a list of GPAs for some students and you have to write a function that can output a list of letter grades using the following table: GPA | Letter grade 4.0 A+ > 3.7 A > 3.3 A- > 3.0 B+ > 2.7 B > 2.3 B- > 2.0 C+ > 1.7 C > 1.3 C- > 1.0 D+ > 0.7 D > 0.0 D- 0.0 E Example: grade_equation([4.0, 3, 1.7, 2, 3.5]) ==> ['A+', 'B', 'C-', 'C', 'A-'] """
letter_grade = [] for gpa in grades: if gpa == 4.0: letter_grade.append("A+") elif gpa > 3.7: letter_grade.append("A") elif gpa > 3.3: letter_grade.append("A-") elif gpa > 3.0: letter_grade.append("B+") elif gpa > 2.7: letter_grade.append("B") elif gpa > 2.3: letter_grade.append("B-") elif gpa > 2.0: letter_grade.append("C+") elif gpa > 1.7: letter_grade.append("C") elif gpa > 1.3: letter_grade.append("C-") elif gpa > 1.0: letter_grade.append("D+") elif gpa > 0.7: letter_grade.append("D") elif gpa > 0.0: letter_grade.append("D-") else: letter_grade.append("E") return letter_grade
def check(candidate): # Check some simple cases assert candidate([4.0, 3, 1.7, 2, 3.5]) == ['A+', 'B', 'C-', 'C', 'A-'] assert candidate([1.2]) == ['D+'] assert candidate([0.5]) == ['D-'] assert candidate([0.0]) == ['E'] assert candidate([1, 0.3, 1.5, 2.8, 3.3]) == ['D', 'D-', 'C-', 'B', 'B+'] assert candidate([0, 0.7]) == ['E', 'D-'] # Check some edge cases that are easy to work out by hand. assert True
numerical_letter_grade
HumanEval/82
def prime_length(string): """Write a function that takes a string and returns True if the string length is a prime number or False otherwise Examples prime_length('Hello') == True prime_length('abcdcba') == True prime_length('kittens') == True prime_length('orange') == False """
l = len(string) if l == 0 or l == 1: return False for i in range(2, l): if l % i == 0: return False return True
def check(candidate): # Check some simple cases assert candidate('Hello') == True assert candidate('abcdcba') == True assert candidate('kittens') == True assert candidate('orange') == False assert candidate('wow') == True assert candidate('world') == True assert candidate('MadaM') == True assert candidate('Wow') == True assert candidate('') == False assert candidate('HI') == True assert candidate('go') == True assert candidate('gogo') == False assert candidate('aaaaaaaaaaaaaaa') == False # Check some edge cases that are easy to work out by hand. assert candidate('Madam') == True assert candidate('M') == False assert candidate('0') == False
prime_length
HumanEval/83
def starts_one_ends(n): """ Given a positive integer n, return the count of the numbers of n-digit positive integers that start or end with 1. """
if n == 1: return 1 return 18 * (10 ** (n - 2))
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate(1) == 1 assert candidate(2) == 18 assert candidate(3) == 180 assert candidate(4) == 1800 assert candidate(5) == 18000 # Check some edge cases that are easy to work out by hand. assert True, "This prints if this assert fails 2 (also good for debugging!)"
starts_one_ends
HumanEval/84
def solve(N): """Given a positive integer N, return the total sum of its digits in binary. Example For N = 1000, the sum of digits will be 1 the output should be "1". For N = 150, the sum of digits will be 6 the output should be "110". For N = 147, the sum of digits will be 12 the output should be "1100". Variables: @N integer Constraints: 0 ≤ N ≤ 10000. Output: a string of binary number """
return bin(sum(int(i) for i in str(N)))[2:]
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate(1000) == "1", "Error" assert candidate(150) == "110", "Error" assert candidate(147) == "1100", "Error" # Check some edge cases that are easy to work out by hand. assert True, "This prints if this assert fails 2 (also good for debugging!)" assert candidate(333) == "1001", "Error" assert candidate(963) == "10010", "Error"
solve
HumanEval/85
def add(lst): """Given a non-empty list of integers lst. add the even elements that are at odd indices.. Examples: add([4, 2, 6, 7]) ==> 2 """
return sum([lst[i] for i in range(1, len(lst), 2) if lst[i]%2 == 0])
def check(candidate): # Check some simple cases assert candidate([4, 88]) == 88 assert candidate([4, 5, 6, 7, 2, 122]) == 122 assert candidate([4, 0, 6, 7]) == 0 assert candidate([4, 4, 6, 8]) == 12 # Check some edge cases that are easy to work out by hand.
add
HumanEval/86
def anti_shuffle(s): """ Write a function that takes a string and returns an ordered version of it. Ordered version of string, is a string where all words (separated by space) are replaced by a new word where all the characters arranged in ascending order based on ascii value. Note: You should keep the order of words and blank spaces in the sentence. For example: anti_shuffle('Hi') returns 'Hi' anti_shuffle('hello') returns 'ehllo' anti_shuffle('Hello World!!!') returns 'Hello !!!Wdlor' """
return ' '.join([''.join(sorted(list(i))) for i in s.split(' ')])
def check(candidate): # Check some simple cases assert candidate('Hi') == 'Hi' assert candidate('hello') == 'ehllo' assert candidate('number') == 'bemnru' assert candidate('abcd') == 'abcd' assert candidate('Hello World!!!') == 'Hello !!!Wdlor' assert candidate('') == '' assert candidate('Hi. My name is Mister Robot. How are you?') == '.Hi My aemn is Meirst .Rboot How aer ?ouy' # Check some edge cases that are easy to work out by hand. assert True
anti_shuffle
HumanEval/87
def get_row(lst, x): """ You are given a 2 dimensional data, as a nested lists, which is similar to matrix, however, unlike matrices, each row may contain a different number of columns. Given lst, and integer x, find integers x in the list, and return list of tuples, [(x1, y1), (x2, y2) ...] such that each tuple is a coordinate - (row, columns), starting with 0. Sort coordinates initially by rows in ascending order. Also, sort coordinates of the row by columns in descending order. Examples: get_row([ [1,2,3,4,5,6], [1,2,3,4,1,6], [1,2,3,4,5,1] ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)] get_row([], 1) == [] get_row([[], [1], [1, 2, 3]], 3) == [(2, 2)] """
coords = [(i, j) for i in range(len(lst)) for j in range(len(lst[i])) if lst[i][j] == x] return sorted(sorted(coords, key=lambda x: x[1], reverse=True), key=lambda x: x[0])
def check(candidate): # Check some simple cases assert candidate([ [1,2,3,4,5,6], [1,2,3,4,1,6], [1,2,3,4,5,1] ], 1) == [(0, 0), (1, 4), (1, 0), (2, 5), (2, 0)] assert candidate([ [1,2,3,4,5,6], [1,2,3,4,5,6], [1,2,3,4,5,6], [1,2,3,4,5,6], [1,2,3,4,5,6], [1,2,3,4,5,6] ], 2) == [(0, 1), (1, 1), (2, 1), (3, 1), (4, 1), (5, 1)] assert candidate([ [1,2,3,4,5,6], [1,2,3,4,5,6], [1,1,3,4,5,6], [1,2,1,4,5,6], [1,2,3,1,5,6], [1,2,3,4,1,6], [1,2,3,4,5,1] ], 1) == [(0, 0), (1, 0), (2, 1), (2, 0), (3, 2), (3, 0), (4, 3), (4, 0), (5, 4), (5, 0), (6, 5), (6, 0)] assert candidate([], 1) == [] assert candidate([[1]], 2) == [] assert candidate([[], [1], [1, 2, 3]], 3) == [(2, 2)] # Check some edge cases that are easy to work out by hand. assert True
get_row
HumanEval/88
def sort_array(array): """ Given an array of non-negative integers, return a copy of the given array after sorting, you will sort the given array in ascending order if the sum( first index value, last index value) is odd, or sort it in descending order if the sum( first index value, last index value) is even. Note: * don't change the given array. Examples: * sort_array([]) => [] * sort_array([5]) => [5] * sort_array([2, 4, 3, 0, 1, 5]) => [0, 1, 2, 3, 4, 5] * sort_array([2, 4, 3, 0, 1, 5, 6]) => [6, 5, 4, 3, 2, 1, 0] """
return [] if len(array) == 0 else sorted(array, reverse= (array[0]+array[-1]) % 2 == 0)
def check(candidate): # Check some simple cases assert True, "This prints if this assert fails 1 (good for debugging!)" assert candidate([]) == [], "Error" assert candidate([5]) == [5], "Error" assert candidate([2, 4, 3, 0, 1, 5]) == [0, 1, 2, 3, 4, 5], "Error" assert candidate([2, 4, 3, 0, 1, 5, 6]) == [6, 5, 4, 3, 2, 1, 0], "Error" # Check some edge cases that are easy to work out by hand. assert True, "This prints if this assert fails 2 (also good for debugging!)" assert candidate([2, 1]) == [1, 2], "Error" assert candidate([15, 42, 87, 32 ,11, 0]) == [0, 11, 15, 32, 42, 87], "Error" assert candidate([21, 14, 23, 11]) == [23, 21, 14, 11], "Error"
sort_array
HumanEval/89
def encrypt(s): """Create a function encrypt that takes a string as an argument and returns a string encrypted with the alphabet being rotated. The alphabet should be rotated in a manner such that the letters shift down by two multiplied to two places. For example: encrypt('hi') returns 'lm' encrypt('asdfghjkl') returns 'ewhjklnop' encrypt('gf') returns 'kj' encrypt('et') returns 'ix' """
d = 'abcdefghijklmnopqrstuvwxyz' out = '' for c in s: if c in d: out += d[(d.index(c)+2*2) % 26] else: out += c return out
def check(candidate): # Check some simple cases assert candidate('hi') == 'lm', "This prints if this assert fails 1 (good for debugging!)" assert candidate('asdfghjkl') == 'ewhjklnop', "This prints if this assert fails 1 (good for debugging!)" assert candidate('gf') == 'kj', "This prints if this assert fails 1 (good for debugging!)" assert candidate('et') == 'ix', "This prints if this assert fails 1 (good for debugging!)" assert candidate('faewfawefaewg')=='jeiajeaijeiak', "This prints if this assert fails 1 (good for debugging!)" assert candidate('hellomyfriend')=='lippsqcjvmirh', "This prints if this assert fails 2 (good for debugging!)" assert candidate('dxzdlmnilfuhmilufhlihufnmlimnufhlimnufhfucufh')=='hbdhpqrmpjylqmpyjlpmlyjrqpmqryjlpmqryjljygyjl', "This prints if this assert fails 3 (good for debugging!)" # Check some edge cases that are easy to work out by hand. assert candidate('a')=='e', "This prints if this assert fails 2 (also good for debugging!)"
encrypt
HumanEval/90
def next_smallest(lst): """ You are given a list of integers. Write a function next_smallest() that returns the 2nd smallest element of the list. Return None if there is no such element. next_smallest([1, 2, 3, 4, 5]) == 2 next_smallest([5, 1, 4, 3, 2]) == 2 next_smallest([]) == None next_smallest([1, 1]) == None """
lst = sorted(set(lst)) return None if len(lst) < 2 else lst[1]
def check(candidate): # Check some simple cases assert candidate([1, 2, 3, 4, 5]) == 2 assert candidate([5, 1, 4, 3, 2]) == 2 assert candidate([]) == None assert candidate([1, 1]) == None assert candidate([1,1,1,1,0]) == 1 assert candidate([1, 0**0]) == None assert candidate([-35, 34, 12, -45]) == -35 # Check some edge cases that are easy to work out by hand. assert True
next_smallest
HumanEval/91
def is_bored(S): """ You'll be given a string of words, and your task is to count the number of boredoms. A boredom is a sentence that starts with the word "I". Sentences are delimited by '.', '?' or '!'. For example: >>> is_bored("Hello world") 0 >>> is_bored("The sky is blue. The sun is shining. I love this weather") 1 """
import re sentences = re.split(r'[.?!]\s*', S) return sum(sentence[0:2] == 'I ' for sentence in sentences)
def check(candidate): # Check some simple cases assert candidate("Hello world") == 0, "Test 1" assert candidate("Is the sky blue?") == 0, "Test 2" assert candidate("I love It !") == 1, "Test 3" assert candidate("bIt") == 0, "Test 4" assert candidate("I feel good today. I will be productive. will kill It") == 2, "Test 5" assert candidate("You and I are going for a walk") == 0, "Test 6" # Check some edge cases that are easy to work out by hand. assert True, "This prints if this assert fails 2 (also good for debugging!)"
is_bored
HumanEval/92
def any_int(x, y, z): ''' Create a function that takes 3 numbers. Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers. Returns false in any other cases. Examples any_int(5, 2, 7) ➞ True any_int(3, 2, 2) ➞ False any_int(3, -2, 1) ➞ True any_int(3.6, -2.2, 2) ➞ False '''
if isinstance(x,int) and isinstance(y,int) and isinstance(z,int): if (x+y==z) or (x+z==y) or (y+z==x): return True return False return False
def check(candidate): # Check some simple cases assert candidate(2, 3, 1)==True, "This prints if this assert fails 1 (good for debugging!)" assert candidate(2.5, 2, 3)==False, "This prints if this assert fails 2 (good for debugging!)" assert candidate(1.5, 5, 3.5)==False, "This prints if this assert fails 3 (good for debugging!)" assert candidate(2, 6, 2)==False, "This prints if this assert fails 4 (good for debugging!)" assert candidate(4, 2, 2)==True, "This prints if this assert fails 5 (good for debugging!)" assert candidate(2.2, 2.2, 2.2)==False, "This prints if this assert fails 6 (good for debugging!)" assert candidate(-4, 6, 2)==True, "This prints if this assert fails 7 (good for debugging!)" # Check some edge cases that are easy to work out by hand. assert candidate(2,1,1)==True, "This prints if this assert fails 8 (also good for debugging!)" assert candidate(3,4,7)==True, "This prints if this assert fails 9 (also good for debugging!)" assert candidate(3.0,4,7)==False, "This prints if this assert fails 10 (also good for debugging!)"
any_int
HumanEval/93
def encode(message): """ Write a function that takes a message, and encodes in such a way that it swaps case of all letters, replaces all vowels in the message with the letter that appears 2 places ahead of that vowel in the english alphabet. Assume only letters. Examples: >>> encode('test') 'TGST' >>> encode('This is a message') 'tHKS KS C MGSSCGG' """
vowels = "aeiouAEIOU" vowels_replace = dict([(i, chr(ord(i) + 2)) for i in vowels]) message = message.swapcase() return ''.join([vowels_replace[i] if i in vowels else i for i in message])
def check(candidate): # Check some simple cases assert candidate('TEST') == 'tgst', "This prints if this assert fails 1 (good for debugging!)" assert candidate('Mudasir') == 'mWDCSKR', "This prints if this assert fails 2 (good for debugging!)" assert candidate('YES') == 'ygs', "This prints if this assert fails 3 (good for debugging!)" # Check some edge cases that are easy to work out by hand. assert candidate('This is a message') == 'tHKS KS C MGSSCGG', "This prints if this assert fails 2 (also good for debugging!)" assert candidate("I DoNt KnOw WhAt tO WrItE") == 'k dQnT kNqW wHcT Tq wRkTg', "This prints if this assert fails 2 (also good for debugging!)"
encode
HumanEval/94
def skjkasdkd(lst): """You are given a list of integers. You need to find the largest prime value and return the sum of its digits. Examples: For lst = [0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3] the output should be 10 For lst = [1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1] the output should be 25 For lst = [1,3,1,32,5107,34,83278,109,163,23,2323,32,30,1,9,3] the output should be 13 For lst = [0,724,32,71,99,32,6,0,5,91,83,0,5,6] the output should be 11 For lst = [0,81,12,3,1,21] the output should be 3 For lst = [0,8,1,2,1,7] the output should be 7 """
def isPrime(n): for i in range(2,int(n**0.5)+1): if n%i==0: return False return True maxx = 0 i = 0 while i < len(lst): if(lst[i] > maxx and isPrime(lst[i])): maxx = lst[i] i+=1 result = sum(int(digit) for digit in str(maxx)) return result
def check(candidate): # Check some simple cases assert candidate([0,3,2,1,3,5,7,4,5,5,5,2,181,32,4,32,3,2,32,324,4,3]) == 10, "This prints if this assert fails 1 (good for debugging!)" # Check some edge cases that are easy to work out by hand. assert candidate([1,0,1,8,2,4597,2,1,3,40,1,2,1,2,4,2,5,1]) == 25, "This prints if this assert fails 2 (also good for debugging!)" # Check some edge cases that are easy to work out by hand. assert candidate([1,3,1,32,5107,34,83278,109,163,23,2323,32,30,1,9,3]) == 13, "This prints if this assert fails 3 (also good for debugging!)" # Check some edge cases that are easy to work out by hand. assert candidate([0,724,32,71,99,32,6,0,5,91,83,0,5,6]) == 11, "This prints if this assert fails 4 (also good for debugging!)" # Check some edge cases that are easy to work out by hand. assert candidate([0,81,12,3,1,21]) == 3, "This prints if this assert fails 5 (also good for debugging!)" # Check some edge cases that are easy to work out by hand. assert candidate([0,8,1,2,1,7]) == 7, "This prints if this assert fails 6 (also good for debugging!)" assert candidate([8191]) == 19, "This prints if this assert fails 7 (also good for debugging!)" assert candidate([8191, 123456, 127, 7]) == 19, "This prints if this assert fails 8 (also good for debugging!)" assert candidate([127, 97, 8192]) == 10, "This prints if this assert fails 9 (also good for debugging!)"
skjkasdkd
HumanEval/95
def check_dict_case(dict): """ Given a dictionary, return True if all keys are strings in lower case or all keys are strings in upper case, else return False. The function should return False is the given dictionary is empty. Examples: check_dict_case({"a":"apple", "b":"banana"}) should return True. check_dict_case({"a":"apple", "A":"banana", "B":"banana"}) should return False. check_dict_case({"a":"apple", 8:"banana", "a":"apple"}) should return False. check_dict_case({"Name":"John", "Age":"36", "City":"Houston"}) should return False. check_dict_case({"STATE":"NC", "ZIP":"12345" }) should return True. """
if len(dict.keys()) == 0: return False else: state = "start" for key in dict.keys(): if isinstance(key, str) == False: state = "mixed" break if state == "start": if key.isupper(): state = "upper" elif key.islower(): state = "lower" else: break elif (state == "upper" and not key.isupper()) or (state == "lower" and not key.islower()): state = "mixed" break else: break return state == "upper" or state == "lower"
def check(candidate): # Check some simple cases assert candidate({"p":"pineapple", "b":"banana"}) == True, "First test error: " + str(candidate({"p":"pineapple", "b":"banana"})) assert candidate({"p":"pineapple", "A":"banana", "B":"banana"}) == False, "Second test error: " + str(candidate({"p":"pineapple", "A":"banana", "B":"banana"})) assert candidate({"p":"pineapple", 5:"banana", "a":"apple"}) == False, "Third test error: " + str(candidate({"p":"pineapple", 5:"banana", "a":"apple"})) assert candidate({"Name":"John", "Age":"36", "City":"Houston"}) == False, "Fourth test error: " + str(candidate({"Name":"John", "Age":"36", "City":"Houston"})) assert candidate({"STATE":"NC", "ZIP":"12345" }) == True, "Fifth test error: " + str(candidate({"STATE":"NC", "ZIP":"12345" })) assert candidate({"fruit":"Orange", "taste":"Sweet" }) == True, "Fourth test error: " + str(candidate({"fruit":"Orange", "taste":"Sweet" })) # Check some edge cases that are easy to work out by hand. assert candidate({}) == False, "1st edge test error: " + str(candidate({}))
check_dict_case
HumanEval/96
def count_up_to(n): """Implement a function that takes an non-negative integer and returns an array of the first n integers that are prime numbers and less than n. for example: count_up_to(5) => [2,3] count_up_to(11) => [2,3,5,7] count_up_to(0) => [] count_up_to(20) => [2,3,5,7,11,13,17,19] count_up_to(1) => [] count_up_to(18) => [2,3,5,7,11,13,17] """
primes = [] for i in range(2, n): is_prime = True for j in range(2, i): if i % j == 0: is_prime = False break if is_prime: primes.append(i) return primes
def check(candidate): assert candidate(5) == [2,3] assert candidate(6) == [2,3,5] assert candidate(7) == [2,3,5] assert candidate(10) == [2,3,5,7] assert candidate(0) == [] assert candidate(22) == [2,3,5,7,11,13,17,19] assert candidate(1) == [] assert candidate(18) == [2,3,5,7,11,13,17] assert candidate(47) == [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43] assert candidate(101) == [2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97]
count_up_to
HumanEval/97
def multiply(a, b): """Complete the function that takes two integers and returns the product of their unit digits. Assume the input is always valid. Examples: multiply(148, 412) should return 16. multiply(19, 28) should return 72. multiply(2020, 1851) should return 0. multiply(14,-15) should return 20. """
return abs(a % 10) * abs(b % 10)
def check(candidate): # Check some simple cases assert candidate(148, 412) == 16, "First test error: " + str(candidate(148, 412)) assert candidate(19, 28) == 72, "Second test error: " + str(candidate(19, 28)) assert candidate(2020, 1851) == 0, "Third test error: " + str(candidate(2020, 1851)) assert candidate(14,-15) == 20, "Fourth test error: " + str(candidate(14,-15)) assert candidate(76, 67) == 42, "Fifth test error: " + str(candidate(76, 67)) assert candidate(17, 27) == 49, "Sixth test error: " + str(candidate(17, 27)) # Check some edge cases that are easy to work out by hand. assert candidate(0, 1) == 0, "1st edge test error: " + str(candidate(0, 1)) assert candidate(0, 0) == 0, "2nd edge test error: " + str(candidate(0, 0))
multiply
HumanEval/98
def count_upper(s): """ Given a string s, count the number of uppercase vowels in even indices. For example: count_upper('aBCdEf') returns 1 count_upper('abcdefg') returns 0 count_upper('dBBE') returns 0 """
count = 0 for i in range(0,len(s),2): if s[i] in "AEIOU": count += 1 return count
def check(candidate): # Check some simple cases assert candidate('aBCdEf') == 1 assert candidate('abcdefg') == 0 assert candidate('dBBE') == 0 assert candidate('B') == 0 assert candidate('U') == 1 assert candidate('') == 0 assert candidate('EEEE') == 2 # Check some edge cases that are easy to work out by hand. assert True
count_upper
HumanEval/99
def closest_integer(value): ''' Create a function that takes a value (string) representing a number and returns the closest integer to it. If the number is equidistant from two integers, round it away from zero. Examples >>> closest_integer("10") 10 >>> closest_integer("15.3") 15 Note: Rounding away from zero means that if the given number is equidistant from two integers, the one you should return is the one that is the farthest from zero. For example closest_integer("14.5") should return 15 and closest_integer("-14.5") should return -15. '''
from math import floor, ceil if value.count('.') == 1: # remove trailing zeros while (value[-1] == '0'): value = value[:-1] num = float(value) if value[-2:] == '.5': if num > 0: res = ceil(num) else: res = floor(num) elif len(value) > 0: res = int(round(num)) else: res = 0 return res
def check(candidate): # Check some simple cases assert candidate("10") == 10, "Test 1" assert candidate("14.5") == 15, "Test 2" assert candidate("-15.5") == -16, "Test 3" assert candidate("15.3") == 15, "Test 3" # Check some edge cases that are easy to work out by hand. assert candidate("0") == 0, "Test 0"
closest_integer
End of preview (truncated to 100 rows)

Dataset Card for OpenAI HumanEval

Dataset Summary

The HumanEval dataset released by OpenAI includes 164 programming problems with a function sig- nature, docstring, body, and several unit tests. They were handwritten to ensure not to be included in the training set of code generation models.

Supported Tasks and Leaderboards

Languages

The programming problems are written in Python and contain English natural text in comments and docstrings.

Dataset Structure

from datasets import load_dataset
load_dataset("openai_humaneval")

DatasetDict({
    test: Dataset({
        features: ['task_id', 'prompt', 'canonical_solution', 'test', 'entry_point'],
        num_rows: 164
    })
})

Data Instances

An example of a dataset instance:

{
    "task_id": "test/0",
    "prompt": "def return1():\n",
    "canonical_solution": "    return 1",
    "test": "def check(candidate):\n    assert candidate() == 1",
    "entry_point": "return1"
}

Data Fields

  • task_id: identifier for the data sample
  • prompt: input for the model containing function header and docstrings
  • canonical_solution: solution for the problem in the prompt
  • test: contains function to test generated code for correctness
  • entry_point: entry point for test

Data Splits

The dataset only consists of a test split with 164 samples.

Dataset Creation

Curation Rationale

Since code generation models are often trained on dumps of GitHub a dataset not included in the dump was necessary to properly evaluate the model. However, since this dataset was published on GitHub it is likely to be included in future dumps.

Source Data

The dataset was handcrafted by engineers and researchers at OpenAI.

Initial Data Collection and Normalization

[More Information Needed]

Who are the source language producers?

[More Information Needed]

Annotations

[More Information Needed]

Annotation process

[More Information Needed]

Who are the annotators?

[More Information Needed]

Personal and Sensitive Information

None.

Considerations for Using the Data

Make sure you execute generated Python code in a safe environment when evauating against this dataset as generated code could be harmful.

Social Impact of Dataset

With this dataset code generating models can be better evaluated which leads to fewer issues introduced when using such models.

Discussion of Biases

[More Information Needed]

Other Known Limitations

[More Information Needed]

Additional Information

Dataset Curators

OpenAI

Licensing Information

MIT License

Citation Information

@misc{chen2021evaluating,
      title={Evaluating Large Language Models Trained on Code},
      author={Mark Chen and Jerry Tworek and Heewoo Jun and Qiming Yuan and Henrique Ponde de Oliveira Pinto and Jared Kaplan and Harri Edwards and Yuri Burda and Nicholas Joseph and Greg Brockman and Alex Ray and Raul Puri and Gretchen Krueger and Michael Petrov and Heidy Khlaaf and Girish Sastry and Pamela Mishkin and Brooke Chan and Scott Gray and Nick Ryder and Mikhail Pavlov and Alethea Power and Lukasz Kaiser and Mohammad Bavarian and Clemens Winter and Philippe Tillet and Felipe Petroski Such and Dave Cummings and Matthias Plappert and Fotios Chantzis and Elizabeth Barnes and Ariel Herbert-Voss and William Hebgen Guss and Alex Nichol and Alex Paino and Nikolas Tezak and Jie Tang and Igor Babuschkin and Suchir Balaji and Shantanu Jain and William Saunders and Christopher Hesse and Andrew N. Carr and Jan Leike and Josh Achiam and Vedant Misra and Evan Morikawa and Alec Radford and Matthew Knight and Miles Brundage and Mira Murati and Katie Mayer and Peter Welinder and Bob McGrew and Dario Amodei and Sam McCandlish and Ilya Sutskever and Wojciech Zaremba},
      year={2021},
      eprint={2107.03374},
      archivePrefix={arXiv},
      primaryClass={cs.LG}
}

Contributions

Thanks to @lvwerra for adding this dataset.

Update on GitHub