File size: 220,520 Bytes
e99a7c1
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
 
1
2
3
4
5
6
7
8
9
10
11
12
13
14
15
16
17
18
19
20
21
22
23
24
25
26
27
28
29
30
31
32
33
34
35
36
37
38
39
40
41
42
43
44
45
46
47
48
49
50
51
52
53
54
55
56
57
58
59
60
61
62
63
64
65
66
67
68
69
70
71
72
73
74
75
76
77
78
79
80
81
82
83
84
85
86
87
88
89
90
91
92
93
94
95
96
97
98
99
100
101
102
103
104
105
106
107
108
109
110
111
112
113
114
115
116
117
118
119
120
121
122
123
124
125
126
127
128
129
130
131
132
133
134
135
136
137
138
139
140
141
142
143
144
145
146
147
148
149
150
151
152
153
154
155
156
157
158
159
160
161
162
163
164
165
166
167
168
169
170
171
172
173
174
175
176
177
178
179
180
181
182
183
184
185
186
187
188
189
190
191
192
193
194
195
196
197
198
199
200
201
202
203
204
205
206
207
208
209
210
211
212
213
214
215
216
217
218
219
220
221
222
223
224
225
226
227
228
229
230
231
232
233
234
235
236
237
238
239
240
241
242
243
244
245
246
247
248
249
250
251
252
253
254
255
256
257
258
259
260
261
262
263
264
265
266
267
268
269
270
271
272
273
274
275
276
277
278
279
280
281
282
283
284
285
286
287
288
289
290
291
292
293
294
295
296
297
298
299
300
301
302
303
304
305
306
307
308
309
310
311
312
313
314
315
316
317
318
319
320
321
322
323
324
325
326
327
328
329
330
331
332
333
334
335
336
337
338
339
340
341
342
343
344
345
346
347
348
349
350
351
352
353
354
355
356
357
358
359
360
361
362
363
364
365
366
367
368
369
370
371
372
373
374
375
376
377
378
379
380
381
382
383
384
385
386
387
388
389
390
391
392
393
394
395
396
397
398
399
400
401
402
403
404
405
406
407
408
409
410
411
412
413
414
415
416
417
418
419
420
421
422
423
424
425
426
427
428
429
430
431
432
433
434
435
436
437
438
439
440
441
442
443
444
445
446
447
448
449
450
451
452
453
454
455
456
457
458
459
460
461
462
463
464
465
466
467
468
469
470
471
472
473
474
475
476
477
478
479
480
481
482
483
484
485
486
487
488
489
490
491
492
493
494
495
496
497
498
499
500
501
502
503
504
505
506
507
508
509
510
511
512
513
514
515
516
517
518
519
520
521
522
523
524
525
526
527
528
529
530
531
532
533
534
535
536
537
538
539
540
541
542
543
544
545
546
547
548
549
550
551
552
553
554
555
556
557
558
559
560
561
562
563
564
565
566
567
568
569
570
571
572
573
574
575
576
577
578
579
580
581
582
583
584
585
586
587
588
589
590
591
592
593
594
595
596
597
598
599
600
601
602
603
604
605
606
607
608
609
610
611
612
613
614
615
616
617
618
619
620
621
622
623
624
625
626
627
628
629
630
631
632
633
634
635
636
637
638
639
640
641
642
643
644
645
646
647
648
649
650
651
652
653
654
655
656
657
658
659
660
661
662
663
664
665
666
667
668
669
670
671
672
673
674
675
676
677
678
679
680
681
682
683
684
685
686
687
688
689
690
691
692
693
694
695
696
697
698
699
700
701
702
703
704
705
706
707
708
709
710
711
712
713
714
715
716
717
718
719
720
721
722
723
724
725
726
727
728
729
730
731
732
733
734
735
736
737
738
739
740
741
742
743
744
745
746
747
748
749
750
751
752
753
754
755
756
757
758
759
760
761
762
763
764
765
766
767
768
769
770
771
772
773
774
775
776
777
778
779
780
781
782
783
784
785
786
787
788
789
790
791
792
793
794
795
796
797
798
799
800
801
802
803
804
805
806
807
808
809
810
811
812
813
814
815
816
817
818
819
820
821
822
823
824
825
826
827
828
829
830
831
832
833
834
835
836
837
838
839
840
841
842
843
844
845
846
847
848
849
850
851
852
853
854
855
856
857
858
859
860
861
862
863
864
865
866
867
868
869
870
871
872
873
874
875
876
877
878
879
880
881
882
883
884
885
886
887
888
889
890
891
892
893
894
895
896
897
898
899
900
901
902
903
904
905
906
907
908
909
910
911
912
913
914
915
916
917
918
919
920
921
922
923
924
925
926
927
928
929
930
931
932
933
934
935
936
937
938
939
940
941
942
943
944
945
946
947
948
949
950
951
952
953
954
955
956
957
958
959
960
961
962
963
964
965
966
967
968
969
970
971
972
973
974
975
976
977
978
979
980
981
982
983
984
985
986
987
988
989
990
991
992
993
994
995
996
997
998
999
1000
1001
1002
1003
1004
1005
1006
1007
1008
1009
1010
1011
1012
1013
1014
1015
1016
1017
1018
1019
1020
1021
1022
1023
1024
1025
1026
1027
1028
1029
1030
1031
1032
1033
1034
1035
1036
1037
1038
1039
1040
1041
1042
1043
1044
1045
1046
1047
1048
1049
1050
1051
1052
1053
1054
1055
1056
1057
1058
1059
1060
1061
1062
1063
1064
1065
1066
1067
1068
1069
1070
1071
1072
1073
1074
1075
1076
1077
1078
1079
1080
1081
1082
1083
1084
1085
1086
1087
1088
1089
1090
1091
1092
1093
1094
1095
1096
1097
1098
1099
1100
1101
1102
1103
1104
1105
1106
1107
1108
1109
1110
1111
1112
1113
1114
1115
1116
1117
1118
1119
1120
1121
1122
1123
1124
1125
1126
1127
1128
1129
1130
1131
1132
1133
1134
1135
1136
1137
1138
1139
1140
1141
1142
1143
1144
1145
1146
1147
1148
1149
1150
1151
1152
1153
1154
1155
1156
1157
1158
1159
1160
1161
1162
1163
1164
1165
1166
1167
1168
1169
1170
1171
1172
1173
1174
1175
1176
1177
1178
1179
1180
1181
1182
1183
1184
1185
1186
1187
1188
1189
1190
1191
1192
1193
1194
1195
1196
1197
1198
1199
1200
1201
1202
1203
1204
1205
1206
1207
1208
1209
1210
1211
1212
1213
1214
1215
1216
1217
1218
1219
1220
1221
1222
1223
1224
1225
1226
1227
1228
1229
1230
1231
1232
1233
1234
1235
1236
1237
1238
1239
1240
1241
1242
1243
1244
1245
1246
1247
1248
1249
1250
1251
1252
1253
1254
1255
1256
1257
1258
1259
1260
1261
1262
1263
1264
1265
1266
1267
1268
1269
1270
1271
1272
1273
1274
1275
1276
1277
1278
1279
1280
1281
1282
1283
1284
1285
1286
1287
1288
1289
1290
1291
1292
1293
1294
1295
1296
1297
1298
1299
1300
1301
1302
1303
1304
1305
1306
1307
1308
1309
1310
1311
1312
1313
1314
1315
1316
1317
1318
1319
1320
1321
1322
1323
1324
1325
1326
1327
1328
1329
1330
1331
1332
1333
1334
1335
1336
1337
1338
1339
1340
1341
1342
1343
1344
1345
1346
1347
1348
1349
1350
1351
1352
1353
1354
1355
1356
1357
1358
1359
1360
1361
1362
1363
1364
1365
1366
1367
1368
1369
1370
1371
1372
1373
1374
1375
1376
1377
1378
1379
1380
1381
1382
1383
1384
1385
1386
1387
1388
1389
1390
1391
1392
1393
1394
1395
1396
1397
1398
1399
1400
1401
1402
1403
1404
1405
1406
1407
1408
1409
1410
1411
1412
1413
1414
1415
1416
1417
1418
1419
1420
1421
1422
1423
1424
1425
1426
1427
1428
1429
1430
1431
1432
1433
1434
1435
1436
1437
1438
1439
1440
1441
1442
1443
1444
1445
1446
1447
1448
1449
1450
1451
1452
1453
1454
1455
1456
1457
1458
1459
1460
1461
1462
1463
1464
1465
1466
1467
1468
1469
1470
1471
1472
1473
1474
1475
1476
1477
1478
1479
1480
1481
1482
1483
1484
1485
1486
1487
1488
1489
1490
1491
1492
1493
1494
1495
1496
1497
1498
1499
1500
1501
1502
1503
1504
1505
1506
1507
1508
1509
1510
1511
1512
1513
1514
1515
1516
1517
1518
1519
1520
1521
1522
1523
1524
1525
1526
1527
1528
1529
1530
1531
1532
1533
1534
1535
1536
1537
1538
1539
1540
1541
1542
1543
1544
1545
1546
1547
1548
1549
1550
1551
1552
1553
1554
1555
1556
1557
1558
1559
1560
1561
1562
1563
1564
1565
1566
1567
1568
1569
1570
1571
1572
1573
1574
1575
1576
1577
1578
1579
1580
1581
1582
1583
1584
1585
1586
1587
1588
1589
1590
1591
1592
1593
1594
1595
1596
1597
1598
1599
1600
1601
1602
1603
1604
1605
1606
1607
1608
1609
1610
1611
1612
1613
1614
1615
1616
1617
1618
1619
1620
1621
1622
1623
1624
1625
1626
1627
1628
1629
1630
1631
1632
1633
1634
1635
1636
1637
1638
1639
1640
1641
1642
1643
1644
1645
1646
1647
1648
1649
1650
1651
1652
1653
1654
1655
1656
1657
1658
1659
1660
1661
1662
1663
1664
1665
1666
1667
1668
1669
1670
1671
1672
1673
1674
1675
1676
1677
1678
1679
1680
1681
1682
1683
1684
1685
1686
1687
1688
1689
1690
1691
1692
1693
1694
1695
1696
1697
1698
1699
1700
1701
1702
1703
1704
1705
1706
1707
1708
1709
1710
1711
1712
1713
1714
1715
1716
1717
1718
1719
1720
1721
1722
1723
1724
1725
1726
1727
1728
1729
1730
1731
1732
1733
1734
1735
1736
1737
1738
1739
1740
1741
1742
1743
1744
1745
1746
1747
1748
1749
1750
1751
1752
1753
1754
1755
1756
1757
1758
1759
1760
1761
1762
1763
1764
1765
1766
1767
1768
1769
1770
1771
1772
1773
1774
1775
1776
1777
1778
1779
1780
1781
1782
1783
1784
1785
1786
1787
1788
1789
1790
1791
1792
1793
1794
1795
1796
1797
1798
1799
1800
1801
1802
1803
1804
1805
1806
1807
1808
1809
1810
1811
1812
1813
1814
1815
1816
1817
1818
1819
1820
1821
1822
1823
1824
1825
1826
1827
1828
1829
1830
1831
1832
1833
1834
1835
1836
1837
1838
1839
1840
1841
1842
1843
1844
1845
1846
1847
1848
1849
1850
1851
1852
1853
1854
1855
1856
1857
1858
1859
1860
1861
1862
1863
1864
1865
1866
1867
1868
1869
1870
1871
1872
1873
1874
1875
1876
1877
1878
1879
1880
1881
1882
1883
1884
1885
1886
1887
1888
1889
1890
1891
1892
1893
1894
1895
1896
1897
1898
1899
1900
1901
1902
1903
1904
1905
1906
1907
1908
1909
1910
1911
1912
1913
1914
1915
1916
1917
1918
1919
1920
1921
1922
1923
1924
1925
1926
1927
1928
1929
1930
1931
1932
1933
1934
1935
1936
1937
1938
1939
1940
1941
1942
1943
1944
1945
1946
1947
1948
1949
1950
1951
1952
1953
1954
1955
1956
1957
1958
1959
1960
1961
1962
1963
1964
1965
1966
1967
1968
1969
1970
1971
1972
1973
1974
1975
1976
1977
1978
1979
1980
1981
1982
1983
1984
1985
1986
1987
1988
1989
1990
1991
1992
1993
1994
1995
1996
1997
1998
1999
2000
2001
2002
2003
2004
2005
2006
2007
2008
2009
2010
2011
2012
2013
2014
2015
2016
2017
2018
2019
2020
2021
2022
2023
2024
2025
2026
2027
2028
2029
2030
2031
2032
2033
2034
2035
2036
2037
2038
2039
2040
2041
2042
2043
2044
2045
2046
2047
2048
2049
2050
2051
2052
2053
2054
2055
2056
2057
2058
2059
2060
2061
2062
2063
2064
2065
2066
2067
2068
2069
2070
2071
2072
2073
2074
2075
2076
2077
2078
2079
2080
2081
2082
2083
2084
2085
2086
2087
2088
2089
2090
2091
2092
2093
2094
2095
[
  {
    "name": "HumanEval_24_largest_divisor",
    "language": "r",
    "prompt": "# For a given number n, find the largest number that divides n evenly, smaller than n\n# >>> largest_divisor(15)\n# 5\nlargest_divisor <- function(n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_24_largest_divisor.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- largest_divisor\n    if(!identical(candidate(3), 1)){quit('no', 1)}\n    if(!identical(candidate(7), 1)){quit('no', 1)}\n    if(!identical(candidate(10), 5)){quit('no', 1)}\n    if(!identical(candidate(100), 50)){quit('no', 1)}\n    if(!identical(candidate(49), 7)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_47_median",
    "language": "r",
    "prompt": "# Return median of elements in the list l.\n# >>> median(c(3, 1, 2, 4, 5))\n# 3\n# >>> median(c(-10, 4, 6, 1000, 10, 20))\n# 15.0\nmedian <- function(l) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_47_median.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- median\n    if(!identical(candidate(c(3, 1, 2, 4, 5)), 3)){quit('no', 1)}\n    if(!identical(candidate(c(-10, 4, 6, 1000, 10, 20)), 8.0)){quit('no', 1)}\n    if(!identical(candidate(c(5)), 5)){quit('no', 1)}\n    if(!identical(candidate(c(6, 5)), 5.5)){quit('no', 1)}\n    if(!identical(candidate(c(8, 1, 3, 9, 9, 2, 7)), 7)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_160_do_algebra",
    "language": "r",
    "prompt": "# Given two lists operator, and operand. The first list has basic algebra operations, and \n# the second list is a list of integers. Use the two given lists to build the algebric \n# expression and return the evaluation of this expression.\n# The basic algebra operations:\n# Addition ( + ) \n# Subtraction ( - ) \n# Multiplication ( * ) \n# Floor division ( // ) \n# Exponentiation ( ** ) \n# Example:\n# operator['+', '*', '-']\n# vector = [2, 3, 4, 5]\n# result = 2 + 3 * 4 - 5\n# => result = 9\n# Note:\n# The length of operator list is equal to the length of operand list minus one.\n# Operand is a list of of non-negative integers.\n# Operator list has at least one operator, and operand list has at least two operands.\ndo_algebra <- function(operator, operand) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_160_do_algebra.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- do_algebra\n    if(!identical(candidate(c('**', '*', '+'), c(2, 3, 4, 5)), 37)){quit('no', 1)}\n    if(!identical(candidate(c('+', '*', '-'), c(2, 3, 4, 5)), 9)){quit('no', 1)}\n    if(!identical(candidate(c('//', '*'), c(7, 3, 4)), 8)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_35_max_element",
    "language": "r",
    "prompt": "# Return maximum element in the list.\n# >>> max_element(c(1, 2, 3))\n# 3\n# >>> max_element(c(5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10))\n# 123\nmax_element <- function(l) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_35_max_element.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- max_element\n    if(!identical(candidate(c(1, 2, 3)), 3)){quit('no', 1)}\n    if(!identical(candidate(c(5, 3, -5, 2, -3, 3, 9, 0, 124, 1, -10)), 124)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_135_can_arrange",
    "language": "r",
    "prompt": "# Create a function which returns the largest index of an element which\n# is not greater than or equal to the element immediately preceding it. If\n# no such element exists then return -1. The given vector will not contain\n# duplicate values.\n# Examples:\n# >>> can_arrange(c(1, 2, 4, 3, 5))\n# 3\n# >>> can_arrange(c(1, 2, 3))\n# -1\ncan_arrange <- function(arr) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_135_can_arrange.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- can_arrange\n    if(!identical(candidate(c(1, 2, 4, 3, 5)), 3)){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 4, 5)), -1)){quit('no', 1)}\n    if(!identical(candidate(c(1, 4, 2, 5, 6, 7, 8, 9, 10)), 2)){quit('no', 1)}\n    if(!identical(candidate(c(4, 8, 5, 7, 3)), 4)){quit('no', 1)}\n    if(!identical(candidate(c()), -1)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_41_car_race_collision",
    "language": "r",
    "prompt": "# Imagine a road that's a perfectly straight infinitely long line.\n# n cars are driving left to right;  simultaneously, a different set of n cars\n# are driving right to left.   The two sets of cars start out being very far from\n# each other.  All cars move in the same speed.  Two cars are said to collide\n# when a car that's moving left to right hits a car that's moving right to left.\n# However, the cars are infinitely sturdy and strong; as a result, they continue moving\n# in their trajectory as if they did not collide.\n# This function outputs the number of such collisions.\ncar_race_collision <- function(n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_41_car_race_collision.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- car_race_collision\n    if(!identical(candidate(2), 4)){quit('no', 1)}\n    if(!identical(candidate(3), 9)){quit('no', 1)}\n    if(!identical(candidate(4), 16)){quit('no', 1)}\n    if(!identical(candidate(8), 64)){quit('no', 1)}\n    if(!identical(candidate(10), 100)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_134_check_if_last_char_is_a_letter",
    "language": "r",
    "prompt": "# Create a function that returns TRUE if the last character\n# of a given string is an alphabetical character and is not\n# a part of a word, and FALSE otherwise.\n# Note: \"word\" is a group of characters separated by space.\n# Examples:\n# >>> check_if_last_char_is_a_letter('apple pie')\n# FALSE\n# >>> check_if_last_char_is_a_letter('apple pi e')\n# TRUE\n# >>> check_if_last_char_is_a_letter('apple pi e ')\n# FALSE\n# >>> check_if_last_char_is_a_letter('')\n# FALSE\ncheck_if_last_char_is_a_letter <- function(txt) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_134_check_if_last_char_is_a_letter.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- check_if_last_char_is_a_letter\n    if(!identical(candidate('apple'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('apple pi e'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('eeeee'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('A'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('Pumpkin pie '), FALSE)){quit('no', 1)}\n    if(!identical(candidate('Pumpkin pie 1'), FALSE)){quit('no', 1)}\n    if(!identical(candidate(''), FALSE)){quit('no', 1)}\n    if(!identical(candidate('eeeee e '), FALSE)){quit('no', 1)}\n    if(!identical(candidate('apple pie'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('apple pi e '), FALSE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_31_is_prime",
    "language": "r",
    "prompt": "# Return true if a given number is prime, and false otherwise.\n# >>> is_prime(6)\n# FALSE\n# >>> is_prime(101)\n# TRUE\n# >>> is_prime(11)\n# TRUE\n# >>> is_prime(13441)\n# TRUE\n# >>> is_prime(61)\n# TRUE\n# >>> is_prime(4)\n# FALSE\n# >>> is_prime(1)\n# FALSE\nis_prime <- function(n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_31_is_prime.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- is_prime\n    if(!identical(candidate(6), FALSE)){quit('no', 1)}\n    if(!identical(candidate(101), TRUE)){quit('no', 1)}\n    if(!identical(candidate(11), TRUE)){quit('no', 1)}\n    if(!identical(candidate(13441), TRUE)){quit('no', 1)}\n    if(!identical(candidate(61), TRUE)){quit('no', 1)}\n    if(!identical(candidate(4), FALSE)){quit('no', 1)}\n    if(!identical(candidate(1), FALSE)){quit('no', 1)}\n    if(!identical(candidate(5), TRUE)){quit('no', 1)}\n    if(!identical(candidate(11), TRUE)){quit('no', 1)}\n    if(!identical(candidate(17), TRUE)){quit('no', 1)}\n    if(!identical(candidate(85), FALSE)){quit('no', 1)}\n    if(!identical(candidate(77), FALSE)){quit('no', 1)}\n    if(!identical(candidate(255379), FALSE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_104_unique_digits",
    "language": "r",
    "prompt": "# Given a list of positive integers x. return a sorted list of all \n# elements that hasn't any even digit.\n# Note: Returned list should be sorted in increasing order.\n# For example:\n# >>> unique_digits(c(15, 33, 1422, 1))\n# list(1, 15, 33)\n# >>> unique_digits(c(152, 323, 1422, 10))\n# list()\nunique_digits <- function(x) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_104_unique_digits.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- unique_digits\n    if(!identical(candidate(c(15, 33, 1422, 1)), list(1, 15, 33))){quit('no', 1)}\n    if(!identical(candidate(c(152, 323, 1422, 10)), list())){quit('no', 1)}\n    if(!identical(candidate(c(12345, 2033, 111, 151)), list(111, 151))){quit('no', 1)}\n    if(!identical(candidate(c(135, 103, 31)), list(31, 135))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_11_string_xor",
    "language": "r",
    "prompt": "# Input are two strings a and b consisting only of 1s and 0s.\n# Perform binary XOR on these inputs and return result also as a string.\n# >>> string_xor('010', '110')\n# '100'\nstring_xor <- function(a, b) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_11_string_xor.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- string_xor\n    if(!identical(candidate('111000', '101010'), '010010')){quit('no', 1)}\n    if(!identical(candidate('1', '1'), '0')){quit('no', 1)}\n    if(!identical(candidate('0101', '0000'), '0101')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_60_sum_to_n",
    "language": "r",
    "prompt": "# sum_to_n is a function that sums numbers from 1 to n.\n# >>> sum_to_n(30)\n# 465\n# >>> sum_to_n(100)\n# 5050\n# >>> sum_to_n(5)\n# 15\n# >>> sum_to_n(10)\n# 55\n# >>> sum_to_n(1)\n# 1\nsum_to_n <- function(n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_60_sum_to_n.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- sum_to_n\n    if(!identical(candidate(1), 1)){quit('no', 1)}\n    if(!identical(candidate(6), 21)){quit('no', 1)}\n    if(!identical(candidate(11), 66)){quit('no', 1)}\n    if(!identical(candidate(30), 465)){quit('no', 1)}\n    if(!identical(candidate(100), 5050)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_151_double_the_difference",
    "language": "r",
    "prompt": "# Given a list of numbers, return the sum of squares of the numbers\n# in the list that are odd. Ignore numbers that are negative or not integers.\n# >>> double_the_difference(c(1, 3, 2, 0))\n# 10\n# >>> double_the_difference(c(-1, -2, 0))\n# 0\n# >>> double_the_difference(c(9, -2))\n# 81\n# >>> double_the_difference(c(0))\n# 0\n# If the input list is empty, return 0.\ndouble_the_difference <- function(lst) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_151_double_the_difference.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- double_the_difference\n    if(!identical(candidate(c()), 0)){quit('no', 1)}\n    if(!identical(candidate(c(5.0, 4.0)), 25)){quit('no', 1)}\n    if(!identical(candidate(c(0.1, 0.2, 0.3)), 0)){quit('no', 1)}\n    if(!identical(candidate(c(-10.0, -20.0, -30.0)), 0)){quit('no', 1)}\n    if(!identical(candidate(c(-1.0, -2.0, 8.0)), 0)){quit('no', 1)}\n    if(!identical(candidate(c(0.2, 3.0, 5.0)), 34)){quit('no', 1)}\n    if(!identical(candidate(c(-9.0, -7.0, -5.0, -3.0, -1.0, 1.0, 3.0, 5.0, 7.0, 9.0)), 165)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_23_strlen",
    "language": "r",
    "prompt": "# Return length of given string\n# >>> strlen('')\n# 0\n# >>> strlen('abc')\n# 3\nstrlen <- function(string) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_23_strlen.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- strlen\n    if(!identical(candidate(''), 0)){quit('no', 1)}\n    if(!identical(candidate('x'), 1)){quit('no', 1)}\n    if(!identical(candidate('asdasnakj'), 9)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_91_is_bored",
    "language": "r",
    "prompt": "# You'll be given a string of words, and your task is to count the number\n# of boredoms. A boredom is a sentence that starts with the word \"I\".\n# Sentences are delimited by '.', '?' or '!'.\n# For example:\n# >>> is_bored('Hello world')\n# 0\n# >>> is_bored('The sky is blue. The sun is shining. I love this weather')\n# 1\nis_bored <- function(S) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_91_is_bored.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- is_bored\n    if(!identical(candidate('Hello world'), 0)){quit('no', 1)}\n    if(!identical(candidate('Is the sky blue?'), 0)){quit('no', 1)}\n    if(!identical(candidate('I love It !'), 1)){quit('no', 1)}\n    if(!identical(candidate('bIt'), 0)){quit('no', 1)}\n    if(!identical(candidate('I feel good today. I will be productive. will kill It'), 2)){quit('no', 1)}\n    if(!identical(candidate('You and I are going for a walk'), 0)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_64_vowels_count",
    "language": "r",
    "prompt": "# Write a function vowels_count which takes a string representing\n# a word as input and returns the number of vowels in the string.\n# Vowels in this case are 'a', 'e', 'i', 'o', 'u'. Here, 'y' is also a\n# vowel, but only when it is at the end of the given word.\n# Example:\n# >>> vowels_count('abcde')\n# 2\n# >>> vowels_count('ACEDY')\n# 3\nvowels_count <- function(s) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_64_vowels_count.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- vowels_count\n    if(!identical(candidate('abcde'), 2)){quit('no', 1)}\n    if(!identical(candidate('Alone'), 3)){quit('no', 1)}\n    if(!identical(candidate('key'), 2)){quit('no', 1)}\n    if(!identical(candidate('bye'), 1)){quit('no', 1)}\n    if(!identical(candidate('keY'), 2)){quit('no', 1)}\n    if(!identical(candidate('bYe'), 1)){quit('no', 1)}\n    if(!identical(candidate('ACEDY'), 3)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_55_fib",
    "language": "r",
    "prompt": "# Return n-th Fibonacci number.\n# >>> fib(10)\n# 55\n# >>> fib(1)\n# 1\n# >>> fib(8)\n# 21\nfib <- function(n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_55_fib.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- fib\n    if(!identical(candidate(10), 55)){quit('no', 1)}\n    if(!identical(candidate(1), 1)){quit('no', 1)}\n    if(!identical(candidate(8), 21)){quit('no', 1)}\n    if(!identical(candidate(11), 89)){quit('no', 1)}\n    if(!identical(candidate(12), 144)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_144_simplify",
    "language": "r",
    "prompt": "# Your task is to implement a function that will simplify the expression\n# x * n. The function returns TRUE if x * n evaluates to a whole number and FALSE\n# otherwise. Both x and n, are string representation of a fraction, and have the following format,\n# <numerator>/<denominator> where both numerator and denominator are positive whole numbers.\n# You can assume that x, and n are valid fractions, and do not have zero as denominator.\n# >>> simplify('1/5', '5/1')\n# TRUE\n# >>> simplify('1/6', '2/1')\n# FALSE\n# >>> simplify('7/10', '10/2')\n# FALSE\nsimplify <- function(x, n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_144_simplify.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- simplify\n    if(!identical(candidate('1/5', '5/1'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('1/6', '2/1'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('5/1', '3/1'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('7/10', '10/2'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('2/10', '50/10'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('7/2', '4/2'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('11/6', '6/1'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('2/3', '5/2'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('5/2', '3/5'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('2/4', '8/4'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('2/4', '4/2'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('1/5', '5/1'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('1/5', '1/5'), FALSE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_98_count_upper",
    "language": "r",
    "prompt": "# Given a string s, count the number of uppercase vowels in even indices.\n# For example:\n# >>> count_upper('aBCdEf')\n# 1\n# >>> count_upper('abcdefg')\n# 0\n# >>> count_upper('dBBE')\n# 0\ncount_upper <- function(s) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_98_count_upper.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- count_upper\n    if(!identical(candidate('aBCdEf'), 1)){quit('no', 1)}\n    if(!identical(candidate('abcdefg'), 0)){quit('no', 1)}\n    if(!identical(candidate('dBBE'), 0)){quit('no', 1)}\n    if(!identical(candidate('B'), 0)){quit('no', 1)}\n    if(!identical(candidate('U'), 1)){quit('no', 1)}\n    if(!identical(candidate(''), 0)){quit('no', 1)}\n    if(!identical(candidate('EEEE'), 2)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_115_max_fill",
    "language": "r",
    "prompt": "# You are given a rectangular grid of wells. Each row represents a single well,\n# and each 1 in a row represents a single unit of water.\n# Each well has a corresponding bucket that can be used to extract water from it, \n# and all buckets have the same capacity.\n# Your task is to use the buckets to empty the wells.\n# Output the number of times you need to lower the buckets.\n# Example 1:\n# >>> max_fill(list(list(0, 0, 1, 0), list(0, 1, 0, 0), list(1, 1, 1, 1)), 1)\n# 6\n# Example 2:\n# >>> max_fill(list(list(0, 0, 1, 1), list(0, 0, 0, 0), list(1, 1, 1, 1), list(0, 1, 1, 1)), 2)\n# 5\n# Example 3:\n# >>> max_fill(list(list(0, 0, 0), list(0, 0, 0)), 5)\n# 0\n# Constraints:\n# * all wells have the same length\n# * 1 <= grid.length <= 10^2\n# * 1 <= grid[:,1].length <= 10^2\n# * grid[i][j] -> 0 | 1\n# * 1 <= capacity <= 10\nmax_fill <- function(grid, capacity) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_115_max_fill.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- max_fill\n    if(!identical(candidate(list(list(0, 0, 1, 0), list(0, 1, 0, 0), list(1, 1, 1, 1)), 1), 6)){quit('no', 1)}\n    if(!identical(candidate(list(list(0, 0, 1, 1), list(0, 0, 0, 0), list(1, 1, 1, 1), list(0, 1, 1, 1)), 2), 5)){quit('no', 1)}\n    if(!identical(candidate(list(list(0, 0, 0), list(0, 0, 0)), 5), 0)){quit('no', 1)}\n    if(!identical(candidate(list(list(1, 1, 1, 1), list(1, 1, 1, 1)), 2), 4)){quit('no', 1)}\n    if(!identical(candidate(list(list(1, 1, 1, 1), list(1, 1, 1, 1)), 9), 2)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_120_maximum",
    "language": "r",
    "prompt": "# Given a vector arr of integers and a positive integer k, return a sorted list \n# of length k with the maximum k numbers in arr.\n# Example 1:\n# >>> maximum(c(-3, -4, 5), 3)\n# list(-4, -3, 5)\n# Example 2:\n# >>> maximum(c(4, -4, 4), 2)\n# list(4, 4)\n# Example 3:\n# >>> maximum(c(-3, 2, 1, 2, -1, -2, 1), 1)\n# list(2)\n# Note:\n# 1. The length of the vector will be in the range of [1, 1000].\n# 2. The elements in the vector will be in the range of [-1000, 1000].\n# 3. 0 <= k <= len(arr)\nmaximum <- function(arr, k) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_120_maximum.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- maximum\n    if(!identical(candidate(c(-3, -4, 5), 3), list(-4, -3, 5))){quit('no', 1)}\n    if(!identical(candidate(c(4, -4, 4), 2), list(4, 4))){quit('no', 1)}\n    if(!identical(candidate(c(-3, 2, 1, 2, -1, -2, 1), 1), list(2))){quit('no', 1)}\n    if(!identical(candidate(c(123, -123, 20, 0, 1, 2, -3), 3), list(2, 20, 123))){quit('no', 1)}\n    if(!identical(candidate(c(-123, 20, 0, 1, 2, -3), 4), list(0, 1, 2, 20))){quit('no', 1)}\n    if(!identical(candidate(c(5, 15, 0, 3, -13, -8, 0), 7), list(-13, -8, 0, 0, 3, 5, 15))){quit('no', 1)}\n    if(!identical(candidate(c(-1, 0, 2, 5, 3, -10), 2), list(3, 5))){quit('no', 1)}\n    if(!identical(candidate(c(1, 0, 5, -7), 1), list(5))){quit('no', 1)}\n    if(!identical(candidate(c(4, -4), 2), list(-4, 4))){quit('no', 1)}\n    if(!identical(candidate(c(-10, 10), 2), list(-10, 10))){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3, -23, 243, -400, 0), 0), list())){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_93_encode",
    "language": "r",
    "prompt": "# Write a function that takes a message, and encodes in such a \n# way that it swaps case of all letters, replaces all vowels in \n# the message with the letter that appears 2 places ahead of that \n# vowel in the english alphabet. \n# Assume only letters. \n# Examples:\n# >>> encode('test')\n# 'TGST'\n# >>> encode('This is a message')\n# 'tHKS KS C MGSSCGG'\nencode <- function(message) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_93_encode.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- encode\n    if(!identical(candidate('TEST'), 'tgst')){quit('no', 1)}\n    if(!identical(candidate('Mudasir'), 'mWDCSKR')){quit('no', 1)}\n    if(!identical(candidate('YES'), 'ygs')){quit('no', 1)}\n    if(!identical(candidate('This is a message'), 'tHKS KS C MGSSCGG')){quit('no', 1)}\n    if(!identical(candidate('I DoNt KnOw WhAt tO WrItE'), 'k dQnT kNqW wHcT Tq wRkTg')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_51_remove_vowels",
    "language": "r",
    "prompt": "# remove_vowels is a function that takes string and returns string without vowels.\n# >>> remove_vowels('')\n# ''\n# >>> remove_vowels('abcdef')\n# 'bcdf'\n# >>> remove_vowels('aaaaa')\n# ''\n# >>> remove_vowels('aaBAA')\n# 'B'\n# >>> remove_vowels('zbcd')\n# 'zbcd'\nremove_vowels <- function(text) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_51_remove_vowels.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- remove_vowels\n    if(!identical(candidate(''), '')){quit('no', 1)}\n    if(!identical(candidate('abcdef\\nghijklm'), 'bcdf\\nghjklm')){quit('no', 1)}\n    if(!identical(candidate('fedcba'), 'fdcb')){quit('no', 1)}\n    if(!identical(candidate('eeeee'), '')){quit('no', 1)}\n    if(!identical(candidate('acBAA'), 'cB')){quit('no', 1)}\n    if(!identical(candidate('EcBOO'), 'cB')){quit('no', 1)}\n    if(!identical(candidate('ybcd'), 'ybcd')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_30_get_positive",
    "language": "r",
    "prompt": "# Return only positive numbers in the list.\n# >>> get_positive(c(-1, 2, -4, 5, 6))\n# list(2, 5, 6)\n# >>> get_positive(c(5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10))\n# list(5, 3, 2, 3, 9, 123, 1)\nget_positive <- function(l) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_30_get_positive.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- get_positive\n    if(!identical(candidate(c(-1, -2, 4, 5, 6)), list(4, 5, 6))){quit('no', 1)}\n    if(!identical(candidate(c(5, 3, -5, 2, 3, 3, 9, 0, 123, 1, -10)), list(5, 3, 2, 3, 3, 9, 123, 1))){quit('no', 1)}\n    if(!identical(candidate(c(-1, -2)), list())){quit('no', 1)}\n    if(!identical(candidate(c()), list())){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_15_string_sequence",
    "language": "r",
    "prompt": "# Return a string containing space-delimited numbers starting from 0 upto n inclusive.\n# >>> string_sequence(0)\n# '0'\n# >>> string_sequence(5)\n# '0 1 2 3 4 5'\nstring_sequence <- function(n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_15_string_sequence.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- string_sequence\n    if(!identical(candidate(0), '0')){quit('no', 1)}\n    if(!identical(candidate(3), '0 1 2 3')){quit('no', 1)}\n    if(!identical(candidate(10), '0 1 2 3 4 5 6 7 8 9 10')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_100_make_a_pile",
    "language": "r",
    "prompt": "# Given a positive integer n, you have to make a pile of n levels of stones.\n# The first level has n stones.\n# The number of stones in the next level is:\n# - the next odd number if n is odd.\n# - the next even number if n is even.\n# Return the number of stones in each level in a list, where element at index\n# i represents the number of stones in the level (i+1).\n# Examples:\n# >>> make_a_pile(3)\n# list(3, 5, 7)\nmake_a_pile <- function(n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_100_make_a_pile.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- make_a_pile\n    if(!identical(candidate(3), list(3, 5, 7))){quit('no', 1)}\n    if(!identical(candidate(4), list(4, 6, 8, 10))){quit('no', 1)}\n    if(!identical(candidate(5), list(5, 7, 9, 11, 13))){quit('no', 1)}\n    if(!identical(candidate(6), list(6, 8, 10, 12, 14, 16))){quit('no', 1)}\n    if(!identical(candidate(8), list(8, 10, 12, 14, 16, 18, 20, 22))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_112_reverse_delete",
    "language": "r",
    "prompt": "# Task\n# We are given two strings s and c, you have to deleted all the characters in s that are equal to any character in c\n# then check if the result string is palindrome.\n# A string is called palindrome if it reads the same backward as forward.\n# You should return a list containing the result string and TRUE/FALSE for the check.\n# Example\n# >>> reverse_delete('abcde', 'ae')\n# list('bcd', FALSE)\n# >>> reverse_delete('abcdef', 'b')\n# list('acdef', FALSE)\n# >>> reverse_delete('abcdedcba', 'ab')\n# list('cdedc', TRUE)\nreverse_delete <- function(s, c) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_112_reverse_delete.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- reverse_delete\n    if(!identical(candidate('abcde', 'ae'), list('bcd', FALSE))){quit('no', 1)}\n    if(!identical(candidate('abcdef', 'b'), list('acdef', FALSE))){quit('no', 1)}\n    if(!identical(candidate('abcdedcba', 'ab'), list('cdedc', TRUE))){quit('no', 1)}\n    if(!identical(candidate('dwik', 'w'), list('dik', FALSE))){quit('no', 1)}\n    if(!identical(candidate('a', 'a'), list('', TRUE))){quit('no', 1)}\n    if(!identical(candidate('abcdedcba', ''), list('abcdedcba', TRUE))){quit('no', 1)}\n    if(!identical(candidate('abcdedcba', 'v'), list('abcdedcba', TRUE))){quit('no', 1)}\n    if(!identical(candidate('vabba', 'v'), list('abba', TRUE))){quit('no', 1)}\n    if(!identical(candidate('mamma', 'mia'), list('', TRUE))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_27_flip_case",
    "language": "r",
    "prompt": "# For a given string, flip lowercase characters to uppercase and uppercase to lowercase.\n# >>> flip_case('Hello')\n# 'hELLO'\nflip_case <- function(string) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_27_flip_case.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- flip_case\n    if(!identical(candidate(''), '')){quit('no', 1)}\n    if(!identical(candidate('Hello!'), 'hELLO!')){quit('no', 1)}\n    if(!identical(candidate('These violent delights have violent ends'), 'tHESE VIOLENT DELIGHTS HAVE VIOLENT ENDS')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_161_solve",
    "language": "r",
    "prompt": "# You are given a string s.\n# if s[i] is a letter, reverse its case from lower to upper or vise versa, \n# otherwise keep it as it is.\n# If the string contains no letters, reverse the string.\n# The function should return the resulted string.\n# Examples\n# >>> solve('1234')\n# '4321'\n# >>> solve('ab')\n# 'AB'\n# >>> solve('#a@C')\n# '#A@c'\nsolve <- function(s) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_161_solve.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- solve\n    if(!identical(candidate('AsDf'), 'aSdF')){quit('no', 1)}\n    if(!identical(candidate('1234'), '4321')){quit('no', 1)}\n    if(!identical(candidate('ab'), 'AB')){quit('no', 1)}\n    if(!identical(candidate('#a@C'), '#A@c')){quit('no', 1)}\n    if(!identical(candidate('#AsdfW^45'), '#aSDFw^45')){quit('no', 1)}\n    if(!identical(candidate('#6@2'), '2@6#')){quit('no', 1)}\n    if(!identical(candidate('#$a^D'), '#$A^d')){quit('no', 1)}\n    if(!identical(candidate('#ccc'), '#CCC')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_29_filter_by_prefix",
    "language": "r",
    "prompt": "# Filter an input list of strings only for ones that start with a given prefix.\n# >>> filter_by_prefix(c(), 'a')\n# list()\n# >>> filter_by_prefix(c('abc', 'bcd', 'cde', 'array'), 'a')\n# list('abc', 'array')\nfilter_by_prefix <- function(strings, prefix) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_29_filter_by_prefix.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- filter_by_prefix\n    if(!identical(candidate(c(), 'john'), list())){quit('no', 1)}\n    if(!identical(candidate(c('xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'), 'xxx'), list('xxx', 'xxxAAA', 'xxx'))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_102_choose_num",
    "language": "r",
    "prompt": "# This function takes two positive numbers x and y and returns the\n# biggest even integer number that is in the range [x, y] inclusive. If \n# there's no such number, then the function should return -1.\n# For example:\n# >>> choose_num(12, 15)\n# 14\n# >>> choose_num(13, 12)\n# -1\nchoose_num <- function(x, y) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_102_choose_num.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- choose_num\n    if(!identical(candidate(12, 15), 14)){quit('no', 1)}\n    if(!identical(candidate(13, 12), -1)){quit('no', 1)}\n    if(!identical(candidate(33, 12354), 12354)){quit('no', 1)}\n    if(!identical(candidate(5234, 5233), -1)){quit('no', 1)}\n    if(!identical(candidate(6, 29), 28)){quit('no', 1)}\n    if(!identical(candidate(27, 10), -1)){quit('no', 1)}\n    if(!identical(candidate(7, 7), -1)){quit('no', 1)}\n    if(!identical(candidate(546, 546), 546)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_143_words_in_sentence",
    "language": "r",
    "prompt": "# You are given a string representing a sentence,\n# the sentence contains some words separated by a space,\n# and you have to return a string that contains the words from the original sentence,\n# whose lengths are prime numbers,\n# the order of the words in the new string should be the same as the original one.\n# Example 1:\n# >>> words_in_sentence('This is a test')\n# 'is'\n# Example 2:\n# >>> words_in_sentence('lets go for swimming')\n# 'go for'\n# Constraints:\n# * 1 <= len(sentence) <= 100\n# * sentence contains only letters\nwords_in_sentence <- function(sentence) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_143_words_in_sentence.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- words_in_sentence\n    if(!identical(candidate('This is a test'), 'is')){quit('no', 1)}\n    if(!identical(candidate('lets go for swimming'), 'go for')){quit('no', 1)}\n    if(!identical(candidate('there is no place available here'), 'there is no place')){quit('no', 1)}\n    if(!identical(candidate('Hi I am Hussein'), 'Hi am Hussein')){quit('no', 1)}\n    if(!identical(candidate('go for it'), 'go for it')){quit('no', 1)}\n    if(!identical(candidate('here'), '')){quit('no', 1)}\n    if(!identical(candidate('here is'), 'is')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_5_intersperse",
    "language": "r",
    "prompt": "# Insert a number 'delimeter' between every two consecutive elements of input list `numbers'\n# >>> intersperse(c(), 4)\n# list()\n# >>> intersperse(c(1, 2, 3), 4)\n# list(1, 4, 2, 4, 3)\nintersperse <- function(numbers, delimeter) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_5_intersperse.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- intersperse\n    if(!identical(candidate(c(), 7), list())){quit('no', 1)}\n    if(!identical(candidate(c(5, 6, 3, 2), 8), list(5, 8, 6, 8, 3, 8, 2))){quit('no', 1)}\n    if(!identical(candidate(c(2, 2, 2), 2), list(2, 2, 2, 2, 2))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_76_is_simple_power",
    "language": "r",
    "prompt": "# Your task is to write a function that returns true if a number x is a simple\n# power of n and false in other cases.\n# x is a simple power of n if n**int=x\n# For example:\n# >>> is_simple_power(1, 4)\n# TRUE\n# >>> is_simple_power(2, 2)\n# TRUE\n# >>> is_simple_power(8, 2)\n# TRUE\n# >>> is_simple_power(3, 2)\n# FALSE\n# >>> is_simple_power(3, 1)\n# FALSE\n# >>> is_simple_power(5, 3)\n# FALSE\nis_simple_power <- function(x, n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_76_is_simple_power.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- is_simple_power\n    if(!identical(candidate(16, 2), TRUE)){quit('no', 1)}\n    if(!identical(candidate(143214, 16), FALSE)){quit('no', 1)}\n    if(!identical(candidate(4, 2), TRUE)){quit('no', 1)}\n    if(!identical(candidate(9, 3), TRUE)){quit('no', 1)}\n    if(!identical(candidate(16, 4), TRUE)){quit('no', 1)}\n    if(!identical(candidate(24, 2), FALSE)){quit('no', 1)}\n    if(!identical(candidate(128, 4), FALSE)){quit('no', 1)}\n    if(!identical(candidate(12, 6), FALSE)){quit('no', 1)}\n    if(!identical(candidate(1, 1), TRUE)){quit('no', 1)}\n    if(!identical(candidate(1, 12), TRUE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_75_is_multiply_prime",
    "language": "r",
    "prompt": "# Write a function that returns true if the given number is the multiplication of 3 prime numbers\n# and false otherwise.\n# Knowing that (a) is less then 100. \n# Example:\n# >>> is_multiply_prime(30)\n# TRUE\n# 30 = 2 * 3 * 5\nis_multiply_prime <- function(a) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_75_is_multiply_prime.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- is_multiply_prime\n    if(!identical(candidate(5), FALSE)){quit('no', 1)}\n    if(!identical(candidate(30), TRUE)){quit('no', 1)}\n    if(!identical(candidate(8), TRUE)){quit('no', 1)}\n    if(!identical(candidate(10), FALSE)){quit('no', 1)}\n    if(!identical(candidate(125), TRUE)){quit('no', 1)}\n    if(!identical(candidate(105), TRUE)){quit('no', 1)}\n    if(!identical(candidate(126), FALSE)){quit('no', 1)}\n    if(!identical(candidate(729), FALSE)){quit('no', 1)}\n    if(!identical(candidate(891), FALSE)){quit('no', 1)}\n    if(!identical(candidate(1001), TRUE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_157_right_angle_triangle",
    "language": "r",
    "prompt": "# Given the lengths of the three sides of a triangle. Return TRUE if the three\n# sides form a right-angled triangle, FALSE otherwise.\n# A right-angled triangle is a triangle in which one angle is right angle or \n# 90 degree.\n# Example:\n# >>> right_angle_triangle(3, 4, 5)\n# TRUE\n# >>> right_angle_triangle(1, 2, 3)\n# FALSE\nright_angle_triangle <- function(a, b, c) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_157_right_angle_triangle.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- right_angle_triangle\n    if(!identical(candidate(3, 4, 5), TRUE)){quit('no', 1)}\n    if(!identical(candidate(1, 2, 3), FALSE)){quit('no', 1)}\n    if(!identical(candidate(10, 6, 8), TRUE)){quit('no', 1)}\n    if(!identical(candidate(2, 2, 2), FALSE)){quit('no', 1)}\n    if(!identical(candidate(7, 24, 25), TRUE)){quit('no', 1)}\n    if(!identical(candidate(10, 5, 7), FALSE)){quit('no', 1)}\n    if(!identical(candidate(5, 12, 13), TRUE)){quit('no', 1)}\n    if(!identical(candidate(15, 8, 17), TRUE)){quit('no', 1)}\n    if(!identical(candidate(48, 55, 73), TRUE)){quit('no', 1)}\n    if(!identical(candidate(1, 1, 1), FALSE)){quit('no', 1)}\n    if(!identical(candidate(2, 2, 10), FALSE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_92_any_int",
    "language": "r",
    "prompt": "# Create a function that takes 3 numbers.\n# Returns true if one of the numbers is equal to the sum of the other two, and all numbers are integers.\n# Returns false in any other cases.\n# Examples\n# >>> any_int(5, 2, 7)\n# TRUE\n# >>> any_int(3, 2, 2)\n# FALSE\n# >>> any_int(3, -2, 1)\n# TRUE\n# >>> any_int(3.6, -2.2, 2)\n# FALSE\nany_int <- function(x, y, z) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_92_any_int.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- any_int\n    if(!identical(candidate(2, 3, 1), TRUE)){quit('no', 1)}\n    if(!identical(candidate(2.5, 2, 3), FALSE)){quit('no', 1)}\n    if(!identical(candidate(1.5, 5, 3.5), FALSE)){quit('no', 1)}\n    if(!identical(candidate(2, 6, 2), FALSE)){quit('no', 1)}\n    if(!identical(candidate(4, 2, 2), TRUE)){quit('no', 1)}\n    if(!identical(candidate(2.2, 2.2, 2.2), FALSE)){quit('no', 1)}\n    if(!identical(candidate(-4, 6, 2), TRUE)){quit('no', 1)}\n    if(!identical(candidate(2, 1, 1), TRUE)){quit('no', 1)}\n    if(!identical(candidate(3, 4, 7), TRUE)){quit('no', 1)}\n    if(!identical(candidate(3.0, 4, 7), FALSE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_33_sort_third",
    "language": "r",
    "prompt": "# This function takes a list l and returns a list l' such that\n# l' is identical to l in the indicies that are not divisible by three, while its values at the indicies that are divisible by three are equal\n# to the values of the corresponding indicies of l, but sorted.\n# >>> sort_third(c(1, 2, 3))\n# list(1, 2, 3)\n# >>> sort_third(c(5, 6, 3, 4, 8, 9, 2))\n# list(2, 6, 3, 4, 8, 9, 5)\nsort_third <- function(l) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_33_sort_third.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- sort_third\n    if(!identical(candidate(c(5, 6, 3, 4, 8, 9, 2)), list(2, 6, 3, 4, 8, 9, 5))){quit('no', 1)}\n    if(!identical(candidate(c(5, 8, 3, 4, 6, 9, 2)), list(2, 8, 3, 4, 6, 9, 5))){quit('no', 1)}\n    if(!identical(candidate(c(5, 6, 9, 4, 8, 3, 2)), list(2, 6, 9, 4, 8, 3, 5))){quit('no', 1)}\n    if(!identical(candidate(c(5, 6, 3, 4, 8, 9, 2, 1)), list(2, 6, 3, 4, 8, 9, 5, 1))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_53_add",
    "language": "r",
    "prompt": "# Add two numbers x and y\n# >>> add(2, 3)\n# 5\n# >>> add(5, 7)\n# 12\nadd <- function(x, y) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_53_add.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- add\n    if(!identical(candidate(0, 1), 1)){quit('no', 1)}\n    if(!identical(candidate(1, 0), 1)){quit('no', 1)}\n    if(!identical(candidate(2, 3), 5)){quit('no', 1)}\n    if(!identical(candidate(5, 7), 12)){quit('no', 1)}\n    if(!identical(candidate(7, 5), 12)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_69_search",
    "language": "r",
    "prompt": "# You are given a non-empty list of positive integers. Return the greatest integer that is greater than \n# zero, and has a frequency greater than or equal to the value of the integer itself. \n# The frequency of an integer is the number of times it appears in the list.\n# If no such a value exist, return -1.\n# Examples:\n# >>> search(c(4, 1, 2, 2, 3, 1))\n# 2\n# >>> search(c(1, 2, 2, 3, 3, 3, 4, 4, 4))\n# 3\n# >>> search(c(5, 5, 4, 4, 4))\n# -1\nsearch <- function(lst) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_69_search.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- search\n    if(!identical(candidate(c(5, 5, 5, 5, 1)), 1)){quit('no', 1)}\n    if(!identical(candidate(c(4, 1, 4, 1, 4, 4)), 4)){quit('no', 1)}\n    if(!identical(candidate(c(3, 3)), -1)){quit('no', 1)}\n    if(!identical(candidate(c(8, 8, 8, 8, 8, 8, 8, 8)), 8)){quit('no', 1)}\n    if(!identical(candidate(c(2, 3, 3, 2, 2)), 2)){quit('no', 1)}\n    if(!identical(candidate(c(2, 7, 8, 8, 4, 8, 7, 3, 9, 6, 5, 10, 4, 3, 6, 7, 1, 7, 4, 10, 8, 1)), 1)){quit('no', 1)}\n    if(!identical(candidate(c(3, 2, 8, 2)), 2)){quit('no', 1)}\n    if(!identical(candidate(c(6, 7, 1, 8, 8, 10, 5, 8, 5, 3, 10)), 1)){quit('no', 1)}\n    if(!identical(candidate(c(8, 8, 3, 6, 5, 6, 4)), -1)){quit('no', 1)}\n    if(!identical(candidate(c(6, 9, 6, 7, 1, 4, 7, 1, 8, 8, 9, 8, 10, 10, 8, 4, 10, 4, 10, 1, 2, 9, 5, 7, 9)), 1)){quit('no', 1)}\n    if(!identical(candidate(c(1, 9, 10, 1, 3)), 1)){quit('no', 1)}\n    if(!identical(candidate(c(6, 9, 7, 5, 8, 7, 5, 3, 7, 5, 10, 10, 3, 6, 10, 2, 8, 6, 5, 4, 9, 5, 3, 10)), 5)){quit('no', 1)}\n    if(!identical(candidate(c(1)), 1)){quit('no', 1)}\n    if(!identical(candidate(c(8, 8, 10, 6, 4, 3, 5, 8, 2, 4, 2, 8, 4, 6, 10, 4, 2, 1, 10, 2, 1, 1, 5)), 4)){quit('no', 1)}\n    if(!identical(candidate(c(2, 10, 4, 8, 2, 10, 5, 1, 2, 9, 5, 5, 6, 3, 8, 6, 4, 10)), 2)){quit('no', 1)}\n    if(!identical(candidate(c(1, 6, 10, 1, 6, 9, 10, 8, 6, 8, 7, 3)), 1)){quit('no', 1)}\n    if(!identical(candidate(c(9, 2, 4, 1, 5, 1, 5, 2, 5, 7, 7, 7, 3, 10, 1, 5, 4, 2, 8, 4, 1, 9, 10, 7, 10, 2, 8, 10, 9, 4)), 4)){quit('no', 1)}\n    if(!identical(candidate(c(2, 6, 4, 2, 8, 7, 5, 6, 4, 10, 4, 6, 3, 7, 8, 8, 3, 1, 4, 2, 2, 10, 7)), 4)){quit('no', 1)}\n    if(!identical(candidate(c(9, 8, 6, 10, 2, 6, 10, 2, 7, 8, 10, 3, 8, 2, 6, 2, 3, 1)), 2)){quit('no', 1)}\n    if(!identical(candidate(c(5, 5, 3, 9, 5, 6, 3, 2, 8, 5, 6, 10, 10, 6, 8, 4, 10, 7, 7, 10, 8)), -1)){quit('no', 1)}\n    if(!identical(candidate(c(10)), -1)){quit('no', 1)}\n    if(!identical(candidate(c(9, 7, 7, 2, 4, 7, 2, 10, 9, 7, 5, 7, 2)), 2)){quit('no', 1)}\n    if(!identical(candidate(c(5, 4, 10, 2, 1, 1, 10, 3, 6, 1, 8)), 1)){quit('no', 1)}\n    if(!identical(candidate(c(7, 9, 9, 9, 3, 4, 1, 5, 9, 1, 2, 1, 1, 10, 7, 5, 6, 7, 6, 7, 7, 6)), 1)){quit('no', 1)}\n    if(!identical(candidate(c(3, 10, 10, 9, 2)), -1)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_82_prime_length",
    "language": "r",
    "prompt": "# Write a function that takes a string and returns TRUE if the string\n# length is a prime number or FALSE otherwise\n# Examples\n# >>> prime_length('Hello')\n# TRUE\n# >>> prime_length('abcdcba')\n# TRUE\n# >>> prime_length('kittens')\n# TRUE\n# >>> prime_length('orange')\n# FALSE\nprime_length <- function(string) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_82_prime_length.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- prime_length\n    if(!identical(candidate('Hello'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('abcdcba'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('kittens'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('orange'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('wow'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('world'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('MadaM'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('Wow'), TRUE)){quit('no', 1)}\n    if(!identical(candidate(''), FALSE)){quit('no', 1)}\n    if(!identical(candidate('HI'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('go'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('gogo'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('aaaaaaaaaaaaaaa'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('Madam'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('M'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('0'), FALSE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_58_common",
    "language": "r",
    "prompt": "# Return sorted unique common elements for two lists.\n# >>> common(c(1, 4, 3, 34, 653, 2, 5), c(5, 7, 1, 5, 9, 653, 121))\n# list(1, 5, 653)\n# >>> common(c(5, 3, 2, 8), c(3, 2))\n# list(2, 3)\ncommon <- function(l1, l2) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_58_common.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- common\n    if(!identical(candidate(c(1, 4, 3, 34, 653, 2, 5), c(5, 7, 1, 5, 9, 653, 121)), list(1, 5, 653))){quit('no', 1)}\n    if(!identical(candidate(c(5, 3, 2, 8), c(3, 2)), list(2, 3))){quit('no', 1)}\n    if(!identical(candidate(c(4, 3, 2, 8), c(3, 2, 4)), list(2, 3, 4))){quit('no', 1)}\n    if(!identical(candidate(c(4, 3, 2, 8), c()), list())){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_139_special_factorial",
    "language": "r",
    "prompt": "# The Brazilian factorial is defined as:\n# brazilian_factorial(n) = n! * (n-1)! * (n-2)! * ... * 1!\n# where n > 0\n# For example:\n# >>> special_factorial(4)\n# 288\n# The function will receive an integer as input and should return the special\n# factorial of this integer.\nspecial_factorial <- function(n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_139_special_factorial.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- special_factorial\n    if(!identical(candidate(4), 288)){quit('no', 1)}\n    if(!identical(candidate(5), 34560)){quit('no', 1)}\n    if(!identical(candidate(7), 125411328000)){quit('no', 1)}\n    if(!identical(candidate(1), 1)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_110_exchange",
    "language": "r",
    "prompt": "# In this problem, you will implement a function that takes two lists of numbers,\n# and determines whether it is possible to perform an exchange of elements\n# between them to make lst1 a list of only even numbers.\n# There is no limit on the number of exchanged elements between lst1 and lst2.\n# If it is possible to exchange elements between the lst1 and lst2 to make\n# all the elements of lst1 to be even, return \"YES\".\n# Otherwise, return \"NO\".\n# For example:\n# >>> exchange(c(1, 2, 3, 4), c(1, 2, 3, 4))\n# 'YES'\n# >>> exchange(c(1, 2, 3, 4), c(1, 5, 3, 4))\n# 'NO'\n# It is assumed that the input lists will be non-empty.\nexchange <- function(lst1, lst2) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_110_exchange.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- exchange\n    if(!identical(candidate(c(1, 2, 3, 4), c(1, 2, 3, 4)), 'YES')){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3, 4), c(1, 5, 3, 4)), 'NO')){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3, 4), c(2, 1, 4, 3)), 'YES')){quit('no', 1)}\n    if(!identical(candidate(c(5, 7, 3), c(2, 6, 4)), 'YES')){quit('no', 1)}\n    if(!identical(candidate(c(5, 7, 3), c(2, 6, 3)), 'NO')){quit('no', 1)}\n    if(!identical(candidate(c(3, 2, 6, 1, 8, 9), c(3, 5, 5, 1, 1, 1)), 'NO')){quit('no', 1)}\n    if(!identical(candidate(c(100, 200), c(200, 200)), 'YES')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_122_add_elements",
    "language": "r",
    "prompt": "# Given a non-empty vector of integers arr and an integer k, return\n# the sum of the elements with at most two digits from the first k elements of arr.\n# Example:\n# >>> add_elements(c(111, 21, 3, 4000, 5, 6, 7, 8, 9), 4)\n# 24\n# Constraints:\n# 1. 1 <= len(arr) <= 100\n# 2. 1 <= k <= len(arr)\nadd_elements <- function(arr, k) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_122_add_elements.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- add_elements\n    if(!identical(candidate(c(1, -2, -3, 41, 57, 76, 87, 88, 99), 3), -4)){quit('no', 1)}\n    if(!identical(candidate(c(111, 121, 3, 4000, 5, 6), 2), 0)){quit('no', 1)}\n    if(!identical(candidate(c(11, 21, 3, 90, 5, 6, 7, 8, 9), 4), 125)){quit('no', 1)}\n    if(!identical(candidate(c(111, 21, 3, 4000, 5, 6, 7, 8, 9), 4), 24)){quit('no', 1)}\n    if(!identical(candidate(c(1), 1), 1)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_150_x_or_y",
    "language": "r",
    "prompt": "# A simple program which should return the value of x if n is \n# a prime number and should return the value of y otherwise.\n# Examples:\n# >>> x_or_y(7, 34, 12)\n# 34\n# >>> x_or_y(15, 8, 5)\n# 5\nx_or_y <- function(n, x, y) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_150_x_or_y.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- x_or_y\n    if(!identical(candidate(7, 34, 12), 34)){quit('no', 1)}\n    if(!identical(candidate(15, 8, 5), 5)){quit('no', 1)}\n    if(!identical(candidate(3, 33, 5212), 33)){quit('no', 1)}\n    if(!identical(candidate(1259, 3, 52), 3)){quit('no', 1)}\n    if(!identical(candidate(7919, -1, 12), -1)){quit('no', 1)}\n    if(!identical(candidate(3609, 1245, 583), 583)){quit('no', 1)}\n    if(!identical(candidate(91, 56, 129), 129)){quit('no', 1)}\n    if(!identical(candidate(6, 34, 1234), 1234)){quit('no', 1)}\n    if(!identical(candidate(1, 2, 0), 0)){quit('no', 1)}\n    if(!identical(candidate(2, 2, 0), 2)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_45_triangle_area",
    "language": "r",
    "prompt": "# Given length of a side and high return area for a triangle.\n# >>> triangle_area(5, 3)\n# 7.5\ntriangle_area <- function(a, h) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_45_triangle_area.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- triangle_area\n    if(!identical(candidate(5, 3), 7.5)){quit('no', 1)}\n    if(!identical(candidate(2, 2), 2.0)){quit('no', 1)}\n    if(!identical(candidate(10, 8), 40.0)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_130_tri",
    "language": "r",
    "prompt": "# Everyone knows Fibonacci sequence, it was studied deeply by mathematicians in \n# the last couple centuries. However, what people don't know is Tribonacci sequence.\n# Tribonacci sequence is defined by the recurrence:\n# tri(1) = 3\n# tri(n) = 1 + n / 2, if n is even.\n# tri(n) =  tri(n - 1) + tri(n - 2) + tri(n + 1), if n is odd.\n# For example:\n# tri(2) = 1 + (2 / 2) = 2\n# tri(4) = 3\n# tri(3) = tri(2) + tri(1) + tri(4)\n# = 2 + 3 + 3 = 8 \n# You are given a non-negative integer number n, you have to a return a list of the \n# first n + 1 numbers of the Tribonacci sequence.\n# Examples:\n# >>> tri(3)\n# list(1, 3, 2, 8)\ntri <- function(n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_130_tri.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- tri\n    if(!identical(candidate(3), list(1, 3, 2, 8))){quit('no', 1)}\n    if(!identical(candidate(4), list(1, 3, 2, 8, 3))){quit('no', 1)}\n    if(!identical(candidate(5), list(1, 3, 2, 8, 3, 15))){quit('no', 1)}\n    if(!identical(candidate(6), list(1, 3, 2, 8, 3, 15, 4))){quit('no', 1)}\n    if(!identical(candidate(7), list(1, 3, 2, 8, 3, 15, 4, 24))){quit('no', 1)}\n    if(!identical(candidate(8), list(1, 3, 2, 8, 3, 15, 4, 24, 5))){quit('no', 1)}\n    if(!identical(candidate(9), list(1, 3, 2, 8, 3, 15, 4, 24, 5, 35))){quit('no', 1)}\n    if(!identical(candidate(20), list(1, 3, 2, 8, 3, 15, 4, 24, 5, 35, 6, 48, 7, 63, 8, 80, 9, 99, 10, 120, 11))){quit('no', 1)}\n    if(!identical(candidate(0), list(1))){quit('no', 1)}\n    if(!identical(candidate(1), list(1, 3))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_119_match_parens",
    "language": "r",
    "prompt": "# You are given a list of two strings, both strings consist of open\n# parentheses '(' or close parentheses ')' only.\n# Your job is to check if it is possible to concatenate the two strings in\n# some order, that the resulting string will be good.\n# A string S is considered to be good if and only if all parentheses in S\n# are balanced. For example: the string '(())()' is good, while the string\n# '())' is not.\n# Return 'Yes' if there's a way to make a good string, and return 'No' otherwise.\n# Examples:\n# >>> match_parens(c('()(', ')'))\n# 'Yes'\n# >>> match_parens(c(')', ')'))\n# 'No'\nmatch_parens <- function(lst) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_119_match_parens.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- match_parens\n    if(!identical(candidate(c('()(', ')')), 'Yes')){quit('no', 1)}\n    if(!identical(candidate(c(')', ')')), 'No')){quit('no', 1)}\n    if(!identical(candidate(c('(()(())', '())())')), 'No')){quit('no', 1)}\n    if(!identical(candidate(c(')())', '(()()(')), 'Yes')){quit('no', 1)}\n    if(!identical(candidate(c('(())))', '(()())((')), 'Yes')){quit('no', 1)}\n    if(!identical(candidate(c('()', '())')), 'No')){quit('no', 1)}\n    if(!identical(candidate(c('(()(', '()))()')), 'Yes')){quit('no', 1)}\n    if(!identical(candidate(c('((((', '((())')), 'No')){quit('no', 1)}\n    if(!identical(candidate(c(')(()', '(()(')), 'No')){quit('no', 1)}\n    if(!identical(candidate(c(')(', ')(')), 'No')){quit('no', 1)}\n    if(!identical(candidate(c('(', ')')), 'Yes')){quit('no', 1)}\n    if(!identical(candidate(c(')', '(')), 'Yes')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_26_remove_duplicates",
    "language": "r",
    "prompt": "# From a list of integers, remove all elements that occur more than once.\n# Keep order of elements left the same as in the input.\n# >>> remove_duplicates(c(1, 2, 3, 2, 4))\n# list(1, 3, 4)\nremove_duplicates <- function(numbers) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_26_remove_duplicates.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- remove_duplicates\n    if(!identical(candidate(c()), list())){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3, 4)), list(1, 2, 3, 4))){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3, 2, 4, 3, 5)), list(1, 4, 5))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_13_greatest_common_divisor",
    "language": "r",
    "prompt": "# Return a greatest common divisor of two integers a and b\n# >>> greatest_common_divisor(3, 5)\n# 1\n# >>> greatest_common_divisor(25, 15)\n# 5\ngreatest_common_divisor <- function(a, b) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_13_greatest_common_divisor.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- greatest_common_divisor\n    if(!identical(candidate(3, 7), 1)){quit('no', 1)}\n    if(!identical(candidate(10, 15), 5)){quit('no', 1)}\n    if(!identical(candidate(49, 14), 7)){quit('no', 1)}\n    if(!identical(candidate(144, 60), 12)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_48_is_palindrome",
    "language": "r",
    "prompt": "# Checks if given string is a palindrome\n# >>> is_palindrome('')\n# TRUE\n# >>> is_palindrome('aba')\n# TRUE\n# >>> is_palindrome('aaaaa')\n# TRUE\n# >>> is_palindrome('zbcd')\n# FALSE\nis_palindrome <- function(text) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_48_is_palindrome.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- is_palindrome\n    if(!identical(candidate(''), TRUE)){quit('no', 1)}\n    if(!identical(candidate('aba'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('aaaaa'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('zbcd'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('xywyx'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('xywyz'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('xywzx'), FALSE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_62_derivative",
    "language": "r",
    "prompt": "# xs represent coefficients of a polynomial.\n# xs[0] + xs[1] * x + xs[2] * x^2 + ....\n# Return derivative of this polynomial in the same form.\n# >>> derivative(c(3, 1, 2, 4, 5))\n# list(1, 4, 12, 20)\n# >>> derivative(c(1, 2, 3))\n# list(2, 6)\nderivative <- function(xs) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_62_derivative.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- derivative\n    if(!identical(candidate(c(3, 1, 2, 4, 5)), list(1, 4, 12, 20))){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3)), list(2, 6))){quit('no', 1)}\n    if(!identical(candidate(c(3, 2, 1)), list(2, 2))){quit('no', 1)}\n    if(!identical(candidate(c(3, 2, 1, 0, 4)), list(2, 2, 0, 16))){quit('no', 1)}\n    if(!identical(candidate(c(1)), list())){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_67_fruit_distribution",
    "language": "r",
    "prompt": "# In this task, you will be given a string that represents a number of apples and oranges \n# that are distributed in a basket of fruit this basket contains \n# apples, oranges, and mango fruits. Given the string that represents the total number of \n# the oranges and apples and an integer that represent the total number of the fruits \n# in the basket return the number of the mango fruits in the basket.\n# for examble:\n# >>> fruit_distribution('5 apples and 6 oranges', 19)\n# 8\n# >>> fruit_distribution('0 apples and 1 oranges', 3)\n# 2\n# >>> fruit_distribution('2 apples and 3 oranges', 100)\n# 95\n# >>> fruit_distribution('100 apples and 1 oranges', 120)\n# 19\nfruit_distribution <- function(s, n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_67_fruit_distribution.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- fruit_distribution\n    if(!identical(candidate('5 apples and 6 oranges', 19), 8)){quit('no', 1)}\n    if(!identical(candidate('5 apples and 6 oranges', 21), 10)){quit('no', 1)}\n    if(!identical(candidate('0 apples and 1 oranges', 3), 2)){quit('no', 1)}\n    if(!identical(candidate('1 apples and 0 oranges', 3), 2)){quit('no', 1)}\n    if(!identical(candidate('2 apples and 3 oranges', 100), 95)){quit('no', 1)}\n    if(!identical(candidate('2 apples and 3 oranges', 5), 0)){quit('no', 1)}\n    if(!identical(candidate('1 apples and 100 oranges', 120), 19)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_77_iscube",
    "language": "r",
    "prompt": "# Write a function that takes an integer a and returns TRUE \n# if this ingeger is a cube of some integer number.\n# Note: you may assume the input is always valid.\n# Examples:\n# >>> iscube(1)\n# TRUE\n# >>> iscube(2)\n# FALSE\n# >>> iscube(-1)\n# TRUE\n# >>> iscube(64)\n# TRUE\n# >>> iscube(0)\n# TRUE\n# >>> iscube(180)\n# FALSE\niscube <- function(a) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_77_iscube.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- iscube\n    if(!identical(candidate(1), TRUE)){quit('no', 1)}\n    if(!identical(candidate(2), FALSE)){quit('no', 1)}\n    if(!identical(candidate(-1), TRUE)){quit('no', 1)}\n    if(!identical(candidate(64), TRUE)){quit('no', 1)}\n    if(!identical(candidate(180), FALSE)){quit('no', 1)}\n    if(!identical(candidate(1000), TRUE)){quit('no', 1)}\n    if(!identical(candidate(0), TRUE)){quit('no', 1)}\n    if(!identical(candidate(1729), FALSE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_116_sort_array",
    "language": "r",
    "prompt": "# In this Kata, you have to sort a vector of non-negative integers according to\n# number of ones in their binary representation in ascending order.\n# For similar number of ones, sort based on decimal value.\n# It must be implemented like this:\n# >>> sort_array(c(1, 5, 2, 3, 4))\n# list(1, 2, 3, 4, 5)\n# >>> sort_array(c(-2, -3, -4, -5, -6))\n# list(-6, -5, -4, -3, -2)\n# >>> sort_array(c(1, 0, 2, 3, 4))\n# list(0, 1, 2, 3, 4)\nsort_array <- function(arr) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_116_sort_array.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- sort_array\n    if(!identical(candidate(c(1, 5, 2, 3, 4)), list(1, 2, 4, 3, 5))){quit('no', 1)}\n    if(!identical(candidate(c(-2, -3, -4, -5, -6)), list(-4, -2, -6, -5, -3))){quit('no', 1)}\n    if(!identical(candidate(c(1, 0, 2, 3, 4)), list(0, 1, 2, 4, 3))){quit('no', 1)}\n    if(!identical(candidate(c()), list())){quit('no', 1)}\n    if(!identical(candidate(c(2, 5, 77, 4, 5, 3, 5, 7, 2, 3, 4)), list(2, 2, 4, 4, 3, 3, 5, 5, 5, 7, 77))){quit('no', 1)}\n    if(!identical(candidate(c(3, 6, 44, 12, 32, 5)), list(32, 3, 5, 6, 12, 44))){quit('no', 1)}\n    if(!identical(candidate(c(2, 4, 8, 16, 32)), list(2, 4, 8, 16, 32))){quit('no', 1)}\n    if(!identical(candidate(c(2, 4, 8, 16, 32)), list(2, 4, 8, 16, 32))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_113_odd_count",
    "language": "r",
    "prompt": "# Given a list of strings, where each string consists of only digits, return a list.\n# Each element i of the output should be \"the number of odd elements in the\n# string i of the input.\" where all the i's should be replaced by the number\n# of odd digits in the i'th string of the input.\n# >>> odd_count(c('1234567'))\n# list('the number of odd elements 4n the str4ng 4 of the 4nput.')\n# >>> odd_count(c('3', '11111111'))\n# list('the number of odd elements 1n the str1ng 1 of the 1nput.', 'the number of odd elements 8n the str8ng 8 of the 8nput.')\nodd_count <- function(lst) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_113_odd_count.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- odd_count\n    if(!identical(candidate(c('1234567')), list('the number of odd elements 4n the str4ng 4 of the 4nput.'))){quit('no', 1)}\n    if(!identical(candidate(c('3', '11111111')), list('the number of odd elements 1n the str1ng 1 of the 1nput.', 'the number of odd elements 8n the str8ng 8 of the 8nput.'))){quit('no', 1)}\n    if(!identical(candidate(c('271', '137', '314')), list('the number of odd elements 2n the str2ng 2 of the 2nput.', 'the number of odd elements 3n the str3ng 3 of the 3nput.', 'the number of odd elements 2n the str2ng 2 of the 2nput.'))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_61_correct_bracketing",
    "language": "r",
    "prompt": "# brackets is a string of \"(\" and \")\".\n# return TRUE if every opening bracket has a corresponding closing bracket.\n# >>> correct_bracketing('(')\n# FALSE\n# >>> correct_bracketing('()')\n# TRUE\n# >>> correct_bracketing('(()())')\n# TRUE\n# >>> correct_bracketing(')(()')\n# FALSE\ncorrect_bracketing <- function(brackets) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_61_correct_bracketing.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- correct_bracketing\n    if(!identical(candidate('()'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('(()())'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('()()(()())()'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('()()((()()())())(()()(()))'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('((()())))'), FALSE)){quit('no', 1)}\n    if(!identical(candidate(')(()'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('('), FALSE)){quit('no', 1)}\n    if(!identical(candidate('(((('), FALSE)){quit('no', 1)}\n    if(!identical(candidate(')'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('(()'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('()()(()())())(()'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('()()(()())()))()'), FALSE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_66_digitSum",
    "language": "r",
    "prompt": "# Task\n# Write a function that takes a string as input and returns the sum of the upper characters only'\n# ASCII codes.\n# Examples:\n# >>> digitSum('')\n# 0\n# >>> digitSum('abAB')\n# 131\n# >>> digitSum('abcCd')\n# 67\n# >>> digitSum('helloE')\n# 69\n# >>> digitSum('woArBld')\n# 131\n# >>> digitSum('aAaaaXa')\n# 153\ndigitSum <- function(s) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_66_digitSum.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- digitSum\n    if(!identical(candidate(''), 0)){quit('no', 1)}\n    if(!identical(candidate('abAB'), 131)){quit('no', 1)}\n    if(!identical(candidate('abcCd'), 67)){quit('no', 1)}\n    if(!identical(candidate('helloE'), 69)){quit('no', 1)}\n    if(!identical(candidate('woArBld'), 131)){quit('no', 1)}\n    if(!identical(candidate('aAaaaXa'), 153)){quit('no', 1)}\n    if(!identical(candidate(' How are yOu?'), 151)){quit('no', 1)}\n    if(!identical(candidate('You arE Very Smart'), 327)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_149_sorted_list_sum",
    "language": "r",
    "prompt": "# Write a function that accepts a list of strings as a parameter,\n# deletes the strings that have odd lengths from it,\n# and returns the resulted list with a sorted order,\n# The list is always a list of strings and never a vector of numbers,\n# and it may contain duplicates.\n# The order of the list should be ascending by length of each word, and you\n# should return the list sorted by that rule.\n# If two words have the same length, sort the list alphabetically.\n# The function should return a list of strings in sorted order.\n# You may assume that all words will have the same length.\n# For example:\n# >>> list_sort(c('aa', 'a', 'aaa'))\n# list('aa')\n# >>> list_sort(c('ab', 'a', 'aaa', 'cd'))\n# list('ab', 'cd')\nsorted_list_sum <- function(lst) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_149_sorted_list_sum.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- sorted_list_sum\n    if(!identical(candidate(c('aa', 'a', 'aaa')), list('aa'))){quit('no', 1)}\n    if(!identical(candidate(c('school', 'AI', 'asdf', 'b')), list('AI', 'asdf', 'school'))){quit('no', 1)}\n    if(!identical(candidate(c('d', 'b', 'c', 'a')), list())){quit('no', 1)}\n    if(!identical(candidate(c('d', 'dcba', 'abcd', 'a')), list('abcd', 'dcba'))){quit('no', 1)}\n    if(!identical(candidate(c('AI', 'ai', 'au')), list('AI', 'ai', 'au'))){quit('no', 1)}\n    if(!identical(candidate(c('a', 'b', 'b', 'c', 'c', 'a')), list())){quit('no', 1)}\n    if(!identical(candidate(c('aaaa', 'bbbb', 'dd', 'cc')), list('cc', 'dd', 'aaaa', 'bbbb'))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_128_prod_signs",
    "language": "r",
    "prompt": "# You are given a vector arr of integers and you need to return\n# sum of magnitudes of integers multiplied by product of all signs\n# of each number in the vector, represented by 1, -1 or 0.\n# Note: return NULL for empty arr.\n# Example:\n# >>> prod_signs(c(1, 2, 2, -4))\n# 9\n# >>> prod_signs(c(0, 1))\n# 0\n# >>> prod_signs(c())\n# NULL\nprod_signs <- function(arr) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_128_prod_signs.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- prod_signs\n    if(!identical(candidate(c(1, 2, 2, -4)), -9)){quit('no', 1)}\n    if(!identical(candidate(c(0, 1)), 0)){quit('no', 1)}\n    if(!identical(candidate(c(1, 1, 1, 2, 3, -1, 1)), -10)){quit('no', 1)}\n    if(!identical(candidate(c()), NULL)){quit('no', 1)}\n    if(!identical(candidate(c(2, 4, 1, 2, -1, -1, 9)), 20)){quit('no', 1)}\n    if(!identical(candidate(c(-1, 1, -1, 1)), 4)){quit('no', 1)}\n    if(!identical(candidate(c(-1, 1, 1, 1)), -4)){quit('no', 1)}\n    if(!identical(candidate(c(-1, 1, 1, 0)), 0)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_42_incr_list",
    "language": "r",
    "prompt": "# Return list with elements incremented by 1.\n# >>> incr_list(c(1, 2, 3))\n# list(2, 3, 4)\n# >>> incr_list(c(5, 3, 5, 2, 3, 3, 9, 0, 123))\n# list(6, 4, 6, 3, 4, 4, 10, 1, 124)\nincr_list <- function(l) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_42_incr_list.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- incr_list\n    if(!identical(candidate(c()), list())){quit('no', 1)}\n    if(!identical(candidate(c(3, 2, 1)), list(4, 3, 2))){quit('no', 1)}\n    if(!identical(candidate(c(5, 2, 5, 2, 3, 3, 9, 0, 123)), list(6, 3, 6, 3, 4, 4, 10, 1, 124))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_9_rolling_max",
    "language": "r",
    "prompt": "# From a given list of integers, generate a list of rolling maximum element found until given moment\n# in the sequence.\n# >>> rolling_max(c(1, 2, 3, 2, 3, 4, 2))\n# list(1, 2, 3, 3, 3, 4, 4)\nrolling_max <- function(numbers) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_9_rolling_max.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- rolling_max\n    if(!identical(candidate(c()), list())){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3, 4)), list(1, 2, 3, 4))){quit('no', 1)}\n    if(!identical(candidate(c(4, 3, 2, 1)), list(4, 4, 4, 4))){quit('no', 1)}\n    if(!identical(candidate(c(3, 2, 3, 100, 3)), list(3, 3, 3, 100, 100))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_1_separate_paren_groups",
    "language": "r",
    "prompt": "# Input to this function is a string containing multiple groups of nested parentheses. Your goal is to\n# separate those group into separate strings and return the list of those.\n# Separate groups are balanced (each open brace is properly closed) and not nested within each other\n# Ignore any spaces in the input string.\n# >>> separate_paren_groups('( ) (( )) (( )( ))')\n# list('()', '(())', '(()())')\nseparate_paren_groups <- function(paren_string) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_1_separate_paren_groups.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- separate_paren_groups\n    if(!identical(candidate('(()()) ((())) () ((())()())'), list('(()())', '((()))', '()', '((())()())'))){quit('no', 1)}\n    if(!identical(candidate('() (()) ((())) (((())))'), list('()', '(())', '((()))', '(((())))'))){quit('no', 1)}\n    if(!identical(candidate('(()(())((())))'), list('(()(())((())))'))){quit('no', 1)}\n    if(!identical(candidate('( ) (( )) (( )( ))'), list('()', '(())', '(()())'))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_101_words_string",
    "language": "r",
    "prompt": "# You will be given a string of words separated by commas or spaces. Your task is\n# to split the string into words and return a vector of the words.\n# For example:\n# >>> words_string('Hi, my name is John')\n# list('Hi', 'my', 'name', 'is', 'John')\n# >>> words_string('One, two, three, four, five, six')\n# list('One', 'two', 'three', 'four', 'five', 'six')\nwords_string <- function(s) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_101_words_string.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- words_string\n    if(!identical(candidate('Hi, my name is John'), list('Hi', 'my', 'name', 'is', 'John'))){quit('no', 1)}\n    if(!identical(candidate('One, two, three, four, five, six'), list('One', 'two', 'three', 'four', 'five', 'six'))){quit('no', 1)}\n    if(!identical(candidate('Hi, my name'), list('Hi', 'my', 'name'))){quit('no', 1)}\n    if(!identical(candidate('One,, two, three, four, five, six,'), list('One', 'two', 'three', 'four', 'five', 'six'))){quit('no', 1)}\n    if(!identical(candidate(''), list())){quit('no', 1)}\n    if(!identical(candidate('ahmed     , gamal'), list('ahmed', 'gamal'))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_137_compare_one",
    "language": "r",
    "prompt": "# Create a function that takes integers, floats, or strings representing\n# real numbers, and returns the larger variable in its given variable type.\n# Return NULL if the values are equal.\n# Note: If a real number is represented as a string, the floating point might be . or ,\n# >>> compare_one(1, 2.5)\n# 2.5\n# >>> compare_one(1, '2,3')\n# '2,3'\n# >>> compare_one('5,1', '6')\n# '6'\n# >>> compare_one('1', 1)\n# NULL\ncompare_one <- function(a, b) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_137_compare_one.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- compare_one\n    if(!identical(candidate(1, 2), 2)){quit('no', 1)}\n    if(!identical(candidate(1, 2.5), 2.5)){quit('no', 1)}\n    if(!identical(candidate(2, 3), 3)){quit('no', 1)}\n    if(!identical(candidate(5, 6), 6)){quit('no', 1)}\n    if(!identical(candidate(1, '2,3'), '2,3')){quit('no', 1)}\n    if(!identical(candidate('5,1', '6'), '6')){quit('no', 1)}\n    if(!identical(candidate('1', '2'), '2')){quit('no', 1)}\n    if(!identical(candidate('1', 1), NULL)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_22_filter_integers",
    "language": "r",
    "prompt": "# Filter given list of any rthon values only for integers\n# >>> filter_integers(list('a', 3.14, 5))\n# list(5)\n# >>> filter_integers(list(1, 2, 3, 'abc', list(), list()))\n# list(1, 2, 3)\nfilter_integers <- function(values) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_22_filter_integers.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- filter_integers\n    if(!identical(candidate(list()), list())){quit('no', 1)}\n    if(!identical(candidate(list(4, list(), list(), 23.2, 9, 'adasd')), list(4, 9))){quit('no', 1)}\n    if(!identical(candidate(list(3, 'c', 3, 3, 'a', 'b')), list(3, 3, 3))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_37_sort_even",
    "language": "r",
    "prompt": "# This function takes a list l and returns a list l' such that\n# l' is identical to l in the odd indicies, while its values at the even indicies are equal\n# to the values of the even indicies of l, but sorted.\n# >>> sort_even(c(1, 2, 3))\n# list(1, 2, 3)\n# >>> sort_even(c(5, 6, 3, 4))\n# list(3, 6, 5, 4)\nsort_even <- function(l) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_37_sort_even.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- sort_even\n    if(!identical(candidate(c(1, 2, 3)), list(1, 2, 3))){quit('no', 1)}\n    if(!identical(candidate(c(5, 3, -5, 2, -3, 3, 9, 0, 123, 1, -10)), list(-10, 3, -5, 2, -3, 3, 5, 0, 9, 1, 123))){quit('no', 1)}\n    if(!identical(candidate(c(5, 8, -12, 4, 23, 2, 3, 11, 12, -10)), list(-12, 8, 3, 4, 5, 2, 12, 11, 23, -10))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_152_compare",
    "language": "r",
    "prompt": "# I think we all remember that feeling when the result of some long-awaited\n# event is finally known. The feelings and thoughts you have at that moment are\n# definitely worth noting down and comparing.\n# Your task is to determine if a person correctly guessed the results of a number of matches.\n# You are given two vectors of scores and guesses of equal length, where each index shows a match. \n# Return a vector of the same length denoting how far off each guess was. If they have guessed correctly,\n# the value is 0, and if not, the value is the absolute difference between the guess and the score.\n# example:\n# >>> compare(c(1, 2, 3, 4, 5, 1), c(1, 2, 3, 4, 2, -2))\n# list(0, 0, 0, 0, 3, 3)\n# >>> compare(c(0, 5, 0, 0, 0, 4), c(4, 1, 1, 0, 0, -2))\n# list(4, 4, 1, 0, 0, 6)\ncompare <- function(game, guess) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_152_compare.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- compare\n    if(!identical(candidate(c(1, 2, 3, 4, 5, 1), c(1, 2, 3, 4, 2, -2)), list(0, 0, 0, 0, 3, 3))){quit('no', 1)}\n    if(!identical(candidate(c(0, 0, 0, 0, 0, 0), c(0, 0, 0, 0, 0, 0)), list(0, 0, 0, 0, 0, 0))){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3), c(-1, -2, -3)), list(2, 4, 6))){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3, 5), c(-1, 2, 3, 4)), list(2, 0, 0, 1))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_107_even_odd_palindrome",
    "language": "r",
    "prompt": "# Given a positive integer n, return a list that has the number of even and odd\n# integer palindromes that fall within the range(1, n), inclusive.\n# Example 1:\n# >>> even_odd_palindrome(3)\n# list(1, 2)\n# Explanation:\n# Integer palindrome are 1, 2, 3. one of them is even, and two of them are odd.\n# Example 2:\n# >>> even_odd_palindrome(12)\n# list(4, 6)\n# Explanation:\n# Integer palindrome are 1, 2, 3, 4, 5, 6, 7, 8, 9, 11. four of them are even, and 6 of them are odd.\n# Note:\n# 1. 1 <= n <= 10^3\n# 2. returned list has the number of even and odd integer palindromes respectively.\neven_odd_palindrome <- function(n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_107_even_odd_palindrome.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- even_odd_palindrome\n    if(!identical(candidate(123), list(8, 13))){quit('no', 1)}\n    if(!identical(candidate(12), list(4, 6))){quit('no', 1)}\n    if(!identical(candidate(3), list(1, 2))){quit('no', 1)}\n    if(!identical(candidate(63), list(6, 8))){quit('no', 1)}\n    if(!identical(candidate(25), list(5, 6))){quit('no', 1)}\n    if(!identical(candidate(19), list(4, 6))){quit('no', 1)}\n    if(!identical(candidate(9), list(4, 5))){quit('no', 1)}\n    if(!identical(candidate(1), list(0, 1))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_46_fib4",
    "language": "r",
    "prompt": "# The Fib4 number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:\n# fib4(0) -> 0\n# fib4(1) -> 0\n# fib4(2) -> 2\n# fib4(3) -> 0\n# fib4(n) -> fib4(n-1) + fib4(n-2) + fib4(n-3) + fib4(n-4).\n# Please write a function to efficiently compute the n-th element of the fib4 number sequence.  Do not use recursion.\n# >>> fib4(5)\n# 4\n# >>> fib4(6)\n# 8\n# >>> fib4(7)\n# 14\nfib4 <- function(n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_46_fib4.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- fib4\n    if(!identical(candidate(5), 4)){quit('no', 1)}\n    if(!identical(candidate(8), 28)){quit('no', 1)}\n    if(!identical(candidate(10), 104)){quit('no', 1)}\n    if(!identical(candidate(12), 386)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_163_generate_integers",
    "language": "r",
    "prompt": "# Given two positive integers a and b, return the even digits between a\n# and b, in ascending order.\n# For example:\n# >>> generate_integers(2, 8)\n# list(2, 4, 6, 8)\n# >>> generate_integers(8, 2)\n# list(2, 4, 6, 8)\n# >>> generate_integers(10, 14)\n# list()\ngenerate_integers <- function(a, b) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_163_generate_integers.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- generate_integers\n    if(!identical(candidate(2, 10), list(2, 4, 6, 8))){quit('no', 1)}\n    if(!identical(candidate(10, 2), list(2, 4, 6, 8))){quit('no', 1)}\n    if(!identical(candidate(132, 2), list(2, 4, 6, 8))){quit('no', 1)}\n    if(!identical(candidate(17, 89), list())){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_4_mean_absolute_deviation",
    "language": "r",
    "prompt": "# For a given list of input numbers, calculate Mean Absolute Deviation\n# around the mean of this dataset.\n# Mean Absolute Deviation is the average absolute difference between each\n# element and a centerpoint (mean in this case):\n# MAD = average | x - x_mean |\n# >>> mean_absolute_deviation(c(1.0, 2.0, 3.0, 4.0))\n# 1.0\nmean_absolute_deviation <- function(numbers) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_4_mean_absolute_deviation.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- mean_absolute_deviation\n    if(!identical(candidate(c(1.0, 2.0)), 0.5)){quit('no', 1)}\n    if(!identical(candidate(c(1.0, 2.0, 3.0, 4.0)), 1.0)){quit('no', 1)}\n    if(!identical(candidate(c(1.0, 2.0, 3.0, 4.0, 5.0)), 1.2)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_89_encrypt",
    "language": "r",
    "prompt": "# Create a function encrypt that takes a string as an argument and\n# returns a string encrypted with the alphabet being rotated. \n# The alphabet should be rotated in a manner such that the letters \n# shift down by two multiplied to two places.\n# For example:\n# >>> encrypt('hi')\n# 'lm'\n# >>> encrypt('asdfghjkl')\n# 'ewhjklnop'\n# >>> encrypt('gf')\n# 'kj'\n# >>> encrypt('et')\n# 'ix'\nencrypt <- function(s) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_89_encrypt.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- encrypt\n    if(!identical(candidate('hi'), 'lm')){quit('no', 1)}\n    if(!identical(candidate('asdfghjkl'), 'ewhjklnop')){quit('no', 1)}\n    if(!identical(candidate('gf'), 'kj')){quit('no', 1)}\n    if(!identical(candidate('et'), 'ix')){quit('no', 1)}\n    if(!identical(candidate('faewfawefaewg'), 'jeiajeaijeiak')){quit('no', 1)}\n    if(!identical(candidate('hellomyfriend'), 'lippsqcjvmirh')){quit('no', 1)}\n    if(!identical(candidate('dxzdlmnilfuhmilufhlihufnmlimnufhlimnufhfucufh'), 'hbdhpqrmpjylqmpyjlpmlyjrqpmqryjlpmqryjljygyjl')){quit('no', 1)}\n    if(!identical(candidate('a'), 'e')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_123_get_odd_collatz",
    "language": "r",
    "prompt": "# Given a positive integer n, return a sorted list that has the odd numbers in collatz sequence.\n# The Collatz conjecture is a conjecture in mathematics that concerns a sequence defined\n# as follows: start with any positive integer n. Then each term is obtained from the \n# previous term as follows: if the previous term is even, the next term is one half of \n# the previous term. If the previous term is odd, the next term is 3 times the previous\n# term plus 1. The conjecture is that no matter what value of n, the sequence will always reach 1.\n# Note: \n# 1. Collatz(1) is [1].\n# 2. returned list sorted in increasing order.\n# For example:\n# get_odd_collatz(5) returns [1, 5] # The collatz sequence for 5 is [5, 16, 8, 4, 2, 1], so the odd numbers are only 1, and 5.\n# >>> get_odd_collatz(5)\n# list(1, 5)\nget_odd_collatz <- function(n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_123_get_odd_collatz.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- get_odd_collatz\n    if(!identical(candidate(14), list(1, 5, 7, 11, 13, 17))){quit('no', 1)}\n    if(!identical(candidate(5), list(1, 5))){quit('no', 1)}\n    if(!identical(candidate(12), list(1, 3, 5))){quit('no', 1)}\n    if(!identical(candidate(1), list(1))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_18_how_many_times",
    "language": "r",
    "prompt": "# Find how many times a given substring can be found in the original string. Count overlaping cases.\n# >>> how_many_times('', 'a')\n# 0\n# >>> how_many_times('aaa', 'a')\n# 3\n# >>> how_many_times('aaaa', 'aa')\n# 3\nhow_many_times <- function(string, substring) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_18_how_many_times.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- how_many_times\n    if(!identical(candidate('', 'x'), 0)){quit('no', 1)}\n    if(!identical(candidate('xyxyxyx', 'x'), 4)){quit('no', 1)}\n    if(!identical(candidate('cacacacac', 'cac'), 4)){quit('no', 1)}\n    if(!identical(candidate('john doe', 'john'), 1)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_109_move_one_ball",
    "language": "r",
    "prompt": "# We have a vector 'arr' of N integers arr[1], arr[2], ..., arr[N].The\n# numbers in the vector will be randomly ordered. Your task is to determine if\n# it is possible to get a vector sorted in non-decreasing order by performing \n# the following operation on the given vector:\n# You are allowed to perform right shift operation any number of times.\n# One right shift operation means shifting all elements of the vector by one\n# position in the right direction. The last element of the vector will be moved to\n# the starting position in the vector i.e. 0th index. \n# If it is possible to obtain the sorted vector by performing the above operation\n# then return TRUE else return FALSE.\n# If the given vector is empty then return TRUE.\n# Note: The given list is guaranteed to have unique elements.\n# For Example:\n# >>> move_one_ball(c(3, 4, 5, 1, 2))\n# TRUE\n# Explanation: By performin 2 right shift operations, non-decreasing order can\n# be achieved for the given vector.\n# >>> move_one_ball(c(3, 5, 4, 1, 2))\n# FALSE\n# Explanation:It is not possible to get non-decreasing order for the given\n# vector by performing any number of right shift operations.\nmove_one_ball <- function(arr) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_109_move_one_ball.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- move_one_ball\n    if(!identical(candidate(c(3, 4, 5, 1, 2)), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(3, 5, 10, 1, 2)), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(4, 3, 1, 2)), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(3, 5, 4, 1, 2)), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c()), TRUE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_145_order_by_points",
    "language": "r",
    "prompt": "# Write a function which sorts the given list of integers\n# in ascending order according to the sum of their digits.\n# Note: if there are several items with similar sum of their digits,\n# order them based on their index in original list.\n# For example:\n# >>> order_by_points(c(1, 11, -1, -11, -12))\n# list(-1, -11, 1, -12, 11)\n# >>> order_by_points(c())\n# list()\norder_by_points <- function(nums) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_145_order_by_points.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- order_by_points\n    if(!identical(candidate(c(1, 11, -1, -11, -12)), list(-1, -11, 1, -12, 11))){quit('no', 1)}\n    if(!identical(candidate(c(1234, 423, 463, 145, 2, 423, 423, 53, 6, 37, 3457, 3, 56, 0, 46)), list(0, 2, 3, 6, 53, 423, 423, 423, 1234, 145, 37, 46, 56, 463, 3457))){quit('no', 1)}\n    if(!identical(candidate(c()), list())){quit('no', 1)}\n    if(!identical(candidate(c(1, -11, -32, 43, 54, -98, 2, -3)), list(-3, -32, -98, -11, 1, 2, 43, 54))){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3, 4, 5, 6, 7, 8, 9, 10, 11)), list(1, 10, 2, 11, 3, 4, 5, 6, 7, 8, 9))){quit('no', 1)}\n    if(!identical(candidate(c(0, 6, 6, -76, -21, 23, 4)), list(-76, -21, 0, 4, 23, 6, 6))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_25_factorize",
    "language": "r",
    "prompt": "# Return list of prime factors of given integer in the order from smallest to largest.\n# Each of the factors should be listed number of times corresponding to how many times it appeares in factorization.\n# Input number should be equal to the product of all factors\n# >>> factorize(8)\n# list(2, 2, 2)\n# >>> factorize(25)\n# list(5, 5)\n# >>> factorize(70)\n# list(2, 5, 7)\nfactorize <- function(n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_25_factorize.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- factorize\n    if(!identical(candidate(2), list(2))){quit('no', 1)}\n    if(!identical(candidate(4), list(2, 2))){quit('no', 1)}\n    if(!identical(candidate(8), list(2, 2, 2))){quit('no', 1)}\n    if(!identical(candidate(57), list(3, 19))){quit('no', 1)}\n    if(!identical(candidate(3249), list(3, 3, 19, 19))){quit('no', 1)}\n    if(!identical(candidate(185193), list(3, 3, 3, 19, 19, 19))){quit('no', 1)}\n    if(!identical(candidate(20577), list(3, 19, 19, 19))){quit('no', 1)}\n    if(!identical(candidate(18), list(2, 3, 3))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_52_below_threshold",
    "language": "r",
    "prompt": "# Return TRUE if all numbers in the list l are below threshold t.\n# >>> below_threshold(c(1, 2, 4, 10), 100)\n# TRUE\n# >>> below_threshold(c(1, 20, 4, 10), 5)\n# FALSE\nbelow_threshold <- function(l, t) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_52_below_threshold.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- below_threshold\n    if(!identical(candidate(c(1, 2, 4, 10), 100), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 20, 4, 10), 5), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 20, 4, 10), 21), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 20, 4, 10), 22), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 8, 4, 10), 11), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 8, 4, 10), 10), FALSE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_103_rounded_avg",
    "language": "r",
    "prompt": "# You are given two positive integers n and m, and your task is to compute the\n# average of the integers from n through m (including n and m). \n# Round the answer to the nearest integer and convert that to binary.\n# If n is greater than m, return -1.\n# Example:\n# >>> rounded_avg(1, 5)\n# '0b11'\n# >>> rounded_avg(7, 5)\n# -1\n# >>> rounded_avg(10, 20)\n# '0b1111'\n# >>> rounded_avg(20, 33)\n# '0b11010'\nrounded_avg <- function(n, m) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_103_rounded_avg.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- rounded_avg\n    if(!identical(candidate(1, 5), '0b11')){quit('no', 1)}\n    if(!identical(candidate(7, 13), '0b1010')){quit('no', 1)}\n    if(!identical(candidate(964, 977), '0b1111001010')){quit('no', 1)}\n    if(!identical(candidate(996, 997), '0b1111100100')){quit('no', 1)}\n    if(!identical(candidate(560, 851), '0b1011000010')){quit('no', 1)}\n    if(!identical(candidate(185, 546), '0b101101110')){quit('no', 1)}\n    if(!identical(candidate(362, 496), '0b110101101')){quit('no', 1)}\n    if(!identical(candidate(350, 902), '0b1001110010')){quit('no', 1)}\n    if(!identical(candidate(197, 233), '0b11010111')){quit('no', 1)}\n    if(!identical(candidate(7, 5), -1)){quit('no', 1)}\n    if(!identical(candidate(5, 1), -1)){quit('no', 1)}\n    if(!identical(candidate(5, 5), '0b101')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_6_parse_nested_parens",
    "language": "r",
    "prompt": "# Input to this function is a string represented multiple groups for nested parentheses separated by spaces.\n# For each of the group, output the deepest level of nesting of parentheses.\n# E.g. (()()) has maximum two levels of nesting while ((())) has three.\n# >>> parse_nested_parens('(()()) ((())) () ((())()())')\n# list(2, 3, 1, 3)\nparse_nested_parens <- function(paren_string) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_6_parse_nested_parens.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- parse_nested_parens\n    if(!identical(candidate('(()()) ((())) () ((())()())'), list(2, 3, 1, 3))){quit('no', 1)}\n    if(!identical(candidate('() (()) ((())) (((())))'), list(1, 2, 3, 4))){quit('no', 1)}\n    if(!identical(candidate('(()(())((())))'), list(4))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_121_solution",
    "language": "r",
    "prompt": "# Given a non-empty list of integers, return the sum of all of the odd elements that are in even positions.\n# Examples\n# >>> solution(c(5, 8, 7, 1))\n# 12\n# >>> solution(c(3, 3, 3, 3, 3))\n# 9\n# >>> solution(c(30, 13, 24, 321))\n# 0\nsolution <- function(lst) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_121_solution.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- solution\n    if(!identical(candidate(c(5, 8, 7, 1)), 12)){quit('no', 1)}\n    if(!identical(candidate(c(3, 3, 3, 3, 3)), 9)){quit('no', 1)}\n    if(!identical(candidate(c(30, 13, 24, 321)), 0)){quit('no', 1)}\n    if(!identical(candidate(c(5, 9)), 5)){quit('no', 1)}\n    if(!identical(candidate(c(2, 4, 8)), 0)){quit('no', 1)}\n    if(!identical(candidate(c(30, 13, 23, 32)), 23)){quit('no', 1)}\n    if(!identical(candidate(c(3, 13, 2, 9)), 3)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_147_get_max_triples",
    "language": "r",
    "prompt": "# You are given a positive integer n. You have to create an integer vector a of length n.\n# For each i (1 \u2264 i \u2264 n), the value of a[i] = i * i - i + 1.\n# Return the number of triples (a[i], a[j], a[k]) of a where i < j < k, \n# and a[i] + a[j] + a[k] is a multiple of 3.\n# Example :\n# >>> get_max_triples(5)\n# 1\n# Explanation: \n# a = [1, 3, 7, 13, 21]\n# The only valid triple is (1, 7, 13).\nget_max_triples <- function(n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_147_get_max_triples.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- get_max_triples\n    if(!identical(candidate(5), 1)){quit('no', 1)}\n    if(!identical(candidate(6), 4)){quit('no', 1)}\n    if(!identical(candidate(10), 36)){quit('no', 1)}\n    if(!identical(candidate(100), 53361)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_148_bf",
    "language": "r",
    "prompt": "# There are eight planets in our solar system: the closerst to the Sun \n# is Mercury, the next one is Venus, then Earth, Mars, Jupiter, Saturn, \n# Uranus, Neptune.\n# Write a function that takes two planet names as strings planet1 and planet2. \n# The function should return a list containing all planets whose orbits are \n# located between the orbit of planet1 and the orbit of planet2, sorted by \n# the proximity to the sun. \n# The function should return an empty list if planet1 or planet2\n# are not correct planet names. \n# Examples\n# >>> bf('Jupiter', 'Neptune')\n# list('Saturn', 'Uranus')\n# >>> bf('Earth', 'Mercury')\n# 'Venus'\n# >>> bf('Mercury', 'Uranus')\n# list('Venus', 'Earth', 'Mars', 'Jupiter', 'Saturn')\nbf <- function(planet1, planet2) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_148_bf.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- bf\n    if(!identical(candidate('Jupiter', 'Neptune'), list('Saturn', 'Uranus'))){quit('no', 1)}\n    if(!identical(candidate('Earth', 'Mercury'), list('Venus'))){quit('no', 1)}\n    if(!identical(candidate('Mercury', 'Uranus'), list('Venus', 'Earth', 'Mars', 'Jupiter', 'Saturn'))){quit('no', 1)}\n    if(!identical(candidate('Neptune', 'Venus'), list('Earth', 'Mars', 'Jupiter', 'Saturn', 'Uranus'))){quit('no', 1)}\n    if(!identical(candidate('Earth', 'Earth'), list())){quit('no', 1)}\n    if(!identical(candidate('Mars', 'Earth'), list())){quit('no', 1)}\n    if(!identical(candidate('Jupiter', 'Makemake'), list())){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_90_next_smallest",
    "language": "r",
    "prompt": "# You are given a list of integers.\n# Write a function next_smallest() that returns the 2nd smallest element of the list.\n# Return NULL if there is no such element.\n# >>> next_smallest(c(1, 2, 3, 4, 5))\n# 2\n# >>> next_smallest(c(5, 1, 4, 3, 2))\n# 2\n# >>> next_smallest(c())\n# NULL\n# >>> next_smallest(c(1, 1))\n# NULL\nnext_smallest <- function(lst) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_90_next_smallest.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- next_smallest\n    if(!identical(candidate(c(1, 2, 3, 4, 5)), 2)){quit('no', 1)}\n    if(!identical(candidate(c(5, 1, 4, 3, 2)), 2)){quit('no', 1)}\n    if(!identical(candidate(c()), NULL)){quit('no', 1)}\n    if(!identical(candidate(c(1, 1)), NULL)){quit('no', 1)}\n    if(!identical(candidate(c(1, 1, 1, 1, 0)), 1)){quit('no', 1)}\n    if(!identical(candidate(c(1, 1)), NULL)){quit('no', 1)}\n    if(!identical(candidate(c(-35, 34, 12, -45)), -35)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_19_sort_numbers",
    "language": "r",
    "prompt": "# Input is a space-delimited string of numberals from 'zero' to 'nine'.\n# Valid choices are 'zero', 'one', 'two', 'three', 'four', 'five', 'six', 'seven', 'eight' and 'nine'.\n# Return the string with numbers sorted from smallest to largest\n# >>> sort_numbers('three one five')\n# 'one three five'\nsort_numbers <- function(numbers) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_19_sort_numbers.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- sort_numbers\n    if(!identical(candidate(''), '')){quit('no', 1)}\n    if(!identical(candidate('three'), 'three')){quit('no', 1)}\n    if(!identical(candidate('three five nine'), 'three five nine')){quit('no', 1)}\n    if(!identical(candidate('five zero four seven nine eight'), 'zero four five seven eight nine')){quit('no', 1)}\n    if(!identical(candidate('six five four three two one zero'), 'zero one two three four five six')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_154_cycpattern_check",
    "language": "r",
    "prompt": "# You are given 2 words. You need to return TRUE if the second word or any of its rotations is a substring in the first word\n# >>> cycpattern_check('abcd', 'abd')\n# FALSE\n# >>> cycpattern_check('hello', 'ell')\n# TRUE\n# >>> cycpattern_check('whassup', 'psus')\n# FALSE\n# >>> cycpattern_check('abab', 'baa')\n# TRUE\n# >>> cycpattern_check('efef', 'eeff')\n# FALSE\n# >>> cycpattern_check('himenss', 'simen')\n# TRUE\ncycpattern_check <- function(a, b) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_154_cycpattern_check.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- cycpattern_check\n    if(!identical(candidate('xyzw', 'xyw'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('yello', 'ell'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('whattup', 'ptut'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('efef', 'fee'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('abab', 'aabb'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('winemtt', 'tinem'), TRUE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_79_decimal_to_binary",
    "language": "r",
    "prompt": "# You will be given a number in decimal form and your task is to convert it to\n# binary format. The function should return a string, with each character representing a binary\n# number. Each character in the string will be '0' or '1'.\n# There will be an extra couple of characters 'db' at the beginning and at the end of the string.\n# The extra characters are there to help with the format.\n# Examples:\n# >>> decimal_to_binary(15)\n# 'db1111db'\n# >>> decimal_to_binary(32)\n# 'db100000db'\ndecimal_to_binary <- function(decimal) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_79_decimal_to_binary.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- decimal_to_binary\n    if(!identical(candidate(0), 'db0db')){quit('no', 1)}\n    if(!identical(candidate(32), 'db100000db')){quit('no', 1)}\n    if(!identical(candidate(103), 'db1100111db')){quit('no', 1)}\n    if(!identical(candidate(15), 'db1111db')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_7_filter_by_substring",
    "language": "r",
    "prompt": "# Filter an input list of strings only for ones that contain given substring\n# >>> filter_by_substring(c(), 'a')\n# list()\n# >>> filter_by_substring(c('abc', 'bacd', 'cde', 'array'), 'a')\n# list('abc', 'bacd', 'array')\nfilter_by_substring <- function(strings, substring) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_7_filter_by_substring.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- filter_by_substring\n    if(!identical(candidate(c(), 'john'), list())){quit('no', 1)}\n    if(!identical(candidate(c('xxx', 'asd', 'xxy', 'john doe', 'xxxAAA', 'xxx'), 'xxx'), list('xxx', 'xxxAAA', 'xxx'))){quit('no', 1)}\n    if(!identical(candidate(c('xxx', 'asd', 'aaaxxy', 'john doe', 'xxxAAA', 'xxx'), 'xx'), list('xxx', 'aaaxxy', 'xxxAAA', 'xxx'))){quit('no', 1)}\n    if(!identical(candidate(c('grunt', 'trumpet', 'prune', 'gruesome'), 'run'), list('grunt', 'prune'))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_155_even_odd_count",
    "language": "r",
    "prompt": "# Given an integer. return a list that has the number of even and odd digits respectively.\n# Example:\n# >>> even_odd_count(-12)\n# list(1, 1)\n# >>> even_odd_count(123)\n# list(1, 2)\neven_odd_count <- function(num) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_155_even_odd_count.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- even_odd_count\n    if(!identical(candidate(7), list(0, 1))){quit('no', 1)}\n    if(!identical(candidate(-78), list(1, 1))){quit('no', 1)}\n    if(!identical(candidate(3452), list(2, 2))){quit('no', 1)}\n    if(!identical(candidate(346211), list(3, 3))){quit('no', 1)}\n    if(!identical(candidate(-345821), list(3, 3))){quit('no', 1)}\n    if(!identical(candidate(-2), list(1, 0))){quit('no', 1)}\n    if(!identical(candidate(-45347), list(2, 3))){quit('no', 1)}\n    if(!identical(candidate(0), list(1, 0))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_158_find_max",
    "language": "r",
    "prompt": "# Write a function that accepts a list of strings.\n# The list contains different words. Return the word with maximum number\n# of unique characters. If multiple strings have maximum number of unique\n# characters, return the one which comes first in lexicographical order.\n# >>> find_max(c('name', 'of', 'string'))\n# 'string'\n# >>> find_max(c('name', 'enam', 'game'))\n# 'enam'\n# >>> find_max(c('aaaaaaa', 'bb', 'cc'))\n# 'aaaaaaa'\nfind_max <- function(words) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_158_find_max.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- find_max\n    if(!identical(candidate(c('name', 'of', 'string')), 'string')){quit('no', 1)}\n    if(!identical(candidate(c('name', 'enam', 'game')), 'enam')){quit('no', 1)}\n    if(!identical(candidate(c('aaaaaaa', 'bb', 'cc')), 'aaaaaaa')){quit('no', 1)}\n    if(!identical(candidate(c('abc', 'cba')), 'abc')){quit('no', 1)}\n    if(!identical(candidate(c('play', 'this', 'game', 'of', 'footbott')), 'footbott')){quit('no', 1)}\n    if(!identical(candidate(c('we', 'are', 'gonna', 'rock')), 'gonna')){quit('no', 1)}\n    if(!identical(candidate(c('we', 'are', 'a', 'mad', 'nation')), 'nation')){quit('no', 1)}\n    if(!identical(candidate(c('this', 'is', 'a', 'prrk')), 'this')){quit('no', 1)}\n    if(!identical(candidate(c('b')), 'b')){quit('no', 1)}\n    if(!identical(candidate(c('play', 'play', 'play')), 'play')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_83_starts_one_ends",
    "language": "r",
    "prompt": "# Given a positive integer n, return the count of the numbers of n-digit\n# positive integers that start or end with 1.\nstarts_one_ends <- function(n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_83_starts_one_ends.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- starts_one_ends\n    if(!identical(candidate(1), 1)){quit('no', 1)}\n    if(!identical(candidate(2), 18)){quit('no', 1)}\n    if(!identical(candidate(3), 180)){quit('no', 1)}\n    if(!identical(candidate(4), 1800)){quit('no', 1)}\n    if(!identical(candidate(5), 18000)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_136_largest_smallest_integers",
    "language": "r",
    "prompt": "# Create a function that returns a list (a, b), where 'a' is\n# the largest of negative integers, and 'b' is the smallest\n# of positive integers in a list.\n# If there is no negative or positive integers, return them as NULL.\n# Examples:\n# >>> largest_smallest_integers(c(2, 4, 1, 3, 5, 7))\n# list(NULL, 1)\n# >>> largest_smallest_integers(c())\n# list(NULL, NULL)\n# >>> largest_smallest_integers(c(0))\n# list(NULL, NULL)\nlargest_smallest_integers <- function(lst) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_136_largest_smallest_integers.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- largest_smallest_integers\n    if(!identical(candidate(c(2, 4, 1, 3, 5, 7)), list(NULL, 1))){quit('no', 1)}\n    if(!identical(candidate(c(2, 4, 1, 3, 5, 7, 0)), list(NULL, 1))){quit('no', 1)}\n    if(!identical(candidate(c(1, 3, 2, 4, 5, 6, -2)), list(-2, 1))){quit('no', 1)}\n    if(!identical(candidate(c(4, 5, 3, 6, 2, 7, -7)), list(-7, 2))){quit('no', 1)}\n    if(!identical(candidate(c(7, 3, 8, 4, 9, 2, 5, -9)), list(-9, 2))){quit('no', 1)}\n    if(!identical(candidate(c()), list(NULL, NULL))){quit('no', 1)}\n    if(!identical(candidate(c(0)), list(NULL, NULL))){quit('no', 1)}\n    if(!identical(candidate(c(-1, -3, -5, -6)), list(-1, NULL))){quit('no', 1)}\n    if(!identical(candidate(c(-1, -3, -5, -6, 0)), list(-1, NULL))){quit('no', 1)}\n    if(!identical(candidate(c(-6, -4, -4, -3, 1)), list(-3, 1))){quit('no', 1)}\n    if(!identical(candidate(c(-6, -4, -4, -3, -100, 1)), list(-3, 1))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_68_pluck",
    "language": "r",
    "prompt": "# \"Given a vector representing a branch of a tree that has non-negative integer nodes\n# your task is to pluck one of the nodes and return it.\n# The plucked node should be the node with the smallest even value.\n# If multiple nodes with the same smallest even value are found return the node that has smallest index.\n# The plucked node should be returned in a list, [ smalest_value, its index ],\n# If there are no even values or the given vector is empty, return [].\n# Example 1:\n# >>> pluck(c(4, 2, 3))\n# list(2, 1)\n# Explanation: 2 has the smallest even value, and 2 has the smallest index.\n# Example 2:\n# >>> pluck(c(1, 2, 3))\n# list(2, 1)\n# Explanation: 2 has the smallest even value, and 2 has the smallest index.\n# Example 3:\n# >>> pluck(c())\n# list()\n# Example 4:\n# >>> pluck(c(5, 0, 3, 0, 4, 2))\n# list(0, 1)\n# Explanation: 0 is the smallest value, but  there are two zeros,\n# so we will choose the first zero, which has the smallest index.\n# Constraints:\n# * 1 <= nodes.length <= 10000\n# * 0 <= node.value\npluck <- function(arr) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_68_pluck.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- pluck\n    if(!identical(candidate(c(4, 2, 3)), list(2, 1))){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3)), list(2, 1))){quit('no', 1)}\n    if(!identical(candidate(c()), list())){quit('no', 1)}\n    if(!identical(candidate(c(5, 0, 3, 0, 4, 2)), list(0, 1))){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3, 0, 5, 3)), list(0, 3))){quit('no', 1)}\n    if(!identical(candidate(c(5, 4, 8, 4, 8)), list(4, 1))){quit('no', 1)}\n    if(!identical(candidate(c(7, 6, 7, 1)), list(6, 1))){quit('no', 1)}\n    if(!identical(candidate(c(7, 9, 7, 1)), list())){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_108_count_nums",
    "language": "r",
    "prompt": "# Write a function count_nums which takes a vector of integers and returns\n# the number of elements which has a sum of digits > 0.\n# If a number is negative, then its first signed digit will be negative:\n# e.g. -123 has signed digits -1, 2, and 3.\n# >>> count_nums(c())\n# 0\n# >>> count_nums(c(-1, 11, -11))\n# 1\n# >>> count_nums(c(1, 1, 2))\n# 3\ncount_nums <- function(arr) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_108_count_nums.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- count_nums\n    if(!identical(candidate(c()), 0)){quit('no', 1)}\n    if(!identical(candidate(c(-1, -2, 0)), 0)){quit('no', 1)}\n    if(!identical(candidate(c(1, 1, 2, -2, 3, 4, 5)), 6)){quit('no', 1)}\n    if(!identical(candidate(c(1, 6, 9, -6, 0, 1, 5)), 5)){quit('no', 1)}\n    if(!identical(candidate(c(1, 100, 98, -7, 1, -1)), 4)){quit('no', 1)}\n    if(!identical(candidate(c(12, 23, 34, -45, -56, 0)), 5)){quit('no', 1)}\n    if(!identical(candidate(c(0, 1)), 1)){quit('no', 1)}\n    if(!identical(candidate(c(1)), 1)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_129_minPath",
    "language": "r",
    "prompt": "# Given a grid with N rows and N columns (N >= 2) and a positive integer k, \n# each cell of the grid contains a value. Every integer in the range [1, N * N]\n# inclusive appears exactly once on the cells of the grid.\n# You have to find the minimum path of length k in the grid. You can start\n# from any cell, and in each step you can move to any of the neighbor cells,\n# in other words, you can go to cells which share an edge with you current\n# cell.\n# Please note that a path of length k means visiting exactly k cells (not\n# necessarily distinct).\n# You CANNOT go off the grid.\n# A path A (of length k) is considered less than a path B (of length k) if\n# after making the ordered lists of the values on the cells that A and B go\n# through (let's call them lst_A and lst_B), lst_A is lexicographically less\n# than lst_B, in other words, there exist an integer index i (1 <= i <= k)\n# such that lst_A[i] < lst_B[i] and for any j (1 <= j < i) we have\n# lst_A[j] = lst_B[j].\n# It is guaranteed that the answer is unique.\n# Return an ordered list of the values on the cells that the minimum path go through.\n# Examples:    \n# >>> minPath(list(list(1, 2, 3), list(4, 5, 6), list(7, 8, 9)), 3)\n# list(1, 2, 1)\n# >>> minPath(list(list(5, 9, 3), list(4, 1, 6), list(7, 8, 2)), 1)\n# list(1)\nminPath <- function(grid, k) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_129_minPath.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- minPath\n    if(!identical(candidate(list(list(1, 2, 3), list(4, 5, 6), list(7, 8, 9)), 3), list(1, 2, 1))){quit('no', 1)}\n    if(!identical(candidate(list(list(5, 9, 3), list(4, 1, 6), list(7, 8, 2)), 1), list(1))){quit('no', 1)}\n    if(!identical(candidate(list(list(1, 2, 3, 4), list(5, 6, 7, 8), list(9, 10, 11, 12), list(13, 14, 15, 16)), 4), list(1, 2, 1, 2))){quit('no', 1)}\n    if(!identical(candidate(list(list(6, 4, 13, 10), list(5, 7, 12, 1), list(3, 16, 11, 15), list(8, 14, 9, 2)), 7), list(1, 10, 1, 10, 1, 10, 1))){quit('no', 1)}\n    if(!identical(candidate(list(list(8, 14, 9, 2), list(6, 4, 13, 15), list(5, 7, 1, 12), list(3, 10, 11, 16)), 5), list(1, 7, 1, 7, 1))){quit('no', 1)}\n    if(!identical(candidate(list(list(11, 8, 7, 2), list(5, 16, 14, 4), list(9, 3, 15, 6), list(12, 13, 10, 1)), 9), list(1, 6, 1, 6, 1, 6, 1, 6, 1))){quit('no', 1)}\n    if(!identical(candidate(list(list(12, 13, 10, 1), list(9, 3, 15, 6), list(5, 16, 14, 4), list(11, 8, 7, 2)), 12), list(1, 6, 1, 6, 1, 6, 1, 6, 1, 6, 1, 6))){quit('no', 1)}\n    if(!identical(candidate(list(list(2, 7, 4), list(3, 1, 5), list(6, 8, 9)), 8), list(1, 3, 1, 3, 1, 3, 1, 3))){quit('no', 1)}\n    if(!identical(candidate(list(list(6, 1, 5), list(3, 8, 9), list(2, 7, 4)), 8), list(1, 5, 1, 5, 1, 5, 1, 5))){quit('no', 1)}\n    if(!identical(candidate(list(list(1, 2), list(3, 4)), 10), list(1, 2, 1, 2, 1, 2, 1, 2, 1, 2))){quit('no', 1)}\n    if(!identical(candidate(list(list(1, 3), list(3, 2)), 10), list(1, 3, 1, 3, 1, 3, 1, 3, 1, 3))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_70_strange_sort_list",
    "language": "r",
    "prompt": "# Given list of integers, return list in strange order.\n# Strange sorting, is when you start with the minimum value,\n# then maximum of the remaining integers, then minimum and so on.\n# Examples:\n# >>> strange_sort_list(c(1, 2, 3, 4))\n# list(1, 4, 2, 3)\n# >>> strange_sort_list(c(5, 5, 5, 5))\n# list(5, 5, 5, 5)\n# >>> strange_sort_list(c())\n# list()\nstrange_sort_list <- function(lst) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_70_strange_sort_list.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- strange_sort_list\n    if(!identical(candidate(c(1, 2, 3, 4)), list(1, 4, 2, 3))){quit('no', 1)}\n    if(!identical(candidate(c(5, 6, 7, 8, 9)), list(5, 9, 6, 8, 7))){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3, 4, 5)), list(1, 5, 2, 4, 3))){quit('no', 1)}\n    if(!identical(candidate(c(5, 6, 7, 8, 9, 1)), list(1, 9, 5, 8, 6, 7))){quit('no', 1)}\n    if(!identical(candidate(c(5, 5, 5, 5)), list(5, 5, 5, 5))){quit('no', 1)}\n    if(!identical(candidate(c()), list())){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3, 4, 5, 6, 7, 8)), list(1, 8, 2, 7, 3, 6, 4, 5))){quit('no', 1)}\n    if(!identical(candidate(c(0, 2, 2, 2, 5, 5, -5, -5)), list(-5, 5, -5, 5, 0, 2, 2, 2))){quit('no', 1)}\n    if(!identical(candidate(c(111111)), list(111111))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_162_string_to_md5",
    "language": "r",
    "prompt": "# Given a string 'text', return its md5 hash equivalent string.\n# If 'text' is an empty string, return NULL.\n# >>> string_to_md5('Hello world')\n# '3e25960a79dbc69b674cd4ec67a72c62'\nstring_to_md5 <- function(text) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_162_string_to_md5.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- string_to_md5\n    if(!identical(candidate('Hello world'), '3e25960a79dbc69b674cd4ec67a72c62')){quit('no', 1)}\n    if(!identical(candidate(''), NULL)){quit('no', 1)}\n    if(!identical(candidate('A B C'), '0ef78513b0cb8cef12743f5aeb35f888')){quit('no', 1)}\n    if(!identical(candidate('password'), '5f4dcc3b5aa765d61d8327deb882cf99')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_118_get_closest_vowel",
    "language": "r",
    "prompt": "# You are given a word. Your task is to find the closest vowel that stands between \n# two consonants from the right side of the word (case sensitive).\n# Vowels in the beginning and ending doesn't count. Return empty string if you didn't\n# find any vowel met the above condition. \n# You may assume that the given string contains English letter only.\n# Example:\n# >>> get_closest_vowel('yogurt')\n# 'u'\n# >>> get_closest_vowel('FULL')\n# 'U'\n# >>> get_closest_vowel('quick')\n# ''\n# >>> get_closest_vowel('ab')\n# ''\nget_closest_vowel <- function(word) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_118_get_closest_vowel.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- get_closest_vowel\n    if(!identical(candidate('yogurt'), 'u')){quit('no', 1)}\n    if(!identical(candidate('full'), 'u')){quit('no', 1)}\n    if(!identical(candidate('easy'), '')){quit('no', 1)}\n    if(!identical(candidate('eAsy'), '')){quit('no', 1)}\n    if(!identical(candidate('ali'), '')){quit('no', 1)}\n    if(!identical(candidate('bad'), 'a')){quit('no', 1)}\n    if(!identical(candidate('most'), 'o')){quit('no', 1)}\n    if(!identical(candidate('ab'), '')){quit('no', 1)}\n    if(!identical(candidate('ba'), '')){quit('no', 1)}\n    if(!identical(candidate('quick'), '')){quit('no', 1)}\n    if(!identical(candidate('anime'), 'i')){quit('no', 1)}\n    if(!identical(candidate('Asia'), '')){quit('no', 1)}\n    if(!identical(candidate('Above'), 'o')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_44_change_base",
    "language": "r",
    "prompt": "# Change numerical base of input number x to base.\n# return string representation after the conversion.\n# base numbers are less than 10.\n# >>> change_base(8, 3)\n# '22'\n# >>> change_base(8, 2)\n# '1000'\n# >>> change_base(7, 2)\n# '111'\nchange_base <- function(x, base) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_44_change_base.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- change_base\n    if(!identical(candidate(8, 3), '22')){quit('no', 1)}\n    if(!identical(candidate(9, 3), '100')){quit('no', 1)}\n    if(!identical(candidate(234, 2), '11101010')){quit('no', 1)}\n    if(!identical(candidate(16, 2), '10000')){quit('no', 1)}\n    if(!identical(candidate(8, 2), '1000')){quit('no', 1)}\n    if(!identical(candidate(7, 2), '111')){quit('no', 1)}\n    if(!identical(candidate(2, 3), '2')){quit('no', 1)}\n    if(!identical(candidate(3, 4), '3')){quit('no', 1)}\n    if(!identical(candidate(4, 5), '4')){quit('no', 1)}\n    if(!identical(candidate(5, 6), '5')){quit('no', 1)}\n    if(!identical(candidate(6, 7), '6')){quit('no', 1)}\n    if(!identical(candidate(7, 8), '7')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_0_has_close_elements",
    "language": "r",
    "prompt": "# Check if in given list of numbers, are any two numbers closer to each other than\n# given threshold.\n# >>> has_close_elements(c(1.0, 2.0, 3.0), 0.5)\n# FALSE\n# >>> has_close_elements(c(1.0, 2.8, 3.0, 4.0, 5.0, 2.0), 0.3)\n# TRUE\nhas_close_elements <- function(numbers, threshold) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_0_has_close_elements.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- has_close_elements\n    if(!identical(candidate(c(1.0, 2.0, 3.9, 4.0, 5.0, 2.2), 0.3), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(1.0, 2.0, 3.9, 4.0, 5.0, 2.2), 0.05), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(1.0, 2.0, 5.9, 4.0, 5.0), 0.95), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(1.0, 2.0, 5.9, 4.0, 5.0), 0.8), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(1.0, 2.0, 3.0, 4.0, 5.0, 2.0), 0.1), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(1.1, 2.2, 3.1, 4.1, 5.1), 1.0), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(1.1, 2.2, 3.1, 4.1, 5.1), 0.5), FALSE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_132_is_nested",
    "language": "r",
    "prompt": "# Create a function that takes a string as input which contains only square brackets.\n# The function should return TRUE if and only if there is a valid subsequence of brackets \n# where at least one bracket in the subsequence is nested.\n# >>> is_nested('[[]]')\n# TRUE\n# >>> is_nested('[]]]]]]][[[[[]')\n# FALSE\n# >>> is_nested('[][]')\n# FALSE\n# >>> is_nested('[]')\n# FALSE\n# >>> is_nested('[[][]]')\n# TRUE\n# >>> is_nested('[[]][[')\n# TRUE\nis_nested <- function(string) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_132_is_nested.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- is_nested\n    if(!identical(candidate('[[]]'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('[]]]]]]][[[[[]'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('[][]'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('[]'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('[[[[]]]]'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('[]]]]]]]]]]'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('[][][[]]'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('[[]'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('[]]'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('[[]][['), TRUE)){quit('no', 1)}\n    if(!identical(candidate('[[][]]'), TRUE)){quit('no', 1)}\n    if(!identical(candidate(''), FALSE)){quit('no', 1)}\n    if(!identical(candidate('[[[[[[[['), FALSE)){quit('no', 1)}\n    if(!identical(candidate(']]]]]]]]'), FALSE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_28_concatenate",
    "language": "r",
    "prompt": "# Concatenate list of strings into a single string\n# >>> concatenate(c())\n# ''\n# >>> concatenate(c('a', 'b', 'c'))\n# 'abc'\nconcatenate <- function(strings) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_28_concatenate.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- concatenate\n    if(!identical(candidate(c()), '')){quit('no', 1)}\n    if(!identical(candidate(c('x', 'y', 'z')), 'xyz')){quit('no', 1)}\n    if(!identical(candidate(c('x', 'y', 'z', 'w', 'k')), 'xyzwk')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_39_prime_fib",
    "language": "r",
    "prompt": "# prime_fib returns n-th number that is a Fibonacci number and it's also prime.\n# >>> prime_fib(1)\n# 2\n# >>> prime_fib(2)\n# 3\n# >>> prime_fib(3)\n# 5\n# >>> prime_fib(4)\n# 13\n# >>> prime_fib(5)\n# 89\nprime_fib <- function(n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_39_prime_fib.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- prime_fib\n    if(!identical(candidate(1), 2)){quit('no', 1)}\n    if(!identical(candidate(2), 3)){quit('no', 1)}\n    if(!identical(candidate(3), 5)){quit('no', 1)}\n    if(!identical(candidate(4), 13)){quit('no', 1)}\n    if(!identical(candidate(5), 89)){quit('no', 1)}\n    if(!identical(candidate(6), 233)){quit('no', 1)}\n    if(!identical(candidate(7), 1597)){quit('no', 1)}\n    if(!identical(candidate(8), 28657)){quit('no', 1)}\n    if(!identical(candidate(9), 514229)){quit('no', 1)}\n    if(!identical(candidate(10), 433494437)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_20_find_closest_elements",
    "language": "r",
    "prompt": "# From a supplied list of numbers (of length at least two) select and return two that are the closest to each\n# other and return them in order (smaller number, larger number).\n# >>> find_closest_elements(c(1.0, 2.0, 3.0, 4.0, 5.0, 2.2))\n# list(2.0, 2.2)\n# >>> find_closest_elements(c(1.0, 2.0, 3.0, 4.0, 5.0, 2.0))\n# list(2.0, 2.0)\nfind_closest_elements <- function(numbers) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_20_find_closest_elements.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- find_closest_elements\n    if(!identical(candidate(c(1.0, 2.0, 3.9, 4.0, 5.0, 2.2)), list(3.9, 4.0))){quit('no', 1)}\n    if(!identical(candidate(c(1.0, 2.0, 5.9, 4.0, 5.0)), list(5.0, 5.9))){quit('no', 1)}\n    if(!identical(candidate(c(1.0, 2.0, 3.0, 4.0, 5.0, 2.2)), list(2.0, 2.2))){quit('no', 1)}\n    if(!identical(candidate(c(1.0, 2.0, 3.0, 4.0, 5.0, 2.0)), list(2.0, 2.0))){quit('no', 1)}\n    if(!identical(candidate(c(1.1, 2.2, 3.1, 4.1, 5.1)), list(2.2, 3.1))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_78_hex_key",
    "language": "r",
    "prompt": "# You have been tasked to write a function that receives \n# a hexadecimal number as a string and counts the number of hexadecimal \n# digits that are primes (prime number, or a prime, is a natural number \n# greater than 1 that is not a product of two smaller natural numbers).\n# Hexadecimal digits are 0, 1, 2, 3, 4, 5, 6, 7, 8, 9, A, B, C, D, E, F.\n# Prime numbers are 2, 3, 5, 7, 11, 13, 17,...\n# So you have to determine a number of the following digits: 2, 3, 5, 7, \n# B (=decimal 11), D (=decimal 13).\n# Note: you may assume the input is always correct or empty string, \n# and symbols A,B,C,D,E,F are always uppercase.\n# Examples:\n# >>> hex_key('AB')\n# 1\n# >>> hex_key('1077E')\n# 2\n# >>> hex_key('ABED1A33')\n# 4\n# >>> hex_key('123456789ABCDEF0')\n# 6\n# >>> hex_key('2020')\n# 2\nhex_key <- function(num) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_78_hex_key.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- hex_key\n    if(!identical(candidate('AB'), 1)){quit('no', 1)}\n    if(!identical(candidate('1077E'), 2)){quit('no', 1)}\n    if(!identical(candidate('ABED1A33'), 4)){quit('no', 1)}\n    if(!identical(candidate('2020'), 2)){quit('no', 1)}\n    if(!identical(candidate('123456789ABCDEF0'), 6)){quit('no', 1)}\n    if(!identical(candidate('112233445566778899AABBCCDDEEFF00'), 12)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_97_multiply",
    "language": "r",
    "prompt": "# Complete the function that takes two integers and returns \n# the product of their unit digits.\n# Assume the input is always valid.\n# Examples:\n# >>> multiply(148, 412)\n# 16\n# >>> multiply(19, 28)\n# 72\n# >>> multiply(2020, 1851)\n# 0\n# >>> multiply(14, -15)\n# 20\nmultiply <- function(a, b) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_97_multiply.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- multiply\n    if(!identical(candidate(148, 412), 16)){quit('no', 1)}\n    if(!identical(candidate(19, 28), 72)){quit('no', 1)}\n    if(!identical(candidate(2020, 1851), 0)){quit('no', 1)}\n    if(!identical(candidate(14, -15), 20)){quit('no', 1)}\n    if(!identical(candidate(76, 67), 42)){quit('no', 1)}\n    if(!identical(candidate(17, 27), 49)){quit('no', 1)}\n    if(!identical(candidate(0, 1), 0)){quit('no', 1)}\n    if(!identical(candidate(0, 0), 0)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_21_rescale_to_unit",
    "language": "r",
    "prompt": "# Given list of numbers (of at least two elements), apply a linear transform to that list,\n# such that the smallest number will become 0 and the largest will become 1\n# >>> rescale_to_unit(c(1.0, 2.0, 3.0, 4.0, 5.0))\n# list(0.0, 0.25, 0.5, 0.75, 1.0)\nrescale_to_unit <- function(numbers) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_21_rescale_to_unit.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- rescale_to_unit\n    if(!identical(candidate(c(2.0, 49.9)), list(0.0, 1.0))){quit('no', 1)}\n    if(!identical(candidate(c(100.0, 49.9)), list(1.0, 0.0))){quit('no', 1)}\n    if(!identical(candidate(c(1.0, 2.0, 3.0, 4.0, 5.0)), list(0.0, 0.25, 0.5, 0.75, 1.0))){quit('no', 1)}\n    if(!identical(candidate(c(2.0, 1.0, 5.0, 3.0, 4.0)), list(0.25, 0.0, 1.0, 0.5, 0.75))){quit('no', 1)}\n    if(!identical(candidate(c(12.0, 11.0, 15.0, 13.0, 14.0)), list(0.25, 0.0, 1.0, 0.5, 0.75))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_131_digits",
    "language": "r",
    "prompt": "# Given a positive integer n, return the product of the odd digits.\n# Return 0 if all digits are even.\n# For example:\n# >>> digits(1)\n# 1\n# >>> digits(4)\n# 0\n# >>> digits(235)\n# 15\ndigits <- function(n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_131_digits.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- digits\n    if(!identical(candidate(5), 5)){quit('no', 1)}\n    if(!identical(candidate(54), 5)){quit('no', 1)}\n    if(!identical(candidate(120), 1)){quit('no', 1)}\n    if(!identical(candidate(5014), 5)){quit('no', 1)}\n    if(!identical(candidate(98765), 315)){quit('no', 1)}\n    if(!identical(candidate(5576543), 2625)){quit('no', 1)}\n    if(!identical(candidate(2468), 0)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_153_Strongest_Extension",
    "language": "r",
    "prompt": "# You will be given the name of a class (a string) and a list of extensions.\n# The extensions are to be used to load additional classes to the class. The\n# strength of the extension is as follows: Let CAP be the number of the uppercase\n# letters in the extension's name, and let SM be the number of lowercase letters \n# in the extension's name, the strength is given by the fraction CAP - SM. \n# You should find the strongest extension and return a string in this \n# format: ClassName.StrongestExtensionName.\n# If there are two or more extensions with the same strength, you should\n# choose the one that comes first in the list.\n# For example, if you are given \"Slices\" as the class and a list of the\n# extensions: ['SErviNGSliCes', 'Cheese', 'StuFfed'] then you should\n# return 'Slices.SErviNGSliCes' since 'SErviNGSliCes' is the strongest extension \n# (its strength is -1).\n# Example:\n# >>> Strongest_Extension('my_class', c('AA', 'Be', 'CC'))\n# 'my_class.AA'\nStrongest_Extension <- function(class_name, extensions) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_153_Strongest_Extension.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- Strongest_Extension\n    if(!identical(candidate('Watashi', c('tEN', 'niNE', 'eIGHt8OKe')), 'Watashi.eIGHt8OKe')){quit('no', 1)}\n    if(!identical(candidate('Boku123', c('nani', 'NazeDa', 'YEs.WeCaNe', '32145tggg')), 'Boku123.YEs.WeCaNe')){quit('no', 1)}\n    if(!identical(candidate('__YESIMHERE', c('t', 'eMptY', 'nothing', 'zeR00', 'NuLl__', '123NoooneB321')), '__YESIMHERE.NuLl__')){quit('no', 1)}\n    if(!identical(candidate('K', c('Ta', 'TAR', 't234An', 'cosSo')), 'K.TAR')){quit('no', 1)}\n    if(!identical(candidate('__HAHA', c('Tab', '123', '781345', '-_-')), '__HAHA.123')){quit('no', 1)}\n    if(!identical(candidate('YameRore', c('HhAas', 'okIWILL123', 'WorkOut', 'Fails', '-_-')), 'YameRore.okIWILL123')){quit('no', 1)}\n    if(!identical(candidate('finNNalLLly', c('Die', 'NowW', 'Wow', 'WoW')), 'finNNalLLly.WoW')){quit('no', 1)}\n    if(!identical(candidate('_', c('Bb', '91245')), '_.Bb')){quit('no', 1)}\n    if(!identical(candidate('Sp', c('671235', 'Bb')), 'Sp.671235')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_111_histogram",
    "language": "r",
    "prompt": "# Given a string representing a space separated lowercase letters, return a named list\n# of the letter with the most repetition and containing the corresponding count.\n# If several letters have the same occurrence, return all of them.\n# Example:\n# >>> histogram('a b c')\n# list('a' = 1, 'b' = 1, 'c' = 1)\n# >>> histogram('a b b a')\n# list('a' = 2, 'b' = 2)\n# >>> histogram('a b c a b')\n# list('a' = 2, 'b' = 2)\n# >>> histogram('b b b b a')\n# list('b' = 4)\n# >>> histogram('')\n# list()\nhistogram <- function(test) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_111_histogram.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- histogram\n    if(!identical(candidate('a b b a'), list('a' = 2, 'b' = 2))){quit('no', 1)}\n    if(!identical(candidate('a b c a b'), list('a' = 2, 'b' = 2))){quit('no', 1)}\n    if(!identical(candidate('a b c d g'), list('a' = 1, 'b' = 1, 'c' = 1, 'd' = 1, 'g' = 1))){quit('no', 1)}\n    if(!identical(candidate('r t g'), list('r' = 1, 't' = 1, 'g' = 1))){quit('no', 1)}\n    if(!identical(candidate('b b b b a'), list('b' = 4))){quit('no', 1)}\n    if(!identical(candidate('r t g'), list('r' = 1, 't' = 1, 'g' = 1))){quit('no', 1)}\n    if(!identical(candidate(''), list())){quit('no', 1)}\n    if(!identical(candidate('a'), list('a' = 1))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_43_pairs_sum_to_zero",
    "language": "r",
    "prompt": "# pairs_sum_to_zero takes a list of integers as an input.\n# it returns TRUE if there are two distinct elements in the list that\n# sum to zero, and FALSE otherwise.\n# >>> pairs_sum_to_zero(c(1, 3, 5, 0))\n# FALSE\n# >>> pairs_sum_to_zero(c(1, 3, -2, 1))\n# FALSE\n# >>> pairs_sum_to_zero(c(1, 2, 3, 7))\n# FALSE\n# >>> pairs_sum_to_zero(c(2, 4, -5, 3, 5, 7))\n# TRUE\n# >>> pairs_sum_to_zero(c(1))\n# FALSE\npairs_sum_to_zero <- function(l) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_43_pairs_sum_to_zero.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- pairs_sum_to_zero\n    if(!identical(candidate(c(1, 3, 5, 0)), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 3, -2, 1)), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3, 7)), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(2, 4, -5, 3, 5, 7)), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(1)), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(-3, 9, -1, 3, 2, 30)), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(-3, 9, -1, 3, 2, 31)), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(-3, 9, -1, 4, 2, 30)), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(-3, 9, -1, 4, 2, 31)), FALSE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_74_total_match",
    "language": "r",
    "prompt": "# Write a function that accepts two lists of strings and returns the list that has \n# total number of chars in the all strings of the list less than the other list.\n# if the two lists have the same number of chars, return the first list.\n# Examples\n# >>> total_match(c(), c())\n# list()\n# >>> total_match(c('hi', 'admin'), c('hI', 'Hi'))\n# list('hI', 'Hi')\n# >>> total_match(c('hi', 'admin'), c('hi', 'hi', 'admin', 'project'))\n# list('hi', 'admin')\n# >>> total_match(c('hi', 'admin'), c('hI', 'hi', 'hi'))\n# list('hI', 'hi', 'hi')\n# >>> total_match(c('4'), c('1', '2', '3', '4', '5'))\n# list('4')\ntotal_match <- function(lst1, lst2) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_74_total_match.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- total_match\n    if(!identical(candidate(c(), c()), list())){quit('no', 1)}\n    if(!identical(candidate(c('hi', 'admin'), c('hi', 'hi')), list('hi', 'hi'))){quit('no', 1)}\n    if(!identical(candidate(c('hi', 'admin'), c('hi', 'hi', 'admin', 'project')), list('hi', 'admin'))){quit('no', 1)}\n    if(!identical(candidate(c('4'), c('1', '2', '3', '4', '5')), list('4'))){quit('no', 1)}\n    if(!identical(candidate(c('hi', 'admin'), c('hI', 'Hi')), list('hI', 'Hi'))){quit('no', 1)}\n    if(!identical(candidate(c('hi', 'admin'), c('hI', 'hi', 'hi')), list('hI', 'hi', 'hi'))){quit('no', 1)}\n    if(!identical(candidate(c('hi', 'admin'), c('hI', 'hi', 'hii')), list('hi', 'admin'))){quit('no', 1)}\n    if(!identical(candidate(c(), c('this')), list())){quit('no', 1)}\n    if(!identical(candidate(c('this'), c()), list())){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_65_circular_shift",
    "language": "r",
    "prompt": "# Circular shift the digits of the integer x, shift the digits right by shift\n# and return the result as a string.\n# If shift > number of digits, return digits reversed.\n# >>> circular_shift(12, 1)\n# '21'\n# >>> circular_shift(12, 2)\n# '12'\ncircular_shift <- function(x, shift) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_65_circular_shift.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- circular_shift\n    if(!identical(candidate(100, 2), '001')){quit('no', 1)}\n    if(!identical(candidate(12, 2), '12')){quit('no', 1)}\n    if(!identical(candidate(97, 8), '79')){quit('no', 1)}\n    if(!identical(candidate(12, 1), '21')){quit('no', 1)}\n    if(!identical(candidate(11, 101), '11')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_57_monotonic",
    "language": "r",
    "prompt": "# Return TRUE is list elements are monotonically increasing or decreasing.\n# >>> monotonic(c(1, 2, 4, 20))\n# TRUE\n# >>> monotonic(c(1, 20, 4, 10))\n# FALSE\n# >>> monotonic(c(4, 1, 0, -10))\n# TRUE\nmonotonic <- function(l) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_57_monotonic.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- monotonic\n    if(!identical(candidate(c(1, 2, 4, 10)), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 4, 20)), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 20, 4, 10)), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(4, 1, 0, -10)), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(4, 1, 1, 0)), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3, 2, 5, 60)), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3, 4, 5, 60)), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(9, 9, 9, 9)), TRUE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_138_is_equal_to_sum_even",
    "language": "r",
    "prompt": "# Evaluate whether the given number n can be written as the sum of exactly 4 positive even numbers\n# Example\n# >>> is_equal_to_sum_even(4)\n# FALSE\n# >>> is_equal_to_sum_even(6)\n# FALSE\n# >>> is_equal_to_sum_even(8)\n# TRUE\nis_equal_to_sum_even <- function(n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_138_is_equal_to_sum_even.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- is_equal_to_sum_even\n    if(!identical(candidate(4), FALSE)){quit('no', 1)}\n    if(!identical(candidate(6), FALSE)){quit('no', 1)}\n    if(!identical(candidate(8), TRUE)){quit('no', 1)}\n    if(!identical(candidate(10), TRUE)){quit('no', 1)}\n    if(!identical(candidate(11), FALSE)){quit('no', 1)}\n    if(!identical(candidate(12), TRUE)){quit('no', 1)}\n    if(!identical(candidate(13), FALSE)){quit('no', 1)}\n    if(!identical(candidate(16), TRUE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_17_parse_music",
    "language": "r",
    "prompt": "# Input to this function is a string representing musical notes in a special ASCII format.\n# Your task is to parse this string and return list of integers corresponding to how many beats does each\n# not last.\n# Here is a legend:\n# 'o' - whole note, lasts four beats\n# 'o|' - half note, lasts two beats\n# '.|' - quater note, lasts one beat\n# >>> parse_music('o o| .| o| o| .| .| .| .| o o')\n# list(4, 2, 1, 2, 2, 1, 1, 1, 1, 4, 4)\nparse_music <- function(music_string) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_17_parse_music.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- parse_music\n    if(!identical(candidate(''), list())){quit('no', 1)}\n    if(!identical(candidate('o o o o'), list(4, 4, 4, 4))){quit('no', 1)}\n    if(!identical(candidate('.| .| .| .|'), list(1, 1, 1, 1))){quit('no', 1)}\n    if(!identical(candidate('o| o| .| .| o o o o'), list(2, 2, 1, 1, 4, 4, 4, 4))){quit('no', 1)}\n    if(!identical(candidate('o| .| o| .| o o| o o|'), list(2, 1, 2, 1, 4, 2, 4, 2))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_142_sum_squares",
    "language": "r",
    "prompt": "# \"\n# This function will take a list of integers. For all entries in the list, the function shall square the integer entry if its index is a \n# multiple of 3 and will cube the integer entry if its index is a multiple of 4 and not a multiple of 3. The function will not \n# change the entries in the list whose indexes are not a multiple of 3 or 4. The function shall then return the sum of all entries. \n# Examples:\n# >>> lst\n# list(1, 2, 3)\n# >>> lst\n# list()\n# >>> lst\n# list(-1, -5, 2, -1, -5)\nsum_squares <- function(lst) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_142_sum_squares.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- sum_squares\n    if(!identical(candidate(c(1, 2, 3)), 6)){quit('no', 1)}\n    if(!identical(candidate(c(1, 4, 9)), 14)){quit('no', 1)}\n    if(!identical(candidate(c()), 0)){quit('no', 1)}\n    if(!identical(candidate(c(1, 1, 1, 1, 1, 1, 1, 1, 1)), 9)){quit('no', 1)}\n    if(!identical(candidate(c(-1, -1, -1, -1, -1, -1, -1, -1, -1)), -3)){quit('no', 1)}\n    if(!identical(candidate(c(0)), 0)){quit('no', 1)}\n    if(!identical(candidate(c(-1, -5, 2, -1, -5)), -126)){quit('no', 1)}\n    if(!identical(candidate(c(-56, -99, 1, 0, -2)), 3030)){quit('no', 1)}\n    if(!identical(candidate(c(-1, 0, 0, 0, 0, 0, 0, 0, -1)), 0)){quit('no', 1)}\n    if(!identical(candidate(c(-16, -9, -2, 36, 36, 26, -20, 25, -40, 20, -4, 12, -26, 35, 37)), -14196)){quit('no', 1)}\n    if(!identical(candidate(c(-1, -3, 17, -1, -15, 13, -1, 14, -14, -12, -5, 14, -14, 6, 13, 11, 16, 16, 4, 10)), -1448)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_40_triples_sum_to_zero",
    "language": "r",
    "prompt": "# triples_sum_to_zero takes a list of integers as an input.\n# it returns TRUE if there are three distinct elements in the list that\n# sum to zero, and FALSE otherwise.\n# >>> triples_sum_to_zero(c(1, 3, 5, 0))\n# FALSE\n# >>> triples_sum_to_zero(c(1, 3, -2, 1))\n# TRUE\n# >>> triples_sum_to_zero(c(1, 2, 3, 7))\n# FALSE\n# >>> triples_sum_to_zero(c(2, 4, -5, 3, 9, 7))\n# TRUE\n# >>> triples_sum_to_zero(c(1))\n# FALSE\ntriples_sum_to_zero <- function(l) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_40_triples_sum_to_zero.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- triples_sum_to_zero\n    if(!identical(candidate(c(1, 3, 5, 0)), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 3, 5, -1)), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 3, -2, 1)), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3, 7)), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 5, 7)), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(2, 4, -5, 3, 9, 7)), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(1)), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 3, 5, -100)), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(100, 3, 5, -100)), FALSE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_56_correct_bracketing",
    "language": "r",
    "prompt": "# brackets is a string of \"<\" and \">\".\n# return TRUE if every opening bracket has a corresponding closing bracket.\n# >>> correct_bracketing('<')\n# FALSE\n# >>> correct_bracketing('<>')\n# TRUE\n# >>> correct_bracketing('<<><>>')\n# TRUE\n# >>> correct_bracketing('><<>')\n# FALSE\ncorrect_bracketing <- function(brackets) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_56_correct_bracketing.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- correct_bracketing\n    if(!identical(candidate('<>'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('<<><>>'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('<><><<><>><>'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('<><><<<><><>><>><<><><<>>>'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('<<<><>>>>'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('><<>'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('<'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('<<<<'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('>'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('<<>'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('<><><<><>><>><<>'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('<><><<><>><>>><>'), FALSE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_146_specialFilter",
    "language": "r",
    "prompt": "# Write a function that takes a vector of numbers as input and returns \n# the number of elements in the vector that are greater than 10 and both \n# first and last digits of a number are odd (1, 3, 5, 7, 9).\n# For example:\n# >>> specialFilter(c(15, -73, 14, -15))\n# 1\n# >>> specialFilter(c(33, -2, -3, 45, 21, 109))\n# 2\nspecialFilter <- function(nums) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_146_specialFilter.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- specialFilter\n    if(!identical(candidate(c(5, -2, 1, -5)), 0)){quit('no', 1)}\n    if(!identical(candidate(c(15, -73, 14, -15)), 1)){quit('no', 1)}\n    if(!identical(candidate(c(33, -2, -3, 45, 21, 109)), 2)){quit('no', 1)}\n    if(!identical(candidate(c(43, -12, 93, 125, 121, 109)), 4)){quit('no', 1)}\n    if(!identical(candidate(c(71, -2, -33, 75, 21, 19)), 3)){quit('no', 1)}\n    if(!identical(candidate(c(1)), 0)){quit('no', 1)}\n    if(!identical(candidate(c()), 0)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_95_check_dict_case",
    "language": "r",
    "prompt": "# Given a named list, return TRUE if all keys are strings in lower \n# case or all keys are strings in upper case, else return FALSE.\n# The function should return FALSE is the given named list is empty.\n# Examples:\n# >>> check_dict_case(list('a' = 'apple', 'b' = 'banana'))\n# TRUE\n# >>> check_dict_case(list('a' = 'apple', 'A' = 'banana', 'B' = 'banana'))\n# FALSE\n# >>> check_dict_case(list('a' = 'apple', 8 = 'banana', 'a' = 'apple'))\n# FALSE\n# >>> check_dict_case(list('Name' = 'John', 'Age' = '36', 'City' = 'Houston'))\n# FALSE\n# >>> check_dict_case(list('STATE' = 'NC', 'ZIP' = '12345'))\n# TRUE\ncheck_dict_case <- function(dict) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_95_check_dict_case.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- check_dict_case\n    if(!identical(candidate(list('p' = 'pineapple', 'b' = 'banana')), TRUE)){quit('no', 1)}\n    if(!identical(candidate(list('p' = 'pineapple', 'A' = 'banana', 'B' = 'banana')), FALSE)){quit('no', 1)}\n    if(!identical(candidate(list('p' = 'pineapple', '5' = 'banana', 'a' = 'apple')), FALSE)){quit('no', 1)}\n    if(!identical(candidate(list('Name' = 'John', 'Age' = '36', 'City' = 'Houston')), FALSE)){quit('no', 1)}\n    if(!identical(candidate(list('STATE' = 'NC', 'ZIP' = '12345')), TRUE)){quit('no', 1)}\n    if(!identical(candidate(list('fruit' = 'Orange', 'taste' = 'Sweet')), TRUE)){quit('no', 1)}\n    if(!identical(candidate(list()), FALSE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_125_split_words",
    "language": "r",
    "prompt": "# Given a string of words, return a list of words split on whitespace, if no whitespaces exists in the text you\n# should split on commas ',' if no commas exists you should return the number of lower-case letters with odd order in the\n# alphabet, ord('a') = 0, ord('b') = 1, ... ord('z') = 25\n# Examples\n# >>> split_words('Hello world!')\n# list('Hello', 'world!')\n# >>> split_words('Hello,world!')\n# list('Hello', 'world!')\n# >>> split_words('abcdef')\n# 3\nsplit_words <- function(txt) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_125_split_words.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- split_words\n    if(!identical(candidate('Hello world!'), list('Hello', 'world!'))){quit('no', 1)}\n    if(!identical(candidate('Hello,world!'), list('Hello', 'world!'))){quit('no', 1)}\n    if(!identical(candidate('Hello world,!'), list('Hello', 'world,!'))){quit('no', 1)}\n    if(!identical(candidate('Hello,Hello,world !'), list('Hello,Hello,world', '!'))){quit('no', 1)}\n    if(!identical(candidate('abcdef'), 3)){quit('no', 1)}\n    if(!identical(candidate('aaabb'), 2)){quit('no', 1)}\n    if(!identical(candidate('aaaBb'), 1)){quit('no', 1)}\n    if(!identical(candidate(''), 0)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_63_fibfib",
    "language": "r",
    "prompt": "# The FibFib number sequence is a sequence similar to the Fibbonacci sequnece that's defined as follows:\n# fibfib(0) == 0\n# fibfib(1) == 0\n# fibfib(2) == 1\n# fibfib(n) == fibfib(n-1) + fibfib(n-2) + fibfib(n-3).\n# Please write a function to efficiently compute the n-th element of the fibfib number sequence.\n# >>> fibfib(1)\n# 0\n# >>> fibfib(5)\n# 4\n# >>> fibfib(8)\n# 24\nfibfib <- function(n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_63_fibfib.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- fibfib\n    if(!identical(candidate(2), 1)){quit('no', 1)}\n    if(!identical(candidate(1), 0)){quit('no', 1)}\n    if(!identical(candidate(5), 4)){quit('no', 1)}\n    if(!identical(candidate(8), 24)){quit('no', 1)}\n    if(!identical(candidate(10), 81)){quit('no', 1)}\n    if(!identical(candidate(12), 274)){quit('no', 1)}\n    if(!identical(candidate(14), 927)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_133_sum_squares",
    "language": "r",
    "prompt": "# You are given a list of numbers.\n# You need to return the sum of squared numbers in the given list,\n# round each element in the list to the upper int(Ceiling) first.\n# Examples:\n# >>> lst(c(1.0, 2.0, 3.0))\n# 14\n# >>> lst(c(1.0, 4.0, 9.0))\n# 98\n# >>> lst(c(1.0, 3.0, 5.0, 7.0))\n# 84\n# >>> lst(c(1.4, 4.2, 0.0))\n# 29\n# >>> lst(c(-2.4, 1.0, 1.0))\n# 6\nsum_squares <- function(lst) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_133_sum_squares.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- sum_squares\n    if(!identical(candidate(c(1.0, 2.0, 3.0)), 14)){quit('no', 1)}\n    if(!identical(candidate(c(1.0, 2.0, 3.0)), 14)){quit('no', 1)}\n    if(!identical(candidate(c(1.0, 3.0, 5.0, 7.0)), 84)){quit('no', 1)}\n    if(!identical(candidate(c(1.4, 4.2, 0.0)), 29)){quit('no', 1)}\n    if(!identical(candidate(c(-2.4, 1.0, 1.0)), 6)){quit('no', 1)}\n    if(!identical(candidate(c(100.0, 1.0, 15.0, 2.0)), 10230)){quit('no', 1)}\n    if(!identical(candidate(c(10000.0, 10000.0)), 200000000)){quit('no', 1)}\n    if(!identical(candidate(c(-1.4, 4.6, 6.3)), 75)){quit('no', 1)}\n    if(!identical(candidate(c(-1.4, 17.9, 18.9, 19.9)), 1086)){quit('no', 1)}\n    if(!identical(candidate(c(0.0)), 0)){quit('no', 1)}\n    if(!identical(candidate(c(-1.0)), 1)){quit('no', 1)}\n    if(!identical(candidate(c(-1.0, 1.0, 0.0)), 2)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_85_add",
    "language": "r",
    "prompt": "# Given a non-empty list of integers lst. add the even elements that are at odd indices..\n# Examples:\n# >>> add(c(4, 2, 6, 7))\n# 2\nadd <- function(lst) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_85_add.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- add\n    if(!identical(candidate(c(4, 88)), 88)){quit('no', 1)}\n    if(!identical(candidate(c(4, 5, 6, 7, 2, 122)), 122)){quit('no', 1)}\n    if(!identical(candidate(c(4, 0, 6, 7)), 0)){quit('no', 1)}\n    if(!identical(candidate(c(4, 4, 6, 8)), 12)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_34_unique",
    "language": "r",
    "prompt": "# Return sorted unique elements in a list\n# >>> unique(c(5, 3, 5, 2, 3, 3, 9, 0, 123))\n# list(0, 2, 3, 5, 9, 123)\nunique <- function(l) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_34_unique.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- unique\n    if(!identical(candidate(c(5, 3, 5, 2, 3, 3, 9, 0, 123)), list(0, 2, 3, 5, 9, 123))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_140_fix_spaces",
    "language": "r",
    "prompt": "# Given a string text, replace all spaces in it with underscores, \n# and if a string has more than 2 consecutive spaces, \n# then replace all consecutive spaces with - \n# >>> fix_spaces(' Example')\n# 'Example'\n# >>> fix_spaces(' Example 1')\n# 'Example_1'\n# >>> fix_spaces(' Example 2')\n# '_Example_2'\n# >>> fix_spaces(' Example 3')\n# '_Example-3'\nfix_spaces <- function(text) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_140_fix_spaces.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- fix_spaces\n    if(!identical(candidate('Example'), 'Example')){quit('no', 1)}\n    if(!identical(candidate('Mudasir Hanif '), 'Mudasir_Hanif_')){quit('no', 1)}\n    if(!identical(candidate('Yellow Yellow  Dirty  Fellow'), 'Yellow_Yellow__Dirty__Fellow')){quit('no', 1)}\n    if(!identical(candidate('Exa   mple'), 'Exa-mple')){quit('no', 1)}\n    if(!identical(candidate('   Exa 1 2 2 mple'), '-Exa_1_2_2_mple')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_49_modp",
    "language": "r",
    "prompt": "# Return 2^n modulo p (be aware of numerics).\n# >>> modp(3, 5)\n# 3\n# >>> modp(1101, 101)\n# 2\n# >>> modp(0, 101)\n# 1\n# >>> modp(3, 11)\n# 8\n# >>> modp(100, 101)\n# 1\nmodp <- function(n, p) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_49_modp.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- modp\n    if(!identical(candidate(3, 5), 3)){quit('no', 1)}\n    if(!identical(candidate(1101, 101), 2)){quit('no', 1)}\n    if(!identical(candidate(0, 101), 1)){quit('no', 1)}\n    if(!identical(candidate(3, 11), 8)){quit('no', 1)}\n    if(!identical(candidate(100, 101), 1)){quit('no', 1)}\n    if(!identical(candidate(30, 5), 4)){quit('no', 1)}\n    if(!identical(candidate(31, 5), 3)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_124_valid_date",
    "language": "r",
    "prompt": "# You have to write a function which validates a given date string and\n# returns TRUE if the date is valid otherwise FALSE.\n# The date is valid if all of the following rules are satisfied:\n# 1. The date string is not empty.\n# 2. The number of days is not less than 1 or higher than 31 days for months 1,3,5,7,8,10,12. And the number of days is not less than 1 or higher than 30 days for months 4,6,9,11. And, the number of days is not less than 1 or higher than 29 for the month 2.\n# 3. The months should not be less than 1 or higher than 12.\n# 4. The date should be in the format: mm-dd-yyyy\n# >>> valid_date('03-11-2000')\n# TRUE\n# >>> valid_date('15-01-2012')\n# FALSE\n# >>> valid_date('04-0-2040')\n# FALSE\n# >>> valid_date('06-04-2020')\n# TRUE\n# >>> valid_date('06/04/2020')\n# FALSE\nvalid_date <- function(date) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_124_valid_date.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- valid_date\n    if(!identical(candidate('03-11-2000'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('15-01-2012'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('04-0-2040'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('06-04-2020'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('01-01-2007'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('03-32-2011'), FALSE)){quit('no', 1)}\n    if(!identical(candidate(''), FALSE)){quit('no', 1)}\n    if(!identical(candidate('04-31-3000'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('06-06-2005'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('21-31-2000'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('04-12-2003'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('04122003'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('20030412'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('2003-04'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('2003-04-12'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('04-2003'), FALSE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_86_anti_shuffle",
    "language": "r",
    "prompt": "# Write a function that takes a string and returns an ordered version of it.\n# Ordered version of string, is a string where all words (separated by space)\n# are replaced by a new word where all the characters arranged in\n# ascending order based on ascii value.\n# Note: You should keep the order of words and blank spaces in the sentence.\n# For example:\n# >>> anti_shuffle('Hi')\n# 'Hi'\n# >>> anti_shuffle('hello')\n# 'ehllo'\n# >>> anti_shuffle('Hello World!!!')\n# 'Hello !!!Wdlor'\nanti_shuffle <- function(s) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_86_anti_shuffle.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- anti_shuffle\n    if(!identical(candidate('Hi'), 'Hi')){quit('no', 1)}\n    if(!identical(candidate('hello'), 'ehllo')){quit('no', 1)}\n    if(!identical(candidate('number'), 'bemnru')){quit('no', 1)}\n    if(!identical(candidate('abcd'), 'abcd')){quit('no', 1)}\n    if(!identical(candidate('Hello World!!!'), 'Hello !!!Wdlor')){quit('no', 1)}\n    if(!identical(candidate(''), '')){quit('no', 1)}\n    if(!identical(candidate('Hi. My name is Mister Robot. How are you?'), '.Hi My aemn is Meirst .Rboot How aer ?ouy')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_126_is_sorted",
    "language": "r",
    "prompt": "# Given a list of numbers, return whether or not they are sorted\n# in ascending order. If list has more than 1 duplicate of the same\n# number, return FALSE. Assume no negative numbers and only integers.\n# Examples\n# >>> is_sorted(c(5))\n# TRUE\n# >>> is_sorted(c(1, 2, 3, 4, 5))\n# TRUE\n# >>> is_sorted(c(1, 3, 2, 4, 5))\n# FALSE\n# >>> is_sorted(c(1, 2, 3, 4, 5, 6))\n# TRUE\n# >>> is_sorted(c(1, 2, 3, 4, 5, 6, 7))\n# TRUE\n# >>> is_sorted(c(1, 3, 2, 4, 5, 6, 7))\n# FALSE\n# >>> is_sorted(c(1, 2, 2, 3, 3, 4))\n# TRUE\n# >>> is_sorted(c(1, 2, 2, 2, 3, 4))\n# FALSE\nis_sorted <- function(lst) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_126_is_sorted.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- is_sorted\n    if(!identical(candidate(c(5)), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3, 4, 5)), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 3, 2, 4, 5)), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3, 4, 5, 6)), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3, 4, 5, 6, 7)), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 3, 2, 4, 5, 6, 7)), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c()), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(1)), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(3, 2, 1)), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 2, 2, 3, 4)), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3, 3, 3, 4)), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 2, 3, 3, 4)), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3, 4)), TRUE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_80_is_happy",
    "language": "r",
    "prompt": "# You are given a string s.\n# Your task is to check if the string is hapr or not.\n# A string is hapr if its length is at least 3 and every 3 consecutive letters are distinct\n# For example:\n# >>> is_happy('a')\n# FALSE\n# >>> is_happy('aa')\n# FALSE\n# >>> is_happy('abcd')\n# TRUE\n# >>> is_happy('aabb')\n# FALSE\n# >>> is_happy('adb')\n# TRUE\n# >>> is_happy('xyy')\n# FALSE\nis_happy <- function(s) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_80_is_happy.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- is_happy\n    if(!identical(candidate('a'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('aa'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('abcd'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('aabb'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('adb'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('xyy'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('iopaxpoi'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('iopaxioi'), FALSE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_72_will_it_fly",
    "language": "r",
    "prompt": "# Write a function that returns TRUE if the object q will fly, and FALSE otherwise.\n# The object q will fly if it's balanced (it is a palindromic list) and the sum of its elements is less than or equal the maximum possible weight w.\n# Example:\n# >>> will_it_fly(c(1, 2), 5)\n# FALSE\n# # 1+2 is less than the maximum possible weight, but it's unbalanced.\n# >>> will_it_fly(c(3, 2, 3), 1)\n# FALSE\n# # it's balanced, but 3+2+3 is more than the maximum possible weight.\n# >>> will_it_fly(c(3, 2, 3), 9)\n# TRUE\n# # 3+2+3 is less than the maximum possible weight, and it's balanced.\n# >>> will_it_fly(c(3), 5)\n# TRUE\n# # 3 is less than the maximum possible weight, and it's balanced.\nwill_it_fly <- function(q, w) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_72_will_it_fly.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- will_it_fly\n    if(!identical(candidate(c(3, 2, 3), 9), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 2), 5), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(3), 5), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(3, 2, 3), 1), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3), 6), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(5), 5), TRUE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_88_sort_array",
    "language": "r",
    "prompt": "# Given a vector of non-negative integers, return a cor of the given vector after sorting,\n# you will sort the given vector in ascending order if the sum( first index value, last index value) is odd,\n# or sort it in descending order if the sum( first index value, last index value) is even.\n# Note:\n# * don't change the given vector.\n# Examples:\n# >>> sort_array(c())\n# list()\n# >>> sort_array(c(5))\n# list(5)\n# >>> sort_array(c(2, 4, 3, 0, 1, 5))\n# list(0, 1, 2, 3, 4, 5)\n# >>> sort_array(c(2, 4, 3, 0, 1, 5, 6))\n# list(6, 5, 4, 3, 2, 1, 0)\nsort_array <- function(array) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_88_sort_array.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- sort_array\n    if(!identical(candidate(c()), list())){quit('no', 1)}\n    if(!identical(candidate(c(5)), list(5))){quit('no', 1)}\n    if(!identical(candidate(c(2, 4, 3, 0, 1, 5)), list(0, 1, 2, 3, 4, 5))){quit('no', 1)}\n    if(!identical(candidate(c(2, 4, 3, 0, 1, 5, 6)), list(6, 5, 4, 3, 2, 1, 0))){quit('no', 1)}\n    if(!identical(candidate(c(2, 1)), list(1, 2))){quit('no', 1)}\n    if(!identical(candidate(c(15, 42, 87, 32, 11, 0)), list(0, 11, 15, 32, 42, 87))){quit('no', 1)}\n    if(!identical(candidate(c(21, 14, 23, 11)), list(23, 21, 14, 11))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_96_count_up_to",
    "language": "r",
    "prompt": "# Implement a function that takes an non-negative integer and returns a vector of the first n\n# integers that are prime numbers and less than n.\n# for example:\n# >>> count_up_to(5)\n# list(2, 3)\n# >>> count_up_to(11)\n# list(2, 3, 5, 7)\n# >>> count_up_to(0)\n# list()\n# >>> count_up_to(20)\n# list(2, 3, 5, 7, 11, 13, 17, 19)\n# >>> count_up_to(1)\n# list()\n# >>> count_up_to(18)\n# list(2, 3, 5, 7, 11, 13, 17)\ncount_up_to <- function(n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_96_count_up_to.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- count_up_to\n    if(!identical(candidate(5), list(2, 3))){quit('no', 1)}\n    if(!identical(candidate(6), list(2, 3, 5))){quit('no', 1)}\n    if(!identical(candidate(7), list(2, 3, 5))){quit('no', 1)}\n    if(!identical(candidate(10), list(2, 3, 5, 7))){quit('no', 1)}\n    if(!identical(candidate(0), list())){quit('no', 1)}\n    if(!identical(candidate(22), list(2, 3, 5, 7, 11, 13, 17, 19))){quit('no', 1)}\n    if(!identical(candidate(1), list())){quit('no', 1)}\n    if(!identical(candidate(18), list(2, 3, 5, 7, 11, 13, 17))){quit('no', 1)}\n    if(!identical(candidate(47), list(2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43))){quit('no', 1)}\n    if(!identical(candidate(101), list(2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67, 71, 73, 79, 83, 89, 97))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_12_longest",
    "language": "r",
    "prompt": "# Out of list of strings, return the longest one. Return the first one in case of multiple\n# strings of the same length. Return NULL in case the input list is empty.\n# >>> longest(c())\n# NULL\n# >>> longest(c('a', 'b', 'c'))\n# 'a'\n# >>> longest(c('a', 'bb', 'ccc'))\n# 'ccc'\nlongest <- function(strings) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_12_longest.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- longest\n    if(!identical(candidate(c()), NULL)){quit('no', 1)}\n    if(!identical(candidate(c('x', 'y', 'z')), 'x')){quit('no', 1)}\n    if(!identical(candidate(c('x', 'yyy', 'zzzz', 'www', 'kkkk', 'abc')), 'zzzz')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_105_by_length",
    "language": "r",
    "prompt": "# Given a vector of integers, sort the integers that are between 1 and 9 inclusive,\n# reverse the resulting vector, and then replace each digit by its corresponding name from\n# \"One\", \"Two\", \"Three\", \"Four\", \"Five\", \"Six\", \"Seven\", \"Eight\", \"Nine\".\n# For example:\n# >>> by_length(c(2, 1, 1, 4, 5, 8, 2, 3))\n# list('Eight', 'Five', 'Four', 'Three', 'Two', 'Two', 'One', 'One')\n# If the vector is empty, return an empty vector:\n# >>> by_length(c())\n# list()\n# If the vector has any strange number ignore it:\n# >>> by_length(c(1, -1, 55))\n# list('One')\nby_length <- function(arr) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_105_by_length.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- by_length\n    if(!identical(candidate(c(2, 1, 1, 4, 5, 8, 2, 3)), list('Eight', 'Five', 'Four', 'Three', 'Two', 'Two', 'One', 'One'))){quit('no', 1)}\n    if(!identical(candidate(c()), list())){quit('no', 1)}\n    if(!identical(candidate(c(1, -1, 55)), list('One'))){quit('no', 1)}\n    if(!identical(candidate(c(1, -1, 3, 2)), list('Three', 'Two', 'One'))){quit('no', 1)}\n    if(!identical(candidate(c(9, 4, 8)), list('Nine', 'Eight', 'Four'))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_106_f",
    "language": "r",
    "prompt": "# Implement the function f that takes n as a parameter,\n# and returns a list of size n, such that the value of the element at index i is the factorial of i if i is even\n# or the sum of numbers from 1 to i otherwise.\n# i starts from 1.\n# the factorial of i is the multiplication of the numbers from 1 to i (1 * 2 * ... * i).\n# Example:\n# >>> f(5)\n# list(1, 2, 6, 24, 15)\nf <- function(n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_106_f.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- f\n    if(!identical(candidate(5), list(1, 2, 6, 24, 15))){quit('no', 1)}\n    if(!identical(candidate(7), list(1, 2, 6, 24, 15, 720, 28))){quit('no', 1)}\n    if(!identical(candidate(1), list(1))){quit('no', 1)}\n    if(!identical(candidate(3), list(1, 2, 6))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_36_fizz_buzz",
    "language": "r",
    "prompt": "# Return the number of times the digit 7 appears in integers less than n which are divisible by 11 or 13.\n# >>> fizz_buzz(50)\n# 0\n# >>> fizz_buzz(78)\n# 2\n# >>> fizz_buzz(79)\n# 3\nfizz_buzz <- function(n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_36_fizz_buzz.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- fizz_buzz\n    if(!identical(candidate(50), 0)){quit('no', 1)}\n    if(!identical(candidate(78), 2)){quit('no', 1)}\n    if(!identical(candidate(79), 3)){quit('no', 1)}\n    if(!identical(candidate(100), 3)){quit('no', 1)}\n    if(!identical(candidate(200), 6)){quit('no', 1)}\n    if(!identical(candidate(4000), 192)){quit('no', 1)}\n    if(!identical(candidate(10000), 639)){quit('no', 1)}\n    if(!identical(candidate(100000), 8026)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_2_truncate_number",
    "language": "r",
    "prompt": "# Given a positive floating point number, it can be decomposed into\n# and integer part (largest integer smaller than given number) and decimals\n# (leftover part always smaller than 1).\n# Return the decimal part of the number.\n# >>> truncate_number(3.5)\n# 0.5\ntruncate_number <- function(number) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_2_truncate_number.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- truncate_number\n    if(!identical(candidate(3.5), 0.5)){quit('no', 1)}\n    if(!identical(candidate(1.25), 0.25)){quit('no', 1)}\n    if(!identical(candidate(123.0), 0.0)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_8_sum_product",
    "language": "r",
    "prompt": "# For a given list of integers, return a list consisting of a sum and a product of all the integers in a list.\n# Empty sum should be equal to 0 and empty product should be equal to 1.\n# >>> sum_product(c())\n# list(0, 1)\n# >>> sum_product(c(1, 2, 3, 4))\n# list(10, 24)\nsum_product <- function(numbers) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_8_sum_product.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- sum_product\n    if(!identical(candidate(c()), list(0, 1))){quit('no', 1)}\n    if(!identical(candidate(c(1, 1, 1)), list(3, 1))){quit('no', 1)}\n    if(!identical(candidate(c(100, 0)), list(100, 0))){quit('no', 1)}\n    if(!identical(candidate(c(3, 5, 7)), list(15, 105))){quit('no', 1)}\n    if(!identical(candidate(c(10)), list(10, 10))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_87_get_row",
    "language": "r",
    "prompt": "# You are given a 2 dimensional data, as a nested lists,\n# which is similar to matrix, however, unlike matrices,\n# each row may contain a different number of columns.\n# Given lst, and integer x, find integers x in the list,\n# and return list of lists, [(x1, y1), (x2, y2) ...] such that\n# each list is a coordinate - (row, columns), starting with 0.\n# Sort coordinates initially by rows in ascending order.\n# Also, sort coordinates of the row by columns in descending order.\n# Examples:\n# >>> get_row(list(list(1, 2, 3, 4, 5, 6), list(1, 2, 3, 4, 1, 6), list(1, 2, 3, 4, 5, 1)), 1)\n# list(list(0, 0), list(1, 4), list(1, 0), list(2, 5), list(2, 0))\n# >>> get_row(list(), 1)\n# list()\n# >>> get_row(list(list(), list(1), list(1, 2, 3)), 3)\n# list(list(2, 2))\nget_row <- function(lst, x) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_87_get_row.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- get_row\n    if(!identical(candidate(list(list(1, 2, 3, 4, 5, 6), list(1, 2, 3, 4, 1, 6), list(1, 2, 3, 4, 5, 1)), 1), list(list(0, 0), list(1, 4), list(1, 0), list(2, 5), list(2, 0)))){quit('no', 1)}\n    if(!identical(candidate(list(list(1, 2, 3, 4, 5, 6), list(1, 2, 3, 4, 5, 6), list(1, 2, 3, 4, 5, 6), list(1, 2, 3, 4, 5, 6), list(1, 2, 3, 4, 5, 6), list(1, 2, 3, 4, 5, 6)), 2), list(list(0, 1), list(1, 1), list(2, 1), list(3, 1), list(4, 1), list(5, 1)))){quit('no', 1)}\n    if(!identical(candidate(list(list(1, 2, 3, 4, 5, 6), list(1, 2, 3, 4, 5, 6), list(1, 1, 3, 4, 5, 6), list(1, 2, 1, 4, 5, 6), list(1, 2, 3, 1, 5, 6), list(1, 2, 3, 4, 1, 6), list(1, 2, 3, 4, 5, 1)), 1), list(list(0, 0), list(1, 0), list(2, 1), list(2, 0), list(3, 2), list(3, 0), list(4, 3), list(4, 0), list(5, 4), list(5, 0), list(6, 5), list(6, 0)))){quit('no', 1)}\n    if(!identical(candidate(list(), 1), list())){quit('no', 1)}\n    if(!identical(candidate(list(list(1)), 2), list())){quit('no', 1)}\n    if(!identical(candidate(list(list(), list(1), list(1, 2, 3)), 3), list(list(2, 2)))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_159_eat",
    "language": "r",
    "prompt": "# You're a hungry rabbit, and you already have eaten a certain number of carrots,\n# but now you need to eat more carrots to complete the day's meals.\n# you should return a vector of [ total number of eaten carrots after your meals,\n# the number of carrots left after your meals ]\n# if there are not enough remaining carrots, you will eat all remaining carrots, but will still be hungry.\n# Example:\n# >>> eat(5, 6, 10)\n# list(11, 4)\n# >>> eat(4, 8, 9)\n# list(12, 1)\n# >>> eat(1, 10, 10)\n# list(11, 0)\n# >>> eat(2, 11, 5)\n# list(7, 0)\n# Variables:\n# @number : integer\n# the number of carrots that you have eaten.\n# @need : integer\n# the number of carrots that you need to eat.\n# @remaining : integer\n# the number of remaining carrots thet exist in stock\n# Constrain:\n# * 0 <= number <= 1000\n# * 0 <= need <= 1000\n# * 0 <= remaining <= 1000\n# Have fun :)\neat <- function(number, need, remaining) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_159_eat.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- eat\n    if(!identical(candidate(5, 6, 10), list(11, 4))){quit('no', 1)}\n    if(!identical(candidate(4, 8, 9), list(12, 1))){quit('no', 1)}\n    if(!identical(candidate(1, 10, 10), list(11, 0))){quit('no', 1)}\n    if(!identical(candidate(2, 11, 5), list(7, 0))){quit('no', 1)}\n    if(!identical(candidate(4, 5, 7), list(9, 2))){quit('no', 1)}\n    if(!identical(candidate(4, 5, 1), list(5, 0))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_84_solve",
    "language": "r",
    "prompt": "# Given a positive integer N, return the total sum of its digits in binary.\n# Example\n# >>> solve(1000)\n# '1'\n# >>> solve(150)\n# '110'\n# >>> solve(147)\n# '1100'\n# Variables:\n# @N integer\n# Constraints: 0 \u2264 N \u2264 10000.\n# Output:\n# a string of binary number\nsolve <- function(N) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_84_solve.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- solve\n    if(!identical(candidate(1000), '1')){quit('no', 1)}\n    if(!identical(candidate(150), '110')){quit('no', 1)}\n    if(!identical(candidate(147), '1100')){quit('no', 1)}\n    if(!identical(candidate(333), '1001')){quit('no', 1)}\n    if(!identical(candidate(963), '10010')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_94_skjkasdkd",
    "language": "r",
    "prompt": "# You are given a list of integers.\n# You need to find the largest prime value and return the sum of its digits.\n# Examples:\n# >>> skjkasdkd(c(0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3))\n# 10\n# >>> skjkasdkd(c(1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1))\n# 25\n# >>> skjkasdkd(c(1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3))\n# 13\n# >>> skjkasdkd(c(0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6))\n# 11\n# >>> skjkasdkd(c(0, 81, 12, 3, 1, 21))\n# 3\n# >>> skjkasdkd(c(0, 8, 1, 2, 1, 7))\n# 7\nskjkasdkd <- function(lst) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_94_skjkasdkd.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- skjkasdkd\n    if(!identical(candidate(c(0, 3, 2, 1, 3, 5, 7, 4, 5, 5, 5, 2, 181, 32, 4, 32, 3, 2, 32, 324, 4, 3)), 10)){quit('no', 1)}\n    if(!identical(candidate(c(1, 0, 1, 8, 2, 4597, 2, 1, 3, 40, 1, 2, 1, 2, 4, 2, 5, 1)), 25)){quit('no', 1)}\n    if(!identical(candidate(c(1, 3, 1, 32, 5107, 34, 83278, 109, 163, 23, 2323, 32, 30, 1, 9, 3)), 13)){quit('no', 1)}\n    if(!identical(candidate(c(0, 724, 32, 71, 99, 32, 6, 0, 5, 91, 83, 0, 5, 6)), 11)){quit('no', 1)}\n    if(!identical(candidate(c(0, 81, 12, 3, 1, 21)), 3)){quit('no', 1)}\n    if(!identical(candidate(c(0, 8, 1, 2, 1, 7)), 7)){quit('no', 1)}\n    if(!identical(candidate(c(8191)), 19)){quit('no', 1)}\n    if(!identical(candidate(c(8191, 123456, 127, 7)), 19)){quit('no', 1)}\n    if(!identical(candidate(c(127, 97, 8192)), 10)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_73_smallest_change",
    "language": "r",
    "prompt": "# Given a vector arr of integers, find the minimum number of elements that\n# need to be changed to make the vector palindromic. A palindromic vector is a vector that\n# is read the same backwards and forwards. In one change, you can change one element to any other element.\n# For example:\n# >>> smallest_change(c(1, 2, 3, 5, 4, 7, 9, 6))\n# 4\n# >>> smallest_change(c(1, 2, 3, 4, 3, 2, 2))\n# 1\n# >>> smallest_change(c(1, 2, 3, 2, 1))\n# 0\nsmallest_change <- function(arr) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_73_smallest_change.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- smallest_change\n    if(!identical(candidate(c(1, 2, 3, 5, 4, 7, 9, 6)), 4)){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3, 4, 3, 2, 2)), 1)){quit('no', 1)}\n    if(!identical(candidate(c(1, 4, 2)), 1)){quit('no', 1)}\n    if(!identical(candidate(c(1, 4, 4, 2)), 1)){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, 3, 2, 1)), 0)){quit('no', 1)}\n    if(!identical(candidate(c(3, 1, 1, 3)), 0)){quit('no', 1)}\n    if(!identical(candidate(c(1)), 0)){quit('no', 1)}\n    if(!identical(candidate(c(0, 1)), 1)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_81_numerical_letter_grade",
    "language": "r",
    "prompt": "# It is the last week of the semester and the teacher has to give the grades\n# to students. The teacher has been making her own algorithm for grading.\n# The only problem is, she has lost the code she used for grading.\n# She has given you a list of GPAs for some students and you have to write \n# a function that can output a list of letter grades using the following table:\n# GPA       |    Letter grade\n# 4.0                A+\n# > 3.7                A \n# > 3.3                A- \n# > 3.0                B+\n# > 2.7                B \n# > 2.3                B-\n# > 2.0                C+\n# > 1.7                C\n# > 1.3                C-\n# > 1.0                D+ \n# > 0.7                D \n# > 0.0                D-\n# 0.0                E\n# Example:\n# >>> grade_equation(c(4.0, 3, 1.7, 2, 3.5))\n# list('A+', 'B', 'C-', 'C', 'A-')\nnumerical_letter_grade <- function(grades) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_81_numerical_letter_grade.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- numerical_letter_grade\n    if(!identical(candidate(c(4.0, 3, 1.7, 2, 3.5)), list('A+', 'B', 'C-', 'C', 'A-'))){quit('no', 1)}\n    if(!identical(candidate(c(1.2)), list('D+'))){quit('no', 1)}\n    if(!identical(candidate(c(0.5)), list('D-'))){quit('no', 1)}\n    if(!identical(candidate(c(0.0)), list('E'))){quit('no', 1)}\n    if(!identical(candidate(c(1.0, 0.3, 1.5, 2.8, 3.3)), list('D', 'D-', 'C-', 'B', 'B+'))){quit('no', 1)}\n    if(!identical(candidate(c(0.0, 0.7)), list('E', 'D-'))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_71_triangle_area",
    "language": "r",
    "prompt": "# Given the lengths of the three sides of a triangle. Return the area of\n# the triangle rounded to 2 decimal points if the three sides form a valid triangle. \n# Otherwise return -1\n# Three sides make a valid triangle when the sum of any two sides is greater \n# than the third side.\n# Example:\n# >>> triangle_area(3, 4, 5)\n# 6.0\n# >>> triangle_area(1, 2, 10)\n# -1\ntriangle_area <- function(a, b, c) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_71_triangle_area.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- triangle_area\n    if(!identical(candidate(3, 4, 5), 6.0)){quit('no', 1)}\n    if(!identical(candidate(1, 2, 10), -1)){quit('no', 1)}\n    if(!identical(candidate(4, 8, 5), 8.18)){quit('no', 1)}\n    if(!identical(candidate(2, 2, 2), 1.73)){quit('no', 1)}\n    if(!identical(candidate(1, 2, 3), -1)){quit('no', 1)}\n    if(!identical(candidate(10, 5, 7), 16.25)){quit('no', 1)}\n    if(!identical(candidate(2, 6, 3), -1)){quit('no', 1)}\n    if(!identical(candidate(1, 1, 1), 0.43)){quit('no', 1)}\n    if(!identical(candidate(2, 2, 10), -1)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_54_same_chars",
    "language": "r",
    "prompt": "# Check if two words have the same characters.\n# >>> same_chars('eabcdzzzz', 'dddzzzzzzzddeddabc')\n# TRUE\n# >>> same_chars('abcd', 'dddddddabc')\n# TRUE\n# >>> same_chars('dddddddabc', 'abcd')\n# TRUE\n# >>> same_chars('eabcd', 'dddddddabc')\n# FALSE\n# >>> same_chars('abcd', 'dddddddabce')\n# FALSE\n# >>> same_chars('eabcdzzzz', 'dddzzzzzzzddddabc')\n# FALSE\nsame_chars <- function(s0, s1) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_54_same_chars.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- same_chars\n    if(!identical(candidate('eabcdzzzz', 'dddzzzzzzzddeddabc'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('abcd', 'dddddddabc'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('dddddddabc', 'abcd'), TRUE)){quit('no', 1)}\n    if(!identical(candidate('eabcd', 'dddddddabc'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('abcd', 'dddddddabcf'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('eabcdzzzz', 'dddzzzzzzzddddabc'), FALSE)){quit('no', 1)}\n    if(!identical(candidate('aabb', 'aaccc'), FALSE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_114_minSubArraySum",
    "language": "r",
    "prompt": "# Given a vector of integers nums, find the minimum sum of any non-empty sub-vector\n# of nums.\n# Example\n# >>> minSubArraySum(c(2, 3, 4, 1, 2, 4))\n# 1\n# >>> minSubArraySum(c(-1, -2, -3))\n# -6\nminSubArraySum <- function(nums) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_114_minSubArraySum.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- minSubArraySum\n    if(!identical(candidate(c(2, 3, 4, 1, 2, 4)), 1)){quit('no', 1)}\n    if(!identical(candidate(c(-1, -2, -3)), -6)){quit('no', 1)}\n    if(!identical(candidate(c(-1, -2, -3, 2, -10)), -14)){quit('no', 1)}\n    if(!identical(candidate(c(-9999999999999999)), -9999999999999999)){quit('no', 1)}\n    if(!identical(candidate(c(0, 10, 20, 1000000)), 0)){quit('no', 1)}\n    if(!identical(candidate(c(-1, -2, -3, 10, -5)), -6)){quit('no', 1)}\n    if(!identical(candidate(c(100, -1, -2, -3, 10, -5)), -6)){quit('no', 1)}\n    if(!identical(candidate(c(10, 11, 13, 8, 3, 4)), 3)){quit('no', 1)}\n    if(!identical(candidate(c(100, -33, 32, -1, 0, -2)), -33)){quit('no', 1)}\n    if(!identical(candidate(c(-10)), -10)){quit('no', 1)}\n    if(!identical(candidate(c(7)), 7)){quit('no', 1)}\n    if(!identical(candidate(c(1, -1)), -1)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_117_select_words",
    "language": "r",
    "prompt": "# Given a string s and a natural number n, you have been tasked to implement \n# a function that returns a list of all words from string s that contain exactly \n# n consonants, in order these words appear in the string s.\n# If the string s is empty then the function should return an empty list.\n# Note: you may assume the input string contains only letters and spaces.\n# Examples:\n# >>> select_words('Mary had a little lamb', 4)\n# list('little')\n# >>> select_words('Mary had a little lamb', 3)\n# list('Mary', 'lamb')\n# >>> select_words('simple white space', 2)\n# list()\n# >>> select_words('Hello world', 4)\n# list('world')\n# >>> select_words('Uncle sam', 3)\n# list('Uncle')\nselect_words <- function(s, n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_117_select_words.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- select_words\n    if(!identical(candidate('Mary had a little lamb', 4), list('little'))){quit('no', 1)}\n    if(!identical(candidate('Mary had a little lamb', 3), list('Mary', 'lamb'))){quit('no', 1)}\n    if(!identical(candidate('simple white space', 2), list())){quit('no', 1)}\n    if(!identical(candidate('Hello world', 4), list('world'))){quit('no', 1)}\n    if(!identical(candidate('Uncle sam', 3), list('Uncle'))){quit('no', 1)}\n    if(!identical(candidate('', 4), list())){quit('no', 1)}\n    if(!identical(candidate('a b c d e f', 1), list('b', 'c', 'd', 'f'))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_14_all_prefixes",
    "language": "r",
    "prompt": "# Return list of all prefixes from shortest to longest of the input string\n# >>> all_prefixes('abc')\n# list('a', 'ab', 'abc')\nall_prefixes <- function(string) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_14_all_prefixes.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- all_prefixes\n    if(!identical(candidate(''), list())){quit('no', 1)}\n    if(!identical(candidate('asdfgh'), list('a', 'as', 'asd', 'asdf', 'asdfg', 'asdfgh'))){quit('no', 1)}\n    if(!identical(candidate('WWW'), list('W', 'WW', 'WWW'))){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_99_closest_integer",
    "language": "r",
    "prompt": "# Create a function that takes a value (string) representing a number\n# and returns the closest integer to it. If the number is equidistant\n# from two integers, round it away from zero.\n# Examples\n# >>> closest_integer('10')\n# 10\n# >>> closest_integer('15.3')\n# 15\n# Note:\n# Rounding away from zero means that if the given number is equidistant\n# from two integers, the one you should return is the one that is the\n# farthest from zero. For example closest_integer(\"14.5\") should\n# return 15 and closest_integer(\"-14.5\") should return -15.\nclosest_integer <- function(value) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_99_closest_integer.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- closest_integer\n    if(!identical(candidate('10'), 10)){quit('no', 1)}\n    if(!identical(candidate('14.5'), 15)){quit('no', 1)}\n    if(!identical(candidate('-15.5'), -16)){quit('no', 1)}\n    if(!identical(candidate('15.3'), 15)){quit('no', 1)}\n    if(!identical(candidate('0'), 0)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_141_file_name_check",
    "language": "r",
    "prompt": "# Create a function which takes a string representing a file's name, and returns\n# 'Yes' if the the file's name is valid, and returns 'No' otherwise.\n# A file's name is considered to be valid if and only if all the following conditions \n# are met:\n# - There should not be more than three digits ('0'-'9') in the file's name.\n# - The file's name contains exactly one dot '.'\n# - The substring before the dot should not be empty, and it starts with a letter from \n# the latin alphapet ('a'-'z' and 'A'-'Z').\n# - The substring after the dot should be one of these: ['txt', 'exe', 'dll']\n# Examples:\n# >>> file_name_check('example.txt')\n# 'Yes'\n# >>> file_name_check('1example.dll')\n# 'No'\nfile_name_check <- function(file_name) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_141_file_name_check.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- file_name_check\n    if(!identical(candidate('example.txt'), 'Yes')){quit('no', 1)}\n    if(!identical(candidate('1example.dll'), 'No')){quit('no', 1)}\n    if(!identical(candidate('s1sdf3.asd'), 'No')){quit('no', 1)}\n    if(!identical(candidate('K.dll'), 'Yes')){quit('no', 1)}\n    if(!identical(candidate('MY16FILE3.exe'), 'Yes')){quit('no', 1)}\n    if(!identical(candidate('His12FILE94.exe'), 'No')){quit('no', 1)}\n    if(!identical(candidate('_Y.txt'), 'No')){quit('no', 1)}\n    if(!identical(candidate('?aREYA.exe'), 'No')){quit('no', 1)}\n    if(!identical(candidate('/this_is_valid.dll'), 'No')){quit('no', 1)}\n    if(!identical(candidate('this_is_valid.wow'), 'No')){quit('no', 1)}\n    if(!identical(candidate('this_is_valid.txt'), 'Yes')){quit('no', 1)}\n    if(!identical(candidate('this_is_valid.txtexe'), 'No')){quit('no', 1)}\n    if(!identical(candidate('#this2_i4s_5valid.ten'), 'No')){quit('no', 1)}\n    if(!identical(candidate('@this1_is6_valid.exe'), 'No')){quit('no', 1)}\n    if(!identical(candidate('this_is_12valid.6exe4.txt'), 'No')){quit('no', 1)}\n    if(!identical(candidate('all.exe.txt'), 'No')){quit('no', 1)}\n    if(!identical(candidate('I563_No.exe'), 'Yes')){quit('no', 1)}\n    if(!identical(candidate('Is3youfault.txt'), 'Yes')){quit('no', 1)}\n    if(!identical(candidate('no_one#knows.dll'), 'Yes')){quit('no', 1)}\n    if(!identical(candidate('1I563_Yes3.exe'), 'No')){quit('no', 1)}\n    if(!identical(candidate('I563_Yes3.txtt'), 'No')){quit('no', 1)}\n    if(!identical(candidate('final..txt'), 'No')){quit('no', 1)}\n    if(!identical(candidate('final132'), 'No')){quit('no', 1)}\n    if(!identical(candidate('_f4indsartal132.'), 'No')){quit('no', 1)}\n    if(!identical(candidate('.txt'), 'No')){quit('no', 1)}\n    if(!identical(candidate('s.'), 'No')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_127_intersection",
    "language": "r",
    "prompt": "# You are given two intervals,\n# where each interval is a pair of integers. For example, interval = (start, end) = (1, 2).\n# The given intervals are closed which means that the interval (start, end)\n# includes both start and end.\n# For each given interval, it is assumed that its start is less or equal its end.\n# Your task is to determine whether the length of intersection of these two \n# intervals is a prime number.\n# Example, the intersection of the intervals (1, 3), (2, 4) is (2, 3)\n# which its length is 1, which not a prime number.\n# If the length of the intersection is a prime number, return \"YES\",\n# otherwise, return \"NO\".\n# If the two intervals don't intersect, return \"NO\".\n# [input/output] samples:\n# >>> intersection(list(1, 2), list(2, 3))\n# 'NO'\n# >>> intersection(list(-1, 1), list(0, 4))\n# 'NO'\n# >>> intersection(list(-3, -1), list(-5, 5))\n# 'YES'\nintersection <- function(interval1, interval2) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_127_intersection.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- intersection\n    if(!identical(candidate(list(1, 2), list(2, 3)), 'NO')){quit('no', 1)}\n    if(!identical(candidate(list(-1, 1), list(0, 4)), 'NO')){quit('no', 1)}\n    if(!identical(candidate(list(-3, -1), list(-5, 5)), 'YES')){quit('no', 1)}\n    if(!identical(candidate(list(-2, 2), list(-4, 0)), 'YES')){quit('no', 1)}\n    if(!identical(candidate(list(-11, 2), list(-1, -1)), 'NO')){quit('no', 1)}\n    if(!identical(candidate(list(1, 2), list(3, 5)), 'NO')){quit('no', 1)}\n    if(!identical(candidate(list(1, 2), list(1, 2)), 'NO')){quit('no', 1)}\n    if(!identical(candidate(list(-2, -2), list(-3, -2)), 'NO')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_59_largest_prime_factor",
    "language": "r",
    "prompt": "# Return the largest prime factor of n. Assume n > 1 and is not a prime.\n# >>> largest_prime_factor(13195)\n# 29\n# >>> largest_prime_factor(2048)\n# 2\nlargest_prime_factor <- function(n) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_59_largest_prime_factor.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- largest_prime_factor\n    if(!identical(candidate(15), 5)){quit('no', 1)}\n    if(!identical(candidate(27), 3)){quit('no', 1)}\n    if(!identical(candidate(63), 7)){quit('no', 1)}\n    if(!identical(candidate(330), 11)){quit('no', 1)}\n    if(!identical(candidate(13195), 29)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_16_count_distinct_characters",
    "language": "r",
    "prompt": "# Given a string, find out how many distinct characters (regardless of case) does it consist of\n# >>> count_distinct_characters('xyzXYZ')\n# 3\n# >>> count_distinct_characters('Jerry')\n# 4\ncount_distinct_characters <- function(string) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_16_count_distinct_characters.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- count_distinct_characters\n    if(!identical(candidate(''), 0)){quit('no', 1)}\n    if(!identical(candidate('abcde'), 5)){quit('no', 1)}\n    if(!identical(candidate('abcdecadeCADE'), 5)){quit('no', 1)}\n    if(!identical(candidate('aaaaAAAAaaaa'), 1)){quit('no', 1)}\n    if(!identical(candidate('Jerry jERRY JeRRRY'), 5)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_3_below_zero",
    "language": "r",
    "prompt": "# You're given a list of deposit and withdrawal operations on a bank account that starts with\n# zero balance. Your task is to detect if at any point the balance of account fallls below zero, and\n# at that point function should return TRUE. Otherwise it should return FALSE.\n# >>> below_zero(c(1, 2, 3))\n# FALSE\n# >>> below_zero(c(1, 2, -4, 5))\n# TRUE\nbelow_zero <- function(operations) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_3_below_zero.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- below_zero\n    if(!identical(candidate(c()), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, -3, 1, 2, -3)), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(1, 2, -4, 5, 6)), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(1, -1, 2, -2, 5, -5, 4, -4)), FALSE)){quit('no', 1)}\n    if(!identical(candidate(c(1, -1, 2, -2, 5, -5, 4, -5)), TRUE)){quit('no', 1)}\n    if(!identical(candidate(c(1, -2, 2, -2, 5, -5, 4, -4)), TRUE)){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_10_make_palindrome",
    "language": "r",
    "prompt": "# Find the shortest palindrome that begins with a supplied string.\n# Algorithm idea is simple:\n# - Find the longest postfix of supplied string that is a palindrome.\n# - Append to the end of the string reverse of a string prefix that comes before the palindromic suffix.\n# >>> make_palindrome('')\n# ''\n# >>> make_palindrome('cat')\n# 'catac'\n# >>> make_palindrome('cata')\n# 'catac'\nmake_palindrome <- function(string) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_10_make_palindrome.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- make_palindrome\n    if(!identical(candidate(''), '')){quit('no', 1)}\n    if(!identical(candidate('x'), 'x')){quit('no', 1)}\n    if(!identical(candidate('xyz'), 'xyzyx')){quit('no', 1)}\n    if(!identical(candidate('xyx'), 'xyx')){quit('no', 1)}\n    if(!identical(candidate('jerry'), 'jerryrrej')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  },
  {
    "name": "HumanEval_156_int_to_mini_roman",
    "language": "r",
    "prompt": "# Given a positive integer, obtain its roman numeral equivalent as a string,\n# and return it in lowercase.\n# Restrictions: 1 <= num <= 1000\n# Examples:\n# >>> int_to_mini_roman(19)\n# 'xix'\n# >>> int_to_mini_roman(152)\n# 'clii'\n# >>> int_to_mini_roman(426)\n# 'cdxxvi'\nint_to_mini_roman <- function(number) {",
    "doctests": "transform",
    "original": "/home/arjun/repos/MultiPL-E/datasets/../datasets/originals-with-cleaned-doctests/HumanEval_156_int_to_mini_roman.py",
    "prompt_terminology": "reworded",
    "tests": "test_humaneval <- function() {\ncandidate <- int_to_mini_roman\n    if(!identical(candidate(19), 'xix')){quit('no', 1)}\n    if(!identical(candidate(152), 'clii')){quit('no', 1)}\n    if(!identical(candidate(251), 'ccli')){quit('no', 1)}\n    if(!identical(candidate(426), 'cdxxvi')){quit('no', 1)}\n    if(!identical(candidate(500), 'd')){quit('no', 1)}\n    if(!identical(candidate(1), 'i')){quit('no', 1)}\n    if(!identical(candidate(4), 'iv')){quit('no', 1)}\n    if(!identical(candidate(43), 'xliii')){quit('no', 1)}\n    if(!identical(candidate(90), 'xc')){quit('no', 1)}\n    if(!identical(candidate(94), 'xciv')){quit('no', 1)}\n    if(!identical(candidate(532), 'dxxxii')){quit('no', 1)}\n    if(!identical(candidate(900), 'cm')){quit('no', 1)}\n    if(!identical(candidate(994), 'cmxciv')){quit('no', 1)}\n    if(!identical(candidate(1000), 'm')){quit('no', 1)}\n}\ntest_humaneval()",
    "stop_tokens": [
      "\n#",
      "\n```"
    ]
  }
]