Newsgroup: it.discussioni.auto
Titolo: Acceleration Times and Distances.

Hi again dear friends,
I developed an Excel model to calculate with very high precision the
Acceleration Time and Distance while the speed varies from v1 to v2, (v2>v1),
taking into account the drag and the mechanical losses.
I considered the following Movement Equation
m dv/dt=Faverage - 1/2 rho Cx Sx v^2        (1)
where Faverage is given by
Faverage=K_Torque 1/2 rho Cx Sx Vmax^2      (2)
where K_Torque is a constant (>1) that 'measures' the average torque between
v1 e v2.
If you want this Excel model mail me. Please don't forget to tell me the
format: Excel 97 or Excel 5.0-7.0.
I also have a Word 97 document that contains the mathematical details of my
Excel model.
Here there are some numbers that I got from my model:
Car Model	v1(Km/h)	v2(Km/h)	m(Kg)	FlagHp_Cv	P(Hp or
Cv)	Cx	Sx(m^2)	p_mec	rho(Kg/m^3)	K_Torque	Vmax(Km/h)
delta_t(s)	delta_x(m)	Faverage(N)	C1	b	a
F1 McLaren	0	100	700	1	800	0,65	1,5	0,15
1,2	K_Torque=3	343	2,46	34	15931,6354	1	0,13791
165,025
F1 Ferrari	0	100	700	1	800	1,1	1,5	0,15
1,2	K_Torque=3,5	288	1,77	25	22176	1	0,21167	149,666
F1 McLaren	100	200	700	1	800	0,65	1,5	0,15
1,2	K_Torque=4	343	1,93	81	21242,1805	1,34129	0,15925
190,555
F1 Ferrari	100	200	700	1	800	1,1	1,5	0,15
1,2	K_Torque=4,5	288	1,46	61	28512	1,39143	0,24001	169,705
1999 F1 McLaren	0	300	700	1	1917	0,65	1,5	0,15
1,2	K_Torque=5	459	2,53	107	47549,5312	1	0,23826
285,098
1999 F1 Ferrari	0	300	700	1	2189	1,1	1,5	0,15
1,2	K_Torque=6	403	1,62	69	74437,4583	1	0,38780
274,206
2000 F1 McLaren	0	400	700	1	2589	0,65	1,5	0,15
1,2	K_Torque=6	508	2,31	131	69892,3333	1	0,28886
345,650
2000 F1 Ferrari	0	400	700	1	3000	1,1	1,5	0,15
1,2	K_Torque=6,5	448	1,63	93	99655,1111	1	0,44871
317,272
Ferrari F355	0	100	750	0	380	0,32	2,04	0,23
1,2	K_Torque=3,4	295	4,71	66	8942,30222	1	0,07890
151,098
Ferrari F360	0	100	800	0	400	0,3	2,07	0,23
1,2	K_Torque=3,9	305	4,3	60	10430,4281	1	0,07792
167,312
Opel Tigra 1.4	0	100	600	0	90	0,28	1,984	0,25
1,2	K_Torque=3,18	191	11,51	162	2983,59453	1	0,05255
94,6116
Opel Tigra 1.6	0	100	650	0	106	0,28	1,984	0,23
1,2	K_Torque=3,55	203	9,83	138	3762,41222	1	0,05448
106,244
Audi A4 1.6i	0	100	800	0	101	0,28	2,15	0,27
1,2	K_Torque=3,75	191	11,95	168	3812,77118	1	0,04638
102,741
Audi A4 1.8 20v	0	100	850	0	125	0,28	2,15	0,27
1,2	K_Torque=3,92	205	10,5	147	4591,30907	1	0,04790
112,744
Audi A4 1.8 Turbo Sport 	0	100	850	0	150	0,28
2,15	0,23	1,2	K_Torque=4,2	222	8,32	116	5768,966
1	0,05370	126,379
Audi A4 1.8 Turbo quattro	0	100	850	0	180	0,28
2,15	0,26	1,2	K_Torque=4,15	233	7,63	107	6279,17632
1	0,05602	131,849
Audi A4 2.8 V6 quattro	0	100	850	0	193	0,28	2,15
0,26	1,2	K_Torque=4,15	238	7,31	102	6551,56042	1
0,05723	134,678
Opel Vectra 1.6i 16v	0	100	850	0	100	0,31	2,024
0,27	1,2	K_Torque=3,78	188	12,49	176	3880,84188	1
0,04496	101,531
Opel Vectra 2.0i 16v	0	100	850	0	136	0,31	2,024
0,2	1,2	K_Torque=3,57	215	10,06	141	4793,61981	1
0,04997	112,841
Mercedes A140	0	100	500	0	82	0,37	1,92	0,25
1,2	K_Torque=2,39	170	12,88	184	2271,66844	1	0,06223
73,0037
Mercedes A160	0	100	550	0	102	0,37	1,92	0,26
1,2	K_Torque=2,7	182	10,8	153	2941,4112	1	0,06437
83,0712
Thank you for your attention and your comments.
Bye. Adeus! Senna diria Chau!
Zé Fonseca
Lisboa, Portugal.
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taking into account the drag and the mechanical losses.
Wow!

Please send me Excel 97 versione.
Tkanks
Enzo Rosadini
enz...@tin.it


Hi again dear friends,
You can verify that we have approximately
m ((v2-v1)/3,6)/delta_t ~ (K_Torque^1/2) 1/2 Cx Sx Vmax^2     (3)
that is the square root of K_Torque is equal to the quotient of the average
torque between v1 and v2 and the torque at Vmax, the top speed.
Bye. Adeus! Senna would say Chau!


 Lisboa, Portugal.
Ma non eri Lenine 2?
Weren't you Lenine2?