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a99c5d36-6ddd-11ea-ae2c-ccda262736ce

https://socratic.org/questions/a-sample-of-a-gas-has-a-volume-of-of-2-0-liters-at-a-pressure-of-1-0-atmosphere-

0.05 atmosphere

start physical_unit 4 4 pressure atm qc_end physical_unit 4 4 10 11 volume qc_end physical_unit 4 4 16 17 pressure qc_end physical_unit 4 4 23 24 volume qc_end c_other constant_temperature qc_end end

[{"type":"physical unit","value":"Pressure2 [OF] the gas sample [IN] atmosphere"}]

[{"type":"physical unit","value":"0.05 atmosphere"}]

[{"type":"physical unit","value":"Volume1 [OF] the gas sample [=] \\pu{2.0 liters}"},{"type":"physical unit","value":"Pressure1 [OF] the gas sample [=] \\pu{1.0 atmosphere}"},{"type":"physical unit","value":"Volume2 [OF] the gas sample [=] \\pu{40 liters}"},{"type":"other","value":"ConstantTemperature"}]

<h1 class="questionTitle" itemprop="name">A sample of a gas has a volume of of 2.0 liters at a pressure of 1.0 atmosphere. When the volume increases to 40 liters, at constant temperature, what will the pressure be?</h1>

0.05 atmosphere

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a> which states that the volume of a gas varies inversely with pressure, when mass and temperature are kept constant.</p> <p><strong>Equation</strong><br/> <mathjax>#V_1P_1=V_2P_2#</mathjax>, where <mathjax>#V#</mathjax> is volume and <mathjax>#P#</mathjax> is pressure.</p> <p><strong>Known</strong><br/> <mathjax>#V_1="2.0 L"#</mathjax><br/> <mathjax>#P_1="1.0 atm"#</mathjax><br/> <mathjax>#V_2="40 L"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#P_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#P_2#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#P_2=(V_1P_1)/V_2#</mathjax></p> <p><mathjax>#P_2=((2.0cancel"L")xx(1.0"atm"))/(40cancel"L")="0.05 atm"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final pressure will be 0.05 atm.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a> which states that the volume of a gas varies inversely with pressure, when mass and temperature are kept constant.</p> <p><strong>Equation</strong><br/> <mathjax>#V_1P_1=V_2P_2#</mathjax>, where <mathjax>#V#</mathjax> is volume and <mathjax>#P#</mathjax> is pressure.</p> <p><strong>Known</strong><br/> <mathjax>#V_1="2.0 L"#</mathjax><br/> <mathjax>#P_1="1.0 atm"#</mathjax><br/> <mathjax>#V_2="40 L"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#P_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#P_2#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#P_2=(V_1P_1)/V_2#</mathjax></p> <p><mathjax>#P_2=((2.0cancel"L")xx(1.0"atm"))/(40cancel"L")="0.05 atm"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A sample of a gas has a volume of of 2.0 liters at a pressure of 1.0 atmosphere. When the volume increases to 40 liters, at constant temperature, what will the pressure be?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="352570" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-16T04:56:39" itemprop="dateCreated"> Dec 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final pressure will be 0.05 atm.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a> which states that the volume of a gas varies inversely with pressure, when mass and temperature are kept constant.</p> <p><strong>Equation</strong><br/> <mathjax>#V_1P_1=V_2P_2#</mathjax>, where <mathjax>#V#</mathjax> is volume and <mathjax>#P#</mathjax> is pressure.</p> <p><strong>Known</strong><br/> <mathjax>#V_1="2.0 L"#</mathjax><br/> <mathjax>#P_1="1.0 atm"#</mathjax><br/> <mathjax>#V_2="40 L"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#P_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#P_2#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#P_2=(V_1P_1)/V_2#</mathjax></p> <p><mathjax>#P_2=((2.0cancel"L")xx(1.0"atm"))/(40cancel"L")="0.05 atm"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/352570" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-gas-pressure-be-changed"> How can gas pressure be changed? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-increase-gas-pressure-in-a-container"> How can you increase gas pressure in a container? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-gas-pressure-created"> How is gas pressure created? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-when-temperature-increases"> Why does gas pressure increase when temperature increases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-gas-pressure-zero-at-absolute-zero"> Why is gas pressure zero at absolute zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-with-temperature"> Why does gas pressure increase with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-there-no-gas-pressure-in-a-vacuum"> Why is there no gas pressure in a vacuum? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-total-gas-pressure-in-a-sealed-flask-that-contains-oxygen-at-a-parti-1"> What is the total gas pressure in a sealed flask that contains oxygen at a partial pressure of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-absolute-pressure-of-a-gas-is-550-280-kpa-what-is-its-gage-pressure"> If the absolute pressure of a gas is 550.280 kPa, what is its gage pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-a-gas-sample-occupies-4-2-l-at-a-pressure-of-101-kpa-what-volume-will-it-occu"> If a gas sample occupies 4.2 L at a pressure of 101 kPa. What volume will it occupy if the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gas-pressure"> See all questions in Gas Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5306 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A sample of a gas has a volume of of 2.0 liters at a pressure of 1.0 atmosphere. When the volume increases to 40 liters, at constant temperature, what will the pressure be?

ab5143e4-6ddd-11ea-84a5-ccda262736ce

https://socratic.org/questions/500-0-ml-of-0-140-m-naoh-is-added-to-565-ml-of-0-250-m-weak-acid-ka-2-92-10-5-wh

4.53

start physical_unit 26 28 ph none qc_end physical_unit 5 5 3 4 molarity qc_end physical_unit 14 15 9 10 volume qc_end physical_unit 14 15 12 13 molarity qc_end physical_unit 14 15 18 20 ka qc_end end

[{"type":"physical unit","value":"pH [OF] the resulting buffer"}]

[{"type":"physical unit","value":"4.53"}]

[{"type":"physical unit","value":"Volume [OF] NaOH solution [=] \\pu{500.0 mL }"},{"type":"physical unit","value":"Molarity [OF] NaOH solution [=] \\pu{0.140 M}"},{"type":"physical unit","value":"Volume [OF] weak acid [=] \\pu{565 mL}"},{"type":"physical unit","value":"Molarity [OF] weak acid [=] \\pu{0.250 M}"},{"type":"physical unit","value":"Ka [OF] weak acid [=] \\pu{2.92 × 10^(-5)}"}]

<h1 class="questionTitle" itemprop="name">500.0 mL of 0.140 M NaOH is added to 565 mL of 0.250 M weak acid (Ka = 2.92 × 10-5). What is the pH of the resulting buffer?</h1>

4.53

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Right from the start, looking at the values given to you, I'd say that the <mathjax>#"pH"#</mathjax> is very close to the <mathjax>#"p"K_a#</mathjax> of the weak acid. </p> <p>So I would say that you have</p> <blockquote> <p><mathjax>#"pH" ~~ "p"K_a#</mathjax></p> </blockquote> <p>or</p> <blockquote> <p><mathjax>#"pH" ~~ - log(2.92 * 10^(-5))#</mathjax></p> <p><mathjax>#"pH" ~~ 4.535#</mathjax></p> </blockquote> <p>Here's why.</p> <p>The idea here is that the hydroxide anions delivered to the solution by the soluble salt will react with the weak acid, let's say <mathjax>#"HA"#</mathjax>, to form the <strong>conjugate base</strong> of the acid, <mathjax>#"A"^(-)#</mathjax>.</p> <blockquote> <p><mathjax>#"HA"_ ((aq)) + "OH"_ ((aq))^(-) -&gt; "A"_ ((aq))^(-) + "H"_ 2"O"_ ((l))#</mathjax></p> </blockquote> <p>The weak acid and the hydroxide anions react in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong> to produce conjugate base. In other words, <strong>every mole</strong> of hydroxide anions added to the solution will consume <mathjax>#1#</mathjax> <strong>mole</strong> of weak acid and produce <mathjax>#1#</mathjax> <strong>mole</strong> of conjugate base.</p> <p>Use the molarities and the volumes of the two <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> to figure out how many moles of each reactant are being mixed</p> <blockquote> <p><mathjax>#500.0 color(red)(cancel(color(black)("mL"))) * "0.140 moles OH"^(-)/(10^3color(red)(cancel(color(black)("mL solution")))) = "0.0700 moles OH"^(-)#</mathjax></p> <p><mathjax>#565 color(red)(cancel(color(black)("mL"))) * "0.250 moles HA"/(10^3color(red)(cancel(color(black)("mL solution")))) = "0.141 moles HA"#</mathjax></p> </blockquote> <p>Now, you have fewer moles of hydroxide anions than moles of weak acid, which implies that the hydroxide anions will act as a <strong><a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></strong>, i.e. they will be <strong>completely consumed</strong> by the reaction. </p> <p>The resulting solution will thus contain </p> <blockquote> <p><mathjax>#n_ ("OH"^(-)) = "0 moles OH"^(-) -&gt;#</mathjax> <em><strong>completely consumed</strong></em></p> <p><mathjax>#n_ ("HA") = "0.141 moles" - "0.0700 moles" = "0.0710 moles HA"#</mathjax></p> <p><mathjax>#n_ ("A"^(-)) = "0 moles" + "0.0700 moles" = "0.0700 moles A"^(-)#</mathjax></p> </blockquote> <p>The <strong>total volume</strong> of the solution will be</p> <blockquote> <p><mathjax>#V_"total" = "500.0 mL" + "565 mL" = "1065 mL"#</mathjax></p> </blockquote> <p>The concentration of the weak acid and of the conjugate base in the resulting solution will be </p> <blockquote> <p><mathjax>#["HA"] = "0.0710 moles"/(1065 * 10^(-3)"L") = "0.0667 M"#</mathjax></p> <p><mathjax>#["A"^(-)] = "0.0700 moles"/(1065 * 10^(-3)"L") = "0.0657 M"#</mathjax></p> </blockquote> <p>Now, you can calculate the <mathjax>#"pH"#</mathjax> of the buffer by using the <strong>Henderson - Hasselbalch equation</strong>, which for your buffer will look like this</p> <blockquote> <p><mathjax>#"pH" = "p"K_a + log( (["A"^(-)])/(["HA"]))#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#"pH" = 4.53 + log(( 0.0657 color(red)(cancel(color(black)("M"))))/(0.0667 color(red)(cancel(color(black)("M")))))#</mathjax></p> <p><mathjax>#"pH" = 4.535 + (-0.00656)#</mathjax></p> <p><mathjax>#color(darkgreen)(ul(color(black)("pH" = 4.528)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong>decimal places</strong>, the number of <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> you have for all but one of your values. </p> <p>Notice that the initial prediction turned out to be correct, we really do have</p> <blockquote> <p><mathjax>#"pH" ~~ "p"K_a#</mathjax></p> </blockquote> <p>The prediction was based on the fact that your values showed that you had almost <strong>twice as many</strong> moles of weak acid than moles of strong base. </p> <p>The <mathjax>#1:1#</mathjax> mole ratio that the two reactants share means that almost <strong>half</strong> of the number of moles of weak acid will be converted to moles of conjugate base. </p> <p>So the concentration of the weak acid and the concentration of the conjugate base were going to come out as being almost equal. </p> <p>And since the Henderson - Hasselbalch equation shows that when</p> <blockquote> <p><mathjax>#["HA"] = ["A"^(-)]#</mathjax></p> </blockquote> <p>you have</p> <blockquote> <p><mathjax>#"pH" = "p"K_a + log(1)#</mathjax></p> <p><mathjax>#"pH" = "p"K_a#</mathjax></p> </blockquote> <p>the prediction was right on the money.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 4.528#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Right from the start, looking at the values given to you, I'd say that the <mathjax>#"pH"#</mathjax> is very close to the <mathjax>#"p"K_a#</mathjax> of the weak acid. </p> <p>So I would say that you have</p> <blockquote> <p><mathjax>#"pH" ~~ "p"K_a#</mathjax></p> </blockquote> <p>or</p> <blockquote> <p><mathjax>#"pH" ~~ - log(2.92 * 10^(-5))#</mathjax></p> <p><mathjax>#"pH" ~~ 4.535#</mathjax></p> </blockquote> <p>Here's why.</p> <p>The idea here is that the hydroxide anions delivered to the solution by the soluble salt will react with the weak acid, let's say <mathjax>#"HA"#</mathjax>, to form the <strong>conjugate base</strong> of the acid, <mathjax>#"A"^(-)#</mathjax>.</p> <blockquote> <p><mathjax>#"HA"_ ((aq)) + "OH"_ ((aq))^(-) -&gt; "A"_ ((aq))^(-) + "H"_ 2"O"_ ((l))#</mathjax></p> </blockquote> <p>The weak acid and the hydroxide anions react in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong> to produce conjugate base. In other words, <strong>every mole</strong> of hydroxide anions added to the solution will consume <mathjax>#1#</mathjax> <strong>mole</strong> of weak acid and produce <mathjax>#1#</mathjax> <strong>mole</strong> of conjugate base.</p> <p>Use the molarities and the volumes of the two <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> to figure out how many moles of each reactant are being mixed</p> <blockquote> <p><mathjax>#500.0 color(red)(cancel(color(black)("mL"))) * "0.140 moles OH"^(-)/(10^3color(red)(cancel(color(black)("mL solution")))) = "0.0700 moles OH"^(-)#</mathjax></p> <p><mathjax>#565 color(red)(cancel(color(black)("mL"))) * "0.250 moles HA"/(10^3color(red)(cancel(color(black)("mL solution")))) = "0.141 moles HA"#</mathjax></p> </blockquote> <p>Now, you have fewer moles of hydroxide anions than moles of weak acid, which implies that the hydroxide anions will act as a <strong><a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></strong>, i.e. they will be <strong>completely consumed</strong> by the reaction. </p> <p>The resulting solution will thus contain </p> <blockquote> <p><mathjax>#n_ ("OH"^(-)) = "0 moles OH"^(-) -&gt;#</mathjax> <em><strong>completely consumed</strong></em></p> <p><mathjax>#n_ ("HA") = "0.141 moles" - "0.0700 moles" = "0.0710 moles HA"#</mathjax></p> <p><mathjax>#n_ ("A"^(-)) = "0 moles" + "0.0700 moles" = "0.0700 moles A"^(-)#</mathjax></p> </blockquote> <p>The <strong>total volume</strong> of the solution will be</p> <blockquote> <p><mathjax>#V_"total" = "500.0 mL" + "565 mL" = "1065 mL"#</mathjax></p> </blockquote> <p>The concentration of the weak acid and of the conjugate base in the resulting solution will be </p> <blockquote> <p><mathjax>#["HA"] = "0.0710 moles"/(1065 * 10^(-3)"L") = "0.0667 M"#</mathjax></p> <p><mathjax>#["A"^(-)] = "0.0700 moles"/(1065 * 10^(-3)"L") = "0.0657 M"#</mathjax></p> </blockquote> <p>Now, you can calculate the <mathjax>#"pH"#</mathjax> of the buffer by using the <strong>Henderson - Hasselbalch equation</strong>, which for your buffer will look like this</p> <blockquote> <p><mathjax>#"pH" = "p"K_a + log( (["A"^(-)])/(["HA"]))#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#"pH" = 4.53 + log(( 0.0657 color(red)(cancel(color(black)("M"))))/(0.0667 color(red)(cancel(color(black)("M")))))#</mathjax></p> <p><mathjax>#"pH" = 4.535 + (-0.00656)#</mathjax></p> <p><mathjax>#color(darkgreen)(ul(color(black)("pH" = 4.528)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong>decimal places</strong>, the number of <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> you have for all but one of your values. </p> <p>Notice that the initial prediction turned out to be correct, we really do have</p> <blockquote> <p><mathjax>#"pH" ~~ "p"K_a#</mathjax></p> </blockquote> <p>The prediction was based on the fact that your values showed that you had almost <strong>twice as many</strong> moles of weak acid than moles of strong base. </p> <p>The <mathjax>#1:1#</mathjax> mole ratio that the two reactants share means that almost <strong>half</strong> of the number of moles of weak acid will be converted to moles of conjugate base. </p> <p>So the concentration of the weak acid and the concentration of the conjugate base were going to come out as being almost equal. </p> <p>And since the Henderson - Hasselbalch equation shows that when</p> <blockquote> <p><mathjax>#["HA"] = ["A"^(-)]#</mathjax></p> </blockquote> <p>you have</p> <blockquote> <p><mathjax>#"pH" = "p"K_a + log(1)#</mathjax></p> <p><mathjax>#"pH" = "p"K_a#</mathjax></p> </blockquote> <p>the prediction was right on the money.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">500.0 mL of 0.140 M NaOH is added to 565 mL of 0.250 M weak acid (Ka = 2.92 × 10-5). What is the pH of the resulting buffer?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/buffer-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Buffer Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="404269" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-10T00:02:17" itemprop="dateCreated"> Apr 10, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 4.528#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Right from the start, looking at the values given to you, I'd say that the <mathjax>#"pH"#</mathjax> is very close to the <mathjax>#"p"K_a#</mathjax> of the weak acid. </p> <p>So I would say that you have</p> <blockquote> <p><mathjax>#"pH" ~~ "p"K_a#</mathjax></p> </blockquote> <p>or</p> <blockquote> <p><mathjax>#"pH" ~~ - log(2.92 * 10^(-5))#</mathjax></p> <p><mathjax>#"pH" ~~ 4.535#</mathjax></p> </blockquote> <p>Here's why.</p> <p>The idea here is that the hydroxide anions delivered to the solution by the soluble salt will react with the weak acid, let's say <mathjax>#"HA"#</mathjax>, to form the <strong>conjugate base</strong> of the acid, <mathjax>#"A"^(-)#</mathjax>.</p> <blockquote> <p><mathjax>#"HA"_ ((aq)) + "OH"_ ((aq))^(-) -&gt; "A"_ ((aq))^(-) + "H"_ 2"O"_ ((l))#</mathjax></p> </blockquote> <p>The weak acid and the hydroxide anions react in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong> to produce conjugate base. In other words, <strong>every mole</strong> of hydroxide anions added to the solution will consume <mathjax>#1#</mathjax> <strong>mole</strong> of weak acid and produce <mathjax>#1#</mathjax> <strong>mole</strong> of conjugate base.</p> <p>Use the molarities and the volumes of the two <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> to figure out how many moles of each reactant are being mixed</p> <blockquote> <p><mathjax>#500.0 color(red)(cancel(color(black)("mL"))) * "0.140 moles OH"^(-)/(10^3color(red)(cancel(color(black)("mL solution")))) = "0.0700 moles OH"^(-)#</mathjax></p> <p><mathjax>#565 color(red)(cancel(color(black)("mL"))) * "0.250 moles HA"/(10^3color(red)(cancel(color(black)("mL solution")))) = "0.141 moles HA"#</mathjax></p> </blockquote> <p>Now, you have fewer moles of hydroxide anions than moles of weak acid, which implies that the hydroxide anions will act as a <strong><a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></strong>, i.e. they will be <strong>completely consumed</strong> by the reaction. </p> <p>The resulting solution will thus contain </p> <blockquote> <p><mathjax>#n_ ("OH"^(-)) = "0 moles OH"^(-) -&gt;#</mathjax> <em><strong>completely consumed</strong></em></p> <p><mathjax>#n_ ("HA") = "0.141 moles" - "0.0700 moles" = "0.0710 moles HA"#</mathjax></p> <p><mathjax>#n_ ("A"^(-)) = "0 moles" + "0.0700 moles" = "0.0700 moles A"^(-)#</mathjax></p> </blockquote> <p>The <strong>total volume</strong> of the solution will be</p> <blockquote> <p><mathjax>#V_"total" = "500.0 mL" + "565 mL" = "1065 mL"#</mathjax></p> </blockquote> <p>The concentration of the weak acid and of the conjugate base in the resulting solution will be </p> <blockquote> <p><mathjax>#["HA"] = "0.0710 moles"/(1065 * 10^(-3)"L") = "0.0667 M"#</mathjax></p> <p><mathjax>#["A"^(-)] = "0.0700 moles"/(1065 * 10^(-3)"L") = "0.0657 M"#</mathjax></p> </blockquote> <p>Now, you can calculate the <mathjax>#"pH"#</mathjax> of the buffer by using the <strong>Henderson - Hasselbalch equation</strong>, which for your buffer will look like this</p> <blockquote> <p><mathjax>#"pH" = "p"K_a + log( (["A"^(-)])/(["HA"]))#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#"pH" = 4.53 + log(( 0.0657 color(red)(cancel(color(black)("M"))))/(0.0667 color(red)(cancel(color(black)("M")))))#</mathjax></p> <p><mathjax>#"pH" = 4.535 + (-0.00656)#</mathjax></p> <p><mathjax>#color(darkgreen)(ul(color(black)("pH" = 4.528)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong>decimal places</strong>, the number of <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> you have for all but one of your values. </p> <p>Notice that the initial prediction turned out to be correct, we really do have</p> <blockquote> <p><mathjax>#"pH" ~~ "p"K_a#</mathjax></p> </blockquote> <p>The prediction was based on the fact that your values showed that you had almost <strong>twice as many</strong> moles of weak acid than moles of strong base. </p> <p>The <mathjax>#1:1#</mathjax> mole ratio that the two reactants share means that almost <strong>half</strong> of the number of moles of weak acid will be converted to moles of conjugate base. </p> <p>So the concentration of the weak acid and the concentration of the conjugate base were going to come out as being almost equal. </p> <p>And since the Henderson - Hasselbalch equation shows that when</p> <blockquote> <p><mathjax>#["HA"] = ["A"^(-)]#</mathjax></p> </blockquote> <p>you have</p> <blockquote> <p><mathjax>#"pH" = "p"K_a + log(1)#</mathjax></p> <p><mathjax>#"pH" = "p"K_a#</mathjax></p> </blockquote> <p>the prediction was right on the money.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/404269" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-buffer-solutions-used"> How are buffer solutions used? 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500.0 mL of 0.140 M NaOH is added to 565 mL of 0.250 M weak acid (Ka = 2.92 × 10-5). What is the pH of the resulting buffer?

ac2bbcd8-6ddd-11ea-8cf7-ccda262736ce

https://socratic.org/questions/on-a-cold-winter-morning-when-the-temperature-is-13-c-the-air-pressure-in-an-aut-1

1.66 atm

start physical_unit 32 33 pressure atm qc_end physical_unit 32 33 9 10 temperature qc_end physical_unit 32 33 19 20 pressure qc_end c_other OTHER qc_end physical_unit 32 33 37 38 temperature qc_end end

[{"type":"physical unit","value":"Pressure2 [OF] the tire [IN] atm"}]

[{"type":"physical unit","value":"1.66 atm"}]

[{"type":"physical unit","value":"Temperature1 [OF] the tire [=] \\pu{-13 ℃}"},{"type":"physical unit","value":"Pressure1 [OF] the tire [=] \\pu{1.5 atm}"},{"type":"other","value":"The volume does not change."},{"type":"physical unit","value":"Temperature2 [OF] the tire [=] \\pu{15 ℃}"}]

<h1 class="questionTitle" itemprop="name">On a cold winter morning when the temperature is -13°C, the air pressure in an automobile tire is 1.5 atm. If the volume does not change, what is the pressure after the tire has warmed to 15°C?</h1>

1.66 atm

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When volume does not change</p> <p><mathjax>#P_i/T_i=P_f/T_f#</mathjax>, where temperature is in kelvins</p> <p>As initial temperature is <mathjax>#-13^@C=(273-13)^@K#</mathjax> and initial pressure is <mathjax>#1.5atm#</mathjax>, at <mathjax>#15^@C=(273+15)^@K#</mathjax>, pressure will be given by</p> <p><mathjax>#1.5/260=P_f/288#</mathjax></p> <p>and <mathjax>#P_f=(288xx1.5)/260=1.662#</mathjax> atm</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Pressure will be <mathjax>#1.662#</mathjax> atm</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When volume does not change</p> <p><mathjax>#P_i/T_i=P_f/T_f#</mathjax>, where temperature is in kelvins</p> <p>As initial temperature is <mathjax>#-13^@C=(273-13)^@K#</mathjax> and initial pressure is <mathjax>#1.5atm#</mathjax>, at <mathjax>#15^@C=(273+15)^@K#</mathjax>, pressure will be given by</p> <p><mathjax>#1.5/260=P_f/288#</mathjax></p> <p>and <mathjax>#P_f=(288xx1.5)/260=1.662#</mathjax> atm</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">On a cold winter morning when the temperature is -13°C, the air pressure in an automobile tire is 1.5 atm. If the volume does not change, what is the pressure after the tire has warmed to 15°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/atmospheric-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Atmospheric Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="404137" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/shwetank-m"><img alt="" class="" src="https://graph.facebook.com/1274310605917442/picture?height=50&amp;width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/shwetank-m"> Shwetank Mauria </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-09T16:55:48" itemprop="dateCreated"> Apr 9, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Pressure will be <mathjax>#1.662#</mathjax> atm</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When volume does not change</p> <p><mathjax>#P_i/T_i=P_f/T_f#</mathjax>, where temperature is in kelvins</p> <p>As initial temperature is <mathjax>#-13^@C=(273-13)^@K#</mathjax> and initial pressure is <mathjax>#1.5atm#</mathjax>, at <mathjax>#15^@C=(273+15)^@K#</mathjax>, pressure will be given by</p> <p><mathjax>#1.5/260=P_f/288#</mathjax></p> <p>and <mathjax>#P_f=(288xx1.5)/260=1.662#</mathjax> atm</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/404137" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-atmospheric-pressure-affect-evaporation"> How does atmospheric pressure affect evaporation? 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On a cold winter morning when the temperature is -13°C, the air pressure in an automobile tire is 1.5 atm. If the volume does not change, what is the pressure after the tire has warmed to 15°C?

a979ac9e-6ddd-11ea-937b-ccda262736ce

https://socratic.org/questions/what-is-the-mass-of-2-75-mol-of-sodium-hydrogen-carbonate-nahco-3

231.03 g

start physical_unit 11 11 mass g qc_end physical_unit 11 11 5 6 mole qc_end end

[{"type":"physical unit","value":"Mass [OF] NaHCO3 [IN] g"}]

[{"type":"physical unit","value":"231.03 g"}]

[{"type":"physical unit","value":"Mole [OF] NaHCO3 [=] \\pu{2.75 mol}"}]

<h1 class="questionTitle" itemprop="name">What is the mass of 2.75 mol of sodium hydrogen carbonate, #NaHCO_3#? </h1>

231.03 g

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So if there are <mathjax>#2.75*mol#</mathjax>, this has a mass of <mathjax>#2.75*molxx84.01*g*mol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??*g#</mathjax>.</p> <p>How did I get the formula mass?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#NaHCO_3#</mathjax> has a formula mass of <mathjax>#84.01*g*mol^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So if there are <mathjax>#2.75*mol#</mathjax>, this has a mass of <mathjax>#2.75*molxx84.01*g*mol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??*g#</mathjax>.</p> <p>How did I get the formula mass?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the mass of 2.75 mol of sodium hydrogen carbonate, #NaHCO_3#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="286644" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-10T05:42:41" itemprop="dateCreated"> Jul 10, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#NaHCO_3#</mathjax> has a formula mass of <mathjax>#84.01*g*mol^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So if there are <mathjax>#2.75*mol#</mathjax>, this has a mass of <mathjax>#2.75*molxx84.01*g*mol^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??*g#</mathjax>.</p> <p>How did I get the formula mass?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/286644" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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What is the mass of 2.75 mol of sodium hydrogen carbonate, #NaHCO_3#?

a87b9cb6-6ddd-11ea-8466-ccda262736ce

https://socratic.org/questions/a-saturated-solution-of-pbbr-2-is-prepared-by-dissolving-the-solid-salt-in-water

6.1 × 10^(-6)

start physical_unit 4 4 equilibrium_constant_k none qc_end physical_unit 17 17 24 25 concentration qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Ksp [OF] PbBr2"}]

[{"type":"physical unit","value":"6.1 × 10^(-6)"}]

[{"type":"physical unit","value":"Concentration [OF] Pb^2+ [=] \\pu{0.0115 M}"},{"type":"other","value":"A saturated solution of PbBr2 is prepared by dissolving the solid salt in water."}]

<h1 class="questionTitle" itemprop="name">A saturated solution of #PbBr_2# is prepared by dissolving the solid salt in water. The concentration of #Pb_2^+# in solution is found to be 0.0115 M. What is the Ksp for #PbBr_2#?</h1>

6.1 × 10^(-6)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the solubility equilibrium.........</p> <p><mathjax>#PbBr_2(s) rightleftharpoonsPb^(2+) + 2Br^(-)#</mathjax></p> <p>Now <mathjax>#K_(sp)=[Pb^(2+)][Br^-]#</mathjax>.........And if we say that the solubility of <mathjax>#PbBr_2-=S#</mathjax>, then by <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>........</p> <p><mathjax>#K_(sp)=[S][2S]^2=4S^3#</mathjax> (because <mathjax>#S=[Pb^(2+)]#</mathjax>, and <mathjax>#[Br^-]=2S#</mathjax></p> <p><mathjax>#=4xx(0.0115)^3=6.1xx10^-6#</mathjax>.........</p> <p>Can you define what is meant by a <mathjax>#"saturated solution......?"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_(sp)=6.1xx10^-6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the solubility equilibrium.........</p> <p><mathjax>#PbBr_2(s) rightleftharpoonsPb^(2+) + 2Br^(-)#</mathjax></p> <p>Now <mathjax>#K_(sp)=[Pb^(2+)][Br^-]#</mathjax>.........And if we say that the solubility of <mathjax>#PbBr_2-=S#</mathjax>, then by <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>........</p> <p><mathjax>#K_(sp)=[S][2S]^2=4S^3#</mathjax> (because <mathjax>#S=[Pb^(2+)]#</mathjax>, and <mathjax>#[Br^-]=2S#</mathjax></p> <p><mathjax>#=4xx(0.0115)^3=6.1xx10^-6#</mathjax>.........</p> <p>Can you define what is meant by a <mathjax>#"saturated solution......?"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A saturated solution of #PbBr_2# is prepared by dissolving the solid salt in water. The concentration of #Pb_2^+# in solution is found to be 0.0115 M. What is the Ksp for #PbBr_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/ksp" itemprop="url"> <span class="breadcrumb" itemprop="title">Ksp</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="451498" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-14T19:01:37" itemprop="dateCreated"> Jul 14, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_(sp)=6.1xx10^-6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the solubility equilibrium.........</p> <p><mathjax>#PbBr_2(s) rightleftharpoonsPb^(2+) + 2Br^(-)#</mathjax></p> <p>Now <mathjax>#K_(sp)=[Pb^(2+)][Br^-]#</mathjax>.........And if we say that the solubility of <mathjax>#PbBr_2-=S#</mathjax>, then by <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>........</p> <p><mathjax>#K_(sp)=[S][2S]^2=4S^3#</mathjax> (because <mathjax>#S=[Pb^(2+)]#</mathjax>, and <mathjax>#[Br^-]=2S#</mathjax></p> <p><mathjax>#=4xx(0.0115)^3=6.1xx10^-6#</mathjax>.........</p> <p>Can you define what is meant by a <mathjax>#"saturated solution......?"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/451498" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-use-the-solubility-product-constant-to-calculate-the-solubility-of-a"> How can you use the solubility product constant to calculate the solubility of a sparingly... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5397ae9102bf3458eddf5130"> Question #f5130 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-ksp"> What is Ksp? 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A saturated solution of #PbBr_2# is prepared by dissolving the solid salt in water. The concentration of #Pb_2^+# in solution is found to be 0.0115 M. What is the Ksp for #PbBr_2#?

a8e7ee4c-6ddd-11ea-b035-ccda262736ce

https://socratic.org/questions/the-titration-of-20-0-ml-of-an-unknown-concentration-h-2so-4-solution-requires-8

0.25 M

start physical_unit 24 26 concentration mol/l qc_end physical_unit 9 10 3 4 volume qc_end physical_unit 17 18 12 13 volume qc_end physical_unit 17 18 15 16 concentration qc_end end

[{"type":"physical unit","value":"Concentration [OF] the H2SO4 solution [IN] M"}]

[{"type":"physical unit","value":"0.25 M"}]

[{"type":"physical unit","value":"Volume [OF] H2SO4 solution [=] \\pu{20.0 mL}"},{"type":"physical unit","value":"Volume [OF] LiOH solution [=] \\pu{83.6 mL}"},{"type":"physical unit","value":"Concentration [OF] LiOH solution [=] \\pu{0.12 M}"}]

<h1 class="questionTitle" itemprop="name">The titration of 20.0 mL of an unknown concentration #H_2SO_4# solution requires 83.6 mL of 0.12 M #LiOH# solution. What is the concentration of the #H_2SO_4# solution (in M)?</h1>

0.25 M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Write a balanced chemical equation for the <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a> reaction to figure out <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> relationship between the sulfuric acid and lithium hydroxide.</p> <p><mathjax>#H_2SO_4 + 2LiOH -&gt; Li_2SO_4 + 2H_2O#</mathjax></p> <p><mathjax>#n_(H_2SO_4) = 1/2 \ n_(LiOH)#</mathjax></p> <p><mathjax>#underbrace((C_MxxV))_("number of moles of "H_2SO_4) = 1/2\ \ \ \ \ \ xxunderbrace((C_MxxV))_("number of moles of "LiOH)#</mathjax></p> <p>Note that <mathjax>#C_M#</mathjax> is the molar concentration and <mathjax>#V#</mathjax>is the volume of solution.</p> <p><mathjax>#(C_MxxV)_(H_2SO_4) = 1/2( C_MxxV)_(LiOH)#</mathjax></p> <p><mathjax>#(C_M)_(H_2SO_4) = (C_MxxV)_(LiOH)/( 2* V_(H_2SO_4)#</mathjax></p> <p><mathjax>#(C_M)_(H_2SO_4) = (0.12 \ mol.L^-1xx 83.6 \ mL)/( 2xx20.0 \ mL)#</mathjax></p> <p><mathjax>#(C_M)_(H_2SO_4) = (0.12 \ mol.L^-1xx 83.6 \ cancel (mL))/( 2xx20.0 \ cancel(mL))#</mathjax></p> <p><mathjax>#(C_M)_(H_2SO_4) = 0.25 \ mol.L^-1#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#(C_M)_(H_2SO_4) = 0.25 \ mol.L^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Write a balanced chemical equation for the <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a> reaction to figure out <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> relationship between the sulfuric acid and lithium hydroxide.</p> <p><mathjax>#H_2SO_4 + 2LiOH -&gt; Li_2SO_4 + 2H_2O#</mathjax></p> <p><mathjax>#n_(H_2SO_4) = 1/2 \ n_(LiOH)#</mathjax></p> <p><mathjax>#underbrace((C_MxxV))_("number of moles of "H_2SO_4) = 1/2\ \ \ \ \ \ xxunderbrace((C_MxxV))_("number of moles of "LiOH)#</mathjax></p> <p>Note that <mathjax>#C_M#</mathjax> is the molar concentration and <mathjax>#V#</mathjax>is the volume of solution.</p> <p><mathjax>#(C_MxxV)_(H_2SO_4) = 1/2( C_MxxV)_(LiOH)#</mathjax></p> <p><mathjax>#(C_M)_(H_2SO_4) = (C_MxxV)_(LiOH)/( 2* V_(H_2SO_4)#</mathjax></p> <p><mathjax>#(C_M)_(H_2SO_4) = (0.12 \ mol.L^-1xx 83.6 \ mL)/( 2xx20.0 \ mL)#</mathjax></p> <p><mathjax>#(C_M)_(H_2SO_4) = (0.12 \ mol.L^-1xx 83.6 \ cancel (mL))/( 2xx20.0 \ cancel(mL))#</mathjax></p> <p><mathjax>#(C_M)_(H_2SO_4) = 0.25 \ mol.L^-1#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">The titration of 20.0 mL of an unknown concentration #H_2SO_4# solution requires 83.6 mL of 0.12 M #LiOH# solution. What is the concentration of the #H_2SO_4# solution (in M)?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/titration-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Titration Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="275881" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/sam-54"><img alt="" class="" src="https://profilepictures.socratic.org/3bkyAGe2RVWw1lx2h1A5_Avatar%201.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/sam-54"> Sam </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-10T09:08:45" itemprop="dateCreated"> Jun 10, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#(C_M)_(H_2SO_4) = 0.25 \ mol.L^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Write a balanced chemical equation for the <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a> reaction to figure out <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> relationship between the sulfuric acid and lithium hydroxide.</p> <p><mathjax>#H_2SO_4 + 2LiOH -&gt; Li_2SO_4 + 2H_2O#</mathjax></p> <p><mathjax>#n_(H_2SO_4) = 1/2 \ n_(LiOH)#</mathjax></p> <p><mathjax>#underbrace((C_MxxV))_("number of moles of "H_2SO_4) = 1/2\ \ \ \ \ \ xxunderbrace((C_MxxV))_("number of moles of "LiOH)#</mathjax></p> <p>Note that <mathjax>#C_M#</mathjax> is the molar concentration and <mathjax>#V#</mathjax>is the volume of solution.</p> <p><mathjax>#(C_MxxV)_(H_2SO_4) = 1/2( C_MxxV)_(LiOH)#</mathjax></p> <p><mathjax>#(C_M)_(H_2SO_4) = (C_MxxV)_(LiOH)/( 2* V_(H_2SO_4)#</mathjax></p> <p><mathjax>#(C_M)_(H_2SO_4) = (0.12 \ mol.L^-1xx 83.6 \ mL)/( 2xx20.0 \ mL)#</mathjax></p> <p><mathjax>#(C_M)_(H_2SO_4) = (0.12 \ mol.L^-1xx 83.6 \ cancel (mL))/( 2xx20.0 \ cancel(mL))#</mathjax></p> <p><mathjax>#(C_M)_(H_2SO_4) = 0.25 \ mol.L^-1#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/275881" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-acid-base-titration-calculations"> How do you do acid base titration calculations? 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The titration of 20.0 mL of an unknown concentration #H_2SO_4# solution requires 83.6 mL of 0.12 M #LiOH# solution. What is the concentration of the #H_2SO_4# solution (in M)?

ac523b9c-6ddd-11ea-b5d0-ccda262736ce

https://socratic.org/questions/a-sample-of-nitrogen-dioxide-has-a-volume-of-28-6-l-at-45-3-c-and-89-9-kpa-what-

22.1 L

start physical_unit 1 4 volume l qc_end physical_unit 1 4 9 10 volume qc_end physical_unit 1 4 15 16 pressure qc_end physical_unit 1 4 12 13 temperature qc_end c_other STP qc_end end

[{"type":"physical unit","value":"Volume2 [OF] nitrogen dioxide sample [IN] L"}]

[{"type":"physical unit","value":"22.1 L"}]

[{"type":"physical unit","value":"Volume1 [OF] nitrogen dioxide sample [=] \\pu{28.6 L}"},{"type":"physical unit","value":"Pressure1 [OF] nitrogen dioxide sample [=] \\pu{89.9 kPa}"},{"type":"physical unit","value":"Temperature1 [OF] nitrogen dioxide sample [=] \\pu{45.3 ℃}"},{"type":"other","value":"STP"}]

<h1 class="questionTitle" itemprop="name">A sample of nitrogen dioxide has a volume of 28.6 L at 45.3°C and 89.9 kPa. What is its volume at STP?</h1>

22.1 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We can solve this problem using the <em><a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a></em>:</p> <p><mathjax>#(P_1V_1)/(T_1) = (P_2V_2)/(T_2)#</mathjax></p> <p>Standard temperature and pressure conditions are</p> <ul> <li> <p><mathjax>#100#</mathjax> <mathjax>#"kPa"#</mathjax></p> </li> <li> <p><mathjax>#0^"o""C"#</mathjax></p> </li> </ul> <p>Remember that the temperatures must be in Kelvin, so we must convert the Celsius temperatures:</p> <p><mathjax>#0^"o""C" = 273.15#</mathjax> <mathjax>#"K"#</mathjax></p> <p><mathjax>#45.3^"o""C" = 318.5#</mathjax> <mathjax>#"K"#</mathjax></p> <p>Since we're trying to find the volume at stp, let's rearrange this equation to solve for <mathjax>#V_2#</mathjax>:</p> <p><mathjax>#V_2 = (P_1V_1T_2)/(T_1P_2)#</mathjax></p> <p>Plugging in known values, we have</p> <p><mathjax>#V_2 = ((89.9cancel("kPa"))(28.6"L")(273.15cancel("K")))/((318.5cancel("K"))(100cancel("kPa"))) = color(red)(22.1#</mathjax> <mathjax>#color(red)("L"#</mathjax></p> <p>rounded to <mathjax>#3#</mathjax> <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, the amount given in the problem.</p> <p>The volume of the nitrogen as sample at stp is thus <mathjax>#22.1#</mathjax> liters.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#22.1#</mathjax> <mathjax>#"L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We can solve this problem using the <em><a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a></em>:</p> <p><mathjax>#(P_1V_1)/(T_1) = (P_2V_2)/(T_2)#</mathjax></p> <p>Standard temperature and pressure conditions are</p> <ul> <li> <p><mathjax>#100#</mathjax> <mathjax>#"kPa"#</mathjax></p> </li> <li> <p><mathjax>#0^"o""C"#</mathjax></p> </li> </ul> <p>Remember that the temperatures must be in Kelvin, so we must convert the Celsius temperatures:</p> <p><mathjax>#0^"o""C" = 273.15#</mathjax> <mathjax>#"K"#</mathjax></p> <p><mathjax>#45.3^"o""C" = 318.5#</mathjax> <mathjax>#"K"#</mathjax></p> <p>Since we're trying to find the volume at stp, let's rearrange this equation to solve for <mathjax>#V_2#</mathjax>:</p> <p><mathjax>#V_2 = (P_1V_1T_2)/(T_1P_2)#</mathjax></p> <p>Plugging in known values, we have</p> <p><mathjax>#V_2 = ((89.9cancel("kPa"))(28.6"L")(273.15cancel("K")))/((318.5cancel("K"))(100cancel("kPa"))) = color(red)(22.1#</mathjax> <mathjax>#color(red)("L"#</mathjax></p> <p>rounded to <mathjax>#3#</mathjax> <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, the amount given in the problem.</p> <p>The volume of the nitrogen as sample at stp is thus <mathjax>#22.1#</mathjax> liters.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A sample of nitrogen dioxide has a volume of 28.6 L at 45.3°C and 89.9 kPa. What is its volume at STP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="437818" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-11T02:12:09" itemprop="dateCreated"> Jun 11, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#22.1#</mathjax> <mathjax>#"L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We can solve this problem using the <em><a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a></em>:</p> <p><mathjax>#(P_1V_1)/(T_1) = (P_2V_2)/(T_2)#</mathjax></p> <p>Standard temperature and pressure conditions are</p> <ul> <li> <p><mathjax>#100#</mathjax> <mathjax>#"kPa"#</mathjax></p> </li> <li> <p><mathjax>#0^"o""C"#</mathjax></p> </li> </ul> <p>Remember that the temperatures must be in Kelvin, so we must convert the Celsius temperatures:</p> <p><mathjax>#0^"o""C" = 273.15#</mathjax> <mathjax>#"K"#</mathjax></p> <p><mathjax>#45.3^"o""C" = 318.5#</mathjax> <mathjax>#"K"#</mathjax></p> <p>Since we're trying to find the volume at stp, let's rearrange this equation to solve for <mathjax>#V_2#</mathjax>:</p> <p><mathjax>#V_2 = (P_1V_1T_2)/(T_1P_2)#</mathjax></p> <p>Plugging in known values, we have</p> <p><mathjax>#V_2 = ((89.9cancel("kPa"))(28.6"L")(273.15cancel("K")))/((318.5cancel("K"))(100cancel("kPa"))) = color(red)(22.1#</mathjax> <mathjax>#color(red)("L"#</mathjax></p> <p>rounded to <mathjax>#3#</mathjax> <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, the amount given in the problem.</p> <p>The volume of the nitrogen as sample at stp is thus <mathjax>#22.1#</mathjax> liters.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/437818" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyles-law-relate-to-breathing"> How does Boyle's law relate to breathing? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/in-avogadro-s-law-what-would-happen-to-v-if-n-is-increased-decreased-and-what-wo"> In Avogadro's Law what would happen to V if N is increased/decreased? 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A sample of nitrogen dioxide has a volume of 28.6 L at 45.3°C and 89.9 kPa. What is its volume at STP?

ac45a4b6-6ddd-11ea-9b51-ccda262736ce

https://socratic.org/questions/calcium-phosphate-will-precipitate-out-of-blood-plasma-when-calcium-concentratio

1.64 × 10^(-7) M

start physical_unit 29 29 concentration mol/l qc_end physical_unit 0 0 14 15 concentration qc_end physical_unit 19 20 22 24 equilibrium_constant_k qc_end c_other OTHER qc_end substance 0 1 qc_end end

[{"type":"physical unit","value":"Minimum concentration [OF] diphospate [IN] M"}]

[{"type":"physical unit","value":"1.64 × 10^(-7) M"}]

[{"type":"physical unit","value":"Concentration [OF] calcium [=] \\pu{9.2 mg/dL}"},{"type":"physical unit","value":"Ksp [OF] calcium diphosphate [=] \\pu{8.64 × 10^(-13)}"},{"type":"other","value":"Results in precipitation."},{"type":"substance name","value":"Calcium phosphate"}]

<h1 class="questionTitle" itemprop="name">Calcium phosphate will precipitate out of blood plasma when calcium concentration in blood is 9.2mg/dL, and Ksp for calcium diphosphate is 8.64x10^(-13), what minimum concentration of diphospate results in precipitation?</h1>

1.64 × 10^(-7) M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I assume that you're actually referring to <em>calcium diphosphate</em>, <mathjax>#"Ca"_2"P"_2"O"_7#</mathjax>, since the question aks for the concentration of the <em>disphosphate ions</em>, <mathjax>#"P"_2"O"_7^(4-)#</mathjax>. </p> <p>Moreover, <em>calcium phosphate</em>, <mathjax>#"Ca"_3("PO"_4)_2#</mathjax>, has a solubility product constant of about <mathjax>#2.0 * 10^(-33)#</mathjax>, much, much smaller than what you have there. </p> <p>So, calcium diphosphate is insoluble in blood plasma, which means that an equilibrium reaction is established between the solid and the dissolved ions</p> <blockquote> <p><mathjax>#"Ca"_2"P"_2"O"_text(7(s]) rightleftharpoons color(red)(2)"Ca"_text((aq])^(2+) + "P"_2"O"_text(7(aq])^(4-)#</mathjax></p> </blockquote> <p>Notice that <mathjax>#1#</mathjax> <strong>mole</strong> of calcium diphosphate will produce <mathjax>#color(red)(2)#</mathjax> <strong>moles</strong> of calcium cations and <mathjax>#1#</mathjax> <strong>mole</strong> of diphosphate anions in solution. </p> <p>To find the concentration of diphosphate anions that will precipitate the calcium diphoshate, write the expression for the <a href="http://socratic.org/chemistry/chemical-equilibrium/ksp">solubility product constant</a>, <mathjax>#K_"sp"#</mathjax></p> <blockquote> <p><mathjax>#K_"sp" = ["Ca"^(2+)]^color(red)(2) * ["P"_2"O"_7^(4-)]#</mathjax></p> </blockquote> <p>Rearrange to solve for the cocnentration of diphosphate anions</p> <blockquote> <p><mathjax>#["P"_2"O"_7^(4-)] = K_text(sp)/(["Ca"^(2+)]^color(red)(2))#</mathjax></p> </blockquote> <p>You need to convert the concentration of the calcium ations to <em>moles per liter</em>. </p> <p>Now, since you didn't specify which units you must use for the concentration of the diphosphate anions, I"ll leave the answer expressed in <em>moles per liter</em> as well. </p> <p>This means that the concentration of the calcium cations will be </p> <blockquote> <p><mathjax>#9.2(color(red)(cancel(color(black)("mg"))))/(color(red)(cancel(color(black)("dL")))) * (10color(red)(cancel(color(black)("dL"))))/"1 L" * (1color(red)(cancel(color(black)("g"))))/(10^3color(red)(cancel(color(black)("mg")))) * "1 mole Ca"^(2+)/(40.078color(red)(cancel(color(black)("g")))) = 2.2955 * 10^(-3)"M"#</mathjax></p> </blockquote> <p>The concentration of the diphosphate anions will thus be </p> <blockquote> <p><mathjax>#["P"_2"O"_7^(4-)] = (8.64 * 10^(-13))/((2.2955 * 10^(-3))^2) = 1.64 * 10^(-7)"M"#</mathjax></p> </blockquote> <p>You need to round this value to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the concentration of calcium cations</p> <blockquote> <p><mathjax>#["P"_2"O"_7^(4-)] = color(green)(1.6 * 10^(-7)"M")#</mathjax></p> </blockquote> <p>As practice, you can convert this value to <mathjax>#"mg/dL"#</mathjax>. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.6 * 10^(-7)"M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I assume that you're actually referring to <em>calcium diphosphate</em>, <mathjax>#"Ca"_2"P"_2"O"_7#</mathjax>, since the question aks for the concentration of the <em>disphosphate ions</em>, <mathjax>#"P"_2"O"_7^(4-)#</mathjax>. </p> <p>Moreover, <em>calcium phosphate</em>, <mathjax>#"Ca"_3("PO"_4)_2#</mathjax>, has a solubility product constant of about <mathjax>#2.0 * 10^(-33)#</mathjax>, much, much smaller than what you have there. </p> <p>So, calcium diphosphate is insoluble in blood plasma, which means that an equilibrium reaction is established between the solid and the dissolved ions</p> <blockquote> <p><mathjax>#"Ca"_2"P"_2"O"_text(7(s]) rightleftharpoons color(red)(2)"Ca"_text((aq])^(2+) + "P"_2"O"_text(7(aq])^(4-)#</mathjax></p> </blockquote> <p>Notice that <mathjax>#1#</mathjax> <strong>mole</strong> of calcium diphosphate will produce <mathjax>#color(red)(2)#</mathjax> <strong>moles</strong> of calcium cations and <mathjax>#1#</mathjax> <strong>mole</strong> of diphosphate anions in solution. </p> <p>To find the concentration of diphosphate anions that will precipitate the calcium diphoshate, write the expression for the <a href="http://socratic.org/chemistry/chemical-equilibrium/ksp">solubility product constant</a>, <mathjax>#K_"sp"#</mathjax></p> <blockquote> <p><mathjax>#K_"sp" = ["Ca"^(2+)]^color(red)(2) * ["P"_2"O"_7^(4-)]#</mathjax></p> </blockquote> <p>Rearrange to solve for the cocnentration of diphosphate anions</p> <blockquote> <p><mathjax>#["P"_2"O"_7^(4-)] = K_text(sp)/(["Ca"^(2+)]^color(red)(2))#</mathjax></p> </blockquote> <p>You need to convert the concentration of the calcium ations to <em>moles per liter</em>. </p> <p>Now, since you didn't specify which units you must use for the concentration of the diphosphate anions, I"ll leave the answer expressed in <em>moles per liter</em> as well. </p> <p>This means that the concentration of the calcium cations will be </p> <blockquote> <p><mathjax>#9.2(color(red)(cancel(color(black)("mg"))))/(color(red)(cancel(color(black)("dL")))) * (10color(red)(cancel(color(black)("dL"))))/"1 L" * (1color(red)(cancel(color(black)("g"))))/(10^3color(red)(cancel(color(black)("mg")))) * "1 mole Ca"^(2+)/(40.078color(red)(cancel(color(black)("g")))) = 2.2955 * 10^(-3)"M"#</mathjax></p> </blockquote> <p>The concentration of the diphosphate anions will thus be </p> <blockquote> <p><mathjax>#["P"_2"O"_7^(4-)] = (8.64 * 10^(-13))/((2.2955 * 10^(-3))^2) = 1.64 * 10^(-7)"M"#</mathjax></p> </blockquote> <p>You need to round this value to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the concentration of calcium cations</p> <blockquote> <p><mathjax>#["P"_2"O"_7^(4-)] = color(green)(1.6 * 10^(-7)"M")#</mathjax></p> </blockquote> <p>As practice, you can convert this value to <mathjax>#"mg/dL"#</mathjax>. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Calcium phosphate will precipitate out of blood plasma when calcium concentration in blood is 9.2mg/dL, and Ksp for calcium diphosphate is 8.64x10^(-13), what minimum concentration of diphospate results in precipitation?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/reactions-between-ions-in-solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions Between Ions in Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="182012" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-01T22:41:05" itemprop="dateCreated"> Nov 1, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.6 * 10^(-7)"M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I assume that you're actually referring to <em>calcium diphosphate</em>, <mathjax>#"Ca"_2"P"_2"O"_7#</mathjax>, since the question aks for the concentration of the <em>disphosphate ions</em>, <mathjax>#"P"_2"O"_7^(4-)#</mathjax>. </p> <p>Moreover, <em>calcium phosphate</em>, <mathjax>#"Ca"_3("PO"_4)_2#</mathjax>, has a solubility product constant of about <mathjax>#2.0 * 10^(-33)#</mathjax>, much, much smaller than what you have there. </p> <p>So, calcium diphosphate is insoluble in blood plasma, which means that an equilibrium reaction is established between the solid and the dissolved ions</p> <blockquote> <p><mathjax>#"Ca"_2"P"_2"O"_text(7(s]) rightleftharpoons color(red)(2)"Ca"_text((aq])^(2+) + "P"_2"O"_text(7(aq])^(4-)#</mathjax></p> </blockquote> <p>Notice that <mathjax>#1#</mathjax> <strong>mole</strong> of calcium diphosphate will produce <mathjax>#color(red)(2)#</mathjax> <strong>moles</strong> of calcium cations and <mathjax>#1#</mathjax> <strong>mole</strong> of diphosphate anions in solution. </p> <p>To find the concentration of diphosphate anions that will precipitate the calcium diphoshate, write the expression for the <a href="http://socratic.org/chemistry/chemical-equilibrium/ksp">solubility product constant</a>, <mathjax>#K_"sp"#</mathjax></p> <blockquote> <p><mathjax>#K_"sp" = ["Ca"^(2+)]^color(red)(2) * ["P"_2"O"_7^(4-)]#</mathjax></p> </blockquote> <p>Rearrange to solve for the cocnentration of diphosphate anions</p> <blockquote> <p><mathjax>#["P"_2"O"_7^(4-)] = K_text(sp)/(["Ca"^(2+)]^color(red)(2))#</mathjax></p> </blockquote> <p>You need to convert the concentration of the calcium ations to <em>moles per liter</em>. </p> <p>Now, since you didn't specify which units you must use for the concentration of the diphosphate anions, I"ll leave the answer expressed in <em>moles per liter</em> as well. </p> <p>This means that the concentration of the calcium cations will be </p> <blockquote> <p><mathjax>#9.2(color(red)(cancel(color(black)("mg"))))/(color(red)(cancel(color(black)("dL")))) * (10color(red)(cancel(color(black)("dL"))))/"1 L" * (1color(red)(cancel(color(black)("g"))))/(10^3color(red)(cancel(color(black)("mg")))) * "1 mole Ca"^(2+)/(40.078color(red)(cancel(color(black)("g")))) = 2.2955 * 10^(-3)"M"#</mathjax></p> </blockquote> <p>The concentration of the diphosphate anions will thus be </p> <blockquote> <p><mathjax>#["P"_2"O"_7^(4-)] = (8.64 * 10^(-13))/((2.2955 * 10^(-3))^2) = 1.64 * 10^(-7)"M"#</mathjax></p> </blockquote> <p>You need to round this value to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the concentration of calcium cations</p> <blockquote> <p><mathjax>#["P"_2"O"_7^(4-)] = color(green)(1.6 * 10^(-7)"M")#</mathjax></p> </blockquote> <p>As practice, you can convert this value to <mathjax>#"mg/dL"#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/182012" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-ions-are-present-in-solutions-of-sodium-hydroxide"> What ions are present in solutions of sodium hydroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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Calcium phosphate will precipitate out of blood plasma when calcium concentration in blood is 9.2mg/dL, and Ksp for calcium diphosphate is 8.64x10^(-13), what minimum concentration of diphospate results in precipitation?

a842ca9a-6ddd-11ea-8e52-ccda262736ce

https://socratic.org/questions/a-2400-gram-sample-of-an-aqueous-solution-contains-0-012-gram-of-nh-3-what-is-th

5 parts per million

start physical_unit 12 12 concentration ppm qc_end physical_unit 3 7 1 2 mass qc_end physical_unit 12 12 9 10 mass qc_end end

[{"type":"physical unit","value":"Concentration [OF] NH3 [IN] parts per million"}]

[{"type":"physical unit","value":"5 parts per million"}]

[{"type":"physical unit","value":"Mass [OF] an aqueous solution sample [=] \\pu{2400 gram}"},{"type":"physical unit","value":"Mass [OF] NH3 [=] \\pu{0.012 gram}"}]

<h1 class="questionTitle" itemprop="name">A 2400-gram sample of an aqueous solution contains 0.012 gram of #NH_3#. What is the concentration of #NH_3# in the solution, expressed as parts per million?</h1>

5 parts per million

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At <mathjax>#"ppm"#</mathjax> concentrations, we don't have to bother with consideration of the <a href="http://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> versus the density of the solution; in any case we don't have these details.</p> <p>There are <mathjax>#12xx10^-3#</mathjax> <mathjax>#g#</mathjax> ammonia in a <mathjax>#2400#</mathjax> <mathjax>#g#</mathjax> mass of solution. We assume (reasonably) that the volume of the solution is <mathjax>#2.400*L#</mathjax>.</p> <p>So <mathjax>#"concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(12xx10^-3gxx10^3*mg*g^-1)/(2.400*L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(12*mg)/(2.400*L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#5*mg*L^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#5#</mathjax> <mathjax>#"ppm"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Parts per million "= " Milligram per litre of solution"#</mathjax>. The concentration of the solution is <mathjax>#5#</mathjax> <mathjax>#"ppm"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At <mathjax>#"ppm"#</mathjax> concentrations, we don't have to bother with consideration of the <a href="http://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> versus the density of the solution; in any case we don't have these details.</p> <p>There are <mathjax>#12xx10^-3#</mathjax> <mathjax>#g#</mathjax> ammonia in a <mathjax>#2400#</mathjax> <mathjax>#g#</mathjax> mass of solution. We assume (reasonably) that the volume of the solution is <mathjax>#2.400*L#</mathjax>.</p> <p>So <mathjax>#"concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(12xx10^-3gxx10^3*mg*g^-1)/(2.400*L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(12*mg)/(2.400*L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#5*mg*L^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#5#</mathjax> <mathjax>#"ppm"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A 2400-gram sample of an aqueous solution contains 0.012 gram of #NH_3#. What is the concentration of #NH_3# in the solution, expressed as parts per million?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solving-using-ppm-parts-per-million" itemprop="url"> <span class="breadcrumb" itemprop="title">Solving Using PPM (Parts Per Million)</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="238056" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-11T05:04:00" itemprop="dateCreated"> Mar 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Parts per million "= " Milligram per litre of solution"#</mathjax>. The concentration of the solution is <mathjax>#5#</mathjax> <mathjax>#"ppm"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At <mathjax>#"ppm"#</mathjax> concentrations, we don't have to bother with consideration of the <a href="http://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> versus the density of the solution; in any case we don't have these details.</p> <p>There are <mathjax>#12xx10^-3#</mathjax> <mathjax>#g#</mathjax> ammonia in a <mathjax>#2400#</mathjax> <mathjax>#g#</mathjax> mass of solution. We assume (reasonably) that the volume of the solution is <mathjax>#2.400*L#</mathjax>.</p> <p>So <mathjax>#"concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(12xx10^-3gxx10^3*mg*g^-1)/(2.400*L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(12*mg)/(2.400*L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#5*mg*L^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#5#</mathjax> <mathjax>#"ppm"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/238056" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-ppm"> What is PPM? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-ppm-be-calculated-in-chemistry"> How can PPM be calculated in chemistry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ppm-a-useful-measurement"> Why is PPM a useful measurement? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54c39459581e2a50bb6742ad"> Question #742ad </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54c4d4dc581e2a50d46797aa"> Question #797aa </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/h2s-g-concentrations-of-660ppm-is-dangerous-6-h2s-generators-continually-release"> H2S (g) concentrations of 660ppm is dangerous. 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A 2400-gram sample of an aqueous solution contains 0.012 gram of #NH_3#. What is the concentration of #NH_3# in the solution, expressed as parts per million?

ac328cc9-6ddd-11ea-92bf-ccda262736ce

https://socratic.org/questions/596636f57c014971b1c680e1

Mg(s) -> Mg^2+ + 2 e-

start chemical_equation qc_end c_other OTHER qc_end substance 16 17 qc_end substance 19 20 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the oxidation"}]

[{"type":"chemical equation","value":"Mg(s) -> Mg^2+ + 2 e-"}]

[{"type":"other","value":"Use the method of half-equations, and redox formalism."},{"type":"substance name","value":"Magnesium metal"},{"type":"substance name","value":"Hydrochloric acid"}]

<h1 class="questionTitle" itemprop="name">How do we use the method of half-equations, and redox formalism to represent the oxidation of magnesium metal by hydrochloric acid?</h1>

Mg(s) -> Mg^2+ + 2 e-

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have performed a redox reaction, the which we could formally separate into oxidation/reduction half equations.......</p> <p><mathjax>#Mg(s) rarr Mg^(2+) +2e^-#</mathjax> <mathjax>#(i)#</mathjax>, i.e. the electron rich metal formally LOSES 2 <a href="https://socratic.org/chemistry/the-periodic-table/valence-electrons-and-the-periodic-table">valence electrons</a></p> <p>And a reduction half-equation.......</p> <p><mathjax>#HCl(aq) + e^(-) rarr 1/2H_2(g)uarr +Cl^-#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>A oxidizing protium ion formally gains one electron........</p> <p>We add <mathjax>#(i)#</mathjax> and <mathjax>#(ii)#</mathjax> such that electrons DO NOT APPEAR in the final redox equation, i.e. <mathjax>#(i) + 2xx(ii)#</mathjax> gives.........</p> <p><mathjax>#Mg(s) + 2HCl(aq) rarr MgCl_2(aq) + H_2(g)uarr#</mathjax></p> <p>........alternatively.......</p> <p><mathjax>#Mg(s) + 2HCl(aq) rarr Mg^(2+) + 2Cl^(-) + H_2(g)uarr#</mathjax></p> <p>Charge and mass are CONSERVED, as is absolutely required for ANY chemical reaction.......</p> <p>Capisce?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <mathjax>#"oxidation state"#</mathjax> of magnesium metal is a big fat <mathjax>#"ZERO"#</mathjax>........ And the metal oxidation state in <mathjax>#MgCl_2#</mathjax> is <mathjax>#+II#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have performed a redox reaction, the which we could formally separate into oxidation/reduction half equations.......</p> <p><mathjax>#Mg(s) rarr Mg^(2+) +2e^-#</mathjax> <mathjax>#(i)#</mathjax>, i.e. the electron rich metal formally LOSES 2 <a href="https://socratic.org/chemistry/the-periodic-table/valence-electrons-and-the-periodic-table">valence electrons</a></p> <p>And a reduction half-equation.......</p> <p><mathjax>#HCl(aq) + e^(-) rarr 1/2H_2(g)uarr +Cl^-#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>A oxidizing protium ion formally gains one electron........</p> <p>We add <mathjax>#(i)#</mathjax> and <mathjax>#(ii)#</mathjax> such that electrons DO NOT APPEAR in the final redox equation, i.e. <mathjax>#(i) + 2xx(ii)#</mathjax> gives.........</p> <p><mathjax>#Mg(s) + 2HCl(aq) rarr MgCl_2(aq) + H_2(g)uarr#</mathjax></p> <p>........alternatively.......</p> <p><mathjax>#Mg(s) + 2HCl(aq) rarr Mg^(2+) + 2Cl^(-) + H_2(g)uarr#</mathjax></p> <p>Charge and mass are CONSERVED, as is absolutely required for ANY chemical reaction.......</p> <p>Capisce?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do we use the method of half-equations, and redox formalism to represent the oxidation of magnesium metal by hydrochloric acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-numbers" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation Numbers</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="450843" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-12T18:06:42" itemprop="dateCreated"> Jul 12, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <mathjax>#"oxidation state"#</mathjax> of magnesium metal is a big fat <mathjax>#"ZERO"#</mathjax>........ And the metal oxidation state in <mathjax>#MgCl_2#</mathjax> is <mathjax>#+II#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have performed a redox reaction, the which we could formally separate into oxidation/reduction half equations.......</p> <p><mathjax>#Mg(s) rarr Mg^(2+) +2e^-#</mathjax> <mathjax>#(i)#</mathjax>, i.e. the electron rich metal formally LOSES 2 <a href="https://socratic.org/chemistry/the-periodic-table/valence-electrons-and-the-periodic-table">valence electrons</a></p> <p>And a reduction half-equation.......</p> <p><mathjax>#HCl(aq) + e^(-) rarr 1/2H_2(g)uarr +Cl^-#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>A oxidizing protium ion formally gains one electron........</p> <p>We add <mathjax>#(i)#</mathjax> and <mathjax>#(ii)#</mathjax> such that electrons DO NOT APPEAR in the final redox equation, i.e. <mathjax>#(i) + 2xx(ii)#</mathjax> gives.........</p> <p><mathjax>#Mg(s) + 2HCl(aq) rarr MgCl_2(aq) + H_2(g)uarr#</mathjax></p> <p>........alternatively.......</p> <p><mathjax>#Mg(s) + 2HCl(aq) rarr Mg^(2+) + 2Cl^(-) + H_2(g)uarr#</mathjax></p> <p>Charge and mass are CONSERVED, as is absolutely required for ANY chemical reaction.......</p> <p>Capisce?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/450843" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-electron-configuration"> How do oxidation numbers relate to electron configuration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-valence-electrons"> How do oxidation numbers relate to valence electrons? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-vary-with-the-periodic-table"> How do oxidation numbers vary with the periodic table? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-oxidation-number-of-an-element-in-a-compound"> How do you calculate the oxidation number of an element in a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-sulfur"> What is the oxidation number for sulfur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-carbon"> What is the oxidation number for carbon? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-copper"> What is the oxidation number for copper? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-nitrogen"> What is the oxidation number for nitrogen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-oxygen"> What is the oxidation number for oxygen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-state-of-noble-gas-zero"> Why is the oxidation state of noble gas zero? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-numbers"> See all questions in Oxidation Numbers </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1483 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How do we use the method of half-equations, and redox formalism to represent the oxidation of magnesium metal by hydrochloric acid?

a8de024a-6ddd-11ea-b198-ccda262736ce

https://socratic.org/questions/591e6bd17c01491a6e3eb402

0.05 M

start physical_unit 22 24 concentration mol/l qc_end physical_unit 6 6 0 1 volume qc_end physical_unit 8 8 4 5 concentration qc_end physical_unit 6 6 15 16 volume qc_end end

[{"type":"physical unit","value":"Concentration2 [OF] the new solution [IN] M"}]

[{"type":"physical unit","value":"0.05 M"}]

[{"type":"physical unit","value":"Volume1 [OF] HCL solution [=] \\pu{60 mL}"},{"type":"physical unit","value":"Concentration1 [OF] HCL solution [=] \\pu{1.5 M}"},{"type":"physical unit","value":"Volume2 [OF] HCL solution [=] \\pu{2.0 L}"}]

<h1 class="questionTitle" itemprop="name">#60# #mL# of a #1.5# #M# solution of #HCl# is diluted to a volume of #2.0# #L#. What is the concentration of the new solution?</h1>

0.05 M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The solution to this is a two-step process: finding the number of moles of HCl in the initial solution, then calculating the concentration of the final solution. </p> <p>We will use the equation <mathjax>#C = n/V#</mathjax> in both steps.</p> <p><mathjax>#C#</mathjax> is the concentration in <mathjax>#molL^-1#</mathjax> (also called <mathjax>#M#</mathjax>), <mathjax>#n#</mathjax> is the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> and <mathjax>#V#</mathjax> is the volume of the solution in <mathjax>#L#</mathjax>.</p> <p>For step 1, rearrange to make <mathjax>#n#</mathjax> the subject:</p> <p><mathjax>#n = CV = 1.5xx0.060 = 0.09#</mathjax> <mathjax>#mol#</mathjax> (changing the volume from <mathjax>#mL#</mathjax> to <mathjax>#L#</mathjax>)</p> <p>For step 2, the original formula is what we need:</p> <p><mathjax>#C = n/V = 0.09/2 = 0.045#</mathjax> <mathjax>#molL^-1#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Step 1: <mathjax>#n = CV = 1.5xx0.060 = 0.09#</mathjax> <mathjax>#mol#</mathjax></p> <p>Step 2: <br/> <mathjax>#C = n/V = 0.09/2 = 0.045#</mathjax> <mathjax>#molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The solution to this is a two-step process: finding the number of moles of HCl in the initial solution, then calculating the concentration of the final solution. </p> <p>We will use the equation <mathjax>#C = n/V#</mathjax> in both steps.</p> <p><mathjax>#C#</mathjax> is the concentration in <mathjax>#molL^-1#</mathjax> (also called <mathjax>#M#</mathjax>), <mathjax>#n#</mathjax> is the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> and <mathjax>#V#</mathjax> is the volume of the solution in <mathjax>#L#</mathjax>.</p> <p>For step 1, rearrange to make <mathjax>#n#</mathjax> the subject:</p> <p><mathjax>#n = CV = 1.5xx0.060 = 0.09#</mathjax> <mathjax>#mol#</mathjax> (changing the volume from <mathjax>#mL#</mathjax> to <mathjax>#L#</mathjax>)</p> <p>For step 2, the original formula is what we need:</p> <p><mathjax>#C = n/V = 0.09/2 = 0.045#</mathjax> <mathjax>#molL^-1#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">#60# #mL# of a #1.5# #M# solution of #HCl# is diluted to a volume of #2.0# #L#. What is the concentration of the new solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/dilution-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Dilution Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="427122" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/david-g-6"><img alt="" class="" src="https://graph.facebook.com/10153408096237887/picture?height=50&amp;width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/david-g-6"> David G. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-21T11:05:10" itemprop="dateCreated"> May 21, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Step 1: <mathjax>#n = CV = 1.5xx0.060 = 0.09#</mathjax> <mathjax>#mol#</mathjax></p> <p>Step 2: <br/> <mathjax>#C = n/V = 0.09/2 = 0.045#</mathjax> <mathjax>#molL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The solution to this is a two-step process: finding the number of moles of HCl in the initial solution, then calculating the concentration of the final solution. </p> <p>We will use the equation <mathjax>#C = n/V#</mathjax> in both steps.</p> <p><mathjax>#C#</mathjax> is the concentration in <mathjax>#molL^-1#</mathjax> (also called <mathjax>#M#</mathjax>), <mathjax>#n#</mathjax> is the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> and <mathjax>#V#</mathjax> is the volume of the solution in <mathjax>#L#</mathjax>.</p> <p>For step 1, rearrange to make <mathjax>#n#</mathjax> the subject:</p> <p><mathjax>#n = CV = 1.5xx0.060 = 0.09#</mathjax> <mathjax>#mol#</mathjax> (changing the volume from <mathjax>#mL#</mathjax> to <mathjax>#L#</mathjax>)</p> <p>For step 2, the original formula is what we need:</p> <p><mathjax>#C = n/V = 0.09/2 = 0.045#</mathjax> <mathjax>#molL^-1#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/427122" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-absorbance"> How do you calculate concentration from absorbance? 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#60# #mL# of a #1.5# #M# solution of #HCl# is diluted to a volume of #2.0# #L#. What is the concentration of the new solution?

a96bd658-6ddd-11ea-abe3-ccda262736ce

https://socratic.org/questions/what-s-the-empirical-formula-of-a-molecule-containing-18-7-lithium-16-3-carbon-a

Li2CO3

start chemical_formula qc_end end

[{"type":"other","value":"Chemical Formula [OF] the molecule [IN] empirical"}]

[{"type":"chemical equation","value":"Li2CO3"}]

[{"type":"physical unit","value":"Percent [OF] lithium in the molecule [=] \\pu{18.7%}"},{"type":"physical unit","value":"Percent [OF] carbon in the molecule [=] \\pu{16.3%}"},{"type":"physical unit","value":"Percent [OF] oxygen in the molecule [=] \\pu{65.0%}"}]

<h1 class="questionTitle" itemprop="name">What’s the empirical formula of a molecule containing 18.7% lithium, 16.3% carbon, and 65.0% oxygen?</h1>

Li2CO3

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Solution:</p> <p>1) Assume <mathjax>#"100 g"#</mathjax> of the compound is present. <mathjax>#"100 g"#</mathjax> of this compound on decomposition gives me </p> <blockquote> <ul> <li><mathjax>#"Li" =&gt; 18.7 %#</mathjax> or <mathjax>#"18.7 g"#</mathjax> of <mathjax>#"Li"#</mathjax></li> <li><mathjax>#"C" =&gt; 16.3 %#</mathjax> or <mathjax>#"16.3 g"#</mathjax> of <mathjax>#"C"#</mathjax></li> <li><mathjax>#"O" =&gt; 65.0%#</mathjax> or <mathjax>#"65 g"#</mathjax> of <mathjax>#"O"#</mathjax></li> </ul> </blockquote> <p>2) Calculate the number of moles of each element.</p> <p><mathjax>#"no. of moles" = "mass of the element"/"molar mass of the element"#</mathjax></p> <p>So</p> <p><mathjax>#"moles of Li" = "18.7 g" /"7 g mol"^(-1) = "2.6 moles"#</mathjax></p> <p><mathjax>#"moles of C" = "16.3 g"/"12 g mol"^(-1) = "1.3 moles"#</mathjax></p> <p><mathjax>#"moles of O" = "65 g"/"15.9 g mol"^(-1) = "4.0 moles"#</mathjax></p> <p>3) Divide by the lowest, seeking the smallest whole-number ratio: </p> <p><mathjax>#"Li: " "2.6 moles" /"1.3 moles" = 2#</mathjax></p> <p><mathjax>#"C: " "1.3 moles"/"1.3 moles" =1#</mathjax></p> <p><mathjax>#"O: " "4.0 moles"/"1.3 moles" = 3#</mathjax></p> <p>4 ) The empirical formula is <mathjax>#"Li"_2 "C"_1"O"_3#</mathjax>, or <mathjax>#"Li"_2"CO"_3#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Li"_2"CO"_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Solution:</p> <p>1) Assume <mathjax>#"100 g"#</mathjax> of the compound is present. <mathjax>#"100 g"#</mathjax> of this compound on decomposition gives me </p> <blockquote> <ul> <li><mathjax>#"Li" =&gt; 18.7 %#</mathjax> or <mathjax>#"18.7 g"#</mathjax> of <mathjax>#"Li"#</mathjax></li> <li><mathjax>#"C" =&gt; 16.3 %#</mathjax> or <mathjax>#"16.3 g"#</mathjax> of <mathjax>#"C"#</mathjax></li> <li><mathjax>#"O" =&gt; 65.0%#</mathjax> or <mathjax>#"65 g"#</mathjax> of <mathjax>#"O"#</mathjax></li> </ul> </blockquote> <p>2) Calculate the number of moles of each element.</p> <p><mathjax>#"no. of moles" = "mass of the element"/"molar mass of the element"#</mathjax></p> <p>So</p> <p><mathjax>#"moles of Li" = "18.7 g" /"7 g mol"^(-1) = "2.6 moles"#</mathjax></p> <p><mathjax>#"moles of C" = "16.3 g"/"12 g mol"^(-1) = "1.3 moles"#</mathjax></p> <p><mathjax>#"moles of O" = "65 g"/"15.9 g mol"^(-1) = "4.0 moles"#</mathjax></p> <p>3) Divide by the lowest, seeking the smallest whole-number ratio: </p> <p><mathjax>#"Li: " "2.6 moles" /"1.3 moles" = 2#</mathjax></p> <p><mathjax>#"C: " "1.3 moles"/"1.3 moles" =1#</mathjax></p> <p><mathjax>#"O: " "4.0 moles"/"1.3 moles" = 3#</mathjax></p> <p>4 ) The empirical formula is <mathjax>#"Li"_2 "C"_1"O"_3#</mathjax>, or <mathjax>#"Li"_2"CO"_3#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What’s the empirical formula of a molecule containing 18.7% lithium, 16.3% carbon, and 65.0% oxygen?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/percent-composition" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Composition</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="106810" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/manish-b"><img alt="" class="" src="https://profilepictures.socratic.org/eW7uaERSSvtv5ff2XPxA_10203153902643748.jpg" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/manish-b"> Manish Bhardwaj </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2014-07-16T05:21:03" itemprop="dateCreated"> Jul 16, 2014 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Li"_2"CO"_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Solution:</p> <p>1) Assume <mathjax>#"100 g"#</mathjax> of the compound is present. <mathjax>#"100 g"#</mathjax> of this compound on decomposition gives me </p> <blockquote> <ul> <li><mathjax>#"Li" =&gt; 18.7 %#</mathjax> or <mathjax>#"18.7 g"#</mathjax> of <mathjax>#"Li"#</mathjax></li> <li><mathjax>#"C" =&gt; 16.3 %#</mathjax> or <mathjax>#"16.3 g"#</mathjax> of <mathjax>#"C"#</mathjax></li> <li><mathjax>#"O" =&gt; 65.0%#</mathjax> or <mathjax>#"65 g"#</mathjax> of <mathjax>#"O"#</mathjax></li> </ul> </blockquote> <p>2) Calculate the number of moles of each element.</p> <p><mathjax>#"no. of moles" = "mass of the element"/"molar mass of the element"#</mathjax></p> <p>So</p> <p><mathjax>#"moles of Li" = "18.7 g" /"7 g mol"^(-1) = "2.6 moles"#</mathjax></p> <p><mathjax>#"moles of C" = "16.3 g"/"12 g mol"^(-1) = "1.3 moles"#</mathjax></p> <p><mathjax>#"moles of O" = "65 g"/"15.9 g mol"^(-1) = "4.0 moles"#</mathjax></p> <p>3) Divide by the lowest, seeking the smallest whole-number ratio: </p> <p><mathjax>#"Li: " "2.6 moles" /"1.3 moles" = 2#</mathjax></p> <p><mathjax>#"C: " "1.3 moles"/"1.3 moles" =1#</mathjax></p> <p><mathjax>#"O: " "4.0 moles"/"1.3 moles" = 3#</mathjax></p> <p>4 ) The empirical formula is <mathjax>#"Li"_2 "C"_1"O"_3#</mathjax>, or <mathjax>#"Li"_2"CO"_3#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/106810" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-mole-percent"> What is mole percent? 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What’s the empirical formula of a molecule containing 18.7% lithium, 16.3% carbon, and 65.0% oxygen?

a9f6b101-6ddd-11ea-a942-ccda262736ce

https://socratic.org/questions/lisa-will-make-punch-that-is-25-fruit-juice-by-adding-pure-fruit-juice-to-a-2-1i

0.4 liters

start physical_unit 11 13 volume l qc_end physical_unit 7 8 6 6 percent qc_end physical_unit 7 8 21 21 percent qc_end physical_unit 7 8 16 17 volume qc_end end

[{"type":"physical unit","value":"Volume [OF] pure fruit juice [IN] liters"}]

[{"type":"physical unit","value":"0.4 liters"}]

[{"type":"physical unit","value":"Percent1 [OF] fruit juice in solution [=] \\pu{25%}"},{"type":"physical unit","value":"Percent2 [OF] fruit juice in solution [=] \\pu{10%}"},{"type":"physical unit","value":"Volume2 [OF] fruit juice [=] \\pu{2 liters}"}]

<h1 class="questionTitle" itemprop="name">Lisa will make punch that is 25% fruit juice by adding pure fruit juice to a 2-liter mixture that is 10% pure fruit juice. How many liters of pure fruit juice does she need to add?</h1>

0.4 liters

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to find the <strong>volume</strong> (in liters) of <mathjax>#100%#</mathjax> fruit juice that must be added to <mathjax>#1#</mathjax> <mathjax>#"L"#</mathjax> of a <mathjax>#10%#</mathjax> fruit juice mixture so that the final concentration is <mathjax>#25%#</mathjax>.</p> <blockquote></blockquote> <p>To do this, we can use the following relationship:</p> <blockquote> <p><mathjax>#C_"final"V_"final" = C_"pure"V_"pure" + C_(25%)V_(25%)#</mathjax></p> </blockquote> <p>where</p> <ul> <li> <p><mathjax>#C_"final"#</mathjax> and <mathjax>#V_"final"#</mathjax> are the <strong>concentration</strong> and <strong>volume</strong> of the <strong>final solution</strong>. We're given that the final concentration must be <mathjax>#25%#</mathjax>.</p> </li> <li> <p><mathjax>#C_"pure"#</mathjax> and <mathjax>#V_"pure"#</mathjax> are the <strong>concentration</strong> and <strong>volume</strong> of the <strong>pure</strong> solution. We'll say that a pure solution has a concentration of <mathjax>#1#</mathjax>.</p> </li> <li> <p><mathjax>#C_(25%)#</mathjax> and <mathjax>#V_(25%)#</mathjax> are the <strong>concentration</strong> and <strong>volume</strong> of the <mathjax>#25%#</mathjax> solution. We're given both of these quantities as <mathjax>#0.10#</mathjax> and <mathjax>#2#</mathjax> <mathjax>#"L"#</mathjax> respectively.</p> </li> </ul> <p>Plugging in all known values, we have</p> <blockquote> <p><mathjax>#0.25(V_"final") = 1(V_"pure") + 0.10(2color(white)(l)"L")#</mathjax></p> <blockquote></blockquote> </blockquote> <p>Volumes here are going to be <strong>additive</strong>; that is, the final volume will be the sum of the volumes of the two components:</p> <blockquote> <p><mathjax>#V_"final" = V_"pure" + 2color(white)(l)"L"#</mathjax></p> </blockquote> <p>We'll now plug this into the equation for <mathjax>#V_"final"#</mathjax>:</p> <blockquote> <p><mathjax>#0.25(V_"pure" + 2color(white)(l)"L") = V_"pure" + 0.10(2color(white)(l)"L")#</mathjax></p> <blockquote></blockquote> </blockquote> <p>Now, we just solve for the necessary volume, <mathjax>#V_"pure"#</mathjax>:</p> <blockquote> <p><mathjax>#0.25(V_"pure") + 0.5color(white)(l)"L" = V_"pure" + 0.2color(white)(l)"L"#</mathjax></p> <p><mathjax>#0.25(V_"pure") + 0.3color(white)(l)"L" = V_"pure"#</mathjax></p> </blockquote> <p>Divide all terms by <mathjax>#V_"pure"#</mathjax>:</p> <blockquote> <p><mathjax>#0.25 + (0.3color(white)(l)"L")/(V_"pure") = 1#</mathjax></p> <p><mathjax>#(0.3color(white)(l)"L")/(V_"pure") = 0.75#</mathjax></p> <p><mathjax>#color(red)(ulbar(|stackrel(" ")(" "V_"pure" = 0.4color(white)(l)"L"" ")|)#</mathjax></p> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.4#</mathjax> <mathjax>#"L"#</mathjax> must be added.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to find the <strong>volume</strong> (in liters) of <mathjax>#100%#</mathjax> fruit juice that must be added to <mathjax>#1#</mathjax> <mathjax>#"L"#</mathjax> of a <mathjax>#10%#</mathjax> fruit juice mixture so that the final concentration is <mathjax>#25%#</mathjax>.</p> <blockquote></blockquote> <p>To do this, we can use the following relationship:</p> <blockquote> <p><mathjax>#C_"final"V_"final" = C_"pure"V_"pure" + C_(25%)V_(25%)#</mathjax></p> </blockquote> <p>where</p> <ul> <li> <p><mathjax>#C_"final"#</mathjax> and <mathjax>#V_"final"#</mathjax> are the <strong>concentration</strong> and <strong>volume</strong> of the <strong>final solution</strong>. We're given that the final concentration must be <mathjax>#25%#</mathjax>.</p> </li> <li> <p><mathjax>#C_"pure"#</mathjax> and <mathjax>#V_"pure"#</mathjax> are the <strong>concentration</strong> and <strong>volume</strong> of the <strong>pure</strong> solution. We'll say that a pure solution has a concentration of <mathjax>#1#</mathjax>.</p> </li> <li> <p><mathjax>#C_(25%)#</mathjax> and <mathjax>#V_(25%)#</mathjax> are the <strong>concentration</strong> and <strong>volume</strong> of the <mathjax>#25%#</mathjax> solution. We're given both of these quantities as <mathjax>#0.10#</mathjax> and <mathjax>#2#</mathjax> <mathjax>#"L"#</mathjax> respectively.</p> </li> </ul> <p>Plugging in all known values, we have</p> <blockquote> <p><mathjax>#0.25(V_"final") = 1(V_"pure") + 0.10(2color(white)(l)"L")#</mathjax></p> <blockquote></blockquote> </blockquote> <p>Volumes here are going to be <strong>additive</strong>; that is, the final volume will be the sum of the volumes of the two components:</p> <blockquote> <p><mathjax>#V_"final" = V_"pure" + 2color(white)(l)"L"#</mathjax></p> </blockquote> <p>We'll now plug this into the equation for <mathjax>#V_"final"#</mathjax>:</p> <blockquote> <p><mathjax>#0.25(V_"pure" + 2color(white)(l)"L") = V_"pure" + 0.10(2color(white)(l)"L")#</mathjax></p> <blockquote></blockquote> </blockquote> <p>Now, we just solve for the necessary volume, <mathjax>#V_"pure"#</mathjax>:</p> <blockquote> <p><mathjax>#0.25(V_"pure") + 0.5color(white)(l)"L" = V_"pure" + 0.2color(white)(l)"L"#</mathjax></p> <p><mathjax>#0.25(V_"pure") + 0.3color(white)(l)"L" = V_"pure"#</mathjax></p> </blockquote> <p>Divide all terms by <mathjax>#V_"pure"#</mathjax>:</p> <blockquote> <p><mathjax>#0.25 + (0.3color(white)(l)"L")/(V_"pure") = 1#</mathjax></p> <p><mathjax>#(0.3color(white)(l)"L")/(V_"pure") = 0.75#</mathjax></p> <p><mathjax>#color(red)(ulbar(|stackrel(" ")(" "V_"pure" = 0.4color(white)(l)"L"" ")|)#</mathjax></p> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Lisa will make punch that is 25% fruit juice by adding pure fruit juice to a 2-liter mixture that is 10% pure fruit juice. How many liters of pure fruit juice does she need to add?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solution-formation---what-happens-when-stuff-dissolves" itemprop="url"> <span class="breadcrumb" itemprop="title">Solution Formation</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="470885" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-02T14:20:54" itemprop="dateCreated"> Sep 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.4#</mathjax> <mathjax>#"L"#</mathjax> must be added.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to find the <strong>volume</strong> (in liters) of <mathjax>#100%#</mathjax> fruit juice that must be added to <mathjax>#1#</mathjax> <mathjax>#"L"#</mathjax> of a <mathjax>#10%#</mathjax> fruit juice mixture so that the final concentration is <mathjax>#25%#</mathjax>.</p> <blockquote></blockquote> <p>To do this, we can use the following relationship:</p> <blockquote> <p><mathjax>#C_"final"V_"final" = C_"pure"V_"pure" + C_(25%)V_(25%)#</mathjax></p> </blockquote> <p>where</p> <ul> <li> <p><mathjax>#C_"final"#</mathjax> and <mathjax>#V_"final"#</mathjax> are the <strong>concentration</strong> and <strong>volume</strong> of the <strong>final solution</strong>. We're given that the final concentration must be <mathjax>#25%#</mathjax>.</p> </li> <li> <p><mathjax>#C_"pure"#</mathjax> and <mathjax>#V_"pure"#</mathjax> are the <strong>concentration</strong> and <strong>volume</strong> of the <strong>pure</strong> solution. We'll say that a pure solution has a concentration of <mathjax>#1#</mathjax>.</p> </li> <li> <p><mathjax>#C_(25%)#</mathjax> and <mathjax>#V_(25%)#</mathjax> are the <strong>concentration</strong> and <strong>volume</strong> of the <mathjax>#25%#</mathjax> solution. We're given both of these quantities as <mathjax>#0.10#</mathjax> and <mathjax>#2#</mathjax> <mathjax>#"L"#</mathjax> respectively.</p> </li> </ul> <p>Plugging in all known values, we have</p> <blockquote> <p><mathjax>#0.25(V_"final") = 1(V_"pure") + 0.10(2color(white)(l)"L")#</mathjax></p> <blockquote></blockquote> </blockquote> <p>Volumes here are going to be <strong>additive</strong>; that is, the final volume will be the sum of the volumes of the two components:</p> <blockquote> <p><mathjax>#V_"final" = V_"pure" + 2color(white)(l)"L"#</mathjax></p> </blockquote> <p>We'll now plug this into the equation for <mathjax>#V_"final"#</mathjax>:</p> <blockquote> <p><mathjax>#0.25(V_"pure" + 2color(white)(l)"L") = V_"pure" + 0.10(2color(white)(l)"L")#</mathjax></p> <blockquote></blockquote> </blockquote> <p>Now, we just solve for the necessary volume, <mathjax>#V_"pure"#</mathjax>:</p> <blockquote> <p><mathjax>#0.25(V_"pure") + 0.5color(white)(l)"L" = V_"pure" + 0.2color(white)(l)"L"#</mathjax></p> <p><mathjax>#0.25(V_"pure") + 0.3color(white)(l)"L" = V_"pure"#</mathjax></p> </blockquote> <p>Divide all terms by <mathjax>#V_"pure"#</mathjax>:</p> <blockquote> <p><mathjax>#0.25 + (0.3color(white)(l)"L")/(V_"pure") = 1#</mathjax></p> <p><mathjax>#(0.3color(white)(l)"L")/(V_"pure") = 0.75#</mathjax></p> <p><mathjax>#color(red)(ulbar(|stackrel(" ")(" "V_"pure" = 0.4color(white)(l)"L"" ")|)#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/470885" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-temperature-affect-the-formation-of-a-solution"> How can temperature affect the formation of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-formation-of-a-solution-be-exothermic-or-endothermic"> How can the formation of a solution be exothermic or endothermic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-formation-of-a-solution-involve-energy"> How does the formation of a solution involve energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-heat-formation-of-solution"> How do you find heat of formation of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factor-promotes-the-formation-of-solutions"> Which factors promote the formation of solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/which-two-processes-are-at-equilibrium-in-a-saturated-sugar-solution"> Which two processes are at equilibrium in a saturated sugar solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutes-lower-the-freezing-point"> Why do solutes lower the freezing point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-solution-formation-require-energy"> Why does solution formation require energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutes-dissolve-in-solvents"> Why do solutes dissolve in solvents? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-solvent-dissolves-silicone"> What solvent dissolves silicone? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/solution-formation---what-happens-when-stuff-dissolves"> See all questions in Solution Formation </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2200 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

Lisa will make punch that is 25% fruit juice by adding pure fruit juice to a 2-liter mixture that is 10% pure fruit juice. How many liters of pure fruit juice does she need to add?

a9037d8a-6ddd-11ea-9e69-ccda262736ce

https://socratic.org/questions/how-many-moles-of-cl-are-in-1-2-10-24-formula-units-of-magnesium-chloride

4.00 moles

start physical_unit 4 4 mole mol qc_end end

[{"type":"physical unit","value":"Mole [OF] Cl [IN] moles"}]

[{"type":"physical unit","value":"4.00 moles"}]

[{"type":"physical unit","value":"Number [OF] magnesium chloride formula units [=] \\pu{1.2 × 10^24}"}]

<h1 class="questionTitle" itemprop="name">How many moles of #Cl# are in #1.2 * 10^24# formula units of magnesium chloride?</h1>

4.00 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Magnesium chloride is an ionic compound with an <mathjax>#"Mg"^(2+)#</mathjax> ion and two <mathjax>#"Cl"^-#</mathjax> ions in each formula unit. Thus: </p> <p><mathjax>#1.2*10^24 " formula units" * ("1 mol MgCl"_2)/(6.023*10^23 " formula units")*("2 mol Cl"^(-) " ions")/("1 mol MgCl"_2) = "2.0 mol Cl"^(-) " ions"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"4.0 mol"#</mathjax> of <mathjax>#"Cl"^-#</mathjax> ions.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Magnesium chloride is an ionic compound with an <mathjax>#"Mg"^(2+)#</mathjax> ion and two <mathjax>#"Cl"^-#</mathjax> ions in each formula unit. Thus: </p> <p><mathjax>#1.2*10^24 " formula units" * ("1 mol MgCl"_2)/(6.023*10^23 " formula units")*("2 mol Cl"^(-) " ions")/("1 mol MgCl"_2) = "2.0 mol Cl"^(-) " ions"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles of #Cl# are in #1.2 * 10^24# formula units of magnesium chloride?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="471628" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/al-e"><img alt="" class="" src="https://lh4.googleusercontent.com/-oz5UmZwruBQ/AAAAAAAAAAI/AAAAAAAAAFs/Oc0IDeN2ejw/photo.jpg?sz=50" title=""/></a> <a class="secondContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/al-e"> Al E. </a>·<a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-04T16:42:01" itemprop="dateCreated"> Sep 4, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"4.0 mol"#</mathjax> of <mathjax>#"Cl"^-#</mathjax> ions.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Magnesium chloride is an ionic compound with an <mathjax>#"Mg"^(2+)#</mathjax> ion and two <mathjax>#"Cl"^-#</mathjax> ions in each formula unit. Thus: </p> <p><mathjax>#1.2*10^24 " formula units" * ("1 mol MgCl"_2)/(6.023*10^23 " formula units")*("2 mol Cl"^(-) " ions")/("1 mol MgCl"_2) = "2.0 mol Cl"^(-) " ions"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/471628" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 10958 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many moles of #Cl# are in #1.2 * 10^24# formula units of magnesium chloride?

a926aab6-6ddd-11ea-a7ca-ccda262736ce

https://socratic.org/questions/in-the-reaction-fe-2o-3-3co-2fe-3co-2-what-is-the-total-number-of-moles-of-co-us

3.00 moles

start physical_unit 6 6 mole mol qc_end chemical_equation 3 12 qc_end physical_unit 28 28 25 26 mass qc_end end

[{"type":"physical unit","value":"Mole [OF] CO [IN] moles"}]

[{"type":"physical unit","value":"3.00 moles"}]

[{"type":"chemical equation","value":"Fe2O3 + 3 CO -> 2 Fe + 3 CO2"},{"type":"physical unit","value":"Mass [OF] iron [=] \\pu{112 grams}"}]

<h1 class="questionTitle" itemprop="name">In the reaction #Fe_2O_3 + 3CO -&gt; 2Fe + 3CO_2#, what is the total number of moles of #CO# used to produce 112 grams of iron?</h1>

3.00 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Assume that:<br/> n = number of moles<br/> m = mass of substance<br/> M = molar mass (equivalent to atomic weight in the periodic table)</p> <p><mathjax>#n = m -: M#</mathjax></p> <p>The mass (m) of Fe is found. <br/> Your next step is to find the molar mass (M) of Fe. <br/> The molar mass of Fe is 55.9 g/mol. </p> <p>To find the number of moles for Fe: <br/> n = 112 grams <mathjax>#-:#</mathjax> 55.9 g/mol = 2.003577818 moles of Fe(don't round because this is not your final answer or you'll get inaccurate final answer)</p> <p>Note that the front number "2Fe" and "3CO" represents the number of molecules used as mole ratio. <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">The mole</a> ratio between Fe:CO is 2:3.</p> <p>If 2 moles of iron (Fe) gives you 3 moles of carbon monoxide (CO), then 2.003577818 moles of 2Fe must give you:<br/> [2.003577818 moles <mathjax>#-:#</mathjax> 2, then <mathjax>#xx#</mathjax> 3] = 3.0053667263 moles of CO.</p> <p>You have now found the number of moles for CO.</p> <p>Therefore, you now know that 3.01 moles of CO is used to produce 112 grams of Fe. (Note that 3.01 moles is rounded to 3 significant figures)</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Find the number of moles and molar mass for 2Fe, then determine the number of moles for 3CO</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Assume that:<br/> n = number of moles<br/> m = mass of substance<br/> M = molar mass (equivalent to atomic weight in the periodic table)</p> <p><mathjax>#n = m -: M#</mathjax></p> <p>The mass (m) of Fe is found. <br/> Your next step is to find the molar mass (M) of Fe. <br/> The molar mass of Fe is 55.9 g/mol. </p> <p>To find the number of moles for Fe: <br/> n = 112 grams <mathjax>#-:#</mathjax> 55.9 g/mol = 2.003577818 moles of Fe(don't round because this is not your final answer or you'll get inaccurate final answer)</p> <p>Note that the front number "2Fe" and "3CO" represents the number of molecules used as mole ratio. <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">The mole</a> ratio between Fe:CO is 2:3.</p> <p>If 2 moles of iron (Fe) gives you 3 moles of carbon monoxide (CO), then 2.003577818 moles of 2Fe must give you:<br/> [2.003577818 moles <mathjax>#-:#</mathjax> 2, then <mathjax>#xx#</mathjax> 3] = 3.0053667263 moles of CO.</p> <p>You have now found the number of moles for CO.</p> <p>Therefore, you now know that 3.01 moles of CO is used to produce 112 grams of Fe. (Note that 3.01 moles is rounded to 3 significant figures)</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">In the reaction #Fe_2O_3 + 3CO -&gt; 2Fe + 3CO_2#, what is the total number of moles of #CO# used to produce 112 grams of iron?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="258473" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/edmund-l"><img alt="" class="" src="https://profilepictures.socratic.org/DnAPD8TISDW0aROTp4qA_Day_3_Story_1._Photo_with_Sky_Tower_from_distance_Walked_around_most_of_west_Auckland_suburbs._Some_of_you_mightve_seen_.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/edmund-l"> Edmund Liew </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-25T10:42:34" itemprop="dateCreated"> Apr 25, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Find the number of moles and molar mass for 2Fe, then determine the number of moles for 3CO</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Assume that:<br/> n = number of moles<br/> m = mass of substance<br/> M = molar mass (equivalent to atomic weight in the periodic table)</p> <p><mathjax>#n = m -: M#</mathjax></p> <p>The mass (m) of Fe is found. <br/> Your next step is to find the molar mass (M) of Fe. <br/> The molar mass of Fe is 55.9 g/mol. </p> <p>To find the number of moles for Fe: <br/> n = 112 grams <mathjax>#-:#</mathjax> 55.9 g/mol = 2.003577818 moles of Fe(don't round because this is not your final answer or you'll get inaccurate final answer)</p> <p>Note that the front number "2Fe" and "3CO" represents the number of molecules used as mole ratio. <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">The mole</a> ratio between Fe:CO is 2:3.</p> <p>If 2 moles of iron (Fe) gives you 3 moles of carbon monoxide (CO), then 2.003577818 moles of 2Fe must give you:<br/> [2.003577818 moles <mathjax>#-:#</mathjax> 2, then <mathjax>#xx#</mathjax> 3] = 3.0053667263 moles of CO.</p> <p>You have now found the number of moles for CO.</p> <p>Therefore, you now know that 3.01 moles of CO is used to produce 112 grams of Fe. (Note that 3.01 moles is rounded to 3 significant figures)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/258473" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -&gt; 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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In the reaction #Fe_2O_3 + 3CO -&gt; 2Fe + 3CO_2#, what is the total number of moles of #CO# used to produce 112 grams of iron?

a95a3c5b-6ddd-11ea-a708-ccda262736ce

https://socratic.org/questions/how-many-miles-of-electrons-is-required-to-deposit-5-6g-of-iron-from-a-solution-

0.07 moles

start physical_unit 4 4 mole mol qc_end physical_unit 12 12 9 10 mass qc_end substance 17 18 qc_end physical_unit 20 20 22 23 molar_mass qc_end physical_unit 24 24 26 27 molar_mass qc_end physical_unit 28 28 30 31 molar_mass qc_end end

[{"type":"physical unit","value":"Mole [OF] electrons [IN] moles"}]

[{"type":"physical unit","value":"0.07 moles"}]

[{"type":"physical unit","value":"Mass [OF] Iron [=] \\pu{5.6 g}"},{"type":"substance name","value":"Iron(II) tetraoxosulphate(VI)"},{"type":"physical unit","value":"Molar mass [OF] Fe [=] \\pu{56 g/mol}"},{"type":"physical unit","value":"Molar mass [OF] S [=] \\pu{32 g/mol}"},{"type":"physical unit","value":"Molar mass [OF] O [=] \\pu{16 g/mol}"}]

<h1 class="questionTitle" itemprop="name">How many moles of electrons are required to deposit #5.6g# of Iron from a solution of Iron(II) tetraoxosulphate(VI) ? [Fe = 56, S = 32, O = 16]</h1>

0.07 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For starters, it's worth pointing out that <em>iron(II) tetraoxosulfate(VI)</em> is just a fancy name for <em>iron(II) sulfate</em>, <mathjax>#"FeSO"_4#</mathjax>. </p> <p>So <em>tetraoxosulfate(VI)</em> is an alternative name used for the <em>sulfate anion</em>, <mathjax>#"SO"_4^(2-)#</mathjax>. The name suggests the number of oxygen atoms present in the anion</p> <blockquote> <p><mathjax>#"tetraoxo = 4 oxygen atoms"#</mathjax></p> </blockquote> <p>and the oxidation state of sulfur in this anion</p> <blockquote> <p><mathjax>#("VI") = +"6 oxidation state for S"#</mathjax></p> </blockquote> <p>Now, before doing anything else, use the <strong>molar mass</strong> of iron(II) sulfate to calculate the number of <em>moles</em> of this compound present in your sample.</p> <blockquote> <p><mathjax>#5.6 color(red)(cancel(color(black)("g"))) * "1 mole FeSO"_4/(152color(red)(cancel(color(black)("g")))) = "0.03684 moles FeSO"_4#</mathjax></p> </blockquote> <p>Since <mathjax>#1#</mathjax> <strong>mole</strong> of iron(II) sulfate contains <mathjax>#1#</mathjax> <strong>mole</strong> of iron(II) cations, you can say that your solution will contain <mathjax>#0.03684#</mathjax> <strong>moles</strong> of iron(II) cations. </p> <p>In order to reduce the iron(II) cations to iron metal, you need</p> <blockquote> <p><mathjax>#"Fe"_ ((aq))^(2+) + 2"e"^(-) -&gt; "Fe"_ ((s))#</mathjax></p> </blockquote> <p>So <mathjax>#1#</mathjax> <strong>mole</strong> of iron(II) cations requires <mathjax>#2#</mathjax> <strong>moles</strong> of electrons, which means that your sample will require</p> <blockquote> <p><mathjax>#0.03684 color(red)(cancel(color(black)("moles Fe"^(2+)))) * "2 moles e"^(-)/(1color(red)(cancel(color(black)("mole Fe"^(2+))))) = color(darkgreen)(ul(color(black)("0.074 moles e"^(-))))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of iron(II) sulfate. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.074 moles e"^(-)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For starters, it's worth pointing out that <em>iron(II) tetraoxosulfate(VI)</em> is just a fancy name for <em>iron(II) sulfate</em>, <mathjax>#"FeSO"_4#</mathjax>. </p> <p>So <em>tetraoxosulfate(VI)</em> is an alternative name used for the <em>sulfate anion</em>, <mathjax>#"SO"_4^(2-)#</mathjax>. The name suggests the number of oxygen atoms present in the anion</p> <blockquote> <p><mathjax>#"tetraoxo = 4 oxygen atoms"#</mathjax></p> </blockquote> <p>and the oxidation state of sulfur in this anion</p> <blockquote> <p><mathjax>#("VI") = +"6 oxidation state for S"#</mathjax></p> </blockquote> <p>Now, before doing anything else, use the <strong>molar mass</strong> of iron(II) sulfate to calculate the number of <em>moles</em> of this compound present in your sample.</p> <blockquote> <p><mathjax>#5.6 color(red)(cancel(color(black)("g"))) * "1 mole FeSO"_4/(152color(red)(cancel(color(black)("g")))) = "0.03684 moles FeSO"_4#</mathjax></p> </blockquote> <p>Since <mathjax>#1#</mathjax> <strong>mole</strong> of iron(II) sulfate contains <mathjax>#1#</mathjax> <strong>mole</strong> of iron(II) cations, you can say that your solution will contain <mathjax>#0.03684#</mathjax> <strong>moles</strong> of iron(II) cations. </p> <p>In order to reduce the iron(II) cations to iron metal, you need</p> <blockquote> <p><mathjax>#"Fe"_ ((aq))^(2+) + 2"e"^(-) -&gt; "Fe"_ ((s))#</mathjax></p> </blockquote> <p>So <mathjax>#1#</mathjax> <strong>mole</strong> of iron(II) cations requires <mathjax>#2#</mathjax> <strong>moles</strong> of electrons, which means that your sample will require</p> <blockquote> <p><mathjax>#0.03684 color(red)(cancel(color(black)("moles Fe"^(2+)))) * "2 moles e"^(-)/(1color(red)(cancel(color(black)("mole Fe"^(2+))))) = color(darkgreen)(ul(color(black)("0.074 moles e"^(-))))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of iron(II) sulfate. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles of electrons are required to deposit #5.6g# of Iron from a solution of Iron(II) tetraoxosulphate(VI) ? [Fe = 56, S = 32, O = 16]</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-and-reduction-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation and Reduction Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="486175" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-10-07T12:56:22" itemprop="dateCreated"> Oct 7, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.074 moles e"^(-)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For starters, it's worth pointing out that <em>iron(II) tetraoxosulfate(VI)</em> is just a fancy name for <em>iron(II) sulfate</em>, <mathjax>#"FeSO"_4#</mathjax>. </p> <p>So <em>tetraoxosulfate(VI)</em> is an alternative name used for the <em>sulfate anion</em>, <mathjax>#"SO"_4^(2-)#</mathjax>. The name suggests the number of oxygen atoms present in the anion</p> <blockquote> <p><mathjax>#"tetraoxo = 4 oxygen atoms"#</mathjax></p> </blockquote> <p>and the oxidation state of sulfur in this anion</p> <blockquote> <p><mathjax>#("VI") = +"6 oxidation state for S"#</mathjax></p> </blockquote> <p>Now, before doing anything else, use the <strong>molar mass</strong> of iron(II) sulfate to calculate the number of <em>moles</em> of this compound present in your sample.</p> <blockquote> <p><mathjax>#5.6 color(red)(cancel(color(black)("g"))) * "1 mole FeSO"_4/(152color(red)(cancel(color(black)("g")))) = "0.03684 moles FeSO"_4#</mathjax></p> </blockquote> <p>Since <mathjax>#1#</mathjax> <strong>mole</strong> of iron(II) sulfate contains <mathjax>#1#</mathjax> <strong>mole</strong> of iron(II) cations, you can say that your solution will contain <mathjax>#0.03684#</mathjax> <strong>moles</strong> of iron(II) cations. </p> <p>In order to reduce the iron(II) cations to iron metal, you need</p> <blockquote> <p><mathjax>#"Fe"_ ((aq))^(2+) + 2"e"^(-) -&gt; "Fe"_ ((s))#</mathjax></p> </blockquote> <p>So <mathjax>#1#</mathjax> <strong>mole</strong> of iron(II) cations requires <mathjax>#2#</mathjax> <strong>moles</strong> of electrons, which means that your sample will require</p> <blockquote> <p><mathjax>#0.03684 color(red)(cancel(color(black)("moles Fe"^(2+)))) * "2 moles e"^(-)/(1color(red)(cancel(color(black)("mole Fe"^(2+))))) = color(darkgreen)(ul(color(black)("0.074 moles e"^(-))))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of iron(II) sulfate. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/486175" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-balance-equations-with-charges"> How to balance equations for reduction/oxidation reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-an-electode-reaction-has-dssolved-oxygen-as-a-reactant-is-the-electrode-an-an"> If an electode reaction has dssolved oxygen as a reactant, is the electrode an anode or a cathode? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-an-electrode-reaction-has-dissolved-oxygen-as-a-reactant-is-the-electrode-and"> If an electrode reaction has dissolved oxygen as a reactant, is the electrode and anode or a cathode? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-balanced-equation-represents-a-redox-reaction-2"> What balanced equation represents a redox reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-redox-reactions-involved-in-electrolysis"> How are redox reactions involved in electrolysis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-oxidation-reduction-reactions-coupled"> Why are oxidation reduction reactions coupled? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-do-oxidation-reduction-reactions-involve"> What do oxidation reduction reactions involve? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-reduction-reactions-used-for"> What are reduction reactions used for? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-calx-mean-in-oxidation-reduction-reactions"> What does "calx" mean in oxidation reduction reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-the-reduced-components-in-this-reaction-zn-2h-zn-2-h2"> What are the reduced components in this reaction? Zn + 2H(+) → Zn(2+) + H2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-and-reduction-reactions"> See all questions in Oxidation and Reduction Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9583 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many moles of electrons are required to deposit #5.6g# of Iron from a solution of Iron(II) tetraoxosulphate(VI) ? [Fe = 56, S = 32, O = 16]

ac28d11a-6ddd-11ea-b83e-ccda262736ce

https://socratic.org/questions/what-is-the-chemical-formula-for-iron-lll-oxide

Fe2O3

start chemical_formula qc_end substance 6 7 qc_end end

[{"type":"other","value":"Chemical Formula [OF] iron(lll) oxide [IN] default"}]

[{"type":"chemical equation","value":"Fe2O3"}]

[{"type":"substance name","value":"Iron(lll) oxide"}]

<h1 class="questionTitle" itemprop="name">What is the chemical formula for iron(lll) oxide?</h1>

Fe2O3

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>What's the other name for this stuff? </p> <p>The iron is assumed to be in a <mathjax>#+III#</mathjax> oxidation state, i.e. we treat it as <mathjax>#Fe^(3+)#</mathjax>. Oxygen generally assumes a <mathjax>#-II#</mathjax> oxidation state, i.e. <mathjax>#O^(2-)#</mathjax> and it does here.</p> <p>We know that it is a neutral species, so we cross multiply the presumed charges to get the given formula: <mathjax>#3xx(-2) +2xx3=0#</mathjax>, as required.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Ferric oxide, <mathjax>#Fe_2O_3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>What's the other name for this stuff? </p> <p>The iron is assumed to be in a <mathjax>#+III#</mathjax> oxidation state, i.e. we treat it as <mathjax>#Fe^(3+)#</mathjax>. Oxygen generally assumes a <mathjax>#-II#</mathjax> oxidation state, i.e. <mathjax>#O^(2-)#</mathjax> and it does here.</p> <p>We know that it is a neutral species, so we cross multiply the presumed charges to get the given formula: <mathjax>#3xx(-2) +2xx3=0#</mathjax>, as required.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the chemical formula for iron(lll) oxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#covalent-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Covalent Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/covalent-bonds-and-formulas/covalent-formulas-and-nomenclature" itemprop="url"> <span class="breadcrumb" itemprop="title">Covalent Formulas and Nomenclature</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="216882" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-25T16:08:03" itemprop="dateCreated"> Jan 25, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Ferric oxide, <mathjax>#Fe_2O_3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>What's the other name for this stuff? </p> <p>The iron is assumed to be in a <mathjax>#+III#</mathjax> oxidation state, i.e. we treat it as <mathjax>#Fe^(3+)#</mathjax>. Oxygen generally assumes a <mathjax>#-II#</mathjax> oxidation state, i.e. <mathjax>#O^(2-)#</mathjax> and it does here.</p> <p>We know that it is a neutral species, so we cross multiply the presumed charges to get the given formula: <mathjax>#3xx(-2) +2xx3=0#</mathjax>, as required.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/216882" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-for-sugar"> What is the chemical formula for sugar? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-chemical-formula-represents-a-carbohydrate"> What chemical formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-for-gold"> What is the chemical formula for gold? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-for-a-diamond"> What is the chemical formula for a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-formulas-for-covalent-compounds"> How do you find formulas for covalent compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-common-mistakes-students-make-with-empirical-forumlas"> What are common mistakes students make with empirical forumlas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-empirical-formulas"> What are empirical formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-empirical-formulas"> What are some examples of empirical formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-naming-a-covalent-bond-between-atoms-how-would-you-write-the-prefix-for-if-"> When naming a covalently-bonded molecule, how would you write the prefix if you had four atoms... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-nomenclature-for-ch3cl"> What is the chemical nomenclature for CH3Cl? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/covalent-bonds-and-formulas/covalent-formulas-and-nomenclature"> See all questions in Covalent Formulas and Nomenclature </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2370 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the chemical formula for iron(lll) oxide?

aa94328c-6ddd-11ea-a509-ccda262736ce

https://socratic.org/questions/how-do-you-write-an-equation-to-represent-calcium-sulfite-decomposes-to-form-cal

CaSO3(s) -> CaO(s) + SO2(g)

start chemical_equation qc_end substance 8 9 qc_end substance 13 14 qc_end substance 16 17 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"CaSO3(s) -> CaO(s) + SO2(g)"}]

[{"type":"substance name","value":"Calcium sulfite"},{"type":"substance name","value":"Calcium oxide"},{"type":"substance name","value":"Sulfur dioxide"}]

<h1 class="questionTitle" itemprop="name">How do you write an equation to represent "Calcium sulfite decomposes to form calcium oxide and sulfur dioxide"?</h1>

CaSO3(s) -> CaO(s) + SO2(g)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first clue to go by is the fact that you're dealing with a <a href="http://socratic.org/chemistry/chemical-reactions/decomposition-reactions">decomposition reaction</a>, so you know that <em>calcium sulfite</em> is the <strong>only reactant</strong> and that you have <strong>two products</strong>, <em>calcium oxide</em> and <em>sulfur dioxide</em>. </p> <p>Start by focusing on the reactant, calcium sulfite. </p> <p>As you know, the <strong>-ite</strong> suffix is used to distinguish between <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/polyatomic-ions">polyatomic anions</a> that contain <strong>oxygen</strong>. These polyatomic anions go by the name of <em>oxyanions</em>. </p> <p>More specifically, the <strong>-ite</strong> suffix is used for <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> that can form multiple oxyanions to represent an oxyanion that contains <strong>fewer atoms of oxygen</strong>.</p> <p>By comparison, for the same element, the <strong>-ate</strong> suffix is used to represent the oxyanion that contains <strong>more atoms of oxygen</strong>. </p> <p>In this case, <em>sulfite</em> is the name given to the <mathjax>#"SO"_3^(2-)#</mathjax> anion. <em>Sulfate</em>, for example, is the name given to the <mathjax>#"SO"_4^(2-)#</mathjax> anion, since it contains an extra oxygen atom than the sulfite anion. </p> <p>So, you know that the reactant is composed of calcium cations, <mathjax>#"Ca"^(2=)#</mathjax>, and sulfite anions, <mathjax>#"SO"_3^(2-)#</mathjax>. This means that you have</p> <blockquote> <p><mathjax>#color(blue)("CaSO"_text(3(s]) -&gt; ? + ?)#</mathjax></p> </blockquote> <p>Next, focus on the oxide. Since calcium cations have a <mathjax>#2+#</mathjax> charge, and oxygen anions have a <mathjax>#2-#</mathjax> charge, <em>&amp;calcium oxide</em> will simply be </p> <blockquote> <p><mathjax>#"Ca"^(2+)"O"^(2-) implies "Ca"_2"O"_2 implies "CaO"#</mathjax></p> </blockquote> <p>You now have</p> <blockquote> <p><mathjax>#color(blue)("CaSO"_text(3(s]) -&gt; "CaO"_text((s]) + ?)#</mathjax></p> </blockquote> <p>Finally, focus on <em>sulfur dioxide</em>. Sulfur dioxide is a <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/covalent-compounds">covalent compound</a>, which means that you can conclude from its name that it contains </p> <ul> <li><em><strong>one</strong> sulfur atom</em> <mathjax>#-&gt;#</mathjax> <em>sulfur has <strong>no prefix</strong> in the name of the compound</em></li> <li><em><strong>two</strong> oxygen atoms</em> <mathjax>#-&gt;#</mathjax> <em>oxygen has a <strong>di-</strong> prefix in the name of the compound</em></li> </ul> <p>Therefore, you can say that sulfur dioxide is <mathjax>#"SO"_2#</mathjax>. This gives you </p> <blockquote> <p><mathjax>#color(blue)("CaSO"_text(3(s]) -&gt; "CaO"_text((s]) + "SO"_text(2(g]) uarr)#</mathjax></p> </blockquote> <p>Since this equation is already balanced, this will be your answer. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"CaSO"_text(3(s]) -&gt; "CaO"_text((s]) + "SO"_text(2(g]) uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first clue to go by is the fact that you're dealing with a <a href="http://socratic.org/chemistry/chemical-reactions/decomposition-reactions">decomposition reaction</a>, so you know that <em>calcium sulfite</em> is the <strong>only reactant</strong> and that you have <strong>two products</strong>, <em>calcium oxide</em> and <em>sulfur dioxide</em>. </p> <p>Start by focusing on the reactant, calcium sulfite. </p> <p>As you know, the <strong>-ite</strong> suffix is used to distinguish between <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/polyatomic-ions">polyatomic anions</a> that contain <strong>oxygen</strong>. These polyatomic anions go by the name of <em>oxyanions</em>. </p> <p>More specifically, the <strong>-ite</strong> suffix is used for <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> that can form multiple oxyanions to represent an oxyanion that contains <strong>fewer atoms of oxygen</strong>.</p> <p>By comparison, for the same element, the <strong>-ate</strong> suffix is used to represent the oxyanion that contains <strong>more atoms of oxygen</strong>. </p> <p>In this case, <em>sulfite</em> is the name given to the <mathjax>#"SO"_3^(2-)#</mathjax> anion. <em>Sulfate</em>, for example, is the name given to the <mathjax>#"SO"_4^(2-)#</mathjax> anion, since it contains an extra oxygen atom than the sulfite anion. </p> <p>So, you know that the reactant is composed of calcium cations, <mathjax>#"Ca"^(2=)#</mathjax>, and sulfite anions, <mathjax>#"SO"_3^(2-)#</mathjax>. This means that you have</p> <blockquote> <p><mathjax>#color(blue)("CaSO"_text(3(s]) -&gt; ? + ?)#</mathjax></p> </blockquote> <p>Next, focus on the oxide. Since calcium cations have a <mathjax>#2+#</mathjax> charge, and oxygen anions have a <mathjax>#2-#</mathjax> charge, <em>&amp;calcium oxide</em> will simply be </p> <blockquote> <p><mathjax>#"Ca"^(2+)"O"^(2-) implies "Ca"_2"O"_2 implies "CaO"#</mathjax></p> </blockquote> <p>You now have</p> <blockquote> <p><mathjax>#color(blue)("CaSO"_text(3(s]) -&gt; "CaO"_text((s]) + ?)#</mathjax></p> </blockquote> <p>Finally, focus on <em>sulfur dioxide</em>. Sulfur dioxide is a <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/covalent-compounds">covalent compound</a>, which means that you can conclude from its name that it contains </p> <ul> <li><em><strong>one</strong> sulfur atom</em> <mathjax>#-&gt;#</mathjax> <em>sulfur has <strong>no prefix</strong> in the name of the compound</em></li> <li><em><strong>two</strong> oxygen atoms</em> <mathjax>#-&gt;#</mathjax> <em>oxygen has a <strong>di-</strong> prefix in the name of the compound</em></li> </ul> <p>Therefore, you can say that sulfur dioxide is <mathjax>#"SO"_2#</mathjax>. This gives you </p> <blockquote> <p><mathjax>#color(blue)("CaSO"_text(3(s]) -&gt; "CaO"_text((s]) + "SO"_text(2(g]) uarr)#</mathjax></p> </blockquote> <p>Since this equation is already balanced, this will be your answer. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you write an equation to represent "Calcium sulfite decomposes to form calcium oxide and sulfur dioxide"?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="201795" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-21T12:02:56" itemprop="dateCreated"> Dec 21, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"CaSO"_text(3(s]) -&gt; "CaO"_text((s]) + "SO"_text(2(g]) uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first clue to go by is the fact that you're dealing with a <a href="http://socratic.org/chemistry/chemical-reactions/decomposition-reactions">decomposition reaction</a>, so you know that <em>calcium sulfite</em> is the <strong>only reactant</strong> and that you have <strong>two products</strong>, <em>calcium oxide</em> and <em>sulfur dioxide</em>. </p> <p>Start by focusing on the reactant, calcium sulfite. </p> <p>As you know, the <strong>-ite</strong> suffix is used to distinguish between <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/polyatomic-ions">polyatomic anions</a> that contain <strong>oxygen</strong>. These polyatomic anions go by the name of <em>oxyanions</em>. </p> <p>More specifically, the <strong>-ite</strong> suffix is used for <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> that can form multiple oxyanions to represent an oxyanion that contains <strong>fewer atoms of oxygen</strong>.</p> <p>By comparison, for the same element, the <strong>-ate</strong> suffix is used to represent the oxyanion that contains <strong>more atoms of oxygen</strong>. </p> <p>In this case, <em>sulfite</em> is the name given to the <mathjax>#"SO"_3^(2-)#</mathjax> anion. <em>Sulfate</em>, for example, is the name given to the <mathjax>#"SO"_4^(2-)#</mathjax> anion, since it contains an extra oxygen atom than the sulfite anion. </p> <p>So, you know that the reactant is composed of calcium cations, <mathjax>#"Ca"^(2=)#</mathjax>, and sulfite anions, <mathjax>#"SO"_3^(2-)#</mathjax>. This means that you have</p> <blockquote> <p><mathjax>#color(blue)("CaSO"_text(3(s]) -&gt; ? + ?)#</mathjax></p> </blockquote> <p>Next, focus on the oxide. Since calcium cations have a <mathjax>#2+#</mathjax> charge, and oxygen anions have a <mathjax>#2-#</mathjax> charge, <em>&amp;calcium oxide</em> will simply be </p> <blockquote> <p><mathjax>#"Ca"^(2+)"O"^(2-) implies "Ca"_2"O"_2 implies "CaO"#</mathjax></p> </blockquote> <p>You now have</p> <blockquote> <p><mathjax>#color(blue)("CaSO"_text(3(s]) -&gt; "CaO"_text((s]) + ?)#</mathjax></p> </blockquote> <p>Finally, focus on <em>sulfur dioxide</em>. Sulfur dioxide is a <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/covalent-compounds">covalent compound</a>, which means that you can conclude from its name that it contains </p> <ul> <li><em><strong>one</strong> sulfur atom</em> <mathjax>#-&gt;#</mathjax> <em>sulfur has <strong>no prefix</strong> in the name of the compound</em></li> <li><em><strong>two</strong> oxygen atoms</em> <mathjax>#-&gt;#</mathjax> <em>oxygen has a <strong>di-</strong> prefix in the name of the compound</em></li> </ul> <p>Therefore, you can say that sulfur dioxide is <mathjax>#"SO"_2#</mathjax>. This gives you </p> <blockquote> <p><mathjax>#color(blue)("CaSO"_text(3(s]) -&gt; "CaO"_text((s]) + "SO"_text(2(g]) uarr)#</mathjax></p> </blockquote> <p>Since this equation is already balanced, this will be your answer. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/201795" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-equation-for-photosynthesis"> What is the chemical equation for photosynthesis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-grams-of-each-substance-used-or-produced-w"> How can I know the relative number of grams of each substance used or produced with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-moles-of-each-substance-with-chemical-equa"> How can I know the relative number of moles of each substance with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-chemical-equations-illustrate-that-atoms-are-conserved-1"> How do chemical equations illustrate that atoms are conserved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-formula-of-the-reactants-and-products-with-chemical-equations"> How can I know the formula of the reactants and products with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-potassium-metal-and-chlorine-gas-combi"> How can I balance this chemical equations? 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How do you write an equation to represent "Calcium sulfite decomposes to form calcium oxide and sulfur dioxide"?

a92c644a-6ddd-11ea-8afe-ccda262736ce

https://socratic.org/questions/a-1-5-liter-flask-is-filled-with-nitrogen-at-a-pressure-of-12-atmospheres-what-s

9.0 L

start physical_unit 3 3 volume l qc_end physical_unit 3 3 1 2 volume qc_end physical_unit 7 7 12 13 pressure qc_end physical_unit 7 7 28 29 pressure qc_end end

[{"type":"physical unit","value":"Volume2 [OF] flask [IN] L"}]

[{"type":"physical unit","value":"9.0 L"}]

[{"type":"physical unit","value":"Volume1 [OF] flask [=] \\pu{1.5 liter}"},{"type":"physical unit","value":"Pressure1 [OF] nitrogen [=] \\pu{12 atmospheres}"},{"type":"physical unit","value":"Pressure2 [OF] nitrogen [=] \\pu{2.0 atmospheres}"}]

<h1 class="questionTitle" itemprop="name">A 1.5 liter flask is filled with nitrogen at a pressure of 12 atmospheres. What size flask would be required to hold this gas at a pressure of 2.0 atmospheres?</h1>

9.0 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To solve this equation, we can use the pressure-volume relationship of gases, illustrated by <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a></strong>:</p> <p><mathjax>#P_1V_1 = P_2V_2#</mathjax> (with constant temperature)</p> <p>Since we need to find the final volume, let's rearrange this equation to solve for <mathjax>#V_2#</mathjax>:</p> <p><mathjax>#V_2 = (P_1V_1)/(P_2)#</mathjax></p> <p>Our known variables are</p> <ul> <li> <p><mathjax>#P_1#</mathjax> - <mathjax>#12#</mathjax> <mathjax>#"atm"#</mathjax></p> </li> <li> <p><mathjax>#V_1#</mathjax> - <mathjax>#1.5#</mathjax> <mathjax>#"L"#</mathjax></p> </li> <li> <p><mathjax>#P_2#</mathjax> - <mathjax>#2.0#</mathjax> <mathjax>#"atm"#</mathjax></p> </li> </ul> <p>Plugging these into the equation we have</p> <p><mathjax>#V_2 = ((12cancel("atm"))(1.5"L"))/(2.0cancel("atm")) = color(red)(9.0#</mathjax> <mathjax>#color(red)("L"#</mathjax></p> <p>Thus, when a <mathjax>#1.5#</mathjax>-liter flask containing gas with a pressure of <mathjax>#12#</mathjax> atmospheres is subjected to a decrease in pressure to <mathjax>#2.0#</mathjax> atmospheres, at constant temperature the volume will expand to <mathjax>#color(red)(9.0#</mathjax> liters.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#9.0#</mathjax> <mathjax>#"L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To solve this equation, we can use the pressure-volume relationship of gases, illustrated by <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a></strong>:</p> <p><mathjax>#P_1V_1 = P_2V_2#</mathjax> (with constant temperature)</p> <p>Since we need to find the final volume, let's rearrange this equation to solve for <mathjax>#V_2#</mathjax>:</p> <p><mathjax>#V_2 = (P_1V_1)/(P_2)#</mathjax></p> <p>Our known variables are</p> <ul> <li> <p><mathjax>#P_1#</mathjax> - <mathjax>#12#</mathjax> <mathjax>#"atm"#</mathjax></p> </li> <li> <p><mathjax>#V_1#</mathjax> - <mathjax>#1.5#</mathjax> <mathjax>#"L"#</mathjax></p> </li> <li> <p><mathjax>#P_2#</mathjax> - <mathjax>#2.0#</mathjax> <mathjax>#"atm"#</mathjax></p> </li> </ul> <p>Plugging these into the equation we have</p> <p><mathjax>#V_2 = ((12cancel("atm"))(1.5"L"))/(2.0cancel("atm")) = color(red)(9.0#</mathjax> <mathjax>#color(red)("L"#</mathjax></p> <p>Thus, when a <mathjax>#1.5#</mathjax>-liter flask containing gas with a pressure of <mathjax>#12#</mathjax> atmospheres is subjected to a decrease in pressure to <mathjax>#2.0#</mathjax> atmospheres, at constant temperature the volume will expand to <mathjax>#color(red)(9.0#</mathjax> liters.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A 1.5 liter flask is filled with nitrogen at a pressure of 12 atmospheres. What size flask would be required to hold this gas at a pressure of 2.0 atmospheres?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="438910" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-13T02:36:26" itemprop="dateCreated"> Jun 13, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#9.0#</mathjax> <mathjax>#"L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To solve this equation, we can use the pressure-volume relationship of gases, illustrated by <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a></strong>:</p> <p><mathjax>#P_1V_1 = P_2V_2#</mathjax> (with constant temperature)</p> <p>Since we need to find the final volume, let's rearrange this equation to solve for <mathjax>#V_2#</mathjax>:</p> <p><mathjax>#V_2 = (P_1V_1)/(P_2)#</mathjax></p> <p>Our known variables are</p> <ul> <li> <p><mathjax>#P_1#</mathjax> - <mathjax>#12#</mathjax> <mathjax>#"atm"#</mathjax></p> </li> <li> <p><mathjax>#V_1#</mathjax> - <mathjax>#1.5#</mathjax> <mathjax>#"L"#</mathjax></p> </li> <li> <p><mathjax>#P_2#</mathjax> - <mathjax>#2.0#</mathjax> <mathjax>#"atm"#</mathjax></p> </li> </ul> <p>Plugging these into the equation we have</p> <p><mathjax>#V_2 = ((12cancel("atm"))(1.5"L"))/(2.0cancel("atm")) = color(red)(9.0#</mathjax> <mathjax>#color(red)("L"#</mathjax></p> <p>Thus, when a <mathjax>#1.5#</mathjax>-liter flask containing gas with a pressure of <mathjax>#12#</mathjax> atmospheres is subjected to a decrease in pressure to <mathjax>#2.0#</mathjax> atmospheres, at constant temperature the volume will expand to <mathjax>#color(red)(9.0#</mathjax> liters.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/438910" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyles-law-relate-to-breathing"> How does Boyle's law relate to breathing? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/in-avogadro-s-law-what-would-happen-to-v-if-n-is-increased-decreased-and-what-wo"> In Avogadro's Law what would happen to V if N is increased/decreased? 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A 1.5 liter flask is filled with nitrogen at a pressure of 12 atmospheres. What size flask would be required to hold this gas at a pressure of 2.0 atmospheres?

aa510934-6ddd-11ea-bbc9-ccda262736ce

https://socratic.org/questions/548e746a581e2a6c70b9d365

236.88 grams

start physical_unit 3 3 mass g qc_end physical_unit 12 12 10 11 mass qc_end chemical_equation 16 21 qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Mass [OF] CCl4 [IN] grams"}]

[{"type":"physical unit","value":"236.88 grams"}]

[{"type":"physical unit","value":"Mass [OF] CH4 [=] \\pu{24.7 g}"},{"type":"chemical equation","value":"CH4 + CCl4 -> 2 CH2Cl2"},{"type":"other","value":"React completely."}]

<h1 class="questionTitle" itemprop="name">What mass of #"CCl"_4# is required to react completely with #"24.7 g CH"_4#? </h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The reaction is <mathjax>#"CH"_4+"CCl"_4#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"2CH"_2"Cl"_2#</mathjax>.</p></div> </h2> </div> </div>

236.88 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start with a balanced equation.</p> <p><mathjax>#"CH"_4+"CCl"_4#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"2CH"_2"Cl"_2#</mathjax> </p> <p><strong>Convert mass of methane to moles of methane</strong> .</p> <p>Divide the given mass of methane by its molar mass <mathjax>#("16.04 g/mol")#</mathjax>. I prefer to divide by multiplying by the inverse of the molar mass, mol/g.</p> <p><mathjax>#24.7color(red)cancel(color(black)("g CH"_4))xx(1"mol CH"_4)/(16.04color(red)cancel(color(black)("g CH"_4)))="1.54 mol CH"_4#</mathjax></p> <p><strong>Convert moles <mathjax>#"CH"_4#</mathjax> to moles <mathjax>#"CCl"_4#</mathjax>.</strong> </p> <p>Multiply mol <mathjax>#"CH"_4#</mathjax> by the mol ratio between <mathjax>#"CCl"_4#</mathjax> and <mathjax>#"CH"_4#</mathjax> from the balanced equation, with <mathjax>#"CCl"_4#</mathjax> in the numerator.</p> <p><mathjax>#1.54color(red)cancel(color(black)("mol CH"_4))xx(1"mol CCl"_4)/(1color(red)cancel(color(black)("mol CH"_4)))="1.54 mol CCl"_4#</mathjax></p> <p><strong>Calculate the mass of <mathjax>#"CCl"_4#</mathjax>.</strong> </p> <p>Multiply mol <mathjax>#"CCl"_4#</mathjax> by its molar mass <mathjax>#("153.82 g/mol")#</mathjax>.</p> <p><mathjax>#1.54color(red)cancel(color(black)("mol CCl"_4))xx(153.82"g CCl"_4)/(1color(red)cancel(color(black)("mol CCl"_4)))= "237 g CCl"_4"#</mathjax></p> <p><mathjax>#"237 g CCl"_4#</mathjax> are required to react completely with <mathjax>#"24.7 g CH"_4#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"237 g CCl"_4#</mathjax> is required to react completely with <mathjax>#"24.7 g CH"_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start with a balanced equation.</p> <p><mathjax>#"CH"_4+"CCl"_4#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"2CH"_2"Cl"_2#</mathjax> </p> <p><strong>Convert mass of methane to moles of methane</strong> .</p> <p>Divide the given mass of methane by its molar mass <mathjax>#("16.04 g/mol")#</mathjax>. I prefer to divide by multiplying by the inverse of the molar mass, mol/g.</p> <p><mathjax>#24.7color(red)cancel(color(black)("g CH"_4))xx(1"mol CH"_4)/(16.04color(red)cancel(color(black)("g CH"_4)))="1.54 mol CH"_4#</mathjax></p> <p><strong>Convert moles <mathjax>#"CH"_4#</mathjax> to moles <mathjax>#"CCl"_4#</mathjax>.</strong> </p> <p>Multiply mol <mathjax>#"CH"_4#</mathjax> by the mol ratio between <mathjax>#"CCl"_4#</mathjax> and <mathjax>#"CH"_4#</mathjax> from the balanced equation, with <mathjax>#"CCl"_4#</mathjax> in the numerator.</p> <p><mathjax>#1.54color(red)cancel(color(black)("mol CH"_4))xx(1"mol CCl"_4)/(1color(red)cancel(color(black)("mol CH"_4)))="1.54 mol CCl"_4#</mathjax></p> <p><strong>Calculate the mass of <mathjax>#"CCl"_4#</mathjax>.</strong> </p> <p>Multiply mol <mathjax>#"CCl"_4#</mathjax> by its molar mass <mathjax>#("153.82 g/mol")#</mathjax>.</p> <p><mathjax>#1.54color(red)cancel(color(black)("mol CCl"_4))xx(153.82"g CCl"_4)/(1color(red)cancel(color(black)("mol CCl"_4)))= "237 g CCl"_4"#</mathjax></p> <p><mathjax>#"237 g CCl"_4#</mathjax> are required to react completely with <mathjax>#"24.7 g CH"_4#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What mass of #"CCl"_4# is required to react completely with #"24.7 g CH"_4#? </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The reaction is <mathjax>#"CH"_4+"CCl"_4#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"2CH"_2"Cl"_2#</mathjax>.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="114495" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2014-12-15T08:39:12" itemprop="dateCreated"> Dec 15, 2014 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"237 g CCl"_4#</mathjax> is required to react completely with <mathjax>#"24.7 g CH"_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start with a balanced equation.</p> <p><mathjax>#"CH"_4+"CCl"_4#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"2CH"_2"Cl"_2#</mathjax> </p> <p><strong>Convert mass of methane to moles of methane</strong> .</p> <p>Divide the given mass of methane by its molar mass <mathjax>#("16.04 g/mol")#</mathjax>. I prefer to divide by multiplying by the inverse of the molar mass, mol/g.</p> <p><mathjax>#24.7color(red)cancel(color(black)("g CH"_4))xx(1"mol CH"_4)/(16.04color(red)cancel(color(black)("g CH"_4)))="1.54 mol CH"_4#</mathjax></p> <p><strong>Convert moles <mathjax>#"CH"_4#</mathjax> to moles <mathjax>#"CCl"_4#</mathjax>.</strong> </p> <p>Multiply mol <mathjax>#"CH"_4#</mathjax> by the mol ratio between <mathjax>#"CCl"_4#</mathjax> and <mathjax>#"CH"_4#</mathjax> from the balanced equation, with <mathjax>#"CCl"_4#</mathjax> in the numerator.</p> <p><mathjax>#1.54color(red)cancel(color(black)("mol CH"_4))xx(1"mol CCl"_4)/(1color(red)cancel(color(black)("mol CH"_4)))="1.54 mol CCl"_4#</mathjax></p> <p><strong>Calculate the mass of <mathjax>#"CCl"_4#</mathjax>.</strong> </p> <p>Multiply mol <mathjax>#"CCl"_4#</mathjax> by its molar mass <mathjax>#("153.82 g/mol")#</mathjax>.</p> <p><mathjax>#1.54color(red)cancel(color(black)("mol CCl"_4))xx(153.82"g CCl"_4)/(1color(red)cancel(color(black)("mol CCl"_4)))= "237 g CCl"_4"#</mathjax></p> <p><mathjax>#"237 g CCl"_4#</mathjax> are required to react completely with <mathjax>#"24.7 g CH"_4#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/114495" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -&gt; 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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What mass of #"CCl"_4# is required to react completely with #"24.7 g CH"_4#?

The reaction is #"CH"_4+"CCl"_4##rarr##"2CH"_2"Cl"_2#.

aacc206e-6ddd-11ea-a2e6-ccda262736ce

https://socratic.org/questions/what-is-the-theoretical-mass-of-copper-ii-carbonate-if-0-565-g-of-copper-ii-sulf

0.44 g

start physical_unit 6 8 theoretical_yield g qc_end physical_unit 13 15 10 11 mass qc_end physical_unit 21 22 18 19 mass qc_end end

[{"type":"physical unit","value":"Theoretical mass [OF] copper (ii) carbonate [IN] g"}]

[{"type":"physical unit","value":"0.44 g"}]

[{"type":"physical unit","value":"Mass [OF] copper (ii) sulfate [=] \\pu{0.565 g}"},{"type":"physical unit","value":"Mass [OF] sodium carbonate [=] \\pu{0.465 g}"}]

<h1 class="questionTitle" itemprop="name">What is the theoretical mass of copper (ii) carbonate if 0.565 g of copper (ii) sulfate reacts with 0.465 g of sodium carbonate?</h1>

0.44 g

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This is a <strong>limiting reactant</strong> problem.</p> <p>We know that we will need a balanced equation, molar masses, and moles of the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> involved.</p> <blockquote></blockquote> <p><strong>1. Gather all the information</strong> in one place with the molecular masses above the formulas and the given masses and moles below them.</p> <blockquote></blockquote> <p><mathjax>#M_r:color(white)(mmmm)159.61color(white)(mm)105.99color(white)(mmll)123.55#</mathjax><br/> <mathjax>#color(white)(mmmmmm)"CuSO"_4 + "Na"_2"CO"_3 → "CuCO"_3 + "Na"_2"SO"_4#</mathjax><br/> <mathjax>#"Mass/g:"color(white)(mmll)0.565color(white)(mmll)0.465#</mathjax><br/> <mathjax>#"Amt/mol:"color(white)(ll)"0.003 540"color(white)(ll)"0.004 387"#</mathjax><br/> <mathjax>#"Divide by:"color(white)(mmm)1color(white)(mmmml)1#</mathjax><br/> <mathjax>#"Moles rxn:"color(white)(ll)"0.003 540"color(white)(ll)"0.004 387"#</mathjax></p> <blockquote></blockquote> <p><strong>2. Identify the limiting reactant</strong></p> <p>An easy way to identify the limiting reactant is to calculate the "moles of reaction" each will give:</p> <p>You divide the moles of each reactant by its corresponding coefficient in the balanced equation.</p> <p>I did that for you in the table above.</p> <p><mathjax>#"CuSO"_4#</mathjax> is the limiting reactant because it gives fewer moles of reaction.</p> <blockquote></blockquote> <p><strong>3. Calculate the mass of <mathjax>#"CuCO"_3#</mathjax></strong></p> <p><mathjax>#"Mass of CuCO"_3 = "0.003 540" color(red)(cancel(color(black)("mol CuSO"_4))) × (1 color(red)(cancel(color(black)("mol CuCO"_3))))/(1 color(red)(cancel(color(black)("mol CuSO"_4)))) × ("123.55 g CuCO"_3)/(1 color(red)(cancel(color(black)("mol CuCO"_3)))) = "0.437 g CuCO"_3#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The theoretical mass of <mathjax>#"CuCO"_3#</mathjax> is 0.437 g.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This is a <strong>limiting reactant</strong> problem.</p> <p>We know that we will need a balanced equation, molar masses, and moles of the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> involved.</p> <blockquote></blockquote> <p><strong>1. Gather all the information</strong> in one place with the molecular masses above the formulas and the given masses and moles below them.</p> <blockquote></blockquote> <p><mathjax>#M_r:color(white)(mmmm)159.61color(white)(mm)105.99color(white)(mmll)123.55#</mathjax><br/> <mathjax>#color(white)(mmmmmm)"CuSO"_4 + "Na"_2"CO"_3 → "CuCO"_3 + "Na"_2"SO"_4#</mathjax><br/> <mathjax>#"Mass/g:"color(white)(mmll)0.565color(white)(mmll)0.465#</mathjax><br/> <mathjax>#"Amt/mol:"color(white)(ll)"0.003 540"color(white)(ll)"0.004 387"#</mathjax><br/> <mathjax>#"Divide by:"color(white)(mmm)1color(white)(mmmml)1#</mathjax><br/> <mathjax>#"Moles rxn:"color(white)(ll)"0.003 540"color(white)(ll)"0.004 387"#</mathjax></p> <blockquote></blockquote> <p><strong>2. Identify the limiting reactant</strong></p> <p>An easy way to identify the limiting reactant is to calculate the "moles of reaction" each will give:</p> <p>You divide the moles of each reactant by its corresponding coefficient in the balanced equation.</p> <p>I did that for you in the table above.</p> <p><mathjax>#"CuSO"_4#</mathjax> is the limiting reactant because it gives fewer moles of reaction.</p> <blockquote></blockquote> <p><strong>3. Calculate the mass of <mathjax>#"CuCO"_3#</mathjax></strong></p> <p><mathjax>#"Mass of CuCO"_3 = "0.003 540" color(red)(cancel(color(black)("mol CuSO"_4))) × (1 color(red)(cancel(color(black)("mol CuCO"_3))))/(1 color(red)(cancel(color(black)("mol CuSO"_4)))) × ("123.55 g CuCO"_3)/(1 color(red)(cancel(color(black)("mol CuCO"_3)))) = "0.437 g CuCO"_3#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the theoretical mass of copper (ii) carbonate if 0.565 g of copper (ii) sulfate reacts with 0.465 g of sodium carbonate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="317502" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-03T20:57:05" itemprop="dateCreated"> Oct 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The theoretical mass of <mathjax>#"CuCO"_3#</mathjax> is 0.437 g.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This is a <strong>limiting reactant</strong> problem.</p> <p>We know that we will need a balanced equation, molar masses, and moles of the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> involved.</p> <blockquote></blockquote> <p><strong>1. Gather all the information</strong> in one place with the molecular masses above the formulas and the given masses and moles below them.</p> <blockquote></blockquote> <p><mathjax>#M_r:color(white)(mmmm)159.61color(white)(mm)105.99color(white)(mmll)123.55#</mathjax><br/> <mathjax>#color(white)(mmmmmm)"CuSO"_4 + "Na"_2"CO"_3 → "CuCO"_3 + "Na"_2"SO"_4#</mathjax><br/> <mathjax>#"Mass/g:"color(white)(mmll)0.565color(white)(mmll)0.465#</mathjax><br/> <mathjax>#"Amt/mol:"color(white)(ll)"0.003 540"color(white)(ll)"0.004 387"#</mathjax><br/> <mathjax>#"Divide by:"color(white)(mmm)1color(white)(mmmml)1#</mathjax><br/> <mathjax>#"Moles rxn:"color(white)(ll)"0.003 540"color(white)(ll)"0.004 387"#</mathjax></p> <blockquote></blockquote> <p><strong>2. Identify the limiting reactant</strong></p> <p>An easy way to identify the limiting reactant is to calculate the "moles of reaction" each will give:</p> <p>You divide the moles of each reactant by its corresponding coefficient in the balanced equation.</p> <p>I did that for you in the table above.</p> <p><mathjax>#"CuSO"_4#</mathjax> is the limiting reactant because it gives fewer moles of reaction.</p> <blockquote></blockquote> <p><strong>3. Calculate the mass of <mathjax>#"CuCO"_3#</mathjax></strong></p> <p><mathjax>#"Mass of CuCO"_3 = "0.003 540" color(red)(cancel(color(black)("mol CuSO"_4))) × (1 color(red)(cancel(color(black)("mol CuCO"_3))))/(1 color(red)(cancel(color(black)("mol CuSO"_4)))) × ("123.55 g CuCO"_3)/(1 color(red)(cancel(color(black)("mol CuCO"_3)))) = "0.437 g CuCO"_3#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/317502" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -&gt; 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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What is the theoretical mass of copper (ii) carbonate if 0.565 g of copper (ii) sulfate reacts with 0.465 g of sodium carbonate?

ab2da818-6ddd-11ea-9b39-ccda262736ce

https://socratic.org/questions/what-is-the-ph-of-a-2-6-10-9-m-h-solution

6.99

start physical_unit 11 11 ph none qc_end physical_unit 10 10 6 9 molarity qc_end end

[{"type":"physical unit","value":"pH [OF] the solution"}]

[{"type":"physical unit","value":"6.99"}]

[{"type":"physical unit","value":"Molarity [OF] H+ [=] \\pu{2.6 × 10^(-9) M}"}]

<h1 class="questionTitle" itemprop="name">What is the pH of a #2.6*10^-9# #M# #H^+# solution?</h1>

6.99

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>In pure water, <mathjax>#["H"^+] = ["OH"^"-"] = 1.00 × 10^"-7" color(white)(l)"mol/L"#</mathjax>.</p> <p>Imagine that we add the <mathjax>#2.6 × 10^"-9" color(white)(l)"mol/L H"^+#</mathjax>, but the equilibrium hasn't had time to re-establish itself.</p> <p>We have just set up a new <strong>initial condition</strong>.</p> <p>Let's put this into an ICE table.</p> <blockquote></blockquote> <p><mathjax>#color(white)(mmmmm)"H"_2"O" ⇌ color(white)(mmmmmll)"H"^+color(white)(mmmm) +color(white)(mll) "OH"^"-"#</mathjax><br/> <mathjax>#"I/mol·L"^"-1": color(white)(mmmm)1.00×10^"-7" + 2.6×10^"-9" color(white)(ml)1.00 × 10^"-7"#</mathjax><br/> <mathjax>#"C/mol·L"^"-":color(white)(mmmmmmmmm) -x color(white)(mmmmmmml)-x#</mathjax><br/> <mathjax>#"E/mol·L"^"-1":color(white)(mmmmm) 1.026 × 10^"-7" -xcolor(white)(mml) 1.00 × 10^"-7" - x#</mathjax></p> <blockquote></blockquote> <p><mathjax>#K_w = ["H"^+]["OH"^"-"] = 1.00 × 10^"-14"#</mathjax></p> <p><mathjax>#(1.026 × 10^"-7" -x)(1.00 × 10^"-7" - x) = 1.00 × 10^"-14"#</mathjax></p> <p><mathjax>#x^2 - 2.026 × 10^"-7"x + 1.026 × 10^"-14" = 1.00 × 10^"-14"#</mathjax></p> <p><mathjax>#x^2 - 2.026 × 10^"-7"x + 0.026 × 10^"-14" = 0#</mathjax></p> <p><mathjax>#x = 1.30 × 10^"-9"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#["H"^+] = 1.026 × 10^"-7" -x = 1.026 × 10^"-7" - 1.03 × 10^"-9" = 1.016 × 10^"-7"#</mathjax></p> <p><mathjax>#"pH" = -log["H"^+] = -log(1.016 × 10^"-7") = 6.99#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> is 6.99.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>In pure water, <mathjax>#["H"^+] = ["OH"^"-"] = 1.00 × 10^"-7" color(white)(l)"mol/L"#</mathjax>.</p> <p>Imagine that we add the <mathjax>#2.6 × 10^"-9" color(white)(l)"mol/L H"^+#</mathjax>, but the equilibrium hasn't had time to re-establish itself.</p> <p>We have just set up a new <strong>initial condition</strong>.</p> <p>Let's put this into an ICE table.</p> <blockquote></blockquote> <p><mathjax>#color(white)(mmmmm)"H"_2"O" ⇌ color(white)(mmmmmll)"H"^+color(white)(mmmm) +color(white)(mll) "OH"^"-"#</mathjax><br/> <mathjax>#"I/mol·L"^"-1": color(white)(mmmm)1.00×10^"-7" + 2.6×10^"-9" color(white)(ml)1.00 × 10^"-7"#</mathjax><br/> <mathjax>#"C/mol·L"^"-":color(white)(mmmmmmmmm) -x color(white)(mmmmmmml)-x#</mathjax><br/> <mathjax>#"E/mol·L"^"-1":color(white)(mmmmm) 1.026 × 10^"-7" -xcolor(white)(mml) 1.00 × 10^"-7" - x#</mathjax></p> <blockquote></blockquote> <p><mathjax>#K_w = ["H"^+]["OH"^"-"] = 1.00 × 10^"-14"#</mathjax></p> <p><mathjax>#(1.026 × 10^"-7" -x)(1.00 × 10^"-7" - x) = 1.00 × 10^"-14"#</mathjax></p> <p><mathjax>#x^2 - 2.026 × 10^"-7"x + 1.026 × 10^"-14" = 1.00 × 10^"-14"#</mathjax></p> <p><mathjax>#x^2 - 2.026 × 10^"-7"x + 0.026 × 10^"-14" = 0#</mathjax></p> <p><mathjax>#x = 1.30 × 10^"-9"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#["H"^+] = 1.026 × 10^"-7" -x = 1.026 × 10^"-7" - 1.03 × 10^"-9" = 1.016 × 10^"-7"#</mathjax></p> <p><mathjax>#"pH" = -log["H"^+] = -log(1.016 × 10^"-7") = 6.99#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the pH of a #2.6*10^-9# #M# #H^+# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="293089" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-28T23:26:35" itemprop="dateCreated"> Jul 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> is 6.99.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>In pure water, <mathjax>#["H"^+] = ["OH"^"-"] = 1.00 × 10^"-7" color(white)(l)"mol/L"#</mathjax>.</p> <p>Imagine that we add the <mathjax>#2.6 × 10^"-9" color(white)(l)"mol/L H"^+#</mathjax>, but the equilibrium hasn't had time to re-establish itself.</p> <p>We have just set up a new <strong>initial condition</strong>.</p> <p>Let's put this into an ICE table.</p> <blockquote></blockquote> <p><mathjax>#color(white)(mmmmm)"H"_2"O" ⇌ color(white)(mmmmmll)"H"^+color(white)(mmmm) +color(white)(mll) "OH"^"-"#</mathjax><br/> <mathjax>#"I/mol·L"^"-1": color(white)(mmmm)1.00×10^"-7" + 2.6×10^"-9" color(white)(ml)1.00 × 10^"-7"#</mathjax><br/> <mathjax>#"C/mol·L"^"-":color(white)(mmmmmmmmm) -x color(white)(mmmmmmml)-x#</mathjax><br/> <mathjax>#"E/mol·L"^"-1":color(white)(mmmmm) 1.026 × 10^"-7" -xcolor(white)(mml) 1.00 × 10^"-7" - x#</mathjax></p> <blockquote></blockquote> <p><mathjax>#K_w = ["H"^+]["OH"^"-"] = 1.00 × 10^"-14"#</mathjax></p> <p><mathjax>#(1.026 × 10^"-7" -x)(1.00 × 10^"-7" - x) = 1.00 × 10^"-14"#</mathjax></p> <p><mathjax>#x^2 - 2.026 × 10^"-7"x + 1.026 × 10^"-14" = 1.00 × 10^"-14"#</mathjax></p> <p><mathjax>#x^2 - 2.026 × 10^"-7"x + 0.026 × 10^"-14" = 0#</mathjax></p> <p><mathjax>#x = 1.30 × 10^"-9"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#["H"^+] = 1.026 × 10^"-7" -x = 1.026 × 10^"-7" - 1.03 × 10^"-9" = 1.016 × 10^"-7"#</mathjax></p> <p><mathjax>#"pH" = -log["H"^+] = -log(1.016 × 10^"-7") = 6.99#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/293089" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? 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What is the pH of a #2.6*10^-9# #M# #H^+# solution?

abb2c627-6ddd-11ea-b2da-ccda262736ce

https://socratic.org/questions/58823731b72cff2e9f2d752c

0

start physical_unit 3 3 oxidation_state none qc_end chemical_equation 7 7 qc_end end

[{"type":"physical unit","value":"Oxidation state [OF] metal"}]

[{"type":"physical unit","value":"0"}]

[{"type":"chemical equation","value":"Ni(CO)4"}]

<h1 class="questionTitle" itemprop="name">What is the metal oxidation state in #Ni(CO)_4#?</h1>

0

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Oxidation number"#</mathjax> is the charge left on the central atom when all the <a href="https://socratic.org/chemistry/bonding-basics/bonding">bonding</a> pairs of electrons are removed, with the charge devolved to the most electronegative atom.</p> <p>For <mathjax>#Ni(CO)_4#</mathjax>, we break the <mathjax>#Ni-CO#</mathjax> bond and we get <mathjax>#Ni^0#</mathjax> <mathjax>#+4xx""^(-):C-=O^+#</mathjax>. And thus nickel has a formal oxidation state of <mathjax>#"ZERO".#</mathjax></p> <p>Because <mathjax>#Ni(CO)_4#</mathjax> is quite volatile, its formation forms the basis for the <a href="https://en.wikipedia.org/wiki/Mond_process" rel="nofollow">Mond process</a> for nickel purification. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We have zerovalent nickel, i.e. <mathjax>#Ni^(0)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Oxidation number"#</mathjax> is the charge left on the central atom when all the <a href="https://socratic.org/chemistry/bonding-basics/bonding">bonding</a> pairs of electrons are removed, with the charge devolved to the most electronegative atom.</p> <p>For <mathjax>#Ni(CO)_4#</mathjax>, we break the <mathjax>#Ni-CO#</mathjax> bond and we get <mathjax>#Ni^0#</mathjax> <mathjax>#+4xx""^(-):C-=O^+#</mathjax>. And thus nickel has a formal oxidation state of <mathjax>#"ZERO".#</mathjax></p> <p>Because <mathjax>#Ni(CO)_4#</mathjax> is quite volatile, its formation forms the basis for the <a href="https://en.wikipedia.org/wiki/Mond_process" rel="nofollow">Mond process</a> for nickel purification. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the metal oxidation state in #Ni(CO)_4#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-numbers" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation Numbers</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="369222" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-25T17:32:55" itemprop="dateCreated"> Jan 25, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We have zerovalent nickel, i.e. <mathjax>#Ni^(0)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Oxidation number"#</mathjax> is the charge left on the central atom when all the <a href="https://socratic.org/chemistry/bonding-basics/bonding">bonding</a> pairs of electrons are removed, with the charge devolved to the most electronegative atom.</p> <p>For <mathjax>#Ni(CO)_4#</mathjax>, we break the <mathjax>#Ni-CO#</mathjax> bond and we get <mathjax>#Ni^0#</mathjax> <mathjax>#+4xx""^(-):C-=O^+#</mathjax>. And thus nickel has a formal oxidation state of <mathjax>#"ZERO".#</mathjax></p> <p>Because <mathjax>#Ni(CO)_4#</mathjax> is quite volatile, its formation forms the basis for the <a href="https://en.wikipedia.org/wiki/Mond_process" rel="nofollow">Mond process</a> for nickel purification. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/369222" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-electron-configuration"> How do oxidation numbers relate to electron configuration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-valence-electrons"> How do oxidation numbers relate to valence electrons? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-vary-with-the-periodic-table"> How do oxidation numbers vary with the periodic table? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-oxidation-number-of-an-element-in-a-compound"> How do you calculate the oxidation number of an element in a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-sulfur"> What is the oxidation number for sulfur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-carbon"> What is the oxidation number for carbon? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-copper"> What is the oxidation number for copper? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-nitrogen"> What is the oxidation number for nitrogen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-oxygen"> What is the oxidation number for oxygen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-state-of-noble-gas-zero"> Why is the oxidation state of noble gas zero? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-numbers"> See all questions in Oxidation Numbers </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11397 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the metal oxidation state in #Ni(CO)_4#?

acd3cda4-6ddd-11ea-8a96-ccda262736ce

https://socratic.org/questions/what-is-the-oxidation-number-of-br-in-brcl

+1

start physical_unit 6 6 oxidation_number none qc_end chemical_equation 8 8 qc_end end

[{"type":"physical unit","value":"Oxidation number [OF] Br"}]

[{"type":"physical unit","value":"+1"}]

[{"type":"chemical equation","value":"BrCl"}]

<h1 class="questionTitle" itemprop="name">What is the oxidation number of Br in BrCl? </h1>

+1

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, oxidation number is the charge left on the given atom when all the <a href="http://socratic.org/chemistry/bonding-basics/bonding">bonding</a> pairs (of electrons) are broken, with charge devolving to the most electronegative atom. Since chlorine is more electronegative than bromine, clearly the 2 bonding electrons devolve to <mathjax>#Cl#</mathjax>. By this reasoning can you assign oxidation numbers to the interhalogen <mathjax>#IF_7#</mathjax>?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Given the definition (to follow), the oxidation state of <mathjax>#Br#</mathjax> is <mathjax>#+I#</mathjax>, and <mathjax>#Cl#</mathjax> is <mathjax>#-I#</mathjax>. Why?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, oxidation number is the charge left on the given atom when all the <a href="http://socratic.org/chemistry/bonding-basics/bonding">bonding</a> pairs (of electrons) are broken, with charge devolving to the most electronegative atom. Since chlorine is more electronegative than bromine, clearly the 2 bonding electrons devolve to <mathjax>#Cl#</mathjax>. By this reasoning can you assign oxidation numbers to the interhalogen <mathjax>#IF_7#</mathjax>?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the oxidation number of Br in BrCl? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-numbers" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation Numbers</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="179289" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-23T10:01:33" itemprop="dateCreated"> Oct 23, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Given the definition (to follow), the oxidation state of <mathjax>#Br#</mathjax> is <mathjax>#+I#</mathjax>, and <mathjax>#Cl#</mathjax> is <mathjax>#-I#</mathjax>. Why?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, oxidation number is the charge left on the given atom when all the <a href="http://socratic.org/chemistry/bonding-basics/bonding">bonding</a> pairs (of electrons) are broken, with charge devolving to the most electronegative atom. Since chlorine is more electronegative than bromine, clearly the 2 bonding electrons devolve to <mathjax>#Cl#</mathjax>. By this reasoning can you assign oxidation numbers to the interhalogen <mathjax>#IF_7#</mathjax>?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/179289" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-electron-configuration"> How do oxidation numbers relate to electron configuration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-valence-electrons"> How do oxidation numbers relate to valence electrons? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-vary-with-the-periodic-table"> How do oxidation numbers vary with the periodic table? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-oxidation-number-of-an-element-in-a-compound"> How do you calculate the oxidation number of an element in a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-sulfur"> What is the oxidation number for sulfur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-carbon"> What is the oxidation number for carbon? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-copper"> What is the oxidation number for copper? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-nitrogen"> What is the oxidation number for nitrogen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-oxygen"> What is the oxidation number for oxygen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-state-of-noble-gas-zero"> Why is the oxidation state of noble gas zero? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-numbers"> See all questions in Oxidation Numbers </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7157 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the oxidation number of Br in BrCl?

a85c631c-6ddd-11ea-b6d8-ccda262736ce

https://socratic.org/questions/a-sample-of-mercury-absorbed-257-j-of-heat-and-its-mass-was-45-kg-if-it-s-temper

139.64 J/(kg * K)

start physical_unit 1 3 specific_heat j/(kg_·_k) qc_end physical_unit 1 3 5 6 heat_energy qc_end physical_unit 1 3 13 14 mass qc_end physical_unit 1 3 20 21 temperature qc_end end

[{"type":"physical unit","value":"Specific heat [OF] the mercury sample [IN] J/(kg * K)"}]

[{"type":"physical unit","value":"139.64 J/(kg * K)"}]

[{"type":"physical unit","value":"Absorbed heat [OF] the mercury sample [=] \\pu{257 J}"},{"type":"physical unit","value":"Mass [OF] the mercury sample [=] \\pu{0.45 kg}"},{"type":"physical unit","value":"Increased temperature [OF] the mercury sample [=] \\pu{4.09 K}"}]

<h1 class="questionTitle" itemprop="name">A sample of mercury absorbed 257 J of heat and its mass was .45 kg. If it's temperature increased by 4.09 K, what is its specific heat in J° / kg K?</h1>

139.64 J/(kg * K)

<div class="answerDescription"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> formula is:</p> <p><mathjax>#c = Q/(m × ΔT)#</mathjax></p> <p>Where:</p> <p><mathjax>#c#</mathjax>: <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a>, in J/(kg.K)</p> <p><mathjax>#Q#</mathjax>: heat required for the temperature change, in J</p> <p><mathjax>#ΔT#</mathjax>: temperature change, in K</p> <p><mathjax>#m#</mathjax>: mass of the object, in kg</p> <p>For our equation, we are given everything in the right units, so all we need is to plug in the numbers.</p> <p><mathjax>#c = Q/(m × ΔT)#</mathjax></p> <p><mathjax>#c = (257)/(.45 xx 4.09)#</mathjax></p> <p><mathjax>#c = 139.64 (J)/(kgxxK)#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> formula is:</p> <p><mathjax>#c = Q/(m × ΔT)#</mathjax></p> <p>Where:</p> <p><mathjax>#c#</mathjax>: <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a>, in J/(kg.K)</p> <p><mathjax>#Q#</mathjax>: heat required for the temperature change, in J</p> <p><mathjax>#ΔT#</mathjax>: temperature change, in K</p> <p><mathjax>#m#</mathjax>: mass of the object, in kg</p> <p>For our equation, we are given everything in the right units, so all we need is to plug in the numbers.</p> <p><mathjax>#c = Q/(m × ΔT)#</mathjax></p> <p><mathjax>#c = (257)/(.45 xx 4.09)#</mathjax></p> <p><mathjax>#c = 139.64 (J)/(kgxxK)#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A sample of mercury absorbed 257 J of heat and its mass was .45 kg. If it's temperature increased by 4.09 K, what is its specific heat in J° / kg K?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="365920" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/wilson-3"><img alt="" class="" src="https://profilepictures.socratic.org/zZkzxeeJTw6nwcUWU7Kt_IMG_4844.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/wilson-3"> Wilson T </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-18T01:50:00" itemprop="dateCreated"> Jan 18, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> formula is:</p> <p><mathjax>#c = Q/(m × ΔT)#</mathjax></p> <p>Where:</p> <p><mathjax>#c#</mathjax>: <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a>, in J/(kg.K)</p> <p><mathjax>#Q#</mathjax>: heat required for the temperature change, in J</p> <p><mathjax>#ΔT#</mathjax>: temperature change, in K</p> <p><mathjax>#m#</mathjax>: mass of the object, in kg</p> <p>For our equation, we are given everything in the right units, so all we need is to plug in the numbers.</p> <p><mathjax>#c = Q/(m × ΔT)#</mathjax></p> <p><mathjax>#c = (257)/(.45 xx 4.09)#</mathjax></p> <p><mathjax>#c = 139.64 (J)/(kgxxK)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/365920" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="365921" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-18T01:53:04" itemprop="dateCreated"> Jan 18, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of mercury to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> is <mathjax>#"140 J"/("kg"*"K")#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the equation <mathjax>#color(red)(Q=mcDeltat)#</mathjax>, where <mathjax>#Q#</mathjax> is energy gained or lost in Joules; <mathjax>#m#</mathjax> is mass, in this case kg; <mathjax>#c#</mathjax> is specific heat, in this case in <mathjax>#"J"/("kg"*"K")"#</mathjax>; and <mathjax>#Deltat#</mathjax> is change in temperature, in this case Kelvins.<br/> Determine what variables are known, and unknown. Then solve the equation for the unknown variable.</p> <p><strong>Known</strong><br/> <mathjax>#Q="257 K"#</mathjax><br/> <mathjax>#m="0.45 kg"#</mathjax><br/> <mathjax>#Deltat="4.09 K"#</mathjax></p> <p><strong>Unknown</strong> <br/> <mathjax>#c_"Hg"#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#c_"Hg"#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#c_"Hg"=(Q)/(m*Deltat)=(257"J")/((0.45"kg")xx(4.09"K"))="140 J"/("kg"*"K")#</mathjax> rounded to two signficant figures</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/365921" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-heat-capacity-of-a-lead-sinker-be-determined"> How can the heat capacity of a lead sinker be determined? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-the-specific-heats-of-metals-compare-with-water"> How do the specific heats of metals compare with water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-specific-heat-change-with-temperature"> How does specific heat change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/dissolving-some-potassium-bromide-in-200cm3-of-water-leads-to-a-decrease-in-temp"> Dissolving some potassium bromide in 200cm3 of water leads to a decrease in temperature of 3oC.... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-heat-capacity-larger-for-polymers"> Is heat capacity larger for polymers? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-heat-capacity-an-extensive-property"> Why is heat capacity an extensive property? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-heat-capacity-change-with-temperature"> Why does heat capacity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-specific-heat-measured-in"> What is specific heat measured in? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-heat-capacity-measured-in"> What is heat capacity measured in? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/specific-heat"> See all questions in Specific Heat </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3137 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A sample of mercury absorbed 257 J of heat and its mass was .45 kg. If it's temperature increased by 4.09 K, what is its specific heat in J° / kg K?

ab1f3e59-6ddd-11ea-9af7-ccda262736ce

https://socratic.org/questions/590b2a9c7c01491a72c7b450

2.33 kg

start physical_unit 12 12 mass kg qc_end physical_unit 6 6 2 3 mass qc_end end

[{"type":"physical unit","value":"Mass [OF] nitrogen [IN] kg"}]

[{"type":"physical unit","value":"2.33 kg"}]

[{"type":"physical unit","value":"Mass [OF] urea [=] \\pu{5 kg}"}]

<h1 class="questionTitle" itemprop="name">In a #5*kg# mass of urea, what is the mass of nitrogen?</h1>

2.33 kg

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Urea has a formula of <mathjax>#O=C(NH_2)_2#</mathjax>, i.e. each mole of urea supplies two moles of (soluble?) nitrogen.</p> <p><mathjax>#"Moles of urea"=(5xx10^3*g)/(60.06*g*mol^-1)=83.25*mol#</mathjax>.</p> <p>And thus there is a mass of................ </p> <p><mathjax>#2xx83.25*molxx14.01*g*mol^-1=2333*g#</mathjax> </p> <p>with respect to nitrogen. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>For a start, urea has a molecular formula of <mathjax>#CH_4N_2O#</mathjax>. I get under <mathjax>#2.5*kg#</mathjax> of nitrogen.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Urea has a formula of <mathjax>#O=C(NH_2)_2#</mathjax>, i.e. each mole of urea supplies two moles of (soluble?) nitrogen.</p> <p><mathjax>#"Moles of urea"=(5xx10^3*g)/(60.06*g*mol^-1)=83.25*mol#</mathjax>.</p> <p>And thus there is a mass of................ </p> <p><mathjax>#2xx83.25*molxx14.01*g*mol^-1=2333*g#</mathjax> </p> <p>with respect to nitrogen. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">In a #5*kg# mass of urea, what is the mass of nitrogen?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/percent-composition" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Composition</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="417585" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-04T13:45:05" itemprop="dateCreated"> May 4, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>For a start, urea has a molecular formula of <mathjax>#CH_4N_2O#</mathjax>. I get under <mathjax>#2.5*kg#</mathjax> of nitrogen.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Urea has a formula of <mathjax>#O=C(NH_2)_2#</mathjax>, i.e. each mole of urea supplies two moles of (soluble?) nitrogen.</p> <p><mathjax>#"Moles of urea"=(5xx10^3*g)/(60.06*g*mol^-1)=83.25*mol#</mathjax>.</p> <p>And thus there is a mass of................ </p> <p><mathjax>#2xx83.25*molxx14.01*g*mol^-1=2333*g#</mathjax> </p> <p>with respect to nitrogen. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/417585" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-mole-percent"> What is mole percent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188602bf3469570e2e8b"> Question #e2e8b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188702bf34695a6bc737"> Question #bc737 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418be02bf34695a6bc73b"> Question #bc73b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c202bf3469570e2e8f"> Question #e2e8f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c802bf346963eb9857"> Question #b9857 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418ca02bf346963eb985b"> Question #b985b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418cc02bf34694a4fee41"> Question #fee41 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418d502bf34694c8c5c01"> Question #c5c01 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4196e02bf34695a6bc73f"> Question #bc73f </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/percent-composition"> See all questions in Percent Composition </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1918 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

In a #5*kg# mass of urea, what is the mass of nitrogen?

acb5e59c-6ddd-11ea-82c7-ccda262736ce

https://socratic.org/questions/what-is-the-molality-of-a-solution-containing-8-moles-of-solute-in-3-2-kg-of-sol

2.5 mol/kg

start physical_unit 6 6 molality mol/kg qc_end physical_unit 11 11 8 9 mole qc_end physical_unit 16 16 13 14 mass qc_end end

[{"type":"physical unit","value":"Molality [OF] solution [IN] mol/kg"}]

[{"type":"physical unit","value":"2.5 mol/kg"}]

[{"type":"physical unit","value":"Mole [OF] solute [=] \\pu{8 moles}"},{"type":"physical unit","value":"Mass [OF] solvnent [=] \\pu{3.2 kg}"}]

<h1 class="questionTitle" itemprop="name">What is the molality of a solution containing 8 moles of solute in 3.2 kg of solvnent?</h1>

2.5 mol/kg

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molality"#</mathjax> is given by the quotient <mathjax>#"Moles of solute"/"kilograms of solvent"#</mathjax>.</p> <p>And thus we simply fill in the blanks, <mathjax>#(8*"mol")/(3.2*"kg")=2.5*"mol"*"kg"^-1.#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Molality"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.5*mol*kg^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molality"#</mathjax> is given by the quotient <mathjax>#"Moles of solute"/"kilograms of solvent"#</mathjax>.</p> <p>And thus we simply fill in the blanks, <mathjax>#(8*"mol")/(3.2*"kg")=2.5*"mol"*"kg"^-1.#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the molality of a solution containing 8 moles of solute in 3.2 kg of solvnent?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="406936" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-14T20:45:12" itemprop="dateCreated"> Apr 14, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Molality"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.5*mol*kg^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molality"#</mathjax> is given by the quotient <mathjax>#"Moles of solute"/"kilograms of solvent"#</mathjax>.</p> <p>And thus we simply fill in the blanks, <mathjax>#(8*"mol")/(3.2*"kg")=2.5*"mol"*"kg"^-1.#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/406936" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2658 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the molality of a solution containing 8 moles of solute in 3.2 kg of solvnent?

a8e90043-6ddd-11ea-8086-ccda262736ce

https://socratic.org/questions/if-the-hydronium-ion-concentration-of-a-solution-is-1-63-10-8-m-what-is-the-hydr

6.13 × 10^(-7) M

start physical_unit 16 17 concentration mol/l qc_end physical_unit 2 3 9 12 concentration qc_end end

[{"type":"physical unit","value":"Concentration [OF] hydroxide ion [IN] M"}]

[{"type":"physical unit","value":"6.13 × 10^(-7) M"}]

[{"type":"physical unit","value":"Concentration [OF] hydronium ion [=] \\pu{1.63 × 10^(−8) M}"}]

<h1 class="questionTitle" itemprop="name">If the hydronium ion concentration of a solution is #1.63 * 10^-8# #M#, what is the hydroxide ion concentration?</h1>

6.13 × 10^(-7) M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If <mathjax>#[H_3O^+]=1.63xx10^-8#</mathjax>, then <mathjax>#pH=-log_10(1.63xx10^-8)#</mathjax>.</p> <p>And <mathjax>#[HO^-]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#10^(pH-14)#</mathjax>, which should be less than <mathjax>#7#</mathjax>. Why so?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH+pOH=14#</mathjax>, in aqueous solution at <mathjax>#298K#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If <mathjax>#[H_3O^+]=1.63xx10^-8#</mathjax>, then <mathjax>#pH=-log_10(1.63xx10^-8)#</mathjax>.</p> <p>And <mathjax>#[HO^-]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#10^(pH-14)#</mathjax>, which should be less than <mathjax>#7#</mathjax>. Why so?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If the hydronium ion concentration of a solution is #1.63 * 10^-8# #M#, what is the hydroxide ion concentration?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="298360" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-13T05:51:47" itemprop="dateCreated"> Aug 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH+pOH=14#</mathjax>, in aqueous solution at <mathjax>#298K#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If <mathjax>#[H_3O^+]=1.63xx10^-8#</mathjax>, then <mathjax>#pH=-log_10(1.63xx10^-8)#</mathjax>.</p> <p>And <mathjax>#[HO^-]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#10^(pH-14)#</mathjax>, which should be less than <mathjax>#7#</mathjax>. Why so?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/298360" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3155 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

If the hydronium ion concentration of a solution is #1.63 * 10^-8# #M#, what is the hydroxide ion concentration?

ab23ab64-6ddd-11ea-8a95-ccda262736ce

https://socratic.org/questions/how-many-moles-of-oxygen-are-lost-in-the-following-problem

0.2 moles

start physical_unit 4 4 mole mol qc_end physical_unit 4 4 21 22 volume qc_end physical_unit 4 4 24 25 mole qc_end physical_unit 4 4 39 40 pressure qc_end physical_unit 4 4 57 58 volume qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"losted mole3 [OF] oxygen [IN] moles"}]

[{"type":"physical unit","value":"0.2 moles"}]

[{"type":"physical unit","value":"Volume1 [OF] oxygen in cylinder with a moveable piston [=] \\pu{12.7 L}"},{"type":"physical unit","value":"Mole1 [OF] oxygen [=] \\pu{3.5 mol}"},{"type":"physical unit","value":"pressure1 [OF] the gas [=] \\pu{5.83 atm}"},{"type":"other","value":"the cylinder develops a leak"},{"type":"physical unit","value":"Volume2 [OF] the gas [=] \\pu{12.1 L}"},{"type":"other","value":"at same pressure"}]

<h1 class="questionTitle" itemprop="name">How many moles of oxygen are lost in the following problem?</h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>A cylinder with a moveable piston records a volume of 12.7 L when 3.5 mol of oxygen is added. The gas in the cylinder has a pressure of 5.83 atm. The cylinder develops a leak, and the volume of the gas is now recorded to be 12.1 L at the same pressure. </p></div> </h2> </div> </div>

0.2 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use Boyles Law to find the volume of Oxygen lost at standard pressure of 1 atm. </p> <p><mathjax># P_1 xx V_1 = P_2 xx V_2#</mathjax> </p> <p><mathjax>#P_1 = 5.83 #</mathjax><br/> <mathjax>#V_1 = 0.6 #</mathjax> <br/> <mathjax>#P_2 = 1.00#</mathjax><br/> <mathjax>#V_2#</mathjax> = Volume of Oxygen lost. </p> <p>Solving the problem to find the Volume of Oxygen lost </p> <p><mathjax># 5.83 xx 0.6 = 1 xx V_2#</mathjax> </p> <p>3.50 liters = <mathjax>#V_2#</mathjax> </p> <p>22.4 liters = 1 mole at STP for an ideal gas. </p> <p>Assuming Oxygen is close to an ideal gas </p> <p><mathjax># 3.50/22.4#</mathjax> = moles Oxygen. </p> <p>0.156 = moles of Oxygen. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>.16 moles of Oxygen assuming the temperature is at standard temperature. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use Boyles Law to find the volume of Oxygen lost at standard pressure of 1 atm. </p> <p><mathjax># P_1 xx V_1 = P_2 xx V_2#</mathjax> </p> <p><mathjax>#P_1 = 5.83 #</mathjax><br/> <mathjax>#V_1 = 0.6 #</mathjax> <br/> <mathjax>#P_2 = 1.00#</mathjax><br/> <mathjax>#V_2#</mathjax> = Volume of Oxygen lost. </p> <p>Solving the problem to find the Volume of Oxygen lost </p> <p><mathjax># 5.83 xx 0.6 = 1 xx V_2#</mathjax> </p> <p>3.50 liters = <mathjax>#V_2#</mathjax> </p> <p>22.4 liters = 1 mole at STP for an ideal gas. </p> <p>Assuming Oxygen is close to an ideal gas </p> <p><mathjax># 3.50/22.4#</mathjax> = moles Oxygen. </p> <p>0.156 = moles of Oxygen. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles of oxygen are lost in the following problem?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>A cylinder with a moveable piston records a volume of 12.7 L when 3.5 mol of oxygen is added. The gas in the cylinder has a pressure of 5.83 atm. The cylinder develops a leak, and the volume of the gas is now recorded to be 12.1 L at the same pressure. </p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/measuring-gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Measuring Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="324363" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/david-drayer"><img alt="" class="" src="https://graph.facebook.com/10206723679871989/picture?height=50&amp;width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/david-drayer"> David Drayer </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-20T22:50:01" itemprop="dateCreated"> Oct 20, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>.16 moles of Oxygen assuming the temperature is at standard temperature. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use Boyles Law to find the volume of Oxygen lost at standard pressure of 1 atm. </p> <p><mathjax># P_1 xx V_1 = P_2 xx V_2#</mathjax> </p> <p><mathjax>#P_1 = 5.83 #</mathjax><br/> <mathjax>#V_1 = 0.6 #</mathjax> <br/> <mathjax>#P_2 = 1.00#</mathjax><br/> <mathjax>#V_2#</mathjax> = Volume of Oxygen lost. </p> <p>Solving the problem to find the Volume of Oxygen lost </p> <p><mathjax># 5.83 xx 0.6 = 1 xx V_2#</mathjax> </p> <p>3.50 liters = <mathjax>#V_2#</mathjax> </p> <p>22.4 liters = 1 mole at STP for an ideal gas. </p> <p>Assuming Oxygen is close to an ideal gas </p> <p><mathjax># 3.50/22.4#</mathjax> = moles Oxygen. </p> <p>0.156 = moles of Oxygen. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/324363" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="325150" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-22T19:48:15" itemprop="dateCreated"> Oct 22, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The cylinder has lost 0.2 mol of oxygen.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The pressure and temperature are constant.</p> <p>Only the volume and the number of moles are changing.</p> <p>The appropriate relationship is therefore <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/avogadro-s-law">Avogadro's law</a></strong>: the volume of a gas is directly proportional to the number of moles, if all other variables are held constant.</p> <p>In symbols,</p> <p><mathjax>#V ∝ n#</mathjax></p> <p><mathjax>#V = kn#</mathjax> or <mathjax>#V/n = k#</mathjax></p> <p>This leads to the relation</p> <blockquote> <p><mathjax>#color(blue)(bar(ul(|color(white)(a/a) V_1/n_1 = V_2/n_2color(white)(a/a)|)))" "#</mathjax></p> </blockquote> <p>In this problem,</p> <p><mathjax>#V_1 = "12.7 L"; n_1 = "3.5 mol"#</mathjax><br/> <mathjax>#V_2 = "12.1 L"; n_2 = "?"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#n_2 = n_1 × V_2/V_1 = "3.5 mol" × (12.1 color(red)(cancel(color(black)("L"))))/(12.7 color(red)(cancel(color(black)("L")))) = "3.33 mol"#</mathjax></p> <p><mathjax>#Δn = n_2 - n_1 = "3.33 mol - 3.5 mol" = "-0.2 mol"#</mathjax> (1 significant figure)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/325150" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-used-to-measure-gas-pressure-in-a-closed-container"> What is used to measure gas pressure in a closed container? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-tool-is-used-to-measure-gas-pressure"> What tool is used to measure gas pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-units-are-used-to-measure-gas-pressure"> What units are used to measure gas pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-boyle-s-law"> What is Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-gas-pressure-practice-problem"> What is an example of a gas pressure practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-when-measuring-gas-pressure"> What are some common mistakes students make when measuring gas pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-boyle-s-law-practice-problem"> What is an example of a Boyle's law practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-boyle-s-law-and-charles-law-differ-1"> How do Boyle's law and Charles' law differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-measure-gas-pressure"> How can I measure gas pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyle-s-law-affect-the-human-body"> How does Boyle's law affect the human body? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/measuring-gas-pressure"> See all questions in Measuring Gas Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4048 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many moles of oxygen are lost in the following problem?

A cylinder with a moveable piston records a volume of 12.7 L when 3.5 mol of oxygen is added. The gas in the cylinder has a pressure of 5.83 atm. The cylinder develops a leak, and the volume of the gas is now recorded to be 12.1 L at the same pressure.

acddf742-6ddd-11ea-b988-ccda262736ce

https://socratic.org/questions/exactly-one-mole-of-an-ideal-gas-is-contained-in-a-2-00-liter-container-at-1-000

41.05 atm

start physical_unit 23 24 pressure atm qc_end physical_unit 5 6 1 2 mole qc_end physical_unit 5 6 11 12 volume qc_end physical_unit 5 6 15 16 temperature qc_end end

[{"type":"physical unit","value":"Pressure [OF] this gas [IN] atm"}]

[{"type":"physical unit","value":"41.05 atm"}]

[{"type":"physical unit","value":"Mole [OF] the ideal gas [=] \\pu{1 mole}"},{"type":"physical unit","value":"Volume [OF] the ideal gas [=] \\pu{2.00 liters}"},{"type":"physical unit","value":"Temperature [OF] the ideal gas [=] \\pu{1,000 K}"}]

<h1 class="questionTitle" itemprop="name">Exactly one mole of an ideal gas is contained in a 2.00 liter container at 1,000 K. What is the pressure exerted by this gas? </h1>

41.05 atm

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P=(nRT)/V#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1*cancel(mol)xx0.0821*cancelL*atm*cancel(K^-1)*cancel(mol^-1)xx1000*cancel(K))/(2.00*cancelL)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??*atm#</mathjax></p> <p>I hope the container is strong. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Over <mathjax>#40*atm#</mathjax>. We follow the ideal gas equation</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P=(nRT)/V#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1*cancel(mol)xx0.0821*cancelL*atm*cancel(K^-1)*cancel(mol^-1)xx1000*cancel(K))/(2.00*cancelL)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??*atm#</mathjax></p> <p>I hope the container is strong. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Exactly one mole of an ideal gas is contained in a 2.00 liter container at 1,000 K. What is the pressure exerted by this gas? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="260853" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-01T06:06:43" itemprop="dateCreated"> May 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Over <mathjax>#40*atm#</mathjax>. We follow the ideal gas equation</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P=(nRT)/V#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1*cancel(mol)xx0.0821*cancelL*atm*cancel(K^-1)*cancel(mol^-1)xx1000*cancel(K))/(2.00*cancelL)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??*atm#</mathjax></p> <p>I hope the container is strong. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/260853" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2720 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

Exactly one mole of an ideal gas is contained in a 2.00 liter container at 1,000 K. What is the pressure exerted by this gas?

ad18ad0c-6ddd-11ea-93a7-ccda262736ce

https://socratic.org/questions/for-the-reaction-2h-2-o-2-2h-2o-how-many-moles-of-water-can-be-produced-from-6-0

12 moles

start physical_unit 14 14 mole mol qc_end chemical_equation 3 9 qc_end physical_unit 22 22 19 20 mole qc_end end

[{"type":"physical unit","value":"Mole [OF] water [IN] moles"}]

[{"type":"physical unit","value":"12 moles"}]

[{"type":"chemical equation","value":"2 H2 + O2 -> 2 H2O"},{"type":"physical unit","value":"Mole [OF] oxygen [=] \\pu{6.0 mol}"}]

<h1 class="questionTitle" itemprop="name">For the reaction #2H_2 + O_2 -&gt; 2H_2O#, how many moles of water can be produced from 6.0 mol of oxygen?</h1>

12 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your tools of choice for <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> problems will always be the <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> that exist between the chemical species that take part in the reaction. </p> <p>As you know, the <strong>stoichiometric coefficients</strong> attributed to each compound in the <strong>balanced</strong> chemical equation can be thought of as <em>moles</em> of reactants needed or <em>moles</em> of products formed in the reaction. </p> <p>In your case, the balanced chemical equation for this <a href="http://socratic.org/chemistry/chemical-reactions/synthesis-reactions">synthesis reaction</a> looks like this </p> <blockquote> <p><mathjax>#2"H"_text(2(g]) + "O"_text(2(g]) -&gt; color(red)(2)"H"_2"O"_text((l]])#</mathjax></p> </blockquote> <p>Notice that the reaction requires <mathjax>#2#</mathjax> moles of hydrogen gas and <mathjax>#1#</mathjax> mole of oxygen gas to produce <mathjax>#color(red)(2)#</mathjax> moles of water. </p> <p>This tells you that the reaction produces <strong>twice as many moles</strong> of water as you have moles of oxygen gas that take part in the reaction. </p> <p>You know that your reaction uses <mathjax>#6.0#</mathjax> moles of oxygen. Assuming that hydrogen gas is not a <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>, you can say that the reaction will produce </p> <blockquote> <p><mathjax>#6.0 color(red)(cancel(color(black)("moles O"_2))) * (color(red)(2)" moles H"_2"O")/(1color(red)(cancel(color(black)("moles O"_2)))) = color(green)("12 moles H"_2"O")#</mathjax></p> </blockquote> <p> <iframe src="https://www.youtube.com/embed/75vcuXeQcRs?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"12 moles H"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your tools of choice for <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> problems will always be the <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> that exist between the chemical species that take part in the reaction. </p> <p>As you know, the <strong>stoichiometric coefficients</strong> attributed to each compound in the <strong>balanced</strong> chemical equation can be thought of as <em>moles</em> of reactants needed or <em>moles</em> of products formed in the reaction. </p> <p>In your case, the balanced chemical equation for this <a href="http://socratic.org/chemistry/chemical-reactions/synthesis-reactions">synthesis reaction</a> looks like this </p> <blockquote> <p><mathjax>#2"H"_text(2(g]) + "O"_text(2(g]) -&gt; color(red)(2)"H"_2"O"_text((l]])#</mathjax></p> </blockquote> <p>Notice that the reaction requires <mathjax>#2#</mathjax> moles of hydrogen gas and <mathjax>#1#</mathjax> mole of oxygen gas to produce <mathjax>#color(red)(2)#</mathjax> moles of water. </p> <p>This tells you that the reaction produces <strong>twice as many moles</strong> of water as you have moles of oxygen gas that take part in the reaction. </p> <p>You know that your reaction uses <mathjax>#6.0#</mathjax> moles of oxygen. Assuming that hydrogen gas is not a <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>, you can say that the reaction will produce </p> <blockquote> <p><mathjax>#6.0 color(red)(cancel(color(black)("moles O"_2))) * (color(red)(2)" moles H"_2"O")/(1color(red)(cancel(color(black)("moles O"_2)))) = color(green)("12 moles H"_2"O")#</mathjax></p> </blockquote> <p> <iframe src="https://www.youtube.com/embed/75vcuXeQcRs?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">For the reaction #2H_2 + O_2 -&gt; 2H_2O#, how many moles of water can be produced from 6.0 mol of oxygen?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="196468" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-05T01:41:03" itemprop="dateCreated"> Dec 5, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"12 moles H"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your tools of choice for <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> problems will always be the <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> that exist between the chemical species that take part in the reaction. </p> <p>As you know, the <strong>stoichiometric coefficients</strong> attributed to each compound in the <strong>balanced</strong> chemical equation can be thought of as <em>moles</em> of reactants needed or <em>moles</em> of products formed in the reaction. </p> <p>In your case, the balanced chemical equation for this <a href="http://socratic.org/chemistry/chemical-reactions/synthesis-reactions">synthesis reaction</a> looks like this </p> <blockquote> <p><mathjax>#2"H"_text(2(g]) + "O"_text(2(g]) -&gt; color(red)(2)"H"_2"O"_text((l]])#</mathjax></p> </blockquote> <p>Notice that the reaction requires <mathjax>#2#</mathjax> moles of hydrogen gas and <mathjax>#1#</mathjax> mole of oxygen gas to produce <mathjax>#color(red)(2)#</mathjax> moles of water. </p> <p>This tells you that the reaction produces <strong>twice as many moles</strong> of water as you have moles of oxygen gas that take part in the reaction. </p> <p>You know that your reaction uses <mathjax>#6.0#</mathjax> moles of oxygen. Assuming that hydrogen gas is not a <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>, you can say that the reaction will produce </p> <blockquote> <p><mathjax>#6.0 color(red)(cancel(color(black)("moles O"_2))) * (color(red)(2)" moles H"_2"O")/(1color(red)(cancel(color(black)("moles O"_2)))) = color(green)("12 moles H"_2"O")#</mathjax></p> </blockquote> <p> <iframe src="https://www.youtube.com/embed/75vcuXeQcRs?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/196468" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179102bf3469517a1072"> Question #a1072 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179402bf34694c8c5bf1"> Question #c5bf1 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179702bf3469588dc373"> Question #dc373 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179c02bf34694c8c5bf9"> Question #c5bf9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417a302bf3469517a1076"> Question #a1076 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417c702bf3469588dc377"> Question #dc377 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d002bf346963eb984f"> Question #b984f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d402bf346950519ea3"> Question #19ea3 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/mole-ratios"> See all questions in Mole Ratios </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 204265 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

For the reaction #2H_2 + O_2 -&gt; 2H_2O#, how many moles of water can be produced from 6.0 mol of oxygen?

ab707a42-6ddd-11ea-ba23-ccda262736ce

https://socratic.org/questions/a-sample-of-nitrogen-gas-has-a-volume-of-32-4-l-at-20-c-the-gas-is-heated-to-220

54.52 L

start physical_unit 1 4 volume l qc_end physical_unit 1 4 9 10 volume qc_end physical_unit 1 4 12 13 temperature qc_end physical_unit 1 4 19 19 temperature qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Volume2 [OF] nitrogen gas sample [IN] L"}]

[{"type":"physical unit","value":"54.52 L"}]

[{"type":"physical unit","value":"Volume1 [OF] nitrogen gas sample [=] \\pu{32.4 L}"},{"type":"physical unit","value":"Temperature1 [OF] nitrogen gas sample [=] \\pu{20 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] nitrogen gas sample [=] \\pu{220°C}"},{"type":"other","value":"Constant pressure."}]

<h1 class="questionTitle" itemprop="name">A sample of nitrogen gas has a volume of 32.4 L at 20°C. The gas is heated to 220°C at constant pressure. What is the final volume of nitrogen?</h1>

54.52 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of <a href="http://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' law</a> which states that the volume of a gas held at constant pressure is directly proportional to the Kelvin temperature. The equation for Charles' law is <mathjax>#V_1/T_1=V_2/T_2#</mathjax>.</p> <p><strong>Given/Known</strong><br/> <mathjax>#V_1="32.4 L"#</mathjax><br/> <mathjax>#T_1="20"^"o""C"+273.15="293 K"#</mathjax><br/> <mathjax>#T_2="220"^"o""C"+273.15="493 K"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#V_2="???"#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax> and solve.</p> <p><mathjax>#V_1/T_1=V_2/T_2#</mathjax></p> <p><mathjax>#V_2=(V_1T_2)/T_1#</mathjax></p> <p><mathjax>#V_2=(32.4"L"xx493cancel"K")/(293cancel"K")="54.5 L"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of nitrogen gas at 493 K will be 54.5 L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of <a href="http://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' law</a> which states that the volume of a gas held at constant pressure is directly proportional to the Kelvin temperature. The equation for Charles' law is <mathjax>#V_1/T_1=V_2/T_2#</mathjax>.</p> <p><strong>Given/Known</strong><br/> <mathjax>#V_1="32.4 L"#</mathjax><br/> <mathjax>#T_1="20"^"o""C"+273.15="293 K"#</mathjax><br/> <mathjax>#T_2="220"^"o""C"+273.15="493 K"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#V_2="???"#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax> and solve.</p> <p><mathjax>#V_1/T_1=V_2/T_2#</mathjax></p> <p><mathjax>#V_2=(V_1T_2)/T_1#</mathjax></p> <p><mathjax>#V_2=(32.4"L"xx493cancel"K")/(293cancel"K")="54.5 L"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A sample of nitrogen gas has a volume of 32.4 L at 20°C. The gas is heated to 220°C at constant pressure. What is the final volume of nitrogen?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/charles-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Charles' Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="202892" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-24T05:15:18" itemprop="dateCreated"> Dec 24, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of nitrogen gas at 493 K will be 54.5 L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of <a href="http://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' law</a> which states that the volume of a gas held at constant pressure is directly proportional to the Kelvin temperature. The equation for Charles' law is <mathjax>#V_1/T_1=V_2/T_2#</mathjax>.</p> <p><strong>Given/Known</strong><br/> <mathjax>#V_1="32.4 L"#</mathjax><br/> <mathjax>#T_1="20"^"o""C"+273.15="293 K"#</mathjax><br/> <mathjax>#T_2="220"^"o""C"+273.15="493 K"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#V_2="???"#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax> and solve.</p> <p><mathjax>#V_1/T_1=V_2/T_2#</mathjax></p> <p><mathjax>#V_2=(V_1T_2)/T_1#</mathjax></p> <p><mathjax>#V_2=(32.4"L"xx493cancel"K")/(293cancel"K")="54.5 L"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/202892" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-must-charles-law-be-in-kelvins"> Why must Charles' law be in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-charles-law-formula"> What is Charles' law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/oxygen-gas-is-at-a-temperature-of-40-c-when-it-occupies-a-volume-of-2-3-liters-t"> Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.3 liters. 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A sample of nitrogen gas has a volume of 32.4 L at 20°C. The gas is heated to 220°C at constant pressure. What is the final volume of nitrogen?

aa5fba28-6ddd-11ea-96d3-ccda262736ce

https://socratic.org/questions/how-many-moles-of-magnesium-oxide-are-produced-by-the-reaction-of-3-82-g-of-magn

0.11 moles

start physical_unit 4 5 mole mol qc_end physical_unit 15 16 12 13 mass qc_end physical_unit 21 21 18 19 mass qc_end chemical_equation 22 31 qc_end end

[{"type":"physical unit","value":"Mole [OF] magnesium oxide [IN] moles"}]

[{"type":"physical unit","value":"0.11 moles"}]

[{"type":"physical unit","value":"Mass [OF] magnesium nitride [=] \\pu{3.82 g}"},{"type":"physical unit","value":"Mass [OF] water [=] \\pu{7.73 g}"},{"type":"chemical equation","value":"Mg3N2 + 3 H2O -> 2 NH3 + 3 MgO"}]

<h1 class="questionTitle" itemprop="name">How many moles of magnesium oxide are produced by the reaction of 3.82 g of magnesium nitride with 7.73 g of water? #Mg_3N_2 + 3H_2O -&gt; 2NH_3 3MgO#</h1>

0.11 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is it balanced? Don't trust my arithmetic.</p> <p>This tells us UNEQUIVOCALLY that <mathjax>#100.95*g#</mathjax> <mathjax>#"magnesium nitride"#</mathjax> reacts with <mathjax>#108.06*g#</mathjax> water to give stoichiometric <mathjax>#"ammonia"#</mathjax>, and <mathjax>#"magnesium hydroxide"#</mathjax>.</p> <p>We have molar quantities of........</p> <p><mathjax>#"moles of"#</mathjax> <mathjax>#Mg_3N_2=(3.82*g)/(100.95*g*mol^-1)=0.0378*mol#</mathjax></p> <p><mathjax>#"moles of"#</mathjax> <mathjax>#OH_2=(7.73*g)/(18.01*g*mol^-1)=0.429*mol#</mathjax></p> <p>Water is thus present in stoichiometric excess. Do you agree?</p> <p>And thus we get stoichiometric <mathjax>#"magnesium hydroxide"#</mathjax>, i.e. <mathjax>#0.0378*molxx3*molxx58.32*g*mol^-1=6.61*g#</mathjax>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We assess the rxn....</p> <p><mathjax>#Mg_3N_2(s)+6H_2O(l) rarr 2NH_3(aq) + 3Mg(OH)_2(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is it balanced? Don't trust my arithmetic.</p> <p>This tells us UNEQUIVOCALLY that <mathjax>#100.95*g#</mathjax> <mathjax>#"magnesium nitride"#</mathjax> reacts with <mathjax>#108.06*g#</mathjax> water to give stoichiometric <mathjax>#"ammonia"#</mathjax>, and <mathjax>#"magnesium hydroxide"#</mathjax>.</p> <p>We have molar quantities of........</p> <p><mathjax>#"moles of"#</mathjax> <mathjax>#Mg_3N_2=(3.82*g)/(100.95*g*mol^-1)=0.0378*mol#</mathjax></p> <p><mathjax>#"moles of"#</mathjax> <mathjax>#OH_2=(7.73*g)/(18.01*g*mol^-1)=0.429*mol#</mathjax></p> <p>Water is thus present in stoichiometric excess. Do you agree?</p> <p>And thus we get stoichiometric <mathjax>#"magnesium hydroxide"#</mathjax>, i.e. <mathjax>#0.0378*molxx3*molxx58.32*g*mol^-1=6.61*g#</mathjax>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles of magnesium oxide are produced by the reaction of 3.82 g of magnesium nitride with 7.73 g of water? #Mg_3N_2 + 3H_2O -&gt; 2NH_3 3MgO#</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="459190" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-02T06:26:27" itemprop="dateCreated"> Aug 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We assess the rxn....</p> <p><mathjax>#Mg_3N_2(s)+6H_2O(l) rarr 2NH_3(aq) + 3Mg(OH)_2(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is it balanced? Don't trust my arithmetic.</p> <p>This tells us UNEQUIVOCALLY that <mathjax>#100.95*g#</mathjax> <mathjax>#"magnesium nitride"#</mathjax> reacts with <mathjax>#108.06*g#</mathjax> water to give stoichiometric <mathjax>#"ammonia"#</mathjax>, and <mathjax>#"magnesium hydroxide"#</mathjax>.</p> <p>We have molar quantities of........</p> <p><mathjax>#"moles of"#</mathjax> <mathjax>#Mg_3N_2=(3.82*g)/(100.95*g*mol^-1)=0.0378*mol#</mathjax></p> <p><mathjax>#"moles of"#</mathjax> <mathjax>#OH_2=(7.73*g)/(18.01*g*mol^-1)=0.429*mol#</mathjax></p> <p>Water is thus present in stoichiometric excess. Do you agree?</p> <p>And thus we get stoichiometric <mathjax>#"magnesium hydroxide"#</mathjax>, i.e. <mathjax>#0.0378*molxx3*molxx58.32*g*mol^-1=6.61*g#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/459190" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 16955 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many moles of magnesium oxide are produced by the reaction of 3.82 g of magnesium nitride with 7.73 g of water? #Mg_3N_2 + 3H_2O -&gt; 2NH_3 3MgO#

ab3b104c-6ddd-11ea-b5b5-ccda262736ce

https://socratic.org/questions/what-pressure-in-pascals-will-be-exerted-by-4-78-grams-of-oxygen-gas-in-a-2-5-li

1455989.13 Pascals

start physical_unit 11 12 pressure pa qc_end physical_unit 11 12 8 9 mass qc_end physical_unit 11 12 15 16 volume qc_end physical_unit 11 12 19 20 temperature qc_end end

[{"type":"physical unit","value":"Pressure [OF] oxygen gas [IN] Pascals"}]

[{"type":"physical unit","value":"1455989.13 Pascals"}]

[{"type":"physical unit","value":"Mass [OF] oxygen gas [=] \\pu{4.78 grams}"},{"type":"physical unit","value":"Volume [OF] oxygen gas [=] \\pu{2.5 liter}"},{"type":"physical unit","value":"Temperature [OF] oxygen gas [=] \\pu{20 ℃}"}]

<h1 class="questionTitle" itemprop="name">What pressure in Pascals will be exerted by 4.78 grams of oxygen gas in a 2.5-liter container at 20 C?</h1>

1455989.13 Pascals

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From the Ideal Gas equation..........</p> <p><mathjax>#P=(nRT)/V=((4.78*g)/(32.00*g*mol^-1)xx0.0821*(L*atm)/(K*mol)xx293*K)/(2.50*L)#</mathjax></p> <p><mathjax>#=1.44*atm-=1.44*atmxx101.3*kPa*atm^-1=145.6*kPa#</mathjax></p> <p>Note that you SIMPLY MUST KNOW that <mathjax>#H_2, O_2, N_2, F_2, Cl_2#</mathjax> are binuclear as the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>. In fact all the elemental gases (at RT) EXCEPT for the Noble Gases are bimolecular. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P~=150*kPa#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From the Ideal Gas equation..........</p> <p><mathjax>#P=(nRT)/V=((4.78*g)/(32.00*g*mol^-1)xx0.0821*(L*atm)/(K*mol)xx293*K)/(2.50*L)#</mathjax></p> <p><mathjax>#=1.44*atm-=1.44*atmxx101.3*kPa*atm^-1=145.6*kPa#</mathjax></p> <p>Note that you SIMPLY MUST KNOW that <mathjax>#H_2, O_2, N_2, F_2, Cl_2#</mathjax> are binuclear as the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>. In fact all the elemental gases (at RT) EXCEPT for the Noble Gases are bimolecular. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What pressure in Pascals will be exerted by 4.78 grams of oxygen gas in a 2.5-liter container at 20 C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="423141" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-14T10:18:17" itemprop="dateCreated"> May 14, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P~=150*kPa#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From the Ideal Gas equation..........</p> <p><mathjax>#P=(nRT)/V=((4.78*g)/(32.00*g*mol^-1)xx0.0821*(L*atm)/(K*mol)xx293*K)/(2.50*L)#</mathjax></p> <p><mathjax>#=1.44*atm-=1.44*atmxx101.3*kPa*atm^-1=145.6*kPa#</mathjax></p> <p>Note that you SIMPLY MUST KNOW that <mathjax>#H_2, O_2, N_2, F_2, Cl_2#</mathjax> are binuclear as the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>. In fact all the elemental gases (at RT) EXCEPT for the Noble Gases are bimolecular. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/423141" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyles-law-relate-to-breathing"> How does Boyle's law relate to breathing? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/in-avogadro-s-law-what-would-happen-to-v-if-n-is-increased-decreased-and-what-wo"> In Avogadro's Law what would happen to V if N is increased/decreased? 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What pressure in Pascals will be exerted by 4.78 grams of oxygen gas in a 2.5-liter container at 20 C?

a84c463a-6ddd-11ea-93e8-ccda262736ce

https://socratic.org/questions/55170a28581e2a41fb420c9c

1.04 kJ

start physical_unit 9 11 kinetic_energy kj qc_end physical_unit 9 10 13 14 velocity qc_end end

[{"type":"physical unit","value":"Kinetic energy [OF] oxygen molecules travelling [IN] kJ"}]

[{"type":"physical unit","value":"1.04 kJ"}]

[{"type":"physical unit","value":"Mole [OF] oxygen molecules [=] \\pu{1 mole}"},{"type":"physical unit","value":"Speed [OF] oxygen molecules [=] \\pu{255 m/s}"}]

<h1 class="questionTitle" itemprop="name">What is the kinetic energy of a mole of oxygen molecules travelling at 255 m/s?</h1>

1.04 kJ

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The mass of 1 oxygen molecule is</p> <p><mathjax>#1 cancel("O₂ molecule") × (32.00 cancel("u"))/(1 cancel("O₂ molecule")) × (1.661 × 10^"-27"color(white)(l) "kg")/(1 cancel("u")) = 5.315 × 10^"-26"color(white)(l) "kg"#</mathjax></p> <p>The formula for kinetic energy is</p> <p><mathjax>#KE = ½mv^2#</mathjax></p> <p>The kinetic energy of 1 molecule is</p> <p><mathjax>#KE = ½ × 5.315 × 10^"-26"color(white)(l) "kg" × ("255 m·s"^"-1")^2 = 1.728 × 10^"-21" cancel("kg·m⁻²s⁻²") × "1 J"/(1 cancel("kg·m⁻²s⁻²")) = 1.728 × 10^-21color(white)(l) "J"#</mathjax></p> <p>For 1 mole of O₂ molecules, the kinetic energy is</p> <p><mathjax>#6.022 × 10^23 cancel("molecules") × (1.728 × 10^"-21"color(white)(l) "J")/(1 cancel("molecule")) = "1041 J" = "1.041 kJ"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The kinetic energy is 1.041 kJ.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The mass of 1 oxygen molecule is</p> <p><mathjax>#1 cancel("O₂ molecule") × (32.00 cancel("u"))/(1 cancel("O₂ molecule")) × (1.661 × 10^"-27"color(white)(l) "kg")/(1 cancel("u")) = 5.315 × 10^"-26"color(white)(l) "kg"#</mathjax></p> <p>The formula for kinetic energy is</p> <p><mathjax>#KE = ½mv^2#</mathjax></p> <p>The kinetic energy of 1 molecule is</p> <p><mathjax>#KE = ½ × 5.315 × 10^"-26"color(white)(l) "kg" × ("255 m·s"^"-1")^2 = 1.728 × 10^"-21" cancel("kg·m⁻²s⁻²") × "1 J"/(1 cancel("kg·m⁻²s⁻²")) = 1.728 × 10^-21color(white)(l) "J"#</mathjax></p> <p>For 1 mole of O₂ molecules, the kinetic energy is</p> <p><mathjax>#6.022 × 10^23 cancel("molecules") × (1.728 × 10^"-21"color(white)(l) "J")/(1 cancel("molecule")) = "1041 J" = "1.041 kJ"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the kinetic energy of a mole of oxygen molecules travelling at 255 m/s?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/kinetic-theory-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Kinetic Theory of Gases</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="134258" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-03-28T20:49:39" itemprop="dateCreated"> Mar 28, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The kinetic energy is 1.041 kJ.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The mass of 1 oxygen molecule is</p> <p><mathjax>#1 cancel("O₂ molecule") × (32.00 cancel("u"))/(1 cancel("O₂ molecule")) × (1.661 × 10^"-27"color(white)(l) "kg")/(1 cancel("u")) = 5.315 × 10^"-26"color(white)(l) "kg"#</mathjax></p> <p>The formula for kinetic energy is</p> <p><mathjax>#KE = ½mv^2#</mathjax></p> <p>The kinetic energy of 1 molecule is</p> <p><mathjax>#KE = ½ × 5.315 × 10^"-26"color(white)(l) "kg" × ("255 m·s"^"-1")^2 = 1.728 × 10^"-21" cancel("kg·m⁻²s⁻²") × "1 J"/(1 cancel("kg·m⁻²s⁻²")) = 1.728 × 10^-21color(white)(l) "J"#</mathjax></p> <p>For 1 mole of O₂ molecules, the kinetic energy is</p> <p><mathjax>#6.022 × 10^23 cancel("molecules") × (1.728 × 10^"-21"color(white)(l) "J")/(1 cancel("molecule")) = "1041 J" = "1.041 kJ"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/134258" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-kinetic-molecular-theory-explain-gas-laws"> How does kinetic molecular theory explain gas laws? 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What is the kinetic energy of a mole of oxygen molecules travelling at 255 m/s?

a8d5114a-6ddd-11ea-b624-ccda262736ce

https://socratic.org/questions/the-decomposition-of-h-2o-2-produces-water-and-oxygen-gas-releasing-197-kj-per-o

4629.5 kJ

start physical_unit 3 3 heat_energy kj qc_end physical_unit 3 3 10 11 heat_energy qc_end physical_unit 3 3 13 14 mole qc_end physical_unit 3 3 26 27 mass qc_end substance 5 5 qc_end substance 7 8 qc_end end

[{"type":"physical unit","value":"Released energy2 [OF] H2O2 [IN] kJ"}]

[{"type":"physical unit","value":"4629.5 kJ"}]

[{"type":"physical unit","value":"Released energy1 [OF] H2O2 [=] \\pu{197 kJ}"},{"type":"physical unit","value":"Mole [OF] H2O2 [=] \\pu{1 mole}"},{"type":"physical unit","value":"Mass [OF] H2O2 [=] \\pu{798 grams}"},{"type":"substance name","value":"Water"},{"type":"substance name","value":"Oxygen gas"}]

<h1 class="questionTitle" itemprop="name">The decomposition of #H_2O_2# produces water and oxygen gas, releasing 197 kJ per one mole of #H_2O_2#. How much energy is released if we start with 798 grams of #H_2O_2#?</h1>

4629.5 kJ

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The amount of heat (<mathjax>#q#</mathjax>) released from decomposing <mathjax>#798g#</mathjax> of <mathjax>#H_2O_2#</mathjax> could be found by:</p> <p><mathjax>#q=DeltaHxxn#</mathjax> where, <mathjax>#DeltaH#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of the reaction and <mathjax>#n#</mathjax> is the number of mole of <mathjax>#H_2O_2#</mathjax>.</p> <p>Note that <mathjax>#DeltaH=197kJ*mol^(-1)#</mathjax></p> <p>To find <mathjax>#n#</mathjax>, we can simply use: <mathjax>#n=m/(MM)#</mathjax> where, <mathjax>#m=798g#</mathjax> is the given mass and <mathjax>#MM=34g*mol^(-1)#</mathjax> is the molar mass of <mathjax>#H_2O_2#</mathjax>.</p> <p><mathjax>#n=m/(MM)=(798cancel(g))/(34cancel(g)*mol^(-1))=23.5molH_2O_2#</mathjax></p> <p>Thus, <mathjax>#q=DeltaHxxn=197(kJ)/(cancel(mol))xx23.5cancel(mol)=4629.5kJ#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#q=4629.5kJ#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The amount of heat (<mathjax>#q#</mathjax>) released from decomposing <mathjax>#798g#</mathjax> of <mathjax>#H_2O_2#</mathjax> could be found by:</p> <p><mathjax>#q=DeltaHxxn#</mathjax> where, <mathjax>#DeltaH#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of the reaction and <mathjax>#n#</mathjax> is the number of mole of <mathjax>#H_2O_2#</mathjax>.</p> <p>Note that <mathjax>#DeltaH=197kJ*mol^(-1)#</mathjax></p> <p>To find <mathjax>#n#</mathjax>, we can simply use: <mathjax>#n=m/(MM)#</mathjax> where, <mathjax>#m=798g#</mathjax> is the given mass and <mathjax>#MM=34g*mol^(-1)#</mathjax> is the molar mass of <mathjax>#H_2O_2#</mathjax>.</p> <p><mathjax>#n=m/(MM)=(798cancel(g))/(34cancel(g)*mol^(-1))=23.5molH_2O_2#</mathjax></p> <p>Thus, <mathjax>#q=DeltaHxxn=197(kJ)/(cancel(mol))xx23.5cancel(mol)=4629.5kJ#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">The decomposition of #H_2O_2# produces water and oxygen gas, releasing 197 kJ per one mole of #H_2O_2#. How much energy is released if we start with 798 grams of #H_2O_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/thermochemistry-with-equation-stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry with Equation Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="269187" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-24T12:38:49" itemprop="dateCreated"> May 24, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#q=4629.5kJ#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The amount of heat (<mathjax>#q#</mathjax>) released from decomposing <mathjax>#798g#</mathjax> of <mathjax>#H_2O_2#</mathjax> could be found by:</p> <p><mathjax>#q=DeltaHxxn#</mathjax> where, <mathjax>#DeltaH#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of the reaction and <mathjax>#n#</mathjax> is the number of mole of <mathjax>#H_2O_2#</mathjax>.</p> <p>Note that <mathjax>#DeltaH=197kJ*mol^(-1)#</mathjax></p> <p>To find <mathjax>#n#</mathjax>, we can simply use: <mathjax>#n=m/(MM)#</mathjax> where, <mathjax>#m=798g#</mathjax> is the given mass and <mathjax>#MM=34g*mol^(-1)#</mathjax> is the molar mass of <mathjax>#H_2O_2#</mathjax>.</p> <p><mathjax>#n=m/(MM)=(798cancel(g))/(34cancel(g)*mol^(-1))=23.5molH_2O_2#</mathjax></p> <p>Thus, <mathjax>#q=DeltaHxxn=197(kJ)/(cancel(mol))xx23.5cancel(mol)=4629.5kJ#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/269187" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-someone-explain-how-to-do-this-consider-the-following-equation-2zns-s-3o2-g-"> Can someone explain how to do this? 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The decomposition of #H_2O_2# produces water and oxygen gas, releasing 197 kJ per one mole of #H_2O_2#. How much energy is released if we start with 798 grams of #H_2O_2#?

aa0d9a0d-6ddd-11ea-9250-ccda262736ce

https://socratic.org/questions/what-is-the-steric-number-of-the-central-atom-in-carbon-disulfide

2

start physical_unit 6 8 steric_number none qc_end substance 10 11 qc_end end

[{"type":"physical unit","value":"Steric number [OF] the central atom"}]

[{"type":"physical unit","value":"2"}]

[{"type":"substance name","value":"Carbon disulfide"}]

<h1 class="questionTitle" itemprop="name">What is the steric number of the central atom in carbon disulfide? </h1>

2

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="https://en.wikipedia.org/wiki/Steric_number" rel="nofollow">steric number</a> is the number of atoms attached to the central atom PLUS the number of lone pairs the central atom bears.</p> <p>And given, <mathjax>#S=C=S#</mathjax>, in which the carbon atom has no lone pairs, the steric number is 2. The parameter is sometimes useful for <mathjax>#"VESPER"#</mathjax> determinations in which the number of electron pairs about the central atom, <a href="https://socratic.org/chemistry/bonding-basics/bonding">bonding</a> AND non-bonding, determines <a href="https://socratic.org/chemistry/molecular-orbital-theory/molecular-geometry-with-molecular-orbital-theory">molecular geometry</a>. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The steric number of the central atom in <mathjax>#CS_2#</mathjax> is <mathjax>#"2"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="https://en.wikipedia.org/wiki/Steric_number" rel="nofollow">steric number</a> is the number of atoms attached to the central atom PLUS the number of lone pairs the central atom bears.</p> <p>And given, <mathjax>#S=C=S#</mathjax>, in which the carbon atom has no lone pairs, the steric number is 2. The parameter is sometimes useful for <mathjax>#"VESPER"#</mathjax> determinations in which the number of electron pairs about the central atom, <a href="https://socratic.org/chemistry/bonding-basics/bonding">bonding</a> AND non-bonding, determines <a href="https://socratic.org/chemistry/molecular-orbital-theory/molecular-geometry-with-molecular-orbital-theory">molecular geometry</a>. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the steric number of the central atom in carbon disulfide? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#covalent-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Covalent Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/covalent-bonds-and-formulas/the-geometrical-arrangement-of-electrons-and-molecular-shape-vsepr" itemprop="url"> <span class="breadcrumb" itemprop="title">VSEPR</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="366169" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-18T16:46:36" itemprop="dateCreated"> Jan 18, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The steric number of the central atom in <mathjax>#CS_2#</mathjax> is <mathjax>#"2"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="https://en.wikipedia.org/wiki/Steric_number" rel="nofollow">steric number</a> is the number of atoms attached to the central atom PLUS the number of lone pairs the central atom bears.</p> <p>And given, <mathjax>#S=C=S#</mathjax>, in which the carbon atom has no lone pairs, the steric number is 2. The parameter is sometimes useful for <mathjax>#"VESPER"#</mathjax> determinations in which the number of electron pairs about the central atom, <a href="https://socratic.org/chemistry/bonding-basics/bonding">bonding</a> AND non-bonding, determines <a href="https://socratic.org/chemistry/molecular-orbital-theory/molecular-geometry-with-molecular-orbital-theory">molecular geometry</a>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/366169" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-draw-vsepr-diagrams"> How do you draw VSEPR diagrams? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/for-vespr-theory-could-you-explain-why-ion-s-follow-the-exact-same-process-why-d"> For VSEPR theory, why do ions follow the exact same process? 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What is the steric number of the central atom in carbon disulfide?

a8a885b4-6ddd-11ea-a340-ccda262736ce

https://socratic.org/questions/5922590411ef6b401f956e01

2.00 M

start physical_unit 11 12 molarity mol/l qc_end physical_unit 11 12 7 8 mass qc_end physical_unit 23 23 20 21 volume qc_end end

[{"type":"physical unit","value":"Molar concentration [OF] hydrogen peroxide [IN] M"}]

[{"type":"physical unit","value":"2.00 M"}]

[{"type":"physical unit","value":"Mass [OF] hydrogen peroxide [=] \\pu{6.8 g}"},{"type":"physical unit","value":"Volume [OF] water [=] \\pu{100 mL}"}]

<h1 class="questionTitle" itemprop="name">What is the molar concentration of a #6.8*g# mass of hydrogen peroxide, that is dissolved in a volume of #100*mL# of water?</h1>

2.00 M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><img alt="My own work (Mert METİN)" src="https://useruploads.socratic.org/rDnuxnzlSuurEqJWHfOO_photo5852947402972047717.jpg"/> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>2 M</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><img alt="My own work (Mert METİN)" src="https://useruploads.socratic.org/rDnuxnzlSuurEqJWHfOO_photo5852947402972047717.jpg"/> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the molar concentration of a #6.8*g# mass of hydrogen peroxide, that is dissolved in a volume of #100*mL# of water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="429349" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mert-m"><img alt="" class="" src="https://profilepictures.socratic.org/saBhsgJSSti0HIIaFUp7_hqdefault.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mert-m"> Mert M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-25T08:14:31" itemprop="dateCreated"> May 25, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>2 M</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><img alt="My own work (Mert METİN)" src="https://useruploads.socratic.org/rDnuxnzlSuurEqJWHfOO_photo5852947402972047717.jpg"/> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/429349" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="429371" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-25T09:26:42" itemprop="dateCreated"> May 25, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[H_2O_2]~=2*mol*L^-1.........#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity"="Moles of solute"/"Volume of solution"#</mathjax></p> <p><mathjax>#=((6.8*g)/(34.01*g*mol^-1))/(100*mLxx10^-3*L*mL^-1)#</mathjax></p> <p><mathjax>#=??*mol*L^-1#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/429371" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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What is the molar concentration of a #6.8*g# mass of hydrogen peroxide, that is dissolved in a volume of #100*mL# of water?

ac32b11e-6ddd-11ea-9d6e-ccda262736ce

https://socratic.org/questions/56536c54581e2a05001b914d

0.11 M

start physical_unit 20 21 concentration mol/l qc_end physical_unit 5 7 1 2 volume qc_end physical_unit 5 7 11 12 concentration qc_end physical_unit 20 21 31 32 volume qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Concentration [OF] oxalic acid [IN] M"}]

[{"type":"physical unit","value":"0.11 M"}]

[{"type":"physical unit","value":"Volume [OF] sodium hydroxide solution [=] \\pu{40.16 mL}"},{"type":"physical unit","value":"Concentration [OF] sodium hydroxide solution [=] \\pu{0.1693 g/mol}"},{"type":"physical unit","value":"Volume [OF] oxalic acid [=] \\pu{30.00 mL}"},{"type":"other","value":"Reached an endpoint."}]

<h1 class="questionTitle" itemprop="name">A #40.16*mL# volume of sodium hydroxide solution with concentration of #0.1693*g*mol^-1# reached an endpoint with a quantity of oxalic acid. If the oxalic acid was initially dissolved in a #30.00*mL# what was the concentration of oxalic acid?</h1>

0.11 M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#HO(O=)C-C(=O)OH + 2NaOHrarr{C(=O)O}_2^(2-)Na_2^+ + 2H_2O#</mathjax></p> <p>Moles of <mathjax>#NaOH#</mathjax> for equivalence <mathjax>#=#</mathjax> <mathjax>#40.16xx10^-3Lxx0.1693#</mathjax> <mathjax>#mol*L^-1 =#</mathjax> <mathjax>#6.80xx10^-3#</mathjax> <mathjax>#mol#</mathjax>.</p> <p>Thus there were <mathjax>#3.40xx10^-3#</mathjax> <mathjax>#mol#</mathjax> oxalic acid (because each equiv acid contributes 2 equiv <mathjax>#H^+#</mathjax>). </p> <p>Since this quantity was dissolved in a <mathjax>#30.00#</mathjax> <mathjax>#mL#</mathjax> volume, concentration was <mathjax>#(3.40xx10^-3*mol)/(30.00xx10^(-3)L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.1133#</mathjax> <mathjax>#mol*L^-1#</mathjax> in oxalic acid.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Concentration of oxalic acid <mathjax>#=#</mathjax> <mathjax>#0.1133#</mathjax> <mathjax>#mol*L^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#HO(O=)C-C(=O)OH + 2NaOHrarr{C(=O)O}_2^(2-)Na_2^+ + 2H_2O#</mathjax></p> <p>Moles of <mathjax>#NaOH#</mathjax> for equivalence <mathjax>#=#</mathjax> <mathjax>#40.16xx10^-3Lxx0.1693#</mathjax> <mathjax>#mol*L^-1 =#</mathjax> <mathjax>#6.80xx10^-3#</mathjax> <mathjax>#mol#</mathjax>.</p> <p>Thus there were <mathjax>#3.40xx10^-3#</mathjax> <mathjax>#mol#</mathjax> oxalic acid (because each equiv acid contributes 2 equiv <mathjax>#H^+#</mathjax>). </p> <p>Since this quantity was dissolved in a <mathjax>#30.00#</mathjax> <mathjax>#mL#</mathjax> volume, concentration was <mathjax>#(3.40xx10^-3*mol)/(30.00xx10^(-3)L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.1133#</mathjax> <mathjax>#mol*L^-1#</mathjax> in oxalic acid.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A #40.16*mL# volume of sodium hydroxide solution with concentration of #0.1693*g*mol^-1# reached an endpoint with a quantity of oxalic acid. If the oxalic acid was initially dissolved in a #30.00*mL# what was the concentration of oxalic acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/titration-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Titration Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="192336" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-23T20:41:21" itemprop="dateCreated"> Nov 23, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Concentration of oxalic acid <mathjax>#=#</mathjax> <mathjax>#0.1133#</mathjax> <mathjax>#mol*L^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#HO(O=)C-C(=O)OH + 2NaOHrarr{C(=O)O}_2^(2-)Na_2^+ + 2H_2O#</mathjax></p> <p>Moles of <mathjax>#NaOH#</mathjax> for equivalence <mathjax>#=#</mathjax> <mathjax>#40.16xx10^-3Lxx0.1693#</mathjax> <mathjax>#mol*L^-1 =#</mathjax> <mathjax>#6.80xx10^-3#</mathjax> <mathjax>#mol#</mathjax>.</p> <p>Thus there were <mathjax>#3.40xx10^-3#</mathjax> <mathjax>#mol#</mathjax> oxalic acid (because each equiv acid contributes 2 equiv <mathjax>#H^+#</mathjax>). </p> <p>Since this quantity was dissolved in a <mathjax>#30.00#</mathjax> <mathjax>#mL#</mathjax> volume, concentration was <mathjax>#(3.40xx10^-3*mol)/(30.00xx10^(-3)L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.1133#</mathjax> <mathjax>#mol*L^-1#</mathjax> in oxalic acid.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/192336" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-acid-base-titration-calculations"> How do you do acid base titration calculations? 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A #40.16*mL# volume of sodium hydroxide solution with concentration of #0.1693*g*mol^-1# reached an endpoint with a quantity of oxalic acid. If the oxalic acid was initially dissolved in a #30.00*mL# what was the concentration of oxalic acid?

abde373b-6ddd-11ea-8c3e-ccda262736ce

https://socratic.org/questions/58314c567c014916d5e31cef

+91.3 kJ/mol

start physical_unit 4 4 deltah^{0}_{f} kj/mol qc_end chemical_equation 4 4 qc_end end

[{"type":"physical unit","value":"deltaH^{0}_{f} [OF] NO(g) [IN] kJ/mol"}]

[{"type":"physical unit","value":"+91.3 kJ/mol"}]

[{"type":"chemical equation","value":"NO(g)"}]

<h1 class="questionTitle" itemprop="name">What is #DeltaH_f^@# for #NO(g)#?</h1>

+91.3 kJ/mol

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To account for the positive value, consider what <mathjax>#DeltaH_f""^@#</mathjax> represents: </p> <p>" <em>the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> associated with the formation of 1 mole of substance from its constituent elements in their standard states under given conditions.......</em> "</p> <p>So here, <mathjax>#DeltaH_f""^@#</mathjax> is the enthalpy associated with the following reaction:</p> <p><mathjax>#1/2N_2(g) + 1/2O_2(g) rarr NO(g)#</mathjax> <mathjax>#;DeltaH""^@""_"rxn"=91.3*kJ*mol^-1#</mathjax></p> <p>In order to make the <mathjax>#N=O#</mathjax> bond, we have to break exceptionally strong <mathjax>#N-=N#</mathjax> and <mathjax>#O=O#</mathjax> bonds. The energy shortfall is anticipated.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>For <mathjax>#"NO"#</mathjax>, <mathjax>#DeltaH_f""^@=+91.3*kJ*mol^-1#</mathjax>; and thus here <mathjax>#DeltaH_f""^@-=DeltaH_"rxn"^@#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To account for the positive value, consider what <mathjax>#DeltaH_f""^@#</mathjax> represents: </p> <p>" <em>the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> associated with the formation of 1 mole of substance from its constituent elements in their standard states under given conditions.......</em> "</p> <p>So here, <mathjax>#DeltaH_f""^@#</mathjax> is the enthalpy associated with the following reaction:</p> <p><mathjax>#1/2N_2(g) + 1/2O_2(g) rarr NO(g)#</mathjax> <mathjax>#;DeltaH""^@""_"rxn"=91.3*kJ*mol^-1#</mathjax></p> <p>In order to make the <mathjax>#N=O#</mathjax> bond, we have to break exceptionally strong <mathjax>#N-=N#</mathjax> and <mathjax>#O=O#</mathjax> bonds. The energy shortfall is anticipated.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is #DeltaH_f^@# for #NO(g)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/enthalpy" itemprop="url"> <span class="breadcrumb" itemprop="title">Enthalpy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="339108" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-20T08:27:35" itemprop="dateCreated"> Nov 20, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>For <mathjax>#"NO"#</mathjax>, <mathjax>#DeltaH_f""^@=+91.3*kJ*mol^-1#</mathjax>; and thus here <mathjax>#DeltaH_f""^@-=DeltaH_"rxn"^@#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To account for the positive value, consider what <mathjax>#DeltaH_f""^@#</mathjax> represents: </p> <p>" <em>the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> associated with the formation of 1 mole of substance from its constituent elements in their standard states under given conditions.......</em> "</p> <p>So here, <mathjax>#DeltaH_f""^@#</mathjax> is the enthalpy associated with the following reaction:</p> <p><mathjax>#1/2N_2(g) + 1/2O_2(g) rarr NO(g)#</mathjax> <mathjax>#;DeltaH""^@""_"rxn"=91.3*kJ*mol^-1#</mathjax></p> <p>In order to make the <mathjax>#N=O#</mathjax> bond, we have to break exceptionally strong <mathjax>#N-=N#</mathjax> and <mathjax>#O=O#</mathjax> bonds. The energy shortfall is anticipated.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/339108" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-enthalpy-changes-expressed-in-chemical-equations"> How are enthalpy changes expressed in chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-enthalpy-change-be-determined-for-an-aqueous-solution"> How can enthalpy change be determined for an aqueous solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-change-with-pressure"> How does enthalpy change with pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-standard-molar-enthalpy-formation"> How do you calculate standard molar enthalpy of formation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-enthalpy-of-formation-of-oxygen-zero"> Why is the enthalpy of formation of oxygen zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function-2"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-enthalpy-cannot-be-measured-directly"> Why can enthalpy not be measured directly? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-pressure-affect-enthalpy"> How does pressure affect enthalpy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-relate-to-internal-energy"> How does enthalpy relate to internal energy? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/enthalpy"> See all questions in Enthalpy </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1892 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is #DeltaH_f^@# for #NO(g)#?

ace3f783-6ddd-11ea-afaa-ccda262736ce

https://socratic.org/questions/how-do-you-balance-rbno-3-bef-2-be-no-3-2-rbf

2 RbNO3 + BeF2 -> Be(NO3)2 + 2 RbF

start chemical_equation qc_end chemical_equation 4 10 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"2 RbNO3 + BeF2 -> Be(NO3)2 + 2 RbF"}]

[{"type":"chemical equation","value":"RbNO3 + BeF2 -> Be(NO3)2 + RbF"}]

<h1 class="questionTitle" itemprop="name">How do you balance #RbNO_3 + BeF_2 -&gt; Be(NO_3)_2 + RbF#?</h1>

2 RbNO3 + BeF2 -> Be(NO3)2 + 2 RbF

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The most important thing to notice here is that <strong>no reaction takes place</strong> when these two <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> are mixed. </p> <p>The reason for why that happens lies with the fact that <strong>both</strong> products are <strong>soluble</strong> in aqueous solution, which implies that they will exist as dissociated ions. </p> <p><em>Rubidium nitrate</em>, <mathjax>#"RbNO"_3#</mathjax>, and <em>beryllium fluoride</em>, <mathjax>#"BeF"_2#</mathjax>, are soluble <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> that dissociate completely in aqueous solution to produce </p> <blockquote> <p><mathjax>#"RbNO"_text(3(aq]) -&gt; "Rb"_text((aq])^(+) + "NO"_text(3(aq])^(-)#</mathjax></p> </blockquote> <p>and </p> <blockquote> <p><mathjax>#"BeF"_text(2(aq]) -&gt; "Be"_text((aq])^(2+) + 2"F"_text((aq])^(-)#</mathjax></p> </blockquote> <p>In order for a <a href="https://socratic.org/chemistry/chemical-reactions/double-replacement-reactions">double replacement reaction</a> to take place, you need one of the products to be <strong>insoluble</strong>, i.e. <em>precipitate</em> out of solution. In this case, all the four compounds will exist as ions in solution, which means that the correct answer to this question is </p> <blockquote> <p><mathjax>#"RbNO"_text(3(aq]) + "BeF"_text(2(aq]) -&gt; color(red)("N. R.")#</mathjax></p> </blockquote> <p>Here <mathjax>#"N"."R".#</mathjax> means "no reaction". </p> <p>Now, <strong>assuming</strong> that these two compounds would actually react to form an insoluble compound, you can balance the equation by looking at <strong>ions</strong>, rather than at <strong>individual atoms</strong>. </p> <p>Notice that you have a <mathjax>#(2+)#</mathjax> charge on the beryllium cation, but only a <mathjax>#(1-)#</mathjax> charge on the nitrate anion, <mathjax>#"NO"_3^(-)#</mathjax>. This means that you will need <strong>two</strong> nitrate anions to balance the positive charge of the beryllium cation. </p> <p>To get two nitrate anions for every one beryllium cation, you need to multiply <em>rubidium nitrate</em> by <mathjax>#2#</mathjax>. </p> <p>This will of course get you <strong>two</strong> rubidium cations as well. Notice that you have <strong>two</strong> fluoride anions, <mathjax>#"F"^(-)#</mathjax>, coming from beryllium fluoride, so you need to multiply rubidium fluoride by <mathjax>#2#</mathjax> to make sure that both of the ions are balanced. </p> <p>This would get you </p> <blockquote> <p><mathjax>#2"RbNO"_text(3(aq]) + "BeF"_text(2(aq]) -&gt; "Be"("NO"_3)_text(2(aq]) + 2"RbF"_text((aq])#</mathjax></p> </blockquote> <p>Remember, this reaction <strong>does not</strong> take place, since all compounds are **soluble in aqueous solution. </p> <blockquote> <p><mathjax>#color(red)(cancel(color(black)(2"RbNO"_text(3(aq]) + "BeF"_text(2(aq]) -&gt; "Be"("NO"_3)_text(2(aq]) + 2"RbF"_text((aq]))))#</mathjax></p> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"RbNO"_text(3(aq]) + "BeF"_text(2(aq]) -&gt; color(red)("N. R.")#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The most important thing to notice here is that <strong>no reaction takes place</strong> when these two <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> are mixed. </p> <p>The reason for why that happens lies with the fact that <strong>both</strong> products are <strong>soluble</strong> in aqueous solution, which implies that they will exist as dissociated ions. </p> <p><em>Rubidium nitrate</em>, <mathjax>#"RbNO"_3#</mathjax>, and <em>beryllium fluoride</em>, <mathjax>#"BeF"_2#</mathjax>, are soluble <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> that dissociate completely in aqueous solution to produce </p> <blockquote> <p><mathjax>#"RbNO"_text(3(aq]) -&gt; "Rb"_text((aq])^(+) + "NO"_text(3(aq])^(-)#</mathjax></p> </blockquote> <p>and </p> <blockquote> <p><mathjax>#"BeF"_text(2(aq]) -&gt; "Be"_text((aq])^(2+) + 2"F"_text((aq])^(-)#</mathjax></p> </blockquote> <p>In order for a <a href="https://socratic.org/chemistry/chemical-reactions/double-replacement-reactions">double replacement reaction</a> to take place, you need one of the products to be <strong>insoluble</strong>, i.e. <em>precipitate</em> out of solution. In this case, all the four compounds will exist as ions in solution, which means that the correct answer to this question is </p> <blockquote> <p><mathjax>#"RbNO"_text(3(aq]) + "BeF"_text(2(aq]) -&gt; color(red)("N. R.")#</mathjax></p> </blockquote> <p>Here <mathjax>#"N"."R".#</mathjax> means "no reaction". </p> <p>Now, <strong>assuming</strong> that these two compounds would actually react to form an insoluble compound, you can balance the equation by looking at <strong>ions</strong>, rather than at <strong>individual atoms</strong>. </p> <p>Notice that you have a <mathjax>#(2+)#</mathjax> charge on the beryllium cation, but only a <mathjax>#(1-)#</mathjax> charge on the nitrate anion, <mathjax>#"NO"_3^(-)#</mathjax>. This means that you will need <strong>two</strong> nitrate anions to balance the positive charge of the beryllium cation. </p> <p>To get two nitrate anions for every one beryllium cation, you need to multiply <em>rubidium nitrate</em> by <mathjax>#2#</mathjax>. </p> <p>This will of course get you <strong>two</strong> rubidium cations as well. Notice that you have <strong>two</strong> fluoride anions, <mathjax>#"F"^(-)#</mathjax>, coming from beryllium fluoride, so you need to multiply rubidium fluoride by <mathjax>#2#</mathjax> to make sure that both of the ions are balanced. </p> <p>This would get you </p> <blockquote> <p><mathjax>#2"RbNO"_text(3(aq]) + "BeF"_text(2(aq]) -&gt; "Be"("NO"_3)_text(2(aq]) + 2"RbF"_text((aq])#</mathjax></p> </blockquote> <p>Remember, this reaction <strong>does not</strong> take place, since all compounds are **soluble in aqueous solution. </p> <blockquote> <p><mathjax>#color(red)(cancel(color(black)(2"RbNO"_text(3(aq]) + "BeF"_text(2(aq]) -&gt; "Be"("NO"_3)_text(2(aq]) + 2"RbF"_text((aq]))))#</mathjax></p> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you balance #RbNO_3 + BeF_2 -&gt; Be(NO_3)_2 + RbF#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="197310" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-07T12:34:12" itemprop="dateCreated"> Dec 7, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"RbNO"_text(3(aq]) + "BeF"_text(2(aq]) -&gt; color(red)("N. R.")#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The most important thing to notice here is that <strong>no reaction takes place</strong> when these two <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> are mixed. </p> <p>The reason for why that happens lies with the fact that <strong>both</strong> products are <strong>soluble</strong> in aqueous solution, which implies that they will exist as dissociated ions. </p> <p><em>Rubidium nitrate</em>, <mathjax>#"RbNO"_3#</mathjax>, and <em>beryllium fluoride</em>, <mathjax>#"BeF"_2#</mathjax>, are soluble <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> that dissociate completely in aqueous solution to produce </p> <blockquote> <p><mathjax>#"RbNO"_text(3(aq]) -&gt; "Rb"_text((aq])^(+) + "NO"_text(3(aq])^(-)#</mathjax></p> </blockquote> <p>and </p> <blockquote> <p><mathjax>#"BeF"_text(2(aq]) -&gt; "Be"_text((aq])^(2+) + 2"F"_text((aq])^(-)#</mathjax></p> </blockquote> <p>In order for a <a href="https://socratic.org/chemistry/chemical-reactions/double-replacement-reactions">double replacement reaction</a> to take place, you need one of the products to be <strong>insoluble</strong>, i.e. <em>precipitate</em> out of solution. In this case, all the four compounds will exist as ions in solution, which means that the correct answer to this question is </p> <blockquote> <p><mathjax>#"RbNO"_text(3(aq]) + "BeF"_text(2(aq]) -&gt; color(red)("N. R.")#</mathjax></p> </blockquote> <p>Here <mathjax>#"N"."R".#</mathjax> means "no reaction". </p> <p>Now, <strong>assuming</strong> that these two compounds would actually react to form an insoluble compound, you can balance the equation by looking at <strong>ions</strong>, rather than at <strong>individual atoms</strong>. </p> <p>Notice that you have a <mathjax>#(2+)#</mathjax> charge on the beryllium cation, but only a <mathjax>#(1-)#</mathjax> charge on the nitrate anion, <mathjax>#"NO"_3^(-)#</mathjax>. This means that you will need <strong>two</strong> nitrate anions to balance the positive charge of the beryllium cation. </p> <p>To get two nitrate anions for every one beryllium cation, you need to multiply <em>rubidium nitrate</em> by <mathjax>#2#</mathjax>. </p> <p>This will of course get you <strong>two</strong> rubidium cations as well. Notice that you have <strong>two</strong> fluoride anions, <mathjax>#"F"^(-)#</mathjax>, coming from beryllium fluoride, so you need to multiply rubidium fluoride by <mathjax>#2#</mathjax> to make sure that both of the ions are balanced. </p> <p>This would get you </p> <blockquote> <p><mathjax>#2"RbNO"_text(3(aq]) + "BeF"_text(2(aq]) -&gt; "Be"("NO"_3)_text(2(aq]) + 2"RbF"_text((aq])#</mathjax></p> </blockquote> <p>Remember, this reaction <strong>does not</strong> take place, since all compounds are **soluble in aqueous solution. </p> <blockquote> <p><mathjax>#color(red)(cancel(color(black)(2"RbNO"_text(3(aq]) + "BeF"_text(2(aq]) -&gt; "Be"("NO"_3)_text(2(aq]) + 2"RbF"_text((aq]))))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/197310" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------&gt; H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -&gt; Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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How do you balance #RbNO_3 + BeF_2 -&gt; Be(NO_3)_2 + RbF#?

abecd240-6ddd-11ea-a328-ccda262736ce

https://socratic.org/questions/what-is-k-if-deltag-18-0-kj-for-a-reaction-at-25-degrees-c

6.97 × 10^(-4)

start physical_unit 10 10 equilibrium_constant_k none qc_end physical_unit 10 10 6 7 deltag^0 qc_end physical_unit 10 10 12 14 temperature qc_end end

[{"type":"physical unit","value":"K [OF] the reaction"}]

[{"type":"physical unit","value":"6.97 × 10^(-4)"}]

[{"type":"physical unit","value":"DeltaG^0 [OF] the reaction [=] \\pu{-18.0 kJ}"},{"type":"physical unit","value":"Temperature [OF] the reaction [=] \\pu{25 degrees C}"}]

<h1 class="questionTitle" itemprop="name">What is K if #DeltaG^@# = -18.0 kJ for a reaction at 25 degrees C?</h1>

6.97 × 10^(-4)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#sf(DeltaG^@=-RTlnK)#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(lnK=-(DeltaG^@)/(RT))#</mathjax></p> <p><mathjax>#sf(lnK=-(18xx10^3)/(8.31xx298)=-7.268)#</mathjax></p> <p><mathjax>#sf(K=6.97xx10^(-4))#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#sf(K=6.97xx10^(-4))#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#sf(DeltaG^@=-RTlnK)#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(lnK=-(DeltaG^@)/(RT))#</mathjax></p> <p><mathjax>#sf(lnK=-(18xx10^3)/(8.31xx298)=-7.268)#</mathjax></p> <p><mathjax>#sf(K=6.97xx10^(-4))#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is K if #DeltaG^@# = -18.0 kJ for a reaction at 25 degrees C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/gibbs-free-energy" itemprop="url"> <span class="breadcrumb" itemprop="title">Gibbs Free Energy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="407638" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michael-2"><img alt="" class="" src="https://lh3.googleusercontent.com/-gCv6FQRhls0/AAAAAAAAAAI/AAAAAAAAAAA/AAnnY7oOJS05Ylqn3KuDSW0LfnbOk7FezQ/mo/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michael-2"> Michael </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-16T19:16:54" itemprop="dateCreated"> Apr 16, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#sf(K=6.97xx10^(-4))#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#sf(DeltaG^@=-RTlnK)#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(lnK=-(DeltaG^@)/(RT))#</mathjax></p> <p><mathjax>#sf(lnK=-(18xx10^3)/(8.31xx298)=-7.268)#</mathjax></p> <p><mathjax>#sf(K=6.97xx10^(-4))#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/407638" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-gibbs-free-energy-be-negative"> Can gibbs free energy be negative? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gibbs-free-energy-have-to-be-negative"> Why does Gibbs free energy have to be negative? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-gibbs-free-energy-affected-by-a-catalyst"> Is Gibbs free energy affected by a catalyst? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-gibbs-free-energy-at-different-temperatures"> How can I calculate Gibbs free energy at different temperatures? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-gibbs-free-energy-measured"> How is Gibbs free energy measured? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/gibbs-free-energy"> See all questions in Gibbs Free Energy </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4896 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is K if #DeltaG^@# = -18.0 kJ for a reaction at 25 degrees C?

ab0f4b0c-6ddd-11ea-b6ce-ccda262736ce

https://socratic.org/questions/what-is-the-ratio-of-the-moles-of-conjugate-base-to-the-moles-of-acid-if-the-ph-

1.38

start physical_unit 5 14 ratio none qc_end end

[{"type":"physical unit","value":"Ratio [OF] the moles of conjugate base to the moles of acid"}]

[{"type":"physical unit","value":"1.38"}]

[{"type":"physical unit","value":"pH [OF] solution [=] \\pu{5.29}"},{"type":"physical unit","value":"pKa [OF] solution [=] \\pu{5.150}"}]

<h1 class="questionTitle" itemprop="name">What is the ratio of the moles of conjugate base to the moles of acid if the pH is 5.29 and the pKa is 5.150? </h1>

1.38

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=pK_a + log_10([[A^-]]/[[HA]])#</mathjax></p> <p>i.e. <mathjax>#5.29=5.150 + log_10([[A^-]]/[[HA]])#</mathjax></p> <p>Thus <mathjax>#log_10([[A^-]]/[[HA]])=0.14#</mathjax>.</p> <p><mathjax>#[[A^-]]/[[HA]]=10^(0.14)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[[A^-]]/[[HA]]=10^(0.14)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=pK_a + log_10([[A^-]]/[[HA]])#</mathjax></p> <p>i.e. <mathjax>#5.29=5.150 + log_10([[A^-]]/[[HA]])#</mathjax></p> <p>Thus <mathjax>#log_10([[A^-]]/[[HA]])=0.14#</mathjax>.</p> <p><mathjax>#[[A^-]]/[[HA]]=10^(0.14)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the ratio of the moles of conjugate base to the moles of acid if the pH is 5.29 and the pKa is 5.150? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="331856" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-05T16:05:48" itemprop="dateCreated"> Nov 5, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[[A^-]]/[[HA]]=10^(0.14)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=pK_a + log_10([[A^-]]/[[HA]])#</mathjax></p> <p>i.e. <mathjax>#5.29=5.150 + log_10([[A^-]]/[[HA]])#</mathjax></p> <p>Thus <mathjax>#log_10([[A^-]]/[[HA]])=0.14#</mathjax>.</p> <p><mathjax>#[[A^-]]/[[HA]]=10^(0.14)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/331856" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? 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What is the ratio of the moles of conjugate base to the moles of acid if the pH is 5.29 and the pKa is 5.150?

aba985b4-6ddd-11ea-97e4-ccda262736ce

https://socratic.org/questions/how-many-grams-of-solute-are-needed-to-prepare-a-3-50-mass-mass-solution-that-ha

8.75 grams

start physical_unit 4 4 mass g qc_end physical_unit 12 12 10 10 mass_percent qc_end physical_unit 12 12 19 22 mass qc_end end

[{"type":"physical unit","value":"Mass [OF] solute [IN] grams"}]

[{"type":"physical unit","value":"8.75 grams"}]

[{"type":"physical unit","value":"Mass/mass [OF] solute in solution [=] \\pu{3.50%}"},{"type":"physical unit","value":"Mass [OF] solution [=] \\pu{2.5 × 10^2 grams}"}]

<h1 class="questionTitle" itemprop="name">How many grams of solute are needed to prepare a 3.50% mass/mass solution that has a solution mass of #2.5 * 10^2# grams?</h1>

8.75 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If the mass of the <em>solution</em> is <mathjax>#2.5xx10^2#</mathjax> <mathjax>#"g"#</mathjax>, and the percentage mass of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> is <mathjax>#3.50%#</mathjax>, then the mass of the solute is</p> <p><mathjax>#(2.5xx10^2color(white)(l)"g solution")(0.0350) = color(red)(8.75#</mathjax> <mathjax>#color(red)("g solute"#</mathjax></p> <p>You would therefore need <mathjax>#color(red)(8.75#</mathjax> <mathjax>#sfcolor(red)("grams of the solute"#</mathjax> to prepare the solution. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#8.75#</mathjax> <mathjax>#"g solute"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If the mass of the <em>solution</em> is <mathjax>#2.5xx10^2#</mathjax> <mathjax>#"g"#</mathjax>, and the percentage mass of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> is <mathjax>#3.50%#</mathjax>, then the mass of the solute is</p> <p><mathjax>#(2.5xx10^2color(white)(l)"g solution")(0.0350) = color(red)(8.75#</mathjax> <mathjax>#color(red)("g solute"#</mathjax></p> <p>You would therefore need <mathjax>#color(red)(8.75#</mathjax> <mathjax>#sfcolor(red)("grams of the solute"#</mathjax> to prepare the solution. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many grams of solute are needed to prepare a 3.50% mass/mass solution that has a solution mass of #2.5 * 10^2# grams?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="443704" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-24T00:26:46" itemprop="dateCreated"> Jun 24, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#8.75#</mathjax> <mathjax>#"g solute"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If the mass of the <em>solution</em> is <mathjax>#2.5xx10^2#</mathjax> <mathjax>#"g"#</mathjax>, and the percentage mass of the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> is <mathjax>#3.50%#</mathjax>, then the mass of the solute is</p> <p><mathjax>#(2.5xx10^2color(white)(l)"g solution")(0.0350) = color(red)(8.75#</mathjax> <mathjax>#color(red)("g solute"#</mathjax></p> <p>You would therefore need <mathjax>#color(red)(8.75#</mathjax> <mathjax>#sfcolor(red)("grams of the solute"#</mathjax> to prepare the solution. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/443704" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? 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How many grams of solute are needed to prepare a 3.50% mass/mass solution that has a solution mass of #2.5 * 10^2# grams?

a9999b98-6ddd-11ea-b501-ccda262736ce

https://socratic.org/questions/2-4-moles-of-lead-ii-hydroxide-is-how-many-grams

578.90 grams

start physical_unit 3 5 mass g qc_end physical_unit 3 5 0 1 mole qc_end end

[{"type":"physical unit","value":"Mass [OF] lead (II) hydroxide [IN] grams"}]

[{"type":"physical unit","value":"578.90 grams"}]

[{"type":"physical unit","value":"Mole [OF] lead (II) hydroxide [=] \\pu{2.4 moles}"}]

<h1 class="questionTitle" itemprop="name">2.4 moles of lead (II) hydroxide is how many grams?</h1>

578.90 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molar mass of lead(II) hydroxide <mathjax>#=#</mathjax> <mathjax>#"241.21 g/mol"#</mathjax></p> <p>Use </p> <p><mathjax>#"mass" = "number of moles" xx "molar mass"#</mathjax> </p> <p>So</p> <p><mathjax>#"mass" = "2.4 mol" xx "241.21 g/mol" = "580 g"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"580 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molar mass of lead(II) hydroxide <mathjax>#=#</mathjax> <mathjax>#"241.21 g/mol"#</mathjax></p> <p>Use </p> <p><mathjax>#"mass" = "number of moles" xx "molar mass"#</mathjax> </p> <p>So</p> <p><mathjax>#"mass" = "2.4 mol" xx "241.21 g/mol" = "580 g"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">2.4 moles of lead (II) hydroxide is how many grams?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="557843" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/amanullah"><img alt="" class="" src="https://profilepictures.socratic.org/pDrkiqyrQh2RcTq4YWN7_Watermelon.png" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/amanullah"> Amanullah </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-02-25T04:59:15" itemprop="dateCreated"> Feb 25, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"580 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molar mass of lead(II) hydroxide <mathjax>#=#</mathjax> <mathjax>#"241.21 g/mol"#</mathjax></p> <p>Use </p> <p><mathjax>#"mass" = "number of moles" xx "molar mass"#</mathjax> </p> <p>So</p> <p><mathjax>#"mass" = "2.4 mol" xx "241.21 g/mol" = "580 g"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/557843" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? 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2.4 moles of lead (II) hydroxide is how many grams?

a8b22165-6ddd-11ea-9843-ccda262736ce

https://socratic.org/questions/how-many-fluorine-atoms-bond-with-calcium-to-form-calcium-fluoride

2

start physical_unit 2 3 number none qc_end substance 6 6 qc_end substance 9 10 qc_end end

[{"type":"physical unit","value":"Number [OF] fluorine atoms"}]

[{"type":"physical unit","value":"2"}]

[{"type":"substance name","value":"Calcium"},{"type":"substance name","value":"Calcium fluoride"}]

<h1 class="questionTitle" itemprop="name">How many fluorine atoms bond with calcium to form calcium fluoride? </h1>

2

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Calcium, a Group 2 metal, commonly forms a <mathjax>#Ca^(2+)#</mathjax> ion. On the other hand, fluorine, a Group 7 non-metal, commonly forms an <mathjax>#F^-#</mathjax> ion. The necessity of electrical neutrality ensures that <mathjax>#2xxF^-#</mathjax> binds to one <mathjax>#Ca^(2+)#</mathjax>.</p> <p>Note that the structure of the mineral, fluorite, affords very high physical constants as it is a very stable structure. <mathjax>#Li_2O#</mathjax> is called <mathjax>#"antfluorite"#</mathjax>. Why?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The formula of calcium fluoride is <mathjax>#CaF_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Calcium, a Group 2 metal, commonly forms a <mathjax>#Ca^(2+)#</mathjax> ion. On the other hand, fluorine, a Group 7 non-metal, commonly forms an <mathjax>#F^-#</mathjax> ion. The necessity of electrical neutrality ensures that <mathjax>#2xxF^-#</mathjax> binds to one <mathjax>#Ca^(2+)#</mathjax>.</p> <p>Note that the structure of the mineral, fluorite, affords very high physical constants as it is a very stable structure. <mathjax>#Li_2O#</mathjax> is called <mathjax>#"antfluorite"#</mathjax>. Why?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many fluorine atoms bond with calcium to form calcium fluoride? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/ionic-bond-formation" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bond Formation</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="256510" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-20T08:08:25" itemprop="dateCreated"> Apr 20, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The formula of calcium fluoride is <mathjax>#CaF_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Calcium, a Group 2 metal, commonly forms a <mathjax>#Ca^(2+)#</mathjax> ion. On the other hand, fluorine, a Group 7 non-metal, commonly forms an <mathjax>#F^-#</mathjax> ion. The necessity of electrical neutrality ensures that <mathjax>#2xxF^-#</mathjax> binds to one <mathjax>#Ca^(2+)#</mathjax>.</p> <p>Note that the structure of the mineral, fluorite, affords very high physical constants as it is a very stable structure. <mathjax>#Li_2O#</mathjax> is called <mathjax>#"antfluorite"#</mathjax>. Why?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/256510" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ionic-bonding-stronger-than-hydrogen-bonding"> Why is ionic bonding stronger than hydrogen bonding? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ionic-bonding-stronger-than-covalent"> Why is ionic bonding stronger than covalent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ionic-bonding-important"> Why is ionic bonding important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-compound-formula-of-sodium-sulfate"> What is the ionic compound formula of sodium sulfate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-compound-formula-of-ammonium-sulfate"> What is the ionic compound formula of ammonium sulfate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-compound-formula-of-magnesium-nitrate"> What is the ionic compound formula of magnesium nitrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-compound-formula-of-sodium-hydroxide"> What is the ionic compound formula of sodium hydroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-compound-formula-of-sodium-phosphate"> What is the ionic compound formula of sodium phosphate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ionic-bonds-differ-from-covalent"> How do ionic bonds differ from covalent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ionic-bonds-dissolve-in-water-1"> How do ionic bonds dissolve in water? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/ionic-bond-formation"> See all questions in Ionic Bond Formation </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6538 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many fluorine atoms bond with calcium to form calcium fluoride?

ab26a25e-6ddd-11ea-837c-ccda262736ce

https://socratic.org/questions/how-many-carbons-are-there-in-ch-3-2choh

3

start physical_unit 2 2 number none qc_end chemical_equation 6 6 qc_end end

[{"type":"physical unit","value":"Number [OF] carbons"}]

[{"type":"physical unit","value":"3"}]

[{"type":"chemical equation","value":"(CH3)2CHOH"}]

<h1 class="questionTitle" itemprop="name">How many carbons are there in #(CH_3)_2CHOH#?</h1>

3

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molecular formula of isopropanol is <mathjax>#C_3H_7OH#</mathjax>. Of butanol, it is <mathjax>#C_4H_9OH#</mathjax>; of pentanol, <mathjax>#C_5H_11OH#</mathjax>. I am simply adding a methylene group, <mathjax>#CH_2#</mathjax>, to extend the carbon chain. </p> <p>What about methyl alcohol, and ethyl alcohol?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>How many carbons in isopropanol? Well, I count 3 in the given formula.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molecular formula of isopropanol is <mathjax>#C_3H_7OH#</mathjax>. Of butanol, it is <mathjax>#C_4H_9OH#</mathjax>; of pentanol, <mathjax>#C_5H_11OH#</mathjax>. I am simply adding a methylene group, <mathjax>#CH_2#</mathjax>, to extend the carbon chain. </p> <p>What about methyl alcohol, and ethyl alcohol?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many carbons are there in #(CH_3)_2CHOH#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/determining-formula-and-molar-masses" itemprop="url"> <span class="breadcrumb" itemprop="title">Determining Formula</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="229357" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-21T17:35:28" itemprop="dateCreated"> Feb 21, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>How many carbons in isopropanol? Well, I count 3 in the given formula.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molecular formula of isopropanol is <mathjax>#C_3H_7OH#</mathjax>. Of butanol, it is <mathjax>#C_4H_9OH#</mathjax>; of pentanol, <mathjax>#C_5H_11OH#</mathjax>. I am simply adding a methylene group, <mathjax>#CH_2#</mathjax>, to extend the carbon chain. </p> <p>What about methyl alcohol, and ethyl alcohol?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/229357" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-possible-to-find-a-molecular-formula-from-molar-mass"> Is it possible to find a molecular formula from molar mass? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5368e0cc02bf34779e175781"> Question #75781 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-when-determining-formulas"> What are some common mistakes students make when determining formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-an-acid"> How can I determine the formula of an acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-chemical-formula-of-a-product"> How can I determine the chemical formula of a product? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-empirical-formula-of-a-compound"> How can I determine the empirical formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-a-hydrate"> How can I determine the formula of a hydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-empirical-formula-indicate"> What does the empirical formula indicate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-molecule-with-molecular-weight-of-180-18-g-mol-is-analyzed-and-found-to-contai"> A molecule with molecular weight of 180.18 g/mol is analyzed and found to contain 40.00% carbon,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-i-need-to-know-the-number-of-moles-of-each-element-to-determine-the-formula-o"> Do I need to know the number of moles of each element to determine the formula of the compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/determining-formula-and-molar-masses"> See all questions in Determining Formula </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3168 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many carbons are there in #(CH_3)_2CHOH#?

a83f6f20-6ddd-11ea-a5ef-ccda262736ce

https://socratic.org/questions/what-is-the-molecular-formula-of-a-compound-with-an-empirical-formula-of-c-4h-9-

C8H18

start chemical_formula qc_end physical_unit 7 7 19 20 molar_mass qc_end c_other OTHER qc_end end

[{"type":"other","value":"Chemical Formula [OF] the compound [IN] molecular"}]

[{"type":"physical unit","value":"C8H18"}]

[{"type":"physical unit","value":"Gram-formula mass [OF] the compound [=] \\pu{114.0 g/mole}"},{"type":"other","value":"The empirical formula of the compound is C4H9."}]

<h1 class="questionTitle" itemprop="name">What is the molecular formula of a compound with an empirical formula of #C_4H_9# and a gram-formula mass of 114.0 g/mole?</h1>

C8H18

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Butyl (4 carbons and 9 hydrogen) has an average mass of 57 grams per mole.</p> <p>Since you are given 114 grams, there are 2 molecules in this butyl.</p> <p>2(<mathjax>#C_4H_9#</mathjax>) is the formula.</p> <p>You can get further information from the following web site:</p> <p>www(dot)chemspider(dot)com(slash)Chemical(dash)Structure(dot)121275(dot)html</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>2-Butyl</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Butyl (4 carbons and 9 hydrogen) has an average mass of 57 grams per mole.</p> <p>Since you are given 114 grams, there are 2 molecules in this butyl.</p> <p>2(<mathjax>#C_4H_9#</mathjax>) is the formula.</p> <p>You can get further information from the following web site:</p> <p>www(dot)chemspider(dot)com(slash)Chemical(dash)Structure(dot)121275(dot)html</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the molecular formula of a compound with an empirical formula of #C_4H_9# and a gram-formula mass of 114.0 g/mole?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="420135" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/g-ozdilek"><img alt="" class="" src="https://profilepictures.socratic.org/KVknsUYQYSYlmT2ycLuw_kentkonseyi-%287%29HGO.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/g-ozdilek"> G_Ozdilek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-09T06:44:25" itemprop="dateCreated"> May 9, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>2-Butyl</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Butyl (4 carbons and 9 hydrogen) has an average mass of 57 grams per mole.</p> <p>Since you are given 114 grams, there are 2 molecules in this butyl.</p> <p>2(<mathjax>#C_4H_9#</mathjax>) is the formula.</p> <p>You can get further information from the following web site:</p> <p>www(dot)chemspider(dot)com(slash)Chemical(dash)Structure(dot)121275(dot)html</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/420135" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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What is the molecular formula of a compound with an empirical formula of #C_4H_9# and a gram-formula mass of 114.0 g/mole?

ab722bd2-6ddd-11ea-b912-ccda262736ce

https://socratic.org/questions/how-would-you-balance-al-s-hno3-aq-al-no3-3-aq-h2-g

2 Al(s) + 6 HNO3(aq) -> 2 Al(NO3)3(aq) + 3 H2(g)

start chemical_equation qc_end chemical_equation 4 10 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"2 Al(s) + 6 HNO3(aq) -> 2 Al(NO3)3(aq) + 3 H2(g)"}]

[{"type":"chemical equation","value":"Al(s) + HNO3(aq) -> Al(NO3)3(aq) + H2(g)"}]

<h1 class="questionTitle" itemprop="name">How would you balance: Al(s) + HNO3(aq) --&gt; Al(NO3)3(aq) + H2(g)? </h1>

2 Al(s) + 6 HNO3(aq) -> 2 Al(NO3)3(aq) + 3 H2(g)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Most students are reluctant to double the beginning compound/element. Don't be afraid to.</p> <p>A helpful tool is to write out each element and count up how many of them are on each side. Then edit those amounts each time WITHOUT doubling back on yourself.</p> <p>If you just changed the number to match the other side, leave it and change something else first.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2Al + 6HNO_3 -&gt; 2Al(NO_3)_3 + 3H_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Most students are reluctant to double the beginning compound/element. Don't be afraid to.</p> <p>A helpful tool is to write out each element and count up how many of them are on each side. Then edit those amounts each time WITHOUT doubling back on yourself.</p> <p>If you just changed the number to match the other side, leave it and change something else first.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How would you balance: Al(s) + HNO3(aq) --&gt; Al(NO3)3(aq) + H2(g)? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="186341" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stuart-w"><img alt="" class="" src="https://profilepictures.socratic.org/8dPtWjNORuHkB120LFRX_Untitled.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stuart-w"> Stuart W. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-10T01:51:16" itemprop="dateCreated"> Nov 10, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2Al + 6HNO_3 -&gt; 2Al(NO_3)_3 + 3H_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Most students are reluctant to double the beginning compound/element. Don't be afraid to.</p> <p>A helpful tool is to write out each element and count up how many of them are on each side. Then edit those amounts each time WITHOUT doubling back on yourself.</p> <p>If you just changed the number to match the other side, leave it and change something else first.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/186341" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------&gt; H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -&gt; Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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How would you balance: Al(s) + HNO3(aq) --&gt; Al(NO3)3(aq) + H2(g)?

aba9a70c-6ddd-11ea-8543-ccda262736ce

https://socratic.org/questions/for-the-reaction-ch-4-2o-2-co-2-h-2o-how-many-moles-of-carbon-dioxide-are-produc-1

6.25 moles

start physical_unit 15 16 mole mol qc_end chemical_equation 3 10 qc_end physical_unit 26 26 23 24 mass qc_end end

[{"type":"physical unit","value":"Mole [OF] carbon dioxide [IN] moles"}]

[{"type":"physical unit","value":"6.25 moles"}]

[{"type":"chemical equation","value":"CH4 + 2 O2 -> CO2 + H2O"},{"type":"physical unit","value":"Mass [OF] methane [=] \\pu{100 g}"}]

<h1 class="questionTitle" itemprop="name">For the reaction #CH_4 + 2O_2 -&gt; CO_2 + H_2O#, how many moles of carbon dioxide are produced from the combustion of 100. g of methane?</h1>

6.25 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>1 mol of methane is 16 grams. Therefore, if you have 100 grams of methane, it means that you have <mathjax>#100/16=6.25#</mathjax> moles of methane.</p> <p>When you burn 6.25 moles of methane, you produce 6.25 moles of carbondioxide.</p> <p>Your reaction is wrong though. I want to correct it.</p> <p><mathjax>#CH_4 + 2O_2 -&gt; CO_2 + 2H_2O#</mathjax> </p> <p>When you burn 6.25 moles of methane, you need 12.5 moles of oxygen gas.</p> <p>When you burn 6.25 moles of methane, you produce 6.25 moles of carbondioxide (275 grams of <mathjax>#CO_2#</mathjax>) and 12.5 moles of water vapour (225 grams of <mathjax>#H_2O#</mathjax>).</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1 mol of methane is 16 grams that produces 6.25 moles of <mathjax>#CO_2#</mathjax> when it is burnt </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>1 mol of methane is 16 grams. Therefore, if you have 100 grams of methane, it means that you have <mathjax>#100/16=6.25#</mathjax> moles of methane.</p> <p>When you burn 6.25 moles of methane, you produce 6.25 moles of carbondioxide.</p> <p>Your reaction is wrong though. I want to correct it.</p> <p><mathjax>#CH_4 + 2O_2 -&gt; CO_2 + 2H_2O#</mathjax> </p> <p>When you burn 6.25 moles of methane, you need 12.5 moles of oxygen gas.</p> <p>When you burn 6.25 moles of methane, you produce 6.25 moles of carbondioxide (275 grams of <mathjax>#CO_2#</mathjax>) and 12.5 moles of water vapour (225 grams of <mathjax>#H_2O#</mathjax>).</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">For the reaction #CH_4 + 2O_2 -&gt; CO_2 + H_2O#, how many moles of carbon dioxide are produced from the combustion of 100. g of methane?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="428837" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/g-ozdilek"><img alt="" class="" src="https://profilepictures.socratic.org/KVknsUYQYSYlmT2ycLuw_kentkonseyi-%287%29HGO.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/g-ozdilek"> G_Ozdilek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-24T11:50:42" itemprop="dateCreated"> May 24, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1 mol of methane is 16 grams that produces 6.25 moles of <mathjax>#CO_2#</mathjax> when it is burnt </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>1 mol of methane is 16 grams. Therefore, if you have 100 grams of methane, it means that you have <mathjax>#100/16=6.25#</mathjax> moles of methane.</p> <p>When you burn 6.25 moles of methane, you produce 6.25 moles of carbondioxide.</p> <p>Your reaction is wrong though. I want to correct it.</p> <p><mathjax>#CH_4 + 2O_2 -&gt; CO_2 + 2H_2O#</mathjax> </p> <p>When you burn 6.25 moles of methane, you need 12.5 moles of oxygen gas.</p> <p>When you burn 6.25 moles of methane, you produce 6.25 moles of carbondioxide (275 grams of <mathjax>#CO_2#</mathjax>) and 12.5 moles of water vapour (225 grams of <mathjax>#H_2O#</mathjax>).</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/428837" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-apply-gas-stoichiometry"> How do you apply gas stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-a-gas-law-stoichiometry-problem"> How do you solve a gas law stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-gas-stoichiometry-problems-at-stp"> How do you do gas stoichiometry problems at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-an-agno3-solution-is-treated-with-50-0-ml-of-hi-gas-to-give-0-235-g-of-agi-"> When an AgNO3 solution is treated with 50.0 mL of HI gas to give 0.235 g of AgI, what is the... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-10-0-ml-of-agno3-solution-is-treated-with-excess-amount-of-hi-gas-to-give-0"> When 10.0 mL of AgNO3 solution is treated with excess amount of HI gas to give 0.235 g of AgI,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/hydrogen-sulfide-reacts-with-sulfur-dioxide-to-give-h2o-and-s-h2s-so2-h2o-s-soli"> Hydrogen sulfide reacts with sulfur dioxide to give H2O and S, H2S + SO2 = H2O + S(solid),... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-200-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 200 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 100 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolve-in-20-ml-of-pure-water-what-i"> If 100 mL of HCl gas at 300 K and 100 kPa dissolve in 20 mL of pure water, what is the concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-2-00-g-mixture-of-na-and-ca-reat-with-water-1-164-l-hydrogen-was-produced-a"> When 2.00 g mixture of Na and Ca reat with water, 1.164 L hydrogen was produced at 300.0 K and... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases"> See all questions in Gas Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 108147 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

For the reaction #CH_4 + 2O_2 -&gt; CO_2 + H_2O#, how many moles of carbon dioxide are produced from the combustion of 100. g of methane?

ab00909e-6ddd-11ea-9e5d-ccda262736ce

https://socratic.org/questions/59757c9db72cff04c6c84f7d

1055.65 mL

start physical_unit 1 1 volume ml qc_end physical_unit 1 1 6 7 volume qc_end c_other STP qc_end physical_unit 1 1 22 23 pressure qc_end c_other constant_temperature qc_end end

[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] mL"}]

[{"type":"physical unit","value":"1055.65 mL"}]

[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{1309 mL}"},{"type":"other","value":"STP"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{941 mmHg}"},{"type":"other","value":"ConstantTemperature"}]

<h1 class="questionTitle" itemprop="name">A gas occupies a volume of #1309*mL# at #"STP"#. At constant temperature, what volume will it occupy at a pressure of #941*mm*Hg#?</h1>

1055.65 mL

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"1 atmosphere"#</mathjax> of pressure will support a column of mercury that is <mathjax>#760*mm*Hg#</mathjax>. It is very UNWISE to put a mercury column under a pressure of GREATER than <mathjax>#1*atm#</mathjax>. Why? Because, you run the risk of breaking the vessel, or overshooting the manometer's height, and getting mercury all over the lab, where it will inhabit every nook and cranny. </p> <p>So we first convert <mathjax>#P_1#</mathjax> and <mathjax>#P_2#</mathjax> to kosher units......</p> <p><mathjax>#"STP"#</mathjax> specifies <mathjax>#1*atm-=760*mm*Hg#</mathjax></p> <p>And the quoted <mathjax>#P_2-=(941*mm*Hg)/(760*mm*Hg*atm^-1)=1.24*atm.#</mathjax> </p> <p>And old <mathjax>#"Boyle's Law"#</mathjax> holds that for a given quantity of gas.......</p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax>. </p> <p>And thus <mathjax>#V_2=(P_1V_1)/P_2=(1*atm*1309*mL)/(1.24*atm)=??*mL#</mathjax>.</p> <p>Remember what I said in regard to the use of <mathjax>#mm*Hg#</mathjax> as a pressure measurement. You should NEVER quote a pressure <mathjax>#&gt;760*mm*Hg#</mathjax>. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>This is a question that has been asked by someone who has never used a mercury manometer. I get a final volume of <mathjax>#V_2~=1000*mL#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"1 atmosphere"#</mathjax> of pressure will support a column of mercury that is <mathjax>#760*mm*Hg#</mathjax>. It is very UNWISE to put a mercury column under a pressure of GREATER than <mathjax>#1*atm#</mathjax>. Why? Because, you run the risk of breaking the vessel, or overshooting the manometer's height, and getting mercury all over the lab, where it will inhabit every nook and cranny. </p> <p>So we first convert <mathjax>#P_1#</mathjax> and <mathjax>#P_2#</mathjax> to kosher units......</p> <p><mathjax>#"STP"#</mathjax> specifies <mathjax>#1*atm-=760*mm*Hg#</mathjax></p> <p>And the quoted <mathjax>#P_2-=(941*mm*Hg)/(760*mm*Hg*atm^-1)=1.24*atm.#</mathjax> </p> <p>And old <mathjax>#"Boyle's Law"#</mathjax> holds that for a given quantity of gas.......</p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax>. </p> <p>And thus <mathjax>#V_2=(P_1V_1)/P_2=(1*atm*1309*mL)/(1.24*atm)=??*mL#</mathjax>.</p> <p>Remember what I said in regard to the use of <mathjax>#mm*Hg#</mathjax> as a pressure measurement. You should NEVER quote a pressure <mathjax>#&gt;760*mm*Hg#</mathjax>. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A gas occupies a volume of #1309*mL# at #"STP"#. At constant temperature, what volume will it occupy at a pressure of #941*mm*Hg#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/boyle-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Boyle's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="455648" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-24T07:39:01" itemprop="dateCreated"> Jul 24, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>This is a question that has been asked by someone who has never used a mercury manometer. I get a final volume of <mathjax>#V_2~=1000*mL#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"1 atmosphere"#</mathjax> of pressure will support a column of mercury that is <mathjax>#760*mm*Hg#</mathjax>. It is very UNWISE to put a mercury column under a pressure of GREATER than <mathjax>#1*atm#</mathjax>. Why? Because, you run the risk of breaking the vessel, or overshooting the manometer's height, and getting mercury all over the lab, where it will inhabit every nook and cranny. </p> <p>So we first convert <mathjax>#P_1#</mathjax> and <mathjax>#P_2#</mathjax> to kosher units......</p> <p><mathjax>#"STP"#</mathjax> specifies <mathjax>#1*atm-=760*mm*Hg#</mathjax></p> <p>And the quoted <mathjax>#P_2-=(941*mm*Hg)/(760*mm*Hg*atm^-1)=1.24*atm.#</mathjax> </p> <p>And old <mathjax>#"Boyle's Law"#</mathjax> holds that for a given quantity of gas.......</p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax>. </p> <p>And thus <mathjax>#V_2=(P_1V_1)/P_2=(1*atm*1309*mL)/(1.24*atm)=??*mL#</mathjax>.</p> <p>Remember what I said in regard to the use of <mathjax>#mm*Hg#</mathjax> as a pressure measurement. You should NEVER quote a pressure <mathjax>#&gt;760*mm*Hg#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/455648" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-graph-boyles-law"> How do you graph Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-functional-groups-are-found-in-lipids"> What functional groups are found in lipids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-k-constant-in-boyle-s-law"> Why is k constant in Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-graph-curved-1"> Why is Boyle's law graph curved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-an-inverse-relationship-2"> Why is Boyle's law an inverse relationship? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-40-0-l-tank-of-ammonia-has-a-pressure-of-8-00-atm-calculate-the-volume-of-the-"> A 40.0 L tank of ammonia has a pressure of 8.00 atm. 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A gas occupies a volume of #1309*mL# at #"STP"#. At constant temperature, what volume will it occupy at a pressure of #941*mm*Hg#?

a96ff4df-6ddd-11ea-80d6-ccda262736ce

https://socratic.org/questions/580578d97c014933baa03b75

SO3^2- + Cu^2+ + 2 OH- -> SO4^2- + Cu(s) + H2O(l)

start chemical_equation qc_end chemical_equation 8 8 qc_end chemical_equation 13 13 qc_end chemical_equation 19 19 qc_end substance 21 22 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"SO3^2- + Cu^2+ + 2 OH- -> SO4^2- + Cu(s) + H2O(l)"}]

[{"type":"chemical equation","value":"SO3^2-"},{"type":"chemical equation","value":"SO4^2-"},{"type":"chemical equation","value":"Cu^2+"},{"type":"substance name","value":"Copper metal"}]

<h1 class="questionTitle" itemprop="name">Can you represent the oxidation of sulfite ion, #SO_3^(2-)#, to give sulfate ion, #SO_4^(2-)#, accompanied by the reduction of #Cu^(2+)# to copper metal?</h1>

SO3^2- + Cu^2+ + 2 OH- -> SO4^2- + Cu(s) + H2O(l)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When basic conditions are specified, it is normally best to balance the equations in acid, and then modify the final equations. </p> <p><mathjax>#"Sulfur (IV+)"#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#"Sulfur(VI+)":#</mathjax></p> <p><mathjax>#SO_3^(2-) + H_2Orarr SO_4^(2-) +2H^(+) + 2e^(-) #</mathjax></p> <p>For basic conditions, add <mathjax>#2xxHO^-#</mathjax> to EACH side <mathjax>#(HO^(-) + H^(+)rarrH_2O)#</mathjax>:</p> <p><mathjax>#SO_3^(2-) + 2HO^(-) rarr SO_4^(2-) +H_2O + 2e^(-) #</mathjax></p> <p><mathjax>#"Copper (II+)"#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#"Copper (0)":#</mathjax></p> <p><mathjax>#Cu^(2+) + 2e^(-) rarr Cu#</mathjax></p> <p>You have asked another such question recently. Do you follow the method of doing redox equations?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#SO_3^(2-) + Cu^(2+)+ 2HO^(-) rarr SO_4^(2-) +Cu(s) + H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When basic conditions are specified, it is normally best to balance the equations in acid, and then modify the final equations. </p> <p><mathjax>#"Sulfur (IV+)"#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#"Sulfur(VI+)":#</mathjax></p> <p><mathjax>#SO_3^(2-) + H_2Orarr SO_4^(2-) +2H^(+) + 2e^(-) #</mathjax></p> <p>For basic conditions, add <mathjax>#2xxHO^-#</mathjax> to EACH side <mathjax>#(HO^(-) + H^(+)rarrH_2O)#</mathjax>:</p> <p><mathjax>#SO_3^(2-) + 2HO^(-) rarr SO_4^(2-) +H_2O + 2e^(-) #</mathjax></p> <p><mathjax>#"Copper (II+)"#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#"Copper (0)":#</mathjax></p> <p><mathjax>#Cu^(2+) + 2e^(-) rarr Cu#</mathjax></p> <p>You have asked another such question recently. Do you follow the method of doing redox equations?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Can you represent the oxidation of sulfite ion, #SO_3^(2-)#, to give sulfate ion, #SO_4^(2-)#, accompanied by the reduction of #Cu^(2+)# to copper metal?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/redox-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Redox Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="323106" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-18T03:21:47" itemprop="dateCreated"> Oct 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#SO_3^(2-) + Cu^(2+)+ 2HO^(-) rarr SO_4^(2-) +Cu(s) + H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When basic conditions are specified, it is normally best to balance the equations in acid, and then modify the final equations. </p> <p><mathjax>#"Sulfur (IV+)"#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#"Sulfur(VI+)":#</mathjax></p> <p><mathjax>#SO_3^(2-) + H_2Orarr SO_4^(2-) +2H^(+) + 2e^(-) #</mathjax></p> <p>For basic conditions, add <mathjax>#2xxHO^-#</mathjax> to EACH side <mathjax>#(HO^(-) + H^(+)rarrH_2O)#</mathjax>:</p> <p><mathjax>#SO_3^(2-) + 2HO^(-) rarr SO_4^(2-) +H_2O + 2e^(-) #</mathjax></p> <p><mathjax>#"Copper (II+)"#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#"Copper (0)":#</mathjax></p> <p><mathjax>#Cu^(2+) + 2e^(-) rarr Cu#</mathjax></p> <p>You have asked another such question recently. Do you follow the method of doing redox equations?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/323106" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54423f26581e2a5bfd08340d"> Question #8340d </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-redox-reaction"> What is a redox reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-oxidation"> What is oxidation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-reduction"> What is reduction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54d532c6581e2a49268014c4"> Question #014c4 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/556ea205581e2a438ccb58e9"> Question #b58e9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/55973977581e2a5f9d456add"> Question #56add </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/55ad1b09581e2a5dd320853f"> Question #0853f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/55b8d545581e2a20b9abe12b"> Question #be12b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5618b78a11ef6b27240f7e3f"> Question #f7e3f </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/redox-reactions"> See all questions in Redox Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4568 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

Can you represent the oxidation of sulfite ion, #SO_3^(2-)#, to give sulfate ion, #SO_4^(2-)#, accompanied by the reduction of #Cu^(2+)# to copper metal?

aad18ed1-6ddd-11ea-b8bf-ccda262736ce

https://socratic.org/questions/balance-the-below-in-acidic-solution-redox-reaction

4 Cr^3+(aq) + 3 ClO4-(aq) + 8 H2O -> 2 Cr2O7^2-(aq) + 3 ClO2-(aq) + 16 H+

start chemical_equation qc_end chemical_equation 8 14 qc_end end

[{"type":"other","value":"Chemical Equation [OF] redox reaction"}]

[{"type":"chemical equation","value":"4 Cr^3+(aq) + 3 ClO4-(aq) + 8 H2O -> 2 Cr2O7^2-(aq) + 3 ClO2-(aq) + 16 H+"}]

[{"type":"chemical equation","value":"Cr^3+(aq) + ClO4-(aq) -> Cr2O7^2-(aq) + ClO2-(aq)"}]

<h1 class="questionTitle" itemprop="name">Balance the below in acidic solution (redox reaction)?</h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#Cr^(3+)(aq)+ClO_4^(-)(aq)\toCr_2O_7^(2-)(aq)+ClO_2^(- )(aq)#</mathjax></p></div> </h2> </div> </div>

4 Cr^3+(aq) + 3 ClO4-(aq) + 8 H2O -> 2 Cr2O7^2-(aq) + 3 ClO2-(aq) + 16 H+

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Well, chromic ion is oxidized...</p> <p><mathjax>#2Cr^(3+)+7H_2Orarr Cr_2O_7^(2-) +14H^++ 6e^(-)#</mathjax></p> <p>And perchlorate is reduced to chlorite...</p> <p><mathjax>#ClO_4^(-) + 4H^+ +4e^(-)rarr ClO_2^(-)+2H_2O#</mathjax></p> <p>The difference in <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> between chromium, and chlorine, which I leave to you to determine, is accounted for by electron transfer...</p> <p>We take TWO of the former, and add THREE of the latter to retire the electrons, virtual particles of convenience. </p> <p><mathjax>#4Cr^(3+)+14H_2O+3ClO_4^(-) + 12H^+ +12e^(-)rarr 2Cr_2O_7^(2-) +28H^+ + 12e^(-)+3ClO_2^(-)+6H_2O#</mathjax></p> <p>And we cancel away to get...</p> <p><mathjax>#underbrace(4Cr^(3+))_"green"+3ClO_4^(-)+8H_2O rarr underbrace(2Cr_2O_7^(2-))_"orange-red" +3ClO_2^(-)+16H^+ #</mathjax></p> <p>This I think is balanced with respect to mass and charge, as indeed it must be if we purport to represent chemical reality. Whether it works or not is a different matter. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#underbrace(4Cr^(3+))_"green"+3ClO_4^(-)+8H_2O rarr underbrace(2Cr_2O_7^(2-))_"orange-red" +3ClO_2^(-)+16H^+ #</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Well, chromic ion is oxidized...</p> <p><mathjax>#2Cr^(3+)+7H_2Orarr Cr_2O_7^(2-) +14H^++ 6e^(-)#</mathjax></p> <p>And perchlorate is reduced to chlorite...</p> <p><mathjax>#ClO_4^(-) + 4H^+ +4e^(-)rarr ClO_2^(-)+2H_2O#</mathjax></p> <p>The difference in <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> between chromium, and chlorine, which I leave to you to determine, is accounted for by electron transfer...</p> <p>We take TWO of the former, and add THREE of the latter to retire the electrons, virtual particles of convenience. </p> <p><mathjax>#4Cr^(3+)+14H_2O+3ClO_4^(-) + 12H^+ +12e^(-)rarr 2Cr_2O_7^(2-) +28H^+ + 12e^(-)+3ClO_2^(-)+6H_2O#</mathjax></p> <p>And we cancel away to get...</p> <p><mathjax>#underbrace(4Cr^(3+))_"green"+3ClO_4^(-)+8H_2O rarr underbrace(2Cr_2O_7^(2-))_"orange-red" +3ClO_2^(-)+16H^+ #</mathjax></p> <p>This I think is balanced with respect to mass and charge, as indeed it must be if we purport to represent chemical reality. Whether it works or not is a different matter. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Balance the below in acidic solution (redox reaction)?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#Cr^(3+)(aq)+ClO_4^(-)(aq)\toCr_2O_7^(2-)(aq)+ClO_2^(- )(aq)#</mathjax></p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/balancing-redox-equations-using-the-oxidation-number-method" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Redox Equations Using the Oxidation Number Method</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="639408" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-07-09T05:05:08" itemprop="dateCreated"> Jul 9, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#underbrace(4Cr^(3+))_"green"+3ClO_4^(-)+8H_2O rarr underbrace(2Cr_2O_7^(2-))_"orange-red" +3ClO_2^(-)+16H^+ #</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Well, chromic ion is oxidized...</p> <p><mathjax>#2Cr^(3+)+7H_2Orarr Cr_2O_7^(2-) +14H^++ 6e^(-)#</mathjax></p> <p>And perchlorate is reduced to chlorite...</p> <p><mathjax>#ClO_4^(-) + 4H^+ +4e^(-)rarr ClO_2^(-)+2H_2O#</mathjax></p> <p>The difference in <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> between chromium, and chlorine, which I leave to you to determine, is accounted for by electron transfer...</p> <p>We take TWO of the former, and add THREE of the latter to retire the electrons, virtual particles of convenience. </p> <p><mathjax>#4Cr^(3+)+14H_2O+3ClO_4^(-) + 12H^+ +12e^(-)rarr 2Cr_2O_7^(2-) +28H^+ + 12e^(-)+3ClO_2^(-)+6H_2O#</mathjax></p> <p>And we cancel away to get...</p> <p><mathjax>#underbrace(4Cr^(3+))_"green"+3ClO_4^(-)+8H_2O rarr underbrace(2Cr_2O_7^(2-))_"orange-red" +3ClO_2^(-)+16H^+ #</mathjax></p> <p>This I think is balanced with respect to mass and charge, as indeed it must be if we purport to represent chemical reality. Whether it works or not is a different matter. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/639408" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-reactions-in-basic-solution"> How do you balance redox reactions in basic solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-equations-by-oxidation-number-method"> How do you balance redox equations by oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-equations-in-acidic-solutions"> How do you balance redox equations in acidic solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-method"> What is the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-balancing-redox-equations-using-the-oxidation-number-m"> What are some examples of balancing redox equations using the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-number-method-useful"> Why is the oxidation number method useful? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-necessary-to-break-the-equation-into-half-reactions-in-the-oxidation-numbe"> Is it necessary to break the equation into half reactions in the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-difference-between-the-oxidation-number-method-and-the-ion-electron-"> What is the difference between the oxidation number method and the ion-electron method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-balance-the-equation-using-the-oxidation-states-method-mno2-al-mn-al2o3"> Can you balance the equation using the oxidation states method MnO2+Al---&gt;Mn+Al2O3? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-this-redox-reaction-using-the-oxidation-number-method-fe2-aq-"> How do you balance this redox reaction using the oxidation number method? Fe2+(aq) + MnO4–(aq)... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/balancing-redox-equations-using-the-oxidation-number-method"> See all questions in Balancing Redox Equations Using the Oxidation Number Method </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1648 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

Balance the below in acidic solution (redox reaction)?

#Cr^(3+)(aq)+ClO_4^(-)(aq)\toCr_2O_7^(2-)(aq)+ClO_2^(- )(aq)#

a9d7fe2d-6ddd-11ea-9d58-ccda262736ce

https://socratic.org/questions/what-is-the-equation-for-calcium-carbonate

Ca^2+(aq) + CO3^2-(aq) -> CaCO3(s)

start chemical_equation qc_end substance 5 6 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"Ca^2+(aq) + CO3^2-(aq) -> CaCO3(s)"}]

[{"type":"substance name","value":"Calcium Carbonate"}]

<h1 class="questionTitle" itemprop="name">What is the equation for Calcium Carbonate?</h1>

Ca^2+(aq) + CO3^2-(aq) -> CaCO3(s)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Its not the equation, its called the chemical formula. The (chemical) equation is getting product(s) by the reaction between the reactants,</p> <p>Its equation can be written like this:<br/> <mathjax>#Ca^(2+) (aq)+ CO_3^(2-) (aq) -&gt; CaCO_3 (s)#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CaCO_3#</mathjax> is the <strong>chemical formula</strong> of Calcium Carbonate.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Its not the equation, its called the chemical formula. The (chemical) equation is getting product(s) by the reaction between the reactants,</p> <p>Its equation can be written like this:<br/> <mathjax>#Ca^(2+) (aq)+ CO_3^(2-) (aq) -&gt; CaCO_3 (s)#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the equation for Calcium Carbonate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="287188" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/muhammad-u"><img alt="" class="" src="https://profilepictures.socratic.org/BLts7yuPTBOGgXOQxVXN_12066012_1654537838157632_4282748404559725492_n.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/muhammad-u"> UmAir.A </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-11T18:59:08" itemprop="dateCreated"> Jul 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CaCO_3#</mathjax> is the <strong>chemical formula</strong> of Calcium Carbonate.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Its not the equation, its called the chemical formula. The (chemical) equation is getting product(s) by the reaction between the reactants,</p> <p>Its equation can be written like this:<br/> <mathjax>#Ca^(2+) (aq)+ CO_3^(2-) (aq) -&gt; CaCO_3 (s)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/287188" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-equation-for-photosynthesis"> What is the chemical equation for photosynthesis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-grams-of-each-substance-used-or-produced-w"> How can I know the relative number of grams of each substance used or produced with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-moles-of-each-substance-with-chemical-equa"> How can I know the relative number of moles of each substance with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-chemical-equations-illustrate-that-atoms-are-conserved-1"> How do chemical equations illustrate that atoms are conserved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-formula-of-the-reactants-and-products-with-chemical-equations"> How can I know the formula of the reactants and products with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-potassium-metal-and-chlorine-gas-combi"> How can I balance this chemical equations? 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What is the equation for Calcium Carbonate?

ad1d622c-6ddd-11ea-8901-ccda262736ce

https://socratic.org/questions/how-much-heat-must-be-removed-to-freeze-a-tray-of-ice-cubes-if-the-water-has-a-m-1

13.36 kJ

start physical_unit 15 15 heat_energy kj qc_end physical_unit 15 15 20 21 mass qc_end physical_unit 15 15 30 31 molar_heat qc_end end

[{"type":"physical unit","value":"Removed heat [OF] water [IN] kJ"}]

[{"type":"physical unit","value":"13.36 kJ"}]

[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{40.0 g}"},{"type":"physical unit","value":"Molar heat of fusion [OF] water [=] \\pu{6.02 kJ/mol}"}]

<h1 class="questionTitle" itemprop="name">How much heat must be removed to freeze a tray of ice cubes if the water has a mass of 40.0 g? (The molar heat of fusion of water is 6.02 kJ/mol.)</h1>

13.36 kJ

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong>molar heat of fusion</strong> of water tells you the amount of heat </p> <blockquote> <ul> <li><strong>needed</strong> to convert <mathjax>#1#</mathjax> <strong>mole</strong> of water from solid at its freezing point to liquid at its freezing point</li> <li><strong>given off</strong> when <mathjax>#1#</mathjax> <strong>mole</strong> of water is converted from liquid at its freezing point to solid at its freezing point</li> </ul> </blockquote> <p>You can thus say that when <mathjax>#1#</mathjax> <strong>mole</strong> of liquid water goes from liquid at its normal freezing point of <mathjax>#0^@"C"#</mathjax> to solid at <mathjax>#0^@"C"#</mathjax>, <mathjax>#"6.04 kJ"#</mathjax> of heat are being <strong>given off</strong>.</p> <p>In other words, you have</p> <blockquote> <ul> <li><mathjax>#DeltaH_"fus" = -"6.02 kJ mol"^(-1) -&gt;#</mathjax> <em>when going from <strong>liquid</strong> to <strong>solid</strong></em></li> </ul> <blockquote> <blockquote> <p>The minus sign is used here to denote <strong>heat given off</strong>.</p> </blockquote> </blockquote> <ul> <li><mathjax>#DeltaH_"fus" = +"6.02 kJ mol"^(-1) -&gt;#</mathjax> <em>when going from <strong>solid</strong> to <strong>liquid</strong></em></li> </ul> <blockquote> <blockquote> <p>The plus sign symbolizes heat <strong>absorbed</strong>. </p> </blockquote> </blockquote> </blockquote> <p>Now, as its name suggests, the <em>molar</em> heat of fusion uses <strong>moles</strong>, not grams, so start by converting the mass of ice to moles by using the <strong>molar mass</strong> of water</p> <blockquote> <p><mathjax>#40.0 color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))) = "2.220 moles H"_2"O"#</mathjax></p> </blockquote> <p>So, use the molar heat of fusion as a <em>conversion factor</em> to calculate the <strong><a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change</strong> that corresponds to the freezing of <mathjax>#"40.0 g"#</mathjax> of liquid water at its normal freezing point</p> <blockquote> <p><mathjax>#2.220 color(red)(cancel(color(black)("moles H"_ 2"O"))) * overbrace((-"6.02 kJ")/(1color(red)(cancel(color(black)("mole H"_ 2"O")))))^(color(blue)(DeltaH_ "fus" color(white)(.)"for liquid to solid")) = -"13.4 kJ"#</mathjax></p> </blockquote> <p>This means that when <mathjax>#"40.0 g"#</mathjax> of water go from liquid at <mathjax>#0^@"C"#</mathjax> to solid at <mathjax>#0^@"C"#</mathjax>, <mathjax>#"13.4 kJ"#</mathjax> of heat are being <strong>released</strong>, hence the minus sign. </p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("heat given off = 13.4 kJ")))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"13.4 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong>molar heat of fusion</strong> of water tells you the amount of heat </p> <blockquote> <ul> <li><strong>needed</strong> to convert <mathjax>#1#</mathjax> <strong>mole</strong> of water from solid at its freezing point to liquid at its freezing point</li> <li><strong>given off</strong> when <mathjax>#1#</mathjax> <strong>mole</strong> of water is converted from liquid at its freezing point to solid at its freezing point</li> </ul> </blockquote> <p>You can thus say that when <mathjax>#1#</mathjax> <strong>mole</strong> of liquid water goes from liquid at its normal freezing point of <mathjax>#0^@"C"#</mathjax> to solid at <mathjax>#0^@"C"#</mathjax>, <mathjax>#"6.04 kJ"#</mathjax> of heat are being <strong>given off</strong>.</p> <p>In other words, you have</p> <blockquote> <ul> <li><mathjax>#DeltaH_"fus" = -"6.02 kJ mol"^(-1) -&gt;#</mathjax> <em>when going from <strong>liquid</strong> to <strong>solid</strong></em></li> </ul> <blockquote> <blockquote> <p>The minus sign is used here to denote <strong>heat given off</strong>.</p> </blockquote> </blockquote> <ul> <li><mathjax>#DeltaH_"fus" = +"6.02 kJ mol"^(-1) -&gt;#</mathjax> <em>when going from <strong>solid</strong> to <strong>liquid</strong></em></li> </ul> <blockquote> <blockquote> <p>The plus sign symbolizes heat <strong>absorbed</strong>. </p> </blockquote> </blockquote> </blockquote> <p>Now, as its name suggests, the <em>molar</em> heat of fusion uses <strong>moles</strong>, not grams, so start by converting the mass of ice to moles by using the <strong>molar mass</strong> of water</p> <blockquote> <p><mathjax>#40.0 color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))) = "2.220 moles H"_2"O"#</mathjax></p> </blockquote> <p>So, use the molar heat of fusion as a <em>conversion factor</em> to calculate the <strong><a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change</strong> that corresponds to the freezing of <mathjax>#"40.0 g"#</mathjax> of liquid water at its normal freezing point</p> <blockquote> <p><mathjax>#2.220 color(red)(cancel(color(black)("moles H"_ 2"O"))) * overbrace((-"6.02 kJ")/(1color(red)(cancel(color(black)("mole H"_ 2"O")))))^(color(blue)(DeltaH_ "fus" color(white)(.)"for liquid to solid")) = -"13.4 kJ"#</mathjax></p> </blockquote> <p>This means that when <mathjax>#"40.0 g"#</mathjax> of water go from liquid at <mathjax>#0^@"C"#</mathjax> to solid at <mathjax>#0^@"C"#</mathjax>, <mathjax>#"13.4 kJ"#</mathjax> of heat are being <strong>released</strong>, hence the minus sign. </p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("heat given off = 13.4 kJ")))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How much heat must be removed to freeze a tray of ice cubes if the water has a mass of 40.0 g? (The molar heat of fusion of water is 6.02 kJ/mol.)</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/thermochemistry-of-phase-changes" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry of Phase Changes</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="438279" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-11T22:52:52" itemprop="dateCreated"> Jun 11, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"13.4 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong>molar heat of fusion</strong> of water tells you the amount of heat </p> <blockquote> <ul> <li><strong>needed</strong> to convert <mathjax>#1#</mathjax> <strong>mole</strong> of water from solid at its freezing point to liquid at its freezing point</li> <li><strong>given off</strong> when <mathjax>#1#</mathjax> <strong>mole</strong> of water is converted from liquid at its freezing point to solid at its freezing point</li> </ul> </blockquote> <p>You can thus say that when <mathjax>#1#</mathjax> <strong>mole</strong> of liquid water goes from liquid at its normal freezing point of <mathjax>#0^@"C"#</mathjax> to solid at <mathjax>#0^@"C"#</mathjax>, <mathjax>#"6.04 kJ"#</mathjax> of heat are being <strong>given off</strong>.</p> <p>In other words, you have</p> <blockquote> <ul> <li><mathjax>#DeltaH_"fus" = -"6.02 kJ mol"^(-1) -&gt;#</mathjax> <em>when going from <strong>liquid</strong> to <strong>solid</strong></em></li> </ul> <blockquote> <blockquote> <p>The minus sign is used here to denote <strong>heat given off</strong>.</p> </blockquote> </blockquote> <ul> <li><mathjax>#DeltaH_"fus" = +"6.02 kJ mol"^(-1) -&gt;#</mathjax> <em>when going from <strong>solid</strong> to <strong>liquid</strong></em></li> </ul> <blockquote> <blockquote> <p>The plus sign symbolizes heat <strong>absorbed</strong>. </p> </blockquote> </blockquote> </blockquote> <p>Now, as its name suggests, the <em>molar</em> heat of fusion uses <strong>moles</strong>, not grams, so start by converting the mass of ice to moles by using the <strong>molar mass</strong> of water</p> <blockquote> <p><mathjax>#40.0 color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))) = "2.220 moles H"_2"O"#</mathjax></p> </blockquote> <p>So, use the molar heat of fusion as a <em>conversion factor</em> to calculate the <strong><a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change</strong> that corresponds to the freezing of <mathjax>#"40.0 g"#</mathjax> of liquid water at its normal freezing point</p> <blockquote> <p><mathjax>#2.220 color(red)(cancel(color(black)("moles H"_ 2"O"))) * overbrace((-"6.02 kJ")/(1color(red)(cancel(color(black)("mole H"_ 2"O")))))^(color(blue)(DeltaH_ "fus" color(white)(.)"for liquid to solid")) = -"13.4 kJ"#</mathjax></p> </blockquote> <p>This means that when <mathjax>#"40.0 g"#</mathjax> of water go from liquid at <mathjax>#0^@"C"#</mathjax> to solid at <mathjax>#0^@"C"#</mathjax>, <mathjax>#"13.4 kJ"#</mathjax> of heat are being <strong>released</strong>, hence the minus sign. </p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("heat given off = 13.4 kJ")))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/438279" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-much-energy-is-required-to-heat-100-g-of-ice-at-0-00-degrees-celsius-to-wate"> How much energy is required to convert 100.g of ice at 0.00 °C to water vapor at 100.00 °C? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534b309602bf34123dd86d5c"> How do you calculate the heat required to melt 15 kg of silver? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-a-liquid-loses-energy-will-it-change-into-a-gas-or-a-solid"> When a liquid loses energy, will it change into a gas 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How much heat must be removed to freeze a tray of ice cubes if the water has a mass of 40.0 g? (The molar heat of fusion of water is 6.02 kJ/mol.)

ac5ce0e3-6ddd-11ea-b527-ccda262736ce

https://socratic.org/questions/a-sample-of-gas-is-collected-over-water-at-a-temperature-of-27-0-c-when-the-baro

722 mmHg

start physical_unit 28 30 partial_pressure mmhg qc_end physical_unit 1 3 12 13 temperature qc_end physical_unit 1 3 20 21 barometric_pressure qc_end end

[{"type":"physical unit","value":"Partial pressure [OF] the dry gas [IN] mmHg"}]

[{"type":"physical unit","value":"722 mmHg"}]

[{"type":"physical unit","value":"Temperature [OF] gas sample [=] \\pu{27.0 ℃}"},{"type":"physical unit","value":"Barometric pressure [OF] gas sample [=] \\pu{750.0 mmHg}"}]

<h1 class="questionTitle" itemprop="name">A sample of gas is collected over water at a temperature of 27.0°C when the barometric pressure reading is 750.0 mm Hg. What is the partial pressure of the dry gas?</h1>

722 mmHg

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The saturated vapour pressure of water at <mathjax>#27.0#</mathjax> <mathjax>#""^@C#</mathjax> (<mathjax>#300#</mathjax> <mathjax>#K#</mathjax>) is <a href="http://hyperphysics.phy-astr.gsu.edu/hbase/kinetic/watvap.html" rel="nofollow">approx.</a> <mathjax>#28#</mathjax> <mathjax>#mm#</mathjax> <mathjax>#Hg#</mathjax>. The actual value should of course have been quoted with the problem. Thus the partial pressure of the gas is <mathjax>#750.0#</mathjax> <mathjax>#mm#</mathjax> <mathjax>#Hg#</mathjax> <mathjax>#-#</mathjax> <mathjax>#28#</mathjax> <mathjax>#mm#</mathjax> <mathjax>#Hg#</mathjax> <mathjax>#=#</mathjax> <mathjax>#722#</mathjax> <mathjax>#mm#</mathjax> <mathjax>#Hg#</mathjax>.</p> <p>Again I could not find the correct value on the interwebs.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of the collected gas is <mathjax>#750#</mathjax> <mathjax>#mm#</mathjax> <mathjax>#Hg#</mathjax> LESS the saturated vapour pressure of water at <mathjax>#27.0#</mathjax> <mathjax>#""^@C#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The saturated vapour pressure of water at <mathjax>#27.0#</mathjax> <mathjax>#""^@C#</mathjax> (<mathjax>#300#</mathjax> <mathjax>#K#</mathjax>) is <a href="http://hyperphysics.phy-astr.gsu.edu/hbase/kinetic/watvap.html" rel="nofollow">approx.</a> <mathjax>#28#</mathjax> <mathjax>#mm#</mathjax> <mathjax>#Hg#</mathjax>. The actual value should of course have been quoted with the problem. Thus the partial pressure of the gas is <mathjax>#750.0#</mathjax> <mathjax>#mm#</mathjax> <mathjax>#Hg#</mathjax> <mathjax>#-#</mathjax> <mathjax>#28#</mathjax> <mathjax>#mm#</mathjax> <mathjax>#Hg#</mathjax> <mathjax>#=#</mathjax> <mathjax>#722#</mathjax> <mathjax>#mm#</mathjax> <mathjax>#Hg#</mathjax>.</p> <p>Again I could not find the correct value on the interwebs.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A sample of gas is collected over water at a temperature of 27.0°C when the barometric pressure reading is 750.0 mm Hg. What is the partial pressure of the dry gas?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/partial-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Partial Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="210415" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-09T20:47:49" itemprop="dateCreated"> Jan 9, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of the collected gas is <mathjax>#750#</mathjax> <mathjax>#mm#</mathjax> <mathjax>#Hg#</mathjax> LESS the saturated vapour pressure of water at <mathjax>#27.0#</mathjax> <mathjax>#""^@C#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The saturated vapour pressure of water at <mathjax>#27.0#</mathjax> <mathjax>#""^@C#</mathjax> (<mathjax>#300#</mathjax> <mathjax>#K#</mathjax>) is <a href="http://hyperphysics.phy-astr.gsu.edu/hbase/kinetic/watvap.html" rel="nofollow">approx.</a> <mathjax>#28#</mathjax> <mathjax>#mm#</mathjax> <mathjax>#Hg#</mathjax>. The actual value should of course have been quoted with the problem. Thus the partial pressure of the gas is <mathjax>#750.0#</mathjax> <mathjax>#mm#</mathjax> <mathjax>#Hg#</mathjax> <mathjax>#-#</mathjax> <mathjax>#28#</mathjax> <mathjax>#mm#</mathjax> <mathjax>#Hg#</mathjax> <mathjax>#=#</mathjax> <mathjax>#722#</mathjax> <mathjax>#mm#</mathjax> <mathjax>#Hg#</mathjax>.</p> <p>Again I could not find the correct value on the interwebs.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/210415" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534e256802bf342adfa30010"> How do you do a steam distillation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/53613f9f02bf3416cd9f8a34"> Question #f8a34 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-i-calculate-the-total-pressure-of-a-mixture-of-gases-by-adding-together-the-"> Can I calculate the total pressure of a mixture of gases by adding together the partial... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-formula-of-partial-pressure"> What is the formula of partial pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-dalton-s-law-of-partial-pressures"> What is the Dalton's law of partial pressures? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/nitrogen-gas-n2-reacts-with-hydrogen-gas-h2-to-form-ammonia-nh3-at-200-c-in-a-cl"> Nitrogen gas (N2) reacts with hydrogen gas (H2) to form ammonia (NH3). 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A sample of gas is collected over water at a temperature of 27.0°C when the barometric pressure reading is 750.0 mm Hg. What is the partial pressure of the dry gas?

a848eacc-6ddd-11ea-bf00-ccda262736ce

https://socratic.org/questions/a-container-of-oxygen-has-a-volume-of-349-ml-at-a-temperature-of-22-0-c-what-vol

398.69 mL

start physical_unit 3 3 volume ml qc_end physical_unit 3 3 8 9 volume qc_end physical_unit 3 3 14 15 temperature qc_end physical_unit 3 3 24 25 temperature qc_end end

[{"type":"physical unit","value":"Volume2 [OF] the oxygen gas [IN] mL"}]

[{"type":"physical unit","value":"398.69 mL"}]

[{"type":"physical unit","value":"Volume1 [OF] the oxygen gas [=] \\pu{349 mL}"},{"type":"physical unit","value":"Temperature1 [OF] the oxygen gas [=] \\pu{22.0 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] the oxygen gas [=] \\pu{50.0 ℃}"}]

<h1 class="questionTitle" itemprop="name">A container of oxygen has a volume of 349 mL at a temperature of 22.0°C . What volume will the gas occupy at 50.0°C?</h1>

398.69 mL

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Charles' Law states that at constant pressure, and constant amount of gas, volume is proportional to absolute temperature, i.e. <mathjax>#VpropT#</mathjax>.</p> <p>So <mathjax>#V=kT#</mathjax>, where <mathjax>#V#</mathjax> = volume, <mathjax>#k#</mathjax> is some constant, and <mathjax>#T#</mathjax> is absolute temperature. </p> <p>So, in each case, <mathjax>#V_1=kT_1, and V_2=kT_2#</mathjax>. If we solve for <mathjax>#k#</mathjax>, then <mathjax>#V_1/T_1 = V_2/T_2#</mathjax>.</p> <p>Thus, <mathjax>#V_2=(V_1xxT_2)/T_1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(0.349*dm^3xx337cancelK)/(295cancelK)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#dm^3#</mathjax></p> <p>Note that <mathjax>#V_2#</mathjax> will be bigger (reasonably), because <mathjax>#T_2#</mathjax> has increased from <mathjax>#T_1#</mathjax>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We assume a constant pressure. Thus <a href="http://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a> applies. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Charles' Law states that at constant pressure, and constant amount of gas, volume is proportional to absolute temperature, i.e. <mathjax>#VpropT#</mathjax>.</p> <p>So <mathjax>#V=kT#</mathjax>, where <mathjax>#V#</mathjax> = volume, <mathjax>#k#</mathjax> is some constant, and <mathjax>#T#</mathjax> is absolute temperature. </p> <p>So, in each case, <mathjax>#V_1=kT_1, and V_2=kT_2#</mathjax>. If we solve for <mathjax>#k#</mathjax>, then <mathjax>#V_1/T_1 = V_2/T_2#</mathjax>.</p> <p>Thus, <mathjax>#V_2=(V_1xxT_2)/T_1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(0.349*dm^3xx337cancelK)/(295cancelK)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#dm^3#</mathjax></p> <p>Note that <mathjax>#V_2#</mathjax> will be bigger (reasonably), because <mathjax>#T_2#</mathjax> has increased from <mathjax>#T_1#</mathjax>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A container of oxygen has a volume of 349 mL at a temperature of 22.0°C . What volume will the gas occupy at 50.0°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/charles-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Charles' Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="193383" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-26T18:16:14" itemprop="dateCreated"> Nov 26, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We assume a constant pressure. Thus <a href="http://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a> applies. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Charles' Law states that at constant pressure, and constant amount of gas, volume is proportional to absolute temperature, i.e. <mathjax>#VpropT#</mathjax>.</p> <p>So <mathjax>#V=kT#</mathjax>, where <mathjax>#V#</mathjax> = volume, <mathjax>#k#</mathjax> is some constant, and <mathjax>#T#</mathjax> is absolute temperature. </p> <p>So, in each case, <mathjax>#V_1=kT_1, and V_2=kT_2#</mathjax>. If we solve for <mathjax>#k#</mathjax>, then <mathjax>#V_1/T_1 = V_2/T_2#</mathjax>.</p> <p>Thus, <mathjax>#V_2=(V_1xxT_2)/T_1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(0.349*dm^3xx337cancelK)/(295cancelK)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#dm^3#</mathjax></p> <p>Note that <mathjax>#V_2#</mathjax> will be bigger (reasonably), because <mathjax>#T_2#</mathjax> has increased from <mathjax>#T_1#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/193383" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="193434" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-26T20:24:56" itemprop="dateCreated"> Nov 26, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final volume will be 382 mL.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="http://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' law</a> states that the volume of a given amount of a gas kept at constant pressure, is directly proportional to the temperature in Kelvins. <a href="http://chemistry.bd.psu.edu/jircitano/gases.html" rel="nofollow" target="_blank">http://chemistry.bd.psu.edu/jircitano/gases.html</a></p> <p>The equation needed to solve this problem is <mathjax>#V_1/T_1=V_2/T_2#</mathjax>.</p> <p><strong>Given/Known</strong><br/> <mathjax>#V_1="349 mL"#</mathjax><br/> <mathjax>#T_1="22.0"^"o""C"+273.15="295.2 K"#</mathjax><br/> <mathjax>#T_2="50.0"^"o""C"+273.15="323.2 K"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#V_2#</mathjax></p> <p><strong>Equation</strong></p> <p><mathjax>#V_1/T_1=V_2/T_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax> and solve.</p> <p><mathjax>#V_2=(V_1T_2)/T_1#</mathjax></p> <p><mathjax>#V_2=(349"mL"xx323.2cancel"K")/(295.2cancel"K")="382 mL"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/193434" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-must-charles-law-be-in-kelvins"> Why must Charles' law be in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-charles-law-formula"> What is Charles' law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/oxygen-gas-is-at-a-temperature-of-40-c-when-it-occupies-a-volume-of-2-3-liters-t"> Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.3 liters. 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A container of oxygen has a volume of 349 mL at a temperature of 22.0°C . What volume will the gas occupy at 50.0°C?

a9443125-6ddd-11ea-9260-ccda262736ce

https://socratic.org/questions/how-many-oxygen-atoms-in-1-44-x-10-5-kg-of-nitrogen-oxide

3.77 × 10^30

start physical_unit 2 3 number none qc_end physical_unit 10 11 5 8 mass qc_end end

[{"type":"physical unit","value":"Number [OF] oxygen atoms"}]

[{"type":"physical unit","value":"3.77 × 10^30"}]

[{"type":"physical unit","value":"Mass [OF] Nitrogen Oxide [=] \\pu{1.44 × 10^5 kg}"}]

<h1 class="questionTitle" itemprop="name">How many Oxygen atoms in 1.44 x 10^5 kg of Nitrogen Oxide?</h1>

3.77 × 10^30

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>But of course there is <mathjax>#NO#</mathjax> and <mathjax>#N_2O#</mathjax>.........</p> <p>For <mathjax>#NO_2#</mathjax>, we have a molecular mass of <mathjax>#46.01*g*mol^-1#</mathjax>.</p> <p>And thus <mathjax>#"Moles of"#</mathjax> <mathjax>#NO_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1.44xx10^8*g)/(46.01*g*mol^-1)#</mathjax></p> <p><mathjax>#-=3.13xx10^6*mol#</mathjax>....and thus <mathjax>#6.26xx10^6*mol#</mathjax> <mathjax>#"oxygen atoms."#</mathjax></p> <p>Then, you continue to solve for the number of oxygen atoms.</p> <p><mathjax>#6.26xx10^6*molxx6.022 * 10^23*mol^-1~= 4.0xx10^30#</mathjax> <mathjax>#"oxygen atoms"#</mathjax> which is nearer to the given answer.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, I will do it for <mathjax>#NO_2(g)#</mathjax>........and get over six million moles......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>But of course there is <mathjax>#NO#</mathjax> and <mathjax>#N_2O#</mathjax>.........</p> <p>For <mathjax>#NO_2#</mathjax>, we have a molecular mass of <mathjax>#46.01*g*mol^-1#</mathjax>.</p> <p>And thus <mathjax>#"Moles of"#</mathjax> <mathjax>#NO_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1.44xx10^8*g)/(46.01*g*mol^-1)#</mathjax></p> <p><mathjax>#-=3.13xx10^6*mol#</mathjax>....and thus <mathjax>#6.26xx10^6*mol#</mathjax> <mathjax>#"oxygen atoms."#</mathjax></p> <p>Then, you continue to solve for the number of oxygen atoms.</p> <p><mathjax>#6.26xx10^6*molxx6.022 * 10^23*mol^-1~= 4.0xx10^30#</mathjax> <mathjax>#"oxygen atoms"#</mathjax> which is nearer to the given answer.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many Oxygen atoms in 1.44 x 10^5 kg of Nitrogen Oxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="452832" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-17T20:57:05" itemprop="dateCreated"> Jul 17, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, I will do it for <mathjax>#NO_2(g)#</mathjax>........and get over six million moles......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>But of course there is <mathjax>#NO#</mathjax> and <mathjax>#N_2O#</mathjax>.........</p> <p>For <mathjax>#NO_2#</mathjax>, we have a molecular mass of <mathjax>#46.01*g*mol^-1#</mathjax>.</p> <p>And thus <mathjax>#"Moles of"#</mathjax> <mathjax>#NO_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1.44xx10^8*g)/(46.01*g*mol^-1)#</mathjax></p> <p><mathjax>#-=3.13xx10^6*mol#</mathjax>....and thus <mathjax>#6.26xx10^6*mol#</mathjax> <mathjax>#"oxygen atoms."#</mathjax></p> <p>Then, you continue to solve for the number of oxygen atoms.</p> <p><mathjax>#6.26xx10^6*molxx6.022 * 10^23*mol^-1~= 4.0xx10^30#</mathjax> <mathjax>#"oxygen atoms"#</mathjax> which is nearer to the given answer.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/452832" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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How many Oxygen atoms in 1.44 x 10^5 kg of Nitrogen Oxide?

a96df7f0-6ddd-11ea-86f9-ccda262736ce

https://socratic.org/questions/how-do-you-balance-fe-h-2so-4-fe-2-so-4-3-h-2

2 Fe + 3 H2SO4 -> Fe2(SO4)3 + 3 H2

start chemical_equation qc_end chemical_equation 4 10 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"2 Fe + 3 H2SO4 -> Fe2(SO4)3 + 3 H2"}]

[{"type":"chemical equation","value":"Fe + H2SO4 -> Fe2(SO4)3 + H2"}]

<h1 class="questionTitle" itemprop="name">How do you balance #Fe+H_2SO_4 -&gt; Fe_2(SO_4)_3 + H_2#?</h1>

2 Fe + 3 H2SO4 -> Fe2(SO4)3 + 3 H2

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by looking at the most complex compound, and balancing around that. In this case, its <mathjax>#Fe_2(SO_4)_(3(aq))#</mathjax>. </p> <p>We see that we need 2 Fe and 3 <mathjax>#SO_4#</mathjax> on the reactants side, so we add those in. After that, there is only an imbalance of <mathjax>#H_2#</mathjax>, which is easily fixed by adding a 3 to the products side. </p> <p>The general way to balance is by starting with the most complex compound first, and making sure the rest of the equation conforms to it (it's much harder to try and balance the more complex compound to the rest of the equation).</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2Fe_((s)) + 3H_2SO_(4(aq)) -&gt; Fe_2(SO_4)_(3(aq)) +#</mathjax> <mathjax>#3H_2#</mathjax>(g)</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by looking at the most complex compound, and balancing around that. In this case, its <mathjax>#Fe_2(SO_4)_(3(aq))#</mathjax>. </p> <p>We see that we need 2 Fe and 3 <mathjax>#SO_4#</mathjax> on the reactants side, so we add those in. After that, there is only an imbalance of <mathjax>#H_2#</mathjax>, which is easily fixed by adding a 3 to the products side. </p> <p>The general way to balance is by starting with the most complex compound first, and making sure the rest of the equation conforms to it (it's much harder to try and balance the more complex compound to the rest of the equation).</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you balance #Fe+H_2SO_4 -&gt; Fe_2(SO_4)_3 + H_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="316829" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/henry-w-2"><img alt="" class="" src="https://profilepictures.socratic.org/7IFCgaDHTbGDlVtThZyG_elephant_seal1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/henry-w-2"> Henry W. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-02T02:59:41" itemprop="dateCreated"> Oct 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2Fe_((s)) + 3H_2SO_(4(aq)) -&gt; Fe_2(SO_4)_(3(aq)) +#</mathjax> <mathjax>#3H_2#</mathjax>(g)</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by looking at the most complex compound, and balancing around that. In this case, its <mathjax>#Fe_2(SO_4)_(3(aq))#</mathjax>. </p> <p>We see that we need 2 Fe and 3 <mathjax>#SO_4#</mathjax> on the reactants side, so we add those in. After that, there is only an imbalance of <mathjax>#H_2#</mathjax>, which is easily fixed by adding a 3 to the products side. </p> <p>The general way to balance is by starting with the most complex compound first, and making sure the rest of the equation conforms to it (it's much harder to try and balance the more complex compound to the rest of the equation).</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/316829" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------&gt; H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -&gt; Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -&gt;# ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1507 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How do you balance #Fe+H_2SO_4 -&gt; Fe_2(SO_4)_3 + H_2#?

a867ea54-6ddd-11ea-9aeb-ccda262736ce

https://socratic.org/questions/how-many-moles-of-ch-3-3nh-are-in-6-0-g-of-ch-3-3nh

0.10 moles

start physical_unit 4 4 mole mol qc_end physical_unit 4 4 7 8 mass qc_end end

[{"type":"physical unit","value":"Mole [OF] (CH3)3NH+ [IN] moles"}]

[{"type":"physical unit","value":"0.10 moles"}]

[{"type":"physical unit","value":"Mass [OF] (CH3)3NH+ [=] \\pu{6.0 g}"}]

<h1 class="questionTitle" itemprop="name">How many moles of #(CH_3)_3NH^+# are in 6.0 g of #(CH_3)_3NH^+# ?</h1>

0.10 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to keep in mind here is that the <strong>charge</strong> of an ion <strong>does not</strong> affect its <strong>molar mass</strong>, so don't be confused by the fact that your polyatomic ion carries a <mathjax>#1+#</mathjax> overall charge. </p> <p>So, you're dealing with the <em>trimethylammonium cation</em>, <mathjax>#("CH"_3)_3"NH"^(+)#</mathjax>, which is formed when trimethylamine, <mathjax>#("CH"_3)_3"N"#</mathjax>, accepts a proton, <mathjax>#"H"^(+)#</mathjax>. </p> <p>Your starting point here will be to figure out the <strong>molar mass</strong> of the trimethylammonium cation by using the molar mass of trimethylamine, which is <a href="https://en.wikipedia.org/wiki/Trimethylamine" rel="nofollow">listed as </a></p> <blockquote> <p><mathjax>#M_("M" ("CH"_3)_3"N") = "59.11026 g mol"^(-1)#</mathjax></p> </blockquote> <p>So, the molar mass of the trimethylammonium cation must account for the <strong>extra proton</strong> that is added to the neutral compound. The molar mass of a proton is <strong>equal</strong> to the molar mass of a neutral hydrogen atom </p> <blockquote> <p><mathjax>#M_("M H") = "1.00794 g mol"^(-1)#</mathjax></p> </blockquote> <p>This means that the molar mass of the trimethylammonium cation will be </p> <blockquote> <p><mathjax>#M_("M"("CH"_3)_3"NH"^(+)) = "59.11026 g mol"^(-1) + "1.00794 g mol"^(-1)#</mathjax></p> <p><mathjax>#M_("M"("CH"_3)_3"NH"^(+)) = "60.11820 g mol"^(-1)#</mathjax></p> </blockquote> <p>Now, the <strong>molar mass</strong> of a substance tells you the mass of <strong>one mole</strong> of that substance. In this case, <strong>one mole</strong> of trimethylammonium cations has a mass of <mathjax>#"60.11820 g"#</mathjax>. </p> <p>This means that your <mathjax>#"6.0 g"#</mathjax> sample will contain </p> <blockquote> <p><mathjax>#6.0 color(red)(cancel(color(black)("g"))) * ("1 mole"color(white)(a)("CH"_3)_3"NH"^(+))/(60.11820color(red)(cancel(color(black)("g")))) = color(green)(|bar(ul(color(white)(a/a)color(black)("0.10 moles"color(white)(a)("CH"_3)_3"NH"^(+))color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of trimethylammonium cations. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.10 mole"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to keep in mind here is that the <strong>charge</strong> of an ion <strong>does not</strong> affect its <strong>molar mass</strong>, so don't be confused by the fact that your polyatomic ion carries a <mathjax>#1+#</mathjax> overall charge. </p> <p>So, you're dealing with the <em>trimethylammonium cation</em>, <mathjax>#("CH"_3)_3"NH"^(+)#</mathjax>, which is formed when trimethylamine, <mathjax>#("CH"_3)_3"N"#</mathjax>, accepts a proton, <mathjax>#"H"^(+)#</mathjax>. </p> <p>Your starting point here will be to figure out the <strong>molar mass</strong> of the trimethylammonium cation by using the molar mass of trimethylamine, which is <a href="https://en.wikipedia.org/wiki/Trimethylamine" rel="nofollow">listed as </a></p> <blockquote> <p><mathjax>#M_("M" ("CH"_3)_3"N") = "59.11026 g mol"^(-1)#</mathjax></p> </blockquote> <p>So, the molar mass of the trimethylammonium cation must account for the <strong>extra proton</strong> that is added to the neutral compound. The molar mass of a proton is <strong>equal</strong> to the molar mass of a neutral hydrogen atom </p> <blockquote> <p><mathjax>#M_("M H") = "1.00794 g mol"^(-1)#</mathjax></p> </blockquote> <p>This means that the molar mass of the trimethylammonium cation will be </p> <blockquote> <p><mathjax>#M_("M"("CH"_3)_3"NH"^(+)) = "59.11026 g mol"^(-1) + "1.00794 g mol"^(-1)#</mathjax></p> <p><mathjax>#M_("M"("CH"_3)_3"NH"^(+)) = "60.11820 g mol"^(-1)#</mathjax></p> </blockquote> <p>Now, the <strong>molar mass</strong> of a substance tells you the mass of <strong>one mole</strong> of that substance. In this case, <strong>one mole</strong> of trimethylammonium cations has a mass of <mathjax>#"60.11820 g"#</mathjax>. </p> <p>This means that your <mathjax>#"6.0 g"#</mathjax> sample will contain </p> <blockquote> <p><mathjax>#6.0 color(red)(cancel(color(black)("g"))) * ("1 mole"color(white)(a)("CH"_3)_3"NH"^(+))/(60.11820color(red)(cancel(color(black)("g")))) = color(green)(|bar(ul(color(white)(a/a)color(black)("0.10 moles"color(white)(a)("CH"_3)_3"NH"^(+))color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of trimethylammonium cations. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles of #(CH_3)_3NH^+# are in 6.0 g of #(CH_3)_3NH^+# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="283505" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-01T12:17:05" itemprop="dateCreated"> Jul 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.10 mole"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The thing to keep in mind here is that the <strong>charge</strong> of an ion <strong>does not</strong> affect its <strong>molar mass</strong>, so don't be confused by the fact that your polyatomic ion carries a <mathjax>#1+#</mathjax> overall charge. </p> <p>So, you're dealing with the <em>trimethylammonium cation</em>, <mathjax>#("CH"_3)_3"NH"^(+)#</mathjax>, which is formed when trimethylamine, <mathjax>#("CH"_3)_3"N"#</mathjax>, accepts a proton, <mathjax>#"H"^(+)#</mathjax>. </p> <p>Your starting point here will be to figure out the <strong>molar mass</strong> of the trimethylammonium cation by using the molar mass of trimethylamine, which is <a href="https://en.wikipedia.org/wiki/Trimethylamine" rel="nofollow">listed as </a></p> <blockquote> <p><mathjax>#M_("M" ("CH"_3)_3"N") = "59.11026 g mol"^(-1)#</mathjax></p> </blockquote> <p>So, the molar mass of the trimethylammonium cation must account for the <strong>extra proton</strong> that is added to the neutral compound. The molar mass of a proton is <strong>equal</strong> to the molar mass of a neutral hydrogen atom </p> <blockquote> <p><mathjax>#M_("M H") = "1.00794 g mol"^(-1)#</mathjax></p> </blockquote> <p>This means that the molar mass of the trimethylammonium cation will be </p> <blockquote> <p><mathjax>#M_("M"("CH"_3)_3"NH"^(+)) = "59.11026 g mol"^(-1) + "1.00794 g mol"^(-1)#</mathjax></p> <p><mathjax>#M_("M"("CH"_3)_3"NH"^(+)) = "60.11820 g mol"^(-1)#</mathjax></p> </blockquote> <p>Now, the <strong>molar mass</strong> of a substance tells you the mass of <strong>one mole</strong> of that substance. In this case, <strong>one mole</strong> of trimethylammonium cations has a mass of <mathjax>#"60.11820 g"#</mathjax>. </p> <p>This means that your <mathjax>#"6.0 g"#</mathjax> sample will contain </p> <blockquote> <p><mathjax>#6.0 color(red)(cancel(color(black)("g"))) * ("1 mole"color(white)(a)("CH"_3)_3"NH"^(+))/(60.11820color(red)(cancel(color(black)("g")))) = color(green)(|bar(ul(color(white)(a/a)color(black)("0.10 moles"color(white)(a)("CH"_3)_3"NH"^(+))color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of trimethylammonium cations. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/283505" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5404 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many moles of #(CH_3)_3NH^+# are in 6.0 g of #(CH_3)_3NH^+# ?

a924d334-6ddd-11ea-9500-ccda262736ce

https://socratic.org/questions/5988003c7c0149747280e953

8 Al(s) + 3 NO3- + 5 HO- + 18 H2O -> 8 Al(OH)4- + 3 NH3(aq)

start chemical_equation qc_end substance 2 3 qc_end substance 6 7 qc_end substance 13 13 qc_end substance 15 16 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"8 Al(s) + 3 NO3- + 5 HO- + 18 H2O -> 8 Al(OH)4- + 3 NH3(aq)"}]

[{"type":"substance name","value":"Aluminum metal"},{"type":"substance name","value":"Nitrate ion"},{"type":"substance name","value":"Ammonia"},{"type":"substance name","value":"Aluminum ion"}]

<h1 class="questionTitle" itemprop="name">How does aluminum metal react with nitrate ion under basic conditions to give ammonia, and aluminum ion?</h1>

8 Al(s) + 3 NO3- + 5 HO- + 18 H2O -> 8 Al(OH)4- + 3 NH3(aq)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Aluminum metal is oxidized to aluminate ion.......under basic conditions.....</p> <p><mathjax>#Al(s) +4HO^(-) rarr Al(OH)_4^(-)+3e^(-)#</mathjax> <mathjax>#(i)#</mathjax></p> <p>Nitrate ion, <mathjax>#stackrel(+V)N#</mathjax>, is reduced to ammonia......<mathjax>#stackrel(-III)N#</mathjax>.</p> <p><mathjax>#NO_3^(-) +9H^(+) + 8e^(-) rarr NH_3(aq) + 3H_2O#</mathjax> <mathjax>#(i)#</mathjax></p> <p>And because we deal with a basic medium, I am simply going to add <mathjax>#9xxHO^-#</mathjax> to each side.........</p> <p><mathjax>#NO_3^(-) +underbrace(9H^(+) + 9HO^(-))_(9H_2O) + 8e^(-) rarr NH_3(aq) + 3H_2O+9HO^-#</mathjax></p> <p>......to give finally.....</p> <p><mathjax>#NO_3^(-) +6H_2O + 8e^(-) rarr NH_3(aq) +9HO^-#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>And so we take <mathjax>#8xx(i) + 3xx(ii)#</mathjax></p> <p><mathjax>#3NO_3^(-) +18H_2O + 24e^(-) rarr 3NH_3(aq) +27HO^-#</mathjax> <mathjax>#+#</mathjax><br/> <mathjax>#8Al(s) +32HO^(-) rarr 8Al(OH)_4^(-)+24e^(-)#</mathjax></p> <p>And after cancelling common reagents.......</p> <p><mathjax>#3NO_3^(-) +18H_2O + cancel(24e^(-)) rarr 3NH_3(aq) +cancel(27HO^-)#</mathjax> <mathjax>#+#</mathjax><br/> <mathjax>#8Al(s) +cancel(32)5HO^(-) rarr 8Al(OH)_4^(-)+cancel(24e^(-))#</mathjax></p> <p>To give finally.....</p> <p><mathjax>#8Al(s)+3NO_3^(-) + 5HO^(-) + 18H_2O rarr 8Al(OH)_4^(-)+3NH_3(aq) #</mathjax></p> <p>Which I think is balanced with respect to mass and charge. Is it? Do not trust my 'rithmetic..........</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Nice redox equation here.......</p> <p><mathjax>#8Al(s)+3NO_3^(-) + 5HO^(-) + 18H_2O rarr 8Al(OH)_4^(-)+3NH_3(aq) #</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Aluminum metal is oxidized to aluminate ion.......under basic conditions.....</p> <p><mathjax>#Al(s) +4HO^(-) rarr Al(OH)_4^(-)+3e^(-)#</mathjax> <mathjax>#(i)#</mathjax></p> <p>Nitrate ion, <mathjax>#stackrel(+V)N#</mathjax>, is reduced to ammonia......<mathjax>#stackrel(-III)N#</mathjax>.</p> <p><mathjax>#NO_3^(-) +9H^(+) + 8e^(-) rarr NH_3(aq) + 3H_2O#</mathjax> <mathjax>#(i)#</mathjax></p> <p>And because we deal with a basic medium, I am simply going to add <mathjax>#9xxHO^-#</mathjax> to each side.........</p> <p><mathjax>#NO_3^(-) +underbrace(9H^(+) + 9HO^(-))_(9H_2O) + 8e^(-) rarr NH_3(aq) + 3H_2O+9HO^-#</mathjax></p> <p>......to give finally.....</p> <p><mathjax>#NO_3^(-) +6H_2O + 8e^(-) rarr NH_3(aq) +9HO^-#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>And so we take <mathjax>#8xx(i) + 3xx(ii)#</mathjax></p> <p><mathjax>#3NO_3^(-) +18H_2O + 24e^(-) rarr 3NH_3(aq) +27HO^-#</mathjax> <mathjax>#+#</mathjax><br/> <mathjax>#8Al(s) +32HO^(-) rarr 8Al(OH)_4^(-)+24e^(-)#</mathjax></p> <p>And after cancelling common reagents.......</p> <p><mathjax>#3NO_3^(-) +18H_2O + cancel(24e^(-)) rarr 3NH_3(aq) +cancel(27HO^-)#</mathjax> <mathjax>#+#</mathjax><br/> <mathjax>#8Al(s) +cancel(32)5HO^(-) rarr 8Al(OH)_4^(-)+cancel(24e^(-))#</mathjax></p> <p>To give finally.....</p> <p><mathjax>#8Al(s)+3NO_3^(-) + 5HO^(-) + 18H_2O rarr 8Al(OH)_4^(-)+3NH_3(aq) #</mathjax></p> <p>Which I think is balanced with respect to mass and charge. Is it? Do not trust my 'rithmetic..........</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How does aluminum metal react with nitrate ion under basic conditions to give ammonia, and aluminum ion?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/balancing-redox-equations-using-the-oxidation-number-method" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Redox Equations Using the Oxidation Number Method</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="461129" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-07T06:17:09" itemprop="dateCreated"> Aug 7, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Nice redox equation here.......</p> <p><mathjax>#8Al(s)+3NO_3^(-) + 5HO^(-) + 18H_2O rarr 8Al(OH)_4^(-)+3NH_3(aq) #</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Aluminum metal is oxidized to aluminate ion.......under basic conditions.....</p> <p><mathjax>#Al(s) +4HO^(-) rarr Al(OH)_4^(-)+3e^(-)#</mathjax> <mathjax>#(i)#</mathjax></p> <p>Nitrate ion, <mathjax>#stackrel(+V)N#</mathjax>, is reduced to ammonia......<mathjax>#stackrel(-III)N#</mathjax>.</p> <p><mathjax>#NO_3^(-) +9H^(+) + 8e^(-) rarr NH_3(aq) + 3H_2O#</mathjax> <mathjax>#(i)#</mathjax></p> <p>And because we deal with a basic medium, I am simply going to add <mathjax>#9xxHO^-#</mathjax> to each side.........</p> <p><mathjax>#NO_3^(-) +underbrace(9H^(+) + 9HO^(-))_(9H_2O) + 8e^(-) rarr NH_3(aq) + 3H_2O+9HO^-#</mathjax></p> <p>......to give finally.....</p> <p><mathjax>#NO_3^(-) +6H_2O + 8e^(-) rarr NH_3(aq) +9HO^-#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>And so we take <mathjax>#8xx(i) + 3xx(ii)#</mathjax></p> <p><mathjax>#3NO_3^(-) +18H_2O + 24e^(-) rarr 3NH_3(aq) +27HO^-#</mathjax> <mathjax>#+#</mathjax><br/> <mathjax>#8Al(s) +32HO^(-) rarr 8Al(OH)_4^(-)+24e^(-)#</mathjax></p> <p>And after cancelling common reagents.......</p> <p><mathjax>#3NO_3^(-) +18H_2O + cancel(24e^(-)) rarr 3NH_3(aq) +cancel(27HO^-)#</mathjax> <mathjax>#+#</mathjax><br/> <mathjax>#8Al(s) +cancel(32)5HO^(-) rarr 8Al(OH)_4^(-)+cancel(24e^(-))#</mathjax></p> <p>To give finally.....</p> <p><mathjax>#8Al(s)+3NO_3^(-) + 5HO^(-) + 18H_2O rarr 8Al(OH)_4^(-)+3NH_3(aq) #</mathjax></p> <p>Which I think is balanced with respect to mass and charge. Is it? Do not trust my 'rithmetic..........</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/461129" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-reactions-in-basic-solution"> How do you balance redox reactions in basic solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-equations-by-oxidation-number-method"> How do you balance redox equations by oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-equations-in-acidic-solutions"> How do you balance redox equations in acidic solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-method"> What is the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-balancing-redox-equations-using-the-oxidation-number-m"> What are some examples of balancing redox equations using the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-number-method-useful"> Why is the oxidation number method useful? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-necessary-to-break-the-equation-into-half-reactions-in-the-oxidation-numbe"> Is it necessary to break the equation into half reactions in the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-difference-between-the-oxidation-number-method-and-the-ion-electron-"> What is the difference between the oxidation number method and the ion-electron method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-balance-the-equation-using-the-oxidation-states-method-mno2-al-mn-al2o3"> Can you balance the equation using the oxidation states method MnO2+Al---&gt;Mn+Al2O3? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-this-redox-reaction-using-the-oxidation-number-method-fe2-aq-"> How do you balance this redox reaction using the oxidation number method? Fe2+(aq) + MnO4–(aq)... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/balancing-redox-equations-using-the-oxidation-number-method"> See all questions in Balancing Redox Equations Using the Oxidation Number Method </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 8598 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How does aluminum metal react with nitrate ion under basic conditions to give ammonia, and aluminum ion?

a9dc2664-6ddd-11ea-bbf3-ccda262736ce

https://socratic.org/questions/59691e727c014971a7702931

0.54 moles

start physical_unit 4 5 mole mol qc_end physical_unit 16 16 11 12 volume qc_end end

[{"type":"physical unit","value":"Mole [OF] sodium hydroxide [IN] moles"}]

[{"type":"physical unit","value":"0.54 moles"}]

[{"type":"physical unit","value":"Volume [OF] sodium hydroxide solution [=] \\pu{447.1 mL}"},{"type":"physical unit","value":"Molarity [OF] sodium hydroxide solution [=] \\pu{1.2 mol/L}"}]

<h1 class="questionTitle" itemprop="name">How many moles of sodium hydroxide are required to prepare a #447.1*mL# volume of a solution that is #1.20*mol*L^-1# in the solute?</h1>

0.54 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity"="Moles of solute"/"Volume of solution"#</mathjax></p> <p>And thus <mathjax>#"moles of solute"="volume of solution"xx"molarity"#</mathjax></p> <p>Is this clear? I am doing this problem dimensionally so that I know when to divide and when to multiply.........</p> <p>And so we take the product..........(given that <mathjax>#1*mL-=10^-3L#</mathjax>)...</p> <p><mathjax>#447.1xx10^-3*cancelLxx1.20*mol*cancel(L^-1)=0.537*mol#</mathjax>.</p> <p>We can even be more explicit than this and quote the mass of <mathjax>#NaOH#</mathjax> required for this solution........</p> <p><mathjax>#"Mass of NaOH"=0.537*molxx40.0*g*mol^-1=21.5*g#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We need a bit over <mathjax>#0.5*mol#</mathjax>..............</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity"="Moles of solute"/"Volume of solution"#</mathjax></p> <p>And thus <mathjax>#"moles of solute"="volume of solution"xx"molarity"#</mathjax></p> <p>Is this clear? I am doing this problem dimensionally so that I know when to divide and when to multiply.........</p> <p>And so we take the product..........(given that <mathjax>#1*mL-=10^-3L#</mathjax>)...</p> <p><mathjax>#447.1xx10^-3*cancelLxx1.20*mol*cancel(L^-1)=0.537*mol#</mathjax>.</p> <p>We can even be more explicit than this and quote the mass of <mathjax>#NaOH#</mathjax> required for this solution........</p> <p><mathjax>#"Mass of NaOH"=0.537*molxx40.0*g*mol^-1=21.5*g#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles of sodium hydroxide are required to prepare a #447.1*mL# volume of a solution that is #1.20*mol*L^-1# in the solute?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="451527" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-14T20:38:31" itemprop="dateCreated"> Jul 14, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We need a bit over <mathjax>#0.5*mol#</mathjax>..............</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity"="Moles of solute"/"Volume of solution"#</mathjax></p> <p>And thus <mathjax>#"moles of solute"="volume of solution"xx"molarity"#</mathjax></p> <p>Is this clear? I am doing this problem dimensionally so that I know when to divide and when to multiply.........</p> <p>And so we take the product..........(given that <mathjax>#1*mL-=10^-3L#</mathjax>)...</p> <p><mathjax>#447.1xx10^-3*cancelLxx1.20*mol*cancel(L^-1)=0.537*mol#</mathjax>.</p> <p>We can even be more explicit than this and quote the mass of <mathjax>#NaOH#</mathjax> required for this solution........</p> <p><mathjax>#"Mass of NaOH"=0.537*molxx40.0*g*mol^-1=21.5*g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/451527" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1146 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many moles of sodium hydroxide are required to prepare a #447.1*mL# volume of a solution that is #1.20*mol*L^-1# in the solute?

aaca9952-6ddd-11ea-bf9c-ccda262736ce

https://socratic.org/questions/what-is-the-formula-of-aluminum-phosphate

AlPO4

start chemical_formula qc_end substance 5 6 qc_end end

[{"type":"other","value":"Chemical Formula [OF] aluminum phosphate [IN] default"}]

[{"type":"chemical equation","value":"AlPO4"}]

[{"type":"substance name","value":"Aluminum phosphate"}]

<h1 class="questionTitle" itemprop="name">What is the formula of aluminum phosphate?</h1>

AlPO4

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The formula for an ionic compound is called a formula unit, which is the lowest whole-number ratio of ions in the compound, which also makes it an empirical formula. This is because <a href="https://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compounds</a> do consist of individual molecules.</p> <p>The overall charge of an ionic compound must be zero. So the sum of the positive and negative ions must equal zero. </p> <p>The formula for the aluminum cation is <mathjax>#"Al"^(3+)"#</mathjax>, and the formula for the phosphate anion is <mathjax>#"PO"_4""^(3-)"#</mathjax>. So the formula unit for aluminum phosphate represents a <mathjax>#1:1#</mathjax> ratio of aluminum and phosphate ions, which is represented as <mathjax>#"AlPO"_4"#</mathjax>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The formula unit for aluminum phosphate is <mathjax>#"AlPO"_4"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The formula for an ionic compound is called a formula unit, which is the lowest whole-number ratio of ions in the compound, which also makes it an empirical formula. This is because <a href="https://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compounds</a> do consist of individual molecules.</p> <p>The overall charge of an ionic compound must be zero. So the sum of the positive and negative ions must equal zero. </p> <p>The formula for the aluminum cation is <mathjax>#"Al"^(3+)"#</mathjax>, and the formula for the phosphate anion is <mathjax>#"PO"_4""^(3-)"#</mathjax>. So the formula unit for aluminum phosphate represents a <mathjax>#1:1#</mathjax> ratio of aluminum and phosphate ions, which is represented as <mathjax>#"AlPO"_4"#</mathjax>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the formula of aluminum phosphate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="330059" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-02T04:09:03" itemprop="dateCreated"> Nov 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The formula unit for aluminum phosphate is <mathjax>#"AlPO"_4"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The formula for an ionic compound is called a formula unit, which is the lowest whole-number ratio of ions in the compound, which also makes it an empirical formula. This is because <a href="https://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compounds</a> do consist of individual molecules.</p> <p>The overall charge of an ionic compound must be zero. So the sum of the positive and negative ions must equal zero. </p> <p>The formula for the aluminum cation is <mathjax>#"Al"^(3+)"#</mathjax>, and the formula for the phosphate anion is <mathjax>#"PO"_4""^(3-)"#</mathjax>. So the formula unit for aluminum phosphate represents a <mathjax>#1:1#</mathjax> ratio of aluminum and phosphate ions, which is represented as <mathjax>#"AlPO"_4"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/330059" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-chloride"> What is the ionic formula for calcium chloride? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-oxide"> What is the ionic formula for calcium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-lithium-oxide"> What is the ionic formula for lithium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-formula-for-ionic-compounds"> How do you write the formula for ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-correctly-write-the-ions-present-in-sn-no3-2"> How do I write #Sn(NO_3)_2# in Ionic formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-an-ionic-compound"> What is the empirical formula for an ionic compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-for-chorate"> What is the molecular formula for chorate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5363023c02bf343b2ee7086b"> Question #7086b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-polyatomic-ions-covalent-1"> Why are polyatomic ions covalent? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas"> See all questions in Writing Ionic Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 25740 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the formula of aluminum phosphate?

a9e217f8-6ddd-11ea-b65a-ccda262736ce

https://socratic.org/questions/how-many-moles-of-n-2-reacted-if-0-75-mol-of-nh-3-is-produced

0.38 moles

start physical_unit 4 4 mole mol qc_end physical_unit 10 10 7 8 mole qc_end end

[{"type":"physical unit","value":"Mole [OF] N2 [IN] moles"}]

[{"type":"physical unit","value":"0.38 moles"}]

[{"type":"physical unit","value":"Mole [OF] NH3 [=] \\pu{0.75 mol}"}]

<h1 class="questionTitle" itemprop="name">How many moles of #N_2# reacted if 0.75 mol of #NH_3# is produced?</h1>

0.38 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given the stoichiometrically balanced equation, if <mathjax>#0.75*mol#</mathjax> ammonia were produced, then at least <mathjax>#(0.75*mol)/2#</mathjax> dinitrogen reacted. Is this clear?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1/2N_2(g) + 3/2H_2(g) rarr NH_3(g)#</mathjax>; <mathjax>#0.38*mol#</mathjax> <mathjax>#N_2#</mathjax> reacted.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given the stoichiometrically balanced equation, if <mathjax>#0.75*mol#</mathjax> ammonia were produced, then at least <mathjax>#(0.75*mol)/2#</mathjax> dinitrogen reacted. Is this clear?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles of #N_2# reacted if 0.75 mol of #NH_3# is produced?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="330674" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-03T10:13:28" itemprop="dateCreated"> Nov 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1/2N_2(g) + 3/2H_2(g) rarr NH_3(g)#</mathjax>; <mathjax>#0.38*mol#</mathjax> <mathjax>#N_2#</mathjax> reacted.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given the stoichiometrically balanced equation, if <mathjax>#0.75*mol#</mathjax> ammonia were produced, then at least <mathjax>#(0.75*mol)/2#</mathjax> dinitrogen reacted. Is this clear?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/330674" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2950 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many moles of #N_2# reacted if 0.75 mol of #NH_3# is produced?

aad62ba6-6ddd-11ea-b7af-ccda262736ce

https://socratic.org/questions/when-30-0-moles-of-zinc-reacts-with-excess-h-3po-4-how-many-grams-of-hydrogen-ar

30 grams

start physical_unit 13 13 mass g qc_end physical_unit 4 4 1 2 mole qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Mass [OF] hydrogen [IN] grams"}]

[{"type":"physical unit","value":"30 grams"}]

[{"type":"physical unit","value":"Mole [OF] zinc [=] \\pu{30.0 moles}"},{"type":"other","value":"Excess H3PO4."}]

<h1 class="questionTitle" itemprop="name">When 30.0 moles of zinc reacts with excess #H_3PO_4#, how many grams of hydrogen are produced?</h1>

30 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#3"Zn" + 2"H"_3"PO"_4 -&gt; "Zn"_3("PO"_4)_2 + 3"H"_2#</mathjax> </p> <p>The molar ratio of zinc: hydrogen is <mathjax>#3:3#</mathjax> so moles of zinc = moles of hydrogen.</p> <p><mathjax>#"m"="nM"=30xx1=30#</mathjax> <mathjax>#"g"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#30#</mathjax> <mathjax>#"g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#3"Zn" + 2"H"_3"PO"_4 -&gt; "Zn"_3("PO"_4)_2 + 3"H"_2#</mathjax> </p> <p>The molar ratio of zinc: hydrogen is <mathjax>#3:3#</mathjax> so moles of zinc = moles of hydrogen.</p> <p><mathjax>#"m"="nM"=30xx1=30#</mathjax> <mathjax>#"g"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">When 30.0 moles of zinc reacts with excess #H_3PO_4#, how many grams of hydrogen are produced?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="346626" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/abdur-r"><img alt="" class="" src="https://profilepictures.socratic.org/YXIUDMM0SoZAxTdY3kn6_niagara_falls_fog_water_height_6376_3840x2160.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/abdur-r"> Monzur R. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-04T18:00:01" itemprop="dateCreated"> Dec 4, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#30#</mathjax> <mathjax>#"g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#3"Zn" + 2"H"_3"PO"_4 -&gt; "Zn"_3("PO"_4)_2 + 3"H"_2#</mathjax> </p> <p>The molar ratio of zinc: hydrogen is <mathjax>#3:3#</mathjax> so moles of zinc = moles of hydrogen.</p> <p><mathjax>#"m"="nM"=30xx1=30#</mathjax> <mathjax>#"g"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/346626" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1061 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

When 30.0 moles of zinc reacts with excess #H_3PO_4#, how many grams of hydrogen are produced?

ad212ad0-6ddd-11ea-9469-ccda262736ce

https://socratic.org/questions/58ffebf97c01495fe00a53e4

16.74 grams

start physical_unit 10 10 mass g qc_end physical_unit 10 10 6 7 volume qc_end physical_unit 10 10 16 17 pressure qc_end end

[{"type":"physical unit","value":"Mass [OF] ethane [IN] grams"}]

[{"type":"physical unit","value":"16.74 grams"}]

[{"type":"physical unit","value":"Volume [OF] ethane [=] \\pu{22.41 L}"},{"type":"physical unit","value":"Pressure [OF] ethane [=] \\pu{780 mmHg}"}]

<h1 class="questionTitle" itemprop="name">What is the mass of a #22.41*L# volume of ethane that has a pressure of #780*mm*Hg#?</h1>

16.74 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#1*atm#</mathjax> pressure will support a column of mercury that is <mathjax>#760*mm*Hg#</mathjax> high. Measurement of pressure in <mathjax>#mm*Hg#</mathjax> is thus useful (because a mercury column is easy to set up!), because it can measure a pressure of about an atmosphere, or very LOW pressures, such as when you do a vacuum distillation, and evacuate the system out to <mathjax>#0.01*mm*Hg#</mathjax>.</p> <p>If you attempt to measure pressures much HIGHER than <mathjax>#1 *atm#</mathjax> with a mercury column, YOU WILL GET metallic mercury all over the laboratory, and this is a major clean-up job. Nevertheless, mercury barometers sometimes read a pressure of slightly greater than <mathjax>#760*mm#</mathjax>. </p> <p>So let's convert the pressure to <mathjax>#"atmospheres"#</mathjax>.</p> <p><mathjax>#"Pressure"=(780*mm*Hg)/(760*mm*Hg*atm^-1)=1.026*atm#</mathjax>.</p> <p>The Ideal Gas Equation tells us that <mathjax>#n=(PV)/(RT)#</mathjax></p> <p>i.e. <mathjax>#"Mass"/"Molar mass"=(PV)/(RT)#</mathjax></p> <p>OR <mathjax>#"Mass"="Molar Mass"xx(PV)/(RT)#</mathjax></p> <p>And now we fill in the <mathjax>#"noombers"#</mathjax>:</p> <p><mathjax>#"Mass"=(16.33*g*cancel(mol^-1)xx1.026*cancel(atm)xx22.410*cancelL)/(0.0821*cancel(L*atm*K^-1*mol^-1)xx273.13*cancelK)#</mathjax></p> <p><mathjax>#=??*g#</mathjax></p> <p>We get an answer in <mathjax>#"grams"#</mathjax> so we must be doing something right. </p> <p>We could have also used the fact that under standard conditions of <mathjax>#273*K#</mathjax>, and <mathjax>#1*atm#</mathjax>, ONE mol of Ideal Gas will occupy <mathjax>#22.4*L#</mathjax>. And we know the molar mass of methane. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We get about <mathjax>#16*g#</mathjax>, i.e. a molar quantity.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#1*atm#</mathjax> pressure will support a column of mercury that is <mathjax>#760*mm*Hg#</mathjax> high. Measurement of pressure in <mathjax>#mm*Hg#</mathjax> is thus useful (because a mercury column is easy to set up!), because it can measure a pressure of about an atmosphere, or very LOW pressures, such as when you do a vacuum distillation, and evacuate the system out to <mathjax>#0.01*mm*Hg#</mathjax>.</p> <p>If you attempt to measure pressures much HIGHER than <mathjax>#1 *atm#</mathjax> with a mercury column, YOU WILL GET metallic mercury all over the laboratory, and this is a major clean-up job. Nevertheless, mercury barometers sometimes read a pressure of slightly greater than <mathjax>#760*mm#</mathjax>. </p> <p>So let's convert the pressure to <mathjax>#"atmospheres"#</mathjax>.</p> <p><mathjax>#"Pressure"=(780*mm*Hg)/(760*mm*Hg*atm^-1)=1.026*atm#</mathjax>.</p> <p>The Ideal Gas Equation tells us that <mathjax>#n=(PV)/(RT)#</mathjax></p> <p>i.e. <mathjax>#"Mass"/"Molar mass"=(PV)/(RT)#</mathjax></p> <p>OR <mathjax>#"Mass"="Molar Mass"xx(PV)/(RT)#</mathjax></p> <p>And now we fill in the <mathjax>#"noombers"#</mathjax>:</p> <p><mathjax>#"Mass"=(16.33*g*cancel(mol^-1)xx1.026*cancel(atm)xx22.410*cancelL)/(0.0821*cancel(L*atm*K^-1*mol^-1)xx273.13*cancelK)#</mathjax></p> <p><mathjax>#=??*g#</mathjax></p> <p>We get an answer in <mathjax>#"grams"#</mathjax> so we must be doing something right. </p> <p>We could have also used the fact that under standard conditions of <mathjax>#273*K#</mathjax>, and <mathjax>#1*atm#</mathjax>, ONE mol of Ideal Gas will occupy <mathjax>#22.4*L#</mathjax>. And we know the molar mass of methane. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the mass of a #22.41*L# volume of ethane that has a pressure of #780*mm*Hg#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="413008" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-26T05:32:40" itemprop="dateCreated"> Apr 26, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We get about <mathjax>#16*g#</mathjax>, i.e. a molar quantity.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#1*atm#</mathjax> pressure will support a column of mercury that is <mathjax>#760*mm*Hg#</mathjax> high. Measurement of pressure in <mathjax>#mm*Hg#</mathjax> is thus useful (because a mercury column is easy to set up!), because it can measure a pressure of about an atmosphere, or very LOW pressures, such as when you do a vacuum distillation, and evacuate the system out to <mathjax>#0.01*mm*Hg#</mathjax>.</p> <p>If you attempt to measure pressures much HIGHER than <mathjax>#1 *atm#</mathjax> with a mercury column, YOU WILL GET metallic mercury all over the laboratory, and this is a major clean-up job. Nevertheless, mercury barometers sometimes read a pressure of slightly greater than <mathjax>#760*mm#</mathjax>. </p> <p>So let's convert the pressure to <mathjax>#"atmospheres"#</mathjax>.</p> <p><mathjax>#"Pressure"=(780*mm*Hg)/(760*mm*Hg*atm^-1)=1.026*atm#</mathjax>.</p> <p>The Ideal Gas Equation tells us that <mathjax>#n=(PV)/(RT)#</mathjax></p> <p>i.e. <mathjax>#"Mass"/"Molar mass"=(PV)/(RT)#</mathjax></p> <p>OR <mathjax>#"Mass"="Molar Mass"xx(PV)/(RT)#</mathjax></p> <p>And now we fill in the <mathjax>#"noombers"#</mathjax>:</p> <p><mathjax>#"Mass"=(16.33*g*cancel(mol^-1)xx1.026*cancel(atm)xx22.410*cancelL)/(0.0821*cancel(L*atm*K^-1*mol^-1)xx273.13*cancelK)#</mathjax></p> <p><mathjax>#=??*g#</mathjax></p> <p>We get an answer in <mathjax>#"grams"#</mathjax> so we must be doing something right. </p> <p>We could have also used the fact that under standard conditions of <mathjax>#273*K#</mathjax>, and <mathjax>#1*atm#</mathjax>, ONE mol of Ideal Gas will occupy <mathjax>#22.4*L#</mathjax>. And we know the molar mass of methane. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/413008" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1378 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the mass of a #22.41*L# volume of ethane that has a pressure of #780*mm*Hg#?

ac4b12be-6ddd-11ea-be83-ccda262736ce

https://socratic.org/questions/a-50-00-ml-1-5-m-of-naoh-titrated-with-25-00-ml-of-h-3po-4-aq-what-is-the-concen

1.50 M

start physical_unit 20 21 concentration mol/l qc_end physical_unit 6 6 3 4 concentration qc_end physical_unit 21 21 1 2 volume qc_end physical_unit 12 12 9 10 volume qc_end end

[{"type":"physical unit","value":"Concentration [OF] H3PO4 solution [IN] M"}]

[{"type":"physical unit","value":"1.50 M"}]

[{"type":"physical unit","value":"Concentration [OF] NaOH solution [=] \\pu{1.5 M}"},{"type":"physical unit","value":"Volume [OF] NaOH solution [=] \\pu{50.00 mL}"},{"type":"physical unit","value":"Volume [OF] H3PO4(aq) [=] \\pu{25.00 ml}"}]

<h1 class="questionTitle" itemprop="name">A 50.00 mL 1.5 M of #NaOH# titrated with 25.00 ml of #H_3PO_4# (aq). What is the concentration of the is #H_3PO_4# solution? </h1>

1.50 M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We follow the stoichiometric reaction......</p> <p><mathjax>#H_3PO_4(aq) + 2NaOH(aq) rarr Na_2HPO_4(aq) + 2H_2O(l)#</mathjax></p> <p>And it is a fact that phosphoric acid acts as DIACID in aqueous solution. <mathjax>#Na_3PO_4#</mathjax> WILL NOT BE ACCESSED even at high <mathjax>#pH#</mathjax>.</p> <p><mathjax>#"Moles of NaOH"=50.00xx10^-3Lxx1.5*mol*L^-1=0.075*mol#</mathjax>.....</p> <p>And thus, with respect to <mathjax>#H_3PO_4#</mathjax>, there was a <mathjax>#(0.075*mol)/2#</mathjax> molar quantity.......</p> <p>And <mathjax>#[H_3PO_4]=((0.075*mol)/2)/(25.00*mLxx10^-3*L*mL^-1)#</mathjax></p> <p><mathjax>#=(0.075*mol)/2#</mathjax> of course, we might have been able to nut this result out directly, had we been on the ball in the first instance. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[H_3PO_4]-=1.50*mol*L^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We follow the stoichiometric reaction......</p> <p><mathjax>#H_3PO_4(aq) + 2NaOH(aq) rarr Na_2HPO_4(aq) + 2H_2O(l)#</mathjax></p> <p>And it is a fact that phosphoric acid acts as DIACID in aqueous solution. <mathjax>#Na_3PO_4#</mathjax> WILL NOT BE ACCESSED even at high <mathjax>#pH#</mathjax>.</p> <p><mathjax>#"Moles of NaOH"=50.00xx10^-3Lxx1.5*mol*L^-1=0.075*mol#</mathjax>.....</p> <p>And thus, with respect to <mathjax>#H_3PO_4#</mathjax>, there was a <mathjax>#(0.075*mol)/2#</mathjax> molar quantity.......</p> <p>And <mathjax>#[H_3PO_4]=((0.075*mol)/2)/(25.00*mLxx10^-3*L*mL^-1)#</mathjax></p> <p><mathjax>#=(0.075*mol)/2#</mathjax> of course, we might have been able to nut this result out directly, had we been on the ball in the first instance. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A 50.00 mL 1.5 M of #NaOH# titrated with 25.00 ml of #H_3PO_4# (aq). What is the concentration of the is #H_3PO_4# solution? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/titration-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Titration Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="459334" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-02T15:08:28" itemprop="dateCreated"> Aug 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[H_3PO_4]-=1.50*mol*L^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We follow the stoichiometric reaction......</p> <p><mathjax>#H_3PO_4(aq) + 2NaOH(aq) rarr Na_2HPO_4(aq) + 2H_2O(l)#</mathjax></p> <p>And it is a fact that phosphoric acid acts as DIACID in aqueous solution. <mathjax>#Na_3PO_4#</mathjax> WILL NOT BE ACCESSED even at high <mathjax>#pH#</mathjax>.</p> <p><mathjax>#"Moles of NaOH"=50.00xx10^-3Lxx1.5*mol*L^-1=0.075*mol#</mathjax>.....</p> <p>And thus, with respect to <mathjax>#H_3PO_4#</mathjax>, there was a <mathjax>#(0.075*mol)/2#</mathjax> molar quantity.......</p> <p>And <mathjax>#[H_3PO_4]=((0.075*mol)/2)/(25.00*mLxx10^-3*L*mL^-1)#</mathjax></p> <p><mathjax>#=(0.075*mol)/2#</mathjax> of course, we might have been able to nut this result out directly, had we been on the ball in the first instance. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/459334" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-acid-base-titration-calculations"> How do you do acid base titration calculations? 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A 50.00 mL 1.5 M of #NaOH# titrated with 25.00 ml of #H_3PO_4# (aq). What is the concentration of the is #H_3PO_4# solution?

abfef813-6ddd-11ea-904d-ccda262736ce

https://socratic.org/questions/a-0-3200-g-sample-of-a-carboxylic-acid-is-burned-in-oxygen-producing-0-5706-g-of

C3H6O2

start chemical_formula qc_end physical_unit 6 7 1 2 mass qc_end physical_unit 16 16 13 14 mass qc_end physical_unit 21 21 18 19 mass qc_end substance 11 11 qc_end end

[{"type":"other","value":"Chemical Formula [OF] carboxylic acid [IN] empirical"}]

[{"type":"chemical equation","value":"C3H6O2"}]

[{"type":"physical unit","value":"Mass [OF] carboxylic acid sample [=] \\pu{0.3200 g}"},{"type":"physical unit","value":"Mass [OF] CO2 [=] \\pu{0.5706 g}"},{"type":"physical unit","value":"Mass [OF] H2O [=] \\pu{0.2349 g}"},{"type":"substance name","value":"Oxygen"}]

<h1 class="questionTitle" itemprop="name">A 0.3200 g sample of a carboxylic acid is burned in oxygen, producing 0.5706 g of CO2 and 0.2349 g of H2O. How would you determine the empirical formula of carboxylic acid?</h1>

C3H6O2

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to figure out how much <em>carbon</em> and <em>hydrogen</em> were present in the initial sample, then use the sample's mass to figure out how much <strong>oxygen</strong> it contained. </p> <p>Once you know how many grams of each element you had in the original sample, use the <em>molar masses</em> of the three <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> to determine how many <em>moles</em> of each you have. </p> <p>So, what you need to do is figure out the <a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of hydrogen in water and of carbon in carbon dioxide. This will allow you to figure out how many grams of hydrogen and carbon, respectively, were produced by the combustion reaction. </p> <p>As you know, <strong>one mole</strong> of water, <mathjax>#"H"_2"O"#</mathjax>, contains <mathjax>#2#</mathjax> <strong>moles</strong> of hydrogen. This means that the <a href="http://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of hydrogen in water will be </p> <blockquote> <p><mathjax>#(2 xx 1.00794 color(red)(cancel(color(black)("g/mol"))))/(18.015color(red)(cancel(color(black)("g/mol")))) xx 100 = "11.19% H"#</mathjax></p> </blockquote> <p>What this means is that <strong>every</strong> <mathjax>#"100 g"#</mathjax> of water will contain <mathjax>#"11.19 g"#</mathjax> of hydrogen. In your case, the <mathjax>#"0.2349-g"#</mathjax> sample of water will contain </p> <blockquote> <p><mathjax>#0.2349 color(red)(cancel(color(black)("g water"))) * "11.19 g H"/(100color(red)(cancel(color(black)("g water")))) = "0.026285 g H"#</mathjax></p> </blockquote> <p>Similarly, <strong>one mole</strong> of carbon dioxide, <mathjax>#"CO"_2#</mathjax>, contains <strong>one mole</strong> of carbon. The percent composition of carbon in carbon dioxide will be </p> <blockquote> <p><mathjax>#(1 xx 12.011 color(red)(cancel(color(black)("g/mol"))))/(44.01 color(red)(cancel(color(black)("g/mol")))) xx 100 = "27.29% C"#</mathjax></p> </blockquote> <p>Once again, this tells you that <strong>every</strong> <mathjax>#"100 g"#</mathjax> of carbon dioxide will contain <mathjax>#"27.29 g"#</mathjax> of carbon. In your case, you will have</p> <blockquote> <p><mathjax>#0.5706 color(red)(cancel(color(black)("g H"_2"O"))) * "27.29 g C"/(100color(red)(cancel(color(black)("g H"_2"O")))) = "0.15572 g C"#</mathjax></p> </blockquote> <p>The mass of carbon + hydrogen originally present in the carboxylic acid sample will be </p> <blockquote> <p><mathjax>#m_"C + H" = "0.026285 g" + "0.15572 g" = "0.18201 g"#</mathjax></p> </blockquote> <p>The initial mass of the sample was equal to <mathjax>#"0.3200 g"#</mathjax>. This tells you that the sample also contained </p> <blockquote> <p><mathjax>#m_"oxygen" = "0.3200 g" - "0.18201 g" = "0.13799 g O"#</mathjax></p> </blockquote> <p>So, now that you know how many grams of each element were present in the initial sample, use their <em>molar masses</em> to convert these to <em>moles</em></p> <blockquote> <p><mathjax>#"For C: " (0.15572 color(red)(cancel(color(black)("g"))))/(12.011color(red)(cancel(color(black)("g")))/"mol") = "0.012965 moles C"#</mathjax></p> <p><mathjax>#"For H: " (0.026285 color(red)(cancel(color(black)("g"))))/(1.00794 color(red)(cancel(color(black)("g")))/"mol") = "0.026078 moles H"#</mathjax></p> <p><mathjax>#"For O: " (0.13799 color(red)(cancel(color(black)("g"))))/(15.9994color(red)(cancel(color(black)("g")))/"mol") = "0.0086247 moles O"#</mathjax></p> </blockquote> <p>Now, to get the compound's <a href="https://socratic.org/chemistry/the-mole-concept/empirical-and-molecular-formulas">empirical formula</a>, you need to find the <strong>smallest whole number ratio</strong> that exists between the number of moles of each element in the compound. </p> <p>To do that, divide these values by the <em>smallest one</em> to get</p> <blockquote> <p><mathjax>#"For C: " (0.012965 color(red)(cancel(color(black)("moles"))))/(0.0086247 color(red)(cancel(color(black)("moles")))) = 1.5032 ~~ 1.5#</mathjax></p> <p><mathjax>#"For H: " (0.026078 color(red)(cancel(color(black)("moles"))))/(0.0086247 color(red)(cancel(color(black)("moles")))) = 3.0236 ~~ 3#</mathjax></p> <p><mathjax>#"For O: " (0.0086247 color(red)(cancel(color(black)("moles"))))/(0.0086247 color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> </blockquote> <p>This means that you have </p> <blockquote> <p><mathjax>#"C"_1.5"H"_3"O"_1#</mathjax></p> </blockquote> <p>Since you're looking for the smallest <strong>whole number ratio</strong> that exists between the elements, multiply each subscript by <mathjax>#2#</mathjax> to get</p> <blockquote> <p><mathjax>#("C"_1.5"H"_3"O"_1)_2 implies color(green)("C"_3"H"_6"O"_2)#</mathjax></p> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"C"_3"H"_6"O"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to figure out how much <em>carbon</em> and <em>hydrogen</em> were present in the initial sample, then use the sample's mass to figure out how much <strong>oxygen</strong> it contained. </p> <p>Once you know how many grams of each element you had in the original sample, use the <em>molar masses</em> of the three <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> to determine how many <em>moles</em> of each you have. </p> <p>So, what you need to do is figure out the <a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of hydrogen in water and of carbon in carbon dioxide. This will allow you to figure out how many grams of hydrogen and carbon, respectively, were produced by the combustion reaction. </p> <p>As you know, <strong>one mole</strong> of water, <mathjax>#"H"_2"O"#</mathjax>, contains <mathjax>#2#</mathjax> <strong>moles</strong> of hydrogen. This means that the <a href="http://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of hydrogen in water will be </p> <blockquote> <p><mathjax>#(2 xx 1.00794 color(red)(cancel(color(black)("g/mol"))))/(18.015color(red)(cancel(color(black)("g/mol")))) xx 100 = "11.19% H"#</mathjax></p> </blockquote> <p>What this means is that <strong>every</strong> <mathjax>#"100 g"#</mathjax> of water will contain <mathjax>#"11.19 g"#</mathjax> of hydrogen. In your case, the <mathjax>#"0.2349-g"#</mathjax> sample of water will contain </p> <blockquote> <p><mathjax>#0.2349 color(red)(cancel(color(black)("g water"))) * "11.19 g H"/(100color(red)(cancel(color(black)("g water")))) = "0.026285 g H"#</mathjax></p> </blockquote> <p>Similarly, <strong>one mole</strong> of carbon dioxide, <mathjax>#"CO"_2#</mathjax>, contains <strong>one mole</strong> of carbon. The percent composition of carbon in carbon dioxide will be </p> <blockquote> <p><mathjax>#(1 xx 12.011 color(red)(cancel(color(black)("g/mol"))))/(44.01 color(red)(cancel(color(black)("g/mol")))) xx 100 = "27.29% C"#</mathjax></p> </blockquote> <p>Once again, this tells you that <strong>every</strong> <mathjax>#"100 g"#</mathjax> of carbon dioxide will contain <mathjax>#"27.29 g"#</mathjax> of carbon. In your case, you will have</p> <blockquote> <p><mathjax>#0.5706 color(red)(cancel(color(black)("g H"_2"O"))) * "27.29 g C"/(100color(red)(cancel(color(black)("g H"_2"O")))) = "0.15572 g C"#</mathjax></p> </blockquote> <p>The mass of carbon + hydrogen originally present in the carboxylic acid sample will be </p> <blockquote> <p><mathjax>#m_"C + H" = "0.026285 g" + "0.15572 g" = "0.18201 g"#</mathjax></p> </blockquote> <p>The initial mass of the sample was equal to <mathjax>#"0.3200 g"#</mathjax>. This tells you that the sample also contained </p> <blockquote> <p><mathjax>#m_"oxygen" = "0.3200 g" - "0.18201 g" = "0.13799 g O"#</mathjax></p> </blockquote> <p>So, now that you know how many grams of each element were present in the initial sample, use their <em>molar masses</em> to convert these to <em>moles</em></p> <blockquote> <p><mathjax>#"For C: " (0.15572 color(red)(cancel(color(black)("g"))))/(12.011color(red)(cancel(color(black)("g")))/"mol") = "0.012965 moles C"#</mathjax></p> <p><mathjax>#"For H: " (0.026285 color(red)(cancel(color(black)("g"))))/(1.00794 color(red)(cancel(color(black)("g")))/"mol") = "0.026078 moles H"#</mathjax></p> <p><mathjax>#"For O: " (0.13799 color(red)(cancel(color(black)("g"))))/(15.9994color(red)(cancel(color(black)("g")))/"mol") = "0.0086247 moles O"#</mathjax></p> </blockquote> <p>Now, to get the compound's <a href="https://socratic.org/chemistry/the-mole-concept/empirical-and-molecular-formulas">empirical formula</a>, you need to find the <strong>smallest whole number ratio</strong> that exists between the number of moles of each element in the compound. </p> <p>To do that, divide these values by the <em>smallest one</em> to get</p> <blockquote> <p><mathjax>#"For C: " (0.012965 color(red)(cancel(color(black)("moles"))))/(0.0086247 color(red)(cancel(color(black)("moles")))) = 1.5032 ~~ 1.5#</mathjax></p> <p><mathjax>#"For H: " (0.026078 color(red)(cancel(color(black)("moles"))))/(0.0086247 color(red)(cancel(color(black)("moles")))) = 3.0236 ~~ 3#</mathjax></p> <p><mathjax>#"For O: " (0.0086247 color(red)(cancel(color(black)("moles"))))/(0.0086247 color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> </blockquote> <p>This means that you have </p> <blockquote> <p><mathjax>#"C"_1.5"H"_3"O"_1#</mathjax></p> </blockquote> <p>Since you're looking for the smallest <strong>whole number ratio</strong> that exists between the elements, multiply each subscript by <mathjax>#2#</mathjax> to get</p> <blockquote> <p><mathjax>#("C"_1.5"H"_3"O"_1)_2 implies color(green)("C"_3"H"_6"O"_2)#</mathjax></p> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A 0.3200 g sample of a carboxylic acid is burned in oxygen, producing 0.5706 g of CO2 and 0.2349 g of H2O. How would you determine the empirical formula of carboxylic acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="201082" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-18T23:23:28" itemprop="dateCreated"> Dec 18, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"C"_3"H"_6"O"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to figure out how much <em>carbon</em> and <em>hydrogen</em> were present in the initial sample, then use the sample's mass to figure out how much <strong>oxygen</strong> it contained. </p> <p>Once you know how many grams of each element you had in the original sample, use the <em>molar masses</em> of the three <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> to determine how many <em>moles</em> of each you have. </p> <p>So, what you need to do is figure out the <a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of hydrogen in water and of carbon in carbon dioxide. This will allow you to figure out how many grams of hydrogen and carbon, respectively, were produced by the combustion reaction. </p> <p>As you know, <strong>one mole</strong> of water, <mathjax>#"H"_2"O"#</mathjax>, contains <mathjax>#2#</mathjax> <strong>moles</strong> of hydrogen. This means that the <a href="http://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of hydrogen in water will be </p> <blockquote> <p><mathjax>#(2 xx 1.00794 color(red)(cancel(color(black)("g/mol"))))/(18.015color(red)(cancel(color(black)("g/mol")))) xx 100 = "11.19% H"#</mathjax></p> </blockquote> <p>What this means is that <strong>every</strong> <mathjax>#"100 g"#</mathjax> of water will contain <mathjax>#"11.19 g"#</mathjax> of hydrogen. In your case, the <mathjax>#"0.2349-g"#</mathjax> sample of water will contain </p> <blockquote> <p><mathjax>#0.2349 color(red)(cancel(color(black)("g water"))) * "11.19 g H"/(100color(red)(cancel(color(black)("g water")))) = "0.026285 g H"#</mathjax></p> </blockquote> <p>Similarly, <strong>one mole</strong> of carbon dioxide, <mathjax>#"CO"_2#</mathjax>, contains <strong>one mole</strong> of carbon. The percent composition of carbon in carbon dioxide will be </p> <blockquote> <p><mathjax>#(1 xx 12.011 color(red)(cancel(color(black)("g/mol"))))/(44.01 color(red)(cancel(color(black)("g/mol")))) xx 100 = "27.29% C"#</mathjax></p> </blockquote> <p>Once again, this tells you that <strong>every</strong> <mathjax>#"100 g"#</mathjax> of carbon dioxide will contain <mathjax>#"27.29 g"#</mathjax> of carbon. In your case, you will have</p> <blockquote> <p><mathjax>#0.5706 color(red)(cancel(color(black)("g H"_2"O"))) * "27.29 g C"/(100color(red)(cancel(color(black)("g H"_2"O")))) = "0.15572 g C"#</mathjax></p> </blockquote> <p>The mass of carbon + hydrogen originally present in the carboxylic acid sample will be </p> <blockquote> <p><mathjax>#m_"C + H" = "0.026285 g" + "0.15572 g" = "0.18201 g"#</mathjax></p> </blockquote> <p>The initial mass of the sample was equal to <mathjax>#"0.3200 g"#</mathjax>. This tells you that the sample also contained </p> <blockquote> <p><mathjax>#m_"oxygen" = "0.3200 g" - "0.18201 g" = "0.13799 g O"#</mathjax></p> </blockquote> <p>So, now that you know how many grams of each element were present in the initial sample, use their <em>molar masses</em> to convert these to <em>moles</em></p> <blockquote> <p><mathjax>#"For C: " (0.15572 color(red)(cancel(color(black)("g"))))/(12.011color(red)(cancel(color(black)("g")))/"mol") = "0.012965 moles C"#</mathjax></p> <p><mathjax>#"For H: " (0.026285 color(red)(cancel(color(black)("g"))))/(1.00794 color(red)(cancel(color(black)("g")))/"mol") = "0.026078 moles H"#</mathjax></p> <p><mathjax>#"For O: " (0.13799 color(red)(cancel(color(black)("g"))))/(15.9994color(red)(cancel(color(black)("g")))/"mol") = "0.0086247 moles O"#</mathjax></p> </blockquote> <p>Now, to get the compound's <a href="https://socratic.org/chemistry/the-mole-concept/empirical-and-molecular-formulas">empirical formula</a>, you need to find the <strong>smallest whole number ratio</strong> that exists between the number of moles of each element in the compound. </p> <p>To do that, divide these values by the <em>smallest one</em> to get</p> <blockquote> <p><mathjax>#"For C: " (0.012965 color(red)(cancel(color(black)("moles"))))/(0.0086247 color(red)(cancel(color(black)("moles")))) = 1.5032 ~~ 1.5#</mathjax></p> <p><mathjax>#"For H: " (0.026078 color(red)(cancel(color(black)("moles"))))/(0.0086247 color(red)(cancel(color(black)("moles")))) = 3.0236 ~~ 3#</mathjax></p> <p><mathjax>#"For O: " (0.0086247 color(red)(cancel(color(black)("moles"))))/(0.0086247 color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> </blockquote> <p>This means that you have </p> <blockquote> <p><mathjax>#"C"_1.5"H"_3"O"_1#</mathjax></p> </blockquote> <p>Since you're looking for the smallest <strong>whole number ratio</strong> that exists between the elements, multiply each subscript by <mathjax>#2#</mathjax> to get</p> <blockquote> <p><mathjax>#("C"_1.5"H"_3"O"_1)_2 implies color(green)("C"_3"H"_6"O"_2)#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/201082" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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A 0.3200 g sample of a carboxylic acid is burned in oxygen, producing 0.5706 g of CO2 and 0.2349 g of H2O. How would you determine the empirical formula of carboxylic acid?

a92c195d-6ddd-11ea-ab50-ccda262736ce

https://socratic.org/questions/what-is-the-ph-of-a-0-050-m-naoh-solution

12.7

start physical_unit 8 9 ph none qc_end physical_unit 8 9 6 7 molarity qc_end end

[{"type":"physical unit","value":"pH [OF] NaOH solution"}]

[{"type":"physical unit","value":"12.7"}]

[{"type":"physical unit","value":"Molarity [OF] NaOH solution [=] \\pu{0.050 M}"}]

<h1 class="questionTitle" itemprop="name">What is the pH of a 0.050 M NaOH solution? </h1>

12.7

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>NaOH is a strong base, meaning it will dissociate basically completely in solution to form <mathjax>#Na^+#</mathjax> and <mathjax>#OH^-#</mathjax> ions in solution. </p> <p>One mole of <mathjax>#OH^-#</mathjax> ions is created for every mole of NaOH that is dissolved. If it's a .05 M solution of NaOH, then it can also be interpreted to be a .05M solution of <mathjax>#OH^-#</mathjax>.</p> <p><mathjax>#pOH#</mathjax> (The pH scale for bases) can be found by taking the negative logarithm of <mathjax>#OH^-#</mathjax> concentration.</p> <p><mathjax>#pOH#</mathjax> = <mathjax>#-log[.05 M]#</mathjax> = 1.3.</p> <p>However, we are trying to find <mathjax>#pH#</mathjax>, so we must use the formula<br/> <mathjax>#pOH + pH = 14#</mathjax>.</p> <p>Now that we know <mathjax>#pOH = 1.3#</mathjax>, <br/> <mathjax>#pH = 14 - 1.3 = 12.7#</mathjax>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> is about 12.7.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>NaOH is a strong base, meaning it will dissociate basically completely in solution to form <mathjax>#Na^+#</mathjax> and <mathjax>#OH^-#</mathjax> ions in solution. </p> <p>One mole of <mathjax>#OH^-#</mathjax> ions is created for every mole of NaOH that is dissolved. If it's a .05 M solution of NaOH, then it can also be interpreted to be a .05M solution of <mathjax>#OH^-#</mathjax>.</p> <p><mathjax>#pOH#</mathjax> (The pH scale for bases) can be found by taking the negative logarithm of <mathjax>#OH^-#</mathjax> concentration.</p> <p><mathjax>#pOH#</mathjax> = <mathjax>#-log[.05 M]#</mathjax> = 1.3.</p> <p>However, we are trying to find <mathjax>#pH#</mathjax>, so we must use the formula<br/> <mathjax>#pOH + pH = 14#</mathjax>.</p> <p>Now that we know <mathjax>#pOH = 1.3#</mathjax>, <br/> <mathjax>#pH = 14 - 1.3 = 12.7#</mathjax>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the pH of a 0.050 M NaOH solution? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="365442" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/wilson-3"><img alt="" class="" src="https://profilepictures.socratic.org/zZkzxeeJTw6nwcUWU7Kt_IMG_4844.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/wilson-3"> Wilson T </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-16T22:57:30" itemprop="dateCreated"> Jan 16, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> is about 12.7.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>NaOH is a strong base, meaning it will dissociate basically completely in solution to form <mathjax>#Na^+#</mathjax> and <mathjax>#OH^-#</mathjax> ions in solution. </p> <p>One mole of <mathjax>#OH^-#</mathjax> ions is created for every mole of NaOH that is dissolved. If it's a .05 M solution of NaOH, then it can also be interpreted to be a .05M solution of <mathjax>#OH^-#</mathjax>.</p> <p><mathjax>#pOH#</mathjax> (The pH scale for bases) can be found by taking the negative logarithm of <mathjax>#OH^-#</mathjax> concentration.</p> <p><mathjax>#pOH#</mathjax> = <mathjax>#-log[.05 M]#</mathjax> = 1.3.</p> <p>However, we are trying to find <mathjax>#pH#</mathjax>, so we must use the formula<br/> <mathjax>#pOH + pH = 14#</mathjax>.</p> <p>Now that we know <mathjax>#pOH = 1.3#</mathjax>, <br/> <mathjax>#pH = 14 - 1.3 = 12.7#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/365442" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 112738 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the pH of a 0.050 M NaOH solution?

ab7eb24a-6ddd-11ea-bbb2-ccda262736ce

https://socratic.org/questions/a-0-2-kg-piece-of-unknown-metal-is-heated-to-87-c-and-then-dropped-into-a-0-28-k

0.19 J/(kg * K)

start physical_unit 41 43 specific_heat j/(kg_·_k) qc_end physical_unit 19 21 17 18 mass qc_end physical_unit 19 21 23 24 temperature qc_end physical_unit 30 31 33 34 temperature qc_end end

[{"type":"physical unit","value":"specific heat [OF] the unknown metal [IN] J/(kg * K)"}]

[{"type":"physical unit","value":"0.19 J/(kg * K)"}]

[{"type":"physical unit","value":"Mass [OF] unknown metal piece [=] \\pu{0.2 kg}"},{"type":"physical unit","value":"Temperature [OF] unknown metal piece [=] \\pu{87 ℃}"},{"type":"physical unit","value":"Mass [OF] water sample [=] \\pu{0.28 kg}"},{"type":"physical unit","value":"Temperature [OF] water sample [=] \\pu{22 ℃}"},{"type":"physical unit","value":"Temperature [OF] the mixture [=] \\pu{24 ℃}"}]

<h1 class="questionTitle" itemprop="name">A 0.2 kg piece of unknown metal is heated to 87 °C and then dropped into a 0.28 kg sample of water at 22°C. If the final temperature of the mixture is 24°C, what is the specific heat of the unknown metal?</h1>

0.19 J/(kg * K)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The heat transferred from the hot metal, is equal to the heat absorbed by the cold water.</p> <p>For the cold water, <mathjax># Delta T_w=24-22=2º#</mathjax></p> <p>For the metal <mathjax>#DeltaT_o=87-24=63º#</mathjax></p> <p><mathjax># m_o C_o (DeltaT_o) = m_w C_w (DeltaT_w)#</mathjax></p> <p><mathjax>#C_w=4.186kJkg^-1K^-1#</mathjax></p> <p><mathjax>#m_0 C_o*63 = m_w* 4.186 *2#</mathjax></p> <p><mathjax>#0.2*C_o*63=0.28*4.186*2#</mathjax></p> <p><mathjax>#C_o=(0.28*4.186*2)/(0.2*63)#</mathjax></p> <p><mathjax>#=0.186kJkg^-1K^-1#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of the metal is <mathjax>#=0.186kJkg^-1K^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The heat transferred from the hot metal, is equal to the heat absorbed by the cold water.</p> <p>For the cold water, <mathjax># Delta T_w=24-22=2º#</mathjax></p> <p>For the metal <mathjax>#DeltaT_o=87-24=63º#</mathjax></p> <p><mathjax># m_o C_o (DeltaT_o) = m_w C_w (DeltaT_w)#</mathjax></p> <p><mathjax>#C_w=4.186kJkg^-1K^-1#</mathjax></p> <p><mathjax>#m_0 C_o*63 = m_w* 4.186 *2#</mathjax></p> <p><mathjax>#0.2*C_o*63=0.28*4.186*2#</mathjax></p> <p><mathjax>#C_o=(0.28*4.186*2)/(0.2*63)#</mathjax></p> <p><mathjax>#=0.186kJkg^-1K^-1#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A 0.2 kg piece of unknown metal is heated to 87 °C and then dropped into a 0.28 kg sample of water at 22°C. If the final temperature of the mixture is 24°C, what is the specific heat of the unknown metal?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="385273" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/narad-t"><img alt="" class="" src="https://profilepictures.socratic.org/zsDo4Wx9QIqYad4PXKE9_150317-1041.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/narad-t"> Narad T. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-02T06:44:07" itemprop="dateCreated"> Mar 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of the metal is <mathjax>#=0.186kJkg^-1K^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The heat transferred from the hot metal, is equal to the heat absorbed by the cold water.</p> <p>For the cold water, <mathjax># Delta T_w=24-22=2º#</mathjax></p> <p>For the metal <mathjax>#DeltaT_o=87-24=63º#</mathjax></p> <p><mathjax># m_o C_o (DeltaT_o) = m_w C_w (DeltaT_w)#</mathjax></p> <p><mathjax>#C_w=4.186kJkg^-1K^-1#</mathjax></p> <p><mathjax>#m_0 C_o*63 = m_w* 4.186 *2#</mathjax></p> <p><mathjax>#0.2*C_o*63=0.28*4.186*2#</mathjax></p> <p><mathjax>#C_o=(0.28*4.186*2)/(0.2*63)#</mathjax></p> <p><mathjax>#=0.186kJkg^-1K^-1#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/385273" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-heat-capacity-of-a-lead-sinker-be-determined"> How can the heat capacity of a lead sinker be determined? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-the-specific-heats-of-metals-compare-with-water"> How do the specific heats of metals compare with water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-specific-heat-change-with-temperature"> How does specific heat change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/dissolving-some-potassium-bromide-in-200cm3-of-water-leads-to-a-decrease-in-temp"> Dissolving some potassium bromide in 200cm3 of water leads to a decrease in temperature of 3oC.... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-heat-capacity-larger-for-polymers"> Is heat capacity larger for polymers? 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A 0.2 kg piece of unknown metal is heated to 87 °C and then dropped into a 0.28 kg sample of water at 22°C. If the final temperature of the mixture is 24°C, what is the specific heat of the unknown metal?

a973c46e-6ddd-11ea-94c7-ccda262736ce

https://socratic.org/questions/how-do-you-balance-ni-c-4h-8n-2o-2-ni-c-4h-8n-2o-2-2

Ni + 2 C4H8N2O2 -> Ni(C4H8N2O2)2

start chemical_equation qc_end chemical_equation 4 8 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"Ni + 2 C4H8N2O2 -> Ni(C4H8N2O2)2"}]

[{"type":"chemical equation","value":"Ni + C4H8N2O2 -> Ni(C4H8N2O2)2"}]

<h1 class="questionTitle" itemprop="name">How do you balance #Ni + C_4H_8N_2O_2 -&gt; Ni(C_4H_8N_2O_2)_2#?</h1>

Ni + 2 C4H8N2O2 -> Ni(C4H8N2O2)2

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Ni + C_4H_8N_2O_2 -&gt; Ni(C_4H_8N_2O_2)_2#</mathjax><br/> as there are 1 molecule nickel, 4 molecules of carbon, 8 molecules of hydrogen, 2 molecules of nitrogen, and 2 molecules of oxygen in left hand side<br/> but 1 molecule of nickel, 8 molecules of carbon, 16 molecules of hydrogen, 4 molecules of nitrogen, and 4 molecules of oxygen<br/> so, by multiplying <mathjax>#C_4H_8N_2O_2#</mathjax> by <mathjax>#2#</mathjax> the equation will be balanced. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Ni + 2C_4H_8N_2O_2 -&gt; Ni(C_4H_8N_2O_2)_2#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Ni + C_4H_8N_2O_2 -&gt; Ni(C_4H_8N_2O_2)_2#</mathjax><br/> as there are 1 molecule nickel, 4 molecules of carbon, 8 molecules of hydrogen, 2 molecules of nitrogen, and 2 molecules of oxygen in left hand side<br/> but 1 molecule of nickel, 8 molecules of carbon, 16 molecules of hydrogen, 4 molecules of nitrogen, and 4 molecules of oxygen<br/> so, by multiplying <mathjax>#C_4H_8N_2O_2#</mathjax> by <mathjax>#2#</mathjax> the equation will be balanced. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you balance #Ni + C_4H_8N_2O_2 -&gt; Ni(C_4H_8N_2O_2)_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="218177" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/sihan-tawsik"><img alt="" class="" src="https://profilepictures.socratic.org/I73bahXRAWAiDjXp46vl_IMG_20160224_111821.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/sihan-tawsik"> Sihan Tawsik </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-28T05:44:51" itemprop="dateCreated"> Jan 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Ni + 2C_4H_8N_2O_2 -&gt; Ni(C_4H_8N_2O_2)_2#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Ni + C_4H_8N_2O_2 -&gt; Ni(C_4H_8N_2O_2)_2#</mathjax><br/> as there are 1 molecule nickel, 4 molecules of carbon, 8 molecules of hydrogen, 2 molecules of nitrogen, and 2 molecules of oxygen in left hand side<br/> but 1 molecule of nickel, 8 molecules of carbon, 16 molecules of hydrogen, 4 molecules of nitrogen, and 4 molecules of oxygen<br/> so, by multiplying <mathjax>#C_4H_8N_2O_2#</mathjax> by <mathjax>#2#</mathjax> the equation will be balanced. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/218177" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="218277" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-28T12:32:18" itemprop="dateCreated"> Jan 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Ni"_text((aq])^(2+) + 2"C"_4"H"_8"N"_2"O"_text(2(aq]) -&gt; "Ni"("C"_4"H"_7"N"_2"O"_2)_text(2(s]) darr + 2"H"_text((aq])^(+)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The starting chemical equation given to you is actually <strong>incorrect</strong>. </p> <p>This reaction takes place in <em>aqueous solution</em> and it involves the nickel(II) cation, <mathjax>#"Ni"^(2+)#</mathjax>, <strong>not</strong> nickel metal, <mathjax>#"Ni"#</mathjax>. </p> <p>Reacting nickel(II) cations with <em>dimethylglyoxime</em>, <mathjax>#"C"_4"H"_8"N"_2"O"_2#</mathjax>, will produce an <strong>insolube solid</strong> called <em>nickel dimethylglyoxime</em>, <mathjax>#"Ni"("C"_4"H"_8"N"_2"O"_2)_2#</mathjax>, which will precipitate out of solution. </p> <p>The nickel(II) cations can be delivered to the solution by a soluble salt like <em>nickel(II) nitrate</em>, <mathjax>#"Ni"("NO"_3)_2#</mathjax>. </p> <p>The actual <strong>balanced</strong> chemical equation for this reaction can be written like this </p> <blockquote> <p><mathjax>#"Ni"_text((aq])^(2+) + 2"C"_4"H"_8"N"_2"O"_text(2(aq]) -&gt; "Ni"("C"_4"H"_7"N"_2"O"_2)_text(2(s]) darr + 2"H"_text((aq])^(+)#</mathjax></p> </blockquote> <p>The reaction involves two dimethylglyoxime molecules acting as <strong>chelating agents</strong> to form the nickel dymethylglyoxime complex. </p> <p><img alt="http://www.che.tohoku.ac.jp/~analchem/precipitate/index_e.html" src="https://useruploads.socratic.org/mnCgsY3TEeWURODXa8JS_react.gif"/> </p> <p>When the nickel(II) cations are delivered via nickel(II) nitrate, the reaction will produce </p> <blockquote> <p><mathjax>#"Ni"("NO"_3)_text(2(aq]) + 2"C"_4"H"_8"N"_2"O"_text(2(aq]) -&gt; "Ni"("C"_4"H"_7"N"_2"O"_2)_text(2(s]) darr + 2"HNO"_text(3(aq])#</mathjax></p> </blockquote> <p>The nitrate anions, <mathjax>#"NO"_3^(-)#</mathjax>, are <em>spectator ions</em> in the reaction, meaning that they can be found on both sides of the chemical equation. </p> <p>This reaction is used as a <em>confirmation test</em> for the presence of nickel(II) cations. Nickel dymethylglyoxime is a red precipitate. </p> <p><img alt="https://commons.wikimedia.org" src="https://useruploads.socratic.org/V3ZKd0eVR0WmWRjTxRyE_1024px-Nickel_Dimethylglyoxime_2014.05.08.jpg"/> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/218277" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------&gt; H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -&gt; Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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How do you balance #Ni + C_4H_8N_2O_2 -&gt; Ni(C_4H_8N_2O_2)_2#?

ad1d622d-6ddd-11ea-94a9-ccda262736ce

https://socratic.org/questions/how-many-grams-of-oxygen-are-produced-by-the-decomposition-of-1-mole-of-potassiu

48.00 grams

start physical_unit 4 4 mass g qc_end physical_unit 16 16 11 12 mole qc_end chemical_equation 20 27 qc_end end

[{"type":"physical unit","value":"Mass [OF] oxygen [IN] grams"}]

[{"type":"physical unit","value":"48.00 grams"}]

[{"type":"physical unit","value":"Mole [OF] KClO3 [=] \\pu{1 mole}"},{"type":"chemical equation","value":"2 KClO3 -> 2 KCl + 3 O2"}]

<h1 class="questionTitle" itemprop="name">How many grams of oxygen are produced by the decomposition of 1 mole of potassium chlorate, #KClO_3# in the reaction #2KClO_3-&gt;2KCl+3O_2#?</h1>

48.00 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"2KClO"_3rarr"2KCl"+"3O"_2#</mathjax></p> <p>This tells us that for every 2 moles of potassium chlorate that are decomposed, then 3 moles of oxygen gas is produced.</p> <p>Using simple proportion:</p> <p><mathjax>#2"mol"rarr3"mol"#</mathjax></p> <p><mathjax>#:.1"mol"rarr3/2"mol"#</mathjax></p> <p>The <mathjax>#"M"_r"#</mathjax> of <mathjax>#"O"_2=32#</mathjax></p> <p><mathjax>#:."mass O"_2=32xx3/2=48"g"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"48g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"2KClO"_3rarr"2KCl"+"3O"_2#</mathjax></p> <p>This tells us that for every 2 moles of potassium chlorate that are decomposed, then 3 moles of oxygen gas is produced.</p> <p>Using simple proportion:</p> <p><mathjax>#2"mol"rarr3"mol"#</mathjax></p> <p><mathjax>#:.1"mol"rarr3/2"mol"#</mathjax></p> <p>The <mathjax>#"M"_r"#</mathjax> of <mathjax>#"O"_2=32#</mathjax></p> <p><mathjax>#:."mass O"_2=32xx3/2=48"g"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many grams of oxygen are produced by the decomposition of 1 mole of potassium chlorate, #KClO_3# in the reaction #2KClO_3-&gt;2KCl+3O_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="253805" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michael-2"><img alt="" class="" src="https://lh3.googleusercontent.com/-gCv6FQRhls0/AAAAAAAAAAI/AAAAAAAAAAA/AAnnY7oOJS05Ylqn3KuDSW0LfnbOk7FezQ/mo/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michael-2"> Michael </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-13T16:11:41" itemprop="dateCreated"> Apr 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"48g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"2KClO"_3rarr"2KCl"+"3O"_2#</mathjax></p> <p>This tells us that for every 2 moles of potassium chlorate that are decomposed, then 3 moles of oxygen gas is produced.</p> <p>Using simple proportion:</p> <p><mathjax>#2"mol"rarr3"mol"#</mathjax></p> <p><mathjax>#:.1"mol"rarr3/2"mol"#</mathjax></p> <p>The <mathjax>#"M"_r"#</mathjax> of <mathjax>#"O"_2=32#</mathjax></p> <p><mathjax>#:."mass O"_2=32xx3/2=48"g"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/253805" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -&gt; 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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How many grams of oxygen are produced by the decomposition of 1 mole of potassium chlorate, #KClO_3# in the reaction #2KClO_3-&gt;2KCl+3O_2#?

ac22443e-6ddd-11ea-9c79-ccda262736ce

https://socratic.org/questions/how-would-you-balance-copper-sulfide-nitric-acid-copper-nitrate-sulfur-water-nit

3 CuS + 8 HNO3 -> 3 Cu(NO3)2 + 3 S + 4 H2O + 2 NO

start chemical_equation qc_end chemical_equation 4 18 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"3 CuS + 8 HNO3 -> 3 Cu(NO3)2 + 3 S + 4 H2O + 2 NO"}]

[{"type":"chemical equation","value":"copper sulfide + nitric acid --> Copper nitrate + sulfur + water + nitrogen monoxide"}]

<h1 class="questionTitle" itemprop="name">How would you balance: copper sulfide + nitric acid --&gt; Copper nitrate + sulfur + water + nitrogen monoxide?</h1>

3 CuS + 8 HNO3 -> 3 Cu(NO3)2 + 3 S + 4 H2O + 2 NO

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let <mathjax>#a,b,c,d,e,f#</mathjax> be the number of molecules of each reactant. Th echecmical eqaution becomes</p> <p><mathjax>#aCuS+bHNO_3-&gt;cCu(NO_3)_2+dS+eH_2O+fNO#</mathjax><br/> Obsrvation reveals that nmber of molecules of <mathjax>#H NO_3#</mathjax> must be an even number to accommodate <mathjax>#H_2#</mathjax> on the right of the equation.</p> <p>Let's start balancing for the radical <mathjax>#NO_3#</mathjax>.<br/> On the right hand side of the equation the radical is either part of <br/> atom <mathjax>#Cu(NO_3)_2#</mathjax> or can be obtained from combination of <mathjax>#H_2O#</mathjax> and <mathjax>#NO#</mathjax>. We may choose lowest integer 1 for either and double the number of atoms of the other. However, choosing lowest integer 1 for <mathjax>#NO#</mathjax> will rquire chosing 2 atoms of <mathjax>#H_2O#</mathjax>. This will increase the number of atoms of <mathjax>#H#</mathjax> required for balancing. Therefore, choosing 2 atoms of <mathjax>#NO#</mathjax> or <mathjax>#f=2#</mathjax>, the equation becomes</p> <p><mathjax>#aCuS+bHNO_3-&gt;cCu(NO_3)_2+dS+eH_2O+2NO#</mathjax></p> <p>With this we need 3 more atoms of <mathjax>#O#</mathjax> for the second atom of <mathjax>#N#</mathjax>. Implies <mathjax>#e=4#</mathjax>. The equation becomes </p> <p><mathjax>#aCuS+bHNO_3-&gt;cCu(NO_3)_2+dS+4H_2O+2NO#</mathjax><br/> Now after having fixed number of atoms of <mathjax>#H#</mathjax> on the right side, it follows that <mathjax>#b #</mathjax> must<mathjax>#=8#</mathjax>. To give us</p> <p><mathjax>#aCuS+8HNO_3-&gt;cCu(NO_3)_2+dS+4H_2O+2NO#</mathjax><br/> Now balacaing 24 number of <mathjax>#O#</mathjax> atoms of left side with the right side atoms we obtain <mathjax>#c=3#</mathjax>. This fixes <mathjax>#a=3=d#</mathjax>. We obtain the balanced equation as</p> <p><mathjax>#3CuS+8HNO_3-&gt;3Cu(NO_3)_2+3S+4H_2O+2NO#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3CuS+8HNO_3-&gt;3Cu(NO_3)_2+3S+4H_2O+2NO#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let <mathjax>#a,b,c,d,e,f#</mathjax> be the number of molecules of each reactant. Th echecmical eqaution becomes</p> <p><mathjax>#aCuS+bHNO_3-&gt;cCu(NO_3)_2+dS+eH_2O+fNO#</mathjax><br/> Obsrvation reveals that nmber of molecules of <mathjax>#H NO_3#</mathjax> must be an even number to accommodate <mathjax>#H_2#</mathjax> on the right of the equation.</p> <p>Let's start balancing for the radical <mathjax>#NO_3#</mathjax>.<br/> On the right hand side of the equation the radical is either part of <br/> atom <mathjax>#Cu(NO_3)_2#</mathjax> or can be obtained from combination of <mathjax>#H_2O#</mathjax> and <mathjax>#NO#</mathjax>. We may choose lowest integer 1 for either and double the number of atoms of the other. However, choosing lowest integer 1 for <mathjax>#NO#</mathjax> will rquire chosing 2 atoms of <mathjax>#H_2O#</mathjax>. This will increase the number of atoms of <mathjax>#H#</mathjax> required for balancing. Therefore, choosing 2 atoms of <mathjax>#NO#</mathjax> or <mathjax>#f=2#</mathjax>, the equation becomes</p> <p><mathjax>#aCuS+bHNO_3-&gt;cCu(NO_3)_2+dS+eH_2O+2NO#</mathjax></p> <p>With this we need 3 more atoms of <mathjax>#O#</mathjax> for the second atom of <mathjax>#N#</mathjax>. Implies <mathjax>#e=4#</mathjax>. The equation becomes </p> <p><mathjax>#aCuS+bHNO_3-&gt;cCu(NO_3)_2+dS+4H_2O+2NO#</mathjax><br/> Now after having fixed number of atoms of <mathjax>#H#</mathjax> on the right side, it follows that <mathjax>#b #</mathjax> must<mathjax>#=8#</mathjax>. To give us</p> <p><mathjax>#aCuS+8HNO_3-&gt;cCu(NO_3)_2+dS+4H_2O+2NO#</mathjax><br/> Now balacaing 24 number of <mathjax>#O#</mathjax> atoms of left side with the right side atoms we obtain <mathjax>#c=3#</mathjax>. This fixes <mathjax>#a=3=d#</mathjax>. We obtain the balanced equation as</p> <p><mathjax>#3CuS+8HNO_3-&gt;3Cu(NO_3)_2+3S+4H_2O+2NO#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How would you balance: copper sulfide + nitric acid --&gt; Copper nitrate + sulfur + water + nitrogen monoxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="215124" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/a08"><img alt="" class="" src="https://profilepictures.socratic.org/fZvgXOhDR1W7ogoxiea9_Ridge%2C_Shimla.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/a08"> A08 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-21T16:23:17" itemprop="dateCreated"> Jan 21, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3CuS+8HNO_3-&gt;3Cu(NO_3)_2+3S+4H_2O+2NO#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let <mathjax>#a,b,c,d,e,f#</mathjax> be the number of molecules of each reactant. Th echecmical eqaution becomes</p> <p><mathjax>#aCuS+bHNO_3-&gt;cCu(NO_3)_2+dS+eH_2O+fNO#</mathjax><br/> Obsrvation reveals that nmber of molecules of <mathjax>#H NO_3#</mathjax> must be an even number to accommodate <mathjax>#H_2#</mathjax> on the right of the equation.</p> <p>Let's start balancing for the radical <mathjax>#NO_3#</mathjax>.<br/> On the right hand side of the equation the radical is either part of <br/> atom <mathjax>#Cu(NO_3)_2#</mathjax> or can be obtained from combination of <mathjax>#H_2O#</mathjax> and <mathjax>#NO#</mathjax>. We may choose lowest integer 1 for either and double the number of atoms of the other. However, choosing lowest integer 1 for <mathjax>#NO#</mathjax> will rquire chosing 2 atoms of <mathjax>#H_2O#</mathjax>. This will increase the number of atoms of <mathjax>#H#</mathjax> required for balancing. Therefore, choosing 2 atoms of <mathjax>#NO#</mathjax> or <mathjax>#f=2#</mathjax>, the equation becomes</p> <p><mathjax>#aCuS+bHNO_3-&gt;cCu(NO_3)_2+dS+eH_2O+2NO#</mathjax></p> <p>With this we need 3 more atoms of <mathjax>#O#</mathjax> for the second atom of <mathjax>#N#</mathjax>. Implies <mathjax>#e=4#</mathjax>. The equation becomes </p> <p><mathjax>#aCuS+bHNO_3-&gt;cCu(NO_3)_2+dS+4H_2O+2NO#</mathjax><br/> Now after having fixed number of atoms of <mathjax>#H#</mathjax> on the right side, it follows that <mathjax>#b #</mathjax> must<mathjax>#=8#</mathjax>. To give us</p> <p><mathjax>#aCuS+8HNO_3-&gt;cCu(NO_3)_2+dS+4H_2O+2NO#</mathjax><br/> Now balacaing 24 number of <mathjax>#O#</mathjax> atoms of left side with the right side atoms we obtain <mathjax>#c=3#</mathjax>. This fixes <mathjax>#a=3=d#</mathjax>. We obtain the balanced equation as</p> <p><mathjax>#3CuS+8HNO_3-&gt;3Cu(NO_3)_2+3S+4H_2O+2NO#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/215124" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------&gt; H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -&gt; Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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How would you balance: copper sulfide + nitric acid --&gt; Copper nitrate + sulfur + water + nitrogen monoxide?

a8a2654a-6ddd-11ea-9071-ccda262736ce

https://socratic.org/questions/a-5-00-ml-sample-of-a-solution-of-kcl-mwt-74-6-g-mol-in-water-mwt-18-01-g-mol-we

20 g

start physical_unit 6 6 mass g qc_end physical_unit 8 8 11 12 molecular_weight qc_end physical_unit 14 14 17 18 molecular_weight qc_end physical_unit 31 31 28 29 mass qc_end physical_unit 8 8 41 42 mass qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"mass [OF] the solution [IN] g"}]

[{"type":"physical unit","value":"20 g"}]

[{"type":"physical unit","value":"Volume [OF] KCl solution sample [=] \\pu{5.00 mL}"},{"type":"physical unit","value":"Mwt [OF] KCl [=] \\pu{74.6 g/mol}"},{"type":"physical unit","value":"Mwt [OF] water [=] \\pu{18.01 g/mol}"},{"type":"physical unit","value":"Weight [OF] KCl solution sample [=] \\pu{5.20 g}"},{"type":"physical unit","value":"Mass [OF] residue [=] \\pu{0.26 g}"},{"type":"physical unit","value":"Mass [OF] KCl [=] \\pu{1.00 g}"},{"type":"other","value":"The water is evaporated off."}]

<h1 class="questionTitle" itemprop="name">A 5.00 mL sample of a solution of KCl (Mwt=74.6 g/mol) in water (Mwt=18.01 g/mol) weighs 5.20 g. The water is evaporated off leaving 0.26 g of residue. What is the mass of solution that would contain 1.00 g of KCl?</h1>

20 g

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing you need to do here is to figure out the <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a></strong> of the solution, <mathjax>#rho#</mathjax>, by using its mass, <mathjax>#m#</mathjax>, and its volume, <mathjax>#V#</mathjax></p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(rho = m/V)))#</mathjax></p> </blockquote> <p>In your case, you will have</p> <blockquote> <p><mathjax>#rho = "5.20 g"/"5.00 mL" = "1.04 g mL"^(-1)#</mathjax></p> </blockquote> <p>Now, the key thing to keep in mind here is that <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> are <strong>homogeneous <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/mixtures">mixtures</a></strong>, which implies that they have the same composition throughout. </p> <p>This allows you to use the known composition of the initial solution, which contains <mathjax>#"0.26 g"#</mathjax> of potassium chloride in <mathjax>#"5.00 mL"#</mathjax> of solution, as a <strong>conversion factor</strong> in order to determine the <em>volume</em> of solution that will contain <mathjax>#"1.00 g"#</mathjax> of potassium chloride.</p> <blockquote> <p><mathjax>#1.00 color(red)(cancel(color(black)("g KCl"))) * overbrace("5.00 mL solution"/(0.26color(red)(cancel(color(black)("g KCl")))))^(color(blue)("the known composition of the solution")) = "19.23 mL solution"#</mathjax></p> </blockquote> <p>Finally, use the density of the solution to convert the volume to <em>mass</em></p> <blockquote> <p><mathjax>#19.23 color(red)(cancel(color(black)("mL solution"))) * overbrace("1.04 g"/(1color(red)(cancel(color(black)("mL solution")))))^(color(blue)("= 1.04 g mL"^(-1))) = color(darkgreen)(ul(color(black)("20. g")))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of potassium chloride. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"20. g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing you need to do here is to figure out the <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a></strong> of the solution, <mathjax>#rho#</mathjax>, by using its mass, <mathjax>#m#</mathjax>, and its volume, <mathjax>#V#</mathjax></p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(rho = m/V)))#</mathjax></p> </blockquote> <p>In your case, you will have</p> <blockquote> <p><mathjax>#rho = "5.20 g"/"5.00 mL" = "1.04 g mL"^(-1)#</mathjax></p> </blockquote> <p>Now, the key thing to keep in mind here is that <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> are <strong>homogeneous <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/mixtures">mixtures</a></strong>, which implies that they have the same composition throughout. </p> <p>This allows you to use the known composition of the initial solution, which contains <mathjax>#"0.26 g"#</mathjax> of potassium chloride in <mathjax>#"5.00 mL"#</mathjax> of solution, as a <strong>conversion factor</strong> in order to determine the <em>volume</em> of solution that will contain <mathjax>#"1.00 g"#</mathjax> of potassium chloride.</p> <blockquote> <p><mathjax>#1.00 color(red)(cancel(color(black)("g KCl"))) * overbrace("5.00 mL solution"/(0.26color(red)(cancel(color(black)("g KCl")))))^(color(blue)("the known composition of the solution")) = "19.23 mL solution"#</mathjax></p> </blockquote> <p>Finally, use the density of the solution to convert the volume to <em>mass</em></p> <blockquote> <p><mathjax>#19.23 color(red)(cancel(color(black)("mL solution"))) * overbrace("1.04 g"/(1color(red)(cancel(color(black)("mL solution")))))^(color(blue)("= 1.04 g mL"^(-1))) = color(darkgreen)(ul(color(black)("20. g")))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of potassium chloride. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A 5.00 mL sample of a solution of KCl (Mwt=74.6 g/mol) in water (Mwt=18.01 g/mol) weighs 5.20 g. The water is evaporated off leaving 0.26 g of residue. What is the mass of solution that would contain 1.00 g of KCl?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="402008" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-05T14:50:45" itemprop="dateCreated"> Apr 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"20. g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing you need to do here is to figure out the <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a></strong> of the solution, <mathjax>#rho#</mathjax>, by using its mass, <mathjax>#m#</mathjax>, and its volume, <mathjax>#V#</mathjax></p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(rho = m/V)))#</mathjax></p> </blockquote> <p>In your case, you will have</p> <blockquote> <p><mathjax>#rho = "5.20 g"/"5.00 mL" = "1.04 g mL"^(-1)#</mathjax></p> </blockquote> <p>Now, the key thing to keep in mind here is that <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> are <strong>homogeneous <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/mixtures">mixtures</a></strong>, which implies that they have the same composition throughout. </p> <p>This allows you to use the known composition of the initial solution, which contains <mathjax>#"0.26 g"#</mathjax> of potassium chloride in <mathjax>#"5.00 mL"#</mathjax> of solution, as a <strong>conversion factor</strong> in order to determine the <em>volume</em> of solution that will contain <mathjax>#"1.00 g"#</mathjax> of potassium chloride.</p> <blockquote> <p><mathjax>#1.00 color(red)(cancel(color(black)("g KCl"))) * overbrace("5.00 mL solution"/(0.26color(red)(cancel(color(black)("g KCl")))))^(color(blue)("the known composition of the solution")) = "19.23 mL solution"#</mathjax></p> </blockquote> <p>Finally, use the density of the solution to convert the volume to <em>mass</em></p> <blockquote> <p><mathjax>#19.23 color(red)(cancel(color(black)("mL solution"))) * overbrace("1.04 g"/(1color(red)(cancel(color(black)("mL solution")))))^(color(blue)("= 1.04 g mL"^(-1))) = color(darkgreen)(ul(color(black)("20. g")))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of potassium chloride. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/402008" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? 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A 5.00 mL sample of a solution of KCl (Mwt=74.6 g/mol) in water (Mwt=18.01 g/mol) weighs 5.20 g. The water is evaporated off leaving 0.26 g of residue. What is the mass of solution that would contain 1.00 g of KCl?

a94bfd1b-6ddd-11ea-8511-ccda262736ce

https://socratic.org/questions/how-do-you-balance-nh-3-h-2so-4-nh-4-2so-4

2 NH3 + H2SO4 -> (NH4)2SO4

start chemical_equation qc_end chemical_equation 4 8 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"2 NH3 + H2SO4 -> (NH4)2SO4"}]

[{"type":"chemical equation","value":"NH3 + H2SO4 -> (NH4)2SO4"}]

<h1 class="questionTitle" itemprop="name">How do you balance #NH_3 + H_2SO_4 -&gt; (NH_4)_2SO_4#?</h1>

2 NH3 + H2SO4 -> (NH4)2SO4

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The balanced equation is the following:</p> <p><mathjax>#color(red)(2)NH_3+H_2SO_4-&gt;(NH_4)_2SO_4#</mathjax></p> <p>Explanation:<br/> First start by looking at the sulfate group <mathjax>#SO_4#</mathjax>, you will need to leave this group intact.</p> <p>Second, we have two nitrogen atoms in the product side, and only one in the reactants side, therefore, we can multiply <mathjax>#NH_3#</mathjax> by <mathjax>#color(red)(2)#</mathjax>.</p> <p>Third, look at the hydrogen atoms, you will find <mathjax>#color(blue)(8)#</mathjax> in each side of the reaction, and therefore, your reaction is balanced.</p> <p>In some cases, I prefer to balance equations using groups (or polyatomic ions) rather than atoms.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#color(red)(2)NH_3+H_2SO_4-&gt;(NH_4)_2SO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The balanced equation is the following:</p> <p><mathjax>#color(red)(2)NH_3+H_2SO_4-&gt;(NH_4)_2SO_4#</mathjax></p> <p>Explanation:<br/> First start by looking at the sulfate group <mathjax>#SO_4#</mathjax>, you will need to leave this group intact.</p> <p>Second, we have two nitrogen atoms in the product side, and only one in the reactants side, therefore, we can multiply <mathjax>#NH_3#</mathjax> by <mathjax>#color(red)(2)#</mathjax>.</p> <p>Third, look at the hydrogen atoms, you will find <mathjax>#color(blue)(8)#</mathjax> in each side of the reaction, and therefore, your reaction is balanced.</p> <p>In some cases, I prefer to balance equations using groups (or polyatomic ions) rather than atoms.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you balance #NH_3 + H_2SO_4 -&gt; (NH_4)_2SO_4#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="191410" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-21T10:24:22" itemprop="dateCreated"> Nov 21, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#color(red)(2)NH_3+H_2SO_4-&gt;(NH_4)_2SO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The balanced equation is the following:</p> <p><mathjax>#color(red)(2)NH_3+H_2SO_4-&gt;(NH_4)_2SO_4#</mathjax></p> <p>Explanation:<br/> First start by looking at the sulfate group <mathjax>#SO_4#</mathjax>, you will need to leave this group intact.</p> <p>Second, we have two nitrogen atoms in the product side, and only one in the reactants side, therefore, we can multiply <mathjax>#NH_3#</mathjax> by <mathjax>#color(red)(2)#</mathjax>.</p> <p>Third, look at the hydrogen atoms, you will find <mathjax>#color(blue)(8)#</mathjax> in each side of the reaction, and therefore, your reaction is balanced.</p> <p>In some cases, I prefer to balance equations using groups (or polyatomic ions) rather than atoms.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/191410" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="191411" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/chiara-g-1"><img alt="" class="" src="https://profilepictures.socratic.org/Y0YMEEsQZuqC7ijLEFP2_DSC_0026_2.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/chiara-g-1"> Chiara G. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-21T10:29:55" itemprop="dateCreated"> Nov 21, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2NH_3 + H_2SO_4 → (NH_4)_2SO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You need to make sure that all the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> are equal on both sides.</p> <p>The first step is write down what you have</p> <p><mathjax>#NH_3 + H_2SO_4 → (NH_4)_2SO_4#</mathjax> </p> <p>N: 1 the side in front of the arrow, 2 on the side after the arrow<br/> H: 5 on the side before the arrow, 8 on the side after the arrow<br/> <mathjax>#SO_4#</mathjax>: 1 on each side</p> <p>Now you can see that you need to change the amount of N and H on the side in front of the arrow, to match the amount of N and H after the arrow.</p> <p>Step two add a number in front of the elements to make both side match:</p> <p><mathjax>#2NH_3 + H_2SO_4 → (NH_4)_2SO_4#</mathjax></p> <p>Step three, check again, make changes if necessary:<br/> N: 2 on both sides<br/> H: 8 on both sides<br/> <mathjax>#SO_4#</mathjax>: 1 on each side</p> <p>As you can see, the reaction is now balanced :)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/191411" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> 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How do you balance #NH_3 + H_2SO_4 -&gt; (NH_4)_2SO_4#?

aa463362-6ddd-11ea-b801-ccda262736ce

https://socratic.org/questions/5919f34c7c014926b923f406

1.20 × 10^24

start physical_unit 2 3 number none qc_end physical_unit 2 2 5 6 mole qc_end end

[{"type":"physical unit","value":"Number [OF] carbon atoms"}]

[{"type":"physical unit","value":"1.20 × 10^24"}]

[{"type":"physical unit","value":"Mole [OF] carbon [=] \\pu{2 mol}"}]

<h1 class="questionTitle" itemprop="name">How many carbon atoms in #2*mol# of carbon?</h1>

1.20 × 10^24

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In one mole of carbon, there are <mathjax>#6.02 xx10^23#</mathjax> atoms. So in two moles, there will be twice that: <mathjax>#1.204xx10^24#</mathjax>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.204 xx 10^24#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In one mole of carbon, there are <mathjax>#6.02 xx10^23#</mathjax> atoms. So in two moles, there will be twice that: <mathjax>#1.204xx10^24#</mathjax>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many carbon atoms in #2*mol# of carbon?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="423932" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/abdur-r"><img alt="" class="" src="https://profilepictures.socratic.org/YXIUDMM0SoZAxTdY3kn6_niagara_falls_fog_water_height_6376_3840x2160.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/abdur-r"> Monzur R. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-15T18:35:04" itemprop="dateCreated"> May 15, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.204 xx 10^24#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In one mole of carbon, there are <mathjax>#6.02 xx10^23#</mathjax> atoms. So in two moles, there will be twice that: <mathjax>#1.204xx10^24#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/423932" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="423934" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-15T18:36:18" itemprop="dateCreated"> May 15, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"In 2 moles of carbon there are "12.04xx10^23" carbon atoms"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In one mole of stuff there are <mathjax>#6.02214085xx10^23#</mathjax> individual items of that stuff. If we got <mathjax>#"2 moles"#</mathjax> we multiply that number by <mathjax>#2#</mathjax>. What is the mass of this quantity of carbon atoms. You should be able to answer this <mathjax>#"pdq"#</mathjax>!</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/423934" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 23526 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many carbon atoms in #2*mol# of carbon?

ab01c952-6ddd-11ea-ba0e-ccda262736ce

https://socratic.org/questions/if-a-gas-in-a-closed-container-is-pressurized-from-15-0-atm-to-16-0-atm-and-its-

317.87 Kelvin

start physical_unit 29 30 temperature k qc_end physical_unit 29 30 10 11 pressure qc_end physical_unit 29 30 13 14 pressure qc_end physical_unit 29 30 20 21 temperature qc_end end

[{"type":"physical unit","value":"Temperature2 [OF] the gas [IN] Kelvin"}]

[{"type":"physical unit","value":"317.87 Kelvin"}]

[{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{15.0 atm}"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{16.0 atm}"},{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{25 ℃}"}]

<h1 class="questionTitle" itemprop="name">If a gas in a closed container is pressurized from 15.0 atm to 16.0 atm and its original temperature was 25°C, what would be the final temperature of the gas in Kelvin? </h1>

317.87 Kelvin

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Gay-Lussac's Law deals with pressure and temperature.</p> <p><mathjax>#P_1/T_1 = P_2/T_2#</mathjax></p> <p>If we rearrange and get <mathjax>#T_2#</mathjax> by itself, we get</p> <p><mathjax>#T_2= (P_2T_1)/ P_1#</mathjax></p> <p>Since temperature needs to be in Kelvin for all gas law calculations, <mathjax>#T_1#</mathjax> = 298. That gives us the following</p> <p><mathjax>#T_2= (16 * 298)/ 15#</mathjax></p> <p>That answer = 317.866666666666667</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>317.867 K</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Gay-Lussac's Law deals with pressure and temperature.</p> <p><mathjax>#P_1/T_1 = P_2/T_2#</mathjax></p> <p>If we rearrange and get <mathjax>#T_2#</mathjax> by itself, we get</p> <p><mathjax>#T_2= (P_2T_1)/ P_1#</mathjax></p> <p>Since temperature needs to be in Kelvin for all gas law calculations, <mathjax>#T_1#</mathjax> = 298. That gives us the following</p> <p><mathjax>#T_2= (16 * 298)/ 15#</mathjax></p> <p>That answer = 317.866666666666667</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If a gas in a closed container is pressurized from 15.0 atm to 16.0 atm and its original temperature was 25°C, what would be the final temperature of the gas in Kelvin? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="531351" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/paul-t-5"><img alt="" class="" src="https://lh5.googleusercontent.com/-iF76U0dV2Js/AAAAAAAAAAI/AAAAAAAABcw/Q98_r2HPV68/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/paul-t-5"> Paul T. the science nerd </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-01-06T18:48:21" itemprop="dateCreated"> Jan 6, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>317.867 K</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Gay-Lussac's Law deals with pressure and temperature.</p> <p><mathjax>#P_1/T_1 = P_2/T_2#</mathjax></p> <p>If we rearrange and get <mathjax>#T_2#</mathjax> by itself, we get</p> <p><mathjax>#T_2= (P_2T_1)/ P_1#</mathjax></p> <p>Since temperature needs to be in Kelvin for all gas law calculations, <mathjax>#T_1#</mathjax> = 298. That gives us the following</p> <p><mathjax>#T_2= (16 * 298)/ 15#</mathjax></p> <p>That answer = 317.866666666666667</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/531351" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-gas-pressure-be-changed"> How can gas pressure be changed? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-increase-gas-pressure-in-a-container"> How can you increase gas pressure in a container? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-gas-pressure-created"> How is gas pressure created? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-when-temperature-increases"> Why does gas pressure increase when temperature increases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-gas-pressure-zero-at-absolute-zero"> Why is gas pressure zero at absolute zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-gas-pressure-increase-with-temperature"> Why does gas pressure increase with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-there-no-gas-pressure-in-a-vacuum"> Why is there no gas pressure in a vacuum? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-total-gas-pressure-in-a-sealed-flask-that-contains-oxygen-at-a-parti-1"> What is the total gas pressure in a sealed flask that contains oxygen at a partial pressure of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-absolute-pressure-of-a-gas-is-550-280-kpa-what-is-its-gage-pressure"> If the absolute pressure of a gas is 550.280 kPa, what is its gage pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-a-gas-sample-occupies-4-2-l-at-a-pressure-of-101-kpa-what-volume-will-it-occu"> If a gas sample occupies 4.2 L at a pressure of 101 kPa. What volume will it occupy if the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gas-pressure"> See all questions in Gas Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 25532 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

If a gas in a closed container is pressurized from 15.0 atm to 16.0 atm and its original temperature was 25°C, what would be the final temperature of the gas in Kelvin?

ac6f798c-6ddd-11ea-bbf4-ccda262736ce

https://socratic.org/questions/how-much-water-would-i-need-to-add-to-500-ml-of-a-2-4-m-kcl-solution-to-make-a-1

0.70 L

start physical_unit 2 2 volume l qc_end physical_unit 15 16 13 14 volume qc_end physical_unit 15 16 13 14 molarity qc_end physical_unit 16 16 20 21 molarity qc_end end

[{"type":"physical unit","value":"Added Volume [OF] water [IN] L"}]

[{"type":"physical unit","value":"0.70 L"}]

[{"type":"physical unit","value":"Volume1 [OF] KCl solution [=] \\pu{2.4 M}"},{"type":"physical unit","value":"Molarity1 [OF] KCl solution [=] \\pu{2.4 M}"},{"type":"physical unit","value":"Molarity2 [OF] solution [=] \\pu{1.0 M}"}]

<h1 class="questionTitle" itemprop="name">How much water would I need to add to 500 mL of a 2.4 M KCl solution to make a 1.0 M solution? </h1>

0.70 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's assume that you're <em>not familiar</em> with the formula for <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/dilution-calculations">dilution calculations</a></strong>.</p> <p>The underlying concept of a <strong>dilution</strong> is that you can <strong>decrease</strong> the concentration of a solution by <strong>increasing its volume</strong> while <strong>keeping the number of moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> constant</strong>. </p> <p>Now, a solution's <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> tells you the number of moles of solute present in <em>one liter</em> of that solution. </p> <blockquote> <p><mathjax>#color(blue)(c = n_"solute"/V_"solution")#</mathjax></p> </blockquote> <p>In a dilution, you know that the number of moles of solute <strong>must remain constant</strong>. This means that you can use the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and volume of the initial solution to figure out how many moles it contains </p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies n = c xx V)#</mathjax></p> <p><mathjax>#n_(KCl) = 2.4"moles"/color(red)(cancel(color(black)("L"))) * 500 * 10^(-3)color(red)(cancel(color(black)("L"))) = "1.2 moles KCl"#</mathjax></p> </blockquote> <p>This is exactly how many moles of potassium chloride must be present in the target solution, which means that you have</p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies V = n/c)#</mathjax></p> <p><mathjax>#V_"target" = (1.2color(red)(cancel(color(black)("moles"))))/(1.0color(red)(cancel(color(black)("moles")))/"L") = "1.2 L"#</mathjax></p> </blockquote> <p>So, you need the volume of the target solution to be equal to </p> <blockquote> <p><mathjax>#V_"target" = "1.2 L" = 1.2 * 10^3"mL" = "1200 mL"#</mathjax></p> </blockquote> <p>This means that you must add </p> <blockquote> <p><mathjax>#V_"added" = "1200 mL" - "500 mL" = color(green)("700 mL")#</mathjax></p> </blockquote> <p>to your initial solution to get its molarity down from <mathjax>#"2.4 M"#</mathjax> to <mathjax>#"1.0 M"#</mathjax>. </p> <p>This is exactly how the formula for <a href="http://socratic.org/chemistry/solutions-and-their-behavior/dilution-calculations">dilution calculations</a> works</p> <blockquote> <p><mathjax>#color(blue)(overbrace(c_1 xx V_1)^(color(brown)("moles of solute in initial solution")) = overbrace(c_2 xx V_2)^(color(brown)("moles of solute in diluted solution")))#</mathjax></p> </blockquote> <p>Here</p> <p><mathjax>#c_1#</mathjax>, <mathjax>#V_1#</mathjax> - the concentration and volume of the initial solution<br/> <mathjax>#c_2#</mathjax>, <mathjax>#V_2#</mathjax> - the concentration and volume of the target solution</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"700 mL"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's assume that you're <em>not familiar</em> with the formula for <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/dilution-calculations">dilution calculations</a></strong>.</p> <p>The underlying concept of a <strong>dilution</strong> is that you can <strong>decrease</strong> the concentration of a solution by <strong>increasing its volume</strong> while <strong>keeping the number of moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> constant</strong>. </p> <p>Now, a solution's <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> tells you the number of moles of solute present in <em>one liter</em> of that solution. </p> <blockquote> <p><mathjax>#color(blue)(c = n_"solute"/V_"solution")#</mathjax></p> </blockquote> <p>In a dilution, you know that the number of moles of solute <strong>must remain constant</strong>. This means that you can use the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and volume of the initial solution to figure out how many moles it contains </p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies n = c xx V)#</mathjax></p> <p><mathjax>#n_(KCl) = 2.4"moles"/color(red)(cancel(color(black)("L"))) * 500 * 10^(-3)color(red)(cancel(color(black)("L"))) = "1.2 moles KCl"#</mathjax></p> </blockquote> <p>This is exactly how many moles of potassium chloride must be present in the target solution, which means that you have</p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies V = n/c)#</mathjax></p> <p><mathjax>#V_"target" = (1.2color(red)(cancel(color(black)("moles"))))/(1.0color(red)(cancel(color(black)("moles")))/"L") = "1.2 L"#</mathjax></p> </blockquote> <p>So, you need the volume of the target solution to be equal to </p> <blockquote> <p><mathjax>#V_"target" = "1.2 L" = 1.2 * 10^3"mL" = "1200 mL"#</mathjax></p> </blockquote> <p>This means that you must add </p> <blockquote> <p><mathjax>#V_"added" = "1200 mL" - "500 mL" = color(green)("700 mL")#</mathjax></p> </blockquote> <p>to your initial solution to get its molarity down from <mathjax>#"2.4 M"#</mathjax> to <mathjax>#"1.0 M"#</mathjax>. </p> <p>This is exactly how the formula for <a href="http://socratic.org/chemistry/solutions-and-their-behavior/dilution-calculations">dilution calculations</a> works</p> <blockquote> <p><mathjax>#color(blue)(overbrace(c_1 xx V_1)^(color(brown)("moles of solute in initial solution")) = overbrace(c_2 xx V_2)^(color(brown)("moles of solute in diluted solution")))#</mathjax></p> </blockquote> <p>Here</p> <p><mathjax>#c_1#</mathjax>, <mathjax>#V_1#</mathjax> - the concentration and volume of the initial solution<br/> <mathjax>#c_2#</mathjax>, <mathjax>#V_2#</mathjax> - the concentration and volume of the target solution</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How much water would I need to add to 500 mL of a 2.4 M KCl solution to make a 1.0 M solution? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="227037" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-16T10:48:53" itemprop="dateCreated"> Feb 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"700 mL"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's assume that you're <em>not familiar</em> with the formula for <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/dilution-calculations">dilution calculations</a></strong>.</p> <p>The underlying concept of a <strong>dilution</strong> is that you can <strong>decrease</strong> the concentration of a solution by <strong>increasing its volume</strong> while <strong>keeping the number of moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> constant</strong>. </p> <p>Now, a solution's <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> tells you the number of moles of solute present in <em>one liter</em> of that solution. </p> <blockquote> <p><mathjax>#color(blue)(c = n_"solute"/V_"solution")#</mathjax></p> </blockquote> <p>In a dilution, you know that the number of moles of solute <strong>must remain constant</strong>. This means that you can use the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and volume of the initial solution to figure out how many moles it contains </p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies n = c xx V)#</mathjax></p> <p><mathjax>#n_(KCl) = 2.4"moles"/color(red)(cancel(color(black)("L"))) * 500 * 10^(-3)color(red)(cancel(color(black)("L"))) = "1.2 moles KCl"#</mathjax></p> </blockquote> <p>This is exactly how many moles of potassium chloride must be present in the target solution, which means that you have</p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies V = n/c)#</mathjax></p> <p><mathjax>#V_"target" = (1.2color(red)(cancel(color(black)("moles"))))/(1.0color(red)(cancel(color(black)("moles")))/"L") = "1.2 L"#</mathjax></p> </blockquote> <p>So, you need the volume of the target solution to be equal to </p> <blockquote> <p><mathjax>#V_"target" = "1.2 L" = 1.2 * 10^3"mL" = "1200 mL"#</mathjax></p> </blockquote> <p>This means that you must add </p> <blockquote> <p><mathjax>#V_"added" = "1200 mL" - "500 mL" = color(green)("700 mL")#</mathjax></p> </blockquote> <p>to your initial solution to get its molarity down from <mathjax>#"2.4 M"#</mathjax> to <mathjax>#"1.0 M"#</mathjax>. </p> <p>This is exactly how the formula for <a href="http://socratic.org/chemistry/solutions-and-their-behavior/dilution-calculations">dilution calculations</a> works</p> <blockquote> <p><mathjax>#color(blue)(overbrace(c_1 xx V_1)^(color(brown)("moles of solute in initial solution")) = overbrace(c_2 xx V_2)^(color(brown)("moles of solute in diluted solution")))#</mathjax></p> </blockquote> <p>Here</p> <p><mathjax>#c_1#</mathjax>, <mathjax>#V_1#</mathjax> - the concentration and volume of the initial solution<br/> <mathjax>#c_2#</mathjax>, <mathjax>#V_2#</mathjax> - the concentration and volume of the target solution</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/227037" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-solution-solute-and-solvent-related"> How are solution, solute, and solvent related? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutions-become-saturated"> Why do solutions become saturated? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-solutions"> How does temperature affect solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-solution-differ-from-a-colloid"> How does a solution differ from a colloid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/calculate-the-amount-of-1-m-naoh-aqueous-solution-needed-to-make-100-ml-of-0-5-m"> Calculate the amount of 1 M NaOH aqueous solution needed to make 100 mL of 0.5 M NaOH aqueous solution. </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-buffering-a-solution-change-the-solutions-behavior"> How does buffering a solution change the solutions behavior? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-benedict-s-solution-change-colour"> How does Benedict's solution change colour? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/describe-how-would-you-prepare-1-l-of-a-1-m-solution-of-sodium-chloride-the-gram"> Describe how would you prepare 1 L of a 1 M solution of sodium chloride. 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How much water would I need to add to 500 mL of a 2.4 M KCl solution to make a 1.0 M solution?

aa7140b7-6ddd-11ea-a5a9-ccda262736ce

https://socratic.org/questions/59a65e9a11ef6b7acf25f722

82.24%

start physical_unit 8 8 mass_percent none qc_end substance 10 10 qc_end end

[{"type":"physical unit","value":"Percentage composition by mass [OF] nitrogen"}]

[{"type":"physical unit","value":"82.24%"}]

[{"type":"substance name","value":"Ammonia"}]

<h1 class="questionTitle" itemprop="name">What is the percentage composition by mass of nitrogen in ammonia?</h1>

82.24%

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus taking molar masses......we get:</p> <p><mathjax>#(14.01*g*mol^-1)/(14.01*g*mol^-1+3xx1.00794*g*mol^-1)xx100%#</mathjax></p> <p><mathjax>#~=80%#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well it is simply <mathjax>#"Mass of nitrogen"/"Mass of nitrogen and hydrogen"xx100%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus taking molar masses......we get:</p> <p><mathjax>#(14.01*g*mol^-1)/(14.01*g*mol^-1+3xx1.00794*g*mol^-1)xx100%#</mathjax></p> <p><mathjax>#~=80%#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the percentage composition by mass of nitrogen in ammonia?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/percent-composition" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Composition</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="469683" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-30T06:58:47" itemprop="dateCreated"> Aug 30, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well it is simply <mathjax>#"Mass of nitrogen"/"Mass of nitrogen and hydrogen"xx100%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus taking molar masses......we get:</p> <p><mathjax>#(14.01*g*mol^-1)/(14.01*g*mol^-1+3xx1.00794*g*mol^-1)xx100%#</mathjax></p> <p><mathjax>#~=80%#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/469683" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="469684" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-30T07:02:46" itemprop="dateCreated"> Aug 30, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The mass percent of <mathjax>#"N"#</mathjax> in <mathjax>#"NH"_3#</mathjax> is <mathjax>#82.244%#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Divide the mass of <mathjax>#"N"#</mathjax> by the mass of <mathjax>#"NH"_3#</mathjax>, then multiply by <mathjax>#100#</mathjax></p> <p>The chemical formula for ammonia is <mathjax>#"NH"_3#</mathjax>. The formula indicates that in each mole of <mathjax>#"NH"_3#</mathjax>, there is one mole of <mathjax>#"N"#</mathjax> atoms.</p> <p>The molar mass of ammonia is <mathjax>#"17.031 g/mol"#</mathjax>. The molar mass of <mathjax>#"N"#</mathjax> is <mathjax>#"14.007 g/mol"#</mathjax>.</p> <p><mathjax>#"mass percent N"#</mathjax><mathjax>#=#</mathjax><mathjax>#(14.007color(red)cancel(color(black)("g/mol")))/(17.031color(red)cancel(color(black)("g/mol")))xx100="82.244%"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/469684" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-mole-percent"> What is mole percent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188602bf3469570e2e8b"> Question #e2e8b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188702bf34695a6bc737"> Question #bc737 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418be02bf34695a6bc73b"> Question #bc73b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c202bf3469570e2e8f"> Question #e2e8f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c802bf346963eb9857"> Question #b9857 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418ca02bf346963eb985b"> Question #b985b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418cc02bf34694a4fee41"> Question #fee41 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418d502bf34694c8c5c01"> Question #c5c01 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4196e02bf34695a6bc73f"> Question #bc73f </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/percent-composition"> See all questions in Percent Composition </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 23388 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the percentage composition by mass of nitrogen in ammonia?

acf2282e-6ddd-11ea-bcb1-ccda262736ce

https://socratic.org/questions/58bd6b8711ef6b029edf1392

11.45

start physical_unit 6 6 ph none qc_end physical_unit 13 13 10 11 concentration qc_end physical_unit 13 13 16 18 kb qc_end end

[{"type":"physical unit","value":"pH [OF] ammonia solution"}]

[{"type":"physical unit","value":"11.45"}]

[{"type":"physical unit","value":"Concentration [OF] ammonia solution [=] \\pu{0.450 mol/L}"},{"type":"physical unit","value":"Kb [OF] ammonia [=] \\pu{1.80 × 10^(-5)}"}]

<h1 class="questionTitle" itemprop="name">What is the #pH# of a solution whose concentration is #0.450*mol*L^-1# in ammonia; #K_b=1.80xx10^-5#?</h1>

11.45

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the equilibrium:</p> <p><mathjax>#NH_3(aq) + H_2O(l) rightleftharpoons NH_4^(+) + HO^-#</mathjax>.</p> <p>We set up the equilibrium in the usual way:</p> <p><mathjax>#K_b=1.80xx10^-5=([NH_4^+][HO^-])/([NH_3(aq)])#</mathjax></p> <p>And we call the concentration of ammonia that hydrolyzes <mathjax>#x#</mathjax>.</p> <p>And thus: <mathjax>#K_b=1.80xx10^-5=x^2/(0.450-x)#</mathjax></p> <p>If, we assume that <mathjax>#0.450&gt;x#</mathjax>, then <mathjax>#x_1=sqrt(1.80xx10^-5xx0.450)#</mathjax></p> <p><mathjax>#=2.85xx10^-3#</mathjax>, which is indeed small compared to <mathjax>#0.450#</mathjax>, but since we have an estimate for <mathjax>#x_1#</mathjax>, we can put it thru the washing again, and come up with:</p> <p><mathjax>#x_2=sqrt(1.80xx10^-5xx(0.450-2.85xx10^-3))=2.84xx10^-3#</mathjax></p> <p><mathjax>#x_3=sqrt(1.80xx10^-5xx(0.450-2.84xx10^-3))=2.84xx10^-3#</mathjax></p> <p>Clearly I am making a meal of the successive approximations, but I think you can get the gist of the operation. Approximate, then substitute, then resubstitute, till you reach a consistent answer. Alternatively, you could have used the quadratic equation, but here there are more terms to include, and more mistakes (potentially) to make. </p> <p>And thus at equilibrium, </p> <p><mathjax>#[NH_4^+]=[HO^-]=2.84xx10^-3*mol*L^-1#</mathjax></p> <p><mathjax>#pOH=-log_10[HO^-]=-log_10(2.84xx10^-3)=2.55#</mathjax></p> <p>And, since in aqueous solution, <mathjax>#pH+pOH=14#</mathjax>, <mathjax>#pH=11.45#</mathjax>.</p> <p>If I were you, I would apply this general method to other <mathjax>#pH#</mathjax> problems. You can get very efficient at their <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>, and you must practise how to manipulate your calculator. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=11.5#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the equilibrium:</p> <p><mathjax>#NH_3(aq) + H_2O(l) rightleftharpoons NH_4^(+) + HO^-#</mathjax>.</p> <p>We set up the equilibrium in the usual way:</p> <p><mathjax>#K_b=1.80xx10^-5=([NH_4^+][HO^-])/([NH_3(aq)])#</mathjax></p> <p>And we call the concentration of ammonia that hydrolyzes <mathjax>#x#</mathjax>.</p> <p>And thus: <mathjax>#K_b=1.80xx10^-5=x^2/(0.450-x)#</mathjax></p> <p>If, we assume that <mathjax>#0.450&gt;x#</mathjax>, then <mathjax>#x_1=sqrt(1.80xx10^-5xx0.450)#</mathjax></p> <p><mathjax>#=2.85xx10^-3#</mathjax>, which is indeed small compared to <mathjax>#0.450#</mathjax>, but since we have an estimate for <mathjax>#x_1#</mathjax>, we can put it thru the washing again, and come up with:</p> <p><mathjax>#x_2=sqrt(1.80xx10^-5xx(0.450-2.85xx10^-3))=2.84xx10^-3#</mathjax></p> <p><mathjax>#x_3=sqrt(1.80xx10^-5xx(0.450-2.84xx10^-3))=2.84xx10^-3#</mathjax></p> <p>Clearly I am making a meal of the successive approximations, but I think you can get the gist of the operation. Approximate, then substitute, then resubstitute, till you reach a consistent answer. Alternatively, you could have used the quadratic equation, but here there are more terms to include, and more mistakes (potentially) to make. </p> <p>And thus at equilibrium, </p> <p><mathjax>#[NH_4^+]=[HO^-]=2.84xx10^-3*mol*L^-1#</mathjax></p> <p><mathjax>#pOH=-log_10[HO^-]=-log_10(2.84xx10^-3)=2.55#</mathjax></p> <p>And, since in aqueous solution, <mathjax>#pH+pOH=14#</mathjax>, <mathjax>#pH=11.45#</mathjax>.</p> <p>If I were you, I would apply this general method to other <mathjax>#pH#</mathjax> problems. You can get very efficient at their <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>, and you must practise how to manipulate your calculator. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the #pH# of a solution whose concentration is #0.450*mol*L^-1# in ammonia; #K_b=1.80xx10^-5#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="387421" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-06T15:15:59" itemprop="dateCreated"> Mar 6, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=11.5#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the equilibrium:</p> <p><mathjax>#NH_3(aq) + H_2O(l) rightleftharpoons NH_4^(+) + HO^-#</mathjax>.</p> <p>We set up the equilibrium in the usual way:</p> <p><mathjax>#K_b=1.80xx10^-5=([NH_4^+][HO^-])/([NH_3(aq)])#</mathjax></p> <p>And we call the concentration of ammonia that hydrolyzes <mathjax>#x#</mathjax>.</p> <p>And thus: <mathjax>#K_b=1.80xx10^-5=x^2/(0.450-x)#</mathjax></p> <p>If, we assume that <mathjax>#0.450&gt;x#</mathjax>, then <mathjax>#x_1=sqrt(1.80xx10^-5xx0.450)#</mathjax></p> <p><mathjax>#=2.85xx10^-3#</mathjax>, which is indeed small compared to <mathjax>#0.450#</mathjax>, but since we have an estimate for <mathjax>#x_1#</mathjax>, we can put it thru the washing again, and come up with:</p> <p><mathjax>#x_2=sqrt(1.80xx10^-5xx(0.450-2.85xx10^-3))=2.84xx10^-3#</mathjax></p> <p><mathjax>#x_3=sqrt(1.80xx10^-5xx(0.450-2.84xx10^-3))=2.84xx10^-3#</mathjax></p> <p>Clearly I am making a meal of the successive approximations, but I think you can get the gist of the operation. Approximate, then substitute, then resubstitute, till you reach a consistent answer. Alternatively, you could have used the quadratic equation, but here there are more terms to include, and more mistakes (potentially) to make. </p> <p>And thus at equilibrium, </p> <p><mathjax>#[NH_4^+]=[HO^-]=2.84xx10^-3*mol*L^-1#</mathjax></p> <p><mathjax>#pOH=-log_10[HO^-]=-log_10(2.84xx10^-3)=2.55#</mathjax></p> <p>And, since in aqueous solution, <mathjax>#pH+pOH=14#</mathjax>, <mathjax>#pH=11.45#</mathjax>.</p> <p>If I were you, I would apply this general method to other <mathjax>#pH#</mathjax> problems. You can get very efficient at their <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>, and you must practise how to manipulate your calculator. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/387421" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-at-an-equivalence-point"> How do you determine pH at an equivalence point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-molarity"> How do you determine pH from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-alkalinity-mean"> What does alkalinity mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-base"> What is a base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-acid-base-indicators-change-color"> How do acid base indicators change color? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-neutral-ph"> What is a neutral pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-alkalinity-affect-pool-water"> How does alkalinity affect pool water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-important-in-drinking-water"> Why is pH important in drinking water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-ph-of-solution"> How can I calculate the pH of a solution? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4718 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the #pH# of a solution whose concentration is #0.450*mol*L^-1# in ammonia; #K_b=1.80xx10^-5#?

a97f2fd0-6ddd-11ea-a3e4-ccda262736ce

https://socratic.org/questions/the-activation-energy-of-a-certain-reaction-is-35-3-kj-mol-at-20-degrees-c-the-r

35 degrees C

start physical_unit 24 25 temperature °c qc_end physical_unit 6 6 8 9 activation_barrier qc_end physical_unit 6 6 11 13 temperature qc_end physical_unit 6 6 18 19 reaction_rate_constant qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Temperature2 [OF] this reaction [IN] degrees C"}]

[{"type":"physical unit","value":"35 degrees C"}]

[{"type":"physical unit","value":"Activation energy [OF] the reaction [=] \\pu{35.3 kJ/mol}"},{"type":"physical unit","value":"Temperature1 [OF] the reaction [=] \\pu{20 degrees C}"},{"type":"physical unit","value":"Rate constant [OF] the reaction [=] \\pu{0.0130 s^(-1)}"},{"type":"other","value":"This reaction go twice as fast."}]

<h1 class="questionTitle" itemprop="name">The activation energy of a certain reaction is 35.3 kJ/mol. At 20 degrees C, the rate constant is #0.0130 s^-1#. At what temperature would this reaction go twice as fast? please help?</h1>

35 degrees C

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To solve this question, we can modify the Arrhenius equation which provides a relationship between the equilibrium constant <mathjax>#k#</mathjax> and temperature <mathjax>#T#</mathjax>:</p> <p><mathjax>#lnk=-(E_a)/R(1/T)+lnA#</mathjax></p> <p>To find the new temperature <mathjax>#T_2#</mathjax> of the reaction in this question, we can use the following expression:</p> <p><mathjax>#ln((k_2)/(k_1))=(E_a)/R(1/(T_1)-1/(T_2))#</mathjax></p> <p>If the rate is doubled, the equilibrium constant will also double and therefore, <mathjax>#k_2=2xxk_1=2xx0.0130s^(-1)=0.0260s^(-1)#</mathjax></p> <p>Therefore, <mathjax>#ln((0.0260cancel(s^(-1)))/(0.0130cancel(s^(-1))))=(35300(cancel(J))/(cancel(mol)*cancel(K)))/(8.31(cancel(J))/(cancel(mol)*cancel(K)))(1/(293K)-1/(T_2))#</mathjax></p> <p>Solving for <mathjax>#T_2#</mathjax>: <mathjax>#=&gt;T_2=308K=35^@C#</mathjax></p> <p>Here is a video that explains the theory behind this topic:<br/> <strong>Chemical Kinetics | A Model for Chemical Kinetics &amp; Catalysis.</strong><br/> <iframe src="https://www.youtube.com/embed/952gAYVygZs?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#T_2=308K=35^@C#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To solve this question, we can modify the Arrhenius equation which provides a relationship between the equilibrium constant <mathjax>#k#</mathjax> and temperature <mathjax>#T#</mathjax>:</p> <p><mathjax>#lnk=-(E_a)/R(1/T)+lnA#</mathjax></p> <p>To find the new temperature <mathjax>#T_2#</mathjax> of the reaction in this question, we can use the following expression:</p> <p><mathjax>#ln((k_2)/(k_1))=(E_a)/R(1/(T_1)-1/(T_2))#</mathjax></p> <p>If the rate is doubled, the equilibrium constant will also double and therefore, <mathjax>#k_2=2xxk_1=2xx0.0130s^(-1)=0.0260s^(-1)#</mathjax></p> <p>Therefore, <mathjax>#ln((0.0260cancel(s^(-1)))/(0.0130cancel(s^(-1))))=(35300(cancel(J))/(cancel(mol)*cancel(K)))/(8.31(cancel(J))/(cancel(mol)*cancel(K)))(1/(293K)-1/(T_2))#</mathjax></p> <p>Solving for <mathjax>#T_2#</mathjax>: <mathjax>#=&gt;T_2=308K=35^@C#</mathjax></p> <p>Here is a video that explains the theory behind this topic:<br/> <strong>Chemical Kinetics | A Model for Chemical Kinetics &amp; Catalysis.</strong><br/> <iframe src="https://www.youtube.com/embed/952gAYVygZs?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">The activation energy of a certain reaction is 35.3 kJ/mol. At 20 degrees C, the rate constant is #0.0130 s^-1#. At what temperature would this reaction go twice as fast? please help?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-kinetics" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Kinetics</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-kinetics/rate-of-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Rate of Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="263726" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-08T21:20:10" itemprop="dateCreated"> May 8, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#T_2=308K=35^@C#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To solve this question, we can modify the Arrhenius equation which provides a relationship between the equilibrium constant <mathjax>#k#</mathjax> and temperature <mathjax>#T#</mathjax>:</p> <p><mathjax>#lnk=-(E_a)/R(1/T)+lnA#</mathjax></p> <p>To find the new temperature <mathjax>#T_2#</mathjax> of the reaction in this question, we can use the following expression:</p> <p><mathjax>#ln((k_2)/(k_1))=(E_a)/R(1/(T_1)-1/(T_2))#</mathjax></p> <p>If the rate is doubled, the equilibrium constant will also double and therefore, <mathjax>#k_2=2xxk_1=2xx0.0130s^(-1)=0.0260s^(-1)#</mathjax></p> <p>Therefore, <mathjax>#ln((0.0260cancel(s^(-1)))/(0.0130cancel(s^(-1))))=(35300(cancel(J))/(cancel(mol)*cancel(K)))/(8.31(cancel(J))/(cancel(mol)*cancel(K)))(1/(293K)-1/(T_2))#</mathjax></p> <p>Solving for <mathjax>#T_2#</mathjax>: <mathjax>#=&gt;T_2=308K=35^@C#</mathjax></p> <p>Here is a video that explains the theory behind this topic:<br/> <strong>Chemical Kinetics | A Model for Chemical Kinetics &amp; Catalysis.</strong><br/> <iframe src="https://www.youtube.com/embed/952gAYVygZs?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/263726" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-rate-of-reaction"> How do you calculate rate of reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-rate-of-reaction-be-affected"> How can rate of reaction be affected? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-rate-of-reaction-be-increased"> How can rate of reaction be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-temperature-affect-reaction-rate"> How can temperature affect reaction rate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-rate-of-reaction-be-calculated-from-a-graph"> How can the rate of reaction be calculated from a graph? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-reaction-rates-give-information-about-mechanisms"> How do reaction rates give information about mechanisms? 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The activation energy of a certain reaction is 35.3 kJ/mol. At 20 degrees C, the rate constant is #0.0130 s^-1#. At what temperature would this reaction go twice as fast? please help?

ab29b10b-6ddd-11ea-833d-ccda262736ce

https://socratic.org/questions/the-mass-of-the-ocean-is-about-1-8-x-10-21-kg-if-the-ocean-contains-1-076-by-mas

1.94 × 10^19 kilograms

start physical_unit 20 20 mass kg qc_end physical_unit 3 4 7 10 mass qc_end physical_unit 28 31 15 15 mass_percent qc_end end

[{"type":"physical unit","value":"Mass [OF] Na+ [IN] kilograms"}]

[{"type":"physical unit","value":"1.94 × 10^19 kilograms"}]

[{"type":"physical unit","value":"Mass [OF] the ocean [=] \\pu{1.8 × 10^21 kg}"},{"type":"physical unit","value":"Percent by mass [OF] Na+ in the ocean [=] \\pu{1.076%}"}]

<h1 class="questionTitle" itemprop="name">The mass of the ocean is about #1.8 x 10^21 kg#. If the ocean contains 1.076% by mass sodium ions, #Na^+#, what is the mass in kilograms of #Na^+# in the ocean? </h1>

1.94 × 10^19 kilograms

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Because <mathjax>#1.076%#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#10^-2#</mathjax>, there are thus at least a <mathjax>#1.8xx10^21*kgxx10^-2#</mathjax> mass of sodium ions, i.e. <mathjax>#=#</mathjax> <mathjax>#1.8xx10^19*kg#</mathjax>, which is not an inconsiderable quantity. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#1.8xx10^21*kgxx1.076%#</mathjax> <mathjax>#kg#</mathjax> of sodium ions. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Because <mathjax>#1.076%#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#10^-2#</mathjax>, there are thus at least a <mathjax>#1.8xx10^21*kgxx10^-2#</mathjax> mass of sodium ions, i.e. <mathjax>#=#</mathjax> <mathjax>#1.8xx10^19*kg#</mathjax>, which is not an inconsiderable quantity. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">The mass of the ocean is about #1.8 x 10^21 kg#. If the ocean contains 1.076% by mass sodium ions, #Na^+#, what is the mass in kilograms of #Na^+# in the ocean? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="308361" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-10T16:56:47" itemprop="dateCreated"> Sep 10, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#1.8xx10^21*kgxx1.076%#</mathjax> <mathjax>#kg#</mathjax> of sodium ions. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Because <mathjax>#1.076%#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#10^-2#</mathjax>, there are thus at least a <mathjax>#1.8xx10^21*kgxx10^-2#</mathjax> mass of sodium ions, i.e. <mathjax>#=#</mathjax> <mathjax>#1.8xx10^19*kg#</mathjax>, which is not an inconsiderable quantity. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/308361" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-solution-solute-and-solvent-related"> How are solution, solute, and solvent related? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutions-become-saturated"> Why do solutions become saturated? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-solutions"> How does temperature affect solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-solution-differ-from-a-colloid"> How does a solution differ from a colloid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/calculate-the-amount-of-1-m-naoh-aqueous-solution-needed-to-make-100-ml-of-0-5-m"> Calculate the amount of 1 M NaOH aqueous solution needed to make 100 mL of 0.5 M NaOH aqueous solution. </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-buffering-a-solution-change-the-solutions-behavior"> How does buffering a solution change the solutions behavior? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-benedict-s-solution-change-colour"> How does Benedict's solution change colour? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/describe-how-would-you-prepare-1-l-of-a-1-m-solution-of-sodium-chloride-the-gram"> Describe how would you prepare 1 L of a 1 M solution of sodium chloride. 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The mass of the ocean is about #1.8 x 10^21 kg#. If the ocean contains 1.076% by mass sodium ions, #Na^+#, what is the mass in kilograms of #Na^+# in the ocean?

a9cde81c-6ddd-11ea-9500-ccda262736ce

https://socratic.org/questions/a-balloon-is-filled-with-5-moles-of-helium-gas-at-a-pressure-of-1-18-atm-and-a-t

105.41 L

start physical_unit 25 26 volume l qc_end physical_unit 8 9 5 6 mole qc_end physical_unit 8 9 14 15 pressure qc_end physical_unit 8 9 20 21 temperature qc_end end

[{"type":"physical unit","value":"Volume [OF] the gas [IN] L"}]

[{"type":"physical unit","value":"105.41 L"}]

[{"type":"physical unit","value":"Mole [OF] helium gas [=] \\pu{5 moles}"},{"type":"physical unit","value":"Pressure [OF] helium gas [=] \\pu{1.18 atm}"},{"type":"physical unit","value":"Temperature [OF] helium gas [=] \\pu{303 K}"}]

<h1 class="questionTitle" itemprop="name">A balloon is filled with 5 moles of helium gas. At a pressure of 1.18 atm and a temperature of 303 K, what volume will the gas occupy? </h1>

105.41 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the venerable Ideal Gas Equation….</p> <p><mathjax>#V=(nRT)/P=(5*molxx0.0821*(L*atm)/(K*mol)xx303*K)/(1.18*atm)=??*L#</mathjax></p> <p>Do the units cancel out to give litres? If they do not I have made a mistake....</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V~=100*L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the venerable Ideal Gas Equation….</p> <p><mathjax>#V=(nRT)/P=(5*molxx0.0821*(L*atm)/(K*mol)xx303*K)/(1.18*atm)=??*L#</mathjax></p> <p>Do the units cancel out to give litres? If they do not I have made a mistake....</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A balloon is filled with 5 moles of helium gas. At a pressure of 1.18 atm and a temperature of 303 K, what volume will the gas occupy? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="617710" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-21T20:36:31" itemprop="dateCreated"> May 21, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V~=100*L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the venerable Ideal Gas Equation….</p> <p><mathjax>#V=(nRT)/P=(5*molxx0.0821*(L*atm)/(K*mol)xx303*K)/(1.18*atm)=??*L#</mathjax></p> <p>Do the units cancel out to give litres? If they do not I have made a mistake....</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/617710" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5313 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A balloon is filled with 5 moles of helium gas. At a pressure of 1.18 atm and a temperature of 303 K, what volume will the gas occupy?

abe9ebc1-6ddd-11ea-ab3b-ccda262736ce

https://socratic.org/questions/595a5a97b72cff185b7c1d5d

(C6H10O5)n(s) + 6n O2(g) -> 6n CO2(g) + 5n H2O(l)

start chemical_equation qc_end substance 7 7 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the combustion"}]

[{"type":"chemical equation","value":"(C6H10O5)n(s) + 6n O2(g) -> 6n CO2(g) + 5n H2O(l)"}]

[{"type":"substance name","value":"Paper"}]

<h1 class="questionTitle" itemprop="name">How would we represent the combustion of paper?</h1>

(C6H10O5)n(s) + 6n O2(g) -> 6n CO2(g) + 5n H2O(l)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And we assume complete combustion...........</p> <p><mathjax>#(C_6H_10O_5)_n(s)+6nO_2(g)rarr6nCO_2(g)+5nH_2O(l)+Delta#</mathjax></p> <p>Is this stoichiometrically balanced......? What does the <mathjax>#Delta#</mathjax> symbol mean in this scenario?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, paper is <mathjax>#"cellulose"#</mathjax>, i.e. <mathjax>#(C_6H_10O_5)_n#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And we assume complete combustion...........</p> <p><mathjax>#(C_6H_10O_5)_n(s)+6nO_2(g)rarr6nCO_2(g)+5nH_2O(l)+Delta#</mathjax></p> <p>Is this stoichiometrically balanced......? What does the <mathjax>#Delta#</mathjax> symbol mean in this scenario?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How would we represent the combustion of paper?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="447422" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-03T15:26:54" itemprop="dateCreated"> Jul 3, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, paper is <mathjax>#"cellulose"#</mathjax>, i.e. <mathjax>#(C_6H_10O_5)_n#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And we assume complete combustion...........</p> <p><mathjax>#(C_6H_10O_5)_n(s)+6nO_2(g)rarr6nCO_2(g)+5nH_2O(l)+Delta#</mathjax></p> <p>Is this stoichiometrically balanced......? What does the <mathjax>#Delta#</mathjax> symbol mean in this scenario?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/447422" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-equation-for-photosynthesis"> What is the chemical equation for photosynthesis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-grams-of-each-substance-used-or-produced-w"> How can I know the relative number of grams of each substance used or produced with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-moles-of-each-substance-with-chemical-equa"> How can I know the relative number of moles of each substance with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-chemical-equations-illustrate-that-atoms-are-conserved-1"> How do chemical equations illustrate that atoms are conserved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-formula-of-the-reactants-and-products-with-chemical-equations"> How can I know the formula of the reactants and products with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-potassium-metal-and-chlorine-gas-combi"> How can I balance this chemical equations? 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How would we represent the combustion of paper?

ac9c6b18-6ddd-11ea-ac50-ccda262736ce

https://socratic.org/questions/when-2-00-l-of-1-00-m-of-agno-3-and-1-25-l-of-1-00-m-of-cai-2-fully-react-what-i

0.39 mol/L

start physical_unit 23 23 molarity mol/l qc_end physical_unit 7 7 4 5 molarity qc_end physical_unit 15 15 4 5 molarity qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Molarity [OF] Ca^2+ [IN] mol/L"}]

[{"type":"physical unit","value":"0.39 mol/L"}]

[{"type":"physical unit","value":"Volume [OF] AgNO3 solution [=] \\pu{2.00 L}"},{"type":"physical unit","value":"Molarity [OF] AgNO3 solution [=] \\pu{1.00 M}"},{"type":"physical unit","value":"Molarity [OF] CaI2 solution [=] \\pu{1.00 M}"},{"type":"physical unit","value":"Volume [OF] CaI2 solution [=] \\pu{1.25 L}"},{"type":"other","value":"Fully react."}]

<h1 class="questionTitle" itemprop="name">When 2.00 L of 1.00 M of #AgNO_3# and 1.25 L of 1.00 M of #CaI_2# fully react, what is the molarity of #Ca^2+#?</h1>

0.39 mol/L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The calcium ion, <mathjax>#Ca^(2+)#</mathjax>, which is present in solution as (probably) <mathjax>#[Ca(OH_2)_6]^(2+)#</mathjax>, remains in solution, and expresses its concentration fully because it does not precipitate....</p> <p><mathjax>#"Moles of"#</mathjax> <mathjax>#Ca^(2+)=1.25*Lxx1.00*mol*L^-1=1.25*mol#</mathjax>.</p> <p>The volume of solution is <mathjax>#(2.00+1.25)*L=3.25*L#</mathjax></p> <p>And thus concentration of calcium ion is............</p> <p><mathjax>#(1.25*mol)/((2.00+1.25)*L)=0.385*mol*L^-1......#</mathjax></p> <p>Of course, the silver ion precipitates as a fine yellow powder of <mathjax>#AgI#</mathjax>.........</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>For <mathjax>#2AgNO_3(aq) + CaI_2(aq) rarr 2AgI(s)darr + Ca(NO_3)_2(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The calcium ion, <mathjax>#Ca^(2+)#</mathjax>, which is present in solution as (probably) <mathjax>#[Ca(OH_2)_6]^(2+)#</mathjax>, remains in solution, and expresses its concentration fully because it does not precipitate....</p> <p><mathjax>#"Moles of"#</mathjax> <mathjax>#Ca^(2+)=1.25*Lxx1.00*mol*L^-1=1.25*mol#</mathjax>.</p> <p>The volume of solution is <mathjax>#(2.00+1.25)*L=3.25*L#</mathjax></p> <p>And thus concentration of calcium ion is............</p> <p><mathjax>#(1.25*mol)/((2.00+1.25)*L)=0.385*mol*L^-1......#</mathjax></p> <p>Of course, the silver ion precipitates as a fine yellow powder of <mathjax>#AgI#</mathjax>.........</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">When 2.00 L of 1.00 M of #AgNO_3# and 1.25 L of 1.00 M of #CaI_2# fully react, what is the molarity of #Ca^2+#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="443962" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-24T19:35:20" itemprop="dateCreated"> Jun 24, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>For <mathjax>#2AgNO_3(aq) + CaI_2(aq) rarr 2AgI(s)darr + Ca(NO_3)_2(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The calcium ion, <mathjax>#Ca^(2+)#</mathjax>, which is present in solution as (probably) <mathjax>#[Ca(OH_2)_6]^(2+)#</mathjax>, remains in solution, and expresses its concentration fully because it does not precipitate....</p> <p><mathjax>#"Moles of"#</mathjax> <mathjax>#Ca^(2+)=1.25*Lxx1.00*mol*L^-1=1.25*mol#</mathjax>.</p> <p>The volume of solution is <mathjax>#(2.00+1.25)*L=3.25*L#</mathjax></p> <p>And thus concentration of calcium ion is............</p> <p><mathjax>#(1.25*mol)/((2.00+1.25)*L)=0.385*mol*L^-1......#</mathjax></p> <p>Of course, the silver ion precipitates as a fine yellow powder of <mathjax>#AgI#</mathjax>.........</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/443962" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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When 2.00 L of 1.00 M of #AgNO_3# and 1.25 L of 1.00 M of #CaI_2# fully react, what is the molarity of #Ca^2+#?

aa7d27d0-6ddd-11ea-98fd-ccda262736ce

https://socratic.org/questions/58a4bb00b72cff7933c74396

0.99 moles

start physical_unit 4 5 mole mol qc_end physical_unit 12 13 9 10 mass qc_end end

[{"type":"physical unit","value":"Mole [OF] sodium chloride [IN] moles"}]

[{"type":"physical unit","value":"0.99 moles"}]

[{"type":"physical unit","value":"Mass [OF] the salt [=] \\pu{58 g}"}]

<h1 class="questionTitle" itemprop="name">How many moles of sodium chloride are present in #58*g# of the salt?</h1>

0.99 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><h2>Molar mass of NaCl</h2> <p><mathjax>#=#</mathjax> <mathjax>#"Atomic mass of sodium + atomic mass of chlorine"#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(22.99+35.45)*g*mol^-1.#</mathjax></p> <p>From where do you get these atomic masses?</p> <p>The number of moles of sodium chloride in a mass of <mathjax>#58*g#</mathjax> sodium chloride is given by the quotient,</p> <p><mathjax>#"Mass"/"Molar mass"=(58*cancelg)/((22.99+35.45)*cancelg*mol^-1)#</mathjax> <mathjax>#=#</mathjax> </p> <p><mathjax>#"A tad under one mole."#</mathjax></p> <p>Note that this is dimensionally consistent in that <mathjax>#1/(mol^-1)=1/(1/(mol))=mol#</mathjax> as required.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molar mass of sodium chloride is in fact <mathjax>#58.44*g#</mathjax>.....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><h2>Molar mass of NaCl</h2> <p><mathjax>#=#</mathjax> <mathjax>#"Atomic mass of sodium + atomic mass of chlorine"#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(22.99+35.45)*g*mol^-1.#</mathjax></p> <p>From where do you get these atomic masses?</p> <p>The number of moles of sodium chloride in a mass of <mathjax>#58*g#</mathjax> sodium chloride is given by the quotient,</p> <p><mathjax>#"Mass"/"Molar mass"=(58*cancelg)/((22.99+35.45)*cancelg*mol^-1)#</mathjax> <mathjax>#=#</mathjax> </p> <p><mathjax>#"A tad under one mole."#</mathjax></p> <p>Note that this is dimensionally consistent in that <mathjax>#1/(mol^-1)=1/(1/(mol))=mol#</mathjax> as required.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles of sodium chloride are present in #58*g# of the salt?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="378343" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-15T21:55:06" itemprop="dateCreated"> Feb 15, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molar mass of sodium chloride is in fact <mathjax>#58.44*g#</mathjax>.....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><h2>Molar mass of NaCl</h2> <p><mathjax>#=#</mathjax> <mathjax>#"Atomic mass of sodium + atomic mass of chlorine"#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(22.99+35.45)*g*mol^-1.#</mathjax></p> <p>From where do you get these atomic masses?</p> <p>The number of moles of sodium chloride in a mass of <mathjax>#58*g#</mathjax> sodium chloride is given by the quotient,</p> <p><mathjax>#"Mass"/"Molar mass"=(58*cancelg)/((22.99+35.45)*cancelg*mol^-1)#</mathjax> <mathjax>#=#</mathjax> </p> <p><mathjax>#"A tad under one mole."#</mathjax></p> <p>Note that this is dimensionally consistent in that <mathjax>#1/(mol^-1)=1/(1/(mol))=mol#</mathjax> as required.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/378343" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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How many moles of sodium chloride are present in #58*g# of the salt?

a9ca2832-6ddd-11ea-a496-ccda262736ce

https://socratic.org/questions/5811657411ef6b7e24f0a9f4

1.37

start physical_unit 19 20 ph none qc_end physical_unit 5 5 1 2 mass qc_end physical_unit 14 14 10 11 volume qc_end end

[{"type":"physical unit","value":"pH [OF] this solution"}]

[{"type":"physical unit","value":"1.37"}]

[{"type":"physical unit","value":"Mass [OF] HCl(g) [=] \\pu{0.0729 g}"},{"type":"physical unit","value":"Volume [OF] water [=] \\pu{50 mL}"}]

<h1 class="questionTitle" itemprop="name">A #0.0729*g# mass of #HCl(g)# was dissolved in a #50*mL# volume of water. What is #pH# of this solution?</h1>

1.37

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#HCl(g) + H_2O(l) rarr H_3O^+ + Cl^-#</mathjax></p> <p>This reaction is essentially quantitative, and the solution will be stoichiometric in <mathjax>#H_3O^+#</mathjax>.</p> <p><mathjax>#"Moles of HCl"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(0.0729*g)/(36.46*g*mol^-1)#</mathjax></p> <p>And thus <mathjax>#[H_3O^+]=(0.0729*g)/(36.46*g*mol^-1)xx1/(50xx10^-3L)#</mathjax>; this gives an answer in <mathjax>#mol*L^-1#</mathjax> as is required for a concentration. </p> <p>And finally.....................</p> <p><mathjax>#pH=-log_10{(0.0729*g)/(36.46*g*mol^-1)xx1/(50xx10^-3L)}#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p> <p>What is <mathjax>#pOH#</mathjax> of this solution?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=-log_10[H_3O^+]=??#</mathjax></p> <p><mathjax>#pH&lt;3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#HCl(g) + H_2O(l) rarr H_3O^+ + Cl^-#</mathjax></p> <p>This reaction is essentially quantitative, and the solution will be stoichiometric in <mathjax>#H_3O^+#</mathjax>.</p> <p><mathjax>#"Moles of HCl"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(0.0729*g)/(36.46*g*mol^-1)#</mathjax></p> <p>And thus <mathjax>#[H_3O^+]=(0.0729*g)/(36.46*g*mol^-1)xx1/(50xx10^-3L)#</mathjax>; this gives an answer in <mathjax>#mol*L^-1#</mathjax> as is required for a concentration. </p> <p>And finally.....................</p> <p><mathjax>#pH=-log_10{(0.0729*g)/(36.46*g*mol^-1)xx1/(50xx10^-3L)}#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p> <p>What is <mathjax>#pOH#</mathjax> of this solution?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A #0.0729*g# mass of #HCl(g)# was dissolved in a #50*mL# volume of water. What is #pH# of this solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="327170" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-27T05:13:49" itemprop="dateCreated"> Oct 27, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=-log_10[H_3O^+]=??#</mathjax></p> <p><mathjax>#pH&lt;3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#HCl(g) + H_2O(l) rarr H_3O^+ + Cl^-#</mathjax></p> <p>This reaction is essentially quantitative, and the solution will be stoichiometric in <mathjax>#H_3O^+#</mathjax>.</p> <p><mathjax>#"Moles of HCl"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(0.0729*g)/(36.46*g*mol^-1)#</mathjax></p> <p>And thus <mathjax>#[H_3O^+]=(0.0729*g)/(36.46*g*mol^-1)xx1/(50xx10^-3L)#</mathjax>; this gives an answer in <mathjax>#mol*L^-1#</mathjax> as is required for a concentration. </p> <p>And finally.....................</p> <p><mathjax>#pH=-log_10{(0.0729*g)/(36.46*g*mol^-1)xx1/(50xx10^-3L)}#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p> <p>What is <mathjax>#pOH#</mathjax> of this solution?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/327170" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? 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A #0.0729*g# mass of #HCl(g)# was dissolved in a #50*mL# volume of water. What is #pH# of this solution?

abdcfe8a-6ddd-11ea-8137-ccda262736ce

https://socratic.org/questions/calculate-the-ph-of-the-solution-below-30-00ml-of-0-100-m-hcl-is-mixed-with-25-0

2.04

start physical_unit 4 5 ph none qc_end physical_unit 5 5 7 8 volume qc_end physical_unit 12 12 10 11 molarity qc_end physical_unit 5 5 16 17 volume qc_end physical_unit 21 21 10 11 molarity qc_end end

[{"type":"physical unit","value":"pH [OF] the solution"}]

[{"type":"physical unit","value":"2.04"}]

[{"type":"physical unit","value":"Volume [OF] HCl solution [=] \\pu{30.00 mL}"},{"type":"physical unit","value":"Molarity [OF] HCl solution [=] \\pu{0.100 M}"},{"type":"physical unit","value":"Volume [OF] NH3 solution [=] \\pu{25.00 mL}"},{"type":"physical unit","value":"Molarity [OF] NH3 solution [=] \\pu{0.100 M}"}]

<h1 class="questionTitle" itemprop="name">Calculate the pH of the solution below. 30.00mL of 0.100 M #"HCl"# is mixed with 25.00 mL of 0.100 M #"NH"_3# ? </h1>

2.04

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing to mention here is that you're <strong>not</strong> dealing with a buffer solution. Here's why. </p> <p>Ammonia and hydrochloric acid react in a <mathjax>#1:1#</mathjax> mole ratio to produce aqueous ammonium chloride, <mathjax>#"NH"_4"Cl"#</mathjax>. </p> <blockquote> <p><mathjax>#"NH"_ (3(aq)) + "HCl"_ ((aq)) -&gt; "NH"_ 4"Cl"_ ((aq))#</mathjax></p> </blockquote> <p>The chloride anions coming from the acid are <em>spectator ions</em>, meaning that you can rewrite the chemical equation as</p> <blockquote> <p><mathjax>#"NH"_ (3(aq)) + "H"_ ((aq))^(+) -&gt; "NH"_ (4(aq))^(+)#</mathjax></p> </blockquote> <p>So, <strong>for every mole</strong> of ammonia present in solution, you need <mathjax>#1#</mathjax> <strong>mole</strong> of hydrochloric acid to neutralize it. Use the <em>molarities</em> and <em>volumes</em> of the two <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> to see how many moles of each you're mixing</p> <blockquote> <p><mathjax>#30.00 color(red)(cancel(color(black)("mL"))) * (1color(red)(cancel(color(black)("L"))))/(10^3color(red)(cancel(color(black)("mL")))) * "0.100 moles H"^(+)/(1color(red)(cancel(color(black)("L")))) = "0.00300 moles HCl"#</mathjax></p> <p><mathjax>#25.00 color(red)(cancel(color(black)("mL"))) * (1color(red)(cancel(color(black)("L"))))/(10^3color(red)(cancel(color(black)("mL")))) * "0.100 moles NH"_3/(1color(red)(cancel(color(black)("L")))) = "0.00250 moles NH"_3#</mathjax></p> </blockquote> <p>Notice that you have <strong>fewer moles</strong> of ammonia than of hydrochloric acid. This implies that ammonia will act as a <strong><a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></strong>, i.e. it will be <strong>completely consumed</strong> by the reaction. </p> <p>Once the <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a> reaction is complete, the resulting solution will contain </p> <blockquote> <p><mathjax>#n_ ("NH"_ 3) = "0.00250 moles" - "0.00250 moles" = "0 moles"#</mathjax></p> <p><mathjax>#n_("H"^(+)) = "0.00300 moles" - "0.00250 moles" = "0.00050 moles H"^(+)#</mathjax></p> </blockquote> <p>Now, the reaction produces ammonium cations, <mathjax>#"NH"_4^(+)#</mathjax>, the <strong>conjugate acid</strong> of ammonia, in <mathjax>#1:1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> with the two reactants. </p> <p>This means that the resulting solution will also contain </p> <blockquote> <p><mathjax>#n_ ("NH"_ 4^(+)) = "0.00250 moles NH"_4^(+)#</mathjax></p> </blockquote> <p>The <strong>total volume</strong> of the solution will be </p> <blockquote> <p><mathjax>#V_"total" = "30.00 mL" + "25.00 mL" = "55.00 mL"#</mathjax></p> </blockquote> <p>The <em>concentration</em> of ammonium cations and of hydrogen ions in the final solution will be </p> <blockquote> <p><mathjax>#["NH"_4^(+)] = "0.00250 moles"/(55.00 * 10^(-3)"L") = "0.04545 M"#</mathjax></p> <p><mathjax>#["H"^(+)] = "0.00050 moles"/(55.00 * 10^(-3)"L") = "0.009091 M"#</mathjax></p> </blockquote> <p>Now, the ammonium cation can act as an acid in aqueous solution to release hydrogen ions and reform ammonia</p> <blockquote> <p><mathjax>#"NH"_ (4(aq))^(+) rightleftharpoons "H"_ ((aq))^(+) + "NH"_ (3(aq))#</mathjax></p> </blockquote> <p>However, the <em>acid dissociation constant</em>, <mathjax>#K_a#</mathjax>, for the ammonium cation is equal to </p> <blockquote> <p><mathjax>#K_a = 5.6 * 10^(-10)#</mathjax></p> </blockquote> <p><a href="http://clas.sa.ucsb.edu/staff/Resource%20folder/Chem109ABC/Acid,%20Base%20Strength/Table%20of%20Acids%20w%20Kas%20and%20pKas.pdf" rel="nofollow" target="_blank">http://clas.sa.ucsb.edu/staff/Resource%20folder/Chem109ABC/Acid,%20Base%20Strength/Table%20of%20Acids%20w%20Kas%20and%20pKas.pdf</a></p> <p>This means that a very, very small number of ammonium cations actually release hydrogen ions in solution. </p> <p>Moreover, because the solution already contains hydrogen ions, the above equilibrium will shift <strong>even more to the left</strong> <mathjax>#-&gt;#</mathjax> think <strong><a href="https://socratic.org/chemistry/chemical-equilibrium/le-chatelier-s-principle">Le Chatelier's Principle</a></strong> here. </p> <p>You can thus say that the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the solution will be determined <strong>exclusively</strong> by the <em>unreacted</em> hydrogen ions that were delivered by the hydrochloric acid, meaning that the above equilibrium will produce a <em>very small</em>* amount of hydrogen ions compared with what's already present in the solution. </p> <p>Therefore, you will have</p> <blockquote> <p><mathjax>#"pH" = - log(["H"^(+)])#</mathjax></p> <p><mathjax>#color(green)(bar(ul(|color(white)(a/a)color(black)("pH" = - log(0.009091) = 2.041)color(white)(a/a)|)))#</mathjax></p> </blockquote> <p><em>So, why is this not a buffer solution?</em></p> <p>As you know, buffers contain a weak acid and its conjugate base or a weak base and its conjugate acid in <strong>comparable amounts</strong>.</p> <p>In this case, the neutralization reaction consumes all the ammonia and produces its conjugate acid. So one important element of a buffer, i.e. the <em>weak base</em>, is missing here.</p> <p>Moreover, you have an excess of hydrochloric acid, a <strong>strong acid</strong>, so right from the start you should be able to tell that the pH of the solution will be <strong>quite acidic</strong>. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 2.041#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing to mention here is that you're <strong>not</strong> dealing with a buffer solution. Here's why. </p> <p>Ammonia and hydrochloric acid react in a <mathjax>#1:1#</mathjax> mole ratio to produce aqueous ammonium chloride, <mathjax>#"NH"_4"Cl"#</mathjax>. </p> <blockquote> <p><mathjax>#"NH"_ (3(aq)) + "HCl"_ ((aq)) -&gt; "NH"_ 4"Cl"_ ((aq))#</mathjax></p> </blockquote> <p>The chloride anions coming from the acid are <em>spectator ions</em>, meaning that you can rewrite the chemical equation as</p> <blockquote> <p><mathjax>#"NH"_ (3(aq)) + "H"_ ((aq))^(+) -&gt; "NH"_ (4(aq))^(+)#</mathjax></p> </blockquote> <p>So, <strong>for every mole</strong> of ammonia present in solution, you need <mathjax>#1#</mathjax> <strong>mole</strong> of hydrochloric acid to neutralize it. Use the <em>molarities</em> and <em>volumes</em> of the two <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> to see how many moles of each you're mixing</p> <blockquote> <p><mathjax>#30.00 color(red)(cancel(color(black)("mL"))) * (1color(red)(cancel(color(black)("L"))))/(10^3color(red)(cancel(color(black)("mL")))) * "0.100 moles H"^(+)/(1color(red)(cancel(color(black)("L")))) = "0.00300 moles HCl"#</mathjax></p> <p><mathjax>#25.00 color(red)(cancel(color(black)("mL"))) * (1color(red)(cancel(color(black)("L"))))/(10^3color(red)(cancel(color(black)("mL")))) * "0.100 moles NH"_3/(1color(red)(cancel(color(black)("L")))) = "0.00250 moles NH"_3#</mathjax></p> </blockquote> <p>Notice that you have <strong>fewer moles</strong> of ammonia than of hydrochloric acid. This implies that ammonia will act as a <strong><a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></strong>, i.e. it will be <strong>completely consumed</strong> by the reaction. </p> <p>Once the <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a> reaction is complete, the resulting solution will contain </p> <blockquote> <p><mathjax>#n_ ("NH"_ 3) = "0.00250 moles" - "0.00250 moles" = "0 moles"#</mathjax></p> <p><mathjax>#n_("H"^(+)) = "0.00300 moles" - "0.00250 moles" = "0.00050 moles H"^(+)#</mathjax></p> </blockquote> <p>Now, the reaction produces ammonium cations, <mathjax>#"NH"_4^(+)#</mathjax>, the <strong>conjugate acid</strong> of ammonia, in <mathjax>#1:1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> with the two reactants. </p> <p>This means that the resulting solution will also contain </p> <blockquote> <p><mathjax>#n_ ("NH"_ 4^(+)) = "0.00250 moles NH"_4^(+)#</mathjax></p> </blockquote> <p>The <strong>total volume</strong> of the solution will be </p> <blockquote> <p><mathjax>#V_"total" = "30.00 mL" + "25.00 mL" = "55.00 mL"#</mathjax></p> </blockquote> <p>The <em>concentration</em> of ammonium cations and of hydrogen ions in the final solution will be </p> <blockquote> <p><mathjax>#["NH"_4^(+)] = "0.00250 moles"/(55.00 * 10^(-3)"L") = "0.04545 M"#</mathjax></p> <p><mathjax>#["H"^(+)] = "0.00050 moles"/(55.00 * 10^(-3)"L") = "0.009091 M"#</mathjax></p> </blockquote> <p>Now, the ammonium cation can act as an acid in aqueous solution to release hydrogen ions and reform ammonia</p> <blockquote> <p><mathjax>#"NH"_ (4(aq))^(+) rightleftharpoons "H"_ ((aq))^(+) + "NH"_ (3(aq))#</mathjax></p> </blockquote> <p>However, the <em>acid dissociation constant</em>, <mathjax>#K_a#</mathjax>, for the ammonium cation is equal to </p> <blockquote> <p><mathjax>#K_a = 5.6 * 10^(-10)#</mathjax></p> </blockquote> <p><a href="http://clas.sa.ucsb.edu/staff/Resource%20folder/Chem109ABC/Acid,%20Base%20Strength/Table%20of%20Acids%20w%20Kas%20and%20pKas.pdf" rel="nofollow" target="_blank">http://clas.sa.ucsb.edu/staff/Resource%20folder/Chem109ABC/Acid,%20Base%20Strength/Table%20of%20Acids%20w%20Kas%20and%20pKas.pdf</a></p> <p>This means that a very, very small number of ammonium cations actually release hydrogen ions in solution. </p> <p>Moreover, because the solution already contains hydrogen ions, the above equilibrium will shift <strong>even more to the left</strong> <mathjax>#-&gt;#</mathjax> think <strong><a href="https://socratic.org/chemistry/chemical-equilibrium/le-chatelier-s-principle">Le Chatelier's Principle</a></strong> here. </p> <p>You can thus say that the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the solution will be determined <strong>exclusively</strong> by the <em>unreacted</em> hydrogen ions that were delivered by the hydrochloric acid, meaning that the above equilibrium will produce a <em>very small</em>* amount of hydrogen ions compared with what's already present in the solution. </p> <p>Therefore, you will have</p> <blockquote> <p><mathjax>#"pH" = - log(["H"^(+)])#</mathjax></p> <p><mathjax>#color(green)(bar(ul(|color(white)(a/a)color(black)("pH" = - log(0.009091) = 2.041)color(white)(a/a)|)))#</mathjax></p> </blockquote> <p><em>So, why is this not a buffer solution?</em></p> <p>As you know, buffers contain a weak acid and its conjugate base or a weak base and its conjugate acid in <strong>comparable amounts</strong>.</p> <p>In this case, the neutralization reaction consumes all the ammonia and produces its conjugate acid. So one important element of a buffer, i.e. the <em>weak base</em>, is missing here.</p> <p>Moreover, you have an excess of hydrochloric acid, a <strong>strong acid</strong>, so right from the start you should be able to tell that the pH of the solution will be <strong>quite acidic</strong>. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Calculate the pH of the solution below. 30.00mL of 0.100 M #"HCl"# is mixed with 25.00 mL of 0.100 M #"NH"_3# ? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="314988" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-27T10:28:55" itemprop="dateCreated"> Sep 27, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 2.041#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing to mention here is that you're <strong>not</strong> dealing with a buffer solution. Here's why. </p> <p>Ammonia and hydrochloric acid react in a <mathjax>#1:1#</mathjax> mole ratio to produce aqueous ammonium chloride, <mathjax>#"NH"_4"Cl"#</mathjax>. </p> <blockquote> <p><mathjax>#"NH"_ (3(aq)) + "HCl"_ ((aq)) -&gt; "NH"_ 4"Cl"_ ((aq))#</mathjax></p> </blockquote> <p>The chloride anions coming from the acid are <em>spectator ions</em>, meaning that you can rewrite the chemical equation as</p> <blockquote> <p><mathjax>#"NH"_ (3(aq)) + "H"_ ((aq))^(+) -&gt; "NH"_ (4(aq))^(+)#</mathjax></p> </blockquote> <p>So, <strong>for every mole</strong> of ammonia present in solution, you need <mathjax>#1#</mathjax> <strong>mole</strong> of hydrochloric acid to neutralize it. Use the <em>molarities</em> and <em>volumes</em> of the two <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> to see how many moles of each you're mixing</p> <blockquote> <p><mathjax>#30.00 color(red)(cancel(color(black)("mL"))) * (1color(red)(cancel(color(black)("L"))))/(10^3color(red)(cancel(color(black)("mL")))) * "0.100 moles H"^(+)/(1color(red)(cancel(color(black)("L")))) = "0.00300 moles HCl"#</mathjax></p> <p><mathjax>#25.00 color(red)(cancel(color(black)("mL"))) * (1color(red)(cancel(color(black)("L"))))/(10^3color(red)(cancel(color(black)("mL")))) * "0.100 moles NH"_3/(1color(red)(cancel(color(black)("L")))) = "0.00250 moles NH"_3#</mathjax></p> </blockquote> <p>Notice that you have <strong>fewer moles</strong> of ammonia than of hydrochloric acid. This implies that ammonia will act as a <strong><a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a></strong>, i.e. it will be <strong>completely consumed</strong> by the reaction. </p> <p>Once the <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a> reaction is complete, the resulting solution will contain </p> <blockquote> <p><mathjax>#n_ ("NH"_ 3) = "0.00250 moles" - "0.00250 moles" = "0 moles"#</mathjax></p> <p><mathjax>#n_("H"^(+)) = "0.00300 moles" - "0.00250 moles" = "0.00050 moles H"^(+)#</mathjax></p> </blockquote> <p>Now, the reaction produces ammonium cations, <mathjax>#"NH"_4^(+)#</mathjax>, the <strong>conjugate acid</strong> of ammonia, in <mathjax>#1:1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> with the two reactants. </p> <p>This means that the resulting solution will also contain </p> <blockquote> <p><mathjax>#n_ ("NH"_ 4^(+)) = "0.00250 moles NH"_4^(+)#</mathjax></p> </blockquote> <p>The <strong>total volume</strong> of the solution will be </p> <blockquote> <p><mathjax>#V_"total" = "30.00 mL" + "25.00 mL" = "55.00 mL"#</mathjax></p> </blockquote> <p>The <em>concentration</em> of ammonium cations and of hydrogen ions in the final solution will be </p> <blockquote> <p><mathjax>#["NH"_4^(+)] = "0.00250 moles"/(55.00 * 10^(-3)"L") = "0.04545 M"#</mathjax></p> <p><mathjax>#["H"^(+)] = "0.00050 moles"/(55.00 * 10^(-3)"L") = "0.009091 M"#</mathjax></p> </blockquote> <p>Now, the ammonium cation can act as an acid in aqueous solution to release hydrogen ions and reform ammonia</p> <blockquote> <p><mathjax>#"NH"_ (4(aq))^(+) rightleftharpoons "H"_ ((aq))^(+) + "NH"_ (3(aq))#</mathjax></p> </blockquote> <p>However, the <em>acid dissociation constant</em>, <mathjax>#K_a#</mathjax>, for the ammonium cation is equal to </p> <blockquote> <p><mathjax>#K_a = 5.6 * 10^(-10)#</mathjax></p> </blockquote> <p><a href="http://clas.sa.ucsb.edu/staff/Resource%20folder/Chem109ABC/Acid,%20Base%20Strength/Table%20of%20Acids%20w%20Kas%20and%20pKas.pdf" rel="nofollow" target="_blank">http://clas.sa.ucsb.edu/staff/Resource%20folder/Chem109ABC/Acid,%20Base%20Strength/Table%20of%20Acids%20w%20Kas%20and%20pKas.pdf</a></p> <p>This means that a very, very small number of ammonium cations actually release hydrogen ions in solution. </p> <p>Moreover, because the solution already contains hydrogen ions, the above equilibrium will shift <strong>even more to the left</strong> <mathjax>#-&gt;#</mathjax> think <strong><a href="https://socratic.org/chemistry/chemical-equilibrium/le-chatelier-s-principle">Le Chatelier's Principle</a></strong> here. </p> <p>You can thus say that the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the solution will be determined <strong>exclusively</strong> by the <em>unreacted</em> hydrogen ions that were delivered by the hydrochloric acid, meaning that the above equilibrium will produce a <em>very small</em>* amount of hydrogen ions compared with what's already present in the solution. </p> <p>Therefore, you will have</p> <blockquote> <p><mathjax>#"pH" = - log(["H"^(+)])#</mathjax></p> <p><mathjax>#color(green)(bar(ul(|color(white)(a/a)color(black)("pH" = - log(0.009091) = 2.041)color(white)(a/a)|)))#</mathjax></p> </blockquote> <p><em>So, why is this not a buffer solution?</em></p> <p>As you know, buffers contain a weak acid and its conjugate base or a weak base and its conjugate acid in <strong>comparable amounts</strong>.</p> <p>In this case, the neutralization reaction consumes all the ammonia and produces its conjugate acid. So one important element of a buffer, i.e. the <em>weak base</em>, is missing here.</p> <p>Moreover, you have an excess of hydrochloric acid, a <strong>strong acid</strong>, so right from the start you should be able to tell that the pH of the solution will be <strong>quite acidic</strong>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/314988" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3683 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

Calculate the pH of the solution below. 30.00mL of 0.100 M #"HCl"# is mixed with 25.00 mL of 0.100 M #"NH"_3# ?

a8cdbe47-6ddd-11ea-8726-ccda262736ce

https://socratic.org/questions/what-will-be-the-ph-of-the-solution-that-results-from-the-addition-of-20ml-of-0-

2.70

start physical_unit 6 7 ph none qc_end physical_unit 19 19 17 18 molarity qc_end physical_unit 19 19 14 15 volume qc_end physical_unit 26 26 17 18 molarity qc_end physical_unit 26 26 21 22 volume qc_end end

[{"type":"physical unit","value":"pH [OF] the solution"}]

[{"type":"physical unit","value":"2.70"}]

[{"type":"physical unit","value":"Molarity [OF] Ca(OH)2 [=] \\pu{0.01 M}"},{"type":"physical unit","value":"Volume [OF] Ca(OH)2 [=] \\pu{20 mL}"},{"type":"physical unit","value":"Molarity [OF] HCl [=] \\pu{0.01 M }"},{"type":"physical unit","value":"Volume [OF] HCl [=] \\pu{30 mL}"}]

<h1 class="questionTitle" itemprop="name">What will be the pH of the solution that results from the addition of 20mL of 0.01M Ca(OH)2 to 30mL of 0.01M HCl?</h1>

2.70

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It is a strong acid-base reaction as HCl is a strong acid and Ca(OH)2 is a strong base</p> <p><mathjax>#Ca(OH)_2 + HCl = CaCl_2 + 2 H_2O#</mathjax></p> <p>The net ionic reaction is </p> <p><mathjax>#H^+(aq) + OH^(-)(aq) = H_2O(l)#</mathjax></p> <p>The number <mathjax>#H^+#</mathjax> ions in the solution is the concentration of HCl because strong acids dissociate completely thus producing <br/> <mathjax>#"1mole of H+"/"1mole of acid."#</mathjax> This is only applicable to strong acids. The same is the case with strong base but instead of <mathjax>#H^+#</mathjax> they produce strong conjugate bases like <mathjax>#OH^(-)#</mathjax></p> <p>HCl is a strong acid thus </p> <p>moles of HCl = moles of <mathjax>#H^+#</mathjax></p> <p>Calculate no. of moles in 30mL of 0.01M HCl</p> <p><mathjax>#L * M = "moles"#</mathjax></p> <p><mathjax>#30* 10^-3L * 0.01 = "0.0003moles"#</mathjax></p> <p>0.0003moles of HCl will produce 0.0003moles of <mathjax>#H^+#</mathjax></p> <p>Now calculate the number of moles in 20mL of 0.01M <mathjax>#Ca(OH)_2#</mathjax> solution.</p> <p><mathjax>#Ca(OH)_2 is a strong base thus#</mathjax></p> <p>moles of <mathjax>#Ca(OH)_2#</mathjax> = moles of <mathjax>#OH^-#</mathjax></p> <p><mathjax>#20 * 10^-3 L * 0.01M = "0.0002moles"#</mathjax></p> <p>0.0002moles of <mathjax>#Ca(OH)_2#</mathjax> = 0.0002moles of <mathjax>#OH^(-)#</mathjax></p> <p>As this is titrating of a strong acid with a strong base the addition of the base results in decrease in <mathjax>#H^+#</mathjax> ions. I mol of OH- results in decrease of 1 mol of H+</p> <p>0.0003mole - 0.0002mole = 0.0001mole of <mathjax>#H^+#</mathjax></p> <p>You must now calculate the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> by using the moles and the total volume</p> <p>But while calculating pH we must use the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and not mole. <br/> For that we need to add both the volumes that is </p> <p>20mL + 30mL = 50mL = 0.05L</p> <p><mathjax>#"0.0001mole"/"0.05L" = x/(1L)#</mathjax></p> <p>= <mathjax>#0.002/(1L)#</mathjax></p> <p>= 0.002M of <mathjax>#H^+#</mathjax> </p> <p><mathjax>#pH = -log(H^+)#</mathjax></p> <p><mathjax>#pH = 2.69897000434#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH = 2.69897000434#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It is a strong acid-base reaction as HCl is a strong acid and Ca(OH)2 is a strong base</p> <p><mathjax>#Ca(OH)_2 + HCl = CaCl_2 + 2 H_2O#</mathjax></p> <p>The net ionic reaction is </p> <p><mathjax>#H^+(aq) + OH^(-)(aq) = H_2O(l)#</mathjax></p> <p>The number <mathjax>#H^+#</mathjax> ions in the solution is the concentration of HCl because strong acids dissociate completely thus producing <br/> <mathjax>#"1mole of H+"/"1mole of acid."#</mathjax> This is only applicable to strong acids. The same is the case with strong base but instead of <mathjax>#H^+#</mathjax> they produce strong conjugate bases like <mathjax>#OH^(-)#</mathjax></p> <p>HCl is a strong acid thus </p> <p>moles of HCl = moles of <mathjax>#H^+#</mathjax></p> <p>Calculate no. of moles in 30mL of 0.01M HCl</p> <p><mathjax>#L * M = "moles"#</mathjax></p> <p><mathjax>#30* 10^-3L * 0.01 = "0.0003moles"#</mathjax></p> <p>0.0003moles of HCl will produce 0.0003moles of <mathjax>#H^+#</mathjax></p> <p>Now calculate the number of moles in 20mL of 0.01M <mathjax>#Ca(OH)_2#</mathjax> solution.</p> <p><mathjax>#Ca(OH)_2 is a strong base thus#</mathjax></p> <p>moles of <mathjax>#Ca(OH)_2#</mathjax> = moles of <mathjax>#OH^-#</mathjax></p> <p><mathjax>#20 * 10^-3 L * 0.01M = "0.0002moles"#</mathjax></p> <p>0.0002moles of <mathjax>#Ca(OH)_2#</mathjax> = 0.0002moles of <mathjax>#OH^(-)#</mathjax></p> <p>As this is titrating of a strong acid with a strong base the addition of the base results in decrease in <mathjax>#H^+#</mathjax> ions. I mol of OH- results in decrease of 1 mol of H+</p> <p>0.0003mole - 0.0002mole = 0.0001mole of <mathjax>#H^+#</mathjax></p> <p>You must now calculate the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> by using the moles and the total volume</p> <p>But while calculating pH we must use the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and not mole. <br/> For that we need to add both the volumes that is </p> <p>20mL + 30mL = 50mL = 0.05L</p> <p><mathjax>#"0.0001mole"/"0.05L" = x/(1L)#</mathjax></p> <p>= <mathjax>#0.002/(1L)#</mathjax></p> <p>= 0.002M of <mathjax>#H^+#</mathjax> </p> <p><mathjax>#pH = -log(H^+)#</mathjax></p> <p><mathjax>#pH = 2.69897000434#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What will be the pH of the solution that results from the addition of 20mL of 0.01M Ca(OH)2 to 30mL of 0.01M HCl?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="401949" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/samriddha"><img alt="" class="" src="https://profilepictures.socratic.org/3bMcXdwZTLqpsJaquExz_Shinjuku.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/samriddha"> Professor Sam </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-05T11:48:16" itemprop="dateCreated"> Apr 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH = 2.69897000434#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It is a strong acid-base reaction as HCl is a strong acid and Ca(OH)2 is a strong base</p> <p><mathjax>#Ca(OH)_2 + HCl = CaCl_2 + 2 H_2O#</mathjax></p> <p>The net ionic reaction is </p> <p><mathjax>#H^+(aq) + OH^(-)(aq) = H_2O(l)#</mathjax></p> <p>The number <mathjax>#H^+#</mathjax> ions in the solution is the concentration of HCl because strong acids dissociate completely thus producing <br/> <mathjax>#"1mole of H+"/"1mole of acid."#</mathjax> This is only applicable to strong acids. The same is the case with strong base but instead of <mathjax>#H^+#</mathjax> they produce strong conjugate bases like <mathjax>#OH^(-)#</mathjax></p> <p>HCl is a strong acid thus </p> <p>moles of HCl = moles of <mathjax>#H^+#</mathjax></p> <p>Calculate no. of moles in 30mL of 0.01M HCl</p> <p><mathjax>#L * M = "moles"#</mathjax></p> <p><mathjax>#30* 10^-3L * 0.01 = "0.0003moles"#</mathjax></p> <p>0.0003moles of HCl will produce 0.0003moles of <mathjax>#H^+#</mathjax></p> <p>Now calculate the number of moles in 20mL of 0.01M <mathjax>#Ca(OH)_2#</mathjax> solution.</p> <p><mathjax>#Ca(OH)_2 is a strong base thus#</mathjax></p> <p>moles of <mathjax>#Ca(OH)_2#</mathjax> = moles of <mathjax>#OH^-#</mathjax></p> <p><mathjax>#20 * 10^-3 L * 0.01M = "0.0002moles"#</mathjax></p> <p>0.0002moles of <mathjax>#Ca(OH)_2#</mathjax> = 0.0002moles of <mathjax>#OH^(-)#</mathjax></p> <p>As this is titrating of a strong acid with a strong base the addition of the base results in decrease in <mathjax>#H^+#</mathjax> ions. I mol of OH- results in decrease of 1 mol of H+</p> <p>0.0003mole - 0.0002mole = 0.0001mole of <mathjax>#H^+#</mathjax></p> <p>You must now calculate the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> by using the moles and the total volume</p> <p>But while calculating pH we must use the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and not mole. <br/> For that we need to add both the volumes that is </p> <p>20mL + 30mL = 50mL = 0.05L</p> <p><mathjax>#"0.0001mole"/"0.05L" = x/(1L)#</mathjax></p> <p>= <mathjax>#0.002/(1L)#</mathjax></p> <p>= 0.002M of <mathjax>#H^+#</mathjax> </p> <p><mathjax>#pH = -log(H^+)#</mathjax></p> <p><mathjax>#pH = 2.69897000434#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/401949" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-at-an-equivalence-point"> How do you determine pH at an equivalence point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-molarity"> How do you determine pH from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-alkalinity-mean"> What does alkalinity mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-base"> What is a base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-acid-base-indicators-change-color"> How do acid base indicators change color? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-neutral-ph"> What is a neutral pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-alkalinity-affect-pool-water"> How does alkalinity affect pool water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-important-in-drinking-water"> Why is pH important in drinking water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-ph-of-solution"> How can I calculate the pH of a solution? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 47683 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What will be the pH of the solution that results from the addition of 20mL of 0.01M Ca(OH)2 to 30mL of 0.01M HCl?

a99c5d37-6ddd-11ea-a7a4-ccda262736ce

https://socratic.org/questions/given-the-equation-2al-3cu-2-2al-3-3cu-what-is-the-reduction-half-reaction

Cu^2+ + 2 e- -> Cu(s)

start chemical_equation qc_end chemical_equation 3 13 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the reduction"}]

[{"type":"chemical equation","value":"Cu^2+ + 2 e- -> Cu(s)"}]

[{"type":"chemical equation","value":"2 Al + 3 Cu^2+ -> 2 Al^3+ + 3 Cu"}]

<h1 class="questionTitle" itemprop="name">Given the equation: #2Al + 3Cu_2 -&gt;2Al^(3+) + 3Cu#. What is the reduction half-reaction?</h1>

Cu^2+ + 2 e- -> Cu(s)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And the oxidation reaction.........</p> <p><mathjax>#Al(s) rarr Al^(3+) + 3e^-#</mathjax></p> <p>And cross-multiplying to remove the electrons.........</p> <p><mathjax>#2Al(s) + 3Cu^(2+) rarr 2Al^(3+) + 2Cu(s)#</mathjax></p> <p>Is charge balanced? Is mass balanced? </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Cu^(2+) + 2e^(-) rarr Cu(s)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And the oxidation reaction.........</p> <p><mathjax>#Al(s) rarr Al^(3+) + 3e^-#</mathjax></p> <p>And cross-multiplying to remove the electrons.........</p> <p><mathjax>#2Al(s) + 3Cu^(2+) rarr 2Al^(3+) + 2Cu(s)#</mathjax></p> <p>Is charge balanced? Is mass balanced? </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Given the equation: #2Al + 3Cu_2 -&gt;2Al^(3+) + 3Cu#. What is the reduction half-reaction?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-and-reduction-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation and Reduction Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="437623" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-10T19:27:54" itemprop="dateCreated"> Jun 10, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Cu^(2+) + 2e^(-) rarr Cu(s)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And the oxidation reaction.........</p> <p><mathjax>#Al(s) rarr Al^(3+) + 3e^-#</mathjax></p> <p>And cross-multiplying to remove the electrons.........</p> <p><mathjax>#2Al(s) + 3Cu^(2+) rarr 2Al^(3+) + 2Cu(s)#</mathjax></p> <p>Is charge balanced? Is mass balanced? </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/437623" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-balance-equations-with-charges"> How to balance equations for reduction/oxidation reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-an-electode-reaction-has-dssolved-oxygen-as-a-reactant-is-the-electrode-an-an"> If an electode reaction has dssolved oxygen as a reactant, is the electrode an anode or a cathode? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-an-electrode-reaction-has-dissolved-oxygen-as-a-reactant-is-the-electrode-and"> If an electrode reaction has dissolved oxygen as a reactant, is the electrode and anode or a cathode? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-balanced-equation-represents-a-redox-reaction-2"> What balanced equation represents a redox reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-redox-reactions-involved-in-electrolysis"> How are redox reactions involved in electrolysis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-oxidation-reduction-reactions-coupled"> Why are oxidation reduction reactions coupled? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-do-oxidation-reduction-reactions-involve"> What do oxidation reduction reactions involve? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-reduction-reactions-used-for"> What are reduction reactions used for? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-calx-mean-in-oxidation-reduction-reactions"> What does "calx" mean in oxidation reduction reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-the-reduced-components-in-this-reaction-zn-2h-zn-2-h2"> What are the reduced components in this reaction? Zn + 2H(+) → Zn(2+) + H2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-and-reduction-reactions"> See all questions in Oxidation and Reduction Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 17494 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

Given the equation: #2Al + 3Cu_2 -&gt;2Al^(3+) + 3Cu#. What is the reduction half-reaction?

aa145268-6ddd-11ea-856f-ccda262736ce

https://socratic.org/questions/what-is-the-molarity-of-a-solution-that-contains-9-63-grams-of-hci-in-1-5-liters

0.26 M

start physical_unit 12 12 molarity mol/l qc_end physical_unit 12 12 9 10 mass qc_end physical_unit 6 6 14 15 volume qc_end end

[{"type":"physical unit","value":"Molarity [OF] HCI solution [IN] M"}]

[{"type":"physical unit","value":"0.26 M"}]

[{"type":"physical unit","value":"Mass [OF] HCI [=] \\pu{9.63 grams}"},{"type":"physical unit","value":"Volume [OF] HCI solution [=] \\pu{1.5 liters}"}]

<h1 class="questionTitle" itemprop="name">What is the molarity of a solution that contains 9.63 grams of HCI in 1.5 liters of solution?</h1>

0.26 M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity"="Moles of solute"/"Volume of solution"#</mathjax></p> <p>And thus <mathjax>#"Molarity"=((9.63*g)/(36.46*g*mol^-1))/(1.5*L)=0.264*mol*L^-1.#</mathjax></p> <p>Note that our dimensions our consistent. We wanted an answer with units of concentrations, i.e. <mathjax>#mol*L^-1#</mathjax>, and the given quotient gave us an answer with such units. It is all too easy to multiply when you should divide, and vice versa.</p> <p>What is <mathjax>#pH#</mathjax> of this solution?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Molarity"=0.264*mol*L^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity"="Moles of solute"/"Volume of solution"#</mathjax></p> <p>And thus <mathjax>#"Molarity"=((9.63*g)/(36.46*g*mol^-1))/(1.5*L)=0.264*mol*L^-1.#</mathjax></p> <p>Note that our dimensions our consistent. We wanted an answer with units of concentrations, i.e. <mathjax>#mol*L^-1#</mathjax>, and the given quotient gave us an answer with such units. It is all too easy to multiply when you should divide, and vice versa.</p> <p>What is <mathjax>#pH#</mathjax> of this solution?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the molarity of a solution that contains 9.63 grams of HCI in 1.5 liters of solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="431020" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-28T17:12:03" itemprop="dateCreated"> May 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Molarity"=0.264*mol*L^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity"="Moles of solute"/"Volume of solution"#</mathjax></p> <p>And thus <mathjax>#"Molarity"=((9.63*g)/(36.46*g*mol^-1))/(1.5*L)=0.264*mol*L^-1.#</mathjax></p> <p>Note that our dimensions our consistent. We wanted an answer with units of concentrations, i.e. <mathjax>#mol*L^-1#</mathjax>, and the given quotient gave us an answer with such units. It is all too easy to multiply when you should divide, and vice versa.</p> <p>What is <mathjax>#pH#</mathjax> of this solution?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/431020" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1853 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the molarity of a solution that contains 9.63 grams of HCI in 1.5 liters of solution?

acedbb58-6ddd-11ea-ab74-ccda262736ce

https://socratic.org/questions/what-is-the-correct-formula-for-the-compound-made-by-magnesium-and-nitrogen

Mg3N2

start chemical_formula qc_end substance 10 10 qc_end substance 12 12 qc_end end

[{"type":"other","value":"Chemical Formula [OF] the compound [IN] default"}]

[{"type":"chemical equation","value":"Mg3N2"}]

[{"type":"substance name","value":"Magnesium"},{"type":"substance name","value":"Nitrogen"}]

<h1 class="questionTitle" itemprop="name">What is the correct formula for the compound made by magnesium and nitrogen? </h1>

Mg3N2

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Magnesium has two <a href="http://socratic.org/chemistry/the-periodic-table/valence-electrons-and-the-periodic-table">valence electrons</a>, and Nitrogen has five <a href="http://socratic.org/chemistry/the-electron-configuration-of-atoms/valence-electrons">valence electrons</a>. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The correct formula for the Magnesium Nitrogen compound is <mathjax>#Mg_3N_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Magnesium has two <a href="http://socratic.org/chemistry/the-periodic-table/valence-electrons-and-the-periodic-table">valence electrons</a>, and Nitrogen has five <a href="http://socratic.org/chemistry/the-electron-configuration-of-atoms/valence-electrons">valence electrons</a>. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the correct formula for the compound made by magnesium and nitrogen? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">3</span> Answers </h5> <div class="answers"> <div class="answer" id="181389" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/elle-4"><img alt="" class="" src="https://profilepictures.socratic.org/ME1NijwDR0ulYHvijDl5_Roses.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/elle-4"> Elle </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-30T22:45:09" itemprop="dateCreated"> Oct 30, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The correct formula for the Magnesium Nitrogen compound is <mathjax>#Mg_3N_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Magnesium has two <a href="http://socratic.org/chemistry/the-periodic-table/valence-electrons-and-the-periodic-table">valence electrons</a>, and Nitrogen has five <a href="http://socratic.org/chemistry/the-electron-configuration-of-atoms/valence-electrons">valence electrons</a>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/181389" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="181390" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-30T22:51:25" itemprop="dateCreated"> Oct 30, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Mg_3N_2#</mathjax>, magnesium nitride.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Magnesium is in Group 2, nitrogen is in Group 15; the formula is as you would predict from magnesium ion, <mathjax>#Mg^(2+)#</mathjax>, and nitride anion, <mathjax>#N^(3-)#</mathjax>. This is an ionic solid that hydrolyzes to give ammonia, and magnesium hydroxide, I.e.:</p> <p><mathjax>#Mg_3N_2#</mathjax> <mathjax>#+#</mathjax> <mathjax>#6H_2O rarr #</mathjax><mathjax>#2NH_3#</mathjax> <mathjax>#+#</mathjax> <mathjax>#3Mg(OH)_2#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/181390" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="181392" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-30T22:56:52" itemprop="dateCreated"> Oct 30, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Magnesium and nitrogen combine to form magnesium nitride, <mathjax>#"Mg"_3"N"_2"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Magnesium nitride is an ionic compound. Magnesium forms ions with a <mathjax>#"2+"#</mathjax> charge, and nitrogen forms nitride ions with a <mathjax>#"3-"#</mathjax> charge. The overall charge of the compound must be zero. Therefore, the numerical value of the positive and negative charge must be <mathjax>#"6"#</mathjax>.</p> <p><mathjax>#3["Mg"]^(2+) + 2 ["N"]^(3-)#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Mg"_3"N"_2"#</mathjax></p> <p><mathjax>#3xx(2+)=6+#</mathjax> and <mathjax>#2xx(3-)=6-#</mathjax></p> <p><mathjax>#(6+)+(6-)=0#</mathjax></p> <p>An easy way to determine the formula unit of an ionic compound is called the crisscross method, as demonstrated in the video below.</p> <p> <iframe src="https://www.youtube.com/embed/d9Xpt5Xh_D4?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/181392" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-chloride"> What is the ionic formula for calcium chloride? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-oxide"> What is the ionic formula for calcium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-lithium-oxide"> What is the ionic formula for lithium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-formula-for-ionic-compounds"> How do you write the formula for ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-correctly-write-the-ions-present-in-sn-no3-2"> How do I write #Sn(NO_3)_2# in Ionic formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-an-ionic-compound"> What is the empirical formula for an ionic compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-for-chorate"> What is the molecular formula for chorate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5363023c02bf343b2ee7086b"> Question #7086b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-polyatomic-ions-covalent-1"> Why are polyatomic ions covalent? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas"> See all questions in Writing Ionic Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 93773 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the correct formula for the compound made by magnesium and nitrogen?

acfdb08c-6ddd-11ea-9f6d-ccda262736ce

https://socratic.org/questions/you-have-25-milliliters-of-a-drink-that-contains-70-caffeine-how-many-milliliter

5 milliliters

start physical_unit 6 6 volume ml qc_end physical_unit 6 6 2 3 volume qc_end end

[{"type":"physical unit","value":"Volume2 [OF] the drink [IN] milliliters"}]

[{"type":"physical unit","value":"5 milliliters"}]

[{"type":"physical unit","value":"Volume1 [OF] the drink [=] \\pu{25 milliliters}"},{"type":"physical unit","value":"Percent1 [OF] Caffeine in the drink [=] \\pu{70%}"},{"type":"physical unit","value":"Percent2 [OF] Caffeine in the drink [=] \\pu{40%}"},{"type":"physical unit","value":"Percent3 [OF] Caffeine in the drink [=] \\pu{65%}"}]

<h1 class="questionTitle" itemprop="name">You have 25 milliliters of a drink that contains 70% Caffeine. How many milliliters of a drink containing 40% Caffeine needs to be added in order to have a final drink that is 65% Caffeine? </h1>

5 milliliters

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The key to these dilution problems is to use the idea that the total amount of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> has to be the same before and after mixing. This is the conservation of mass.</p> <p>Concentration = amount of stuff / volume of solution</p> <p><mathjax>#sf(c=m/v)#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(m=vxxc)#</mathjax></p> <p>This means that:</p> <p><mathjax>#sf((Vxx0.4)+(25xx0.7)=0.65xx(V+25))#</mathjax></p> <p><mathjax>#sf(0.4V+17.5=0.65V+16.25)#</mathjax></p> <p><mathjax>#sf((0.65-0.4)V=17.5-16.25)#</mathjax></p> <p><mathjax>#sf(0.25V=1.25)#</mathjax></p> <p><mathjax>#sf(V=1.25/0.25=5color(white)(x)ml)#</mathjax></p> <hr/> <p>Iteration check:</p> <p>Before mixing:</p> <p><mathjax>#sf(m=(25xx0.7)+(5xx0.4)=19.5color(white)(x)g)#</mathjax></p> <p>After mixing:</p> <p><mathjax>#sf(m=30xx0.65=19.5color(white)(x)g)#</mathjax></p> <p>So that's all good.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>5 ml</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The key to these dilution problems is to use the idea that the total amount of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> has to be the same before and after mixing. This is the conservation of mass.</p> <p>Concentration = amount of stuff / volume of solution</p> <p><mathjax>#sf(c=m/v)#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(m=vxxc)#</mathjax></p> <p>This means that:</p> <p><mathjax>#sf((Vxx0.4)+(25xx0.7)=0.65xx(V+25))#</mathjax></p> <p><mathjax>#sf(0.4V+17.5=0.65V+16.25)#</mathjax></p> <p><mathjax>#sf((0.65-0.4)V=17.5-16.25)#</mathjax></p> <p><mathjax>#sf(0.25V=1.25)#</mathjax></p> <p><mathjax>#sf(V=1.25/0.25=5color(white)(x)ml)#</mathjax></p> <hr/> <p>Iteration check:</p> <p>Before mixing:</p> <p><mathjax>#sf(m=(25xx0.7)+(5xx0.4)=19.5color(white)(x)g)#</mathjax></p> <p>After mixing:</p> <p><mathjax>#sf(m=30xx0.65=19.5color(white)(x)g)#</mathjax></p> <p>So that's all good.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">You have 25 milliliters of a drink that contains 70% Caffeine. How many milliliters of a drink containing 40% Caffeine needs to be added in order to have a final drink that is 65% Caffeine? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/measuring-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Measuring Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="612057" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michael-2"><img alt="" class="" src="https://lh3.googleusercontent.com/-gCv6FQRhls0/AAAAAAAAAAI/AAAAAAAAAAA/AAnnY7oOJS05Ylqn3KuDSW0LfnbOk7FezQ/mo/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michael-2"> Michael </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-12T08:13:02" itemprop="dateCreated"> May 12, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>5 ml</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The key to these dilution problems is to use the idea that the total amount of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> has to be the same before and after mixing. This is the conservation of mass.</p> <p>Concentration = amount of stuff / volume of solution</p> <p><mathjax>#sf(c=m/v)#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(m=vxxc)#</mathjax></p> <p>This means that:</p> <p><mathjax>#sf((Vxx0.4)+(25xx0.7)=0.65xx(V+25))#</mathjax></p> <p><mathjax>#sf(0.4V+17.5=0.65V+16.25)#</mathjax></p> <p><mathjax>#sf((0.65-0.4)V=17.5-16.25)#</mathjax></p> <p><mathjax>#sf(0.25V=1.25)#</mathjax></p> <p><mathjax>#sf(V=1.25/0.25=5color(white)(x)ml)#</mathjax></p> <hr/> <p>Iteration check:</p> <p>Before mixing:</p> <p><mathjax>#sf(m=(25xx0.7)+(5xx0.4)=19.5color(white)(x)g)#</mathjax></p> <p>After mixing:</p> <p><mathjax>#sf(m=30xx0.65=19.5color(white)(x)g)#</mathjax></p> <p>So that's all good.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/612057" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-concentration-from-absorbance"> How do you measure concentration from absorbance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-concentration-of-a-solution"> How do you measure concentration of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-concentration-of-co2"> How do you measure concentration of CO2? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-concentration-measure-changes-with-temperature"> What concentration measure changes with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-measure-the-concentration-of-salt-in-water"> How can I measure the concentration of salt in water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-the-concentration-of-a-solution-measured"> How is the concentration of a solution measured? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-concentration-of-electrolyte-affect-an-electrochemical-cell"> How does the concentration of electrolyte affect an electrochemical cell? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-normality-differ-from-molarity"> How does normality differ from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molality-of-a-solution-of-10-g-naoh-in-500-g-water"> What is the molality of a solution of 10 g NaOH in 500 g water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-the-mole-fractions-of-the-components-of-the-solution-formed-when-92-g-g"> What are the mole fractions of the components of the solution formed when 92 g glycerol is mixed... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/measuring-concentration"> See all questions in Measuring Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1901 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

You have 25 milliliters of a drink that contains 70% Caffeine. How many milliliters of a drink containing 40% Caffeine needs to be added in order to have a final drink that is 65% Caffeine?

a972964a-6ddd-11ea-afff-ccda262736ce

https://socratic.org/questions/an-aqueous-solution-of-3-47-m-silver-nitrate-agno-3-has-a-density-of-1-47-g-ml-w

40.10%

start physical_unit 21 24 mass_percent none qc_end end

[{"type":"physical unit","value":"Percent by mass [OF] AgNO3 in the solution"}]

[{"type":"physical unit","value":"40.10%"}]

[{"type":"physical unit","value":"Molarity [OF] AgNO3 aqueous solution [=] \\pu{3.47 M}"},{"type":"physical unit","value":"Density [OF] AgNO3 aqueous solution [=] \\pu{1.47 g/mL}"}]

<h1 class="questionTitle" itemprop="name">An aqueous solution of 3.47 M silver nitrate, #AgNO_3#, has a density of 1.47 g/mL. What is percent by mass of #AgNO_3# in the solution?</h1>

40.10%

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here's your strategy for this problem - you need to pick a sample volume of this solution, use the given <a href="http://socratic.org/chemistry/measurement-in-chemistry/density">density</a> to find its mass, then the number of moles of silver nitrate to get mass of silver nitrate it contains. </p> <p>So, to make the calculations easier, let's take a <mathjax>#"1.00-L"#</mathjax> sample of this solution. Use the given density to determine its mass</p> <blockquote> <p><mathjax>#1.00color(red)(cancel(color(black)("L"))) * (1000color(red)(cancel(color(black)("mL"))))/(1color(red)(cancel(color(black)("L")))) * "1.47 g"/(1color(red)(cancel(color(black)("mL")))) = "1470 g"#</mathjax></p> </blockquote> <p>Now, this <mathjax>#"1.00-L"#</mathjax> solution will contain </p> <blockquote> <p><mathjax>#c = n/V implies n = c * V#</mathjax></p> <p><mathjax>#n = 3.47"moles"/color(red)(cancel(color(black)("L"))) * 1.00color(red)(cancel(color(black)("L"))) = "3.47 moles"#</mathjax></p> </blockquote> <p>Use silver nitrate's molar mass to help you determine how many grams of silver nitrate would contain this many moles</p> <blockquote> <p><mathjax>#3.47color(red)(cancel(color(black)("moles AgNO"_3))) * "169.87 g"/(1color(red)(cancel(color(black)("mole AgNO"_3)))) = "589.4 g AgNO"_3#</mathjax></p> </blockquote> <p>Now, the solution's <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration by mass</a> is defined as the mass of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, in your case silver nitrate, divided by the mass of the solution, and multiplied by <mathjax>#100#</mathjax>. </p> <blockquote> <p><mathjax>#color(blue)("%w/w" = "mass of solute"/"mass of solution" xx 100)#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#"%w/w" = (589.4color(red)(cancel(color(black)("g"))))/(1470color(red)(cancel(color(black)("g")))) xx 100 = color(green)("40.1%")#</mathjax></p> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#40.1%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here's your strategy for this problem - you need to pick a sample volume of this solution, use the given <a href="http://socratic.org/chemistry/measurement-in-chemistry/density">density</a> to find its mass, then the number of moles of silver nitrate to get mass of silver nitrate it contains. </p> <p>So, to make the calculations easier, let's take a <mathjax>#"1.00-L"#</mathjax> sample of this solution. Use the given density to determine its mass</p> <blockquote> <p><mathjax>#1.00color(red)(cancel(color(black)("L"))) * (1000color(red)(cancel(color(black)("mL"))))/(1color(red)(cancel(color(black)("L")))) * "1.47 g"/(1color(red)(cancel(color(black)("mL")))) = "1470 g"#</mathjax></p> </blockquote> <p>Now, this <mathjax>#"1.00-L"#</mathjax> solution will contain </p> <blockquote> <p><mathjax>#c = n/V implies n = c * V#</mathjax></p> <p><mathjax>#n = 3.47"moles"/color(red)(cancel(color(black)("L"))) * 1.00color(red)(cancel(color(black)("L"))) = "3.47 moles"#</mathjax></p> </blockquote> <p>Use silver nitrate's molar mass to help you determine how many grams of silver nitrate would contain this many moles</p> <blockquote> <p><mathjax>#3.47color(red)(cancel(color(black)("moles AgNO"_3))) * "169.87 g"/(1color(red)(cancel(color(black)("mole AgNO"_3)))) = "589.4 g AgNO"_3#</mathjax></p> </blockquote> <p>Now, the solution's <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration by mass</a> is defined as the mass of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, in your case silver nitrate, divided by the mass of the solution, and multiplied by <mathjax>#100#</mathjax>. </p> <blockquote> <p><mathjax>#color(blue)("%w/w" = "mass of solute"/"mass of solution" xx 100)#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#"%w/w" = (589.4color(red)(cancel(color(black)("g"))))/(1470color(red)(cancel(color(black)("g")))) xx 100 = color(green)("40.1%")#</mathjax></p> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">An aqueous solution of 3.47 M silver nitrate, #AgNO_3#, has a density of 1.47 g/mL. What is percent by mass of #AgNO_3# in the solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="189511" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-16T22:53:17" itemprop="dateCreated"> Nov 16, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#40.1%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here's your strategy for this problem - you need to pick a sample volume of this solution, use the given <a href="http://socratic.org/chemistry/measurement-in-chemistry/density">density</a> to find its mass, then the number of moles of silver nitrate to get mass of silver nitrate it contains. </p> <p>So, to make the calculations easier, let's take a <mathjax>#"1.00-L"#</mathjax> sample of this solution. Use the given density to determine its mass</p> <blockquote> <p><mathjax>#1.00color(red)(cancel(color(black)("L"))) * (1000color(red)(cancel(color(black)("mL"))))/(1color(red)(cancel(color(black)("L")))) * "1.47 g"/(1color(red)(cancel(color(black)("mL")))) = "1470 g"#</mathjax></p> </blockquote> <p>Now, this <mathjax>#"1.00-L"#</mathjax> solution will contain </p> <blockquote> <p><mathjax>#c = n/V implies n = c * V#</mathjax></p> <p><mathjax>#n = 3.47"moles"/color(red)(cancel(color(black)("L"))) * 1.00color(red)(cancel(color(black)("L"))) = "3.47 moles"#</mathjax></p> </blockquote> <p>Use silver nitrate's molar mass to help you determine how many grams of silver nitrate would contain this many moles</p> <blockquote> <p><mathjax>#3.47color(red)(cancel(color(black)("moles AgNO"_3))) * "169.87 g"/(1color(red)(cancel(color(black)("mole AgNO"_3)))) = "589.4 g AgNO"_3#</mathjax></p> </blockquote> <p>Now, the solution's <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration by mass</a> is defined as the mass of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, in your case silver nitrate, divided by the mass of the solution, and multiplied by <mathjax>#100#</mathjax>. </p> <blockquote> <p><mathjax>#color(blue)("%w/w" = "mass of solute"/"mass of solution" xx 100)#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#"%w/w" = (589.4color(red)(cancel(color(black)("g"))))/(1470color(red)(cancel(color(black)("g")))) xx 100 = color(green)("40.1%")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/189511" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? 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An aqueous solution of 3.47 M silver nitrate, #AgNO_3#, has a density of 1.47 g/mL. What is percent by mass of #AgNO_3# in the solution?

a9f7ea00-6ddd-11ea-9e70-ccda262736ce

https://socratic.org/questions/a-sample-of-drinking-water-severely-contaminated-with-chloroform-chcl3-is-suppos

1.2 × 10^(-4) mol/kg

start physical_unit 8 8 molality mol/kg qc_end physical_unit 35 37 24 25 mass_percent qc_end end

[{"type":"physical unit","value":"Molality [OF] chloroform [IN] mol/kg"}]

[{"type":"physical unit","value":"1.2 × 10^(-4) mol/kg"}]

[{"type":"physical unit","value":"Level of combination by mass [OF] the water sample [=] \\pu{15 ppm}"}]

<h1 class="questionTitle" itemprop="name">A sample of drinking water severely contaminated with chloroform , CHCl3 ,is supposed to be carcinogenic in nature . The level of combination was 15 ppm (by mass) .What is the molality of chloroform in the water sample ?</h1>

1.2 × 10^(-4) mol/kg

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"1 ppm"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1*mg*L^-1#</mathjax>, by definition.</p> <p>If there is a <mathjax>#"15 ppm"#</mathjax> solution of chloroform in water, this represents, <mathjax>#(15xx10^-3*g)/(119.37*g*mol^-1)xx1/(1*kg)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??*mol*kg^-1#</mathjax>, with respect to chloroform.</p> <p>You might object to this treatment in that the chloroform solution will have a slightly different <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> than pure water, but it will have a negligible effect. This is quite probably concentrated enough to taste. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"15 ppm" ~=#</mathjax> <mathjax>#(15xx10^-3*g)/(119.37*g*mol^-1)xx1/(1*kg)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??*mol*kg^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"1 ppm"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1*mg*L^-1#</mathjax>, by definition.</p> <p>If there is a <mathjax>#"15 ppm"#</mathjax> solution of chloroform in water, this represents, <mathjax>#(15xx10^-3*g)/(119.37*g*mol^-1)xx1/(1*kg)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??*mol*kg^-1#</mathjax>, with respect to chloroform.</p> <p>You might object to this treatment in that the chloroform solution will have a slightly different <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> than pure water, but it will have a negligible effect. This is quite probably concentrated enough to taste. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A sample of drinking water severely contaminated with chloroform , CHCl3 ,is supposed to be carcinogenic in nature . The level of combination was 15 ppm (by mass) .What is the molality of chloroform in the water sample ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="266755" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-17T15:47:48" itemprop="dateCreated"> May 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"15 ppm" ~=#</mathjax> <mathjax>#(15xx10^-3*g)/(119.37*g*mol^-1)xx1/(1*kg)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??*mol*kg^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"1 ppm"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1*mg*L^-1#</mathjax>, by definition.</p> <p>If there is a <mathjax>#"15 ppm"#</mathjax> solution of chloroform in water, this represents, <mathjax>#(15xx10^-3*g)/(119.37*g*mol^-1)xx1/(1*kg)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??*mol*kg^-1#</mathjax>, with respect to chloroform.</p> <p>You might object to this treatment in that the chloroform solution will have a slightly different <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> than pure water, but it will have a negligible effect. This is quite probably concentrated enough to taste. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/266755" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="266767" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-17T16:12:14" itemprop="dateCreated"> May 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of chloroform is <mathjax>#1.2 × 10^"-4"color(white)(l) "mol/kg"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The formula for molality is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(|bar(ul(color(white)(a/a) "Molality" = "moles of solute"/"kilograms of solute"color(white)(a/a)|)))" "#</mathjax></p> </blockquote> </blockquote> <p>Assume that you have 1 L of water. Then the mass of water is 1000 g.</p> <p><mathjax>#"Mass of CHCl"_3 = 1000 color(red)(cancel(color(black)("g water"))) × "15 g CHCl"_3/(10^6 color(red)(cancel(color(black)("g water")))) = "0.015 g CHCl"_3#</mathjax></p> <p><mathjax>#"Moles of CHCl"_3 = 0.015 color(red)(cancel(color(black)("g CHCl"_3))) × "1 mol CHCl"_3/(119.38 color(red)(cancel(color(black)("g CHCl"_3))) ) = 1.2 × 10^"-4"color(white)(l) "mol CHCl"_3#</mathjax></p> <p><mathjax>#"Molality" = (1.2 × 10^"-4" color(white)(l)"mol")/"1 kg" = 1.2 × 10^"-4" color(white)(l)"mol/kg"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/266767" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-read-differential-scanning-in-calorimetry"> What information do you get from a differential scanning calorimetry plot? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-calorimetry"> How do you measure calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531d304102bf341e75b962a7"> Question #962a7 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5335021802bf344ae911dfc5"> Question #1dfc5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668f502bf34572c341af6"> Question #41af6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-definition-of-calorimetry"> What is calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-differential-scanning-calorimeter"> What is a differential scanning calorimeter? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-calorimeter-measure-energy"> How can a calorimeter measure energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-calorimeters-made-of"> What are calorimeters made of? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/calorimetry"> See all questions in Calorimetry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3015 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A sample of drinking water severely contaminated with chloroform , CHCl3 ,is supposed to be carcinogenic in nature . The level of combination was 15 ppm (by mass) .What is the molality of chloroform in the water sample ?

ac2b6e2c-6ddd-11ea-aba4-ccda262736ce

https://socratic.org/questions/on-analysing-a-sample-of-water-a-chemist-finds-that-100-cm-3-of-it-contains-0-00

70.00 ppm

start physical_unit 18 19 concentration ppm qc_end physical_unit 3 5 10 11 volume qc_end physical_unit 18 19 15 16 mass qc_end end

[{"type":"physical unit","value":"Concentration [OF] calcium carbonate [IN] ppm"}]

[{"type":"physical unit","value":"70.00 ppm"}]

[{"type":"physical unit","value":"Volume [OF] water sample [=] \\pu{100 cm^3}"},{"type":"physical unit","value":"Mass [OF] calcium carbonate [=] \\pu{0.007 g}"}]

<h1 class="questionTitle" itemprop="name">On analysing a sample of water, a chemist finds that 100#cm^3# of it contains 0.007g of calcium carbonate. What is the concentration of calcium carbonate in ppm? </h1>

70.00 ppm

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus <mathjax>#"concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass of solute"/"Volume"#</mathjax>.</p> <p><mathjax>#=(7*mg)/(0.100*L)=70*mg*L^-1#</mathjax></p> <p>And thus <mathjax>#0.070*g*L^-1-=70*mg*L^-1-="70 ppm"#</mathjax>.</p> <p>At these concentrations, we don't really have to worry too much about the <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of the solution. <mathjax>#"70 ppm"#</mathjax> denotes a concentration of <mathjax>#70*mg*L^-1#</mathjax> with respect to <mathjax>#"calcium carbonate"#</mathjax>. Of course this will be a GREATER concentration than the concentration with respect to the metal ion. Why should this be so?</p> <p>I think you can see why a concentration of <mathjax>#1*mg*L^-1#</mathjax> is referred to as a <mathjax>#"part per million"#</mathjax>. A litre of water has a mass of <mathjax>#1000*g#</mathjax>, and each of these <mathjax>#"grams"#</mathjax> is composed of a <mathjax>#1000*mg#</mathjax> (i.e. <mathjax>#1*mg=10^-3g#</mathjax>. <mathjax>#1000xx1000 equiv"million"#</mathjax>, hence <mathjax>#1*mg#</mathjax> <mathjax>#equiv#</mathjax> <mathjax>#"1 part per million"#</mathjax>. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1 ppm"-=" 1*mg*L^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus <mathjax>#"concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass of solute"/"Volume"#</mathjax>.</p> <p><mathjax>#=(7*mg)/(0.100*L)=70*mg*L^-1#</mathjax></p> <p>And thus <mathjax>#0.070*g*L^-1-=70*mg*L^-1-="70 ppm"#</mathjax>.</p> <p>At these concentrations, we don't really have to worry too much about the <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of the solution. <mathjax>#"70 ppm"#</mathjax> denotes a concentration of <mathjax>#70*mg*L^-1#</mathjax> with respect to <mathjax>#"calcium carbonate"#</mathjax>. Of course this will be a GREATER concentration than the concentration with respect to the metal ion. Why should this be so?</p> <p>I think you can see why a concentration of <mathjax>#1*mg*L^-1#</mathjax> is referred to as a <mathjax>#"part per million"#</mathjax>. A litre of water has a mass of <mathjax>#1000*g#</mathjax>, and each of these <mathjax>#"grams"#</mathjax> is composed of a <mathjax>#1000*mg#</mathjax> (i.e. <mathjax>#1*mg=10^-3g#</mathjax>. <mathjax>#1000xx1000 equiv"million"#</mathjax>, hence <mathjax>#1*mg#</mathjax> <mathjax>#equiv#</mathjax> <mathjax>#"1 part per million"#</mathjax>. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">On analysing a sample of water, a chemist finds that 100#cm^3# of it contains 0.007g of calcium carbonate. What is the concentration of calcium carbonate in ppm? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/measuring-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Measuring Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="363179" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-11T16:28:50" itemprop="dateCreated"> Jan 11, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1 ppm"-=" 1*mg*L^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus <mathjax>#"concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass of solute"/"Volume"#</mathjax>.</p> <p><mathjax>#=(7*mg)/(0.100*L)=70*mg*L^-1#</mathjax></p> <p>And thus <mathjax>#0.070*g*L^-1-=70*mg*L^-1-="70 ppm"#</mathjax>.</p> <p>At these concentrations, we don't really have to worry too much about the <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of the solution. <mathjax>#"70 ppm"#</mathjax> denotes a concentration of <mathjax>#70*mg*L^-1#</mathjax> with respect to <mathjax>#"calcium carbonate"#</mathjax>. Of course this will be a GREATER concentration than the concentration with respect to the metal ion. Why should this be so?</p> <p>I think you can see why a concentration of <mathjax>#1*mg*L^-1#</mathjax> is referred to as a <mathjax>#"part per million"#</mathjax>. A litre of water has a mass of <mathjax>#1000*g#</mathjax>, and each of these <mathjax>#"grams"#</mathjax> is composed of a <mathjax>#1000*mg#</mathjax> (i.e. <mathjax>#1*mg=10^-3g#</mathjax>. <mathjax>#1000xx1000 equiv"million"#</mathjax>, hence <mathjax>#1*mg#</mathjax> <mathjax>#equiv#</mathjax> <mathjax>#"1 part per million"#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/363179" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-concentration-from-absorbance"> How do you measure concentration from absorbance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-concentration-of-a-solution"> How do you measure concentration of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-concentration-of-co2"> How do you measure concentration of CO2? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-concentration-measure-changes-with-temperature"> What concentration measure changes with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-measure-the-concentration-of-salt-in-water"> How can I measure the concentration of salt in water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-the-concentration-of-a-solution-measured"> How is the concentration of a solution measured? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-concentration-of-electrolyte-affect-an-electrochemical-cell"> How does the concentration of electrolyte affect an electrochemical cell? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-normality-differ-from-molarity"> How does normality differ from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molality-of-a-solution-of-10-g-naoh-in-500-g-water"> What is the molality of a solution of 10 g NaOH in 500 g water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-the-mole-fractions-of-the-components-of-the-solution-formed-when-92-g-g"> What are the mole fractions of the components of the solution formed when 92 g glycerol is mixed... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/measuring-concentration"> See all questions in Measuring Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1308 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

On analysing a sample of water, a chemist finds that 100#cm^3# of it contains 0.007g of calcium carbonate. What is the concentration of calcium carbonate in ppm?

a98e7a86-6ddd-11ea-9285-ccda262736ce

https://socratic.org/questions/what-is-the-oxidation-state-of-pb-in-pbo2

+4

start physical_unit 6 6 oxidation_state none qc_end chemical_equation 8 8 qc_end end

[{"type":"physical unit","value":"Oxidation state [OF] Pb"}]

[{"type":"physical unit","value":"+4"}]

[{"type":"chemical equation","value":"PbO2"}]

<h1 class="questionTitle" itemprop="name">What is the oxidation state of #"Pb"# in #"PbO"_2# ?</h1>

+4

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In <mathjax>#"PbO"_2#</mathjax>, oxygen exhibits an oxidation number of <mathjax>#-2#</mathjax> (since it's not a peroxide or superoxide):</p> <p>Let the oxidation number of <mathjax>#"Pb"#</mathjax> be <mathjax>#x#</mathjax>. Then, for the compound to be neutral, the oxidation numbers of all atoms should add up to zero.</p> <p><mathjax>#=&gt;x +(-2) +(-2) = 0#</mathjax></p> <p><mathjax>#x=+4 #</mathjax></p> <p>So the oxidation no. of <mathjax>#"Pb"#</mathjax> is <mathjax>#+4#</mathjax>.</p> <p>Hope it helps!</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>It is <mathjax>#+4#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In <mathjax>#"PbO"_2#</mathjax>, oxygen exhibits an oxidation number of <mathjax>#-2#</mathjax> (since it's not a peroxide or superoxide):</p> <p>Let the oxidation number of <mathjax>#"Pb"#</mathjax> be <mathjax>#x#</mathjax>. Then, for the compound to be neutral, the oxidation numbers of all atoms should add up to zero.</p> <p><mathjax>#=&gt;x +(-2) +(-2) = 0#</mathjax></p> <p><mathjax>#x=+4 #</mathjax></p> <p>So the oxidation no. of <mathjax>#"Pb"#</mathjax> is <mathjax>#+4#</mathjax>.</p> <p>Hope it helps!</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the oxidation state of #"Pb"# in #"PbO"_2# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-numbers" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation Numbers</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="574951" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/the-a"><img alt="" class="" src="https://lh4.googleusercontent.com/-aMy83gCcLmg/AAAAAAAAAAI/AAAAAAAAAJ8/4Mp-A3eJr-o/photo.jpg?sz=50" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/the-a"> The A. </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-03-16T12:29:59" itemprop="dateCreated"> Mar 16, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>It is <mathjax>#+4#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In <mathjax>#"PbO"_2#</mathjax>, oxygen exhibits an oxidation number of <mathjax>#-2#</mathjax> (since it's not a peroxide or superoxide):</p> <p>Let the oxidation number of <mathjax>#"Pb"#</mathjax> be <mathjax>#x#</mathjax>. Then, for the compound to be neutral, the oxidation numbers of all atoms should add up to zero.</p> <p><mathjax>#=&gt;x +(-2) +(-2) = 0#</mathjax></p> <p><mathjax>#x=+4 #</mathjax></p> <p>So the oxidation no. of <mathjax>#"Pb"#</mathjax> is <mathjax>#+4#</mathjax>.</p> <p>Hope it helps!</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/574951" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-electron-configuration"> How do oxidation numbers relate to electron configuration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-valence-electrons"> How do oxidation numbers relate to valence electrons? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-vary-with-the-periodic-table"> How do oxidation numbers vary with the periodic table? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-oxidation-number-of-an-element-in-a-compound"> How do you calculate the oxidation number of an element in a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-sulfur"> What is the oxidation number for sulfur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-carbon"> What is the oxidation number for carbon? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-copper"> What is the oxidation number for copper? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-nitrogen"> What is the oxidation number for nitrogen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-oxygen"> What is the oxidation number for oxygen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-state-of-noble-gas-zero"> Why is the oxidation state of noble gas zero? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-numbers"> See all questions in Oxidation Numbers </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 28360 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the oxidation state of #"Pb"# in #"PbO"_2# ?

aafc98e5-6ddd-11ea-ae32-ccda262736ce

https://socratic.org/questions/592b65507c014979d4ea3f00

64.49 g

start physical_unit 14 15 mass g qc_end physical_unit 4 5 1 2 mass qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Mass [OF] zinc carbonate [IN] g"}]

[{"type":"physical unit","value":"64.49 g"}]

[{"type":"physical unit","value":"Mass [OF] lithium carbonate [=] \\pu{38 g}"},{"type":"other","value":"Excess zinc sulfate."}]

<h1 class="questionTitle" itemprop="name">If #"38 g"# of lithium carbonate reacts with excess zinc sulfate, what mass of zinc carbonate can be produced?</h1>

64.49 g

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"ZnSO"_4 + "Li"_2"CO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"ZnCO"_3 + "Li"_2"SO"_4#</mathjax></p> <p>The process used to answer this question will be:</p> <p><mathjax>#color(red)("given mass Li"_2"CO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)("mol Li"_2"CO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(green)("mol ZnCO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(purple)("mass ZnCO"_3"#</mathjax></p> <p>The molar masses of lithium carbonate and zinc sulfate is needed.</p> <p><mathjax>#"Li"_2"CO"_3:#</mathjax><mathjax>#"73.888 g/mol"#</mathjax><br/> <a href="https://pubchem.ncbi.nlm.nih.gov/compound/11125" rel="nofollow" target="_blank">https://pubchem.ncbi.nlm.nih.gov/compound/11125</a><br/> <mathjax>#"ZnCO"_3:#</mathjax><mathjax>#"125.388 g/mol"#</mathjax> <br/> <a href="https://www.ncbi.nlm.nih.gov/pccompound?term=%22ZINC+CARBONATE%22" rel="nofollow" target="_blank">https://www.ncbi.nlm.nih.gov/pccompound?term=%22ZINC+CARBONATE%22</a></p> <p><mathjax>#color(red)("Given Mass Li"_2"CO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)("Mol Li"_2"CO"_3"#</mathjax><br/> Divide the given mass by the molar mass by multiplying the given mass by the inverse of the molar mass.</p> <p><mathjax>#38color(red)cancel(color(black)("g Li"_2"CO"_3))xx(1"mol Li"_2"CO"_3)/(73.888color(red)cancel(color(black)("g Li"_2"CO"_3)))="0.51429 mol Li"_2"CO"_3"#</mathjax></p> <p><mathjax>#color(blue)("Mol Li"_2"CO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>###</mathjax>color(green)("Mol ZnCO"_3"#<br/> Multiply the mol lithium carbonate by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio from the balanced equation so that mol lithium carbonate cancels.</p> <p><mathjax>#0.51429color(red)cancel(color(black)("mol Li"_2"CO"_3))xx(1"mol ZnCO"_3)/(1color(red)cancel(color(black)("mol Li"_2"CO"_3)))="0.51429 mol ZnCO"_3"#</mathjax></p> <p><mathjax>#color(green)("Mol ZnCO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(purple)("Mass ZnCO"_3"#</mathjax><br/> Multiply mol zinc carbonate by its molar mass.</p> <p><mathjax>#0.51429color(red)cancel(color(black)("mol ZnCO"_3))xx(125.388"g ZnCO"_3)/(1color(red)cancel(color(black)("mol ZnCO"_3)))="64 g ZnCO"_3"#</mathjax> rounded to two sig figs due to <mathjax>#"38 g"#</mathjax>.</p> <p>You can write the steps as one equation, like this:</p> <p><mathjax>#(color(red)stackrel"given mass Li2CO3"(38color(black)cancel(color(red)("g Li"_2"CO"_2))))xx(color(blue)stackrel"mole Li2CO3" (1"mol Li"_2"CO"_3)/(color(blue)(73.888color(black)cancel(color(blue)("g Li"_2"CO"_3)))))xx(color(green)stackrel"mole ZnCO3"(1color(green)("mol ZnCO"_3))/(color(green)(1color(black)cancel(color(green)("mol Li"_2"CO"_3)))))xx(color(purple)stackrel"mass ZnCO3"(125.388"g ZnCO"_3)/color(purple)(0.51429color(black)cancel(color(purple)("mol ZnCO"_3))))=color(purple)("64 g ZnCO"_3#</mathjax> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"64 g ZnCO"_3"#</mathjax> will be produced.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"ZnSO"_4 + "Li"_2"CO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"ZnCO"_3 + "Li"_2"SO"_4#</mathjax></p> <p>The process used to answer this question will be:</p> <p><mathjax>#color(red)("given mass Li"_2"CO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)("mol Li"_2"CO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(green)("mol ZnCO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(purple)("mass ZnCO"_3"#</mathjax></p> <p>The molar masses of lithium carbonate and zinc sulfate is needed.</p> <p><mathjax>#"Li"_2"CO"_3:#</mathjax><mathjax>#"73.888 g/mol"#</mathjax><br/> <a href="https://pubchem.ncbi.nlm.nih.gov/compound/11125" rel="nofollow" target="_blank">https://pubchem.ncbi.nlm.nih.gov/compound/11125</a><br/> <mathjax>#"ZnCO"_3:#</mathjax><mathjax>#"125.388 g/mol"#</mathjax> <br/> <a href="https://www.ncbi.nlm.nih.gov/pccompound?term=%22ZINC+CARBONATE%22" rel="nofollow" target="_blank">https://www.ncbi.nlm.nih.gov/pccompound?term=%22ZINC+CARBONATE%22</a></p> <p><mathjax>#color(red)("Given Mass Li"_2"CO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)("Mol Li"_2"CO"_3"#</mathjax><br/> Divide the given mass by the molar mass by multiplying the given mass by the inverse of the molar mass.</p> <p><mathjax>#38color(red)cancel(color(black)("g Li"_2"CO"_3))xx(1"mol Li"_2"CO"_3)/(73.888color(red)cancel(color(black)("g Li"_2"CO"_3)))="0.51429 mol Li"_2"CO"_3"#</mathjax></p> <p><mathjax>#color(blue)("Mol Li"_2"CO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>###</mathjax>color(green)("Mol ZnCO"_3"#<br/> Multiply the mol lithium carbonate by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio from the balanced equation so that mol lithium carbonate cancels.</p> <p><mathjax>#0.51429color(red)cancel(color(black)("mol Li"_2"CO"_3))xx(1"mol ZnCO"_3)/(1color(red)cancel(color(black)("mol Li"_2"CO"_3)))="0.51429 mol ZnCO"_3"#</mathjax></p> <p><mathjax>#color(green)("Mol ZnCO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(purple)("Mass ZnCO"_3"#</mathjax><br/> Multiply mol zinc carbonate by its molar mass.</p> <p><mathjax>#0.51429color(red)cancel(color(black)("mol ZnCO"_3))xx(125.388"g ZnCO"_3)/(1color(red)cancel(color(black)("mol ZnCO"_3)))="64 g ZnCO"_3"#</mathjax> rounded to two sig figs due to <mathjax>#"38 g"#</mathjax>.</p> <p>You can write the steps as one equation, like this:</p> <p><mathjax>#(color(red)stackrel"given mass Li2CO3"(38color(black)cancel(color(red)("g Li"_2"CO"_2))))xx(color(blue)stackrel"mole Li2CO3" (1"mol Li"_2"CO"_3)/(color(blue)(73.888color(black)cancel(color(blue)("g Li"_2"CO"_3)))))xx(color(green)stackrel"mole ZnCO3"(1color(green)("mol ZnCO"_3))/(color(green)(1color(black)cancel(color(green)("mol Li"_2"CO"_3)))))xx(color(purple)stackrel"mass ZnCO3"(125.388"g ZnCO"_3)/color(purple)(0.51429color(black)cancel(color(purple)("mol ZnCO"_3))))=color(purple)("64 g ZnCO"_3#</mathjax> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If #"38 g"# of lithium carbonate reacts with excess zinc sulfate, what mass of zinc carbonate can be produced?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="431181" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-29T03:14:00" itemprop="dateCreated"> May 29, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"64 g ZnCO"_3"#</mathjax> will be produced.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"ZnSO"_4 + "Li"_2"CO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"ZnCO"_3 + "Li"_2"SO"_4#</mathjax></p> <p>The process used to answer this question will be:</p> <p><mathjax>#color(red)("given mass Li"_2"CO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)("mol Li"_2"CO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(green)("mol ZnCO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(purple)("mass ZnCO"_3"#</mathjax></p> <p>The molar masses of lithium carbonate and zinc sulfate is needed.</p> <p><mathjax>#"Li"_2"CO"_3:#</mathjax><mathjax>#"73.888 g/mol"#</mathjax><br/> <a href="https://pubchem.ncbi.nlm.nih.gov/compound/11125" rel="nofollow" target="_blank">https://pubchem.ncbi.nlm.nih.gov/compound/11125</a><br/> <mathjax>#"ZnCO"_3:#</mathjax><mathjax>#"125.388 g/mol"#</mathjax> <br/> <a href="https://www.ncbi.nlm.nih.gov/pccompound?term=%22ZINC+CARBONATE%22" rel="nofollow" target="_blank">https://www.ncbi.nlm.nih.gov/pccompound?term=%22ZINC+CARBONATE%22</a></p> <p><mathjax>#color(red)("Given Mass Li"_2"CO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(blue)("Mol Li"_2"CO"_3"#</mathjax><br/> Divide the given mass by the molar mass by multiplying the given mass by the inverse of the molar mass.</p> <p><mathjax>#38color(red)cancel(color(black)("g Li"_2"CO"_3))xx(1"mol Li"_2"CO"_3)/(73.888color(red)cancel(color(black)("g Li"_2"CO"_3)))="0.51429 mol Li"_2"CO"_3"#</mathjax></p> <p><mathjax>#color(blue)("Mol Li"_2"CO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>###</mathjax>color(green)("Mol ZnCO"_3"#<br/> Multiply the mol lithium carbonate by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio from the balanced equation so that mol lithium carbonate cancels.</p> <p><mathjax>#0.51429color(red)cancel(color(black)("mol Li"_2"CO"_3))xx(1"mol ZnCO"_3)/(1color(red)cancel(color(black)("mol Li"_2"CO"_3)))="0.51429 mol ZnCO"_3"#</mathjax></p> <p><mathjax>#color(green)("Mol ZnCO"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(purple)("Mass ZnCO"_3"#</mathjax><br/> Multiply mol zinc carbonate by its molar mass.</p> <p><mathjax>#0.51429color(red)cancel(color(black)("mol ZnCO"_3))xx(125.388"g ZnCO"_3)/(1color(red)cancel(color(black)("mol ZnCO"_3)))="64 g ZnCO"_3"#</mathjax> rounded to two sig figs due to <mathjax>#"38 g"#</mathjax>.</p> <p>You can write the steps as one equation, like this:</p> <p><mathjax>#(color(red)stackrel"given mass Li2CO3"(38color(black)cancel(color(red)("g Li"_2"CO"_2))))xx(color(blue)stackrel"mole Li2CO3" (1"mol Li"_2"CO"_3)/(color(blue)(73.888color(black)cancel(color(blue)("g Li"_2"CO"_3)))))xx(color(green)stackrel"mole ZnCO3"(1color(green)("mol ZnCO"_3))/(color(green)(1color(black)cancel(color(green)("mol Li"_2"CO"_3)))))xx(color(purple)stackrel"mass ZnCO3"(125.388"g ZnCO"_3)/color(purple)(0.51429color(black)cancel(color(purple)("mol ZnCO"_3))))=color(purple)("64 g ZnCO"_3#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/431181" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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If #"38 g"# of lithium carbonate reacts with excess zinc sulfate, what mass of zinc carbonate can be produced?

aaf10078-6ddd-11ea-ad75-ccda262736ce

https://socratic.org/questions/a-particular-drain-cleaner-contains-naoh-what-is-the-value-of-oh-in-a-solution-p

1.00 M

start physical_unit 14 14 [oh-] mol/l qc_end physical_unit 5 5 17 18 mass qc_end physical_unit 14 14 27 28 volume qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Value of [OH-] [OF] the solution [IN] M"}]

[{"type":"physical unit","value":"1.00 M"}]

[{"type":"physical unit","value":"Mass [OF] NaOH [=] \\pu{15.0 g}"},{"type":"physical unit","value":"Volume [OF] NaOH solution [=] \\pu{375 mL}"},{"type":"other","value":"Enough water."}]

<h1 class="questionTitle" itemprop="name">A particular drain cleaner contains #"NaOH"#. What is the value of #["OH"^(-)]# in a solution produced when #"15.0 g"# of #"NaOH"# dissolves in enough water to make #"375 mL"# of solution? </h1>

1.00 M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by calculating the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the sodium hydroxide solution. As you know, <strong>molarity</strong> can be calculated by dividing the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> by the total volume of the solution <strong>in liters</strong>.</p> <blockquote> <p><mathjax>#["NaOH"] = "moles NaOH"/(color(white)(underbrace(color(blue)(375 * 10^(-3) quad "L")))#</mathjax><br/> <mathjax>#color(white)(aaaaaaaaaaaa)uarr#</mathjax><br/> <mathjax>#color(blue)("using the fact that 1 L" = 10^3 quad "mL")#</mathjax></p> </blockquote> <p>To find the number of moles of sodium hydroxide present in your sample, use the <strong>molar mass</strong> of the compound.</p> <blockquote> <p><mathjax>#15.0 color(red)(cancel(color(black)("g"))) * "1 mole NaOH"/(39.997color(red)(cancel(color(black)("g")))) = "0.3750 moles NaOH"#</mathjax></p> </blockquote> <p>This means that the molarity of the sodium hydroxide solution is</p> <blockquote> <p><mathjax>#["NaOH"] = "0.3750 moles"/(375 * 10^(-3) quad "L") = "1.00 mol L"^(-1)#</mathjax></p> </blockquote> <p>Now, sodium hydroxide is a <strong>strong base</strong>, which implies that it dissociates completely in aqueous solution to produce sodium cations and hydroxide anions in <mathjax>#1:1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a>.</p> <blockquote> <p><mathjax>#color(white)(overbrace(color(black)("NaOH"_ ((aq))))^(color(blue)("1 mole dissolved"))) -&gt; color(white)(overbrace(color(black)("Na"_ ((aq))^(+)))^(color(blue)("1 mole produced"))) + color(white)(overbrace(color(black)("OH"_ ((aq))^(-)))^(color(blue)("1 mole produced")))#</mathjax></p> </blockquote> <p>This means that your solution will have</p> <blockquote> <p><mathjax>#["Na"^(+)] = ["OH"^(-)] = ["NaOH"]#</mathjax></p> </blockquote> <p>and so</p> <blockquote> <p><mathjax>#["OH"^(-)] = color(darkgreen)(ul(color(black)("1.00 mol L"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for your values. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1.00 mol L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by calculating the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the sodium hydroxide solution. As you know, <strong>molarity</strong> can be calculated by dividing the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> by the total volume of the solution <strong>in liters</strong>.</p> <blockquote> <p><mathjax>#["NaOH"] = "moles NaOH"/(color(white)(underbrace(color(blue)(375 * 10^(-3) quad "L")))#</mathjax><br/> <mathjax>#color(white)(aaaaaaaaaaaa)uarr#</mathjax><br/> <mathjax>#color(blue)("using the fact that 1 L" = 10^3 quad "mL")#</mathjax></p> </blockquote> <p>To find the number of moles of sodium hydroxide present in your sample, use the <strong>molar mass</strong> of the compound.</p> <blockquote> <p><mathjax>#15.0 color(red)(cancel(color(black)("g"))) * "1 mole NaOH"/(39.997color(red)(cancel(color(black)("g")))) = "0.3750 moles NaOH"#</mathjax></p> </blockquote> <p>This means that the molarity of the sodium hydroxide solution is</p> <blockquote> <p><mathjax>#["NaOH"] = "0.3750 moles"/(375 * 10^(-3) quad "L") = "1.00 mol L"^(-1)#</mathjax></p> </blockquote> <p>Now, sodium hydroxide is a <strong>strong base</strong>, which implies that it dissociates completely in aqueous solution to produce sodium cations and hydroxide anions in <mathjax>#1:1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a>.</p> <blockquote> <p><mathjax>#color(white)(overbrace(color(black)("NaOH"_ ((aq))))^(color(blue)("1 mole dissolved"))) -&gt; color(white)(overbrace(color(black)("Na"_ ((aq))^(+)))^(color(blue)("1 mole produced"))) + color(white)(overbrace(color(black)("OH"_ ((aq))^(-)))^(color(blue)("1 mole produced")))#</mathjax></p> </blockquote> <p>This means that your solution will have</p> <blockquote> <p><mathjax>#["Na"^(+)] = ["OH"^(-)] = ["NaOH"]#</mathjax></p> </blockquote> <p>and so</p> <blockquote> <p><mathjax>#["OH"^(-)] = color(darkgreen)(ul(color(black)("1.00 mol L"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for your values. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A particular drain cleaner contains #"NaOH"#. What is the value of #["OH"^(-)]# in a solution produced when #"15.0 g"# of #"NaOH"# dissolves in enough water to make #"375 mL"# of solution? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="590630" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-04-08T12:30:55" itemprop="dateCreated"> Apr 8, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1.00 mol L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by calculating the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the sodium hydroxide solution. As you know, <strong>molarity</strong> can be calculated by dividing the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> by the total volume of the solution <strong>in liters</strong>.</p> <blockquote> <p><mathjax>#["NaOH"] = "moles NaOH"/(color(white)(underbrace(color(blue)(375 * 10^(-3) quad "L")))#</mathjax><br/> <mathjax>#color(white)(aaaaaaaaaaaa)uarr#</mathjax><br/> <mathjax>#color(blue)("using the fact that 1 L" = 10^3 quad "mL")#</mathjax></p> </blockquote> <p>To find the number of moles of sodium hydroxide present in your sample, use the <strong>molar mass</strong> of the compound.</p> <blockquote> <p><mathjax>#15.0 color(red)(cancel(color(black)("g"))) * "1 mole NaOH"/(39.997color(red)(cancel(color(black)("g")))) = "0.3750 moles NaOH"#</mathjax></p> </blockquote> <p>This means that the molarity of the sodium hydroxide solution is</p> <blockquote> <p><mathjax>#["NaOH"] = "0.3750 moles"/(375 * 10^(-3) quad "L") = "1.00 mol L"^(-1)#</mathjax></p> </blockquote> <p>Now, sodium hydroxide is a <strong>strong base</strong>, which implies that it dissociates completely in aqueous solution to produce sodium cations and hydroxide anions in <mathjax>#1:1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a>.</p> <blockquote> <p><mathjax>#color(white)(overbrace(color(black)("NaOH"_ ((aq))))^(color(blue)("1 mole dissolved"))) -&gt; color(white)(overbrace(color(black)("Na"_ ((aq))^(+)))^(color(blue)("1 mole produced"))) + color(white)(overbrace(color(black)("OH"_ ((aq))^(-)))^(color(blue)("1 mole produced")))#</mathjax></p> </blockquote> <p>This means that your solution will have</p> <blockquote> <p><mathjax>#["Na"^(+)] = ["OH"^(-)] = ["NaOH"]#</mathjax></p> </blockquote> <p>and so</p> <blockquote> <p><mathjax>#["OH"^(-)] = color(darkgreen)(ul(color(black)("1.00 mol L"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for your values. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/590630" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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A particular drain cleaner contains #"NaOH"#. What is the value of #["OH"^(-)]# in a solution produced when #"15.0 g"# of #"NaOH"# dissolves in enough water to make #"375 mL"# of solution?

ad0b716f-6ddd-11ea-8a38-ccda262736ce

https://socratic.org/questions/the-mass-of-carbon-anode-consumed-in-the-production-of-270kg-al-metal-from-bauxi

90.08 kg

start physical_unit 3 4 mass kg qc_end physical_unit 12 13 10 11 mass qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Mass [OF] carbon anode [IN] kg"}]

[{"type":"physical unit","value":"90.08 kg"}]

[{"type":"physical unit","value":"Mass [OF] Al metal [=] \\pu{270 kg}"},{"type":"other","value":"Hall process gives only carbon dioxide."}]

<h1 class="questionTitle" itemprop="name">The mass of. Carbon anode consumed in the production of 270kg Al metal from bauxite by hall process giving only carbon dioxide? </h1>

90.08 kg

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The aluminum and fluoride salts are added to the reaction mix to depress the (high) metling point of alumina....even so, this is a very energy intensive reaction. Think about that the next time you throw away that aluminum foil you used to cook your spuds in (and you don't need foil anyway, just cook the scrubbed potatoes in their jackets!). </p> <p><mathjax>#"Moles of aluminum"=(270xx10^3*g)/(27.0*g*mol^-1)=10^4*mol#</mathjax></p> <p>And given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the reaction, we produce a <mathjax>#(10^4*mol)/2=5000*mol#</mathjax> quantity of aluminum. </p> <p>And thus we need an equivalent molar quantity with respect to carbon....</p> <p><mathjax>#7500*molxx12.011*g*mol^-1xx10^-3*kg*g^-1=90*kg#</mathjax> with respect to carbon. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We assess the reaction...<mathjax>#Al_2O_3(s) + 3/2 C(s) +Deltastackrel(AlF_3"/"NaF)→ 2 Al(s) + 3/2 CO_2(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The aluminum and fluoride salts are added to the reaction mix to depress the (high) metling point of alumina....even so, this is a very energy intensive reaction. Think about that the next time you throw away that aluminum foil you used to cook your spuds in (and you don't need foil anyway, just cook the scrubbed potatoes in their jackets!). </p> <p><mathjax>#"Moles of aluminum"=(270xx10^3*g)/(27.0*g*mol^-1)=10^4*mol#</mathjax></p> <p>And given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the reaction, we produce a <mathjax>#(10^4*mol)/2=5000*mol#</mathjax> quantity of aluminum. </p> <p>And thus we need an equivalent molar quantity with respect to carbon....</p> <p><mathjax>#7500*molxx12.011*g*mol^-1xx10^-3*kg*g^-1=90*kg#</mathjax> with respect to carbon. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">The mass of. Carbon anode consumed in the production of 270kg Al metal from bauxite by hall process giving only carbon dioxide? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="463148" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-12T17:23:01" itemprop="dateCreated"> Aug 12, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We assess the reaction...<mathjax>#Al_2O_3(s) + 3/2 C(s) +Deltastackrel(AlF_3"/"NaF)→ 2 Al(s) + 3/2 CO_2(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The aluminum and fluoride salts are added to the reaction mix to depress the (high) metling point of alumina....even so, this is a very energy intensive reaction. Think about that the next time you throw away that aluminum foil you used to cook your spuds in (and you don't need foil anyway, just cook the scrubbed potatoes in their jackets!). </p> <p><mathjax>#"Moles of aluminum"=(270xx10^3*g)/(27.0*g*mol^-1)=10^4*mol#</mathjax></p> <p>And given the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> of the reaction, we produce a <mathjax>#(10^4*mol)/2=5000*mol#</mathjax> quantity of aluminum. </p> <p>And thus we need an equivalent molar quantity with respect to carbon....</p> <p><mathjax>#7500*molxx12.011*g*mol^-1xx10^-3*kg*g^-1=90*kg#</mathjax> with respect to carbon. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/463148" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -&gt; 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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The mass of. Carbon anode consumed in the production of 270kg Al metal from bauxite by hall process giving only carbon dioxide?