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a9b2de54-6ddd-11ea-9865-ccda262736ce

https://socratic.org/questions/the-value-of-k-sp-for-srso-4-is-2-8-times-10-7-what-is-the-solubility-of-srso-4-

0.10 moles per liter

start physical_unit 5 5 solubility mol/l qc_end physical_unit 5 5 7 9 equilibrium_constant_k qc_end end

[{"type":"physical unit","value":"Solubility [OF] SrSO4 [IN] moles per liter"}]

[{"type":"physical unit","value":"0.10 moles per liter"}]

[{"type":"physical unit","value":"Ksp [OF] SrSO4 [=] \\pu{2.8 × 10^(-7)}"}]

<h1 class="questionTitle" itemprop="name">The value of #K_(sp)# for #SrSO_4# is #2.8 times 10^-7#. What is the solubility of #SrSO_4# in moles per liter?</h1>

0.10 moles per liter

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Now we interrogate the solubility equilibrium.....</p> <p><mathjax>#SrSO_4(s) rightleftharpoons Sr^(2+) + SO_4^(2-)#</mathjax></p> <p>And <mathjax>#K_"sp"=[Sr^(2+)][SO_4^(2-)]#</mathjax></p> <p>We write <mathjax>#S="solubility of strontium sulfate."#</mathjax> And thus <mathjax>#S=[Sr^(2+)]#</mathjax>, and <mathjax>#S=[SO_4^(2-)]#</mathjax>...and we substitute these values into the solubility expression......</p> <p><mathjax>#K_"sp"=[Sr^(2+)][SO_4^(2-)]=SxxS=S^2#</mathjax></p> <p>And thus..............................</p> <p><mathjax>#S=sqrt(K_"sp")=sqrt(2.8xx10^-7)=5.29xx10^-4*mol*L^-1#</mathjax>.</p> <p>And the gram solubility is thus.....</p> <p><mathjax>#5.29xx10^-4*mol*L^-1xx183.68*mol*L^-1=??#</mathjax></p> <p>If we attempted to dissolve the slat up in say <mathjax>#0.100*mol*L^-1#</mathjax> <mathjax>#"sodium sulfate"#</mathjax>, do you think the solubility would increase or decrease? Why?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Solubility"#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#100*mg*L^-1?#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Now we interrogate the solubility equilibrium.....</p> <p><mathjax>#SrSO_4(s) rightleftharpoons Sr^(2+) + SO_4^(2-)#</mathjax></p> <p>And <mathjax>#K_"sp"=[Sr^(2+)][SO_4^(2-)]#</mathjax></p> <p>We write <mathjax>#S="solubility of strontium sulfate."#</mathjax> And thus <mathjax>#S=[Sr^(2+)]#</mathjax>, and <mathjax>#S=[SO_4^(2-)]#</mathjax>...and we substitute these values into the solubility expression......</p> <p><mathjax>#K_"sp"=[Sr^(2+)][SO_4^(2-)]=SxxS=S^2#</mathjax></p> <p>And thus..............................</p> <p><mathjax>#S=sqrt(K_"sp")=sqrt(2.8xx10^-7)=5.29xx10^-4*mol*L^-1#</mathjax>.</p> <p>And the gram solubility is thus.....</p> <p><mathjax>#5.29xx10^-4*mol*L^-1xx183.68*mol*L^-1=??#</mathjax></p> <p>If we attempted to dissolve the slat up in say <mathjax>#0.100*mol*L^-1#</mathjax> <mathjax>#"sodium sulfate"#</mathjax>, do you think the solubility would increase or decrease? Why?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">The value of #K_(sp)# for #SrSO_4# is #2.8 times 10^-7#. What is the solubility of #SrSO_4# in moles per liter?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/factors-affecting-solubility" itemprop="url"> <span class="breadcrumb" itemprop="title">Factors Affecting Solubility</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="471917" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-05T07:41:24" itemprop="dateCreated"> Sep 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Solubility"#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#100*mg*L^-1?#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Now we interrogate the solubility equilibrium.....</p> <p><mathjax>#SrSO_4(s) rightleftharpoons Sr^(2+) + SO_4^(2-)#</mathjax></p> <p>And <mathjax>#K_"sp"=[Sr^(2+)][SO_4^(2-)]#</mathjax></p> <p>We write <mathjax>#S="solubility of strontium sulfate."#</mathjax> And thus <mathjax>#S=[Sr^(2+)]#</mathjax>, and <mathjax>#S=[SO_4^(2-)]#</mathjax>...and we substitute these values into the solubility expression......</p> <p><mathjax>#K_"sp"=[Sr^(2+)][SO_4^(2-)]=SxxS=S^2#</mathjax></p> <p>And thus..............................</p> <p><mathjax>#S=sqrt(K_"sp")=sqrt(2.8xx10^-7)=5.29xx10^-4*mol*L^-1#</mathjax>.</p> <p>And the gram solubility is thus.....</p> <p><mathjax>#5.29xx10^-4*mol*L^-1xx183.68*mol*L^-1=??#</mathjax></p> <p>If we attempted to dissolve the slat up in say <mathjax>#0.100*mol*L^-1#</mathjax> <mathjax>#"sodium sulfate"#</mathjax>, do you think the solubility would increase or decrease? Why?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/471917" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factors-affect-solubility-in-a-solid-liquid-combination"> What factors affect solubility in a solid-liquid combination? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factors-affect-solubility-in-water"> What factors affect solubility in water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factors-affect-solubility-of-ionic-compounds"> What factors affect solubility of ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factors-affect-the-solubility-of-gases-in-liquids"> What factors affect the solubility of gases in liquids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factors-affect-the-solubility-of-a-solid"> What factors affect the solubility of a solid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-solubility-of-potassium-nitrate"> How can I calculate solubility of potassium nitrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-solubility-of-kno3-depend-on"> What does the solubility of KNO3 depend on? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-solubility-of-a-solution"> How can I calculate the solubility of solute in a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-solubility-is-affected-by-polymer-chain-structure"> How is solubility affected by polymer chain structure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/does-solubility-differ-from-molar-solubility"> Does solubility differ from molar solubility? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/factors-affecting-solubility"> See all questions in Factors Affecting Solubility </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5017 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

The value of #K_(sp)# for #SrSO_4# is #2.8 times 10^-7#. What is the solubility of #SrSO_4# in moles per liter?

ac614a37-6ddd-11ea-ad16-ccda262736ce

https://socratic.org/questions/how-do-you-write-the-equation-for-the-following-reaction-solid-diphosphorus-pent

P4O10 + 6 H2O(l) -> 4 H3PO4(aq)

start chemical_equation qc_end substance 10 12 qc_end substance 15 15 qc_end substance 18 19 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"P4O10 + 6 H2O(l) -> 4 H3PO4(aq)"}]

[{"type":"substance name","value":"Solid diphosphorus pentaoxide"},{"type":"substance name","value":"Water"},{"type":"substance name","value":"Phosphoric acid"}]

<h1 class="questionTitle" itemprop="name">How do you write the equation for the following reaction: solid diphosphorus pentaoxide reacts with water to form phosphoric acid?</h1>

P4O10 + 6 H2O(l) -> 4 H3PO4(aq)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is this stoichiometrically balanced? <mathjax>#P_4O_10#</mathjax> is the so-called <mathjax>#"anhydride"#</mathjax> of phosphoric acid. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_4O_10 + 6H_2O(l) rarr 4H_3PO_4(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is this stoichiometrically balanced? <mathjax>#P_4O_10#</mathjax> is the so-called <mathjax>#"anhydride"#</mathjax> of phosphoric acid. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you write the equation for the following reaction: solid diphosphorus pentaoxide reacts with water to form phosphoric acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="346932" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-05T06:23:03" itemprop="dateCreated"> Dec 5, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_4O_10 + 6H_2O(l) rarr 4H_3PO_4(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is this stoichiometrically balanced? <mathjax>#P_4O_10#</mathjax> is the so-called <mathjax>#"anhydride"#</mathjax> of phosphoric acid. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/346932" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-equation-for-photosynthesis"> What is the chemical equation for photosynthesis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-grams-of-each-substance-used-or-produced-w"> How can I know the relative number of grams of each substance used or produced with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-moles-of-each-substance-with-chemical-equa"> How can I know the relative number of moles of each substance with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-chemical-equations-illustrate-that-atoms-are-conserved-1"> How do chemical equations illustrate that atoms are conserved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-formula-of-the-reactants-and-products-with-chemical-equations"> How can I know the formula of the reactants and products with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-potassium-metal-and-chlorine-gas-combi"> How can I balance this chemical equations? 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How do you write the equation for the following reaction: solid diphosphorus pentaoxide reacts with water to form phosphoric acid?

a8f5f45a-6ddd-11ea-995a-ccda262736ce

https://socratic.org/questions/if-a-chemist-needs-to-make-35-05-g-of-cui-2-how-many-ml-of-a-3-3-m-solution-of-n

66.94 mL

start physical_unit 17 17 volume ml qc_end physical_unit 9 9 6 7 mass qc_end physical_unit 19 19 15 16 molarity qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Volume [OF] NaI solution [IN] mL"}]

[{"type":"physical unit","value":"66.94 mL"}]

[{"type":"physical unit","value":"Mass [OF] CuI2 [=] \\pu{35.05 g}"},{"type":"physical unit","value":"Molarity [OF] NaI solution [=] \\pu{3.3 M}"},{"type":"other","value":"Excess copper (II) nitrate."}]

<h1 class="questionTitle" itemprop="name">If a chemist needs to make 35.05 g of #CuI_2#, how many mL of a 3.3 M solution of #NaI# must he use, assuming there is excess copper (II) nitrate?</h1>

66.94 mL

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To answer this problem, determine the balanced chemical reaction involved which is shown below:</p> <p><img alt="enter image source here" src="https://useruploads.socratic.org/cqQRJAB1SviSwHW86QjH_Presentation1.jpg"/> </p> <p>Using dimensional analysis, lets determine the number of moles of sodium iodide needed to produced 35.05 g of copper (II) iodide. An outline of the calculation will be first divide first the amount of copper (II) iodide with its multiply then multiply it with the appropriate dimension factor based on the balanced chemical reaction which will give you an answer equal to 0.2209 mol NaI:</p> <p><img alt="enter image source here" src="https://useruploads.socratic.org/mFOJsqzRyKLg5QhuYAhq_2.jpg"/> </p> <p>Then, two determined the volume of NaI needed, will going to divide the calculated number of moles of NaI that was calculated with the concentration of NaI solution that was given in the answer. Converting liter to milliliters will give us a volume equal to 66.94 mL:</p> <p><mathjax>#volume NaI = (0.2209 mol NaI) x ((1 L NaI solution)/(3.3 mol NaI) ) x ((1000 mL NaI solution)/(1L NaI solution)) = 66.94 mL of 3.3M NaI solution#</mathjax> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>This will be equal to 66.94 mL of 3.3 M NaI solution.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To answer this problem, determine the balanced chemical reaction involved which is shown below:</p> <p><img alt="enter image source here" src="https://useruploads.socratic.org/cqQRJAB1SviSwHW86QjH_Presentation1.jpg"/> </p> <p>Using dimensional analysis, lets determine the number of moles of sodium iodide needed to produced 35.05 g of copper (II) iodide. An outline of the calculation will be first divide first the amount of copper (II) iodide with its multiply then multiply it with the appropriate dimension factor based on the balanced chemical reaction which will give you an answer equal to 0.2209 mol NaI:</p> <p><img alt="enter image source here" src="https://useruploads.socratic.org/mFOJsqzRyKLg5QhuYAhq_2.jpg"/> </p> <p>Then, two determined the volume of NaI needed, will going to divide the calculated number of moles of NaI that was calculated with the concentration of NaI solution that was given in the answer. Converting liter to milliliters will give us a volume equal to 66.94 mL:</p> <p><mathjax>#volume NaI = (0.2209 mol NaI) x ((1 L NaI solution)/(3.3 mol NaI) ) x ((1000 mL NaI solution)/(1L NaI solution)) = 66.94 mL of 3.3M NaI solution#</mathjax> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If a chemist needs to make 35.05 g of #CuI_2#, how many mL of a 3.3 M solution of #NaI# must he use, assuming there is excess copper (II) nitrate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="224371" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/bong-carlo-r"><img alt="" class="" src="https://graph.facebook.com/10205519946625209/picture?height=50&amp;width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/bong-carlo-r"> Carlo Remillion </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-10T14:29:24" itemprop="dateCreated"> Feb 10, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>This will be equal to 66.94 mL of 3.3 M NaI solution.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To answer this problem, determine the balanced chemical reaction involved which is shown below:</p> <p><img alt="enter image source here" src="https://useruploads.socratic.org/cqQRJAB1SviSwHW86QjH_Presentation1.jpg"/> </p> <p>Using dimensional analysis, lets determine the number of moles of sodium iodide needed to produced 35.05 g of copper (II) iodide. An outline of the calculation will be first divide first the amount of copper (II) iodide with its multiply then multiply it with the appropriate dimension factor based on the balanced chemical reaction which will give you an answer equal to 0.2209 mol NaI:</p> <p><img alt="enter image source here" src="https://useruploads.socratic.org/mFOJsqzRyKLg5QhuYAhq_2.jpg"/> </p> <p>Then, two determined the volume of NaI needed, will going to divide the calculated number of moles of NaI that was calculated with the concentration of NaI solution that was given in the answer. Converting liter to milliliters will give us a volume equal to 66.94 mL:</p> <p><mathjax>#volume NaI = (0.2209 mol NaI) x ((1 L NaI solution)/(3.3 mol NaI) ) x ((1000 mL NaI solution)/(1L NaI solution)) = 66.94 mL of 3.3M NaI solution#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/224371" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2431 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

If a chemist needs to make 35.05 g of #CuI_2#, how many mL of a 3.3 M solution of #NaI# must he use, assuming there is excess copper (II) nitrate?

a9130cc2-6ddd-11ea-9817-ccda262736ce

https://socratic.org/questions/balance-this-reaction-using-ion-electron-method-in-shortest-way-possible-but-mus

5 Fe^2+ + MnO4- + 8 H+ -> 5 Fe^3+ + Mn^2+ + 4 H2O

start chemical_equation qc_end chemical_equation 17 27 qc_end end

[{"type":"other","value":"Chemical Equation [OF] this reaction"}]

[{"type":"chemical equation","value":"5 Fe^2+ + MnO4- + 8 H+ -> 5 Fe^3+ + Mn^2+ + 4 H2O"}]

[{"type":"chemical equation","value":"Fe^2+ + MnO4- + H+ -> Fe^3+ + Mn^2+ + H2O"}]

<h1 class="questionTitle" itemprop="name">Balance this reaction using ion electron method in shortest way possible . but must be clear .. #Fe^(2+)+MnO_4^(-)+H^(+) -&gt; Fe^(3+)+Mn^(2+)+H_2O# ?</h1>

5 Fe^2+ + MnO4- + 8 H+ -> 5 Fe^3+ + Mn^2+ + 4 H2O

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In ion electron method one reaction is divided into two reaction (half reaction) and then they are balanced and then added together</p> <p>Figure the reducing(increase of electrons) and oxidizing(decrease of electrons) agent <br/> <mathjax>#color(white)(Fe^())2color(white)(Mln)7^+ -2color(white)(lllllllxxlll)+3color(white)(llxlllll)2+#</mathjax><br/> <mathjax>#Fe^(2+) + MnO_4^-) + H^+ → Fe^(3+)+Mn^(2+) + H2O#</mathjax></p> <p>Iron has already lost 2 electrons and in this reaction it is losing another one</p> <p><mathjax>#Fe^(2+) = Fe^(3+)#</mathjax></p> <p>Thus iron is being oxidized </p> <p><mathjax>#MnO_4^-) = Mn^(2+)#</mathjax></p> <p>In the ion MnO4, Mn has a charge of 7+ and it changing into 2+ in this reaction </p> <p>Thus MnO4 is being oxidized</p> <p>Now balance the the oxygen atoms</p> <p><mathjax>#MnO4^-) = Mn^(2+) + 4O#</mathjax></p> <p>You can see in the reaction that oxygen is used to make water and no oxygen is let which is <mathjax>#O_2#</mathjax></p> <p>thus 4 oxygen atoms can produce 4 water molecules</p> <p><mathjax>#MnO4^-) + H^+ = Mn^(2+) + 4H_2O#</mathjax></p> <p>balance the reaction</p> <p><mathjax>#MnO4^-) + 8H^+= Mn^(2+) + 4H_2O#</mathjax></p> <p>Now for a redox reaction the addition of charges on both sides should be equal.So try it in this reaction</p> <p><mathjax>#(-1) + 8 = +7#</mathjax><br/> <mathjax>#(+2) + 0 = +2#</mathjax></p> <p>So both sides are not equal. To make them equal you should add electrons as you cant add protons.Thus if you think of adding 5 protons to the other side to make it equal to 7 it is wrong.But you can add 5 electrons to the other side to make it equal to 2</p> <p><mathjax>#MnO4^-) + 8H^+ + 5e^-)= Mn^(2+) + 4H_2O#</mathjax></p> <p>Where <mathjax>#5e^-#</mathjax> is 5 electrons</p> <p>Make electron gain equivalent to electron lost. The electrons lost in the oxidation half-reaction must be equal the electrons gained in the reduction half-reaction. And this electrons come from the oxidizing agent that is <mathjax>#Fe^(2+)#</mathjax></p> <p><mathjax>#Fe^(2+) = Fe^(3+)#</mathjax></p> <p>Again try to make the charges equal on same side and you would get </p> <p><mathjax>#Fe^(2+) = Fe^(3+) + e^-#</mathjax></p> <p>Now we want 5electrons not one so to get 5electrons you must have more <mathjax>#Fe^(2+)#</mathjax></p> <p><mathjax>#5Fe^(2+) = 5Fe^(3+) + 5e^-#</mathjax></p> <p>Add both the reactions</p> <p><mathjax>#MnO4^-) + 8H^+ + 5e^-) + 5Fe^(2+)= Mn^(2+) + 4H_2O+5Fe^(3+) + 5e^-#</mathjax></p> <p>cancel the same terms</p> <p><mathjax>#MnO4^-) + 8H^+ +cancel( 5e^-) + 5Fe^(2+)= Mn^(2+) + 4H_2O+5Fe^(3+) + cancel(5e^-)#</mathjax></p> <p><mathjax>#MnO4^-) + 8H^+ + 5Fe^(2+)= Mn^(2+) + 4H_2O+5Fe^(3+) #</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#MnO4^-) + 8H^+ + 5Fe^(2+)= Mn^(2+) + 4H_2O+5Fe^(3+) #</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In ion electron method one reaction is divided into two reaction (half reaction) and then they are balanced and then added together</p> <p>Figure the reducing(increase of electrons) and oxidizing(decrease of electrons) agent <br/> <mathjax>#color(white)(Fe^())2color(white)(Mln)7^+ -2color(white)(lllllllxxlll)+3color(white)(llxlllll)2+#</mathjax><br/> <mathjax>#Fe^(2+) + MnO_4^-) + H^+ → Fe^(3+)+Mn^(2+) + H2O#</mathjax></p> <p>Iron has already lost 2 electrons and in this reaction it is losing another one</p> <p><mathjax>#Fe^(2+) = Fe^(3+)#</mathjax></p> <p>Thus iron is being oxidized </p> <p><mathjax>#MnO_4^-) = Mn^(2+)#</mathjax></p> <p>In the ion MnO4, Mn has a charge of 7+ and it changing into 2+ in this reaction </p> <p>Thus MnO4 is being oxidized</p> <p>Now balance the the oxygen atoms</p> <p><mathjax>#MnO4^-) = Mn^(2+) + 4O#</mathjax></p> <p>You can see in the reaction that oxygen is used to make water and no oxygen is let which is <mathjax>#O_2#</mathjax></p> <p>thus 4 oxygen atoms can produce 4 water molecules</p> <p><mathjax>#MnO4^-) + H^+ = Mn^(2+) + 4H_2O#</mathjax></p> <p>balance the reaction</p> <p><mathjax>#MnO4^-) + 8H^+= Mn^(2+) + 4H_2O#</mathjax></p> <p>Now for a redox reaction the addition of charges on both sides should be equal.So try it in this reaction</p> <p><mathjax>#(-1) + 8 = +7#</mathjax><br/> <mathjax>#(+2) + 0 = +2#</mathjax></p> <p>So both sides are not equal. To make them equal you should add electrons as you cant add protons.Thus if you think of adding 5 protons to the other side to make it equal to 7 it is wrong.But you can add 5 electrons to the other side to make it equal to 2</p> <p><mathjax>#MnO4^-) + 8H^+ + 5e^-)= Mn^(2+) + 4H_2O#</mathjax></p> <p>Where <mathjax>#5e^-#</mathjax> is 5 electrons</p> <p>Make electron gain equivalent to electron lost. The electrons lost in the oxidation half-reaction must be equal the electrons gained in the reduction half-reaction. And this electrons come from the oxidizing agent that is <mathjax>#Fe^(2+)#</mathjax></p> <p><mathjax>#Fe^(2+) = Fe^(3+)#</mathjax></p> <p>Again try to make the charges equal on same side and you would get </p> <p><mathjax>#Fe^(2+) = Fe^(3+) + e^-#</mathjax></p> <p>Now we want 5electrons not one so to get 5electrons you must have more <mathjax>#Fe^(2+)#</mathjax></p> <p><mathjax>#5Fe^(2+) = 5Fe^(3+) + 5e^-#</mathjax></p> <p>Add both the reactions</p> <p><mathjax>#MnO4^-) + 8H^+ + 5e^-) + 5Fe^(2+)= Mn^(2+) + 4H_2O+5Fe^(3+) + 5e^-#</mathjax></p> <p>cancel the same terms</p> <p><mathjax>#MnO4^-) + 8H^+ +cancel( 5e^-) + 5Fe^(2+)= Mn^(2+) + 4H_2O+5Fe^(3+) + cancel(5e^-)#</mathjax></p> <p><mathjax>#MnO4^-) + 8H^+ + 5Fe^(2+)= Mn^(2+) + 4H_2O+5Fe^(3+) #</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Balance this reaction using ion electron method in shortest way possible . but must be clear .. #Fe^(2+)+MnO_4^(-)+H^(+) -&gt; Fe^(3+)+Mn^(2+)+H_2O# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/balancing-redox-equations-using-the-oxidation-number-method" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Redox Equations Using the Oxidation Number Method</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">3</span> Answers </h5> <div class="answers"> <div class="answer" id="407983" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/samriddha"><img alt="" class="" src="https://profilepictures.socratic.org/3bMcXdwZTLqpsJaquExz_Shinjuku.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/samriddha"> Professor Sam </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-17T13:44:22" itemprop="dateCreated"> Apr 17, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#MnO4^-) + 8H^+ + 5Fe^(2+)= Mn^(2+) + 4H_2O+5Fe^(3+) #</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In ion electron method one reaction is divided into two reaction (half reaction) and then they are balanced and then added together</p> <p>Figure the reducing(increase of electrons) and oxidizing(decrease of electrons) agent <br/> <mathjax>#color(white)(Fe^())2color(white)(Mln)7^+ -2color(white)(lllllllxxlll)+3color(white)(llxlllll)2+#</mathjax><br/> <mathjax>#Fe^(2+) + MnO_4^-) + H^+ → Fe^(3+)+Mn^(2+) + H2O#</mathjax></p> <p>Iron has already lost 2 electrons and in this reaction it is losing another one</p> <p><mathjax>#Fe^(2+) = Fe^(3+)#</mathjax></p> <p>Thus iron is being oxidized </p> <p><mathjax>#MnO_4^-) = Mn^(2+)#</mathjax></p> <p>In the ion MnO4, Mn has a charge of 7+ and it changing into 2+ in this reaction </p> <p>Thus MnO4 is being oxidized</p> <p>Now balance the the oxygen atoms</p> <p><mathjax>#MnO4^-) = Mn^(2+) + 4O#</mathjax></p> <p>You can see in the reaction that oxygen is used to make water and no oxygen is let which is <mathjax>#O_2#</mathjax></p> <p>thus 4 oxygen atoms can produce 4 water molecules</p> <p><mathjax>#MnO4^-) + H^+ = Mn^(2+) + 4H_2O#</mathjax></p> <p>balance the reaction</p> <p><mathjax>#MnO4^-) + 8H^+= Mn^(2+) + 4H_2O#</mathjax></p> <p>Now for a redox reaction the addition of charges on both sides should be equal.So try it in this reaction</p> <p><mathjax>#(-1) + 8 = +7#</mathjax><br/> <mathjax>#(+2) + 0 = +2#</mathjax></p> <p>So both sides are not equal. To make them equal you should add electrons as you cant add protons.Thus if you think of adding 5 protons to the other side to make it equal to 7 it is wrong.But you can add 5 electrons to the other side to make it equal to 2</p> <p><mathjax>#MnO4^-) + 8H^+ + 5e^-)= Mn^(2+) + 4H_2O#</mathjax></p> <p>Where <mathjax>#5e^-#</mathjax> is 5 electrons</p> <p>Make electron gain equivalent to electron lost. The electrons lost in the oxidation half-reaction must be equal the electrons gained in the reduction half-reaction. And this electrons come from the oxidizing agent that is <mathjax>#Fe^(2+)#</mathjax></p> <p><mathjax>#Fe^(2+) = Fe^(3+)#</mathjax></p> <p>Again try to make the charges equal on same side and you would get </p> <p><mathjax>#Fe^(2+) = Fe^(3+) + e^-#</mathjax></p> <p>Now we want 5electrons not one so to get 5electrons you must have more <mathjax>#Fe^(2+)#</mathjax></p> <p><mathjax>#5Fe^(2+) = 5Fe^(3+) + 5e^-#</mathjax></p> <p>Add both the reactions</p> <p><mathjax>#MnO4^-) + 8H^+ + 5e^-) + 5Fe^(2+)= Mn^(2+) + 4H_2O+5Fe^(3+) + 5e^-#</mathjax></p> <p>cancel the same terms</p> <p><mathjax>#MnO4^-) + 8H^+ +cancel( 5e^-) + 5Fe^(2+)= Mn^(2+) + 4H_2O+5Fe^(3+) + cancel(5e^-)#</mathjax></p> <p><mathjax>#MnO4^-) + 8H^+ + 5Fe^(2+)= Mn^(2+) + 4H_2O+5Fe^(3+) #</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/407983" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="408022" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/truong-son-n"><img alt="" class="" src="https://profilepictures.socratic.org/07k4plnQfmnmzMuesQzw_14844-1449381920.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/truong-son-n"> Truong-Son N. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-17T14:33:59" itemprop="dateCreated"> Apr 17, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><blockquote> <p><mathjax>#bb(5stackrel(color(blue)(+2))("Fe"^(2+))(aq) + 8stackrel(color(blue)(+1))("H"^(+)(aq)) + stackrel(color(blue)(+7))("Mn")stackrel(color(blue)(-2))("O"_4^(-))(aq) -&gt; stackrel(color(blue)(+2))("Mn"^(2+))(aq) + 4stackrel(color(blue)(+1))("H"_2)stackrel(color(blue)(-2))("O")(l) + 5stackrel(color(blue)(+3))("Fe"^(3+))(aq))#</mathjax></p> </blockquote> <hr/> <p>Here are the primary steps for <strong>balancing in ACIDIC solution</strong>:</p> <ol> <li><strong>Pick out</strong> the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> being oxidized and reduced and write out their <em>unbalanced</em> half-reactions (this should require almost zero effort as this is the easy part).</li> <li><strong>Balance the non-</strong><mathjax>#bb"O"#</mathjax> and <strong>non-</strong><mathjax>#bb"H"#</mathjax> atoms.</li> <li><strong>Balance</strong> <mathjax>#bb"O"#</mathjax> using <mathjax>#"H"_2"O"#</mathjax> molecules, since the solution is <em>aqueous</em>.</li> <li><strong>Balance</strong> <mathjax>#bb"H"#</mathjax> using <mathjax>#"H"^(+)#</mathjax> ions, since the solution is <em>acidic</em>.</li> <li><strong>Balance the remaining charge</strong> using electrons on the side with more positive charge, since electrons must cancel out in the overall reaction.</li> <li><strong>Scale one or both reactions</strong> to cancel out the electrons.</li> <li><strong>Add</strong> the reactions together.</li> </ol> <p>In BASIC solution, add the step of adding <mathjax>#"OH"^(-)#</mathjax> to both sides of the final reaction, combining <mathjax>#"H"^(+)#</mathjax> and <mathjax>#"OH"^(-)#</mathjax> to make water, then canceling out common waters on each side.</p> <p><em>Usually you don't have to do all of these steps, and the nice thing is that if you have to balance another reaction that involves the same oxidation or reduction half-reaction, you can recycle the same half-reaction.</em></p> <p><strong>OXIDATION HALF-REACTION</strong></p> <p>Iron gets oxidized from a <mathjax>#+2#</mathjax> to <mathjax>#+3#</mathjax> oxidation state. For pure ions, the charge <em>is</em> the oxidation state.</p> <blockquote> <p><mathjax>#stackrel(color(blue)(+2))("Fe"^(2+))(aq) -&gt; stackrel(color(blue)(+3))("Fe"^(3+))(aq)#</mathjax> (step 1)</p> </blockquote> <p>Everything is balanced except for the charge, so we can skip straight to step 5.</p> <blockquote> <p><mathjax>#stackrel(color(blue)(+2))("Fe"^(2+))(aq) -&gt; stackrel(color(blue)(+3))("Fe"^(3+))(aq) + e^(-)#</mathjax> (step 5)</p> </blockquote> <p>The total charge on each side is now:</p> <blockquote> <p><mathjax>#(+2) = (+3) + (-1)#</mathjax> <mathjax>#color(blue)(sqrt"")#</mathjax></p> </blockquote> <p>Done with the oxidation half-reaction.</p> <p><strong>REDUCTION HALF-REACTION</strong></p> <p>In some respects, this is the easier one to identify. <strong>Reduction</strong> can sometimes be thought of as the <strong>loss of oxygen atoms</strong>, and oxidation the gain of oxygen atoms. </p> <p>Manganese can be readily seen to have <strong><em>lost</em></strong> oxygen atoms going from <mathjax>#"MnO"_4^(-)#</mathjax> to <mathjax>#"Mn"^(2+)#</mathjax>, which is why I suggested this easier way to spot reduction if applicable.</p> <blockquote> <p><mathjax>#stackrel(color(blue)(+7))("Mn")stackrel(color(blue)(-2))("O"_4^(-))(aq) -&gt; stackrel(color(blue)(+2))("Mn"^(2+))(aq)#</mathjax> (step 1)</p> </blockquote> <p>The non-oxygen and non-hydrogen atoms (i.e. <mathjax>#"Mn"#</mathjax>) are balanced, so we skip to step 3. Add water to balance the oxygens.</p> <blockquote> <p><mathjax>#stackrel(color(blue)(+7))("Mn")stackrel(color(blue)(-2))("O"_4^(-))(aq) -&gt; stackrel(color(blue)(+2))("Mn"^(2+))(aq) + 4stackrel(color(blue)(+1))("H"_2)stackrel(color(blue)(-2))("O")(l)#</mathjax> (step 3)</p> </blockquote> <p>Add <mathjax>#"H"^(+)#</mathjax> to balance the hydrogens.</p> <blockquote> <p><mathjax>#8stackrel(color(blue)(+1))("H"^(+))(aq) + stackrel(color(blue)(+7))("Mn")stackrel(color(blue)(-2))("O"_4^(-))(aq) -&gt; stackrel(color(blue)(+2))("Mn"^(2+))(aq) + 4stackrel(color(blue)(+1))("H"_2)stackrel(color(blue)(-2))("O")(l)#</mathjax> (step 4)</p> </blockquote> <p><em>Balance the charge</em> using electrons on the more positive side. Each side has:</p> <blockquote> <p><mathjax>#(??) + (+8) + (-1) = (+2)#</mathjax></p> </blockquote> <p>Hence, add <mathjax>#5e^(-)#</mathjax> to the left side.</p> <blockquote> <p><mathjax>#5e^(-) + 8stackrel(color(blue)(+1))("H"^(+)(aq)) + stackrel(color(blue)(+7))("Mn")stackrel(color(blue)(-2))("O"_4^(-))(aq) -&gt; stackrel(color(blue)(+2))("Mn"^(2+))(aq) + 4stackrel(color(blue)(+1))("H"_2)stackrel(color(blue)(-2))("O")(l)#</mathjax> (step 5)</p> <p><mathjax>#(-5) + (+8) + (-1) = (+2) color(blue)(sqrt"")#</mathjax></p> </blockquote> <p>Done with the reduction half-reaction.</p> <p><strong>OVERALL REACTION</strong></p> <p>Now make the electrons cancel out. (Step 6)</p> <blockquote> <p><mathjax>#5(stackrel(color(blue)(+2))("Fe"^(2+))(aq) -&gt; stackrel(color(blue)(+3))("Fe"^(3+))(aq) + cancel(e^(-)))#</mathjax><br/> <mathjax>#cancel(5e^(-)) + 8stackrel(color(blue)(+1))("H"^(+)(aq)) + stackrel(color(blue)(+7))("Mn")stackrel(color(blue)(-2))("O"_4^(-))(aq) -&gt; stackrel(color(blue)(+2))("Mn"^(2+))(aq) + 4stackrel(color(blue)(+1))("H"_2)stackrel(color(blue)(-2))("O")(l)#</mathjax></p> </blockquote> <p>Add the reactions to get: (Step 7)</p> <blockquote> <p><mathjax>#bb(5stackrel(color(blue)(+2))("Fe"^(2+))(aq) + 8stackrel(color(blue)(+1))("H"^(+)(aq)) + stackrel(color(blue)(+7))("Mn")stackrel(color(blue)(-2))("O"_4^(-))(aq) -&gt; stackrel(color(blue)(+2))("Mn"^(2+))(aq) + 4stackrel(color(blue)(+1))("H"_2)stackrel(color(blue)(-2))("O")(l) + 5stackrel(color(blue)(+3))("Fe"^(3+))(aq))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/408022" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="478283" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-21T08:01:35" itemprop="dateCreated"> Sep 21, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#MnO_4^(-) +8H^+ + 5Fe^(2+) rarr Mn^(2+) + 5Fe^(3+) + 4H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Fe^(2+) rarr Fe^(3+) + e^-#</mathjax> <mathjax>#(i)#</mathjax></p> <p><mathjax>#MnO_4^(-) +8H^+ + 5e^(-) rarr Mn^(2+) + 4H_2O#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>And we take <mathjax>#5xx(i)+(ii)#</mathjax> to eliminate the electrons.....</p> <p><mathjax>#MnO_4^(-) +8H^+ + 5Fe^(2+) rarr Mn^(2+) + 5Fe^(3+) + 4H_2O#</mathjax></p> <p>Charge and mass are balanced so this is kosher. And what would see in the reaction. The deep purple colour of permanganate would dissipate to give almost colourless <mathjax>#Mn^(2+)#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/478283" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-reactions-in-basic-solution"> How do you balance redox reactions in basic solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-equations-by-oxidation-number-method"> How do you balance redox equations by oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-equations-in-acidic-solutions"> How do you balance redox equations in acidic solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-method"> What is the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-balancing-redox-equations-using-the-oxidation-number-m"> What are some examples of balancing redox equations using the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-number-method-useful"> Why is the oxidation number method useful? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-necessary-to-break-the-equation-into-half-reactions-in-the-oxidation-numbe"> Is it necessary to break the equation into half reactions in the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-difference-between-the-oxidation-number-method-and-the-ion-electron-"> What is the difference between the oxidation number method and the ion-electron method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-balance-the-equation-using-the-oxidation-states-method-mno2-al-mn-al2o3"> Can you balance the equation using the oxidation states method MnO2+Al---&gt;Mn+Al2O3? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-this-redox-reaction-using-the-oxidation-number-method-fe2-aq-"> How do you balance this redox reaction using the oxidation number method? Fe2+(aq) + MnO4–(aq)... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/balancing-redox-equations-using-the-oxidation-number-method"> See all questions in Balancing Redox Equations Using the Oxidation Number Method </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 25348 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

Balance this reaction using ion electron method in shortest way possible . but must be clear .. #Fe^(2+)+MnO_4^(-)+H^(+) -&gt; Fe^(3+)+Mn^(2+)+H_2O# ?

ad05f32e-6ddd-11ea-b267-ccda262736ce

https://socratic.org/questions/a-sample-of-sulfur-having-a-mass-of-1-28-g-combines-with-oxygen-to-form-a-compou-1

SO3

start chemical_formula qc_end physical_unit 3 3 8 9 mass qc_end physical_unit 28 29 20 21 mass qc_end substance 12 12 qc_end end

[{"type":"other","value":"Chemical Formula [OF] the compound [IN] empirical"}]

[{"type":"chemical equation","value":"SO3"}]

[{"type":"physical unit","value":"Mass [OF] sulfur [=] \\pu{1.28 g}"},{"type":"physical unit","value":"Mass [OF] the compound [=] \\pu{3.20 g}"},{"type":"substance name","value":"Oxygen"}]

<h1 class="questionTitle" itemprop="name">A sample of sulfur having a mass of #1.28# g combines with oxygen to form a compound with a mass #3.20# g. What is the empirical formula of the compound? </h1>

SO3

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your goal when dealing with <a href="https://socratic.org/chemistry/the-mole-concept/empirical-and-molecular-formulas">empirical formulas</a> is to determine the <strong>smallest whole number ratio</strong> that exists between the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> that make up the compound.</p> <p>In order to do that, you first need to know exactly <em>how many moles</em> of each element are present in your sample. </p> <p>You are told that a <mathjax>#"1.28-g"#</mathjax> sample of sulfur combines with oxygen gas to form a compound that has a mass of <mathjax>#"3.20 g"#</mathjax>. </p> <p>Right from the start, with the <a href="https://socratic.org/chemistry/a-closer-look-at-the-atom/mass-conservation">Law of conservation of mass</a> in mind, you can say that the mass of oxygen <strong>must be equal to</strong> the difference between the final mass of the compound and the mass of the sulfur. </p> <blockquote> <p><mathjax>#m_"compound" = m_"sulfur" + m_"oxygen"#</mathjax></p> </blockquote> <p>In this case, you can say that</p> <blockquote> <p><mathjax>#m_"oxygen" = "3.20 g" - "1.28 g" = "1.92 g"#</mathjax></p> </blockquote> <p>So, your compound contains <mathjax>#"1.28 g"#</mathjax> of sulfur and <mathjax>#"1.92 g"#</mathjax> of oxygen. Next, use the <strong>molar masses</strong> of the two elements to determine how many moles of each you have</p> <blockquote> <p><mathjax>#1.28 color(red)(cancel(color(black)("g"))) * "1 mole S"/(32.066color(red)(cancel(color(black)("g")))) = "0.03992 moles S"#</mathjax></p> <p><mathjax>#1.92 color(red)(cancel(color(black)("g"))) * "1 mole O"/(15.9994color(red)(cancel(color(black)("g")))) = "0.1200 moles O"#</mathjax></p> </blockquote> <p>To get the <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> that exists between the two elements, divided both values by the <em>smallest one</em></p> <blockquote> <p><mathjax>#"For S: " (0.03992 color(red)(cancel(color(black)("moles"))))/(0.03992color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> <p><mathjax>#"For O: " (0.1200color(red)(cancel(color(black)("moles"))))/(0.03992color(red)(cancel(color(black)("moles")))) = 3.01 ~~3#</mathjax></p> </blockquote> <p>Since you can't have a <em>smallest whole number ratio</em> between the two elements, it follows that the empirical formula of the compound is</p> <blockquote> <p><mathjax>#"S"_1"O"_3 implies color(green)("SO"_3)#</mathjax></p> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"SO"_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your goal when dealing with <a href="https://socratic.org/chemistry/the-mole-concept/empirical-and-molecular-formulas">empirical formulas</a> is to determine the <strong>smallest whole number ratio</strong> that exists between the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> that make up the compound.</p> <p>In order to do that, you first need to know exactly <em>how many moles</em> of each element are present in your sample. </p> <p>You are told that a <mathjax>#"1.28-g"#</mathjax> sample of sulfur combines with oxygen gas to form a compound that has a mass of <mathjax>#"3.20 g"#</mathjax>. </p> <p>Right from the start, with the <a href="https://socratic.org/chemistry/a-closer-look-at-the-atom/mass-conservation">Law of conservation of mass</a> in mind, you can say that the mass of oxygen <strong>must be equal to</strong> the difference between the final mass of the compound and the mass of the sulfur. </p> <blockquote> <p><mathjax>#m_"compound" = m_"sulfur" + m_"oxygen"#</mathjax></p> </blockquote> <p>In this case, you can say that</p> <blockquote> <p><mathjax>#m_"oxygen" = "3.20 g" - "1.28 g" = "1.92 g"#</mathjax></p> </blockquote> <p>So, your compound contains <mathjax>#"1.28 g"#</mathjax> of sulfur and <mathjax>#"1.92 g"#</mathjax> of oxygen. Next, use the <strong>molar masses</strong> of the two elements to determine how many moles of each you have</p> <blockquote> <p><mathjax>#1.28 color(red)(cancel(color(black)("g"))) * "1 mole S"/(32.066color(red)(cancel(color(black)("g")))) = "0.03992 moles S"#</mathjax></p> <p><mathjax>#1.92 color(red)(cancel(color(black)("g"))) * "1 mole O"/(15.9994color(red)(cancel(color(black)("g")))) = "0.1200 moles O"#</mathjax></p> </blockquote> <p>To get the <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> that exists between the two elements, divided both values by the <em>smallest one</em></p> <blockquote> <p><mathjax>#"For S: " (0.03992 color(red)(cancel(color(black)("moles"))))/(0.03992color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> <p><mathjax>#"For O: " (0.1200color(red)(cancel(color(black)("moles"))))/(0.03992color(red)(cancel(color(black)("moles")))) = 3.01 ~~3#</mathjax></p> </blockquote> <p>Since you can't have a <em>smallest whole number ratio</em> between the two elements, it follows that the empirical formula of the compound is</p> <blockquote> <p><mathjax>#"S"_1"O"_3 implies color(green)("SO"_3)#</mathjax></p> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A sample of sulfur having a mass of #1.28# g combines with oxygen to form a compound with a mass #3.20# g. What is the empirical formula of the compound? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="201638" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-20T19:55:16" itemprop="dateCreated"> Dec 20, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"SO"_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your goal when dealing with <a href="https://socratic.org/chemistry/the-mole-concept/empirical-and-molecular-formulas">empirical formulas</a> is to determine the <strong>smallest whole number ratio</strong> that exists between the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> that make up the compound.</p> <p>In order to do that, you first need to know exactly <em>how many moles</em> of each element are present in your sample. </p> <p>You are told that a <mathjax>#"1.28-g"#</mathjax> sample of sulfur combines with oxygen gas to form a compound that has a mass of <mathjax>#"3.20 g"#</mathjax>. </p> <p>Right from the start, with the <a href="https://socratic.org/chemistry/a-closer-look-at-the-atom/mass-conservation">Law of conservation of mass</a> in mind, you can say that the mass of oxygen <strong>must be equal to</strong> the difference between the final mass of the compound and the mass of the sulfur. </p> <blockquote> <p><mathjax>#m_"compound" = m_"sulfur" + m_"oxygen"#</mathjax></p> </blockquote> <p>In this case, you can say that</p> <blockquote> <p><mathjax>#m_"oxygen" = "3.20 g" - "1.28 g" = "1.92 g"#</mathjax></p> </blockquote> <p>So, your compound contains <mathjax>#"1.28 g"#</mathjax> of sulfur and <mathjax>#"1.92 g"#</mathjax> of oxygen. Next, use the <strong>molar masses</strong> of the two elements to determine how many moles of each you have</p> <blockquote> <p><mathjax>#1.28 color(red)(cancel(color(black)("g"))) * "1 mole S"/(32.066color(red)(cancel(color(black)("g")))) = "0.03992 moles S"#</mathjax></p> <p><mathjax>#1.92 color(red)(cancel(color(black)("g"))) * "1 mole O"/(15.9994color(red)(cancel(color(black)("g")))) = "0.1200 moles O"#</mathjax></p> </blockquote> <p>To get the <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> that exists between the two elements, divided both values by the <em>smallest one</em></p> <blockquote> <p><mathjax>#"For S: " (0.03992 color(red)(cancel(color(black)("moles"))))/(0.03992color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> <p><mathjax>#"For O: " (0.1200color(red)(cancel(color(black)("moles"))))/(0.03992color(red)(cancel(color(black)("moles")))) = 3.01 ~~3#</mathjax></p> </blockquote> <p>Since you can't have a <em>smallest whole number ratio</em> between the two elements, it follows that the empirical formula of the compound is</p> <blockquote> <p><mathjax>#"S"_1"O"_3 implies color(green)("SO"_3)#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/201638" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3764 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A sample of sulfur having a mass of #1.28# g combines with oxygen to form a compound with a mass #3.20# g. What is the empirical formula of the compound?

aa142b0c-6ddd-11ea-b3a4-ccda262736ce

https://socratic.org/questions/can-you-write-and-balance-the-equation-for-the-complete-combustion-of-ethane-c-2

2 C2H6 + 7O2 -> 4 CO2 + 6 H2O

start chemical_equation qc_end chemical_equation 13 13 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"2 C2H6 + 7O2 -> 4 CO2 + 6 H2O "}]

[{"type":"chemical equation","value":"C2H6"},{"type":"other","value":"Complete combustion."}]

<h1 class="questionTitle" itemprop="name">Can you write and balance the equation for the complete combustion of ethane, #C_2H_6#?</h1>

2 C2H6 + 7O2 -> 4 CO2 + 6 H2O

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In a combustion reaction with a hydrocarbon in the reactant side you will always have <mathjax>#O_2#</mathjax> as another reactant. As you will always have <mathjax>#CO_2#</mathjax> and <mathjax>#H_2O#</mathjax> as the products.</p> <p>Knowing that much you can set up your reaction equation..</p> <p><mathjax>#C_2H_6 + O_2#</mathjax><mathjax>#-&gt;#</mathjax> <mathjax>#CO_2 + H_2O#</mathjax></p> <p>Now the balancing can begin. Balancing hydrocarbon combustion reactions can be tricky, but if with practice they can be really fun and very rewarding.</p> <p>Start with the <mathjax>#C#</mathjax> atoms first and move to the <mathjax>#H#</mathjax> atoms next. It's easier to leave the <mathjax>#O_2#</mathjax> to the last, it has a way to alter the equation.</p> <p>Initially, you would arrive at this, before the <mathjax>#O_2#</mathjax> has been balanced:</p> <p><mathjax>#C_2H_6 + O_2 -&gt; 2CO_2 + 3H_2O#</mathjax> </p> <p>But, as you can see, you have an odd amount of <mathjax>#O_2#</mathjax> on the product side. In this case, you have to find the common factor of the amount of <mathjax>#O#</mathjax> on the product side and 2, Because of the <mathjax>#O_2#</mathjax> diatom. Therefore, 14 would be the lowest common factor of 2 and 7. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2C_2H_6+7O_2#</mathjax> <mathjax>#-&gt;#</mathjax> <mathjax>#4O_2+6H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In a combustion reaction with a hydrocarbon in the reactant side you will always have <mathjax>#O_2#</mathjax> as another reactant. As you will always have <mathjax>#CO_2#</mathjax> and <mathjax>#H_2O#</mathjax> as the products.</p> <p>Knowing that much you can set up your reaction equation..</p> <p><mathjax>#C_2H_6 + O_2#</mathjax><mathjax>#-&gt;#</mathjax> <mathjax>#CO_2 + H_2O#</mathjax></p> <p>Now the balancing can begin. Balancing hydrocarbon combustion reactions can be tricky, but if with practice they can be really fun and very rewarding.</p> <p>Start with the <mathjax>#C#</mathjax> atoms first and move to the <mathjax>#H#</mathjax> atoms next. It's easier to leave the <mathjax>#O_2#</mathjax> to the last, it has a way to alter the equation.</p> <p>Initially, you would arrive at this, before the <mathjax>#O_2#</mathjax> has been balanced:</p> <p><mathjax>#C_2H_6 + O_2 -&gt; 2CO_2 + 3H_2O#</mathjax> </p> <p>But, as you can see, you have an odd amount of <mathjax>#O_2#</mathjax> on the product side. In this case, you have to find the common factor of the amount of <mathjax>#O#</mathjax> on the product side and 2, Because of the <mathjax>#O_2#</mathjax> diatom. Therefore, 14 would be the lowest common factor of 2 and 7. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Can you write and balance the equation for the complete combustion of ethane, #C_2H_6#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="187555" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/slangus"><img alt="" class="" src="https://profilepictures.socratic.org/drkbgwWiTc2nF7Sd9TrX_1103421756345992.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/slangus"> Slangus </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-12T19:48:55" itemprop="dateCreated"> Nov 12, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2C_2H_6+7O_2#</mathjax> <mathjax>#-&gt;#</mathjax> <mathjax>#4O_2+6H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In a combustion reaction with a hydrocarbon in the reactant side you will always have <mathjax>#O_2#</mathjax> as another reactant. As you will always have <mathjax>#CO_2#</mathjax> and <mathjax>#H_2O#</mathjax> as the products.</p> <p>Knowing that much you can set up your reaction equation..</p> <p><mathjax>#C_2H_6 + O_2#</mathjax><mathjax>#-&gt;#</mathjax> <mathjax>#CO_2 + H_2O#</mathjax></p> <p>Now the balancing can begin. Balancing hydrocarbon combustion reactions can be tricky, but if with practice they can be really fun and very rewarding.</p> <p>Start with the <mathjax>#C#</mathjax> atoms first and move to the <mathjax>#H#</mathjax> atoms next. It's easier to leave the <mathjax>#O_2#</mathjax> to the last, it has a way to alter the equation.</p> <p>Initially, you would arrive at this, before the <mathjax>#O_2#</mathjax> has been balanced:</p> <p><mathjax>#C_2H_6 + O_2 -&gt; 2CO_2 + 3H_2O#</mathjax> </p> <p>But, as you can see, you have an odd amount of <mathjax>#O_2#</mathjax> on the product side. In this case, you have to find the common factor of the amount of <mathjax>#O#</mathjax> on the product side and 2, Because of the <mathjax>#O_2#</mathjax> diatom. Therefore, 14 would be the lowest common factor of 2 and 7. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/187555" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="210870" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-10T19:22:51" itemprop="dateCreated"> Jan 10, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_2H_6(g) + 7/2O_2(g) rarr 2CO_2(g) + 3H_2O(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Any hydrocarbon combusts completely to give carbon dioxide and water. Is it balanced? The oxygen bears a half-coefficient. How could I remove it?</p> <p>Can you represent the combustion of propane and butane with similar reactions?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/210870" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-equation-for-photosynthesis"> What is the chemical equation for photosynthesis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-grams-of-each-substance-used-or-produced-w"> How can I know the relative number of grams of each substance used or produced with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-moles-of-each-substance-with-chemical-equa"> How can I know the relative number of moles of each substance with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-chemical-equations-illustrate-that-atoms-are-conserved-1"> How do chemical equations illustrate that atoms are conserved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-formula-of-the-reactants-and-products-with-chemical-equations"> How can I know the formula of the reactants and products with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-potassium-metal-and-chlorine-gas-combi"> How can I balance this chemical equations? 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Can you write and balance the equation for the complete combustion of ethane, #C_2H_6#?

a8f61adc-6ddd-11ea-b3df-ccda262736ce

https://socratic.org/questions/if-the-balloon-had-a-volume-of-2-l-at-a-depth-of-40-m-what-was-the-original-volu

10 L

start physical_unit 1 2 volume l qc_end physical_unit 1 2 7 8 volume qc_end physical_unit 1 2 13 14 depth qc_end physical_unit 33 33 35 36 pressure qc_end end

[{"type":"physical unit","value":"Volume1 [OF] the balloon [IN] L"}]

[{"type":"physical unit","value":"10 L"}]

[{"type":"physical unit","value":"Volume2 [OF] the balloon [=] \\pu{2 L}"},{"type":"physical unit","value":"Depth [OF] the balloon [=] \\pu{40 m}"},{"type":"physical unit","value":"Pressure at the surface [OF] water [=] \\pu{14.7 psi}"}]

<h1 class="questionTitle" itemprop="name">If the balloon had a volume of 2 L at a depth of 40 m, what was the original volume of the balloon if we assume the pressure at the surface of the water is 14.7 psi?</h1>

10 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The pressure at a depth of 40 m is the hydrostatic pressure of the water plus the <a href="https://socratic.org/chemistry/the-behavior-of-gases/atmospheric-pressure">atmospheric pressure</a>.</p> <p>The hydrostatic pressure <mathjax>#P#</mathjax> of a liquid is given by the formula</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(|color(white)(a/a)P = ρghcolor(white)(a/a)|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#ρ#</mathjax> = the <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of the liquid<br/> <mathjax>#g#</mathjax> = the acceleration due to gravity<br/> <mathjax>#h#</mathjax> = the depth of the liquid</p> <p><mathjax>#P_"water" = "1000 kg"·stackrelcolor(blue)("m"^"-1")(color(red)(cancel(color(black)("m"^"-3"))))× 9.81 color(red)(cancel(color(black)("m")))·"s"^"-2" × 40 color(red)(cancel(color(black)("m"))) = 3.92 × 10^5color(white)(l) "kg·m"^"-1""s"^"-2" = 3.92 × 10^5 color(white)(l)"Pa"#</mathjax></p> <p><mathjax>#P_"water" = 3.92 × 10^5 color(red)(cancel(color(black)("Pa"))) × "1 atm"/(101.325 × 10^3 color(red)(cancel(color(black)("Pa")))) = "3.87 atm"#</mathjax></p> <p><mathjax>#P_"atm" = 14.7 "psi" × "1 atm"/(14.70 "psi") = "1.00 atm"#</mathjax></p> <p>∴ The total pressure at 40 m is</p> <p><mathjax>#P_"tot" = "3.87 atm + 1.00 atm" = "4.87 atm"#</mathjax></p> <blockquote></blockquote> <p>Now we can use <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a></strong> to calculate the volume of the balloon at the surface.</p> <blockquote> <p><mathjax>#color(blue)(bar(ul(|color(white)(a/a) P_1V_1 = P_2V_2color(white)(a/a)|)))" "#</mathjax></p> <blockquote> <p><mathjax>#V_2 = V_1 × P_1/P_2#</mathjax></p> </blockquote> </blockquote> <p>In your problem,</p> <p><mathjax>#P_1 = "4.87 atm"; V_1 = "2 L"#</mathjax><br/> <mathjax>#P_2 = "1.00 atm;"color(white)(l) V_2 = "?"#</mathjax></p> <p>∴ <mathjax>#V_2 = "2 L" × (4.87 color(red)(cancel(color(black)("atm"))))/(1.00 color(red)(cancel(color(black)("atm")))) = "10 L"#</mathjax> (1 significant figure)</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume at the surface is 10 L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The pressure at a depth of 40 m is the hydrostatic pressure of the water plus the <a href="https://socratic.org/chemistry/the-behavior-of-gases/atmospheric-pressure">atmospheric pressure</a>.</p> <p>The hydrostatic pressure <mathjax>#P#</mathjax> of a liquid is given by the formula</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(|color(white)(a/a)P = ρghcolor(white)(a/a)|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#ρ#</mathjax> = the <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of the liquid<br/> <mathjax>#g#</mathjax> = the acceleration due to gravity<br/> <mathjax>#h#</mathjax> = the depth of the liquid</p> <p><mathjax>#P_"water" = "1000 kg"·stackrelcolor(blue)("m"^"-1")(color(red)(cancel(color(black)("m"^"-3"))))× 9.81 color(red)(cancel(color(black)("m")))·"s"^"-2" × 40 color(red)(cancel(color(black)("m"))) = 3.92 × 10^5color(white)(l) "kg·m"^"-1""s"^"-2" = 3.92 × 10^5 color(white)(l)"Pa"#</mathjax></p> <p><mathjax>#P_"water" = 3.92 × 10^5 color(red)(cancel(color(black)("Pa"))) × "1 atm"/(101.325 × 10^3 color(red)(cancel(color(black)("Pa")))) = "3.87 atm"#</mathjax></p> <p><mathjax>#P_"atm" = 14.7 "psi" × "1 atm"/(14.70 "psi") = "1.00 atm"#</mathjax></p> <p>∴ The total pressure at 40 m is</p> <p><mathjax>#P_"tot" = "3.87 atm + 1.00 atm" = "4.87 atm"#</mathjax></p> <blockquote></blockquote> <p>Now we can use <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a></strong> to calculate the volume of the balloon at the surface.</p> <blockquote> <p><mathjax>#color(blue)(bar(ul(|color(white)(a/a) P_1V_1 = P_2V_2color(white)(a/a)|)))" "#</mathjax></p> <blockquote> <p><mathjax>#V_2 = V_1 × P_1/P_2#</mathjax></p> </blockquote> </blockquote> <p>In your problem,</p> <p><mathjax>#P_1 = "4.87 atm"; V_1 = "2 L"#</mathjax><br/> <mathjax>#P_2 = "1.00 atm;"color(white)(l) V_2 = "?"#</mathjax></p> <p>∴ <mathjax>#V_2 = "2 L" × (4.87 color(red)(cancel(color(black)("atm"))))/(1.00 color(red)(cancel(color(black)("atm")))) = "10 L"#</mathjax> (1 significant figure)</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If the balloon had a volume of 2 L at a depth of 40 m, what was the original volume of the balloon if we assume the pressure at the surface of the water is 14.7 psi?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="329415" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-31T23:17:54" itemprop="dateCreated"> Oct 31, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume at the surface is 10 L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The pressure at a depth of 40 m is the hydrostatic pressure of the water plus the <a href="https://socratic.org/chemistry/the-behavior-of-gases/atmospheric-pressure">atmospheric pressure</a>.</p> <p>The hydrostatic pressure <mathjax>#P#</mathjax> of a liquid is given by the formula</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(|color(white)(a/a)P = ρghcolor(white)(a/a)|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#ρ#</mathjax> = the <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of the liquid<br/> <mathjax>#g#</mathjax> = the acceleration due to gravity<br/> <mathjax>#h#</mathjax> = the depth of the liquid</p> <p><mathjax>#P_"water" = "1000 kg"·stackrelcolor(blue)("m"^"-1")(color(red)(cancel(color(black)("m"^"-3"))))× 9.81 color(red)(cancel(color(black)("m")))·"s"^"-2" × 40 color(red)(cancel(color(black)("m"))) = 3.92 × 10^5color(white)(l) "kg·m"^"-1""s"^"-2" = 3.92 × 10^5 color(white)(l)"Pa"#</mathjax></p> <p><mathjax>#P_"water" = 3.92 × 10^5 color(red)(cancel(color(black)("Pa"))) × "1 atm"/(101.325 × 10^3 color(red)(cancel(color(black)("Pa")))) = "3.87 atm"#</mathjax></p> <p><mathjax>#P_"atm" = 14.7 "psi" × "1 atm"/(14.70 "psi") = "1.00 atm"#</mathjax></p> <p>∴ The total pressure at 40 m is</p> <p><mathjax>#P_"tot" = "3.87 atm + 1.00 atm" = "4.87 atm"#</mathjax></p> <blockquote></blockquote> <p>Now we can use <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a></strong> to calculate the volume of the balloon at the surface.</p> <blockquote> <p><mathjax>#color(blue)(bar(ul(|color(white)(a/a) P_1V_1 = P_2V_2color(white)(a/a)|)))" "#</mathjax></p> <blockquote> <p><mathjax>#V_2 = V_1 × P_1/P_2#</mathjax></p> </blockquote> </blockquote> <p>In your problem,</p> <p><mathjax>#P_1 = "4.87 atm"; V_1 = "2 L"#</mathjax><br/> <mathjax>#P_2 = "1.00 atm;"color(white)(l) V_2 = "?"#</mathjax></p> <p>∴ <mathjax>#V_2 = "2 L" × (4.87 color(red)(cancel(color(black)("atm"))))/(1.00 color(red)(cancel(color(black)("atm")))) = "10 L"#</mathjax> (1 significant figure)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/329415" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-gas-pressure-be-changed"> How can gas pressure be changed? 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If the balloon had a volume of 2 L at a depth of 40 m, what was the original volume of the balloon if we assume the pressure at the surface of the water is 14.7 psi?

ac2f076c-6ddd-11ea-864e-ccda262736ce

https://socratic.org/questions/abreathing-mixture-used-by-deep-sea-divers-contains-helium-oxygen-and-carbon-dio

0.20 atm

start physical_unit 10 10 partial_pressure atm qc_end physical_unit 1 2 22 23 total_pressure qc_end end

[{"type":"physical unit","value":"Partial pressure [OF] oxygen [IN] atm"}]

[{"type":"physical unit","value":"0.20 atm"}]

[{"type":"physical unit","value":"Partial pressure [OF] He [=] \\pu{609.5 mmHg}"},{"type":"physical unit","value":"Partial pressure [OF] CO2 [=] \\pu{0.5 mmHg}"},{"type":"physical unit","value":"Total pressure [OF] breathing mixture [=] \\pu{1 atmosphere}"}]

<h1 class="questionTitle" itemprop="name">Abreathing mixture used by deep sea divers contains helium, oxygen, and carbon dioxide. What is the partial pressure of oxygen at 1 atmosphere if P He- 609.5 mm Hg and P #CO_2# = 0.5 mm Hg?</h1>

0.20 atm

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Sigmap_i=1*atm#</mathjax>, where <mathjax>#p_i#</mathjax> are the individual partial pressures. </p> <p>And thus <mathjax>#p_(CO_2)+p_(O_2)+p_(He)=760*mm*Hg#</mathjax></p> <p>And thus, <mathjax>#p_(O_2)={760-p_(CO_2)-p_(He)}*mm*Hg#</mathjax></p> <p><mathjax>#p_(O_2)={760-0.5-609.5}*mm*Hg#</mathjax></p> <p><mathjax>#p_(O_2)=150*mm*Hg#</mathjax></p> <p>And we convert <mathjax>#p_(O_2)#</mathjax> to atmospheres, knowing that <mathjax>#1*atm-=760*mm*Hg#</mathjax>.</p> <p><mathjax>#p_(O_2)=(150*mm*Hg)/(760*mm*Hg*atm^-1)=??atm#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The sum of the <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> are <mathjax>#1*atm#</mathjax></p> <p><mathjax>#p_(O_2)~=0.20*atm#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Sigmap_i=1*atm#</mathjax>, where <mathjax>#p_i#</mathjax> are the individual partial pressures. </p> <p>And thus <mathjax>#p_(CO_2)+p_(O_2)+p_(He)=760*mm*Hg#</mathjax></p> <p>And thus, <mathjax>#p_(O_2)={760-p_(CO_2)-p_(He)}*mm*Hg#</mathjax></p> <p><mathjax>#p_(O_2)={760-0.5-609.5}*mm*Hg#</mathjax></p> <p><mathjax>#p_(O_2)=150*mm*Hg#</mathjax></p> <p>And we convert <mathjax>#p_(O_2)#</mathjax> to atmospheres, knowing that <mathjax>#1*atm-=760*mm*Hg#</mathjax>.</p> <p><mathjax>#p_(O_2)=(150*mm*Hg)/(760*mm*Hg*atm^-1)=??atm#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Abreathing mixture used by deep sea divers contains helium, oxygen, and carbon dioxide. What is the partial pressure of oxygen at 1 atmosphere if P He- 609.5 mm Hg and P #CO_2# = 0.5 mm Hg?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/partial-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Partial Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="363481" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-12T10:12:59" itemprop="dateCreated"> Jan 12, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The sum of the <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> are <mathjax>#1*atm#</mathjax></p> <p><mathjax>#p_(O_2)~=0.20*atm#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Sigmap_i=1*atm#</mathjax>, where <mathjax>#p_i#</mathjax> are the individual partial pressures. </p> <p>And thus <mathjax>#p_(CO_2)+p_(O_2)+p_(He)=760*mm*Hg#</mathjax></p> <p>And thus, <mathjax>#p_(O_2)={760-p_(CO_2)-p_(He)}*mm*Hg#</mathjax></p> <p><mathjax>#p_(O_2)={760-0.5-609.5}*mm*Hg#</mathjax></p> <p><mathjax>#p_(O_2)=150*mm*Hg#</mathjax></p> <p>And we convert <mathjax>#p_(O_2)#</mathjax> to atmospheres, knowing that <mathjax>#1*atm-=760*mm*Hg#</mathjax>.</p> <p><mathjax>#p_(O_2)=(150*mm*Hg)/(760*mm*Hg*atm^-1)=??atm#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/363481" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534e256802bf342adfa30010"> How do you do a steam distillation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/53613f9f02bf3416cd9f8a34"> Question #f8a34 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-i-calculate-the-total-pressure-of-a-mixture-of-gases-by-adding-together-the-"> Can I calculate the total pressure of a mixture of gases by adding together the partial... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-formula-of-partial-pressure"> What is the formula of partial pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-dalton-s-law-of-partial-pressures"> What is the Dalton's law of partial pressures? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/nitrogen-gas-n2-reacts-with-hydrogen-gas-h2-to-form-ammonia-nh3-at-200-c-in-a-cl"> Nitrogen gas (N2) reacts with hydrogen gas (H2) to form ammonia (NH3). 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Abreathing mixture used by deep sea divers contains helium, oxygen, and carbon dioxide. What is the partial pressure of oxygen at 1 atmosphere if P He- 609.5 mm Hg and P #CO_2# = 0.5 mm Hg?

ab437ea0-6ddd-11ea-ade5-ccda262736ce

https://socratic.org/questions/a-12-0-l-sample-of-argon-gas-has-a-pressure-of-28-0-atm-what-volume-would-this-g

34.64 L

start physical_unit 16 17 volume l qc_end physical_unit 3 6 1 2 volume qc_end physical_unit 3 6 11 12 pressure qc_end physical_unit 16 17 20 21 pressure qc_end end

[{"type":"physical unit","value":"Volume2 [OF] this gas [IN] L"}]

[{"type":"physical unit","value":"34.64 L"}]

[{"type":"physical unit","value":"Volume1 [OF] argon gas sample [=] \\pu{12.0 L}"},{"type":"physical unit","value":"Pressure1 [OF] argon gas sample [=] \\pu{28.0 atm}"},{"type":"physical unit","value":"Pressure2 [OF] argon gas sample [=] \\pu{9.70 atm}"}]

<h1 class="questionTitle" itemprop="name">A 12.0 L sample of argon gas has a pressure of 28.0 atm. What volume would this gas occupy at 9.70 atm? </h1>

34.64 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's start off with identifying our known and unknown variables. <br/> The first volume we have is 12.0 L, the first pressure is 28.0 atm, and the second pressure is 9.70 atm. Our only unknown is the second volume.</p> <p>We can obtain the answer using <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a> which shows that there is an inverse relationship between pressure and volume as long as the temperature and number of moles remain constant.</p> <p>The equation we use is <mathjax>#P_1V_1=P_2V_2#</mathjax><br/> where the numbers 1 and 2 represent the first and second conditions. All we have to do is rearrange the equation to solve for the volume. </p> <p>We do this by dividing both sides by <mathjax>#P_2#</mathjax> in order to get <mathjax>#V_2#</mathjax> by itself like so:<br/> <mathjax>#P_1V_1#</mathjax> <mathjax>#-:#</mathjax><mathjax>#P_2#</mathjax> = <mathjax>#V_2#</mathjax> </p> <p>Now all we do is plug and chug!<br/> (28.0 <mathjax>#cancel (atm#</mathjax>)) (12.0 L) <mathjax>#-:#</mathjax> (9.70 <mathjax>#cancel (atm#</mathjax>)) = 34.6 L </p> <p><a href="http://www.chemteam.info/GasLaw/Gas-Boyle.html" rel="nofollow">Boyle's Law Practice Problems </a> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume that this gas occupies is <mathjax>#34.6 L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's start off with identifying our known and unknown variables. <br/> The first volume we have is 12.0 L, the first pressure is 28.0 atm, and the second pressure is 9.70 atm. Our only unknown is the second volume.</p> <p>We can obtain the answer using <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a> which shows that there is an inverse relationship between pressure and volume as long as the temperature and number of moles remain constant.</p> <p>The equation we use is <mathjax>#P_1V_1=P_2V_2#</mathjax><br/> where the numbers 1 and 2 represent the first and second conditions. All we have to do is rearrange the equation to solve for the volume. </p> <p>We do this by dividing both sides by <mathjax>#P_2#</mathjax> in order to get <mathjax>#V_2#</mathjax> by itself like so:<br/> <mathjax>#P_1V_1#</mathjax> <mathjax>#-:#</mathjax><mathjax>#P_2#</mathjax> = <mathjax>#V_2#</mathjax> </p> <p>Now all we do is plug and chug!<br/> (28.0 <mathjax>#cancel (atm#</mathjax>)) (12.0 L) <mathjax>#-:#</mathjax> (9.70 <mathjax>#cancel (atm#</mathjax>)) = 34.6 L </p> <p><a href="http://www.chemteam.info/GasLaw/Gas-Boyle.html" rel="nofollow">Boyle's Law Practice Problems </a> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A 12.0 L sample of argon gas has a pressure of 28.0 atm. What volume would this gas occupy at 9.70 atm? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/boyle-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Boyle's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="274526" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-06T04:59:10" itemprop="dateCreated"> Jun 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume that this gas occupies is <mathjax>#34.6 L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's start off with identifying our known and unknown variables. <br/> The first volume we have is 12.0 L, the first pressure is 28.0 atm, and the second pressure is 9.70 atm. Our only unknown is the second volume.</p> <p>We can obtain the answer using <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a> which shows that there is an inverse relationship between pressure and volume as long as the temperature and number of moles remain constant.</p> <p>The equation we use is <mathjax>#P_1V_1=P_2V_2#</mathjax><br/> where the numbers 1 and 2 represent the first and second conditions. All we have to do is rearrange the equation to solve for the volume. </p> <p>We do this by dividing both sides by <mathjax>#P_2#</mathjax> in order to get <mathjax>#V_2#</mathjax> by itself like so:<br/> <mathjax>#P_1V_1#</mathjax> <mathjax>#-:#</mathjax><mathjax>#P_2#</mathjax> = <mathjax>#V_2#</mathjax> </p> <p>Now all we do is plug and chug!<br/> (28.0 <mathjax>#cancel (atm#</mathjax>)) (12.0 L) <mathjax>#-:#</mathjax> (9.70 <mathjax>#cancel (atm#</mathjax>)) = 34.6 L </p> <p><a href="http://www.chemteam.info/GasLaw/Gas-Boyle.html" rel="nofollow">Boyle's Law Practice Problems </a> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/274526" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="274527" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/sam-54"><img alt="" class="" src="https://profilepictures.socratic.org/3bkyAGe2RVWw1lx2h1A5_Avatar%201.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/sam-54"> Sam </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-06T05:04:28" itemprop="dateCreated"> Jun 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V_2-=34.6 L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the combined gas low equation.</p> <p><mathjax>#(P_1xxV_1)/T_1=(P_2xxV_2)/T_2#</mathjax></p> <p><mathjax>#T_1=T_2#</mathjax> since the temperature remains constant.</p> <p><mathjax>#P_1xxV_1=P_2xxV_2#</mathjax></p> <p><mathjax>#V_2=(P_1xxV_1)/P_2#</mathjax></p> <p><mathjax>#V_2=(28.0\ atm xx 12.0\ L)/(9.70\ atm)#</mathjax></p> <p><mathjax>#V_2-=34.6 L#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/274527" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-graph-boyles-law"> How do you graph Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-functional-groups-are-found-in-lipids"> What functional groups are found in lipids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-k-constant-in-boyle-s-law"> Why is k constant in Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-graph-curved-1"> Why is Boyle's law graph curved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-an-inverse-relationship-2"> Why is Boyle's law an inverse relationship? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-40-0-l-tank-of-ammonia-has-a-pressure-of-8-00-atm-calculate-the-volume-of-the-"> A 40.0 L tank of ammonia has a pressure of 8.00 atm. 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A 12.0 L sample of argon gas has a pressure of 28.0 atm. What volume would this gas occupy at 9.70 atm?

aabae802-6ddd-11ea-9a80-ccda262736ce

https://socratic.org/questions/what-is-the-oxidation-number-of-kmno-4

+7

start physical_unit 6 6 oxidation_number none qc_end chemical_equation 8 8 qc_end end

[{"type":"physical unit","value":"Oxidation number [OF] Mn"}]

[{"type":"physical unit","value":"+7"}]

[{"type":"chemical equation","value":"KMnO4"}]

<h1 class="questionTitle" itemprop="name">What is the oxidation number of #"Mn"# in #"KMnO"_4#? </h1>

+7

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>We assign the oxidation number per a set of rules.</p> <p>For this question, the important rules are:</p> <ol> <li> <p>The oxidation number of <mathjax>#"O"#</mathjax> in <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> is usually -2, but it is -1 in peroxides.</p> </li> <li> <p>The oxidation number of a Group 1 element in a compound is +1.</p> </li> <li> <p>The sum of the <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> of all of the atoms in a neutral compound is 0.</p> </li> </ol> <blockquote></blockquote> <p><strong>Rule 1</strong> states that the oxidation number of <mathjax>#"O"#</mathjax> is -2.</p> <p>We write the oxidation number of the element above its symbol and the total for 3 <mathjax>#"O"#</mathjax> atoms below the symbol.</p> <p>This gives <mathjax>#"KMn"stackrelcolor(blue)("-2")("O")_4#</mathjax><br/> <mathjax>#color(white)(mmmmmmmll)stackrelcolor(blue)("-8"color(white)(mm))#</mathjax></p> <blockquote></blockquote> <p><strong>Rule 2</strong> states that the oxidation number of K is +1.</p> <p>This gives <mathjax>#stackrelcolor(blue)("+1")("K")"Mn"stackrelcolor(blue)("-2")("O")_4#</mathjax><br/> <mathjax>#color(white)(mmll)stackrelcolor(blue)("+1")color(white)(mmmmm)stackrelcolor(blue)("-8")color(white)(ml)#</mathjax></p> <blockquote></blockquote> <p><strong>Rule 3</strong> states the numbers along the bottom must add up to zero.</p> <p>The number under <mathjax>#"Mn"#</mathjax> must be +7.</p> <p>This gives <mathjax>#stackrelcolor(blue)("+1")("K")"Mn"stackrelcolor(blue)("-2")("O")_4#</mathjax><br/> <mathjax>#color(white)(mmmml)stackrelcolor(blue)("+1")color(white)(mm)stackrelcolor(blue)("+7")(color(white)(ll))stackrelcolor(blue)("-8")color(white)(ml)#</mathjax></p> <p>There is only one <mathjax>#"Mn"#</mathjax> atom, so its oxidation number is +7.</p> <p>This gives <mathjax>#stackrelcolor(blue)("+1")("K")stackrelcolor(blue)("+7")"Mn"stackrelcolor(blue)("-2")("O")_4#</mathjax><br/> <mathjax>#color(white)(mmmml)stackrelcolor(blue)("+1")color(white)(mm)stackrelcolor(blue)("+7")(color(white)(ll))stackrelcolor(blue)("-8")color(white)(ml)#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The oxidation number of <mathjax>#"Mn"#</mathjax> is +7.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>We assign the oxidation number per a set of rules.</p> <p>For this question, the important rules are:</p> <ol> <li> <p>The oxidation number of <mathjax>#"O"#</mathjax> in <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> is usually -2, but it is -1 in peroxides.</p> </li> <li> <p>The oxidation number of a Group 1 element in a compound is +1.</p> </li> <li> <p>The sum of the <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> of all of the atoms in a neutral compound is 0.</p> </li> </ol> <blockquote></blockquote> <p><strong>Rule 1</strong> states that the oxidation number of <mathjax>#"O"#</mathjax> is -2.</p> <p>We write the oxidation number of the element above its symbol and the total for 3 <mathjax>#"O"#</mathjax> atoms below the symbol.</p> <p>This gives <mathjax>#"KMn"stackrelcolor(blue)("-2")("O")_4#</mathjax><br/> <mathjax>#color(white)(mmmmmmmll)stackrelcolor(blue)("-8"color(white)(mm))#</mathjax></p> <blockquote></blockquote> <p><strong>Rule 2</strong> states that the oxidation number of K is +1.</p> <p>This gives <mathjax>#stackrelcolor(blue)("+1")("K")"Mn"stackrelcolor(blue)("-2")("O")_4#</mathjax><br/> <mathjax>#color(white)(mmll)stackrelcolor(blue)("+1")color(white)(mmmmm)stackrelcolor(blue)("-8")color(white)(ml)#</mathjax></p> <blockquote></blockquote> <p><strong>Rule 3</strong> states the numbers along the bottom must add up to zero.</p> <p>The number under <mathjax>#"Mn"#</mathjax> must be +7.</p> <p>This gives <mathjax>#stackrelcolor(blue)("+1")("K")"Mn"stackrelcolor(blue)("-2")("O")_4#</mathjax><br/> <mathjax>#color(white)(mmmml)stackrelcolor(blue)("+1")color(white)(mm)stackrelcolor(blue)("+7")(color(white)(ll))stackrelcolor(blue)("-8")color(white)(ml)#</mathjax></p> <p>There is only one <mathjax>#"Mn"#</mathjax> atom, so its oxidation number is +7.</p> <p>This gives <mathjax>#stackrelcolor(blue)("+1")("K")stackrelcolor(blue)("+7")"Mn"stackrelcolor(blue)("-2")("O")_4#</mathjax><br/> <mathjax>#color(white)(mmmml)stackrelcolor(blue)("+1")color(white)(mm)stackrelcolor(blue)("+7")(color(white)(ll))stackrelcolor(blue)("-8")color(white)(ml)#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the oxidation number of #"Mn"# in #"KMnO"_4#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-numbers" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation Numbers</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="364818" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-15T17:40:45" itemprop="dateCreated"> Jan 15, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The oxidation number of <mathjax>#"Mn"#</mathjax> is +7.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>We assign the oxidation number per a set of rules.</p> <p>For this question, the important rules are:</p> <ol> <li> <p>The oxidation number of <mathjax>#"O"#</mathjax> in <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> is usually -2, but it is -1 in peroxides.</p> </li> <li> <p>The oxidation number of a Group 1 element in a compound is +1.</p> </li> <li> <p>The sum of the <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> of all of the atoms in a neutral compound is 0.</p> </li> </ol> <blockquote></blockquote> <p><strong>Rule 1</strong> states that the oxidation number of <mathjax>#"O"#</mathjax> is -2.</p> <p>We write the oxidation number of the element above its symbol and the total for 3 <mathjax>#"O"#</mathjax> atoms below the symbol.</p> <p>This gives <mathjax>#"KMn"stackrelcolor(blue)("-2")("O")_4#</mathjax><br/> <mathjax>#color(white)(mmmmmmmll)stackrelcolor(blue)("-8"color(white)(mm))#</mathjax></p> <blockquote></blockquote> <p><strong>Rule 2</strong> states that the oxidation number of K is +1.</p> <p>This gives <mathjax>#stackrelcolor(blue)("+1")("K")"Mn"stackrelcolor(blue)("-2")("O")_4#</mathjax><br/> <mathjax>#color(white)(mmll)stackrelcolor(blue)("+1")color(white)(mmmmm)stackrelcolor(blue)("-8")color(white)(ml)#</mathjax></p> <blockquote></blockquote> <p><strong>Rule 3</strong> states the numbers along the bottom must add up to zero.</p> <p>The number under <mathjax>#"Mn"#</mathjax> must be +7.</p> <p>This gives <mathjax>#stackrelcolor(blue)("+1")("K")"Mn"stackrelcolor(blue)("-2")("O")_4#</mathjax><br/> <mathjax>#color(white)(mmmml)stackrelcolor(blue)("+1")color(white)(mm)stackrelcolor(blue)("+7")(color(white)(ll))stackrelcolor(blue)("-8")color(white)(ml)#</mathjax></p> <p>There is only one <mathjax>#"Mn"#</mathjax> atom, so its oxidation number is +7.</p> <p>This gives <mathjax>#stackrelcolor(blue)("+1")("K")stackrelcolor(blue)("+7")"Mn"stackrelcolor(blue)("-2")("O")_4#</mathjax><br/> <mathjax>#color(white)(mmmml)stackrelcolor(blue)("+1")color(white)(mm)stackrelcolor(blue)("+7")(color(white)(ll))stackrelcolor(blue)("-8")color(white)(ml)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/364818" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="366659" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-19T18:35:13" itemprop="dateCreated"> Jan 19, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The metal has a <mathjax>#+VII#</mathjax> oxidation state in <mathjax>#MnO_4^-#</mathjax>, <mathjax>#"permanganate ion"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>See <a href="https://socratic.org/questions/how-do-you-write-oxidation-reduction-half-reactions#278689">this link</a> for more of the same. Remember that oxidation number is a factitious entity, however, it does help us to balance <a href="https://socratic.org/chemistry/chemical-reactions/redox-reactions">redox reactions</a>. </p> <p><a href="https://socratic.org/questions/how-do-you-find-the-oxidation-number-of-the-central-atom">And also here.</a> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/366659" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-electron-configuration"> How do oxidation numbers relate to electron configuration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-valence-electrons"> How do oxidation numbers relate to valence electrons? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-vary-with-the-periodic-table"> How do oxidation numbers vary with the periodic table? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-oxidation-number-of-an-element-in-a-compound"> How do you calculate the oxidation number of an element in a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-sulfur"> What is the oxidation number for sulfur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-carbon"> What is the oxidation number for carbon? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-copper"> What is the oxidation number for copper? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-nitrogen"> What is the oxidation number for nitrogen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-oxygen"> What is the oxidation number for oxygen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-state-of-noble-gas-zero"> Why is the oxidation state of noble gas zero? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-numbers"> See all questions in Oxidation Numbers </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11610 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the oxidation number of #"Mn"# in #"KMnO"_4#?

a9a1b1da-6ddd-11ea-899d-ccda262736ce

https://socratic.org/questions/hydrogen-is-collected-over-water-at-19c-and-785-mmhg-of-pressure-the-total-volum

1.84 L

start physical_unit 0 0 volume l qc_end physical_unit 0 0 6 7 temperature qc_end physical_unit 0 0 9 10 pressure qc_end physical_unit 0 0 20 21 volume qc_end c_other STP qc_end end

[{"type":"physical unit","value":"Volume2 [OF] hydrogen [IN] L"}]

[{"type":"physical unit","value":"1.84 L"}]

[{"type":"physical unit","value":"Temperature1 [OF] hydrogen [=] \\pu{19 ℃}"},{"type":"physical unit","value":"Pressure1 [OF] hydrogen [=] \\pu{785 mmHg}"},{"type":"physical unit","value":"Volume1 [OF] hydrogen sample [=] \\pu{1.93 L}"},{"type":"other","value":"STP"}]

<h1 class="questionTitle" itemprop="name">Hydrogen is collected over water at 19C and 785 mmHg of pressure. THe total volume of the sample was 1.93L How do you calculate the volume of hydrogen at STP? </h1>

1.84 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This is an example of a <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">Combined Gas Laws</a> problem.</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(|bar(ul((P_1V_1)/T_1 = (P_2V_2)/T_2|)#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange this formula to get</p> <blockquote> <blockquote> <p><mathjax>#V_2 = V_1 × P_1/P_2 × T_2/T_1#</mathjax></p> </blockquote> </blockquote> <p>The vapour pressure of water at 19 °C = 16.5 mmHg.</p> <p>∴ The pressure of the dry hydrogen is given by</p> <p><mathjax>#P_"H₂" = P_"atm" -P_"H₂O" = "785 mmHg" - "16.5 mmHg" = 768.5 color(red)(cancel(color(black)("mmHg"))) × "1 atm"/(760 color(red)(cancel(color(black)("mmHg")))) = "1.011 atm"#</mathjax></p> <blockquote></blockquote> <p>Your data are then:</p> <p><mathjax>#P_1 = "1.011 atm"; V_1 = "1.93 L"; T_1 = "(19 + 273.15) K" ="292.15 K"#</mathjax></p> <p><mathjax>#P_2 = 1 color(red)(cancel(color(black)("bar"))) × "1 atm"/(1.013 color(red)(cancel(color(black)("bar")))) = "0.9872 atm"; V_2 = "?"; T_2 = "273.15 K"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#V_2 = V_1 × P_1/P_2 × T_2/T_1 = "1.93 L" × (1.011 color(red)(cancel(color(black)("atm"))))/(0.9872 color(red)(cancel(color(black)("atm")))) × (273.15 color(red)(cancel(color(black)("K"))))/(293.15 color(red)(cancel(color(black)("K")))) = "1.84 L"#</mathjax></p> <p>The volume is 1.84 L.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of hydrogen is 1.84 L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This is an example of a <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">Combined Gas Laws</a> problem.</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(|bar(ul((P_1V_1)/T_1 = (P_2V_2)/T_2|)#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange this formula to get</p> <blockquote> <blockquote> <p><mathjax>#V_2 = V_1 × P_1/P_2 × T_2/T_1#</mathjax></p> </blockquote> </blockquote> <p>The vapour pressure of water at 19 °C = 16.5 mmHg.</p> <p>∴ The pressure of the dry hydrogen is given by</p> <p><mathjax>#P_"H₂" = P_"atm" -P_"H₂O" = "785 mmHg" - "16.5 mmHg" = 768.5 color(red)(cancel(color(black)("mmHg"))) × "1 atm"/(760 color(red)(cancel(color(black)("mmHg")))) = "1.011 atm"#</mathjax></p> <blockquote></blockquote> <p>Your data are then:</p> <p><mathjax>#P_1 = "1.011 atm"; V_1 = "1.93 L"; T_1 = "(19 + 273.15) K" ="292.15 K"#</mathjax></p> <p><mathjax>#P_2 = 1 color(red)(cancel(color(black)("bar"))) × "1 atm"/(1.013 color(red)(cancel(color(black)("bar")))) = "0.9872 atm"; V_2 = "?"; T_2 = "273.15 K"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#V_2 = V_1 × P_1/P_2 × T_2/T_1 = "1.93 L" × (1.011 color(red)(cancel(color(black)("atm"))))/(0.9872 color(red)(cancel(color(black)("atm")))) × (273.15 color(red)(cancel(color(black)("K"))))/(293.15 color(red)(cancel(color(black)("K")))) = "1.84 L"#</mathjax></p> <p>The volume is 1.84 L.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Hydrogen is collected over water at 19C and 785 mmHg of pressure. THe total volume of the sample was 1.93L How do you calculate the volume of hydrogen at STP? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="272585" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-01T15:24:41" itemprop="dateCreated"> Jun 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of hydrogen is 1.84 L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This is an example of a <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">Combined Gas Laws</a> problem.</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(|bar(ul((P_1V_1)/T_1 = (P_2V_2)/T_2|)#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange this formula to get</p> <blockquote> <blockquote> <p><mathjax>#V_2 = V_1 × P_1/P_2 × T_2/T_1#</mathjax></p> </blockquote> </blockquote> <p>The vapour pressure of water at 19 °C = 16.5 mmHg.</p> <p>∴ The pressure of the dry hydrogen is given by</p> <p><mathjax>#P_"H₂" = P_"atm" -P_"H₂O" = "785 mmHg" - "16.5 mmHg" = 768.5 color(red)(cancel(color(black)("mmHg"))) × "1 atm"/(760 color(red)(cancel(color(black)("mmHg")))) = "1.011 atm"#</mathjax></p> <blockquote></blockquote> <p>Your data are then:</p> <p><mathjax>#P_1 = "1.011 atm"; V_1 = "1.93 L"; T_1 = "(19 + 273.15) K" ="292.15 K"#</mathjax></p> <p><mathjax>#P_2 = 1 color(red)(cancel(color(black)("bar"))) × "1 atm"/(1.013 color(red)(cancel(color(black)("bar")))) = "0.9872 atm"; V_2 = "?"; T_2 = "273.15 K"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#V_2 = V_1 × P_1/P_2 × T_2/T_1 = "1.93 L" × (1.011 color(red)(cancel(color(black)("atm"))))/(0.9872 color(red)(cancel(color(black)("atm")))) × (273.15 color(red)(cancel(color(black)("K"))))/(293.15 color(red)(cancel(color(black)("K")))) = "1.84 L"#</mathjax></p> <p>The volume is 1.84 L.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/272585" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? 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Hydrogen is collected over water at 19C and 785 mmHg of pressure. THe total volume of the sample was 1.93L How do you calculate the volume of hydrogen at STP?

ad0ef3e7-6ddd-11ea-ae7c-ccda262736ce

https://socratic.org/questions/591c615611ef6b3d7e7d2fee

7500.00 L

start physical_unit 3 5 volume l qc_end physical_unit 18 18 14 15 volume qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Volume [OF] carbon dioxide gas [IN] L"}]

[{"type":"physical unit","value":"7500.00 L"}]

[{"type":"physical unit","value":"Volume [OF] propane [=] \\pu{2500 L}"},{"type":"other","value":"Complete combustion."}]

<h1 class="questionTitle" itemprop="name">What volume of carbon dioxide gas will result from the complete combustion of a #2500*L# volume of propane?</h1>

7500.00 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You gots your equation:</p> <p><mathjax>#C_3H_8(g) + 5O_2(g) rarr 3CO_2(g) + 4H_2O(l)#</mathjax></p> <p>And CLEARY this is stoichiometrically balanced. Garbage in equals garbage out.</p> <p>Now there are 3 moles of product gas per mol of propane reactant. And since <mathjax>#"volume"#</mathjax> of gas is proportional to the number of moles (pressure and temperature constant! which conditions we may reasonably assume), <mathjax>#"THERE MUST BE THREE VOLUMES"#</mathjax> of <mathjax>#CO_2(g)#</mathjax> <mathjax>#"PER VOLUME"#</mathjax> of <mathjax>#C_3H_8(g)#</mathjax>.</p> <p>SInce we combusted <mathjax>#2500*L#</mathjax> <mathjax>#"propane"#</mathjax> there are thus <mathjax>#3xx2500*L=7500*L#</mathjax> carbon dioxide evolved. That is the stoichiometric coefficients of the balanced chemical equation give you the ratios of the volumes. </p> <p>You should be able to tell me the volume of dioxygen gas reacted pdq. </p> <p>Good luck in your final. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#7500*L#</mathjax> of <mathjax>#CO_2#</mathjax> are evolved.....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You gots your equation:</p> <p><mathjax>#C_3H_8(g) + 5O_2(g) rarr 3CO_2(g) + 4H_2O(l)#</mathjax></p> <p>And CLEARY this is stoichiometrically balanced. Garbage in equals garbage out.</p> <p>Now there are 3 moles of product gas per mol of propane reactant. And since <mathjax>#"volume"#</mathjax> of gas is proportional to the number of moles (pressure and temperature constant! which conditions we may reasonably assume), <mathjax>#"THERE MUST BE THREE VOLUMES"#</mathjax> of <mathjax>#CO_2(g)#</mathjax> <mathjax>#"PER VOLUME"#</mathjax> of <mathjax>#C_3H_8(g)#</mathjax>.</p> <p>SInce we combusted <mathjax>#2500*L#</mathjax> <mathjax>#"propane"#</mathjax> there are thus <mathjax>#3xx2500*L=7500*L#</mathjax> carbon dioxide evolved. That is the stoichiometric coefficients of the balanced chemical equation give you the ratios of the volumes. </p> <p>You should be able to tell me the volume of dioxygen gas reacted pdq. </p> <p>Good luck in your final. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What volume of carbon dioxide gas will result from the complete combustion of a #2500*L# volume of propane?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="424992" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-17T15:19:12" itemprop="dateCreated"> May 17, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#7500*L#</mathjax> of <mathjax>#CO_2#</mathjax> are evolved.....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You gots your equation:</p> <p><mathjax>#C_3H_8(g) + 5O_2(g) rarr 3CO_2(g) + 4H_2O(l)#</mathjax></p> <p>And CLEARY this is stoichiometrically balanced. Garbage in equals garbage out.</p> <p>Now there are 3 moles of product gas per mol of propane reactant. And since <mathjax>#"volume"#</mathjax> of gas is proportional to the number of moles (pressure and temperature constant! which conditions we may reasonably assume), <mathjax>#"THERE MUST BE THREE VOLUMES"#</mathjax> of <mathjax>#CO_2(g)#</mathjax> <mathjax>#"PER VOLUME"#</mathjax> of <mathjax>#C_3H_8(g)#</mathjax>.</p> <p>SInce we combusted <mathjax>#2500*L#</mathjax> <mathjax>#"propane"#</mathjax> there are thus <mathjax>#3xx2500*L=7500*L#</mathjax> carbon dioxide evolved. That is the stoichiometric coefficients of the balanced chemical equation give you the ratios of the volumes. </p> <p>You should be able to tell me the volume of dioxygen gas reacted pdq. </p> <p>Good luck in your final. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/424992" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-apply-gas-stoichiometry"> How do you apply gas stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-a-gas-law-stoichiometry-problem"> How do you solve a gas law stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-gas-stoichiometry-problems-at-stp"> How do you do gas stoichiometry problems at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-an-agno3-solution-is-treated-with-50-0-ml-of-hi-gas-to-give-0-235-g-of-agi-"> When an AgNO3 solution is treated with 50.0 mL of HI gas to give 0.235 g of AgI, what is the... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-10-0-ml-of-agno3-solution-is-treated-with-excess-amount-of-hi-gas-to-give-0"> When 10.0 mL of AgNO3 solution is treated with excess amount of HI gas to give 0.235 g of AgI,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/hydrogen-sulfide-reacts-with-sulfur-dioxide-to-give-h2o-and-s-h2s-so2-h2o-s-soli"> Hydrogen sulfide reacts with sulfur dioxide to give H2O and S, H2S + SO2 = H2O + S(solid),... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-200-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 200 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 100 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolve-in-20-ml-of-pure-water-what-i"> If 100 mL of HCl gas at 300 K and 100 kPa dissolve in 20 mL of pure water, what is the concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-2-00-g-mixture-of-na-and-ca-reat-with-water-1-164-l-hydrogen-was-produced-a"> When 2.00 g mixture of Na and Ca reat with water, 1.164 L hydrogen was produced at 300.0 K and... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases"> See all questions in Gas Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5107 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What volume of carbon dioxide gas will result from the complete combustion of a #2500*L# volume of propane?

acb29726-6ddd-11ea-9c93-ccda262736ce

https://socratic.org/questions/what-volume-of-a-0-855-m-koh-solution-is-required-to-make-a-3-55-l-solution-at-a

104.21 mL

start physical_unit 6 7 volume ml qc_end physical_unit 6 7 4 5 molarity qc_end physical_unit 6 7 13 14 volume qc_end physical_unit 6 7 20 20 ph qc_end end

[{"type":"physical unit","value":"Volume1 [OF] KOH solution [IN] mL"}]

[{"type":"physical unit","value":"104.21 mL"}]

[{"type":"physical unit","value":"Molarity1 [OF] KOH solution [=] \\pu{0.855 M}"},{"type":"physical unit","value":"Volume2 [OF] KOH solution [=] \\pu{3.55 L}"},{"type":"physical unit","value":"pH2 [OF] KOH solution [=] \\pu{12.4}"}]

<h1 class="questionTitle" itemprop="name">What volume of a 0.855 M KOH solution is required to make a 3.55 L solution at a pH of 12.4?</h1>

104.21 mL

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by using the <mathjax>#"pOH"#</mathjax> of the solution to figure out the concentration of hydroxide anions, <mathjax>#"OH"^(-)#</mathjax>. You should know that</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("pOH" = - log(["OH"^(-)]))))#</mathjax></p> </blockquote> <p>To solve for the concentration of hydroxide anions, rearrange the equation as </p> <blockquote> <p><mathjax>#log(["OH"^(-)]) = - "pOH"#</mathjax></p> </blockquote> <p>This can be written as </p> <blockquote> <p><mathjax>#10^log(["OH"^(-)]) = 10^(-"pOH")#</mathjax></p> </blockquote> <p>which is equivalent to </p> <blockquote> <p><mathjax>#["OH"^(-)] = 10^(-"pOH")#</mathjax></p> </blockquote> <p>Now, an aqueous solution at room temperature has</p> <blockquote> <p><mathjax>#color(red)(ul(color(black)("pH " + " pOH" = 14)))#</mathjax></p> </blockquote> <p>This means that the <mathjax>#"pOH"#</mathjax> of the target solution is equal to </p> <blockquote> <p><mathjax>#"pOH" = 14 -12.4 = 1.6#</mathjax></p> </blockquote> <p>Consequently, the target solution must have</p> <blockquote> <p><mathjax>#["OH"^(-)] = 10^(-1.6) = 2.51 * 10^(-2)"M"#</mathjax></p> </blockquote> <p>As you know, <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> is defined as the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present in <mathjax>#"1 L"#</mathjax> of solution. This means that the <strong>number of moles</strong> of potassium hydroxide needed to ensure that concentration of hydroxide anions is equal to</p> <blockquote> <p><mathjax>#3.55 color(red)(cancel(color(black)("L solution"))) * (2.51 * 10^(-2)"moles OH"^(-))/(1color(red)(cancel(color(black)("L solution")))) = 8.91 * 10^(-2)"moles OH"^(-)#</mathjax></p> </blockquote> <p>All you have to do now is figure out what volume of the stock solution contains the needed number of moles of hydroxide anions</p> <blockquote> <p><mathjax>#8.91 * 10^(-2) color(red)(cancel(color(black)("moles OH"^(-)))) * "1 L solution"/(0.855color(red)(cancel(color(black)("moles OH"^(-))))) = "0.104 L"#</mathjax></p> </blockquote> <p>Expressed in <em>milliliters</em>, the answer will be </p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)(V_"stock KOH" = "104 mL")))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p> <p>So, in order to prepare this solution, take <mathjax>#"104 mL"#</mathjax> of <mathjax>#"0.855 M"#</mathjax> stock potassium hydroxide solution and add <em>enough water</em> until the final volume of the solution is equal to <mathjax>#"3.55 L"#</mathjax>. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"104 mL"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by using the <mathjax>#"pOH"#</mathjax> of the solution to figure out the concentration of hydroxide anions, <mathjax>#"OH"^(-)#</mathjax>. You should know that</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("pOH" = - log(["OH"^(-)]))))#</mathjax></p> </blockquote> <p>To solve for the concentration of hydroxide anions, rearrange the equation as </p> <blockquote> <p><mathjax>#log(["OH"^(-)]) = - "pOH"#</mathjax></p> </blockquote> <p>This can be written as </p> <blockquote> <p><mathjax>#10^log(["OH"^(-)]) = 10^(-"pOH")#</mathjax></p> </blockquote> <p>which is equivalent to </p> <blockquote> <p><mathjax>#["OH"^(-)] = 10^(-"pOH")#</mathjax></p> </blockquote> <p>Now, an aqueous solution at room temperature has</p> <blockquote> <p><mathjax>#color(red)(ul(color(black)("pH " + " pOH" = 14)))#</mathjax></p> </blockquote> <p>This means that the <mathjax>#"pOH"#</mathjax> of the target solution is equal to </p> <blockquote> <p><mathjax>#"pOH" = 14 -12.4 = 1.6#</mathjax></p> </blockquote> <p>Consequently, the target solution must have</p> <blockquote> <p><mathjax>#["OH"^(-)] = 10^(-1.6) = 2.51 * 10^(-2)"M"#</mathjax></p> </blockquote> <p>As you know, <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> is defined as the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present in <mathjax>#"1 L"#</mathjax> of solution. This means that the <strong>number of moles</strong> of potassium hydroxide needed to ensure that concentration of hydroxide anions is equal to</p> <blockquote> <p><mathjax>#3.55 color(red)(cancel(color(black)("L solution"))) * (2.51 * 10^(-2)"moles OH"^(-))/(1color(red)(cancel(color(black)("L solution")))) = 8.91 * 10^(-2)"moles OH"^(-)#</mathjax></p> </blockquote> <p>All you have to do now is figure out what volume of the stock solution contains the needed number of moles of hydroxide anions</p> <blockquote> <p><mathjax>#8.91 * 10^(-2) color(red)(cancel(color(black)("moles OH"^(-)))) * "1 L solution"/(0.855color(red)(cancel(color(black)("moles OH"^(-))))) = "0.104 L"#</mathjax></p> </blockquote> <p>Expressed in <em>milliliters</em>, the answer will be </p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)(V_"stock KOH" = "104 mL")))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p> <p>So, in order to prepare this solution, take <mathjax>#"104 mL"#</mathjax> of <mathjax>#"0.855 M"#</mathjax> stock potassium hydroxide solution and add <em>enough water</em> until the final volume of the solution is equal to <mathjax>#"3.55 L"#</mathjax>. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What volume of a 0.855 M KOH solution is required to make a 3.55 L solution at a pH of 12.4?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/saturated-and-supersaturated-solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Saturated and Supersaturated Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="356967" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-27T01:37:10" itemprop="dateCreated"> Dec 27, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"104 mL"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by using the <mathjax>#"pOH"#</mathjax> of the solution to figure out the concentration of hydroxide anions, <mathjax>#"OH"^(-)#</mathjax>. You should know that</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("pOH" = - log(["OH"^(-)]))))#</mathjax></p> </blockquote> <p>To solve for the concentration of hydroxide anions, rearrange the equation as </p> <blockquote> <p><mathjax>#log(["OH"^(-)]) = - "pOH"#</mathjax></p> </blockquote> <p>This can be written as </p> <blockquote> <p><mathjax>#10^log(["OH"^(-)]) = 10^(-"pOH")#</mathjax></p> </blockquote> <p>which is equivalent to </p> <blockquote> <p><mathjax>#["OH"^(-)] = 10^(-"pOH")#</mathjax></p> </blockquote> <p>Now, an aqueous solution at room temperature has</p> <blockquote> <p><mathjax>#color(red)(ul(color(black)("pH " + " pOH" = 14)))#</mathjax></p> </blockquote> <p>This means that the <mathjax>#"pOH"#</mathjax> of the target solution is equal to </p> <blockquote> <p><mathjax>#"pOH" = 14 -12.4 = 1.6#</mathjax></p> </blockquote> <p>Consequently, the target solution must have</p> <blockquote> <p><mathjax>#["OH"^(-)] = 10^(-1.6) = 2.51 * 10^(-2)"M"#</mathjax></p> </blockquote> <p>As you know, <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> is defined as the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present in <mathjax>#"1 L"#</mathjax> of solution. This means that the <strong>number of moles</strong> of potassium hydroxide needed to ensure that concentration of hydroxide anions is equal to</p> <blockquote> <p><mathjax>#3.55 color(red)(cancel(color(black)("L solution"))) * (2.51 * 10^(-2)"moles OH"^(-))/(1color(red)(cancel(color(black)("L solution")))) = 8.91 * 10^(-2)"moles OH"^(-)#</mathjax></p> </blockquote> <p>All you have to do now is figure out what volume of the stock solution contains the needed number of moles of hydroxide anions</p> <blockquote> <p><mathjax>#8.91 * 10^(-2) color(red)(cancel(color(black)("moles OH"^(-)))) * "1 L solution"/(0.855color(red)(cancel(color(black)("moles OH"^(-))))) = "0.104 L"#</mathjax></p> </blockquote> <p>Expressed in <em>milliliters</em>, the answer will be </p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)(V_"stock KOH" = "104 mL")))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p> <p>So, in order to prepare this solution, take <mathjax>#"104 mL"#</mathjax> of <mathjax>#"0.855 M"#</mathjax> stock potassium hydroxide solution and add <em>enough water</em> until the final volume of the solution is equal to <mathjax>#"3.55 L"#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/356967" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-saturated-solutions-at-equilibrium"> How are saturated solutions at equilibrium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-supersaturated-solutions-prepared"> How are supersaturated solutions prepared? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-identify-a-saturated-solution"> How can you identify a saturated solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-supersaturated-solutions-demonstrate-conservation-of-energy"> How do supersaturated solutions demonstrate conservation of energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-saturated-solution-of-potassium-iodide"> How do you make saturated solution of potassium iodide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-saturated-solution-of-sodium-bicarbonate"> How do you make saturated solution of sodium bicarbonate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-saturation-practice-problem"> What is an example of a saturation practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-saturated-solution"> What is a saturated solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-saturated-solution-practice-problem"> What is an example of a saturated solution practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-with-saturated-solutions"> What are some common mistakes students make with saturated solutions? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/saturated-and-supersaturated-solutions"> See all questions in Saturated and Supersaturated Solutions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 36728 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What volume of a 0.855 M KOH solution is required to make a 3.55 L solution at a pH of 12.4?

a91d5e74-6ddd-11ea-ad8e-ccda262736ce

https://socratic.org/questions/what-is-the-number-of-atoms-in-one-mole-of-carbon-atoms

6.02 × 10^23

start physical_unit 10 11 number none qc_end physical_unit 10 11 7 8 mole qc_end end

[{"type":"physical unit","value":"Number [OF] carbon atoms"}]

[{"type":"physical unit","value":"6.02 × 10^23"}]

[{"type":"physical unit","value":"Mole [OF] carbon atoms [=] \\pu{1 mole}"}]

<h1 class="questionTitle" itemprop="name">What is the number of atoms in one mole of carbon atoms?</h1>

6.02 × 10^23

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>No it is slightly more than that .... it is <mathjax>#"Avogadro's number"#</mathjax>, <mathjax>#6.02214xx10^23#</mathjax>. One mole of <mathjax>#""^12C#</mathjax> atoms has a mass of <mathjax>#12.00*g#</mathjax> PRECISELY. And this is why we use <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> in chemical calculations ... it is a link, a bridge, between the submicro world of atoms and molecules, about which we theorize, to the macro worlds of grams, and litres, that which we can measure on a laboratory bench.</p> <p>It is worth spending some time digesting this, because the mole is absolutely vital and fundamental to every chemical equation.... And so we could easily quote the mass of a SINGLE carbon atom with these data...i.e.</p> <p><mathjax>#"mass of ONE carbon atom"=(12.0*g*mol^-1)/(6.0224xx10^23*mol^-1)=1.99xx10^-23*g#</mathjax> </p> <p>And you are quoted molar masses of EVERY chemical element on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the Periodic Table</a>....</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Is it twelve?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>No it is slightly more than that .... it is <mathjax>#"Avogadro's number"#</mathjax>, <mathjax>#6.02214xx10^23#</mathjax>. One mole of <mathjax>#""^12C#</mathjax> atoms has a mass of <mathjax>#12.00*g#</mathjax> PRECISELY. And this is why we use <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> in chemical calculations ... it is a link, a bridge, between the submicro world of atoms and molecules, about which we theorize, to the macro worlds of grams, and litres, that which we can measure on a laboratory bench.</p> <p>It is worth spending some time digesting this, because the mole is absolutely vital and fundamental to every chemical equation.... And so we could easily quote the mass of a SINGLE carbon atom with these data...i.e.</p> <p><mathjax>#"mass of ONE carbon atom"=(12.0*g*mol^-1)/(6.0224xx10^23*mol^-1)=1.99xx10^-23*g#</mathjax> </p> <p>And you are quoted molar masses of EVERY chemical element on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the Periodic Table</a>....</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the number of atoms in one mole of carbon atoms?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/avogadro-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Avogadro's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="612530" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-13T06:09:21" itemprop="dateCreated"> May 13, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Is it twelve?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>No it is slightly more than that .... it is <mathjax>#"Avogadro's number"#</mathjax>, <mathjax>#6.02214xx10^23#</mathjax>. One mole of <mathjax>#""^12C#</mathjax> atoms has a mass of <mathjax>#12.00*g#</mathjax> PRECISELY. And this is why we use <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> in chemical calculations ... it is a link, a bridge, between the submicro world of atoms and molecules, about which we theorize, to the macro worlds of grams, and litres, that which we can measure on a laboratory bench.</p> <p>It is worth spending some time digesting this, because the mole is absolutely vital and fundamental to every chemical equation.... And so we could easily quote the mass of a SINGLE carbon atom with these data...i.e.</p> <p><mathjax>#"mass of ONE carbon atom"=(12.0*g*mol^-1)/(6.0224xx10^23*mol^-1)=1.99xx10^-23*g#</mathjax> </p> <p>And you are quoted molar masses of EVERY chemical element on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the Periodic Table</a>....</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/612530" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="612541" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/reign"><img alt="" class="" src="https://profilepictures.socratic.org/GzIXeMHQRPWI4sAkWD8Y_anime.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/reign"> Reign </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-13T06:25:49" itemprop="dateCreated"> May 13, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1 mol C=<mathjax>#6.022*10^23#</mathjax> atoms C</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For what I know, 1 mole is equivalent to <mathjax>#6.022*10^23#</mathjax> atoms.</p> <p>So, 1 mol C = <mathjax>#6.022*10^23#</mathjax> atoms C</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/612541" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-avogadro-s-law-important"> Why is Avogadro's law important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-was-the-avogadro-s-law-discovered"> How was the Avogadro's law discovered? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-avogadro-s-law-used-in-stoichiometry"> Is Avogadro's law used in stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-avogadro-s-law-used-in-everyday-life"> How is Avogadro's law used in everyday life? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-with-avogadro-s-law"> What are some common mistakes students make with Avogadro's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-an-avogadro-s-law-practice-problem"> What is an example of an Avogadro's law practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-the-avogadro-s-law"> What are some examples of the Avogadro's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/according-to-avogadro-s-law-as-the-number-of-moles-of-gas-increases-what-happens"> According to Avogadro's law, as the number of moles of gas increases, what happens to its volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-the-avogadro-s-law-written"> How is the Avogadro's law written? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-avogadro-s-principle"> What is the Avogadro's principle? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/avogadro-s-law"> See all questions in Avogadro's Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 29350 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the number of atoms in one mole of carbon atoms?

ad0137ba-6ddd-11ea-b685-ccda262736ce

https://socratic.org/questions/how-do-you-balance-this-equation-c-5h-12-o-2-co-2-h-2o-heat

C5H12 + O2 -> 6 H2O + 5 CO2 + heat

start chemical_equation qc_end chemical_equation 6 14 qc_end end

[{"type":"other","value":"Chemical Equation [OF] this equation"}]

[{"type":"chemical equation","value":"C5H12 + O2 -> 6 H2O + 5 CO2 + heat"}]

[{"type":"chemical equation","value":"C5H12 + O2 -> H2O + CO2 + heat"}]

<h1 class="questionTitle" itemprop="name">How do you balance this equation: #?C_5H_12 + ?O_2 → ?CO_2 + ?H_2O + heat#?</h1>

C5H12 + O2 -> 6 H2O + 5 CO2 + heat

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Well is it stoichiometrically balanced? Garbage out must equal garbage in if it is to be a proper representation of chemical reality. And not only is it balanced with respect to mass and charge, it is also balanced in terms of energy transfer. A given quantity of pentane results in a precise quantity of energy upon complete combustion. </p> <p>As to how to do it, the usual rigmarole is to:</p> <p><mathjax>#(i)#</mathjax> <mathjax>#"Balance the carbons as carbon dioxide"#</mathjax></p> <p><mathjax>#(ii)#</mathjax> <mathjax>#"Then balance the hydrogens as water"#</mathjax></p> <p><mathjax>#(iii)#</mathjax> <mathjax>#"And then balance the oxygens on the LHS".#</mathjax></p> <p>See <a href="https://socratic.org/questions/what-is-the-product-of-c6h5oh-reacting-with-oxygen-gas-and-how-do-i-balance-it?answerEditSuccess=1">here for another example.</a> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_5H_12 + 8O_2 rarr 5CO_2 +6H_2O + Delta#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Well is it stoichiometrically balanced? Garbage out must equal garbage in if it is to be a proper representation of chemical reality. And not only is it balanced with respect to mass and charge, it is also balanced in terms of energy transfer. A given quantity of pentane results in a precise quantity of energy upon complete combustion. </p> <p>As to how to do it, the usual rigmarole is to:</p> <p><mathjax>#(i)#</mathjax> <mathjax>#"Balance the carbons as carbon dioxide"#</mathjax></p> <p><mathjax>#(ii)#</mathjax> <mathjax>#"Then balance the hydrogens as water"#</mathjax></p> <p><mathjax>#(iii)#</mathjax> <mathjax>#"And then balance the oxygens on the LHS".#</mathjax></p> <p>See <a href="https://socratic.org/questions/what-is-the-product-of-c6h5oh-reacting-with-oxygen-gas-and-how-do-i-balance-it?answerEditSuccess=1">here for another example.</a> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you balance this equation: #?C_5H_12 + ?O_2 → ?CO_2 + ?H_2O + heat#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="387225" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-06T05:11:54" itemprop="dateCreated"> Mar 6, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_5H_12 + 8O_2 rarr 5CO_2 +6H_2O + Delta#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Well is it stoichiometrically balanced? Garbage out must equal garbage in if it is to be a proper representation of chemical reality. And not only is it balanced with respect to mass and charge, it is also balanced in terms of energy transfer. A given quantity of pentane results in a precise quantity of energy upon complete combustion. </p> <p>As to how to do it, the usual rigmarole is to:</p> <p><mathjax>#(i)#</mathjax> <mathjax>#"Balance the carbons as carbon dioxide"#</mathjax></p> <p><mathjax>#(ii)#</mathjax> <mathjax>#"Then balance the hydrogens as water"#</mathjax></p> <p><mathjax>#(iii)#</mathjax> <mathjax>#"And then balance the oxygens on the LHS".#</mathjax></p> <p>See <a href="https://socratic.org/questions/what-is-the-product-of-c6h5oh-reacting-with-oxygen-gas-and-how-do-i-balance-it?answerEditSuccess=1">here for another example.</a> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/387225" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="387226" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-06T05:12:44" itemprop="dateCreated"> Mar 6, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><ol> <li>Balance the carbon atoms.</li> <li>Balance the hydrogen atoms.</li> <li>Balance the oxygen atoms.</li> </ol> <p><mathjax>#"C"_5"H"_12 + color(purple)("8")"O"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(red)("5")"CO"_2 + color(green)("6")"H"_2"O" + "heat"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Balance the equation:</p> <p><mathjax>#"C"_5"H"_12 + "O"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"CO"_2 + "H"_2"O" + "heat"#</mathjax></p> <p>Due to the <strong>law of conservation of mass/matter</strong> , the number of atoms for each element must be the same on both sides. When balancing a chemical equation, the <strong>chemical formulas are never changed</strong> , which means subscripts are never changed. <strong>What can change is the amount of each reactant and product. The amount is indicated by a coefficient in front of a formula. The coefficient is multiplied by the subscripts of the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in the formula.</strong></p> <p><strong>The strategy for balancing combustion reactions is:</strong></p> <ol> <li>Balance the carbon atoms.</li> <li>Balance the hydrogen atoms.</li> <li>Balance the oxygen atoms.</li> </ol> <p><strong>Carbon and Hydrogen</strong></p> <p>There are 5 C atoms on the left and 1 C atom on the right. Place a coefficient of <mathjax>#5#</mathjax> in front of the <mathjax>#"CO"_2#</mathjax>. There are 12 H atoms on the left side, and 2 H atoms on the right. Place a coefficient of <mathjax>#6#</mathjax> in front of the <mathjax>#"H"_2"O"#</mathjax>.</p> <p><mathjax>#"C"_5"H"_12 + "O"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(red)("5")"CO"_2 + color(green)("6")"H"_2"O" + "heat"#</mathjax></p> <p><strong>Oxygen</strong></p> <p>There are 2 O atoms on the left and 16 O atoms on the right. Place a coefficient of <mathjax>#8#</mathjax> in front of the <mathjax>#"O"_2"#</mathjax>.</p> <p><mathjax>#"C"_5"H"_12 + color(purple)("8")"O"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#color(red)("5")"CO"_2 + color(green)("6")"H"_2"O" + "heat"#</mathjax></p> <p><strong>Check the numbers of atoms of each element on each side.</strong></p> <p><strong>Left Side:</strong> <mathjax>#"5 C atoms"#</mathjax>, <mathjax>#"12 H atoms"#</mathjax>, <mathjax>#"16 O atoms"#</mathjax></p> <p><strong>Right Side:</strong> <mathjax>#"5 C atoms"#</mathjax>, <mathjax>#"12 H atoms"#</mathjax>, <mathjax>#"16 O atoms"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/387226" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------&gt; H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -&gt; Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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How do you balance this equation: #?C_5H_12 + ?O_2 → ?CO_2 + ?H_2O + heat#?

acb78cb0-6ddd-11ea-88c5-ccda262736ce

https://socratic.org/questions/a-solution-contains-0-600-g-of-mg-2-in-enough-water-to-make-a-1930-ml-solution-w

25.58 mEq/L

start physical_unit 6 6 concentration meq/l qc_end physical_unit 6 6 3 4 mass qc_end physical_unit 1 1 13 14 volume qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Concentration [OF] Mg^2+ solution [IN] mEq/L"}]

[{"type":"physical unit","value":"25.58 mEq/L"}]

[{"type":"physical unit","value":"Mass [OF] Mg^2+ [=] \\pu{0.600 g}"},{"type":"physical unit","value":"Volume [OF] Mg^2+ solution [=] \\pu{1930 mL}"},{"type":"other","value":"Enough water."}]

<h1 class="questionTitle" itemprop="name">A solution contains 0.600 g of #Mg^(2+)# in enough water to make a 1930 mL solution. What is the concentration in milliequivalents per liter (mEq/L)?</h1>

25.58 mEq/L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy here will be use determine how many moles of magnesium your solution will contain by using magnesium's <em>molar mass</em>. </p> <p>Once you know the number of moles of magnesium cations, you can determine how many <strong>equivalents</strong> you have. </p> <p>So, magnesium has a molar mass of <mathjax>#"24.3050 g/mol"#</mathjax>. This means that <strong>one mole</strong> of magnesium cations will have a mass of <mathjax>#24.3050#</mathjax> grams. </p> <p>In your case, the solution will contain </p> <blockquote> <p><mathjax>#0.600 color(red)(cancel(color(black)("g Mg"^(2+)))) * "1 mole Mg"^(2+)/(24.3050color(red)(cancel(color(black)("g Mg"^(2+))))) = "0.02469 moles Mg"^(2+)#</mathjax></p> </blockquote> <p>For an ion in aqueous solution, the number of <strong>equivalents</strong> will be equal to the number of moles of that ion multiplied by its <em>valence</em>. </p> <blockquote> <p><mathjax>#color(blue)("Eq" = "moles" xx "valence")#</mathjax></p> </blockquote> <p>As you know, magnesium has a valence of <mathjax>#2#</mathjax>, which is why it forms <mathjax>#(2+)#</mathjax> cations in solution. This means that you have </p> <blockquote> <p><mathjax>#"0.02469 moles Mg"^(2+) xx 2 = "0.04938 Eq Mg"^(2+)#</mathjax></p> </blockquote> <p>To express this value in <em>milliequivalents</em>, <mathjax>#"mEq"#</mathjax>, use the conversion factor </p> <blockquote> <p><mathjax>#"1 Eq" = 10^3"mEq"#</mathjax></p> </blockquote> <p>This will get you </p> <blockquote> <p><mathjax>#0.04938 color(red)(cancel(color(black)("Eq"))) * (10^3"mEq")/(1color(red)(cancel(color(black)("Eq")))) = "49.38 mEq"#</mathjax></p> </blockquote> <p>Finally, to get the magnesium cations' concentration in <em>milliequivalents per liter</em>, divide the number of mEq by the volume of the solution - <strong>do not</strong> forget to convert it to <em>liters</em>!</p> <blockquote> <p><mathjax>#["Mg"^(2+)] = "49.38 mEq"/(1930 * 10^(-3)"L") = color(green)("25.6 mEq/L")#</mathjax></p> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"25.6 mEq/L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy here will be use determine how many moles of magnesium your solution will contain by using magnesium's <em>molar mass</em>. </p> <p>Once you know the number of moles of magnesium cations, you can determine how many <strong>equivalents</strong> you have. </p> <p>So, magnesium has a molar mass of <mathjax>#"24.3050 g/mol"#</mathjax>. This means that <strong>one mole</strong> of magnesium cations will have a mass of <mathjax>#24.3050#</mathjax> grams. </p> <p>In your case, the solution will contain </p> <blockquote> <p><mathjax>#0.600 color(red)(cancel(color(black)("g Mg"^(2+)))) * "1 mole Mg"^(2+)/(24.3050color(red)(cancel(color(black)("g Mg"^(2+))))) = "0.02469 moles Mg"^(2+)#</mathjax></p> </blockquote> <p>For an ion in aqueous solution, the number of <strong>equivalents</strong> will be equal to the number of moles of that ion multiplied by its <em>valence</em>. </p> <blockquote> <p><mathjax>#color(blue)("Eq" = "moles" xx "valence")#</mathjax></p> </blockquote> <p>As you know, magnesium has a valence of <mathjax>#2#</mathjax>, which is why it forms <mathjax>#(2+)#</mathjax> cations in solution. This means that you have </p> <blockquote> <p><mathjax>#"0.02469 moles Mg"^(2+) xx 2 = "0.04938 Eq Mg"^(2+)#</mathjax></p> </blockquote> <p>To express this value in <em>milliequivalents</em>, <mathjax>#"mEq"#</mathjax>, use the conversion factor </p> <blockquote> <p><mathjax>#"1 Eq" = 10^3"mEq"#</mathjax></p> </blockquote> <p>This will get you </p> <blockquote> <p><mathjax>#0.04938 color(red)(cancel(color(black)("Eq"))) * (10^3"mEq")/(1color(red)(cancel(color(black)("Eq")))) = "49.38 mEq"#</mathjax></p> </blockquote> <p>Finally, to get the magnesium cations' concentration in <em>milliequivalents per liter</em>, divide the number of mEq by the volume of the solution - <strong>do not</strong> forget to convert it to <em>liters</em>!</p> <blockquote> <p><mathjax>#["Mg"^(2+)] = "49.38 mEq"/(1930 * 10^(-3)"L") = color(green)("25.6 mEq/L")#</mathjax></p> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A solution contains 0.600 g of #Mg^(2+)# in enough water to make a 1930 mL solution. What is the concentration in milliequivalents per liter (mEq/L)?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="196791" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-06T01:04:46" itemprop="dateCreated"> Dec 6, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"25.6 mEq/L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy here will be use determine how many moles of magnesium your solution will contain by using magnesium's <em>molar mass</em>. </p> <p>Once you know the number of moles of magnesium cations, you can determine how many <strong>equivalents</strong> you have. </p> <p>So, magnesium has a molar mass of <mathjax>#"24.3050 g/mol"#</mathjax>. This means that <strong>one mole</strong> of magnesium cations will have a mass of <mathjax>#24.3050#</mathjax> grams. </p> <p>In your case, the solution will contain </p> <blockquote> <p><mathjax>#0.600 color(red)(cancel(color(black)("g Mg"^(2+)))) * "1 mole Mg"^(2+)/(24.3050color(red)(cancel(color(black)("g Mg"^(2+))))) = "0.02469 moles Mg"^(2+)#</mathjax></p> </blockquote> <p>For an ion in aqueous solution, the number of <strong>equivalents</strong> will be equal to the number of moles of that ion multiplied by its <em>valence</em>. </p> <blockquote> <p><mathjax>#color(blue)("Eq" = "moles" xx "valence")#</mathjax></p> </blockquote> <p>As you know, magnesium has a valence of <mathjax>#2#</mathjax>, which is why it forms <mathjax>#(2+)#</mathjax> cations in solution. This means that you have </p> <blockquote> <p><mathjax>#"0.02469 moles Mg"^(2+) xx 2 = "0.04938 Eq Mg"^(2+)#</mathjax></p> </blockquote> <p>To express this value in <em>milliequivalents</em>, <mathjax>#"mEq"#</mathjax>, use the conversion factor </p> <blockquote> <p><mathjax>#"1 Eq" = 10^3"mEq"#</mathjax></p> </blockquote> <p>This will get you </p> <blockquote> <p><mathjax>#0.04938 color(red)(cancel(color(black)("Eq"))) * (10^3"mEq")/(1color(red)(cancel(color(black)("Eq")))) = "49.38 mEq"#</mathjax></p> </blockquote> <p>Finally, to get the magnesium cations' concentration in <em>milliequivalents per liter</em>, divide the number of mEq by the volume of the solution - <strong>do not</strong> forget to convert it to <em>liters</em>!</p> <blockquote> <p><mathjax>#["Mg"^(2+)] = "49.38 mEq"/(1930 * 10^(-3)"L") = color(green)("25.6 mEq/L")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/196791" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 13396 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A solution contains 0.600 g of #Mg^(2+)# in enough water to make a 1930 mL solution. What is the concentration in milliequivalents per liter (mEq/L)?

aba783de-6ddd-11ea-8e86-ccda262736ce

https://socratic.org/questions/how-many-moles-of-h-3po-4-are-in-94-052-grams-of-h-3po-4

0.96 moles

start physical_unit 4 4 mole mol qc_end physical_unit 4 4 7 8 mass qc_end end

[{"type":"physical unit","value":"Mole [OF] H3PO4 [IN] moles"}]

[{"type":"physical unit","value":"0.96 moles"}]

[{"type":"physical unit","value":"Mass [OF] H3PO4 [=] \\pu{94.052 grams}"}]

<h1 class="questionTitle" itemprop="name">How many moles of #H_3PO_4# are in 94.052 grams of # H_3PO_4#?</h1>

0.96 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given a mass, we assess the number of moles by the QUOTIENT.....</p> <p><mathjax>#"Number of moles"-="Mass"/"Molar mass of stuff"#</mathjax></p> <p>And note that this is consistent dimensionally, because a molar mass is reported as <mathjax>#g*mol^-1#</mathjax>...and so we get the quotient....</p> <p><mathjax>#(g)/(g*mol^-1)=cancelg/(cancelg*mol^-1)=1/(1/(mol))=mol#</mathjax> as required....</p> <p>And so here we take the quotient....</p> <p><mathjax>#(94.052*g)/(97.99*g*mol^-1)=??*mol#</mathjax>.....not quite a mole.....</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We gots almost <mathjax>#1*mol#</mathjax> <mathjax>#"phosphoric acid"#</mathjax>......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given a mass, we assess the number of moles by the QUOTIENT.....</p> <p><mathjax>#"Number of moles"-="Mass"/"Molar mass of stuff"#</mathjax></p> <p>And note that this is consistent dimensionally, because a molar mass is reported as <mathjax>#g*mol^-1#</mathjax>...and so we get the quotient....</p> <p><mathjax>#(g)/(g*mol^-1)=cancelg/(cancelg*mol^-1)=1/(1/(mol))=mol#</mathjax> as required....</p> <p>And so here we take the quotient....</p> <p><mathjax>#(94.052*g)/(97.99*g*mol^-1)=??*mol#</mathjax>.....not quite a mole.....</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles of #H_3PO_4# are in 94.052 grams of # H_3PO_4#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="485355" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-10-05T17:48:41" itemprop="dateCreated"> Oct 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We gots almost <mathjax>#1*mol#</mathjax> <mathjax>#"phosphoric acid"#</mathjax>......</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given a mass, we assess the number of moles by the QUOTIENT.....</p> <p><mathjax>#"Number of moles"-="Mass"/"Molar mass of stuff"#</mathjax></p> <p>And note that this is consistent dimensionally, because a molar mass is reported as <mathjax>#g*mol^-1#</mathjax>...and so we get the quotient....</p> <p><mathjax>#(g)/(g*mol^-1)=cancelg/(cancelg*mol^-1)=1/(1/(mol))=mol#</mathjax> as required....</p> <p>And so here we take the quotient....</p> <p><mathjax>#(94.052*g)/(97.99*g*mol^-1)=??*mol#</mathjax>.....not quite a mole.....</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/485355" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li 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2263 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many moles of #H_3PO_4# are in 94.052 grams of # H_3PO_4#?

a8e4e0d9-6ddd-11ea-828a-ccda262736ce

https://socratic.org/questions/what-is-the-ph-of-a-solution-that-has-a-hydronium-ion-concentration-of-1-00-time

4

start physical_unit 5 6 ph none qc_end physical_unit 10 11 14 17 concentration qc_end end

[{"type":"physical unit","value":"pH [OF] a solution"}]

[{"type":"physical unit","value":"4"}]

[{"type":"physical unit","value":"Concentration [OF] hydronium ion [=] \\pu{1.00 × 10^(−4) M}"}]

<h1 class="questionTitle" itemprop="name">What is the pH of a solution that has a hydronium ion concentration of #1.00 times 10^-4 M#? </h1>

4

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To calculate the pH of a solution, use the equation</p> <p><mathjax>#pH = -log[H_3O^+]#</mathjax></p> <p>Since we are given the hydronium ion (<mathjax>#H_3O^+#</mathjax>) concentration of the solution, we can plug this value into the formula.</p> <p><mathjax>#pH = -log[1.00 xx 10^-4 M]#</mathjax><br/> <mathjax>#pH = 4#</mathjax></p> <p><strong>The pH of this solution is 4.</strong></p> <p>Added notes:<br/> <mathjax>#pH = pH_3O^+#</mathjax> because hydrogen ions attach to water molecules for form hydronium ions.</p> <p>Some other key things to remember for pH calculations include:</p> <p>pH + pOH = 14</p> <p>pH = -log[<mathjax>#H^+#</mathjax>] <br/> pOH = -log[<mathjax>#OH^-#</mathjax>]</p> <p><mathjax>#[H^+] = 10^(-pH)#</mathjax><br/> <mathjax>#[OH^-] = 10^(-pOH) #</mathjax></p> <p>The video below explains how to use all this information so that you can complete these types of calculations.</p> <p> <iframe src="https://www.youtube.com/embed/WDpMkw176I4?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p> <p>Hope this helps!</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> = 4</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To calculate the pH of a solution, use the equation</p> <p><mathjax>#pH = -log[H_3O^+]#</mathjax></p> <p>Since we are given the hydronium ion (<mathjax>#H_3O^+#</mathjax>) concentration of the solution, we can plug this value into the formula.</p> <p><mathjax>#pH = -log[1.00 xx 10^-4 M]#</mathjax><br/> <mathjax>#pH = 4#</mathjax></p> <p><strong>The pH of this solution is 4.</strong></p> <p>Added notes:<br/> <mathjax>#pH = pH_3O^+#</mathjax> because hydrogen ions attach to water molecules for form hydronium ions.</p> <p>Some other key things to remember for pH calculations include:</p> <p>pH + pOH = 14</p> <p>pH = -log[<mathjax>#H^+#</mathjax>] <br/> pOH = -log[<mathjax>#OH^-#</mathjax>]</p> <p><mathjax>#[H^+] = 10^(-pH)#</mathjax><br/> <mathjax>#[OH^-] = 10^(-pOH) #</mathjax></p> <p>The video below explains how to use all this information so that you can complete these types of calculations.</p> <p> <iframe src="https://www.youtube.com/embed/WDpMkw176I4?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p> <p>Hope this helps!</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the pH of a solution that has a hydronium ion concentration of #1.00 times 10^-4 M#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="445473" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/noel-p"><img alt="" class="" src="https://profilepictures.socratic.org/02ThC0uRMah0LVgFe9Tg_CrabbyMrP.jpg" title=""/></a> <a class="secondContributorPic" href="/users/michelle-33"><img alt="" class="" src="https://profilepictures.socratic.org/QwvZBefRmOXvj0OScuwA_bfb655b5a099a18b5c1023c5f8de9367--violet-aesthetic-pastel-tumblr-purple-aesthetic.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/noel-p"> mrpauller.weebly.com </a>·<a class="topContributorLink" href="/users/michelle-33"> Michelle </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-28T15:08:59" itemprop="dateCreated"> Jun 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> = 4</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To calculate the pH of a solution, use the equation</p> <p><mathjax>#pH = -log[H_3O^+]#</mathjax></p> <p>Since we are given the hydronium ion (<mathjax>#H_3O^+#</mathjax>) concentration of the solution, we can plug this value into the formula.</p> <p><mathjax>#pH = -log[1.00 xx 10^-4 M]#</mathjax><br/> <mathjax>#pH = 4#</mathjax></p> <p><strong>The pH of this solution is 4.</strong></p> <p>Added notes:<br/> <mathjax>#pH = pH_3O^+#</mathjax> because hydrogen ions attach to water molecules for form hydronium ions.</p> <p>Some other key things to remember for pH calculations include:</p> <p>pH + pOH = 14</p> <p>pH = -log[<mathjax>#H^+#</mathjax>] <br/> pOH = -log[<mathjax>#OH^-#</mathjax>]</p> <p><mathjax>#[H^+] = 10^(-pH)#</mathjax><br/> <mathjax>#[OH^-] = 10^(-pOH) #</mathjax></p> <p>The video below explains how to use all this information so that you can complete these types of calculations.</p> <p> <iframe src="https://www.youtube.com/embed/WDpMkw176I4?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p> <p>Hope this helps!</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/445473" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? 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What is the pH of a solution that has a hydronium ion concentration of #1.00 times 10^-4 M#?

a90df6d8-6ddd-11ea-8ed8-ccda262736ce

https://socratic.org/questions/the-vapor-pressure-of-pure-water-at-25-degrees-celsius-is-23-8-torr-what-is-the-

23.36 torr

start physical_unit 19 20 vapor_pressure torr qc_end physical_unit 4 5 11 12 vapor_pressure qc_end physical_unit 4 5 7 9 temperature qc_end physical_unit 27 27 31 32 molecular_weight qc_end physical_unit 27 27 24 25 mass qc_end physical_unit 5 5 34 35 mass qc_end end

[{"type":"physical unit","value":"Vapor pressure [OF] a solution [IN] torr"}]

[{"type":"physical unit","value":"23.36 torr"}]

[{"type":"physical unit","value":"Vapor pressure [OF] pure water [=] \\pu{23.8 torr}"},{"type":"physical unit","value":"Temperature [OF] pure water [=] \\pu{25 degrees Celsius}"},{"type":"physical unit","value":"Molecular weight [OF] glucose [=] \\pu{180.0 g/mol}"},{"type":"physical unit","value":"Mass [OF] glucose [=] \\pu{18.0 g}"},{"type":"physical unit","value":"Mass [OF] water [=] \\pu{95.0 g}"}]

<h1 class="questionTitle" itemprop="name">The vapor pressure of pure water at 25 degrees Celsius is 23.8 torr. What is the vapor pressure of a solution prepared by dissolving 18.0 g of glucose (molecular weight = 180.0g/mol) in 95.0 g of water?</h1>

23.36 torr

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> that contain <em>non-volatile solutes</em>, the vapor pressure of the solution can be determined by using the <strong>mole fraction</strong> of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> and the vapor pressure of the <em>pure solvent</em> at the same temperature. </p> <blockquote> <p><mathjax>#color(blue)(P_"sol" = chi_"solvent" * P_"solvent"^@)" "#</mathjax>, where</p> <ul> <li><mathjax>#P_"sol"#</mathjax> is the vapor pressure of the solution</li> <li><mathjax>#chi_"solvent"#</mathjax> is the <strong>mole fraction</strong> of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a></li> <li><mathjax>#P_"solvent"^@#</mathjax> is the vapor pressure of the <em>pure solvent</em></li> </ul> </blockquote> <p>In your case, you know that the vapor pressure of pure water at <mathjax>#25^@"C"#</mathjax> is equal to <mathjax>#23.8#</mathjax> torr. This means that all you have to do is determine <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fraction of water in the solution. </p> <p>As you know, <strong>mole fraction</strong> is defined as the number of moles of a component of a solution divided by the <strong>total number of moles</strong> present in that solution. </p> <p>Use glucose and water's respective molar masses to determine how many moles of each you have</p> <blockquote> <p><mathjax>#18.0color(red)(cancel(color(black)("g"))) * "1 mole glucose"/(180.0color(red)(cancel(color(black)("g")))) = "0.100 moles glucose"#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#95.0color(red)(cancel(color(black)("g"))) * "1 mole water"/(18.015color(red)(cancel(color(black)("g")))) = "5.273 moles water"#</mathjax></p> </blockquote> <p>The total number of moles present in the solution will be </p> <blockquote> <p><mathjax>#n_"total" = n_"glucose" + n_"water"#</mathjax></p> <p><mathjax>#n_"total" = 0.100 + 5.273 = "5.373 moles"#</mathjax></p> </blockquote> <p>This means that the mole fraction of water will be </p> <blockquote> <p><mathjax>#chi_"water" = (5.273color(red)(cancel(color(black)("moles"))))/(5.373color(red)(cancel(color(black)("moles")))) = 0.9814#</mathjax></p> </blockquote> <p>Finally, the vapor pressure of the solution will be </p> <blockquote> <p><mathjax>#P_"sol" = 0.9814 * "23.8 torr" = color(green)("23.4 torr")#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"23.4 torr"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> that contain <em>non-volatile solutes</em>, the vapor pressure of the solution can be determined by using the <strong>mole fraction</strong> of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> and the vapor pressure of the <em>pure solvent</em> at the same temperature. </p> <blockquote> <p><mathjax>#color(blue)(P_"sol" = chi_"solvent" * P_"solvent"^@)" "#</mathjax>, where</p> <ul> <li><mathjax>#P_"sol"#</mathjax> is the vapor pressure of the solution</li> <li><mathjax>#chi_"solvent"#</mathjax> is the <strong>mole fraction</strong> of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a></li> <li><mathjax>#P_"solvent"^@#</mathjax> is the vapor pressure of the <em>pure solvent</em></li> </ul> </blockquote> <p>In your case, you know that the vapor pressure of pure water at <mathjax>#25^@"C"#</mathjax> is equal to <mathjax>#23.8#</mathjax> torr. This means that all you have to do is determine <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fraction of water in the solution. </p> <p>As you know, <strong>mole fraction</strong> is defined as the number of moles of a component of a solution divided by the <strong>total number of moles</strong> present in that solution. </p> <p>Use glucose and water's respective molar masses to determine how many moles of each you have</p> <blockquote> <p><mathjax>#18.0color(red)(cancel(color(black)("g"))) * "1 mole glucose"/(180.0color(red)(cancel(color(black)("g")))) = "0.100 moles glucose"#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#95.0color(red)(cancel(color(black)("g"))) * "1 mole water"/(18.015color(red)(cancel(color(black)("g")))) = "5.273 moles water"#</mathjax></p> </blockquote> <p>The total number of moles present in the solution will be </p> <blockquote> <p><mathjax>#n_"total" = n_"glucose" + n_"water"#</mathjax></p> <p><mathjax>#n_"total" = 0.100 + 5.273 = "5.373 moles"#</mathjax></p> </blockquote> <p>This means that the mole fraction of water will be </p> <blockquote> <p><mathjax>#chi_"water" = (5.273color(red)(cancel(color(black)("moles"))))/(5.373color(red)(cancel(color(black)("moles")))) = 0.9814#</mathjax></p> </blockquote> <p>Finally, the vapor pressure of the solution will be </p> <blockquote> <p><mathjax>#P_"sol" = 0.9814 * "23.8 torr" = color(green)("23.4 torr")#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">The vapor pressure of pure water at 25 degrees Celsius is 23.8 torr. What is the vapor pressure of a solution prepared by dissolving 18.0 g of glucose (molecular weight = 180.0g/mol) in 95.0 g of water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/colligative-properties" itemprop="url"> <span class="breadcrumb" itemprop="title">Colligative Properties</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="192924" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-25T11:49:59" itemprop="dateCreated"> Nov 25, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"23.4 torr"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> that contain <em>non-volatile solutes</em>, the vapor pressure of the solution can be determined by using the <strong>mole fraction</strong> of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> and the vapor pressure of the <em>pure solvent</em> at the same temperature. </p> <blockquote> <p><mathjax>#color(blue)(P_"sol" = chi_"solvent" * P_"solvent"^@)" "#</mathjax>, where</p> <ul> <li><mathjax>#P_"sol"#</mathjax> is the vapor pressure of the solution</li> <li><mathjax>#chi_"solvent"#</mathjax> is the <strong>mole fraction</strong> of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a></li> <li><mathjax>#P_"solvent"^@#</mathjax> is the vapor pressure of the <em>pure solvent</em></li> </ul> </blockquote> <p>In your case, you know that the vapor pressure of pure water at <mathjax>#25^@"C"#</mathjax> is equal to <mathjax>#23.8#</mathjax> torr. This means that all you have to do is determine <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fraction of water in the solution. </p> <p>As you know, <strong>mole fraction</strong> is defined as the number of moles of a component of a solution divided by the <strong>total number of moles</strong> present in that solution. </p> <p>Use glucose and water's respective molar masses to determine how many moles of each you have</p> <blockquote> <p><mathjax>#18.0color(red)(cancel(color(black)("g"))) * "1 mole glucose"/(180.0color(red)(cancel(color(black)("g")))) = "0.100 moles glucose"#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#95.0color(red)(cancel(color(black)("g"))) * "1 mole water"/(18.015color(red)(cancel(color(black)("g")))) = "5.273 moles water"#</mathjax></p> </blockquote> <p>The total number of moles present in the solution will be </p> <blockquote> <p><mathjax>#n_"total" = n_"glucose" + n_"water"#</mathjax></p> <p><mathjax>#n_"total" = 0.100 + 5.273 = "5.373 moles"#</mathjax></p> </blockquote> <p>This means that the mole fraction of water will be </p> <blockquote> <p><mathjax>#chi_"water" = (5.273color(red)(cancel(color(black)("moles"))))/(5.373color(red)(cancel(color(black)("moles")))) = 0.9814#</mathjax></p> </blockquote> <p>Finally, the vapor pressure of the solution will be </p> <blockquote> <p><mathjax>#P_"sol" = 0.9814 * "23.8 torr" = color(green)("23.4 torr")#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/192924" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-colligative-properties-determined"> How are colligative properties determined? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-freezing-point-depression"> How do you calculate freezing point depression? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-freezing-point-depression-determine-purity"> How can freezing point depression determine purity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-colligative-properties-affect-boiling-point"> How does the nature of the solute affect boiling point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-colligative-properties-affect-freezing-point"> How do colligative properties affect freezing point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-colligative-property-causes-ice-to-melt"> What colligative property causes ice to melt? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-colligative-properties-depend-on-the-number-of-particles"> Why do colligative properties depend on the number of particles? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ionic-bonding-affect-the-boiling-point"> How do ionic solutes affect the boiling point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutes-lower-vapor-pressure"> Why do solutes lower vapor pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-boiling-point"> How does solubility affect boiling point? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/colligative-properties"> See all questions in Colligative Properties </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 116047 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

The vapor pressure of pure water at 25 degrees Celsius is 23.8 torr. What is the vapor pressure of a solution prepared by dissolving 18.0 g of glucose (molecular weight = 180.0g/mol) in 95.0 g of water?

ad294066-6ddd-11ea-830d-ccda262736ce

https://socratic.org/questions/2-0-g-of-molybdenum-mo-combines-with-oxygen-to-form-3-0-g-of-a-molybdenum-oxide-

16.00 g/eq

start physical_unit 4 4 equivalent_weight g/eq qc_end physical_unit 4 4 0 1 mass qc_end physical_unit 14 15 10 11 mass qc_end substance 7 7 qc_end end

[{"type":"physical unit","value":"Equivalent weight [OF] Mo [IN] g/eq"}]

[{"type":"physical unit","value":"16.00 g/eq"}]

[{"type":"physical unit","value":"Weight [OF] Mo [=] \\pu{2.0 g}"},{"type":"physical unit","value":"Weight [OF] the molybdenum oxide [=] \\pu{3.0 g}"},{"type":"substance name","value":"Oxygen"}]

<h1 class="questionTitle" itemprop="name">2.0 g of molybdenum (Mo) combines with oxygen to form 3.0 g of a molybdenum oxide. What is the equivalent weight of Mo in this compound?</h1>

16.00 g/eq

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The trick here is to recognize that you're dealing with a <a href="https://socratic.org/chemistry/chemical-reactions/redox-reactions">redox reaction</a> in which molybdenum is being <strong>oxidized</strong> and oxygen is being <strong>reduced</strong>. </p> <p>You don't actually have to know the formula of the oxide in order to be able to determine the <em>equivalent weight</em> of molybdenum in the oxide, you can use oxygen's known oxidation state. </p> <p>More specifically, oxygen will go from an oxidation state of <mathjax>#0#</mathjax> as a reactant to an oxidation state of <mathjax>#(-2)#</mathjax> as part of the oxide. </p> <p>This means that <strong>every mole</strong> of oxygen that takes part in the reaction will <strong>gain</strong> <em>2 moles</em> of electrons. </p> <p>As you know, <strong>equivalent weight</strong> in the context of a redox reaction is defined as the mass of a compound that supplies or reacts with <strong>one mole</strong> of electrons. </p> <p>So, if one mole of oxygen has a mass of <mathjax>#"16.0 g"#</mathjax>, and you have one mole of oxygen gaining <strong>2 moles</strong> of electrons, it follows that oxygen's equivalent weight in this reaction will be </p> <blockquote> <p><mathjax>#16.0"g"/color(red)(cancel(color(black)("mol"))) * (1color(red)(cancel(color(black)("mole"))))/("2 moles electrons") = "8.00 g/equiv."#</mathjax></p> </blockquote> <p>Here <mathjax>#"1 equiv ." = " 1 mole electrons"#</mathjax>. </p> <p>Now all you have to do is figure out <strong>exactly</strong> what mass of oxygen took part in the reaction. So, if you start with <mathjax>#"2.0 g"#</mathjax> of molybdenum and end up with <mathjax>#"3.0 g"#</mathjax> of oxide, it follows that the difference between these two masses will be the mass of <em>oxygen</em> that took part in the reaction. </p> <blockquote> <p><mathjax>#m_"oxygen" = "3.00 g" - "2.0 g" = "1.0 g O"#</mathjax></p> </blockquote> <p>If your reaction used <mathjax>#"1.0 g"#</mathjax> of oxygen, and its equivalent weight is <mathjax>#"8.00 g/equiv."#</mathjax>, it follows that your reaction needed </p> <blockquote> <p><mathjax>#1.0 color(red)(cancel(color(black)("g O"))) * "1 equiv."/(8.00color(red)(cancel(color(black)("g O")))) = "0.125 equiv. O"#</mathjax></p> </blockquote> <p>Since in any redox reaction the number of equivalents gained by the species that gets <em>reduced</em> must be <strong>equal</strong> to the number of equivalents lost by the species that gets <em>oxidized</em>, you know that molybdenum lost <mathjax>#"0.125 equiv."#</mathjax>.</p> <p>Since <mathjax>#"2.0 g"#</mathjax> of molybdenum took part in the reaction, you can say that its equivalent weight will be </p> <blockquote> <p><mathjax>#"2.0 g"/"0.125 equiv." = "16 g/equiv."#</mathjax></p> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"16 g/equiv."#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The trick here is to recognize that you're dealing with a <a href="https://socratic.org/chemistry/chemical-reactions/redox-reactions">redox reaction</a> in which molybdenum is being <strong>oxidized</strong> and oxygen is being <strong>reduced</strong>. </p> <p>You don't actually have to know the formula of the oxide in order to be able to determine the <em>equivalent weight</em> of molybdenum in the oxide, you can use oxygen's known oxidation state. </p> <p>More specifically, oxygen will go from an oxidation state of <mathjax>#0#</mathjax> as a reactant to an oxidation state of <mathjax>#(-2)#</mathjax> as part of the oxide. </p> <p>This means that <strong>every mole</strong> of oxygen that takes part in the reaction will <strong>gain</strong> <em>2 moles</em> of electrons. </p> <p>As you know, <strong>equivalent weight</strong> in the context of a redox reaction is defined as the mass of a compound that supplies or reacts with <strong>one mole</strong> of electrons. </p> <p>So, if one mole of oxygen has a mass of <mathjax>#"16.0 g"#</mathjax>, and you have one mole of oxygen gaining <strong>2 moles</strong> of electrons, it follows that oxygen's equivalent weight in this reaction will be </p> <blockquote> <p><mathjax>#16.0"g"/color(red)(cancel(color(black)("mol"))) * (1color(red)(cancel(color(black)("mole"))))/("2 moles electrons") = "8.00 g/equiv."#</mathjax></p> </blockquote> <p>Here <mathjax>#"1 equiv ." = " 1 mole electrons"#</mathjax>. </p> <p>Now all you have to do is figure out <strong>exactly</strong> what mass of oxygen took part in the reaction. So, if you start with <mathjax>#"2.0 g"#</mathjax> of molybdenum and end up with <mathjax>#"3.0 g"#</mathjax> of oxide, it follows that the difference between these two masses will be the mass of <em>oxygen</em> that took part in the reaction. </p> <blockquote> <p><mathjax>#m_"oxygen" = "3.00 g" - "2.0 g" = "1.0 g O"#</mathjax></p> </blockquote> <p>If your reaction used <mathjax>#"1.0 g"#</mathjax> of oxygen, and its equivalent weight is <mathjax>#"8.00 g/equiv."#</mathjax>, it follows that your reaction needed </p> <blockquote> <p><mathjax>#1.0 color(red)(cancel(color(black)("g O"))) * "1 equiv."/(8.00color(red)(cancel(color(black)("g O")))) = "0.125 equiv. O"#</mathjax></p> </blockquote> <p>Since in any redox reaction the number of equivalents gained by the species that gets <em>reduced</em> must be <strong>equal</strong> to the number of equivalents lost by the species that gets <em>oxidized</em>, you know that molybdenum lost <mathjax>#"0.125 equiv."#</mathjax>.</p> <p>Since <mathjax>#"2.0 g"#</mathjax> of molybdenum took part in the reaction, you can say that its equivalent weight will be </p> <blockquote> <p><mathjax>#"2.0 g"/"0.125 equiv." = "16 g/equiv."#</mathjax></p> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">2.0 g of molybdenum (Mo) combines with oxygen to form 3.0 g of a molybdenum oxide. What is the equivalent weight of Mo in this compound?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/redox-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Redox Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="194144" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-28T23:59:13" itemprop="dateCreated"> Nov 28, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"16 g/equiv."#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The trick here is to recognize that you're dealing with a <a href="https://socratic.org/chemistry/chemical-reactions/redox-reactions">redox reaction</a> in which molybdenum is being <strong>oxidized</strong> and oxygen is being <strong>reduced</strong>. </p> <p>You don't actually have to know the formula of the oxide in order to be able to determine the <em>equivalent weight</em> of molybdenum in the oxide, you can use oxygen's known oxidation state. </p> <p>More specifically, oxygen will go from an oxidation state of <mathjax>#0#</mathjax> as a reactant to an oxidation state of <mathjax>#(-2)#</mathjax> as part of the oxide. </p> <p>This means that <strong>every mole</strong> of oxygen that takes part in the reaction will <strong>gain</strong> <em>2 moles</em> of electrons. </p> <p>As you know, <strong>equivalent weight</strong> in the context of a redox reaction is defined as the mass of a compound that supplies or reacts with <strong>one mole</strong> of electrons. </p> <p>So, if one mole of oxygen has a mass of <mathjax>#"16.0 g"#</mathjax>, and you have one mole of oxygen gaining <strong>2 moles</strong> of electrons, it follows that oxygen's equivalent weight in this reaction will be </p> <blockquote> <p><mathjax>#16.0"g"/color(red)(cancel(color(black)("mol"))) * (1color(red)(cancel(color(black)("mole"))))/("2 moles electrons") = "8.00 g/equiv."#</mathjax></p> </blockquote> <p>Here <mathjax>#"1 equiv ." = " 1 mole electrons"#</mathjax>. </p> <p>Now all you have to do is figure out <strong>exactly</strong> what mass of oxygen took part in the reaction. So, if you start with <mathjax>#"2.0 g"#</mathjax> of molybdenum and end up with <mathjax>#"3.0 g"#</mathjax> of oxide, it follows that the difference between these two masses will be the mass of <em>oxygen</em> that took part in the reaction. </p> <blockquote> <p><mathjax>#m_"oxygen" = "3.00 g" - "2.0 g" = "1.0 g O"#</mathjax></p> </blockquote> <p>If your reaction used <mathjax>#"1.0 g"#</mathjax> of oxygen, and its equivalent weight is <mathjax>#"8.00 g/equiv."#</mathjax>, it follows that your reaction needed </p> <blockquote> <p><mathjax>#1.0 color(red)(cancel(color(black)("g O"))) * "1 equiv."/(8.00color(red)(cancel(color(black)("g O")))) = "0.125 equiv. O"#</mathjax></p> </blockquote> <p>Since in any redox reaction the number of equivalents gained by the species that gets <em>reduced</em> must be <strong>equal</strong> to the number of equivalents lost by the species that gets <em>oxidized</em>, you know that molybdenum lost <mathjax>#"0.125 equiv."#</mathjax>.</p> <p>Since <mathjax>#"2.0 g"#</mathjax> of molybdenum took part in the reaction, you can say that its equivalent weight will be </p> <blockquote> <p><mathjax>#"2.0 g"/"0.125 equiv." = "16 g/equiv."#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/194144" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54423f26581e2a5bfd08340d"> Question #8340d </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-redox-reaction"> What is a redox reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-oxidation"> What is oxidation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-reduction"> What is reduction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/54d532c6581e2a49268014c4"> Question #014c4 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/556ea205581e2a438ccb58e9"> Question #b58e9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/55973977581e2a5f9d456add"> Question #56add </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/55ad1b09581e2a5dd320853f"> Question #0853f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/55b8d545581e2a20b9abe12b"> Question #be12b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5618b78a11ef6b27240f7e3f"> Question #f7e3f </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/redox-reactions"> See all questions in Redox Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2033 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

2.0 g of molybdenum (Mo) combines with oxygen to form 3.0 g of a molybdenum oxide. What is the equivalent weight of Mo in this compound?

abea60d1-6ddd-11ea-9f95-ccda262736ce

https://socratic.org/questions/what-is-the-formula-for-potassium-periodate

KIO4

start chemical_formula qc_end substance 5 6 qc_end end

[{"type":"other","value":"Chemical Formula [OF] potassium periodate [IN] default"}]

[{"type":"chemical equation","value":"KIO4"}]

[{"type":"substance name","value":"Potassium periodate"}]

<h1 class="questionTitle" itemprop="name">What is the formula for potassium periodate?</h1>

KIO4

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Potassium periodate is a potent oxidizing agent. It is one of the less soluble potassium salts. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#KIO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Potassium periodate is a potent oxidizing agent. It is one of the less soluble potassium salts. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the formula for potassium periodate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="196421" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-04T21:07:59" itemprop="dateCreated"> Dec 4, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#KIO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Potassium periodate is a potent oxidizing agent. It is one of the less soluble potassium salts. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/196421" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-chloride"> What is the ionic formula for calcium chloride? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-oxide"> What is the ionic formula for calcium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-lithium-oxide"> What is the ionic formula for lithium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-formula-for-ionic-compounds"> How do you write the formula for ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-correctly-write-the-ions-present-in-sn-no3-2"> How do I write #Sn(NO_3)_2# in Ionic formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-an-ionic-compound"> What is the empirical formula for an ionic compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-for-chorate"> What is the molecular formula for chorate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5363023c02bf343b2ee7086b"> Question #7086b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-polyatomic-ions-covalent-1"> Why are polyatomic ions covalent? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas"> See all questions in Writing Ionic Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2081 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the formula for potassium periodate?

a91075c0-6ddd-11ea-8755-ccda262736ce

https://socratic.org/questions/what-numerical-value-represents-1-00-mol-of-any-substance

6.02 × 10^23

start physical_unit 7 8 number none qc_end physical_unit 7 8 4 5 mole qc_end end

[{"type":"physical unit","value":"Numerical value [OF] any substance"}]

[{"type":"physical unit","value":"6.02 × 10^23"}]

[{"type":"physical unit","value":"Mole [OF] any substance [=] \\pu{1.00 mol}"}]

<h1 class="questionTitle" itemprop="name">What numerical value represents 1.00 mol of any substance? </h1>

6.02 × 10^23

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Avogadro's constant",#</mathjax> often given the symbol <mathjax>#N_A#</mathjax> or less commonly <mathjax>#L#</mathjax>, has the value <mathjax>#6.022140857(74)xx10^23* mol^-1#</mathjax>.</p> <p><mathjax>#"Avogadro's number"#</mathjax> of <mathjax>#""^1H#</mathjax> atoms have a mass of <mathjax>#1.00*g#</mathjax>. And thus it is the link between the micro world of atoms and molecules, and the benchtop world of grams, and kilograms, and litres. </p> <p>See this <a href="https://socratic.org/questions/what-is-meant-by-the-term-one-mole-of-molecules?answerSuccess=1">older answer.</a> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#6.022xx10^23#</mathjax> individual items of that substance.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Avogadro's constant",#</mathjax> often given the symbol <mathjax>#N_A#</mathjax> or less commonly <mathjax>#L#</mathjax>, has the value <mathjax>#6.022140857(74)xx10^23* mol^-1#</mathjax>.</p> <p><mathjax>#"Avogadro's number"#</mathjax> of <mathjax>#""^1H#</mathjax> atoms have a mass of <mathjax>#1.00*g#</mathjax>. And thus it is the link between the micro world of atoms and molecules, and the benchtop world of grams, and kilograms, and litres. </p> <p>See this <a href="https://socratic.org/questions/what-is-meant-by-the-term-one-mole-of-molecules?answerSuccess=1">older answer.</a> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What numerical value represents 1.00 mol of any substance? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="363063" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-11T08:59:59" itemprop="dateCreated"> Jan 11, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#6.022xx10^23#</mathjax> individual items of that substance.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Avogadro's constant",#</mathjax> often given the symbol <mathjax>#N_A#</mathjax> or less commonly <mathjax>#L#</mathjax>, has the value <mathjax>#6.022140857(74)xx10^23* mol^-1#</mathjax>.</p> <p><mathjax>#"Avogadro's number"#</mathjax> of <mathjax>#""^1H#</mathjax> atoms have a mass of <mathjax>#1.00*g#</mathjax>. And thus it is the link between the micro world of atoms and molecules, and the benchtop world of grams, and kilograms, and litres. </p> <p>See this <a href="https://socratic.org/questions/what-is-meant-by-the-term-one-mole-of-molecules?answerSuccess=1">older answer.</a> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/363063" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1297 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What numerical value represents 1.00 mol of any substance?

aa85b365-6ddd-11ea-b52a-ccda262736ce

https://socratic.org/questions/a-gas-at-55-0-c-occupies-a-volume-of-3-60-l-what-volume-will-it-occupy-at-30-0-c

3.33 L

start physical_unit 1 1 volume l qc_end physical_unit 1 1 3 4 temperature qc_end physical_unit 1 1 9 10 volume qc_end physical_unit 1 1 17 18 temperature qc_end end

[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] L"}]

[{"type":"physical unit","value":"3.33 L"}]

[{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{55.0 ℃}"},{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{3.60 L}"},{"type":"physical unit","value":"Temperature2 [OF] the gas [=] \\pu{30.0 ℃}"}]

<h1 class="questionTitle" itemprop="name">A gas at 55.0°C occupies a volume of 3.60 L. What volume will it occupy at 30.0°C?</h1>

3.33 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For an ideal gas</p> <blockquote> <blockquote> <p><mathjax>#"V ∝ T"#</mathjax></p> </blockquote> <p><mathjax>#"V"_2/"V"_1 = "T"_2/"T"_1#</mathjax></p> </blockquote> <ul> <li><mathjax>#"V"_1 = "3.60 L"#</mathjax></li> <li><mathjax>#"V"_2 = ?#</mathjax></li> <li><mathjax>#"T"_1 = "55.0°C" = "(55.0 + 273)K" = "328 K"#</mathjax></li> <li><mathjax>#"T"_2 = "30.0°C" = "(30.0 + 273)K" = "303 K"#</mathjax></li> </ul> <p><mathjax>#"V"_2 = "V"_1 × "T"_2/"T"_1 = "3.60 L" × (303 cancel"K")/(328 cancel"K") = "3.33 L"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"3.33 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For an ideal gas</p> <blockquote> <blockquote> <p><mathjax>#"V ∝ T"#</mathjax></p> </blockquote> <p><mathjax>#"V"_2/"V"_1 = "T"_2/"T"_1#</mathjax></p> </blockquote> <ul> <li><mathjax>#"V"_1 = "3.60 L"#</mathjax></li> <li><mathjax>#"V"_2 = ?#</mathjax></li> <li><mathjax>#"T"_1 = "55.0°C" = "(55.0 + 273)K" = "328 K"#</mathjax></li> <li><mathjax>#"T"_2 = "30.0°C" = "(30.0 + 273)K" = "303 K"#</mathjax></li> </ul> <p><mathjax>#"V"_2 = "V"_1 × "T"_2/"T"_1 = "3.60 L" × (303 cancel"K")/(328 cancel"K") = "3.33 L"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A gas at 55.0°C occupies a volume of 3.60 L. What volume will it occupy at 30.0°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/charles-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Charles' Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="581380" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/junaid-mirza"><img alt="" class="" src="https://profilepictures.socratic.org/BBeNx7NTQ7WmDQKll8wN_BDC9EDF4-5DCB-440D-8ADC-ADACE2966216.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/junaid-mirza"> Junaid Mirza </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-03-25T03:12:14" itemprop="dateCreated"> Mar 25, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"3.33 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For an ideal gas</p> <blockquote> <blockquote> <p><mathjax>#"V ∝ T"#</mathjax></p> </blockquote> <p><mathjax>#"V"_2/"V"_1 = "T"_2/"T"_1#</mathjax></p> </blockquote> <ul> <li><mathjax>#"V"_1 = "3.60 L"#</mathjax></li> <li><mathjax>#"V"_2 = ?#</mathjax></li> <li><mathjax>#"T"_1 = "55.0°C" = "(55.0 + 273)K" = "328 K"#</mathjax></li> <li><mathjax>#"T"_2 = "30.0°C" = "(30.0 + 273)K" = "303 K"#</mathjax></li> </ul> <p><mathjax>#"V"_2 = "V"_1 × "T"_2/"T"_1 = "3.60 L" × (303 cancel"K")/(328 cancel"K") = "3.33 L"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/581380" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-must-charles-law-be-in-kelvins"> Why must Charles' law be in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-charles-law-formula"> What is Charles' law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/oxygen-gas-is-at-a-temperature-of-40-c-when-it-occupies-a-volume-of-2-3-liters-t"> Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.3 liters. 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What will be volume of oxygen when the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/charles-law"> See all questions in Charles' Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7427 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A gas at 55.0°C occupies a volume of 3.60 L. What volume will it occupy at 30.0°C?

a967dde4-6ddd-11ea-99f3-ccda262736ce

https://socratic.org/questions/what-is-partial-pressure-of-oxygen-in-blood

100 mmHg

start physical_unit 5 7 partial_pressure mmhg qc_end substance 5 5 qc_end end

[{"type":"physical unit","value":"Partial pressure [OF] oxygen in blood [IN] mmHg"}]

[{"type":"physical unit","value":"100 mmHg"}]

[{"type":"substance name","value":"Oxygen"}]

<h1 class="questionTitle" itemprop="name">What is partial pressure of oxygen in blood? </h1>

100 mmHg

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Here's a simplified diagram if the respiratory system.</p> <p><img alt="Respiratory System" src="https://useruploads.socratic.org/erdEUmi0Qc2aZQQIe1fu_PO2%20Gradients_resize.jpg"/> <br/> (From <a href="http://www.studyblue.com" rel="nofollow" target="_blank">www.studyblue.com</a>)</p> <p>In <strong>ambient air</strong>, <mathjax>#P_"O₂"#</mathjax> = 160 mmHg.</p> <blockquote></blockquote> <p><strong>In the alveoli</strong></p> <p><mathjax>#P_"O₂"#</mathjax> in the alveoli is about 104 mmHg</p> <p>The <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> in the alveoli is less than <mathjax>#P_"O₂"#</mathjax> in ambient air because of the continual diffusion of oxygen into the alveolar capillaries.</p> <blockquote></blockquote> <p><strong>Leaving the alveolar capillaries</strong></p> <p>Oxygen diffuses from the alveoli into the alveolar capillaries. where <mathjax>#P_"O₂"#</mathjax> ≈ 100 mmHg.</p> <blockquote></blockquote> <p><strong>In the pulmonary veins</strong></p> <p>There is no gas diffusion through veins and arteries, so <mathjax>#P_"O₂"#</mathjax> is about 100 mmHg.</p> <blockquote></blockquote> <p><strong>Entering the systemic capillaries</strong></p> <p>Blood leaving pulmonary veins enters the left atrium and is pumped from the left ventricle into the systemic circulation.</p> <p>It enters the systemic capillaries with <mathjax>#P_"O₂"#</mathjax> at 80 - 100 mmHg.</p> <blockquote></blockquote> <p><strong>Leaving the systemic capillaries</strong></p> <p><mathjax>#P_"O₂"#</mathjax> in the body cells is less than 40 mmHg.</p> <p>Because <mathjax>#P_"O₂"#</mathjax> in the systemic capillaries is greater than the partial pressure in the body cells, oxygen diffuses from the blood and into the cells.</p> <p>Leaving the systemic capillaries, <mathjax>#P_"O₂"#</mathjax> = 40 - 50 mmHg.</p> <blockquote></blockquote> <p><strong>Entering the alveolar capillaries</strong></p> <p>Blood leaves the systemic capillaries and returns to the right atrium via veins. </p> <p>The right ventricle then pumps the blood to the alveolar capillaries, with <mathjax>#P_"O₂"#</mathjax> = 20 - 40 mmHg, and the cycle starts again.</p> <blockquote></blockquote> <p>Here's an interesting <a href="http://highered.mheducation.com/sites/0072507470/student_view0/chapter23/animation__changes_in_the_partial_pressures_of_oxygen_and_carbon_dioxide.html" rel="nofollow">animation</a> showing the changes in <mathjax>#P_"O₂"#</mathjax> and <mathjax>#P_"CO₂"#</mathjax> as the blood moves through the body.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_"O₂"#</mathjax> ≈ 100 mmHg in arterial blood, but it is different in other locations.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Here's a simplified diagram if the respiratory system.</p> <p><img alt="Respiratory System" src="https://useruploads.socratic.org/erdEUmi0Qc2aZQQIe1fu_PO2%20Gradients_resize.jpg"/> <br/> (From <a href="http://www.studyblue.com" rel="nofollow" target="_blank">www.studyblue.com</a>)</p> <p>In <strong>ambient air</strong>, <mathjax>#P_"O₂"#</mathjax> = 160 mmHg.</p> <blockquote></blockquote> <p><strong>In the alveoli</strong></p> <p><mathjax>#P_"O₂"#</mathjax> in the alveoli is about 104 mmHg</p> <p>The <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> in the alveoli is less than <mathjax>#P_"O₂"#</mathjax> in ambient air because of the continual diffusion of oxygen into the alveolar capillaries.</p> <blockquote></blockquote> <p><strong>Leaving the alveolar capillaries</strong></p> <p>Oxygen diffuses from the alveoli into the alveolar capillaries. where <mathjax>#P_"O₂"#</mathjax> ≈ 100 mmHg.</p> <blockquote></blockquote> <p><strong>In the pulmonary veins</strong></p> <p>There is no gas diffusion through veins and arteries, so <mathjax>#P_"O₂"#</mathjax> is about 100 mmHg.</p> <blockquote></blockquote> <p><strong>Entering the systemic capillaries</strong></p> <p>Blood leaving pulmonary veins enters the left atrium and is pumped from the left ventricle into the systemic circulation.</p> <p>It enters the systemic capillaries with <mathjax>#P_"O₂"#</mathjax> at 80 - 100 mmHg.</p> <blockquote></blockquote> <p><strong>Leaving the systemic capillaries</strong></p> <p><mathjax>#P_"O₂"#</mathjax> in the body cells is less than 40 mmHg.</p> <p>Because <mathjax>#P_"O₂"#</mathjax> in the systemic capillaries is greater than the partial pressure in the body cells, oxygen diffuses from the blood and into the cells.</p> <p>Leaving the systemic capillaries, <mathjax>#P_"O₂"#</mathjax> = 40 - 50 mmHg.</p> <blockquote></blockquote> <p><strong>Entering the alveolar capillaries</strong></p> <p>Blood leaves the systemic capillaries and returns to the right atrium via veins. </p> <p>The right ventricle then pumps the blood to the alveolar capillaries, with <mathjax>#P_"O₂"#</mathjax> = 20 - 40 mmHg, and the cycle starts again.</p> <blockquote></blockquote> <p>Here's an interesting <a href="http://highered.mheducation.com/sites/0072507470/student_view0/chapter23/animation__changes_in_the_partial_pressures_of_oxygen_and_carbon_dioxide.html" rel="nofollow">animation</a> showing the changes in <mathjax>#P_"O₂"#</mathjax> and <mathjax>#P_"CO₂"#</mathjax> as the blood moves through the body.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is partial pressure of oxygen in blood? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/partial-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Partial Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="299681" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-16T21:14:17" itemprop="dateCreated"> Aug 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_"O₂"#</mathjax> ≈ 100 mmHg in arterial blood, but it is different in other locations.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Here's a simplified diagram if the respiratory system.</p> <p><img alt="Respiratory System" src="https://useruploads.socratic.org/erdEUmi0Qc2aZQQIe1fu_PO2%20Gradients_resize.jpg"/> <br/> (From <a href="http://www.studyblue.com" rel="nofollow" target="_blank">www.studyblue.com</a>)</p> <p>In <strong>ambient air</strong>, <mathjax>#P_"O₂"#</mathjax> = 160 mmHg.</p> <blockquote></blockquote> <p><strong>In the alveoli</strong></p> <p><mathjax>#P_"O₂"#</mathjax> in the alveoli is about 104 mmHg</p> <p>The <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> in the alveoli is less than <mathjax>#P_"O₂"#</mathjax> in ambient air because of the continual diffusion of oxygen into the alveolar capillaries.</p> <blockquote></blockquote> <p><strong>Leaving the alveolar capillaries</strong></p> <p>Oxygen diffuses from the alveoli into the alveolar capillaries. where <mathjax>#P_"O₂"#</mathjax> ≈ 100 mmHg.</p> <blockquote></blockquote> <p><strong>In the pulmonary veins</strong></p> <p>There is no gas diffusion through veins and arteries, so <mathjax>#P_"O₂"#</mathjax> is about 100 mmHg.</p> <blockquote></blockquote> <p><strong>Entering the systemic capillaries</strong></p> <p>Blood leaving pulmonary veins enters the left atrium and is pumped from the left ventricle into the systemic circulation.</p> <p>It enters the systemic capillaries with <mathjax>#P_"O₂"#</mathjax> at 80 - 100 mmHg.</p> <blockquote></blockquote> <p><strong>Leaving the systemic capillaries</strong></p> <p><mathjax>#P_"O₂"#</mathjax> in the body cells is less than 40 mmHg.</p> <p>Because <mathjax>#P_"O₂"#</mathjax> in the systemic capillaries is greater than the partial pressure in the body cells, oxygen diffuses from the blood and into the cells.</p> <p>Leaving the systemic capillaries, <mathjax>#P_"O₂"#</mathjax> = 40 - 50 mmHg.</p> <blockquote></blockquote> <p><strong>Entering the alveolar capillaries</strong></p> <p>Blood leaves the systemic capillaries and returns to the right atrium via veins. </p> <p>The right ventricle then pumps the blood to the alveolar capillaries, with <mathjax>#P_"O₂"#</mathjax> = 20 - 40 mmHg, and the cycle starts again.</p> <blockquote></blockquote> <p>Here's an interesting <a href="http://highered.mheducation.com/sites/0072507470/student_view0/chapter23/animation__changes_in_the_partial_pressures_of_oxygen_and_carbon_dioxide.html" rel="nofollow">animation</a> showing the changes in <mathjax>#P_"O₂"#</mathjax> and <mathjax>#P_"CO₂"#</mathjax> as the blood moves through the body.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/299681" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534e256802bf342adfa30010"> How do you do a steam distillation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/53613f9f02bf3416cd9f8a34"> Question #f8a34 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-i-calculate-the-total-pressure-of-a-mixture-of-gases-by-adding-together-the-"> Can I calculate the total pressure of a mixture of gases by adding together the partial... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-formula-of-partial-pressure"> What is the formula of partial pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-dalton-s-law-of-partial-pressures"> What is the Dalton's law of partial pressures? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/nitrogen-gas-n2-reacts-with-hydrogen-gas-h2-to-form-ammonia-nh3-at-200-c-in-a-cl"> Nitrogen gas (N2) reacts with hydrogen gas (H2) to form ammonia (NH3). 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What is partial pressure of oxygen in blood?

a8e8e08c-6ddd-11ea-a122-ccda262736ce

https://socratic.org/questions/the-ratio-of-carbon-atoms-to-hydrogen-atoms-to-oxygen-atoms-in-a-molecule-of-dic

C16H24O4

start chemical_formula qc_end c_other OTHER qc_end physical_unit 15 16 33 34 molar_mass qc_end end

[{"type":"other","value":"Chemical Formula [OF] dicyclohexyl maleate [IN] molecular"}]

[{"type":"chemical equation","value":"C16H24O4"}]

[{"type":"other","value":"The ratio of carbon atoms to hydrogen atoms to oxygen atoms in a molecule of dicyclohexyl maleate is 4 to 6 to 1. "},{"type":"physical unit","value":"Molar mass [OF] dicyclohexyl maleate [=] \\pu{280 g}"}]

<h1 class="questionTitle" itemprop="name">The ratio of carbon atoms to hydrogen atoms to oxygen atoms in a molecule of dicyclohexyl maleate is 4 to 6 to 1. What is its molecular formula if its molar mass is 280 g? </h1>

C16H24O4

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We have been given an empirical formula of <mathjax>#C_4H_6O#</mathjax>. We know that the molecular formula is always a whole number multiple of the empirical formula. Thus <mathjax>#{4xx12.01+6xx1.01+16.0}xxn=280*g*mol^-1#</mathjax>. My arithmetic gives <mathjax>#n=4#</mathjax>. And thus the molecular formula is <mathjax>#C_16H_24O_4#</mathjax>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_16H_24O_4#</mathjax>.....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We have been given an empirical formula of <mathjax>#C_4H_6O#</mathjax>. We know that the molecular formula is always a whole number multiple of the empirical formula. Thus <mathjax>#{4xx12.01+6xx1.01+16.0}xxn=280*g*mol^-1#</mathjax>. My arithmetic gives <mathjax>#n=4#</mathjax>. And thus the molecular formula is <mathjax>#C_16H_24O_4#</mathjax>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">The ratio of carbon atoms to hydrogen atoms to oxygen atoms in a molecule of dicyclohexyl maleate is 4 to 6 to 1. What is its molecular formula if its molar mass is 280 g? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="427610" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-22T06:59:58" itemprop="dateCreated"> May 22, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_16H_24O_4#</mathjax>.....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We have been given an empirical formula of <mathjax>#C_4H_6O#</mathjax>. We know that the molecular formula is always a whole number multiple of the empirical formula. Thus <mathjax>#{4xx12.01+6xx1.01+16.0}xxn=280*g*mol^-1#</mathjax>. My arithmetic gives <mathjax>#n=4#</mathjax>. And thus the molecular formula is <mathjax>#C_16H_24O_4#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/427610" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 14973 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

The ratio of carbon atoms to hydrogen atoms to oxygen atoms in a molecule of dicyclohexyl maleate is 4 to 6 to 1. What is its molecular formula if its molar mass is 280 g?

aa4e22e4-6ddd-11ea-9de7-ccda262736ce

https://socratic.org/questions/if-40-0-ml-of-a-3-0x10-5-solution-is-diluted-to-100-ml-what-is-the-resulting-con

1.20 × 10^(-5) M

start physical_unit 9 9 concentration mol/l qc_end physical_unit 9 9 5 8 concentration qc_end physical_unit 9 9 1 2 volume qc_end physical_unit 9 9 13 14 volume qc_end end

[{"type":"physical unit","value":"Concentration2 [OF] the solution [IN] M"}]

[{"type":"physical unit","value":"1.20 × 10^(-5) M"}]

[{"type":"physical unit","value":"Concentration1 [OF] the solution [=] \\pu{3.0 × 10^(-5) M}"},{"type":"physical unit","value":"Volume1 [OF] the solution [=] \\pu{40.0 mL}"},{"type":"physical unit","value":"Volume2 [OF] the solution [=] \\pu{100 mL}"}]

<h1 class="questionTitle" itemprop="name">If 40.0 mL of a #3.0x10^(-5)# solution is diluted to 100 mL, what is the resulting concentration?</h1>

1.20 × 10^(-5) M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When a solution is diluted, the number of mole of particles in the solution does not change.</p> <p>The relationship between the number of mole <mathjax>#n#</mathjax> and the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> <mathjax>#M#</mathjax> is the following:</p> <p><mathjax>#M=n/V=&gt;n=MxxV#</mathjax></p> <p>where, <mathjax>#V#</mathjax> is the volume of the solution.</p> <p>If we consider that initially the volume and the molarity are:</p> <p><mathjax>#M_i=3.0xx10^(-5)M#</mathjax></p> <p><mathjax>#V_i=40 mL#</mathjax></p> <p>What would be the final molarity <mathjax>#M_f=?#</mathjax> when the final volume is <mathjax>#V_f=100mL#</mathjax>?</p> <p>since the number of mole does not change, we can write:</p> <p><mathjax>#M_ixxV_i=M_fxxV_f#</mathjax></p> <p><mathjax>#=&gt;M_f=(M_ixxV_i)/(V_f)=(3.0xx10^(-5)Mxx40cancel(mL))/(100cancel(mL))=1.2xx10^(-5)M#</mathjax></p> <p>Here is a video that discusses the solution preparation and dilution:<br/> <strong>Lab Demonstration | Solution Preparation &amp; Dilution.</strong><br/> <iframe src="https://www.youtube.com/embed/j_0JWjI2Yxs?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#M_f=1.2xx10^(-5)M#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When a solution is diluted, the number of mole of particles in the solution does not change.</p> <p>The relationship between the number of mole <mathjax>#n#</mathjax> and the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> <mathjax>#M#</mathjax> is the following:</p> <p><mathjax>#M=n/V=&gt;n=MxxV#</mathjax></p> <p>where, <mathjax>#V#</mathjax> is the volume of the solution.</p> <p>If we consider that initially the volume and the molarity are:</p> <p><mathjax>#M_i=3.0xx10^(-5)M#</mathjax></p> <p><mathjax>#V_i=40 mL#</mathjax></p> <p>What would be the final molarity <mathjax>#M_f=?#</mathjax> when the final volume is <mathjax>#V_f=100mL#</mathjax>?</p> <p>since the number of mole does not change, we can write:</p> <p><mathjax>#M_ixxV_i=M_fxxV_f#</mathjax></p> <p><mathjax>#=&gt;M_f=(M_ixxV_i)/(V_f)=(3.0xx10^(-5)Mxx40cancel(mL))/(100cancel(mL))=1.2xx10^(-5)M#</mathjax></p> <p>Here is a video that discusses the solution preparation and dilution:<br/> <strong>Lab Demonstration | Solution Preparation &amp; Dilution.</strong><br/> <iframe src="https://www.youtube.com/embed/j_0JWjI2Yxs?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If 40.0 mL of a #3.0x10^(-5)# solution is diluted to 100 mL, what is the resulting concentration?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/measuring-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Measuring Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="303005" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-26T17:36:12" itemprop="dateCreated"> Aug 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#M_f=1.2xx10^(-5)M#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When a solution is diluted, the number of mole of particles in the solution does not change.</p> <p>The relationship between the number of mole <mathjax>#n#</mathjax> and the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> <mathjax>#M#</mathjax> is the following:</p> <p><mathjax>#M=n/V=&gt;n=MxxV#</mathjax></p> <p>where, <mathjax>#V#</mathjax> is the volume of the solution.</p> <p>If we consider that initially the volume and the molarity are:</p> <p><mathjax>#M_i=3.0xx10^(-5)M#</mathjax></p> <p><mathjax>#V_i=40 mL#</mathjax></p> <p>What would be the final molarity <mathjax>#M_f=?#</mathjax> when the final volume is <mathjax>#V_f=100mL#</mathjax>?</p> <p>since the number of mole does not change, we can write:</p> <p><mathjax>#M_ixxV_i=M_fxxV_f#</mathjax></p> <p><mathjax>#=&gt;M_f=(M_ixxV_i)/(V_f)=(3.0xx10^(-5)Mxx40cancel(mL))/(100cancel(mL))=1.2xx10^(-5)M#</mathjax></p> <p>Here is a video that discusses the solution preparation and dilution:<br/> <strong>Lab Demonstration | Solution Preparation &amp; Dilution.</strong><br/> <iframe src="https://www.youtube.com/embed/j_0JWjI2Yxs?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/303005" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-concentration-from-absorbance"> How do you measure concentration from absorbance? 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If 40.0 mL of a #3.0x10^(-5)# solution is diluted to 100 mL, what is the resulting concentration?

acb76766-6ddd-11ea-9ffe-ccda262736ce

https://socratic.org/questions/what-is-the-mass-of-3-moles-of-c2h2

78.12 g

start physical_unit 8 8 mass g qc_end physical_unit 8 8 5 6 mole qc_end end

[{"type":"physical unit","value":"Mass [OF] C2H2 [IN] g"}]

[{"type":"physical unit","value":"78.12 g"}]

[{"type":"physical unit","value":"Mole [OF] C2H2 [=] \\pu{3 moles}"}]

<h1 class="questionTitle" itemprop="name">What is the mass of 3 moles of #"C"_2"H"_2# ? </h1>

78.12 g

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Every mole of <mathjax>#"C"_2"H"_2#</mathjax> (acetylene) has a mass of <mathjax>#"26.04 g"#</mathjax>, i.e. acetylene has a molar mass of <mathjax>#"26.04 g/mol"#</mathjax>.</p> <p>Thus, </p> <p><mathjax>#"26.04 g/mol " * " 3 mol"#</mathjax> </p> <p>gives you the mass of <mathjax>#3#</mathjax> moles, <mathjax>#"78 g"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"78 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Every mole of <mathjax>#"C"_2"H"_2#</mathjax> (acetylene) has a mass of <mathjax>#"26.04 g"#</mathjax>, i.e. acetylene has a molar mass of <mathjax>#"26.04 g/mol"#</mathjax>.</p> <p>Thus, </p> <p><mathjax>#"26.04 g/mol " * " 3 mol"#</mathjax> </p> <p>gives you the mass of <mathjax>#3#</mathjax> moles, <mathjax>#"78 g"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the mass of 3 moles of #"C"_2"H"_2# ? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">3</span> Answers </h5> <div class="answers"> <div class="answer" id="558833" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/chemistryiseasy"><img alt="" class="" src="https://profilepictures.socratic.org/4fHM3b7QOmEbzwTsJOqU_Paints3.png" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/chemistryiseasy"> ChemistryIsEasy </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-02-26T17:46:29" itemprop="dateCreated"> Feb 26, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"78 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Every mole of <mathjax>#"C"_2"H"_2#</mathjax> (acetylene) has a mass of <mathjax>#"26.04 g"#</mathjax>, i.e. acetylene has a molar mass of <mathjax>#"26.04 g/mol"#</mathjax>.</p> <p>Thus, </p> <p><mathjax>#"26.04 g/mol " * " 3 mol"#</mathjax> </p> <p>gives you the mass of <mathjax>#3#</mathjax> moles, <mathjax>#"78 g"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/558833" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="558836" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/sahar-1"><img alt="" class="" src="https://profilepictures.socratic.org/DngTNrTHQgWGqJMBtGGy_Screenshot%20%28182%29.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/sahar-1"> Sahar Mulla ❤ </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-02-26T17:50:17" itemprop="dateCreated"> Feb 26, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><p>Molar mass of <mathjax>#C_2H_2 =&gt; 26g#</mathjax>, that's the mass of 1 mole.</p> <p>Therefore, mass of 3 moles of <mathjax>#C_2H_2#</mathjax> would be <mathjax>#26 xx 3 = color(red)(78g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/558836" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="559079" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nam-d"><img alt="" class="" src="https://profilepictures.socratic.org/QG4MnkoER6u99DIDVWKK_787554714770341.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nam-d"> Nam D. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-02-27T00:25:53" itemprop="dateCreated"> Feb 27, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#78 \ "g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Acetylene <mathjax>#(C_2H_2)#</mathjax> has a molar mass of <mathjax>#26.04 \ "g/mol"#</mathjax>.</p> <p>To find out the mass of moles, we have to multiply the number of moles by the molar mass of the substance, i.e. we can form an equation like this:</p> <p><mathjax>#"mass"="moles"*"molar mass"#</mathjax></p> <p>So, the mass of three moles of acetylene is</p> <p><mathjax>#"mass"_(C_2H_2)=3color(red)cancelcolor(black)"mol"*(26.04 \ "g")/(color(red)cancelcolor(black)"mol")=78.12 \ "g"#</mathjax></p> <p>Now, we can round off to the nearest whole number to make the answer more reasonable, so it'll be</p> <p><mathjax>#78.12 \ "g"~~78 \ "g"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/559079" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9372 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the mass of 3 moles of #"C"_2"H"_2# ?

ac9049b1-6ddd-11ea-bedf-ccda262736ce

https://socratic.org/questions/a-compound-is-found-to-contain-1-32-moles-of-li-0-66-moles-of-se-and-2-64-moles-

Li2SeO4

start chemical_formula qc_end physical_unit 9 9 6 7 mole qc_end physical_unit 13 13 10 11 mole qc_end physical_unit 18 18 15 16 mole qc_end end

[{"type":"other","value":"Chemical Formula [OF] the compound [IN] empirical"}]

[{"type":"chemical equation","value":"Li2SeO4"}]

[{"type":"physical unit","value":"Mole [OF] Li [=] \\pu{1.32 moles}"},{"type":"physical unit","value":"Mole [OF] Se [=] \\pu{0.66 moles}"},{"type":"physical unit","value":"Mole [OF] O [=] \\pu{2.64 moles}"}]

<h1 class="questionTitle" itemprop="name">A compound is found to contain 1.32 moles of Li, 0.66 moles of Se, and 2.64 moles of O. What is the empirical formula of the compound?</h1>

Li2SeO4

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula is the SIMPLEST whole number ratio that defines constituent atoms in a species. If we divide the given molar quantities, by the LEAST molar quantity (that of selenium), we get the empirical formula above. </p> <p><mathjax>#Li_2SeO_4#</mathjax> is clearly ionic, and non-molecular (<mathjax>#SeO_4^(2-)#</mathjax> is an analogue of the sulfate ion, <mathjax>#SO_4^(2-)#</mathjax>). Typically with these problems you are asked to provide the empirical formula, and then asked to provide the molecular formula given a molecular mass. The molecular formula is always a multiple of the empirical formula: <mathjax>#MF#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(EF)_n#</mathjax>. Of course, the molecular formula might be the same as the empirical formula; in which case <mathjax>#n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Li_2SeO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula is the SIMPLEST whole number ratio that defines constituent atoms in a species. If we divide the given molar quantities, by the LEAST molar quantity (that of selenium), we get the empirical formula above. </p> <p><mathjax>#Li_2SeO_4#</mathjax> is clearly ionic, and non-molecular (<mathjax>#SeO_4^(2-)#</mathjax> is an analogue of the sulfate ion, <mathjax>#SO_4^(2-)#</mathjax>). Typically with these problems you are asked to provide the empirical formula, and then asked to provide the molecular formula given a molecular mass. The molecular formula is always a multiple of the empirical formula: <mathjax>#MF#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(EF)_n#</mathjax>. Of course, the molecular formula might be the same as the empirical formula; in which case <mathjax>#n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A compound is found to contain 1.32 moles of Li, 0.66 moles of Se, and 2.64 moles of O. What is the empirical formula of the compound?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="215053" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-21T13:21:54" itemprop="dateCreated"> Jan 21, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Li_2SeO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula is the SIMPLEST whole number ratio that defines constituent atoms in a species. If we divide the given molar quantities, by the LEAST molar quantity (that of selenium), we get the empirical formula above. </p> <p><mathjax>#Li_2SeO_4#</mathjax> is clearly ionic, and non-molecular (<mathjax>#SeO_4^(2-)#</mathjax> is an analogue of the sulfate ion, <mathjax>#SO_4^(2-)#</mathjax>). Typically with these problems you are asked to provide the empirical formula, and then asked to provide the molecular formula given a molecular mass. The molecular formula is always a multiple of the empirical formula: <mathjax>#MF#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(EF)_n#</mathjax>. Of course, the molecular formula might be the same as the empirical formula; in which case <mathjax>#n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/215053" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3139 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A compound is found to contain 1.32 moles of Li, 0.66 moles of Se, and 2.64 moles of O. What is the empirical formula of the compound?

ac5e4c70-6ddd-11ea-b726-ccda262736ce

https://socratic.org/questions/in-the-reaction-zn-2hcl-zncl-2-h-2-how-many-moles-of-hydrogen-will-be-formed-whe

2.00 moles

start physical_unit 15 15 mole mol qc_end physical_unit 6 6 20 21 mole qc_end chemical_equation 3 10 qc_end end

[{"type":"physical unit","value":"Mole [OF] hydrogen [IN] moles"}]

[{"type":"physical unit","value":"2.00 moles"}]

[{"type":"physical unit","value":"Mole [OF] HCl [=] \\pu{4 moles}"},{"type":"chemical equation","value":"Zn + 2 HCl -> ZnCl2 + H2"}]

<h1 class="questionTitle" itemprop="name">In the reaction #Zn + 2HCl -&gt; ZnCl_2 + H_2#, how many moles of hydrogen will be formed when 4 moles of #HCl# are consumed?</h1>

2.00 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your tool of choice here will be the <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> that exists between zinc metal, <mathjax>#"Zn"#</mathjax>, and hydrochloric acid, <mathjax>#":HCl"#</mathjax>, in the balanced chemical equation. </p> <blockquote> <p><mathjax>#"Zn"_text((s]) + color(red)(2)"HCl"_text((aq]) -&gt; "ZnCl"_text(2(aq]) + "H"_text(2(g]) uarr#</mathjax></p> </blockquote> <p>You're dealing with a <a href="http://socratic.org/chemistry/chemical-reactions/single-replacement-reactions">single replacement reaction</a> in which zinc displaces the hydrogen from hydrochloric acid. The products of the reaction are aqueous zinc chloride and hydrogen gas. </p> <p>Now, as you can see from the balance chemical equation, a <mathjax>#1:color(red)(2)#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> exists between the two reactants. </p> <p>This tells you that in order for the reaction to take place, you need to have <strong>twice as many</strong> moles of hydrochloric acid as you do of zinc metal. </p> <p><img alt="http://people.springfield.k12.or.us/jim.tyser/chemcom/Resources/unit1ans.html" src="https://useruploads.socratic.org/MXUaxaK9SYGUz3PgZhd1_ZnHCl.gif"/> </p> <p>At the same time, you have a <mathjax>#color(red)(2):1#</mathjax> mole ratio between hydrochloric acid and hydrogen gas. </p> <p>This means that the reaction will always produce <strong>half as many</strong> moles of hydrogen gas as you have moles of hydrochloric acid. </p> <p>Since you know that <mathjax>#4#</mathjax> moles of hydrochloric acid are taking part in the reaction, and assuming that you have <em>enough</em> zinc metal so that it doesn't act as a <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>, you can say that the reaction will produce</p> <blockquote> <p><mathjax>#4 color(red)(cancel(color(black)("moles HCl"))) * "1 mole H"_2/(color(red)(2)color(red)(cancel(color(black)("moles HCl")))) = color(green)("2 moles H"_2)#</mathjax></p> </blockquote> <p> <iframe src="https://www.youtube.com/embed/UpjpQ34DZlQ?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2 moles H"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your tool of choice here will be the <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> that exists between zinc metal, <mathjax>#"Zn"#</mathjax>, and hydrochloric acid, <mathjax>#":HCl"#</mathjax>, in the balanced chemical equation. </p> <blockquote> <p><mathjax>#"Zn"_text((s]) + color(red)(2)"HCl"_text((aq]) -&gt; "ZnCl"_text(2(aq]) + "H"_text(2(g]) uarr#</mathjax></p> </blockquote> <p>You're dealing with a <a href="http://socratic.org/chemistry/chemical-reactions/single-replacement-reactions">single replacement reaction</a> in which zinc displaces the hydrogen from hydrochloric acid. The products of the reaction are aqueous zinc chloride and hydrogen gas. </p> <p>Now, as you can see from the balance chemical equation, a <mathjax>#1:color(red)(2)#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> exists between the two reactants. </p> <p>This tells you that in order for the reaction to take place, you need to have <strong>twice as many</strong> moles of hydrochloric acid as you do of zinc metal. </p> <p><img alt="http://people.springfield.k12.or.us/jim.tyser/chemcom/Resources/unit1ans.html" src="https://useruploads.socratic.org/MXUaxaK9SYGUz3PgZhd1_ZnHCl.gif"/> </p> <p>At the same time, you have a <mathjax>#color(red)(2):1#</mathjax> mole ratio between hydrochloric acid and hydrogen gas. </p> <p>This means that the reaction will always produce <strong>half as many</strong> moles of hydrogen gas as you have moles of hydrochloric acid. </p> <p>Since you know that <mathjax>#4#</mathjax> moles of hydrochloric acid are taking part in the reaction, and assuming that you have <em>enough</em> zinc metal so that it doesn't act as a <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>, you can say that the reaction will produce</p> <blockquote> <p><mathjax>#4 color(red)(cancel(color(black)("moles HCl"))) * "1 mole H"_2/(color(red)(2)color(red)(cancel(color(black)("moles HCl")))) = color(green)("2 moles H"_2)#</mathjax></p> </blockquote> <p> <iframe src="https://www.youtube.com/embed/UpjpQ34DZlQ?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">In the reaction #Zn + 2HCl -&gt; ZnCl_2 + H_2#, how many moles of hydrogen will be formed when 4 moles of #HCl# are consumed?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="212534" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-14T22:59:45" itemprop="dateCreated"> Jan 14, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2 moles H"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your tool of choice here will be the <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> that exists between zinc metal, <mathjax>#"Zn"#</mathjax>, and hydrochloric acid, <mathjax>#":HCl"#</mathjax>, in the balanced chemical equation. </p> <blockquote> <p><mathjax>#"Zn"_text((s]) + color(red)(2)"HCl"_text((aq]) -&gt; "ZnCl"_text(2(aq]) + "H"_text(2(g]) uarr#</mathjax></p> </blockquote> <p>You're dealing with a <a href="http://socratic.org/chemistry/chemical-reactions/single-replacement-reactions">single replacement reaction</a> in which zinc displaces the hydrogen from hydrochloric acid. The products of the reaction are aqueous zinc chloride and hydrogen gas. </p> <p>Now, as you can see from the balance chemical equation, a <mathjax>#1:color(red)(2)#</mathjax> <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> exists between the two reactants. </p> <p>This tells you that in order for the reaction to take place, you need to have <strong>twice as many</strong> moles of hydrochloric acid as you do of zinc metal. </p> <p><img alt="http://people.springfield.k12.or.us/jim.tyser/chemcom/Resources/unit1ans.html" src="https://useruploads.socratic.org/MXUaxaK9SYGUz3PgZhd1_ZnHCl.gif"/> </p> <p>At the same time, you have a <mathjax>#color(red)(2):1#</mathjax> mole ratio between hydrochloric acid and hydrogen gas. </p> <p>This means that the reaction will always produce <strong>half as many</strong> moles of hydrogen gas as you have moles of hydrochloric acid. </p> <p>Since you know that <mathjax>#4#</mathjax> moles of hydrochloric acid are taking part in the reaction, and assuming that you have <em>enough</em> zinc metal so that it doesn't act as a <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>, you can say that the reaction will produce</p> <blockquote> <p><mathjax>#4 color(red)(cancel(color(black)("moles HCl"))) * "1 mole H"_2/(color(red)(2)color(red)(cancel(color(black)("moles HCl")))) = color(green)("2 moles H"_2)#</mathjax></p> </blockquote> <p> <iframe src="https://www.youtube.com/embed/UpjpQ34DZlQ?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/212534" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179102bf3469517a1072"> Question #a1072 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179402bf34694c8c5bf1"> Question #c5bf1 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179702bf3469588dc373"> Question #dc373 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179c02bf34694c8c5bf9"> Question #c5bf9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417a302bf3469517a1076"> Question #a1076 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417c702bf3469588dc377"> Question #dc377 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d002bf346963eb984f"> Question #b984f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d402bf346950519ea3"> Question #19ea3 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/mole-ratios"> See all questions in Mole Ratios </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 185330 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

In the reaction #Zn + 2HCl -&gt; ZnCl_2 + H_2#, how many moles of hydrogen will be formed when 4 moles of #HCl# are consumed?

a8dd9ce2-6ddd-11ea-adfc-ccda262736ce

https://socratic.org/questions/what-is-the-ph-of-a-5-00-x-10-2-m-aqueous-solution-of-ba-oh-2

13

start physical_unit 11 11 ph none qc_end end

[{"type":"physical unit","value":"pH [OF] Ba(OH)2 aqueous solution"}]

[{"type":"physical unit","value":"13"}]

[{"type":"physical unit","value":"Molarity [OF] Ba(OH)2 aqueous solution [=] \\pu{5.00 × 10^(−2) M}"}]

<h1 class="questionTitle" itemprop="name">What is the pH of a #5.00 x 10^-2# M aqueous solution of #Ba(OH)_2#?</h1>

13

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We know that in water under standard conditions, <mathjax>#pH+pOH=14#</mathjax>.</p> <p>Now for <mathjax>#5.00xx10^-2*mol*L^-1#</mathjax> <mathjax>#Ba(OH)_2#</mathjax>, <mathjax>#[HO^-]=0.100*mol*L^-1#</mathjax>; and thus <mathjax>#pOH=-log_10[HO^-]#</mathjax> <mathjax>#=-log_10(10^-1)=1#</mathjax>. And thus <mathjax>#pH=13#</mathjax>.</p> <p>For another example see <a href="https://socratic.org/questions/what-is-the-ph-of-a-1-00-x-10-4-m-solution-of-lithium-hydroxide-solution#306871">this linky.</a> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=13#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We know that in water under standard conditions, <mathjax>#pH+pOH=14#</mathjax>.</p> <p>Now for <mathjax>#5.00xx10^-2*mol*L^-1#</mathjax> <mathjax>#Ba(OH)_2#</mathjax>, <mathjax>#[HO^-]=0.100*mol*L^-1#</mathjax>; and thus <mathjax>#pOH=-log_10[HO^-]#</mathjax> <mathjax>#=-log_10(10^-1)=1#</mathjax>. And thus <mathjax>#pH=13#</mathjax>.</p> <p>For another example see <a href="https://socratic.org/questions/what-is-the-ph-of-a-1-00-x-10-4-m-solution-of-lithium-hydroxide-solution#306871">this linky.</a> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the pH of a #5.00 x 10^-2# M aqueous solution of #Ba(OH)_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="414169" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-28T02:42:58" itemprop="dateCreated"> Apr 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=13#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We know that in water under standard conditions, <mathjax>#pH+pOH=14#</mathjax>.</p> <p>Now for <mathjax>#5.00xx10^-2*mol*L^-1#</mathjax> <mathjax>#Ba(OH)_2#</mathjax>, <mathjax>#[HO^-]=0.100*mol*L^-1#</mathjax>; and thus <mathjax>#pOH=-log_10[HO^-]#</mathjax> <mathjax>#=-log_10(10^-1)=1#</mathjax>. And thus <mathjax>#pH=13#</mathjax>.</p> <p>For another example see <a href="https://socratic.org/questions/what-is-the-ph-of-a-1-00-x-10-4-m-solution-of-lithium-hydroxide-solution#306871">this linky.</a> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/414169" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-at-an-equivalence-point"> How do you determine pH at an equivalence point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-molarity"> How do you determine pH from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-alkalinity-mean"> What does alkalinity mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-base"> What is a base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-acid-base-indicators-change-color"> How do acid base indicators change color? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-neutral-ph"> What is a neutral pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-alkalinity-affect-pool-water"> How does alkalinity affect pool water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-important-in-drinking-water"> Why is pH important in drinking water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-ph-of-solution"> How can I calculate the pH of a solution? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2448 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the pH of a #5.00 x 10^-2# M aqueous solution of #Ba(OH)_2#?

ac3a6966-6ddd-11ea-8a80-ccda262736ce

https://socratic.org/questions/what-is-the-molecular-formula-of-a-substance-that-has-an-empirical-formula-of-c2

C4H10

start chemical_formula qc_end c_other OTHER qc_end physical_unit 7 7 20 21 molecular_weight qc_end end

[{"type":"other","value":"Chemical Formula [OF] the substance [IN] molecular"}]

[{"type":"chemical equation","value":"C4H10"}]

[{"type":"other","value":"The substance has an empirical formula of C2H5."},{"type":"physical unit","value":"Molecular mass [OF] the substance [=] \\pu{58 g/mole}"}]

<h1 class="questionTitle" itemprop="name">What is the molecular formula of a substance that has an empirical formula of C2H5 and a molecular mass of 58 g/mole?</h1>

C4H10

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So <mathjax>#MF=(EF)xxn#</mathjax>. Thus <mathjax>#[2xx12.011*g*mol^(-1)+ 5xx1.00794*g*mol^(-1)]xxn=58*g*mol^(-1).#</mathjax></p> <p>It does not take much algebra to find that <mathjax>#n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2#</mathjax>.</p> <p>Thus the molecular formula <mathjax>#=#</mathjax> <mathjax>#2xxC_2H_5#</mathjax> <mathjax>#=#</mathjax> <mathjax>#C_4H_10#</mathjax>, butane.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The empirical formula is always a multiple of the empirical formula, but remember the multiple may be <mathjax>#1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So <mathjax>#MF=(EF)xxn#</mathjax>. Thus <mathjax>#[2xx12.011*g*mol^(-1)+ 5xx1.00794*g*mol^(-1)]xxn=58*g*mol^(-1).#</mathjax></p> <p>It does not take much algebra to find that <mathjax>#n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2#</mathjax>.</p> <p>Thus the molecular formula <mathjax>#=#</mathjax> <mathjax>#2xxC_2H_5#</mathjax> <mathjax>#=#</mathjax> <mathjax>#C_4H_10#</mathjax>, butane.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the molecular formula of a substance that has an empirical formula of C2H5 and a molecular mass of 58 g/mole?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="188452" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-14T16:39:56" itemprop="dateCreated"> Nov 14, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The empirical formula is always a multiple of the empirical formula, but remember the multiple may be <mathjax>#1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So <mathjax>#MF=(EF)xxn#</mathjax>. Thus <mathjax>#[2xx12.011*g*mol^(-1)+ 5xx1.00794*g*mol^(-1)]xxn=58*g*mol^(-1).#</mathjax></p> <p>It does not take much algebra to find that <mathjax>#n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2#</mathjax>.</p> <p>Thus the molecular formula <mathjax>#=#</mathjax> <mathjax>#2xxC_2H_5#</mathjax> <mathjax>#=#</mathjax> <mathjax>#C_4H_10#</mathjax>, butane.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/188452" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 37252 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the molecular formula of a substance that has an empirical formula of C2H5 and a molecular mass of 58 g/mole?

abd6b704-6ddd-11ea-9462-ccda262736ce

https://socratic.org/questions/what-is-the-reduction-half-reaction-for-2mg-o-2-2mgo

O2 + 4 e- -> 2 O^2-

start chemical_equation qc_end chemical_equation 6 12 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the reduction half-reaction"}]

[{"type":"chemical equation","value":"O2 + 4 e- -> 2 O^2-"}]

[{"type":"chemical equation","value":"2 Mg + O2 -> 2 MgO"}]

<h1 class="questionTitle" itemprop="name">What is the reduction half-reaction for #2Mg + O_2 -&gt; 2MgO#?</h1>

O2 + 4 e- -> 2 O^2-

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by assigning <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> to all the atoms that take part in the reaction--it's actually a good idea to start with the <em>unbalanced</em> chemical equation</p> <blockquote> <p><mathjax>#stackrel(color(blue)(0))("Mg")_ ((s)) + stackrel(color(blue)(0))("O") _ (2(g)) -&gt; stackrel(color(blue)(+2))("Mg")stackrel(color(blue)(-2))("O")_ ((s))#</mathjax></p> </blockquote> <p>Now, notice that the oxidation state of oxygen goes from <mathjax>#color(blue)(0)#</mathjax> on the reactants' side to <mathjax>#color(blue)(-2)#</mathjax> on the products' side, which means that oxygen is being <strong>reduced</strong>.</p> <p>The <em>reduction half-reaction</em> will look like this</p> <blockquote> <p><mathjax>#stackrel(color(blue)(0))("O") _ 2 + 4"e"^(-) -&gt; 2stackrel(color(blue)(-2))("O") ""^(2-)#</mathjax></p> </blockquote> <p>Here every atom of oxygen takes in <mathjax>#2#</mathjax> <strong>electrons</strong>, which means that a molecule of oxygen will take in <mathjax>#4#</mathjax> <strong>electrons</strong>. </p> <p>Notice that the charge is balanced because you have</p> <blockquote> <p><mathjax>#2 xx 0 + 4 xx (1-) = 2 xx (2-)#</mathjax></p> </blockquote> <p>On the other hand, the oxidation state of magnesium is going from <mathjax>#color(blue)(0)#</mathjax> on the reactants' side to <mathjax>#color(blue)(+2)#</mathjax> on the products' side, which means that magnesium is being <strong>oxidized</strong>. </p> <p>The <em>oxidation half-reaction</em> will look like this</p> <blockquote> <p><mathjax>#stackrel(color(blue)(0))("Mg") -&gt; stackrel(color(blue)(+2))("Mg") ""^(2+) + 2"e"^(-)#</mathjax></p> </blockquote> <p>Here every atom of magnesium loses <mathjax>#2#</mathjax> <strong>electrons</strong>. The charge is balanced because you have</p> <blockquote> <p><mathjax>#0 = (2+) + 2 xx (1-)#</mathjax></p> </blockquote> <p>Now, to get the balanced chemical equation, multiply the oxidation half-reaction by <mathjax>#2#</mathjax> to get <strong>equal numbers</strong> of electrons lost in oxidation half-reaction and gained in the reduction half-reaction.</p> <blockquote> <p><mathjax>#color(white)(a)stackrel(color(blue)(0))("Mg") -&gt; stackrel(color(blue)(+2))("Mg") ""^(2+) + 2"e"^(-)" " |xx 2#</mathjax></p> <p><mathjax>#2stackrel(color(blue)(0))("Mg") -&gt; 2stackrel(color(blue)(+2))("Mg") ""^(2+) + 4"e"^(-)#</mathjax></p> </blockquote> <p>Now add the two half-reactions to get</p> <blockquote> <p><mathjax>#stackrel(color(blue)(0))("O") _ 2 + 4"e"^(-) -&gt; 2stackrel(color(blue)(-2))("O") ""^(2-)#</mathjax><br/> <mathjax>#color(white)(aaaa)2stackrel(color(blue)(0))("Mg") -&gt; 2stackrel(color(blue)(+2))("Mg") ""^(2+) + 4"e"^(-)#</mathjax><br/> <mathjax>#color(white)(aaaaaaaaaaaaaaaaaaaaaaa)/color(white)(a)#</mathjax></p> <p><mathjax>#stackrel(color(blue)(0))("O") _ 2 + color(red)(cancel(color(black)(4"e"^(-)))) + 2stackrel(color(blue)(0))("Mg") -&gt; 2stackrel(color(blue)(-2))("O") ""^(2-) + 2stackrel(color(blue)(+2))("Mg") ""^(2+) + color(red)(cancel(color(black)(4"e"^(-))))#</mathjax></p> </blockquote> <p>which is equivalent to </p> <blockquote> <p><mathjax>#2"Mg"_ ((s)) + "O"_ (2(g)) -&gt; 2"MgO"_ ((s))#</mathjax></p> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"O"_ 2 + 4"e"^(-) -&gt; 2"O"^(2-)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by assigning <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> to all the atoms that take part in the reaction--it's actually a good idea to start with the <em>unbalanced</em> chemical equation</p> <blockquote> <p><mathjax>#stackrel(color(blue)(0))("Mg")_ ((s)) + stackrel(color(blue)(0))("O") _ (2(g)) -&gt; stackrel(color(blue)(+2))("Mg")stackrel(color(blue)(-2))("O")_ ((s))#</mathjax></p> </blockquote> <p>Now, notice that the oxidation state of oxygen goes from <mathjax>#color(blue)(0)#</mathjax> on the reactants' side to <mathjax>#color(blue)(-2)#</mathjax> on the products' side, which means that oxygen is being <strong>reduced</strong>.</p> <p>The <em>reduction half-reaction</em> will look like this</p> <blockquote> <p><mathjax>#stackrel(color(blue)(0))("O") _ 2 + 4"e"^(-) -&gt; 2stackrel(color(blue)(-2))("O") ""^(2-)#</mathjax></p> </blockquote> <p>Here every atom of oxygen takes in <mathjax>#2#</mathjax> <strong>electrons</strong>, which means that a molecule of oxygen will take in <mathjax>#4#</mathjax> <strong>electrons</strong>. </p> <p>Notice that the charge is balanced because you have</p> <blockquote> <p><mathjax>#2 xx 0 + 4 xx (1-) = 2 xx (2-)#</mathjax></p> </blockquote> <p>On the other hand, the oxidation state of magnesium is going from <mathjax>#color(blue)(0)#</mathjax> on the reactants' side to <mathjax>#color(blue)(+2)#</mathjax> on the products' side, which means that magnesium is being <strong>oxidized</strong>. </p> <p>The <em>oxidation half-reaction</em> will look like this</p> <blockquote> <p><mathjax>#stackrel(color(blue)(0))("Mg") -&gt; stackrel(color(blue)(+2))("Mg") ""^(2+) + 2"e"^(-)#</mathjax></p> </blockquote> <p>Here every atom of magnesium loses <mathjax>#2#</mathjax> <strong>electrons</strong>. The charge is balanced because you have</p> <blockquote> <p><mathjax>#0 = (2+) + 2 xx (1-)#</mathjax></p> </blockquote> <p>Now, to get the balanced chemical equation, multiply the oxidation half-reaction by <mathjax>#2#</mathjax> to get <strong>equal numbers</strong> of electrons lost in oxidation half-reaction and gained in the reduction half-reaction.</p> <blockquote> <p><mathjax>#color(white)(a)stackrel(color(blue)(0))("Mg") -&gt; stackrel(color(blue)(+2))("Mg") ""^(2+) + 2"e"^(-)" " |xx 2#</mathjax></p> <p><mathjax>#2stackrel(color(blue)(0))("Mg") -&gt; 2stackrel(color(blue)(+2))("Mg") ""^(2+) + 4"e"^(-)#</mathjax></p> </blockquote> <p>Now add the two half-reactions to get</p> <blockquote> <p><mathjax>#stackrel(color(blue)(0))("O") _ 2 + 4"e"^(-) -&gt; 2stackrel(color(blue)(-2))("O") ""^(2-)#</mathjax><br/> <mathjax>#color(white)(aaaa)2stackrel(color(blue)(0))("Mg") -&gt; 2stackrel(color(blue)(+2))("Mg") ""^(2+) + 4"e"^(-)#</mathjax><br/> <mathjax>#color(white)(aaaaaaaaaaaaaaaaaaaaaaa)/color(white)(a)#</mathjax></p> <p><mathjax>#stackrel(color(blue)(0))("O") _ 2 + color(red)(cancel(color(black)(4"e"^(-)))) + 2stackrel(color(blue)(0))("Mg") -&gt; 2stackrel(color(blue)(-2))("O") ""^(2-) + 2stackrel(color(blue)(+2))("Mg") ""^(2+) + color(red)(cancel(color(black)(4"e"^(-))))#</mathjax></p> </blockquote> <p>which is equivalent to </p> <blockquote> <p><mathjax>#2"Mg"_ ((s)) + "O"_ (2(g)) -&gt; 2"MgO"_ ((s))#</mathjax></p> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the reduction half-reaction for #2Mg + O_2 -&gt; 2MgO#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-and-reduction-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation and Reduction Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="438339" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-12T01:51:58" itemprop="dateCreated"> Jun 12, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"O"_ 2 + 4"e"^(-) -&gt; 2"O"^(2-)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by assigning <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> to all the atoms that take part in the reaction--it's actually a good idea to start with the <em>unbalanced</em> chemical equation</p> <blockquote> <p><mathjax>#stackrel(color(blue)(0))("Mg")_ ((s)) + stackrel(color(blue)(0))("O") _ (2(g)) -&gt; stackrel(color(blue)(+2))("Mg")stackrel(color(blue)(-2))("O")_ ((s))#</mathjax></p> </blockquote> <p>Now, notice that the oxidation state of oxygen goes from <mathjax>#color(blue)(0)#</mathjax> on the reactants' side to <mathjax>#color(blue)(-2)#</mathjax> on the products' side, which means that oxygen is being <strong>reduced</strong>.</p> <p>The <em>reduction half-reaction</em> will look like this</p> <blockquote> <p><mathjax>#stackrel(color(blue)(0))("O") _ 2 + 4"e"^(-) -&gt; 2stackrel(color(blue)(-2))("O") ""^(2-)#</mathjax></p> </blockquote> <p>Here every atom of oxygen takes in <mathjax>#2#</mathjax> <strong>electrons</strong>, which means that a molecule of oxygen will take in <mathjax>#4#</mathjax> <strong>electrons</strong>. </p> <p>Notice that the charge is balanced because you have</p> <blockquote> <p><mathjax>#2 xx 0 + 4 xx (1-) = 2 xx (2-)#</mathjax></p> </blockquote> <p>On the other hand, the oxidation state of magnesium is going from <mathjax>#color(blue)(0)#</mathjax> on the reactants' side to <mathjax>#color(blue)(+2)#</mathjax> on the products' side, which means that magnesium is being <strong>oxidized</strong>. </p> <p>The <em>oxidation half-reaction</em> will look like this</p> <blockquote> <p><mathjax>#stackrel(color(blue)(0))("Mg") -&gt; stackrel(color(blue)(+2))("Mg") ""^(2+) + 2"e"^(-)#</mathjax></p> </blockquote> <p>Here every atom of magnesium loses <mathjax>#2#</mathjax> <strong>electrons</strong>. The charge is balanced because you have</p> <blockquote> <p><mathjax>#0 = (2+) + 2 xx (1-)#</mathjax></p> </blockquote> <p>Now, to get the balanced chemical equation, multiply the oxidation half-reaction by <mathjax>#2#</mathjax> to get <strong>equal numbers</strong> of electrons lost in oxidation half-reaction and gained in the reduction half-reaction.</p> <blockquote> <p><mathjax>#color(white)(a)stackrel(color(blue)(0))("Mg") -&gt; stackrel(color(blue)(+2))("Mg") ""^(2+) + 2"e"^(-)" " |xx 2#</mathjax></p> <p><mathjax>#2stackrel(color(blue)(0))("Mg") -&gt; 2stackrel(color(blue)(+2))("Mg") ""^(2+) + 4"e"^(-)#</mathjax></p> </blockquote> <p>Now add the two half-reactions to get</p> <blockquote> <p><mathjax>#stackrel(color(blue)(0))("O") _ 2 + 4"e"^(-) -&gt; 2stackrel(color(blue)(-2))("O") ""^(2-)#</mathjax><br/> <mathjax>#color(white)(aaaa)2stackrel(color(blue)(0))("Mg") -&gt; 2stackrel(color(blue)(+2))("Mg") ""^(2+) + 4"e"^(-)#</mathjax><br/> <mathjax>#color(white)(aaaaaaaaaaaaaaaaaaaaaaa)/color(white)(a)#</mathjax></p> <p><mathjax>#stackrel(color(blue)(0))("O") _ 2 + color(red)(cancel(color(black)(4"e"^(-)))) + 2stackrel(color(blue)(0))("Mg") -&gt; 2stackrel(color(blue)(-2))("O") ""^(2-) + 2stackrel(color(blue)(+2))("Mg") ""^(2+) + color(red)(cancel(color(black)(4"e"^(-))))#</mathjax></p> </blockquote> <p>which is equivalent to </p> <blockquote> <p><mathjax>#2"Mg"_ ((s)) + "O"_ (2(g)) -&gt; 2"MgO"_ ((s))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/438339" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-balance-equations-with-charges"> How to balance equations for reduction/oxidation reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-an-electode-reaction-has-dssolved-oxygen-as-a-reactant-is-the-electrode-an-an"> If an electode reaction has dssolved oxygen as a reactant, is the electrode an anode or a cathode? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-an-electrode-reaction-has-dissolved-oxygen-as-a-reactant-is-the-electrode-and"> If an electrode reaction has dissolved oxygen as a reactant, is the electrode and anode or a cathode? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-balanced-equation-represents-a-redox-reaction-2"> What balanced equation represents a redox reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-redox-reactions-involved-in-electrolysis"> How are redox reactions involved in electrolysis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-oxidation-reduction-reactions-coupled"> Why are oxidation reduction reactions coupled? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-do-oxidation-reduction-reactions-involve"> What do oxidation reduction reactions involve? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-reduction-reactions-used-for"> What are reduction reactions used for? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-calx-mean-in-oxidation-reduction-reactions"> What does "calx" mean in oxidation reduction reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-the-reduced-components-in-this-reaction-zn-2h-zn-2-h2"> What are the reduced components in this reaction? Zn + 2H(+) → Zn(2+) + H2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-and-reduction-reactions"> See all questions in Oxidation and Reduction Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 39386 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the reduction half-reaction for #2Mg + O_2 -&gt; 2MgO#?

a8508bca-6ddd-11ea-85fe-ccda262736ce

https://socratic.org/questions/how-many-joules-are-required-for-heating-65-g-of-water-from-12-c-to-76-c

17000 joules

start physical_unit 10 10 energy j qc_end physical_unit 10 10 7 8 mass qc_end physical_unit 10 10 12 13 temperature qc_end physical_unit 10 10 15 16 temperature qc_end end

[{"type":"physical unit","value":"Required energy [OF] water [IN] joules"}]

[{"type":"physical unit","value":"17000 joules"}]

[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{65 g}"},{"type":"physical unit","value":"Temprature1 [OF] water [=] \\pu{12 ℃}"},{"type":"physical unit","value":"Temprature2 [OF] water [=] \\pu{76 ℃}"}]

<h1 class="questionTitle" itemprop="name">How many joules are required for heating 65 g of water from 12 °C to 76 °C?</h1>

17000 joules

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>With knowledge of the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity of a substance, its mass, and the temperature change, we can convert this to the energy required for this temperature change using:</p> <p><mathjax>#DeltaH=mCDeltaT#</mathjax>, where</p> <p><mathjax>#DeltaH=#</mathjax>change in <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> (J)</p> <p><mathjax>#m=#</mathjax> mass of substance being heated (g) i.e. water in this question</p> <p><mathjax>#C=#</mathjax> specific heat capacity (J/g°C)</p> <p><mathjax>#DeltaT=#</mathjax> change in temperature (°C)</p> <p>We know mass<mathjax>#=65g#</mathjax> and <mathjax>#DeltaT=76°C-12°C=64°C#</mathjax></p> <p>The specific heat capacity of water is <mathjax>#4.18#</mathjax>J/g°C</p> <p>Therefore, <mathjax>#DeltaH=65cancel(g)*(4.18J)/cancel(g°C)*64cancel(°C)#</mathjax></p> <p><mathjax>#=17388.8J#</mathjax></p> <p><mathjax>#=17000J#</mathjax> (2 significant figures)</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#17000#</mathjax> joules</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>With knowledge of the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity of a substance, its mass, and the temperature change, we can convert this to the energy required for this temperature change using:</p> <p><mathjax>#DeltaH=mCDeltaT#</mathjax>, where</p> <p><mathjax>#DeltaH=#</mathjax>change in <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> (J)</p> <p><mathjax>#m=#</mathjax> mass of substance being heated (g) i.e. water in this question</p> <p><mathjax>#C=#</mathjax> specific heat capacity (J/g°C)</p> <p><mathjax>#DeltaT=#</mathjax> change in temperature (°C)</p> <p>We know mass<mathjax>#=65g#</mathjax> and <mathjax>#DeltaT=76°C-12°C=64°C#</mathjax></p> <p>The specific heat capacity of water is <mathjax>#4.18#</mathjax>J/g°C</p> <p>Therefore, <mathjax>#DeltaH=65cancel(g)*(4.18J)/cancel(g°C)*64cancel(°C)#</mathjax></p> <p><mathjax>#=17388.8J#</mathjax></p> <p><mathjax>#=17000J#</mathjax> (2 significant figures)</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many joules are required for heating 65 g of water from 12 °C to 76 °C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="392321" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/henry-w-2"><img alt="" class="" src="https://profilepictures.socratic.org/7IFCgaDHTbGDlVtThZyG_elephant_seal1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/henry-w-2"> Henry W. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-16T20:08:25" itemprop="dateCreated"> Mar 16, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#17000#</mathjax> joules</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>With knowledge of the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity of a substance, its mass, and the temperature change, we can convert this to the energy required for this temperature change using:</p> <p><mathjax>#DeltaH=mCDeltaT#</mathjax>, where</p> <p><mathjax>#DeltaH=#</mathjax>change in <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> (J)</p> <p><mathjax>#m=#</mathjax> mass of substance being heated (g) i.e. water in this question</p> <p><mathjax>#C=#</mathjax> specific heat capacity (J/g°C)</p> <p><mathjax>#DeltaT=#</mathjax> change in temperature (°C)</p> <p>We know mass<mathjax>#=65g#</mathjax> and <mathjax>#DeltaT=76°C-12°C=64°C#</mathjax></p> <p>The specific heat capacity of water is <mathjax>#4.18#</mathjax>J/g°C</p> <p>Therefore, <mathjax>#DeltaH=65cancel(g)*(4.18J)/cancel(g°C)*64cancel(°C)#</mathjax></p> <p><mathjax>#=17388.8J#</mathjax></p> <p><mathjax>#=17000J#</mathjax> (2 significant figures)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/392321" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? 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How many joules are required for heating 65 g of water from 12 °C to 76 °C?

a85a8e8c-6ddd-11ea-8656-ccda262736ce

https://socratic.org/questions/according-to-the-following-reaction-how-many-grams-of-hydrogen-peroxide-h-2o-2-a

12.74 grams

start physical_unit 11 11 mass g qc_end physical_unit 18 19 16 17 mole qc_end chemical_equation 20 28 qc_end end

[{"type":"physical unit","value":"Mass [OF] H2O2 [IN] grams"}]

[{"type":"physical unit","value":"12.74 grams"}]

[{"type":"physical unit","value":"Mole [OF] oxygen gas [=] \\pu{0.182 moles}"},{"type":"chemical equation","value":"hydrogen peroxide(H2O2) (aq) -> water (l) + oxygen (g)"}]

<h1 class="questionTitle" itemprop="name">According to the following reaction, how many grams of hydrogen peroxide (#H_2O_2#) are necessary to form 0.182 moles oxygen gas? </h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>hydrogen peroxide (<mathjax>#H_2O_2#</mathjax>) (aq) <mathjax>#-&gt;#</mathjax> water (l) + oxygen (g) </p></div> </h2> </div> </div>

12.74 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#2H_"2"O_"2"#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#2H_"2"O#</mathjax> + <mathjax>#O_"2"#</mathjax></p> <p>As per <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio, 2 moles of hydrogen peroxide burns to form 1 mole of oxygen. The ratio is 2:1.<br/> steps : </p> <p>multiply 0.182 with 2 to find out total moles of hydrogen peroxide<br/> answer = 0.364</p> <p>to convert from moles to grams multiply the moles with molar mass<br/> molar mass of hydrogen peroxide = 34</p> <p>0.364*34 = 12.376 grams of hydrogen peroxide</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>12.736 grams of hydrogen peroxide. please read explanation.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#2H_"2"O_"2"#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#2H_"2"O#</mathjax> + <mathjax>#O_"2"#</mathjax></p> <p>As per <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio, 2 moles of hydrogen peroxide burns to form 1 mole of oxygen. The ratio is 2:1.<br/> steps : </p> <p>multiply 0.182 with 2 to find out total moles of hydrogen peroxide<br/> answer = 0.364</p> <p>to convert from moles to grams multiply the moles with molar mass<br/> molar mass of hydrogen peroxide = 34</p> <p>0.364*34 = 12.376 grams of hydrogen peroxide</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">According to the following reaction, how many grams of hydrogen peroxide (#H_2O_2#) are necessary to form 0.182 moles oxygen gas? </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>hydrogen peroxide (<mathjax>#H_2O_2#</mathjax>) (aq) <mathjax>#-&gt;#</mathjax> water (l) + oxygen (g) </p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="386296" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/shreya737"><img alt="" class="" src="https://profilepictures.socratic.org/AermZQQ2Rw2mv57lQfYK_death.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/shreya737"> shreya737 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-04T11:22:35" itemprop="dateCreated"> Mar 4, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>12.736 grams of hydrogen peroxide. please read explanation.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#2H_"2"O_"2"#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#2H_"2"O#</mathjax> + <mathjax>#O_"2"#</mathjax></p> <p>As per <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio, 2 moles of hydrogen peroxide burns to form 1 mole of oxygen. The ratio is 2:1.<br/> steps : </p> <p>multiply 0.182 with 2 to find out total moles of hydrogen peroxide<br/> answer = 0.364</p> <p>to convert from moles to grams multiply the moles with molar mass<br/> molar mass of hydrogen peroxide = 34</p> <p>0.364*34 = 12.376 grams of hydrogen peroxide</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/386296" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -&gt; 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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According to the following reaction, how many grams of hydrogen peroxide (#H_2O_2#) are necessary to form 0.182 moles oxygen gas?

hydrogen peroxide (#H_2O_2#) (aq) #-&gt;# water (l) + oxygen (g)

a8389137-6ddd-11ea-b445-ccda262736ce

https://socratic.org/questions/what-is-the-molecular-mass-of-a-compound-if-560ml-have-a-mass-of-1-10g-at-stp

44.59 g/mol

start physical_unit 6 7 molecular_weight g/mol qc_end physical_unit 6 7 9 10 volume qc_end physical_unit 6 7 15 16 mass qc_end c_other STP qc_end end

[{"type":"physical unit","value":"Molecular mass [OF] a compound [IN] g/mol"}]

[{"type":"physical unit","value":"44.59 g/mol"}]

[{"type":"physical unit","value":"Volume [OF] a compound [=] \\pu{560 mL}"},{"type":"physical unit","value":"Mass [OF] a compound [=] \\pu{1.10 g}"},{"type":"other","value":"STP"}]

<h1 class="questionTitle" itemprop="name">What is the molecular mass of a compound if 560mL have a mass of 1.10g at STP? </h1>

44.59 g/mol

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Note: This is going to be a long answer.</p> <p><strong>First determine the number of moles.</strong></p> <p><mathjax>#"STP=273.15 K and 100 kPa"#</mathjax></p> <p><strong>Use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>.</strong></p> <p><mathjax>#PV=nRT#</mathjax>, <br/> where <mathjax>#P#</mathjax> is pressure in kiloPascals <mathjax>#("kPa")#</mathjax>, <mathjax>#V#</mathjax> is volume in liters <mathjax>#("L")#</mathjax>, <mathjax>#n#</mathjax> is moles, <mathjax>#R#</mathjax> is the gas constant, and <mathjax>#T#</mathjax> is temperature in Kelvins <mathjax>#("K")#</mathjax>.</p> <p><strong>Given/Known</strong></p> <p><mathjax>#P="100 kPa"#</mathjax></p> <p><mathjax>#T="273.15 K"#</mathjax></p> <p><mathjax>#V=560cancel"mL"xx(1"L")/(1000cancel"mL")="0.56 L"#</mathjax></p> <p><mathjax>#R="8.3144598 L kPa K"^(-1) "mol"^(-1)"#</mathjax> </p> <p><strong>Unknown</strong></p> <p>moles, n</p> <p><strong>Equation</strong></p> <p><mathjax>#PV=nRT#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#n#</mathjax> and solve.</p> <p><mathjax>#n=(PV)/(RT)=#</mathjax></p> <p><mathjax>#n=((100cancel"kPa")(0.56cancel"L"))/((8.3144598cancel "L" cancel"kPa"cancel" K"^(-1) "mol"^(-1)")#</mathjax><mathjax>#=#</mathjax><mathjax>#"0.024658 mol"#</mathjax></p> <p><mathjax>#n"=0.024658 mol"#</mathjax> (keeping a couple of guard digits)</p> <p><strong>Determine the molecular (molar) mass.</strong></p> <p><strong>Given/Known</strong></p> <p><mathjax>#n"=0.024658 mol"#</mathjax></p> <p><mathjax>#"m"="mass"="1.10 g"#</mathjax></p> <p><strong>Unknown</strong></p> <p>Molar mass: <mathjax>#"MM"#</mathjax></p> <p><strong>Equation</strong></p> <p><mathjax>#n=("m")/("MM")#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#"MM"#</mathjax> and solve.</p> <p><mathjax>#"MM"xx("m")/(n)#</mathjax></p> <p><mathjax>#"MM"xx(1.10"g")/(0.024658 "mol")=#</mathjax></p> <p><mathjax>#"MM"="45 g/mol"#</mathjax> (rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> due to 0.56 L)</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molar mass (molecular mass in grams) is <mathjax>#"45 g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Note: This is going to be a long answer.</p> <p><strong>First determine the number of moles.</strong></p> <p><mathjax>#"STP=273.15 K and 100 kPa"#</mathjax></p> <p><strong>Use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>.</strong></p> <p><mathjax>#PV=nRT#</mathjax>, <br/> where <mathjax>#P#</mathjax> is pressure in kiloPascals <mathjax>#("kPa")#</mathjax>, <mathjax>#V#</mathjax> is volume in liters <mathjax>#("L")#</mathjax>, <mathjax>#n#</mathjax> is moles, <mathjax>#R#</mathjax> is the gas constant, and <mathjax>#T#</mathjax> is temperature in Kelvins <mathjax>#("K")#</mathjax>.</p> <p><strong>Given/Known</strong></p> <p><mathjax>#P="100 kPa"#</mathjax></p> <p><mathjax>#T="273.15 K"#</mathjax></p> <p><mathjax>#V=560cancel"mL"xx(1"L")/(1000cancel"mL")="0.56 L"#</mathjax></p> <p><mathjax>#R="8.3144598 L kPa K"^(-1) "mol"^(-1)"#</mathjax> </p> <p><strong>Unknown</strong></p> <p>moles, n</p> <p><strong>Equation</strong></p> <p><mathjax>#PV=nRT#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#n#</mathjax> and solve.</p> <p><mathjax>#n=(PV)/(RT)=#</mathjax></p> <p><mathjax>#n=((100cancel"kPa")(0.56cancel"L"))/((8.3144598cancel "L" cancel"kPa"cancel" K"^(-1) "mol"^(-1)")#</mathjax><mathjax>#=#</mathjax><mathjax>#"0.024658 mol"#</mathjax></p> <p><mathjax>#n"=0.024658 mol"#</mathjax> (keeping a couple of guard digits)</p> <p><strong>Determine the molecular (molar) mass.</strong></p> <p><strong>Given/Known</strong></p> <p><mathjax>#n"=0.024658 mol"#</mathjax></p> <p><mathjax>#"m"="mass"="1.10 g"#</mathjax></p> <p><strong>Unknown</strong></p> <p>Molar mass: <mathjax>#"MM"#</mathjax></p> <p><strong>Equation</strong></p> <p><mathjax>#n=("m")/("MM")#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#"MM"#</mathjax> and solve.</p> <p><mathjax>#"MM"xx("m")/(n)#</mathjax></p> <p><mathjax>#"MM"xx(1.10"g")/(0.024658 "mol")=#</mathjax></p> <p><mathjax>#"MM"="45 g/mol"#</mathjax> (rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> due to 0.56 L)</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the molecular mass of a compound if 560mL have a mass of 1.10g at STP? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="180846" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-29T02:14:03" itemprop="dateCreated"> Oct 29, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molar mass (molecular mass in grams) is <mathjax>#"45 g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Note: This is going to be a long answer.</p> <p><strong>First determine the number of moles.</strong></p> <p><mathjax>#"STP=273.15 K and 100 kPa"#</mathjax></p> <p><strong>Use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>.</strong></p> <p><mathjax>#PV=nRT#</mathjax>, <br/> where <mathjax>#P#</mathjax> is pressure in kiloPascals <mathjax>#("kPa")#</mathjax>, <mathjax>#V#</mathjax> is volume in liters <mathjax>#("L")#</mathjax>, <mathjax>#n#</mathjax> is moles, <mathjax>#R#</mathjax> is the gas constant, and <mathjax>#T#</mathjax> is temperature in Kelvins <mathjax>#("K")#</mathjax>.</p> <p><strong>Given/Known</strong></p> <p><mathjax>#P="100 kPa"#</mathjax></p> <p><mathjax>#T="273.15 K"#</mathjax></p> <p><mathjax>#V=560cancel"mL"xx(1"L")/(1000cancel"mL")="0.56 L"#</mathjax></p> <p><mathjax>#R="8.3144598 L kPa K"^(-1) "mol"^(-1)"#</mathjax> </p> <p><strong>Unknown</strong></p> <p>moles, n</p> <p><strong>Equation</strong></p> <p><mathjax>#PV=nRT#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#n#</mathjax> and solve.</p> <p><mathjax>#n=(PV)/(RT)=#</mathjax></p> <p><mathjax>#n=((100cancel"kPa")(0.56cancel"L"))/((8.3144598cancel "L" cancel"kPa"cancel" K"^(-1) "mol"^(-1)")#</mathjax><mathjax>#=#</mathjax><mathjax>#"0.024658 mol"#</mathjax></p> <p><mathjax>#n"=0.024658 mol"#</mathjax> (keeping a couple of guard digits)</p> <p><strong>Determine the molecular (molar) mass.</strong></p> <p><strong>Given/Known</strong></p> <p><mathjax>#n"=0.024658 mol"#</mathjax></p> <p><mathjax>#"m"="mass"="1.10 g"#</mathjax></p> <p><strong>Unknown</strong></p> <p>Molar mass: <mathjax>#"MM"#</mathjax></p> <p><strong>Equation</strong></p> <p><mathjax>#n=("m")/("MM")#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#"MM"#</mathjax> and solve.</p> <p><mathjax>#"MM"xx("m")/(n)#</mathjax></p> <p><mathjax>#"MM"xx(1.10"g")/(0.024658 "mol")=#</mathjax></p> <p><mathjax>#"MM"="45 g/mol"#</mathjax> (rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> due to 0.56 L)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/180846" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="180847" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-29T02:20:44" itemprop="dateCreated"> Oct 29, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"45 g/mol"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the fact that at <strong>STP conditions</strong>, <em>one mole</em> of any ideal gas occupies exactly <mathjax>#"22.7 L"#</mathjax> - this is known as the <a href="http://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas at STP</a>. </p> <p>This means that if you know the volume of the gas, you can determine how many moles the sample contains by using the known molar volume at STP</p> <blockquote> <p><mathjax>#560color(red)(cancel(color(black)("mL"))) * (1color(red)(cancel(color(black)("L"))))/(1000color(red)(cancel(color(black)("mL")))) * "1 mole"/(22.7color(red)(cancel(color(black)("L")))) = "0.02467 moles"#</mathjax></p> </blockquote> <p>The molar mass of the compound, which tells you what the exact mass of <em>one mole</em> of the gas is, can be determined by using the mass of the sample. </p> <blockquote> <p><mathjax>#M_"M" = m/n#</mathjax></p> <p><mathjax>#M_"M" = "1.10 g"/"0.02467 moles" = "44.59 g/mol"#</mathjax></p> </blockquote> <p>Rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the nswer will be </p> <blockquote> <p><mathjax>#M_"M" = color(green)("45 g/mol")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/180847" itemprop="url">Answer link</a> </div> </div> </div> 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What is the molecular mass of a compound if 560mL have a mass of 1.10g at STP?

ad1b70a9-6ddd-11ea-a271-ccda262736ce

https://socratic.org/questions/the-temperature-of-a-sample-of-iron-with-a-mass-of-10-0-g-changed-from-50-4-c-to

448.81 J/(kg * K)

start physical_unit 6 6 specific_heat j/(kg_·_k) qc_end physical_unit 4 6 15 16 temperature qc_end physical_unit 4 6 18 19 temperature qc_end physical_unit 4 6 11 12 mass qc_end physical_unit 4 6 24 25 heat_energy qc_end end

[{"type":"physical unit","value":"specific heat [OF] iron [IN] J/(kg * K)"}]

[{"type":"physical unit","value":"448.81 J/(kg * K)"}]

[{"type":"physical unit","value":"Temperature1 [OF] iron sample [=] \\pu{50.4 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] iron sample [=] \\pu{25.0 ℃}"},{"type":"physical unit","value":"Mass [OF] iron sample [=] \\pu{10.0 g}"},{"type":"physical unit","value":"Released energy [OF] iron sample [=] \\pu{114 J}"}]

<h1 class="questionTitle" itemprop="name">The temperature of a sample of iron with a mass of 10.0 g changed from 50.4°C to 25.0°C with the release of 114 J of energy. What is the specific heat of iron? </h1>

448.81 J/(kg * K)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The equation needed to solve this problem is the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity equation: <mathjax>#ΔQ = mc Δ θ#</mathjax><br/> Where the terms are as follows:<br/> - ΔQ is heat energy transferred (in J)<br/> - m is the mass (in kg)<br/> - c is the specific heat capacity (in J kg⁻¹ K⁻¹)<br/> - Δθ is the temperature chance (in K or ºC)</p> <p>The only unit conversion necessary is for the mass: <mathjax>#10.0 g = 0.010 kg#</mathjax></p> <p>To solve for the specific heat rearrange the equation and substitute the values in.<br/> <mathjax>#c = (ΔQ) / (m Δθ) = 114 / (0.010 × (50.4 - 25.0)) = 448.81…#</mathjax></p> <p>To 3 sig. figs c = 449 J kg⁻¹ K⁻¹</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>c = 449 J kg⁻¹ K⁻¹</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The equation needed to solve this problem is the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity equation: <mathjax>#ΔQ = mc Δ θ#</mathjax><br/> Where the terms are as follows:<br/> - ΔQ is heat energy transferred (in J)<br/> - m is the mass (in kg)<br/> - c is the specific heat capacity (in J kg⁻¹ K⁻¹)<br/> - Δθ is the temperature chance (in K or ºC)</p> <p>The only unit conversion necessary is for the mass: <mathjax>#10.0 g = 0.010 kg#</mathjax></p> <p>To solve for the specific heat rearrange the equation and substitute the values in.<br/> <mathjax>#c = (ΔQ) / (m Δθ) = 114 / (0.010 × (50.4 - 25.0)) = 448.81…#</mathjax></p> <p>To 3 sig. figs c = 449 J kg⁻¹ K⁻¹</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">The temperature of a sample of iron with a mass of 10.0 g changed from 50.4°C to 25.0°C with the release of 114 J of energy. What is the specific heat of iron? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="294317" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/daniel-w"><img alt="" class="" src="https://profilepictures.socratic.org/oy1o80IvSSaxl05ajnhq_Dan%20Teaching%20-%20Google%20Plus%20Profile.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/daniel-w"> Daniel W. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-01T07:58:13" itemprop="dateCreated"> Aug 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>c = 449 J kg⁻¹ K⁻¹</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The equation needed to solve this problem is the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity equation: <mathjax>#ΔQ = mc Δ θ#</mathjax><br/> Where the terms are as follows:<br/> - ΔQ is heat energy transferred (in J)<br/> - m is the mass (in kg)<br/> - c is the specific heat capacity (in J kg⁻¹ K⁻¹)<br/> - Δθ is the temperature chance (in K or ºC)</p> <p>The only unit conversion necessary is for the mass: <mathjax>#10.0 g = 0.010 kg#</mathjax></p> <p>To solve for the specific heat rearrange the equation and substitute the values in.<br/> <mathjax>#c = (ΔQ) / (m Δθ) = 114 / (0.010 × (50.4 - 25.0)) = 448.81…#</mathjax></p> <p>To 3 sig. figs c = 449 J kg⁻¹ K⁻¹</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/294317" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? 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The temperature of a sample of iron with a mass of 10.0 g changed from 50.4°C to 25.0°C with the release of 114 J of energy. What is the specific heat of iron?

ab684ab6-6ddd-11ea-b812-ccda262736ce

https://socratic.org/questions/a-vat-contains-100-gallons-of-a-50-brine-solution-what-is-the-greatest-amount-of

100 gallons

start physical_unit 16 16 volume gallon qc_end physical_unit 8 9 3 4 volume qc_end physical_unit 8 8 7 7 percent qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Volume [OF] water [IN] gallons"}]

[{"type":"physical unit","value":"100 gallons"}]

[{"type":"physical unit","value":"Volume1 [OF] brine solution [=] \\pu{100 gallons}"},{"type":"physical unit","value":"Percent1 [OF] brine in solution [=] \\pu{50%}"},{"type":"other","value":"The salt content cannot drop below 25%."}]

<h1 class="questionTitle" itemprop="name">A vat contains 100 gallons of a 50% brine solution. What is the greatest amount of water that can be added if the salt content cannot drop below 25%?</h1>

100 gallons

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In the original 100 gallons, 50% is brine. Hence, there is 100<mathjax>#/#</mathjax>2= 50 gallons of brine solution. For 50 gallons to be at minimum 25% of the total volume, total volume must be 50 x (100/25) = 200 gallons. </p> <p>Therefore the greatest amount of water which can be added is 200 - 100 = 100 gallons.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>100 gallons</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In the original 100 gallons, 50% is brine. Hence, there is 100<mathjax>#/#</mathjax>2= 50 gallons of brine solution. For 50 gallons to be at minimum 25% of the total volume, total volume must be 50 x (100/25) = 200 gallons. </p> <p>Therefore the greatest amount of water which can be added is 200 - 100 = 100 gallons.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A vat contains 100 gallons of a 50% brine solution. What is the greatest amount of water that can be added if the salt content cannot drop below 25%?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="333603" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/crunchy-numeros"><img alt="" class="" src="https://profilepictures.socratic.org/rX3AnyQMQwadXYoepo06_Cat.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/crunchy-numeros"> crunchy numeros </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-09T01:03:29" itemprop="dateCreated"> Nov 9, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>100 gallons</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In the original 100 gallons, 50% is brine. Hence, there is 100<mathjax>#/#</mathjax>2= 50 gallons of brine solution. For 50 gallons to be at minimum 25% of the total volume, total volume must be 50 x (100/25) = 200 gallons. </p> <p>Therefore the greatest amount of water which can be added is 200 - 100 = 100 gallons.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/333603" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-solution-solute-and-solvent-related"> How are solution, solute, and solvent related? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutions-become-saturated"> Why do solutions become saturated? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-solutions"> How does temperature affect solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-solution-differ-from-a-colloid"> How does a solution differ from a colloid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/calculate-the-amount-of-1-m-naoh-aqueous-solution-needed-to-make-100-ml-of-0-5-m"> Calculate the amount of 1 M NaOH aqueous solution needed to make 100 mL of 0.5 M NaOH aqueous solution. </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-buffering-a-solution-change-the-solutions-behavior"> How does buffering a solution change the solutions behavior? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-benedict-s-solution-change-colour"> How does Benedict's solution change colour? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/describe-how-would-you-prepare-1-l-of-a-1-m-solution-of-sodium-chloride-the-gram"> Describe how would you prepare 1 L of a 1 M solution of sodium chloride. 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A vat contains 100 gallons of a 50% brine solution. What is the greatest amount of water that can be added if the salt content cannot drop below 25%?

aca85d99-6ddd-11ea-ba50-ccda262736ce

https://socratic.org/questions/the-gases-in-a-hair-spray-can-are-at-a-temperature-of-27-c-and-a-pressure-of-30-

627 ℃

start physical_unit 0 1 temperature °c qc_end c_other OTHER qc_end physical_unit 0 1 12 13 temperature qc_end physical_unit 0 1 18 19 pressure qc_end physical_unit 0 1 29 30 pressure qc_end end

[{"type":"physical unit","value":"Temperature2 [OF] the gases [IN] ℃"}]

[{"type":"physical unit","value":"627 ℃"}]

[{"type":"other","value":"Assume constant volume."},{"type":"physical unit","value":"Temperature1 [OF] the gases [=] \\pu{27 ℃}"},{"type":"physical unit","value":"Pressure1 [OF] the gases [=] \\pu{30 kPa}"},{"type":"physical unit","value":"Pressure2 [OF] the gases [=] \\pu{90 kPa}"}]

<h1 class="questionTitle" itemprop="name">The gases in a hair spray can are at a temperature of 27 C and a pressure of 30 kPa. If the gases in the can reach a pressure 90 kPa, the can will explode. To what temperature must the gases be raised in order for the can to explode? </h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Assume constant volume.</p></div> </h2> </div> </div>

627 ℃

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Since the volume is constant but the pressure and temperature are changing, this is an example of <strong>Gay-Lussac's Law</strong>:</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(|color(white)(a/a) p_1/T_1=p_2/T_2color(white)(a/a)|)))" "#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange the above formula to get</p> <blockquote> <blockquote> <p><mathjax>#T_2 = T_1 × p_2/p_1#</mathjax></p> </blockquote> </blockquote> <p>Your data are:</p> <p><mathjax>#p_1 = "30 kPa"#</mathjax><br/> <mathjax>#T_1 = "(27 + 273.15) K" = "300.15 K"#</mathjax><br/> <mathjax>#p_2 = "90 kPa"#</mathjax><br/> <mathjax>#T_2 = ?#</mathjax></p> <blockquote></blockquote> <p><mathjax>#T_2 = "300.15 K" × (90 color(red)(cancel(color(black)("kPa"))))/(30 color(red)(cancel(color(black)("kPa")))) = "900 K" = "627 °C"#</mathjax></p> <p>The new temperature is 627 °C.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The gases must reach a temperature of 627 °C.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Since the volume is constant but the pressure and temperature are changing, this is an example of <strong>Gay-Lussac's Law</strong>:</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(|color(white)(a/a) p_1/T_1=p_2/T_2color(white)(a/a)|)))" "#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange the above formula to get</p> <blockquote> <blockquote> <p><mathjax>#T_2 = T_1 × p_2/p_1#</mathjax></p> </blockquote> </blockquote> <p>Your data are:</p> <p><mathjax>#p_1 = "30 kPa"#</mathjax><br/> <mathjax>#T_1 = "(27 + 273.15) K" = "300.15 K"#</mathjax><br/> <mathjax>#p_2 = "90 kPa"#</mathjax><br/> <mathjax>#T_2 = ?#</mathjax></p> <blockquote></blockquote> <p><mathjax>#T_2 = "300.15 K" × (90 color(red)(cancel(color(black)("kPa"))))/(30 color(red)(cancel(color(black)("kPa")))) = "900 K" = "627 °C"#</mathjax></p> <p>The new temperature is 627 °C.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">The gases in a hair spray can are at a temperature of 27 C and a pressure of 30 kPa. If the gases in the can reach a pressure 90 kPa, the can will explode. To what temperature must the gases be raised in order for the can to explode? </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Assume constant volume.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="419114" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-07T12:28:59" itemprop="dateCreated"> May 7, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The gases must reach a temperature of 627 °C.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Since the volume is constant but the pressure and temperature are changing, this is an example of <strong>Gay-Lussac's Law</strong>:</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(|color(white)(a/a) p_1/T_1=p_2/T_2color(white)(a/a)|)))" "#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange the above formula to get</p> <blockquote> <blockquote> <p><mathjax>#T_2 = T_1 × p_2/p_1#</mathjax></p> </blockquote> </blockquote> <p>Your data are:</p> <p><mathjax>#p_1 = "30 kPa"#</mathjax><br/> <mathjax>#T_1 = "(27 + 273.15) K" = "300.15 K"#</mathjax><br/> <mathjax>#p_2 = "90 kPa"#</mathjax><br/> <mathjax>#T_2 = ?#</mathjax></p> <blockquote></blockquote> <p><mathjax>#T_2 = "300.15 K" × (90 color(red)(cancel(color(black)("kPa"))))/(30 color(red)(cancel(color(black)("kPa")))) = "900 K" = "627 °C"#</mathjax></p> <p>The new temperature is 627 °C.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/419114" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-gas-pressure-be-changed"> How can gas pressure be changed? 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The gases in a hair spray can are at a temperature of 27 C and a pressure of 30 kPa. If the gases in the can reach a pressure 90 kPa, the can will explode. To what temperature must the gases be raised in order for the can to explode?

Assume constant volume.

aa699a2f-6ddd-11ea-8e4f-ccda262736ce

https://socratic.org/questions/a-mixture-of-h-2-and-water-vapor-is-present-in-a-closed-vessel-at-20-c-the-total

737.50 mmHg

start physical_unit 3 3 partial_pressure mmhg qc_end physical_unit 10 12 14 15 temperature qc_end physical_unit 20 21 23 24 total_pressure qc_end physical_unit 5 6 33 34 partial_pressure qc_end physical_unit 5 6 14 15 temperature qc_end end

[{"type":"physical unit","value":"Partial pressure [OF] H2 [IN] mmHg"}]

[{"type":"physical unit","value":"737.50 mmHg"}]

[{"type":"physical unit","value":"Temperature [OF] a closed vessel [=] \\pu{20 ℃}"},{"type":"physical unit","value":"Total Pressure [OF] the system [=] \\pu{755.0 mmHg}"},{"type":"physical unit","value":"Partial pressure [OF] water vapor [=] \\pu{17.5 mmHg}"},{"type":"physical unit","value":"Temperature [OF] water vapor [=] \\pu{20 ℃}"}]

<h1 class="questionTitle" itemprop="name">A mixture of #H_2# and water vapor is present in a closed vessel at 20°C. The total pressure of the system is 755.0 mmHg. Partial pressure of water vapor at 20°C equals 17.5 mmHg. What is the partial pressure of #H_2#?</h1>

737.50 mmHg

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the <strong>total pressure</strong> of the system will be equal to the sum of the <em>partial pressures</em> of each gaseous component of the system, as given by <strong>Dalton's Law of Partial Pressures</strong>.</p> <p><img alt="https://www.alcaweb.org/arch.php/resource/view/86033" src="https://useruploads.socratic.org/hR1appgQjq94gWKmW5Uw_Blh7W8x3T3.jpg"/> </p> <p>In your case, you have</p> <blockquote> <p><mathjax>#P_ "total" = P_ ("H"_ 2) + P_ ("H"_ 2"O")#</mathjax></p> </blockquote> <p>Here</p> <p><mathjax>#P_("H"_2)#</mathjax> - the <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of hydrogen gas </p> <p><mathjax>#P_("H"_2"O")#</mathjax> - the partial pressure of water vapor</p> <p>That happens because when temperature and volume are <strong>kept constant</strong>, the pressure of a gas is <strong>directly proportional</strong> to the number of moles present. </p> <p>In other words, more moles of gas will result in a proportional increase in the pressure exerted by the gas. </p> <p>Simply put, the pressure you'd get if the number of moles of hydrogen gas were <strong>isolated</strong> in the <em>same volume</em> and kept under the <em>same temperature</em> will be equal to the <strong>partial pressure</strong> of hydrogen gas in the mixture. </p> <p>The same thing can be said for the water vapor. <strong>Isolating</strong> the water vapor in the <em>same volume</em> and under the <em>same temperature</em> will give you a pressure that is equal to the <strong>partial pressure</strong> of water vapor in the mixture. </p> <p>Therefore, the partial pressure of hydrogen gas in this mixture is </p> <blockquote> <p><mathjax>#P_ ("H"_ 2) = "755.0 mmHg" - "17.5 mmHg" = color(green)(|bar(ul(color(white)(a/a)color(black)("737.5 mmHg")color(white)(a/a)|)))#</mathjax></p> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"737.5 mmHg"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the <strong>total pressure</strong> of the system will be equal to the sum of the <em>partial pressures</em> of each gaseous component of the system, as given by <strong>Dalton's Law of Partial Pressures</strong>.</p> <p><img alt="https://www.alcaweb.org/arch.php/resource/view/86033" src="https://useruploads.socratic.org/hR1appgQjq94gWKmW5Uw_Blh7W8x3T3.jpg"/> </p> <p>In your case, you have</p> <blockquote> <p><mathjax>#P_ "total" = P_ ("H"_ 2) + P_ ("H"_ 2"O")#</mathjax></p> </blockquote> <p>Here</p> <p><mathjax>#P_("H"_2)#</mathjax> - the <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of hydrogen gas </p> <p><mathjax>#P_("H"_2"O")#</mathjax> - the partial pressure of water vapor</p> <p>That happens because when temperature and volume are <strong>kept constant</strong>, the pressure of a gas is <strong>directly proportional</strong> to the number of moles present. </p> <p>In other words, more moles of gas will result in a proportional increase in the pressure exerted by the gas. </p> <p>Simply put, the pressure you'd get if the number of moles of hydrogen gas were <strong>isolated</strong> in the <em>same volume</em> and kept under the <em>same temperature</em> will be equal to the <strong>partial pressure</strong> of hydrogen gas in the mixture. </p> <p>The same thing can be said for the water vapor. <strong>Isolating</strong> the water vapor in the <em>same volume</em> and under the <em>same temperature</em> will give you a pressure that is equal to the <strong>partial pressure</strong> of water vapor in the mixture. </p> <p>Therefore, the partial pressure of hydrogen gas in this mixture is </p> <blockquote> <p><mathjax>#P_ ("H"_ 2) = "755.0 mmHg" - "17.5 mmHg" = color(green)(|bar(ul(color(white)(a/a)color(black)("737.5 mmHg")color(white)(a/a)|)))#</mathjax></p> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A mixture of #H_2# and water vapor is present in a closed vessel at 20°C. The total pressure of the system is 755.0 mmHg. Partial pressure of water vapor at 20°C equals 17.5 mmHg. What is the partial pressure of #H_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/partial-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Partial Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="281674" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-26T23:53:59" itemprop="dateCreated"> Jun 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"737.5 mmHg"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the <strong>total pressure</strong> of the system will be equal to the sum of the <em>partial pressures</em> of each gaseous component of the system, as given by <strong>Dalton's Law of Partial Pressures</strong>.</p> <p><img alt="https://www.alcaweb.org/arch.php/resource/view/86033" src="https://useruploads.socratic.org/hR1appgQjq94gWKmW5Uw_Blh7W8x3T3.jpg"/> </p> <p>In your case, you have</p> <blockquote> <p><mathjax>#P_ "total" = P_ ("H"_ 2) + P_ ("H"_ 2"O")#</mathjax></p> </blockquote> <p>Here</p> <p><mathjax>#P_("H"_2)#</mathjax> - the <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of hydrogen gas </p> <p><mathjax>#P_("H"_2"O")#</mathjax> - the partial pressure of water vapor</p> <p>That happens because when temperature and volume are <strong>kept constant</strong>, the pressure of a gas is <strong>directly proportional</strong> to the number of moles present. </p> <p>In other words, more moles of gas will result in a proportional increase in the pressure exerted by the gas. </p> <p>Simply put, the pressure you'd get if the number of moles of hydrogen gas were <strong>isolated</strong> in the <em>same volume</em> and kept under the <em>same temperature</em> will be equal to the <strong>partial pressure</strong> of hydrogen gas in the mixture. </p> <p>The same thing can be said for the water vapor. <strong>Isolating</strong> the water vapor in the <em>same volume</em> and under the <em>same temperature</em> will give you a pressure that is equal to the <strong>partial pressure</strong> of water vapor in the mixture. </p> <p>Therefore, the partial pressure of hydrogen gas in this mixture is </p> <blockquote> <p><mathjax>#P_ ("H"_ 2) = "755.0 mmHg" - "17.5 mmHg" = color(green)(|bar(ul(color(white)(a/a)color(black)("737.5 mmHg")color(white)(a/a)|)))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/281674" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534e256802bf342adfa30010"> How do you do a steam distillation? 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A mixture of #H_2# and water vapor is present in a closed vessel at 20°C. The total pressure of the system is 755.0 mmHg. Partial pressure of water vapor at 20°C equals 17.5 mmHg. What is the partial pressure of #H_2#?

a90817a6-6ddd-11ea-a378-ccda262736ce

https://socratic.org/questions/a-gas-cylinder-contains-2-0-mol-of-gas-x-and-6-0-mol-of-gas-y-at-a-total-pressur

1.58 atm

start physical_unit 13 14 partial_pressure atm qc_end physical_unit 1 1 20 21 total_pressure qc_end physical_unit 7 8 4 5 mole qc_end physical_unit 13 14 10 11 mole qc_end end

[{"type":"physical unit","value":"Partial pressure [OF] gas Y [IN] atm"}]

[{"type":"physical unit","value":"1.58 atm"}]

[{"type":"physical unit","value":"Total pressure [OF] gas [=] \\pu{2.1 atm}"},{"type":"physical unit","value":"Mole [OF] gas X [=] \\pu{2.0 mol}"},{"type":"physical unit","value":"Mole [OF] gas Y [=] \\pu{6.0 mol}"}]

<h1 class="questionTitle" itemprop="name">A gas cylinder contains 2.0 mol of gas X and 6.0 mol of gas Y at a total pressure of 2.1 atm. What is is partial pressure of gas Y?</h1>

1.58 atm

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Okay, so here is what is going on.</p> <p>You have some gas cylinder which contains a mixture of 2 different gases: <mathjax>#"Gas X" and "gas Y"#</mathjax>. Each gas is exerting its own pressure which is contributing to the total pressure. You are asked to figure out the <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of gas Y. Here is how you go about doing that.</p> <p><mathjax>#---------------------#</mathjax></p> <p>Write out our givens.</p> <p><strong>Given</strong></p> <ul> <li><mathjax>#"2.0 moles of gas X"#</mathjax></li> <li><mathjax>#"6.0 moles of gas Y"#</mathjax></li> <li><mathjax>#"Total pressure = 2.1 atm"#</mathjax></li> </ul> <p>To find the partial pressure of <mathjax>#"gas Y"#</mathjax>, you need to use the following formula:</p> <p><mathjax>#color(white)(aaaaaaaaaaaaaa)color(blue)[P_"Y" = P_"T" * x_"Y"#</mathjax></p> <p><strong>Where</strong></p> <ul> <li> <p><mathjax>#"P"_"Y" = "partial pressure of gas Y"#</mathjax></p> </li> <li> <p><mathjax>#"P"_"T" = "total pressure"#</mathjax></p> </li> <li> <p><mathjax>#"x"_"Y" = "mole fraction of gas Y"#</mathjax></p> </li> </ul> <p>We were given the total pressure of the system, but we need to figure out <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fraction of gas Y. To calculate it, we use the following equation:</p> <p><mathjax>#color(white)(aaaaaaaaaa)color(blue)[x_"Y" = ("moles of gas Y")/("total moles of gas")#</mathjax><br/> <mathjax>#color(white)(aaaaaaaaaaaaaa)#</mathjax></p> <p><strong>Plugin and solve for the mole fraction of gas Y</strong></p> <ul> <li> <p><mathjax>#color(blue)[x_"Y" = ("moles of gas Y")/("total moles of gas")#</mathjax><br/> <mathjax>#color(white)(-)#</mathjax></p> </li> <li> <p><mathjax>#rarr("6.0 moles of gas Y")/("2.0 moles of gas X + 6.0 moles of gas Y")#</mathjax></p> </li> <li> <p><mathjax>#rarr("6" cancel"moles")/("8" cancel"moles")#</mathjax></p> </li> <li> <p><mathjax>#rarrcolor(red)" 0.75"#</mathjax></p> </li> </ul> <p><em>Note: moles over moles cancel out so the mole fraction is unitless</em><br/> <mathjax>#color(white)(aaaaaaaaaaaaaa)#</mathjax></p> <p>You now can use the mole fraction to solve for the partial pressure of gas Y by using the first equation which was given out.</p> <ul> <li><mathjax>#color(blue)[P_"Y" = P_"T" * x_"Y"#</mathjax></li> <li><mathjax>#P_"Y" = "(2.1 atm)" * "(0.75)"#</mathjax></li> <li><mathjax>#P_"Y" = color(magenta)"1.58 atm"#</mathjax></li> </ul> <p><strong>Answer:</strong> <mathjax>#P_"Y" = color(magenta)"1.58 atm"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_"Y" = "1.58 atm"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Okay, so here is what is going on.</p> <p>You have some gas cylinder which contains a mixture of 2 different gases: <mathjax>#"Gas X" and "gas Y"#</mathjax>. Each gas is exerting its own pressure which is contributing to the total pressure. You are asked to figure out the <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of gas Y. Here is how you go about doing that.</p> <p><mathjax>#---------------------#</mathjax></p> <p>Write out our givens.</p> <p><strong>Given</strong></p> <ul> <li><mathjax>#"2.0 moles of gas X"#</mathjax></li> <li><mathjax>#"6.0 moles of gas Y"#</mathjax></li> <li><mathjax>#"Total pressure = 2.1 atm"#</mathjax></li> </ul> <p>To find the partial pressure of <mathjax>#"gas Y"#</mathjax>, you need to use the following formula:</p> <p><mathjax>#color(white)(aaaaaaaaaaaaaa)color(blue)[P_"Y" = P_"T" * x_"Y"#</mathjax></p> <p><strong>Where</strong></p> <ul> <li> <p><mathjax>#"P"_"Y" = "partial pressure of gas Y"#</mathjax></p> </li> <li> <p><mathjax>#"P"_"T" = "total pressure"#</mathjax></p> </li> <li> <p><mathjax>#"x"_"Y" = "mole fraction of gas Y"#</mathjax></p> </li> </ul> <p>We were given the total pressure of the system, but we need to figure out <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fraction of gas Y. To calculate it, we use the following equation:</p> <p><mathjax>#color(white)(aaaaaaaaaa)color(blue)[x_"Y" = ("moles of gas Y")/("total moles of gas")#</mathjax><br/> <mathjax>#color(white)(aaaaaaaaaaaaaa)#</mathjax></p> <p><strong>Plugin and solve for the mole fraction of gas Y</strong></p> <ul> <li> <p><mathjax>#color(blue)[x_"Y" = ("moles of gas Y")/("total moles of gas")#</mathjax><br/> <mathjax>#color(white)(-)#</mathjax></p> </li> <li> <p><mathjax>#rarr("6.0 moles of gas Y")/("2.0 moles of gas X + 6.0 moles of gas Y")#</mathjax></p> </li> <li> <p><mathjax>#rarr("6" cancel"moles")/("8" cancel"moles")#</mathjax></p> </li> <li> <p><mathjax>#rarrcolor(red)" 0.75"#</mathjax></p> </li> </ul> <p><em>Note: moles over moles cancel out so the mole fraction is unitless</em><br/> <mathjax>#color(white)(aaaaaaaaaaaaaa)#</mathjax></p> <p>You now can use the mole fraction to solve for the partial pressure of gas Y by using the first equation which was given out.</p> <ul> <li><mathjax>#color(blue)[P_"Y" = P_"T" * x_"Y"#</mathjax></li> <li><mathjax>#P_"Y" = "(2.1 atm)" * "(0.75)"#</mathjax></li> <li><mathjax>#P_"Y" = color(magenta)"1.58 atm"#</mathjax></li> </ul> <p><strong>Answer:</strong> <mathjax>#P_"Y" = color(magenta)"1.58 atm"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A gas cylinder contains 2.0 mol of gas X and 6.0 mol of gas Y at a total pressure of 2.1 atm. What is is partial pressure of gas Y?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/partial-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Partial Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="448780" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/maxwell-1"><img alt="" class="" src="https://profilepictures.socratic.org/eVKXLKEcRRaVNXSCjdU0_Climbing.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/maxwell-1"> Maxwell </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-06T22:48:38" itemprop="dateCreated"> Jul 6, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_"Y" = "1.58 atm"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Okay, so here is what is going on.</p> <p>You have some gas cylinder which contains a mixture of 2 different gases: <mathjax>#"Gas X" and "gas Y"#</mathjax>. Each gas is exerting its own pressure which is contributing to the total pressure. You are asked to figure out the <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> of gas Y. Here is how you go about doing that.</p> <p><mathjax>#---------------------#</mathjax></p> <p>Write out our givens.</p> <p><strong>Given</strong></p> <ul> <li><mathjax>#"2.0 moles of gas X"#</mathjax></li> <li><mathjax>#"6.0 moles of gas Y"#</mathjax></li> <li><mathjax>#"Total pressure = 2.1 atm"#</mathjax></li> </ul> <p>To find the partial pressure of <mathjax>#"gas Y"#</mathjax>, you need to use the following formula:</p> <p><mathjax>#color(white)(aaaaaaaaaaaaaa)color(blue)[P_"Y" = P_"T" * x_"Y"#</mathjax></p> <p><strong>Where</strong></p> <ul> <li> <p><mathjax>#"P"_"Y" = "partial pressure of gas Y"#</mathjax></p> </li> <li> <p><mathjax>#"P"_"T" = "total pressure"#</mathjax></p> </li> <li> <p><mathjax>#"x"_"Y" = "mole fraction of gas Y"#</mathjax></p> </li> </ul> <p>We were given the total pressure of the system, but we need to figure out <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fraction of gas Y. To calculate it, we use the following equation:</p> <p><mathjax>#color(white)(aaaaaaaaaa)color(blue)[x_"Y" = ("moles of gas Y")/("total moles of gas")#</mathjax><br/> <mathjax>#color(white)(aaaaaaaaaaaaaa)#</mathjax></p> <p><strong>Plugin and solve for the mole fraction of gas Y</strong></p> <ul> <li> <p><mathjax>#color(blue)[x_"Y" = ("moles of gas Y")/("total moles of gas")#</mathjax><br/> <mathjax>#color(white)(-)#</mathjax></p> </li> <li> <p><mathjax>#rarr("6.0 moles of gas Y")/("2.0 moles of gas X + 6.0 moles of gas Y")#</mathjax></p> </li> <li> <p><mathjax>#rarr("6" cancel"moles")/("8" cancel"moles")#</mathjax></p> </li> <li> <p><mathjax>#rarrcolor(red)" 0.75"#</mathjax></p> </li> </ul> <p><em>Note: moles over moles cancel out so the mole fraction is unitless</em><br/> <mathjax>#color(white)(aaaaaaaaaaaaaa)#</mathjax></p> <p>You now can use the mole fraction to solve for the partial pressure of gas Y by using the first equation which was given out.</p> <ul> <li><mathjax>#color(blue)[P_"Y" = P_"T" * x_"Y"#</mathjax></li> <li><mathjax>#P_"Y" = "(2.1 atm)" * "(0.75)"#</mathjax></li> <li><mathjax>#P_"Y" = color(magenta)"1.58 atm"#</mathjax></li> </ul> <p><strong>Answer:</strong> <mathjax>#P_"Y" = color(magenta)"1.58 atm"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/448780" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534e256802bf342adfa30010"> How do you do a steam distillation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/53613f9f02bf3416cd9f8a34"> Question #f8a34 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-i-calculate-the-total-pressure-of-a-mixture-of-gases-by-adding-together-the-"> Can I calculate the total pressure of a mixture of gases by adding together the partial... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-formula-of-partial-pressure"> What is the formula of partial pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-dalton-s-law-of-partial-pressures"> What is the Dalton's law of partial pressures? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/nitrogen-gas-n2-reacts-with-hydrogen-gas-h2-to-form-ammonia-nh3-at-200-c-in-a-cl"> Nitrogen gas (N2) reacts with hydrogen gas (H2) to form ammonia (NH3). 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A gas cylinder contains 2.0 mol of gas X and 6.0 mol of gas Y at a total pressure of 2.1 atm. What is is partial pressure of gas Y?

ab51b910-6ddd-11ea-8d89-ccda262736ce

https://socratic.org/questions/what-volume-is-occupied-by-0-963-mol-of-co-2-at-300-9-k-and-913-mmhg

19.82 L

start physical_unit 8 8 volume l qc_end physical_unit 8 8 5 6 mole qc_end physical_unit 8 8 10 11 temperature qc_end physical_unit 8 8 13 14 pressure qc_end end

[{"type":"physical unit","value":"Volume [OF] CO2 [IN] L"}]

[{"type":"physical unit","value":"19.82 L"}]

[{"type":"physical unit","value":"Mole [OF] CO2 [=] \\pu{0.963 mol}"},{"type":"physical unit","value":"Temperature [OF] CO2 [=] \\pu{300.9 K}"},{"type":"physical unit","value":"Pressure [OF] CO2 [=] \\pu{913 mmHg}"}]

<h1 class="questionTitle" itemprop="name">What volume is occupied by 0.963 mol of #CO_2# at 300.9 K and 913 mmHg?</h1>

19.82 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The only difficulty in solving this problem is getting the appropriate units. The quoted units of pressure are unfortunate. We know that <mathjax>#1#</mathjax> <mathjax>#atm#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#760*mm*Hg#</mathjax>; i.e. that <mathjax>#1*atm#</mathjax> will support a column of mercury <mathjax>#760*mm#</mathjax> high. Thus <mathjax>#P#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(913*mm*Hg)/(760*mm*Hg*atm^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.20*atm#</mathjax> (and this measurement should have been quoted in the problem). If you measured pressures with such a mercury column you would end up getting mercury all over the laboratory, so whoever set this question was ignorant, and deserves a bollocking.</p> <p>Given appropriate units of pressure,</p> <p><mathjax>#V=(0.963*molxx0.0821*L*atm*K^-1*mol^-1xx300.9K)/(1.20*atm)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??L#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V=(nRT)/P#</mathjax> <mathjax>#~=20L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The only difficulty in solving this problem is getting the appropriate units. The quoted units of pressure are unfortunate. We know that <mathjax>#1#</mathjax> <mathjax>#atm#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#760*mm*Hg#</mathjax>; i.e. that <mathjax>#1*atm#</mathjax> will support a column of mercury <mathjax>#760*mm#</mathjax> high. Thus <mathjax>#P#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(913*mm*Hg)/(760*mm*Hg*atm^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.20*atm#</mathjax> (and this measurement should have been quoted in the problem). If you measured pressures with such a mercury column you would end up getting mercury all over the laboratory, so whoever set this question was ignorant, and deserves a bollocking.</p> <p>Given appropriate units of pressure,</p> <p><mathjax>#V=(0.963*molxx0.0821*L*atm*K^-1*mol^-1xx300.9K)/(1.20*atm)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??L#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What volume is occupied by 0.963 mol of #CO_2# at 300.9 K and 913 mmHg?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="297803" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-11T15:19:59" itemprop="dateCreated"> Aug 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V=(nRT)/P#</mathjax> <mathjax>#~=20L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The only difficulty in solving this problem is getting the appropriate units. The quoted units of pressure are unfortunate. We know that <mathjax>#1#</mathjax> <mathjax>#atm#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#760*mm*Hg#</mathjax>; i.e. that <mathjax>#1*atm#</mathjax> will support a column of mercury <mathjax>#760*mm#</mathjax> high. Thus <mathjax>#P#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(913*mm*Hg)/(760*mm*Hg*atm^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.20*atm#</mathjax> (and this measurement should have been quoted in the problem). If you measured pressures with such a mercury column you would end up getting mercury all over the laboratory, so whoever set this question was ignorant, and deserves a bollocking.</p> <p>Given appropriate units of pressure,</p> <p><mathjax>#V=(0.963*molxx0.0821*L*atm*K^-1*mol^-1xx300.9K)/(1.20*atm)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??L#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/297803" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? 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What volume is occupied by 0.963 mol of #CO_2# at 300.9 K and 913 mmHg?

a9480295-6ddd-11ea-8fbe-ccda262736ce

https://socratic.org/questions/a-3-50-l-gas-sample-at-20-c-and-a-pressure-of-86-7-kpa-expands-to-a-volume-of-8-

164.98 degrees Celsius

start physical_unit 25 26 temperature °c qc_end physical_unit 25 26 1 2 volume qc_end physical_unit 25 26 6 7 temperature qc_end physical_unit 25 26 12 13 pressure qc_end physical_unit 25 26 28 29 pressure qc_end physical_unit 25 26 19 20 volume qc_end end

[{"type":"physical unit","value":"Temperature2 [OF] the gas [IN] degrees Celsius"}]

[{"type":"physical unit","value":"164.98 degrees Celsius"}]

[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{3.50 L}"},{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{20 ℃}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{86.7 kPa}"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{56.7 kPa}"},{"type":"physical unit","value":"Volume2 [OF] the gas [=] \\pu{8.00 L}"}]

<h1 class="questionTitle" itemprop="name">A 3.50-L gas sample at 20°C and a pressure of 86.7 kPa expands to a volume of 8.00 L. The final pressure of the gas is 56.7 kPa. What is the final temperature of the gas, in degrees Celsius?</h1>

164.98 degrees Celsius

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We can use here the <em><a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a></em>, relating the temperature, pressure, and volume of a gas with a constant quantity:</p> <p><mathjax>#(P_1V_1)/(T_1) = (P_2V_2)/(T_2)#</mathjax></p> <p>If you're using the ideal-gas equation, which we're NOT using here, you would have to convert each measurement into the appropriate units (<mathjax>#"L", "K", "atm",#</mathjax>and <mathjax>#"mol"#</mathjax>). The only measurement that needs conversion here is temperature, from <mathjax>#"^oC#</mathjax> to <mathjax>#"K"#</mathjax>. (You will <strong>always</strong> convert temperature to Kelvin (absolute temperature) when using gas equations).</p> <p>The Kelvin temperature is</p> <p><mathjax>#"K" = 20^(o)C + 273 = 293"K"#</mathjax></p> <p>Let's rearrange the combined gas law to solve for the final temperature, <mathjax>#T_2#</mathjax>:</p> <p><mathjax>#T_2 = (P_2V_2T_1)/(P_1V_1)#</mathjax></p> <p>Plugging in known values, we can find the final temperature:</p> <p><mathjax>#T_2 = ((56.7"kPa")(8.00"L")(293"K"))/((86.7"kPa")(3.50"L")) = 438"K"#</mathjax></p> <p>Lastly, we'll convert back from <mathjax>#"K"#</mathjax> to <mathjax>#"^oC#</mathjax>:</p> <p><mathjax>#438"K" - 273 = color(blue)(165^oC#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#165^oC#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We can use here the <em><a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a></em>, relating the temperature, pressure, and volume of a gas with a constant quantity:</p> <p><mathjax>#(P_1V_1)/(T_1) = (P_2V_2)/(T_2)#</mathjax></p> <p>If you're using the ideal-gas equation, which we're NOT using here, you would have to convert each measurement into the appropriate units (<mathjax>#"L", "K", "atm",#</mathjax>and <mathjax>#"mol"#</mathjax>). The only measurement that needs conversion here is temperature, from <mathjax>#"^oC#</mathjax> to <mathjax>#"K"#</mathjax>. (You will <strong>always</strong> convert temperature to Kelvin (absolute temperature) when using gas equations).</p> <p>The Kelvin temperature is</p> <p><mathjax>#"K" = 20^(o)C + 273 = 293"K"#</mathjax></p> <p>Let's rearrange the combined gas law to solve for the final temperature, <mathjax>#T_2#</mathjax>:</p> <p><mathjax>#T_2 = (P_2V_2T_1)/(P_1V_1)#</mathjax></p> <p>Plugging in known values, we can find the final temperature:</p> <p><mathjax>#T_2 = ((56.7"kPa")(8.00"L")(293"K"))/((86.7"kPa")(3.50"L")) = 438"K"#</mathjax></p> <p>Lastly, we'll convert back from <mathjax>#"K"#</mathjax> to <mathjax>#"^oC#</mathjax>:</p> <p><mathjax>#438"K" - 273 = color(blue)(165^oC#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A 3.50-L gas sample at 20°C and a pressure of 86.7 kPa expands to a volume of 8.00 L. The final pressure of the gas is 56.7 kPa. What is the final temperature of the gas, in degrees Celsius?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="428459" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-23T16:40:24" itemprop="dateCreated"> May 23, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#165^oC#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We can use here the <em><a href="https://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a></em>, relating the temperature, pressure, and volume of a gas with a constant quantity:</p> <p><mathjax>#(P_1V_1)/(T_1) = (P_2V_2)/(T_2)#</mathjax></p> <p>If you're using the ideal-gas equation, which we're NOT using here, you would have to convert each measurement into the appropriate units (<mathjax>#"L", "K", "atm",#</mathjax>and <mathjax>#"mol"#</mathjax>). The only measurement that needs conversion here is temperature, from <mathjax>#"^oC#</mathjax> to <mathjax>#"K"#</mathjax>. (You will <strong>always</strong> convert temperature to Kelvin (absolute temperature) when using gas equations).</p> <p>The Kelvin temperature is</p> <p><mathjax>#"K" = 20^(o)C + 273 = 293"K"#</mathjax></p> <p>Let's rearrange the combined gas law to solve for the final temperature, <mathjax>#T_2#</mathjax>:</p> <p><mathjax>#T_2 = (P_2V_2T_1)/(P_1V_1)#</mathjax></p> <p>Plugging in known values, we can find the final temperature:</p> <p><mathjax>#T_2 = ((56.7"kPa")(8.00"L")(293"K"))/((86.7"kPa")(3.50"L")) = 438"K"#</mathjax></p> <p>Lastly, we'll convert back from <mathjax>#"K"#</mathjax> to <mathjax>#"^oC#</mathjax>:</p> <p><mathjax>#438"K" - 273 = color(blue)(165^oC#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/428459" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyles-law-relate-to-breathing"> How does Boyle's law relate to breathing? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/in-avogadro-s-law-what-would-happen-to-v-if-n-is-increased-decreased-and-what-wo"> In Avogadro's Law what would happen to V if N is increased/decreased? 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A 3.50-L gas sample at 20°C and a pressure of 86.7 kPa expands to a volume of 8.00 L. The final pressure of the gas is 56.7 kPa. What is the final temperature of the gas, in degrees Celsius?

aaab7fd0-6ddd-11ea-be25-ccda262736ce

https://socratic.org/questions/a-tank-of-gas-has-partial-pressures-of-nitrogen-and-oxygen-equal-to-1-61-x-10-4-

4.50 × 10^5 kPa

start physical_unit 29 30 total_pressure kpa qc_end physical_unit 10 10 18 21 partial_pressure qc_end end

[{"type":"physical unit","value":"Total pressure [OF] the tank [IN] kPa"}]

[{"type":"physical unit","value":"4.50 × 10^5 kPa"}]

[{"type":"physical unit","value":"Partial pressures [OF] nitrogen gas [=] \\pu{1.61 × 10^4 kPa}"},{"type":"physical unit","value":"Partial pressures [OF] oxygen gas [=] \\pu{4.34 × 10^5 kPa}"}]

<h1 class="questionTitle" itemprop="name">A tank of gas has partial pressures of nitrogen and oxygen equal to #1.61 xx 10^4# #"kPa"# and #4.34 xx 10^5# #"kPa"#, respectively. What is the total pressure of the tank? </h1>

4.50 × 10^5 kPa

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that when the volume and the temperature of a gaseous mixture are kept <em>constant</em>, the <strong>total pressure</strong> of the mixture is equal to the sum of the <em>partial pressures</em> of its gaseous components <mathjax>#-&gt;#</mathjax> this is known as <strong>Dalton's Law of Partial Pressures</strong>.</p> <p><img alt="https://www.ck12.org/book/CK-12-Chemistry-Concepts-Intermediate/section/14.12/" src="https://useruploads.socratic.org/ANYt1puRl6jzbxWaGHJO_f-d%253Aaa7b820f730dd7f29451dcf420a450b9a418da33562c64772ef80c33%252BIMAGE_THUMB_POSTCARD_TINY%252BIMAGE_THUMB_POSTCARD_TINY.1"/> </p> <p>In your case, you know that the mixture contains nitrogen gas, <mathjax>#"N"_2#</mathjax>, and oxygen gas, <mathjax>#"O"_2#</mathjax>, which means that the total pressure of the mixture will be</p> <blockquote> <p><mathjax>#P_"total" = P_ ("N" _ 2) + P_ ("O"_ 2)#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#P_"total" = 1.61 * 10^4color(white)(.)"kPa" + 4.34 * 10^5color(white)(.)"kPa"#</mathjax></p> <p><mathjax>#P_"total" = color(darkgreen)(ul(color(black)(4.50 * 10^5color(white)(.)"kPa")))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong>decimal places</strong>, the number of decimal places you have for your values. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4.50 * 10^5#</mathjax> <mathjax>#"kPa"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that when the volume and the temperature of a gaseous mixture are kept <em>constant</em>, the <strong>total pressure</strong> of the mixture is equal to the sum of the <em>partial pressures</em> of its gaseous components <mathjax>#-&gt;#</mathjax> this is known as <strong>Dalton's Law of Partial Pressures</strong>.</p> <p><img alt="https://www.ck12.org/book/CK-12-Chemistry-Concepts-Intermediate/section/14.12/" src="https://useruploads.socratic.org/ANYt1puRl6jzbxWaGHJO_f-d%253Aaa7b820f730dd7f29451dcf420a450b9a418da33562c64772ef80c33%252BIMAGE_THUMB_POSTCARD_TINY%252BIMAGE_THUMB_POSTCARD_TINY.1"/> </p> <p>In your case, you know that the mixture contains nitrogen gas, <mathjax>#"N"_2#</mathjax>, and oxygen gas, <mathjax>#"O"_2#</mathjax>, which means that the total pressure of the mixture will be</p> <blockquote> <p><mathjax>#P_"total" = P_ ("N" _ 2) + P_ ("O"_ 2)#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#P_"total" = 1.61 * 10^4color(white)(.)"kPa" + 4.34 * 10^5color(white)(.)"kPa"#</mathjax></p> <p><mathjax>#P_"total" = color(darkgreen)(ul(color(black)(4.50 * 10^5color(white)(.)"kPa")))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong>decimal places</strong>, the number of decimal places you have for your values. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A tank of gas has partial pressures of nitrogen and oxygen equal to #1.61 xx 10^4# #"kPa"# and #4.34 xx 10^5# #"kPa"#, respectively. What is the total pressure of the tank? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/partial-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Partial Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="438375" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-12T02:42:20" itemprop="dateCreated"> Jun 12, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4.50 * 10^5#</mathjax> <mathjax>#"kPa"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that when the volume and the temperature of a gaseous mixture are kept <em>constant</em>, the <strong>total pressure</strong> of the mixture is equal to the sum of the <em>partial pressures</em> of its gaseous components <mathjax>#-&gt;#</mathjax> this is known as <strong>Dalton's Law of Partial Pressures</strong>.</p> <p><img alt="https://www.ck12.org/book/CK-12-Chemistry-Concepts-Intermediate/section/14.12/" src="https://useruploads.socratic.org/ANYt1puRl6jzbxWaGHJO_f-d%253Aaa7b820f730dd7f29451dcf420a450b9a418da33562c64772ef80c33%252BIMAGE_THUMB_POSTCARD_TINY%252BIMAGE_THUMB_POSTCARD_TINY.1"/> </p> <p>In your case, you know that the mixture contains nitrogen gas, <mathjax>#"N"_2#</mathjax>, and oxygen gas, <mathjax>#"O"_2#</mathjax>, which means that the total pressure of the mixture will be</p> <blockquote> <p><mathjax>#P_"total" = P_ ("N" _ 2) + P_ ("O"_ 2)#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#P_"total" = 1.61 * 10^4color(white)(.)"kPa" + 4.34 * 10^5color(white)(.)"kPa"#</mathjax></p> <p><mathjax>#P_"total" = color(darkgreen)(ul(color(black)(4.50 * 10^5color(white)(.)"kPa")))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong>decimal places</strong>, the number of decimal places you have for your values. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/438375" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534e256802bf342adfa30010"> How do you do a steam distillation? 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A tank of gas has partial pressures of nitrogen and oxygen equal to #1.61 xx 10^4# #"kPa"# and #4.34 xx 10^5# #"kPa"#, respectively. What is the total pressure of the tank?

a993d113-6ddd-11ea-8378-ccda262736ce

https://socratic.org/questions/write-a-balanced-equation-for-the-following-including-physical-states-magnesium-

Mg(s) + 2 HCl (aq) -> MgCl2(aq) + H2(g)

start chemical_equation qc_end chemical_equation 19 25 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"Mg(s) + 2 HCl (aq) -> MgCl2(aq) + H2(g)"}]

[{"type":"chemical equation","value":"Mg + HCl -> MgCl2 + H2"}]

<h1 class="questionTitle" itemprop="name">Write a balanced equation for the following, including physical states: Magnesium + Hydrochloric Acid &gt; Magnesiumchloride + Hydrogen gas Mg + HCl &gt; MgCl + H Is that it? I feel like I'm missing something. </h1>

Mg(s) + 2 HCl (aq) -> MgCl2(aq) + H2(g)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Some small details you missed are that magnesium chloride is <mathjax>#MgCl_2#</mathjax> and that hydrogen gas is <mathjax>#H_2#</mathjax>.</p> <p>So it should be:</p> <p><mathjax>#Mg_((s)) + HCl_((aq)) rarr MgCl_(2(aq)) + H_(2(g)) uarr#</mathjax></p> <p>When you balance it, it will become:</p> <p><mathjax>#Mg_((s)) + 2HCl_((aq)) rarr MgCl_(2(aq)) + H_(2(g)) uarr#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Mg_((s)) +2HCl_((aq)) rarr MgCl_(2(aq))+ H_(2(g)) uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Some small details you missed are that magnesium chloride is <mathjax>#MgCl_2#</mathjax> and that hydrogen gas is <mathjax>#H_2#</mathjax>.</p> <p>So it should be:</p> <p><mathjax>#Mg_((s)) + HCl_((aq)) rarr MgCl_(2(aq)) + H_(2(g)) uarr#</mathjax></p> <p>When you balance it, it will become:</p> <p><mathjax>#Mg_((s)) + 2HCl_((aq)) rarr MgCl_(2(aq)) + H_(2(g)) uarr#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Write a balanced equation for the following, including physical states: Magnesium + Hydrochloric Acid &gt; Magnesiumchloride + Hydrogen gas Mg + HCl &gt; MgCl + H Is that it? I feel like I'm missing something. </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="173648" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/rafael-h"><img alt="" class="" src="https://profilepictures.socratic.org/WuiPxqi9TgWHj0mFY0il_9itqpi.png" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/rafael-h"> Rafael </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-02T04:30:00" itemprop="dateCreated"> Oct 2, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Mg_((s)) +2HCl_((aq)) rarr MgCl_(2(aq))+ H_(2(g)) uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Some small details you missed are that magnesium chloride is <mathjax>#MgCl_2#</mathjax> and that hydrogen gas is <mathjax>#H_2#</mathjax>.</p> <p>So it should be:</p> <p><mathjax>#Mg_((s)) + HCl_((aq)) rarr MgCl_(2(aq)) + H_(2(g)) uarr#</mathjax></p> <p>When you balance it, it will become:</p> <p><mathjax>#Mg_((s)) + 2HCl_((aq)) rarr MgCl_(2(aq)) + H_(2(g)) uarr#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/173648" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------&gt; H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -&gt; Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Write a balanced equation for the following, including physical states: Magnesium + Hydrochloric Acid &gt; Magnesiumchloride + Hydrogen gas Mg + HCl &gt; MgCl + H Is that it? I feel like I'm missing something.

ab5ebfb6-6ddd-11ea-a776-ccda262736ce

https://socratic.org/questions/how-many-individual-atoms-make-up-one-unit-of-aluminum-chloride-alcl-3

4

start physical_unit 2 3 number none qc_end end

[{"type":"physical unit","value":"Number [OF] individual atoms"}]

[{"type":"physical unit","value":"4"}]

[{"type":"physical unit","value":"Number [OF] AlCl3 unit [=] \\pu{1}"}]

<h1 class="questionTitle" itemprop="name">How many individual atoms make up one unit of aluminum chloride, #AlCl_3#?</h1>

4

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The compound <mathjax>#"AlCl"_3#</mathjax> takes different forms depending on the temperature of its surroundings <strong>and</strong> the state that it is found in.</p> <p>As a <strong>solid</strong>, the aluminium central atoms exhibit <strong>octahedral coordinate geometry</strong>: this is because the <mathjax>#"AlCl"_3#</mathjax> unit functions as a <strong>Lewis acid</strong>, that is it will accept <strong>lone pairs of electrons</strong> donated from another source (the <strong>Lewis base</strong>) to form a <strong>dative covalent bond / coordinate bond</strong> between the two. A chlorine atom from one <mathjax>#"AlCl"_3#</mathjax> unit can donate their lone pairs to the central aluminium atom of <em>another</em> unit in this way. This results in a <strong>giant covalent structure</strong>, but the formula remains to be <mathjax>#"AlCl"_3#</mathjax>.</p> <p><img alt="Source: chemguide" src="https://useruploads.socratic.org/dAU97pKWTs6GYD090UjN_al2cl6.gif"/></p> <p>It is as a <strong>liquid</strong> that <mathjax>#8#</mathjax> atom complexes exist. As a liquid, aluminium trichloride exists in <strong>dimers</strong>, where the <mathjax>#"AlCl"_3#</mathjax> <strong>monomers</strong> exist in groups of two thanks to aluminium's ability to support <strong>tetrahedral geometry</strong> (once again through <strong>coordinate <a href="http://socratic.org/chemistry/bonding-basics/bonding">bonding</a></strong>). Observe that the central aluminium atoms support fewer bonds as a liquid than as a solid: this is because the constituent <mathjax>#"AlCl"_3#</mathjax> units have more energy and so do not require bond formation to stabilise to as great an extent. Recall that the formation of bonds <em>liberates</em> energy.</p> <p><img alt="Source: Wikipedia" src="https://useruploads.socratic.org/gnqimr8QmORjRKjBoM73_Aluminium-trichloride-dimer-3D-balls.png"/></p> <p>Aluminium trichloride dimers also exist in the <strong>vapour phase</strong>. In either of the liquid <em>or</em> vapour phases, aluminium trichloride dimers will <strong>dissociate</strong> into aluminium trichloride molecules, with a <strong>trigonal planar geometry</strong>. It is in this state that a unit of <mathjax>#"AlCl"_3#</mathjax> certainly does have <mathjax>#4#</mathjax> atoms.</p> <p><img alt="Source: scbt" src="https://useruploads.socratic.org/6VYmTG0tRwAAnnAfxEx5_111648.jpg"/></p> <p>If you would like to know more about aluminium chloride (<mathjax>#"AlCl"_3#</mathjax>), <strong><a href="https://en.wikipedia.org/wiki/Aluminium_chloride" rel="nofollow">click here</a></strong> to visit its corresponding Wikipedia article.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><strong>Macromolecular crystal OR</strong> <mathjax>#4#</mathjax> atoms <strong>OR</strong> <mathjax>#8#</mathjax> atoms</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The compound <mathjax>#"AlCl"_3#</mathjax> takes different forms depending on the temperature of its surroundings <strong>and</strong> the state that it is found in.</p> <p>As a <strong>solid</strong>, the aluminium central atoms exhibit <strong>octahedral coordinate geometry</strong>: this is because the <mathjax>#"AlCl"_3#</mathjax> unit functions as a <strong>Lewis acid</strong>, that is it will accept <strong>lone pairs of electrons</strong> donated from another source (the <strong>Lewis base</strong>) to form a <strong>dative covalent bond / coordinate bond</strong> between the two. A chlorine atom from one <mathjax>#"AlCl"_3#</mathjax> unit can donate their lone pairs to the central aluminium atom of <em>another</em> unit in this way. This results in a <strong>giant covalent structure</strong>, but the formula remains to be <mathjax>#"AlCl"_3#</mathjax>.</p> <p><img alt="Source: chemguide" src="https://useruploads.socratic.org/dAU97pKWTs6GYD090UjN_al2cl6.gif"/></p> <p>It is as a <strong>liquid</strong> that <mathjax>#8#</mathjax> atom complexes exist. As a liquid, aluminium trichloride exists in <strong>dimers</strong>, where the <mathjax>#"AlCl"_3#</mathjax> <strong>monomers</strong> exist in groups of two thanks to aluminium's ability to support <strong>tetrahedral geometry</strong> (once again through <strong>coordinate <a href="http://socratic.org/chemistry/bonding-basics/bonding">bonding</a></strong>). Observe that the central aluminium atoms support fewer bonds as a liquid than as a solid: this is because the constituent <mathjax>#"AlCl"_3#</mathjax> units have more energy and so do not require bond formation to stabilise to as great an extent. Recall that the formation of bonds <em>liberates</em> energy.</p> <p><img alt="Source: Wikipedia" src="https://useruploads.socratic.org/gnqimr8QmORjRKjBoM73_Aluminium-trichloride-dimer-3D-balls.png"/></p> <p>Aluminium trichloride dimers also exist in the <strong>vapour phase</strong>. In either of the liquid <em>or</em> vapour phases, aluminium trichloride dimers will <strong>dissociate</strong> into aluminium trichloride molecules, with a <strong>trigonal planar geometry</strong>. It is in this state that a unit of <mathjax>#"AlCl"_3#</mathjax> certainly does have <mathjax>#4#</mathjax> atoms.</p> <p><img alt="Source: scbt" src="https://useruploads.socratic.org/6VYmTG0tRwAAnnAfxEx5_111648.jpg"/></p> <p>If you would like to know more about aluminium chloride (<mathjax>#"AlCl"_3#</mathjax>), <strong><a href="https://en.wikipedia.org/wiki/Aluminium_chloride" rel="nofollow">click here</a></strong> to visit its corresponding Wikipedia article.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many individual atoms make up one unit of aluminum chloride, #AlCl_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="205905" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/owen-b"><img alt="" class="" src="https://profilepictures.socratic.org/5O90HPzZRGiovfbNkapI_Screenshot_20170906-141654.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/owen-b"> Owen Bell </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-30T22:24:36" itemprop="dateCreated"> Dec 30, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><strong>Macromolecular crystal OR</strong> <mathjax>#4#</mathjax> atoms <strong>OR</strong> <mathjax>#8#</mathjax> atoms</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The compound <mathjax>#"AlCl"_3#</mathjax> takes different forms depending on the temperature of its surroundings <strong>and</strong> the state that it is found in.</p> <p>As a <strong>solid</strong>, the aluminium central atoms exhibit <strong>octahedral coordinate geometry</strong>: this is because the <mathjax>#"AlCl"_3#</mathjax> unit functions as a <strong>Lewis acid</strong>, that is it will accept <strong>lone pairs of electrons</strong> donated from another source (the <strong>Lewis base</strong>) to form a <strong>dative covalent bond / coordinate bond</strong> between the two. A chlorine atom from one <mathjax>#"AlCl"_3#</mathjax> unit can donate their lone pairs to the central aluminium atom of <em>another</em> unit in this way. This results in a <strong>giant covalent structure</strong>, but the formula remains to be <mathjax>#"AlCl"_3#</mathjax>.</p> <p><img alt="Source: chemguide" src="https://useruploads.socratic.org/dAU97pKWTs6GYD090UjN_al2cl6.gif"/></p> <p>It is as a <strong>liquid</strong> that <mathjax>#8#</mathjax> atom complexes exist. As a liquid, aluminium trichloride exists in <strong>dimers</strong>, where the <mathjax>#"AlCl"_3#</mathjax> <strong>monomers</strong> exist in groups of two thanks to aluminium's ability to support <strong>tetrahedral geometry</strong> (once again through <strong>coordinate <a href="http://socratic.org/chemistry/bonding-basics/bonding">bonding</a></strong>). Observe that the central aluminium atoms support fewer bonds as a liquid than as a solid: this is because the constituent <mathjax>#"AlCl"_3#</mathjax> units have more energy and so do not require bond formation to stabilise to as great an extent. Recall that the formation of bonds <em>liberates</em> energy.</p> <p><img alt="Source: Wikipedia" src="https://useruploads.socratic.org/gnqimr8QmORjRKjBoM73_Aluminium-trichloride-dimer-3D-balls.png"/></p> <p>Aluminium trichloride dimers also exist in the <strong>vapour phase</strong>. In either of the liquid <em>or</em> vapour phases, aluminium trichloride dimers will <strong>dissociate</strong> into aluminium trichloride molecules, with a <strong>trigonal planar geometry</strong>. It is in this state that a unit of <mathjax>#"AlCl"_3#</mathjax> certainly does have <mathjax>#4#</mathjax> atoms.</p> <p><img alt="Source: scbt" src="https://useruploads.socratic.org/6VYmTG0tRwAAnnAfxEx5_111648.jpg"/></p> <p>If you would like to know more about aluminium chloride (<mathjax>#"AlCl"_3#</mathjax>), <strong><a href="https://en.wikipedia.org/wiki/Aluminium_chloride" rel="nofollow">click here</a></strong> to visit its corresponding Wikipedia article.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/205905" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 12105 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many individual atoms make up one unit of aluminum chloride, #AlCl_3#?

ac217e3a-6ddd-11ea-a07d-ccda262736ce

https://socratic.org/questions/how-many-moles-of-sulfur-are-in-80-grams-of-sulfur

2.5 moles

start physical_unit 4 4 mole mol qc_end physical_unit 4 4 7 8 mass qc_end end

[{"type":"physical unit","value":"Mole [OF] sulfur [IN] moles"}]

[{"type":"physical unit","value":"2.5 moles"}]

[{"type":"physical unit","value":"Mass [OF] sulfur [=] \\pu{80 grams}"}]

<h1 class="questionTitle" itemprop="name">How many moles of sulfur are in 80 grams of sulfur? </h1>

2.5 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Number of moles"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass"/"Molar mass"#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(80*g)/(32.06*g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??mol#</mathjax></p> <p>Note that sulfur likely exists in its elemental state as <mathjax>#S_8#</mathjax>. I am perfectly justified in treating sulfur as <mathjax>#S#</mathjax>. The number of <mathjax>#"sulfur atoms"#</mathjax> is the same in each case. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>About <mathjax>#2.5" moles"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Number of moles"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass"/"Molar mass"#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(80*g)/(32.06*g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??mol#</mathjax></p> <p>Note that sulfur likely exists in its elemental state as <mathjax>#S_8#</mathjax>. I am perfectly justified in treating sulfur as <mathjax>#S#</mathjax>. The number of <mathjax>#"sulfur atoms"#</mathjax> is the same in each case. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles of sulfur are in 80 grams of sulfur? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="296457" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-07T13:12:31" itemprop="dateCreated"> Aug 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>About <mathjax>#2.5" moles"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Number of moles"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass"/"Molar mass"#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(80*g)/(32.06*g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??mol#</mathjax></p> <p>Note that sulfur likely exists in its elemental state as <mathjax>#S_8#</mathjax>. I am perfectly justified in treating sulfur as <mathjax>#S#</mathjax>. The number of <mathjax>#"sulfur atoms"#</mathjax> is the same in each case. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/296457" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 13533 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many moles of sulfur are in 80 grams of sulfur?

acc9889c-6ddd-11ea-b11d-ccda262736ce

https://socratic.org/questions/what-is-the-formula-for-ammonium-nitrate

NH4NO3

start chemical_formula qc_end substance 5 6 qc_end end

[{"type":"other","value":"Chemical Formula [OF] ammonium nitrate [IN] default"}]

[{"type":"chemical equation","value":"NH4NO3"}]

[{"type":"substance name","value":"Ammonium nitrate"}]

<h1 class="questionTitle" itemprop="name">What is the formula for ammonium nitrate?</h1>

NH4NO3

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Ammonium ion <mathjax>#NH_4^+#</mathjax><br/> Nitrate ion <mathjax>#NO_3^-#</mathjax></p> <p>These have equal, but opposing charges, so we take just one of each to 'build' the salt.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#NH_4NO_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Ammonium ion <mathjax>#NH_4^+#</mathjax><br/> Nitrate ion <mathjax>#NO_3^-#</mathjax></p> <p>These have equal, but opposing charges, so we take just one of each to 'build' the salt.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the formula for ammonium nitrate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/determining-formula-and-molar-masses" itemprop="url"> <span class="breadcrumb" itemprop="title">Determining Formula</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="350326" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meneernask"><img alt="" class="" src="https://profilepictures.socratic.org/gpA0lokRGK9vLVUnAMAy_meneernask.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meneernask"> MeneerNask </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-11T23:01:24" itemprop="dateCreated"> Dec 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#NH_4NO_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Ammonium ion <mathjax>#NH_4^+#</mathjax><br/> Nitrate ion <mathjax>#NO_3^-#</mathjax></p> <p>These have equal, but opposing charges, so we take just one of each to 'build' the salt.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/350326" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-possible-to-find-a-molecular-formula-from-molar-mass"> Is it possible to find a molecular formula from molar mass? 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What is the formula for ammonium nitrate?

acd4b85e-6ddd-11ea-b97e-ccda262736ce

https://socratic.org/questions/what-net-lonic-equation-can-be-derived-from-this-complete-ionic-equation-2fe-3-a

2 Fe^3+(aq) + 3 CO3^2-(aq) -> Fe2(CO3)3(s)

start chemical_equation qc_end chemical_equation 12 30 qc_end end

[{"type":"other","value":"Chemical Equation [OF] net lonic equation"}]

[{"type":"chemical equation","value":"2 Fe^3+(aq) + 3 CO3^2-(aq) -> Fe2(CO3)3(s) "}]

[{"type":"chemical equation","value":"2 Fe^3+(aq) + 6 Cl-(aq) + 6 Na+(aq) + 3 CO3^2-(aq) -> Fe2(CO3)3(s) + 6 Cl-(aq) + 6 Na+(aq)?"}]

<h1 class="questionTitle" itemprop="name">What net lonic equation can be derived from this complete ionic equation? #2Fe^(3+)(aq) + 6Cl^-(aq) + 6Na^+(aq) + 3CO_3^(2-)(aq) -&gt; Fe_2(CO_3)_3(s) + 6Cl^-(aq) + 6Na^+(aq)#?</h1>

2 Fe^3+(aq) + 3 CO3^2-(aq) -> Fe2(CO3)3(s)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Simply cancel out the common items, the ones that do not undergo chemical change in the original equation:</p> <p><mathjax>#2Fe^(3+) + cancel(6Cl^(-) + 6Na^(+)) + 3CO_3^(2-) rarr Fe_2(CO_3)_3(s)darr +cancel(6Na^(+) + 6Cl^(-))#</mathjax></p> <p>Are mass and charge balanced in the given equation? If they are not, you know that the equation cannot be accepted as a representation of reality. In other words these equations must obey <a href="https://socratic.org/questions/can-you-give-examples-of-the-uses-of-stoichiometry-in-our-daily-life">stoichiometry.</a> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2Fe^(3+) + 3CO_3^(2-) rarr Fe_2(CO_3)_3(s)darr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Simply cancel out the common items, the ones that do not undergo chemical change in the original equation:</p> <p><mathjax>#2Fe^(3+) + cancel(6Cl^(-) + 6Na^(+)) + 3CO_3^(2-) rarr Fe_2(CO_3)_3(s)darr +cancel(6Na^(+) + 6Cl^(-))#</mathjax></p> <p>Are mass and charge balanced in the given equation? If they are not, you know that the equation cannot be accepted as a representation of reality. In other words these equations must obey <a href="https://socratic.org/questions/can-you-give-examples-of-the-uses-of-stoichiometry-in-our-daily-life">stoichiometry.</a> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What net lonic equation can be derived from this complete ionic equation? #2Fe^(3+)(aq) + 6Cl^-(aq) + 6Na^+(aq) + 3CO_3^(2-)(aq) -&gt; Fe_2(CO_3)_3(s) + 6Cl^-(aq) + 6Na^+(aq)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="399314" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-31T02:12:14" itemprop="dateCreated"> Mar 31, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2Fe^(3+) + 3CO_3^(2-) rarr Fe_2(CO_3)_3(s)darr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Simply cancel out the common items, the ones that do not undergo chemical change in the original equation:</p> <p><mathjax>#2Fe^(3+) + cancel(6Cl^(-) + 6Na^(+)) + 3CO_3^(2-) rarr Fe_2(CO_3)_3(s)darr +cancel(6Na^(+) + 6Cl^(-))#</mathjax></p> <p>Are mass and charge balanced in the given equation? If they are not, you know that the equation cannot be accepted as a representation of reality. In other words these equations must obey <a href="https://socratic.org/questions/can-you-give-examples-of-the-uses-of-stoichiometry-in-our-daily-life">stoichiometry.</a> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/399314" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="399315" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/dwight"><img alt="" class="" src="https://profilepictures.socratic.org/ZDiTFWmAQmWOT3sd0Xpr_Dwight.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/dwight"> Dwight </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-31T02:12:43" itemprop="dateCreated"> Mar 31, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Cancel the "spectator ions" - that undergo no changes, and the net ionic equation appears. Details follow.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In a net ionic equation you omit any particles (generally ions) that are not changed in any way as the reaction occurs.</p> <p>In this case, this applies to the <mathjax>#Na^+#</mathjax> and <mathjax>#Cl^-#</mathjax> ions. </p> <p>So, the net ionic equation is:</p> <p><mathjax>#2Fe^(3+) (aq)+ 3 CO_3^(2-)(aq) rarr Fe_2(CO_3)_3(s)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/399315" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-chloride"> What is the ionic formula for calcium chloride? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-oxide"> What is the ionic formula for calcium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-lithium-oxide"> What is the ionic formula for lithium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-formula-for-ionic-compounds"> How do you write the formula for ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-correctly-write-the-ions-present-in-sn-no3-2"> How do I write #Sn(NO_3)_2# in Ionic formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-an-ionic-compound"> What is the empirical formula for an ionic compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-for-chorate"> What is the molecular formula for chorate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5363023c02bf343b2ee7086b"> Question #7086b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-polyatomic-ions-covalent-1"> Why are polyatomic ions covalent? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas"> See all questions in Writing Ionic Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6083 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What net lonic equation can be derived from this complete ionic equation? #2Fe^(3+)(aq) + 6Cl^-(aq) + 6Na^+(aq) + 3CO_3^(2-)(aq) -&gt; Fe_2(CO_3)_3(s) + 6Cl^-(aq) + 6Na^+(aq)#?

a90441de-6ddd-11ea-b8fc-ccda262736ce

https://socratic.org/questions/what-is-the-oxidation-state-of-chlorine-in-kclo3

+5

start physical_unit 6 6 oxidation_state none qc_end chemical_equation 8 8 qc_end end

[{"type":"physical unit","value":"Oxidation state [OF] chlorine"}]

[{"type":"physical unit","value":"+5"}]

[{"type":"chemical equation","value":"KClO3"}]

<h1 class="questionTitle" itemprop="name">What is the oxidation state of chlorine in KClO3?</h1>

+5

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Excellent question! I love oxidation state questions.</p> <p>First, let's look at the <mathjax>#"K"#</mathjax> (potassium). In an ionic compound, the potassium's oxidation state is always <mathjax>#+1#</mathjax>.</p> <p>Next, let's look at the chlorate , <mathjax>#"ClO"_3^-#</mathjax>. The charge on the polyatomic ion is <mathjax>#-1#</mathjax>. You may be asking yourself, <em>how do I know its charge will be</em> <mathjax>#-1#</mathjax><em>?</em></p> <p>Since the entire compound <mathjax>#"KClO"_3#</mathjax> has a charge of <mathjax>#0#</mathjax> and the <mathjax>#"K"#</mathjax> will have a charge of <mathjax>#+1#</mathjax>, the <mathjax>#"ClO"_3#</mathjax> must balance the <mathjax>#"K"#</mathjax>'s <mathjax>#+1#</mathjax> in the form of <mathjax>#-1#</mathjax> for a net charge of <mathjax>#0#</mathjax>.</p> <p>When oxygen is with another element that is less electronegative than it is, the charge on the oxygen is <mathjax>#-2#</mathjax>. There are <mathjax>#3#</mathjax> oxygen atoms in the chlorate ion, for a total of <mathjax>#-6#</mathjax> charge on the total of the <mathjax>#3#</mathjax> oxygen atoms. </p> <p>Thus, <mathjax>#"charge of Cl"#</mathjax> <mathjax>#+(-6)=-1#</mathjax>. That means that the charge on chlorine in potassium chlorate is <mathjax>#+5#</mathjax>.</p> <p>Have a great day!! </p> <p> <iframe src="https://www.youtube.com/embed/hSNwds-H1_0?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#+5#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Excellent question! I love oxidation state questions.</p> <p>First, let's look at the <mathjax>#"K"#</mathjax> (potassium). In an ionic compound, the potassium's oxidation state is always <mathjax>#+1#</mathjax>.</p> <p>Next, let's look at the chlorate , <mathjax>#"ClO"_3^-#</mathjax>. The charge on the polyatomic ion is <mathjax>#-1#</mathjax>. You may be asking yourself, <em>how do I know its charge will be</em> <mathjax>#-1#</mathjax><em>?</em></p> <p>Since the entire compound <mathjax>#"KClO"_3#</mathjax> has a charge of <mathjax>#0#</mathjax> and the <mathjax>#"K"#</mathjax> will have a charge of <mathjax>#+1#</mathjax>, the <mathjax>#"ClO"_3#</mathjax> must balance the <mathjax>#"K"#</mathjax>'s <mathjax>#+1#</mathjax> in the form of <mathjax>#-1#</mathjax> for a net charge of <mathjax>#0#</mathjax>.</p> <p>When oxygen is with another element that is less electronegative than it is, the charge on the oxygen is <mathjax>#-2#</mathjax>. There are <mathjax>#3#</mathjax> oxygen atoms in the chlorate ion, for a total of <mathjax>#-6#</mathjax> charge on the total of the <mathjax>#3#</mathjax> oxygen atoms. </p> <p>Thus, <mathjax>#"charge of Cl"#</mathjax> <mathjax>#+(-6)=-1#</mathjax>. That means that the charge on chlorine in potassium chlorate is <mathjax>#+5#</mathjax>.</p> <p>Have a great day!! </p> <p> <iframe src="https://www.youtube.com/embed/hSNwds-H1_0?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the oxidation state of chlorine in KClO3?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-numbers" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation Numbers</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="106733" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kathryn-celestine"><img alt="" class="" src="https://lh3.googleusercontent.com/-XdUIqdMkCWA/AAAAAAAAAAI/AAAAAAAAAAA/4252rscbv5M/photo.jpg?sz=50" title=""/></a> <a class="secondContributorPic" href="/users/mason-m"><img alt="" class="" src="https://profilepictures.socratic.org/U70pu8hUTGGkEuy92fsO_IMG_2585.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kathryn-celestine"> Kathryn Celestine </a>·<a class="topContributorLink" href="/users/mason-m"> mason m </a>·<a class="topContributorLink" href="/users/dwayne-m"> Dwayne M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2014-07-14T19:25:56" itemprop="dateCreated"> Jul 14, 2014 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#+5#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Excellent question! I love oxidation state questions.</p> <p>First, let's look at the <mathjax>#"K"#</mathjax> (potassium). In an ionic compound, the potassium's oxidation state is always <mathjax>#+1#</mathjax>.</p> <p>Next, let's look at the chlorate , <mathjax>#"ClO"_3^-#</mathjax>. The charge on the polyatomic ion is <mathjax>#-1#</mathjax>. You may be asking yourself, <em>how do I know its charge will be</em> <mathjax>#-1#</mathjax><em>?</em></p> <p>Since the entire compound <mathjax>#"KClO"_3#</mathjax> has a charge of <mathjax>#0#</mathjax> and the <mathjax>#"K"#</mathjax> will have a charge of <mathjax>#+1#</mathjax>, the <mathjax>#"ClO"_3#</mathjax> must balance the <mathjax>#"K"#</mathjax>'s <mathjax>#+1#</mathjax> in the form of <mathjax>#-1#</mathjax> for a net charge of <mathjax>#0#</mathjax>.</p> <p>When oxygen is with another element that is less electronegative than it is, the charge on the oxygen is <mathjax>#-2#</mathjax>. There are <mathjax>#3#</mathjax> oxygen atoms in the chlorate ion, for a total of <mathjax>#-6#</mathjax> charge on the total of the <mathjax>#3#</mathjax> oxygen atoms. </p> <p>Thus, <mathjax>#"charge of Cl"#</mathjax> <mathjax>#+(-6)=-1#</mathjax>. That means that the charge on chlorine in potassium chlorate is <mathjax>#+5#</mathjax>.</p> <p>Have a great day!! </p> <p> <iframe src="https://www.youtube.com/embed/hSNwds-H1_0?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/106733" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-electron-configuration"> How do oxidation numbers relate to electron configuration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-valence-electrons"> How do oxidation numbers relate to valence electrons? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-vary-with-the-periodic-table"> How do oxidation numbers vary with the periodic table? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-oxidation-number-of-an-element-in-a-compound"> How do you calculate the oxidation number of an element in a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-sulfur"> What is the oxidation number for sulfur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-carbon"> What is the oxidation number for carbon? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-copper"> What is the oxidation number for copper? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-nitrogen"> What is the oxidation number for nitrogen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-oxygen"> What is the oxidation number for oxygen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-state-of-noble-gas-zero"> Why is the oxidation state of noble gas zero? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-numbers"> See all questions in Oxidation Numbers </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 80364 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the oxidation state of chlorine in KClO3?

aaf80528-6ddd-11ea-9647-ccda262736ce

https://socratic.org/questions/what-the-mass-percent-of-aluminum-in-al-oh-3

34.59%

start physical_unit 5 7 mass_percent none qc_end physical_unit 7 7 14 15 molar_mass qc_end physical_unit 15 15 17 18 molar_mass qc_end physical_unit 20 20 22 23 molar_mass qc_end end

[{"type":"physical unit","value":"Mass percent [OF] aluminum in Al(OH)3"}]

[{"type":"physical unit","value":"34.59%"}]

[{"type":"physical unit","value":"Molar mass [OF] Al [=] \\pu{26.98 g/mol}"},{"type":"physical unit","value":"Molar mass [OF] H [=] \\pu{1.0079 g/mol}"},{"type":"physical unit","value":"Molar mass [OF] O [=] \\pu{16.00 g/mol}"}]

<h1 class="questionTitle" itemprop="name">What the mass percent of aluminum in #Al(OH)_3#?</h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The molar mass of <mathjax>#Al = 26.98, H = 1.0079, #</mathjax> and <mathjax>#O=16.00#</mathjax>.</p></div> </h2> </div> </div>

34.59%

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to calculate the mass percent of aluminum in that ionic compound, we're going to need two things:</p> <p><mathjax>#color(blue) "1: The formula mass of the entire compound"#</mathjax><br/> <mathjax>#color(blue) "2: The atomic mass of aluminum"#</mathjax></p> <p>The formula mass of aluminum hydroxide is <mathjax>#78.00 g/(mol)#</mathjax> because:</p> <p><mathjax>#26.98g/(mol) + 3(16.00g/"mol") + 3(1.0079 g/"mol")#</mathjax> <mathjax>#= 78.00 g/(mol)#</mathjax></p> <p>We already know the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of aluminum since that's already given.</p> <p>Now, we have to use the following equation:</p> <p><img alt="https://wilsonsch3u-01-2012.wikispaces.com/Unit+4+Moles?responseToken=6fbe1bc52003b1c7d0a470e50127b3a2" src="https://useruploads.socratic.org/XGlGuOsiTiC7KTHJGH5y_Percent%20Composition%20Formula.jpg"/> </p> <p>The numerator represents the mass of the desired atom, which is Al in our case, and the denominator represents the mass of the entire compound. You just divide the two and multiply by 100 to obtain the <a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a>:</p> <p><mathjax>#"Mass of Al"/("Molar Mass of Al(OH)"_3)" xx100%#</mathjax></p> <p><mathjax>#"26.98 g/mol"/"78.00g/mol"xx100% = 34.59%#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#color(magenta)"34.59%"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to calculate the mass percent of aluminum in that ionic compound, we're going to need two things:</p> <p><mathjax>#color(blue) "1: The formula mass of the entire compound"#</mathjax><br/> <mathjax>#color(blue) "2: The atomic mass of aluminum"#</mathjax></p> <p>The formula mass of aluminum hydroxide is <mathjax>#78.00 g/(mol)#</mathjax> because:</p> <p><mathjax>#26.98g/(mol) + 3(16.00g/"mol") + 3(1.0079 g/"mol")#</mathjax> <mathjax>#= 78.00 g/(mol)#</mathjax></p> <p>We already know the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of aluminum since that's already given.</p> <p>Now, we have to use the following equation:</p> <p><img alt="https://wilsonsch3u-01-2012.wikispaces.com/Unit+4+Moles?responseToken=6fbe1bc52003b1c7d0a470e50127b3a2" src="https://useruploads.socratic.org/XGlGuOsiTiC7KTHJGH5y_Percent%20Composition%20Formula.jpg"/> </p> <p>The numerator represents the mass of the desired atom, which is Al in our case, and the denominator represents the mass of the entire compound. You just divide the two and multiply by 100 to obtain the <a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a>:</p> <p><mathjax>#"Mass of Al"/("Molar Mass of Al(OH)"_3)" xx100%#</mathjax></p> <p><mathjax>#"26.98 g/mol"/"78.00g/mol"xx100% = 34.59%#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What the mass percent of aluminum in #Al(OH)_3#?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The molar mass of <mathjax>#Al = 26.98, H = 1.0079, #</mathjax> and <mathjax>#O=16.00#</mathjax>.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/percent-composition" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Composition</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="359226" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> <a class="secondContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a>·<a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-02T03:17:55" itemprop="dateCreated"> Jan 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#color(magenta)"34.59%"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to calculate the mass percent of aluminum in that ionic compound, we're going to need two things:</p> <p><mathjax>#color(blue) "1: The formula mass of the entire compound"#</mathjax><br/> <mathjax>#color(blue) "2: The atomic mass of aluminum"#</mathjax></p> <p>The formula mass of aluminum hydroxide is <mathjax>#78.00 g/(mol)#</mathjax> because:</p> <p><mathjax>#26.98g/(mol) + 3(16.00g/"mol") + 3(1.0079 g/"mol")#</mathjax> <mathjax>#= 78.00 g/(mol)#</mathjax></p> <p>We already know the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of aluminum since that's already given.</p> <p>Now, we have to use the following equation:</p> <p><img alt="https://wilsonsch3u-01-2012.wikispaces.com/Unit+4+Moles?responseToken=6fbe1bc52003b1c7d0a470e50127b3a2" src="https://useruploads.socratic.org/XGlGuOsiTiC7KTHJGH5y_Percent%20Composition%20Formula.jpg"/> </p> <p>The numerator represents the mass of the desired atom, which is Al in our case, and the denominator represents the mass of the entire compound. You just divide the two and multiply by 100 to obtain the <a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a>:</p> <p><mathjax>#"Mass of Al"/("Molar Mass of Al(OH)"_3)" xx100%#</mathjax></p> <p><mathjax>#"26.98 g/mol"/"78.00g/mol"xx100% = 34.59%#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/359226" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-mole-percent"> What is mole percent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188602bf3469570e2e8b"> Question #e2e8b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188702bf34695a6bc737"> Question #bc737 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418be02bf34695a6bc73b"> Question #bc73b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c202bf3469570e2e8f"> Question #e2e8f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c802bf346963eb9857"> Question #b9857 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418ca02bf346963eb985b"> Question #b985b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418cc02bf34694a4fee41"> Question #fee41 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418d502bf34694c8c5c01"> Question #c5c01 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4196e02bf34695a6bc73f"> Question #bc73f </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/percent-composition"> See all questions in Percent Composition </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 15932 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What the mass percent of aluminum in #Al(OH)_3#?

The molar mass of #Al = 26.98, H = 1.0079, # and #O=16.00#.

ab9fbf02-6ddd-11ea-89d8-ccda262736ce

https://socratic.org/questions/565b5c21581e2a2493d6b6b1

Al2(SO4)3

start chemical_formula qc_end substance 6 7 qc_end end

[{"type":"other","value":"Chemical Formula [OF] aluminum sulfate [IN] default"}]

[{"type":"chemical equation","value":"Al2(SO4)3"}]

[{"type":"substance name","value":"Aluminum sulfate"}]

<h1 class="questionTitle" itemprop="name">What is the chemical formula of #"aluminum sulfate"#?</h1>

Al2(SO4)3

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The sulfate anion has a <mathjax>#-2#</mathjax> charge, whereas the aluminum cation has a <mathjax>#+3#</mathjax> charge. The ionic compound must be electrically neutral. Thus we take 2 aluminum ions (6+ charge) and 3 sulfate ions (6-) charge, and achieve electrical neutrality. Are you happy with this treatment? What is the formula for sodium sulfate?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Al_2(SO_4)_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The sulfate anion has a <mathjax>#-2#</mathjax> charge, whereas the aluminum cation has a <mathjax>#+3#</mathjax> charge. The ionic compound must be electrically neutral. Thus we take 2 aluminum ions (6+ charge) and 3 sulfate ions (6-) charge, and achieve electrical neutrality. Are you happy with this treatment? What is the formula for sodium sulfate?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the chemical formula of #"aluminum sulfate"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="194462" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-29T21:09:04" itemprop="dateCreated"> Nov 29, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Al_2(SO_4)_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The sulfate anion has a <mathjax>#-2#</mathjax> charge, whereas the aluminum cation has a <mathjax>#+3#</mathjax> charge. The ionic compound must be electrically neutral. Thus we take 2 aluminum ions (6+ charge) and 3 sulfate ions (6-) charge, and achieve electrical neutrality. Are you happy with this treatment? What is the formula for sodium sulfate?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/194462" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-chloride"> What is the ionic formula for calcium chloride? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-oxide"> What is the ionic formula for calcium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-lithium-oxide"> What is the ionic formula for lithium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-formula-for-ionic-compounds"> How do you write the formula for ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-correctly-write-the-ions-present-in-sn-no3-2"> How do I write #Sn(NO_3)_2# in Ionic formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-an-ionic-compound"> What is the empirical formula for an ionic compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-for-chorate"> What is the molecular formula for chorate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5363023c02bf343b2ee7086b"> Question #7086b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-polyatomic-ions-covalent-1"> Why are polyatomic ions covalent? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas"> See all questions in Writing Ionic Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 12615 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the chemical formula of #"aluminum sulfate"#?

ac7015ee-6ddd-11ea-891e-ccda262736ce

https://socratic.org/questions/a-substance-has-a-molar-mass-of-40-0g-mol-if-the-decomposition-of-1-00mole-of-th

30.0 kJ

start physical_unit 36 37 heat_energy kj qc_end physical_unit 36 37 7 8 molar_mass qc_end physical_unit 36 37 13 14 mole qc_end physical_unit 36 37 19 20 heat_energy qc_end physical_unit 36 37 33 34 mass qc_end end

[{"type":"physical unit","value":"Absorbed energy2 [OF] the substance [IN] kJ"}]

[{"type":"physical unit","value":"30.0 kJ"}]

[{"type":"physical unit","value":"Molar mass [OF] the substance [=] \\pu{40.0 g/mol}"},{"type":"physical unit","value":"Mole1 [OF] the substance [=] \\pu{1.00 mole}"},{"type":"physical unit","value":"Absorbed energy1 [OF] the substance [=] \\pu{60.0 kJ}"},{"type":"physical unit","value":"Mass2 [OF] the substance [=] \\pu{20.0 g}"}]

<h1 class="questionTitle" itemprop="name">A substance has a molar mass of 40.0g/mol. If the decomposition of 1.00mole of this substance absorbs 60.0KJ of energy, how much energy would be absorbed by the decomposition of 20.0g of the substance?</h1>

30.0 kJ

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the given molar mass to determine how many moles you'd get in the <mathjax>#"20.0 g"#</mathjax> sample. </p> <p>So, a substance's molar mass tells you what the exact mass of <strong>one mole</strong> of said substance is. In your case, the substance has a molar mass of <mathjax>#"40.0 g/mol"#</mathjax>, which means that <strong>every mole</strong> will have a mass of <mathjax>#"40.0 g"#</mathjax>. </p> <p>If that's the case, then you can say that</p> <blockquote> <p><mathjax>#20.0color(red)(cancel(color(black)("g"))) * "1 mole"/(40.0color(red)(cancel(color(black)("g")))) = "0.500 moles"#</mathjax></p> </blockquote> <p>So, if <mathjax>#"60.0 kJ"#</mathjax> of heat are being absorbed when <mathjax>#1.00#</mathjax> moles undergo decomposition, it follows that the decomposition of <mathjax>#0.500#</mathjax> moles wil require</p> <blockquote> <p><mathjax>#0.500color(red)(cancel(color(black)("moles"))) * "60.0 kJ"/(1.00color(red)(cancel(color(black)("mole")))) = color(green)("30.0 kJ")#</mathjax></p> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"30.0 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the given molar mass to determine how many moles you'd get in the <mathjax>#"20.0 g"#</mathjax> sample. </p> <p>So, a substance's molar mass tells you what the exact mass of <strong>one mole</strong> of said substance is. In your case, the substance has a molar mass of <mathjax>#"40.0 g/mol"#</mathjax>, which means that <strong>every mole</strong> will have a mass of <mathjax>#"40.0 g"#</mathjax>. </p> <p>If that's the case, then you can say that</p> <blockquote> <p><mathjax>#20.0color(red)(cancel(color(black)("g"))) * "1 mole"/(40.0color(red)(cancel(color(black)("g")))) = "0.500 moles"#</mathjax></p> </blockquote> <p>So, if <mathjax>#"60.0 kJ"#</mathjax> of heat are being absorbed when <mathjax>#1.00#</mathjax> moles undergo decomposition, it follows that the decomposition of <mathjax>#0.500#</mathjax> moles wil require</p> <blockquote> <p><mathjax>#0.500color(red)(cancel(color(black)("moles"))) * "60.0 kJ"/(1.00color(red)(cancel(color(black)("mole")))) = color(green)("30.0 kJ")#</mathjax></p> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A substance has a molar mass of 40.0g/mol. If the decomposition of 1.00mole of this substance absorbs 60.0KJ of energy, how much energy would be absorbed by the decomposition of 20.0g of the substance?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="184283" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-05T20:11:54" itemprop="dateCreated"> Nov 5, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"30.0 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the given molar mass to determine how many moles you'd get in the <mathjax>#"20.0 g"#</mathjax> sample. </p> <p>So, a substance's molar mass tells you what the exact mass of <strong>one mole</strong> of said substance is. In your case, the substance has a molar mass of <mathjax>#"40.0 g/mol"#</mathjax>, which means that <strong>every mole</strong> will have a mass of <mathjax>#"40.0 g"#</mathjax>. </p> <p>If that's the case, then you can say that</p> <blockquote> <p><mathjax>#20.0color(red)(cancel(color(black)("g"))) * "1 mole"/(40.0color(red)(cancel(color(black)("g")))) = "0.500 moles"#</mathjax></p> </blockquote> <p>So, if <mathjax>#"60.0 kJ"#</mathjax> of heat are being absorbed when <mathjax>#1.00#</mathjax> moles undergo decomposition, it follows that the decomposition of <mathjax>#0.500#</mathjax> moles wil require</p> <blockquote> <p><mathjax>#0.500color(red)(cancel(color(black)("moles"))) * "60.0 kJ"/(1.00color(red)(cancel(color(black)("mole")))) = color(green)("30.0 kJ")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/184283" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-read-differential-scanning-in-calorimetry"> What information do you get from a differential scanning calorimetry plot? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-calorimetry"> How do you measure calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531d304102bf341e75b962a7"> Question #962a7 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5335021802bf344ae911dfc5"> Question #1dfc5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668f502bf34572c341af6"> Question #41af6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-definition-of-calorimetry"> What is calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-differential-scanning-calorimeter"> What is a differential scanning calorimeter? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-calorimeter-measure-energy"> How can a calorimeter measure energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-calorimeters-made-of"> What are calorimeters made of? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/calorimetry"> See all questions in Calorimetry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3264 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A substance has a molar mass of 40.0g/mol. If the decomposition of 1.00mole of this substance absorbs 60.0KJ of energy, how much energy would be absorbed by the decomposition of 20.0g of the substance?

ad1b1869-6ddd-11ea-836b-ccda262736ce

https://socratic.org/questions/an-oxygen-gas-container-has-a-volume-of-20-0-l-how-many-grams-of-oxygen-are-in-t

30.4 grams

start physical_unit 1 2 mass g qc_end physical_unit 1 2 8 9 volume qc_end physical_unit 1 2 26 27 pressure qc_end physical_unit 1 2 29 30 temperature qc_end end

[{"type":"physical unit","value":"Mass [OF] oxygen gas [IN] grams"}]

[{"type":"physical unit","value":"30.4 grams"}]

[{"type":"physical unit","value":"Volume [OF] oxygen gas [=] \\pu{20.0 L}"},{"type":"physical unit","value":"Pressure [OF] oxygen gas [=] \\pu{876 mmHg}"},{"type":"physical unit","value":"Temperature [OF] oxygen gas [=] \\pu{23 ℃}"}]

<h1 class="questionTitle" itemprop="name">An oxygen gas container has a volume of 20.0 L. How many grams of oxygen are in the container if the gas has a pressure of 876 mmHg at 23 C?</h1>

30.4 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>. We are given the pressure, the temperature and the volume. The gas constant will be <mathjax>#62.36#</mathjax></p> <p><mathjax>#PV = nRT#</mathjax></p> <p>We're looking for <mathjax>#n#</mathjax>, the number of moles in the sample. Note that <mathjax>#23˚C= 23 + 273 = 296K#</mathjax></p> <blockquote> <p><mathjax>#(20.0 L)(876 mmHg) = n(62.36 mmHg L k^-1 mol^-1)296K#</mathjax></p> </blockquote> <p>If we cancel all units we're left with</p> <blockquote> <p><mathjax>#n = 0.949 #</mathjax> mol</p> </blockquote> <p>Knowing that </p> <blockquote> <p><mathjax>#"molar mass" = ("number of grams per sample")/("number of moles")#</mathjax></p> </blockquote> <p>And that the molar mass of oxygen is <mathjax>#32.00 g/(mol)#</mathjax>, we can solve for number of grams in sample. </p> <blockquote> <p><mathjax>#32.00 g/(mol) * 0.949 mol = g#</mathjax></p> <p><mathjax>#g = 30.4 " grams"#</mathjax></p> </blockquote> <p>Notice I rounded to <mathjax>#3#</mathjax> sig figs. </p> <p>Hopefully this helps!</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#30.4#</mathjax> grams of oxygen in the sample. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>. We are given the pressure, the temperature and the volume. The gas constant will be <mathjax>#62.36#</mathjax></p> <p><mathjax>#PV = nRT#</mathjax></p> <p>We're looking for <mathjax>#n#</mathjax>, the number of moles in the sample. Note that <mathjax>#23˚C= 23 + 273 = 296K#</mathjax></p> <blockquote> <p><mathjax>#(20.0 L)(876 mmHg) = n(62.36 mmHg L k^-1 mol^-1)296K#</mathjax></p> </blockquote> <p>If we cancel all units we're left with</p> <blockquote> <p><mathjax>#n = 0.949 #</mathjax> mol</p> </blockquote> <p>Knowing that </p> <blockquote> <p><mathjax>#"molar mass" = ("number of grams per sample")/("number of moles")#</mathjax></p> </blockquote> <p>And that the molar mass of oxygen is <mathjax>#32.00 g/(mol)#</mathjax>, we can solve for number of grams in sample. </p> <blockquote> <p><mathjax>#32.00 g/(mol) * 0.949 mol = g#</mathjax></p> <p><mathjax>#g = 30.4 " grams"#</mathjax></p> </blockquote> <p>Notice I rounded to <mathjax>#3#</mathjax> sig figs. </p> <p>Hopefully this helps!</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">An oxygen gas container has a volume of 20.0 L. How many grams of oxygen are in the container if the gas has a pressure of 876 mmHg at 23 C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="532206" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/hsbc244"><img alt="" class="" src="https://profilepictures.socratic.org/mbvLHvFcSSXGyfQGclNQ_image.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/hsbc244"> Noah G </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-01-08T16:28:07" itemprop="dateCreated"> Jan 8, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#30.4#</mathjax> grams of oxygen in the sample. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>. We are given the pressure, the temperature and the volume. The gas constant will be <mathjax>#62.36#</mathjax></p> <p><mathjax>#PV = nRT#</mathjax></p> <p>We're looking for <mathjax>#n#</mathjax>, the number of moles in the sample. Note that <mathjax>#23˚C= 23 + 273 = 296K#</mathjax></p> <blockquote> <p><mathjax>#(20.0 L)(876 mmHg) = n(62.36 mmHg L k^-1 mol^-1)296K#</mathjax></p> </blockquote> <p>If we cancel all units we're left with</p> <blockquote> <p><mathjax>#n = 0.949 #</mathjax> mol</p> </blockquote> <p>Knowing that </p> <blockquote> <p><mathjax>#"molar mass" = ("number of grams per sample")/("number of moles")#</mathjax></p> </blockquote> <p>And that the molar mass of oxygen is <mathjax>#32.00 g/(mol)#</mathjax>, we can solve for number of grams in sample. </p> <blockquote> <p><mathjax>#32.00 g/(mol) * 0.949 mol = g#</mathjax></p> <p><mathjax>#g = 30.4 " grams"#</mathjax></p> </blockquote> <p>Notice I rounded to <mathjax>#3#</mathjax> sig figs. </p> <p>Hopefully this helps!</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/532206" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 12776 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

An oxygen gas container has a volume of 20.0 L. How many grams of oxygen are in the container if the gas has a pressure of 876 mmHg at 23 C?

aab3b2d2-6ddd-11ea-9689-ccda262736ce

https://socratic.org/questions/5732ce8011ef6b68409fbc5f

0.40 g

start physical_unit 17 18 mass g qc_end physical_unit 5 5 1 2 mass qc_end physical_unit 12 13 10 11 mass qc_end end

[{"type":"physical unit","value":"Mass [OF] dihydrogen gas [IN] g"}]

[{"type":"physical unit","value":"0.40 g"}]

[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{3.6 g}"},{"type":"physical unit","value":"Mass [OF] dioxygen gas [=] \\pu{3.2 g}"}]

<h1 class="questionTitle" itemprop="name">A #3.6*g# mass of water was decomposed to give #3.2*g# dioxygen gas. What mass of dihydrogen gas was evolved?</h1>

0.40 g

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Mass is conserved in every chemical reaction. So, if I start with 10 g of reactant I must finish with 10 g of product. You started with 3.6 g of water, and this mass was decomposed. You got 3.2 g oxygen gas, and the balance must have been the other constituent, hydrogen gas. </p> <p>What the question tries to develop is an appreciation of the conservation of mass. 10 g, 10 kg, 10 tonnes, of reactant, NECESSARILY leads to 10 g, 10 kg, 10 tonnes of product. </p> <p>As to the equation, this is simply gravy:</p> <p><mathjax>#H_2O(g) rarr H_2(g) + 1/2O_2(g)#</mathjax></p> <p>Is conservation of mass apparent here? Why and how?</p> <p>Just on the question of balancing the equation, you could of course remove the half coefficient on dioxygen gas by doubling the entire equation. I have never seen the need to do so, inasmuch as the stoichiometry, the proportion of reactants and products, is easier to appreciate with the half coefficient.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We can immediately state that 0.4 g hydrogen gas will be produced.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Mass is conserved in every chemical reaction. So, if I start with 10 g of reactant I must finish with 10 g of product. You started with 3.6 g of water, and this mass was decomposed. You got 3.2 g oxygen gas, and the balance must have been the other constituent, hydrogen gas. </p> <p>What the question tries to develop is an appreciation of the conservation of mass. 10 g, 10 kg, 10 tonnes, of reactant, NECESSARILY leads to 10 g, 10 kg, 10 tonnes of product. </p> <p>As to the equation, this is simply gravy:</p> <p><mathjax>#H_2O(g) rarr H_2(g) + 1/2O_2(g)#</mathjax></p> <p>Is conservation of mass apparent here? Why and how?</p> <p>Just on the question of balancing the equation, you could of course remove the half coefficient on dioxygen gas by doubling the entire equation. I have never seen the need to do so, inasmuch as the stoichiometry, the proportion of reactants and products, is easier to appreciate with the half coefficient.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A #3.6*g# mass of water was decomposed to give #3.2*g# dioxygen gas. What mass of dihydrogen gas was evolved?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="264531" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-11T06:24:39" itemprop="dateCreated"> May 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We can immediately state that 0.4 g hydrogen gas will be produced.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Mass is conserved in every chemical reaction. So, if I start with 10 g of reactant I must finish with 10 g of product. You started with 3.6 g of water, and this mass was decomposed. You got 3.2 g oxygen gas, and the balance must have been the other constituent, hydrogen gas. </p> <p>What the question tries to develop is an appreciation of the conservation of mass. 10 g, 10 kg, 10 tonnes, of reactant, NECESSARILY leads to 10 g, 10 kg, 10 tonnes of product. </p> <p>As to the equation, this is simply gravy:</p> <p><mathjax>#H_2O(g) rarr H_2(g) + 1/2O_2(g)#</mathjax></p> <p>Is conservation of mass apparent here? Why and how?</p> <p>Just on the question of balancing the equation, you could of course remove the half coefficient on dioxygen gas by doubling the entire equation. I have never seen the need to do so, inasmuch as the stoichiometry, the proportion of reactants and products, is easier to appreciate with the half coefficient.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/264531" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -&gt; 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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A #3.6*g# mass of water was decomposed to give #3.2*g# dioxygen gas. What mass of dihydrogen gas was evolved?

aacc206f-6ddd-11ea-8fce-ccda262736ce

https://socratic.org/questions/what-is-the-empirical-formula-of-magnesium-chloride-if-0-96-g-of-magnesium-combi

MgCl2

start chemical_formula qc_end physical_unit 6 6 9 10 mass qc_end physical_unit 18 18 15 16 mass qc_end end

[{"type":"other","value":"Chemical Formula [OF] magnesium chloride [IN] empirical"}]

[{"type":"chemical equation","value":"MgCl2"}]

[{"type":"physical unit","value":"Mass [OF] magnesium [=] \\pu{0.96 g}"},{"type":"physical unit","value":"Mass [OF] chlorine [=] \\pu{2.84 g}"}]

<h1 class="questionTitle" itemprop="name">What is the empirical formula of magnesium chloride if 0.96 g of magnesium combines with 2.84 g of chlorine?</h1>

MgCl2

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given that the weight of Mg is 0.96g and Cl is 2.84g and completely disregarding the possible chemical reactions, we need to convert each weight into the corresponding number of moles by multiplying the weight with its respective atomic weight. </p> <blockquote> <p><mathjax>#"Mg: " 0.96 cancel "g" xx "1 mol"/(24.305 cancel"g") = "0.395 mol"#</mathjax> </p> <p><mathjax>#"Cl: " 2.84 cancel "g" xx "1 mol"/(35.453 cancel "g") = "0.801 mol"#</mathjax></p> </blockquote> <p>Dividing the larger amount of mole with the smaller one (0.801 mol &gt; 0.395 mol),</p> <blockquote> <p><mathjax>#"Mg: " "0.395"/"0.395" = 1#</mathjax></p> <p><mathjax>#"Cl: " "0.801"/"0.395" = 2#</mathjax></p> </blockquote> <p>Therefore, empirical formula is <mathjax>#MgCl_2#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#MgCl_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given that the weight of Mg is 0.96g and Cl is 2.84g and completely disregarding the possible chemical reactions, we need to convert each weight into the corresponding number of moles by multiplying the weight with its respective atomic weight. </p> <blockquote> <p><mathjax>#"Mg: " 0.96 cancel "g" xx "1 mol"/(24.305 cancel"g") = "0.395 mol"#</mathjax> </p> <p><mathjax>#"Cl: " 2.84 cancel "g" xx "1 mol"/(35.453 cancel "g") = "0.801 mol"#</mathjax></p> </blockquote> <p>Dividing the larger amount of mole with the smaller one (0.801 mol &gt; 0.395 mol),</p> <blockquote> <p><mathjax>#"Mg: " "0.395"/"0.395" = 1#</mathjax></p> <p><mathjax>#"Cl: " "0.801"/"0.395" = 2#</mathjax></p> </blockquote> <p>Therefore, empirical formula is <mathjax>#MgCl_2#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the empirical formula of magnesium chloride if 0.96 g of magnesium combines with 2.84 g of chlorine?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="179778" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nikka-c"><img alt="" class="" src="https://profilepictures.socratic.org/AQ8VOCyTM1J7U0TvIWhw_nkahara.jpg" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nikka-c"> Nikka C. </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-25T05:02:43" itemprop="dateCreated"> Oct 25, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#MgCl_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given that the weight of Mg is 0.96g and Cl is 2.84g and completely disregarding the possible chemical reactions, we need to convert each weight into the corresponding number of moles by multiplying the weight with its respective atomic weight. </p> <blockquote> <p><mathjax>#"Mg: " 0.96 cancel "g" xx "1 mol"/(24.305 cancel"g") = "0.395 mol"#</mathjax> </p> <p><mathjax>#"Cl: " 2.84 cancel "g" xx "1 mol"/(35.453 cancel "g") = "0.801 mol"#</mathjax></p> </blockquote> <p>Dividing the larger amount of mole with the smaller one (0.801 mol &gt; 0.395 mol),</p> <blockquote> <p><mathjax>#"Mg: " "0.395"/"0.395" = 1#</mathjax></p> <p><mathjax>#"Cl: " "0.801"/"0.395" = 2#</mathjax></p> </blockquote> <p>Therefore, empirical formula is <mathjax>#MgCl_2#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/179778" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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What is the empirical formula of magnesium chloride if 0.96 g of magnesium combines with 2.84 g of chlorine?

a8cde58a-6ddd-11ea-a277-ccda262736ce

https://socratic.org/questions/how-many-moles-are-in-15-grams-of-naoh

0.38 moles

start physical_unit 8 8 mole mol qc_end physical_unit 8 8 5 6 mass qc_end end

[{"type":"physical unit","value":"Mole [OF] NaOH [IN] moles"}]

[{"type":"physical unit","value":"0.38 moles"}]

[{"type":"physical unit","value":"Mass [OF] NaOH [=] \\pu{15 grams}"}]

<h1 class="questionTitle" itemprop="name">How many moles are in 15 grams of NaOH?</h1>

0.38 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So, if you have <mathjax>#15.00#</mathjax> <mathjax>#g#</mathjax>, this represents a molar quantity of:</p> <p><mathjax>#(15*cancelg)/(40.00*cancelg*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#"mol"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Sodium hydroxide has a mass of <mathjax>#40.00#</mathjax> <mathjax>#g*mol^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So, if you have <mathjax>#15.00#</mathjax> <mathjax>#g#</mathjax>, this represents a molar quantity of:</p> <p><mathjax>#(15*cancelg)/(40.00*cancelg*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#"mol"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles are in 15 grams of NaOH?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="234060" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-02T16:21:26" itemprop="dateCreated"> Mar 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Sodium hydroxide has a mass of <mathjax>#40.00#</mathjax> <mathjax>#g*mol^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So, if you have <mathjax>#15.00#</mathjax> <mathjax>#g#</mathjax>, this represents a molar quantity of:</p> <p><mathjax>#(15*cancelg)/(40.00*cancelg*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#"mol"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/234060" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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How many moles are in 15 grams of NaOH?

acac2e69-6ddd-11ea-bffa-ccda262736ce

https://socratic.org/questions/how-do-you-determine-the-oxidation-state-of-c-in-co-3-2

+4

start physical_unit 8 8 oxidation_state none qc_end chemical_equation 10 10 qc_end end

[{"type":"physical unit","value":"Oxidation state [OF] C"}]

[{"type":"physical unit","value":"+4"}]

[{"type":"chemical equation","value":"CO3^2-"}]

<h1 class="questionTitle" itemprop="name">How do you determine the oxidation state of #C# in #CO_3 ^(2-)#?</h1>

+4

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>the equation would be </p> <p><mathjax># 1 xx C + 3 xx O = -2 #</mathjax></p> <p><mathjax># O = -2 #</mathjax> this is almost alway the oxidation state of Oxygen so</p> <p><mathjax># 1 xx C + 3 xx ( -2) = -2#</mathjax> so </p> <p><mathjax># 1 xx C + -6 = -2#</mathjax> add +6 to both sides</p> <p><mathjax># C + -6 +6 = -2 +6 #</mathjax> this gives </p> <p><mathjax># C = + 4#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>+4 Write an equation using the information and solve for C </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>the equation would be </p> <p><mathjax># 1 xx C + 3 xx O = -2 #</mathjax></p> <p><mathjax># O = -2 #</mathjax> this is almost alway the oxidation state of Oxygen so</p> <p><mathjax># 1 xx C + 3 xx ( -2) = -2#</mathjax> so </p> <p><mathjax># 1 xx C + -6 = -2#</mathjax> add +6 to both sides</p> <p><mathjax># C + -6 +6 = -2 +6 #</mathjax> this gives </p> <p><mathjax># C = + 4#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you determine the oxidation state of #C# in #CO_3 ^(2-)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-and-reduction-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation and Reduction Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="453361" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/david-drayer"><img alt="" class="" src="https://graph.facebook.com/10206723679871989/picture?height=50&amp;width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/david-drayer"> David Drayer </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-19T01:57:06" itemprop="dateCreated"> Jul 19, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>+4 Write an equation using the information and solve for C </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>the equation would be </p> <p><mathjax># 1 xx C + 3 xx O = -2 #</mathjax></p> <p><mathjax># O = -2 #</mathjax> this is almost alway the oxidation state of Oxygen so</p> <p><mathjax># 1 xx C + 3 xx ( -2) = -2#</mathjax> so </p> <p><mathjax># 1 xx C + -6 = -2#</mathjax> add +6 to both sides</p> <p><mathjax># C + -6 +6 = -2 +6 #</mathjax> this gives </p> <p><mathjax># C = + 4#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/453361" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-balance-equations-with-charges"> How to balance equations for reduction/oxidation reaction? 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How do you determine the oxidation state of #C# in #CO_3 ^(2-)#?

ac99721c-6ddd-11ea-b687-ccda262736ce

https://socratic.org/questions/how-many-moles-of-na-ions-are-present-in-275-0-ml-of-0-35-m-na-3po-4-solution

0.29 moles

start physical_unit 4 5 mole mol qc_end physical_unit 14 15 12 13 molarity qc_end physical_unit 14 15 9 10 volume qc_end end

[{"type":"physical unit","value":"Mole [OF] Na+ ions [IN] moles"}]

[{"type":"physical unit","value":"0.29 moles"}]

[{"type":"physical unit","value":"Molarity [OF] Na3PO4 solution [=] \\pu{0.35 M}"},{"type":"physical unit","value":"Volume [OF] Na3PO4 solution [=] \\pu{275.0 mL}"}]

<h1 class="questionTitle" itemprop="name">How many moles of #Na^+# ions are present in 275.0 mL of 0.35 M #Na_3PO_4# solution?</h1>

0.29 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The definition of concentration is </p> <p><mathjax>#C=n/V#</mathjax></p> <p>where concentration is is moles per litre (M), n is the number of moles (mol) and V is the volume in litres (L). Make sure to use these units to get the right answer. <br/> I.e.</p> <p><mathjax>#C=0.35" M"#</mathjax><br/> <mathjax>#L=275.0*10^-3" L"#</mathjax></p> <p>Now rearrange the concentration formula to solve for the number of moles of <mathjax>#Na_3PO_4#</mathjax>. I will round my answers to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, as that is the least amount given in the question.</p> <p><mathjax>#n(Na_3PO_4)=C*V=0.35*275.0*10^-3=9.6*10^-2" mol"#</mathjax></p> <p>The number of moles is a measure of how many particles there are. The chemical formula shows that for every <mathjax>#Na_3PO_4#</mathjax> salt particle, there are three <mathjax>#Na^+#</mathjax> ions, so we need to multiply the answer by three, giving</p> <p><mathjax>#n(Na^+)=3*n(Na_3PO_4)=3*9.6*10^-2=0.29" mol"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#n(Na^+)=3*n(Na_3PO_4)=0.29" mol"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The definition of concentration is </p> <p><mathjax>#C=n/V#</mathjax></p> <p>where concentration is is moles per litre (M), n is the number of moles (mol) and V is the volume in litres (L). Make sure to use these units to get the right answer. <br/> I.e.</p> <p><mathjax>#C=0.35" M"#</mathjax><br/> <mathjax>#L=275.0*10^-3" L"#</mathjax></p> <p>Now rearrange the concentration formula to solve for the number of moles of <mathjax>#Na_3PO_4#</mathjax>. I will round my answers to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, as that is the least amount given in the question.</p> <p><mathjax>#n(Na_3PO_4)=C*V=0.35*275.0*10^-3=9.6*10^-2" mol"#</mathjax></p> <p>The number of moles is a measure of how many particles there are. The chemical formula shows that for every <mathjax>#Na_3PO_4#</mathjax> salt particle, there are three <mathjax>#Na^+#</mathjax> ions, so we need to multiply the answer by three, giving</p> <p><mathjax>#n(Na^+)=3*n(Na_3PO_4)=3*9.6*10^-2=0.29" mol"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles of #Na^+# ions are present in 275.0 mL of 0.35 M #Na_3PO_4# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="430840" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/peter-m-8"><img alt="" class="" src="https://lh6.googleusercontent.com/-8YyKx7wqg0I/AAAAAAAAAAI/AAAAAAAAACo/JWBHiurCais/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/peter-m-8"> Peter M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-28T05:46:54" itemprop="dateCreated"> May 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#n(Na^+)=3*n(Na_3PO_4)=0.29" mol"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The definition of concentration is </p> <p><mathjax>#C=n/V#</mathjax></p> <p>where concentration is is moles per litre (M), n is the number of moles (mol) and V is the volume in litres (L). Make sure to use these units to get the right answer. <br/> I.e.</p> <p><mathjax>#C=0.35" M"#</mathjax><br/> <mathjax>#L=275.0*10^-3" L"#</mathjax></p> <p>Now rearrange the concentration formula to solve for the number of moles of <mathjax>#Na_3PO_4#</mathjax>. I will round my answers to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, as that is the least amount given in the question.</p> <p><mathjax>#n(Na_3PO_4)=C*V=0.35*275.0*10^-3=9.6*10^-2" mol"#</mathjax></p> <p>The number of moles is a measure of how many particles there are. The chemical formula shows that for every <mathjax>#Na_3PO_4#</mathjax> salt particle, there are three <mathjax>#Na^+#</mathjax> ions, so we need to multiply the answer by three, giving</p> <p><mathjax>#n(Na^+)=3*n(Na_3PO_4)=3*9.6*10^-2=0.29" mol"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/430840" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-solution-solute-and-solvent-related"> How are solution, solute, and solvent related? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutions-become-saturated"> Why do solutions become saturated? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-solutions"> How does temperature affect solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-solution-differ-from-a-colloid"> How does a solution differ from a colloid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/calculate-the-amount-of-1-m-naoh-aqueous-solution-needed-to-make-100-ml-of-0-5-m"> Calculate the amount of 1 M NaOH aqueous solution needed to make 100 mL of 0.5 M NaOH aqueous solution. </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-buffering-a-solution-change-the-solutions-behavior"> How does buffering a solution change the solutions behavior? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-benedict-s-solution-change-colour"> How does Benedict's solution change colour? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/describe-how-would-you-prepare-1-l-of-a-1-m-solution-of-sodium-chloride-the-gram"> Describe how would you prepare 1 L of a 1 M solution of sodium chloride. 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How many moles of #Na^+# ions are present in 275.0 mL of 0.35 M #Na_3PO_4# solution?

acbeb6b6-6ddd-11ea-b8c7-ccda262736ce

https://socratic.org/questions/567bd4ea11ef6b46c4825990

SO4^2-

start chemical_formula qc_end substance 5 6 qc_end end

[{"type":"other","value":"Chemical Formula [OF] sulfate ion [IN] default"}]

[{"type":"chemical equation","value":"SO4^2-"}]

[{"type":"substance name","value":"Sulfate ion"}]

<h1 class="questionTitle" itemprop="name">How do we represent the #"sulfate ion"#?</h1>

SO4^2-

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> composing the <mathjax>#SO_4^(2-)#</mathjax> are located in Group 16 which have 6 <a href="http://socratic.org/chemistry/the-periodic-table/valence-electrons-and-the-periodic-table">valence electrons</a> each and both are nonmetallic. This means that these elements have the tendency of sharing their electrons to achieve stability. </p> <p><img alt="www.chemistryland.com" src="http://www.chemistryland.com/CHM130W/11-Bonds/SulfateLewisDot.jpg"/></p> <p>Sulfur shares its 6e- to 3 Oxygen atoms to complete the octet leaving 1 Oxygen with only 6. The oxidation number of <mathjax>#-2#</mathjax> for this covalently bonded ion signifies that it has gained 2e- to complete the octet of the other Oxygen atom.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#SO_4^(2-)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> composing the <mathjax>#SO_4^(2-)#</mathjax> are located in Group 16 which have 6 <a href="http://socratic.org/chemistry/the-periodic-table/valence-electrons-and-the-periodic-table">valence electrons</a> each and both are nonmetallic. This means that these elements have the tendency of sharing their electrons to achieve stability. </p> <p><img alt="www.chemistryland.com" src="http://www.chemistryland.com/CHM130W/11-Bonds/SulfateLewisDot.jpg"/></p> <p>Sulfur shares its 6e- to 3 Oxygen atoms to complete the octet leaving 1 Oxygen with only 6. The oxidation number of <mathjax>#-2#</mathjax> for this covalently bonded ion signifies that it has gained 2e- to complete the octet of the other Oxygen atom.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do we represent the #"sulfate ion"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="235329" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jarni-renz"><img alt="" class="" src="https://profilepictures.socratic.org/i6OiZQmVRHWljDVlwm8v_WIN_20160301_180231.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jarni-renz"> Jarni Renz </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-05T11:20:43" itemprop="dateCreated"> Mar 5, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#SO_4^(2-)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> composing the <mathjax>#SO_4^(2-)#</mathjax> are located in Group 16 which have 6 <a href="http://socratic.org/chemistry/the-periodic-table/valence-electrons-and-the-periodic-table">valence electrons</a> each and both are nonmetallic. This means that these elements have the tendency of sharing their electrons to achieve stability. </p> <p><img alt="www.chemistryland.com" src="http://www.chemistryland.com/CHM130W/11-Bonds/SulfateLewisDot.jpg"/></p> <p>Sulfur shares its 6e- to 3 Oxygen atoms to complete the octet leaving 1 Oxygen with only 6. The oxidation number of <mathjax>#-2#</mathjax> for this covalently bonded ion signifies that it has gained 2e- to complete the octet of the other Oxygen atom.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/235329" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-chloride"> What is the ionic formula for calcium chloride? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-oxide"> What is the ionic formula for calcium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-lithium-oxide"> What is the ionic formula for lithium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-formula-for-ionic-compounds"> How do you write the formula for ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-correctly-write-the-ions-present-in-sn-no3-2"> How do I write #Sn(NO_3)_2# in Ionic formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-an-ionic-compound"> What is the empirical formula for an ionic compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-for-chorate"> What is the molecular formula for chorate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5363023c02bf343b2ee7086b"> Question #7086b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-polyatomic-ions-covalent-1"> Why are polyatomic ions covalent? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas"> See all questions in Writing Ionic Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4817 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How do we represent the #"sulfate ion"#?

ab0153f0-6ddd-11ea-bd81-ccda262736ce

https://socratic.org/questions/what-is-the-formula-for-ammonium-sulfate

(NH4)2SO4

start chemical_formula qc_end substance 5 6 qc_end end

[{"type":"other","value":"Chemical Formula [OF] ammonium sulfate [IN] default"}]

[{"type":"chemical equation","value":"(NH4)2SO4"}]

[{"type":"substance name","value":"Ammonium sulfate"}]

<h1 class="questionTitle" itemprop="name">What is the formula for ammonium sulfate?</h1>

(NH4)2SO4

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#NH_4^+ + SO_4^(2-) -&gt; (NH_4)_2SO_4 #</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#(NH_4)_2SO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#NH_4^+ + SO_4^(2-) -&gt; (NH_4)_2SO_4 #</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the formula for ammonium sulfate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="310508" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kristhia-loren-maree-rafols-c"><img alt="" class="" src="https://profilepictures.socratic.org/LCQvyymMQmyD0Ro56Sh6_IMG_20161030_204540.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kristhia-loren-maree-rafols-c"> Kris Caceres </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-15T16:18:33" itemprop="dateCreated"> Sep 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#(NH_4)_2SO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#NH_4^+ + SO_4^(2-) -&gt; (NH_4)_2SO_4 #</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/310508" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-chloride"> What is the ionic formula for calcium chloride? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-oxide"> What is the ionic formula for calcium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-lithium-oxide"> What is the ionic formula for lithium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-formula-for-ionic-compounds"> How do you write the formula for ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-correctly-write-the-ions-present-in-sn-no3-2"> How do I write #Sn(NO_3)_2# in Ionic formula? 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What is the formula for ammonium sulfate?

a8d25b9e-6ddd-11ea-86c9-ccda262736ce

https://socratic.org/questions/how-many-liters-of-oxygen-are-required-to-react-completely-with-1-2-liters-of-hy

0.6 liters

start physical_unit 4 4 volume l qc_end physical_unit 14 14 11 12 volume qc_end c_other OTHER qc_end substance 17 17 qc_end end

[{"type":"physical unit","value":"Volume [OF] oxygen [IN] liters"}]

[{"type":"physical unit","value":"0.6 liters"}]

[{"type":"physical unit","value":"Volume [OF] hydrogen [=] \\pu{1.2 liters}"},{"type":"other","value":"React completely."},{"type":"substance name","value":"Water"}]

<h1 class="questionTitle" itemprop="name">How many liters of oxygen are required to react completely with 1.2 liters of hydrogen to form water?</h1>

0.6 liters

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#H_2(g) + 1/2O_2(g) rarr H_2O(l)#</mathjax></p> <p>Under equivalent conditions, equal volumes of gases contain equal numbers of gaseous particles. We need 1 equiv <mathjax>#O_2(g)#</mathjax> for each 2 equiv <mathjax>#H_2(g)#</mathjax>. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Under the same conditions a volume of <mathjax>#0.6*L#</mathjax> of dioxygen is required.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#H_2(g) + 1/2O_2(g) rarr H_2O(l)#</mathjax></p> <p>Under equivalent conditions, equal volumes of gases contain equal numbers of gaseous particles. We need 1 equiv <mathjax>#O_2(g)#</mathjax> for each 2 equiv <mathjax>#H_2(g)#</mathjax>. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many liters of oxygen are required to react completely with 1.2 liters of hydrogen to form water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="277359" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-14T17:17:59" itemprop="dateCreated"> Jun 14, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Under the same conditions a volume of <mathjax>#0.6*L#</mathjax> of dioxygen is required.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#H_2(g) + 1/2O_2(g) rarr H_2O(l)#</mathjax></p> <p>Under equivalent conditions, equal volumes of gases contain equal numbers of gaseous particles. We need 1 equiv <mathjax>#O_2(g)#</mathjax> for each 2 equiv <mathjax>#H_2(g)#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/277359" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="277361" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/brian-m"><img alt="" class="" src="https://profilepictures.socratic.org/ZCpnJDgSFKORtvaSPDeG_Lego%20Me.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/brian-m"> BRIAN M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-14T17:21:57" itemprop="dateCreated"> Jun 14, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.6 L O_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Without the pressure and temperature we cannot calculate this value. </p> <p>However, if we assume this reaction is taking place at Standard Temperature and Pressure (STP) we can use Avogadro's constant of <mathjax>#22.4 L#</mathjax> per mole.</p> <p>The balanced equation for this reaction is</p> <p><mathjax>#2H_2 + O_2 -&gt; 2H_2O#</mathjax></p> <p>Now we can use <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio to convert the values.</p> <p><mathjax>#1.2 L H_2 * (1 mol H_2)/(22.4 L H_2) * (1 mol O_2)/(2 mol H_2) * (22.4 L O_2)/(1 mol O_2)#</mathjax> </p> <p><mathjax>#1.2 cancel(L H_2) * (1 cancel(mol H_2))/(cancel(22.4)cancel( L H_2)) * (1 cancel(mol O_2))/(2 cancel(mol H_2)) * (cancel(22.4) L O_2)/(1 cancel(mol O_2))#</mathjax> </p> <p><mathjax>#0.6 L O_2#</mathjax></p> <p> <iframe src="https://www.youtube.com/embed/5K4nPvP4bjo?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/277361" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-apply-gas-stoichiometry"> How do you apply gas stoichiometry? 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How many liters of oxygen are required to react completely with 1.2 liters of hydrogen to form water?

acb89d16-6ddd-11ea-aedf-ccda262736ce

https://socratic.org/questions/the-empirical-formula-of-a-compound-is-determined-to-be-c-2h-3-and-its-molecular

C4H6

start chemical_formula qc_end c_other OTHER qc_end physical_unit 29 30 19 20 molecular_weight qc_end end

[{"type":"other","value":"Chemical Formula [OF] the compound [IN] molecular"}]

[{"type":"chemical equation","value":"C4H6"}]

[{"type":"other","value":"The empirical formula of a compound is determined to be C2H3."},{"type":"physical unit","value":"Molecular mass [OF] the compound [=] \\pu{54.10 g/mol}"}]

<h1 class="questionTitle" itemprop="name">The empirical formula of a compound is determined to be #"C"_2"H"_3#, and its molecular mass is found to be 54.10 g/mol. How do you determine the molecular formula of the compound?</h1>

C4H6

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We simply divide the molecular mass by the empirical mass and multiply the result by the number of molecules in the compound.</p> <p><mathjax>#54.1/27approx2#</mathjax></p> <p><mathjax>#"C"_2"H"_3xx2="C"_4"H"_6#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"C"_4"H"_6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We simply divide the molecular mass by the empirical mass and multiply the result by the number of molecules in the compound.</p> <p><mathjax>#54.1/27approx2#</mathjax></p> <p><mathjax>#"C"_2"H"_3xx2="C"_4"H"_6#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">The empirical formula of a compound is determined to be #"C"_2"H"_3#, and its molecular mass is found to be 54.10 g/mol. How do you determine the molecular formula of the compound?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="344048" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/abdur-r"><img alt="" class="" src="https://profilepictures.socratic.org/YXIUDMM0SoZAxTdY3kn6_niagara_falls_fog_water_height_6376_3840x2160.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/abdur-r"> Monzur R. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-29T23:05:41" itemprop="dateCreated"> Nov 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"C"_4"H"_6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We simply divide the molecular mass by the empirical mass and multiply the result by the number of molecules in the compound.</p> <p><mathjax>#54.1/27approx2#</mathjax></p> <p><mathjax>#"C"_2"H"_3xx2="C"_4"H"_6#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/344048" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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The empirical formula of a compound is determined to be #"C"_2"H"_3#, and its molecular mass is found to be 54.10 g/mol. How do you determine the molecular formula of the compound?

a9bcea00-6ddd-11ea-848d-ccda262736ce

https://socratic.org/questions/how-many-grams-are-in-4-1-moles-of-co-2

180.4 grams

start physical_unit 8 8 mass g qc_end physical_unit 8 8 5 6 mole qc_end end

[{"type":"physical unit","value":"Mass [OF] CO2 [IN] grams"}]

[{"type":"physical unit","value":"180.4 grams"}]

[{"type":"physical unit","value":"Mole [OF] CO2 [=] \\pu{4.1 moles}"}]

<h1 class="questionTitle" itemprop="name">How many grams are in 4.1 moles of #CO_2#?</h1>

180.4 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The relationship between the mass and number of mole is giving by:</p> <p><mathjax>#n=m/(MM)#</mathjax></p> <p>where, <mathjax>#n#</mathjax> is the number of mole<br/> <mathjax>#m#</mathjax> is the mass of the compound <br/> and <mathjax>#MM#</mathjax> is the molar mass</p> <p><mathjax>#=&gt;m=nxxMM=4.1cancel(mol)xx44g/(cancel(mol))=180.4g#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#m=180.4g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The relationship between the mass and number of mole is giving by:</p> <p><mathjax>#n=m/(MM)#</mathjax></p> <p>where, <mathjax>#n#</mathjax> is the number of mole<br/> <mathjax>#m#</mathjax> is the mass of the compound <br/> and <mathjax>#MM#</mathjax> is the molar mass</p> <p><mathjax>#=&gt;m=nxxMM=4.1cancel(mol)xx44g/(cancel(mol))=180.4g#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many grams are in 4.1 moles of #CO_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="214742" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-20T19:27:33" itemprop="dateCreated"> Jan 20, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#m=180.4g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The relationship between the mass and number of mole is giving by:</p> <p><mathjax>#n=m/(MM)#</mathjax></p> <p>where, <mathjax>#n#</mathjax> is the number of mole<br/> <mathjax>#m#</mathjax> is the mass of the compound <br/> and <mathjax>#MM#</mathjax> is the molar mass</p> <p><mathjax>#=&gt;m=nxxMM=4.1cancel(mol)xx44g/(cancel(mol))=180.4g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/214742" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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How many grams are in 4.1 moles of #CO_2#?

ac05128a-6ddd-11ea-9d83-ccda262736ce

https://socratic.org/questions/54f21fe6581e2a3a69d6eb32

+309.32 kJ

start physical_unit 13 13 energy kj qc_end physical_unit 13 13 9 10 mass qc_end physical_unit 13 13 15 16 temperature qc_end physical_unit 13 13 18 19 temperature qc_end end

[{"type":"physical unit","value":"Required energy [OF] water [IN] kJ"}]

[{"type":"physical unit","value":"+309.32 kJ"}]

[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{1.0 kg}"},{"type":"physical unit","value":"Temperature1 [OF] water [=] \\pu{25 ℃ }"},{"type":"physical unit","value":"Temperature2 [OF] water [=] \\pu{99 ℃}"}]

<h1 class="questionTitle" itemprop="name">How much energy will be required to heat a #"1.0 kg"# mass of water from #25^@"C"# to #99^@"C"#? </h1>

+309.32 kJ

<div class="answerDescription"> <div> <div class="markdown"><p>You'd need <mathjax>#"310 kJ"#</mathjax> to raise the temperature of <strong>1 kg</strong> of water from <mathjax>#25#</mathjax> to <mathjax>#99^@"C"#</mathjax>.</p> <p>So, you have all the information you need to use the equation</p> <p><mathjax>#q = m * c * DeltaT#</mathjax>, where</p> <p><mathjax>#q#</mathjax> - the amount of heat needed;<br/> <mathjax>#m#</mathjax> - the mass of water - in your case <strong>1.0 kg</strong>:<br/> <mathjax>#c#</mathjax> - the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of water;<br/> <mathjax>#DeltaT#</mathjax> - the difference between the final temperature, <mathjax>#99^@"C"#</mathjax>, and the initial temperature, <mathjax>#25^@"C"#</mathjax>, of the water. </p> <p>Plug your data into the equation to get </p> <p><mathjax>#q = "1,000 g" * 4.18"J"/("g" * ^@"C") * (99-25)^@"C"#</mathjax></p> <p><mathjax>#q = "309,320 J" = "+309.3 kJ"#</mathjax></p> <p>Rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <p><mathjax>#q = "+310 kJ"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><p>You'd need <mathjax>#"310 kJ"#</mathjax> to raise the temperature of <strong>1 kg</strong> of water from <mathjax>#25#</mathjax> to <mathjax>#99^@"C"#</mathjax>.</p> <p>So, you have all the information you need to use the equation</p> <p><mathjax>#q = m * c * DeltaT#</mathjax>, where</p> <p><mathjax>#q#</mathjax> - the amount of heat needed;<br/> <mathjax>#m#</mathjax> - the mass of water - in your case <strong>1.0 kg</strong>:<br/> <mathjax>#c#</mathjax> - the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of water;<br/> <mathjax>#DeltaT#</mathjax> - the difference between the final temperature, <mathjax>#99^@"C"#</mathjax>, and the initial temperature, <mathjax>#25^@"C"#</mathjax>, of the water. </p> <p>Plug your data into the equation to get </p> <p><mathjax>#q = "1,000 g" * 4.18"J"/("g" * ^@"C") * (99-25)^@"C"#</mathjax></p> <p><mathjax>#q = "309,320 J" = "+309.3 kJ"#</mathjax></p> <p>Rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <p><mathjax>#q = "+310 kJ"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How much energy will be required to heat a #"1.0 kg"# mass of water from #25^@"C"# to #99^@"C"#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="131130" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-02-28T20:48:09" itemprop="dateCreated"> Feb 28, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><p>You'd need <mathjax>#"310 kJ"#</mathjax> to raise the temperature of <strong>1 kg</strong> of water from <mathjax>#25#</mathjax> to <mathjax>#99^@"C"#</mathjax>.</p> <p>So, you have all the information you need to use the equation</p> <p><mathjax>#q = m * c * DeltaT#</mathjax>, where</p> <p><mathjax>#q#</mathjax> - the amount of heat needed;<br/> <mathjax>#m#</mathjax> - the mass of water - in your case <strong>1.0 kg</strong>:<br/> <mathjax>#c#</mathjax> - the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of water;<br/> <mathjax>#DeltaT#</mathjax> - the difference between the final temperature, <mathjax>#99^@"C"#</mathjax>, and the initial temperature, <mathjax>#25^@"C"#</mathjax>, of the water. </p> <p>Plug your data into the equation to get </p> <p><mathjax>#q = "1,000 g" * 4.18"J"/("g" * ^@"C") * (99-25)^@"C"#</mathjax></p> <p><mathjax>#q = "309,320 J" = "+309.3 kJ"#</mathjax></p> <p>Rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <p><mathjax>#q = "+310 kJ"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/131130" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="131133" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-02-28T21:03:42" itemprop="dateCreated"> Feb 28, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>It will require <mathjax>#"310,000 J"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to answer this question, you you will need to use the following equation:</p> <p><mathjax>#q = cmDeltaT#</mathjax>, </p> <p>where <mathjax>#q#</mathjax> is the quantity of heat gained or lost, <mathjax>#c#</mathjax> is the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity (of water in this case), <mathjax>#m#</mathjax> is mass in grams, and <mathjax>#DeltaT#</mathjax> is the difference in temperature, <mathjax>#DeltaT=T_"final"-T_"initial"#</mathjax></p> <p><strong>Known/Given:</strong><br/> <mathjax>#c_"water"= 4.184 "J"/("g"*""^("o")"C"#</mathjax></p> <p><mathjax>#m=1.0color(red)cancel(color(black)("kg"))xx"1000 g"/(1color(red)cancel(color(black)("kg")))=1.0xx10^3#</mathjax> <mathjax>#"g"#</mathjax></p> <p><mathjax>#T_i="25"^@"C"#</mathjax></p> <p><mathjax>#T_f="99"^@"C"#</mathjax></p> <p><mathjax>#DeltaT="99"^@"C" - "25"^@"C"="74"^@"C"#</mathjax></p> <p><strong>Unknown:</strong><br/> <mathjax>#q#</mathjax></p> <p><strong>Solution:</strong></p> <p>Plug the known values into the equation and solve.</p> <p><mathjax>#q=4.184"J"/(color(red)cancel(color(black)("g"))*""^@color(red)cancel(color(black)("C")))xx1.0xx10^3color(red)cancel(color(black)("g"))xx74^@color(red)cancel(color(black)("C")) = "310,000 J"#</mathjax> (rounded to two significant figures)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/131133" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-heat-capacity-of-a-lead-sinker-be-determined"> How can the heat capacity of a lead sinker be determined? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-the-specific-heats-of-metals-compare-with-water"> How do the specific heats of metals compare with water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-specific-heat-change-with-temperature"> How does specific heat change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/dissolving-some-potassium-bromide-in-200cm3-of-water-leads-to-a-decrease-in-temp"> Dissolving some potassium bromide in 200cm3 of water leads to a decrease in temperature of 3oC.... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-heat-capacity-larger-for-polymers"> Is heat capacity larger for polymers? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-heat-capacity-an-extensive-property"> Why is heat capacity an extensive property? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-heat-capacity-change-with-temperature"> Why does heat capacity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-specific-heat-measured-in"> What is specific heat measured in? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-heat-capacity-measured-in"> What is heat capacity measured in? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/specific-heat"> See all questions in Specific Heat </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 20061 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How much energy will be required to heat a #"1.0 kg"# mass of water from #25^@"C"# to #99^@"C"#?

a8ca8a1c-6ddd-11ea-8e84-ccda262736ce

https://socratic.org/questions/how-many-moles-of-co-2-g-are-in-a-5-6-l-sample-of-co-2-measured-at-stp

0.25 moles

start physical_unit 4 4 mole mol qc_end physical_unit 4 4 8 9 volume qc_end c_other STP qc_end end

[{"type":"physical unit","value":"Mole [OF] CO2(g) [IN] moles"}]

[{"type":"physical unit","value":"0.25 moles"}]

[{"type":"physical unit","value":"Volume [OF] CO2(g) sample [=] \\pu{5.6 L}"},{"type":"other","value":"STP"}]

<h1 class="questionTitle" itemprop="name">How many moles of #CO_2# (g) are in a 5.6 L sample of #CO_2# measured at STP? </h1>

0.25 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Using the ideal gas equation, we can solve for the number of moles:</p> <blockquote> <p><mathjax>#PV=nRT#</mathjax></p> </blockquote> <p>where:<br/> <mathjax>#P=#</mathjax>pressure<br/> <mathjax>#V=#</mathjax>volume<br/> <mathjax>#n=#</mathjax>moles<br/> <mathjax>#R=#</mathjax>universal constant <mathjax>#(8.314(kPa*L)/(mol*K))#</mathjax><br/> <mathjax>#T=#</mathjax>temperature (Kelvin)</p> <p>Recall that at STP conditions:</p> <blockquote> <p><mathjax>#P=101.325#</mathjax> <mathjax>#kPa#</mathjax><br/> <mathjax>#T=273.15#</mathjax> <mathjax>#K#</mathjax></p> </blockquote> <p>To solve for the number of moles of carbon dioxide gas, substitute your known values into the ideal gas equation:</p> <blockquote> <p><mathjax>#PV=nRT#</mathjax></p> <p><mathjax>#n=(PV)/(RT)#</mathjax></p> <p><mathjax>#n=((101.325kPa)(5.6L))/((8.314(kPa*L)/(mol*K))(273.15K))#</mathjax></p> <p><mathjax>#n=((101.325color(red)cancelcolor(black)(kPa))(5.6color(orange)cancelcolor(black)(L)))/((8.314(color(red)cancelcolor(black)(kPa)*color(orange)cancelcolor(black)(L))/(mol*color(green)cancelcolor(black)(K)))(273.15color(green)cancelcolor(black)(K)))#</mathjax></p> <p><mathjax>#n=0.2498580892#</mathjax> <mathjax>#mol#</mathjax></p> <p><mathjax>#n=0.25#</mathjax> <mathjax>#mol#</mathjax> (rounded to <mathjax>#2#</mathjax> significant figures)</p> </blockquote> <p><mathjax>#:.#</mathjax>, there are <mathjax>#0.25#</mathjax> <mathjax>#mol#</mathjax> in <mathjax>#5.6#</mathjax> <mathjax>#L#</mathjax> of <mathjax>#CO_(2(g))#</mathjax> at STP conditions.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"moles"=0.25#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Using the ideal gas equation, we can solve for the number of moles:</p> <blockquote> <p><mathjax>#PV=nRT#</mathjax></p> </blockquote> <p>where:<br/> <mathjax>#P=#</mathjax>pressure<br/> <mathjax>#V=#</mathjax>volume<br/> <mathjax>#n=#</mathjax>moles<br/> <mathjax>#R=#</mathjax>universal constant <mathjax>#(8.314(kPa*L)/(mol*K))#</mathjax><br/> <mathjax>#T=#</mathjax>temperature (Kelvin)</p> <p>Recall that at STP conditions:</p> <blockquote> <p><mathjax>#P=101.325#</mathjax> <mathjax>#kPa#</mathjax><br/> <mathjax>#T=273.15#</mathjax> <mathjax>#K#</mathjax></p> </blockquote> <p>To solve for the number of moles of carbon dioxide gas, substitute your known values into the ideal gas equation:</p> <blockquote> <p><mathjax>#PV=nRT#</mathjax></p> <p><mathjax>#n=(PV)/(RT)#</mathjax></p> <p><mathjax>#n=((101.325kPa)(5.6L))/((8.314(kPa*L)/(mol*K))(273.15K))#</mathjax></p> <p><mathjax>#n=((101.325color(red)cancelcolor(black)(kPa))(5.6color(orange)cancelcolor(black)(L)))/((8.314(color(red)cancelcolor(black)(kPa)*color(orange)cancelcolor(black)(L))/(mol*color(green)cancelcolor(black)(K)))(273.15color(green)cancelcolor(black)(K)))#</mathjax></p> <p><mathjax>#n=0.2498580892#</mathjax> <mathjax>#mol#</mathjax></p> <p><mathjax>#n=0.25#</mathjax> <mathjax>#mol#</mathjax> (rounded to <mathjax>#2#</mathjax> significant figures)</p> </blockquote> <p><mathjax>#:.#</mathjax>, there are <mathjax>#0.25#</mathjax> <mathjax>#mol#</mathjax> in <mathjax>#5.6#</mathjax> <mathjax>#L#</mathjax> of <mathjax>#CO_(2(g))#</mathjax> at STP conditions.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles of #CO_2# (g) are in a 5.6 L sample of #CO_2# measured at STP? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="219302" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/johnson"><img alt="" class="" src="https://profilepictures.socratic.org/CODc7QKDQ4O1bKIs5CiO_SnakeSkin.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/johnson"> Johnson Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-30T17:21:02" itemprop="dateCreated"> Jan 30, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"moles"=0.25#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Using the ideal gas equation, we can solve for the number of moles:</p> <blockquote> <p><mathjax>#PV=nRT#</mathjax></p> </blockquote> <p>where:<br/> <mathjax>#P=#</mathjax>pressure<br/> <mathjax>#V=#</mathjax>volume<br/> <mathjax>#n=#</mathjax>moles<br/> <mathjax>#R=#</mathjax>universal constant <mathjax>#(8.314(kPa*L)/(mol*K))#</mathjax><br/> <mathjax>#T=#</mathjax>temperature (Kelvin)</p> <p>Recall that at STP conditions:</p> <blockquote> <p><mathjax>#P=101.325#</mathjax> <mathjax>#kPa#</mathjax><br/> <mathjax>#T=273.15#</mathjax> <mathjax>#K#</mathjax></p> </blockquote> <p>To solve for the number of moles of carbon dioxide gas, substitute your known values into the ideal gas equation:</p> <blockquote> <p><mathjax>#PV=nRT#</mathjax></p> <p><mathjax>#n=(PV)/(RT)#</mathjax></p> <p><mathjax>#n=((101.325kPa)(5.6L))/((8.314(kPa*L)/(mol*K))(273.15K))#</mathjax></p> <p><mathjax>#n=((101.325color(red)cancelcolor(black)(kPa))(5.6color(orange)cancelcolor(black)(L)))/((8.314(color(red)cancelcolor(black)(kPa)*color(orange)cancelcolor(black)(L))/(mol*color(green)cancelcolor(black)(K)))(273.15color(green)cancelcolor(black)(K)))#</mathjax></p> <p><mathjax>#n=0.2498580892#</mathjax> <mathjax>#mol#</mathjax></p> <p><mathjax>#n=0.25#</mathjax> <mathjax>#mol#</mathjax> (rounded to <mathjax>#2#</mathjax> significant figures)</p> </blockquote> <p><mathjax>#:.#</mathjax>, there are <mathjax>#0.25#</mathjax> <mathjax>#mol#</mathjax> in <mathjax>#5.6#</mathjax> <mathjax>#L#</mathjax> of <mathjax>#CO_(2(g))#</mathjax> at STP conditions.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/219302" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? 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R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 23335 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many moles of #CO_2# (g) are in a 5.6 L sample of #CO_2# measured at STP?

ab72c3e4-6ddd-11ea-84ed-ccda262736ce

https://socratic.org/questions/how-would-you-write-a-balanced-equation-for-the-combustion-of-octane-c8h18-with-

2 C8H18 + 25 O2 -> 16 CO2 + 18 H2O

start chemical_equation qc_end chemical_equation 12 12 qc_end substance 14 14 qc_end substance 17 18 qc_end substance 20 20 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the combustion"}]

[{"type":"chemical equation","value":"2 C8H18 + 25 O2 -> 16 CO2 + 18 H2O"}]

[{"type":"chemical equation","value":"C8H18"},{"type":"substance name","value":"Oxygen"},{"type":"substance name","value":"Carbon dioxide"},{"type":"substance name","value":"Water"}]

<h1 class="questionTitle" itemprop="name">How would you write a balanced equation for the combustion of octane, C8H18 with oxygen to obtain carbon dioxide and water?</h1>

2 C8H18 + 25 O2 -> 16 CO2 + 18 H2O

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You just have to check the number of atoms of each element is the same in both sides.<br/> You can do it by steps starting with the unbalanced equation</p> <p><mathjax>#C_8H_18 + O_2 -&gt; CO_2 + H_2O#</mathjax></p> <p>By making a list of the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> and the number of atoms on each side of the equation</p> <p><mathjax># 8-C-1#</mathjax><br/> <mathjax>#18-H-2#</mathjax><br/> <mathjax>#2-O-3#</mathjax></p> <p>Then as you can see, the molecule with 1 carbon (<mathjax>#CO_2#</mathjax>) you have to multiply by eight, the molecule with 2 hydrogens (<mathjax>#H_2O#</mathjax>) you have to multiply it by 9 to be equal to the left. And when you find that you have to multiply by a fraction then you can multiply the whole equation by an integer so you have only integers.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2C_8H_18 + 25O_2 -&gt; 16CO_2 + 18H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You just have to check the number of atoms of each element is the same in both sides.<br/> You can do it by steps starting with the unbalanced equation</p> <p><mathjax>#C_8H_18 + O_2 -&gt; CO_2 + H_2O#</mathjax></p> <p>By making a list of the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> and the number of atoms on each side of the equation</p> <p><mathjax># 8-C-1#</mathjax><br/> <mathjax>#18-H-2#</mathjax><br/> <mathjax>#2-O-3#</mathjax></p> <p>Then as you can see, the molecule with 1 carbon (<mathjax>#CO_2#</mathjax>) you have to multiply by eight, the molecule with 2 hydrogens (<mathjax>#H_2O#</mathjax>) you have to multiply it by 9 to be equal to the left. And when you find that you have to multiply by a fraction then you can multiply the whole equation by an integer so you have only integers.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How would you write a balanced equation for the combustion of octane, C8H18 with oxygen to obtain carbon dioxide and water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="186374" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/apgt512"><img alt="" class="" src="https://profilepictures.socratic.org/1uF0g9QgSOuzxlhNBGXs_Laser.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/apgt512"> Apgt512 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-10T02:50:44" itemprop="dateCreated"> Nov 10, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2C_8H_18 + 25O_2 -&gt; 16CO_2 + 18H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You just have to check the number of atoms of each element is the same in both sides.<br/> You can do it by steps starting with the unbalanced equation</p> <p><mathjax>#C_8H_18 + O_2 -&gt; CO_2 + H_2O#</mathjax></p> <p>By making a list of the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> and the number of atoms on each side of the equation</p> <p><mathjax># 8-C-1#</mathjax><br/> <mathjax>#18-H-2#</mathjax><br/> <mathjax>#2-O-3#</mathjax></p> <p>Then as you can see, the molecule with 1 carbon (<mathjax>#CO_2#</mathjax>) you have to multiply by eight, the molecule with 2 hydrogens (<mathjax>#H_2O#</mathjax>) you have to multiply it by 9 to be equal to the left. And when you find that you have to multiply by a fraction then you can multiply the whole equation by an integer so you have only integers.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/186374" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -&gt; 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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How would you write a balanced equation for the combustion of octane, C8H18 with oxygen to obtain carbon dioxide and water?

ab8f5828-6ddd-11ea-a85e-ccda262736ce

https://socratic.org/questions/nacl-has-a-deltah-fus-30-2-kj-mol-what-is-the-mass-of-a-sample-of-nacl-that-need

559 g

start physical_unit 13 15 mass g qc_end physical_unit 0 0 5 6 deltah qc_end physical_unit 13 15 18 19 heat_energy qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Mass [OF] NaCl sample [IN] g"}]

[{"type":"physical unit","value":"559 g"}]

[{"type":"physical unit","value":"DeltaH [OF] NaCl [=] \\pu{30.2 kJ/mol}"},{"type":"physical unit","value":"Needed heat [OF] NaCl sample [=] \\pu{732.6 kJ}"},{"type":"other","value":"Melt completely."}]

<h1 class="questionTitle" itemprop="name">NaCl has a #DeltaH_(fus)# = 30.2 kJ/mol. What is the mass of a sample of NaCl that needs 732.6 kJ of heat to melt completely?</h1>

559 g

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Determine moles Na by dividing by its heat of fusion.</p> <p><mathjax>#732.6color(red)cancel(color(black)("kJ"))xx(1"mol Na")/(30.2color(red)cancel(color(black)("kJ")))="24.3 mol Na"#</mathjax></p> <p>Determine mass of Na by dividing by its molar mass (atomic weight in g/mol).</p> <p><mathjax>#24.3color(red)cancel(color(black)("mol Na"))xx(22.98977"g Na")/(1color(red)cancel(color(black)("mol Na")))="559 Na"#</mathjax> rounded to three sig figs</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"559 g Na"#</mathjax> would need <mathjax>#"732.6 kJ"#</mathjax> of heat to melt completely.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Determine moles Na by dividing by its heat of fusion.</p> <p><mathjax>#732.6color(red)cancel(color(black)("kJ"))xx(1"mol Na")/(30.2color(red)cancel(color(black)("kJ")))="24.3 mol Na"#</mathjax></p> <p>Determine mass of Na by dividing by its molar mass (atomic weight in g/mol).</p> <p><mathjax>#24.3color(red)cancel(color(black)("mol Na"))xx(22.98977"g Na")/(1color(red)cancel(color(black)("mol Na")))="559 Na"#</mathjax> rounded to three sig figs</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">NaCl has a #DeltaH_(fus)# = 30.2 kJ/mol. What is the mass of a sample of NaCl that needs 732.6 kJ of heat to melt completely?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/enthalpy" itemprop="url"> <span class="breadcrumb" itemprop="title">Enthalpy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="440010" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-15T02:18:22" itemprop="dateCreated"> Jun 15, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"559 g Na"#</mathjax> would need <mathjax>#"732.6 kJ"#</mathjax> of heat to melt completely.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Determine moles Na by dividing by its heat of fusion.</p> <p><mathjax>#732.6color(red)cancel(color(black)("kJ"))xx(1"mol Na")/(30.2color(red)cancel(color(black)("kJ")))="24.3 mol Na"#</mathjax></p> <p>Determine mass of Na by dividing by its molar mass (atomic weight in g/mol).</p> <p><mathjax>#24.3color(red)cancel(color(black)("mol Na"))xx(22.98977"g Na")/(1color(red)cancel(color(black)("mol Na")))="559 Na"#</mathjax> rounded to three sig figs</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/440010" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-enthalpy-changes-expressed-in-chemical-equations"> How are enthalpy changes expressed in chemical equations? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function-2"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-enthalpy-cannot-be-measured-directly"> Why can enthalpy not be measured directly? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-pressure-affect-enthalpy"> How does pressure affect enthalpy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-relate-to-internal-energy"> How does enthalpy relate to internal energy? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/enthalpy"> See all questions in Enthalpy </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4364 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

NaCl has a #DeltaH_(fus)# = 30.2 kJ/mol. What is the mass of a sample of NaCl that needs 732.6 kJ of heat to melt completely?

abb0f1ba-6ddd-11ea-a923-ccda262736ce

https://socratic.org/questions/what-is-the-mole-fraction-of-methanol-in-a-solution-that-contains-6-0-mol-of-met

0.67

start physical_unit 6 9 mole_fraction none qc_end physical_unit 6 6 12 13 mole qc_end physical_unit 20 20 17 18 mole qc_end chemical_equation 26 26 qc_end end

[{"type":"physical unit","value":"Mole fraction [OF] methanol in a solution"}]

[{"type":"physical unit","value":"0.67"}]

[{"type":"physical unit","value":"Mole [OF] methanol [=] \\pu{6.0 mol}"},{"type":"physical unit","value":"Mole [OF] water [=] \\pu{3.0 mol}"},{"type":"chemical equation","value":"CH3OH"}]

<h1 class="questionTitle" itemprop="name">What is the mole fraction of methanol in a solution that contains 6.0 mol of methanol and 3.0 mol of water? The formula for methanol is #CH_3OH#.</h1>

0.67

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#chi_"MeOH"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of MeOH"/"Moles of methanol + moles of water"#</mathjax></p> <p><mathjax>#(6.0*mol)/((6.0+3.0)*mol)=2/3#</mathjax> as required.............</p> <p>What is the <mathjax>#"mole fraction of water?"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"The mole fraction of methanol is"#</mathjax> <mathjax>#2/3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#chi_"MeOH"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of MeOH"/"Moles of methanol + moles of water"#</mathjax></p> <p><mathjax>#(6.0*mol)/((6.0+3.0)*mol)=2/3#</mathjax> as required.............</p> <p>What is the <mathjax>#"mole fraction of water?"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the mole fraction of methanol in a solution that contains 6.0 mol of methanol and 3.0 mol of water? The formula for methanol is #CH_3OH#.</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="376565" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-11T16:41:48" itemprop="dateCreated"> Feb 11, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"The mole fraction of methanol is"#</mathjax> <mathjax>#2/3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#chi_"MeOH"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of MeOH"/"Moles of methanol + moles of water"#</mathjax></p> <p><mathjax>#(6.0*mol)/((6.0+3.0)*mol)=2/3#</mathjax> as required.............</p> <p>What is the <mathjax>#"mole fraction of water?"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/376565" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179102bf3469517a1072"> Question #a1072 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179402bf34694c8c5bf1"> Question #c5bf1 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179702bf3469588dc373"> Question #dc373 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179c02bf34694c8c5bf9"> Question #c5bf9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417a302bf3469517a1076"> Question #a1076 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417c702bf3469588dc377"> Question #dc377 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d002bf346963eb984f"> Question #b984f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d402bf346950519ea3"> Question #19ea3 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/mole-ratios"> See all questions in Mole Ratios </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 8990 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the mole fraction of methanol in a solution that contains 6.0 mol of methanol and 3.0 mol of water? The formula for methanol is #CH_3OH#.

a84ff180-6ddd-11ea-aa68-ccda262736ce

https://socratic.org/questions/5978b66a7c014974f839286a

1.81 × 10^25

start physical_unit 2 3 number none qc_end physical_unit 17 18 13 14 mass qc_end end

[{"type":"physical unit","value":"Number [OF] aluminum-based electrons"}]

[{"type":"physical unit","value":"1.81 × 10^25"}]

[{"type":"physical unit","value":"Mass [OF] aluminum ions [=] \\pu{81 g}"}]

<h1 class="questionTitle" itemprop="name">How many aluminum-based electrons are present in a salt where there is an #81*g# mass of aluminum ions....?</h1>

1.81 × 10^25

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Well, we take the quotient, <mathjax>#(81*g)/(27*g*mol^-1)=3*mol#</mathjax>.</p> <p>And thus there are <mathjax>#3 *mol#</mathjax> of aluminum ions, and since there are 10 electrons per <mathjax>#Al^(3+)#</mathjax> ions (for <mathjax>#Al, Z=13)#</mathjax>, there are <mathjax>#30*mol#</mathjax> of aluminum electrons. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>How many aluminum-based electrons in a salt where there is an <mathjax>#81*g#</mathjax> mass of aluminum ions....?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Well, we take the quotient, <mathjax>#(81*g)/(27*g*mol^-1)=3*mol#</mathjax>.</p> <p>And thus there are <mathjax>#3 *mol#</mathjax> of aluminum ions, and since there are 10 electrons per <mathjax>#Al^(3+)#</mathjax> ions (for <mathjax>#Al, Z=13)#</mathjax>, there are <mathjax>#30*mol#</mathjax> of aluminum electrons. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many aluminum-based electrons are present in a salt where there is an #81*g# mass of aluminum ions....?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="456581" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-26T18:00:20" itemprop="dateCreated"> Jul 26, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>How many aluminum-based electrons in a salt where there is an <mathjax>#81*g#</mathjax> mass of aluminum ions....?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Well, we take the quotient, <mathjax>#(81*g)/(27*g*mol^-1)=3*mol#</mathjax>.</p> <p>And thus there are <mathjax>#3 *mol#</mathjax> of aluminum ions, and since there are 10 electrons per <mathjax>#Al^(3+)#</mathjax> ions (for <mathjax>#Al, Z=13)#</mathjax>, there are <mathjax>#30*mol#</mathjax> of aluminum electrons. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/456581" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 898 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many aluminum-based electrons are present in a salt where there is an #81*g# mass of aluminum ions....?

abe604bf-6ddd-11ea-b282-ccda262736ce

https://socratic.org/questions/number-pf-moles-present-in-44g-pf-co2

1.00 moles

start physical_unit 9 9 mole mol qc_end physical_unit 9 9 6 7 mass qc_end end

[{"type":"physical unit","value":"Mole [OF] CO2 [IN] moles"}]

[{"type":"physical unit","value":"1.00 moles"}]

[{"type":"physical unit","value":"Mass [OF] CO2 [=] \\pu{44 g}"}]

<h1 class="questionTitle" itemprop="name">The number of moles present in #"44 g"# of #"CO"_2# ?</h1>

1.00 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#CO_2#</mathjax> has a molar mass of <mathjax>#44.009 \ "g/mol"#</mathjax>. That means that one mole of <mathjax>#CO_2#</mathjax> has a mass of <mathjax>#44.009 \ "g"#</mathjax>.</p> <p>So, in <mathjax>#44 \ "g"#</mathjax> of <mathjax>#CO_2#</mathjax>, there is a little under one mole of <mathjax>#"CO"_2#</mathjax>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.9998 mols" -&gt; "1.0 mols"#</mathjax> (2 sig figs)</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#CO_2#</mathjax> has a molar mass of <mathjax>#44.009 \ "g/mol"#</mathjax>. That means that one mole of <mathjax>#CO_2#</mathjax> has a mass of <mathjax>#44.009 \ "g"#</mathjax>.</p> <p>So, in <mathjax>#44 \ "g"#</mathjax> of <mathjax>#CO_2#</mathjax>, there is a little under one mole of <mathjax>#"CO"_2#</mathjax>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">The number of moles present in #"44 g"# of #"CO"_2# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="553323" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nam-d"><img alt="" class="" src="https://profilepictures.socratic.org/QG4MnkoER6u99DIDVWKK_787554714770341.jpg" title=""/></a> <a class="secondContributorPic" href="/users/truong-son-n"><img alt="" class="" src="https://profilepictures.socratic.org/07k4plnQfmnmzMuesQzw_14844-1449381920.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nam-d"> Nam D. </a>·<a class="topContributorLink" href="/users/truong-son-n"> Truong-Son N. </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-02-17T15:36:53" itemprop="dateCreated"> Feb 17, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.9998 mols" -&gt; "1.0 mols"#</mathjax> (2 sig figs)</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#CO_2#</mathjax> has a molar mass of <mathjax>#44.009 \ "g/mol"#</mathjax>. That means that one mole of <mathjax>#CO_2#</mathjax> has a mass of <mathjax>#44.009 \ "g"#</mathjax>.</p> <p>So, in <mathjax>#44 \ "g"#</mathjax> of <mathjax>#CO_2#</mathjax>, there is a little under one mole of <mathjax>#"CO"_2#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/553323" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5320 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

The number of moles present in #"44 g"# of #"CO"_2# ?

ac0bc96e-6ddd-11ea-8a79-ccda262736ce

https://socratic.org/questions/56f281c311ef6b17880e5b98

1.25 molar

start physical_unit 1 1 mole mol/l qc_end physical_unit 6 6 4 5 mole qc_end end

[{"type":"physical unit","value":"Mole [OF] methane [IN] molar"}]

[{"type":"physical unit","value":"1.25 molar"}]

[{"type":"physical unit","value":"Mole [OF] O2 [=] \\pu{2.5 mol}"}]

<h1 class="questionTitle" itemprop="name">In methane combustion, if #2.5*mol# #O_2# were present, what molar quantity of methane would react?</h1>

1.25 molar

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#CH_4(g) + 2O_2(g) rarr CO_2(g) + 2H_2O(g)#</mathjax>. </p> <p>This equation clearly tells us that each mole of methane requires 2 mole of dioxygen for complete combustion. There are <mathjax>#2.5#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#O_2#</mathjax>; if complete combustion occurred, then <mathjax>#1.25#</mathjax> <mathjax>#mol#</mathjax> methane gas were combusted.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CH_4(g) + 2O_2(g) rarr CO_2(g) + 2H_2O(g)#</mathjax>. So <mathjax>#1.25#</mathjax> <mathjax>#mol#</mathjax> methane are necessary for the given quantity of dioxygen.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#CH_4(g) + 2O_2(g) rarr CO_2(g) + 2H_2O(g)#</mathjax>. </p> <p>This equation clearly tells us that each mole of methane requires 2 mole of dioxygen for complete combustion. There are <mathjax>#2.5#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#O_2#</mathjax>; if complete combustion occurred, then <mathjax>#1.25#</mathjax> <mathjax>#mol#</mathjax> methane gas were combusted.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">In methane combustion, if #2.5*mol# #O_2# were present, what molar quantity of methane would react?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="247110" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-30T07:07:38" itemprop="dateCreated"> Mar 30, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CH_4(g) + 2O_2(g) rarr CO_2(g) + 2H_2O(g)#</mathjax>. So <mathjax>#1.25#</mathjax> <mathjax>#mol#</mathjax> methane are necessary for the given quantity of dioxygen.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#CH_4(g) + 2O_2(g) rarr CO_2(g) + 2H_2O(g)#</mathjax>. </p> <p>This equation clearly tells us that each mole of methane requires 2 mole of dioxygen for complete combustion. There are <mathjax>#2.5#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#O_2#</mathjax>; if complete combustion occurred, then <mathjax>#1.25#</mathjax> <mathjax>#mol#</mathjax> methane gas were combusted.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/247110" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-apply-gas-stoichiometry"> How do you apply gas stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-a-gas-law-stoichiometry-problem"> How do you solve a gas law stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-gas-stoichiometry-problems-at-stp"> How do you do gas stoichiometry problems at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-an-agno3-solution-is-treated-with-50-0-ml-of-hi-gas-to-give-0-235-g-of-agi-"> When an AgNO3 solution is treated with 50.0 mL of HI gas to give 0.235 g of AgI, what is the... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-10-0-ml-of-agno3-solution-is-treated-with-excess-amount-of-hi-gas-to-give-0"> When 10.0 mL of AgNO3 solution is treated with excess amount of HI gas to give 0.235 g of AgI,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/hydrogen-sulfide-reacts-with-sulfur-dioxide-to-give-h2o-and-s-h2s-so2-h2o-s-soli"> Hydrogen sulfide reacts with sulfur dioxide to give H2O and S, H2S + SO2 = H2O + S(solid),... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-200-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 200 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 100 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolve-in-20-ml-of-pure-water-what-i"> If 100 mL of HCl gas at 300 K and 100 kPa dissolve in 20 mL of pure water, what is the concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-2-00-g-mixture-of-na-and-ca-reat-with-water-1-164-l-hydrogen-was-produced-a"> When 2.00 g mixture of Na and Ca reat with water, 1.164 L hydrogen was produced at 300.0 K and... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases"> See all questions in Gas Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1350 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

In methane combustion, if #2.5*mol# #O_2# were present, what molar quantity of methane would react?

ab50f5c7-6ddd-11ea-a279-ccda262736ce

https://socratic.org/questions/what-volume-of-0-100-m-hcl-solution-is-needed-to-neutralize-50-0-ml-of-0-350-m-k

175.00 mL

start physical_unit 5 6 volume ml qc_end physical_unit 6 6 11 12 volume qc_end physical_unit 16 16 14 15 molarity qc_end physical_unit 5 6 3 4 molarity qc_end end

[{"type":"physical unit","value":"Volume [OF] HCl solution [IN] mL"}]

[{"type":"physical unit","value":"175.00 mL"}]

[{"type":"physical unit","value":"Volume [OF] KOH solution [=] \\pu{50.0 mL}"},{"type":"physical unit","value":"Molarity [OF] KOH solution [=] \\pu{0.350 M}"},{"type":"physical unit","value":"Molarity [OF] HCl solution [=] \\pu{0.100 M}"}]

<h1 class="questionTitle" itemprop="name">What volume of 0.100 M #"HCl"# solution is needed to neutralize 50.0 mL of 0.350 M #"KOH"#?</h1>

175.00 mL

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><em>Hydrochloric acid</em>, <mathjax>#"HCl"#</mathjax>, and <em>potassium hydroxide</em>, <mathjax>#"KOH"#</mathjax>, react in a <mathjax>#1:1#</mathjax> <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a></strong> to produce <em>aqueous potassium chloride</em>, <mathjax>#"KCl"#</mathjax>, and water. </p> <blockquote> <p><mathjax>#"HCl"_ ((aq)) + "KOH"_ ((aq)) -&gt; "KCl"_ ((aq)) + "H"_ 2"O"_ ((l))#</mathjax></p> </blockquote> <p>This means that a <em>complete <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a></em> requires <strong>equal numbers of moles</strong> of hydrochloric acid, i.e. of hydronium cations, <mathjax>#"H"_3"O"^(+)#</mathjax>, and of potassium hydroxide, i.e. of hydroxide anions, <mathjax>#"OH"^(-)#</mathjax>. </p> <p>As you know,m <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> is defined as the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present in <mathjax>#"1 L"#</mathjax> <strong>of solution</strong>. </p> <p>Now, notice that the potassium hydroxide solution, which has a molarity of <mathjax>#"0.350 M"#</mathjax>, is </p> <blockquote> <p><mathjax>#(0.350 color(red)(cancel(color(black)("M"))))/(0.100color(red)(cancel(color(black)("M")))) = color(red)(3.5)#</mathjax></p> </blockquote> <p><strong>times more concentrated</strong> than the hydrochloric acid solution, which has a molarity of <mathjax>#"0.100 M"#</mathjax>. In other words, for the <strong>same volume</strong> of both <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>, the potassium hydroxide solution contains <mathjax>#color(red)(3.5)#</mathjax> <strong>times more moles</strong> of solute than the hydrochloric acid solution. </p> <p>This means that in order to have <strong>equal numbers of moles</strong> of both solutes, you need to have a volume of hydrochloric acid solution that is <mathjax>#color(red)(3.5)#</mathjax> <strong>times</strong> bigger than the volume of the sodium hydroixde solution. </p> <p>Since the sodium hydroixde solution has a volume of <mathjax>#"50.0 mL"#</mathjax>, it follows that the volume of hydrochloric acid needed will be </p> <blockquote> <p><mathjax>#V_"HCl" = color(red)(3.5) xx "50.0 mL" = color(green)(|bar(ul(color(white)(a/a)color(black)("175 mL")color(white)(a/a)|)))-&gt;#</mathjax> <em>to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></em></p> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"175 mL"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><em>Hydrochloric acid</em>, <mathjax>#"HCl"#</mathjax>, and <em>potassium hydroxide</em>, <mathjax>#"KOH"#</mathjax>, react in a <mathjax>#1:1#</mathjax> <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a></strong> to produce <em>aqueous potassium chloride</em>, <mathjax>#"KCl"#</mathjax>, and water. </p> <blockquote> <p><mathjax>#"HCl"_ ((aq)) + "KOH"_ ((aq)) -&gt; "KCl"_ ((aq)) + "H"_ 2"O"_ ((l))#</mathjax></p> </blockquote> <p>This means that a <em>complete <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a></em> requires <strong>equal numbers of moles</strong> of hydrochloric acid, i.e. of hydronium cations, <mathjax>#"H"_3"O"^(+)#</mathjax>, and of potassium hydroxide, i.e. of hydroxide anions, <mathjax>#"OH"^(-)#</mathjax>. </p> <p>As you know,m <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> is defined as the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present in <mathjax>#"1 L"#</mathjax> <strong>of solution</strong>. </p> <p>Now, notice that the potassium hydroxide solution, which has a molarity of <mathjax>#"0.350 M"#</mathjax>, is </p> <blockquote> <p><mathjax>#(0.350 color(red)(cancel(color(black)("M"))))/(0.100color(red)(cancel(color(black)("M")))) = color(red)(3.5)#</mathjax></p> </blockquote> <p><strong>times more concentrated</strong> than the hydrochloric acid solution, which has a molarity of <mathjax>#"0.100 M"#</mathjax>. In other words, for the <strong>same volume</strong> of both <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>, the potassium hydroxide solution contains <mathjax>#color(red)(3.5)#</mathjax> <strong>times more moles</strong> of solute than the hydrochloric acid solution. </p> <p>This means that in order to have <strong>equal numbers of moles</strong> of both solutes, you need to have a volume of hydrochloric acid solution that is <mathjax>#color(red)(3.5)#</mathjax> <strong>times</strong> bigger than the volume of the sodium hydroixde solution. </p> <p>Since the sodium hydroixde solution has a volume of <mathjax>#"50.0 mL"#</mathjax>, it follows that the volume of hydrochloric acid needed will be </p> <blockquote> <p><mathjax>#V_"HCl" = color(red)(3.5) xx "50.0 mL" = color(green)(|bar(ul(color(white)(a/a)color(black)("175 mL")color(white)(a/a)|)))-&gt;#</mathjax> <em>to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></em></p> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What volume of 0.100 M #"HCl"# solution is needed to neutralize 50.0 mL of 0.350 M #"KOH"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/neutralization" itemprop="url"> <span class="breadcrumb" itemprop="title">Neutralization</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="287204" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-11T19:55:32" itemprop="dateCreated"> Jul 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"175 mL"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><em>Hydrochloric acid</em>, <mathjax>#"HCl"#</mathjax>, and <em>potassium hydroxide</em>, <mathjax>#"KOH"#</mathjax>, react in a <mathjax>#1:1#</mathjax> <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a></strong> to produce <em>aqueous potassium chloride</em>, <mathjax>#"KCl"#</mathjax>, and water. </p> <blockquote> <p><mathjax>#"HCl"_ ((aq)) + "KOH"_ ((aq)) -&gt; "KCl"_ ((aq)) + "H"_ 2"O"_ ((l))#</mathjax></p> </blockquote> <p>This means that a <em>complete <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a></em> requires <strong>equal numbers of moles</strong> of hydrochloric acid, i.e. of hydronium cations, <mathjax>#"H"_3"O"^(+)#</mathjax>, and of potassium hydroxide, i.e. of hydroxide anions, <mathjax>#"OH"^(-)#</mathjax>. </p> <p>As you know,m <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> is defined as the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present in <mathjax>#"1 L"#</mathjax> <strong>of solution</strong>. </p> <p>Now, notice that the potassium hydroxide solution, which has a molarity of <mathjax>#"0.350 M"#</mathjax>, is </p> <blockquote> <p><mathjax>#(0.350 color(red)(cancel(color(black)("M"))))/(0.100color(red)(cancel(color(black)("M")))) = color(red)(3.5)#</mathjax></p> </blockquote> <p><strong>times more concentrated</strong> than the hydrochloric acid solution, which has a molarity of <mathjax>#"0.100 M"#</mathjax>. In other words, for the <strong>same volume</strong> of both <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>, the potassium hydroxide solution contains <mathjax>#color(red)(3.5)#</mathjax> <strong>times more moles</strong> of solute than the hydrochloric acid solution. </p> <p>This means that in order to have <strong>equal numbers of moles</strong> of both solutes, you need to have a volume of hydrochloric acid solution that is <mathjax>#color(red)(3.5)#</mathjax> <strong>times</strong> bigger than the volume of the sodium hydroixde solution. </p> <p>Since the sodium hydroixde solution has a volume of <mathjax>#"50.0 mL"#</mathjax>, it follows that the volume of hydrochloric acid needed will be </p> <blockquote> <p><mathjax>#V_"HCl" = color(red)(3.5) xx "50.0 mL" = color(green)(|bar(ul(color(white)(a/a)color(black)("175 mL")color(white)(a/a)|)))-&gt;#</mathjax> <em>to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></em></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/287204" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-neutralization-reactions-useful"> How are neutralization reactions useful? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-neutralization-reactions-be-identified-symbolically"> How can neutralization reactions be identified symbolically? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-neutralization-reaction-differ-from-buffer"> How does neutralization reaction differ from using a buffer? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-acid-base-neutralization-reactions"> How do you do acid base neutralization reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-neutralization-reactions-produce-heat"> Why do neutralization reactions produce heat? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-neutralization-a-double-replacement-reaction"> Why is neutralization a double replacement reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-a-neutralization-reaction-exothermic"> Why is a neutralization reaction exothermic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-predict-and-balance-acid-base-reactions"> How do you predict the products in acid-base reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-determine-the-strength-of-sulfuric-acid"> How can you determine the strength of sulfuric acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-a-neutralisation-reaction-exothermic"> Why is a neutralisation reaction exothermic? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/reactions-in-solution/neutralization"> See all questions in Neutralization </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 74722 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What volume of 0.100 M #"HCl"# solution is needed to neutralize 50.0 mL of 0.350 M #"KOH"#?

a92efb3f-6ddd-11ea-b00b-ccda262736ce

https://socratic.org/questions/how-many-moles-are-there-in-120-g-of-glucose

0.67 moles

start physical_unit 9 9 mole mol qc_end physical_unit 9 9 6 7 mass qc_end end

[{"type":"physical unit","value":"Mole [OF] glucose [IN] moles"}]

[{"type":"physical unit","value":"0.67 moles"}]

[{"type":"physical unit","value":"Mass [OF] glucose [=] \\pu{120 g}"}]

<h1 class="questionTitle" itemprop="name">How many moles are there in 120 g of glucose?</h1>

0.67 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus <mathjax>#"no. of moles"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass"/"Molar mass"#</mathjax> <mathjax>#=#</mathjax> </p> <p><mathjax>#(120*g)/(180.16*g*mol^-1)#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#4/6*mol#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, glucose, <mathjax>#C_6H_12O_6#</mathjax> has a molar mass of <mathjax>#120.16*g*mol^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus <mathjax>#"no. of moles"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass"/"Molar mass"#</mathjax> <mathjax>#=#</mathjax> </p> <p><mathjax>#(120*g)/(180.16*g*mol^-1)#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#4/6*mol#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles are there in 120 g of glucose?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="330614" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-03T07:00:25" itemprop="dateCreated"> Nov 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, glucose, <mathjax>#C_6H_12O_6#</mathjax> has a molar mass of <mathjax>#120.16*g*mol^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus <mathjax>#"no. of moles"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass"/"Molar mass"#</mathjax> <mathjax>#=#</mathjax> </p> <p><mathjax>#(120*g)/(180.16*g*mol^-1)#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#4/6*mol#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/330614" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? 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How many moles are there in 120 g of glucose?

ab9a5cae-6ddd-11ea-ae53-ccda262736ce

https://socratic.org/questions/what-is-the-formula-for-sodium-nitride

Na3N

start chemical_formula qc_end substance 5 6 qc_end end

[{"type":"other","value":"Chemical Formula [OF] sodium nitride [IN] default"}]

[{"type":"chemical equation","value":"Na3N"}]

[{"type":"substance name","value":"Sodium nitride"}]

<h1 class="questionTitle" itemprop="name">What is the formula for sodium nitride?</h1>

Na3N

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Sodium</strong> is an element in <strong>group 1</strong> of <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>. As such, it will form an electron by <em>losing</em> a single electron to form a <mathjax>#"1+"#</mathjax> ion: <mathjax>#"Na"^+#</mathjax>.</p> <p><strong>Nitrogen</strong> is an element in <strong>group 5</strong> of the periodic table. When it forms the <strong>nitride ion</strong>, it <em>gains</em> three electrons to form a <mathjax>#"3-"#</mathjax> ion: <mathjax>#"N"^(3-)#</mathjax>.</p> <p>In <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compounds</a>, the charges of constituent ions must balance. This can be achieved by having three sodium ions per nitride ion. Therefore, the formula of sodium nitride is <mathjax>#"Na"_3"N"#</mathjax>.</p> <p>However, <mathjax>#"Na"_3"N"#</mathjax> is <em>extremely</em> unstable. It rapidly decomposes into its constituent <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> according to the equation:</p> <p><mathjax>#2"Na"_3"N" -&gt; 6"Na" + "N"_2#</mathjax></p> <p>It lacks a <strong>boiling point</strong> because of this. Since ionic <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> have very high melting and boiling points as a result of the strong electrostatic attraction between oppositely charged ions that holds them together, sodium nitride should be no different; however, it will decompose as shown at around <mathjax>#360#</mathjax> <strong>Kelvin</strong> (<mathjax>#"K"#</mathjax>) or <mathjax>#86.85#</mathjax> <mathjax>#""^@ "C"#</mathjax>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Na"_3"N"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Sodium</strong> is an element in <strong>group 1</strong> of <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>. As such, it will form an electron by <em>losing</em> a single electron to form a <mathjax>#"1+"#</mathjax> ion: <mathjax>#"Na"^+#</mathjax>.</p> <p><strong>Nitrogen</strong> is an element in <strong>group 5</strong> of the periodic table. When it forms the <strong>nitride ion</strong>, it <em>gains</em> three electrons to form a <mathjax>#"3-"#</mathjax> ion: <mathjax>#"N"^(3-)#</mathjax>.</p> <p>In <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compounds</a>, the charges of constituent ions must balance. This can be achieved by having three sodium ions per nitride ion. Therefore, the formula of sodium nitride is <mathjax>#"Na"_3"N"#</mathjax>.</p> <p>However, <mathjax>#"Na"_3"N"#</mathjax> is <em>extremely</em> unstable. It rapidly decomposes into its constituent <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> according to the equation:</p> <p><mathjax>#2"Na"_3"N" -&gt; 6"Na" + "N"_2#</mathjax></p> <p>It lacks a <strong>boiling point</strong> because of this. Since ionic <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> have very high melting and boiling points as a result of the strong electrostatic attraction between oppositely charged ions that holds them together, sodium nitride should be no different; however, it will decompose as shown at around <mathjax>#360#</mathjax> <strong>Kelvin</strong> (<mathjax>#"K"#</mathjax>) or <mathjax>#86.85#</mathjax> <mathjax>#""^@ "C"#</mathjax>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the formula for sodium nitride?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/determining-formula-and-molar-masses" itemprop="url"> <span class="breadcrumb" itemprop="title">Determining Formula</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="208239" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/owen-b"><img alt="" class="" src="https://profilepictures.socratic.org/5O90HPzZRGiovfbNkapI_Screenshot_20170906-141654.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/owen-b"> Owen Bell </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-05T00:07:05" itemprop="dateCreated"> Jan 5, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Na"_3"N"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Sodium</strong> is an element in <strong>group 1</strong> of <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>. As such, it will form an electron by <em>losing</em> a single electron to form a <mathjax>#"1+"#</mathjax> ion: <mathjax>#"Na"^+#</mathjax>.</p> <p><strong>Nitrogen</strong> is an element in <strong>group 5</strong> of the periodic table. When it forms the <strong>nitride ion</strong>, it <em>gains</em> three electrons to form a <mathjax>#"3-"#</mathjax> ion: <mathjax>#"N"^(3-)#</mathjax>.</p> <p>In <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compounds</a>, the charges of constituent ions must balance. This can be achieved by having three sodium ions per nitride ion. Therefore, the formula of sodium nitride is <mathjax>#"Na"_3"N"#</mathjax>.</p> <p>However, <mathjax>#"Na"_3"N"#</mathjax> is <em>extremely</em> unstable. It rapidly decomposes into its constituent <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> according to the equation:</p> <p><mathjax>#2"Na"_3"N" -&gt; 6"Na" + "N"_2#</mathjax></p> <p>It lacks a <strong>boiling point</strong> because of this. Since ionic <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> have very high melting and boiling points as a result of the strong electrostatic attraction between oppositely charged ions that holds them together, sodium nitride should be no different; however, it will decompose as shown at around <mathjax>#360#</mathjax> <strong>Kelvin</strong> (<mathjax>#"K"#</mathjax>) or <mathjax>#86.85#</mathjax> <mathjax>#""^@ "C"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/208239" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-possible-to-find-a-molecular-formula-from-molar-mass"> Is it possible to find a molecular formula from molar mass? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5368e0cc02bf34779e175781"> Question #75781 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-when-determining-formulas"> What are some common mistakes students make when determining formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-an-acid"> How can I determine the formula of an acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-chemical-formula-of-a-product"> How can I determine the chemical formula of a product? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-empirical-formula-of-a-compound"> How can I determine the empirical formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-a-hydrate"> How can I determine the formula of a hydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-empirical-formula-indicate"> What does the empirical formula indicate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-molecule-with-molecular-weight-of-180-18-g-mol-is-analyzed-and-found-to-contai"> A molecule with molecular weight of 180.18 g/mol is analyzed and found to contain 40.00% carbon,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-i-need-to-know-the-number-of-moles-of-each-element-to-determine-the-formula-o"> Do I need to know the number of moles of each element to determine the formula of the compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/determining-formula-and-molar-masses"> See all questions in Determining Formula </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 47969 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the formula for sodium nitride?

a83d7343-6ddd-11ea-95cf-ccda262736ce

https://socratic.org/questions/59b51bd37c014919d438701b

2.17 × 10^25

start physical_unit 2 3 number none qc_end physical_unit 8 8 5 6 mole qc_end end

[{"type":"physical unit","value":"Number [OF] oxygen atoms"}]

[{"type":"physical unit","value":"2.17 × 10^25"}]

[{"type":"physical unit","value":"Mole [OF] glucose [=] \\pu{6 mol}"}]

<h1 class="questionTitle" itemprop="name">How many oxygen atoms in #6*mol# of glucose?</h1>

2.17 × 10^25

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Where <mathjax>#N_A-=6.022xx10^23*mol^-1#</mathjax>....</p> <p>In each mole of glucose, i.e. in each <mathjax>#6.022xx10^23#</mathjax> individual glucose molecules, there are CLEARLY <mathjax>#6*mol#</mathjax> of oxygen atoms, <mathjax>#12*mol#</mathjax> of hydrogen atoms, and <mathjax>#6*mol#</mathjax> of carbon atoms... Do you appreciate this? Here I use <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> as I would ANY OTHER collective number, i.e. <mathjax>#"dozen"#</mathjax>, <mathjax>#"gross"#</mathjax>, or <mathjax>#"half-dozen"#</mathjax>. </p> <p>Why do we use such an absurdly large number? Well, because <mathjax>#1*mol#</mathjax> of <mathjax>#""^12C#</mathjax> atoms has a mass of <mathjax>#12*g#</mathjax>; <mathjax>#1*mol#</mathjax> of <mathjax>#""^16O#</mathjax> atoms has a mass of <mathjax>#16*g#</mathjax>; and <mathjax>#1*mol#</mathjax> of <mathjax>#""^1H#</mathjax> atoms has a mass of <mathjax>#1*g#</mathjax>. The mole is thus the link between the micro world of atoms, and molecules, which we certainly cannot see, but whose existence we can infer, with the macro world or grams, and kilograms, and pounds, and litres, etc, the which we can measure out by some means in a laboratory....... </p> <p>So what is the mass of the given molar quantity of oxygen atoms?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Are there not <mathjax>#36*N_A#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Where <mathjax>#N_A-=6.022xx10^23*mol^-1#</mathjax>....</p> <p>In each mole of glucose, i.e. in each <mathjax>#6.022xx10^23#</mathjax> individual glucose molecules, there are CLEARLY <mathjax>#6*mol#</mathjax> of oxygen atoms, <mathjax>#12*mol#</mathjax> of hydrogen atoms, and <mathjax>#6*mol#</mathjax> of carbon atoms... Do you appreciate this? Here I use <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> as I would ANY OTHER collective number, i.e. <mathjax>#"dozen"#</mathjax>, <mathjax>#"gross"#</mathjax>, or <mathjax>#"half-dozen"#</mathjax>. </p> <p>Why do we use such an absurdly large number? Well, because <mathjax>#1*mol#</mathjax> of <mathjax>#""^12C#</mathjax> atoms has a mass of <mathjax>#12*g#</mathjax>; <mathjax>#1*mol#</mathjax> of <mathjax>#""^16O#</mathjax> atoms has a mass of <mathjax>#16*g#</mathjax>; and <mathjax>#1*mol#</mathjax> of <mathjax>#""^1H#</mathjax> atoms has a mass of <mathjax>#1*g#</mathjax>. The mole is thus the link between the micro world of atoms, and molecules, which we certainly cannot see, but whose existence we can infer, with the macro world or grams, and kilograms, and pounds, and litres, etc, the which we can measure out by some means in a laboratory....... </p> <p>So what is the mass of the given molar quantity of oxygen atoms?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many oxygen atoms in #6*mol# of glucose?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="473710" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-10T14:07:10" itemprop="dateCreated"> Sep 10, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Are there not <mathjax>#36*N_A#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Where <mathjax>#N_A-=6.022xx10^23*mol^-1#</mathjax>....</p> <p>In each mole of glucose, i.e. in each <mathjax>#6.022xx10^23#</mathjax> individual glucose molecules, there are CLEARLY <mathjax>#6*mol#</mathjax> of oxygen atoms, <mathjax>#12*mol#</mathjax> of hydrogen atoms, and <mathjax>#6*mol#</mathjax> of carbon atoms... Do you appreciate this? Here I use <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> as I would ANY OTHER collective number, i.e. <mathjax>#"dozen"#</mathjax>, <mathjax>#"gross"#</mathjax>, or <mathjax>#"half-dozen"#</mathjax>. </p> <p>Why do we use such an absurdly large number? Well, because <mathjax>#1*mol#</mathjax> of <mathjax>#""^12C#</mathjax> atoms has a mass of <mathjax>#12*g#</mathjax>; <mathjax>#1*mol#</mathjax> of <mathjax>#""^16O#</mathjax> atoms has a mass of <mathjax>#16*g#</mathjax>; and <mathjax>#1*mol#</mathjax> of <mathjax>#""^1H#</mathjax> atoms has a mass of <mathjax>#1*g#</mathjax>. The mole is thus the link between the micro world of atoms, and molecules, which we certainly cannot see, but whose existence we can infer, with the macro world or grams, and kilograms, and pounds, and litres, etc, the which we can measure out by some means in a laboratory....... </p> <p>So what is the mass of the given molar quantity of oxygen atoms?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/473710" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2174 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many oxygen atoms in #6*mol# of glucose?

a9be5138-6ddd-11ea-b6bd-ccda262736ce

https://socratic.org/questions/the-titration-of-25-ml-of-a-water-sample-required-15-75-ml-of-0-0125-m-edta-how-

16.61 ppm MgCO3

start physical_unit 7 7 hardness ppm qc_end c_other OTHER qc_end physical_unit 6 8 3 4 volume qc_end physical_unit 15 15 10 11 volume qc_end physical_unit 15 15 13 14 molarity qc_end end

[{"type":"physical unit","value":"Hardness [OF] water [IN] ppm MgCO3"}]

[{"type":"physical unit","value":"16.61 ppm MgCO3"}]

[{"type":"other","value":"Assume the moles of EDTA are equal to the moles of MgCO3."},{"type":"physical unit","value":"Volume [OF] a water sample [=] \\pu{25 mL}"},{"type":"physical unit","value":"Volume [OF] EDTA [=] \\pu{15.75 mL}"},{"type":"physical unit","value":"Molarity [OF] EDTA [=] \\pu{0.0125 M}"}]

<h1 class="questionTitle" itemprop="name">The titration of 25 mL of a water sample required 15.75 mL of 0.0125 M EDTA. How do you calculate the hardness of water in the unit of ppm #MgCO_3#? (Assume the moles of EDTA are equal to the moles of MgCO3)</h1>

16.61 ppm MgCO3

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of EDTA"=15.75xx10^-3*Lxx0.0125*mol*L^-1=1.97xx10^-5mol*L^-1#</mathjax></p> <p>And thus in a <mathjax>#1*L#</mathjax> volume of this water, there are <mathjax>#1.97xx10^-5mol#</mathjax> of <mathjax>#MgCO_3#</mathjax>, given the assumed 1:1 equivalence.</p> <p><mathjax>#"Mass of"#</mathjax> <mathjax>#MgCO_3#</mathjax> in a <mathjax>#1*L#</mathjax> volume,</p> <p><mathjax>#=#</mathjax> <mathjax>#1*cancelLxx1.97xx10^-5*cancel(mol*L^-1)xx 84.32*g*cancel(mol^-1)=#</mathjax></p> <p><mathjax>#1.66xx10^-2*g#</mathjax></p> <p>With respect to <mathjax>#"magnesium carbonate"#</mathjax>, this is <mathjax>#17#</mathjax> <mathjax>#"ppm"#</mathjax>, i.e. <mathjax>#17*mg#</mathjax> of <mathjax>#MgCO_3#</mathjax> <mathjax>#"per litre of solution"#</mathjax>.</p> <p>Normally, we would use <mathjax>#"ppm"#</mathjax> to express the concentration in terms of magnesium or carbonate ions separately in solution. </p> <p>Note that when we deal with <mathjax>#"ppm"#</mathjax> concentrations, typically we deal with trace quantities of ions in solution. And thus we don't really have to consider how the densities of these solutions vary. The densities are near as dammit to that of pure water. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>In <mathjax>#"parts per million"#</mathjax> with respect to <mathjax>#MgCO_3#</mathjax>, the water is <mathjax>#17#</mathjax> <mathjax>#"ppm"#</mathjax>.</p> <p>We know that <mathjax>#"1 ppm"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#1*mg*L^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of EDTA"=15.75xx10^-3*Lxx0.0125*mol*L^-1=1.97xx10^-5mol*L^-1#</mathjax></p> <p>And thus in a <mathjax>#1*L#</mathjax> volume of this water, there are <mathjax>#1.97xx10^-5mol#</mathjax> of <mathjax>#MgCO_3#</mathjax>, given the assumed 1:1 equivalence.</p> <p><mathjax>#"Mass of"#</mathjax> <mathjax>#MgCO_3#</mathjax> in a <mathjax>#1*L#</mathjax> volume,</p> <p><mathjax>#=#</mathjax> <mathjax>#1*cancelLxx1.97xx10^-5*cancel(mol*L^-1)xx 84.32*g*cancel(mol^-1)=#</mathjax></p> <p><mathjax>#1.66xx10^-2*g#</mathjax></p> <p>With respect to <mathjax>#"magnesium carbonate"#</mathjax>, this is <mathjax>#17#</mathjax> <mathjax>#"ppm"#</mathjax>, i.e. <mathjax>#17*mg#</mathjax> of <mathjax>#MgCO_3#</mathjax> <mathjax>#"per litre of solution"#</mathjax>.</p> <p>Normally, we would use <mathjax>#"ppm"#</mathjax> to express the concentration in terms of magnesium or carbonate ions separately in solution. </p> <p>Note that when we deal with <mathjax>#"ppm"#</mathjax> concentrations, typically we deal with trace quantities of ions in solution. And thus we don't really have to consider how the densities of these solutions vary. The densities are near as dammit to that of pure water. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">The titration of 25 mL of a water sample required 15.75 mL of 0.0125 M EDTA. How do you calculate the hardness of water in the unit of ppm #MgCO_3#? (Assume the moles of EDTA are equal to the moles of MgCO3)</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/titration-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Titration Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="346460" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-04T11:15:55" itemprop="dateCreated"> Dec 4, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>In <mathjax>#"parts per million"#</mathjax> with respect to <mathjax>#MgCO_3#</mathjax>, the water is <mathjax>#17#</mathjax> <mathjax>#"ppm"#</mathjax>.</p> <p>We know that <mathjax>#"1 ppm"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#1*mg*L^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of EDTA"=15.75xx10^-3*Lxx0.0125*mol*L^-1=1.97xx10^-5mol*L^-1#</mathjax></p> <p>And thus in a <mathjax>#1*L#</mathjax> volume of this water, there are <mathjax>#1.97xx10^-5mol#</mathjax> of <mathjax>#MgCO_3#</mathjax>, given the assumed 1:1 equivalence.</p> <p><mathjax>#"Mass of"#</mathjax> <mathjax>#MgCO_3#</mathjax> in a <mathjax>#1*L#</mathjax> volume,</p> <p><mathjax>#=#</mathjax> <mathjax>#1*cancelLxx1.97xx10^-5*cancel(mol*L^-1)xx 84.32*g*cancel(mol^-1)=#</mathjax></p> <p><mathjax>#1.66xx10^-2*g#</mathjax></p> <p>With respect to <mathjax>#"magnesium carbonate"#</mathjax>, this is <mathjax>#17#</mathjax> <mathjax>#"ppm"#</mathjax>, i.e. <mathjax>#17*mg#</mathjax> of <mathjax>#MgCO_3#</mathjax> <mathjax>#"per litre of solution"#</mathjax>.</p> <p>Normally, we would use <mathjax>#"ppm"#</mathjax> to express the concentration in terms of magnesium or carbonate ions separately in solution. </p> <p>Note that when we deal with <mathjax>#"ppm"#</mathjax> concentrations, typically we deal with trace quantities of ions in solution. And thus we don't really have to consider how the densities of these solutions vary. The densities are near as dammit to that of pure water. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/346460" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-acid-base-titration-calculations"> How do you do acid base titration calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-use-titration-calculations-to-find-ph"> How do you use titration calculations to find pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/radox-titration"> What is a redox titration and what is it used for? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-titration-used-when-standardizing-a-solution"> Why is titration used when standardizing a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-titration-suitable-for-sodium-nitrate"> Is titration suitable for sodium nitrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-do-redox-titration-calculations"> How can I do redox titration calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-titration-of-weak-acid-and-strong-base"> How can I calculate the titration of a weak acid and a strong base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-make-back-titration-calculations"> How can I make back titration calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-titration-affect-molarity"> How does titration affect molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-endpoint-of-a-titration-differ-from-the-equivalence-point"> How does the endpoint of a titration differ from the equivalence point? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/reactions-in-solution/titration-calculations"> See all questions in Titration Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 33764 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

The titration of 25 mL of a water sample required 15.75 mL of 0.0125 M EDTA. How do you calculate the hardness of water in the unit of ppm #MgCO_3#? (Assume the moles of EDTA are equal to the moles of MgCO3)

a9a1fffb-6ddd-11ea-840c-ccda262736ce

https://socratic.org/questions/57f473507c014970094f18a9

3.56 × 10^24

start physical_unit 2 3 number none qc_end physical_unit 10 10 6 7 mass qc_end end

[{"type":"physical unit","value":"Number [OF] hydrogen atoms"}]

[{"type":"physical unit","value":"3.56 × 10^24"}]

[{"type":"physical unit","value":"Mass [OF] methane [=] \\pu{23.7 g }"}]

<h1 class="questionTitle" itemprop="name">How many hydrogen atoms in a #23.7*g# MASS of methane?</h1>

3.56 × 10^24

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We work the molar quantity to get an answer in moles of methane. Because for each mole of methane there four moles of hydrogen atoms, we multiply this number by four to get an answer in moles of hydrogen. Because for each mole there <mathjax>#"Avogadro's number"#</mathjax> of particles, we (finally!) multiply this last number by <mathjax>#N_A#</mathjax> to get the number of hydrogen atoms. </p> <p>Got your calculator ready?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#(23.7*g)/(16.04*g*mol^-1)xx"4 hydrogen atoms mol"^-1xxN_A#</mathjax> <mathjax>#=#</mathjax></p> <p><mathjax>#??"how many hydrogen atoms."#</mathjax><br/> <mathjax>#N_A="Avogadro's number,"#</mathjax> <mathjax>#6.022xx10^23#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We work the molar quantity to get an answer in moles of methane. Because for each mole of methane there four moles of hydrogen atoms, we multiply this number by four to get an answer in moles of hydrogen. Because for each mole there <mathjax>#"Avogadro's number"#</mathjax> of particles, we (finally!) multiply this last number by <mathjax>#N_A#</mathjax> to get the number of hydrogen atoms. </p> <p>Got your calculator ready?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many hydrogen atoms in a #23.7*g# MASS of methane?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="318004" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-05T06:01:19" itemprop="dateCreated"> Oct 5, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#(23.7*g)/(16.04*g*mol^-1)xx"4 hydrogen atoms mol"^-1xxN_A#</mathjax> <mathjax>#=#</mathjax></p> <p><mathjax>#??"how many hydrogen atoms."#</mathjax><br/> <mathjax>#N_A="Avogadro's number,"#</mathjax> <mathjax>#6.022xx10^23#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We work the molar quantity to get an answer in moles of methane. Because for each mole of methane there four moles of hydrogen atoms, we multiply this number by four to get an answer in moles of hydrogen. Because for each mole there <mathjax>#"Avogadro's number"#</mathjax> of particles, we (finally!) multiply this last number by <mathjax>#N_A#</mathjax> to get the number of hydrogen atoms. </p> <p>Got your calculator ready?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/318004" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1201 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many hydrogen atoms in a #23.7*g# MASS of methane?

ac0ba228-6ddd-11ea-956f-ccda262736ce

https://socratic.org/questions/what-is-the-poh-of-a-2-1-10-6-m-solution

5.68

start physical_unit 10 10 poh none qc_end physical_unit 10 10 6 9 molarity qc_end end

[{"type":"physical unit","value":"pOH [OF] solution"}]

[{"type":"physical unit","value":"5.68"}]

[{"type":"physical unit","value":"Molarity [OF] solution [=] \\pu{2.1 × 10^(-6) M}"}]

<h1 class="questionTitle" itemprop="name">What is the #pOH# of a #2.1*10^-6# #M# solution? </h1>

5.68

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pOH=-log_10[HO^-]#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#-log_10(2.1xx10^-6)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-(-5.68)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#5.68#</mathjax>.</p> <p>What is <mathjax>#pH#</mathjax> of this solution? You should be able to answer this easily.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We assume that you mean a <mathjax>#2.1xx10^-6*mol*L^-1#</mathjax> solution of <mathjax>#KOH#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pOH=-log_10[HO^-]#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#-log_10(2.1xx10^-6)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-(-5.68)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#5.68#</mathjax>.</p> <p>What is <mathjax>#pH#</mathjax> of this solution? You should be able to answer this easily.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the #pOH# of a #2.1*10^-6# #M# solution? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="283858" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-02T13:04:43" itemprop="dateCreated"> Jul 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We assume that you mean a <mathjax>#2.1xx10^-6*mol*L^-1#</mathjax> solution of <mathjax>#KOH#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pOH=-log_10[HO^-]#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#-log_10(2.1xx10^-6)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-(-5.68)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#5.68#</mathjax>.</p> <p>What is <mathjax>#pH#</mathjax> of this solution? You should be able to answer this easily.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/283858" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-at-an-equivalence-point"> How do you determine pH at an equivalence point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-molarity"> How do you determine pH from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-alkalinity-mean"> What does alkalinity mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-base"> What is a base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-acid-base-indicators-change-color"> How do acid base indicators change color? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-neutral-ph"> What is a neutral pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-alkalinity-affect-pool-water"> How does alkalinity affect pool water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-important-in-drinking-water"> Why is pH important in drinking water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-ph-of-solution"> How can I calculate the pH of a solution? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/ph-calculations"> See all questions in pH calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5048 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the #pOH# of a #2.1*10^-6# #M# solution?

a90c07a4-6ddd-11ea-99c4-ccda262736ce

https://socratic.org/questions/5843689e11ef6b0585039d95

386.57 ℃

start physical_unit 4 6 temperature °c qc_end physical_unit 4 6 16 17 volume qc_end physical_unit 4 6 13 14 temperature qc_end physical_unit 4 6 8 9 pressure qc_end physical_unit 4 6 24 25 volume qc_end physical_unit 4 6 28 29 pressure qc_end end

[{"type":"physical unit","value":"Temperature2 [OF] an ideal gas [IN] ℃"}]

[{"type":"physical unit","value":"386.57 ℃"}]

[{"type":"physical unit","value":"Volume1 [OF] an ideal gas [=] \\pu{450 L}"},{"type":"physical unit","value":"Temperature1 [OF] an ideal gas [=] \\pu{25 ℃}"},{"type":"physical unit","value":"Pressure1 [OF] an ideal gas [=] \\pu{350 torr}"},{"type":"physical unit","value":"Volume2 [OF] an ideal gas [=] \\pu{420 L}"},{"type":"physical unit","value":"Pressure2 [OF] an ideal gas [=] \\pu{830 torr}"}]

<h1 class="questionTitle" itemprop="name">If the volume of an ideal gas at #"350 torr"# of pressure and #25^@ "C"# is #"450 L"#, at what temperature is its volume #"420 L"# and pressure #"830 torr"# in a sealed balloon?</h1>

386.57 ℃

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax># (V_1 xx P_1)/T_1 = (V_2 xx P_2)/T_2#</mathjax> </p> <p><mathjax># V_1 = 450#</mathjax> <br/> <mathjax># P_1 = 350#</mathjax><br/> <mathjax># T_1 = 273 + 25 = 298 #</mathjax> temperature must be calculated in degrees K or <a href="https://socratic.org/chemistry/the-behavior-of-gases/kelvin-temperatures-and-absolute-zero">absolute zero</a>. </p> <p><mathjax># V_2 = 420#</mathjax> <br/> <mathjax># P_2 = 830#</mathjax> <br/> <mathjax># T_2 = unknown ?#</mathjax></p> <p>putting these values into the equation gives </p> <p><mathjax># (450 xx 350)/298 = (420 xx 830)/T_2#</mathjax> Solving for <mathjax>#T_2#</mathjax> gives</p> <p><mathjax>#T_2 = (420 xx 830 xx 298)/ (450 xx 350)#</mathjax> solving gives </p> <p>#T_2 = 659.57333333 subtract 273 to bring back to degrees C and round off to four significant figures. gives </p> <p><mathjax>#T_2 = 386.6 #</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>386.6 degrees C </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax># (V_1 xx P_1)/T_1 = (V_2 xx P_2)/T_2#</mathjax> </p> <p><mathjax># V_1 = 450#</mathjax> <br/> <mathjax># P_1 = 350#</mathjax><br/> <mathjax># T_1 = 273 + 25 = 298 #</mathjax> temperature must be calculated in degrees K or <a href="https://socratic.org/chemistry/the-behavior-of-gases/kelvin-temperatures-and-absolute-zero">absolute zero</a>. </p> <p><mathjax># V_2 = 420#</mathjax> <br/> <mathjax># P_2 = 830#</mathjax> <br/> <mathjax># T_2 = unknown ?#</mathjax></p> <p>putting these values into the equation gives </p> <p><mathjax># (450 xx 350)/298 = (420 xx 830)/T_2#</mathjax> Solving for <mathjax>#T_2#</mathjax> gives</p> <p><mathjax>#T_2 = (420 xx 830 xx 298)/ (450 xx 350)#</mathjax> solving gives </p> <p>#T_2 = 659.57333333 subtract 273 to bring back to degrees C and round off to four significant figures. gives </p> <p><mathjax>#T_2 = 386.6 #</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If the volume of an ideal gas at #"350 torr"# of pressure and #25^@ "C"# is #"450 L"#, at what temperature is its volume #"420 L"# and pressure #"830 torr"# in a sealed balloon?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/combined-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Combined Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="348764" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/david-drayer"><img alt="" class="" src="https://graph.facebook.com/10206723679871989/picture?height=50&amp;width=50" title=""/></a> <a class="secondContributorPic" href="/users/truong-son-n"><img alt="" class="" src="https://profilepictures.socratic.org/07k4plnQfmnmzMuesQzw_14844-1449381920.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/david-drayer"> David Drayer </a>·<a class="topContributorLink" href="/users/truong-son-n"> Truong-Son N. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-08T13:53:44" itemprop="dateCreated"> Dec 8, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>386.6 degrees C </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax># (V_1 xx P_1)/T_1 = (V_2 xx P_2)/T_2#</mathjax> </p> <p><mathjax># V_1 = 450#</mathjax> <br/> <mathjax># P_1 = 350#</mathjax><br/> <mathjax># T_1 = 273 + 25 = 298 #</mathjax> temperature must be calculated in degrees K or <a href="https://socratic.org/chemistry/the-behavior-of-gases/kelvin-temperatures-and-absolute-zero">absolute zero</a>. </p> <p><mathjax># V_2 = 420#</mathjax> <br/> <mathjax># P_2 = 830#</mathjax> <br/> <mathjax># T_2 = unknown ?#</mathjax></p> <p>putting these values into the equation gives </p> <p><mathjax># (450 xx 350)/298 = (420 xx 830)/T_2#</mathjax> Solving for <mathjax>#T_2#</mathjax> gives</p> <p><mathjax>#T_2 = (420 xx 830 xx 298)/ (450 xx 350)#</mathjax> solving gives </p> <p>#T_2 = 659.57333333 subtract 273 to bring back to degrees C and round off to four significant figures. gives </p> <p><mathjax>#T_2 = 386.6 #</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/348764" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5345df5f02bf345f71b1c8e8"> Question #1c8e8 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ac3df02bf342f4c3bfabb"> Question #bfabb </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-you-want-to-solve-for-the-volume-of-a-gas-v2-and-p1-is-greater-than-p2-would-"> If you want to solve for the volume of a gas (V2) and P1 is greater than P2, would you expect V2... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-modern-refrigerator-take-advantage-of-the-gas-laws-to-remove-heat-f"> How does the modern refrigerator take advantage of the gas laws to remove heat from a system? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-certain-sample-of-gas-has-a-volume-of-0-452-l-measured-at-87-c-and-0-620-atm-w"> A certain sample of gas has a volume of 0.452 L measured at 87°C and 0.620 atm. 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If the volume of an ideal gas at #"350 torr"# of pressure and #25^@ "C"# is #"450 L"#, at what temperature is its volume #"420 L"# and pressure #"830 torr"# in a sealed balloon?

a94834ae-6ddd-11ea-b9f6-ccda262736ce

https://socratic.org/questions/597473cc7c01496a1a4cc5c8

4 Al + 3 O2 -> 2 Al2O3

start chemical_equation qc_end substance 5 6 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the oxidation"}]

[{"type":"chemical equation","value":"4 Al + 3 O2 -> 2 Al2O3"}]

[{"type":"substance name","value":"Aluminum metal"}]

<h1 class="questionTitle" itemprop="name">How is the oxidation of aluminum metal represented?</h1>

4 Al + 3 O2 -> 2 Al2O3

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At first we have <mathjax>#Al+O_2&gt;Al_2O_3#</mathjax></p> <p>Let's first balance <mathjax>#Al#</mathjax>, the LHS has 1 Al atom, while the RHS has 2. To balance this we add another <mathjax>#Al#</mathjax> to the LHS, to get: <mathjax>#2Al+O_2&gt;Al_2O_3#</mathjax></p> <p>Now to balance <mathjax>#O#</mathjax>, the LHS has 2, while the RHS has 3, <mathjax>#2*3=6#</mathjax>, so we have <mathjax>#2Al+3O_2&gt;2Al_2O_3#</mathjax></p> <p>Mow <mathjax>#Al#</mathjax> is unbalanced again, to balance, we just add an extra 2 <mathjax>#Al#</mathjax> to the LHS to get <mathjax>#4Al + 3O_2&gt;2Al_2O_3#</mathjax>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4Al+3O_"&gt;2Al_2O_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At first we have <mathjax>#Al+O_2&gt;Al_2O_3#</mathjax></p> <p>Let's first balance <mathjax>#Al#</mathjax>, the LHS has 1 Al atom, while the RHS has 2. To balance this we add another <mathjax>#Al#</mathjax> to the LHS, to get: <mathjax>#2Al+O_2&gt;Al_2O_3#</mathjax></p> <p>Now to balance <mathjax>#O#</mathjax>, the LHS has 2, while the RHS has 3, <mathjax>#2*3=6#</mathjax>, so we have <mathjax>#2Al+3O_2&gt;2Al_2O_3#</mathjax></p> <p>Mow <mathjax>#Al#</mathjax> is unbalanced again, to balance, we just add an extra 2 <mathjax>#Al#</mathjax> to the LHS to get <mathjax>#4Al + 3O_2&gt;2Al_2O_3#</mathjax>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How is the oxidation of aluminum metal represented?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="455374" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/idkwhatname"><img alt="" class="" src="https://profilepictures.socratic.org/FoNvPMlqRulVUxwohUEn_download%20%281%29.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/idkwhatname"> IDKwhatName </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-23T10:18:11" itemprop="dateCreated"> Jul 23, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4Al+3O_"&gt;2Al_2O_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At first we have <mathjax>#Al+O_2&gt;Al_2O_3#</mathjax></p> <p>Let's first balance <mathjax>#Al#</mathjax>, the LHS has 1 Al atom, while the RHS has 2. To balance this we add another <mathjax>#Al#</mathjax> to the LHS, to get: <mathjax>#2Al+O_2&gt;Al_2O_3#</mathjax></p> <p>Now to balance <mathjax>#O#</mathjax>, the LHS has 2, while the RHS has 3, <mathjax>#2*3=6#</mathjax>, so we have <mathjax>#2Al+3O_2&gt;2Al_2O_3#</mathjax></p> <p>Mow <mathjax>#Al#</mathjax> is unbalanced again, to balance, we just add an extra 2 <mathjax>#Al#</mathjax> to the LHS to get <mathjax>#4Al + 3O_2&gt;2Al_2O_3#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/455374" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="455376" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-23T10:21:02" itemprop="dateCreated"> Jul 23, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Garbage in must equal garbage out......."#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#2Al(s) + 3/2O_2(g) rarr Al_2O_3(s)#</mathjax></p> <p>If the non-stoichiometric coefficients offend thine sensibilities.....then DOUBLE the entire equation......</p> <p><mathjax>#4Al(s) + 3O_2(g) rarr 2Al_2O_3(s)#</mathjax></p> <p>In either instance, 2 equiv of aluminum metal are oxidized by 3 equiv dioxygen gas to give one equiv alumina. </p> <p>Note that with regard to dioxygen gas, ALL of the elemental gases (save for the Noble Gases) are diatomic, e.g. <mathjax>#H_2, N_2, O_2, F_2, Cl_2#</mathjax> are BINUCLEAR. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/455376" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------&gt; H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -&gt; Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -&gt;# ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3611 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How is the oxidation of aluminum metal represented?

a96626c1-6ddd-11ea-a115-ccda262736ce

https://socratic.org/questions/how-do-you-balance-lino-3-cabr-2-ca-no-3-2-libr

2 LiNO3 + CaBr2 -> Ca(NO3)2 + 2 LiBr

start chemical_equation qc_end chemical_equation 4 10 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"2 LiNO3 + CaBr2 -> Ca(NO3)2 + 2 LiBr"}]

[{"type":"chemical equation","value":"LiNO3 + CaBr2 -> Ca(NO3)2 + LiBr"}]

<h1 class="questionTitle" itemprop="name">How do you balance #LiNO_3 + CaBr_2 -&gt; Ca(NO_3)_2 + LiBr#?</h1>

2 LiNO3 + CaBr2 -> Ca(NO3)2 + 2 LiBr

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><ol> <li>This is done through trial and error method, wherein coefficients are assigned to each compound temporarily and replaced until the no. of atoms of <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> of both sides of the equation are balanced;</li> <li>Generally, in this method you have to consider the complex compound first and work your way to the least one;</li> <li><a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/polyatomic-ions">Polyatomic ions</a> are usually consider as one unit, as in the case of nitrate (<mathjax>#NO_3#</mathjax>), which has 2 ions on the right side of the equation .</li> <li>Looking at the left side <mathjax>#NO_3#</mathjax> is only one, thus putting a coefficient of 2 would balance the nitrate and of course will change the no. of atoms of <mathjax>#Li#</mathjax> which would increase to <mathjax>#2#</mathjax>.</li> <li>Back to the right side, <mathjax>#Li#</mathjax> is only one, thus putting again a coefficient of 2 would balance the no. of atoms of <mathjax>#Li#</mathjax>., and of course affect the number of atoms of <mathjax>#Br#</mathjax> which would increase to <mathjax>#2#</mathjax></li> <li>Checking the left side for <mathjax>#Br#</mathjax>, the no. of atom is already 2, thus the equation is now balance. </li> <li>You may create a T balance, to check whether elements have same number of atoms both sides of the equation;<br/> <mathjax>#ReactantTTProduct#</mathjax><br/> <mathjax>#Li =2#</mathjax>.......L<mathjax>#Li=2#</mathjax><br/> <mathjax>#N=2#</mathjax>........L<mathjax>#N=2#</mathjax><br/> <mathjax>#O=6#</mathjax>.........L<mathjax>#O=6#</mathjax><br/> <mathjax>#Ca=1#</mathjax>.......L<mathjax>#Ca=1#</mathjax><br/> <mathjax>#Br=2#</mathjax>.......L<mathjax>#Br=2#</mathjax></li> </ol></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2LiNO_3 + CaBr_2 -&gt; Ca(NO_3)_2 + 2LiBr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><ol> <li>This is done through trial and error method, wherein coefficients are assigned to each compound temporarily and replaced until the no. of atoms of <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> of both sides of the equation are balanced;</li> <li>Generally, in this method you have to consider the complex compound first and work your way to the least one;</li> <li><a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/polyatomic-ions">Polyatomic ions</a> are usually consider as one unit, as in the case of nitrate (<mathjax>#NO_3#</mathjax>), which has 2 ions on the right side of the equation .</li> <li>Looking at the left side <mathjax>#NO_3#</mathjax> is only one, thus putting a coefficient of 2 would balance the nitrate and of course will change the no. of atoms of <mathjax>#Li#</mathjax> which would increase to <mathjax>#2#</mathjax>.</li> <li>Back to the right side, <mathjax>#Li#</mathjax> is only one, thus putting again a coefficient of 2 would balance the no. of atoms of <mathjax>#Li#</mathjax>., and of course affect the number of atoms of <mathjax>#Br#</mathjax> which would increase to <mathjax>#2#</mathjax></li> <li>Checking the left side for <mathjax>#Br#</mathjax>, the no. of atom is already 2, thus the equation is now balance. </li> <li>You may create a T balance, to check whether elements have same number of atoms both sides of the equation;<br/> <mathjax>#ReactantTTProduct#</mathjax><br/> <mathjax>#Li =2#</mathjax>.......L<mathjax>#Li=2#</mathjax><br/> <mathjax>#N=2#</mathjax>........L<mathjax>#N=2#</mathjax><br/> <mathjax>#O=6#</mathjax>.........L<mathjax>#O=6#</mathjax><br/> <mathjax>#Ca=1#</mathjax>.......L<mathjax>#Ca=1#</mathjax><br/> <mathjax>#Br=2#</mathjax>.......L<mathjax>#Br=2#</mathjax></li> </ol></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you balance #LiNO_3 + CaBr_2 -&gt; Ca(NO_3)_2 + LiBr#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="242675" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jarni-renz"><img alt="" class="" src="https://profilepictures.socratic.org/i6OiZQmVRHWljDVlwm8v_WIN_20160301_180231.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jarni-renz"> Jarni Renz </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-20T20:59:09" itemprop="dateCreated"> Mar 20, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2LiNO_3 + CaBr_2 -&gt; Ca(NO_3)_2 + 2LiBr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><ol> <li>This is done through trial and error method, wherein coefficients are assigned to each compound temporarily and replaced until the no. of atoms of <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> of both sides of the equation are balanced;</li> <li>Generally, in this method you have to consider the complex compound first and work your way to the least one;</li> <li><a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/polyatomic-ions">Polyatomic ions</a> are usually consider as one unit, as in the case of nitrate (<mathjax>#NO_3#</mathjax>), which has 2 ions on the right side of the equation .</li> <li>Looking at the left side <mathjax>#NO_3#</mathjax> is only one, thus putting a coefficient of 2 would balance the nitrate and of course will change the no. of atoms of <mathjax>#Li#</mathjax> which would increase to <mathjax>#2#</mathjax>.</li> <li>Back to the right side, <mathjax>#Li#</mathjax> is only one, thus putting again a coefficient of 2 would balance the no. of atoms of <mathjax>#Li#</mathjax>., and of course affect the number of atoms of <mathjax>#Br#</mathjax> which would increase to <mathjax>#2#</mathjax></li> <li>Checking the left side for <mathjax>#Br#</mathjax>, the no. of atom is already 2, thus the equation is now balance. </li> <li>You may create a T balance, to check whether elements have same number of atoms both sides of the equation;<br/> <mathjax>#ReactantTTProduct#</mathjax><br/> <mathjax>#Li =2#</mathjax>.......L<mathjax>#Li=2#</mathjax><br/> <mathjax>#N=2#</mathjax>........L<mathjax>#N=2#</mathjax><br/> <mathjax>#O=6#</mathjax>.........L<mathjax>#O=6#</mathjax><br/> <mathjax>#Ca=1#</mathjax>.......L<mathjax>#Ca=1#</mathjax><br/> <mathjax>#Br=2#</mathjax>.......L<mathjax>#Br=2#</mathjax></li> </ol></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/242675" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------&gt; H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -&gt; Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? Aluminum and hydrochloric acid react to form aluminum... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equation-sodium-phosphate-and-calcium-chloride-r"> How can I balance this chemical equation? Sodium phosphate and calcium chloride react to form... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-equation-kclo3-kcl-o2"> How can I balance this equation? ____ #KClO_3 -&gt;# ____ #KCl +# ____ #O_2# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-balancing-chemical-equations-important"> Why is balancing chemical equations important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/balancing-chemical-equations"> See all questions in Balancing Chemical Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1294 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How do you balance #LiNO_3 + CaBr_2 -&gt; Ca(NO_3)_2 + LiBr#?

a838df62-6ddd-11ea-bf85-ccda262736ce

https://socratic.org/questions/what-is-the-total-number-of-different-elements-present-in-nh-4no-3

3

start physical_unit 6 7 number none qc_end chemical_equation 10 10 qc_end end

[{"type":"physical unit","value":"Total number [OF] different elements"}]

[{"type":"physical unit","value":"3"}]

[{"type":"chemical equation","value":"NH4NO3"}]

<h1 class="questionTitle" itemprop="name">What is the total number of different elements present in #NH_4NO_3#?</h1>

3

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Ammonium nitrate has </p> <ul> <li>2 nitrogen atoms</li> <li>4 hydrogen atoms</li> <li>3 oxygen atoms</li> </ul> <p>Hence 3 different <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> present ie. nitrogen, hydrogen, and oxygen.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Ammonium nitrate has </p> <ul> <li>2 nitrogen atoms</li> <li>4 hydrogen atoms</li> <li>3 oxygen atoms</li> </ul> <p>Hence 3 different <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> present ie. nitrogen, hydrogen, and oxygen.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the total number of different elements present in #NH_4NO_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/review-of-elements-and-compounds" itemprop="url"> <span class="breadcrumb" itemprop="title">Review of Elements and Compounds</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="214194" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/trevor-r-1"><img alt="" class="" src="https://profilepictures.socratic.org/2Wf9lLD9RaSzPbXY0EW8_S5002678.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/trevor-r-1"> Trevor Ryan. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-19T13:23:42" itemprop="dateCreated"> Jan 19, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Ammonium nitrate has </p> <ul> <li>2 nitrogen atoms</li> <li>4 hydrogen atoms</li> <li>3 oxygen atoms</li> </ul> <p>Hence 3 different <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> present ie. nitrogen, hydrogen, and oxygen.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/214194" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d6f5cb02bf347f12bf13ae"> Question #f13ae </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d6f5f602bf347f105bb7b1"> Question #bb7b1 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d6f5fc02bf347f13478896"> Question #78896 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d6f60102bf347f076fd74b"> Question #fd74b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d6f60a02bf347f12bf13b2"> Question #f13b2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-find-the-molar-mass-of-an-element"> How do I find the molar mass of an element? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-element"> What is an element? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-with-elements"> What are some common mistakes students make with elements? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-compounds"> What are some examples of compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/explain-how-compounds-are-formed"> How are compounds formed? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/review-of-elements-and-compounds"> See all questions in Review of Elements and Compounds </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 10498 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the total number of different elements present in #NH_4NO_3#?

ab5737da-6ddd-11ea-86bc-ccda262736ce

https://socratic.org/questions/how-many-gallons-of-a-3-salt-solution-must-be-mixed-with-50-gallons-of-a-7-solut

50.00 gallons

start physical_unit 6 7 volume gallon qc_end physical_unit 6 6 5 5 percent qc_end physical_unit 6 7 12 13 volume qc_end physical_unit 6 6 16 16 percent qc_end physical_unit 6 6 21 21 percent qc_end end

[{"type":"physical unit","value":"Volume1 [OF] salt solution [IN] gallons"}]

[{"type":"physical unit","value":"50.00 gallons"}]

[{"type":"physical unit","value":"Percentage1 [OF] salt in solution [=] \\pu{3%}"},{"type":"physical unit","value":"Volume2 [OF] salt solution [=] \\pu{50 gallons}"},{"type":"physical unit","value":"Percentage2 [OF] salt in solution [=] \\pu{7%}"},{"type":"physical unit","value":"Percentage3 [OF] salt in solution [=] \\pu{5%}"}]

<h1 class="questionTitle" itemprop="name">How many gallons of a 3% salt solution must be mixed with 50 gallons of a 7% solution to obtain a 5% solution? </h1>

50.00 gallons

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This was an interesting question. And here is how I tackled it.</p> <p>What is required is a 5% solution, and this is made up by adding an unknown volume (we'll call that v) of a 3% solution to 50 gallons of a 7% solution.</p> <p>So, the above can be expressed as:</p> <p>7% solution + 3% solution = 5% solution</p> <p>So:<br/> (7 x 50) + (3 x v) = 5 x (50 + v)<br/> 350 + 3v = 250 + 5v<br/> 350 - 250 + 3v = 5v<br/> 100 + 3v = 5v<br/> 100 = 5v - 3v<br/> 100 = v(5 - 3)<br/> 100 = 2v</p> <p>Therefore v = 50 gallons</p> <p>Hence, you need to add 50 gallons of the 3% solution to the 50 gallons of the 7% solution and that will give 100 gallons of a 5% solution.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>50 gallons</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This was an interesting question. And here is how I tackled it.</p> <p>What is required is a 5% solution, and this is made up by adding an unknown volume (we'll call that v) of a 3% solution to 50 gallons of a 7% solution.</p> <p>So, the above can be expressed as:</p> <p>7% solution + 3% solution = 5% solution</p> <p>So:<br/> (7 x 50) + (3 x v) = 5 x (50 + v)<br/> 350 + 3v = 250 + 5v<br/> 350 - 250 + 3v = 5v<br/> 100 + 3v = 5v<br/> 100 = 5v - 3v<br/> 100 = v(5 - 3)<br/> 100 = 2v</p> <p>Therefore v = 50 gallons</p> <p>Hence, you need to add 50 gallons of the 3% solution to the 50 gallons of the 7% solution and that will give 100 gallons of a 5% solution.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many gallons of a 3% salt solution must be mixed with 50 gallons of a 7% solution to obtain a 5% solution? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solution-formation---what-happens-when-stuff-dissolves" itemprop="url"> <span class="breadcrumb" itemprop="title">Solution Formation</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="308836" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nick-41"><img alt="" class="" src="https://profilepictures.socratic.org/Sq1QmKQKSPCfDM110rRn_16.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nick-41"> Nick </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-11T21:25:25" itemprop="dateCreated"> Sep 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>50 gallons</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This was an interesting question. And here is how I tackled it.</p> <p>What is required is a 5% solution, and this is made up by adding an unknown volume (we'll call that v) of a 3% solution to 50 gallons of a 7% solution.</p> <p>So, the above can be expressed as:</p> <p>7% solution + 3% solution = 5% solution</p> <p>So:<br/> (7 x 50) + (3 x v) = 5 x (50 + v)<br/> 350 + 3v = 250 + 5v<br/> 350 - 250 + 3v = 5v<br/> 100 + 3v = 5v<br/> 100 = 5v - 3v<br/> 100 = v(5 - 3)<br/> 100 = 2v</p> <p>Therefore v = 50 gallons</p> <p>Hence, you need to add 50 gallons of the 3% solution to the 50 gallons of the 7% solution and that will give 100 gallons of a 5% solution.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/308836" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-temperature-affect-the-formation-of-a-solution"> How can temperature affect the formation of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-formation-of-a-solution-be-exothermic-or-endothermic"> How can the formation of a solution be exothermic or endothermic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-formation-of-a-solution-involve-energy"> How does the formation of a solution involve energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-heat-formation-of-solution"> How do you find heat of formation of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factor-promotes-the-formation-of-solutions"> Which factors promote the formation of solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/which-two-processes-are-at-equilibrium-in-a-saturated-sugar-solution"> Which two processes are at equilibrium in a saturated sugar solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutes-lower-the-freezing-point"> Why do solutes lower the freezing point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-solution-formation-require-energy"> Why does solution formation require energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutes-dissolve-in-solvents"> Why do solutes dissolve in solvents? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-solvent-dissolves-silicone"> What solvent dissolves silicone? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/solution-formation---what-happens-when-stuff-dissolves"> See all questions in Solution Formation </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4139 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many gallons of a 3% salt solution must be mixed with 50 gallons of a 7% solution to obtain a 5% solution?

a9a5daf8-6ddd-11ea-8bed-ccda262736ce

https://socratic.org/questions/how-many-joules-of-heat-are-required-to-melt-a-55-0-g-ice-cube-at-0-c

18345.25 joules

start physical_unit 12 13 heat_energy j qc_end physical_unit 12 13 10 11 mass qc_end physical_unit 12 13 15 16 temperature qc_end c_other melt qc_end end

[{"type":"physical unit","value":"Required heat [OF] ice cube [IN] joules"}]

[{"type":"physical unit","value":"18345.25 joules"}]

[{"type":"physical unit","value":"Mass [OF] ice cube [=] \\pu{55.0 g}"},{"type":"physical unit","value":"Temperature [OF] ice cube [=] \\pu{0 ℃}"},{"type":"other","value":"melt"}]

<h1 class="questionTitle" itemprop="name">How many joules of heat are required to melt a 55.0-g ice cube at 0°C? </h1>

18345.25 joules

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to be able to answer this question, you must know the value of water's <em><a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of fusion</em>, <mathjax>#DeltaH_"fus"#</mathjax>, which is listed as </p> <blockquote> <p><mathjax>#DeltaH_"fus" = "33.55 J g"^(-1)#</mathjax></p> </blockquote> <p><a href="https://en.wikipedia.org/wiki/Enthalpy_of_fusion" rel="nofollow" target="_blank">https://en.wikipedia.org/wiki/Enthalpy_of_fusion</a></p> <p>Now, a substance's enthalpy of fusion tells you how much heat is needed in order to convert <mathjax>#"1 g"#</mathjax> of said substance from <em>solid</em> at its melting point to <em>liquid</em> at its melting point. </p> <p>In water's case, an enthalpy of fusion equal to <mathjax>#"333.55 J g"^(-1)#</mathjax> tells you that <mathjax>#"1 g"#</mathjax> of ice at <mathjax>#0^@"C"#</mathjax> can be converted to <mathjax>#"1 g"#</mathjax> of liquid water at <mathjax>#0^@"C"#</mathjax> by supplying <mathjax>#"333.55 J"#</mathjax> of heat. </p> <p>Your ice cube has a mass of <mathjax>#"55.0 g"#</mathjax>, which means that it will require</p> <blockquote> <p><mathjax>#55.0 color(red)(cancel(color(black)("g"))) * overbrace("333.55 J"/(1color(red)(cancel(color(black)("g")))))^(color(blue)( = DeltaH_"fus")) = "18,345.25 J"#</mathjax></p> </blockquote> <p>Rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of the ice cube, the answer will be </p> <blockquote> <p><mathjax>#"heat needed" = color(green)(|bar(ul(color(white)(a/a)color(black)("18,300 J")color(white)(a/a)|)))#</mathjax></p> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"18,300 J"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to be able to answer this question, you must know the value of water's <em><a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of fusion</em>, <mathjax>#DeltaH_"fus"#</mathjax>, which is listed as </p> <blockquote> <p><mathjax>#DeltaH_"fus" = "33.55 J g"^(-1)#</mathjax></p> </blockquote> <p><a href="https://en.wikipedia.org/wiki/Enthalpy_of_fusion" rel="nofollow" target="_blank">https://en.wikipedia.org/wiki/Enthalpy_of_fusion</a></p> <p>Now, a substance's enthalpy of fusion tells you how much heat is needed in order to convert <mathjax>#"1 g"#</mathjax> of said substance from <em>solid</em> at its melting point to <em>liquid</em> at its melting point. </p> <p>In water's case, an enthalpy of fusion equal to <mathjax>#"333.55 J g"^(-1)#</mathjax> tells you that <mathjax>#"1 g"#</mathjax> of ice at <mathjax>#0^@"C"#</mathjax> can be converted to <mathjax>#"1 g"#</mathjax> of liquid water at <mathjax>#0^@"C"#</mathjax> by supplying <mathjax>#"333.55 J"#</mathjax> of heat. </p> <p>Your ice cube has a mass of <mathjax>#"55.0 g"#</mathjax>, which means that it will require</p> <blockquote> <p><mathjax>#55.0 color(red)(cancel(color(black)("g"))) * overbrace("333.55 J"/(1color(red)(cancel(color(black)("g")))))^(color(blue)( = DeltaH_"fus")) = "18,345.25 J"#</mathjax></p> </blockquote> <p>Rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of the ice cube, the answer will be </p> <blockquote> <p><mathjax>#"heat needed" = color(green)(|bar(ul(color(white)(a/a)color(black)("18,300 J")color(white)(a/a)|)))#</mathjax></p> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many joules of heat are required to melt a 55.0-g ice cube at 0°C? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/thermochemistry-of-phase-changes" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry of Phase Changes</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="288337" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-15T11:57:46" itemprop="dateCreated"> Jul 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"18,300 J"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to be able to answer this question, you must know the value of water's <em><a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of fusion</em>, <mathjax>#DeltaH_"fus"#</mathjax>, which is listed as </p> <blockquote> <p><mathjax>#DeltaH_"fus" = "33.55 J g"^(-1)#</mathjax></p> </blockquote> <p><a href="https://en.wikipedia.org/wiki/Enthalpy_of_fusion" rel="nofollow" target="_blank">https://en.wikipedia.org/wiki/Enthalpy_of_fusion</a></p> <p>Now, a substance's enthalpy of fusion tells you how much heat is needed in order to convert <mathjax>#"1 g"#</mathjax> of said substance from <em>solid</em> at its melting point to <em>liquid</em> at its melting point. </p> <p>In water's case, an enthalpy of fusion equal to <mathjax>#"333.55 J g"^(-1)#</mathjax> tells you that <mathjax>#"1 g"#</mathjax> of ice at <mathjax>#0^@"C"#</mathjax> can be converted to <mathjax>#"1 g"#</mathjax> of liquid water at <mathjax>#0^@"C"#</mathjax> by supplying <mathjax>#"333.55 J"#</mathjax> of heat. </p> <p>Your ice cube has a mass of <mathjax>#"55.0 g"#</mathjax>, which means that it will require</p> <blockquote> <p><mathjax>#55.0 color(red)(cancel(color(black)("g"))) * overbrace("333.55 J"/(1color(red)(cancel(color(black)("g")))))^(color(blue)( = DeltaH_"fus")) = "18,345.25 J"#</mathjax></p> </blockquote> <p>Rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of the ice cube, the answer will be </p> <blockquote> <p><mathjax>#"heat needed" = color(green)(|bar(ul(color(white)(a/a)color(black)("18,300 J")color(white)(a/a)|)))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/288337" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-much-energy-is-required-to-heat-100-g-of-ice-at-0-00-degrees-celsius-to-wate"> How much energy is required to convert 100.g of ice at 0.00 °C to water vapor at 100.00 °C? 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How many joules of heat are required to melt a 55.0-g ice cube at 0°C?

abdd7980-6ddd-11ea-a8eb-ccda262736ce

https://socratic.org/questions/if-120-moles-of-sodium-carbonate-are-mixed-with-calcium-hydroxide-how-many-moles

240.00 moles

start physical_unit 15 16 mole mol qc_end physical_unit 4 5 1 2 mole qc_end substance 9 10 qc_end end

[{"type":"physical unit","value":"Mole [OF] sodium hydroxide [IN] moles"}]

[{"type":"physical unit","value":"240.00 moles"}]

[{"type":"physical unit","value":"Mole [OF] sodium carbonate [=] \\pu{120 moles}"},{"type":"substance name","value":"Calcium hydroxide"}]

<h1 class="questionTitle" itemprop="name">If 120 moles of sodium carbonate are mixed with calcium hydroxide, how many moles of sodium hydroxide are formed? </h1>

240.00 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have not told us the quantity of <mathjax>#"Ca(OH)"_2(aq)#</mathjax> you have. <mathjax>#"Saturated Ca(OH)"_2(aq)#</mathjax>, aka <mathjax>#"lime water"#</mathjax>, does not contain a lot of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>. Anyway, the given equation is stoichiometrically balanced. You have to tell us how much calcium hydroxide was used. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Ca(OH)"_2(aq) + "Na"_2"CO"_3(aq) rarr "CaCO"_3(s)darr+"2NaOH"(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have not told us the quantity of <mathjax>#"Ca(OH)"_2(aq)#</mathjax> you have. <mathjax>#"Saturated Ca(OH)"_2(aq)#</mathjax>, aka <mathjax>#"lime water"#</mathjax>, does not contain a lot of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>. Anyway, the given equation is stoichiometrically balanced. You have to tell us how much calcium hydroxide was used. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If 120 moles of sodium carbonate are mixed with calcium hydroxide, how many moles of sodium hydroxide are formed? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="362095" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-09T08:57:59" itemprop="dateCreated"> Jan 9, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Ca(OH)"_2(aq) + "Na"_2"CO"_3(aq) rarr "CaCO"_3(s)darr+"2NaOH"(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have not told us the quantity of <mathjax>#"Ca(OH)"_2(aq)#</mathjax> you have. <mathjax>#"Saturated Ca(OH)"_2(aq)#</mathjax>, aka <mathjax>#"lime water"#</mathjax>, does not contain a lot of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>. Anyway, the given equation is stoichiometrically balanced. You have to tell us how much calcium hydroxide was used. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/362095" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2806 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

If 120 moles of sodium carbonate are mixed with calcium hydroxide, how many moles of sodium hydroxide are formed?

abb97d98-6ddd-11ea-9049-ccda262736ce

https://socratic.org/questions/how-many-total-atoms-are-represented-by-propanes-chemical-formula

11

start physical_unit 2 3 number none qc_end substance 7 7 qc_end end

[{"type":"physical unit","value":"Number [OF] total atoms"}]

[{"type":"physical unit","value":"11"}]

[{"type":"substance name","value":"Propanes"}]

<h1 class="questionTitle" itemprop="name">How many total atoms are represented by propanes chemical formula? </h1>

11

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I count <mathjax>#"11 atoms"#</mathjax> in a single formula unit: <mathjax>#3xxC#</mathjax>; <mathjax>#8xxH#</mathjax>. How many atoms in <mathjax>#44*g#</mathjax> of <mathjax>#"propane"#</mathjax>?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>In <mathjax>#H_3C-CH_2-CH_3#</mathjax>.............?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I count <mathjax>#"11 atoms"#</mathjax> in a single formula unit: <mathjax>#3xxC#</mathjax>; <mathjax>#8xxH#</mathjax>. How many atoms in <mathjax>#44*g#</mathjax> of <mathjax>#"propane"#</mathjax>?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many total atoms are represented by propanes chemical formula? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/determining-formula-and-molar-masses" itemprop="url"> <span class="breadcrumb" itemprop="title">Determining Formula</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="385991" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-03T17:54:16" itemprop="dateCreated"> Mar 3, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>In <mathjax>#H_3C-CH_2-CH_3#</mathjax>.............?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I count <mathjax>#"11 atoms"#</mathjax> in a single formula unit: <mathjax>#3xxC#</mathjax>; <mathjax>#8xxH#</mathjax>. How many atoms in <mathjax>#44*g#</mathjax> of <mathjax>#"propane"#</mathjax>?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/385991" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-possible-to-find-a-molecular-formula-from-molar-mass"> Is it possible to find a molecular formula from molar mass? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5368e0cc02bf34779e175781"> Question #75781 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-when-determining-formulas"> What are some common mistakes students make when determining formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-an-acid"> How can I determine the formula of an acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-chemical-formula-of-a-product"> How can I determine the chemical formula of a product? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-empirical-formula-of-a-compound"> How can I determine the empirical formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-a-hydrate"> How can I determine the formula of a hydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-empirical-formula-indicate"> What does the empirical formula indicate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-molecule-with-molecular-weight-of-180-18-g-mol-is-analyzed-and-found-to-contai"> A molecule with molecular weight of 180.18 g/mol is analyzed and found to contain 40.00% carbon,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-i-need-to-know-the-number-of-moles-of-each-element-to-determine-the-formula-o"> Do I need to know the number of moles of each element to determine the formula of the compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/determining-formula-and-molar-masses"> See all questions in Determining Formula </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1613 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many total atoms are represented by propanes chemical formula?

aaac912e-6ddd-11ea-b7b7-ccda262736ce

https://socratic.org/questions/53f9286102bf34373a32b6da

2 KMnO4 + 5 Na2C2O4 + 8 H2SO4 -> K2SO4 + 5 Na2SO4 + MnSO4 + 10 CO2 + 8 H2O

start chemical_equation qc_end chemical_equation 7 21 qc_end end

[{"type":"other","value":"Chemical Equation [OF] "}]

[{"type":"chemical equation","value":"2 KMnO4 + 5 Na2C2O4 + 8 H2SO4 -> K2SO4 + 5 Na2SO4 + MnSO4 + 10 CO2 + 8 H2O"}]

[{"type":"chemical equation","value":"KMnO4 + Na2C2O4 + H2SO4 -> K2SO4 + Na2SO4 + MnSO4 + CO2 + H2O"}]

<h1 class="questionTitle" itemprop="name">How do you balance this chemical equation? #"KMnO"_4 + "Na"_2"C"_2"O"_4 + "H"_2"SO"_4 → "K"_2"SO"_4 + "Na"_2"SO"_4 + "MnSO"_4 + "CO"_2 + "H"_2"O"#</h1>

2 KMnO4 + 5 Na2C2O4 + 8 H2SO4 -> K2SO4 + 5 Na2SO4 + MnSO4 + 10 CO2 + 8 H2O

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>One method is to balance equations by the <a href="http://socratic.org/questions/how-do-you-balance-redox-equations-by-oxidation-number-method">oxidation number method</a>.</p> <blockquote></blockquote> <p><strong>Step 1. Calculate the <a href="http://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> of every atom:</strong></p> <p><mathjax>#stackrelcolor(blue)(+1)("K")stackrelcolor(blue)(+7)("Mn")stackrelcolor(blue)("-2")("O")_4 + stackrelcolor(blue)(+1)("Na")_2stackrelcolor(blue)(+3)("C")_2stackrelcolor(blue)("-2")("O")_4 + stackrelcolor(blue)(+1)("H")_2stackrelcolor(blue)(+6)("S")stackrelcolor(blue)("-2")("O")_4 → stackrelcolor(blue)(+1)("K")_2stackrelcolor(blue)(+6)("S")stackrelcolor(blue)("-2")("O")_4 + stackrelcolor(blue)(+1)("Na")_2stackrelcolor(blue)(+6)("S")stackrelcolor(blue)("-2")("O")_4 + stackrelcolor(blue)(+2)("Mn")stackrelcolor(blue)(+6)("S")stackrelcolor(blue)("-2")("O")_4 + stackrelcolor(blue)(+4)("C")stackrelcolor(blue)("-2")("O")_2 + stackrelcolor(blue)(+1)("H")_2stackrelcolor(blue)("-2")("O")#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Identify the atoms that change oxidation number.</strong></p> <p><mathjax>#"Mn: +7 → +2; Change = -5"#</mathjax><br/> <mathjax>#"C: +3 → +4; Change = +1"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 3. Equalize the changes in oxidation number.</strong></p> <p>You need <mathjax>#"1 atom of Mn"#</mathjax> for every <mathjax>#"5 atoms of C"#</mathjax> or <mathjax>#"2 atoms of Mn"#</mathjax> for every <mathjax>#"10 atoms of C"#</mathjax>. This gives us total changes of <mathjax>#+10#</mathjax> and <mathjax>#"-10"#</mathjax>.</p> <blockquote></blockquote> <p><strong>Step 4. Insert coefficients to get these numbers.</strong></p> <p><mathjax>#color(red)(2)"KMnO"_4 + color(red)(5)"Na"_2"C"_2"O"_4 + "H"_2"SO"_4 → "K"_2"SO"_4 + "Na"_2"SO"_4 + color(red)(2)"MnSO"_4 + color(red)(10)"CO"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 5 Balance <mathjax>#"K"#</mathjax>.</strong></p> <p><mathjax>#color(red)(2)"KMnO"_4 + color(red)(5)"Na"_2"C"_2"O"_4 + "H"_2"SO"_4 → color(blue)(1)"K"_2"SO"_4 + "Na"_2"SO"_4 + color(red)(2)"MnSO"_4 + color(red)(10)"CO"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 6 Balance <mathjax>#"Na"#</mathjax>.</strong></p> <p><mathjax>#color(red)(2)"KMnO"_4 + color(red)(5)"Na"_2"C"_2"O"_4 + "H"_2"SO"_4 → color(blue)(1)"K"_2"SO"_4 + color(orange)(5)"Na"_2"SO"_4 + color(red)(2)"MnSO"_4 + color(red)(10)"CO"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 7. Balance <mathjax>#"S"#</mathjax>.</strong></p> <p><mathjax>#color(red)(2)"KMnO"_4 + color(red)(5)"Na"_2"C"_2"O"_4 + color(olive)(8)"H"_2"SO"_4 → color(blue)(1)"K"_2"SO"_4 + color(orange)(5)"Na"_2"SO"_4 + color(red)(2)"MnSO"_4 + color(red)(10)"CO"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 8. Balance <mathjax>#"O"#</mathjax>.</strong></p> <p><mathjax>#color(red)(2)"KMnO"_4 + color(red)(5)"Na"_2"C"_2"O"_4 + color(olive)(8)"H"_2"SO"_4 → color(blue)(1)"K"_2"SO"_4 + color(orange)(5)"Na"_2"SO"_4 + color(red)(2)"MnSO"_4 + color(red)(10)"CO"_2 + color(brown)(8)"H"_2"O"#</mathjax></p> <blockquote></blockquote> <p>Every substance now has a coefficient, so the equation should be balanced.</p> <blockquote></blockquote> <p><strong>Step 9. Check that all atoms balance.</strong></p> <p><mathjax>#bb"Atom"color(white)(m) bb"Left Hand Side"color(white)(m) bb"Right Hand Side"#</mathjax><br/> <mathjax>#color(white)(m)"K"color(white)(mmmmm) 2 color(white)(mmmmmmmmmm)2#</mathjax><br/> <mathjax>#color(white)(m)"Mn" color(white)(mmmml)2 color(white)(mmmmmmmmmm)2#</mathjax><br/> <mathjax>#color(white)(m)"O"color(white)(mmmmll)60 color(white)(mmmmmmmmml)60#</mathjax><br/> <mathjax>#color(white)(m)"Na" color(white)(mmmm)10 color(white)(mmmmmmmmml)10#</mathjax><br/> <mathjax>#color(white)(m)"C"color(white)(mmmmll)10 color(white)(mmmmmmmmml)10#</mathjax><br/> <mathjax>#color(white)(m)"H"color(white)(mmmmll)16color(white)(mmmmmmmmml)16#</mathjax><br/> <mathjax>#color(white)(m)"S"color(white)(mmmmml)8color(white)(mmmmmmmmmm)8#</mathjax></p> <blockquote></blockquote> <p>The balanced equation is</p> <p><mathjax>#"2KMnO"_4 + "5Na"_2"C"_2"O"_4 + "8H"_2"SO"_4 → "K"_2"SO"_4 + "5Na"_2"SO"_4 + "MnSO"_4 + "10CO"_2 + "8H"_2"O"#</mathjax></p> <blockquote></blockquote> <p>Here's a video on balancing equations by the oxidation number method.</p> <p> <iframe src="https://www.youtube.com/embed/mvbPtQfAfUQ?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#color(blue)("2KMnO"_4 + "5Na"_2"C"_2"O"_4 + "8H"_2"SO"_4 → "K"_2"SO"_4 + "5Na"_2"SO"_4 + "MnSO"_4 + "10CO"_2 + "8H"_2"O")#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>One method is to balance equations by the <a href="http://socratic.org/questions/how-do-you-balance-redox-equations-by-oxidation-number-method">oxidation number method</a>.</p> <blockquote></blockquote> <p><strong>Step 1. Calculate the <a href="http://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> of every atom:</strong></p> <p><mathjax>#stackrelcolor(blue)(+1)("K")stackrelcolor(blue)(+7)("Mn")stackrelcolor(blue)("-2")("O")_4 + stackrelcolor(blue)(+1)("Na")_2stackrelcolor(blue)(+3)("C")_2stackrelcolor(blue)("-2")("O")_4 + stackrelcolor(blue)(+1)("H")_2stackrelcolor(blue)(+6)("S")stackrelcolor(blue)("-2")("O")_4 → stackrelcolor(blue)(+1)("K")_2stackrelcolor(blue)(+6)("S")stackrelcolor(blue)("-2")("O")_4 + stackrelcolor(blue)(+1)("Na")_2stackrelcolor(blue)(+6)("S")stackrelcolor(blue)("-2")("O")_4 + stackrelcolor(blue)(+2)("Mn")stackrelcolor(blue)(+6)("S")stackrelcolor(blue)("-2")("O")_4 + stackrelcolor(blue)(+4)("C")stackrelcolor(blue)("-2")("O")_2 + stackrelcolor(blue)(+1)("H")_2stackrelcolor(blue)("-2")("O")#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Identify the atoms that change oxidation number.</strong></p> <p><mathjax>#"Mn: +7 → +2; Change = -5"#</mathjax><br/> <mathjax>#"C: +3 → +4; Change = +1"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 3. Equalize the changes in oxidation number.</strong></p> <p>You need <mathjax>#"1 atom of Mn"#</mathjax> for every <mathjax>#"5 atoms of C"#</mathjax> or <mathjax>#"2 atoms of Mn"#</mathjax> for every <mathjax>#"10 atoms of C"#</mathjax>. This gives us total changes of <mathjax>#+10#</mathjax> and <mathjax>#"-10"#</mathjax>.</p> <blockquote></blockquote> <p><strong>Step 4. Insert coefficients to get these numbers.</strong></p> <p><mathjax>#color(red)(2)"KMnO"_4 + color(red)(5)"Na"_2"C"_2"O"_4 + "H"_2"SO"_4 → "K"_2"SO"_4 + "Na"_2"SO"_4 + color(red)(2)"MnSO"_4 + color(red)(10)"CO"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 5 Balance <mathjax>#"K"#</mathjax>.</strong></p> <p><mathjax>#color(red)(2)"KMnO"_4 + color(red)(5)"Na"_2"C"_2"O"_4 + "H"_2"SO"_4 → color(blue)(1)"K"_2"SO"_4 + "Na"_2"SO"_4 + color(red)(2)"MnSO"_4 + color(red)(10)"CO"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 6 Balance <mathjax>#"Na"#</mathjax>.</strong></p> <p><mathjax>#color(red)(2)"KMnO"_4 + color(red)(5)"Na"_2"C"_2"O"_4 + "H"_2"SO"_4 → color(blue)(1)"K"_2"SO"_4 + color(orange)(5)"Na"_2"SO"_4 + color(red)(2)"MnSO"_4 + color(red)(10)"CO"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 7. Balance <mathjax>#"S"#</mathjax>.</strong></p> <p><mathjax>#color(red)(2)"KMnO"_4 + color(red)(5)"Na"_2"C"_2"O"_4 + color(olive)(8)"H"_2"SO"_4 → color(blue)(1)"K"_2"SO"_4 + color(orange)(5)"Na"_2"SO"_4 + color(red)(2)"MnSO"_4 + color(red)(10)"CO"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 8. Balance <mathjax>#"O"#</mathjax>.</strong></p> <p><mathjax>#color(red)(2)"KMnO"_4 + color(red)(5)"Na"_2"C"_2"O"_4 + color(olive)(8)"H"_2"SO"_4 → color(blue)(1)"K"_2"SO"_4 + color(orange)(5)"Na"_2"SO"_4 + color(red)(2)"MnSO"_4 + color(red)(10)"CO"_2 + color(brown)(8)"H"_2"O"#</mathjax></p> <blockquote></blockquote> <p>Every substance now has a coefficient, so the equation should be balanced.</p> <blockquote></blockquote> <p><strong>Step 9. Check that all atoms balance.</strong></p> <p><mathjax>#bb"Atom"color(white)(m) bb"Left Hand Side"color(white)(m) bb"Right Hand Side"#</mathjax><br/> <mathjax>#color(white)(m)"K"color(white)(mmmmm) 2 color(white)(mmmmmmmmmm)2#</mathjax><br/> <mathjax>#color(white)(m)"Mn" color(white)(mmmml)2 color(white)(mmmmmmmmmm)2#</mathjax><br/> <mathjax>#color(white)(m)"O"color(white)(mmmmll)60 color(white)(mmmmmmmmml)60#</mathjax><br/> <mathjax>#color(white)(m)"Na" color(white)(mmmm)10 color(white)(mmmmmmmmml)10#</mathjax><br/> <mathjax>#color(white)(m)"C"color(white)(mmmmll)10 color(white)(mmmmmmmmml)10#</mathjax><br/> <mathjax>#color(white)(m)"H"color(white)(mmmmll)16color(white)(mmmmmmmmml)16#</mathjax><br/> <mathjax>#color(white)(m)"S"color(white)(mmmmml)8color(white)(mmmmmmmmmm)8#</mathjax></p> <blockquote></blockquote> <p>The balanced equation is</p> <p><mathjax>#"2KMnO"_4 + "5Na"_2"C"_2"O"_4 + "8H"_2"SO"_4 → "K"_2"SO"_4 + "5Na"_2"SO"_4 + "MnSO"_4 + "10CO"_2 + "8H"_2"O"#</mathjax></p> <blockquote></blockquote> <p>Here's a video on balancing equations by the oxidation number method.</p> <p> <iframe src="https://www.youtube.com/embed/mvbPtQfAfUQ?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you balance this chemical equation? #"KMnO"_4 + "Na"_2"C"_2"O"_4 + "H"_2"SO"_4 → "K"_2"SO"_4 + "Na"_2"SO"_4 + "MnSO"_4 + "CO"_2 + "H"_2"O"#</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/balancing-redox-equations-using-the-oxidation-number-method" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Redox Equations Using the Oxidation Number Method</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="108203" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2014-08-24T14:51:21" itemprop="dateCreated"> Aug 24, 2014 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#color(blue)("2KMnO"_4 + "5Na"_2"C"_2"O"_4 + "8H"_2"SO"_4 → "K"_2"SO"_4 + "5Na"_2"SO"_4 + "MnSO"_4 + "10CO"_2 + "8H"_2"O")#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>One method is to balance equations by the <a href="http://socratic.org/questions/how-do-you-balance-redox-equations-by-oxidation-number-method">oxidation number method</a>.</p> <blockquote></blockquote> <p><strong>Step 1. Calculate the <a href="http://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> of every atom:</strong></p> <p><mathjax>#stackrelcolor(blue)(+1)("K")stackrelcolor(blue)(+7)("Mn")stackrelcolor(blue)("-2")("O")_4 + stackrelcolor(blue)(+1)("Na")_2stackrelcolor(blue)(+3)("C")_2stackrelcolor(blue)("-2")("O")_4 + stackrelcolor(blue)(+1)("H")_2stackrelcolor(blue)(+6)("S")stackrelcolor(blue)("-2")("O")_4 → stackrelcolor(blue)(+1)("K")_2stackrelcolor(blue)(+6)("S")stackrelcolor(blue)("-2")("O")_4 + stackrelcolor(blue)(+1)("Na")_2stackrelcolor(blue)(+6)("S")stackrelcolor(blue)("-2")("O")_4 + stackrelcolor(blue)(+2)("Mn")stackrelcolor(blue)(+6)("S")stackrelcolor(blue)("-2")("O")_4 + stackrelcolor(blue)(+4)("C")stackrelcolor(blue)("-2")("O")_2 + stackrelcolor(blue)(+1)("H")_2stackrelcolor(blue)("-2")("O")#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Identify the atoms that change oxidation number.</strong></p> <p><mathjax>#"Mn: +7 → +2; Change = -5"#</mathjax><br/> <mathjax>#"C: +3 → +4; Change = +1"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 3. Equalize the changes in oxidation number.</strong></p> <p>You need <mathjax>#"1 atom of Mn"#</mathjax> for every <mathjax>#"5 atoms of C"#</mathjax> or <mathjax>#"2 atoms of Mn"#</mathjax> for every <mathjax>#"10 atoms of C"#</mathjax>. This gives us total changes of <mathjax>#+10#</mathjax> and <mathjax>#"-10"#</mathjax>.</p> <blockquote></blockquote> <p><strong>Step 4. Insert coefficients to get these numbers.</strong></p> <p><mathjax>#color(red)(2)"KMnO"_4 + color(red)(5)"Na"_2"C"_2"O"_4 + "H"_2"SO"_4 → "K"_2"SO"_4 + "Na"_2"SO"_4 + color(red)(2)"MnSO"_4 + color(red)(10)"CO"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 5 Balance <mathjax>#"K"#</mathjax>.</strong></p> <p><mathjax>#color(red)(2)"KMnO"_4 + color(red)(5)"Na"_2"C"_2"O"_4 + "H"_2"SO"_4 → color(blue)(1)"K"_2"SO"_4 + "Na"_2"SO"_4 + color(red)(2)"MnSO"_4 + color(red)(10)"CO"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 6 Balance <mathjax>#"Na"#</mathjax>.</strong></p> <p><mathjax>#color(red)(2)"KMnO"_4 + color(red)(5)"Na"_2"C"_2"O"_4 + "H"_2"SO"_4 → color(blue)(1)"K"_2"SO"_4 + color(orange)(5)"Na"_2"SO"_4 + color(red)(2)"MnSO"_4 + color(red)(10)"CO"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 7. Balance <mathjax>#"S"#</mathjax>.</strong></p> <p><mathjax>#color(red)(2)"KMnO"_4 + color(red)(5)"Na"_2"C"_2"O"_4 + color(olive)(8)"H"_2"SO"_4 → color(blue)(1)"K"_2"SO"_4 + color(orange)(5)"Na"_2"SO"_4 + color(red)(2)"MnSO"_4 + color(red)(10)"CO"_2 + "H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 8. Balance <mathjax>#"O"#</mathjax>.</strong></p> <p><mathjax>#color(red)(2)"KMnO"_4 + color(red)(5)"Na"_2"C"_2"O"_4 + color(olive)(8)"H"_2"SO"_4 → color(blue)(1)"K"_2"SO"_4 + color(orange)(5)"Na"_2"SO"_4 + color(red)(2)"MnSO"_4 + color(red)(10)"CO"_2 + color(brown)(8)"H"_2"O"#</mathjax></p> <blockquote></blockquote> <p>Every substance now has a coefficient, so the equation should be balanced.</p> <blockquote></blockquote> <p><strong>Step 9. Check that all atoms balance.</strong></p> <p><mathjax>#bb"Atom"color(white)(m) bb"Left Hand Side"color(white)(m) bb"Right Hand Side"#</mathjax><br/> <mathjax>#color(white)(m)"K"color(white)(mmmmm) 2 color(white)(mmmmmmmmmm)2#</mathjax><br/> <mathjax>#color(white)(m)"Mn" color(white)(mmmml)2 color(white)(mmmmmmmmmm)2#</mathjax><br/> <mathjax>#color(white)(m)"O"color(white)(mmmmll)60 color(white)(mmmmmmmmml)60#</mathjax><br/> <mathjax>#color(white)(m)"Na" color(white)(mmmm)10 color(white)(mmmmmmmmml)10#</mathjax><br/> <mathjax>#color(white)(m)"C"color(white)(mmmmll)10 color(white)(mmmmmmmmml)10#</mathjax><br/> <mathjax>#color(white)(m)"H"color(white)(mmmmll)16color(white)(mmmmmmmmml)16#</mathjax><br/> <mathjax>#color(white)(m)"S"color(white)(mmmmml)8color(white)(mmmmmmmmmm)8#</mathjax></p> <blockquote></blockquote> <p>The balanced equation is</p> <p><mathjax>#"2KMnO"_4 + "5Na"_2"C"_2"O"_4 + "8H"_2"SO"_4 → "K"_2"SO"_4 + "5Na"_2"SO"_4 + "MnSO"_4 + "10CO"_2 + "8H"_2"O"#</mathjax></p> <blockquote></blockquote> <p>Here's a video on balancing equations by the oxidation number method.</p> <p> <iframe src="https://www.youtube.com/embed/mvbPtQfAfUQ?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/108203" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-reactions-in-basic-solution"> How do you balance redox reactions in basic solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-equations-by-oxidation-number-method"> How do you balance redox equations by oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-equations-in-acidic-solutions"> How do you balance redox equations in acidic solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-method"> What is the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-balancing-redox-equations-using-the-oxidation-number-m"> What are some examples of balancing redox equations using the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-number-method-useful"> Why is the oxidation number method useful? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-necessary-to-break-the-equation-into-half-reactions-in-the-oxidation-numbe"> Is it necessary to break the equation into half reactions in the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-difference-between-the-oxidation-number-method-and-the-ion-electron-"> What is the difference between the oxidation number method and the ion-electron method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-balance-the-equation-using-the-oxidation-states-method-mno2-al-mn-al2o3"> Can you balance the equation using the oxidation states method MnO2+Al---&gt;Mn+Al2O3? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-this-redox-reaction-using-the-oxidation-number-method-fe2-aq-"> How do you balance this redox reaction using the oxidation number method? Fe2+(aq) + MnO4–(aq)... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/balancing-redox-equations-using-the-oxidation-number-method"> See all questions in Balancing Redox Equations Using the Oxidation Number Method </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 32386 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How do you balance this chemical equation? #"KMnO"_4 + "Na"_2"C"_2"O"_4 + "H"_2"SO"_4 → "K"_2"SO"_4 + "Na"_2"SO"_4 + "MnSO"_4 + "CO"_2 + "H"_2"O"#

abccf3e6-6ddd-11ea-9654-ccda262736ce

https://socratic.org/questions/solid-nacl-is-produced-by-the-reaction-of-metallic-sodium-with-chlorine-gas-how-

Na(s) + 1/2 Cl2(g) -> NaCl(s)

start chemical_equation qc_end chemical_equation 1 1 qc_end substance 8 9 qc_end substance 11 12 qc_end end

[{"type":"other","value":"Chemical Equation [OF] this reaction"}]

[{"type":"chemical equation","value":"Na(s) + 1/2 Cl2(g) -> NaCl(s)"}]

[{"type":"chemical equation","value":"NaCl"},{"type":"substance name","value":"Metallic sodium"},{"type":"substance name","value":"Chlorine gas"}]

<h1 class="questionTitle" itemprop="name">Solid #NaCl# is produced by the reaction of metallic sodium with chlorine gas. How do you write a equation to show this reaction?</h1>

Na(s) + 1/2 Cl2(g) -> NaCl(s)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is this equation balanced? How do you know? How could I remove the half coefficient?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Na(s) + 1/2Cl_2(g) rarr NaCl(s)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is this equation balanced? How do you know? How could I remove the half coefficient?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Solid #NaCl# is produced by the reaction of metallic sodium with chlorine gas. How do you write a equation to show this reaction?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="228895" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-20T13:20:06" itemprop="dateCreated"> Feb 20, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Na(s) + 1/2Cl_2(g) rarr NaCl(s)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is this equation balanced? How do you know? How could I remove the half coefficient?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/228895" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2562 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

Solid #NaCl# is produced by the reaction of metallic sodium with chlorine gas. How do you write a equation to show this reaction?

a957bc64-6ddd-11ea-9316-ccda262736ce

https://socratic.org/questions/at-what-kelvin-temperature-will-a-sample-of-gas-occupy-12-liters-if-the-same-sam

450.00 Kelvin

start physical_unit 6 8 temperature k qc_end physical_unit 6 8 17 18 volume qc_end physical_unit 6 8 10 11 volume qc_end physical_unit 6 8 20 21 temperature qc_end end

[{"type":"physical unit","value":"Temperature2 [OF] the gas sample [IN] Kelvin"}]

[{"type":"physical unit","value":"450.00 Kelvin"}]

[{"type":"physical unit","value":"Volume1 [OF] the gas sample [=] \\pu{8 liters}"},{"type":"physical unit","value":"Volume2 [OF] the gas sample [=] \\pu{12 liters}"},{"type":"physical unit","value":"Temperature1 [OF] the gas sample [=] \\pu{27 ℃}"}]

<h1 class="questionTitle" itemprop="name">At what Kelvin temperature will a sample of gas occupy 12 liters if the same sample occupies 8 liters at 27 ℃?</h1>

450.00 Kelvin

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since the gas it is getting compressed with a change on temperature, we consider that <strong>the pressure is constant</strong>, and of course <strong>the number of mole is constant</strong> (same gas), therefore, from the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> <mathjax>#PV=nRT#</mathjax> we can say:</p> <p><mathjax>#V/T=" constant"#</mathjax></p> <p>Therefore, <mathjax>#(V_1)/(T_1)=(V_2)/(T_2)=&gt;T_1=V_1xx(T_2)/(V_2)#</mathjax></p> <p><mathjax>#=&gt;T_1=12cancel(L)xx(300K)/(8cancel(L))=450K#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#T_1=450K#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since the gas it is getting compressed with a change on temperature, we consider that <strong>the pressure is constant</strong>, and of course <strong>the number of mole is constant</strong> (same gas), therefore, from the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> <mathjax>#PV=nRT#</mathjax> we can say:</p> <p><mathjax>#V/T=" constant"#</mathjax></p> <p>Therefore, <mathjax>#(V_1)/(T_1)=(V_2)/(T_2)=&gt;T_1=V_1xx(T_2)/(V_2)#</mathjax></p> <p><mathjax>#=&gt;T_1=12cancel(L)xx(300K)/(8cancel(L))=450K#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">At what Kelvin temperature will a sample of gas occupy 12 liters if the same sample occupies 8 liters at 27 ℃?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="236515" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-07T21:04:11" itemprop="dateCreated"> Mar 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#T_1=450K#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since the gas it is getting compressed with a change on temperature, we consider that <strong>the pressure is constant</strong>, and of course <strong>the number of mole is constant</strong> (same gas), therefore, from the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> <mathjax>#PV=nRT#</mathjax> we can say:</p> <p><mathjax>#V/T=" constant"#</mathjax></p> <p>Therefore, <mathjax>#(V_1)/(T_1)=(V_2)/(T_2)=&gt;T_1=V_1xx(T_2)/(V_2)#</mathjax></p> <p><mathjax>#=&gt;T_1=12cancel(L)xx(300K)/(8cancel(L))=450K#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/236515" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? 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At what Kelvin temperature will a sample of gas occupy 12 liters if the same sample occupies 8 liters at 27 ℃?

a9d9fa2e-6ddd-11ea-a7ba-ccda262736ce

https://socratic.org/questions/calculate-the-volume-of-chlorine-at-120-kpa-and-20-celsius-degrees-which-is-requ

372 m^3

start physical_unit 4 4 volume m^3 qc_end physical_unit 18 18 16 17 mass qc_end substance 20 21 qc_end end

[{"type":"physical unit","value":"Volume [OF] chlorine [IN] m^3"}]

[{"type":"physical unit","value":"372 m^3"}]

[{"type":"physical unit","value":"Pressure [OF] the reaction [=] \\pu{120 kPa}"},{"type":"physical unit","value":"Temperature [OF] the reaction [=] \\pu{20 ℃}"},{"type":"physical unit","value":"Mass [OF] iron [=] \\pu{7 kg}"},{"type":"substance name","value":"Ferric chloride"}]

<h1 class="questionTitle" itemprop="name">Calculate the volume of chlorine at 120 kPa and 20 °C that is required to convert 7 kg iron to ferric chloride?</h1>

372 m^3

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The balanced equation is </p> <p><mathjax>#"2Fe + 3Cl"_2 → "2FeCl"_3#</mathjax></p> <blockquote></blockquote> <p><strong>1. Calculate the moles of Fe</strong></p> <p><mathjax>#"Moles of Fe" = 7000 color(red)(cancel(color(black)("g Fe"))) × "1 mol Fe"/(55.84 color(red)(cancel(color(black)("g Fe")))) = "125.4 mol Fe"#</mathjax></p> <blockquote></blockquote> <p><strong>2. Calculate moles of <mathjax>#"Cl"_2#</mathjax></strong></p> <p><mathjax>#"Moles of Cl"_2 = 125.4 color(red)(cancel(color(black)("mol Fe"))) × ("3 mol Cl"_2)/(2 color(red)(cancel(color(black)("mol Fe")))) = "188.0 mol Cl"_2"#</mathjax></p> <blockquote></blockquote> <p><strong>3. Calculate the volume of <mathjax>#"Cl"_2#</mathjax></strong></p> <p>We can use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a>:</p> <blockquote> <p><mathjax>#color(blue)(|bar(ul(color(white)(a/a)PV = nRT color(white)(a/a)|)))" "#</mathjax></p> </blockquote> <p>Rearrangement gives us</p> <p><mathjax>#V = (nRT)/P#</mathjax></p> <blockquote></blockquote> <p>Your data are:</p> <p>n = <mathjax>#"188.0 mol"#</mathjax>; <mathjax>#color(white)(mmmmmmmmmll)R "= 8.314 kPa·L·K"^"-1""mol"^"-1"#</mathjax>;</p> <p><mathjax>#T = "(20 + 273.15) K = 293.15 K"#</mathjax>; <mathjax>#P = "120 kPa"#</mathjax></p> <blockquote></blockquote> <p>∴ <mathjax>#V = (188.0 color(red)(cancel(color(black)("mol"))) × 8.314 color(red)(cancel(color(black)("kPa")))·"L"·color(red)(cancel(color(black)("K"^"-1""mol"^"-1"))) × 293.15 color(red)(cancel(color(black)("K"))))/(120 color(red)(cancel(color(black)("kPa")))) = "3720 L" = "372 m"^3#</mathjax></p> <p>The volume of chlorine is <mathjax>#"372 m"^3#</mathjax>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of chlorine is <mathjax>#"372 m"^3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The balanced equation is </p> <p><mathjax>#"2Fe + 3Cl"_2 → "2FeCl"_3#</mathjax></p> <blockquote></blockquote> <p><strong>1. Calculate the moles of Fe</strong></p> <p><mathjax>#"Moles of Fe" = 7000 color(red)(cancel(color(black)("g Fe"))) × "1 mol Fe"/(55.84 color(red)(cancel(color(black)("g Fe")))) = "125.4 mol Fe"#</mathjax></p> <blockquote></blockquote> <p><strong>2. Calculate moles of <mathjax>#"Cl"_2#</mathjax></strong></p> <p><mathjax>#"Moles of Cl"_2 = 125.4 color(red)(cancel(color(black)("mol Fe"))) × ("3 mol Cl"_2)/(2 color(red)(cancel(color(black)("mol Fe")))) = "188.0 mol Cl"_2"#</mathjax></p> <blockquote></blockquote> <p><strong>3. Calculate the volume of <mathjax>#"Cl"_2#</mathjax></strong></p> <p>We can use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a>:</p> <blockquote> <p><mathjax>#color(blue)(|bar(ul(color(white)(a/a)PV = nRT color(white)(a/a)|)))" "#</mathjax></p> </blockquote> <p>Rearrangement gives us</p> <p><mathjax>#V = (nRT)/P#</mathjax></p> <blockquote></blockquote> <p>Your data are:</p> <p>n = <mathjax>#"188.0 mol"#</mathjax>; <mathjax>#color(white)(mmmmmmmmmll)R "= 8.314 kPa·L·K"^"-1""mol"^"-1"#</mathjax>;</p> <p><mathjax>#T = "(20 + 273.15) K = 293.15 K"#</mathjax>; <mathjax>#P = "120 kPa"#</mathjax></p> <blockquote></blockquote> <p>∴ <mathjax>#V = (188.0 color(red)(cancel(color(black)("mol"))) × 8.314 color(red)(cancel(color(black)("kPa")))·"L"·color(red)(cancel(color(black)("K"^"-1""mol"^"-1"))) × 293.15 color(red)(cancel(color(black)("K"))))/(120 color(red)(cancel(color(black)("kPa")))) = "3720 L" = "372 m"^3#</mathjax></p> <p>The volume of chlorine is <mathjax>#"372 m"^3#</mathjax>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Calculate the volume of chlorine at 120 kPa and 20 °C that is required to convert 7 kg iron to ferric chloride?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/equation-stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Equation Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="267795" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-20T15:15:13" itemprop="dateCreated"> May 20, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of chlorine is <mathjax>#"372 m"^3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The balanced equation is </p> <p><mathjax>#"2Fe + 3Cl"_2 → "2FeCl"_3#</mathjax></p> <blockquote></blockquote> <p><strong>1. Calculate the moles of Fe</strong></p> <p><mathjax>#"Moles of Fe" = 7000 color(red)(cancel(color(black)("g Fe"))) × "1 mol Fe"/(55.84 color(red)(cancel(color(black)("g Fe")))) = "125.4 mol Fe"#</mathjax></p> <blockquote></blockquote> <p><strong>2. Calculate moles of <mathjax>#"Cl"_2#</mathjax></strong></p> <p><mathjax>#"Moles of Cl"_2 = 125.4 color(red)(cancel(color(black)("mol Fe"))) × ("3 mol Cl"_2)/(2 color(red)(cancel(color(black)("mol Fe")))) = "188.0 mol Cl"_2"#</mathjax></p> <blockquote></blockquote> <p><strong>3. Calculate the volume of <mathjax>#"Cl"_2#</mathjax></strong></p> <p>We can use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a>:</p> <blockquote> <p><mathjax>#color(blue)(|bar(ul(color(white)(a/a)PV = nRT color(white)(a/a)|)))" "#</mathjax></p> </blockquote> <p>Rearrangement gives us</p> <p><mathjax>#V = (nRT)/P#</mathjax></p> <blockquote></blockquote> <p>Your data are:</p> <p>n = <mathjax>#"188.0 mol"#</mathjax>; <mathjax>#color(white)(mmmmmmmmmll)R "= 8.314 kPa·L·K"^"-1""mol"^"-1"#</mathjax>;</p> <p><mathjax>#T = "(20 + 273.15) K = 293.15 K"#</mathjax>; <mathjax>#P = "120 kPa"#</mathjax></p> <blockquote></blockquote> <p>∴ <mathjax>#V = (188.0 color(red)(cancel(color(black)("mol"))) × 8.314 color(red)(cancel(color(black)("kPa")))·"L"·color(red)(cancel(color(black)("K"^"-1""mol"^"-1"))) × 293.15 color(red)(cancel(color(black)("K"))))/(120 color(red)(cancel(color(black)("kPa")))) = "3720 L" = "372 m"^3#</mathjax></p> <p>The volume of chlorine is <mathjax>#"372 m"^3#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/267795" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4171602bf3469588dc36e"> What are the types of stoichiometry examples, with examples? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4171802bf3469570e2e82"> Question #e2e82 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668a402bf34573b4e66fb"> What mass of carbon dioxide can 1.00 kg of lithium oxide absorb? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-stoichiometry-practice-problem"> What is an example of a stoichiometry practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-balanced-equation-practice-problem"> What is an example of a balanced equation practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-a-chemical-equation"> How can I balance a chemical equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-stoichiometry-be-used"> How can stoichiometry be used? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-reactants-to-products"> How do stoichiometric ratios relate reactants to products? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-gas-stoichiometry-differ-from-stoichiometry-of-solids-and-liquids"> How does gas stoichiometry differ from stoichiometry of solids and liquids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-stoichiometry-relate-to-the-law-of-conservation"> How does stoichiometry relate to the law of conservation? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/equation-stoichiometry"> See all questions in Equation Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1640 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

Calculate the volume of chlorine at 120 kPa and 20 °C that is required to convert 7 kg iron to ferric chloride?

ac7aeb19-6ddd-11ea-b8a8-ccda262736ce

https://socratic.org/questions/what-is-the-concentration-of-hydrogen-ions-in-a-solution-of-ph-4-0

1.00 × 10^(-4) M

start physical_unit 5 6 concentration mol/l qc_end physical_unit 9 9 13 13 ph qc_end end

[{"type":"physical unit","value":"Concentration [OF] hydrogen ions [IN] M"}]

[{"type":"physical unit","value":"1.00 × 10^(-4) M"}]

[{"type":"physical unit","value":"pH [OF] the solution [=] \\pu{4.0}"}]

<h1 class="questionTitle" itemprop="name">What is the concentration of hydrogen ions in a solution of pH = 4.0?</h1>

1.00 × 10^(-4) M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"pH" = -log("concentration of H"^+)#</mathjax></p> <p><mathjax>#or, 10^-"pH" = "concentration of H"^+#</mathjax></p> <p>From the given info</p> <p><mathjax>#"pH"#</mathjax> = 4</p> <p><mathjax>#therefore 10^-4 = 0.0001#</mathjax></p> <p><mathjax>#"concentration of H"^+ = "0.0001M"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"concentration of H"^+ = "0.0001M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"pH" = -log("concentration of H"^+)#</mathjax></p> <p><mathjax>#or, 10^-"pH" = "concentration of H"^+#</mathjax></p> <p>From the given info</p> <p><mathjax>#"pH"#</mathjax> = 4</p> <p><mathjax>#therefore 10^-4 = 0.0001#</mathjax></p> <p><mathjax>#"concentration of H"^+ = "0.0001M"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the concentration of hydrogen ions in a solution of pH = 4.0?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="440989" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/samriddha"><img alt="" class="" src="https://profilepictures.socratic.org/3bMcXdwZTLqpsJaquExz_Shinjuku.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/samriddha"> Professor Sam </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-17T11:37:10" itemprop="dateCreated"> Jun 17, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"concentration of H"^+ = "0.0001M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"pH" = -log("concentration of H"^+)#</mathjax></p> <p><mathjax>#or, 10^-"pH" = "concentration of H"^+#</mathjax></p> <p>From the given info</p> <p><mathjax>#"pH"#</mathjax> = 4</p> <p><mathjax>#therefore 10^-4 = 0.0001#</mathjax></p> <p><mathjax>#"concentration of H"^+ = "0.0001M"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/440989" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? 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What is the concentration of hydrogen ions in a solution of pH = 4.0?

aa20d54a-6ddd-11ea-acf4-ccda262736ce

https://socratic.org/questions/5592bf64581e2a452d72e879

45.42 L

start physical_unit 10 11 volume l qc_end physical_unit 10 11 7 8 mole qc_end c_other STP qc_end end

[{"type":"physical unit","value":"Volume [OF] chlorine gas [IN] L"}]

[{"type":"physical unit","value":"45.42 L"}]

[{"type":"physical unit","value":"Mole [OF] chlorine gas [=] \\pu{2 mols}"},{"type":"other","value":"STP"}]

<h1 class="questionTitle" itemprop="name">At STP, what is the volume of #"2 mols"# of chlorine gas?</h1>

45.42 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The cool thing about STP conditions is that <em>1 mole</em> of any ideal gas occupies exactly <strong>22.7 L</strong> - this is known as the <a href="http://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas at STP</a>.</p> <p>STP conditions imply a temperature of <strong>273.15 K</strong> and a pressure of <strong>100 kPa</strong>. When tose conditions are met, 1 mole of any ideal gas will have a volume of 22.7 L. </p> <p>So, if 1 mole occupies a volume of 22.7 L, 2 moles will occupy a volume twice as big. </p> <p><mathjax>#2cancel("moles") * "22.7 L"/(1cancel("mole")) = "45.4 L"#</mathjax></p> <p>Likewise, <strong>0.5</strong> moles will occupy half the volume 1 mole occupies.</p> <p><mathjax>#0.5cancel("moles") * "22.7 L"/(1cancel("mole")) = "11.35 L"#</mathjax></p> <p><strong>SIDE NOTE</strong> <em>Many online sources and textbooks still list the old STP conditions of 273.15 K and 1 atm. Under these conditions, the <a href="http://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas</a> is actually 22.4 L.</em></p> <p><em>If your teacher or textbook still uses that value, simply redo the calculation using 22.4 L instead of 22.7 L.</em></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><strong>45.4 L</strong>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The cool thing about STP conditions is that <em>1 mole</em> of any ideal gas occupies exactly <strong>22.7 L</strong> - this is known as the <a href="http://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas at STP</a>.</p> <p>STP conditions imply a temperature of <strong>273.15 K</strong> and a pressure of <strong>100 kPa</strong>. When tose conditions are met, 1 mole of any ideal gas will have a volume of 22.7 L. </p> <p>So, if 1 mole occupies a volume of 22.7 L, 2 moles will occupy a volume twice as big. </p> <p><mathjax>#2cancel("moles") * "22.7 L"/(1cancel("mole")) = "45.4 L"#</mathjax></p> <p>Likewise, <strong>0.5</strong> moles will occupy half the volume 1 mole occupies.</p> <p><mathjax>#0.5cancel("moles") * "22.7 L"/(1cancel("mole")) = "11.35 L"#</mathjax></p> <p><strong>SIDE NOTE</strong> <em>Many online sources and textbooks still list the old STP conditions of 273.15 K and 1 atm. Under these conditions, the <a href="http://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas</a> is actually 22.4 L.</em></p> <p><em>If your teacher or textbook still uses that value, simply redo the calculation using 22.4 L instead of 22.7 L.</em></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">At STP, what is the volume of #"2 mols"# of chlorine gas?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="155552" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-06-30T16:34:45" itemprop="dateCreated"> Jun 30, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><strong>45.4 L</strong>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The cool thing about STP conditions is that <em>1 mole</em> of any ideal gas occupies exactly <strong>22.7 L</strong> - this is known as the <a href="http://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas at STP</a>.</p> <p>STP conditions imply a temperature of <strong>273.15 K</strong> and a pressure of <strong>100 kPa</strong>. When tose conditions are met, 1 mole of any ideal gas will have a volume of 22.7 L. </p> <p>So, if 1 mole occupies a volume of 22.7 L, 2 moles will occupy a volume twice as big. </p> <p><mathjax>#2cancel("moles") * "22.7 L"/(1cancel("mole")) = "45.4 L"#</mathjax></p> <p>Likewise, <strong>0.5</strong> moles will occupy half the volume 1 mole occupies.</p> <p><mathjax>#0.5cancel("moles") * "22.7 L"/(1cancel("mole")) = "11.35 L"#</mathjax></p> <p><strong>SIDE NOTE</strong> <em>Many online sources and textbooks still list the old STP conditions of 273.15 K and 1 atm. Under these conditions, the <a href="http://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas</a> is actually 22.4 L.</em></p> <p><em>If your teacher or textbook still uses that value, simply redo the calculation using 22.4 L instead of 22.7 L.</em></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/155552" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="155558" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/truong-son-n"><img alt="" class="" src="https://profilepictures.socratic.org/07k4plnQfmnmzMuesQzw_14844-1449381920.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/truong-son-n"> Truong-Son N. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-06-30T17:16:51" itemprop="dateCreated"> Jun 30, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><p>I'm going to assume the ideal case, but if you want to know a more accurate value, I'll show that below.</p> <p>Using the <strong><a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a></strong>:</p> <blockquote> <p><mathjax>#PV = nRT#</mathjax></p> </blockquote> <p>At STP, <mathjax>#P = "1 bar"#</mathjax>, <mathjax>#R = "0.083145 L"*"bar""/mol"cdot"K"#</mathjax>, and <mathjax>#T = "273.15 K"#</mathjax>. Therefore, with <mathjax>#n = "2 mol"#</mathjax>:</p> <blockquote> <p><mathjax>#V = (nRT)/P = [(2 cancel("mol"))(("0.083145 L"cdotcancel("bar"))/(cancel("mol"*"K")))(273.15 cancel("K"))]/(1 cancel("bar"))#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#color(blue)("45.422 L")#</mathjax></p> </blockquote> <hr/> <p>A more accurate answer would be <mathjax>#color(blue)("44.968 L")#</mathjax>, using the <strong>van der Waals</strong> equation of state:</p> <blockquote> <p><mathjax>#P = (RT)/(barV - b) - a/(barV^2)#</mathjax></p> </blockquote> <p>In this case, we'd need to know <a href="http://www2.ucdsb.on.ca/tiss/stretton/database/van_der_waals_constants.html" rel="nofollow">the constants</a> <mathjax>#a#</mathjax> and <mathjax>#b#</mathjax> for <mathjax>#Cl_2#</mathjax> specifically.</p> <blockquote> <p><mathjax>#a = "6.343 bar/L"^2"mol"^2#</mathjax></p> <p><mathjax>#b = "0.05422 L/mol"#</mathjax></p> </blockquote> <p>Now we need to solve for <mathjax>#barV#</mathjax>:</p> <blockquote> <p><mathjax>#P = (RTbarV^2 - a(barV - b))/((barV - b)barV^2)#</mathjax><br/> (cross-multiply)</p> <p><mathjax>#PbarV^2(barV - b)= RTbarV^2 - abarV + ab#</mathjax><br/> (subtract through, multiply by denominator)</p> <p><mathjax>#PbarV^3 - bPbarV^2= RTbarV^2 - abarV + ab#</mathjax><br/> (distribute)</p> <p><mathjax>#PbarV^3 - bPbarV^2 - RTbarV^2 + abarV - ab = 0#</mathjax><br/> (move things around)</p> <p><mathjax>#PbarV^3 - (bP+RT)barV^2 + abarV - ab = 0#</mathjax><br/> (factor)</p> </blockquote> <p>And now to solve this, one way I know of is to use the <strong>Newton-Raphson approximation method</strong> to approach the answer from above. </p> <p>Let:</p> <blockquote> <p><mathjax>#P = color(green)(A) = color(green)("1 bar")#</mathjax></p> <p><mathjax>#bP + RT = color(green)(B) = ("0.05422 L/mol")("1 bar") + ("0.083145 L"cdot"bar/mol"cdot"K")("273.15 K") = color(green)("22.76527675 L"cdot"bar/mol")#</mathjax></p> <p><mathjax>#a = color(green)(C) = color(green)("6.343 bar/L"^2"mol"^2)#</mathjax></p> <p><mathjax>#ab = color(green)(D) = "6.343 bar/L"^2"mol"^2 cdot "0.05422 L/mol" = color(green)("0.34391746 bar/L"cdot"mol"^3)#</mathjax></p> <p><mathjax>#barV = X#</mathjax> in <mathjax>#"L/mol"#</mathjax></p> </blockquote> <p>Now we have:</p> <blockquote> <p><mathjax>#AX^3 - BX^2 + CX - D = 0#</mathjax></p> </blockquote> <p>What you can do is use the following formula for the Newton-Raphson method:</p> <blockquote> <p><mathjax>#color(darkblue)(X_"new" = X_"old" - (f(x))/(f'(x)))#</mathjax></p> <p><mathjax>#f(x) = AX^3 - BX^2 + CX - D#</mathjax><br/> <mathjax>#f'(x) = 3AX^2 - 2BX + C#</mathjax></p> </blockquote> <p>Thus:</p> <blockquote> <p><mathjax>#color(darkred)(X_"new" = X_"old" - (AX^3 - BX^2 + CX - D)/(3AX^2 - 2BX + C))#</mathjax></p> </blockquote> <p>Now what you may want to do is store a number into each variable in this equation, because you'll have to keep recalling a long expression. The coefficients are given above. </p> <p>For <mathjax>#X_"old"#</mathjax>, just pick a number and guess. I would pick either something less than <mathjax>#1#</mathjax>, something near <mathjax>#1#</mathjax>, or something between <mathjax>#2#</mathjax> and <mathjax>#30#</mathjax>. This will give you three answers.</p> <p>Then, if you use a TI calculator, write this into your calculator to store variables:</p> <blockquote> <p><mathjax>#2-&gt;X#</mathjax><br/> <mathjax>#1 -&gt;A#</mathjax><br/> etc.</p> </blockquote> <p>and this to solve:</p> <blockquote> <p><mathjax>#(X - ((AX^3 - BX^2 + CX - D)/(3AX^2 - 2BX + C))) -&gt; X#</mathjax></p> </blockquote> <p>and then press Enter until your answer stops changing. </p> <ol> <li> <p>Using <mathjax>#X_"old" = 2#</mathjax>, I got <mathjax>#X_"new" = 0.2078358407#</mathjax> after 7 times pressing Enter. Knowing that, I would try something under <mathjax>#0.207#</mathjax>.</p> </li> <li> <p>Using <mathjax>#X_"old" = 0.1#</mathjax>, I got <mathjax>#X_"new" = 0.0735975286#</mathjax> after 6 times pressing Enter. Having tried something near <mathjax>#1#</mathjax> and something below <mathjax>#1#</mathjax>, let's try something high.</p> </li> <li> <p>Using <mathjax>#X_"old" = 20#</mathjax>, I got <mathjax>#X_"new" = 22.48384338#</mathjax> after 6 times pressing Enter.</p> </li> </ol> <p>This means then that the three answers I got are:</p> <blockquote> <p><mathjax>#"0.2078358407 L/mol"#</mathjax></p> <p><mathjax>#"0.0735975286 L/mol"#</mathjax></p> <p><mathjax>#"22.48384338 L/mol"#</mathjax></p> </blockquote> <p>The lowest answer corresponds to the volume of 1 mol of liquid chlorine. The highest answer is the volume of 1 mol of gaseous chlorine. The middle answer is nonphysical, so we're not going to use it. This looks something like this:</p> <p><img alt="https://www.e-education.psu.edu/" src="https://useruploads.socratic.org/6uzk3xhQdisaekq7w2XR_figure1001.gif"/> </p> <p>If you see the horizontal line below "Two-Phase", that is the intersection between the three answers. The liquid is on the left, and the gas is on the right.</p> <p>Thus, to get the <strong>more realistic result</strong> for gaseous chlorine:</p> <blockquote> <p><mathjax>#"22.48384338 L/mol" * "2 mol" = 44.96768676 -&gt; color(blue)("44.968 L")#</mathjax></p> <p>compared to the ideal case of <mathjax>#color(blue)("45.422 L")#</mathjax>.</p> </blockquote> <p>Checking its <strong>compressibility factor</strong>:</p> <blockquote> <p><mathjax>#Z = (PbarV)/(RT) = ((1)(22.48384338))/((0.083145)(273.15)) = 0.989995#</mathjax></p> </blockquote> <p>Since <mathjax>#Z &lt; 1#</mathjax>, <mathjax>#Cl_2#</mathjax> is easier to compress in real life than its ideal version, so its volume at STP <strong>should</strong> be smaller in real life than in the ideal case, which we got.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/155558" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 17998 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

At STP, what is the volume of #"2 mols"# of chlorine gas?

acac2e68-6ddd-11ea-8825-ccda262736ce

https://socratic.org/questions/a-sample-of-a-gas-occupies-1-40-10-3-ml-at-25-c-and-760-mmhg-what-volume-will-it

2.80 L

start physical_unit 4 4 volume l qc_end physical_unit 4 4 6 9 volume qc_end physical_unit 4 4 11 12 temperature qc_end physical_unit 4 4 14 15 pressure qc_end physical_unit 4 4 26 27 pressure qc_end c_other constant_temperature qc_end end

[{"type":"physical unit","value":"Volume2 [OF] the gas sample [IN] L"}]

[{"type":"physical unit","value":"2.80 L"}]

[{"type":"physical unit","value":"Volume1 [OF] the gas sample [=] \\pu{1.40 × 10^3 mL}"},{"type":"physical unit","value":"Temperature1 [OF] the gas sample [=] \\pu{25 ℃}"},{"type":"physical unit","value":"Pressure1 [OF] the gas sample [=] \\pu{760 mmHg}"},{"type":"physical unit","value":"Pressure2 [OF] the gas sample [=] \\pu{380 mmHg}"},{"type":"other","value":"ConstantTemperature"}]

<h1 class="questionTitle" itemprop="name">A sample of a gas occupies #1.40 * 10^3# mL at 25°C and 760 mmHg. What volume will it occupy at the same temperature and 380 mmHg?</h1>

2.80 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>On its initial state, the gas <br/> - occupies <mathjax>#1.4L#</mathjax><br/> - is on a system of <mathjax>#298.15k#</mathjax>, and<br/> - <mathjax>#1 atm#</mathjax></p> <p>And on its second state,<br/> - <mathjax>#x L#</mathjax><br/> - <mathjax>#298.15K#</mathjax><br/> - <mathjax>#380/760 atm#</mathjax></p> <p><mathjax>#(P_0V_0)/T_0 = (PV)/T#</mathjax>,</p> <p>Solve for V.</p> <p><mathjax>#V = 2.8L#</mathjax></p> <p>The answer is obtainable through <a href="http://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a> - when temperature is held constant, there exists an inverse correlation factor between the state functions of pressure and volume.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V = 2.8L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>On its initial state, the gas <br/> - occupies <mathjax>#1.4L#</mathjax><br/> - is on a system of <mathjax>#298.15k#</mathjax>, and<br/> - <mathjax>#1 atm#</mathjax></p> <p>And on its second state,<br/> - <mathjax>#x L#</mathjax><br/> - <mathjax>#298.15K#</mathjax><br/> - <mathjax>#380/760 atm#</mathjax></p> <p><mathjax>#(P_0V_0)/T_0 = (PV)/T#</mathjax>,</p> <p>Solve for V.</p> <p><mathjax>#V = 2.8L#</mathjax></p> <p>The answer is obtainable through <a href="http://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a> - when temperature is held constant, there exists an inverse correlation factor between the state functions of pressure and volume.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A sample of a gas occupies #1.40 * 10^3# mL at 25°C and 760 mmHg. What volume will it occupy at the same temperature and 380 mmHg?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/boyle-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Boyle's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="206118" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/james-e"><img alt="" class="" src="https://graph.facebook.com/10204921285063135/picture?height=50&amp;width=50" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/james-e"> Mark Keanu James E. Exconde </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-31T09:49:32" itemprop="dateCreated"> Dec 31, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V = 2.8L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>On its initial state, the gas <br/> - occupies <mathjax>#1.4L#</mathjax><br/> - is on a system of <mathjax>#298.15k#</mathjax>, and<br/> - <mathjax>#1 atm#</mathjax></p> <p>And on its second state,<br/> - <mathjax>#x L#</mathjax><br/> - <mathjax>#298.15K#</mathjax><br/> - <mathjax>#380/760 atm#</mathjax></p> <p><mathjax>#(P_0V_0)/T_0 = (PV)/T#</mathjax>,</p> <p>Solve for V.</p> <p><mathjax>#V = 2.8L#</mathjax></p> <p>The answer is obtainable through <a href="http://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a> - when temperature is held constant, there exists an inverse correlation factor between the state functions of pressure and volume.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/206118" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-graph-boyles-law"> How do you graph Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-functional-groups-are-found-in-lipids"> What functional groups are found in lipids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-k-constant-in-boyle-s-law"> Why is k constant in Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-graph-curved-1"> Why is Boyle's law graph curved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-an-inverse-relationship-2"> Why is Boyle's law an inverse relationship? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-40-0-l-tank-of-ammonia-has-a-pressure-of-8-00-atm-calculate-the-volume-of-the-"> A 40.0 L tank of ammonia has a pressure of 8.00 atm. 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A sample of a gas occupies #1.40 * 10^3# mL at 25°C and 760 mmHg. What volume will it occupy at the same temperature and 380 mmHg?

acac5de2-6ddd-11ea-a505-ccda262736ce

https://socratic.org/questions/the-volume-of-a-bicycle-tire-is-1-35-liters-and-the-manufacturer-recommends-a-ti

10.83 L

start physical_unit 36 36 volume l qc_end physical_unit 22 24 7 8 volume qc_end physical_unit 22 24 17 18 pressure qc_end physical_unit 22 24 31 32 temperature qc_end c_other STP qc_end end

[{"type":"physical unit","value":"Volume [OF] air [IN] L"}]

[{"type":"physical unit","value":"10.83 L"}]

[{"type":"physical unit","value":"Volume [OF] the bicycle tire [=] \\pu{1.35 liters}"},{"type":"physical unit","value":"Pressure [OF] the bicycle tire [=] \\pu{8.5 atm}"},{"type":"physical unit","value":"Temperature [OF] the bicycle tire [=] \\pu{20.0 ℃}"},{"type":"other","value":"STP"}]

<h1 class="questionTitle" itemprop="name">The volume of a bicycle tire is 1.35 liters and the manufacturer recommends a tire pressure of 8.5 atm. If you want the bicycle tire to have the correct pressure at 20.0°C, what volume of air is required at STP?</h1>

10.83 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to figure out what volume of gas held at <strong>STP</strong> conditions is needed in order for the tire to have a volume of <mathjax>#"1.35 L"#</mathjax> at <mathjax>#"8.5 atm"#</mathjax> and <mathjax>#20.0^@"C"#</mathjax>.</p> <p>Since <em>pressure</em>, <em>temperature</em>, and <em>volume change</em>, you can use the <strong><a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a></strong> equation to find the volume of gas at STP.</p> <p>The <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a> equation looks like this</p> <blockquote> <p><mathjax>#color(blue)(|bar(ul((P_1V_1)/T_1 = (P_2V_2)/T_2))|)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P_1#</mathjax>, <mathjax>#V_1#</mathjax>, <mathjax>#T_1#</mathjax> - the pressure, volume, and absolute temperature of the gas at an initial state<br/> <mathjax>#P_2#</mathjax>, <mathjax>#V_2#</mathjax>, <mathjax>#T_2#</mathjax> - the pressure, volume, and absolute temperature of a gas at a final state</p> <p>So, <strong>STP</strong> conditions are defined as a pressure of <mathjax>#"100 kPa"#</mathjax> and a temperature of <mathjax>#0^@"C"#</mathjax>. To convert the pressure to <em>atm</em> and the temperature to <em>Kelvin</em>, use the conversion factors</p> <blockquote> <p><mathjax>#"1 atm " = " 101.325 kPa"#</mathjax></p> <p><mathjax>#T["K"] = t[""^@"C"] + 273.15#</mathjax></p> </blockquote> <p>You're starting with the gas under STP conditions, then changing its temperature to <mathjax>#20.0^@"C"#</mathjax> and its pressure to <mathjax>#"8.5 atm"#</mathjax>. </p> <p>Rearrange the combined gas law equation to solve for <mathjax>#V_1#</mathjax></p> <blockquote> <p><mathjax>#(P_1V_1)/T_1 = (P_2V_2)/T_2 implies V_1 = P_2/P_1 * T_1/T_2 * V_2#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#V_1 = (8.5 color(red)(cancel(color(black)("atm"))))/(100/101.325color(red)(cancel(color(black)("atm")))) * ((273.15 + 0)color(red)(cancel(color(black)("K"))))/((273.15 + 20.0)color(red)(cancel(color(black)("K")))) * "1.35 L"#</mathjax></p> <p><mathjax>#V_1 = "10.834 L"#</mathjax></p> </blockquote> <p>Rounded to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the pressure of the tire at <mathjax>#20.0^@"C"#</mathjax>, the answer will be</p> <blockquote> <p><mathjax>#V = color(green)(|bar(ul("11 L"))|)#</mathjax></p> </blockquote> <p><strong>SIDE NOTE</strong> <em>STP conditions are often given as a pressure of</em> <mathjax>#"1 atm"#</mathjax> <em>and a temperature of</em> <mathjax>#0^@"C"#</mathjax>, <em>so if that is how STP conditions were defined ti you, simply redo the calculations using a pressure of</em> <mathjax>#"1 atm"#</mathjax> <em>instead of a pressure of</em> <mathjax>#"100 kPa"#</mathjax>.</p> <p><em>Rounded to two sig figs, the answer will come out to be the same,</em> <mathjax>#"11 L"#</mathjax>. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"11 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to figure out what volume of gas held at <strong>STP</strong> conditions is needed in order for the tire to have a volume of <mathjax>#"1.35 L"#</mathjax> at <mathjax>#"8.5 atm"#</mathjax> and <mathjax>#20.0^@"C"#</mathjax>.</p> <p>Since <em>pressure</em>, <em>temperature</em>, and <em>volume change</em>, you can use the <strong><a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a></strong> equation to find the volume of gas at STP.</p> <p>The <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a> equation looks like this</p> <blockquote> <p><mathjax>#color(blue)(|bar(ul((P_1V_1)/T_1 = (P_2V_2)/T_2))|)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P_1#</mathjax>, <mathjax>#V_1#</mathjax>, <mathjax>#T_1#</mathjax> - the pressure, volume, and absolute temperature of the gas at an initial state<br/> <mathjax>#P_2#</mathjax>, <mathjax>#V_2#</mathjax>, <mathjax>#T_2#</mathjax> - the pressure, volume, and absolute temperature of a gas at a final state</p> <p>So, <strong>STP</strong> conditions are defined as a pressure of <mathjax>#"100 kPa"#</mathjax> and a temperature of <mathjax>#0^@"C"#</mathjax>. To convert the pressure to <em>atm</em> and the temperature to <em>Kelvin</em>, use the conversion factors</p> <blockquote> <p><mathjax>#"1 atm " = " 101.325 kPa"#</mathjax></p> <p><mathjax>#T["K"] = t[""^@"C"] + 273.15#</mathjax></p> </blockquote> <p>You're starting with the gas under STP conditions, then changing its temperature to <mathjax>#20.0^@"C"#</mathjax> and its pressure to <mathjax>#"8.5 atm"#</mathjax>. </p> <p>Rearrange the combined gas law equation to solve for <mathjax>#V_1#</mathjax></p> <blockquote> <p><mathjax>#(P_1V_1)/T_1 = (P_2V_2)/T_2 implies V_1 = P_2/P_1 * T_1/T_2 * V_2#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#V_1 = (8.5 color(red)(cancel(color(black)("atm"))))/(100/101.325color(red)(cancel(color(black)("atm")))) * ((273.15 + 0)color(red)(cancel(color(black)("K"))))/((273.15 + 20.0)color(red)(cancel(color(black)("K")))) * "1.35 L"#</mathjax></p> <p><mathjax>#V_1 = "10.834 L"#</mathjax></p> </blockquote> <p>Rounded to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the pressure of the tire at <mathjax>#20.0^@"C"#</mathjax>, the answer will be</p> <blockquote> <p><mathjax>#V = color(green)(|bar(ul("11 L"))|)#</mathjax></p> </blockquote> <p><strong>SIDE NOTE</strong> <em>STP conditions are often given as a pressure of</em> <mathjax>#"1 atm"#</mathjax> <em>and a temperature of</em> <mathjax>#0^@"C"#</mathjax>, <em>so if that is how STP conditions were defined ti you, simply redo the calculations using a pressure of</em> <mathjax>#"1 atm"#</mathjax> <em>instead of a pressure of</em> <mathjax>#"100 kPa"#</mathjax>.</p> <p><em>Rounded to two sig figs, the answer will come out to be the same,</em> <mathjax>#"11 L"#</mathjax>. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">The volume of a bicycle tire is 1.35 liters and the manufacturer recommends a tire pressure of 8.5 atm. If you want the bicycle tire to have the correct pressure at 20.0°C, what volume of air is required at STP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/combined-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Combined Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="235421" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-05T14:55:16" itemprop="dateCreated"> Mar 5, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"11 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to figure out what volume of gas held at <strong>STP</strong> conditions is needed in order for the tire to have a volume of <mathjax>#"1.35 L"#</mathjax> at <mathjax>#"8.5 atm"#</mathjax> and <mathjax>#20.0^@"C"#</mathjax>.</p> <p>Since <em>pressure</em>, <em>temperature</em>, and <em>volume change</em>, you can use the <strong><a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a></strong> equation to find the volume of gas at STP.</p> <p>The <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a> equation looks like this</p> <blockquote> <p><mathjax>#color(blue)(|bar(ul((P_1V_1)/T_1 = (P_2V_2)/T_2))|)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P_1#</mathjax>, <mathjax>#V_1#</mathjax>, <mathjax>#T_1#</mathjax> - the pressure, volume, and absolute temperature of the gas at an initial state<br/> <mathjax>#P_2#</mathjax>, <mathjax>#V_2#</mathjax>, <mathjax>#T_2#</mathjax> - the pressure, volume, and absolute temperature of a gas at a final state</p> <p>So, <strong>STP</strong> conditions are defined as a pressure of <mathjax>#"100 kPa"#</mathjax> and a temperature of <mathjax>#0^@"C"#</mathjax>. To convert the pressure to <em>atm</em> and the temperature to <em>Kelvin</em>, use the conversion factors</p> <blockquote> <p><mathjax>#"1 atm " = " 101.325 kPa"#</mathjax></p> <p><mathjax>#T["K"] = t[""^@"C"] + 273.15#</mathjax></p> </blockquote> <p>You're starting with the gas under STP conditions, then changing its temperature to <mathjax>#20.0^@"C"#</mathjax> and its pressure to <mathjax>#"8.5 atm"#</mathjax>. </p> <p>Rearrange the combined gas law equation to solve for <mathjax>#V_1#</mathjax></p> <blockquote> <p><mathjax>#(P_1V_1)/T_1 = (P_2V_2)/T_2 implies V_1 = P_2/P_1 * T_1/T_2 * V_2#</mathjax></p> </blockquote> <p>Plug in your values to get</p> <blockquote> <p><mathjax>#V_1 = (8.5 color(red)(cancel(color(black)("atm"))))/(100/101.325color(red)(cancel(color(black)("atm")))) * ((273.15 + 0)color(red)(cancel(color(black)("K"))))/((273.15 + 20.0)color(red)(cancel(color(black)("K")))) * "1.35 L"#</mathjax></p> <p><mathjax>#V_1 = "10.834 L"#</mathjax></p> </blockquote> <p>Rounded to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the pressure of the tire at <mathjax>#20.0^@"C"#</mathjax>, the answer will be</p> <blockquote> <p><mathjax>#V = color(green)(|bar(ul("11 L"))|)#</mathjax></p> </blockquote> <p><strong>SIDE NOTE</strong> <em>STP conditions are often given as a pressure of</em> <mathjax>#"1 atm"#</mathjax> <em>and a temperature of</em> <mathjax>#0^@"C"#</mathjax>, <em>so if that is how STP conditions were defined ti you, simply redo the calculations using a pressure of</em> <mathjax>#"1 atm"#</mathjax> <em>instead of a pressure of</em> <mathjax>#"100 kPa"#</mathjax>.</p> <p><em>Rounded to two sig figs, the answer will come out to be the same,</em> <mathjax>#"11 L"#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/235421" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5345df5f02bf345f71b1c8e8"> Question #1c8e8 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ac3df02bf342f4c3bfabb"> Question #bfabb </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-you-want-to-solve-for-the-volume-of-a-gas-v2-and-p1-is-greater-than-p2-would-"> If you want to solve for the volume of a gas (V2) and P1 is greater than P2, would you expect V2... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-modern-refrigerator-take-advantage-of-the-gas-laws-to-remove-heat-f"> How does the modern refrigerator take advantage of the gas laws to remove heat from a system? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-certain-sample-of-gas-has-a-volume-of-0-452-l-measured-at-87-c-and-0-620-atm-w"> A certain sample of gas has a volume of 0.452 L measured at 87°C and 0.620 atm. 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The volume of a bicycle tire is 1.35 liters and the manufacturer recommends a tire pressure of 8.5 atm. If you want the bicycle tire to have the correct pressure at 20.0°C, what volume of air is required at STP?

a9a5daf9-6ddd-11ea-bfb4-ccda262736ce

https://socratic.org/questions/how-do-you-write-the-chemical-equation-for-the-acid-ionization-equilibrium-of-ac

H3CCOOH(aq) + H2O(l) <=> H3CCOO- + H3O+

start chemical_equation qc_end substance 12 13 qc_end substance 15 15 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the acid-ionization equilibrium"}]

[{"type":"chemical equation","value":"H3CCOOH(aq) + H2O(l) <=> H3CCOO- + H3O+"}]

[{"type":"substance name","value":"acetic acid"},{"type":"substance name","value":"water"}]

<h1 class="questionTitle" itemprop="name">How do you write the chemical equation for the acid-ionization equilibrium of acetic acid in water?</h1>

H3CCOOH(aq) + H2O(l) <=> H3CCOO- + H3O+

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is charge balanced? Is mass balanced? The answer is yes to both questions.</p> <p>We write <mathjax>#"K"_a=(["H"_3"O"^+][""^(-)"OAc"])/(["HOAc"]), ("HOAc"-="HO(O=)CCH"_3)#</mathjax>, and under standard conditions, <mathjax>#"K"_a=1.74xx10^-5#</mathjax>.</p> <p>Please check the value. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"H"_3"CCO"_2"H(aq)" + "H"_2"O(l)" rightleftharpoons"H"_3"CCO"_2^(-) + "H"_3"O"^+#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is charge balanced? Is mass balanced? The answer is yes to both questions.</p> <p>We write <mathjax>#"K"_a=(["H"_3"O"^+][""^(-)"OAc"])/(["HOAc"]), ("HOAc"-="HO(O=)CCH"_3)#</mathjax>, and under standard conditions, <mathjax>#"K"_a=1.74xx10^-5#</mathjax>.</p> <p>Please check the value. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you write the chemical equation for the acid-ionization equilibrium of acetic acid in water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/equilibrium-stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Equilibrium Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="383806" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-27T14:32:22" itemprop="dateCreated"> Feb 27, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"H"_3"CCO"_2"H(aq)" + "H"_2"O(l)" rightleftharpoons"H"_3"CCO"_2^(-) + "H"_3"O"^+#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is charge balanced? Is mass balanced? The answer is yes to both questions.</p> <p>We write <mathjax>#"K"_a=(["H"_3"O"^+][""^(-)"OAc"])/(["HOAc"]), ("HOAc"-="HO(O=)CCH"_3)#</mathjax>, and under standard conditions, <mathjax>#"K"_a=1.74xx10^-5#</mathjax>.</p> <p>Please check the value. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/383806" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-a-sample-of-no-g-11-75-mol-is-placed-in-440-0-l-reaction-vessel-at-882-0-k-"> When a sample of NO(g) (11.75 mol) is placed in 440.0 L reaction vessel at 882.0 K and allowed... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-23-0-g-sample-of-i2-g-is-sealed-in-a-gas-bottle-having-a-volume-of-500-ml-some"> A 23.0 g sample of I2(g) is sealed in a gas bottle having a volume of 500 mL. 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How do you write the chemical equation for the acid-ionization equilibrium of acetic acid in water?

a98f8b64-6ddd-11ea-b36e-ccda262736ce

https://socratic.org/questions/what-volume-of-0-365-n-lithium-hydroxide-is-needed-to-completely-neutralize-27-6

42.39 mL

start physical_unit 5 6 volume ml qc_end physical_unit 5 6 3 4 molarity qc_end c_other OTHER qc_end physical_unit 17 18 12 13 volume qc_end physical_unit 17 18 15 16 molarity qc_end end

[{"type":"physical unit","value":"Volume [OF] lithium hydroxide [IN] mL"}]

[{"type":"physical unit","value":"42.39 mL"}]

[{"type":"physical unit","value":"Molarity [OF] lithium hydroxide [=] \\pu{0.365 M}"},{"type":"other","value":"Completely neutralize."},{"type":"physical unit","value":"Volume [OF] nitric acid [=] \\pu{27.68 mL}"},{"type":"physical unit","value":"Molarity [OF] nitric acid [=] \\pu{0.559 M}"}]

<h1 class="questionTitle" itemprop="name">What volume of 0.365 N lithium hydroxide is needed to completely neutralize 27.68 mL of 0.559 N nitric acid?</h1>

42.39 mL

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Moles of nitric acid?</p> <p><mathjax>#27.68xx10^(-3)cancelLxx0.559*mol*cancel(L^(-1))#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.54xx10^(-2)#</mathjax> <mathjax>#mol#</mathjax>. </p> <p>So we need <mathjax>#(1.54xx10^(-2)*cancel(mol))/(0.365*cancel(mol)*L^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#4.24xx10^(-2)#</mathjax> <mathjax>#L#</mathjax></p> <p>Or <mathjax>#4.24xx10^(-2)#</mathjax> <mathjax>#cancelL#</mathjax> <mathjax>#xx#</mathjax> <mathjax>#1000#</mathjax> <mathjax>#mL#</mathjax> <mathjax>#cancel(L^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#mL#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#LiOH(aq) + HNO_3(aq) rarr H_2O(l) + LiNO_3(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Moles of nitric acid?</p> <p><mathjax>#27.68xx10^(-3)cancelLxx0.559*mol*cancel(L^(-1))#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.54xx10^(-2)#</mathjax> <mathjax>#mol#</mathjax>. </p> <p>So we need <mathjax>#(1.54xx10^(-2)*cancel(mol))/(0.365*cancel(mol)*L^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#4.24xx10^(-2)#</mathjax> <mathjax>#L#</mathjax></p> <p>Or <mathjax>#4.24xx10^(-2)#</mathjax> <mathjax>#cancelL#</mathjax> <mathjax>#xx#</mathjax> <mathjax>#1000#</mathjax> <mathjax>#mL#</mathjax> <mathjax>#cancel(L^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#mL#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What volume of 0.365 N lithium hydroxide is needed to completely neutralize 27.68 mL of 0.559 N nitric acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="207181" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-02T19:50:25" itemprop="dateCreated"> Jan 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#LiOH(aq) + HNO_3(aq) rarr H_2O(l) + LiNO_3(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Moles of nitric acid?</p> <p><mathjax>#27.68xx10^(-3)cancelLxx0.559*mol*cancel(L^(-1))#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.54xx10^(-2)#</mathjax> <mathjax>#mol#</mathjax>. </p> <p>So we need <mathjax>#(1.54xx10^(-2)*cancel(mol))/(0.365*cancel(mol)*L^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#4.24xx10^(-2)#</mathjax> <mathjax>#L#</mathjax></p> <p>Or <mathjax>#4.24xx10^(-2)#</mathjax> <mathjax>#cancelL#</mathjax> <mathjax>#xx#</mathjax> <mathjax>#1000#</mathjax> <mathjax>#mL#</mathjax> <mathjax>#cancel(L^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#mL#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/207181" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -&gt; 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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What volume of 0.365 N lithium hydroxide is needed to completely neutralize 27.68 mL of 0.559 N nitric acid?

abd02776-6ddd-11ea-ba04-ccda262736ce

https://socratic.org/questions/how-do-you-balance-co-oh-3-hno-3-co-no-3-3-h-2o

Co(OH)3 + 3 HNO3 -> Co(NO3)3 + 3 H2O

start chemical_equation qc_end chemical_equation 4 10 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"Co(OH)3 + 3 HNO3 -> Co(NO3)3 + 3 H2O"}]

[{"type":"chemical equation","value":"Co(OH)3 + HNO3 -> Co(NO3)3 + H2O"}]

<h1 class="questionTitle" itemprop="name">How do you balance #Co(OH)_3 + HNO_3 -&gt; Co(NO_3)_3 + H_2O#?</h1>

Co(OH)3 + 3 HNO3 -> Co(NO3)3 + 3 H2O

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You really have to know your complex ions for this one! </p> <p>On the left side of the equation we see, initially, one nitrate group (<mathjax>#NO_3#</mathjax>) On the right, we have three. So that means on the left we need three nitrate groups which means three <mathjax>#HNO_3#</mathjax> (aka nitric acids). </p> <p><mathjax>#Co(OH)_3#</mathjax> + <mathjax>#3HNO_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Co(NO_3)_3#</mathjax> + <mathjax>#H_2O#</mathjax> (not balanced)</p> <p>Now, on the left side of the left side of the unbalanced equation we have six hydrogens, but on the right we only have two. We can fix that by putting a 3 coefficient in front of the water:</p> <p><mathjax>#Co(OH)_3#</mathjax> + <mathjax>#3HNO_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Co(NO_3)_3#</mathjax> + <mathjax>#3H_2O#</mathjax></p> <p>Now we see that all the hydrogens balance out on both sides (six and six), all the nitrate groups balance out (three and three), the cobalt is balanced (one and one), and the oxygen (not counting the oxygen we have with the nitrate groups we already counted!) is also balanced (three and three). </p> <p>Notice what I did here: I treated the nitrate groups as distinct species and balanced them as a whole even though the nitrate group has both nitrogen and oxygen! If you think about it, you will probably realize that I could have done the same thing with the hydroxide groups--water is just a hydroxide group wiht an extra hydrogen.</p> <p>Now try a few and see if treating the complex ions as individual species works for you.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Co(OH)_3#</mathjax> + <mathjax>#3HNO_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Co(NO_3)_3#</mathjax> + <mathjax>#3H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You really have to know your complex ions for this one! </p> <p>On the left side of the equation we see, initially, one nitrate group (<mathjax>#NO_3#</mathjax>) On the right, we have three. So that means on the left we need three nitrate groups which means three <mathjax>#HNO_3#</mathjax> (aka nitric acids). </p> <p><mathjax>#Co(OH)_3#</mathjax> + <mathjax>#3HNO_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Co(NO_3)_3#</mathjax> + <mathjax>#H_2O#</mathjax> (not balanced)</p> <p>Now, on the left side of the left side of the unbalanced equation we have six hydrogens, but on the right we only have two. We can fix that by putting a 3 coefficient in front of the water:</p> <p><mathjax>#Co(OH)_3#</mathjax> + <mathjax>#3HNO_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Co(NO_3)_3#</mathjax> + <mathjax>#3H_2O#</mathjax></p> <p>Now we see that all the hydrogens balance out on both sides (six and six), all the nitrate groups balance out (three and three), the cobalt is balanced (one and one), and the oxygen (not counting the oxygen we have with the nitrate groups we already counted!) is also balanced (three and three). </p> <p>Notice what I did here: I treated the nitrate groups as distinct species and balanced them as a whole even though the nitrate group has both nitrogen and oxygen! If you think about it, you will probably realize that I could have done the same thing with the hydroxide groups--water is just a hydroxide group wiht an extra hydrogen.</p> <p>Now try a few and see if treating the complex ions as individual species works for you.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you balance #Co(OH)_3 + HNO_3 -&gt; Co(NO_3)_3 + H_2O#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="402157" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/andy-wolff"><img alt="" class="" src="https://profilepictures.socratic.org/GbR11eWOTFWVJhdGvFAL_1EhpiCmLTQaUVYrKxoji_Andy%2520Wolff%2520005_r1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/andy-wolff"> Andy Wolff </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-05T19:38:22" itemprop="dateCreated"> Apr 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Co(OH)_3#</mathjax> + <mathjax>#3HNO_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Co(NO_3)_3#</mathjax> + <mathjax>#3H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You really have to know your complex ions for this one! </p> <p>On the left side of the equation we see, initially, one nitrate group (<mathjax>#NO_3#</mathjax>) On the right, we have three. So that means on the left we need three nitrate groups which means three <mathjax>#HNO_3#</mathjax> (aka nitric acids). </p> <p><mathjax>#Co(OH)_3#</mathjax> + <mathjax>#3HNO_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Co(NO_3)_3#</mathjax> + <mathjax>#H_2O#</mathjax> (not balanced)</p> <p>Now, on the left side of the left side of the unbalanced equation we have six hydrogens, but on the right we only have two. We can fix that by putting a 3 coefficient in front of the water:</p> <p><mathjax>#Co(OH)_3#</mathjax> + <mathjax>#3HNO_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Co(NO_3)_3#</mathjax> + <mathjax>#3H_2O#</mathjax></p> <p>Now we see that all the hydrogens balance out on both sides (six and six), all the nitrate groups balance out (three and three), the cobalt is balanced (one and one), and the oxygen (not counting the oxygen we have with the nitrate groups we already counted!) is also balanced (three and three). </p> <p>Notice what I did here: I treated the nitrate groups as distinct species and balanced them as a whole even though the nitrate group has both nitrogen and oxygen! If you think about it, you will probably realize that I could have done the same thing with the hydroxide groups--water is just a hydroxide group wiht an extra hydrogen.</p> <p>Now try a few and see if treating the complex ions as individual species works for you.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/402157" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------&gt; H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -&gt; Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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How do you balance #Co(OH)_3 + HNO_3 -&gt; Co(NO_3)_3 + H_2O#?

a86ccd2c-6ddd-11ea-a87d-ccda262736ce

https://socratic.org/questions/a-sample-of-gas-has-a-volume-of-12-liters-at-0-c-and-380-torr-what-will-be-its-v

6 liters

start physical_unit 1 3 volume l qc_end physical_unit 1 3 8 9 volume qc_end physical_unit 1 3 11 12 temperature qc_end physical_unit 1 3 27 28 pressure qc_end c_other constant_temperature qc_end end

[{"type":"physical unit","value":"Volume2 [OF] the gas sample [IN] liters"}]

[{"type":"physical unit","value":"6 liters"}]

[{"type":"physical unit","value":"Volume1 [OF] the gas sample [=] \\pu{12 liters}"},{"type":"physical unit","value":"Temperature [OF] the gas sample [=] \\pu{0 ℃}"},{"type":"physical unit","value":"Pressure1 [OF] the gas sample [=] \\pu{390 torr}"},{"type":"physical unit","value":"Pressure2 [OF] the gas sample [=] \\pu{760 torr}"},{"type":"other","value":"ConstantTemperature"}]

<h1 class="questionTitle" itemprop="name">A sample of gas has a volume of 12 liters at 0°C and 380 torr. What will be its volume when the pressure is changed to 760 torr at a constant temperature?</h1>

6 liters

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#PV = nRT#</mathjax></p> <p><mathjax>#P#</mathjax> is pressure in atm (760 torr = 1 atm); <mathjax>#V#</mathjax> is volume in liters; <mathjax>#n#</mathjax> is the number of moles; <mathjax>#R#</mathjax> is the constant 0.0821; <mathjax>#T#</mathjax> is temperature in Kelvin. </p> <p><mathjax>#n#</mathjax>, <mathjax>#R#</mathjax>, and <mathjax>#T#</mathjax> are constant; therefore, <mathjax>#P_1V_1 = P_2V_2#</mathjax></p> <p>Convert the torr into atm </p> <p><mathjax>#P_1#</mathjax> = <mathjax>#(380"torr")/(760 "torr" times atm^(-1))#</mathjax> = <mathjax>#0.5#</mathjax> atm <br/> <mathjax>#P_2#</mathjax> = <mathjax>#(760"torr")/(760 "torr" times atm^(-1))#</mathjax> = <mathjax>#1#</mathjax> atm</p> <p>Set the volume </p> <p><mathjax>#V_1#</mathjax> = 12 L<br/> <mathjax>#V_2#</mathjax> = <mathjax>#x#</mathjax> L </p> <p><mathjax>#P_1V_1 = P_2V_2#</mathjax><br/> <mathjax>#0.5"atm" times 12 "L"#</mathjax> = <mathjax>#1"atm" times x "L"#</mathjax><br/> <mathjax>#x#</mathjax>L = 6L</p> <p>The new volume would be 6 liters.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new volume would be 6 liters.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#PV = nRT#</mathjax></p> <p><mathjax>#P#</mathjax> is pressure in atm (760 torr = 1 atm); <mathjax>#V#</mathjax> is volume in liters; <mathjax>#n#</mathjax> is the number of moles; <mathjax>#R#</mathjax> is the constant 0.0821; <mathjax>#T#</mathjax> is temperature in Kelvin. </p> <p><mathjax>#n#</mathjax>, <mathjax>#R#</mathjax>, and <mathjax>#T#</mathjax> are constant; therefore, <mathjax>#P_1V_1 = P_2V_2#</mathjax></p> <p>Convert the torr into atm </p> <p><mathjax>#P_1#</mathjax> = <mathjax>#(380"torr")/(760 "torr" times atm^(-1))#</mathjax> = <mathjax>#0.5#</mathjax> atm <br/> <mathjax>#P_2#</mathjax> = <mathjax>#(760"torr")/(760 "torr" times atm^(-1))#</mathjax> = <mathjax>#1#</mathjax> atm</p> <p>Set the volume </p> <p><mathjax>#V_1#</mathjax> = 12 L<br/> <mathjax>#V_2#</mathjax> = <mathjax>#x#</mathjax> L </p> <p><mathjax>#P_1V_1 = P_2V_2#</mathjax><br/> <mathjax>#0.5"atm" times 12 "L"#</mathjax> = <mathjax>#1"atm" times x "L"#</mathjax><br/> <mathjax>#x#</mathjax>L = 6L</p> <p>The new volume would be 6 liters.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A sample of gas has a volume of 12 liters at 0°C and 380 torr. What will be its volume when the pressure is changed to 760 torr at a constant temperature?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="384389" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kevin-l-7"><img alt="" class="" src="https://lh4.googleusercontent.com/-CG4wcoEOi6I/AAAAAAAAAAI/AAAAAAAAAS0/fMUL1SpRP9Q/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kevin-l-7"> Kevin L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-28T16:47:02" itemprop="dateCreated"> Feb 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new volume would be 6 liters.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#PV = nRT#</mathjax></p> <p><mathjax>#P#</mathjax> is pressure in atm (760 torr = 1 atm); <mathjax>#V#</mathjax> is volume in liters; <mathjax>#n#</mathjax> is the number of moles; <mathjax>#R#</mathjax> is the constant 0.0821; <mathjax>#T#</mathjax> is temperature in Kelvin. </p> <p><mathjax>#n#</mathjax>, <mathjax>#R#</mathjax>, and <mathjax>#T#</mathjax> are constant; therefore, <mathjax>#P_1V_1 = P_2V_2#</mathjax></p> <p>Convert the torr into atm </p> <p><mathjax>#P_1#</mathjax> = <mathjax>#(380"torr")/(760 "torr" times atm^(-1))#</mathjax> = <mathjax>#0.5#</mathjax> atm <br/> <mathjax>#P_2#</mathjax> = <mathjax>#(760"torr")/(760 "torr" times atm^(-1))#</mathjax> = <mathjax>#1#</mathjax> atm</p> <p>Set the volume </p> <p><mathjax>#V_1#</mathjax> = 12 L<br/> <mathjax>#V_2#</mathjax> = <mathjax>#x#</mathjax> L </p> <p><mathjax>#P_1V_1 = P_2V_2#</mathjax><br/> <mathjax>#0.5"atm" times 12 "L"#</mathjax> = <mathjax>#1"atm" times x "L"#</mathjax><br/> <mathjax>#x#</mathjax>L = 6L</p> <p>The new volume would be 6 liters.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/384389" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyles-law-relate-to-breathing"> How does Boyle's law relate to breathing? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/in-avogadro-s-law-what-would-happen-to-v-if-n-is-increased-decreased-and-what-wo"> In Avogadro's Law what would happen to V if N is increased/decreased? 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A sample of gas has a volume of 12 liters at 0°C and 380 torr. What will be its volume when the pressure is changed to 760 torr at a constant temperature?

a912e565-6ddd-11ea-bdee-ccda262736ce

https://socratic.org/questions/how-many-moles-of-nitrogen-n-are-in-85-0-g-of-nitrous-oxide-n-2o

3.86 moles

start physical_unit 5 5 mole mol qc_end physical_unit 13 13 8 9 mass qc_end end

[{"type":"physical unit","value":"Mole [OF] N [IN] moles"}]

[{"type":"physical unit","value":"3.86 moles"}]

[{"type":"physical unit","value":"Mass [OF] N2O [=] \\pu{85.0 g}"}]

<h1 class="questionTitle" itemprop="name">How many moles of nitrogen, N, are in 85.0 g of nitrous oxide, #N_2O#?</h1>

3.86 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of nitrous oxide"=(85*g)/(44.01*g*mol^-1)#</mathjax></p> <p><mathjax>#=1.93*mol#</mathjax>.</p> <p>Since, clearly, there are <mathjax>#"2 moles of nitrogen atoms"#</mathjax> <mathjax>#"per mole of nitrous oxide"#</mathjax>, we simply double the molar quantity of <mathjax>#"nitrous oxide:"#</mathjax></p> <p><mathjax>#1.93*molxx2*mol*N*mol^-1NO=??mol#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Approx. 4 moles"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of nitrous oxide"=(85*g)/(44.01*g*mol^-1)#</mathjax></p> <p><mathjax>#=1.93*mol#</mathjax>.</p> <p>Since, clearly, there are <mathjax>#"2 moles of nitrogen atoms"#</mathjax> <mathjax>#"per mole of nitrous oxide"#</mathjax>, we simply double the molar quantity of <mathjax>#"nitrous oxide:"#</mathjax></p> <p><mathjax>#1.93*molxx2*mol*N*mol^-1NO=??mol#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles of nitrogen, N, are in 85.0 g of nitrous oxide, #N_2O#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="383313" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-26T14:57:39" itemprop="dateCreated"> Feb 26, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Approx. 4 moles"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of nitrous oxide"=(85*g)/(44.01*g*mol^-1)#</mathjax></p> <p><mathjax>#=1.93*mol#</mathjax>.</p> <p>Since, clearly, there are <mathjax>#"2 moles of nitrogen atoms"#</mathjax> <mathjax>#"per mole of nitrous oxide"#</mathjax>, we simply double the molar quantity of <mathjax>#"nitrous oxide:"#</mathjax></p> <p><mathjax>#1.93*molxx2*mol*N*mol^-1NO=??mol#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/383313" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="383319" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/andrew-b-13"><img alt="" class="" src="https://graph.facebook.com/1372625799474311/picture?height=50&amp;width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/andrew-b-13"> Andrew B. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-26T15:12:05" itemprop="dateCreated"> Feb 26, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>3.86 moles of N</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><img alt="enter image source here" src="https://useruploads.socratic.org/pWBqGa1SNaAezZ2JcGCw_Scan_Pic0001.jpg"/> <br/> Source: me</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/383319" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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How many moles of nitrogen, N, are in 85.0 g of nitrous oxide, #N_2O#?

aa3a56ca-6ddd-11ea-94a3-ccda262736ce

https://socratic.org/questions/what-is-the-formula-of-the-conjugate-base-of-hs

S^2-

start chemical_formula qc_end chemical_equation 9 9 qc_end end

[{"type":"other","value":"Chemical Formula [OF] the conjugate base [IN] default"}]

[{"type":"chemical equation","value":"S^2-"}]

[{"type":"chemical equation","value":"HS-"}]

<h1 class="questionTitle" itemprop="name">What is the formula of the conjugate base of HS?</h1>

S^2-

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the conjugate base of any acid, simply remove <mathjax>#H^+#</mathjax> from the acid, and remember to conserve mass and charge. What are the conjugate bases of <mathjax>#HSO_4^-#</mathjax>, <mathjax>#H_2PO_4^-#</mathjax>, and <mathjax>#H_2SO_4#</mathjax>?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The conjugate base of hydrogen sulfide anion, <mathjax>#HS^-#</mathjax>, is sulfide ion, <mathjax>#S^(2-)#</mathjax>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the conjugate base of any acid, simply remove <mathjax>#H^+#</mathjax> from the acid, and remember to conserve mass and charge. What are the conjugate bases of <mathjax>#HSO_4^-#</mathjax>, <mathjax>#H_2PO_4^-#</mathjax>, and <mathjax>#H_2SO_4#</mathjax>?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the formula of the conjugate base of HS?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/conjugate-acids-and-conjugate-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Conjugate Acids and Conjugate Bases</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="201529" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-20T10:06:25" itemprop="dateCreated"> Dec 20, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The conjugate base of hydrogen sulfide anion, <mathjax>#HS^-#</mathjax>, is sulfide ion, <mathjax>#S^(2-)#</mathjax>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the conjugate base of any acid, simply remove <mathjax>#H^+#</mathjax> from the acid, and remember to conserve mass and charge. What are the conjugate bases of <mathjax>#HSO_4^-#</mathjax>, <mathjax>#H_2PO_4^-#</mathjax>, and <mathjax>#H_2SO_4#</mathjax>?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/201529" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-conjugate-base-differ-from-the-acid-hbr"> How does a conjugate base differ from the acid hbr? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-conjugate-base-concentration"> How do you find conjugate base concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-identify-conjugate-acid-base-pairs"> How do you identify conjugate acid base pairs? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-conjugate-base-will-deprotonate-water"> What conjugate base(s) will deprotonate water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-conjugate-acid-of-hco3-"> What is the conjugate acid of #HCO_3^-#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-conjugate-base-of-a-strong-acid-weak"> Why is the conjugate base of a strong acid weak? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-conjugate-base-of-h2so4"> What is the conjugate base of h2so4? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-weak-acids-and-bases-poor-electrical-conductors"> Why are weak acids and bases poor electrical conductors? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-identify-conjugate-acids-and-bases"> How can I identify conjugate acids and bases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-strong-acids-react-in-water"> How do strong acids react in water? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/conjugate-acids-and-conjugate-bases"> See all questions in Conjugate Acids and Conjugate Bases </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 17824 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the formula of the conjugate base of HS?