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a8a751ae-6ddd-11ea-8fe1-ccda262736ce

https://socratic.org/questions/in-an-experiment-to-prepare-a-particular-compound-the-theoreticalye-d-s-65-3-g-a

86.22%

start physical_unit 2 2 percent_yield none qc_end physical_unit 2 2 12 13 theoretical_yield qc_end physical_unit 2 2 19 20 actual_yield qc_end end

[{"type":"physical unit","value":"Percent yield [OF] the experiment"}]

[{"type":"physical unit","value":"86.22%"}]

[{"type":"physical unit","value":"Theoretical yield [OF] the experiment [=] \\pu{65.3 g}"},{"type":"physical unit","value":"Actual yield [OF] the experiment [=] \\pu{56.3 g}"}]

<h1 class="questionTitle" itemprop="name">In an experiment to prepare a particular compound, the theoretical yield s 65.3 g and the actual yield is 56.3 g. What is the percent yield?</h1>

86.22%

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A reaction's <strong><a href="https://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a></strong> is simply the number of grams of a product that you <strong>actually</strong> get <strong>for every</strong> <mathjax>#"100 g"#</mathjax> of said product that you could <strong>theoretically</strong> get. </p> <p>The number of grams of a product that can <strong>theoretically</strong> be obtained by a reaction is called the <strong>theoretical yield</strong>. This value is calculated using <em>stoichimetry</em> and assuming that the raction has a <mathjax>#100%#</mathjax> yield. </p> <p>The number of grams of a product that are <strong>actually</strong> produced by a reaction is called the <strong>actual yield</strong>. This value is detemined experimentally, i.e. by actually doing the reaction. </p> <p>In your case, the reaction has a theoretical yield of <mathjax>#"65.3 g"#</mathjax> and an actual yield of <mathjax>#"56.3 g"#</mathjax>. </p> <p>Since your goal is to determine the number of grams produced <strong>for every</strong> <mathjax>#"100 g"#</mathjax> that could <strong>theoretically</strong> be produced, you can use this ratio as a conversion factor</p> <blockquote> <p><mathjax>#100 color(red)(cancel(color(black)("g theoretically"))) * "56.3 g actually"/(65.3color(red)(cancel(color(black)("g theoretically")))) = "86.2 g actually"#</mathjax></p> </blockquote> <p>Thsi means that the reaction has a <strong>percent yield</strong> of</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("% yield = 86.2%")))#</mathjax></p> <blockquote> <p><em><strong>For every</strong></em> <mathjax>#"100 g"#</mathjax> <em>of product that <strong>could</strong> be produced, the reaction produces</em> <mathjax>#"86.2 g"#</mathjax> <em>of product</em>.</p> </blockquote> </blockquote> <p>The answer is rounded to the <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#86.2%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A reaction's <strong><a href="https://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a></strong> is simply the number of grams of a product that you <strong>actually</strong> get <strong>for every</strong> <mathjax>#"100 g"#</mathjax> of said product that you could <strong>theoretically</strong> get. </p> <p>The number of grams of a product that can <strong>theoretically</strong> be obtained by a reaction is called the <strong>theoretical yield</strong>. This value is calculated using <em>stoichimetry</em> and assuming that the raction has a <mathjax>#100%#</mathjax> yield. </p> <p>The number of grams of a product that are <strong>actually</strong> produced by a reaction is called the <strong>actual yield</strong>. This value is detemined experimentally, i.e. by actually doing the reaction. </p> <p>In your case, the reaction has a theoretical yield of <mathjax>#"65.3 g"#</mathjax> and an actual yield of <mathjax>#"56.3 g"#</mathjax>. </p> <p>Since your goal is to determine the number of grams produced <strong>for every</strong> <mathjax>#"100 g"#</mathjax> that could <strong>theoretically</strong> be produced, you can use this ratio as a conversion factor</p> <blockquote> <p><mathjax>#100 color(red)(cancel(color(black)("g theoretically"))) * "56.3 g actually"/(65.3color(red)(cancel(color(black)("g theoretically")))) = "86.2 g actually"#</mathjax></p> </blockquote> <p>Thsi means that the reaction has a <strong>percent yield</strong> of</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("% yield = 86.2%")))#</mathjax></p> <blockquote> <p><em><strong>For every</strong></em> <mathjax>#"100 g"#</mathjax> <em>of product that <strong>could</strong> be produced, the reaction produces</em> <mathjax>#"86.2 g"#</mathjax> <em>of product</em>.</p> </blockquote> </blockquote> <p>The answer is rounded to the <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">In an experiment to prepare a particular compound, the theoretical yield s 65.3 g and the actual yield is 56.3 g. What is the percent yield?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/percent-yield" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Yield</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="386626" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-05T00:03:23" itemprop="dateCreated"> Mar 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#86.2%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A reaction's <strong><a href="https://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a></strong> is simply the number of grams of a product that you <strong>actually</strong> get <strong>for every</strong> <mathjax>#"100 g"#</mathjax> of said product that you could <strong>theoretically</strong> get. </p> <p>The number of grams of a product that can <strong>theoretically</strong> be obtained by a reaction is called the <strong>theoretical yield</strong>. This value is calculated using <em>stoichimetry</em> and assuming that the raction has a <mathjax>#100%#</mathjax> yield. </p> <p>The number of grams of a product that are <strong>actually</strong> produced by a reaction is called the <strong>actual yield</strong>. This value is detemined experimentally, i.e. by actually doing the reaction. </p> <p>In your case, the reaction has a theoretical yield of <mathjax>#"65.3 g"#</mathjax> and an actual yield of <mathjax>#"56.3 g"#</mathjax>. </p> <p>Since your goal is to determine the number of grams produced <strong>for every</strong> <mathjax>#"100 g"#</mathjax> that could <strong>theoretically</strong> be produced, you can use this ratio as a conversion factor</p> <blockquote> <p><mathjax>#100 color(red)(cancel(color(black)("g theoretically"))) * "56.3 g actually"/(65.3color(red)(cancel(color(black)("g theoretically")))) = "86.2 g actually"#</mathjax></p> </blockquote> <p>Thsi means that the reaction has a <strong>percent yield</strong> of</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("% yield = 86.2%")))#</mathjax></p> <blockquote> <p><em><strong>For every</strong></em> <mathjax>#"100 g"#</mathjax> <em>of product that <strong>could</strong> be produced, the reaction produces</em> <mathjax>#"86.2 g"#</mathjax> <em>of product</em>.</p> </blockquote> </blockquote> <p>The answer is rounded to the <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/386626" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ebd02bf3469570e2e62"> Question #e2e62 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec502bf34694a4fee2e"> Question #fee2e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec902bf34694a4fee32"> Question #fee32 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ece02bf346950519e89"> Question #19e89 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ed302bf34694c8c5bdc"> Question #c5bdc </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ee302bf3469517a1065"> Question #a1065 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-26-0-grams-of-c3h9n-were-reacted-with-46-3"> What would be the limiting reagent if 26.0 grams of C3H9N were reacted with 46.3 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-percent-yield-always-less-than-100"> Is percent yield always less than 100? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-41-9-grams-of-c2h3of-were-reacted-with-61-"> What would be the limiting reagent if 41.9 grams of C2H3OF were reacted with 61.0 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-yield-of-the-following-reaction-if-60-grams-of-caco3-is-heat"> What is the percent yield of the following reaction if 60 grams of CaCO3 is heated to give 15... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/percent-yield"> See all questions in Percent Yield </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1658 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

In an experiment to prepare a particular compound, the theoretical yield s 65.3 g and the actual yield is 56.3 g. What is the percent yield?

a8b1acba-6ddd-11ea-a6f6-ccda262736ce

https://socratic.org/questions/57a2264e11ef6b5bab5733f4

57.75 kPa

start physical_unit 1 1 pressure kpa qc_end physical_unit 1 1 3 4 volume qc_end physical_unit 1 1 7 8 pressure qc_end physical_unit 1 1 16 17 volume qc_end end

[{"type":"physical unit","value":"Pressure2 [OF] the piston [IN] kPa"}]

[{"type":"physical unit","value":"57.75 kPa"}]

[{"type":"physical unit","value":"Volume1 [OF] the piston [=] \\pu{11 L}"},{"type":"physical unit","value":"Pressure1 [OF] the piston [=] \\pu{42 kPa}"},{"type":"physical unit","value":"Volume2 [OF] the piston [=] \\pu{8 L}"}]

<h1 class="questionTitle" itemprop="name">A piston of #11*L# volume under #42*kPa# pressure is compressed to a volume of #8*L#; what is the new pressure?</h1>

57.75 kPa

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P_2=(P_1V_1)/V_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(42*kPaxx11*L)/(8*L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p> <p>This is not a very realistically described experiment. How does the volume decrease? Was the gas originally in a piston whose volume reduced? Well, the reaction does not say so, but the volume reduced somehow. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_1V_1=P_2V_2#</mathjax>. <mathjax>#P_2~=58*kPa#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P_2=(P_1V_1)/V_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(42*kPaxx11*L)/(8*L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p> <p>This is not a very realistically described experiment. How does the volume decrease? Was the gas originally in a piston whose volume reduced? Well, the reaction does not say so, but the volume reduced somehow. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A piston of #11*L# volume under #42*kPa# pressure is compressed to a volume of #8*L#; what is the new pressure?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/boyle-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Boyle's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="295143" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-03T17:24:06" itemprop="dateCreated"> Aug 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_1V_1=P_2V_2#</mathjax>. <mathjax>#P_2~=58*kPa#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P_2=(P_1V_1)/V_2#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(42*kPaxx11*L)/(8*L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p> <p>This is not a very realistically described experiment. How does the volume decrease? Was the gas originally in a piston whose volume reduced? Well, the reaction does not say so, but the volume reduced somehow. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/295143" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-graph-boyles-law"> How do you graph Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-functional-groups-are-found-in-lipids"> What functional groups are found in lipids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-k-constant-in-boyle-s-law"> Why is k constant in Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-graph-curved-1"> Why is Boyle's law graph curved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-an-inverse-relationship-2"> Why is Boyle's law an inverse relationship? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-40-0-l-tank-of-ammonia-has-a-pressure-of-8-00-atm-calculate-the-volume-of-the-"> A 40.0 L tank of ammonia has a pressure of 8.00 atm. Calculate the volume of the ammonia if its... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-charles-law-different-from-boyle-s-law"> How is Charles' law different from Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-boyle-s-law-written-mathematically"> How is Boyle's law written mathematically? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-boyle-s-law"> How does temperature affect Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyle-s-law-relate-to-ventilation"> How does Boyle's law relate to ventilation? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/boyle-s-law"> See all questions in Boyle's Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2076 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A piston of #11*L# volume under #42*kPa# pressure is compressed to a volume of #8*L#; what is the new pressure?

aae0f527-6ddd-11ea-b24c-ccda262736ce

https://socratic.org/questions/at-constant-pressure-what-temperature-must-be-reached-to-increase-a-100-millilit

600.00 K

start physical_unit 16 16 temperature k qc_end physical_unit 16 16 11 12 volume qc_end physical_unit 16 16 25 26 volume qc_end physical_unit 16 16 19 20 temperature qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Temperature2 [OF] the gas sample [IN] K"}]

[{"type":"physical unit","value":"600.00 K"}]

[{"type":"physical unit","value":"Volume2 [OF] the gas sample [=] \\pu{100 milliliter}"},{"type":"physical unit","value":"Volume1 [OF] the gas sample [=] \\pu{200 milliliters}"},{"type":"physical unit","value":"Temperature1 [OF] the gas sample [=] \\pu{300 K}"},{"type":"other","value":"Constant pressure."}]

<h1 class="questionTitle" itemprop="name">At constant pressure, what temperature must be reached to increase a 100-milliliter sample of a gas initially at 300 K to a volume of 200 milliliters? </h1>

600.00 K

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Given</strong></p> <p>The volume <mathjax>#V_1#</mathjax> of a gas at a temperature <mathjax>#T_1#</mathjax>.<br/> A second volume <mathjax>#V_2#</mathjax>.</p> <p><strong>Find</strong></p> <p>The second temperature <mathjax>#T_2#</mathjax>.</p> <blockquote></blockquote> <p><strong>Strategy</strong></p> <p>A problem involving two gas volumes and two temperatures must be a <a href="http://socratic.org/questions/what-is-the-charles-law">Charles' Law</a> problem.</p> <p><mathjax>#V_1/T_1 = V_2/T_2#</mathjax></p> <blockquote></blockquote> <p>In your problem, </p> <p><mathjax>#V_1 = "100 mL"#</mathjax>; <mathjax>#T_1 = "300 K"#</mathjax><br/> <mathjax>#V_2 = "200 mL"#</mathjax>; <mathjax>#T_2 = "?"#</mathjax></p> <p><mathjax>#V_1/T_1 = V_2/T_2#</mathjax></p> <p><mathjax>#T_2 = T_1 × V_2/V_1 = "300 K" × (200 cancel("mL"))/(100 cancel("mL")) = "600 K"#</mathjax></p> <p>The new temperature is 600 K.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new temperature is 600 K.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Given</strong></p> <p>The volume <mathjax>#V_1#</mathjax> of a gas at a temperature <mathjax>#T_1#</mathjax>.<br/> A second volume <mathjax>#V_2#</mathjax>.</p> <p><strong>Find</strong></p> <p>The second temperature <mathjax>#T_2#</mathjax>.</p> <blockquote></blockquote> <p><strong>Strategy</strong></p> <p>A problem involving two gas volumes and two temperatures must be a <a href="http://socratic.org/questions/what-is-the-charles-law">Charles' Law</a> problem.</p> <p><mathjax>#V_1/T_1 = V_2/T_2#</mathjax></p> <blockquote></blockquote> <p>In your problem, </p> <p><mathjax>#V_1 = "100 mL"#</mathjax>; <mathjax>#T_1 = "300 K"#</mathjax><br/> <mathjax>#V_2 = "200 mL"#</mathjax>; <mathjax>#T_2 = "?"#</mathjax></p> <p><mathjax>#V_1/T_1 = V_2/T_2#</mathjax></p> <p><mathjax>#T_2 = T_1 × V_2/V_1 = "300 K" × (200 cancel("mL"))/(100 cancel("mL")) = "600 K"#</mathjax></p> <p>The new temperature is 600 K.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">At constant pressure, what temperature must be reached to increase a 100-milliliter sample of a gas initially at 300 K to a volume of 200 milliliters? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="216615" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-25T00:47:33" itemprop="dateCreated"> Jan 25, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new temperature is 600 K.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Given</strong></p> <p>The volume <mathjax>#V_1#</mathjax> of a gas at a temperature <mathjax>#T_1#</mathjax>.<br/> A second volume <mathjax>#V_2#</mathjax>.</p> <p><strong>Find</strong></p> <p>The second temperature <mathjax>#T_2#</mathjax>.</p> <blockquote></blockquote> <p><strong>Strategy</strong></p> <p>A problem involving two gas volumes and two temperatures must be a <a href="http://socratic.org/questions/what-is-the-charles-law">Charles' Law</a> problem.</p> <p><mathjax>#V_1/T_1 = V_2/T_2#</mathjax></p> <blockquote></blockquote> <p>In your problem, </p> <p><mathjax>#V_1 = "100 mL"#</mathjax>; <mathjax>#T_1 = "300 K"#</mathjax><br/> <mathjax>#V_2 = "200 mL"#</mathjax>; <mathjax>#T_2 = "?"#</mathjax></p> <p><mathjax>#V_1/T_1 = V_2/T_2#</mathjax></p> <p><mathjax>#T_2 = T_1 × V_2/V_1 = "300 K" × (200 cancel("mL"))/(100 cancel("mL")) = "600 K"#</mathjax></p> <p>The new temperature is 600 K.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/216615" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? 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At constant pressure, what temperature must be reached to increase a 100-milliliter sample of a gas initially at 300 K to a volume of 200 milliliters?

a953c47b-6ddd-11ea-8bdb-ccda262736ce

https://socratic.org/questions/in-photosynthesis-glucose-c6h12o6-and-o2-are-produced-from-co2-and-h2o-6co-g-6h2-1

308 kilojoules

start physical_unit 3 3 heat_energy kj qc_end chemical_equation 12 24 qc_end physical_unit 3 3 34 35 mass qc_end end

[{"type":"physical unit","value":"Needed heat [OF] C6H12O6 [IN] kilojoules"}]

[{"type":"physical unit","value":"308 kilojoules"}]

[{"type":"chemical equation","value":"6 CO2(g) + 6 H2O(l) + 680 kcal -> C6H12O6(aq) + 6 O2(g)"},{"type":"physical unit","value":"Mass [OF] C6H12O6 [=] \\pu{19.5 g}"}]

<h1 class="questionTitle" itemprop="name">In photosynthesis glucose c6h12o6 and o2 are produced from co2 and h2o. 6CO2(g)+6H2O(l)+680kcal=C6H12O6(aq)+6O2(g) How much heat in kilojoules is needed to produce 19.5g of c6h12o6?</h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Not sure how to set up the conversion for the problem</p> <p><img alt="" src="https://s3.amazonaws.com/socratic-ocr-uploads/prod/47c050e9-d51e-4d46-9e83-e091c2d9958b/processed.jpeg"/></p></div> </h2> </div> </div>

308 kilojoules

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The thermochemical equation is</p> <p><mathjax>#"6CO"_2 + "6H"_2"O" + "680 kcal" → "C"_6"H"_12"O"_6 + "6O"_2#</mathjax></p> <blockquote></blockquote> <p>The steps in your calculation will be:</p> <ol> <li>Convert grams of glucose to moles of glucose.</li> <li>Convert moles of glucose to kilocalories.</li> <li>Convert kilocalories to kilojoules.</li> </ol> <blockquote></blockquote> <p><strong>1. Calculate moles of glucose</strong></p> <p><mathjax>#"Moles of glucose" = 19.5 color(red)(cancel(color(black)("g glucose"))) × "1 mol glucose"/(180.16 color(red)(cancel(color(black)("g glucose")))) = "0.1082 mol glucose"#</mathjax></p> <blockquote></blockquote> <p><strong>2. Calculate kilocalories</strong></p> <p><mathjax>#"Kilocalories" = 0.1082 color(red)(cancel(color(black)("mol glucose"))) × "680 kcal"/(1 color(red)(cancel(color(black)("mol glucose")))) = "73.60 kcal"#</mathjax></p> <blockquote></blockquote> <p><strong>3. Convert kilocalories to kilojoules</strong></p> <p><mathjax>#"Kilojoules" = 73.60 color(red)(cancel(color(black)("kcal"))) × "4.184 kJ"/(1 color(red)(cancel(color(black)("kcal")))) = "308 kJ"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You need 308 kJ of heat energy.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The thermochemical equation is</p> <p><mathjax>#"6CO"_2 + "6H"_2"O" + "680 kcal" → "C"_6"H"_12"O"_6 + "6O"_2#</mathjax></p> <blockquote></blockquote> <p>The steps in your calculation will be:</p> <ol> <li>Convert grams of glucose to moles of glucose.</li> <li>Convert moles of glucose to kilocalories.</li> <li>Convert kilocalories to kilojoules.</li> </ol> <blockquote></blockquote> <p><strong>1. Calculate moles of glucose</strong></p> <p><mathjax>#"Moles of glucose" = 19.5 color(red)(cancel(color(black)("g glucose"))) × "1 mol glucose"/(180.16 color(red)(cancel(color(black)("g glucose")))) = "0.1082 mol glucose"#</mathjax></p> <blockquote></blockquote> <p><strong>2. Calculate kilocalories</strong></p> <p><mathjax>#"Kilocalories" = 0.1082 color(red)(cancel(color(black)("mol glucose"))) × "680 kcal"/(1 color(red)(cancel(color(black)("mol glucose")))) = "73.60 kcal"#</mathjax></p> <blockquote></blockquote> <p><strong>3. Convert kilocalories to kilojoules</strong></p> <p><mathjax>#"Kilojoules" = 73.60 color(red)(cancel(color(black)("kcal"))) × "4.184 kJ"/(1 color(red)(cancel(color(black)("kcal")))) = "308 kJ"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">In photosynthesis glucose c6h12o6 and o2 are produced from co2 and h2o. 6CO2(g)+6H2O(l)+680kcal=C6H12O6(aq)+6O2(g) How much heat in kilojoules is needed to produce 19.5g of c6h12o6?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Not sure how to set up the conversion for the problem</p> <p><img alt="" src="https://s3.amazonaws.com/socratic-ocr-uploads/prod/47c050e9-d51e-4d46-9e83-e091c2d9958b/processed.jpeg"/></p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/thermochemistry-with-equation-stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry with Equation Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="292769" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-28T02:23:36" itemprop="dateCreated"> Jul 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You need 308 kJ of heat energy.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The thermochemical equation is</p> <p><mathjax>#"6CO"_2 + "6H"_2"O" + "680 kcal" → "C"_6"H"_12"O"_6 + "6O"_2#</mathjax></p> <blockquote></blockquote> <p>The steps in your calculation will be:</p> <ol> <li>Convert grams of glucose to moles of glucose.</li> <li>Convert moles of glucose to kilocalories.</li> <li>Convert kilocalories to kilojoules.</li> </ol> <blockquote></blockquote> <p><strong>1. Calculate moles of glucose</strong></p> <p><mathjax>#"Moles of glucose" = 19.5 color(red)(cancel(color(black)("g glucose"))) × "1 mol glucose"/(180.16 color(red)(cancel(color(black)("g glucose")))) = "0.1082 mol glucose"#</mathjax></p> <blockquote></blockquote> <p><strong>2. Calculate kilocalories</strong></p> <p><mathjax>#"Kilocalories" = 0.1082 color(red)(cancel(color(black)("mol glucose"))) × "680 kcal"/(1 color(red)(cancel(color(black)("mol glucose")))) = "73.60 kcal"#</mathjax></p> <blockquote></blockquote> <p><strong>3. Convert kilocalories to kilojoules</strong></p> <p><mathjax>#"Kilojoules" = 73.60 color(red)(cancel(color(black)("kcal"))) × "4.184 kJ"/(1 color(red)(cancel(color(black)("kcal")))) = "308 kJ"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/292769" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-someone-explain-how-to-do-this-consider-the-following-equation-2zns-s-3o2-g-"> Can someone explain how to do this? 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In photosynthesis glucose c6h12o6 and o2 are produced from co2 and h2o. 6CO2(g)+6H2O(l)+680kcal=C6H12O6(aq)+6O2(g) How much heat in kilojoules is needed to produce 19.5g of c6h12o6?

Not sure how to set up the conversion for the problem

ac3ade80-6ddd-11ea-b3e2-ccda262736ce

https://socratic.org/questions/what-is-the-weight-in-grams-of-3-36-10-23-molecules-of-copper-sulfate-cuso-4

89.06 grams

start physical_unit 14 14 mass g qc_end end

[{"type":"physical unit","value":"Weight [OF] CuSO4 [IN] grams"}]

[{"type":"physical unit","value":"89.06 grams"}]

[{"type":"physical unit","value":"Number [OF] CuSO4 molecules [=] \\pu{3.36 × 10^23}"}]

<h1 class="questionTitle" itemprop="name">What is the weight in grams of #3.36 * 10^23# molecules of copper sulfate #CuSO_4#?</h1>

89.06 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Do the following conversions:</p> <p><mathjax># "Molecules "-&gt; \ "mol. "-&gt; "grams"#</mathjax></p> <p><mathjax>#3.36xx10^23\ "molecules "CuSO_4xx ( 1 \ mol. CuSO_4)/ ( 6.02xx10^23 \ "molecules "CuSO_4)#</mathjax></p> <p><mathjax>#3.36xx10^23\ cancel("molecules "CuSO_4)xx( 1 \ mol. CuSO_4)/ ( 6.02xx10^23 \ cancel("molecules "CuSO_4 ))#</mathjax></p> <p><mathjax>#= 0.558 \ mol.\ CuSO_4#</mathjax></p> <p>The molar mass of <mathjax>#CuSO_4 = 159.57 \ g/(mol)#</mathjax></p> <p><mathjax>#0.558 \ mol. \ CuSO_4xx(159.57 \ g \ CuSO_4)/(1\ mol. \ CuSO_4)#</mathjax></p> <p><mathjax>#0.558 \ cancel (mol. \ CuSO_4)xx(159.57 \ g \ CuSO_4)/(1\ cancel(mol. \ CuSO_4))#</mathjax></p> <p><mathjax>#~=89.1 \ g#</mathjax></p> <p>Note that <mathjax>#CuSO_4#</mathjax> is copper (II) sulfate.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#~=89.1 \ g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Do the following conversions:</p> <p><mathjax># "Molecules "-&gt; \ "mol. "-&gt; "grams"#</mathjax></p> <p><mathjax>#3.36xx10^23\ "molecules "CuSO_4xx ( 1 \ mol. CuSO_4)/ ( 6.02xx10^23 \ "molecules "CuSO_4)#</mathjax></p> <p><mathjax>#3.36xx10^23\ cancel("molecules "CuSO_4)xx( 1 \ mol. CuSO_4)/ ( 6.02xx10^23 \ cancel("molecules "CuSO_4 ))#</mathjax></p> <p><mathjax>#= 0.558 \ mol.\ CuSO_4#</mathjax></p> <p>The molar mass of <mathjax>#CuSO_4 = 159.57 \ g/(mol)#</mathjax></p> <p><mathjax>#0.558 \ mol. \ CuSO_4xx(159.57 \ g \ CuSO_4)/(1\ mol. \ CuSO_4)#</mathjax></p> <p><mathjax>#0.558 \ cancel (mol. \ CuSO_4)xx(159.57 \ g \ CuSO_4)/(1\ cancel(mol. \ CuSO_4))#</mathjax></p> <p><mathjax>#~=89.1 \ g#</mathjax></p> <p>Note that <mathjax>#CuSO_4#</mathjax> is copper (II) sulfate.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the weight in grams of #3.36 * 10^23# molecules of copper sulfate #CuSO_4#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="274967" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/sam-54"><img alt="" class="" src="https://profilepictures.socratic.org/3bkyAGe2RVWw1lx2h1A5_Avatar%201.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/sam-54"> Sam </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-07T11:54:37" itemprop="dateCreated"> Jun 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#~=89.1 \ g#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Do the following conversions:</p> <p><mathjax># "Molecules "-&gt; \ "mol. "-&gt; "grams"#</mathjax></p> <p><mathjax>#3.36xx10^23\ "molecules "CuSO_4xx ( 1 \ mol. CuSO_4)/ ( 6.02xx10^23 \ "molecules "CuSO_4)#</mathjax></p> <p><mathjax>#3.36xx10^23\ cancel("molecules "CuSO_4)xx( 1 \ mol. CuSO_4)/ ( 6.02xx10^23 \ cancel("molecules "CuSO_4 ))#</mathjax></p> <p><mathjax>#= 0.558 \ mol.\ CuSO_4#</mathjax></p> <p>The molar mass of <mathjax>#CuSO_4 = 159.57 \ g/(mol)#</mathjax></p> <p><mathjax>#0.558 \ mol. \ CuSO_4xx(159.57 \ g \ CuSO_4)/(1\ mol. \ CuSO_4)#</mathjax></p> <p><mathjax>#0.558 \ cancel (mol. \ CuSO_4)xx(159.57 \ g \ CuSO_4)/(1\ cancel(mol. \ CuSO_4))#</mathjax></p> <p><mathjax>#~=89.1 \ g#</mathjax></p> <p>Note that <mathjax>#CuSO_4#</mathjax> is copper (II) sulfate.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/274967" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7597 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the weight in grams of #3.36 * 10^23# molecules of copper sulfate #CuSO_4#?

ac18298a-6ddd-11ea-b0ee-ccda262736ce

https://socratic.org/questions/what-is-the-equation-for-this-reaction-sodium-bicarbonate-and-sulfuric-acid-reac

2 NaHCO3(aq) + H2SO4(aq) -> Na2SO4(aq) + 2 CO2(g) + 2 H2O(l)

start chemical_equation qc_end substance 7 8 qc_end substance 10 11 qc_end substance 15 16 qc_end substance 17 17 qc_end substance 19 20 qc_end end

[{"type":"other","value":"Chemical Equation [OF] this reaction"}]

[{"type":"chemical equation","value":"2 NaHCO3(aq) + H2SO4(aq) -> Na2SO4(aq) + 2 CO2(g) + 2 H2O(l)"}]

[{"type":"substance name","value":"Sodium bicarbonate"},{"type":"substance name","value":"Sulfuric acid"},{"type":"substance name","value":"Sodium sulfate"},{"type":"substance name","value":"Water"},{"type":"substance name","value":"Carbon dioxide"}]

<h1 class="questionTitle" itemprop="name">What is the equation for this reaction: Sodium bicarbonate and sulfuric acid react to form sodium sulfate, water, and carbon dioxide?</h1>

2 NaHCO3(aq) + H2SO4(aq) -> Na2SO4(aq) + 2 CO2(g) + 2 H2O(l)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The net ionic equation is simply......</p> <p><mathjax>#HCO_3^(-) + H_3O^+ rarr CO_2(g)uarr + 2H_2O(l)#</mathjax></p> <p>Is this balanced? If either charge or mass is unequal with respect to both sides of the equation, then it cannot be accepted as a representation of chemical reality. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2NaHCO_3(aq) + H_2SO_4(aq) rarr Na_2SO_4(aq) +2CO_2(g) +2H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The net ionic equation is simply......</p> <p><mathjax>#HCO_3^(-) + H_3O^+ rarr CO_2(g)uarr + 2H_2O(l)#</mathjax></p> <p>Is this balanced? If either charge or mass is unequal with respect to both sides of the equation, then it cannot be accepted as a representation of chemical reality. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the equation for this reaction: Sodium bicarbonate and sulfuric acid react to form sodium sulfate, water, and carbon dioxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="464618" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-16T05:17:01" itemprop="dateCreated"> Aug 16, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2NaHCO_3(aq) + H_2SO_4(aq) rarr Na_2SO_4(aq) +2CO_2(g) +2H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The net ionic equation is simply......</p> <p><mathjax>#HCO_3^(-) + H_3O^+ rarr CO_2(g)uarr + 2H_2O(l)#</mathjax></p> <p>Is this balanced? If either charge or mass is unequal with respect to both sides of the equation, then it cannot be accepted as a representation of chemical reality. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/464618" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-equation-for-photosynthesis"> What is the chemical equation for photosynthesis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-grams-of-each-substance-used-or-produced-w"> How can I know the relative number of grams of each substance used or produced with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-moles-of-each-substance-with-chemical-equa"> How can I know the relative number of moles of each substance with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-chemical-equations-illustrate-that-atoms-are-conserved-1"> How do chemical equations illustrate that atoms are conserved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-formula-of-the-reactants-and-products-with-chemical-equations"> How can I know the formula of the reactants and products with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-potassium-metal-and-chlorine-gas-combi"> How can I balance this chemical equations? 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What is the equation for this reaction: Sodium bicarbonate and sulfuric acid react to form sodium sulfate, water, and carbon dioxide?

ad135076-6ddd-11ea-838a-ccda262736ce

https://socratic.org/questions/what-weight-of-agcl-will-be-precipitated-when-a-solution-containing-4-77g-of-nac

4.87 g

start physical_unit 3 3 mass g qc_end physical_unit 14 14 11 12 mass qc_end physical_unit 24 24 21 22 mass qc_end end

[{"type":"physical unit","value":"Weight [OF] AgCl [IN] g"}]

[{"type":"physical unit","value":"4.87 g"}]

[{"type":"physical unit","value":"Weight [OF] NaCl [=] \\pu{4.77 g}"},{"type":"physical unit","value":"Weight [OF] AgNO3 [=] \\pu{5.77 g}"}]

<h1 class="questionTitle" itemprop="name">What weight of #AgCl# will be precipitated when a solution containing #4.77#g of #NaCl# is added to a solution of #5.77g# of #AgNO_3# ?</h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>I really don't get this question! I know how to solve a basic stoichiometry problem but this one is tough for me, so please help me with this so I can solve this kind of problem.</p></div> </h2> </div> </div>

4.87 g

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing to do is to write down the reaction that is described in the question. Since the reactant and one of the product are given, we can write the balanced reaction:</p> <p><mathjax>#NaCl+AgNO_3-&gt;AgCl +NaNO_3#</mathjax></p> <p>In this type of questions, it is nice to write down a kind of 'scheme' in which we place all the information provided so we can have a clear look what to do. But first, it is important to calculate the masses into moles, before we on accident calculate with the wrong numbers. To do this, we need to molar masses of the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a>. This can be calculated by adding up the masses of the atoms in the compounds. We obtain:</p> <p><mathjax>#AgCl#</mathjax>=<mathjax>#1xxAg +1xxCl =107.9u+35.45u=143.35u#</mathjax><br/> <mathjax>#NaCl#</mathjax>=<mathjax>#1xxNa+1xxCl=22.99u+34.45u=57.44u#</mathjax><br/> <mathjax>#AgNO_3#</mathjax>=<mathjax>#1xxAg+1xxN+3xxO=107.9u+14.01u+3xx16.00u=169.91u#</mathjax></p> <p>Now we calculate a number of moles with the formula below. </p> <p><mathjax># mol=(mass)/(molar mass)#</mathjax></p> <p>I only display the calculation for <mathjax>#NaCl#</mathjax> here.<br/> <mathjax>#mol=(4.77 (color(red)(cancel(color(blue)(gram)))))/(57.44(color(red)(cancel(color(blue)(gram)))/color(blue)(mol)))=0.083 color(white)(a)color(blue)(mol)#</mathjax> <mathjax>#NaCl#</mathjax><br/> <mathjax>#AgNO_3=0.034 color(white)(a)color(blue)(mol)#</mathjax></p> <p>Now we have the moles, we write the molar ratio below the reaction and the moles at the correct places. We obtain something like this:</p> <p><mathjax>#color(white)(aa)#</mathjax><mathjax>#NaCl+AgNO_3-&gt;AgCl +NaNO_3#</mathjax><mathjax>#color(white)(aaa)color(blue)("reaction")#</mathjax><br/> <mathjax>#color(white)(aaaa)1 color(white)(aab):color(white)(aaa)1color(white)(aaab):color(white)(aaa)1color(white)(aa):color(white)(aaab)1color(white)(aa.aa)color(blue)("molar ratio")#</mathjax><br/> <mathjax>#color(white)(aa)0.083 color(white)(aaa)0.034color(white)(aaaaaaa)?color(white)(aaaaaaaaaaaaa)color(blue)("moles")#</mathjax></p> <p>We don't need to do anything with the <mathjax>#NaNO_3#</mathjax> in this question. </p> <p>We calculate the question mark <mathjax>#?#</mathjax> by applying the law of conservation of mass. This can be done by:<br/> mol <mathjax>#AgCl#</mathjax> =<mathjax>#(mol color(red)(AgNO_3)xxcolor(blue)(cancel(color(black)(molar ratio))) color(red)(AgCl))/(color(blue)(cancel(color(black)(molar ratio)) color(red)(AgNO_3))#</mathjax><br/> mol <mathjax>#AgCl#</mathjax> =<mathjax>#(0.034 xx1)/1=0.034#</mathjax></p> <p>Now we calculate the mass of <mathjax>#AgCl#</mathjax> that is created. The molar mass was <mathjax>#143.35 u#</mathjax></p> <p>mass <mathjax>#AgCl#</mathjax>=<mathjax>#mol xx molar mass#</mathjax><br/> mass <mathjax>#AgCl#</mathjax> =<mathjax>#0.034 color(red)(cancel(color(blue)(mol)))xx143.35 (color(blue)(gram))/(color(red)(cancel(color(blue)(mol))))=4.87 color(white)(a)color(blue)(gram)#</mathjax></p> <p>For this particular question, it seems useless to calculate the molar mass of the other reactant, but for future questions, they may ask something more about the reaction and then you already have made a nice scheme.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4.87#</mathjax> gram <mathjax>#AgCl#</mathjax> will be precipitated.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing to do is to write down the reaction that is described in the question. Since the reactant and one of the product are given, we can write the balanced reaction:</p> <p><mathjax>#NaCl+AgNO_3-&gt;AgCl +NaNO_3#</mathjax></p> <p>In this type of questions, it is nice to write down a kind of 'scheme' in which we place all the information provided so we can have a clear look what to do. But first, it is important to calculate the masses into moles, before we on accident calculate with the wrong numbers. To do this, we need to molar masses of the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a>. This can be calculated by adding up the masses of the atoms in the compounds. We obtain:</p> <p><mathjax>#AgCl#</mathjax>=<mathjax>#1xxAg +1xxCl =107.9u+35.45u=143.35u#</mathjax><br/> <mathjax>#NaCl#</mathjax>=<mathjax>#1xxNa+1xxCl=22.99u+34.45u=57.44u#</mathjax><br/> <mathjax>#AgNO_3#</mathjax>=<mathjax>#1xxAg+1xxN+3xxO=107.9u+14.01u+3xx16.00u=169.91u#</mathjax></p> <p>Now we calculate a number of moles with the formula below. </p> <p><mathjax># mol=(mass)/(molar mass)#</mathjax></p> <p>I only display the calculation for <mathjax>#NaCl#</mathjax> here.<br/> <mathjax>#mol=(4.77 (color(red)(cancel(color(blue)(gram)))))/(57.44(color(red)(cancel(color(blue)(gram)))/color(blue)(mol)))=0.083 color(white)(a)color(blue)(mol)#</mathjax> <mathjax>#NaCl#</mathjax><br/> <mathjax>#AgNO_3=0.034 color(white)(a)color(blue)(mol)#</mathjax></p> <p>Now we have the moles, we write the molar ratio below the reaction and the moles at the correct places. We obtain something like this:</p> <p><mathjax>#color(white)(aa)#</mathjax><mathjax>#NaCl+AgNO_3-&gt;AgCl +NaNO_3#</mathjax><mathjax>#color(white)(aaa)color(blue)("reaction")#</mathjax><br/> <mathjax>#color(white)(aaaa)1 color(white)(aab):color(white)(aaa)1color(white)(aaab):color(white)(aaa)1color(white)(aa):color(white)(aaab)1color(white)(aa.aa)color(blue)("molar ratio")#</mathjax><br/> <mathjax>#color(white)(aa)0.083 color(white)(aaa)0.034color(white)(aaaaaaa)?color(white)(aaaaaaaaaaaaa)color(blue)("moles")#</mathjax></p> <p>We don't need to do anything with the <mathjax>#NaNO_3#</mathjax> in this question. </p> <p>We calculate the question mark <mathjax>#?#</mathjax> by applying the law of conservation of mass. This can be done by:<br/> mol <mathjax>#AgCl#</mathjax> =<mathjax>#(mol color(red)(AgNO_3)xxcolor(blue)(cancel(color(black)(molar ratio))) color(red)(AgCl))/(color(blue)(cancel(color(black)(molar ratio)) color(red)(AgNO_3))#</mathjax><br/> mol <mathjax>#AgCl#</mathjax> =<mathjax>#(0.034 xx1)/1=0.034#</mathjax></p> <p>Now we calculate the mass of <mathjax>#AgCl#</mathjax> that is created. The molar mass was <mathjax>#143.35 u#</mathjax></p> <p>mass <mathjax>#AgCl#</mathjax>=<mathjax>#mol xx molar mass#</mathjax><br/> mass <mathjax>#AgCl#</mathjax> =<mathjax>#0.034 color(red)(cancel(color(blue)(mol)))xx143.35 (color(blue)(gram))/(color(red)(cancel(color(blue)(mol))))=4.87 color(white)(a)color(blue)(gram)#</mathjax></p> <p>For this particular question, it seems useless to calculate the molar mass of the other reactant, but for future questions, they may ask something more about the reaction and then you already have made a nice scheme.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What weight of #AgCl# will be precipitated when a solution containing #4.77#g of #NaCl# is added to a solution of #5.77g# of #AgNO_3# ?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>I really don't get this question! I know how to solve a basic stoichiometry problem but this one is tough for me, so please help me with this so I can solve this kind of problem.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solution-formation---what-happens-when-stuff-dissolves" itemprop="url"> <span class="breadcrumb" itemprop="title">Solution Formation</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="429999" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/martin-m-2"><img alt="" class="" src="https://profilepictures.socratic.org/f0sDBdFaTJCkuFNIfZjD_Profielfoto.PNG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/martin-m-2"> Martin M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-26T12:59:42" itemprop="dateCreated"> May 26, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4.87#</mathjax> gram <mathjax>#AgCl#</mathjax> will be precipitated.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The first thing to do is to write down the reaction that is described in the question. Since the reactant and one of the product are given, we can write the balanced reaction:</p> <p><mathjax>#NaCl+AgNO_3-&gt;AgCl +NaNO_3#</mathjax></p> <p>In this type of questions, it is nice to write down a kind of 'scheme' in which we place all the information provided so we can have a clear look what to do. But first, it is important to calculate the masses into moles, before we on accident calculate with the wrong numbers. To do this, we need to molar masses of the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a>. This can be calculated by adding up the masses of the atoms in the compounds. We obtain:</p> <p><mathjax>#AgCl#</mathjax>=<mathjax>#1xxAg +1xxCl =107.9u+35.45u=143.35u#</mathjax><br/> <mathjax>#NaCl#</mathjax>=<mathjax>#1xxNa+1xxCl=22.99u+34.45u=57.44u#</mathjax><br/> <mathjax>#AgNO_3#</mathjax>=<mathjax>#1xxAg+1xxN+3xxO=107.9u+14.01u+3xx16.00u=169.91u#</mathjax></p> <p>Now we calculate a number of moles with the formula below. </p> <p><mathjax># mol=(mass)/(molar mass)#</mathjax></p> <p>I only display the calculation for <mathjax>#NaCl#</mathjax> here.<br/> <mathjax>#mol=(4.77 (color(red)(cancel(color(blue)(gram)))))/(57.44(color(red)(cancel(color(blue)(gram)))/color(blue)(mol)))=0.083 color(white)(a)color(blue)(mol)#</mathjax> <mathjax>#NaCl#</mathjax><br/> <mathjax>#AgNO_3=0.034 color(white)(a)color(blue)(mol)#</mathjax></p> <p>Now we have the moles, we write the molar ratio below the reaction and the moles at the correct places. We obtain something like this:</p> <p><mathjax>#color(white)(aa)#</mathjax><mathjax>#NaCl+AgNO_3-&gt;AgCl +NaNO_3#</mathjax><mathjax>#color(white)(aaa)color(blue)("reaction")#</mathjax><br/> <mathjax>#color(white)(aaaa)1 color(white)(aab):color(white)(aaa)1color(white)(aaab):color(white)(aaa)1color(white)(aa):color(white)(aaab)1color(white)(aa.aa)color(blue)("molar ratio")#</mathjax><br/> <mathjax>#color(white)(aa)0.083 color(white)(aaa)0.034color(white)(aaaaaaa)?color(white)(aaaaaaaaaaaaa)color(blue)("moles")#</mathjax></p> <p>We don't need to do anything with the <mathjax>#NaNO_3#</mathjax> in this question. </p> <p>We calculate the question mark <mathjax>#?#</mathjax> by applying the law of conservation of mass. This can be done by:<br/> mol <mathjax>#AgCl#</mathjax> =<mathjax>#(mol color(red)(AgNO_3)xxcolor(blue)(cancel(color(black)(molar ratio))) color(red)(AgCl))/(color(blue)(cancel(color(black)(molar ratio)) color(red)(AgNO_3))#</mathjax><br/> mol <mathjax>#AgCl#</mathjax> =<mathjax>#(0.034 xx1)/1=0.034#</mathjax></p> <p>Now we calculate the mass of <mathjax>#AgCl#</mathjax> that is created. The molar mass was <mathjax>#143.35 u#</mathjax></p> <p>mass <mathjax>#AgCl#</mathjax>=<mathjax>#mol xx molar mass#</mathjax><br/> mass <mathjax>#AgCl#</mathjax> =<mathjax>#0.034 color(red)(cancel(color(blue)(mol)))xx143.35 (color(blue)(gram))/(color(red)(cancel(color(blue)(mol))))=4.87 color(white)(a)color(blue)(gram)#</mathjax></p> <p>For this particular question, it seems useless to calculate the molar mass of the other reactant, but for future questions, they may ask something more about the reaction and then you already have made a nice scheme.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/429999" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-temperature-affect-the-formation-of-a-solution"> How can temperature affect the formation of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-formation-of-a-solution-be-exothermic-or-endothermic"> How can the formation of a solution be exothermic or endothermic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-formation-of-a-solution-involve-energy"> How does the formation of a solution involve energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-heat-formation-of-solution"> How do you find heat of formation of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factor-promotes-the-formation-of-solutions"> Which factors promote the formation of solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/which-two-processes-are-at-equilibrium-in-a-saturated-sugar-solution"> Which two processes are at equilibrium in a saturated sugar solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutes-lower-the-freezing-point"> Why do solutes lower the freezing point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-solution-formation-require-energy"> Why does solution formation require energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutes-dissolve-in-solvents"> Why do solutes dissolve in solvents? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-solvent-dissolves-silicone"> What solvent dissolves silicone? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/solution-formation---what-happens-when-stuff-dissolves"> See all questions in Solution Formation </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 26611 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What weight of #AgCl# will be precipitated when a solution containing #4.77#g of #NaCl# is added to a solution of #5.77g# of #AgNO_3# ?

I really don't get this question! I know how to solve a basic stoichiometry problem but this one is tough for me, so please help me with this so I can solve this kind of problem.

a9a565c0-6ddd-11ea-945b-ccda262736ce

https://socratic.org/questions/how-do-you-calculate-the-amount-of-heat-needed-to-melt-35-0-g-of-ice-at-0-c

11.69 kJ

start physical_unit 14 14 heat_energy kj qc_end physical_unit 14 14 11 12 mass qc_end physical_unit 14 14 16 17 temperature qc_end c_other melt qc_end end

[{"type":"physical unit","value":"Needed heat [OF] ice [IN] kJ"}]

[{"type":"physical unit","value":"11.69 kJ"}]

[{"type":"physical unit","value":"Mass [OF] ice [=] \\pu{35.0 g}"},{"type":"physical unit","value":"Temperature [OF] ice [=] \\pu{0 ℃}"},{"type":"other","value":"melt"}]

<h1 class="questionTitle" itemprop="name">How do you calculate the amount of heat needed to melt 35.0 g of ice at 0 °C?</h1>

11.69 kJ

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use formula Q = mL<br/> where:<br/> Q = Energy (J)<br/> m = Mass (g)<br/> L = Latent heat of fusion for water (J/g) = 344J/g <br/> Therefore:<br/> Q = 35.0 x 344<br/> Q = 11690J</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>11690J</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use formula Q = mL<br/> where:<br/> Q = Energy (J)<br/> m = Mass (g)<br/> L = Latent heat of fusion for water (J/g) = 344J/g <br/> Therefore:<br/> Q = 35.0 x 344<br/> Q = 11690J</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you calculate the amount of heat needed to melt 35.0 g of ice at 0 °C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="428269" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mozzie"><img alt="" class="" src="https://profilepictures.socratic.org/5KcxHZHQQ6zqJYXnEz1w_Buhoportada.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mozzie"> mozzie </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-23T10:22:27" itemprop="dateCreated"> May 23, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>11690J</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use formula Q = mL<br/> where:<br/> Q = Energy (J)<br/> m = Mass (g)<br/> L = Latent heat of fusion for water (J/g) = 344J/g <br/> Therefore:<br/> Q = 35.0 x 344<br/> Q = 11690J</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/428269" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? 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How do you calculate the amount of heat needed to melt 35.0 g of ice at 0 °C?

a8e4bddc-6ddd-11ea-99f8-ccda262736ce

https://socratic.org/questions/57139c207c01491a08756648

3 × 10^(-14) mol/L

start physical_unit 6 7 [oh-] mol/l qc_end physical_unit 6 7 3 3 ph qc_end end

[{"type":"physical unit","value":"[HO-] [OF] the aqueous solution [IN] mol/L"}]

[{"type":"physical unit","value":"3 × 10^(-14) mol/L"}]

[{"type":"physical unit","value":"pH [OF] the aqueous solution [=] \\pu{0.325}"}]

<h1 class="questionTitle" itemprop="name">If #pH=0.325# for an aqueous solution, what is #[HO^-]#?</h1>

3 × 10^(-14) mol/L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#K_w=10^-14=[H_3O^+][HO^-]#</mathjax> under standard conditions of <mathjax>#298*K#</mathjax> and (near to) <mathjax>#1*atm#</mathjax> pressure.........</p> <p>It is usually simpler to convert this <mathjax>#pH#</mathjax> and <mathjax>#pOH#</mathjax> values than pfaff about with exponential products........</p> <p><mathjax>#14=pH+pOH#</mathjax>; <mathjax>#pH=-log_10(0.325)=0.488#</mathjax>; and <mathjax>#pOH=13.51#</mathjax>..</p> <p><mathjax>#[HO^-]=10^(-13.51)*mol*L^-1=??*mol*L^-1#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[HO^-]~=3xx10^-14*mol*L^-1#</mathjax>. The low <mathjax>#pH#</mathjax> specifies AN ACIDIC solution....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#K_w=10^-14=[H_3O^+][HO^-]#</mathjax> under standard conditions of <mathjax>#298*K#</mathjax> and (near to) <mathjax>#1*atm#</mathjax> pressure.........</p> <p>It is usually simpler to convert this <mathjax>#pH#</mathjax> and <mathjax>#pOH#</mathjax> values than pfaff about with exponential products........</p> <p><mathjax>#14=pH+pOH#</mathjax>; <mathjax>#pH=-log_10(0.325)=0.488#</mathjax>; and <mathjax>#pOH=13.51#</mathjax>..</p> <p><mathjax>#[HO^-]=10^(-13.51)*mol*L^-1=??*mol*L^-1#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If #pH=0.325# for an aqueous solution, what is #[HO^-]#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="454699" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-21T19:44:20" itemprop="dateCreated"> Jul 21, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[HO^-]~=3xx10^-14*mol*L^-1#</mathjax>. The low <mathjax>#pH#</mathjax> specifies AN ACIDIC solution....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#K_w=10^-14=[H_3O^+][HO^-]#</mathjax> under standard conditions of <mathjax>#298*K#</mathjax> and (near to) <mathjax>#1*atm#</mathjax> pressure.........</p> <p>It is usually simpler to convert this <mathjax>#pH#</mathjax> and <mathjax>#pOH#</mathjax> values than pfaff about with exponential products........</p> <p><mathjax>#14=pH+pOH#</mathjax>; <mathjax>#pH=-log_10(0.325)=0.488#</mathjax>; and <mathjax>#pOH=13.51#</mathjax>..</p> <p><mathjax>#[HO^-]=10^(-13.51)*mol*L^-1=??*mol*L^-1#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/454699" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1282 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

If #pH=0.325# for an aqueous solution, what is #[HO^-]#?

ab0c40a4-6ddd-11ea-b97c-ccda262736ce

https://socratic.org/questions/what-is-the-hydronium-ion-concentration-of-a-solution-whose-ph-is-4-12

7.59 × 10^(-5) M

start physical_unit 3 4 concentration mol/l qc_end physical_unit 8 8 12 12 ph qc_end end

[{"type":"physical unit","value":"Concentration [OF] hydronium ion [IN] M"}]

[{"type":"physical unit","value":"7.59 × 10^(-5) M"}]

[{"type":"physical unit","value":"pH [OF] a solution [=] \\pu{4.12}"}]

<h1 class="questionTitle" itemprop="name">What is the hydronium ion concentration of a solution whose pH is 4.12? </h1>

7.59 × 10^(-5) M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, <mathjax>#pH=-log_10[H_3O^+]#</mathjax>, and this represents a measure of the concentration of the hydronium ion, conceived to be the characteristic cation of water. We can also develop a <mathjax>#pOH#</mathjax> function, where <mathjax>#pOH=-log_10[HO^-]#</mathjax>. In water, under standard conditions, <mathjax>#pH+pOH=14#</mathjax>.</p> <p>Historically, before the days of electronic calculators, log tables were habitually used by chemists, and mathematicians, and engineers, and students because logarithmic functions allowed fairly speedy calculation of products and quotients. </p> <p>AS a bit of background, when we write <mathjax>#log_(a)b=c#</mathjax>, this means that <mathjax>#a^c=b#</mathjax>. </p> <p>And thus ...............................................................</p> <p><mathjax>#log_(10)0.1=-1; log_(10)1=0; log_(10)10=1; log_(10)100=2; log_(10)1000=3#</mathjax>. </p> <p>Note that you still have to plug that value into a calculator, and raise <mathjax>#10#</mathjax> to that power...........</p> <p>See <a href="https://socratic.org/questions/what-is-the-ph-of-a-1-00-x-10-4-m-solution-of-lithium-hydroxide-solution#306871">here for a similar spray. </a> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[H_3O^+]=10^(-4.12)*mol*L^-1..........#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, <mathjax>#pH=-log_10[H_3O^+]#</mathjax>, and this represents a measure of the concentration of the hydronium ion, conceived to be the characteristic cation of water. We can also develop a <mathjax>#pOH#</mathjax> function, where <mathjax>#pOH=-log_10[HO^-]#</mathjax>. In water, under standard conditions, <mathjax>#pH+pOH=14#</mathjax>.</p> <p>Historically, before the days of electronic calculators, log tables were habitually used by chemists, and mathematicians, and engineers, and students because logarithmic functions allowed fairly speedy calculation of products and quotients. </p> <p>AS a bit of background, when we write <mathjax>#log_(a)b=c#</mathjax>, this means that <mathjax>#a^c=b#</mathjax>. </p> <p>And thus ...............................................................</p> <p><mathjax>#log_(10)0.1=-1; log_(10)1=0; log_(10)10=1; log_(10)100=2; log_(10)1000=3#</mathjax>. </p> <p>Note that you still have to plug that value into a calculator, and raise <mathjax>#10#</mathjax> to that power...........</p> <p>See <a href="https://socratic.org/questions/what-is-the-ph-of-a-1-00-x-10-4-m-solution-of-lithium-hydroxide-solution#306871">here for a similar spray. </a> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the hydronium ion concentration of a solution whose pH is 4.12? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/measuring-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Measuring Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="415343" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-30T17:05:44" itemprop="dateCreated"> Apr 30, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[H_3O^+]=10^(-4.12)*mol*L^-1..........#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, <mathjax>#pH=-log_10[H_3O^+]#</mathjax>, and this represents a measure of the concentration of the hydronium ion, conceived to be the characteristic cation of water. We can also develop a <mathjax>#pOH#</mathjax> function, where <mathjax>#pOH=-log_10[HO^-]#</mathjax>. In water, under standard conditions, <mathjax>#pH+pOH=14#</mathjax>.</p> <p>Historically, before the days of electronic calculators, log tables were habitually used by chemists, and mathematicians, and engineers, and students because logarithmic functions allowed fairly speedy calculation of products and quotients. </p> <p>AS a bit of background, when we write <mathjax>#log_(a)b=c#</mathjax>, this means that <mathjax>#a^c=b#</mathjax>. </p> <p>And thus ...............................................................</p> <p><mathjax>#log_(10)0.1=-1; log_(10)1=0; log_(10)10=1; log_(10)100=2; log_(10)1000=3#</mathjax>. </p> <p>Note that you still have to plug that value into a calculator, and raise <mathjax>#10#</mathjax> to that power...........</p> <p>See <a href="https://socratic.org/questions/what-is-the-ph-of-a-1-00-x-10-4-m-solution-of-lithium-hydroxide-solution#306871">here for a similar spray. </a> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/415343" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="415348" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/tartar-c"><img alt="" class="" src="https://profilepictures.socratic.org/m0AqR4w7RXSxm9gd4o1l_cool-wallpaper-16.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/tartar-c"> Tartar C. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-30T17:10:22" itemprop="dateCreated"> Apr 30, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[H^+] = 7.59 * 10^(-5)M#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Take the formula:<br/> <mathjax>#pH = -log[H^+]#</mathjax><br/> and isolate <mathjax>#[H^+]#</mathjax>. You should get:</p> <p><mathjax>#[H^+] = 10^(-pH)#</mathjax></p> <p><mathjax>#[H^+] = 10^(-4.12)#</mathjax></p> <p><mathjax>#[H^+] = 0.000075858M#</mathjax></p> <p>Since yo only have 3 sig figs the answer would be:</p> <p><mathjax>#[H^+] = 7.59 * 10^(-5)M#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/415348" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-concentration-from-absorbance"> How do you measure concentration from absorbance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-concentration-of-a-solution"> How do you measure concentration of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-concentration-of-co2"> How do you measure concentration of CO2? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-concentration-measure-changes-with-temperature"> What concentration measure changes with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-measure-the-concentration-of-salt-in-water"> How can I measure the concentration of salt in water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-the-concentration-of-a-solution-measured"> How is the concentration of a solution measured? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-concentration-of-electrolyte-affect-an-electrochemical-cell"> How does the concentration of electrolyte affect an electrochemical cell? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-normality-differ-from-molarity"> How does normality differ from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molality-of-a-solution-of-10-g-naoh-in-500-g-water"> What is the molality of a solution of 10 g NaOH in 500 g water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-the-mole-fractions-of-the-components-of-the-solution-formed-when-92-g-g"> What are the mole fractions of the components of the solution formed when 92 g glycerol is mixed... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/measuring-concentration"> See all questions in Measuring Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 40102 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the hydronium ion concentration of a solution whose pH is 4.12?

a8e88b42-6ddd-11ea-9a77-ccda262736ce

https://socratic.org/questions/597038b311ef6b7fdbcfe58b

0.02 L

start physical_unit 16 17 volume l qc_end physical_unit 0 1 3 4 volume qc_end physical_unit 0 1 9 10 pressure qc_end physical_unit 16 17 33 34 pressure qc_end end

[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] L"}]

[{"type":"physical unit","value":"0.02 L"}]

[{"type":"physical unit","value":"Volume1 [OF] a gas [=] \\pu{1.46 L}"},{"type":"physical unit","value":"Pressure1 [OF] a gas [=] \\pu{1.00 bar}"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{60.0 bar}"}]

<h1 class="questionTitle" itemprop="name">A gas occupies #"1.46 L"# at a pressure of #"1.00 bar"#. What is the volume when the gas is dropped into the ocean to a depth such that the pressure is increased to #"60.0 bar"#?</h1>

0.02 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This question involves <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a>, which states that the volume of a gas held at constant temperature varies inversely with the pressure. The means that if the volume increases, the pressure decreases, and vice versa. The equation for Boyle's law is:</p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax></p> <p><strong>Organize the data.</strong></p> <p><mathjax>#P_1="1.00 bar"#</mathjax></p> <p><mathjax>#V_1="1.46 L"#</mathjax></p> <p><mathjax>#P_2="60.0 bar"#</mathjax></p> <p><mathjax>#V_2="?"#</mathjax></p> <p><strong>Solution</strong></p> <p>Rearrange the equation to isolate <mathjax>#V_2#</mathjax>. Substitute the data into the equation and solve.</p> <p><mathjax>#V_2=(P_1V_1)/P_2#</mathjax></p> <p><mathjax>#V_2=(1.00color(red)cancel(color(black)("bar"))xx1.46"L")/(60.0color(red)cancel(color(black)("bar")))="0.0243 L"#</mathjax> (rounded to three significant figures)</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final volume <mathjax>#(V_2)#</mathjax> is <mathjax>#"0.0243 L"#</mathjax>.</p> <p>Refer to the explanation for the process.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This question involves <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a>, which states that the volume of a gas held at constant temperature varies inversely with the pressure. The means that if the volume increases, the pressure decreases, and vice versa. The equation for Boyle's law is:</p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax></p> <p><strong>Organize the data.</strong></p> <p><mathjax>#P_1="1.00 bar"#</mathjax></p> <p><mathjax>#V_1="1.46 L"#</mathjax></p> <p><mathjax>#P_2="60.0 bar"#</mathjax></p> <p><mathjax>#V_2="?"#</mathjax></p> <p><strong>Solution</strong></p> <p>Rearrange the equation to isolate <mathjax>#V_2#</mathjax>. Substitute the data into the equation and solve.</p> <p><mathjax>#V_2=(P_1V_1)/P_2#</mathjax></p> <p><mathjax>#V_2=(1.00color(red)cancel(color(black)("bar"))xx1.46"L")/(60.0color(red)cancel(color(black)("bar")))="0.0243 L"#</mathjax> (rounded to three significant figures)</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A gas occupies #"1.46 L"# at a pressure of #"1.00 bar"#. What is the volume when the gas is dropped into the ocean to a depth such that the pressure is increased to #"60.0 bar"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="453901" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-20T05:16:41" itemprop="dateCreated"> Jul 20, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final volume <mathjax>#(V_2)#</mathjax> is <mathjax>#"0.0243 L"#</mathjax>.</p> <p>Refer to the explanation for the process.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This question involves <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a>, which states that the volume of a gas held at constant temperature varies inversely with the pressure. The means that if the volume increases, the pressure decreases, and vice versa. The equation for Boyle's law is:</p> <p><mathjax>#P_1V_1=P_2V_2#</mathjax></p> <p><strong>Organize the data.</strong></p> <p><mathjax>#P_1="1.00 bar"#</mathjax></p> <p><mathjax>#V_1="1.46 L"#</mathjax></p> <p><mathjax>#P_2="60.0 bar"#</mathjax></p> <p><mathjax>#V_2="?"#</mathjax></p> <p><strong>Solution</strong></p> <p>Rearrange the equation to isolate <mathjax>#V_2#</mathjax>. Substitute the data into the equation and solve.</p> <p><mathjax>#V_2=(P_1V_1)/P_2#</mathjax></p> <p><mathjax>#V_2=(1.00color(red)cancel(color(black)("bar"))xx1.46"L")/(60.0color(red)cancel(color(black)("bar")))="0.0243 L"#</mathjax> (rounded to three significant figures)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/453901" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyles-law-relate-to-breathing"> How does Boyle's law relate to breathing? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/in-avogadro-s-law-what-would-happen-to-v-if-n-is-increased-decreased-and-what-wo"> In Avogadro's Law what would happen to V if N is increased/decreased? 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A gas occupies #"1.46 L"# at a pressure of #"1.00 bar"#. What is the volume when the gas is dropped into the ocean to a depth such that the pressure is increased to #"60.0 bar"#?

a8377ffc-6ddd-11ea-806d-ccda262736ce

https://socratic.org/questions/what-is-the-concentration-of-10-00-mlof-hbr-if-it-takes-5-ml-of-a-0-253-m-lioh-s

0.1 mol/L

start physical_unit 8 8 concentration mol/l qc_end physical_unit 19 19 5 6 volume qc_end physical_unit 18 19 16 17 concentration qc_end physical_unit 18 19 12 13 volume qc_end end

[{"type":"physical unit","value":"Concentration [OF] HBr solution [IN] mol/L"}]

[{"type":"physical unit","value":"0.1 mol/L"}]

[{"type":"physical unit","value":"Volume [OF] HBr solution [=] \\pu{10.00 mL}"},{"type":"physical unit","value":"Concentration [OF] LiOH solution [=] \\pu{0.253 M}"},{"type":"physical unit","value":"Volume [OF] LiOH solution [=] \\pu{5 mL}"}]

<h1 class="questionTitle" itemprop="name">What is the concentration of 10.00 mLof HBr if it takes 5 mL of a 0.253 M LiOH solution to neutralize it?</h1>

0.1 mol/L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>AS with all these problems, we need a stoichiometrically balanced equation:</p> <p><mathjax>#HBr(aq) + LiOH(aq) rarr LiBr(aq) + H_2O(l)#</mathjax></p> <p>So, there is <mathjax>#"1:1 molar equivalence"#</mathjax></p> <p><mathjax>#[HBr]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(5xx10^-3*cancelLxx0.253*mol*L^-1)/(10.00xx10^-3*cancelL)#</mathjax> <mathjax>#=??mol*L^-1#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#0.1*mol*L^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>AS with all these problems, we need a stoichiometrically balanced equation:</p> <p><mathjax>#HBr(aq) + LiOH(aq) rarr LiBr(aq) + H_2O(l)#</mathjax></p> <p>So, there is <mathjax>#"1:1 molar equivalence"#</mathjax></p> <p><mathjax>#[HBr]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(5xx10^-3*cancelLxx0.253*mol*L^-1)/(10.00xx10^-3*cancelL)#</mathjax> <mathjax>#=??mol*L^-1#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the concentration of 10.00 mLof HBr if it takes 5 mL of a 0.253 M LiOH solution to neutralize it?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/measuring-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Measuring Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="350530" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-12T10:11:25" itemprop="dateCreated"> Dec 12, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#0.1*mol*L^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>AS with all these problems, we need a stoichiometrically balanced equation:</p> <p><mathjax>#HBr(aq) + LiOH(aq) rarr LiBr(aq) + H_2O(l)#</mathjax></p> <p>So, there is <mathjax>#"1:1 molar equivalence"#</mathjax></p> <p><mathjax>#[HBr]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(5xx10^-3*cancelLxx0.253*mol*L^-1)/(10.00xx10^-3*cancelL)#</mathjax> <mathjax>#=??mol*L^-1#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/350530" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-concentration-from-absorbance"> How do you measure concentration from absorbance? 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What is the concentration of 10.00 mLof HBr if it takes 5 mL of a 0.253 M LiOH solution to neutralize it?

ac0bf0c9-6ddd-11ea-91b8-ccda262736ce

https://socratic.org/questions/what-is-the-molarity-of-060-mol-of-nahco-3-in-1500-ml-of-solution

0.04 M

start physical_unit 8 8 molarity mol/l qc_end physical_unit 8 8 5 6 mole qc_end physical_unit 13 13 10 11 volume qc_end end

[{"type":"physical unit","value":"Molarity [OF] NaHCO3 solution [IN] M"}]

[{"type":"physical unit","value":"0.04 M"}]

[{"type":"physical unit","value":"Mole [OF] NaHCO3 [=] \\pu{0.060 mol}"},{"type":"physical unit","value":"Volume [OF] NaHCO3 solution [=] \\pu{1500 mL}"}]

<h1 class="questionTitle" itemprop="name">What is the molarity of .060 mol of #NaHCO_3# in 1500 mL of solution?</h1>

0.04 M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to find <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>, you would first determine the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> that are present, followed by the volume of solution (must be in liters). We already have the number of moles, so we just have to go from milliliters of solution to liters of solution. We do this by using the conversion factor: 1000 mL = 1 L. When you divide the 1500 mL that you're given by 1000 mL/L you obtain 1.5 L. </p> <p>Afterwards, you would simply divide the two like so:</p> <p>Molarity = moles of solute / liter of solution</p> <p>0.060 mol NaHCO3 / 1.5 L of solution = 0.040 M.</p> <p>I hope this explanation makes sense.</p> <p><a href="http://www.chemteam.info/Solutions/Molarity.html" rel="nofollow">Take a look at this website for additional help :)</a> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.040 M</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to find <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>, you would first determine the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> that are present, followed by the volume of solution (must be in liters). We already have the number of moles, so we just have to go from milliliters of solution to liters of solution. We do this by using the conversion factor: 1000 mL = 1 L. When you divide the 1500 mL that you're given by 1000 mL/L you obtain 1.5 L. </p> <p>Afterwards, you would simply divide the two like so:</p> <p>Molarity = moles of solute / liter of solution</p> <p>0.060 mol NaHCO3 / 1.5 L of solution = 0.040 M.</p> <p>I hope this explanation makes sense.</p> <p><a href="http://www.chemteam.info/Solutions/Molarity.html" rel="nofollow">Take a look at this website for additional help :)</a> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the molarity of .060 mol of #NaHCO_3# in 1500 mL of solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="273226" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> <a class="secondContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a>·<a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-03T02:22:49" itemprop="dateCreated"> Jun 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.040 M</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to find <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>, you would first determine the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> that are present, followed by the volume of solution (must be in liters). We already have the number of moles, so we just have to go from milliliters of solution to liters of solution. We do this by using the conversion factor: 1000 mL = 1 L. When you divide the 1500 mL that you're given by 1000 mL/L you obtain 1.5 L. </p> <p>Afterwards, you would simply divide the two like so:</p> <p>Molarity = moles of solute / liter of solution</p> <p>0.060 mol NaHCO3 / 1.5 L of solution = 0.040 M.</p> <p>I hope this explanation makes sense.</p> <p><a href="http://www.chemteam.info/Solutions/Molarity.html" rel="nofollow">Take a look at this website for additional help :)</a> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/273226" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11570 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the molarity of .060 mol of #NaHCO_3# in 1500 mL of solution?

ad0caa36-6ddd-11ea-a7b2-ccda262736ce

https://socratic.org/questions/the-specific-heat-capacity-of-steel-is-420-j-kg-c-how-much-energy-is-required-to

8400.00 J

start physical_unit 4 4 energy j qc_end physical_unit 4 4 6 9 specific_heat qc_end physical_unit 4 4 17 18 mass qc_end physical_unit 4 4 22 23 temperature qc_end end

[{"type":"physical unit","value":"Required energy [OF] steel [IN] J"}]

[{"type":"physical unit","value":"8400.00 J"}]

[{"type":"physical unit","value":"specific heat [OF] steel [=] \\pu{420 J/(kg * ℃)}"},{"type":"physical unit","value":"Mass [OF] steel [=] \\pu{1 kg}"},{"type":"physical unit","value":"Raised temperature [OF] steel [=] \\pu{20 ℃}"}]

<h1 class="questionTitle" itemprop="name">The specific heat of steel is 420 J/(kg°C). How much energy is required to heat 1 kg of steel by 20 °C?</h1>

8400.00 J

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a></strong> of a substance tells you how much heat is required in order to heat <em>one unit of mass</em>, usually <mathjax>#"1 g"#</mathjax>, of that substance by <mathjax>#1^@"C"#</mathjax>. </p> <p>In this case, the specific heat of steel uses <mathjax>#"1 kg"#</mathjax> as the unit of mass, which means that the value given to you tells you how much heat is required in order to heat <mathjax>#"1 kg"#</mathjax> of steel by <mathjax>#1^@"C"#</mathjax>.</p> <p>Since you have</p> <blockquote> <p><mathjax>#c = "420 J kg"^(-1)""^@"C"^(-1)#</mathjax></p> </blockquote> <p>you can say that you need <mathjax>#"420 J"#</mathjax> of heat in order to increase the temperature of <mathjax>#"1 kg"#</mathjax> of steel by <mathjax>#1^@"C"#</mathjax>. </p> <p>This means that in order to increase the temperature of a given mass of steel by <mathjax>#20^@"C"#</mathjax>, you'd need</p> <blockquote> <p><mathjax>#20 color(red)(cancel(color(black)(""^@"C"))) * "420 J"/("1 kg" color(red)(cancel(color(black)(""^@"C")))) = "8400 J kg"^(-1)#</mathjax></p> </blockquote> <p>For <mathjax>#"1 kg"#</mathjax>, this gives you </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("kg"))) * "8400 J"/(1color(red)(cancel(color(black)("kg")))) = color(darkgreen)(ul(color(black)("8400 J")))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"8400 J"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a></strong> of a substance tells you how much heat is required in order to heat <em>one unit of mass</em>, usually <mathjax>#"1 g"#</mathjax>, of that substance by <mathjax>#1^@"C"#</mathjax>. </p> <p>In this case, the specific heat of steel uses <mathjax>#"1 kg"#</mathjax> as the unit of mass, which means that the value given to you tells you how much heat is required in order to heat <mathjax>#"1 kg"#</mathjax> of steel by <mathjax>#1^@"C"#</mathjax>.</p> <p>Since you have</p> <blockquote> <p><mathjax>#c = "420 J kg"^(-1)""^@"C"^(-1)#</mathjax></p> </blockquote> <p>you can say that you need <mathjax>#"420 J"#</mathjax> of heat in order to increase the temperature of <mathjax>#"1 kg"#</mathjax> of steel by <mathjax>#1^@"C"#</mathjax>. </p> <p>This means that in order to increase the temperature of a given mass of steel by <mathjax>#20^@"C"#</mathjax>, you'd need</p> <blockquote> <p><mathjax>#20 color(red)(cancel(color(black)(""^@"C"))) * "420 J"/("1 kg" color(red)(cancel(color(black)(""^@"C")))) = "8400 J kg"^(-1)#</mathjax></p> </blockquote> <p>For <mathjax>#"1 kg"#</mathjax>, this gives you </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("kg"))) * "8400 J"/(1color(red)(cancel(color(black)("kg")))) = color(darkgreen)(ul(color(black)("8400 J")))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">The specific heat of steel is 420 J/(kg°C). How much energy is required to heat 1 kg of steel by 20 °C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="361114" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-07T00:16:40" itemprop="dateCreated"> Jan 7, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"8400 J"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a></strong> of a substance tells you how much heat is required in order to heat <em>one unit of mass</em>, usually <mathjax>#"1 g"#</mathjax>, of that substance by <mathjax>#1^@"C"#</mathjax>. </p> <p>In this case, the specific heat of steel uses <mathjax>#"1 kg"#</mathjax> as the unit of mass, which means that the value given to you tells you how much heat is required in order to heat <mathjax>#"1 kg"#</mathjax> of steel by <mathjax>#1^@"C"#</mathjax>.</p> <p>Since you have</p> <blockquote> <p><mathjax>#c = "420 J kg"^(-1)""^@"C"^(-1)#</mathjax></p> </blockquote> <p>you can say that you need <mathjax>#"420 J"#</mathjax> of heat in order to increase the temperature of <mathjax>#"1 kg"#</mathjax> of steel by <mathjax>#1^@"C"#</mathjax>. </p> <p>This means that in order to increase the temperature of a given mass of steel by <mathjax>#20^@"C"#</mathjax>, you'd need</p> <blockquote> <p><mathjax>#20 color(red)(cancel(color(black)(""^@"C"))) * "420 J"/("1 kg" color(red)(cancel(color(black)(""^@"C")))) = "8400 J kg"^(-1)#</mathjax></p> </blockquote> <p>For <mathjax>#"1 kg"#</mathjax>, this gives you </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("kg"))) * "8400 J"/(1color(red)(cancel(color(black)("kg")))) = color(darkgreen)(ul(color(black)("8400 J")))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/361114" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? 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The specific heat of steel is 420 J/(kg°C). How much energy is required to heat 1 kg of steel by 20 °C?

abe9ebc0-6ddd-11ea-9be5-ccda262736ce

https://socratic.org/questions/56536bc311ef6b6da807790e

HNO3(aq) + NaOH(aq) -> NaNO3(aq) + H2O(l)

start chemical_equation qc_end substance 2 3 qc_end substance 6 7 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"HNO3(aq) + NaOH(aq) -> NaNO3(aq) + H2O(l)"}]

[{"type":"substance name","value":"Nitric acid"},{"type":"substance name","value":"Sodium hydroxide"}]

<h1 class="questionTitle" itemprop="name">How does nitric acid reaction with sodium hydroxide?</h1>

HNO3(aq) + NaOH(aq) -> NaNO3(aq) + H2O(l)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Acid + base yields a salt and water, as the above reaction signifies.</p> <p>Because it is 1:1 reaction (what do I mean here?), the quantity (the amount) of sodium hydroxide is precisely equal to the amount of nitric acid.</p> <p>Moles of nitric acid: <mathjax>#680 xx 10^(-3) cancel(L)xx0.640*molcancel(L^(-1))#</mathjax> <mathjax>#=#</mathjax> <mathjax>#???#</mathjax> <mathjax>#mol#</mathjax>. I included the units in the calculation, because if a calculation makes sense dimensionally (and here it did, I required an answer in <mathjax>#mol#</mathjax>), it is a good indication that I have set up the problem correctly. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#HNO_3(aq) + NaOH(aq) rarr NaNO_3(aq) + H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Acid + base yields a salt and water, as the above reaction signifies.</p> <p>Because it is 1:1 reaction (what do I mean here?), the quantity (the amount) of sodium hydroxide is precisely equal to the amount of nitric acid.</p> <p>Moles of nitric acid: <mathjax>#680 xx 10^(-3) cancel(L)xx0.640*molcancel(L^(-1))#</mathjax> <mathjax>#=#</mathjax> <mathjax>#???#</mathjax> <mathjax>#mol#</mathjax>. I included the units in the calculation, because if a calculation makes sense dimensionally (and here it did, I required an answer in <mathjax>#mol#</mathjax>), it is a good indication that I have set up the problem correctly. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How does nitric acid reaction with sodium hydroxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/neutralization" itemprop="url"> <span class="breadcrumb" itemprop="title">Neutralization</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="209314" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-07T08:51:43" itemprop="dateCreated"> Jan 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#HNO_3(aq) + NaOH(aq) rarr NaNO_3(aq) + H_2O(l)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Acid + base yields a salt and water, as the above reaction signifies.</p> <p>Because it is 1:1 reaction (what do I mean here?), the quantity (the amount) of sodium hydroxide is precisely equal to the amount of nitric acid.</p> <p>Moles of nitric acid: <mathjax>#680 xx 10^(-3) cancel(L)xx0.640*molcancel(L^(-1))#</mathjax> <mathjax>#=#</mathjax> <mathjax>#???#</mathjax> <mathjax>#mol#</mathjax>. I included the units in the calculation, because if a calculation makes sense dimensionally (and here it did, I required an answer in <mathjax>#mol#</mathjax>), it is a good indication that I have set up the problem correctly. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/209314" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-neutralization-reactions-useful"> How are neutralization reactions useful? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-neutralization-reactions-be-identified-symbolically"> How can neutralization reactions be identified symbolically? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-neutralization-reaction-differ-from-buffer"> How does neutralization reaction differ from using a buffer? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-acid-base-neutralization-reactions"> How do you do acid base neutralization reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-neutralization-reactions-produce-heat"> Why do neutralization reactions produce heat? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-neutralization-a-double-replacement-reaction"> Why is neutralization a double replacement reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-a-neutralization-reaction-exothermic"> Why is a neutralization reaction exothermic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-predict-and-balance-acid-base-reactions"> How do you predict the products in acid-base reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-determine-the-strength-of-sulfuric-acid"> How can you determine the strength of sulfuric acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-a-neutralisation-reaction-exothermic"> Why is a neutralisation reaction exothermic? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/reactions-in-solution/neutralization"> See all questions in Neutralization </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3046 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How does nitric acid reaction with sodium hydroxide?

a95efacb-6ddd-11ea-91d9-ccda262736ce

https://socratic.org/questions/for-the-reaction-2hno-3-mg-oh-2-mg-no-3-2-2h-2o-how-many-grams-of-magnesium-nitr

593.2 grams

start physical_unit 16 17 mass g qc_end chemical_equation 3 11 qc_end physical_unit 24 24 21 22 mole qc_end end

[{"type":"physical unit","value":"Mass [OF] magnesium nitrate [IN] grams"}]

[{"type":"physical unit","value":"593.2 grams"}]

[{"type":"chemical equation","value":"2 HNO3 + Mg(OH)2 -> Mg(NO3)2 + 2 H2O"},{"type":"physical unit","value":"Mole [OF] water [=] \\pu{8 moles}"}]

<h1 class="questionTitle" itemprop="name">For the reaction #2HNO_3 + Mg(OH)_2 -&gt; Mg(NO_3)_2 + 2H_2O#, how many grams of magnesium nitrate are produced from 8 moles of water?</h1>

593.2 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We can use <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> to find the moles of <mathjax>#Mg(NO_3)_2#</mathjax> and then the respective grams of <mathjax>#Mg(NO_3)_2#</mathjax>.</p> <p>If 8 moles of water are produced, we can find out how many moles of <mathjax>#Mg(NO_3)_2#</mathjax> are produced using this equation:</p> <p><mathjax>#(8 " "cancel("mol "H_2O))/1*(1 " mol " Mg(NO_3)_2)/(2" "cancel("mol "H_2O))=4" mol "Mg(NO_3)_2#</mathjax></p> <p>From here, we can use ratios to convert to the <em>grams</em> of <mathjax>#Mg(NO_3)_2#</mathjax>:</p> <p><mathjax>#(4 " "cancel("mol "Mg(NO_3)_2))/1*(148.3 " g " Mg(NO_3)_2)/(1 " "cancel("mol " Mg(NO_3)_2))=593.2 " g "Mg(NO_3)_2#</mathjax></p> <p>(You can get the molar mass of <mathjax>#Mg(NO_3)_2#</mathjax> by referencing a periodic table and summing the masses of each element in the compound.)</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#593.2 " g "Mg(NO_3)_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We can use <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> to find the moles of <mathjax>#Mg(NO_3)_2#</mathjax> and then the respective grams of <mathjax>#Mg(NO_3)_2#</mathjax>.</p> <p>If 8 moles of water are produced, we can find out how many moles of <mathjax>#Mg(NO_3)_2#</mathjax> are produced using this equation:</p> <p><mathjax>#(8 " "cancel("mol "H_2O))/1*(1 " mol " Mg(NO_3)_2)/(2" "cancel("mol "H_2O))=4" mol "Mg(NO_3)_2#</mathjax></p> <p>From here, we can use ratios to convert to the <em>grams</em> of <mathjax>#Mg(NO_3)_2#</mathjax>:</p> <p><mathjax>#(4 " "cancel("mol "Mg(NO_3)_2))/1*(148.3 " g " Mg(NO_3)_2)/(1 " "cancel("mol " Mg(NO_3)_2))=593.2 " g "Mg(NO_3)_2#</mathjax></p> <p>(You can get the molar mass of <mathjax>#Mg(NO_3)_2#</mathjax> by referencing a periodic table and summing the masses of each element in the compound.)</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">For the reaction #2HNO_3 + Mg(OH)_2 -&gt; Mg(NO_3)_2 + 2H_2O#, how many grams of magnesium nitrate are produced from 8 moles of water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="623934" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/rjsh"><img alt="" class="" src="https://profilepictures.socratic.org/HG7AXBKURJqe2lz1ijoI_0037.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/rjsh"> Daniel M </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-02T01:11:24" itemprop="dateCreated"> Jun 2, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#593.2 " g "Mg(NO_3)_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We can use <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> to find the moles of <mathjax>#Mg(NO_3)_2#</mathjax> and then the respective grams of <mathjax>#Mg(NO_3)_2#</mathjax>.</p> <p>If 8 moles of water are produced, we can find out how many moles of <mathjax>#Mg(NO_3)_2#</mathjax> are produced using this equation:</p> <p><mathjax>#(8 " "cancel("mol "H_2O))/1*(1 " mol " Mg(NO_3)_2)/(2" "cancel("mol "H_2O))=4" mol "Mg(NO_3)_2#</mathjax></p> <p>From here, we can use ratios to convert to the <em>grams</em> of <mathjax>#Mg(NO_3)_2#</mathjax>:</p> <p><mathjax>#(4 " "cancel("mol "Mg(NO_3)_2))/1*(148.3 " g " Mg(NO_3)_2)/(1 " "cancel("mol " Mg(NO_3)_2))=593.2 " g "Mg(NO_3)_2#</mathjax></p> <p>(You can get the molar mass of <mathjax>#Mg(NO_3)_2#</mathjax> by referencing a periodic table and summing the masses of each element in the compound.)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/623934" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179102bf3469517a1072"> Question #a1072 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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For the reaction #2HNO_3 + Mg(OH)_2 -&gt; Mg(NO_3)_2 + 2H_2O#, how many grams of magnesium nitrate are produced from 8 moles of water?

a984fb5c-6ddd-11ea-ae56-ccda262736ce

https://socratic.org/questions/a-buffer-solution-was-prepared-by-mixing-392-ml-of-0-301-m-naocl-and-181-ml-of-0

7.86

start physical_unit 24 25 ph none qc_end physical_unit 2 2 7 8 volume qc_end physical_unit 12 12 10 11 molarity qc_end physical_unit 2 2 14 15 volume qc_end physical_unit 19 19 17 18 molarity qc_end physical_unit 24 25 30 32 ka qc_end end

[{"type":"physical unit","value":"pH [OF] the solution"}]

[{"type":"physical unit","value":"7.86"}]

[{"type":"physical unit","value":"Volume [OF] NaClO solution [=] \\pu{392 mL}"},{"type":"physical unit","value":"Molarity [OF] NaClO solution [=] \\pu{0.301 M}"},{"type":"physical unit","value":"Volume [OF] HClO solution [=] \\pu{181 mL}"},{"type":"physical unit","value":"Molarity [OF] HClO solution [=] \\pu{0.281 M}"},{"type":"physical unit","value":"Ka [OF] the solution [=] \\pu{3.2 × 10^(-8)}"}]

<h1 class="questionTitle" itemprop="name">A buffer solution was prepared by mixing #"392 mL"# of #"0.301 M"# #"NaClO"# and #"181 mL"# of #"0.281 M"# #"HClO"#. Calculate the #"pH"# of the solution?</h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Given that <mathjax>#K_a = 3.2 * 10^(-8)#</mathjax>. Express the answer rounded to 3 decimal places.</p></div> </h2> </div> </div>

7.86

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with a weak acid - conjugate base buffer that has hypochlorous acid, <mathjax>#"HClO"#</mathjax>, as the weak acid and the hypochlorite anion, <mathjax>#"ClO"^(-)#</mathjax>, as its conjugate base. </p> <p>As you know, the <mathjax>#"pH"#</mathjax> of a weak acid - conjugate base buffer can be calculated using the <strong>Henderson - Hasselbalch equation</strong>.</p> <blockquote> <p><mathjax>#"pH" = "p"K_a + log ((["conjugate base"])/(["weak acid"]))#</mathjax></p> </blockquote> <p>Here</p> <blockquote> <p><mathjax>#"p"K_a = - log(K_a)#</mathjax></p> </blockquote> <p>Now, your goal here is to figure out the concentrations of the hypochlorous acid and of the hypochlorite anion <strong>after</strong> you mix the two <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>. </p> <p>Right from the start, you know that the volume of the resulting solution will be</p> <blockquote> <p><mathjax>#"392 mL + 181 mL = 573 mL"#</mathjax></p> </blockquote> <p>Now, use the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and the volume of the hypochlorous solution to calculate how many moles of the weak acid are present. </p> <blockquote> <p><mathjax>#181 color(red)(cancel(color(black)("mL solution"))) * "0.281 moles HClO"/(10^3color(red)(cancel(color(black)("mL solution")))) = "0.050861 moles HClO"#</mathjax></p> </blockquote> <p>Next, do the same for the sodium hypochlorite solution, which as you know, dissociates in a <mathjax>#1:1#</mathjax> mole ratio to produce hypochlorite anions. </p> <blockquote> <p><mathjax>#392 color(red)(cancel(color(black)("mL solution"))) * "0.301 moles ClO"^(-)/(10^3color(red)(cancel(color(black)("mL solution")))) = "0.11799 moles ClO"^(-)#</mathjax></p> </blockquote> <p>To calculate the concentrations of the two species <strong>after</strong> the two solutions are mixed, use the total volume of the solution--do not forget to convert it to <em>liters</em>!</p> <blockquote> <p><mathjax>#["HClO"] = "0.050861 moles"/(573 * 10^(-3) quad "L") = "0.08876 M"#</mathjax></p> <p><mathjax>#["ClO"^(-)] = "0.11799 moles"/(573 * 10^(-3) quad "L") = "0.2059 M"#</mathjax></p> </blockquote> <p>Plug your values into the Henderson - Hasselbalch equation to find the <mathjax>#"pH"#</mathjax> of the solution.</p> <blockquote> <p><mathjax>#"pH" = - log(3.2 * 10^(-8)) + log ( (0.2059 color(red)(cancel(color(black)("M"))))/(0.08876 color(red)(cancel(color(black)("M")))))#</mathjax></p> <p><mathjax>#color(darkgreen)(ul(color(black)("pH" = 7.860)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong>decimal places</strong>, the number of <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> you have for your values. </p> <p>Notice that the <mathjax>#"pH"#</mathjax> of the solution is <strong>higher</strong> than the <mathjax>#"p"K_a#</mathjax> of the weak acid, which happens because the buffer contains a higher concentration of the conjugate base than of the weak acid. </p> <p>When this happens, the <mathjax>#"pH"#</mathjax> of the buffer will be <strong>higher</strong> than the <mathjax>#"p"K_a#</mathjax> of the weak acid. Similarly, when a buffer contains a higher concentration of the weak acid than of the conjugate base, then the <mathjax>#"pH"#</mathjax> of the buffer will be <strong>lower</strong> than the <mathjax>#"p"K_a#</mathjax> of the weak acid. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 7.860#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with a weak acid - conjugate base buffer that has hypochlorous acid, <mathjax>#"HClO"#</mathjax>, as the weak acid and the hypochlorite anion, <mathjax>#"ClO"^(-)#</mathjax>, as its conjugate base. </p> <p>As you know, the <mathjax>#"pH"#</mathjax> of a weak acid - conjugate base buffer can be calculated using the <strong>Henderson - Hasselbalch equation</strong>.</p> <blockquote> <p><mathjax>#"pH" = "p"K_a + log ((["conjugate base"])/(["weak acid"]))#</mathjax></p> </blockquote> <p>Here</p> <blockquote> <p><mathjax>#"p"K_a = - log(K_a)#</mathjax></p> </blockquote> <p>Now, your goal here is to figure out the concentrations of the hypochlorous acid and of the hypochlorite anion <strong>after</strong> you mix the two <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>. </p> <p>Right from the start, you know that the volume of the resulting solution will be</p> <blockquote> <p><mathjax>#"392 mL + 181 mL = 573 mL"#</mathjax></p> </blockquote> <p>Now, use the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and the volume of the hypochlorous solution to calculate how many moles of the weak acid are present. </p> <blockquote> <p><mathjax>#181 color(red)(cancel(color(black)("mL solution"))) * "0.281 moles HClO"/(10^3color(red)(cancel(color(black)("mL solution")))) = "0.050861 moles HClO"#</mathjax></p> </blockquote> <p>Next, do the same for the sodium hypochlorite solution, which as you know, dissociates in a <mathjax>#1:1#</mathjax> mole ratio to produce hypochlorite anions. </p> <blockquote> <p><mathjax>#392 color(red)(cancel(color(black)("mL solution"))) * "0.301 moles ClO"^(-)/(10^3color(red)(cancel(color(black)("mL solution")))) = "0.11799 moles ClO"^(-)#</mathjax></p> </blockquote> <p>To calculate the concentrations of the two species <strong>after</strong> the two solutions are mixed, use the total volume of the solution--do not forget to convert it to <em>liters</em>!</p> <blockquote> <p><mathjax>#["HClO"] = "0.050861 moles"/(573 * 10^(-3) quad "L") = "0.08876 M"#</mathjax></p> <p><mathjax>#["ClO"^(-)] = "0.11799 moles"/(573 * 10^(-3) quad "L") = "0.2059 M"#</mathjax></p> </blockquote> <p>Plug your values into the Henderson - Hasselbalch equation to find the <mathjax>#"pH"#</mathjax> of the solution.</p> <blockquote> <p><mathjax>#"pH" = - log(3.2 * 10^(-8)) + log ( (0.2059 color(red)(cancel(color(black)("M"))))/(0.08876 color(red)(cancel(color(black)("M")))))#</mathjax></p> <p><mathjax>#color(darkgreen)(ul(color(black)("pH" = 7.860)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong>decimal places</strong>, the number of <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> you have for your values. </p> <p>Notice that the <mathjax>#"pH"#</mathjax> of the solution is <strong>higher</strong> than the <mathjax>#"p"K_a#</mathjax> of the weak acid, which happens because the buffer contains a higher concentration of the conjugate base than of the weak acid. </p> <p>When this happens, the <mathjax>#"pH"#</mathjax> of the buffer will be <strong>higher</strong> than the <mathjax>#"p"K_a#</mathjax> of the weak acid. Similarly, when a buffer contains a higher concentration of the weak acid than of the conjugate base, then the <mathjax>#"pH"#</mathjax> of the buffer will be <strong>lower</strong> than the <mathjax>#"p"K_a#</mathjax> of the weak acid. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A buffer solution was prepared by mixing #"392 mL"# of #"0.301 M"# #"NaClO"# and #"181 mL"# of #"0.281 M"# #"HClO"#. Calculate the #"pH"# of the solution?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Given that <mathjax>#K_a = 3.2 * 10^(-8)#</mathjax>. Express the answer rounded to 3 decimal places.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/buffer-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Buffer Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="586051" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-03-31T23:50:40" itemprop="dateCreated"> Mar 31, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 7.860#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with a weak acid - conjugate base buffer that has hypochlorous acid, <mathjax>#"HClO"#</mathjax>, as the weak acid and the hypochlorite anion, <mathjax>#"ClO"^(-)#</mathjax>, as its conjugate base. </p> <p>As you know, the <mathjax>#"pH"#</mathjax> of a weak acid - conjugate base buffer can be calculated using the <strong>Henderson - Hasselbalch equation</strong>.</p> <blockquote> <p><mathjax>#"pH" = "p"K_a + log ((["conjugate base"])/(["weak acid"]))#</mathjax></p> </blockquote> <p>Here</p> <blockquote> <p><mathjax>#"p"K_a = - log(K_a)#</mathjax></p> </blockquote> <p>Now, your goal here is to figure out the concentrations of the hypochlorous acid and of the hypochlorite anion <strong>after</strong> you mix the two <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>. </p> <p>Right from the start, you know that the volume of the resulting solution will be</p> <blockquote> <p><mathjax>#"392 mL + 181 mL = 573 mL"#</mathjax></p> </blockquote> <p>Now, use the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and the volume of the hypochlorous solution to calculate how many moles of the weak acid are present. </p> <blockquote> <p><mathjax>#181 color(red)(cancel(color(black)("mL solution"))) * "0.281 moles HClO"/(10^3color(red)(cancel(color(black)("mL solution")))) = "0.050861 moles HClO"#</mathjax></p> </blockquote> <p>Next, do the same for the sodium hypochlorite solution, which as you know, dissociates in a <mathjax>#1:1#</mathjax> mole ratio to produce hypochlorite anions. </p> <blockquote> <p><mathjax>#392 color(red)(cancel(color(black)("mL solution"))) * "0.301 moles ClO"^(-)/(10^3color(red)(cancel(color(black)("mL solution")))) = "0.11799 moles ClO"^(-)#</mathjax></p> </blockquote> <p>To calculate the concentrations of the two species <strong>after</strong> the two solutions are mixed, use the total volume of the solution--do not forget to convert it to <em>liters</em>!</p> <blockquote> <p><mathjax>#["HClO"] = "0.050861 moles"/(573 * 10^(-3) quad "L") = "0.08876 M"#</mathjax></p> <p><mathjax>#["ClO"^(-)] = "0.11799 moles"/(573 * 10^(-3) quad "L") = "0.2059 M"#</mathjax></p> </blockquote> <p>Plug your values into the Henderson - Hasselbalch equation to find the <mathjax>#"pH"#</mathjax> of the solution.</p> <blockquote> <p><mathjax>#"pH" = - log(3.2 * 10^(-8)) + log ( (0.2059 color(red)(cancel(color(black)("M"))))/(0.08876 color(red)(cancel(color(black)("M")))))#</mathjax></p> <p><mathjax>#color(darkgreen)(ul(color(black)("pH" = 7.860)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong>decimal places</strong>, the number of <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> you have for your values. </p> <p>Notice that the <mathjax>#"pH"#</mathjax> of the solution is <strong>higher</strong> than the <mathjax>#"p"K_a#</mathjax> of the weak acid, which happens because the buffer contains a higher concentration of the conjugate base than of the weak acid. </p> <p>When this happens, the <mathjax>#"pH"#</mathjax> of the buffer will be <strong>higher</strong> than the <mathjax>#"p"K_a#</mathjax> of the weak acid. Similarly, when a buffer contains a higher concentration of the weak acid than of the conjugate base, then the <mathjax>#"pH"#</mathjax> of the buffer will be <strong>lower</strong> than the <mathjax>#"p"K_a#</mathjax> of the weak acid. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/586051" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-buffer-solutions-used"> How are buffer solutions used? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-buffer-capacity"> How do you calculate buffer capacity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-buffer-solutions-maintain-the-ph-of-blood"> How do buffer solutions maintain the pH of blood? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-buffer-a-solution-with-a-ph-of-12"> How do you buffer a solution with a pH of 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-buffer-solutions-used-to-calibrate-ph"> Why are buffer solutions used to calibrate pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is--solution-used-in-complexometric-titration"> What is the role of buffer solution in complexometric titrations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-you-would-make-100-0-ml-of-a-bu-er-solution-with-a-ph-of-10-80-to-be-made-us"> How you would make 100.0 ml of a 1.00 mol/L buffer solution with a pH of 10.80 to be made using... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-henderson-hasselbalch-equation"> What is the Henderson-Hasselbalch equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-ph-buffer-calculation-problem"> What is an example of a pH buffer calculation problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-bicarbonate-buffering-system-important"> Why is the bicarbonate buffering system important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/reactions-in-solution/buffer-calculations"> See all questions in Buffer Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 21154 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A buffer solution was prepared by mixing #"392 mL"# of #"0.301 M"# #"NaClO"# and #"181 mL"# of #"0.281 M"# #"HClO"#. Calculate the #"pH"# of the solution?

Given that #K_a = 3.2 * 10^(-8)#. Express the answer rounded to 3 decimal places.

a8d7345d-6ddd-11ea-b20b-ccda262736ce

https://socratic.org/questions/583c4b8e11ef6b5fc8d1938e

7.4 L

start physical_unit 8 9 volume l qc_end physical_unit 8 9 4 5 mass qc_end physical_unit 8 9 16 17 pressure qc_end physical_unit 8 9 19 20 temperature qc_end end

[{"type":"physical unit","value":"Volume [OF] carbon monoxide [IN] L"}]

[{"type":"physical unit","value":"7.4 L"}]

[{"type":"physical unit","value":"Mass [OF] carbon monoxide [=] \\pu{10 g}"},{"type":"physical unit","value":"Pressure [OF] carbon monoxide [=] \\pu{1 atm}"},{"type":"physical unit","value":"Temperature [OF] carbon monoxide [=] \\pu{0 ℃}"}]

<h1 class="questionTitle" itemprop="name">What volume would a #10*g# mass of carbon monoxide enclosed in a piston occupy at #1*atm#, and #0# #""^@C#?</h1>

7.4 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So, we have <mathjax>#(10*g)/(28.01*g*mol)~=1/3*"mole"#</mathjax>.</p> <p>And thus if we assume carbon monoxide behaves ideally, its volume (if enclosed in a piston expanding against atmospheric pressure) would be approx. <mathjax>#7.4*L#</mathjax>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, one mole of ideal gas occupies <a href="http://www.chemteam.info/GasLaw/MolarVolume.html" rel="nofollow">22.4 L</a>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So, we have <mathjax>#(10*g)/(28.01*g*mol)~=1/3*"mole"#</mathjax>.</p> <p>And thus if we assume carbon monoxide behaves ideally, its volume (if enclosed in a piston expanding against atmospheric pressure) would be approx. <mathjax>#7.4*L#</mathjax>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What volume would a #10*g# mass of carbon monoxide enclosed in a piston occupy at #1*atm#, and #0# #""^@C#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="343235" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-28T16:10:54" itemprop="dateCreated"> Nov 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, one mole of ideal gas occupies <a href="http://www.chemteam.info/GasLaw/MolarVolume.html" rel="nofollow">22.4 L</a>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So, we have <mathjax>#(10*g)/(28.01*g*mol)~=1/3*"mole"#</mathjax>.</p> <p>And thus if we assume carbon monoxide behaves ideally, its volume (if enclosed in a piston expanding against atmospheric pressure) would be approx. <mathjax>#7.4*L#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/343235" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="343553" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/suresh-rawal"><img alt="" class="" src="https://profilepictures.socratic.org/xtD9rRMRMOIMqQl8Irg3_scan0002.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/suresh-rawal"> Suresh Rawal </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-29T04:34:22" itemprop="dateCreated"> Nov 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>8.00 Liter</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It can be further explained as :-</p> <p>idle gas equation is </p> <p><mathjax>#PV=nRT#</mathjax></p> <p>Here ,</p> <p>P = 1 atm<br/> V = To be find out<br/> R = 0.08206 Universal Gas constant <br/> T = 273 k<br/> <mathjax>#n = m/M#</mathjax><br/> m = mass of gas [g], given 10 g <br/> M = mass of 1 mole of gas [g] that is 28.01 of CO</p> <p>By putting all values -</p> <p><mathjax># 1*V=10/28.01*0.08206*273#</mathjax><br/> or<br/> <mathjax>#V = 24.238/28.01#</mathjax><br/> or<br/> V = 8.00</p> <p>Hence Answer is 8.00 Liter Volume </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/343553" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? 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What volume would a #10*g# mass of carbon monoxide enclosed in a piston occupy at #1*atm#, and #0# #""^@C#?

a967b6a6-6ddd-11ea-9002-ccda262736ce

https://socratic.org/questions/how-do-you-calculate-the-percentage-composition-of-iodine-in-ni-3-1

32.15%

start physical_unit 8 10 percent_composition none qc_end chemical_equation 10 10 qc_end end

[{"type":"physical unit","value":"Percentage composition [OF] Iodine in NI3"}]

[{"type":"physical unit","value":"32.15%"}]

[{"type":"chemical equation","value":"NI3"}]

<h1 class="questionTitle" itemprop="name">How do you calculate the percentage composition of Iodine in #NI_3#?</h1>

32.15%

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to calculate the percent composition of an element in a compound, you need to divide the molar mass (MM) of the element by the MM of the compound then multiply by 100.</p> <p><mathjax>#%"composition of element"=("MM of element")/("MM of compound")xx100#</mathjax></p> <p><mathjax>#"MM of Iodine=126.90447 g/mol"#</mathjax><br/> <a href="https://en.m.wikipedia.org/wiki/Iodine" rel="nofollow" target="_blank">https://en.m.wikipedia.org/wiki/Iodine</a></p> <p><mathjax>#"MM of NI"_3="394.719 g/mol"#</mathjax><br/> <a href="https://en.m.wikipedia.org/wiki/Nitrogen_triiodide" rel="nofollow" target="_blank">https://en.m.wikipedia.org/wiki/Nitrogen_triiodide</a></p> <p><strong>Percent Composition of Iodine in Nitrogen Triiodide</strong></p> <p><mathjax>#%"composition I"=(126.90447 cancel"g/mol")/(394.719 cancel"g/mol")xx100="32.1506%"~~32%"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of iodine in nitrogen triioxide is <mathjax>#32.1506%~~32%"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to calculate the percent composition of an element in a compound, you need to divide the molar mass (MM) of the element by the MM of the compound then multiply by 100.</p> <p><mathjax>#%"composition of element"=("MM of element")/("MM of compound")xx100#</mathjax></p> <p><mathjax>#"MM of Iodine=126.90447 g/mol"#</mathjax><br/> <a href="https://en.m.wikipedia.org/wiki/Iodine" rel="nofollow" target="_blank">https://en.m.wikipedia.org/wiki/Iodine</a></p> <p><mathjax>#"MM of NI"_3="394.719 g/mol"#</mathjax><br/> <a href="https://en.m.wikipedia.org/wiki/Nitrogen_triiodide" rel="nofollow" target="_blank">https://en.m.wikipedia.org/wiki/Nitrogen_triiodide</a></p> <p><strong>Percent Composition of Iodine in Nitrogen Triiodide</strong></p> <p><mathjax>#%"composition I"=(126.90447 cancel"g/mol")/(394.719 cancel"g/mol")xx100="32.1506%"~~32%"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you calculate the percentage composition of Iodine in #NI_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/percent-composition" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Composition</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="232499" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-28T13:25:58" itemprop="dateCreated"> Feb 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of iodine in nitrogen triioxide is <mathjax>#32.1506%~~32%"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to calculate the percent composition of an element in a compound, you need to divide the molar mass (MM) of the element by the MM of the compound then multiply by 100.</p> <p><mathjax>#%"composition of element"=("MM of element")/("MM of compound")xx100#</mathjax></p> <p><mathjax>#"MM of Iodine=126.90447 g/mol"#</mathjax><br/> <a href="https://en.m.wikipedia.org/wiki/Iodine" rel="nofollow" target="_blank">https://en.m.wikipedia.org/wiki/Iodine</a></p> <p><mathjax>#"MM of NI"_3="394.719 g/mol"#</mathjax><br/> <a href="https://en.m.wikipedia.org/wiki/Nitrogen_triiodide" rel="nofollow" target="_blank">https://en.m.wikipedia.org/wiki/Nitrogen_triiodide</a></p> <p><strong>Percent Composition of Iodine in Nitrogen Triiodide</strong></p> <p><mathjax>#%"composition I"=(126.90447 cancel"g/mol")/(394.719 cancel"g/mol")xx100="32.1506%"~~32%"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/232499" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-mole-percent"> What is mole percent? 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How do you calculate the percentage composition of Iodine in #NI_3#?

a99509c0-6ddd-11ea-ab42-ccda262736ce

https://socratic.org/questions/an-ionic-compound-forms-when-calcium-reacts-with-iodine-if-the-sample-contains-7

1.48 × 10^22

start physical_unit 19 20 number none qc_end physical_unit 15 16 13 14 number qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Number [OF] iodide ions"}]

[{"type":"physical unit","value":"1.48 × 10^22"}]

[{"type":"physical unit","value":"Number [OF] calcium ions [=] \\pu{7.4× 10^21}"},{"type":"other","value":"An ionic compound forms when calcium reacts with iodine."}]

<h1 class="questionTitle" itemprop="name">An ionic compound forms when calcium reacts with iodine. If the sample contains #7.4 xx 10^21# calcium ions, how many iodide ions does it contain?</h1>

1.48 × 10^22

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Calcium metal has 2 <a href="https://socratic.org/chemistry/the-periodic-table/valence-electrons-and-the-periodic-table">valence electrons</a>. It readily forms a <mathjax>#Ca^(2+)#</mathjax> ion. Because iodine readily forms a uninegative ion, <mathjax>#I^-#</mathjax>, a neutral salt will form with composition <mathjax>#CaI_2#</mathjax>.</p> <p>Is the following a redox reaction?</p> <p><mathjax>#Ca(g) + I_2(g) rarr CaI_2(s)#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>It must contain <mathjax>#14.8xx10^21#</mathjax> iodide ions. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Calcium metal has 2 <a href="https://socratic.org/chemistry/the-periodic-table/valence-electrons-and-the-periodic-table">valence electrons</a>. It readily forms a <mathjax>#Ca^(2+)#</mathjax> ion. Because iodine readily forms a uninegative ion, <mathjax>#I^-#</mathjax>, a neutral salt will form with composition <mathjax>#CaI_2#</mathjax>.</p> <p>Is the following a redox reaction?</p> <p><mathjax>#Ca(g) + I_2(g) rarr CaI_2(s)#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">An ionic compound forms when calcium reacts with iodine. If the sample contains #7.4 xx 10^21# calcium ions, how many iodide ions does it contain?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/ionic-compounds" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Compounds</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="306358" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-05T12:06:16" itemprop="dateCreated"> Sep 5, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>It must contain <mathjax>#14.8xx10^21#</mathjax> iodide ions. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Calcium metal has 2 <a href="https://socratic.org/chemistry/the-periodic-table/valence-electrons-and-the-periodic-table">valence electrons</a>. It readily forms a <mathjax>#Ca^(2+)#</mathjax> ion. Because iodine readily forms a uninegative ion, <mathjax>#I^-#</mathjax>, a neutral salt will form with composition <mathjax>#CaI_2#</mathjax>.</p> <p>Is the following a redox reaction?</p> <p><mathjax>#Ca(g) + I_2(g) rarr CaI_2(s)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/306358" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151302bf34732c779c2f"> Question #79c2f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151302bf3473360cd842"> Question #cd842 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151702bf34733dc14e7e"> Why do ionic compounds dissolve in water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151b02bf3473394975aa"> Question #975aa </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151b02bf3473394975ae"> Question #975ae </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151e02bf34733e367e72"> Question #67e72 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/532eff8902bf341e776bd809"> What do the terms anhydrous, hydrous, and undissociated mean? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-ionic-compounds"> What are ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-identify-ionic-compounds"> How can I identify ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-ionic-compounds-solid-at-a-room-temperature"> Why are ionic compounds solid at room temperature? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/ionic-compounds"> See all questions in Ionic Compounds </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11268 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

An ionic compound forms when calcium reacts with iodine. If the sample contains #7.4 xx 10^21# calcium ions, how many iodide ions does it contain?

a8f705a6-6ddd-11ea-afbc-ccda262736ce

https://socratic.org/questions/carbon-disulfide-cs2-can-be-made-from-coke-c-and-sulfur-dioxide-so2-3c-2-so2-cs2

523 g

start physical_unit 7 7 mass g qc_end chemical_equation 13 21 qc_end physical_unit 2 2 42 43 mass qc_end end

[{"type":"physical unit","value":"Mass [OF] coke [IN] g"}]

[{"type":"physical unit","value":"523 g"}]

[{"type":"physical unit","value":"Actual yield [OF] CS2 of the theoretical yield [=] \\pu{86%}"},{"type":"chemical equation","value":"3 C + 2 SO2 -> CS2 + CO2"},{"type":"physical unit","value":"Mass [OF] CS2 [=] \\pu{950 g}"}]

<h1 class="questionTitle" itemprop="name">Carbon disulfide, CS2 can be made from coke, C and sulfur dioxide, SO2: 3C + 2 SO2→ CS2 + CO2. If the actual yield of CS2 is 86% of the theoretical yield, what mass of coke is needed to produce 950g of CS2?</h1>

523 g

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since <mathjax>#950#</mathjax> <mathjax>#"g"#</mathjax> is the desired mass of <mathjax>#"CS"_2#</mathjax>, and the <a href="https://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a> is <mathjax>#86%#</mathjax>, the <em>theoretical yield</em> of <mathjax>#"CS"_2#</mathjax> is</p> <p><mathjax>#950#</mathjax> <mathjax>#"g CS"_2"#</mathjax> <mathjax>#xx 100/86 = ul(1107color(white)(l)"g CS"_2#</mathjax></p> <blockquote></blockquote> <p>Now, let's convert this value to <em>moles</em>, using the <strong>molar mass</strong> of carbon disulfide:</p> <p><mathjax>#1107cancel("g CS"_2)((1color(white)(l)"mol CS"_2)/(76.14cancel("g CS"_2))) = color(red)(14.5#</mathjax> <mathjax>#color(red)("mol CS"_2#</mathjax></p> <blockquote></blockquote> <p>Now, we use the coefficients of the chemical equation to find the relative number of moles of <mathjax>#"C"#</mathjax>:</p> <p><mathjax>#color(red)(14.5)cancel(color(red)("mol CS"_2))((3color(white)(l)"mol C")/(1cancel("mol CS"_2))) = color(green)(43.5#</mathjax> <mathjax>#color(green)("mol C"#</mathjax></p> <blockquote></blockquote> <p>Finally, we use the molar mass of coke (carbon) to find the mass:</p> <p><mathjax>#color(green)(43.5)cancel(color(green)("mol C"))((12.011color(white)(l)"g C")/(1cancel("mol C"))) = color(blue)(ul(523color(white)(l)"g C"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#523#</mathjax> <mathjax>#"g C"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since <mathjax>#950#</mathjax> <mathjax>#"g"#</mathjax> is the desired mass of <mathjax>#"CS"_2#</mathjax>, and the <a href="https://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a> is <mathjax>#86%#</mathjax>, the <em>theoretical yield</em> of <mathjax>#"CS"_2#</mathjax> is</p> <p><mathjax>#950#</mathjax> <mathjax>#"g CS"_2"#</mathjax> <mathjax>#xx 100/86 = ul(1107color(white)(l)"g CS"_2#</mathjax></p> <blockquote></blockquote> <p>Now, let's convert this value to <em>moles</em>, using the <strong>molar mass</strong> of carbon disulfide:</p> <p><mathjax>#1107cancel("g CS"_2)((1color(white)(l)"mol CS"_2)/(76.14cancel("g CS"_2))) = color(red)(14.5#</mathjax> <mathjax>#color(red)("mol CS"_2#</mathjax></p> <blockquote></blockquote> <p>Now, we use the coefficients of the chemical equation to find the relative number of moles of <mathjax>#"C"#</mathjax>:</p> <p><mathjax>#color(red)(14.5)cancel(color(red)("mol CS"_2))((3color(white)(l)"mol C")/(1cancel("mol CS"_2))) = color(green)(43.5#</mathjax> <mathjax>#color(green)("mol C"#</mathjax></p> <blockquote></blockquote> <p>Finally, we use the molar mass of coke (carbon) to find the mass:</p> <p><mathjax>#color(green)(43.5)cancel(color(green)("mol C"))((12.011color(white)(l)"g C")/(1cancel("mol C"))) = color(blue)(ul(523color(white)(l)"g C"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Carbon disulfide, CS2 can be made from coke, C and sulfur dioxide, SO2: 3C + 2 SO2→ CS2 + CO2. If the actual yield of CS2 is 86% of the theoretical yield, what mass of coke is needed to produce 950g of CS2?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/percent-yield" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Yield</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="458251" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-31T01:23:20" itemprop="dateCreated"> Jul 31, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#523#</mathjax> <mathjax>#"g C"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since <mathjax>#950#</mathjax> <mathjax>#"g"#</mathjax> is the desired mass of <mathjax>#"CS"_2#</mathjax>, and the <a href="https://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a> is <mathjax>#86%#</mathjax>, the <em>theoretical yield</em> of <mathjax>#"CS"_2#</mathjax> is</p> <p><mathjax>#950#</mathjax> <mathjax>#"g CS"_2"#</mathjax> <mathjax>#xx 100/86 = ul(1107color(white)(l)"g CS"_2#</mathjax></p> <blockquote></blockquote> <p>Now, let's convert this value to <em>moles</em>, using the <strong>molar mass</strong> of carbon disulfide:</p> <p><mathjax>#1107cancel("g CS"_2)((1color(white)(l)"mol CS"_2)/(76.14cancel("g CS"_2))) = color(red)(14.5#</mathjax> <mathjax>#color(red)("mol CS"_2#</mathjax></p> <blockquote></blockquote> <p>Now, we use the coefficients of the chemical equation to find the relative number of moles of <mathjax>#"C"#</mathjax>:</p> <p><mathjax>#color(red)(14.5)cancel(color(red)("mol CS"_2))((3color(white)(l)"mol C")/(1cancel("mol CS"_2))) = color(green)(43.5#</mathjax> <mathjax>#color(green)("mol C"#</mathjax></p> <blockquote></blockquote> <p>Finally, we use the molar mass of coke (carbon) to find the mass:</p> <p><mathjax>#color(green)(43.5)cancel(color(green)("mol C"))((12.011color(white)(l)"g C")/(1cancel("mol C"))) = color(blue)(ul(523color(white)(l)"g C"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/458251" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ebd02bf3469570e2e62"> Question #e2e62 </a> </div> </li> <li class="relatedQuestionItem"> 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Carbon disulfide, CS2 can be made from coke, C and sulfur dioxide, SO2: 3C + 2 SO2→ CS2 + CO2. If the actual yield of CS2 is 86% of the theoretical yield, what mass of coke is needed to produce 950g of CS2?

abcc2c4c-6ddd-11ea-b688-ccda262736ce

https://socratic.org/questions/how-many-cl-ions-are-there-in-584-6-grams-of-alcl-3

7.92 × 10^24

start physical_unit 2 3 number none qc_end physical_unit 10 10 7 8 mass qc_end end

[{"type":"physical unit","value":"Number [OF] Cl- ions"}]

[{"type":"physical unit","value":"7.92 × 10^24"}]

[{"type":"physical unit","value":"Mass [OF] AlCl3 [=] \\pu{584.6 grams}"}]

<h1 class="questionTitle" itemprop="name">How many #Cl^(-)# ions are there in 584.6 grams of #AlCl_3#?</h1>

7.92 × 10^24

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so we (i) assess the molar quantity of aluminum chloride, <mathjax>#=(584.6*g)/(133.34*g*mol^-1)=4.38*mol#</mathjax>...</p> <p>And (ii) we multiply this molar quantity by factors of THREE and Avogadro's number to get the number of chloride ligands...</p> <p><mathjax>#=13.15*molxx"avocado number"#</mathjax></p> <p><mathjax>#13.15*molxx6.022xx10^23*mol^-1=7.92xx10^24*"chlorides"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, formally there are 3 moles of chloride per mole of aluminum chloride..</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so we (i) assess the molar quantity of aluminum chloride, <mathjax>#=(584.6*g)/(133.34*g*mol^-1)=4.38*mol#</mathjax>...</p> <p>And (ii) we multiply this molar quantity by factors of THREE and Avogadro's number to get the number of chloride ligands...</p> <p><mathjax>#=13.15*molxx"avocado number"#</mathjax></p> <p><mathjax>#13.15*molxx6.022xx10^23*mol^-1=7.92xx10^24*"chlorides"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many #Cl^(-)# ions are there in 584.6 grams of #AlCl_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="529713" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-01-03T10:09:10" itemprop="dateCreated"> Jan 3, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, formally there are 3 moles of chloride per mole of aluminum chloride..</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so we (i) assess the molar quantity of aluminum chloride, <mathjax>#=(584.6*g)/(133.34*g*mol^-1)=4.38*mol#</mathjax>...</p> <p>And (ii) we multiply this molar quantity by factors of THREE and Avogadro's number to get the number of chloride ligands...</p> <p><mathjax>#=13.15*molxx"avocado number"#</mathjax></p> <p><mathjax>#13.15*molxx6.022xx10^23*mol^-1=7.92xx10^24*"chlorides"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/529713" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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How many #Cl^(-)# ions are there in 584.6 grams of #AlCl_3#?

abea2224-6ddd-11ea-82fa-ccda262736ce

https://socratic.org/questions/a-55-0-g-aluminum-block-initially-at-27-5-c-absorbs-725-j-of-heat-what-is-the-fi

42.14 ℃

start physical_unit 20 21 temperature °c qc_end physical_unit 3 4 1 2 mass qc_end physical_unit 3 4 7 8 temperature qc_end physical_unit 3 4 10 11 heat_energy qc_end end

[{"type":"physical unit","value":"Temperature2 [OF] the aluminum [IN] ℃"}]

[{"type":"physical unit","value":"42.14 ℃"}]

[{"type":"physical unit","value":"Mass [OF] aluminum block [=] \\pu{55.0 g}"},{"type":"physical unit","value":"Temperature1 [OF] aluminum block [=] \\pu{27.5 ℃}"},{"type":"physical unit","value":"Absorbed heat [OF] aluminum block [=] \\pu{725 J}"}]

<h1 class="questionTitle" itemprop="name">A 55.0-g aluminum block initially at 27.5 C absorbs 725 J of heat. What is the final temperature of the aluminum?</h1>

42.14 ℃

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Q=mc∆T#</mathjax></p> <p>This means that the amount of energy produced is equal to the mass of the system multiplied by its change of temperature and multiplied by its <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a>. </p> <blockquote></blockquote> <p>LET'S PUT IN WHAT WE KNOW!!!</p> <p><mathjax>#Q ="725 J"#</mathjax></p> <p><mathjax>#m="55.0 g"#</mathjax></p> <p><mathjax>#c = "0.900 J/(°C·g)"#</mathjax></p> <p><mathjax>#∆T = "final temperature - initial temperature"#</mathjax></p> <p><mathjax>#∆T = (x-27.5) " °C"#</mathjax></p> <blockquote></blockquote> <p>We solve for <mathjax>#∆T#</mathjax>.</p> <p><mathjax>#"725 J" = "55.0 g"*"0.900 J/(°C·g)"(x-27.5) " °C"#</mathjax></p> <blockquote></blockquote> <p>NOW IT'S JUST BASIC ALGREBRA </p> <p><mathjax>#725 = 49.5x-1361#</mathjax></p> <p><mathjax>#2086=49.5x#</mathjax></p> <p><mathjax>#42.1 = x#</mathjax></p> <p>The final temperature is 42.1 °C.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final temperature of aluminum is 42.1 °C.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Q=mc∆T#</mathjax></p> <p>This means that the amount of energy produced is equal to the mass of the system multiplied by its change of temperature and multiplied by its <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a>. </p> <blockquote></blockquote> <p>LET'S PUT IN WHAT WE KNOW!!!</p> <p><mathjax>#Q ="725 J"#</mathjax></p> <p><mathjax>#m="55.0 g"#</mathjax></p> <p><mathjax>#c = "0.900 J/(°C·g)"#</mathjax></p> <p><mathjax>#∆T = "final temperature - initial temperature"#</mathjax></p> <p><mathjax>#∆T = (x-27.5) " °C"#</mathjax></p> <blockquote></blockquote> <p>We solve for <mathjax>#∆T#</mathjax>.</p> <p><mathjax>#"725 J" = "55.0 g"*"0.900 J/(°C·g)"(x-27.5) " °C"#</mathjax></p> <blockquote></blockquote> <p>NOW IT'S JUST BASIC ALGREBRA </p> <p><mathjax>#725 = 49.5x-1361#</mathjax></p> <p><mathjax>#2086=49.5x#</mathjax></p> <p><mathjax>#42.1 = x#</mathjax></p> <p>The final temperature is 42.1 °C.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A 55.0-g aluminum block initially at 27.5 C absorbs 725 J of heat. What is the final temperature of the aluminum?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/energy-change-in-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Energy Change in Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="343749" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/david-h-8"><img alt="" class="" src="https://lh3.googleusercontent.com/-tmIn95xDlyU/AAAAAAAAAAI/AAAAAAAAAAA/MWeA6xrQHF0/photo.jpg?sz=50" title=""/></a> <a class="secondContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/david-h-8"> David H. </a>·<a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-29T13:04:40" itemprop="dateCreated"> Nov 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final temperature of aluminum is 42.1 °C.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Q=mc∆T#</mathjax></p> <p>This means that the amount of energy produced is equal to the mass of the system multiplied by its change of temperature and multiplied by its <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a>. </p> <blockquote></blockquote> <p>LET'S PUT IN WHAT WE KNOW!!!</p> <p><mathjax>#Q ="725 J"#</mathjax></p> <p><mathjax>#m="55.0 g"#</mathjax></p> <p><mathjax>#c = "0.900 J/(°C·g)"#</mathjax></p> <p><mathjax>#∆T = "final temperature - initial temperature"#</mathjax></p> <p><mathjax>#∆T = (x-27.5) " °C"#</mathjax></p> <blockquote></blockquote> <p>We solve for <mathjax>#∆T#</mathjax>.</p> <p><mathjax>#"725 J" = "55.0 g"*"0.900 J/(°C·g)"(x-27.5) " °C"#</mathjax></p> <blockquote></blockquote> <p>NOW IT'S JUST BASIC ALGREBRA </p> <p><mathjax>#725 = 49.5x-1361#</mathjax></p> <p><mathjax>#2086=49.5x#</mathjax></p> <p><mathjax>#42.1 = x#</mathjax></p> <p>The final temperature is 42.1 °C.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/343749" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-endothermic-reactions-happen"> Why do endothermic reactions happen? 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A 55.0-g aluminum block initially at 27.5 C absorbs 725 J of heat. What is the final temperature of the aluminum?

ab4d42a4-6ddd-11ea-a5b8-ccda262736ce

https://socratic.org/questions/if-oxygen-effuses-through-an-opening-at-a-rate-of-67-particles-per-second-how-fa

268.00 particles per second

start physical_unit 18 19 percent particles/s qc_end physical_unit 1 1 10 13 percent qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Rate [OF] hydrogen gas [IN] particles per second"}]

[{"type":"physical unit","value":"268.00 particles per second"}]

[{"type":"physical unit","value":"Rate [OF] oxygen [=] \\pu{67 particles per second}"},{"type":"other","value":"Through the same opening."}]

<h1 class="questionTitle" itemprop="name">If oxygen effuses through an opening at a rate of 67 particles per second, how fast would effuses Hydrogen gas effuse through the same opening?</h1>

268.00 particles per second

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Graham's law of effusion says that </p> <p><mathjax>#R_1/R_2=sqrt(M_2/M_1)#</mathjax>,</p> <p>where <mathjax>#R#</mathjax> is the rate of effusion and <mathjax>#M#</mathjax> is the mass. The subscript number refers to either oxygen or hydrogen - it's a relative equation. </p> <p>If we say that substance <mathjax>#1#</mathjax> is hydrogen and <mathjax>#2#</mathjax> is oxygen, then</p> <p><mathjax>#R_1=?#</mathjax><br/> <mathjax>#R_2=67#</mathjax></p> <p><mathjax>#M_1=1#</mathjax><br/> <mathjax>#M_2=16#</mathjax></p> <p>(<mathjax>#M#</mathjax> values from the periodic table).</p> <p>Putting these values into a rearranged equation, </p> <p><mathjax>#R_1=R_2*sqrt(M_2/M_1)#</mathjax><br/> <mathjax>#R_1=67*sqrt(16/1)=67*4=268#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#268#</mathjax> particles per second. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Graham's law of effusion says that </p> <p><mathjax>#R_1/R_2=sqrt(M_2/M_1)#</mathjax>,</p> <p>where <mathjax>#R#</mathjax> is the rate of effusion and <mathjax>#M#</mathjax> is the mass. The subscript number refers to either oxygen or hydrogen - it's a relative equation. </p> <p>If we say that substance <mathjax>#1#</mathjax> is hydrogen and <mathjax>#2#</mathjax> is oxygen, then</p> <p><mathjax>#R_1=?#</mathjax><br/> <mathjax>#R_2=67#</mathjax></p> <p><mathjax>#M_1=1#</mathjax><br/> <mathjax>#M_2=16#</mathjax></p> <p>(<mathjax>#M#</mathjax> values from the periodic table).</p> <p>Putting these values into a rearranged equation, </p> <p><mathjax>#R_1=R_2*sqrt(M_2/M_1)#</mathjax><br/> <mathjax>#R_1=67*sqrt(16/1)=67*4=268#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If oxygen effuses through an opening at a rate of 67 particles per second, how fast would effuses Hydrogen gas effuse through the same opening?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/kinetic-theory-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Kinetic Theory of Gases</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="260905" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/reudhreghs"><img alt="" class="" src="https://profilepictures.socratic.org/cbvHaqiiRa2eTNL3y20D_Just%20monkeying%20around%20%F0%9F%90%92%F0%9F%98%8D%F0%9F%8C%9E.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/reudhreghs"> reudhreghs </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-01T10:23:27" itemprop="dateCreated"> May 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#268#</mathjax> particles per second. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Graham's law of effusion says that </p> <p><mathjax>#R_1/R_2=sqrt(M_2/M_1)#</mathjax>,</p> <p>where <mathjax>#R#</mathjax> is the rate of effusion and <mathjax>#M#</mathjax> is the mass. The subscript number refers to either oxygen or hydrogen - it's a relative equation. </p> <p>If we say that substance <mathjax>#1#</mathjax> is hydrogen and <mathjax>#2#</mathjax> is oxygen, then</p> <p><mathjax>#R_1=?#</mathjax><br/> <mathjax>#R_2=67#</mathjax></p> <p><mathjax>#M_1=1#</mathjax><br/> <mathjax>#M_2=16#</mathjax></p> <p>(<mathjax>#M#</mathjax> values from the periodic table).</p> <p>Putting these values into a rearranged equation, </p> <p><mathjax>#R_1=R_2*sqrt(M_2/M_1)#</mathjax><br/> <mathjax>#R_1=67*sqrt(16/1)=67*4=268#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/260905" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-kinetic-molecular-theory-explain-gas-laws"> How does kinetic molecular theory explain gas laws? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/garaham-s-law-of-diffusion-1"> What is Graham's Law of Effusion? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-the-kinetic-theory-of-gases"> What are some examples of the kinetic theory of gases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-relationship-between-charles-law-and-the-kinetic-theory-of-gases"> What is the relationship between Charles law and the kinetic theory of gases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-the-kinetic-theory-apply-to-gases"> Why does the kinetic theory apply to gases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-average-kinetic-energy-of-the-molecules-in-a-gas-at-273k"> What is the average kinetic energy of the molecules in a gas at 273K? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-absolute-temperature-of-a-substance-relate-to-the-average-kinetic-e"> How does the absolute temperature of a substance relate to the average kinetic energy of its molecules? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-gas-expand-according-to-the-kinetic-molecular-theory"> How does a gas expand according to the kinetic molecular theory? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/according-to-kinetic-molecular-theory-how-are-gases-compared-with-liquids-and-so"> According to kinetic molecular theory, how are gases compared with liquids and solids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/use-the-terms-volume-and-density-to-compare-gases-liquids-and-solids-in-terms-of"> Use the terms volume and density to compare gases, liquids and solids in terms of the kinetic... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/kinetic-theory-of-gases"> See all questions in Kinetic Theory of Gases </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1152 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

If oxygen effuses through an opening at a rate of 67 particles per second, how fast would effuses Hydrogen gas effuse through the same opening?

aa6246f4-6ddd-11ea-a811-ccda262736ce

https://socratic.org/questions/what-is-the-volume-of-gas-inside-this-balloon

120.76 L

start physical_unit 5 5 volume l qc_end physical_unit 5 5 21 22 temperature qc_end physical_unit 5 5 28 29 pressure qc_end physical_unit 5 5 43 44 mole qc_end end

[{"type":"physical unit","value":"Volume [OF] gas [IN] L"}]

[{"type":"physical unit","value":"120.76 L"}]

[{"type":"physical unit","value":"Temperature [OF] gas [=] \\pu{39 ℃}"},{"type":"physical unit","value":"Air pressure [OF] gas [=] \\pu{0.700 atm}"},{"type":"physical unit","value":"Mole [OF] gas [=] \\pu{3.30 moles}"}]

<h1 class="questionTitle" itemprop="name">What is the volume of gas inside this balloon?</h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>A balloon is floating around outside your window. The temperature outside is 39°C, and the air pressure is 0.700 atm. Your neighbor, who released the balloon, tells you that he filled it with 3.30 moles of gas</p></div> </h2> </div> </div>

120.76 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#V=(3.30*molxx0.0821*L*atm*K^-1*mol^-1xx312*K)/(0.700*atm)=??L#</mathjax></p> <p>Would the gas inside the balloon be normal air, or something else? How could you tell?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V=(nRT)/P~=120*L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#V=(3.30*molxx0.0821*L*atm*K^-1*mol^-1xx312*K)/(0.700*atm)=??L#</mathjax></p> <p>Would the gas inside the balloon be normal air, or something else? How could you tell?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the volume of gas inside this balloon?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>A balloon is floating around outside your window. The temperature outside is 39°C, and the air pressure is 0.700 atm. Your neighbor, who released the balloon, tells you that he filled it with 3.30 moles of gas</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="298379" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-13T07:27:53" itemprop="dateCreated"> Aug 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V=(nRT)/P~=120*L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#V=(3.30*molxx0.0821*L*atm*K^-1*mol^-1xx312*K)/(0.700*atm)=??L#</mathjax></p> <p>Would the gas inside the balloon be normal air, or something else? How could you tell?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/298379" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 8707 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the volume of gas inside this balloon?

A balloon is floating around outside your window. The temperature outside is 39°C, and the air pressure is 0.700 atm. Your neighbor, who released the balloon, tells you that he filled it with 3.30 moles of gas

aa4ebfe8-6ddd-11ea-b6d7-ccda262736ce

https://socratic.org/questions/how-do-you-calculate-the-percent-by-mass-sulfur-in-sulfuric-acid

32.69%

start physical_unit 8 11 mass_percent none qc_end substance 10 11 qc_end end

[{"type":"physical unit","value":"Percent by mass [OF] sulfur in sulfuric acid"}]

[{"type":"physical unit","value":"32.69%"}]

[{"type":"substance name","value":"Sulfuric acid"}]

<h1 class="questionTitle" itemprop="name">How do you calculate the percent by mass sulfur in sulfuric acid?</h1>

32.69%

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Percentage sulfur"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass of sulfur"/"Mass of sufuric acid"xx100%#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(32.06*g*mol^-1)/(98.08*g*mol^-1)xx100%=??#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#%S" in sulfuric acid"~=33%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Percentage sulfur"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass of sulfur"/"Mass of sufuric acid"xx100%#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(32.06*g*mol^-1)/(98.08*g*mol^-1)xx100%=??#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you calculate the percent by mass sulfur in sulfuric acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/percent-composition" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Composition</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="300324" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-18T17:23:22" itemprop="dateCreated"> Aug 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#%S" in sulfuric acid"~=33%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Percentage sulfur"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass of sulfur"/"Mass of sufuric acid"xx100%#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(32.06*g*mol^-1)/(98.08*g*mol^-1)xx100%=??#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/300324" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-mole-percent"> What is mole percent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188602bf3469570e2e8b"> Question #e2e8b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188702bf34695a6bc737"> Question #bc737 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418be02bf34695a6bc73b"> Question #bc73b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c202bf3469570e2e8f"> Question #e2e8f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c802bf346963eb9857"> Question #b9857 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418ca02bf346963eb985b"> Question #b985b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418cc02bf34694a4fee41"> Question #fee41 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418d502bf34694c8c5c01"> Question #c5c01 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4196e02bf34695a6bc73f"> Question #bc73f </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/percent-composition"> See all questions in Percent Composition </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 16616 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How do you calculate the percent by mass sulfur in sulfuric acid?

ac3447b7-6ddd-11ea-a6e9-ccda262736ce

https://socratic.org/questions/when-4-22-moles-of-al-reacts-with-5-0-moles-of-hbr-how-many-moles-of-h-2-are-for

2.5 moles

start physical_unit 15 15 mole mol qc_end physical_unit 4 4 1 2 mole qc_end physical_unit 10 10 7 8 mole qc_end end

[{"type":"physical unit","value":"Mole [OF] H2 [IN] moles"}]

[{"type":"physical unit","value":"2.5 moles"}]

[{"type":"physical unit","value":"Mole [OF] Al [=] \\pu{4.22 moles}"},{"type":"physical unit","value":"Mole [OF] HBr [=] \\pu{5.0 moles}"}]

<h1 class="questionTitle" itemprop="name">When 4.22 moles of #Al# reacts with 5.0 moles of #HBr#, how many moles of #H_2# are formed?</h1>

2.5 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First write a balanced chemical equation for the reaction of the metal with the acid :</p> <p><mathjax>#2Al+6HBr-&gt;2AlBr_3+3H_2#</mathjax>.</p> <p>This represents <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio in which the reactants combine and in which the products are formed.</p> <p>Since <mathjax>#2#</mathjax> moles <mathjax>#Al#</mathjax> requires <mathjax>#6#</mathjax> moles <mathjax>#HBr#</mathjax>, it implies that, given <mathjax>#4.22#</mathjax> moles <mathjax>#Al#</mathjax> and <mathjax>#5.0#</mathjax> moles <mathjax>#HBr#</mathjax>, then <mathjax>#HBr#</mathjax> is in excess and <mathjax>#Al#</mathjax> is the <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>.</p> <p>Hence all <mathjax>#5.0 mol HBr#</mathjax> will react with <mathjax>#5.0/3=1.667mol Al#</mathjax> to form <mathjax>#1.667mol AlBr_3#</mathjax> and <mathjax>#5.0/2=2.5 mol H_2#</mathjax> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.5mol#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First write a balanced chemical equation for the reaction of the metal with the acid :</p> <p><mathjax>#2Al+6HBr-&gt;2AlBr_3+3H_2#</mathjax>.</p> <p>This represents <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio in which the reactants combine and in which the products are formed.</p> <p>Since <mathjax>#2#</mathjax> moles <mathjax>#Al#</mathjax> requires <mathjax>#6#</mathjax> moles <mathjax>#HBr#</mathjax>, it implies that, given <mathjax>#4.22#</mathjax> moles <mathjax>#Al#</mathjax> and <mathjax>#5.0#</mathjax> moles <mathjax>#HBr#</mathjax>, then <mathjax>#HBr#</mathjax> is in excess and <mathjax>#Al#</mathjax> is the <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>.</p> <p>Hence all <mathjax>#5.0 mol HBr#</mathjax> will react with <mathjax>#5.0/3=1.667mol Al#</mathjax> to form <mathjax>#1.667mol AlBr_3#</mathjax> and <mathjax>#5.0/2=2.5 mol H_2#</mathjax> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">When 4.22 moles of #Al# reacts with 5.0 moles of #HBr#, how many moles of #H_2# are formed?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="245523" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/trevor-r-1"><img alt="" class="" src="https://profilepictures.socratic.org/2Wf9lLD9RaSzPbXY0EW8_S5002678.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/trevor-r-1"> Trevor Ryan. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-26T19:34:15" itemprop="dateCreated"> Mar 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.5mol#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First write a balanced chemical equation for the reaction of the metal with the acid :</p> <p><mathjax>#2Al+6HBr-&gt;2AlBr_3+3H_2#</mathjax>.</p> <p>This represents <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio in which the reactants combine and in which the products are formed.</p> <p>Since <mathjax>#2#</mathjax> moles <mathjax>#Al#</mathjax> requires <mathjax>#6#</mathjax> moles <mathjax>#HBr#</mathjax>, it implies that, given <mathjax>#4.22#</mathjax> moles <mathjax>#Al#</mathjax> and <mathjax>#5.0#</mathjax> moles <mathjax>#HBr#</mathjax>, then <mathjax>#HBr#</mathjax> is in excess and <mathjax>#Al#</mathjax> is the <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>.</p> <p>Hence all <mathjax>#5.0 mol HBr#</mathjax> will react with <mathjax>#5.0/3=1.667mol Al#</mathjax> to form <mathjax>#1.667mol AlBr_3#</mathjax> and <mathjax>#5.0/2=2.5 mol H_2#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/245523" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="245525" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-26T19:36:22" itemprop="dateCreated"> Mar 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.5#</mathjax> <mathjax>#mol#</mathjax> dihydrogen gas are formed. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Al(s) + 3HBr(aq) rarr AlBr_3(aq) + 3/2H_2(g)uarr#</mathjax></p> <p>Clearly, hydrobromic acid is in deficiency (complete rxn requires <mathjax>#&gt;12*mol#</mathjax> <mathjax>#HBr#</mathjax>). From the equation, <mathjax>#1/2#</mathjax> <mathjax>#mol#</mathjax> dihydrogen gas are evolved per mole of <mathjax>#HBr#</mathjax>. Since <mathjax>#5#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#HBr#</mathjax> are used, half of this quantity of <mathjax>#H_2#</mathjax> evolve. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/245525" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179102bf3469517a1072"> Question #a1072 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179402bf34694c8c5bf1"> Question #c5bf1 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179702bf3469588dc373"> Question #dc373 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179c02bf34694c8c5bf9"> Question #c5bf9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417a302bf3469517a1076"> Question #a1076 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417c702bf3469588dc377"> Question #dc377 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d002bf346963eb984f"> Question #b984f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d402bf346950519ea3"> Question #19ea3 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/mole-ratios"> See all questions in Mole Ratios </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1644 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

When 4.22 moles of #Al# reacts with 5.0 moles of #HBr#, how many moles of #H_2# are formed?

ac30dc59-6ddd-11ea-b1ec-ccda262736ce

https://socratic.org/questions/how-many-hydrogen-atoms-are-present-in-the-compound-c-6h-12o-6

12

start physical_unit 2 3 number none qc_end chemical_equation 9 9 qc_end end

[{"type":"physical unit","value":"Number [OF] hydrogen atoms"}]

[{"type":"physical unit","value":"12"}]

[{"type":"chemical equation","value":"C6H12O6"}]

<h1 class="questionTitle" itemprop="name">How many hydrogen atoms are present in the compound #C_6H_12O_6#?</h1>

12

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The subscript (small numbers after the element symbol) tells you how many atoms of the element are in one molecule of the compound. So, <mathjax>#H_12#</mathjax> indicates that there are 12 atoms of Hydrogen in that one molecule of <mathjax>#C_6H_12O_6#</mathjax>.</p> <p>Fun fact: <mathjax>#C_6H_12O_6#</mathjax> is more commonly known as glucose, a simple sugar.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>12</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The subscript (small numbers after the element symbol) tells you how many atoms of the element are in one molecule of the compound. So, <mathjax>#H_12#</mathjax> indicates that there are 12 atoms of Hydrogen in that one molecule of <mathjax>#C_6H_12O_6#</mathjax>.</p> <p>Fun fact: <mathjax>#C_6H_12O_6#</mathjax> is more commonly known as glucose, a simple sugar.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many hydrogen atoms are present in the compound #C_6H_12O_6#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#covalent-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Covalent Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/covalent-bonds-and-formulas/covalent-formulas-and-nomenclature" itemprop="url"> <span class="breadcrumb" itemprop="title">Covalent Formulas and Nomenclature</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="472874" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mr-danger"><img alt="" class="" src="https://profilepictures.socratic.org/LVEzYyMT7yOypAYBoakA_JLyzEQD1fAAAAAElFTkSuQmCC.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mr-danger"> Mr. Danger </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-08T00:05:33" itemprop="dateCreated"> Sep 8, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>12</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The subscript (small numbers after the element symbol) tells you how many atoms of the element are in one molecule of the compound. So, <mathjax>#H_12#</mathjax> indicates that there are 12 atoms of Hydrogen in that one molecule of <mathjax>#C_6H_12O_6#</mathjax>.</p> <p>Fun fact: <mathjax>#C_6H_12O_6#</mathjax> is more commonly known as glucose, a simple sugar.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/472874" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-for-sugar"> What is the chemical formula for sugar? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-chemical-formula-represents-a-carbohydrate"> What chemical formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-for-gold"> What is the chemical formula for gold? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-for-a-diamond"> What is the chemical formula for a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-formulas-for-covalent-compounds"> How do you find formulas for covalent compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-common-mistakes-students-make-with-empirical-forumlas"> What are common mistakes students make with empirical forumlas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-empirical-formulas"> What are empirical formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-empirical-formulas"> What are some examples of empirical formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-naming-a-covalent-bond-between-atoms-how-would-you-write-the-prefix-for-if-"> When naming a covalently-bonded molecule, how would you write the prefix if you had four atoms... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-nomenclature-for-ch3cl"> What is the chemical nomenclature for CH3Cl? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/covalent-bonds-and-formulas/covalent-formulas-and-nomenclature"> See all questions in Covalent Formulas and Nomenclature </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9226 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many hydrogen atoms are present in the compound #C_6H_12O_6#?

a86340b8-6ddd-11ea-bedd-ccda262736ce

https://socratic.org/questions/how-many-oxygen-molecules-are-in-3-36-g-of-oxygen

6.32 × 10^22

start physical_unit 2 3 number none qc_end physical_unit 2 2 6 7 mass qc_end end

[{"type":"physical unit","value":"Number [OF] oxygen molecules"}]

[{"type":"physical unit","value":"6.32 × 10^22"}]

[{"type":"physical unit","value":"Mass [OF] oxygen [=] \\pu{3.36 g}"}]

<h1 class="questionTitle" itemprop="name">How many oxygen molecules are in 3.36 g of oxygen?</h1>

6.32 × 10^22

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Solution</strong>:</p> <p>Mass of Oxygen = <mathjax>#3.36g#</mathjax><br/> Molar mass of oxygen (<mathjax>#O_2#</mathjax>) = 16 x 2 = <mathjax>#32gmol^-#</mathjax><br/> Total molecules in oxygen = Mass in grams/Molar mass x <mathjax>#N_A#</mathjax> <br/> = <mathjax>#3.36/32#</mathjax> x<mathjax># 6.02#</mathjax> x <mathjax>#10^23#</mathjax> <br/> = <mathjax>#6.321#</mathjax> x<mathjax># 10^22#</mathjax></p> <p><strong>Note:</strong><br/> <mathjax>#N_A#</mathjax>(Avagadro's number) = <mathjax>#6.02#</mathjax> x <mathjax>#10^23#</mathjax></p> <p>Hope it helps... </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#6.321#</mathjax> x <mathjax>#10^22#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Solution</strong>:</p> <p>Mass of Oxygen = <mathjax>#3.36g#</mathjax><br/> Molar mass of oxygen (<mathjax>#O_2#</mathjax>) = 16 x 2 = <mathjax>#32gmol^-#</mathjax><br/> Total molecules in oxygen = Mass in grams/Molar mass x <mathjax>#N_A#</mathjax> <br/> = <mathjax>#3.36/32#</mathjax> x<mathjax># 6.02#</mathjax> x <mathjax>#10^23#</mathjax> <br/> = <mathjax>#6.321#</mathjax> x<mathjax># 10^22#</mathjax></p> <p><strong>Note:</strong><br/> <mathjax>#N_A#</mathjax>(Avagadro's number) = <mathjax>#6.02#</mathjax> x <mathjax>#10^23#</mathjax></p> <p>Hope it helps... </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many oxygen molecules are in 3.36 g of oxygen?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="495200" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/arsala-k"><img alt="" class="" src="https://profilepictures.socratic.org/4u93ZEXlRySXl9rCH0EU_1634260.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/arsala-k"> Saliha </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-10-25T03:31:13" itemprop="dateCreated"> Oct 25, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#6.321#</mathjax> x <mathjax>#10^22#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Solution</strong>:</p> <p>Mass of Oxygen = <mathjax>#3.36g#</mathjax><br/> Molar mass of oxygen (<mathjax>#O_2#</mathjax>) = 16 x 2 = <mathjax>#32gmol^-#</mathjax><br/> Total molecules in oxygen = Mass in grams/Molar mass x <mathjax>#N_A#</mathjax> <br/> = <mathjax>#3.36/32#</mathjax> x<mathjax># 6.02#</mathjax> x <mathjax>#10^23#</mathjax> <br/> = <mathjax>#6.321#</mathjax> x<mathjax># 10^22#</mathjax></p> <p><strong>Note:</strong><br/> <mathjax>#N_A#</mathjax>(Avagadro's number) = <mathjax>#6.02#</mathjax> x <mathjax>#10^23#</mathjax></p> <p>Hope it helps... </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/495200" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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How many oxygen molecules are in 3.36 g of oxygen?

aa489ad3-6ddd-11ea-be9a-ccda262736ce

https://socratic.org/questions/what-is-the-mass-of-0-35-moles-of-oxygen-gas-molecules

11.20 g

start physical_unit 8 10 mass g qc_end physical_unit 8 10 5 6 mole qc_end end

[{"type":"physical unit","value":"Mass [OF] oxygen gas molecules [IN] g"}]

[{"type":"physical unit","value":"11.20 g"}]

[{"type":"physical unit","value":"Mole [OF] oxygen gas molecules [=] \\pu{0.35 moles}"}]

<h1 class="questionTitle" itemprop="name">What is the mass of 0.35 moles of oxygen gas molecules?</h1>

11.20 g

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#n = m/M#</mathjax></p> <p>Where <mathjax>#n#</mathjax> = number of moles, <mathjax>#m#</mathjax> = mass in grams and <mathjax>#M#</mathjax> = molar mass.</p> <p>We know the molar mass of <mathjax>#O_2#</mathjax> is 32.00 g/mol <br/> i.e. 2 <mathjax>#xx#</mathjax> 16 g, the molar mass of one oxygen atom (<mathjax>#O#</mathjax>)</p> <p>We can rearrange the formula to:<br/> <mathjax>#m = nM#</mathjax></p> <p><mathjax>#"mass" = "0.35 mol" xx "32.00 g/mol" = "11 g" -&gt;#</mathjax> two sig figs</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The answer is: <mathjax>#"11 g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#n = m/M#</mathjax></p> <p>Where <mathjax>#n#</mathjax> = number of moles, <mathjax>#m#</mathjax> = mass in grams and <mathjax>#M#</mathjax> = molar mass.</p> <p>We know the molar mass of <mathjax>#O_2#</mathjax> is 32.00 g/mol <br/> i.e. 2 <mathjax>#xx#</mathjax> 16 g, the molar mass of one oxygen atom (<mathjax>#O#</mathjax>)</p> <p>We can rearrange the formula to:<br/> <mathjax>#m = nM#</mathjax></p> <p><mathjax>#"mass" = "0.35 mol" xx "32.00 g/mol" = "11 g" -&gt;#</mathjax> two sig figs</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the mass of 0.35 moles of oxygen gas molecules?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="538165" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/chemstudent-1"><img alt="" class="" src="https://profilepictures.socratic.org/I3lAvyVRIWOMcp2w7wcZ_17.jpg" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/chemstudent-1"> ChemStudent </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-01-20T01:22:46" itemprop="dateCreated"> Jan 20, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The answer is: <mathjax>#"11 g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#n = m/M#</mathjax></p> <p>Where <mathjax>#n#</mathjax> = number of moles, <mathjax>#m#</mathjax> = mass in grams and <mathjax>#M#</mathjax> = molar mass.</p> <p>We know the molar mass of <mathjax>#O_2#</mathjax> is 32.00 g/mol <br/> i.e. 2 <mathjax>#xx#</mathjax> 16 g, the molar mass of one oxygen atom (<mathjax>#O#</mathjax>)</p> <p>We can rearrange the formula to:<br/> <mathjax>#m = nM#</mathjax></p> <p><mathjax>#"mass" = "0.35 mol" xx "32.00 g/mol" = "11 g" -&gt;#</mathjax> two sig figs</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/538165" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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What is the mass of 0.35 moles of oxygen gas molecules?

a837a701-6ddd-11ea-9a9f-ccda262736ce

https://socratic.org/questions/a-gas-collected-by-water-displacement-occupies-781-cm-3-at-14-c-and-99-1-kpa-wha

736.67 cm^3

start physical_unit 18 20 volume cm^3 qc_end physical_unit 1 1 7 8 volume qc_end physical_unit 1 1 10 11 temperature qc_end physical_unit 1 1 13 14 pressure qc_end c_other STP qc_end end

[{"type":"physical unit","value":"Volume2 [OF] the dry gas [IN] cm^3"}]

[{"type":"physical unit","value":"736.67 cm^3"}]

[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{781 cm^3}"},{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{14 °C}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{99.1 kPa}"},{"type":"other","value":"STP"}]

<h1 class="questionTitle" itemprop="name"> A gas, collected by water displacement, occupies #781# #cm^3# at #14°C# and #99.1# #kPa#. What volume will the dry gas occupy at STP? </h1>

736.67 cm^3

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P_"SVP"=12.0*mm*Hg#</mathjax> at <mathjax>#14#</mathjax> <mathjax>#""^@C#</mathjax></p> <p>Now the quoted pressure is …….</p> <p><mathjax>#(99.1*kPa)/(101.3*kPa*atm^-1)xx760*mm*Hg*atm^-1=743.5*mm*Hg#</mathjax></p> <p>And <mathjax>#P_"Total"=P_"SVP"+P_"gas"#</mathjax></p> <p><mathjax>#P_"gas"=P_"Total"-P_"SVP"=(743.5-12.0)*mm*Hg=731.5*mm*Hg#</mathjax></p> <p>And <mathjax>#"STP"#</mathjax> specifies a pressure of <mathjax>#0.987*atm-=750.2*mm*Hg#</mathjax>, and <mathjax>#T-=273.15*K#</mathjax></p> <p>That out of the way...<mathjax>#(P_1V_1)/T_1-=(P_2V_2)/T_2#</mathjax></p> <p>We solve for <mathjax>#V_2=(P_1V_1)/T_1xxT_2/P_2#</mathjax></p> <p><mathjax>#(743.5*mm*Hgxx781*cm^3)/(287*K)xx(273.15*K)/(750.2*mm*Hg)#</mathjax></p> <p><mathjax>#=736.6*cm^3#</mathjax>...</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The question is INCOMPLETE...we need <mathjax>#P_"saturated vapour pressure"#</mathjax> at <mathjax>#14#</mathjax> <mathjax>#""^@C#</mathjax>...we also need to specify <mathjax>#"STP"#</mathjax>...</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P_"SVP"=12.0*mm*Hg#</mathjax> at <mathjax>#14#</mathjax> <mathjax>#""^@C#</mathjax></p> <p>Now the quoted pressure is …….</p> <p><mathjax>#(99.1*kPa)/(101.3*kPa*atm^-1)xx760*mm*Hg*atm^-1=743.5*mm*Hg#</mathjax></p> <p>And <mathjax>#P_"Total"=P_"SVP"+P_"gas"#</mathjax></p> <p><mathjax>#P_"gas"=P_"Total"-P_"SVP"=(743.5-12.0)*mm*Hg=731.5*mm*Hg#</mathjax></p> <p>And <mathjax>#"STP"#</mathjax> specifies a pressure of <mathjax>#0.987*atm-=750.2*mm*Hg#</mathjax>, and <mathjax>#T-=273.15*K#</mathjax></p> <p>That out of the way...<mathjax>#(P_1V_1)/T_1-=(P_2V_2)/T_2#</mathjax></p> <p>We solve for <mathjax>#V_2=(P_1V_1)/T_1xxT_2/P_2#</mathjax></p> <p><mathjax>#(743.5*mm*Hgxx781*cm^3)/(287*K)xx(273.15*K)/(750.2*mm*Hg)#</mathjax></p> <p><mathjax>#=736.6*cm^3#</mathjax>...</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name"> A gas, collected by water displacement, occupies #781# #cm^3# at #14°C# and #99.1# #kPa#. What volume will the dry gas occupy at STP? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="634071" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-22T19:09:05" itemprop="dateCreated"> Jun 22, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The question is INCOMPLETE...we need <mathjax>#P_"saturated vapour pressure"#</mathjax> at <mathjax>#14#</mathjax> <mathjax>#""^@C#</mathjax>...we also need to specify <mathjax>#"STP"#</mathjax>...</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P_"SVP"=12.0*mm*Hg#</mathjax> at <mathjax>#14#</mathjax> <mathjax>#""^@C#</mathjax></p> <p>Now the quoted pressure is …….</p> <p><mathjax>#(99.1*kPa)/(101.3*kPa*atm^-1)xx760*mm*Hg*atm^-1=743.5*mm*Hg#</mathjax></p> <p>And <mathjax>#P_"Total"=P_"SVP"+P_"gas"#</mathjax></p> <p><mathjax>#P_"gas"=P_"Total"-P_"SVP"=(743.5-12.0)*mm*Hg=731.5*mm*Hg#</mathjax></p> <p>And <mathjax>#"STP"#</mathjax> specifies a pressure of <mathjax>#0.987*atm-=750.2*mm*Hg#</mathjax>, and <mathjax>#T-=273.15*K#</mathjax></p> <p>That out of the way...<mathjax>#(P_1V_1)/T_1-=(P_2V_2)/T_2#</mathjax></p> <p>We solve for <mathjax>#V_2=(P_1V_1)/T_1xxT_2/P_2#</mathjax></p> <p><mathjax>#(743.5*mm*Hgxx781*cm^3)/(287*K)xx(273.15*K)/(750.2*mm*Hg)#</mathjax></p> <p><mathjax>#=736.6*cm^3#</mathjax>...</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/634071" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? 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A gas, collected by water displacement, occupies #781# #cm^3# at #14°C# and #99.1# #kPa#. What volume will the dry gas occupy at STP?

ab285024-6ddd-11ea-9b21-ccda262736ce

https://socratic.org/questions/if-h-3o-8-26-times-10-5-m-what-is-the-ph-of-the-solution

4.08

start physical_unit 12 13 ph none qc_end physical_unit 12 13 3 6 [h3o+] qc_end end

[{"type":"physical unit","value":"pH [OF] the solution"}]

[{"type":"physical unit","value":"4.08"}]

[{"type":"physical unit","value":"[H3O+] [OF] the solution [=] \\pu{8.26 × 10^(-5) M}"}]

<h1 class="questionTitle" itemprop="name">If #[H_3O^+] = 8.26 times 10^-5# #M#, what is the pH of the solution?</h1>

4.08

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=-log_10[H_3O^+]#</mathjax></p> <p><mathjax>#=-log_10(8.26xx10^-5)=??#</mathjax></p> <p>See <a href="https://socratic.org/questions/ph-value-definition">this old answer for more details.</a> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=4.08............#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=-log_10[H_3O^+]#</mathjax></p> <p><mathjax>#=-log_10(8.26xx10^-5)=??#</mathjax></p> <p>See <a href="https://socratic.org/questions/ph-value-definition">this old answer for more details.</a> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If #[H_3O^+] = 8.26 times 10^-5# #M#, what is the pH of the solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="432647" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-31T19:00:49" itemprop="dateCreated"> May 31, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=4.08............#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=-log_10[H_3O^+]#</mathjax></p> <p><mathjax>#=-log_10(8.26xx10^-5)=??#</mathjax></p> <p>See <a href="https://socratic.org/questions/ph-value-definition">this old answer for more details.</a> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/432647" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? 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If #[H_3O^+] = 8.26 times 10^-5# #M#, what is the pH of the solution?

ab80970c-6ddd-11ea-b922-ccda262736ce

https://socratic.org/questions/how-many-moles-of-feo-are-produced-if-8-moles-of-so-2-are-produced-in-2cufes-2-5

4.00 moles

start physical_unit 4 4 mole mol qc_end physical_unit 11 11 8 9 mole qc_end chemical_equation 15 28 qc_end end

[{"type":"physical unit","value":"Mole [OF] FeO [IN] moles"}]

[{"type":"physical unit","value":"4.00 moles"}]

[{"type":"physical unit","value":"Mole [OF] SO2 [=] \\pu{8 moles}"},{"type":"chemical equation","value":"2 CuFeS2 + 5 O2 -> 2 Cu + 2 FeO + 4 SO2"}]

<h1 class="questionTitle" itemprop="name">How many moles of #FeO# are produced if 8 moles of #SO_2# are produced in #2CuFeS_2 + 5O_2 -&gt; 2Cu + 2FeO + 4SO_2#?</h1>

4.00 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So: <mathjax>#8 mol SO_2harr4mol FeO#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/the-mole-concept/the-mole">The mole</a> ratio <mathjax>#FeOdivSO_2=2div4=1div2#</mathjax>, as you can see from the equation.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So: <mathjax>#8 mol SO_2harr4mol FeO#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles of #FeO# are produced if 8 moles of #SO_2# are produced in #2CuFeS_2 + 5O_2 -&gt; 2Cu + 2FeO + 4SO_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="374223" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meneernask"><img alt="" class="" src="https://profilepictures.socratic.org/gpA0lokRGK9vLVUnAMAy_meneernask.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meneernask"> MeneerNask </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-06T16:04:51" itemprop="dateCreated"> Feb 6, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/the-mole-concept/the-mole">The mole</a> ratio <mathjax>#FeOdivSO_2=2div4=1div2#</mathjax>, as you can see from the equation.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So: <mathjax>#8 mol SO_2harr4mol FeO#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/374223" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="374228" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/samriddha"><img alt="" class="" src="https://profilepictures.socratic.org/3bMcXdwZTLqpsJaquExz_Shinjuku.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/samriddha"> Professor Sam </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-06T16:17:53" itemprop="dateCreated"> Feb 6, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"4 moles of FeO"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"In every reaction we can determine amount of reactants and"#</mathjax> <mathjax>#"products by using ratio formulas."#</mathjax></p> <p>#"In this reaction the ratio formula = </p> <p><mathjax>#2CuFeS_2 : 5O_2 = 2Cu : 2FeO : 4SO_2#</mathjax></p> <p>By solving the ratio we see </p> <p><mathjax>#(2 * 2CuFeS_2) : (5/4 * 5O_2) = (2* 2 Cu) : (2 * 2FeO) : (4 * 2 SO_2)#</mathjax></p> <p><mathjax>#(4CuFeS_2) : ( 6.2O_2) = (4Cu) : (4FeO) : (8SO_2)#</mathjax></p> <p>Therefore FeO produced is 4 moles</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/374228" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> 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How many moles of #FeO# are produced if 8 moles of #SO_2# are produced in #2CuFeS_2 + 5O_2 -&gt; 2Cu + 2FeO + 4SO_2#?

aa718eef-6ddd-11ea-a4c9-ccda262736ce

https://socratic.org/questions/the-volume-of-gas-in-a-balloon-is-1-90-l-at-21-0-c-the-balloon-is-heated-causing

882.39 K

start physical_unit 33 34 temperature k qc_end physical_unit 33 34 8 9 volume qc_end physical_unit 33 34 11 12 temperature qc_end physical_unit 33 34 25 26 volume qc_end end

[{"type":"physical unit","value":"Temperature2 [OF] the gas [IN] K"}]

[{"type":"physical unit","value":"882.39 K"}]

[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{1.90 L}"},{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{21.0 ℃}"},{"type":"physical unit","value":"Volume2 [OF] the gas [=] \\pu{5.70 L}"}]

<h1 class="questionTitle" itemprop="name">The volume of gas in a balloon is 1.90 L at 21.0°C. The balloon is heated, causing it to expand to a volume of 5.70 L. What is the new temperature of the gas inside the balloon?</h1>

882.39 K

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#V_1/T_1=V_2/T_2#</mathjax>; this assumes a given quantity of gas, and absolute temperatures......</p> <p>And so....<mathjax>#T_2=V_2/V_1xxT_1=(5.70*L)/(1.90*L)xx(21.0+273.13*K)#</mathjax></p> <p><mathjax>#=??*K#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We use old <a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' law</a>.....and get <mathjax>#T_2=879.6*K#</mathjax>....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#V_1/T_1=V_2/T_2#</mathjax>; this assumes a given quantity of gas, and absolute temperatures......</p> <p>And so....<mathjax>#T_2=V_2/V_1xxT_1=(5.70*L)/(1.90*L)xx(21.0+273.13*K)#</mathjax></p> <p><mathjax>#=??*K#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">The volume of gas in a balloon is 1.90 L at 21.0°C. The balloon is heated, causing it to expand to a volume of 5.70 L. What is the new temperature of the gas inside the balloon?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="471879" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-05T03:59:39" itemprop="dateCreated"> Sep 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We use old <a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' law</a>.....and get <mathjax>#T_2=879.6*K#</mathjax>....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#V_1/T_1=V_2/T_2#</mathjax>; this assumes a given quantity of gas, and absolute temperatures......</p> <p>And so....<mathjax>#T_2=V_2/V_1xxT_1=(5.70*L)/(1.90*L)xx(21.0+273.13*K)#</mathjax></p> <p><mathjax>#=??*K#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/471879" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyles-law-relate-to-breathing"> How does Boyle's law relate to breathing? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/in-avogadro-s-law-what-would-happen-to-v-if-n-is-increased-decreased-and-what-wo"> In Avogadro's Law what would happen to V if N is increased/decreased? 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The volume of gas in a balloon is 1.90 L at 21.0°C. The balloon is heated, causing it to expand to a volume of 5.70 L. What is the new temperature of the gas inside the balloon?

aafcc024-6ddd-11ea-9ffb-ccda262736ce

https://socratic.org/questions/what-is-the-hydrocarbon-formula-for-c-c-c

C3H4

start chemical_formula qc_end chemical_equation 6 6 qc_end end

[{"type":"other","value":"Chemical Formula [OF] the hydrocarbon formula [IN] default"}]

[{"type":"chemical equation","value":"C3H4"}]

[{"type":"chemical equation","value":"C#C−C"}]

<h1 class="questionTitle" itemprop="name">What is the hydrocarbon formula for #C-=C-C#?</h1>

C3H4

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I have written here before on the idea of degrees of unsaturation, and I am going to do it again. A carbon chain of 3 carbons that are fully saturated has a formula of <mathjax>#C_3H_8#</mathjax>; that is the number of hydrogen atoms is equal to <mathjax>#2n+2#</mathjax>, when <mathjax>#n#</mathjax> is the number of carbon atoms. Propane is of course a saturated hydrocarbon. Each 2 hydrogens LESS than <mathjax>#2n+2#</mathjax> represents 1 degree of unsaturation, which represents A DOUBLE BOND OR A RING. </p> <p>For propyne, the saturated carbon chain would <mathjax>#C_3H_8#</mathjax>, but here the triple bond counts for <mathjax>#2""^@#</mathjax> of unsaturation, and hence the formula is <mathjax>#C_3H_4#</mathjax>. Both propene and cylcopropane (1 olefinic bond OR 1 ring, <mathjax>#1""^@#</mathjax> of unsaturation) have the formula <mathjax>#C_3H_6#</mathjax>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>If you have such a carbon skeleton, then the formula is <mathjax>#H-C-=C-CH_3#</mathjax>, propyne, <mathjax>#C_3H_4#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I have written here before on the idea of degrees of unsaturation, and I am going to do it again. A carbon chain of 3 carbons that are fully saturated has a formula of <mathjax>#C_3H_8#</mathjax>; that is the number of hydrogen atoms is equal to <mathjax>#2n+2#</mathjax>, when <mathjax>#n#</mathjax> is the number of carbon atoms. Propane is of course a saturated hydrocarbon. Each 2 hydrogens LESS than <mathjax>#2n+2#</mathjax> represents 1 degree of unsaturation, which represents A DOUBLE BOND OR A RING. </p> <p>For propyne, the saturated carbon chain would <mathjax>#C_3H_8#</mathjax>, but here the triple bond counts for <mathjax>#2""^@#</mathjax> of unsaturation, and hence the formula is <mathjax>#C_3H_4#</mathjax>. Both propene and cylcopropane (1 olefinic bond OR 1 ring, <mathjax>#1""^@#</mathjax> of unsaturation) have the formula <mathjax>#C_3H_6#</mathjax>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the hydrocarbon formula for #C-=C-C#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#organic-chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Organic Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/organic-chemistry/naming-alkanes-alkenes-and-alkynes" itemprop="url"> <span class="breadcrumb" itemprop="title">Naming Alkanes, Alkenes, and Alkynes</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="206613" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-01T16:14:42" itemprop="dateCreated"> Jan 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>If you have such a carbon skeleton, then the formula is <mathjax>#H-C-=C-CH_3#</mathjax>, propyne, <mathjax>#C_3H_4#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I have written here before on the idea of degrees of unsaturation, and I am going to do it again. A carbon chain of 3 carbons that are fully saturated has a formula of <mathjax>#C_3H_8#</mathjax>; that is the number of hydrogen atoms is equal to <mathjax>#2n+2#</mathjax>, when <mathjax>#n#</mathjax> is the number of carbon atoms. Propane is of course a saturated hydrocarbon. Each 2 hydrogens LESS than <mathjax>#2n+2#</mathjax> represents 1 degree of unsaturation, which represents A DOUBLE BOND OR A RING. </p> <p>For propyne, the saturated carbon chain would <mathjax>#C_3H_8#</mathjax>, but here the triple bond counts for <mathjax>#2""^@#</mathjax> of unsaturation, and hence the formula is <mathjax>#C_3H_4#</mathjax>. Both propene and cylcopropane (1 olefinic bond OR 1 ring, <mathjax>#1""^@#</mathjax> of unsaturation) have the formula <mathjax>#C_3H_6#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/206613" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-branched-chain-alkanes"> How do you name branched chain alkanes? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-branched-alkanes"> How do you name branched alkanes? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-alkanes-from-newman-projections"> How do you name alkanes from Newman projections? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-alkanes-with-double-bonds"> How do you name alkanes with double bonds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-alkanes-with-halogens"> How do you name alkanes with halogens? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-alkenes-with-two-double-bonds"> How do you name alkenes with two double bonds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-alkenes-using-systematic-names"> How do you name alkenes using systematic names? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-alkenes-with-alcohols"> How do you name alkenes with alcohols? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-alkenes-with-double-bonds"> How do you name alkenes with double bonds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-name-alkynes-with-two-triple-bonds"> How do you name alkynes with two triple bonds? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/organic-chemistry/naming-alkanes-alkenes-and-alkynes"> See all questions in Naming Alkanes, Alkenes, and Alkynes </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3510 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the hydrocarbon formula for #C-=C-C#?

a912a091-6ddd-11ea-882f-ccda262736ce

https://socratic.org/questions/58f6e888b72cff42393bb976

22.4 L

start physical_unit 16 16 volume l qc_end physical_unit 11 12 1 2 volume qc_end physical_unit 4 5 1 2 volume qc_end end

[{"type":"physical unit","value":"Volume [OF] HCl(g) [IN] L"}]

[{"type":"physical unit","value":"22.4 L"}]

[{"type":"physical unit","value":"Volume [OF] chlorine gas [=] \\pu{12 L}"},{"type":"physical unit","value":"Volume [OF] hydrogen gas [=] \\pu{12 L}"}]

<h1 class="questionTitle" itemprop="name">If #12*L# of hydrogen gas react with #12*L# of chlorine gas, what volume of #HCl(g)# will result?</h1>

22.4 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the reaction:</p> <p><mathjax>#1/2H_2(g) + 1/2Cl_2(g) rarr HCl(g)#</mathjax>,</p> <p>equivalently,</p> <p><mathjax>#H_2(g) + Cl_2(g) rarr 2HCl(g)#</mathjax>,</p> <p>Given the opening statement, i.e. which is due to Avogadro, the volumes are proportional to the number of molecules each gas contains. Dihydrogen gas is present in HALF MOLAR proportion, and dichlorine is present in excess. And thus, given complete reaction, <mathjax>#11.2*L#</mathjax> of <mathjax>#H_2#</mathjax> reacts with <mathjax>#11.2*L#</mathjax> of <mathjax>#Cl_2#</mathjax> to give <mathjax>#22.4*L#</mathjax> <mathjax>#HCl(g)#</mathjax>.</p> <p>All of this is based on the stoichiometric equation..........</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of a gas is equivalent to the number of molecules it contains under equivalent temperature and pressure. And thus we should get <mathjax>#22.4*L#</mathjax> <mathjax>#HCl(g)#</mathjax>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the reaction:</p> <p><mathjax>#1/2H_2(g) + 1/2Cl_2(g) rarr HCl(g)#</mathjax>,</p> <p>equivalently,</p> <p><mathjax>#H_2(g) + Cl_2(g) rarr 2HCl(g)#</mathjax>,</p> <p>Given the opening statement, i.e. which is due to Avogadro, the volumes are proportional to the number of molecules each gas contains. Dihydrogen gas is present in HALF MOLAR proportion, and dichlorine is present in excess. And thus, given complete reaction, <mathjax>#11.2*L#</mathjax> of <mathjax>#H_2#</mathjax> reacts with <mathjax>#11.2*L#</mathjax> of <mathjax>#Cl_2#</mathjax> to give <mathjax>#22.4*L#</mathjax> <mathjax>#HCl(g)#</mathjax>.</p> <p>All of this is based on the stoichiometric equation..........</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If #12*L# of hydrogen gas react with #12*L# of chlorine gas, what volume of #HCl(g)# will result?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="409134" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-19T04:55:56" itemprop="dateCreated"> Apr 19, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of a gas is equivalent to the number of molecules it contains under equivalent temperature and pressure. And thus we should get <mathjax>#22.4*L#</mathjax> <mathjax>#HCl(g)#</mathjax>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the reaction:</p> <p><mathjax>#1/2H_2(g) + 1/2Cl_2(g) rarr HCl(g)#</mathjax>,</p> <p>equivalently,</p> <p><mathjax>#H_2(g) + Cl_2(g) rarr 2HCl(g)#</mathjax>,</p> <p>Given the opening statement, i.e. which is due to Avogadro, the volumes are proportional to the number of molecules each gas contains. Dihydrogen gas is present in HALF MOLAR proportion, and dichlorine is present in excess. And thus, given complete reaction, <mathjax>#11.2*L#</mathjax> of <mathjax>#H_2#</mathjax> reacts with <mathjax>#11.2*L#</mathjax> of <mathjax>#Cl_2#</mathjax> to give <mathjax>#22.4*L#</mathjax> <mathjax>#HCl(g)#</mathjax>.</p> <p>All of this is based on the stoichiometric equation..........</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/409134" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-apply-gas-stoichiometry"> How do you apply gas stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-a-gas-law-stoichiometry-problem"> How do you solve a gas law stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-gas-stoichiometry-problems-at-stp"> How do you do gas stoichiometry problems at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-an-agno3-solution-is-treated-with-50-0-ml-of-hi-gas-to-give-0-235-g-of-agi-"> When an AgNO3 solution is treated with 50.0 mL of HI gas to give 0.235 g of AgI, what is the... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-10-0-ml-of-agno3-solution-is-treated-with-excess-amount-of-hi-gas-to-give-0"> When 10.0 mL of AgNO3 solution is treated with excess amount of HI gas to give 0.235 g of AgI,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/hydrogen-sulfide-reacts-with-sulfur-dioxide-to-give-h2o-and-s-h2s-so2-h2o-s-soli"> Hydrogen sulfide reacts with sulfur dioxide to give H2O and S, H2S + SO2 = H2O + S(solid),... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-200-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 200 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 100 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolve-in-20-ml-of-pure-water-what-i"> If 100 mL of HCl gas at 300 K and 100 kPa dissolve in 20 mL of pure water, what is the concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-2-00-g-mixture-of-na-and-ca-reat-with-water-1-164-l-hydrogen-was-produced-a"> When 2.00 g mixture of Na and Ca reat with water, 1.164 L hydrogen was produced at 300.0 K and... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases"> See all questions in Gas Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2835 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

If #12*L# of hydrogen gas react with #12*L# of chlorine gas, what volume of #HCl(g)# will result?

ac5c91b4-6ddd-11ea-aabb-ccda262736ce

https://socratic.org/questions/you-have-a-compound-that-is-composed-of-62-0-grams-c-12-15-grams-h-13-771-grams-

C6H14NO

start chemical_formula qc_end physical_unit 10 10 8 9 mass qc_end physical_unit 13 13 11 12 mass qc_end physical_unit 16 16 14 15 mass qc_end physical_unit 20 20 18 19 mass qc_end end

[{"type":"other","value":"Chemical Formula [OF] the compound [IN] empirical"}]

[{"type":"chemical equation","value":"C6H14NO"}]

[{"type":"physical unit","value":"Mass [OF] C [=] \\pu{62.0 grams}"},{"type":"physical unit","value":"Mass [OF] H [=] \\pu{12.15 grams}"},{"type":"physical unit","value":"Mass [OF] O [=] \\pu{13.771 grams}"},{"type":"physical unit","value":"Mass [OF] N [=] \\pu{12.059 grams}"}]

<h1 class="questionTitle" itemprop="name">You have a compound that is composed of 62.0 grams #C#, 12.15 grams #H#, 13.771 grams #O# and 12.059 grams #N#. What is its empirical formula?</h1>

C6H14NO

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><img alt="enter image source here" src="https://useruploads.socratic.org/ES99i3v1QpKcJNVmILBq_image.jpeg"/> </p> <p>The empirical formula is <mathjax>#C_6H_14NO#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_6H_14NO#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><img alt="enter image source here" src="https://useruploads.socratic.org/ES99i3v1QpKcJNVmILBq_image.jpeg"/> </p> <p>The empirical formula is <mathjax>#C_6H_14NO#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">You have a compound that is composed of 62.0 grams #C#, 12.15 grams #H#, 13.771 grams #O# and 12.059 grams #N#. What is its empirical formula?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="265814" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/sam-54"><img alt="" class="" src="https://profilepictures.socratic.org/3bkyAGe2RVWw1lx2h1A5_Avatar%201.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/sam-54"> Sam </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-14T19:58:21" itemprop="dateCreated"> May 14, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_6H_14NO#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><img alt="enter image source here" src="https://useruploads.socratic.org/ES99i3v1QpKcJNVmILBq_image.jpeg"/> </p> <p>The empirical formula is <mathjax>#C_6H_14NO#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/265814" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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You have a compound that is composed of 62.0 grams #C#, 12.15 grams #H#, 13.771 grams #O# and 12.059 grams #N#. What is its empirical formula?

ac334d54-6ddd-11ea-9c84-ccda262736ce

https://socratic.org/questions/how-much-heat-is-required-to-convert-20-0-g-of-ice-at-50-0-c-to-liquid-water-at-

8740 J

start physical_unit 10 10 heat_energy j qc_end physical_unit 10 10 7 8 mass qc_end physical_unit 10 10 12 13 temperature qc_end physical_unit 15 16 18 19 temperature qc_end physical_unit 10 10 26 29 specific_heat qc_end physical_unit 16 16 38 39 enthalpy_of_fusion qc_end end

[{"type":"physical unit","value":"Required heat [OF] ice [IN] J"}]

[{"type":"physical unit","value":"8740 J"}]

[{"type":"physical unit","value":"Mass [OF] ice [=] \\pu{20.0 g}"},{"type":"physical unit","value":"Temperature1 [OF] ice [=] \\pu{-50.0 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] liquid water [=] \\pu{0.0 ℃}"},{"type":"physical unit","value":"Specific heat [OF] ice [=] \\pu{2.06 J/(g * ℃)}"},{"type":"physical unit","value":"Heat of fusion [OF] water [=] \\pu{334 J/g}"}]

<h1 class="questionTitle" itemprop="name">How much heat is required to convert 20.0 g of ice at -50.0°C to liquid water at 0.0°C? The specific heat of ice is 2.06 J/(g *#"^o#C) and the heat of fusion of water is 334 J/g?</h1>

8740 J

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the process.....</p> <p><mathjax>#H_2O(s)stackrel(Delta_1, -20^@C...0^@C)rarrH_2O(s)stackrel(Delta_2=Delta_"fusion")rarrH_2O(l)#</mathjax></p> <p>Now <mathjax>#Delta_1=20.0*gxx2.06*J*g^-1*""^@C^-1xxDeltaT=#</mathjax></p> <p><mathjax>#20.0*gxx2.06*J*g^-1*""^@C^-1xx50#</mathjax> <mathjax>#""^@C=2060*J#</mathjax></p> <p>And <mathjax>#Delta_2=20.0*gxx334*J*g^-1=#</mathjax></p> <p><mathjax>#20.0*gxx334*J*g^-1=6680*J#</mathjax></p> <p><mathjax>#"Total heat"=Delta_1+Delta_2=2060*J+6680*J=??*J#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, you perform an energy summation.....and get <mathjax>#DeltaH~=9000*J.#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the process.....</p> <p><mathjax>#H_2O(s)stackrel(Delta_1, -20^@C...0^@C)rarrH_2O(s)stackrel(Delta_2=Delta_"fusion")rarrH_2O(l)#</mathjax></p> <p>Now <mathjax>#Delta_1=20.0*gxx2.06*J*g^-1*""^@C^-1xxDeltaT=#</mathjax></p> <p><mathjax>#20.0*gxx2.06*J*g^-1*""^@C^-1xx50#</mathjax> <mathjax>#""^@C=2060*J#</mathjax></p> <p>And <mathjax>#Delta_2=20.0*gxx334*J*g^-1=#</mathjax></p> <p><mathjax>#20.0*gxx334*J*g^-1=6680*J#</mathjax></p> <p><mathjax>#"Total heat"=Delta_1+Delta_2=2060*J+6680*J=??*J#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How much heat is required to convert 20.0 g of ice at -50.0°C to liquid water at 0.0°C? The specific heat of ice is 2.06 J/(g *#"^o#C) and the heat of fusion of water is 334 J/g?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="462710" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-11T07:05:38" itemprop="dateCreated"> Aug 11, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, you perform an energy summation.....and get <mathjax>#DeltaH~=9000*J.#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the process.....</p> <p><mathjax>#H_2O(s)stackrel(Delta_1, -20^@C...0^@C)rarrH_2O(s)stackrel(Delta_2=Delta_"fusion")rarrH_2O(l)#</mathjax></p> <p>Now <mathjax>#Delta_1=20.0*gxx2.06*J*g^-1*""^@C^-1xxDeltaT=#</mathjax></p> <p><mathjax>#20.0*gxx2.06*J*g^-1*""^@C^-1xx50#</mathjax> <mathjax>#""^@C=2060*J#</mathjax></p> <p>And <mathjax>#Delta_2=20.0*gxx334*J*g^-1=#</mathjax></p> <p><mathjax>#20.0*gxx334*J*g^-1=6680*J#</mathjax></p> <p><mathjax>#"Total heat"=Delta_1+Delta_2=2060*J+6680*J=??*J#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/462710" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? 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How much heat is required to convert 20.0 g of ice at -50.0°C to liquid water at 0.0°C? The specific heat of ice is 2.06 J/(g *#"^o#C) and the heat of fusion of water is 334 J/g?

abd02777-6ddd-11ea-b13c-ccda262736ce

https://socratic.org/questions/a-3-0-mol-gas-sample-occupies-6-0-liters-at-25-c-what-is-the-pressure-of-the-gas

1240 kPa

start physical_unit 16 17 pressure kpa qc_end physical_unit 3 4 1 2 mole qc_end physical_unit 3 4 6 7 volume qc_end physical_unit 3 4 9 10 temperature qc_end end

[{"type":"physical unit","value":"Pressure [OF] the gas [IN] kPa"}]

[{"type":"physical unit","value":"1240 kPa"}]

[{"type":"physical unit","value":"Mole [OF] gas sample [=] \\pu{3.0 mol}"},{"type":"physical unit","value":"Volume [OF] gas sample [=] \\pu{6.0 liters}"},{"type":"physical unit","value":"Temperature [OF] gas sample [=] \\pu{25 ℃}"}]

<h1 class="questionTitle" itemprop="name"> A 3.0 mol gas sample occupies 6.0 liters at 25 °C. What is the pressure of the gas in kPa’s?</h1>

1240 kPa

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P=(nRT)/V#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#{(3.0*cancel(mol)*0.0821*cancel(L)*atm*cancel(K^(-1))cancel(mol)^(-1)xx298cancelK)/(6.0*cancelL)}xx101.3*kPa*(atm)^-1#</mathjax></p> <p>Is the pressure you get sensible? Would you <em>a priori</em> expect it to be greater or lesser than <a href="http://socratic.org/chemistry/the-behavior-of-gases/atmospheric-pressure">atmospheric pressure</a>?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The pressure will be quite high!</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P=(nRT)/V#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#{(3.0*cancel(mol)*0.0821*cancel(L)*atm*cancel(K^(-1))cancel(mol)^(-1)xx298cancelK)/(6.0*cancelL)}xx101.3*kPa*(atm)^-1#</mathjax></p> <p>Is the pressure you get sensible? Would you <em>a priori</em> expect it to be greater or lesser than <a href="http://socratic.org/chemistry/the-behavior-of-gases/atmospheric-pressure">atmospheric pressure</a>?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name"> A 3.0 mol gas sample occupies 6.0 liters at 25 °C. What is the pressure of the gas in kPa’s?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="195322" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-02T07:59:00" itemprop="dateCreated"> Dec 2, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The pressure will be quite high!</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#P=(nRT)/V#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#{(3.0*cancel(mol)*0.0821*cancel(L)*atm*cancel(K^(-1))cancel(mol)^(-1)xx298cancelK)/(6.0*cancelL)}xx101.3*kPa*(atm)^-1#</mathjax></p> <p>Is the pressure you get sensible? Would you <em>a priori</em> expect it to be greater or lesser than <a href="http://socratic.org/chemistry/the-behavior-of-gases/atmospheric-pressure">atmospheric pressure</a>?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/195322" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="195335" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-02T08:54:43" itemprop="dateCreated"> Dec 2, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The pressure will be <mathjax>#"1240 kPa"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> with the equation <mathjax>#PV=nRT#</mathjax>, where <mathjax>#P#</mathjax> is pressure, <mathjax>#V#</mathjax> is volume, <mathjax>#n#</mathjax> is moles, <mathjax>#R#</mathjax> is the gas constant, and <mathjax>#T#</mathjax> is the Kelvin temperature.</p> <p><strong>Given/Known</strong><br/> <mathjax>#V="6.0 L"#</mathjax><br/> <mathjax>#n="3.0 mol"#</mathjax><br/> <mathjax>#R="8.3144598 L kPa K"^(-1) "mol"^(-1)"#</mathjax><br/> <a href="https://en.wikipedia.org/wiki/Gas_constant" rel="nofollow" target="_blank">https://en.wikipedia.org/wiki/Gas_constant</a><br/> <mathjax>#T="25"^"o""C"+273.15="298 K"#</mathjax></p> <p><strong>Unknown</strong><br/> pressure, <mathjax>#P#</mathjax></p> <p><strong>Equation</strong><br/> <mathjax>#PV=nRT#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#P#</mathjax> and solve.</p> <p><mathjax>#P=(nRT)/V#</mathjax></p> <p><mathjax>#P=(3.0cancel"mol"xx8.3144598cancel"L" "kPa" cancel("K"^(-1)) cancel("mol"^(-1))xx298cancel"K")/(6.0cancel"L")="1240 kPa"#</mathjax> (rounded to three significant figures) <a href="http://academic.umf.maine.edu/magri/PUBLIC.acd/tools/SigFigsAndRounding.html" rel="nofollow" target="_blank">http://academic.umf.maine.edu/magri/PUBLIC.acd/tools/SigFigsAndRounding.html</a></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/195335" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? 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A 3.0 mol gas sample occupies 6.0 liters at 25 °C. What is the pressure of the gas in kPa’s?

aaeae5ae-6ddd-11ea-a4de-ccda262736ce

https://socratic.org/questions/given-this-reaction-ch-4-2o-2-co-2-h-2o-16-g-of-ch-4-react-with-64-g-of-o-2-prod

36 grams

start physical_unit 30 30 mass g qc_end chemical_equation 3 10 qc_end physical_unit 3 3 11 12 mass qc_end physical_unit 6 6 17 18 mass qc_end physical_unit 8 8 22 23 mass qc_end end

[{"type":"physical unit","value":"Mass [OF] water [IN] grams"}]

[{"type":"physical unit","value":"36 grams"}]

[{"type":"chemical equation","value":"CH4 + 2 O2 -> CO2 + H2O"},{"type":"physical unit","value":"Mass [OF] CH4 [=] \\pu{16 g}"},{"type":"physical unit","value":"Mass [OF] O2 [=] \\pu{64 g}"},{"type":"physical unit","value":"Mass [OF] CO2 [=] \\pu{44 g}"}]

<h1 class="questionTitle" itemprop="name">Given this reaction: #CH_4 + 2O_2 -&gt; CO_2 + H_2O#, 16 g of #CH_4# react with 64 g of #O_2#, producing 44 g of #CO_2#. How many grams of water are produced?</h1>

36 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>There are actually two methods of doing it - stoichimetry &amp; also with the help of law of conservation of mass.</p> <p><strong>First by <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>:</strong></p> <p><mathjax>#16#</mathjax>grams of <mathjax>#CH_4#</mathjax> means <mathjax>#1#</mathjax>mole of it.</p> <p>Now, after balancing the entire equation we get:</p> <p><mathjax>#CH_4+2O_2 rarr CO_2+2H_2O#</mathjax>.</p> <p>So, 1 mole of methane produces 2 moles of water. Hence, <mathjax>#36#</mathjax> grams of water is formed.</p> <p><strong>Now by law of conservation of mass:</strong></p> <p>The entire mass of the reactants will be equal to the entire mass of the products after the reaction.</p> <p>So, mass of water formed <mathjax>#=(16+64)-44#</mathjax> grams, i.e. <mathjax>#36#</mathjax> grams.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#36#</mathjax> grams of water will get formed.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>There are actually two methods of doing it - stoichimetry &amp; also with the help of law of conservation of mass.</p> <p><strong>First by <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>:</strong></p> <p><mathjax>#16#</mathjax>grams of <mathjax>#CH_4#</mathjax> means <mathjax>#1#</mathjax>mole of it.</p> <p>Now, after balancing the entire equation we get:</p> <p><mathjax>#CH_4+2O_2 rarr CO_2+2H_2O#</mathjax>.</p> <p>So, 1 mole of methane produces 2 moles of water. Hence, <mathjax>#36#</mathjax> grams of water is formed.</p> <p><strong>Now by law of conservation of mass:</strong></p> <p>The entire mass of the reactants will be equal to the entire mass of the products after the reaction.</p> <p>So, mass of water formed <mathjax>#=(16+64)-44#</mathjax> grams, i.e. <mathjax>#36#</mathjax> grams.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Given this reaction: #CH_4 + 2O_2 -&gt; CO_2 + H_2O#, 16 g of #CH_4# react with 64 g of #O_2#, producing 44 g of #CO_2#. How many grams of water are produced?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="343772" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/aditya-9"><img alt="" class="" src="https://profilepictures.socratic.org/JI8xltWvSDeHqZTzxqDb_25.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/aditya-9"> Aditya Banerjee. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-29T14:20:18" itemprop="dateCreated"> Nov 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#36#</mathjax> grams of water will get formed.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>There are actually two methods of doing it - stoichimetry &amp; also with the help of law of conservation of mass.</p> <p><strong>First by <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>:</strong></p> <p><mathjax>#16#</mathjax>grams of <mathjax>#CH_4#</mathjax> means <mathjax>#1#</mathjax>mole of it.</p> <p>Now, after balancing the entire equation we get:</p> <p><mathjax>#CH_4+2O_2 rarr CO_2+2H_2O#</mathjax>.</p> <p>So, 1 mole of methane produces 2 moles of water. Hence, <mathjax>#36#</mathjax> grams of water is formed.</p> <p><strong>Now by law of conservation of mass:</strong></p> <p>The entire mass of the reactants will be equal to the entire mass of the products after the reaction.</p> <p>So, mass of water formed <mathjax>#=(16+64)-44#</mathjax> grams, i.e. <mathjax>#36#</mathjax> grams.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/343772" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3597 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

Given this reaction: #CH_4 + 2O_2 -&gt; CO_2 + H_2O#, 16 g of #CH_4# react with 64 g of #O_2#, producing 44 g of #CO_2#. How many grams of water are produced?

aabce42c-6ddd-11ea-b670-ccda262736ce

https://socratic.org/questions/how-do-you-balance-the-following-equation-a-h-2s-ag-2s-h-2

2 Ag(s) + H2S(aq) -> Ag2S(aq) + H2(g)^

start chemical_equation qc_end chemical_equation 7 13 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"2 Ag(s) + H2S(aq) -> Ag2S(aq) + H2(g)^"}]

[{"type":"chemical equation","value":"Ag + H2S -> Ag2S + H2"}]

<h1 class="questionTitle" itemprop="name">How do you balance the following equation: #Ag + H_2S → Ag_2S + H_2#?</h1>

2 Ag(s) + H2S(aq) -> Ag2S(aq) + H2(g)^

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your equation is:</p> <p><mathjax>#Ag(s)+H_2S(aq)-&gt;Ag_2S(aq)+H_2(g)uarr#</mathjax></p> <p>This is a common reaction between an acid and metal, where it produces a salt and hydrogen gas. </p> <p>From here, I see that everything is balanced, except that there are two silver atoms on the right side, but only one on the left side, so we multiply <mathjax>#Ag#</mathjax> on the left by <mathjax>#2#</mathjax> to get the balanced equation:</p> <p><mathjax>#2Ag(s)+H_2S(aq)-&gt;Ag_2S(aq)+H_2(g)uarr#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Put a coefficient of <mathjax>#2#</mathjax> in the first <mathjax>#Ag#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your equation is:</p> <p><mathjax>#Ag(s)+H_2S(aq)-&gt;Ag_2S(aq)+H_2(g)uarr#</mathjax></p> <p>This is a common reaction between an acid and metal, where it produces a salt and hydrogen gas. </p> <p>From here, I see that everything is balanced, except that there are two silver atoms on the right side, but only one on the left side, so we multiply <mathjax>#Ag#</mathjax> on the left by <mathjax>#2#</mathjax> to get the balanced equation:</p> <p><mathjax>#2Ag(s)+H_2S(aq)-&gt;Ag_2S(aq)+H_2(g)uarr#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you balance the following equation: #Ag + H_2S → Ag_2S + H_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="599474" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nam-d"><img alt="" class="" src="https://profilepictures.socratic.org/QG4MnkoER6u99DIDVWKK_787554714770341.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nam-d"> Nam D. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-04-22T01:45:43" itemprop="dateCreated"> Apr 22, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Put a coefficient of <mathjax>#2#</mathjax> in the first <mathjax>#Ag#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your equation is:</p> <p><mathjax>#Ag(s)+H_2S(aq)-&gt;Ag_2S(aq)+H_2(g)uarr#</mathjax></p> <p>This is a common reaction between an acid and metal, where it produces a salt and hydrogen gas. </p> <p>From here, I see that everything is balanced, except that there are two silver atoms on the right side, but only one on the left side, so we multiply <mathjax>#Ag#</mathjax> on the left by <mathjax>#2#</mathjax> to get the balanced equation:</p> <p><mathjax>#2Ag(s)+H_2S(aq)-&gt;Ag_2S(aq)+H_2(g)uarr#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/599474" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------&gt; H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -&gt; Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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How do you balance the following equation: #Ag + H_2S → Ag_2S + H_2#?

aa226e86-6ddd-11ea-8c4b-ccda262736ce

https://socratic.org/questions/what-mass-of-ticl-4-is-needed-to-produce-25-0-g-of-ti-if-the-reaction-proceeds-w

121 g

start physical_unit 3 3 mass g qc_end physical_unit 11 11 8 9 mass qc_end physical_unit 13 14 18 18 percent_yield qc_end chemical_equation 23 31 qc_end end

[{"type":"physical unit","value":"Mass [OF] TiCl4 [IN] g"}]

[{"type":"physical unit","value":"121 g"}]

[{"type":"physical unit","value":"Mass [OF] Ti [=] \\pu{25.0 g}"},{"type":"physical unit","value":"Yield [OF] the reaction [=] \\pu{82%}"},{"type":"chemical equation","value":"TiCl4 + 2 Mg -> Ti + 2 MgCl2"}]

<h1 class="questionTitle" itemprop="name">What mass of #TiCl_4# is needed to produce 25.0 g of #Ti# if the reaction proceeds with an 82% yield in the reaction #TiCl_4 + 2Mg -&gt; Ti + 2MgCl_2#?</h1>

121 g

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>1. Write the balanced equation</strong></p> <p>The balanced equation is</p> <p><mathjax>#"TiCl"_4 + "2Mg" → "Ti" + "2MgCl"_2#</mathjax></p> <blockquote></blockquote> <p><strong>2. Calculate the theoretical amount of Ti</strong></p> <p>An 82 % yield means that we get 82 g of product from a theoretical value of 100 g.</p> <p>∴ <mathjax>#"Theoretical yield" = 25.0 color(red)(cancel(color(black)("g actual"))) × "100 g theoretical"/(82 color(red)(cancel(color(black)("g actual"))))= "30.5 g theoretical"#</mathjax></p> <p>We must plan to get 30.5 g of <mathjax>#"Ti"#</mathjax> to produce an actual yield of 25.0 g.</p> <blockquote></blockquote> <p><strong>3. Calculate the moles of <mathjax>#"Ti"#</mathjax></strong></p> <p><mathjax>#"Moles of Ti" = 30.5 color(red)(cancel(color(black)("g Ti"))) × "1 mol Ti"/(47.87 color(red)(cancel(color(black)("g Ti")))) = "0.637 mol Ti"#</mathjax></p> <blockquote></blockquote> <p><strong>4. Calculate the moles of <mathjax>#"TiCl"_4#</mathjax></strong></p> <p><mathjax>#"Moles of TiCl"_4 = 0.637 color(red)(cancel(color(black)("mol Ti"))) × ("1 mol TiCl"_4)/(1 color(red)(cancel(color(black)("mol Ti")))) = "0.637 mol TiCl"_4#</mathjax></p> <blockquote></blockquote> <p><strong>5. Calculate the mass of <mathjax>#"TiCl"_4#</mathjax></strong></p> <p><mathjax>#"Mass of TiCl"_ 4 = 0.637 color(red)(cancel(color(black)("mol TiCl"_4))) × "189.68 g TiCl"_4/(1 color(red)(cancel(color(black)("mol TiCl"_4)))) = "121 g TiCl"_4#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You need 121 g of <mathjax>#"TiCl"_4#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>1. Write the balanced equation</strong></p> <p>The balanced equation is</p> <p><mathjax>#"TiCl"_4 + "2Mg" → "Ti" + "2MgCl"_2#</mathjax></p> <blockquote></blockquote> <p><strong>2. Calculate the theoretical amount of Ti</strong></p> <p>An 82 % yield means that we get 82 g of product from a theoretical value of 100 g.</p> <p>∴ <mathjax>#"Theoretical yield" = 25.0 color(red)(cancel(color(black)("g actual"))) × "100 g theoretical"/(82 color(red)(cancel(color(black)("g actual"))))= "30.5 g theoretical"#</mathjax></p> <p>We must plan to get 30.5 g of <mathjax>#"Ti"#</mathjax> to produce an actual yield of 25.0 g.</p> <blockquote></blockquote> <p><strong>3. Calculate the moles of <mathjax>#"Ti"#</mathjax></strong></p> <p><mathjax>#"Moles of Ti" = 30.5 color(red)(cancel(color(black)("g Ti"))) × "1 mol Ti"/(47.87 color(red)(cancel(color(black)("g Ti")))) = "0.637 mol Ti"#</mathjax></p> <blockquote></blockquote> <p><strong>4. Calculate the moles of <mathjax>#"TiCl"_4#</mathjax></strong></p> <p><mathjax>#"Moles of TiCl"_4 = 0.637 color(red)(cancel(color(black)("mol Ti"))) × ("1 mol TiCl"_4)/(1 color(red)(cancel(color(black)("mol Ti")))) = "0.637 mol TiCl"_4#</mathjax></p> <blockquote></blockquote> <p><strong>5. Calculate the mass of <mathjax>#"TiCl"_4#</mathjax></strong></p> <p><mathjax>#"Mass of TiCl"_ 4 = 0.637 color(red)(cancel(color(black)("mol TiCl"_4))) × "189.68 g TiCl"_4/(1 color(red)(cancel(color(black)("mol TiCl"_4)))) = "121 g TiCl"_4#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What mass of #TiCl_4# is needed to produce 25.0 g of #Ti# if the reaction proceeds with an 82% yield in the reaction #TiCl_4 + 2Mg -&gt; Ti + 2MgCl_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/percent-yield" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Yield</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="284075" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-03T00:10:12" itemprop="dateCreated"> Jul 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You need 121 g of <mathjax>#"TiCl"_4#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>1. Write the balanced equation</strong></p> <p>The balanced equation is</p> <p><mathjax>#"TiCl"_4 + "2Mg" → "Ti" + "2MgCl"_2#</mathjax></p> <blockquote></blockquote> <p><strong>2. Calculate the theoretical amount of Ti</strong></p> <p>An 82 % yield means that we get 82 g of product from a theoretical value of 100 g.</p> <p>∴ <mathjax>#"Theoretical yield" = 25.0 color(red)(cancel(color(black)("g actual"))) × "100 g theoretical"/(82 color(red)(cancel(color(black)("g actual"))))= "30.5 g theoretical"#</mathjax></p> <p>We must plan to get 30.5 g of <mathjax>#"Ti"#</mathjax> to produce an actual yield of 25.0 g.</p> <blockquote></blockquote> <p><strong>3. Calculate the moles of <mathjax>#"Ti"#</mathjax></strong></p> <p><mathjax>#"Moles of Ti" = 30.5 color(red)(cancel(color(black)("g Ti"))) × "1 mol Ti"/(47.87 color(red)(cancel(color(black)("g Ti")))) = "0.637 mol Ti"#</mathjax></p> <blockquote></blockquote> <p><strong>4. Calculate the moles of <mathjax>#"TiCl"_4#</mathjax></strong></p> <p><mathjax>#"Moles of TiCl"_4 = 0.637 color(red)(cancel(color(black)("mol Ti"))) × ("1 mol TiCl"_4)/(1 color(red)(cancel(color(black)("mol Ti")))) = "0.637 mol TiCl"_4#</mathjax></p> <blockquote></blockquote> <p><strong>5. Calculate the mass of <mathjax>#"TiCl"_4#</mathjax></strong></p> <p><mathjax>#"Mass of TiCl"_ 4 = 0.637 color(red)(cancel(color(black)("mol TiCl"_4))) × "189.68 g TiCl"_4/(1 color(red)(cancel(color(black)("mol TiCl"_4)))) = "121 g TiCl"_4#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/284075" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ebd02bf3469570e2e62"> Question #e2e62 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec502bf34694a4fee2e"> Question #fee2e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec902bf34694a4fee32"> Question #fee32 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ece02bf346950519e89"> Question #19e89 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ed302bf34694c8c5bdc"> Question #c5bdc </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ee302bf3469517a1065"> Question #a1065 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-26-0-grams-of-c3h9n-were-reacted-with-46-3"> What would be the limiting reagent if 26.0 grams of C3H9N were reacted with 46.3 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-percent-yield-always-less-than-100"> Is percent yield always less than 100? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-41-9-grams-of-c2h3of-were-reacted-with-61-"> What would be the limiting reagent if 41.9 grams of C2H3OF were reacted with 61.0 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-yield-of-the-following-reaction-if-60-grams-of-caco3-is-heat"> What is the percent yield of the following reaction if 60 grams of CaCO3 is heated to give 15... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/percent-yield"> See all questions in Percent Yield </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6657 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What mass of #TiCl_4# is needed to produce 25.0 g of #Ti# if the reaction proceeds with an 82% yield in the reaction #TiCl_4 + 2Mg -&gt; Ti + 2MgCl_2#?

ab359ec0-6ddd-11ea-9dff-ccda262736ce

https://socratic.org/questions/what-is-the-cell-potential-for-the-reaction-mg-s-fe-2-aq-rarrmg-2-aq-fe-s-at-47-

1.96 V

start physical_unit 6 7 cell_potential v qc_end physical_unit 6 7 16 17 temperature qc_end chemical_equation 8 14 qc_end end

[{"type":"physical unit","value":"Cell potential [OF] the reaction [IN] V"}]

[{"type":"physical unit","value":"1.96 V"}]

[{"type":"physical unit","value":"Temperature [OF] the reaction [=] \\pu{47 ℃}"},{"type":"chemical equation","value":"Mg(s) + Fe^2+(aq) -> Mg^2+(aq) + Fe(s)"},{"type":"physical unit","value":"[Fe^2+] [OF] solution [=] \\pu{3.50 M}"},{"type":"physical unit","value":"[Mg^2+] [OF] solution [=] \\pu{0.110 M}"}]

<h1 class="questionTitle" itemprop="name">What is the cell potential for the reaction# Mg(s)+Fe^(2+)(aq)\rarrMg^(2+)(aq)+Fe(s)# at 47 °C when #[Fe^(2+)]#= 3.50 M and #[Mg^(2+)]#= 0.110 M?</h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Notes:<br/> To learn how to use the Nernst equation.<br/> The standard reduction potentials listed in any reference table are only valid at standard-state conditions of 25 °C and 1 M. To calculate the cell potential at non-standard-state conditions, one uses the Nernst equation,</p> <p><mathjax>#E=E°−(2.303RT)/(nF)\log_10Q#</mathjax><br/> where E is the potential in volts, E° is the standard potential in volts, R=8.314J/(K⋅mol) is the gas constant, T is the temperature in kelvins, n is the number of moles of electrons transferred, <mathjax>#F=96,500C/(\text(mol )e^(-))#</mathjax> is the Faraday constant, and Q is the reaction quotient.</p> <p>Substituting each constant into the equation the result is</p> <p><mathjax>#E=E°-(0.0592 V)/nlog_10Q#</mathjax></p></div> </h2> </div> </div>

1.96 V

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Please check if my work is correct!</strong><br/> Extra data:</p> <ul> <li>Q = <mathjax>#3.14\cdot10^(-2)#</mathjax></li> <li>T = 320 K</li> <li>n = 2 mol</li> <li>E° = 1.92 V</li> </ul> <p>My work:<br/> <mathjax>#E=1.92 V - (0.0592 V)/(2 mol)\log_10(3.14\cdot10^(-2))\approx 1.96 V#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.96 V#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Please check if my work is correct!</strong><br/> Extra data:</p> <ul> <li>Q = <mathjax>#3.14\cdot10^(-2)#</mathjax></li> <li>T = 320 K</li> <li>n = 2 mol</li> <li>E° = 1.92 V</li> </ul> <p>My work:<br/> <mathjax>#E=1.92 V - (0.0592 V)/(2 mol)\log_10(3.14\cdot10^(-2))\approx 1.96 V#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the cell potential for the reaction# Mg(s)+Fe^(2+)(aq)\rarrMg^(2+)(aq)+Fe(s)# at 47 °C when #[Fe^(2+)]#= 3.50 M and #[Mg^(2+)]#= 0.110 M?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Notes:<br/> To learn how to use the Nernst equation.<br/> The standard reduction potentials listed in any reference table are only valid at standard-state conditions of 25 °C and 1 M. To calculate the cell potential at non-standard-state conditions, one uses the Nernst equation,</p> <p><mathjax>#E=E°−(2.303RT)/(nF)\log_10Q#</mathjax><br/> where E is the potential in volts, E° is the standard potential in volts, R=8.314J/(K⋅mol) is the gas constant, T is the temperature in kelvins, n is the number of moles of electrons transferred, <mathjax>#F=96,500C/(\text(mol )e^(-))#</mathjax> is the Faraday constant, and Q is the reaction quotient.</p> <p>Substituting each constant into the equation the result is</p> <p><mathjax>#E=E°-(0.0592 V)/nlog_10Q#</mathjax></p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/calculating-energy-in-electrochemical-processes" itemprop="url"> <span class="breadcrumb" itemprop="title">Calculating Energy in Electrochemical Processes</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="417872" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/reno-a"><img alt="" class="" src="https://profilepictures.socratic.org/pJYnRtEIRJGgklm4tuPp_c20ce912ebe0452d6865508f040a4db4.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/reno-a"> seol </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-04T23:54:09" itemprop="dateCreated"> May 4, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.96 V#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Please check if my work is correct!</strong><br/> Extra data:</p> <ul> <li>Q = <mathjax>#3.14\cdot10^(-2)#</mathjax></li> <li>T = 320 K</li> <li>n = 2 mol</li> <li>E° = 1.92 V</li> </ul> <p>My work:<br/> <mathjax>#E=1.92 V - (0.0592 V)/(2 mol)\log_10(3.14\cdot10^(-2))\approx 1.96 V#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/417872" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-cells-generate-an-electrochemical-gradient"> How do cells generate an electrochemical gradient? 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What is the cell potential for the reaction# Mg(s)+Fe^(2+)(aq)\rarrMg^(2+)(aq)+Fe(s)# at 47 °C when #[Fe^(2+)]#= 3.50 M and #[Mg^(2+)]#= 0.110 M?

Notes: To learn how to use the Nernst equation. The standard reduction potentials listed in any reference table are only valid at standard-state conditions of 25 °C and 1 M. To calculate the cell potential at non-standard-state conditions, one uses the Nernst equation, #E=E°−(2.303RT)/(nF)\log_10Q# where E is the potential in volts, E° is the standard potential in volts, R=8.314J/(K⋅mol) is the gas constant, T is the temperature in kelvins, n is the number of moles of electrons transferred, #F=96,500C/(\text(mol )e^(-))# is the Faraday constant, and Q is the reaction quotient. Substituting each constant into the equation the result is #E=E°-(0.0592 V)/nlog_10Q#

ac7ac45a-6ddd-11ea-9d1f-ccda262736ce

https://socratic.org/questions/what-mass-of-aluminum-contains-twice-as-many-atoms-as-35-00-grams-of-copper

29.72 grams

start physical_unit 3 3 mass g qc_end physical_unit 13 13 10 11 mass qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Mass [OF] aluminum [IN] grams"}]

[{"type":"physical unit","value":"29.72 grams"}]

[{"type":"physical unit","value":"Mass [OF] copper [=] \\pu{35.00 grams}"},{"type":"other","value":"Aluminum contains twice as many atoms as copper."}]

<h1 class="questionTitle" itemprop="name">What mass of aluminum contains twice as many atoms as 35.00 grams of copper?</h1>

29.72 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#(35gCu)/(63.546g/(mol)Cu)=0.55078molCu#</mathjax></p> <p><mathjax>#0.55078mol*2=1.1015molAl#</mathjax></p> <p><mathjax>#1.1015molAl*26.982g/(mol)Al=29.72gAl#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#29.72gAl#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#(35gCu)/(63.546g/(mol)Cu)=0.55078molCu#</mathjax></p> <p><mathjax>#0.55078mol*2=1.1015molAl#</mathjax></p> <p><mathjax>#1.1015molAl*26.982g/(mol)Al=29.72gAl#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What mass of aluminum contains twice as many atoms as 35.00 grams of copper?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="465652" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/tcw1"><img alt="" class="" src="https://profilepictures.socratic.org/Ox6b9VazRq1N5FiU8YFj_fractal-026.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/tcw1"> tcw1 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-19T02:22:36" itemprop="dateCreated"> Aug 19, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#29.72gAl#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#(35gCu)/(63.546g/(mol)Cu)=0.55078molCu#</mathjax></p> <p><mathjax>#0.55078mol*2=1.1015molAl#</mathjax></p> <p><mathjax>#1.1015molAl*26.982g/(mol)Al=29.72gAl#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/465652" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="465655" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-19T02:34:23" itemprop="dateCreated"> Aug 19, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"29.72 g Al"#</mathjax> contains twice the number of atoms of <mathjax>#"35.00 g Cu"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to determine the mass of Al that contains twice as many atoms of Cu in 35.00 g, first determine the number of Cu atoms found in 35.00 g. Then multiply by 2 to get the number of atoms of Al, then determine the mass of Al.</p> <p>To determine the number of atoms of copper in <mathjax>#"35.00 g"#</mathjax>, calculate the moles <mathjax>#"Cu"#</mathjax> and multiply by <mathjax>#6.022xx10^23#</mathjax> atoms/mol.</p> <p><strong>Atoms of Cu</strong></p> <p>The molar mass of <mathjax>#"Cu"#</mathjax> is <mathjax>#"63.546 g/mol"#</mathjax>. To get moles, divide the given mass by the molar mass. Since g/mol is a fraction, <mathjax>#"g"/"mol"#</mathjax>, multiply the given mass by the inverse of the molar mass. Then multiply by <mathjax>#6.022xx10^23#</mathjax> atoms/mol.</p> <p><mathjax>#35.00color(red)cancel(color(black)("g Cu"))xx(1color(red)cancel(color(black)("mol Cu")))/(63.546color(red)cancel(color(black)("g Cu")))xx(6.022xx10^23"atoms Cu")/(1color(red)cancel(color(black)("mol Cu")))=3.317xx10^23"atoms Cu"#</mathjax></p> <p><strong>Mass of Al (molar mass = 26.982 g/mol)</strong></p> <p>Do the reverse of finding the atoms of <mathjax>#"Cu"#</mathjax>.</p> <p><strong>Atoms of Al:</strong></p> <p><mathjax>#2xx(3.317xx10^23)=6.634xx10^23"atoms Al"#</mathjax></p> <p><strong>Mass of Al:</strong></p> <p><mathjax>#6.634xx10^23color(red)cancel(color(black)("atoms Al"))xx(1color(red)cancel(color(black)("mol Al")))/(6.022xx10^23color(red)cancel(color(black)("atoms Al")))xx(26.982"g Al")/(1color(red)cancel(color(black)("mol Al")))="29.72 g Al"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/465655" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2510 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What mass of aluminum contains twice as many atoms as 35.00 grams of copper?

aa5f60d9-6ddd-11ea-ad71-ccda262736ce

https://socratic.org/questions/a-sample-of-carbon-dioxide-occupies-a-volume-of-3-50-l-at-125-atm-pressure-what-

175 atm

start physical_unit 18 19 pressure atm qc_end physical_unit 1 4 12 13 pressure qc_end physical_unit 1 4 9 10 volume qc_end physical_unit 1 4 27 28 volume qc_end end

[{"type":"physical unit","value":"Pressure2 [OF] the gas [IN] atm"}]

[{"type":"physical unit","value":"175 atm"}]

[{"type":"physical unit","value":"Pressure1 [OF] carbon dioxide sample [=] \\pu{125 atm}"},{"type":"physical unit","value":"Volume1 [OF] carbon dioxide sample [=] \\pu{3.50 L}"},{"type":"physical unit","value":"Volume2 [OF] carbon dioxide sample [=] \\pu{2.00 L}"}]

<h1 class="questionTitle" itemprop="name">A sample of carbon dioxide occupies a volume of 3.50 L at 125 atm pressure. What pressure would the gas exert if the volume was decreased to 2.00 L? </h1>

175 atm

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>According to Boyle's Law</p> <p><mathjax>#P_1V_1#</mathjax> = <mathjax>#P_2V_2#</mathjax></p> <p>(125)(3.50) = <mathjax>#P_2#</mathjax> (2.0)</p> <p><mathjax>#P_2#</mathjax> = <mathjax>#(125)(3.50)/(2.50)#</mathjax> = 175 atm</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Using <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a> we find an answer of 175 atm for the new pressure.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>According to Boyle's Law</p> <p><mathjax>#P_1V_1#</mathjax> = <mathjax>#P_2V_2#</mathjax></p> <p>(125)(3.50) = <mathjax>#P_2#</mathjax> (2.0)</p> <p><mathjax>#P_2#</mathjax> = <mathjax>#(125)(3.50)/(2.50)#</mathjax> = 175 atm</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A sample of carbon dioxide occupies a volume of 3.50 L at 125 atm pressure. What pressure would the gas exert if the volume was decreased to 2.00 L? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/measuring-gas-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Measuring Gas Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="352002" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/dwight"><img alt="" class="" src="https://profilepictures.socratic.org/ZDiTFWmAQmWOT3sd0Xpr_Dwight.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/dwight"> Dwight </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-15T04:47:26" itemprop="dateCreated"> Dec 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Using <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's law</a> we find an answer of 175 atm for the new pressure.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>According to Boyle's Law</p> <p><mathjax>#P_1V_1#</mathjax> = <mathjax>#P_2V_2#</mathjax></p> <p>(125)(3.50) = <mathjax>#P_2#</mathjax> (2.0)</p> <p><mathjax>#P_2#</mathjax> = <mathjax>#(125)(3.50)/(2.50)#</mathjax> = 175 atm</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/352002" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-used-to-measure-gas-pressure-in-a-closed-container"> What is used to measure gas pressure in a closed container? 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</a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-boyle-s-law-practice-problem"> What is an example of a Boyle's law practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-boyle-s-law-and-charles-law-differ-1"> How do Boyle's law and Charles' law differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-measure-gas-pressure"> How can I measure gas pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyle-s-law-affect-the-human-body"> How does Boyle's law affect the human body? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/measuring-gas-pressure"> See all questions in Measuring Gas Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 25732 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A sample of carbon dioxide occupies a volume of 3.50 L at 125 atm pressure. What pressure would the gas exert if the volume was decreased to 2.00 L?

a991624a-6ddd-11ea-b4cf-ccda262736ce

https://socratic.org/questions/what-is-the-ph-of-a-1-4-10-2-m-naoh-solution

12.15

start physical_unit 10 11 ph none qc_end physical_unit 10 11 6 9 molarity qc_end end

[{"type":"physical unit","value":"pH [OF] NaOH solution"}]

[{"type":"physical unit","value":"12.15"}]

[{"type":"physical unit","value":"Molarity [OF] NaOH solution [=] \\pu{1.4 × 10^(-2) M}"}]

<h1 class="questionTitle" itemprop="name">What is the pH of a #1.4 * 10^-2 M# NaOH solution?</h1>

12.15

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Even before doing any calculations, you can say that since you're dealing with a <strong> strong base</strong>, the <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the solution <strong>must</strong> be <strong>higher</strong> than <mathjax>#7#</mathjax>. </p> <p>The higher the concentration of the base, the <strong>higher</strong> the pH will be. </p> <p>In your case, you're dealing with a solution of <em>sodium hydroxide</em>, <mathjax>#"NaOH"#</mathjax>, a strong base that dissociates completely in aqueous solution to form sodium cations, <mathjax>#"Na"^(+)#</mathjax>, and <em>hydroxide anions</em>, <mathjax>#"OH"^(-)#</mathjax></p> <blockquote> <p><mathjax>#"NaOH"_text((aq]) -&gt; "Na"_text((aq])^(+) + "OH"_text((aq])^(-)#</mathjax></p> </blockquote> <p><img alt="http://wps.prenhall.com/wps/media/objects/476/488316/ch14.html" src="https://useruploads.socratic.org/dUPEeD8fQcyibvFrk6Hu_FG14_13.JPG"/> </p> <p>Notice that the salt dissociates in a <mathjax>#1:1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> with the hydroxide anions, you you can say that </p> <blockquote> <p><mathjax>#["OH"^(-)] = ["NaOH"] = 1.4 * 10^(-2)"M"#</mathjax></p> </blockquote> <p>Now, the pH of the solution is determined by the concentration of <strong>hydronium ions</strong>, <mathjax>#"H"_3"O"^(+)#</mathjax>. For aqueous <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>, the concentration of hydronium ions is related to the concentration of hydroxide ions by the <strong>ion product constant</strong> of water, <mathjax>#K_W#</mathjax></p> <blockquote> <p><mathjax>#K_W = ["OH"^(-)] * ["H"_3"O"^(+)]#</mathjax></p> </blockquote> <p>At room temperature, you have </p> <blockquote> <p><mathjax>#K_W = 10^(-14)#</mathjax></p> </blockquote> <p>This means that the concentration of hydronium ions can be determined by using </p> <blockquote> <p><mathjax>#["H"_3"O"^(+)] = K_W/(["OH"^(-)])#</mathjax></p> </blockquote> <p>Plug in your values to get </p> <blockquote> <p><mathjax>#["H"_3"O"^(+)] = 10^(-14)/(1.4 * 10^(-2)) = 7.14 * 10^(-13)"M"#</mathjax></p> </blockquote> <p>The pH of the solution is equal to </p> <blockquote> <p><mathjax>#color(blue)("pH" = - log(["H"_3"O"^(+)])#</mathjax></p> </blockquote> <p>In your case, </p> <blockquote> <p><mathjax>#"pH" = -log(7.14 * 10^(-13)) = color(green)(12.15)#</mathjax></p> </blockquote> <p>As predicted, the pH is not only higher than <mathjax>#7#</mathjax>, but it is <em>significantly</em> higher than <mathjax>#7#</mathjax>. </p> <p><strong>Alternatively</strong>, you can use the pOH of the solution to find its pH. As you know, </p> <blockquote> <p><mathjax>#color(blue)("pOH" = - log(["OH"^(-)]))#</mathjax></p> </blockquote> <p>In your case, </p> <blockquote> <p><mathjax>#"pOH" = - log(1.4 * 10^(-2)) = 1.85#</mathjax></p> </blockquote> <p>You know that</p> <blockquote> <p><mathjax>#color(blue)("pH" + "pOH" = 14)#</mathjax></p> </blockquote> <p>and so, once again, you have </p> <blockquote> <p><mathjax>#"pH" = 14 - 1.85 = color(green)(12.15)#</mathjax></p> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 12.15#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Even before doing any calculations, you can say that since you're dealing with a <strong> strong base</strong>, the <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the solution <strong>must</strong> be <strong>higher</strong> than <mathjax>#7#</mathjax>. </p> <p>The higher the concentration of the base, the <strong>higher</strong> the pH will be. </p> <p>In your case, you're dealing with a solution of <em>sodium hydroxide</em>, <mathjax>#"NaOH"#</mathjax>, a strong base that dissociates completely in aqueous solution to form sodium cations, <mathjax>#"Na"^(+)#</mathjax>, and <em>hydroxide anions</em>, <mathjax>#"OH"^(-)#</mathjax></p> <blockquote> <p><mathjax>#"NaOH"_text((aq]) -&gt; "Na"_text((aq])^(+) + "OH"_text((aq])^(-)#</mathjax></p> </blockquote> <p><img alt="http://wps.prenhall.com/wps/media/objects/476/488316/ch14.html" src="https://useruploads.socratic.org/dUPEeD8fQcyibvFrk6Hu_FG14_13.JPG"/> </p> <p>Notice that the salt dissociates in a <mathjax>#1:1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> with the hydroxide anions, you you can say that </p> <blockquote> <p><mathjax>#["OH"^(-)] = ["NaOH"] = 1.4 * 10^(-2)"M"#</mathjax></p> </blockquote> <p>Now, the pH of the solution is determined by the concentration of <strong>hydronium ions</strong>, <mathjax>#"H"_3"O"^(+)#</mathjax>. For aqueous <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>, the concentration of hydronium ions is related to the concentration of hydroxide ions by the <strong>ion product constant</strong> of water, <mathjax>#K_W#</mathjax></p> <blockquote> <p><mathjax>#K_W = ["OH"^(-)] * ["H"_3"O"^(+)]#</mathjax></p> </blockquote> <p>At room temperature, you have </p> <blockquote> <p><mathjax>#K_W = 10^(-14)#</mathjax></p> </blockquote> <p>This means that the concentration of hydronium ions can be determined by using </p> <blockquote> <p><mathjax>#["H"_3"O"^(+)] = K_W/(["OH"^(-)])#</mathjax></p> </blockquote> <p>Plug in your values to get </p> <blockquote> <p><mathjax>#["H"_3"O"^(+)] = 10^(-14)/(1.4 * 10^(-2)) = 7.14 * 10^(-13)"M"#</mathjax></p> </blockquote> <p>The pH of the solution is equal to </p> <blockquote> <p><mathjax>#color(blue)("pH" = - log(["H"_3"O"^(+)])#</mathjax></p> </blockquote> <p>In your case, </p> <blockquote> <p><mathjax>#"pH" = -log(7.14 * 10^(-13)) = color(green)(12.15)#</mathjax></p> </blockquote> <p>As predicted, the pH is not only higher than <mathjax>#7#</mathjax>, but it is <em>significantly</em> higher than <mathjax>#7#</mathjax>. </p> <p><strong>Alternatively</strong>, you can use the pOH of the solution to find its pH. As you know, </p> <blockquote> <p><mathjax>#color(blue)("pOH" = - log(["OH"^(-)]))#</mathjax></p> </blockquote> <p>In your case, </p> <blockquote> <p><mathjax>#"pOH" = - log(1.4 * 10^(-2)) = 1.85#</mathjax></p> </blockquote> <p>You know that</p> <blockquote> <p><mathjax>#color(blue)("pH" + "pOH" = 14)#</mathjax></p> </blockquote> <p>and so, once again, you have </p> <blockquote> <p><mathjax>#"pH" = 14 - 1.85 = color(green)(12.15)#</mathjax></p> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the pH of a #1.4 * 10^-2 M# NaOH solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="204831" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-28T18:12:13" itemprop="dateCreated"> Dec 28, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 12.15#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Even before doing any calculations, you can say that since you're dealing with a <strong> strong base</strong>, the <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the solution <strong>must</strong> be <strong>higher</strong> than <mathjax>#7#</mathjax>. </p> <p>The higher the concentration of the base, the <strong>higher</strong> the pH will be. </p> <p>In your case, you're dealing with a solution of <em>sodium hydroxide</em>, <mathjax>#"NaOH"#</mathjax>, a strong base that dissociates completely in aqueous solution to form sodium cations, <mathjax>#"Na"^(+)#</mathjax>, and <em>hydroxide anions</em>, <mathjax>#"OH"^(-)#</mathjax></p> <blockquote> <p><mathjax>#"NaOH"_text((aq]) -&gt; "Na"_text((aq])^(+) + "OH"_text((aq])^(-)#</mathjax></p> </blockquote> <p><img alt="http://wps.prenhall.com/wps/media/objects/476/488316/ch14.html" src="https://useruploads.socratic.org/dUPEeD8fQcyibvFrk6Hu_FG14_13.JPG"/> </p> <p>Notice that the salt dissociates in a <mathjax>#1:1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> with the hydroxide anions, you you can say that </p> <blockquote> <p><mathjax>#["OH"^(-)] = ["NaOH"] = 1.4 * 10^(-2)"M"#</mathjax></p> </blockquote> <p>Now, the pH of the solution is determined by the concentration of <strong>hydronium ions</strong>, <mathjax>#"H"_3"O"^(+)#</mathjax>. For aqueous <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a>, the concentration of hydronium ions is related to the concentration of hydroxide ions by the <strong>ion product constant</strong> of water, <mathjax>#K_W#</mathjax></p> <blockquote> <p><mathjax>#K_W = ["OH"^(-)] * ["H"_3"O"^(+)]#</mathjax></p> </blockquote> <p>At room temperature, you have </p> <blockquote> <p><mathjax>#K_W = 10^(-14)#</mathjax></p> </blockquote> <p>This means that the concentration of hydronium ions can be determined by using </p> <blockquote> <p><mathjax>#["H"_3"O"^(+)] = K_W/(["OH"^(-)])#</mathjax></p> </blockquote> <p>Plug in your values to get </p> <blockquote> <p><mathjax>#["H"_3"O"^(+)] = 10^(-14)/(1.4 * 10^(-2)) = 7.14 * 10^(-13)"M"#</mathjax></p> </blockquote> <p>The pH of the solution is equal to </p> <blockquote> <p><mathjax>#color(blue)("pH" = - log(["H"_3"O"^(+)])#</mathjax></p> </blockquote> <p>In your case, </p> <blockquote> <p><mathjax>#"pH" = -log(7.14 * 10^(-13)) = color(green)(12.15)#</mathjax></p> </blockquote> <p>As predicted, the pH is not only higher than <mathjax>#7#</mathjax>, but it is <em>significantly</em> higher than <mathjax>#7#</mathjax>. </p> <p><strong>Alternatively</strong>, you can use the pOH of the solution to find its pH. As you know, </p> <blockquote> <p><mathjax>#color(blue)("pOH" = - log(["OH"^(-)]))#</mathjax></p> </blockquote> <p>In your case, </p> <blockquote> <p><mathjax>#"pOH" = - log(1.4 * 10^(-2)) = 1.85#</mathjax></p> </blockquote> <p>You know that</p> <blockquote> <p><mathjax>#color(blue)("pH" + "pOH" = 14)#</mathjax></p> </blockquote> <p>and so, once again, you have </p> <blockquote> <p><mathjax>#"pH" = 14 - 1.85 = color(green)(12.15)#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/204831" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 68786 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the pH of a #1.4 * 10^-2 M# NaOH solution?

aaad1281-6ddd-11ea-bb07-ccda262736ce

https://socratic.org/questions/what-is-the-oxidation-state-of-magnesium

+2

start physical_unit 6 6 oxidation_state none qc_end substance 6 6 qc_end end

[{"type":"physical unit","value":"Oxidation state [OF] magnesium"}]

[{"type":"physical unit","value":"+2"}]

[{"type":"substance name","value":"Magnesium"}]

<h1 class="questionTitle" itemprop="name">What is the oxidation state of magnesium?</h1>

+2

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The electrical ground state of magnesium is <mathjax># 1s^2 2s^2 2p^6 3s^2#</mathjax></p> <p>The 3s electrons are not stable. If magnesium loses the 2 3s electrons it has the electron configuration of Neon which is stable.</p> <p>So when Magnesium loses the 2 3s electrons it has a charge of +2</p> <p>Magnesium still has 12 protons but now has only 10 electrons</p> <p>The 12 protons have a charge of +12 <br/> The 10 electrons have a charge of -10</p> <p>+12 + (-10) = + 2 </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The oxidation number of magnesium is +2 </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The electrical ground state of magnesium is <mathjax># 1s^2 2s^2 2p^6 3s^2#</mathjax></p> <p>The 3s electrons are not stable. If magnesium loses the 2 3s electrons it has the electron configuration of Neon which is stable.</p> <p>So when Magnesium loses the 2 3s electrons it has a charge of +2</p> <p>Magnesium still has 12 protons but now has only 10 electrons</p> <p>The 12 protons have a charge of +12 <br/> The 10 electrons have a charge of -10</p> <p>+12 + (-10) = + 2 </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the oxidation state of magnesium?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-and-reduction-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation and Reduction Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="310854" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/david-drayer"><img alt="" class="" src="https://graph.facebook.com/10206723679871989/picture?height=50&amp;width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/david-drayer"> David Drayer </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-16T12:49:22" itemprop="dateCreated"> Sep 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The oxidation number of magnesium is +2 </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The electrical ground state of magnesium is <mathjax># 1s^2 2s^2 2p^6 3s^2#</mathjax></p> <p>The 3s electrons are not stable. If magnesium loses the 2 3s electrons it has the electron configuration of Neon which is stable.</p> <p>So when Magnesium loses the 2 3s electrons it has a charge of +2</p> <p>Magnesium still has 12 protons but now has only 10 electrons</p> <p>The 12 protons have a charge of +12 <br/> The 10 electrons have a charge of -10</p> <p>+12 + (-10) = + 2 </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/310854" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-balance-equations-with-charges"> How to balance equations for reduction/oxidation reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-an-electode-reaction-has-dssolved-oxygen-as-a-reactant-is-the-electrode-an-an"> If an electode reaction has dssolved oxygen as a reactant, is the electrode an anode or a cathode? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-an-electrode-reaction-has-dissolved-oxygen-as-a-reactant-is-the-electrode-and"> If an electrode reaction has dissolved oxygen as a reactant, is the electrode and anode or a cathode? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-balanced-equation-represents-a-redox-reaction-2"> What balanced equation represents a redox reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-redox-reactions-involved-in-electrolysis"> How are redox reactions involved in electrolysis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-oxidation-reduction-reactions-coupled"> Why are oxidation reduction reactions coupled? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-do-oxidation-reduction-reactions-involve"> What do oxidation reduction reactions involve? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-reduction-reactions-used-for"> What are reduction reactions used for? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-calx-mean-in-oxidation-reduction-reactions"> What does "calx" mean in oxidation reduction reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-the-reduced-components-in-this-reaction-zn-2h-zn-2-h2"> What are the reduced components in this reaction? Zn + 2H(+) → Zn(2+) + H2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-and-reduction-reactions"> See all questions in Oxidation and Reduction Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 8973 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the oxidation state of magnesium?

aa91e840-6ddd-11ea-ae66-ccda262736ce

https://socratic.org/questions/59bb4bf511ef6b314c20ce96

8.00 L

start physical_unit 10 10 volume l qc_end physical_unit 10 10 6 7 mass qc_end physical_unit 10 10 25 26 pressure qc_end physical_unit 10 10 31 32 temperature qc_end end

[{"type":"physical unit","value":"Volume [OF] ammonia [IN] L"}]

[{"type":"physical unit","value":"8.00 L"}]

[{"type":"physical unit","value":"Mass [OF] ammonia [=] \\pu{5.0 g}"},{"type":"physical unit","value":"Pressure [OF] ammonia [=] \\pu{740 mmHg}"},{"type":"physical unit","value":"Temperature [OF] ammonia [=] \\pu{50 ℃}"}]

<h1 class="questionTitle" itemprop="name">What volume is occupied by a #5.0*g# mass of ammonia that is placed in a piston and allowed to expand against a pressure of #740*mm*Hg# at a temperature of #50# #""^@C#?</h1>

8.00 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the old Ideal Gas equation.....</p> <p><mathjax>#V=(nRT)/P=((5.0*g)/(17.03*g*mol^-1)xx0.0821*(L*atm)/(K*mol)xx323*K)/((740*mm*Hg)/(760*mm*Hg*atm^-1))#</mathjax></p> <p><mathjax>#~=8*L#</mathjax>......</p> <p>Do the units in the expression cancel out to give an answer in litres? If they do not, then we have made a mistake. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>So we conceive that in this experiment, a mass of condensed ammonia is enclosed in a piston, which is allowed to expand against a pressure of <mathjax>#740*mm*Hg#</mathjax> and a temperature of <mathjax>#50#</mathjax> <mathjax>#""^@C#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the old Ideal Gas equation.....</p> <p><mathjax>#V=(nRT)/P=((5.0*g)/(17.03*g*mol^-1)xx0.0821*(L*atm)/(K*mol)xx323*K)/((740*mm*Hg)/(760*mm*Hg*atm^-1))#</mathjax></p> <p><mathjax>#~=8*L#</mathjax>......</p> <p>Do the units in the expression cancel out to give an answer in litres? If they do not, then we have made a mistake. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What volume is occupied by a #5.0*g# mass of ammonia that is placed in a piston and allowed to expand against a pressure of #740*mm*Hg# at a temperature of #50# #""^@C#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="475701" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-15T06:13:33" itemprop="dateCreated"> Sep 15, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>So we conceive that in this experiment, a mass of condensed ammonia is enclosed in a piston, which is allowed to expand against a pressure of <mathjax>#740*mm*Hg#</mathjax> and a temperature of <mathjax>#50#</mathjax> <mathjax>#""^@C#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the old Ideal Gas equation.....</p> <p><mathjax>#V=(nRT)/P=((5.0*g)/(17.03*g*mol^-1)xx0.0821*(L*atm)/(K*mol)xx323*K)/((740*mm*Hg)/(760*mm*Hg*atm^-1))#</mathjax></p> <p><mathjax>#~=8*L#</mathjax>......</p> <p>Do the units in the expression cancel out to give an answer in litres? If they do not, then we have made a mistake. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/475701" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1181 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What volume is occupied by a #5.0*g# mass of ammonia that is placed in a piston and allowed to expand against a pressure of #740*mm*Hg# at a temperature of #50# #""^@C#?

a8e50836-6ddd-11ea-aae4-ccda262736ce

https://socratic.org/questions/how-many-moles-of-sr-no-3-2-would-be-used-in-the-preparation-of-2-50-l-of-a-3-5-

8.8 moles

start physical_unit 4 4 mole mol qc_end physical_unit 4 4 16 17 molarity qc_end physical_unit 18 18 12 13 volume qc_end end

[{"type":"physical unit","value":"Mole [OF] Sr(NO3)2 [IN] moles"}]

[{"type":"physical unit","value":"8.8 moles"}]

[{"type":"physical unit","value":"Molarity [OF] Sr(NO3)2 solution [=] \\pu{3.5 M}"},{"type":"physical unit","value":"Volume [OF] Sr(NO3)2 solution [=] \\pu{2.50 L}"}]

<h1 class="questionTitle" itemprop="name">How many moles of #Sr(NO_3)_2# would be used in the preparation of 2.50 L of a 3.5 M solution?</h1>

8.8 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem can be directly solved using the standard formula</p> <p><mathjax>#"Molarity"(M)=(("number of moles")(eta))/(("Liter solution")(V)#</mathjax>, so that</p> <p><mathjax>#eta=(M)xx(V)#</mathjax></p> <p><mathjax>#eta=(3.5mol)/cancel(L)xx2.50cancelL#</mathjax></p> <p><mathjax>#eta=8.8mol#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#eta=8.8" mol of " Sr(NO_3)2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem can be directly solved using the standard formula</p> <p><mathjax>#"Molarity"(M)=(("number of moles")(eta))/(("Liter solution")(V)#</mathjax>, so that</p> <p><mathjax>#eta=(M)xx(V)#</mathjax></p> <p><mathjax>#eta=(3.5mol)/cancel(L)xx2.50cancelL#</mathjax></p> <p><mathjax>#eta=8.8mol#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles of #Sr(NO_3)_2# would be used in the preparation of 2.50 L of a 3.5 M solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solution-formation---what-happens-when-stuff-dissolves" itemprop="url"> <span class="breadcrumb" itemprop="title">Solution Formation</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="535452" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jarni-renz"><img alt="" class="" src="https://profilepictures.socratic.org/i6OiZQmVRHWljDVlwm8v_WIN_20160301_180231.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jarni-renz"> Jarni Renz </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-01-14T23:51:50" itemprop="dateCreated"> Jan 14, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#eta=8.8" mol of " Sr(NO_3)2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem can be directly solved using the standard formula</p> <p><mathjax>#"Molarity"(M)=(("number of moles")(eta))/(("Liter solution")(V)#</mathjax>, so that</p> <p><mathjax>#eta=(M)xx(V)#</mathjax></p> <p><mathjax>#eta=(3.5mol)/cancel(L)xx2.50cancelL#</mathjax></p> <p><mathjax>#eta=8.8mol#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/535452" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-temperature-affect-the-formation-of-a-solution"> How can temperature affect the formation of a solution? 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How many moles of #Sr(NO_3)_2# would be used in the preparation of 2.50 L of a 3.5 M solution?

aa20b3f7-6ddd-11ea-8a40-ccda262736ce

https://socratic.org/questions/what-is-the-volume-in-ml-of-a-2-50m-hcl-solution-that-must-be-used-in-order-to-c

161.00 mL

start physical_unit 10 11 volume ml qc_end physical_unit 10 11 8 9 molarity qc_end physical_unit 10 11 23 24 molarity qc_end physical_unit 10 11 21 22 volume qc_end end

[{"type":"physical unit","value":"Volume1 [OF] HCl solution [IN] mL"}]

[{"type":"physical unit","value":"161.00 mL"}]

[{"type":"physical unit","value":"Molarity1 [OF] HCl solution [=] \\pu{2.50 M}"},{"type":"physical unit","value":"Molarity2 [OF] HCl solution [=] \\pu{1.15 M}"},{"type":"physical unit","value":"Volume2 [OF] HCl solution [=] \\pu{350 mL}"}]

<h1 class="questionTitle" itemprop="name">What is the volume, in mL, of a 2.50M #HCl# solution that must be used in order to create a 350 mL 1.15M #HCl# solution?</h1>

161.00 mL

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a dilution problem.</p> <p>This formula must be known/looked up:</p> <p><mathjax>#M1 x V1 = M2 x V2#</mathjax></p> <p>Given:</p> <p>M1 = 2.50 M<br/> V1 = ?</p> <p>M2 = 1.15 M<br/> V2 = 350 mL <strong>(must be converted to L as <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is in mol/L)</strong></p> <p>Plug in the formula:</p> <p>2.50 x <mathjax>#V1#</mathjax> = 1.15 M x 0.350 L</p> <p><strong><mathjax>#V1#</mathjax> = 0.161 L</strong></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><strong>0.161 L</strong> of 2.50M HCl</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a dilution problem.</p> <p>This formula must be known/looked up:</p> <p><mathjax>#M1 x V1 = M2 x V2#</mathjax></p> <p>Given:</p> <p>M1 = 2.50 M<br/> V1 = ?</p> <p>M2 = 1.15 M<br/> V2 = 350 mL <strong>(must be converted to L as <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is in mol/L)</strong></p> <p>Plug in the formula:</p> <p>2.50 x <mathjax>#V1#</mathjax> = 1.15 M x 0.350 L</p> <p><strong><mathjax>#V1#</mathjax> = 0.161 L</strong></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the volume, in mL, of a 2.50M #HCl# solution that must be used in order to create a 350 mL 1.15M #HCl# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/dilution-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Dilution Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="271090" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/duc-t"><img alt="" class="" src="https://profilepictures.socratic.org/u2hTUu4RiOQiMhHE4cgw_11045387_10204593299244687_8686932263378317671_o.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/duc-t"> David Tran </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-29T19:08:02" itemprop="dateCreated"> May 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><strong>0.161 L</strong> of 2.50M HCl</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a dilution problem.</p> <p>This formula must be known/looked up:</p> <p><mathjax>#M1 x V1 = M2 x V2#</mathjax></p> <p>Given:</p> <p>M1 = 2.50 M<br/> V1 = ?</p> <p>M2 = 1.15 M<br/> V2 = 350 mL <strong>(must be converted to L as <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is in mol/L)</strong></p> <p>Plug in the formula:</p> <p>2.50 x <mathjax>#V1#</mathjax> = 1.15 M x 0.350 L</p> <p><strong><mathjax>#V1#</mathjax> = 0.161 L</strong></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/271090" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-absorbance"> How do you calculate concentration from absorbance? 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What is the volume, in mL, of a 2.50M #HCl# solution that must be used in order to create a 350 mL 1.15M #HCl# solution?

a8c0ed09-6ddd-11ea-b966-ccda262736ce

https://socratic.org/questions/how-many-grams-of-nh-4-2so-4-are-present-in-100-moles-of-nh-4-2so-4

132.14 grams

start physical_unit 4 4 mass g qc_end physical_unit 4 4 8 9 mole qc_end end

[{"type":"physical unit","value":"Mass [OF] (NH4)2SO4 [IN] grams"}]

[{"type":"physical unit","value":"132.14 grams"}]

[{"type":"physical unit","value":"Mole [OF] (NH4)2SO4 [=] \\pu{0.100 moles}"}]

<h1 class="questionTitle" itemprop="name">How many grams of #(NH_4)_2SO_4# are present in .100 moles of #(NH_4)_2SO_4# ?</h1>

132.14 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have a <mathjax>#0.100#</mathjax> <mathjax>#mol#</mathjax> quantity.</p> <p><mathjax>#0.100#</mathjax> <mathjax>#cancel(mol)#</mathjax> <mathjax>#xx#</mathjax> <mathjax>#132.14#</mathjax> <mathjax>#g*cancel(mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#g#</mathjax>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Ammonium sulfate has an equivalent weight of <mathjax>#132.14#</mathjax> <mathjax>#g*mol^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have a <mathjax>#0.100#</mathjax> <mathjax>#mol#</mathjax> quantity.</p> <p><mathjax>#0.100#</mathjax> <mathjax>#cancel(mol)#</mathjax> <mathjax>#xx#</mathjax> <mathjax>#132.14#</mathjax> <mathjax>#g*cancel(mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#g#</mathjax>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many grams of #(NH_4)_2SO_4# are present in .100 moles of #(NH_4)_2SO_4# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="230006" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-23T09:03:56" itemprop="dateCreated"> Feb 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Ammonium sulfate has an equivalent weight of <mathjax>#132.14#</mathjax> <mathjax>#g*mol^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have a <mathjax>#0.100#</mathjax> <mathjax>#mol#</mathjax> quantity.</p> <p><mathjax>#0.100#</mathjax> <mathjax>#cancel(mol)#</mathjax> <mathjax>#xx#</mathjax> <mathjax>#132.14#</mathjax> <mathjax>#g*cancel(mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#g#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/230006" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="230034" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-23T10:39:40" itemprop="dateCreated"> Feb 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The mass in grams of 0.100 mol <mathjax>#"(NH"_4)_2"SO"_4"#</mathjax> is 13.2 g.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molar mass of <mathjax>#"(NH"_4)_2"SO"_4"#</mathjax> is needed, which is <mathjax>#"132.13952 g/mol"#</mathjax>. <a href="http://pubchem.ncbi.nlm.nih.gov/compound/6097028#section=Top" rel="nofollow" target="_blank">http://pubchem.ncbi.nlm.nih.gov/compound/6097028#section=Top</a></p> <p>To determine the mass of 0.100 mol ammonium sulfate, multiply the given mole by its molar mass.</p> <p><mathjax>#0.100 cancel(mol (NH_4)_2SO_4)xx(132.13952 g (NH_4)_2SO_4)/(1 cancel(mol (NH_4)_2SO_4))=13.2 g (NH_4)_2SO_4"#</mathjax> (rounded to three significant figures)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/230034" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? 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How many grams of #(NH_4)_2SO_4# are present in .100 moles of #(NH_4)_2SO_4# ?

a8ce1710-6ddd-11ea-8b69-ccda262736ce

https://socratic.org/questions/570e403811ef6b071557bc25

12 mol/L

start physical_unit 8 8 molarity mol/l qc_end end

[{"type":"physical unit","value":"Molar concentration [OF] HCl(aq) [IN] mol/L"}]

[{"type":"physical unit","value":"12 mol/L"}]

[{"type":"physical unit","value":"w/w [OF] HCl(aq) in the solution [=] \\pu{78%}"}]

<h1 class="questionTitle" itemprop="name">What is the molar concentration of #"78% w/w"# #HCl(aq)#?</h1>

12 mol/L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The concentrated <mathjax>#HCl#</mathjax> solution supplied to laboratories is 38% (w/w), with <mathjax>#rho#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.189*g*mL^-1#</mathjax>. This corresponds to a <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of approx. <mathjax>#12#</mathjax> <mathjax>#mol*L^-1#</mathjax>. I imagine stronger concentrations than this would have to be made under <mathjax>#HCl(g)#</mathjax> atmospheres.</p> <p>At any rate, the procedure for diluting strong acids IS ALWAYS ACID TO WATER. Why? Because if you spit in acid, it spits back at you! </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Are you sure there is a 78% (w/w) hydrochloric acid?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The concentrated <mathjax>#HCl#</mathjax> solution supplied to laboratories is 38% (w/w), with <mathjax>#rho#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.189*g*mL^-1#</mathjax>. This corresponds to a <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of approx. <mathjax>#12#</mathjax> <mathjax>#mol*L^-1#</mathjax>. I imagine stronger concentrations than this would have to be made under <mathjax>#HCl(g)#</mathjax> atmospheres.</p> <p>At any rate, the procedure for diluting strong acids IS ALWAYS ACID TO WATER. Why? Because if you spit in acid, it spits back at you! </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the molar concentration of #"78% w/w"# #HCl(aq)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="255810" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-18T16:49:13" itemprop="dateCreated"> Apr 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Are you sure there is a 78% (w/w) hydrochloric acid?</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The concentrated <mathjax>#HCl#</mathjax> solution supplied to laboratories is 38% (w/w), with <mathjax>#rho#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.189*g*mL^-1#</mathjax>. This corresponds to a <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of approx. <mathjax>#12#</mathjax> <mathjax>#mol*L^-1#</mathjax>. I imagine stronger concentrations than this would have to be made under <mathjax>#HCl(g)#</mathjax> atmospheres.</p> <p>At any rate, the procedure for diluting strong acids IS ALWAYS ACID TO WATER. Why? Because if you spit in acid, it spits back at you! </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/255810" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-resonance-structures-affect-acidity"> How do resonance structures affect acidity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-carbon-dioxide-change-the-acid-base-condition-of-a-solution"> How does carbon dioxide change the acid-base condition of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-strong-acids-have-a-low-ph"> Why do strong acids have a low pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-neutralization-a-double-replacement-reaction"> Is neutralization a double replacement reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-nah-a-strong-base"> Why is NaH a strong base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-hbr-a-strong-acid"> Is HBr a strong acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-hf-a-strong-acid"> Is HF a strong acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-neutralization-occur"> Why does neutralization occur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-strong-acids-completely-dissociate-in-water"> Do strong acids completely dissociate in water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-ph-of-weak-acid"> How can I calculate pH of weak acid? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/acids-and-bases"> See all questions in Acids and Bases </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1407 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the molar concentration of #"78% w/w"# #HCl(aq)#?

ac06725f-6ddd-11ea-a964-ccda262736ce

https://socratic.org/questions/5804e43c11ef6b49d721eca6

-46.2 kJ/mol

start physical_unit 7 7 deltahf^0 kj/mol qc_end chemical_equation 1 10 qc_end end

[{"type":"physical unit","value":"DeltaHf^0 [OF] NH3(g) [IN] kJ/mol"}]

[{"type":"physical unit","value":"-46.2 kJ/mol"}]

[{"type":"chemical equation","value":"N2(g) + 3 H2(g) -> 2 NH3(g) + 92.4 kJ"}]

<h1 class="questionTitle" itemprop="name">Given... #N_2(g) + 3H_2(g) rarr 2NH_3(g) + 92.4*kJ#... ..what is #DeltaH_f^@# #NH_3(g)#? </h1>

-46.2 kJ/mol

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, <mathjax>#DeltaH_f^@#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change associated with the formation of 1 mole of product from its constituent <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in their standard states at <mathjax>#298*K#</mathjax>.</p> <p>I think you have quoted the enthalpy change for the reaction:</p> <p><mathjax>#N_2(g) + 3H_2(g) rarr 2NH_3(g)#</mathjax>, which of course is TWICE the enthalpy of formation for <mathjax>#NH_3#</mathjax>, because this reaction formed TWO moles of ammonia.</p> <p>Finally, we can write:</p> <p><mathjax>#1/2N_2(g) + 3/2H_2(g) rarr NH_3(g)#</mathjax> <mathjax>#;DeltaH_"rxn"^@=DeltaH_f^@"ammonia"=-46.2*kJ*mol^-1#</mathjax>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#DeltaH_f^@#</mathjax> <mathjax>#NH_3(g)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-46.2*kJ*mol^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, <mathjax>#DeltaH_f^@#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change associated with the formation of 1 mole of product from its constituent <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in their standard states at <mathjax>#298*K#</mathjax>.</p> <p>I think you have quoted the enthalpy change for the reaction:</p> <p><mathjax>#N_2(g) + 3H_2(g) rarr 2NH_3(g)#</mathjax>, which of course is TWICE the enthalpy of formation for <mathjax>#NH_3#</mathjax>, because this reaction formed TWO moles of ammonia.</p> <p>Finally, we can write:</p> <p><mathjax>#1/2N_2(g) + 3/2H_2(g) rarr NH_3(g)#</mathjax> <mathjax>#;DeltaH_"rxn"^@=DeltaH_f^@"ammonia"=-46.2*kJ*mol^-1#</mathjax>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Given... #N_2(g) + 3H_2(g) rarr 2NH_3(g) + 92.4*kJ#... ..what is #DeltaH_f^@# #NH_3(g)#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/enthalpy" itemprop="url"> <span class="breadcrumb" itemprop="title">Enthalpy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="322871" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-17T15:07:13" itemprop="dateCreated"> Oct 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#DeltaH_f^@#</mathjax> <mathjax>#NH_3(g)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-46.2*kJ*mol^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, <mathjax>#DeltaH_f^@#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change associated with the formation of 1 mole of product from its constituent <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> in their standard states at <mathjax>#298*K#</mathjax>.</p> <p>I think you have quoted the enthalpy change for the reaction:</p> <p><mathjax>#N_2(g) + 3H_2(g) rarr 2NH_3(g)#</mathjax>, which of course is TWICE the enthalpy of formation for <mathjax>#NH_3#</mathjax>, because this reaction formed TWO moles of ammonia.</p> <p>Finally, we can write:</p> <p><mathjax>#1/2N_2(g) + 3/2H_2(g) rarr NH_3(g)#</mathjax> <mathjax>#;DeltaH_"rxn"^@=DeltaH_f^@"ammonia"=-46.2*kJ*mol^-1#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/322871" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-enthalpy-changes-expressed-in-chemical-equations"> How are enthalpy changes expressed in chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-enthalpy-change-be-determined-for-an-aqueous-solution"> How can enthalpy change be determined for an aqueous solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-change-with-pressure"> How does enthalpy change with pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-standard-molar-enthalpy-formation"> How do you calculate standard molar enthalpy of formation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-enthalpy-of-formation-of-oxygen-zero"> Why is the enthalpy of formation of oxygen zero? 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Given... #N_2(g) + 3H_2(g) rarr 2NH_3(g) + 92.4*kJ#... ..what is #DeltaH_f^@# #NH_3(g)#?

ad1165b5-6ddd-11ea-9fbc-ccda262736ce

https://socratic.org/questions/how-many-ions-are-there-in-a-solution-with-9-656-mol-of-ni-2

5.81 × 10^24

start physical_unit 2 2 number none qc_end physical_unit 12 12 9 10 mole qc_end end

[{"type":"physical unit","value":"Number [OF] ions"}]

[{"type":"physical unit","value":"5.81 × 10^24"}]

[{"type":"physical unit","value":"Mole [OF] Ni^2+ [=] \\pu{9.656 mol}"}]

<h1 class="questionTitle" itemprop="name">How many ions are there in a solution with 9.656 mol of #Ni^(2+)#?</h1>

5.81 × 10^24

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>How do I know this? Because <mathjax>#Ni^(2+)#</mathjax> must have a counterion. This could have been halide, or nitrate, or acetate, or something else. </p> <p>The number of <mathjax>#Ni^(2+)#</mathjax> ions is <mathjax>#N_A#</mathjax> <mathjax>#xx#</mathjax> <mathjax>#9.656#</mathjax> <mathjax>#mol#</mathjax>. <mathjax>#N_A#</mathjax> is Avogadro's number <mathjax>#=#</mathjax> <mathjax>#6.022xx10^23*mol^-1#</mathjax>. So the number of ions is rather large. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Clearly there are <mathjax>#9.656#</mathjax> <mathjax>#mol#</mathjax> of <mathjax>#Ni^(2+)#</mathjax>. But <mathjax>#Ni^(2+)#</mathjax> is not the only ion present.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>How do I know this? Because <mathjax>#Ni^(2+)#</mathjax> must have a counterion. This could have been halide, or nitrate, or acetate, or something else. </p> <p>The number of <mathjax>#Ni^(2+)#</mathjax> ions is <mathjax>#N_A#</mathjax> <mathjax>#xx#</mathjax> <mathjax>#9.656#</mathjax> <mathjax>#mol#</mathjax>. <mathjax>#N_A#</mathjax> is Avogadro's number <mathjax>#=#</mathjax> <mathjax>#6.022xx10^23*mol^-1#</mathjax>. So the number of ions is rather large. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many ions are there in a solution with 9.656 mol of #Ni^(2+)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="236931" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-08T18:04:08" itemprop="dateCreated"> Mar 8, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Clearly there are <mathjax>#9.656#</mathjax> <mathjax>#mol#</mathjax> of <mathjax>#Ni^(2+)#</mathjax>. But <mathjax>#Ni^(2+)#</mathjax> is not the only ion present.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>How do I know this? Because <mathjax>#Ni^(2+)#</mathjax> must have a counterion. This could have been halide, or nitrate, or acetate, or something else. </p> <p>The number of <mathjax>#Ni^(2+)#</mathjax> ions is <mathjax>#N_A#</mathjax> <mathjax>#xx#</mathjax> <mathjax>#9.656#</mathjax> <mathjax>#mol#</mathjax>. <mathjax>#N_A#</mathjax> is Avogadro's number <mathjax>#=#</mathjax> <mathjax>#6.022xx10^23*mol^-1#</mathjax>. So the number of ions is rather large. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/236931" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2557 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many ions are there in a solution with 9.656 mol of #Ni^(2+)#?

a8de2b1d-6ddd-11ea-99e7-ccda262736ce

https://socratic.org/questions/if-a-sample-of-oxygen-gas-has-a-pressure-of-810-torr-at-298-k-what-will-be-its-p

897 torr

start physical_unit 2 5 pressure torr qc_end physical_unit 2 5 13 14 temperature qc_end physical_unit 2 5 10 11 pressure qc_end physical_unit 2 5 26 27 temperature qc_end end

[{"type":"physical unit","value":"Pressure2 [OF] the oxygen gas sample [IN] torr"}]

[{"type":"physical unit","value":"897 torr"}]

[{"type":"physical unit","value":"Temperature1 [OF] the oxygen gas sample [=] \\pu{298 K}"},{"type":"physical unit","value":"Pressure1 [OF] the oxygen gas sample [=] \\pu{810 torr}"},{"type":"physical unit","value":"Temperature2 [OF] the oxygen gas sample [=] \\pu{330 K}"}]

<h1 class="questionTitle" itemprop="name">If a sample of oxygen gas has a pressure of 810 torr at 298 K, what will be its pressure if its temperature is raised to 330 K?</h1>

897 torr

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use Gay Lussac's Law</p> <p><mathjax>#P_1/T_1=P_2/T_2#</mathjax></p> <p><mathjax>#P_1=810 #</mathjax>torr</p> <p><mathjax>#T_1=298K#</mathjax></p> <p><mathjax>#T_2=330K#</mathjax></p> <p><mathjax>#P_2=P_1/T_1*T_2=810/298*330=897#</mathjax> torr</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The pressure is <mathjax>#=897#</mathjax>torr</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use Gay Lussac's Law</p> <p><mathjax>#P_1/T_1=P_2/T_2#</mathjax></p> <p><mathjax>#P_1=810 #</mathjax>torr</p> <p><mathjax>#T_1=298K#</mathjax></p> <p><mathjax>#T_2=330K#</mathjax></p> <p><mathjax>#P_2=P_1/T_1*T_2=810/298*330=897#</mathjax> torr</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If a sample of oxygen gas has a pressure of 810 torr at 298 K, what will be its pressure if its temperature is raised to 330 K?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gay-lussac-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Gay Lussac's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="357074" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/narad-t"><img alt="" class="" src="https://profilepictures.socratic.org/zsDo4Wx9QIqYad4PXKE9_150317-1041.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/narad-t"> Narad T. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-27T07:01:56" itemprop="dateCreated"> Dec 27, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The pressure is <mathjax>#=897#</mathjax>torr</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use Gay Lussac's Law</p> <p><mathjax>#P_1/T_1=P_2/T_2#</mathjax></p> <p><mathjax>#P_1=810 #</mathjax>torr</p> <p><mathjax>#T_1=298K#</mathjax></p> <p><mathjax>#T_2=330K#</mathjax></p> <p><mathjax>#P_2=P_1/T_1*T_2=810/298*330=897#</mathjax> torr</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/357074" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535d701102bf342f53d9bcb0"> Question #9bcb0 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-gay-lussac-s-law-formula"> What is the Gay Lussac's law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-temperature-of-a-gas-in-a-container-is-doubled-on-the-kelvin-scale-the-pr"> If the temperature of a gas in a container is doubled on the Kelvin scale, what will happen to... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-original-pressure-of-a-gas-sample-at-20-c-was-5-00-atm-and-it-is-heated-u"> If the original pressure of a gas sample at 20 ˚C was 5.00 atm, and it is heated up to 40. ˚C ,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-gay-lussac-s-law-state"> What does Gay Lussac's law state? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-gay-lussac-s-law-relate"> What does Gay Lussac's law relate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-sample-of-o2-under-2-00-atm-occupies-500-ml-at-25-0-c-what-pressure-will-the-s"> A sample of O2 under 2.00 atm occupies 500 ml at 25.0˚C. 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If a sample of oxygen gas has a pressure of 810 torr at 298 K, what will be its pressure if its temperature is raised to 330 K?

aae651ca-6ddd-11ea-976c-ccda262736ce

https://socratic.org/questions/300-ml-is-added-to-5-ml-of-a-12-m-solution-of-ki-what-is-the-resulting-molarity-

0.20 M

start physical_unit 15 15 molarity mol/l qc_end physical_unit 3 3 0 1 volume qc_end physical_unit 13 13 7 8 volume qc_end physical_unit 15 15 11 12 molarity qc_end end

[{"type":"physical unit","value":"Molarity2 [OF] KI solution [IN] M"}]

[{"type":"physical unit","value":"0.20 M"}]

[{"type":"physical unit","value":"Volume [OF] water [=] \\pu{300 mL}"},{"type":"physical unit","value":"Volume1 [OF] KI solution [=] \\pu{5 mL}"},{"type":"physical unit","value":"Molarity1 [OF] KI solution [=] \\pu{12 M}"}]

<h1 class="questionTitle" itemprop="name"> 300 mL of water is added to 5 mL of a 12 M solution of #"KI"#. What is the resulting molarity of the solution?</h1>

0.20 M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The trick here is to realize that in a <strong>dilution</strong>, the ratio that exists between the concentration of the <em>stock solution</em> and the concentration of the <em>diluted solution</em> is <strong>equal</strong> to the ratio that exists between the volume of the diluted solution and the volume of the stock solution. </p> <p>These two ratios give you the <strong><a href="https://socratic.org/questions/how-do-you-calculate-dilution-factor">dilution factor</a></strong></p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("DF" = c_"stock"/c_"diluted" = V_"diluted"/V_"stock")))#</mathjax></p> </blockquote> <p>In your case, you know that the volume of the stock solution is equal to <mathjax>#"5 mL"#</mathjax>. Adding <mathjax>#"300 mL"#</mathjax> of water to the stock solution will dilute it to a final volume of </p> <blockquote> <p><mathjax>#"5 mL " + " 300 mL" = "305 mL"#</mathjax></p> </blockquote> <p>This means that the dilution factor will be equal to </p> <blockquote> <p><mathjax>#"DF" = (305 color(red)(cancel(color(black)("mL"))))/(5color(red)(cancel(color(black)("mL")))) = color(blue)(61)#</mathjax></p> </blockquote> <p>Therefore, you can say that the concentration of the diluted solution will be </p> <blockquote> <p><mathjax>#"DF" = c_"stock"/c_"diluted" implies c_"diluted" = c_"stock"/"DF"#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#c_"diluted" = "12 M"/color(blue)(61) = color(darkgreen)(ul(color(black)("0.2 M")))#</mathjax></p> </blockquote> <p>The answer must be rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.2 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The trick here is to realize that in a <strong>dilution</strong>, the ratio that exists between the concentration of the <em>stock solution</em> and the concentration of the <em>diluted solution</em> is <strong>equal</strong> to the ratio that exists between the volume of the diluted solution and the volume of the stock solution. </p> <p>These two ratios give you the <strong><a href="https://socratic.org/questions/how-do-you-calculate-dilution-factor">dilution factor</a></strong></p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("DF" = c_"stock"/c_"diluted" = V_"diluted"/V_"stock")))#</mathjax></p> </blockquote> <p>In your case, you know that the volume of the stock solution is equal to <mathjax>#"5 mL"#</mathjax>. Adding <mathjax>#"300 mL"#</mathjax> of water to the stock solution will dilute it to a final volume of </p> <blockquote> <p><mathjax>#"5 mL " + " 300 mL" = "305 mL"#</mathjax></p> </blockquote> <p>This means that the dilution factor will be equal to </p> <blockquote> <p><mathjax>#"DF" = (305 color(red)(cancel(color(black)("mL"))))/(5color(red)(cancel(color(black)("mL")))) = color(blue)(61)#</mathjax></p> </blockquote> <p>Therefore, you can say that the concentration of the diluted solution will be </p> <blockquote> <p><mathjax>#"DF" = c_"stock"/c_"diluted" implies c_"diluted" = c_"stock"/"DF"#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#c_"diluted" = "12 M"/color(blue)(61) = color(darkgreen)(ul(color(black)("0.2 M")))#</mathjax></p> </blockquote> <p>The answer must be rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name"> 300 mL of water is added to 5 mL of a 12 M solution of #"KI"#. What is the resulting molarity of the solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/dilution-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Dilution Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="380794" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-21T00:14:17" itemprop="dateCreated"> Feb 21, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.2 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The trick here is to realize that in a <strong>dilution</strong>, the ratio that exists between the concentration of the <em>stock solution</em> and the concentration of the <em>diluted solution</em> is <strong>equal</strong> to the ratio that exists between the volume of the diluted solution and the volume of the stock solution. </p> <p>These two ratios give you the <strong><a href="https://socratic.org/questions/how-do-you-calculate-dilution-factor">dilution factor</a></strong></p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("DF" = c_"stock"/c_"diluted" = V_"diluted"/V_"stock")))#</mathjax></p> </blockquote> <p>In your case, you know that the volume of the stock solution is equal to <mathjax>#"5 mL"#</mathjax>. Adding <mathjax>#"300 mL"#</mathjax> of water to the stock solution will dilute it to a final volume of </p> <blockquote> <p><mathjax>#"5 mL " + " 300 mL" = "305 mL"#</mathjax></p> </blockquote> <p>This means that the dilution factor will be equal to </p> <blockquote> <p><mathjax>#"DF" = (305 color(red)(cancel(color(black)("mL"))))/(5color(red)(cancel(color(black)("mL")))) = color(blue)(61)#</mathjax></p> </blockquote> <p>Therefore, you can say that the concentration of the diluted solution will be </p> <blockquote> <p><mathjax>#"DF" = c_"stock"/c_"diluted" implies c_"diluted" = c_"stock"/"DF"#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#c_"diluted" = "12 M"/color(blue)(61) = color(darkgreen)(ul(color(black)("0.2 M")))#</mathjax></p> </blockquote> <p>The answer must be rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/380794" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-absorbance"> How do you calculate concentration from absorbance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-titration"> How do you calculate concentration from titration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-dilution-factor"> How do you calculate dilution factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-serial-dilution-calculations"> How do you calculate serial dilutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-calculate-concentration-of-solution-when-its-diluted"> How to calculate concentration of solution when it's diluted? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-dilution-calculations"> What are some examples of dilution calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-concentration-of-a-solution-made-by-adding-250-ml-of-water-to-"> What would be the concentration of a solution made by adding 250 mL of water to 45.0 mL of 4.2 M KOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-concentration-of-a-solution-made-by-diluting-45-0-ml-of-4-2-m-"> What would be the concentration of a solution made by diluting 45.0 mL of 4.2 M KOH to 250 mL? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-a-solution-that-is-made-by-diluting-50-00-ml-of-a-4-74-m"> What is the molarity of a solution that is made by diluting 50.00 mL of a 4.74 M solution of HCl... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-of-water-would-you-add-to-15-00-ml-of-a-6-77-m-solution-of-nitric-ac"> What volume of water would you add to 15.00 mL of a 6.77 M solution of nitric acid in order to... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/dilution-calculations"> See all questions in Dilution Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4600 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

300 mL of water is added to 5 mL of a 12 M solution of #"KI"#. What is the resulting molarity of the solution?

ab22cb22-6ddd-11ea-bc8f-ccda262736ce

https://socratic.org/questions/nicotine-a-component-of-tobacco-is-composed-of-c-h-and-n-a-3-150-mg-sample-of-ni

C5H7N

start chemical_formula qc_end c_other OTHER qc_end physical_unit 15 17 13 14 mass qc_end physical_unit 24 24 21 22 mass qc_end physical_unit 29 29 26 27 mass qc_end end

[{"type":"other","value":"Chemical Formula [OF] nicotine [IN] empirical"}]

[{"type":"chemical equation","value":"C5H7N"}]

[{"type":"other","value":"Nicotine is composed of C, H, and N."},{"type":"physical unit","value":"Mass [OF] nicotine sample [=] \\pu{3.150 mg}"},{"type":"physical unit","value":"Mass [OF] CO [=] \\pu{8.545 mg}"},{"type":"physical unit","value":"Mass [OF] H2O [=] \\pu{2.450 mg}"}]

<h1 class="questionTitle" itemprop="name">Nicotine, a component of tobacco, is composed of C, H, and N. A 3.150-mg sample of nicotine was combusted, producing 8.545 mg of co and 2.450 mg of H20. what is the empirical formula for nicotine?</h1>

C5H7N

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so we got <mathjax>#C_xH_yN_n#</mathjax></p> <p>We combust a <mathjax>#3.159*mg#</mathjax> mass of the stuff to get....</p> <p><mathjax>#(8.545*mg)/(44.01*g*mol^-1)=1.94xx10^-4*mol#</mathjax> <mathjax>#CO_2#</mathjax>...i.e. a mass with respect to carbon of <mathjax>#2.33*mg#</mathjax>....(<mathjax>#CO#</mathjax> would not result from the combustion.)</p> <p><mathjax>#(2.450*mg)/(18.01*g*mol^-1)=1.36xx10^-4*mol#</mathjax> <mathjax>#H_2O#</mathjax>...i.e. a mass with respect to hydrogen of <mathjax>#0.274*mg#</mathjax>, <mathjax>#0.272*mg#</mathjax>..</p> <p>The balance of the mass was due to NITROGEN....<mathjax>#{3.159-2.33-0.272}*mg=0.557*mg-=3.98xx10^-5*mol#</mathjax></p> <p>We divide the molar quantities thru by the LEAST molar quantity to get an empirical formula of....</p> <p><mathjax>#C_((1.94xx10^-4*mol)/(3.98xx10^-5*mol))H_((2.74xx10^-4*mol)/(3.98xx10^-5*mol))N_((3.98xx10^-5*mol)/(3.98xx10^-5*mol))-=C_(4.87)H_(6.88)N~=C_5H_7N#</mathjax></p> <p><mathjax>#"Whew, arithmetic.....!!"#</mathjax> I take it this is first year....?</p> <p>Ordinarily combustion analysis gives you <mathjax>#%N#</mathjax>...here we had to interpolate the nitrogen mass by subtracting the calculated masses of carbon, and hydrogen, from the starting mass....</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I make it <mathjax>#C_5H_7N#</mathjax>...</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so we got <mathjax>#C_xH_yN_n#</mathjax></p> <p>We combust a <mathjax>#3.159*mg#</mathjax> mass of the stuff to get....</p> <p><mathjax>#(8.545*mg)/(44.01*g*mol^-1)=1.94xx10^-4*mol#</mathjax> <mathjax>#CO_2#</mathjax>...i.e. a mass with respect to carbon of <mathjax>#2.33*mg#</mathjax>....(<mathjax>#CO#</mathjax> would not result from the combustion.)</p> <p><mathjax>#(2.450*mg)/(18.01*g*mol^-1)=1.36xx10^-4*mol#</mathjax> <mathjax>#H_2O#</mathjax>...i.e. a mass with respect to hydrogen of <mathjax>#0.274*mg#</mathjax>, <mathjax>#0.272*mg#</mathjax>..</p> <p>The balance of the mass was due to NITROGEN....<mathjax>#{3.159-2.33-0.272}*mg=0.557*mg-=3.98xx10^-5*mol#</mathjax></p> <p>We divide the molar quantities thru by the LEAST molar quantity to get an empirical formula of....</p> <p><mathjax>#C_((1.94xx10^-4*mol)/(3.98xx10^-5*mol))H_((2.74xx10^-4*mol)/(3.98xx10^-5*mol))N_((3.98xx10^-5*mol)/(3.98xx10^-5*mol))-=C_(4.87)H_(6.88)N~=C_5H_7N#</mathjax></p> <p><mathjax>#"Whew, arithmetic.....!!"#</mathjax> I take it this is first year....?</p> <p>Ordinarily combustion analysis gives you <mathjax>#%N#</mathjax>...here we had to interpolate the nitrogen mass by subtracting the calculated masses of carbon, and hydrogen, from the starting mass....</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Nicotine, a component of tobacco, is composed of C, H, and N. A 3.150-mg sample of nicotine was combusted, producing 8.545 mg of co and 2.450 mg of H20. what is the empirical formula for nicotine?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="622926" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-31T04:56:33" itemprop="dateCreated"> May 31, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I make it <mathjax>#C_5H_7N#</mathjax>...</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And so we got <mathjax>#C_xH_yN_n#</mathjax></p> <p>We combust a <mathjax>#3.159*mg#</mathjax> mass of the stuff to get....</p> <p><mathjax>#(8.545*mg)/(44.01*g*mol^-1)=1.94xx10^-4*mol#</mathjax> <mathjax>#CO_2#</mathjax>...i.e. a mass with respect to carbon of <mathjax>#2.33*mg#</mathjax>....(<mathjax>#CO#</mathjax> would not result from the combustion.)</p> <p><mathjax>#(2.450*mg)/(18.01*g*mol^-1)=1.36xx10^-4*mol#</mathjax> <mathjax>#H_2O#</mathjax>...i.e. a mass with respect to hydrogen of <mathjax>#0.274*mg#</mathjax>, <mathjax>#0.272*mg#</mathjax>..</p> <p>The balance of the mass was due to NITROGEN....<mathjax>#{3.159-2.33-0.272}*mg=0.557*mg-=3.98xx10^-5*mol#</mathjax></p> <p>We divide the molar quantities thru by the LEAST molar quantity to get an empirical formula of....</p> <p><mathjax>#C_((1.94xx10^-4*mol)/(3.98xx10^-5*mol))H_((2.74xx10^-4*mol)/(3.98xx10^-5*mol))N_((3.98xx10^-5*mol)/(3.98xx10^-5*mol))-=C_(4.87)H_(6.88)N~=C_5H_7N#</mathjax></p> <p><mathjax>#"Whew, arithmetic.....!!"#</mathjax> I take it this is first year....?</p> <p>Ordinarily combustion analysis gives you <mathjax>#%N#</mathjax>...here we had to interpolate the nitrogen mass by subtracting the calculated masses of carbon, and hydrogen, from the starting mass....</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/622926" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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Nicotine, a component of tobacco, is composed of C, H, and N. A 3.150-mg sample of nicotine was combusted, producing 8.545 mg of co and 2.450 mg of H20. what is the empirical formula for nicotine?

abf33a46-6ddd-11ea-ba63-ccda262736ce

https://socratic.org/questions/the-specific-heat-of-iron-is-0-46-j-gc-how-many-joules-will-it-take-to-make-the-

2415.00 joules

start physical_unit 4 4 heat_energy j qc_end physical_unit 4 4 6 9 specific_heat qc_end physical_unit 24 24 22 23 mass qc_end physical_unit 24 24 28 29 temperature qc_end physical_unit 24 24 31 32 temperature qc_end end

[{"type":"physical unit","value":"Taken energy [OF] iron [IN] joules"}]

[{"type":"physical unit","value":"2415.00 joules"}]

[{"type":"physical unit","value":"Specific heat [OF] iron [=] \\pu{0.46 J/(g * ℃)}"},{"type":"physical unit","value":"Mass [OF] bar [=] \\pu{150 g}"},{"type":"physical unit","value":"Temperature1 [OF] bar [=] \\pu{25 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] bar [=] \\pu{60 ℃}"}]

<h1 class="questionTitle" itemprop="name">The specific heat of iron is 0.46 J/gC. How many joules will it take to make the temperature of a 150 g bar go up from 25 C to 60 C?</h1>

2415.00 joules

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We know, Heat Absorbed or Evolved by a substance = mass * <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity * change in temperature.</p> <p>Here, </p> <blockquote> <p>Mass <mathjax>#(m) = 150g#</mathjax><br/> Specific heat capacity <mathjax>#(c) = (0.46J)/(gK)#</mathjax><br/> Initial Temperature = <mathjax>#25^@C#</mathjax><br/> Final Temperature = <mathjax>#60^@C#</mathjax><br/> <mathjax>#DeltaT=60-25=35^@C=35K#</mathjax></p> </blockquote> <p>Therefore, total heat supplied = <mathjax>#DeltaE#</mathjax> = <mathjax>#mcDeltaT#</mathjax> <br/> <mathjax>#= 150 * 0.46 * 35#</mathjax> J<br/> <mathjax>#= 2415#</mathjax> J</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>2415 J</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We know, Heat Absorbed or Evolved by a substance = mass * <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity * change in temperature.</p> <p>Here, </p> <blockquote> <p>Mass <mathjax>#(m) = 150g#</mathjax><br/> Specific heat capacity <mathjax>#(c) = (0.46J)/(gK)#</mathjax><br/> Initial Temperature = <mathjax>#25^@C#</mathjax><br/> Final Temperature = <mathjax>#60^@C#</mathjax><br/> <mathjax>#DeltaT=60-25=35^@C=35K#</mathjax></p> </blockquote> <p>Therefore, total heat supplied = <mathjax>#DeltaE#</mathjax> = <mathjax>#mcDeltaT#</mathjax> <br/> <mathjax>#= 150 * 0.46 * 35#</mathjax> J<br/> <mathjax>#= 2415#</mathjax> J</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">The specific heat of iron is 0.46 J/gC. How many joules will it take to make the temperature of a 150 g bar go up from 25 C to 60 C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="434817" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/soumalya-p"><img alt="" class="" src="https://profilepictures.socratic.org/y3rdUVmLSqqZYNQNXYxx_IMG_20180224_134054.jpg" title=""/></a> <a class="secondContributorPic" href="/users/justin-15"><img alt="" class="" src="https://profilepictures.socratic.org/dLvvyawSQcelaE5CHpqo_Adventuretimejake.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/soumalya-p"> Soumalya Pramanik </a>·<a class="topContributorLink" href="/users/justin-15"> Justin </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-05T06:19:38" itemprop="dateCreated"> Jun 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>2415 J</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We know, Heat Absorbed or Evolved by a substance = mass * <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity * change in temperature.</p> <p>Here, </p> <blockquote> <p>Mass <mathjax>#(m) = 150g#</mathjax><br/> Specific heat capacity <mathjax>#(c) = (0.46J)/(gK)#</mathjax><br/> Initial Temperature = <mathjax>#25^@C#</mathjax><br/> Final Temperature = <mathjax>#60^@C#</mathjax><br/> <mathjax>#DeltaT=60-25=35^@C=35K#</mathjax></p> </blockquote> <p>Therefore, total heat supplied = <mathjax>#DeltaE#</mathjax> = <mathjax>#mcDeltaT#</mathjax> <br/> <mathjax>#= 150 * 0.46 * 35#</mathjax> J<br/> <mathjax>#= 2415#</mathjax> J</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/434817" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? 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The specific heat of iron is 0.46 J/gC. How many joules will it take to make the temperature of a 150 g bar go up from 25 C to 60 C?

ab01a1f0-6ddd-11ea-8529-ccda262736ce

https://socratic.org/questions/how-many-water-molecules-are-present-in-54-gram-of-water

1.81 × 10^24

start physical_unit 2 3 number none qc_end physical_unit 2 2 7 8 mass qc_end end

[{"type":"physical unit","value":"Number [OF] water molecules"}]

[{"type":"physical unit","value":"1.81 × 10^24"}]

[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{54 grams}"}]

<h1 class="questionTitle" itemprop="name">How many water molecules are present in 54 gram of water? </h1>

1.81 × 10^24

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We assess the molar quantity of water in the usual way...</p> <p><mathjax>#"Number of moles"="mass"/"molar mass"#</mathjax></p> <p><mathjax>#-=(54*g)/(18.01*g*mol^-1)=3.00*mol#</mathjax></p> <p>But the <mathjax>#mol#</mathjax> is like the <mathjax>#"dozen"#</mathjax>, or the <mathjax>#"gross"#</mathjax>, it specifies a NUMBER, here <mathjax>#N_A-=6.022xx10^23*mol#</mathjax>. Why do we use such an absurdly large number? Because <mathjax>#N_A*""^1H*"atoms"#</mathjax> have a MASS of <mathjax>#1*g#</mathjax> precisely...and thus <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> is the link between the micro world of atoms, and molecules, to the macro world of grams and litres....</p> <p>And so (finally!) we take the product...</p> <p><mathjax>#"Number of water molecules"="molar quantity"xx"Avogadro's number."#</mathjax></p> <p><mathjax>#=underbrace(3.00*cancel(mol)xx6.022xx10^23*cancel(mol^-1))_"a number as required.."=??*"water molecules"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We get <mathjax>#1.81xx10^24#</mathjax> water molecules...</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We assess the molar quantity of water in the usual way...</p> <p><mathjax>#"Number of moles"="mass"/"molar mass"#</mathjax></p> <p><mathjax>#-=(54*g)/(18.01*g*mol^-1)=3.00*mol#</mathjax></p> <p>But the <mathjax>#mol#</mathjax> is like the <mathjax>#"dozen"#</mathjax>, or the <mathjax>#"gross"#</mathjax>, it specifies a NUMBER, here <mathjax>#N_A-=6.022xx10^23*mol#</mathjax>. Why do we use such an absurdly large number? Because <mathjax>#N_A*""^1H*"atoms"#</mathjax> have a MASS of <mathjax>#1*g#</mathjax> precisely...and thus <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> is the link between the micro world of atoms, and molecules, to the macro world of grams and litres....</p> <p>And so (finally!) we take the product...</p> <p><mathjax>#"Number of water molecules"="molar quantity"xx"Avogadro's number."#</mathjax></p> <p><mathjax>#=underbrace(3.00*cancel(mol)xx6.022xx10^23*cancel(mol^-1))_"a number as required.."=??*"water molecules"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many water molecules are present in 54 gram of water? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="635033" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-25T04:37:29" itemprop="dateCreated"> Jun 25, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We get <mathjax>#1.81xx10^24#</mathjax> water molecules...</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We assess the molar quantity of water in the usual way...</p> <p><mathjax>#"Number of moles"="mass"/"molar mass"#</mathjax></p> <p><mathjax>#-=(54*g)/(18.01*g*mol^-1)=3.00*mol#</mathjax></p> <p>But the <mathjax>#mol#</mathjax> is like the <mathjax>#"dozen"#</mathjax>, or the <mathjax>#"gross"#</mathjax>, it specifies a NUMBER, here <mathjax>#N_A-=6.022xx10^23*mol#</mathjax>. Why do we use such an absurdly large number? Because <mathjax>#N_A*""^1H*"atoms"#</mathjax> have a MASS of <mathjax>#1*g#</mathjax> precisely...and thus <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> is the link between the micro world of atoms, and molecules, to the macro world of grams and litres....</p> <p>And so (finally!) we take the product...</p> <p><mathjax>#"Number of water molecules"="molar quantity"xx"Avogadro's number."#</mathjax></p> <p><mathjax>#=underbrace(3.00*cancel(mol)xx6.022xx10^23*cancel(mol^-1))_"a number as required.."=??*"water molecules"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/635033" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="635039" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nile-river"><img alt="" class="" src="https://profilepictures.socratic.org/Wh7a1sWCQTW2QS9ybW5h_islamic%20design.png" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nile-river"> Nile River </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-25T04:52:54" itemprop="dateCreated"> Jun 25, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.8 xx 10^24#</mathjax> water molecules.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>There are <mathjax>#6.022 xx 10^23#</mathjax> molecules in a mole.</p> <p>There are <mathjax>#18.01528#</mathjax> grams of water per mole of water.</p> <p>These can be figured out using the concept of moles and molecular weight. I have attached a video that provides a good explanation.</p> <p><a href="https://www.youtube.com/watch?v=JC76NR8EtTQ" rel="nofollow">Explanation of moles and molecular weight</a></p> <p>Now you have all the information needed to solve the problem. </p> <p>You start out with 54 grams of water. You want to convert that into molecules, but how can you do that? You can't go directly from grams to molecules because there is no easy unit conversion. However, you can go from grams to moles using </p> <p><mathjax>#18.01528#</mathjax> grams of water per mole of water.</p> <p>From there, you can go from moles to molecules using <mathjax>#6.022 xx 10^23#</mathjax> molecules in a mole.</p> <p>A T chart is useful for this kind of problem.</p> <p><mathjax>#"54 g H"_2"O" xx ("1 mol H"_2"O")/("18.0152 g H"_2"O") xx(6.022 xx 10^23 \ "molecules")/("1 mol H"_2"O")#</mathjax></p> <p><mathjax>#"54" cancel("g H"_2"O") xx (cancel("1 mol H"_2"O"))/(18.0152cancel ("g H"_2"O")) xx (6.022 xx 10^23 \ "molecules")/(cancel("1 mol H"_2"O"))#</mathjax></p> <p>Notice when you apply this T chart, the units cancel out, leaving molecules in the final answer, which is the correct units.</p> <p>Now actually multiply everything out</p> <p><mathjax>#(54 xx 6.022xx10^23)/18.0152= 1.805 xx 10^24#</mathjax></p> <p>You are left with <mathjax>#1.8 xx 10^24#</mathjax> water molecules (rounded to two sig figs).</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/635039" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 70579 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many water molecules are present in 54 gram of water?

a8b3812e-6ddd-11ea-a321-ccda262736ce

https://socratic.org/questions/at-a-pressure-47-kpa-the-gas-in-a-cylinder-has-a-volume-of-12-liters-assuming-te

70.50 kPa

start physical_unit 5 6 pressure kpa qc_end physical_unit 5 6 14 15 volume qc_end physical_unit 5 6 30 31 volume qc_end physical_unit 5 6 3 4 pressure qc_end c_other constant_temperature qc_end end

[{"type":"physical unit","value":"Pressure2 [OF] the gas [IN] kPa"}]

[{"type":"physical unit","value":"70.50 kPa"}]

[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{12 liters}"},{"type":"physical unit","value":"Volume2 [OF] the gas [=] \\pu{8 liters}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{47 kPa}"},{"type":"other","value":"ConstantTemperature"}]

<h1 class="questionTitle" itemprop="name">At a pressure 47 kPa, the gas in a cylinder has a volume of 12 liters. Assuming temperature remains the same, if the volume of the gas is decreased to 8 liters, what is the new pressure? </h1>

70.50 kPa

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Boyles Law is the only inverse relationship between gas phase variable of the Empirical Gas Law set. That is ... </p> <p>For the Empirical <a href="https://socratic.org/chemistry/the-behavior-of-gases/gas-laws">Gas Laws</a> the primary variables considered are Pressure (P), Volume (V). Temperature (T) and Mass (n). The macrolevel relationships are defined in terms of 4 'named expressions. Such are ...<br/> Boyles Law =&gt; <mathjax>#P prop 1/V#</mathjax> (mass &amp; Temp are constant) <br/> =&gt; Decreasing V =&gt; Increases P (Inverse relationship)</p> <p>Charles Law =&gt; <mathjax>#V prop T#</mathjax> (pressure &amp; mass are constant) <br/> =&gt; Increasing T =&gt; Increasing V (Direct Relationship)</p> <p>Gay-Lussac Law =&gt; <mathjax>#P prop T#</mathjax> (mass and Volume are constant)<br/> =&gt; Increasing T =&gt; Increasing P (Direct Relationship)</p> <p><a href="https://socratic.org/chemistry/the-behavior-of-gases/avogadro-s-law">Avogadro's Law</a> =&gt; <mathjax>#V prop n#</mathjax> (pressure and Temperature are constant) (Direct Relationship)</p> <p>Boyles Law therefore applies to the posted problem and for two conditions given, the following expression is applied ... </p> <p><mathjax>#P_1V_1 = P_2V_2#</mathjax> <br/> Substituting given data ...<br/> <mathjax>#P_1 = 47 kPa#</mathjax> <br/> <mathjax>#V_1 = 12 Liters#</mathjax><br/> <mathjax>#P_2 = ? "(unknown)"#</mathjax><br/> <mathjax>#V_2 = 8 Liters#</mathjax></p> <p>Substituting and solving for <mathjax>#P_2#</mathjax> ...</p> <p>=&gt; <mathjax>#(47kPa)(12Liters) = (P_2)(8Liters)#</mathjax></p> <p>=&gt; <mathjax>#P_2 = (47kPa)(12cancel(L))/(8cancel(L))#</mathjax> = <mathjax>#70.5 kPa #</mathjax> <br/> (Note: The decreased Volume (12L =&gt; 8L) resulted in an increase in pressure (47kPa =&gt; 70.5kPa); consistent with Boyles Law relationship.)</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Boyles Law problem. Empirical relationship <mathjax>#P prop (1/V)#</mathjax> =&gt; For conditions 1 &amp; 2 =&gt; <mathjax>#P_1V_1 = P_2V_2#</mathjax>. Substitute given pressure &amp; volume values and solve for the unknown. =&gt; 70.5 kPa.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Boyles Law is the only inverse relationship between gas phase variable of the Empirical Gas Law set. That is ... </p> <p>For the Empirical <a href="https://socratic.org/chemistry/the-behavior-of-gases/gas-laws">Gas Laws</a> the primary variables considered are Pressure (P), Volume (V). Temperature (T) and Mass (n). The macrolevel relationships are defined in terms of 4 'named expressions. Such are ...<br/> Boyles Law =&gt; <mathjax>#P prop 1/V#</mathjax> (mass &amp; Temp are constant) <br/> =&gt; Decreasing V =&gt; Increases P (Inverse relationship)</p> <p>Charles Law =&gt; <mathjax>#V prop T#</mathjax> (pressure &amp; mass are constant) <br/> =&gt; Increasing T =&gt; Increasing V (Direct Relationship)</p> <p>Gay-Lussac Law =&gt; <mathjax>#P prop T#</mathjax> (mass and Volume are constant)<br/> =&gt; Increasing T =&gt; Increasing P (Direct Relationship)</p> <p><a href="https://socratic.org/chemistry/the-behavior-of-gases/avogadro-s-law">Avogadro's Law</a> =&gt; <mathjax>#V prop n#</mathjax> (pressure and Temperature are constant) (Direct Relationship)</p> <p>Boyles Law therefore applies to the posted problem and for two conditions given, the following expression is applied ... </p> <p><mathjax>#P_1V_1 = P_2V_2#</mathjax> <br/> Substituting given data ...<br/> <mathjax>#P_1 = 47 kPa#</mathjax> <br/> <mathjax>#V_1 = 12 Liters#</mathjax><br/> <mathjax>#P_2 = ? "(unknown)"#</mathjax><br/> <mathjax>#V_2 = 8 Liters#</mathjax></p> <p>Substituting and solving for <mathjax>#P_2#</mathjax> ...</p> <p>=&gt; <mathjax>#(47kPa)(12Liters) = (P_2)(8Liters)#</mathjax></p> <p>=&gt; <mathjax>#P_2 = (47kPa)(12cancel(L))/(8cancel(L))#</mathjax> = <mathjax>#70.5 kPa #</mathjax> <br/> (Note: The decreased Volume (12L =&gt; 8L) resulted in an increase in pressure (47kPa =&gt; 70.5kPa); consistent with Boyles Law relationship.)</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">At a pressure 47 kPa, the gas in a cylinder has a volume of 12 liters. Assuming temperature remains the same, if the volume of the gas is decreased to 8 liters, what is the new pressure? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/boyle-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Boyle's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="468304" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/doc048"><img alt="" class="" src="https://profilepictures.socratic.org/e4gaeUMMQESTpfte6aRu_Friendly%20Chem%20Professor.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/doc048"> Doc048 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-26T12:17:50" itemprop="dateCreated"> Aug 26, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Boyles Law problem. Empirical relationship <mathjax>#P prop (1/V)#</mathjax> =&gt; For conditions 1 &amp; 2 =&gt; <mathjax>#P_1V_1 = P_2V_2#</mathjax>. Substitute given pressure &amp; volume values and solve for the unknown. =&gt; 70.5 kPa.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Boyles Law is the only inverse relationship between gas phase variable of the Empirical Gas Law set. That is ... </p> <p>For the Empirical <a href="https://socratic.org/chemistry/the-behavior-of-gases/gas-laws">Gas Laws</a> the primary variables considered are Pressure (P), Volume (V). Temperature (T) and Mass (n). The macrolevel relationships are defined in terms of 4 'named expressions. Such are ...<br/> Boyles Law =&gt; <mathjax>#P prop 1/V#</mathjax> (mass &amp; Temp are constant) <br/> =&gt; Decreasing V =&gt; Increases P (Inverse relationship)</p> <p>Charles Law =&gt; <mathjax>#V prop T#</mathjax> (pressure &amp; mass are constant) <br/> =&gt; Increasing T =&gt; Increasing V (Direct Relationship)</p> <p>Gay-Lussac Law =&gt; <mathjax>#P prop T#</mathjax> (mass and Volume are constant)<br/> =&gt; Increasing T =&gt; Increasing P (Direct Relationship)</p> <p><a href="https://socratic.org/chemistry/the-behavior-of-gases/avogadro-s-law">Avogadro's Law</a> =&gt; <mathjax>#V prop n#</mathjax> (pressure and Temperature are constant) (Direct Relationship)</p> <p>Boyles Law therefore applies to the posted problem and for two conditions given, the following expression is applied ... </p> <p><mathjax>#P_1V_1 = P_2V_2#</mathjax> <br/> Substituting given data ...<br/> <mathjax>#P_1 = 47 kPa#</mathjax> <br/> <mathjax>#V_1 = 12 Liters#</mathjax><br/> <mathjax>#P_2 = ? "(unknown)"#</mathjax><br/> <mathjax>#V_2 = 8 Liters#</mathjax></p> <p>Substituting and solving for <mathjax>#P_2#</mathjax> ...</p> <p>=&gt; <mathjax>#(47kPa)(12Liters) = (P_2)(8Liters)#</mathjax></p> <p>=&gt; <mathjax>#P_2 = (47kPa)(12cancel(L))/(8cancel(L))#</mathjax> = <mathjax>#70.5 kPa #</mathjax> <br/> (Note: The decreased Volume (12L =&gt; 8L) resulted in an increase in pressure (47kPa =&gt; 70.5kPa); consistent with Boyles Law relationship.)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/468304" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-graph-boyles-law"> How do you graph Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-functional-groups-are-found-in-lipids"> What functional groups are found in lipids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-k-constant-in-boyle-s-law"> Why is k constant in Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-graph-curved-1"> Why is Boyle's law graph curved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-an-inverse-relationship-2"> Why is Boyle's law an inverse relationship? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-40-0-l-tank-of-ammonia-has-a-pressure-of-8-00-atm-calculate-the-volume-of-the-"> A 40.0 L tank of ammonia has a pressure of 8.00 atm. 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At a pressure 47 kPa, the gas in a cylinder has a volume of 12 liters. Assuming temperature remains the same, if the volume of the gas is decreased to 8 liters, what is the new pressure?

aa105a64-6ddd-11ea-9c9f-ccda262736ce

https://socratic.org/questions/in-the-reaction-2kclo-3-s-2kcl-s-3o-2-g-how-many-liters-of-oxygen-would-be-produ

64.18 liters

start physical_unit 15 15 volume l qc_end physical_unit 23 24 20 21 mass qc_end chemical_equation 3 10 qc_end end

[{"type":"physical unit","value":"Volume [OF] oxygen [IN] liters"}]

[{"type":"physical unit","value":"64.18 liters"}]

[{"type":"physical unit","value":"Mass [OF] potassium chlorate [=] \\pu{231 g}"},{"type":"chemical equation","value":"2 KClO3(s) -> 2 KCl(s) + 3 O2(g)"}]

<h1 class="questionTitle" itemprop="name">In the reaction #2KClO_3(s) -&gt; 2KCl(s) + 3O_2(g)#, how many liters of oxygen would be produced from 231 g of potassium chlorate?</h1>

64.18 liters

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to be able to calculate the volume of oxygen gas produced by this reaction, you need to know the conditions for <em>pressure</em> and <em>temperature</em>. </p> <p>Since no mention of those conditions was made, I'll assume that the reaction takes place at <strong>STP</strong>, Standard Temperature and Pressure. </p> <p><strong>STP conditions</strong> are defined as a pressure of <mathjax>#"100 kPa"#</mathjax> and a temperature of <mathjax>#0^@"C"#</mathjax>. Under these conditions for pressure and temperature, <strong>one mole</strong> of any ideal gas occupies <mathjax>#"22.7 L"#</mathjax> - this is known as <a href="https://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">the molar volume of a gas at STP</a>.</p> <p>So, in order to find the volume of oxygen gas at STP, you need to know how many <em>moles</em> of oxygen are produced by this reaction. </p> <p>The balanced chemical equation for this <a href="https://socratic.org/chemistry/chemical-reactions/decomposition-reactions">decomposition reaction</a> looks like this</p> <blockquote> <p><mathjax>#color(blue)(2)"KClO"_text(3(s]) stackrel(color(purple)("heat")color(white)(xx))(-&gt;) 2"KCl"_text((s]) + color(red)(3)"O"_text(2(g]) uarr#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#color(blue)(2):color(red)(3)#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between <em>potassium chlorate</em> and <em>oxygen gas</em>. </p> <p>This tells you that the reaction will always produce <mathjax>#3/2#</mathjax> <strong>times more moles</strong> of oxygen gas than the number of moles of potassium chlorate that underwent decomposition. </p> <p>Use potassium chlorate's <strong>molar mass</strong> to determine how many moles you have in that <mathjax>#"231-g"#</mathjax> sample</p> <blockquote> <p><mathjax>#231 color(red)(cancel(color(black)("g"))) * "1 mole KClO"_3/(122.55color(red)(cancel(color(black)("g")))) = "1.885 moles KClO"_3#</mathjax></p> </blockquote> <p>Use the aforementioned mole ratio to determine how many moles of oxygen would be produced from this many moles of potassium chlorate</p> <blockquote> <p><mathjax>#1.885 color(red)(cancel(color(black)("moles KClO"_3))) * (color(red)(3)" moles O"_2)/(color(blue)(2)color(red)(cancel(color(black)("moles KClO"_3)))) = "2.8275 moles O"_2#</mathjax></p> </blockquote> <p>So, what volume would this many moles occupy <em>at STP</em>? </p> <blockquote> <p><mathjax>#2.8275 color(red)(cancel(color(black)("moles"))) * "22.7 L"/(1color(red)(cancel(color(black)("mol")))) = color(green)("64.2 L")#</mathjax></p> </blockquote> <p>The answer is rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"64.2 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to be able to calculate the volume of oxygen gas produced by this reaction, you need to know the conditions for <em>pressure</em> and <em>temperature</em>. </p> <p>Since no mention of those conditions was made, I'll assume that the reaction takes place at <strong>STP</strong>, Standard Temperature and Pressure. </p> <p><strong>STP conditions</strong> are defined as a pressure of <mathjax>#"100 kPa"#</mathjax> and a temperature of <mathjax>#0^@"C"#</mathjax>. Under these conditions for pressure and temperature, <strong>one mole</strong> of any ideal gas occupies <mathjax>#"22.7 L"#</mathjax> - this is known as <a href="https://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">the molar volume of a gas at STP</a>.</p> <p>So, in order to find the volume of oxygen gas at STP, you need to know how many <em>moles</em> of oxygen are produced by this reaction. </p> <p>The balanced chemical equation for this <a href="https://socratic.org/chemistry/chemical-reactions/decomposition-reactions">decomposition reaction</a> looks like this</p> <blockquote> <p><mathjax>#color(blue)(2)"KClO"_text(3(s]) stackrel(color(purple)("heat")color(white)(xx))(-&gt;) 2"KCl"_text((s]) + color(red)(3)"O"_text(2(g]) uarr#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#color(blue)(2):color(red)(3)#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between <em>potassium chlorate</em> and <em>oxygen gas</em>. </p> <p>This tells you that the reaction will always produce <mathjax>#3/2#</mathjax> <strong>times more moles</strong> of oxygen gas than the number of moles of potassium chlorate that underwent decomposition. </p> <p>Use potassium chlorate's <strong>molar mass</strong> to determine how many moles you have in that <mathjax>#"231-g"#</mathjax> sample</p> <blockquote> <p><mathjax>#231 color(red)(cancel(color(black)("g"))) * "1 mole KClO"_3/(122.55color(red)(cancel(color(black)("g")))) = "1.885 moles KClO"_3#</mathjax></p> </blockquote> <p>Use the aforementioned mole ratio to determine how many moles of oxygen would be produced from this many moles of potassium chlorate</p> <blockquote> <p><mathjax>#1.885 color(red)(cancel(color(black)("moles KClO"_3))) * (color(red)(3)" moles O"_2)/(color(blue)(2)color(red)(cancel(color(black)("moles KClO"_3)))) = "2.8275 moles O"_2#</mathjax></p> </blockquote> <p>So, what volume would this many moles occupy <em>at STP</em>? </p> <blockquote> <p><mathjax>#2.8275 color(red)(cancel(color(black)("moles"))) * "22.7 L"/(1color(red)(cancel(color(black)("mol")))) = color(green)("64.2 L")#</mathjax></p> </blockquote> <p>The answer is rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">In the reaction #2KClO_3(s) -&gt; 2KCl(s) + 3O_2(g)#, how many liters of oxygen would be produced from 231 g of potassium chlorate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/equation-stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Equation Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="204423" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-27T17:11:32" itemprop="dateCreated"> Dec 27, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"64.2 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to be able to calculate the volume of oxygen gas produced by this reaction, you need to know the conditions for <em>pressure</em> and <em>temperature</em>. </p> <p>Since no mention of those conditions was made, I'll assume that the reaction takes place at <strong>STP</strong>, Standard Temperature and Pressure. </p> <p><strong>STP conditions</strong> are defined as a pressure of <mathjax>#"100 kPa"#</mathjax> and a temperature of <mathjax>#0^@"C"#</mathjax>. Under these conditions for pressure and temperature, <strong>one mole</strong> of any ideal gas occupies <mathjax>#"22.7 L"#</mathjax> - this is known as <a href="https://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">the molar volume of a gas at STP</a>.</p> <p>So, in order to find the volume of oxygen gas at STP, you need to know how many <em>moles</em> of oxygen are produced by this reaction. </p> <p>The balanced chemical equation for this <a href="https://socratic.org/chemistry/chemical-reactions/decomposition-reactions">decomposition reaction</a> looks like this</p> <blockquote> <p><mathjax>#color(blue)(2)"KClO"_text(3(s]) stackrel(color(purple)("heat")color(white)(xx))(-&gt;) 2"KCl"_text((s]) + color(red)(3)"O"_text(2(g]) uarr#</mathjax></p> </blockquote> <p>Notice that you have a <mathjax>#color(blue)(2):color(red)(3)#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> between <em>potassium chlorate</em> and <em>oxygen gas</em>. </p> <p>This tells you that the reaction will always produce <mathjax>#3/2#</mathjax> <strong>times more moles</strong> of oxygen gas than the number of moles of potassium chlorate that underwent decomposition. </p> <p>Use potassium chlorate's <strong>molar mass</strong> to determine how many moles you have in that <mathjax>#"231-g"#</mathjax> sample</p> <blockquote> <p><mathjax>#231 color(red)(cancel(color(black)("g"))) * "1 mole KClO"_3/(122.55color(red)(cancel(color(black)("g")))) = "1.885 moles KClO"_3#</mathjax></p> </blockquote> <p>Use the aforementioned mole ratio to determine how many moles of oxygen would be produced from this many moles of potassium chlorate</p> <blockquote> <p><mathjax>#1.885 color(red)(cancel(color(black)("moles KClO"_3))) * (color(red)(3)" moles O"_2)/(color(blue)(2)color(red)(cancel(color(black)("moles KClO"_3)))) = "2.8275 moles O"_2#</mathjax></p> </blockquote> <p>So, what volume would this many moles occupy <em>at STP</em>? </p> <blockquote> <p><mathjax>#2.8275 color(red)(cancel(color(black)("moles"))) * "22.7 L"/(1color(red)(cancel(color(black)("mol")))) = color(green)("64.2 L")#</mathjax></p> </blockquote> <p>The answer is rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/204423" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4171602bf3469588dc36e"> What are the types of stoichiometry examples, with examples? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4171802bf3469570e2e82"> Question #e2e82 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668a402bf34573b4e66fb"> What mass of carbon dioxide can 1.00 kg of lithium oxide absorb? 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In the reaction #2KClO_3(s) -&gt; 2KCl(s) + 3O_2(g)#, how many liters of oxygen would be produced from 231 g of potassium chlorate?

a9a9d4f7-6ddd-11ea-9a46-ccda262736ce

https://socratic.org/questions/how-many-ml-of-a-10-m-naoh-solution-are-needed-to-neutralize-15-ml-of-20-m-h-3po

30 mL

start physical_unit 7 8 volume ml qc_end physical_unit 7 8 5 6 molarity qc_end physical_unit 18 19 16 17 molarity qc_end physical_unit 18 19 13 14 volume qc_end end

[{"type":"physical unit","value":"Volume [OF] NaOH solution [IN] mL"}]

[{"type":"physical unit","value":"30 mL"}]

[{"type":"physical unit","value":"Molarity [OF] NaOH solution [=] \\pu{10 M}"},{"type":"physical unit","value":"Molarity [OF] H3PO4 solution [=] \\pu{20 M}"},{"type":"physical unit","value":"Volume [OF] H3PO4 solution [=] \\pu{15 mL}"}]

<h1 class="questionTitle" itemprop="name">How many mL of a .10 M #NaOH# solution are needed to neutralize 15 mL of .20 M #H_3PO_4# solution?</h1>

30 mL

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Use the formula <mathjax>#M_AV_A = M_BV_B#</mathjax>.</strong></p> <p><mathjax>#M_A =#</mathjax> <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> of acid, <mathjax>#V_A =#</mathjax>Volume of acid<br/> <mathjax>#M_B =#</mathjax> Molarity of base, <mathjax>#V_B =#</mathjax>Volume of base</p> <p><strong>1. Plug known values into the formula.</strong></p> <p><mathjax>#(.20)(15) = .10(x)#</mathjax></p> <p><strong>2. Solve for x.</strong></p> <p><mathjax>#3 = .10x#</mathjax><br/> <mathjax>#x = 30#</mathjax></p> <p>30 mL is your answer.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>30 mL</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Use the formula <mathjax>#M_AV_A = M_BV_B#</mathjax>.</strong></p> <p><mathjax>#M_A =#</mathjax> <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> of acid, <mathjax>#V_A =#</mathjax>Volume of acid<br/> <mathjax>#M_B =#</mathjax> Molarity of base, <mathjax>#V_B =#</mathjax>Volume of base</p> <p><strong>1. Plug known values into the formula.</strong></p> <p><mathjax>#(.20)(15) = .10(x)#</mathjax></p> <p><strong>2. Solve for x.</strong></p> <p><mathjax>#3 = .10x#</mathjax><br/> <mathjax>#x = 30#</mathjax></p> <p>30 mL is your answer.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many mL of a .10 M #NaOH# solution are needed to neutralize 15 mL of .20 M #H_3PO_4# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="442064" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michelle-33"><img alt="" class="" src="https://profilepictures.socratic.org/QwvZBefRmOXvj0OScuwA_bfb655b5a099a18b5c1023c5f8de9367--violet-aesthetic-pastel-tumblr-purple-aesthetic.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michelle-33"> Michelle </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-19T21:48:58" itemprop="dateCreated"> Jun 19, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>30 mL</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Use the formula <mathjax>#M_AV_A = M_BV_B#</mathjax>.</strong></p> <p><mathjax>#M_A =#</mathjax> <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> of acid, <mathjax>#V_A =#</mathjax>Volume of acid<br/> <mathjax>#M_B =#</mathjax> Molarity of base, <mathjax>#V_B =#</mathjax>Volume of base</p> <p><strong>1. Plug known values into the formula.</strong></p> <p><mathjax>#(.20)(15) = .10(x)#</mathjax></p> <p><strong>2. Solve for x.</strong></p> <p><mathjax>#3 = .10x#</mathjax><br/> <mathjax>#x = 30#</mathjax></p> <p>30 mL is your answer.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/442064" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-solution-solute-and-solvent-related"> How are solution, solute, and solvent related? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutions-become-saturated"> Why do solutions become saturated? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-solutions"> How does temperature affect solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-solution-differ-from-a-colloid"> How does a solution differ from a colloid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/calculate-the-amount-of-1-m-naoh-aqueous-solution-needed-to-make-100-ml-of-0-5-m"> Calculate the amount of 1 M NaOH aqueous solution needed to make 100 mL of 0.5 M NaOH aqueous solution. </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-buffering-a-solution-change-the-solutions-behavior"> How does buffering a solution change the solutions behavior? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-benedict-s-solution-change-colour"> How does Benedict's solution change colour? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/describe-how-would-you-prepare-1-l-of-a-1-m-solution-of-sodium-chloride-the-gram"> Describe how would you prepare 1 L of a 1 M solution of sodium chloride. The gram formula weight... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-solutions-differ-from-suspensions"> How do solutions differ from suspensions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-solution-differ-from-a-compound"> How does a solution differ from a compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/solutions"> See all questions in Solutions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 27858 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many mL of a .10 M #NaOH# solution are needed to neutralize 15 mL of .20 M #H_3PO_4# solution?

a92bda34-6ddd-11ea-a467-ccda262736ce

https://socratic.org/questions/trimethylamine-ch3-3n-is-a-weak-base-kb-6-4-10-5-that-hydrolyzes-by-the-followin

4.40

start physical_unit 32 32 ph none qc_end physical_unit 1 1 8 10 kb qc_end chemical_equation 17 23 qc_end physical_unit 21 21 30 31 molarity qc_end end

[{"type":"physical unit","value":"pH [OF] (CH3)3NH+ solution"}]

[{"type":"physical unit","value":"4.40"}]

[{"type":"physical unit","value":"Kb [OF] (CH3)3N [=] \\pu{6.4 × 10^(-5)}"},{"type":"chemical equation","value":"(CH3)3N + H2O -> (CH3)3NH+ + OH-"},{"type":"physical unit","value":"Molarity [OF] (CH3)3NH+ solution [=] \\pu{0.1 M}"}]

<h1 class="questionTitle" itemprop="name">Trimethylamine, (CH3)3N, is a weak base (Kb = 6.4 × 10–5) that hydrolyzes by the following equilibrium: (CH3)3N + H2O → (CH3)3NH+ + OH– What is the pH of a 0.1 M solution of (CH3)3NH+? (Enter pH to 2 decimal places; hundredth's.</h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><img alt="canvas" src="https://useruploads.socratic.org/AHNiz2rTSmGeNgw2VzLd_Screen%20Shot%202016-05-25%20at%209.08.38+PM.png"/> </p></div> </h2> </div> </div>

4.40

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your starting point here will be to write the balanced chemical equation that describes the ionization of the <em>trimethylammonium cation</em>, <mathjax>#("CH"_3)_3"NH"^(+)#</mathjax>, the <strong>conjugate acid</strong> of trimethylamine, <mathjax>#("CH"_3)_3"N"#</mathjax>. </p> <p>Next, use an <strong>ICE table</strong> to determine the equilibrium concentration of the hydronium cations, <mathjax>#"H"_3"O"^(+)#</mathjax>, that result from the ionization of the conjugate acid. </p> <p>The trimethylammonium cation will react with water to reform some of the weak base and produce hydronium cations, both in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong>. </p> <p>This means that for every mole of conjugate acid <strong>that ionizes</strong>, you get <strong>one mole</strong> of weak base and <strong>one mole</strong> of hydronium cations.</p> <p>The <strong>ICE table</strong> will thus look like this </p> <blockquote> <p><mathjax>#("CH"_ 3)_ 3"NH"_ ((aq))^(+) + "H"_ 2"O"_ ((l)) rightleftharpoons ("CH"_ 3)_ 3"N"_ ((aq)) + "H"_ 3"O"_ ((aq))^(+)#</mathjax></p> </blockquote> <p><mathjax>#color(purple)("I")color(white)(aaaaacolor(black)(0.1)aaaaaaaaaaaaaaaaaaaaacolor(black)(0)aaaaaaaaacolor(black)(0)#</mathjax><br/> <mathjax>#color(purple)("C")color(white)(aaacolor(black)((-x))aaaaaaaaaaaaaaaaaacolor(black)((+x))aaaaacolor(black)((+x))#</mathjax><br/> <mathjax>#color(purple)("E")color(white)(aaacolor(black)(0.1-x)aaaaaaaaaaaaaaaaaaacolor(black)(x)aaaaaaaaacolor(black)(x)#</mathjax></p> <p>Now, you know that an aqueous solution at room temperature has </p> <blockquote> <p><mathjax>#color(purple)(|bar(ul(color(white)(a/a)color(black)(K_a xx K_b = K_W)color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>where</p> <blockquote> <p><mathjax>#K_w = 10^(-14) -&gt;#</mathjax> <em>the <strong>ionization constant</strong> of water</em> </p> </blockquote> <p>Use this equation to calculate the <em>acid dissociation constant</em>, <mathjax>#K_a#</mathjax>, for the trimethylammonium cation </p> <blockquote> <p><mathjax>#K_a = K_W/K_b#</mathjax></p> <p><mathjax>#K_a = 10^(-14)/(6.4 * 10^(-5)) = 1.56 * 10^(-10)#</mathjax></p> </blockquote> <p>By definition, the acid dissociation constant will be equal to </p> <blockquote> <p><mathjax>#K_a = ([("CH"_3)_3"N"] * ["H"_3"O"^(+)])/([("CH"_3)_3"NH"^(+)])#</mathjax></p> </blockquote> <p>In your case, you will have </p> <blockquote> <p><mathjax>#K_b = (x * x)/(0.1 - x) = 6.4 * 10^(-5)#</mathjax></p> </blockquote> <p>Since <mathjax>#K_a#</mathjax> has such a small value when compared with the initial concentration of the conjugate acid, you can use the approximation </p> <blockquote> <p><mathjax>#0.1 - x ~~ 0.1#</mathjax></p> </blockquote> <p>This will get you </p> <blockquote> <p><mathjax>#1.56 * 10^(-10) = x^2/0.1#</mathjax></p> </blockquote> <p>Solve for <mathjax>#x#</mathjax> to find</p> <blockquote> <p><mathjax>#x = sqrt((1.56 * 10^(-10))/0.1) = 3.95 * 10^(-5)#</mathjax></p> </blockquote> <p>Since <mathjax>#x#</mathjax> represents the <strong>equilibrium concentration</strong> of the hydronium cations, you will have </p> <blockquote> <p><mathjax>#["H"_3"O"^(+)] = 3.95 * 10^(-5)"M"#</mathjax></p> </blockquote> <p>As you know, the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the solution is defined as </p> <blockquote> <p><mathjax>#color(blue)(|bar(ul(color(white)(a/a)"pH" = - log(["H"_3"O"^(+)])color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>Plug in your value to find</p> <blockquote> <p><mathjax>#"pH" = - log(3.95 * 10^(-5)) = color(green)(|bar(ul(color(white)(a/a)4.40color(white)(a/a)|)))#</mathjax></p> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 4.40#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your starting point here will be to write the balanced chemical equation that describes the ionization of the <em>trimethylammonium cation</em>, <mathjax>#("CH"_3)_3"NH"^(+)#</mathjax>, the <strong>conjugate acid</strong> of trimethylamine, <mathjax>#("CH"_3)_3"N"#</mathjax>. </p> <p>Next, use an <strong>ICE table</strong> to determine the equilibrium concentration of the hydronium cations, <mathjax>#"H"_3"O"^(+)#</mathjax>, that result from the ionization of the conjugate acid. </p> <p>The trimethylammonium cation will react with water to reform some of the weak base and produce hydronium cations, both in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong>. </p> <p>This means that for every mole of conjugate acid <strong>that ionizes</strong>, you get <strong>one mole</strong> of weak base and <strong>one mole</strong> of hydronium cations.</p> <p>The <strong>ICE table</strong> will thus look like this </p> <blockquote> <p><mathjax>#("CH"_ 3)_ 3"NH"_ ((aq))^(+) + "H"_ 2"O"_ ((l)) rightleftharpoons ("CH"_ 3)_ 3"N"_ ((aq)) + "H"_ 3"O"_ ((aq))^(+)#</mathjax></p> </blockquote> <p><mathjax>#color(purple)("I")color(white)(aaaaacolor(black)(0.1)aaaaaaaaaaaaaaaaaaaaacolor(black)(0)aaaaaaaaacolor(black)(0)#</mathjax><br/> <mathjax>#color(purple)("C")color(white)(aaacolor(black)((-x))aaaaaaaaaaaaaaaaaacolor(black)((+x))aaaaacolor(black)((+x))#</mathjax><br/> <mathjax>#color(purple)("E")color(white)(aaacolor(black)(0.1-x)aaaaaaaaaaaaaaaaaaacolor(black)(x)aaaaaaaaacolor(black)(x)#</mathjax></p> <p>Now, you know that an aqueous solution at room temperature has </p> <blockquote> <p><mathjax>#color(purple)(|bar(ul(color(white)(a/a)color(black)(K_a xx K_b = K_W)color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>where</p> <blockquote> <p><mathjax>#K_w = 10^(-14) -&gt;#</mathjax> <em>the <strong>ionization constant</strong> of water</em> </p> </blockquote> <p>Use this equation to calculate the <em>acid dissociation constant</em>, <mathjax>#K_a#</mathjax>, for the trimethylammonium cation </p> <blockquote> <p><mathjax>#K_a = K_W/K_b#</mathjax></p> <p><mathjax>#K_a = 10^(-14)/(6.4 * 10^(-5)) = 1.56 * 10^(-10)#</mathjax></p> </blockquote> <p>By definition, the acid dissociation constant will be equal to </p> <blockquote> <p><mathjax>#K_a = ([("CH"_3)_3"N"] * ["H"_3"O"^(+)])/([("CH"_3)_3"NH"^(+)])#</mathjax></p> </blockquote> <p>In your case, you will have </p> <blockquote> <p><mathjax>#K_b = (x * x)/(0.1 - x) = 6.4 * 10^(-5)#</mathjax></p> </blockquote> <p>Since <mathjax>#K_a#</mathjax> has such a small value when compared with the initial concentration of the conjugate acid, you can use the approximation </p> <blockquote> <p><mathjax>#0.1 - x ~~ 0.1#</mathjax></p> </blockquote> <p>This will get you </p> <blockquote> <p><mathjax>#1.56 * 10^(-10) = x^2/0.1#</mathjax></p> </blockquote> <p>Solve for <mathjax>#x#</mathjax> to find</p> <blockquote> <p><mathjax>#x = sqrt((1.56 * 10^(-10))/0.1) = 3.95 * 10^(-5)#</mathjax></p> </blockquote> <p>Since <mathjax>#x#</mathjax> represents the <strong>equilibrium concentration</strong> of the hydronium cations, you will have </p> <blockquote> <p><mathjax>#["H"_3"O"^(+)] = 3.95 * 10^(-5)"M"#</mathjax></p> </blockquote> <p>As you know, the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the solution is defined as </p> <blockquote> <p><mathjax>#color(blue)(|bar(ul(color(white)(a/a)"pH" = - log(["H"_3"O"^(+)])color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>Plug in your value to find</p> <blockquote> <p><mathjax>#"pH" = - log(3.95 * 10^(-5)) = color(green)(|bar(ul(color(white)(a/a)4.40color(white)(a/a)|)))#</mathjax></p> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Trimethylamine, (CH3)3N, is a weak base (Kb = 6.4 × 10–5) that hydrolyzes by the following equilibrium: (CH3)3N + H2O → (CH3)3NH+ + OH– What is the pH of a 0.1 M solution of (CH3)3NH+? (Enter pH to 2 decimal places; hundredth's.</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><img alt="canvas" src="https://useruploads.socratic.org/AHNiz2rTSmGeNgw2VzLd_Screen%20Shot%202016-05-25%20at%209.08.38+PM.png"/> </p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="270088" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-27T01:04:10" itemprop="dateCreated"> May 27, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 4.40#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your starting point here will be to write the balanced chemical equation that describes the ionization of the <em>trimethylammonium cation</em>, <mathjax>#("CH"_3)_3"NH"^(+)#</mathjax>, the <strong>conjugate acid</strong> of trimethylamine, <mathjax>#("CH"_3)_3"N"#</mathjax>. </p> <p>Next, use an <strong>ICE table</strong> to determine the equilibrium concentration of the hydronium cations, <mathjax>#"H"_3"O"^(+)#</mathjax>, that result from the ionization of the conjugate acid. </p> <p>The trimethylammonium cation will react with water to reform some of the weak base and produce hydronium cations, both in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong>. </p> <p>This means that for every mole of conjugate acid <strong>that ionizes</strong>, you get <strong>one mole</strong> of weak base and <strong>one mole</strong> of hydronium cations.</p> <p>The <strong>ICE table</strong> will thus look like this </p> <blockquote> <p><mathjax>#("CH"_ 3)_ 3"NH"_ ((aq))^(+) + "H"_ 2"O"_ ((l)) rightleftharpoons ("CH"_ 3)_ 3"N"_ ((aq)) + "H"_ 3"O"_ ((aq))^(+)#</mathjax></p> </blockquote> <p><mathjax>#color(purple)("I")color(white)(aaaaacolor(black)(0.1)aaaaaaaaaaaaaaaaaaaaacolor(black)(0)aaaaaaaaacolor(black)(0)#</mathjax><br/> <mathjax>#color(purple)("C")color(white)(aaacolor(black)((-x))aaaaaaaaaaaaaaaaaacolor(black)((+x))aaaaacolor(black)((+x))#</mathjax><br/> <mathjax>#color(purple)("E")color(white)(aaacolor(black)(0.1-x)aaaaaaaaaaaaaaaaaaacolor(black)(x)aaaaaaaaacolor(black)(x)#</mathjax></p> <p>Now, you know that an aqueous solution at room temperature has </p> <blockquote> <p><mathjax>#color(purple)(|bar(ul(color(white)(a/a)color(black)(K_a xx K_b = K_W)color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>where</p> <blockquote> <p><mathjax>#K_w = 10^(-14) -&gt;#</mathjax> <em>the <strong>ionization constant</strong> of water</em> </p> </blockquote> <p>Use this equation to calculate the <em>acid dissociation constant</em>, <mathjax>#K_a#</mathjax>, for the trimethylammonium cation </p> <blockquote> <p><mathjax>#K_a = K_W/K_b#</mathjax></p> <p><mathjax>#K_a = 10^(-14)/(6.4 * 10^(-5)) = 1.56 * 10^(-10)#</mathjax></p> </blockquote> <p>By definition, the acid dissociation constant will be equal to </p> <blockquote> <p><mathjax>#K_a = ([("CH"_3)_3"N"] * ["H"_3"O"^(+)])/([("CH"_3)_3"NH"^(+)])#</mathjax></p> </blockquote> <p>In your case, you will have </p> <blockquote> <p><mathjax>#K_b = (x * x)/(0.1 - x) = 6.4 * 10^(-5)#</mathjax></p> </blockquote> <p>Since <mathjax>#K_a#</mathjax> has such a small value when compared with the initial concentration of the conjugate acid, you can use the approximation </p> <blockquote> <p><mathjax>#0.1 - x ~~ 0.1#</mathjax></p> </blockquote> <p>This will get you </p> <blockquote> <p><mathjax>#1.56 * 10^(-10) = x^2/0.1#</mathjax></p> </blockquote> <p>Solve for <mathjax>#x#</mathjax> to find</p> <blockquote> <p><mathjax>#x = sqrt((1.56 * 10^(-10))/0.1) = 3.95 * 10^(-5)#</mathjax></p> </blockquote> <p>Since <mathjax>#x#</mathjax> represents the <strong>equilibrium concentration</strong> of the hydronium cations, you will have </p> <blockquote> <p><mathjax>#["H"_3"O"^(+)] = 3.95 * 10^(-5)"M"#</mathjax></p> </blockquote> <p>As you know, the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the solution is defined as </p> <blockquote> <p><mathjax>#color(blue)(|bar(ul(color(white)(a/a)"pH" = - log(["H"_3"O"^(+)])color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>Plug in your value to find</p> <blockquote> <p><mathjax>#"pH" = - log(3.95 * 10^(-5)) = color(green)(|bar(ul(color(white)(a/a)4.40color(white)(a/a)|)))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/270088" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 87416 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

Trimethylamine, (CH3)3N, is a weak base (Kb = 6.4 × 10–5) that hydrolyzes by the following equilibrium: (CH3)3N + H2O → (CH3)3NH+ + OH– What is the pH of a 0.1 M solution of (CH3)3NH+? (Enter pH to 2 decimal places; hundredth's.

a8c69251-6ddd-11ea-b472-ccda262736ce

https://socratic.org/questions/what-is-the-concentration-m-of-sodium-ions-in-4-57-l-of-a-1-25-m-na-3po-4-soluti

3.75 M

start physical_unit 6 7 concentration mol/l qc_end physical_unit 15 16 9 10 volume qc_end physical_unit 15 16 13 14 concentration qc_end end

[{"type":"physical unit","value":"Concentration [OF] sodium ions [IN] M"}]

[{"type":"physical unit","value":"3.75 M"}]

[{"type":"physical unit","value":"Volume [OF] Na3PO4 solution [=] \\pu{4.57 L}"},{"type":"physical unit","value":"Concentration [OF] Na3PO4 solution [=] \\pu{1.25 M}"}]

<h1 class="questionTitle" itemprop="name">What is the concentration (M) of sodium ions in 4.57 L of a 1.25 M #Na_3PO_4# solution?</h1>

3.75 M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When asked to find the concentration of sodium ions in a given concentration, you need to first find the ratio of ions per molecule.</p> <p><mathjax>#"Na"_3"PO"_4 = "Na"^(+) + "Na"^(+) + "Na"^(+) + "PO"_4^(3-)#</mathjax></p> <p>We see that for every <strong>formula unit</strong> of <mathjax>#"Na"_3"PO"_4#</mathjax>, there are <mathjax>#3#</mathjax> <strong>ions</strong> of <mathjax>#"Na"^(+)#</mathjax>.</p> <h2></h2> <p><strong>Step 1</strong></p> <p>We are given <mathjax>#"4.57 L"#</mathjax> of a <mathjax>#"1.25-M"#</mathjax> (molarity) solution of <mathjax>#"Na"_3"PO"_4#</mathjax>. From the formula </p> <p><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity"><mathjax>#"molarity"#</mathjax></a> <mathjax>#(c) = ("moles solute")/("1 L solution")#</mathjax></p> <p>we can derive that </p> <p><mathjax>#"1.25 M Na"_3"PO"_4 = ("1.25 mol")/("1 L solution")#</mathjax></p> <p><strong>Step 2</strong></p> <p>With the two pieces of information, we can solve straight across;</p> <p><mathjax>#"4.57 L solution" xx ("1.25 mol Na"_3"PO"_4)/("1 L solution") xx (6.022*10^23 \ "for. units Na"_3"PO"_4)/("1 mol Na"_3"PO"_4) xx ("3 ions Na"^(+))/("1 mol Na"_3"O"_4) = 1.03*10^25 \ "ions Na"^(+)#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.03*10^25 \ "ions Na"^(+)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When asked to find the concentration of sodium ions in a given concentration, you need to first find the ratio of ions per molecule.</p> <p><mathjax>#"Na"_3"PO"_4 = "Na"^(+) + "Na"^(+) + "Na"^(+) + "PO"_4^(3-)#</mathjax></p> <p>We see that for every <strong>formula unit</strong> of <mathjax>#"Na"_3"PO"_4#</mathjax>, there are <mathjax>#3#</mathjax> <strong>ions</strong> of <mathjax>#"Na"^(+)#</mathjax>.</p> <h2></h2> <p><strong>Step 1</strong></p> <p>We are given <mathjax>#"4.57 L"#</mathjax> of a <mathjax>#"1.25-M"#</mathjax> (molarity) solution of <mathjax>#"Na"_3"PO"_4#</mathjax>. From the formula </p> <p><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity"><mathjax>#"molarity"#</mathjax></a> <mathjax>#(c) = ("moles solute")/("1 L solution")#</mathjax></p> <p>we can derive that </p> <p><mathjax>#"1.25 M Na"_3"PO"_4 = ("1.25 mol")/("1 L solution")#</mathjax></p> <p><strong>Step 2</strong></p> <p>With the two pieces of information, we can solve straight across;</p> <p><mathjax>#"4.57 L solution" xx ("1.25 mol Na"_3"PO"_4)/("1 L solution") xx (6.022*10^23 \ "for. units Na"_3"PO"_4)/("1 mol Na"_3"PO"_4) xx ("3 ions Na"^(+))/("1 mol Na"_3"O"_4) = 1.03*10^25 \ "ions Na"^(+)#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the concentration (M) of sodium ions in 4.57 L of a 1.25 M #Na_3PO_4# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="233482" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/wil052"><img alt="" class="" src="https://profilepictures.socratic.org/0P5SVeaCSfqbcHcQzSFx_Visiblelight.png" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/wil052"> Wil052 </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-01T12:36:29" itemprop="dateCreated"> Mar 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.03*10^25 \ "ions Na"^(+)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>When asked to find the concentration of sodium ions in a given concentration, you need to first find the ratio of ions per molecule.</p> <p><mathjax>#"Na"_3"PO"_4 = "Na"^(+) + "Na"^(+) + "Na"^(+) + "PO"_4^(3-)#</mathjax></p> <p>We see that for every <strong>formula unit</strong> of <mathjax>#"Na"_3"PO"_4#</mathjax>, there are <mathjax>#3#</mathjax> <strong>ions</strong> of <mathjax>#"Na"^(+)#</mathjax>.</p> <h2></h2> <p><strong>Step 1</strong></p> <p>We are given <mathjax>#"4.57 L"#</mathjax> of a <mathjax>#"1.25-M"#</mathjax> (molarity) solution of <mathjax>#"Na"_3"PO"_4#</mathjax>. From the formula </p> <p><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity"><mathjax>#"molarity"#</mathjax></a> <mathjax>#(c) = ("moles solute")/("1 L solution")#</mathjax></p> <p>we can derive that </p> <p><mathjax>#"1.25 M Na"_3"PO"_4 = ("1.25 mol")/("1 L solution")#</mathjax></p> <p><strong>Step 2</strong></p> <p>With the two pieces of information, we can solve straight across;</p> <p><mathjax>#"4.57 L solution" xx ("1.25 mol Na"_3"PO"_4)/("1 L solution") xx (6.022*10^23 \ "for. units Na"_3"PO"_4)/("1 mol Na"_3"PO"_4) xx ("3 ions Na"^(+))/("1 mol Na"_3"O"_4) = 1.03*10^25 \ "ions Na"^(+)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/233482" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 36120 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the concentration (M) of sodium ions in 4.57 L of a 1.25 M #Na_3PO_4# solution?

aa89371f-6ddd-11ea-afd3-ccda262736ce

https://socratic.org/questions/590cbad97c01494db3f340f1

1.49 g/L

start physical_unit 6 7 density g/l qc_end physical_unit 6 7 9 10 pressure qc_end physical_unit 6 7 16 17 temperature qc_end end

[{"type":"physical unit","value":"Density [OF] dioxygen gas [IN] g/L"}]

[{"type":"physical unit","value":"1.49 g/L"}]

[{"type":"physical unit","value":"Pressure [OF] dioxygen gas [=] \\pu{840 mmHg}"},{"type":"physical unit","value":"Temperature [OF] dioxygen gas [=] \\pu{291 K}"}]

<h1 class="questionTitle" itemprop="name">What is the density of a dioxygen gas at #840*"mm Hg"# pressure at a temperature of #291*K#?</h1>

1.49 g/L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#PV=nRT#</mathjax>; i.e. <mathjax>#P=(nRT)/V="mass"/Vxx(RT)/"molar mass"#</mathjax>.</p> <p>And thus <mathjax>#rho="mass"/V=P/(RT)xx"Molar mass"#</mathjax>.</p> <p>The signal problem with this question is that you do not measure pressure OVER <mathjax>#1*atm#</mathjax> in <mathjax>#mm*Hg#</mathjax>. A mercury column is good for measuring pressures <mathjax>#&lt;=1*atm#</mathjax>.</p> <p>We know that <mathjax>#1*atm-=760*mm*Hg#</mathjax>, i.e. an atmosphere will support a column of mercury that is <mathjax>#760*mm#</mathjax> high......A mercury column is thus suitable to measure <a href="https://socratic.org/chemistry/the-behavior-of-gases/atmospheric-pressure">atmospheric pressure</a>, or for pressures LESS than one atmosphere. </p> <p>And thus, here, <mathjax>#P=(840*mm*Hg)/(760*mm*Hg*atm^-1)=1.11*atm.#</mathjax></p> <p>And so, <mathjax>#rho=(1.11*cancel(atm)xx32.0*g*cancel(mol^-1))/(0.0821*L*cancel(atm)*cancel(K^-1)*cancel(mol^-1)xx291*cancelK)#</mathjax></p> <p><mathjax>#~=1.5*g*L^-1.........#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#rho&lt;0.15*g*mL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#PV=nRT#</mathjax>; i.e. <mathjax>#P=(nRT)/V="mass"/Vxx(RT)/"molar mass"#</mathjax>.</p> <p>And thus <mathjax>#rho="mass"/V=P/(RT)xx"Molar mass"#</mathjax>.</p> <p>The signal problem with this question is that you do not measure pressure OVER <mathjax>#1*atm#</mathjax> in <mathjax>#mm*Hg#</mathjax>. A mercury column is good for measuring pressures <mathjax>#&lt;=1*atm#</mathjax>.</p> <p>We know that <mathjax>#1*atm-=760*mm*Hg#</mathjax>, i.e. an atmosphere will support a column of mercury that is <mathjax>#760*mm#</mathjax> high......A mercury column is thus suitable to measure <a href="https://socratic.org/chemistry/the-behavior-of-gases/atmospheric-pressure">atmospheric pressure</a>, or for pressures LESS than one atmosphere. </p> <p>And thus, here, <mathjax>#P=(840*mm*Hg)/(760*mm*Hg*atm^-1)=1.11*atm.#</mathjax></p> <p>And so, <mathjax>#rho=(1.11*cancel(atm)xx32.0*g*cancel(mol^-1))/(0.0821*L*cancel(atm)*cancel(K^-1)*cancel(mol^-1)xx291*cancelK)#</mathjax></p> <p><mathjax>#~=1.5*g*L^-1.........#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the density of a dioxygen gas at #840*"mm Hg"# pressure at a temperature of #291*K#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="418242" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-05T18:40:34" itemprop="dateCreated"> May 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#rho&lt;0.15*g*mL^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#PV=nRT#</mathjax>; i.e. <mathjax>#P=(nRT)/V="mass"/Vxx(RT)/"molar mass"#</mathjax>.</p> <p>And thus <mathjax>#rho="mass"/V=P/(RT)xx"Molar mass"#</mathjax>.</p> <p>The signal problem with this question is that you do not measure pressure OVER <mathjax>#1*atm#</mathjax> in <mathjax>#mm*Hg#</mathjax>. A mercury column is good for measuring pressures <mathjax>#&lt;=1*atm#</mathjax>.</p> <p>We know that <mathjax>#1*atm-=760*mm*Hg#</mathjax>, i.e. an atmosphere will support a column of mercury that is <mathjax>#760*mm#</mathjax> high......A mercury column is thus suitable to measure <a href="https://socratic.org/chemistry/the-behavior-of-gases/atmospheric-pressure">atmospheric pressure</a>, or for pressures LESS than one atmosphere. </p> <p>And thus, here, <mathjax>#P=(840*mm*Hg)/(760*mm*Hg*atm^-1)=1.11*atm.#</mathjax></p> <p>And so, <mathjax>#rho=(1.11*cancel(atm)xx32.0*g*cancel(mol^-1))/(0.0821*L*cancel(atm)*cancel(K^-1)*cancel(mol^-1)xx291*cancelK)#</mathjax></p> <p><mathjax>#~=1.5*g*L^-1.........#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/418242" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1220 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the density of a dioxygen gas at #840*"mm Hg"# pressure at a temperature of #291*K#?

ad113e0c-6ddd-11ea-bf55-ccda262736ce

https://socratic.org/questions/a-yield-of-nh-3-of-approximately-98-can-be-obtained-at-200-deg-c-and-1-000-atmos

1.43 grams

start physical_unit 23 23 mass g qc_end physical_unit 3 3 6 6 percent_yield qc_end physical_unit 3 3 28 29 mass qc_end end

[{"type":"physical unit","value":"Mass [OF] N2 [IN] grams"}]

[{"type":"physical unit","value":"1.43 grams"}]

[{"type":"physical unit","value":"Yield [OF] NH3 [=] \\pu{98%}"},{"type":"physical unit","value":"Temperature [OF] the reaction [=] \\pu{200 deg C}"},{"type":"physical unit","value":"Pressure [OF] the reaction [=] \\pu{1,000 atmospheres}"},{"type":"physical unit","value":"Mass [OF] NH3 [=] \\pu{1.7 grams}"}]

<h1 class="questionTitle" itemprop="name">A yield of #NH_3# of approximately 98% can be obtained at 200 deg C and 1,000 atmospheres of pressure. How many grams of #N_2# must react to form 1.7 grams of ammonia, #NH_3#?</h1>

1.43 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We always have to read the problems completely to understand the question. In this case even when we have pressure and temperature conditions specified, they don't matter, first because they are constant and in second because the question ask for grams of <mathjax>#N_2#</mathjax> to produce grams of <mathjax>#NH_3#</mathjax>.</p> <p>We cannot compare grams of a substance to another in chemical reactions, we need to use moles, then we have to convert the weight of NH3 to moles. </p> <p><mathjax>#eta = m//MW#</mathjax> <br/> <mathjax>#MW_(NH_3) = 14.007 + 3(1.008) = 17.031 g//mol#</mathjax><br/> :. <mathjax>#eta = 1.7g//17.031 g//mol = 0.100 mol#</mathjax></p> <p>The yield is 98%, then the number of moles that would be produced are:</p> <p><mathjax>#0.100mol//0.98 = 0.102 mol#</mathjax> of <mathjax>#NH_3#</mathjax></p> <p>From the reaction (the hydrogen was implicit in the problem, because you are obtaining <mathjax>#NH_3#</mathjax>):</p> <p><mathjax>#N2 + 3H2 rarr 2NH3#</mathjax> </p> <p>There are 2 parts of <mathjax>#NH_3#</mathjax> that are obtained from 1 part of <mathjax>#N_2#</mathjax></p> <p>Then the moles of <mathjax>#N_2#</mathjax> required are going to be the half of the <mathjax>#NH_3#</mathjax> moles produced.</p> <p><mathjax>#N_2#</mathjax> moles = <mathjax>#NH_3 "moles"//2 = 0.102mol//2 = 0.051 mol#</mathjax> </p> <p>Last step is too convert the moles back to grams using the MW of <mathjax>#N_2 #</mathjax></p> <p><mathjax>#m_(N_2) = mol xx MW = 0.051mol xx (14.007g//molxx2) = 1.429 g#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1.429 g of <mathjax>#N_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We always have to read the problems completely to understand the question. In this case even when we have pressure and temperature conditions specified, they don't matter, first because they are constant and in second because the question ask for grams of <mathjax>#N_2#</mathjax> to produce grams of <mathjax>#NH_3#</mathjax>.</p> <p>We cannot compare grams of a substance to another in chemical reactions, we need to use moles, then we have to convert the weight of NH3 to moles. </p> <p><mathjax>#eta = m//MW#</mathjax> <br/> <mathjax>#MW_(NH_3) = 14.007 + 3(1.008) = 17.031 g//mol#</mathjax><br/> :. <mathjax>#eta = 1.7g//17.031 g//mol = 0.100 mol#</mathjax></p> <p>The yield is 98%, then the number of moles that would be produced are:</p> <p><mathjax>#0.100mol//0.98 = 0.102 mol#</mathjax> of <mathjax>#NH_3#</mathjax></p> <p>From the reaction (the hydrogen was implicit in the problem, because you are obtaining <mathjax>#NH_3#</mathjax>):</p> <p><mathjax>#N2 + 3H2 rarr 2NH3#</mathjax> </p> <p>There are 2 parts of <mathjax>#NH_3#</mathjax> that are obtained from 1 part of <mathjax>#N_2#</mathjax></p> <p>Then the moles of <mathjax>#N_2#</mathjax> required are going to be the half of the <mathjax>#NH_3#</mathjax> moles produced.</p> <p><mathjax>#N_2#</mathjax> moles = <mathjax>#NH_3 "moles"//2 = 0.102mol//2 = 0.051 mol#</mathjax> </p> <p>Last step is too convert the moles back to grams using the MW of <mathjax>#N_2 #</mathjax></p> <p><mathjax>#m_(N_2) = mol xx MW = 0.051mol xx (14.007g//molxx2) = 1.429 g#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A yield of #NH_3# of approximately 98% can be obtained at 200 deg C and 1,000 atmospheres of pressure. How many grams of #N_2# must react to form 1.7 grams of ammonia, #NH_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/atmospheric-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Atmospheric Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="430233" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kind-newt"><img alt="" class="" src="https://profilepictures.socratic.org/Qzc89tpQ1Sicc5weUinb_Koala.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kind-newt"> Alex M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-26T22:35:46" itemprop="dateCreated"> May 26, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1.429 g of <mathjax>#N_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We always have to read the problems completely to understand the question. In this case even when we have pressure and temperature conditions specified, they don't matter, first because they are constant and in second because the question ask for grams of <mathjax>#N_2#</mathjax> to produce grams of <mathjax>#NH_3#</mathjax>.</p> <p>We cannot compare grams of a substance to another in chemical reactions, we need to use moles, then we have to convert the weight of NH3 to moles. </p> <p><mathjax>#eta = m//MW#</mathjax> <br/> <mathjax>#MW_(NH_3) = 14.007 + 3(1.008) = 17.031 g//mol#</mathjax><br/> :. <mathjax>#eta = 1.7g//17.031 g//mol = 0.100 mol#</mathjax></p> <p>The yield is 98%, then the number of moles that would be produced are:</p> <p><mathjax>#0.100mol//0.98 = 0.102 mol#</mathjax> of <mathjax>#NH_3#</mathjax></p> <p>From the reaction (the hydrogen was implicit in the problem, because you are obtaining <mathjax>#NH_3#</mathjax>):</p> <p><mathjax>#N2 + 3H2 rarr 2NH3#</mathjax> </p> <p>There are 2 parts of <mathjax>#NH_3#</mathjax> that are obtained from 1 part of <mathjax>#N_2#</mathjax></p> <p>Then the moles of <mathjax>#N_2#</mathjax> required are going to be the half of the <mathjax>#NH_3#</mathjax> moles produced.</p> <p><mathjax>#N_2#</mathjax> moles = <mathjax>#NH_3 "moles"//2 = 0.102mol//2 = 0.051 mol#</mathjax> </p> <p>Last step is too convert the moles back to grams using the MW of <mathjax>#N_2 #</mathjax></p> <p><mathjax>#m_(N_2) = mol xx MW = 0.051mol xx (14.007g//molxx2) = 1.429 g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/430233" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-atmospheric-pressure-affect-evaporation"> How does atmospheric pressure affect evaporation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-atmospheric-pressure-at-an-altitude"> How do you calculate atmospheric pressure at an altitude? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-air-pressure-greatest-at-the-earth-s-surface"> Why is air pressure greatest at the Earth's surface? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-causes-hydrostatic-pressure-in-blood-vessels"> What causes hydrostatic pressure in blood vessels? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-hydrostatic-pressure-created"> How is hydrostatic pressure created? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-atmospheric-pressure-change-in-the-troposphere"> How does atmospheric pressure change in the troposphere? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/does-air-pressure-change-with-humidity"> Does air pressure change with humidity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-atmospheric-pressure-affect-boiling-points"> How does atmospheric pressure affect boiling points? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-air-pressure-is-measured-for-weather-information"> How is air pressure measured for weather information? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-air-pressure-regulators-work"> How do air pressure regulators work? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/atmospheric-pressure"> See all questions in Atmospheric Pressure </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3387 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A yield of #NH_3# of approximately 98% can be obtained at 200 deg C and 1,000 atmospheres of pressure. How many grams of #N_2# must react to form 1.7 grams of ammonia, #NH_3#?

ab68e722-6ddd-11ea-a4fd-ccda262736ce

https://socratic.org/questions/what-s-the-formula-for-potassium-sulfate

K2SO4

start chemical_formula qc_end substance 4 5 qc_end end

[{"type":"other","value":"Chemical Formula [OF] potassium sulfate [IN] default"}]

[{"type":"chemical equation","value":"K2SO4"}]

[{"type":"substance name","value":"Potassium sulfate"}]

<h1 class="questionTitle" itemprop="name">What's the formula for potassium sulfate?</h1>

K2SO4

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Potassium: <mathjax>#"K"^+#</mathjax></p> <p>Sulfate: <mathjax>#"SO"_4^(2-)#</mathjax></p> <p>We can't just combine them as it is, since potassium and sulfate have different charges. We need to <strong>equalize charges</strong> by criss-crossing the charges, like this example:<br/> <img alt="enter image source here" src="https://useruploads.socratic.org/kKQta1BiRGIOQiKLvTRb_DWFFFpoyRzSkxEYlZWBF.jpg"/></p> <p>Following this image, we know that since potassium has just <strong>1 positive charge</strong> , then there is just <strong>1 molecule of sulfate</strong>.</p> <p>Also, sulfate has a <strong>negative 2 charge</strong>, so there will be <strong>2 atoms of potassium</strong>.</p> <p>This can be written out as:<br/> <mathjax>#"K"_2"SO"_4#</mathjax></p> <p>Hope this helps!</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"K"_2"SO"_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Potassium: <mathjax>#"K"^+#</mathjax></p> <p>Sulfate: <mathjax>#"SO"_4^(2-)#</mathjax></p> <p>We can't just combine them as it is, since potassium and sulfate have different charges. We need to <strong>equalize charges</strong> by criss-crossing the charges, like this example:<br/> <img alt="enter image source here" src="https://useruploads.socratic.org/kKQta1BiRGIOQiKLvTRb_DWFFFpoyRzSkxEYlZWBF.jpg"/></p> <p>Following this image, we know that since potassium has just <strong>1 positive charge</strong> , then there is just <strong>1 molecule of sulfate</strong>.</p> <p>Also, sulfate has a <strong>negative 2 charge</strong>, so there will be <strong>2 atoms of potassium</strong>.</p> <p>This can be written out as:<br/> <mathjax>#"K"_2"SO"_4#</mathjax></p> <p>Hope this helps!</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What's the formula for potassium sulfate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="625795" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/shanyting"><img alt="" class="" src="https://profilepictures.socratic.org/d3RS0THSX2bSQSAnEMv6_cats-animals-kittens-background.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/shanyting"> Shantelle </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-05T17:13:04" itemprop="dateCreated"> Jun 5, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"K"_2"SO"_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Potassium: <mathjax>#"K"^+#</mathjax></p> <p>Sulfate: <mathjax>#"SO"_4^(2-)#</mathjax></p> <p>We can't just combine them as it is, since potassium and sulfate have different charges. We need to <strong>equalize charges</strong> by criss-crossing the charges, like this example:<br/> <img alt="enter image source here" src="https://useruploads.socratic.org/kKQta1BiRGIOQiKLvTRb_DWFFFpoyRzSkxEYlZWBF.jpg"/></p> <p>Following this image, we know that since potassium has just <strong>1 positive charge</strong> , then there is just <strong>1 molecule of sulfate</strong>.</p> <p>Also, sulfate has a <strong>negative 2 charge</strong>, so there will be <strong>2 atoms of potassium</strong>.</p> <p>This can be written out as:<br/> <mathjax>#"K"_2"SO"_4#</mathjax></p> <p>Hope this helps!</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/625795" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-chloride"> What is the ionic formula for calcium chloride? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-oxide"> What is the ionic formula for calcium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-lithium-oxide"> What is the ionic formula for lithium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-formula-for-ionic-compounds"> How do you write the formula for ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-correctly-write-the-ions-present-in-sn-no3-2"> How do I write #Sn(NO_3)_2# in Ionic formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-an-ionic-compound"> What is the empirical formula for an ionic compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-for-chorate"> What is the molecular formula for chorate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5363023c02bf343b2ee7086b"> Question #7086b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-polyatomic-ions-covalent-1"> Why are polyatomic ions covalent? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas"> See all questions in Writing Ionic Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7992 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What's the formula for potassium sulfate?

ac03b312-6ddd-11ea-bd0e-ccda262736ce

https://socratic.org/questions/how-much-heat-is-needed-to-raise-the-temperature-of-25-g-of-a-substance-by-15-c-

0.35 kJ

start physical_unit 14 14 heat_energy kj qc_end physical_unit 14 14 10 11 mass qc_end physical_unit 14 14 16 16 temperature qc_end physical_unit 14 14 22 25 specific_heat qc_end end

[{"type":"physical unit","value":"Needed heat [OF] the substance [IN] kJ"}]

[{"type":"physical unit","value":"0.35 kJ"}]

[{"type":"physical unit","value":"Mass [OF] the substance [=] \\pu{25 g}"},{"type":"physical unit","value":"Raised temperature [OF] the substance [=] \\pu{15°C}"},{"type":"physical unit","value":"Specific heat [OF] the substance [=] \\pu{0.92 J/(g * ℃)}"}]

<h1 class="questionTitle" itemprop="name">How much heat is needed to raise the temperature of 25 g of a substance by 15°C when the specific heat is .92 J/g-°C?</h1>

0.35 kJ

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the following equation:</p> <p><mathjax>#q=cmDeltat,#</mathjax></p> <p>where:</p> <p><mathjax>#q#</mathjax> is heat energy, <mathjax>#c#</mathjax> is <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a>, <mathjax>#m#</mathjax> is mass, and <mathjax>#Deltat#</mathjax> is the change in temperature. <mathjax>#Deltat=T_"final"-T_"initial"#</mathjax></p> <p><strong>Organize the data:</strong></p> <p><strong>Known</strong></p> <p><mathjax>#c=("0.92 J")/("g"*""^@"C")#</mathjax></p> <p><mathjax>#m="25 g"#</mathjax></p> <p><mathjax>#Deltat="15"^@"C"#</mathjax></p> <p><strong>Unknown</strong></p> <p><mathjax>#q#</mathjax></p> <p><strong>Solution</strong></p> <p>Plug in the known values and solve for <mathjax>#q#</mathjax>.</p> <p><mathjax>#q=("0.92 J")/(color(red)cancel(color(black)("g"))*""^@color(red)cancel(color(black)("C")))xx25color(red)cancel(color(black)("g"))xx"15"^@color(red)cancel(color(black)("C"))="350 J"#</mathjax> (rounded to two significant figures)</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>It will require <mathjax>#"350 J"#</mathjax> of heat energy to raise the temperature of the substance under the given conditions.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the following equation:</p> <p><mathjax>#q=cmDeltat,#</mathjax></p> <p>where:</p> <p><mathjax>#q#</mathjax> is heat energy, <mathjax>#c#</mathjax> is <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a>, <mathjax>#m#</mathjax> is mass, and <mathjax>#Deltat#</mathjax> is the change in temperature. <mathjax>#Deltat=T_"final"-T_"initial"#</mathjax></p> <p><strong>Organize the data:</strong></p> <p><strong>Known</strong></p> <p><mathjax>#c=("0.92 J")/("g"*""^@"C")#</mathjax></p> <p><mathjax>#m="25 g"#</mathjax></p> <p><mathjax>#Deltat="15"^@"C"#</mathjax></p> <p><strong>Unknown</strong></p> <p><mathjax>#q#</mathjax></p> <p><strong>Solution</strong></p> <p>Plug in the known values and solve for <mathjax>#q#</mathjax>.</p> <p><mathjax>#q=("0.92 J")/(color(red)cancel(color(black)("g"))*""^@color(red)cancel(color(black)("C")))xx25color(red)cancel(color(black)("g"))xx"15"^@color(red)cancel(color(black)("C"))="350 J"#</mathjax> (rounded to two significant figures)</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How much heat is needed to raise the temperature of 25 g of a substance by 15°C when the specific heat is .92 J/g-°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="576168" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-03-18T09:04:57" itemprop="dateCreated"> Mar 18, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>It will require <mathjax>#"350 J"#</mathjax> of heat energy to raise the temperature of the substance under the given conditions.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the following equation:</p> <p><mathjax>#q=cmDeltat,#</mathjax></p> <p>where:</p> <p><mathjax>#q#</mathjax> is heat energy, <mathjax>#c#</mathjax> is <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a>, <mathjax>#m#</mathjax> is mass, and <mathjax>#Deltat#</mathjax> is the change in temperature. <mathjax>#Deltat=T_"final"-T_"initial"#</mathjax></p> <p><strong>Organize the data:</strong></p> <p><strong>Known</strong></p> <p><mathjax>#c=("0.92 J")/("g"*""^@"C")#</mathjax></p> <p><mathjax>#m="25 g"#</mathjax></p> <p><mathjax>#Deltat="15"^@"C"#</mathjax></p> <p><strong>Unknown</strong></p> <p><mathjax>#q#</mathjax></p> <p><strong>Solution</strong></p> <p>Plug in the known values and solve for <mathjax>#q#</mathjax>.</p> <p><mathjax>#q=("0.92 J")/(color(red)cancel(color(black)("g"))*""^@color(red)cancel(color(black)("C")))xx25color(red)cancel(color(black)("g"))xx"15"^@color(red)cancel(color(black)("C"))="350 J"#</mathjax> (rounded to two significant figures)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/576168" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? 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How much heat is needed to raise the temperature of 25 g of a substance by 15°C when the specific heat is .92 J/g-°C?

ac595b0a-6ddd-11ea-8d41-ccda262736ce

https://socratic.org/questions/chlorine-reacts-with-hot-sodium-hydroxide-solution-a-sample-of-a-compound-formed

NaClO3

start chemical_formula qc_end physical_unit 23 24 20 21 mass qc_end physical_unit 28 29 25 26 mass qc_end physical_unit 34 35 31 32 mass qc_end end

[{"type":"other","value":"Chemical Formula [OF] the compound [IN] empirical"}]

[{"type":"chemical equation","value":"NaClO3"}]

[{"type":"physical unit","value":"Mass [OF] sodium atoms [=] \\pu{10.8 g}"},{"type":"physical unit","value":"Mass [OF] chlorine atoms [=] \\pu{16.7 g}"},{"type":"physical unit","value":"Mass [OF] oxygen atoms [=] \\pu{22.5 g}"},{"type":"substance name","value":"Chlorine"},{"type":"substance name","value":"Sodium hydroxide solution"}]

<h1 class="questionTitle" itemprop="name">Chlorine reacts with hot sodium hydroxide solution. A sample of a compound formed in the reaction was found to contain 10.8 g of sodium atoms, 16.7 g of chlorine atoms and 22.5 g of oxygen atoms. What is the empirical formula of the compound formed?</h1>

NaClO3

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of chlorine"=(16.7*g)/(35.45*g*mol^-1)=0.47*mol#</mathjax></p> <p><mathjax>#"Moles of sodium"=(10.8*g)/(22.99*g*mol^-1)=0.47*mol#</mathjax></p> <p><mathjax>#"Moles of oxygen"=(22.5*g)/(16.00*g*mol^-1)=1.41*mol#</mathjax></p> <p>We divide thru by the smallest quantity, that of sodium, to give an empirical formula.....of <mathjax>#NaClO_3#</mathjax>, i.e. <mathjax>#"sodium chlorate"#</mathjax>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#NaClO_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of chlorine"=(16.7*g)/(35.45*g*mol^-1)=0.47*mol#</mathjax></p> <p><mathjax>#"Moles of sodium"=(10.8*g)/(22.99*g*mol^-1)=0.47*mol#</mathjax></p> <p><mathjax>#"Moles of oxygen"=(22.5*g)/(16.00*g*mol^-1)=1.41*mol#</mathjax></p> <p>We divide thru by the smallest quantity, that of sodium, to give an empirical formula.....of <mathjax>#NaClO_3#</mathjax>, i.e. <mathjax>#"sodium chlorate"#</mathjax>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Chlorine reacts with hot sodium hydroxide solution. A sample of a compound formed in the reaction was found to contain 10.8 g of sodium atoms, 16.7 g of chlorine atoms and 22.5 g of oxygen atoms. What is the empirical formula of the compound formed?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="457492" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-29T06:58:15" itemprop="dateCreated"> Jul 29, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#NaClO_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of chlorine"=(16.7*g)/(35.45*g*mol^-1)=0.47*mol#</mathjax></p> <p><mathjax>#"Moles of sodium"=(10.8*g)/(22.99*g*mol^-1)=0.47*mol#</mathjax></p> <p><mathjax>#"Moles of oxygen"=(22.5*g)/(16.00*g*mol^-1)=1.41*mol#</mathjax></p> <p>We divide thru by the smallest quantity, that of sodium, to give an empirical formula.....of <mathjax>#NaClO_3#</mathjax>, i.e. <mathjax>#"sodium chlorate"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/457492" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="457773" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-30T01:56:59" itemprop="dateCreated"> Jul 30, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The empirical formula is <mathjax>#"NaClO"_3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula for a compound represents the lowest whole number ratio of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>. In order to determine the empirical formula of a compound, you must find the number of moles of each element. Once you know the moles, you divide the moles of each element by the smallest number of moles. This will give you the empirical formula, unless you do not have whole numbers. If you don't have all whole numbers, you need to multiply by a number that will result in all whole numbers.</p> <p><strong>Moles of Each Element</strong></p> <p>Divide the given mass of each element by its molar mass (atomic weight on <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a> in g/mol) by multiplying by its inverse.</p> <p><mathjax>#"Na":#</mathjax><mathjax>#10.8color(red)cancel(color(black)("g Na"))xx(1"mol Na")/(22.990color(red)cancel(color(black)("g Na")))="0.470 mol Na"#</mathjax></p> <p><mathjax>#"Cl":#</mathjax><mathjax>#16.7color(red)cancel(color(black)("g Cl"))xx(1"mol Cl")/(35.453color(red)cancel(color(black)("g Cl")))="0.471 mol Cl"#</mathjax></p> <p><mathjax>#"O":#</mathjax><mathjax>#22.5color(red)cancel(color(black)("g O"))xx(1"mol O")/(15.999color(red)cancel(color(black)("g O")))="1.41 mol O"#</mathjax></p> <p><strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">Mole Ratios</a> (Subscripts)</strong></p> <p>Divide the moles of each element by the least number of moles.</p> <p><mathjax>#"Na":#</mathjax><mathjax>#(0.470color(red)cancel(color(black)("mol")))/(0.470color(red)cancel(color(black)("mol")))=1.00#</mathjax></p> <p><mathjax>#"Cl":#</mathjax><mathjax>#(0.471color(red)cancel(color(black)("mol")))/(0.470color(red)cancel(color(black)("mol")))=1.00#</mathjax></p> <p><mathjax>#"O":#</mathjax><mathjax>#(1.41color(red)cancel(color(black)("mol")))/(0.470color(red)cancel(color(black)("mol")))=3.00#</mathjax></p> <p>Since the mole ratios are all whole numbers, you do not need to do anything else except write the formula.</p> <p>The empirical formula is <mathjax>#"NaClO"_3#</mathjax>, which is the ionic compound sodium chlorate, composed of the <mathjax>#"Na"^(2+)#</mathjax> sodium cation and the <mathjax>#"ClO"_3"^(1-)#</mathjax> chlorate anion.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/457773" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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Chlorine reacts with hot sodium hydroxide solution. A sample of a compound formed in the reaction was found to contain 10.8 g of sodium atoms, 16.7 g of chlorine atoms and 22.5 g of oxygen atoms. What is the empirical formula of the compound formed?

ac15434c-6ddd-11ea-9254-ccda262736ce

https://socratic.org/questions/given-the-reaction-n2-3h2-2nh3-what-volume-of-hydrogen-is-necessary-to-react-wit

15.00 L

start physical_unit 13 13 volume l qc_end chemical_equation 3 9 qc_end c_other ConstantTemperaturePressue qc_end end

[{"type":"physical unit","value":"Volume [OF] hydrogen [IN] L"}]

[{"type":"physical unit","value":"15.00 L"}]

[{"type":"physical unit","value":"Volume [OF] nitrogen [=] \\pu{5 L}"},{"type":"chemical equation","value":"N2 + 3 H2 -> 2 NH3"},{"type":"other","value":"ConstantTemperaturePressue"}]

<h1 class="questionTitle" itemprop="name">Given the reaction N2 + 3H2 --&gt;2NH3, what volume of hydrogen is necessary to react with five liters of nitrogen to produce ammonia, assuming constant temperature and pressure? </h1>

15.00 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Assuming complete reaction with no excess of reactants, the addition of reactants will be based on <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>.</p> <p>Assuming ideal gas behaviour, the addition of reactant by volume will be based on its stoichiometric coefficient. This means that reaction between 1 mole of reactant A with 3 mole of reactant B is the same as X L of reactant A with 3X L of reactant B. This is true because volume is proportional to number of moles in the ideal gas relation (PV=nRT)</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>15 Liters</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Assuming complete reaction with no excess of reactants, the addition of reactants will be based on <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>.</p> <p>Assuming ideal gas behaviour, the addition of reactant by volume will be based on its stoichiometric coefficient. This means that reaction between 1 mole of reactant A with 3 mole of reactant B is the same as X L of reactant A with 3X L of reactant B. This is true because volume is proportional to number of moles in the ideal gas relation (PV=nRT)</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Given the reaction N2 + 3H2 --&gt;2NH3, what volume of hydrogen is necessary to react with five liters of nitrogen to produce ammonia, assuming constant temperature and pressure? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="181474" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/xzvjcb3j-j"><img alt="" class="" src="https://lh3.googleusercontent.com/-IiZUwOaKykc/AAAAAAAAAAI/AAAAAAAAAAA/AB6qoq3YW6IJjpRnS31E-eZRpj63Pv8r8Q/mo/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/xzvjcb3j-j"> le experz </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-31T06:43:49" itemprop="dateCreated"> Oct 31, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>15 Liters</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Assuming complete reaction with no excess of reactants, the addition of reactants will be based on <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>.</p> <p>Assuming ideal gas behaviour, the addition of reactant by volume will be based on its stoichiometric coefficient. This means that reaction between 1 mole of reactant A with 3 mole of reactant B is the same as X L of reactant A with 3X L of reactant B. This is true because volume is proportional to number of moles in the ideal gas relation (PV=nRT)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/181474" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-apply-gas-stoichiometry"> How do you apply gas stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-a-gas-law-stoichiometry-problem"> How do you solve a gas law stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-gas-stoichiometry-problems-at-stp"> How do you do gas stoichiometry problems at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-an-agno3-solution-is-treated-with-50-0-ml-of-hi-gas-to-give-0-235-g-of-agi-"> When an AgNO3 solution is treated with 50.0 mL of HI gas to give 0.235 g of AgI, what is the... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-10-0-ml-of-agno3-solution-is-treated-with-excess-amount-of-hi-gas-to-give-0"> When 10.0 mL of AgNO3 solution is treated with excess amount of HI gas to give 0.235 g of AgI,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/hydrogen-sulfide-reacts-with-sulfur-dioxide-to-give-h2o-and-s-h2s-so2-h2o-s-soli"> Hydrogen sulfide reacts with sulfur dioxide to give H2O and S, H2S + SO2 = H2O + S(solid),... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-200-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 200 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolved-in-pure-water-requires-12-50"> If 100 mL of HCl gas at 300 K and 100 kPa dissolved in pure water requires 12.50 mL of the NaOH... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-100-ml-of-hcl-gas-at-300-k-and-100-kpa-dissolve-in-20-ml-of-pure-water-what-i"> If 100 mL of HCl gas at 300 K and 100 kPa dissolve in 20 mL of pure water, what is the concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-2-00-g-mixture-of-na-and-ca-reat-with-water-1-164-l-hydrogen-was-produced-a"> When 2.00 g mixture of Na and Ca reat with water, 1.164 L hydrogen was produced at 300.0 K and... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases"> See all questions in Gas Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6412 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

Given the reaction N2 + 3H2 --&gt;2NH3, what volume of hydrogen is necessary to react with five liters of nitrogen to produce ammonia, assuming constant temperature and pressure?

abd6b703-6ddd-11ea-8cf6-ccda262736ce

https://socratic.org/questions/given-the-reaction-2al-3cl-2-2alcl-3-how-many-grams-of-al-are-needed-to-produce-

18.31 grams

start physical_unit 4 4 mass g qc_end chemical_equation 3 10 qc_end physical_unit 10 10 20 21 mass qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Mass [OF] Al [IN] grams"}]

[{"type":"physical unit","value":"18.31 grams"}]

[{"type":"chemical equation","value":"2 Al + 3 Cl2 -> 2 AlCl3"},{"type":"physical unit","value":"Mass [OF] AlCl3 [=] \\pu{90.50 grams}"},{"type":"other","value":"Unlimited supply of Cl2."}]

<h1 class="questionTitle" itemprop="name">Given the reaction #2Al + 3Cl_2 -&gt; 2AlCl_3#, how many grams of #Al# are needed to produce 90.50 grams of #AlCl_3#, if we have an unlimited supply of #Cl_2#?</h1>

18.31 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"2Al + 3Cl"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"2AlCl"_3"#</mathjax></p> <p>This is a stoichiometry problem converting grams of <mathjax>#"AlCl"_3"#</mathjax> to grams of <mathjax>#"Al"#</mathjax>.</p> <p><mathjax>#"grams AlCl"_3#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"moles AlCl"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"moles Al"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"grams Al"#</mathjax></p> <p><mathjax>#"grams of given" xx (1"mol given")/("molar mass of given")xx("mol of want")/("mol of given")xx("molar mass of want")/(1"mol of want")#</mathjax></p> <p><mathjax>#"Molar mass Al=26.9815385 g/mol"#</mathjax> (periodic table)<br/> <mathjax>#"Molar mass AlCl"_3"=133.340539 g/mol"#</mathjax><br/> <a href="https://pubchem.ncbi.nlm.nih.gov/compound/24012#section=Top" rel="nofollow" target="_blank">https://pubchem.ncbi.nlm.nih.gov/compound/24012#section=Top</a></p> <p><mathjax>#"90.50 g AlCl"_3xx(1"mol AlCl"_3)/(133.340539"g AlCl"_3)xx(2"mol Al")/(2"mol AlCl"_3)xx(26.9815385"g Al")/(1"mol Al")="18.31 grams of Al"#</mathjax> rounded to four significant figures</p> <p> <iframe src="https://www.youtube.com/embed/qa9G9yhG61M?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>18.31 grams of Al are necessary to produce 90.50 grams of <mathjax>#"AlCl"_3"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"2Al + 3Cl"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"2AlCl"_3"#</mathjax></p> <p>This is a stoichiometry problem converting grams of <mathjax>#"AlCl"_3"#</mathjax> to grams of <mathjax>#"Al"#</mathjax>.</p> <p><mathjax>#"grams AlCl"_3#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"moles AlCl"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"moles Al"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"grams Al"#</mathjax></p> <p><mathjax>#"grams of given" xx (1"mol given")/("molar mass of given")xx("mol of want")/("mol of given")xx("molar mass of want")/(1"mol of want")#</mathjax></p> <p><mathjax>#"Molar mass Al=26.9815385 g/mol"#</mathjax> (periodic table)<br/> <mathjax>#"Molar mass AlCl"_3"=133.340539 g/mol"#</mathjax><br/> <a href="https://pubchem.ncbi.nlm.nih.gov/compound/24012#section=Top" rel="nofollow" target="_blank">https://pubchem.ncbi.nlm.nih.gov/compound/24012#section=Top</a></p> <p><mathjax>#"90.50 g AlCl"_3xx(1"mol AlCl"_3)/(133.340539"g AlCl"_3)xx(2"mol Al")/(2"mol AlCl"_3)xx(26.9815385"g Al")/(1"mol Al")="18.31 grams of Al"#</mathjax> rounded to four significant figures</p> <p> <iframe src="https://www.youtube.com/embed/qa9G9yhG61M?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Given the reaction #2Al + 3Cl_2 -&gt; 2AlCl_3#, how many grams of #Al# are needed to produce 90.50 grams of #AlCl_3#, if we have an unlimited supply of #Cl_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="234726" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/brian-m"><img alt="" class="" src="https://profilepictures.socratic.org/ZCpnJDgSFKORtvaSPDeG_Lego%20Me.png" title=""/></a> <a class="secondContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/brian-m"> BRIAN M. </a>·<a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-04T02:55:33" itemprop="dateCreated"> Mar 4, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>18.31 grams of Al are necessary to produce 90.50 grams of <mathjax>#"AlCl"_3"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"2Al + 3Cl"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"2AlCl"_3"#</mathjax></p> <p>This is a stoichiometry problem converting grams of <mathjax>#"AlCl"_3"#</mathjax> to grams of <mathjax>#"Al"#</mathjax>.</p> <p><mathjax>#"grams AlCl"_3#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"moles AlCl"_3"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"moles Al"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"grams Al"#</mathjax></p> <p><mathjax>#"grams of given" xx (1"mol given")/("molar mass of given")xx("mol of want")/("mol of given")xx("molar mass of want")/(1"mol of want")#</mathjax></p> <p><mathjax>#"Molar mass Al=26.9815385 g/mol"#</mathjax> (periodic table)<br/> <mathjax>#"Molar mass AlCl"_3"=133.340539 g/mol"#</mathjax><br/> <a href="https://pubchem.ncbi.nlm.nih.gov/compound/24012#section=Top" rel="nofollow" target="_blank">https://pubchem.ncbi.nlm.nih.gov/compound/24012#section=Top</a></p> <p><mathjax>#"90.50 g AlCl"_3xx(1"mol AlCl"_3)/(133.340539"g AlCl"_3)xx(2"mol Al")/(2"mol AlCl"_3)xx(26.9815385"g Al")/(1"mol Al")="18.31 grams of Al"#</mathjax> rounded to four significant figures</p> <p> <iframe src="https://www.youtube.com/embed/qa9G9yhG61M?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/234726" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? 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Given the reaction #2Al + 3Cl_2 -&gt; 2AlCl_3#, how many grams of #Al# are needed to produce 90.50 grams of #AlCl_3#, if we have an unlimited supply of #Cl_2#?

a9b151d4-6ddd-11ea-b21a-ccda262736ce

https://socratic.org/questions/when-iron-rusts-in-air-iron-ill-oxide-is-produced-how-many-moles-of-oxygen-react

4.8 moles

start physical_unit 14 14 mole mol qc_end physical_unit 1 1 17 18 mole qc_end substance 5 7 qc_end end

[{"type":"physical unit","value":"Mole [OF] oxygen [IN] moles"}]

[{"type":"physical unit","value":"4.8 moles"}]

[{"type":"physical unit","value":"Mole [OF] iron [=] \\pu{6.4 mol}"},{"type":"substance name","value":"Iron (Ill) oxide"}]

<h1 class="questionTitle" itemprop="name">When iron rusts in air, iron (Ill) oxide is produced. How many moles of oxygen react with 6.4 mol of iron in the rusting reaction?</h1>

4.8 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Balanced equation</p> <p><mathjax>#"4Fe(s) + 3O"_2("g")"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"2Fe"_2"O"_3("s")"#</mathjax></p> <p>Multiply the given moles of iron by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between oxygen and iron from the balanced equation, with moles oxygen in the numerator.</p> <p><mathjax>#6.4color(red)cancel(color(black)("mol Fe"))xx(3"mol O"_2)/(4color(red)cancel(color(black)("mol Fe")))="4.8 mol O"_2"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"4.8 mol O"_2"#</mathjax> react with <mathjax>#"6.4 mol Fe"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Balanced equation</p> <p><mathjax>#"4Fe(s) + 3O"_2("g")"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"2Fe"_2"O"_3("s")"#</mathjax></p> <p>Multiply the given moles of iron by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between oxygen and iron from the balanced equation, with moles oxygen in the numerator.</p> <p><mathjax>#6.4color(red)cancel(color(black)("mol Fe"))xx(3"mol O"_2)/(4color(red)cancel(color(black)("mol Fe")))="4.8 mol O"_2"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">When iron rusts in air, iron (Ill) oxide is produced. How many moles of oxygen react with 6.4 mol of iron in the rusting reaction?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="631106" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-16T23:49:14" itemprop="dateCreated"> Jun 16, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"4.8 mol O"_2"#</mathjax> react with <mathjax>#"6.4 mol Fe"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Balanced equation</p> <p><mathjax>#"4Fe(s) + 3O"_2("g")"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"2Fe"_2"O"_3("s")"#</mathjax></p> <p>Multiply the given moles of iron by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between oxygen and iron from the balanced equation, with moles oxygen in the numerator.</p> <p><mathjax>#6.4color(red)cancel(color(black)("mol Fe"))xx(3"mol O"_2)/(4color(red)cancel(color(black)("mol Fe")))="4.8 mol O"_2"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/631106" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? 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When iron rusts in air, iron (Ill) oxide is produced. How many moles of oxygen react with 6.4 mol of iron in the rusting reaction?

a96cc2d2-6ddd-11ea-892e-ccda262736ce

https://socratic.org/questions/how-much-heat-is-released-when-275-g-of-water-cools-from-85-2-c-to-38-4-c

53796.6 J

start physical_unit 9 9 heat_energy j qc_end physical_unit 9 9 6 7 mass qc_end physical_unit 9 9 12 13 temperature qc_end physical_unit 9 9 15 16 temperature qc_end end

[{"type":"physical unit","value":"Released heat [OF] water [IN] J"}]

[{"type":"physical unit","value":"53796.6 J"}]

[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{275 g}"},{"type":"physical unit","value":"Temperature1 [OF] water [=] \\pu{85.2 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] water [=] \\pu{38.4 ℃}"}]

<h1 class="questionTitle" itemprop="name">How much heat is released when 275 g of water cools from 85.2°C to 38.4 °C?</h1>

53796.6 J

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The equation for heat is <br/> <mathjax>#Q = m(t_f -t_i)C_p#</mathjax></p> <p>Q = heat in Joules<br/> m = mass in grams<br/> <mathjax>#t_f#</mathjax> = final temp<br/> <mathjax>#t_i#</mathjax> = initial temp<br/> <mathjax>#C_p#</mathjax> = <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">Specific Heat</a> Capacity</p> <p>For this problem<br/> <mathjax>#Q = ???#</mathjax><br/> <mathjax>#m = 275 g#</mathjax><br/> <mathjax>#t_f = 38.4^oC#</mathjax><br/> <mathjax>#t_i = 85.2^oC#</mathjax><br/> <mathjax>#C_p = 4.18 j/(g^oC)#</mathjax></p> <p><mathjax>#Q = 275g(38.4^oC -85.2^oC)4.18J/(g^oC)#</mathjax><br/> <mathjax>#Q = 275cancel(g)( -46.8^ocancelC))4.18J/(cancel(g^oC))#</mathjax></p> <p><mathjax>#Q = -53,796.6 J#</mathjax> </p> <p>The negative Joule value means heat is being lost in an exothermic reaction.</p> <p> <iframe src="https://www.youtube.com/embed/n41G-TGkc-4?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Q = -53,796.6 J#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The equation for heat is <br/> <mathjax>#Q = m(t_f -t_i)C_p#</mathjax></p> <p>Q = heat in Joules<br/> m = mass in grams<br/> <mathjax>#t_f#</mathjax> = final temp<br/> <mathjax>#t_i#</mathjax> = initial temp<br/> <mathjax>#C_p#</mathjax> = <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">Specific Heat</a> Capacity</p> <p>For this problem<br/> <mathjax>#Q = ???#</mathjax><br/> <mathjax>#m = 275 g#</mathjax><br/> <mathjax>#t_f = 38.4^oC#</mathjax><br/> <mathjax>#t_i = 85.2^oC#</mathjax><br/> <mathjax>#C_p = 4.18 j/(g^oC)#</mathjax></p> <p><mathjax>#Q = 275g(38.4^oC -85.2^oC)4.18J/(g^oC)#</mathjax><br/> <mathjax>#Q = 275cancel(g)( -46.8^ocancelC))4.18J/(cancel(g^oC))#</mathjax></p> <p><mathjax>#Q = -53,796.6 J#</mathjax> </p> <p>The negative Joule value means heat is being lost in an exothermic reaction.</p> <p> <iframe src="https://www.youtube.com/embed/n41G-TGkc-4?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How much heat is released when 275 g of water cools from 85.2°C to 38.4 °C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="240112" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/brian-m"><img alt="" class="" src="https://profilepictures.socratic.org/ZCpnJDgSFKORtvaSPDeG_Lego%20Me.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/brian-m"> BRIAN M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-15T18:02:37" itemprop="dateCreated"> Mar 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Q = -53,796.6 J#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The equation for heat is <br/> <mathjax>#Q = m(t_f -t_i)C_p#</mathjax></p> <p>Q = heat in Joules<br/> m = mass in grams<br/> <mathjax>#t_f#</mathjax> = final temp<br/> <mathjax>#t_i#</mathjax> = initial temp<br/> <mathjax>#C_p#</mathjax> = <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">Specific Heat</a> Capacity</p> <p>For this problem<br/> <mathjax>#Q = ???#</mathjax><br/> <mathjax>#m = 275 g#</mathjax><br/> <mathjax>#t_f = 38.4^oC#</mathjax><br/> <mathjax>#t_i = 85.2^oC#</mathjax><br/> <mathjax>#C_p = 4.18 j/(g^oC)#</mathjax></p> <p><mathjax>#Q = 275g(38.4^oC -85.2^oC)4.18J/(g^oC)#</mathjax><br/> <mathjax>#Q = 275cancel(g)( -46.8^ocancelC))4.18J/(cancel(g^oC))#</mathjax></p> <p><mathjax>#Q = -53,796.6 J#</mathjax> </p> <p>The negative Joule value means heat is being lost in an exothermic reaction.</p> <p> <iframe src="https://www.youtube.com/embed/n41G-TGkc-4?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/240112" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? 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How much heat is released when 275 g of water cools from 85.2°C to 38.4 °C?

acad7108-6ddd-11ea-9a52-ccda262736ce

https://socratic.org/questions/5980fa2511ef6b3a47d12c2a

17.08%

start physical_unit 8 11 mass_percent none qc_end substance 10 11 qc_end substance 8 8 qc_end end

[{"type":"physical unit","value":"Percentage composition by mass [OF] nitrogen in calcium nitrate"}]

[{"type":"physical unit","value":"17.08%"}]

[{"type":"substance name","value":"Calcium nitrate"},{"type":"substance name","value":"Nitrogen"}]

<h1 class="questionTitle" itemprop="name">What is the percentage composition by mass of nitrogen in calcium nitrate?</h1>

17.08%

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So we gots <mathjax>#Ca(NO_3)_2#</mathjax>, whose formula mass <mathjax>#=164.09*g*mol^-1#</mathjax></p> <p><mathjax>#%N=(2xx14.01*g*mol^-1)/(164.09*g*mol^-1)~=20%#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#%N="Mass of nitrogen in one mole of salt"/"Mass of one mole of calcium nitrate"xx100%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So we gots <mathjax>#Ca(NO_3)_2#</mathjax>, whose formula mass <mathjax>#=164.09*g*mol^-1#</mathjax></p> <p><mathjax>#%N=(2xx14.01*g*mol^-1)/(164.09*g*mol^-1)~=20%#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the percentage composition by mass of nitrogen in calcium nitrate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/percent-composition" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Composition</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="511330" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-11-26T04:10:58" itemprop="dateCreated"> Nov 26, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#%N="Mass of nitrogen in one mole of salt"/"Mass of one mole of calcium nitrate"xx100%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So we gots <mathjax>#Ca(NO_3)_2#</mathjax>, whose formula mass <mathjax>#=164.09*g*mol^-1#</mathjax></p> <p><mathjax>#%N=(2xx14.01*g*mol^-1)/(164.09*g*mol^-1)~=20%#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/511330" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-mole-percent"> What is mole percent? 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What is the percentage composition by mass of nitrogen in calcium nitrate?

acaccc64-6ddd-11ea-9d57-ccda262736ce

https://socratic.org/questions/how-many-liters-of-carbon-dioxide-can-be-produced-if-37-8-grams-of-carbon-disulf

12.06 liters

start physical_unit 4 5 volume l qc_end physical_unit 13 14 10 11 mass qc_end physical_unit 13 14 21 23 temperature qc_end physical_unit 13 14 25 26 pressure qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Volume [OF] carbon dioxide [IN] liters"}]

[{"type":"physical unit","value":"12.06 liters"}]

[{"type":"physical unit","value":"Mass [OF] carbon disulfide [=] \\pu{37.8 grams}"},{"type":"physical unit","value":"Temperature [OF] carbon disulfide [=] \\pu{28.85 degrees Celsius }"},{"type":"physical unit","value":"Pressure [OF] carbon disulfide [=] \\pu{1.02 atmospheres}"},{"type":"other","value":"Excess oxygen gas."}]

<h1 class="questionTitle" itemprop="name">How many liters of carbon dioxide can be produced if 37.8 grams of carbon disulfide react with excess oxygen gas at 28.85 degrees Celsius and 1.02 atmospheres? </h1>

12.06 liters

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Carbon disulfide reacts with oxygen to form carbon dioxide and sulfur dioxide.</p> <p><mathjax>#CS_2 + O_2 -&gt; CO_2 + SO_2#</mathjax></p> <p>Start by finding the number of moles of the carbon dioxide produced.</p> <p><mathjax>#37.8 \ "g" \ CS_2 xx ( 1\ "mol."\ CS_2)/(76.1407 \ "g" \ CS_2)xx ("1 mol."\ CO_2)/( 1 \ "mol."\ CS_2)#</mathjax></p> <p><mathjax>#37.8 \cancel ( "g" \ CS_2) xx ( color(red) cancel( 1\ "mol."\ CS_2))/(76.1407 \cancel( "g" \ CS_2))xx ("1 mol."\ CO_2)/(color (red) cancel( 1\ "mol."\ CS_2))#</mathjax></p> <p><mathjax>#0.496 \ mol. \ CO_2#</mathjax></p> <p>Now use the ideal gas equation to figure out the the volume of the <mathjax>#CO_2#</mathjax> produced.</p> <p><mathjax># P*V= n*R*T#</mathjax></p> <p>Where</p> <p><mathjax>#P" "#</mathjax> is the pressure expressed in atm.</p> <p><mathjax>#V" "#</mathjax> is the volume expressed in L.</p> <p><mathjax>#n" " #</mathjax> is the number of moles.</p> <p><mathjax>#R" "#</mathjax> is the universal gas constant, it has a value of <mathjax>#0.0821\ L* atm. mol^-1*K^-1#</mathjax></p> <p><mathjax>#T" " #</mathjax>is the Kelvin temperature.</p> <p>Now rearrange the ideal gas equation and solve for V.</p> <p><mathjax># V= (n*R*T)/P#</mathjax></p> <p><mathjax># V= (0.496\ molxx0.0821\ L*atm*mol^-1*K^-1 xx 302.00 \ K)/ (1.02\ atm)#</mathjax></p> <p><mathjax>#V= (0.496\cancel( mol)xx0.0821\ L*cancel(atm)*cancel(mol^-1)*cancel(K^-1)xx 302.00 \cancel(K))/ (1.02\ cancel(atm))#</mathjax></p> <p><mathjax>#V= 12.1 \ L#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#12.1 \ L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Carbon disulfide reacts with oxygen to form carbon dioxide and sulfur dioxide.</p> <p><mathjax>#CS_2 + O_2 -&gt; CO_2 + SO_2#</mathjax></p> <p>Start by finding the number of moles of the carbon dioxide produced.</p> <p><mathjax>#37.8 \ "g" \ CS_2 xx ( 1\ "mol."\ CS_2)/(76.1407 \ "g" \ CS_2)xx ("1 mol."\ CO_2)/( 1 \ "mol."\ CS_2)#</mathjax></p> <p><mathjax>#37.8 \cancel ( "g" \ CS_2) xx ( color(red) cancel( 1\ "mol."\ CS_2))/(76.1407 \cancel( "g" \ CS_2))xx ("1 mol."\ CO_2)/(color (red) cancel( 1\ "mol."\ CS_2))#</mathjax></p> <p><mathjax>#0.496 \ mol. \ CO_2#</mathjax></p> <p>Now use the ideal gas equation to figure out the the volume of the <mathjax>#CO_2#</mathjax> produced.</p> <p><mathjax># P*V= n*R*T#</mathjax></p> <p>Where</p> <p><mathjax>#P" "#</mathjax> is the pressure expressed in atm.</p> <p><mathjax>#V" "#</mathjax> is the volume expressed in L.</p> <p><mathjax>#n" " #</mathjax> is the number of moles.</p> <p><mathjax>#R" "#</mathjax> is the universal gas constant, it has a value of <mathjax>#0.0821\ L* atm. mol^-1*K^-1#</mathjax></p> <p><mathjax>#T" " #</mathjax>is the Kelvin temperature.</p> <p>Now rearrange the ideal gas equation and solve for V.</p> <p><mathjax># V= (n*R*T)/P#</mathjax></p> <p><mathjax># V= (0.496\ molxx0.0821\ L*atm*mol^-1*K^-1 xx 302.00 \ K)/ (1.02\ atm)#</mathjax></p> <p><mathjax>#V= (0.496\cancel( mol)xx0.0821\ L*cancel(atm)*cancel(mol^-1)*cancel(K^-1)xx 302.00 \cancel(K))/ (1.02\ cancel(atm))#</mathjax></p> <p><mathjax>#V= 12.1 \ L#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many liters of carbon dioxide can be produced if 37.8 grams of carbon disulfide react with excess oxygen gas at 28.85 degrees Celsius and 1.02 atmospheres? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/stoichiometry-involving-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="285329" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/sam-54"><img alt="" class="" src="https://profilepictures.socratic.org/3bkyAGe2RVWw1lx2h1A5_Avatar%201.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/sam-54"> Sam </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-06T12:21:10" itemprop="dateCreated"> Jul 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#12.1 \ L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Carbon disulfide reacts with oxygen to form carbon dioxide and sulfur dioxide.</p> <p><mathjax>#CS_2 + O_2 -&gt; CO_2 + SO_2#</mathjax></p> <p>Start by finding the number of moles of the carbon dioxide produced.</p> <p><mathjax>#37.8 \ "g" \ CS_2 xx ( 1\ "mol."\ CS_2)/(76.1407 \ "g" \ CS_2)xx ("1 mol."\ CO_2)/( 1 \ "mol."\ CS_2)#</mathjax></p> <p><mathjax>#37.8 \cancel ( "g" \ CS_2) xx ( color(red) cancel( 1\ "mol."\ CS_2))/(76.1407 \cancel( "g" \ CS_2))xx ("1 mol."\ CO_2)/(color (red) cancel( 1\ "mol."\ CS_2))#</mathjax></p> <p><mathjax>#0.496 \ mol. \ CO_2#</mathjax></p> <p>Now use the ideal gas equation to figure out the the volume of the <mathjax>#CO_2#</mathjax> produced.</p> <p><mathjax># P*V= n*R*T#</mathjax></p> <p>Where</p> <p><mathjax>#P" "#</mathjax> is the pressure expressed in atm.</p> <p><mathjax>#V" "#</mathjax> is the volume expressed in L.</p> <p><mathjax>#n" " #</mathjax> is the number of moles.</p> <p><mathjax>#R" "#</mathjax> is the universal gas constant, it has a value of <mathjax>#0.0821\ L* atm. mol^-1*K^-1#</mathjax></p> <p><mathjax>#T" " #</mathjax>is the Kelvin temperature.</p> <p>Now rearrange the ideal gas equation and solve for V.</p> <p><mathjax># V= (n*R*T)/P#</mathjax></p> <p><mathjax># V= (0.496\ molxx0.0821\ L*atm*mol^-1*K^-1 xx 302.00 \ K)/ (1.02\ atm)#</mathjax></p> <p><mathjax>#V= (0.496\cancel( mol)xx0.0821\ L*cancel(atm)*cancel(mol^-1)*cancel(K^-1)xx 302.00 \cancel(K))/ (1.02\ cancel(atm))#</mathjax></p> <p><mathjax>#V= 12.1 \ L#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/285329" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-apply-gas-stoichiometry"> How do you apply gas stoichiometry? 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How many liters of carbon dioxide can be produced if 37.8 grams of carbon disulfide react with excess oxygen gas at 28.85 degrees Celsius and 1.02 atmospheres?

a9a22bd5-6ddd-11ea-bd02-ccda262736ce

https://socratic.org/questions/how-do-you-balance-co-g-i-2o-5-s-i-2-s-co-2

5 CO(g) + I2O5(s) -> I2(s) + 5 CO2(g)

start chemical_equation qc_end chemical_equation 4 10 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"5 CO(g) + I2O5(s) -> I2(s) + 5 CO2(g)"}]

[{"type":"chemical equation","value":"CO(g) + I2O5(s) -> I2(s) + CO2(g)"}]

<h1 class="questionTitle" itemprop="name">How do you balance #CO(g) + I_2O_5(s) -&gt; I_2(s) + CO_2(g)#?</h1>

5 CO(g) + I2O5(s) -> I2(s) + 5 CO2(g)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're actually dealing with a <strong><a href="http://socratic.org/chemistry/chemical-reactions/redox-reactions">redox reaction</a></strong> used to convert carbon monoxide, <mathjax>#"CO"#</mathjax>, to carbon dioxide, <mathjax>#"CO"_2#</mathjax>, by using what is known as the <strong>Schutze reagent</strong>, which is iodine pentoxide, <mathjax>#"I"_2"O"_5#</mathjax>, on silica gel. </p> <p>Iodine pentoxide acts as an <strong>oxidizing agent</strong> here and oxidizes carbon monoxide to carbon dioxide while being reduced to iodine in the process. </p> <p>Assign <strong><a href="http://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a></strong> to the atoms that take part in the reaction - for the sake of simplicity, I will not add the states of the chemical species involved in the reaction</p> <blockquote> <p><mathjax>#stackrel(color(blue)(+2))("C") stackrel(color(blue)(-2))("O") + stackrel(color(blue)(+5))("I")_2 stackrel(color(blue)(-2))("O")_5 -&gt; stackrel(color(blue)(0))("I")_2 + stackrel(color(blue)(+4))("C")stackrel(color(blue)(-2))("O")_2#</mathjax></p> </blockquote> <p>You can balance this equation by <strong>assuming</strong> that the reaction takes place in <em>acidic conditions</em> (you will get the same result if you assume basic conditions). </p> <p>So, carbon's oxidation state goes from <mathjax>#color(blue)(+2)#</mathjax> on the reactants' side, to <mathjax>#color(blue)(+4)#</mathjax> on the products' side, which of course means that it's being <strong>oxidized</strong>. </p> <p>The <em>oxidation half-equation</em> will look like this </p> <blockquote> <p><mathjax>#stackrel(color(blue)(+2))("C")"O" -&gt; stackrel(color(blue)(+4))("C")"O"_2 + 2"e"^(-)#</mathjax></p> </blockquote> <p>Here each carbon atoms loses <strong>two electrons</strong>. Balance the oxygen atoms by adding water molecules to the side that needs oxygen, and the hydrogen atoms by adding protons, <mathjax>#"H"^(+)#</mathjax>, to the side that needs hydrogen. </p> <blockquote> <p><mathjax>#"H"_2"O" + stackrel(color(blue)(+2))("C")"O" -&gt; stackrel(color(blue)(+4))("C")"O"_2 + 2"e"^(-) + 2"H"^(+)#</mathjax></p> </blockquote> <p>The oxidation state of iodine goes from <mathjax>#color(blue)(+5)#</mathjax> on the reactant's side, to <mathjax>#color(blue)(0)#</mathjax> on the products' side, which means that it's being <strong>reduced</strong>. </p> <p>The <em>reduction half-reaction</em> will be </p> <blockquote> <p><mathjax>#stackrel(color(blue)(+5))("I")_2"O"_5 + 10"e"^(-) -&gt; stackrel(color(blue)(0))"I"_2#</mathjax></p> </blockquote> <p>Here each iodine atom gains <strong>five electrons</strong>, so two atoms will gain a total of <strong>ten electrons</strong>. Once again, balance the oxygen and hydrogen to get</p> <blockquote> <p><mathjax>#10 "H"^(+) + stackrel(color(blue)(+5))("I")_2"O"_5 + 10"e"^(-) -&gt; stackrel(color(blue)(0))"I"_2 + 5"H"_2"O"#</mathjax></p> </blockquote> <p>As you know, in any redox reaction, the number of electrons <strong>lost</strong> in the oxidation half-equation <strong>must be equal to</strong> the number of electrons <strong>gained</strong> in the reduction half-equation. </p> <p>In order to get these two balanced, multiply the oxidation half-equation by <mathjax>#5#</mathjax>. Add the two half-equations to get</p> <blockquote> <p><mathjax>#{ ("H"_2"O" + stackrel(color(blue)(+2))("C")"O" -&gt; stackrel(color(blue)(+4))("C")"O"_2 + 2"e"^(-) + 2"H"^(+) | xx 5), (10 "H"^(+) + stackrel(color(blue)(+5))("I")_2"O"_5 + 10"e"^(-) -&gt; stackrel(color(blue)(0))"I"_2 + 5"H"_2"O") :}#</mathjax> <br/> <mathjax>#color(white)(aaaaaaaaaaaaaaaaaaaaaaaaaaa)/color(white)(aaaaaaaaaaaaaaaaaaaa)#</mathjax></p> <p><mathjax>#color(red)(cancel(color(black)(5"H"_2"O"))) + 5"CO" + color(red)(cancel(color(black)(10"H"^(+)))) + "I"_2"O"_5 + color(red)(cancel(color(black)(10"e"^(-)))) -&gt; 5"CO"_2 + color(red)(cancel(color(black)(10"e"^(-)))) + "I"_2 + color(red)(cancel(color(black)(10"H"^(+)))) + color(red)(cancel(color(black)(5"H"_2"O")))#</mathjax></p> </blockquote> <p>The balanced chemical equation for this reaction will thus be - state symbols included! </p> <blockquote> <p><mathjax>#color(green)(|bar(ul(color(white)(a/a)color(black)(5"CO"_ ((g)) + "I"_ 2"O"_ (5(s)) -&gt; "I"_ (2(s)) + 5"CO"_ (2(g)))color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>As you can see, the reaction must be balanced in <strong>neutral conditions</strong>, so the result will be the same regardless if you pick acidic or basic conditions. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#5"CO"_ ((g)) + "I"_ 2"O"_ (5(s)) -&gt; "I"_ (2(s)) + 5"CO"_ (2(g))#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're actually dealing with a <strong><a href="http://socratic.org/chemistry/chemical-reactions/redox-reactions">redox reaction</a></strong> used to convert carbon monoxide, <mathjax>#"CO"#</mathjax>, to carbon dioxide, <mathjax>#"CO"_2#</mathjax>, by using what is known as the <strong>Schutze reagent</strong>, which is iodine pentoxide, <mathjax>#"I"_2"O"_5#</mathjax>, on silica gel. </p> <p>Iodine pentoxide acts as an <strong>oxidizing agent</strong> here and oxidizes carbon monoxide to carbon dioxide while being reduced to iodine in the process. </p> <p>Assign <strong><a href="http://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a></strong> to the atoms that take part in the reaction - for the sake of simplicity, I will not add the states of the chemical species involved in the reaction</p> <blockquote> <p><mathjax>#stackrel(color(blue)(+2))("C") stackrel(color(blue)(-2))("O") + stackrel(color(blue)(+5))("I")_2 stackrel(color(blue)(-2))("O")_5 -&gt; stackrel(color(blue)(0))("I")_2 + stackrel(color(blue)(+4))("C")stackrel(color(blue)(-2))("O")_2#</mathjax></p> </blockquote> <p>You can balance this equation by <strong>assuming</strong> that the reaction takes place in <em>acidic conditions</em> (you will get the same result if you assume basic conditions). </p> <p>So, carbon's oxidation state goes from <mathjax>#color(blue)(+2)#</mathjax> on the reactants' side, to <mathjax>#color(blue)(+4)#</mathjax> on the products' side, which of course means that it's being <strong>oxidized</strong>. </p> <p>The <em>oxidation half-equation</em> will look like this </p> <blockquote> <p><mathjax>#stackrel(color(blue)(+2))("C")"O" -&gt; stackrel(color(blue)(+4))("C")"O"_2 + 2"e"^(-)#</mathjax></p> </blockquote> <p>Here each carbon atoms loses <strong>two electrons</strong>. Balance the oxygen atoms by adding water molecules to the side that needs oxygen, and the hydrogen atoms by adding protons, <mathjax>#"H"^(+)#</mathjax>, to the side that needs hydrogen. </p> <blockquote> <p><mathjax>#"H"_2"O" + stackrel(color(blue)(+2))("C")"O" -&gt; stackrel(color(blue)(+4))("C")"O"_2 + 2"e"^(-) + 2"H"^(+)#</mathjax></p> </blockquote> <p>The oxidation state of iodine goes from <mathjax>#color(blue)(+5)#</mathjax> on the reactant's side, to <mathjax>#color(blue)(0)#</mathjax> on the products' side, which means that it's being <strong>reduced</strong>. </p> <p>The <em>reduction half-reaction</em> will be </p> <blockquote> <p><mathjax>#stackrel(color(blue)(+5))("I")_2"O"_5 + 10"e"^(-) -&gt; stackrel(color(blue)(0))"I"_2#</mathjax></p> </blockquote> <p>Here each iodine atom gains <strong>five electrons</strong>, so two atoms will gain a total of <strong>ten electrons</strong>. Once again, balance the oxygen and hydrogen to get</p> <blockquote> <p><mathjax>#10 "H"^(+) + stackrel(color(blue)(+5))("I")_2"O"_5 + 10"e"^(-) -&gt; stackrel(color(blue)(0))"I"_2 + 5"H"_2"O"#</mathjax></p> </blockquote> <p>As you know, in any redox reaction, the number of electrons <strong>lost</strong> in the oxidation half-equation <strong>must be equal to</strong> the number of electrons <strong>gained</strong> in the reduction half-equation. </p> <p>In order to get these two balanced, multiply the oxidation half-equation by <mathjax>#5#</mathjax>. Add the two half-equations to get</p> <blockquote> <p><mathjax>#{ ("H"_2"O" + stackrel(color(blue)(+2))("C")"O" -&gt; stackrel(color(blue)(+4))("C")"O"_2 + 2"e"^(-) + 2"H"^(+) | xx 5), (10 "H"^(+) + stackrel(color(blue)(+5))("I")_2"O"_5 + 10"e"^(-) -&gt; stackrel(color(blue)(0))"I"_2 + 5"H"_2"O") :}#</mathjax> <br/> <mathjax>#color(white)(aaaaaaaaaaaaaaaaaaaaaaaaaaa)/color(white)(aaaaaaaaaaaaaaaaaaaa)#</mathjax></p> <p><mathjax>#color(red)(cancel(color(black)(5"H"_2"O"))) + 5"CO" + color(red)(cancel(color(black)(10"H"^(+)))) + "I"_2"O"_5 + color(red)(cancel(color(black)(10"e"^(-)))) -&gt; 5"CO"_2 + color(red)(cancel(color(black)(10"e"^(-)))) + "I"_2 + color(red)(cancel(color(black)(10"H"^(+)))) + color(red)(cancel(color(black)(5"H"_2"O")))#</mathjax></p> </blockquote> <p>The balanced chemical equation for this reaction will thus be - state symbols included! </p> <blockquote> <p><mathjax>#color(green)(|bar(ul(color(white)(a/a)color(black)(5"CO"_ ((g)) + "I"_ 2"O"_ (5(s)) -&gt; "I"_ (2(s)) + 5"CO"_ (2(g)))color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>As you can see, the reaction must be balanced in <strong>neutral conditions</strong>, so the result will be the same regardless if you pick acidic or basic conditions. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you balance #CO(g) + I_2O_5(s) -&gt; I_2(s) + CO_2(g)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/balancing-redox-equations-using-the-oxidation-number-method" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Redox Equations Using the Oxidation Number Method</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="249184" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-04T00:18:45" itemprop="dateCreated"> Apr 4, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#5"CO"_ ((g)) + "I"_ 2"O"_ (5(s)) -&gt; "I"_ (2(s)) + 5"CO"_ (2(g))#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're actually dealing with a <strong><a href="http://socratic.org/chemistry/chemical-reactions/redox-reactions">redox reaction</a></strong> used to convert carbon monoxide, <mathjax>#"CO"#</mathjax>, to carbon dioxide, <mathjax>#"CO"_2#</mathjax>, by using what is known as the <strong>Schutze reagent</strong>, which is iodine pentoxide, <mathjax>#"I"_2"O"_5#</mathjax>, on silica gel. </p> <p>Iodine pentoxide acts as an <strong>oxidizing agent</strong> here and oxidizes carbon monoxide to carbon dioxide while being reduced to iodine in the process. </p> <p>Assign <strong><a href="http://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a></strong> to the atoms that take part in the reaction - for the sake of simplicity, I will not add the states of the chemical species involved in the reaction</p> <blockquote> <p><mathjax>#stackrel(color(blue)(+2))("C") stackrel(color(blue)(-2))("O") + stackrel(color(blue)(+5))("I")_2 stackrel(color(blue)(-2))("O")_5 -&gt; stackrel(color(blue)(0))("I")_2 + stackrel(color(blue)(+4))("C")stackrel(color(blue)(-2))("O")_2#</mathjax></p> </blockquote> <p>You can balance this equation by <strong>assuming</strong> that the reaction takes place in <em>acidic conditions</em> (you will get the same result if you assume basic conditions). </p> <p>So, carbon's oxidation state goes from <mathjax>#color(blue)(+2)#</mathjax> on the reactants' side, to <mathjax>#color(blue)(+4)#</mathjax> on the products' side, which of course means that it's being <strong>oxidized</strong>. </p> <p>The <em>oxidation half-equation</em> will look like this </p> <blockquote> <p><mathjax>#stackrel(color(blue)(+2))("C")"O" -&gt; stackrel(color(blue)(+4))("C")"O"_2 + 2"e"^(-)#</mathjax></p> </blockquote> <p>Here each carbon atoms loses <strong>two electrons</strong>. Balance the oxygen atoms by adding water molecules to the side that needs oxygen, and the hydrogen atoms by adding protons, <mathjax>#"H"^(+)#</mathjax>, to the side that needs hydrogen. </p> <blockquote> <p><mathjax>#"H"_2"O" + stackrel(color(blue)(+2))("C")"O" -&gt; stackrel(color(blue)(+4))("C")"O"_2 + 2"e"^(-) + 2"H"^(+)#</mathjax></p> </blockquote> <p>The oxidation state of iodine goes from <mathjax>#color(blue)(+5)#</mathjax> on the reactant's side, to <mathjax>#color(blue)(0)#</mathjax> on the products' side, which means that it's being <strong>reduced</strong>. </p> <p>The <em>reduction half-reaction</em> will be </p> <blockquote> <p><mathjax>#stackrel(color(blue)(+5))("I")_2"O"_5 + 10"e"^(-) -&gt; stackrel(color(blue)(0))"I"_2#</mathjax></p> </blockquote> <p>Here each iodine atom gains <strong>five electrons</strong>, so two atoms will gain a total of <strong>ten electrons</strong>. Once again, balance the oxygen and hydrogen to get</p> <blockquote> <p><mathjax>#10 "H"^(+) + stackrel(color(blue)(+5))("I")_2"O"_5 + 10"e"^(-) -&gt; stackrel(color(blue)(0))"I"_2 + 5"H"_2"O"#</mathjax></p> </blockquote> <p>As you know, in any redox reaction, the number of electrons <strong>lost</strong> in the oxidation half-equation <strong>must be equal to</strong> the number of electrons <strong>gained</strong> in the reduction half-equation. </p> <p>In order to get these two balanced, multiply the oxidation half-equation by <mathjax>#5#</mathjax>. Add the two half-equations to get</p> <blockquote> <p><mathjax>#{ ("H"_2"O" + stackrel(color(blue)(+2))("C")"O" -&gt; stackrel(color(blue)(+4))("C")"O"_2 + 2"e"^(-) + 2"H"^(+) | xx 5), (10 "H"^(+) + stackrel(color(blue)(+5))("I")_2"O"_5 + 10"e"^(-) -&gt; stackrel(color(blue)(0))"I"_2 + 5"H"_2"O") :}#</mathjax> <br/> <mathjax>#color(white)(aaaaaaaaaaaaaaaaaaaaaaaaaaa)/color(white)(aaaaaaaaaaaaaaaaaaaa)#</mathjax></p> <p><mathjax>#color(red)(cancel(color(black)(5"H"_2"O"))) + 5"CO" + color(red)(cancel(color(black)(10"H"^(+)))) + "I"_2"O"_5 + color(red)(cancel(color(black)(10"e"^(-)))) -&gt; 5"CO"_2 + color(red)(cancel(color(black)(10"e"^(-)))) + "I"_2 + color(red)(cancel(color(black)(10"H"^(+)))) + color(red)(cancel(color(black)(5"H"_2"O")))#</mathjax></p> </blockquote> <p>The balanced chemical equation for this reaction will thus be - state symbols included! </p> <blockquote> <p><mathjax>#color(green)(|bar(ul(color(white)(a/a)color(black)(5"CO"_ ((g)) + "I"_ 2"O"_ (5(s)) -&gt; "I"_ (2(s)) + 5"CO"_ (2(g)))color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>As you can see, the reaction must be balanced in <strong>neutral conditions</strong>, so the result will be the same regardless if you pick acidic or basic conditions. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/249184" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-reactions-in-basic-solution"> How do you balance redox reactions in basic solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-equations-by-oxidation-number-method"> How do you balance redox equations by oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-equations-in-acidic-solutions"> How do you balance redox equations in acidic solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-method"> What is the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-balancing-redox-equations-using-the-oxidation-number-m"> What are some examples of balancing redox equations using the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-number-method-useful"> Why is the oxidation number method useful? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-necessary-to-break-the-equation-into-half-reactions-in-the-oxidation-numbe"> Is it necessary to break the equation into half reactions in the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-difference-between-the-oxidation-number-method-and-the-ion-electron-"> What is the difference between the oxidation number method and the ion-electron method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-balance-the-equation-using-the-oxidation-states-method-mno2-al-mn-al2o3"> Can you balance the equation using the oxidation states method MnO2+Al---&gt;Mn+Al2O3? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-this-redox-reaction-using-the-oxidation-number-method-fe2-aq-"> How do you balance this redox reaction using the oxidation number method? 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How do you balance #CO(g) + I_2O_5(s) -&gt; I_2(s) + CO_2(g)#?

ad18f77a-6ddd-11ea-a696-ccda262736ce

https://socratic.org/questions/at-sea-level-the-atmosphere-exerts-a-pressure-of-450-pounds-on-a-surface-with-an

15 per square inch

start physical_unit 3 4 pressure in^(-2) qc_end physical_unit 3 4 9 10 pressure qc_end physical_unit 13 13 18 20 area qc_end end

[{"type":"physical unit","value":"PSI [OF] the atmosphere [IN] per square inch"}]

[{"type":"physical unit","value":"15 per square inch"}]

[{"type":"physical unit","value":"Pressure [OF] the atmosphere [=] \\pu{450 pounds}"},{"type":"physical unit","value":"Area [OF] the surface [=] \\pu{30 square inches}"}]

<h1 class="questionTitle" itemprop="name">At sea level, the atmosphere exerts a pressure of 450 pounds on a surface with an area of 30 square inches. How much pressure per square inch does the atmosphere exert on surfaces at sea level?</h1>

15 per square inch

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We can use the equation</p> <p><mathjax>#p = F_(⊥)/A#</mathjax></p> <p>where <mathjax>#p#</mathjax> is the pressure at the surface,<br/> <mathjax>#F_(⊥)#</mathjax> is the force perpendicular to the surface (commonly in newtons), and<br/> <mathjax>#A#</mathjax> is the area the force is acting upon, commonly is units of square meters.</p> <p>We're given the force (which is in pounds), and the area (in square inches), so the pressure is</p> <p><mathjax>#p = (450lb)/(30i n^2) = color(blue)(15p si#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#15p si#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We can use the equation</p> <p><mathjax>#p = F_(⊥)/A#</mathjax></p> <p>where <mathjax>#p#</mathjax> is the pressure at the surface,<br/> <mathjax>#F_(⊥)#</mathjax> is the force perpendicular to the surface (commonly in newtons), and<br/> <mathjax>#A#</mathjax> is the area the force is acting upon, commonly is units of square meters.</p> <p>We're given the force (which is in pounds), and the area (in square inches), so the pressure is</p> <p><mathjax>#p = (450lb)/(30i n^2) = color(blue)(15p si#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">At sea level, the atmosphere exerts a pressure of 450 pounds on a surface with an area of 30 square inches. How much pressure per square inch does the atmosphere exert on surfaces at sea level?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/atmospheric-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Atmospheric Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="426705" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-20T13:32:35" itemprop="dateCreated"> May 20, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#15p si#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We can use the equation</p> <p><mathjax>#p = F_(⊥)/A#</mathjax></p> <p>where <mathjax>#p#</mathjax> is the pressure at the surface,<br/> <mathjax>#F_(⊥)#</mathjax> is the force perpendicular to the surface (commonly in newtons), and<br/> <mathjax>#A#</mathjax> is the area the force is acting upon, commonly is units of square meters.</p> <p>We're given the force (which is in pounds), and the area (in square inches), so the pressure is</p> <p><mathjax>#p = (450lb)/(30i n^2) = color(blue)(15p si#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/426705" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-atmospheric-pressure-affect-evaporation"> How does atmospheric pressure affect evaporation? 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At sea level, the atmosphere exerts a pressure of 450 pounds on a surface with an area of 30 square inches. How much pressure per square inch does the atmosphere exert on surfaces at sea level?

aa7e3fda-6ddd-11ea-ab2d-ccda262736ce

https://socratic.org/questions/how-many-moles-of-kcl-are-in-27-5-g-of-kcl

0.37 moles

start physical_unit 4 4 mole mol qc_end physical_unit 4 4 7 8 mass qc_end end

[{"type":"physical unit","value":"Mole [OF] KCl [IN] moles"}]

[{"type":"physical unit","value":"0.37 moles"}]

[{"type":"physical unit","value":"Mass [OF] KCl [=] \\pu{27.5 g}"}]

<h1 class="questionTitle" itemprop="name">How many moles of KCl are in 27.5 g of KCl? </h1>

0.37 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To convert a known weight of any substance into its number of moles, you need first to compute the molar (or molecular) mass of that substance.</p> <p>In order to get the molar mass, you would need the atomic weights of the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> making up that substance (just consult a periodic table). In this case,</p> <p>atomic weight of potassium, <mathjax>#K#</mathjax> = <mathjax>#39.10 g/"mol"#</mathjax></p> <p>atomic weight of chlorine, <mathjax>#Cl#</mathjax> = <mathjax>#35.45 g/"mol"#</mathjax> </p> <p>Afterwards, you need to get the sum of the atomic weights. For the problem above,</p> <p>molar mass of <mathjax>#KCl#</mathjax> = <mathjax>#74.55 g/"mol"#</mathjax></p> <p>Now, we are ready to convert.</p> <p><mathjax>#27.5 cancel "grams KCl"#</mathjax> x <mathjax>#1 "mol KCl"/(74.55 cancel "grams" KCl) = 0.369 "mol KCl"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.369 moles</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To convert a known weight of any substance into its number of moles, you need first to compute the molar (or molecular) mass of that substance.</p> <p>In order to get the molar mass, you would need the atomic weights of the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> making up that substance (just consult a periodic table). In this case,</p> <p>atomic weight of potassium, <mathjax>#K#</mathjax> = <mathjax>#39.10 g/"mol"#</mathjax></p> <p>atomic weight of chlorine, <mathjax>#Cl#</mathjax> = <mathjax>#35.45 g/"mol"#</mathjax> </p> <p>Afterwards, you need to get the sum of the atomic weights. For the problem above,</p> <p>molar mass of <mathjax>#KCl#</mathjax> = <mathjax>#74.55 g/"mol"#</mathjax></p> <p>Now, we are ready to convert.</p> <p><mathjax>#27.5 cancel "grams KCl"#</mathjax> x <mathjax>#1 "mol KCl"/(74.55 cancel "grams" KCl) = 0.369 "mol KCl"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles of KCl are in 27.5 g of KCl? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="180642" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nikka-c"><img alt="" class="" src="https://profilepictures.socratic.org/AQ8VOCyTM1J7U0TvIWhw_nkahara.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nikka-c"> Nikka C. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-28T09:01:26" itemprop="dateCreated"> Oct 28, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.369 moles</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To convert a known weight of any substance into its number of moles, you need first to compute the molar (or molecular) mass of that substance.</p> <p>In order to get the molar mass, you would need the atomic weights of the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> making up that substance (just consult a periodic table). In this case,</p> <p>atomic weight of potassium, <mathjax>#K#</mathjax> = <mathjax>#39.10 g/"mol"#</mathjax></p> <p>atomic weight of chlorine, <mathjax>#Cl#</mathjax> = <mathjax>#35.45 g/"mol"#</mathjax> </p> <p>Afterwards, you need to get the sum of the atomic weights. For the problem above,</p> <p>molar mass of <mathjax>#KCl#</mathjax> = <mathjax>#74.55 g/"mol"#</mathjax></p> <p>Now, we are ready to convert.</p> <p><mathjax>#27.5 cancel "grams KCl"#</mathjax> x <mathjax>#1 "mol KCl"/(74.55 cancel "grams" KCl) = 0.369 "mol KCl"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/180642" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9349 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many moles of KCl are in 27.5 g of KCl?

abe6a0a2-6ddd-11ea-83ea-ccda262736ce

https://socratic.org/questions/what-mass-of-precipitate-can-be-produced-when-120-0-ml-of-130-m-barium-chloride-

3.64 grams

start physical_unit 3 3 mass g qc_end physical_unit 13 14 11 12 molarity qc_end physical_unit 21 22 19 20 molarity qc_end end

[{"type":"physical unit","value":"Mass [OF] precipitate [IN] grams"}]

[{"type":"physical unit","value":"3.64 grams"}]

[{"type":"physical unit","value":"Volume [OF] barium chloride solution [=] \\pu{120.0 mL}"},{"type":"physical unit","value":"Molarity [OF] barium chloride solution [=] \\pu{0.130 M}"},{"type":"physical unit","value":"Volume [OF] iron(Ill) sulfate solution [=] \\pu{160.0 mL}"},{"type":"physical unit","value":"Molarity [OF] iron(Ill) sulfate solution [=] \\pu{0.140 M}"}]

<h1 class="questionTitle" itemprop="name">What mass of precipitate can be produced when 120.0 mL of .130 M barium chloride and 160.0 mL of 0.140 M iron(Ill) sulfate are mixed?</h1>

3.64 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Fe_2(SO_4)_3(aq) + 3BaCl_2(aq)rarr2FeCl_3(aq) + 3BaSO_4(s)darr#</mathjax></p> <p><mathjax>#"Moles of barium ion"=120.0xx10^-3*Lxx0.130*mol*L^-1=0.0156*mol#</mathjax>.</p> <p><mathjax>#"Moles of sulfate ion"=3xx160.0xx10^-3*Lxx0.140*mol*L^-1=0.0672*mol#</mathjax>.</p> <p>Sulfate ion is in excess, and thus <mathjax>#BaSO_4(s)#</mathjax> should precipitate quantitatively.....</p> <p>We get <mathjax>#0.0156*molxx233.43*g*mol^-1=??*g#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Approx. <mathjax>#3.6*g#</mathjax> <mathjax>#"barium sulfate"#</mathjax> will precipitate.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Fe_2(SO_4)_3(aq) + 3BaCl_2(aq)rarr2FeCl_3(aq) + 3BaSO_4(s)darr#</mathjax></p> <p><mathjax>#"Moles of barium ion"=120.0xx10^-3*Lxx0.130*mol*L^-1=0.0156*mol#</mathjax>.</p> <p><mathjax>#"Moles of sulfate ion"=3xx160.0xx10^-3*Lxx0.140*mol*L^-1=0.0672*mol#</mathjax>.</p> <p>Sulfate ion is in excess, and thus <mathjax>#BaSO_4(s)#</mathjax> should precipitate quantitatively.....</p> <p>We get <mathjax>#0.0156*molxx233.43*g*mol^-1=??*g#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What mass of precipitate can be produced when 120.0 mL of .130 M barium chloride and 160.0 mL of 0.140 M iron(Ill) sulfate are mixed?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="458585" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-31T18:54:00" itemprop="dateCreated"> Jul 31, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Approx. <mathjax>#3.6*g#</mathjax> <mathjax>#"barium sulfate"#</mathjax> will precipitate.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Fe_2(SO_4)_3(aq) + 3BaCl_2(aq)rarr2FeCl_3(aq) + 3BaSO_4(s)darr#</mathjax></p> <p><mathjax>#"Moles of barium ion"=120.0xx10^-3*Lxx0.130*mol*L^-1=0.0156*mol#</mathjax>.</p> <p><mathjax>#"Moles of sulfate ion"=3xx160.0xx10^-3*Lxx0.140*mol*L^-1=0.0672*mol#</mathjax>.</p> <p>Sulfate ion is in excess, and thus <mathjax>#BaSO_4(s)#</mathjax> should precipitate quantitatively.....</p> <p>We get <mathjax>#0.0156*molxx233.43*g*mol^-1=??*g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/458585" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="458588" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-31T18:58:21" itemprop="dateCreated"> Jul 31, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.64#</mathjax> <mathjax>#"g BaSO"_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to find the theoretical yield of the precipitate of a reaction, given the reactants and their amounts.</p> <p>We'll first write a balanced chemical equation for this reaction:</p> <blockquote> <p><mathjax>#3"BaCl"_2(aq) + "Fe"_2"(SO"_4")"_3(aq) rarr 3"BaSO"_4(s) + 2"FeCl"_3(aq)#</mathjax></p> </blockquote> <p>What we need to do is find the <em>limiting reactant</em>, by first finding the moles of each reactant present (via the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> equation) and then dividing <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> value by their respective coefficients; whichever reactant has the lower value is limiting.</p> <p><mathjax>#"mol BaCl"_2 = ("molarity")("L soln") = (0.130M)overbrace((0.1200color(white)(l)"L"))^"convert volume to L"#</mathjax></p> <p><mathjax>#= ul(0.0156color(white)(l)"mol BaCl"_2#</mathjax></p> <p><mathjax>#"mol Fe"_2"(SO"_4")"_3 = (0.140M)overbrace((0.1600color(white)(l)"L"))^"convert volume to L"#</mathjax></p> <p><mathjax>#= ul(0.0224color(white)(l)"mol Fe"_2"(SO"_4")"_3#</mathjax></p> <blockquote></blockquote> <p>Divide by respective coefficients to find limiting reactant:</p> <p><mathjax>#(0.0156color(white)(l)"mol BaCl"_2)/(3color(white)(l)"(coefficient)") = ul(0.00520#</mathjax></p> <p><mathjax>#(0.0224color(white)(l)"mol Fe"_2"(SO"_4")"_3)/(1color(white)(l)"(coefficient)") = 0.0224#</mathjax></p> <blockquote></blockquote> <p>Barium chloride is thus the limiting reactant.</p> <blockquote></blockquote> <p>Now we use the mole value of <mathjax>#"BaCl"_2#</mathjax> (<mathjax>#0.0156#</mathjax> <mathjax>#"mol"#</mathjax>) and the coefficients of the chemical equation to find the relative number of <em>moles</em> of <mathjax>#"BaSO"_4#</mathjax> (the precipitate) that can form:</p> <p><mathjax>#0.0156cancel("mol BaCl"_2)((3color(white)(l)"mol BaSO"_4)/(3cancel("mol BaCl"_2))) = color(red)(0.0156color(white)(l)"mol BaSO"_4#</mathjax></p> <blockquote></blockquote> <p>Finally, we use the <strong>molar mass</strong> of <mathjax>#"BaSO"_4#</mathjax> (<mathjax>#233.39#</mathjax> <mathjax>#"g/mol"#</mathjax>) to find the mass in grams:</p> <p><mathjax>#color(red)(0.0156)cancel(color(red)("mol BaSO"_4))((233.39color(white)(l)"g BaSO"_4)/(1cancel("mol BaSO"_4))) = color(blue)(ul(3.64color(white)(l)"g BaSO"_4#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/458588" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7055 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What mass of precipitate can be produced when 120.0 mL of .130 M barium chloride and 160.0 mL of 0.140 M iron(Ill) sulfate are mixed?

aa081c10-6ddd-11ea-9e8f-ccda262736ce

https://socratic.org/questions/how-much-sodium-chloride-can-dissolve-in-40-g-of-water-at-50-c

14.98 grams

start physical_unit 2 3 mass g qc_end physical_unit 10 10 7 8 mass qc_end physical_unit 10 10 12 13 temperature qc_end end

[{"type":"physical unit","value":"Mass [OF] sodium chloride [IN] grams"}]

[{"type":"physical unit","value":"14.98 grams"}]

[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{40 g}"},{"type":"physical unit","value":"Temperature [OF] water [=] \\pu{50 ℃}"}]

<h1 class="questionTitle" itemprop="name"> How much sodium chloride can dissolve in 40 g of water at 50°C?</h1>

14.98 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>With a solubility of 37g/100mL at 50’C and a water <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of 0.988 g/mL at the same temperature, 40g of water would be 40.49 mL, so it could dissolve <mathjax>#(40.49/100)*37 = 14.98#</mathjax>g of NaCl.<br/> <a href="http://www.800mainstreet.com/9/0009-004-solub.html" rel="nofollow" target="_blank">http://www.800mainstreet.com/9/0009-004-solub.html</a></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>14.98g</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>With a solubility of 37g/100mL at 50’C and a water <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of 0.988 g/mL at the same temperature, 40g of water would be 40.49 mL, so it could dissolve <mathjax>#(40.49/100)*37 = 14.98#</mathjax>g of NaCl.<br/> <a href="http://www.800mainstreet.com/9/0009-004-solub.html" rel="nofollow" target="_blank">http://www.800mainstreet.com/9/0009-004-solub.html</a></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name"> How much sodium chloride can dissolve in 40 g of water at 50°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solution-formation---what-happens-when-stuff-dissolves" itemprop="url"> <span class="breadcrumb" itemprop="title">Solution Formation</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="409219" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/scooke"><img alt="" class="" src="https://profilepictures.socratic.org/ezAzqDkjRS6NXBmMH3lg_BioPic2010a.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/scooke"> SCooke </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-19T08:59:49" itemprop="dateCreated"> Apr 19, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>14.98g</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>With a solubility of 37g/100mL at 50’C and a water <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of 0.988 g/mL at the same temperature, 40g of water would be 40.49 mL, so it could dissolve <mathjax>#(40.49/100)*37 = 14.98#</mathjax>g of NaCl.<br/> <a href="http://www.800mainstreet.com/9/0009-004-solub.html" rel="nofollow" target="_blank">http://www.800mainstreet.com/9/0009-004-solub.html</a></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/409219" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="409223" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/g-ozdilek"><img alt="" class="" src="https://profilepictures.socratic.org/KVknsUYQYSYlmT2ycLuw_kentkonseyi-%287%29HGO.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/g-ozdilek"> G_Ozdilek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-19T09:03:36" itemprop="dateCreated"> Apr 19, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>100 mL water (at 50 degrees) can dissolve 37 grams of NaCl. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>According to Volland (2005), 100 mL water can dissolve 37 grams of NaCl. Since you have 40 grams of water, it means at 50 degrees you have <mathjax>#((40 g)/(0.988 g/(cm^3)))#</mathjax> or <mathjax>#40.49 cm^3#</mathjax> (The Engineering Toolbox, 2017). Thererefore, you have 40.49 mL of water. </p> <p>Now you can compute solved NaCl by:</p> <p><mathjax>#(40.49*37)/100#</mathjax> </p> <p>The answer is <mathjax>#14.98 grams#</mathjax> of NaCl </p> <p>References: </p> <p>The Engineering Toolbox (2017). Water <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">Density</a> and Specific Weight. Retrieved on the internet: www(dot)engineeringtoolbox(dot)com(slash)water(dash)density(dash)specific(dash)weight(dash)d_595(dot)html</p> <p>Volland, W. (2005). Online Introductory Chemistry. Retrieved on the Internet: www(dot)800mainstreet(dot)com(slash)9(slash)0009(dash)004(dash)solub(dot)html</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/409223" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-temperature-affect-the-formation-of-a-solution"> How can temperature affect the formation of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-formation-of-a-solution-be-exothermic-or-endothermic"> How can the formation of a solution be exothermic or endothermic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-formation-of-a-solution-involve-energy"> How does the formation of a solution involve energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-heat-formation-of-solution"> How do you find heat of formation of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-factor-promotes-the-formation-of-solutions"> Which factors promote the formation of solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/which-two-processes-are-at-equilibrium-in-a-saturated-sugar-solution"> Which two processes are at equilibrium in a saturated sugar solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutes-lower-the-freezing-point"> Why do solutes lower the freezing point? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-solution-formation-require-energy"> Why does solution formation require energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutes-dissolve-in-solvents"> Why do solutes dissolve in solvents? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-solvent-dissolves-silicone"> What solvent dissolves silicone? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/solution-formation---what-happens-when-stuff-dissolves"> See all questions in Solution Formation </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11871 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How much sodium chloride can dissolve in 40 g of water at 50°C?

a85addc8-6ddd-11ea-8a2f-ccda262736ce

https://socratic.org/questions/zinc-reacts-with-water-to-produce-zinc-hydroxide-and-hydrogen-gas-what-is-the-eq

Zn + 2 H2O -> Zn(OH)2 +H2

start chemical_equation qc_end substance 0 0 qc_end substance 3 3 qc_end substance 6 7 qc_end substance 9 10 qc_end end

[{"type":"other","value":"Chemical Equation [OF] this reaction"}]

[{"type":"chemical equation","value":"Zn + 2 H2O -> Zn(OH)2 +H2"}]

[{"type":"substance name","value":"Zinc"},{"type":"substance name","value":"Water"},{"type":"substance name","value":"Zinc hydroxide"},{"type":"substance name","value":"Hydrogen gas"}]

<h1 class="questionTitle" itemprop="name">Zinc reacts with water to produce zinc hydroxide and hydrogen gas. What is the equation for this reaction?</h1>

Zn + 2 H2O -> Zn(OH)2 +H2

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To get this chemical equation, all you have to do is reference the question because it already gives you all of the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> you need. </p> <p>To get the formula for zinc (II) hydroxide, you need to know that hydroxide has a 1- charge and you need 2 of them to cancel out zinc's 2+ charge. </p> <p>Hydrogen gas is a diatomic molecule from the mnemonic Br I N Cl H O F. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Zn + 2H_2O -&gt; Zn(OH)_2 + H_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To get this chemical equation, all you have to do is reference the question because it already gives you all of the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> you need. </p> <p>To get the formula for zinc (II) hydroxide, you need to know that hydroxide has a 1- charge and you need 2 of them to cancel out zinc's 2+ charge. </p> <p>Hydrogen gas is a diatomic molecule from the mnemonic Br I N Cl H O F. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Zinc reacts with water to produce zinc hydroxide and hydrogen gas. What is the equation for this reaction?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="507994" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/evan-12"><img alt="" class="" src="https://profilepictures.socratic.org/VVKGFJEmQ66DHVnuBvTK_fireball-422746_960_720.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/evan-12"> Evan Holbrook </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-11-19T03:34:23" itemprop="dateCreated"> Nov 19, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Zn + 2H_2O -&gt; Zn(OH)_2 + H_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To get this chemical equation, all you have to do is reference the question because it already gives you all of the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> you need. </p> <p>To get the formula for zinc (II) hydroxide, you need to know that hydroxide has a 1- charge and you need 2 of them to cancel out zinc's 2+ charge. </p> <p>Hydrogen gas is a diatomic molecule from the mnemonic Br I N Cl H O F. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/507994" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? 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Zinc reacts with water to produce zinc hydroxide and hydrogen gas. What is the equation for this reaction?

a9c74229-6ddd-11ea-a57a-ccda262736ce

https://socratic.org/questions/what-is-the-temperature-of-350-ml-of-gas-at-85-atm-if-it-has-a-volume-of-920-ml-

88.28 K

start physical_unit 8 8 temperature k qc_end physical_unit 8 8 5 6 volume qc_end physical_unit 8 8 10 11 pressure qc_end physical_unit 8 8 18 19 volume qc_end c_other STP qc_end end

[{"type":"physical unit","value":"Temperature2 [OF] the gas [IN] K"}]

[{"type":"physical unit","value":"88.28 K"}]

[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{350 mL}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{0.85 atm}"},{"type":"physical unit","value":"Volume2 [OF] the gas [=] \\pu{920 mL}"},{"type":"other","value":"STP"}]

<h1 class="questionTitle" itemprop="name">What is the temperature of 350 mL of gas at .85 atm if it has a volume of 920 mL at STP?</h1>

88.28 K

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the equation:</p> <p><mathjax>#(P_1 * V_1)/(T_1) = (P_2*V_2)/T_2#</mathjax></p> <p>Where <mathjax>#P_1#</mathjax> is the pressure at STP, <mathjax>#T_1#</mathjax> is the temperature at STP and <mathjax>#V_1#</mathjax> is <mathjax>#0.92L#</mathjax>.</p> <p>Substitute all the values in. </p> <p><mathjax>#[(1 atm)(0.92L)]/(273K) = [(0.85atm)(0.35L)]/T_2#</mathjax></p> <p><mathjax>#(T_2)(0.92L)= (273K)(0.85atm)(0.35L)#</mathjax></p> <p><mathjax>#(T_2)(0.92L)= 81.22#</mathjax></p> <p><mathjax>#(T_2) = 88.3K#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#88.3K#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the equation:</p> <p><mathjax>#(P_1 * V_1)/(T_1) = (P_2*V_2)/T_2#</mathjax></p> <p>Where <mathjax>#P_1#</mathjax> is the pressure at STP, <mathjax>#T_1#</mathjax> is the temperature at STP and <mathjax>#V_1#</mathjax> is <mathjax>#0.92L#</mathjax>.</p> <p>Substitute all the values in. </p> <p><mathjax>#[(1 atm)(0.92L)]/(273K) = [(0.85atm)(0.35L)]/T_2#</mathjax></p> <p><mathjax>#(T_2)(0.92L)= (273K)(0.85atm)(0.35L)#</mathjax></p> <p><mathjax>#(T_2)(0.92L)= 81.22#</mathjax></p> <p><mathjax>#(T_2) = 88.3K#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the temperature of 350 mL of gas at .85 atm if it has a volume of 920 mL at STP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/combined-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Combined Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="263070" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/prim"><img alt="" class="" src="https://profilepictures.socratic.org/GAepgFbiSHKCiEE3ByEe_tumblr_n5wio1sTz91tummxoo1_250.gif" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/prim"> Madi </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-07T02:47:56" itemprop="dateCreated"> May 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#88.3K#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the equation:</p> <p><mathjax>#(P_1 * V_1)/(T_1) = (P_2*V_2)/T_2#</mathjax></p> <p>Where <mathjax>#P_1#</mathjax> is the pressure at STP, <mathjax>#T_1#</mathjax> is the temperature at STP and <mathjax>#V_1#</mathjax> is <mathjax>#0.92L#</mathjax>.</p> <p>Substitute all the values in. </p> <p><mathjax>#[(1 atm)(0.92L)]/(273K) = [(0.85atm)(0.35L)]/T_2#</mathjax></p> <p><mathjax>#(T_2)(0.92L)= (273K)(0.85atm)(0.35L)#</mathjax></p> <p><mathjax>#(T_2)(0.92L)= 81.22#</mathjax></p> <p><mathjax>#(T_2) = 88.3K#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/263070" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5345df5f02bf345f71b1c8e8"> Question #1c8e8 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ac3df02bf342f4c3bfabb"> Question #bfabb </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-you-want-to-solve-for-the-volume-of-a-gas-v2-and-p1-is-greater-than-p2-would-"> If you want to solve for the volume of a gas (V2) and P1 is greater than P2, would you expect V2... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-modern-refrigerator-take-advantage-of-the-gas-laws-to-remove-heat-f"> How does the modern refrigerator take advantage of the gas laws to remove heat from a system? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-certain-sample-of-gas-has-a-volume-of-0-452-l-measured-at-87-c-and-0-620-atm-w"> A certain sample of gas has a volume of 0.452 L measured at 87°C and 0.620 atm. 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What is the temperature of 350 mL of gas at .85 atm if it has a volume of 920 mL at STP?

a83f584d-6ddd-11ea-99e8-ccda262736ce

https://socratic.org/questions/a-0-596-g-sample-of-a-gaseous-compound-containing-only-boron-and-hydrogen-occupi-1

BH3

start chemical_formula qc_end physical_unit 3 3 1 2 mass qc_end c_other OTHER qc_end physical_unit 3 3 14 15 volume qc_end c_other STP qc_end c_other OTHER qc_end c_other OTHER qc_end physical_unit 32 32 29 30 mass qc_end c_other OTHER qc_end end

[{"type":"other","value":"Chemical Formula [OF] the gaseous compound [IN] empirical"}]

[{"type":"chemical equation","value":"BH3"}]

[{"type":"physical unit","value":"Mass [OF] sample [=] \\pu{0.596 g}"},{"type":"other","value":"The sample of a gaseous compound contains only boron and hydrogen."},{"type":"physical unit","value":"Volume [OF] sample [=] \\pu{484 cm^3}"},{"type":"other","value":"STP"},{"type":"other","value":"Excess oxygen."},{"type":"other","value":"All the hydrogen was recovered as water."},{"type":"physical unit","value":"Mass [OF] water [=] \\pu{1.17 g}"},{"type":"other","value":"All the boron was present as B2O3."}]

<h1 class="questionTitle" itemprop="name">A 0.596 g sample of a gaseous compound containing only boron and hydrogen occupied 484 cm^3 at STP. When ignited in excess oxygen all the hydrogen was recovered as 1.17 g of water, and all the boron was present as B2O3. What is the empirical formula? </h1>

BH3

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>!! LONG ANSWER !!</strong></p> <p>The trick here is to recognize the fact that you can use the mass of water produced by the reaction to determine how much hydrogen the original compound contained, then use the original sample's mass to determine how much boron it contained.</p> <p>Basically, you don't need to worry about the compound that contains the boron, <mathjax>#"B"_2"O"_3#</mathjax>, since that has no relevance to finding the mass of boron. </p> <p>So, start by figuring out how much hydrogen you get <em>per mole</em> of water. You know that <em>every mole</em> of water, <mathjax>#"H"_2"O"#</mathjax>, contains</p> <blockquote> <ul> <li><em><strong>2 moles</strong> of hydrongen</em></li> <li><em><strong>1 mole</strong> of oxygen</em></li> </ul> </blockquote> <p>This means that if you use the molar masses of the two <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>, you can determine how much hydrogen you get per mole of water, i.e. the <a href="http://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of water</p> <p>Don't forget about the fact that you have <mathjax>#2#</mathjax> moles of hydrogen!</p> <blockquote> <p><mathjax>#(2 xx 1.00794color(red)(cancel(color(black)("g/mol"))))/(18.015color(red)(cancel(color(black)("g/mol")))) xx 100 = 11.19% "H"#</mathjax></p> </blockquote> <p>This means that you get <mathjax>#"11.19 g"#</mathjax> of hydrogen <em>for every</em> <mathjax>#"100 g"#</mathjax> of water. This means that the reaction produced</p> <blockquote> <p><mathjax>#1.17color(red)(cancel(color(black)("g water"))) * "11.19 g H"/(100color(red)(cancel(color(black)("g water")))) = "0.1309 g H"#</mathjax></p> </blockquote> <p>SInce all the hydrogen that was originally present in the compound is now a part of the water, it follows that your compound contained <mathjax>#"0.1309 g"#</mathjax> of hydrogen. </p> <p>This means that it also contained</p> <blockquote> <p><mathjax>#m_"compound" = m_"hydrogen" + m_"boron"#</mathjax></p> <p><mathjax>#m_"boron" = "0.596 g" - "0.1309 g" = "0.465 g B"#</mathjax></p> </blockquote> <p>To get the compound's <em>empirical formula</em>, you need to figure out what the <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> betyween boron and hydrogen is in the compound. </p> <blockquote> <p><mathjax>#0.1309color(red)(cancel(color(black)("g"))) * "1 mole H"/(1.00794color(red)(cancel(color(black)("g")))) = "0.12987 moles H"#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#0.465color(red)(cancel(color(black)("g"))) * "1 mole B"/(10.811color(red)(cancel(color(black)("g")))) = "0.043012 moles B"#</mathjax></p> </blockquote> <p>Now divide both these values by the <em>smallest one</em> to get</p> <blockquote> <p><mathjax>#"For H: " (0.12987 color(red)(cancel(color(black)("moles"))))/(0.043012color(red)(cancel(color(black)("moles")))) = 3.0194 ~~ 3#</mathjax></p> <p><mathjax>#"For B: " (0.043012 color(red)(cancel(color(black)("moles"))))/(0.043012color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> </blockquote> <p>The empirical formula of the compound wil thus be </p> <blockquote> <p><mathjax>#"B"_1"H"_3 implies "BH"_3#</mathjax></p> </blockquote> <p>Notice that they tell you that the compound occupies a volume of <mathjax>#"484 cm"^3#</mathjax> at STP, which means that you can use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas at STP</a> to find how many moles you ahve in that sample. </p> <p>At STP conditions, a pressure of <mathjax>#"100 kPa"#</mathjax> and a temperature of <mathjax>#0^@"C"#</mathjax>, <strong>one mole</strong> of any ideal gas occupies exactly <mathjax>#"22.7 L"#</mathjax>. This means that your sample will contain</p> <blockquote> <p><mathjax>#484color(red)(cancel(color(black)("cm"^3))) * (1color(red)(cancel(color(black)("L"))))/(1000color(red)(cancel(color(black)("cm"^3)))) * "1 mole"/(22.7color(red)(cancel(color(black)("L")))) = "0.02132 moles"#</mathjax></p> </blockquote> <p>Now you can find the compound's <strong>molar mass</strong></p> <blockquote> <p><mathjax>#M_"M" = m/n = "0.596 g"/"0.02132 moles" = "27.95 g/mol"#</mathjax></p> </blockquote> <p>You can use this value to find the compound's <strong>molecular formula</strong></p> <blockquote> <p><mathjax>#("10.811 g/mol" + 3 xx "1.00794 g/mol") xx color(blue)(n) = "27.95 g/mol"#</mathjax></p> </blockquote> <p>This means that you have </p> <blockquote> <p><mathjax>#color(blue)(n) = (27.95color(red)(cancel(color(black)("g/mol"))))/((10.811 + 3 * 1.00794)color(red)(cancel(color(black)("g/mol")))) = 2.0203 ~~ 2#</mathjax></p> </blockquote> <p>The molecular formula will thus be </p> <blockquote> <p><mathjax>#("BH"_3)_color(blue)(2) = "B"_2"H"_6 -&gt;#</mathjax> <em>diborane</em></p> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Empirical formula: <mathjax>#"BH"_3#</mathjax><br/> Molecular formula: <mathjax>#"B"_2"H"_6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>!! LONG ANSWER !!</strong></p> <p>The trick here is to recognize the fact that you can use the mass of water produced by the reaction to determine how much hydrogen the original compound contained, then use the original sample's mass to determine how much boron it contained.</p> <p>Basically, you don't need to worry about the compound that contains the boron, <mathjax>#"B"_2"O"_3#</mathjax>, since that has no relevance to finding the mass of boron. </p> <p>So, start by figuring out how much hydrogen you get <em>per mole</em> of water. You know that <em>every mole</em> of water, <mathjax>#"H"_2"O"#</mathjax>, contains</p> <blockquote> <ul> <li><em><strong>2 moles</strong> of hydrongen</em></li> <li><em><strong>1 mole</strong> of oxygen</em></li> </ul> </blockquote> <p>This means that if you use the molar masses of the two <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>, you can determine how much hydrogen you get per mole of water, i.e. the <a href="http://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of water</p> <p>Don't forget about the fact that you have <mathjax>#2#</mathjax> moles of hydrogen!</p> <blockquote> <p><mathjax>#(2 xx 1.00794color(red)(cancel(color(black)("g/mol"))))/(18.015color(red)(cancel(color(black)("g/mol")))) xx 100 = 11.19% "H"#</mathjax></p> </blockquote> <p>This means that you get <mathjax>#"11.19 g"#</mathjax> of hydrogen <em>for every</em> <mathjax>#"100 g"#</mathjax> of water. This means that the reaction produced</p> <blockquote> <p><mathjax>#1.17color(red)(cancel(color(black)("g water"))) * "11.19 g H"/(100color(red)(cancel(color(black)("g water")))) = "0.1309 g H"#</mathjax></p> </blockquote> <p>SInce all the hydrogen that was originally present in the compound is now a part of the water, it follows that your compound contained <mathjax>#"0.1309 g"#</mathjax> of hydrogen. </p> <p>This means that it also contained</p> <blockquote> <p><mathjax>#m_"compound" = m_"hydrogen" + m_"boron"#</mathjax></p> <p><mathjax>#m_"boron" = "0.596 g" - "0.1309 g" = "0.465 g B"#</mathjax></p> </blockquote> <p>To get the compound's <em>empirical formula</em>, you need to figure out what the <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> betyween boron and hydrogen is in the compound. </p> <blockquote> <p><mathjax>#0.1309color(red)(cancel(color(black)("g"))) * "1 mole H"/(1.00794color(red)(cancel(color(black)("g")))) = "0.12987 moles H"#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#0.465color(red)(cancel(color(black)("g"))) * "1 mole B"/(10.811color(red)(cancel(color(black)("g")))) = "0.043012 moles B"#</mathjax></p> </blockquote> <p>Now divide both these values by the <em>smallest one</em> to get</p> <blockquote> <p><mathjax>#"For H: " (0.12987 color(red)(cancel(color(black)("moles"))))/(0.043012color(red)(cancel(color(black)("moles")))) = 3.0194 ~~ 3#</mathjax></p> <p><mathjax>#"For B: " (0.043012 color(red)(cancel(color(black)("moles"))))/(0.043012color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> </blockquote> <p>The empirical formula of the compound wil thus be </p> <blockquote> <p><mathjax>#"B"_1"H"_3 implies "BH"_3#</mathjax></p> </blockquote> <p>Notice that they tell you that the compound occupies a volume of <mathjax>#"484 cm"^3#</mathjax> at STP, which means that you can use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas at STP</a> to find how many moles you ahve in that sample. </p> <p>At STP conditions, a pressure of <mathjax>#"100 kPa"#</mathjax> and a temperature of <mathjax>#0^@"C"#</mathjax>, <strong>one mole</strong> of any ideal gas occupies exactly <mathjax>#"22.7 L"#</mathjax>. This means that your sample will contain</p> <blockquote> <p><mathjax>#484color(red)(cancel(color(black)("cm"^3))) * (1color(red)(cancel(color(black)("L"))))/(1000color(red)(cancel(color(black)("cm"^3)))) * "1 mole"/(22.7color(red)(cancel(color(black)("L")))) = "0.02132 moles"#</mathjax></p> </blockquote> <p>Now you can find the compound's <strong>molar mass</strong></p> <blockquote> <p><mathjax>#M_"M" = m/n = "0.596 g"/"0.02132 moles" = "27.95 g/mol"#</mathjax></p> </blockquote> <p>You can use this value to find the compound's <strong>molecular formula</strong></p> <blockquote> <p><mathjax>#("10.811 g/mol" + 3 xx "1.00794 g/mol") xx color(blue)(n) = "27.95 g/mol"#</mathjax></p> </blockquote> <p>This means that you have </p> <blockquote> <p><mathjax>#color(blue)(n) = (27.95color(red)(cancel(color(black)("g/mol"))))/((10.811 + 3 * 1.00794)color(red)(cancel(color(black)("g/mol")))) = 2.0203 ~~ 2#</mathjax></p> </blockquote> <p>The molecular formula will thus be </p> <blockquote> <p><mathjax>#("BH"_3)_color(blue)(2) = "B"_2"H"_6 -&gt;#</mathjax> <em>diborane</em></p> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A 0.596 g sample of a gaseous compound containing only boron and hydrogen occupied 484 cm^3 at STP. When ignited in excess oxygen all the hydrogen was recovered as 1.17 g of water, and all the boron was present as B2O3. What is the empirical formula? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="181075" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-29T20:29:50" itemprop="dateCreated"> Oct 29, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Empirical formula: <mathjax>#"BH"_3#</mathjax><br/> Molecular formula: <mathjax>#"B"_2"H"_6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>!! LONG ANSWER !!</strong></p> <p>The trick here is to recognize the fact that you can use the mass of water produced by the reaction to determine how much hydrogen the original compound contained, then use the original sample's mass to determine how much boron it contained.</p> <p>Basically, you don't need to worry about the compound that contains the boron, <mathjax>#"B"_2"O"_3#</mathjax>, since that has no relevance to finding the mass of boron. </p> <p>So, start by figuring out how much hydrogen you get <em>per mole</em> of water. You know that <em>every mole</em> of water, <mathjax>#"H"_2"O"#</mathjax>, contains</p> <blockquote> <ul> <li><em><strong>2 moles</strong> of hydrongen</em></li> <li><em><strong>1 mole</strong> of oxygen</em></li> </ul> </blockquote> <p>This means that if you use the molar masses of the two <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>, you can determine how much hydrogen you get per mole of water, i.e. the <a href="http://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of water</p> <p>Don't forget about the fact that you have <mathjax>#2#</mathjax> moles of hydrogen!</p> <blockquote> <p><mathjax>#(2 xx 1.00794color(red)(cancel(color(black)("g/mol"))))/(18.015color(red)(cancel(color(black)("g/mol")))) xx 100 = 11.19% "H"#</mathjax></p> </blockquote> <p>This means that you get <mathjax>#"11.19 g"#</mathjax> of hydrogen <em>for every</em> <mathjax>#"100 g"#</mathjax> of water. This means that the reaction produced</p> <blockquote> <p><mathjax>#1.17color(red)(cancel(color(black)("g water"))) * "11.19 g H"/(100color(red)(cancel(color(black)("g water")))) = "0.1309 g H"#</mathjax></p> </blockquote> <p>SInce all the hydrogen that was originally present in the compound is now a part of the water, it follows that your compound contained <mathjax>#"0.1309 g"#</mathjax> of hydrogen. </p> <p>This means that it also contained</p> <blockquote> <p><mathjax>#m_"compound" = m_"hydrogen" + m_"boron"#</mathjax></p> <p><mathjax>#m_"boron" = "0.596 g" - "0.1309 g" = "0.465 g B"#</mathjax></p> </blockquote> <p>To get the compound's <em>empirical formula</em>, you need to figure out what the <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> betyween boron and hydrogen is in the compound. </p> <blockquote> <p><mathjax>#0.1309color(red)(cancel(color(black)("g"))) * "1 mole H"/(1.00794color(red)(cancel(color(black)("g")))) = "0.12987 moles H"#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#0.465color(red)(cancel(color(black)("g"))) * "1 mole B"/(10.811color(red)(cancel(color(black)("g")))) = "0.043012 moles B"#</mathjax></p> </blockquote> <p>Now divide both these values by the <em>smallest one</em> to get</p> <blockquote> <p><mathjax>#"For H: " (0.12987 color(red)(cancel(color(black)("moles"))))/(0.043012color(red)(cancel(color(black)("moles")))) = 3.0194 ~~ 3#</mathjax></p> <p><mathjax>#"For B: " (0.043012 color(red)(cancel(color(black)("moles"))))/(0.043012color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> </blockquote> <p>The empirical formula of the compound wil thus be </p> <blockquote> <p><mathjax>#"B"_1"H"_3 implies "BH"_3#</mathjax></p> </blockquote> <p>Notice that they tell you that the compound occupies a volume of <mathjax>#"484 cm"^3#</mathjax> at STP, which means that you can use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas at STP</a> to find how many moles you ahve in that sample. </p> <p>At STP conditions, a pressure of <mathjax>#"100 kPa"#</mathjax> and a temperature of <mathjax>#0^@"C"#</mathjax>, <strong>one mole</strong> of any ideal gas occupies exactly <mathjax>#"22.7 L"#</mathjax>. This means that your sample will contain</p> <blockquote> <p><mathjax>#484color(red)(cancel(color(black)("cm"^3))) * (1color(red)(cancel(color(black)("L"))))/(1000color(red)(cancel(color(black)("cm"^3)))) * "1 mole"/(22.7color(red)(cancel(color(black)("L")))) = "0.02132 moles"#</mathjax></p> </blockquote> <p>Now you can find the compound's <strong>molar mass</strong></p> <blockquote> <p><mathjax>#M_"M" = m/n = "0.596 g"/"0.02132 moles" = "27.95 g/mol"#</mathjax></p> </blockquote> <p>You can use this value to find the compound's <strong>molecular formula</strong></p> <blockquote> <p><mathjax>#("10.811 g/mol" + 3 xx "1.00794 g/mol") xx color(blue)(n) = "27.95 g/mol"#</mathjax></p> </blockquote> <p>This means that you have </p> <blockquote> <p><mathjax>#color(blue)(n) = (27.95color(red)(cancel(color(black)("g/mol"))))/((10.811 + 3 * 1.00794)color(red)(cancel(color(black)("g/mol")))) = 2.0203 ~~ 2#</mathjax></p> </blockquote> <p>The molecular formula will thus be </p> <blockquote> <p><mathjax>#("BH"_3)_color(blue)(2) = "B"_2"H"_6 -&gt;#</mathjax> <em>diborane</em></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/181075" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5568 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A 0.596 g sample of a gaseous compound containing only boron and hydrogen occupied 484 cm^3 at STP. When ignited in excess oxygen all the hydrogen was recovered as 1.17 g of water, and all the boron was present as B2O3. What is the empirical formula?

aaded24c-6ddd-11ea-ba2d-ccda262736ce

https://socratic.org/questions/562fc72611ef6b5268864303

124 J/(kg * K)

start physical_unit 27 28 specific_heat j/(kg_·_k) qc_end physical_unit 27 28 0 1 energy qc_end physical_unit 27 28 9 10 mass qc_end physical_unit 27 28 16 17 temperature qc_end physical_unit 27 28 19 20 temperature qc_end end

[{"type":"physical unit","value":"Specific heat [OF] the metal [IN] J/(kg * K)"}]

[{"type":"physical unit","value":"124 J/(kg * K)"}]

[{"type":"physical unit","value":"Required energy [OF] the metal sample [=] \\pu{1351 J}"},{"type":"physical unit","value":"Mass [OF] the metal sample [=] \\pu{0.125 kg}"},{"type":"physical unit","value":"Temperature1 [OF] the metal sample [=] \\pu{25.0 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] the metal sample [=] \\pu{112.1 ℃}"}]

<h1 class="questionTitle" itemprop="name">#"1351 J"# of energy are required to heat a #"0.125 kg"# sample of a metal from #25.0^@"C"# to #112.1^@"C"#. What is the specific heat of the metal? </h1>

124 J/(kg * K)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Heat energy required is given by <mathjax>#W=mcDeltaT#</mathjax>.</p> <p><mathjax>#therefore c= W/(mDeltaT)=(1351"J")/((0,125"kg")(112,1^"o""C"-25.0^"o""C"))="124 J/kg·K"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#124"J/kg·K"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Heat energy required is given by <mathjax>#W=mcDeltaT#</mathjax>.</p> <p><mathjax>#therefore c= W/(mDeltaT)=(1351"J")/((0,125"kg")(112,1^"o""C"-25.0^"o""C"))="124 J/kg·K"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">#"1351 J"# of energy are required to heat a #"0.125 kg"# sample of a metal from #25.0^@"C"# to #112.1^@"C"#. What is the specific heat of the metal? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="180470" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/trevor-r-1"><img alt="" class="" src="https://profilepictures.socratic.org/2Wf9lLD9RaSzPbXY0EW8_S5002678.JPG" title=""/></a> <a class="secondContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/trevor-r-1"> Trevor Ryan. </a>·<a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-27T19:28:09" itemprop="dateCreated"> Oct 27, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#124"J/kg·K"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Heat energy required is given by <mathjax>#W=mcDeltaT#</mathjax>.</p> <p><mathjax>#therefore c= W/(mDeltaT)=(1351"J")/((0,125"kg")(112,1^"o""C"-25.0^"o""C"))="124 J/kg·K"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/180470" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? 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#"1351 J"# of energy are required to heat a #"0.125 kg"# sample of a metal from #25.0^@"C"# to #112.1^@"C"#. What is the specific heat of the metal?

a89b1ab6-6ddd-11ea-b7e7-ccda262736ce

https://socratic.org/questions/how-do-you-calculate-the-molarity-of-the-hno-3-solution

0.12 mol/L

start physical_unit 8 9 molarity mol/l qc_end physical_unit 31 32 29 30 volume qc_end c_other OTHER qc_end physical_unit 40 41 37 38 volume qc_end physical_unit 57 59 53 54 volume qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"molarity [OF] HNO3 solution [IN] mol/L"}]

[{"type":"physical unit","value":"0.12 mol/L"}]

[{"type":"physical unit","value":"Mass1 [OF] barium hydroxide pure sample [=] \\pu{5.68 g}"},{"type":"physical unit","value":"Volume1 [OF] volumetric flask [=] \\pu{250 mL}"},{"type":"other","value":"A pure sample of barium hydroxide was dissolved and diluted in volumetric flask."},{"type":"physical unit","value":"Volume2 [OF] this solution [=] \\pu{13.01 mL}"},{"type":"physical unit","value":"Volume2 [OF] nitric acid solution [=] \\pu{29.7 mL}"},{"type":"other","value":"reach the stoichiometric point"}]

<h1 class="questionTitle" itemprop="name">How do you calculate the molarity of the #HNO_3# solution?</h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>A pure sample of barium hydroxide of mass 5.68 g was dissolved and diluted to the mark in a 250 mL volumetric flask. It was found that 13.01 mL of this solution was needed to reach the stoichiometric point in a titration of 29.7 mL of a nitric acid solution. </p></div> </h2> </div> </div>

0.12 mol/L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This is really a two-part question:</p> <ol> <li>What is the molarity of the barium hydroxide solution?</li> <li>What is the molarity of the nitric acid?</li> </ol> <blockquote></blockquote> <p><strong>1. Molarity of <mathjax>#"Ba(OH)"_2#</mathjax></strong></p> <p>The formula for molarity is </p> <blockquote> <blockquote> <p><mathjax>#color(blue)(|bar(ul(color(white)(a/a) "Molarity" = "moles"/"litres"color(white)(a/a)|)))" "#</mathjax></p> </blockquote> </blockquote> <p><mathjax>#"Moles of Ba(OH)"_2 = 5.68 color(red)(cancel(color(black)("g Ba(OH)"_2))) × "1 mol Ba(OH)"_2/(171.34 color(red)(cancel(color(black)("g Ba(OH)"_2)))) = "0.033 15 mol Ba(OH)"_2#</mathjax></p> <p><mathjax>#"Volume" = "250 mL" = "0.250 L"#</mathjax></p> <p><mathjax>#"Molarity" = "moles"/"litres" = "0.033 15 mol"/"0.250 L" = "0.1326 mol/L"#</mathjax></p> <blockquote></blockquote> <p><strong>2. Molarity of <mathjax>#"HNO"_3#</mathjax></strong></p> <p>The equation for the <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a> reaction is</p> <p><mathjax>#"Ba(OH)"_2 + "2HNO"_3 → "Ba"("NO"_3)_2 +"2H"_2"O"#</mathjax></p> <p><mathjax>#"Moles of Ba(OH)"_2 = "0.013 01" color(red)(cancel(color(black)("L Ba(OH)"_2))) × "0.1326 mol Ba(OH)"_2/(1 color(red)(cancel(color(black)("L Ba(OH)"_2)))) = "0.001 725 mol Ba(OH)"_2#</mathjax></p> <p><mathjax>#"Moles of HNO"_3 = "0.0017 25" color(red)(cancel(color(black)("mol Ba(OH)"_2))) × "2 mol HNO"_3/(1 color(red)(cancel(color(black)("mol Ba(OH)"_2)))) = "0.003 450 mol HNO"_3#</mathjax></p> <p><mathjax>#"Molarity of HNO"_3 = "moles"/"litres" = "0.003 450 mol"/"0.0297 L" = "0.116 mol/L"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the nitric acid was 0.116 mol/L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This is really a two-part question:</p> <ol> <li>What is the molarity of the barium hydroxide solution?</li> <li>What is the molarity of the nitric acid?</li> </ol> <blockquote></blockquote> <p><strong>1. Molarity of <mathjax>#"Ba(OH)"_2#</mathjax></strong></p> <p>The formula for molarity is </p> <blockquote> <blockquote> <p><mathjax>#color(blue)(|bar(ul(color(white)(a/a) "Molarity" = "moles"/"litres"color(white)(a/a)|)))" "#</mathjax></p> </blockquote> </blockquote> <p><mathjax>#"Moles of Ba(OH)"_2 = 5.68 color(red)(cancel(color(black)("g Ba(OH)"_2))) × "1 mol Ba(OH)"_2/(171.34 color(red)(cancel(color(black)("g Ba(OH)"_2)))) = "0.033 15 mol Ba(OH)"_2#</mathjax></p> <p><mathjax>#"Volume" = "250 mL" = "0.250 L"#</mathjax></p> <p><mathjax>#"Molarity" = "moles"/"litres" = "0.033 15 mol"/"0.250 L" = "0.1326 mol/L"#</mathjax></p> <blockquote></blockquote> <p><strong>2. Molarity of <mathjax>#"HNO"_3#</mathjax></strong></p> <p>The equation for the <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a> reaction is</p> <p><mathjax>#"Ba(OH)"_2 + "2HNO"_3 → "Ba"("NO"_3)_2 +"2H"_2"O"#</mathjax></p> <p><mathjax>#"Moles of Ba(OH)"_2 = "0.013 01" color(red)(cancel(color(black)("L Ba(OH)"_2))) × "0.1326 mol Ba(OH)"_2/(1 color(red)(cancel(color(black)("L Ba(OH)"_2)))) = "0.001 725 mol Ba(OH)"_2#</mathjax></p> <p><mathjax>#"Moles of HNO"_3 = "0.0017 25" color(red)(cancel(color(black)("mol Ba(OH)"_2))) × "2 mol HNO"_3/(1 color(red)(cancel(color(black)("mol Ba(OH)"_2)))) = "0.003 450 mol HNO"_3#</mathjax></p> <p><mathjax>#"Molarity of HNO"_3 = "moles"/"litres" = "0.003 450 mol"/"0.0297 L" = "0.116 mol/L"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you calculate the molarity of the #HNO_3# solution?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>A pure sample of barium hydroxide of mass 5.68 g was dissolved and diluted to the mark in a 250 mL volumetric flask. It was found that 13.01 mL of this solution was needed to reach the stoichiometric point in a titration of 29.7 mL of a nitric acid solution. </p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/titration-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Titration Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="281570" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-26T16:21:48" itemprop="dateCreated"> Jun 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of the nitric acid was 0.116 mol/L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>This is really a two-part question:</p> <ol> <li>What is the molarity of the barium hydroxide solution?</li> <li>What is the molarity of the nitric acid?</li> </ol> <blockquote></blockquote> <p><strong>1. Molarity of <mathjax>#"Ba(OH)"_2#</mathjax></strong></p> <p>The formula for molarity is </p> <blockquote> <blockquote> <p><mathjax>#color(blue)(|bar(ul(color(white)(a/a) "Molarity" = "moles"/"litres"color(white)(a/a)|)))" "#</mathjax></p> </blockquote> </blockquote> <p><mathjax>#"Moles of Ba(OH)"_2 = 5.68 color(red)(cancel(color(black)("g Ba(OH)"_2))) × "1 mol Ba(OH)"_2/(171.34 color(red)(cancel(color(black)("g Ba(OH)"_2)))) = "0.033 15 mol Ba(OH)"_2#</mathjax></p> <p><mathjax>#"Volume" = "250 mL" = "0.250 L"#</mathjax></p> <p><mathjax>#"Molarity" = "moles"/"litres" = "0.033 15 mol"/"0.250 L" = "0.1326 mol/L"#</mathjax></p> <blockquote></blockquote> <p><strong>2. Molarity of <mathjax>#"HNO"_3#</mathjax></strong></p> <p>The equation for the <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a> reaction is</p> <p><mathjax>#"Ba(OH)"_2 + "2HNO"_3 → "Ba"("NO"_3)_2 +"2H"_2"O"#</mathjax></p> <p><mathjax>#"Moles of Ba(OH)"_2 = "0.013 01" color(red)(cancel(color(black)("L Ba(OH)"_2))) × "0.1326 mol Ba(OH)"_2/(1 color(red)(cancel(color(black)("L Ba(OH)"_2)))) = "0.001 725 mol Ba(OH)"_2#</mathjax></p> <p><mathjax>#"Moles of HNO"_3 = "0.0017 25" color(red)(cancel(color(black)("mol Ba(OH)"_2))) × "2 mol HNO"_3/(1 color(red)(cancel(color(black)("mol Ba(OH)"_2)))) = "0.003 450 mol HNO"_3#</mathjax></p> <p><mathjax>#"Molarity of HNO"_3 = "moles"/"litres" = "0.003 450 mol"/"0.0297 L" = "0.116 mol/L"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/281570" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-acid-base-titration-calculations"> How do you do acid base titration calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-use-titration-calculations-to-find-ph"> How do you use titration calculations to find pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/radox-titration"> What is a redox titration and what is it used for? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-titration-used-when-standardizing-a-solution"> Why is titration used when standardizing a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-titration-suitable-for-sodium-nitrate"> Is titration suitable for sodium nitrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-do-redox-titration-calculations"> How can I do redox titration calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-titration-of-weak-acid-and-strong-base"> How can I calculate the titration of a weak acid and a strong base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-make-back-titration-calculations"> How can I make back titration calculations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-titration-affect-molarity"> How does titration affect molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-endpoint-of-a-titration-differ-from-the-equivalence-point"> How does the endpoint of a titration differ from the equivalence point? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/reactions-in-solution/titration-calculations"> See all questions in Titration Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 10091 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How do you calculate the molarity of the #HNO_3# solution?

A pure sample of barium hydroxide of mass 5.68 g was dissolved and diluted to the mark in a 250 mL volumetric flask. It was found that 13.01 mL of this solution was needed to reach the stoichiometric point in a titration of 29.7 mL of a nitric acid solution.

abda8f8c-6ddd-11ea-9c6b-ccda262736ce

https://socratic.org/questions/how-many-helium-atoms-are-in-a-helium-blimp-containing-494-kg-of-helium

7.44 × 10^28

start physical_unit 2 3 number none qc_end physical_unit 2 2 10 11 mass qc_end end

[{"type":"physical unit","value":"Number [OF] helium atoms"}]

[{"type":"physical unit","value":"7.44 × 10^28"}]

[{"type":"physical unit","value":"Mass [OF] helium [=] \\pu{494 kg}"}]

<h1 class="questionTitle" itemprop="name">How many helium atoms are in a helium blimp containing 494 kg of helium? </h1>

7.44 × 10^28

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Step 1:</strong> calculate how the number of moles using the molar mass.<br/> The molar mass of helium = <mathjax>#4.00#</mathjax> g/mol. <br/> This means that 1 mole of helium atoms weighs 4 gram. </p> <p>In this case you have <mathjax>#494#</mathjax> kg which is <mathjax>#494.000#</mathjax> grams. How many moles is this?</p> <p><mathjax>#(494.000 color(red)cancel(color(black)(gram)))/ (4.00 color(red)cancel(color(black)(gram))/(mol)) = 123.500 mol#</mathjax></p> <p><strong>Step 2</strong> : calculate the number of atoms using Avogadro's constant.<br/> Avogadro's constant states that there are <mathjax>#6.02*10^23#</mathjax> atoms in one mole of any element.</p> <p>How many atoms are in 123.500 moles?</p> <p><mathjax>#6.02*10^23 "atoms"/color(red)cancel(color(black)((mol))) * 123.500 color(red)cancel(color(black)(mol)) = 7.44*10^28 "atoms"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#7.44*10^28#</mathjax> atoms</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Step 1:</strong> calculate how the number of moles using the molar mass.<br/> The molar mass of helium = <mathjax>#4.00#</mathjax> g/mol. <br/> This means that 1 mole of helium atoms weighs 4 gram. </p> <p>In this case you have <mathjax>#494#</mathjax> kg which is <mathjax>#494.000#</mathjax> grams. How many moles is this?</p> <p><mathjax>#(494.000 color(red)cancel(color(black)(gram)))/ (4.00 color(red)cancel(color(black)(gram))/(mol)) = 123.500 mol#</mathjax></p> <p><strong>Step 2</strong> : calculate the number of atoms using Avogadro's constant.<br/> Avogadro's constant states that there are <mathjax>#6.02*10^23#</mathjax> atoms in one mole of any element.</p> <p>How many atoms are in 123.500 moles?</p> <p><mathjax>#6.02*10^23 "atoms"/color(red)cancel(color(black)((mol))) * 123.500 color(red)cancel(color(black)(mol)) = 7.44*10^28 "atoms"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many helium atoms are in a helium blimp containing 494 kg of helium? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="291238" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jo-lle"><img alt="" class="" src="https://profilepictures.socratic.org/QLjj3UhKRDegWjG5OG8v_1712995393.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jo-lle"> Joëlle </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-23T17:34:37" itemprop="dateCreated"> Jul 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#7.44*10^28#</mathjax> atoms</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Step 1:</strong> calculate how the number of moles using the molar mass.<br/> The molar mass of helium = <mathjax>#4.00#</mathjax> g/mol. <br/> This means that 1 mole of helium atoms weighs 4 gram. </p> <p>In this case you have <mathjax>#494#</mathjax> kg which is <mathjax>#494.000#</mathjax> grams. How many moles is this?</p> <p><mathjax>#(494.000 color(red)cancel(color(black)(gram)))/ (4.00 color(red)cancel(color(black)(gram))/(mol)) = 123.500 mol#</mathjax></p> <p><strong>Step 2</strong> : calculate the number of atoms using Avogadro's constant.<br/> Avogadro's constant states that there are <mathjax>#6.02*10^23#</mathjax> atoms in one mole of any element.</p> <p>How many atoms are in 123.500 moles?</p> <p><mathjax>#6.02*10^23 "atoms"/color(red)cancel(color(black)((mol))) * 123.500 color(red)cancel(color(black)(mol)) = 7.44*10^28 "atoms"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/291238" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 32608 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many helium atoms are in a helium blimp containing 494 kg of helium?

aa8628c0-6ddd-11ea-a249-ccda262736ce

https://socratic.org/questions/how-much-heat-is-transferred-when-a-24-7-kg-iron-ingot-is-cooled-from-880-c-to-1

2.3 × 10^6 cal

start physical_unit 10 11 heat_energy cal qc_end physical_unit 10 11 8 9 mass qc_end physical_unit 10 11 15 16 temperature qc_end physical_unit 10 11 18 19 temperature qc_end physical_unit 10 10 26 29 specific_heat qc_end end

[{"type":"physical unit","value":"Given off heat [OF] iron ingot [IN] cal"}]

[{"type":"physical unit","value":"2.3 × 10^6 cal"}]

[{"type":"physical unit","value":"Mass [OF] iron ingot [=] \\pu{24.7 kg}"},{"type":"physical unit","value":"Temperature1 [OF] iron ingot [=] \\pu{880 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] iron ingot [=] \\pu{13 ℃}"},{"type":"physical unit","value":"Specific heat [OF] iron [=] \\pu{0.107 cal/(g * ℃)}"}]

<h1 class="questionTitle" itemprop="name"> How much heat is given off when a 24.7 kg iron ingot is cooled from 880°C to 13°C? </h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The specific heat of iron is 0.107 cal/g * °C.</p></div> </h2> </div> </div>

2.3 × 10^6 cal

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Notice that the problem provides you with the mass of the iron ingot, but that it's being expressed in <em>kilograms</em>. </p> <p>Since the <strong><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a></strong> of iron is given in <em>joules per gram Celsius</em>, <mathjax>#"J g"^(-1) ""^@"C"^(-1)#</mathjax>, you must convert the mass of the sample from <em>kilograms</em> to <em>grams</em> before doing anything else</p> <blockquote> <p><mathjax>#24.7 color(red)(cancel(color(black)("kg"))) * (10^3"g")/(1color(red)(cancel(color(black)("kg")))) = 24.7 * 10^3"g"#</mathjax></p> </blockquote> <p>Now, you can use the specific heat of iron to figure out how much heat would be <strong>released</strong> when the temperature of <mathjax>#24.7 * 10^3"g"#</mathjax> of iron decreases by <mathjax>#1^@"C"#</mathjax></p> <blockquote> <p><mathjax>#24.7 * 10^3 color(red)(cancel(color(black)("g"))) * overbrace("0.107 cal"/(1color(red)(cancel(color(black)("g"))) ""^@"C"))^(color(purple)("the specific heat of iron")) = 2.643 * 10^3"cal" ""^@"C"^(-1)#</mathjax></p> </blockquote> <p>This tells you that in order to cause a <mathjax>#1^@"C"#</mathjax> decrease in temperature to a <mathjax>#24.7 * 10^3"g"#</mathjax> sample of iron, you must remove <mathjax>#2.643 * 10^3"cal"#</mathjax> of heat. </p> <p>In your case, the temperature of the ingot must decrease by </p> <blockquote> <p><mathjax>#"change in temperature" = |13^@"C" - 880^@"C"| = 867^@"C"#</mathjax></p> </blockquote> <p>You can thus say that when the temperature of <mathjax>#2.643 * 10^3"g"#</mathjax> of iron decreases by <mathjax>#867^@"C"#</mathjax>, the process releases</p> <blockquote> <p><mathjax>#867 color(red)(cancel(color(black)(""^@"C"))) * overbrace((2.643 * 10^3"cal")/(1color(red)(cancel(color(black)(""^@"C")))))^(color(purple)("for 2.643" * 10^3"g of iron")) = color(green)(bar(ul(|color(white)(a/a)color(black)(2.3 * 10^6"cal")color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.3* 10^6"cal"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Notice that the problem provides you with the mass of the iron ingot, but that it's being expressed in <em>kilograms</em>. </p> <p>Since the <strong><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a></strong> of iron is given in <em>joules per gram Celsius</em>, <mathjax>#"J g"^(-1) ""^@"C"^(-1)#</mathjax>, you must convert the mass of the sample from <em>kilograms</em> to <em>grams</em> before doing anything else</p> <blockquote> <p><mathjax>#24.7 color(red)(cancel(color(black)("kg"))) * (10^3"g")/(1color(red)(cancel(color(black)("kg")))) = 24.7 * 10^3"g"#</mathjax></p> </blockquote> <p>Now, you can use the specific heat of iron to figure out how much heat would be <strong>released</strong> when the temperature of <mathjax>#24.7 * 10^3"g"#</mathjax> of iron decreases by <mathjax>#1^@"C"#</mathjax></p> <blockquote> <p><mathjax>#24.7 * 10^3 color(red)(cancel(color(black)("g"))) * overbrace("0.107 cal"/(1color(red)(cancel(color(black)("g"))) ""^@"C"))^(color(purple)("the specific heat of iron")) = 2.643 * 10^3"cal" ""^@"C"^(-1)#</mathjax></p> </blockquote> <p>This tells you that in order to cause a <mathjax>#1^@"C"#</mathjax> decrease in temperature to a <mathjax>#24.7 * 10^3"g"#</mathjax> sample of iron, you must remove <mathjax>#2.643 * 10^3"cal"#</mathjax> of heat. </p> <p>In your case, the temperature of the ingot must decrease by </p> <blockquote> <p><mathjax>#"change in temperature" = |13^@"C" - 880^@"C"| = 867^@"C"#</mathjax></p> </blockquote> <p>You can thus say that when the temperature of <mathjax>#2.643 * 10^3"g"#</mathjax> of iron decreases by <mathjax>#867^@"C"#</mathjax>, the process releases</p> <blockquote> <p><mathjax>#867 color(red)(cancel(color(black)(""^@"C"))) * overbrace((2.643 * 10^3"cal")/(1color(red)(cancel(color(black)(""^@"C")))))^(color(purple)("for 2.643" * 10^3"g of iron")) = color(green)(bar(ul(|color(white)(a/a)color(black)(2.3 * 10^6"cal")color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name"> How much heat is given off when a 24.7 kg iron ingot is cooled from 880°C to 13°C? </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The specific heat of iron is 0.107 cal/g * °C.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="310656" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-15T23:56:31" itemprop="dateCreated"> Sep 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.3* 10^6"cal"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Notice that the problem provides you with the mass of the iron ingot, but that it's being expressed in <em>kilograms</em>. </p> <p>Since the <strong><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a></strong> of iron is given in <em>joules per gram Celsius</em>, <mathjax>#"J g"^(-1) ""^@"C"^(-1)#</mathjax>, you must convert the mass of the sample from <em>kilograms</em> to <em>grams</em> before doing anything else</p> <blockquote> <p><mathjax>#24.7 color(red)(cancel(color(black)("kg"))) * (10^3"g")/(1color(red)(cancel(color(black)("kg")))) = 24.7 * 10^3"g"#</mathjax></p> </blockquote> <p>Now, you can use the specific heat of iron to figure out how much heat would be <strong>released</strong> when the temperature of <mathjax>#24.7 * 10^3"g"#</mathjax> of iron decreases by <mathjax>#1^@"C"#</mathjax></p> <blockquote> <p><mathjax>#24.7 * 10^3 color(red)(cancel(color(black)("g"))) * overbrace("0.107 cal"/(1color(red)(cancel(color(black)("g"))) ""^@"C"))^(color(purple)("the specific heat of iron")) = 2.643 * 10^3"cal" ""^@"C"^(-1)#</mathjax></p> </blockquote> <p>This tells you that in order to cause a <mathjax>#1^@"C"#</mathjax> decrease in temperature to a <mathjax>#24.7 * 10^3"g"#</mathjax> sample of iron, you must remove <mathjax>#2.643 * 10^3"cal"#</mathjax> of heat. </p> <p>In your case, the temperature of the ingot must decrease by </p> <blockquote> <p><mathjax>#"change in temperature" = |13^@"C" - 880^@"C"| = 867^@"C"#</mathjax></p> </blockquote> <p>You can thus say that when the temperature of <mathjax>#2.643 * 10^3"g"#</mathjax> of iron decreases by <mathjax>#867^@"C"#</mathjax>, the process releases</p> <blockquote> <p><mathjax>#867 color(red)(cancel(color(black)(""^@"C"))) * overbrace((2.643 * 10^3"cal")/(1color(red)(cancel(color(black)(""^@"C")))))^(color(purple)("for 2.643" * 10^3"g of iron")) = color(green)(bar(ul(|color(white)(a/a)color(black)(2.3 * 10^6"cal")color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/310656" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-read-differential-scanning-in-calorimetry"> What information do you get from a differential scanning calorimetry plot? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-calorimetry"> How do you measure calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531d304102bf341e75b962a7"> Question #962a7 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5335021802bf344ae911dfc5"> Question #1dfc5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668f502bf34572c341af6"> Question #41af6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-definition-of-calorimetry"> What is calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-differential-scanning-calorimeter"> What is a differential scanning calorimeter? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-calorimeter-measure-energy"> How can a calorimeter measure energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-calorimeters-made-of"> What are calorimeters made of? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/calorimetry"> See all questions in Calorimetry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4261 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How much heat is given off when a 24.7 kg iron ingot is cooled from 880°C to 13°C?

The specific heat of iron is 0.107 cal/g * °C.

a9d87b3e-6ddd-11ea-a105-ccda262736ce

https://socratic.org/questions/how-many-liters-of-c-3h-8-are-in-1-505-x-10-23-molecules-of-c-3h-8

5.60 liters

start physical_unit 4 4 volume l qc_end end

[{"type":"physical unit","value":"Volume [OF] C3H8 [IN] liters"}]

[{"type":"physical unit","value":"5.60 liters"}]

[{"type":"physical unit","value":"Number [OF] C3H8 molecules [=] \\pu{1.505 × 10^23}"}]

<h1 class="questionTitle" itemprop="name">How many liters of #C_3H_8# are in #1.505 xx 10^23# molecules of #C_3H_8#?</h1>

5.60 liters

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>There are <mathjax>#6.02 * 1 0^23#</mathjax> molecules in a mole, therefore <mathjax>#1.505*10^23#</mathjax> molecules constitute 0.25 moles.<br/> One mole of ideal gas at STP occupies 22.41 liters, therefore 0.25 moles of propane gas has a volume of 5.6 liters</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>5.6 liters</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>There are <mathjax>#6.02 * 1 0^23#</mathjax> molecules in a mole, therefore <mathjax>#1.505*10^23#</mathjax> molecules constitute 0.25 moles.<br/> One mole of ideal gas at STP occupies 22.41 liters, therefore 0.25 moles of propane gas has a volume of 5.6 liters</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many liters of #C_3H_8# are in #1.505 xx 10^23# molecules of #C_3H_8#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="591430" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/il-maestro"><img alt="" class="" src="https://profilepictures.socratic.org/oYBS23uRcXBi586nTXQi_400405_3781938059986_310806394_n.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/il-maestro"> il maestro </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-04-09T16:24:39" itemprop="dateCreated"> Apr 9, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>5.6 liters</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>There are <mathjax>#6.02 * 1 0^23#</mathjax> molecules in a mole, therefore <mathjax>#1.505*10^23#</mathjax> molecules constitute 0.25 moles.<br/> One mole of ideal gas at STP occupies 22.41 liters, therefore 0.25 moles of propane gas has a volume of 5.6 liters</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/591430" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? 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How many liters of #C_3H_8# are in #1.505 xx 10^23# molecules of #C_3H_8#?

a8a01c66-6ddd-11ea-8a54-ccda262736ce

https://socratic.org/questions/what-is-the-vapor-pressure-in-mmhg-of-a-solution-of-16-0-g-of-glucose-c6h12o6-in

135.2 mmHg

start physical_unit 30 31 vapor_pressure mmhg qc_end physical_unit 15 15 11 12 mass qc_end physical_unit 21 21 17 18 mass qc_end physical_unit 21 21 23 25 temperature qc_end physical_unit 30 31 37 38 vapor_pressure qc_end physical_unit 30 31 23 25 temperature qc_end end

[{"type":"physical unit","value":"vapor pressure [OF] pure methanol [IN] mmHg"}]

[{"type":"physical unit","value":"135.2 mmHg"}]

[{"type":"physical unit","value":"mass [OF] C6H12O6 [=] \\pu{16.0 g}"},{"type":"physical unit","value":"mass [OF] CH3OH [=] \\pu{80.0 g}"},{"type":"physical unit","value":"Temperture [OF] CH3OH [=] \\pu{27 degrees C}"},{"type":"physical unit","value":"Vapor pressure [OF] pure methanol [=] \\pu{140 mmHg}"},{"type":"physical unit","value":"Temperture [OF] pure methanol [=] \\pu{27 degrees C}"}]

<h1 class="questionTitle" itemprop="name">What is the vapor pressure in mmHg of a solution of 16.0 g of glucose (C6H12O6) in 80.0 g of methanol (CH3OH) at 27 degrees C? The vapor pressure of pure methanol at 27 degrees C is 140 mmHg. </h1>

135.2 mmHg

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to be able to determine the <a href="https://socratic.org/chemistry/phases-of-matter/vapor-pressure-and-boiling">vapor pressure</a> of this solution, you need to know two things</p> <ul> <li><em>the vapor pressure of pure methanol at <mathjax>#27^@"C"#</mathjax> - given to you as <mathjax>#"140 mmHg"#</mathjax></em></li> <li><em>the <strong>mole fraction</strong> of methanol in the solution</em></li> </ul> <p>As you know, the vapor pressure of a solution that contains a <strong>non-volatile <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></strong> will depend exclusively on <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fraction of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>, which in your case is methanol, and on the pure solvent's vapor pressure at that temperature</p> <blockquote> <p><mathjax>#color(blue)(P_"sol" = chi_"solvent" xx P_"solvent"^@)#</mathjax></p> </blockquote> <p>The <strong>mole fraction</strong> of the solvent will be equal to the number of moles of solvent divided by the <em>total number of moles</em> present in solution. </p> <p>Use the molar masses of the two <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> to determine how many moles of each you have</p> <blockquote> <p><mathjax>#16.0 color(red)(cancel(color(black)("g"))) * ("1 mole C"_6"H"_12"O"_6)/(180.16color(red)(cancel(color(black)("g")))) = "0.08881 moles C"_6"H"_12"O"_6#</mathjax></p> <p><mathjax>#80.0color(red)(cancel(color(black)("g"))) * ("1 mole CH"_3"OH")/(32.04color(red)(cancel(color(black)("g")))) = "2.4969 moles CH"_3"OH"#</mathjax></p> </blockquote> <p>The <strong>total number of moles</strong> present in solution will be </p> <blockquote> <p><mathjax>#n_"total" = n_"glucose" + n_"methanol"#</mathjax></p> <p><mathjax>#n_"total" = 0.08881 + 2.4969 = "2.5857 moles"#</mathjax></p> </blockquote> <p>The mole fraction of methanol will be </p> <blockquote> <p><mathjax>#chi_"methanol" = (2.4969 color(red)(cancel(color(black)("moles"))))/(2.5857color(red)(cancel(color(black)("moles")))) = 0.9657#</mathjax></p> </blockquote> <p>The vapor pressure of the solution will thus be </p> <blockquote> <p><mathjax>#P_"sol" = 0.9657 * "140 mmHg" = "135.2 mmHg"#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, despite the fact that you only have two sig figs for the vapor pressure of the pure solvent</p> <blockquote> <p><mathjax>#P_"sol" = color(green)("135 mmHg")#</mathjax></p> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_"sol" = "135 mmHg"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to be able to determine the <a href="https://socratic.org/chemistry/phases-of-matter/vapor-pressure-and-boiling">vapor pressure</a> of this solution, you need to know two things</p> <ul> <li><em>the vapor pressure of pure methanol at <mathjax>#27^@"C"#</mathjax> - given to you as <mathjax>#"140 mmHg"#</mathjax></em></li> <li><em>the <strong>mole fraction</strong> of methanol in the solution</em></li> </ul> <p>As you know, the vapor pressure of a solution that contains a <strong>non-volatile <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></strong> will depend exclusively on <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fraction of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>, which in your case is methanol, and on the pure solvent's vapor pressure at that temperature</p> <blockquote> <p><mathjax>#color(blue)(P_"sol" = chi_"solvent" xx P_"solvent"^@)#</mathjax></p> </blockquote> <p>The <strong>mole fraction</strong> of the solvent will be equal to the number of moles of solvent divided by the <em>total number of moles</em> present in solution. </p> <p>Use the molar masses of the two <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> to determine how many moles of each you have</p> <blockquote> <p><mathjax>#16.0 color(red)(cancel(color(black)("g"))) * ("1 mole C"_6"H"_12"O"_6)/(180.16color(red)(cancel(color(black)("g")))) = "0.08881 moles C"_6"H"_12"O"_6#</mathjax></p> <p><mathjax>#80.0color(red)(cancel(color(black)("g"))) * ("1 mole CH"_3"OH")/(32.04color(red)(cancel(color(black)("g")))) = "2.4969 moles CH"_3"OH"#</mathjax></p> </blockquote> <p>The <strong>total number of moles</strong> present in solution will be </p> <blockquote> <p><mathjax>#n_"total" = n_"glucose" + n_"methanol"#</mathjax></p> <p><mathjax>#n_"total" = 0.08881 + 2.4969 = "2.5857 moles"#</mathjax></p> </blockquote> <p>The mole fraction of methanol will be </p> <blockquote> <p><mathjax>#chi_"methanol" = (2.4969 color(red)(cancel(color(black)("moles"))))/(2.5857color(red)(cancel(color(black)("moles")))) = 0.9657#</mathjax></p> </blockquote> <p>The vapor pressure of the solution will thus be </p> <blockquote> <p><mathjax>#P_"sol" = 0.9657 * "140 mmHg" = "135.2 mmHg"#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, despite the fact that you only have two sig figs for the vapor pressure of the pure solvent</p> <blockquote> <p><mathjax>#P_"sol" = color(green)("135 mmHg")#</mathjax></p> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the vapor pressure in mmHg of a solution of 16.0 g of glucose (C6H12O6) in 80.0 g of methanol (CH3OH) at 27 degrees C? The vapor pressure of pure methanol at 27 degrees C is 140 mmHg. </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/colligative-properties" itemprop="url"> <span class="breadcrumb" itemprop="title">Colligative Properties</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="199870" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-14T23:40:50" itemprop="dateCreated"> Dec 14, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_"sol" = "135 mmHg"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to be able to determine the <a href="https://socratic.org/chemistry/phases-of-matter/vapor-pressure-and-boiling">vapor pressure</a> of this solution, you need to know two things</p> <ul> <li><em>the vapor pressure of pure methanol at <mathjax>#27^@"C"#</mathjax> - given to you as <mathjax>#"140 mmHg"#</mathjax></em></li> <li><em>the <strong>mole fraction</strong> of methanol in the solution</em></li> </ul> <p>As you know, the vapor pressure of a solution that contains a <strong>non-volatile <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></strong> will depend exclusively on <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fraction of the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>, which in your case is methanol, and on the pure solvent's vapor pressure at that temperature</p> <blockquote> <p><mathjax>#color(blue)(P_"sol" = chi_"solvent" xx P_"solvent"^@)#</mathjax></p> </blockquote> <p>The <strong>mole fraction</strong> of the solvent will be equal to the number of moles of solvent divided by the <em>total number of moles</em> present in solution. </p> <p>Use the molar masses of the two <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> to determine how many moles of each you have</p> <blockquote> <p><mathjax>#16.0 color(red)(cancel(color(black)("g"))) * ("1 mole C"_6"H"_12"O"_6)/(180.16color(red)(cancel(color(black)("g")))) = "0.08881 moles C"_6"H"_12"O"_6#</mathjax></p> <p><mathjax>#80.0color(red)(cancel(color(black)("g"))) * ("1 mole CH"_3"OH")/(32.04color(red)(cancel(color(black)("g")))) = "2.4969 moles CH"_3"OH"#</mathjax></p> </blockquote> <p>The <strong>total number of moles</strong> present in solution will be </p> <blockquote> <p><mathjax>#n_"total" = n_"glucose" + n_"methanol"#</mathjax></p> <p><mathjax>#n_"total" = 0.08881 + 2.4969 = "2.5857 moles"#</mathjax></p> </blockquote> <p>The mole fraction of methanol will be </p> <blockquote> <p><mathjax>#chi_"methanol" = (2.4969 color(red)(cancel(color(black)("moles"))))/(2.5857color(red)(cancel(color(black)("moles")))) = 0.9657#</mathjax></p> </blockquote> <p>The vapor pressure of the solution will thus be </p> <blockquote> <p><mathjax>#P_"sol" = 0.9657 * "140 mmHg" = "135.2 mmHg"#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, despite the fact that you only have two sig figs for the vapor pressure of the pure solvent</p> <blockquote> <p><mathjax>#P_"sol" = color(green)("135 mmHg")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/199870" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div 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What is the vapor pressure in mmHg of a solution of 16.0 g of glucose (C6H12O6) in 80.0 g of methanol (CH3OH) at 27 degrees C? The vapor pressure of pure methanol at 27 degrees C is 140 mmHg.

ab2828ae-6ddd-11ea-8167-ccda262736ce

https://socratic.org/questions/if-17-8-grams-of-koh-dissolve-in-enough-water-to-make-a-198-gram-solution-what-i

8.99%

start physical_unit 4 4 mass_percent none qc_end physical_unit 4 4 1 2 mass qc_end physical_unit 14 14 12 13 mass qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Percent by mass [OF] KOH in solution"}]

[{"type":"physical unit","value":"8.99%"}]

[{"type":"physical unit","value":"Mass [OF] KOH [=] \\pu{17.8 grams}"},{"type":"physical unit","value":"Mass [OF] solution [=] \\pu{198 gram}"},{"type":"other","value":"Enough water."}]

<h1 class="questionTitle" itemprop="name">If 17.8 grams of #KOH# dissolve in enough water to make a 198-gram solution, what is the concentration in percent by mass?</h1>

8.99%

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The formula to use is</p> <blockquote> <p><mathjax>#color(blue)(|bar(ul(color(white)(a/a) "% by mass" = "mass of component"/"total mass of sample" × 100 %color(white)(a/a)|)))" "#</mathjax></p> </blockquote> <p>For your solution,</p> <p><mathjax>#"% by mass" = (17.8 color(red)(cancel(color(black)("g"))))/(198 color(red)(cancel(color(black)("g")))) × 100 % = 8.99 %#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The concentration of <mathjax>#"KOH"#</mathjax> is 8.99 % by mass.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The formula to use is</p> <blockquote> <p><mathjax>#color(blue)(|bar(ul(color(white)(a/a) "% by mass" = "mass of component"/"total mass of sample" × 100 %color(white)(a/a)|)))" "#</mathjax></p> </blockquote> <p>For your solution,</p> <p><mathjax>#"% by mass" = (17.8 color(red)(cancel(color(black)("g"))))/(198 color(red)(cancel(color(black)("g")))) × 100 % = 8.99 %#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If 17.8 grams of #KOH# dissolve in enough water to make a 198-gram solution, what is the concentration in percent by mass?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="269572" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-25T15:14:36" itemprop="dateCreated"> May 25, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The concentration of <mathjax>#"KOH"#</mathjax> is 8.99 % by mass.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The formula to use is</p> <blockquote> <p><mathjax>#color(blue)(|bar(ul(color(white)(a/a) "% by mass" = "mass of component"/"total mass of sample" × 100 %color(white)(a/a)|)))" "#</mathjax></p> </blockquote> <p>For your solution,</p> <p><mathjax>#"% by mass" = (17.8 color(red)(cancel(color(black)("g"))))/(198 color(red)(cancel(color(black)("g")))) × 100 % = 8.99 %#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/269572" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? 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If 17.8 grams of #KOH# dissolve in enough water to make a 198-gram solution, what is the concentration in percent by mass?

ac574df1-6ddd-11ea-9a56-ccda262736ce

https://socratic.org/questions/how-do-you-calculate-the-number-of-mol-corresponding-to-6-2-g-h-2

3.10 mol

start physical_unit 12 12 mole mol qc_end physical_unit 12 12 10 11 mass qc_end end

[{"type":"physical unit","value":"Mole [OF] H2 [IN] mol"}]

[{"type":"physical unit","value":"3.10 mol"}]

[{"type":"physical unit","value":"Mass [OF] H2 [=] \\pu{6.2 g}"}]

<h1 class="questionTitle" itemprop="name">How do you calculate the number of mol corresponding to 6.2 g #H_2#?</h1>

3.10 mol

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You must note that hydrogen gas (like oxygen, nitrogen, chlorine and others) exists in the gas phase in the form of diatomic (two-atom) molecules.</p> <p>So, if you look up the molar mass of hydrogen on a periodic table, you must multiply by two (the number of hydrogen atoms in each molecule) to obtain the mass of one mole of hydrogen gas.</p> <p>Then as you would for any molecule, divide the given mass by the molar mass to get the number of moles of that substance.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Divide the given mass (6.2 g) by the molar mass of hydrogen gas, which is 2.0 g, and you get 3.1 moles.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You must note that hydrogen gas (like oxygen, nitrogen, chlorine and others) exists in the gas phase in the form of diatomic (two-atom) molecules.</p> <p>So, if you look up the molar mass of hydrogen on a periodic table, you must multiply by two (the number of hydrogen atoms in each molecule) to obtain the mass of one mole of hydrogen gas.</p> <p>Then as you would for any molecule, divide the given mass by the molar mass to get the number of moles of that substance.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you calculate the number of mol corresponding to 6.2 g #H_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="386950" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/dwight"><img alt="" class="" src="https://profilepictures.socratic.org/ZDiTFWmAQmWOT3sd0Xpr_Dwight.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/dwight"> Dwight </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-05T16:18:52" itemprop="dateCreated"> Mar 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Divide the given mass (6.2 g) by the molar mass of hydrogen gas, which is 2.0 g, and you get 3.1 moles.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You must note that hydrogen gas (like oxygen, nitrogen, chlorine and others) exists in the gas phase in the form of diatomic (two-atom) molecules.</p> <p>So, if you look up the molar mass of hydrogen on a periodic table, you must multiply by two (the number of hydrogen atoms in each molecule) to obtain the mass of one mole of hydrogen gas.</p> <p>Then as you would for any molecule, divide the given mass by the molar mass to get the number of moles of that substance.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/386950" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? 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How do you calculate the number of mol corresponding to 6.2 g #H_2#?

a8f03b8a-6ddd-11ea-9a3e-ccda262736ce

https://socratic.org/questions/what-is-the-molarity-of-a-sulfuric-acid-solution-prepared-by-diluting-500-0-ml-o

2.00 mol/L

start physical_unit 17 17 molarity mol/l qc_end physical_unit 17 17 15 16 molarity qc_end physical_unit 8 8 12 13 volume qc_end physical_unit 8 8 23 24 volume qc_end end

[{"type":"physical unit","value":"Molarity2 [OF] H2SO4 solution [IN] mol/L"}]

[{"type":"physical unit","value":"2.00 mol/L"}]

[{"type":"physical unit","value":"Molarity1 [OF] H2SO4 solution [=] \\pu{1.00 M}"},{"type":"physical unit","value":"Volume1 [OF] H2SO4 solution [=] \\pu{500.0 mL}"},{"type":"physical unit","value":"Volume2 [OF] H2SO4 solution [=] \\pu{2.50 L}"}]

<h1 class="questionTitle" itemprop="name">What is the molarity of a sulfuric acid solution prepared by diluting 500.0 mL of 1.00 M H2SO4 to a total volume of 2.50 L? </h1>

2.00 mol/L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute"/"Volume of solution"#</mathjax>, and thus has the units of <mathjax>#mol*L^-1#</mathjax>.</p> <p>So we work out this quotient with respect to the given conditions:</p> <p><mathjax>#(500xx10^-3*cancelLxx1.00*mol*L^-1)/(2.50*cancelL)=2.00*mol*L^-1#</mathjax>. At least our answer is dimensionally consistent. </p> <p>Note that the given concentration is with respect to <mathjax>#"sulfuric acid"#</mathjax>. What would it be with respect to <mathjax>#SO_4^(2-)#</mathjax>, and to <mathjax>#H_3O^+#</mathjax>?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Molarity"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.00*mol*L^-1#</mathjax> with respect to <mathjax>#"sulfuric acid"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute"/"Volume of solution"#</mathjax>, and thus has the units of <mathjax>#mol*L^-1#</mathjax>.</p> <p>So we work out this quotient with respect to the given conditions:</p> <p><mathjax>#(500xx10^-3*cancelLxx1.00*mol*L^-1)/(2.50*cancelL)=2.00*mol*L^-1#</mathjax>. At least our answer is dimensionally consistent. </p> <p>Note that the given concentration is with respect to <mathjax>#"sulfuric acid"#</mathjax>. What would it be with respect to <mathjax>#SO_4^(2-)#</mathjax>, and to <mathjax>#H_3O^+#</mathjax>?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the molarity of a sulfuric acid solution prepared by diluting 500.0 mL of 1.00 M H2SO4 to a total volume of 2.50 L? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="337885" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-17T15:35:04" itemprop="dateCreated"> Nov 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Molarity"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.00*mol*L^-1#</mathjax> with respect to <mathjax>#"sulfuric acid"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute"/"Volume of solution"#</mathjax>, and thus has the units of <mathjax>#mol*L^-1#</mathjax>.</p> <p>So we work out this quotient with respect to the given conditions:</p> <p><mathjax>#(500xx10^-3*cancelLxx1.00*mol*L^-1)/(2.50*cancelL)=2.00*mol*L^-1#</mathjax>. At least our answer is dimensionally consistent. </p> <p>Note that the given concentration is with respect to <mathjax>#"sulfuric acid"#</mathjax>. What would it be with respect to <mathjax>#SO_4^(2-)#</mathjax>, and to <mathjax>#H_3O^+#</mathjax>?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/337885" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6301 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the molarity of a sulfuric acid solution prepared by diluting 500.0 mL of 1.00 M H2SO4 to a total volume of 2.50 L?

abca5326-6ddd-11ea-8566-ccda262736ce

https://socratic.org/questions/a-1-15-mol-sample-of-carbon-monoxide-gas-has-a-temperature-of-27-c-and-a-pressur

0.29 atm

start physical_unit 3 7 pressure atm qc_end physical_unit 3 7 1 2 mole qc_end physical_unit 3 7 12 13 temperature qc_end physical_unit 3 7 18 19 pressure qc_end physical_unit 3 7 26 27 temperature qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Pressure2 [OF] carbon monoxide gas sample [IN] atm"}]

[{"type":"physical unit","value":"0.29 atm"}]

[{"type":"physical unit","value":"Mole [OF] carbon monoxide gas sample [=] \\pu{1.15 mol}"},{"type":"physical unit","value":"Temperature1 [OF] carbon monoxide gas sample [=] \\pu{27 ℃}"},{"type":"physical unit","value":"Pressure1 [OF] carbon monoxide gas sample [=] \\pu{0.300 atm}"},{"type":"physical unit","value":"Temperature2 [OF] carbon monoxide gas sample [=] \\pu{17 ℃}"},{"type":"other","value":"Constant volume."}]

<h1 class="questionTitle" itemprop="name">A 1.15 mol sample of carbon monoxide gas has a temperature of 27°C and a pressure of 0.300 atm. If the temperature were lowered to 17°C, at constant volume, what would be the new pressure?</h1>

0.29 atm

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of Gay-Lussac's gas law, which states that the pressure of a given amount of gas kept at constant volume is directly proportional to the temperature in Kelvins. </p> <p>The equation for this gas law is <mathjax>#(P_1)/(T_1)=(P_2)/(T_2)#</mathjax>. Notice that the number of moles is not a variable in the equation. The number of moles was given to indicate that the <mathjax>#"1.15 mol CO"_2"#</mathjax> does not change, and is the "given amount of gas."</p> <p>Determine the known and unknown values.</p> <p><strong>Known</strong><br/> <mathjax>#P_1="0.300 atm"#</mathjax><br/> <mathjax>#T_1="27"^@"C"+"273.15"="300 K"#</mathjax><br/> <mathjax>#T_2="17"^@"C"+"273.15"="290 K"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#P_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#P_2#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#P_2=(P_1T_2)/(T_1)#</mathjax></p> <p><mathjax>#P_2=((0.300"atm")xx(290cancel"K"))/(300cancel"K")="0.29 atm"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new pressure will be <strong>0.29 atm</strong> .</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of Gay-Lussac's gas law, which states that the pressure of a given amount of gas kept at constant volume is directly proportional to the temperature in Kelvins. </p> <p>The equation for this gas law is <mathjax>#(P_1)/(T_1)=(P_2)/(T_2)#</mathjax>. Notice that the number of moles is not a variable in the equation. The number of moles was given to indicate that the <mathjax>#"1.15 mol CO"_2"#</mathjax> does not change, and is the "given amount of gas."</p> <p>Determine the known and unknown values.</p> <p><strong>Known</strong><br/> <mathjax>#P_1="0.300 atm"#</mathjax><br/> <mathjax>#T_1="27"^@"C"+"273.15"="300 K"#</mathjax><br/> <mathjax>#T_2="17"^@"C"+"273.15"="290 K"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#P_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#P_2#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#P_2=(P_1T_2)/(T_1)#</mathjax></p> <p><mathjax>#P_2=((0.300"atm")xx(290cancel"K"))/(300cancel"K")="0.29 atm"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A 1.15 mol sample of carbon monoxide gas has a temperature of 27°C and a pressure of 0.300 atm. If the temperature were lowered to 17°C, at constant volume, what would be the new pressure?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gay-lussac-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Gay Lussac's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="319939" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-10T06:55:37" itemprop="dateCreated"> Oct 10, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new pressure will be <strong>0.29 atm</strong> .</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is an example of Gay-Lussac's gas law, which states that the pressure of a given amount of gas kept at constant volume is directly proportional to the temperature in Kelvins. </p> <p>The equation for this gas law is <mathjax>#(P_1)/(T_1)=(P_2)/(T_2)#</mathjax>. Notice that the number of moles is not a variable in the equation. The number of moles was given to indicate that the <mathjax>#"1.15 mol CO"_2"#</mathjax> does not change, and is the "given amount of gas."</p> <p>Determine the known and unknown values.</p> <p><strong>Known</strong><br/> <mathjax>#P_1="0.300 atm"#</mathjax><br/> <mathjax>#T_1="27"^@"C"+"273.15"="300 K"#</mathjax><br/> <mathjax>#T_2="17"^@"C"+"273.15"="290 K"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#P_2#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#P_2#</mathjax>. Substitute the known values into the equation and solve.</p> <p><mathjax>#P_2=(P_1T_2)/(T_1)#</mathjax></p> <p><mathjax>#P_2=((0.300"atm")xx(290cancel"K"))/(300cancel"K")="0.29 atm"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/319939" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535d701102bf342f53d9bcb0"> Question #9bcb0 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-gay-lussac-s-law-formula"> What is the Gay Lussac's law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-temperature-of-a-gas-in-a-container-is-doubled-on-the-kelvin-scale-the-pr"> If the temperature of a gas in a container is doubled on the Kelvin scale, what will happen to... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-the-original-pressure-of-a-gas-sample-at-20-c-was-5-00-atm-and-it-is-heated-u"> If the original pressure of a gas sample at 20 ˚C was 5.00 atm, and it is heated up to 40. ˚C ,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-gay-lussac-s-law-state"> What does Gay Lussac's law state? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-gay-lussac-s-law-relate"> What does Gay Lussac's law relate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-sample-of-o2-under-2-00-atm-occupies-500-ml-at-25-0-c-what-pressure-will-the-s"> A sample of O2 under 2.00 atm occupies 500 ml at 25.0˚C. 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A 1.15 mol sample of carbon monoxide gas has a temperature of 27°C and a pressure of 0.300 atm. If the temperature were lowered to 17°C, at constant volume, what would be the new pressure?

a908b050-6ddd-11ea-9d5f-ccda262736ce

https://socratic.org/questions/591c04cdb72cff2f9dfdee0c

6.63 × 10^(-5) mol/L

start physical_unit 6 7 molarity mol/l qc_end physical_unit 18 20 13 14 molarity qc_end end

[{"type":"physical unit","value":"Molar concentration [OF] potassium ion [IN] mol/L"}]

[{"type":"physical unit","value":"6.63 × 10^(-5) mol/L"}]

[{"type":"physical unit","value":"Molar concentration [OF] K3[Fe(C ≡ N)6] [=] \\pu{73 ppm}"}]

<h1 class="questionTitle" itemprop="name">What is the molar concentration of potassium ion in a solution that is #73*"ppm"# with respect to #K_3[Fe(C-=N)_6]#?</h1>

6.63 × 10^(-5) mol/L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus in <mathjax>#1*L#</mathjax> of solution, we have............</p> <p><mathjax>#((73xx10^-3*g)/(329.24*g*mol^-1))/(1*L)=2.21xx10^-5*mol*L^-1#</mathjax> with respect to <mathjax>#K_3[Fe(C-=N)_6]#</mathjax>.</p> <p>Since that are 3 moles of potassium ion per mole of salt, <mathjax>#[K^+]=6.7xx10^-5*mol*L^-1#</mathjax>.</p> <p>You might be tempted to argue that I should have accounted for the solution <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> in these calculations. Even if these data were available, at <mathjax>#"ppm"#</mathjax> concentrations they would make negligible difference, and so may be ignored. </p> <p>If I dissolved <mathjax>#1*g#</mathjax> of common salt, <mathjax>#NaCl#</mathjax>, in a <mathjax>#1*L#</mathjax> volume of water, what would be the <mathjax>#"ppm"#</mathjax> concentration?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1 ppm"#</mathjax> specifies <mathjax>#1*mg*L^-1#</mathjax> of solution.........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus in <mathjax>#1*L#</mathjax> of solution, we have............</p> <p><mathjax>#((73xx10^-3*g)/(329.24*g*mol^-1))/(1*L)=2.21xx10^-5*mol*L^-1#</mathjax> with respect to <mathjax>#K_3[Fe(C-=N)_6]#</mathjax>.</p> <p>Since that are 3 moles of potassium ion per mole of salt, <mathjax>#[K^+]=6.7xx10^-5*mol*L^-1#</mathjax>.</p> <p>You might be tempted to argue that I should have accounted for the solution <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> in these calculations. Even if these data were available, at <mathjax>#"ppm"#</mathjax> concentrations they would make negligible difference, and so may be ignored. </p> <p>If I dissolved <mathjax>#1*g#</mathjax> of common salt, <mathjax>#NaCl#</mathjax>, in a <mathjax>#1*L#</mathjax> volume of water, what would be the <mathjax>#"ppm"#</mathjax> concentration?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the molar concentration of potassium ion in a solution that is #73*"ppm"# with respect to #K_3[Fe(C-=N)_6]#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="425375" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-18T04:21:15" itemprop="dateCreated"> May 18, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1 ppm"#</mathjax> specifies <mathjax>#1*mg*L^-1#</mathjax> of solution.........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus in <mathjax>#1*L#</mathjax> of solution, we have............</p> <p><mathjax>#((73xx10^-3*g)/(329.24*g*mol^-1))/(1*L)=2.21xx10^-5*mol*L^-1#</mathjax> with respect to <mathjax>#K_3[Fe(C-=N)_6]#</mathjax>.</p> <p>Since that are 3 moles of potassium ion per mole of salt, <mathjax>#[K^+]=6.7xx10^-5*mol*L^-1#</mathjax>.</p> <p>You might be tempted to argue that I should have accounted for the solution <a href="https://socratic.org/chemistry/measurement-in-chemistry/density">density</a> in these calculations. Even if these data were available, at <mathjax>#"ppm"#</mathjax> concentrations they would make negligible difference, and so may be ignored. </p> <p>If I dissolved <mathjax>#1*g#</mathjax> of common salt, <mathjax>#NaCl#</mathjax>, in a <mathjax>#1*L#</mathjax> volume of water, what would be the <mathjax>#"ppm"#</mathjax> concentration?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/425375" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7721 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the molar concentration of potassium ion in a solution that is #73*"ppm"# with respect to #K_3[Fe(C-=N)_6]#?

a9c964c8-6ddd-11ea-9851-ccda262736ce

https://socratic.org/questions/how-many-moles-is-in-15-5-g-sio-2

0.26 moles

start physical_unit 7 7 mole mol qc_end physical_unit 7 7 5 6 mass qc_end end

[{"type":"physical unit","value":"Mole [OF] SiO2 [IN] moles"}]

[{"type":"physical unit","value":"0.26 moles"}]

[{"type":"physical unit","value":"Mass [OF] SiO2 [=] \\pu{15.5 g}"}]

<h1 class="questionTitle" itemprop="name">How many moles are in 15.5 g #SiO_2#?</h1>

0.26 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Silicon dioxide has a molar mass of <mathjax>#60.08#</mathjax> <mathjax>#g#</mathjax> <mathjax>#mol^-1#</mathjax>. What does this mean? It means that Avogadro's number of <mathjax>#SiO_2#</mathjax> units has a mass of <mathjax>#60.08#</mathjax> <mathjax>#g#</mathjax>.</p> <p>So to find the molar quantity of silicon dioxide, all I have to do is divide the mass by the molar mass:</p> <p><mathjax>#"Moles of silicon dioxide " = "Mass"/"Molar Mass"#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(15.5*cancelg)/(60.08*cancelg*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#mol#</mathjax></p> <p>By doing the equation with units included it helps to prevent me from making mistakes. Should I divide or should I multiply? The fact that the calculation gave me an answer in moles persuades me that I did the right thing. It's all too easy to make a mistake. </p> <p>What is silicon dioxide? How do you calculate its molar mass?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>About a 1/4 of a mole.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Silicon dioxide has a molar mass of <mathjax>#60.08#</mathjax> <mathjax>#g#</mathjax> <mathjax>#mol^-1#</mathjax>. What does this mean? It means that Avogadro's number of <mathjax>#SiO_2#</mathjax> units has a mass of <mathjax>#60.08#</mathjax> <mathjax>#g#</mathjax>.</p> <p>So to find the molar quantity of silicon dioxide, all I have to do is divide the mass by the molar mass:</p> <p><mathjax>#"Moles of silicon dioxide " = "Mass"/"Molar Mass"#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(15.5*cancelg)/(60.08*cancelg*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#mol#</mathjax></p> <p>By doing the equation with units included it helps to prevent me from making mistakes. Should I divide or should I multiply? The fact that the calculation gave me an answer in moles persuades me that I did the right thing. It's all too easy to make a mistake. </p> <p>What is silicon dioxide? How do you calculate its molar mass?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles are in 15.5 g #SiO_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="228803" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-20T07:16:02" itemprop="dateCreated"> Feb 20, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>About a 1/4 of a mole.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Silicon dioxide has a molar mass of <mathjax>#60.08#</mathjax> <mathjax>#g#</mathjax> <mathjax>#mol^-1#</mathjax>. What does this mean? It means that Avogadro's number of <mathjax>#SiO_2#</mathjax> units has a mass of <mathjax>#60.08#</mathjax> <mathjax>#g#</mathjax>.</p> <p>So to find the molar quantity of silicon dioxide, all I have to do is divide the mass by the molar mass:</p> <p><mathjax>#"Moles of silicon dioxide " = "Mass"/"Molar Mass"#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(15.5*cancelg)/(60.08*cancelg*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax> <mathjax>#mol#</mathjax></p> <p>By doing the equation with units included it helps to prevent me from making mistakes. Should I divide or should I multiply? The fact that the calculation gave me an answer in moles persuades me that I did the right thing. It's all too easy to make a mistake. </p> <p>What is silicon dioxide? How do you calculate its molar mass?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/228803" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -&gt; 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? Na2O + H2O ---&gt; 2 NaOH </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-mass-of-iron-is-needed-to-react-with-16-0-grams-of-sulfur-8-fe-s8-8-fes"> What mass of iron is needed to react with 16.0 grams of sulfur? 8 Fe + S8 ---&gt; 8 FeS </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/according-to-8-fe-s8-8-fes-how-many-grams-of-fes-are-produced"> According to 8 Fe + S8 ---&gt; 8 FeS How many grams of FeS are produced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/12-00-moles-of-naclo3-will-produce-how-many-grams-of-o2-2-naclo3-2-nacl-3-o2"> 12.00 moles of NaClO3 will produce how many grams of O2? 2 NaClO3 ---&gt; 2 NaCl + 3 O2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-nacl-are-produced-when-80-0-grams-of-o2-are-produced-2-naclo3-"> How many grams of NaCl are produced when 80.0 grams of O2 are produced? 2 NaClO3 ---&gt; 2 NaCl + 3 O2 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/stoichiometry"> See all questions in Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 13222 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many moles are in 15.5 g #SiO_2#?

a8b184fe-6ddd-11ea-94f4-ccda262736ce

https://socratic.org/questions/what-is-the-molarity-for-23-4-g-of-sodium-hydroxide-in-250-0-ml

2.34 M

start physical_unit 8 9 molarity mol/l qc_end physical_unit 8 9 5 6 mass qc_end physical_unit 8 9 11 12 volume qc_end end

[{"type":"physical unit","value":"Molarity [OF] sodium hydroxide [IN] M"}]

[{"type":"physical unit","value":"2.34 M"}]

[{"type":"physical unit","value":"Mass [OF] sodium hydroxide [=] \\pu{23.4 g}"},{"type":"physical unit","value":"Volume [OF] sodium hydroxide [=] \\pu{250.0 mL}"}]

<h1 class="questionTitle" itemprop="name">What is the molarity for 23.4 g of sodium hydroxide in 250.0 mL?</h1>

2.34 M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molecular weight of sodium hydroxide is <mathjax>#"39.997 g/mol"#</mathjax>. That is, 1 mole weights <mathjax>#"39.997 g"#</mathjax>.</p> <p>You have <mathjax>#"23.4 g"#</mathjax>, so you have </p> <blockquote> <p><mathjax>#(23.4cancel("g"))/(39.997cancel("g")/"mol") = "0.585 moles"#</mathjax>.</p> </blockquote> <p>These <mathjax>#0.585#</mathjax> moles are present in <mathjax>#"250 ml"#</mathjax>, and <mathjax>#"250 ml"#</mathjax> is equivalent to <mathjax>#0.25#</mathjax> liters.</p> <p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is moles per liter.</p> <blockquote> <p><mathjax>#"molarity" = "moles" / "litre"#</mathjax></p> <p><mathjax>#"molarity" = "0.585 moles" / "0.25 L"#</mathjax></p> <p><mathjax>#"molarity " = " 2.34 M"#</mathjax></p> </blockquote> <p>Here is a blog post on <a href="http://maths4biosciences.com/blog/concentrations/molarity-formula/" rel="nofollow">moles and molarity</a> you might like to look at.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2.34 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molecular weight of sodium hydroxide is <mathjax>#"39.997 g/mol"#</mathjax>. That is, 1 mole weights <mathjax>#"39.997 g"#</mathjax>.</p> <p>You have <mathjax>#"23.4 g"#</mathjax>, so you have </p> <blockquote> <p><mathjax>#(23.4cancel("g"))/(39.997cancel("g")/"mol") = "0.585 moles"#</mathjax>.</p> </blockquote> <p>These <mathjax>#0.585#</mathjax> moles are present in <mathjax>#"250 ml"#</mathjax>, and <mathjax>#"250 ml"#</mathjax> is equivalent to <mathjax>#0.25#</mathjax> liters.</p> <p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is moles per liter.</p> <blockquote> <p><mathjax>#"molarity" = "moles" / "litre"#</mathjax></p> <p><mathjax>#"molarity" = "0.585 moles" / "0.25 L"#</mathjax></p> <p><mathjax>#"molarity " = " 2.34 M"#</mathjax></p> </blockquote> <p>Here is a blog post on <a href="http://maths4biosciences.com/blog/concentrations/molarity-formula/" rel="nofollow">moles and molarity</a> you might like to look at.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the molarity for 23.4 g of sodium hydroxide in 250.0 mL?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="299945" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nick-41"><img alt="" class="" src="https://profilepictures.socratic.org/Sq1QmKQKSPCfDM110rRn_16.jpg" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nick-41"> Nick </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-17T18:28:33" itemprop="dateCreated"> Aug 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"2.34 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The molecular weight of sodium hydroxide is <mathjax>#"39.997 g/mol"#</mathjax>. That is, 1 mole weights <mathjax>#"39.997 g"#</mathjax>.</p> <p>You have <mathjax>#"23.4 g"#</mathjax>, so you have </p> <blockquote> <p><mathjax>#(23.4cancel("g"))/(39.997cancel("g")/"mol") = "0.585 moles"#</mathjax>.</p> </blockquote> <p>These <mathjax>#0.585#</mathjax> moles are present in <mathjax>#"250 ml"#</mathjax>, and <mathjax>#"250 ml"#</mathjax> is equivalent to <mathjax>#0.25#</mathjax> liters.</p> <p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> is moles per liter.</p> <blockquote> <p><mathjax>#"molarity" = "moles" / "litre"#</mathjax></p> <p><mathjax>#"molarity" = "0.585 moles" / "0.25 L"#</mathjax></p> <p><mathjax>#"molarity " = " 2.34 M"#</mathjax></p> </blockquote> <p>Here is a blog post on <a href="http://maths4biosciences.com/blog/concentrations/molarity-formula/" rel="nofollow">moles and molarity</a> you might like to look at.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/299945" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3106 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the molarity for 23.4 g of sodium hydroxide in 250.0 mL?

a965181c-6ddd-11ea-91d2-ccda262736ce

https://socratic.org/questions/5873cb08b72cff5facd89ba6

-282 kJ

start physical_unit 27 28 enthalpy_of_formation kj qc_end chemical_equation 1 7 qc_end physical_unit 27 28 24 25 mass qc_end end

[{"type":"physical unit","value":"Enthalpy associated with the formation [OF] carbon dioxide [IN] kJ"}]

[{"type":"physical unit","value":"-282 kJ"}]

[{"type":"chemical equation","value":"2 CO(g) + O2(g) -> 2 CO2(g)"},{"type":"physical unit","value":"DeltaH^0 [OF] the reaction [=] \\pu{-564 kJ/mol}"},{"type":"physical unit","value":"Mass [OF] carbon dioxide [=] \\pu{44.0 g}"}]

<h1 class="questionTitle" itemprop="name">Given #2CO(g) + O_2(g) rarr 2CO_2(g)# #DeltaH^@=-564*kJ*mol^-1#...what is the enthalpy associated with the formation of a mass of #44.0*g# of carbon dioxide by these means?</h1>

-282 kJ

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"2CO +O"_2rarr"2CO"_2#</mathjax> <mathjax>#;DeltaH^@=-564*kJ*mol^-1#</mathjax></p> <p><mathjax>#DeltaH^@#</mathjax> is always quoted per mole of reaction as written. That is synthesis of 2 moles of carbon dioxide from 2 moles of carbon monoxide and stoichiometric dioxygen has an associated <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change of <mathjax>#-564*kJ#</mathjax>. Because we combusted 1 mole of carbon monoxide, rather than 2 moles as specified in the equation, the enthalpy calculation is modified and HALVED.........</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#DeltaH^@=-282*kJ#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"2CO +O"_2rarr"2CO"_2#</mathjax> <mathjax>#;DeltaH^@=-564*kJ*mol^-1#</mathjax></p> <p><mathjax>#DeltaH^@#</mathjax> is always quoted per mole of reaction as written. That is synthesis of 2 moles of carbon dioxide from 2 moles of carbon monoxide and stoichiometric dioxygen has an associated <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change of <mathjax>#-564*kJ#</mathjax>. Because we combusted 1 mole of carbon monoxide, rather than 2 moles as specified in the equation, the enthalpy calculation is modified and HALVED.........</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Given #2CO(g) + O_2(g) rarr 2CO_2(g)# #DeltaH^@=-564*kJ*mol^-1#...what is the enthalpy associated with the formation of a mass of #44.0*g# of carbon dioxide by these means?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/energy-change-in-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Energy Change in Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="362290" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-09T17:52:57" itemprop="dateCreated"> Jan 9, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#DeltaH^@=-282*kJ#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"2CO +O"_2rarr"2CO"_2#</mathjax> <mathjax>#;DeltaH^@=-564*kJ*mol^-1#</mathjax></p> <p><mathjax>#DeltaH^@#</mathjax> is always quoted per mole of reaction as written. That is synthesis of 2 moles of carbon dioxide from 2 moles of carbon monoxide and stoichiometric dioxygen has an associated <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change of <mathjax>#-564*kJ#</mathjax>. Because we combusted 1 mole of carbon monoxide, rather than 2 moles as specified in the equation, the enthalpy calculation is modified and HALVED.........</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/362290" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-endothermic-reactions-happen"> Why do endothermic reactions happen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-causes-energy-changes-in-chemical-reactions"> What causes energy changes in chemical reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-endothermic-reactions-absorb-heat"> How do endothermic reactions absorb heat? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-endothermic-reaction-be-spontaneous"> How can endothermic reaction be spontaneous? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5584c3ec581e2a7bc3ecf000"> How do I relate equilibrium constants to temperature change to find the enthalpy of reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-happens-to-particles-when-a-substance-gains-energy-and-changes-state"> What happens to particles when a substance gains energy and changes state? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/for-an-isothermal-process-s"> For an isothermal process, S = __________? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-you-seal-the-end-of-a-syringe-and-push-on-the-plunger-is-that-process-isother"> If you seal the end of a syringe and push on the plunger, is that process isothermal? 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What is the change in... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/energy-change-in-reactions"> See all questions in Energy Change in Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2155 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

Given #2CO(g) + O_2(g) rarr 2CO_2(g)# #DeltaH^@=-564*kJ*mol^-1#...what is the enthalpy associated with the formation of a mass of #44.0*g# of carbon dioxide by these means?

ab45f05c-6ddd-11ea-831d-ccda262736ce

https://socratic.org/questions/a-sample-of-nitrogen-gas-was-collected-via-water-displacement-therefore-the-samp

1.48 atm

start physical_unit 3 3 partial_pressure atm qc_end physical_unit 23 24 29 30 total_pressure qc_end physical_unit 23 24 26 27 temperature qc_end physical_unit 8 8 47 48 vapor_pressure qc_end physical_unit 8 8 26 27 temperature qc_end end

[{"type":"physical unit","value":"Partial pressure [OF] nitrogen [IN] atm"}]

[{"type":"physical unit","value":"1.48 atm"}]

[{"type":"physical unit","value":"Total pressure [OF] the mixture [=] \\pu{1.50 atm}"},{"type":"physical unit","value":"Temperature [OF] the mixture [=] \\pu{21 ℃}"},{"type":"physical unit","value":"Vapor pressure [OF] water [=] \\pu{18.7 mmHg}"},{"type":"physical unit","value":"Temperature [OF] water [=] \\pu{21 ℃}"}]

<h1 class="questionTitle" itemprop="name">A sample of nitrogen gas was collected via water displacement. Therefore, the sample is saturated with water vapor. If the total pressure of the mixture at 21 °C is 1.50 atm, what is the partial pressure of nitrogen?</h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The vapor pressure of water at 21°C is 18.7 mmHg</p></div> </h2> </div> </div>

1.48 atm

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Where <mathjax>#P_"SVP"="saturated vapour pressure....."#</mathjax>, which here <mathjax>#=(18.7*mm*Hg)/(760*mm*Hg*atm^-1)=0.025*atm#</mathjax>.</p> <p>Thus <mathjax>#P_(N_2)=P_"Total"-P_"SVP"=(1.50-0.025)*atm=1.475*atm#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_"Total"=P_(N_2)+P_"SVP"#</mathjax>.............<mathjax>#P_(N_2)=1.475*atm#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Where <mathjax>#P_"SVP"="saturated vapour pressure....."#</mathjax>, which here <mathjax>#=(18.7*mm*Hg)/(760*mm*Hg*atm^-1)=0.025*atm#</mathjax>.</p> <p>Thus <mathjax>#P_(N_2)=P_"Total"-P_"SVP"=(1.50-0.025)*atm=1.475*atm#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A sample of nitrogen gas was collected via water displacement. Therefore, the sample is saturated with water vapor. If the total pressure of the mixture at 21 °C is 1.50 atm, what is the partial pressure of nitrogen?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The vapor pressure of water at 21°C is 18.7 mmHg</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/partial-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Partial Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="423318" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-14T17:42:18" itemprop="dateCreated"> May 14, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_"Total"=P_(N_2)+P_"SVP"#</mathjax>.............<mathjax>#P_(N_2)=1.475*atm#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Where <mathjax>#P_"SVP"="saturated vapour pressure....."#</mathjax>, which here <mathjax>#=(18.7*mm*Hg)/(760*mm*Hg*atm^-1)=0.025*atm#</mathjax>.</p> <p>Thus <mathjax>#P_(N_2)=P_"Total"-P_"SVP"=(1.50-0.025)*atm=1.475*atm#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/423318" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534e256802bf342adfa30010"> How do you do a steam distillation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/53613f9f02bf3416cd9f8a34"> Question #f8a34 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-i-calculate-the-total-pressure-of-a-mixture-of-gases-by-adding-together-the-"> Can I calculate the total pressure of a mixture of gases by adding together the partial... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-formula-of-partial-pressure"> What is the formula of partial pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-dalton-s-law-of-partial-pressures"> What is the Dalton's law of partial pressures? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/nitrogen-gas-n2-reacts-with-hydrogen-gas-h2-to-form-ammonia-nh3-at-200-c-in-a-cl"> Nitrogen gas (N2) reacts with hydrogen gas (H2) to form ammonia (NH3). 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A sample of nitrogen gas was collected via water displacement. Therefore, the sample is saturated with water vapor. If the total pressure of the mixture at 21 °C is 1.50 atm, what is the partial pressure of nitrogen?

The vapor pressure of water at 21°C is 18.7 mmHg

a85a67a4-6ddd-11ea-ac7d-ccda262736ce

https://socratic.org/questions/hydrogen-gas-reacts-rapidly-with-oxygen-gas-in-the-presence-of-a-platinum-cataly

H2(g) + 1/2 O2(g) -> H2O(g)

start chemical_equation qc_end substance 0 1 qc_end substance 5 6 qc_end substance 12 13 qc_end end

[{"type":"other","value":"Chemical Equation [OF] this reaction"}]

[{"type":"chemical equation","value":"H2(g) + 1/2 O2(g) -> H2O(g) "}]

[{"type":"substance name","value":"Hydrogen gas"},{"type":"substance name","value":"Oxygen gas"},{"type":"substance name","value":"Platinum catalyst"}]

<h1 class="questionTitle" itemprop="name">Hydrogen gas reacts rapidly with oxygen gas in the presence of a platinum catalyst. What equation would represent this reaction?</h1>

H2(g) + 1/2 O2(g) -> H2O(g)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is the given equation stoichiometrically balanced? How may we remove the non-integral coefficient? Do we need to remove the non-integral coefficient?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_2(g) + 1/2O_2(g) rarr H_2O(g) + "energy"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is the given equation stoichiometrically balanced? How may we remove the non-integral coefficient? Do we need to remove the non-integral coefficient?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Hydrogen gas reacts rapidly with oxygen gas in the presence of a platinum catalyst. What equation would represent this reaction?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="312996" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-22T06:36:42" itemprop="dateCreated"> Sep 22, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_2(g) + 1/2O_2(g) rarr H_2O(g) + "energy"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Is the given equation stoichiometrically balanced? How may we remove the non-integral coefficient? Do we need to remove the non-integral coefficient?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/312996" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4083 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

Hydrogen gas reacts rapidly with oxygen gas in the presence of a platinum catalyst. What equation would represent this reaction?

aca139fe-6ddd-11ea-a714-ccda262736ce

https://socratic.org/questions/5991e24fb72cff54d2427fbe

CH3

start chemical_formula qc_end end

[{"type":"other","value":"Chemical Formula [OF] hydrocarbon [IN] empirical"}]

[{"type":"chemical equation","value":"CH3"}]

[{"type":"physical unit","value":"Percentage [OF] carbon in hydrocarbon [=] \\pu{80%}"}]

<h1 class="questionTitle" itemprop="name">A hydrocarbon has #80%# carbon content. What is its empirical formula?</h1>

CH3

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We assume a mass of <mathjax>#100*g#</mathjax> of stuff...</p> <p><mathjax>#"Moles of carbon"=(80.0*g)/(12.011*g*mol^-1)=6.67*mol.#</mathjax></p> <p><mathjax>#"Moles of hydrogen"=(20.0*g)/(1.00794*g*mol^-1)=19.84*mol.#</mathjax></p> <p>We divide thru by the smallest quantity, i.e.</p> <p><mathjax>#C:(6.67*mol)/(6.67*mol)=1#</mathjax></p> <p><mathjax>#H:(19.84*mol)/(6.67*mol)=3#</mathjax></p> <p>So our empirical formula is <mathjax>#CH_3#</mathjax>. In fact, this is consistent with a molecular formula of <mathjax>#C_2H_6#</mathjax>, i.e. <mathjax>#"ethane"#</mathjax>. The question might have asked this, had they quoted a proper value for molecular weight. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>If the hydrocarbon has 80% carbon content, then the empirical formula is <mathjax>#CH_3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We assume a mass of <mathjax>#100*g#</mathjax> of stuff...</p> <p><mathjax>#"Moles of carbon"=(80.0*g)/(12.011*g*mol^-1)=6.67*mol.#</mathjax></p> <p><mathjax>#"Moles of hydrogen"=(20.0*g)/(1.00794*g*mol^-1)=19.84*mol.#</mathjax></p> <p>We divide thru by the smallest quantity, i.e.</p> <p><mathjax>#C:(6.67*mol)/(6.67*mol)=1#</mathjax></p> <p><mathjax>#H:(19.84*mol)/(6.67*mol)=3#</mathjax></p> <p>So our empirical formula is <mathjax>#CH_3#</mathjax>. In fact, this is consistent with a molecular formula of <mathjax>#C_2H_6#</mathjax>, i.e. <mathjax>#"ethane"#</mathjax>. The question might have asked this, had they quoted a proper value for molecular weight. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A hydrocarbon has #80%# carbon content. What is its empirical formula?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="464068" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-14T18:02:53" itemprop="dateCreated"> Aug 14, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>If the hydrocarbon has 80% carbon content, then the empirical formula is <mathjax>#CH_3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We assume a mass of <mathjax>#100*g#</mathjax> of stuff...</p> <p><mathjax>#"Moles of carbon"=(80.0*g)/(12.011*g*mol^-1)=6.67*mol.#</mathjax></p> <p><mathjax>#"Moles of hydrogen"=(20.0*g)/(1.00794*g*mol^-1)=19.84*mol.#</mathjax></p> <p>We divide thru by the smallest quantity, i.e.</p> <p><mathjax>#C:(6.67*mol)/(6.67*mol)=1#</mathjax></p> <p><mathjax>#H:(19.84*mol)/(6.67*mol)=3#</mathjax></p> <p>So our empirical formula is <mathjax>#CH_3#</mathjax>. In fact, this is consistent with a molecular formula of <mathjax>#C_2H_6#</mathjax>, i.e. <mathjax>#"ethane"#</mathjax>. The question might have asked this, had they quoted a proper value for molecular weight. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/464068" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 31764 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A hydrocarbon has #80%# carbon content. What is its empirical formula?