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a9a338de-6ddd-11ea-9ba4-ccda262736ce

https://socratic.org/questions/how-many-elements-in-total-are-joined-together-to-form-magnesium-chloride

2

start physical_unit 2 2 number none qc_end substance 10 11 qc_end end

[{"type":"physical unit","value":"Number [OF] elements"}]

[{"type":"physical unit","value":"2"}]

[{"type":"substance name","value":"Magnesium chloride"}]

<h1 class="questionTitle" itemprop="name">How many elements, in total, are joined together to form magnesium chloride? </h1>

2

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#MgCl_2#</mathjax> is the molecular formula.</p> <p>So here you can see, that the compound is made by forming 1 <mathjax>#Mg#</mathjax> and 2 <mathjax>#Cl#</mathjax> atoms. </p> <p>There is an ionic bond existing, due to which the compound is an ionic halide, and highly soluble in water. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#MgCl_2#</mathjax> is the molecular formula of magnesium chloride.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#MgCl_2#</mathjax> is the molecular formula.</p> <p>So here you can see, that the compound is made by forming 1 <mathjax>#Mg#</mathjax> and 2 <mathjax>#Cl#</mathjax> atoms. </p> <p>There is an ionic bond existing, due to which the compound is an ionic halide, and highly soluble in water. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many elements, in total, are joined together to form magnesium chloride? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/ionic-compounds" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Compounds</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="459323" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/grace-9"><img alt="" class="" src="https://profilepictures.socratic.org/gzi0U3RQNuMSxgKVeKgw_10960213_10153434463490909_9111641440892052754_o.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/grace-9"> Grace </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-02T14:43:48" itemprop="dateCreated"> Aug 2, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#MgCl_2#</mathjax> is the molecular formula of magnesium chloride.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#MgCl_2#</mathjax> is the molecular formula.</p> <p>So here you can see, that the compound is made by forming 1 <mathjax>#Mg#</mathjax> and 2 <mathjax>#Cl#</mathjax> atoms. </p> <p>There is an ionic bond existing, due to which the compound is an ionic halide, and highly soluble in water. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/459323" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151302bf34732c779c2f"> Question #79c2f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151302bf3473360cd842"> Question #cd842 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52f1151702bf34733dc14e7e"> Why do ionic compounds dissolve in water? 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How many elements, in total, are joined together to form magnesium chloride?

a9e03bac-6ddd-11ea-9161-ccda262736ce

https://socratic.org/questions/what-is-the-empirical-formula-for-a-compound-that-is-36-1-ca-and-63-9-ci

CaCl2

start chemical_formula qc_end end

[{"type":"other","value":"Chemical Formula [OF] the compound [IN] empirical"}]

[{"type":"chemical equation","value":"CaCl2"}]

[{"type":"physical unit","value":"Percent [OF] Ca in the compound [=] \\pu{36.1%}"},{"type":"physical unit","value":"Percent [OF] Cl in the compound [=] \\pu{63.9%}"}]

<h1 class="questionTitle" itemprop="name">What is the empirical formula for a compound that is 36.1% Ca and 63.9% CI? </h1>

CaCl2

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As with all these problems, we assume a <mathjax>#100*"g"#</mathjax> of compound, and divide through by the ATOMIC masses of each component element:</p> <p><mathjax>#"Moles of calcium"#</mathjax> <mathjax>#=(36.1*"g")/(40.08*"g"*"mol"^-1)=0.901 ·"mol"#</mathjax>.</p> <p><mathjax>#"Moles of chlorine"#</mathjax> <mathjax>#=(63.9*"g")/(35.45*"g"*"mol"^-1)=1.802·"mol"#</mathjax>.</p> <p>We divide each molar quantity through by the smallest molar quantity (that of calcium) to give an empirical formula of <mathjax>#"CaCl"_2#</mathjax>.</p> <p>For ionic materials, we do not speak of the molecular formula, and the empirical formula is the formula we quote for reference. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"CaCl"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As with all these problems, we assume a <mathjax>#100*"g"#</mathjax> of compound, and divide through by the ATOMIC masses of each component element:</p> <p><mathjax>#"Moles of calcium"#</mathjax> <mathjax>#=(36.1*"g")/(40.08*"g"*"mol"^-1)=0.901 ·"mol"#</mathjax>.</p> <p><mathjax>#"Moles of chlorine"#</mathjax> <mathjax>#=(63.9*"g")/(35.45*"g"*"mol"^-1)=1.802·"mol"#</mathjax>.</p> <p>We divide each molar quantity through by the smallest molar quantity (that of calcium) to give an empirical formula of <mathjax>#"CaCl"_2#</mathjax>.</p> <p>For ionic materials, we do not speak of the molecular formula, and the empirical formula is the formula we quote for reference. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the empirical formula for a compound that is 36.1% Ca and 63.9% CI? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="340933" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> <a class="secondContributorPic" href="/users/abdur-r"><img alt="" class="" src="https://profilepictures.socratic.org/YXIUDMM0SoZAxTdY3kn6_niagara_falls_fog_water_height_6376_3840x2160.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a>·<a class="topContributorLink" href="/users/abdur-r"> Monzur R. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-23T19:54:06" itemprop="dateCreated"> Nov 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"CaCl"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As with all these problems, we assume a <mathjax>#100*"g"#</mathjax> of compound, and divide through by the ATOMIC masses of each component element:</p> <p><mathjax>#"Moles of calcium"#</mathjax> <mathjax>#=(36.1*"g")/(40.08*"g"*"mol"^-1)=0.901 ·"mol"#</mathjax>.</p> <p><mathjax>#"Moles of chlorine"#</mathjax> <mathjax>#=(63.9*"g")/(35.45*"g"*"mol"^-1)=1.802·"mol"#</mathjax>.</p> <p>We divide each molar quantity through by the smallest molar quantity (that of calcium) to give an empirical formula of <mathjax>#"CaCl"_2#</mathjax>.</p> <p>For ionic materials, we do not speak of the molecular formula, and the empirical formula is the formula we quote for reference. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/340933" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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What is the empirical formula for a compound that is 36.1% Ca and 63.9% CI?

a9db3310-6ddd-11ea-8201-ccda262736ce

https://socratic.org/questions/what-is-the-ph-of-2-34-10-5-naoh-solution

9.37

start physical_unit 9 10 ph none qc_end physical_unit 9 10 5 8 molarity qc_end end

[{"type":"physical unit","value":"pH [OF] NaOH solution"}]

[{"type":"physical unit","value":"9.37"}]

[{"type":"physical unit","value":"Molarity [OF] NaOH solution [=] \\pu{2.34 × 10^(-5) M}"}]

<h1 class="questionTitle" itemprop="name">What is the pH of #2.34 * 10^-5# #NaOH# solution?</h1>

9.37

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And <mathjax>#[HO^-]2.34xx10^-5*mol*L^-1#</mathjax>...</p> <p><mathjax>#pOH=-log_10[HO^-]=-log_10(2.34xx10^-5)=4.63#</mathjax></p> <p><mathjax>#pH=14-pH=13-4.63=9.37.#</mathjax>...the solution is slightly basic...</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, we know that <mathjax>#pH+pOH=14#</mathjax> in water...</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And <mathjax>#[HO^-]2.34xx10^-5*mol*L^-1#</mathjax>...</p> <p><mathjax>#pOH=-log_10[HO^-]=-log_10(2.34xx10^-5)=4.63#</mathjax></p> <p><mathjax>#pH=14-pH=13-4.63=9.37.#</mathjax>...the solution is slightly basic...</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the pH of #2.34 * 10^-5# #NaOH# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="635573" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-26T05:12:28" itemprop="dateCreated"> Jun 26, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, we know that <mathjax>#pH+pOH=14#</mathjax> in water...</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And <mathjax>#[HO^-]2.34xx10^-5*mol*L^-1#</mathjax>...</p> <p><mathjax>#pOH=-log_10[HO^-]=-log_10(2.34xx10^-5)=4.63#</mathjax></p> <p><mathjax>#pH=14-pH=13-4.63=9.37.#</mathjax>...the solution is slightly basic...</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/635573" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? 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What is the pH of #2.34 * 10^-5# #NaOH# solution?

ab4505b9-6ddd-11ea-a6d9-ccda262736ce

https://socratic.org/questions/57ff1aa5b72cff6976a735db

HO- + H+ -> H2O(aq)

start chemical_equation qc_end substance 10 11 qc_end substance 13 14 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the net ionic equation"}]

[{"type":"chemical equation","value":"HO- + H+ -> H2O(aq)"}]

[{"type":"substance name","value":"Hydroiodic acid"},{"type":"substance name","value":"Potassium hydroxide"}]

<h1 class="questionTitle" itemprop="name">What is the net ionic equation for the reaction between hydroiodic acid, and potassium hydroxide?</h1>

HO- + H+ -> H2O(aq)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And the complete equation:</p> <p><mathjax>#NaOH(aq) + HI(aq) rarr NaI(aq) +H_2O(l)#</mathjax></p> <p>So this is an acid base <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a>. Sodium and iodide ions are along for the ride, and remain solvated aqua ions in aqueous solution: i.e. we write <mathjax>#NaI(aq)#</mathjax> or <mathjax>#Na^(+)#</mathjax> and <mathjax>#I^-#</mathjax>; at a molecular level <mathjax>#Na^(+)(aq)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#Na(OH_2)_6^+#</mathjax> for instance.</p> <p>Bond making is conceived to occur between the hydronium ion, <mathjax>#H_3O^+#</mathjax>, and the hydroxide ion, <mathjax>#HO^-#</mathjax> to form 2 equiv of water:</p> <p><mathjax>#HO^(-) + H_3O^+ rarr 2H_2O#</mathjax></p> <p>Mass is balanced, and charge is balanced in all these equations (I think so anyway), so these are reasonable equations. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>This is simply: <mathjax>#HO^(-) + H^(+) rarr H_2O(aq)#</mathjax> OR <mathjax>#HO^(-) + H_3O^(+) rarr 2H_2O(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And the complete equation:</p> <p><mathjax>#NaOH(aq) + HI(aq) rarr NaI(aq) +H_2O(l)#</mathjax></p> <p>So this is an acid base <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a>. Sodium and iodide ions are along for the ride, and remain solvated aqua ions in aqueous solution: i.e. we write <mathjax>#NaI(aq)#</mathjax> or <mathjax>#Na^(+)#</mathjax> and <mathjax>#I^-#</mathjax>; at a molecular level <mathjax>#Na^(+)(aq)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#Na(OH_2)_6^+#</mathjax> for instance.</p> <p>Bond making is conceived to occur between the hydronium ion, <mathjax>#H_3O^+#</mathjax>, and the hydroxide ion, <mathjax>#HO^-#</mathjax> to form 2 equiv of water:</p> <p><mathjax>#HO^(-) + H_3O^+ rarr 2H_2O#</mathjax></p> <p>Mass is balanced, and charge is balanced in all these equations (I think so anyway), so these are reasonable equations. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the net ionic equation for the reaction between hydroiodic acid, and potassium hydroxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/equilibrium-stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Equilibrium Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="321183" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-13T07:49:35" itemprop="dateCreated"> Oct 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>This is simply: <mathjax>#HO^(-) + H^(+) rarr H_2O(aq)#</mathjax> OR <mathjax>#HO^(-) + H_3O^(+) rarr 2H_2O(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And the complete equation:</p> <p><mathjax>#NaOH(aq) + HI(aq) rarr NaI(aq) +H_2O(l)#</mathjax></p> <p>So this is an acid base <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a>. Sodium and iodide ions are along for the ride, and remain solvated aqua ions in aqueous solution: i.e. we write <mathjax>#NaI(aq)#</mathjax> or <mathjax>#Na^(+)#</mathjax> and <mathjax>#I^-#</mathjax>; at a molecular level <mathjax>#Na^(+)(aq)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#Na(OH_2)_6^+#</mathjax> for instance.</p> <p>Bond making is conceived to occur between the hydronium ion, <mathjax>#H_3O^+#</mathjax>, and the hydroxide ion, <mathjax>#HO^-#</mathjax> to form 2 equiv of water:</p> <p><mathjax>#HO^(-) + H_3O^+ rarr 2H_2O#</mathjax></p> <p>Mass is balanced, and charge is balanced in all these equations (I think so anyway), so these are reasonable equations. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/321183" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-a-sample-of-no-g-11-75-mol-is-placed-in-440-0-l-reaction-vessel-at-882-0-k-"> When a sample of NO(g) (11.75 mol) is placed in 440.0 L reaction vessel at 882.0 K and allowed... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-23-0-g-sample-of-i2-g-is-sealed-in-a-gas-bottle-having-a-volume-of-500-ml-some"> A 23.0 g sample of I2(g) is sealed in a gas bottle having a volume of 500 mL. 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What is the net ionic equation for the reaction between hydroiodic acid, and potassium hydroxide?

aab42890-6ddd-11ea-813b-ccda262736ce

https://socratic.org/questions/what-is-the-ph-of-a-6-49-10-3-m-koh-solution

11.81

start physical_unit 10 11 ph none qc_end physical_unit 10 11 6 9 molarity qc_end end

[{"type":"physical unit","value":"pH [OF] KOH solution"}]

[{"type":"physical unit","value":"11.81"}]

[{"type":"physical unit","value":"Molarity [OF] KOH solution [=] \\pu{6.49 × 10^(-3) M}"}]

<h1 class="questionTitle" itemprop="name">What is the pH of a #6.49 * 10^-3# #M# #KOH# solution?</h1>

11.81

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It is a fact that in aqueous solution under standard conditions, </p> <p><mathjax>#14=pH+pOH#</mathjax></p> <p>So we can directly calculate <mathjax>#pOH#</mathjax>, and then approach <mathjax>#pH#</mathjax>.</p> <p><mathjax>#pOH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_10[HO^-]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_10[6.49xx10^-3]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.19#</mathjax></p> <p>Thus <mathjax>#pH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#14.00-2.19#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH~=11.8#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It is a fact that in aqueous solution under standard conditions, </p> <p><mathjax>#14=pH+pOH#</mathjax></p> <p>So we can directly calculate <mathjax>#pOH#</mathjax>, and then approach <mathjax>#pH#</mathjax>.</p> <p><mathjax>#pOH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_10[HO^-]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_10[6.49xx10^-3]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.19#</mathjax></p> <p>Thus <mathjax>#pH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#14.00-2.19#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the pH of a #6.49 * 10^-3# #M# #KOH# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="270612" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-28T14:11:03" itemprop="dateCreated"> May 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH~=11.8#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It is a fact that in aqueous solution under standard conditions, </p> <p><mathjax>#14=pH+pOH#</mathjax></p> <p>So we can directly calculate <mathjax>#pOH#</mathjax>, and then approach <mathjax>#pH#</mathjax>.</p> <p><mathjax>#pOH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_10[HO^-]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_10[6.49xx10^-3]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.19#</mathjax></p> <p>Thus <mathjax>#pH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#14.00-2.19#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/270612" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? 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What is the pH of a #6.49 * 10^-3# #M# #KOH# solution?

a8ca630b-6ddd-11ea-99c8-ccda262736ce

https://socratic.org/questions/how-do-you-balance-mg-h-3po-4-mg-3-po-4-2-h-2

3 Mg + 2 H3PO4 -> Mg3(PO4)2 + 3 H2

start chemical_equation qc_end chemical_equation 4 10 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"3 Mg + 2 H3PO4 -> Mg3(PO4)2 + 3 H2"}]

[{"type":"chemical equation","value":"Mg + H3PO4 -> Mg3(PO4)2 + H2"}]

<h1 class="questionTitle" itemprop="name">How do you balance #Mg + H_3PO_4 -&gt; Mg_3(PO_4)_2 + H_2#?</h1>

3 Mg + 2 H3PO4 -> Mg3(PO4)2 + 3 H2

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/chemical-reactions/balancing-chemical-equations">Balancing chemical equations</a> always involves a bit of algebra, and maybe some trial-and-error. The objective is always to ensure that the numbers (moles) of each element are the same on each side of the equation. </p> <p>In this case it is a redox reaction, so sometimes the use of the oxidation state changes can help. First, the phosphate ion is not changing, just switching partners. The magnesium is being oxidized (<mathjax>#Mg^0 -&gt; Mg^(2+)#</mathjax>) and the hydrogen is being reduced (<mathjax>#H^1 -&gt; H^0#</mathjax>). If we balance that charge transfer, we balance the element quantities involved.</p> <p><mathjax>#Mg + H_3PO_4 → Mg_3(PO_4)_2 + H_2#</mathjax></p> <p>The key changes are:<br/> <mathjax>#Mg^0 → Mg^(+2) xx 3#</mathjax> and<br/> <mathjax>#H^(1) xx 3→ H^(0) xx 2#</mathjax></p> <p><mathjax>#Mg^0 → Mg^(+2)#</mathjax> requires giving up 2 electrons<br/> <mathjax>#H^(1)→ H^(0)#</mathjax> requires adding 1 electron</p> <p>So, there must be twice as many <mathjax>#H#</mathjax> atoms involved as <mathjax>#Mg#</mathjax> atoms. Balancing the <mathjax>#H#</mathjax> first requires increasing the left side by 2 and the right side by 3:<br/> <mathjax>#2H^(1) xx 3→ 3H^(0) xx 2#</mathjax> 6 electrons transfered.</p> <p>That means the <mathjax>#PO_4#</mathjax> ion is also changed on the left, and balanced on the right:<br/> <mathjax>#2H_3PO_4 -&gt; Mg_3(PO_4)_2#</mathjax></p> <p>Put them all together and check the <mathjax>#Mg#</mathjax> balance:<br/> <mathjax>#3Mg + 2H_3PO_4 → Mg_3(PO_4)_2 + 3H_2#</mathjax></p> <p>Total Balance:<br/> <mathjax>#" " Left" "Right#</mathjax><br/> <mathjax>#Mg" 3" " "3#</mathjax><br/> <mathjax>#H" " 6 " "6#</mathjax><br/> <mathjax>#PO_4" 2" " "2#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2H_3PO_4 -&gt; Mg_3(PO_4)_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/chemical-reactions/balancing-chemical-equations">Balancing chemical equations</a> always involves a bit of algebra, and maybe some trial-and-error. The objective is always to ensure that the numbers (moles) of each element are the same on each side of the equation. </p> <p>In this case it is a redox reaction, so sometimes the use of the oxidation state changes can help. First, the phosphate ion is not changing, just switching partners. The magnesium is being oxidized (<mathjax>#Mg^0 -&gt; Mg^(2+)#</mathjax>) and the hydrogen is being reduced (<mathjax>#H^1 -&gt; H^0#</mathjax>). If we balance that charge transfer, we balance the element quantities involved.</p> <p><mathjax>#Mg + H_3PO_4 → Mg_3(PO_4)_2 + H_2#</mathjax></p> <p>The key changes are:<br/> <mathjax>#Mg^0 → Mg^(+2) xx 3#</mathjax> and<br/> <mathjax>#H^(1) xx 3→ H^(0) xx 2#</mathjax></p> <p><mathjax>#Mg^0 → Mg^(+2)#</mathjax> requires giving up 2 electrons<br/> <mathjax>#H^(1)→ H^(0)#</mathjax> requires adding 1 electron</p> <p>So, there must be twice as many <mathjax>#H#</mathjax> atoms involved as <mathjax>#Mg#</mathjax> atoms. Balancing the <mathjax>#H#</mathjax> first requires increasing the left side by 2 and the right side by 3:<br/> <mathjax>#2H^(1) xx 3→ 3H^(0) xx 2#</mathjax> 6 electrons transfered.</p> <p>That means the <mathjax>#PO_4#</mathjax> ion is also changed on the left, and balanced on the right:<br/> <mathjax>#2H_3PO_4 -&gt; Mg_3(PO_4)_2#</mathjax></p> <p>Put them all together and check the <mathjax>#Mg#</mathjax> balance:<br/> <mathjax>#3Mg + 2H_3PO_4 → Mg_3(PO_4)_2 + 3H_2#</mathjax></p> <p>Total Balance:<br/> <mathjax>#" " Left" "Right#</mathjax><br/> <mathjax>#Mg" 3" " "3#</mathjax><br/> <mathjax>#H" " 6 " "6#</mathjax><br/> <mathjax>#PO_4" 2" " "2#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you balance #Mg + H_3PO_4 -&gt; Mg_3(PO_4)_2 + H_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="611352" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/scooke"><img alt="" class="" src="https://profilepictures.socratic.org/ezAzqDkjRS6NXBmMH3lg_BioPic2010a.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/scooke"> SCooke </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-11T03:19:42" itemprop="dateCreated"> May 11, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2H_3PO_4 -&gt; Mg_3(PO_4)_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/chemical-reactions/balancing-chemical-equations">Balancing chemical equations</a> always involves a bit of algebra, and maybe some trial-and-error. The objective is always to ensure that the numbers (moles) of each element are the same on each side of the equation. </p> <p>In this case it is a redox reaction, so sometimes the use of the oxidation state changes can help. First, the phosphate ion is not changing, just switching partners. The magnesium is being oxidized (<mathjax>#Mg^0 -&gt; Mg^(2+)#</mathjax>) and the hydrogen is being reduced (<mathjax>#H^1 -&gt; H^0#</mathjax>). If we balance that charge transfer, we balance the element quantities involved.</p> <p><mathjax>#Mg + H_3PO_4 → Mg_3(PO_4)_2 + H_2#</mathjax></p> <p>The key changes are:<br/> <mathjax>#Mg^0 → Mg^(+2) xx 3#</mathjax> and<br/> <mathjax>#H^(1) xx 3→ H^(0) xx 2#</mathjax></p> <p><mathjax>#Mg^0 → Mg^(+2)#</mathjax> requires giving up 2 electrons<br/> <mathjax>#H^(1)→ H^(0)#</mathjax> requires adding 1 electron</p> <p>So, there must be twice as many <mathjax>#H#</mathjax> atoms involved as <mathjax>#Mg#</mathjax> atoms. Balancing the <mathjax>#H#</mathjax> first requires increasing the left side by 2 and the right side by 3:<br/> <mathjax>#2H^(1) xx 3→ 3H^(0) xx 2#</mathjax> 6 electrons transfered.</p> <p>That means the <mathjax>#PO_4#</mathjax> ion is also changed on the left, and balanced on the right:<br/> <mathjax>#2H_3PO_4 -&gt; Mg_3(PO_4)_2#</mathjax></p> <p>Put them all together and check the <mathjax>#Mg#</mathjax> balance:<br/> <mathjax>#3Mg + 2H_3PO_4 → Mg_3(PO_4)_2 + 3H_2#</mathjax></p> <p>Total Balance:<br/> <mathjax>#" " Left" "Right#</mathjax><br/> <mathjax>#Mg" 3" " "3#</mathjax><br/> <mathjax>#H" " 6 " "6#</mathjax><br/> <mathjax>#PO_4" 2" " "2#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/611352" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------&gt; H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -&gt; Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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How do you balance #Mg + H_3PO_4 -&gt; Mg_3(PO_4)_2 + H_2#?

a8c11406-6ddd-11ea-ad59-ccda262736ce

https://socratic.org/questions/5909351111ef6b3e353427b8

0.14 mol

start physical_unit 19 20 mole mol qc_end physical_unit 3 4 1 2 mole qc_end substance 11 12 qc_end substance 14 15 qc_end end

[{"type":"physical unit","value":"Mole [OF] magnesium nitrate [IN] mol"}]

[{"type":"physical unit","value":"0.14 mol"}]

[{"type":"physical unit","value":"Mole [OF] silver chloride [=] \\pu{0.276 mol}"},{"type":"substance name","value":"Silver nitrate"},{"type":"substance name","value":"Magnesium chloride"}]

<h1 class="questionTitle" itemprop="name">If #0.276*mol# silver chloride was collected from a reaction between silver nitrate and magnesium chloride, how many equiv magnesium nitrate were used?</h1>

0.14 mol

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And how do we know? Well, if we write the stoichiometric equation we have illustrated the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>:</p> <p><mathjax>#2AgNO_3(aq) + MgCl_2(aq) rarr Mg(NO_3)_2(aq) + 2AgCl(s)darr#</mathjax></p> <p>Alternatively, we could write the net ionic equation...........</p> <p><mathjax>#Ag^(+) + Cl^(-) rarr AgCl(s)darr#</mathjax></p> <p>Given the stoichiometry, <mathjax>#(0.276*mol)/2#</mathjax> <mathjax>#MgCl_2#</mathjax> were used..</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>One equiv of silver ion, <mathjax>#Ag^+#</mathjax>, and half an equiv of <mathjax>#MgCl_2(aq)#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And how do we know? Well, if we write the stoichiometric equation we have illustrated the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>:</p> <p><mathjax>#2AgNO_3(aq) + MgCl_2(aq) rarr Mg(NO_3)_2(aq) + 2AgCl(s)darr#</mathjax></p> <p>Alternatively, we could write the net ionic equation...........</p> <p><mathjax>#Ag^(+) + Cl^(-) rarr AgCl(s)darr#</mathjax></p> <p>Given the stoichiometry, <mathjax>#(0.276*mol)/2#</mathjax> <mathjax>#MgCl_2#</mathjax> were used..</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If #0.276*mol# silver chloride was collected from a reaction between silver nitrate and magnesium chloride, how many equiv magnesium nitrate were used?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="418748" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-06T17:59:31" itemprop="dateCreated"> May 6, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>One equiv of silver ion, <mathjax>#Ag^+#</mathjax>, and half an equiv of <mathjax>#MgCl_2(aq)#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And how do we know? Well, if we write the stoichiometric equation we have illustrated the <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>:</p> <p><mathjax>#2AgNO_3(aq) + MgCl_2(aq) rarr Mg(NO_3)_2(aq) + 2AgCl(s)darr#</mathjax></p> <p>Alternatively, we could write the net ionic equation...........</p> <p><mathjax>#Ag^(+) + Cl^(-) rarr AgCl(s)darr#</mathjax></p> <p>Given the stoichiometry, <mathjax>#(0.276*mol)/2#</mathjax> <mathjax>#MgCl_2#</mathjax> were used..</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/418748" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -&gt; 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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If #0.276*mol# silver chloride was collected from a reaction between silver nitrate and magnesium chloride, how many equiv magnesium nitrate were used?

a8bf8d77-6ddd-11ea-b338-ccda262736ce

https://socratic.org/questions/how-many-moles-of-ammonium-nitrate-are-in-335-ml-of-0-425m-nh-4no-3

0.14 moles

start physical_unit 13 13 mole mol qc_end physical_unit 13 13 8 9 volume qc_end physical_unit 13 13 11 12 molarity qc_end end

[{"type":"physical unit","value":"Mole [OF] NH4NO3 [IN] moles"}]

[{"type":"physical unit","value":"0.14 moles"}]

[{"type":"physical unit","value":"Volume [OF] NH4NO3 [=] \\pu{335 mL}"},{"type":"physical unit","value":"Molarity [OF] NH4NO3 [=] \\pu{0.425 M}"}]

<h1 class="questionTitle" itemprop="name">How many moles of ammonium nitrate are in 335 mL of 0.425M #NH_4NO_3#?</h1>

0.14 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You could get fancy and say that this <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> contains <strong>zero moles</strong> of <em>ammonium nitrate</em>, but that would not be the answer the problem is looking for. </p> <p>Here's why that is. </p> <p>A solution's <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> will tell you how many <em>moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em> you get <strong>per liter</strong> of solution. </p> <p>The problem with <strong>soluble <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compounds</a></strong> is that they dissociate completely in aqueous solution to form cations and anions. In this case, ammonium nitrate exists in solution as ammonium cations, <mathjax>#"NH"_4^(+)#</mathjax>, and nitrate anions, <mathjax>#"NO"_3^(-)#</mathjax></p> <blockquote> <p><mathjax>#"NH"_4"NO"_text(3(aq]) -&gt; "NH"_text(4(aq])^(+) + "NO"_text(3(aq])^(-)#</mathjax></p> </blockquote> <p>This means that your solution contains no ammonium nitrate, so technically the concentration of ammonium nitrate is <strong>zero</strong>. </p> <p>Simply put, <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> was initially used as a way to express the concentration of a <strong>particular chemical species</strong> present in solution. (For more on that, go <a href="https://en.wikipedia.org/wiki/Molar_concentration#Formal" rel="nofollow">here</a>).</p> <p>However, it is now common to use molarity as a was to express the concentration of a solute <strong>regardless</strong> of the form in which it exists in solutions. </p> <p>In your case, you know that the solution has a molariy of <mathjax>#"0.425 mol L"^(-1)#</mathjax> and a total volume of <mathjax>#"335 mL"#</mathjax>. To find how many moles of ammonium nitrate you have in solution, use the equation</p> <blockquote> <p><mathjax>#color(blue)(|bar(ul(color(white)(a/a)c = n_"solute"/V_"solution"color(white)(a/a)|)))#</mathjax></p> </blockquote> <p><strong>Do not</strong> forget to convert the volume to <em>liters</em> by using the conversion factor</p> <blockquote> <p><mathjax>#"1 L" = 10^3"mL"#</mathjax></p> </blockquote> <p>You will have</p> <blockquote> <p><mathjax>#c = n/V implies n = c * V#</mathjax></p> <p><mathjax>#n = "0.425 mol" color(red)(cancel(color(black)("L"^(-1)))) * 335 * 10^(-3)color(red)(cancel(color(black)("L"))) = color(green)(|bar(ul(color(white)(a/a)"0.142 moles"color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.142 moles"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You could get fancy and say that this <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> contains <strong>zero moles</strong> of <em>ammonium nitrate</em>, but that would not be the answer the problem is looking for. </p> <p>Here's why that is. </p> <p>A solution's <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> will tell you how many <em>moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em> you get <strong>per liter</strong> of solution. </p> <p>The problem with <strong>soluble <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compounds</a></strong> is that they dissociate completely in aqueous solution to form cations and anions. In this case, ammonium nitrate exists in solution as ammonium cations, <mathjax>#"NH"_4^(+)#</mathjax>, and nitrate anions, <mathjax>#"NO"_3^(-)#</mathjax></p> <blockquote> <p><mathjax>#"NH"_4"NO"_text(3(aq]) -&gt; "NH"_text(4(aq])^(+) + "NO"_text(3(aq])^(-)#</mathjax></p> </blockquote> <p>This means that your solution contains no ammonium nitrate, so technically the concentration of ammonium nitrate is <strong>zero</strong>. </p> <p>Simply put, <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> was initially used as a way to express the concentration of a <strong>particular chemical species</strong> present in solution. (For more on that, go <a href="https://en.wikipedia.org/wiki/Molar_concentration#Formal" rel="nofollow">here</a>).</p> <p>However, it is now common to use molarity as a was to express the concentration of a solute <strong>regardless</strong> of the form in which it exists in solutions. </p> <p>In your case, you know that the solution has a molariy of <mathjax>#"0.425 mol L"^(-1)#</mathjax> and a total volume of <mathjax>#"335 mL"#</mathjax>. To find how many moles of ammonium nitrate you have in solution, use the equation</p> <blockquote> <p><mathjax>#color(blue)(|bar(ul(color(white)(a/a)c = n_"solute"/V_"solution"color(white)(a/a)|)))#</mathjax></p> </blockquote> <p><strong>Do not</strong> forget to convert the volume to <em>liters</em> by using the conversion factor</p> <blockquote> <p><mathjax>#"1 L" = 10^3"mL"#</mathjax></p> </blockquote> <p>You will have</p> <blockquote> <p><mathjax>#c = n/V implies n = c * V#</mathjax></p> <p><mathjax>#n = "0.425 mol" color(red)(cancel(color(black)("L"^(-1)))) * 335 * 10^(-3)color(red)(cancel(color(black)("L"))) = color(green)(|bar(ul(color(white)(a/a)"0.142 moles"color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles of ammonium nitrate are in 335 mL of 0.425M #NH_4NO_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="237072" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-09T01:39:13" itemprop="dateCreated"> Mar 9, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.142 moles"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You could get fancy and say that this <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> contains <strong>zero moles</strong> of <em>ammonium nitrate</em>, but that would not be the answer the problem is looking for. </p> <p>Here's why that is. </p> <p>A solution's <strong><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> will tell you how many <em>moles of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em> you get <strong>per liter</strong> of solution. </p> <p>The problem with <strong>soluble <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compounds</a></strong> is that they dissociate completely in aqueous solution to form cations and anions. In this case, ammonium nitrate exists in solution as ammonium cations, <mathjax>#"NH"_4^(+)#</mathjax>, and nitrate anions, <mathjax>#"NO"_3^(-)#</mathjax></p> <blockquote> <p><mathjax>#"NH"_4"NO"_text(3(aq]) -&gt; "NH"_text(4(aq])^(+) + "NO"_text(3(aq])^(-)#</mathjax></p> </blockquote> <p>This means that your solution contains no ammonium nitrate, so technically the concentration of ammonium nitrate is <strong>zero</strong>. </p> <p>Simply put, <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> was initially used as a way to express the concentration of a <strong>particular chemical species</strong> present in solution. (For more on that, go <a href="https://en.wikipedia.org/wiki/Molar_concentration#Formal" rel="nofollow">here</a>).</p> <p>However, it is now common to use molarity as a was to express the concentration of a solute <strong>regardless</strong> of the form in which it exists in solutions. </p> <p>In your case, you know that the solution has a molariy of <mathjax>#"0.425 mol L"^(-1)#</mathjax> and a total volume of <mathjax>#"335 mL"#</mathjax>. To find how many moles of ammonium nitrate you have in solution, use the equation</p> <blockquote> <p><mathjax>#color(blue)(|bar(ul(color(white)(a/a)c = n_"solute"/V_"solution"color(white)(a/a)|)))#</mathjax></p> </blockquote> <p><strong>Do not</strong> forget to convert the volume to <em>liters</em> by using the conversion factor</p> <blockquote> <p><mathjax>#"1 L" = 10^3"mL"#</mathjax></p> </blockquote> <p>You will have</p> <blockquote> <p><mathjax>#c = n/V implies n = c * V#</mathjax></p> <p><mathjax>#n = "0.425 mol" color(red)(cancel(color(black)("L"^(-1)))) * 335 * 10^(-3)color(red)(cancel(color(black)("L"))) = color(green)(|bar(ul(color(white)(a/a)"0.142 moles"color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/237072" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 15076 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many moles of ammonium nitrate are in 335 mL of 0.425M #NH_4NO_3#?

a97f704c-6ddd-11ea-a601-ccda262736ce

https://socratic.org/questions/a-mixture-of-n2-o2-and-co2-has-a-total-pressure-of-740-torr-in-this-mixture-the-

220 torr

start physical_unit 6 6 partial_pressure torr qc_end physical_unit 1 1 12 13 total_pressure qc_end physical_unit 4 4 32 33 partial_pressure qc_end physical_unit 3 3 23 24 partial_pressure qc_end end

[{"type":"physical unit","value":"Partial pressure [OF] CO2 [IN] torr"}]

[{"type":"physical unit","value":"220 torr"}]

[{"type":"physical unit","value":"Total pressure [OF] mixture [=] \\pu{740 torr}"},{"type":"physical unit","value":"Partial pressure [OF] O2 [=] \\pu{400 torr}"},{"type":"physical unit","value":"Partial pressure [OF] N2 [=] \\pu{120 torr}"}]

<h1 class="questionTitle" itemprop="name">A mixture of #"N"_2#, #"O"_2#. and #"CO"_2# has a total pressure of #"740 torr"# In this mixture, the partial pressure of #"N"_2# is #"120 torr"# and the partial pressure of #"O"_2# is #"400 torr"#. What is the partial pressure of #"CO"_2# ? </h1>

220 torr

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From Dalton's Law of <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">Partial Pressures</a>, the total pressure of a mixture of gases is the sum of the partial pressures of each gas.</p> <p>Therefore, the partial pressure of <mathjax>#"CO"_2#</mathjax> is </p> <p><mathjax>#"740 torr " - " 120 torr " - " 400 torr = 220 torr"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"220 torr"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From Dalton's Law of <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">Partial Pressures</a>, the total pressure of a mixture of gases is the sum of the partial pressures of each gas.</p> <p>Therefore, the partial pressure of <mathjax>#"CO"_2#</mathjax> is </p> <p><mathjax>#"740 torr " - " 120 torr " - " 400 torr = 220 torr"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A mixture of #"N"_2#, #"O"_2#. and #"CO"_2# has a total pressure of #"740 torr"# In this mixture, the partial pressure of #"N"_2# is #"120 torr"# and the partial pressure of #"O"_2# is #"400 torr"#. What is the partial pressure of #"CO"_2# ? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/partial-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Partial Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="557364" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/il-maestro"><img alt="" class="" src="https://profilepictures.socratic.org/oYBS23uRcXBi586nTXQi_400405_3781938059986_310806394_n.jpg" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/il-maestro"> il maestro </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-02-24T09:40:48" itemprop="dateCreated"> Feb 24, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"220 torr"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From Dalton's Law of <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">Partial Pressures</a>, the total pressure of a mixture of gases is the sum of the partial pressures of each gas.</p> <p>Therefore, the partial pressure of <mathjax>#"CO"_2#</mathjax> is </p> <p><mathjax>#"740 torr " - " 120 torr " - " 400 torr = 220 torr"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/557364" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="557365" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/surya-k-2"><img alt="" class="" src="https://profilepictures.socratic.org/g84xu6vTUmSnPW2MqvuP_phi-symbol-1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/surya-k-2"> Surya K. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-02-24T09:42:47" itemprop="dateCreated"> Feb 24, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#220"torr"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>According to Dalton's Law of Partial Pressures, </p> <p><mathjax>#P_"total"=SigmaP_i#</mathjax>, or <mathjax>#P_"total"=P_1+P_2+....P_n#</mathjax></p> <p>Here, we can write the above as:</p> <p><mathjax>#P_"total"=P_(N_2)+P_(CO_2)+P_(O_2)#</mathjax></p> <p>Here, </p> <p><mathjax>#P_"total"=740"torr"#</mathjax></p> <p><mathjax>#P_(N_2)=120"torr"#</mathjax></p> <p><mathjax>#P_(O_2)=400"torr"#</mathjax></p> <p>Inputting, we get:</p> <p><mathjax>#740=120+400+P_(CO_2)#</mathjax></p> <p><mathjax>#740=520+P_(CO_2)#</mathjax></p> <p><mathjax>#P_(CO_2)=220"torr"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/557365" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534e256802bf342adfa30010"> How do you do a steam distillation? 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A mixture of #"N"_2#, #"O"_2#. and #"CO"_2# has a total pressure of #"740 torr"# In this mixture, the partial pressure of #"N"_2# is #"120 torr"# and the partial pressure of #"O"_2# is #"400 torr"#. What is the partial pressure of #"CO"_2# ?

abfb77aa-6ddd-11ea-96ac-ccda262736ce

https://socratic.org/questions/what-is-the-volume-of-4-5-gr-of-co-2

2.3 L

start physical_unit 8 8 volume ml qc_end physical_unit 8 8 5 6 mass qc_end end

[{"type":"physical unit","value":"Volume [OF] CO2 [IN] L"}]

[{"type":"physical unit","value":"2.3 L"}]

[{"type":"physical unit","value":"Mass [OF] CO2 [=] \\pu{4.5 g}"}]

<h1 class="questionTitle" itemprop="name">What is the volume of 4.5 g of #"CO_2"#?</h1>

2.3 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At STP, <mathjax>#"273.15 K"#</mathjax> and <mathjax>#"1 atm"#</mathjax>, the <a href="http://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of carbon dioxide is <mathjax>#"0.001977 g/cm"^3"#</mathjax>.<br/> <a href="http://www.engineeringtoolbox.com/gas-density-d_158.html" rel="nofollow" target="_blank">http://www.engineeringtoolbox.com/gas-density-d_158.html</a></p> <p>We can use the given mass and known density to determine the volume of <mathjax>#"CO"_2"#</mathjax> at STP. Divide the mass by the density.</p> <p><mathjax>#4.5cancel"g CO"_2xx(1"cm"^3 "CO"_2)/(0.001977cancel"g CO"_2)="2300 cm"^3 "CO"_2"#</mathjax> (rounded to two significant figures)</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of <mathjax>#"4.5 g CO"_2"#</mathjax> is <mathjax>#"2300 cm"^3"#</mathjax> at STP.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At STP, <mathjax>#"273.15 K"#</mathjax> and <mathjax>#"1 atm"#</mathjax>, the <a href="http://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of carbon dioxide is <mathjax>#"0.001977 g/cm"^3"#</mathjax>.<br/> <a href="http://www.engineeringtoolbox.com/gas-density-d_158.html" rel="nofollow" target="_blank">http://www.engineeringtoolbox.com/gas-density-d_158.html</a></p> <p>We can use the given mass and known density to determine the volume of <mathjax>#"CO"_2"#</mathjax> at STP. Divide the mass by the density.</p> <p><mathjax>#4.5cancel"g CO"_2xx(1"cm"^3 "CO"_2)/(0.001977cancel"g CO"_2)="2300 cm"^3 "CO"_2"#</mathjax> (rounded to two significant figures)</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the volume of 4.5 g of #"CO_2"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="194931" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-01T05:25:56" itemprop="dateCreated"> Dec 1, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of <mathjax>#"4.5 g CO"_2"#</mathjax> is <mathjax>#"2300 cm"^3"#</mathjax> at STP.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At STP, <mathjax>#"273.15 K"#</mathjax> and <mathjax>#"1 atm"#</mathjax>, the <a href="http://socratic.org/chemistry/measurement-in-chemistry/density">density</a> of carbon dioxide is <mathjax>#"0.001977 g/cm"^3"#</mathjax>.<br/> <a href="http://www.engineeringtoolbox.com/gas-density-d_158.html" rel="nofollow" target="_blank">http://www.engineeringtoolbox.com/gas-density-d_158.html</a></p> <p>We can use the given mass and known density to determine the volume of <mathjax>#"CO"_2"#</mathjax> at STP. Divide the mass by the density.</p> <p><mathjax>#4.5cancel"g CO"_2xx(1"cm"^3 "CO"_2)/(0.001977cancel"g CO"_2)="2300 cm"^3 "CO"_2"#</mathjax> (rounded to two significant figures)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/194931" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="194936" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-01T06:11:32" itemprop="dateCreated"> Dec 1, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of <mathjax>#"4.5 g CO"_2"#</mathjax> is <mathjax>#"2300 cm"^3"#</mathjax> at STP.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We can also use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> to solve this problem.<br/> The equation is <mathjax>#PV=nRT#</mathjax>, where <mathjax>#n#</mathjax> is the number of moles, and <mathjax>#R#</mathjax> is the gas constant.</p> <p>In this problem, <mathjax>#T#</mathjax> and <mathjax>#P#</mathjax> are at STP, <mathjax>#"273.15 K"#</mathjax> and <mathjax>#"1 atm"#</mathjax>.</p> <p>Determine moles of <mathjax>#"CO"_2"#</mathjax> by dividing the given mass by the molar mass.</p> <p><mathjax>#4.5cancel"g CO"_2xx(1"mol CO"_2)/(44.01cancel"g CO"_2)="0.10225 mol CO"_2"#</mathjax></p> <p>I am leaving some guard digits to reduce rounding errors.</p> <p><strong>Ideal Gas Law</strong></p> <p><strong>Given/Known</strong><br/> <mathjax>#P="1 atm"#</mathjax><br/> <mathjax>#n="0.10225 mol"#</mathjax><br/> <mathjax>#R="0.082057338 L atm K"^(-1) "mol"^(-1)"#</mathjax><br/> <a href="https://en.m.wikipedia.org/wiki/Gas_constant" rel="nofollow" target="_blank">https://en.m.wikipedia.org/wiki/Gas_constant</a><br/> <mathjax>#T="273.15 K"#</mathjax></p> <p><strong>Unknown</strong><br/> Volume, <mathjax>#V#</mathjax></p> <p><strong>Equation</strong><br/> <mathjax>#P_1V_1=nRT#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V#</mathjax> and solve.</p> <p><mathjax>#V=(nRT)/(P)#</mathjax></p> <p><mathjax>#V=((0.10225cancel"mol"xx0.082057338 "L" cancel"atm" cancel("K"^(-1)) cancel("mol"^(-1))xx273.15cancel"K"))/(1cancel"atm")="2.3 L"#</mathjax> (rounded to two significant figures)</p> <p>Convert to <mathjax>#"cm"^3"#</mathjax>.</p> <p><mathjax>#2.3cancel"L"xx(1000cancel"mL")/(1cancel"L")xx(1"cm"^3)/(1cancel"mL")="2300 cm"^3"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/194936" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? 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What is the volume of 4.5 g of #"CO_2"#?

a90e51e2-6ddd-11ea-a0a4-ccda262736ce

https://socratic.org/questions/a-student-observes-that-36-76-ml-of-1-013-m-naoh-are-required-to-neutralize-a-12

6.09 M

start physical_unit 20 21 concentration mol/l qc_end physical_unit 18 18 4 5 volume qc_end physical_unit 9 9 7 8 concentration qc_end physical_unit 18 18 15 16 volume qc_end end

[{"type":"physical unit","value":"Concentration [OF] sulfuric acid sample [IN] M"}]

[{"type":"physical unit","value":"6.09 M"}]

[{"type":"physical unit","value":"Volume [OF] NaOH solution [=] \\pu{36.76 mL}"},{"type":"physical unit","value":"Concentration [OF] NaOH solution [=] \\pu{1.013 M}"},{"type":"physical unit","value":"Volume [OF] sulfuric acid aqueous solution [=] \\pu{12.23 mL}"}]

<h1 class="questionTitle" itemprop="name">A student observes that 36.76 mL of 1.013 M NaOH are required to neutralize a 12.23 mL aqueous solution of sulfuric acid. What is the concentration of sulfuric acid in the initial sample?</h1>

6.09 M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Balanced equation</strong></p> <p><mathjax>#"H"_2"SO"_4("aq") + "2NaOH(aq)"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Na"_2"SO"_4("aq") + "2H"_2"O("l")"#</mathjax></p> <p><strong>Titration formula:</strong></p> <p><mathjax>#M_"acid"V_"acid"=M_"base"V_"base"#</mathjax></p> <p>Since <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is mol/L, you will need to convert mL to L.</p> <p><strong>Known</strong></p> <p><mathjax>#V_"acid"=12.23"mL"xx"1 L"/"1000 mL"="0.01223 L"#</mathjax></p> <p><mathjax>#M_"base"="1.013 M"="1.013 mol/L"#</mathjax></p> <p><mathjax>#V_"base"=36.76"mL"xx"1 L"/"1000 mL"="0.03676 L"#</mathjax></p> <p><strong>Unknown</strong></p> <p>#M_"acid"</p> <p><strong>Solution</strong></p> <p>Rearrange the equation to isolate <mathjax>#M_"acid"#</mathjax>. Plug in known values and solve. The molarity of the base will be multiplied by <mathjax>#2#</mathjax> because the mole ratio between the molarity of the base and the molarity of the acid is <mathjax>#2: 1#</mathjax>.</p> <p><mathjax>#M_"acid"=(2xxM_"base"xxV_"base")/(V_"acid")#</mathjax></p> <p><mathjax>#M_"acid"=(2xx1.013"mol"/color(red)cancel(color(black)("L"))xx0.03676color(red)cancel(color(black)("L")))/(0.01223"L")="6.090 mol/L"="6.090 M"#</mathjax> (rounded to four significant figures)</p> <p>The concentration of sulfuric acid in the initial sample is <mathjax>#"6.090 M"#</mathjax>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The concentration of sulfuric acid in the initial sample is <mathjax>#"6.090 M"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Balanced equation</strong></p> <p><mathjax>#"H"_2"SO"_4("aq") + "2NaOH(aq)"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Na"_2"SO"_4("aq") + "2H"_2"O("l")"#</mathjax></p> <p><strong>Titration formula:</strong></p> <p><mathjax>#M_"acid"V_"acid"=M_"base"V_"base"#</mathjax></p> <p>Since <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is mol/L, you will need to convert mL to L.</p> <p><strong>Known</strong></p> <p><mathjax>#V_"acid"=12.23"mL"xx"1 L"/"1000 mL"="0.01223 L"#</mathjax></p> <p><mathjax>#M_"base"="1.013 M"="1.013 mol/L"#</mathjax></p> <p><mathjax>#V_"base"=36.76"mL"xx"1 L"/"1000 mL"="0.03676 L"#</mathjax></p> <p><strong>Unknown</strong></p> <p>#M_"acid"</p> <p><strong>Solution</strong></p> <p>Rearrange the equation to isolate <mathjax>#M_"acid"#</mathjax>. Plug in known values and solve. The molarity of the base will be multiplied by <mathjax>#2#</mathjax> because the mole ratio between the molarity of the base and the molarity of the acid is <mathjax>#2: 1#</mathjax>.</p> <p><mathjax>#M_"acid"=(2xxM_"base"xxV_"base")/(V_"acid")#</mathjax></p> <p><mathjax>#M_"acid"=(2xx1.013"mol"/color(red)cancel(color(black)("L"))xx0.03676color(red)cancel(color(black)("L")))/(0.01223"L")="6.090 mol/L"="6.090 M"#</mathjax> (rounded to four significant figures)</p> <p>The concentration of sulfuric acid in the initial sample is <mathjax>#"6.090 M"#</mathjax>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A student observes that 36.76 mL of 1.013 M NaOH are required to neutralize a 12.23 mL aqueous solution of sulfuric acid. What is the concentration of sulfuric acid in the initial sample?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/neutralization" itemprop="url"> <span class="breadcrumb" itemprop="title">Neutralization</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="611916" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-12T02:23:27" itemprop="dateCreated"> May 12, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The concentration of sulfuric acid in the initial sample is <mathjax>#"6.090 M"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Balanced equation</strong></p> <p><mathjax>#"H"_2"SO"_4("aq") + "2NaOH(aq)"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"Na"_2"SO"_4("aq") + "2H"_2"O("l")"#</mathjax></p> <p><strong>Titration formula:</strong></p> <p><mathjax>#M_"acid"V_"acid"=M_"base"V_"base"#</mathjax></p> <p>Since <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> is mol/L, you will need to convert mL to L.</p> <p><strong>Known</strong></p> <p><mathjax>#V_"acid"=12.23"mL"xx"1 L"/"1000 mL"="0.01223 L"#</mathjax></p> <p><mathjax>#M_"base"="1.013 M"="1.013 mol/L"#</mathjax></p> <p><mathjax>#V_"base"=36.76"mL"xx"1 L"/"1000 mL"="0.03676 L"#</mathjax></p> <p><strong>Unknown</strong></p> <p>#M_"acid"</p> <p><strong>Solution</strong></p> <p>Rearrange the equation to isolate <mathjax>#M_"acid"#</mathjax>. Plug in known values and solve. The molarity of the base will be multiplied by <mathjax>#2#</mathjax> because the mole ratio between the molarity of the base and the molarity of the acid is <mathjax>#2: 1#</mathjax>.</p> <p><mathjax>#M_"acid"=(2xxM_"base"xxV_"base")/(V_"acid")#</mathjax></p> <p><mathjax>#M_"acid"=(2xx1.013"mol"/color(red)cancel(color(black)("L"))xx0.03676color(red)cancel(color(black)("L")))/(0.01223"L")="6.090 mol/L"="6.090 M"#</mathjax> (rounded to four significant figures)</p> <p>The concentration of sulfuric acid in the initial sample is <mathjax>#"6.090 M"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/611916" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-neutralization-reactions-useful"> How are neutralization reactions useful? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-neutralization-reactions-be-identified-symbolically"> How can neutralization reactions be identified symbolically? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-neutralization-reaction-differ-from-buffer"> How does neutralization reaction differ from using a buffer? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-acid-base-neutralization-reactions"> How do you do acid base neutralization reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-neutralization-reactions-produce-heat"> Why do neutralization reactions produce heat? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-neutralization-a-double-replacement-reaction"> Why is neutralization a double replacement reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-a-neutralization-reaction-exothermic"> Why is a neutralization reaction exothermic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-predict-and-balance-acid-base-reactions"> How do you predict the products in acid-base reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-determine-the-strength-of-sulfuric-acid"> How can you determine the strength of sulfuric acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-a-neutralisation-reaction-exothermic"> Why is a neutralisation reaction exothermic? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/reactions-in-solution/neutralization"> See all questions in Neutralization </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1710 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A student observes that 36.76 mL of 1.013 M NaOH are required to neutralize a 12.23 mL aqueous solution of sulfuric acid. What is the concentration of sulfuric acid in the initial sample?

a87f6d68-6ddd-11ea-8ade-ccda262736ce

https://socratic.org/questions/find-the-mass-of-urea-ch4n2o-needed-to-prepare-49-0-g-of-a-solution-in-water-in-

1.05 × 10^1 g

start physical_unit 5 5 mass g qc_end physical_unit 13 15 9 10 mass qc_end physical_unit 5 5 24 26 mole_fraction qc_end end

[{"type":"physical unit","value":"Mass [OF] CO(NH2)2 [IN] g"}]

[{"type":"physical unit","value":"1.05 × 10^1 g"}]

[{"type":"physical unit","value":"Mass [OF] the solution in water [=] \\pu{49.0 g}"},{"type":"physical unit","value":"Mole fraction [OF] CO(NH2)2 [=] \\pu{7.58 × 10^(−2)}"}]

<h1 class="questionTitle" itemprop="name">Find the mass of urea, #"CO"("NH"_2)_2#, needed to prepare #"49.0 g"# of a solution in water in which the mole fraction of urea is #7.58 * 10^(−2)#?</h1>

1.05 × 10^1 g

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong>mole fraction</strong> of urea is defined as the ratio between the number of moles of urea and the <strong>total number of moles</strong> present in the solution.</p> <p>In your case, <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fraction of urea is said to be equal to </p> <blockquote> <p><mathjax>#chi_"urea" = 7.58 * 10^(-2) = 0.0758#</mathjax></p> </blockquote> <p>Now, you know that the <strong>total mass</strong> of the solution is equal to <mathjax>#"49.0 g"#</mathjax>. You can write this as</p> <blockquote> <p><mathjax>#m_"urea" + m_"water" = "49.0 g"#</mathjax></p> </blockquote> <p>with <mathjax>#m_"urea"#</mathjax> being the mass of urea and <mathjax>#m_"water"#</mathjax> being the mass of water. As you know, you can express the mass of a substance using its <strong>molar mass</strong> and the number of moles it contains.</p> <blockquote> <p><mathjax>#m_"urea" = n_"urea" * M_ "M urea"#</mathjax></p> <blockquote> <p>Here <mathjax>#n_"urea"#</mathjax> represents the <strong>number of moles</strong> of urea present in the solution and <mathjax>#M_ "M urea"#</mathjax> is the <strong>molar mass</strong> of urea.</p> </blockquote> <p><mathjax>#m_"water" = n_"water" * M_"water"#</mathjax></p> <blockquote> <p>Here <mathjax>#n_"water"#</mathjax> represents the <strong>number of moles</strong> of water present in the solution and <mathjax>#M_ "M water"#</mathjax> is the <strong>molar mass</strong> of water.</p> </blockquote> </blockquote> <p>This means that you can write</p> <blockquote> <p><mathjax># n_"urea" * M_ "M urea" + n_"water" * M_"water" = "49.0 g" " " " "color(darkorange)((1))#</mathjax></p> </blockquote> <p>By definition, the mole fraction of urea is</p> <blockquote> <p><mathjax>#chi_"urea" = n_"urea"/(n_"urea" + n_"water")#</mathjax></p> </blockquote> <p>which means that you have</p> <blockquote> <p><mathjax>#n_"urea"/(n_"urea" + n_"water") = 0.0758" " " " color(darkorange)((2))#</mathjax></p> </blockquote> <p>You now have two equations with two unknowns, <mathjax>#n_"urea"#</mathjax> and <mathjax>#n_"water"#</mathjax>. Use equation <mathjax>#color(darkorange)((2))#</mathjax> to say that</p> <blockquote> <p><mathjax>#n_"urea" - 0.0758 * n_"urea" = 0.0758 * n_"water"#</mathjax></p> <p><mathjax>#n_"water" = (0.9242 * n_"urea")/0.0758#</mathjax></p> <p><mathjax>#n_"water" = 12.19 * n_"urea"#</mathjax></p> </blockquote> <p>Plug this into equation <mathjax>#color(darkorange)((1))#</mathjax> to find</p> <blockquote> <p><mathjax>#n_"urea" * M_"M urea" + 12.19 * n_"urea" * M_ "M water" = "49.0 g"#</mathjax></p> <p><mathjax>#n_"urea" * (M_ "M urea" + 12.19 * M_ "M water") = "49.0 g"#</mathjax></p> </blockquote> <p>This will get you </p> <blockquote> <p><mathjax>#n_"urea" = "49.0 g"/(M_ "M urea" + 12.19 * M_ "M water")#</mathjax></p> </blockquote> <p>Plug in the molar mass of urea and the molar mass of water to get</p> <blockquote> <p><mathjax>#n_"urea" = (49.0 color(red)(cancel(color(black)("g"))))/((60.06 + 12.19 * 18.015) color(red)(cancel(color(black)("g"))) "mol"^(-1))#</mathjax></p> <p><mathjax>#n_"urea" = "0.1752 moles"#</mathjax></p> </blockquote> <p>Finally, to find the mass of urea, use the molar mass of the compound.</p> <blockquote> <p><mathjax>#0.1752 color(red)(cancel(color(black)("moles urea"))) * "60.06 g"/(1color(red)(cancel(color(black)("mole urea")))) = "10.5 g"#</mathjax></p> </blockquote> <p>Therefore, you can say that this solution contains</p> <blockquote> <p><mathjax>#m_"urea" = color(darkgreen)(ul(color(black)(1.05 * 10^1 quad "g"#</mathjax></p> </blockquote> <p>of urea. The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> and expressed in <a href="https://socratic.org/chemistry/measurement-in-chemistry/scientific-notation">scientific notation</a>. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.05 * 10^1#</mathjax> <mathjax>#"g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong>mole fraction</strong> of urea is defined as the ratio between the number of moles of urea and the <strong>total number of moles</strong> present in the solution.</p> <p>In your case, <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fraction of urea is said to be equal to </p> <blockquote> <p><mathjax>#chi_"urea" = 7.58 * 10^(-2) = 0.0758#</mathjax></p> </blockquote> <p>Now, you know that the <strong>total mass</strong> of the solution is equal to <mathjax>#"49.0 g"#</mathjax>. You can write this as</p> <blockquote> <p><mathjax>#m_"urea" + m_"water" = "49.0 g"#</mathjax></p> </blockquote> <p>with <mathjax>#m_"urea"#</mathjax> being the mass of urea and <mathjax>#m_"water"#</mathjax> being the mass of water. As you know, you can express the mass of a substance using its <strong>molar mass</strong> and the number of moles it contains.</p> <blockquote> <p><mathjax>#m_"urea" = n_"urea" * M_ "M urea"#</mathjax></p> <blockquote> <p>Here <mathjax>#n_"urea"#</mathjax> represents the <strong>number of moles</strong> of urea present in the solution and <mathjax>#M_ "M urea"#</mathjax> is the <strong>molar mass</strong> of urea.</p> </blockquote> <p><mathjax>#m_"water" = n_"water" * M_"water"#</mathjax></p> <blockquote> <p>Here <mathjax>#n_"water"#</mathjax> represents the <strong>number of moles</strong> of water present in the solution and <mathjax>#M_ "M water"#</mathjax> is the <strong>molar mass</strong> of water.</p> </blockquote> </blockquote> <p>This means that you can write</p> <blockquote> <p><mathjax># n_"urea" * M_ "M urea" + n_"water" * M_"water" = "49.0 g" " " " "color(darkorange)((1))#</mathjax></p> </blockquote> <p>By definition, the mole fraction of urea is</p> <blockquote> <p><mathjax>#chi_"urea" = n_"urea"/(n_"urea" + n_"water")#</mathjax></p> </blockquote> <p>which means that you have</p> <blockquote> <p><mathjax>#n_"urea"/(n_"urea" + n_"water") = 0.0758" " " " color(darkorange)((2))#</mathjax></p> </blockquote> <p>You now have two equations with two unknowns, <mathjax>#n_"urea"#</mathjax> and <mathjax>#n_"water"#</mathjax>. Use equation <mathjax>#color(darkorange)((2))#</mathjax> to say that</p> <blockquote> <p><mathjax>#n_"urea" - 0.0758 * n_"urea" = 0.0758 * n_"water"#</mathjax></p> <p><mathjax>#n_"water" = (0.9242 * n_"urea")/0.0758#</mathjax></p> <p><mathjax>#n_"water" = 12.19 * n_"urea"#</mathjax></p> </blockquote> <p>Plug this into equation <mathjax>#color(darkorange)((1))#</mathjax> to find</p> <blockquote> <p><mathjax>#n_"urea" * M_"M urea" + 12.19 * n_"urea" * M_ "M water" = "49.0 g"#</mathjax></p> <p><mathjax>#n_"urea" * (M_ "M urea" + 12.19 * M_ "M water") = "49.0 g"#</mathjax></p> </blockquote> <p>This will get you </p> <blockquote> <p><mathjax>#n_"urea" = "49.0 g"/(M_ "M urea" + 12.19 * M_ "M water")#</mathjax></p> </blockquote> <p>Plug in the molar mass of urea and the molar mass of water to get</p> <blockquote> <p><mathjax>#n_"urea" = (49.0 color(red)(cancel(color(black)("g"))))/((60.06 + 12.19 * 18.015) color(red)(cancel(color(black)("g"))) "mol"^(-1))#</mathjax></p> <p><mathjax>#n_"urea" = "0.1752 moles"#</mathjax></p> </blockquote> <p>Finally, to find the mass of urea, use the molar mass of the compound.</p> <blockquote> <p><mathjax>#0.1752 color(red)(cancel(color(black)("moles urea"))) * "60.06 g"/(1color(red)(cancel(color(black)("mole urea")))) = "10.5 g"#</mathjax></p> </blockquote> <p>Therefore, you can say that this solution contains</p> <blockquote> <p><mathjax>#m_"urea" = color(darkgreen)(ul(color(black)(1.05 * 10^1 quad "g"#</mathjax></p> </blockquote> <p>of urea. The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> and expressed in <a href="https://socratic.org/chemistry/measurement-in-chemistry/scientific-notation">scientific notation</a>. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Find the mass of urea, #"CO"("NH"_2)_2#, needed to prepare #"49.0 g"# of a solution in water in which the mole fraction of urea is #7.58 * 10^(−2)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="549340" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-02-09T23:53:42" itemprop="dateCreated"> Feb 9, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.05 * 10^1#</mathjax> <mathjax>#"g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong>mole fraction</strong> of urea is defined as the ratio between the number of moles of urea and the <strong>total number of moles</strong> present in the solution.</p> <p>In your case, <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fraction of urea is said to be equal to </p> <blockquote> <p><mathjax>#chi_"urea" = 7.58 * 10^(-2) = 0.0758#</mathjax></p> </blockquote> <p>Now, you know that the <strong>total mass</strong> of the solution is equal to <mathjax>#"49.0 g"#</mathjax>. You can write this as</p> <blockquote> <p><mathjax>#m_"urea" + m_"water" = "49.0 g"#</mathjax></p> </blockquote> <p>with <mathjax>#m_"urea"#</mathjax> being the mass of urea and <mathjax>#m_"water"#</mathjax> being the mass of water. As you know, you can express the mass of a substance using its <strong>molar mass</strong> and the number of moles it contains.</p> <blockquote> <p><mathjax>#m_"urea" = n_"urea" * M_ "M urea"#</mathjax></p> <blockquote> <p>Here <mathjax>#n_"urea"#</mathjax> represents the <strong>number of moles</strong> of urea present in the solution and <mathjax>#M_ "M urea"#</mathjax> is the <strong>molar mass</strong> of urea.</p> </blockquote> <p><mathjax>#m_"water" = n_"water" * M_"water"#</mathjax></p> <blockquote> <p>Here <mathjax>#n_"water"#</mathjax> represents the <strong>number of moles</strong> of water present in the solution and <mathjax>#M_ "M water"#</mathjax> is the <strong>molar mass</strong> of water.</p> </blockquote> </blockquote> <p>This means that you can write</p> <blockquote> <p><mathjax># n_"urea" * M_ "M urea" + n_"water" * M_"water" = "49.0 g" " " " "color(darkorange)((1))#</mathjax></p> </blockquote> <p>By definition, the mole fraction of urea is</p> <blockquote> <p><mathjax>#chi_"urea" = n_"urea"/(n_"urea" + n_"water")#</mathjax></p> </blockquote> <p>which means that you have</p> <blockquote> <p><mathjax>#n_"urea"/(n_"urea" + n_"water") = 0.0758" " " " color(darkorange)((2))#</mathjax></p> </blockquote> <p>You now have two equations with two unknowns, <mathjax>#n_"urea"#</mathjax> and <mathjax>#n_"water"#</mathjax>. Use equation <mathjax>#color(darkorange)((2))#</mathjax> to say that</p> <blockquote> <p><mathjax>#n_"urea" - 0.0758 * n_"urea" = 0.0758 * n_"water"#</mathjax></p> <p><mathjax>#n_"water" = (0.9242 * n_"urea")/0.0758#</mathjax></p> <p><mathjax>#n_"water" = 12.19 * n_"urea"#</mathjax></p> </blockquote> <p>Plug this into equation <mathjax>#color(darkorange)((1))#</mathjax> to find</p> <blockquote> <p><mathjax>#n_"urea" * M_"M urea" + 12.19 * n_"urea" * M_ "M water" = "49.0 g"#</mathjax></p> <p><mathjax>#n_"urea" * (M_ "M urea" + 12.19 * M_ "M water") = "49.0 g"#</mathjax></p> </blockquote> <p>This will get you </p> <blockquote> <p><mathjax>#n_"urea" = "49.0 g"/(M_ "M urea" + 12.19 * M_ "M water")#</mathjax></p> </blockquote> <p>Plug in the molar mass of urea and the molar mass of water to get</p> <blockquote> <p><mathjax>#n_"urea" = (49.0 color(red)(cancel(color(black)("g"))))/((60.06 + 12.19 * 18.015) color(red)(cancel(color(black)("g"))) "mol"^(-1))#</mathjax></p> <p><mathjax>#n_"urea" = "0.1752 moles"#</mathjax></p> </blockquote> <p>Finally, to find the mass of urea, use the molar mass of the compound.</p> <blockquote> <p><mathjax>#0.1752 color(red)(cancel(color(black)("moles urea"))) * "60.06 g"/(1color(red)(cancel(color(black)("mole urea")))) = "10.5 g"#</mathjax></p> </blockquote> <p>Therefore, you can say that this solution contains</p> <blockquote> <p><mathjax>#m_"urea" = color(darkgreen)(ul(color(black)(1.05 * 10^1 quad "g"#</mathjax></p> </blockquote> <p>of urea. The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> and expressed in <a href="https://socratic.org/chemistry/measurement-in-chemistry/scientific-notation">scientific notation</a>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/549340" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-solution-solute-and-solvent-related"> How are solution, solute, and solvent related? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutions-become-saturated"> Why do solutions become saturated? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-solutions"> How does temperature affect solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-solution-differ-from-a-colloid"> How does a solution differ from a colloid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/calculate-the-amount-of-1-m-naoh-aqueous-solution-needed-to-make-100-ml-of-0-5-m"> Calculate the amount of 1 M NaOH aqueous solution needed to make 100 mL of 0.5 M NaOH aqueous solution. </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-buffering-a-solution-change-the-solutions-behavior"> How does buffering a solution change the solutions behavior? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-benedict-s-solution-change-colour"> How does Benedict's solution change colour? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/describe-how-would-you-prepare-1-l-of-a-1-m-solution-of-sodium-chloride-the-gram"> Describe how would you prepare 1 L of a 1 M solution of sodium chloride. 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Find the mass of urea, #"CO"("NH"_2)_2#, needed to prepare #"49.0 g"# of a solution in water in which the mole fraction of urea is #7.58 * 10^(−2)#?

a9b919a3-6ddd-11ea-ae01-ccda262736ce

https://socratic.org/questions/what-is-the-chemical-formula-for-blue-vitriol-whose-systematic-name-is-copper-ii

CuSO4.5H2O

start chemical_formula qc_end substance 12 13 qc_end end

[{"type":"other","value":"Chemical Formula [OF] blue vitriol [IN] default"}]

[{"type":"chemical equation","value":"CuSO4.5H2O"}]

[{"type":"substance name","value":"Copper(II) sulfate"}]

<h1 class="questionTitle" itemprop="name">What is the chemical formula for blue vitriol, whose systematic name is copper(II) sulfate? </h1>

CuSO4.5H2O

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Actually the compound ,blue vitriol is a hydrated crystalline substance ,so its formula is written as <mathjax>#CuSO_4. 5H_2O#</mathjax> <br/> and its chemically known as <mathjax>#color(blue)("copper(II)sulphate pentahydrate")#</mathjax></p> <p>To know more click <br/> <a href="http://antoine.frostburg.edu/chem/senese/101/inorganic/faq/blue-vitriol.shtml" rel="nofollow" target="_blank">http://antoine.frostburg.edu/chem/senese/101/inorganic/faq/blue-vitriol.shtml</a></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CuSO_4. 5H_2O#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Actually the compound ,blue vitriol is a hydrated crystalline substance ,so its formula is written as <mathjax>#CuSO_4. 5H_2O#</mathjax> <br/> and its chemically known as <mathjax>#color(blue)("copper(II)sulphate pentahydrate")#</mathjax></p> <p>To know more click <br/> <a href="http://antoine.frostburg.edu/chem/senese/101/inorganic/faq/blue-vitriol.shtml" rel="nofollow" target="_blank">http://antoine.frostburg.edu/chem/senese/101/inorganic/faq/blue-vitriol.shtml</a></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the chemical formula for blue vitriol, whose systematic name is copper(II) sulfate? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="265730" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/dk-ch"><img alt="" class="" src="https://profilepictures.socratic.org/0aBlt69MSiWhfD1SEqb8_lotus.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/dk-ch"> P dilip_k </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-14T14:01:45" itemprop="dateCreated"> May 14, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#CuSO_4. 5H_2O#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Actually the compound ,blue vitriol is a hydrated crystalline substance ,so its formula is written as <mathjax>#CuSO_4. 5H_2O#</mathjax> <br/> and its chemically known as <mathjax>#color(blue)("copper(II)sulphate pentahydrate")#</mathjax></p> <p>To know more click <br/> <a href="http://antoine.frostburg.edu/chem/senese/101/inorganic/faq/blue-vitriol.shtml" rel="nofollow" target="_blank">http://antoine.frostburg.edu/chem/senese/101/inorganic/faq/blue-vitriol.shtml</a></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/265730" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? 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What is the chemical formula for blue vitriol, whose systematic name is copper(II) sulfate?

a94394a8-6ddd-11ea-9b79-ccda262736ce

https://socratic.org/questions/2nh-3-aq-h-2so-4-aq-nh-4-2so-4-aq-how-many-grams-of-ammonium-sulfate-can-be-prod

7962 grams

start physical_unit 10 11 mass g qc_end chemical_equation 0 5 qc_end physical_unit 19 20 16 17 mole qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Mass [OF] ammonium sulfate [IN] grams"}]

[{"type":"physical unit","value":"7962 grams"}]

[{"type":"chemical equation","value":"2 NH3(aq) + H2SO4(aq) -> (NH4)2SO4(aq)"},{"type":"physical unit","value":"Mole [OF] sulfuric acid [=] \\pu{60.0 mol}"},{"type":"other","value":"Excess of ammonia."}]

<h1 class="questionTitle" itemprop="name">#2NH_3(aq) + H_2SO_4(aq) -&gt; (NH_4)_2SO_4(aq)#. How many grams of ammonium sulfate can be produced if 60.0 mol of sulfuric acid react with an excess of ammonia? </h1>

7962 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>What you are trying to find is called the theoretical yield, or how much of a particular product can we expect to form from a given amount of a reactant, assuming that the given reactant reacts completely.</p> <p>Of course, this does not happen in reality where substances don't fully react therefore this is called the theoretical yield. </p> <p>When you calculate the theoretical yield, you are actually asking: <br/> How much of the product can I produce using all of the given reactant? <br/> -<br/> In this case, the question will be: <br/> How much ammonium sulfate can I form if I use all the 60 moles of sulfuric acid?<br/> - </p> <p>In order to answer this question, there are several steps involved: </p> <h2>STEPS:</h2> <h2><strong>1. Identify the givens and what you need to find</strong></h2> <ul> <li>You are given 60 moles of sulfuric acid </li> <li>An excess amount of Ammonia </li> </ul> <h2><strong>2. Use the balanced equation's ratios (if the equation isn't balanced, balance it) and apply the ratios to the problem</strong></h2> <p>The balanced equation is like a recipe. </p> <p>For example, in order to make one sandwich, there must be two slices of bread and one slice of ham. In other words: </p> <p>**2 Slices of Bread + 1 Slice of Ham ==&gt; 1 sandwich</p> <p>** To make a dozen sandwiches, simply multiply both sides by 12 which will change the ratios proportionally </p> <p><strong>24 Slices of Bread + 12 Slices of Ham ==&gt; 12 sandwiches</strong></p> <p>A mole is like a dozen, it equals Avogadro's Number which is approximately 6.022 × 10^23, so you would need to multiply both sides by this number in order to express the number in moles. This large number is simply expressed as "moles."</p> <p><strong>2 Moles of Slices of Bread + 1 Mole of Slices of Ham ==&gt; 1 Mole of Sandwiches</strong> </p> <p>In <a href="https://socratic.org/chemistry/chemical-reactions/chemical-equations">chemical equations</a>, the same applies. The number of substances in a chemical equation are assumed to be in moles. In this problem, we can see: <em>2NH3 + H2SO4 → (NH4)2SO4</em> </p> <p>That <strong>2 moles of NH3</strong> combined with <strong>1 mole of H2SO4</strong> produces <strong>one mole of (NH4)2SO4</strong> So for <strong>every mole of H2SO4</strong> that reacts, we produce <strong>one mole of (NH4)2SO4</strong> </p> <p>So it is a 1:1 (one-to-one ratio of NH3 and (NH4)2SO4) So we can similarly conclude that it takes <strong>60 moles of NH3</strong> to produce <strong>60 moles of (NH4)2SO4</strong> </p> <p>Therefore, we produce: <em>60 moles of (NH4)2SO4</em><br/> -</p> <h2><strong>3. Calculate the molar mass of the product (NH4)2SO4 </strong></h2> <p>Molar mass, or grams per mole of each element is found in <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>. In order to calculate the molar mass of a substance that includes more than one element, we simply add the molar mass of each element that makes-up the substance:</p> <p><mathjax>#"2(N + 4H) + S + 4(O) = 2N + 8H + S + 4O = 2(14.01) + 8(1.01) + 32.07 + 4(16.00)"#</mathjax></p> <p><mathjax>#"= 132.17 g/mol of" ("NH"_4)_2"SO"_4#</mathjax> </p> <p>(This will be your conversion factor of grams to moles) </p> <h2><strong>4. Finally, convert the moles of product to grams of product</strong></h2> <p>We have sixty moles of <mathjax>#("NH"_4)_2"SO"_4#</mathjax> to convert into grams: </p> <p><img alt="" src="https://useruploads.socratic.org/81qeJUaLQbapPhIaDGYR_Screen%20Shot%202017-06-10%20at%202.30.05+PM.png"/> </p> <p>And we need to find x grams of <mathjax>#("NH"_4)_2"SO"_4#</mathjax>. The grams of <mathjax>#("NH"_4)_2"SO"_4#</mathjax> in the numerator of the first fraction cancels out with the denominator of the second fraction which leaves us with</p> <p><mathjax>#60 xx "132.7 g of (NH"_4)_2"SO"_4#</mathjax> </p> <p>OR</p> <h2><mathjax>#"7962 g of (NH"_4)_2"SO"_4#</mathjax></h2></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Assuming that there is an excess in ammonia, there are 7962 grams of of ammonium sulfate that can be produced for every 60 moles of sulfuric acid that reacts. More on that below.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>What you are trying to find is called the theoretical yield, or how much of a particular product can we expect to form from a given amount of a reactant, assuming that the given reactant reacts completely.</p> <p>Of course, this does not happen in reality where substances don't fully react therefore this is called the theoretical yield. </p> <p>When you calculate the theoretical yield, you are actually asking: <br/> How much of the product can I produce using all of the given reactant? <br/> -<br/> In this case, the question will be: <br/> How much ammonium sulfate can I form if I use all the 60 moles of sulfuric acid?<br/> - </p> <p>In order to answer this question, there are several steps involved: </p> <h2>STEPS:</h2> <h2><strong>1. Identify the givens and what you need to find</strong></h2> <ul> <li>You are given 60 moles of sulfuric acid </li> <li>An excess amount of Ammonia </li> </ul> <h2><strong>2. Use the balanced equation's ratios (if the equation isn't balanced, balance it) and apply the ratios to the problem</strong></h2> <p>The balanced equation is like a recipe. </p> <p>For example, in order to make one sandwich, there must be two slices of bread and one slice of ham. In other words: </p> <p>**2 Slices of Bread + 1 Slice of Ham ==&gt; 1 sandwich</p> <p>** To make a dozen sandwiches, simply multiply both sides by 12 which will change the ratios proportionally </p> <p><strong>24 Slices of Bread + 12 Slices of Ham ==&gt; 12 sandwiches</strong></p> <p>A mole is like a dozen, it equals Avogadro's Number which is approximately 6.022 × 10^23, so you would need to multiply both sides by this number in order to express the number in moles. This large number is simply expressed as "moles."</p> <p><strong>2 Moles of Slices of Bread + 1 Mole of Slices of Ham ==&gt; 1 Mole of Sandwiches</strong> </p> <p>In <a href="https://socratic.org/chemistry/chemical-reactions/chemical-equations">chemical equations</a>, the same applies. The number of substances in a chemical equation are assumed to be in moles. In this problem, we can see: <em>2NH3 + H2SO4 → (NH4)2SO4</em> </p> <p>That <strong>2 moles of NH3</strong> combined with <strong>1 mole of H2SO4</strong> produces <strong>one mole of (NH4)2SO4</strong> So for <strong>every mole of H2SO4</strong> that reacts, we produce <strong>one mole of (NH4)2SO4</strong> </p> <p>So it is a 1:1 (one-to-one ratio of NH3 and (NH4)2SO4) So we can similarly conclude that it takes <strong>60 moles of NH3</strong> to produce <strong>60 moles of (NH4)2SO4</strong> </p> <p>Therefore, we produce: <em>60 moles of (NH4)2SO4</em><br/> -</p> <h2><strong>3. Calculate the molar mass of the product (NH4)2SO4 </strong></h2> <p>Molar mass, or grams per mole of each element is found in <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>. In order to calculate the molar mass of a substance that includes more than one element, we simply add the molar mass of each element that makes-up the substance:</p> <p><mathjax>#"2(N + 4H) + S + 4(O) = 2N + 8H + S + 4O = 2(14.01) + 8(1.01) + 32.07 + 4(16.00)"#</mathjax></p> <p><mathjax>#"= 132.17 g/mol of" ("NH"_4)_2"SO"_4#</mathjax> </p> <p>(This will be your conversion factor of grams to moles) </p> <h2><strong>4. Finally, convert the moles of product to grams of product</strong></h2> <p>We have sixty moles of <mathjax>#("NH"_4)_2"SO"_4#</mathjax> to convert into grams: </p> <p><img alt="" src="https://useruploads.socratic.org/81qeJUaLQbapPhIaDGYR_Screen%20Shot%202017-06-10%20at%202.30.05+PM.png"/> </p> <p>And we need to find x grams of <mathjax>#("NH"_4)_2"SO"_4#</mathjax>. The grams of <mathjax>#("NH"_4)_2"SO"_4#</mathjax> in the numerator of the first fraction cancels out with the denominator of the second fraction which leaves us with</p> <p><mathjax>#60 xx "132.7 g of (NH"_4)_2"SO"_4#</mathjax> </p> <p>OR</p> <h2><mathjax>#"7962 g of (NH"_4)_2"SO"_4#</mathjax></h2></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">#2NH_3(aq) + H_2SO_4(aq) -&gt; (NH_4)_2SO_4(aq)#. How many grams of ammonium sulfate can be produced if 60.0 mol of sulfuric acid react with an excess of ammonia? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/equation-stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Equation Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="437663" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michael-l-13"><img alt="" class="" src="https://lh3.googleusercontent.com/-x25Cyr0jiss/AAAAAAAAAAI/AAAAAAAAAAA/U30j176zIfI/photo.jpg?sz=50" title=""/></a> <a class="secondContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michael-l-13"> Michael L. </a>·<a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-10T21:37:59" itemprop="dateCreated"> Jun 10, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Assuming that there is an excess in ammonia, there are 7962 grams of of ammonium sulfate that can be produced for every 60 moles of sulfuric acid that reacts. More on that below.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>What you are trying to find is called the theoretical yield, or how much of a particular product can we expect to form from a given amount of a reactant, assuming that the given reactant reacts completely.</p> <p>Of course, this does not happen in reality where substances don't fully react therefore this is called the theoretical yield. </p> <p>When you calculate the theoretical yield, you are actually asking: <br/> How much of the product can I produce using all of the given reactant? <br/> -<br/> In this case, the question will be: <br/> How much ammonium sulfate can I form if I use all the 60 moles of sulfuric acid?<br/> - </p> <p>In order to answer this question, there are several steps involved: </p> <h2>STEPS:</h2> <h2><strong>1. Identify the givens and what you need to find</strong></h2> <ul> <li>You are given 60 moles of sulfuric acid </li> <li>An excess amount of Ammonia </li> </ul> <h2><strong>2. Use the balanced equation's ratios (if the equation isn't balanced, balance it) and apply the ratios to the problem</strong></h2> <p>The balanced equation is like a recipe. </p> <p>For example, in order to make one sandwich, there must be two slices of bread and one slice of ham. In other words: </p> <p>**2 Slices of Bread + 1 Slice of Ham ==&gt; 1 sandwich</p> <p>** To make a dozen sandwiches, simply multiply both sides by 12 which will change the ratios proportionally </p> <p><strong>24 Slices of Bread + 12 Slices of Ham ==&gt; 12 sandwiches</strong></p> <p>A mole is like a dozen, it equals Avogadro's Number which is approximately 6.022 × 10^23, so you would need to multiply both sides by this number in order to express the number in moles. This large number is simply expressed as "moles."</p> <p><strong>2 Moles of Slices of Bread + 1 Mole of Slices of Ham ==&gt; 1 Mole of Sandwiches</strong> </p> <p>In <a href="https://socratic.org/chemistry/chemical-reactions/chemical-equations">chemical equations</a>, the same applies. The number of substances in a chemical equation are assumed to be in moles. In this problem, we can see: <em>2NH3 + H2SO4 → (NH4)2SO4</em> </p> <p>That <strong>2 moles of NH3</strong> combined with <strong>1 mole of H2SO4</strong> produces <strong>one mole of (NH4)2SO4</strong> So for <strong>every mole of H2SO4</strong> that reacts, we produce <strong>one mole of (NH4)2SO4</strong> </p> <p>So it is a 1:1 (one-to-one ratio of NH3 and (NH4)2SO4) So we can similarly conclude that it takes <strong>60 moles of NH3</strong> to produce <strong>60 moles of (NH4)2SO4</strong> </p> <p>Therefore, we produce: <em>60 moles of (NH4)2SO4</em><br/> -</p> <h2><strong>3. Calculate the molar mass of the product (NH4)2SO4 </strong></h2> <p>Molar mass, or grams per mole of each element is found in <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>. In order to calculate the molar mass of a substance that includes more than one element, we simply add the molar mass of each element that makes-up the substance:</p> <p><mathjax>#"2(N + 4H) + S + 4(O) = 2N + 8H + S + 4O = 2(14.01) + 8(1.01) + 32.07 + 4(16.00)"#</mathjax></p> <p><mathjax>#"= 132.17 g/mol of" ("NH"_4)_2"SO"_4#</mathjax> </p> <p>(This will be your conversion factor of grams to moles) </p> <h2><strong>4. Finally, convert the moles of product to grams of product</strong></h2> <p>We have sixty moles of <mathjax>#("NH"_4)_2"SO"_4#</mathjax> to convert into grams: </p> <p><img alt="" src="https://useruploads.socratic.org/81qeJUaLQbapPhIaDGYR_Screen%20Shot%202017-06-10%20at%202.30.05+PM.png"/> </p> <p>And we need to find x grams of <mathjax>#("NH"_4)_2"SO"_4#</mathjax>. The grams of <mathjax>#("NH"_4)_2"SO"_4#</mathjax> in the numerator of the first fraction cancels out with the denominator of the second fraction which leaves us with</p> <p><mathjax>#60 xx "132.7 g of (NH"_4)_2"SO"_4#</mathjax> </p> <p>OR</p> <h2><mathjax>#"7962 g of (NH"_4)_2"SO"_4#</mathjax></h2></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/437663" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4171602bf3469588dc36e"> What are the types of stoichiometry examples, with examples? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4171802bf3469570e2e82"> Question #e2e82 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668a402bf34573b4e66fb"> What mass of carbon dioxide can 1.00 kg of lithium oxide absorb? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-stoichiometry-practice-problem"> What is an example of a stoichiometry practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-balanced-equation-practice-problem"> What is an example of a balanced equation practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-a-chemical-equation"> How can I balance a chemical equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-stoichiometry-be-used"> How can stoichiometry be used? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-reactants-to-products"> How do stoichiometric ratios relate reactants to products? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-gas-stoichiometry-differ-from-stoichiometry-of-solids-and-liquids"> How does gas stoichiometry differ from stoichiometry of solids and liquids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-stoichiometry-relate-to-the-law-of-conservation"> How does stoichiometry relate to the law of conservation? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/equation-stoichiometry"> See all questions in Equation Stoichiometry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 30450 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

#2NH_3(aq) + H_2SO_4(aq) -&gt; (NH_4)_2SO_4(aq)#. How many grams of ammonium sulfate can be produced if 60.0 mol of sulfuric acid react with an excess of ammonia?

aa868fb0-6ddd-11ea-84bc-ccda262736ce

https://socratic.org/questions/what-is-the-empirical-formula-of-vanillin

C8H8O3

start chemical_formula qc_end substance 6 6 qc_end end

[{"type":"other","value":"Chemical Formula [OF] Vanillin [IN] empirical"}]

[{"type":"chemical equation","value":"C8H8O3"}]

[{"type":"substance name","value":"Vanillin"}]

<h1 class="questionTitle" itemprop="name">What is the empirical formula of Vanillin?</h1>

C8H8O3

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula of Vanillin is the same as its molecular formula: <mathjax>#C_8H_8O_3#</mathjax>.</p> <p>Empirical formula by definition is the simplest formula of a compound. It is determined by dividing all subscripts of all <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> by the same integer and obtain whole numbers.</p> <p>Example: The empirical formula of <mathjax>#C_6H_12O_6#</mathjax> is <mathjax>#CH_2O#</mathjax>. We can divide all subscripts by <mathjax>#6#</mathjax> and obtain whole numbers.</p> <p>For vanillin, it is not possible to find a number where we can divide <mathjax>#8 and 3#</mathjax> and obtain whole numbers, therefore, in this case the empirical formula is the same as the molecular formula.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The same as its molecular formula: <mathjax>#C_8H_8O_3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula of Vanillin is the same as its molecular formula: <mathjax>#C_8H_8O_3#</mathjax>.</p> <p>Empirical formula by definition is the simplest formula of a compound. It is determined by dividing all subscripts of all <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> by the same integer and obtain whole numbers.</p> <p>Example: The empirical formula of <mathjax>#C_6H_12O_6#</mathjax> is <mathjax>#CH_2O#</mathjax>. We can divide all subscripts by <mathjax>#6#</mathjax> and obtain whole numbers.</p> <p>For vanillin, it is not possible to find a number where we can divide <mathjax>#8 and 3#</mathjax> and obtain whole numbers, therefore, in this case the empirical formula is the same as the molecular formula.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the empirical formula of Vanillin?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="178845" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-21T16:52:16" itemprop="dateCreated"> Oct 21, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The same as its molecular formula: <mathjax>#C_8H_8O_3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula of Vanillin is the same as its molecular formula: <mathjax>#C_8H_8O_3#</mathjax>.</p> <p>Empirical formula by definition is the simplest formula of a compound. It is determined by dividing all subscripts of all <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> by the same integer and obtain whole numbers.</p> <p>Example: The empirical formula of <mathjax>#C_6H_12O_6#</mathjax> is <mathjax>#CH_2O#</mathjax>. We can divide all subscripts by <mathjax>#6#</mathjax> and obtain whole numbers.</p> <p>For vanillin, it is not possible to find a number where we can divide <mathjax>#8 and 3#</mathjax> and obtain whole numbers, therefore, in this case the empirical formula is the same as the molecular formula.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/178845" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9524 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the empirical formula of Vanillin?

a93cde06-6ddd-11ea-8501-ccda262736ce

https://socratic.org/questions/the-concentration-of-aqueous-methanol-is-10-of-it-s-mass-what-is-the-molar-fract

0.05

start physical_unit 4 4 molar_ratio none qc_end physical_unit 3 4 6 6 concentration qc_end end

[{"type":"physical unit","value":"Molar fraction [OF] methanol"}]

[{"type":"physical unit","value":"0.05"}]

[{"type":"physical unit","value":"Concentration [OF] aqueous methanol [=] \\pu{10%}"}]

<h1 class="questionTitle" itemprop="name">The concentration of aqueous methanol is 10% of its mass. What is the molar fraction of methanol?</h1>

0.05

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem wants you to find the <strong>mole fraction</strong> of methanol, <mathjax>#"CH"_3"OH"#</mathjax>, by using the fact that its solution has a <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a> by mass</strong> equal to <mathjax>#10%#</mathjax>.</p> <p>This means that if you take <mathjax>#"100 g"#</mathjax> of this solution, the sample will contain <mathjax>#"10 g"#</mathjax> of methanol, the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, and <mathjax>#"90 g"#</mathjax> of water, the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>. </p> <p>Now, <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fraction of methanol is defined as the ratio between the number of moles of methanol and the <strong>total number of moles</strong> present in the solution. </p> <p>To make the calculations easier, let's work with a <mathjax>#"100-g"#</mathjax> sample of this solution. Use the <strong>molar mass</strong> of water to find the number of moles of water present in the sample.</p> <blockquote> <p><mathjax>#100 color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))) = "5.551 moles H"_2"O"#</mathjax></p> </blockquote> <p>Next, use the <strong>molar mass</strong> of methanol to find the number of moles of methanol present in the sample.</p> <blockquote> <p><mathjax>#10 color(red)(cancel(color(black)("g"))) * ("1 mole CH"_3"OH")/(32.04color(red)(cancel(color(black)("g")))) = "0.312 moles CH"_3"OH"#</mathjax></p> </blockquote> <p>This means that the mole fraction of methanol, which we'll label <mathjax>#chi_"methanol"#</mathjax>, is equal to</p> <blockquote> <p><mathjax>#chi_"methanol" = (0.312 color(red)(cancel(color(black)("moles"))))/((5.551 + 0.312)color(red)(cancel(color(black)("moles")))) = color(darkgreen)(ul(color(black)(0.05)))#</mathjax></p> </blockquote> <p>The answer is rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>, the number of sig figs you have for the percent concentration of the solution. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.05#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem wants you to find the <strong>mole fraction</strong> of methanol, <mathjax>#"CH"_3"OH"#</mathjax>, by using the fact that its solution has a <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a> by mass</strong> equal to <mathjax>#10%#</mathjax>.</p> <p>This means that if you take <mathjax>#"100 g"#</mathjax> of this solution, the sample will contain <mathjax>#"10 g"#</mathjax> of methanol, the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, and <mathjax>#"90 g"#</mathjax> of water, the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>. </p> <p>Now, <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fraction of methanol is defined as the ratio between the number of moles of methanol and the <strong>total number of moles</strong> present in the solution. </p> <p>To make the calculations easier, let's work with a <mathjax>#"100-g"#</mathjax> sample of this solution. Use the <strong>molar mass</strong> of water to find the number of moles of water present in the sample.</p> <blockquote> <p><mathjax>#100 color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))) = "5.551 moles H"_2"O"#</mathjax></p> </blockquote> <p>Next, use the <strong>molar mass</strong> of methanol to find the number of moles of methanol present in the sample.</p> <blockquote> <p><mathjax>#10 color(red)(cancel(color(black)("g"))) * ("1 mole CH"_3"OH")/(32.04color(red)(cancel(color(black)("g")))) = "0.312 moles CH"_3"OH"#</mathjax></p> </blockquote> <p>This means that the mole fraction of methanol, which we'll label <mathjax>#chi_"methanol"#</mathjax>, is equal to</p> <blockquote> <p><mathjax>#chi_"methanol" = (0.312 color(red)(cancel(color(black)("moles"))))/((5.551 + 0.312)color(red)(cancel(color(black)("moles")))) = color(darkgreen)(ul(color(black)(0.05)))#</mathjax></p> </blockquote> <p>The answer is rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>, the number of sig figs you have for the percent concentration of the solution. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">The concentration of aqueous methanol is 10% of its mass. What is the molar fraction of methanol?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="535453" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-01-14T23:53:14" itemprop="dateCreated"> Jan 14, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.05#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem wants you to find the <strong>mole fraction</strong> of methanol, <mathjax>#"CH"_3"OH"#</mathjax>, by using the fact that its solution has a <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a> by mass</strong> equal to <mathjax>#10%#</mathjax>.</p> <p>This means that if you take <mathjax>#"100 g"#</mathjax> of this solution, the sample will contain <mathjax>#"10 g"#</mathjax> of methanol, the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, and <mathjax>#"90 g"#</mathjax> of water, the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>. </p> <p>Now, <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> fraction of methanol is defined as the ratio between the number of moles of methanol and the <strong>total number of moles</strong> present in the solution. </p> <p>To make the calculations easier, let's work with a <mathjax>#"100-g"#</mathjax> sample of this solution. Use the <strong>molar mass</strong> of water to find the number of moles of water present in the sample.</p> <blockquote> <p><mathjax>#100 color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))) = "5.551 moles H"_2"O"#</mathjax></p> </blockquote> <p>Next, use the <strong>molar mass</strong> of methanol to find the number of moles of methanol present in the sample.</p> <blockquote> <p><mathjax>#10 color(red)(cancel(color(black)("g"))) * ("1 mole CH"_3"OH")/(32.04color(red)(cancel(color(black)("g")))) = "0.312 moles CH"_3"OH"#</mathjax></p> </blockquote> <p>This means that the mole fraction of methanol, which we'll label <mathjax>#chi_"methanol"#</mathjax>, is equal to</p> <blockquote> <p><mathjax>#chi_"methanol" = (0.312 color(red)(cancel(color(black)("moles"))))/((5.551 + 0.312)color(red)(cancel(color(black)("moles")))) = color(darkgreen)(ul(color(black)(0.05)))#</mathjax></p> </blockquote> <p>The answer is rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>, the number of sig figs you have for the percent concentration of the solution. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/535453" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-a-solution-be-increased"> How can the concentration of a solution be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-concentration-of-a-solution-in-ppm"> How do you find the concentration of a solution in ppm? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-10-percent-solution"> How do you make a 10 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-2-percent-solution"> How do you make a 2 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-weight-per-volume-method-to-calculate-concentration"> What is the weight per volume method to calculate concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-percent-concentration-of-kcl-would-be-isotonic"> What percent concentration of KCl would be isotonic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-sodium-chloride-in-normal-saline"> What is the percent concentration of sodium chloride in normal saline? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-a-6m-solution-of-nacl"> What is the percent concentration of a 6m solution of NaCl? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-formula"> What is the percent concentration formula? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/percent-concentration"> See all questions in Percent Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4891 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

The concentration of aqueous methanol is 10% of its mass. What is the molar fraction of methanol?

aa2012ec-6ddd-11ea-a513-ccda262736ce

https://socratic.org/questions/how-would-you-balance-the-following-equation-fe-o2-fe2o3-1

4 Fe + 3 O2 -> 2 Fe2O3

start chemical_equation qc_end chemical_equation 7 11 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"4 Fe + 3 O2 -> 2 Fe2O3"}]

[{"type":"chemical equation","value":"Fe + O2 -> Fe2O3"}]

<h1 class="questionTitle" itemprop="name">How would you balance the following equation: Fe+O2 --&gt; Fe2O3? </h1>

4 Fe + 3 O2 -> 2 Fe2O3

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Step 1: Tally the number of atoms based on subscript.</p> <p><mathjax>#Fe#</mathjax> + <mathjax>#O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Fe_2O_3#</mathjax> (unbalanced)</p> <p>left side: Fe = 1; O = 2<br/> right side: Fe = 2; O = 3</p> <p>Step 2: Start balancing the simple molecules first, in this case the <mathjax>#O_2#</mathjax></p> <p><mathjax>#Fe#</mathjax> + <mathjax>#color (green) 3O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Fe_2O_3#</mathjax> </p> <p>left side: Fe = 1; O = 2 x <mathjax>#color (green) 3#</mathjax> = <strong>6</strong><br/> right side: Fe = 2; O = 3</p> <p>Since there are now 6 <mathjax>#O#</mathjax> atoms on the left, there must also be 6 <mathjax>#O#</mathjax> atoms on the right. Notice that the right hand is one big molecule so whatever coefficient you would use to balance the <mathjax>#O#</mathjax> atoms, you would also need to apply to the bonded <mathjax>#Fe#</mathjax> atom.</p> <p><mathjax>#Fe#</mathjax> + <mathjax>#3O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#color (red) 2Fe_2O_3#</mathjax> </p> <p>left side: Fe = 1; O = 2 x 3 = <strong>6</strong><br/> right side: Fe = 2 x <mathjax>#color (red) 2#</mathjax> = <strong>4</strong>; O = 3 x <mathjax>#color (red) 2#</mathjax> = <strong>6</strong></p> <p>Step 3: Now balance the rest of the equation.</p> <p><mathjax>#color (blue) 4Fe#</mathjax> + <mathjax>#3O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#2Fe_2O_3#</mathjax> </p> <p>left side: Fe = 1 x <mathjax>#color (blue) 4#</mathjax> = <strong>4</strong>; O = 2 x 3 = <strong>6</strong><br/> right side: Fe = 2 x 2 = <strong>4</strong>; O = 3 x 2 = <strong>6</strong></p> <p>The equation is now balanced.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4Fe#</mathjax> + <mathjax>#3O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#2Fe_2O_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Step 1: Tally the number of atoms based on subscript.</p> <p><mathjax>#Fe#</mathjax> + <mathjax>#O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Fe_2O_3#</mathjax> (unbalanced)</p> <p>left side: Fe = 1; O = 2<br/> right side: Fe = 2; O = 3</p> <p>Step 2: Start balancing the simple molecules first, in this case the <mathjax>#O_2#</mathjax></p> <p><mathjax>#Fe#</mathjax> + <mathjax>#color (green) 3O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Fe_2O_3#</mathjax> </p> <p>left side: Fe = 1; O = 2 x <mathjax>#color (green) 3#</mathjax> = <strong>6</strong><br/> right side: Fe = 2; O = 3</p> <p>Since there are now 6 <mathjax>#O#</mathjax> atoms on the left, there must also be 6 <mathjax>#O#</mathjax> atoms on the right. Notice that the right hand is one big molecule so whatever coefficient you would use to balance the <mathjax>#O#</mathjax> atoms, you would also need to apply to the bonded <mathjax>#Fe#</mathjax> atom.</p> <p><mathjax>#Fe#</mathjax> + <mathjax>#3O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#color (red) 2Fe_2O_3#</mathjax> </p> <p>left side: Fe = 1; O = 2 x 3 = <strong>6</strong><br/> right side: Fe = 2 x <mathjax>#color (red) 2#</mathjax> = <strong>4</strong>; O = 3 x <mathjax>#color (red) 2#</mathjax> = <strong>6</strong></p> <p>Step 3: Now balance the rest of the equation.</p> <p><mathjax>#color (blue) 4Fe#</mathjax> + <mathjax>#3O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#2Fe_2O_3#</mathjax> </p> <p>left side: Fe = 1 x <mathjax>#color (blue) 4#</mathjax> = <strong>4</strong>; O = 2 x 3 = <strong>6</strong><br/> right side: Fe = 2 x 2 = <strong>4</strong>; O = 3 x 2 = <strong>6</strong></p> <p>The equation is now balanced.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How would you balance the following equation: Fe+O2 --&gt; Fe2O3? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="182134" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nikka-c"><img alt="" class="" src="https://profilepictures.socratic.org/AQ8VOCyTM1J7U0TvIWhw_nkahara.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nikka-c"> Nikka C. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-02T06:48:40" itemprop="dateCreated"> Nov 2, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4Fe#</mathjax> + <mathjax>#3O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#2Fe_2O_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Step 1: Tally the number of atoms based on subscript.</p> <p><mathjax>#Fe#</mathjax> + <mathjax>#O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Fe_2O_3#</mathjax> (unbalanced)</p> <p>left side: Fe = 1; O = 2<br/> right side: Fe = 2; O = 3</p> <p>Step 2: Start balancing the simple molecules first, in this case the <mathjax>#O_2#</mathjax></p> <p><mathjax>#Fe#</mathjax> + <mathjax>#color (green) 3O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#Fe_2O_3#</mathjax> </p> <p>left side: Fe = 1; O = 2 x <mathjax>#color (green) 3#</mathjax> = <strong>6</strong><br/> right side: Fe = 2; O = 3</p> <p>Since there are now 6 <mathjax>#O#</mathjax> atoms on the left, there must also be 6 <mathjax>#O#</mathjax> atoms on the right. Notice that the right hand is one big molecule so whatever coefficient you would use to balance the <mathjax>#O#</mathjax> atoms, you would also need to apply to the bonded <mathjax>#Fe#</mathjax> atom.</p> <p><mathjax>#Fe#</mathjax> + <mathjax>#3O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#color (red) 2Fe_2O_3#</mathjax> </p> <p>left side: Fe = 1; O = 2 x 3 = <strong>6</strong><br/> right side: Fe = 2 x <mathjax>#color (red) 2#</mathjax> = <strong>4</strong>; O = 3 x <mathjax>#color (red) 2#</mathjax> = <strong>6</strong></p> <p>Step 3: Now balance the rest of the equation.</p> <p><mathjax>#color (blue) 4Fe#</mathjax> + <mathjax>#3O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#2Fe_2O_3#</mathjax> </p> <p>left side: Fe = 1 x <mathjax>#color (blue) 4#</mathjax> = <strong>4</strong>; O = 2 x 3 = <strong>6</strong><br/> right side: Fe = 2 x 2 = <strong>4</strong>; O = 3 x 2 = <strong>6</strong></p> <p>The equation is now balanced.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/182134" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------&gt; H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -&gt; Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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How would you balance the following equation: Fe+O2 --&gt; Fe2O3?

a9f6698a-6ddd-11ea-9ac8-ccda262736ce

https://socratic.org/questions/what-is-the-the-volume-occupied-by-2-34-g-of-carbon-dioxide-gas-at-stp

1.18 L

start physical_unit 10 12 volume l qc_end physical_unit 10 12 7 8 mass qc_end c_other STP qc_end end

[{"type":"physical unit","value":"Volume [OF] carbon dioxide gas [IN] L"}]

[{"type":"physical unit","value":"1.18 L"}]

[{"type":"physical unit","value":"Mass [OF] carbon dioxide gas [=] \\pu{2.34 g}"},{"type":"other","value":"STP"}]

<h1 class="questionTitle" itemprop="name">What is the the volume occupied by 2.34 g of carbon dioxide gas at STP?</h1>

1.18 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to solve this problem we would use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> formula <mathjax>#PV=nRT#</mathjax></p> <p><mathjax>#P =#</mathjax> Pressure in <mathjax>#atm#</mathjax><br/> <mathjax>#V=#</mathjax> Volume in <mathjax>#L#</mathjax><br/> <mathjax>#n=#</mathjax> moles<br/> <mathjax>#R=#</mathjax> Ideal Gas Law Constant <br/> <mathjax>#T=#</mathjax> Temp in <mathjax>#K#</mathjax></p> <p><mathjax>#STP#</mathjax> is Standard Temperature and Pressure which has values of <br/> <mathjax>#1 atm#</mathjax> and <mathjax>#273K#</mathjax></p> <p><mathjax>#2.34g CO_2#</mathjax> must be converted to moles</p> <p><mathjax>#2.34g CO_2 x (1mol)/(44gCO_2) = 0.053 mols#</mathjax></p> <p><mathjax>#P = 1atm#</mathjax><br/> <mathjax>#V= ??? L#</mathjax><br/> <mathjax>#n= 0.053 mols#</mathjax><br/> <mathjax>#R=0.0821 (atmL)/(molK)#</mathjax> <br/> <mathjax>#T=273K#</mathjax></p> <p><mathjax>#PV=nRT#</mathjax> becomes</p> <p><mathjax>#V = (nRT)/P#</mathjax></p> <p><mathjax>#V = (0.053cancel(mols)(0.0821 (cancel(atm)L)/(cancel(mol)cancel(K)))(273cancelK))/(1atm)#</mathjax></p> <p><mathjax>#V = 1.18 L#</mathjax></p> <p> <iframe src="https://www.youtube.com/embed/DlNjUYLZ_Aw?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V = 1.18 L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to solve this problem we would use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> formula <mathjax>#PV=nRT#</mathjax></p> <p><mathjax>#P =#</mathjax> Pressure in <mathjax>#atm#</mathjax><br/> <mathjax>#V=#</mathjax> Volume in <mathjax>#L#</mathjax><br/> <mathjax>#n=#</mathjax> moles<br/> <mathjax>#R=#</mathjax> Ideal Gas Law Constant <br/> <mathjax>#T=#</mathjax> Temp in <mathjax>#K#</mathjax></p> <p><mathjax>#STP#</mathjax> is Standard Temperature and Pressure which has values of <br/> <mathjax>#1 atm#</mathjax> and <mathjax>#273K#</mathjax></p> <p><mathjax>#2.34g CO_2#</mathjax> must be converted to moles</p> <p><mathjax>#2.34g CO_2 x (1mol)/(44gCO_2) = 0.053 mols#</mathjax></p> <p><mathjax>#P = 1atm#</mathjax><br/> <mathjax>#V= ??? L#</mathjax><br/> <mathjax>#n= 0.053 mols#</mathjax><br/> <mathjax>#R=0.0821 (atmL)/(molK)#</mathjax> <br/> <mathjax>#T=273K#</mathjax></p> <p><mathjax>#PV=nRT#</mathjax> becomes</p> <p><mathjax>#V = (nRT)/P#</mathjax></p> <p><mathjax>#V = (0.053cancel(mols)(0.0821 (cancel(atm)L)/(cancel(mol)cancel(K)))(273cancelK))/(1atm)#</mathjax></p> <p><mathjax>#V = 1.18 L#</mathjax></p> <p> <iframe src="https://www.youtube.com/embed/DlNjUYLZ_Aw?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the the volume occupied by 2.34 g of carbon dioxide gas at STP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="262990" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/brian-m"><img alt="" class="" src="https://profilepictures.socratic.org/ZCpnJDgSFKORtvaSPDeG_Lego%20Me.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/brian-m"> BRIAN M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-06T20:32:55" itemprop="dateCreated"> May 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V = 1.18 L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to solve this problem we would use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a> formula <mathjax>#PV=nRT#</mathjax></p> <p><mathjax>#P =#</mathjax> Pressure in <mathjax>#atm#</mathjax><br/> <mathjax>#V=#</mathjax> Volume in <mathjax>#L#</mathjax><br/> <mathjax>#n=#</mathjax> moles<br/> <mathjax>#R=#</mathjax> Ideal Gas Law Constant <br/> <mathjax>#T=#</mathjax> Temp in <mathjax>#K#</mathjax></p> <p><mathjax>#STP#</mathjax> is Standard Temperature and Pressure which has values of <br/> <mathjax>#1 atm#</mathjax> and <mathjax>#273K#</mathjax></p> <p><mathjax>#2.34g CO_2#</mathjax> must be converted to moles</p> <p><mathjax>#2.34g CO_2 x (1mol)/(44gCO_2) = 0.053 mols#</mathjax></p> <p><mathjax>#P = 1atm#</mathjax><br/> <mathjax>#V= ??? L#</mathjax><br/> <mathjax>#n= 0.053 mols#</mathjax><br/> <mathjax>#R=0.0821 (atmL)/(molK)#</mathjax> <br/> <mathjax>#T=273K#</mathjax></p> <p><mathjax>#PV=nRT#</mathjax> becomes</p> <p><mathjax>#V = (nRT)/P#</mathjax></p> <p><mathjax>#V = (0.053cancel(mols)(0.0821 (cancel(atm)L)/(cancel(mol)cancel(K)))(273cancelK))/(1atm)#</mathjax></p> <p><mathjax>#V = 1.18 L#</mathjax></p> <p> <iframe src="https://www.youtube.com/embed/DlNjUYLZ_Aw?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/262990" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="263064" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/prim"><img alt="" class="" src="https://profilepictures.socratic.org/GAepgFbiSHKCiEE3ByEe_tumblr_n5wio1sTz91tummxoo1_250.gif" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/prim"> Madi </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-07T02:17:48" itemprop="dateCreated"> May 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.18 L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Alternative solution:</p> <p>Calculate how many moles <mathjax>#2.34g#</mathjax> <mathjax>#CO_2#</mathjax> is</p> <p><mathjax>#2.34g * (1mol)/(44g CO_2) = 0.053 mol#</mathjax></p> <p>Simple <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratios</a> tell us that <mathjax>#1#</mathjax> mol of any gas at STP is <mathjax>#22.4L#</mathjax>, but since we only have <mathjax>#0.053 mol#</mathjax>, we times <mathjax>#22.4L/(mol)#</mathjax> by <mathjax>#0.053mol.#</mathjax></p> <p><mathjax>#(22.4L)/cancel(mol) * 0.053 cancel(mol) = 1.18L#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/263064" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? 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What is the the volume occupied by 2.34 g of carbon dioxide gas at STP?

a9a31340-6ddd-11ea-afed-ccda262736ce

https://socratic.org/questions/how-do-you-write-a-equation-for-aluminum-copper-ll-sulfate-copper-aluminum-sulfa

2 Al(s) + 3 CuSO4(aq) -> Al2(SO4)3(aq) + 3 Cu(s)

start chemical_equation qc_end chemical_equation 7 16 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"2 Al(s) + 3 CuSO4(aq) -> Al2(SO4)3(aq) + 3 Cu(s)"}]

[{"type":"chemical equation","value":"Aluminum + copper (ll) sulfate -> copper + aluminum sulfate"}]

<h1 class="questionTitle" itemprop="name">How do you write a equation for "Aluminum + copper (ll) sulfate -&gt; copper + aluminum sulfate"?</h1>

2 Al(s) + 3 CuSO4(aq) -> Al2(SO4)3(aq) + 3 Cu(s)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The reaction would be the following :</p> <p><mathjax>#2Al(s)+3CuSO_4(aq)-&gt;Al_2(SO_4)_3(aq)+3Cu(s)#</mathjax></p> <p>This is an oxidation-reduction reaction were electrons are transferred from Aluminum <mathjax>#Al#</mathjax> which get oxidized to Copper <mathjax>#Cu^(2+)#</mathjax> which gets reduced.</p> <p>Oxidation: <mathjax>#Al(s)-&gt;Al^(3+)(aq)+3e^-#</mathjax></p> <p>Reduction: <mathjax>#Cu^(2+)(aq)+2e^(-)-&gt;Cu(s)#</mathjax></p> <p>The net redox reaction would then be:</p> <p><mathjax>#color(red)(2xx)(Al(s)-&gt;Al^(3+)(aq)+cancel(3e^-))#</mathjax><br/> <mathjax>#color(red)(3xx)(Cu^(2+)(aq)+cancel(2e^(-))-&gt;Cu(s))#</mathjax><br/> <mathjax>#---------------#</mathjax><br/> <mathjax>#2Al(s)+3Cu^(2+)(aq)-&gt;2Al^(3+)(aq)+3Cu(s)#</mathjax></p> <p>Note that <mathjax>#SO_4^(2-)#</mathjax> is a spectator ion.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2Al(s)+3CuSO_4(aq)-&gt;Al_2(SO_4)_3(aq)+3Cu(s)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The reaction would be the following :</p> <p><mathjax>#2Al(s)+3CuSO_4(aq)-&gt;Al_2(SO_4)_3(aq)+3Cu(s)#</mathjax></p> <p>This is an oxidation-reduction reaction were electrons are transferred from Aluminum <mathjax>#Al#</mathjax> which get oxidized to Copper <mathjax>#Cu^(2+)#</mathjax> which gets reduced.</p> <p>Oxidation: <mathjax>#Al(s)-&gt;Al^(3+)(aq)+3e^-#</mathjax></p> <p>Reduction: <mathjax>#Cu^(2+)(aq)+2e^(-)-&gt;Cu(s)#</mathjax></p> <p>The net redox reaction would then be:</p> <p><mathjax>#color(red)(2xx)(Al(s)-&gt;Al^(3+)(aq)+cancel(3e^-))#</mathjax><br/> <mathjax>#color(red)(3xx)(Cu^(2+)(aq)+cancel(2e^(-))-&gt;Cu(s))#</mathjax><br/> <mathjax>#---------------#</mathjax><br/> <mathjax>#2Al(s)+3Cu^(2+)(aq)-&gt;2Al^(3+)(aq)+3Cu(s)#</mathjax></p> <p>Note that <mathjax>#SO_4^(2-)#</mathjax> is a spectator ion.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you write a equation for "Aluminum + copper (ll) sulfate -&gt; copper + aluminum sulfate"?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="202677" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-23T18:55:23" itemprop="dateCreated"> Dec 23, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2Al(s)+3CuSO_4(aq)-&gt;Al_2(SO_4)_3(aq)+3Cu(s)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The reaction would be the following :</p> <p><mathjax>#2Al(s)+3CuSO_4(aq)-&gt;Al_2(SO_4)_3(aq)+3Cu(s)#</mathjax></p> <p>This is an oxidation-reduction reaction were electrons are transferred from Aluminum <mathjax>#Al#</mathjax> which get oxidized to Copper <mathjax>#Cu^(2+)#</mathjax> which gets reduced.</p> <p>Oxidation: <mathjax>#Al(s)-&gt;Al^(3+)(aq)+3e^-#</mathjax></p> <p>Reduction: <mathjax>#Cu^(2+)(aq)+2e^(-)-&gt;Cu(s)#</mathjax></p> <p>The net redox reaction would then be:</p> <p><mathjax>#color(red)(2xx)(Al(s)-&gt;Al^(3+)(aq)+cancel(3e^-))#</mathjax><br/> <mathjax>#color(red)(3xx)(Cu^(2+)(aq)+cancel(2e^(-))-&gt;Cu(s))#</mathjax><br/> <mathjax>#---------------#</mathjax><br/> <mathjax>#2Al(s)+3Cu^(2+)(aq)-&gt;2Al^(3+)(aq)+3Cu(s)#</mathjax></p> <p>Note that <mathjax>#SO_4^(2-)#</mathjax> is a spectator ion.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/202677" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? 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How do you write a equation for "Aluminum + copper (ll) sulfate -&gt; copper + aluminum sulfate"?

a8df89a9-6ddd-11ea-acf5-ccda262736ce

https://socratic.org/questions/how-do-you-balance-zn-oh-2-ch-3cooh-zn-ch-3coo-2-h-2o

Zn(OH)2 + 2 CH3COOH -> ZN(CH3COO)2 + 2 H2O

start chemical_equation qc_end chemical_equation 4 10 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"Zn(OH)2 + 2 CH3COOH -> ZN(CH3COO)2 + 2 H2O"}]

[{"type":"chemical equation","value":"Zn(OH)2 + CH3COOH -> ZN(CH3COO)2 + H2O"}]

<h1 class="questionTitle" itemprop="name">How do you balance #Zn(OH)_2 + CH_3COOH -&gt; Zn(CH_3COO)_2 + H_2O#?</h1>

Zn(OH)2 + 2 CH3COOH -> ZN(CH3COO)2 + 2 H2O

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>One way to do it is to think of it as a proton donation (acid) reaction and a proton acceptance (base) reaction:</p> <p>Acid:</p> <p><mathjax>#"CH"_3"COOH" rarr "CH"_3"COO"^{-} + "H"^+#</mathjax></p> <p>Base:</p> <p><mathjax>#"Zn"("OH")_2 + 2 "H"^{+} rarr "Zn"^{2+} + 2 "H"_2"O"#</mathjax></p> <p>The acid gives one mole of protons but tge base takes two. To balance the protons take two moles of the acid to one of the base:</p> <p><mathjax>#2"CH"_3"COOH" rarr 2"CH"_3"COO"^{-} +2 "H"^+#</mathjax></p> <p><mathjax>#"Zn"("OH")_2 + 2 "H"^{+} rarr "Zn"^{2+} + 2 "H"_2"O"#</mathjax></p> <p>Then add them up. The protons cancel and the remaining ions combine to make the salt:</p> <p><mathjax>#2"CH"_3"COOH" + "Zn"("OH")_2 rarr "Zn"("CH"_3"COO")_2 + 2"H"_2"O"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Use the proton balance method given below to obtain:</p> <p><mathjax>#2"CH"_3"COOH" + "Zn"("OH")_2 rarr "Zn"("CH"_3"COO")_2 + 2"H"_2"O"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>One way to do it is to think of it as a proton donation (acid) reaction and a proton acceptance (base) reaction:</p> <p>Acid:</p> <p><mathjax>#"CH"_3"COOH" rarr "CH"_3"COO"^{-} + "H"^+#</mathjax></p> <p>Base:</p> <p><mathjax>#"Zn"("OH")_2 + 2 "H"^{+} rarr "Zn"^{2+} + 2 "H"_2"O"#</mathjax></p> <p>The acid gives one mole of protons but tge base takes two. To balance the protons take two moles of the acid to one of the base:</p> <p><mathjax>#2"CH"_3"COOH" rarr 2"CH"_3"COO"^{-} +2 "H"^+#</mathjax></p> <p><mathjax>#"Zn"("OH")_2 + 2 "H"^{+} rarr "Zn"^{2+} + 2 "H"_2"O"#</mathjax></p> <p>Then add them up. The protons cancel and the remaining ions combine to make the salt:</p> <p><mathjax>#2"CH"_3"COOH" + "Zn"("OH")_2 rarr "Zn"("CH"_3"COO")_2 + 2"H"_2"O"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you balance #Zn(OH)_2 + CH_3COOH -&gt; Zn(CH_3COO)_2 + H_2O#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="302097" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/olthe3rd"><img alt="" class="" src="https://profilepictures.socratic.org/ooIp4P3ES4imZU7Cwexy_Squirrel.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/olthe3rd"> Oscar L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-23T23:15:17" itemprop="dateCreated"> Aug 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Use the proton balance method given below to obtain:</p> <p><mathjax>#2"CH"_3"COOH" + "Zn"("OH")_2 rarr "Zn"("CH"_3"COO")_2 + 2"H"_2"O"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>One way to do it is to think of it as a proton donation (acid) reaction and a proton acceptance (base) reaction:</p> <p>Acid:</p> <p><mathjax>#"CH"_3"COOH" rarr "CH"_3"COO"^{-} + "H"^+#</mathjax></p> <p>Base:</p> <p><mathjax>#"Zn"("OH")_2 + 2 "H"^{+} rarr "Zn"^{2+} + 2 "H"_2"O"#</mathjax></p> <p>The acid gives one mole of protons but tge base takes two. To balance the protons take two moles of the acid to one of the base:</p> <p><mathjax>#2"CH"_3"COOH" rarr 2"CH"_3"COO"^{-} +2 "H"^+#</mathjax></p> <p><mathjax>#"Zn"("OH")_2 + 2 "H"^{+} rarr "Zn"^{2+} + 2 "H"_2"O"#</mathjax></p> <p>Then add them up. The protons cancel and the remaining ions combine to make the salt:</p> <p><mathjax>#2"CH"_3"COOH" + "Zn"("OH")_2 rarr "Zn"("CH"_3"COO")_2 + 2"H"_2"O"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/302097" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------&gt; H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -&gt; Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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How do you balance #Zn(OH)_2 + CH_3COOH -&gt; Zn(CH_3COO)_2 + H_2O#?

a903f2e4-6ddd-11ea-8e8d-ccda262736ce

https://socratic.org/questions/a-balloon-has-a-volume-of-253-2-l-at-356-k-the-volume-of-the-balloon-is-decrease

232.55 K

start physical_unit 14 15 temperature k qc_end physical_unit 14 15 6 7 volume qc_end physical_unit 14 15 9 10 temperature qc_end physical_unit 14 15 19 20 volume qc_end end

[{"type":"physical unit","value":"Temperature2 [OF] the balloon [IN] K"}]

[{"type":"physical unit","value":"232.55 K"}]

[{"type":"physical unit","value":"Volume1 [OF] the balloon [=] \\pu{253.2 L}"},{"type":"physical unit","value":"Temperature1 [OF] the balloon [=] \\pu{356 K}"},{"type":"physical unit","value":"Volume2 [OF] the balloon [=] \\pu{165.4 L}"}]

<h1 class="questionTitle" itemprop="name">A balloon has a volume of 253.2 L at 356 K. The volume of the balloon is decreased to 165.4 L. What is the new temperature?</h1>

232.55 K

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Before doing any calculation, try to predict what you expect the new temperature to be <em>relative</em> to the initial temperature. </p> <p>In your case, <em>number of moles</em> of gas and <em>pressure</em> are <strong>kept constant</strong>. When this is the case, <em>volume</em> and <em>temperature</em> have a <strong>direct relationship</strong> - this is known as <a href="http://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a>. </p> <p><img alt="http://agaul01.blogspot.ro/2014/04/boyles-charles-law-in-relation-to.html" src="https://useruploads.socratic.org/9592ajQXQdWpURyfGQT9_CL%20Double.png"/> </p> <p>So, why is this the case? </p> <p>As you know, the <em>pressure</em> of a gas is determined by the <strong>force</strong> with which its molecules collide with the walls of the balloon. </p> <p><em>Temperature</em> is simply a measure of the <strong>average kinetic energy</strong> of the gas molecules. When a gas is <em>heated</em>, its molecules move faster. </p> <p>This will result in <em>more powerful and more frequent</em> collisions with the walls of the balloon, which in turn will cause the <em>pressure</em> to increase. </p> <p>However, when pressure is <strong>kept constant</strong>, this increase in the average kinetic energy of the gas molecules causes an <strong>increase</strong> in the volume of the balloon. </p> <p>Simply put, increasing the volume counteracts the increase in temperature, keeping pressure <strong>constant</strong>. A bigger volume implies <em>more room</em> for the molecules to move in, which will result in <em>less frequent</em> collisions between the gas molecules and the walls of the balloon. </p> <p>In your case, the volume actually <strong>decreases</strong>. This means that you can expect the temperature of the gas molecules to be <em>lower</em>, since reducing volume while decreasing the average kinetic speed of the molecules will <strong>keep pressure constant</strong>. </p> <p>Mathematically, this is written as </p> <blockquote> <p><mathjax>#color(blue)(V_1/T_1 = V_2/T_2)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#V_1#</mathjax>, <mathjax>#T_1#</mathjax> - the volume and temperature of the gas at an initial state<br/> <mathjax>#V_2#</mathjax>, <mathjax>#T_2#</mathjax> - the volume and temperature of the gas at a final state</p> <p>In your case, you will have </p> <blockquote> <p><mathjax>#T_2 = V_2/V_1 * T_1#</mathjax></p> <p><mathjax>#T_2 = (165.4 color(red)(cancel(color(black)("L"))))/(253.2color(red)(cancel(color(black)("L")))) * "356 K" = "232.55 K"#</mathjax></p> </blockquote> <p>Rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the initial temperature of the gas, the answer will be </p> <blockquote> <p><mathjax>#T_2 = color(green)("233 K")#</mathjax></p> </blockquote> <p>Indeed, our prediction turned out to be correct, <mathjax>#T_2 &lt; T_1#</mathjax>!</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"233 K"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Before doing any calculation, try to predict what you expect the new temperature to be <em>relative</em> to the initial temperature. </p> <p>In your case, <em>number of moles</em> of gas and <em>pressure</em> are <strong>kept constant</strong>. When this is the case, <em>volume</em> and <em>temperature</em> have a <strong>direct relationship</strong> - this is known as <a href="http://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a>. </p> <p><img alt="http://agaul01.blogspot.ro/2014/04/boyles-charles-law-in-relation-to.html" src="https://useruploads.socratic.org/9592ajQXQdWpURyfGQT9_CL%20Double.png"/> </p> <p>So, why is this the case? </p> <p>As you know, the <em>pressure</em> of a gas is determined by the <strong>force</strong> with which its molecules collide with the walls of the balloon. </p> <p><em>Temperature</em> is simply a measure of the <strong>average kinetic energy</strong> of the gas molecules. When a gas is <em>heated</em>, its molecules move faster. </p> <p>This will result in <em>more powerful and more frequent</em> collisions with the walls of the balloon, which in turn will cause the <em>pressure</em> to increase. </p> <p>However, when pressure is <strong>kept constant</strong>, this increase in the average kinetic energy of the gas molecules causes an <strong>increase</strong> in the volume of the balloon. </p> <p>Simply put, increasing the volume counteracts the increase in temperature, keeping pressure <strong>constant</strong>. A bigger volume implies <em>more room</em> for the molecules to move in, which will result in <em>less frequent</em> collisions between the gas molecules and the walls of the balloon. </p> <p>In your case, the volume actually <strong>decreases</strong>. This means that you can expect the temperature of the gas molecules to be <em>lower</em>, since reducing volume while decreasing the average kinetic speed of the molecules will <strong>keep pressure constant</strong>. </p> <p>Mathematically, this is written as </p> <blockquote> <p><mathjax>#color(blue)(V_1/T_1 = V_2/T_2)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#V_1#</mathjax>, <mathjax>#T_1#</mathjax> - the volume and temperature of the gas at an initial state<br/> <mathjax>#V_2#</mathjax>, <mathjax>#T_2#</mathjax> - the volume and temperature of the gas at a final state</p> <p>In your case, you will have </p> <blockquote> <p><mathjax>#T_2 = V_2/V_1 * T_1#</mathjax></p> <p><mathjax>#T_2 = (165.4 color(red)(cancel(color(black)("L"))))/(253.2color(red)(cancel(color(black)("L")))) * "356 K" = "232.55 K"#</mathjax></p> </blockquote> <p>Rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the initial temperature of the gas, the answer will be </p> <blockquote> <p><mathjax>#T_2 = color(green)("233 K")#</mathjax></p> </blockquote> <p>Indeed, our prediction turned out to be correct, <mathjax>#T_2 &lt; T_1#</mathjax>!</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A balloon has a volume of 253.2 L at 356 K. The volume of the balloon is decreased to 165.4 L. What is the new temperature?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/charles-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Charles' Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="205013" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-29T00:52:19" itemprop="dateCreated"> Dec 29, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"233 K"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Before doing any calculation, try to predict what you expect the new temperature to be <em>relative</em> to the initial temperature. </p> <p>In your case, <em>number of moles</em> of gas and <em>pressure</em> are <strong>kept constant</strong>. When this is the case, <em>volume</em> and <em>temperature</em> have a <strong>direct relationship</strong> - this is known as <a href="http://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a>. </p> <p><img alt="http://agaul01.blogspot.ro/2014/04/boyles-charles-law-in-relation-to.html" src="https://useruploads.socratic.org/9592ajQXQdWpURyfGQT9_CL%20Double.png"/> </p> <p>So, why is this the case? </p> <p>As you know, the <em>pressure</em> of a gas is determined by the <strong>force</strong> with which its molecules collide with the walls of the balloon. </p> <p><em>Temperature</em> is simply a measure of the <strong>average kinetic energy</strong> of the gas molecules. When a gas is <em>heated</em>, its molecules move faster. </p> <p>This will result in <em>more powerful and more frequent</em> collisions with the walls of the balloon, which in turn will cause the <em>pressure</em> to increase. </p> <p>However, when pressure is <strong>kept constant</strong>, this increase in the average kinetic energy of the gas molecules causes an <strong>increase</strong> in the volume of the balloon. </p> <p>Simply put, increasing the volume counteracts the increase in temperature, keeping pressure <strong>constant</strong>. A bigger volume implies <em>more room</em> for the molecules to move in, which will result in <em>less frequent</em> collisions between the gas molecules and the walls of the balloon. </p> <p>In your case, the volume actually <strong>decreases</strong>. This means that you can expect the temperature of the gas molecules to be <em>lower</em>, since reducing volume while decreasing the average kinetic speed of the molecules will <strong>keep pressure constant</strong>. </p> <p>Mathematically, this is written as </p> <blockquote> <p><mathjax>#color(blue)(V_1/T_1 = V_2/T_2)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#V_1#</mathjax>, <mathjax>#T_1#</mathjax> - the volume and temperature of the gas at an initial state<br/> <mathjax>#V_2#</mathjax>, <mathjax>#T_2#</mathjax> - the volume and temperature of the gas at a final state</p> <p>In your case, you will have </p> <blockquote> <p><mathjax>#T_2 = V_2/V_1 * T_1#</mathjax></p> <p><mathjax>#T_2 = (165.4 color(red)(cancel(color(black)("L"))))/(253.2color(red)(cancel(color(black)("L")))) * "356 K" = "232.55 K"#</mathjax></p> </blockquote> <p>Rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the number of sig figs you have for the initial temperature of the gas, the answer will be </p> <blockquote> <p><mathjax>#T_2 = color(green)("233 K")#</mathjax></p> </blockquote> <p>Indeed, our prediction turned out to be correct, <mathjax>#T_2 &lt; T_1#</mathjax>!</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/205013" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-must-charles-law-be-in-kelvins"> Why must Charles' law be in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-charles-law-formula"> What is Charles' law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/oxygen-gas-is-at-a-temperature-of-40-c-when-it-occupies-a-volume-of-2-3-liters-t"> Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.3 liters. 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What will be volume of oxygen when the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/charles-law"> See all questions in Charles' Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3088 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A balloon has a volume of 253.2 L at 356 K. The volume of the balloon is decreased to 165.4 L. What is the new temperature?

a8616c0c-6ddd-11ea-9209-ccda262736ce

https://socratic.org/questions/how-much-energy-is-required-to-raise-the-temperature-of-3-g-of-silver-from-15-c-

3.53 J

start physical_unit 13 13 energy j qc_end physical_unit 13 13 15 16 temperature qc_end physical_unit 13 13 18 19 temperature qc_end physical_unit 13 13 10 11 mass qc_end end

[{"type":"physical unit","value":"Required energy [OF] silver [IN] J"}]

[{"type":"physical unit","value":"3.53 J"}]

[{"type":"physical unit","value":"Temperature1 [OF] silver [=] \\pu{15 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] silver [=] \\pu{20 ℃}"},{"type":"physical unit","value":"Mass [OF] silver [=] \\pu{3 g}"}]

<h1 class="questionTitle" itemprop="name">How much energy is required to raise the temperature of 3 g of silver from 15°C to 20°C? </h1>

3.53 J

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of silver is <mathjax>#s=0.235kJkg^-1K^-1#</mathjax></p> <p>The mass is <mathjax>#m=0.003kg#</mathjax></p> <p><mathjax>#Delta T=20-15=5º#</mathjax></p> <p>Energy, <mathjax>#E=ms DeltaT=0.003*0.235*5=0.003525kJ=3.525J#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The energy is <mathjax>#=3.525J#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of silver is <mathjax>#s=0.235kJkg^-1K^-1#</mathjax></p> <p>The mass is <mathjax>#m=0.003kg#</mathjax></p> <p><mathjax>#Delta T=20-15=5º#</mathjax></p> <p>Energy, <mathjax>#E=ms DeltaT=0.003*0.235*5=0.003525kJ=3.525J#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How much energy is required to raise the temperature of 3 g of silver from 15°C to 20°C? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/thermochemistry-of-phase-changes" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry of Phase Changes</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="391712" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/narad-t"><img alt="" class="" src="https://profilepictures.socratic.org/zsDo4Wx9QIqYad4PXKE9_150317-1041.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/narad-t"> Narad T. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-15T15:15:54" itemprop="dateCreated"> Mar 15, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The energy is <mathjax>#=3.525J#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of silver is <mathjax>#s=0.235kJkg^-1K^-1#</mathjax></p> <p>The mass is <mathjax>#m=0.003kg#</mathjax></p> <p><mathjax>#Delta T=20-15=5º#</mathjax></p> <p>Energy, <mathjax>#E=ms DeltaT=0.003*0.235*5=0.003525kJ=3.525J#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/391712" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-much-energy-is-required-to-heat-100-g-of-ice-at-0-00-degrees-celsius-to-wate"> How much energy is required to convert 100.g of ice at 0.00 °C to water vapor at 100.00 °C? 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How much energy is required to raise the temperature of 3 g of silver from 15°C to 20°C?

ab089734-6ddd-11ea-8fab-ccda262736ce

https://socratic.org/questions/57e6d379b72cff057fce3624

C10H12NO

start chemical_formula qc_end substance 15 15 qc_end end

[{"type":"other","value":"Chemical Formula [OF] the organic compound [IN] empirical"}]

[{"type":"chemical equation","value":"C10H12NO"}]

[{"type":"physical unit","value":"Percentage [OF] C in organic compound [=] \\pu{74.0%}"},{"type":"physical unit","value":"Percentage [OF] H in organic compound [=] \\pu{7.4%}"},{"type":"physical unit","value":"Percentage [OF] N in organic compound [=] \\pu{8.6%}"},{"type":"substance name","value":"Oxygen"}]

<h1 class="questionTitle" itemprop="name">Combustion data of an organic compound yielded #74.0%, C;# #7.4%, H;# #8.6%, N;# and the balance oxygen. What is the empirical formula?</h1>

C10H12NO

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As with all problems of this type, we assume a <mathjax>#100*g#</mathjax> mass of compound, and we determine the molar composition with respect to each element:</p> <p>And thus:</p> <p><mathjax>#"Moles of carbon"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(74.0*g)/(12.011*g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#6.16*mol#</mathjax></p> <p><mathjax>#"Moles of hydrogen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(7.4*g)/(1.00794*g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#7.34*mol#</mathjax></p> <p><mathjax>#"Moles of nitrogen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(8.6*g)/(14.01*g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.614*mol#</mathjax></p> <p><mathjax>#"Moles of oxygen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(10.0*g)/(16.00*g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.625*mol#</mathjax></p> <p>So we have the molar composition. We simply divide thru by the smallest molar quantity to gets our empirical formula:</p> <p>Dividing thru by <mathjax>#0.614*mol#</mathjax> we get <mathjax>#C_10H_12NO#</mathjax> (clearly, I have done some rounding off!), as the empirical formula. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_10H_12NO#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As with all problems of this type, we assume a <mathjax>#100*g#</mathjax> mass of compound, and we determine the molar composition with respect to each element:</p> <p>And thus:</p> <p><mathjax>#"Moles of carbon"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(74.0*g)/(12.011*g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#6.16*mol#</mathjax></p> <p><mathjax>#"Moles of hydrogen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(7.4*g)/(1.00794*g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#7.34*mol#</mathjax></p> <p><mathjax>#"Moles of nitrogen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(8.6*g)/(14.01*g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.614*mol#</mathjax></p> <p><mathjax>#"Moles of oxygen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(10.0*g)/(16.00*g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.625*mol#</mathjax></p> <p>So we have the molar composition. We simply divide thru by the smallest molar quantity to gets our empirical formula:</p> <p>Dividing thru by <mathjax>#0.614*mol#</mathjax> we get <mathjax>#C_10H_12NO#</mathjax> (clearly, I have done some rounding off!), as the empirical formula. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Combustion data of an organic compound yielded #74.0%, C;# #7.4%, H;# #8.6%, N;# and the balance oxygen. What is the empirical formula?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="315656" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-29T04:27:36" itemprop="dateCreated"> Sep 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_10H_12NO#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As with all problems of this type, we assume a <mathjax>#100*g#</mathjax> mass of compound, and we determine the molar composition with respect to each element:</p> <p>And thus:</p> <p><mathjax>#"Moles of carbon"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(74.0*g)/(12.011*g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#6.16*mol#</mathjax></p> <p><mathjax>#"Moles of hydrogen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(7.4*g)/(1.00794*g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#7.34*mol#</mathjax></p> <p><mathjax>#"Moles of nitrogen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(8.6*g)/(14.01*g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.614*mol#</mathjax></p> <p><mathjax>#"Moles of oxygen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(10.0*g)/(16.00*g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.625*mol#</mathjax></p> <p>So we have the molar composition. We simply divide thru by the smallest molar quantity to gets our empirical formula:</p> <p>Dividing thru by <mathjax>#0.614*mol#</mathjax> we get <mathjax>#C_10H_12NO#</mathjax> (clearly, I have done some rounding off!), as the empirical formula. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/315656" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1326 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

Combustion data of an organic compound yielded #74.0%, C;# #7.4%, H;# #8.6%, N;# and the balance oxygen. What is the empirical formula?

a9922389-6ddd-11ea-9682-ccda262736ce

https://socratic.org/questions/analysis-of-a-compound-shows-that-it-contains-7-0-g-nitrogen-and-16-0-g-oxygen-w

NO2

start chemical_formula qc_end physical_unit 10 10 8 9 mass qc_end physical_unit 14 14 12 13 mass qc_end end

[{"type":"other","value":"Chemical Formula [OF] the compound [IN] empirical"}]

[{"type":"chemical equation","value":"NO2"}]

[{"type":"physical unit","value":"Mass [OF] nitrogen [=] \\pu{7.0 g}"},{"type":"physical unit","value":"Mass [OF] oxygen [=] \\pu{16.0 g}"}]

<h1 class="questionTitle" itemprop="name">Analysis of a compound shows that it contains 7.0 g nitrogen and 16.0 g oxygen. What is its empirical formula? </h1>

NO2

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula is the simplest whole number that defines constituent atoms in a species. </p> <p>Using the given masses, and the atomic masses of each constituent, we define an empirical formula this way:</p> <p><mathjax>#"Moles of nitrogen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(7.0*g)/(7.0*g+16*g)xx1/(14.01*g*mol^-1)=0.0217*mol#</mathjax>.</p> <p><mathjax>#"Moles of oxygen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(16.0*g)/(7.0*g+16*g)xx1/(15.999*g*mol^-1)=0.0435*mol#</mathjax>.</p> <p>And thus we have the molar quantities of nitrogen, and oxygen respectively. To access the empirical formula, we simply divide thru by the LOWEST molar quantity, that of nitrogen:</p> <p><mathjax>#N:(0.0217*mol)/(0.0217*mol)=1#</mathjax></p> <p><mathjax>#O:(0.0435*mol)/(0.0217*mol)=2#</mathjax></p> <p>And thus the empirical formula is <mathjax>#NO_2#</mathjax>.</p> <p>Note that to find the molecular formula we need an estimate of molecular mass.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#NO_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula is the simplest whole number that defines constituent atoms in a species. </p> <p>Using the given masses, and the atomic masses of each constituent, we define an empirical formula this way:</p> <p><mathjax>#"Moles of nitrogen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(7.0*g)/(7.0*g+16*g)xx1/(14.01*g*mol^-1)=0.0217*mol#</mathjax>.</p> <p><mathjax>#"Moles of oxygen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(16.0*g)/(7.0*g+16*g)xx1/(15.999*g*mol^-1)=0.0435*mol#</mathjax>.</p> <p>And thus we have the molar quantities of nitrogen, and oxygen respectively. To access the empirical formula, we simply divide thru by the LOWEST molar quantity, that of nitrogen:</p> <p><mathjax>#N:(0.0217*mol)/(0.0217*mol)=1#</mathjax></p> <p><mathjax>#O:(0.0435*mol)/(0.0217*mol)=2#</mathjax></p> <p>And thus the empirical formula is <mathjax>#NO_2#</mathjax>.</p> <p>Note that to find the molecular formula we need an estimate of molecular mass.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Analysis of a compound shows that it contains 7.0 g nitrogen and 16.0 g oxygen. What is its empirical formula? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="325495" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-23T14:59:22" itemprop="dateCreated"> Oct 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#NO_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula is the simplest whole number that defines constituent atoms in a species. </p> <p>Using the given masses, and the atomic masses of each constituent, we define an empirical formula this way:</p> <p><mathjax>#"Moles of nitrogen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(7.0*g)/(7.0*g+16*g)xx1/(14.01*g*mol^-1)=0.0217*mol#</mathjax>.</p> <p><mathjax>#"Moles of oxygen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(16.0*g)/(7.0*g+16*g)xx1/(15.999*g*mol^-1)=0.0435*mol#</mathjax>.</p> <p>And thus we have the molar quantities of nitrogen, and oxygen respectively. To access the empirical formula, we simply divide thru by the LOWEST molar quantity, that of nitrogen:</p> <p><mathjax>#N:(0.0217*mol)/(0.0217*mol)=1#</mathjax></p> <p><mathjax>#O:(0.0435*mol)/(0.0217*mol)=2#</mathjax></p> <p>And thus the empirical formula is <mathjax>#NO_2#</mathjax>.</p> <p>Note that to find the molecular formula we need an estimate of molecular mass.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/325495" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1935 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

Analysis of a compound shows that it contains 7.0 g nitrogen and 16.0 g oxygen. What is its empirical formula?

a9d6509c-6ddd-11ea-b361-ccda262736ce

https://socratic.org/questions/how-would-you-balance-the-following-equation-na2co3-bacl2-nacl-baco3

Na2CO3 + BaCl2 -> 2 NaCl + BaCO3

start chemical_equation qc_end chemical_equation 7 13 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"Na2CO3 + BaCl2 -> 2 NaCl + BaCO3"}]

[{"type":"chemical equation","value":"Na2CO3 + BaCl2 -> NaCl + BaCO3"}]

<h1 class="questionTitle" itemprop="name">How would you balance the following equation: Na2CO3 + BaCl2 --&gt; NaCl + BaCO3?</h1>

Na2CO3 + BaCl2 -> 2 NaCl + BaCO3

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It is important to notice that the <mathjax>#CO_3^(2-)#</mathjax> is a polyatomic ion, known as the carbonate ion. When balancing equations with <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/polyatomic-ions">polyatomic ions</a> you can consider them to be a single entity.</p> <p>On the reactant side you have:<br/> 2 <mathjax>#Na#</mathjax> <br/> 1 <mathjax>#CO_3#</mathjax> ion<br/> 1 <mathjax>#Ba#</mathjax><br/> 2 <mathjax>#Cl#</mathjax></p> <p>By placing 2 moles on the product side you conserve the mass of both <mathjax>#Na#</mathjax> and <mathjax>#Cl#</mathjax>.</p> <p>Since there is one <mathjax>#CO_3#</mathjax> ion and one<mathjax>#Ba#</mathjax> you don't need to worry about their stoiciometric coefficient.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Na_2CO_3+BaCl_2-&gt;2NaCl+BaCO_3#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It is important to notice that the <mathjax>#CO_3^(2-)#</mathjax> is a polyatomic ion, known as the carbonate ion. When balancing equations with <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/polyatomic-ions">polyatomic ions</a> you can consider them to be a single entity.</p> <p>On the reactant side you have:<br/> 2 <mathjax>#Na#</mathjax> <br/> 1 <mathjax>#CO_3#</mathjax> ion<br/> 1 <mathjax>#Ba#</mathjax><br/> 2 <mathjax>#Cl#</mathjax></p> <p>By placing 2 moles on the product side you conserve the mass of both <mathjax>#Na#</mathjax> and <mathjax>#Cl#</mathjax>.</p> <p>Since there is one <mathjax>#CO_3#</mathjax> ion and one<mathjax>#Ba#</mathjax> you don't need to worry about their stoiciometric coefficient.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How would you balance the following equation: Na2CO3 + BaCl2 --&gt; NaCl + BaCO3?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="185838" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/slangus"><img alt="" class="" src="https://profilepictures.socratic.org/drkbgwWiTc2nF7Sd9TrX_1103421756345992.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/slangus"> Slangus </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-09T00:52:08" itemprop="dateCreated"> Nov 9, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Na_2CO_3+BaCl_2-&gt;2NaCl+BaCO_3#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It is important to notice that the <mathjax>#CO_3^(2-)#</mathjax> is a polyatomic ion, known as the carbonate ion. When balancing equations with <a href="http://socratic.org/chemistry/ionic-bonds-and-formulas/polyatomic-ions">polyatomic ions</a> you can consider them to be a single entity.</p> <p>On the reactant side you have:<br/> 2 <mathjax>#Na#</mathjax> <br/> 1 <mathjax>#CO_3#</mathjax> ion<br/> 1 <mathjax>#Ba#</mathjax><br/> 2 <mathjax>#Cl#</mathjax></p> <p>By placing 2 moles on the product side you conserve the mass of both <mathjax>#Na#</mathjax> and <mathjax>#Cl#</mathjax>.</p> <p>Since there is one <mathjax>#CO_3#</mathjax> ion and one<mathjax>#Ba#</mathjax> you don't need to worry about their stoiciometric coefficient.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/185838" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------&gt; H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -&gt; Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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How would you balance the following equation: Na2CO3 + BaCl2 --&gt; NaCl + BaCO3?

aab4ec2c-6ddd-11ea-bac5-ccda262736ce

https://socratic.org/questions/a-sample-of-neon-has-a-volume-of-75-8-at-stp-how-many-moles-are-present

3.38 moles

start physical_unit 1 3 mole mol qc_end physical_unit 1 3 8 9 volume qc_end c_other STP qc_end end

[{"type":"physical unit","value":"Mole [OF] neon sample [IN] moles"}]

[{"type":"physical unit","value":"3.38 moles"}]

[{"type":"physical unit","value":"Volume [OF] neon sample [=] \\pu{75.8 L}"},{"type":"other","value":"STP"}]

<h1 class="questionTitle" itemprop="name">A sample of neon has a volume of 75.8 at STP. How many moles are present?</h1>

3.38 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>I am going to assume that you mean 75.8 L since there are no units associated with the volume you provided.</strong></p> <p>Because we are at standard temperature and pressure and are given only one set of conditions, we can to use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law equation</a>:<br/> <img alt="slideplayer.com" src="https://useruploads.socratic.org/Aj9e7GO2Svm4efvXTi8E_slide_2.jpg"/> </p> <p>I should mention that the pressure does not always have units of atm, it depends on the units of pressure given in the gas constant.</p> <p>List your known and unknown variables. </p> <p><mathjax>#color(magenta)("Knowns:"#</mathjax><br/> - Volume<br/> - Temperature<br/> - Pressure</p> <p><mathjax>#color(blue)("Unknowns:"#</mathjax><br/> Moles of neon</p> <p>At STP, the temperature is 273K and the pressure is 1 atm.</p> <p>Let's rearrange the equation to solve for n:</p> <p><mathjax># (PV)/(RT)=n#</mathjax></p> <p><mathjax>#n = (1 cancel"atm" xx 75.8 cancel"L")/((0.0821 cancel"L"xxcancel"atm")/("mol"cancel"K")xx273cancel"K"#</mathjax></p> <p><mathjax>#n#</mathjax> = 3.38 mol</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>3.38 moles are present</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>I am going to assume that you mean 75.8 L since there are no units associated with the volume you provided.</strong></p> <p>Because we are at standard temperature and pressure and are given only one set of conditions, we can to use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law equation</a>:<br/> <img alt="slideplayer.com" src="https://useruploads.socratic.org/Aj9e7GO2Svm4efvXTi8E_slide_2.jpg"/> </p> <p>I should mention that the pressure does not always have units of atm, it depends on the units of pressure given in the gas constant.</p> <p>List your known and unknown variables. </p> <p><mathjax>#color(magenta)("Knowns:"#</mathjax><br/> - Volume<br/> - Temperature<br/> - Pressure</p> <p><mathjax>#color(blue)("Unknowns:"#</mathjax><br/> Moles of neon</p> <p>At STP, the temperature is 273K and the pressure is 1 atm.</p> <p>Let's rearrange the equation to solve for n:</p> <p><mathjax># (PV)/(RT)=n#</mathjax></p> <p><mathjax>#n = (1 cancel"atm" xx 75.8 cancel"L")/((0.0821 cancel"L"xxcancel"atm")/("mol"cancel"K")xx273cancel"K"#</mathjax></p> <p><mathjax>#n#</mathjax> = 3.38 mol</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A sample of neon has a volume of 75.8 at STP. How many moles are present?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="354792" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-20T21:57:30" itemprop="dateCreated"> Dec 20, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>3.38 moles are present</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>I am going to assume that you mean 75.8 L since there are no units associated with the volume you provided.</strong></p> <p>Because we are at standard temperature and pressure and are given only one set of conditions, we can to use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law equation</a>:<br/> <img alt="slideplayer.com" src="https://useruploads.socratic.org/Aj9e7GO2Svm4efvXTi8E_slide_2.jpg"/> </p> <p>I should mention that the pressure does not always have units of atm, it depends on the units of pressure given in the gas constant.</p> <p>List your known and unknown variables. </p> <p><mathjax>#color(magenta)("Knowns:"#</mathjax><br/> - Volume<br/> - Temperature<br/> - Pressure</p> <p><mathjax>#color(blue)("Unknowns:"#</mathjax><br/> Moles of neon</p> <p>At STP, the temperature is 273K and the pressure is 1 atm.</p> <p>Let's rearrange the equation to solve for n:</p> <p><mathjax># (PV)/(RT)=n#</mathjax></p> <p><mathjax>#n = (1 cancel"atm" xx 75.8 cancel"L")/((0.0821 cancel"L"xxcancel"atm")/("mol"cancel"K")xx273cancel"K"#</mathjax></p> <p><mathjax>#n#</mathjax> = 3.38 mol</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/354792" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? 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A sample of neon has a volume of 75.8 at STP. How many moles are present?

aa588338-6ddd-11ea-9bb5-ccda262736ce

https://socratic.org/questions/a-gas-expands-from-35-ml-to-70ml-if-the-temperature-was-at-22-celsius-what-will-

317 celsius

start physical_unit 1 1 temperature °c qc_end physical_unit 1 1 14 15 temperature qc_end physical_unit 1 1 4 5 volume qc_end physical_unit 1 1 7 8 volume qc_end end

[{"type":"physical unit","value":"Temperature2 [OF] the gas [IN] celsius"}]

[{"type":"physical unit","value":"317 celsius"}]

[{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{22 celsius}"},{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{35 ml}"},{"type":"physical unit","value":"Volume2 [OF] the gas [=] \\pu{70 ml}"}]

<h1 class="questionTitle" itemprop="name">A gas expands from 35 ml to 70ml. if the temperature was at 22 Celsius, what will the final temperature be? </h1>

317 celsius

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is explained by <a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a>. The volume of a gas is directly proportional to the Kelvin temperature of the gas. In order to double the volume (as is seen here) we must double the Kelvin temperature.</p> <p>In equation form, Charles' Law can be expressed as:</p> <p><mathjax>#(V_2)/(T_2) = (V_1)/(T_1)#</mathjax></p> <p>Hence:</p> <p><mathjax>#T_2 = ((V_2)*(T_1))/(V_1) = ((70)*(295))/(35) = 590 K#</mathjax></p> <p>where you note the Celsius temperatures are converted to Kelvin by adding 273 to each.</p> <p><mathjax>#590 K = 590 - 273 = 317 °C#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final temperature would be 317°C</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is explained by <a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a>. The volume of a gas is directly proportional to the Kelvin temperature of the gas. In order to double the volume (as is seen here) we must double the Kelvin temperature.</p> <p>In equation form, Charles' Law can be expressed as:</p> <p><mathjax>#(V_2)/(T_2) = (V_1)/(T_1)#</mathjax></p> <p>Hence:</p> <p><mathjax>#T_2 = ((V_2)*(T_1))/(V_1) = ((70)*(295))/(35) = 590 K#</mathjax></p> <p>where you note the Celsius temperatures are converted to Kelvin by adding 273 to each.</p> <p><mathjax>#590 K = 590 - 273 = 317 °C#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A gas expands from 35 ml to 70ml. if the temperature was at 22 Celsius, what will the final temperature be? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/charles-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Charles' Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="413280" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/dwight"><img alt="" class="" src="https://profilepictures.socratic.org/ZDiTFWmAQmWOT3sd0Xpr_Dwight.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/dwight"> Dwight </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-26T16:43:42" itemprop="dateCreated"> Apr 26, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final temperature would be 317°C</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is explained by <a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a>. The volume of a gas is directly proportional to the Kelvin temperature of the gas. In order to double the volume (as is seen here) we must double the Kelvin temperature.</p> <p>In equation form, Charles' Law can be expressed as:</p> <p><mathjax>#(V_2)/(T_2) = (V_1)/(T_1)#</mathjax></p> <p>Hence:</p> <p><mathjax>#T_2 = ((V_2)*(T_1))/(V_1) = ((70)*(295))/(35) = 590 K#</mathjax></p> <p>where you note the Celsius temperatures are converted to Kelvin by adding 273 to each.</p> <p><mathjax>#590 K = 590 - 273 = 317 °C#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/413280" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-must-charles-law-be-in-kelvins"> Why must Charles' law be in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-charles-law-formula"> What is Charles' law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/oxygen-gas-is-at-a-temperature-of-40-c-when-it-occupies-a-volume-of-2-3-liters-t"> Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.3 liters. 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A gas expands from 35 ml to 70ml. if the temperature was at 22 Celsius, what will the final temperature be?

ac4cbd0a-6ddd-11ea-8f4c-ccda262736ce

https://socratic.org/questions/a-quantity-of-n-2-gas-originally-held-at-4-75-am-in-a-1-00l-container-at-26-c-is

0.47 atm

start physical_unit 3 4 pressure atm qc_end physical_unit 3 4 8 9 pressure qc_end physical_unit 3 4 12 13 volume qc_end physical_unit 3 4 16 17 temperature qc_end physical_unit 3 4 22 23 volume qc_end physical_unit 3 4 26 27 temperature qc_end end

[{"type":"physical unit","value":"Pressure2 [OF] N2 gas [IN] atm"}]

[{"type":"physical unit","value":"0.47 atm"}]

[{"type":"physical unit","value":"Pressure1 [OF] N2 gas [=] \\pu{4.75 atm}"},{"type":"physical unit","value":"Volume1 [OF] N2 gas [=] \\pu{1.00 L}"},{"type":"physical unit","value":"Temperature1 [OF] N2 gas [=] \\pu{26 ℃}"},{"type":"physical unit","value":"Volume2 [OF] N2 gas [=] \\pu{10.0 L}"},{"type":"physical unit","value":"Temperature2 [OF] N2 gas [=] \\pu{20 ℃}"}]

<h1 class="questionTitle" itemprop="name">A quantity of #N_2# gas originally held at 4.75 am in a 1.00L container at 26°C is transferred to a 10.0 L container at 20°C. What is the total pressure in the new container?</h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Also, a quantity of <mathjax>#O_2#</mathjax> gas originally at 5.25 atm and 26°C in a 5.00 L container is transferred to this same container. </p></div> </h2> </div> </div>

0.47 atm

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Notice that the <em>volume</em> and the <em>temperature</em> of the gas change when going from the first container to the second container, but that the <em>number of moles</em> of gas remains <strong>constant</strong>. </p> <p>This tells you that you can use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a> equation to find the change in <em>pressure</em></p> <blockquote> <p><mathjax>#color(blue)((P_1V_1)/T_1 = (P_2V_2)/T_2)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P_1#</mathjax>, <mathjax>#T_1#</mathjax>, <mathjax>#V_1#</mathjax> - the pressure, temperature, and volume of the gas in the first container<br/> <mathjax>#P_2#</mathjax>, <mathjax>#T_2#</mathjax>, <mathjax>#V_2#</mathjax> - the pressure, temperature, and volume of the gas in the second container</p> <p>Notice that the <strong>volume</strong> of the container <em>increases</em> by a factor of <mathjax>#10#</mathjax>, and that the temperature of the gas <strong>decreases</strong>. Both these changes allow you to precit that the pressure of the gas will be <strong>smaller</strong> in the second container. </p> <p>Plug your values and solve for <mathjax>#P_2#</mathjax> - <strong>do not</strong> forget to convert the temperature from <em>degrees Celsius</em> to <em>Kelvin</em>!</p> <blockquote> <p><mathjax>#P_2 = V_1/V_2 * T_2/T_1 * P_1#</mathjax></p> <p><mathjax>#P_2 = (1.00 color(red)(cancel(color(black)("L"))))/(10.0color(red)(cancel(color(black)("L")))) * ( (273.15 + 20)color(red)(cancel(color(black)("K"))))/( (273.15 + 26)color(red)(cancel(color(black)("K")))) * "4.75 atm"#</mathjax></p> <p><mathjax>#P_2 = "0.4655 atm"#</mathjax></p> </blockquote> <p>You <em>should</em> round this off to one <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a>, the number of sig figs you have for the temperature of the gas in the second container, but I'll leave it rounded to two sig figs</p> <blockquote> <p><mathjax>#P_2 = color(green)("0.47 atm")#</mathjax></p> </blockquote> <p>I'll leave the second part of the problem, the one with the sample of oxygen, to you as practice. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.47 atm"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Notice that the <em>volume</em> and the <em>temperature</em> of the gas change when going from the first container to the second container, but that the <em>number of moles</em> of gas remains <strong>constant</strong>. </p> <p>This tells you that you can use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a> equation to find the change in <em>pressure</em></p> <blockquote> <p><mathjax>#color(blue)((P_1V_1)/T_1 = (P_2V_2)/T_2)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P_1#</mathjax>, <mathjax>#T_1#</mathjax>, <mathjax>#V_1#</mathjax> - the pressure, temperature, and volume of the gas in the first container<br/> <mathjax>#P_2#</mathjax>, <mathjax>#T_2#</mathjax>, <mathjax>#V_2#</mathjax> - the pressure, temperature, and volume of the gas in the second container</p> <p>Notice that the <strong>volume</strong> of the container <em>increases</em> by a factor of <mathjax>#10#</mathjax>, and that the temperature of the gas <strong>decreases</strong>. Both these changes allow you to precit that the pressure of the gas will be <strong>smaller</strong> in the second container. </p> <p>Plug your values and solve for <mathjax>#P_2#</mathjax> - <strong>do not</strong> forget to convert the temperature from <em>degrees Celsius</em> to <em>Kelvin</em>!</p> <blockquote> <p><mathjax>#P_2 = V_1/V_2 * T_2/T_1 * P_1#</mathjax></p> <p><mathjax>#P_2 = (1.00 color(red)(cancel(color(black)("L"))))/(10.0color(red)(cancel(color(black)("L")))) * ( (273.15 + 20)color(red)(cancel(color(black)("K"))))/( (273.15 + 26)color(red)(cancel(color(black)("K")))) * "4.75 atm"#</mathjax></p> <p><mathjax>#P_2 = "0.4655 atm"#</mathjax></p> </blockquote> <p>You <em>should</em> round this off to one <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a>, the number of sig figs you have for the temperature of the gas in the second container, but I'll leave it rounded to two sig figs</p> <blockquote> <p><mathjax>#P_2 = color(green)("0.47 atm")#</mathjax></p> </blockquote> <p>I'll leave the second part of the problem, the one with the sample of oxygen, to you as practice. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A quantity of #N_2# gas originally held at 4.75 am in a 1.00L container at 26°C is transferred to a 10.0 L container at 20°C. What is the total pressure in the new container?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Also, a quantity of <mathjax>#O_2#</mathjax> gas originally at 5.25 atm and 26°C in a 5.00 L container is transferred to this same container. </p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/combined-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Combined Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="198794" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-12T00:38:19" itemprop="dateCreated"> Dec 12, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.47 atm"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Notice that the <em>volume</em> and the <em>temperature</em> of the gas change when going from the first container to the second container, but that the <em>number of moles</em> of gas remains <strong>constant</strong>. </p> <p>This tells you that you can use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a> equation to find the change in <em>pressure</em></p> <blockquote> <p><mathjax>#color(blue)((P_1V_1)/T_1 = (P_2V_2)/T_2)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P_1#</mathjax>, <mathjax>#T_1#</mathjax>, <mathjax>#V_1#</mathjax> - the pressure, temperature, and volume of the gas in the first container<br/> <mathjax>#P_2#</mathjax>, <mathjax>#T_2#</mathjax>, <mathjax>#V_2#</mathjax> - the pressure, temperature, and volume of the gas in the second container</p> <p>Notice that the <strong>volume</strong> of the container <em>increases</em> by a factor of <mathjax>#10#</mathjax>, and that the temperature of the gas <strong>decreases</strong>. Both these changes allow you to precit that the pressure of the gas will be <strong>smaller</strong> in the second container. </p> <p>Plug your values and solve for <mathjax>#P_2#</mathjax> - <strong>do not</strong> forget to convert the temperature from <em>degrees Celsius</em> to <em>Kelvin</em>!</p> <blockquote> <p><mathjax>#P_2 = V_1/V_2 * T_2/T_1 * P_1#</mathjax></p> <p><mathjax>#P_2 = (1.00 color(red)(cancel(color(black)("L"))))/(10.0color(red)(cancel(color(black)("L")))) * ( (273.15 + 20)color(red)(cancel(color(black)("K"))))/( (273.15 + 26)color(red)(cancel(color(black)("K")))) * "4.75 atm"#</mathjax></p> <p><mathjax>#P_2 = "0.4655 atm"#</mathjax></p> </blockquote> <p>You <em>should</em> round this off to one <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a>, the number of sig figs you have for the temperature of the gas in the second container, but I'll leave it rounded to two sig figs</p> <blockquote> <p><mathjax>#P_2 = color(green)("0.47 atm")#</mathjax></p> </blockquote> <p>I'll leave the second part of the problem, the one with the sample of oxygen, to you as practice. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/198794" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5345df5f02bf345f71b1c8e8"> Question #1c8e8 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ac3df02bf342f4c3bfabb"> Question #bfabb </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-you-want-to-solve-for-the-volume-of-a-gas-v2-and-p1-is-greater-than-p2-would-"> If you want to solve for the volume of a gas (V2) and P1 is greater than P2, would you expect V2... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-modern-refrigerator-take-advantage-of-the-gas-laws-to-remove-heat-f"> How does the modern refrigerator take advantage of the gas laws to remove heat from a system? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-certain-sample-of-gas-has-a-volume-of-0-452-l-measured-at-87-c-and-0-620-atm-w"> A certain sample of gas has a volume of 0.452 L measured at 87°C and 0.620 atm. 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A quantity of #N_2# gas originally held at 4.75 am in a 1.00L container at 26°C is transferred to a 10.0 L container at 20°C. What is the total pressure in the new container?

Also, a quantity of #O_2# gas originally at 5.25 atm and 26°C in a 5.00 L container is transferred to this same container.

ab2605b8-6ddd-11ea-8617-ccda262736ce

https://socratic.org/questions/what-mass-is-a-sample-of-oxygen-gas-that-contains-avogadro-s-number-of-atoms

16.00 g

start physical_unit 4 7 mass g qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Mass [OF] oxygen gas sample [IN] g"}]

[{"type":"physical unit","value":"16.00 g"}]

[{"type":"other","value":"Sample of oxygen gas that contains Avogadro's number of atoms."}]

<h1 class="questionTitle" itemprop="name">What mass is a sample of oxygen gas that contains Avogadro's number of atoms?</h1>

16.00 g

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Most of the elemental gases, certainly the gases with any chemistry are BINUCLEAR... We speak of <mathjax>#"dinitrogen"#</mathjax>, <mathjax>#"dioxygen"#</mathjax>, <mathjax>#"dihalogen"#</mathjax>...</p> <p>And so given a <mathjax>#16*g#</mathjax> mass of <mathjax>#O_2#</mathjax>...we gots HALF a mole of <mathjax>#O_2#</mathjax> <mathjax>#"oxygen molecules"#</mathjax>, and this is EQUIVALENT to <mathjax>#"ONE MOLE"#</mathjax> of <mathjax>#"oxygen atoms"#</mathjax>...</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"A 16 g mass..."#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Most of the elemental gases, certainly the gases with any chemistry are BINUCLEAR... We speak of <mathjax>#"dinitrogen"#</mathjax>, <mathjax>#"dioxygen"#</mathjax>, <mathjax>#"dihalogen"#</mathjax>...</p> <p>And so given a <mathjax>#16*g#</mathjax> mass of <mathjax>#O_2#</mathjax>...we gots HALF a mole of <mathjax>#O_2#</mathjax> <mathjax>#"oxygen molecules"#</mathjax>, and this is EQUIVALENT to <mathjax>#"ONE MOLE"#</mathjax> of <mathjax>#"oxygen atoms"#</mathjax>...</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What mass is a sample of oxygen gas that contains Avogadro's number of atoms?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/avogadro-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Avogadro's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="636831" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-28T18:14:19" itemprop="dateCreated"> Jun 28, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"A 16 g mass..."#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Most of the elemental gases, certainly the gases with any chemistry are BINUCLEAR... We speak of <mathjax>#"dinitrogen"#</mathjax>, <mathjax>#"dioxygen"#</mathjax>, <mathjax>#"dihalogen"#</mathjax>...</p> <p>And so given a <mathjax>#16*g#</mathjax> mass of <mathjax>#O_2#</mathjax>...we gots HALF a mole of <mathjax>#O_2#</mathjax> <mathjax>#"oxygen molecules"#</mathjax>, and this is EQUIVALENT to <mathjax>#"ONE MOLE"#</mathjax> of <mathjax>#"oxygen atoms"#</mathjax>...</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/636831" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-avogadro-s-law-important"> Why is Avogadro's law important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-was-the-avogadro-s-law-discovered"> How was the Avogadro's law discovered? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-avogadro-s-law-used-in-stoichiometry"> Is Avogadro's law used in stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-avogadro-s-law-used-in-everyday-life"> How is Avogadro's law used in everyday life? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-with-avogadro-s-law"> What are some common mistakes students make with Avogadro's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-an-avogadro-s-law-practice-problem"> What is an example of an Avogadro's law practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-the-avogadro-s-law"> What are some examples of the Avogadro's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/according-to-avogadro-s-law-as-the-number-of-moles-of-gas-increases-what-happens"> According to Avogadro's law, as the number of moles of gas increases, what happens to its volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-the-avogadro-s-law-written"> How is the Avogadro's law written? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-avogadro-s-principle"> What is the Avogadro's principle? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/avogadro-s-law"> See all questions in Avogadro's Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2777 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What mass is a sample of oxygen gas that contains Avogadro's number of atoms?

ac2fcb66-6ddd-11ea-bcfe-ccda262736ce

https://socratic.org/questions/given-that-the-molar-mass-of-nacl-58-44-g-mol-what-is-the-molarity-of-a-solution

3.00 M

start physical_unit 6 6 molarity mol/l qc_end physical_unit 6 6 7 8 molar_mass qc_end physical_unit 6 6 18 19 mass qc_end physical_unit 15 15 23 24 volume qc_end end

[{"type":"physical unit","value":"Molarity [OF] NaCl solution [IN] M"}]

[{"type":"physical unit","value":"3.00 M"}]

[{"type":"physical unit","value":"Molar mass [OF] NaCl [=] \\pu{58.44 g/mol}"},{"type":"physical unit","value":"Mass [OF] NaCl [=] \\pu{87.75 g }"},{"type":"physical unit","value":"Volume [OF] NaCl solution [=] \\pu{500 mL}"}]

<h1 class="questionTitle" itemprop="name">Given that the molar mass of NaCl 58.44 g/mol, what is the molarity of a solution that contains 87.75 g of NaCl in 500. mL of solution?</h1>

3.00 M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a></strong> is a measure of how many <em>moles</em> of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> you get in exactly <mathjax>#"1 L"#</mathjax> of a given solution. </p> <p>Your goal here is to use the <strong>molar mass</strong> of sodium chloride to find the number of <em>moles</em> present in the sample.</p> <blockquote> <p><mathjax>#87.75 color(red)(cancel(color(black)("g"))) * "1 mole NaCl"/(58.44color(red)(cancel(color(black)("g")))) = "1.5015 moles NaCl"#</mathjax></p> </blockquote> <p>Now, you know that this solution contains <mathjax>#1.5015#</mathjax> <strong>moles</strong> of sodium chloride, the solute, in <mathjax>#"500. mL"#</mathjax> of solution. Since </p> <blockquote> <p><mathjax>#500.0 color(red)(cancel(color(black)("mL"))) * "1 L"/(10^3color(red)(cancel(color(black)("mL")))) = "0.500 L"#</mathjax></p> </blockquote> <p>you can use this known composition of the solution as a <em>conversion factor</em> to help you find the number of moles of solute present in <mathjax>#"1 L"#</mathjax> of solution </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("L solution"))) * "1.5015 moles NaCl"/(0.500color(red)(cancel(color(black)("L solution")))) = "3.003 moles NaCl"#</mathjax></p> </blockquote> <p>You can now say that the molarity of the solution is </p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("molarity = 3.00 mol L"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the volume of the solution. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"3.00 mol L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a></strong> is a measure of how many <em>moles</em> of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> you get in exactly <mathjax>#"1 L"#</mathjax> of a given solution. </p> <p>Your goal here is to use the <strong>molar mass</strong> of sodium chloride to find the number of <em>moles</em> present in the sample.</p> <blockquote> <p><mathjax>#87.75 color(red)(cancel(color(black)("g"))) * "1 mole NaCl"/(58.44color(red)(cancel(color(black)("g")))) = "1.5015 moles NaCl"#</mathjax></p> </blockquote> <p>Now, you know that this solution contains <mathjax>#1.5015#</mathjax> <strong>moles</strong> of sodium chloride, the solute, in <mathjax>#"500. mL"#</mathjax> of solution. Since </p> <blockquote> <p><mathjax>#500.0 color(red)(cancel(color(black)("mL"))) * "1 L"/(10^3color(red)(cancel(color(black)("mL")))) = "0.500 L"#</mathjax></p> </blockquote> <p>you can use this known composition of the solution as a <em>conversion factor</em> to help you find the number of moles of solute present in <mathjax>#"1 L"#</mathjax> of solution </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("L solution"))) * "1.5015 moles NaCl"/(0.500color(red)(cancel(color(black)("L solution")))) = "3.003 moles NaCl"#</mathjax></p> </blockquote> <p>You can now say that the molarity of the solution is </p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("molarity = 3.00 mol L"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the volume of the solution. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Given that the molar mass of NaCl 58.44 g/mol, what is the molarity of a solution that contains 87.75 g of NaCl in 500. mL of solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="382081" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-24T00:02:40" itemprop="dateCreated"> Feb 24, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"3.00 mol L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a></strong> is a measure of how many <em>moles</em> of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> you get in exactly <mathjax>#"1 L"#</mathjax> of a given solution. </p> <p>Your goal here is to use the <strong>molar mass</strong> of sodium chloride to find the number of <em>moles</em> present in the sample.</p> <blockquote> <p><mathjax>#87.75 color(red)(cancel(color(black)("g"))) * "1 mole NaCl"/(58.44color(red)(cancel(color(black)("g")))) = "1.5015 moles NaCl"#</mathjax></p> </blockquote> <p>Now, you know that this solution contains <mathjax>#1.5015#</mathjax> <strong>moles</strong> of sodium chloride, the solute, in <mathjax>#"500. mL"#</mathjax> of solution. Since </p> <blockquote> <p><mathjax>#500.0 color(red)(cancel(color(black)("mL"))) * "1 L"/(10^3color(red)(cancel(color(black)("mL")))) = "0.500 L"#</mathjax></p> </blockquote> <p>you can use this known composition of the solution as a <em>conversion factor</em> to help you find the number of moles of solute present in <mathjax>#"1 L"#</mathjax> of solution </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("L solution"))) * "1.5015 moles NaCl"/(0.500color(red)(cancel(color(black)("L solution")))) = "3.003 moles NaCl"#</mathjax></p> </blockquote> <p>You can now say that the molarity of the solution is </p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("molarity = 3.00 mol L"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the volume of the solution. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/382081" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 16353 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

Given that the molar mass of NaCl 58.44 g/mol, what is the molarity of a solution that contains 87.75 g of NaCl in 500. mL of solution?

ac4640d4-6ddd-11ea-ae73-ccda262736ce

https://socratic.org/questions/given-the-balanced-equation-lioh-kcl-licl-koh-what-is-the-theoretical-yield-of-l

35.4 g

start physical_unit 17 18 theoretical_yield g qc_end chemical_equation 4 10 qc_end physical_unit 28 29 25 26 mass qc_end end

[{"type":"physical unit","value":"Theoretical yield [OF] lithium chloride [IN] g"}]

[{"type":"physical unit","value":"35.4 g"}]

[{"type":"chemical equation","value":"LiOH + KCl -> LiCl + KOH"},{"type":"physical unit","value":"Mass [OF] lithium hydroxide [=] \\pu{20.0 grams}"}]

<h1 class="questionTitle" itemprop="name">Given the balanced equation, #LiOH + KCl -&gt; LiCl + KOH#, what is the theoretical yield of lithium chloride if you start this reaction with 20.0 grams of lithium hydroxide?</h1>

35.4 g

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The five basic steps to solve a theoretical yield problem are:</p> <ol> <li>Write the balanced equation for the reaction between <mathjax>#"LiOH"#</mathjax> and <mathjax>#"KCl"#</mathjax>.</li> <li>Use the molar mass of <mathjax>#"LiOH"#</mathjax> to convert grams of <mathjax>#"LiOH"#</mathjax> to moles of <mathjax>#"LiOH"#</mathjax>.</li> <li>Use the molar ratio from the balanced equation to convert moles of <mathjax>#"LiOH"#</mathjax> to moles of <mathjax>#"LiCl"#</mathjax>.</li> <li>Use the molar mass of <mathjax>#"LiCl"#</mathjax> to convert moles of <mathjax>#"LiCl"#</mathjax> to grams of <mathjax>#"LiCl"#</mathjax>.</li> </ol> <p>In summary, the conversions are</p> <p><mathjax>#"g LiOH" stackrel(color(blue)("molar mass"color(white)(m)))(→) "mol LiOH" stackrel(color(blue)("molar ratio"color(white)(m)))(→) "mol LiCl" stackrel(color(blue)("molar mass"color(white)(m)))(→) "g LiCl"#</mathjax></p> <p>To 3 <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, you should get</p> <p><mathjax>#"20.0 g LiOH" → "0.835 mol LiOH" → "0.835 mol LiCl" → "35.4 g LiCl"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The theoretical yield is <mathjax>#"35.4 g LiCl"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The five basic steps to solve a theoretical yield problem are:</p> <ol> <li>Write the balanced equation for the reaction between <mathjax>#"LiOH"#</mathjax> and <mathjax>#"KCl"#</mathjax>.</li> <li>Use the molar mass of <mathjax>#"LiOH"#</mathjax> to convert grams of <mathjax>#"LiOH"#</mathjax> to moles of <mathjax>#"LiOH"#</mathjax>.</li> <li>Use the molar ratio from the balanced equation to convert moles of <mathjax>#"LiOH"#</mathjax> to moles of <mathjax>#"LiCl"#</mathjax>.</li> <li>Use the molar mass of <mathjax>#"LiCl"#</mathjax> to convert moles of <mathjax>#"LiCl"#</mathjax> to grams of <mathjax>#"LiCl"#</mathjax>.</li> </ol> <p>In summary, the conversions are</p> <p><mathjax>#"g LiOH" stackrel(color(blue)("molar mass"color(white)(m)))(→) "mol LiOH" stackrel(color(blue)("molar ratio"color(white)(m)))(→) "mol LiCl" stackrel(color(blue)("molar mass"color(white)(m)))(→) "g LiCl"#</mathjax></p> <p>To 3 <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, you should get</p> <p><mathjax>#"20.0 g LiOH" → "0.835 mol LiOH" → "0.835 mol LiCl" → "35.4 g LiCl"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Given the balanced equation, #LiOH + KCl -&gt; LiCl + KOH#, what is the theoretical yield of lithium chloride if you start this reaction with 20.0 grams of lithium hydroxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/percent-yield" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Yield</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="245477" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-26T16:41:07" itemprop="dateCreated"> Mar 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The theoretical yield is <mathjax>#"35.4 g LiCl"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The five basic steps to solve a theoretical yield problem are:</p> <ol> <li>Write the balanced equation for the reaction between <mathjax>#"LiOH"#</mathjax> and <mathjax>#"KCl"#</mathjax>.</li> <li>Use the molar mass of <mathjax>#"LiOH"#</mathjax> to convert grams of <mathjax>#"LiOH"#</mathjax> to moles of <mathjax>#"LiOH"#</mathjax>.</li> <li>Use the molar ratio from the balanced equation to convert moles of <mathjax>#"LiOH"#</mathjax> to moles of <mathjax>#"LiCl"#</mathjax>.</li> <li>Use the molar mass of <mathjax>#"LiCl"#</mathjax> to convert moles of <mathjax>#"LiCl"#</mathjax> to grams of <mathjax>#"LiCl"#</mathjax>.</li> </ol> <p>In summary, the conversions are</p> <p><mathjax>#"g LiOH" stackrel(color(blue)("molar mass"color(white)(m)))(→) "mol LiOH" stackrel(color(blue)("molar ratio"color(white)(m)))(→) "mol LiCl" stackrel(color(blue)("molar mass"color(white)(m)))(→) "g LiCl"#</mathjax></p> <p>To 3 <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, you should get</p> <p><mathjax>#"20.0 g LiOH" → "0.835 mol LiOH" → "0.835 mol LiCl" → "35.4 g LiCl"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/245477" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ebd02bf3469570e2e62"> Question #e2e62 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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Given the balanced equation, #LiOH + KCl -&gt; LiCl + KOH#, what is the theoretical yield of lithium chloride if you start this reaction with 20.0 grams of lithium hydroxide?

acde2e29-6ddd-11ea-9092-ccda262736ce

https://socratic.org/questions/58cab7ce11ef6b67966920c2

3.01 × 10^23

start physical_unit 3 4 number none qc_end physical_unit 13 14 9 10 mass qc_end end

[{"type":"physical unit","value":"Number [OF] magnesium ATOMS"}]

[{"type":"physical unit","value":"3.01 × 10^23"}]

[{"type":"physical unit","value":"Mass [OF] the metal [=] \\pu{12 g}"}]

<h1 class="questionTitle" itemprop="name">What number of magnesium ATOMS are contained in a #12*g# mass of the metal?</h1>

3.01 × 10^23

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Number of atoms of Mg"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#"Mass of metal"/"Molar mass of metal"xxN_A#</mathjax>, </p> <p>where <mathjax>#N_A-="Avogadro's number"=6.022xx10^23*mol^-1#</mathjax></p> <p>And so to business, </p> <p><mathjax>#"Number of atoms of Mg"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#(12*g)/(24.31*g*mol^-1)xxN_A#</mathjax>, </p> <p><mathjax>#=1/2*cancel(mol)xx6.022xx10^23*cancel(mol^-1)#</mathjax></p> <p><mathjax>#=3.011xx10^23#</mathjax>, a <mathjax>#"noomber"#</mathjax> as required.........</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Number of atoms......= "3.011xx10^23#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Number of atoms of Mg"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#"Mass of metal"/"Molar mass of metal"xxN_A#</mathjax>, </p> <p>where <mathjax>#N_A-="Avogadro's number"=6.022xx10^23*mol^-1#</mathjax></p> <p>And so to business, </p> <p><mathjax>#"Number of atoms of Mg"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#(12*g)/(24.31*g*mol^-1)xxN_A#</mathjax>, </p> <p><mathjax>#=1/2*cancel(mol)xx6.022xx10^23*cancel(mol^-1)#</mathjax></p> <p><mathjax>#=3.011xx10^23#</mathjax>, a <mathjax>#"noomber"#</mathjax> as required.........</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What number of magnesium ATOMS are contained in a #12*g# mass of the metal?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="392223" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-16T16:19:56" itemprop="dateCreated"> Mar 16, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Number of atoms......= "3.011xx10^23#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Number of atoms of Mg"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#"Mass of metal"/"Molar mass of metal"xxN_A#</mathjax>, </p> <p>where <mathjax>#N_A-="Avogadro's number"=6.022xx10^23*mol^-1#</mathjax></p> <p>And so to business, </p> <p><mathjax>#"Number of atoms of Mg"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#(12*g)/(24.31*g*mol^-1)xxN_A#</mathjax>, </p> <p><mathjax>#=1/2*cancel(mol)xx6.022xx10^23*cancel(mol^-1)#</mathjax></p> <p><mathjax>#=3.011xx10^23#</mathjax>, a <mathjax>#"noomber"#</mathjax> as required.........</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/392223" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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What number of magnesium ATOMS are contained in a #12*g# mass of the metal?

ac056fe2-6ddd-11ea-a8ed-ccda262736ce

https://socratic.org/questions/58d3be23b72cff5c2be2b467

70.73 L

start physical_unit 11 12 volume l qc_end physical_unit 11 12 7 8 mass qc_end physical_unit 11 12 14 15 temperature qc_end physical_unit 11 12 24 25 pressure qc_end end

[{"type":"physical unit","value":"Volume [OF] carbon dioxide [IN] L"}]

[{"type":"physical unit","value":"70.73 L"}]

[{"type":"physical unit","value":"Mass [OF] carbon dioxide [=] \\pu{74.3 g}"},{"type":"physical unit","value":"Temperature [OF] carbon dioxide [=] \\pu{294 K}"},{"type":"physical unit","value":"Pressure [OF] carbon dioxide [=] \\pu{439 mmHg}"}]

<h1 class="questionTitle" itemprop="name">What is the volume expressed by a #74.3*g# mass of carbon dioxide at #294.9*K# enclosed in a piston at a pressure of #439*"mm Hg"#?</h1>

70.73 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The key to this question is to express the pressure, which is given in <mathjax>#"mm Hg"#</mathjax>, to atmospheres. We know (or should know) that <mathjax>#1*atm#</mathjax> will support a column of mercury that is <mathjax>#760*mm#</mathjax> high. Mercury columns (which are fast disappearing in laboratories these days) provides a highly visual and accessible measurement of pressures BELOW atmospheric.</p> <p>And thus <mathjax>#P=("439 mm Hg")/("760 mm Hg"*atm^-1)=0.578*atm#</mathjax></p> <p>And thus <mathjax>#V=((74.3*g)/(44.0*g*mol^-1)xx0.0821*L*atm*K^-1*mol^-1xx294.9K)/(0.578*atm)#</mathjax></p> <p><mathjax>#~=70*L#</mathjax></p> <p>Do the units in the calculation cancel out to give an answer in <mathjax>#L#</mathjax>? If not they should!</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V=(nRT)/P~=70*L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The key to this question is to express the pressure, which is given in <mathjax>#"mm Hg"#</mathjax>, to atmospheres. We know (or should know) that <mathjax>#1*atm#</mathjax> will support a column of mercury that is <mathjax>#760*mm#</mathjax> high. Mercury columns (which are fast disappearing in laboratories these days) provides a highly visual and accessible measurement of pressures BELOW atmospheric.</p> <p>And thus <mathjax>#P=("439 mm Hg")/("760 mm Hg"*atm^-1)=0.578*atm#</mathjax></p> <p>And thus <mathjax>#V=((74.3*g)/(44.0*g*mol^-1)xx0.0821*L*atm*K^-1*mol^-1xx294.9K)/(0.578*atm)#</mathjax></p> <p><mathjax>#~=70*L#</mathjax></p> <p>Do the units in the calculation cancel out to give an answer in <mathjax>#L#</mathjax>? If not they should!</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the volume expressed by a #74.3*g# mass of carbon dioxide at #294.9*K# enclosed in a piston at a pressure of #439*"mm Hg"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="395384" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-23T13:53:09" itemprop="dateCreated"> Mar 23, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V=(nRT)/P~=70*L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The key to this question is to express the pressure, which is given in <mathjax>#"mm Hg"#</mathjax>, to atmospheres. We know (or should know) that <mathjax>#1*atm#</mathjax> will support a column of mercury that is <mathjax>#760*mm#</mathjax> high. Mercury columns (which are fast disappearing in laboratories these days) provides a highly visual and accessible measurement of pressures BELOW atmospheric.</p> <p>And thus <mathjax>#P=("439 mm Hg")/("760 mm Hg"*atm^-1)=0.578*atm#</mathjax></p> <p>And thus <mathjax>#V=((74.3*g)/(44.0*g*mol^-1)xx0.0821*L*atm*K^-1*mol^-1xx294.9K)/(0.578*atm)#</mathjax></p> <p><mathjax>#~=70*L#</mathjax></p> <p>Do the units in the calculation cancel out to give an answer in <mathjax>#L#</mathjax>? If not they should!</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/395384" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1200 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the volume expressed by a #74.3*g# mass of carbon dioxide at #294.9*K# enclosed in a piston at a pressure of #439*"mm Hg"#?

a8e4e0db-6ddd-11ea-9851-ccda262736ce

https://socratic.org/questions/what-is-the-percent-composition-by-mass-of-oxygen-in-magnesium-oxide

39.70%

start physical_unit 8 11 mass_percent none qc_end substance 10 11 qc_end end

[{"type":"physical unit","value":"Percent composition by mass [OF] oxygen in magnesium oxide"}]

[{"type":"physical unit","value":"39.70%"}]

[{"type":"substance name","value":"Magnesium oxide"}]

<h1 class="questionTitle" itemprop="name"> What is the percent composition by mass of oxygen in magnesium oxide?</h1>

39.70%

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Percentage oxygen composition in magnesium oxide "=#</mathjax></p> <p><mathjax>#"Mass of oxygen"/"Mass of oxygen + mass of magnesium"xx100%#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(15.999*cancel(g*mol^-1))/(15.999*cancel(g*mol^-1)+24.305*cancel(g*mol^-1))xx100%=??#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Percentage oxygen composition in magnesium oxide"~=40%#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Percentage oxygen composition in magnesium oxide "=#</mathjax></p> <p><mathjax>#"Mass of oxygen"/"Mass of oxygen + mass of magnesium"xx100%#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(15.999*cancel(g*mol^-1))/(15.999*cancel(g*mol^-1)+24.305*cancel(g*mol^-1))xx100%=??#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name"> What is the percent composition by mass of oxygen in magnesium oxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/percent-composition" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Composition</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="331916" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-05T18:26:37" itemprop="dateCreated"> Nov 5, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Percentage oxygen composition in magnesium oxide"~=40%#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Percentage oxygen composition in magnesium oxide "=#</mathjax></p> <p><mathjax>#"Mass of oxygen"/"Mass of oxygen + mass of magnesium"xx100%#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(15.999*cancel(g*mol^-1))/(15.999*cancel(g*mol^-1)+24.305*cancel(g*mol^-1))xx100%=??#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/331916" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-mole-percent"> What is mole percent? 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What is the percent composition by mass of oxygen in magnesium oxide?

acfb2ab7-6ddd-11ea-923a-ccda262736ce

https://socratic.org/questions/a-gas-cylinder-with-a-volume-of-3-00-dm-3-contains-8-00-moles-of-oxygen-gas-at-a

11 atm

start physical_unit 13 14 pressure atm qc_end physical_unit 13 14 7 8 volume qc_end physical_unit 13 14 10 11 mole qc_end physical_unit 13 14 19 20 temperature qc_end end

[{"type":"physical unit","value":"Pressure [OF] oxygen gas [IN] atm"}]

[{"type":"physical unit","value":"11 atm"}]

[{"type":"physical unit","value":"Volume [OF] oxygen gas [=] \\pu{3.00 dm^3}"},{"type":"physical unit","value":"Mole [OF] oxygen gas [=] \\pu{8.00 moles}"},{"type":"physical unit","value":"Temperature [OF] oxygen gas [=] \\pu{50.0 K}"}]

<h1 class="questionTitle" itemprop="name">A gas cylinder with a volume of 3.00 #dm^3# contains 8.00 moles of oxygen gas at a temperature of 50.0 K. What is the pressure inside the cylinder?</h1>

11 atm

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a>: <mathjax>#P=(nRT)/V#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(8.00*cancel(mol)xx0.0821*cancelL*atm*cancel(K^-1)*cancel(mol^-1)xx50.0*cancel(K))/(3.0*cancel(dm^3)xx1*cancelL*cancel(dm^-3))#</mathjax>.</p> <p>Given the low temperature, and the small volume of the container, this value is liable to differ from the actual pressure measured in the cylinder. It is a first approximation. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P~=11*atm#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a>: <mathjax>#P=(nRT)/V#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(8.00*cancel(mol)xx0.0821*cancelL*atm*cancel(K^-1)*cancel(mol^-1)xx50.0*cancel(K))/(3.0*cancel(dm^3)xx1*cancelL*cancel(dm^-3))#</mathjax>.</p> <p>Given the low temperature, and the small volume of the container, this value is liable to differ from the actual pressure measured in the cylinder. It is a first approximation. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A gas cylinder with a volume of 3.00 #dm^3# contains 8.00 moles of oxygen gas at a temperature of 50.0 K. What is the pressure inside the cylinder?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="311512" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-18T07:38:46" itemprop="dateCreated"> Sep 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P~=11*atm#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a>: <mathjax>#P=(nRT)/V#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(8.00*cancel(mol)xx0.0821*cancelL*atm*cancel(K^-1)*cancel(mol^-1)xx50.0*cancel(K))/(3.0*cancel(dm^3)xx1*cancelL*cancel(dm^-3))#</mathjax>.</p> <p>Given the low temperature, and the small volume of the container, this value is liable to differ from the actual pressure measured in the cylinder. It is a first approximation. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/311512" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? 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A gas cylinder with a volume of 3.00 #dm^3# contains 8.00 moles of oxygen gas at a temperature of 50.0 K. What is the pressure inside the cylinder?

a872095b-6ddd-11ea-a835-ccda262736ce

https://socratic.org/questions/using-graham-s-law-of-effusion-if-co2-takes-32sec-to-effuse-how-long-will-the-hy-1

7.71 sec

start physical_unit 15 15 time s qc_end physical_unit 6 6 8 9 time qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"take time [OF] hydrogen [IN] sec"}]

[{"type":"physical unit","value":"7.71 sec"}]

[{"type":"physical unit","value":"effused time [OF] CO2 [=] \\pu{32 sec}"},{"type":"other","value":"Graham's law of effusion"}]

<h1 class="questionTitle" itemprop="name">Using Graham's law of effusion, if #"CO"_2# takes 32 sec to effuse, how long will hydrogen take?</h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>using Graham's law of effusion, if co2 takes 32sec to effuse how long will the hydrogen take?</p></div> </h2> </div> </div>

7.71 sec

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Graham's Law of Effusion</strong> tells you that the <em>rate of effusion</em> of a gas is <strong>inversely proportional</strong> to the square root of the mass of the particles of gas. </p> <p>This can be written as </p> <blockquote> <p><mathjax>#color(blue)("rate of effusion " prop color(white)(a)1/sqrt("molar mass"))#</mathjax></p> </blockquote> <p>Essentially, the rate of effusion of a gas will depend on how <em>massive</em> its molecules are. The <strong>heavier</strong> the molecules, the <em>slower</em> the rate of effusion. </p> <p>Likewise, the <strong>lighter</strong> the molecules, the <em>faster</em> the rate of effusion. </p> <p>Right from the start, you should look at your two gases, carbon dioxide, <mathjax>#"CO"_2#</mathjax>, and hydrogen gas, <mathjax>#"H"_2#</mathjax>, and be able to predict that it will take <strong>less time</strong> for the hydrogen gas to effuse when compared with the carbon dioxide. </p> <p>This is a valid prediction because the molecules of hydrogen gas are <strong>smaller</strong>, i.e. <strong>lighter</strong>, than the molecules of carbon dioxide. </p> <p>Look for the <em>molar mass</em>* of the two gases</p> <blockquote> <p><mathjax>#"For CO"_2: " 44.01 g mol"^(-1)#</mathjax></p> <p><mathjax>#"For H"_2: " 2.016 g mol"^(-1)#</mathjax></p> </blockquote> <p>The rates of effusion of the two gases can be written as </p> <blockquote> <p><mathjax>#"rate"_(CO_2) prop 1/sqrt("44.01 g mol"^(-1))#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#"rate"_(H_2) prop 1/sqrt("2.016 g mol"^(-1))#</mathjax></p> </blockquote> <p>This means that you can write</p> <blockquote> <p><mathjax>#"rate"_(CO_2)/"rate"_(H_2) = 1/sqrt("44.01 g mol"^(-1)) * sqrt("2.016 g mol"^(-1))/1#</mathjax></p> <p><mathjax>#"rate"_(CO_2)/"rate"_(H_2) = sqrt((2.016 color(red)(cancel(color(black)("g mol"^(-1)))))/(44.01color(red)(cancel(color(black)("g mol"^(-1)))))) = 0.214#</mathjax></p> </blockquote> <p>This means that you have</p> <blockquote> <p><mathjax>#"rate"_(H_2) = "rate"_(CO_2) * 1/0.241#</mathjax></p> <p><mathjax>#"rate"_(H_2) = 4.15 * "rate"_(CO_2)#</mathjax></p> </blockquote> <p>As predicted, hydrogen gas will effuse at a <strong>faster rate</strong> than carbon dioxide. </p> <p>Therefore, if it takes <mathjax>#"32 s"#</mathjax> for carbon dioxide to effuse, and hydrogen effuses <mathjax>#4.15#</mathjax> <strong>times faster</strong>, you can say that you have</p> <blockquote> <p><mathjax>#t_(H_2) = "32 s"/4.15 = color(green)("7.7 s")#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p> <p><strong>SIDE NOTE</strong> <em>The answer will vary a little depending on which values you take for the molar masses of the two gases.</em> </p> <p><em>If other values are given to you, for example</em> <mathjax>#"44 g mol"^(-1)#</mathjax> <em>and</em> <mathjax>#"2.0 g mol"^(-1)#</mathjax>, <em>simply redo the calculations and follow the same steps shown here</em>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"7.7 s"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Graham's Law of Effusion</strong> tells you that the <em>rate of effusion</em> of a gas is <strong>inversely proportional</strong> to the square root of the mass of the particles of gas. </p> <p>This can be written as </p> <blockquote> <p><mathjax>#color(blue)("rate of effusion " prop color(white)(a)1/sqrt("molar mass"))#</mathjax></p> </blockquote> <p>Essentially, the rate of effusion of a gas will depend on how <em>massive</em> its molecules are. The <strong>heavier</strong> the molecules, the <em>slower</em> the rate of effusion. </p> <p>Likewise, the <strong>lighter</strong> the molecules, the <em>faster</em> the rate of effusion. </p> <p>Right from the start, you should look at your two gases, carbon dioxide, <mathjax>#"CO"_2#</mathjax>, and hydrogen gas, <mathjax>#"H"_2#</mathjax>, and be able to predict that it will take <strong>less time</strong> for the hydrogen gas to effuse when compared with the carbon dioxide. </p> <p>This is a valid prediction because the molecules of hydrogen gas are <strong>smaller</strong>, i.e. <strong>lighter</strong>, than the molecules of carbon dioxide. </p> <p>Look for the <em>molar mass</em>* of the two gases</p> <blockquote> <p><mathjax>#"For CO"_2: " 44.01 g mol"^(-1)#</mathjax></p> <p><mathjax>#"For H"_2: " 2.016 g mol"^(-1)#</mathjax></p> </blockquote> <p>The rates of effusion of the two gases can be written as </p> <blockquote> <p><mathjax>#"rate"_(CO_2) prop 1/sqrt("44.01 g mol"^(-1))#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#"rate"_(H_2) prop 1/sqrt("2.016 g mol"^(-1))#</mathjax></p> </blockquote> <p>This means that you can write</p> <blockquote> <p><mathjax>#"rate"_(CO_2)/"rate"_(H_2) = 1/sqrt("44.01 g mol"^(-1)) * sqrt("2.016 g mol"^(-1))/1#</mathjax></p> <p><mathjax>#"rate"_(CO_2)/"rate"_(H_2) = sqrt((2.016 color(red)(cancel(color(black)("g mol"^(-1)))))/(44.01color(red)(cancel(color(black)("g mol"^(-1)))))) = 0.214#</mathjax></p> </blockquote> <p>This means that you have</p> <blockquote> <p><mathjax>#"rate"_(H_2) = "rate"_(CO_2) * 1/0.241#</mathjax></p> <p><mathjax>#"rate"_(H_2) = 4.15 * "rate"_(CO_2)#</mathjax></p> </blockquote> <p>As predicted, hydrogen gas will effuse at a <strong>faster rate</strong> than carbon dioxide. </p> <p>Therefore, if it takes <mathjax>#"32 s"#</mathjax> for carbon dioxide to effuse, and hydrogen effuses <mathjax>#4.15#</mathjax> <strong>times faster</strong>, you can say that you have</p> <blockquote> <p><mathjax>#t_(H_2) = "32 s"/4.15 = color(green)("7.7 s")#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p> <p><strong>SIDE NOTE</strong> <em>The answer will vary a little depending on which values you take for the molar masses of the two gases.</em> </p> <p><em>If other values are given to you, for example</em> <mathjax>#"44 g mol"^(-1)#</mathjax> <em>and</em> <mathjax>#"2.0 g mol"^(-1)#</mathjax>, <em>simply redo the calculations and follow the same steps shown here</em>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Using Graham's law of effusion, if #"CO"_2# takes 32 sec to effuse, how long will hydrogen take?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>using Graham's law of effusion, if co2 takes 32sec to effuse how long will the hydrogen take?</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/kinetic-theory-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Kinetic Theory of Gases</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="231157" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-26T00:59:07" itemprop="dateCreated"> Feb 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"7.7 s"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Graham's Law of Effusion</strong> tells you that the <em>rate of effusion</em> of a gas is <strong>inversely proportional</strong> to the square root of the mass of the particles of gas. </p> <p>This can be written as </p> <blockquote> <p><mathjax>#color(blue)("rate of effusion " prop color(white)(a)1/sqrt("molar mass"))#</mathjax></p> </blockquote> <p>Essentially, the rate of effusion of a gas will depend on how <em>massive</em> its molecules are. The <strong>heavier</strong> the molecules, the <em>slower</em> the rate of effusion. </p> <p>Likewise, the <strong>lighter</strong> the molecules, the <em>faster</em> the rate of effusion. </p> <p>Right from the start, you should look at your two gases, carbon dioxide, <mathjax>#"CO"_2#</mathjax>, and hydrogen gas, <mathjax>#"H"_2#</mathjax>, and be able to predict that it will take <strong>less time</strong> for the hydrogen gas to effuse when compared with the carbon dioxide. </p> <p>This is a valid prediction because the molecules of hydrogen gas are <strong>smaller</strong>, i.e. <strong>lighter</strong>, than the molecules of carbon dioxide. </p> <p>Look for the <em>molar mass</em>* of the two gases</p> <blockquote> <p><mathjax>#"For CO"_2: " 44.01 g mol"^(-1)#</mathjax></p> <p><mathjax>#"For H"_2: " 2.016 g mol"^(-1)#</mathjax></p> </blockquote> <p>The rates of effusion of the two gases can be written as </p> <blockquote> <p><mathjax>#"rate"_(CO_2) prop 1/sqrt("44.01 g mol"^(-1))#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#"rate"_(H_2) prop 1/sqrt("2.016 g mol"^(-1))#</mathjax></p> </blockquote> <p>This means that you can write</p> <blockquote> <p><mathjax>#"rate"_(CO_2)/"rate"_(H_2) = 1/sqrt("44.01 g mol"^(-1)) * sqrt("2.016 g mol"^(-1))/1#</mathjax></p> <p><mathjax>#"rate"_(CO_2)/"rate"_(H_2) = sqrt((2.016 color(red)(cancel(color(black)("g mol"^(-1)))))/(44.01color(red)(cancel(color(black)("g mol"^(-1)))))) = 0.214#</mathjax></p> </blockquote> <p>This means that you have</p> <blockquote> <p><mathjax>#"rate"_(H_2) = "rate"_(CO_2) * 1/0.241#</mathjax></p> <p><mathjax>#"rate"_(H_2) = 4.15 * "rate"_(CO_2)#</mathjax></p> </blockquote> <p>As predicted, hydrogen gas will effuse at a <strong>faster rate</strong> than carbon dioxide. </p> <p>Therefore, if it takes <mathjax>#"32 s"#</mathjax> for carbon dioxide to effuse, and hydrogen effuses <mathjax>#4.15#</mathjax> <strong>times faster</strong>, you can say that you have</p> <blockquote> <p><mathjax>#t_(H_2) = "32 s"/4.15 = color(green)("7.7 s")#</mathjax></p> </blockquote> <p>The answer is rounded to two <strong><a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>. </p> <p><strong>SIDE NOTE</strong> <em>The answer will vary a little depending on which values you take for the molar masses of the two gases.</em> </p> <p><em>If other values are given to you, for example</em> <mathjax>#"44 g mol"^(-1)#</mathjax> <em>and</em> <mathjax>#"2.0 g mol"^(-1)#</mathjax>, <em>simply redo the calculations and follow the same steps shown here</em>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/231157" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-kinetic-molecular-theory-explain-gas-laws"> How does kinetic molecular theory explain gas laws? 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Using Graham's law of effusion, if #"CO"_2# takes 32 sec to effuse, how long will hydrogen take?

using Graham's law of effusion, if co2 takes 32sec to effuse how long will the hydrogen take?

aada3818-6ddd-11ea-8192-ccda262736ce

https://socratic.org/questions/what-is-the-molarity-of-a-solution-made-of-2-5-moles-of-kno-3-in-5-l-of-water

0.50 M

start physical_unit 6 6 molarity mol/l qc_end physical_unit 12 12 9 10 mole qc_end physical_unit 17 17 14 15 volume qc_end end

[{"type":"physical unit","value":"Molarity [OF] the solution [IN] M"}]

[{"type":"physical unit","value":"0.50 M"}]

[{"type":"physical unit","value":"Mole [OF] KNO3 [=] \\pu{2.5 moles}"},{"type":"physical unit","value":"Volume [OF] water [=] \\pu{5 L}"}]

<h1 class="questionTitle" itemprop="name"> What is the molarity of a solution made of 2.5 moles of #KNO_3# in 5 L of water?</h1>

0.50 M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#("Moles of solute")/("Volume of solution (L)")#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(2.50*mol)/(5*L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.50#</mathjax> <mathjax>#mol*L^-1#</mathjax>.</p> <p>The volume of the solution formed when such a quantity of potassium nitrate is dissolved in <mathjax>#5#</mathjax> <mathjax>#L#</mathjax> of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> would remain at <mathjax>#5#</mathjax> <mathjax>#L#</mathjax>, or so close that the difference is negligible.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Molarity"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.50#</mathjax> <mathjax>#mol*L^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#("Moles of solute")/("Volume of solution (L)")#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(2.50*mol)/(5*L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.50#</mathjax> <mathjax>#mol*L^-1#</mathjax>.</p> <p>The volume of the solution formed when such a quantity of potassium nitrate is dissolved in <mathjax>#5#</mathjax> <mathjax>#L#</mathjax> of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> would remain at <mathjax>#5#</mathjax> <mathjax>#L#</mathjax>, or so close that the difference is negligible.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name"> What is the molarity of a solution made of 2.5 moles of #KNO_3# in 5 L of water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="241095" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-17T20:33:23" itemprop="dateCreated"> Mar 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Molarity"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.50#</mathjax> <mathjax>#mol*L^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#("Moles of solute")/("Volume of solution (L)")#</mathjax></p> <p><mathjax>#=#</mathjax> <mathjax>#(2.50*mol)/(5*L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.50#</mathjax> <mathjax>#mol*L^-1#</mathjax>.</p> <p>The volume of the solution formed when such a quantity of potassium nitrate is dissolved in <mathjax>#5#</mathjax> <mathjax>#L#</mathjax> of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> would remain at <mathjax>#5#</mathjax> <mathjax>#L#</mathjax>, or so close that the difference is negligible.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/241095" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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What is the molarity of a solution made of 2.5 moles of #KNO_3# in 5 L of water?

ac4565c0-6ddd-11ea-87ae-ccda262736ce

https://socratic.org/questions/how-many-moles-of-argon-are-in-452-g-of-argon

13.31 moles

start physical_unit 4 4 mole mol qc_end physical_unit 4 4 7 8 mass qc_end end

[{"type":"physical unit","value":"Mole [OF] argon [IN] moles"}]

[{"type":"physical unit","value":"13.31 moles"}]

[{"type":"physical unit","value":"Mass [OF] argon [=] \\pu{452 g}"}]

<h1 class="questionTitle" itemprop="name">How many moles of argon are in 452 g of argon?</h1>

13.31 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to convert a substance from grams to moles, you must use that substance's molar mass. In this case, Argon's molar mass can be found using the periodic table. You can round however you like, but I am using 33.45 g/mol. </p> <p>So start with what you are given: 452 grams of Argon. As mentioned before, you use the molar mass to convert from grams to moles. So take 452 grams of Argon and multiply by the molar mass of Argon. Your units will cancel out, leaving you with moles of Argon. <img alt="enter image source here" src="https://useruploads.socratic.org/I2C0YixSYeXdN4hokyMn_12386501_895667110530411_1846772047_n.jpg"/> </p> <p>I hope that was helpful. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The number of moles in 452 grams of Argon is 13.31 moles.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to convert a substance from grams to moles, you must use that substance's molar mass. In this case, Argon's molar mass can be found using the periodic table. You can round however you like, but I am using 33.45 g/mol. </p> <p>So start with what you are given: 452 grams of Argon. As mentioned before, you use the molar mass to convert from grams to moles. So take 452 grams of Argon and multiply by the molar mass of Argon. Your units will cancel out, leaving you with moles of Argon. <img alt="enter image source here" src="https://useruploads.socratic.org/I2C0YixSYeXdN4hokyMn_12386501_895667110530411_1846772047_n.jpg"/> </p> <p>I hope that was helpful. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles of argon are in 452 g of argon?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="200574" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/tristanrforbes"><img alt="" class="" src="https://lh3.googleusercontent.com/-XdUIqdMkCWA/AAAAAAAAAAI/AAAAAAAAAAA/4252rscbv5M/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/tristanrforbes"> tristanrforbes </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-17T04:01:47" itemprop="dateCreated"> Dec 17, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The number of moles in 452 grams of Argon is 13.31 moles.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In order to convert a substance from grams to moles, you must use that substance's molar mass. In this case, Argon's molar mass can be found using the periodic table. You can round however you like, but I am using 33.45 g/mol. </p> <p>So start with what you are given: 452 grams of Argon. As mentioned before, you use the molar mass to convert from grams to moles. So take 452 grams of Argon and multiply by the molar mass of Argon. Your units will cancel out, leaving you with moles of Argon. <img alt="enter image source here" src="https://useruploads.socratic.org/I2C0YixSYeXdN4hokyMn_12386501_895667110530411_1846772047_n.jpg"/> </p> <p>I hope that was helpful. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/200574" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 46108 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many moles of argon are in 452 g of argon?

a8e2c0b4-6ddd-11ea-bd5e-ccda262736ce

https://socratic.org/questions/how-much-heat-must-be-removed-to-freeze-a-tray-of-ice-cubes-at-0c-the-mass-of-th

18 kcal

start physical_unit 11 12 heat_energy kcal qc_end physical_unit 11 12 14 15 temperature qc_end physical_unit 20 20 22 23 mass qc_end end

[{"type":"physical unit","value":"Removed heat [OF] ice cubes [IN] kcal"}]

[{"type":"physical unit","value":"18 kcal"}]

[{"type":"physical unit","value":"Temperature [OF] ice cubes [=] \\pu{0 ℃}"},{"type":"physical unit","value":"Mass [OF] water [=] \\pu{225 g}"},{"type":"physical unit","value":"Tray number [OF] ice cubes [=] \\pu{1}"}]

<h1 class="questionTitle" itemprop="name">How much heat must be removed to freeze a tray of ice cubes at 0C? The mass of the water is 225 g? </h1>

18 kcal

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong>latent heat</strong> of water freezing is <mathjax>#80"cal/g"#</mathjax> -- that amount of heat has to be removed to freeze water at a constant temperature equal to its melting/freezing point <mathjax>#0°"C"#</mathjax>.</p> <p>For <mathjax>#225"g"#</mathjax> of water, the total latent heat is</p> <p><mathjax>#(80"cal/g")×(225"g")=18,000"cal"=18"kcal"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#18"kcal"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong>latent heat</strong> of water freezing is <mathjax>#80"cal/g"#</mathjax> -- that amount of heat has to be removed to freeze water at a constant temperature equal to its melting/freezing point <mathjax>#0°"C"#</mathjax>.</p> <p>For <mathjax>#225"g"#</mathjax> of water, the total latent heat is</p> <p><mathjax>#(80"cal/g")×(225"g")=18,000"cal"=18"kcal"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How much heat must be removed to freeze a tray of ice cubes at 0C? The mass of the water is 225 g? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/thermochemistry-of-phase-changes" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry of Phase Changes</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="525602" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/olthe3rd"><img alt="" class="" src="https://profilepictures.socratic.org/ooIp4P3ES4imZU7Cwexy_Squirrel.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/olthe3rd"> Oscar L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-12-21T23:37:33" itemprop="dateCreated"> Dec 21, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#18"kcal"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong>latent heat</strong> of water freezing is <mathjax>#80"cal/g"#</mathjax> -- that amount of heat has to be removed to freeze water at a constant temperature equal to its melting/freezing point <mathjax>#0°"C"#</mathjax>.</p> <p>For <mathjax>#225"g"#</mathjax> of water, the total latent heat is</p> <p><mathjax>#(80"cal/g")×(225"g")=18,000"cal"=18"kcal"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/525602" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-much-energy-is-required-to-heat-100-g-of-ice-at-0-00-degrees-celsius-to-wate"> How much energy is required to convert 100.g of ice at 0.00 °C to water vapor at 100.00 °C? 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How much heat must be removed to freeze a tray of ice cubes at 0C? The mass of the water is 225 g?

aa4eb08a-6ddd-11ea-83ba-ccda262736ce

https://socratic.org/questions/diphosphorus-pentaoxide-reacts-with-water-to-produce-phosphoric-acid-h-3po-4-how

P4O10(s) + 6 H2O(l) -> 4 H3PO4(aq)

start chemical_equation qc_end substance 0 1 qc_end substance 4 4 qc_end chemical_equation 10 10 qc_end end

[{"type":"other","value":"Chemical Equation [OF] this reaction"}]

[{"type":"chemical equation","value":"P4O10(s) + 6 H2O(l) -> 4 H3PO4(aq)"}]

[{"type":"substance name","value":"Diphosphorus pentoxide"},{"type":"substance name","value":"Water"},{"type":"chemical equation","value":"H3PO4"}]

<h1 class="questionTitle" itemprop="name">Diphosphorus pentoxide reacts with water to produce phosphoric acid (#H_3PO_4#). How do you write the balanced equation for this reaction?</h1>

P4O10(s) + 6 H2O(l) -> 4 H3PO4(aq)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The interesting thing about <em>diphosphorus pentoxide</em>, <mathjax>#"P"_2"O"_5#</mathjax>, is that it usually exists as a <em>dimer</em>. </p> <p>This implies that <mathjax>#"P"_2"O"_5#</mathjax> is actually the compound's <a href="http://socratic.org/chemistry/the-mole-concept/empirical-and-molecular-formulas">empirical formula</a> and that you should use <mathjax>#"P"_4"O"_10#</mathjax> as its <em>molecular formula</em>. </p> <p>Now, diphosphorus pentoxide reacts <strong>violently</strong> with water to form <em>phosphoric acid</em>, <mathjax>#"H"_3"PO"_4#</mathjax>. The reaction is <em>highly exothermic</em> and leads to the formation of toxic fumes. </p> <p>The <em>unbalanced</em> chemical equation for this reaction looks like this </p> <blockquote> <p><mathjax>#"P"_4"O"_text(10(s]) + "H"_2"O"_text((l]) -&gt; "H"_3"PO"_text(4(aq])#</mathjax></p> </blockquote> <p>To balance this equation, start by multiplying the phosphoric acid by <mathjax>#4#</mathjax> to get equal numbers of atoms of phosphorus on both sides of the equation</p> <blockquote> <p><mathjax>#"P"_4"O"_text(10(s]) + "H"_2"O"_text((l]) -&gt; 4"H"_3"PO"_text(4(aq])#</mathjax></p> </blockquote> <p>Notice that you have <mathjax>#2#</mathjax> atoms of hydrogen on the reactants' side and <mathjax>#12#</mathjax> on the products' side. Multiply the water molecule by <mathjax>#6#</mathjax> to balance the hydrogen atoms out. </p> <p>Incidentally, this will also balance out the atoms of oxygen, since you'd now have <mathjax>#16#</mathjax> on the reactants' side and <mathjax>#16#</mathjax> on the products' side. </p> <p>The <em>balanced</em> chemical equation for this reaction will thus be </p> <blockquote> <p><mathjax>#"P"_4"O"_text(10(s]) + 6"H"_2"O"_text((l]) -&gt; 4"H"_3"PO"_text(4(aq])#</mathjax></p> </blockquote> <p>It's worth mentioning that diphosphorus pentoxide is a very powerful <strong>dehydrating agent</strong>. </p> <p> <iframe src="https://www.youtube.com/embed/ccPcfYQnmVw?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p> <p><strong>SIDE NOTE</strong> <em>You'll sometimes see this reaction written using the empirical formula of diphosphorus pentoxide</em>, <mathjax>#"P"_2"O"_5#</mathjax>. <em>In that case, the balanced chemical equation will be</em></p> <blockquote> <p><mathjax>#"P"_2"O"_text(5(s]) + 3"H"_2"O"_text((l]) -&gt; 2"H"_3"PO"_text(4(aq])#</mathjax></p> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"P"_4"O"_text(10(s]) + 6"H"_2"O"_text((l]) -&gt; 4"H"_3"PO"_text(4(aq])#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The interesting thing about <em>diphosphorus pentoxide</em>, <mathjax>#"P"_2"O"_5#</mathjax>, is that it usually exists as a <em>dimer</em>. </p> <p>This implies that <mathjax>#"P"_2"O"_5#</mathjax> is actually the compound's <a href="http://socratic.org/chemistry/the-mole-concept/empirical-and-molecular-formulas">empirical formula</a> and that you should use <mathjax>#"P"_4"O"_10#</mathjax> as its <em>molecular formula</em>. </p> <p>Now, diphosphorus pentoxide reacts <strong>violently</strong> with water to form <em>phosphoric acid</em>, <mathjax>#"H"_3"PO"_4#</mathjax>. The reaction is <em>highly exothermic</em> and leads to the formation of toxic fumes. </p> <p>The <em>unbalanced</em> chemical equation for this reaction looks like this </p> <blockquote> <p><mathjax>#"P"_4"O"_text(10(s]) + "H"_2"O"_text((l]) -&gt; "H"_3"PO"_text(4(aq])#</mathjax></p> </blockquote> <p>To balance this equation, start by multiplying the phosphoric acid by <mathjax>#4#</mathjax> to get equal numbers of atoms of phosphorus on both sides of the equation</p> <blockquote> <p><mathjax>#"P"_4"O"_text(10(s]) + "H"_2"O"_text((l]) -&gt; 4"H"_3"PO"_text(4(aq])#</mathjax></p> </blockquote> <p>Notice that you have <mathjax>#2#</mathjax> atoms of hydrogen on the reactants' side and <mathjax>#12#</mathjax> on the products' side. Multiply the water molecule by <mathjax>#6#</mathjax> to balance the hydrogen atoms out. </p> <p>Incidentally, this will also balance out the atoms of oxygen, since you'd now have <mathjax>#16#</mathjax> on the reactants' side and <mathjax>#16#</mathjax> on the products' side. </p> <p>The <em>balanced</em> chemical equation for this reaction will thus be </p> <blockquote> <p><mathjax>#"P"_4"O"_text(10(s]) + 6"H"_2"O"_text((l]) -&gt; 4"H"_3"PO"_text(4(aq])#</mathjax></p> </blockquote> <p>It's worth mentioning that diphosphorus pentoxide is a very powerful <strong>dehydrating agent</strong>. </p> <p> <iframe src="https://www.youtube.com/embed/ccPcfYQnmVw?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p> <p><strong>SIDE NOTE</strong> <em>You'll sometimes see this reaction written using the empirical formula of diphosphorus pentoxide</em>, <mathjax>#"P"_2"O"_5#</mathjax>. <em>In that case, the balanced chemical equation will be</em></p> <blockquote> <p><mathjax>#"P"_2"O"_text(5(s]) + 3"H"_2"O"_text((l]) -&gt; 2"H"_3"PO"_text(4(aq])#</mathjax></p> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Diphosphorus pentoxide reacts with water to produce phosphoric acid (#H_3PO_4#). How do you write the balanced equation for this reaction?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="212567" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-15T00:43:04" itemprop="dateCreated"> Jan 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"P"_4"O"_text(10(s]) + 6"H"_2"O"_text((l]) -&gt; 4"H"_3"PO"_text(4(aq])#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The interesting thing about <em>diphosphorus pentoxide</em>, <mathjax>#"P"_2"O"_5#</mathjax>, is that it usually exists as a <em>dimer</em>. </p> <p>This implies that <mathjax>#"P"_2"O"_5#</mathjax> is actually the compound's <a href="http://socratic.org/chemistry/the-mole-concept/empirical-and-molecular-formulas">empirical formula</a> and that you should use <mathjax>#"P"_4"O"_10#</mathjax> as its <em>molecular formula</em>. </p> <p>Now, diphosphorus pentoxide reacts <strong>violently</strong> with water to form <em>phosphoric acid</em>, <mathjax>#"H"_3"PO"_4#</mathjax>. The reaction is <em>highly exothermic</em> and leads to the formation of toxic fumes. </p> <p>The <em>unbalanced</em> chemical equation for this reaction looks like this </p> <blockquote> <p><mathjax>#"P"_4"O"_text(10(s]) + "H"_2"O"_text((l]) -&gt; "H"_3"PO"_text(4(aq])#</mathjax></p> </blockquote> <p>To balance this equation, start by multiplying the phosphoric acid by <mathjax>#4#</mathjax> to get equal numbers of atoms of phosphorus on both sides of the equation</p> <blockquote> <p><mathjax>#"P"_4"O"_text(10(s]) + "H"_2"O"_text((l]) -&gt; 4"H"_3"PO"_text(4(aq])#</mathjax></p> </blockquote> <p>Notice that you have <mathjax>#2#</mathjax> atoms of hydrogen on the reactants' side and <mathjax>#12#</mathjax> on the products' side. Multiply the water molecule by <mathjax>#6#</mathjax> to balance the hydrogen atoms out. </p> <p>Incidentally, this will also balance out the atoms of oxygen, since you'd now have <mathjax>#16#</mathjax> on the reactants' side and <mathjax>#16#</mathjax> on the products' side. </p> <p>The <em>balanced</em> chemical equation for this reaction will thus be </p> <blockquote> <p><mathjax>#"P"_4"O"_text(10(s]) + 6"H"_2"O"_text((l]) -&gt; 4"H"_3"PO"_text(4(aq])#</mathjax></p> </blockquote> <p>It's worth mentioning that diphosphorus pentoxide is a very powerful <strong>dehydrating agent</strong>. </p> <p> <iframe src="https://www.youtube.com/embed/ccPcfYQnmVw?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p> <p><strong>SIDE NOTE</strong> <em>You'll sometimes see this reaction written using the empirical formula of diphosphorus pentoxide</em>, <mathjax>#"P"_2"O"_5#</mathjax>. <em>In that case, the balanced chemical equation will be</em></p> <blockquote> <p><mathjax>#"P"_2"O"_text(5(s]) + 3"H"_2"O"_text((l]) -&gt; 2"H"_3"PO"_text(4(aq])#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/212567" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 69871 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

Diphosphorus pentoxide reacts with water to produce phosphoric acid (#H_3PO_4#). How do you write the balanced equation for this reaction?

a9cd71f8-6ddd-11ea-b23c-ccda262736ce

https://socratic.org/questions/what-is-the-ph-of-1-2-10-3-hbr-solution

2.92

start physical_unit 9 10 ph none qc_end physical_unit 9 10 5 8 molarity qc_end end

[{"type":"physical unit","value":"pH [OF] HBr solution"}]

[{"type":"physical unit","value":"2.92"}]

[{"type":"physical unit","value":"Molarity [OF] HBr solution [=] \\pu{1.2 × 10^(-3) M}"}]

<h1 class="questionTitle" itemprop="name">What is the pH of #1.2 * 10^-3# HBr solution?</h1>

2.92

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Even without doing any calculations, you can say that the <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of this solution will be <em>a little lower</em> than <mathjax>#3#</mathjax>. </p> <p>Why is that the case?</p> <p><em>Hydrobromic acid</em>, <mathjax>#"HBr"#</mathjax>, is a <strong>strong acid</strong>, which means that it ionizes completely in aqueous solution to form <em>hydronium ions</em>, <mathjax>#"H"_3"O"^(+)#</mathjax>, and <em>bromide anions</em>, <mathjax>#"Br"^(-)#</mathjax>. </p> <blockquote> <p><mathjax>#"HBr"_text((aq]) + "H"_2"O"_text((l]) -&gt; "H"_3"O"_text((aq])^(+) + "Br"_text((aq])^(-)#</mathjax></p> </blockquote> <p>Now, when an acid ionizes completely, you can expect <strong>all the molecules</strong> to donate their proton to the water. This of course means that the initial concentration of hydrobromic acid will now be equivalent to the concentration of hydronium ions and bromide anions. </p> <p>Since <em>every</em> molecule of <mathjax>#"HBr"#</mathjax> produces <em>one</em> hydronium ion in aqueous solution, you can say that</p> <blockquote> <p><mathjax>#["H"_3"O"^(+)] = ["HBr"] = 1.2 * 10^(-3)"M"#</mathjax></p> </blockquote> <p>As you know, the pH of the solution is a measure of the concentration of hydronium ions</p> <blockquote> <p><mathjax>#"pH" = -log( ["H"_3"O"^(+)])#</mathjax></p> </blockquote> <p>In this case, the pH of the solution will be </p> <blockquote> <p><mathjax>#"pH" = - log(1.2 * 10^(-3)) = color(green)(2.92)#</mathjax></p> </blockquote> <p>As predicted, the pH is a little lower than <mathjax>#3#</mathjax>. If the initial concentration of hydrobromic acid would have been <mathjax>#1.0 * 10^(-3)"M"#</mathjax>, then the pH would have been equal to <mathjax>#3#</mathjax>. </p> <p>Since </p> <blockquote> <p><mathjax>#1.2 * 10^(-3)"M" &gt; 1.0 * 10^(-3)"M"#</mathjax></p> </blockquote> <p>the pH will be <strong>lower</strong> than <mathjax>#3#</mathjax>, i.e. the solution is <em>more acidic</em>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.92#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Even without doing any calculations, you can say that the <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of this solution will be <em>a little lower</em> than <mathjax>#3#</mathjax>. </p> <p>Why is that the case?</p> <p><em>Hydrobromic acid</em>, <mathjax>#"HBr"#</mathjax>, is a <strong>strong acid</strong>, which means that it ionizes completely in aqueous solution to form <em>hydronium ions</em>, <mathjax>#"H"_3"O"^(+)#</mathjax>, and <em>bromide anions</em>, <mathjax>#"Br"^(-)#</mathjax>. </p> <blockquote> <p><mathjax>#"HBr"_text((aq]) + "H"_2"O"_text((l]) -&gt; "H"_3"O"_text((aq])^(+) + "Br"_text((aq])^(-)#</mathjax></p> </blockquote> <p>Now, when an acid ionizes completely, you can expect <strong>all the molecules</strong> to donate their proton to the water. This of course means that the initial concentration of hydrobromic acid will now be equivalent to the concentration of hydronium ions and bromide anions. </p> <p>Since <em>every</em> molecule of <mathjax>#"HBr"#</mathjax> produces <em>one</em> hydronium ion in aqueous solution, you can say that</p> <blockquote> <p><mathjax>#["H"_3"O"^(+)] = ["HBr"] = 1.2 * 10^(-3)"M"#</mathjax></p> </blockquote> <p>As you know, the pH of the solution is a measure of the concentration of hydronium ions</p> <blockquote> <p><mathjax>#"pH" = -log( ["H"_3"O"^(+)])#</mathjax></p> </blockquote> <p>In this case, the pH of the solution will be </p> <blockquote> <p><mathjax>#"pH" = - log(1.2 * 10^(-3)) = color(green)(2.92)#</mathjax></p> </blockquote> <p>As predicted, the pH is a little lower than <mathjax>#3#</mathjax>. If the initial concentration of hydrobromic acid would have been <mathjax>#1.0 * 10^(-3)"M"#</mathjax>, then the pH would have been equal to <mathjax>#3#</mathjax>. </p> <p>Since </p> <blockquote> <p><mathjax>#1.2 * 10^(-3)"M" &gt; 1.0 * 10^(-3)"M"#</mathjax></p> </blockquote> <p>the pH will be <strong>lower</strong> than <mathjax>#3#</mathjax>, i.e. the solution is <em>more acidic</em>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the pH of #1.2 * 10^-3# HBr solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="200971" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-18T12:31:59" itemprop="dateCreated"> Dec 18, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.92#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Even without doing any calculations, you can say that the <a href="http://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of this solution will be <em>a little lower</em> than <mathjax>#3#</mathjax>. </p> <p>Why is that the case?</p> <p><em>Hydrobromic acid</em>, <mathjax>#"HBr"#</mathjax>, is a <strong>strong acid</strong>, which means that it ionizes completely in aqueous solution to form <em>hydronium ions</em>, <mathjax>#"H"_3"O"^(+)#</mathjax>, and <em>bromide anions</em>, <mathjax>#"Br"^(-)#</mathjax>. </p> <blockquote> <p><mathjax>#"HBr"_text((aq]) + "H"_2"O"_text((l]) -&gt; "H"_3"O"_text((aq])^(+) + "Br"_text((aq])^(-)#</mathjax></p> </blockquote> <p>Now, when an acid ionizes completely, you can expect <strong>all the molecules</strong> to donate their proton to the water. This of course means that the initial concentration of hydrobromic acid will now be equivalent to the concentration of hydronium ions and bromide anions. </p> <p>Since <em>every</em> molecule of <mathjax>#"HBr"#</mathjax> produces <em>one</em> hydronium ion in aqueous solution, you can say that</p> <blockquote> <p><mathjax>#["H"_3"O"^(+)] = ["HBr"] = 1.2 * 10^(-3)"M"#</mathjax></p> </blockquote> <p>As you know, the pH of the solution is a measure of the concentration of hydronium ions</p> <blockquote> <p><mathjax>#"pH" = -log( ["H"_3"O"^(+)])#</mathjax></p> </blockquote> <p>In this case, the pH of the solution will be </p> <blockquote> <p><mathjax>#"pH" = - log(1.2 * 10^(-3)) = color(green)(2.92)#</mathjax></p> </blockquote> <p>As predicted, the pH is a little lower than <mathjax>#3#</mathjax>. If the initial concentration of hydrobromic acid would have been <mathjax>#1.0 * 10^(-3)"M"#</mathjax>, then the pH would have been equal to <mathjax>#3#</mathjax>. </p> <p>Since </p> <blockquote> <p><mathjax>#1.2 * 10^(-3)"M" &gt; 1.0 * 10^(-3)"M"#</mathjax></p> </blockquote> <p>the pH will be <strong>lower</strong> than <mathjax>#3#</mathjax>, i.e. the solution is <em>more acidic</em>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/200971" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 38282 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the pH of #1.2 * 10^-3# HBr solution?

ab4d69c2-6ddd-11ea-bc6a-ccda262736ce

https://socratic.org/questions/what-is-the-mass-of-water-produced-when-9-33-g-of-butane-reacts-with-excess-oxyg

14.50 g

start physical_unit 5 5 mass g qc_end physical_unit 11 11 8 9 mass qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Mass [OF] water [IN] g"}]

[{"type":"physical unit","value":"14.50 g"}]

[{"type":"physical unit","value":"Mass [OF] butane [=] \\pu{9.33 g}"},{"type":"other","value":"Excess oxygen."}]

<h1 class="questionTitle" itemprop="name">What is the mass of water produced when 9.33 g of butane reacts with excess oxygen?</h1>

14.50 g

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#C_4H_10(g) + 13/2O_2(g) rarr 4CO_2(g) + 5H_2O(l)#</mathjax></p> <p><mathjax>#"Moles of butane"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(9.33*g)/(58.12*g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.161*mol#</mathjax>.</p> <p>We assume complete combustion, and know that each mole of butane gives off 5 mol of water upon combustion.</p> <p>Given that we know the molar quantity of butane, we simply perform the operation, <mathjax>#5xx0.161*molxx18.01*g*mol^-1=??#</mathjax></p> <p>What is the mass of carbon dioxide gas evolved in the reaction?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#5xx0.161*molxx18.01*g*mol^-1=??#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#C_4H_10(g) + 13/2O_2(g) rarr 4CO_2(g) + 5H_2O(l)#</mathjax></p> <p><mathjax>#"Moles of butane"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(9.33*g)/(58.12*g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.161*mol#</mathjax>.</p> <p>We assume complete combustion, and know that each mole of butane gives off 5 mol of water upon combustion.</p> <p>Given that we know the molar quantity of butane, we simply perform the operation, <mathjax>#5xx0.161*molxx18.01*g*mol^-1=??#</mathjax></p> <p>What is the mass of carbon dioxide gas evolved in the reaction?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the mass of water produced when 9.33 g of butane reacts with excess oxygen?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="242804" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-21T06:56:11" itemprop="dateCreated"> Mar 21, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#5xx0.161*molxx18.01*g*mol^-1=??#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#C_4H_10(g) + 13/2O_2(g) rarr 4CO_2(g) + 5H_2O(l)#</mathjax></p> <p><mathjax>#"Moles of butane"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(9.33*g)/(58.12*g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.161*mol#</mathjax>.</p> <p>We assume complete combustion, and know that each mole of butane gives off 5 mol of water upon combustion.</p> <p>Given that we know the molar quantity of butane, we simply perform the operation, <mathjax>#5xx0.161*molxx18.01*g*mol^-1=??#</mathjax></p> <p>What is the mass of carbon dioxide gas evolved in the reaction?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/242804" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -&gt; 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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What is the mass of water produced when 9.33 g of butane reacts with excess oxygen?

aa9f9388-6ddd-11ea-aa80-ccda262736ce

https://socratic.org/questions/how-many-carbon-dioxide-molecules-are-needed-to-make-a-single-glucose-molecule

6

start physical_unit 2 4 number none qc_end end

[{"type":"physical unit","value":"Number [OF] carbon dioxide molecules"}]

[{"type":"physical unit","value":"6"}]

[{"type":"physical unit","value":"Number [OF] glucose molecule [=] \\pu{1}"}]

<h1 class="questionTitle" itemprop="name">How many carbon dioxide molecules are needed to make a single glucose molecule? </h1>

6

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Glucose is <mathjax>#"C"_6"H"_12"O"_6#</mathjax>.</p> <p>Remember the equation for photosynthesis:</p> <p><mathjax>#"6CO"_2 + "6H"_2"O" → "C"_6"H"_12"O"_6 + "6O"_2#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You need 6 molecules of <mathjax>#"CO"_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Glucose is <mathjax>#"C"_6"H"_12"O"_6#</mathjax>.</p> <p>Remember the equation for photosynthesis:</p> <p><mathjax>#"6CO"_2 + "6H"_2"O" → "C"_6"H"_12"O"_6 + "6O"_2#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many carbon dioxide molecules are needed to make a single glucose molecule? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="236785" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> <a class="secondContributorPic" href="/users/flavio-p"><img alt="" class="" src="https://graph.facebook.com/100003687744283/picture?height=50&amp;width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a>·<a class="topContributorLink" href="/users/flavio-p"> Flavio P. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-08T13:09:34" itemprop="dateCreated"> Mar 8, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You need 6 molecules of <mathjax>#"CO"_2#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>Glucose is <mathjax>#"C"_6"H"_12"O"_6#</mathjax>.</p> <p>Remember the equation for photosynthesis:</p> <p><mathjax>#"6CO"_2 + "6H"_2"O" → "C"_6"H"_12"O"_6 + "6O"_2#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/236785" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11174 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many carbon dioxide molecules are needed to make a single glucose molecule?

ace02b36-6ddd-11ea-8e90-ccda262736ce

https://socratic.org/questions/what-is-the-mole-ratio-of-fe-3o-4-to-fe-in-the-equation-3fe-4h-2o-fe-3o-4-4h-2

1:3

start physical_unit 6 8 mole_fraction none qc_end chemical_equation 12 21 qc_end end

[{"type":"physical unit","value":"Mole ratio [OF] Fe3O4 to Fe"}]

[{"type":"physical unit","value":"1:3"}]

[{"type":"chemical equation","value":"3 Fe + 4 H2O -> Fe3O4 + 4 H2"}]

<h1 class="questionTitle" itemprop="name">What is the mole ratio of #Fe_3O_4# to #Fe# in the equation #3Fe + 4H_2O -&gt; Fe_3O_4 + 4H_2#?</h1>

1:3

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><ol> <li>To determine <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio of <a href="http://socratic.org/chemistry/chemical-reactions/chemical-equations">chemical equations</a>, generally is to make sure that the equation is balanced following the Law of the Conservation of Mass;</li> <li>Since the problem presents a balanced equation, all you have to do is to identify which <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> involved to get the right mole ratio;</li> <li>The number in front of each compound/element are called coefficients which also serves as the number of moles of the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>/compounds present in the chemical equation;</li> <li>The balanced equation has the following number of moles<br/> <mathjax>#3 mol Fe#</mathjax><br/> <mathjax>#4 mol H_2O#</mathjax><br/> <mathjax>#1 mol Fe_2O_4#</mathjax><br/> <mathjax>#4 mol H_2#</mathjax></li> <li>Therefore; the mole ratio is <mathjax>#(1 mol Fe_2O_4)/(3 mol Fe)#</mathjax></li> </ol></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#(Fe_3O_4)/(Fe)#</mathjax> is equal to<br/> <mathjax>#(1 mol)/(3 mol)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><ol> <li>To determine <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio of <a href="http://socratic.org/chemistry/chemical-reactions/chemical-equations">chemical equations</a>, generally is to make sure that the equation is balanced following the Law of the Conservation of Mass;</li> <li>Since the problem presents a balanced equation, all you have to do is to identify which <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> involved to get the right mole ratio;</li> <li>The number in front of each compound/element are called coefficients which also serves as the number of moles of the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>/compounds present in the chemical equation;</li> <li>The balanced equation has the following number of moles<br/> <mathjax>#3 mol Fe#</mathjax><br/> <mathjax>#4 mol H_2O#</mathjax><br/> <mathjax>#1 mol Fe_2O_4#</mathjax><br/> <mathjax>#4 mol H_2#</mathjax></li> <li>Therefore; the mole ratio is <mathjax>#(1 mol Fe_2O_4)/(3 mol Fe)#</mathjax></li> </ol></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the mole ratio of #Fe_3O_4# to #Fe# in the equation #3Fe + 4H_2O -&gt; Fe_3O_4 + 4H_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="240640" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jarni-renz"><img alt="" class="" src="https://profilepictures.socratic.org/i6OiZQmVRHWljDVlwm8v_WIN_20160301_180231.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jarni-renz"> Jarni Renz </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-16T23:28:17" itemprop="dateCreated"> Mar 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#(Fe_3O_4)/(Fe)#</mathjax> is equal to<br/> <mathjax>#(1 mol)/(3 mol)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><ol> <li>To determine <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio of <a href="http://socratic.org/chemistry/chemical-reactions/chemical-equations">chemical equations</a>, generally is to make sure that the equation is balanced following the Law of the Conservation of Mass;</li> <li>Since the problem presents a balanced equation, all you have to do is to identify which <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a> involved to get the right mole ratio;</li> <li>The number in front of each compound/element are called coefficients which also serves as the number of moles of the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a>/compounds present in the chemical equation;</li> <li>The balanced equation has the following number of moles<br/> <mathjax>#3 mol Fe#</mathjax><br/> <mathjax>#4 mol H_2O#</mathjax><br/> <mathjax>#1 mol Fe_2O_4#</mathjax><br/> <mathjax>#4 mol H_2#</mathjax></li> <li>Therefore; the mole ratio is <mathjax>#(1 mol Fe_2O_4)/(3 mol Fe)#</mathjax></li> </ol></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/240640" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179102bf3469517a1072"> Question #a1072 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179402bf34694c8c5bf1"> Question #c5bf1 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179702bf3469588dc373"> Question #dc373 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179c02bf34694c8c5bf9"> Question #c5bf9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417a302bf3469517a1076"> Question #a1076 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417c702bf3469588dc377"> Question #dc377 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d002bf346963eb984f"> Question #b984f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d402bf346950519ea3"> Question #19ea3 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/mole-ratios"> See all questions in Mole Ratios </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 8920 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the mole ratio of #Fe_3O_4# to #Fe# in the equation #3Fe + 4H_2O -&gt; Fe_3O_4 + 4H_2#?

a8f0eb2c-6ddd-11ea-ac83-ccda262736ce

https://socratic.org/questions/what-is-the-ph-of-a-0-150-m-naoh-solution

13.18

start physical_unit 8 9 ph none qc_end physical_unit 8 9 6 7 molarity qc_end end

[{"type":"physical unit","value":"pH [OF] NaOH solution"}]

[{"type":"physical unit","value":"13.18"}]

[{"type":"physical unit","value":"Molarity [OF] NaOH solution [=] \\pu{0.150 M}"}]

<h1 class="questionTitle" itemprop="name">What is the pH of a #"0.150-M"# #"NaOH"# solution?</h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The answer is 13.18 but I'm not sure how to get that answer? From what I know the formula is pH = -log[H+] so I just put -log(.150) which = .82 but that's not the correct answer. Can someone please correct me and show steps?</p></div> </h2> </div> </div>

13.18

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <mathjax>#"pH"#</mathjax> of the solution is given by </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("pH" = - log (["H"_3"O"^(+)]))))#</mathjax></p> </blockquote> <p>so you can't use</p> <blockquote> <p><mathjax>#color(red)(cancel(color(black)("pH" = - log(0.150))))#</mathjax></p> </blockquote> <p>because that's the concentration of the hydroxide anions, <mathjax>#"OH"^(-)#</mathjax>, <strong>not</strong> of the hydronium cations, <mathjax>#"H"_3"O"^(+)#</mathjax>. In essence, you calculated the <mathjax>#"pOH"#</mathjax> of the solution, not its <mathjax>#"pH"#</mathjax>.</p> <p>Sodium hydroxide is a <strong>strong base</strong>, which means that it dissociates <em>completely</em> in aqueous solution to produce hydroxide anions in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong>.</p> <blockquote> <p><mathjax>#"NaOH"_ ((aq)) -&gt; "Na"_ ((aq))^(+) + "OH"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>So your solution has</p> <blockquote> <p><mathjax>#["OH"^(-)] = ["NaOH"] = "0.150 M"#</mathjax></p> </blockquote> <p>Now, the <mathjax>#"pOH"#</mathjax> of the solution can be calculated by using</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("pOH" = - log(["OH"^(-)]))))#</mathjax></p> </blockquote> <p>In your case, you have</p> <blockquote> <p><mathjax>#"pOH" = - log(0.150) = 0.824#</mathjax></p> </blockquote> <p>Now, an aqueous solution at <mathjax>#25^@"C"#</mathjax> has</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("pH + pOH" = 14)))#</mathjax></p> </blockquote> <p>This means that you have</p> <blockquote> <p><mathjax>#"pH" = 14 - 0.824 = 13.176#</mathjax></p> </blockquote> <p>You should leave the answer rounded to three <em>decimal places</em> because you have three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> for the concentration of the solution. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#13.176#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <mathjax>#"pH"#</mathjax> of the solution is given by </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("pH" = - log (["H"_3"O"^(+)]))))#</mathjax></p> </blockquote> <p>so you can't use</p> <blockquote> <p><mathjax>#color(red)(cancel(color(black)("pH" = - log(0.150))))#</mathjax></p> </blockquote> <p>because that's the concentration of the hydroxide anions, <mathjax>#"OH"^(-)#</mathjax>, <strong>not</strong> of the hydronium cations, <mathjax>#"H"_3"O"^(+)#</mathjax>. In essence, you calculated the <mathjax>#"pOH"#</mathjax> of the solution, not its <mathjax>#"pH"#</mathjax>.</p> <p>Sodium hydroxide is a <strong>strong base</strong>, which means that it dissociates <em>completely</em> in aqueous solution to produce hydroxide anions in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong>.</p> <blockquote> <p><mathjax>#"NaOH"_ ((aq)) -&gt; "Na"_ ((aq))^(+) + "OH"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>So your solution has</p> <blockquote> <p><mathjax>#["OH"^(-)] = ["NaOH"] = "0.150 M"#</mathjax></p> </blockquote> <p>Now, the <mathjax>#"pOH"#</mathjax> of the solution can be calculated by using</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("pOH" = - log(["OH"^(-)]))))#</mathjax></p> </blockquote> <p>In your case, you have</p> <blockquote> <p><mathjax>#"pOH" = - log(0.150) = 0.824#</mathjax></p> </blockquote> <p>Now, an aqueous solution at <mathjax>#25^@"C"#</mathjax> has</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("pH + pOH" = 14)))#</mathjax></p> </blockquote> <p>This means that you have</p> <blockquote> <p><mathjax>#"pH" = 14 - 0.824 = 13.176#</mathjax></p> </blockquote> <p>You should leave the answer rounded to three <em>decimal places</em> because you have three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> for the concentration of the solution. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the pH of a #"0.150-M"# #"NaOH"# solution?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The answer is 13.18 but I'm not sure how to get that answer? From what I know the formula is pH = -log[H+] so I just put -log(.150) which = .82 but that's not the correct answer. Can someone please correct me and show steps?</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="516967" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-12-06T02:02:54" itemprop="dateCreated"> Dec 6, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#13.176#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <mathjax>#"pH"#</mathjax> of the solution is given by </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("pH" = - log (["H"_3"O"^(+)]))))#</mathjax></p> </blockquote> <p>so you can't use</p> <blockquote> <p><mathjax>#color(red)(cancel(color(black)("pH" = - log(0.150))))#</mathjax></p> </blockquote> <p>because that's the concentration of the hydroxide anions, <mathjax>#"OH"^(-)#</mathjax>, <strong>not</strong> of the hydronium cations, <mathjax>#"H"_3"O"^(+)#</mathjax>. In essence, you calculated the <mathjax>#"pOH"#</mathjax> of the solution, not its <mathjax>#"pH"#</mathjax>.</p> <p>Sodium hydroxide is a <strong>strong base</strong>, which means that it dissociates <em>completely</em> in aqueous solution to produce hydroxide anions in a <mathjax>#1:1#</mathjax> <strong>mole ratio</strong>.</p> <blockquote> <p><mathjax>#"NaOH"_ ((aq)) -&gt; "Na"_ ((aq))^(+) + "OH"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>So your solution has</p> <blockquote> <p><mathjax>#["OH"^(-)] = ["NaOH"] = "0.150 M"#</mathjax></p> </blockquote> <p>Now, the <mathjax>#"pOH"#</mathjax> of the solution can be calculated by using</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("pOH" = - log(["OH"^(-)]))))#</mathjax></p> </blockquote> <p>In your case, you have</p> <blockquote> <p><mathjax>#"pOH" = - log(0.150) = 0.824#</mathjax></p> </blockquote> <p>Now, an aqueous solution at <mathjax>#25^@"C"#</mathjax> has</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("pH + pOH" = 14)))#</mathjax></p> </blockquote> <p>This means that you have</p> <blockquote> <p><mathjax>#"pH" = 14 - 0.824 = 13.176#</mathjax></p> </blockquote> <p>You should leave the answer rounded to three <em>decimal places</em> because you have three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> for the concentration of the solution. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/516967" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 32474 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the pH of a #"0.150-M"# #"NaOH"# solution?

The answer is 13.18 but I'm not sure how to get that answer? From what I know the formula is pH = -log[H+] so I just put -log(.150) which = .82 but that's not the correct answer. Can someone please correct me and show steps?

abe1e5dc-6ddd-11ea-9fab-ccda262736ce

https://socratic.org/questions/how-many-moles-are-in-3-70-10-1-g-of-boron

0.03 moles

start physical_unit 10 10 mole mol qc_end physical_unit 10 10 5 8 mass qc_end end

[{"type":"physical unit","value":"Mole [OF] boron [IN] moles"}]

[{"type":"physical unit","value":"0.03 moles"}]

[{"type":"physical unit","value":"Mass [OF] boron [=] \\pu{3.70 × 10^(-1) g}"}]

<h1 class="questionTitle" itemprop="name">How many moles are in #3.70 * 10^-1# g of boron?</h1>

0.03 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Molar quantity <mathjax>#=#</mathjax> <mathjax>#(3.70xx10^(-1)*cancelg)/(10.81*cancelg*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#?? mol#</mathjax>. Note how this treatment is dimensionally consistent; I used <mathjax>#g#</mathjax> and <mathjax>#g*mol^-1#</mathjax> units, and I get an answer in <mathjax>#mol#</mathjax> as required <mathjax>#((mol^-1)^-1=mol)#</mathjax>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1 mol of boron has a mass of <mathjax>#10.81#</mathjax> <mathjax>#g#</mathjax>. To find the molar quantity divide the mass by the molar mass.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Molar quantity <mathjax>#=#</mathjax> <mathjax>#(3.70xx10^(-1)*cancelg)/(10.81*cancelg*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#?? mol#</mathjax>. Note how this treatment is dimensionally consistent; I used <mathjax>#g#</mathjax> and <mathjax>#g*mol^-1#</mathjax> units, and I get an answer in <mathjax>#mol#</mathjax> as required <mathjax>#((mol^-1)^-1=mol)#</mathjax>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles are in #3.70 * 10^-1# g of boron?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="201614" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-20T18:07:54" itemprop="dateCreated"> Dec 20, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1 mol of boron has a mass of <mathjax>#10.81#</mathjax> <mathjax>#g#</mathjax>. To find the molar quantity divide the mass by the molar mass.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Molar quantity <mathjax>#=#</mathjax> <mathjax>#(3.70xx10^(-1)*cancelg)/(10.81*cancelg*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#?? mol#</mathjax>. Note how this treatment is dimensionally consistent; I used <mathjax>#g#</mathjax> and <mathjax>#g*mol^-1#</mathjax> units, and I get an answer in <mathjax>#mol#</mathjax> as required <mathjax>#((mol^-1)^-1=mol)#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/201614" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 20729 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many moles are in #3.70 * 10^-1# g of boron?

abef1bf2-6ddd-11ea-aef3-ccda262736ce

https://socratic.org/questions/if-it-takes-41-72-joules-to-heat-a-piece-of-gold-weighing-18-69-g-from-10-0-c-to

0.13 J/(g * ℃)

start physical_unit 26 27 specific_heat j/(°c_·_g) qc_end physical_unit 26 27 3 4 heat_energy qc_end physical_unit 26 27 12 13 mass qc_end physical_unit 26 27 15 16 temperature qc_end physical_unit 26 27 18 19 temperature qc_end end

[{"type":"physical unit","value":"Specific heat [OF] the gold [IN] J/(g * ℃)"}]

[{"type":"physical unit","value":"0.13 J/(g * ℃)"}]

[{"type":"physical unit","value":"Taken energy [OF] the gold [=] \\pu{41.72 joules}"},{"type":"physical unit","value":"Weight [OF] the gold [=] \\pu{18.69 g}"},{"type":"physical unit","value":"Temperature1 [OF] the gold [=] \\pu{10.0 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] the gold [=] \\pu{27.0 ℃}"}]

<h1 class="questionTitle" itemprop="name">If it takes 41.72 joules to heat a piece of gold weighing 18.69 g from 10.0°C to 27.0°C, what is the specific heat of the gold?</h1>

0.13 J/(g * ℃)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The amount of heat (<mathjax>#q#</mathjax>) absorbed by gold could be expressed as:</p> <p><mathjax>#q=mxxsxxDeltaT#</mathjax></p> <p>where, <mathjax>#m=18.69g#</mathjax> is the mass of the object,<br/> <mathjax>#s#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity,<br/> and <mathjax>#DeltaT=T_f-T_i#</mathjax> is the change on temperature of the sample.</p> <p>Thus, the specific heat capacity is found by: </p> <p><mathjax>#s=q/(mxxDeltaT)=(41.72J)/(18.69gxx(27.0^@C-10.0^@C))=0.131J/(g*""^@C)#</mathjax></p> <p><strong>Thermochemistry | <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">Enthalpy</a> and <a href="https://socratic.org/chemistry/thermochemistry/calorimetry">Calorimetry</a>.</strong><br/> <iframe src="https://www.youtube.com/embed/RuBReH04pyE?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#s=0.131J/(g*""^@C)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The amount of heat (<mathjax>#q#</mathjax>) absorbed by gold could be expressed as:</p> <p><mathjax>#q=mxxsxxDeltaT#</mathjax></p> <p>where, <mathjax>#m=18.69g#</mathjax> is the mass of the object,<br/> <mathjax>#s#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity,<br/> and <mathjax>#DeltaT=T_f-T_i#</mathjax> is the change on temperature of the sample.</p> <p>Thus, the specific heat capacity is found by: </p> <p><mathjax>#s=q/(mxxDeltaT)=(41.72J)/(18.69gxx(27.0^@C-10.0^@C))=0.131J/(g*""^@C)#</mathjax></p> <p><strong>Thermochemistry | <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">Enthalpy</a> and <a href="https://socratic.org/chemistry/thermochemistry/calorimetry">Calorimetry</a>.</strong><br/> <iframe src="https://www.youtube.com/embed/RuBReH04pyE?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If it takes 41.72 joules to heat a piece of gold weighing 18.69 g from 10.0°C to 27.0°C, what is the specific heat of the gold?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="273478" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-03T17:23:20" itemprop="dateCreated"> Jun 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#s=0.131J/(g*""^@C)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The amount of heat (<mathjax>#q#</mathjax>) absorbed by gold could be expressed as:</p> <p><mathjax>#q=mxxsxxDeltaT#</mathjax></p> <p>where, <mathjax>#m=18.69g#</mathjax> is the mass of the object,<br/> <mathjax>#s#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity,<br/> and <mathjax>#DeltaT=T_f-T_i#</mathjax> is the change on temperature of the sample.</p> <p>Thus, the specific heat capacity is found by: </p> <p><mathjax>#s=q/(mxxDeltaT)=(41.72J)/(18.69gxx(27.0^@C-10.0^@C))=0.131J/(g*""^@C)#</mathjax></p> <p><strong>Thermochemistry | <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">Enthalpy</a> and <a href="https://socratic.org/chemistry/thermochemistry/calorimetry">Calorimetry</a>.</strong><br/> <iframe src="https://www.youtube.com/embed/RuBReH04pyE?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/273478" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? 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If it takes 41.72 joules to heat a piece of gold weighing 18.69 g from 10.0°C to 27.0°C, what is the specific heat of the gold?

ad118c5e-6ddd-11ea-ac64-ccda262736ce

https://socratic.org/questions/595c0fb47c014916d2f5f5d3

1.51 ppm

start physical_unit 14 15 concentration ppm qc_end physical_unit 2 2 4 6 equilibrium_constant_k qc_end end

[{"type":"physical unit","value":"Concentration [OF] ZnCO3 saturated solution [IN] ppm"}]

[{"type":"physical unit","value":"1.51 ppm"}]

[{"type":"physical unit","value":"Ksp [OF] ZnCO3 [=] \\pu{1.46 × 10^(-10)}"}]

<h1 class="questionTitle" itemprop="name">Given #K_"sp"# #ZnCO_3=1.46xx10^-10#, what is the #"ppm"# concentration of a saturated solution? </h1>

1.51 ppm

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#ZnCO_3 rightleftharpoons Zn^(+2) + CO_3^(2-)#</mathjax> is a 1:1 ionization ratio. The solubility can be determined using <mathjax>#S = sqrt(Ksp)#</mathjax></p> <p><mathjax>#S = sqrt(Ksp) = sqrt(1.46xx10^-10)M = 1.21xx10^-5M#</mathjax></p> <p><mathjax>#1.21xx10^-5(mol)/Lxx (125g)/"mol" = 1.51xx10^-3(g/L)#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#S = 1.21xx10^-5M = 1.51xx10^-3(g/L)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#ZnCO_3 rightleftharpoons Zn^(+2) + CO_3^(2-)#</mathjax> is a 1:1 ionization ratio. The solubility can be determined using <mathjax>#S = sqrt(Ksp)#</mathjax></p> <p><mathjax>#S = sqrt(Ksp) = sqrt(1.46xx10^-10)M = 1.21xx10^-5M#</mathjax></p> <p><mathjax>#1.21xx10^-5(mol)/Lxx (125g)/"mol" = 1.51xx10^-3(g/L)#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Given #K_"sp"# #ZnCO_3=1.46xx10^-10#, what is the #"ppm"# concentration of a saturated solution? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/solubility-equilbria" itemprop="url"> <span class="breadcrumb" itemprop="title">Solubility Equilbria</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="448056" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/doc048"><img alt="" class="" src="https://profilepictures.socratic.org/e4gaeUMMQESTpfte6aRu_Friendly%20Chem%20Professor.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/doc048"> Doc048 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-05T02:12:53" itemprop="dateCreated"> Jul 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#S = 1.21xx10^-5M = 1.51xx10^-3(g/L)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#ZnCO_3 rightleftharpoons Zn^(+2) + CO_3^(2-)#</mathjax> is a 1:1 ionization ratio. The solubility can be determined using <mathjax>#S = sqrt(Ksp)#</mathjax></p> <p><mathjax>#S = sqrt(Ksp) = sqrt(1.46xx10^-10)M = 1.21xx10^-5M#</mathjax></p> <p><mathjax>#1.21xx10^-5(mol)/Lxx (125g)/"mol" = 1.51xx10^-3(g/L)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/448056" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="448076" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-05T03:51:46" itemprop="dateCreated"> Jul 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Solubility"_(ZnCO_3) = "1 ppm"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We consider the equilibrium reaction.........</p> <p><mathjax>#ZnCO_3(s) stackrel(H_2O)rightleftharpoonsZn^(2+) + CO_3^(2-)#</mathjax></p> <p>And <mathjax>#K_(sp)=[Zn^(2+)][CO_3^(2-)]=1.46xx10^-10#</mathjax></p> <p>We let the <mathjax>#"Solubility"_(ZnCO_3) = x*mol*L^-1#</mathjax></p> <p>And thus <mathjax>#"Solubility"_(ZnCO_3)=sqrt(1.46xx10^-10)#</mathjax></p> <p><mathjax>#=1.21xx10^-5*mol*L^-1#</mathjax></p> <p>And thus the <mathjax>#"gram solubility"#</mathjax> of <mathjax>#"zinc carbonate"#</mathjax></p> <p><mathjax>#-=1.21xx10^-5*mol*L^-1xx125.4*g*mol^-1~=1*mg*L^-1#</mathjax>, i.e. <mathjax>#"ppm"#</mathjax> concentrations. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/448076" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-equilibrium"> How does solubility affect equilibrium? 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Given #K_"sp"# #ZnCO_3=1.46xx10^-10#, what is the #"ppm"# concentration of a saturated solution?

ac6f52ca-6ddd-11ea-8a88-ccda262736ce

https://socratic.org/questions/given-the-reaction-2c3h7oh-9o2-co2-8h2o-how-many-moles-of-oxygen-are-needed-to-r

15.30 moles

start physical_unit 17 17 mole mol qc_end chemical_equation 3 12 qc_end physical_unit 4 4 23 24 mole qc_end end

[{"type":"physical unit","value":"Mole [OF] oxygen [IN] moles"}]

[{"type":"physical unit","value":"15.30 moles"}]

[{"type":"physical unit","value":"Mole [OF] C3H7OH [=] \\pu{3.40 mol}"},{"type":"chemical equation","value":"2 C3H7OH + 9 O2 -> CO2 + 8 H2O"}]

<h1 class="questionTitle" itemprop="name"> Given the reaction 2C3H7OH + 9O2 --&gt;CO2 + 8H2O, how many moles of oxygen are needed to react with 3.40 mol C3H7OH? </h1>

15.30 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Equation:</p> <p><mathjax>#C_3H_7OH + 9/2O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#3CO_2 + 4H_2O#</mathjax></p> <p>Is the equation above balanced? (If this was change from a large denomination bill I think you would immediately know whether you were being short-changed!). Let's see: LHS, <mathjax>#3C#</mathjax>, <mathjax>#8H#</mathjax>, and <mathjax>#10O#</mathjax>; RHS, <mathjax>#3C#</mathjax>, <mathjax>#8H#</mathjax>, and <mathjax>#10O#</mathjax>. So it is balanced.</p> <p>Your starting conditions requires the combustion of 3.4 mol propanol. You do the arithmetic, but make sure that you are right.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Given the balanced equation to follow, <mathjax>#9/2#</mathjax> moles of dioxygen gas are required to combust 1 mol propanol. So the answer? </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Equation:</p> <p><mathjax>#C_3H_7OH + 9/2O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#3CO_2 + 4H_2O#</mathjax></p> <p>Is the equation above balanced? (If this was change from a large denomination bill I think you would immediately know whether you were being short-changed!). Let's see: LHS, <mathjax>#3C#</mathjax>, <mathjax>#8H#</mathjax>, and <mathjax>#10O#</mathjax>; RHS, <mathjax>#3C#</mathjax>, <mathjax>#8H#</mathjax>, and <mathjax>#10O#</mathjax>. So it is balanced.</p> <p>Your starting conditions requires the combustion of 3.4 mol propanol. You do the arithmetic, but make sure that you are right.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name"> Given the reaction 2C3H7OH + 9O2 --&gt;CO2 + 8H2O, how many moles of oxygen are needed to react with 3.40 mol C3H7OH? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="179668" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-24T19:10:51" itemprop="dateCreated"> Oct 24, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Given the balanced equation to follow, <mathjax>#9/2#</mathjax> moles of dioxygen gas are required to combust 1 mol propanol. So the answer? </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Equation:</p> <p><mathjax>#C_3H_7OH + 9/2O_2#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#3CO_2 + 4H_2O#</mathjax></p> <p>Is the equation above balanced? (If this was change from a large denomination bill I think you would immediately know whether you were being short-changed!). Let's see: LHS, <mathjax>#3C#</mathjax>, <mathjax>#8H#</mathjax>, and <mathjax>#10O#</mathjax>; RHS, <mathjax>#3C#</mathjax>, <mathjax>#8H#</mathjax>, and <mathjax>#10O#</mathjax>. So it is balanced.</p> <p>Your starting conditions requires the combustion of 3.4 mol propanol. You do the arithmetic, but make sure that you are right.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/179668" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="180305" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nikka-c"><img alt="" class="" src="https://profilepictures.socratic.org/AQ8VOCyTM1J7U0TvIWhw_nkahara.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nikka-c"> Nikka C. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-27T10:26:29" itemprop="dateCreated"> Oct 27, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Are you sure about the equation? seems this isn't balanced seeing that there are 5 carbons on the left side of the equation and only 1 carbon on the right side... </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, let's balance the above equation properly.</p> <p><mathjax>#C_3H_7OH#</mathjax> + <mathjax>#O_2#</mathjax> = <mathjax>#CO_2#</mathjax> + <mathjax>#H_2O#</mathjax></p> <p>left side:<br/> C = 3<br/> H = 8<br/> O = 1 + 2 (DO NOT ADD IT UP YET)</p> <p>right side:<br/> C = 1<br/> H = 2<br/> O = 2 + 1 (DO NOT ADD IT UP YET)</p> <p>balancing this equation we have</p> <p><mathjax>#C_3H_7OH#</mathjax> + <mathjax>#color (red) (9/2)O_2#</mathjax> = <mathjax>#color (red) 3CO_2#</mathjax> + <mathjax>#color (red) 4H_2O#</mathjax></p> <p>left side:<br/> C = 3<br/> H = 8<br/> O = 1 + (2 x <mathjax>#color (red) (9/2)#</mathjax>) = 10</p> <p>right side:<br/> C = 1 x <mathjax>#color (red) 3#</mathjax> = 3<br/> H = 2 x <mathjax>#color (red) 4#</mathjax> = 8<br/> O = (2 x <mathjax>#color (red) 3#</mathjax>) + (1 x <mathjax>#color (red) 4#</mathjax>) = 10</p> <p>Now that the equation is balanced, we can proceed in answering your initial question. Please note to <strong>ALWAYS</strong> check if the equation is balanced as your computation hangs on the correct coefficients in the chemical equation.</p> <p>You are being asked to compute the number of <mathjax>#O_2#</mathjax> moles needed to react with 3.40 moles of <mathjax>#C_3H_7OH#</mathjax>. </p> <p>From the balanced equation, we know that for every 1 mole of <mathjax>#C_3H_7OH#</mathjax>, it needs <mathjax>#9/2#</mathjax> (or 4.5) moles of <mathjax>#O_2#</mathjax> to react. Thus, </p> <p><mathjax>#3.40#</mathjax> <mathjax>#cancel "mol"#</mathjax> <mathjax>#C_3H_7OH#</mathjax> x <mathjax>#(4.5 "mol" O_2)/(1 cancel ("mol") C_3H_7OH)#</mathjax> = <mathjax>#15.3#</mathjax> <mathjax>#"mol"#</mathjax> <mathjax>#O_2#</mathjax></p> <p>Therefore, the correct answer should be <strong>15.3 moles of <mathjax>#O_2#</mathjax></strong></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/180305" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -&gt; 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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Given the reaction 2C3H7OH + 9O2 --&gt;CO2 + 8H2O, how many moles of oxygen are needed to react with 3.40 mol C3H7OH?

ad27b9f4-6ddd-11ea-8a3c-ccda262736ce

https://socratic.org/questions/a-5-00-l-container-contains-ch-4-at-35-c-with-a-total-pressure-of-1-81-atm-what-

0.35 atm

start physical_unit 5 5 pressure atm qc_end physical_unit 5 5 1 2 volume qc_end physical_unit 5 5 7 8 temperature qc_end physical_unit 5 5 14 15 total_pressure qc_end physical_unit 5 5 27 28 volume qc_end physical_unit 5 5 30 31 temperature qc_end end

[{"type":"physical unit","value":"Pressure2 [OF] CH4 [IN] atm"}]

[{"type":"physical unit","value":"0.35 atm"}]

[{"type":"physical unit","value":"Volume1 [OF] CH4 [=] \\pu{5.00 L}"},{"type":"physical unit","value":"Temperature1 [OF] CH4 [=] \\pu{35 ℃}"},{"type":"physical unit","value":"Total pressure1 [OF] CH4 [=] \\pu{1.81 atm}"},{"type":"physical unit","value":"Volume2 [OF] CH4 [=] \\pu{25.0 L}"},{"type":"physical unit","value":"Temperature2 [OF] CH4 [=] \\pu{25 ℃}"}]

<h1 class="questionTitle" itemprop="name">A 5.00 L container contains #CH_4# at 35°C with a total pressure of 1.81 atm. What is the pressure of the gas when it expands to 25.0 L at 25°C? </h1>

0.35 atm

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#(P_1V_1)/T_1=(P_2V_2)/T_2#</mathjax></p> <p><mathjax>#P_2=(P_1V_1)/T_1xxT_2/V_2#</mathjax></p> <p><mathjax>#=(1.81*atmxx5.00*Lxx298*K)/(308*Kxx25.0*L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??atm#</mathjax></p> <p>Note that I used absolute temperature, as these problems always require such readings:</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#(P_1V_1)/T_1=(P_2V_2)/T_2#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#0.4*atm#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#(P_1V_1)/T_1=(P_2V_2)/T_2#</mathjax></p> <p><mathjax>#P_2=(P_1V_1)/T_1xxT_2/V_2#</mathjax></p> <p><mathjax>#=(1.81*atmxx5.00*Lxx298*K)/(308*Kxx25.0*L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??atm#</mathjax></p> <p>Note that I used absolute temperature, as these problems always require such readings:</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A 5.00 L container contains #CH_4# at 35°C with a total pressure of 1.81 atm. What is the pressure of the gas when it expands to 25.0 L at 25°C? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/combined-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Combined Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="278921" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-19T05:01:54" itemprop="dateCreated"> Jun 19, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#(P_1V_1)/T_1=(P_2V_2)/T_2#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#0.4*atm#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#(P_1V_1)/T_1=(P_2V_2)/T_2#</mathjax></p> <p><mathjax>#P_2=(P_1V_1)/T_1xxT_2/V_2#</mathjax></p> <p><mathjax>#=(1.81*atmxx5.00*Lxx298*K)/(308*Kxx25.0*L)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??atm#</mathjax></p> <p>Note that I used absolute temperature, as these problems always require such readings:</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/278921" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5345df5f02bf345f71b1c8e8"> Question #1c8e8 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ac3df02bf342f4c3bfabb"> Question #bfabb </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-you-want-to-solve-for-the-volume-of-a-gas-v2-and-p1-is-greater-than-p2-would-"> If you want to solve for the volume of a gas (V2) and P1 is greater than P2, would you expect V2... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-modern-refrigerator-take-advantage-of-the-gas-laws-to-remove-heat-f"> How does the modern refrigerator take advantage of the gas laws to remove heat from a system? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-certain-sample-of-gas-has-a-volume-of-0-452-l-measured-at-87-c-and-0-620-atm-w"> A certain sample of gas has a volume of 0.452 L measured at 87°C and 0.620 atm. What is its... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/which-situations-does-the-combined-gas-law-enable-you-to-do-calculations-when-th"> Which situations does the combined gas law enable you to do calculations when the other gas laws... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-small-research-submarine-with-a-volume-of-1-2x10-5-l-has-an-internal-pressure-"> A small research submarine with a volume of 1.2x10 ^5 L has an internal pressure of 1.0 atm and... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-is-the-combined-gas-law-different-from-boyle-s-law"> How is the combined gas law different from boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-pressure-of-an-combined-gas-change-as-temperature-increases"> How does the pressure of an combined gas change as temperature increases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-ideal-gas-law-differ-from-the-combined-gas-law-1"> How does the ideal gas law differ from the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/combined-gas-law"> See all questions in Combined Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2033 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A 5.00 L container contains #CH_4# at 35°C with a total pressure of 1.81 atm. What is the pressure of the gas when it expands to 25.0 L at 25°C?

ad0c82e1-6ddd-11ea-9422-ccda262736ce

https://socratic.org/questions/if-a-buffer-made-by-dissolving-20-0-g-of-sodium-benzoate-144g-mol-and-10-grams-o

4.43

start physical_unit 35 36 ph none qc_end physical_unit 9 10 6 7 mass qc_end physical_unit 9 10 11 12 molar_mass qc_end physical_unit 17 18 14 15 mass qc_end physical_unit 17 18 19 20 molar_mass qc_end substance 22 22 qc_end physical_unit 35 36 28 29 volume qc_end end

[{"type":"physical unit","value":"pH [OF] the buffer"}]

[{"type":"physical unit","value":"4.43"}]

[{"type":"physical unit","value":"Mass [OF] sodium benzoate [=] \\pu{20.0 g}"},{"type":"physical unit","value":"Molar mass [OF] sodium benzoate [=] \\pu{144 g/mol}"},{"type":"physical unit","value":"Mass [OF] benzoic acid [=] \\pu{10 grams}"},{"type":"physical unit","value":"Molar mass [OF] benzoic acid [=] \\pu{122 g/mol}"},{"type":"substance name","value":"Water"},{"type":"physical unit","value":"Volume [OF] the buffer [=] \\pu{500.0 ml}"}]

<h1 class="questionTitle" itemprop="name">If a buffer made by dissolving 20.0 g of sodium benzoate (144g/mol) and 10 grams of benzoic acid (122g/mol) in water to a final volume of 500.0 ml, what is the pH of the buffer? </h1>

4.43

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the buffered solution in question, we can simply use the Henderson-Hasselbach equation:</p> <p><mathjax>#pH=pK_a+log(([Base])/([Acid]))#</mathjax></p> <p>where, <mathjax>#pK_a#</mathjax> for benzoic acid is <mathjax>#4.20#</mathjax>.</p> <p>and <mathjax>#[Benzoate]=n/V and n=m/(MM)=(20.0cancel(g))/(144cancel(g)/(mol))=0.139mol#</mathjax></p> <p><mathjax>#[Benzoate]=n/V=(0.139mol)/(0.500L)=0.278M#</mathjax></p> <p>and <mathjax>#["Benzoic acid"]=n/V and n=m/(MM)=(10.0cancel(g))/(122cancel(g)/(mol))=0.0820mol#</mathjax></p> <p><mathjax>#[Benzoate]=n/V=(0.0820mol)/(0.500L)=0.164M#</mathjax></p> <p>Therefore, <mathjax>#pH=4.20+log((0.278)/(0.164))=4.43#</mathjax></p> <p><strong>Acid - Base Equilibria | Buffer Solution.</strong><br/> <iframe src="https://www.youtube.com/embed/k5kciTohejA?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=4.43#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the buffered solution in question, we can simply use the Henderson-Hasselbach equation:</p> <p><mathjax>#pH=pK_a+log(([Base])/([Acid]))#</mathjax></p> <p>where, <mathjax>#pK_a#</mathjax> for benzoic acid is <mathjax>#4.20#</mathjax>.</p> <p>and <mathjax>#[Benzoate]=n/V and n=m/(MM)=(20.0cancel(g))/(144cancel(g)/(mol))=0.139mol#</mathjax></p> <p><mathjax>#[Benzoate]=n/V=(0.139mol)/(0.500L)=0.278M#</mathjax></p> <p>and <mathjax>#["Benzoic acid"]=n/V and n=m/(MM)=(10.0cancel(g))/(122cancel(g)/(mol))=0.0820mol#</mathjax></p> <p><mathjax>#[Benzoate]=n/V=(0.0820mol)/(0.500L)=0.164M#</mathjax></p> <p>Therefore, <mathjax>#pH=4.20+log((0.278)/(0.164))=4.43#</mathjax></p> <p><strong>Acid - Base Equilibria | Buffer Solution.</strong><br/> <iframe src="https://www.youtube.com/embed/k5kciTohejA?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If a buffer made by dissolving 20.0 g of sodium benzoate (144g/mol) and 10 grams of benzoic acid (122g/mol) in water to a final volume of 500.0 ml, what is the pH of the buffer? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/buffer-theory" itemprop="url"> <span class="breadcrumb" itemprop="title">Buffer Theory</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="252939" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-11T16:30:57" itemprop="dateCreated"> Apr 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=4.43#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To find the <a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of the buffered solution in question, we can simply use the Henderson-Hasselbach equation:</p> <p><mathjax>#pH=pK_a+log(([Base])/([Acid]))#</mathjax></p> <p>where, <mathjax>#pK_a#</mathjax> for benzoic acid is <mathjax>#4.20#</mathjax>.</p> <p>and <mathjax>#[Benzoate]=n/V and n=m/(MM)=(20.0cancel(g))/(144cancel(g)/(mol))=0.139mol#</mathjax></p> <p><mathjax>#[Benzoate]=n/V=(0.139mol)/(0.500L)=0.278M#</mathjax></p> <p>and <mathjax>#["Benzoic acid"]=n/V and n=m/(MM)=(10.0cancel(g))/(122cancel(g)/(mol))=0.0820mol#</mathjax></p> <p><mathjax>#[Benzoate]=n/V=(0.0820mol)/(0.500L)=0.164M#</mathjax></p> <p>Therefore, <mathjax>#pH=4.20+log((0.278)/(0.164))=4.43#</mathjax></p> <p><strong>Acid - Base Equilibria | Buffer Solution.</strong><br/> <iframe src="https://www.youtube.com/embed/k5kciTohejA?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/252939" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-the-applications-of-a-buffer"> What are the applications of a buffer? 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What are the different types of buffers found in the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/reactions-in-solution/buffer-theory"> See all questions in Buffer Theory </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2974 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

If a buffer made by dissolving 20.0 g of sodium benzoate (144g/mol) and 10 grams of benzoic acid (122g/mol) in water to a final volume of 500.0 ml, what is the pH of the buffer?

ab7694b4-6ddd-11ea-97f0-ccda262736ce

https://socratic.org/questions/an-aqueous-solution-of-lead-ii-phosphate-is-added-to-an-aqueous-solution-of-pota

PbHPO4(aq) + 2 KI(aq) -> PbI2(s) + KH2PO4

start chemical_equation qc_end c_other OTHER qc_end end

[{"type":"other","value":"Chemical Equation [OF] the balanced chemical equation"}]

[{"type":"chemical equation","value":"PbHPO4(aq) + 2 KI(aq) -> PbI2(s) + KH2PO4"}]

[{"type":"other","value":"When the two colorless solutions mix, a bright yellow precipitate forms in a double replacement reaction."},{"type":"substance name","value":"Lead II phosphate aqueous solution"},{"type":"substance name","value":"Potassium iodide aqueous solution"}]

<h1 class="questionTitle" itemprop="name">An aqueous solution of lead II phosphate is added to an aqueous solution of potassium iodide. When the two colorless solutions mix, a bright yellow precipitate forms in a double replacement reaction. What is the balanced chemical equation? </h1>

PbHPO4(aq) + 2 KI(aq) -> PbI2(s) + KH2PO4

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This question is unfortunate as phosphate salts tend to be as soluble as bricks, and lead phosphate, <mathjax>#Pb_3(PO_4)_2#</mathjax> would be even more insoluble. Thus I have assumed a biphosphate salt; <mathjax>#HPO_4^(2-)#</mathjax> can have some solubility (at any rate phosphate ion, <mathjax>#PO_4^(3-)#</mathjax>, is fairly rare, and speciates to <mathjax>#HPO_4^(2-)#</mathjax> in aqueous solution). </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#PbHPO_4(aq) + 2KI(aq) rarr PbI_2(s)darr + KH_2PO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This question is unfortunate as phosphate salts tend to be as soluble as bricks, and lead phosphate, <mathjax>#Pb_3(PO_4)_2#</mathjax> would be even more insoluble. Thus I have assumed a biphosphate salt; <mathjax>#HPO_4^(2-)#</mathjax> can have some solubility (at any rate phosphate ion, <mathjax>#PO_4^(3-)#</mathjax>, is fairly rare, and speciates to <mathjax>#HPO_4^(2-)#</mathjax> in aqueous solution). </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">An aqueous solution of lead II phosphate is added to an aqueous solution of potassium iodide. When the two colorless solutions mix, a bright yellow precipitate forms in a double replacement reaction. What is the balanced chemical equation? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/double-replacement-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Double Replacement Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="212644" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-15T07:53:14" itemprop="dateCreated"> Jan 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#PbHPO_4(aq) + 2KI(aq) rarr PbI_2(s)darr + KH_2PO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This question is unfortunate as phosphate salts tend to be as soluble as bricks, and lead phosphate, <mathjax>#Pb_3(PO_4)_2#</mathjax> would be even more insoluble. Thus I have assumed a biphosphate salt; <mathjax>#HPO_4^(2-)#</mathjax> can have some solubility (at any rate phosphate ion, <mathjax>#PO_4^(3-)#</mathjax>, is fairly rare, and speciates to <mathjax>#HPO_4^(2-)#</mathjax> in aqueous solution). </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/212644" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41c3a02bf346963eb9867"> How do you balance the chemical equations for double replacement reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41c5202bf34694c8c5c10"> Question #c5c10 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-chemical-equation-for-the-neutralization-of-nitric-acid-hno3-wit"> How do you write chemical equation for the neutralization of nitric acid, HNO3, with magnesium... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535df00c02bf342f4b808090"> Question #08090 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-neutralization-a-double-replacement-reaction-1"> Why is neutralization a double replacement reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-double-displacement-reactions"> How can I identify double displacement reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-single-replacement-reactions-differ-from-double-replacement-reactions"> How do single replacement reactions differ from double replacement reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-double-replacement-reactions"> How do you balance double replacement reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-double-replacement-reactions-be-redox-reactions"> Can double replacement reactions be redox reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-with-double-replacement-reactions"> What are some common mistakes students make with double replacement reactions? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/double-replacement-reactions"> See all questions in Double Replacement Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5247 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

An aqueous solution of lead II phosphate is added to an aqueous solution of potassium iodide. When the two colorless solutions mix, a bright yellow precipitate forms in a double replacement reaction. What is the balanced chemical equation?

aad18ed3-6ddd-11ea-b445-ccda262736ce

https://socratic.org/questions/57c7fc4b11ef6b28d3890fab

116.25 g

start physical_unit 3 4 mass g qc_end physical_unit 14 14 10 11 mass qc_end physical_unit 21 22 17 18 mass qc_end end

[{"type":"physical unit","value":"Mass [OF] ammonium sulfate [IN] g"}]

[{"type":"physical unit","value":"116.25 g"}]

[{"type":"physical unit","value":"Mass [OF] ammonia [=] \\pu{30 g}"},{"type":"physical unit","value":"Mass [OF] sulfuric acid [=] \\pu{196 g}"}]

<h1 class="questionTitle" itemprop="name">What mass of #"ammonium sulfate"# can be prepared from a #30*g# mass of #"ammonia"#, and a #196*g# mass of #"sulfuric acid"#?</h1>

116.25 g

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We have a balanced chemical equation that represents the <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a> of ammonia by sulfuric acid.</p> <p><mathjax>#"Moles of ammonia"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(30*g)/(17*g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.76*mol#</mathjax>.</p> <p><mathjax>#"Moles of vitriol"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(196*g)/(98.08*g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.00*mol#</mathjax>.</p> <p>Now clearly, given the 2:1 <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, ammonia is the <a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>, and sulfuric is in excess. (What do I mean by 2:1 stoichiometry?)</p> <p>Given <mathjax>#1.76#</mathjax> <mathjax>#mol#</mathjax> ammonia, we can make <mathjax>#(1.76*mol)/2#</mathjax> ammonium sulfate;</p> <p>i.e. <mathjax>#(1.76*cancel(mol))/2xx132.1*g*cancel(mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2NH_3(aq) + H_2SO_4(aq) rarr (NH_4)_2SO_4(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We have a balanced chemical equation that represents the <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a> of ammonia by sulfuric acid.</p> <p><mathjax>#"Moles of ammonia"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(30*g)/(17*g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.76*mol#</mathjax>.</p> <p><mathjax>#"Moles of vitriol"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(196*g)/(98.08*g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.00*mol#</mathjax>.</p> <p>Now clearly, given the 2:1 <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, ammonia is the <a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>, and sulfuric is in excess. (What do I mean by 2:1 stoichiometry?)</p> <p>Given <mathjax>#1.76#</mathjax> <mathjax>#mol#</mathjax> ammonia, we can make <mathjax>#(1.76*mol)/2#</mathjax> ammonium sulfate;</p> <p>i.e. <mathjax>#(1.76*cancel(mol))/2xx132.1*g*cancel(mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What mass of #"ammonium sulfate"# can be prepared from a #30*g# mass of #"ammonia"#, and a #196*g# mass of #"sulfuric acid"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="305895" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-04T07:27:06" itemprop="dateCreated"> Sep 4, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2NH_3(aq) + H_2SO_4(aq) rarr (NH_4)_2SO_4(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We have a balanced chemical equation that represents the <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a> of ammonia by sulfuric acid.</p> <p><mathjax>#"Moles of ammonia"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(30*g)/(17*g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#1.76*mol#</mathjax>.</p> <p><mathjax>#"Moles of vitriol"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(196*g)/(98.08*g*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#2.00*mol#</mathjax>.</p> <p>Now clearly, given the 2:1 <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, ammonia is the <a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>, and sulfuric is in excess. (What do I mean by 2:1 stoichiometry?)</p> <p>Given <mathjax>#1.76#</mathjax> <mathjax>#mol#</mathjax> ammonia, we can make <mathjax>#(1.76*mol)/2#</mathjax> ammonium sulfate;</p> <p>i.e. <mathjax>#(1.76*cancel(mol))/2xx132.1*g*cancel(mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??g#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/305895" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1008 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What mass of #"ammonium sulfate"# can be prepared from a #30*g# mass of #"ammonia"#, and a #196*g# mass of #"sulfuric acid"#?

ab6600c8-6ddd-11ea-9f26-ccda262736ce

https://socratic.org/questions/what-is-the-formula-mass-for-carbon-tetrafloride

88.00 amu

start physical_unit 6 7 molecular_weight amu qc_end substance 6 7 qc_end end

[{"type":"physical unit","value":"Formula mass [OF] carbon tetrafloride [IN] amu"}]

[{"type":"physical unit","value":"88.00 amu"}]

[{"type":"substance name","value":"Carbon tetrafloride"}]

<h1 class="questionTitle" itemprop="name">What is the formula mass for carbon tetrafloride?</h1>

88.00 amu

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><ol> <li>Write down the formula of the compound;<br/> <mathjax>#CF_4#</mathjax></li> <li>Identify the number of atoms of each element composing the compound;<br/> <mathjax>#C=1#</mathjax><br/> <mathjax>#F=4#</mathjax></li> <li>Take the atomic masses of the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> from <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the Periodic Table</a> and multiply with the number of atoms;<br/> <mathjax>#C = 1 #</mathjax>x<mathjax># 12 = 12#</mathjax> amu<br/> <mathjax>#F=4 #</mathjax>x<mathjax># 19 = 76#</mathjax> amu</li> <li>Total is <mathjax>#88#</mathjax> amu</li> </ol></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#88#</mathjax> amu</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><ol> <li>Write down the formula of the compound;<br/> <mathjax>#CF_4#</mathjax></li> <li>Identify the number of atoms of each element composing the compound;<br/> <mathjax>#C=1#</mathjax><br/> <mathjax>#F=4#</mathjax></li> <li>Take the atomic masses of the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> from <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the Periodic Table</a> and multiply with the number of atoms;<br/> <mathjax>#C = 1 #</mathjax>x<mathjax># 12 = 12#</mathjax> amu<br/> <mathjax>#F=4 #</mathjax>x<mathjax># 19 = 76#</mathjax> amu</li> <li>Total is <mathjax>#88#</mathjax> amu</li> </ol></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the formula mass for carbon tetrafloride?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#covalent-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Covalent Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/covalent-bonds-and-formulas/covalent-formulas-and-nomenclature" itemprop="url"> <span class="breadcrumb" itemprop="title">Covalent Formulas and Nomenclature</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="239140" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jarni-renz"><img alt="" class="" src="https://profilepictures.socratic.org/i6OiZQmVRHWljDVlwm8v_WIN_20160301_180231.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jarni-renz"> Jarni Renz </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-13T12:03:04" itemprop="dateCreated"> Mar 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#88#</mathjax> amu</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><ol> <li>Write down the formula of the compound;<br/> <mathjax>#CF_4#</mathjax></li> <li>Identify the number of atoms of each element composing the compound;<br/> <mathjax>#C=1#</mathjax><br/> <mathjax>#F=4#</mathjax></li> <li>Take the atomic masses of the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> from <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the Periodic Table</a> and multiply with the number of atoms;<br/> <mathjax>#C = 1 #</mathjax>x<mathjax># 12 = 12#</mathjax> amu<br/> <mathjax>#F=4 #</mathjax>x<mathjax># 19 = 76#</mathjax> amu</li> <li>Total is <mathjax>#88#</mathjax> amu</li> </ol></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/239140" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-for-sugar"> What is the chemical formula for sugar? 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What is the formula mass for carbon tetrafloride?

aaf573ee-6ddd-11ea-a5b2-ccda262736ce

https://socratic.org/questions/find-the-molecular-formula-of-an-acid-with-a-molar-mass-of-98-grams-per-moles-an

H2SO4

start chemical_formula qc_end physical_unit 24 25 12 15 molar_mass qc_end end

[{"type":"other","value":"Chemical Formula [OF] the acid [IN] molecular"}]

[{"type":"chemical equation","value":"H2SO4"}]

[{"type":"physical unit","value":"Molar mass [OF] the acid [=] \\pu{98 grams per moles}"},{"type":"physical unit","value":"Percentage composition [OF] hydrogen in the acid [=] \\pu{2%}"},{"type":"physical unit","value":"Percentage composition [OF] sulphur in the acid [=] \\pu{33%}"},{"type":"physical unit","value":"Percentage composition [OF] oxygen in the acid [=] \\pu{65%}"}]

<h1 class="questionTitle" itemprop="name">Find the molecular formula of an acid with a molar mass of 98 grams per moles and the percentage composition of the elements in the acid is as such: hydrogen=2%, sulphur=33%, oxygen=65% ?</h1>

H2SO4

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We must first find the empirical formula.</p> <p>We can say that, in a <mathjax>#100"g"#</mathjax> sample, we have <mathjax>#2"g"#</mathjax> hydrogen, <mathjax>#"33g"#</mathjax> sulfur, and <mathjax>#65"g"#</mathjax> oxygen.</p> <p>Converting to <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">moles</a>:</p> <p><mathjax>#2"g H"*(1 "mol H")/(1 "g H")= 2 "mol H"#</mathjax></p> <p><mathjax>#33"g S"*(1 "mol S")/(32 "g S")=1.03"mol S" #</mathjax></p> <p><mathjax>#65 "g O"*(1 "mol O")/(16"g O")=4.06"mol O"#</mathjax></p> <p>We must divide each mole number by the smallest number, which, here, is <mathjax>#1.03#</mathjax>. Then round to the nearest whole number.</p> <p>For hydrogen: <mathjax>#2/1.03=1.94~~2#</mathjax><br/> For sulfur: <mathjax>#1.03/1.03=1#</mathjax><br/> For oxygen: <mathjax>#4.06/1.03=3.94~~4#</mathjax></p> <p>Putting them all together, we get:</p> <p><mathjax>#"H"_2"SO"_4#</mathjax>, sulfuric acid.</p> <p>We must check if the molar mass of sulfuric acid is <mathjax>#98"g"#</mathjax>:</p> <p><mathjax>#(1*2)+32+(16*4)=98#</mathjax></p> <p>So the molecular formula is also <mathjax>#"H"_2"SO"_4#</mathjax>, sulfuric acid.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"H"_2"SO"_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We must first find the empirical formula.</p> <p>We can say that, in a <mathjax>#100"g"#</mathjax> sample, we have <mathjax>#2"g"#</mathjax> hydrogen, <mathjax>#"33g"#</mathjax> sulfur, and <mathjax>#65"g"#</mathjax> oxygen.</p> <p>Converting to <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">moles</a>:</p> <p><mathjax>#2"g H"*(1 "mol H")/(1 "g H")= 2 "mol H"#</mathjax></p> <p><mathjax>#33"g S"*(1 "mol S")/(32 "g S")=1.03"mol S" #</mathjax></p> <p><mathjax>#65 "g O"*(1 "mol O")/(16"g O")=4.06"mol O"#</mathjax></p> <p>We must divide each mole number by the smallest number, which, here, is <mathjax>#1.03#</mathjax>. Then round to the nearest whole number.</p> <p>For hydrogen: <mathjax>#2/1.03=1.94~~2#</mathjax><br/> For sulfur: <mathjax>#1.03/1.03=1#</mathjax><br/> For oxygen: <mathjax>#4.06/1.03=3.94~~4#</mathjax></p> <p>Putting them all together, we get:</p> <p><mathjax>#"H"_2"SO"_4#</mathjax>, sulfuric acid.</p> <p>We must check if the molar mass of sulfuric acid is <mathjax>#98"g"#</mathjax>:</p> <p><mathjax>#(1*2)+32+(16*4)=98#</mathjax></p> <p>So the molecular formula is also <mathjax>#"H"_2"SO"_4#</mathjax>, sulfuric acid.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Find the molecular formula of an acid with a molar mass of 98 grams per moles and the percentage composition of the elements in the acid is as such: hydrogen=2%, sulphur=33%, oxygen=65% ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="556181" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/surya-k-2"><img alt="" class="" src="https://profilepictures.socratic.org/g84xu6vTUmSnPW2MqvuP_phi-symbol-1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/surya-k-2"> Surya K. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-02-22T12:46:29" itemprop="dateCreated"> Feb 22, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"H"_2"SO"_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We must first find the empirical formula.</p> <p>We can say that, in a <mathjax>#100"g"#</mathjax> sample, we have <mathjax>#2"g"#</mathjax> hydrogen, <mathjax>#"33g"#</mathjax> sulfur, and <mathjax>#65"g"#</mathjax> oxygen.</p> <p>Converting to <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">moles</a>:</p> <p><mathjax>#2"g H"*(1 "mol H")/(1 "g H")= 2 "mol H"#</mathjax></p> <p><mathjax>#33"g S"*(1 "mol S")/(32 "g S")=1.03"mol S" #</mathjax></p> <p><mathjax>#65 "g O"*(1 "mol O")/(16"g O")=4.06"mol O"#</mathjax></p> <p>We must divide each mole number by the smallest number, which, here, is <mathjax>#1.03#</mathjax>. Then round to the nearest whole number.</p> <p>For hydrogen: <mathjax>#2/1.03=1.94~~2#</mathjax><br/> For sulfur: <mathjax>#1.03/1.03=1#</mathjax><br/> For oxygen: <mathjax>#4.06/1.03=3.94~~4#</mathjax></p> <p>Putting them all together, we get:</p> <p><mathjax>#"H"_2"SO"_4#</mathjax>, sulfuric acid.</p> <p>We must check if the molar mass of sulfuric acid is <mathjax>#98"g"#</mathjax>:</p> <p><mathjax>#(1*2)+32+(16*4)=98#</mathjax></p> <p>So the molecular formula is also <mathjax>#"H"_2"SO"_4#</mathjax>, sulfuric acid.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/556181" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4817 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

Find the molecular formula of an acid with a molar mass of 98 grams per moles and the percentage composition of the elements in the acid is as such: hydrogen=2%, sulphur=33%, oxygen=65% ?

a875a94c-6ddd-11ea-b15f-ccda262736ce

https://socratic.org/questions/59a4324d7c014974b1114933

48 × 10^23

start physical_unit 2 3 number none qc_end physical_unit 10 11 6 7 quantity qc_end end

[{"type":"physical unit","value":"number [OF] oxygen atoms"}]

[{"type":"physical unit","value":"48 × 10^23"}]

[{"type":"physical unit","value":"quantity [OF] carbon dioxide [=] \\pu{8 mole}"}]

<h1 class="questionTitle" itemprop="name">How many oxygen atoms in an 8 mole quantity of carbon dioxide?</h1>

48 × 10^23

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Before we do this in detail, let us suppose that the question asked....<mathjax>#"find the number of atoms in 8 DOZEN molecules of"#</mathjax> <mathjax>#CO_2#</mathjax>.</p> <p>And thus, there are <mathjax>#3*"atoms"#</mathjax><mathjax>#*"molecule"^-1#</mathjax> <mathjax>#xx8xx12#</mathjax> <mathjax>#"molecules"#</mathjax></p> <p><mathjax>#=3xx8xx12=288*"atoms"#</mathjax></p> <p>The question asked here is ENTIRELY ANALOGOUS EXCEPT that instead of <mathjax>#"dozens"#</mathjax> we use <mathjax>#"moles"#</mathjax> where <mathjax>#1*"mole of stuff"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#6.022xx10^23*"individual items of stuff"#</mathjax>.</p> <p>And thus there are <mathjax>#8xx6.022xx10^23*"atoms"#</mathjax></p> <p><mathjax>#~=48xx10^23*"atoms"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#24*mol#</mathjax> of atoms in <mathjax>#8*mol#</mathjax> of <mathjax>#CO_2#</mathjax>....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Before we do this in detail, let us suppose that the question asked....<mathjax>#"find the number of atoms in 8 DOZEN molecules of"#</mathjax> <mathjax>#CO_2#</mathjax>.</p> <p>And thus, there are <mathjax>#3*"atoms"#</mathjax><mathjax>#*"molecule"^-1#</mathjax> <mathjax>#xx8xx12#</mathjax> <mathjax>#"molecules"#</mathjax></p> <p><mathjax>#=3xx8xx12=288*"atoms"#</mathjax></p> <p>The question asked here is ENTIRELY ANALOGOUS EXCEPT that instead of <mathjax>#"dozens"#</mathjax> we use <mathjax>#"moles"#</mathjax> where <mathjax>#1*"mole of stuff"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#6.022xx10^23*"individual items of stuff"#</mathjax>.</p> <p>And thus there are <mathjax>#8xx6.022xx10^23*"atoms"#</mathjax></p> <p><mathjax>#~=48xx10^23*"atoms"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many oxygen atoms in an 8 mole quantity of carbon dioxide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="469042" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-28T16:46:49" itemprop="dateCreated"> Aug 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#24*mol#</mathjax> of atoms in <mathjax>#8*mol#</mathjax> of <mathjax>#CO_2#</mathjax>....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Before we do this in detail, let us suppose that the question asked....<mathjax>#"find the number of atoms in 8 DOZEN molecules of"#</mathjax> <mathjax>#CO_2#</mathjax>.</p> <p>And thus, there are <mathjax>#3*"atoms"#</mathjax><mathjax>#*"molecule"^-1#</mathjax> <mathjax>#xx8xx12#</mathjax> <mathjax>#"molecules"#</mathjax></p> <p><mathjax>#=3xx8xx12=288*"atoms"#</mathjax></p> <p>The question asked here is ENTIRELY ANALOGOUS EXCEPT that instead of <mathjax>#"dozens"#</mathjax> we use <mathjax>#"moles"#</mathjax> where <mathjax>#1*"mole of stuff"#</mathjax> <mathjax>#-=#</mathjax> <mathjax>#6.022xx10^23*"individual items of stuff"#</mathjax>.</p> <p>And thus there are <mathjax>#8xx6.022xx10^23*"atoms"#</mathjax></p> <p><mathjax>#~=48xx10^23*"atoms"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/469042" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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How many oxygen atoms in an 8 mole quantity of carbon dioxide?

ab230f6f-6ddd-11ea-8949-ccda262736ce

https://socratic.org/questions/if-i-have-45-liters-of-helium-in-a-balloon-at-25-degress-celcius-and-increase-th

49.53 L

start physical_unit 6 6 volume l qc_end physical_unit 6 6 3 4 volume qc_end physical_unit 6 6 11 13 temperature qc_end physical_unit 6 6 19 21 temperature qc_end end

[{"type":"physical unit","value":"Volume2 [OF] helium [IN] L"}]

[{"type":"physical unit","value":"49.53 L"}]

[{"type":"physical unit","value":"Volume1 [OF] helium [=] \\pu{45 liters}"},{"type":"physical unit","value":"Temperature1 [OF] helium [=] \\pu{25 degress celcius}"},{"type":"physical unit","value":"Temperature2 [OF] helium [=] \\pu{55 degrees celcius}"}]

<h1 class="questionTitle" itemprop="name">If I have 45 liters of helium in a balloon at 25 degress celcius and increase the tempurate to 55 degrees celcius what will the new volume be? </h1>

49.53 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a problem involving the temperature-volume relationship of gases, which is represented by Charles's law: </p> <p><mathjax>#(V_1)/(T_1) = (V_2)/(T_2)#</mathjax></p> <p>Remember that <mathjax>#T#</mathjax> is the absolute temperature, so you must convert the temperature from Celcius to Kelvin:</p> <p><mathjax>#25 ^o C + 273 = 298K#</mathjax><br/> <mathjax>#55 ^o C + 273 = 328 K#</mathjax></p> <p>Now, rearrange the equation to solve for <mathjax>#V_2#</mathjax> (the new volume):</p> <p><mathjax>#V_2 = (V_1)(T_2)/(T_1)#</mathjax></p> <p>and plug in the known values:</p> <p><mathjax>#V_2 = 45 L(328 K)/(298 K) = 50.L#</mathjax></p> <p>(The decimal place is present to emphasize there are two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, otherwise it's arbitrary whether you're using one or two.)</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#50.L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a problem involving the temperature-volume relationship of gases, which is represented by Charles's law: </p> <p><mathjax>#(V_1)/(T_1) = (V_2)/(T_2)#</mathjax></p> <p>Remember that <mathjax>#T#</mathjax> is the absolute temperature, so you must convert the temperature from Celcius to Kelvin:</p> <p><mathjax>#25 ^o C + 273 = 298K#</mathjax><br/> <mathjax>#55 ^o C + 273 = 328 K#</mathjax></p> <p>Now, rearrange the equation to solve for <mathjax>#V_2#</mathjax> (the new volume):</p> <p><mathjax>#V_2 = (V_1)(T_2)/(T_1)#</mathjax></p> <p>and plug in the known values:</p> <p><mathjax>#V_2 = 45 L(328 K)/(298 K) = 50.L#</mathjax></p> <p>(The decimal place is present to emphasize there are two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, otherwise it's arbitrary whether you're using one or two.)</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If I have 45 liters of helium in a balloon at 25 degress celcius and increase the tempurate to 55 degrees celcius what will the new volume be? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="422847" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-13T20:58:34" itemprop="dateCreated"> May 13, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#50.L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is a problem involving the temperature-volume relationship of gases, which is represented by Charles's law: </p> <p><mathjax>#(V_1)/(T_1) = (V_2)/(T_2)#</mathjax></p> <p>Remember that <mathjax>#T#</mathjax> is the absolute temperature, so you must convert the temperature from Celcius to Kelvin:</p> <p><mathjax>#25 ^o C + 273 = 298K#</mathjax><br/> <mathjax>#55 ^o C + 273 = 328 K#</mathjax></p> <p>Now, rearrange the equation to solve for <mathjax>#V_2#</mathjax> (the new volume):</p> <p><mathjax>#V_2 = (V_1)(T_2)/(T_1)#</mathjax></p> <p>and plug in the known values:</p> <p><mathjax>#V_2 = 45 L(328 K)/(298 K) = 50.L#</mathjax></p> <p>(The decimal place is present to emphasize there are two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>, otherwise it's arbitrary whether you're using one or two.)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/422847" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? 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If I have 45 liters of helium in a balloon at 25 degress celcius and increase the tempurate to 55 degrees celcius what will the new volume be?

aca33a69-6ddd-11ea-85c1-ccda262736ce

https://socratic.org/questions/what-is-the-percentage-of-water-in-mn-2-co-3-3-8h-2o

55.63%

start physical_unit 5 7 percent none qc_end chemical_equation 7 7 qc_end end

[{"type":"physical unit","value":"Percentage [OF] water in MnCO3.8H2O"}]

[{"type":"physical unit","value":"55.63%"}]

[{"type":"chemical equation","value":"MnCO3.8H2O"}]

<h1 class="questionTitle" itemprop="name">What is the percentage of water in #"MnCO"_3 *8"H"_2"O"#?</h1>

55.63%

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with a <strong>hydrated compound</strong>, also known as a <em>hydrate</em>, called <em>manganese(II) carbonate octahydrate</em>, <mathjax>#"MnCO"_3 * 8"H"_2"O"#</mathjax>. </p> <p>This hydrate contains <em>manganese(II) carbonate</em>, <mathjax>#"MnCO"_3#</mathjax>, as the <strong>anhydrous salt</strong>. Each formula unit of the hydrate also contains <mathjax>#8#</mathjax> <strong>molecules</strong> of water of crystallization, hence the prefix <em><strong>octa</strong></em> added to the word <em>hydrate</em> in the name of the compound. </p> <p>Now, the idea here is that you can look at the chemical formula of the hydrate and say two things</p> <blockquote> <ul> <li><em><strong>one formula unit</strong> of the hydrate contains <strong>one formula unit</strong> of manganese(II) carbonate</em> </li> <li><em><strong>one formula unit</strong> of the hydrate contains <strong>eight molecules</strong> of water</em></li> </ul> </blockquote> <p>This implies that <strong>one mole</strong> of manganese(II) carbonate octahydrate will contain</p> <blockquote> <ul> <li><em><strong>one mole</strong> of anhydrous salt</em></li> <li><em><strong>eight moles</strong> of water</em></li> </ul> </blockquote> <p>Look up the <strong>molar mass</strong> of manganese(II) carbonate</p> <blockquote> <p><mathjax>#M_("M MnCO"_3) = "114.947 g mol"^(-1)#</mathjax></p> </blockquote> <p>This tells you that <strong>one mole</strong> of <em>anhydrous</em> manganese(II) carbonate has a mass of <mathjax>#"114.947 g"#</mathjax>. Water has a <strong>molar mass</strong> of</p> <blockquote> <p><mathjax>#M_("M H"_2"O") = "18.015 g mol"^(-1)#</mathjax></p> </blockquote> <p>so you know that <strong>one mole</strong> of water has amass of <mathjax>#"18.015 g"#</mathjax>. You can thus say that the <a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of water in the hydrate is </p> <blockquote> <p><mathjax>#"% H"_2"O" = (8 xx 18.015 color(red)(cancel(color(black)("g"))))/((114.947 + 8 xx 18.015)color(red)(cancel(color(black)("g")))) xx 100 = color(green)(|bar(ul(color(white)(a/a)color(black)(55.63%)color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>This tells you that <strong>for every</strong> <mathjax>#"100 g"#</mathjax> of manganese(II) carbonate octahydrate, you get <mathjax>#"55.63 g"#</mathjax> of water. </p> <p>Here is a similar lab with analysis conducted using copper (II) sulfate.</p> <p> <iframe src="https://www.youtube.com/embed/RPWkndwt2FA?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p> <p>Hope this helps!</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"55.63% H"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with a <strong>hydrated compound</strong>, also known as a <em>hydrate</em>, called <em>manganese(II) carbonate octahydrate</em>, <mathjax>#"MnCO"_3 * 8"H"_2"O"#</mathjax>. </p> <p>This hydrate contains <em>manganese(II) carbonate</em>, <mathjax>#"MnCO"_3#</mathjax>, as the <strong>anhydrous salt</strong>. Each formula unit of the hydrate also contains <mathjax>#8#</mathjax> <strong>molecules</strong> of water of crystallization, hence the prefix <em><strong>octa</strong></em> added to the word <em>hydrate</em> in the name of the compound. </p> <p>Now, the idea here is that you can look at the chemical formula of the hydrate and say two things</p> <blockquote> <ul> <li><em><strong>one formula unit</strong> of the hydrate contains <strong>one formula unit</strong> of manganese(II) carbonate</em> </li> <li><em><strong>one formula unit</strong> of the hydrate contains <strong>eight molecules</strong> of water</em></li> </ul> </blockquote> <p>This implies that <strong>one mole</strong> of manganese(II) carbonate octahydrate will contain</p> <blockquote> <ul> <li><em><strong>one mole</strong> of anhydrous salt</em></li> <li><em><strong>eight moles</strong> of water</em></li> </ul> </blockquote> <p>Look up the <strong>molar mass</strong> of manganese(II) carbonate</p> <blockquote> <p><mathjax>#M_("M MnCO"_3) = "114.947 g mol"^(-1)#</mathjax></p> </blockquote> <p>This tells you that <strong>one mole</strong> of <em>anhydrous</em> manganese(II) carbonate has a mass of <mathjax>#"114.947 g"#</mathjax>. Water has a <strong>molar mass</strong> of</p> <blockquote> <p><mathjax>#M_("M H"_2"O") = "18.015 g mol"^(-1)#</mathjax></p> </blockquote> <p>so you know that <strong>one mole</strong> of water has amass of <mathjax>#"18.015 g"#</mathjax>. You can thus say that the <a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of water in the hydrate is </p> <blockquote> <p><mathjax>#"% H"_2"O" = (8 xx 18.015 color(red)(cancel(color(black)("g"))))/((114.947 + 8 xx 18.015)color(red)(cancel(color(black)("g")))) xx 100 = color(green)(|bar(ul(color(white)(a/a)color(black)(55.63%)color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>This tells you that <strong>for every</strong> <mathjax>#"100 g"#</mathjax> of manganese(II) carbonate octahydrate, you get <mathjax>#"55.63 g"#</mathjax> of water. </p> <p>Here is a similar lab with analysis conducted using copper (II) sulfate.</p> <p> <iframe src="https://www.youtube.com/embed/RPWkndwt2FA?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p> <p>Hope this helps!</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the percentage of water in #"MnCO"_3 *8"H"_2"O"#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/percent-composition" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Composition</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="292767" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> <a class="secondContributorPic" href="/users/noel-p"><img alt="" class="" src="https://profilepictures.socratic.org/02ThC0uRMah0LVgFe9Tg_CrabbyMrP.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a>·<a class="topContributorLink" href="/users/noel-p"> mrpauller.weebly.com </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-28T02:19:41" itemprop="dateCreated"> Jul 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"55.63% H"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with a <strong>hydrated compound</strong>, also known as a <em>hydrate</em>, called <em>manganese(II) carbonate octahydrate</em>, <mathjax>#"MnCO"_3 * 8"H"_2"O"#</mathjax>. </p> <p>This hydrate contains <em>manganese(II) carbonate</em>, <mathjax>#"MnCO"_3#</mathjax>, as the <strong>anhydrous salt</strong>. Each formula unit of the hydrate also contains <mathjax>#8#</mathjax> <strong>molecules</strong> of water of crystallization, hence the prefix <em><strong>octa</strong></em> added to the word <em>hydrate</em> in the name of the compound. </p> <p>Now, the idea here is that you can look at the chemical formula of the hydrate and say two things</p> <blockquote> <ul> <li><em><strong>one formula unit</strong> of the hydrate contains <strong>one formula unit</strong> of manganese(II) carbonate</em> </li> <li><em><strong>one formula unit</strong> of the hydrate contains <strong>eight molecules</strong> of water</em></li> </ul> </blockquote> <p>This implies that <strong>one mole</strong> of manganese(II) carbonate octahydrate will contain</p> <blockquote> <ul> <li><em><strong>one mole</strong> of anhydrous salt</em></li> <li><em><strong>eight moles</strong> of water</em></li> </ul> </blockquote> <p>Look up the <strong>molar mass</strong> of manganese(II) carbonate</p> <blockquote> <p><mathjax>#M_("M MnCO"_3) = "114.947 g mol"^(-1)#</mathjax></p> </blockquote> <p>This tells you that <strong>one mole</strong> of <em>anhydrous</em> manganese(II) carbonate has a mass of <mathjax>#"114.947 g"#</mathjax>. Water has a <strong>molar mass</strong> of</p> <blockquote> <p><mathjax>#M_("M H"_2"O") = "18.015 g mol"^(-1)#</mathjax></p> </blockquote> <p>so you know that <strong>one mole</strong> of water has amass of <mathjax>#"18.015 g"#</mathjax>. You can thus say that the <a href="https://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of water in the hydrate is </p> <blockquote> <p><mathjax>#"% H"_2"O" = (8 xx 18.015 color(red)(cancel(color(black)("g"))))/((114.947 + 8 xx 18.015)color(red)(cancel(color(black)("g")))) xx 100 = color(green)(|bar(ul(color(white)(a/a)color(black)(55.63%)color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>This tells you that <strong>for every</strong> <mathjax>#"100 g"#</mathjax> of manganese(II) carbonate octahydrate, you get <mathjax>#"55.63 g"#</mathjax> of water. </p> <p>Here is a similar lab with analysis conducted using copper (II) sulfate.</p> <p> <iframe src="https://www.youtube.com/embed/RPWkndwt2FA?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p> <p>Hope this helps!</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/292767" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-mole-percent"> What is mole percent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188602bf3469570e2e8b"> Question #e2e8b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188702bf34695a6bc737"> Question #bc737 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418be02bf34695a6bc73b"> Question #bc73b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c202bf3469570e2e8f"> Question #e2e8f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c802bf346963eb9857"> Question #b9857 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418ca02bf346963eb985b"> Question #b985b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418cc02bf34694a4fee41"> Question #fee41 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418d502bf34694c8c5c01"> Question #c5c01 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4196e02bf34695a6bc73f"> Question #bc73f </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/percent-composition"> See all questions in Percent Composition </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2108 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the percentage of water in #"MnCO"_3 *8"H"_2"O"#?

a92f2239-6ddd-11ea-a350-ccda262736ce

https://socratic.org/questions/5856a8c1b72cff6a47c93077

2.47 kJ

start physical_unit 10 10 heat_energy kj qc_end physical_unit 10 10 7 8 volume qc_end end

[{"type":"physical unit","value":"Absorbed energy [OF] nitrogen [IN] kJ"}]

[{"type":"physical unit","value":"2.47 kJ"}]

[{"type":"physical unit","value":"Volume [OF] nitrogen [=] \\pu{6.03 L}"}]

<h1 class="questionTitle" itemprop="name">How much energy does the oxidation of 6.03 L of nitrogen absorb?</h1>

2.47 kJ

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>You don’t say what the oxidation product is, so I shall assume that it is dinitrogen tetroxide.</p> <p>Then the reaction is</p> <p><mathjax>#"N"_2 + "2O"_2 → "N"_2"O"_4; Δ_text(f)H = "9.16 kJ/mol"#</mathjax></p> <blockquote></blockquote> <p>The formula for the amount of heat <mathjax>#q#</mathjax> absorbed during the formation of <mathjax>#n#</mathjax> mol of a compound is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(barul|stackrel(" ")(q = nΔ_text(f)H)|)#</mathjax></p> </blockquote> </blockquote> <p>where <mathjax>#Δ_text(f)H#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of formation of the compound.</p> <blockquote></blockquote> <p><strong>Step 1. Calculate the number of moles of <mathjax>#"N"_2#</mathjax></strong></p> <p>We know that the volume of 1 mol of nitrogen at 1 atm and 273 K (the old definition of <strong>STP</strong>) is 22.4 L.</p> <p>∴ <mathjax>#"Moles of N"_2 = 6.03 color(red)(cancel(color(black)("L N"_2))) × "1 mol N"_2/(22.4 color(red)(cancel(color(black)("L N"_2)))) = "0.2692 mol N"_2#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Calculate the amount of heat absorbed</strong></p> <p><mathjax>#q = 0.2692 color(red)(cancel(color(black)("mol N"_2"O"_4))) × "9.16 kJ"/(1 color(red)(cancel(color(black)("mol N"_2"O"_4)))) = "2.47 kJ"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><blockquote></blockquote> <p>The reaction absorbs 2.47 kJ.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>You don’t say what the oxidation product is, so I shall assume that it is dinitrogen tetroxide.</p> <p>Then the reaction is</p> <p><mathjax>#"N"_2 + "2O"_2 → "N"_2"O"_4; Δ_text(f)H = "9.16 kJ/mol"#</mathjax></p> <blockquote></blockquote> <p>The formula for the amount of heat <mathjax>#q#</mathjax> absorbed during the formation of <mathjax>#n#</mathjax> mol of a compound is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(barul|stackrel(" ")(q = nΔ_text(f)H)|)#</mathjax></p> </blockquote> </blockquote> <p>where <mathjax>#Δ_text(f)H#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of formation of the compound.</p> <blockquote></blockquote> <p><strong>Step 1. Calculate the number of moles of <mathjax>#"N"_2#</mathjax></strong></p> <p>We know that the volume of 1 mol of nitrogen at 1 atm and 273 K (the old definition of <strong>STP</strong>) is 22.4 L.</p> <p>∴ <mathjax>#"Moles of N"_2 = 6.03 color(red)(cancel(color(black)("L N"_2))) × "1 mol N"_2/(22.4 color(red)(cancel(color(black)("L N"_2)))) = "0.2692 mol N"_2#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Calculate the amount of heat absorbed</strong></p> <p><mathjax>#q = 0.2692 color(red)(cancel(color(black)("mol N"_2"O"_4))) × "9.16 kJ"/(1 color(red)(cancel(color(black)("mol N"_2"O"_4)))) = "2.47 kJ"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How much energy does the oxidation of 6.03 L of nitrogen absorb?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/enthalpy" itemprop="url"> <span class="breadcrumb" itemprop="title">Enthalpy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="469111" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-28T20:17:15" itemprop="dateCreated"> Aug 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><blockquote></blockquote> <p>The reaction absorbs 2.47 kJ.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>You don’t say what the oxidation product is, so I shall assume that it is dinitrogen tetroxide.</p> <p>Then the reaction is</p> <p><mathjax>#"N"_2 + "2O"_2 → "N"_2"O"_4; Δ_text(f)H = "9.16 kJ/mol"#</mathjax></p> <blockquote></blockquote> <p>The formula for the amount of heat <mathjax>#q#</mathjax> absorbed during the formation of <mathjax>#n#</mathjax> mol of a compound is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(barul|stackrel(" ")(q = nΔ_text(f)H)|)#</mathjax></p> </blockquote> </blockquote> <p>where <mathjax>#Δ_text(f)H#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of formation of the compound.</p> <blockquote></blockquote> <p><strong>Step 1. Calculate the number of moles of <mathjax>#"N"_2#</mathjax></strong></p> <p>We know that the volume of 1 mol of nitrogen at 1 atm and 273 K (the old definition of <strong>STP</strong>) is 22.4 L.</p> <p>∴ <mathjax>#"Moles of N"_2 = 6.03 color(red)(cancel(color(black)("L N"_2))) × "1 mol N"_2/(22.4 color(red)(cancel(color(black)("L N"_2)))) = "0.2692 mol N"_2#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Calculate the amount of heat absorbed</strong></p> <p><mathjax>#q = 0.2692 color(red)(cancel(color(black)("mol N"_2"O"_4))) × "9.16 kJ"/(1 color(red)(cancel(color(black)("mol N"_2"O"_4)))) = "2.47 kJ"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/469111" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-enthalpy-changes-expressed-in-chemical-equations"> How are enthalpy changes expressed in chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-enthalpy-change-be-determined-for-an-aqueous-solution"> How can enthalpy change be determined for an aqueous solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-change-with-pressure"> How does enthalpy change with pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-standard-molar-enthalpy-formation"> How do you calculate standard molar enthalpy of formation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-enthalpy-of-formation-of-oxygen-zero"> Why is the enthalpy of formation of oxygen zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function-2"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-enthalpy-cannot-be-measured-directly"> Why can enthalpy not be measured directly? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-pressure-affect-enthalpy"> How does pressure affect enthalpy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-relate-to-internal-energy"> How does enthalpy relate to internal energy? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/enthalpy"> See all questions in Enthalpy </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1632 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How much energy does the oxidation of 6.03 L of nitrogen absorb?

a96e467a-6ddd-11ea-8513-ccda262736ce

https://socratic.org/questions/to-reduce-16-ounces-of-a-25-solution-of-antiseptic-to-a-10-solution-how-much-dis

24 ounces

start physical_unit 16 17 mass oz qc_end physical_unit 7 7 2 3 mass qc_end physical_unit 9 9 6 6 percent qc_end physical_unit 9 9 12 12 percent qc_end end

[{"type":"physical unit","value":"Added mass [OF] distilled water [IN] ounces"}]

[{"type":"physical unit","value":"24 ounces"}]

[{"type":"physical unit","value":"Mass1 [OF] antiseptic solution [=] \\pu{16 ounces}"},{"type":"physical unit","value":"Percent1 [OF] antiseptic in solution [=] \\pu{25%}"},{"type":"physical unit","value":"Percent2 [OF] antiseptic in solution [=] \\pu{10%}"}]

<h1 class="questionTitle" itemprop="name">To reduce 16 ounces of a 25% solution of antiseptic to a 10% solution, how much distilled water should a nurse add? </h1>

24 ounces

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here's a more intuitive approach to use here.</p> <p>You know that your initial solution has a <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a>, presumably <em>volume by volume</em>, of <mathjax>#25%#</mathjax>. This means that <strong>any volume</strong> of this solution contains <mathjax>#1#</mathjax> <strong>part</strong> <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> and <mathjax>#3#</mathjax> <strong>parts</strong> <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>. </p> <p>The target solution must have a concentration of <mathjax>#10%#</mathjax>, which means that <strong>any volume</strong> of this solution will contain <mathjax>#1#</mathjax> <strong>part</strong> of solute and <mathjax>#9#</mathjax> <strong>parts</strong> solvent. </p> <p>Your starting solution has a volume of <mathjax>#16#</mathjax> <strong>ounces</strong>, or <mathjax>#4#</mathjax> <strong>parts</strong>, each with a volume of <mathjax>#4#</mathjax> <strong>ounces</strong>. </p> <p>In order to get to a solution that has a total of <mathjax>#10#</mathjax> <strong>parts</strong>, you must add <mathjax>#6#</mathjax> <strong>parts</strong> of solvent to the initial solution. Since we know that</p> <blockquote> <p><mathjax>#"1 part " = " 4 ounces"#</mathjax></p> </blockquote> <p>it follows that you must add</p> <blockquote> <p><mathjax>#6color(red)(cancel(color(black)("parts"))) * "4 ounces"/(1color(red)(cancel(color(black)("part solvent")))) = "24 ounces"#</mathjax></p> </blockquote> <p>of distilled water, which is your solvent, to the initial solution. </p> <p>The target solution will contain <mathjax>#1#</mathjax> <strong>part</strong> solute and <mathjax>#9#</mathjax> <strong>parts</strong> distilled water for a total of <mathjax>#10#</mathjax> <strong>parts</strong> of solution, and hence have a percent concentration of <mathjax>#10%#</mathjax>. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"24 ounces"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here's a more intuitive approach to use here.</p> <p>You know that your initial solution has a <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a>, presumably <em>volume by volume</em>, of <mathjax>#25%#</mathjax>. This means that <strong>any volume</strong> of this solution contains <mathjax>#1#</mathjax> <strong>part</strong> <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> and <mathjax>#3#</mathjax> <strong>parts</strong> <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>. </p> <p>The target solution must have a concentration of <mathjax>#10%#</mathjax>, which means that <strong>any volume</strong> of this solution will contain <mathjax>#1#</mathjax> <strong>part</strong> of solute and <mathjax>#9#</mathjax> <strong>parts</strong> solvent. </p> <p>Your starting solution has a volume of <mathjax>#16#</mathjax> <strong>ounces</strong>, or <mathjax>#4#</mathjax> <strong>parts</strong>, each with a volume of <mathjax>#4#</mathjax> <strong>ounces</strong>. </p> <p>In order to get to a solution that has a total of <mathjax>#10#</mathjax> <strong>parts</strong>, you must add <mathjax>#6#</mathjax> <strong>parts</strong> of solvent to the initial solution. Since we know that</p> <blockquote> <p><mathjax>#"1 part " = " 4 ounces"#</mathjax></p> </blockquote> <p>it follows that you must add</p> <blockquote> <p><mathjax>#6color(red)(cancel(color(black)("parts"))) * "4 ounces"/(1color(red)(cancel(color(black)("part solvent")))) = "24 ounces"#</mathjax></p> </blockquote> <p>of distilled water, which is your solvent, to the initial solution. </p> <p>The target solution will contain <mathjax>#1#</mathjax> <strong>part</strong> solute and <mathjax>#9#</mathjax> <strong>parts</strong> distilled water for a total of <mathjax>#10#</mathjax> <strong>parts</strong> of solution, and hence have a percent concentration of <mathjax>#10%#</mathjax>. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">To reduce 16 ounces of a 25% solution of antiseptic to a 10% solution, how much distilled water should a nurse add? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="277694" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-15T15:01:01" itemprop="dateCreated"> Jun 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"24 ounces"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Here's a more intuitive approach to use here.</p> <p>You know that your initial solution has a <a href="https://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concentration</a>, presumably <em>volume by volume</em>, of <mathjax>#25%#</mathjax>. This means that <strong>any volume</strong> of this solution contains <mathjax>#1#</mathjax> <strong>part</strong> <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> and <mathjax>#3#</mathjax> <strong>parts</strong> <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>. </p> <p>The target solution must have a concentration of <mathjax>#10%#</mathjax>, which means that <strong>any volume</strong> of this solution will contain <mathjax>#1#</mathjax> <strong>part</strong> of solute and <mathjax>#9#</mathjax> <strong>parts</strong> solvent. </p> <p>Your starting solution has a volume of <mathjax>#16#</mathjax> <strong>ounces</strong>, or <mathjax>#4#</mathjax> <strong>parts</strong>, each with a volume of <mathjax>#4#</mathjax> <strong>ounces</strong>. </p> <p>In order to get to a solution that has a total of <mathjax>#10#</mathjax> <strong>parts</strong>, you must add <mathjax>#6#</mathjax> <strong>parts</strong> of solvent to the initial solution. Since we know that</p> <blockquote> <p><mathjax>#"1 part " = " 4 ounces"#</mathjax></p> </blockquote> <p>it follows that you must add</p> <blockquote> <p><mathjax>#6color(red)(cancel(color(black)("parts"))) * "4 ounces"/(1color(red)(cancel(color(black)("part solvent")))) = "24 ounces"#</mathjax></p> </blockquote> <p>of distilled water, which is your solvent, to the initial solution. </p> <p>The target solution will contain <mathjax>#1#</mathjax> <strong>part</strong> solute and <mathjax>#9#</mathjax> <strong>parts</strong> distilled water for a total of <mathjax>#10#</mathjax> <strong>parts</strong> of solution, and hence have a percent concentration of <mathjax>#10%#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/277694" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-a-solution-be-increased"> How can the concentration of a solution be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-concentration-of-a-solution-in-ppm"> How do you find the concentration of a solution in ppm? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-10-percent-solution"> How do you make a 10 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-2-percent-solution"> How do you make a 2 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-weight-per-volume-method-to-calculate-concentration"> What is the weight per volume method to calculate concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-percent-concentration-of-kcl-would-be-isotonic"> What percent concentration of KCl would be isotonic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-sodium-chloride-in-normal-saline"> What is the percent concentration of sodium chloride in normal saline? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-a-6m-solution-of-nacl"> What is the percent concentration of a 6m solution of NaCl? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-formula"> What is the percent concentration formula? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/percent-concentration"> See all questions in Percent Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7332 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

To reduce 16 ounces of a 25% solution of antiseptic to a 10% solution, how much distilled water should a nurse add?

ac17b45a-6ddd-11ea-ae82-ccda262736ce

https://socratic.org/questions/590f404b7c01491563104c53

C6H12O6

start chemical_formula qc_end physical_unit 7 7 21 22 molecular_weight qc_end end

[{"type":"other","value":"Chemical Formula [OF] the material [IN] molecular"}]

[{"type":"chemical equation","value":"C6H12O6"}]

[{"type":"physical unit","value":"Percentage composition [OF] C in the material [=] \\pu{40.5%}"},{"type":"physical unit","value":"Percentage composition [OF] H in the material [=] \\pu{6.67%}"},{"type":"physical unit","value":"Percentage composition [OF] O in the material [=] \\pu{53.33%}"},{"type":"physical unit","value":"Molecular mass [OF] the material [=] \\pu{180.0 g/mol}"}]

<h1 class="questionTitle" itemprop="name">What is the molecular formula of a material with percentage composition #C:40.5%#, #H:6.67%#, #O:53.33%#, and molecular mass of #180.0*g*mol^-1#?</h1>

C6H12O6

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So if there are <mathjax>#100*g#</mathjax> of unknown compound, we can access the empirical formula given the percentage composition:</p> <p><mathjax>#"Moles of carbon"=(40.0*g)/(12.011*g*mol^-1)=3.33*mol#</mathjax></p> <p><mathjax>#"Moles of hydrogen"=(6.67*g)/(1.00794*g*mol^-1)=6.62*mol#</mathjax></p> <p><mathjax>#"Moles of oxygen"=(53.33*g)/(16.00*g*mol^-1)=3.33*mol#</mathjax></p> <p>We divide thru by the LOWEST molar quantity, that of oxygen/carbon to give an empirical formula of:</p> <p><mathjax>#CH_2O#</mathjax>, which represents the simplest whole number ratio defining constituent atoms in a species, i.e. the <mathjax>#"empirical formula"#</mathjax>.</p> <p>But we also have the molecular mass, <mathjax>#180*g*mol^-1#</mathjax>.</p> <p>Now it is a fact that the molecular formula is always a whole number multiple of the empirical formula, and thus..............</p> <p><mathjax>#180*g*mol^-1=nxx(12.011+2xx1.00794+15.999)*g*mol^-1#</mathjax>,....................... and so we solve for <mathjax>#n#</mathjax>. Clearly, <mathjax>#n=6#</mathjax>, and the molecular formula is <mathjax>#C_6H_12O_6#</mathjax>. </p> <p>Just on a practical issue, an analyst would normally NEVER give you the percentage oxygen by mass. Most of the time you get <mathjax>#%C,H,N#</mathjax>, and if their sum is not <mathjax>#100%#</mathjax>, then the BALANCE is assumed to be due to <mathjax>#"oxygen"#</mathjax>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>This is a standard question, and as a routine we ASSUME a mass of <mathjax>#100*g#</mathjax> of unknown compound.......and get a molecular formula of <mathjax>#C_6H_12O_6#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So if there are <mathjax>#100*g#</mathjax> of unknown compound, we can access the empirical formula given the percentage composition:</p> <p><mathjax>#"Moles of carbon"=(40.0*g)/(12.011*g*mol^-1)=3.33*mol#</mathjax></p> <p><mathjax>#"Moles of hydrogen"=(6.67*g)/(1.00794*g*mol^-1)=6.62*mol#</mathjax></p> <p><mathjax>#"Moles of oxygen"=(53.33*g)/(16.00*g*mol^-1)=3.33*mol#</mathjax></p> <p>We divide thru by the LOWEST molar quantity, that of oxygen/carbon to give an empirical formula of:</p> <p><mathjax>#CH_2O#</mathjax>, which represents the simplest whole number ratio defining constituent atoms in a species, i.e. the <mathjax>#"empirical formula"#</mathjax>.</p> <p>But we also have the molecular mass, <mathjax>#180*g*mol^-1#</mathjax>.</p> <p>Now it is a fact that the molecular formula is always a whole number multiple of the empirical formula, and thus..............</p> <p><mathjax>#180*g*mol^-1=nxx(12.011+2xx1.00794+15.999)*g*mol^-1#</mathjax>,....................... and so we solve for <mathjax>#n#</mathjax>. Clearly, <mathjax>#n=6#</mathjax>, and the molecular formula is <mathjax>#C_6H_12O_6#</mathjax>. </p> <p>Just on a practical issue, an analyst would normally NEVER give you the percentage oxygen by mass. Most of the time you get <mathjax>#%C,H,N#</mathjax>, and if their sum is not <mathjax>#100%#</mathjax>, then the BALANCE is assumed to be due to <mathjax>#"oxygen"#</mathjax>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the molecular formula of a material with percentage composition #C:40.5%#, #H:6.67%#, #O:53.33%#, and molecular mass of #180.0*g*mol^-1#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="419210" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-07T15:57:20" itemprop="dateCreated"> May 7, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>This is a standard question, and as a routine we ASSUME a mass of <mathjax>#100*g#</mathjax> of unknown compound.......and get a molecular formula of <mathjax>#C_6H_12O_6#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So if there are <mathjax>#100*g#</mathjax> of unknown compound, we can access the empirical formula given the percentage composition:</p> <p><mathjax>#"Moles of carbon"=(40.0*g)/(12.011*g*mol^-1)=3.33*mol#</mathjax></p> <p><mathjax>#"Moles of hydrogen"=(6.67*g)/(1.00794*g*mol^-1)=6.62*mol#</mathjax></p> <p><mathjax>#"Moles of oxygen"=(53.33*g)/(16.00*g*mol^-1)=3.33*mol#</mathjax></p> <p>We divide thru by the LOWEST molar quantity, that of oxygen/carbon to give an empirical formula of:</p> <p><mathjax>#CH_2O#</mathjax>, which represents the simplest whole number ratio defining constituent atoms in a species, i.e. the <mathjax>#"empirical formula"#</mathjax>.</p> <p>But we also have the molecular mass, <mathjax>#180*g*mol^-1#</mathjax>.</p> <p>Now it is a fact that the molecular formula is always a whole number multiple of the empirical formula, and thus..............</p> <p><mathjax>#180*g*mol^-1=nxx(12.011+2xx1.00794+15.999)*g*mol^-1#</mathjax>,....................... and so we solve for <mathjax>#n#</mathjax>. Clearly, <mathjax>#n=6#</mathjax>, and the molecular formula is <mathjax>#C_6H_12O_6#</mathjax>. </p> <p>Just on a practical issue, an analyst would normally NEVER give you the percentage oxygen by mass. Most of the time you get <mathjax>#%C,H,N#</mathjax>, and if their sum is not <mathjax>#100%#</mathjax>, then the BALANCE is assumed to be due to <mathjax>#"oxygen"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/419210" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2094 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the molecular formula of a material with percentage composition #C:40.5%#, #H:6.67%#, #O:53.33%#, and molecular mass of #180.0*g*mol^-1#?

aabe432e-6ddd-11ea-ba2f-ccda262736ce

https://socratic.org/questions/what-is-the-molarity-of-a-500-0-ml-solution-containing-0-75-moles-of-solute

1.50 M

start physical_unit 8 8 molarity mol/l qc_end physical_unit 8 8 6 7 volume qc_end physical_unit 13 13 10 11 mole qc_end end

[{"type":"physical unit","value":"Molarity [OF] the solution [IN] M"}]

[{"type":"physical unit","value":"1.50 M"}]

[{"type":"physical unit","value":"Volume [OF] the solution [=] \\pu{500.0 mL}"},{"type":"physical unit","value":"Mole [OF] solute [=] \\pu{0.75 moles}"}]

<h1 class="questionTitle" itemprop="name">What is the molarity of a 500.0 mL solution containing 0.75 moles of solute? </h1>

1.50 M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> of a solution is the mumber of moles per litre. You have 0.75 moles in 500 ml. Therefore, you have 0.75 moles / 0.5 litre, which is 1.5 moles per liter, or 1.5 Molar.</p> <p>This blog post might help: <a href="http://maths4biosciences.com/blog/concentrations/molarity-formula/" rel="nofollow">Molarity and Moles</a> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1.5 M</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> of a solution is the mumber of moles per litre. You have 0.75 moles in 500 ml. Therefore, you have 0.75 moles / 0.5 litre, which is 1.5 moles per liter, or 1.5 Molar.</p> <p>This blog post might help: <a href="http://maths4biosciences.com/blog/concentrations/molarity-formula/" rel="nofollow">Molarity and Moles</a> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the molarity of a 500.0 mL solution containing 0.75 moles of solute? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="299941" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nick-41"><img alt="" class="" src="https://profilepictures.socratic.org/Sq1QmKQKSPCfDM110rRn_16.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nick-41"> Nick </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-17T18:17:33" itemprop="dateCreated"> Aug 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1.5 M</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> of a solution is the mumber of moles per litre. You have 0.75 moles in 500 ml. Therefore, you have 0.75 moles / 0.5 litre, which is 1.5 moles per liter, or 1.5 Molar.</p> <p>This blog post might help: <a href="http://maths4biosciences.com/blog/concentrations/molarity-formula/" rel="nofollow">Molarity and Moles</a> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/299941" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 8001 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the molarity of a 500.0 mL solution containing 0.75 moles of solute?

ace0fc68-6ddd-11ea-bb71-ccda262736ce

https://socratic.org/questions/a-mole-of-o-atoms-contains-how-many-atoms

6.02 × 10^23

start physical_unit 3 4 number none qc_end end

[{"type":"physical unit","value":"Number [OF] O atoms"}]

[{"type":"physical unit","value":"6.02 × 10^23"}]

[{"type":"physical unit","value":"Mole [OF] O atoms [=] \\pu{1 mole}"}]

<h1 class="questionTitle" itemprop="name">A mole of O atoms contains how many atoms?</h1>

6.02 × 10^23

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>One mole of any substance contains one Avogadro's Number of particles. Avogadro's Number = <mathjax>#6.02xx10^23#</mathjax> particle units</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#6.02xx10^23#</mathjax> Oxygen atoms</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>One mole of any substance contains one Avogadro's Number of particles. Avogadro's Number = <mathjax>#6.02xx10^23#</mathjax> particle units</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A mole of O atoms contains how many atoms?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="443692" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/doc048"><img alt="" class="" src="https://profilepictures.socratic.org/e4gaeUMMQESTpfte6aRu_Friendly%20Chem%20Professor.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/doc048"> Doc048 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-23T23:49:54" itemprop="dateCreated"> Jun 23, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#6.02xx10^23#</mathjax> Oxygen atoms</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>One mole of any substance contains one Avogadro's Number of particles. Avogadro's Number = <mathjax>#6.02xx10^23#</mathjax> particle units</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/443692" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6318 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A mole of O atoms contains how many atoms?

a9e1faad-6ddd-11ea-9151-ccda262736ce

https://socratic.org/questions/how-many-grams-in-113-5-moles-of-lino-3

7830 grams

start physical_unit 7 7 mass g qc_end physical_unit 7 7 4 5 mole qc_end end

[{"type":"physical unit","value":"Mass [OF] LiNO3 [IN] grams"}]

[{"type":"physical unit","value":"7830 grams"}]

[{"type":"physical unit","value":"Mole [OF] LiNO3 [=] \\pu{113.5 moles}"}]

<h1 class="questionTitle" itemprop="name">How many grams in 113.5 moles of #LiNO_3#?</h1>

7830 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Determine the mass of one mole of <mathjax>#"LiNO"_3"#</mathjax>. This is its molar mass. The molar mass of <mathjax>#"LiNO"_3"#</mathjax> is <mathjax>#"68.944 g/mol"#</mathjax>.<br/> <a href="https://pubchem.ncbi.nlm.nih.gov/compound/10129889" rel="nofollow" target="_blank">https://pubchem.ncbi.nlm.nih.gov/compound/10129889</a></p> <p>Multiply the molar mass by the number of moles.</p> <p><mathjax>#113.5cancel"mol" "LiNO"_3xx(68.944 "g")/(1cancel"mol")="7830 g LiNO"_3"#</mathjax> rounded to four significant figures)</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"113.5 mol LiNO"_3"#</mathjax> has a mass of <mathjax>#"7830 g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Determine the mass of one mole of <mathjax>#"LiNO"_3"#</mathjax>. This is its molar mass. The molar mass of <mathjax>#"LiNO"_3"#</mathjax> is <mathjax>#"68.944 g/mol"#</mathjax>.<br/> <a href="https://pubchem.ncbi.nlm.nih.gov/compound/10129889" rel="nofollow" target="_blank">https://pubchem.ncbi.nlm.nih.gov/compound/10129889</a></p> <p>Multiply the molar mass by the number of moles.</p> <p><mathjax>#113.5cancel"mol" "LiNO"_3xx(68.944 "g")/(1cancel"mol")="7830 g LiNO"_3"#</mathjax> rounded to four significant figures)</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many grams in 113.5 moles of #LiNO_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="391517" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-15T05:38:02" itemprop="dateCreated"> Mar 15, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"113.5 mol LiNO"_3"#</mathjax> has a mass of <mathjax>#"7830 g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Determine the mass of one mole of <mathjax>#"LiNO"_3"#</mathjax>. This is its molar mass. The molar mass of <mathjax>#"LiNO"_3"#</mathjax> is <mathjax>#"68.944 g/mol"#</mathjax>.<br/> <a href="https://pubchem.ncbi.nlm.nih.gov/compound/10129889" rel="nofollow" target="_blank">https://pubchem.ncbi.nlm.nih.gov/compound/10129889</a></p> <p>Multiply the molar mass by the number of moles.</p> <p><mathjax>#113.5cancel"mol" "LiNO"_3xx(68.944 "g")/(1cancel"mol")="7830 g LiNO"_3"#</mathjax> rounded to four significant figures)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/391517" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1017 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many grams in 113.5 moles of #LiNO_3#?

a9664dca-6ddd-11ea-ac17-ccda262736ce

https://socratic.org/questions/an-naoh-solution-contains-1-90-mol-of-naoh-and-its-concentration-is-0-555-m-what

3.42 L

start physical_unit 1 2 volume l qc_end physical_unit 1 1 4 5 mole qc_end physical_unit 1 2 12 13 concentration qc_end end

[{"type":"physical unit","value":"Volume [OF] NaOH solution [IN] L"}]

[{"type":"physical unit","value":"3.42 L"}]

[{"type":"physical unit","value":"Mole [OF] NaOH [=] \\pu{1.90 mol}"},{"type":"physical unit","value":"Concentration [OF] NaOH solution [=] \\pu{0.555 M}"}]

<h1 class="questionTitle" itemprop="name">An #NaOH# solution contains 1.90 mol of #NaOH#, and its concentration is 0.555 M. What is its volume?</h1>

3.42 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First rewrite the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of NaOH, <mathjax>#"0.555 M"#</mathjax>, as <mathjax>#"0.555 mol/L"#</mathjax>.</p> <p>Next divide the given moles NaOH by the molarity of the solution in mol/L.</p> <p><mathjax>#cancel"1.90mol NaOH"xx("1L NaOH")/(cancel"0.555 mol NaOH")="3.42 L"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume is <mathjax>#"3.42 L"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First rewrite the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of NaOH, <mathjax>#"0.555 M"#</mathjax>, as <mathjax>#"0.555 mol/L"#</mathjax>.</p> <p>Next divide the given moles NaOH by the molarity of the solution in mol/L.</p> <p><mathjax>#cancel"1.90mol NaOH"xx("1L NaOH")/(cancel"0.555 mol NaOH")="3.42 L"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">An #NaOH# solution contains 1.90 mol of #NaOH#, and its concentration is 0.555 M. What is its volume?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="217156" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-26T08:19:46" itemprop="dateCreated"> Jan 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume is <mathjax>#"3.42 L"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First rewrite the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> of NaOH, <mathjax>#"0.555 M"#</mathjax>, as <mathjax>#"0.555 mol/L"#</mathjax>.</p> <p>Next divide the given moles NaOH by the molarity of the solution in mol/L.</p> <p><mathjax>#cancel"1.90mol NaOH"xx("1L NaOH")/(cancel"0.555 mol NaOH")="3.42 L"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/217156" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -&gt; 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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An #NaOH# solution contains 1.90 mol of #NaOH#, and its concentration is 0.555 M. What is its volume?

a8f641cd-6ddd-11ea-967e-ccda262736ce

https://socratic.org/questions/595e6a0511ef6b6157c52c27

85 g

start physical_unit 12 12 mass g qc_end physical_unit 5 5 1 2 mass qc_end physical_unit 18 18 16 16 w/w qc_end substance 12 12 qc_end end

[{"type":"physical unit","value":"Mass [OF] water [IN] g"}]

[{"type":"physical unit","value":"85 g"}]

[{"type":"physical unit","value":"Mass [OF] solute [=] \\pu{15 g}"},{"type":"physical unit","value":"w/w [OF] solution [=] \\pu{15%}"},{"type":"substance name","value":"Water"}]

<h1 class="questionTitle" itemprop="name">A #15*g# mass of solute was dissolved in a mass of water to give a #15%# #"w/w"# solution. What was the mass of water used to make the solution? </h1>

85 g

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#%"solution"="Mass of solute"/"Mass of solvent and solute"xx100%#</mathjax></p> <p><mathjax>#=(15*g)/(15.0*g+85.0*g)xx100%=15%w/w#</mathjax></p> <p>Here we define <mathjax>#w/w%#</mathjax>......There are other definitions, <mathjax>#"weight"/"volume"#</mathjax>, but given the context here it is <mathjax>#w/wxx100%#</mathjax>.......</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Why.........<mathjax>#85*g#</mathjax> of water.........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#%"solution"="Mass of solute"/"Mass of solvent and solute"xx100%#</mathjax></p> <p><mathjax>#=(15*g)/(15.0*g+85.0*g)xx100%=15%w/w#</mathjax></p> <p>Here we define <mathjax>#w/w%#</mathjax>......There are other definitions, <mathjax>#"weight"/"volume"#</mathjax>, but given the context here it is <mathjax>#w/wxx100%#</mathjax>.......</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A #15*g# mass of solute was dissolved in a mass of water to give a #15%# #"w/w"# solution. What was the mass of water used to make the solution? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="448712" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-06T17:26:03" itemprop="dateCreated"> Jul 6, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Why.........<mathjax>#85*g#</mathjax> of water.........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#%"solution"="Mass of solute"/"Mass of solvent and solute"xx100%#</mathjax></p> <p><mathjax>#=(15*g)/(15.0*g+85.0*g)xx100%=15%w/w#</mathjax></p> <p>Here we define <mathjax>#w/w%#</mathjax>......There are other definitions, <mathjax>#"weight"/"volume"#</mathjax>, but given the context here it is <mathjax>#w/wxx100%#</mathjax>.......</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/448712" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? 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A #15*g# mass of solute was dissolved in a mass of water to give a #15%# #"w/w"# solution. What was the mass of water used to make the solution?

ac5f0d6e-6ddd-11ea-b32e-ccda262736ce

https://socratic.org/questions/what-is-the-ph-of-a-043-m-hcl-solution

1.37

start physical_unit 8 9 ph none qc_end physical_unit 8 9 6 7 molarity qc_end end

[{"type":"physical unit","value":"pH [OF] HCl solution"}]

[{"type":"physical unit","value":"1.37"}]

[{"type":"physical unit","value":"Molarity [OF] HCl solution [=] \\pu{0.043 M}"}]

<h1 class="questionTitle" itemprop="name">What is the pH of a .043 M #HCl# solution?</h1>

1.37

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> = <mathjax>#-lg(0.043)#</mathjax> = 1.34</p> <p>pH is 1.34.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#-lg(H_(Cation))#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> = <mathjax>#-lg(0.043)#</mathjax> = 1.34</p> <p>pH is 1.34.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the pH of a .043 M #HCl# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">3</span> Answers </h5> <div class="answers"> <div class="answer" id="599108" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/udhaya-s"><img alt="" class="" src="https://graph.facebook.com/1599962916686505/picture?height=50&amp;width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/udhaya-s"> Udhaya S. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-04-21T10:49:03" itemprop="dateCreated"> Apr 21, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#-lg(H_(Cation))#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> = <mathjax>#-lg(0.043)#</mathjax> = 1.34</p> <p>pH is 1.34.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/599108" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="599119" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nam-d"><img alt="" class="" src="https://profilepictures.socratic.org/QG4MnkoER6u99DIDVWKK_787554714770341.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nam-d"> Nam D. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-04-21T11:22:17" itemprop="dateCreated"> Apr 21, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Approximately <mathjax>#1.37#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <mathjax>#"pH"#</mathjax> of a solution is given by:</p> <p><mathjax>#"pH"=-log[H^+]#</mathjax></p> <blockquote> <ul> <li><mathjax>#[H^+]#</mathjax> is the hydrogen ion concentration in terms of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></li> </ul> </blockquote> <p>The dissociation of <mathjax>#HCl#</mathjax> is:</p> <p><mathjax>#HCl(aq)-&gt;H^+(aq)+Cl^(-)(aq)#</mathjax></p> <p>So, one mole of hydrochloric acid contains one mole of hydrogen ions. So here, there are <mathjax>#0.43 \ "mol/L"#</mathjax> of hydrogen ions.</p> <p>Therefore, its <mathjax>#"pH"#</mathjax> will be:</p> <p><mathjax>#"pH"=-log[0.043]#</mathjax></p> <p><mathjax>#~~1.37#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/599119" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="599140" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-04-21T12:24:03" itemprop="dateCreated"> Apr 21, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, I make it <mathjax>#1.37#</mathjax>...bowling another googly...</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>By definition, <mathjax>#pH=-log_10[H_3O^+]#</mathjax>...i.e. <mathjax>#"pouvoir hydrogène"#</mathjax> for <mathjax>#[HCl]#</mathjax> of <mathjax>#0.043*mol*L^-1#</mathjax> concentration...is given by....</p> <p><mathjax>#pH-=-log_10([HCl])=-log_10(0.043)=-(-1.366)=1.37#</mathjax>...</p> <p>And we assume here, quite reasonably, that the strong acid <mathjax>#HCl#</mathjax> undergoes complete protonolysis in the water <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a> according to the reaction....</p> <p><mathjax>#HCl(aq) + H_2O(l) rarr underbrace(H_3O^+)_"molar concentration of 0.043 mol/L" + Cl^-#</mathjax> </p> <p>And so we take the logarithm of the initial <mathjax>#[HCl]#</mathjax> concentration DIRECTLY....</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/599140" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-resonance-structures-affect-acidity"> How do resonance structures affect acidity? 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What is the pH of a .043 M #HCl# solution?

a9b4864b-6ddd-11ea-80f4-ccda262736ce

https://socratic.org/questions/how-many-carbon-atoms-are-represented-by-c-2h-5-2nch-3

5

start physical_unit 2 3 number none qc_end chemical_equation 7 7 qc_end end

[{"type":"physical unit","value":"Number [OF] carbon atoms"}]

[{"type":"physical unit","value":"5"}]

[{"type":"chemical equation","value":"(C2H5)2NCH3"}]

<h1 class="questionTitle" itemprop="name">How many carbon atoms are represented by #(C_2H_5)_2NCH_3#?</h1>

5

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Looking at the formula, clearly there are <mathjax>#"5 carbon atoms"#</mathjax>, <mathjax>#"1 nitrogen atom"#</mathjax>, and <mathjax>#"13 hydrogen atoms"#</mathjax>. All I did was expand the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> inside the brackets. In this amine, nitrogen is bound to <mathjax>#"1 methyl group"#</mathjax> and <mathjax>#"2 ethyl groups"#</mathjax>. If you are having trouble seeing this, reply to this thread, and we'll have another go. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#"5 carbon atoms"#</mathjax> in <mathjax>#"diethylmethylamine"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Looking at the formula, clearly there are <mathjax>#"5 carbon atoms"#</mathjax>, <mathjax>#"1 nitrogen atom"#</mathjax>, and <mathjax>#"13 hydrogen atoms"#</mathjax>. All I did was expand the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> inside the brackets. In this amine, nitrogen is bound to <mathjax>#"1 methyl group"#</mathjax> and <mathjax>#"2 ethyl groups"#</mathjax>. If you are having trouble seeing this, reply to this thread, and we'll have another go. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many carbon atoms are represented by #(C_2H_5)_2NCH_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/determining-formula-and-molar-masses" itemprop="url"> <span class="breadcrumb" itemprop="title">Determining Formula</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="283598" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-01T16:47:27" itemprop="dateCreated"> Jul 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#"5 carbon atoms"#</mathjax> in <mathjax>#"diethylmethylamine"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Looking at the formula, clearly there are <mathjax>#"5 carbon atoms"#</mathjax>, <mathjax>#"1 nitrogen atom"#</mathjax>, and <mathjax>#"13 hydrogen atoms"#</mathjax>. All I did was expand the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> inside the brackets. In this amine, nitrogen is bound to <mathjax>#"1 methyl group"#</mathjax> and <mathjax>#"2 ethyl groups"#</mathjax>. If you are having trouble seeing this, reply to this thread, and we'll have another go. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/283598" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-possible-to-find-a-molecular-formula-from-molar-mass"> Is it possible to find a molecular formula from molar mass? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5368e0cc02bf34779e175781"> Question #75781 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-when-determining-formulas"> What are some common mistakes students make when determining formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-an-acid"> How can I determine the formula of an acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-chemical-formula-of-a-product"> How can I determine the chemical formula of a product? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-empirical-formula-of-a-compound"> How can I determine the empirical formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-a-hydrate"> How can I determine the formula of a hydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-empirical-formula-indicate"> What does the empirical formula indicate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-molecule-with-molecular-weight-of-180-18-g-mol-is-analyzed-and-found-to-contai"> A molecule with molecular weight of 180.18 g/mol is analyzed and found to contain 40.00% carbon,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-i-need-to-know-the-number-of-moles-of-each-element-to-determine-the-formula-o"> Do I need to know the number of moles of each element to determine the formula of the compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/determining-formula-and-molar-masses"> See all questions in Determining Formula </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3885 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many carbon atoms are represented by #(C_2H_5)_2NCH_3#?

a91c20ac-6ddd-11ea-805e-ccda262736ce

https://socratic.org/questions/what-is-the-oh-for-a-solution-at-25-c-that-has-a-h-3o-of-5-36-times-10-5

1.87 × 10^(-10) M

start physical_unit 5 6 [oh-] mol/l qc_end physical_unit 5 6 15 18 [h3o+] qc_end physical_unit 5 6 8 9 temperature qc_end end

[{"type":"physical unit","value":"[OH−] [OF] a solution [IN] M"}]

[{"type":"physical unit","value":"1.87 × 10^(-10) M"}]

[{"type":"physical unit","value":"[H3O+] [OF] a solution [=] \\pu{5.36 × 10^(-5) M}"},{"type":"physical unit","value":"Temperature [OF] a solution [=] \\pu{25 ℃}"}]

<h1 class="questionTitle" itemprop="name">What is the #[OH^-]# for a solution at 25°C that has a #[H_3O^+]# of #5.36 times 10^-5#?</h1>

1.87 × 10^(-10) M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given.......</p> <p><mathjax>#2H_2O(l) rightleftharpoonsH_3O^+ + HO^-#</mathjax></p> <p><mathjax>#K_w'=([H_3O^+][HO^-])/([H_2O(l)])#</mathjax></p> <p>Because <mathjax>#[H_2O]#</mathjax> is so large, we remove it from the expression to give,,,,,,</p> <p><mathjax>#K_w=[H_3O^+][HO^-]=10^-14#</mathjax> under standard conditions of temperature <mathjax>#(298*K)#</mathjax> and pressure <mathjax>#(1*atm)#</mathjax>...</p> <p>Thus <mathjax>#[HO^-]=10^-14/(5.36xx10^-5)=1.87xx10^-10*mol*L^-1#</mathjax>.</p> <p>Alternatively, we could take <mathjax>#log_10#</mathjax> of both sides of <mathjax>#K_w=[H_3O^+][HO^-]=10^-14#</mathjax> to give.........</p> <p><mathjax>#log_10K_w=log_10[H_3O^+]+log_10[HO^-]#</mathjax></p> <p>On rearrangement</p> <p><mathjax>#underbrace(-log_10[H_3O^+])_color(red)(pH)underbrace(-log_10[HO^-])_color(blue)(pOH)=underbrace(-log_10K_w)_(pK_w)#</mathjax></p> <p>And thus <mathjax>#color(red)(pH)+color(blue)(pOH)=pK_w=14#</mathjax>.</p> <p>And here, <mathjax>#pH=-log_10(5.36xx10^-5)=4.27#</mathjax>, and clearly, <mathjax>#pOH=9.73#</mathjax>.</p> <p><mathjax>#[HO^-]=10^(-9.73)=1.87xx10^-10*mol*L^-1#</mathjax>, as required.......</p> <p>I don't know about you, but I think the <mathjax>#log#</mathjax> method is better.....</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[HO^-]=1.87xx10^-10*mol*L^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given.......</p> <p><mathjax>#2H_2O(l) rightleftharpoonsH_3O^+ + HO^-#</mathjax></p> <p><mathjax>#K_w'=([H_3O^+][HO^-])/([H_2O(l)])#</mathjax></p> <p>Because <mathjax>#[H_2O]#</mathjax> is so large, we remove it from the expression to give,,,,,,</p> <p><mathjax>#K_w=[H_3O^+][HO^-]=10^-14#</mathjax> under standard conditions of temperature <mathjax>#(298*K)#</mathjax> and pressure <mathjax>#(1*atm)#</mathjax>...</p> <p>Thus <mathjax>#[HO^-]=10^-14/(5.36xx10^-5)=1.87xx10^-10*mol*L^-1#</mathjax>.</p> <p>Alternatively, we could take <mathjax>#log_10#</mathjax> of both sides of <mathjax>#K_w=[H_3O^+][HO^-]=10^-14#</mathjax> to give.........</p> <p><mathjax>#log_10K_w=log_10[H_3O^+]+log_10[HO^-]#</mathjax></p> <p>On rearrangement</p> <p><mathjax>#underbrace(-log_10[H_3O^+])_color(red)(pH)underbrace(-log_10[HO^-])_color(blue)(pOH)=underbrace(-log_10K_w)_(pK_w)#</mathjax></p> <p>And thus <mathjax>#color(red)(pH)+color(blue)(pOH)=pK_w=14#</mathjax>.</p> <p>And here, <mathjax>#pH=-log_10(5.36xx10^-5)=4.27#</mathjax>, and clearly, <mathjax>#pOH=9.73#</mathjax>.</p> <p><mathjax>#[HO^-]=10^(-9.73)=1.87xx10^-10*mol*L^-1#</mathjax>, as required.......</p> <p>I don't know about you, but I think the <mathjax>#log#</mathjax> method is better.....</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the #[OH^-]# for a solution at 25°C that has a #[H_3O^+]# of #5.36 times 10^-5#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/measuring-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Measuring Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="442983" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-22T04:26:03" itemprop="dateCreated"> Jun 22, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[HO^-]=1.87xx10^-10*mol*L^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given.......</p> <p><mathjax>#2H_2O(l) rightleftharpoonsH_3O^+ + HO^-#</mathjax></p> <p><mathjax>#K_w'=([H_3O^+][HO^-])/([H_2O(l)])#</mathjax></p> <p>Because <mathjax>#[H_2O]#</mathjax> is so large, we remove it from the expression to give,,,,,,</p> <p><mathjax>#K_w=[H_3O^+][HO^-]=10^-14#</mathjax> under standard conditions of temperature <mathjax>#(298*K)#</mathjax> and pressure <mathjax>#(1*atm)#</mathjax>...</p> <p>Thus <mathjax>#[HO^-]=10^-14/(5.36xx10^-5)=1.87xx10^-10*mol*L^-1#</mathjax>.</p> <p>Alternatively, we could take <mathjax>#log_10#</mathjax> of both sides of <mathjax>#K_w=[H_3O^+][HO^-]=10^-14#</mathjax> to give.........</p> <p><mathjax>#log_10K_w=log_10[H_3O^+]+log_10[HO^-]#</mathjax></p> <p>On rearrangement</p> <p><mathjax>#underbrace(-log_10[H_3O^+])_color(red)(pH)underbrace(-log_10[HO^-])_color(blue)(pOH)=underbrace(-log_10K_w)_(pK_w)#</mathjax></p> <p>And thus <mathjax>#color(red)(pH)+color(blue)(pOH)=pK_w=14#</mathjax>.</p> <p>And here, <mathjax>#pH=-log_10(5.36xx10^-5)=4.27#</mathjax>, and clearly, <mathjax>#pOH=9.73#</mathjax>.</p> <p><mathjax>#[HO^-]=10^(-9.73)=1.87xx10^-10*mol*L^-1#</mathjax>, as required.......</p> <p>I don't know about you, but I think the <mathjax>#log#</mathjax> method is better.....</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/442983" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-concentration-from-absorbance"> How do you measure concentration from absorbance? 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What is the #[OH^-]# for a solution at 25°C that has a #[H_3O^+]# of #5.36 times 10^-5#?

aa8ba6f8-6ddd-11ea-9824-ccda262736ce

https://socratic.org/questions/what-is-the-molarity-of-a-solution-of-ammonium-chloride-prepared-by-diluting-50-

0.09 M

start physical_unit 19 20 molarity mol/l qc_end physical_unit 19 20 17 18 molarity qc_end physical_unit 19 20 13 14 volume qc_end physical_unit 19 20 22 23 volume qc_end end

[{"type":"physical unit","value":"Molarity2 [OF] NH4Cl solution [IN] M"}]

[{"type":"physical unit","value":"0.09 M"}]

[{"type":"physical unit","value":"Molarity1 [OF] NH4Cl solution [=] \\pu{3.79 M}"},{"type":"physical unit","value":"Volume1 [OF] NH4Cl solution [=] \\pu{50.00 mL}"},{"type":"physical unit","value":"Volume2 [OF] NH4Cl solution [=] \\pu{2.00 L}"}]

<h1 class="questionTitle" itemprop="name">What is the molarity of a solution of ammonium chloride prepared by diluting 50.00 mL of a 3.79 M #NH_4Cl# solution to 2.00 L?</h1>

0.09 M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>How many moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> did you start with?</p> <p>Use <mathjax>#M = n/V#</mathjax></p> <p>Where M is <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> in moles/litre, n is number of moles, and V is number of litres.</p> <p>Rearrange for n: <mathjax>#n = M.V#</mathjax> = 3.79 x 0.05 = 0.1895 moles.</p> <p>After diluting, how many moles of solute will you have? Answer: The same. But now the solution volume will be 2 litres.</p> <p>Therefore: <mathjax>#M = n/V#</mathjax> = 0.1895 / 2 = 0.09475 mol/litre.</p> <p>And if you want to make it even simpler - you are diluting 50 ml to 2000 ml, which is a dilution of 40 times.</p> <p>So simply divide your starting molarity by 40. 3.79 divided by 40 is 0.09475.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.09475 moles per litre.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>How many moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> did you start with?</p> <p>Use <mathjax>#M = n/V#</mathjax></p> <p>Where M is <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> in moles/litre, n is number of moles, and V is number of litres.</p> <p>Rearrange for n: <mathjax>#n = M.V#</mathjax> = 3.79 x 0.05 = 0.1895 moles.</p> <p>After diluting, how many moles of solute will you have? Answer: The same. But now the solution volume will be 2 litres.</p> <p>Therefore: <mathjax>#M = n/V#</mathjax> = 0.1895 / 2 = 0.09475 mol/litre.</p> <p>And if you want to make it even simpler - you are diluting 50 ml to 2000 ml, which is a dilution of 40 times.</p> <p>So simply divide your starting molarity by 40. 3.79 divided by 40 is 0.09475.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the molarity of a solution of ammonium chloride prepared by diluting 50.00 mL of a 3.79 M #NH_4Cl# solution to 2.00 L?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="292930" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/simon-moore"><img alt="" class="" src="https://profilepictures.socratic.org/0ztdJJ7RCWUlBSPeGa9N_6EB6CADA-35F5-4BAA-9B66-9D6F64A622BA.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/simon-moore"> Simon Moore </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-28T14:22:54" itemprop="dateCreated"> Jul 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.09475 moles per litre.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>How many moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> did you start with?</p> <p>Use <mathjax>#M = n/V#</mathjax></p> <p>Where M is <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> in moles/litre, n is number of moles, and V is number of litres.</p> <p>Rearrange for n: <mathjax>#n = M.V#</mathjax> = 3.79 x 0.05 = 0.1895 moles.</p> <p>After diluting, how many moles of solute will you have? Answer: The same. But now the solution volume will be 2 litres.</p> <p>Therefore: <mathjax>#M = n/V#</mathjax> = 0.1895 / 2 = 0.09475 mol/litre.</p> <p>And if you want to make it even simpler - you are diluting 50 ml to 2000 ml, which is a dilution of 40 times.</p> <p>So simply divide your starting molarity by 40. 3.79 divided by 40 is 0.09475.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/292930" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 12762 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the molarity of a solution of ammonium chloride prepared by diluting 50.00 mL of a 3.79 M #NH_4Cl# solution to 2.00 L?

a8d86d40-6ddd-11ea-9a24-ccda262736ce

https://socratic.org/questions/599907b87c014904aab5606f

2

start physical_unit 6 6 ph none qc_end physical_unit 13 13 8 9 volume qc_end physical_unit 13 13 15 16 molarity qc_end physical_unit 18 18 8 9 volume qc_end physical_unit 18 18 20 21 molarity qc_end end

[{"type":"physical unit","value":"pH [OF] solution"}]

[{"type":"physical unit","value":"2"}]

[{"type":"physical unit","value":"Volume [OF] HCl(aq) [=] \\pu{100 mL}"},{"type":"physical unit","value":"Molarity [OF] HCl(aq) [=] \\pu{0.20 mol/L}"},{"type":"physical unit","value":"Volume [OF] NaOH(aq) [=] \\pu{100 mL}"},{"type":"physical unit","value":"Molarity [OF] NaOH(aq) [=] \\pu{0.18 mol/L}"}]

<h1 class="questionTitle" itemprop="name">What is the #pH# of a solution comprising #100*mL# volumes EACH of #HCl(aq)# at #0.20*mol*L^-1# and #NaOH(aq)# at #0.18*mol*L^-1#?</h1>

2

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the chemical reaction....</p> <p><mathjax>#HCl(aq) + NaOH(aq) rarr NaCl(aq) + H_2O(l)#</mathjax>.</p> <p><mathjax>#"Moles of HCl(aq)"=100xx10^-3*Lxx0.2*mol*L^-1=2.0xx10^-2*mol#</mathjax>.</p> <p><mathjax>#"Moles of NaOH(aq)"=100xx10^-3*Lxx0.18*mol*L^-1=1.8xx10^-2*mol#</mathjax>.</p> <p>There is thus an excess of hydronium ions, to the tune of <mathjax>#2.0xx10^-2*mol-1.8xx10^-2*mol=2.0xx10^-3*mol#</mathjax></p> <p>But this is dissolved in a solution whose volume is now <mathjax>#200xx10^-3*L#</mathjax></p> <p>And so <mathjax>#[HCl]=(2.0xx10^-3*mol)/(200xx10^-3*L)=0.01*mol*L^-1#</mathjax></p> <p>But <mathjax>#pH-=-log_10{[H_3O^+]}=-log_10(0.01)=2.0#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH-=2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the chemical reaction....</p> <p><mathjax>#HCl(aq) + NaOH(aq) rarr NaCl(aq) + H_2O(l)#</mathjax>.</p> <p><mathjax>#"Moles of HCl(aq)"=100xx10^-3*Lxx0.2*mol*L^-1=2.0xx10^-2*mol#</mathjax>.</p> <p><mathjax>#"Moles of NaOH(aq)"=100xx10^-3*Lxx0.18*mol*L^-1=1.8xx10^-2*mol#</mathjax>.</p> <p>There is thus an excess of hydronium ions, to the tune of <mathjax>#2.0xx10^-2*mol-1.8xx10^-2*mol=2.0xx10^-3*mol#</mathjax></p> <p>But this is dissolved in a solution whose volume is now <mathjax>#200xx10^-3*L#</mathjax></p> <p>And so <mathjax>#[HCl]=(2.0xx10^-3*mol)/(200xx10^-3*L)=0.01*mol*L^-1#</mathjax></p> <p>But <mathjax>#pH-=-log_10{[H_3O^+]}=-log_10(0.01)=2.0#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the #pH# of a solution comprising #100*mL# volumes EACH of #HCl(aq)# at #0.20*mol*L^-1# and #NaOH(aq)# at #0.18*mol*L^-1#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="480177" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-25T16:44:28" itemprop="dateCreated"> Sep 25, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH-=2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We interrogate the chemical reaction....</p> <p><mathjax>#HCl(aq) + NaOH(aq) rarr NaCl(aq) + H_2O(l)#</mathjax>.</p> <p><mathjax>#"Moles of HCl(aq)"=100xx10^-3*Lxx0.2*mol*L^-1=2.0xx10^-2*mol#</mathjax>.</p> <p><mathjax>#"Moles of NaOH(aq)"=100xx10^-3*Lxx0.18*mol*L^-1=1.8xx10^-2*mol#</mathjax>.</p> <p>There is thus an excess of hydronium ions, to the tune of <mathjax>#2.0xx10^-2*mol-1.8xx10^-2*mol=2.0xx10^-3*mol#</mathjax></p> <p>But this is dissolved in a solution whose volume is now <mathjax>#200xx10^-3*L#</mathjax></p> <p>And so <mathjax>#[HCl]=(2.0xx10^-3*mol)/(200xx10^-3*L)=0.01*mol*L^-1#</mathjax></p> <p>But <mathjax>#pH-=-log_10{[H_3O^+]}=-log_10(0.01)=2.0#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/480177" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? 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What is the #pH# of a solution comprising #100*mL# volumes EACH of #HCl(aq)# at #0.20*mol*L^-1# and #NaOH(aq)# at #0.18*mol*L^-1#?

ac5c1a06-6ddd-11ea-8619-ccda262736ce

https://socratic.org/questions/a-compound-is-53-31-c-11-18-h-and-35-51-o-by-mass-what-is-its-empirical-formula

C2H5O

start chemical_formula qc_end end

[{"type":"other","value":"Chemical Formula [OF] the compound [IN] empirical"}]

[{"type":"chemical equation","value":"C2H5O"}]

[{"type":"physical unit","value":"Percent by mass [OF] C in the compound [=] \\pu{53.31%}"},{"type":"physical unit","value":"Percent by mass [OF] H in the compound [=] \\pu{11.18%}"},{"type":"physical unit","value":"Percent by mass [OF] O in the compound [=] \\pu{35.51%}"}]

<h1 class="questionTitle" itemprop="name">A compound is 53.31% C, 11.18% H, and 35.51% O by mass. What is its empirical formula?</h1>

C2H5O

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The atomic weights:</p> <ul> <li>C - <a href="https://www.google.com/#q=atomic+weight+carbon" rel="nofollow">carbon</a> - 12.0107</li> <li>H - <a href="https://www.google.com/#q=atomic+weight+hydrogen" rel="nofollow">hydrogen</a> - 1.00794</li> <li>O - <a href="https://www.google.com/#q=atomic+weight+oxygen" rel="nofollow">oxygen</a> - 15.9994 </li> </ul> <p>Therefore, 100 g would contain:</p> <p>Carbon: 53.31 g, which is 53.31 / 12.0107 = 4.4385 moles<br/> Hydrogen: 11.18 g, which is 11.18 / 1.00794 = 11.0919 moles<br/> Oxygen: 35.51 g , which is 35.51 / 15.9994 = 2.2194 moles</p> <p>Working the ratios:<br/> Carbon: 4.4385 / 2.2194 = 1.9999<br/> Hydrogen: 11.0919 / 2.2194 = 4.9977<br/> Oxygen: 2.2194 / 2.2194 = 1</p> <p>So, the answer is <mathjax>#C_2H_5O_1#</mathjax>, which is ethanol</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_2H_5O_1#</mathjax> - ethanol</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The atomic weights:</p> <ul> <li>C - <a href="https://www.google.com/#q=atomic+weight+carbon" rel="nofollow">carbon</a> - 12.0107</li> <li>H - <a href="https://www.google.com/#q=atomic+weight+hydrogen" rel="nofollow">hydrogen</a> - 1.00794</li> <li>O - <a href="https://www.google.com/#q=atomic+weight+oxygen" rel="nofollow">oxygen</a> - 15.9994 </li> </ul> <p>Therefore, 100 g would contain:</p> <p>Carbon: 53.31 g, which is 53.31 / 12.0107 = 4.4385 moles<br/> Hydrogen: 11.18 g, which is 11.18 / 1.00794 = 11.0919 moles<br/> Oxygen: 35.51 g , which is 35.51 / 15.9994 = 2.2194 moles</p> <p>Working the ratios:<br/> Carbon: 4.4385 / 2.2194 = 1.9999<br/> Hydrogen: 11.0919 / 2.2194 = 4.9977<br/> Oxygen: 2.2194 / 2.2194 = 1</p> <p>So, the answer is <mathjax>#C_2H_5O_1#</mathjax>, which is ethanol</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A compound is 53.31% C, 11.18% H, and 35.51% O by mass. What is its empirical formula?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="309816" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nick-41"><img alt="" class="" src="https://profilepictures.socratic.org/Sq1QmKQKSPCfDM110rRn_16.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nick-41"> Nick </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-13T18:35:50" itemprop="dateCreated"> Sep 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C_2H_5O_1#</mathjax> - ethanol</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The atomic weights:</p> <ul> <li>C - <a href="https://www.google.com/#q=atomic+weight+carbon" rel="nofollow">carbon</a> - 12.0107</li> <li>H - <a href="https://www.google.com/#q=atomic+weight+hydrogen" rel="nofollow">hydrogen</a> - 1.00794</li> <li>O - <a href="https://www.google.com/#q=atomic+weight+oxygen" rel="nofollow">oxygen</a> - 15.9994 </li> </ul> <p>Therefore, 100 g would contain:</p> <p>Carbon: 53.31 g, which is 53.31 / 12.0107 = 4.4385 moles<br/> Hydrogen: 11.18 g, which is 11.18 / 1.00794 = 11.0919 moles<br/> Oxygen: 35.51 g , which is 35.51 / 15.9994 = 2.2194 moles</p> <p>Working the ratios:<br/> Carbon: 4.4385 / 2.2194 = 1.9999<br/> Hydrogen: 11.0919 / 2.2194 = 4.9977<br/> Oxygen: 2.2194 / 2.2194 = 1</p> <p>So, the answer is <mathjax>#C_2H_5O_1#</mathjax>, which is ethanol</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/309816" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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A compound is 53.31% C, 11.18% H, and 35.51% O by mass. What is its empirical formula?

acde559c-6ddd-11ea-8e9e-ccda262736ce

https://socratic.org/questions/to-what-volume-should-you-dilute-55-ml-of-a-11-m-stock-hno-3-solution-to-obtain-

4.42 L

start physical_unit 13 14 volume l qc_end physical_unit 12 14 6 7 volume qc_end physical_unit 12 14 10 11 molarity qc_end physical_unit 13 14 18 19 molarity qc_end end

[{"type":"physical unit","value":"Volume2 [OF] HNO3 solution [IN] L"}]

[{"type":"physical unit","value":"4.42 L"}]

[{"type":"physical unit","value":"Volume1 [OF] stock HNO3 solution [=] \\pu{55 mL}"},{"type":"physical unit","value":"Molarity1 [OF] stock HNO3 solution [=] \\pu{11 M}"},{"type":"physical unit","value":"Molarity2 [OF] HNO3 solution [=] \\pu{0.137 M}"}]

<h1 class="questionTitle" itemprop="name">To what volume should you dilute 55 mL of a 11 M stock #HNO_3# solution to obtain a 0.137 M #HNO_3# solution?</h1>

4.42 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> <mathjax>#("M")#</mathjax> represents the concentration of a solution in moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>/liters of solution.</p> <p><mathjax>#M_1V_1=M_2V_2#</mathjax></p> <p><mathjax>#M_1="11 M"="11 mol/L"#</mathjax><br/> <mathjax>#V_1="55 mL"="0.055 L"#</mathjax><br/> <mathjax>#M_2="0.137 M"="0.137 mol/L"#</mathjax><br/> <mathjax>#V_2="???#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax>, then substitute the given values into the equation and solve.</p> <p><mathjax>#V_2=(M_1V_1)/M_2#</mathjax></p> <p><mathjax>#V_2=(11cancel"mol/L" * 0.055"L")/(0.137cancel"mol/L")="4.4 L"#</mathjax> (rounded to two significant figures)</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You need to dilute the given volume of stock solution to <mathjax>#"4.4 L"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> <mathjax>#("M")#</mathjax> represents the concentration of a solution in moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>/liters of solution.</p> <p><mathjax>#M_1V_1=M_2V_2#</mathjax></p> <p><mathjax>#M_1="11 M"="11 mol/L"#</mathjax><br/> <mathjax>#V_1="55 mL"="0.055 L"#</mathjax><br/> <mathjax>#M_2="0.137 M"="0.137 mol/L"#</mathjax><br/> <mathjax>#V_2="???#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax>, then substitute the given values into the equation and solve.</p> <p><mathjax>#V_2=(M_1V_1)/M_2#</mathjax></p> <p><mathjax>#V_2=(11cancel"mol/L" * 0.055"L")/(0.137cancel"mol/L")="4.4 L"#</mathjax> (rounded to two significant figures)</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">To what volume should you dilute 55 mL of a 11 M stock #HNO_3# solution to obtain a 0.137 M #HNO_3# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/dilution-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Dilution Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="267540" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-19T23:39:34" itemprop="dateCreated"> May 19, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You need to dilute the given volume of stock solution to <mathjax>#"4.4 L"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> <mathjax>#("M")#</mathjax> represents the concentration of a solution in moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>/liters of solution.</p> <p><mathjax>#M_1V_1=M_2V_2#</mathjax></p> <p><mathjax>#M_1="11 M"="11 mol/L"#</mathjax><br/> <mathjax>#V_1="55 mL"="0.055 L"#</mathjax><br/> <mathjax>#M_2="0.137 M"="0.137 mol/L"#</mathjax><br/> <mathjax>#V_2="???#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#V_2#</mathjax>, then substitute the given values into the equation and solve.</p> <p><mathjax>#V_2=(M_1V_1)/M_2#</mathjax></p> <p><mathjax>#V_2=(11cancel"mol/L" * 0.055"L")/(0.137cancel"mol/L")="4.4 L"#</mathjax> (rounded to two significant figures)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/267540" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-concentration-from-absorbance"> How do you calculate concentration from absorbance? 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To what volume should you dilute 55 mL of a 11 M stock #HNO_3# solution to obtain a 0.137 M #HNO_3# solution?

a96c4d34-6ddd-11ea-8139-ccda262736ce

https://socratic.org/questions/what-is-the-specific-heat-of-a-substance-if-1560-cal-are-required-to-raise-the-t

0.33 cal/(g * ℃)

start physical_unit 6 7 specific_heat cal/(g_·_°c) qc_end physical_unit 6 7 9 10 energy qc_end physical_unit 6 7 23 24 temperature qc_end physical_unit 6 7 19 20 mass qc_end end

[{"type":"physical unit","value":"Specific heat [OF] a substance [IN] cal/(g * ℃)"}]

[{"type":"physical unit","value":"0.33 cal/(g * ℃)"}]

[{"type":"physical unit","value":"Required energy [OF] a substance [=] \\pu{1560 cal}"},{"type":"physical unit","value":"Raised temperature [OF] a substance [=] \\pu{15 ℃}"},{"type":"physical unit","value":"Mass [OF] a substance sample [=] \\pu{312 g}"}]

<h1 class="questionTitle" itemprop="name">What is the specific heat of a substance if 1560 cal are required to raise the temperature of a 312-g sample by 15° C?</h1>

0.33 cal/(g * ℃)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The amount of heat required is determined from the formula</p> <p><mathjax>#q = mcΔT#</mathjax>,</p> <p>where</p> <ul> <li><mathjax>#q#</mathjax> is the amount of heat transferred</li> <li><mathjax>#m#</mathjax> is the mass of the substance</li> <li><mathjax>#c#</mathjax> is the specific heat capacity of the substance</li> <li><mathjax>#ΔT#</mathjax> is the change in temperature</li> </ul> <p><mathjax>#q = "1560 cal"#</mathjax><br/> <mathjax>#m = "312 g"#</mathjax><br/> <mathjax>#ΔT = "15 °C"#</mathjax></p> <p><mathjax>#c = q/(mΔT) = "1560 cal"/("312 g × 15 °C") = "0.33 cal·g"^"-1""°C"^"-1"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity of the substance is <mathjax>#"0.33 cal·g"^"-1""°C"^"-1"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The amount of heat required is determined from the formula</p> <p><mathjax>#q = mcΔT#</mathjax>,</p> <p>where</p> <ul> <li><mathjax>#q#</mathjax> is the amount of heat transferred</li> <li><mathjax>#m#</mathjax> is the mass of the substance</li> <li><mathjax>#c#</mathjax> is the specific heat capacity of the substance</li> <li><mathjax>#ΔT#</mathjax> is the change in temperature</li> </ul> <p><mathjax>#q = "1560 cal"#</mathjax><br/> <mathjax>#m = "312 g"#</mathjax><br/> <mathjax>#ΔT = "15 °C"#</mathjax></p> <p><mathjax>#c = q/(mΔT) = "1560 cal"/("312 g × 15 °C") = "0.33 cal·g"^"-1""°C"^"-1"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the specific heat of a substance if 1560 cal are required to raise the temperature of a 312-g sample by 15° C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="235434" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-05T15:33:43" itemprop="dateCreated"> Mar 5, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity of the substance is <mathjax>#"0.33 cal·g"^"-1""°C"^"-1"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The amount of heat required is determined from the formula</p> <p><mathjax>#q = mcΔT#</mathjax>,</p> <p>where</p> <ul> <li><mathjax>#q#</mathjax> is the amount of heat transferred</li> <li><mathjax>#m#</mathjax> is the mass of the substance</li> <li><mathjax>#c#</mathjax> is the specific heat capacity of the substance</li> <li><mathjax>#ΔT#</mathjax> is the change in temperature</li> </ul> <p><mathjax>#q = "1560 cal"#</mathjax><br/> <mathjax>#m = "312 g"#</mathjax><br/> <mathjax>#ΔT = "15 °C"#</mathjax></p> <p><mathjax>#c = q/(mΔT) = "1560 cal"/("312 g × 15 °C") = "0.33 cal·g"^"-1""°C"^"-1"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/235434" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? 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What is the specific heat of a substance if 1560 cal are required to raise the temperature of a 312-g sample by 15° C?

aa4b0bba-6ddd-11ea-96fd-ccda262736ce

https://socratic.org/questions/59b73a337c014903b4ce4fd8

1154.59 kJ

start physical_unit 10 10 energy kj qc_end physical_unit 10 10 7 8 mass qc_end physical_unit 12 12 14 15 temperature qc_end physical_unit 10 10 18 21 specific_heat_capacity qc_end end

[{"type":"physical unit","value":"Required energy [OF] water [IN] kJ"}]

[{"type":"physical unit","value":"1154.59 kJ"}]

[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{429 g}"},{"type":"physical unit","value":"Temperature [OF] steam [=] \\pu{156 ℃}"},{"type":"physical unit","value":"C [OF] water [=] \\pu{4.184 J/(℃ * mol)}"},{"type":"physical unit","value":"C [OF] vapour [=] \\pu{2.078 J/(℃ * mol)}"},{"type":"physical unit","value":"Delta_{vap}H [OF] the reaction [=] \\pu{2257 J/g}"}]

<h1 class="questionTitle" itemprop="name">How much energy is required to convert 429 g of water to steam at 156 °C?</h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#C_text(water) = "4.184 J/(°C·mol)"; C_text(vapour) = "2.078 J/(°C·mol)"; Δ_text(vap)H = "2257 J/g"#</mathjax></p></div> </h2> </div> </div>

1154.59 kJ

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We will be using the formula: <mathjax>#mcDeltaT#</mathjax>, where:<br/> =&gt; <mathjax>#m#</mathjax> is the mass of the object in grams. <br/> =&gt; <mathjax>#c#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity of the object. <br/> =&gt; <mathjax>#DeltaT#</mathjax> is the change in temperature found by subtracting the initial temperature from the final. </p> <p>Let's go over what we are given:</p> <blockquote> <p><mathjax>#m = 429 "g"#</mathjax></p> <p><mathjax>#c_"liquid water" = 4.184 J/(g*^oC)#</mathjax></p> <p><mathjax>#c_"water vapour" = 2.078 J/(g*^oC)#</mathjax> </p> <p><mathjax># DeltaT = T_"final" - T_"initial"#</mathjax></p> </blockquote> <p>Now there's something we have to consider, we can't just get from liquid at <mathjax>#24^oC#</mathjax> to steam at <mathjax>#156^oC#</mathjax>. What we have to do is convert from liquid to it's boiling point of <mathjax>#100^oC#</mathjax>, and then from <mathjax>#100^oC#</mathjax> to <mathjax>#156^oC#</mathjax>. </p> <p>So let's do the liquid to gas first. </p> <blockquote> <p><mathjax>#q_"liquid water" =mcDeltaT#</mathjax></p> <blockquote> <blockquote> <blockquote> <p><mathjax>#=(429)(4.184)(100-24)#</mathjax></p> <p><mathjax>#=136415.136 J/(g*^oC)#</mathjax></p> </blockquote> </blockquote> </blockquote> </blockquote> <p>Next, we convert the liquid at <mathjax>#100 °"C"#</mathjax> to vapour at <mathjax>#100 °"C"#</mathjax>. For this, we </p> <blockquote> <p><mathjax>#q_"conversion"=mDeltaH#</mathjax></p> <blockquote> <p><mathjax>#= 429(2257)#</mathjax></p> <p><mathjax>#=968253#</mathjax></p> </blockquote> </blockquote> <p>Now let's do the gas to hotter gas. </p> <blockquote> <p><mathjax>#q_"water vapour"=mcDeltaT#</mathjax></p> <blockquote> <blockquote> <blockquote> <blockquote> <p><mathjax>#=(429)(2.078)(156-100)#</mathjax></p> <p><mathjax>#=49921.87J/(g*^oC)#</mathjax></p> </blockquote> </blockquote> </blockquote> </blockquote> </blockquote> <p>Now all we have to do is add the energies. </p> <blockquote> <p><mathjax>#q_"total"=q_"liquid water" + q_"conversion" + q_"water vapour"#</mathjax></p> <blockquote> <blockquote> <p><mathjax>#=136415.136+968253+49921.87#</mathjax></p> <p><mathjax>#=1154590.01J/(g*^oC)#</mathjax></p> <p><mathjax>#=1154.59001(kJ)/(g*^oC)#</mathjax></p> <p><mathjax>#~~1155(kJ)/(g*^oC)#</mathjax></p> </blockquote> </blockquote> </blockquote> <p>Hope this helps :)</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#~~1155(kJ)/(g*^oC)#</mathjax>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We will be using the formula: <mathjax>#mcDeltaT#</mathjax>, where:<br/> =&gt; <mathjax>#m#</mathjax> is the mass of the object in grams. <br/> =&gt; <mathjax>#c#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity of the object. <br/> =&gt; <mathjax>#DeltaT#</mathjax> is the change in temperature found by subtracting the initial temperature from the final. </p> <p>Let's go over what we are given:</p> <blockquote> <p><mathjax>#m = 429 "g"#</mathjax></p> <p><mathjax>#c_"liquid water" = 4.184 J/(g*^oC)#</mathjax></p> <p><mathjax>#c_"water vapour" = 2.078 J/(g*^oC)#</mathjax> </p> <p><mathjax># DeltaT = T_"final" - T_"initial"#</mathjax></p> </blockquote> <p>Now there's something we have to consider, we can't just get from liquid at <mathjax>#24^oC#</mathjax> to steam at <mathjax>#156^oC#</mathjax>. What we have to do is convert from liquid to it's boiling point of <mathjax>#100^oC#</mathjax>, and then from <mathjax>#100^oC#</mathjax> to <mathjax>#156^oC#</mathjax>. </p> <p>So let's do the liquid to gas first. </p> <blockquote> <p><mathjax>#q_"liquid water" =mcDeltaT#</mathjax></p> <blockquote> <blockquote> <blockquote> <p><mathjax>#=(429)(4.184)(100-24)#</mathjax></p> <p><mathjax>#=136415.136 J/(g*^oC)#</mathjax></p> </blockquote> </blockquote> </blockquote> </blockquote> <p>Next, we convert the liquid at <mathjax>#100 °"C"#</mathjax> to vapour at <mathjax>#100 °"C"#</mathjax>. For this, we </p> <blockquote> <p><mathjax>#q_"conversion"=mDeltaH#</mathjax></p> <blockquote> <p><mathjax>#= 429(2257)#</mathjax></p> <p><mathjax>#=968253#</mathjax></p> </blockquote> </blockquote> <p>Now let's do the gas to hotter gas. </p> <blockquote> <p><mathjax>#q_"water vapour"=mcDeltaT#</mathjax></p> <blockquote> <blockquote> <blockquote> <blockquote> <p><mathjax>#=(429)(2.078)(156-100)#</mathjax></p> <p><mathjax>#=49921.87J/(g*^oC)#</mathjax></p> </blockquote> </blockquote> </blockquote> </blockquote> </blockquote> <p>Now all we have to do is add the energies. </p> <blockquote> <p><mathjax>#q_"total"=q_"liquid water" + q_"conversion" + q_"water vapour"#</mathjax></p> <blockquote> <blockquote> <p><mathjax>#=136415.136+968253+49921.87#</mathjax></p> <p><mathjax>#=1154590.01J/(g*^oC)#</mathjax></p> <p><mathjax>#=1154.59001(kJ)/(g*^oC)#</mathjax></p> <p><mathjax>#~~1155(kJ)/(g*^oC)#</mathjax></p> </blockquote> </blockquote> </blockquote> <p>Hope this helps :)</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How much energy is required to convert 429 g of water to steam at 156 °C?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#C_text(water) = "4.184 J/(°C·mol)"; C_text(vapour) = "2.078 J/(°C·mol)"; Δ_text(vap)H = "2257 J/g"#</mathjax></p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="474329" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ryuu"><img alt="" class="" src="https://profilepictures.socratic.org/ybMAUPwJSLW0wuAqV5i2_meh.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ryuu"> Ryuu </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-09-12T04:10:06" itemprop="dateCreated"> Sep 12, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#~~1155(kJ)/(g*^oC)#</mathjax>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We will be using the formula: <mathjax>#mcDeltaT#</mathjax>, where:<br/> =&gt; <mathjax>#m#</mathjax> is the mass of the object in grams. <br/> =&gt; <mathjax>#c#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity of the object. <br/> =&gt; <mathjax>#DeltaT#</mathjax> is the change in temperature found by subtracting the initial temperature from the final. </p> <p>Let's go over what we are given:</p> <blockquote> <p><mathjax>#m = 429 "g"#</mathjax></p> <p><mathjax>#c_"liquid water" = 4.184 J/(g*^oC)#</mathjax></p> <p><mathjax>#c_"water vapour" = 2.078 J/(g*^oC)#</mathjax> </p> <p><mathjax># DeltaT = T_"final" - T_"initial"#</mathjax></p> </blockquote> <p>Now there's something we have to consider, we can't just get from liquid at <mathjax>#24^oC#</mathjax> to steam at <mathjax>#156^oC#</mathjax>. What we have to do is convert from liquid to it's boiling point of <mathjax>#100^oC#</mathjax>, and then from <mathjax>#100^oC#</mathjax> to <mathjax>#156^oC#</mathjax>. </p> <p>So let's do the liquid to gas first. </p> <blockquote> <p><mathjax>#q_"liquid water" =mcDeltaT#</mathjax></p> <blockquote> <blockquote> <blockquote> <p><mathjax>#=(429)(4.184)(100-24)#</mathjax></p> <p><mathjax>#=136415.136 J/(g*^oC)#</mathjax></p> </blockquote> </blockquote> </blockquote> </blockquote> <p>Next, we convert the liquid at <mathjax>#100 °"C"#</mathjax> to vapour at <mathjax>#100 °"C"#</mathjax>. For this, we </p> <blockquote> <p><mathjax>#q_"conversion"=mDeltaH#</mathjax></p> <blockquote> <p><mathjax>#= 429(2257)#</mathjax></p> <p><mathjax>#=968253#</mathjax></p> </blockquote> </blockquote> <p>Now let's do the gas to hotter gas. </p> <blockquote> <p><mathjax>#q_"water vapour"=mcDeltaT#</mathjax></p> <blockquote> <blockquote> <blockquote> <blockquote> <p><mathjax>#=(429)(2.078)(156-100)#</mathjax></p> <p><mathjax>#=49921.87J/(g*^oC)#</mathjax></p> </blockquote> </blockquote> </blockquote> </blockquote> </blockquote> <p>Now all we have to do is add the energies. </p> <blockquote> <p><mathjax>#q_"total"=q_"liquid water" + q_"conversion" + q_"water vapour"#</mathjax></p> <blockquote> <blockquote> <p><mathjax>#=136415.136+968253+49921.87#</mathjax></p> <p><mathjax>#=1154590.01J/(g*^oC)#</mathjax></p> <p><mathjax>#=1154.59001(kJ)/(g*^oC)#</mathjax></p> <p><mathjax>#~~1155(kJ)/(g*^oC)#</mathjax></p> </blockquote> </blockquote> </blockquote> <p>Hope this helps :)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/474329" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-read-differential-scanning-in-calorimetry"> What information do you get from a differential scanning calorimetry plot? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-calorimetry"> How do you measure calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531d304102bf341e75b962a7"> Question #962a7 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5335021802bf344ae911dfc5"> Question #1dfc5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668f502bf34572c341af6"> Question #41af6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-definition-of-calorimetry"> What is calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-differential-scanning-calorimeter"> What is a differential scanning calorimeter? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-calorimeter-measure-energy"> How can a calorimeter measure energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-calorimeters-made-of"> What are calorimeters made of? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/calorimetry"> See all questions in Calorimetry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2369 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How much energy is required to convert 429 g of water to steam at 156 °C?

#C_text(water) = "4.184 J/(°C·mol)"; C_text(vapour) = "2.078 J/(°C·mol)"; Δ_text(vap)H = "2257 J/g"#

ab23ab65-6ddd-11ea-8790-ccda262736ce

https://socratic.org/questions/gas-samples-a-b-c-are-contained-at-stp-partial-pressure-of-sample-a-is-38-0-kpa-

44.3 kPa

start physical_unit 29 30 partial_pressure kpa qc_end c_other STP qc_end physical_unit 12 13 15 16 partial_pressure qc_end physical_unit 18 19 21 22 partial_pressure qc_end end

[{"type":"physical unit","value":"Partial pressure [OF] sample C [IN] kPa"}]

[{"type":"physical unit","value":"44.3 kPa"}]

[{"type":"other","value":"STP"},{"type":"physical unit","value":"Partial pressure [OF] sample A [=] \\pu{38.0 kPa}"},{"type":"physical unit","value":"Partial pressure [OF] sample B [=] \\pu{19.0 kPa}"}]

<h1 class="questionTitle" itemprop="name">Gas samples A, B, C are contained at STP. Partial pressure of sample A is 38.0 kPa and sample B is 19.0 kPa. What is the partial pressure of sample C?</h1>

44.3 kPa

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If the mixture of gases A, B and C is contained at STP, this means that the total pressure is 1 atm.</p> <p>Note that <mathjax>#1atm=101.325kPa#</mathjax></p> <p>According to Dalton's law, the total pressure of a mixture is equal to the sum of the partial pressures of the gases in the mixture:</p> <p><mathjax>#P_("total")=P_A+P_B+P_C#</mathjax></p> <p><mathjax>#=&gt;P_C=P_("total")-P_A-P_B#</mathjax></p> <p><mathjax>#=&gt;P_C=101.325kPa-38.0kPa-19.0kPa=44.3kPa#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#=&gt;P_C=44.3kPa#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If the mixture of gases A, B and C is contained at STP, this means that the total pressure is 1 atm.</p> <p>Note that <mathjax>#1atm=101.325kPa#</mathjax></p> <p>According to Dalton's law, the total pressure of a mixture is equal to the sum of the partial pressures of the gases in the mixture:</p> <p><mathjax>#P_("total")=P_A+P_B+P_C#</mathjax></p> <p><mathjax>#=&gt;P_C=P_("total")-P_A-P_B#</mathjax></p> <p><mathjax>#=&gt;P_C=101.325kPa-38.0kPa-19.0kPa=44.3kPa#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Gas samples A, B, C are contained at STP. Partial pressure of sample A is 38.0 kPa and sample B is 19.0 kPa. What is the partial pressure of sample C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/partial-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Partial Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="195468" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-02T17:04:52" itemprop="dateCreated"> Dec 2, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#=&gt;P_C=44.3kPa#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If the mixture of gases A, B and C is contained at STP, this means that the total pressure is 1 atm.</p> <p>Note that <mathjax>#1atm=101.325kPa#</mathjax></p> <p>According to Dalton's law, the total pressure of a mixture is equal to the sum of the partial pressures of the gases in the mixture:</p> <p><mathjax>#P_("total")=P_A+P_B+P_C#</mathjax></p> <p><mathjax>#=&gt;P_C=P_("total")-P_A-P_B#</mathjax></p> <p><mathjax>#=&gt;P_C=101.325kPa-38.0kPa-19.0kPa=44.3kPa#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/195468" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="195475" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-02T17:34:26" itemprop="dateCreated"> Dec 2, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Pressures are additive. The pressure exerted by C is approx. 44 kPa.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Dalton's law of partial pressures states that in a gaseous mixture the <a href="http://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a> exerted by each component is the same pressure it would exert if it ALONE occupied the container; the total pressure is the sum of the partial pressures. We know that the total pressure is atmospheric, 101.3 kPa. Since the partial pressures, <mathjax>#P_A#</mathjax>, and <mathjax>#P_B#</mathjax> are known, <mathjax>#P_C#</mathjax> is simply the difference between these pressures and the total pressure:</p> <p><mathjax>#P_C = 101.3 - P_A - P_B = ?? kPa#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/195475" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534e256802bf342adfa30010"> How do you do a steam distillation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/53613f9f02bf3416cd9f8a34"> Question #f8a34 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-i-calculate-the-total-pressure-of-a-mixture-of-gases-by-adding-together-the-"> Can I calculate the total pressure of a mixture of gases by adding together the partial... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-formula-of-partial-pressure"> What is the formula of partial pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-dalton-s-law-of-partial-pressures"> What is the Dalton's law of partial pressures? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/nitrogen-gas-n2-reacts-with-hydrogen-gas-h2-to-form-ammonia-nh3-at-200-c-in-a-cl"> Nitrogen gas (N2) reacts with hydrogen gas (H2) to form ammonia (NH3). 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Gas samples A, B, C are contained at STP. Partial pressure of sample A is 38.0 kPa and sample B is 19.0 kPa. What is the partial pressure of sample C?

abd0a0b1-6ddd-11ea-abdc-ccda262736ce

https://socratic.org/questions/572c0c3511ef6b72467484b1

3 N2H4(g) + 4 ClO3-(aq) -> 6 NO(g) + 6 H2O(l) + 4 Cl-(aq)

start chemical_equation qc_end substance 2 2 qc_end substance 4 4 qc_end chemical_equation 7 7 qc_end substance 9 10 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"3 N2H4(g) + 4 ClO3-(aq) -> 6 NO(g) + 6 H2O(l) + 4 Cl-(aq)"}]

[{"type":"substance name","value":"Chlorate"},{"type":"substance name","value":"Hydrazine"},{"type":"chemical equation","value":"NO"},{"type":"substance name","value":"Chloride anion"}]

<h1 class="questionTitle" itemprop="name">How does #"chlorate"# oxidize hydrazine to give #NO# and chloride anion?</h1>

3 N2H4(g) + 4 ClO3-(aq) -> 6 NO(g) + 6 H2O(l) + 4 Cl-(aq)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is one equation for the oxidation of hydrazine to nitrous oxide. It also accords with your question. Quite clearly, the equation should have appeared with the question.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3N_2H_4(g) + 4ClO_3^(-)(aq) rarr 6NO(g) + 6H_2O(l) + 4Cl^(-)(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is one equation for the oxidation of hydrazine to nitrous oxide. It also accords with your question. Quite clearly, the equation should have appeared with the question.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How does #"chlorate"# oxidize hydrazine to give #NO# and chloride anion?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="262778" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-06T08:07:46" itemprop="dateCreated"> May 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3N_2H_4(g) + 4ClO_3^(-)(aq) rarr 6NO(g) + 6H_2O(l) + 4Cl^(-)(aq)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is one equation for the oxidation of hydrazine to nitrous oxide. It also accords with your question. Quite clearly, the equation should have appeared with the question.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/262778" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-resonance-structures-affect-acidity"> How do resonance structures affect acidity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-carbon-dioxide-change-the-acid-base-condition-of-a-solution"> How does carbon dioxide change the acid-base condition of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-strong-acids-have-a-low-ph"> Why do strong acids have a low pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-neutralization-a-double-replacement-reaction"> Is neutralization a double replacement reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-nah-a-strong-base"> Why is NaH a strong base? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-hbr-a-strong-acid"> Is HBr a strong acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-hf-a-strong-acid"> Is HF a strong acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-neutralization-occur"> Why does neutralization occur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-strong-acids-completely-dissociate-in-water"> Do strong acids completely dissociate in water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-ph-of-weak-acid"> How can I calculate pH of weak acid? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/acids-and-bases"> See all questions in Acids and Bases </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1446 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How does #"chlorate"# oxidize hydrazine to give #NO# and chloride anion?

a8f5f45b-6ddd-11ea-a63d-ccda262736ce

https://socratic.org/questions/if-10-drops-of-pyruvic-acid-hc-3h-3o-3-are-titrated-with-20-drops-of-0-25-m-naoh

0.50 M

start physical_unit 22 25 molarity mol/l qc_end physical_unit 15 15 13 14 molarity qc_end physical_unit 15 15 10 11 volume qc_end physical_unit 6 6 1 2 volume qc_end end

[{"type":"physical unit","value":"Molar concentration [OF] the pyruvic acid solution [IN] M"}]

[{"type":"physical unit","value":"0.50 M"}]

[{"type":"physical unit","value":"Molarity [OF] NaOH [=] \\pu{0.25 M}"},{"type":"physical unit","value":"Volume [OF] NaOH [=] \\pu{20 drops}"},{"type":"physical unit","value":"Volume [OF] HC3H3O3 [=] \\pu{10 drops}"}]

<h1 class="questionTitle" itemprop="name">If 10 drops of pyruvic acid (#HC_3H_3O_3#) are titrated with 20 drops of 0.25 M #NaOH#, what is the molar concentration of the pyruvic acid solution?</h1>

0.50 M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you don't need to know what a <em>drop</em> means in terms of volume, all you need to do is focus on the fact that you need <strong>twice as many</strong> drops of sodium hydroxide solution than of pyruvic acid solution. </p> <p>Pyruvic acid, a <strong>weak acid</strong>, will react with the hydroxide anions delivered to the solution by the sodium hydroxide, a <strong>strong base</strong>, in a <mathjax>#1:1#</mathjax> <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a></strong> to form the <em>pyruvirate anion</em>, <mathjax>#"CH"_3"COCOO"^(-)#</mathjax>, and water. </p> <blockquote> <p><mathjax>#"CH"_ 3 "COCOOH" _ ((aq)) + "OH"_ ((aq))^(-) -&gt; "CH"_ 3"COCOO"_ ((aq))^(-) + "H"_ 2"O"_((l))#</mathjax></p> </blockquote> <p>This means that a <em>complete <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a></em> will require <strong>equal numbers of moles</strong> of pyruvic acid and of hydroxide anions. </p> <p>You know that you have <mathjax>#10#</mathjax> <strong>drops</strong> of pyruvic acid solution of <em>unknown concentration</em> that require <mathjax>#20#</mathjax> <strong>drops</strong> of the sodium hydroxide solution for complete neutralization. </p> <p>This means that the <mathjax>#10#</mathjax> drops of pyruvic acid must contain <strong>the same number of moles</strong> of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> as the <mathjax>#20#</mathjax> drops of sodium hydroxide. </p> <p>In other words, for the <em>same volume</em> of pyruvic acid solution you get <strong>twice as many moles</strong> of solute than you get for the sodium hydroxide solution.</p> <p>This means that the pyruvixc acid solution is <strong>twice as concentrated</strong> as the sodium hydroxide solution, which means that its <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> will be </p> <blockquote> <p><mathjax>#["CH"_3"COCOOH"] = 2 xx "0.25 M" = color(green)(|bar(ul(color(white)(a/a)color(black)("0.50 M")color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>An important thing to note here is that we're assuming that the drops of pyruvic acid solution and the drops of sodium hydroxide solution have <strong>equal volumes</strong>. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.50 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you don't need to know what a <em>drop</em> means in terms of volume, all you need to do is focus on the fact that you need <strong>twice as many</strong> drops of sodium hydroxide solution than of pyruvic acid solution. </p> <p>Pyruvic acid, a <strong>weak acid</strong>, will react with the hydroxide anions delivered to the solution by the sodium hydroxide, a <strong>strong base</strong>, in a <mathjax>#1:1#</mathjax> <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a></strong> to form the <em>pyruvirate anion</em>, <mathjax>#"CH"_3"COCOO"^(-)#</mathjax>, and water. </p> <blockquote> <p><mathjax>#"CH"_ 3 "COCOOH" _ ((aq)) + "OH"_ ((aq))^(-) -&gt; "CH"_ 3"COCOO"_ ((aq))^(-) + "H"_ 2"O"_((l))#</mathjax></p> </blockquote> <p>This means that a <em>complete <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a></em> will require <strong>equal numbers of moles</strong> of pyruvic acid and of hydroxide anions. </p> <p>You know that you have <mathjax>#10#</mathjax> <strong>drops</strong> of pyruvic acid solution of <em>unknown concentration</em> that require <mathjax>#20#</mathjax> <strong>drops</strong> of the sodium hydroxide solution for complete neutralization. </p> <p>This means that the <mathjax>#10#</mathjax> drops of pyruvic acid must contain <strong>the same number of moles</strong> of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> as the <mathjax>#20#</mathjax> drops of sodium hydroxide. </p> <p>In other words, for the <em>same volume</em> of pyruvic acid solution you get <strong>twice as many moles</strong> of solute than you get for the sodium hydroxide solution.</p> <p>This means that the pyruvixc acid solution is <strong>twice as concentrated</strong> as the sodium hydroxide solution, which means that its <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> will be </p> <blockquote> <p><mathjax>#["CH"_3"COCOOH"] = 2 xx "0.25 M" = color(green)(|bar(ul(color(white)(a/a)color(black)("0.50 M")color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>An important thing to note here is that we're assuming that the drops of pyruvic acid solution and the drops of sodium hydroxide solution have <strong>equal volumes</strong>. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If 10 drops of pyruvic acid (#HC_3H_3O_3#) are titrated with 20 drops of 0.25 M #NaOH#, what is the molar concentration of the pyruvic acid solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="278454" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-17T16:12:03" itemprop="dateCreated"> Jun 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.50 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you don't need to know what a <em>drop</em> means in terms of volume, all you need to do is focus on the fact that you need <strong>twice as many</strong> drops of sodium hydroxide solution than of pyruvic acid solution. </p> <p>Pyruvic acid, a <strong>weak acid</strong>, will react with the hydroxide anions delivered to the solution by the sodium hydroxide, a <strong>strong base</strong>, in a <mathjax>#1:1#</mathjax> <strong><a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a></strong> to form the <em>pyruvirate anion</em>, <mathjax>#"CH"_3"COCOO"^(-)#</mathjax>, and water. </p> <blockquote> <p><mathjax>#"CH"_ 3 "COCOOH" _ ((aq)) + "OH"_ ((aq))^(-) -&gt; "CH"_ 3"COCOO"_ ((aq))^(-) + "H"_ 2"O"_((l))#</mathjax></p> </blockquote> <p>This means that a <em>complete <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a></em> will require <strong>equal numbers of moles</strong> of pyruvic acid and of hydroxide anions. </p> <p>You know that you have <mathjax>#10#</mathjax> <strong>drops</strong> of pyruvic acid solution of <em>unknown concentration</em> that require <mathjax>#20#</mathjax> <strong>drops</strong> of the sodium hydroxide solution for complete neutralization. </p> <p>This means that the <mathjax>#10#</mathjax> drops of pyruvic acid must contain <strong>the same number of moles</strong> of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> as the <mathjax>#20#</mathjax> drops of sodium hydroxide. </p> <p>In other words, for the <em>same volume</em> of pyruvic acid solution you get <strong>twice as many moles</strong> of solute than you get for the sodium hydroxide solution.</p> <p>This means that the pyruvixc acid solution is <strong>twice as concentrated</strong> as the sodium hydroxide solution, which means that its <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> will be </p> <blockquote> <p><mathjax>#["CH"_3"COCOOH"] = 2 xx "0.25 M" = color(green)(|bar(ul(color(white)(a/a)color(black)("0.50 M")color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>An important thing to note here is that we're assuming that the drops of pyruvic acid solution and the drops of sodium hydroxide solution have <strong>equal volumes</strong>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/278454" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3456 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

If 10 drops of pyruvic acid (#HC_3H_3O_3#) are titrated with 20 drops of 0.25 M #NaOH#, what is the molar concentration of the pyruvic acid solution?

ab1bc978-6ddd-11ea-9816-ccda262736ce

https://socratic.org/questions/when-2-moles-of-h-2-g-and-1-mole-of-o-2-g-react-to-give-liquid-water-572-kj-of-h

276 kJ

start physical_unit 13 14 thermochemical_equation kj qc_end physical_unit 4 4 1 2 mole qc_end physical_unit 9 9 6 7 mole qc_end chemical_equation 20 26 qc_end physical_unit 13 14 6 7 mole qc_end end

[{"type":"physical unit","value":"Themochemical eq. [OF] liquid water [IN] kJ"}]

[{"type":"physical unit","value":"276 kJ"}]

[{"type":"physical unit","value":"Mole [OF] H2(g) [=] \\pu{2 moles}"},{"type":"physical unit","value":"Mole [OF] O2(g) [=] \\pu{1 mole}"},{"type":"physical unit","value":"Evolved heat [OF] the reaction [=] \\pu{572 kJ}"},{"type":"chemical equation","value":"2 H2(g) + O2(g) -> 2 H2O(l)"},{"type":"physical unit","value":"Mole [OF] liquid water [=] \\pu{1 mole}"}]

<h1 class="questionTitle" itemprop="name">When 2 moles of #H_2(g)# and 1 mole of #O_2(g)# react to give liquid water, 572 kJ of heat evolve. #2H_2(g)# + #O_2(g)# #rarr# #2H_2O(l)# ; #DeltaH# = -572 kJ a) What is the themochemical eq. for 1 mole of liquid water? </h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>b) Write the reverse thermochemical equation in which 1 mole of liquid water disassociates into hydrogen and oxygen gas.<br/> Thank you so much for your help. :)</p></div> </h2> </div> </div>

276 kJ

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You know that when <mathjax>#2#</mathjax> <strong>moles</strong> of hydrogen gas react with <mathjax>#1#</mathjax> <strong>mole</strong> of oxygen gas, you get <mathjax>#2#</mathjax> <strong>moles</strong> of water and <mathjax>#"572 kJ"#</mathjax> of heat are <strong>evolved</strong>. </p> <blockquote> <p><mathjax>#2"H"_ (2(g)) + "O"_ (2(g)) -&gt; 2"H"_ 2"O"_ ((l))" "DeltaH = -"572 kJ"#</mathjax></p> <blockquote> <p>Don't forget that the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change of reaction must be <strong>negative</strong> here to illustrate the fact that heat if being <strong>given off</strong> by the reaction. </p> </blockquote> </blockquote> <p>Now, in order for this reaction to produce <mathjax>#1#</mathjax> <strong>mole</strong> of water, all the coefficients of the chemical equation must be <strong>halved</strong>.</p> <blockquote> <p><mathjax>#(1/2 * 2)"H"_ (2(g)) + 1/2"O"_( 2(g)) -&gt; (1/2 * 2)"H"_ 2"O"_ ((l))#</mathjax></p> </blockquote> <p>This will get you </p> <blockquote> <p><mathjax>#"H"_ (2(g)) + 1/2"O"_ (2(g)) -&gt; "H"_ 2"O"_ ((l))#</mathjax></p> </blockquote> <p>Now, the enthalpy change for this reaction will be <strong>half</strong> the value of the enthalpy change for the reaction that produced <mathjax>#2#</mathjax> <strong>moles</strong> of water. </p> <blockquote> <p><mathjax>#DeltaH_ ("1 mole H"_ 2"O") = 1/2 * DeltaH_ ("2 moles H"_ 2"O")#</mathjax></p> <p><mathjax>#DeltaH_ ("1 mole H"- 2"O") = (-"572 kJ")/2 = -"286 kJ"#</mathjax></p> </blockquote> <p>This means that the <strong>thermochemical equation</strong> that describes the formation of <mathjax>#1#</mathjax> <strong>mole</strong> of water looks like this</p> <blockquote> <p><mathjax>#"H"_ (2(g)) + 1/2"O"_ (2(g)) -&gt; "H"_ 2"O"_ ((l))" " DeltaH = -"276 kJ"#</mathjax></p> </blockquote> <p>To write the thermochemical equation that describes the <strong>decomposition</strong> of <mathjax>#1#</mathjax> <strong>mole</strong> of water into hydrogen gas and oxygen gas, you need to <em>reverse</em> the chemical equation</p> <blockquote> <p><mathjax>#"H"_ 2"O"_ ((l)) -&gt; "H"_ (2(g)) + 1/2"O"_ (2(g))#</mathjax></p> </blockquote> <p>and <strong>change the sign</strong> of the enthalpy change of reaction. </p> <blockquote> <p><mathjax>#DeltaH_"reverse" = -DeltaH_"forward"#</mathjax></p> </blockquote> <p>This means that the thermochemical equation will look like this</p> <blockquote> <p><mathjax>#"H"_ 2"O"_ ((l)) -&gt; "H"_ (2(g)) + 1/2"O"_ (2(g))" " DeltaH = +"276 kJ"#</mathjax></p> <blockquote> <p>This means that when <mathjax>#1#</mathjax> <strong>mole</strong> of water undergoes decomposition, <mathjax>#"276 kJ"#</mathjax> of heat are being <strong>absorbed</strong>!</p> </blockquote> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"H"_ (2(g)) + 1/2"O"_ (2(g)) -&gt; "H"_ 2"O"_ ((l))" " DeltaH = -"276 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You know that when <mathjax>#2#</mathjax> <strong>moles</strong> of hydrogen gas react with <mathjax>#1#</mathjax> <strong>mole</strong> of oxygen gas, you get <mathjax>#2#</mathjax> <strong>moles</strong> of water and <mathjax>#"572 kJ"#</mathjax> of heat are <strong>evolved</strong>. </p> <blockquote> <p><mathjax>#2"H"_ (2(g)) + "O"_ (2(g)) -&gt; 2"H"_ 2"O"_ ((l))" "DeltaH = -"572 kJ"#</mathjax></p> <blockquote> <p>Don't forget that the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change of reaction must be <strong>negative</strong> here to illustrate the fact that heat if being <strong>given off</strong> by the reaction. </p> </blockquote> </blockquote> <p>Now, in order for this reaction to produce <mathjax>#1#</mathjax> <strong>mole</strong> of water, all the coefficients of the chemical equation must be <strong>halved</strong>.</p> <blockquote> <p><mathjax>#(1/2 * 2)"H"_ (2(g)) + 1/2"O"_( 2(g)) -&gt; (1/2 * 2)"H"_ 2"O"_ ((l))#</mathjax></p> </blockquote> <p>This will get you </p> <blockquote> <p><mathjax>#"H"_ (2(g)) + 1/2"O"_ (2(g)) -&gt; "H"_ 2"O"_ ((l))#</mathjax></p> </blockquote> <p>Now, the enthalpy change for this reaction will be <strong>half</strong> the value of the enthalpy change for the reaction that produced <mathjax>#2#</mathjax> <strong>moles</strong> of water. </p> <blockquote> <p><mathjax>#DeltaH_ ("1 mole H"_ 2"O") = 1/2 * DeltaH_ ("2 moles H"_ 2"O")#</mathjax></p> <p><mathjax>#DeltaH_ ("1 mole H"- 2"O") = (-"572 kJ")/2 = -"286 kJ"#</mathjax></p> </blockquote> <p>This means that the <strong>thermochemical equation</strong> that describes the formation of <mathjax>#1#</mathjax> <strong>mole</strong> of water looks like this</p> <blockquote> <p><mathjax>#"H"_ (2(g)) + 1/2"O"_ (2(g)) -&gt; "H"_ 2"O"_ ((l))" " DeltaH = -"276 kJ"#</mathjax></p> </blockquote> <p>To write the thermochemical equation that describes the <strong>decomposition</strong> of <mathjax>#1#</mathjax> <strong>mole</strong> of water into hydrogen gas and oxygen gas, you need to <em>reverse</em> the chemical equation</p> <blockquote> <p><mathjax>#"H"_ 2"O"_ ((l)) -&gt; "H"_ (2(g)) + 1/2"O"_ (2(g))#</mathjax></p> </blockquote> <p>and <strong>change the sign</strong> of the enthalpy change of reaction. </p> <blockquote> <p><mathjax>#DeltaH_"reverse" = -DeltaH_"forward"#</mathjax></p> </blockquote> <p>This means that the thermochemical equation will look like this</p> <blockquote> <p><mathjax>#"H"_ 2"O"_ ((l)) -&gt; "H"_ (2(g)) + 1/2"O"_ (2(g))" " DeltaH = +"276 kJ"#</mathjax></p> <blockquote> <p>This means that when <mathjax>#1#</mathjax> <strong>mole</strong> of water undergoes decomposition, <mathjax>#"276 kJ"#</mathjax> of heat are being <strong>absorbed</strong>!</p> </blockquote> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">When 2 moles of #H_2(g)# and 1 mole of #O_2(g)# react to give liquid water, 572 kJ of heat evolve. #2H_2(g)# + #O_2(g)# #rarr# #2H_2O(l)# ; #DeltaH# = -572 kJ a) What is the themochemical eq. for 1 mole of liquid water? </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>b) Write the reverse thermochemical equation in which 1 mole of liquid water disassociates into hydrogen and oxygen gas.<br/> Thank you so much for your help. :)</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/enthalpy" itemprop="url"> <span class="breadcrumb" itemprop="title">Enthalpy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="559661" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-02-27T23:46:09" itemprop="dateCreated"> Feb 27, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"H"_ (2(g)) + 1/2"O"_ (2(g)) -&gt; "H"_ 2"O"_ ((l))" " DeltaH = -"276 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You know that when <mathjax>#2#</mathjax> <strong>moles</strong> of hydrogen gas react with <mathjax>#1#</mathjax> <strong>mole</strong> of oxygen gas, you get <mathjax>#2#</mathjax> <strong>moles</strong> of water and <mathjax>#"572 kJ"#</mathjax> of heat are <strong>evolved</strong>. </p> <blockquote> <p><mathjax>#2"H"_ (2(g)) + "O"_ (2(g)) -&gt; 2"H"_ 2"O"_ ((l))" "DeltaH = -"572 kJ"#</mathjax></p> <blockquote> <p>Don't forget that the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change of reaction must be <strong>negative</strong> here to illustrate the fact that heat if being <strong>given off</strong> by the reaction. </p> </blockquote> </blockquote> <p>Now, in order for this reaction to produce <mathjax>#1#</mathjax> <strong>mole</strong> of water, all the coefficients of the chemical equation must be <strong>halved</strong>.</p> <blockquote> <p><mathjax>#(1/2 * 2)"H"_ (2(g)) + 1/2"O"_( 2(g)) -&gt; (1/2 * 2)"H"_ 2"O"_ ((l))#</mathjax></p> </blockquote> <p>This will get you </p> <blockquote> <p><mathjax>#"H"_ (2(g)) + 1/2"O"_ (2(g)) -&gt; "H"_ 2"O"_ ((l))#</mathjax></p> </blockquote> <p>Now, the enthalpy change for this reaction will be <strong>half</strong> the value of the enthalpy change for the reaction that produced <mathjax>#2#</mathjax> <strong>moles</strong> of water. </p> <blockquote> <p><mathjax>#DeltaH_ ("1 mole H"_ 2"O") = 1/2 * DeltaH_ ("2 moles H"_ 2"O")#</mathjax></p> <p><mathjax>#DeltaH_ ("1 mole H"- 2"O") = (-"572 kJ")/2 = -"286 kJ"#</mathjax></p> </blockquote> <p>This means that the <strong>thermochemical equation</strong> that describes the formation of <mathjax>#1#</mathjax> <strong>mole</strong> of water looks like this</p> <blockquote> <p><mathjax>#"H"_ (2(g)) + 1/2"O"_ (2(g)) -&gt; "H"_ 2"O"_ ((l))" " DeltaH = -"276 kJ"#</mathjax></p> </blockquote> <p>To write the thermochemical equation that describes the <strong>decomposition</strong> of <mathjax>#1#</mathjax> <strong>mole</strong> of water into hydrogen gas and oxygen gas, you need to <em>reverse</em> the chemical equation</p> <blockquote> <p><mathjax>#"H"_ 2"O"_ ((l)) -&gt; "H"_ (2(g)) + 1/2"O"_ (2(g))#</mathjax></p> </blockquote> <p>and <strong>change the sign</strong> of the enthalpy change of reaction. </p> <blockquote> <p><mathjax>#DeltaH_"reverse" = -DeltaH_"forward"#</mathjax></p> </blockquote> <p>This means that the thermochemical equation will look like this</p> <blockquote> <p><mathjax>#"H"_ 2"O"_ ((l)) -&gt; "H"_ (2(g)) + 1/2"O"_ (2(g))" " DeltaH = +"276 kJ"#</mathjax></p> <blockquote> <p>This means that when <mathjax>#1#</mathjax> <strong>mole</strong> of water undergoes decomposition, <mathjax>#"276 kJ"#</mathjax> of heat are being <strong>absorbed</strong>!</p> </blockquote> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/559661" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-enthalpy-changes-expressed-in-chemical-equations"> How are enthalpy changes expressed in chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-enthalpy-change-be-determined-for-an-aqueous-solution"> How can enthalpy change be determined for an aqueous solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-change-with-pressure"> How does enthalpy change with pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-standard-molar-enthalpy-formation"> How do you calculate standard molar enthalpy of formation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-enthalpy-of-formation-of-oxygen-zero"> Why is the enthalpy of formation of oxygen zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function-2"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-enthalpy-cannot-be-measured-directly"> Why can enthalpy not be measured directly? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-pressure-affect-enthalpy"> How does pressure affect enthalpy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-relate-to-internal-energy"> How does enthalpy relate to internal energy? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/enthalpy"> See all questions in Enthalpy </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 49410 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

When 2 moles of #H_2(g)# and 1 mole of #O_2(g)# react to give liquid water, 572 kJ of heat evolve. #2H_2(g)# + #O_2(g)# #rarr# #2H_2O(l)# ; #DeltaH# = -572 kJ a) What is the themochemical eq. for 1 mole of liquid water?

b) Write the reverse thermochemical equation in which 1 mole of liquid water disassociates into hydrogen and oxygen gas. Thank you so much for your help. :)

a9fb9f8a-6ddd-11ea-9658-ccda262736ce

https://socratic.org/questions/if-26-03-g-of-water-showed-a-temperature-increase-of-102-c-upon-addition-of-hot-

11.15 kJ

start physical_unit 4 4 heat_energy kj qc_end physical_unit 4 4 1 2 mass qc_end physical_unit 4 4 10 11 temperature qc_end end

[{"type":"physical unit","value":"Heat change [OF] water [IN] kJ"}]

[{"type":"physical unit","value":"11.15 kJ"}]

[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{26.03 g}"},{"type":"physical unit","value":"Increased temperature [OF] water [=] \\pu{102 ℃}"}]

<h1 class="questionTitle" itemprop="name">If 26.03 g of water showed a temperature increase of 102°C upon addition of hot metal, what is the heat change for the water?</h1>

11.15 kJ

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I would go for:<br/> <mathjax>#Q=mcDeltaT#</mathjax><br/> where:<br/> <mathjax>#Q=#</mathjax> heat gained or lost;<br/> <mathjax>#m=#</mathjax> mass;<br/> <mathjax>#c=#</mathjax> heat capacity of the specific material (<mathjax>#4.2J/(gK)#</mathjax> for water);<br/> <mathjax>#DeltaT=#</mathjax> change in temperature.</p> <p>in your case:</p> <p><mathjax>#Q=26.03*4.2*102=11,151.2J~~11kJ#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I found <mathjax>#11kJ#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I would go for:<br/> <mathjax>#Q=mcDeltaT#</mathjax><br/> where:<br/> <mathjax>#Q=#</mathjax> heat gained or lost;<br/> <mathjax>#m=#</mathjax> mass;<br/> <mathjax>#c=#</mathjax> heat capacity of the specific material (<mathjax>#4.2J/(gK)#</mathjax> for water);<br/> <mathjax>#DeltaT=#</mathjax> change in temperature.</p> <p>in your case:</p> <p><mathjax>#Q=26.03*4.2*102=11,151.2J~~11kJ#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If 26.03 g of water showed a temperature increase of 102°C upon addition of hot metal, what is the heat change for the water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="215929" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/gio"><img alt="" class="" src="https://profilepictures.socratic.org/PDAQ7XlwRXWLdTy9hfbV_kuruma.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/gio"> Gió </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-23T11:09:02" itemprop="dateCreated"> Jan 23, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I found <mathjax>#11kJ#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I would go for:<br/> <mathjax>#Q=mcDeltaT#</mathjax><br/> where:<br/> <mathjax>#Q=#</mathjax> heat gained or lost;<br/> <mathjax>#m=#</mathjax> mass;<br/> <mathjax>#c=#</mathjax> heat capacity of the specific material (<mathjax>#4.2J/(gK)#</mathjax> for water);<br/> <mathjax>#DeltaT=#</mathjax> change in temperature.</p> <p>in your case:</p> <p><mathjax>#Q=26.03*4.2*102=11,151.2J~~11kJ#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/215929" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? 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If 26.03 g of water showed a temperature increase of 102°C upon addition of hot metal, what is the heat change for the water?

abfd987a-6ddd-11ea-b7c9-ccda262736ce

https://socratic.org/questions/an-exothermic-reaction-releases-86-5-kj-how-many-kilocalories-of-energy-are-rele

20.67 kilocalories

start physical_unit 1 2 heat_energy kcal qc_end physical_unit 1 2 4 5 heat_energy qc_end end

[{"type":"physical unit","value":"Released energy [OF] the exothermic reaction [IN] kilocalories"}]

[{"type":"physical unit","value":"20.67 kilocalories"}]

[{"type":"physical unit","value":"Released energy [OF] the exothermic reaction [=] \\pu{86.5 kJ}"}]

<h1 class="questionTitle" itemprop="name">An exothermic reaction releases 86.5 kJ. How many kilocalories of energy are released?</h1>

20.67 kilocalories

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This problem is just a unit conversion, so you need to know the definition of a calorie. A calorie is a unit of energy equal to 4.184 J. This is the energy required to heat up one gram of water by one degree celsius at a pressure of one atmosphere. If 1 cal = 4.184 J, then 1000 cal = 4184 J. <br/> Therefore:</p> <p><mathjax>#1 " kcal"=4.184" kJ"#</mathjax> </p> <p>Divide both sides by 4.184 to get kJ in terms of kcal.</p> <p><mathjax>#1 " kJ"=0.239" kcal"#</mathjax> </p> <p>Now you have your conversion factor and just need to multiply both sides by 86.5.</p> <p><mathjax>#1*86.5 " kJ"=0.239*86.5" kcal"#</mathjax> </p> <p><mathjax>#86.5 " kJ"=20.7" kcal"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1 " kJ"=0.239" kcal"#</mathjax></p> <p><mathjax>#86.5 " kJ"=86.5*0.239=20.7" kcal"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This problem is just a unit conversion, so you need to know the definition of a calorie. A calorie is a unit of energy equal to 4.184 J. This is the energy required to heat up one gram of water by one degree celsius at a pressure of one atmosphere. If 1 cal = 4.184 J, then 1000 cal = 4184 J. <br/> Therefore:</p> <p><mathjax>#1 " kcal"=4.184" kJ"#</mathjax> </p> <p>Divide both sides by 4.184 to get kJ in terms of kcal.</p> <p><mathjax>#1 " kJ"=0.239" kcal"#</mathjax> </p> <p>Now you have your conversion factor and just need to multiply both sides by 86.5.</p> <p><mathjax>#1*86.5 " kJ"=0.239*86.5" kcal"#</mathjax> </p> <p><mathjax>#86.5 " kJ"=20.7" kcal"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">An exothermic reaction releases 86.5 kJ. How many kilocalories of energy are released?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="420152" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/peter-m-8"><img alt="" class="" src="https://lh6.googleusercontent.com/-8YyKx7wqg0I/AAAAAAAAAAI/AAAAAAAAACo/JWBHiurCais/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/peter-m-8"> Peter M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-09T07:25:45" itemprop="dateCreated"> May 9, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1 " kJ"=0.239" kcal"#</mathjax></p> <p><mathjax>#86.5 " kJ"=86.5*0.239=20.7" kcal"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This problem is just a unit conversion, so you need to know the definition of a calorie. A calorie is a unit of energy equal to 4.184 J. This is the energy required to heat up one gram of water by one degree celsius at a pressure of one atmosphere. If 1 cal = 4.184 J, then 1000 cal = 4184 J. <br/> Therefore:</p> <p><mathjax>#1 " kcal"=4.184" kJ"#</mathjax> </p> <p>Divide both sides by 4.184 to get kJ in terms of kcal.</p> <p><mathjax>#1 " kJ"=0.239" kcal"#</mathjax> </p> <p>Now you have your conversion factor and just need to multiply both sides by 86.5.</p> <p><mathjax>#1*86.5 " kJ"=0.239*86.5" kcal"#</mathjax> </p> <p><mathjax>#86.5 " kJ"=20.7" kcal"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/420152" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 15348 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

An exothermic reaction releases 86.5 kJ. How many kilocalories of energy are released?

a989abdc-6ddd-11ea-b9f0-ccda262736ce

https://socratic.org/questions/water-2290-g-is-heated-until-it-just-begins-to-boil-if-the-water-absorbs-5-47x10

42.86 ℃

start physical_unit 12 13 temperature °c qc_end c_other OTHER qc_end physical_unit 0 0 1 2 mass qc_end physical_unit 12 13 15 18 heat_energy qc_end end

[{"type":"physical unit","value":"Temperature1 [OF] the water [IN] ℃"}]

[{"type":"physical unit","value":"42.86 ℃"}]

[{"type":"other","value":"Water is heated until it just begins to boil."},{"type":"physical unit","value":"Mass [OF] water [=] \\pu{2290 g}"},{"type":"physical unit","value":"Absorbed heat [OF] the water [=] \\pu{5.47 × 10^5 J}"}]

<h1 class="questionTitle" itemprop="name">Water (2290 g) is heated until it just begins to boil. If the water absorbs #5.47xx10^5 J# of heat in the process what was the initial temperature of the water?</h1>

42.86 ℃

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the problem is providing you with the amount of heat needed to raise the temperature of a given sample of water from an initial temperature to its <strong>boiling point</strong>, i.e. to <mathjax>#100^@"C"#</mathjax>. </p> <p>This tells you that the first thing to do here is to calculate the <em>change in temperature</em> that occurs when you provide <mathjax>#5.47 * 10^5"J"#</mathjax> of heat to <mathjax>#"2290 g"#</mathjax> of water. </p> <p>Your tool of choice here will this equation</p> <blockquote> <p><mathjax>#color(blue)(bar(ul(|color(white)(a/a)q = m * c * DeltaTcolor(white)(a/a)|)))" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - the amount of heat gained<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of the substance<br/> <mathjax>#DeltaT#</mathjax> - the <em>change in temperature</em>, defined as the difference between the <strong>final temperature</strong> and the <strong>initial temperature</strong></p> <p>Water has a <strong><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a></strong> of <mathjax>#"4.18 J g"^(-1)""^@"C"^(-1)#</mathjax></p> <p><a href="http://www.engineeringtoolbox.com/water-thermal-properties-d_162.html" rel="nofollow" target="_blank">http://www.engineeringtoolbox.com/water-thermal-properties-d_162.html</a></p> <p>Rearrange the equation to solve for <mathjax>#DeltaT#</mathjax></p> <blockquote> <p><mathjax>#q = m * c * DeltaT implies DeltaT = q/(m * c)#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#DeltaT = (5.47 * 10^5 color(red)(cancel(color(black)("J"))))/(2290 color(red)(cancel(color(black)("g"))) * 4.18 color(red)(cancel(color(black)("J"))) color(red)(cancel(color(black)("g"^(-1))))""^@"C"^(-1)) = 57.14^@"C"#</mathjax></p> </blockquote> <p>So, you know that the final temperature of the water is <mathjax>#100^@"C"#</mathjax> and that this final temperature is <mathjax>#57.14^@"C"#</mathjax> <strong>higher</strong> than the initial temperature of the sample.</p> <p>You can thus say that you have</p> <blockquote> <p><mathjax>#DeltaT = T_"f" - T_"i"#</mathjax></p> </blockquote> <p>and </p> <blockquote> <p><mathjax>#T_"i" = T_"f" - DeltaT#</mathjax></p> <p><mathjax>#T_"i" = 100^@"C" - 57.14^@"C" = color(green)(bar(ul(|color(white)(a/a)color(black)(42.9^@"C")color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> and one decimal place.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#42.9^@"C"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the problem is providing you with the amount of heat needed to raise the temperature of a given sample of water from an initial temperature to its <strong>boiling point</strong>, i.e. to <mathjax>#100^@"C"#</mathjax>. </p> <p>This tells you that the first thing to do here is to calculate the <em>change in temperature</em> that occurs when you provide <mathjax>#5.47 * 10^5"J"#</mathjax> of heat to <mathjax>#"2290 g"#</mathjax> of water. </p> <p>Your tool of choice here will this equation</p> <blockquote> <p><mathjax>#color(blue)(bar(ul(|color(white)(a/a)q = m * c * DeltaTcolor(white)(a/a)|)))" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - the amount of heat gained<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of the substance<br/> <mathjax>#DeltaT#</mathjax> - the <em>change in temperature</em>, defined as the difference between the <strong>final temperature</strong> and the <strong>initial temperature</strong></p> <p>Water has a <strong><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a></strong> of <mathjax>#"4.18 J g"^(-1)""^@"C"^(-1)#</mathjax></p> <p><a href="http://www.engineeringtoolbox.com/water-thermal-properties-d_162.html" rel="nofollow" target="_blank">http://www.engineeringtoolbox.com/water-thermal-properties-d_162.html</a></p> <p>Rearrange the equation to solve for <mathjax>#DeltaT#</mathjax></p> <blockquote> <p><mathjax>#q = m * c * DeltaT implies DeltaT = q/(m * c)#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#DeltaT = (5.47 * 10^5 color(red)(cancel(color(black)("J"))))/(2290 color(red)(cancel(color(black)("g"))) * 4.18 color(red)(cancel(color(black)("J"))) color(red)(cancel(color(black)("g"^(-1))))""^@"C"^(-1)) = 57.14^@"C"#</mathjax></p> </blockquote> <p>So, you know that the final temperature of the water is <mathjax>#100^@"C"#</mathjax> and that this final temperature is <mathjax>#57.14^@"C"#</mathjax> <strong>higher</strong> than the initial temperature of the sample.</p> <p>You can thus say that you have</p> <blockquote> <p><mathjax>#DeltaT = T_"f" - T_"i"#</mathjax></p> </blockquote> <p>and </p> <blockquote> <p><mathjax>#T_"i" = T_"f" - DeltaT#</mathjax></p> <p><mathjax>#T_"i" = 100^@"C" - 57.14^@"C" = color(green)(bar(ul(|color(white)(a/a)color(black)(42.9^@"C")color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> and one decimal place.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Water (2290 g) is heated until it just begins to boil. If the water absorbs #5.47xx10^5 J# of heat in the process what was the initial temperature of the water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="310647" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-15T22:58:40" itemprop="dateCreated"> Sep 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#42.9^@"C"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that the problem is providing you with the amount of heat needed to raise the temperature of a given sample of water from an initial temperature to its <strong>boiling point</strong>, i.e. to <mathjax>#100^@"C"#</mathjax>. </p> <p>This tells you that the first thing to do here is to calculate the <em>change in temperature</em> that occurs when you provide <mathjax>#5.47 * 10^5"J"#</mathjax> of heat to <mathjax>#"2290 g"#</mathjax> of water. </p> <p>Your tool of choice here will this equation</p> <blockquote> <p><mathjax>#color(blue)(bar(ul(|color(white)(a/a)q = m * c * DeltaTcolor(white)(a/a)|)))" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - the amount of heat gained<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of the substance<br/> <mathjax>#DeltaT#</mathjax> - the <em>change in temperature</em>, defined as the difference between the <strong>final temperature</strong> and the <strong>initial temperature</strong></p> <p>Water has a <strong><a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a></strong> of <mathjax>#"4.18 J g"^(-1)""^@"C"^(-1)#</mathjax></p> <p><a href="http://www.engineeringtoolbox.com/water-thermal-properties-d_162.html" rel="nofollow" target="_blank">http://www.engineeringtoolbox.com/water-thermal-properties-d_162.html</a></p> <p>Rearrange the equation to solve for <mathjax>#DeltaT#</mathjax></p> <blockquote> <p><mathjax>#q = m * c * DeltaT implies DeltaT = q/(m * c)#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#DeltaT = (5.47 * 10^5 color(red)(cancel(color(black)("J"))))/(2290 color(red)(cancel(color(black)("g"))) * 4.18 color(red)(cancel(color(black)("J"))) color(red)(cancel(color(black)("g"^(-1))))""^@"C"^(-1)) = 57.14^@"C"#</mathjax></p> </blockquote> <p>So, you know that the final temperature of the water is <mathjax>#100^@"C"#</mathjax> and that this final temperature is <mathjax>#57.14^@"C"#</mathjax> <strong>higher</strong> than the initial temperature of the sample.</p> <p>You can thus say that you have</p> <blockquote> <p><mathjax>#DeltaT = T_"f" - T_"i"#</mathjax></p> </blockquote> <p>and </p> <blockquote> <p><mathjax>#T_"i" = T_"f" - DeltaT#</mathjax></p> <p><mathjax>#T_"i" = 100^@"C" - 57.14^@"C" = color(green)(bar(ul(|color(white)(a/a)color(black)(42.9^@"C")color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> and one decimal place.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/310647" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-read-differential-scanning-in-calorimetry"> What information do you get from a differential scanning calorimetry plot? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-calorimetry"> How do you measure calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531d304102bf341e75b962a7"> Question #962a7 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5335021802bf344ae911dfc5"> Question #1dfc5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668f502bf34572c341af6"> Question #41af6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-definition-of-calorimetry"> What is calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-differential-scanning-calorimeter"> What is a differential scanning calorimeter? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-calorimeter-measure-energy"> How can a calorimeter measure energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-calorimeters-made-of"> What are calorimeters made of? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/calorimetry"> See all questions in Calorimetry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 35634 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

Water (2290 g) is heated until it just begins to boil. If the water absorbs #5.47xx10^5 J# of heat in the process what was the initial temperature of the water?

a982f9ac-6ddd-11ea-a94d-ccda262736ce

https://socratic.org/questions/once-ignited-it-will-produce-120-cubic-feet-of-o-2-at-0-5-psi-enough-to-support-

7.71 × 10^5 g

start physical_unit 29 29 mass g qc_end physical_unit 9 9 11 12 pressure qc_end physical_unit 9 9 5 7 volume qc_end physical_unit 42 43 16 16 number qc_end physical_unit 20 21 45 46 temperature qc_end c_other OTHER qc_end chemical_equation 62 66 qc_end end

[{"type":"physical unit","value":"Mass [OF] NaClO3 [IN] g"}]

[{"type":"physical unit","value":"7.71 × 10^5 g"}]

[{"type":"physical unit","value":"Number [OF] people [=] \\pu{100}"},{"type":"physical unit","value":"Pressure [OF] O2 [=] \\pu{0.5 psi}"},{"type":"physical unit","value":"Volume [OF] O2 [=] \\pu{120 cubic feet}"},{"type":"physical unit","value":"Number [OF] crew members [=] \\pu{100}"},{"type":"physical unit","value":"Temperature [OF] the equation [=] \\pu{300 K}"},{"type":"other","value":"Chlorate candles are used to produce emergency oxygen."},{"type":"chemical equation","value":"NaClO3(s) -> NaCl(s) + O2(g)"}]

<h1 class="questionTitle" itemprop="name">Once ignited, it will produce 120 cubic feet of #O_2# at 0.5 psi, enough to support 100 persons. After balancing the equation, how do you compute the mass of #NaClO_3# required to generate the moles of gas needed to support the 100 crew members at 300K?</h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>On submarines, chlorate candles are used to produce emergency oxygen. Once ignited, it decomposes via: <mathjax>#NaClO_3(s) -&gt; NaCl(s) + O_2(g)#</mathjax>. </p></div> </h2> </div> </div>

7.71 × 10^5 g

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Typically, this reaction is catalyzed by an oxygen transfer reagent, <mathjax>#MnO_2#</mathjax>. This is a very convenient preparation of laboratory oxygen (and also, as you say, on board a submarine or submersible! This is not a use of which I would like to have experience.)</p> <p>Your question is rather open-ended, so I will try to address it like this. <a href="http://health.howstuffworks.com/human-body/systems/respiratory/question98.htm" rel="nofollow">From this site</a>, we learn that the average punter consumes <mathjax>#11#</mathjax> <mathjax>#m^3#</mathjax> of oxygen gas per day. This is <mathjax>#11xx10^3*L#</mathjax>.</p> <p>Given that <mathjax>#n=(PV)/(RT)#</mathjax> <mathjax>#=#</mathjax> </p> <p><mathjax>#(21%xx1*atmxx11xx10^3*L)/(0.0821*L*atm*K^-1*mol^-1xx298*K)#</mathjax></p> <p><mathjax>#=94.4*mol#</mathjax></p> <p>So, for each man, we need AT LEAST, <mathjax>#2/3xx94.4*molxx122.55*g*mol^-1=7.71xx10^3*g#</mathjax>, call it <mathjax>#8*kg#</mathjax> per day. For 100 persons, that's about a tonne of oxygen candles daily. I don't think this could be done realistically. </p> <p>You are certainly free to question my assumptions, and calculations, but I suspect that oxygen candles were supplied to the sailors who manned midget submarines, i.e. with a crew of 1-2, where storage of <mathjax>#100*kg#</mathjax> or so of sodium chlorate might be feasible. The sailors who did this, i.e. travelled with these quantities of potent oxidant into a war zone in a submersible, along with their explosives, were certainly brave and desperate men. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#NaClO_3(s) rarr NaCl(s) + 3/2O_2(g)uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Typically, this reaction is catalyzed by an oxygen transfer reagent, <mathjax>#MnO_2#</mathjax>. This is a very convenient preparation of laboratory oxygen (and also, as you say, on board a submarine or submersible! This is not a use of which I would like to have experience.)</p> <p>Your question is rather open-ended, so I will try to address it like this. <a href="http://health.howstuffworks.com/human-body/systems/respiratory/question98.htm" rel="nofollow">From this site</a>, we learn that the average punter consumes <mathjax>#11#</mathjax> <mathjax>#m^3#</mathjax> of oxygen gas per day. This is <mathjax>#11xx10^3*L#</mathjax>.</p> <p>Given that <mathjax>#n=(PV)/(RT)#</mathjax> <mathjax>#=#</mathjax> </p> <p><mathjax>#(21%xx1*atmxx11xx10^3*L)/(0.0821*L*atm*K^-1*mol^-1xx298*K)#</mathjax></p> <p><mathjax>#=94.4*mol#</mathjax></p> <p>So, for each man, we need AT LEAST, <mathjax>#2/3xx94.4*molxx122.55*g*mol^-1=7.71xx10^3*g#</mathjax>, call it <mathjax>#8*kg#</mathjax> per day. For 100 persons, that's about a tonne of oxygen candles daily. I don't think this could be done realistically. </p> <p>You are certainly free to question my assumptions, and calculations, but I suspect that oxygen candles were supplied to the sailors who manned midget submarines, i.e. with a crew of 1-2, where storage of <mathjax>#100*kg#</mathjax> or so of sodium chlorate might be feasible. The sailors who did this, i.e. travelled with these quantities of potent oxidant into a war zone in a submersible, along with their explosives, were certainly brave and desperate men. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Once ignited, it will produce 120 cubic feet of #O_2# at 0.5 psi, enough to support 100 persons. After balancing the equation, how do you compute the mass of #NaClO_3# required to generate the moles of gas needed to support the 100 crew members at 300K?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>On submarines, chlorate candles are used to produce emergency oxygen. Once ignited, it decomposes via: <mathjax>#NaClO_3(s) -&gt; NaCl(s) + O_2(g)#</mathjax>. </p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="353219" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-17T14:13:01" itemprop="dateCreated"> Dec 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#NaClO_3(s) rarr NaCl(s) + 3/2O_2(g)uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Typically, this reaction is catalyzed by an oxygen transfer reagent, <mathjax>#MnO_2#</mathjax>. This is a very convenient preparation of laboratory oxygen (and also, as you say, on board a submarine or submersible! This is not a use of which I would like to have experience.)</p> <p>Your question is rather open-ended, so I will try to address it like this. <a href="http://health.howstuffworks.com/human-body/systems/respiratory/question98.htm" rel="nofollow">From this site</a>, we learn that the average punter consumes <mathjax>#11#</mathjax> <mathjax>#m^3#</mathjax> of oxygen gas per day. This is <mathjax>#11xx10^3*L#</mathjax>.</p> <p>Given that <mathjax>#n=(PV)/(RT)#</mathjax> <mathjax>#=#</mathjax> </p> <p><mathjax>#(21%xx1*atmxx11xx10^3*L)/(0.0821*L*atm*K^-1*mol^-1xx298*K)#</mathjax></p> <p><mathjax>#=94.4*mol#</mathjax></p> <p>So, for each man, we need AT LEAST, <mathjax>#2/3xx94.4*molxx122.55*g*mol^-1=7.71xx10^3*g#</mathjax>, call it <mathjax>#8*kg#</mathjax> per day. For 100 persons, that's about a tonne of oxygen candles daily. I don't think this could be done realistically. </p> <p>You are certainly free to question my assumptions, and calculations, but I suspect that oxygen candles were supplied to the sailors who manned midget submarines, i.e. with a crew of 1-2, where storage of <mathjax>#100*kg#</mathjax> or so of sodium chlorate might be feasible. The sailors who did this, i.e. travelled with these quantities of potent oxidant into a war zone in a submersible, along with their explosives, were certainly brave and desperate men. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/353219" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179102bf3469517a1072"> Question #a1072 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179402bf34694c8c5bf1"> Question #c5bf1 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179702bf3469588dc373"> Question #dc373 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179c02bf34694c8c5bf9"> Question #c5bf9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417a302bf3469517a1076"> Question #a1076 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417c702bf3469588dc377"> Question #dc377 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d002bf346963eb984f"> Question #b984f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d402bf346950519ea3"> Question #19ea3 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/mole-ratios"> See all questions in Mole Ratios </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1521 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

Once ignited, it will produce 120 cubic feet of #O_2# at 0.5 psi, enough to support 100 persons. After balancing the equation, how do you compute the mass of #NaClO_3# required to generate the moles of gas needed to support the 100 crew members at 300K?

On submarines, chlorate candles are used to produce emergency oxygen. Once ignited, it decomposes via: #NaClO_3(s) -&gt; NaCl(s) + O_2(g)#.

aaeabe8a-6ddd-11ea-b6f4-ccda262736ce

https://socratic.org/questions/58d3dc28b72cff2e15eb8836

3.29 g

start physical_unit 19 20 mass g qc_end physical_unit 5 6 1 2 volume qc_end physical_unit 5 6 10 10 ph qc_end physical_unit 5 6 14 15 [nh3] qc_end end

[{"type":"physical unit","value":"Mass [OF] ammonium chloride [IN] g"}]

[{"type":"physical unit","value":"3.29 g"}]

[{"type":"physical unit","value":"Volume [OF] ammonia/ammonium buffer [=] \\pu{0.500 L}"},{"type":"physical unit","value":"pH [OF] ammonia/ammonium buffer [=] \\pu{9.15}"},{"type":"physical unit","value":"[NH3] [OF] ammonia/ammonium buffer [=] \\pu{0.10 mol/L}"}]

<h1 class="questionTitle" itemprop="name">An #0.500*L# volume of ammonia/ammonium buffer has #pH=9.15#. If #[NH_3]=0.10*mol*L^-1#, what MASS of ammonium chloride does this buffer contain?</h1>

3.29 g

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Now for <mathjax>#"ammonium ion"#</mathjax> in water <mathjax>#pK_a=9.24#</mathjax></p> <p>And thus, <mathjax>#9.15=9.24+log_10{[[NH_3]]/[[NH_4^+]]}#</mathjax></p> <p>Clearly, <mathjax>#log_10{[[NH_3]]/[[NH_4^+]]}=-0.09#</mathjax></p> <p>And so, <mathjax>#[[NH_3]]/[[NH_4^+]]=10^(-0.09)=0.813#</mathjax></p> <p>And given that <mathjax>#[NH_3]=0.10*mol*L^-1#</mathjax>, <mathjax>#[NH_4^+]=0.123*mol*L^-1#</mathjax>.</p> <p>Because the volume of the solution was specified to be <mathjax>#0.500*L#</mathjax>, there were <mathjax>#0.500*Lxx0.123*mol*L^-1=0.0615*mol#</mathjax>, i,e, <mathjax>#0.0615*molxx53.49*g*mol^-1=3.29*g#</mathjax>.</p> <p>For the derivation of the <mathjax>#"buffer equation"#</mathjax>, see <a href="https://socratic.org/questions/how-do-buffers-maintain-ph">here for details.</a> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We use the buffer equation, <mathjax>#pH=pK_a+log_10{[[NH_3]]/[[NH_4^+]]}#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Now for <mathjax>#"ammonium ion"#</mathjax> in water <mathjax>#pK_a=9.24#</mathjax></p> <p>And thus, <mathjax>#9.15=9.24+log_10{[[NH_3]]/[[NH_4^+]]}#</mathjax></p> <p>Clearly, <mathjax>#log_10{[[NH_3]]/[[NH_4^+]]}=-0.09#</mathjax></p> <p>And so, <mathjax>#[[NH_3]]/[[NH_4^+]]=10^(-0.09)=0.813#</mathjax></p> <p>And given that <mathjax>#[NH_3]=0.10*mol*L^-1#</mathjax>, <mathjax>#[NH_4^+]=0.123*mol*L^-1#</mathjax>.</p> <p>Because the volume of the solution was specified to be <mathjax>#0.500*L#</mathjax>, there were <mathjax>#0.500*Lxx0.123*mol*L^-1=0.0615*mol#</mathjax>, i,e, <mathjax>#0.0615*molxx53.49*g*mol^-1=3.29*g#</mathjax>.</p> <p>For the derivation of the <mathjax>#"buffer equation"#</mathjax>, see <a href="https://socratic.org/questions/how-do-buffers-maintain-ph">here for details.</a> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">An #0.500*L# volume of ammonia/ammonium buffer has #pH=9.15#. If #[NH_3]=0.10*mol*L^-1#, what MASS of ammonium chloride does this buffer contain?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/buffer-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Buffer Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="396167" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-25T07:58:57" itemprop="dateCreated"> Mar 25, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We use the buffer equation, <mathjax>#pH=pK_a+log_10{[[NH_3]]/[[NH_4^+]]}#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Now for <mathjax>#"ammonium ion"#</mathjax> in water <mathjax>#pK_a=9.24#</mathjax></p> <p>And thus, <mathjax>#9.15=9.24+log_10{[[NH_3]]/[[NH_4^+]]}#</mathjax></p> <p>Clearly, <mathjax>#log_10{[[NH_3]]/[[NH_4^+]]}=-0.09#</mathjax></p> <p>And so, <mathjax>#[[NH_3]]/[[NH_4^+]]=10^(-0.09)=0.813#</mathjax></p> <p>And given that <mathjax>#[NH_3]=0.10*mol*L^-1#</mathjax>, <mathjax>#[NH_4^+]=0.123*mol*L^-1#</mathjax>.</p> <p>Because the volume of the solution was specified to be <mathjax>#0.500*L#</mathjax>, there were <mathjax>#0.500*Lxx0.123*mol*L^-1=0.0615*mol#</mathjax>, i,e, <mathjax>#0.0615*molxx53.49*g*mol^-1=3.29*g#</mathjax>.</p> <p>For the derivation of the <mathjax>#"buffer equation"#</mathjax>, see <a href="https://socratic.org/questions/how-do-buffers-maintain-ph">here for details.</a> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/396167" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-buffer-solutions-used"> How are buffer solutions used? 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An #0.500*L# volume of ammonia/ammonium buffer has #pH=9.15#. If #[NH_3]=0.10*mol*L^-1#, what MASS of ammonium chloride does this buffer contain?

ad0ea5c6-6ddd-11ea-919a-ccda262736ce

https://socratic.org/questions/how-many-chloride-ions-are-there-in-4-50-mol-of-aluminum-chloride

8.13 × 10^24

start physical_unit 2 3 number none qc_end physical_unit 10 11 7 8 mole qc_end end

[{"type":"physical unit","value":"Number [OF] chloride ions"}]

[{"type":"physical unit","value":"8.13 × 10^24"}]

[{"type":"physical unit","value":"Mole [OF] aluminum chloride [=] \\pu{4.50 mol}"}]

<h1 class="questionTitle" itemprop="name">How many chloride ions are there in 4.50 mol of aluminum chloride?</h1>

8.13 × 10^24

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So <mathjax>#4.50#</mathjax> mol <mathjax>#AlCl_3harr3xx4.50=13.50#</mathjax> mol <mathjax>#Cl^-#</mathjax></p> <p>1 mol contains <mathjax>#~~6.02xx10^23#</mathjax> particles, so the answer is:</p> <p><mathjax>#n_(Cl^-)=13.50xx6.02xx10^23=81.27xx10^23~~8.13xx10^24#</mathjax></p> <p>(rounded to 3 significant digit because of the <mathjax>#4.50#</mathjax>)</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1 mol aluminium chloride <mathjax>#AlCl_3#</mathjax> delivers 3 mol of <mathjax>#Cl^-#</mathjax> ions.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So <mathjax>#4.50#</mathjax> mol <mathjax>#AlCl_3harr3xx4.50=13.50#</mathjax> mol <mathjax>#Cl^-#</mathjax></p> <p>1 mol contains <mathjax>#~~6.02xx10^23#</mathjax> particles, so the answer is:</p> <p><mathjax>#n_(Cl^-)=13.50xx6.02xx10^23=81.27xx10^23~~8.13xx10^24#</mathjax></p> <p>(rounded to 3 significant digit because of the <mathjax>#4.50#</mathjax>)</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many chloride ions are there in 4.50 mol of aluminum chloride?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="277181" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meneernask"><img alt="" class="" src="https://profilepictures.socratic.org/gpA0lokRGK9vLVUnAMAy_meneernask.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meneernask"> MeneerNask </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-14T09:16:36" itemprop="dateCreated"> Jun 14, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>1 mol aluminium chloride <mathjax>#AlCl_3#</mathjax> delivers 3 mol of <mathjax>#Cl^-#</mathjax> ions.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So <mathjax>#4.50#</mathjax> mol <mathjax>#AlCl_3harr3xx4.50=13.50#</mathjax> mol <mathjax>#Cl^-#</mathjax></p> <p>1 mol contains <mathjax>#~~6.02xx10^23#</mathjax> particles, so the answer is:</p> <p><mathjax>#n_(Cl^-)=13.50xx6.02xx10^23=81.27xx10^23~~8.13xx10^24#</mathjax></p> <p>(rounded to 3 significant digit because of the <mathjax>#4.50#</mathjax>)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/277181" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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How many chloride ions are there in 4.50 mol of aluminum chloride?

abfb77a9-6ddd-11ea-95a3-ccda262736ce

https://socratic.org/questions/what-would-be-the-volume-of-6-00-g-of-helium-gas-at-stp

33.6 L

start physical_unit 9 10 volume l qc_end physical_unit 9 10 6 7 mass qc_end c_other STP qc_end end

[{"type":"physical unit","value":"Volume [OF] helium gas [IN] L"}]

[{"type":"physical unit","value":"33.6 L"}]

[{"type":"physical unit","value":"Mass [OF] helium gas [=] \\pu{6.00 g}"},{"type":"other","value":"STP"}]

<h1 class="questionTitle" itemprop="name">What would be the volume of 6.00 g of helium gas at STP?</h1>

33.6 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To answer this question, we'll need to use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a>:</p> <p><mathjax>#pV = nRT#</mathjax>,<br/> where <mathjax>#p#</mathjax> is pressure, <mathjax>#V#</mathjax> is volume, <mathjax>#n#</mathjax> is the number of moles <mathjax>#R#</mathjax> is the gas constant, and <mathjax>#T#</mathjax> is temperature in Kelvin.</p> <p>The question already gives us the values for <mathjax>#p#</mathjax> and <mathjax>#T#</mathjax>, because helium is at STP. This means that temperature is <mathjax>#"273.15 K"#</mathjax> and pressure is <mathjax>#"1 atm"#</mathjax>. </p> <p>We also already know the gas constant. In our case, we'll use the value of <mathjax>#"0.08206 L atm/K mol"#</mathjax> since these units fit the units of our given values the best. </p> <p>We can find the value for <mathjax>#n#</mathjax> by dividing the mass of helium gas by its molar mass: </p> <p><mathjax>#n = "number of moles" = "mass of sample"/"molar mass"#</mathjax><br/> <mathjax>#= "6.00 g"/"4.00 g/mol" = "1.50 mol"#</mathjax></p> <p>Now, we can just plug all of these values in and solve for <mathjax>#V#</mathjax>:</p> <p><mathjax>#pV = nRT#</mathjax></p> <p><mathjax>#V = (nRT)/p = ("1.50 mol" xx "0.08206 L atm/K mol" xx "273.15 K")/"1 atm"#</mathjax></p> <p><mathjax>#"= 33.6 L"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"33.6 L"#</mathjax>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To answer this question, we'll need to use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a>:</p> <p><mathjax>#pV = nRT#</mathjax>,<br/> where <mathjax>#p#</mathjax> is pressure, <mathjax>#V#</mathjax> is volume, <mathjax>#n#</mathjax> is the number of moles <mathjax>#R#</mathjax> is the gas constant, and <mathjax>#T#</mathjax> is temperature in Kelvin.</p> <p>The question already gives us the values for <mathjax>#p#</mathjax> and <mathjax>#T#</mathjax>, because helium is at STP. This means that temperature is <mathjax>#"273.15 K"#</mathjax> and pressure is <mathjax>#"1 atm"#</mathjax>. </p> <p>We also already know the gas constant. In our case, we'll use the value of <mathjax>#"0.08206 L atm/K mol"#</mathjax> since these units fit the units of our given values the best. </p> <p>We can find the value for <mathjax>#n#</mathjax> by dividing the mass of helium gas by its molar mass: </p> <p><mathjax>#n = "number of moles" = "mass of sample"/"molar mass"#</mathjax><br/> <mathjax>#= "6.00 g"/"4.00 g/mol" = "1.50 mol"#</mathjax></p> <p>Now, we can just plug all of these values in and solve for <mathjax>#V#</mathjax>:</p> <p><mathjax>#pV = nRT#</mathjax></p> <p><mathjax>#V = (nRT)/p = ("1.50 mol" xx "0.08206 L atm/K mol" xx "273.15 K")/"1 atm"#</mathjax></p> <p><mathjax>#"= 33.6 L"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What would be the volume of 6.00 g of helium gas at STP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="629030" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/z-15"><img alt="" class="" src="https://profilepictures.socratic.org/2RYTfnQ27oIM5G69ZmQg_chrome.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/z-15"> zhirou </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-12T06:31:47" itemprop="dateCreated"> Jun 12, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"33.6 L"#</mathjax>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>To answer this question, we'll need to use the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a>:</p> <p><mathjax>#pV = nRT#</mathjax>,<br/> where <mathjax>#p#</mathjax> is pressure, <mathjax>#V#</mathjax> is volume, <mathjax>#n#</mathjax> is the number of moles <mathjax>#R#</mathjax> is the gas constant, and <mathjax>#T#</mathjax> is temperature in Kelvin.</p> <p>The question already gives us the values for <mathjax>#p#</mathjax> and <mathjax>#T#</mathjax>, because helium is at STP. This means that temperature is <mathjax>#"273.15 K"#</mathjax> and pressure is <mathjax>#"1 atm"#</mathjax>. </p> <p>We also already know the gas constant. In our case, we'll use the value of <mathjax>#"0.08206 L atm/K mol"#</mathjax> since these units fit the units of our given values the best. </p> <p>We can find the value for <mathjax>#n#</mathjax> by dividing the mass of helium gas by its molar mass: </p> <p><mathjax>#n = "number of moles" = "mass of sample"/"molar mass"#</mathjax><br/> <mathjax>#= "6.00 g"/"4.00 g/mol" = "1.50 mol"#</mathjax></p> <p>Now, we can just plug all of these values in and solve for <mathjax>#V#</mathjax>:</p> <p><mathjax>#pV = nRT#</mathjax></p> <p><mathjax>#V = (nRT)/p = ("1.50 mol" xx "0.08206 L atm/K mol" xx "273.15 K")/"1 atm"#</mathjax></p> <p><mathjax>#"= 33.6 L"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/629030" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="629064" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/simon-moore"><img alt="" class="" src="https://profilepictures.socratic.org/0ztdJJ7RCWUlBSPeGa9N_6EB6CADA-35F5-4BAA-9B66-9D6F64A622BA.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/simon-moore"> Simon Moore </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-12T09:13:10" itemprop="dateCreated"> Jun 12, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>33.6 litres</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Assuming that helium behaves as an ideal gas, we know that a mole of ideal gas occupies 22.4 litres at STP.</p> <p>The atomic weight of helium is 4 g/mol, so 6 g is 1.5 moles. </p> <p>The volume occupied at STP, therefore, is 22.4 x 1.5 = 33.6 litres.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/629064" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? 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What would be the volume of 6.00 g of helium gas at STP?

ab68c69c-6ddd-11ea-bc13-ccda262736ce

https://socratic.org/questions/5789cfae11ef6b45dce62b76

0.56 mol/kg

start physical_unit 6 6 molality mol/kg qc_end physical_unit 12 12 9 10 mass qc_end physical_unit 18 18 15 16 mass qc_end end

[{"type":"physical unit","value":"Molality [OF] the solution [IN] mol/kg"}]

[{"type":"physical unit","value":"0.56 mol/kg"}]

[{"type":"physical unit","value":"Mass [OF] glucose [=] \\pu{3 g}"},{"type":"physical unit","value":"Mass [OF] water [=] \\pu{30 g}"}]

<h1 class="questionTitle" itemprop="name">What is the molality of a solution that contains #"3 g"# of glucose dissolved in #"30 g"# of water?</h1>

0.56 mol/kg

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">Molality</a></strong> is all about <em>moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em> dissolved <strong>per kilogram of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a></strong>. In other words, all you have to do in order to calculate a solution's molality is to find out how many moles of solute you have <strong>per kilogram of solvent</strong>. </p> <p>Use the <strong>molar mass</strong> of glucose, <mathjax>#"C"_6"H"_12"O"_6#</mathjax>, to determine how many <em>moles</em> are present in your sample</p> <blockquote> <p><mathjax>#3 color(red)(cancel(color(black)("g"))) * ("1 mole C"_6"H"_12"O"_6)/(180.16color(red)(cancel(color(black)("g")))) = "0.01665 moles C"_6"H"_12"O"_6#</mathjax></p> </blockquote> <p>Now, you know that this many moles of glucose, your <strong>solute</strong>, are dissolved in <mathjax>#"30 g"#</mathjax> of water, which is your <strong>solvent</strong>. </p> <p>Your goal now is to "scale up" this solution to <mathjax>#"1 kg"#</mathjax> of water by keeping the given <em>proportion</em> between the number of moles of solute and the mass of solvent. </p> <p>Convert the mass of water from <em>grams</em> to <em>kilograms</em></p> <blockquote> <p><mathjax>#30 color(red)(cancel(color(black)("g"))) * "1 kg"/(10^3color(red)(cancel(color(black)("g")))) = "0.030 kg"#</mathjax></p> </blockquote> <p>So, if <mathjax>#"0.030 kg"#</mathjax> of water contain <mathjax>#0.01665#</mathjax> *<em>moles8</em> of glucose, it follows that <mathjax>#"1 kg"#</mathjax> of water will contain </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("kg water"))) * ("0.01665 moles C"_6"H"_12"O"_6)/(0.030color(red)(cancel(color(black)("kg water")))) = "0.555 moles C"_6"H"_12"O"_6#</mathjax></p> </blockquote> <p>Therefore, you can say that the molality of the solution is </p> <blockquote> <p><mathjax>#"molality" = color(green)(|bar(ul(color(white)(a/a)color(black)("0.6 mol kg"^(-1) = "0.6 molal")color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>The answer must be rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a></strong>, the number of sig figs given to you for the mass of glucose and the mass of water. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.6 mol kg"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">Molality</a></strong> is all about <em>moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em> dissolved <strong>per kilogram of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a></strong>. In other words, all you have to do in order to calculate a solution's molality is to find out how many moles of solute you have <strong>per kilogram of solvent</strong>. </p> <p>Use the <strong>molar mass</strong> of glucose, <mathjax>#"C"_6"H"_12"O"_6#</mathjax>, to determine how many <em>moles</em> are present in your sample</p> <blockquote> <p><mathjax>#3 color(red)(cancel(color(black)("g"))) * ("1 mole C"_6"H"_12"O"_6)/(180.16color(red)(cancel(color(black)("g")))) = "0.01665 moles C"_6"H"_12"O"_6#</mathjax></p> </blockquote> <p>Now, you know that this many moles of glucose, your <strong>solute</strong>, are dissolved in <mathjax>#"30 g"#</mathjax> of water, which is your <strong>solvent</strong>. </p> <p>Your goal now is to "scale up" this solution to <mathjax>#"1 kg"#</mathjax> of water by keeping the given <em>proportion</em> between the number of moles of solute and the mass of solvent. </p> <p>Convert the mass of water from <em>grams</em> to <em>kilograms</em></p> <blockquote> <p><mathjax>#30 color(red)(cancel(color(black)("g"))) * "1 kg"/(10^3color(red)(cancel(color(black)("g")))) = "0.030 kg"#</mathjax></p> </blockquote> <p>So, if <mathjax>#"0.030 kg"#</mathjax> of water contain <mathjax>#0.01665#</mathjax> *<em>moles8</em> of glucose, it follows that <mathjax>#"1 kg"#</mathjax> of water will contain </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("kg water"))) * ("0.01665 moles C"_6"H"_12"O"_6)/(0.030color(red)(cancel(color(black)("kg water")))) = "0.555 moles C"_6"H"_12"O"_6#</mathjax></p> </blockquote> <p>Therefore, you can say that the molality of the solution is </p> <blockquote> <p><mathjax>#"molality" = color(green)(|bar(ul(color(white)(a/a)color(black)("0.6 mol kg"^(-1) = "0.6 molal")color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>The answer must be rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a></strong>, the number of sig figs given to you for the mass of glucose and the mass of water. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the molality of a solution that contains #"3 g"# of glucose dissolved in #"30 g"# of water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molality" itemprop="url"> <span class="breadcrumb" itemprop="title">Molality</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="288676" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-16T11:41:42" itemprop="dateCreated"> Jul 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"0.6 mol kg"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">Molality</a></strong> is all about <em>moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a></em> dissolved <strong>per kilogram of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a></strong>. In other words, all you have to do in order to calculate a solution's molality is to find out how many moles of solute you have <strong>per kilogram of solvent</strong>. </p> <p>Use the <strong>molar mass</strong> of glucose, <mathjax>#"C"_6"H"_12"O"_6#</mathjax>, to determine how many <em>moles</em> are present in your sample</p> <blockquote> <p><mathjax>#3 color(red)(cancel(color(black)("g"))) * ("1 mole C"_6"H"_12"O"_6)/(180.16color(red)(cancel(color(black)("g")))) = "0.01665 moles C"_6"H"_12"O"_6#</mathjax></p> </blockquote> <p>Now, you know that this many moles of glucose, your <strong>solute</strong>, are dissolved in <mathjax>#"30 g"#</mathjax> of water, which is your <strong>solvent</strong>. </p> <p>Your goal now is to "scale up" this solution to <mathjax>#"1 kg"#</mathjax> of water by keeping the given <em>proportion</em> between the number of moles of solute and the mass of solvent. </p> <p>Convert the mass of water from <em>grams</em> to <em>kilograms</em></p> <blockquote> <p><mathjax>#30 color(red)(cancel(color(black)("g"))) * "1 kg"/(10^3color(red)(cancel(color(black)("g")))) = "0.030 kg"#</mathjax></p> </blockquote> <p>So, if <mathjax>#"0.030 kg"#</mathjax> of water contain <mathjax>#0.01665#</mathjax> *<em>moles8</em> of glucose, it follows that <mathjax>#"1 kg"#</mathjax> of water will contain </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("kg water"))) * ("0.01665 moles C"_6"H"_12"O"_6)/(0.030color(red)(cancel(color(black)("kg water")))) = "0.555 moles C"_6"H"_12"O"_6#</mathjax></p> </blockquote> <p>Therefore, you can say that the molality of the solution is </p> <blockquote> <p><mathjax>#"molality" = color(green)(|bar(ul(color(white)(a/a)color(black)("0.6 mol kg"^(-1) = "0.6 molal")color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>The answer must be rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig fig</a></strong>, the number of sig figs given to you for the mass of glucose and the mass of water. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/288676" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-molality-and-molarity-differ"> How do molality and molarity differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molality-be"> How high can molality be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molality-from-molarity"> How do you calculate molality from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-molality-used-for-colligative-properties"> Why is molality used for colligative properties? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-molality-independent-of-temperature"> Why is molality independent of temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-molality-when-75-0-grams-of-mgcl2-is-dissolved-in-500-0-"> How can I calculate the molality when 75.0 grams of MgCl2 is dissolved in 500.0 g of solvent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/49-8-grams-of-ki-is-dissolved-in-1-00-kg-of-solvent-what-is-the-molality"> 49.8 grams of KI is dissolved in 1.00 kg of solvent. 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What is the molality of a solution that contains #"3 g"# of glucose dissolved in #"30 g"# of water?

a8d7a974-6ddd-11ea-9da6-ccda262736ce

https://socratic.org/questions/583d0f16b72cff28ad578588

3.99

start physical_unit 6 6 percent none qc_end substance 8 8 qc_end substance 13 13 qc_end end

[{"type":"physical unit","value":"Rate [OF] effusion"}]

[{"type":"physical unit","value":"3.99"}]

[{"type":"substance name","value":"Hydrogen"},{"type":"substance name","value":"Oxygen"}]

<h1 class="questionTitle" itemprop="name">How fast is the rate of effusion of hydrogen compared to that of oxygen?</h1>

3.99

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Graham's Law of Effusion</strong> is:</p> <blockquote> <p><mathjax>#color(blue)(bar(ul(|color(white)(a/a) "Rate"_1/"Rate"_2 = sqrt(M_2/M_1)color(white)(a/a)|)))" "#</mathjax></p> </blockquote> <p>The <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a></strong> is</p> <blockquote> <p><mathjax>#color(blue)(bar(ul(|color(white)(a/a) PV = nRT color(white)(a/a)|)))" "#</mathjax></p> </blockquote> <p>We can re-write this to get</p> <p><mathjax>#PV = (m/M)RT= (mRT)/M#</mathjax></p> <p><mathjax>#P = (m/V)((RT)/M) = (ρRT)/M#</mathjax></p> <p><mathjax>#M = (ρRT)/P#</mathjax></p> <blockquote></blockquote> <p>∴ <mathjax>#"Rate"_1/"Rate"_2 = sqrt(M_2/M_1) = sqrt((ρ_2(color(red)(cancel(color(black)((RT)/P)))))/(ρ_1color(red)(cancel(color(black)(((RT)/P))))) )=sqrt(ρ_2/ρ_1)#</mathjax></p> <p>Let component 1 be hydrogen and component 2 be oxygen.</p> <p><mathjax>#"Rate"_2/"Rate"_1 = sqrt((1.43 color(red)(cancel(color(black)("g/L"))))/(0.0899 color(red)(cancel(color(black)("g/L"))))) = sqrt15.9 = 3.99#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Rate"_text(H₂)/"Rate"_text(O₂) = 3.99#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Graham's Law of Effusion</strong> is:</p> <blockquote> <p><mathjax>#color(blue)(bar(ul(|color(white)(a/a) "Rate"_1/"Rate"_2 = sqrt(M_2/M_1)color(white)(a/a)|)))" "#</mathjax></p> </blockquote> <p>The <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a></strong> is</p> <blockquote> <p><mathjax>#color(blue)(bar(ul(|color(white)(a/a) PV = nRT color(white)(a/a)|)))" "#</mathjax></p> </blockquote> <p>We can re-write this to get</p> <p><mathjax>#PV = (m/M)RT= (mRT)/M#</mathjax></p> <p><mathjax>#P = (m/V)((RT)/M) = (ρRT)/M#</mathjax></p> <p><mathjax>#M = (ρRT)/P#</mathjax></p> <blockquote></blockquote> <p>∴ <mathjax>#"Rate"_1/"Rate"_2 = sqrt(M_2/M_1) = sqrt((ρ_2(color(red)(cancel(color(black)((RT)/P)))))/(ρ_1color(red)(cancel(color(black)(((RT)/P))))) )=sqrt(ρ_2/ρ_1)#</mathjax></p> <p>Let component 1 be hydrogen and component 2 be oxygen.</p> <p><mathjax>#"Rate"_2/"Rate"_1 = sqrt((1.43 color(red)(cancel(color(black)("g/L"))))/(0.0899 color(red)(cancel(color(black)("g/L"))))) = sqrt15.9 = 3.99#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How fast is the rate of effusion of hydrogen compared to that of oxygen?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/kinetic-theory-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Kinetic Theory of Gases</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="346232" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-03T21:54:55" itemprop="dateCreated"> Dec 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Rate"_text(H₂)/"Rate"_text(O₂) = 3.99#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Graham's Law of Effusion</strong> is:</p> <blockquote> <p><mathjax>#color(blue)(bar(ul(|color(white)(a/a) "Rate"_1/"Rate"_2 = sqrt(M_2/M_1)color(white)(a/a)|)))" "#</mathjax></p> </blockquote> <p>The <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">Ideal Gas Law</a></strong> is</p> <blockquote> <p><mathjax>#color(blue)(bar(ul(|color(white)(a/a) PV = nRT color(white)(a/a)|)))" "#</mathjax></p> </blockquote> <p>We can re-write this to get</p> <p><mathjax>#PV = (m/M)RT= (mRT)/M#</mathjax></p> <p><mathjax>#P = (m/V)((RT)/M) = (ρRT)/M#</mathjax></p> <p><mathjax>#M = (ρRT)/P#</mathjax></p> <blockquote></blockquote> <p>∴ <mathjax>#"Rate"_1/"Rate"_2 = sqrt(M_2/M_1) = sqrt((ρ_2(color(red)(cancel(color(black)((RT)/P)))))/(ρ_1color(red)(cancel(color(black)(((RT)/P))))) )=sqrt(ρ_2/ρ_1)#</mathjax></p> <p>Let component 1 be hydrogen and component 2 be oxygen.</p> <p><mathjax>#"Rate"_2/"Rate"_1 = sqrt((1.43 color(red)(cancel(color(black)("g/L"))))/(0.0899 color(red)(cancel(color(black)("g/L"))))) = sqrt15.9 = 3.99#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/346232" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-kinetic-molecular-theory-explain-gas-laws"> How does kinetic molecular theory explain gas laws? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/garaham-s-law-of-diffusion-1"> What is Graham's Law of Effusion? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-the-kinetic-theory-of-gases"> What are some examples of the kinetic theory of gases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-relationship-between-charles-law-and-the-kinetic-theory-of-gases"> What is the relationship between Charles law and the kinetic theory of gases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-does-the-kinetic-theory-apply-to-gases"> Why does the kinetic theory apply to gases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-average-kinetic-energy-of-the-molecules-in-a-gas-at-273k"> What is the average kinetic energy of the molecules in a gas at 273K? 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How fast is the rate of effusion of hydrogen compared to that of oxygen?

a9b2ac7e-6ddd-11ea-8eb1-ccda262736ce

https://socratic.org/questions/what-is-the-formula-for-barium-fluoride

BaF2

start chemical_formula qc_end substance 5 6 qc_end end

[{"type":"other","value":"Chemical Formula [OF] barium fluoride [IN] default"}]

[{"type":"chemical equation","value":"BaF2"}]

[{"type":"substance name","value":"Barium fluoride"}]

<h1 class="questionTitle" itemprop="name">What is the formula for barium fluoride? </h1>

BaF2

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Barium is an alkaline earth, and commonly forms a <mathjax>#Ba^(2+)#</mathjax> cation. Given the fluoride ion, <mathjax>#F^-#</mathjax>, a neutral salt requires a formulation of <mathjax>#BaF_2#</mathjax>. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#BaF_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Barium is an alkaline earth, and commonly forms a <mathjax>#Ba^(2+)#</mathjax> cation. Given the fluoride ion, <mathjax>#F^-#</mathjax>, a neutral salt requires a formulation of <mathjax>#BaF_2#</mathjax>. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the formula for barium fluoride? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="330926" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-03T19:59:56" itemprop="dateCreated"> Nov 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#BaF_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Barium is an alkaline earth, and commonly forms a <mathjax>#Ba^(2+)#</mathjax> cation. Given the fluoride ion, <mathjax>#F^-#</mathjax>, a neutral salt requires a formulation of <mathjax>#BaF_2#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/330926" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 10595 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the formula for barium fluoride?

a92d9c9c-6ddd-11ea-ac27-ccda262736ce

https://socratic.org/questions/how-do-you-write-the-formula-for-this-reaction-potassium-chlorate-decomposes-to-

2 KClO3 -> 2 KCl + 3 O2

start chemical_equation qc_end substance 9 10 qc_end substance 13 14 qc_end substance 16 17 qc_end end

[{"type":"other","value":"Chemical Equation [OF] this reaction"}]

[{"type":"chemical equation","value":"2 KClO3 -> 2 KCl + 3 O2"}]

[{"type":"substance name","value":"Potassium chlorate"},{"type":"substance name","value":"Potassium chloride"},{"type":"substance name","value":"Oxygen gas"}]

<h1 class="questionTitle" itemprop="name">How do you write the formula for this reaction: Potassium chlorate decomposes to potassium chloride and oxygen gas?</h1>

2 KClO3 -> 2 KCl + 3 O2

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Formula for Potassium chlorate is <mathjax>#KClO_3#</mathjax>.<br/> Formula for Potassium chloride is <mathjax>#KCl.#</mathjax> <br/> Formula for Oxygen gas as molecule is <mathjax>#O_2.#</mathjax></p> <p><mathjax>#:.#</mathjax> Reaction is : <mathjax>#KClO_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#KCl#</mathjax> <mathjax>#+#</mathjax> <mathjax>#O_2uarr.#</mathjax></p> <p>Now, balancing the equation, it comes to be :<br/> <mathjax>#2KClO_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#2KCl#</mathjax> <mathjax>#+#</mathjax> <mathjax>#3O_2uarr.#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Reaction is <mathjax>#2KClO_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#2KCl#</mathjax> <mathjax>#+#</mathjax> <mathjax>#3O_2uarr.#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Formula for Potassium chlorate is <mathjax>#KClO_3#</mathjax>.<br/> Formula for Potassium chloride is <mathjax>#KCl.#</mathjax> <br/> Formula for Oxygen gas as molecule is <mathjax>#O_2.#</mathjax></p> <p><mathjax>#:.#</mathjax> Reaction is : <mathjax>#KClO_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#KCl#</mathjax> <mathjax>#+#</mathjax> <mathjax>#O_2uarr.#</mathjax></p> <p>Now, balancing the equation, it comes to be :<br/> <mathjax>#2KClO_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#2KCl#</mathjax> <mathjax>#+#</mathjax> <mathjax>#3O_2uarr.#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you write the formula for this reaction: Potassium chlorate decomposes to potassium chloride and oxygen gas?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/decomposition-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Decomposition Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="330656" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/aditya-9"><img alt="" class="" src="https://profilepictures.socratic.org/JI8xltWvSDeHqZTzxqDb_25.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/aditya-9"> Aditya Banerjee. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-03T09:18:23" itemprop="dateCreated"> Nov 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Reaction is <mathjax>#2KClO_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#2KCl#</mathjax> <mathjax>#+#</mathjax> <mathjax>#3O_2uarr.#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Formula for Potassium chlorate is <mathjax>#KClO_3#</mathjax>.<br/> Formula for Potassium chloride is <mathjax>#KCl.#</mathjax> <br/> Formula for Oxygen gas as molecule is <mathjax>#O_2.#</mathjax></p> <p><mathjax>#:.#</mathjax> Reaction is : <mathjax>#KClO_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#KCl#</mathjax> <mathjax>#+#</mathjax> <mathjax>#O_2uarr.#</mathjax></p> <p>Now, balancing the equation, it comes to be :<br/> <mathjax>#2KClO_3#</mathjax> <mathjax>#rarr#</mathjax> <mathjax>#2KCl#</mathjax> <mathjax>#+#</mathjax> <mathjax>#3O_2uarr.#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/330656" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-decomposition-reactions"> What are decomposition reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-decomposition-reactions"> What are some examples of decomposition reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-decomposition-reaction-be-recognized"> How can a decomposition reaction be recognized? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-decomposition-reaction-differ-from-other-types-of-reactions"> How does a decomposition reaction differ from other types of reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-double-decomposition-reactions"> What are double decomposition reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-decomposition-reactions"> How can I balance decomposition reactions? 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How do you write the formula for this reaction: Potassium chlorate decomposes to potassium chloride and oxygen gas?

acf55fc8-6ddd-11ea-90ec-ccda262736ce

https://socratic.org/questions/what-is-the-molar-mass-of-k

39.1 g/mol

start physical_unit 6 6 molar_mass g/mol qc_end chemical_equation 6 6 qc_end end

[{"type":"physical unit","value":"Molar mass [OF] K [IN] g/mol"}]

[{"type":"physical unit","value":"39.1 g/mol"}]

[{"type":"chemical equation","value":"K"}]

<h1 class="questionTitle" itemprop="name">What is the molar mass of #K#?</h1>

39.1 g/mol

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong>molar mass</strong> of a species is the mass of 1 mole of that substance in grams, and equates to its <strong>relative <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a></strong>; however, molar mass also requires the unit <mathjax>#"g"#</mathjax> <mathjax>#"mol"^-1#</mathjax> to be appended. Thus:</p> <p><mathjax>#"molar mass"#</mathjax> <mathjax>#("K") = 39.1#</mathjax> <mathjax>#"g"#</mathjax> <mathjax>#"mol"^-1#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"molar mass"#</mathjax> <mathjax>#("K") = 39.1#</mathjax> <mathjax>#"g"#</mathjax> <mathjax>#"mol"^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong>molar mass</strong> of a species is the mass of 1 mole of that substance in grams, and equates to its <strong>relative <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a></strong>; however, molar mass also requires the unit <mathjax>#"g"#</mathjax> <mathjax>#"mol"^-1#</mathjax> to be appended. Thus:</p> <p><mathjax>#"molar mass"#</mathjax> <mathjax>#("K") = 39.1#</mathjax> <mathjax>#"g"#</mathjax> <mathjax>#"mol"^-1#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the molar mass of #K#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="207779" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/owen-b"><img alt="" class="" src="https://profilepictures.socratic.org/5O90HPzZRGiovfbNkapI_Screenshot_20170906-141654.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/owen-b"> Owen Bell </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-03T23:40:00" itemprop="dateCreated"> Jan 3, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"molar mass"#</mathjax> <mathjax>#("K") = 39.1#</mathjax> <mathjax>#"g"#</mathjax> <mathjax>#"mol"^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The <strong>molar mass</strong> of a species is the mass of 1 mole of that substance in grams, and equates to its <strong>relative <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a></strong>; however, molar mass also requires the unit <mathjax>#"g"#</mathjax> <mathjax>#"mol"^-1#</mathjax> to be appended. Thus:</p> <p><mathjax>#"molar mass"#</mathjax> <mathjax>#("K") = 39.1#</mathjax> <mathjax>#"g"#</mathjax> <mathjax>#"mol"^-1#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/207779" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 7344 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the molar mass of #K#?

acbce1ed-6ddd-11ea-b5dd-ccda262736ce

https://socratic.org/questions/determine-the-volume-occupied-by-2-50-g-of-hydrogen-gas-at-a-pressure-of-828-mm-

28.77 L

start physical_unit 8 9 volume l qc_end physical_unit 8 9 5 6 mass qc_end physical_unit 8 9 22 23 temperature qc_end physical_unit 8 9 14 17 pressure qc_end end

[{"type":"physical unit","value":"Volume [OF] hydrogen gas [IN] L"}]

[{"type":"physical unit","value":"28.77 L"}]

[{"type":"physical unit","value":"Mass [OF] hydrogen gas [=] \\pu{2.50 g}"},{"type":"physical unit","value":"Temperature [OF] hydrogen gas [=] \\pu{35.0 ℃}"},{"type":"physical unit","value":"Pressure [OF] hydrogen gas [=] \\pu{828 mm of mercury}"}]

<h1 class="questionTitle" itemprop="name">Determine the volume occupied by 2.50 g of hydrogen gas at a pressure of 828 mm of mercury and a temperature of 35.0 C ?</h1>

28.77 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It looks like you may not have converted the mass of <mathjax>#"H"_2"#</mathjax> to moles <mathjax>#(n)#</mathjax>. Also, you have the incorrect value for <mathjax>#R#</mathjax> because you are using mmHg as the pressure unit. The value you were using is what you would use if the pressure was in atm. You could convert from mmHg to atm.</p> <p>The equation for the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> is:</p> <p><mathjax>#PV=nRT#</mathjax>, </p> <p>where <mathjax>#P#</mathjax> is pressure, <mathjax>#V#</mathjax> is volume, <mathjax>#n#</mathjax> is moles, <mathjax>#R#</mathjax> is a gas constant, and <mathjax>#T#</mathjax> is temperature in Kelvins.</p> <p>You have to convert the mass into moles. You do that by multiplying the given mass of <mathjax>#"H"_2"#</mathjax> by its molar mass which is <mathjax>#"2.016 g/mol"#</mathjax>, which is 2 times the molar mass of <mathjax>#"H"_2"#</mathjax>, which is its atomic weight in grams/mole, or g/mol.</p> <p><mathjax>#2.50color(red)cancel(color(black)("g H"_2))xx(1"mol H"_2)/(2.016color(red)cancel(color(black)("g H"_2)))="1.24 mol H"#</mathjax></p> <p><mathjax>#color(blue)("Organize you data"#</mathjax>.</p> <p><strong>Given/Known</strong></p> <p><mathjax>#P="828 mmHg"#</mathjax> <mathjax>#lArr#</mathjax> You also gave a pressure of 820 mmHg. If its supposed to be 820, you can recalculate using that value.</p> <p><mathjax>#n="1.24 mol"#</mathjax> </p> <p><mathjax>#R="62.36367 L mmHg K"^(-1) "mol"^(-1)"#</mathjax><br/> <a href="http://www.cpp.edu/~lllee/gasconstant.pdf" rel="nofollow" target="_blank">http://www.cpp.edu/~lllee/gasconstant.pdf</a><br/> <mathjax>#T="308 K"#</mathjax> </p> <p><strong>Unknown:</strong> <mathjax>#V#</mathjax></p> <p><mathjax>#color(blue)("Solution"#</mathjax><br/> Rearrange the equation to isolate <mathjax>#V#</mathjax>. Insert your data and solve.</p> <p><mathjax>#V=(nRT)/P#</mathjax></p> <p><mathjax>#V=(1.24color(red)cancel(color(black)("mol"))xx62.36367color(white)(.) "L" color(red)cancel(color(black)("mmHg")) color(red)cancel(color(black)("K"))^(-1) color(red)cancel(color(black)("mol"))^(-1)xx308color(red)cancel(color(black)("K")))/(828color(red)cancel(color(black)("mmHg")))"="28.8color(white)(.)"L H"_2"#</mathjax> </p> <p>Just in case you meant <mathjax>#"820 mmHg"#</mathjax>, you would get the following:</p> <p><mathjax>#V=(1.24color(red)cancel(color(black)("mol"))xx62.36367color(white)(.) "L" color(red)cancel(color(black)("mmHg")) color(red)cancel(color(black)("K"))^(-1) color(red)cancel(color(black)("mol"))^(-1)xx308color(red)cancel(color(black)("K")))/(820color(red)cancel(color(black)("mmHg")))"="29.0color(white)(.)"L H"_2"#</mathjax> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume is <mathjax>#"28.8 L"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It looks like you may not have converted the mass of <mathjax>#"H"_2"#</mathjax> to moles <mathjax>#(n)#</mathjax>. Also, you have the incorrect value for <mathjax>#R#</mathjax> because you are using mmHg as the pressure unit. The value you were using is what you would use if the pressure was in atm. You could convert from mmHg to atm.</p> <p>The equation for the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> is:</p> <p><mathjax>#PV=nRT#</mathjax>, </p> <p>where <mathjax>#P#</mathjax> is pressure, <mathjax>#V#</mathjax> is volume, <mathjax>#n#</mathjax> is moles, <mathjax>#R#</mathjax> is a gas constant, and <mathjax>#T#</mathjax> is temperature in Kelvins.</p> <p>You have to convert the mass into moles. You do that by multiplying the given mass of <mathjax>#"H"_2"#</mathjax> by its molar mass which is <mathjax>#"2.016 g/mol"#</mathjax>, which is 2 times the molar mass of <mathjax>#"H"_2"#</mathjax>, which is its atomic weight in grams/mole, or g/mol.</p> <p><mathjax>#2.50color(red)cancel(color(black)("g H"_2))xx(1"mol H"_2)/(2.016color(red)cancel(color(black)("g H"_2)))="1.24 mol H"#</mathjax></p> <p><mathjax>#color(blue)("Organize you data"#</mathjax>.</p> <p><strong>Given/Known</strong></p> <p><mathjax>#P="828 mmHg"#</mathjax> <mathjax>#lArr#</mathjax> You also gave a pressure of 820 mmHg. If its supposed to be 820, you can recalculate using that value.</p> <p><mathjax>#n="1.24 mol"#</mathjax> </p> <p><mathjax>#R="62.36367 L mmHg K"^(-1) "mol"^(-1)"#</mathjax><br/> <a href="http://www.cpp.edu/~lllee/gasconstant.pdf" rel="nofollow" target="_blank">http://www.cpp.edu/~lllee/gasconstant.pdf</a><br/> <mathjax>#T="308 K"#</mathjax> </p> <p><strong>Unknown:</strong> <mathjax>#V#</mathjax></p> <p><mathjax>#color(blue)("Solution"#</mathjax><br/> Rearrange the equation to isolate <mathjax>#V#</mathjax>. Insert your data and solve.</p> <p><mathjax>#V=(nRT)/P#</mathjax></p> <p><mathjax>#V=(1.24color(red)cancel(color(black)("mol"))xx62.36367color(white)(.) "L" color(red)cancel(color(black)("mmHg")) color(red)cancel(color(black)("K"))^(-1) color(red)cancel(color(black)("mol"))^(-1)xx308color(red)cancel(color(black)("K")))/(828color(red)cancel(color(black)("mmHg")))"="28.8color(white)(.)"L H"_2"#</mathjax> </p> <p>Just in case you meant <mathjax>#"820 mmHg"#</mathjax>, you would get the following:</p> <p><mathjax>#V=(1.24color(red)cancel(color(black)("mol"))xx62.36367color(white)(.) "L" color(red)cancel(color(black)("mmHg")) color(red)cancel(color(black)("K"))^(-1) color(red)cancel(color(black)("mol"))^(-1)xx308color(red)cancel(color(black)("K")))/(820color(red)cancel(color(black)("mmHg")))"="29.0color(white)(.)"L H"_2"#</mathjax> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Determine the volume occupied by 2.50 g of hydrogen gas at a pressure of 828 mm of mercury and a temperature of 35.0 C ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="425360" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-18T03:47:34" itemprop="dateCreated"> May 18, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume is <mathjax>#"28.8 L"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>It looks like you may not have converted the mass of <mathjax>#"H"_2"#</mathjax> to moles <mathjax>#(n)#</mathjax>. Also, you have the incorrect value for <mathjax>#R#</mathjax> because you are using mmHg as the pressure unit. The value you were using is what you would use if the pressure was in atm. You could convert from mmHg to atm.</p> <p>The equation for the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> is:</p> <p><mathjax>#PV=nRT#</mathjax>, </p> <p>where <mathjax>#P#</mathjax> is pressure, <mathjax>#V#</mathjax> is volume, <mathjax>#n#</mathjax> is moles, <mathjax>#R#</mathjax> is a gas constant, and <mathjax>#T#</mathjax> is temperature in Kelvins.</p> <p>You have to convert the mass into moles. You do that by multiplying the given mass of <mathjax>#"H"_2"#</mathjax> by its molar mass which is <mathjax>#"2.016 g/mol"#</mathjax>, which is 2 times the molar mass of <mathjax>#"H"_2"#</mathjax>, which is its atomic weight in grams/mole, or g/mol.</p> <p><mathjax>#2.50color(red)cancel(color(black)("g H"_2))xx(1"mol H"_2)/(2.016color(red)cancel(color(black)("g H"_2)))="1.24 mol H"#</mathjax></p> <p><mathjax>#color(blue)("Organize you data"#</mathjax>.</p> <p><strong>Given/Known</strong></p> <p><mathjax>#P="828 mmHg"#</mathjax> <mathjax>#lArr#</mathjax> You also gave a pressure of 820 mmHg. If its supposed to be 820, you can recalculate using that value.</p> <p><mathjax>#n="1.24 mol"#</mathjax> </p> <p><mathjax>#R="62.36367 L mmHg K"^(-1) "mol"^(-1)"#</mathjax><br/> <a href="http://www.cpp.edu/~lllee/gasconstant.pdf" rel="nofollow" target="_blank">http://www.cpp.edu/~lllee/gasconstant.pdf</a><br/> <mathjax>#T="308 K"#</mathjax> </p> <p><strong>Unknown:</strong> <mathjax>#V#</mathjax></p> <p><mathjax>#color(blue)("Solution"#</mathjax><br/> Rearrange the equation to isolate <mathjax>#V#</mathjax>. Insert your data and solve.</p> <p><mathjax>#V=(nRT)/P#</mathjax></p> <p><mathjax>#V=(1.24color(red)cancel(color(black)("mol"))xx62.36367color(white)(.) "L" color(red)cancel(color(black)("mmHg")) color(red)cancel(color(black)("K"))^(-1) color(red)cancel(color(black)("mol"))^(-1)xx308color(red)cancel(color(black)("K")))/(828color(red)cancel(color(black)("mmHg")))"="28.8color(white)(.)"L H"_2"#</mathjax> </p> <p>Just in case you meant <mathjax>#"820 mmHg"#</mathjax>, you would get the following:</p> <p><mathjax>#V=(1.24color(red)cancel(color(black)("mol"))xx62.36367color(white)(.) "L" color(red)cancel(color(black)("mmHg")) color(red)cancel(color(black)("K"))^(-1) color(red)cancel(color(black)("mol"))^(-1)xx308color(red)cancel(color(black)("K")))/(820color(red)cancel(color(black)("mmHg")))"="29.0color(white)(.)"L H"_2"#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/425360" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? 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Determine the volume occupied by 2.50 g of hydrogen gas at a pressure of 828 mm of mercury and a temperature of 35.0 C ?

abe652a0-6ddd-11ea-8a3a-ccda262736ce

https://socratic.org/questions/how-do-you-balance-nh-3-g-o-2-g-n-2-g-h-2o-g

4 NH3(g) + 3 O2(g) -> 2 N2(g) + 6 H2O(g)

start chemical_equation qc_end chemical_equation 4 10 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"4 NH3(g) + 3 O2(g) -> 2 N2(g) + 6 H2O(g)"}]

[{"type":"chemical equation","value":"NH3(g) + O2(g) -> N2(g) + H2O(g)"}]

<h1 class="questionTitle" itemprop="name">How do you balance #NH_3(g) + O_2(g) -&gt; N_2(g) + H_2O(g)#?</h1>

4 NH3(g) + 3 O2(g) -> 2 N2(g) + 6 H2O(g)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This can be easily balanced through trial and error method or through algebraic method. Always consider to take inventories of the atoms from each element of the reactants and the products; that is, before and after it is balanced.</p> <p>Balancing through trial and error method:</p> <p>Reactants:</p> <p><mathjax>#N=cancel(1)4#</mathjax><br/> <mathjax>#H=cancel(3)12#</mathjax><br/> <mathjax>#O=cancel(2)6#</mathjax></p> <p>Products:</p> <p><mathjax>#N=cancel(2)4#</mathjax><br/> <mathjax>#H=cancel(2)12#</mathjax><br/> <mathjax>#O=cancel(1)6#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4NH_3(g) + 3O_2(g) → 2N_2(g) + 6 H_2O(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This can be easily balanced through trial and error method or through algebraic method. Always consider to take inventories of the atoms from each element of the reactants and the products; that is, before and after it is balanced.</p> <p>Balancing through trial and error method:</p> <p>Reactants:</p> <p><mathjax>#N=cancel(1)4#</mathjax><br/> <mathjax>#H=cancel(3)12#</mathjax><br/> <mathjax>#O=cancel(2)6#</mathjax></p> <p>Products:</p> <p><mathjax>#N=cancel(2)4#</mathjax><br/> <mathjax>#H=cancel(2)12#</mathjax><br/> <mathjax>#O=cancel(1)6#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you balance #NH_3(g) + O_2(g) -&gt; N_2(g) + H_2O(g)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="209496" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jarni-renz"><img alt="" class="" src="https://profilepictures.socratic.org/i6OiZQmVRHWljDVlwm8v_WIN_20160301_180231.JPG" title=""/></a> <a class="secondContributorPic" href="/users/abigail-f-2"><img alt="" class="" src="https://lh3.googleusercontent.com/-8f0QTns54JM/AAAAAAAAAAI/AAAAAAAAAF0/TLeR8d_iXl8/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jarni-renz"> Jarni Renz </a>·<a class="topContributorLink" href="/users/abigail-f-2"> Abigail F. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-07T18:28:22" itemprop="dateCreated"> Jan 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4NH_3(g) + 3O_2(g) → 2N_2(g) + 6 H_2O(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This can be easily balanced through trial and error method or through algebraic method. Always consider to take inventories of the atoms from each element of the reactants and the products; that is, before and after it is balanced.</p> <p>Balancing through trial and error method:</p> <p>Reactants:</p> <p><mathjax>#N=cancel(1)4#</mathjax><br/> <mathjax>#H=cancel(3)12#</mathjax><br/> <mathjax>#O=cancel(2)6#</mathjax></p> <p>Products:</p> <p><mathjax>#N=cancel(2)4#</mathjax><br/> <mathjax>#H=cancel(2)12#</mathjax><br/> <mathjax>#O=cancel(1)6#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/209496" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------&gt; H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -&gt; Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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How do you balance #NH_3(g) + O_2(g) -&gt; N_2(g) + H_2O(g)#?

a83f6f1e-6ddd-11ea-9c45-ccda262736ce

https://socratic.org/questions/when-steam-hot-water-is-passed-over-iron-hydrogen-gas-and-iron-lll-oxide-are-for

48.4 g

start physical_unit 1 1 mass g qc_end physical_unit 7 7 27 28 mass qc_end c_other OTHER qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Mass [OF] steam [IN] g"}]

[{"type":"physical unit","value":"48.4 g"}]

[{"type":"physical unit","value":"Mass [OF] iron [=] \\pu{100.0 g}"},{"type":"other","value":"When steam (hot water) is passed over iron, hydrogen gas and iron (lll) oxide are formed. "},{"type":"other","value":"react completely"}]

<h1 class="questionTitle" itemprop="name">When steam (hot water) is passed over iron, hydrogen gas and iron (lll) oxide are formed. What mass of steam would be needed to react completely with 100.0 g of iron? </h1>

48.4 g

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Write the balanced equation.</strong></p> <p><mathjax>#"2Fe" + "3H"_2"O" → "Fe"_2"O"_3 + "3H"_2#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Calculate the moles of iron.</strong></p> <p><mathjax>#100 cancel("g Fe") × "1 mol Fe"/(55.84 cancel("g Fe")) = "1.791 mol Fe"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 3. Calculate the moles of <mathjax>#"H"_2"O"#</mathjax>.</strong></p> <p><mathjax>#1.791 cancel("mol Fe") × ("3 mol H"_2"O")/(2 cancel("mol Fe")) = "2.686 mol H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 4. Calculate the mass of <mathjax>#"H"_2"O"#</mathjax>.</strong></p> <p><mathjax>#2.686 cancel("mol H"_2"O") × ("18.02 g H"_2"O")/(1 cancel("mol H_2"O"")) = "48.4 g H"_2"O"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The reaction requires 48.4 g of steam.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Write the balanced equation.</strong></p> <p><mathjax>#"2Fe" + "3H"_2"O" → "Fe"_2"O"_3 + "3H"_2#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Calculate the moles of iron.</strong></p> <p><mathjax>#100 cancel("g Fe") × "1 mol Fe"/(55.84 cancel("g Fe")) = "1.791 mol Fe"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 3. Calculate the moles of <mathjax>#"H"_2"O"#</mathjax>.</strong></p> <p><mathjax>#1.791 cancel("mol Fe") × ("3 mol H"_2"O")/(2 cancel("mol Fe")) = "2.686 mol H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 4. Calculate the mass of <mathjax>#"H"_2"O"#</mathjax>.</strong></p> <p><mathjax>#2.686 cancel("mol H"_2"O") × ("18.02 g H"_2"O")/(1 cancel("mol H_2"O"")) = "48.4 g H"_2"O"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">When steam (hot water) is passed over iron, hydrogen gas and iron (lll) oxide are formed. What mass of steam would be needed to react completely with 100.0 g of iron? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="236085" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-07T02:25:16" itemprop="dateCreated"> Mar 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The reaction requires 48.4 g of steam.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Write the balanced equation.</strong></p> <p><mathjax>#"2Fe" + "3H"_2"O" → "Fe"_2"O"_3 + "3H"_2#</mathjax></p> <blockquote></blockquote> <p><strong>Step 2. Calculate the moles of iron.</strong></p> <p><mathjax>#100 cancel("g Fe") × "1 mol Fe"/(55.84 cancel("g Fe")) = "1.791 mol Fe"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 3. Calculate the moles of <mathjax>#"H"_2"O"#</mathjax>.</strong></p> <p><mathjax>#1.791 cancel("mol Fe") × ("3 mol H"_2"O")/(2 cancel("mol Fe")) = "2.686 mol H"_2"O"#</mathjax></p> <blockquote></blockquote> <p><strong>Step 4. Calculate the mass of <mathjax>#"H"_2"O"#</mathjax>.</strong></p> <p><mathjax>#2.686 cancel("mol H"_2"O") × ("18.02 g H"_2"O")/(1 cancel("mol H_2"O"")) = "48.4 g H"_2"O"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/236085" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -&gt; 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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When steam (hot water) is passed over iron, hydrogen gas and iron (lll) oxide are formed. What mass of steam would be needed to react completely with 100.0 g of iron?

aada862e-6ddd-11ea-8619-ccda262736ce

https://socratic.org/questions/a-chemist-weighed-out-3-89-g-of-nickel-what-is-the-number-of-moles-of-nickel-she

0.07 moles

start physical_unit 7 7 mole mol qc_end physical_unit 7 7 4 5 mass qc_end end

[{"type":"physical unit","value":"Mole [OF] nickel [IN] moles"}]

[{"type":"physical unit","value":"0.07 moles"}]

[{"type":"physical unit","value":"Weight [OF] nickel [=] \\pu{3.89 g}"}]

<h1 class="questionTitle" itemprop="name">A chemist weighed out 3.89 g of nickel. What is the number of moles of nickel she weighed out?</h1>

0.07 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>For this question, we need to use <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the Periodic Table</a> to find the molar mass of <mathjax>#"Ni"#</mathjax> (58.69 g/mol).</p> <blockquote></blockquote> <p>The formula for molar mass is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(|bar(ul(color(white)(a/a) "molar mass" = "mass"/"moles"color(white)(a/a)|)))" "#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange the formula to read</p> <blockquote> <blockquote> <p><mathjax>#"moles" = "mass"/"molar mass"#</mathjax></p> </blockquote> </blockquote> <p>∴ <mathjax>#"moles" = 3.89 color(red)(cancel(color(black)("g Ni"))) × "1 mol Ni"/(58.69 color(red)(cancel(color(black)("g Ni")))) = "0.0663 mol Ni"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>She measured out <strong>0.0663 mol of nickel</strong>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>For this question, we need to use <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the Periodic Table</a> to find the molar mass of <mathjax>#"Ni"#</mathjax> (58.69 g/mol).</p> <blockquote></blockquote> <p>The formula for molar mass is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(|bar(ul(color(white)(a/a) "molar mass" = "mass"/"moles"color(white)(a/a)|)))" "#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange the formula to read</p> <blockquote> <blockquote> <p><mathjax>#"moles" = "mass"/"molar mass"#</mathjax></p> </blockquote> </blockquote> <p>∴ <mathjax>#"moles" = 3.89 color(red)(cancel(color(black)("g Ni"))) × "1 mol Ni"/(58.69 color(red)(cancel(color(black)("g Ni")))) = "0.0663 mol Ni"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A chemist weighed out 3.89 g of nickel. What is the number of moles of nickel she weighed out?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="255160" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-17T01:35:34" itemprop="dateCreated"> Apr 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>She measured out <strong>0.0663 mol of nickel</strong>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>For this question, we need to use <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the Periodic Table</a> to find the molar mass of <mathjax>#"Ni"#</mathjax> (58.69 g/mol).</p> <blockquote></blockquote> <p>The formula for molar mass is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(|bar(ul(color(white)(a/a) "molar mass" = "mass"/"moles"color(white)(a/a)|)))" "#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange the formula to read</p> <blockquote> <blockquote> <p><mathjax>#"moles" = "mass"/"molar mass"#</mathjax></p> </blockquote> </blockquote> <p>∴ <mathjax>#"moles" = 3.89 color(red)(cancel(color(black)("g Ni"))) × "1 mol Ni"/(58.69 color(red)(cancel(color(black)("g Ni")))) = "0.0663 mol Ni"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/255160" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? 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A chemist weighed out 3.89 g of nickel. What is the number of moles of nickel she weighed out?

ac9747b6-6ddd-11ea-9a53-ccda262736ce

https://socratic.org/questions/how-do-you-find-the-empirical-formulas-for-65-2-sc-34-8-o

Sc2O3

start chemical_formula qc_end end

[{"type":"other","value":"Chemical Formula [OF] the compound [IN] empirical"}]

[{"type":"chemical equation","value":"Sc2O3"}]

[{"type":"physical unit","value":"Percent [OF] Sc in the compound [=] \\pu{65.2%}"},{"type":"physical unit","value":"Percent [OF] O in the compound [=] \\pu{34.8%}"}]

<h1 class="questionTitle" itemprop="name">How do you find the empirical formulas for 65.2% Sc, 34.8% O?</h1>

Sc2O3

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula is the simplest whole number ratio defining constituent atoms in a species. We assume a <mathjax>#100*g#</mathjax> mass of <mathjax>#Sc_2O_3#</mathjax>, and we come up with a molar ratio:</p> <p><mathjax>#"Moles of scandium"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass of scandium"/"Molar mass of scandium"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(65.2*g)/(44.96*g*mol^-1)=1.45*mol#</mathjax>.</p> <p><mathjax>#"Moles of oxygen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass of oxygen"/"Molar mass of scandium"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(34.8*g)/(16.00*g*mol^-1)=2.175*mol#</mathjax>.</p> <p>In each instance, I divided thru by the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">ATOMIC MASS</a> of the element. And now if we divide thru by the smallest molar quantity, (that of the metal), I get a formula of <mathjax>#ScO_(1.5)#</mathjax>. Because, by specification, the empirical formula is a WHOLE number ratio, we quote its empirical formula as <mathjax>#Sc_2O_3#</mathjax>. Capisce?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>As with all these problems, we ASSUME a <mathjax>#100*g#</mathjax> mass of compound.........and come up with an empirical formula of <mathjax>#Sc_2O_3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula is the simplest whole number ratio defining constituent atoms in a species. We assume a <mathjax>#100*g#</mathjax> mass of <mathjax>#Sc_2O_3#</mathjax>, and we come up with a molar ratio:</p> <p><mathjax>#"Moles of scandium"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass of scandium"/"Molar mass of scandium"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(65.2*g)/(44.96*g*mol^-1)=1.45*mol#</mathjax>.</p> <p><mathjax>#"Moles of oxygen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass of oxygen"/"Molar mass of scandium"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(34.8*g)/(16.00*g*mol^-1)=2.175*mol#</mathjax>.</p> <p>In each instance, I divided thru by the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">ATOMIC MASS</a> of the element. And now if we divide thru by the smallest molar quantity, (that of the metal), I get a formula of <mathjax>#ScO_(1.5)#</mathjax>. Because, by specification, the empirical formula is a WHOLE number ratio, we quote its empirical formula as <mathjax>#Sc_2O_3#</mathjax>. Capisce?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you find the empirical formulas for 65.2% Sc, 34.8% O?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="386331" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-04T13:29:15" itemprop="dateCreated"> Mar 4, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>As with all these problems, we ASSUME a <mathjax>#100*g#</mathjax> mass of compound.........and come up with an empirical formula of <mathjax>#Sc_2O_3#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The empirical formula is the simplest whole number ratio defining constituent atoms in a species. We assume a <mathjax>#100*g#</mathjax> mass of <mathjax>#Sc_2O_3#</mathjax>, and we come up with a molar ratio:</p> <p><mathjax>#"Moles of scandium"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass of scandium"/"Molar mass of scandium"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(65.2*g)/(44.96*g*mol^-1)=1.45*mol#</mathjax>.</p> <p><mathjax>#"Moles of oxygen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass of oxygen"/"Molar mass of scandium"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(34.8*g)/(16.00*g*mol^-1)=2.175*mol#</mathjax>.</p> <p>In each instance, I divided thru by the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">ATOMIC MASS</a> of the element. And now if we divide thru by the smallest molar quantity, (that of the metal), I get a formula of <mathjax>#ScO_(1.5)#</mathjax>. Because, by specification, the empirical formula is a WHOLE number ratio, we quote its empirical formula as <mathjax>#Sc_2O_3#</mathjax>. Capisce?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/386331" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5708 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How do you find the empirical formulas for 65.2% Sc, 34.8% O?

ace2becc-6ddd-11ea-9bd9-ccda262736ce

https://socratic.org/questions/how-would-you-balance-h2-o2-h2o-1

2 H2 + O2 -> 2 H2O

start chemical_equation qc_end chemical_equation 4 8 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"2 H2 + O2 -> 2 H2O"}]

[{"type":"chemical equation","value":"H2 + O2 -> H2O"}]

<h1 class="questionTitle" itemprop="name">How would you balance H2 + O2 = H2O?</h1>

2 H2 + O2 -> 2 H2O

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From the original equation, you first need to write each component separately.</p> <p><mathjax>#H_2 + O_2 = H_2O#</mathjax> </p> <p>Left side: H = <strong>2</strong> ; O = <strong>2</strong> (number based on the subscript)<br/> Right side: H = <strong>2</strong> ; O = <strong>1</strong> (number based on the subscripts; no subscript means that the element is just 1)</p> <p>Notice that the number of H is already balance but the number of O is not. In order to balance the O, you need to multiply the element by 2, but you CANNOT do this by simply changing the subscript. </p> <p>Hence,</p> <p><mathjax>#H_2 + O_2 = 2H_2O#</mathjax> </p> <p>Left side: H = <strong>2</strong> ; O = <strong>2</strong> <br/> Right side: H = 2 x 2 = <strong>4</strong> ; O = 1 x 2 = <strong>2</strong></p> <p>Now, notice that the number of O is now balance (both are 2) but the number of H is not (since <mathjax>#H_2O#</mathjax> is a substance and not an element, you need to multiply everything by 2). So, what to do? </p> <p>You also multiply the left side H by 2. Hence,</p> <p><mathjax>#2H_2 + O_2 = 2H_2O#</mathjax> </p> <p>Left side: H = 2 x 2 = <strong>4</strong> ; O = <strong>2</strong> <br/> Right side: H = 2 x 2 = <strong>4</strong> ; O = 1 x 2 = <strong>2</strong></p> <p>The equation is now balanced. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>2H2 + O2 = 2H2O</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How would you balance H2 + O2 = H2O?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="179324" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/irealwilliam"><img alt="" class="" src="https://profilepictures.socratic.org/4AcGRXkESNe7JWiwD34Y_10867230_10202133442618011_804888101_n.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/irealwilliam"> KPaukstis </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-23T12:02:22" itemprop="dateCreated"> Oct 23, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>2H2 + O2 = 2H2O</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/179324" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="179325" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nikka-c"><img alt="" class="" src="https://profilepictures.socratic.org/AQ8VOCyTM1J7U0TvIWhw_nkahara.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nikka-c"> Nikka C. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-23T12:02:53" itemprop="dateCreated"> Oct 23, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2H_2 + O_2 = 2H_2O#</mathjax> </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From the original equation, you first need to write each component separately.</p> <p><mathjax>#H_2 + O_2 = H_2O#</mathjax> </p> <p>Left side: H = <strong>2</strong> ; O = <strong>2</strong> (number based on the subscript)<br/> Right side: H = <strong>2</strong> ; O = <strong>1</strong> (number based on the subscripts; no subscript means that the element is just 1)</p> <p>Notice that the number of H is already balance but the number of O is not. In order to balance the O, you need to multiply the element by 2, but you CANNOT do this by simply changing the subscript. </p> <p>Hence,</p> <p><mathjax>#H_2 + O_2 = 2H_2O#</mathjax> </p> <p>Left side: H = <strong>2</strong> ; O = <strong>2</strong> <br/> Right side: H = 2 x 2 = <strong>4</strong> ; O = 1 x 2 = <strong>2</strong></p> <p>Now, notice that the number of O is now balance (both are 2) but the number of H is not (since <mathjax>#H_2O#</mathjax> is a substance and not an element, you need to multiply everything by 2). So, what to do? </p> <p>You also multiply the left side H by 2. Hence,</p> <p><mathjax>#2H_2 + O_2 = 2H_2O#</mathjax> </p> <p>Left side: H = 2 x 2 = <strong>4</strong> ; O = <strong>2</strong> <br/> Right side: H = 2 x 2 = <strong>4</strong> ; O = 1 x 2 = <strong>2</strong></p> <p>The equation is now balanced. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/179325" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------&gt; H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -&gt; Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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How would you balance H2 + O2 = H2O?

a86ef11e-6ddd-11ea-b61a-ccda262736ce

https://socratic.org/questions/in-the-reaction-k-2cro-4-aq-pbcl-2-aq-2kcl-aq-pbcro-4-s-how-many-grams-of-pbcro-

24.2 grams

start physical_unit 10 10 mass g qc_end c_other OTHER qc_end chemical_equation 3 10 qc_end physical_unit 3 3 23 24 volume qc_end physical_unit 3 3 26 27 molarity qc_end end

[{"type":"physical unit","value":"Mass [OF] PbCrO4 [IN] grams"}]

[{"type":"physical unit","value":"24.2 grams"}]

[{"type":"other","value":"Excess of PbCl2."},{"type":"chemical equation","value":"K2CrO4(aq) + PbCl2(aq) -> 2 KCl(aq) + PbCrO4(s)"},{"type":"physical unit","value":"Volume [OF] K2CrO4 [=] \\pu{25.0 milliliters}"},{"type":"physical unit","value":"Molarity [OF] K2CrO4 [=] \\pu{3.0 M}"}]

<h1 class="questionTitle" itemprop="name">In the reaction #K_2CrO_4(aq) + PbCl_2(aq)-&gt;2KCl(aq) + PbCrO_4(s),# how many grams of #PbCrO_4# will precipitate out from the reaction between 25.0 milliliters of 3.0 M #K_2CrO_4# in an excess of #PbCl_2#? </h1>

24.2 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Given:</strong></p> <ul> <li>Balanced chemical equation</li> <li>Volume of <mathjax>#"K"_2"CrO"_4#</mathjax> solution</li> <li><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> of <mathjax>#"K"_2"CrO"_4#</mathjax> solution</li> </ul> <blockquote></blockquote> <p><strong>Find:</strong></p> <ul> <li>Mass of <mathjax>#"PbCrO"_4#</mathjax></li> </ul> <blockquote></blockquote> <p><strong>Strategy:</strong></p> <ul> <li>Write the balanced chemical equation</li> <li>Use the volume and molarity of <mathjax>#"K"_2"CrO"_4#</mathjax> to calculate moles of <mathjax>#"K"_2"CrO"_4#</mathjax></li> <li>Use the molar ratio to convert moles of <mathjax>#"K"_2"CrO"_4#</mathjax> to moles of <mathjax>#"PbCrO"_4#</mathjax></li> <li>Use the molar mass of <mathjax>#"PbCrO"_4#</mathjax> to convert to mass of <mathjax>#"PbCrO"_4#</mathjax></li> </ul> <blockquote></blockquote> <p><strong>Solution:</strong></p> <p><mathjax>#"K"_2"CrO"_4"(aq)"+"PbCl"_2"(aq)"→"2KCl(aq)"+"PbCrO"_4"(s)"#</mathjax></p> <p><mathjax>#0.0250 color(red)(cancel(color(black)("L K"_2"CrO"_4))) × ("3.0 mol K"_2"CrO"_4)/(1 color(red)(cancel(color(black)("L K"_2"CrO"_4)))) = "0.0750 mol K"_2"CrO"_4#</mathjax></p> <p><mathjax>#0.0750 color(red)(cancel(color(black)("mol K"_2"CrO"_4))) × ("1 mol PbCrO"_4)/(1 color(red)(cancel(color(black)("mol K"_2"CrO"_4)))) = "0.0750 mol PbCrO"_4#</mathjax></p> <p><mathjax>#0.0750color(red)(cancel(color(black)( "mol PbCrO"_4))) × ("323.19 g PbCrO"_4)/(1 color(red)(cancel(color(black)("mol PbCrO"_4)))) = "24.2 g PbCrO"_4#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>24.2 g of <mathjax>#"PbCrO"_4#</mathjax> will precipitate from the reaction.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Given:</strong></p> <ul> <li>Balanced chemical equation</li> <li>Volume of <mathjax>#"K"_2"CrO"_4#</mathjax> solution</li> <li><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> of <mathjax>#"K"_2"CrO"_4#</mathjax> solution</li> </ul> <blockquote></blockquote> <p><strong>Find:</strong></p> <ul> <li>Mass of <mathjax>#"PbCrO"_4#</mathjax></li> </ul> <blockquote></blockquote> <p><strong>Strategy:</strong></p> <ul> <li>Write the balanced chemical equation</li> <li>Use the volume and molarity of <mathjax>#"K"_2"CrO"_4#</mathjax> to calculate moles of <mathjax>#"K"_2"CrO"_4#</mathjax></li> <li>Use the molar ratio to convert moles of <mathjax>#"K"_2"CrO"_4#</mathjax> to moles of <mathjax>#"PbCrO"_4#</mathjax></li> <li>Use the molar mass of <mathjax>#"PbCrO"_4#</mathjax> to convert to mass of <mathjax>#"PbCrO"_4#</mathjax></li> </ul> <blockquote></blockquote> <p><strong>Solution:</strong></p> <p><mathjax>#"K"_2"CrO"_4"(aq)"+"PbCl"_2"(aq)"→"2KCl(aq)"+"PbCrO"_4"(s)"#</mathjax></p> <p><mathjax>#0.0250 color(red)(cancel(color(black)("L K"_2"CrO"_4))) × ("3.0 mol K"_2"CrO"_4)/(1 color(red)(cancel(color(black)("L K"_2"CrO"_4)))) = "0.0750 mol K"_2"CrO"_4#</mathjax></p> <p><mathjax>#0.0750 color(red)(cancel(color(black)("mol K"_2"CrO"_4))) × ("1 mol PbCrO"_4)/(1 color(red)(cancel(color(black)("mol K"_2"CrO"_4)))) = "0.0750 mol PbCrO"_4#</mathjax></p> <p><mathjax>#0.0750color(red)(cancel(color(black)( "mol PbCrO"_4))) × ("323.19 g PbCrO"_4)/(1 color(red)(cancel(color(black)("mol PbCrO"_4)))) = "24.2 g PbCrO"_4#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">In the reaction #K_2CrO_4(aq) + PbCl_2(aq)-&gt;2KCl(aq) + PbCrO_4(s),# how many grams of #PbCrO_4# will precipitate out from the reaction between 25.0 milliliters of 3.0 M #K_2CrO_4# in an excess of #PbCl_2#? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="222576" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-07T02:01:14" itemprop="dateCreated"> Feb 7, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>24.2 g of <mathjax>#"PbCrO"_4#</mathjax> will precipitate from the reaction.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Given:</strong></p> <ul> <li>Balanced chemical equation</li> <li>Volume of <mathjax>#"K"_2"CrO"_4#</mathjax> solution</li> <li><a href="http://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> of <mathjax>#"K"_2"CrO"_4#</mathjax> solution</li> </ul> <blockquote></blockquote> <p><strong>Find:</strong></p> <ul> <li>Mass of <mathjax>#"PbCrO"_4#</mathjax></li> </ul> <blockquote></blockquote> <p><strong>Strategy:</strong></p> <ul> <li>Write the balanced chemical equation</li> <li>Use the volume and molarity of <mathjax>#"K"_2"CrO"_4#</mathjax> to calculate moles of <mathjax>#"K"_2"CrO"_4#</mathjax></li> <li>Use the molar ratio to convert moles of <mathjax>#"K"_2"CrO"_4#</mathjax> to moles of <mathjax>#"PbCrO"_4#</mathjax></li> <li>Use the molar mass of <mathjax>#"PbCrO"_4#</mathjax> to convert to mass of <mathjax>#"PbCrO"_4#</mathjax></li> </ul> <blockquote></blockquote> <p><strong>Solution:</strong></p> <p><mathjax>#"K"_2"CrO"_4"(aq)"+"PbCl"_2"(aq)"→"2KCl(aq)"+"PbCrO"_4"(s)"#</mathjax></p> <p><mathjax>#0.0250 color(red)(cancel(color(black)("L K"_2"CrO"_4))) × ("3.0 mol K"_2"CrO"_4)/(1 color(red)(cancel(color(black)("L K"_2"CrO"_4)))) = "0.0750 mol K"_2"CrO"_4#</mathjax></p> <p><mathjax>#0.0750 color(red)(cancel(color(black)("mol K"_2"CrO"_4))) × ("1 mol PbCrO"_4)/(1 color(red)(cancel(color(black)("mol K"_2"CrO"_4)))) = "0.0750 mol PbCrO"_4#</mathjax></p> <p><mathjax>#0.0750color(red)(cancel(color(black)( "mol PbCrO"_4))) × ("323.19 g PbCrO"_4)/(1 color(red)(cancel(color(black)("mol PbCrO"_4)))) = "24.2 g PbCrO"_4#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/222576" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li 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In the reaction #K_2CrO_4(aq) + PbCl_2(aq)-&gt;2KCl(aq) + PbCrO_4(s),# how many grams of #PbCrO_4# will precipitate out from the reaction between 25.0 milliliters of 3.0 M #K_2CrO_4# in an excess of #PbCl_2#?

aa7962aa-6ddd-11ea-9a47-ccda262736ce

https://socratic.org/questions/how-many-grams-of-fe-2o-3-are-there-in-0-500-mole-of-fe-2o-3

79.90 grams

start physical_unit 4 4 mass g qc_end physical_unit 4 4 8 9 mole qc_end end

[{"type":"physical unit","value":"Mass [OF] Fe2O3 [IN] grams"}]

[{"type":"physical unit","value":"79.90 grams"}]

[{"type":"physical unit","value":"Mole [OF] Fe2O3 [=] \\pu{0.500 mole}"}]

<h1 class="questionTitle" itemprop="name">How many grams of #Fe_2O_3# are there in 0.500 mole of #Fe_2O_3#?</h1>

79.90 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Assume that:<br/> n = number of moles <br/> m = mass of substance<br/> M = molar mass (equivalent to atomic weight on the periodic table)<br/> <mathjax>#n = m -: M#</mathjax></p> <p>0.500 moles has been given to you</p> <p>Now you need to find the molar mass of <mathjax>#Fe_2O_3#</mathjax>. Before you do that, you gotta know what <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> are present. If you look closely, you can see that Iron (Fe) and Oxygen (O) is present. </p> <p>If you refer to your periodic table, Iron has a molar mass of 55.9 g/mol whereas Oxygen has the molar mass of 16.0 g/mol.</p> <p>Since there are 2 Iron and 3 Oxygen, the molar mass of <mathjax>#Fe_2O_3#</mathjax> is:<br/> [<mathjax>#2 xx 55.9 + 3 xx 16.0#</mathjax>] = 159.8 g/mol.</p> <p>Therefore the mass of <mathjax>#Fe_2O_3#</mathjax> is:<br/> [m = 159.8 g/mol <mathjax>#xx#</mathjax> 0.500 moles] = 79.9 grams.</p> <p>79.9 grams are in 0.500 moles of <mathjax>#Fe_2O_3.#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.500 moles <mathjax>#xx#</mathjax> molar mass of <mathjax>#Fe_2O_3#</mathjax> = ??</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Assume that:<br/> n = number of moles <br/> m = mass of substance<br/> M = molar mass (equivalent to atomic weight on the periodic table)<br/> <mathjax>#n = m -: M#</mathjax></p> <p>0.500 moles has been given to you</p> <p>Now you need to find the molar mass of <mathjax>#Fe_2O_3#</mathjax>. Before you do that, you gotta know what <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> are present. If you look closely, you can see that Iron (Fe) and Oxygen (O) is present. </p> <p>If you refer to your periodic table, Iron has a molar mass of 55.9 g/mol whereas Oxygen has the molar mass of 16.0 g/mol.</p> <p>Since there are 2 Iron and 3 Oxygen, the molar mass of <mathjax>#Fe_2O_3#</mathjax> is:<br/> [<mathjax>#2 xx 55.9 + 3 xx 16.0#</mathjax>] = 159.8 g/mol.</p> <p>Therefore the mass of <mathjax>#Fe_2O_3#</mathjax> is:<br/> [m = 159.8 g/mol <mathjax>#xx#</mathjax> 0.500 moles] = 79.9 grams.</p> <p>79.9 grams are in 0.500 moles of <mathjax>#Fe_2O_3.#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many grams of #Fe_2O_3# are there in 0.500 mole of #Fe_2O_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="258970" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/edmund-l"><img alt="" class="" src="https://profilepictures.socratic.org/DnAPD8TISDW0aROTp4qA_Day_3_Story_1._Photo_with_Sky_Tower_from_distance_Walked_around_most_of_west_Auckland_suburbs._Some_of_you_mightve_seen_.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/edmund-l"> Edmund Liew </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-26T11:48:21" itemprop="dateCreated"> Apr 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.500 moles <mathjax>#xx#</mathjax> molar mass of <mathjax>#Fe_2O_3#</mathjax> = ??</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Assume that:<br/> n = number of moles <br/> m = mass of substance<br/> M = molar mass (equivalent to atomic weight on the periodic table)<br/> <mathjax>#n = m -: M#</mathjax></p> <p>0.500 moles has been given to you</p> <p>Now you need to find the molar mass of <mathjax>#Fe_2O_3#</mathjax>. Before you do that, you gotta know what <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> are present. If you look closely, you can see that Iron (Fe) and Oxygen (O) is present. </p> <p>If you refer to your periodic table, Iron has a molar mass of 55.9 g/mol whereas Oxygen has the molar mass of 16.0 g/mol.</p> <p>Since there are 2 Iron and 3 Oxygen, the molar mass of <mathjax>#Fe_2O_3#</mathjax> is:<br/> [<mathjax>#2 xx 55.9 + 3 xx 16.0#</mathjax>] = 159.8 g/mol.</p> <p>Therefore the mass of <mathjax>#Fe_2O_3#</mathjax> is:<br/> [m = 159.8 g/mol <mathjax>#xx#</mathjax> 0.500 moles] = 79.9 grams.</p> <p>79.9 grams are in 0.500 moles of <mathjax>#Fe_2O_3.#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/258970" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 14252 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many grams of #Fe_2O_3# are there in 0.500 mole of #Fe_2O_3#?

a979840c-6ddd-11ea-a99a-ccda262736ce

https://socratic.org/questions/how-much-thermal-energy-is-absorbed-by-750-grams-of-water-when-its-temperature-i

222.48 kJ

start physical_unit 10 10 heat_energy kj qc_end physical_unit 10 10 7 8 mass qc_end physical_unit 10 10 16 17 temperature qc_end physical_unit 10 10 19 20 temperature qc_end end

[{"type":"physical unit","value":"Absorbed thermal energy [OF] water [IN] kJ"}]

[{"type":"physical unit","value":"222.48 kJ"}]

[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{750 grams}"},{"type":"physical unit","value":"Temperature1 [OF] water [=] \\pu{15.4 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] water [=] \\pu{86.3 ℃}"}]

<h1 class="questionTitle" itemprop="name">How much thermal energy is absorbed by 750 grams of water when its temperature increases from 15.4 C to 86.3°C? </h1>

222.48 kJ

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Q = m*c*DeltaT#</mathjax></p> <p>Where ,</p> <p>Q = Thermal Energy<br/> m = mass of the matter,<br/> c = Specific heat<br/> ΔT = Temperature difference [ Delta T]</p> <p>So there is "-</p> <p>m = 750 gm<br/> c = 4.184 Joule<br/> ΔT = 70.9 Degree C</p> <p><mathjax>#Q = 750*4.184*70.9=222248#</mathjax></p> <p>22248 Joules <br/> or 222.48 kJ</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>222.27 kJ</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Q = m*c*DeltaT#</mathjax></p> <p>Where ,</p> <p>Q = Thermal Energy<br/> m = mass of the matter,<br/> c = Specific heat<br/> ΔT = Temperature difference [ Delta T]</p> <p>So there is "-</p> <p>m = 750 gm<br/> c = 4.184 Joule<br/> ΔT = 70.9 Degree C</p> <p><mathjax>#Q = 750*4.184*70.9=222248#</mathjax></p> <p>22248 Joules <br/> or 222.48 kJ</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How much thermal energy is absorbed by 750 grams of water when its temperature increases from 15.4 C to 86.3°C? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="343047" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/suresh-rawal"><img alt="" class="" src="https://profilepictures.socratic.org/xtD9rRMRMOIMqQl8Irg3_scan0002.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/suresh-rawal"> Suresh Rawal </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-28T09:46:39" itemprop="dateCreated"> Nov 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>222.27 kJ</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Q = m*c*DeltaT#</mathjax></p> <p>Where ,</p> <p>Q = Thermal Energy<br/> m = mass of the matter,<br/> c = Specific heat<br/> ΔT = Temperature difference [ Delta T]</p> <p>So there is "-</p> <p>m = 750 gm<br/> c = 4.184 Joule<br/> ΔT = 70.9 Degree C</p> <p><mathjax>#Q = 750*4.184*70.9=222248#</mathjax></p> <p>22248 Joules <br/> or 222.48 kJ</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/343047" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? 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How much thermal energy is absorbed by 750 grams of water when its temperature increases from 15.4 C to 86.3°C?