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aae1433e-6ddd-11ea-8416-ccda262736ce

https://socratic.org/questions/a-12-0-l-sample-of-argon-gas-has-a-pressure-of-28-0-atm-what-volume-would-this-g

34.64 L

start physical_unit 16 17 volume l qc_end physical_unit 3 6 1 2 volume qc_end physical_unit 3 6 11 12 pressure qc_end physical_unit 3 6 20 21 pressure qc_end end

[{"type":"physical unit","value":"Volume2 [OF] this gas [IN] L"}]

[{"type":"physical unit","value":"34.64 L"}]

[{"type":"physical unit","value":"Volume1 [OF] argon gas sample [=] \\pu{12.0 L}"},{"type":"physical unit","value":"Pressure1 [OF] argon gas sample [=] \\pu{28.0 atm}"},{"type":"physical unit","value":"Pressure2 [OF] argon gas sample [=] \\pu{9.70 atm}"}]

<h1 class="questionTitle" itemprop="name">A 12.0 L sample of argon gas has a pressure of 28.0 atm. What volume would this gas occupy at 9.70 atm? </h1>

34.64 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's start off with identifying our known and unknown variables. <br/> The first volume we have is 12.0 L, the first pressure is 28.0 atm, and the second pressure is 9.70 atm. Our only unknown is the second volume.</p> <p>We can obtain the answer using <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a> which shows that there is an inverse relationship between pressure and volume as long as the temperature and number of moles remain constant.</p> <p>The equation we use is <mathjax>#P_1V_1=P_2V_2#</mathjax><br/> where the numbers 1 and 2 represent the first and second conditions. All we have to do is rearrange the equation to solve for the volume. </p> <p>We do this by dividing both sides by <mathjax>#P_2#</mathjax> in order to get <mathjax>#V_2#</mathjax> by itself like so:<br/> <mathjax>#P_1V_1#</mathjax> <mathjax>#-:#</mathjax><mathjax>#P_2#</mathjax> = <mathjax>#V_2#</mathjax> </p> <p>Now all we do is plug and chug!<br/> (28.0 <mathjax>#cancel (atm#</mathjax>)) (12.0 L) <mathjax>#-:#</mathjax> (9.70 <mathjax>#cancel (atm#</mathjax>)) = 34.6 L </p> <p><a href="http://www.chemteam.info/GasLaw/Gas-Boyle.html" rel="nofollow">Boyle's Law Practice Problems </a> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume that this gas occupies is <mathjax>#34.6 L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's start off with identifying our known and unknown variables. <br/> The first volume we have is 12.0 L, the first pressure is 28.0 atm, and the second pressure is 9.70 atm. Our only unknown is the second volume.</p> <p>We can obtain the answer using <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a> which shows that there is an inverse relationship between pressure and volume as long as the temperature and number of moles remain constant.</p> <p>The equation we use is <mathjax>#P_1V_1=P_2V_2#</mathjax><br/> where the numbers 1 and 2 represent the first and second conditions. All we have to do is rearrange the equation to solve for the volume. </p> <p>We do this by dividing both sides by <mathjax>#P_2#</mathjax> in order to get <mathjax>#V_2#</mathjax> by itself like so:<br/> <mathjax>#P_1V_1#</mathjax> <mathjax>#-:#</mathjax><mathjax>#P_2#</mathjax> = <mathjax>#V_2#</mathjax> </p> <p>Now all we do is plug and chug!<br/> (28.0 <mathjax>#cancel (atm#</mathjax>)) (12.0 L) <mathjax>#-:#</mathjax> (9.70 <mathjax>#cancel (atm#</mathjax>)) = 34.6 L </p> <p><a href="http://www.chemteam.info/GasLaw/Gas-Boyle.html" rel="nofollow">Boyle's Law Practice Problems </a> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A 12.0 L sample of argon gas has a pressure of 28.0 atm. What volume would this gas occupy at 9.70 atm? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/boyle-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Boyle's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="274526" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kayla-14"><img alt="" class="" src="https://profilepictures.socratic.org/OvMTWaamQPWcqLIkUNnG_793604964071127.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kayla-14"> Kayla </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-06T04:59:10" itemprop="dateCreated"> Jun 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume that this gas occupies is <mathjax>#34.6 L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Let's start off with identifying our known and unknown variables. <br/> The first volume we have is 12.0 L, the first pressure is 28.0 atm, and the second pressure is 9.70 atm. Our only unknown is the second volume.</p> <p>We can obtain the answer using <a href="https://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a> which shows that there is an inverse relationship between pressure and volume as long as the temperature and number of moles remain constant.</p> <p>The equation we use is <mathjax>#P_1V_1=P_2V_2#</mathjax><br/> where the numbers 1 and 2 represent the first and second conditions. All we have to do is rearrange the equation to solve for the volume. </p> <p>We do this by dividing both sides by <mathjax>#P_2#</mathjax> in order to get <mathjax>#V_2#</mathjax> by itself like so:<br/> <mathjax>#P_1V_1#</mathjax> <mathjax>#-:#</mathjax><mathjax>#P_2#</mathjax> = <mathjax>#V_2#</mathjax> </p> <p>Now all we do is plug and chug!<br/> (28.0 <mathjax>#cancel (atm#</mathjax>)) (12.0 L) <mathjax>#-:#</mathjax> (9.70 <mathjax>#cancel (atm#</mathjax>)) = 34.6 L </p> <p><a href="http://www.chemteam.info/GasLaw/Gas-Boyle.html" rel="nofollow">Boyle's Law Practice Problems </a> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/274526" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="274527" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/sam-54"><img alt="" class="" src="https://profilepictures.socratic.org/3bkyAGe2RVWw1lx2h1A5_Avatar%201.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/sam-54"> Sam </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-06T05:04:28" itemprop="dateCreated"> Jun 6, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#V_2-=34.6 L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the combined gas low equation.</p> <p><mathjax>#(P_1xxV_1)/T_1=(P_2xxV_2)/T_2#</mathjax></p> <p><mathjax>#T_1=T_2#</mathjax> since the temperature remains constant.</p> <p><mathjax>#P_1xxV_1=P_2xxV_2#</mathjax></p> <p><mathjax>#V_2=(P_1xxV_1)/P_2#</mathjax></p> <p><mathjax>#V_2=(28.0\ atm xx 12.0\ L)/(9.70\ atm)#</mathjax></p> <p><mathjax>#V_2-=34.6 L#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/274527" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-graph-boyles-law"> How do you graph Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-functional-groups-are-found-in-lipids"> What functional groups are found in lipids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-k-constant-in-boyle-s-law"> Why is k constant in Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-graph-curved-1"> Why is Boyle's law graph curved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-an-inverse-relationship-2"> Why is Boyle's law an inverse relationship? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-40-0-l-tank-of-ammonia-has-a-pressure-of-8-00-atm-calculate-the-volume-of-the-"> A 40.0 L tank of ammonia has a pressure of 8.00 atm. 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A 12.0 L sample of argon gas has a pressure of 28.0 atm. What volume would this gas occupy at 9.70 atm?

ac876e8e-6ddd-11ea-9ccd-ccda262736ce

https://socratic.org/questions/57b671367c014948ffb15435

4.17

start physical_unit 5 5 ph none qc_end physical_unit 5 5 9 12 [h3o+] qc_end end

[{"type":"physical unit","value":"pH [OF] the solution"}]

[{"type":"physical unit","value":"4.17"}]

[{"type":"physical unit","value":"[H3O+] [OF] the solution [=] \\pu{6.7 × 10^(-5) mol/L}"}]

<h1 class="questionTitle" itemprop="name">What is #pH# for a solution whose #[H_3O^+]=6.7xx10^-5*mol*L^-1#?</h1>

4.17

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=log_10[H_3O^+]#</mathjax> (equivalently <mathjax>#pH=log_10[H^+]#</mathjax>).</p> <p>Thus <mathjax>#pH=log_10(6.7xx10^-5)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-(-4.17)#</mathjax></p> <p>Note that when we write <mathjax>#log_ab=c#</mathjax>, we are looking for the power to which we raise the base <mathjax>#a#</mathjax> to get <mathjax>#b#</mathjax>; here <mathjax>#a^c=b#</mathjax>. What are <mathjax>#log_(10)100#</mathjax>, <mathjax>#log_(10)1000000#</mathjax>, and <mathjax>#log_(10)0.001#</mathjax>?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=4.17#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=log_10[H_3O^+]#</mathjax> (equivalently <mathjax>#pH=log_10[H^+]#</mathjax>).</p> <p>Thus <mathjax>#pH=log_10(6.7xx10^-5)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-(-4.17)#</mathjax></p> <p>Note that when we write <mathjax>#log_ab=c#</mathjax>, we are looking for the power to which we raise the base <mathjax>#a#</mathjax> to get <mathjax>#b#</mathjax>; here <mathjax>#a^c=b#</mathjax>. What are <mathjax>#log_(10)100#</mathjax>, <mathjax>#log_(10)1000000#</mathjax>, and <mathjax>#log_(10)0.001#</mathjax>?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is #pH# for a solution whose #[H_3O^+]=6.7xx10^-5*mol*L^-1#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="300488" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-19T04:53:56" itemprop="dateCreated"> Aug 19, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#pH=4.17#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH=log_10[H_3O^+]#</mathjax> (equivalently <mathjax>#pH=log_10[H^+]#</mathjax>).</p> <p>Thus <mathjax>#pH=log_10(6.7xx10^-5)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-(-4.17)#</mathjax></p> <p>Note that when we write <mathjax>#log_ab=c#</mathjax>, we are looking for the power to which we raise the base <mathjax>#a#</mathjax> to get <mathjax>#b#</mathjax>; here <mathjax>#a^c=b#</mathjax>. What are <mathjax>#log_(10)100#</mathjax>, <mathjax>#log_(10)1000000#</mathjax>, and <mathjax>#log_(10)0.001#</mathjax>?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/300488" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1566 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is #pH# for a solution whose #[H_3O^+]=6.7xx10^-5*mol*L^-1#?

ac3b2d79-6ddd-11ea-899d-ccda262736ce

https://socratic.org/questions/how-many-grams-of-sulfur-are-needed-to-produce-1-40-moles-of-sodium-sulfide

44.80 grams

start physical_unit 4 4 mass g qc_end physical_unit 12 13 9 10 mole qc_end end

[{"type":"physical unit","value":"Mass [OF] sulfur [IN] grams"}]

[{"type":"physical unit","value":"44.80 grams"}]

[{"type":"physical unit","value":"Mole [OF] sodium sulfide [=] \\pu{1.40 moles}"}]

<h1 class="questionTitle" itemprop="name">How many grams of sulfur are needed to produce 1.40 moles of sodium sulfide?</h1>

44.80 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Formula of sodium sulfide is <mathjax>#Na_2S#</mathjax> ,This means 1 mole sulfide will contain 1 mole or 32g sulfur . Hence 1.4 mole sulfide salt requires 1.4x32=44.8 g sulfur</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>44.8 g of sulfur is needed</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Formula of sodium sulfide is <mathjax>#Na_2S#</mathjax> ,This means 1 mole sulfide will contain 1 mole or 32g sulfur . Hence 1.4 mole sulfide salt requires 1.4x32=44.8 g sulfur</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many grams of sulfur are needed to produce 1.40 moles of sodium sulfide?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="225621" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/dk-ch"><img alt="" class="" src="https://profilepictures.socratic.org/0aBlt69MSiWhfD1SEqb8_lotus.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/dk-ch"> P dilip_k </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-13T12:11:25" itemprop="dateCreated"> Feb 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>44.8 g of sulfur is needed</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Formula of sodium sulfide is <mathjax>#Na_2S#</mathjax> ,This means 1 mole sulfide will contain 1 mole or 32g sulfur . Hence 1.4 mole sulfide salt requires 1.4x32=44.8 g sulfur</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/225621" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -&gt; 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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How many grams of sulfur are needed to produce 1.40 moles of sodium sulfide?

abc67754-6ddd-11ea-a0ec-ccda262736ce

https://socratic.org/questions/how-many-grams-of-nacl-are-present-in-350-ml-of-0-020-m-nacl-solution-remember-t

0.41 grams

start physical_unit 4 4 mass g qc_end physical_unit 13 14 8 9 volume qc_end physical_unit 13 14 11 12 molarity qc_end physical_unit 4 4 19 20 molar_mass qc_end end

[{"type":"physical unit","value":"Mass [OF] NaCl [IN] grams"}]

[{"type":"physical unit","value":"0.41 grams"}]

[{"type":"physical unit","value":"Volume [OF] NaCl solution [=] \\pu{350 mL}"},{"type":"physical unit","value":"Molarity [OF] NaCl solution [=] \\pu{0.020 M}"},{"type":"physical unit","value":"Molar mass [OF] NaCl [=] \\pu{58.44 g/mole}"}]

<h1 class="questionTitle" itemprop="name">How many grams of NaCl are present in 350 mL of 0.020 M NaCL solution? (Remember that 1 mole NaCL = 58.44 grams g/mole.)?</h1>

0.41 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As stated, 1 mole of NaCl weighs 58.44 g.</p> <p>A 0.02 M solution contains 0.02 moles per liter.</p> <p>Hence, 1 litre would contain:</p> <p>58.44 x 0.02 = 1.1688 g</p> <p>However, there are only 350 ml, which is 0.35 liters.</p> <p>Therefore, there would be 0.35 x 1.1688 g in total, 0.409 g</p> <p>For further help this blog post on <a href="http://maths4biosciences.com/blog/concentrations/molarity-formula/" rel="nofollow">moles and molarity</a> may be useful.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.409 g</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As stated, 1 mole of NaCl weighs 58.44 g.</p> <p>A 0.02 M solution contains 0.02 moles per liter.</p> <p>Hence, 1 litre would contain:</p> <p>58.44 x 0.02 = 1.1688 g</p> <p>However, there are only 350 ml, which is 0.35 liters.</p> <p>Therefore, there would be 0.35 x 1.1688 g in total, 0.409 g</p> <p>For further help this blog post on <a href="http://maths4biosciences.com/blog/concentrations/molarity-formula/" rel="nofollow">moles and molarity</a> may be useful.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many grams of NaCl are present in 350 mL of 0.020 M NaCL solution? (Remember that 1 mole NaCL = 58.44 grams g/mole.)?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="300410" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nick-41"><img alt="" class="" src="https://profilepictures.socratic.org/Sq1QmKQKSPCfDM110rRn_16.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nick-41"> Nick </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-18T21:33:02" itemprop="dateCreated"> Aug 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.409 g</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As stated, 1 mole of NaCl weighs 58.44 g.</p> <p>A 0.02 M solution contains 0.02 moles per liter.</p> <p>Hence, 1 litre would contain:</p> <p>58.44 x 0.02 = 1.1688 g</p> <p>However, there are only 350 ml, which is 0.35 liters.</p> <p>Therefore, there would be 0.35 x 1.1688 g in total, 0.409 g</p> <p>For further help this blog post on <a href="http://maths4biosciences.com/blog/concentrations/molarity-formula/" rel="nofollow">moles and molarity</a> may be useful.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/300410" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="301493" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-22T03:15:22" itemprop="dateCreated"> Aug 22, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The 350 mL solution will contain 0.4 g NaCl.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The symbol for <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a>, M, represents the units mol/L. When you perform equations involving molarity, use the units mol/L. The 0.02 M solution is said to be 0.02 molar, and is 0.02 mol/L.</p> <p>Convert <mathjax>#"350 mL"#</mathjax> to liters.</p> <p><mathjax>#350cancel "mL"xx(1 "L")/(1000 cancel"mL")="0.35 L"#</mathjax></p> <p>In order to determine the moles of NaCl in the 0.35 L solution, multiply <mathjax>#"0.35 L"#</mathjax> by the molarity of the <mathjax>#"0.02 M NaCl"#</mathjax> solution. (Remember that the unit for molarity, M, is mol/L.)</p> <p><mathjax>#0.35 cancel"L"xx(0.02 "mol NaCl")/(1 cancel"L")="0.007 mol NaCl"#</mathjax></p> <p>In order to determine the mass of the NaCl in the 0.35 L NaCl solution, multiply the moles of <mathjax>#"NaCl"#</mathjax> by the molar mass of NaCl.</p> <p><mathjax>#0.007 cancel"mol NaCl"xx(58.44"g NaCl")/(1cancel"mol NaCl")="0.4 g NaCl"#</mathjax> (rounded to one significant figure, because of the 0.02 M solution)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/301493" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 42945 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many grams of NaCl are present in 350 mL of 0.020 M NaCL solution? (Remember that 1 mole NaCL = 58.44 grams g/mole.)?

ad1fc9bf-6ddd-11ea-a24c-ccda262736ce

https://socratic.org/questions/5616baf3581e2a51d0aadac7

24.00 mol/L

start physical_unit 5 6 concentration mol/l qc_end physical_unit 12 12 9 10 concentration qc_end end

[{"type":"physical unit","value":"Concentration [OF] sulfate ion [IN] mol/L"}]

[{"type":"physical unit","value":"24.00 mol/L"}]

[{"type":"physical unit","value":"Concentration [OF] Mn(SO4)2 [=] \\pu{12 mol/L}"}]

<h1 class="questionTitle" itemprop="name">What is the concentration of sulfate ion in a #12*mol*L^-1# of #Mn(SO_4)_2#?</h1>

24.00 mol/L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If it is indeed <mathjax>#Mn(IV)#</mathjax> sulfate, the concentration is <mathjax>#2xx#</mathjax> the stated concentration.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Concentration of <mathjax>#Mn(SO_4)_2#</mathjax> in a <mathjax>#12*mol*L^(-1)#</mathjax> solution? Are you sure it's <mathjax>#Mn(IV)#</mathjax>? </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If it is indeed <mathjax>#Mn(IV)#</mathjax> sulfate, the concentration is <mathjax>#2xx#</mathjax> the stated concentration.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the concentration of sulfate ion in a #12*mol*L^-1# of #Mn(SO_4)_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="175223" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-08T21:20:32" itemprop="dateCreated"> Oct 8, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Concentration of <mathjax>#Mn(SO_4)_2#</mathjax> in a <mathjax>#12*mol*L^(-1)#</mathjax> solution? Are you sure it's <mathjax>#Mn(IV)#</mathjax>? </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>If it is indeed <mathjax>#Mn(IV)#</mathjax> sulfate, the concentration is <mathjax>#2xx#</mathjax> the stated concentration.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/175223" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1557 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the concentration of sulfate ion in a #12*mol*L^-1# of #Mn(SO_4)_2#?

a9480294-6ddd-11ea-82a4-ccda262736ce

https://socratic.org/questions/if-the-heat-of-combustion-for-a-specific-compound-is-1110-0-kj-mol-and-its-molar

67.22 grams

start physical_unit 23 24 mass g qc_end physical_unit 23 24 10 11 enthalpy_of_combustion qc_end physical_unit 23 24 17 18 molar_mass qc_end physical_unit 23 24 30 31 heat_energy qc_end end

[{"type":"physical unit","value":"Mass [OF] this compound [IN] grams"}]

[{"type":"physical unit","value":"67.22 grams"}]

[{"type":"physical unit","value":"Heat of combustion [OF] this compound [=] \\pu{-1110.0 kJ/mol}"},{"type":"physical unit","value":"Molar mass [OF] this compound [=] \\pu{89.45 g/mol}"},{"type":"physical unit","value":"Released heat [OF] this compound [=] \\pu{834.20 kJ}"}]

<h1 class="questionTitle" itemprop="name">If the heat of combustion for a specific compound is -1110.0 kJ/mol and its molar mass is 89.45 g/mol, how many grams of this compound must you burn to release 834.20 kJ of heat? </h1>

67.22 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#834.20kJ((mol)/(1110.0kJ))((89.45g)/(mol)) = 67.22g#</mathjax></p> <p>The reason the sign was changed is because "releasing" heat in the question implies an exothermic system. That's exactly what this substance is, so the signs were matched.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#67.22g#</mathjax> of the substance must be burned to release that much heat.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#834.20kJ((mol)/(1110.0kJ))((89.45g)/(mol)) = 67.22g#</mathjax></p> <p>The reason the sign was changed is because "releasing" heat in the question implies an exothermic system. That's exactly what this substance is, so the signs were matched.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If the heat of combustion for a specific compound is -1110.0 kJ/mol and its molar mass is 89.45 g/mol, how many grams of this compound must you burn to release 834.20 kJ of heat? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/enthalpy" itemprop="url"> <span class="breadcrumb" itemprop="title">Enthalpy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="448812" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/al-e"><img alt="" class="" src="https://lh4.googleusercontent.com/-oz5UmZwruBQ/AAAAAAAAAAI/AAAAAAAAAFs/Oc0IDeN2ejw/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/al-e"> Al E. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-07T00:58:57" itemprop="dateCreated"> Jul 7, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#67.22g#</mathjax> of the substance must be burned to release that much heat.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#834.20kJ((mol)/(1110.0kJ))((89.45g)/(mol)) = 67.22g#</mathjax></p> <p>The reason the sign was changed is because "releasing" heat in the question implies an exothermic system. That's exactly what this substance is, so the signs were matched.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/448812" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-enthalpy-changes-expressed-in-chemical-equations"> How are enthalpy changes expressed in chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-enthalpy-change-be-determined-for-an-aqueous-solution"> How can enthalpy change be determined for an aqueous solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-change-with-pressure"> How does enthalpy change with pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-standard-molar-enthalpy-formation"> How do you calculate standard molar enthalpy of formation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-enthalpy-of-formation-of-oxygen-zero"> Why is the enthalpy of formation of oxygen zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function-2"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-enthalpy-cannot-be-measured-directly"> Why can enthalpy not be measured directly? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-pressure-affect-enthalpy"> How does pressure affect enthalpy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-relate-to-internal-energy"> How does enthalpy relate to internal energy? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/enthalpy"> See all questions in Enthalpy </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5801 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

If the heat of combustion for a specific compound is -1110.0 kJ/mol and its molar mass is 89.45 g/mol, how many grams of this compound must you burn to release 834.20 kJ of heat?

ad0eccca-6ddd-11ea-954c-ccda262736ce

https://socratic.org/questions/given-the-balanced-equation-representing-a-reaction-mg-s-ni-2-aq-mg-2-aq-ni-s-wh

2.00 moles

start physical_unit 22 25 mole mol qc_end chemical_equation 7 13 qc_end end

[{"type":"physical unit","value":"Mole [OF] electrons lost by Mg(s) [IN] moles"}]

[{"type":"physical unit","value":"2.00 moles"}]

[{"type":"physical unit","value":"Mole [OF] electrons gained by Ni^2+(aq) [=] \\pu{2.0 moles}"},{"type":"chemical equation","value":"Mg(s) + Ni^2+(aq) -> Mg^2+(aq) + Ni(s)"}]

<h1 class="questionTitle" itemprop="name">Given the balanced equation representing a reaction: #Mg(s) + Ni^(2+)(aq) -&gt; Mg^(2+)(aq) + Ni(s)# What is the total number of moles of electrons lost by Mg(s) when 2.0 moles of electrons are gained by #Ni^(2+)#(aq)?</h1>

2.00 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since the equation is balanced, the reactants (and their total charge) must equal the products and their overall charge. </p> <p>In other words, nothing is lost during the reaction. </p> <p>In this reaction, magnesium is oxidized and nickel is reduced. </p> <p>The electrons are transferred from magnesium to nickel and because electrons have a negative charge, this results in <mathjax>#"Ni"^"2+"#</mathjax> becoming neutral <mathjax>#"Ni"#</mathjax>. </p> <p>Because the magnesium lost the two electrons, it now becomes <mathjax>#"Mg"^"2+"#</mathjax> because there are now 2 more protons than electrons,</p> <p>(in a neutral atom the number of electrons = the number of protons) </p> <p>Thus resulting in the 2+ charge.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are also 2.0 moles of electrons lost from Mg.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since the equation is balanced, the reactants (and their total charge) must equal the products and their overall charge. </p> <p>In other words, nothing is lost during the reaction. </p> <p>In this reaction, magnesium is oxidized and nickel is reduced. </p> <p>The electrons are transferred from magnesium to nickel and because electrons have a negative charge, this results in <mathjax>#"Ni"^"2+"#</mathjax> becoming neutral <mathjax>#"Ni"#</mathjax>. </p> <p>Because the magnesium lost the two electrons, it now becomes <mathjax>#"Mg"^"2+"#</mathjax> because there are now 2 more protons than electrons,</p> <p>(in a neutral atom the number of electrons = the number of protons) </p> <p>Thus resulting in the 2+ charge.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Given the balanced equation representing a reaction: #Mg(s) + Ni^(2+)(aq) -&gt; Mg^(2+)(aq) + Ni(s)# What is the total number of moles of electrons lost by Mg(s) when 2.0 moles of electrons are gained by #Ni^(2+)#(aq)?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="437266" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michael-l-13"><img alt="" class="" src="https://lh3.googleusercontent.com/-x25Cyr0jiss/AAAAAAAAAAI/AAAAAAAAAAA/U30j176zIfI/photo.jpg?sz=50" title=""/></a> <a class="secondContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michael-l-13"> Michael L. </a>·<a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-09T22:59:26" itemprop="dateCreated"> Jun 9, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are also 2.0 moles of electrons lost from Mg.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Since the equation is balanced, the reactants (and their total charge) must equal the products and their overall charge. </p> <p>In other words, nothing is lost during the reaction. </p> <p>In this reaction, magnesium is oxidized and nickel is reduced. </p> <p>The electrons are transferred from magnesium to nickel and because electrons have a negative charge, this results in <mathjax>#"Ni"^"2+"#</mathjax> becoming neutral <mathjax>#"Ni"#</mathjax>. </p> <p>Because the magnesium lost the two electrons, it now becomes <mathjax>#"Mg"^"2+"#</mathjax> because there are now 2 more protons than electrons,</p> <p>(in a neutral atom the number of electrons = the number of protons) </p> <p>Thus resulting in the 2+ charge.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/437266" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? 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Given the balanced equation representing a reaction: #Mg(s) + Ni^(2+)(aq) -&gt; Mg^(2+)(aq) + Ni(s)# What is the total number of moles of electrons lost by Mg(s) when 2.0 moles of electrons are gained by #Ni^(2+)#(aq)?

aaabf524-6ddd-11ea-bcb2-ccda262736ce

https://socratic.org/questions/what-is-the-ph-of-a-solution-whose-h-3o-concentration-is-1-10-9

9.00

start physical_unit 6 6 ph none qc_end physical_unit 8 8 11 13 concentration qc_end end

[{"type":"physical unit","value":"pH [OF] the solution"}]

[{"type":"physical unit","value":"9.00"}]

[{"type":"physical unit","value":"Concentration [OF] H3O+ [=] \\pu{1 × 10^(-9)}"}]

<h1 class="questionTitle" itemprop="name">What is the pH of a solution whose #H_3O^+# concentration is #1*10^-9#?</h1>

9.00

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of an acid is given by <mathjax>#-log[H_3O]#</mathjax></p> <p>Where <mathjax>#[H_3O]#</mathjax> is concentration of <mathjax>#[H_3O]#</mathjax> ions</p> <p>So, pH is <mathjax>#-log(10^-9)#</mathjax></p> <p><mathjax>#=-(-9)#</mathjax></p> <p><mathjax>#=9#</mathjax></p> <p>Note: The logarithm is to the base 10.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>9</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of an acid is given by <mathjax>#-log[H_3O]#</mathjax></p> <p>Where <mathjax>#[H_3O]#</mathjax> is concentration of <mathjax>#[H_3O]#</mathjax> ions</p> <p>So, pH is <mathjax>#-log(10^-9)#</mathjax></p> <p><mathjax>#=-(-9)#</mathjax></p> <p><mathjax>#=9#</mathjax></p> <p>Note: The logarithm is to the base 10.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the pH of a solution whose #H_3O^+# concentration is #1*10^-9#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="581068" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/anish-m"><img alt="" class="" src="https://lh3.googleusercontent.com/-XdUIqdMkCWA/AAAAAAAAAAI/AAAAAAAAAAA/4252rscbv5M/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/anish-m"> Anish M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-03-24T16:59:11" itemprop="dateCreated"> Mar 24, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>9</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> of an acid is given by <mathjax>#-log[H_3O]#</mathjax></p> <p>Where <mathjax>#[H_3O]#</mathjax> is concentration of <mathjax>#[H_3O]#</mathjax> ions</p> <p>So, pH is <mathjax>#-log(10^-9)#</mathjax></p> <p><mathjax>#=-(-9)#</mathjax></p> <p><mathjax>#=9#</mathjax></p> <p>Note: The logarithm is to the base 10.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/581068" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? 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What is the pH of a solution whose #H_3O^+# concentration is #1*10^-9#?

a9cde81a-6ddd-11ea-b0c7-ccda262736ce

https://socratic.org/questions/a-mass-of-18-gram-of-compound-m-2-co-3-x-h-2-o-molar-mass-of-m-24-g-mol-is-disso

2

start physical_unit 41 41 value none qc_end physical_unit 8 8 3 4 mass qc_end physical_unit 9 10 12 13 molar_mass qc_end physical_unit 20 20 17 18 volume qc_end physical_unit 27 28 25 26 molarity qc_end physical_unit 27 28 17 18 volume qc_end end

[{"type":"physical unit","value":"Value [OF] x"}]

[{"type":"physical unit","value":"2"}]

[{"type":"physical unit","value":"Mass [OF] M2CO3.xH2O [=] \\pu{18 g}"},{"type":"physical unit","value":"M [OF] M metal [=] \\pu{24 g/mol}"},{"type":"physical unit","value":"Volume [OF] water [=] \\pu{500 mL}"},{"type":"physical unit","value":"Molarity [OF] HCl solution [=] \\pu{0.5 M}"},{"type":"physical unit","value":"Volume [OF] HCl solution [=] \\pu{500 mL}"}]

<h1 class="questionTitle" itemprop="name">A mass of #"18 g"# of a compound #"M"_2"CO"_3 * x"H"_2"O"# #(M_ "M metal" = "24 g/mol")# is dissolved in #"500 mL"# of water and titrated against a #"0.5-M"# #"HCl"# solution. If the volume of #"HCl"# consumed is #"500 mL"#, the value of #x# is?</h1>

2

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you can use the number of moles of <em>anhydrous metal carbonate</em> that took place in the reaction to figure out the number of moles of water present in the hydrate. </p> <p>You know that you have</p> <blockquote> <p><mathjax>#"M"_ 2"CO"_ (3(aq)) + 2"HCl"_ ((aq)) -&gt; 2"MCl"_ ((aq)) + "H"_ 2"O"_ ((l)) + "CO"_ (2(g)) uarr#</mathjax></p> </blockquote> <p>The reaction consumes <mathjax>#2#</mathjax> <strong>moles</strong> of hydrochloric acid for every <mathjax>#1#</mathjax> <strong>mole</strong> of anhydrous metal carbonate. </p> <p>Use the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and the volume of the hydrochloric acid solution to find the number of moles of acid that were consumed in the reaction. </p> <blockquote> <p><mathjax>#500 color(red)(cancel(color(black)("mL solution"))) * "0.5 moles HCl"/(10^3color(red)(cancel(color(black)("mL solution")))) = "0.25 moles HCl"#</mathjax></p> </blockquote> <p>This implies that the reaction consumed</p> <blockquote> <p><mathjax>#0.25 color(red)(cancel(color(black)("moles HCl"))) * ("1 mole M"_2"CO"_3)/(2color(red)(cancel(color(black)("moles HCl")))) = "0.125 moles M"_2"CO"_3#</mathjax></p> </blockquote> <p>Now, use the molar mass of the metal to find the molar mass of the anhydrous metal carbonate. You will end up with</p> <blockquote> <p><mathjax>#M_ ("M M"_2"CO"_3) = 2 * "24 g mol"^(-1) + "12.011 g mol"^(-1) + 3 * "16.0 g mol"^(-1)#</mathjax></p> <p><mathjax>#M_ ("M M"_2"CO"_3) = "108.011 g mol"^(-1)#</mathjax></p> </blockquote> <p>Use this value to find the number of grams of anhydrous metal carbonate present in the initial sample, i.e. in the <em>hydrated metal carbonate</em>. </p> <blockquote> <p><mathjax>#0.125 color(red)(cancel(color(black)("moles M"_2"CO"_3))) * "108.011 g"/(1color(red)(cancel(color(black)("mole M"_2"CO"_3)))) = "13.5 g"#</mathjax></p> </blockquote> <p>This implies that the hydrate contained</p> <blockquote> <p><mathjax>#m_ ("H"_ 2"O") = "18 g " - " 13.5 g"#</mathjax></p> <p><mathjax>#m_ ("H"_ 2"O") = "4.5 g"#</mathjax></p> </blockquote> <p>of water of hydration. Use the <strong>molar mass</strong> of water to find the number of moles of water of hydration present in the hydrate.</p> <blockquote> <p><mathjax>#4.5 color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))) = "0.2498 moles H"_2"O"#</mathjax></p> </blockquote> <p>Finally, to find the value of <mathjax>#x#</mathjax>, you need to find the number of moles of water present in exactly <mathjax>#1#</mathjax> <strong>mole</strong> of hydrate. Since you know that <strong>every mole</strong> of hydrate contains <mathjax>#1#</mathjax> <strong>mole</strong> of anhydrous metal carbonate, you can say that </p> <blockquote> <p><mathjax>#"0.125 moles M"_2"CO"_3 * x"H"_2"O" " " -&gt; " " "0.2498 moles H"_2"O"#</mathjax></p> </blockquote> <p>This implies that <mathjax>#1#</mathjax> <strong>mole</strong> of hydrate will contain </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("mole hydrate"))) * ("0.2498 moles H"_2"O")/(0.125 color(red)(cancel(color(black)("moles hydrate")))) ~~ "2 moles H"_2"O"#</mathjax></p> </blockquote> <p>Therefore, you have </p> <blockquote> <p><mathjax>#x = 2#</mathjax></p> </blockquote> <p>which means that you're dealing with a <em>dihydrate</em>.</p> <blockquote> <p><mathjax>#"M"_2"CO"_3 * 2"H"_2"O"#</mathjax></p> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#x = 2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you can use the number of moles of <em>anhydrous metal carbonate</em> that took place in the reaction to figure out the number of moles of water present in the hydrate. </p> <p>You know that you have</p> <blockquote> <p><mathjax>#"M"_ 2"CO"_ (3(aq)) + 2"HCl"_ ((aq)) -&gt; 2"MCl"_ ((aq)) + "H"_ 2"O"_ ((l)) + "CO"_ (2(g)) uarr#</mathjax></p> </blockquote> <p>The reaction consumes <mathjax>#2#</mathjax> <strong>moles</strong> of hydrochloric acid for every <mathjax>#1#</mathjax> <strong>mole</strong> of anhydrous metal carbonate. </p> <p>Use the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and the volume of the hydrochloric acid solution to find the number of moles of acid that were consumed in the reaction. </p> <blockquote> <p><mathjax>#500 color(red)(cancel(color(black)("mL solution"))) * "0.5 moles HCl"/(10^3color(red)(cancel(color(black)("mL solution")))) = "0.25 moles HCl"#</mathjax></p> </blockquote> <p>This implies that the reaction consumed</p> <blockquote> <p><mathjax>#0.25 color(red)(cancel(color(black)("moles HCl"))) * ("1 mole M"_2"CO"_3)/(2color(red)(cancel(color(black)("moles HCl")))) = "0.125 moles M"_2"CO"_3#</mathjax></p> </blockquote> <p>Now, use the molar mass of the metal to find the molar mass of the anhydrous metal carbonate. You will end up with</p> <blockquote> <p><mathjax>#M_ ("M M"_2"CO"_3) = 2 * "24 g mol"^(-1) + "12.011 g mol"^(-1) + 3 * "16.0 g mol"^(-1)#</mathjax></p> <p><mathjax>#M_ ("M M"_2"CO"_3) = "108.011 g mol"^(-1)#</mathjax></p> </blockquote> <p>Use this value to find the number of grams of anhydrous metal carbonate present in the initial sample, i.e. in the <em>hydrated metal carbonate</em>. </p> <blockquote> <p><mathjax>#0.125 color(red)(cancel(color(black)("moles M"_2"CO"_3))) * "108.011 g"/(1color(red)(cancel(color(black)("mole M"_2"CO"_3)))) = "13.5 g"#</mathjax></p> </blockquote> <p>This implies that the hydrate contained</p> <blockquote> <p><mathjax>#m_ ("H"_ 2"O") = "18 g " - " 13.5 g"#</mathjax></p> <p><mathjax>#m_ ("H"_ 2"O") = "4.5 g"#</mathjax></p> </blockquote> <p>of water of hydration. Use the <strong>molar mass</strong> of water to find the number of moles of water of hydration present in the hydrate.</p> <blockquote> <p><mathjax>#4.5 color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))) = "0.2498 moles H"_2"O"#</mathjax></p> </blockquote> <p>Finally, to find the value of <mathjax>#x#</mathjax>, you need to find the number of moles of water present in exactly <mathjax>#1#</mathjax> <strong>mole</strong> of hydrate. Since you know that <strong>every mole</strong> of hydrate contains <mathjax>#1#</mathjax> <strong>mole</strong> of anhydrous metal carbonate, you can say that </p> <blockquote> <p><mathjax>#"0.125 moles M"_2"CO"_3 * x"H"_2"O" " " -&gt; " " "0.2498 moles H"_2"O"#</mathjax></p> </blockquote> <p>This implies that <mathjax>#1#</mathjax> <strong>mole</strong> of hydrate will contain </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("mole hydrate"))) * ("0.2498 moles H"_2"O")/(0.125 color(red)(cancel(color(black)("moles hydrate")))) ~~ "2 moles H"_2"O"#</mathjax></p> </blockquote> <p>Therefore, you have </p> <blockquote> <p><mathjax>#x = 2#</mathjax></p> </blockquote> <p>which means that you're dealing with a <em>dihydrate</em>.</p> <blockquote> <p><mathjax>#"M"_2"CO"_3 * 2"H"_2"O"#</mathjax></p> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A mass of #"18 g"# of a compound #"M"_2"CO"_3 * x"H"_2"O"# #(M_ "M metal" = "24 g/mol")# is dissolved in #"500 mL"# of water and titrated against a #"0.5-M"# #"HCl"# solution. If the volume of #"HCl"# consumed is #"500 mL"#, the value of #x# is?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/determining-formula-and-molar-masses" itemprop="url"> <span class="breadcrumb" itemprop="title">Determining Formula</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="511255" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-11-26T00:46:04" itemprop="dateCreated"> Nov 26, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#x = 2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you can use the number of moles of <em>anhydrous metal carbonate</em> that took place in the reaction to figure out the number of moles of water present in the hydrate. </p> <p>You know that you have</p> <blockquote> <p><mathjax>#"M"_ 2"CO"_ (3(aq)) + 2"HCl"_ ((aq)) -&gt; 2"MCl"_ ((aq)) + "H"_ 2"O"_ ((l)) + "CO"_ (2(g)) uarr#</mathjax></p> </blockquote> <p>The reaction consumes <mathjax>#2#</mathjax> <strong>moles</strong> of hydrochloric acid for every <mathjax>#1#</mathjax> <strong>mole</strong> of anhydrous metal carbonate. </p> <p>Use the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a> and the volume of the hydrochloric acid solution to find the number of moles of acid that were consumed in the reaction. </p> <blockquote> <p><mathjax>#500 color(red)(cancel(color(black)("mL solution"))) * "0.5 moles HCl"/(10^3color(red)(cancel(color(black)("mL solution")))) = "0.25 moles HCl"#</mathjax></p> </blockquote> <p>This implies that the reaction consumed</p> <blockquote> <p><mathjax>#0.25 color(red)(cancel(color(black)("moles HCl"))) * ("1 mole M"_2"CO"_3)/(2color(red)(cancel(color(black)("moles HCl")))) = "0.125 moles M"_2"CO"_3#</mathjax></p> </blockquote> <p>Now, use the molar mass of the metal to find the molar mass of the anhydrous metal carbonate. You will end up with</p> <blockquote> <p><mathjax>#M_ ("M M"_2"CO"_3) = 2 * "24 g mol"^(-1) + "12.011 g mol"^(-1) + 3 * "16.0 g mol"^(-1)#</mathjax></p> <p><mathjax>#M_ ("M M"_2"CO"_3) = "108.011 g mol"^(-1)#</mathjax></p> </blockquote> <p>Use this value to find the number of grams of anhydrous metal carbonate present in the initial sample, i.e. in the <em>hydrated metal carbonate</em>. </p> <blockquote> <p><mathjax>#0.125 color(red)(cancel(color(black)("moles M"_2"CO"_3))) * "108.011 g"/(1color(red)(cancel(color(black)("mole M"_2"CO"_3)))) = "13.5 g"#</mathjax></p> </blockquote> <p>This implies that the hydrate contained</p> <blockquote> <p><mathjax>#m_ ("H"_ 2"O") = "18 g " - " 13.5 g"#</mathjax></p> <p><mathjax>#m_ ("H"_ 2"O") = "4.5 g"#</mathjax></p> </blockquote> <p>of water of hydration. Use the <strong>molar mass</strong> of water to find the number of moles of water of hydration present in the hydrate.</p> <blockquote> <p><mathjax>#4.5 color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))) = "0.2498 moles H"_2"O"#</mathjax></p> </blockquote> <p>Finally, to find the value of <mathjax>#x#</mathjax>, you need to find the number of moles of water present in exactly <mathjax>#1#</mathjax> <strong>mole</strong> of hydrate. Since you know that <strong>every mole</strong> of hydrate contains <mathjax>#1#</mathjax> <strong>mole</strong> of anhydrous metal carbonate, you can say that </p> <blockquote> <p><mathjax>#"0.125 moles M"_2"CO"_3 * x"H"_2"O" " " -&gt; " " "0.2498 moles H"_2"O"#</mathjax></p> </blockquote> <p>This implies that <mathjax>#1#</mathjax> <strong>mole</strong> of hydrate will contain </p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("mole hydrate"))) * ("0.2498 moles H"_2"O")/(0.125 color(red)(cancel(color(black)("moles hydrate")))) ~~ "2 moles H"_2"O"#</mathjax></p> </blockquote> <p>Therefore, you have </p> <blockquote> <p><mathjax>#x = 2#</mathjax></p> </blockquote> <p>which means that you're dealing with a <em>dihydrate</em>.</p> <blockquote> <p><mathjax>#"M"_2"CO"_3 * 2"H"_2"O"#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/511255" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-possible-to-find-a-molecular-formula-from-molar-mass"> Is it possible to find a molecular formula from molar mass? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5368e0cc02bf34779e175781"> Question #75781 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-when-determining-formulas"> What are some common mistakes students make when determining formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-an-acid"> How can I determine the formula of an acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-chemical-formula-of-a-product"> How can I determine the chemical formula of a product? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-empirical-formula-of-a-compound"> How can I determine the empirical formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-a-hydrate"> How can I determine the formula of a hydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-empirical-formula-indicate"> What does the empirical formula indicate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-molecule-with-molecular-weight-of-180-18-g-mol-is-analyzed-and-found-to-contai"> A molecule with molecular weight of 180.18 g/mol is analyzed and found to contain 40.00% carbon,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-i-need-to-know-the-number-of-moles-of-each-element-to-determine-the-formula-o"> Do I need to know the number of moles of each element to determine the formula of the compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/determining-formula-and-molar-masses"> See all questions in Determining Formula </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1738 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A mass of #"18 g"# of a compound #"M"_2"CO"_3 * x"H"_2"O"# #(M_ "M metal" = "24 g/mol")# is dissolved in #"500 mL"# of water and titrated against a #"0.5-M"# #"HCl"# solution. If the volume of #"HCl"# consumed is #"500 mL"#, the value of #x# is?

ac243d50-6ddd-11ea-8f89-ccda262736ce

https://socratic.org/questions/58c816707c0149606678cb5e

MgCO3(s) ->[\delta] MgO(s) + CO2(g)

start chemical_equation qc_end substance 2 3 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"MgCO3(s) ->[\\delta] MgO(s) + CO2(g)"}]

[{"type":"substance name","value":"Magnesium carbonate"}]

<h1 class="questionTitle" itemprop="name">How does magnesium carbonate decompose under heating?</h1>

MgCO3(s) ->[\delta] MgO(s) + CO2(g)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Most metal carbonates decompose according to this scheme to give the metal oxide and carbon dioxide gas. I leave it to you to calculate the percentage loss with respect to the magnesium salt. The <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> are constant for products and reactants: <mathjax>#Mg(+II); C(+IV); O(-II)#</mathjax> for products and reactants; i.e. this is not a redox reaction. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#MgCO_3(s) + Delta rarr MgO(s) + CO_2(g)uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Most metal carbonates decompose according to this scheme to give the metal oxide and carbon dioxide gas. I leave it to you to calculate the percentage loss with respect to the magnesium salt. The <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> are constant for products and reactants: <mathjax>#Mg(+II); C(+IV); O(-II)#</mathjax> for products and reactants; i.e. this is not a redox reaction. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How does magnesium carbonate decompose under heating?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/decomposition-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Decomposition Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="391205" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-14T16:31:27" itemprop="dateCreated"> Mar 14, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#MgCO_3(s) + Delta rarr MgO(s) + CO_2(g)uarr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Most metal carbonates decompose according to this scheme to give the metal oxide and carbon dioxide gas. I leave it to you to calculate the percentage loss with respect to the magnesium salt. The <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a> are constant for products and reactants: <mathjax>#Mg(+II); C(+IV); O(-II)#</mathjax> for products and reactants; i.e. this is not a redox reaction. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/391205" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-decomposition-reactions"> What are decomposition reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-decomposition-reactions"> What are some examples of decomposition reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-decomposition-reaction-be-recognized"> How can a decomposition reaction be recognized? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-decomposition-reaction-differ-from-other-types-of-reactions"> How does a decomposition reaction differ from other types of reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-double-decomposition-reactions"> What are double decomposition reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-decomposition-reactions"> How can I balance decomposition reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-thermal-decomposition-reactions"> What are thermal decomposition reactions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-decomposition-reactions-require-energy"> Do decomposition reactions require energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-mass-spectrometry-relate-to-decomposition"> How does mass spectrometry relate to decomposition? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-chlorates-decompose-when-heated"> Do chlorates decompose when heated? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/decomposition-reactions"> See all questions in Decomposition Reactions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6110 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How does magnesium carbonate decompose under heating?

aac939d0-6ddd-11ea-9555-ccda262736ce

https://socratic.org/questions/how-many-grams-of-nacl-equal-a-mole-of-naci

58.44 grams

start physical_unit 4 4 mass g qc_end end

[{"type":"physical unit","value":"Mass [OF] NaCl [IN] grams"}]

[{"type":"physical unit","value":"58.44 grams"}]

[{"type":"physical unit","value":"Mole [OF] NaCl [=] \\pu{1 mole}"}]

<h1 class="questionTitle" itemprop="name">How many grams of NaCl equal a mole of NaCI? </h1>

58.44 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem essentially wants you to find the <strong>molar mass</strong> of sodium chloride, <mathjax>#"NaCl"#</mathjax>. As you know, the <em>molar mass</em> of an ionic compound gives you the mass of <strong>one mole</strong> of formula units of that compound. </p> <p>Now, as given by the compound's chemical formula, one formula unit of sodium chloride contains</p> <blockquote> <ul> <li><em><strong>one sodium cation</strong></em>, <mathjax>#1 xx "Na"^(+)#</mathjax></li> <li><em><strong>one chloride anion</strong></em>, <mathjax>#1 xx "Cl"^(-)#</mathjax></li> </ul> </blockquote> <p>This means that the mass of <strong>one mole of formula units</strong> will be equal to the sum of the mass of <strong>one mole</strong> of sodium cations and the mass of <strong>one mole</strong> of chloride anions. </p> <p>Since the mass of an ion is basically <em>the same</em> as the mass of the <strong>neutral atom</strong>, you can say that the <strong>molar mass</strong> of sodium chloride will be equal to the sum of the <strong>molar mass</strong> of sodium, <mathjax>#"Na"#</mathjax>, and the <strong>molar mass</strong> of chlorine, <mathjax>#"Cl"#</mathjax>. </p> <p>As given in <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the Periodic Table</a> of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">Elements</a>, these are equal to </p> <blockquote> <p><mathjax>#M_("M Na") = "22.98977 g mol"^(-1)#</mathjax></p> <p><mathjax>#M_("MCl") = "35.4527 g mol"^(-1)#</mathjax></p> </blockquote> <p>You thus have</p> <blockquote> <p><mathjax>#M_("M NaCl") = "22.98977 g mol"^(-1) + "35.4527 g mol"^(-1)#</mathjax></p> <p><mathjax>#M_("M NaCl") = "58.44247 g mol"^(-1)#</mathjax></p> </blockquote> <p>This means that the mass of <strong>one mole</strong> of sodium chloride is equal to</p> <blockquote> <p><mathjax>#color(green)(|bar(ul(color(white)(a/a)color(black)(m_("NaCl / 1 mole") = "58.44247 g")color(white)(a/a)|)))#</mathjax></p> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"58.44247 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem essentially wants you to find the <strong>molar mass</strong> of sodium chloride, <mathjax>#"NaCl"#</mathjax>. As you know, the <em>molar mass</em> of an ionic compound gives you the mass of <strong>one mole</strong> of formula units of that compound. </p> <p>Now, as given by the compound's chemical formula, one formula unit of sodium chloride contains</p> <blockquote> <ul> <li><em><strong>one sodium cation</strong></em>, <mathjax>#1 xx "Na"^(+)#</mathjax></li> <li><em><strong>one chloride anion</strong></em>, <mathjax>#1 xx "Cl"^(-)#</mathjax></li> </ul> </blockquote> <p>This means that the mass of <strong>one mole of formula units</strong> will be equal to the sum of the mass of <strong>one mole</strong> of sodium cations and the mass of <strong>one mole</strong> of chloride anions. </p> <p>Since the mass of an ion is basically <em>the same</em> as the mass of the <strong>neutral atom</strong>, you can say that the <strong>molar mass</strong> of sodium chloride will be equal to the sum of the <strong>molar mass</strong> of sodium, <mathjax>#"Na"#</mathjax>, and the <strong>molar mass</strong> of chlorine, <mathjax>#"Cl"#</mathjax>. </p> <p>As given in <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the Periodic Table</a> of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">Elements</a>, these are equal to </p> <blockquote> <p><mathjax>#M_("M Na") = "22.98977 g mol"^(-1)#</mathjax></p> <p><mathjax>#M_("MCl") = "35.4527 g mol"^(-1)#</mathjax></p> </blockquote> <p>You thus have</p> <blockquote> <p><mathjax>#M_("M NaCl") = "22.98977 g mol"^(-1) + "35.4527 g mol"^(-1)#</mathjax></p> <p><mathjax>#M_("M NaCl") = "58.44247 g mol"^(-1)#</mathjax></p> </blockquote> <p>This means that the mass of <strong>one mole</strong> of sodium chloride is equal to</p> <blockquote> <p><mathjax>#color(green)(|bar(ul(color(white)(a/a)color(black)(m_("NaCl / 1 mole") = "58.44247 g")color(white)(a/a)|)))#</mathjax></p> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many grams of NaCl equal a mole of NaCI? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="299171" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-15T12:47:17" itemprop="dateCreated"> Aug 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"58.44247 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The problem essentially wants you to find the <strong>molar mass</strong> of sodium chloride, <mathjax>#"NaCl"#</mathjax>. As you know, the <em>molar mass</em> of an ionic compound gives you the mass of <strong>one mole</strong> of formula units of that compound. </p> <p>Now, as given by the compound's chemical formula, one formula unit of sodium chloride contains</p> <blockquote> <ul> <li><em><strong>one sodium cation</strong></em>, <mathjax>#1 xx "Na"^(+)#</mathjax></li> <li><em><strong>one chloride anion</strong></em>, <mathjax>#1 xx "Cl"^(-)#</mathjax></li> </ul> </blockquote> <p>This means that the mass of <strong>one mole of formula units</strong> will be equal to the sum of the mass of <strong>one mole</strong> of sodium cations and the mass of <strong>one mole</strong> of chloride anions. </p> <p>Since the mass of an ion is basically <em>the same</em> as the mass of the <strong>neutral atom</strong>, you can say that the <strong>molar mass</strong> of sodium chloride will be equal to the sum of the <strong>molar mass</strong> of sodium, <mathjax>#"Na"#</mathjax>, and the <strong>molar mass</strong> of chlorine, <mathjax>#"Cl"#</mathjax>. </p> <p>As given in <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the Periodic Table</a> of <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">Elements</a>, these are equal to </p> <blockquote> <p><mathjax>#M_("M Na") = "22.98977 g mol"^(-1)#</mathjax></p> <p><mathjax>#M_("MCl") = "35.4527 g mol"^(-1)#</mathjax></p> </blockquote> <p>You thus have</p> <blockquote> <p><mathjax>#M_("M NaCl") = "22.98977 g mol"^(-1) + "35.4527 g mol"^(-1)#</mathjax></p> <p><mathjax>#M_("M NaCl") = "58.44247 g mol"^(-1)#</mathjax></p> </blockquote> <p>This means that the mass of <strong>one mole</strong> of sodium chloride is equal to</p> <blockquote> <p><mathjax>#color(green)(|bar(ul(color(white)(a/a)color(black)(m_("NaCl / 1 mole") = "58.44247 g")color(white)(a/a)|)))#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/299171" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 20265 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many grams of NaCl equal a mole of NaCI?

a8fe0006-6ddd-11ea-9373-ccda262736ce

https://socratic.org/questions/how-do-you-calculate-the-molarity-of-0-060-moles-nahco-3-in-1500-ml-of-solution

0.04 M

start physical_unit 9 9 molarity mol/l qc_end physical_unit 9 9 7 8 mole qc_end physical_unit 14 14 11 12 volume qc_end end

[{"type":"physical unit","value":"Molarity [OF] NaHCO3 solution [IN] M"}]

[{"type":"physical unit","value":"0.04 M"}]

[{"type":"physical unit","value":"Mole [OF] NaHCO3 [=] \\pu{0.060 moles}"},{"type":"physical unit","value":"Volume [OF] NaHCO3 solution [=] \\pu{1500 mL}"}]

<h1 class="questionTitle" itemprop="name">How do you calculate the molarity of 0.060 moles #NaHCO_3# in 1500. mL of solution?</h1>

0.04 M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#M = {"moles solute"}/{"litres solution"} = 0.060/{1500 cdot 10^-3} "mol"/L = 0.04 M#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[NaHCO_3] = 0.04 M#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#M = {"moles solute"}/{"litres solution"} = 0.060/{1500 cdot 10^-3} "mol"/L = 0.04 M#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you calculate the molarity of 0.060 moles #NaHCO_3# in 1500. mL of solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="386940" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/pitufox27"><img alt="" class="" src="https://profilepictures.socratic.org/ECp7QE4rSIv87risZu2l_Anne%20Stokes%20-%20Rock%20God.bmp" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/pitufox27"> Pitufox27 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-05T16:11:10" itemprop="dateCreated"> Mar 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[NaHCO_3] = 0.04 M#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#M = {"moles solute"}/{"litres solution"} = 0.060/{1500 cdot 10^-3} "mol"/L = 0.04 M#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/386940" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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How do you calculate the molarity of 0.060 moles #NaHCO_3# in 1500. mL of solution?

abf53648-6ddd-11ea-9c0b-ccda262736ce

https://socratic.org/questions/what-is-the-equilibrium-concentration-of-cl2in-a-100-liter-vessel-containing-o-2

3.03 × 10^(-3) M

start physical_unit 6 6 equilibrium_concentration mol/l qc_end physical_unit 11 11 9 10 volume qc_end physical_unit 16 16 13 14 mole qc_end physical_unit 21 21 18 19 mole qc_end chemical_equation 33 37 qc_end end

[{"type":"physical unit","value":"Equilibrium concentration [OF] Cl2 [IN] M"}]

[{"type":"physical unit","value":"3.03 × 10^(-3) M"}]

[{"type":"physical unit","value":"Volume [OF] vessel [=] \\pu{100 liters}"},{"type":"physical unit","value":"Mole [OF] PCI5 [=] \\pu{0.235 mole}"},{"type":"physical unit","value":"Mole [OF] PCI3 [=] \\pu{0.174 mole}"},{"type":"chemical equation","value":"PCI5(g) <=> Cl2(g) + PCI3(g)"},{"type":"physical unit","value":"Keq [OF] the reaction [=] \\pu{2.24 × 10^(-2)}"},{"type":"physical unit","value":"Temperature [OF] the reaction [=] \\pu{327 ℃}"}]

<h1 class="questionTitle" itemprop="name">What is the equilibrium concentration of Cl2in a 100 liter vessel containing o.235 mole of PCI5 and 0.174 mole of PCI3? </h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The compound <mathjax>#PCI_5#</mathjax> decomposes into <mathjax>#Cl_2#</mathjax> and <mathjax>#PCI_3#</mathjax>. The equilibrium of <mathjax>#PCI_5(g) rightleftharpoons Cl_2 (g) + PCI_3(g)#</mathjax> has a <mathjax>#K_(eq)#</mathjax> of <mathjax>#2.24 x 10^-2#</mathjax> at 327 <mathjax>#"^o#</mathjax>C. </p></div> </h2> </div> </div>

3.03 × 10^(-3) M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to find the <strong>equilibrium concentration</strong> of <mathjax>#"Cl"_2#</mathjax> in a given reaction.</p> <blockquote></blockquote> <p>Let's first write the <strong>chemical equation</strong> for this reaction:</p> <blockquote> <p><mathjax>#"PCl"_5(g) rightleftharpoons "PCl"_3(g) + "Cl"_2(g)#</mathjax> <mathjax>#" "#</mathjax>(which is given to us) </p> </blockquote> <p>The <strong>equilirium constant expression</strong> for this reaction is thus</p> <blockquote> <p><mathjax>#K_"eq" = (["PCl"_3]["Cl"_2])/(["PCl"_5"]) = 2.24xx10^-2#</mathjax></p> <blockquote></blockquote> </blockquote> <p>We're given the number of <em>moles</em> of two species:</p> <ul> <li> <p><mathjax>#0.235#</mathjax> <mathjax>#"mol PCl"_5#</mathjax></p> </li> <li> <p><mathjax>#0.174#</mathjax> <mathjax>#"mol PCl"_3#</mathjax></p> </li> </ul> <p>And since the vessel has a <em>volume</em> of <mathjax>#100#</mathjax> <mathjax>#"L"#</mathjax>, the <strong>molar concentrations</strong> of each are </p> <ul> <li> <p><mathjax>#["PCl"_5] = (0.235color(white)(l)"mol")/(100color(white)(l)"L") = color(red)(ul(0.00235color(white)(l)M#</mathjax></p> </li> <li> <p><mathjax>#["PCl"_3] = (0.174color(white)(l)"mol")/(100color(white)(l)"L") = color(green)(ul(0.00174color(white)(l)M#</mathjax></p> <blockquote></blockquote> </li> </ul> <p>Plugging these values into the equilibrium constant expression equation:</p> <blockquote> <p><mathjax>#K_"eq" = ((color(green)(0.00174color(white)(l)M))["Cl"_2])/(color(red)(0.00235color(white)(l)M)) = 2.24xx10^-2#</mathjax></p> </blockquote> <p>Solving for <mathjax>#["Cl"_2]#</mathjax> yields</p> <blockquote> <p><mathjax>#color(blue)(ulbar(|stackrel(" ")(" "["Cl"_2] = 0.00303color(white)(l)M" ")|)#</mathjax></p> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#["Cl"_2] = 0.00303#</mathjax> <mathjax>#M#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to find the <strong>equilibrium concentration</strong> of <mathjax>#"Cl"_2#</mathjax> in a given reaction.</p> <blockquote></blockquote> <p>Let's first write the <strong>chemical equation</strong> for this reaction:</p> <blockquote> <p><mathjax>#"PCl"_5(g) rightleftharpoons "PCl"_3(g) + "Cl"_2(g)#</mathjax> <mathjax>#" "#</mathjax>(which is given to us) </p> </blockquote> <p>The <strong>equilirium constant expression</strong> for this reaction is thus</p> <blockquote> <p><mathjax>#K_"eq" = (["PCl"_3]["Cl"_2])/(["PCl"_5"]) = 2.24xx10^-2#</mathjax></p> <blockquote></blockquote> </blockquote> <p>We're given the number of <em>moles</em> of two species:</p> <ul> <li> <p><mathjax>#0.235#</mathjax> <mathjax>#"mol PCl"_5#</mathjax></p> </li> <li> <p><mathjax>#0.174#</mathjax> <mathjax>#"mol PCl"_3#</mathjax></p> </li> </ul> <p>And since the vessel has a <em>volume</em> of <mathjax>#100#</mathjax> <mathjax>#"L"#</mathjax>, the <strong>molar concentrations</strong> of each are </p> <ul> <li> <p><mathjax>#["PCl"_5] = (0.235color(white)(l)"mol")/(100color(white)(l)"L") = color(red)(ul(0.00235color(white)(l)M#</mathjax></p> </li> <li> <p><mathjax>#["PCl"_3] = (0.174color(white)(l)"mol")/(100color(white)(l)"L") = color(green)(ul(0.00174color(white)(l)M#</mathjax></p> <blockquote></blockquote> </li> </ul> <p>Plugging these values into the equilibrium constant expression equation:</p> <blockquote> <p><mathjax>#K_"eq" = ((color(green)(0.00174color(white)(l)M))["Cl"_2])/(color(red)(0.00235color(white)(l)M)) = 2.24xx10^-2#</mathjax></p> </blockquote> <p>Solving for <mathjax>#["Cl"_2]#</mathjax> yields</p> <blockquote> <p><mathjax>#color(blue)(ulbar(|stackrel(" ")(" "["Cl"_2] = 0.00303color(white)(l)M" ")|)#</mathjax></p> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the equilibrium concentration of Cl2in a 100 liter vessel containing o.235 mole of PCI5 and 0.174 mole of PCI3? </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The compound <mathjax>#PCI_5#</mathjax> decomposes into <mathjax>#Cl_2#</mathjax> and <mathjax>#PCI_3#</mathjax>. The equilibrium of <mathjax>#PCI_5(g) rightleftharpoons Cl_2 (g) + PCI_3(g)#</mathjax> has a <mathjax>#K_(eq)#</mathjax> of <mathjax>#2.24 x 10^-2#</mathjax> at 327 <mathjax>#"^o#</mathjax>C. </p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/dynamic-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Dynamic Equilibrium</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="462299" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/mrtas"><img alt="" class="" src="https://profilepictures.socratic.org/HY14X7r4S6AyDQgK2gwQ_IMG_0062.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/mrtas"> Nathan L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-10T04:12:18" itemprop="dateCreated"> Aug 10, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#["Cl"_2] = 0.00303#</mathjax> <mathjax>#M#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We're asked to find the <strong>equilibrium concentration</strong> of <mathjax>#"Cl"_2#</mathjax> in a given reaction.</p> <blockquote></blockquote> <p>Let's first write the <strong>chemical equation</strong> for this reaction:</p> <blockquote> <p><mathjax>#"PCl"_5(g) rightleftharpoons "PCl"_3(g) + "Cl"_2(g)#</mathjax> <mathjax>#" "#</mathjax>(which is given to us) </p> </blockquote> <p>The <strong>equilirium constant expression</strong> for this reaction is thus</p> <blockquote> <p><mathjax>#K_"eq" = (["PCl"_3]["Cl"_2])/(["PCl"_5"]) = 2.24xx10^-2#</mathjax></p> <blockquote></blockquote> </blockquote> <p>We're given the number of <em>moles</em> of two species:</p> <ul> <li> <p><mathjax>#0.235#</mathjax> <mathjax>#"mol PCl"_5#</mathjax></p> </li> <li> <p><mathjax>#0.174#</mathjax> <mathjax>#"mol PCl"_3#</mathjax></p> </li> </ul> <p>And since the vessel has a <em>volume</em> of <mathjax>#100#</mathjax> <mathjax>#"L"#</mathjax>, the <strong>molar concentrations</strong> of each are </p> <ul> <li> <p><mathjax>#["PCl"_5] = (0.235color(white)(l)"mol")/(100color(white)(l)"L") = color(red)(ul(0.00235color(white)(l)M#</mathjax></p> </li> <li> <p><mathjax>#["PCl"_3] = (0.174color(white)(l)"mol")/(100color(white)(l)"L") = color(green)(ul(0.00174color(white)(l)M#</mathjax></p> <blockquote></blockquote> </li> </ul> <p>Plugging these values into the equilibrium constant expression equation:</p> <blockquote> <p><mathjax>#K_"eq" = ((color(green)(0.00174color(white)(l)M))["Cl"_2])/(color(red)(0.00235color(white)(l)M)) = 2.24xx10^-2#</mathjax></p> </blockquote> <p>Solving for <mathjax>#["Cl"_2]#</mathjax> yields</p> <blockquote> <p><mathjax>#color(blue)(ulbar(|stackrel(" ")(" "["Cl"_2] = 0.00303color(white)(l)M" ")|)#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/462299" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-dynamic-equilibrium"> How does temperature affect dynamic equilibrium? 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What is the equilibrium concentration of Cl2in a 100 liter vessel containing o.235 mole of PCI5 and 0.174 mole of PCI3?

The compound #PCI_5# decomposes into #Cl_2# and #PCI_3#. The equilibrium of #PCI_5(g) rightleftharpoons Cl_2 (g) + PCI_3(g)# has a #K_(eq)# of #2.24 x 10^-2# at 327 #"^o#C.

a999c94a-6ddd-11ea-8663-ccda262736ce

https://socratic.org/questions/if-the-heat-of-combustion-for-a-specific-compound-is-1220-kj-mol-and-its-molar-m

41.74 grams

start physical_unit 23 24 mass g qc_end physical_unit 8 8 10 11 enthalpy_of_combustion qc_end physical_unit 8 8 17 18 molar_mass qc_end physical_unit 23 24 30 31 heat_energy qc_end end

[{"type":"physical unit","value":"Mass [OF] this compound [IN] grams"}]

[{"type":"physical unit","value":"41.74 grams"}]

[{"type":"physical unit","value":"Heat of combustion [OF] the compound [=] \\pu{-1220 kJ/mol}"},{"type":"physical unit","value":"Molar mass [OF] the compound [=] \\pu{78.35 g/mol}"},{"type":"physical unit","value":"Released heat [OF] this compound [=] \\pu{649.90 kJ}"}]

<h1 class="questionTitle" itemprop="name">If the heat of combustion for a specific compound is -1220 kJ/mol and its molar mass is 78.35 g/mol, how many grams of this compound must you burn to release 649.90 kJ of heat?</h1>

41.74 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Before doing anything else, make sure that you understand what a compound's <em>heat of combustion</em> tells you. </p> <p>The heat of combustion, also referred to as the <em><a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change of combustion</em>, <mathjax>#DeltaH_"comb"#</mathjax>, represents the heat <strong>given off</strong> when <strong>one mole</strong> of a substance undergoes complete combustion, usually under <em>standard conditions</em>. </p> <p>In your case, you have </p> <blockquote> <p><mathjax>#DeltaH_"comb" = -"1220 kJ/mol"#</mathjax></p> </blockquote> <p>Two things to notice here</p> <ul> <li><em>the enthalpy change of combustion carries a <strong>negative sign</strong> - this confirms that you're dealing with heat <strong>given off</strong></em></li> <li><em>the enthalpy change of combustion is given <strong>per mole</strong> of the compound</em></li> </ul> <p>So, simply put, <mathjax>#"1220 kJ"#</mathjax> are <strong>given off</strong> when <strong>one mole</strong> of your mystery compound undergoes complete combustion. </p> <p>Now, to solve this problem, you can convert the enthalpy change of combustion from <em>kilojoules per mole</em> to <em>kilojoules per gram</em>, then calculate the mass needed to give off that much heat. </p> <p>To do that, use the compound's <strong>molar mass</strong>, which is said to be equal to <mathjax>#"78.35 kJ/mol"#</mathjax>. This tells you that <strong>one mole</strong> of this compound has a mass of <mathjax>#"78.35 g"#</mathjax>. </p> <p>This means that you have </p> <blockquote> <p><mathjax>#1220 "kJ"/color(red)(cancel(color(black)("mol"))) * (1color(red)(cancel(color(black)("mol"))))/"78.35 g" = "15.571 kJ/g"#</mathjax></p> </blockquote> <p>So, when <strong>one gram</strong> undergoes complete combustion, <mathjax>#"15.571 kJ"#</mathjax> of heat are <strong>given off</strong>, This means that you have </p> <blockquote> <p><mathjax>#649.90 color(red)(cancel(color(black)("kJ"))) * "1 g"/(15.571color(red)(cancel(color(black)("kJ")))) = "41.739 g"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <blockquote> <p><mathjax>#m = color(green)("41.7 g")#</mathjax></p> </blockquote> <p>So, you can conclude that</p> <ul> <li> <p><em>when</em> <mathjax>#"41.7 g"#</mathjax> <em>of this compound undergo complete combustion,</em> <mathjax>#"649.90 kJ"#</mathjax> <em>of heat are being <strong>given off</strong></em></p> </li> <li> <p><em>when</em> <mathjax>#"41.7 g"#</mathjax> <em>of this compound undergo complete combustion, the enthalpy change of reaction is equal to</em> <mathjax>#DeltaH_"rxn" = -"649.90 kJ"#</mathjax></p> </li> </ul> <p>Remember, those two statements are <strong>equivalent</strong>. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"41.7 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Before doing anything else, make sure that you understand what a compound's <em>heat of combustion</em> tells you. </p> <p>The heat of combustion, also referred to as the <em><a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change of combustion</em>, <mathjax>#DeltaH_"comb"#</mathjax>, represents the heat <strong>given off</strong> when <strong>one mole</strong> of a substance undergoes complete combustion, usually under <em>standard conditions</em>. </p> <p>In your case, you have </p> <blockquote> <p><mathjax>#DeltaH_"comb" = -"1220 kJ/mol"#</mathjax></p> </blockquote> <p>Two things to notice here</p> <ul> <li><em>the enthalpy change of combustion carries a <strong>negative sign</strong> - this confirms that you're dealing with heat <strong>given off</strong></em></li> <li><em>the enthalpy change of combustion is given <strong>per mole</strong> of the compound</em></li> </ul> <p>So, simply put, <mathjax>#"1220 kJ"#</mathjax> are <strong>given off</strong> when <strong>one mole</strong> of your mystery compound undergoes complete combustion. </p> <p>Now, to solve this problem, you can convert the enthalpy change of combustion from <em>kilojoules per mole</em> to <em>kilojoules per gram</em>, then calculate the mass needed to give off that much heat. </p> <p>To do that, use the compound's <strong>molar mass</strong>, which is said to be equal to <mathjax>#"78.35 kJ/mol"#</mathjax>. This tells you that <strong>one mole</strong> of this compound has a mass of <mathjax>#"78.35 g"#</mathjax>. </p> <p>This means that you have </p> <blockquote> <p><mathjax>#1220 "kJ"/color(red)(cancel(color(black)("mol"))) * (1color(red)(cancel(color(black)("mol"))))/"78.35 g" = "15.571 kJ/g"#</mathjax></p> </blockquote> <p>So, when <strong>one gram</strong> undergoes complete combustion, <mathjax>#"15.571 kJ"#</mathjax> of heat are <strong>given off</strong>, This means that you have </p> <blockquote> <p><mathjax>#649.90 color(red)(cancel(color(black)("kJ"))) * "1 g"/(15.571color(red)(cancel(color(black)("kJ")))) = "41.739 g"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <blockquote> <p><mathjax>#m = color(green)("41.7 g")#</mathjax></p> </blockquote> <p>So, you can conclude that</p> <ul> <li> <p><em>when</em> <mathjax>#"41.7 g"#</mathjax> <em>of this compound undergo complete combustion,</em> <mathjax>#"649.90 kJ"#</mathjax> <em>of heat are being <strong>given off</strong></em></p> </li> <li> <p><em>when</em> <mathjax>#"41.7 g"#</mathjax> <em>of this compound undergo complete combustion, the enthalpy change of reaction is equal to</em> <mathjax>#DeltaH_"rxn" = -"649.90 kJ"#</mathjax></p> </li> </ul> <p>Remember, those two statements are <strong>equivalent</strong>. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If the heat of combustion for a specific compound is -1220 kJ/mol and its molar mass is 78.35 g/mol, how many grams of this compound must you burn to release 649.90 kJ of heat?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/enthalpy" itemprop="url"> <span class="breadcrumb" itemprop="title">Enthalpy</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="210989" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-11T01:22:13" itemprop="dateCreated"> Jan 11, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"41.7 g"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Before doing anything else, make sure that you understand what a compound's <em>heat of combustion</em> tells you. </p> <p>The heat of combustion, also referred to as the <em><a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change of combustion</em>, <mathjax>#DeltaH_"comb"#</mathjax>, represents the heat <strong>given off</strong> when <strong>one mole</strong> of a substance undergoes complete combustion, usually under <em>standard conditions</em>. </p> <p>In your case, you have </p> <blockquote> <p><mathjax>#DeltaH_"comb" = -"1220 kJ/mol"#</mathjax></p> </blockquote> <p>Two things to notice here</p> <ul> <li><em>the enthalpy change of combustion carries a <strong>negative sign</strong> - this confirms that you're dealing with heat <strong>given off</strong></em></li> <li><em>the enthalpy change of combustion is given <strong>per mole</strong> of the compound</em></li> </ul> <p>So, simply put, <mathjax>#"1220 kJ"#</mathjax> are <strong>given off</strong> when <strong>one mole</strong> of your mystery compound undergoes complete combustion. </p> <p>Now, to solve this problem, you can convert the enthalpy change of combustion from <em>kilojoules per mole</em> to <em>kilojoules per gram</em>, then calculate the mass needed to give off that much heat. </p> <p>To do that, use the compound's <strong>molar mass</strong>, which is said to be equal to <mathjax>#"78.35 kJ/mol"#</mathjax>. This tells you that <strong>one mole</strong> of this compound has a mass of <mathjax>#"78.35 g"#</mathjax>. </p> <p>This means that you have </p> <blockquote> <p><mathjax>#1220 "kJ"/color(red)(cancel(color(black)("mol"))) * (1color(red)(cancel(color(black)("mol"))))/"78.35 g" = "15.571 kJ/g"#</mathjax></p> </blockquote> <p>So, when <strong>one gram</strong> undergoes complete combustion, <mathjax>#"15.571 kJ"#</mathjax> of heat are <strong>given off</strong>, This means that you have </p> <blockquote> <p><mathjax>#649.90 color(red)(cancel(color(black)("kJ"))) * "1 g"/(15.571color(red)(cancel(color(black)("kJ")))) = "41.739 g"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the answer will be </p> <blockquote> <p><mathjax>#m = color(green)("41.7 g")#</mathjax></p> </blockquote> <p>So, you can conclude that</p> <ul> <li> <p><em>when</em> <mathjax>#"41.7 g"#</mathjax> <em>of this compound undergo complete combustion,</em> <mathjax>#"649.90 kJ"#</mathjax> <em>of heat are being <strong>given off</strong></em></p> </li> <li> <p><em>when</em> <mathjax>#"41.7 g"#</mathjax> <em>of this compound undergo complete combustion, the enthalpy change of reaction is equal to</em> <mathjax>#DeltaH_"rxn" = -"649.90 kJ"#</mathjax></p> </li> </ul> <p>Remember, those two statements are <strong>equivalent</strong>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/210989" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-enthalpy-changes-expressed-in-chemical-equations"> How are enthalpy changes expressed in chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-enthalpy-change-be-determined-for-an-aqueous-solution"> How can enthalpy change be determined for an aqueous solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-change-with-pressure"> How does enthalpy change with pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-standard-molar-enthalpy-formation"> How do you calculate standard molar enthalpy of formation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-enthalpy-of-formation-of-oxygen-zero"> Why is the enthalpy of formation of oxygen zero? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-enthalpy-a-state-function-2"> Why is enthalpy a state function? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-enthalpy-cannot-be-measured-directly"> Why can enthalpy not be measured directly? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-pressure-affect-enthalpy"> How does pressure affect enthalpy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-enthalpy-relate-to-internal-energy"> How does enthalpy relate to internal energy? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/enthalpy"> See all questions in Enthalpy </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 39393 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

If the heat of combustion for a specific compound is -1220 kJ/mol and its molar mass is 78.35 g/mol, how many grams of this compound must you burn to release 649.90 kJ of heat?

aaefeeb1-6ddd-11ea-a741-ccda262736ce

https://socratic.org/questions/how-many-moles-are-in-sodium-chloride-in-150-ml-of-a-2-mm-nacl-solution

3.00 × 10^(-4) moles

start physical_unit 4 5 mole mol qc_end physical_unit 13 14 7 8 volume qc_end physical_unit 13 14 11 12 molarity qc_end end

[{"type":"physical unit","value":"Mole [OF] sodium chloride [IN] moles"}]

[{"type":"physical unit","value":"3.00 × 10^(-4) moles"}]

[{"type":"physical unit","value":"Volume [OF] NaCl solution [=] \\pu{150 mL}"},{"type":"physical unit","value":"Molarity [OF] NaCl solution [=] \\pu{2 mM}"}]

<h1 class="questionTitle" itemprop="name">How many moles are in sodium chloride in 150 mL of a 2 mM NaCl solution?</h1>

3.00 × 10^(-4) moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"="Moles of solute"/"Volume of solution"#</mathjax></p> <p>And thus <mathjax>#"moles of solute"="volume"xx"concentration"#</mathjax></p> <p>And here, for this product we have:</p> <p><mathjax>#150xx10^-3cancelLxx2xx10^-3*mol*cancel(L^-1)=3.00xx10^-4*mol#</mathjax>.</p> <p>(I have changed the volume from <mathjax>#mL#</mathjax> to <mathjax>#L#</mathjax>, and from <mathjax>#mmol#</mathjax> to <mathjax>#mol#</mathjax> simply by using the appropriate multiplier. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Concentration"="Moles of solute"/"Volume of solution"#</mathjax>. And here there are:<br/> <mathjax>#150xx10^-3cancelLxx2xx10^-3*mol*cancel(L^-1)=3.00xx10^-4*mol#</mathjax> of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"="Moles of solute"/"Volume of solution"#</mathjax></p> <p>And thus <mathjax>#"moles of solute"="volume"xx"concentration"#</mathjax></p> <p>And here, for this product we have:</p> <p><mathjax>#150xx10^-3cancelLxx2xx10^-3*mol*cancel(L^-1)=3.00xx10^-4*mol#</mathjax>.</p> <p>(I have changed the volume from <mathjax>#mL#</mathjax> to <mathjax>#L#</mathjax>, and from <mathjax>#mmol#</mathjax> to <mathjax>#mol#</mathjax> simply by using the appropriate multiplier. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles are in sodium chloride in 150 mL of a 2 mM NaCl solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="396286" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-25T14:28:36" itemprop="dateCreated"> Mar 25, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Concentration"="Moles of solute"/"Volume of solution"#</mathjax>. And here there are:<br/> <mathjax>#150xx10^-3cancelLxx2xx10^-3*mol*cancel(L^-1)=3.00xx10^-4*mol#</mathjax> of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"="Moles of solute"/"Volume of solution"#</mathjax></p> <p>And thus <mathjax>#"moles of solute"="volume"xx"concentration"#</mathjax></p> <p>And here, for this product we have:</p> <p><mathjax>#150xx10^-3cancelLxx2xx10^-3*mol*cancel(L^-1)=3.00xx10^-4*mol#</mathjax>.</p> <p>(I have changed the volume from <mathjax>#mL#</mathjax> to <mathjax>#L#</mathjax>, and from <mathjax>#mmol#</mathjax> to <mathjax>#mol#</mathjax> simply by using the appropriate multiplier. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/396286" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-solution-solute-and-solvent-related"> How are solution, solute, and solvent related? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutions-become-saturated"> Why do solutions become saturated? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-solutions"> How does temperature affect solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-solution-differ-from-a-colloid"> How does a solution differ from a colloid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/calculate-the-amount-of-1-m-naoh-aqueous-solution-needed-to-make-100-ml-of-0-5-m"> Calculate the amount of 1 M NaOH aqueous solution needed to make 100 mL of 0.5 M NaOH aqueous solution. </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-buffering-a-solution-change-the-solutions-behavior"> How does buffering a solution change the solutions behavior? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-benedict-s-solution-change-colour"> How does Benedict's solution change colour? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/describe-how-would-you-prepare-1-l-of-a-1-m-solution-of-sodium-chloride-the-gram"> Describe how would you prepare 1 L of a 1 M solution of sodium chloride. The gram formula weight... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-solutions-differ-from-suspensions"> How do solutions differ from suspensions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-solution-differ-from-a-compound"> How does a solution differ from a compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/solutions"> See all questions in Solutions </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6744 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many moles are in sodium chloride in 150 mL of a 2 mM NaCl solution?

abb1db82-6ddd-11ea-afc5-ccda262736ce

https://socratic.org/questions/how-many-grams-of-cuso-4-are-present-in-652-ml-of-250-m-cuso-4-solution

26.00 grams

start physical_unit 4 4 mass g qc_end physical_unit 13 14 8 9 volume qc_end physical_unit 13 14 11 12 molarity qc_end end

[{"type":"physical unit","value":"Mass [OF] CuSO4 [IN] grams"}]

[{"type":"physical unit","value":"26.00 grams"}]

[{"type":"physical unit","value":"Volume [OF] CuSO4 solution [=] \\pu{652 mL}"},{"type":"physical unit","value":"Molarity [OF] CuSO4 solution [=] \\pu{0.250 M}"}]

<h1 class="questionTitle" itemprop="name">How many grams of #CuSO_4# are present in 652 mL of .250 M #CuSO_4# solution?</h1>

26.00 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the defining quotient....</p> <p><mathjax>#"concentration"="moles of solute"/"volume of solution"#</mathjax></p> <p>And thus <mathjax>#"moles of solute"="volume"xx"concentraion"#</mathjax></p> <p>And for <mathjax>#"moles of solute"#</mathjax>, we gots.....</p> <p><mathjax>#652*cancel(mL)xx10^-3*cancel(L*mL^-1)xx0.250*mol*cancel(L^-1)=#</mathjax></p> <p><mathjax>#0.163*mol#</mathjax>...</p> <p>And with respect to <mathjax>#"copper sulfate"#</mathjax> there is a mass of <mathjax>#0.163*molxx159.61*g*mol^-1=26.0*g#</mathjax>...</p> <p>Of course in an aqueous solution of copper sulfate, the copper is present as <mathjax>#[Cu(OH_2)_6]^(2+)#</mathjax>, a beautifully blue-coloured complex ion. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Approx. <mathjax>#26*g#</mathjax> of salt.....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the defining quotient....</p> <p><mathjax>#"concentration"="moles of solute"/"volume of solution"#</mathjax></p> <p>And thus <mathjax>#"moles of solute"="volume"xx"concentraion"#</mathjax></p> <p>And for <mathjax>#"moles of solute"#</mathjax>, we gots.....</p> <p><mathjax>#652*cancel(mL)xx10^-3*cancel(L*mL^-1)xx0.250*mol*cancel(L^-1)=#</mathjax></p> <p><mathjax>#0.163*mol#</mathjax>...</p> <p>And with respect to <mathjax>#"copper sulfate"#</mathjax> there is a mass of <mathjax>#0.163*molxx159.61*g*mol^-1=26.0*g#</mathjax>...</p> <p>Of course in an aqueous solution of copper sulfate, the copper is present as <mathjax>#[Cu(OH_2)_6]^(2+)#</mathjax>, a beautifully blue-coloured complex ion. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many grams of #CuSO_4# are present in 652 mL of .250 M #CuSO_4# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/solutions" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="537054" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-01-17T21:14:37" itemprop="dateCreated"> Jan 17, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Approx. <mathjax>#26*g#</mathjax> of salt.....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the defining quotient....</p> <p><mathjax>#"concentration"="moles of solute"/"volume of solution"#</mathjax></p> <p>And thus <mathjax>#"moles of solute"="volume"xx"concentraion"#</mathjax></p> <p>And for <mathjax>#"moles of solute"#</mathjax>, we gots.....</p> <p><mathjax>#652*cancel(mL)xx10^-3*cancel(L*mL^-1)xx0.250*mol*cancel(L^-1)=#</mathjax></p> <p><mathjax>#0.163*mol#</mathjax>...</p> <p>And with respect to <mathjax>#"copper sulfate"#</mathjax> there is a mass of <mathjax>#0.163*molxx159.61*g*mol^-1=26.0*g#</mathjax>...</p> <p>Of course in an aqueous solution of copper sulfate, the copper is present as <mathjax>#[Cu(OH_2)_6]^(2+)#</mathjax>, a beautifully blue-coloured complex ion. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/537054" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="537073" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jarni-renz"><img alt="" class="" src="https://profilepictures.socratic.org/i6OiZQmVRHWljDVlwm8v_WIN_20160301_180231.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jarni-renz"> Jarni Renz </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-01-17T21:55:27" itemprop="dateCreated"> Jan 17, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#m=ul ?g CuSO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Given the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a><mathjax>#(M)#</mathjax> and the volume<mathjax>#(V)#</mathjax> of the solution, the number of moles<mathjax>#(eta)#</mathjax> can be solved using the formula shown below:</p> <blockquote> <p><mathjax>#M=eta/V#</mathjax></p> <blockquote> <p>where:</p> <blockquote> <p><mathjax>#eta=("mass"(m))/("molar mass"(Mm))#</mathjax></p> </blockquote> </blockquote> </blockquote> <p>Now, plug in this value to the formula. Rearrange formula to isolate <mathjax>#eta#</mathjax>. Always attached unit to each variable's value to ensure that the desired unit is correctly labeled to the required variable; that is, </p> <blockquote> <p><mathjax>#M=((m)/(Mm))/V#</mathjax>; cross multiply to simplify</p> <p><mathjax>#MV=m/(Mm#</mathjax>; isolate the required variable <mathjax>#m#</mathjax></p> <p><mathjax>#m=MVMm#</mathjax>; now, plug in the values of each variable</p> <blockquote> <p>where:</p> <blockquote> <p><mathjax>#M=0.250M=(0.250mol)/(L)#</mathjax></p> <p><mathjax>#V=652cancel(mL)xx(1L)/(1000cancel(mL))=0.652L#</mathjax></p> <p><mathjax>#Mm_(CuSO_4)=(159.5g)/(mol)#</mathjax>, obtainable from <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>.</p> </blockquote> </blockquote> <p><mathjax>#m=(0.250cancel(mol))/cancel(L)xx0.652cancel(L)xx(159.5g)/cancel(mol)#</mathjax></p> <p><mathjax>#m=ul ?g CuSO_4#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/537073" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-solution-solute-and-solvent-related"> How are solution, solute, and solvent related? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-solutions-become-saturated"> Why do solutions become saturated? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-temperature-affect-solutions"> How does temperature affect solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-solution-differ-from-a-colloid"> How does a solution differ from a colloid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/calculate-the-amount-of-1-m-naoh-aqueous-solution-needed-to-make-100-ml-of-0-5-m"> Calculate the amount of 1 M NaOH aqueous solution needed to make 100 mL of 0.5 M NaOH aqueous solution. </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-buffering-a-solution-change-the-solutions-behavior"> How does buffering a solution change the solutions behavior? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-benedict-s-solution-change-colour"> How does Benedict's solution change colour? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/describe-how-would-you-prepare-1-l-of-a-1-m-solution-of-sodium-chloride-the-gram"> Describe how would you prepare 1 L of a 1 M solution of sodium chloride. 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How many grams of #CuSO_4# are present in 652 mL of .250 M #CuSO_4# solution?

ad0d2334-6ddd-11ea-a373-ccda262736ce

https://socratic.org/questions/when-the-equation-fe-cl-2-fecl-3-is-balanced-what-is-the-coefficient-for-cl-2

3

start physical_unit 5 5 coefficient none qc_end chemical_equation 3 7 qc_end end

[{"type":"physical unit","value":"Coefficient [OF] Cl2"}]

[{"type":"physical unit","value":"3"}]

[{"type":"chemical equation","value":"Fe + Cl2 -> FeCl3"}]

<h1 class="questionTitle" itemprop="name">When the equation #Fe + Cl_2 -&gt; FeCl_3# is balanced, what is the coefficient for #Cl_2#?</h1>

3

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>2Fe + 3Cl2 -&gt; 2FeCl3</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>3</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>2Fe + 3Cl2 -&gt; 2FeCl3</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">When the equation #Fe + Cl_2 -&gt; FeCl_3# is balanced, what is the coefficient for #Cl_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="323287" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/arnav"><img alt="" class="" src="https://profilepictures.socratic.org/ADQ9Gpv9QMq8swEt508e_916af7c78e993e4c9623cf391a3029b8.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/arnav"> Arnav </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-18T14:03:33" itemprop="dateCreated"> Oct 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>3</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>2Fe + 3Cl2 -&gt; 2FeCl3</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/323287" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------&gt; H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -&gt; Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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When the equation #Fe + Cl_2 -&gt; FeCl_3# is balanced, what is the coefficient for #Cl_2#?

aa2198a2-6ddd-11ea-87f0-ccda262736ce

https://socratic.org/questions/58f992fa11ef6b5262ea1cd6

2.00 × 10^(-3) mol/L

start physical_unit 5 6 solubility mol/l qc_end physical_unit 13 14 9 10 molarity qc_end physical_unit 15 15 17 19 equilibrium_constant_k qc_end physical_unit 20 20 22 24 kf qc_end end

[{"type":"physical unit","value":"Solubility [OF] silver bromide [IN] mol/L"}]

[{"type":"physical unit","value":"2.00 × 10^(-3) mol/L"}]

[{"type":"physical unit","value":"Molarity [OF] potassium cyanide [=] \\pu{0.1 mol/L}"},{"type":"physical unit","value":"Ksp [OF] AgBr [=] \\pu{7.7 × 10^(-13)}"},{"type":"physical unit","value":"Kf [OF] Ag(CN)^2- [=] \\pu{5.6 × 10^8}"}]

<h1 class="questionTitle" itemprop="name">What is the solubility of silver bromide in a 0.1 mol/L solution of potassium cyanide?</h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>For <mathjax>#"AgBr", K_text(sp) = 7.7 × 10^"-13"#</mathjax>.</p> <p>For <mathjax>#"Ag(CN)"_2^"-", K_text(f) = 5.6 × 10^8#</mathjax>.</p></div> </h2> </div> </div>

2.00 × 10^(-3) mol/L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>We have the two equilibria:</p> <p><mathjax>#"AgBr(s)" ⇌ "Ag"^"+""(aq)" + "Br"^"-""(aq)"; color(white)(mmml)K_text(sp) = 7.7 × 10^"-13"#</mathjax><br/> <mathjax>#"Ag"^"+""(aq)" + "2CN"^"-""(aq)" → "Ag(CN)"_2^"-""(aq)"; K_text(f) = color(white)(l)5.6 × 10^8#</mathjax></p> <blockquote></blockquote> <p>If we add the two equations, we get</p> <p><mathjax>#"AgBr(s)" + "2CN"^"-""(aq)" ⇌ "Ag(CN)"_2^"-""(aq)" + "Br"^"-""(aq)"#</mathjax></p> <blockquote></blockquote> <p>For this equilibrium, </p> <p><mathjax>#K = (["Ag(CN)"_2^"-" ]["Br"^"-"])/["CN"^"-"]^2 = K_text(sp)K_text(f) = 7.7 × 10^"-13" × 5.6 × 10^8 = 4.31 × 10^"-4"#</mathjax></p> <blockquote></blockquote> <p>Now, we can set up an ICE table to calculate the solubility of <mathjax>#"AgBr"#</mathjax> in <mathjax>#"KCN"#</mathjax>.</p> <p><mathjax>#color(white)(mmmmmm)"AgBr + 2CN"^"-" ⇌ "Ag(CN)"_2^"-" + "Br"^"-"#</mathjax><br/> <mathjax>#"I/mol·L"^"-1":color(white)(mmmmml)0.1color(white)(llmmmm)0color(white)(mmmll)0#</mathjax><br/> <mathjax>#"C/mol·L"^"-1":color(white)(mmmmll)"-2"xcolor(white)(mmmml)"+"xcolor(white)(mmm)"+"x#</mathjax><br/> <mathjax>#"E/mol·L"^"-1":color(white)(mmmml)"0.1-2"xcolor(white)(mmmm)xcolor(white)(mmmll)x#</mathjax></p> <blockquote></blockquote> <p><mathjax>#K = x^2/(0.1-2x)^2 = 4.31 × 10^"-4"#</mathjax></p> <p><mathjax>#x/(0.1-2x) = 0.0208#</mathjax></p> <p><mathjax>#x = 0.0208(0.1-2x) = "0.002 08" - 0.0415x#</mathjax></p> <p><mathjax>#"1.04 15"x = "0.002 08"#</mathjax></p> <p><mathjax>#x = "0.002 08"/"1.04 15" = 0.002#</mathjax></p> <p>∴ The solubility of <mathjax>#"AgBr"#</mathjax> in the <mathjax>#"KCN"#</mathjax> solution is 0.002 mol/L.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The solubility is 0.002 mol/L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>We have the two equilibria:</p> <p><mathjax>#"AgBr(s)" ⇌ "Ag"^"+""(aq)" + "Br"^"-""(aq)"; color(white)(mmml)K_text(sp) = 7.7 × 10^"-13"#</mathjax><br/> <mathjax>#"Ag"^"+""(aq)" + "2CN"^"-""(aq)" → "Ag(CN)"_2^"-""(aq)"; K_text(f) = color(white)(l)5.6 × 10^8#</mathjax></p> <blockquote></blockquote> <p>If we add the two equations, we get</p> <p><mathjax>#"AgBr(s)" + "2CN"^"-""(aq)" ⇌ "Ag(CN)"_2^"-""(aq)" + "Br"^"-""(aq)"#</mathjax></p> <blockquote></blockquote> <p>For this equilibrium, </p> <p><mathjax>#K = (["Ag(CN)"_2^"-" ]["Br"^"-"])/["CN"^"-"]^2 = K_text(sp)K_text(f) = 7.7 × 10^"-13" × 5.6 × 10^8 = 4.31 × 10^"-4"#</mathjax></p> <blockquote></blockquote> <p>Now, we can set up an ICE table to calculate the solubility of <mathjax>#"AgBr"#</mathjax> in <mathjax>#"KCN"#</mathjax>.</p> <p><mathjax>#color(white)(mmmmmm)"AgBr + 2CN"^"-" ⇌ "Ag(CN)"_2^"-" + "Br"^"-"#</mathjax><br/> <mathjax>#"I/mol·L"^"-1":color(white)(mmmmml)0.1color(white)(llmmmm)0color(white)(mmmll)0#</mathjax><br/> <mathjax>#"C/mol·L"^"-1":color(white)(mmmmll)"-2"xcolor(white)(mmmml)"+"xcolor(white)(mmm)"+"x#</mathjax><br/> <mathjax>#"E/mol·L"^"-1":color(white)(mmmml)"0.1-2"xcolor(white)(mmmm)xcolor(white)(mmmll)x#</mathjax></p> <blockquote></blockquote> <p><mathjax>#K = x^2/(0.1-2x)^2 = 4.31 × 10^"-4"#</mathjax></p> <p><mathjax>#x/(0.1-2x) = 0.0208#</mathjax></p> <p><mathjax>#x = 0.0208(0.1-2x) = "0.002 08" - 0.0415x#</mathjax></p> <p><mathjax>#"1.04 15"x = "0.002 08"#</mathjax></p> <p><mathjax>#x = "0.002 08"/"1.04 15" = 0.002#</mathjax></p> <p>∴ The solubility of <mathjax>#"AgBr"#</mathjax> in the <mathjax>#"KCN"#</mathjax> solution is 0.002 mol/L.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the solubility of silver bromide in a 0.1 mol/L solution of potassium cyanide?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>For <mathjax>#"AgBr", K_text(sp) = 7.7 × 10^"-13"#</mathjax>.</p> <p>For <mathjax>#"Ag(CN)"_2^"-", K_text(f) = 5.6 × 10^8#</mathjax>.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/ksp" itemprop="url"> <span class="breadcrumb" itemprop="title">Ksp</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="414052" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-27T21:25:49" itemprop="dateCreated"> Apr 27, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The solubility is 0.002 mol/L.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>We have the two equilibria:</p> <p><mathjax>#"AgBr(s)" ⇌ "Ag"^"+""(aq)" + "Br"^"-""(aq)"; color(white)(mmml)K_text(sp) = 7.7 × 10^"-13"#</mathjax><br/> <mathjax>#"Ag"^"+""(aq)" + "2CN"^"-""(aq)" → "Ag(CN)"_2^"-""(aq)"; K_text(f) = color(white)(l)5.6 × 10^8#</mathjax></p> <blockquote></blockquote> <p>If we add the two equations, we get</p> <p><mathjax>#"AgBr(s)" + "2CN"^"-""(aq)" ⇌ "Ag(CN)"_2^"-""(aq)" + "Br"^"-""(aq)"#</mathjax></p> <blockquote></blockquote> <p>For this equilibrium, </p> <p><mathjax>#K = (["Ag(CN)"_2^"-" ]["Br"^"-"])/["CN"^"-"]^2 = K_text(sp)K_text(f) = 7.7 × 10^"-13" × 5.6 × 10^8 = 4.31 × 10^"-4"#</mathjax></p> <blockquote></blockquote> <p>Now, we can set up an ICE table to calculate the solubility of <mathjax>#"AgBr"#</mathjax> in <mathjax>#"KCN"#</mathjax>.</p> <p><mathjax>#color(white)(mmmmmm)"AgBr + 2CN"^"-" ⇌ "Ag(CN)"_2^"-" + "Br"^"-"#</mathjax><br/> <mathjax>#"I/mol·L"^"-1":color(white)(mmmmml)0.1color(white)(llmmmm)0color(white)(mmmll)0#</mathjax><br/> <mathjax>#"C/mol·L"^"-1":color(white)(mmmmll)"-2"xcolor(white)(mmmml)"+"xcolor(white)(mmm)"+"x#</mathjax><br/> <mathjax>#"E/mol·L"^"-1":color(white)(mmmml)"0.1-2"xcolor(white)(mmmm)xcolor(white)(mmmll)x#</mathjax></p> <blockquote></blockquote> <p><mathjax>#K = x^2/(0.1-2x)^2 = 4.31 × 10^"-4"#</mathjax></p> <p><mathjax>#x/(0.1-2x) = 0.0208#</mathjax></p> <p><mathjax>#x = 0.0208(0.1-2x) = "0.002 08" - 0.0415x#</mathjax></p> <p><mathjax>#"1.04 15"x = "0.002 08"#</mathjax></p> <p><mathjax>#x = "0.002 08"/"1.04 15" = 0.002#</mathjax></p> <p>∴ The solubility of <mathjax>#"AgBr"#</mathjax> in the <mathjax>#"KCN"#</mathjax> solution is 0.002 mol/L.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/414052" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-you-use-the-solubility-product-constant-to-calculate-the-solubility-of-a"> How can you use the solubility product constant to calculate the solubility of a sparingly... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5397ae9102bf3458eddf5130"> Question #f5130 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-ksp"> What is Ksp? 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What is the solubility of silver bromide in a 0.1 mol/L solution of potassium cyanide?

For #"AgBr", K_text(sp) = 7.7 × 10^"-13"#. For #"Ag(CN)"_2^"-", K_text(f) = 5.6 × 10^8#.

ab44b708-6ddd-11ea-8b6a-ccda262736ce

https://socratic.org/questions/what-is-the-volume-of-5-0-grams-of-co-2-at-stp

2.58 L

start physical_unit 8 8 volume l qc_end physical_unit 8 8 5 6 mass qc_end c_other STP qc_end end

[{"type":"physical unit","value":"Volume [OF] CO2 [IN] L"}]

[{"type":"physical unit","value":"2.58 L"}]

[{"type":"physical unit","value":"Mass [OF] CO2 [=] \\pu{5.0 grams}"},{"type":"other","value":"STP"}]

<h1 class="questionTitle" itemprop="name">What is the volume of 5.0 grams of #CO_2# at STP?</h1>

2.58 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#color(blue)("STP"#</mathjax></p> <p>STP is currently <mathjax>#0^@"C"#</mathjax> or <mathjax>#"273.15 K"#</mathjax>, which are equal, though the Kelvin temperature scale is used for <a href="https://socratic.org/chemistry/the-behavior-of-gases/gas-laws">gas laws</a>; and pressure is <mathjax>#"10"^5color(white)(.)"Pascals (Pa)"#</mathjax>, but most people use <mathjax>#"100 kPa"#</mathjax>, which is equal to <mathjax>#10^5color(white)(.)"Pa"#</mathjax>.</p> <p>You will use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a></strong> to answer this question. Its formula is:</p> <p><mathjax>#PV=nRT#</mathjax>,</p> <p>where <mathjax>#P#</mathjax> is pressure, <mathjax>#V#</mathjax> is volume, <mathjax>#n#</mathjax> is moles, <mathjax>#R#</mathjax> is a gas constant, and <mathjax>#T#</mathjax> is temperature in Kelvins.</p> <p><mathjax>#color(blue)("Determine moles"#</mathjax><br/> You may have noticed that the equation requires moles <mathjax>#(n)#</mathjax>, but you have been given the mass of <mathjax>#"CO"_2"#</mathjax>. To determine moles, you <strong>multiply the given mass by the inverse of the molar mass</strong> of <mathjax>#"CO"_2"#</mathjax>, which is <mathjax>#"44.009 g/mol"#</mathjax>.</p> <p><mathjax>#5.0color(red)cancel(color(black)("g CO"_2))xx(1"mol CO"_2)/(44.009color(red)cancel(color(black)("g CO"_2)))="0.1136 mol CO"_2"#</mathjax></p> <p><mathjax>#color(blue)("Organize your data"#</mathjax>.</p> <p><strong>Given/Known</strong><br/> <mathjax>#P="100 kPa"#</mathjax><br/> <mathjax>#n="0.1136 mol"#</mathjax><br/> <mathjax>#R="8.3145 L kPa K"^(-1) "mol"^(-1)"#</mathjax><br/> <a href="https://en.wikipedia.org/wiki/Gas_constant" rel="nofollow" target="_blank">https://en.wikipedia.org/wiki/Gas_constant</a><br/> <mathjax>#T="273.15 K"#</mathjax></p> <p><strong>Unknown:</strong> <mathjax>#V#</mathjax></p> <p><mathjax>#color(blue)("Solve for volume using the ideal gas law."#</mathjax><br/> Rearrange the formula to isolate <mathjax>#V#</mathjax>. Insert your data into the equation and solve.</p> <p><mathjax>#V=(nRT)/P#</mathjax></p> <p><mathjax>#V=(0.1136color(red)cancel(color(black)("mol"))xx8.3145 color(white)(.)"L" color(red)cancel(color(black)("kPa")) color(red)cancel(color(black)("K"))^(-1) color(red)cancel(color(black)("mol"))^(-1)xx273.15color(red)cancel(color(black)("K")))/(100color(red)cancel(color(black)("kPa")))="2.6 L CO"_2"#</mathjax> rounded to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> due to <mathjax>#"5.0 g"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of <mathjax>#"5.0 g CO"_2"#</mathjax> is <mathjax>#"2.6 L CO"_2"#</mathjax> at STP.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#color(blue)("STP"#</mathjax></p> <p>STP is currently <mathjax>#0^@"C"#</mathjax> or <mathjax>#"273.15 K"#</mathjax>, which are equal, though the Kelvin temperature scale is used for <a href="https://socratic.org/chemistry/the-behavior-of-gases/gas-laws">gas laws</a>; and pressure is <mathjax>#"10"^5color(white)(.)"Pascals (Pa)"#</mathjax>, but most people use <mathjax>#"100 kPa"#</mathjax>, which is equal to <mathjax>#10^5color(white)(.)"Pa"#</mathjax>.</p> <p>You will use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a></strong> to answer this question. Its formula is:</p> <p><mathjax>#PV=nRT#</mathjax>,</p> <p>where <mathjax>#P#</mathjax> is pressure, <mathjax>#V#</mathjax> is volume, <mathjax>#n#</mathjax> is moles, <mathjax>#R#</mathjax> is a gas constant, and <mathjax>#T#</mathjax> is temperature in Kelvins.</p> <p><mathjax>#color(blue)("Determine moles"#</mathjax><br/> You may have noticed that the equation requires moles <mathjax>#(n)#</mathjax>, but you have been given the mass of <mathjax>#"CO"_2"#</mathjax>. To determine moles, you <strong>multiply the given mass by the inverse of the molar mass</strong> of <mathjax>#"CO"_2"#</mathjax>, which is <mathjax>#"44.009 g/mol"#</mathjax>.</p> <p><mathjax>#5.0color(red)cancel(color(black)("g CO"_2))xx(1"mol CO"_2)/(44.009color(red)cancel(color(black)("g CO"_2)))="0.1136 mol CO"_2"#</mathjax></p> <p><mathjax>#color(blue)("Organize your data"#</mathjax>.</p> <p><strong>Given/Known</strong><br/> <mathjax>#P="100 kPa"#</mathjax><br/> <mathjax>#n="0.1136 mol"#</mathjax><br/> <mathjax>#R="8.3145 L kPa K"^(-1) "mol"^(-1)"#</mathjax><br/> <a href="https://en.wikipedia.org/wiki/Gas_constant" rel="nofollow" target="_blank">https://en.wikipedia.org/wiki/Gas_constant</a><br/> <mathjax>#T="273.15 K"#</mathjax></p> <p><strong>Unknown:</strong> <mathjax>#V#</mathjax></p> <p><mathjax>#color(blue)("Solve for volume using the ideal gas law."#</mathjax><br/> Rearrange the formula to isolate <mathjax>#V#</mathjax>. Insert your data into the equation and solve.</p> <p><mathjax>#V=(nRT)/P#</mathjax></p> <p><mathjax>#V=(0.1136color(red)cancel(color(black)("mol"))xx8.3145 color(white)(.)"L" color(red)cancel(color(black)("kPa")) color(red)cancel(color(black)("K"))^(-1) color(red)cancel(color(black)("mol"))^(-1)xx273.15color(red)cancel(color(black)("K")))/(100color(red)cancel(color(black)("kPa")))="2.6 L CO"_2"#</mathjax> rounded to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> due to <mathjax>#"5.0 g"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the volume of 5.0 grams of #CO_2# at STP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="425305" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> <a class="secondContributorPic" href="/users/doc048"><img alt="" class="" src="https://profilepictures.socratic.org/e4gaeUMMQESTpfte6aRu_Friendly%20Chem%20Professor.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a>·<a class="topContributorLink" href="/users/doc048"> Doc048 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-18T01:28:29" itemprop="dateCreated"> May 18, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The volume of <mathjax>#"5.0 g CO"_2"#</mathjax> is <mathjax>#"2.6 L CO"_2"#</mathjax> at STP.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#color(blue)("STP"#</mathjax></p> <p>STP is currently <mathjax>#0^@"C"#</mathjax> or <mathjax>#"273.15 K"#</mathjax>, which are equal, though the Kelvin temperature scale is used for <a href="https://socratic.org/chemistry/the-behavior-of-gases/gas-laws">gas laws</a>; and pressure is <mathjax>#"10"^5color(white)(.)"Pascals (Pa)"#</mathjax>, but most people use <mathjax>#"100 kPa"#</mathjax>, which is equal to <mathjax>#10^5color(white)(.)"Pa"#</mathjax>.</p> <p>You will use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a></strong> to answer this question. Its formula is:</p> <p><mathjax>#PV=nRT#</mathjax>,</p> <p>where <mathjax>#P#</mathjax> is pressure, <mathjax>#V#</mathjax> is volume, <mathjax>#n#</mathjax> is moles, <mathjax>#R#</mathjax> is a gas constant, and <mathjax>#T#</mathjax> is temperature in Kelvins.</p> <p><mathjax>#color(blue)("Determine moles"#</mathjax><br/> You may have noticed that the equation requires moles <mathjax>#(n)#</mathjax>, but you have been given the mass of <mathjax>#"CO"_2"#</mathjax>. To determine moles, you <strong>multiply the given mass by the inverse of the molar mass</strong> of <mathjax>#"CO"_2"#</mathjax>, which is <mathjax>#"44.009 g/mol"#</mathjax>.</p> <p><mathjax>#5.0color(red)cancel(color(black)("g CO"_2))xx(1"mol CO"_2)/(44.009color(red)cancel(color(black)("g CO"_2)))="0.1136 mol CO"_2"#</mathjax></p> <p><mathjax>#color(blue)("Organize your data"#</mathjax>.</p> <p><strong>Given/Known</strong><br/> <mathjax>#P="100 kPa"#</mathjax><br/> <mathjax>#n="0.1136 mol"#</mathjax><br/> <mathjax>#R="8.3145 L kPa K"^(-1) "mol"^(-1)"#</mathjax><br/> <a href="https://en.wikipedia.org/wiki/Gas_constant" rel="nofollow" target="_blank">https://en.wikipedia.org/wiki/Gas_constant</a><br/> <mathjax>#T="273.15 K"#</mathjax></p> <p><strong>Unknown:</strong> <mathjax>#V#</mathjax></p> <p><mathjax>#color(blue)("Solve for volume using the ideal gas law."#</mathjax><br/> Rearrange the formula to isolate <mathjax>#V#</mathjax>. Insert your data into the equation and solve.</p> <p><mathjax>#V=(nRT)/P#</mathjax></p> <p><mathjax>#V=(0.1136color(red)cancel(color(black)("mol"))xx8.3145 color(white)(.)"L" color(red)cancel(color(black)("kPa")) color(red)cancel(color(black)("K"))^(-1) color(red)cancel(color(black)("mol"))^(-1)xx273.15color(red)cancel(color(black)("K")))/(100color(red)cancel(color(black)("kPa")))="2.6 L CO"_2"#</mathjax> rounded to two <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> due to <mathjax>#"5.0 g"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/425305" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="425354" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/doc048"><img alt="" class="" src="https://profilepictures.socratic.org/e4gaeUMMQESTpfte6aRu_Friendly%20Chem%20Professor.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/doc048"> Doc048 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-18T03:40:52" itemprop="dateCreated"> May 18, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I got 2.55 Liters</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>1 mole of any gas at STP = 22.4 Liters<br/> <mathjax>#5 g CO_2(g) = (5 g)/(44(g/"mole")) = 0.114 "mole" CO_2(g) #</mathjax><br/> Volume of 0.114 mole <mathjax>#CO_2(g)#</mathjax> = (0.114 mole)(22.4 L/mole) = 2.55 Liters <mathjax>#CO_2#</mathjax>(g) at STP</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/425354" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? 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What is the volume of 5.0 grams of #CO_2# at STP?

aaf0b23a-6ddd-11ea-b8a3-ccda262736ce

https://socratic.org/questions/57e95c2911ef6b3672700174

0.12 M

start physical_unit 11 13 concentration mol/l qc_end physical_unit 11 13 8 9 volume qc_end physical_unit 13 13 0 1 volume qc_end physical_unit 5 6 3 4 concentration qc_end end

[{"type":"physical unit","value":"Concentration [OF] sodium hydroxide solution [IN] M"}]

[{"type":"physical unit","value":"0.12 M"}]

[{"type":"physical unit","value":"Volume [OF] sodium hydroxide solution [=] \\pu{18.65 ml}"},{"type":"physical unit","value":"Volume [OF] oxalic acid solution [=] \\pu{10.00 ml}"},{"type":"physical unit","value":"Concentration [OF] oxalic acid solution [=] \\pu{0.1089 M}"}]

<h1 class="questionTitle" itemprop="name">10.00 ml of 0.1089 M oxalic acid neutralises 18.65 ml of sodium hydroxide solution. What is the concentration of the sodium hydroxide ?</h1>

0.12 M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#sf(H_2C_2O_(4(aq))+2NaOH_((aq))rarrNa_2C_2O_(4(aq))+2H_2O_((l)))#</mathjax></p> <p><mathjax>#sf(n_(H_2C_2O_4)=cxxv=0.1089xx10.00/1000=0.001089)#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(n_(NaOH)=0.001089xx2=0.002178)#</mathjax></p> <p><mathjax>#sf(c=n/v)#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf([NaOH]-=(0.002178)/(0.01865)=0.1168color(white)(x)"mol/l")#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#sf([NaOH]=0.1168color(white)(x)"mol/l")#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#sf(H_2C_2O_(4(aq))+2NaOH_((aq))rarrNa_2C_2O_(4(aq))+2H_2O_((l)))#</mathjax></p> <p><mathjax>#sf(n_(H_2C_2O_4)=cxxv=0.1089xx10.00/1000=0.001089)#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(n_(NaOH)=0.001089xx2=0.002178)#</mathjax></p> <p><mathjax>#sf(c=n/v)#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf([NaOH]-=(0.002178)/(0.01865)=0.1168color(white)(x)"mol/l")#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">10.00 ml of 0.1089 M oxalic acid neutralises 18.65 ml of sodium hydroxide solution. What is the concentration of the sodium hydroxide ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/measuring-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Measuring Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="314810" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michael-2"><img alt="" class="" src="https://lh3.googleusercontent.com/-gCv6FQRhls0/AAAAAAAAAAI/AAAAAAAAAAA/AAnnY7oOJS05Ylqn3KuDSW0LfnbOk7FezQ/mo/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michael-2"> Michael </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-26T22:54:53" itemprop="dateCreated"> Sep 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#sf([NaOH]=0.1168color(white)(x)"mol/l")#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#sf(H_2C_2O_(4(aq))+2NaOH_((aq))rarrNa_2C_2O_(4(aq))+2H_2O_((l)))#</mathjax></p> <p><mathjax>#sf(n_(H_2C_2O_4)=cxxv=0.1089xx10.00/1000=0.001089)#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(n_(NaOH)=0.001089xx2=0.002178)#</mathjax></p> <p><mathjax>#sf(c=n/v)#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf([NaOH]-=(0.002178)/(0.01865)=0.1168color(white)(x)"mol/l")#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/314810" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-concentration-from-absorbance"> How do you measure concentration from absorbance? 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10.00 ml of 0.1089 M oxalic acid neutralises 18.65 ml of sodium hydroxide solution. What is the concentration of the sodium hydroxide ?

a8d51149-6ddd-11ea-9323-ccda262736ce

https://socratic.org/questions/a-280-ml-solution-is-20-salt-how-much-water-should-be-added-to-make-the-solution

120 mL

start physical_unit 9 9 volume ml qc_end physical_unit 3 3 1 2 volume qc_end physical_unit 6 6 5 5 percent qc_end physical_unit 6 6 17 17 percent qc_end end

[{"type":"physical unit","value":"Volume [OF] water [IN] mL"}]

[{"type":"physical unit","value":"120 mL"}]

[{"type":"physical unit","value":"Volume [OF] salt solution [=] \\pu{280 mL}"},{"type":"physical unit","value":"Percent1 [OF] salt in solution [=] \\pu{20%}"},{"type":"physical unit","value":"Percent2 [OF] salt in solution [=] \\pu{14%}"}]

<h1 class="questionTitle" itemprop="name">A 280 mL solution is 20% salt. How much water should be added to make the solution 14% salt? </h1>

120 mL

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The key to this problem is to realize that the amount of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> you started with <strong>remains unchanged</strong> after the solution is <a href="http://socratic.org/chemistry/solutions-and-their-behavior/dilution-calculations">diluted</a>. </p> <p>In essence, the amount of salt you had in the first solution will be found in the final solution as well. </p> <p>This means that you can determine how much water to add to the first solution by first calculating how much salt you have</p> <p><mathjax>#"x g salt"/"280 mL solution" * 100 = 20%#</mathjax></p> <p>This means that </p> <p><mathjax>#x = (280 * 20)/100 = "56 g salt"#</mathjax></p> <p>Let's say that <mathjax>#y#</mathjax> represents the mass of water that you need to add to the initial solution. This volume of water will impact the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concetration</a> of the solution by increasing the <em>mass of the solution</em>.</p> <p>This means that you can write </p> <p><mathjax>#"56 g salt"/((280 + y)"mL solution") * 100 = 14%#</mathjax></p> <p>Solve for <mathjax>#y#</mathjax> to get </p> <p><mathjax>#14 * (280 + y) = 56 * 100#</mathjax></p> <p><mathjax>#3920 + 14y = 5600#</mathjax></p> <p><mathjax>#14t = 1680 implies y = 1680/14 = color(green)("120 mL")#</mathjax></p> <p>So, if you add <strong>120 mL</strong> of water to 280 mL of a 20% salt solution, you will get a final solution that is 14% salt. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You need to add <strong>120 mL</strong> of water. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The key to this problem is to realize that the amount of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> you started with <strong>remains unchanged</strong> after the solution is <a href="http://socratic.org/chemistry/solutions-and-their-behavior/dilution-calculations">diluted</a>. </p> <p>In essence, the amount of salt you had in the first solution will be found in the final solution as well. </p> <p>This means that you can determine how much water to add to the first solution by first calculating how much salt you have</p> <p><mathjax>#"x g salt"/"280 mL solution" * 100 = 20%#</mathjax></p> <p>This means that </p> <p><mathjax>#x = (280 * 20)/100 = "56 g salt"#</mathjax></p> <p>Let's say that <mathjax>#y#</mathjax> represents the mass of water that you need to add to the initial solution. This volume of water will impact the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concetration</a> of the solution by increasing the <em>mass of the solution</em>.</p> <p>This means that you can write </p> <p><mathjax>#"56 g salt"/((280 + y)"mL solution") * 100 = 14%#</mathjax></p> <p>Solve for <mathjax>#y#</mathjax> to get </p> <p><mathjax>#14 * (280 + y) = 56 * 100#</mathjax></p> <p><mathjax>#3920 + 14y = 5600#</mathjax></p> <p><mathjax>#14t = 1680 implies y = 1680/14 = color(green)("120 mL")#</mathjax></p> <p>So, if you add <strong>120 mL</strong> of water to 280 mL of a 20% salt solution, you will get a final solution that is 14% salt. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A 280 mL solution is 20% salt. How much water should be added to make the solution 14% salt? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/percent-concentration" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Concentration</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="162949" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-08-09T18:01:10" itemprop="dateCreated"> Aug 9, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You need to add <strong>120 mL</strong> of water. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The key to this problem is to realize that the amount of <a href="http://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> you started with <strong>remains unchanged</strong> after the solution is <a href="http://socratic.org/chemistry/solutions-and-their-behavior/dilution-calculations">diluted</a>. </p> <p>In essence, the amount of salt you had in the first solution will be found in the final solution as well. </p> <p>This means that you can determine how much water to add to the first solution by first calculating how much salt you have</p> <p><mathjax>#"x g salt"/"280 mL solution" * 100 = 20%#</mathjax></p> <p>This means that </p> <p><mathjax>#x = (280 * 20)/100 = "56 g salt"#</mathjax></p> <p>Let's say that <mathjax>#y#</mathjax> represents the mass of water that you need to add to the initial solution. This volume of water will impact the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/percent-concentration">percent concetration</a> of the solution by increasing the <em>mass of the solution</em>.</p> <p>This means that you can write </p> <p><mathjax>#"56 g salt"/((280 + y)"mL solution") * 100 = 14%#</mathjax></p> <p>Solve for <mathjax>#y#</mathjax> to get </p> <p><mathjax>#14 * (280 + y) = 56 * 100#</mathjax></p> <p><mathjax>#3920 + 14y = 5600#</mathjax></p> <p><mathjax>#14t = 1680 implies y = 1680/14 = color(green)("120 mL")#</mathjax></p> <p>So, if you add <strong>120 mL</strong> of water to 280 mL of a 20% salt solution, you will get a final solution that is 14% salt. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/162949" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-water-in-solution-be-decreased"> How can the concentration of water in solution be decreased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-the-concentration-of-a-solution-be-increased"> How can the concentration of a solution be increased? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-concentration-of-a-solution-in-ppm"> How do you find the concentration of a solution in ppm? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-10-percent-solution"> How do you make a 10 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-make-a-2-percent-solution"> How do you make a 2 percent solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-weight-per-volume-method-to-calculate-concentration"> What is the weight per volume method to calculate concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-percent-concentration-of-kcl-would-be-isotonic"> What percent concentration of KCl would be isotonic? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-sodium-chloride-in-normal-saline"> What is the percent concentration of sodium chloride in normal saline? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-of-a-6m-solution-of-nacl"> What is the percent concentration of a 6m solution of NaCl? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-concentration-formula"> What is the percent concentration formula? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/percent-concentration"> See all questions in Percent Concentration </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9892 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A 280 mL solution is 20% salt. How much water should be added to make the solution 14% salt?

a93bcca6-6ddd-11ea-a8c1-ccda262736ce

https://socratic.org/questions/how-many-milliliters-of-0-200m-naoh-solution-are-needed-to-react-with-22-0-ml-of

108.00 milliliters

start physical_unit 6 7 volume ml qc_end physical_unit 6 7 4 5 molarity qc_end physical_unit 19 20 17 18 molarity qc_end physical_unit 19 20 13 14 volume qc_end end

[{"type":"physical unit","value":"Volume [OF] NaOH solution [IN] milliliters"}]

[{"type":"physical unit","value":"108.00 milliliters"}]

[{"type":"physical unit","value":"Molarity [OF] NaOH solution [=] \\pu{0.200 M}"},{"type":"physical unit","value":"Molarity [OF] NiCl2 solution [=] \\pu{0.490 M}"},{"type":"physical unit","value":"Volume [OF] NiCl2 solution [=] \\pu{22.0 mL}"}]

<h1 class="questionTitle" itemprop="name">How many milliliters of 0.200M #NaOH# solution are needed to react with 22.0 mL of a 0.490 M #NiCl_2# solution?</h1>

108.00 milliliters

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#NiCl_2(aq) + 2NaOH(aq) rarr Ni(OH)_2(s)darr + 2NaCl(aq)#</mathjax></p> <p>There are <mathjax>#0.0108#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#NiCl_2#</mathjax> (<mathjax>#22.0xx10^(-3)cancelLxx0.490*mol*cancel(L^-1)#</mathjax>). So, by <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> <mathjax>#0.0216#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#NaOH#</mathjax> are required. </p> <p>There is <mathjax>#0.200#</mathjax> <mathjax>#mol*L^-1#</mathjax> <mathjax>#NaOH#</mathjax> solution available, so...</p> <p><mathjax>#(0.0216*cancel(mol))/(0.200*cancel(mol)*cancel(L^-1))xx1000*mL*cancel(L^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#?? mL#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#0.0108#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#NiCl_2#</mathjax>. <mathjax>#0.0216#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#NaOH#</mathjax> are required, given <mathjax>#0.200#</mathjax> <mathjax>#mol*L^-1#</mathjax> <mathjax>#NaOH(aq)#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#NiCl_2(aq) + 2NaOH(aq) rarr Ni(OH)_2(s)darr + 2NaCl(aq)#</mathjax></p> <p>There are <mathjax>#0.0108#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#NiCl_2#</mathjax> (<mathjax>#22.0xx10^(-3)cancelLxx0.490*mol*cancel(L^-1)#</mathjax>). So, by <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> <mathjax>#0.0216#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#NaOH#</mathjax> are required. </p> <p>There is <mathjax>#0.200#</mathjax> <mathjax>#mol*L^-1#</mathjax> <mathjax>#NaOH#</mathjax> solution available, so...</p> <p><mathjax>#(0.0216*cancel(mol))/(0.200*cancel(mol)*cancel(L^-1))xx1000*mL*cancel(L^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#?? mL#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many milliliters of 0.200M #NaOH# solution are needed to react with 22.0 mL of a 0.490 M #NiCl_2# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="197811" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-08T18:02:32" itemprop="dateCreated"> Dec 8, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>There are <mathjax>#0.0108#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#NiCl_2#</mathjax>. <mathjax>#0.0216#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#NaOH#</mathjax> are required, given <mathjax>#0.200#</mathjax> <mathjax>#mol*L^-1#</mathjax> <mathjax>#NaOH(aq)#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#NiCl_2(aq) + 2NaOH(aq) rarr Ni(OH)_2(s)darr + 2NaCl(aq)#</mathjax></p> <p>There are <mathjax>#0.0108#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#NiCl_2#</mathjax> (<mathjax>#22.0xx10^(-3)cancelLxx0.490*mol*cancel(L^-1)#</mathjax>). So, by <a href="http://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a> <mathjax>#0.0216#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#NaOH#</mathjax> are required. </p> <p>There is <mathjax>#0.200#</mathjax> <mathjax>#mol*L^-1#</mathjax> <mathjax>#NaOH#</mathjax> solution available, so...</p> <p><mathjax>#(0.0216*cancel(mol))/(0.200*cancel(mol)*cancel(L^-1))xx1000*mL*cancel(L^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#?? mL#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/197811" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -&gt; 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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How many milliliters of 0.200M #NaOH# solution are needed to react with 22.0 mL of a 0.490 M #NiCl_2# solution?

ac8c9180-6ddd-11ea-8036-ccda262736ce

https://socratic.org/questions/how-do-you-convert-1-35-10-24-atoms-of-carbon-to-moles-of-carbon

2.24 moles

start physical_unit 9 9 mole mol qc_end end

[{"type":"physical unit","value":"Mole [OF] carbon [IN] moles"}]

[{"type":"physical unit","value":"2.24 moles"}]

[{"type":"physical unit","value":"Number [OF] carbon atoms [=] \\pu{1.35 × 10^24}"}]

<h1 class="questionTitle" itemprop="name">How do you convert #1.35 * 10^24# atoms of carbon to moles of carbon?</h1>

2.24 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus we take the quotient.......</p> <p><mathjax>#(1.35xx10^24*C*"atoms")/(6.022xx10^23*C *"atoms"*mol^-1)=2.24*mol#</mathjax></p> <p>And what mass of carbon does this molar quantity represent? You should be able to answer pdq. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well one mole of carbon specifies <mathjax>#6.022xx10^23#</mathjax> INDIVIDUAL carbon atoms, i.e. a mole of carbon.........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus we take the quotient.......</p> <p><mathjax>#(1.35xx10^24*C*"atoms")/(6.022xx10^23*C *"atoms"*mol^-1)=2.24*mol#</mathjax></p> <p>And what mass of carbon does this molar quantity represent? You should be able to answer pdq. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you convert #1.35 * 10^24# atoms of carbon to moles of carbon?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="462481" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-10T15:30:38" itemprop="dateCreated"> Aug 10, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well one mole of carbon specifies <mathjax>#6.022xx10^23#</mathjax> INDIVIDUAL carbon atoms, i.e. a mole of carbon.........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus we take the quotient.......</p> <p><mathjax>#(1.35xx10^24*C*"atoms")/(6.022xx10^23*C *"atoms"*mol^-1)=2.24*mol#</mathjax></p> <p>And what mass of carbon does this molar quantity represent? You should be able to answer pdq. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/462481" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 67142 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How do you convert #1.35 * 10^24# atoms of carbon to moles of carbon?

ab452c9c-6ddd-11ea-987a-ccda262736ce

https://socratic.org/questions/what-is-the-boiling-point-of-a-solution-containing-2-33-g-of-caffeine-c-8h-10n-4

82.12 ℃

start physical_unit 7 7 boiling_point_temperature °c qc_end physical_unit 13 13 9 10 mass qc_end physical_unit 19 19 16 17 mass qc_end physical_unit 24 25 27 28 boiling_point_temperature qc_end physical_unit 24 25 37 38 kbp qc_end end

[{"type":"physical unit","value":"Boiling point [OF] the solution [IN] ℃"}]

[{"type":"physical unit","value":"82.12 ℃"}]

[{"type":"physical unit","value":"Mass [OF] C8H10N4O2 [=] \\pu{2.33 g}"},{"type":"physical unit","value":"Mass [OF] benzene [=] \\pu{15.0 g}"},{"type":"physical unit","value":"Boiling point [OF] pure benzene [=] \\pu{80.1 ℃}"},{"type":"physical unit","value":"Kbp [OF] pure benzene [=] \\pu{2.53 ℃/m}"}]

<h1 class="questionTitle" itemprop="name">What is the boiling point of a solution containing 2.33 g of caffeine, #C_8H_10N_4O_2#, dissolved in 15.0 g of benzene? The boiling point of pure benzene is 80.1 °C and the boiling point elevation constant, Kbp, is 2.53 °C/m.</h1>

82.12 ℃

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The formulae for <strong>boiling point elevation</strong> is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(|bar(ul(ΔT_"b" = K_"b"m)|)#</mathjax></p> </blockquote> </blockquote> <p>where</p> <ul> <li><mathjax>#ΔT_"b"#</mathjax> is the boiling point elevation</li> <li><mathjax>#K_"b"#</mathjax> is the boiling point elevation constant</li> <li><mathjax>#m#</mathjax> is the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution</li> </ul> <p>Our first task is to <strong>calculate the molality of the solution</strong>.</p> <p>The molar mass of caffeine, <mathjax>#"Caf"#</mathjax>, is 194.19 g/mol.</p> <p><mathjax>#"moles of Caf" = 2.33 color(red)(cancel(color(black)("g Caf"))) × "1 mol Caf"/(194.19 color(red)(cancel(color(black)("g Caf")))) = "0.012 00 mol Caf"#</mathjax> </p> <p><mathjax>#"Molality" = "moles of solute"/"kilograms of solvent" = "0.012 00 mol"/"0.0150 kg" = "0.800 mol/kg"#</mathjax></p> <blockquote></blockquote> <p>Now, we calculate the <strong>boiling point elevation</strong>.</p> <p><mathjax>#ΔT_"b" = K_"b"m = "2.53 °C·"color(red)(cancel(color(black)("kg·mol"^"-1"))) × 0.800 color(red)(cancel(color(black)("mol·kg"^"-1"))) = "2.02 °C"#</mathjax></p> <blockquote></blockquote> <p>Finally, we <strong>calculate the new boiling point</strong>.</p> <p><mathjax>#T_"b" = T_"b"^° + ΔT_"b" = "80.1 °C + 2.02 °C" = "82.1 °C"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The boiling point of the solution is 82.1 °C.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The formulae for <strong>boiling point elevation</strong> is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(|bar(ul(ΔT_"b" = K_"b"m)|)#</mathjax></p> </blockquote> </blockquote> <p>where</p> <ul> <li><mathjax>#ΔT_"b"#</mathjax> is the boiling point elevation</li> <li><mathjax>#K_"b"#</mathjax> is the boiling point elevation constant</li> <li><mathjax>#m#</mathjax> is the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution</li> </ul> <p>Our first task is to <strong>calculate the molality of the solution</strong>.</p> <p>The molar mass of caffeine, <mathjax>#"Caf"#</mathjax>, is 194.19 g/mol.</p> <p><mathjax>#"moles of Caf" = 2.33 color(red)(cancel(color(black)("g Caf"))) × "1 mol Caf"/(194.19 color(red)(cancel(color(black)("g Caf")))) = "0.012 00 mol Caf"#</mathjax> </p> <p><mathjax>#"Molality" = "moles of solute"/"kilograms of solvent" = "0.012 00 mol"/"0.0150 kg" = "0.800 mol/kg"#</mathjax></p> <blockquote></blockquote> <p>Now, we calculate the <strong>boiling point elevation</strong>.</p> <p><mathjax>#ΔT_"b" = K_"b"m = "2.53 °C·"color(red)(cancel(color(black)("kg·mol"^"-1"))) × 0.800 color(red)(cancel(color(black)("mol·kg"^"-1"))) = "2.02 °C"#</mathjax></p> <blockquote></blockquote> <p>Finally, we <strong>calculate the new boiling point</strong>.</p> <p><mathjax>#T_"b" = T_"b"^° + ΔT_"b" = "80.1 °C + 2.02 °C" = "82.1 °C"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the boiling point of a solution containing 2.33 g of caffeine, #C_8H_10N_4O_2#, dissolved in 15.0 g of benzene? The boiling point of pure benzene is 80.1 °C and the boiling point elevation constant, Kbp, is 2.53 °C/m.</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/colligative-properties" itemprop="url"> <span class="breadcrumb" itemprop="title">Colligative Properties</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="245576" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-26T22:24:30" itemprop="dateCreated"> Mar 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The boiling point of the solution is 82.1 °C.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The formulae for <strong>boiling point elevation</strong> is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(|bar(ul(ΔT_"b" = K_"b"m)|)#</mathjax></p> </blockquote> </blockquote> <p>where</p> <ul> <li><mathjax>#ΔT_"b"#</mathjax> is the boiling point elevation</li> <li><mathjax>#K_"b"#</mathjax> is the boiling point elevation constant</li> <li><mathjax>#m#</mathjax> is the <a href="http://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a> of the solution</li> </ul> <p>Our first task is to <strong>calculate the molality of the solution</strong>.</p> <p>The molar mass of caffeine, <mathjax>#"Caf"#</mathjax>, is 194.19 g/mol.</p> <p><mathjax>#"moles of Caf" = 2.33 color(red)(cancel(color(black)("g Caf"))) × "1 mol Caf"/(194.19 color(red)(cancel(color(black)("g Caf")))) = "0.012 00 mol Caf"#</mathjax> </p> <p><mathjax>#"Molality" = "moles of solute"/"kilograms of solvent" = "0.012 00 mol"/"0.0150 kg" = "0.800 mol/kg"#</mathjax></p> <blockquote></blockquote> <p>Now, we calculate the <strong>boiling point elevation</strong>.</p> <p><mathjax>#ΔT_"b" = K_"b"m = "2.53 °C·"color(red)(cancel(color(black)("kg·mol"^"-1"))) × 0.800 color(red)(cancel(color(black)("mol·kg"^"-1"))) = "2.02 °C"#</mathjax></p> <blockquote></blockquote> <p>Finally, we <strong>calculate the new boiling point</strong>.</p> <p><mathjax>#T_"b" = T_"b"^° + ΔT_"b" = "80.1 °C + 2.02 °C" = "82.1 °C"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/245576" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-colligative-properties-determined"> How are colligative properties determined? 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What is the boiling point of a solution containing 2.33 g of caffeine, #C_8H_10N_4O_2#, dissolved in 15.0 g of benzene? The boiling point of pure benzene is 80.1 °C and the boiling point elevation constant, Kbp, is 2.53 °C/m.

a92833a4-6ddd-11ea-a5ed-ccda262736ce

https://socratic.org/questions/how-many-grams-of-hydrogen-are-necessary-to-react-completely-with-50-0-g-of-nitr

10.80 grams

start physical_unit 4 4 mass g qc_end physical_unit 14 14 11 12 mass qc_end chemical_equation 18 24 qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Mass [OF] hydrogen [IN] grams"}]

[{"type":"physical unit","value":"10.80 grams"}]

[{"type":"physical unit","value":"Mass [OF] nitrogen [=] \\pu{50.0 g}"},{"type":"chemical equation","value":"N2 + 3 H2 -> 2 NH3"},{"type":"other","value":"React completely."}]

<h1 class="questionTitle" itemprop="name"> How many grams of hydrogen are necessary to react completely with 50.0 g of nitrogen in the reaction #N_2+3H_2-&gt;2NH_3#?</h1>

10.80 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>As per the equation, let us calculate the mole ratio. </p> <p><mathjax>#N_2 + 3H_2 → 2NH_3#</mathjax> </p> <p>As per the equation one mole of nitrogen reacts with 1 mol of hydrogen. </p> <p>In terms of mass. 28.01 g of nitrogen needs 3 mol of hydrogen or 6.048 g of hydrogen.</p> <blockquote></blockquote> <p>We can set up the ratio;</p> <p><mathjax>#"28.01 g of"color(white)(l) N_2#</mathjax> needs <mathjax>#"6.048 g of"color(white)(l) H_2#</mathjax> </p> <p><mathjax>#"1 g of" color(white)(l)N_2#</mathjax> needs <mathjax>#6.048/28.01 "g of"color(white)(l) H_2#</mathjax> </p> <p><mathjax>#"50.0 g of"color(white)(l)N_2#</mathjax> needs <mathjax>#(6.048 × 50.0)/28.01color(white)(l) "g of"color(white)(l) H_2 = "10.80 g of"color(white)(l) H_2#</mathjax> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>10.80 g of <mathjax>#H_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>As per the equation, let us calculate the mole ratio. </p> <p><mathjax>#N_2 + 3H_2 → 2NH_3#</mathjax> </p> <p>As per the equation one mole of nitrogen reacts with 1 mol of hydrogen. </p> <p>In terms of mass. 28.01 g of nitrogen needs 3 mol of hydrogen or 6.048 g of hydrogen.</p> <blockquote></blockquote> <p>We can set up the ratio;</p> <p><mathjax>#"28.01 g of"color(white)(l) N_2#</mathjax> needs <mathjax>#"6.048 g of"color(white)(l) H_2#</mathjax> </p> <p><mathjax>#"1 g of" color(white)(l)N_2#</mathjax> needs <mathjax>#6.048/28.01 "g of"color(white)(l) H_2#</mathjax> </p> <p><mathjax>#"50.0 g of"color(white)(l)N_2#</mathjax> needs <mathjax>#(6.048 × 50.0)/28.01color(white)(l) "g of"color(white)(l) H_2 = "10.80 g of"color(white)(l) H_2#</mathjax> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name"> How many grams of hydrogen are necessary to react completely with 50.0 g of nitrogen in the reaction #N_2+3H_2-&gt;2NH_3#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="255212" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/manish-b"><img alt="" class="" src="https://profilepictures.socratic.org/eW7uaERSSvtv5ff2XPxA_10203153902643748.jpg" title=""/></a> <a class="secondContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/manish-b"> Manish Bhardwaj </a>·<a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a>·<a class="topContributorLink" href="/users/apple-s"> Room 204 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-17T05:06:43" itemprop="dateCreated"> Apr 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>10.80 g of <mathjax>#H_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>As per the equation, let us calculate the mole ratio. </p> <p><mathjax>#N_2 + 3H_2 → 2NH_3#</mathjax> </p> <p>As per the equation one mole of nitrogen reacts with 1 mol of hydrogen. </p> <p>In terms of mass. 28.01 g of nitrogen needs 3 mol of hydrogen or 6.048 g of hydrogen.</p> <blockquote></blockquote> <p>We can set up the ratio;</p> <p><mathjax>#"28.01 g of"color(white)(l) N_2#</mathjax> needs <mathjax>#"6.048 g of"color(white)(l) H_2#</mathjax> </p> <p><mathjax>#"1 g of" color(white)(l)N_2#</mathjax> needs <mathjax>#6.048/28.01 "g of"color(white)(l) H_2#</mathjax> </p> <p><mathjax>#"50.0 g of"color(white)(l)N_2#</mathjax> needs <mathjax>#(6.048 × 50.0)/28.01color(white)(l) "g of"color(white)(l) H_2 = "10.80 g of"color(white)(l) H_2#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/255212" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="258964" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/edmund-l"><img alt="" class="" src="https://profilepictures.socratic.org/DnAPD8TISDW0aROTp4qA_Day_3_Story_1._Photo_with_Sky_Tower_from_distance_Walked_around_most_of_west_Auckland_suburbs._Some_of_you_mightve_seen_.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/edmund-l"> Edmund Liew </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-26T11:25:02" itemprop="dateCreated"> Apr 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>See below..</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Assume that:<br/> n = number of moles<br/> m = mass of substance<br/> M = molar mass (equivalent to atomic weight on the periodic table)</p> <p><mathjax>#n = m -: M#</mathjax></p> <p>The mass (m) of <mathjax>#N_2#</mathjax> has been given to you: 50.0 grams.</p> <p>You first need to find out the molar mass (M) of nitrogen. If you refer to your periodic table, the molar mass (M) of nitrogen is 14.0 g/mol. <br/> Since there are two nitrogens (refer to equation - look carefully), the molar mass of <mathjax>#N_2#</mathjax> in this reaction is 28.0 g/mol.</p> <p>Now you need to calculate the number of moles (n) for nitrogen. If you refer back to the formula "<mathjax>#n= m -: M#</mathjax>", you need to find n.<br/> The number of moles (n) for nitrogen is:<br/> [<mathjax>#n = 50.0 -: 28.0 #</mathjax>] = 1.785714286 moles.<br/> Note: Don't round it off just yet because this is not the final answer - or you'll get inaccurate answer.</p> <p>You next step is to determine the number of moles (n) for hydrogen <mathjax>#(3H_2)#</mathjax>.</p> <p>Since <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between <mathjax>#N_2 : H_2#</mathjax> is 1 : 3, so,<br/> If 1 mole of <mathjax>#N_2#</mathjax> gives you 3 moles of <mathjax>#H_2#</mathjax>,<br/> then 1.785714286 moles of <mathjax>#N_2#</mathjax> should give you:<br/> [<mathjax>#1.785714286 xx 3#</mathjax>] = 5.357142857 moles of <mathjax>#H_2#</mathjax>.</p> <p>Now you know the number of moles for <mathjax>#H_2#</mathjax>.</p> <p>The next step is to find out the molar mass (M) of Hydrogen. If you refer to your periodic table, you know that hydrogen's molar mass is 1.0 g/mol.</p> <p>Since there are two hydrogens present<em> the molar mass of hydrogen in this reaction is 2.0 g/mol.<br/> </em>(look at equation, carefully - there are 2, not 5 or 6 because the front number is only used for moles).</p> <p>Your last step is to find out its mass (m).</p> <p>If you refer back to the formula <mathjax>#n = m -: M#</mathjax>, you need to make (m) as the subject because you are finding the mass. <br/> Once you've make m as the subject, the formula will look <mathjax>#m = n xx M#</mathjax>.</p> <p>The mass (m) of hydrogen is:<br/> [<mathjax>#m = 5.357142857 xx 2.0#</mathjax>] = 10.7 grams. <br/> Note that: this answer is rounded to 3 <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a>.</p> <p>Therefore, 10.7 grams of Hydrogen are necessary to fully react with 50.0 grams of Nitrogen.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/258964" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -&gt; 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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How many grams of hydrogen are necessary to react completely with 50.0 g of nitrogen in the reaction #N_2+3H_2-&gt;2NH_3#?

ac04ebc0-6ddd-11ea-b55e-ccda262736ce

https://socratic.org/questions/the-ph-of-a-2m-solution-of-naoh-is-please-include-the-complete-solution-of-the-p

14.30

start physical_unit 6 6 ph none qc_end physical_unit 8 8 4 5 molarity qc_end end

[{"type":"physical unit","value":"pH [OF] NaOH solution"}]

[{"type":"physical unit","value":"14.30"}]

[{"type":"physical unit","value":"Molarity [OF] NaOH solution [=] \\pu{2 M}"}]

<h1 class="questionTitle" itemprop="name">The pH of a 2M solution of NaOH is...? (please include the complete solution of the problem)</h1>

14.30

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For starters, you should know that an aqueous solution at room temperature has</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("pH + pOH = 14")))#</mathjax></p> </blockquote> <p>This means that you express the <mathjax>#"pH"#</mathjax> of the solution in terms of its <mathjax>#"pOH"#</mathjax> by writing</p> <blockquote> <p><mathjax>#"pH" = 14 - "pOH"#</mathjax></p> </blockquote> <p>Now, the <mathjax>#"pOH"#</mathjax> of the solution is defined as the negative log base <mathjax>#10#</mathjax> of the concentration of hydroxide anions</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("pOH" = - log(["OH"^(-)]))))#</mathjax></p> </blockquote> <p>This means that the <mathjax>#"pH"#</mathjax> of the solution can be expressed as</p> <blockquote> <p><mathjax>#"pH" = 14 - [- log(["OH"^(-)])]#</mathjax></p> <p><mathjax>#"pH" = 14 + log(["OH"^(-)])" "color(darkorange)("(*)")#</mathjax></p> </blockquote> <p>As you know, sodium hydroxide is a <strong>strong base</strong>, which implies that it <em>ionizes completely</em> in aqueous solution to produce sodium cations and hydroxide anions. </p> <p><img alt="http://wps.prenhall.com/wps/media/objects/476/488316/ch14.html" src="https://useruploads.socratic.org/2fU0w6NrRvWJtkiCffP8_FG14_13.JPG"/> </p> <p>You can thus say that</p> <blockquote> <p><mathjax>#"NaOH"_ ((aq)) -&gt; "Na"_ ((aq))^(+) + "OH"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>Since <strong>every</strong> <mathjax>#1#</mathjax> <strong>mole</strong> of sodium hydroxide that is dissolved in water produces <mathjax>#1#</mathjax> <strong>mole</strong> of hydroxide anions, your solution will have</p> <blockquote> <p><mathjax>#["OH"^(-)] = ["NaOH"]#</mathjax></p> </blockquote> <p>In your case, this is equal to</p> <blockquote> <p><mathjax>#["OH"^(-)] = "2 M"#</mathjax></p> </blockquote> <p>Plug this into equation <mathjax>#color(orange)("(*)")#</mathjax> and calculate the <mathjax>#"pH"#</mathjax> of the solution</p> <blockquote> <p><mathjax>#"pH" = 14 + log(2) = color(darkgreen)(ul(color(black)(14.3)))#</mathjax></p> </blockquote> <p>The answer is rounded to one <em>decimal place</em>, the number of <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> you have for the concentration of the solution. </p> <p>As a final note, don't get confused by the fact that you have</p> <blockquote> <p><mathjax>#"pH" &gt; 14#</mathjax></p> </blockquote> <p>This is what you'll always get for basic <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> that have </p> <p><mathjax>#["OH"^(-)] &gt; 1#</mathjax></p> <p>and it means that <mathjax>#"pOH" &lt; 0#</mathjax>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 14.3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For starters, you should know that an aqueous solution at room temperature has</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("pH + pOH = 14")))#</mathjax></p> </blockquote> <p>This means that you express the <mathjax>#"pH"#</mathjax> of the solution in terms of its <mathjax>#"pOH"#</mathjax> by writing</p> <blockquote> <p><mathjax>#"pH" = 14 - "pOH"#</mathjax></p> </blockquote> <p>Now, the <mathjax>#"pOH"#</mathjax> of the solution is defined as the negative log base <mathjax>#10#</mathjax> of the concentration of hydroxide anions</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("pOH" = - log(["OH"^(-)]))))#</mathjax></p> </blockquote> <p>This means that the <mathjax>#"pH"#</mathjax> of the solution can be expressed as</p> <blockquote> <p><mathjax>#"pH" = 14 - [- log(["OH"^(-)])]#</mathjax></p> <p><mathjax>#"pH" = 14 + log(["OH"^(-)])" "color(darkorange)("(*)")#</mathjax></p> </blockquote> <p>As you know, sodium hydroxide is a <strong>strong base</strong>, which implies that it <em>ionizes completely</em> in aqueous solution to produce sodium cations and hydroxide anions. </p> <p><img alt="http://wps.prenhall.com/wps/media/objects/476/488316/ch14.html" src="https://useruploads.socratic.org/2fU0w6NrRvWJtkiCffP8_FG14_13.JPG"/> </p> <p>You can thus say that</p> <blockquote> <p><mathjax>#"NaOH"_ ((aq)) -&gt; "Na"_ ((aq))^(+) + "OH"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>Since <strong>every</strong> <mathjax>#1#</mathjax> <strong>mole</strong> of sodium hydroxide that is dissolved in water produces <mathjax>#1#</mathjax> <strong>mole</strong> of hydroxide anions, your solution will have</p> <blockquote> <p><mathjax>#["OH"^(-)] = ["NaOH"]#</mathjax></p> </blockquote> <p>In your case, this is equal to</p> <blockquote> <p><mathjax>#["OH"^(-)] = "2 M"#</mathjax></p> </blockquote> <p>Plug this into equation <mathjax>#color(orange)("(*)")#</mathjax> and calculate the <mathjax>#"pH"#</mathjax> of the solution</p> <blockquote> <p><mathjax>#"pH" = 14 + log(2) = color(darkgreen)(ul(color(black)(14.3)))#</mathjax></p> </blockquote> <p>The answer is rounded to one <em>decimal place</em>, the number of <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> you have for the concentration of the solution. </p> <p>As a final note, don't get confused by the fact that you have</p> <blockquote> <p><mathjax>#"pH" &gt; 14#</mathjax></p> </blockquote> <p>This is what you'll always get for basic <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> that have </p> <p><mathjax>#["OH"^(-)] &gt; 1#</mathjax></p> <p>and it means that <mathjax>#"pOH" &lt; 0#</mathjax>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">The pH of a 2M solution of NaOH is...? (please include the complete solution of the problem)</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="432007" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> <a class="secondContributorPic" href="/users/abdur-r"><img alt="" class="" src="https://profilepictures.socratic.org/YXIUDMM0SoZAxTdY3kn6_niagara_falls_fog_water_height_6376_3840x2160.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a>·<a class="topContributorLink" href="/users/abdur-r"> Monzur R. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-30T15:55:56" itemprop="dateCreated"> May 30, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"pH" = 14.3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For starters, you should know that an aqueous solution at room temperature has</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("pH + pOH = 14")))#</mathjax></p> </blockquote> <p>This means that you express the <mathjax>#"pH"#</mathjax> of the solution in terms of its <mathjax>#"pOH"#</mathjax> by writing</p> <blockquote> <p><mathjax>#"pH" = 14 - "pOH"#</mathjax></p> </blockquote> <p>Now, the <mathjax>#"pOH"#</mathjax> of the solution is defined as the negative log base <mathjax>#10#</mathjax> of the concentration of hydroxide anions</p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)("pOH" = - log(["OH"^(-)]))))#</mathjax></p> </blockquote> <p>This means that the <mathjax>#"pH"#</mathjax> of the solution can be expressed as</p> <blockquote> <p><mathjax>#"pH" = 14 - [- log(["OH"^(-)])]#</mathjax></p> <p><mathjax>#"pH" = 14 + log(["OH"^(-)])" "color(darkorange)("(*)")#</mathjax></p> </blockquote> <p>As you know, sodium hydroxide is a <strong>strong base</strong>, which implies that it <em>ionizes completely</em> in aqueous solution to produce sodium cations and hydroxide anions. </p> <p><img alt="http://wps.prenhall.com/wps/media/objects/476/488316/ch14.html" src="https://useruploads.socratic.org/2fU0w6NrRvWJtkiCffP8_FG14_13.JPG"/> </p> <p>You can thus say that</p> <blockquote> <p><mathjax>#"NaOH"_ ((aq)) -&gt; "Na"_ ((aq))^(+) + "OH"_ ((aq))^(-)#</mathjax></p> </blockquote> <p>Since <strong>every</strong> <mathjax>#1#</mathjax> <strong>mole</strong> of sodium hydroxide that is dissolved in water produces <mathjax>#1#</mathjax> <strong>mole</strong> of hydroxide anions, your solution will have</p> <blockquote> <p><mathjax>#["OH"^(-)] = ["NaOH"]#</mathjax></p> </blockquote> <p>In your case, this is equal to</p> <blockquote> <p><mathjax>#["OH"^(-)] = "2 M"#</mathjax></p> </blockquote> <p>Plug this into equation <mathjax>#color(orange)("(*)")#</mathjax> and calculate the <mathjax>#"pH"#</mathjax> of the solution</p> <blockquote> <p><mathjax>#"pH" = 14 + log(2) = color(darkgreen)(ul(color(black)(14.3)))#</mathjax></p> </blockquote> <p>The answer is rounded to one <em>decimal place</em>, the number of <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong> you have for the concentration of the solution. </p> <p>As a final note, don't get confused by the fact that you have</p> <blockquote> <p><mathjax>#"pH" &gt; 14#</mathjax></p> </blockquote> <p>This is what you'll always get for basic <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> that have </p> <p><mathjax>#["OH"^(-)] &gt; 1#</mathjax></p> <p>and it means that <mathjax>#"pOH" &lt; 0#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/432007" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 34018 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

The pH of a 2M solution of NaOH is...? (please include the complete solution of the problem)

aa3a7e12-6ddd-11ea-82c5-ccda262736ce

https://socratic.org/questions/how-many-moles-of-h-2so-4-are-present-in-0-500-l-of-a-0-150-m-h-2so-4-solution

0.08 moles

start physical_unit 4 4 mole mol qc_end physical_unit 14 15 8 9 volume qc_end physical_unit 14 15 12 13 molarity qc_end end

[{"type":"physical unit","value":"Mole [OF] H2SO4 [IN] moles"}]

[{"type":"physical unit","value":"0.08 moles"}]

[{"type":"physical unit","value":"Volume [OF] H2SO4 solution [=] \\pu{0.500 L}"},{"type":"physical unit","value":"Molarity [OF] H2SO4 solution [=] \\pu{0.150 M}"}]

<h1 class="questionTitle" itemprop="name">How many moles of #H_2SO_4# are present in 0.500 L of a 0.150 M #H_2SO_4# solution? </h1>

0.08 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Numer of moles of <mathjax>#H_2SO_4#</mathjax> are present in 0.500 L of a 0.150 M <mathjax>#H_2SO_4#</mathjax> solution is <br/> <mathjax>#="concentration in molarity"xx "Volume in liter" #</mathjax><br/> <mathjax>#=0.15 (mol)/Lxx0.500L=0.075mol#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.075mol#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Numer of moles of <mathjax>#H_2SO_4#</mathjax> are present in 0.500 L of a 0.150 M <mathjax>#H_2SO_4#</mathjax> solution is <br/> <mathjax>#="concentration in molarity"xx "Volume in liter" #</mathjax><br/> <mathjax>#=0.15 (mol)/Lxx0.500L=0.075mol#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles of #H_2SO_4# are present in 0.500 L of a 0.150 M #H_2SO_4# solution? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="265763" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/dk-ch"><img alt="" class="" src="https://profilepictures.socratic.org/0aBlt69MSiWhfD1SEqb8_lotus.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/dk-ch"> P dilip_k </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-14T16:19:28" itemprop="dateCreated"> May 14, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#0.075mol#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Numer of moles of <mathjax>#H_2SO_4#</mathjax> are present in 0.500 L of a 0.150 M <mathjax>#H_2SO_4#</mathjax> solution is <br/> <mathjax>#="concentration in molarity"xx "Volume in liter" #</mathjax><br/> <mathjax>#=0.15 (mol)/Lxx0.500L=0.075mol#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/265763" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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How many moles of #H_2SO_4# are present in 0.500 L of a 0.150 M #H_2SO_4# solution?

abc5e128-6ddd-11ea-830a-ccda262736ce

https://socratic.org/questions/a-775-ml-sample-of-nitrogen-gas-is-cooled-from-67-c-to-42-c-what-is-the-new-volu

718.01 mL

start physical_unit 3 6 volume ml qc_end physical_unit 3 6 1 2 volume qc_end physical_unit 3 6 10 11 temperature qc_end physical_unit 3 6 13 14 temperature qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Volume2 [OF] nitrogen gas sample [IN] mL"}]

[{"type":"physical unit","value":"718.01 mL"}]

[{"type":"physical unit","value":"Volume1 [OF] nitrogen gas sample [=] \\pu{775 mL}"},{"type":"physical unit","value":"Temperature1 [OF] nitrogen gas sample [=] \\pu{67 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] nitrogen gas sample [=] \\pu{42 ℃}"},{"type":"other","value":"The pressure remains the same."}]

<h1 class="questionTitle" itemprop="name">A 775 ml sample of nitrogen gas is cooled from 67#"^@#C to 42#"^@#C. What is the new volume if the pressure remains the same?</h1>

718.01 mL

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We apply <a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a></p> <p><mathjax>#V_1/T_1=V_2/T_2#</mathjax></p> <p>Volume, <mathjax>#V_1=0.775L#</mathjax></p> <p>Temperature, <mathjax>#T_1=67+273=340K#</mathjax></p> <p>Temperature, <mathjax>#T_2=42+273=315K#</mathjax></p> <p>So,</p> <p><mathjax>#V_2=T_2/T_1*V_1#</mathjax></p> <p><mathjax>#=315/340*0.775=0.718L#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new volume is <mathjax>#=718mL#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We apply <a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a></p> <p><mathjax>#V_1/T_1=V_2/T_2#</mathjax></p> <p>Volume, <mathjax>#V_1=0.775L#</mathjax></p> <p>Temperature, <mathjax>#T_1=67+273=340K#</mathjax></p> <p>Temperature, <mathjax>#T_2=42+273=315K#</mathjax></p> <p>So,</p> <p><mathjax>#V_2=T_2/T_1*V_1#</mathjax></p> <p><mathjax>#=315/340*0.775=0.718L#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A 775 ml sample of nitrogen gas is cooled from 67#"^@#C to 42#"^@#C. What is the new volume if the pressure remains the same?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="400817" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/narad-t"><img alt="" class="" src="https://profilepictures.socratic.org/zsDo4Wx9QIqYad4PXKE9_150317-1041.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/narad-t"> Narad T. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-03T10:19:07" itemprop="dateCreated"> Apr 3, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The new volume is <mathjax>#=718mL#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We apply <a href="https://socratic.org/chemistry/the-behavior-of-gases/charles-law">Charles' Law</a></p> <p><mathjax>#V_1/T_1=V_2/T_2#</mathjax></p> <p>Volume, <mathjax>#V_1=0.775L#</mathjax></p> <p>Temperature, <mathjax>#T_1=67+273=340K#</mathjax></p> <p>Temperature, <mathjax>#T_2=42+273=315K#</mathjax></p> <p>So,</p> <p><mathjax>#V_2=T_2/T_1*V_1#</mathjax></p> <p><mathjax>#=315/340*0.775=0.718L#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/400817" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? 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A 775 ml sample of nitrogen gas is cooled from 67#"^@#C to 42#"^@#C. What is the new volume if the pressure remains the same?

a8ca8a1a-6ddd-11ea-889c-ccda262736ce

https://socratic.org/questions/how-much-heat-does-it-take-to-raise-the-temperature-of-2-5-kg-of-plastic-from-15

390 kJ

start physical_unit 14 14 heat_energy kj qc_end physical_unit 14 14 16 17 temperature qc_end physical_unit 14 14 19 20 temperature qc_end physical_unit 14 14 11 12 mass qc_end end

[{"type":"physical unit","value":"Taken heat [OF] plastic [IN] kJ"}]

[{"type":"physical unit","value":"390 kJ"}]

[{"type":"physical unit","value":"Temperature1 [OF] plastic [=] \\pu{15 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] plastic [=] \\pu{75 ℃}"},{"type":"physical unit","value":"Mass [OF] plastic [=] \\pu{2.5 kg}"}]

<h1 class="questionTitle" itemprop="name">How much heat does it take to raise the temperature of 2.5 kg of plastic from 15°C to 75°C?</h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The specific heat of plastic is 2.60 kJ/(kg•°C)</p></div> </h2> </div> </div>

390 kJ

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The energy <mathjax>#q#</mathjax> required to heat an object is given by the formula</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(|color(white)(a/a)q = mcΔTcolor(white)(a/a)|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#m#</mathjax> is the mass<br/> <mathjax>#c#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity<br/> <mathjax>#ΔT#</mathjax> is the change in temperature</p> <blockquote></blockquote> <p>In your problem,</p> <p><mathjax>#m = "2.5 kg"#</mathjax><br/> <mathjax>#c = "2.60 kJ·°C"^"-1""kg"^"-1"#</mathjax><br/> <mathjax>#ΔT = T_"f" - T_"i" = "75 °C - 15 °C = 60 °C"#</mathjax></p> <p>∴ <mathjax>#q = "2.5" color(red)(cancel(color(black)("kg"))) × "2.60 kJ"·color(red)(cancel(color(black)("°C"^"-1"·"kg"^"-1"))) × "60" color(red)(cancel(color(black)("°C"))) = "390 kJ"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>It will take 390 kJ of heat.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The energy <mathjax>#q#</mathjax> required to heat an object is given by the formula</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(|color(white)(a/a)q = mcΔTcolor(white)(a/a)|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#m#</mathjax> is the mass<br/> <mathjax>#c#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity<br/> <mathjax>#ΔT#</mathjax> is the change in temperature</p> <blockquote></blockquote> <p>In your problem,</p> <p><mathjax>#m = "2.5 kg"#</mathjax><br/> <mathjax>#c = "2.60 kJ·°C"^"-1""kg"^"-1"#</mathjax><br/> <mathjax>#ΔT = T_"f" - T_"i" = "75 °C - 15 °C = 60 °C"#</mathjax></p> <p>∴ <mathjax>#q = "2.5" color(red)(cancel(color(black)("kg"))) × "2.60 kJ"·color(red)(cancel(color(black)("°C"^"-1"·"kg"^"-1"))) × "60" color(red)(cancel(color(black)("°C"))) = "390 kJ"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How much heat does it take to raise the temperature of 2.5 kg of plastic from 15°C to 75°C?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>The specific heat of plastic is 2.60 kJ/(kg•°C)</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="323295" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-18T14:35:56" itemprop="dateCreated"> Oct 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>It will take 390 kJ of heat.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The energy <mathjax>#q#</mathjax> required to heat an object is given by the formula</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(|color(white)(a/a)q = mcΔTcolor(white)(a/a)|)))" "#</mathjax></p> </blockquote> </blockquote> <p>where</p> <p><mathjax>#m#</mathjax> is the mass<br/> <mathjax>#c#</mathjax> is the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> capacity<br/> <mathjax>#ΔT#</mathjax> is the change in temperature</p> <blockquote></blockquote> <p>In your problem,</p> <p><mathjax>#m = "2.5 kg"#</mathjax><br/> <mathjax>#c = "2.60 kJ·°C"^"-1""kg"^"-1"#</mathjax><br/> <mathjax>#ΔT = T_"f" - T_"i" = "75 °C - 15 °C = 60 °C"#</mathjax></p> <p>∴ <mathjax>#q = "2.5" color(red)(cancel(color(black)("kg"))) × "2.60 kJ"·color(red)(cancel(color(black)("°C"^"-1"·"kg"^"-1"))) × "60" color(red)(cancel(color(black)("°C"))) = "390 kJ"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/323295" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? 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How much heat does it take to raise the temperature of 2.5 kg of plastic from 15°C to 75°C?

The specific heat of plastic is 2.60 kJ/(kg•°C)

aa147e22-6ddd-11ea-a6ec-ccda262736ce

https://socratic.org/questions/if-i-add-75-ml-of-water-to-125-ml-of-a-0-15-m-naoh-solution-what-will-the-molari

0.09 M

start physical_unit 22 23 molarity mol/l qc_end physical_unit 14 15 12 13 molarity qc_end physical_unit 6 6 3 4 volume qc_end physical_unit 14 15 8 9 volume qc_end end

[{"type":"physical unit","value":"Molarity2 [OF] diluted solution [IN] M"}]

[{"type":"physical unit","value":"0.09 M"}]

[{"type":"physical unit","value":"Molarity1 [OF] NaOH solution [=] \\pu{0.15 M}"},{"type":"physical unit","value":"Volume1 [OF] water [=] \\pu{75 mL}"},{"type":"physical unit","value":"Volume [OF] NaOH solution [=] \\pu{125 mL}"}]

<h1 class="questionTitle" itemprop="name">If I add 75 mL of water to 125 mL of a 0.15 M #NaOH# solution, what will the molarity of the diluted solution be?</h1>

0.09 M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> refers to the number of moles of a substance per litre of substance.</p> <p>125/1000=0.125 (This is the proportion of 1 litre that 125 ml s is, seems like a redundant step but it helps you keep track of your numbers)</p> <p>0.15x0.125=0.01875 (This is the number of moles of NaOH in your 125 ml sample)</p> <p>The next step is adding the 75 ml of water to your 125 ml sample. This brings the total volume to 200 ml.</p> <p>The concentration is now 0.01875 moles in 200 ml, simply multiply by 5 to scale to a litre to get your molarity</p> <p>0.09375 moles <mathjax>#dm^-3#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.09375 mol <mathjax>#dm^-3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> refers to the number of moles of a substance per litre of substance.</p> <p>125/1000=0.125 (This is the proportion of 1 litre that 125 ml s is, seems like a redundant step but it helps you keep track of your numbers)</p> <p>0.15x0.125=0.01875 (This is the number of moles of NaOH in your 125 ml sample)</p> <p>The next step is adding the 75 ml of water to your 125 ml sample. This brings the total volume to 200 ml.</p> <p>The concentration is now 0.01875 moles in 200 ml, simply multiply by 5 to scale to a litre to get your molarity</p> <p>0.09375 moles <mathjax>#dm^-3#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If I add 75 mL of water to 125 mL of a 0.15 M #NaOH# solution, what will the molarity of the diluted solution be?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="421321" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/slothdemon"><img alt="" class="" src="https://profilepictures.socratic.org/xUTxipVlRRW0UuhRuwNm_tumblrn79z8o3AeS1t0194go1500.gif" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/slothdemon"> slothdemon </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-11T05:05:31" itemprop="dateCreated"> May 11, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.09375 mol <mathjax>#dm^-3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">Molarity</a> refers to the number of moles of a substance per litre of substance.</p> <p>125/1000=0.125 (This is the proportion of 1 litre that 125 ml s is, seems like a redundant step but it helps you keep track of your numbers)</p> <p>0.15x0.125=0.01875 (This is the number of moles of NaOH in your 125 ml sample)</p> <p>The next step is adding the 75 ml of water to your 125 ml sample. This brings the total volume to 200 ml.</p> <p>The concentration is now 0.01875 moles in 200 ml, simply multiply by 5 to scale to a litre to get your molarity</p> <p>0.09375 moles <mathjax>#dm^-3#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/421321" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 9207 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

If I add 75 mL of water to 125 mL of a 0.15 M #NaOH# solution, what will the molarity of the diluted solution be?

ace8b201-6ddd-11ea-85e3-ccda262736ce

https://socratic.org/questions/if-100-00-j-are-added-to-20-0-g-water-at-30-0-c-what-will-be-the-final-temperatu

31.20 ℃

start physical_unit 8 8 temperature °c qc_end physical_unit 8 8 10 11 temperature qc_end physical_unit 8 8 1 2 energy qc_end physical_unit 8 8 6 7 mass qc_end end

[{"type":"physical unit","value":"Temperature2 [OF] water [IN] ℃"}]

[{"type":"physical unit","value":"31.20 ℃"}]

[{"type":"physical unit","value":"Temperature1 [OF] water [=] \\pu{30.0 ℃}"},{"type":"physical unit","value":"Added energy [OF] water [=] \\pu{100.00 J}"},{"type":"physical unit","value":"Mass [OF] water [=] \\pu{20.0 g}"}]

<h1 class="questionTitle" itemprop="name">If 100.00 J are added to 20.0 g water at 30.0°C, what will be the final temperature of the water?</h1>

31.20 ℃

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The formula for the heat gained or lost by a substance is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(|color(white)(a/a)q = mcΔTcolor(white)(a/a)|)))" "#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange this equation to get</p> <blockquote> <blockquote> <p><mathjax>#ΔT = q/(mc)#</mathjax></p> </blockquote> </blockquote> <p>In this problem,</p> <p><mathjax>#q = "100.00 J"#</mathjax><br/> <mathjax>#m = "20.0 g"#</mathjax><br/> <mathjax>#c = "4.178 J·K"^"-1""g"^"-1"#</mathjax></p> <p><mathjax>#ΔT = (100.00 color(red)(cancel(color(black)("J"))))/(20.0 color(red)(cancel(color(black)("g"))) × "4.178 J"·color(red)(cancel(color(black)("K"^"-1""g"^"-1")))) = "1.197 °C"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#ΔT = T_"f" - T_"i" = T_"f"color(white)(l) "- 30.0 °C" = "1.197 °C"#</mathjax></p> <p><mathjax>#T_"f" = "30.0 °C + 1.197 °C" = "31.2 °C"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final temperature of the water will be 31.2 °C.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The formula for the heat gained or lost by a substance is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(|color(white)(a/a)q = mcΔTcolor(white)(a/a)|)))" "#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange this equation to get</p> <blockquote> <blockquote> <p><mathjax>#ΔT = q/(mc)#</mathjax></p> </blockquote> </blockquote> <p>In this problem,</p> <p><mathjax>#q = "100.00 J"#</mathjax><br/> <mathjax>#m = "20.0 g"#</mathjax><br/> <mathjax>#c = "4.178 J·K"^"-1""g"^"-1"#</mathjax></p> <p><mathjax>#ΔT = (100.00 color(red)(cancel(color(black)("J"))))/(20.0 color(red)(cancel(color(black)("g"))) × "4.178 J"·color(red)(cancel(color(black)("K"^"-1""g"^"-1")))) = "1.197 °C"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#ΔT = T_"f" - T_"i" = T_"f"color(white)(l) "- 30.0 °C" = "1.197 °C"#</mathjax></p> <p><mathjax>#T_"f" = "30.0 °C + 1.197 °C" = "31.2 °C"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If 100.00 J are added to 20.0 g water at 30.0°C, what will be the final temperature of the water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/energy-change-in-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Energy Change in Reactions</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="360368" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-05T01:16:21" itemprop="dateCreated"> Jan 5, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The final temperature of the water will be 31.2 °C.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>The formula for the heat gained or lost by a substance is</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(bar(ul(|color(white)(a/a)q = mcΔTcolor(white)(a/a)|)))" "#</mathjax></p> </blockquote> </blockquote> <p>We can rearrange this equation to get</p> <blockquote> <blockquote> <p><mathjax>#ΔT = q/(mc)#</mathjax></p> </blockquote> </blockquote> <p>In this problem,</p> <p><mathjax>#q = "100.00 J"#</mathjax><br/> <mathjax>#m = "20.0 g"#</mathjax><br/> <mathjax>#c = "4.178 J·K"^"-1""g"^"-1"#</mathjax></p> <p><mathjax>#ΔT = (100.00 color(red)(cancel(color(black)("J"))))/(20.0 color(red)(cancel(color(black)("g"))) × "4.178 J"·color(red)(cancel(color(black)("K"^"-1""g"^"-1")))) = "1.197 °C"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#ΔT = T_"f" - T_"i" = T_"f"color(white)(l) "- 30.0 °C" = "1.197 °C"#</mathjax></p> <p><mathjax>#T_"f" = "30.0 °C + 1.197 °C" = "31.2 °C"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/360368" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-endothermic-reactions-happen"> Why do endothermic reactions happen? 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If 100.00 J are added to 20.0 g water at 30.0°C, what will be the final temperature of the water?

a956d42d-6ddd-11ea-8e72-ccda262736ce

https://socratic.org/questions/the-ksp-of-manganese-ii-carbonate-mnco-3-is-2-42-10-11-what-is-the-solubility-of

5.65 × 10^(-5) g/L

start physical_unit 15 16 solubility g/l qc_end physical_unit 5 5 7 9 equilibrium_constant_k qc_end end

[{"type":"physical unit","value":"Solubility [OF] this compound [IN] g/L"}]

[{"type":"physical unit","value":"5.65 × 10^(-5) g/L"}]

[{"type":"physical unit","value":"Ksp [OF] MnCO3 [=] \\pu{2.42 × 10^(-11)}"}]

<h1 class="questionTitle" itemprop="name">The Ksp of manganese(II) carbonate, #MnCO_3#, is #2.42 * 10^-11#. What is the solubility of this compound in g/L?</h1>

5.65 × 10^(-5) g/L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Manganese(II) carbonate dissociate in water according to the following equation:</p> <p><mathjax>#MnCO_3(s)rightleftharpoonsMn^(2+)(aq)+CO_3^(2-)(aq)" " "K_(sp)=2.42xx10^(-11)#</mathjax></p> <p>The expression of <mathjax>#K_(sp)#</mathjax> is given by: <mathjax>#K_(sp)=[Mn^(2+)][CO_3^(2-)]#</mathjax></p> <p>Let us use ICE table to solve this question:<br/> <mathjax>#" " " " " " "MnCO_3(s)rightleftharpoonsMn^(2+)(aq)+CO_3^(2-)(aq)#</mathjax><br/> <mathjax>#"Initial" " " " "C_M" " " " " " " "0 M" " " " " "0 M"#</mathjax><br/> <mathjax>#"Change" " " " -sM " " " " " " " +s M" " " "" +s M"#</mathjax><br/> <mathjax>#"Equilibrium" " " " " " " " " " " " "s M" " " " " " sM#</mathjax></p> <p>Therefore, the equilibrium concentrations are:<br/> <mathjax>#[Mn^(2+)]=sM#</mathjax><br/> <mathjax>#[CO_3^(2-)]=sM#</mathjax></p> <p>Therefore, <mathjax>#K_(sp)=sxxs=s^2=&gt;s=sqrt(K_(sp))=sqrt(2.42xx10^(-11))#</mathjax></p> <p><mathjax>#=&gt;s=4.92xx10^(-6)M#</mathjax></p> <p>Therefore, the solubility of Manganese(II) carbonate is <mathjax>#s=4.92xx10^(-6)M#</mathjax></p> <p>To convert it to <mathjax>#g/L#</mathjax> using the molar mass of manganese(II) carbonate <mathjax>#114.9469g/"mol"#</mathjax>:</p> <p><mathjax>#s=(4.92xx10^(-6)cancel(mol))/(1L)xx(114.9469g)/(1cancel(mol))=5.65xx10^(-5)g/L#</mathjax></p> <p>Here is a video that will be of great help on solubility equilibria:<br/> <strong>Solubility Equilibria | Solubility Product. </strong><br/> <iframe src="https://www.youtube.com/embed/gJrTx3w3IBA?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#s=5.65xx10^(-5)g/L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Manganese(II) carbonate dissociate in water according to the following equation:</p> <p><mathjax>#MnCO_3(s)rightleftharpoonsMn^(2+)(aq)+CO_3^(2-)(aq)" " "K_(sp)=2.42xx10^(-11)#</mathjax></p> <p>The expression of <mathjax>#K_(sp)#</mathjax> is given by: <mathjax>#K_(sp)=[Mn^(2+)][CO_3^(2-)]#</mathjax></p> <p>Let us use ICE table to solve this question:<br/> <mathjax>#" " " " " " "MnCO_3(s)rightleftharpoonsMn^(2+)(aq)+CO_3^(2-)(aq)#</mathjax><br/> <mathjax>#"Initial" " " " "C_M" " " " " " " "0 M" " " " " "0 M"#</mathjax><br/> <mathjax>#"Change" " " " -sM " " " " " " " +s M" " " "" +s M"#</mathjax><br/> <mathjax>#"Equilibrium" " " " " " " " " " " " "s M" " " " " " sM#</mathjax></p> <p>Therefore, the equilibrium concentrations are:<br/> <mathjax>#[Mn^(2+)]=sM#</mathjax><br/> <mathjax>#[CO_3^(2-)]=sM#</mathjax></p> <p>Therefore, <mathjax>#K_(sp)=sxxs=s^2=&gt;s=sqrt(K_(sp))=sqrt(2.42xx10^(-11))#</mathjax></p> <p><mathjax>#=&gt;s=4.92xx10^(-6)M#</mathjax></p> <p>Therefore, the solubility of Manganese(II) carbonate is <mathjax>#s=4.92xx10^(-6)M#</mathjax></p> <p>To convert it to <mathjax>#g/L#</mathjax> using the molar mass of manganese(II) carbonate <mathjax>#114.9469g/"mol"#</mathjax>:</p> <p><mathjax>#s=(4.92xx10^(-6)cancel(mol))/(1L)xx(114.9469g)/(1cancel(mol))=5.65xx10^(-5)g/L#</mathjax></p> <p>Here is a video that will be of great help on solubility equilibria:<br/> <strong>Solubility Equilibria | Solubility Product. </strong><br/> <iframe src="https://www.youtube.com/embed/gJrTx3w3IBA?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">The Ksp of manganese(II) carbonate, #MnCO_3#, is #2.42 * 10^-11#. What is the solubility of this compound in g/L?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/solubility-equilbria" itemprop="url"> <span class="breadcrumb" itemprop="title">Solubility Equilbria</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="198335" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-10T07:49:16" itemprop="dateCreated"> Dec 10, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#s=5.65xx10^(-5)g/L#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Manganese(II) carbonate dissociate in water according to the following equation:</p> <p><mathjax>#MnCO_3(s)rightleftharpoonsMn^(2+)(aq)+CO_3^(2-)(aq)" " "K_(sp)=2.42xx10^(-11)#</mathjax></p> <p>The expression of <mathjax>#K_(sp)#</mathjax> is given by: <mathjax>#K_(sp)=[Mn^(2+)][CO_3^(2-)]#</mathjax></p> <p>Let us use ICE table to solve this question:<br/> <mathjax>#" " " " " " "MnCO_3(s)rightleftharpoonsMn^(2+)(aq)+CO_3^(2-)(aq)#</mathjax><br/> <mathjax>#"Initial" " " " "C_M" " " " " " " "0 M" " " " " "0 M"#</mathjax><br/> <mathjax>#"Change" " " " -sM " " " " " " " +s M" " " "" +s M"#</mathjax><br/> <mathjax>#"Equilibrium" " " " " " " " " " " " "s M" " " " " " sM#</mathjax></p> <p>Therefore, the equilibrium concentrations are:<br/> <mathjax>#[Mn^(2+)]=sM#</mathjax><br/> <mathjax>#[CO_3^(2-)]=sM#</mathjax></p> <p>Therefore, <mathjax>#K_(sp)=sxxs=s^2=&gt;s=sqrt(K_(sp))=sqrt(2.42xx10^(-11))#</mathjax></p> <p><mathjax>#=&gt;s=4.92xx10^(-6)M#</mathjax></p> <p>Therefore, the solubility of Manganese(II) carbonate is <mathjax>#s=4.92xx10^(-6)M#</mathjax></p> <p>To convert it to <mathjax>#g/L#</mathjax> using the molar mass of manganese(II) carbonate <mathjax>#114.9469g/"mol"#</mathjax>:</p> <p><mathjax>#s=(4.92xx10^(-6)cancel(mol))/(1L)xx(114.9469g)/(1cancel(mol))=5.65xx10^(-5)g/L#</mathjax></p> <p>Here is a video that will be of great help on solubility equilibria:<br/> <strong>Solubility Equilibria | Solubility Product. </strong><br/> <iframe src="https://www.youtube.com/embed/gJrTx3w3IBA?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/198335" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-equilibrium"> How does solubility affect equilibrium? 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The Ksp of manganese(II) carbonate, #MnCO_3#, is #2.42 * 10^-11#. What is the solubility of this compound in g/L?

a8fe9c06-6ddd-11ea-a76f-ccda262736ce

https://socratic.org/questions/a-gas-sample-weighing-3-78-grams-occupies-a-volume-of-2-28-l-at-stp-what-is-the-

37.6 g/mol

start physical_unit 20 21 molecular_weight g/mol qc_end physical_unit 1 2 4 5 mass qc_end physical_unit 1 2 10 11 volume qc_end c_other STP qc_end end

[{"type":"physical unit","value":"Molecular mass [OF] the sample [IN] g/mol"}]

[{"type":"physical unit","value":"37.6 g/mol"}]

[{"type":"physical unit","value":"Mass [OF] the gas sample [=] \\pu{3.78 grams}"},{"type":"physical unit","value":"Volume [OF] the gas sample [=] \\pu{2.28 L}"},{"type":"other","value":"STP"}]

<h1 class="questionTitle" itemprop="name">A gas sample weighing 3.78 grams occupies a volume of 2.28 L at STP. What is the molecular mass of the sample? </h1>

37.6 g/mol

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The trick here is to realize that if you know the <em>volume</em> of a gas at <strong>STP</strong>, you can use the fact that <mathjax>#1#</mathjax> <strong>mole</strong> of any ideal gas occupies <mathjax>#"22.7 L"#</mathjax> under STP conditions to calculate how many <strong>moles</strong> of gas you have in your sample. </p> <blockquote> <p><mathjax>#color(red)(ul(color(black)("Under STP conditions: " "1 mole of an ideal gas = 22.7 L")))#</mathjax></p> </blockquote> <p>In your case, you know that your sample of gas occupies <mathjax>#"2.28 L"#</mathjax> under STP conditions, which are <em><strong>currently</strong></em> defined as a pressure of <mathjax>#"100 kPa"#</mathjax> and a temperature of <mathjax>#0^@"C"#</mathjax>.</p> <p>This means that your sample will contain</p> <blockquote> <p><mathjax>#2.28 color(red)(cancel(color(black)("L"))) * overbrace("1 mole gas"/(22.7color(red)(cancel(color(black)("L")))))^(color(blue)("molar volume of a gas at STP")) = "0.10044 moles gas"#</mathjax></p> </blockquote> <p>Now, the <strong>molar mass</strong> of the gas is the mass of exactly <mathjax>#1#</mathjax> <strong>mole</strong> of the gas. In your case, you know that you get <mathjax>#"3.78 g"#</mathjax> <strong>for every</strong> <mathjax>#0.10044#</mathjax> <strong>moles</strong>, which means that you have</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("mole"))) * "3.78 g"/(0.10044color(red)(cancel(color(black)("moles")))) = "37.6 g"#</mathjax></p> </blockquote> <p>Since this is the mass of <mathjax>#1#</mathjax> mole of gas, you can say that the molar mass of the gas is </p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("molar mass = 37.6 g mol"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p> <p><strong>SIDE NOTE</strong> <em>A lot of textbooks and online sources still use <strong>the old definition</strong> of STP conditions, i.e. a pressure of</em> <mathjax>#"1 atm"#</mathjax> <em>and a temperature of</em> <mathjax>#0^@"C"#</mathjax>. </p> <p><em>Under these conditions,</em> <mathjax>#1#</mathjax> <em><strong>mole</strong> of any ideal gas occupies</em> <mathjax>#"22.4 L"#</mathjax>. <em>If this is the value of the <a href="https://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas</a> at STP given to you, simply redo the calculations using</em> <mathjax>#"22.4 L"#</mathjax> <em>instaed of</em> <mathjax>#"22.7 L"#</mathjax>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"37.6 g mol"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The trick here is to realize that if you know the <em>volume</em> of a gas at <strong>STP</strong>, you can use the fact that <mathjax>#1#</mathjax> <strong>mole</strong> of any ideal gas occupies <mathjax>#"22.7 L"#</mathjax> under STP conditions to calculate how many <strong>moles</strong> of gas you have in your sample. </p> <blockquote> <p><mathjax>#color(red)(ul(color(black)("Under STP conditions: " "1 mole of an ideal gas = 22.7 L")))#</mathjax></p> </blockquote> <p>In your case, you know that your sample of gas occupies <mathjax>#"2.28 L"#</mathjax> under STP conditions, which are <em><strong>currently</strong></em> defined as a pressure of <mathjax>#"100 kPa"#</mathjax> and a temperature of <mathjax>#0^@"C"#</mathjax>.</p> <p>This means that your sample will contain</p> <blockquote> <p><mathjax>#2.28 color(red)(cancel(color(black)("L"))) * overbrace("1 mole gas"/(22.7color(red)(cancel(color(black)("L")))))^(color(blue)("molar volume of a gas at STP")) = "0.10044 moles gas"#</mathjax></p> </blockquote> <p>Now, the <strong>molar mass</strong> of the gas is the mass of exactly <mathjax>#1#</mathjax> <strong>mole</strong> of the gas. In your case, you know that you get <mathjax>#"3.78 g"#</mathjax> <strong>for every</strong> <mathjax>#0.10044#</mathjax> <strong>moles</strong>, which means that you have</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("mole"))) * "3.78 g"/(0.10044color(red)(cancel(color(black)("moles")))) = "37.6 g"#</mathjax></p> </blockquote> <p>Since this is the mass of <mathjax>#1#</mathjax> mole of gas, you can say that the molar mass of the gas is </p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("molar mass = 37.6 g mol"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p> <p><strong>SIDE NOTE</strong> <em>A lot of textbooks and online sources still use <strong>the old definition</strong> of STP conditions, i.e. a pressure of</em> <mathjax>#"1 atm"#</mathjax> <em>and a temperature of</em> <mathjax>#0^@"C"#</mathjax>. </p> <p><em>Under these conditions,</em> <mathjax>#1#</mathjax> <em><strong>mole</strong> of any ideal gas occupies</em> <mathjax>#"22.4 L"#</mathjax>. <em>If this is the value of the <a href="https://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas</a> at STP given to you, simply redo the calculations using</em> <mathjax>#"22.4 L"#</mathjax> <em>instaed of</em> <mathjax>#"22.7 L"#</mathjax>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A gas sample weighing 3.78 grams occupies a volume of 2.28 L at STP. What is the molecular mass of the sample? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="380790" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-21T00:02:35" itemprop="dateCreated"> Feb 21, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"37.6 g mol"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The trick here is to realize that if you know the <em>volume</em> of a gas at <strong>STP</strong>, you can use the fact that <mathjax>#1#</mathjax> <strong>mole</strong> of any ideal gas occupies <mathjax>#"22.7 L"#</mathjax> under STP conditions to calculate how many <strong>moles</strong> of gas you have in your sample. </p> <blockquote> <p><mathjax>#color(red)(ul(color(black)("Under STP conditions: " "1 mole of an ideal gas = 22.7 L")))#</mathjax></p> </blockquote> <p>In your case, you know that your sample of gas occupies <mathjax>#"2.28 L"#</mathjax> under STP conditions, which are <em><strong>currently</strong></em> defined as a pressure of <mathjax>#"100 kPa"#</mathjax> and a temperature of <mathjax>#0^@"C"#</mathjax>.</p> <p>This means that your sample will contain</p> <blockquote> <p><mathjax>#2.28 color(red)(cancel(color(black)("L"))) * overbrace("1 mole gas"/(22.7color(red)(cancel(color(black)("L")))))^(color(blue)("molar volume of a gas at STP")) = "0.10044 moles gas"#</mathjax></p> </blockquote> <p>Now, the <strong>molar mass</strong> of the gas is the mass of exactly <mathjax>#1#</mathjax> <strong>mole</strong> of the gas. In your case, you know that you get <mathjax>#"3.78 g"#</mathjax> <strong>for every</strong> <mathjax>#0.10044#</mathjax> <strong>moles</strong>, which means that you have</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("mole"))) * "3.78 g"/(0.10044color(red)(cancel(color(black)("moles")))) = "37.6 g"#</mathjax></p> </blockquote> <p>Since this is the mass of <mathjax>#1#</mathjax> mole of gas, you can say that the molar mass of the gas is </p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("molar mass = 37.6 g mol"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p> <p><strong>SIDE NOTE</strong> <em>A lot of textbooks and online sources still use <strong>the old definition</strong> of STP conditions, i.e. a pressure of</em> <mathjax>#"1 atm"#</mathjax> <em>and a temperature of</em> <mathjax>#0^@"C"#</mathjax>. </p> <p><em>Under these conditions,</em> <mathjax>#1#</mathjax> <em><strong>mole</strong> of any ideal gas occupies</em> <mathjax>#"22.4 L"#</mathjax>. <em>If this is the value of the <a href="https://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas</a> at STP given to you, simply redo the calculations using</em> <mathjax>#"22.4 L"#</mathjax> <em>instaed of</em> <mathjax>#"22.7 L"#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/380790" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 40010 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A gas sample weighing 3.78 grams occupies a volume of 2.28 L at STP. What is the molecular mass of the sample?

aa346325-6ddd-11ea-80d1-ccda262736ce

https://socratic.org/questions/what-is-the-ph-of-a-1-10-5-m-solution-of-sulfuric-acid

4.73

start physical_unit 10 10 ph none qc_end physical_unit 12 13 6 9 molarity qc_end end

[{"type":"physical unit","value":"pH [OF] sulfuric acid solution"}]

[{"type":"physical unit","value":"4.73"}]

[{"type":"physical unit","value":"Molarity [OF] sulfuric acid solution [=] \\pu{1 × 10^(-5) M}"}]

<h1 class="questionTitle" itemprop="name">What is the pH of a #1*10^-5# #M# solution of sulfuric acid?</h1>

4.73

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Sulphuric acid is diprotic, and it dissociates in two steps: </p> <p><mathjax>#H_2SO_4 --&gt; H^+ + HSO_4^- #</mathjax></p> <p>This has equilibrium constant that is very large and can be assumed to be "total dissociation". </p> <p>The second step is the dissociation of the bisulphate ion <mathjax>#HSO_4^-#</mathjax>, but this only partially dissociates and the equilibrium constant of this reaction is much lower, in fact the <mathjax>#K_a#</mathjax> value for bisulphate is only 0.0120.</p> <p>Bisulphate dissociates as follows: <mathjax>#HSO_4^-#</mathjax> = <mathjax>#H^+ + SO_4^ 2-#</mathjax> </p> <p><mathjax>#K_a = ([H+]*[SO_4^2-]) / [[HSO4-]#</mathjax></p> <p>If we let the hydrogen ion concentration be X, then:</p> <p>X = [H+] = <mathjax>#[SO_4^ 2-]#</mathjax> , therefore [H+].<mathjax>#[SO_4^2-]#</mathjax> = [X]² </p> <p>The concentration of bisulphate remaining in solution is going to be the original concentration of bisulphate less the amount that dissociated, which is 0.00001 - X.</p> <p>We know that <mathjax>#K_a#</mathjax> is 0.0120, so now we can write:: </p> <p>0.0120 = [X]² / (0.00001-X) <br/> So [X]² = 0.0120*( 0.00001 - X) <br/> X² = 0.0000001 - 0.0120X </p> <p>Now rearrange to quadratic equation:: </p> <p>X² +0.0120X - 0.0000001 = 0</p> <p>X = 0.00000833 (the other root is negative and can be ignored) </p> <p>So now we know the total [H+] is 0.00001 (from initial dissociation) and 0.00000833 (from dissociation of bisulphate dissociation) = 0.00001833 </p> <p>pH = -log [H+] <br/> pH = -log 0.00001833<br/> pH = 4.73 </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I make it 4.73</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Sulphuric acid is diprotic, and it dissociates in two steps: </p> <p><mathjax>#H_2SO_4 --&gt; H^+ + HSO_4^- #</mathjax></p> <p>This has equilibrium constant that is very large and can be assumed to be "total dissociation". </p> <p>The second step is the dissociation of the bisulphate ion <mathjax>#HSO_4^-#</mathjax>, but this only partially dissociates and the equilibrium constant of this reaction is much lower, in fact the <mathjax>#K_a#</mathjax> value for bisulphate is only 0.0120.</p> <p>Bisulphate dissociates as follows: <mathjax>#HSO_4^-#</mathjax> = <mathjax>#H^+ + SO_4^ 2-#</mathjax> </p> <p><mathjax>#K_a = ([H+]*[SO_4^2-]) / [[HSO4-]#</mathjax></p> <p>If we let the hydrogen ion concentration be X, then:</p> <p>X = [H+] = <mathjax>#[SO_4^ 2-]#</mathjax> , therefore [H+].<mathjax>#[SO_4^2-]#</mathjax> = [X]² </p> <p>The concentration of bisulphate remaining in solution is going to be the original concentration of bisulphate less the amount that dissociated, which is 0.00001 - X.</p> <p>We know that <mathjax>#K_a#</mathjax> is 0.0120, so now we can write:: </p> <p>0.0120 = [X]² / (0.00001-X) <br/> So [X]² = 0.0120*( 0.00001 - X) <br/> X² = 0.0000001 - 0.0120X </p> <p>Now rearrange to quadratic equation:: </p> <p>X² +0.0120X - 0.0000001 = 0</p> <p>X = 0.00000833 (the other root is negative and can be ignored) </p> <p>So now we know the total [H+] is 0.00001 (from initial dissociation) and 0.00000833 (from dissociation of bisulphate dissociation) = 0.00001833 </p> <p>pH = -log [H+] <br/> pH = -log 0.00001833<br/> pH = 4.73 </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the pH of a #1*10^-5# #M# solution of sulfuric acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/ph-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">pH calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="286073" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/simon-moore"><img alt="" class="" src="https://profilepictures.socratic.org/0ztdJJ7RCWUlBSPeGa9N_6EB6CADA-35F5-4BAA-9B66-9D6F64A622BA.jpeg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/simon-moore"> Simon Moore </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-08T15:08:02" itemprop="dateCreated"> Jul 8, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I make it 4.73</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Sulphuric acid is diprotic, and it dissociates in two steps: </p> <p><mathjax>#H_2SO_4 --&gt; H^+ + HSO_4^- #</mathjax></p> <p>This has equilibrium constant that is very large and can be assumed to be "total dissociation". </p> <p>The second step is the dissociation of the bisulphate ion <mathjax>#HSO_4^-#</mathjax>, but this only partially dissociates and the equilibrium constant of this reaction is much lower, in fact the <mathjax>#K_a#</mathjax> value for bisulphate is only 0.0120.</p> <p>Bisulphate dissociates as follows: <mathjax>#HSO_4^-#</mathjax> = <mathjax>#H^+ + SO_4^ 2-#</mathjax> </p> <p><mathjax>#K_a = ([H+]*[SO_4^2-]) / [[HSO4-]#</mathjax></p> <p>If we let the hydrogen ion concentration be X, then:</p> <p>X = [H+] = <mathjax>#[SO_4^ 2-]#</mathjax> , therefore [H+].<mathjax>#[SO_4^2-]#</mathjax> = [X]² </p> <p>The concentration of bisulphate remaining in solution is going to be the original concentration of bisulphate less the amount that dissociated, which is 0.00001 - X.</p> <p>We know that <mathjax>#K_a#</mathjax> is 0.0120, so now we can write:: </p> <p>0.0120 = [X]² / (0.00001-X) <br/> So [X]² = 0.0120*( 0.00001 - X) <br/> X² = 0.0000001 - 0.0120X </p> <p>Now rearrange to quadratic equation:: </p> <p>X² +0.0120X - 0.0000001 = 0</p> <p>X = 0.00000833 (the other root is negative and can be ignored) </p> <p>So now we know the total [H+] is 0.00001 (from initial dissociation) and 0.00000833 (from dissociation of bisulphate dissociation) = 0.00001833 </p> <p>pH = -log [H+] <br/> pH = -log 0.00001833<br/> pH = 4.73 </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/286073" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-of-a-solution"> How do you determine ph of a solution? 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What is the pH of a #1*10^-5# #M# solution of sulfuric acid?

a8bfb4a4-6ddd-11ea-8cd0-ccda262736ce

https://socratic.org/questions/what-concentration-of-no-3-results-when-697-ml-of-0-515-m-nano-3-is-mixed-with-6

1.02 M

start physical_unit 3 3 concentration mol/l qc_end physical_unit 11 11 6 7 volume qc_end physical_unit 11 11 9 10 concentration qc_end physical_unit 20 20 15 16 volume qc_end physical_unit 20 20 18 19 concentration qc_end end

[{"type":"physical unit","value":"Concentration [OF] NO3- [IN] M"}]

[{"type":"physical unit","value":"1.02 M"}]

[{"type":"physical unit","value":"Volume [OF] NaNO3 [=] \\pu{697 mL}"},{"type":"physical unit","value":"Concentration [OF] NaNO3 [=] \\pu{0.515 M}"},{"type":"physical unit","value":"Volume [OF] Ca(NO3)2 [=] \\pu{635 mL}"},{"type":"physical unit","value":"Concentration [OF] Ca(NO3)2 [=] \\pu{0.785 M}"}]

<h1 class="questionTitle" itemprop="name">What concentration of #NO_3^(-)# results when 697 mL of 0.515 M #NaNO_3# is mixed with 635 mL of 0.785 M #Ca(NO_3)_2#?</h1>

1.02 M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, <em>sodium nitrate</em>, <mathjax>#"NaNO"_3#</mathjax>, and <em>calcium nitrate</em>, <mathjax>#"Ca"("NO"_3)_2#</mathjax>, are both <strong>soluble</strong> in aqueous solution.</p> <p>This means that when dissolved in water, these <a href="https://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compounds</a> will dissociate completely and exist as cations and anions. </p> <p>More specifically, they will dissociate to form </p> <blockquote> <p><mathjax>#"NaNO"_text(3(aq]) -&gt; "Na"_text((aq])^(+) + "NO"_text(3(aq])^(-)#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#"Ca"("NO"_3)_text(2(aq]) -&gt; "Ca"_text((aq])^(2+) + color(red)(2)"NO"_text(3(aq])^(-)#</mathjax></p> </blockquote> <p>Notice that sodium nitrate dissociates in a <mathjax>#1:1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> with the nitrate anions, which means that <strong>every mole</strong> of the former will produce <mathjax>#1#</mathjax> <strong>mole</strong> of nitrate anions in solution.</p> <p>On the other hand, calcium nitrate dissociates in a <mathjax>#1:color(red)(2)#</mathjax> mole ratio with the nitrate anions, which means that <strong>every mole</strong> of the former will produce <mathjax>#color(red)(2)#</mathjax> <strong>moles</strong> of nitrate anions in solution. </p> <p>Use the molarities and volumes of the two solution to figure out how many moles of each salt you start with</p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies n = c * V)#</mathjax></p> <p><mathjax>#n_(NaNO_3) = "0.515 M" * 697 * 10^(-3)"L" = "0.3590 moles NanO"_3#</mathjax></p> <p><mathjax>#n_(Ca(NO_3)_2) = "0.785 M" * 635 * 10^(-3)"L" = "0.4985 moles Ca"("NO"_3)_2#</mathjax></p> </blockquote> <p>This corresponds to </p> <blockquote> <p><mathjax>#0.3590 color(red)(cancel(color(black)("moles NaNO"_3))) * ("1 mole NO"_3^(-))/(1color(red)(cancel(color(black)("mole NaNO"_3)))) = "0.3590 moles NO"_3^(-)#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#0.4985 color(red)(cancel(color(black)("moles Ca"("NO"_3)_2))) * (color(red)(2)" moles NO"_3^(-))/(1color(red)(cancel(color(black)("mole Ca"("NO"_3)_2)))) = "0.9970 moles NO"_3^(-)#</mathjax></p> </blockquote> <p>The <strong>total number of moles</strong> of nitrate anions will thus be</p> <blockquote> <p><mathjax>#n_"total" = 0.3590 + 0.9970 = "1.356 moles NO"_3^(-)#</mathjax></p> </blockquote> <p>Now, in order to get the concentration of the anions, you need to get the <em>total volume</em> of the solution <strong>in liters</strong></p> <blockquote> <p><mathjax>#V_"total" = 697 * 10^(-3)"L" + 635 * 10^(-3)"L" = "1.332 L"#</mathjax></p> </blockquote> <p>Therefore, the concentration of the nitrate anions will be</p> <blockquote> <p><mathjax>#["NO"_3^(-)] = "1.356 moles"/"1.332 L" = color(green)("1.02 M")#</mathjax></p> </blockquote> <p>The answer is rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#["NO"_3^(-)] = "1.02 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, <em>sodium nitrate</em>, <mathjax>#"NaNO"_3#</mathjax>, and <em>calcium nitrate</em>, <mathjax>#"Ca"("NO"_3)_2#</mathjax>, are both <strong>soluble</strong> in aqueous solution.</p> <p>This means that when dissolved in water, these <a href="https://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compounds</a> will dissociate completely and exist as cations and anions. </p> <p>More specifically, they will dissociate to form </p> <blockquote> <p><mathjax>#"NaNO"_text(3(aq]) -&gt; "Na"_text((aq])^(+) + "NO"_text(3(aq])^(-)#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#"Ca"("NO"_3)_text(2(aq]) -&gt; "Ca"_text((aq])^(2+) + color(red)(2)"NO"_text(3(aq])^(-)#</mathjax></p> </blockquote> <p>Notice that sodium nitrate dissociates in a <mathjax>#1:1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> with the nitrate anions, which means that <strong>every mole</strong> of the former will produce <mathjax>#1#</mathjax> <strong>mole</strong> of nitrate anions in solution.</p> <p>On the other hand, calcium nitrate dissociates in a <mathjax>#1:color(red)(2)#</mathjax> mole ratio with the nitrate anions, which means that <strong>every mole</strong> of the former will produce <mathjax>#color(red)(2)#</mathjax> <strong>moles</strong> of nitrate anions in solution. </p> <p>Use the molarities and volumes of the two solution to figure out how many moles of each salt you start with</p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies n = c * V)#</mathjax></p> <p><mathjax>#n_(NaNO_3) = "0.515 M" * 697 * 10^(-3)"L" = "0.3590 moles NanO"_3#</mathjax></p> <p><mathjax>#n_(Ca(NO_3)_2) = "0.785 M" * 635 * 10^(-3)"L" = "0.4985 moles Ca"("NO"_3)_2#</mathjax></p> </blockquote> <p>This corresponds to </p> <blockquote> <p><mathjax>#0.3590 color(red)(cancel(color(black)("moles NaNO"_3))) * ("1 mole NO"_3^(-))/(1color(red)(cancel(color(black)("mole NaNO"_3)))) = "0.3590 moles NO"_3^(-)#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#0.4985 color(red)(cancel(color(black)("moles Ca"("NO"_3)_2))) * (color(red)(2)" moles NO"_3^(-))/(1color(red)(cancel(color(black)("mole Ca"("NO"_3)_2)))) = "0.9970 moles NO"_3^(-)#</mathjax></p> </blockquote> <p>The <strong>total number of moles</strong> of nitrate anions will thus be</p> <blockquote> <p><mathjax>#n_"total" = 0.3590 + 0.9970 = "1.356 moles NO"_3^(-)#</mathjax></p> </blockquote> <p>Now, in order to get the concentration of the anions, you need to get the <em>total volume</em> of the solution <strong>in liters</strong></p> <blockquote> <p><mathjax>#V_"total" = 697 * 10^(-3)"L" + 635 * 10^(-3)"L" = "1.332 L"#</mathjax></p> </blockquote> <p>Therefore, the concentration of the nitrate anions will be</p> <blockquote> <p><mathjax>#["NO"_3^(-)] = "1.356 moles"/"1.332 L" = color(green)("1.02 M")#</mathjax></p> </blockquote> <p>The answer is rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What concentration of #NO_3^(-)# results when 697 mL of 0.515 M #NaNO_3# is mixed with 635 mL of 0.785 M #Ca(NO_3)_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="202198" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-12-22T15:02:52" itemprop="dateCreated"> Dec 22, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#["NO"_3^(-)] = "1.02 M"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, <em>sodium nitrate</em>, <mathjax>#"NaNO"_3#</mathjax>, and <em>calcium nitrate</em>, <mathjax>#"Ca"("NO"_3)_2#</mathjax>, are both <strong>soluble</strong> in aqueous solution.</p> <p>This means that when dissolved in water, these <a href="https://socratic.org/chemistry/ionic-bonds-and-formulas/ionic-compounds">ionic compounds</a> will dissociate completely and exist as cations and anions. </p> <p>More specifically, they will dissociate to form </p> <blockquote> <p><mathjax>#"NaNO"_text(3(aq]) -&gt; "Na"_text((aq])^(+) + "NO"_text(3(aq])^(-)#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#"Ca"("NO"_3)_text(2(aq]) -&gt; "Ca"_text((aq])^(2+) + color(red)(2)"NO"_text(3(aq])^(-)#</mathjax></p> </blockquote> <p>Notice that sodium nitrate dissociates in a <mathjax>#1:1#</mathjax> <a href="https://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> with the nitrate anions, which means that <strong>every mole</strong> of the former will produce <mathjax>#1#</mathjax> <strong>mole</strong> of nitrate anions in solution.</p> <p>On the other hand, calcium nitrate dissociates in a <mathjax>#1:color(red)(2)#</mathjax> mole ratio with the nitrate anions, which means that <strong>every mole</strong> of the former will produce <mathjax>#color(red)(2)#</mathjax> <strong>moles</strong> of nitrate anions in solution. </p> <p>Use the molarities and volumes of the two solution to figure out how many moles of each salt you start with</p> <blockquote> <p><mathjax>#color(blue)(c = n/V implies n = c * V)#</mathjax></p> <p><mathjax>#n_(NaNO_3) = "0.515 M" * 697 * 10^(-3)"L" = "0.3590 moles NanO"_3#</mathjax></p> <p><mathjax>#n_(Ca(NO_3)_2) = "0.785 M" * 635 * 10^(-3)"L" = "0.4985 moles Ca"("NO"_3)_2#</mathjax></p> </blockquote> <p>This corresponds to </p> <blockquote> <p><mathjax>#0.3590 color(red)(cancel(color(black)("moles NaNO"_3))) * ("1 mole NO"_3^(-))/(1color(red)(cancel(color(black)("mole NaNO"_3)))) = "0.3590 moles NO"_3^(-)#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#0.4985 color(red)(cancel(color(black)("moles Ca"("NO"_3)_2))) * (color(red)(2)" moles NO"_3^(-))/(1color(red)(cancel(color(black)("mole Ca"("NO"_3)_2)))) = "0.9970 moles NO"_3^(-)#</mathjax></p> </blockquote> <p>The <strong>total number of moles</strong> of nitrate anions will thus be</p> <blockquote> <p><mathjax>#n_"total" = 0.3590 + 0.9970 = "1.356 moles NO"_3^(-)#</mathjax></p> </blockquote> <p>Now, in order to get the concentration of the anions, you need to get the <em>total volume</em> of the solution <strong>in liters</strong></p> <blockquote> <p><mathjax>#V_"total" = 697 * 10^(-3)"L" + 635 * 10^(-3)"L" = "1.332 L"#</mathjax></p> </blockquote> <p>Therefore, the concentration of the nitrate anions will be</p> <blockquote> <p><mathjax>#["NO"_3^(-)] = "1.356 moles"/"1.332 L" = color(green)("1.02 M")#</mathjax></p> </blockquote> <p>The answer is rounded to three <a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/202198" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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What concentration of #NO_3^(-)# results when 697 mL of 0.515 M #NaNO_3# is mixed with 635 mL of 0.785 M #Ca(NO_3)_2#?

acab9265-6ddd-11ea-b95a-ccda262736ce

https://socratic.org/questions/9-50g-of-a-sample-of-hydrated-mgso4-are-heated-and-4-85g-of-h20-are-lost-how-wou

MgSO4.7H2O

start chemical_formula qc_end physical_unit 4 7 0 1 mass qc_end physical_unit 14 14 11 12 mass qc_end end

[{"type":"other","value":"Chemical Formula [OF] this hydrated salt [IN] empirical"}]

[{"type":"chemical equation","value":"MgSO4.7H2O"}]

[{"type":"physical unit","value":"Mass [OF] hydrated MgSO4 sample [=] \\pu{9.50 g}"},{"type":"physical unit","value":"Mass [OF] H2O [=] \\pu{4.85 g}"}]

<h1 class="questionTitle" itemprop="name">9.50g of a sample of hydrated MgSO4 are heated and 4.85g of H20 are lost, how would you calculate the empirical formula of this hydrated salt? </h1>

MgSO4.7H2O

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you will use the mass of evaporated water and the mass of the initial hydrated sample to find the formula of the hydrate, <mathjax>#"MgSO"_4 * color(blue)(n)"H"_2"O"#</mathjax>.</p> <p>So, if you start with a sample of hydrated salt that has a mass of <mathjax>#"9.50 g"#</mathjax>, and evaporate all the water of hydration it contains, you are left with</p> <blockquote> <p><mathjax>#m_"anhydrous" = m_"hydrate" - m_"water"#</mathjax></p> <p><mathjax>#m_"anhydrous" = "9.50 g" - "4.85 g" = "4.65 g"#</mathjax></p> </blockquote> <p>This is the mass of the <em>anhydrous salt</em>, which in your case is magnesium sulfate, <mathjax>#"MgSO"_4#</mathjax>. </p> <p>You now know that the hydrate contained </p> <blockquote> <ul> <li><mathjax>#"4.85 g"#</mathjax> of water</li> <li><mathjax>#"4.65 g"#</mathjax> of anhydrous magnesium sulfate</li> </ul> </blockquote> <p>What you need to do next is work out <em>how many moles</em> of each you had in the hydrate. To do that, use their respective molar masses</p> <blockquote> <p><mathjax>#4.85color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))) = "0.26922 moles H"_2"O"#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#4.65color(red)(cancel(color(black)("g"))) * ("1 mole MgSO"_4)/(120.37color(red)(cancel(color(black)("g")))) = "0.03863 moles MgSO"_4#</mathjax></p> </blockquote> <p>Now divide both these numbers by the <em>smallest</em> one to get the <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> that exists between magnesium sulfate and water in the hydrate</p> <blockquote> <p><mathjax>#"For H"_2"O: " (0.26922color(red)(cancel(color(black)("moles"))))/(0.03863color(red)(cancel(color(black)("moles")))) = 6.97 ~~7#</mathjax> </p> <p><mathjax>#"For MgSO"_4:" " (0.03863color(red)(cancel(color(black)("moles"))))/(0.03863color(red)(cancel(color(black)("moles")))) = 1#</mathjax> </p> </blockquote> <p>For every mole of mgnesium sulfate, the hydrate contained <mathjax>#7#</mathjax> moles of water. This means that the empirical formula of the hydrate is</p> <blockquote> <p><mathjax>#"MgSO"_4 * color(blue)(7)"H"_2"O"#</mathjax></p> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"MgSO"_4 * 7"H"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you will use the mass of evaporated water and the mass of the initial hydrated sample to find the formula of the hydrate, <mathjax>#"MgSO"_4 * color(blue)(n)"H"_2"O"#</mathjax>.</p> <p>So, if you start with a sample of hydrated salt that has a mass of <mathjax>#"9.50 g"#</mathjax>, and evaporate all the water of hydration it contains, you are left with</p> <blockquote> <p><mathjax>#m_"anhydrous" = m_"hydrate" - m_"water"#</mathjax></p> <p><mathjax>#m_"anhydrous" = "9.50 g" - "4.85 g" = "4.65 g"#</mathjax></p> </blockquote> <p>This is the mass of the <em>anhydrous salt</em>, which in your case is magnesium sulfate, <mathjax>#"MgSO"_4#</mathjax>. </p> <p>You now know that the hydrate contained </p> <blockquote> <ul> <li><mathjax>#"4.85 g"#</mathjax> of water</li> <li><mathjax>#"4.65 g"#</mathjax> of anhydrous magnesium sulfate</li> </ul> </blockquote> <p>What you need to do next is work out <em>how many moles</em> of each you had in the hydrate. To do that, use their respective molar masses</p> <blockquote> <p><mathjax>#4.85color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))) = "0.26922 moles H"_2"O"#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#4.65color(red)(cancel(color(black)("g"))) * ("1 mole MgSO"_4)/(120.37color(red)(cancel(color(black)("g")))) = "0.03863 moles MgSO"_4#</mathjax></p> </blockquote> <p>Now divide both these numbers by the <em>smallest</em> one to get the <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> that exists between magnesium sulfate and water in the hydrate</p> <blockquote> <p><mathjax>#"For H"_2"O: " (0.26922color(red)(cancel(color(black)("moles"))))/(0.03863color(red)(cancel(color(black)("moles")))) = 6.97 ~~7#</mathjax> </p> <p><mathjax>#"For MgSO"_4:" " (0.03863color(red)(cancel(color(black)("moles"))))/(0.03863color(red)(cancel(color(black)("moles")))) = 1#</mathjax> </p> </blockquote> <p>For every mole of mgnesium sulfate, the hydrate contained <mathjax>#7#</mathjax> moles of water. This means that the empirical formula of the hydrate is</p> <blockquote> <p><mathjax>#"MgSO"_4 * color(blue)(7)"H"_2"O"#</mathjax></p> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">9.50g of a sample of hydrated MgSO4 are heated and 4.85g of H20 are lost, how would you calculate the empirical formula of this hydrated salt? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/determining-formula-and-molar-masses" itemprop="url"> <span class="breadcrumb" itemprop="title">Determining Formula</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="179571" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-24T11:44:37" itemprop="dateCreated"> Oct 24, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"MgSO"_4 * 7"H"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you will use the mass of evaporated water and the mass of the initial hydrated sample to find the formula of the hydrate, <mathjax>#"MgSO"_4 * color(blue)(n)"H"_2"O"#</mathjax>.</p> <p>So, if you start with a sample of hydrated salt that has a mass of <mathjax>#"9.50 g"#</mathjax>, and evaporate all the water of hydration it contains, you are left with</p> <blockquote> <p><mathjax>#m_"anhydrous" = m_"hydrate" - m_"water"#</mathjax></p> <p><mathjax>#m_"anhydrous" = "9.50 g" - "4.85 g" = "4.65 g"#</mathjax></p> </blockquote> <p>This is the mass of the <em>anhydrous salt</em>, which in your case is magnesium sulfate, <mathjax>#"MgSO"_4#</mathjax>. </p> <p>You now know that the hydrate contained </p> <blockquote> <ul> <li><mathjax>#"4.85 g"#</mathjax> of water</li> <li><mathjax>#"4.65 g"#</mathjax> of anhydrous magnesium sulfate</li> </ul> </blockquote> <p>What you need to do next is work out <em>how many moles</em> of each you had in the hydrate. To do that, use their respective molar masses</p> <blockquote> <p><mathjax>#4.85color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"O")/(18.015color(red)(cancel(color(black)("g")))) = "0.26922 moles H"_2"O"#</mathjax></p> </blockquote> <p>and</p> <blockquote> <p><mathjax>#4.65color(red)(cancel(color(black)("g"))) * ("1 mole MgSO"_4)/(120.37color(red)(cancel(color(black)("g")))) = "0.03863 moles MgSO"_4#</mathjax></p> </blockquote> <p>Now divide both these numbers by the <em>smallest</em> one to get the <a href="http://socratic.org/chemistry/stoichiometry/mole-ratios">mole ratio</a> that exists between magnesium sulfate and water in the hydrate</p> <blockquote> <p><mathjax>#"For H"_2"O: " (0.26922color(red)(cancel(color(black)("moles"))))/(0.03863color(red)(cancel(color(black)("moles")))) = 6.97 ~~7#</mathjax> </p> <p><mathjax>#"For MgSO"_4:" " (0.03863color(red)(cancel(color(black)("moles"))))/(0.03863color(red)(cancel(color(black)("moles")))) = 1#</mathjax> </p> </blockquote> <p>For every mole of mgnesium sulfate, the hydrate contained <mathjax>#7#</mathjax> moles of water. This means that the empirical formula of the hydrate is</p> <blockquote> <p><mathjax>#"MgSO"_4 * color(blue)(7)"H"_2"O"#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/179571" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-possible-to-find-a-molecular-formula-from-molar-mass"> Is it possible to find a molecular formula from molar mass? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5368e0cc02bf34779e175781"> Question #75781 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-when-determining-formulas"> What are some common mistakes students make when determining formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-an-acid"> How can I determine the formula of an acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-chemical-formula-of-a-product"> How can I determine the chemical formula of a product? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-empirical-formula-of-a-compound"> How can I determine the empirical formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-a-hydrate"> How can I determine the formula of a hydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-empirical-formula-indicate"> What does the empirical formula indicate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-molecule-with-molecular-weight-of-180-18-g-mol-is-analyzed-and-found-to-contai"> A molecule with molecular weight of 180.18 g/mol is analyzed and found to contain 40.00% carbon,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-i-need-to-know-the-number-of-moles-of-each-element-to-determine-the-formula-o"> Do I need to know the number of moles of each element to determine the formula of the compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/determining-formula-and-molar-masses"> See all questions in Determining Formula </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 36612 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

9.50g of a sample of hydrated MgSO4 are heated and 4.85g of H20 are lost, how would you calculate the empirical formula of this hydrated salt?

ac0ee146-6ddd-11ea-b068-ccda262736ce

https://socratic.org/questions/the-ka-value-of-a-weak-acid-ha-is-10-6-an-initial-solution-containing-1-0-m-of-h

3.00

start physical_unit 26 27 ph none qc_end physical_unit 7 7 9 9 ka qc_end physical_unit 7 7 14 15 molarity qc_end c_other Equilibrium qc_end end

[{"type":"physical unit","value":"pH [OF] final solution"}]

[{"type":"physical unit","value":"3.00"}]

[{"type":"physical unit","value":"Ka [OF] HA [=] \\pu{10^(-6)}"},{"type":"physical unit","value":"Molarity [OF] HA solution [=] \\pu{1.0 M}"},{"type":"other","value":"Equilibrium."}]

<h1 class="questionTitle" itemprop="name">The Ka value of a weak acid, HA, is 10-6. An initial solution containing 1.0 M of HA is prepared. What is the pH of the final solution at equilibrium?</h1>

3.00

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For a weak acid you can use the expression:</p> <p><mathjax>#sf(pH=1/2[pK_a-log[acid])#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(pH=1/2[6-log(1)]#</mathjax></p> <p><mathjax>#sf(pH=3)#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#sf(pH=3)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For a weak acid you can use the expression:</p> <p><mathjax>#sf(pH=1/2[pK_a-log[acid])#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(pH=1/2[6-log(1)]#</mathjax></p> <p><mathjax>#sf(pH=3)#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">The Ka value of a weak acid, HA, is 10-6. An initial solution containing 1.0 M of HA is prepared. What is the pH of the final solution at equilibrium?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="461362" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michael-2"><img alt="" class="" src="https://lh3.googleusercontent.com/-gCv6FQRhls0/AAAAAAAAAAI/AAAAAAAAAAA/AAnnY7oOJS05Ylqn3KuDSW0LfnbOk7FezQ/mo/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michael-2"> Michael </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-07T19:00:07" itemprop="dateCreated"> Aug 7, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#sf(pH=3)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>For a weak acid you can use the expression:</p> <p><mathjax>#sf(pH=1/2[pK_a-log[acid])#</mathjax></p> <p><mathjax>#:.#</mathjax><mathjax>#sf(pH=1/2[6-log(1)]#</mathjax></p> <p><mathjax>#sf(pH=3)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/461362" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="461412" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/truong-son-n"><img alt="" class="" src="https://profilepictures.socratic.org/07k4plnQfmnmzMuesQzw_14844-1449381920.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/truong-son-n"> Truong-Son N. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-07T21:54:45" itemprop="dateCreated"> Aug 7, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><blockquote> <p><mathjax>#"pH" = 3#</mathjax>.</p> </blockquote> <p>If you wish, you could use <a href="https://socratic.org/scratchpad/b5f61145339f13057762">the equation shown at the end here</a>, which is what Michael has done.</p> <hr/> <p>For this weak acid, a <strong>general equilibrium</strong> can be written:</p> <blockquote> <p><mathjax>#"HA"(aq) rightleftharpoons "H"^(+)(aq) + "A"^(-)(aq)#</mathjax></p> </blockquote> <p>After you make your ICE table, or whatever floats your boat, you should end up with a <strong>mass action expression</strong> of:</p> <blockquote> <p><mathjax>#K_a = 10^(-6) = (x^2)/(1.0 - x)#</mathjax></p> </blockquote> <p>For typical concentrations (about <mathjax>#0.01 - "1.0 M"#</mathjax>), if <mathjax>#K_a &lt; 10^(-5)#</mathjax> or so, we can consider the small <mathjax>#x#</mathjax> approximation without much loss of accuracy. </p> <p>(Furthermore, the percent dissociation decreases with increasing starting concentration, so a <mathjax>#"1.0 M"#</mathjax> concentration is even better for the approximation than, say, <mathjax>#"0.01 M"#</mathjax>.)</p> <p>This says that we can write:</p> <blockquote> <p><mathjax>#K_a ~~ (x^2)/(1.0)#</mathjax></p> </blockquote> <p>or that</p> <blockquote> <p><mathjax>#x -= ["H"^(+)] = sqrt(K_a("1.0 M"))#</mathjax></p> <p><mathjax>#= sqrt(10^(-6) cdot 1)#</mathjax></p> <p><mathjax>#= 10^(-3)#</mathjax> <mathjax>#"M"#</mathjax></p> </blockquote> <p>And thus, the <mathjax>#"pH"#</mathjax> would be:</p> <blockquote> <p><mathjax>#color(blue)("pH") = -log["H"^(+)]#</mathjax></p> <p><mathjax>#= -log(10^(-3)) = color(blue)(3)#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/461412" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-ph-values-of-acids-and-bases-differ"> How do pH values of acids and bases differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-something-on-a-ph-scale"> How do you calculate something on a pH scale? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-diprotic-acid"> How do you calculate pH diprotic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-from-acid-dissociation-constant"> How do you calculate pH from acid dissociation constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-ph-of-acid-and-base-solution"> How do you calculate pH of acid and base solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ph-scale-0-14"> Why is the pH scale 0-14? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-ph-the-measure-of-the-hydrogen-ion-concentration"> Is pH a measure of the hydrogen ion concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-solubility-affect-ph"> How does solubility affect pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-ph-relate-to-pka-in-a-titration"> How does pH relate to pKa in a titration? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/the-ph-concept"> See all questions in pH </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 23069 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

The Ka value of a weak acid, HA, is 10-6. An initial solution containing 1.0 M of HA is prepared. What is the pH of the final solution at equilibrium?

aa36fbdc-6ddd-11ea-bff9-ccda262736ce

https://socratic.org/questions/the-following-chemical-equation-is-not-balanced-fe-2o-3-h-2so-4-fe-2-so-4-3-h-2o

3

start physical_unit 27 28 coefficient none qc_end chemical_equation 7 13 qc_end end

[{"type":"physical unit","value":"Coefficient [OF] water molecule"}]

[{"type":"physical unit","value":"3"}]

[{"type":"chemical equation","value":"Fe2O3 + H2SO4 -> Fe2(SO4)3 + H2O"}]

<h1 class="questionTitle" itemprop="name">The following chemical equation is not balanced: #Fe_2O_3 + H_2SO_4 -&gt; Fe_2(SO_4)_3 + H_2O#. When this chemical equation is correctly balanced, what is the coefficient of the water molecule? </h1>

3

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Water has a <mathjax>#3#</mathjax> coeeficient. Is the equation stoichiometrically balanced? If not, then it should be.</p> <p>The oxide ion is dibasic, and reacts with 2 equiv <mathjax>#H^+#</mathjax> to give the water molecule:</p> <p><mathjax>#O^(2-) +2H^(+) rarr H_2O#</mathjax></p> <p>How would write a balanced equation that represented the formation of nickel chloride from nickel oxide?</p> <p><mathjax>#"Nickel oxide + hydrochloric acid "rarr" Nickel chloride + water"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Fe_2O_3(s) + 3H_2SO_4(aq)rarrFe_2(SO_4)_3 + 3H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Water has a <mathjax>#3#</mathjax> coeeficient. Is the equation stoichiometrically balanced? If not, then it should be.</p> <p>The oxide ion is dibasic, and reacts with 2 equiv <mathjax>#H^+#</mathjax> to give the water molecule:</p> <p><mathjax>#O^(2-) +2H^(+) rarr H_2O#</mathjax></p> <p>How would write a balanced equation that represented the formation of nickel chloride from nickel oxide?</p> <p><mathjax>#"Nickel oxide + hydrochloric acid "rarr" Nickel chloride + water"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">The following chemical equation is not balanced: #Fe_2O_3 + H_2SO_4 -&gt; Fe_2(SO_4)_3 + H_2O#. When this chemical equation is correctly balanced, what is the coefficient of the water molecule? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="294472" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-01T15:51:58" itemprop="dateCreated"> Aug 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Fe_2O_3(s) + 3H_2SO_4(aq)rarrFe_2(SO_4)_3 + 3H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Water has a <mathjax>#3#</mathjax> coeeficient. Is the equation stoichiometrically balanced? If not, then it should be.</p> <p>The oxide ion is dibasic, and reacts with 2 equiv <mathjax>#H^+#</mathjax> to give the water molecule:</p> <p><mathjax>#O^(2-) +2H^(+) rarr H_2O#</mathjax></p> <p>How would write a balanced equation that represented the formation of nickel chloride from nickel oxide?</p> <p><mathjax>#"Nickel oxide + hydrochloric acid "rarr" Nickel chloride + water"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/294472" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------&gt; H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -&gt; Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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The following chemical equation is not balanced: #Fe_2O_3 + H_2SO_4 -&gt; Fe_2(SO_4)_3 + H_2O#. When this chemical equation is correctly balanced, what is the coefficient of the water molecule?

a8b50b89-6ddd-11ea-b9ce-ccda262736ce

https://socratic.org/questions/what-is-the-volume-occupied-by-one-mole-of-helium-at-0-c-and-1-atm-pressure

22.4 L

start physical_unit 9 9 volume l qc_end physical_unit 9 9 11 12 temperature qc_end physical_unit 9 9 14 15 pressure qc_end physical_unit 9 9 6 7 mole qc_end end

[{"type":"physical unit","value":"Volume [OF] helium [IN] L"}]

[{"type":"physical unit","value":"22.4 L"}]

[{"type":"physical unit","value":"Temperature [OF] helium [=] \\pu{0 ℃}"},{"type":"physical unit","value":"Pressure [OF] helium [=] \\pu{1 atm}"},{"type":"physical unit","value":"Mole [OF] helium [=] \\pu{1 mole}"}]

<h1 class="questionTitle" itemprop="name">What is the volume occupied by one mole of helium at 0 C and 1 atm pressure? </h1>

22.4 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The conditions for temperature and pressure provided to you actually correspond to the <em><strong>old</strong></em> definition of <strong>STP</strong> (Standard Pressure and Temperature).</p> <p>Under these specific conditions, <mathjax>#1#</mathjax> <strong>mole</strong> of any ideal gas occupies <mathjax>#"22.4 L"#</mathjax>. This value is known as the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas</a></strong>.</p> <p>You can show that this is the case by using the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</strong>, which looks like this </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(PV = nRT)))#</mathjax></p> </blockquote> <p>Here</p> <blockquote> <ul> <li><mathjax>#P#</mathjax> is the pressure of the gas</li> <li><mathjax>#V#</mathjax> is the volume it occupies</li> <li><mathjax>#n#</mathjax> is the number of moles of gas present in the sample</li> <li><mathjax>#R#</mathjax> is the <em>universal gas constant</em>, equal to <mathjax>#0.0821("atm L")/("mol K")#</mathjax></li> <li><mathjax>#T#</mathjax> is the <strong>absolute temperature</strong> of the gas</li> </ul> </blockquote> <p>Rearrange the ideal gas law equation to </p> <blockquote> <p><mathjax>#PV = nRT implies V/n = (RT)/P#</mathjax></p> </blockquote> <p>Plug in your values to find -- <strong>do not</strong> forget to convert the temperature from <em>degrees Celsius</em> to <em>Kelvin</em></p> <blockquote> <p><mathjax>#V/n = (0.0821 (color(red)(cancel(color(black)("atm"))) * "L")/("mol" * color(red)(cancel(color(black)("K")))) * (273.15 + 0)color(red)(cancel(color(black)("K"))))/(1color(red)(cancel(color(black)("atm"))))#</mathjax></p> <p><mathjax>#V/n = "22.4 L mol"^(-1)#</mathjax></p> </blockquote> <p>This means that under these conditions for pressure and temperature, you get <mathjax>#"22.4 L"#</mathjax> <strong>for every mole</strong> of an ideal gas present in a sample. </p> <p><strong>SIDE NOTE</strong> <em>STP conditions are <strong>currently</strong> defined as a pressure of</em> <mathjax>#"100 kPa"#</mathjax> <em>and a temperature of</em> <mathjax>#0^@"C"#</mathjax>.</p> <p><em>Under these specific conditions, the <strong>molar volume of a gas</strong> is equal to</em> <mathjax>#"22.7 L mol"^(-1)#</mathjax>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"22.4 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The conditions for temperature and pressure provided to you actually correspond to the <em><strong>old</strong></em> definition of <strong>STP</strong> (Standard Pressure and Temperature).</p> <p>Under these specific conditions, <mathjax>#1#</mathjax> <strong>mole</strong> of any ideal gas occupies <mathjax>#"22.4 L"#</mathjax>. This value is known as the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas</a></strong>.</p> <p>You can show that this is the case by using the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</strong>, which looks like this </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(PV = nRT)))#</mathjax></p> </blockquote> <p>Here</p> <blockquote> <ul> <li><mathjax>#P#</mathjax> is the pressure of the gas</li> <li><mathjax>#V#</mathjax> is the volume it occupies</li> <li><mathjax>#n#</mathjax> is the number of moles of gas present in the sample</li> <li><mathjax>#R#</mathjax> is the <em>universal gas constant</em>, equal to <mathjax>#0.0821("atm L")/("mol K")#</mathjax></li> <li><mathjax>#T#</mathjax> is the <strong>absolute temperature</strong> of the gas</li> </ul> </blockquote> <p>Rearrange the ideal gas law equation to </p> <blockquote> <p><mathjax>#PV = nRT implies V/n = (RT)/P#</mathjax></p> </blockquote> <p>Plug in your values to find -- <strong>do not</strong> forget to convert the temperature from <em>degrees Celsius</em> to <em>Kelvin</em></p> <blockquote> <p><mathjax>#V/n = (0.0821 (color(red)(cancel(color(black)("atm"))) * "L")/("mol" * color(red)(cancel(color(black)("K")))) * (273.15 + 0)color(red)(cancel(color(black)("K"))))/(1color(red)(cancel(color(black)("atm"))))#</mathjax></p> <p><mathjax>#V/n = "22.4 L mol"^(-1)#</mathjax></p> </blockquote> <p>This means that under these conditions for pressure and temperature, you get <mathjax>#"22.4 L"#</mathjax> <strong>for every mole</strong> of an ideal gas present in a sample. </p> <p><strong>SIDE NOTE</strong> <em>STP conditions are <strong>currently</strong> defined as a pressure of</em> <mathjax>#"100 kPa"#</mathjax> <em>and a temperature of</em> <mathjax>#0^@"C"#</mathjax>.</p> <p><em>Under these specific conditions, the <strong>molar volume of a gas</strong> is equal to</em> <mathjax>#"22.7 L mol"^(-1)#</mathjax>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the volume occupied by one mole of helium at 0 C and 1 atm pressure? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="381643" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-23T00:41:55" itemprop="dateCreated"> Feb 23, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"22.4 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The conditions for temperature and pressure provided to you actually correspond to the <em><strong>old</strong></em> definition of <strong>STP</strong> (Standard Pressure and Temperature).</p> <p>Under these specific conditions, <mathjax>#1#</mathjax> <strong>mole</strong> of any ideal gas occupies <mathjax>#"22.4 L"#</mathjax>. This value is known as the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas</a></strong>.</p> <p>You can show that this is the case by using the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</strong>, which looks like this </p> <blockquote> <p><mathjax>#color(blue)(ul(color(black)(PV = nRT)))#</mathjax></p> </blockquote> <p>Here</p> <blockquote> <ul> <li><mathjax>#P#</mathjax> is the pressure of the gas</li> <li><mathjax>#V#</mathjax> is the volume it occupies</li> <li><mathjax>#n#</mathjax> is the number of moles of gas present in the sample</li> <li><mathjax>#R#</mathjax> is the <em>universal gas constant</em>, equal to <mathjax>#0.0821("atm L")/("mol K")#</mathjax></li> <li><mathjax>#T#</mathjax> is the <strong>absolute temperature</strong> of the gas</li> </ul> </blockquote> <p>Rearrange the ideal gas law equation to </p> <blockquote> <p><mathjax>#PV = nRT implies V/n = (RT)/P#</mathjax></p> </blockquote> <p>Plug in your values to find -- <strong>do not</strong> forget to convert the temperature from <em>degrees Celsius</em> to <em>Kelvin</em></p> <blockquote> <p><mathjax>#V/n = (0.0821 (color(red)(cancel(color(black)("atm"))) * "L")/("mol" * color(red)(cancel(color(black)("K")))) * (273.15 + 0)color(red)(cancel(color(black)("K"))))/(1color(red)(cancel(color(black)("atm"))))#</mathjax></p> <p><mathjax>#V/n = "22.4 L mol"^(-1)#</mathjax></p> </blockquote> <p>This means that under these conditions for pressure and temperature, you get <mathjax>#"22.4 L"#</mathjax> <strong>for every mole</strong> of an ideal gas present in a sample. </p> <p><strong>SIDE NOTE</strong> <em>STP conditions are <strong>currently</strong> defined as a pressure of</em> <mathjax>#"100 kPa"#</mathjax> <em>and a temperature of</em> <mathjax>#0^@"C"#</mathjax>.</p> <p><em>Under these specific conditions, the <strong>molar volume of a gas</strong> is equal to</em> <mathjax>#"22.7 L mol"^(-1)#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/381643" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? 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What is the volume occupied by one mole of helium at 0 C and 1 atm pressure?

a911d3da-6ddd-11ea-bf6b-ccda262736ce

https://socratic.org/questions/how-many-moles-of-water-are-in-0-34g-of-water

0.02 moles

start physical_unit 4 4 mole mol qc_end physical_unit 4 4 7 8 mass qc_end end

[{"type":"physical unit","value":"Mole [OF] water [IN] moles"}]

[{"type":"physical unit","value":"0.02 moles"}]

[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{0.34 g}"}]

<h1 class="questionTitle" itemprop="name">How many moles of water are in 0.34g of water? </h1>

0.02 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus, <mathjax>#(0.34*cancelg)/(18.01*cancelg*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(??)/(mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??mol#</mathjax></p> <p>Note that all I have done here is set up the problem dimensionally. I want an answer in moles, and it seems I got an answer in moles, which makes me think that I have done it right. How many water molecules in such a quantity?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Number of moles"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass"/"Molar mass"#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#0.02*mol#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus, <mathjax>#(0.34*cancelg)/(18.01*cancelg*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(??)/(mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??mol#</mathjax></p> <p>Note that all I have done here is set up the problem dimensionally. I want an answer in moles, and it seems I got an answer in moles, which makes me think that I have done it right. How many water molecules in such a quantity?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles of water are in 0.34g of water? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="299038" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-08-15T04:14:32" itemprop="dateCreated"> Aug 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Number of moles"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Mass"/"Molar mass"#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#0.02*mol#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>And thus, <mathjax>#(0.34*cancelg)/(18.01*cancelg*mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(??)/(mol^-1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??mol#</mathjax></p> <p>Note that all I have done here is set up the problem dimensionally. I want an answer in moles, and it seems I got an answer in moles, which makes me think that I have done it right. How many water molecules in such a quantity?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/299038" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4891 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many moles of water are in 0.34g of water?

a997ee10-6ddd-11ea-aa16-ccda262736ce

https://socratic.org/questions/a-sample-of-gas-has-a-mass-of-0-565-g-its-volume-is-117-ml-at-a-temperature-of-9

148.04 g/mol

start physical_unit 35 36 molar_mass g/mol qc_end physical_unit 1 3 8 9 mass qc_end physical_unit 1 3 13 14 volume qc_end physical_unit 1 3 19 20 temperature qc_end physical_unit 1 3 25 26 pressure qc_end end

[{"type":"physical unit","value":"Molar mass [OF] the gas [IN] g/mol"}]

[{"type":"physical unit","value":"148.04 g/mol"}]

[{"type":"physical unit","value":"Mass [OF] the gas sample [=] \\pu{0.565 g}"},{"type":"physical unit","value":"Volume [OF] the gas sample [=] \\pu{117 mL}"},{"type":"physical unit","value":"Temperature [OF] the gas sample [=] \\pu{95 ℃}"},{"type":"physical unit","value":"Pressure [OF] the gas sample [=] \\pu{749 mmHg}"}]

<h1 class="questionTitle" itemprop="name">A sample of gas has a mass of 0.565 g. Its volume is 117 mL at a temperature of 95 C and a pressure of 749 mm Hg. How would you find the molar mass of the gas?</h1>

148.04 g/mol

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From the Ideal Gas equation, <mathjax>#n=(PV)/(RT)#</mathjax>, where, <mathjax>#n="Mass"/"Molar mass"#</mathjax>.</p> <p>And thus <mathjax>#"Molar mass "=("Mass"xxRT)/(PV)#</mathjax></p> <p><mathjax>#=(0.565*gxx0.0821*L*atm*K^-1*mol^-1xx368*K)/((749*mm*Hg)/(760*mm*Hg*atm^-1)xx0.117*L)=???g*mol^-1#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Molar mass"#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#150*g*mol^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From the Ideal Gas equation, <mathjax>#n=(PV)/(RT)#</mathjax>, where, <mathjax>#n="Mass"/"Molar mass"#</mathjax>.</p> <p>And thus <mathjax>#"Molar mass "=("Mass"xxRT)/(PV)#</mathjax></p> <p><mathjax>#=(0.565*gxx0.0821*L*atm*K^-1*mol^-1xx368*K)/((749*mm*Hg)/(760*mm*Hg*atm^-1)xx0.117*L)=???g*mol^-1#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A sample of gas has a mass of 0.565 g. Its volume is 117 mL at a temperature of 95 C and a pressure of 749 mm Hg. How would you find the molar mass of the gas?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="345013" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-12-01T16:59:13" itemprop="dateCreated"> Dec 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Molar mass"#</mathjax> <mathjax>#~=#</mathjax> <mathjax>#150*g*mol^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From the Ideal Gas equation, <mathjax>#n=(PV)/(RT)#</mathjax>, where, <mathjax>#n="Mass"/"Molar mass"#</mathjax>.</p> <p>And thus <mathjax>#"Molar mass "=("Mass"xxRT)/(PV)#</mathjax></p> <p><mathjax>#=(0.565*gxx0.0821*L*atm*K^-1*mol^-1xx368*K)/((749*mm*Hg)/(760*mm*Hg*atm^-1)xx0.117*L)=???g*mol^-1#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/345013" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 26456 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A sample of gas has a mass of 0.565 g. Its volume is 117 mL at a temperature of 95 C and a pressure of 749 mm Hg. How would you find the molar mass of the gas?

ad1b8dce-6ddd-11ea-a158-ccda262736ce

https://socratic.org/questions/574079387c01494d69bb1a62

8.48 moles

start physical_unit 3 3 mole mol qc_end physical_unit 10 10 8 9 mole qc_end chemical_equation 11 17 qc_end end

[{"type":"physical unit","value":"Mole [OF] Ag2O [IN] moles"}]

[{"type":"physical unit","value":"8.48 moles"}]

[{"type":"physical unit","value":"Mole [OF] O2 [=] \\pu{4.24 mol}"},{"type":"chemical equation","value":"2 Ag2O -> 4 Ag + O2"}]

<h1 class="questionTitle" itemprop="name">How many moles #"Ag"_2"O"# are needed to produce #"4.24 mol O"_2"#?</h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#"2Ag"_2"O"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"4Ag + O"_2"#</mathjax></p></div> </h2> </div> </div>

8.48 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Balanced Equation</strong></p> <p><mathjax>#"2Ag"_2"O"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"4Ag"+"O"_2"#</mathjax></p> <p>Multiply the given moles of <mathjax>#"O"_2"#</mathjax> times <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between <mathjax>#"Ag"_2"O"#</mathjax> and <mathjax>#"O"_2"#</mathjax> from the balanced equation, with <mathjax>#"Ag"_2"O"#</mathjax> as the numerator.</p> <p><mathjax>#4.25cancel"mol O"_2xx(2"mol Ag"_2"O")/(1cancel"mol O"_2)="8.50 mol Ag"_2"O"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"8.50 mol Ag"_2"O"#</mathjax> are needed to produce <mathjax>#"4.25 mol O"_2"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Balanced Equation</strong></p> <p><mathjax>#"2Ag"_2"O"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"4Ag"+"O"_2"#</mathjax></p> <p>Multiply the given moles of <mathjax>#"O"_2"#</mathjax> times <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between <mathjax>#"Ag"_2"O"#</mathjax> and <mathjax>#"O"_2"#</mathjax> from the balanced equation, with <mathjax>#"Ag"_2"O"#</mathjax> as the numerator.</p> <p><mathjax>#4.25cancel"mol O"_2xx(2"mol Ag"_2"O")/(1cancel"mol O"_2)="8.50 mol Ag"_2"O"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles #"Ag"_2"O"# are needed to produce #"4.24 mol O"_2"#?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#"2Ag"_2"O"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"4Ag + O"_2"#</mathjax></p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="268178" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-21T16:21:54" itemprop="dateCreated"> May 21, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"8.50 mol Ag"_2"O"#</mathjax> are needed to produce <mathjax>#"4.25 mol O"_2"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>Balanced Equation</strong></p> <p><mathjax>#"2Ag"_2"O"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"4Ag"+"O"_2"#</mathjax></p> <p>Multiply the given moles of <mathjax>#"O"_2"#</mathjax> times <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between <mathjax>#"Ag"_2"O"#</mathjax> and <mathjax>#"O"_2"#</mathjax> from the balanced equation, with <mathjax>#"Ag"_2"O"#</mathjax> as the numerator.</p> <p><mathjax>#4.25cancel"mol O"_2xx(2"mol Ag"_2"O")/(1cancel"mol O"_2)="8.50 mol Ag"_2"O"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/268178" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179102bf3469517a1072"> Question #a1072 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" 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How many moles #"Ag"_2"O"# are needed to produce #"4.24 mol O"_2"#?

#"2Ag"_2"O"##rarr##"4Ag + O"_2"#

aca33a68-6ddd-11ea-be1c-ccda262736ce

https://socratic.org/questions/according-to-this-reaction-2al-6hbr-2albr-3-3h-2-if-4-moles-of-al-reacts-with-8-

6.00 mioles

start physical_unit 14 14 mole mol qc_end physical_unit 5 5 16 17 mole qc_end physical_unit 8 8 22 23 mole qc_end chemical_equation 4 14 qc_end end

[{"type":"physical unit","value":"Mole [OF] H2 [IN] moles"}]

[{"type":"physical unit","value":"6.00 mioles"}]

[{"type":"physical unit","value":"Mole [OF] Al [=] \\pu{4 moles}"},{"type":"physical unit","value":"Mole [OF] HBr [=] \\pu{8 moles}"},{"type":"chemical equation","value":"2 Al + 6 HBr -> 2 AlBr3 + 3 H2"}]

<h1 class="questionTitle" itemprop="name">According to this reaction: #2Al+6HBr -&gt; 2AlBr_3 + 3H_2# If 4 moles of #Al# react with 8 moles of #HBr#, how many moles of #H_2# are formed?</h1>

6.00 mioles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#2Al(s) + 6HBr(aq) rarr 2AlBr_3(aq) + 3H_2(g)uarr#</mathjax></p> <p>You have the chemical equation, it tells you EXPLICITLY, that 2 moles of aluminum metal give 3 moles of dihydrogen gas upon reaction. You started with 4 moles of aluminum, thus <mathjax>#3/2#</mathjax> that quantity of dihydrogen are formed.</p> <p>This problem was posed to introduce you to <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, which is a fancy way of saying garbage in equals garbage out. We practise stoichiometry on a smaller scale when we balance our bank accounts, or even when we make a cash or electronic transaction. The debit made to out account for goods of a certain value, must equal the credit made to the account of the vendor who sold you the goods. Likewise, when you hand a shopkeeper a £10-00 note to cover a purchase, the value of the goods purchased + the change you receive must equal £10-00. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#6#</mathjax> <mathjax>#"moles"#</mathjax> of <mathjax>#H_2(g)#</mathjax> are formed. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#2Al(s) + 6HBr(aq) rarr 2AlBr_3(aq) + 3H_2(g)uarr#</mathjax></p> <p>You have the chemical equation, it tells you EXPLICITLY, that 2 moles of aluminum metal give 3 moles of dihydrogen gas upon reaction. You started with 4 moles of aluminum, thus <mathjax>#3/2#</mathjax> that quantity of dihydrogen are formed.</p> <p>This problem was posed to introduce you to <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, which is a fancy way of saying garbage in equals garbage out. We practise stoichiometry on a smaller scale when we balance our bank accounts, or even when we make a cash or electronic transaction. The debit made to out account for goods of a certain value, must equal the credit made to the account of the vendor who sold you the goods. Likewise, when you hand a shopkeeper a £10-00 note to cover a purchase, the value of the goods purchased + the change you receive must equal £10-00. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">According to this reaction: #2Al+6HBr -&gt; 2AlBr_3 + 3H_2# If 4 moles of #Al# react with 8 moles of #HBr#, how many moles of #H_2# are formed?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="255221" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-17T06:05:29" itemprop="dateCreated"> Apr 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#6#</mathjax> <mathjax>#"moles"#</mathjax> of <mathjax>#H_2(g)#</mathjax> are formed. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#2Al(s) + 6HBr(aq) rarr 2AlBr_3(aq) + 3H_2(g)uarr#</mathjax></p> <p>You have the chemical equation, it tells you EXPLICITLY, that 2 moles of aluminum metal give 3 moles of dihydrogen gas upon reaction. You started with 4 moles of aluminum, thus <mathjax>#3/2#</mathjax> that quantity of dihydrogen are formed.</p> <p>This problem was posed to introduce you to <a href="https://socratic.org/chemistry/stoichiometry/stoichiometry">stoichiometry</a>, which is a fancy way of saying garbage in equals garbage out. We practise stoichiometry on a smaller scale when we balance our bank accounts, or even when we make a cash or electronic transaction. The debit made to out account for goods of a certain value, must equal the credit made to the account of the vendor who sold you the goods. Likewise, when you hand a shopkeeper a £10-00 note to cover a purchase, the value of the goods purchased + the change you receive must equal £10-00. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/255221" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1666 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

According to this reaction: #2Al+6HBr -&gt; 2AlBr_3 + 3H_2# If 4 moles of #Al# react with 8 moles of #HBr#, how many moles of #H_2# are formed?

a8d40030-6ddd-11ea-9a48-ccda262736ce

https://socratic.org/questions/calculate-the-heat-required-to-raise-the-temperature-of-2-0-kg-of-ice-at-25-c-to

4.0 × 10^5 J

start physical_unit 12 12 heat_energy j qc_end physical_unit 12 12 9 10 mass qc_end physical_unit 12 12 14 15 temperature qc_end physical_unit 12 12 17 18 temperature qc_end end

[{"type":"physical unit","value":"Required heat [OF] ice [IN] J"}]

[{"type":"physical unit","value":"4.0 × 10^5 J"}]

[{"type":"physical unit","value":"Temperature1 [OF] ice [=] \\pu{-25 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] ice [=] \\pu{70 ℃}"},{"type":"physical unit","value":"Mass [OF] ice [=] \\pu{2.0 kg}"}]

<h1 class="questionTitle" itemprop="name">Calculate the heat required to raise the temperature of 2.0 kg of ice at -25˚C to 70.˚C? </h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>(I keep on getting a value of <mathjax>#4.0 * 10^5#</mathjax> but the answer key says, <mathjax>#1.4 * 10^6 J#</mathjax>.</p></div> </h2> </div> </div>

4.0 × 10^5 J

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#q = mC_sDeltaT#</mathjax></p> <p><mathjax>#q = (2.0*10^3g) * (2.06J/(g*°C)) * 95°C#</mathjax><br/> <mathjax>#q = 4.0*10^5J#</mathjax></p> <p><mathjax>#1.4*10^6J = (2.0*10^3g) * C_s * 95°C#</mathjax></p> <p>If the answer key is "right", then the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of ice is <mathjax>#7.368J*g^-1*°C^-1#</mathjax>. That doesn't sound accurate, so perhaps the key is wrong—maybe I'm missing something that someone else can catch!</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#q = 4.0*10^5J#</mathjax></p> <p>I have a feeling you're right.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#q = mC_sDeltaT#</mathjax></p> <p><mathjax>#q = (2.0*10^3g) * (2.06J/(g*°C)) * 95°C#</mathjax><br/> <mathjax>#q = 4.0*10^5J#</mathjax></p> <p><mathjax>#1.4*10^6J = (2.0*10^3g) * C_s * 95°C#</mathjax></p> <p>If the answer key is "right", then the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of ice is <mathjax>#7.368J*g^-1*°C^-1#</mathjax>. That doesn't sound accurate, so perhaps the key is wrong—maybe I'm missing something that someone else can catch!</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Calculate the heat required to raise the temperature of 2.0 kg of ice at -25˚C to 70.˚C? </h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>(I keep on getting a value of <mathjax>#4.0 * 10^5#</mathjax> but the answer key says, <mathjax>#1.4 * 10^6 J#</mathjax>.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="447424" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/al-e"><img alt="" class="" src="https://lh4.googleusercontent.com/-oz5UmZwruBQ/AAAAAAAAAAI/AAAAAAAAAFs/Oc0IDeN2ejw/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/al-e"> Al E. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-03T15:32:46" itemprop="dateCreated"> Jul 3, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#q = 4.0*10^5J#</mathjax></p> <p>I have a feeling you're right.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#q = mC_sDeltaT#</mathjax></p> <p><mathjax>#q = (2.0*10^3g) * (2.06J/(g*°C)) * 95°C#</mathjax><br/> <mathjax>#q = 4.0*10^5J#</mathjax></p> <p><mathjax>#1.4*10^6J = (2.0*10^3g) * C_s * 95°C#</mathjax></p> <p>If the answer key is "right", then the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of ice is <mathjax>#7.368J*g^-1*°C^-1#</mathjax>. That doesn't sound accurate, so perhaps the key is wrong—maybe I'm missing something that someone else can catch!</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/447424" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="447537" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-03T20:19:16" itemprop="dateCreated"> Jul 3, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The heat required is <mathjax>#1.40 × 10^6color(white)(l) "J"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>A typical heating curve of water is shown below.</p> <p><img alt="www.kentchemistry.com" src="http://www.kentchemistry.com/images/links/matter/aim10.5.jpg"/></p> <p>There are three separate heat transfers involved in this problem:</p> <ul> <li><mathjax>#q_1#</mathjax> = heat required to warm the ice from -25 °C to 0 °C (Point <strong>A</strong> to <strong>B</strong> in the diagram)</li> <li><mathjax>#q_2#</mathjax> = heat required to melt the ice to water at 0 °C (Point <strong>B</strong> to <strong>C</strong>)</li> <li><mathjax>#q_3#</mathjax> = heat required to warm the water from 0 °C to 70. °C (From Point <strong>C</strong> part way to Point <strong>D</strong>)</li> </ul> <blockquote></blockquote> <p><mathjax>#q = q_1 + q_2 + q_3 = mc_1ΔT_1 + mΔ_text(fus)H + mc_3ΔT_3#</mathjax></p> <p>where</p> <p><mathjax>#q_1, q_2,#</mathjax> and <mathjax>#q_3#</mathjax> are the heats involved in each step</p> <p><mathjax>#m#</mathjax> is the mass of the sample</p> <p><mathjax>#ΔTcolor(white)(m) = T_"f" -T_"i"#</mathjax></p> <p><mathjax>#c_1color(white)(mm) = "the specific heat capacity of ice" = "2.03 J·°C"^"-1""g"^"-1"#</mathjax></p> <p><mathjax>#c_3color(white)(mm) = "the specific heat capacity of water" = "4.179 J·°C"^"-1""g"^"-1"#</mathjax></p> <p><mathjax>#Δ_text(fus)H = "the enthalpy of fusion of ice" = 3.33 × 10^5 color(white)(l)"J·kg"^"-1"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#bbq_1#</mathjax></p> <p><mathjax>#ΔT_1 = "0 °C - (-25 °C)" = "25 °C"#</mathjax></p> <p><mathjax>#q_1 = mc_1ΔT_1 = 2.0 × 10^3 color(red)(cancel(color(black)("g"))) × 2.03 color(white)(l)"J"·color(red)(cancel(color(black)( "°C"^"-1""g"^"-1"))) × 25 color(red)(cancel(color(black)("°C"))) = 1.02 × 10^5color(white)(l) "J"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#bbq_2#</mathjax></p> <p><mathjax>#q_2 = 2.0 color(red)(cancel(color(black)("kg"))) × 3.33 × 10^5color(white)(l) "J"·color(red)(cancel(color(black)("kg"^"-1"))) = 6.66 × 10^5color(white)(l) "J"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#bbq_3#</mathjax></p> <p><mathjax>#ΔT = "70. °C - 0 °C" = "70. °C"#</mathjax></p> <p><mathjax>#q_3 = mcΔT = 2.0 × 10^3 color(red)(cancel(color(black)("g"))) × 4.179 color(white)(l)"J"·color(red)(cancel(color(black)( "°C"^"-1""g"^"-1"))) × 70. color(red)(cancel(color(black)("°C"))) = 5.85 × 10^5color(white)(l) "J"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#q = q_1 + q_2 + q_3 = (1.02 + 6.66 + 5.85) × 10^5color(white)(l) "J" = 14.0 × 10^5color(white)(l) "J"#</mathjax></p> <p><mathjax>#= 1.40 × 10^6color(white)(l) "J"#</mathjax></p> <p>The process absorbs <mathjax>#1.40 × 10^6color(white)(l) "J"#</mathjax> of heat.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/447537" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? 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Calculate the heat required to raise the temperature of 2.0 kg of ice at -25˚C to 70.˚C?

(I keep on getting a value of #4.0 * 10^5# but the answer key says, #1.4 * 10^6 J#.

a8a6d289-6ddd-11ea-88d4-ccda262736ce

https://socratic.org/questions/what-is-the-formula-of-the-compound-formed-when-ammonium-ions-nh-4-and-phosphate

(NH4)3PO4

start chemical_formula qc_end chemical_equation 11 11 qc_end chemical_equation 15 15 qc_end end

[{"type":"other","value":"Chemical Formula [OF] the compound [IN] default"}]

[{"type":"chemical equation","value":"(NH4)3PO4"}]

[{"type":"chemical equation","value":"NH4+"},{"type":"chemical equation","value":"PO4^(3-)"}]

<h1 class="questionTitle" itemprop="name">What is the formula of the compound formed when ammonium ions, #NH_4 ^+#, and phosphate ions, #PO_4^(3-)# combine?</h1>

(NH4)3PO4

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is because <mathjax>#NH_4^(+)#</mathjax> has a charge of 1+, and <mathjax>#PO_4^(3-)#</mathjax> has a charge of 3-. The compound should have a neutral charge, so it takes three <mathjax>#NH_4^+#</mathjax> to balance out <mathjax>#PO_4^(3-)#</mathjax>. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#(NH_4)_3PO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is because <mathjax>#NH_4^(+)#</mathjax> has a charge of 1+, and <mathjax>#PO_4^(3-)#</mathjax> has a charge of 3-. The compound should have a neutral charge, so it takes three <mathjax>#NH_4^+#</mathjax> to balance out <mathjax>#PO_4^(3-)#</mathjax>. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the formula of the compound formed when ammonium ions, #NH_4 ^+#, and phosphate ions, #PO_4^(3-)# combine?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/covalent-compounds" itemprop="url"> <span class="breadcrumb" itemprop="title">Covalent compounds</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="383347" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/kevin-l-7"><img alt="" class="" src="https://lh4.googleusercontent.com/-CG4wcoEOi6I/AAAAAAAAAAI/AAAAAAAAAS0/fMUL1SpRP9Q/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/kevin-l-7"> Kevin L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-02-26T16:27:10" itemprop="dateCreated"> Feb 26, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#(NH_4)_3PO_4#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This is because <mathjax>#NH_4^(+)#</mathjax> has a charge of 1+, and <mathjax>#PO_4^(3-)#</mathjax> has a charge of 3-. The compound should have a neutral charge, so it takes three <mathjax>#NH_4^+#</mathjax> to balance out <mathjax>#PO_4^(3-)#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/383347" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534baa5402bf34123fdc4f8c"> Question #c4f8c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-covalent-compound"> What is a covalent compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-covalent-compounds-1"> What are some examples of covalent compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-covalent-compound-practice-problem"> What is an example of a covalent compound practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-calcium-sulfate-an-ionic-or-covalent-compound"> Is calcium sulfate an ionic or covalent compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-can-covalent-compounds-conduct-electricity"> Why can covalent compounds conduct electricity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-covalent-compounds-differ-from-ionic-compounds"> How do covalent compounds differ from ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-covalent-compounds-follow-the-octet-rule"> Why do covalent compounds follow the octet rule? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-covalent-compound-is-co"> What covalent compound is CO? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-covalent-compound-is-n2s"> What covalent compound is N2S? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/covalent-compounds"> See all questions in Covalent compounds </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 23445 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the formula of the compound formed when ammonium ions, #NH_4 ^+#, and phosphate ions, #PO_4^(3-)# combine?

ac894f13-6ddd-11ea-918c-ccda262736ce

https://socratic.org/questions/5906c120b72cff522389b12c

3 Ca^2+ + 2 PO4^3- -> Ca3(PO4)2(s)

start chemical_equation qc_end substance 2 3 qc_end substance 5 6 qc_end substance 9 9 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"3 Ca^2+ + 2 PO4^3- -> Ca3(PO4)2(s)"}]

[{"type":"substance name","value":"Calcium ion"},{"type":"substance name","value":"Phosphate ion"},{"type":"substance name","value":"Water"}]

<h1 class="questionTitle" itemprop="name">How do calcium ion and phosphate ion react in water?</h1>

3 Ca^2+ + 2 PO4^3- -> Ca3(PO4)2(s)

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Phosphates are usually as soluble as a brick, and all except the alkali metal salts come a crashing out of solution. In fact, the phosphate species in aqueous solution is probably, <mathjax>#HPO_4^(2-)#</mathjax>, <mathjax>#"biphosphate"#</mathjax>, and the precipitate is thus possibly <mathjax>#CaHPO_4(s)#</mathjax>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3Ca^(2+) + 2PO_4^(3-) rarr Ca_3(PO_4)_2(s)darr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Phosphates are usually as soluble as a brick, and all except the alkali metal salts come a crashing out of solution. In fact, the phosphate species in aqueous solution is probably, <mathjax>#HPO_4^(2-)#</mathjax>, <mathjax>#"biphosphate"#</mathjax>, and the precipitate is thus possibly <mathjax>#CaHPO_4(s)#</mathjax>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do calcium ion and phosphate ion react in water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="415605" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-01T05:07:12" itemprop="dateCreated"> May 1, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3Ca^(2+) + 2PO_4^(3-) rarr Ca_3(PO_4)_2(s)darr#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Phosphates are usually as soluble as a brick, and all except the alkali metal salts come a crashing out of solution. In fact, the phosphate species in aqueous solution is probably, <mathjax>#HPO_4^(2-)#</mathjax>, <mathjax>#"biphosphate"#</mathjax>, and the precipitate is thus possibly <mathjax>#CaHPO_4(s)#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/415605" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-equation-for-photosynthesis"> What is the chemical equation for photosynthesis? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-grams-of-each-substance-used-or-produced-w"> How can I know the relative number of grams of each substance used or produced with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-relative-number-of-moles-of-each-substance-with-chemical-equa"> How can I know the relative number of moles of each substance with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-chemical-equations-illustrate-that-atoms-are-conserved-1"> How do chemical equations illustrate that atoms are conserved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-know-the-formula-of-the-reactants-and-products-with-chemical-equations"> How can I know the formula of the reactants and products with chemical equations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-potassium-metal-and-chlorine-gas-combi"> How can I balance this chemical equations? 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How do calcium ion and phosphate ion react in water?

ab168c00-6ddd-11ea-a89a-ccda262736ce

https://socratic.org/questions/599c35a87c01495b806fba3e

90

start physical_unit 6 7 equilibrium_constant_k none qc_end chemical_equation 8 13 qc_end end

[{"type":"physical unit","value":"Equilibrium constant [OF] the reaction"}]

[{"type":"physical unit","value":"90"}]

[{"type":"chemical equation","value":"2 CH2Cl2(g) <=> CH4(g) + CCl4(g)"},{"type":"physical unit","value":"[CH2Cl2] [OF] solution [=] \\pu{0.021 M}"},{"type":"physical unit","value":"[CH4] [OF] solution [=] \\pu{0.2 M}"},{"type":"physical unit","value":"[CCl4] [OF] solution [=] \\pu{0.2 M}"}]

<h1 class="questionTitle" itemprop="name">What is the equilibrium constant for the reaction #2"CH"_ 2"Cl" _ (2(g)) rightleftharpoons "CH"_ (4(g)) + "CCl"_ (4(g))# ?</h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Given that, at equilibrium, the vessel contains: </p> <p><mathjax>#["CH"_2"Cl"_2] = "0.021 M"#</mathjax><br/> <mathjax>#["CH"_4] = "0.2 M"#</mathjax><br/> <mathjax>#["CCl"_4] = "0.2 M"#</mathjax></p></div> </h2> </div> </div>

90

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The equilibrium reaction given to you looks like this</p> <blockquote> <p><mathjax>#2"CH"_ 2"Cl" _ (2(g)) rightleftharpoons "CH"_ (4(g)) + "CCl"_ (4(g))#</mathjax></p> </blockquote> <p>Now, the equilibrium constant takes into account the <em>equilibrium concentrations</em> of the products and of the reactants <strong>and</strong> the stoichiometric coefficients that correspond to them. </p> <p>More specifically, the equilibrium constant is calculated by <strong>dividing</strong> the product of the equilibrium concentrations of the <strong>products</strong> raised to the power of their respective stoichiometric coefficients by the product of the equilibrium concentrations of the <strong>reactants</strong> raised to the power of their respective stoichiometric coefficients. </p> <p>In this case, you have</p> <blockquote> <ul> <li><mathjax>#"CH"_4 -&gt; "no coefficient = coefficient of 1"#</mathjax></li> <li><mathjax>#"CCl"_4 -&gt; "no coefficient = coefficient of 1"#</mathjax></li> <li><mathjax>#"CH"_2"Cl"_2 -&gt; "coefficient of 2"#</mathjax></li> </ul> </blockquote> <p>The equilibrium constant will take the form </p> <blockquote> <p><mathjax>#K_c = (["CH"_4]^1 * ["CCl"_4]^1)/(["CH"_2"Cl"_2]^2)#</mathjax></p> </blockquote> <p>which is equivalent to</p> <blockquote> <p><mathjax>#K_c= (["CH"_4] * ["CCl"_4])/(["CH"_2"Cl"_2]^2)#</mathjax></p> </blockquote> <p>To find the actual value of the equilibrium constant at the given temperature, plug in the values you have for the equilibrium concentrations of the three chemical species</p> <blockquote> <p><mathjax>#K_c = (0.2 color(red)(cancel(color(black)("M"))) * 0.2 color(red)(cancel(color(black)("M"))))/(0.021^2 color(red)(cancel(color(black)("M"^2)))) = 90#</mathjax></p> </blockquote> <p>The answer is rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_c = 90#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The equilibrium reaction given to you looks like this</p> <blockquote> <p><mathjax>#2"CH"_ 2"Cl" _ (2(g)) rightleftharpoons "CH"_ (4(g)) + "CCl"_ (4(g))#</mathjax></p> </blockquote> <p>Now, the equilibrium constant takes into account the <em>equilibrium concentrations</em> of the products and of the reactants <strong>and</strong> the stoichiometric coefficients that correspond to them. </p> <p>More specifically, the equilibrium constant is calculated by <strong>dividing</strong> the product of the equilibrium concentrations of the <strong>products</strong> raised to the power of their respective stoichiometric coefficients by the product of the equilibrium concentrations of the <strong>reactants</strong> raised to the power of their respective stoichiometric coefficients. </p> <p>In this case, you have</p> <blockquote> <ul> <li><mathjax>#"CH"_4 -&gt; "no coefficient = coefficient of 1"#</mathjax></li> <li><mathjax>#"CCl"_4 -&gt; "no coefficient = coefficient of 1"#</mathjax></li> <li><mathjax>#"CH"_2"Cl"_2 -&gt; "coefficient of 2"#</mathjax></li> </ul> </blockquote> <p>The equilibrium constant will take the form </p> <blockquote> <p><mathjax>#K_c = (["CH"_4]^1 * ["CCl"_4]^1)/(["CH"_2"Cl"_2]^2)#</mathjax></p> </blockquote> <p>which is equivalent to</p> <blockquote> <p><mathjax>#K_c= (["CH"_4] * ["CCl"_4])/(["CH"_2"Cl"_2]^2)#</mathjax></p> </blockquote> <p>To find the actual value of the equilibrium constant at the given temperature, plug in the values you have for the equilibrium concentrations of the three chemical species</p> <blockquote> <p><mathjax>#K_c = (0.2 color(red)(cancel(color(black)("M"))) * 0.2 color(red)(cancel(color(black)("M"))))/(0.021^2 color(red)(cancel(color(black)("M"^2)))) = 90#</mathjax></p> </blockquote> <p>The answer is rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the equilibrium constant for the reaction #2"CH"_ 2"Cl" _ (2(g)) rightleftharpoons "CH"_ (4(g)) + "CCl"_ (4(g))# ?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>Given that, at equilibrium, the vessel contains: </p> <p><mathjax>#["CH"_2"Cl"_2] = "0.021 M"#</mathjax><br/> <mathjax>#["CH"_4] = "0.2 M"#</mathjax><br/> <mathjax>#["CCl"_4] = "0.2 M"#</mathjax></p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-equilibrium" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Equilibrium</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-equilibrium/equilibrium-constants" itemprop="url"> <span class="breadcrumb" itemprop="title">Equilibrium Constants</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="466861" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-22T14:36:04" itemprop="dateCreated"> Aug 22, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#K_c = 90#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The equilibrium reaction given to you looks like this</p> <blockquote> <p><mathjax>#2"CH"_ 2"Cl" _ (2(g)) rightleftharpoons "CH"_ (4(g)) + "CCl"_ (4(g))#</mathjax></p> </blockquote> <p>Now, the equilibrium constant takes into account the <em>equilibrium concentrations</em> of the products and of the reactants <strong>and</strong> the stoichiometric coefficients that correspond to them. </p> <p>More specifically, the equilibrium constant is calculated by <strong>dividing</strong> the product of the equilibrium concentrations of the <strong>products</strong> raised to the power of their respective stoichiometric coefficients by the product of the equilibrium concentrations of the <strong>reactants</strong> raised to the power of their respective stoichiometric coefficients. </p> <p>In this case, you have</p> <blockquote> <ul> <li><mathjax>#"CH"_4 -&gt; "no coefficient = coefficient of 1"#</mathjax></li> <li><mathjax>#"CCl"_4 -&gt; "no coefficient = coefficient of 1"#</mathjax></li> <li><mathjax>#"CH"_2"Cl"_2 -&gt; "coefficient of 2"#</mathjax></li> </ul> </blockquote> <p>The equilibrium constant will take the form </p> <blockquote> <p><mathjax>#K_c = (["CH"_4]^1 * ["CCl"_4]^1)/(["CH"_2"Cl"_2]^2)#</mathjax></p> </blockquote> <p>which is equivalent to</p> <blockquote> <p><mathjax>#K_c= (["CH"_4] * ["CCl"_4])/(["CH"_2"Cl"_2]^2)#</mathjax></p> </blockquote> <p>To find the actual value of the equilibrium constant at the given temperature, plug in the values you have for the equilibrium concentrations of the three chemical species</p> <blockquote> <p><mathjax>#K_c = (0.2 color(red)(cancel(color(black)("M"))) * 0.2 color(red)(cancel(color(black)("M"))))/(0.021^2 color(red)(cancel(color(black)("M"^2)))) = 90#</mathjax></p> </blockquote> <p>The answer is rounded to one <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figure</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/466861" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-equilibrium-constant-change-with-temperature"> How does the equilibrium constant change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-equilibrium-constant-for-a-reverse-reaction"> How do you find equilibrium constant for a reversable reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/532a4f1602bf347ef7da90d2"> Question #a90d2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-equilibrium-constant-for-the-reaction-of-nh3-with-water"> What is the equilibrium constant for the reaction of NH3 with water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-equation-for-finding-the-equilibrium-constant-for-a-chemical-reactio"> What is the equation for finding the equilibrium constant for a chemical reaction? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-equilibrium-constant-for-the-weak-acid-khp"> What is the equilibrium constant for the weak acid KHP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/consider-this-equilibrium-i2-s-h2o-l-h-aq-i-aq-hoi-aq-what-is-the-keq-expression"> Consider this equilibrium: I2(s) + H2O(l) ⇌ H+(aq) + I-(aq) + HOI(aq). 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What is the equilibrium constant for the reaction #2"CH"_ 2"Cl" _ (2(g)) rightleftharpoons "CH"_ (4(g)) + "CCl"_ (4(g))# ?

Given that, at equilibrium, the vessel contains: #["CH"_2"Cl"_2] = "0.021 M"# #["CH"_4] = "0.2 M"# #["CCl"_4] = "0.2 M"#

ab3c96ed-6ddd-11ea-8b4f-ccda262736ce

https://socratic.org/questions/how-many-moles-of-solute-are-contained-in-200-milliliters-of-a-1-m-solution

0.20 moles

start physical_unit 4 4 mole mol qc_end physical_unit 14 14 8 9 volume qc_end physical_unit 14 14 12 13 molarity qc_end end

[{"type":"physical unit","value":"Mole [OF] solute [IN] moles"}]

[{"type":"physical unit","value":"0.20 moles"}]

[{"type":"physical unit","value":"Volume [OF] solution [=] \\pu{200 milliliters}"},{"type":"physical unit","value":"Molarity [OF] solution [=] \\pu{1 M}"}]

<h1 class="questionTitle" itemprop="name">How many moles of solute are contained in 200 milliliters of a 1 M solution?</h1>

0.20 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute"/"Volume of solution"#</mathjax>.</p> <p>Typically, we perform the calculation: <mathjax>#C=n/V#</mathjax>, where <mathjax>#n#</mathjax> is the amount of solute in moles, <mathjax>#V#</mathjax> the volume of the solution in <mathjax>#"litres"#</mathjax>, and <mathjax>#C#</mathjax>, the concentration in <mathjax>#mol*L^-1#</mathjax>.</p> <p>Given <mathjax>#C=n/V#</mathjax>, then <mathjax>#n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#CxxV#</mathjax>.</p> <p>Here, <mathjax>#n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#200xx10^-3*Lxx1*mol*L^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.200*mol#</mathjax>. This calculation is consistent dimensionally, as when <mathjax>#L#</mathjax> cancel, we get an answer in <mathjax>#mol#</mathjax>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Such a volume contains <mathjax>#0.200#</mathjax> <mathjax>#mol#</mathjax> of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute"/"Volume of solution"#</mathjax>.</p> <p>Typically, we perform the calculation: <mathjax>#C=n/V#</mathjax>, where <mathjax>#n#</mathjax> is the amount of solute in moles, <mathjax>#V#</mathjax> the volume of the solution in <mathjax>#"litres"#</mathjax>, and <mathjax>#C#</mathjax>, the concentration in <mathjax>#mol*L^-1#</mathjax>.</p> <p>Given <mathjax>#C=n/V#</mathjax>, then <mathjax>#n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#CxxV#</mathjax>.</p> <p>Here, <mathjax>#n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#200xx10^-3*Lxx1*mol*L^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.200*mol#</mathjax>. This calculation is consistent dimensionally, as when <mathjax>#L#</mathjax> cancel, we get an answer in <mathjax>#mol#</mathjax>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles of solute are contained in 200 milliliters of a 1 M solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="271044" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-29T17:15:12" itemprop="dateCreated"> May 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Such a volume contains <mathjax>#0.200#</mathjax> <mathjax>#mol#</mathjax> of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute"/"Volume of solution"#</mathjax>.</p> <p>Typically, we perform the calculation: <mathjax>#C=n/V#</mathjax>, where <mathjax>#n#</mathjax> is the amount of solute in moles, <mathjax>#V#</mathjax> the volume of the solution in <mathjax>#"litres"#</mathjax>, and <mathjax>#C#</mathjax>, the concentration in <mathjax>#mol*L^-1#</mathjax>.</p> <p>Given <mathjax>#C=n/V#</mathjax>, then <mathjax>#n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#CxxV#</mathjax>.</p> <p>Here, <mathjax>#n#</mathjax> <mathjax>#=#</mathjax> <mathjax>#200xx10^-3*Lxx1*mol*L^-1#</mathjax> <mathjax>#=#</mathjax> <mathjax>#0.200*mol#</mathjax>. This calculation is consistent dimensionally, as when <mathjax>#L#</mathjax> cancel, we get an answer in <mathjax>#mol#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/271044" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 19181 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many moles of solute are contained in 200 milliliters of a 1 M solution?

ab64f058-6ddd-11ea-90aa-ccda262736ce

https://socratic.org/questions/56edba7f11ef6b5cfb709278

+2

start physical_unit 2 3 oxidation_number none qc_end chemical_equation 10 10 qc_end end

[{"type":"physical unit","value":"Oxidation number [OF] the metal"}]

[{"type":"physical unit","value":"+2"}]

[{"type":"chemical equation","value":"[Zn(OH)4]^2-"}]

<h1 class="questionTitle" itemprop="name">What is the metal oxidation number in the complex ion, #[Zn(OH)_4]^(2-)#?</h1>

+2

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>How do we know this? Well, look at its formation reaction:</p> <p><mathjax>#Zn^(2+) + 4HO^(-) rarr [Zn(OH)_4]^(2-)#</mathjax></p> <p>Charge and mass are conserved, as in every chemical equation. The <mathjax>#[Zn(OH)_4]^(2-)#</mathjax> species is a complex ion, for which there are many examples. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Zn(OH)_4^(2-)#</mathjax> is a complex ion in which the oxidation number of <mathjax>#Zn#</mathjax> is <mathjax>#+II#</mathjax>. <a href="http://socratic.org/chemistry/electrochemistry/oxidation-numbers">Oxidation numbers</a> of hydrogen (<mathjax>#+I#</mathjax>) and oxygen (<mathjax>#-II#</mathjax>) are standard.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>How do we know this? Well, look at its formation reaction:</p> <p><mathjax>#Zn^(2+) + 4HO^(-) rarr [Zn(OH)_4]^(2-)#</mathjax></p> <p>Charge and mass are conserved, as in every chemical equation. The <mathjax>#[Zn(OH)_4]^(2-)#</mathjax> species is a complex ion, for which there are many examples. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the metal oxidation number in the complex ion, #[Zn(OH)_4]^(2-)#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/oxidation-numbers" itemprop="url"> <span class="breadcrumb" itemprop="title">Oxidation Numbers</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="242138" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-19T21:52:30" itemprop="dateCreated"> Mar 19, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Zn(OH)_4^(2-)#</mathjax> is a complex ion in which the oxidation number of <mathjax>#Zn#</mathjax> is <mathjax>#+II#</mathjax>. <a href="http://socratic.org/chemistry/electrochemistry/oxidation-numbers">Oxidation numbers</a> of hydrogen (<mathjax>#+I#</mathjax>) and oxygen (<mathjax>#-II#</mathjax>) are standard.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>How do we know this? Well, look at its formation reaction:</p> <p><mathjax>#Zn^(2+) + 4HO^(-) rarr [Zn(OH)_4]^(2-)#</mathjax></p> <p>Charge and mass are conserved, as in every chemical equation. The <mathjax>#[Zn(OH)_4]^(2-)#</mathjax> species is a complex ion, for which there are many examples. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/242138" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="242148" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/scooke"><img alt="" class="" src="https://profilepictures.socratic.org/ezAzqDkjRS6NXBmMH3lg_BioPic2010a.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/scooke"> SCooke </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-19T22:42:07" itemprop="dateCreated"> Mar 19, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Starting with the common grouping of a hydroxyl (OH) as <mathjax>#O^(-2), H^(+1)#</mathjax> for a <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/net-charge">net charge</a> of -1. That gives a total of -4 charge for the four OH groups. If the whole molecule has a charge of -2, the Zn must be <mathjax>#Zn^(+2)#</mathjax>. Checking <a href="http://socratic.org/chemistry/the-periodic-table/the-periodic-table">the Periodic Table</a>, this is a highly likely oxidation state (giving up its 4s electrons).</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/242148" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-electron-configuration"> How do oxidation numbers relate to electron configuration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-relate-to-valence-electrons"> How do oxidation numbers relate to valence electrons? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-oxidation-numbers-vary-with-the-periodic-table"> How do oxidation numbers vary with the periodic table? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-oxidation-number-of-an-element-in-a-compound"> How do you calculate the oxidation number of an element in a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-sulfur"> What is the oxidation number for sulfur? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-carbon"> What is the oxidation number for carbon? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-copper"> What is the oxidation number for copper? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-nitrogen"> What is the oxidation number for nitrogen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-for-oxygen"> What is the oxidation number for oxygen? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-state-of-noble-gas-zero"> Why is the oxidation state of noble gas zero? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/electrochemistry/oxidation-numbers"> See all questions in Oxidation Numbers </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 13992 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the metal oxidation number in the complex ion, #[Zn(OH)_4]^(2-)#?

a9338f30-6ddd-11ea-88b1-ccda262736ce

https://socratic.org/questions/q-i-how-many-moles-of-sulphur-will-be-produced-when-2-moles-of-h2s-reacts-with-1

0.19 moles

start physical_unit 4 4 mole mol qc_end physical_unit 12 12 9 10 mole qc_end physical_unit 18 18 15 16 volume qc_end c_other NTP qc_end end

[{"type":"physical unit","value":"Mole [OF] sulphur [IN] moles"}]

[{"type":"physical unit","value":"0.19 moles"}]

[{"type":"physical unit","value":"Mole [OF] H2S [=] \\pu{2 moles}"},{"type":"physical unit","value":"Volume [OF] SO2 [=] \\pu{11.2 L}"},{"type":"other","value":"NTP"}]

<h1 class="questionTitle" itemprop="name">Q.)(i) How many moles of sulphur will be produced when 2 moles of H2S reacts with 11.2L of SO2at NTP?</h1>

0.19 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The sulfide in <mathjax>#"hydrogen sulfide"#</mathjax> is OXIDIZED <mathjax>#(i)#</mathjax> to elemental sulfur, and the <mathjax>#"sulfur dioxide"#</mathjax> is REDUCED to elemental sulfur......<mathjax>#(ii)#</mathjax></p> <p><mathjax>#S^(2-) rarrS +2e^(-)#</mathjax> <mathjax>#(i)#</mathjax></p> <p><mathjax>#SO_2 +4H^(+) + 4e^(-) rarrS+2H_2O#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>Both mass and charge are balanced in each reaction, as indeed they must be if we purport to represent chemical reality.....and so we simply add <mathjax>#2xx(i) + (ii)#</mathjax> to eliminate the electrons to give........</p> <p><mathjax>#2S^(2-) + SO_2 +4H^(+) + cancel(4e^(-)) rarr3S+2H_2O+cancel(4e^(-))#</mathjax> </p> <p>And we could simplify further to give.......</p> <p><mathjax>#2H_2S + SO_2 rarr3S+2H_2O#</mathjax></p> <p>And now (finally) we can address your question. <mathjax>#"NTP"#</mathjax> specifies a molar volume of <mathjax>#24.06*L*mol^-1#</mathjax>......</p> <p>With respect to <mathjax>#SO_2#</mathjax> we have a molar quantity of <mathjax>#(11.2*L)/(24.06*L*mol^-1)=0.466*mol....#</mathjax>. And thus <mathjax>#SO_2#</mathjax> is the <a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a> and <mathjax>#"hydrogen sulfide"#</mathjax> is in excess. </p> <p>And so we gets <mathjax>#3 xx#</mathjax> an equivalent quantity of <mathjax>#S#</mathjax>, i.e. <mathjax>#(3 * S)/(1 * SO_2) xx 0.466*molsxx32.06*g*mol^-1=44.8*g#</mathjax>. </p> <p>And even if you did this reaction carefully in a well-ventilated hood, it would still stink, and the upstairs chemists would come down to give you a beatdown......</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I think you refer to the so-called <mathjax>#"comproportionation reaction"#</mathjax>....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The sulfide in <mathjax>#"hydrogen sulfide"#</mathjax> is OXIDIZED <mathjax>#(i)#</mathjax> to elemental sulfur, and the <mathjax>#"sulfur dioxide"#</mathjax> is REDUCED to elemental sulfur......<mathjax>#(ii)#</mathjax></p> <p><mathjax>#S^(2-) rarrS +2e^(-)#</mathjax> <mathjax>#(i)#</mathjax></p> <p><mathjax>#SO_2 +4H^(+) + 4e^(-) rarrS+2H_2O#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>Both mass and charge are balanced in each reaction, as indeed they must be if we purport to represent chemical reality.....and so we simply add <mathjax>#2xx(i) + (ii)#</mathjax> to eliminate the electrons to give........</p> <p><mathjax>#2S^(2-) + SO_2 +4H^(+) + cancel(4e^(-)) rarr3S+2H_2O+cancel(4e^(-))#</mathjax> </p> <p>And we could simplify further to give.......</p> <p><mathjax>#2H_2S + SO_2 rarr3S+2H_2O#</mathjax></p> <p>And now (finally) we can address your question. <mathjax>#"NTP"#</mathjax> specifies a molar volume of <mathjax>#24.06*L*mol^-1#</mathjax>......</p> <p>With respect to <mathjax>#SO_2#</mathjax> we have a molar quantity of <mathjax>#(11.2*L)/(24.06*L*mol^-1)=0.466*mol....#</mathjax>. And thus <mathjax>#SO_2#</mathjax> is the <a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a> and <mathjax>#"hydrogen sulfide"#</mathjax> is in excess. </p> <p>And so we gets <mathjax>#3 xx#</mathjax> an equivalent quantity of <mathjax>#S#</mathjax>, i.e. <mathjax>#(3 * S)/(1 * SO_2) xx 0.466*molsxx32.06*g*mol^-1=44.8*g#</mathjax>. </p> <p>And even if you did this reaction carefully in a well-ventilated hood, it would still stink, and the upstairs chemists would come down to give you a beatdown......</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">Q.)(i) How many moles of sulphur will be produced when 2 moles of H2S reacts with 11.2L of SO2at NTP?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="449349" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> <a class="secondContributorPic" href="/users/truong-son-n"><img alt="" class="" src="https://profilepictures.socratic.org/07k4plnQfmnmzMuesQzw_14844-1449381920.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a>·<a class="topContributorLink" href="/users/truong-son-n"> Truong-Son N. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-08T16:50:27" itemprop="dateCreated"> Jul 8, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I think you refer to the so-called <mathjax>#"comproportionation reaction"#</mathjax>....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The sulfide in <mathjax>#"hydrogen sulfide"#</mathjax> is OXIDIZED <mathjax>#(i)#</mathjax> to elemental sulfur, and the <mathjax>#"sulfur dioxide"#</mathjax> is REDUCED to elemental sulfur......<mathjax>#(ii)#</mathjax></p> <p><mathjax>#S^(2-) rarrS +2e^(-)#</mathjax> <mathjax>#(i)#</mathjax></p> <p><mathjax>#SO_2 +4H^(+) + 4e^(-) rarrS+2H_2O#</mathjax> <mathjax>#(ii)#</mathjax></p> <p>Both mass and charge are balanced in each reaction, as indeed they must be if we purport to represent chemical reality.....and so we simply add <mathjax>#2xx(i) + (ii)#</mathjax> to eliminate the electrons to give........</p> <p><mathjax>#2S^(2-) + SO_2 +4H^(+) + cancel(4e^(-)) rarr3S+2H_2O+cancel(4e^(-))#</mathjax> </p> <p>And we could simplify further to give.......</p> <p><mathjax>#2H_2S + SO_2 rarr3S+2H_2O#</mathjax></p> <p>And now (finally) we can address your question. <mathjax>#"NTP"#</mathjax> specifies a molar volume of <mathjax>#24.06*L*mol^-1#</mathjax>......</p> <p>With respect to <mathjax>#SO_2#</mathjax> we have a molar quantity of <mathjax>#(11.2*L)/(24.06*L*mol^-1)=0.466*mol....#</mathjax>. And thus <mathjax>#SO_2#</mathjax> is the <a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a> and <mathjax>#"hydrogen sulfide"#</mathjax> is in excess. </p> <p>And so we gets <mathjax>#3 xx#</mathjax> an equivalent quantity of <mathjax>#S#</mathjax>, i.e. <mathjax>#(3 * S)/(1 * SO_2) xx 0.466*molsxx32.06*g*mol^-1=44.8*g#</mathjax>. </p> <p>And even if you did this reaction carefully in a well-ventilated hood, it would still stink, and the upstairs chemists would come down to give you a beatdown......</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/449349" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="449361" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/doc048"><img alt="" class="" src="https://profilepictures.socratic.org/e4gaeUMMQESTpfte6aRu_Friendly%20Chem%20Professor.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/doc048"> Doc048 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-08T17:20:38" itemprop="dateCreated"> Jul 8, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.188 mole <mathjax>#S_8(s)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#16H_2S(g) + 8SO_2(g)#</mathjax> =&gt; <mathjax>#16H_2O(l)#</mathjax> + <mathjax>#3S_8(s)#</mathjax><em><br/> Since the form of sulfur is not specified, the above reaction is assumed.</em>*<br/> <a href="http://**https://en.intl.chemicalaid.com" rel="nofollow" target="_blank">**https://en.intl.chemicalaid.com</a>/tools/equationbalancer.php?equation=H2S+%2B+SO2+%3D+S8+%2B+H2O</p> <p>**Phases of <mathjax>#H_2S#</mathjax> &amp; <mathjax>#H_2O#</mathjax> are assumed.</p> <p>Given 2 moles <mathjax>#H_2S + 11.2L SO_2(g)#</mathjax> at STP <br/> =&gt; 2 <mathjax>#"moles"#</mathjax> <mathjax>#H_2S#</mathjax> + 0.50 mole <mathjax>#SO_2(g)#</mathjax> at STP<br/> =&gt; <a href="https://socratic.org/chemistry/stoichiometry/limiting-reagent">Limiting Reagent</a> =&gt; 0.50 mole <mathjax>#SO_2(g)#</mathjax>; 1 mole <mathjax>#H_2S#</mathjax> excess</p> <p>8 moles <mathjax>#SO_2(g)#</mathjax> =&gt; 3 moles <mathjax>#S_8(s)#</mathjax><br/> 0.50 mole <mathjax>#SO_2(g)#</mathjax> =&gt; ? moles <mathjax>#S_8(s)#</mathjax></p> <p><mathjax>#(8"mole"SO_2)/(0.50"mole"SO_2)#</mathjax> = <mathjax>#(3"mole"S_8(s))/(X)#</mathjax></p> <p><mathjax>#X = ((0.50"mole"SO_2(g))(3"mole"S_8(s)))/(8"mole"SO_2(g))#</mathjax> = <mathjax>#0.188 "mole" S_8(s)#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/449361" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -&gt; 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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Q.)(i) How many moles of sulphur will be produced when 2 moles of H2S reacts with 11.2L of SO2at NTP?

ac9a3556-6ddd-11ea-a0b6-ccda262736ce

https://socratic.org/questions/how-would-you-balance-the-following-equation-s-hno3-h2so4-no2-h2o

S + 6 HNO3 -> H2SO4 + 6 NO2 + 2 H2O

start chemical_equation qc_end chemical_equation 7 15 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"S + 6 HNO3 -> H2SO4 + 6 NO2 + 2 H2O"}]

[{"type":"chemical equation","value":"S + HNO3 -> H2SO4 + NO2 + H2O"}]

<h1 class="questionTitle" itemprop="name">How would you balance the following equation: #"S" + "HNO"_3 -&gt; "H"_2"SO"_4 + "NO"_2 + "H"_2"O"# ?</h1>

S + 6 HNO3 -> H2SO4 + 6 NO2 + 2 H2O

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the standard method for <strong>redox reactions</strong>.</p> <p>Oxidation:</p> <p>Sulfur goes from 0 oxidation state in the element to +6 in sulfuric acid, so it gives off six (moles of) electrons per (mole of) atoms:</p> <p><mathjax>#"S"^0 \rarr "S"^{"VI"}+6e^-#</mathjax></p> <p>Reduction:</p> <p>Nitrogen goes from +5 oxidation state in nitric acid to +4 in nitrogen dioxide, so it takes up one (mole of) electron(s) per (mole of) atoms:</p> <p><mathjax>#"N"^"V"+e^- \rarr "N"^{"IV"}#</mathjax></p> <p>Balancing:</p> <p>For a redox eeaction to be balanced, the electrons given up must be matched with the electrons taken up. Here, we need six moles of notrogen atoms to take up tge electrons given off by one mole of sulfur atoms:</p> <p><mathjax>#"S"^0+6"N"^"V" \rarr "S"^{"VI"}+6"N"^{"IV"}#</mathjax></p> <p>Then we put those coefficients back into the original <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a>. <mathjax>#"S"^0#</mathjax> is the elementsl sulfur, <mathjax>#"N"^"V"#</mathjax> is the nitrogen in nitric scid, etc.:</p> <p><mathjax>#"S"+6"HNO"_3 \rarr "H"_2"SO"_4+6"NO"_2+"H"_2"O"#</mathjax></p> <p>And don't forget the easy part:</p> <p>The reaction is still not balanced because the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> that were not oxidized or reduced, hydrogen and oxygen, haven't been balanced. But.by balancing electrons in the oxidation and reduction components, we now have to balance only one other element; the last element is forced to fall into place. So.we selwct hydrogen and to keep the sulfur and nitrogen balanced, we adjust the coefficient on the water. Then:</p> <p><mathjax>#"S"+6"HNO"_3 \rarr "H"_2"SO"_4+6"NO"_2+2"H"_2"O"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>By the standard method for <a href="https://socratic.org/chemistry/chemical-reactions/redox-reactions">redox reactions</a> we get:</p> <p><mathjax>#"S"+6"HNO"_3 \rarr "H"_2"SO"_4+6"NO"_2+2"H"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the standard method for <strong>redox reactions</strong>.</p> <p>Oxidation:</p> <p>Sulfur goes from 0 oxidation state in the element to +6 in sulfuric acid, so it gives off six (moles of) electrons per (mole of) atoms:</p> <p><mathjax>#"S"^0 \rarr "S"^{"VI"}+6e^-#</mathjax></p> <p>Reduction:</p> <p>Nitrogen goes from +5 oxidation state in nitric acid to +4 in nitrogen dioxide, so it takes up one (mole of) electron(s) per (mole of) atoms:</p> <p><mathjax>#"N"^"V"+e^- \rarr "N"^{"IV"}#</mathjax></p> <p>Balancing:</p> <p>For a redox eeaction to be balanced, the electrons given up must be matched with the electrons taken up. Here, we need six moles of notrogen atoms to take up tge electrons given off by one mole of sulfur atoms:</p> <p><mathjax>#"S"^0+6"N"^"V" \rarr "S"^{"VI"}+6"N"^{"IV"}#</mathjax></p> <p>Then we put those coefficients back into the original <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a>. <mathjax>#"S"^0#</mathjax> is the elementsl sulfur, <mathjax>#"N"^"V"#</mathjax> is the nitrogen in nitric scid, etc.:</p> <p><mathjax>#"S"+6"HNO"_3 \rarr "H"_2"SO"_4+6"NO"_2+"H"_2"O"#</mathjax></p> <p>And don't forget the easy part:</p> <p>The reaction is still not balanced because the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> that were not oxidized or reduced, hydrogen and oxygen, haven't been balanced. But.by balancing electrons in the oxidation and reduction components, we now have to balance only one other element; the last element is forced to fall into place. So.we selwct hydrogen and to keep the sulfur and nitrogen balanced, we adjust the coefficient on the water. Then:</p> <p><mathjax>#"S"+6"HNO"_3 \rarr "H"_2"SO"_4+6"NO"_2+2"H"_2"O"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How would you balance the following equation: #"S" + "HNO"_3 -&gt; "H"_2"SO"_4 + "NO"_2 + "H"_2"O"# ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#electrochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Electrochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/electrochemistry/balancing-redox-equations-using-the-oxidation-number-method" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Redox Equations Using the Oxidation Number Method</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="314830" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/olthe3rd"><img alt="" class="" src="https://profilepictures.socratic.org/ooIp4P3ES4imZU7Cwexy_Squirrel.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/olthe3rd"> Oscar L. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-26T23:52:37" itemprop="dateCreated"> Sep 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>By the standard method for <a href="https://socratic.org/chemistry/chemical-reactions/redox-reactions">redox reactions</a> we get:</p> <p><mathjax>#"S"+6"HNO"_3 \rarr "H"_2"SO"_4+6"NO"_2+2"H"_2"O"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the standard method for <strong>redox reactions</strong>.</p> <p>Oxidation:</p> <p>Sulfur goes from 0 oxidation state in the element to +6 in sulfuric acid, so it gives off six (moles of) electrons per (mole of) atoms:</p> <p><mathjax>#"S"^0 \rarr "S"^{"VI"}+6e^-#</mathjax></p> <p>Reduction:</p> <p>Nitrogen goes from +5 oxidation state in nitric acid to +4 in nitrogen dioxide, so it takes up one (mole of) electron(s) per (mole of) atoms:</p> <p><mathjax>#"N"^"V"+e^- \rarr "N"^{"IV"}#</mathjax></p> <p>Balancing:</p> <p>For a redox eeaction to be balanced, the electrons given up must be matched with the electrons taken up. Here, we need six moles of notrogen atoms to take up tge electrons given off by one mole of sulfur atoms:</p> <p><mathjax>#"S"^0+6"N"^"V" \rarr "S"^{"VI"}+6"N"^{"IV"}#</mathjax></p> <p>Then we put those coefficients back into the original <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">compounds</a>. <mathjax>#"S"^0#</mathjax> is the elementsl sulfur, <mathjax>#"N"^"V"#</mathjax> is the nitrogen in nitric scid, etc.:</p> <p><mathjax>#"S"+6"HNO"_3 \rarr "H"_2"SO"_4+6"NO"_2+"H"_2"O"#</mathjax></p> <p>And don't forget the easy part:</p> <p>The reaction is still not balanced because the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> that were not oxidized or reduced, hydrogen and oxygen, haven't been balanced. But.by balancing electrons in the oxidation and reduction components, we now have to balance only one other element; the last element is forced to fall into place. So.we selwct hydrogen and to keep the sulfur and nitrogen balanced, we adjust the coefficient on the water. Then:</p> <p><mathjax>#"S"+6"HNO"_3 \rarr "H"_2"SO"_4+6"NO"_2+2"H"_2"O"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/314830" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="314836" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-27T00:08:22" itemprop="dateCreated"> Sep 27, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Here's what I got. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You're dealing with a <strong><a href="https://socratic.org/chemistry/chemical-reactions/redox-reactions">redox reaction</a></strong> in which nitric acid <strong>oxidizes</strong> elemental sulfur to sulfuric acid, <mathjax>#"H"_2"SO"_4#</mathjax>, while being reduced to nitrogen dioxide, <mathjax>#"NO"_2#</mathjax>, in the process. </p> <p>Start by assigning <strong>oxidation numbers</strong> to the atoms that take place in the reaction</p> <blockquote> <p><mathjax>#stackrel(color(blue)(0))("S")_ ((s)) + stackrel(color(blue)(+1))("H") stackrel(color(blue)(+5))("N") stackrel(color(blue)(-2))("O")_ (3(aq)) -&gt; stackrel(color(blue)(+1))("H")_ 2 stackrel(color(blue)(+6))("S") stackrel(color(blue)(-2))("O")_ (4(aq)) + stackrel(color(blue)(+4))("N") stackrel(color(blue)(-2))("O")_ (2(g)) + stackrel(color(blue)(+1))("H")_ 2 stackrel(color(blue)(-2))("O")_ ((l))#</mathjax></p> </blockquote> <p>Notice that the oxidation state of nitrogen goes from <mathjax>#color(blue)(+5)#</mathjax> on the products' side to <mathjax>#color(blue)(+4)#</mathjax> on the reactants' side, which means that nitrogen is being <strong>reduced</strong>. </p> <p>On the other hand, the oxidation state of sulfur goes from <mathjax>#color(blue)(0)#</mathjax> on the reactants' side to <mathjax>#color(blue)(+6)#</mathjax> on the products' side, which means that sulfur is being <strong>oxidized</strong>. </p> <p>The <em>oxidation half-reaction</em> looks like this</p> <blockquote> <p><mathjax>#stackrel(color(blue)(0))("S")_ ((s)) -&gt; "H"stackrel(color(blue)(+6))("S") "O"_ (4(aq))^(-) + 6"e"^(-)#</mathjax></p> </blockquote> <p>Balance the oxygen atoms by using water molecules.</p> <blockquote> <p><mathjax>#4"H"_ 2"O"_ ((l)) + stackrel(color(blue)(0))("S")_ ((s)) -&gt; "H"stackrel(color(blue)(+6))("S") "O"_ (4(aq))^(-) + 6"e"^(-)#</mathjax></p> </blockquote> <p>To balance the hydrogen atoms, add protons, <mathjax>#"H"^(+)#</mathjax>, to the side that needs hydrogen atoms.</p> <blockquote> <p><mathjax>#4"H"_ 2"O"_ ((l)) + stackrel(color(blue)(0))("S")_ ((s)) -&gt; "H"stackrel(color(blue)(+6))("S") "O"_ (4(aq))^(-) + 6"e"^(-) + 7"H"_ ((aq))^(+)#</mathjax></p> </blockquote> <p>The <em>reduction half-reaction</em> looks like this</p> <blockquote> <p><mathjax>#stackrel(color(blue)(+5))("N")"O"_ (3(aq))^(-) + "e"^(-) -&gt; stackrel(color(blue)(+4))("N") "O"_ (2(g))#</mathjax></p> </blockquote> <p>Once again, balance the oxygen atoms by adding water molecules.</p> <blockquote> <p><mathjax>#stackrel(color(blue)(+5))("N")"O"_ (3(aq))^(-) + "e"^(-) -&gt; stackrel(color(blue)(+4))("N") "O"_ (2(g)) + "H"_ 2"O"_ ((l))#</mathjax></p> </blockquote> <p>Balance the hydrogen atoms by adding protons. </p> <blockquote> <p><mathjax>#2"H"_ ((aq))^(+) + stackrel(color(blue)(+5))("N")"O"_ (3(aq))^(-) + "e"^(-) -&gt; stackrel(color(blue)(+4))("N") "O"_ (2(g)) + "H"_ 2"O"_ ((l))#</mathjax></p> </blockquote> <p>Now, in any redox reaction ,the number of electrons lost in the <strong>oxidation half-reaction</strong> must be <strong>equal</strong> to the number of electrons gained in the <strong>reduction half-reaction</strong>. </p> <p>To balance out the number of electrons transferred, multiply the reduction half-reaction by <mathjax>#6#</mathjax>. Add the two half-reactions to get </p> <blockquote> <p><mathjax>#{(color(white)(aaaaaaa.)4"H"_ 2"O"_ ((l)) + stackrel(color(blue)(0))("S")_ ((s)) -&gt; "H"stackrel(color(blue)(+6))("S") "O"_ (4(aq))^(-) + 6"e"^(-) + 7"H"_ ((aq))^(+)), (2"H"_ ((aq))^(+) + stackrel(color(blue)(+5))("N")"O"_ (3(aq))^(-) + "e"^(-) -&gt; stackrel(color(blue)(+4))("N") "O"_ (2(g)) + "H"_ 2"O"_ ((l))" "| xx 6) :}#</mathjax><br/> <mathjax>#color(white)(aaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaaa)/color(white)(a)#</mathjax></p> <p><mathjax>#4"H"_ 2"O"_ ((l)) + "S"_ ((s)) + 12"H"_ ((aq))^(+) + 6"NO"_ (3(aq))^(-) + color(red)(cancel(color(black)(6"e"^(-)))) -&gt; "HSO"_ (4(aq))^(-) + 6"NO"_ (2(g)) + color(red)(cancel(color(black)(6"e"^(-)))) + 7"H"_ ((aq))^(+) + 6"H"_ 2"O"_ ((l))#</mathjax></p> </blockquote> <p>This will be equivalent to </p> <p><mathjax>#color(green)(bar(ul(|color(white)(a/a)color(black)("S"_ ((s)) + 6"NO"_ (3(aq))^(-) + 5"H"_ ((aq))^(+) -&gt; "HSO"_ (4(aq))^(-) + 6"NO"_ (2(g)) uarr + 2"H"_ 2"O"_ ((l)))color(white)(a/a)|)))#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/314836" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-reactions-in-basic-solution"> How do you balance redox reactions in basic solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-equations-by-oxidation-number-method"> How do you balance redox equations by oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-redox-equations-in-acidic-solutions"> How do you balance redox equations in acidic solutions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-oxidation-number-method"> What is the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-balancing-redox-equations-using-the-oxidation-number-m"> What are some examples of balancing redox equations using the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-oxidation-number-method-useful"> Why is the oxidation number method useful? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-necessary-to-break-the-equation-into-half-reactions-in-the-oxidation-numbe"> Is it necessary to break the equation into half reactions in the oxidation number method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-difference-between-the-oxidation-number-method-and-the-ion-electron-"> What is the difference between the oxidation number method and the ion-electron method? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-balance-the-equation-using-the-oxidation-states-method-mno2-al-mn-al2o3"> Can you balance the equation using the oxidation states method MnO2+Al---&gt;Mn+Al2O3? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-balance-this-redox-reaction-using-the-oxidation-number-method-fe2-aq-"> How do you balance this redox reaction using the oxidation number method? 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How would you balance the following equation: #"S" + "HNO"_3 -&gt; "H"_2"SO"_4 + "NO"_2 + "H"_2"O"# ?

a9d0f915-6ddd-11ea-a766-ccda262736ce

https://socratic.org/questions/how-many-nitrogen-molecules-are-in-2-4-moles-of-n-2

1.44 × 10^24

start physical_unit 2 3 number none qc_end physical_unit 9 9 6 7 mole qc_end end

[{"type":"physical unit","value":"Number [OF] nitrogen molecules"}]

[{"type":"physical unit","value":"1.44 × 10^24"}]

[{"type":"physical unit","value":"Mole [OF] N2 [=] \\pu{2.4 moles}"}]

<h1 class="questionTitle" itemprop="name">How many nitrogen molecules are in 2.4 moles of #N_2#?</h1>

1.44 × 10^24

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Using Avogadro's constant of 1 mole is equal to <mathjax>#6.02810^23#</mathjax>molecules, we can convert moles to molecules. </p> <p><mathjax>#2.4 mol N_2 * (6.02810^23 mlcsN_2)/(1 mol N_2)#</mathjax></p> <p><mathjax>#2.4 cancel(mol N_2) * (6.02810^23 mlcsN_2)/(1 cancel(mol N_2))#</mathjax></p> <p><mathjax>#1.44*10^24#</mathjax>molecules<mathjax>#N_2#</mathjax></p> <p>This would means that there would be </p> <p><mathjax>#2.88*10^24#</mathjax>atoms<mathjax>#N_2#</mathjax></p> <p>as there are two atoms of Nitrogen in each of the molecules. </p> <p> <iframe src="https://www.youtube.com/embed/bcWaSS8wMaI?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.44*10^24#</mathjax>molecules<mathjax>#N_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Using Avogadro's constant of 1 mole is equal to <mathjax>#6.02810^23#</mathjax>molecules, we can convert moles to molecules. </p> <p><mathjax>#2.4 mol N_2 * (6.02810^23 mlcsN_2)/(1 mol N_2)#</mathjax></p> <p><mathjax>#2.4 cancel(mol N_2) * (6.02810^23 mlcsN_2)/(1 cancel(mol N_2))#</mathjax></p> <p><mathjax>#1.44*10^24#</mathjax>molecules<mathjax>#N_2#</mathjax></p> <p>This would means that there would be </p> <p><mathjax>#2.88*10^24#</mathjax>atoms<mathjax>#N_2#</mathjax></p> <p>as there are two atoms of Nitrogen in each of the molecules. </p> <p> <iframe src="https://www.youtube.com/embed/bcWaSS8wMaI?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many nitrogen molecules are in 2.4 moles of #N_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="277312" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/brian-m"><img alt="" class="" src="https://profilepictures.socratic.org/ZCpnJDgSFKORtvaSPDeG_Lego%20Me.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/brian-m"> BRIAN M. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-14T15:43:30" itemprop="dateCreated"> Jun 14, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.44*10^24#</mathjax>molecules<mathjax>#N_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Using Avogadro's constant of 1 mole is equal to <mathjax>#6.02810^23#</mathjax>molecules, we can convert moles to molecules. </p> <p><mathjax>#2.4 mol N_2 * (6.02810^23 mlcsN_2)/(1 mol N_2)#</mathjax></p> <p><mathjax>#2.4 cancel(mol N_2) * (6.02810^23 mlcsN_2)/(1 cancel(mol N_2))#</mathjax></p> <p><mathjax>#1.44*10^24#</mathjax>molecules<mathjax>#N_2#</mathjax></p> <p>This would means that there would be </p> <p><mathjax>#2.88*10^24#</mathjax>atoms<mathjax>#N_2#</mathjax></p> <p>as there are two atoms of Nitrogen in each of the molecules. </p> <p> <iframe src="https://www.youtube.com/embed/bcWaSS8wMaI?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/277312" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? 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How many nitrogen molecules are in 2.4 moles of #N_2#?

ab666014-6ddd-11ea-b98b-ccda262736ce

https://socratic.org/questions/560648e711ef6b340e584d26

1.81 × 10^21

start physical_unit 2 3 number none qc_end physical_unit 12 13 7 8 volume qc_end physical_unit 12 13 10 11 molarity qc_end end

[{"type":"physical unit","value":"Number [OF] OH- ions"}]

[{"type":"physical unit","value":"1.81 × 10^21"}]

[{"type":"physical unit","value":"Volume [OF] Ba(OH)2 solution [=] \\pu{5.0 mL}"},{"type":"physical unit","value":"Molarity [OF] Ba(OH)2 solution [=] \\pu{0.3 M}"}]

<h1 class="questionTitle" itemprop="name">How many #sf(OH^-)# ions are present in 5.0 ml of 0.3M #sf(Ba(OH)_2)# solution ?</h1>

1.81 × 10^21

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>1 mole barium hydroxide produces 2 moles hydroxide ions:</p> <p><mathjax>#rarrBa_((aq))^(2+)+2OH_((aq))^-#</mathjax></p> <p><mathjax>#c=n/v#</mathjax></p> <p><mathjax>#n=cxxv#</mathjax></p> <p>so no. moles <mathjax>#OH^(-) = 2xx0.3xx0.005=0.003"mol"#</mathjax></p> <p>Multiplying by <mathjax>#L#</mathjax> The Avogadro Constant:</p> <p><mathjax>#=6.02xx10^(23)xx0.003=1.8xx10^(21)#</mathjax> ions.</p> <p>This ignores the small amount present from the ionisation of water.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.8xx10^21#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>1 mole barium hydroxide produces 2 moles hydroxide ions:</p> <p><mathjax>#rarrBa_((aq))^(2+)+2OH_((aq))^-#</mathjax></p> <p><mathjax>#c=n/v#</mathjax></p> <p><mathjax>#n=cxxv#</mathjax></p> <p>so no. moles <mathjax>#OH^(-) = 2xx0.3xx0.005=0.003"mol"#</mathjax></p> <p>Multiplying by <mathjax>#L#</mathjax> The Avogadro Constant:</p> <p><mathjax>#=6.02xx10^(23)xx0.003=1.8xx10^(21)#</mathjax> ions.</p> <p>This ignores the small amount present from the ionisation of water.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many #sf(OH^-)# ions are present in 5.0 ml of 0.3M #sf(Ba(OH)_2)# solution ?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="172067" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michael-2"><img alt="" class="" src="https://lh3.googleusercontent.com/-gCv6FQRhls0/AAAAAAAAAAI/AAAAAAAAAAA/AAnnY7oOJS05Ylqn3KuDSW0LfnbOk7FezQ/mo/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michael-2"> Michael </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-09-26T12:27:18" itemprop="dateCreated"> Sep 26, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#1.8xx10^21#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>1 mole barium hydroxide produces 2 moles hydroxide ions:</p> <p><mathjax>#rarrBa_((aq))^(2+)+2OH_((aq))^-#</mathjax></p> <p><mathjax>#c=n/v#</mathjax></p> <p><mathjax>#n=cxxv#</mathjax></p> <p>so no. moles <mathjax>#OH^(-) = 2xx0.3xx0.005=0.003"mol"#</mathjax></p> <p>Multiplying by <mathjax>#L#</mathjax> The Avogadro Constant:</p> <p><mathjax>#=6.02xx10^(23)xx0.003=1.8xx10^(21)#</mathjax> ions.</p> <p>This ignores the small amount present from the ionisation of water.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/172067" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1755 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many #sf(OH^-)# ions are present in 5.0 ml of 0.3M #sf(Ba(OH)_2)# solution ?

ac3a9074-6ddd-11ea-bf18-ccda262736ce

https://socratic.org/questions/what-is-the-hydrogen-ion-concentration-of-a-solution-with-ph-3-75

10^(-3.75) M

start physical_unit 3 4 concentration mol/l qc_end physical_unit 8 8 12 12 ph qc_end end

[{"type":"physical unit","value":"Concentration [OF] hydrogen ion [IN] M"}]

[{"type":"physical unit","value":"10^(-3.75) M"}]

[{"type":"physical unit","value":"pH [OF] the solution [=] \\pu{3.75}"}]

<h1 class="questionTitle" itemprop="name">What is the hydrogen ion concentration of a solution with pH = 3.75?</h1>

10^(-3.75) M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_10[H_3O^+]#</mathjax> by definition.</p> <p>So we take antilogs, <mathjax>#[H_3O^+] = 10^(-3.75)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[H_3O^+]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#10^(-3.75)*mol*L^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_10[H_3O^+]#</mathjax> by definition.</p> <p>So we take antilogs, <mathjax>#[H_3O^+] = 10^(-3.75)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the hydrogen ion concentration of a solution with pH = 3.75?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="261164" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-02T06:17:08" itemprop="dateCreated"> May 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[H_3O^+]#</mathjax> <mathjax>#=#</mathjax> <mathjax>#10^(-3.75)*mol*L^-1#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#pH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#-log_10[H_3O^+]#</mathjax> by definition.</p> <p>So we take antilogs, <mathjax>#[H_3O^+] = 10^(-3.75)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/261164" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? 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What is the hydrogen ion concentration of a solution with pH = 3.75?

a8a72a34-6ddd-11ea-8a99-ccda262736ce

https://socratic.org/questions/how-many-moles-of-s-are-in-25-g-of-s

0.78 moles

start physical_unit 4 4 mole mol qc_end physical_unit 4 4 7 8 mass qc_end end

[{"type":"physical unit","value":"Mole [OF] S [IN] moles"}]

[{"type":"physical unit","value":"0.78 moles"}]

[{"type":"physical unit","value":"Mass [OF] S [=] \\pu{25 g}"}]

<h1 class="questionTitle" itemprop="name">How many moles of #S# are in 25 g of #S#?</h1>

0.78 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>, the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of sulfur (S) is 32.065 g/mol. We can present the atomic mass in either conversion factors:</p> <p><mathjax>#("32.065 g S")/("1 mol S") or ("1 mol S")/("32.065 g S")#</mathjax></p> <p>To convert from grams to moles, we'll use the atomic mass like this so that the g of S will cancel off each other, giving moles of S:</p> <p><mathjax>#"moles of S" = "25" cancel("g S") xx ("1 mol S")/(32.065 cancel("g S")) = 0.78 " mols S"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.78 mols</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>, the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of sulfur (S) is 32.065 g/mol. We can present the atomic mass in either conversion factors:</p> <p><mathjax>#("32.065 g S")/("1 mol S") or ("1 mol S")/("32.065 g S")#</mathjax></p> <p>To convert from grams to moles, we'll use the atomic mass like this so that the g of S will cancel off each other, giving moles of S:</p> <p><mathjax>#"moles of S" = "25" cancel("g S") xx ("1 mol S")/(32.065 cancel("g S")) = 0.78 " mols S"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles of #S# are in 25 g of #S#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="644693" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/dr-k"><img alt="" class="" src="https://yt3.ggpht.com/-9hqy4z72uJU/AAAAAAAAAAI/AAAAAAAAAAA/U4oALcr4dCU/s88-c-k-no-mo-rj-c0xffffff/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/dr-k"> Dr. K. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-07-31T01:29:35" itemprop="dateCreated"> Jul 31, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>0.78 mols</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From <a href="https://socratic.org/chemistry/the-periodic-table/the-periodic-table">the periodic table</a>, the <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/atomic-mass-and-isotope-abundance">atomic mass</a> of sulfur (S) is 32.065 g/mol. We can present the atomic mass in either conversion factors:</p> <p><mathjax>#("32.065 g S")/("1 mol S") or ("1 mol S")/("32.065 g S")#</mathjax></p> <p>To convert from grams to moles, we'll use the atomic mass like this so that the g of S will cancel off each other, giving moles of S:</p> <p><mathjax>#"moles of S" = "25" cancel("g S") xx ("1 mol S")/(32.065 cancel("g S")) = 0.78 " mols S"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/644693" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 11004 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many moles of #S# are in 25 g of #S#?

aae78aa6-6ddd-11ea-964d-ccda262736ce

https://socratic.org/questions/how-many-calories-are-absorbed-by-a-pot-of-water-with-a-mass-of-500-g-in-order-t

5000 calories

start physical_unit 9 9 heat_energy cal qc_end physical_unit 9 9 14 15 mass qc_end physical_unit 9 9 23 24 temperature qc_end physical_unit 9 9 26 27 temperature qc_end end

[{"type":"physical unit","value":"Absorbed energy [OF] water [IN] calories"}]

[{"type":"physical unit","value":"5000 calories"}]

[{"type":"physical unit","value":"Mass [OF] water [=] \\pu{500 g}"},{"type":"physical unit","value":"Temperature1 [OF] water [=] \\pu{20 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] water [=] \\pu{30 ℃}"}]

<h1 class="questionTitle" itemprop="name">How many calories are absorbed by a pot of water with a mass of 500 g in order to raise the temperature from 20° C to 30° C?</h1>

5000 calories

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>I assume that the pot itself absorbs no heat.</p> <p>The formula for the heat absorbed by the water is</p> <p><mathjax>#q = mcΔt#</mathjax>, where</p> <p><mathjax>#m = "500 g"#</mathjax><br/> <mathjax>#c = 1.00color(white)(l) "cal°C"^(-1)"g"^(-1)#</mathjax><br/> <mathjax>#ΔT = T_2 –T_1 = "30 °C – 20°C" = "10 °C"#</mathjax></p> <p>∴ <mathjax>#q = mcΔT = 500 color(red)(cancel(color(black)("g"))) ×1.00color(white)(l) "cal"color(red)(cancel(color(black)("°C"^(-1)"g"^(-1)))) × 10 color(red)(cancel(color(black)("°C"))) = "5000 cal"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The water absorbs 5000 cal.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>I assume that the pot itself absorbs no heat.</p> <p>The formula for the heat absorbed by the water is</p> <p><mathjax>#q = mcΔt#</mathjax>, where</p> <p><mathjax>#m = "500 g"#</mathjax><br/> <mathjax>#c = 1.00color(white)(l) "cal°C"^(-1)"g"^(-1)#</mathjax><br/> <mathjax>#ΔT = T_2 –T_1 = "30 °C – 20°C" = "10 °C"#</mathjax></p> <p>∴ <mathjax>#q = mcΔT = 500 color(red)(cancel(color(black)("g"))) ×1.00color(white)(l) "cal"color(red)(cancel(color(black)("°C"^(-1)"g"^(-1)))) × 10 color(red)(cancel(color(black)("°C"))) = "5000 cal"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many calories are absorbed by a pot of water with a mass of 500 g in order to raise the temperature from 20° C to 30° C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="212600" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-15T02:35:14" itemprop="dateCreated"> Jan 15, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The water absorbs 5000 cal.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p>I assume that the pot itself absorbs no heat.</p> <p>The formula for the heat absorbed by the water is</p> <p><mathjax>#q = mcΔt#</mathjax>, where</p> <p><mathjax>#m = "500 g"#</mathjax><br/> <mathjax>#c = 1.00color(white)(l) "cal°C"^(-1)"g"^(-1)#</mathjax><br/> <mathjax>#ΔT = T_2 –T_1 = "30 °C – 20°C" = "10 °C"#</mathjax></p> <p>∴ <mathjax>#q = mcΔT = 500 color(red)(cancel(color(black)("g"))) ×1.00color(white)(l) "cal"color(red)(cancel(color(black)("°C"^(-1)"g"^(-1)))) × 10 color(red)(cancel(color(black)("°C"))) = "5000 cal"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/212600" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? 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How many calories are absorbed by a pot of water with a mass of 500 g in order to raise the temperature from 20° C to 30° C?

abcc2c4f-6ddd-11ea-9a10-ccda262736ce

https://socratic.org/questions/570d40a87c014941f945b1d0

3.08 × 10^(-14) M

start physical_unit 5 6 concentration mol/l qc_end physical_unit 10 11 16 17 [h3o+] qc_end physical_unit 10 11 21 22 kw qc_end end

[{"type":"physical unit","value":"Concentration [OF] hydroxide anions [IN] M"}]

[{"type":"physical unit","value":"3.08 × 10^(-14) M"}]

[{"type":"physical unit","value":"[H3O+] [OF] the aqueous solution [=] \\pu{0.325 M}"},{"type":"physical unit","value":"Kw [OF] the aqueous solution [=] \\pu{10^(-14) mol^2L^2}"}]

<h1 class="questionTitle" itemprop="name">What would the concentration of hydroxide anions be in an aqueous solution that has #["H"_3"O"^(+)] = "0.325 M"# ? Given: #K_w = 10^(-14)# #"mol"^2"L"^2#</h1>

3.08 × 10^(-14) M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At <mathjax>#25^@"C"#</mathjax> the ionic product of water is given by:</p> <p><mathjax>#K_w=[H_3O_((aq))^(+)][OH_((aq))^(-)]=10^(-14)" ""mol"^(2)."l"^(-2)#</mathjax></p> <p><mathjax>#:.[OH_((aq))^(-)]=K_w/[[H_3O_((aq))^(+)]]#</mathjax></p> <p><mathjax>#[OH_((aq))^(-)]=10^(-14)/0.325=3.08xx10^(-14)" ""mol""/""l"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.08xx10^(-14)" ""mol""/""l"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At <mathjax>#25^@"C"#</mathjax> the ionic product of water is given by:</p> <p><mathjax>#K_w=[H_3O_((aq))^(+)][OH_((aq))^(-)]=10^(-14)" ""mol"^(2)."l"^(-2)#</mathjax></p> <p><mathjax>#:.[OH_((aq))^(-)]=K_w/[[H_3O_((aq))^(+)]]#</mathjax></p> <p><mathjax>#[OH_((aq))^(-)]=10^(-14)/0.325=3.08xx10^(-14)" ""mol""/""l"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What would the concentration of hydroxide anions be in an aqueous solution that has #["H"_3"O"^(+)] = "0.325 M"# ? Given: #K_w = 10^(-14)# #"mol"^2"L"^2#</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/the-ph-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">pH</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="256918" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/michael-2"><img alt="" class="" src="https://lh3.googleusercontent.com/-gCv6FQRhls0/AAAAAAAAAAI/AAAAAAAAAAA/AAnnY7oOJS05Ylqn3KuDSW0LfnbOk7FezQ/mo/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/michael-2"> Michael </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-21T11:41:27" itemprop="dateCreated"> Apr 21, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3.08xx10^(-14)" ""mol""/""l"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>At <mathjax>#25^@"C"#</mathjax> the ionic product of water is given by:</p> <p><mathjax>#K_w=[H_3O_((aq))^(+)][OH_((aq))^(-)]=10^(-14)" ""mol"^(2)."l"^(-2)#</mathjax></p> <p><mathjax>#:.[OH_((aq))^(-)]=K_w/[[H_3O_((aq))^(+)]]#</mathjax></p> <p><mathjax>#[OH_((aq))^(-)]=10^(-14)/0.325=3.08xx10^(-14)" ""mol""/""l"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/256918" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-ph-from-pka"> How do you determine pH from pKa? 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What would the concentration of hydroxide anions be in an aqueous solution that has #["H"_3"O"^(+)] = "0.325 M"# ? Given: #K_w = 10^(-14)# #"mol"^2"L"^2#

aa175fdb-6ddd-11ea-88c7-ccda262736ce

https://socratic.org/questions/what-is-the-formula-for-mercury-ii-nitride

Hg3N2

start chemical_formula qc_end substance 5 7 qc_end end

[{"type":"other","value":"Chemical Formula [OF] mercury (II) nitride [IN] default"}]

[{"type":"chemical equation","value":"Hg3N2"}]

[{"type":"substance name","value":"Mercury (II) nitride"}]

<h1 class="questionTitle" itemprop="name">What is the formula for mercury (II) nitride? </h1>

Hg3N2

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>With <mathjax>#Hg^(2+)#</mathjax> it forms the <mathjax>#Hg_3N_2#</mathjax> salt, <mathjax>#"mercuric nitride"#</mathjax>. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Nitrogen may be reduced to the <mathjax>#"nitride anion, "N^(3-)#</mathjax>, so.....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>With <mathjax>#Hg^(2+)#</mathjax> it forms the <mathjax>#Hg_3N_2#</mathjax> salt, <mathjax>#"mercuric nitride"#</mathjax>. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the formula for mercury (II) nitride? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="315440" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-28T16:11:19" itemprop="dateCreated"> Sep 28, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Nitrogen may be reduced to the <mathjax>#"nitride anion, "N^(3-)#</mathjax>, so.....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>With <mathjax>#Hg^(2+)#</mathjax> it forms the <mathjax>#Hg_3N_2#</mathjax> salt, <mathjax>#"mercuric nitride"#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/315440" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? 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What is the formula for mercury (II) nitride?

a95701c6-6ddd-11ea-a6d8-ccda262736ce

https://socratic.org/questions/what-is-the-formula-for-nickel-ii-phosphate

Ni3(PO4)2

start chemical_formula qc_end substance 5 7 qc_end end

[{"type":"other","value":"Chemical Formula [OF] nickel (II) phosphate [IN] default"}]

[{"type":"chemical equation","value":"Ni3(PO4)2"}]

[{"type":"substance name","value":"Nickel (II) phosphate"}]

<h1 class="questionTitle" itemprop="name">What is the formula for nickel (II) phosphate?</h1>

Ni3(PO4)2

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From aqueous solution, we are more likely to isolate...</p> <p><mathjax>#Ni(HPO_4)(s)#</mathjax>...i.e. <mathjax>#"nickel biphosphate…."#</mathjax> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, <mathjax>#Ni_3(PO_4)_2#</mathjax>....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From aqueous solution, we are more likely to isolate...</p> <p><mathjax>#Ni(HPO_4)(s)#</mathjax>...i.e. <mathjax>#"nickel biphosphate…."#</mathjax> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the formula for nickel (II) phosphate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/review-of-elements-and-compounds" itemprop="url"> <span class="breadcrumb" itemprop="title">Review of Elements and Compounds</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="622374" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-05-30T08:44:54" itemprop="dateCreated"> May 30, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Well, <mathjax>#Ni_3(PO_4)_2#</mathjax>....</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From aqueous solution, we are more likely to isolate...</p> <p><mathjax>#Ni(HPO_4)(s)#</mathjax>...i.e. <mathjax>#"nickel biphosphate…."#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/622374" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d6f5cb02bf347f12bf13ae"> Question #f13ae </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d6f5f602bf347f105bb7b1"> Question #bb7b1 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d6f5fc02bf347f13478896"> Question #78896 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d6f60102bf347f076fd74b"> Question #fd74b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d6f60a02bf347f12bf13b2"> Question #f13b2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-find-the-molar-mass-of-an-element"> How do I find the molar mass of an element? 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What is the formula for nickel (II) phosphate?

a90e035c-6ddd-11ea-84b4-ccda262736ce

https://socratic.org/questions/the-pressure-acting-on-60-cubic-meters-of-gas-is-raised-from-236-kpa-to-354-kpa-

40 cubic meters

start physical_unit 26 27 volume m^3 qc_end physical_unit 26 27 4 6 volume qc_end physical_unit 26 27 12 13 pressure qc_end physical_unit 26 27 15 16 pressure qc_end c_other constant_temperature qc_end end

[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] cubic meters"}]

[{"type":"physical unit","value":"40 cubic meters"}]

[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{60 cubic meters}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{236 kPa}"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{354 kPa}"},{"type":"other","value":"ConstantTemperature"}]

<h1 class="questionTitle" itemprop="name">The pressure acting on 60 cubic meters of gas is raised from 236 kPa to 354 kPa. The temperature is kept constant. What new volume does the gas occupy?</h1>

40 cubic meters

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="http://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a> states that the volume of an enclosed gas is inversely proportional tot he pressure exerted on it, provided the temperature remains constant.</p> <p><mathjax>#therefore P_1V_1=P_2V_2#</mathjax></p> <p><mathjax>#therefore V_2=(P_1V_1)/P_2#</mathjax></p> <p><mathjax>#=(236xx60)/354#</mathjax></p> <p><mathjax>#=40m^3#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#40m^3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="http://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a> states that the volume of an enclosed gas is inversely proportional tot he pressure exerted on it, provided the temperature remains constant.</p> <p><mathjax>#therefore P_1V_1=P_2V_2#</mathjax></p> <p><mathjax>#therefore V_2=(P_1V_1)/P_2#</mathjax></p> <p><mathjax>#=(236xx60)/354#</mathjax></p> <p><mathjax>#=40m^3#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">The pressure acting on 60 cubic meters of gas is raised from 236 kPa to 354 kPa. The temperature is kept constant. What new volume does the gas occupy?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="222066" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/trevor-r-1"><img alt="" class="" src="https://profilepictures.socratic.org/2Wf9lLD9RaSzPbXY0EW8_S5002678.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/trevor-r-1"> Trevor Ryan. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-05T22:10:36" itemprop="dateCreated"> Feb 5, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#40m^3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><a href="http://socratic.org/chemistry/the-behavior-of-gases/boyle-s-law">Boyle's Law</a> states that the volume of an enclosed gas is inversely proportional tot he pressure exerted on it, provided the temperature remains constant.</p> <p><mathjax>#therefore P_1V_1=P_2V_2#</mathjax></p> <p><mathjax>#therefore V_2=(P_1V_1)/P_2#</mathjax></p> <p><mathjax>#=(236xx60)/354#</mathjax></p> <p><mathjax>#=40m^3#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/222066" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyles-law-relate-to-breathing"> How does Boyle's law relate to breathing? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/in-avogadro-s-law-what-would-happen-to-v-if-n-is-increased-decreased-and-what-wo"> In Avogadro's Law what would happen to V if N is increased/decreased? 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The pressure acting on 60 cubic meters of gas is raised from 236 kPa to 354 kPa. The temperature is kept constant. What new volume does the gas occupy?

ac5e3ce4-6ddd-11ea-9f38-ccda262736ce

https://socratic.org/questions/if-1-35-g-of-aluminum-is-mixed-with-6-0-moles-of-copper-ii-chloride-what-mass-of

4.77 g

start physical_unit 11 11 mass g qc_end physical_unit 4 4 1 2 mass qc_end physical_unit 11 13 8 9 mole qc_end end

[{"type":"physical unit","value":"Mass [OF] copper [IN] g"}]

[{"type":"physical unit","value":"4.77 g"}]

[{"type":"physical unit","value":"Mass [OF] aluminum [=] \\pu{1.35 g}"},{"type":"physical unit","value":"Mole [OF] copper (II) chloride [=] \\pu{6.0 moles}"}]

<h1 class="questionTitle" itemprop="name">If 1.35 g of aluminum is mixed with 6.0 moles of copper (II) chloride, what mass of copper would be produced?</h1>

4.77 g

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start with a balanced equation.</p> <p><mathjax>#"2Al + 3CuCl"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"2AlCl"_3 + "3Cu"#</mathjax></p> <p>Convert <mathjax>#"1.35 g Al"#</mathjax> to moles by dividing by its molar mass, <mathjax>#"26.982 g/mol"#</mathjax>. Since molar mass is a fraction, <strong>g/mol</strong>, you can divide by multiplying the given mass by the inverse of the molar mass, <strong>mol/g</strong> .</p> <p><mathjax>#1.35color(red)cancel(color(black)("g Al"))xx(1"mol Al")/(26.982color(red)cancel(color(black)("g Al")))="0.0500 mol Al"#</mathjax></p> <p>You need to determine the limiting reactant (or limiting reagent). You need to determine which element or compound produces the least amount of <mathjax>#"Cu"#</mathjax>.</p> <p>The process involves multiplying the mol <mathjax>#"Al"#</mathjax> and <mathjax>#"CuCl"_2"#</mathjax> by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between each of them and <mathjax>#"Cu"#</mathjax>, and then multiply by the molar mass of <mathjax>#"Cu"#</mathjax>, <mathjax>#"63.546 g/mol"#</mathjax>.</p> <p>Possible Mass of Cu from Al</p> <p><mathjax>#0.0500color(red)cancel(color(black)("mol Al"))xx(3color(red)cancel(color(black)("mol Cu")))/(2color(red)cancel(color(black)("mol Al")))xx(53.546"Cu")/(1color(red)cancel(color(black)("mol Cu")))="4.77 g Cu"#</mathjax></p> <p>Possible Mass of Cu from <mathjax>#"CuCl"_2#</mathjax></p> <p><mathjax>#6.0color(red)cancel(color(black)("g CuCl"_2))xx(3color(red)cancel(color(black)("mol Cu")))/(3color(red)cancel(color(black)("mol CuCl"_2)))xx(63.546"g Cu")/(1color(red)cancel(color(black)("mol Cu")))="380 g Cu"#</mathjax></p> <p>Under the conditions given, Al is the limiting reactant because it will produce only <mathjax>#"4.77 g Cu"#</mathjax>, whereas, if there were enough Al present, the <mathjax>#"CuCl"_2"#</mathjax> would produce <mathjax>#"380 g Cu"#</mathjax>. However, under the conditions given, the Al would run out before the reaction could produce <mathjax>#"380 g Cu"#</mathjax>. The <mathjax>#"CuCl"_2#</mathjax> is the reactant in excess.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Since aluminum is the limiting reactant, so the reaction will produce <mathjax>#"4.77 g Cu"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start with a balanced equation.</p> <p><mathjax>#"2Al + 3CuCl"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"2AlCl"_3 + "3Cu"#</mathjax></p> <p>Convert <mathjax>#"1.35 g Al"#</mathjax> to moles by dividing by its molar mass, <mathjax>#"26.982 g/mol"#</mathjax>. Since molar mass is a fraction, <strong>g/mol</strong>, you can divide by multiplying the given mass by the inverse of the molar mass, <strong>mol/g</strong> .</p> <p><mathjax>#1.35color(red)cancel(color(black)("g Al"))xx(1"mol Al")/(26.982color(red)cancel(color(black)("g Al")))="0.0500 mol Al"#</mathjax></p> <p>You need to determine the limiting reactant (or limiting reagent). You need to determine which element or compound produces the least amount of <mathjax>#"Cu"#</mathjax>.</p> <p>The process involves multiplying the mol <mathjax>#"Al"#</mathjax> and <mathjax>#"CuCl"_2"#</mathjax> by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between each of them and <mathjax>#"Cu"#</mathjax>, and then multiply by the molar mass of <mathjax>#"Cu"#</mathjax>, <mathjax>#"63.546 g/mol"#</mathjax>.</p> <p>Possible Mass of Cu from Al</p> <p><mathjax>#0.0500color(red)cancel(color(black)("mol Al"))xx(3color(red)cancel(color(black)("mol Cu")))/(2color(red)cancel(color(black)("mol Al")))xx(53.546"Cu")/(1color(red)cancel(color(black)("mol Cu")))="4.77 g Cu"#</mathjax></p> <p>Possible Mass of Cu from <mathjax>#"CuCl"_2#</mathjax></p> <p><mathjax>#6.0color(red)cancel(color(black)("g CuCl"_2))xx(3color(red)cancel(color(black)("mol Cu")))/(3color(red)cancel(color(black)("mol CuCl"_2)))xx(63.546"g Cu")/(1color(red)cancel(color(black)("mol Cu")))="380 g Cu"#</mathjax></p> <p>Under the conditions given, Al is the limiting reactant because it will produce only <mathjax>#"4.77 g Cu"#</mathjax>, whereas, if there were enough Al present, the <mathjax>#"CuCl"_2"#</mathjax> would produce <mathjax>#"380 g Cu"#</mathjax>. However, under the conditions given, the Al would run out before the reaction could produce <mathjax>#"380 g Cu"#</mathjax>. The <mathjax>#"CuCl"_2#</mathjax> is the reactant in excess.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If 1.35 g of aluminum is mixed with 6.0 moles of copper (II) chloride, what mass of copper would be produced?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="466663" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-08-22T01:07:32" itemprop="dateCreated"> Aug 22, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Since aluminum is the limiting reactant, so the reaction will produce <mathjax>#"4.77 g Cu"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start with a balanced equation.</p> <p><mathjax>#"2Al + 3CuCl"_2#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"2AlCl"_3 + "3Cu"#</mathjax></p> <p>Convert <mathjax>#"1.35 g Al"#</mathjax> to moles by dividing by its molar mass, <mathjax>#"26.982 g/mol"#</mathjax>. Since molar mass is a fraction, <strong>g/mol</strong>, you can divide by multiplying the given mass by the inverse of the molar mass, <strong>mol/g</strong> .</p> <p><mathjax>#1.35color(red)cancel(color(black)("g Al"))xx(1"mol Al")/(26.982color(red)cancel(color(black)("g Al")))="0.0500 mol Al"#</mathjax></p> <p>You need to determine the limiting reactant (or limiting reagent). You need to determine which element or compound produces the least amount of <mathjax>#"Cu"#</mathjax>.</p> <p>The process involves multiplying the mol <mathjax>#"Al"#</mathjax> and <mathjax>#"CuCl"_2"#</mathjax> by <a href="https://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio between each of them and <mathjax>#"Cu"#</mathjax>, and then multiply by the molar mass of <mathjax>#"Cu"#</mathjax>, <mathjax>#"63.546 g/mol"#</mathjax>.</p> <p>Possible Mass of Cu from Al</p> <p><mathjax>#0.0500color(red)cancel(color(black)("mol Al"))xx(3color(red)cancel(color(black)("mol Cu")))/(2color(red)cancel(color(black)("mol Al")))xx(53.546"Cu")/(1color(red)cancel(color(black)("mol Cu")))="4.77 g Cu"#</mathjax></p> <p>Possible Mass of Cu from <mathjax>#"CuCl"_2#</mathjax></p> <p><mathjax>#6.0color(red)cancel(color(black)("g CuCl"_2))xx(3color(red)cancel(color(black)("mol Cu")))/(3color(red)cancel(color(black)("mol CuCl"_2)))xx(63.546"g Cu")/(1color(red)cancel(color(black)("mol Cu")))="380 g Cu"#</mathjax></p> <p>Under the conditions given, Al is the limiting reactant because it will produce only <mathjax>#"4.77 g Cu"#</mathjax>, whereas, if there were enough Al present, the <mathjax>#"CuCl"_2"#</mathjax> would produce <mathjax>#"380 g Cu"#</mathjax>. However, under the conditions given, the Al would run out before the reaction could produce <mathjax>#"380 g Cu"#</mathjax>. The <mathjax>#"CuCl"_2#</mathjax> is the reactant in excess.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/466663" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-solve-the-problems-of-stiohiomerty-what-is-the-formula-of-stiohiomerty"> How do you solve a stoichiometry problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-stiohiomerty"> What is stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/535ab82402bf342f48d93ac6"> Question #93ac6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-we-study-stoichiometry"> Why do we study stoichiometry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-naoh-is-produced-from-1-20-x-102-grams-of-na2o-na2o-h2o-2-naoh"> How many grams of NaOH is produced from #1.20 x 10^2# grams of #Na_2O#? #Na_2O + H_2O -&gt; 2NaOH# </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-many-grams-of-na2o-are-required-to-produce-1-60-x-102-grams-of-naoh-na2o-h2o"> How many grams of Na2O are required to produce 1.60 x 102 grams of NaOH? 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If 1.35 g of aluminum is mixed with 6.0 moles of copper (II) chloride, what mass of copper would be produced?

ac9615e6-6ddd-11ea-862d-ccda262736ce

https://socratic.org/questions/how-would-you-balance-na-h2o-naoh-h2

2 Na + 2 H2O -> 2 NaOH + H2

start chemical_equation qc_end chemical_equation 4 10 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"2 Na + 2 H2O -> 2 NaOH + H2"}]

[{"type":"chemical equation","value":"Na + H2O -> NaOH + H2"}]

<h1 class="questionTitle" itemprop="name">How would you balance: Na + H2O --&gt; NaOH + H2? </h1>

2 Na + 2 H2O -> 2 NaOH + H2

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have to count the number of atoms in both sides of the reaction to be equal, to make it a little easier you can make a list. So in the equation <mathjax>#Na+H_2O-&gt;NaOH+H_2#</mathjax>, there are<br/> <mathjax>#1-Na-1#</mathjax><br/> <mathjax>#2-H-3#</mathjax><br/> <mathjax>#1-O-1#</mathjax><br/> So you multiply NaOH and H2O by 2, so you have 4 hydrogens in both sides, and then multiply Na by 2 to be equal to the NaOH you previously multiplied.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2Na + 2H_2O -&gt; 2NaOH +H_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have to count the number of atoms in both sides of the reaction to be equal, to make it a little easier you can make a list. So in the equation <mathjax>#Na+H_2O-&gt;NaOH+H_2#</mathjax>, there are<br/> <mathjax>#1-Na-1#</mathjax><br/> <mathjax>#2-H-3#</mathjax><br/> <mathjax>#1-O-1#</mathjax><br/> So you multiply NaOH and H2O by 2, so you have 4 hydrogens in both sides, and then multiply Na by 2 to be equal to the NaOH you previously multiplied.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How would you balance: Na + H2O --&gt; NaOH + H2? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="189452" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/apgt512"><img alt="" class="" src="https://profilepictures.socratic.org/1uF0g9QgSOuzxlhNBGXs_Laser.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/apgt512"> Apgt512 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-16T19:37:11" itemprop="dateCreated"> Nov 16, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2Na + 2H_2O -&gt; 2NaOH +H_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You have to count the number of atoms in both sides of the reaction to be equal, to make it a little easier you can make a list. So in the equation <mathjax>#Na+H_2O-&gt;NaOH+H_2#</mathjax>, there are<br/> <mathjax>#1-Na-1#</mathjax><br/> <mathjax>#2-H-3#</mathjax><br/> <mathjax>#1-O-1#</mathjax><br/> So you multiply NaOH and H2O by 2, so you have 4 hydrogens in both sides, and then multiply Na by 2 to be equal to the NaOH you previously multiplied.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/189452" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="335018" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-11-12T01:57:29" itemprop="dateCreated"> Nov 12, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2"Na"_ ((s)) + 2"H"_ 2"O"_ ((l)) -&gt; 2"NaOH"_ ((aq)) + "H"_ (2(g))#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>I'm assuming that you're supposed to balance this chemical equation <em>by inspection</em>. You could also balance it by using <a href="https://socratic.org/chemistry/electrochemistry/oxidation-numbers">oxidation numbers</a>, but I don't think that you're supposed to go that route here. </p> <p>So, your unbalanced chemical equation looks like this</p> <blockquote> <p><mathjax>#"Na"_ ((s)) + "H"_ 2"O"_ ((l)) -&gt; "NaOH"_ ((aq)) + "H"_ (2(g))#</mathjax></p> </blockquote> <p>Notice that you have <mathjax>#3#</mathjax> atoms of hydrogen on the products' side, but only <mathjax>#2#</mathjax> on the reactants' side. </p> <p>Here is where a little experience can come in handy. You can multiply the sodium hydroxide by <mathjax>#2#</mathjax> to get a total of <mathjax>#4#</mathjax> atoms of hydrogen on the products' side. </p> <p>This will allow you to simply double the number of water molecules to get <mathjax>#4#</mathjax> atoms of hydrogen on the reactants' side.</p> <p>So you now have</p> <blockquote> <p><mathjax>#"Na"_ ((s)) + color(blue)(2)"H"_ 2"O"_ ((l)) -&gt; color(blue)(2)"NaOH"_ ((aq)) + "H"_ (2(g))#</mathjax></p> </blockquote> <p>Balance the atoms of sodium by multiplying sodium metal by <mathjax>#2#</mathjax></p> <blockquote> <p><mathjax>#2"Na"_ ((s)) + color(blue)(2)"H"_ 2"O"_ ((l)) -&gt; color(blue)(2)"NaOH"_ ((aq)) + "H"_ (2(g))#</mathjax></p> </blockquote> <p>And now check to see if the atoms of oxygen are balanced. You have <mathjax>#2#</mathjax> atoms of hydrogen on the reactants' side and <mathjax>#2#</mathjax> on the products' side, which means that the equation is <strong>balanced</strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/335018" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------&gt; H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -&gt; Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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How would you balance: Na + H2O --&gt; NaOH + H2?

a8c2ec58-6ddd-11ea-b559-ccda262736ce

https://socratic.org/questions/how-do-i-find-the-percentage-composition-of-chlorine-in-cocl-2

54.61%

start physical_unit 8 10 percent_composition none qc_end chemical_equation 10 10 qc_end end

[{"type":"physical unit","value":"Percentage composition [OF] Chlorine in COCl2"}]

[{"type":"physical unit","value":"54.61%"}]

[{"type":"chemical equation","value":"COCl2"}]

<h1 class="questionTitle" itemprop="name">How do I find the percentage composition of Chlorine in #CoCl_2#?</h1>

54.61%

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First determine the molar mass of cobalt chloride <mathjax>#("CoCl"_2")#</mathjax> and the mass of chlorine in the compound. Divide the mass of chlorine by the molar mass of cobalt chloride, then multiply by 100.</p> <p><strong>Molar Mass of Cobalt Chloride</strong></p> <p><mathjax>#"CoCl"_2":#</mathjax><mathjax>#overbrace((1xx58.933195 "g/mol"))^color(blue)"cobalt"+overbrace((2xx35.453 "g/mol"))^color(red)"chlorine"=overbrace"129.839 g/mol"^color(purple)"cobalt chloride"#</mathjax></p> <p><strong>Mass of Chlorine in Cobalt Chloride</strong></p> <p><mathjax>#"Cl"_2":#</mathjax><mathjax>#(2xx35.453 "g/mol")="70.906 g/mol"#</mathjax></p> <p><strong>Percent Composition of Chlorine</strong></p> <p><mathjax>#%"Composition of Cl"=(70.906 cancel"g/mol")/(129.839 cancel"g/mol")xx100="54.611% #</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of chlorine in <mathjax>#"CoCl"_2"#</mathjax> is <mathjax>#54.611%#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First determine the molar mass of cobalt chloride <mathjax>#("CoCl"_2")#</mathjax> and the mass of chlorine in the compound. Divide the mass of chlorine by the molar mass of cobalt chloride, then multiply by 100.</p> <p><strong>Molar Mass of Cobalt Chloride</strong></p> <p><mathjax>#"CoCl"_2":#</mathjax><mathjax>#overbrace((1xx58.933195 "g/mol"))^color(blue)"cobalt"+overbrace((2xx35.453 "g/mol"))^color(red)"chlorine"=overbrace"129.839 g/mol"^color(purple)"cobalt chloride"#</mathjax></p> <p><strong>Mass of Chlorine in Cobalt Chloride</strong></p> <p><mathjax>#"Cl"_2":#</mathjax><mathjax>#(2xx35.453 "g/mol")="70.906 g/mol"#</mathjax></p> <p><strong>Percent Composition of Chlorine</strong></p> <p><mathjax>#%"Composition of Cl"=(70.906 cancel"g/mol")/(129.839 cancel"g/mol")xx100="54.611% #</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do I find the percentage composition of Chlorine in #CoCl_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/percent-composition" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Composition</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="240371" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-16T09:12:48" itemprop="dateCreated"> Mar 16, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The <a href="http://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of chlorine in <mathjax>#"CoCl"_2"#</mathjax> is <mathjax>#54.611%#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First determine the molar mass of cobalt chloride <mathjax>#("CoCl"_2")#</mathjax> and the mass of chlorine in the compound. Divide the mass of chlorine by the molar mass of cobalt chloride, then multiply by 100.</p> <p><strong>Molar Mass of Cobalt Chloride</strong></p> <p><mathjax>#"CoCl"_2":#</mathjax><mathjax>#overbrace((1xx58.933195 "g/mol"))^color(blue)"cobalt"+overbrace((2xx35.453 "g/mol"))^color(red)"chlorine"=overbrace"129.839 g/mol"^color(purple)"cobalt chloride"#</mathjax></p> <p><strong>Mass of Chlorine in Cobalt Chloride</strong></p> <p><mathjax>#"Cl"_2":#</mathjax><mathjax>#(2xx35.453 "g/mol")="70.906 g/mol"#</mathjax></p> <p><strong>Percent Composition of Chlorine</strong></p> <p><mathjax>#%"Composition of Cl"=(70.906 cancel"g/mol")/(129.839 cancel"g/mol")xx100="54.611% #</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/240371" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-mole-percent"> What is mole percent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188602bf3469570e2e8b"> Question #e2e8b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4188702bf34695a6bc737"> Question #bc737 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418be02bf34695a6bc73b"> Question #bc73b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c202bf3469570e2e8f"> Question #e2e8f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418c802bf346963eb9857"> Question #b9857 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418ca02bf346963eb985b"> Question #b985b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418cc02bf34694a4fee41"> Question #fee41 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d418d502bf34694c8c5c01"> Question #c5c01 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4196e02bf34695a6bc73f"> Question #bc73f </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/percent-composition"> See all questions in Percent Composition </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 10868 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How do I find the percentage composition of Chlorine in #CoCl_2#?

a997c766-6ddd-11ea-a85f-ccda262736ce

https://socratic.org/questions/a-sample-of-argon-gas-occupies-a-volume-of-950-ml-at-25-c-what-volume-will-the-g

1029.70 mL

start physical_unit 1 4 volume ml qc_end physical_unit 1 4 9 10 volume qc_end physical_unit 1 4 12 13 temperature qc_end physical_unit 1 4 21 22 temperature qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Volume2 [OF] argon gas sample [IN] mL"}]

[{"type":"physical unit","value":"1029.70 mL"}]

[{"type":"physical unit","value":"Volume1 [OF] argon gas sample [=] \\pu{950 mL}"},{"type":"physical unit","value":"Temperature1 [OF] argon gas sample [=] \\pu{25 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] argon gas sample [=] \\pu{50 ℃}"},{"type":"other","value":"The pressure remains constant."}]

<h1 class="questionTitle" itemprop="name">A sample of argon gas occupies a volume of 950 mL at 25°C. What volume will the gas occupy at 50°C if the pressure remains constant?</h1>

1029.70 mL

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Considering the gas as ideal we can use:<br/> <mathjax>#PV=nRT#</mathjax><br/> Where:<br/> <mathjax>#P=#</mathjax> pressure;<br/> <mathjax>#V=#</mathjax> volume;<br/> <mathjax>#n=#</mathjax> number of moles;<br/> <mathjax>#R=#</mathjax> universal gas constant;<br/> <mathjax>#T=#</mathjax> temperature.<br/> So pasically our gas undergo a transformation from equilibrium state 1 to equilibrium state 2 where we have:<br/> from:<br/> <mathjax>#P_1V_1=nRT_1#</mathjax><br/> to:<br/> <mathjax>#P_2V_2=nRT_2#</mathjax></p> <p>But <mathjax>#n#</mathjax> and <mathjax>#P#</mathjax> remain unchanged so we have that:<br/> <mathjax>#(V_1)/T_1=nR/(P_1)#</mathjax><br/> <mathjax>#(V_2)/T_2=nR/(P_1)#</mathjax><br/> and so:<br/> <mathjax>#(V_1)/T_1=(V_2)/T_2#</mathjax></p> <p>But:<br/> <mathjax>#T_1=273+25=298K#</mathjax><br/> <mathjax>#T_2=273+50=323K#</mathjax><br/> and:<br/> <mathjax>#V_2=(950*323)/298=1029.7ml#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I fond: <mathjax>#1029.7ml#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Considering the gas as ideal we can use:<br/> <mathjax>#PV=nRT#</mathjax><br/> Where:<br/> <mathjax>#P=#</mathjax> pressure;<br/> <mathjax>#V=#</mathjax> volume;<br/> <mathjax>#n=#</mathjax> number of moles;<br/> <mathjax>#R=#</mathjax> universal gas constant;<br/> <mathjax>#T=#</mathjax> temperature.<br/> So pasically our gas undergo a transformation from equilibrium state 1 to equilibrium state 2 where we have:<br/> from:<br/> <mathjax>#P_1V_1=nRT_1#</mathjax><br/> to:<br/> <mathjax>#P_2V_2=nRT_2#</mathjax></p> <p>But <mathjax>#n#</mathjax> and <mathjax>#P#</mathjax> remain unchanged so we have that:<br/> <mathjax>#(V_1)/T_1=nR/(P_1)#</mathjax><br/> <mathjax>#(V_2)/T_2=nR/(P_1)#</mathjax><br/> and so:<br/> <mathjax>#(V_1)/T_1=(V_2)/T_2#</mathjax></p> <p>But:<br/> <mathjax>#T_1=273+25=298K#</mathjax><br/> <mathjax>#T_2=273+50=323K#</mathjax><br/> and:<br/> <mathjax>#V_2=(950*323)/298=1029.7ml#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A sample of argon gas occupies a volume of 950 mL at 25°C. What volume will the gas occupy at 50°C if the pressure remains constant?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/charles-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Charles' Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="225791" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/gio"><img alt="" class="" src="https://profilepictures.socratic.org/PDAQ7XlwRXWLdTy9hfbV_kuruma.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/gio"> Gió </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-13T18:46:13" itemprop="dateCreated"> Feb 13, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I fond: <mathjax>#1029.7ml#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Considering the gas as ideal we can use:<br/> <mathjax>#PV=nRT#</mathjax><br/> Where:<br/> <mathjax>#P=#</mathjax> pressure;<br/> <mathjax>#V=#</mathjax> volume;<br/> <mathjax>#n=#</mathjax> number of moles;<br/> <mathjax>#R=#</mathjax> universal gas constant;<br/> <mathjax>#T=#</mathjax> temperature.<br/> So pasically our gas undergo a transformation from equilibrium state 1 to equilibrium state 2 where we have:<br/> from:<br/> <mathjax>#P_1V_1=nRT_1#</mathjax><br/> to:<br/> <mathjax>#P_2V_2=nRT_2#</mathjax></p> <p>But <mathjax>#n#</mathjax> and <mathjax>#P#</mathjax> remain unchanged so we have that:<br/> <mathjax>#(V_1)/T_1=nR/(P_1)#</mathjax><br/> <mathjax>#(V_2)/T_2=nR/(P_1)#</mathjax><br/> and so:<br/> <mathjax>#(V_1)/T_1=(V_2)/T_2#</mathjax></p> <p>But:<br/> <mathjax>#T_1=273+25=298K#</mathjax><br/> <mathjax>#T_2=273+50=323K#</mathjax><br/> and:<br/> <mathjax>#V_2=(950*323)/298=1029.7ml#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/225791" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-must-charles-law-be-in-kelvins"> Why must Charles' law be in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-charles-law-formula"> What is Charles' law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/oxygen-gas-is-at-a-temperature-of-40-c-when-it-occupies-a-volume-of-2-3-liters-t"> Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.3 liters. 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A sample of argon gas occupies a volume of 950 mL at 25°C. What volume will the gas occupy at 50°C if the pressure remains constant?

a9a65846-6ddd-11ea-b771-ccda262736ce

https://socratic.org/questions/what-is-the-molarity-of-a-sample-of-phosphoric-acid-if-15-00-ml-of-2-m-koh-was-r

1.25 M

start physical_unit 6 9 molarity mol/l qc_end physical_unit 25 26 21 22 volume qc_end physical_unit 16 16 14 15 molarity qc_end end

[{"type":"physical unit","value":"Molarity [OF] phosphoric acid sample [IN] M"}]

[{"type":"physical unit","value":"1.25 M"}]

[{"type":"physical unit","value":"Volume [OF] H3PO4 sample [=] \\pu{12 ml}"},{"type":"physical unit","value":"Volume [OF] KOH solution [=] \\pu{15.00 ml}"},{"type":"physical unit","value":"Molarity [OF] KOH solution [=] \\pu{2 M}"}]

<h1 class="questionTitle" itemprop="name">What is the molarity of a sample of phosphoric acid if 15.00 ml of 2 M #KOH# was required to titrate 12 ml of the #H_3PO_4# sample? </h1>

1.25 M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This one is not so straightforward, and requires specialist knowledge.</p> <p>It is a fact that phosphoric acid is a DIACID in aqueous solution, and reaches a stoichiometric endpoint at <mathjax>#HPO_4^(2-)#</mathjax>:</p> <p><mathjax>#H_3PO_4(aq) +2KOH(aq) rarr K_2HPO_4(aq) + 2H_2O#</mathjax>.</p> <p>And thus moles of <mathjax>#KOH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#15.00xx10^-3*Lxx2.0*mol*L^-1#</mathjax> <mathjax>#=0.030*mol#</mathjax>.</p> <p>And thus the equivalent quantity of <mathjax>#H_3PO_4#</mathjax> was <mathjax>#0.015*mol#</mathjax> which were present in a <mathjax>#12*mL#</mathjax> volume of the acid........</p> <p><mathjax>#=((0.030*mol)/2)/(12xx10^-3*L)=1.25*mol*L^-1#</mathjax>.</p> <p>Remember what I said with regard to the acid-base behaviour of phosphoric acid. It is NOT a triacid..........and you might win brownie points from your prof if you know this fact. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[H_3PO_4]=1.25*mol*L^-1#</mathjax></p> <p>Of course, there is a catch.............</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This one is not so straightforward, and requires specialist knowledge.</p> <p>It is a fact that phosphoric acid is a DIACID in aqueous solution, and reaches a stoichiometric endpoint at <mathjax>#HPO_4^(2-)#</mathjax>:</p> <p><mathjax>#H_3PO_4(aq) +2KOH(aq) rarr K_2HPO_4(aq) + 2H_2O#</mathjax>.</p> <p>And thus moles of <mathjax>#KOH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#15.00xx10^-3*Lxx2.0*mol*L^-1#</mathjax> <mathjax>#=0.030*mol#</mathjax>.</p> <p>And thus the equivalent quantity of <mathjax>#H_3PO_4#</mathjax> was <mathjax>#0.015*mol#</mathjax> which were present in a <mathjax>#12*mL#</mathjax> volume of the acid........</p> <p><mathjax>#=((0.030*mol)/2)/(12xx10^-3*L)=1.25*mol*L^-1#</mathjax>.</p> <p>Remember what I said with regard to the acid-base behaviour of phosphoric acid. It is NOT a triacid..........and you might win brownie points from your prof if you know this fact. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the molarity of a sample of phosphoric acid if 15.00 ml of 2 M #KOH# was required to titrate 12 ml of the #H_3PO_4# sample? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="436701" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-08T18:27:18" itemprop="dateCreated"> Jun 8, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#[H_3PO_4]=1.25*mol*L^-1#</mathjax></p> <p>Of course, there is a catch.............</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>This one is not so straightforward, and requires specialist knowledge.</p> <p>It is a fact that phosphoric acid is a DIACID in aqueous solution, and reaches a stoichiometric endpoint at <mathjax>#HPO_4^(2-)#</mathjax>:</p> <p><mathjax>#H_3PO_4(aq) +2KOH(aq) rarr K_2HPO_4(aq) + 2H_2O#</mathjax>.</p> <p>And thus moles of <mathjax>#KOH#</mathjax> <mathjax>#=#</mathjax> <mathjax>#15.00xx10^-3*Lxx2.0*mol*L^-1#</mathjax> <mathjax>#=0.030*mol#</mathjax>.</p> <p>And thus the equivalent quantity of <mathjax>#H_3PO_4#</mathjax> was <mathjax>#0.015*mol#</mathjax> which were present in a <mathjax>#12*mL#</mathjax> volume of the acid........</p> <p><mathjax>#=((0.030*mol)/2)/(12xx10^-3*L)=1.25*mol*L^-1#</mathjax>.</p> <p>Remember what I said with regard to the acid-base behaviour of phosphoric acid. It is NOT a triacid..........and you might win brownie points from your prof if you know this fact. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/436701" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3570 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the molarity of a sample of phosphoric acid if 15.00 ml of 2 M #KOH# was required to titrate 12 ml of the #H_3PO_4# sample?

abd6f840-6ddd-11ea-b00a-ccda262736ce

https://socratic.org/questions/if-1-93-10-3-mol-of-argon-occupies-a-65-8-ml-container-at-20-degrees-celsius-wha

536.56 torr

start physical_unit 6 6 pressure torr qc_end physical_unit 6 6 1 4 mole qc_end physical_unit 6 6 9 10 volume qc_end physical_unit 6 6 13 15 temperature qc_end end

[{"type":"physical unit","value":"Pressure [OF] argon [IN] torr"}]

[{"type":"physical unit","value":"536.56 torr"}]

[{"type":"physical unit","value":"Mole [OF] argon [=] \\pu{1.93 × 10^(-3) mol}"},{"type":"physical unit","value":"Volume [OF] argon [=] \\pu{65.8 mL}"},{"type":"physical unit","value":"Temperature [OF] argon [=] \\pu{20 degrees Celsius}"}]

<h1 class="questionTitle" itemprop="name">If 1.93 * 10^-3 mol of argon occupies a 65.8-mL container at 20 degrees Celsius, what is the pressure (in torr)?</h1>

536.56 torr

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From the Ideal Gas equation, which you must be getting sick of.......</p> <p><mathjax>#P=(nRT)/V=(1.93xx10^-3*molxx0.0821*(L*atm)/(K*mol)xx293*K)/(65.8*mLxx10^-3*L*mL^-1)#</mathjax></p> <p><mathjax>#-=0.706*atm#</mathjax></p> <p>And here the trick is to know that <mathjax>#1000*mL-=1*L#</mathjax>, i.e. <mathjax>#1*mL-=10^-3*L#</mathjax>.</p> <p>Anyway, you know the relationship between <mathjax>#"atmospheres"#</mathjax> and <mathjax>#mm*Hg#</mathjax> so have at it.............</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P~=0.706*atm-=??"Torr"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From the Ideal Gas equation, which you must be getting sick of.......</p> <p><mathjax>#P=(nRT)/V=(1.93xx10^-3*molxx0.0821*(L*atm)/(K*mol)xx293*K)/(65.8*mLxx10^-3*L*mL^-1)#</mathjax></p> <p><mathjax>#-=0.706*atm#</mathjax></p> <p>And here the trick is to know that <mathjax>#1000*mL-=1*L#</mathjax>, i.e. <mathjax>#1*mL-=10^-3*L#</mathjax>.</p> <p>Anyway, you know the relationship between <mathjax>#"atmospheres"#</mathjax> and <mathjax>#mm*Hg#</mathjax> so have at it.............</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If 1.93 * 10^-3 mol of argon occupies a 65.8-mL container at 20 degrees Celsius, what is the pressure (in torr)?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="448481" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-07-06T05:01:47" itemprop="dateCreated"> Jul 6, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P~=0.706*atm-=??"Torr"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>From the Ideal Gas equation, which you must be getting sick of.......</p> <p><mathjax>#P=(nRT)/V=(1.93xx10^-3*molxx0.0821*(L*atm)/(K*mol)xx293*K)/(65.8*mLxx10^-3*L*mL^-1)#</mathjax></p> <p><mathjax>#-=0.706*atm#</mathjax></p> <p>And here the trick is to know that <mathjax>#1000*mL-=1*L#</mathjax>, i.e. <mathjax>#1*mL-=10^-3*L#</mathjax>.</p> <p>Anyway, you know the relationship between <mathjax>#"atmospheres"#</mathjax> and <mathjax>#mm*Hg#</mathjax> so have at it.............</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/448481" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? 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If 1.93 * 10^-3 mol of argon occupies a 65.8-mL container at 20 degrees Celsius, what is the pressure (in torr)?

a8ff8608-6ddd-11ea-bae1-ccda262736ce

https://socratic.org/questions/to-sterilize-a-50-0-g-glass-baby-battle-we-must-raise-its-temperature-from-22-c-

3066 J

start physical_unit 5 7 heat_energy j qc_end physical_unit 5 7 3 4 mass qc_end physical_unit 5 7 14 15 temperature qc_end physical_unit 5 7 17 18 temperature qc_end end

[{"type":"physical unit","value":"Required heat [OF] glass baby battle [IN] J"}]

[{"type":"physical unit","value":"3066 J"}]

[{"type":"physical unit","value":"Mass [OF] glass baby battle [=] \\pu{50.0 g}"},{"type":"physical unit","value":"Temperature1 [OF] glass baby battle [=] \\pu{22 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] glass baby battle [=] \\pu{95.0 ℃}"}]

<h1 class="questionTitle" itemprop="name">To sterilize a 50.0 g glass baby battle, we must raise its temperature from 22°C to 95.0°C. How much heat is required?</h1>

3066 J

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> equation, which states that,</p> <p><mathjax>#q=mcDeltaT#</mathjax></p> <p>where:</p> <blockquote> <ul> <li> <p><mathjax>#q#</mathjax> is the heat energy supplied in joules</p> </li> <li> <p><mathjax>#m#</mathjax> is the mass of substance</p> </li> <li> <p><mathjax>#c#</mathjax> is the specific heat capacity of the substance, which is <mathjax>#(0.84 \ "J")/("g"""^@"C")#</mathjax> for pure glass (<a href="http://www2.ucdsb.on.ca/tiss/stretton/database/specific_heat_capacity_table.html" rel="nofollow">source</a>)</p> </li> <li> <p><mathjax>#DeltaT#</mathjax> is the change in temperature</p> </li> </ul> </blockquote> <p>So, we get:</p> <p><mathjax>#q=50color(red)cancelcolor(black)"g"*(0.84 \ "J")/(color(red)cancelcolor(black)"g"color(red)cancelcolor(black)(""^@"C"))*(95^@"C"-22^@"C")#</mathjax></p> <p><mathjax>#=50color(red)cancelcolor(black)"g"*(0.84 \ "J")/(color(red)cancelcolor(black)"g"color(red)cancelcolor(black)(""^@"C"))*73color(red)cancelcolor(black)(""^@"C")#</mathjax></p> <p><mathjax>#=3066 \ "J"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3066#</mathjax> joules</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> equation, which states that,</p> <p><mathjax>#q=mcDeltaT#</mathjax></p> <p>where:</p> <blockquote> <ul> <li> <p><mathjax>#q#</mathjax> is the heat energy supplied in joules</p> </li> <li> <p><mathjax>#m#</mathjax> is the mass of substance</p> </li> <li> <p><mathjax>#c#</mathjax> is the specific heat capacity of the substance, which is <mathjax>#(0.84 \ "J")/("g"""^@"C")#</mathjax> for pure glass (<a href="http://www2.ucdsb.on.ca/tiss/stretton/database/specific_heat_capacity_table.html" rel="nofollow">source</a>)</p> </li> <li> <p><mathjax>#DeltaT#</mathjax> is the change in temperature</p> </li> </ul> </blockquote> <p>So, we get:</p> <p><mathjax>#q=50color(red)cancelcolor(black)"g"*(0.84 \ "J")/(color(red)cancelcolor(black)"g"color(red)cancelcolor(black)(""^@"C"))*(95^@"C"-22^@"C")#</mathjax></p> <p><mathjax>#=50color(red)cancelcolor(black)"g"*(0.84 \ "J")/(color(red)cancelcolor(black)"g"color(red)cancelcolor(black)(""^@"C"))*73color(red)cancelcolor(black)(""^@"C")#</mathjax></p> <p><mathjax>#=3066 \ "J"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">To sterilize a 50.0 g glass baby battle, we must raise its temperature from 22°C to 95.0°C. How much heat is required?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="630755" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nam-d"><img alt="" class="" src="https://profilepictures.socratic.org/QG4MnkoER6u99DIDVWKK_787554714770341.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nam-d"> Nam D. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-06-16T01:39:43" itemprop="dateCreated"> Jun 16, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#3066#</mathjax> joules</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>We use the <a href="https://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> equation, which states that,</p> <p><mathjax>#q=mcDeltaT#</mathjax></p> <p>where:</p> <blockquote> <ul> <li> <p><mathjax>#q#</mathjax> is the heat energy supplied in joules</p> </li> <li> <p><mathjax>#m#</mathjax> is the mass of substance</p> </li> <li> <p><mathjax>#c#</mathjax> is the specific heat capacity of the substance, which is <mathjax>#(0.84 \ "J")/("g"""^@"C")#</mathjax> for pure glass (<a href="http://www2.ucdsb.on.ca/tiss/stretton/database/specific_heat_capacity_table.html" rel="nofollow">source</a>)</p> </li> <li> <p><mathjax>#DeltaT#</mathjax> is the change in temperature</p> </li> </ul> </blockquote> <p>So, we get:</p> <p><mathjax>#q=50color(red)cancelcolor(black)"g"*(0.84 \ "J")/(color(red)cancelcolor(black)"g"color(red)cancelcolor(black)(""^@"C"))*(95^@"C"-22^@"C")#</mathjax></p> <p><mathjax>#=50color(red)cancelcolor(black)"g"*(0.84 \ "J")/(color(red)cancelcolor(black)"g"color(red)cancelcolor(black)(""^@"C"))*73color(red)cancelcolor(black)(""^@"C")#</mathjax></p> <p><mathjax>#=3066 \ "J"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/630755" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? 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To sterilize a 50.0 g glass baby battle, we must raise its temperature from 22°C to 95.0°C. How much heat is required?

a95e5e8c-6ddd-11ea-8cef-ccda262736ce

https://socratic.org/questions/the-reaction-of-iron-with-hydrochloric-acid-is-represented-by-the-following-ther

1.90 L

start physical_unit 31 31 volume l qc_end physical_unit 0 1 19 20 heat_energy qc_end c_other OTHER qc_end c_other STP qc_end chemical_equation 37 44 qc_end physical_unit 0 1 47 48 deltah qc_end physical_unit 0 1 51 56 constant_r qc_end end

[{"type":"physical unit","value":"volume [OF] H2(g) [IN] L"}]

[{"type":"physical unit","value":"1.90 L"}]

[{"type":"physical unit","value":"Released heat [OF] the reaction [=] \\pu{7.36 kJ}"},{"type":"other","value":"Constant pressure."},{"type":"other","value":"STP"},{"type":"chemical equation","value":"Fe(s) + 2 HCl(aq) -> FeCl2(aq) + H2(g)"},{"type":"physical unit","value":"deltaH [OF] the reaction [=] \\pu{-87.9 kJ}"},{"type":"physical unit","value":"R [OF] the reaction [=] \\pu{0.0821 (L * atm)/(K * mol)}"}]

<h1 class="questionTitle" itemprop="name">The reaction of iron with hydrochloric acid is represented by the following thermochemical equation. If, in a particular experiment, 7.36 kJ of heat was released at constant pressure, what volume of #H_2(g)#, measured at STP, was produced?</h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#Fe(s) + 2HCl(aq) -&gt; FeCl_2(aq) + H_2(g)#</mathjax>;<br/> <mathjax>#DeltaH = -"87.9 kJ"#</mathjax> </p> <p><mathjax>#R = 0.0821 (L * atm)/(K* mol)#</mathjax></p></div> </h2> </div> </div>

1.90 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change of reaction, <mathjax>#DeltaH#</mathjax>, to figure out the <strong>number of moles</strong> of iron, and consequently of hydrochloric acid, that took part in the reaction. </p> <p>This will then allow you to figure out how many <em>moles</em> of hydrogen gas were produced by the reaction. At that point, you can use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas</a> at STP</strong> to calculate the <em>volume</em> of the hydrogen gas. </p> <p>So, the <strong>thermochemical equation</strong> that describes this <strong><a href="https://socratic.org/chemistry/chemical-reactions/single-replacement-reactions">single replacement reaction</a></strong> looks like this </p> <blockquote> <p><mathjax>#"Fe"_ ((s)) + 2"HCl"_ ((aq)) -&gt; "FeCl"_ (2(aq)) + "H"_ (2(g)) uarr" "DeltaH = -"87.9 kJ"#</mathjax></p> </blockquote> <p>This tells you that when <mathjax>#1#</mathjax> <strong>mole</strong> of iron reacts with <mathjax>#2#</mathjax> <strong>moles</strong> of hydrochloric acid, <mathjax>#1#</mathjax> <strong>mole</strong> of hydrogen gas is produced and <mathjax>#"87.9 kJ"#</mathjax> of heat are <strong>given off</strong>, hence the <em>minus sign</em> used for the value of <mathjax>#DeltaH#</mathjax>. </p> <p>In your case, you know that <mathjax>#"7.36 kJ"#</mathjax> of heat were given off by the reaction. This should automatically tell you that the reaction consumed <strong>less than one mole</strong> of iron.</p> <p>More specifically, it consumed </p> <blockquote> <p><mathjax>#7.36 color(red)(cancel(color(black)("kJ given off"))) * "1 mole Fe"/(87.9 color(red)(cancel(color(black)("kJ given off")))) = "0.08373 moles Fe"#</mathjax></p> </blockquote> <p>You know how many moles of iron were consumed in the reaction, so use the <mathjax>#1:1#</mathjax> mole ratio that exists between iron and hydrogen gas to say that the reaction produced</p> <blockquote> <p><mathjax>#0.08373 color(red)(cancel(color(black)("moles Fe"))) * "1 mole H"_2/(1color(red)(cancel(color(black)("mole Fe")))) = "0.08373 moles H"_2#</mathjax></p> </blockquote> <p>Now, <strong>STP conditions</strong> are <em><strong>currently</strong></em> defined as a pressure of <mathjax>#"100 kPa"#</mathjax> and a temperature of <mathjax>#0^@"C"#</mathjax>. The thing to remember here is that when an ideal gas is kept under STP conditions, <strong>one mole</strong> occupies <mathjax>#"22.7 L"#</mathjax>. </p> <blockquote> <p><mathjax>#color(blue)(|bar(ul(color(white)(a/a)"1 mole" = "22.7 L"color(white)(a/a)|))) -&gt;#</mathjax> <em>the <strong>molar volume of a gas at STP</strong></em></p> </blockquote> <p>Use this as a <em>conversion factor</em> to calculate the volume occupied by <mathjax>#0.08373#</mathjax> <strong>moles</strong> of hydrogen gas kept under STP conditions</p> <blockquote> <p><mathjax>#0.08373 color(red)(cancel(color(black)("moles H"_2))) * "22.7 L"/(1color(red)(cancel(color(black)("mole H"_2)))) = color(green)(|bar(ul(color(white)(a/a)color(black)("1.90 L")color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p> <p>Notice that the problem provides you with the value of the universal gas constant, <mathjax>#R#</mathjax>. You <em>don't really need to use it</em> here because you can use the <strong>molar volume of gas at STP</strong>.</p> <p>In fact, you can prove that the molar volume of a gas at STP is <mathjax>#"22.7 L"#</mathjax> by using the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</p> <blockquote> <p><mathjax>#PV = nRT#</mathjax></p> <p><mathjax>#V/n = (RT)/P#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#V/n = (0.0821 (color(red)(cancel(color(black)("atm"))) * "L")/("mol" * color(red)(cancel(color(black)("K")))) * (273.15 + 0)color(red)(cancel(color(black)("K"))))/(100/101.325color(red)(cancel(color(black)("atm")))) = "22.7 L mol"^(-1)#</mathjax></p> </blockquote> <p>This is why <strong>one mole</strong> of an ideal gas occupies <mathjax>#"22.7 L"#</mathjax> at STP. </p> <p><strong>SIDE NOTE</strong> <em>If the molar volume of a gas at STP is given to you as</em> <mathjax>#"22.4 L"#</mathjax>, <em>which is the value that corresponds to the <strong>old definition</strong> of STP conditions, i.e. a pressure of</em> <mathjax>#"1 atm"#</mathjax> <em>and a temperature of</em> <mathjax>#0^@"C"#</mathjax>, <em>simply redo the final calculation using</em> <mathjax>#"22.4 L"#</mathjax> <em>instead of</em> <mathjax>#"22.7 L"#</mathjax>. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1.90 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change of reaction, <mathjax>#DeltaH#</mathjax>, to figure out the <strong>number of moles</strong> of iron, and consequently of hydrochloric acid, that took part in the reaction. </p> <p>This will then allow you to figure out how many <em>moles</em> of hydrogen gas were produced by the reaction. At that point, you can use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas</a> at STP</strong> to calculate the <em>volume</em> of the hydrogen gas. </p> <p>So, the <strong>thermochemical equation</strong> that describes this <strong><a href="https://socratic.org/chemistry/chemical-reactions/single-replacement-reactions">single replacement reaction</a></strong> looks like this </p> <blockquote> <p><mathjax>#"Fe"_ ((s)) + 2"HCl"_ ((aq)) -&gt; "FeCl"_ (2(aq)) + "H"_ (2(g)) uarr" "DeltaH = -"87.9 kJ"#</mathjax></p> </blockquote> <p>This tells you that when <mathjax>#1#</mathjax> <strong>mole</strong> of iron reacts with <mathjax>#2#</mathjax> <strong>moles</strong> of hydrochloric acid, <mathjax>#1#</mathjax> <strong>mole</strong> of hydrogen gas is produced and <mathjax>#"87.9 kJ"#</mathjax> of heat are <strong>given off</strong>, hence the <em>minus sign</em> used for the value of <mathjax>#DeltaH#</mathjax>. </p> <p>In your case, you know that <mathjax>#"7.36 kJ"#</mathjax> of heat were given off by the reaction. This should automatically tell you that the reaction consumed <strong>less than one mole</strong> of iron.</p> <p>More specifically, it consumed </p> <blockquote> <p><mathjax>#7.36 color(red)(cancel(color(black)("kJ given off"))) * "1 mole Fe"/(87.9 color(red)(cancel(color(black)("kJ given off")))) = "0.08373 moles Fe"#</mathjax></p> </blockquote> <p>You know how many moles of iron were consumed in the reaction, so use the <mathjax>#1:1#</mathjax> mole ratio that exists between iron and hydrogen gas to say that the reaction produced</p> <blockquote> <p><mathjax>#0.08373 color(red)(cancel(color(black)("moles Fe"))) * "1 mole H"_2/(1color(red)(cancel(color(black)("mole Fe")))) = "0.08373 moles H"_2#</mathjax></p> </blockquote> <p>Now, <strong>STP conditions</strong> are <em><strong>currently</strong></em> defined as a pressure of <mathjax>#"100 kPa"#</mathjax> and a temperature of <mathjax>#0^@"C"#</mathjax>. The thing to remember here is that when an ideal gas is kept under STP conditions, <strong>one mole</strong> occupies <mathjax>#"22.7 L"#</mathjax>. </p> <blockquote> <p><mathjax>#color(blue)(|bar(ul(color(white)(a/a)"1 mole" = "22.7 L"color(white)(a/a)|))) -&gt;#</mathjax> <em>the <strong>molar volume of a gas at STP</strong></em></p> </blockquote> <p>Use this as a <em>conversion factor</em> to calculate the volume occupied by <mathjax>#0.08373#</mathjax> <strong>moles</strong> of hydrogen gas kept under STP conditions</p> <blockquote> <p><mathjax>#0.08373 color(red)(cancel(color(black)("moles H"_2))) * "22.7 L"/(1color(red)(cancel(color(black)("mole H"_2)))) = color(green)(|bar(ul(color(white)(a/a)color(black)("1.90 L")color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p> <p>Notice that the problem provides you with the value of the universal gas constant, <mathjax>#R#</mathjax>. You <em>don't really need to use it</em> here because you can use the <strong>molar volume of gas at STP</strong>.</p> <p>In fact, you can prove that the molar volume of a gas at STP is <mathjax>#"22.7 L"#</mathjax> by using the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</p> <blockquote> <p><mathjax>#PV = nRT#</mathjax></p> <p><mathjax>#V/n = (RT)/P#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#V/n = (0.0821 (color(red)(cancel(color(black)("atm"))) * "L")/("mol" * color(red)(cancel(color(black)("K")))) * (273.15 + 0)color(red)(cancel(color(black)("K"))))/(100/101.325color(red)(cancel(color(black)("atm")))) = "22.7 L mol"^(-1)#</mathjax></p> </blockquote> <p>This is why <strong>one mole</strong> of an ideal gas occupies <mathjax>#"22.7 L"#</mathjax> at STP. </p> <p><strong>SIDE NOTE</strong> <em>If the molar volume of a gas at STP is given to you as</em> <mathjax>#"22.4 L"#</mathjax>, <em>which is the value that corresponds to the <strong>old definition</strong> of STP conditions, i.e. a pressure of</em> <mathjax>#"1 atm"#</mathjax> <em>and a temperature of</em> <mathjax>#0^@"C"#</mathjax>, <em>simply redo the final calculation using</em> <mathjax>#"22.4 L"#</mathjax> <em>instead of</em> <mathjax>#"22.7 L"#</mathjax>. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">The reaction of iron with hydrochloric acid is represented by the following thermochemical equation. If, in a particular experiment, 7.36 kJ of heat was released at constant pressure, what volume of #H_2(g)#, measured at STP, was produced?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p><mathjax>#Fe(s) + 2HCl(aq) -&gt; FeCl_2(aq) + H_2(g)#</mathjax>;<br/> <mathjax>#DeltaH = -"87.9 kJ"#</mathjax> </p> <p><mathjax>#R = 0.0821 (L * atm)/(K* mol)#</mathjax></p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="287292" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-12T01:56:16" itemprop="dateCreated"> Jul 12, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1.90 L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the <a href="https://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> change of reaction, <mathjax>#DeltaH#</mathjax>, to figure out the <strong>number of moles</strong> of iron, and consequently of hydrochloric acid, that took part in the reaction. </p> <p>This will then allow you to figure out how many <em>moles</em> of hydrogen gas were produced by the reaction. At that point, you can use the <strong><a href="https://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas</a> at STP</strong> to calculate the <em>volume</em> of the hydrogen gas. </p> <p>So, the <strong>thermochemical equation</strong> that describes this <strong><a href="https://socratic.org/chemistry/chemical-reactions/single-replacement-reactions">single replacement reaction</a></strong> looks like this </p> <blockquote> <p><mathjax>#"Fe"_ ((s)) + 2"HCl"_ ((aq)) -&gt; "FeCl"_ (2(aq)) + "H"_ (2(g)) uarr" "DeltaH = -"87.9 kJ"#</mathjax></p> </blockquote> <p>This tells you that when <mathjax>#1#</mathjax> <strong>mole</strong> of iron reacts with <mathjax>#2#</mathjax> <strong>moles</strong> of hydrochloric acid, <mathjax>#1#</mathjax> <strong>mole</strong> of hydrogen gas is produced and <mathjax>#"87.9 kJ"#</mathjax> of heat are <strong>given off</strong>, hence the <em>minus sign</em> used for the value of <mathjax>#DeltaH#</mathjax>. </p> <p>In your case, you know that <mathjax>#"7.36 kJ"#</mathjax> of heat were given off by the reaction. This should automatically tell you that the reaction consumed <strong>less than one mole</strong> of iron.</p> <p>More specifically, it consumed </p> <blockquote> <p><mathjax>#7.36 color(red)(cancel(color(black)("kJ given off"))) * "1 mole Fe"/(87.9 color(red)(cancel(color(black)("kJ given off")))) = "0.08373 moles Fe"#</mathjax></p> </blockquote> <p>You know how many moles of iron were consumed in the reaction, so use the <mathjax>#1:1#</mathjax> mole ratio that exists between iron and hydrogen gas to say that the reaction produced</p> <blockquote> <p><mathjax>#0.08373 color(red)(cancel(color(black)("moles Fe"))) * "1 mole H"_2/(1color(red)(cancel(color(black)("mole Fe")))) = "0.08373 moles H"_2#</mathjax></p> </blockquote> <p>Now, <strong>STP conditions</strong> are <em><strong>currently</strong></em> defined as a pressure of <mathjax>#"100 kPa"#</mathjax> and a temperature of <mathjax>#0^@"C"#</mathjax>. The thing to remember here is that when an ideal gas is kept under STP conditions, <strong>one mole</strong> occupies <mathjax>#"22.7 L"#</mathjax>. </p> <blockquote> <p><mathjax>#color(blue)(|bar(ul(color(white)(a/a)"1 mole" = "22.7 L"color(white)(a/a)|))) -&gt;#</mathjax> <em>the <strong>molar volume of a gas at STP</strong></em></p> </blockquote> <p>Use this as a <em>conversion factor</em> to calculate the volume occupied by <mathjax>#0.08373#</mathjax> <strong>moles</strong> of hydrogen gas kept under STP conditions</p> <blockquote> <p><mathjax>#0.08373 color(red)(cancel(color(black)("moles H"_2))) * "22.7 L"/(1color(red)(cancel(color(black)("mole H"_2)))) = color(green)(|bar(ul(color(white)(a/a)color(black)("1.90 L")color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p> <p>Notice that the problem provides you with the value of the universal gas constant, <mathjax>#R#</mathjax>. You <em>don't really need to use it</em> here because you can use the <strong>molar volume of gas at STP</strong>.</p> <p>In fact, you can prove that the molar volume of a gas at STP is <mathjax>#"22.7 L"#</mathjax> by using the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation</p> <blockquote> <p><mathjax>#PV = nRT#</mathjax></p> <p><mathjax>#V/n = (RT)/P#</mathjax></p> </blockquote> <p>Plug in your values to find</p> <blockquote> <p><mathjax>#V/n = (0.0821 (color(red)(cancel(color(black)("atm"))) * "L")/("mol" * color(red)(cancel(color(black)("K")))) * (273.15 + 0)color(red)(cancel(color(black)("K"))))/(100/101.325color(red)(cancel(color(black)("atm")))) = "22.7 L mol"^(-1)#</mathjax></p> </blockquote> <p>This is why <strong>one mole</strong> of an ideal gas occupies <mathjax>#"22.7 L"#</mathjax> at STP. </p> <p><strong>SIDE NOTE</strong> <em>If the molar volume of a gas at STP is given to you as</em> <mathjax>#"22.4 L"#</mathjax>, <em>which is the value that corresponds to the <strong>old definition</strong> of STP conditions, i.e. a pressure of</em> <mathjax>#"1 atm"#</mathjax> <em>and a temperature of</em> <mathjax>#0^@"C"#</mathjax>, <em>simply redo the final calculation using</em> <mathjax>#"22.4 L"#</mathjax> <em>instead of</em> <mathjax>#"22.7 L"#</mathjax>. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/287292" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 13562 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

The reaction of iron with hydrochloric acid is represented by the following thermochemical equation. If, in a particular experiment, 7.36 kJ of heat was released at constant pressure, what volume of #H_2(g)#, measured at STP, was produced?

#Fe(s) + 2HCl(aq) -&gt; FeCl_2(aq) + H_2(g)#; #DeltaH = -"87.9 kJ"# #R = 0.0821 (L * atm)/(K* mol)#

a8cff694-6ddd-11ea-8bb4-ccda262736ce

https://socratic.org/questions/5a1a74bb7c01496a7da17519

4.9

start physical_unit 5 6 ph none qc_end physical_unit 15 15 10 11 volume qc_end physical_unit 15 15 13 14 molarity qc_end physical_unit 22 23 17 18 volume qc_end physical_unit 22 23 20 21 molarity qc_end physical_unit 15 15 28 28 pka qc_end end

[{"type":"physical unit","value":"pH [OF] the solution"}]

[{"type":"physical unit","value":"4.9"}]

[{"type":"physical unit","value":"Volume [OF] ammonia [=] \\pu{100 mL}"},{"type":"physical unit","value":"Molarity [OF] ammonia [=] \\pu{0.5 mol/L}"},{"type":"physical unit","value":"Volume [OF] hydrochloric acid [=] \\pu{50 mL}"},{"type":"physical unit","value":"Molarity [OF] hydrochloric acid [=] \\pu{1 M}"},{"type":"physical unit","value":"pKa [OF] ammonia [=] \\pu{9.25}"}]

<h1 class="questionTitle" itemprop="name">What is the pH of the solution formed by mixing 100 mL of 0.5 mol/L ammonia with 50 mL of 1 M hydrochloric acid?</h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>For ammonia. <mathjax>#"p"K_text(a) = 9.25#</mathjax>.</p></div> </h2> </div> </div>

4.9

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Figure out what is happening</strong></p> <p>The <mathjax>#"p"K_text(a)#</mathjax> values tell you that <mathjax>#"HCl"#</mathjax> is a strong acid, that <mathjax>#"NH"_4^"+"#</mathjax> is a weak acid, and that <mathjax>#"NH"_3#</mathjax> is a weak base. </p> <p>Thus, when you mix the strong acid <mathjax>#"HCl"#</mathjax> with the weak base <mathjax>#"NH"_3#</mathjax>, the reaction will go to completion.</p> <p><mathjax>#"Initial moles of NH"_3 = 0.100 color(red)(cancel(color(black)("L NH"_3))) × "0.5 mol NH"_3/(1 color(red)(cancel(color(black)("L NH"_3)))) = "0.050 mol NH"_3#</mathjax></p> <p><mathjax>#"Initial moles of HCl" = 0.050 color(red)(cancel(color(black)("L HCl"))) × "1 mol HCl"/(1 color(red)(cancel(color(black)("L HCl")))) = "0.050 mol HCl"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#color(white)(mmmmml)"NH"_3 +color(white)(l) "HCl" → "NH"_4"Cl"#</mathjax><br/> <mathjax>#"I/mol":color(white)(mll)0.050color(white)(ml)0.050color(white)(mmml)0#</mathjax><br/> <mathjax>#"C/mol":color(white)(m)"-0.050"color(white)(m)"-0.050"color(white)(m)"+0.050#</mathjax><br/> <mathjax>#"E/mol":color(white)(mmll)0color(white)(mmml)0color(white)(mmml)0.050#</mathjax></p> <p>The ammonia and hydrochloric acid react completely.</p> <p>You now have 0.050 mol of <mathjax>#"NH"_4"Cl"#</mathjax> in 150 mL of solution.</p> <blockquote></blockquote> <p><strong>Step 2. Calculate the pH of the solution</strong></p> <p><mathjax>#"Initial concentration of NH"_4^"+" = "0.050 mol"/"0.150 L" = "0.33 mol/L"#</mathjax> </p> <p>Now, we can use an ICE table.</p> <p><mathjax>#color(white)(mmmmmml)"NH"_4^"+" + "H"_2"O" ⇌ "NH"_3 + "H"_3"O"^"+"#</mathjax><br/> <mathjax>#"I/mol·L"^"-1":color(white)(ml)0.33 color(white)(mmmmmml)0color(white)(mmml)0#</mathjax><br/> <mathjax>#"C/mol·L"^"-1":color(white)(mll)"-"xcolor(white)(mmmmmm)"+"xcolor(white)(mml)"+"x#</mathjax><br/> <mathjax>#"E/mol·L"^"-1":color(white)(m)"0.33-"xcolor(white)(mmmmml)xcolor(white)(mmml)x#</mathjax></p> <p><mathjax>#K_text(a) = (["NH"_3]["H"_3"O"^"+"])/(["NH"_4^"+"]) = x^2/(0.33-x)#</mathjax></p> <blockquote></blockquote> <p><mathjax>#"p"K_text(a) = 9.25#</mathjax></p> <p><mathjax>#K_text(a) = 10^("-p"K_text(a)) = 10^"-9.25" = 5.62 × 10^"-10"#</mathjax></p> <p>∴ <mathjax>#x^2/(0.33-x) = 5.62 × 10^"-10"#</mathjax></p> <p><mathjax>#0.33/(5.62 × 10^"-10") = 5.9 ×10^8#</mathjax>, so <mathjax>#x≪ 0.33#</mathjax></p> <p>Then,</p> <p><mathjax>#x^2/0.33 = 5.62 × 10^"-10"#</mathjax></p> <p><mathjax>#x^2 = 0.33 × 5.62 × 10^"-10" = 1.9 × 10^"-10"#</mathjax></p> <p><mathjax>#x = 1.4 × 10^"-5"#</mathjax></p> <p><mathjax>#["H"_3"O"^"+"] = xcolor(white)(l) "mol/L" = 1.4 × 10^"-5"color(white)(l) "mol/L"#</mathjax></p> <p><mathjax>#"pH" = "-log"["H"_3"O"^"+"] = -log(1.4 × 10^"-5") =4.9#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> = 4.9</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Figure out what is happening</strong></p> <p>The <mathjax>#"p"K_text(a)#</mathjax> values tell you that <mathjax>#"HCl"#</mathjax> is a strong acid, that <mathjax>#"NH"_4^"+"#</mathjax> is a weak acid, and that <mathjax>#"NH"_3#</mathjax> is a weak base. </p> <p>Thus, when you mix the strong acid <mathjax>#"HCl"#</mathjax> with the weak base <mathjax>#"NH"_3#</mathjax>, the reaction will go to completion.</p> <p><mathjax>#"Initial moles of NH"_3 = 0.100 color(red)(cancel(color(black)("L NH"_3))) × "0.5 mol NH"_3/(1 color(red)(cancel(color(black)("L NH"_3)))) = "0.050 mol NH"_3#</mathjax></p> <p><mathjax>#"Initial moles of HCl" = 0.050 color(red)(cancel(color(black)("L HCl"))) × "1 mol HCl"/(1 color(red)(cancel(color(black)("L HCl")))) = "0.050 mol HCl"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#color(white)(mmmmml)"NH"_3 +color(white)(l) "HCl" → "NH"_4"Cl"#</mathjax><br/> <mathjax>#"I/mol":color(white)(mll)0.050color(white)(ml)0.050color(white)(mmml)0#</mathjax><br/> <mathjax>#"C/mol":color(white)(m)"-0.050"color(white)(m)"-0.050"color(white)(m)"+0.050#</mathjax><br/> <mathjax>#"E/mol":color(white)(mmll)0color(white)(mmml)0color(white)(mmml)0.050#</mathjax></p> <p>The ammonia and hydrochloric acid react completely.</p> <p>You now have 0.050 mol of <mathjax>#"NH"_4"Cl"#</mathjax> in 150 mL of solution.</p> <blockquote></blockquote> <p><strong>Step 2. Calculate the pH of the solution</strong></p> <p><mathjax>#"Initial concentration of NH"_4^"+" = "0.050 mol"/"0.150 L" = "0.33 mol/L"#</mathjax> </p> <p>Now, we can use an ICE table.</p> <p><mathjax>#color(white)(mmmmmml)"NH"_4^"+" + "H"_2"O" ⇌ "NH"_3 + "H"_3"O"^"+"#</mathjax><br/> <mathjax>#"I/mol·L"^"-1":color(white)(ml)0.33 color(white)(mmmmmml)0color(white)(mmml)0#</mathjax><br/> <mathjax>#"C/mol·L"^"-1":color(white)(mll)"-"xcolor(white)(mmmmmm)"+"xcolor(white)(mml)"+"x#</mathjax><br/> <mathjax>#"E/mol·L"^"-1":color(white)(m)"0.33-"xcolor(white)(mmmmml)xcolor(white)(mmml)x#</mathjax></p> <p><mathjax>#K_text(a) = (["NH"_3]["H"_3"O"^"+"])/(["NH"_4^"+"]) = x^2/(0.33-x)#</mathjax></p> <blockquote></blockquote> <p><mathjax>#"p"K_text(a) = 9.25#</mathjax></p> <p><mathjax>#K_text(a) = 10^("-p"K_text(a)) = 10^"-9.25" = 5.62 × 10^"-10"#</mathjax></p> <p>∴ <mathjax>#x^2/(0.33-x) = 5.62 × 10^"-10"#</mathjax></p> <p><mathjax>#0.33/(5.62 × 10^"-10") = 5.9 ×10^8#</mathjax>, so <mathjax>#x≪ 0.33#</mathjax></p> <p>Then,</p> <p><mathjax>#x^2/0.33 = 5.62 × 10^"-10"#</mathjax></p> <p><mathjax>#x^2 = 0.33 × 5.62 × 10^"-10" = 1.9 × 10^"-10"#</mathjax></p> <p><mathjax>#x = 1.4 × 10^"-5"#</mathjax></p> <p><mathjax>#["H"_3"O"^"+"] = xcolor(white)(l) "mol/L" = 1.4 × 10^"-5"color(white)(l) "mol/L"#</mathjax></p> <p><mathjax>#"pH" = "-log"["H"_3"O"^"+"] = -log(1.4 × 10^"-5") =4.9#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the pH of the solution formed by mixing 100 mL of 0.5 mol/L ammonia with 50 mL of 1 M hydrochloric acid?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>For ammonia. <mathjax>#"p"K_text(a) = 9.25#</mathjax>.</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/buffer-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Buffer Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="511810" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-11-27T02:45:23" itemprop="dateCreated"> Nov 27, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><a href="https://socratic.org/chemistry/acids-and-bases/the-ph-concept">pH</a> = 4.9</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Step 1. Figure out what is happening</strong></p> <p>The <mathjax>#"p"K_text(a)#</mathjax> values tell you that <mathjax>#"HCl"#</mathjax> is a strong acid, that <mathjax>#"NH"_4^"+"#</mathjax> is a weak acid, and that <mathjax>#"NH"_3#</mathjax> is a weak base. </p> <p>Thus, when you mix the strong acid <mathjax>#"HCl"#</mathjax> with the weak base <mathjax>#"NH"_3#</mathjax>, the reaction will go to completion.</p> <p><mathjax>#"Initial moles of NH"_3 = 0.100 color(red)(cancel(color(black)("L NH"_3))) × "0.5 mol NH"_3/(1 color(red)(cancel(color(black)("L NH"_3)))) = "0.050 mol NH"_3#</mathjax></p> <p><mathjax>#"Initial moles of HCl" = 0.050 color(red)(cancel(color(black)("L HCl"))) × "1 mol HCl"/(1 color(red)(cancel(color(black)("L HCl")))) = "0.050 mol HCl"#</mathjax></p> <blockquote></blockquote> <p><mathjax>#color(white)(mmmmml)"NH"_3 +color(white)(l) "HCl" → "NH"_4"Cl"#</mathjax><br/> <mathjax>#"I/mol":color(white)(mll)0.050color(white)(ml)0.050color(white)(mmml)0#</mathjax><br/> <mathjax>#"C/mol":color(white)(m)"-0.050"color(white)(m)"-0.050"color(white)(m)"+0.050#</mathjax><br/> <mathjax>#"E/mol":color(white)(mmll)0color(white)(mmml)0color(white)(mmml)0.050#</mathjax></p> <p>The ammonia and hydrochloric acid react completely.</p> <p>You now have 0.050 mol of <mathjax>#"NH"_4"Cl"#</mathjax> in 150 mL of solution.</p> <blockquote></blockquote> <p><strong>Step 2. Calculate the pH of the solution</strong></p> <p><mathjax>#"Initial concentration of NH"_4^"+" = "0.050 mol"/"0.150 L" = "0.33 mol/L"#</mathjax> </p> <p>Now, we can use an ICE table.</p> <p><mathjax>#color(white)(mmmmmml)"NH"_4^"+" + "H"_2"O" ⇌ "NH"_3 + "H"_3"O"^"+"#</mathjax><br/> <mathjax>#"I/mol·L"^"-1":color(white)(ml)0.33 color(white)(mmmmmml)0color(white)(mmml)0#</mathjax><br/> <mathjax>#"C/mol·L"^"-1":color(white)(mll)"-"xcolor(white)(mmmmmm)"+"xcolor(white)(mml)"+"x#</mathjax><br/> <mathjax>#"E/mol·L"^"-1":color(white)(m)"0.33-"xcolor(white)(mmmmml)xcolor(white)(mmml)x#</mathjax></p> <p><mathjax>#K_text(a) = (["NH"_3]["H"_3"O"^"+"])/(["NH"_4^"+"]) = x^2/(0.33-x)#</mathjax></p> <blockquote></blockquote> <p><mathjax>#"p"K_text(a) = 9.25#</mathjax></p> <p><mathjax>#K_text(a) = 10^("-p"K_text(a)) = 10^"-9.25" = 5.62 × 10^"-10"#</mathjax></p> <p>∴ <mathjax>#x^2/(0.33-x) = 5.62 × 10^"-10"#</mathjax></p> <p><mathjax>#0.33/(5.62 × 10^"-10") = 5.9 ×10^8#</mathjax>, so <mathjax>#x≪ 0.33#</mathjax></p> <p>Then,</p> <p><mathjax>#x^2/0.33 = 5.62 × 10^"-10"#</mathjax></p> <p><mathjax>#x^2 = 0.33 × 5.62 × 10^"-10" = 1.9 × 10^"-10"#</mathjax></p> <p><mathjax>#x = 1.4 × 10^"-5"#</mathjax></p> <p><mathjax>#["H"_3"O"^"+"] = xcolor(white)(l) "mol/L" = 1.4 × 10^"-5"color(white)(l) "mol/L"#</mathjax></p> <p><mathjax>#"pH" = "-log"["H"_3"O"^"+"] = -log(1.4 × 10^"-5") =4.9#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/511810" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-are-buffer-solutions-used"> How are buffer solutions used? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-buffer-capacity"> How do you calculate buffer capacity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-buffer-solutions-maintain-the-ph-of-blood"> How do buffer solutions maintain the pH of blood? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-buffer-a-solution-with-a-ph-of-12"> How do you buffer a solution with a pH of 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-buffer-solutions-used-to-calibrate-ph"> Why are buffer solutions used to calibrate pH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is--solution-used-in-complexometric-titration"> What is the role of buffer solution in complexometric titrations? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-you-would-make-100-0-ml-of-a-bu-er-solution-with-a-ph-of-10-80-to-be-made-us"> How you would make 100.0 ml of a 1.00 mol/L buffer solution with a pH of 10.80 to be made using... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-henderson-hasselbalch-equation"> What is the Henderson-Hasselbalch equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-ph-buffer-calculation-problem"> What is an example of a pH buffer calculation problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-bicarbonate-buffering-system-important"> Why is the bicarbonate buffering system important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/reactions-in-solution/buffer-calculations"> See all questions in Buffer Calculations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 6196 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the pH of the solution formed by mixing 100 mL of 0.5 mol/L ammonia with 50 mL of 1 M hydrochloric acid?

For ammonia. #"p"K_text(a) = 9.25#.

ac765f12-6ddd-11ea-80da-ccda262736ce

https://socratic.org/questions/a-flask-contains-methane-chlorine-and-carbon-monoxide-gases-the-partial-pressure

1.11 atm

start physical_unit 29 30 total_pressure atm qc_end end

[{"type":"physical unit","value":"Total pressure [OF] the flask [IN] atm"}]

[{"type":"physical unit","value":"1.11 atm"}]

[{"type":"physical unit","value":"Partial pressure [OF] methane gas [=] \\pu{0.215 atm}"},{"type":"physical unit","value":"Partial pressure [OF] chlorine gas [=] \\pu{50 torr}"},{"type":"physical unit","value":"Partial pressure [OF] carbon monoxide gas [=] \\pu{0.826 atm}"}]

<h1 class="questionTitle" itemprop="name">A flask contains methane, chlorine, and carbon monoxide gases. The partial pressures of each are 0.215 atm, 50 torr, and 0.826 respectively. What is the total pressure in the flask?</h1>

1.11 atm

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>According to Raoul's law of <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a>, the total pressure of a mixture of gases is equal to the sum of the partial pressure of the individual gases"</p> <p><mathjax>#P_("total")=P_1+P_2+P_3+...#</mathjax></p> <p>Therefore, the total pressure of this mixture would be:</p> <p><mathjax>#P_("total")=P_(CH_4)+P_(Cl_2)+P_(CO)#</mathjax></p> <p><mathjax>#=&gt;P_("total")=0.215atm+50cancel("torr")xx(1atm)/(760cancel("torr"))+0.826atm=1.11atm#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_("total")=1.11atm#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>According to Raoul's law of <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a>, the total pressure of a mixture of gases is equal to the sum of the partial pressure of the individual gases"</p> <p><mathjax>#P_("total")=P_1+P_2+P_3+...#</mathjax></p> <p>Therefore, the total pressure of this mixture would be:</p> <p><mathjax>#P_("total")=P_(CH_4)+P_(Cl_2)+P_(CO)#</mathjax></p> <p><mathjax>#=&gt;P_("total")=0.215atm+50cancel("torr")xx(1atm)/(760cancel("torr"))+0.826atm=1.11atm#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A flask contains methane, chlorine, and carbon monoxide gases. The partial pressures of each are 0.215 atm, 50 torr, and 0.826 respectively. What is the total pressure in the flask?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/partial-pressure" itemprop="url"> <span class="breadcrumb" itemprop="title">Partial Pressure</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="267176" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ali-h-1"><img alt="" class="" src="https://profilepictures.socratic.org/IITeL1YTQdODdLp0aJTL_StereoPicture%20copy.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ali-h-1"> Dr. Hayek </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-18T21:35:09" itemprop="dateCreated"> May 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#P_("total")=1.11atm#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>According to Raoul's law of <a href="https://socratic.org/chemistry/the-behavior-of-gases/partial-pressure">partial pressure</a>, the total pressure of a mixture of gases is equal to the sum of the partial pressure of the individual gases"</p> <p><mathjax>#P_("total")=P_1+P_2+P_3+...#</mathjax></p> <p>Therefore, the total pressure of this mixture would be:</p> <p><mathjax>#P_("total")=P_(CH_4)+P_(Cl_2)+P_(CO)#</mathjax></p> <p><mathjax>#=&gt;P_("total")=0.215atm+50cancel("torr")xx(1atm)/(760cancel("torr"))+0.826atm=1.11atm#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/267176" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534e256802bf342adfa30010"> How do you do a steam distillation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/53613f9f02bf3416cd9f8a34"> Question #f8a34 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-i-calculate-the-total-pressure-of-a-mixture-of-gases-by-adding-together-the-"> Can I calculate the total pressure of a mixture of gases by adding together the partial... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-formula-of-partial-pressure"> What is the formula of partial pressure? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-dalton-s-law-of-partial-pressures"> What is the Dalton's law of partial pressures? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/nitrogen-gas-n2-reacts-with-hydrogen-gas-h2-to-form-ammonia-nh3-at-200-c-in-a-cl"> Nitrogen gas (N2) reacts with hydrogen gas (H2) to form ammonia (NH3). 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A flask contains methane, chlorine, and carbon monoxide gases. The partial pressures of each are 0.215 atm, 50 torr, and 0.826 respectively. What is the total pressure in the flask?

a8e7c764-6ddd-11ea-a64c-ccda262736ce

https://socratic.org/questions/a-sample-of-hydrogen-gas-h-2-has-a-volume-of-8-56-l-at-a-temperature-of-0-oc-and

0.6 moles

start physical_unit 31 32 mole mol qc_end end

[{"type":"physical unit","value":"Mole [OF] H2 molecules [IN] moles"}]

[{"type":"physical unit","value":"0.6 moles"}]

[{"type":"physical unit","value":"Volume [OF] H2 gas [=] \\pu{8.56 L}"},{"type":"physical unit","value":"Temperature [OF] H2 gas [=] \\pu{0 ℃}"},{"type":"physical unit","value":"Pressure [OF] H2 gas [=] \\pu{1.5 atm}"}]

<h1 class="questionTitle" itemprop="name">A sample of hydrogen gas (#H_2#) has a volume of 8.56 L at a temperature of 0#"^oC# and a pressure of 1.5 atm. How do you calculate the moles of #H_2# molecules present in this gas sample?</h1>

0.6 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#n=(PV)/(RT)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1.5*atmxx8.56*L)/(0.0821*L*atm*mol^-1*K^-1xx273*K)#</mathjax></p> <p>If we have set up this problem right, the answer should give units of moles. How many grams of dihydrogen does this represent?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We use the ideal gas equation.......<mathjax>#PV=nRT#</mathjax>, to get <mathjax>#n~=0.6*mol#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#n=(PV)/(RT)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1.5*atmxx8.56*L)/(0.0821*L*atm*mol^-1*K^-1xx273*K)#</mathjax></p> <p>If we have set up this problem right, the answer should give units of moles. How many grams of dihydrogen does this represent?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A sample of hydrogen gas (#H_2#) has a volume of 8.56 L at a temperature of 0#"^oC# and a pressure of 1.5 atm. How do you calculate the moles of #H_2# molecules present in this gas sample?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="323378" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-18T18:59:55" itemprop="dateCreated"> Oct 18, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We use the ideal gas equation.......<mathjax>#PV=nRT#</mathjax>, to get <mathjax>#n~=0.6*mol#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#n=(PV)/(RT)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1.5*atmxx8.56*L)/(0.0821*L*atm*mol^-1*K^-1xx273*K)#</mathjax></p> <p>If we have set up this problem right, the answer should give units of moles. How many grams of dihydrogen does this represent?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/323378" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-stoichiometric-ratios-relate-to-molar-volume-of-a-gas"> How do stoichiometric ratios relate to molar volume of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-a-gas-at-stp"> How do you calculate molar volume of a gas at STP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-molar-volume-of-hydrogen-gas"> How do you find the molar volume of hydrogen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molar-volume-of-oxygen-gas"> How do you calculate molar volume of oxygen gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molar-gas-volume"> What is molar gas volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534c7bf202bf3420a007f014"> What is the volume at 0 °C and 1 atm of a mixture that contains 4.0 g of methane and 2.0 g of helium? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5361f75702bf3429040e0599"> What is the difference between STP and NTP? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-volume-of-25-moles-of-oxygen-o2-gas"> What is the volume of .25 moles of oxygen (O2) Gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-would-knowing-the-molar-volume-of-a-gas-be-important"> Why would knowing the molar volume of a gas be important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-22-4-liters-called-the-molar-volume-of-a-gas"> Why is 22.4 liters called the molar volume of a gas? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp"> See all questions in Molar Volume of a Gas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 28531 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A sample of hydrogen gas (#H_2#) has a volume of 8.56 L at a temperature of 0#"^oC# and a pressure of 1.5 atm. How do you calculate the moles of #H_2# molecules present in this gas sample?

a9ac43a2-6ddd-11ea-b684-ccda262736ce

https://socratic.org/questions/how-much-heat-is-absorbed-by-a-2000-kg-granite-boulder-as-energy-from-the-sun-ca

3.00 MJ

start physical_unit 9 10 heat_energy mj qc_end physical_unit 9 10 7 8 mass qc_end physical_unit 9 10 22 23 temperature qc_end physical_unit 9 10 25 26 temperature qc_end end

[{"type":"physical unit","value":"Absorbed heat [OF] granite boulder [IN] MJ"}]

[{"type":"physical unit","value":"3.00 MJ"}]

[{"type":"physical unit","value":"Mass [OF] granite boulder [=] \\pu{2000 kg}"},{"type":"physical unit","value":"Temperature1 [OF] granite boulder [=] \\pu{10 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] granite boulder [=] \\pu{29 ℃}"}]

<h1 class="questionTitle" itemprop="name">How much heat is absorbed by a 2000 kg granite boulder as energy from the sun causes its temperature to change from 10°C to 29°C?</h1>

3.00 MJ

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Heat absorbed,<br/> <mathjax>#H= m.c. del(theta)#</mathjax><br/> Where, m= mass,<br/> C= specific heat capacity. Assume <mathjax>#c=790 J/(kg)/K#</mathjax> for granite.<br/> <mathjax>#del(theta)#</mathjax> is the change in temperature. <br/> Hence, <mathjax>#del(theta)=29-10=19K#</mathjax></p> <p>(Note: For difference of temperature, Celsius degrees and Kelvin are interchangeable, as the interval for both scales is the same.)</p> <p>Then we have, <br/> <mathjax>#H=2000*790*19 = 3002000 J = 3.002 MJ#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>3.002 MJ</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Heat absorbed,<br/> <mathjax>#H= m.c. del(theta)#</mathjax><br/> Where, m= mass,<br/> C= specific heat capacity. Assume <mathjax>#c=790 J/(kg)/K#</mathjax> for granite.<br/> <mathjax>#del(theta)#</mathjax> is the change in temperature. <br/> Hence, <mathjax>#del(theta)=29-10=19K#</mathjax></p> <p>(Note: For difference of temperature, Celsius degrees and Kelvin are interchangeable, as the interval for both scales is the same.)</p> <p>Then we have, <br/> <mathjax>#H=2000*790*19 = 3002000 J = 3.002 MJ#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How much heat is absorbed by a 2000 kg granite boulder as energy from the sun causes its temperature to change from 10°C to 29°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="411976" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/abhinav-t"><img alt="" class="" src="https://lh6.googleusercontent.com/-xC7MnyC-w0w/AAAAAAAAAAI/AAAAAAAACvk/a_zlm9tVN4w/photo.jpg?sz=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/abhinav-t"> Abhinav T. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-24T16:12:12" itemprop="dateCreated"> Apr 24, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>3.002 MJ</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Heat absorbed,<br/> <mathjax>#H= m.c. del(theta)#</mathjax><br/> Where, m= mass,<br/> C= specific heat capacity. Assume <mathjax>#c=790 J/(kg)/K#</mathjax> for granite.<br/> <mathjax>#del(theta)#</mathjax> is the change in temperature. <br/> Hence, <mathjax>#del(theta)=29-10=19K#</mathjax></p> <p>(Note: For difference of temperature, Celsius degrees and Kelvin are interchangeable, as the interval for both scales is the same.)</p> <p>Then we have, <br/> <mathjax>#H=2000*790*19 = 3002000 J = 3.002 MJ#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/411976" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="411993" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/samriddha"><img alt="" class="" src="https://profilepictures.socratic.org/3bMcXdwZTLqpsJaquExz_Shinjuku.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/samriddha"> Professor Sam </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-24T16:39:49" itemprop="dateCreated"> Apr 24, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerDescription"> <div> <div class="markdown"><p>Apply the equation</p> <p><mathjax>#color (red)(Q = mCpDeltaT)#</mathjax></p> <p><mathjax>#color(blue)("Where Q is heat absorbed")#</mathjax></p> <p><mathjax>#color(blue)("Cp is the specific heat")#</mathjax></p> <p><mathjax>#color(blue)(DeltaT "is " t_"final" - t_"initial"#</mathjax></p> <p><mathjax>#color(blue)("m is mass in grams")#</mathjax></p> <p>The <mathjax>#Cp#</mathjax> of granite </p> <p><mathjax>#Cp#</mathjax> of granite is <mathjax>#"0.79J/g"*C^@#</mathjax></p> <p>Convert 2000kg to grams = <mathjax>#2*10^6g#</mathjax></p> <p><mathjax>#2*10^6g xx "0.79J/g"*C^@ xx (29C^@-10C^@) = 30 020 000J#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/411993" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? 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How much heat is absorbed by a 2000 kg granite boulder as energy from the sun causes its temperature to change from 10°C to 29°C?

a97cb7fa-6ddd-11ea-8125-ccda262736ce

https://socratic.org/questions/what-is-the-molar-concentration-of-hydrogen-ions-if-12-drops-of-a-benzoic-acid-h

1.3 × 10^(-9) M

start physical_unit 6 7 molarity mol/l qc_end physical_unit 26 27 24 25 molarity qc_end end

[{"type":"physical unit","value":"Molar concentration [OF] hydrogen ions [IN] M"}]

[{"type":"physical unit","value":"1.3 × 10^(-9) M"}]

[{"type":"physical unit","value":"Number [OF] HC7H5O2 solution drops [=] \\pu{12}"},{"type":"physical unit","value":"Number [OF] KOH solution drops [=] \\pu{26}"},{"type":"physical unit","value":"Molar concentration [OF] KOH solution [=] \\pu{0.40 M}"}]

<h1 class="questionTitle" itemprop="name">What is the molar concentration of hydrogen ions if 12 drops of a benzoic acid #HC_7H_5O_2# solution are titrated with 26 drops of a .40 M #KOH# solution?</h1>

1.3 × 10^(-9) M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Warning! Long Answer.</strong></p> <p>I assume that you have titrated to the end point.</p> <blockquote></blockquote> <p>The equation for the reaction is</p> <p><mathjax>#"HA" + "KOH" → "KA" +"H"_2"O"#</mathjax></p> <p>Since <mathjax>#"HA"#</mathjax> and <mathjax>#"KOH"#</mathjax> react in a 1:1 molar ratio, we can write</p> <p><mathjax>#c_aV_a =c_bV_b#</mathjax></p> <p>∴ <mathjax>#c_a = c_b × V_b/V_a = "0.40 mol/L" × (26 color(red)(cancel(color(black)("drops"))))/(12 color(red)(cancel(color(black)("drops")))) = "0.867 mol/L"#</mathjax></p> <blockquote></blockquote> <p>At <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a>, you have only <mathjax>#"KA"#</mathjax> present.</p> <p>If there had been no change in volume, its concentration would have been 0.867 mol/L.</p> <p>However, the volume increased during the titration to <mathjax>#"(12 drops + 26 drops) = 38 drops"#</mathjax>.</p> <p>To calculate the new concentration, we can use the dilution formula</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(|bar(ul(color(white)(a/a) c_1V_1 = c_2V_2color(white)(a/a)|)))" "#</mathjax></p> </blockquote> </blockquote> <p><mathjax>#c_1 = "0.867 mol/L"; V_1 = "12 drops"#</mathjax><br/> <mathjax>#c_2 = ?; color(white)(mmmmml)V_2 = "38 drops"#</mathjax></p> <p><mathjax>#c_2 = c_1 × V_1/V_2 = "0.867 mol/L" × (12 color(red)(cancel(color(black)("drops"))))/(28color(red)(cancel(color(black)( "drops")))) = "0.372 mol/L"#</mathjax></p> <p>∴ At neutralization, we have a 0.372 mol/L solution of <mathjax>#"KA"#</mathjax>.</p> <blockquote></blockquote> <p><strong>Calculate the concentration of <mathjax>#["H"^+]#</mathjax> in a 0.372 mol/L solution of KA</strong></p> <p><mathjax>#color(white)(mmmmmmmmll)"A"^"-" + "H"_2"O" ⇌ "HA" + "OH"^"-"#</mathjax><br/> <mathjax>#"I/mol·L"^"-1": color(white)(mml)0.372color(white)(mmmmmll) 0color(white)(mmll) 0#</mathjax><br/> <mathjax>#"C/mol·L"^"-1":color(white)(mmm) "-"xcolor(white)(mmmmml) +x color(white)(m)+x#</mathjax><br/> <mathjax>#"E/mol·L"^"-1": color(white)(m)0.372 -xcolor(white)(mmmmll) x color(white)(mmll)x#</mathjax></p> <p><mathjax>#K_b = K_w/K_a = (1.00 × 10^"-14")/(6.46 × 10^"-5") = 1.55 × 10^"-10"#</mathjax></p> <p><mathjax>#K_b = (["HA"]["OH"^"-"])/(["A"^"-"])#</mathjax></p> <p><mathjax>#1.55 × 10^"-10" = (x × x)/(0.372 -x) - x^2/(0.372-x)#</mathjax></p> <blockquote></blockquote> <p><strong>Check if <mathjax>#x#</mathjax> is negligible</strong></p> <p><mathjax>#0.372/(1.55 × 10^"-10") = 2.11 × 10^9 &gt; 400; ∴ x « 0.372#</mathjax></p> <blockquote></blockquote> <p><mathjax>#1.55 × 10^"-10" = x^2/0.372#</mathjax></p> <p><mathjax>#x^2 = 0.372 × 1.55 × 10^"-10" = 5.77 × 10^"-11"#</mathjax></p> <p><mathjax>#x = ["OH"^"-"] = 7.59 ×10^"-6"#</mathjax></p> <p><mathjax>#["H"^+] = K_w/["OH"^"-"] = (1.00 × 10^"-14")/(7.59 ×10^"-6") = 1.3 × 10^"-9"color(white)(l) "mol/L"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#["H"^+] = 1.3 × 10^"-9" color(white)(l)"mol/L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Warning! Long Answer.</strong></p> <p>I assume that you have titrated to the end point.</p> <blockquote></blockquote> <p>The equation for the reaction is</p> <p><mathjax>#"HA" + "KOH" → "KA" +"H"_2"O"#</mathjax></p> <p>Since <mathjax>#"HA"#</mathjax> and <mathjax>#"KOH"#</mathjax> react in a 1:1 molar ratio, we can write</p> <p><mathjax>#c_aV_a =c_bV_b#</mathjax></p> <p>∴ <mathjax>#c_a = c_b × V_b/V_a = "0.40 mol/L" × (26 color(red)(cancel(color(black)("drops"))))/(12 color(red)(cancel(color(black)("drops")))) = "0.867 mol/L"#</mathjax></p> <blockquote></blockquote> <p>At <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a>, you have only <mathjax>#"KA"#</mathjax> present.</p> <p>If there had been no change in volume, its concentration would have been 0.867 mol/L.</p> <p>However, the volume increased during the titration to <mathjax>#"(12 drops + 26 drops) = 38 drops"#</mathjax>.</p> <p>To calculate the new concentration, we can use the dilution formula</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(|bar(ul(color(white)(a/a) c_1V_1 = c_2V_2color(white)(a/a)|)))" "#</mathjax></p> </blockquote> </blockquote> <p><mathjax>#c_1 = "0.867 mol/L"; V_1 = "12 drops"#</mathjax><br/> <mathjax>#c_2 = ?; color(white)(mmmmml)V_2 = "38 drops"#</mathjax></p> <p><mathjax>#c_2 = c_1 × V_1/V_2 = "0.867 mol/L" × (12 color(red)(cancel(color(black)("drops"))))/(28color(red)(cancel(color(black)( "drops")))) = "0.372 mol/L"#</mathjax></p> <p>∴ At neutralization, we have a 0.372 mol/L solution of <mathjax>#"KA"#</mathjax>.</p> <blockquote></blockquote> <p><strong>Calculate the concentration of <mathjax>#["H"^+]#</mathjax> in a 0.372 mol/L solution of KA</strong></p> <p><mathjax>#color(white)(mmmmmmmmll)"A"^"-" + "H"_2"O" ⇌ "HA" + "OH"^"-"#</mathjax><br/> <mathjax>#"I/mol·L"^"-1": color(white)(mml)0.372color(white)(mmmmmll) 0color(white)(mmll) 0#</mathjax><br/> <mathjax>#"C/mol·L"^"-1":color(white)(mmm) "-"xcolor(white)(mmmmml) +x color(white)(m)+x#</mathjax><br/> <mathjax>#"E/mol·L"^"-1": color(white)(m)0.372 -xcolor(white)(mmmmll) x color(white)(mmll)x#</mathjax></p> <p><mathjax>#K_b = K_w/K_a = (1.00 × 10^"-14")/(6.46 × 10^"-5") = 1.55 × 10^"-10"#</mathjax></p> <p><mathjax>#K_b = (["HA"]["OH"^"-"])/(["A"^"-"])#</mathjax></p> <p><mathjax>#1.55 × 10^"-10" = (x × x)/(0.372 -x) - x^2/(0.372-x)#</mathjax></p> <blockquote></blockquote> <p><strong>Check if <mathjax>#x#</mathjax> is negligible</strong></p> <p><mathjax>#0.372/(1.55 × 10^"-10") = 2.11 × 10^9 &gt; 400; ∴ x « 0.372#</mathjax></p> <blockquote></blockquote> <p><mathjax>#1.55 × 10^"-10" = x^2/0.372#</mathjax></p> <p><mathjax>#x^2 = 0.372 × 1.55 × 10^"-10" = 5.77 × 10^"-11"#</mathjax></p> <p><mathjax>#x = ["OH"^"-"] = 7.59 ×10^"-6"#</mathjax></p> <p><mathjax>#["H"^+] = K_w/["OH"^"-"] = (1.00 × 10^"-14")/(7.59 ×10^"-6") = 1.3 × 10^"-9"color(white)(l) "mol/L"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the molar concentration of hydrogen ions if 12 drops of a benzoic acid #HC_7H_5O_2# solution are titrated with 26 drops of a .40 M #KOH# solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#reactions-in-solution" itemprop="url"> <span class="breadcrumb" itemprop="title">Reactions in Solution</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/reactions-in-solution/titration-calculations" itemprop="url"> <span class="breadcrumb" itemprop="title">Titration Calculations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="272155" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ernest-z"><img alt="" class="" src="https://profilepictures.socratic.org/MtyBxlg6QwSf17eOY77u_Ernest.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ernest-z"> Ernest Z. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-05-31T17:44:11" itemprop="dateCreated"> May 31, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#["H"^+] = 1.3 × 10^"-9" color(white)(l)"mol/L"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><blockquote></blockquote> <p><strong>Warning! Long Answer.</strong></p> <p>I assume that you have titrated to the end point.</p> <blockquote></blockquote> <p>The equation for the reaction is</p> <p><mathjax>#"HA" + "KOH" → "KA" +"H"_2"O"#</mathjax></p> <p>Since <mathjax>#"HA"#</mathjax> and <mathjax>#"KOH"#</mathjax> react in a 1:1 molar ratio, we can write</p> <p><mathjax>#c_aV_a =c_bV_b#</mathjax></p> <p>∴ <mathjax>#c_a = c_b × V_b/V_a = "0.40 mol/L" × (26 color(red)(cancel(color(black)("drops"))))/(12 color(red)(cancel(color(black)("drops")))) = "0.867 mol/L"#</mathjax></p> <blockquote></blockquote> <p>At <a href="https://socratic.org/chemistry/reactions-in-solution/neutralization">neutralization</a>, you have only <mathjax>#"KA"#</mathjax> present.</p> <p>If there had been no change in volume, its concentration would have been 0.867 mol/L.</p> <p>However, the volume increased during the titration to <mathjax>#"(12 drops + 26 drops) = 38 drops"#</mathjax>.</p> <p>To calculate the new concentration, we can use the dilution formula</p> <blockquote> <blockquote> <p><mathjax>#color(blue)(|bar(ul(color(white)(a/a) c_1V_1 = c_2V_2color(white)(a/a)|)))" "#</mathjax></p> </blockquote> </blockquote> <p><mathjax>#c_1 = "0.867 mol/L"; V_1 = "12 drops"#</mathjax><br/> <mathjax>#c_2 = ?; color(white)(mmmmml)V_2 = "38 drops"#</mathjax></p> <p><mathjax>#c_2 = c_1 × V_1/V_2 = "0.867 mol/L" × (12 color(red)(cancel(color(black)("drops"))))/(28color(red)(cancel(color(black)( "drops")))) = "0.372 mol/L"#</mathjax></p> <p>∴ At neutralization, we have a 0.372 mol/L solution of <mathjax>#"KA"#</mathjax>.</p> <blockquote></blockquote> <p><strong>Calculate the concentration of <mathjax>#["H"^+]#</mathjax> in a 0.372 mol/L solution of KA</strong></p> <p><mathjax>#color(white)(mmmmmmmmll)"A"^"-" + "H"_2"O" ⇌ "HA" + "OH"^"-"#</mathjax><br/> <mathjax>#"I/mol·L"^"-1": color(white)(mml)0.372color(white)(mmmmmll) 0color(white)(mmll) 0#</mathjax><br/> <mathjax>#"C/mol·L"^"-1":color(white)(mmm) "-"xcolor(white)(mmmmml) +x color(white)(m)+x#</mathjax><br/> <mathjax>#"E/mol·L"^"-1": color(white)(m)0.372 -xcolor(white)(mmmmll) x color(white)(mmll)x#</mathjax></p> <p><mathjax>#K_b = K_w/K_a = (1.00 × 10^"-14")/(6.46 × 10^"-5") = 1.55 × 10^"-10"#</mathjax></p> <p><mathjax>#K_b = (["HA"]["OH"^"-"])/(["A"^"-"])#</mathjax></p> <p><mathjax>#1.55 × 10^"-10" = (x × x)/(0.372 -x) - x^2/(0.372-x)#</mathjax></p> <blockquote></blockquote> <p><strong>Check if <mathjax>#x#</mathjax> is negligible</strong></p> <p><mathjax>#0.372/(1.55 × 10^"-10") = 2.11 × 10^9 &gt; 400; ∴ x « 0.372#</mathjax></p> <blockquote></blockquote> <p><mathjax>#1.55 × 10^"-10" = x^2/0.372#</mathjax></p> <p><mathjax>#x^2 = 0.372 × 1.55 × 10^"-10" = 5.77 × 10^"-11"#</mathjax></p> <p><mathjax>#x = ["OH"^"-"] = 7.59 ×10^"-6"#</mathjax></p> <p><mathjax>#["H"^+] = K_w/["OH"^"-"] = (1.00 × 10^"-14")/(7.59 ×10^"-6") = 1.3 × 10^"-9"color(white)(l) "mol/L"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/272155" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-do-acid-base-titration-calculations"> How do you do acid base titration calculations? 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What is the molar concentration of hydrogen ions if 12 drops of a benzoic acid #HC_7H_5O_2# solution are titrated with 26 drops of a .40 M #KOH# solution?

ab441ad2-6ddd-11ea-a70d-ccda262736ce

https://socratic.org/questions/if-5-00-l-of-hydrogen-gas-measured-at-20-0-c-and-80-1-kpa-is-burned-in-an-excess

0.33 grams

start physical_unit 4 5 mass g qc_end physical_unit 4 5 1 2 volume qc_end physical_unit 4 5 8 9 temperature qc_end physical_unit 4 5 11 12 pressure qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Mass [OF] hydrogen gas [IN] grams"}]

[{"type":"physical unit","value":"0.33 grams"}]

[{"type":"physical unit","value":"Volume [OF] hydrogen gas [=] \\pu{5.00 L}"},{"type":"physical unit","value":"Temperature [OF] hydrogen gas [=] \\pu{20.0 ℃}"},{"type":"physical unit","value":"Pressure [OF] hydrogen gas [=] \\pu{80.1 kPa}"},{"type":"other","value":"Excess oxygen."}]

<h1 class="questionTitle" itemprop="name"> If 5.00 L of hydrogen gas measured at 20.0*C and 80.1 kPa is burned in an excess of oxygen, what mass under the same conditions, would be consumed? </h1>

0.33 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the equation for the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> to find the moles of hydrogen gas. Then determine the mass by multiplying the moles by its molar mass.</p> <p><strong>Ideal gas law</strong></p> <p><mathjax>#PV=nRT#</mathjax></p> <p><strong>Known</strong></p> <p><mathjax>#P="80.1 kPa"#</mathjax></p> <p><mathjax>#V="5.00 L"#</mathjax></p> <p><mathjax>#R="8.31447 L kPa K"^(-1) "mol"^(-1)#</mathjax></p> <p><mathjax>#T="20.0"^@"C + 273.15"="293.2 K"#</mathjax></p> <p><strong>Unknown</strong></p> <p>moles, <mathjax>#n#</mathjax></p> <p>To determine moles <mathjax>#"H"_2"#</mathjax>, rearrange the equation to isolate <mathjax>#n#</mathjax>. Plug in the known values and solve.</p> <p><mathjax>#n=(PV)/(RT)#</mathjax></p> <p><mathjax>#n=(80.1color(red)cancel(color(black)("kPa"))xx5.00color(red)cancel(color(black)("L")))/(8.31447color(red)cancel(color(black)("L")) color(red)cancel(color(black)("kPa")) color(red)cancel(color(black)("K"))^(-1) "mol"^(-1)xx293.2color(red)cancel(color(black)("K")))="0.164 mol H"_2"#</mathjax></p> <p>To determine the mass of <mathjax>#"H"_2"#</mathjax> by multiplying the moles by its molar mass <mathjax>#("2.016 g/mol")#</mathjax>.</p> <p><mathjax>#0.164color(red)cancel(color(black)("mol H"_2))xx(2.016"g H"_2)/(1color(red)cancel(color(black)("mol H"_2)))="0.331 g H"_2"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The mass of <mathjax>#"H"_2"#</mathjax> consumed is <mathjax>#"0.331 g H"_2"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the equation for the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> to find the moles of hydrogen gas. Then determine the mass by multiplying the moles by its molar mass.</p> <p><strong>Ideal gas law</strong></p> <p><mathjax>#PV=nRT#</mathjax></p> <p><strong>Known</strong></p> <p><mathjax>#P="80.1 kPa"#</mathjax></p> <p><mathjax>#V="5.00 L"#</mathjax></p> <p><mathjax>#R="8.31447 L kPa K"^(-1) "mol"^(-1)#</mathjax></p> <p><mathjax>#T="20.0"^@"C + 273.15"="293.2 K"#</mathjax></p> <p><strong>Unknown</strong></p> <p>moles, <mathjax>#n#</mathjax></p> <p>To determine moles <mathjax>#"H"_2"#</mathjax>, rearrange the equation to isolate <mathjax>#n#</mathjax>. Plug in the known values and solve.</p> <p><mathjax>#n=(PV)/(RT)#</mathjax></p> <p><mathjax>#n=(80.1color(red)cancel(color(black)("kPa"))xx5.00color(red)cancel(color(black)("L")))/(8.31447color(red)cancel(color(black)("L")) color(red)cancel(color(black)("kPa")) color(red)cancel(color(black)("K"))^(-1) "mol"^(-1)xx293.2color(red)cancel(color(black)("K")))="0.164 mol H"_2"#</mathjax></p> <p>To determine the mass of <mathjax>#"H"_2"#</mathjax> by multiplying the moles by its molar mass <mathjax>#("2.016 g/mol")#</mathjax>.</p> <p><mathjax>#0.164color(red)cancel(color(black)("mol H"_2))xx(2.016"g H"_2)/(1color(red)cancel(color(black)("mol H"_2)))="0.331 g H"_2"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name"> If 5.00 L of hydrogen gas measured at 20.0*C and 80.1 kPa is burned in an excess of oxygen, what mass under the same conditions, would be consumed? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="642092" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2018-07-20T02:33:58" itemprop="dateCreated"> Jul 20, 2018 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The mass of <mathjax>#"H"_2"#</mathjax> consumed is <mathjax>#"0.331 g H"_2"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Use the equation for the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> to find the moles of hydrogen gas. Then determine the mass by multiplying the moles by its molar mass.</p> <p><strong>Ideal gas law</strong></p> <p><mathjax>#PV=nRT#</mathjax></p> <p><strong>Known</strong></p> <p><mathjax>#P="80.1 kPa"#</mathjax></p> <p><mathjax>#V="5.00 L"#</mathjax></p> <p><mathjax>#R="8.31447 L kPa K"^(-1) "mol"^(-1)#</mathjax></p> <p><mathjax>#T="20.0"^@"C + 273.15"="293.2 K"#</mathjax></p> <p><strong>Unknown</strong></p> <p>moles, <mathjax>#n#</mathjax></p> <p>To determine moles <mathjax>#"H"_2"#</mathjax>, rearrange the equation to isolate <mathjax>#n#</mathjax>. Plug in the known values and solve.</p> <p><mathjax>#n=(PV)/(RT)#</mathjax></p> <p><mathjax>#n=(80.1color(red)cancel(color(black)("kPa"))xx5.00color(red)cancel(color(black)("L")))/(8.31447color(red)cancel(color(black)("L")) color(red)cancel(color(black)("kPa")) color(red)cancel(color(black)("K"))^(-1) "mol"^(-1)xx293.2color(red)cancel(color(black)("K")))="0.164 mol H"_2"#</mathjax></p> <p>To determine the mass of <mathjax>#"H"_2"#</mathjax> by multiplying the moles by its molar mass <mathjax>#("2.016 g/mol")#</mathjax>.</p> <p><mathjax>#0.164color(red)cancel(color(black)("mol H"_2))xx(2.016"g H"_2)/(1color(red)cancel(color(black)("mol H"_2)))="0.331 g H"_2"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/642092" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-find-grams-to-mole"> How do you convert grams to mole? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5346cdc702bf346ce0e258e5"> Question #258e5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5364ef2702bf343b32f8d48c"> Question #8d48c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-mole-an-important-unit-to-chemists"> Why is the mole an important unit to chemists? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-s-the-mole-number"> What's the mole number? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-carbon-12"> How does the mole relate to carbon 12? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-the-mole-relate-to-molecules-and-ions"> How does the mole relate to molecules and ions? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-moles-of-a-substance"> How do you calculate the moles of a substance? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-moles-of-a-solute"> How can I calculate the moles of a solute? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/the-mole"> See all questions in The Mole </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 3794 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

If 5.00 L of hydrogen gas measured at 20.0*C and 80.1 kPa is burned in an excess of oxygen, what mass under the same conditions, would be consumed?

acb533e4-6ddd-11ea-86ca-ccda262736ce

https://socratic.org/questions/a-common-laboratory-preparation-for-small-for-quantities-of-o-2-is-to-decompose-

91.91%

start physical_unit 43 44 percent_yield none qc_end chemical_equation 16 23 qc_end physical_unit 31 31 28 29 mass qc_end physical_unit 9 9 33 34 mass qc_end end

[{"type":"physical unit","value":"Percent yield [OF] the reaction"}]

[{"type":"physical unit","value":"91.91%"}]

[{"type":"chemical equation","value":"2 KClO3(s) -> 2 KCl(s) + 3 O2(g)"},{"type":"physical unit","value":"Mass [OF] KCIO3 [=] \\pu{2.00 g}"},{"type":"physical unit","value":"Mass [OF] O2 [=] \\pu{0.720 g}"}]

<h1 class="questionTitle" itemprop="name">A common laboratory preparation for small for quantities of #O_2# is to decompose #KClO_3# by heating: #2KClO_3 (s) -&gt; 2KCl (s) + 3O_2 (g)#. If the decomposition of 2.00 g of #KCIO_3# gives 0.720 g of #O_2#, what is the percent yield for the reaction?</h1>

91.91%

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by examining the balanced chemical equation that describes this <strong><a href="https://socratic.org/chemistry/chemical-reactions/decomposition-reactions">decomposition reaction</a></strong></p> <blockquote> <p><mathjax>#color(darkgreen)(2)"KClO"_ (3(s)) stackrel(color(white)(acolor(red)(Delta)aaa))(-&gt;) 2"KCl"_ ((s)) + color(blue)(3)"O"_ (2(g))#</mathjax></p> </blockquote> <p>Notice that it takes <mathjax>#color(darkgreen)(2)#</mathjax> <strong>moles</strong> of potassium chlorate to produce <mathjax>#color(blue)(3)#</mathjax> <strong>moles</strong> of oxygen gas. This represents the reaction's <strong>theoretical yield</strong>, i.e. the amount of oxygen gas that you can expect to see for a reaction that has a <mathjax>#100%#</mathjax> <strong><a href="https://socratic.org/chemistry/stoichiometry/percent-yield">yield</a></strong>. </p> <p>The reaction provides you with <em>grams</em> of potassium chlorate, so use the <strong>molar masses</strong> of potassium chlorate and of oxygen gas to convert the <strong>mole ratio</strong> to a <em>gram ratio</em>. </p> <blockquote> <p><mathjax>#(color(darkgreen)(2)color(red)(cancel(color(black)("moles KClO"_3))) * "122.55 g"/(1color(red)(cancel(color(black)("mole KClO"_3)))))/(color(blue)(3)color(red)(cancel(color(black)("moles O"_2))) * "32.0 g"/(1color(red)(cancel(color(black)("mole O"_2))))) = "2.553 g KClO"_3/"1 g O"_2#</mathjax> </p> </blockquote> <p>This means that <strong>for every</strong> <mathjax>#"2.553 g"#</mathjax> of potassium chlorate that undergo combustion, the reaction can <strong>theoretically produce</strong> <mathjax>#"1 g"#</mathjax> of oxygen gas. </p> <p>Now, the problem tells you that you decompose <mathjax>#"2.00 g"#</mathjax> of potassium chlorate. The reaction should <strong>theoretically</strong> produce</p> <blockquote> <p><mathjax>#2.00 color(red)(cancel(color(black)("g KClO"_3))) * "1 g O"_2/(2.553color(red)(cancel(color(black)("g KClO"_3)))) = "0.7834 g O"_2#</mathjax></p> </blockquote> <p>This represents the reaction's <em>theoretical yield</em>. You know that the reaction <strong>actually produced</strong> <mathjax>#"0.720 g"#</mathjax> of oxygen gas, which means that its <em><a href="https://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a></em> was </p> <blockquote> <p><mathjax>#(0.720 color(red)(cancel(color(black)("g O"_2))))/(0.7834color(red)(cancel(color(black)("g O"_2))))xx 100 = color(green)(|bar(ul(color(white)(a/a)color(black)(91.9%)color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#91.9%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by examining the balanced chemical equation that describes this <strong><a href="https://socratic.org/chemistry/chemical-reactions/decomposition-reactions">decomposition reaction</a></strong></p> <blockquote> <p><mathjax>#color(darkgreen)(2)"KClO"_ (3(s)) stackrel(color(white)(acolor(red)(Delta)aaa))(-&gt;) 2"KCl"_ ((s)) + color(blue)(3)"O"_ (2(g))#</mathjax></p> </blockquote> <p>Notice that it takes <mathjax>#color(darkgreen)(2)#</mathjax> <strong>moles</strong> of potassium chlorate to produce <mathjax>#color(blue)(3)#</mathjax> <strong>moles</strong> of oxygen gas. This represents the reaction's <strong>theoretical yield</strong>, i.e. the amount of oxygen gas that you can expect to see for a reaction that has a <mathjax>#100%#</mathjax> <strong><a href="https://socratic.org/chemistry/stoichiometry/percent-yield">yield</a></strong>. </p> <p>The reaction provides you with <em>grams</em> of potassium chlorate, so use the <strong>molar masses</strong> of potassium chlorate and of oxygen gas to convert the <strong>mole ratio</strong> to a <em>gram ratio</em>. </p> <blockquote> <p><mathjax>#(color(darkgreen)(2)color(red)(cancel(color(black)("moles KClO"_3))) * "122.55 g"/(1color(red)(cancel(color(black)("mole KClO"_3)))))/(color(blue)(3)color(red)(cancel(color(black)("moles O"_2))) * "32.0 g"/(1color(red)(cancel(color(black)("mole O"_2))))) = "2.553 g KClO"_3/"1 g O"_2#</mathjax> </p> </blockquote> <p>This means that <strong>for every</strong> <mathjax>#"2.553 g"#</mathjax> of potassium chlorate that undergo combustion, the reaction can <strong>theoretically produce</strong> <mathjax>#"1 g"#</mathjax> of oxygen gas. </p> <p>Now, the problem tells you that you decompose <mathjax>#"2.00 g"#</mathjax> of potassium chlorate. The reaction should <strong>theoretically</strong> produce</p> <blockquote> <p><mathjax>#2.00 color(red)(cancel(color(black)("g KClO"_3))) * "1 g O"_2/(2.553color(red)(cancel(color(black)("g KClO"_3)))) = "0.7834 g O"_2#</mathjax></p> </blockquote> <p>This represents the reaction's <em>theoretical yield</em>. You know that the reaction <strong>actually produced</strong> <mathjax>#"0.720 g"#</mathjax> of oxygen gas, which means that its <em><a href="https://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a></em> was </p> <blockquote> <p><mathjax>#(0.720 color(red)(cancel(color(black)("g O"_2))))/(0.7834color(red)(cancel(color(black)("g O"_2))))xx 100 = color(green)(|bar(ul(color(white)(a/a)color(black)(91.9%)color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A common laboratory preparation for small for quantities of #O_2# is to decompose #KClO_3# by heating: #2KClO_3 (s) -&gt; 2KCl (s) + 3O_2 (g)#. If the decomposition of 2.00 g of #KCIO_3# gives 0.720 g of #O_2#, what is the percent yield for the reaction?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/percent-yield" itemprop="url"> <span class="breadcrumb" itemprop="title">Percent Yield</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="304682" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-09-01T00:08:25" itemprop="dateCreated"> Sep 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#91.9%#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Start by examining the balanced chemical equation that describes this <strong><a href="https://socratic.org/chemistry/chemical-reactions/decomposition-reactions">decomposition reaction</a></strong></p> <blockquote> <p><mathjax>#color(darkgreen)(2)"KClO"_ (3(s)) stackrel(color(white)(acolor(red)(Delta)aaa))(-&gt;) 2"KCl"_ ((s)) + color(blue)(3)"O"_ (2(g))#</mathjax></p> </blockquote> <p>Notice that it takes <mathjax>#color(darkgreen)(2)#</mathjax> <strong>moles</strong> of potassium chlorate to produce <mathjax>#color(blue)(3)#</mathjax> <strong>moles</strong> of oxygen gas. This represents the reaction's <strong>theoretical yield</strong>, i.e. the amount of oxygen gas that you can expect to see for a reaction that has a <mathjax>#100%#</mathjax> <strong><a href="https://socratic.org/chemistry/stoichiometry/percent-yield">yield</a></strong>. </p> <p>The reaction provides you with <em>grams</em> of potassium chlorate, so use the <strong>molar masses</strong> of potassium chlorate and of oxygen gas to convert the <strong>mole ratio</strong> to a <em>gram ratio</em>. </p> <blockquote> <p><mathjax>#(color(darkgreen)(2)color(red)(cancel(color(black)("moles KClO"_3))) * "122.55 g"/(1color(red)(cancel(color(black)("mole KClO"_3)))))/(color(blue)(3)color(red)(cancel(color(black)("moles O"_2))) * "32.0 g"/(1color(red)(cancel(color(black)("mole O"_2))))) = "2.553 g KClO"_3/"1 g O"_2#</mathjax> </p> </blockquote> <p>This means that <strong>for every</strong> <mathjax>#"2.553 g"#</mathjax> of potassium chlorate that undergo combustion, the reaction can <strong>theoretically produce</strong> <mathjax>#"1 g"#</mathjax> of oxygen gas. </p> <p>Now, the problem tells you that you decompose <mathjax>#"2.00 g"#</mathjax> of potassium chlorate. The reaction should <strong>theoretically</strong> produce</p> <blockquote> <p><mathjax>#2.00 color(red)(cancel(color(black)("g KClO"_3))) * "1 g O"_2/(2.553color(red)(cancel(color(black)("g KClO"_3)))) = "0.7834 g O"_2#</mathjax></p> </blockquote> <p>This represents the reaction's <em>theoretical yield</em>. You know that the reaction <strong>actually produced</strong> <mathjax>#"0.720 g"#</mathjax> of oxygen gas, which means that its <em><a href="https://socratic.org/chemistry/stoichiometry/percent-yield">percent yield</a></em> was </p> <blockquote> <p><mathjax>#(0.720 color(red)(cancel(color(black)("g O"_2))))/(0.7834color(red)(cancel(color(black)("g O"_2))))xx 100 = color(green)(|bar(ul(color(white)(a/a)color(black)(91.9%)color(white)(a/a)|)))#</mathjax></p> </blockquote> <p>The answer is rounded to three <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/304682" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ebd02bf3469570e2e62"> Question #e2e62 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec502bf34694a4fee2e"> Question #fee2e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ec902bf34694a4fee32"> Question #fee32 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ece02bf346950519e89"> Question #19e89 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ed302bf34694c8c5bdc"> Question #c5bdc </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d40ee302bf3469517a1065"> Question #a1065 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-26-0-grams-of-c3h9n-were-reacted-with-46-3"> What would be the limiting reagent if 26.0 grams of C3H9N were reacted with 46.3 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-percent-yield-always-less-than-100"> Is percent yield always less than 100? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-would-be-the-limiting-reagent-if-41-9-grams-of-c2h3of-were-reacted-with-61-"> What would be the limiting reagent if 41.9 grams of C2H3OF were reacted with 61.0 grams of... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-percent-yield-of-the-following-reaction-if-60-grams-of-caco3-is-heat"> What is the percent yield of the following reaction if 60 grams of CaCO3 is heated to give 15... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/percent-yield"> See all questions in Percent Yield </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4339 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A common laboratory preparation for small for quantities of #O_2# is to decompose #KClO_3# by heating: #2KClO_3 (s) -&gt; 2KCl (s) + 3O_2 (g)#. If the decomposition of 2.00 g of #KCIO_3# gives 0.720 g of #O_2#, what is the percent yield for the reaction?

a911d3db-6ddd-11ea-a62a-ccda262736ce

https://socratic.org/questions/how-do-you-balance-nh3-o2-no2-h2o-the-number-in-the-parenthasis-are-subscribts-t

4 NH3 + 7 O2 -> 4 NO2 + 6 H2O

start chemical_equation qc_end chemical_equation 4 10 qc_end end

[{"type":"other","value":"Chemical Equation [OF] the equation"}]

[{"type":"chemical equation","value":"4 NH3 + 7 O2 -> 4 NO2 + 6 H2O"}]

[{"type":"chemical equation","value":"NH3 + O2 -> NO2 + H2O"}]

<h1 class="questionTitle" itemprop="name">How do you balance __ NH3 + __O2--&gt; __NO2 + __H2O? The number in the parenthasis are subscribts, thank you all so much!!!?</h1>

4 NH3 + 7 O2 -> 4 NO2 + 6 H2O

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>There is no fixed method actually. You have to take a random number as the number of molecules for <mathjax>#NH_3#</mathjax>, then calculate result. </p> <p>As for here, I have taken <mathjax>#4#</mathjax> as the number of molecules of <mathjax>#NH_3#</mathjax>. That means <mathjax>#4#</mathjax> nitrogen atoms and <mathjax>#12#</mathjax> hydrogen atoms are taking part in this reaction.</p> <p>Now, hydrogen atoms are present only in <mathjax>#H_2O#</mathjax> as a product in this reaction. So that makes <mathjax>#6#</mathjax> molecules of <mathjax>#H_2O#</mathjax> (as there are <mathjax>#12#</mathjax> hydrogen atoms). </p> <p>Now, when we calculated the number of molecules of <mathjax>#H_2O#</mathjax>, we also got the number of oxygen atoms present there.</p> <p>On the other hand, as there are <mathjax>#4#</mathjax> molecules of <mathjax>#NH_3#</mathjax>, there has to be <mathjax>#4#</mathjax> molecules of <mathjax>#NO_2#</mathjax> as well to balance the number of nitrogen atoms in both side of the reaction.</p> <p>That makes <mathjax>#8#</mathjax> another atoms of oxygen. </p> <p>So now the total number of oxygen atoms is <mathjax>#(8+6)#</mathjax> or <mathjax>#14#</mathjax>, which means <mathjax>#14#</mathjax> atoms or <mathjax>#7#</mathjax> molecules of oxygen.</p> <p>So the final balanced reaction is :</p> <blockquote> <p><mathjax>#4NH_3 + 7O_2 -&gt; 4NO_2 + 6H_2O#</mathjax></p> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4NH_3 + 7O_2 -&gt; 4NO_2 + 6H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>There is no fixed method actually. You have to take a random number as the number of molecules for <mathjax>#NH_3#</mathjax>, then calculate result. </p> <p>As for here, I have taken <mathjax>#4#</mathjax> as the number of molecules of <mathjax>#NH_3#</mathjax>. That means <mathjax>#4#</mathjax> nitrogen atoms and <mathjax>#12#</mathjax> hydrogen atoms are taking part in this reaction.</p> <p>Now, hydrogen atoms are present only in <mathjax>#H_2O#</mathjax> as a product in this reaction. So that makes <mathjax>#6#</mathjax> molecules of <mathjax>#H_2O#</mathjax> (as there are <mathjax>#12#</mathjax> hydrogen atoms). </p> <p>Now, when we calculated the number of molecules of <mathjax>#H_2O#</mathjax>, we also got the number of oxygen atoms present there.</p> <p>On the other hand, as there are <mathjax>#4#</mathjax> molecules of <mathjax>#NH_3#</mathjax>, there has to be <mathjax>#4#</mathjax> molecules of <mathjax>#NO_2#</mathjax> as well to balance the number of nitrogen atoms in both side of the reaction.</p> <p>That makes <mathjax>#8#</mathjax> another atoms of oxygen. </p> <p>So now the total number of oxygen atoms is <mathjax>#(8+6)#</mathjax> or <mathjax>#14#</mathjax>, which means <mathjax>#14#</mathjax> atoms or <mathjax>#7#</mathjax> molecules of oxygen.</p> <p>So the final balanced reaction is :</p> <blockquote> <p><mathjax>#4NH_3 + 7O_2 -&gt; 4NO_2 + 6H_2O#</mathjax></p> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you balance __ NH3 + __O2--&gt; __NO2 + __H2O? The number in the parenthasis are subscribts, thank you all so much!!!?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/balancing-chemical-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Balancing Chemical Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="179376" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/jahan-psyche"><img alt="" class="" src="https://profilepictures.socratic.org/WSRftNQRSGkDaYJKW0Uc_IMG_2553pic.jpg" title=""/></a> <a class="secondContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/jahan-psyche"> Jahan Psyche </a>·<a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-23T14:42:31" itemprop="dateCreated"> Oct 23, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#4NH_3 + 7O_2 -&gt; 4NO_2 + 6H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>There is no fixed method actually. You have to take a random number as the number of molecules for <mathjax>#NH_3#</mathjax>, then calculate result. </p> <p>As for here, I have taken <mathjax>#4#</mathjax> as the number of molecules of <mathjax>#NH_3#</mathjax>. That means <mathjax>#4#</mathjax> nitrogen atoms and <mathjax>#12#</mathjax> hydrogen atoms are taking part in this reaction.</p> <p>Now, hydrogen atoms are present only in <mathjax>#H_2O#</mathjax> as a product in this reaction. So that makes <mathjax>#6#</mathjax> molecules of <mathjax>#H_2O#</mathjax> (as there are <mathjax>#12#</mathjax> hydrogen atoms). </p> <p>Now, when we calculated the number of molecules of <mathjax>#H_2O#</mathjax>, we also got the number of oxygen atoms present there.</p> <p>On the other hand, as there are <mathjax>#4#</mathjax> molecules of <mathjax>#NH_3#</mathjax>, there has to be <mathjax>#4#</mathjax> molecules of <mathjax>#NO_2#</mathjax> as well to balance the number of nitrogen atoms in both side of the reaction.</p> <p>That makes <mathjax>#8#</mathjax> another atoms of oxygen. </p> <p>So now the total number of oxygen atoms is <mathjax>#(8+6)#</mathjax> or <mathjax>#14#</mathjax>, which means <mathjax>#14#</mathjax> atoms or <mathjax>#7#</mathjax> molecules of oxygen.</p> <p>So the final balanced reaction is :</p> <blockquote> <p><mathjax>#4NH_3 + 7O_2 -&gt; 4NO_2 + 6H_2O#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/179376" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="179585" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/nikka-c"><img alt="" class="" src="https://profilepictures.socratic.org/AQ8VOCyTM1J7U0TvIWhw_nkahara.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/nikka-c"> Nikka C. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-24T12:24:13" itemprop="dateCreated"> Oct 24, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Two possible answers: (1) <mathjax>#2NH_3#</mathjax> + <mathjax>#7/2O_2#</mathjax> = <mathjax>#2NO_2#</mathjax> + <mathjax>#3H_2O#</mathjax> or (2) <mathjax>#4NH_3#</mathjax> + <mathjax>#7O_2#</mathjax> = <mathjax>#4NO_2#</mathjax> + <mathjax>#6H_2O#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First, you need to tally all the atoms.</p> <p><mathjax>#NH_3#</mathjax> + <mathjax>#O_2#</mathjax> = <mathjax>#NO_2#</mathjax> + <mathjax>#H_2O#</mathjax></p> <p><em>Left side:</em><br/> N = 1<br/> H = 3<br/> O = 2</p> <p><em>Right side:</em><br/> N = 1<br/> H = 2<br/> O = 2 + 1 (two from the <mathjax>#NO_2#</mathjax> and one from <mathjax>#H_2O#</mathjax> ; <strong>DO NOT ADD IT UP YET</strong> )</p> <p>You always have to find the simplest element that you can balance (in this case, the H).</p> <p><em>Left side:</em><br/> N = 1 x 2 = <strong>2</strong><br/> H = 3 x 2 = <strong>6</strong><br/> O = 2</p> <p><em>Right side:</em><br/> N = <strong>1</strong><br/> H = 2 x 3 = <strong>6</strong><br/> O = 2 + (1 x 3) from the O in <mathjax>#H_2O#</mathjax></p> <p>Notice that with balancing the atoms, you do not forget that they are part of a substance - meaning, you have to multiply everything. </p> <p><mathjax>#2NH_3#</mathjax> + <mathjax>#O_2#</mathjax> = <mathjax>#NO_2#</mathjax> + <mathjax>#3H_2O#</mathjax></p> <p>Now, the N is not balanced so you need to multiply the right side N by 2.</p> <p><em>Left side:</em><br/> N = 1 x 2 = <strong>2</strong><br/> H = 3 x 2 = <strong>6</strong><br/> O = 2</p> <p><em>Right side:</em><br/> N = 1 x 2 = <strong>2</strong><br/> H = 2 x 3 = <strong>6</strong><br/> O = (2 x 2) + (1 x 3) = 7</p> <p><mathjax>#2NH_3#</mathjax> + <mathjax>#O_2#</mathjax> = <mathjax>#2NO_2#</mathjax> + <mathjax>#3H_2O#</mathjax></p> <p>Now, the only element left to be balanced is O. Since 7 is an odd number, you can use a fraction for the equation to be in its reduced form. </p> <p><em>Left side:</em><br/> N = 1 x 2 = <strong>2</strong><br/> H = 3 x 2 = <strong>6</strong><br/> O = 2 x 3.5 = <strong>7</strong> (the decimal 3.5 can be written as <mathjax>#7/2#</mathjax>)</p> <p><em>Right side:</em><br/> N = 1 x 2 = <strong>2</strong><br/> H = 2 x 3 = <strong>6</strong><br/> O = (2 x 2) + (1 x 3) = <strong>7</strong> </p> <p>Hence,</p> <p><mathjax>#2NH_3#</mathjax> + <mathjax>#7/2O_2#</mathjax> = <mathjax>#2NO_2#</mathjax> + <mathjax>#3H_2O#</mathjax></p> <p>but if you want the equation to show whole numbers only, you can always multiply everything by the denominator in the fraction.</p> <p><strong><mathjax>#(cancel 2)#</mathjax></strong> [<mathjax>#2NH_3#</mathjax> + <mathjax>#7/(cancel 2)O_2#</mathjax> = <mathjax>#2NO_2#</mathjax> + <mathjax>#3H_2O#</mathjax>]</p> <p>=</p> <p><mathjax>#4NH_3#</mathjax> + <mathjax>#7O_2#</mathjax> = <mathjax>#4NO_2#</mathjax> + <mathjax>#6H_2O#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/179585" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-balancing-equations-which-numbers-are-you-allowed-to-change-why-only-these"> When balancing equations, which numbers are you allowed to change? why only these? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-i-get-the-chemical-equation-of-aniline-to-phenylisocyanide"> How do I get the chemical equation of aniline to phenylisocyanide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-balanced-equation"> What is a balanced equation? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/can-you-write-a-balanced-equation-for-bcl3-g-h2o-l-h3bo3-s-hcl-g"> Can you write a balanced equation for BCl3 (g)+H2O (l)-------&gt; H3BO3 (s)+HCl (g)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-balanced-equation-for-the-chemical-reaction-mg3n2-2h2o-mg-oh-2-nh3"> What is the balanced equation for the chemical reaction #Mg_3N_2+2H_2O -&gt; Mg(OH)_2+NH_3#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-chemical-equations-need-to-be-balanced"> Why do chemical equations need to be balanced? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-balance-this-chemical-equations-aluminum-and-hydrochloric-acid-react-t"> How can I balance this chemical equations? 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How do you balance __ NH3 + __O2--&gt; __NO2 + __H2O? The number in the parenthasis are subscribts, thank you all so much!!!?

a83d4c34-6ddd-11ea-8d5e-ccda262736ce

https://socratic.org/questions/58e54ff97c0149694e54e5e4

0.05 mol/L

start physical_unit 19 19 volume mol/l qc_end physical_unit 10 12 6 7 mass qc_end physical_unit 19 19 15 16 volume qc_end end

[{"type":"physical unit","value":"Volume [OF] copper sulfate pentahydrate solution [IN] mol/L"}]

[{"type":"physical unit","value":"0.05 mol/L"}]

[{"type":"physical unit","value":"Mass [OF] copper sulfate pentahydrate [=] \\pu{1.24 g}"},{"type":"physical unit","value":"Volume [OF] solution [=] \\pu{100 cm^3}"}]

<h1 class="questionTitle" itemprop="name">What is the formality of a #1.24*g# mass of #"copper sulfate pentahydrate"# in a #100*cm^3# volume of solution?</h1>

0.05 mol/L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration of sodium thiosulfate pentahydrate:"#</mathjax></p> <p><mathjax>#-=#</mathjax> <mathjax>#((1.24*g)/(248.18*g*mol^-1))/(100*cm^3xx10^-3*cm^-3*L)#</mathjax></p> <p><mathjax>#=0.0500*mol*L^-1#</mathjax> WITH RESPECT TO THE PENTAHYDRATE. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Formality"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute"/"Volume of solution (L)"=0.05*mol*L^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration of sodium thiosulfate pentahydrate:"#</mathjax></p> <p><mathjax>#-=#</mathjax> <mathjax>#((1.24*g)/(248.18*g*mol^-1))/(100*cm^3xx10^-3*cm^-3*L)#</mathjax></p> <p><mathjax>#=0.0500*mol*L^-1#</mathjax> WITH RESPECT TO THE PENTAHYDRATE. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the formality of a #1.24*g# mass of #"copper sulfate pentahydrate"# in a #100*cm^3# volume of solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="403215" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-07T15:40:40" itemprop="dateCreated"> Apr 7, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Formality"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute"/"Volume of solution (L)"=0.05*mol*L^-1#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration of sodium thiosulfate pentahydrate:"#</mathjax></p> <p><mathjax>#-=#</mathjax> <mathjax>#((1.24*g)/(248.18*g*mol^-1))/(100*cm^3xx10^-3*cm^-3*L)#</mathjax></p> <p><mathjax>#=0.0500*mol*L^-1#</mathjax> WITH RESPECT TO THE PENTAHYDRATE. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/403215" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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What is the formality of a #1.24*g# mass of #"copper sulfate pentahydrate"# in a #100*cm^3# volume of solution?

ac30dc58-6ddd-11ea-898e-ccda262736ce

https://socratic.org/questions/a-250-ml-sample-of-oxygen-is-collected-over-water-at-25-c-and-760-0-torr-pressur

736.20 mmHg

start physical_unit 22 24 pressure mmhg qc_end physical_unit 3 5 1 2 volume qc_end physical_unit 3 5 11 12 temperature qc_end physical_unit 3 5 14 15 pressure qc_end end

[{"type":"physical unit","value":"Pressure [OF] the dry gas [IN] mmHg"}]

[{"type":"physical unit","value":"736.20 mmHg"}]

[{"type":"physical unit","value":"Volume [OF] oxygen sample [=] \\pu{250 mL}"},{"type":"physical unit","value":"Temperature [OF] oxygen sample [=] \\pu{25 ℃}"},{"type":"physical unit","value":"Pressure [OF] oxygen sample [=] \\pu{760.0 torr}"},{"type":"substance name","value":"Water "}]

<h1 class="questionTitle" itemprop="name">A 250 mL sample of oxygen is collected over water at 25°C and 760.0 torr pressure. What is the pressure of the dry gas alone? </h1>

736.20 mmHg

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The gas collected over water consists of (i) whatever the gas is, and (ii) the saturated vapour pressure. At <mathjax>#25#</mathjax> <mathjax>#""^@C#</mathjax>, <mathjax>#"SVP"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#23.8#</mathjax> <mathjax>#mm*Hg#</mathjax>. At higher temperatures, how would you expect <mathjax>#"SVP"#</mathjax> to evolve.</p> <p>Thus the pressure exerted by the gas is thus <mathjax>#(760-23.8)*mm*Hg#</mathjax>.</p> <p><mathjax>#"SVP"#</mathjax> would always be given in such a problem. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You need to know the <mathjax>#"saturated vapour pressure"#</mathjax> of water at <mathjax>#25#</mathjax> <mathjax>#""^@C#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The gas collected over water consists of (i) whatever the gas is, and (ii) the saturated vapour pressure. At <mathjax>#25#</mathjax> <mathjax>#""^@C#</mathjax>, <mathjax>#"SVP"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#23.8#</mathjax> <mathjax>#mm*Hg#</mathjax>. At higher temperatures, how would you expect <mathjax>#"SVP"#</mathjax> to evolve.</p> <p>Thus the pressure exerted by the gas is thus <mathjax>#(760-23.8)*mm*Hg#</mathjax>.</p> <p><mathjax>#"SVP"#</mathjax> would always be given in such a problem. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A 250 mL sample of oxygen is collected over water at 25°C and 760.0 torr pressure. What is the pressure of the dry gas alone? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/ideal-gas-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Ideal Gas Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="260335" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-04-29T18:57:59" itemprop="dateCreated"> Apr 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You need to know the <mathjax>#"saturated vapour pressure"#</mathjax> of water at <mathjax>#25#</mathjax> <mathjax>#""^@C#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The gas collected over water consists of (i) whatever the gas is, and (ii) the saturated vapour pressure. At <mathjax>#25#</mathjax> <mathjax>#""^@C#</mathjax>, <mathjax>#"SVP"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#23.8#</mathjax> <mathjax>#mm*Hg#</mathjax>. At higher temperatures, how would you expect <mathjax>#"SVP"#</mathjax> to evolve.</p> <p>Thus the pressure exerted by the gas is thus <mathjax>#(760-23.8)*mm*Hg#</mathjax>.</p> <p><mathjax>#"SVP"#</mathjax> would always be given in such a problem. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/260335" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-the-ideal-gas-constant"> How do you find the ideal gas constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-solve-ideal-gas-law-problems"> How do you solve ideal gas law problems? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-to-know-which-ideal-gas-constant-to-use"> How do you know which ideal gas constant to use? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ideal-gas-constant-for-butane"> What is the ideal gas constant for butane? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-ideal-gas-law-in-kelvin"> Why is ideal gas law in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-ideal-gas-constant-important"> Why is the ideal gas constant important? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-di-electric-constant"> What is the di-electric constant? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-volume-l-will-0-20-mol-hi-occupy-at-300-k-and-100-0-kpa-r-8-314-kpa-l-k-mol"> What volume (L) will 0.20 mol HI occupy at 300 K and 100.0 kPa? R = 8.314 kPa L / (K mol) =... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-molar-mass-of-a-gas"> How do you calculate the molar mass of a gas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/when-should-i-use-the-ideal-gas-law-and-not-the-combined-gas-law"> When should I use the ideal gas law and not the combined gas law? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/ideal-gas-law"> See all questions in Ideal Gas Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 16600 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A 250 mL sample of oxygen is collected over water at 25°C and 760.0 torr pressure. What is the pressure of the dry gas alone?

aad5d492-6ddd-11ea-b8c4-ccda262736ce

https://socratic.org/questions/when-4-22-moles-of-al-reacts-with-5-0-moles-of-hbr-how-many-moles-of-h-2-are-for

2.5 moles

start physical_unit 15 15 mole mol qc_end physical_unit 4 4 1 2 mole qc_end physical_unit 10 10 7 8 mole qc_end end

[{"type":"physical unit","value":"Mole [OF] H2 [IN] moles"}]

[{"type":"physical unit","value":"2.5 moles"}]

[{"type":"physical unit","value":"Mole [OF] Al [=] \\pu{4.22 moles}"},{"type":"physical unit","value":"Mole [OF] HBr [=] \\pu{5.0 moles}"}]

<h1 class="questionTitle" itemprop="name">When 4.22 moles of #Al# reacts with 5.0 moles of #HBr#, how many moles of #H_2# are formed?</h1>

2.5 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First write a balanced chemical equation for the reaction of the metal with the acid :</p> <p><mathjax>#2Al+6HBr-&gt;2AlBr_3+3H_2#</mathjax>.</p> <p>This represents <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio in which the reactants combine and in which the products are formed.</p> <p>Since <mathjax>#2#</mathjax> moles <mathjax>#Al#</mathjax> requires <mathjax>#6#</mathjax> moles <mathjax>#HBr#</mathjax>, it implies that, given <mathjax>#4.22#</mathjax> moles <mathjax>#Al#</mathjax> and <mathjax>#5.0#</mathjax> moles <mathjax>#HBr#</mathjax>, then <mathjax>#HBr#</mathjax> is in excess and <mathjax>#Al#</mathjax> is the <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>.</p> <p>Hence all <mathjax>#5.0 mol HBr#</mathjax> will react with <mathjax>#5.0/3=1.667mol Al#</mathjax> to form <mathjax>#1.667mol AlBr_3#</mathjax> and <mathjax>#5.0/2=2.5 mol H_2#</mathjax> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.5mol#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First write a balanced chemical equation for the reaction of the metal with the acid :</p> <p><mathjax>#2Al+6HBr-&gt;2AlBr_3+3H_2#</mathjax>.</p> <p>This represents <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio in which the reactants combine and in which the products are formed.</p> <p>Since <mathjax>#2#</mathjax> moles <mathjax>#Al#</mathjax> requires <mathjax>#6#</mathjax> moles <mathjax>#HBr#</mathjax>, it implies that, given <mathjax>#4.22#</mathjax> moles <mathjax>#Al#</mathjax> and <mathjax>#5.0#</mathjax> moles <mathjax>#HBr#</mathjax>, then <mathjax>#HBr#</mathjax> is in excess and <mathjax>#Al#</mathjax> is the <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>.</p> <p>Hence all <mathjax>#5.0 mol HBr#</mathjax> will react with <mathjax>#5.0/3=1.667mol Al#</mathjax> to form <mathjax>#1.667mol AlBr_3#</mathjax> and <mathjax>#5.0/2=2.5 mol H_2#</mathjax> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">When 4.22 moles of #Al# reacts with 5.0 moles of #HBr#, how many moles of #H_2# are formed?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="245523" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/trevor-r-1"><img alt="" class="" src="https://profilepictures.socratic.org/2Wf9lLD9RaSzPbXY0EW8_S5002678.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/trevor-r-1"> Trevor Ryan. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-26T19:34:15" itemprop="dateCreated"> Mar 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.5mol#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>First write a balanced chemical equation for the reaction of the metal with the acid :</p> <p><mathjax>#2Al+6HBr-&gt;2AlBr_3+3H_2#</mathjax>.</p> <p>This represents <a href="http://socratic.org/chemistry/the-mole-concept/the-mole">the mole</a> ratio in which the reactants combine and in which the products are formed.</p> <p>Since <mathjax>#2#</mathjax> moles <mathjax>#Al#</mathjax> requires <mathjax>#6#</mathjax> moles <mathjax>#HBr#</mathjax>, it implies that, given <mathjax>#4.22#</mathjax> moles <mathjax>#Al#</mathjax> and <mathjax>#5.0#</mathjax> moles <mathjax>#HBr#</mathjax>, then <mathjax>#HBr#</mathjax> is in excess and <mathjax>#Al#</mathjax> is the <a href="http://socratic.org/chemistry/stoichiometry/limiting-reagent">limiting reagent</a>.</p> <p>Hence all <mathjax>#5.0 mol HBr#</mathjax> will react with <mathjax>#5.0/3=1.667mol Al#</mathjax> to form <mathjax>#1.667mol AlBr_3#</mathjax> and <mathjax>#5.0/2=2.5 mol H_2#</mathjax> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/245523" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="245525" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-26T19:36:22" itemprop="dateCreated"> Mar 26, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#2.5#</mathjax> <mathjax>#mol#</mathjax> dihydrogen gas are formed. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#Al(s) + 3HBr(aq) rarr AlBr_3(aq) + 3/2H_2(g)uarr#</mathjax></p> <p>Clearly, hydrobromic acid is in deficiency (complete rxn requires <mathjax>#&gt;12*mol#</mathjax> <mathjax>#HBr#</mathjax>). From the equation, <mathjax>#1/2#</mathjax> <mathjax>#mol#</mathjax> dihydrogen gas are evolved per mole of <mathjax>#HBr#</mathjax>. Since <mathjax>#5#</mathjax> <mathjax>#mol#</mathjax> <mathjax>#HBr#</mathjax> are used, half of this quantity of <mathjax>#H_2#</mathjax> evolve. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/245525" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179102bf3469517a1072"> Question #a1072 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179402bf34694c8c5bf1"> Question #c5bf1 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179702bf3469588dc373"> Question #dc373 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179c02bf34694c8c5bf9"> Question #c5bf9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417a302bf3469517a1076"> Question #a1076 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417c702bf3469588dc377"> Question #dc377 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d002bf346963eb984f"> Question #b984f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d402bf346950519ea3"> Question #19ea3 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/mole-ratios"> See all questions in Mole Ratios </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1643 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

When 4.22 moles of #Al# reacts with 5.0 moles of #HBr#, how many moles of #H_2# are formed?

aacac046-6ddd-11ea-84ba-ccda262736ce

https://socratic.org/questions/if-you-have-3-mol-of-glucose-in-6-l-of-solution-what-is-the-molarity-of-the-solu

0.50 M

start physical_unit 17 18 molarity mol/l qc_end physical_unit 6 6 3 4 mole qc_end physical_unit 11 11 8 9 volume qc_end end

[{"type":"physical unit","value":"Molarity [OF] the solution [IN] M"}]

[{"type":"physical unit","value":"0.50 M"}]

[{"type":"physical unit","value":"Mole [OF] glucose [=] \\pu{3 mol}"},{"type":"physical unit","value":"Volume [OF] glucose solution [=] \\pu{6 L}"}]

<h1 class="questionTitle" itemprop="name">If you have 3 mol of glucose in 6 L of solution, what is the molarity of the solution? </h1>

0.50 M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity"="Moles of solute"/"Volume of solution"#</mathjax></p> <p>And here, this quotient is <mathjax>#(3*mol)/(6*L)=0.5*mol*L^-1#</mathjax> WITH RESPECT to GLUCOSE.............</p> <p>Given that glucose, <mathjax>#C_6H_12O_6#</mathjax>, has a molar mass of <mathjax>#180.2*g*mol^-1#</mathjax>, what is the concentration of this solution with respect to <mathjax>#g*L^-1#</mathjax>?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Why <mathjax>#0.5*mol*L^-1#</mathjax>..............</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity"="Moles of solute"/"Volume of solution"#</mathjax></p> <p>And here, this quotient is <mathjax>#(3*mol)/(6*L)=0.5*mol*L^-1#</mathjax> WITH RESPECT to GLUCOSE.............</p> <p>Given that glucose, <mathjax>#C_6H_12O_6#</mathjax>, has a molar mass of <mathjax>#180.2*g*mol^-1#</mathjax>, what is the concentration of this solution with respect to <mathjax>#g*L^-1#</mathjax>?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If you have 3 mol of glucose in 6 L of solution, what is the molarity of the solution? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="402767" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-06T19:19:22" itemprop="dateCreated"> Apr 6, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>Why <mathjax>#0.5*mol*L^-1#</mathjax>..............</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Molarity"="Moles of solute"/"Volume of solution"#</mathjax></p> <p>And here, this quotient is <mathjax>#(3*mol)/(6*L)=0.5*mol*L^-1#</mathjax> WITH RESPECT to GLUCOSE.............</p> <p>Given that glucose, <mathjax>#C_6H_12O_6#</mathjax>, has a molar mass of <mathjax>#180.2*g*mol^-1#</mathjax>, what is the concentration of this solution with respect to <mathjax>#g*L^-1#</mathjax>?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/402767" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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If you have 3 mol of glucose in 6 L of solution, what is the molarity of the solution?

a96c988b-6ddd-11ea-811c-ccda262736ce

https://socratic.org/questions/if-i-inhale-2-20-l-of-gas-at-a-temperature-of-18-c-at-a-pressure-of-1-50-atm-how

0.14 moles

start physical_unit 6 6 mole mol qc_end physical_unit 6 6 3 4 volume qc_end physical_unit 6 6 11 12 temperature qc_end physical_unit 6 6 17 18 pressure qc_end end

[{"type":"physical unit","value":"Mole [OF] gas [IN] moles"}]

[{"type":"physical unit","value":"0.14 moles"}]

[{"type":"physical unit","value":"Volume [OF] gas [=] \\pu{2.20 L}"},{"type":"physical unit","value":"Temperature [OF] gas [=] \\pu{18 ℃}"},{"type":"physical unit","value":"Pressure [OF] gas [=] \\pu{1.50 atm}"}]

<h1 class="questionTitle" itemprop="name">If I inhale 2.20 L of gas at a temperature of 18°C at a pressure of 1.50 atm, how many moles of gas were inhaled?</h1>

0.14 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You will need the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> to answer this question. The formula for the ideal gas law is:<br/> <img alt="https://jahschem.wikispaces.com/ideal+gas+law" src="https://useruploads.socratic.org/hq2dzSNiRPO7oyLXJ3qv_ideal.png%22%3B+size%3D%2231420"/> </p> <p><strong>Known</strong><br/> <mathjax>#P="1.50 atm"#</mathjax><br/> <mathjax>#V="2.20 L"#</mathjax><br/> <mathjax>#R="0.082057338 L atm K"^(-1) "mol"^(-1)"#</mathjax><br/> <mathjax>#T="18"^@"C"+"273.15 K=291 K"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#n#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the formula to isolate <mathjax>#n#</mathjax>. Substitute the known values into the formula and solve.</p> <p><mathjax>#n=(PV)/(RT)#</mathjax></p> <p><mathjax>#n=(1.50cancel"atm"xx2.20cancel"L")/(0.082057338cancel"L" cancel"atm" cancel"K"^(-1) "mol"^(-1)xx291cancel"K")="0.138 mol"#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#n="0.138 mol"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You will need the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> to answer this question. The formula for the ideal gas law is:<br/> <img alt="https://jahschem.wikispaces.com/ideal+gas+law" src="https://useruploads.socratic.org/hq2dzSNiRPO7oyLXJ3qv_ideal.png%22%3B+size%3D%2231420"/> </p> <p><strong>Known</strong><br/> <mathjax>#P="1.50 atm"#</mathjax><br/> <mathjax>#V="2.20 L"#</mathjax><br/> <mathjax>#R="0.082057338 L atm K"^(-1) "mol"^(-1)"#</mathjax><br/> <mathjax>#T="18"^@"C"+"273.15 K=291 K"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#n#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the formula to isolate <mathjax>#n#</mathjax>. Substitute the known values into the formula and solve.</p> <p><mathjax>#n=(PV)/(RT)#</mathjax></p> <p><mathjax>#n=(1.50cancel"atm"xx2.20cancel"L")/(0.082057338cancel"L" cancel"atm" cancel"K"^(-1) "mol"^(-1)xx291cancel"K")="0.138 mol"#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If I inhale 2.20 L of gas at a temperature of 18°C at a pressure of 1.50 atm, how many moles of gas were inhaled?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/gas-laws" itemprop="url"> <span class="breadcrumb" itemprop="title">Gas Laws</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="316741" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-01T21:49:44" itemprop="dateCreated"> Oct 1, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#n="0.138 mol"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>You will need the <a href="https://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> to answer this question. The formula for the ideal gas law is:<br/> <img alt="https://jahschem.wikispaces.com/ideal+gas+law" src="https://useruploads.socratic.org/hq2dzSNiRPO7oyLXJ3qv_ideal.png%22%3B+size%3D%2231420"/> </p> <p><strong>Known</strong><br/> <mathjax>#P="1.50 atm"#</mathjax><br/> <mathjax>#V="2.20 L"#</mathjax><br/> <mathjax>#R="0.082057338 L atm K"^(-1) "mol"^(-1)"#</mathjax><br/> <mathjax>#T="18"^@"C"+"273.15 K=291 K"#</mathjax></p> <p><strong>Unknown</strong><br/> <mathjax>#n#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the formula to isolate <mathjax>#n#</mathjax>. Substitute the known values into the formula and solve.</p> <p><mathjax>#n=(PV)/(RT)#</mathjax></p> <p><mathjax>#n=(1.50cancel"atm"xx2.20cancel"L")/(0.082057338cancel"L" cancel"atm" cancel"K"^(-1) "mol"^(-1)xx291cancel"K")="0.138 mol"#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/316741" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-boyles-law-relate-to-breathing"> How does Boyle's law relate to breathing? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/in-avogadro-s-law-what-would-happen-to-v-if-n-is-increased-decreased-and-what-wo"> In Avogadro's Law what would happen to V if N is increased/decreased? 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If the gas is compressed to 23.52 L and the... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-r-stand-for-in-the-ideal-gas-law-pv-nrt"> What does the R stand for in the ideal gas law (PV=nRT)? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-mass-of-a-gas-that-occupies-48-9-liters-has-a-pressure-of-724-torr-a"> What is the mass of a gas that occupies 48.9 liters, has a pressure of 724 torr, a temperature... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/if-a-sample-of-neon-gas-occupies-a-volume-of-2-8l-at-1-8-atm-what-will-its-volum"> If a sample of neon gas occupies a volume of 2.8L at 1.8 atm. what will its volume be at 1.2 atm? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/gas-laws"> See all questions in Gas Laws </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1466 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

If I inhale 2.20 L of gas at a temperature of 18°C at a pressure of 1.50 atm, how many moles of gas were inhaled?

ac21bfa2-6ddd-11ea-9c0b-ccda262736ce

https://socratic.org/questions/a-gas-has-a-volume-of-2-00-l-at-323-k-and-3-00-atm-what-will-be-the-new-volume-i

5.07 L

start physical_unit 1 1 volume l qc_end physical_unit 1 1 6 7 volume qc_end physical_unit 1 1 12 13 pressure qc_end physical_unit 1 1 34 35 pressure qc_end physical_unit 1 1 9 10 temperature qc_end physical_unit 1 1 26 27 temperature qc_end end

[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] L"}]

[{"type":"physical unit","value":"5.07 L"}]

[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{2.00 L}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{3.00 atm}"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{1 atm}"},{"type":"physical unit","value":"Temperature1 [OF] the gas [=] \\pu{323 K}"},{"type":"physical unit","value":"Temperature2 [OF] the gas [=] \\pu{273 K}"}]

<h1 class="questionTitle" itemprop="name">A gas has a volume of 2.00 L at 323 K and 3.00 atm. What will be the new volume if the temperature is changed to 273 K and the pressure is changed to 1 atm?</h1>

5.07 L

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So <mathjax>#V_2 =(P_1V_1T_2)/(P_2T_1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1.00*cancel(atm)xx2.00*L*273*cancelK)/(3.00*cancel(atm)xx323*cancelK)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??L#</mathjax>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a>: <mathjax>#(P_1V_1)/T_1 =(P_2V_2)/T_2 #</mathjax>. The volume should reasonably REDUCE on compression and cooling. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So <mathjax>#V_2 =(P_1V_1T_2)/(P_2T_1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1.00*cancel(atm)xx2.00*L*273*cancelK)/(3.00*cancel(atm)xx323*cancelK)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??L#</mathjax>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">A gas has a volume of 2.00 L at 323 K and 3.00 atm. What will be the new volume if the temperature is changed to 273 K and the pressure is changed to 1 atm?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/charles-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Charles' Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="230617" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-02-24T20:07:22" itemprop="dateCreated"> Feb 24, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>We use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/combined-gas-law">combined gas law</a>: <mathjax>#(P_1V_1)/T_1 =(P_2V_2)/T_2 #</mathjax>. The volume should reasonably REDUCE on compression and cooling. </p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>So <mathjax>#V_2 =(P_1V_1T_2)/(P_2T_1)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(1.00*cancel(atm)xx2.00*L*273*cancelK)/(3.00*cancel(atm)xx323*cancelK)#</mathjax> <mathjax>#=#</mathjax> <mathjax>#??L#</mathjax>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/230617" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-must-charles-law-be-in-kelvins"> Why must Charles' law be in kelvin? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-charles-law-formula"> What is Charles' law formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/oxygen-gas-is-at-a-temperature-of-40-c-when-it-occupies-a-volume-of-2-3-liters-t"> Oxygen gas is at a temperature of 40°C when it occupies a volume of 2.3 liters. 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What will be volume of oxygen when the... </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-behavior-of-gases/charles-law"> See all questions in Charles' Law </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 14352 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

A gas has a volume of 2.00 L at 323 K and 3.00 atm. What will be the new volume if the temperature is changed to 273 K and the pressure is changed to 1 atm?

a9ce3548-6ddd-11ea-94ce-ccda262736ce

https://socratic.org/questions/what-is-the-molecular-mass-of-a-compound-if-560ml-have-a-mass-of-1-10g-at-stp

44.59 g/mol

start physical_unit 6 7 molecular_weight g/mol qc_end physical_unit 6 7 9 10 volume qc_end physical_unit 6 7 15 16 mass qc_end c_other STP qc_end end

[{"type":"physical unit","value":"Molecular mass [OF] a compound [IN] g/mol"}]

[{"type":"physical unit","value":"44.59 g/mol"}]

[{"type":"physical unit","value":"Volume [OF] a compound [=] \\pu{560 mL}"},{"type":"physical unit","value":"Mass [OF] a compound [=] \\pu{1.10 g}"},{"type":"other","value":"STP"}]

<h1 class="questionTitle" itemprop="name">What is the molecular mass of a compound if 560mL have a mass of 1.10g at STP? </h1>

44.59 g/mol

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Note: This is going to be a long answer.</p> <p><strong>First determine the number of moles.</strong></p> <p><mathjax>#"STP=273.15 K and 100 kPa"#</mathjax></p> <p><strong>Use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>.</strong></p> <p><mathjax>#PV=nRT#</mathjax>, <br/> where <mathjax>#P#</mathjax> is pressure in kiloPascals <mathjax>#("kPa")#</mathjax>, <mathjax>#V#</mathjax> is volume in liters <mathjax>#("L")#</mathjax>, <mathjax>#n#</mathjax> is moles, <mathjax>#R#</mathjax> is the gas constant, and <mathjax>#T#</mathjax> is temperature in Kelvins <mathjax>#("K")#</mathjax>.</p> <p><strong>Given/Known</strong></p> <p><mathjax>#P="100 kPa"#</mathjax></p> <p><mathjax>#T="273.15 K"#</mathjax></p> <p><mathjax>#V=560cancel"mL"xx(1"L")/(1000cancel"mL")="0.56 L"#</mathjax></p> <p><mathjax>#R="8.3144598 L kPa K"^(-1) "mol"^(-1)"#</mathjax> </p> <p><strong>Unknown</strong></p> <p>moles, n</p> <p><strong>Equation</strong></p> <p><mathjax>#PV=nRT#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#n#</mathjax> and solve.</p> <p><mathjax>#n=(PV)/(RT)=#</mathjax></p> <p><mathjax>#n=((100cancel"kPa")(0.56cancel"L"))/((8.3144598cancel "L" cancel"kPa"cancel" K"^(-1) "mol"^(-1)")#</mathjax><mathjax>#=#</mathjax><mathjax>#"0.024658 mol"#</mathjax></p> <p><mathjax>#n"=0.024658 mol"#</mathjax> (keeping a couple of guard digits)</p> <p><strong>Determine the molecular (molar) mass.</strong></p> <p><strong>Given/Known</strong></p> <p><mathjax>#n"=0.024658 mol"#</mathjax></p> <p><mathjax>#"m"="mass"="1.10 g"#</mathjax></p> <p><strong>Unknown</strong></p> <p>Molar mass: <mathjax>#"MM"#</mathjax></p> <p><strong>Equation</strong></p> <p><mathjax>#n=("m")/("MM")#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#"MM"#</mathjax> and solve.</p> <p><mathjax>#"MM"xx("m")/(n)#</mathjax></p> <p><mathjax>#"MM"xx(1.10"g")/(0.024658 "mol")=#</mathjax></p> <p><mathjax>#"MM"="45 g/mol"#</mathjax> (rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> due to 0.56 L)</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molar mass (molecular mass in grams) is <mathjax>#"45 g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Note: This is going to be a long answer.</p> <p><strong>First determine the number of moles.</strong></p> <p><mathjax>#"STP=273.15 K and 100 kPa"#</mathjax></p> <p><strong>Use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>.</strong></p> <p><mathjax>#PV=nRT#</mathjax>, <br/> where <mathjax>#P#</mathjax> is pressure in kiloPascals <mathjax>#("kPa")#</mathjax>, <mathjax>#V#</mathjax> is volume in liters <mathjax>#("L")#</mathjax>, <mathjax>#n#</mathjax> is moles, <mathjax>#R#</mathjax> is the gas constant, and <mathjax>#T#</mathjax> is temperature in Kelvins <mathjax>#("K")#</mathjax>.</p> <p><strong>Given/Known</strong></p> <p><mathjax>#P="100 kPa"#</mathjax></p> <p><mathjax>#T="273.15 K"#</mathjax></p> <p><mathjax>#V=560cancel"mL"xx(1"L")/(1000cancel"mL")="0.56 L"#</mathjax></p> <p><mathjax>#R="8.3144598 L kPa K"^(-1) "mol"^(-1)"#</mathjax> </p> <p><strong>Unknown</strong></p> <p>moles, n</p> <p><strong>Equation</strong></p> <p><mathjax>#PV=nRT#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#n#</mathjax> and solve.</p> <p><mathjax>#n=(PV)/(RT)=#</mathjax></p> <p><mathjax>#n=((100cancel"kPa")(0.56cancel"L"))/((8.3144598cancel "L" cancel"kPa"cancel" K"^(-1) "mol"^(-1)")#</mathjax><mathjax>#=#</mathjax><mathjax>#"0.024658 mol"#</mathjax></p> <p><mathjax>#n"=0.024658 mol"#</mathjax> (keeping a couple of guard digits)</p> <p><strong>Determine the molecular (molar) mass.</strong></p> <p><strong>Given/Known</strong></p> <p><mathjax>#n"=0.024658 mol"#</mathjax></p> <p><mathjax>#"m"="mass"="1.10 g"#</mathjax></p> <p><strong>Unknown</strong></p> <p>Molar mass: <mathjax>#"MM"#</mathjax></p> <p><strong>Equation</strong></p> <p><mathjax>#n=("m")/("MM")#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#"MM"#</mathjax> and solve.</p> <p><mathjax>#"MM"xx("m")/(n)#</mathjax></p> <p><mathjax>#"MM"xx(1.10"g")/(0.024658 "mol")=#</mathjax></p> <p><mathjax>#"MM"="45 g/mol"#</mathjax> (rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> due to 0.56 L)</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the molecular mass of a compound if 560mL have a mass of 1.10g at STP? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp" itemprop="url"> <span class="breadcrumb" itemprop="title">Molar Volume of a Gas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">2</span> Answers </h5> <div class="answers"> <div class="answer" id="180846" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-29T02:14:03" itemprop="dateCreated"> Oct 29, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The molar mass (molecular mass in grams) is <mathjax>#"45 g"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Note: This is going to be a long answer.</p> <p><strong>First determine the number of moles.</strong></p> <p><mathjax>#"STP=273.15 K and 100 kPa"#</mathjax></p> <p><strong>Use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a>.</strong></p> <p><mathjax>#PV=nRT#</mathjax>, <br/> where <mathjax>#P#</mathjax> is pressure in kiloPascals <mathjax>#("kPa")#</mathjax>, <mathjax>#V#</mathjax> is volume in liters <mathjax>#("L")#</mathjax>, <mathjax>#n#</mathjax> is moles, <mathjax>#R#</mathjax> is the gas constant, and <mathjax>#T#</mathjax> is temperature in Kelvins <mathjax>#("K")#</mathjax>.</p> <p><strong>Given/Known</strong></p> <p><mathjax>#P="100 kPa"#</mathjax></p> <p><mathjax>#T="273.15 K"#</mathjax></p> <p><mathjax>#V=560cancel"mL"xx(1"L")/(1000cancel"mL")="0.56 L"#</mathjax></p> <p><mathjax>#R="8.3144598 L kPa K"^(-1) "mol"^(-1)"#</mathjax> </p> <p><strong>Unknown</strong></p> <p>moles, n</p> <p><strong>Equation</strong></p> <p><mathjax>#PV=nRT#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#n#</mathjax> and solve.</p> <p><mathjax>#n=(PV)/(RT)=#</mathjax></p> <p><mathjax>#n=((100cancel"kPa")(0.56cancel"L"))/((8.3144598cancel "L" cancel"kPa"cancel" K"^(-1) "mol"^(-1)")#</mathjax><mathjax>#=#</mathjax><mathjax>#"0.024658 mol"#</mathjax></p> <p><mathjax>#n"=0.024658 mol"#</mathjax> (keeping a couple of guard digits)</p> <p><strong>Determine the molecular (molar) mass.</strong></p> <p><strong>Given/Known</strong></p> <p><mathjax>#n"=0.024658 mol"#</mathjax></p> <p><mathjax>#"m"="mass"="1.10 g"#</mathjax></p> <p><strong>Unknown</strong></p> <p>Molar mass: <mathjax>#"MM"#</mathjax></p> <p><strong>Equation</strong></p> <p><mathjax>#n=("m")/("MM")#</mathjax></p> <p><strong>Solution</strong><br/> Rearrange the equation to isolate <mathjax>#"MM"#</mathjax> and solve.</p> <p><mathjax>#"MM"xx("m")/(n)#</mathjax></p> <p><mathjax>#"MM"xx(1.10"g")/(0.024658 "mol")=#</mathjax></p> <p><mathjax>#"MM"="45 g/mol"#</mathjax> (rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">significant figures</a> due to 0.56 L)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/180846" itemprop="url">Answer link</a> </div> </div> <div class="answer" id="180847" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-29T02:20:44" itemprop="dateCreated"> Oct 29, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"45 g/mol"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the fact that at <strong>STP conditions</strong>, <em>one mole</em> of any ideal gas occupies exactly <mathjax>#"22.7 L"#</mathjax> - this is known as the <a href="http://socratic.org/chemistry/the-behavior-of-gases/molar-volume-of-a-gas-224-l-at-stp">molar volume of a gas at STP</a>. </p> <p>This means that if you know the volume of the gas, you can determine how many moles the sample contains by using the known molar volume at STP</p> <blockquote> <p><mathjax>#560color(red)(cancel(color(black)("mL"))) * (1color(red)(cancel(color(black)("L"))))/(1000color(red)(cancel(color(black)("mL")))) * "1 mole"/(22.7color(red)(cancel(color(black)("L")))) = "0.02467 moles"#</mathjax></p> </blockquote> <p>The molar mass of the compound, which tells you what the exact mass of <em>one mole</em> of the gas is, can be determined by using the mass of the sample. </p> <blockquote> <p><mathjax>#M_"M" = m/n#</mathjax></p> <p><mathjax>#M_"M" = "1.10 g"/"0.02467 moles" = "44.59 g/mol"#</mathjax></p> </blockquote> <p>Rounded to two <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a>, the nswer will be </p> <blockquote> <p><mathjax>#M_"M" = color(green)("45 g/mol")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/180847" itemprop="url">Answer link</a> </div> </div> </div> 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What is the molecular mass of a compound if 560mL have a mass of 1.10g at STP?

a8d5114b-6ddd-11ea-b81d-ccda262736ce

https://socratic.org/questions/c-2h-4-3o-2-2co-2-2h-2o-if-you-start-with-45-grams-of-ethylene-c-2h-4-how-many-g

141.42 grams

start physical_unit 23 24 mass g qc_end chemical_equation 0 9 qc_end physical_unit 0 0 14 15 mass qc_end end

[{"type":"physical unit","value":"Mass [OF] carbon dioxide [IN] grams"}]

[{"type":"physical unit","value":"141.42 grams"}]

[{"type":"chemical equation","value":"C2H4 + 3 O2 -> 2 CO2 + 2 H2O"},{"type":"physical unit","value":"Mass [OF] C2H4 [=] \\pu{45 grams}"}]

<h1 class="questionTitle" itemprop="name">#C_2H_4 + 3O_2 -&gt; 2CO_2 +2H_2O#. If you start with 45 grams of ethylene (#C_2H_4#), how many grams of carbon dioxide will be produced?</h1>

141.42 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"No. of mol of ethylene"=45/(2*12+4*1)~~1.607mol#</mathjax></p> <p><mathjax>#"No. of mol of "CO_2" produced"=2*1.607=3.214mol#</mathjax></p> <p><mathjax>#"Mass of "CO_2"=3.214*(12+2*16)=141.416g#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>141.416g</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"No. of mol of ethylene"=45/(2*12+4*1)~~1.607mol#</mathjax></p> <p><mathjax>#"No. of mol of "CO_2" produced"=2*1.607=3.214mol#</mathjax></p> <p><mathjax>#"Mass of "CO_2"=3.214*(12+2*16)=141.416g#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">#C_2H_4 + 3O_2 -&gt; 2CO_2 +2H_2O#. If you start with 45 grams of ethylene (#C_2H_4#), how many grams of carbon dioxide will be produced?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="398609" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/ngbro"><img alt="" class="" src="https://profilepictures.socratic.org/RwPvaYOCQKioWlAlZJxY_Angry_face_meme.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/ngbro"> NGBRO </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-29T18:20:02" itemprop="dateCreated"> Mar 29, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>141.416g</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"No. of mol of ethylene"=45/(2*12+4*1)~~1.607mol#</mathjax></p> <p><mathjax>#"No. of mol of "CO_2" produced"=2*1.607=3.214mol#</mathjax></p> <p><mathjax>#"Mass of "CO_2"=3.214*(12+2*16)=141.416g#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/398609" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 15316 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

#C_2H_4 + 3O_2 -&gt; 2CO_2 +2H_2O#. If you start with 45 grams of ethylene (#C_2H_4#), how many grams of carbon dioxide will be produced?

ace52fb8-6ddd-11ea-b033-ccda262736ce

https://socratic.org/questions/how-many-copper-atoms-are-in-5-6-moles-of-cu-2o

6.74 × 10^24

start physical_unit 2 3 number none qc_end physical_unit 9 9 6 7 mole qc_end end

[{"type":"physical unit","value":"Number [OF] copper atoms"}]

[{"type":"physical unit","value":"6.74 × 10^24"}]

[{"type":"physical unit","value":"Mole [OF] Cu2O [=] \\pu{5.6 moles}"}]

<h1 class="questionTitle" itemprop="name">How many copper atoms are in 5.6 moles of #Cu_2O#?</h1>

6.74 × 10^24

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In one mole you have Avogadro's number (<mathjax>#6.022×10^(23)#</mathjax>) of objects, in this case 'formula units' of <mathjax>#Cu_2O#</mathjax>.</p> <p>So, in <mathjax>#5.6#</mathjax> moles we have:</p> <p><mathjax>#5.6×6.022×10^(23)#</mathjax> formula units of <mathjax>#Cu_2O#</mathjax>, each one with <mathjax>#2#</mathjax> Cu atoms giving:</p> <p><mathjax>#2×5.6×6.022×10^(23)=6.74×10^(24)#</mathjax> atoms of Cu...</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I found <mathjax>#6.74×10^(24)#</mathjax> Cu atoms.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In one mole you have Avogadro's number (<mathjax>#6.022×10^(23)#</mathjax>) of objects, in this case 'formula units' of <mathjax>#Cu_2O#</mathjax>.</p> <p>So, in <mathjax>#5.6#</mathjax> moles we have:</p> <p><mathjax>#5.6×6.022×10^(23)#</mathjax> formula units of <mathjax>#Cu_2O#</mathjax>, each one with <mathjax>#2#</mathjax> Cu atoms giving:</p> <p><mathjax>#2×5.6×6.022×10^(23)=6.74×10^(24)#</mathjax> atoms of Cu...</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many copper atoms are in 5.6 moles of #Cu_2O#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/the-mole" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="244229" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/gio"><img alt="" class="" src="https://profilepictures.socratic.org/PDAQ7XlwRXWLdTy9hfbV_kuruma.jpg" title=""/></a> <a class="secondContributorPic" href="/users/david-g-6"><img alt="" class="" src="https://graph.facebook.com/10153408096237887/picture?height=50&amp;width=50" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/gio"> Gió </a>·<a class="topContributorLink" href="/users/david-g-6"> David G. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-03-24T03:51:44" itemprop="dateCreated"> Mar 24, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>I found <mathjax>#6.74×10^(24)#</mathjax> Cu atoms.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>In one mole you have Avogadro's number (<mathjax>#6.022×10^(23)#</mathjax>) of objects, in this case 'formula units' of <mathjax>#Cu_2O#</mathjax>.</p> <p>So, in <mathjax>#5.6#</mathjax> moles we have:</p> <p><mathjax>#5.6×6.022×10^(23)#</mathjax> formula units of <mathjax>#Cu_2O#</mathjax>, each one with <mathjax>#2#</mathjax> Cu atoms giving:</p> <p><mathjax>#2×5.6×6.022×10^(23)=6.74×10^(24)#</mathjax> atoms of Cu...</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/244229" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-the-number-of-moles-from-volume"> How do you calculate the number of moles from volume? 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How many copper atoms are in 5.6 moles of #Cu_2O#?

a8e50837-6ddd-11ea-b3f7-ccda262736ce

https://socratic.org/questions/how-many-grams-of-sodium-fluoride-naf-are-needed-to-prepare-a-0-400-m-naf-soluti

12.60 g

start physical_unit 6 6 mass g qc_end physical_unit 14 15 12 13 molarity qc_end physical_unit 20 20 18 19 mass qc_end end

[{"type":"physical unit","value":"Mass [OF] NaF [IN] grams"}]

[{"type":"physical unit","value":"12.60 g"}]

[{"type":"physical unit","value":"Molarity [OF] NaF solution [=] \\pu{0.400 M}"},{"type":"physical unit","value":"Mass [OF] water [=] \\pu{750 g}"}]

<h1 class="questionTitle" itemprop="name">How many grams of sodium fluoride (NaF) are needed to prepare a 0.400 m NaF solution that contains 750 g water?</h1>

12.60 g

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, the <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a></strong> of a solution represents the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present for every <mathjax>#"1 kg"#</mathjax> of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>. </p> <p>This means that in order to find a solution's molality, all you need to do is to figure out exactly how many moles of solute you have for <mathjax>#"1 kg"#</mathjax> of solvent. </p> <p>In your case, a <mathjax>#"0.400-m"#</mathjax> sodium fluoride solution will contain <mathjax>#0.400#</mathjax> <strong>moles</strong> of sodium fluoride, the solute, <strong>for every</strong> <mathjax>#"1 kg"#</mathjax> of water, the solvent. </p> <p>As you know, you have</p> <blockquote> <p><mathjax>#"1 kg" = 10^3#</mathjax> <mathjax>#"g"#</mathjax></p> </blockquote> <p>This means that your target solution contains</p> <blockquote> <p><mathjax>#750 color(red)(cancel(color(black)("g"))) * "1 kg"/(10^3color(red)(cancel(color(black)("g")))) = "0.750 kg" = color(blue)(3/4)* "1 kg"#</mathjax></p> </blockquote> <p>of water. Since you already know that <mathjax>#"1 kg"#</mathjax> of this solution must contain <mathjax>#0.400#</mathjax> <strong>moles</strong> of sodium fluoride, you can say that your sample will contain</p> <blockquote> <p><mathjax>#color(blue)(3/4) * overbrace("0.400 moles NaF")^(color(red)("no. of moles of NaF in 1 kg of water")) = "0.300 moles NaF"#</mathjax></p> </blockquote> <p>Finally, to convert this to <em>grams</em>, use the <strong>molar mass</strong> of the compound</p> <blockquote> <p><mathjax>#0.300 color(red)(cancel(color(black)("moles NaF"))) * "41.988 g"/(1color(red)(cancel(color(black)("mole NaF")))) = color(darkgreen)(ul(color(black)("13 g")))#</mathjax></p> </blockquote> <p>The answer must be rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of water. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"13 g NaF"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, the <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a></strong> of a solution represents the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present for every <mathjax>#"1 kg"#</mathjax> of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>. </p> <p>This means that in order to find a solution's molality, all you need to do is to figure out exactly how many moles of solute you have for <mathjax>#"1 kg"#</mathjax> of solvent. </p> <p>In your case, a <mathjax>#"0.400-m"#</mathjax> sodium fluoride solution will contain <mathjax>#0.400#</mathjax> <strong>moles</strong> of sodium fluoride, the solute, <strong>for every</strong> <mathjax>#"1 kg"#</mathjax> of water, the solvent. </p> <p>As you know, you have</p> <blockquote> <p><mathjax>#"1 kg" = 10^3#</mathjax> <mathjax>#"g"#</mathjax></p> </blockquote> <p>This means that your target solution contains</p> <blockquote> <p><mathjax>#750 color(red)(cancel(color(black)("g"))) * "1 kg"/(10^3color(red)(cancel(color(black)("g")))) = "0.750 kg" = color(blue)(3/4)* "1 kg"#</mathjax></p> </blockquote> <p>of water. Since you already know that <mathjax>#"1 kg"#</mathjax> of this solution must contain <mathjax>#0.400#</mathjax> <strong>moles</strong> of sodium fluoride, you can say that your sample will contain</p> <blockquote> <p><mathjax>#color(blue)(3/4) * overbrace("0.400 moles NaF")^(color(red)("no. of moles of NaF in 1 kg of water")) = "0.300 moles NaF"#</mathjax></p> </blockquote> <p>Finally, to convert this to <em>grams</em>, use the <strong>molar mass</strong> of the compound</p> <blockquote> <p><mathjax>#0.300 color(red)(cancel(color(black)("moles NaF"))) * "41.988 g"/(1color(red)(cancel(color(black)("mole NaF")))) = color(darkgreen)(ul(color(black)("13 g")))#</mathjax></p> </blockquote> <p>The answer must be rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of water. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many grams of sodium fluoride (NaF) are needed to prepare a 0.400 m NaF solution that contains 750 g water?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molality" itemprop="url"> <span class="breadcrumb" itemprop="title">Molality</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="445594" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-29T00:02:24" itemprop="dateCreated"> Jun 29, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"13 g NaF"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>As you know, the <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molality">molality</a></strong> of a solution represents the number of moles of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a> present for every <mathjax>#"1 kg"#</mathjax> of <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solvent">solvent</a>. </p> <p>This means that in order to find a solution's molality, all you need to do is to figure out exactly how many moles of solute you have for <mathjax>#"1 kg"#</mathjax> of solvent. </p> <p>In your case, a <mathjax>#"0.400-m"#</mathjax> sodium fluoride solution will contain <mathjax>#0.400#</mathjax> <strong>moles</strong> of sodium fluoride, the solute, <strong>for every</strong> <mathjax>#"1 kg"#</mathjax> of water, the solvent. </p> <p>As you know, you have</p> <blockquote> <p><mathjax>#"1 kg" = 10^3#</mathjax> <mathjax>#"g"#</mathjax></p> </blockquote> <p>This means that your target solution contains</p> <blockquote> <p><mathjax>#750 color(red)(cancel(color(black)("g"))) * "1 kg"/(10^3color(red)(cancel(color(black)("g")))) = "0.750 kg" = color(blue)(3/4)* "1 kg"#</mathjax></p> </blockquote> <p>of water. Since you already know that <mathjax>#"1 kg"#</mathjax> of this solution must contain <mathjax>#0.400#</mathjax> <strong>moles</strong> of sodium fluoride, you can say that your sample will contain</p> <blockquote> <p><mathjax>#color(blue)(3/4) * overbrace("0.400 moles NaF")^(color(red)("no. of moles of NaF in 1 kg of water")) = "0.300 moles NaF"#</mathjax></p> </blockquote> <p>Finally, to convert this to <em>grams</em>, use the <strong>molar mass</strong> of the compound</p> <blockquote> <p><mathjax>#0.300 color(red)(cancel(color(black)("moles NaF"))) * "41.988 g"/(1color(red)(cancel(color(black)("mole NaF")))) = color(darkgreen)(ul(color(black)("13 g")))#</mathjax></p> </blockquote> <p>The answer must be rounded to two <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>, the number of sig figs you have for the mass of water. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/445594" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-molality-and-molarity-differ"> How do molality and molarity differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molality-be"> How high can molality be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-calculate-molality-from-molarity"> How do you calculate molality from molarity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-molality-used-for-colligative-properties"> Why is molality used for colligative properties? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-molality-independent-of-temperature"> Why is molality independent of temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-calculate-the-molality-when-75-0-grams-of-mgcl2-is-dissolved-in-500-0-"> How can I calculate the molality when 75.0 grams of MgCl2 is dissolved in 500.0 g of solvent? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/49-8-grams-of-ki-is-dissolved-in-1-00-kg-of-solvent-what-is-the-molality"> 49.8 grams of KI is dissolved in 1.00 kg of solvent. 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How many grams of sodium fluoride (NaF) are needed to prepare a 0.400 m NaF solution that contains 750 g water?

aab5d5ae-6ddd-11ea-bfa3-ccda262736ce

https://socratic.org/questions/what-is-the-actual-formula-for-iron-rust

Fe2O3

start chemical_formula qc_end substance 6 7 qc_end end

[{"type":"other","value":"Chemical Formula [OF] iron rust [IN] default"}]

[{"type":"chemical equation","value":"Fe2O3"}]

[{"type":"substance name","value":"Iron rust"}]

<h1 class="questionTitle" itemprop="name">What is the actual formula for iron rust ?? </h1>

Fe2O3

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Rust is just iron oxide, so it is made up of iron and oxygen. We can find the empirical formula (simplest ratio of a compound's components) by looking at the ions each element forms.<br/> Oxygen forms <mathjax>#O^(2-)#</mathjax> ions and iron forms <mathjax>#Fe^(3+)#</mathjax> ions. Now iron can actually form different ions because it is a transition element, but we usually stick to it being 3+ (if it forms a different ion then it will have the charge represented by a roman numeral after iron, e.g. iron(II) forms 2+ ions).</p> <p><a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">Compounds</a> have an overall neutral charge, so we need to find a combination of iron and oxygen which results in their charges balancing out. This basically involves finding the lowest common multiple of their two charges - so for 2 and 3 this is 6, and so we have <mathjax>#6/2=3#</mathjax> oxygen ions and <mathjax>#6/3=2#</mathjax> iron ions.<br/> This gives us the final formula <mathjax>#Fe_2O_3#</mathjax></p> <p>Hope this helped; let me know if I can do anything else:)</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Fe_2O_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Rust is just iron oxide, so it is made up of iron and oxygen. We can find the empirical formula (simplest ratio of a compound's components) by looking at the ions each element forms.<br/> Oxygen forms <mathjax>#O^(2-)#</mathjax> ions and iron forms <mathjax>#Fe^(3+)#</mathjax> ions. Now iron can actually form different ions because it is a transition element, but we usually stick to it being 3+ (if it forms a different ion then it will have the charge represented by a roman numeral after iron, e.g. iron(II) forms 2+ ions).</p> <p><a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">Compounds</a> have an overall neutral charge, so we need to find a combination of iron and oxygen which results in their charges balancing out. This basically involves finding the lowest common multiple of their two charges - so for 2 and 3 this is 6, and so we have <mathjax>#6/2=3#</mathjax> oxygen ions and <mathjax>#6/3=2#</mathjax> iron ions.<br/> This gives us the final formula <mathjax>#Fe_2O_3#</mathjax></p> <p>Hope this helped; let me know if I can do anything else:)</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the actual formula for iron rust ?? </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="430924" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/sarah-c-7"><img alt="" class="" src="https://profilepictures.socratic.org/UWEvw7fxSwSTqsMemJwl_IMG_3617.JPG" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/sarah-c-7"> Sarah C </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-05-28T11:08:44" itemprop="dateCreated"> May 28, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#Fe_2O_3#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Rust is just iron oxide, so it is made up of iron and oxygen. We can find the empirical formula (simplest ratio of a compound's components) by looking at the ions each element forms.<br/> Oxygen forms <mathjax>#O^(2-)#</mathjax> ions and iron forms <mathjax>#Fe^(3+)#</mathjax> ions. Now iron can actually form different ions because it is a transition element, but we usually stick to it being 3+ (if it forms a different ion then it will have the charge represented by a roman numeral after iron, e.g. iron(II) forms 2+ ions).</p> <p><a href="https://socratic.org/chemistry/a-first-introduction-to-matter/compounds">Compounds</a> have an overall neutral charge, so we need to find a combination of iron and oxygen which results in their charges balancing out. This basically involves finding the lowest common multiple of their two charges - so for 2 and 3 this is 6, and so we have <mathjax>#6/2=3#</mathjax> oxygen ions and <mathjax>#6/3=2#</mathjax> iron ions.<br/> This gives us the final formula <mathjax>#Fe_2O_3#</mathjax></p> <p>Hope this helped; let me know if I can do anything else:)</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/430924" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-chloride"> What is the ionic formula for calcium chloride? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-oxide"> What is the ionic formula for calcium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-lithium-oxide"> What is the ionic formula for lithium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-formula-for-ionic-compounds"> How do you write the formula for ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-correctly-write-the-ions-present-in-sn-no3-2"> How do I write #Sn(NO_3)_2# in Ionic formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-an-ionic-compound"> What is the empirical formula for an ionic compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-for-chorate"> What is the molecular formula for chorate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5363023c02bf343b2ee7086b"> Question #7086b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-polyatomic-ions-covalent-1"> Why are polyatomic ions covalent? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas"> See all questions in Writing Ionic Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 5346 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the actual formula for iron rust ??

a8aa7bc6-6ddd-11ea-a877-ccda262736ce

https://socratic.org/questions/in-the-equation-2c-2h-6-7o-2-4co-2-6h-2o-if-15-g-of-c-2h-6-react-with-45-g-of-o-

27 grams

start physical_unit 29 29 mass g qc_end chemical_equation 3 13 qc_end physical_unit 4 4 15 16 mass qc_end physical_unit 7 7 21 22 mass qc_end end

[{"type":"physical unit","value":"Mass [OF] water [IN] grams"}]

[{"type":"physical unit","value":"27 grams"}]

[{"type":"chemical equation","value":"2 C2H6 + 7 O2 -> 4 CO2 + 6 H2O"},{"type":"physical unit","value":"Mass [OF] C2H6 [=] \\pu{15 g}"},{"type":"physical unit","value":"Mass [OF] O2 [=] \\pu{45 g}"}]

<h1 class="questionTitle" itemprop="name">In the equation #2C_2H_6 + 7O_2 -&gt; 4CO_2 + 6H_2O#, if 15 g of #C_2H_6# react with 45 g of #O_2#, how many grams of water will be produced?</h1>

27 grams

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of dioxygen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(45*g)/(32.00*g*mol^-1)=1.41*mol#</mathjax>.</p> <p>Clearly, there is insufficient dioxygen for complete combustion; i.e. complete combustion requires <mathjax>#1.75*mol#</mathjax> <mathjax>#O_2#</mathjax>. We ASSUME incomplete combustion, i.e.</p> <p><mathjax>#"COMPLETE COMBUSTION GIVES...."#</mathjax></p> <p><mathjax>#C_2H_6(g) + 7/2O_2(g) rarr 2CO_2(g) + 3H_2O(l)#</mathjax></p> <p><mathjax>#"INCOMPLETE COMBUSTION GIVES...."#</mathjax></p> <p><mathjax>#C_2H_6(g)+3O_2(g)rarrCO_2(g) + CO(g)+3H_2O(l)#</mathjax></p> <p><mathjax>#"OR.........."#</mathjax></p> <p><mathjax>#C_2H_6(g)+2O_2(g)rarrC(s)+ CO(g)+3H_2O(l)#</mathjax></p> <p>(What would we obtain? This would be the subject of experiment. Certainly incomplete combustion occurs in the internal combustion engine, and in diesels.) In each case, however, combustion of ethane, complete, or incomplete, gives rise to...........</p> <p><mathjax>#"THREE EQUIV of WATER PER EQUIV ETHANE."#</mathjax></p> <p>And thus if there are <mathjax>#0.5*mol#</mathjax> ethane reactant, there will be <mathjax>#1.5*mol#</mathjax> water product.........a mass of <mathjax>#27*g#</mathjax>. </p> <p>Good question, which I am stealing for my A2 class. </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Moles of ethane"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(15*g)/(30.07*g*mol^-1)=0.499*mol#</mathjax>.</p> <p>I gets <mathjax>#27*g#</mathjax> water product............</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of dioxygen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(45*g)/(32.00*g*mol^-1)=1.41*mol#</mathjax>.</p> <p>Clearly, there is insufficient dioxygen for complete combustion; i.e. complete combustion requires <mathjax>#1.75*mol#</mathjax> <mathjax>#O_2#</mathjax>. We ASSUME incomplete combustion, i.e.</p> <p><mathjax>#"COMPLETE COMBUSTION GIVES...."#</mathjax></p> <p><mathjax>#C_2H_6(g) + 7/2O_2(g) rarr 2CO_2(g) + 3H_2O(l)#</mathjax></p> <p><mathjax>#"INCOMPLETE COMBUSTION GIVES...."#</mathjax></p> <p><mathjax>#C_2H_6(g)+3O_2(g)rarrCO_2(g) + CO(g)+3H_2O(l)#</mathjax></p> <p><mathjax>#"OR.........."#</mathjax></p> <p><mathjax>#C_2H_6(g)+2O_2(g)rarrC(s)+ CO(g)+3H_2O(l)#</mathjax></p> <p>(What would we obtain? This would be the subject of experiment. Certainly incomplete combustion occurs in the internal combustion engine, and in diesels.) In each case, however, combustion of ethane, complete, or incomplete, gives rise to...........</p> <p><mathjax>#"THREE EQUIV of WATER PER EQUIV ETHANE."#</mathjax></p> <p>And thus if there are <mathjax>#0.5*mol#</mathjax> ethane reactant, there will be <mathjax>#1.5*mol#</mathjax> water product.........a mass of <mathjax>#27*g#</mathjax>. </p> <p>Good question, which I am stealing for my A2 class. </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">In the equation #2C_2H_6 + 7O_2 -&gt; 4CO_2 + 6H_2O#, if 15 g of #C_2H_6# react with 45 g of #O_2#, how many grams of water will be produced?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#chemical-reactions" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/chemical-reactions/chemical-reactions-and-equations" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemical Reactions and Equations</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="434362" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-04T06:49:56" itemprop="dateCreated"> Jun 4, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"Moles of ethane"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(15*g)/(30.07*g*mol^-1)=0.499*mol#</mathjax>.</p> <p>I gets <mathjax>#27*g#</mathjax> water product............</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Moles of dioxygen"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#(45*g)/(32.00*g*mol^-1)=1.41*mol#</mathjax>.</p> <p>Clearly, there is insufficient dioxygen for complete combustion; i.e. complete combustion requires <mathjax>#1.75*mol#</mathjax> <mathjax>#O_2#</mathjax>. We ASSUME incomplete combustion, i.e.</p> <p><mathjax>#"COMPLETE COMBUSTION GIVES...."#</mathjax></p> <p><mathjax>#C_2H_6(g) + 7/2O_2(g) rarr 2CO_2(g) + 3H_2O(l)#</mathjax></p> <p><mathjax>#"INCOMPLETE COMBUSTION GIVES...."#</mathjax></p> <p><mathjax>#C_2H_6(g)+3O_2(g)rarrCO_2(g) + CO(g)+3H_2O(l)#</mathjax></p> <p><mathjax>#"OR.........."#</mathjax></p> <p><mathjax>#C_2H_6(g)+2O_2(g)rarrC(s)+ CO(g)+3H_2O(l)#</mathjax></p> <p>(What would we obtain? This would be the subject of experiment. Certainly incomplete combustion occurs in the internal combustion engine, and in diesels.) In each case, however, combustion of ethane, complete, or incomplete, gives rise to...........</p> <p><mathjax>#"THREE EQUIV of WATER PER EQUIV ETHANE."#</mathjax></p> <p>And thus if there are <mathjax>#0.5*mol#</mathjax> ethane reactant, there will be <mathjax>#1.5*mol#</mathjax> water product.........a mass of <mathjax>#27*g#</mathjax>. </p> <p>Good question, which I am stealing for my A2 class. </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/434362" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb002bf34694a4fee47"> Question #fee47 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb402bf34694c8c5c15"> Question #c5c15 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cb802bf346950519eb9"> Question #19eb9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cbf02bf3469570e2ea2"> Question #e2ea2 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc002bf34695a6bc751"> Question #bc751 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d41cc202bf3469570e2ea6"> Question #e2ea6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531e867a02bf342492a08b07"> Question #08b07 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-thermochemical-equation-for-the-combustion-of-benzene"> What is the thermochemical equation for the combustion of benzene? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-reversible"> Why are chemical reactions reversible? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-chemical-reactions-important"> Why are chemical reactions important? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/chemical-reactions/chemical-reactions-and-equations"> See all questions in Chemical Reactions and Equations </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4218 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

In the equation #2C_2H_6 + 7O_2 -&gt; 4CO_2 + 6H_2O#, if 15 g of #C_2H_6# react with 45 g of #O_2#, how many grams of water will be produced?

aab51264-6ddd-11ea-a2f3-ccda262736ce

https://socratic.org/questions/how-do-you-calculate-the-molarity-m-of-157-6-g-of-h-2so-4-in-1-170-l-of-solution

1.37 M

start physical_unit 11 11 molarity mol/l qc_end physical_unit 11 11 8 9 mass qc_end physical_unit 16 16 13 14 volume qc_end end

[{"type":"physical unit","value":"Molarity [OF] H2SO4 solution [IN] M"}]

[{"type":"physical unit","value":"1.37 M"}]

[{"type":"physical unit","value":"Mass [OF] H2SO4 [=] \\pu{157.6 g}"},{"type":"physical unit","value":"Volume [OF] H2SO4 solution [=] \\pu{1.170 L}"}]

<h1 class="questionTitle" itemprop="name">How do you calculate the molarity (M) of 157.6 g of #H_2SO_4# in 1.170 L of solution?</h1>

1.37 M

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>An interesting approach to try here is to calculate the number of <em>grams</em> of sulfuric acid present in <mathjax>#"1 L"#</mathjax> of solution first, then convert this to <em>moles</em> present in <mathjax>#"1 L"#</mathjax> of solution. </p> <p>So, you know that you get <mathjax>#"157.6 g"#</mathjax> of sulfuric acid, the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, in <mathjax>#"1.170 L"#</mathjax> of solution. Since <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> are homogeneous <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/mixtures">mixtures</a>, you can use the known composition of the solution as a conversion factor to calculate the mass of sulfuric acid present in <mathjax>#"1 L"#</mathjax> of solution</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("L solution"))) * ("157.6 g H"_2"SO"_4)/(1.170color(red)(cancel(color(black)("L solution")))) = "134.7 g H"_2"SO"_4#</mathjax></p> </blockquote> <p>So, you know that this solution contains</p> <blockquote> <p><mathjax>#("134.7 g H"_2"SO"_4)/"1 L solution"#</mathjax></p> </blockquote> <p>Now, <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> is defined as the number of <strong>moles</strong> of solute present in <mathjax>#"1 L"#</mathjax> of solution. Since you already know the mass of solute present in the desired volume, use the <strong>molar mass</strong> of sulfuric acid to convert it to <em>moles</em></p> <blockquote> <p><mathjax>#134.7 color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"SO"_4)/(98.079color(red)(cancel(color(black)("g")))) = "1.373 moles H"_2"SO"_4#</mathjax></p> </blockquote> <p>Therefore, you can say that the molarity of the solution is equal to</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("molarity = 1.373 mol L"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to four <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1.373 mol L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>An interesting approach to try here is to calculate the number of <em>grams</em> of sulfuric acid present in <mathjax>#"1 L"#</mathjax> of solution first, then convert this to <em>moles</em> present in <mathjax>#"1 L"#</mathjax> of solution. </p> <p>So, you know that you get <mathjax>#"157.6 g"#</mathjax> of sulfuric acid, the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, in <mathjax>#"1.170 L"#</mathjax> of solution. Since <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> are homogeneous <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/mixtures">mixtures</a>, you can use the known composition of the solution as a conversion factor to calculate the mass of sulfuric acid present in <mathjax>#"1 L"#</mathjax> of solution</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("L solution"))) * ("157.6 g H"_2"SO"_4)/(1.170color(red)(cancel(color(black)("L solution")))) = "134.7 g H"_2"SO"_4#</mathjax></p> </blockquote> <p>So, you know that this solution contains</p> <blockquote> <p><mathjax>#("134.7 g H"_2"SO"_4)/"1 L solution"#</mathjax></p> </blockquote> <p>Now, <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> is defined as the number of <strong>moles</strong> of solute present in <mathjax>#"1 L"#</mathjax> of solution. Since you already know the mass of solute present in the desired volume, use the <strong>molar mass</strong> of sulfuric acid to convert it to <em>moles</em></p> <blockquote> <p><mathjax>#134.7 color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"SO"_4)/(98.079color(red)(cancel(color(black)("g")))) = "1.373 moles H"_2"SO"_4#</mathjax></p> </blockquote> <p>Therefore, you can say that the molarity of the solution is equal to</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("molarity = 1.373 mol L"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to four <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you calculate the molarity (M) of 157.6 g of #H_2SO_4# in 1.170 L of solution?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="437719" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-06-10T23:13:16" itemprop="dateCreated"> Jun 10, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1.373 mol L"^(-1)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>An interesting approach to try here is to calculate the number of <em>grams</em> of sulfuric acid present in <mathjax>#"1 L"#</mathjax> of solution first, then convert this to <em>moles</em> present in <mathjax>#"1 L"#</mathjax> of solution. </p> <p>So, you know that you get <mathjax>#"157.6 g"#</mathjax> of sulfuric acid, the <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solute">solute</a>, in <mathjax>#"1.170 L"#</mathjax> of solution. Since <a href="https://socratic.org/chemistry/solutions-and-their-behavior/solutions">solutions</a> are homogeneous <a href="https://socratic.org/chemistry/a-first-introduction-to-matter/mixtures">mixtures</a>, you can use the known composition of the solution as a conversion factor to calculate the mass of sulfuric acid present in <mathjax>#"1 L"#</mathjax> of solution</p> <blockquote> <p><mathjax>#1 color(red)(cancel(color(black)("L solution"))) * ("157.6 g H"_2"SO"_4)/(1.170color(red)(cancel(color(black)("L solution")))) = "134.7 g H"_2"SO"_4#</mathjax></p> </blockquote> <p>So, you know that this solution contains</p> <blockquote> <p><mathjax>#("134.7 g H"_2"SO"_4)/"1 L solution"#</mathjax></p> </blockquote> <p>Now, <strong><a href="https://socratic.org/chemistry/solutions-and-their-behavior/molarity">molarity</a></strong> is defined as the number of <strong>moles</strong> of solute present in <mathjax>#"1 L"#</mathjax> of solution. Since you already know the mass of solute present in the desired volume, use the <strong>molar mass</strong> of sulfuric acid to convert it to <em>moles</em></p> <blockquote> <p><mathjax>#134.7 color(red)(cancel(color(black)("g"))) * ("1 mole H"_2"SO"_4)/(98.079color(red)(cancel(color(black)("g")))) = "1.373 moles H"_2"SO"_4#</mathjax></p> </blockquote> <p>Therefore, you can say that the molarity of the solution is equal to</p> <blockquote> <p><mathjax>#color(darkgreen)(ul(color(black)("molarity = 1.373 mol L"^(-1))))#</mathjax></p> </blockquote> <p>The answer is rounded to four <strong><a href="https://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a></strong>.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/437719" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-morality-be-used-as-a-conversion-factor"> How can molarity be used as a conversion factor? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-high-can-molarity-be"> How high can molarity be? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-molarity-change-with-temperature"> How does molarity change with temperature? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molarity-of-a-solution"> How do you find molarity of a solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-10-naoh"> What is the molarity of 10 NaOH? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-3-hydrogen-peroxide"> What is the molarity of 3 hydrogen peroxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5332c9d002bf343bc937da40"> What is the molarity of a solution that contains 3.2 mol of solute in 0.98 L of solution? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-molarity"> What is molarity? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/solutions-and-their-behavior/molarity"> See all questions in Molarity </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 25881 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How do you calculate the molarity (M) of 157.6 g of #H_2SO_4# in 1.170 L of solution?

ac0eb495-6ddd-11ea-a643-ccda262736ce

https://socratic.org/questions/how-many-moles-of-c-are-needed-to-react-with-0-480-mole-so-2

0.480 moles

start physical_unit 4 4 mole mol qc_end physical_unit 12 12 10 11 mole qc_end end

[{"type":"physical unit","value":"Mole [OF] C [IN] moles"}]

[{"type":"physical unit","value":"0.480 moles"}]

[{"type":"physical unit","value":"Mole [OF] SO2 [=] \\pu{0.480 moles}"}]

<h1 class="questionTitle" itemprop="name">How many moles of #C# are needed to react with 0.480 mole #SO_2#?</h1>

0.480 moles

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The equation is stoichiometrically balanced. Clearly, if 0.480 mol sulfure are reduced, 0.480 mol of carbon are required. What are the masses of each reactant given these molar quantities.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C(s)+SO_2(g) rarrS(s) + CO_2(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The equation is stoichiometrically balanced. Clearly, if 0.480 mol sulfure are reduced, 0.480 mol of carbon are required. What are the masses of each reactant given these molar quantities.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How many moles of #C# are needed to react with 0.480 mole #SO_2#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#stoichiometry" itemprop="url"> <span class="breadcrumb" itemprop="title">Stoichiometry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/stoichiometry/mole-ratios" itemprop="url"> <span class="breadcrumb" itemprop="title">Mole Ratios</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="278310" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-06-17T07:24:18" itemprop="dateCreated"> Jun 17, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#C(s)+SO_2(g) rarrS(s) + CO_2(g)#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The equation is stoichiometrically balanced. Clearly, if 0.480 mol sulfure are reduced, 0.480 mol of carbon are required. What are the masses of each reactant given these molar quantities.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/278310" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469517a106e"> Question #a106e </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4178e02bf3469570e2e86"> Question #e2e86 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179102bf3469517a1072"> Question #a1072 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179402bf34694c8c5bf1"> Question #c5bf1 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179702bf3469588dc373"> Question #dc373 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d4179c02bf34694c8c5bf9"> Question #c5bf9 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417a302bf3469517a1076"> Question #a1076 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417c702bf3469588dc377"> Question #dc377 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d002bf346963eb984f"> Question #b984f </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/52d417d402bf346950519ea3"> Question #19ea3 </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/stoichiometry/mole-ratios"> See all questions in Mole Ratios </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 4546 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How many moles of #C# are needed to react with 0.480 mole #SO_2#?

ac8f84a8-6ddd-11ea-b44d-ccda262736ce

https://socratic.org/questions/how-much-heat-is-required-to-convert-5-88-g-of-ice-at-12-0-c-to-water-at-25-0-c-

2.73 kJ

start physical_unit 10 10 heat_energy kj qc_end physical_unit 10 10 7 8 mass qc_end physical_unit 10 10 12 13 temperature qc_end physical_unit 15 15 17 18 temperature qc_end physical_unit 10 10 26 27 heat_capacity qc_end end

[{"type":"physical unit","value":"Required heat [OF] ice [IN] kJ"}]

[{"type":"physical unit","value":"2.73 kJ"}]

[{"type":"physical unit","value":"Mass [OF] ice [=] \\pu{5.88 g}"},{"type":"physical unit","value":"Temperature1 [OF] ice [=] \\pu{-12.0 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] water [=] \\pu{25.0 ℃}"},{"type":"physical unit","value":"Heat capacity [OF] ice [=] \\pu{2.09 J/℃}"}]

<h1 class="questionTitle" itemprop="name">How much heat is required to convert 5.88 g of ice at -12.0°C to water at 25.0°C, if the heat capacity of ice is 2.09 J/°C?</h1>

2.73 kJ

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy here will be to determine </p> <ul> <li> <p><em>how much heat is required to convert that sample of ice from <strong>solid</strong> at</em> <mathjax>#-12.0^@"C"#</mathjax> <em>to <strong>solid</strong> at</em> <mathjax>#0^@"C"#</mathjax></p> </li> <li> <p><em>determine how much heat is required to convert that sample of ice from <strong>solid</strong> at</em> <mathjax>#0^@"C"#</mathjax> <em>to <strong>liquid</strong> at</em> <mathjax>#0^@"C"#</mathjax></p> </li> <li> <p><em>finally, determine how much heat is required to heat that sample of now liquid water from</em> <mathjax>#0^@"C"#</mathjax> <em>to</em> <mathjax>#25.0^@"C"#</mathjax></p> </li> </ul> <p>In order to be able to calculate all this, you will need to know the values for the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of <em>ice</em> and that of <em>water</em>, and the value of the <em><a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of fusion</em>, <mathjax>#DeltaH_"fus"#</mathjax>, for water</p> <blockquote> <p><mathjax>#c_"ice" = 2.09"J"/("g" ""^@"C")" "#</mathjax> and <mathjax>#" "c_"water" = 4.18"J"/("g" ""^@"C")#</mathjax></p> <p><mathjax>#DeltaH_"fus" = 334"J"/"g"#</mathjax></p> </blockquote> <p><a href="http://www.engineeringtoolbox.com/latent-heat-melting-solids-d_96.html" rel="nofollow" target="_blank">http://www.engineeringtoolbox.com/latent-heat-melting-solids-d_96.html</a></p> <p>Two equations will come in handy here </p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - heat absorbed / lost<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of the substance<br/> <mathjax>#DeltaT#</mathjax> - the change in temperature, defined as <em>final temperature</em> minus <em>initial temperature</em></p> <blockquote> <p><mathjax>#color(blue)(q = m * DeltaH_"fus")" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - heat absorbed / lost<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#DeltaH_"fus"#</mathjax> - the enthalpy of fusion of the substance</p> <p>So, to get your <mathjax>#"5.88-g"#</mathjax> sample of ice from solid at <mathjax>#-12.0^@"C"#</mathjax> to <mathjax>#9^@"C"#</mathjax>, you will need to provide it with </p> <blockquote> <p><mathjax>#q_1 = 5.88 color(red)(cancel(color(black)("g"))) * 2.09"J"/(color(red)(cancel(color(black)("g"))) color(red)(cancel(color(black)(""^@"C")))) * [0 - (-12.0)]color(red)(cancel(color(black)(""^@"C")))#</mathjax></p> <p><mathjax>#q_1 = "147.47 J"#</mathjax></p> </blockquote> <p>To get you sample to undergo a <em>solid</em> <mathjax>#-&gt;#</mathjax> <em>liquid</em> <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/introduction-to-phase-changes">phase change</a> at its melting point, i.e. at <mathjax>#0^@"C"#</mathjax>, you will need to provide it with </p> <blockquote> <p><mathjax>#q_2 = 5.88 color(red)(cancel(color(black)("g"))) * 334"J"/color(red)(cancel(color(black)("g")))#</mathjax></p> <p><mathjax>#q_2 = "1963.9 J"#</mathjax></p> </blockquote> <p>Finally, to heat the sample from <mathjax>#0^@"C"#</mathjax> to <mathjax>#25.0^@"C"#</mathjax>, you need to provide it with </p> <blockquote> <p><mathjax>#q_3 = 5.88 color(red)(cancel(color(black)("g"))) * 4.18"J"/(color(red)(cancel(color(black)("g"))) color(red)(cancel(color(black)(""^@"C")))) * (25.0 - 0)color(red)(cancel(color(black)(""^@"C")))#</mathjax></p> <p><mathjax>#q_3 = "614.46 J"#</mathjax></p> </blockquote> <p>The <em>total heat</em>* required to get your sample from ice at <mathjax>#-12.0^@"C"#</mathjax> to liquid at <mathjax>#25.0^@"C"#</mathjax> will thus be equal to </p> <blockquote> <p><mathjax>#q_"total" = q_1 + q_2 + q_3#</mathjax></p> <p><mathjax>#q_"total" = "147.47 J" + "1963.9 J" + "614.46 J"#</mathjax></p> <p><mathjax>#q_"total" = "2725.83 J"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a> and expressed in <em>kilojoules</em>, the answer will be </p> <blockquote> <p><mathjax>#q_"total" = color(green)("2.73 kJ")#</mathjax></p> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#q_"total" = "2.73 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy here will be to determine </p> <ul> <li> <p><em>how much heat is required to convert that sample of ice from <strong>solid</strong> at</em> <mathjax>#-12.0^@"C"#</mathjax> <em>to <strong>solid</strong> at</em> <mathjax>#0^@"C"#</mathjax></p> </li> <li> <p><em>determine how much heat is required to convert that sample of ice from <strong>solid</strong> at</em> <mathjax>#0^@"C"#</mathjax> <em>to <strong>liquid</strong> at</em> <mathjax>#0^@"C"#</mathjax></p> </li> <li> <p><em>finally, determine how much heat is required to heat that sample of now liquid water from</em> <mathjax>#0^@"C"#</mathjax> <em>to</em> <mathjax>#25.0^@"C"#</mathjax></p> </li> </ul> <p>In order to be able to calculate all this, you will need to know the values for the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of <em>ice</em> and that of <em>water</em>, and the value of the <em><a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of fusion</em>, <mathjax>#DeltaH_"fus"#</mathjax>, for water</p> <blockquote> <p><mathjax>#c_"ice" = 2.09"J"/("g" ""^@"C")" "#</mathjax> and <mathjax>#" "c_"water" = 4.18"J"/("g" ""^@"C")#</mathjax></p> <p><mathjax>#DeltaH_"fus" = 334"J"/"g"#</mathjax></p> </blockquote> <p><a href="http://www.engineeringtoolbox.com/latent-heat-melting-solids-d_96.html" rel="nofollow" target="_blank">http://www.engineeringtoolbox.com/latent-heat-melting-solids-d_96.html</a></p> <p>Two equations will come in handy here </p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - heat absorbed / lost<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of the substance<br/> <mathjax>#DeltaT#</mathjax> - the change in temperature, defined as <em>final temperature</em> minus <em>initial temperature</em></p> <blockquote> <p><mathjax>#color(blue)(q = m * DeltaH_"fus")" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - heat absorbed / lost<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#DeltaH_"fus"#</mathjax> - the enthalpy of fusion of the substance</p> <p>So, to get your <mathjax>#"5.88-g"#</mathjax> sample of ice from solid at <mathjax>#-12.0^@"C"#</mathjax> to <mathjax>#9^@"C"#</mathjax>, you will need to provide it with </p> <blockquote> <p><mathjax>#q_1 = 5.88 color(red)(cancel(color(black)("g"))) * 2.09"J"/(color(red)(cancel(color(black)("g"))) color(red)(cancel(color(black)(""^@"C")))) * [0 - (-12.0)]color(red)(cancel(color(black)(""^@"C")))#</mathjax></p> <p><mathjax>#q_1 = "147.47 J"#</mathjax></p> </blockquote> <p>To get you sample to undergo a <em>solid</em> <mathjax>#-&gt;#</mathjax> <em>liquid</em> <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/introduction-to-phase-changes">phase change</a> at its melting point, i.e. at <mathjax>#0^@"C"#</mathjax>, you will need to provide it with </p> <blockquote> <p><mathjax>#q_2 = 5.88 color(red)(cancel(color(black)("g"))) * 334"J"/color(red)(cancel(color(black)("g")))#</mathjax></p> <p><mathjax>#q_2 = "1963.9 J"#</mathjax></p> </blockquote> <p>Finally, to heat the sample from <mathjax>#0^@"C"#</mathjax> to <mathjax>#25.0^@"C"#</mathjax>, you need to provide it with </p> <blockquote> <p><mathjax>#q_3 = 5.88 color(red)(cancel(color(black)("g"))) * 4.18"J"/(color(red)(cancel(color(black)("g"))) color(red)(cancel(color(black)(""^@"C")))) * (25.0 - 0)color(red)(cancel(color(black)(""^@"C")))#</mathjax></p> <p><mathjax>#q_3 = "614.46 J"#</mathjax></p> </blockquote> <p>The <em>total heat</em>* required to get your sample from ice at <mathjax>#-12.0^@"C"#</mathjax> to liquid at <mathjax>#25.0^@"C"#</mathjax> will thus be equal to </p> <blockquote> <p><mathjax>#q_"total" = q_1 + q_2 + q_3#</mathjax></p> <p><mathjax>#q_"total" = "147.47 J" + "1963.9 J" + "614.46 J"#</mathjax></p> <p><mathjax>#q_"total" = "2725.83 J"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a> and expressed in <em>kilojoules</em>, the answer will be </p> <blockquote> <p><mathjax>#q_"total" = color(green)("2.73 kJ")#</mathjax></p> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How much heat is required to convert 5.88 g of ice at -12.0°C to water at 25.0°C, if the heat capacity of ice is 2.09 J/°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/calorimetry" itemprop="url"> <span class="breadcrumb" itemprop="title">Calorimetry</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="207050" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-02T14:50:43" itemprop="dateCreated"> Jan 2, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#q_"total" = "2.73 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Your strategy here will be to determine </p> <ul> <li> <p><em>how much heat is required to convert that sample of ice from <strong>solid</strong> at</em> <mathjax>#-12.0^@"C"#</mathjax> <em>to <strong>solid</strong> at</em> <mathjax>#0^@"C"#</mathjax></p> </li> <li> <p><em>determine how much heat is required to convert that sample of ice from <strong>solid</strong> at</em> <mathjax>#0^@"C"#</mathjax> <em>to <strong>liquid</strong> at</em> <mathjax>#0^@"C"#</mathjax></p> </li> <li> <p><em>finally, determine how much heat is required to heat that sample of now liquid water from</em> <mathjax>#0^@"C"#</mathjax> <em>to</em> <mathjax>#25.0^@"C"#</mathjax></p> </li> </ul> <p>In order to be able to calculate all this, you will need to know the values for the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of <em>ice</em> and that of <em>water</em>, and the value of the <em><a href="http://socratic.org/chemistry/thermochemistry/enthalpy">enthalpy</a> of fusion</em>, <mathjax>#DeltaH_"fus"#</mathjax>, for water</p> <blockquote> <p><mathjax>#c_"ice" = 2.09"J"/("g" ""^@"C")" "#</mathjax> and <mathjax>#" "c_"water" = 4.18"J"/("g" ""^@"C")#</mathjax></p> <p><mathjax>#DeltaH_"fus" = 334"J"/"g"#</mathjax></p> </blockquote> <p><a href="http://www.engineeringtoolbox.com/latent-heat-melting-solids-d_96.html" rel="nofollow" target="_blank">http://www.engineeringtoolbox.com/latent-heat-melting-solids-d_96.html</a></p> <p>Two equations will come in handy here </p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - heat absorbed / lost<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of the substance<br/> <mathjax>#DeltaT#</mathjax> - the change in temperature, defined as <em>final temperature</em> minus <em>initial temperature</em></p> <blockquote> <p><mathjax>#color(blue)(q = m * DeltaH_"fus")" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - heat absorbed / lost<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#DeltaH_"fus"#</mathjax> - the enthalpy of fusion of the substance</p> <p>So, to get your <mathjax>#"5.88-g"#</mathjax> sample of ice from solid at <mathjax>#-12.0^@"C"#</mathjax> to <mathjax>#9^@"C"#</mathjax>, you will need to provide it with </p> <blockquote> <p><mathjax>#q_1 = 5.88 color(red)(cancel(color(black)("g"))) * 2.09"J"/(color(red)(cancel(color(black)("g"))) color(red)(cancel(color(black)(""^@"C")))) * [0 - (-12.0)]color(red)(cancel(color(black)(""^@"C")))#</mathjax></p> <p><mathjax>#q_1 = "147.47 J"#</mathjax></p> </blockquote> <p>To get you sample to undergo a <em>solid</em> <mathjax>#-&gt;#</mathjax> <em>liquid</em> <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/introduction-to-phase-changes">phase change</a> at its melting point, i.e. at <mathjax>#0^@"C"#</mathjax>, you will need to provide it with </p> <blockquote> <p><mathjax>#q_2 = 5.88 color(red)(cancel(color(black)("g"))) * 334"J"/color(red)(cancel(color(black)("g")))#</mathjax></p> <p><mathjax>#q_2 = "1963.9 J"#</mathjax></p> </blockquote> <p>Finally, to heat the sample from <mathjax>#0^@"C"#</mathjax> to <mathjax>#25.0^@"C"#</mathjax>, you need to provide it with </p> <blockquote> <p><mathjax>#q_3 = 5.88 color(red)(cancel(color(black)("g"))) * 4.18"J"/(color(red)(cancel(color(black)("g"))) color(red)(cancel(color(black)(""^@"C")))) * (25.0 - 0)color(red)(cancel(color(black)(""^@"C")))#</mathjax></p> <p><mathjax>#q_3 = "614.46 J"#</mathjax></p> </blockquote> <p>The <em>total heat</em>* required to get your sample from ice at <mathjax>#-12.0^@"C"#</mathjax> to liquid at <mathjax>#25.0^@"C"#</mathjax> will thus be equal to </p> <blockquote> <p><mathjax>#q_"total" = q_1 + q_2 + q_3#</mathjax></p> <p><mathjax>#q_"total" = "147.47 J" + "1963.9 J" + "614.46 J"#</mathjax></p> <p><mathjax>#q_"total" = "2725.83 J"#</mathjax></p> </blockquote> <p>Rounded to three <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">sig figs</a> and expressed in <em>kilojoules</em>, the answer will be </p> <blockquote> <p><mathjax>#q_"total" = color(green)("2.73 kJ")#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/207050" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-differential-scanning-in-calorimetry-work"> How does differential scanning in calorimetry work? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-read-differential-scanning-in-calorimetry"> What information do you get from a differential scanning calorimetry plot? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-measure-calorimetry"> How do you measure calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/531d304102bf341e75b962a7"> Question #962a7 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5335021802bf344ae911dfc5"> Question #1dfc5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/533668f502bf34572c341af6"> Question #41af6 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-definition-of-calorimetry"> What is calorimetry? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-differential-scanning-calorimeter"> What is a differential scanning calorimeter? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-a-calorimeter-measure-energy"> How can a calorimeter measure energy? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-calorimeters-made-of"> What are calorimeters made of? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/thermochemistry/calorimetry"> See all questions in Calorimetry </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 74763 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How much heat is required to convert 5.88 g of ice at -12.0°C to water at 25.0°C, if the heat capacity of ice is 2.09 J/°C?

a837a702-6ddd-11ea-bbc3-ccda262736ce

https://socratic.org/questions/what-is-the-covalent-compound-formula-for-nitric-acid

NO2OH

start chemical_formula qc_end substance 7 8 qc_end end

[{"type":"other","value":"Chemical Formula [OF] the covalent compound [IN] default"}]

[{"type":"chemical equation","value":"NO2OH"}]

[{"type":"substance name","value":"Nitric Acid"}]

<h1 class="questionTitle" itemprop="name">What is the covalent compound formula for Nitric Acid?</h1>

NO2OH

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Imagine the <mathjax>#N#</mathjax> with 5 valencies, in the centre. Four of those are taken by two double-bonded <mathjax>#O#</mathjax>, and the fifth is taken by an <mathjax>#OH#</mathjax></p> <p>In a watery environment, the <mathjax>#H#</mathjax> is quickly 'donated' to a water molecule in the form of an <mathjax>#H^+#</mathjax> to form the hydronium or acid ion <mathjax>#H_3O^+#</mathjax>, leving the <mathjax>#NO_3^-#</mathjax> ion.</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>It would be <mathjax>#NO_2OH#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Imagine the <mathjax>#N#</mathjax> with 5 valencies, in the centre. Four of those are taken by two double-bonded <mathjax>#O#</mathjax>, and the fifth is taken by an <mathjax>#OH#</mathjax></p> <p>In a watery environment, the <mathjax>#H#</mathjax> is quickly 'donated' to a water molecule in the form of an <mathjax>#H^+#</mathjax> to form the hydronium or acid ion <mathjax>#H_3O^+#</mathjax>, leving the <mathjax>#NO_3^-#</mathjax> ion.</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the covalent compound formula for Nitric Acid?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/covalent-compounds" itemprop="url"> <span class="breadcrumb" itemprop="title">Covalent compounds</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="363894" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meneernask"><img alt="" class="" src="https://profilepictures.socratic.org/gpA0lokRGK9vLVUnAMAy_meneernask.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meneernask"> MeneerNask </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-01-13T03:45:42" itemprop="dateCreated"> Jan 13, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>It would be <mathjax>#NO_2OH#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Imagine the <mathjax>#N#</mathjax> with 5 valencies, in the centre. Four of those are taken by two double-bonded <mathjax>#O#</mathjax>, and the fifth is taken by an <mathjax>#OH#</mathjax></p> <p>In a watery environment, the <mathjax>#H#</mathjax> is quickly 'donated' to a water molecule in the form of an <mathjax>#H^+#</mathjax> to form the hydronium or acid ion <mathjax>#H_3O^+#</mathjax>, leving the <mathjax>#NO_3^-#</mathjax> ion.</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/363894" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/534baa5402bf34123fdc4f8c"> Question #c4f8c </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-a-covalent-compound"> What is a covalent compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-examples-of-covalent-compounds-1"> What are some examples of covalent compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-an-example-of-a-covalent-compound-practice-problem"> What is an example of a covalent compound practice problem? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-calcium-sulfate-an-ionic-or-covalent-compound"> Is calcium sulfate an ionic or covalent compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-can-covalent-compounds-conduct-electricity"> Why can covalent compounds conduct electricity? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-covalent-compounds-differ-from-ionic-compounds"> How do covalent compounds differ from ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-do-covalent-compounds-follow-the-octet-rule"> Why do covalent compounds follow the octet rule? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-covalent-compound-is-co"> What covalent compound is CO? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-covalent-compound-is-n2s"> What covalent compound is N2S? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/covalent-compounds"> See all questions in Covalent compounds </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 2065 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the covalent compound formula for Nitric Acid?

a9cda212-6ddd-11ea-a486-ccda262736ce

https://socratic.org/questions/how-do-you-write-the-formula-for-calcium-fluoride

CaF2

start chemical_formula qc_end substance 7 8 qc_end end

[{"type":"other","value":"Chemical Formula [OF] calcium fluoride [IN] default"}]

[{"type":"chemical equation","value":"CaF2"}]

[{"type":"substance name","value":"Calcium fluoride"}]

<h1 class="questionTitle" itemprop="name">How do you write the formula for calcium fluoride?</h1>

CaF2

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>An ionic compound is neutral, which means its overall charge is zero. Therefore, the sum of the charges of each ion in the compound must equal zero.</p> <p>In calcium fluoride, the calcium ion <mathjax>#"Ca"^(2+)"#</mathjax>, has a charge of <mathjax>#2+#</mathjax>, and the fluoride ion <mathjax>#"F"^(1-)"#</mathjax> has a charge of <mathjax>#1-#</mathjax>. We will need two fluoride ions to make the overall charge zero.</p> <p><mathjax>#"Ca"^(2+)"+ 2F"^(1-)"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"CaF"_2"#</mathjax></p> <p>There is a method that makes it fairly easy to determine the formula unit of an ionic compound. It's called the crisscross method. In the crisscross method, the size of the charge of each ion becomes the subscript of the other ion.</p> <p><img alt="http://mcclearyeocchemreview.weebly.com/reporting-category-3-bonding-and-chemical-reactions.html" src="https://useruploads.socratic.org/jeTgY1ZgSvuWHsEg5DRw_3370902.jpg"/> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The formula for calcium fluoride is <mathjax>#"CaF"_2"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>An ionic compound is neutral, which means its overall charge is zero. Therefore, the sum of the charges of each ion in the compound must equal zero.</p> <p>In calcium fluoride, the calcium ion <mathjax>#"Ca"^(2+)"#</mathjax>, has a charge of <mathjax>#2+#</mathjax>, and the fluoride ion <mathjax>#"F"^(1-)"#</mathjax> has a charge of <mathjax>#1-#</mathjax>. We will need two fluoride ions to make the overall charge zero.</p> <p><mathjax>#"Ca"^(2+)"+ 2F"^(1-)"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"CaF"_2"#</mathjax></p> <p>There is a method that makes it fairly easy to determine the formula unit of an ionic compound. It's called the crisscross method. In the crisscross method, the size of the charge of each ion becomes the subscript of the other ion.</p> <p><img alt="http://mcclearyeocchemreview.weebly.com/reporting-category-3-bonding-and-chemical-reactions.html" src="https://useruploads.socratic.org/jeTgY1ZgSvuWHsEg5DRw_3370902.jpg"/> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you write the formula for calcium fluoride?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/determining-formula-and-molar-masses" itemprop="url"> <span class="breadcrumb" itemprop="title">Determining Formula</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="211423" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/meave60"><img alt="" class="" src="https://profilepictures.socratic.org/4se3PnQTNiJS64rgWMfs_UYDz0EsWQUOLMGhTLDxt_jack%2520russell%2520rainbow.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/meave60"> Meave60 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-12T05:05:27" itemprop="dateCreated"> Jan 12, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>The formula for calcium fluoride is <mathjax>#"CaF"_2"#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>An ionic compound is neutral, which means its overall charge is zero. Therefore, the sum of the charges of each ion in the compound must equal zero.</p> <p>In calcium fluoride, the calcium ion <mathjax>#"Ca"^(2+)"#</mathjax>, has a charge of <mathjax>#2+#</mathjax>, and the fluoride ion <mathjax>#"F"^(1-)"#</mathjax> has a charge of <mathjax>#1-#</mathjax>. We will need two fluoride ions to make the overall charge zero.</p> <p><mathjax>#"Ca"^(2+)"+ 2F"^(1-)"#</mathjax><mathjax>#rarr#</mathjax><mathjax>#"CaF"_2"#</mathjax></p> <p>There is a method that makes it fairly easy to determine the formula unit of an ionic compound. It's called the crisscross method. In the crisscross method, the size of the charge of each ion becomes the subscript of the other ion.</p> <p><img alt="http://mcclearyeocchemreview.weebly.com/reporting-category-3-bonding-and-chemical-reactions.html" src="https://useruploads.socratic.org/jeTgY1ZgSvuWHsEg5DRw_3370902.jpg"/> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/211423" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/is-it-possible-to-find-a-molecular-formula-from-molar-mass"> Is it possible to find a molecular formula from molar mass? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5368e0cc02bf34779e175781"> Question #75781 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-are-some-common-mistakes-students-make-when-determining-formulas"> What are some common mistakes students make when determining formulas? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-an-acid"> How can I determine the formula of an acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-chemical-formula-of-a-product"> How can I determine the chemical formula of a product? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-empirical-formula-of-a-compound"> How can I determine the empirical formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-determine-the-formula-of-a-hydrate"> How can I determine the formula of a hydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-does-the-empirical-formula-indicate"> What does the empirical formula indicate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-molecule-with-molecular-weight-of-180-18-g-mol-is-analyzed-and-found-to-contai"> A molecule with molecular weight of 180.18 g/mol is analyzed and found to contain 40.00% carbon,... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/do-i-need-to-know-the-number-of-moles-of-each-element-to-determine-the-formula-o"> Do I need to know the number of moles of each element to determine the formula of the compound? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/determining-formula-and-molar-masses"> See all questions in Determining Formula </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 52807 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

How do you write the formula for calcium fluoride?

a9217876-6ddd-11ea-8c49-ccda262736ce

https://socratic.org/questions/the-volume-v-of-gas-varies-inversely-as-the-pressure-p-on-it-the-volume-of-a-gas

140 cm^3

start physical_unit 4 4 volume cm^3 qc_end physical_unit 4 4 19 20 volume qc_end physical_unit 4 4 25 26 pressure qc_end physical_unit 4 4 35 36 pressure qc_end c_other OTHER qc_end end

[{"type":"physical unit","value":"Volume2 [OF] the gas [IN] cm^3"}]

[{"type":"physical unit","value":"140 cm^3"}]

[{"type":"physical unit","value":"Volume1 [OF] the gas [=] \\pu{200 cm^3}"},{"type":"physical unit","value":"Pressure1 [OF] the gas [=] \\pu{21 kg/cm^2}"},{"type":"physical unit","value":"Pressure2 [OF] the gas [=] \\pu{30 kg/cm^2}"},{"type":"other","value":"The volume V of gas varies inversely as the pressure P on it."}]

<h1 class="questionTitle" itemprop="name">The volume V of gas varies inversely as the pressure P on it. The volume of a gas is 200 cm^3 under a pressure of 21 kg/cm^2. What will it's volume under a pressure of 30/kg/cm^2?</h1>

140 cm^3

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Boyle's law states that for a fixed mass of gas at constant temperature, the absolute pressure and the volume of a gas are inversely proportional.<br/> <mathjax>#p1*v1 =p2*v2#</mathjax></p> <p>So,<br/> <mathjax>#p1*v1 =p2*v2#</mathjax><br/> 21 kg/<mathjax>#cm^2#</mathjax> × 200 <mathjax>#cm^3#</mathjax> = 30 kg/<mathjax>#cm^2#</mathjax>× <strong>v2</strong></p> <p><strong>v2</strong> = 140 <mathjax>#cm^2#</mathjax></p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>140 <mathjax>#cm^2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Boyle's law states that for a fixed mass of gas at constant temperature, the absolute pressure and the volume of a gas are inversely proportional.<br/> <mathjax>#p1*v1 =p2*v2#</mathjax></p> <p>So,<br/> <mathjax>#p1*v1 =p2*v2#</mathjax><br/> 21 kg/<mathjax>#cm^2#</mathjax> × 200 <mathjax>#cm^3#</mathjax> = 30 kg/<mathjax>#cm^2#</mathjax>× <strong>v2</strong></p> <p><strong>v2</strong> = 140 <mathjax>#cm^2#</mathjax></p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">The volume V of gas varies inversely as the pressure P on it. The volume of a gas is 200 cm^3 under a pressure of 21 kg/cm^2. What will it's volume under a pressure of 30/kg/cm^2?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-behavior-of-gases" itemprop="url"> <span class="breadcrumb" itemprop="title">Gases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-behavior-of-gases/boyle-s-law" itemprop="url"> <span class="breadcrumb" itemprop="title">Boyle's Law</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="327519" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/sobiya"><img alt="" class="" src="https://profilepictures.socratic.org/RbdM23WSyepkAwZEEKEw_Screen%20Shot%202017-09-21%20at%202.25.34%20PM.png" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/sobiya"> Sobiya </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-10-27T20:04:06" itemprop="dateCreated"> Oct 27, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>140 <mathjax>#cm^2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Boyle's law states that for a fixed mass of gas at constant temperature, the absolute pressure and the volume of a gas are inversely proportional.<br/> <mathjax>#p1*v1 =p2*v2#</mathjax></p> <p>So,<br/> <mathjax>#p1*v1 =p2*v2#</mathjax><br/> 21 kg/<mathjax>#cm^2#</mathjax> × 200 <mathjax>#cm^3#</mathjax> = 30 kg/<mathjax>#cm^2#</mathjax>× <strong>v2</strong></p> <p><strong>v2</strong> = 140 <mathjax>#cm^2#</mathjax></p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/327519" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-graph-boyles-law"> How do you graph Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-functional-groups-are-found-in-lipids"> What functional groups are found in lipids? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-k-constant-in-boyle-s-law"> Why is k constant in Boyle's law? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-graph-curved-1"> Why is Boyle's law graph curved? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-boyle-s-law-an-inverse-relationship-2"> Why is Boyle's law an inverse relationship? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/a-40-0-l-tank-of-ammonia-has-a-pressure-of-8-00-atm-calculate-the-volume-of-the-"> A 40.0 L tank of ammonia has a pressure of 8.00 atm. 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The volume V of gas varies inversely as the pressure P on it. The volume of a gas is 200 cm^3 under a pressure of 21 kg/cm^2. What will it's volume under a pressure of 30/kg/cm^2?

ac3d28cb-6ddd-11ea-9c09-ccda262736ce

https://socratic.org/questions/what-is-the-formula-of-the-conjugate-acid-of-hso-4

H2SO4

start chemical_formula qc_end chemical_equation 9 9 qc_end end

[{"type":"other","value":"Chemical Formula [OF] the conjugate acid [IN] default"}]

[{"type":"chemical equation","value":"H2SO4"}]

[{"type":"chemical equation","value":"HSO4-"}]

<h1 class="questionTitle" itemprop="name">What is the formula of the conjugate acid of #HSO_4^-#?</h1>

H2SO4

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The conjugate acid of a species is simply the original species PLUS a proton, <mathjax>#H^+#</mathjax>. As with all such exercises, both mass and charge are CONSERVED. What do I mean here?</p> <p>Can you tell the conjugate acid of sulfate ion, <mathjax>#SO_4^(2-)#</mathjax>, and the conjugate acid of <mathjax>#H_2SO_4#</mathjax>?</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_2SO_4#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The conjugate acid of a species is simply the original species PLUS a proton, <mathjax>#H^+#</mathjax>. As with all such exercises, both mass and charge are CONSERVED. What do I mean here?</p> <p>Can you tell the conjugate acid of sulfate ion, <mathjax>#SO_4^(2-)#</mathjax>, and the conjugate acid of <mathjax>#H_2SO_4#</mathjax>?</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the formula of the conjugate acid of #HSO_4^-#?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#acids-and-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Acids and Bases</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/acids-and-bases/conjugate-acids-and-conjugate-bases" itemprop="url"> <span class="breadcrumb" itemprop="title">Conjugate Acids and Conjugate Bases</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="293141" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-07-29T05:07:23" itemprop="dateCreated"> Jul 29, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#H_2SO_4#</mathjax>.</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The conjugate acid of a species is simply the original species PLUS a proton, <mathjax>#H^+#</mathjax>. As with all such exercises, both mass and charge are CONSERVED. What do I mean here?</p> <p>Can you tell the conjugate acid of sulfate ion, <mathjax>#SO_4^(2-)#</mathjax>, and the conjugate acid of <mathjax>#H_2SO_4#</mathjax>?</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/293141" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-does-a-conjugate-base-differ-from-the-acid-hbr"> How does a conjugate base differ from the acid hbr? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-conjugate-base-concentration"> How do you find conjugate base concentration? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-identify-conjugate-acid-base-pairs"> How do you identify conjugate acid base pairs? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-conjugate-base-will-deprotonate-water"> What conjugate base(s) will deprotonate water? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-conjugate-acid-of-hco3-"> What is the conjugate acid of #HCO_3^-#? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-conjugate-base-of-a-strong-acid-weak"> Why is the conjugate base of a strong acid weak? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-conjugate-base-of-h2so4"> What is the conjugate base of h2so4? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-weak-acids-and-bases-poor-electrical-conductors"> Why are weak acids and bases poor electrical conductors? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-identify-conjugate-acids-and-bases"> How can I identify conjugate acids and bases? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-strong-acids-react-in-water"> How do strong acids react in water? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/acids-and-bases/conjugate-acids-and-conjugate-bases"> See all questions in Conjugate Acids and Conjugate Bases </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 1711 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the formula of the conjugate acid of #HSO_4^-#?

a8e49e4e-6ddd-11ea-a91c-ccda262736ce

https://socratic.org/questions/how-do-you-find-the-molecular-formula-of-nicotine-cxhynz-when-0-438-grams-of-nic

C10H14N2

start chemical_formula qc_end physical_unit 20 20 18 19 mass qc_end physical_unit 24 24 22 23 mass qc_end physical_unit 8 8 11 12 mass qc_end physical_unit 8 8 32 35 molecular_weight qc_end end

[{"type":"other","value":"Chemical Formula [OF] CxHyNz [IN] molecular"}]

[{"type":"chemical equation","value":"C10H14N2"}]

[{"type":"physical unit","value":"Mass [OF] CO2 [=] \\pu{1.188 g}"},{"type":"physical unit","value":"Mass [OF] H2O [=] \\pu{0.341 g}"},{"type":"physical unit","value":"Mass [OF] nicotine [=] \\pu{0.438 grams}"},{"type":"physical unit","value":"Molecular weight [OF] nicotine [=] \\pu{162.2 g per mole}"}]

<h1 class="questionTitle" itemprop="name">How do you find the molecular formula of nicotine (CxHyNz), when 0.438 grams of nicotine burns to make 1.188 g CO2 and 0.341 g H2O? The molecular weight of the nicotine is 162.2g per mole. </h1>

C10H14N2

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>!! LONG ANSWER !!</strong></p> <p>Notice that despite the fact that nicotine is said to contain carbon, hydrogen, <strong>and</strong> nitrogen, the problem only provides you with information about how much carbon dioxide, <mathjax>#"CO"_2#</mathjax>, and water, <mathjax>#"H"_2"O"#</mathjax>, are produced by the reaction. </p> <p>This means that you will have to determine the mass of nitrogen <em>by subtracting</em> the mass of carbon and the mass of hydrogen from the <strong>total mass</strong> of the sample. </p> <p>So, the idea here is that after compound undergoes combustion, <strong>all the carbon</strong> that it originally contained will not be apart of the carbon dioxide. </p> <p>Likewise, <strong>all the hydrogen</strong> that it originally contained will now be a part of the water. </p> <p>Use the <a href="http://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of carbon dioxide to determine how much carbon you'd get in that <mathjax>#"1.188-g"#</mathjax> sample of <mathjax>#"CO"_2#</mathjax> - keep in mind that <strong>every mole</strong> of carbon dioxide contains <strong>one mole</strong> of carbon</p> <blockquote> <p><mathjax>#(1 xx 12.011 color(red)(cancel(color(black)("g/mol"))))/(44.01color(red)(cancel(color(black)("g/mol")))) xx 100 = "27.29% C"#</mathjax></p> </blockquote> <p>This tells you that <strong>every</strong> <mathjax>#"100 g"#</mathjax> of carbon dioxide will contain <mathjax>#"27.29 g"#</mathjax> of carbon. Your sample will thus contain </p> <blockquote> <p><mathjax>#1.188 color(red)(cancel(color(black)("g CO"_2))) * "27.29 g C"/(100color(red)(cancel(color(black)("g CO"_2)))) = "0.324 g C"#</mathjax></p> </blockquote> <p>Do the same for water, but <strong>do not</strong> forget that <strong>every mole</strong> of water contains <strong>two moles</strong> of hydrogen </p> <blockquote> <p><mathjax>#(2 xx 1.00794color(red)(cancel(color(black)("g/mol"))))/(18.015color(red)(cancel(color(black)("g/mol")))) xx 100 = "11.19% H"#</mathjax></p> </blockquote> <p>This means that your <mathjax>#"0.341-g"#</mathjax> sample of water will contain </p> <blockquote> <p><mathjax>#0.341 color(red)(cancel(color(black)("g H"_2"O"))) * "11.19 g H"/(100color(red)(cancel(color(black)("g H"_2"O")))) = "0.0382 g H"#</mathjax></p> </blockquote> <p>The mass of <strong>nitrogen</strong> originally contained in the nicotine sample will thus be </p> <blockquote> <p><mathjax>#m_"sample" = m_(N) + m_(H) + m_(C)#</mathjax></p> <p><mathjax>#m_(N) = "0.438 g" - "0.324 g" - "0.0382 g"#</mathjax></p> <p><mathjax>#m_(N) = "0.0758 g N"#</mathjax></p> </blockquote> <p>Next, focus on finding the compound's <strong>empirical formula</strong>, which as you know tells you the <strong>smallest whole number ratio</strong> that exists between the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> that make up the compound. </p> <p>To do that, use the <strong>molar masses</strong> of carbon, hydrogen, and nitrogen, respectively, to find how many <em>moles</em> of each you get in the original sample</p> <blockquote> <p><mathjax>#"For C: " (0.324 color(red)(cancel(color(black)("g"))))/(12.0110.324 color(red)(cancel(color(black)("g")))/"mol") = "0.02698 moles C"#</mathjax></p> <p><mathjax>#"For H: " (0.0382 color(red)(cancel(color(black)("g"))))/(1.00794color(red)(cancel(color(black)("g")))/"mol") = "0.03790 moles H"#</mathjax></p> <p><mathjax>#"For N: " (0.0758 color(red)(cancel(color(black)("g"))))/(14.007color(red)(cancel(color(black)("g")))/"mol") = "0.005412 moles N"#</mathjax></p> </blockquote> <p>Divide these values by the <em>smallest one</em> to get </p> <blockquote> <p><mathjax>#"For C: " (0.02698color(red)(cancel(color(black)("moles"))))/(0.005412color(red)(cancel(color(black)("moles")))) = 4.985 ~~ 5#</mathjax></p> <p><mathjax>#"For H: " (0.03790color(red)(cancel(color(black)("moles"))))/(0.005412color(red)(cancel(color(black)("moles")))) = 7.003 ~~ 7#</mathjax></p> <p><mathjax>#"For N: " (0.005412color(red)(cancel(color(black)("moles"))))/(0.005412color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> </blockquote> <p>The <em>empirical formula</em> of nicotine will thus be </p> <blockquote> <p><mathjax>#"C"_5"H"_7"N"_1#</mathjax></p> </blockquote> <p>Now, the <strong>molecular formula</strong>, which tells you <strong>exactly</strong> how many atoms of each element are needed to form a molecule of your compound, will <strong>always</strong> be a whole number multiple of the empirical formula.</p> <p>This means that if you find the <strong>molar mass</strong> of the empirical formula, you can use the molar mass of the compound to find the molecular formula. </p> <p>The molar mass of the empirical formula will be </p> <blockquote> <p><mathjax>#5 xx "12.011 g/mol" + 7 xx "1.00794 g/mol" + 1 xx "14.007 g/mol" = "81.12 g/mol"#</mathjax></p> </blockquote> <p>This means that you have </p> <blockquote> <p><mathjax>#81.12 color(red)(cancel(color(black)("g/mol"))) xx color(blue)(n) = 162.2 color(red)(cancel(color(black)("g/mol")))#</mathjax></p> </blockquote> <p>Therefore, </p> <blockquote> <p><mathjax>#color(blue)(n) = 162.2/81.12 = 1.9995 ~~ 2#</mathjax></p> </blockquote> <p>The <strong>molecular formula</strong> of nicotine will thus be </p> <blockquote> <p><mathjax>#("C"_5"H"_7"N"_1)_color(blue)(2) implies color(green)("C"_10"H"_14"N"_2)#</mathjax></p> </blockquote> <p><img alt="http://www.dreamstime.com/royalty-free-stock-photography-molecule-nicotine-image14804357" src="https://useruploads.socratic.org/5gSrSObSf68ESCwoWhFh_nicotine-molecule-11084558.jpg"/> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"C"_10"H"_14"N"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>!! LONG ANSWER !!</strong></p> <p>Notice that despite the fact that nicotine is said to contain carbon, hydrogen, <strong>and</strong> nitrogen, the problem only provides you with information about how much carbon dioxide, <mathjax>#"CO"_2#</mathjax>, and water, <mathjax>#"H"_2"O"#</mathjax>, are produced by the reaction. </p> <p>This means that you will have to determine the mass of nitrogen <em>by subtracting</em> the mass of carbon and the mass of hydrogen from the <strong>total mass</strong> of the sample. </p> <p>So, the idea here is that after compound undergoes combustion, <strong>all the carbon</strong> that it originally contained will not be apart of the carbon dioxide. </p> <p>Likewise, <strong>all the hydrogen</strong> that it originally contained will now be a part of the water. </p> <p>Use the <a href="http://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of carbon dioxide to determine how much carbon you'd get in that <mathjax>#"1.188-g"#</mathjax> sample of <mathjax>#"CO"_2#</mathjax> - keep in mind that <strong>every mole</strong> of carbon dioxide contains <strong>one mole</strong> of carbon</p> <blockquote> <p><mathjax>#(1 xx 12.011 color(red)(cancel(color(black)("g/mol"))))/(44.01color(red)(cancel(color(black)("g/mol")))) xx 100 = "27.29% C"#</mathjax></p> </blockquote> <p>This tells you that <strong>every</strong> <mathjax>#"100 g"#</mathjax> of carbon dioxide will contain <mathjax>#"27.29 g"#</mathjax> of carbon. Your sample will thus contain </p> <blockquote> <p><mathjax>#1.188 color(red)(cancel(color(black)("g CO"_2))) * "27.29 g C"/(100color(red)(cancel(color(black)("g CO"_2)))) = "0.324 g C"#</mathjax></p> </blockquote> <p>Do the same for water, but <strong>do not</strong> forget that <strong>every mole</strong> of water contains <strong>two moles</strong> of hydrogen </p> <blockquote> <p><mathjax>#(2 xx 1.00794color(red)(cancel(color(black)("g/mol"))))/(18.015color(red)(cancel(color(black)("g/mol")))) xx 100 = "11.19% H"#</mathjax></p> </blockquote> <p>This means that your <mathjax>#"0.341-g"#</mathjax> sample of water will contain </p> <blockquote> <p><mathjax>#0.341 color(red)(cancel(color(black)("g H"_2"O"))) * "11.19 g H"/(100color(red)(cancel(color(black)("g H"_2"O")))) = "0.0382 g H"#</mathjax></p> </blockquote> <p>The mass of <strong>nitrogen</strong> originally contained in the nicotine sample will thus be </p> <blockquote> <p><mathjax>#m_"sample" = m_(N) + m_(H) + m_(C)#</mathjax></p> <p><mathjax>#m_(N) = "0.438 g" - "0.324 g" - "0.0382 g"#</mathjax></p> <p><mathjax>#m_(N) = "0.0758 g N"#</mathjax></p> </blockquote> <p>Next, focus on finding the compound's <strong>empirical formula</strong>, which as you know tells you the <strong>smallest whole number ratio</strong> that exists between the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> that make up the compound. </p> <p>To do that, use the <strong>molar masses</strong> of carbon, hydrogen, and nitrogen, respectively, to find how many <em>moles</em> of each you get in the original sample</p> <blockquote> <p><mathjax>#"For C: " (0.324 color(red)(cancel(color(black)("g"))))/(12.0110.324 color(red)(cancel(color(black)("g")))/"mol") = "0.02698 moles C"#</mathjax></p> <p><mathjax>#"For H: " (0.0382 color(red)(cancel(color(black)("g"))))/(1.00794color(red)(cancel(color(black)("g")))/"mol") = "0.03790 moles H"#</mathjax></p> <p><mathjax>#"For N: " (0.0758 color(red)(cancel(color(black)("g"))))/(14.007color(red)(cancel(color(black)("g")))/"mol") = "0.005412 moles N"#</mathjax></p> </blockquote> <p>Divide these values by the <em>smallest one</em> to get </p> <blockquote> <p><mathjax>#"For C: " (0.02698color(red)(cancel(color(black)("moles"))))/(0.005412color(red)(cancel(color(black)("moles")))) = 4.985 ~~ 5#</mathjax></p> <p><mathjax>#"For H: " (0.03790color(red)(cancel(color(black)("moles"))))/(0.005412color(red)(cancel(color(black)("moles")))) = 7.003 ~~ 7#</mathjax></p> <p><mathjax>#"For N: " (0.005412color(red)(cancel(color(black)("moles"))))/(0.005412color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> </blockquote> <p>The <em>empirical formula</em> of nicotine will thus be </p> <blockquote> <p><mathjax>#"C"_5"H"_7"N"_1#</mathjax></p> </blockquote> <p>Now, the <strong>molecular formula</strong>, which tells you <strong>exactly</strong> how many atoms of each element are needed to form a molecule of your compound, will <strong>always</strong> be a whole number multiple of the empirical formula.</p> <p>This means that if you find the <strong>molar mass</strong> of the empirical formula, you can use the molar mass of the compound to find the molecular formula. </p> <p>The molar mass of the empirical formula will be </p> <blockquote> <p><mathjax>#5 xx "12.011 g/mol" + 7 xx "1.00794 g/mol" + 1 xx "14.007 g/mol" = "81.12 g/mol"#</mathjax></p> </blockquote> <p>This means that you have </p> <blockquote> <p><mathjax>#81.12 color(red)(cancel(color(black)("g/mol"))) xx color(blue)(n) = 162.2 color(red)(cancel(color(black)("g/mol")))#</mathjax></p> </blockquote> <p>Therefore, </p> <blockquote> <p><mathjax>#color(blue)(n) = 162.2/81.12 = 1.9995 ~~ 2#</mathjax></p> </blockquote> <p>The <strong>molecular formula</strong> of nicotine will thus be </p> <blockquote> <p><mathjax>#("C"_5"H"_7"N"_1)_color(blue)(2) implies color(green)("C"_10"H"_14"N"_2)#</mathjax></p> </blockquote> <p><img alt="http://www.dreamstime.com/royalty-free-stock-photography-molecule-nicotine-image14804357" src="https://useruploads.socratic.org/5gSrSObSf68ESCwoWhFh_nicotine-molecule-11084558.jpg"/> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">How do you find the molecular formula of nicotine (CxHyNz), when 0.438 grams of nicotine burns to make 1.188 g CO2 and 0.341 g H2O? The molecular weight of the nicotine is 162.2g per mole. </h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="209610" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2016-01-08T00:04:17" itemprop="dateCreated"> Jan 8, 2016 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"C"_10"H"_14"N"_2#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><strong>!! LONG ANSWER !!</strong></p> <p>Notice that despite the fact that nicotine is said to contain carbon, hydrogen, <strong>and</strong> nitrogen, the problem only provides you with information about how much carbon dioxide, <mathjax>#"CO"_2#</mathjax>, and water, <mathjax>#"H"_2"O"#</mathjax>, are produced by the reaction. </p> <p>This means that you will have to determine the mass of nitrogen <em>by subtracting</em> the mass of carbon and the mass of hydrogen from the <strong>total mass</strong> of the sample. </p> <p>So, the idea here is that after compound undergoes combustion, <strong>all the carbon</strong> that it originally contained will not be apart of the carbon dioxide. </p> <p>Likewise, <strong>all the hydrogen</strong> that it originally contained will now be a part of the water. </p> <p>Use the <a href="http://socratic.org/chemistry/the-mole-concept/percent-composition">percent composition</a> of carbon dioxide to determine how much carbon you'd get in that <mathjax>#"1.188-g"#</mathjax> sample of <mathjax>#"CO"_2#</mathjax> - keep in mind that <strong>every mole</strong> of carbon dioxide contains <strong>one mole</strong> of carbon</p> <blockquote> <p><mathjax>#(1 xx 12.011 color(red)(cancel(color(black)("g/mol"))))/(44.01color(red)(cancel(color(black)("g/mol")))) xx 100 = "27.29% C"#</mathjax></p> </blockquote> <p>This tells you that <strong>every</strong> <mathjax>#"100 g"#</mathjax> of carbon dioxide will contain <mathjax>#"27.29 g"#</mathjax> of carbon. Your sample will thus contain </p> <blockquote> <p><mathjax>#1.188 color(red)(cancel(color(black)("g CO"_2))) * "27.29 g C"/(100color(red)(cancel(color(black)("g CO"_2)))) = "0.324 g C"#</mathjax></p> </blockquote> <p>Do the same for water, but <strong>do not</strong> forget that <strong>every mole</strong> of water contains <strong>two moles</strong> of hydrogen </p> <blockquote> <p><mathjax>#(2 xx 1.00794color(red)(cancel(color(black)("g/mol"))))/(18.015color(red)(cancel(color(black)("g/mol")))) xx 100 = "11.19% H"#</mathjax></p> </blockquote> <p>This means that your <mathjax>#"0.341-g"#</mathjax> sample of water will contain </p> <blockquote> <p><mathjax>#0.341 color(red)(cancel(color(black)("g H"_2"O"))) * "11.19 g H"/(100color(red)(cancel(color(black)("g H"_2"O")))) = "0.0382 g H"#</mathjax></p> </blockquote> <p>The mass of <strong>nitrogen</strong> originally contained in the nicotine sample will thus be </p> <blockquote> <p><mathjax>#m_"sample" = m_(N) + m_(H) + m_(C)#</mathjax></p> <p><mathjax>#m_(N) = "0.438 g" - "0.324 g" - "0.0382 g"#</mathjax></p> <p><mathjax>#m_(N) = "0.0758 g N"#</mathjax></p> </blockquote> <p>Next, focus on finding the compound's <strong>empirical formula</strong>, which as you know tells you the <strong>smallest whole number ratio</strong> that exists between the <a href="http://socratic.org/chemistry/a-first-introduction-to-matter/elements">elements</a> that make up the compound. </p> <p>To do that, use the <strong>molar masses</strong> of carbon, hydrogen, and nitrogen, respectively, to find how many <em>moles</em> of each you get in the original sample</p> <blockquote> <p><mathjax>#"For C: " (0.324 color(red)(cancel(color(black)("g"))))/(12.0110.324 color(red)(cancel(color(black)("g")))/"mol") = "0.02698 moles C"#</mathjax></p> <p><mathjax>#"For H: " (0.0382 color(red)(cancel(color(black)("g"))))/(1.00794color(red)(cancel(color(black)("g")))/"mol") = "0.03790 moles H"#</mathjax></p> <p><mathjax>#"For N: " (0.0758 color(red)(cancel(color(black)("g"))))/(14.007color(red)(cancel(color(black)("g")))/"mol") = "0.005412 moles N"#</mathjax></p> </blockquote> <p>Divide these values by the <em>smallest one</em> to get </p> <blockquote> <p><mathjax>#"For C: " (0.02698color(red)(cancel(color(black)("moles"))))/(0.005412color(red)(cancel(color(black)("moles")))) = 4.985 ~~ 5#</mathjax></p> <p><mathjax>#"For H: " (0.03790color(red)(cancel(color(black)("moles"))))/(0.005412color(red)(cancel(color(black)("moles")))) = 7.003 ~~ 7#</mathjax></p> <p><mathjax>#"For N: " (0.005412color(red)(cancel(color(black)("moles"))))/(0.005412color(red)(cancel(color(black)("moles")))) = 1#</mathjax></p> </blockquote> <p>The <em>empirical formula</em> of nicotine will thus be </p> <blockquote> <p><mathjax>#"C"_5"H"_7"N"_1#</mathjax></p> </blockquote> <p>Now, the <strong>molecular formula</strong>, which tells you <strong>exactly</strong> how many atoms of each element are needed to form a molecule of your compound, will <strong>always</strong> be a whole number multiple of the empirical formula.</p> <p>This means that if you find the <strong>molar mass</strong> of the empirical formula, you can use the molar mass of the compound to find the molecular formula. </p> <p>The molar mass of the empirical formula will be </p> <blockquote> <p><mathjax>#5 xx "12.011 g/mol" + 7 xx "1.00794 g/mol" + 1 xx "14.007 g/mol" = "81.12 g/mol"#</mathjax></p> </blockquote> <p>This means that you have </p> <blockquote> <p><mathjax>#81.12 color(red)(cancel(color(black)("g/mol"))) xx color(blue)(n) = 162.2 color(red)(cancel(color(black)("g/mol")))#</mathjax></p> </blockquote> <p>Therefore, </p> <blockquote> <p><mathjax>#color(blue)(n) = 162.2/81.12 = 1.9995 ~~ 2#</mathjax></p> </blockquote> <p>The <strong>molecular formula</strong> of nicotine will thus be </p> <blockquote> <p><mathjax>#("C"_5"H"_7"N"_1)_color(blue)(2) implies color(green)("C"_10"H"_14"N"_2)#</mathjax></p> </blockquote> <p><img alt="http://www.dreamstime.com/royalty-free-stock-photography-molecule-nicotine-image14804357" src="https://useruploads.socratic.org/5gSrSObSf68ESCwoWhFh_nicotine-molecule-11084558.jpg"/> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/209610" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? 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How do you find the molecular formula of nicotine (CxHyNz), when 0.438 grams of nicotine burns to make 1.188 g CO2 and 0.341 g H2O? The molecular weight of the nicotine is 162.2g per mole.

aca9241e-6ddd-11ea-bccb-ccda262736ce

https://socratic.org/questions/if-the-specific-heat-of-mercury-is-0-14-j-g-c-how-much-heat-is-required-to-raise

1.8 kJ

start physical_unit 5 5 heat_energy kj qc_end physical_unit 5 5 7 10 specific_heat qc_end physical_unit 5 5 21 22 mass qc_end physical_unit 5 5 26 27 temperature qc_end physical_unit 5 5 29 30 temperature qc_end end

[{"type":"physical unit","value":"Required heat [OF] mercury [IN] kJ"}]

[{"type":"physical unit","value":"1.8 kJ"}]

[{"type":"physical unit","value":"Specific heat [OF] mercury [=] \\pu{0.14 J/(g * ℃)}"},{"type":"physical unit","value":"Mass [OF] mercury [=] \\pu{250.0 g}"},{"type":"physical unit","value":"Temperature1 [OF] mercury [=] \\pu{10 ℃}"},{"type":"physical unit","value":"Temperature2 [OF] mercury [=] \\pu{62 ℃}"}]

<h1 class="questionTitle" itemprop="name">If the specific heat of mercury is 0.14 J/g°C, how much heat is required to raise the temperature of 250.0g of mercury from 10°C to 62°C?</h1>

1.8 kJ

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A substance's <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> tells you how much heat is required to increase the mass of <mathjax>#"1 g"#</mathjax> of that substance by <mathjax>#1^@"C"#</mathjax>. </p> <p>The equation that establishes a rel;ationship between heat absorbed and change in temperature looks like this</p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - heat absorbed<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of the substance<br/> <mathjax>#DeltaT#</mathjax> - the change in temperature, defined as the difference between the <em>final temperature</em> and the <em>initial temperature</em> of the sample</p> <p>You have all the information needed to find the amount of heat required to increase the temperature of your sample of mercury by that many degrees Celsius, so just rearange the above equation and solve for <mathjax>#q#</mathjax></p> <blockquote> <p><mathjax>#q = 250.0color(red)(cancel(color(black)("g"))) * 0.14"J"/(color(red)(cancel(color(black)("g"))) color(red)(cancel(color(black)(""^@"C")))) * (62 - 10)color(red)(cancel(color(black)(""^@"C"))) = "1820 J"#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">two sig figs</a> and expressed in <em>kilojoules</em></p> <blockquote> <p><mathjax>#q = color(green)("1.8 kJ")#</mathjax></p> </blockquote> <p> <iframe src="https://www.youtube.com/embed/vqCZt34Ye3g?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1.8 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A substance's <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> tells you how much heat is required to increase the mass of <mathjax>#"1 g"#</mathjax> of that substance by <mathjax>#1^@"C"#</mathjax>. </p> <p>The equation that establishes a rel;ationship between heat absorbed and change in temperature looks like this</p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - heat absorbed<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of the substance<br/> <mathjax>#DeltaT#</mathjax> - the change in temperature, defined as the difference between the <em>final temperature</em> and the <em>initial temperature</em> of the sample</p> <p>You have all the information needed to find the amount of heat required to increase the temperature of your sample of mercury by that many degrees Celsius, so just rearange the above equation and solve for <mathjax>#q#</mathjax></p> <blockquote> <p><mathjax>#q = 250.0color(red)(cancel(color(black)("g"))) * 0.14"J"/(color(red)(cancel(color(black)("g"))) color(red)(cancel(color(black)(""^@"C")))) * (62 - 10)color(red)(cancel(color(black)(""^@"C"))) = "1820 J"#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">two sig figs</a> and expressed in <em>kilojoules</em></p> <blockquote> <p><mathjax>#q = color(green)("1.8 kJ")#</mathjax></p> </blockquote> <p> <iframe src="https://www.youtube.com/embed/vqCZt34Ye3g?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">If the specific heat of mercury is 0.14 J/g°C, how much heat is required to raise the temperature of 250.0g of mercury from 10°C to 62°C?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#thermochemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Thermochemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/thermochemistry/specific-heat" itemprop="url"> <span class="breadcrumb" itemprop="title">Specific Heat</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="181555" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-10-31T12:15:00" itemprop="dateCreated"> Oct 31, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"1.8 kJ"#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>A substance's <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> tells you how much heat is required to increase the mass of <mathjax>#"1 g"#</mathjax> of that substance by <mathjax>#1^@"C"#</mathjax>. </p> <p>The equation that establishes a rel;ationship between heat absorbed and change in temperature looks like this</p> <blockquote> <p><mathjax>#color(blue)(q = m * c * DeltaT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#q#</mathjax> - heat absorbed<br/> <mathjax>#m#</mathjax> - the mass of the sample<br/> <mathjax>#c#</mathjax> - the <a href="http://socratic.org/chemistry/thermochemistry/specific-heat">specific heat</a> of the substance<br/> <mathjax>#DeltaT#</mathjax> - the change in temperature, defined as the difference between the <em>final temperature</em> and the <em>initial temperature</em> of the sample</p> <p>You have all the information needed to find the amount of heat required to increase the temperature of your sample of mercury by that many degrees Celsius, so just rearange the above equation and solve for <mathjax>#q#</mathjax></p> <blockquote> <p><mathjax>#q = 250.0color(red)(cancel(color(black)("g"))) * 0.14"J"/(color(red)(cancel(color(black)("g"))) color(red)(cancel(color(black)(""^@"C")))) * (62 - 10)color(red)(cancel(color(black)(""^@"C"))) = "1820 J"#</mathjax></p> </blockquote> <p>I'll leave the answer rounded to <a href="http://socratic.org/chemistry/measurement-in-chemistry/significant-figures">two sig figs</a> and expressed in <em>kilojoules</em></p> <blockquote> <p><mathjax>#q = color(green)("1.8 kJ")#</mathjax></p> </blockquote> <p> <iframe src="https://www.youtube.com/embed/vqCZt34Ye3g?origin=https://socratic.org&amp;wmode=transparent" type="text/html"></iframe> </p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/181555" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-specific-heat-be-used-to-identify-substances"> How can specific heat be used to identify substances? 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If the specific heat of mercury is 0.14 J/g°C, how much heat is required to raise the temperature of 250.0g of mercury from 10°C to 62°C?

a8ecfe3b-6ddd-11ea-ad49-ccda262736ce

https://socratic.org/questions/what-is-the-formula-for-vanadium-v-phosphate

V3(PO4)5

start chemical_formula qc_end substance 5 6 qc_end end

[{"type":"other","value":"Chemical Formula [OF] vanadium(V) phosphate [IN] default"}]

[{"type":"chemical equation","value":"V3(PO4)5"}]

[{"type":"substance name","value":"Vanadium(V) phosphate"}]

<h1 class="questionTitle" itemprop="name">What is the formula for vanadium(V) phosphate?</h1>

V3(PO4)5

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Vanadium(V) phosphate is an <strong>ionic compound</strong> made up of vanadium(V) cations and phosphate anions. </p> <p>The <strong>(V)</strong> Roman numeral used to name the cation indicates that vanadium, a <em>transition metal</em>, is in its <mathjax>#+5#</mathjax> oxidation state, i.e. the vanadium cation carries a <mathjax>#5+#</mathjax> charge. </p> <blockquote> <p><mathjax>#"V"^(5+) -&gt;#</mathjax> <em>the <strong>vanadium(V) cation</strong></em></p> </blockquote> <p>The phosphate anion is a <strong>polyatomic ion</strong> that consists of <mathjax>#1#</mathjax> phosphorus atom and <mathjax>#4#</mathjax> oxygen atoms. This polyatomic ion carries a <mathjax>#3-#</mathjax> charge.</p> <blockquote> <p><mathjax>#"PO"_4^(3-) -&gt;#</mathjax> <em>the <strong>phophate anion</strong></em></p> </blockquote> <p>Now, vanadium(V) phosphate is a <em>neutral compound</em>, which means that the overall positive charge coming from the cations must be <strong>balanced</strong> by the overall negative charge coming from the anions. </p> <p>In this case, you will need <mathjax>#3#</mathjax> vanadium(V) cations and <mathjax>#5#</mathjax> phosphate anions to balance out an overall <mathjax>#15+#</mathjax> charge coming from cations and <mathjax>#15-#</mathjax> coming from the anions.</p> <blockquote> <p><mathjax>#color(blue)(3)"V"^color(red)(5+) + color(red)(5)"PO"_ 4^color(blue)(3-) -&gt; "V"_ color(blue)(3)("PO"_ 4)_color(red)(5)#</mathjax></p> </blockquote> <p>Therefore, the ionic formula for vanadium(V) phosphate will be </p> <blockquote> <p><mathjax>#"V"_3("PO"_4)_5 -&gt;#</mathjax> <em><strong>vanadium(V) phosphate</strong></em></p> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"V"_3("PO"_4)_5#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Vanadium(V) phosphate is an <strong>ionic compound</strong> made up of vanadium(V) cations and phosphate anions. </p> <p>The <strong>(V)</strong> Roman numeral used to name the cation indicates that vanadium, a <em>transition metal</em>, is in its <mathjax>#+5#</mathjax> oxidation state, i.e. the vanadium cation carries a <mathjax>#5+#</mathjax> charge. </p> <blockquote> <p><mathjax>#"V"^(5+) -&gt;#</mathjax> <em>the <strong>vanadium(V) cation</strong></em></p> </blockquote> <p>The phosphate anion is a <strong>polyatomic ion</strong> that consists of <mathjax>#1#</mathjax> phosphorus atom and <mathjax>#4#</mathjax> oxygen atoms. This polyatomic ion carries a <mathjax>#3-#</mathjax> charge.</p> <blockquote> <p><mathjax>#"PO"_4^(3-) -&gt;#</mathjax> <em>the <strong>phophate anion</strong></em></p> </blockquote> <p>Now, vanadium(V) phosphate is a <em>neutral compound</em>, which means that the overall positive charge coming from the cations must be <strong>balanced</strong> by the overall negative charge coming from the anions. </p> <p>In this case, you will need <mathjax>#3#</mathjax> vanadium(V) cations and <mathjax>#5#</mathjax> phosphate anions to balance out an overall <mathjax>#15+#</mathjax> charge coming from cations and <mathjax>#15-#</mathjax> coming from the anions.</p> <blockquote> <p><mathjax>#color(blue)(3)"V"^color(red)(5+) + color(red)(5)"PO"_ 4^color(blue)(3-) -&gt; "V"_ color(blue)(3)("PO"_ 4)_color(red)(5)#</mathjax></p> </blockquote> <p>Therefore, the ionic formula for vanadium(V) phosphate will be </p> <blockquote> <p><mathjax>#"V"_3("PO"_4)_5 -&gt;#</mathjax> <em><strong>vanadium(V) phosphate</strong></em></p> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What is the formula for vanadium(V) phosphate?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#ionic-bonds-and-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Ionic Bonds</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Writing Ionic Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="385115" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-03-01T23:04:57" itemprop="dateCreated"> Mar 1, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"V"_3("PO"_4)_5#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>Vanadium(V) phosphate is an <strong>ionic compound</strong> made up of vanadium(V) cations and phosphate anions. </p> <p>The <strong>(V)</strong> Roman numeral used to name the cation indicates that vanadium, a <em>transition metal</em>, is in its <mathjax>#+5#</mathjax> oxidation state, i.e. the vanadium cation carries a <mathjax>#5+#</mathjax> charge. </p> <blockquote> <p><mathjax>#"V"^(5+) -&gt;#</mathjax> <em>the <strong>vanadium(V) cation</strong></em></p> </blockquote> <p>The phosphate anion is a <strong>polyatomic ion</strong> that consists of <mathjax>#1#</mathjax> phosphorus atom and <mathjax>#4#</mathjax> oxygen atoms. This polyatomic ion carries a <mathjax>#3-#</mathjax> charge.</p> <blockquote> <p><mathjax>#"PO"_4^(3-) -&gt;#</mathjax> <em>the <strong>phophate anion</strong></em></p> </blockquote> <p>Now, vanadium(V) phosphate is a <em>neutral compound</em>, which means that the overall positive charge coming from the cations must be <strong>balanced</strong> by the overall negative charge coming from the anions. </p> <p>In this case, you will need <mathjax>#3#</mathjax> vanadium(V) cations and <mathjax>#5#</mathjax> phosphate anions to balance out an overall <mathjax>#15+#</mathjax> charge coming from cations and <mathjax>#15-#</mathjax> coming from the anions.</p> <blockquote> <p><mathjax>#color(blue)(3)"V"^color(red)(5+) + color(red)(5)"PO"_ 4^color(blue)(3-) -&gt; "V"_ color(blue)(3)("PO"_ 4)_color(red)(5)#</mathjax></p> </blockquote> <p>Therefore, the ionic formula for vanadium(V) phosphate will be </p> <blockquote> <p><mathjax>#"V"_3("PO"_4)_5 -&gt;#</mathjax> <em><strong>vanadium(V) phosphate</strong></em></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/385115" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-write-ionic-formulas-for-binary-compounds"> How do you write ionic formulas for binary compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-chloride"> What is the ionic formula for calcium chloride? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-calcium-oxide"> What is the ionic formula for calcium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-ionic-formula-for-lithium-oxide"> What is the ionic formula for lithium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-determine-formula-for-ionic-compounds"> How do you write the formula for ionic compounds? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-i-correctly-write-the-ions-present-in-sn-no3-2"> How do I write #Sn(NO_3)_2# in Ionic formula? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-an-ionic-compound"> What is the empirical formula for an ionic compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-for-chorate"> What is the molecular formula for chorate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5363023c02bf343b2ee7086b"> Question #7086b </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-are-polyatomic-ions-covalent-1"> Why are polyatomic ions covalent? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/ionic-bonds-and-formulas/writing-ionic-formulas"> See all questions in Writing Ionic Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 37104 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

What is the formula for vanadium(V) phosphate?

aa86c4a2-6ddd-11ea-9c91-ccda262736ce

https://socratic.org/questions/when-0-72-g-of-a-liquid-is-vaporized-at-110-c-and-0-967-atm-the-gas-occupies-a-v

C3H6

start chemical_formula qc_end physical_unit 5 5 1 2 mass qc_end physical_unit 5 5 12 13 pressure qc_end physical_unit 5 5 9 10 temperature qc_end physical_unit 14 15 20 21 volume qc_end c_other OTHER qc_end end

[{"type":"other","value":"Chemical Formula [OF] the gas [IN] molecular"}]

[{"type":"chemical equation","value":"C3H6"}]

[{"type":"physical unit","value":"Mass [OF] the liquid [=] \\pu{0.72 g}"},{"type":"physical unit","value":"Pressure [OF] the liquid [=] \\pu{0.967 atm}"},{"type":"physical unit","value":"Temperature [OF] the liquid [=] \\pu{110 ℃}"},{"type":"physical unit","value":"Volume [OF] the gas [=] \\pu{0.559 L}"},{"type":"other","value":"The empirical formula of the gas is CH2."}]

<h1 class="questionTitle" itemprop="name">When 0.72 g of a liquid is vaporized at 110 C and 0.967 atm, the gas occupies a volume of 0.559 L. The empirical formula of the gas is CH2. What is the molecular formula of the gas? Please give easy to follow, step by step instruction and the answer.?</h1>

C3H6

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation to determine how many <strong>moles</strong> of gas you have in that sample. </p> <p>Once you know how many moles of gas were vaporized, you can use the sample's mass to determine the compound's' <strong>molar mass</strong>. </p> <p>So, the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation looks like this</p> <blockquote> <p><mathjax>#color(blue)(PV = nRT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P#</mathjax> - the pressure of the gas<br/> <mathjax>#V#</mathjax> - the volume it occupies<br/> <mathjax>#n#</mathjax> - the number of moles of gas<br/> <mathjax>#R#</mathjax> - the <em>universal gas constant</em>, usually given as <mathjax>#0.082("atm" * "L")/("mol" * "K")#</mathjax><br/> <mathjax>#T#</mathjax> - the temperatue of the gas, expressed in Kelvin</p> <p>Rearrange this equation to solve for <mathjax>#n#</mathjax> and plug in your values - don't forget to convert the temperature to Kelvin!@</p> <blockquote> <p><mathjax>#PV = nRT implies n = (PV)/(RT)#</mathjax></p> <p><mathjax>#n = (0.967color(red)(cancel(color(black)("atm"))) * 0.559color(red)(cancel(color(black)("L"))))/(0.082(color(red)(cancel(color(black)("atm"))) * color(red)(cancel(color(black)("L"))))/("mol" * color(red)(cancel(color(black)("K")))) * (273.15 + 110)color(red)(cancel(color(black)("K")))) = "0.01721 moles"#</mathjax></p> </blockquote> <p>So, your sample contained<mathjax>#0.01721#</mathjax> moles of gas. Assuming that all the moles that were present in the liquid were vaporized, you can say that the initial sample contained <mathjax>#0.01721#</mathjax> moles as well. </p> <p>Now, a compound's <strong>molar mass</strong> tells you what the mass of <strong>one mole</strong> of that compound is. In your case, you know that <mathjax>#0.01721#</mathjax> moles have a mass of <mathjax>#0.72#</mathjax> grams, which means that <em>one mole</em> will have a mass of </p> <blockquote> <p><mathjax>#M_"M" = m/n#</mathjax></p> <p><mathjax>#M_"M" = "0.72 g"/"0.01721 moles" = "41.84 g/mol"#</mathjax></p> </blockquote> <p>You know that the <strong>empirical formula</strong> of the compound is <mathjax>#"CH"_2#</mathjax>. This tells you that the <em>smallest whole number ratio</em> that exists between the number of atoms of carbon and the number of atoms of hydrogen is <mathjax>#1:2#</mathjax>. </p> <p>In order to determine the compound's <strong>molecular formula</strong>, you need to determine exactly how many atoms of each element you get <strong>per molecule</strong>. </p> <p>This is of course equivalent to finding how many moles of carbon and moles of hydrogen you get <em>per mole</em> of compound. </p> <p>The molecular formula is actually a <strong>multiple</strong> of the empirical formula. The molar mass of th e<em>empirical formula</em> will be </p> <blockquote> <p><mathjax>#"12.011 g/mol" + 2 xx "1.00794 g/mol" = "14.029 g/mol"#</mathjax></p> </blockquote> <p>So, how many empirical formulas are needed to make the molecular formula?</p> <blockquote> <p><mathjax>#14.029color(red)(cancel(color(black)("g/mol"))) xx color(blue)(n) = 41.84color(red)(cancel(color(black)("g/mol")))#</mathjax></p> <p><mathjax>#color(blue)(n) = 41.84/14.029 = 2.982 ~~ 3#</mathjax></p> </blockquote> <p>Therefore, the molecular formula of the compound is </p> <blockquote> <p><mathjax>#("CH"_2)_color(blue)(3) implies "C"_3"H"_6#</mathjax></p> </blockquote></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"C"_3"H"_6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation to determine how many <strong>moles</strong> of gas you have in that sample. </p> <p>Once you know how many moles of gas were vaporized, you can use the sample's mass to determine the compound's' <strong>molar mass</strong>. </p> <p>So, the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation looks like this</p> <blockquote> <p><mathjax>#color(blue)(PV = nRT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P#</mathjax> - the pressure of the gas<br/> <mathjax>#V#</mathjax> - the volume it occupies<br/> <mathjax>#n#</mathjax> - the number of moles of gas<br/> <mathjax>#R#</mathjax> - the <em>universal gas constant</em>, usually given as <mathjax>#0.082("atm" * "L")/("mol" * "K")#</mathjax><br/> <mathjax>#T#</mathjax> - the temperatue of the gas, expressed in Kelvin</p> <p>Rearrange this equation to solve for <mathjax>#n#</mathjax> and plug in your values - don't forget to convert the temperature to Kelvin!@</p> <blockquote> <p><mathjax>#PV = nRT implies n = (PV)/(RT)#</mathjax></p> <p><mathjax>#n = (0.967color(red)(cancel(color(black)("atm"))) * 0.559color(red)(cancel(color(black)("L"))))/(0.082(color(red)(cancel(color(black)("atm"))) * color(red)(cancel(color(black)("L"))))/("mol" * color(red)(cancel(color(black)("K")))) * (273.15 + 110)color(red)(cancel(color(black)("K")))) = "0.01721 moles"#</mathjax></p> </blockquote> <p>So, your sample contained<mathjax>#0.01721#</mathjax> moles of gas. Assuming that all the moles that were present in the liquid were vaporized, you can say that the initial sample contained <mathjax>#0.01721#</mathjax> moles as well. </p> <p>Now, a compound's <strong>molar mass</strong> tells you what the mass of <strong>one mole</strong> of that compound is. In your case, you know that <mathjax>#0.01721#</mathjax> moles have a mass of <mathjax>#0.72#</mathjax> grams, which means that <em>one mole</em> will have a mass of </p> <blockquote> <p><mathjax>#M_"M" = m/n#</mathjax></p> <p><mathjax>#M_"M" = "0.72 g"/"0.01721 moles" = "41.84 g/mol"#</mathjax></p> </blockquote> <p>You know that the <strong>empirical formula</strong> of the compound is <mathjax>#"CH"_2#</mathjax>. This tells you that the <em>smallest whole number ratio</em> that exists between the number of atoms of carbon and the number of atoms of hydrogen is <mathjax>#1:2#</mathjax>. </p> <p>In order to determine the compound's <strong>molecular formula</strong>, you need to determine exactly how many atoms of each element you get <strong>per molecule</strong>. </p> <p>This is of course equivalent to finding how many moles of carbon and moles of hydrogen you get <em>per mole</em> of compound. </p> <p>The molecular formula is actually a <strong>multiple</strong> of the empirical formula. The molar mass of th e<em>empirical formula</em> will be </p> <blockquote> <p><mathjax>#"12.011 g/mol" + 2 xx "1.00794 g/mol" = "14.029 g/mol"#</mathjax></p> </blockquote> <p>So, how many empirical formulas are needed to make the molecular formula?</p> <blockquote> <p><mathjax>#14.029color(red)(cancel(color(black)("g/mol"))) xx color(blue)(n) = 41.84color(red)(cancel(color(black)("g/mol")))#</mathjax></p> <p><mathjax>#color(blue)(n) = 41.84/14.029 = 2.982 ~~ 3#</mathjax></p> </blockquote> <p>Therefore, the molecular formula of the compound is </p> <blockquote> <p><mathjax>#("CH"_2)_color(blue)(3) implies "C"_3"H"_6#</mathjax></p> </blockquote></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">When 0.72 g of a liquid is vaporized at 110 C and 0.967 atm, the gas occupies a volume of 0.559 L. The empirical formula of the gas is CH2. What is the molecular formula of the gas? Please give easy to follow, step by step instruction and the answer.?</h1> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#the-mole-concept" itemprop="url"> <span class="breadcrumb" itemprop="title">The Mole Concept</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/the-mole-concept/empirical-and-molecular-formulas" itemprop="url"> <span class="breadcrumb" itemprop="title">Empirical and Molecular Formulas</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="185778" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/stefan-zdre"><img alt="" class="" src="https://profilepictures.socratic.org/LrguokJzR9yQlbiWbCvr_proba_1.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/stefan-zdre"> Stefan V. </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2015-11-08T20:34:04" itemprop="dateCreated"> Nov 8, 2015 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p><mathjax>#"C"_3"H"_6#</mathjax></p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p>The idea here is that you need to use the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation to determine how many <strong>moles</strong> of gas you have in that sample. </p> <p>Once you know how many moles of gas were vaporized, you can use the sample's mass to determine the compound's' <strong>molar mass</strong>. </p> <p>So, the <a href="http://socratic.org/chemistry/the-behavior-of-gases/ideal-gas-law">ideal gas law</a> equation looks like this</p> <blockquote> <p><mathjax>#color(blue)(PV = nRT)" "#</mathjax>, where</p> </blockquote> <p><mathjax>#P#</mathjax> - the pressure of the gas<br/> <mathjax>#V#</mathjax> - the volume it occupies<br/> <mathjax>#n#</mathjax> - the number of moles of gas<br/> <mathjax>#R#</mathjax> - the <em>universal gas constant</em>, usually given as <mathjax>#0.082("atm" * "L")/("mol" * "K")#</mathjax><br/> <mathjax>#T#</mathjax> - the temperatue of the gas, expressed in Kelvin</p> <p>Rearrange this equation to solve for <mathjax>#n#</mathjax> and plug in your values - don't forget to convert the temperature to Kelvin!@</p> <blockquote> <p><mathjax>#PV = nRT implies n = (PV)/(RT)#</mathjax></p> <p><mathjax>#n = (0.967color(red)(cancel(color(black)("atm"))) * 0.559color(red)(cancel(color(black)("L"))))/(0.082(color(red)(cancel(color(black)("atm"))) * color(red)(cancel(color(black)("L"))))/("mol" * color(red)(cancel(color(black)("K")))) * (273.15 + 110)color(red)(cancel(color(black)("K")))) = "0.01721 moles"#</mathjax></p> </blockquote> <p>So, your sample contained<mathjax>#0.01721#</mathjax> moles of gas. Assuming that all the moles that were present in the liquid were vaporized, you can say that the initial sample contained <mathjax>#0.01721#</mathjax> moles as well. </p> <p>Now, a compound's <strong>molar mass</strong> tells you what the mass of <strong>one mole</strong> of that compound is. In your case, you know that <mathjax>#0.01721#</mathjax> moles have a mass of <mathjax>#0.72#</mathjax> grams, which means that <em>one mole</em> will have a mass of </p> <blockquote> <p><mathjax>#M_"M" = m/n#</mathjax></p> <p><mathjax>#M_"M" = "0.72 g"/"0.01721 moles" = "41.84 g/mol"#</mathjax></p> </blockquote> <p>You know that the <strong>empirical formula</strong> of the compound is <mathjax>#"CH"_2#</mathjax>. This tells you that the <em>smallest whole number ratio</em> that exists between the number of atoms of carbon and the number of atoms of hydrogen is <mathjax>#1:2#</mathjax>. </p> <p>In order to determine the compound's <strong>molecular formula</strong>, you need to determine exactly how many atoms of each element you get <strong>per molecule</strong>. </p> <p>This is of course equivalent to finding how many moles of carbon and moles of hydrogen you get <em>per mole</em> of compound. </p> <p>The molecular formula is actually a <strong>multiple</strong> of the empirical formula. The molar mass of th e<em>empirical formula</em> will be </p> <blockquote> <p><mathjax>#"12.011 g/mol" + 2 xx "1.00794 g/mol" = "14.029 g/mol"#</mathjax></p> </blockquote> <p>So, how many empirical formulas are needed to make the molecular formula?</p> <blockquote> <p><mathjax>#14.029color(red)(cancel(color(black)("g/mol"))) xx color(blue)(n) = 41.84color(red)(cancel(color(black)("g/mol")))#</mathjax></p> <p><mathjax>#color(blue)(n) = 41.84/14.029 = 2.982 ~~ 3#</mathjax></p> </blockquote> <p>Therefore, the molecular formula of the compound is </p> <blockquote> <p><mathjax>#("CH"_2)_color(blue)(3) implies "C"_3"H"_6#</mathjax></p> </blockquote></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/185778" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-empirical-formulas-and-molecular-formulas-differ"> How do empirical formulas and molecular formulas differ? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-do-you-find-molecular-formula-of-a-compound"> How do you find molecular formula of a compound? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-diamond"> What is the chemical formula of a diamond? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-chemical-formula-of-a-carbohydrate"> What is the chemical formula of a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-for-valproic-acid"> What is the empirical formula for valproic acid? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-empirical-formula-of-magnesium-oxide"> What is the empirical formula of magnesium oxide? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/why-is-the-empirical-formula-not-double-that-of-the-monosaccharides"> Why is the empirical formula not double that of the monosaccharides? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/5331180502bf342f40b5c3b5"> Question #5c3b5 </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-molecular-formula-represents-a-carbohydrate"> What molecular formula represents a carbohydrate? </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molecular-formula-of-vinegar"> What is the molecular formula of vinegar? </a> </div> </li> </ul> <div class="showMoreRelatedQuestionsContainer"> <a class="showMoreRelatedQuestions" href="/chemistry/the-mole-concept/empirical-and-molecular-formulas"> See all questions in Empirical and Molecular Formulas </a> </div> </div> <div class="bordered"> <div class="impactSection clearfix"> <h5>Impact of this question</h5> <div class="impactStatements"> 15668 views around the world </div> </div> <div class="creativeCommons clearfix"> <img src="/static/images/legal/creative-commons.png"/> <div> You can reuse this answer <br/> <a class="no-color" href="http://creativecommons.org/licenses/by-nc-sa/4.0/"> Creative Commons License </a> </div> </div> </div> </div> </div> </div> </article>

When 0.72 g of a liquid is vaporized at 110 C and 0.967 atm, the gas occupies a volume of 0.559 L. The empirical formula of the gas is CH2. What is the molecular formula of the gas? Please give easy to follow, step by step instruction and the answer.?

ab463db8-6ddd-11ea-8c4e-ccda262736ce

https://socratic.org/questions/58e5d06911ef6b52b5d7887d

88259.01 g

start physical_unit 3 4 mass g qc_end physical_unit 16 16 20 21 concentration qc_end end

[{"type":"physical unit","value":"Mass [OF] sodium chloride [IN] g"}]

[{"type":"physical unit","value":"88259.01 g"}]

[{"type":"physical unit","value":"Volume [OF] NaCl(aq) solution [=] \\pu{350.00 L}"},{"type":"physical unit","value":"Concentration [OF] NaCl(aq) solution [=] \\pu{4.315 mol/L}"}]

<h1 class="questionTitle" itemprop="name">What mass of sodium chloride is required in the following scenario?</h1>

<div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>A <mathjax>#350.00*L#</mathjax> volume of <mathjax>#NaCl(aq)#</mathjax> is required at <mathjax>#4.315*mol*L^-1#</mathjax> concentration. What mass of solute is required?</p></div> </h2> </div> </div>

88259.01 g

<div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute"/"Volume of solution"#</mathjax>.</p> <p>And thus <mathjax>#"moles of solute"="concentration"xx"volume of solution"#</mathjax></p> <p>And the problem gives us 2 of these 3 quantities, we just have to multiply and divide. </p> <p><mathjax>#"moles of solute"=350.00*cancelLxx4.315*mol*cancel(L^-1)=1510.25*mol#</mathjax>.</p> <p>And we then need to multiply this molar quantity by the molar mass of <mathjax>#NaCl#</mathjax> in <mathjax>#g*mol^-1#</mathjax>:</p> <p><mathjax>#1510.25*cancel(mol)xx(35.45+22.99)*g*cancel(mol^-1)=#</mathjax></p> <p><mathjax>#??*g#</mathjax> of salt..........</p></div> </div> </div>

<div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You would need over <mathjax>#88*kg#</mathjax> of salt........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute"/"Volume of solution"#</mathjax>.</p> <p>And thus <mathjax>#"moles of solute"="concentration"xx"volume of solution"#</mathjax></p> <p>And the problem gives us 2 of these 3 quantities, we just have to multiply and divide. </p> <p><mathjax>#"moles of solute"=350.00*cancelLxx4.315*mol*cancel(L^-1)=1510.25*mol#</mathjax>.</p> <p>And we then need to multiply this molar quantity by the molar mass of <mathjax>#NaCl#</mathjax> in <mathjax>#g*mol^-1#</mathjax>:</p> <p><mathjax>#1510.25*cancel(mol)xx(35.45+22.99)*g*cancel(mol^-1)=#</mathjax></p> <p><mathjax>#??*g#</mathjax> of salt..........</p></div> </div> </div> </div>

<article> <h1 class="questionTitle" itemprop="name">What mass of sodium chloride is required in the following scenario?</h1> <div class="questionDetailsContainer"> <div class="collapsedQuestionDetails"> <h2 class="questionDetails" itemprop="text"> <div class="markdown"><p>A <mathjax>#350.00*L#</mathjax> volume of <mathjax>#NaCl(aq)#</mathjax> is required at <mathjax>#4.315*mol*L^-1#</mathjax> concentration. What mass of solute is required?</p></div> </h2> </div> </div> <div class="clearfix"> <div class="breadcrumbs weak-text"> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry" itemprop="url"> <span class="breadcrumb" itemprop="title">Chemistry</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry#solutions-and-their-behavior" itemprop="url"> <span class="breadcrumb" itemprop="title">Solutions</span> </a> </span> <span class="breadcrumb-gray"></span> <span itemscope="" itemtype="http://data-vocabulary.org/Breadcrumb"> <a href="/chemistry/solutions-and-their-behavior/molarity" itemprop="url"> <span class="breadcrumb" itemprop="title">Molarity</span> </a> </span> </div> </div> <div class="clearfix" id="main"> <div class="questionPageLeft floatLeft"> <h5 class="answersHeader hidesWhenAnswerEditing"> <span itemprop="answerCount">1</span> Answer </h5> <div class="answers"> <div class="answer" id="402453" itemprop="suggestedAnswer" itemscope="" itemtype="http://schema.org/Answer"> <div class="hidesWhenAnswerEditing"> <div class="answerTop clearfix"> <div class="contributorPic"> <a class="topContributorPic" href="/users/guy-c"><img alt="" class="" src="https://profilepictures.socratic.org/Uu4JCvRsQK6i1eeFlUfz_amadeo_3.jpg" title=""/></a> </div> <div class="answerInfo"> <div class="answerInfoTop clearfix"><a class="topContributorLink" href="/users/guy-c"> anor277 </a></div> <div class="answerInfoBottom clearfix weak-text"> <span class="dateCreated" datetime="2017-04-06T06:17:32" itemprop="dateCreated"> Apr 6, 2017 </span> </div> </div> </div> <div class="answerContainer clearfix"> <div class="answerText" itemprop="text"> <div class="answerSummary"> <div> <div class="markdown"><p>You would need over <mathjax>#88*kg#</mathjax> of salt........</p></div> </div> </div> <div class="answerDescription"> <h4 class="answerHeader">Explanation:</h4> <div> <div class="markdown"><p><mathjax>#"Concentration"#</mathjax> <mathjax>#=#</mathjax> <mathjax>#"Moles of solute"/"Volume of solution"#</mathjax>.</p> <p>And thus <mathjax>#"moles of solute"="concentration"xx"volume of solution"#</mathjax></p> <p>And the problem gives us 2 of these 3 quantities, we just have to multiply and divide. </p> <p><mathjax>#"moles of solute"=350.00*cancelLxx4.315*mol*cancel(L^-1)=1510.25*mol#</mathjax>.</p> <p>And we then need to multiply this molar quantity by the molar mass of <mathjax>#NaCl#</mathjax> in <mathjax>#g*mol^-1#</mathjax>:</p> <p><mathjax>#1510.25*cancel(mol)xx(35.45+22.99)*g*cancel(mol^-1)=#</mathjax></p> <p><mathjax>#??*g#</mathjax> of salt..........</p></div> </div> </div> </div> </div> </div> <div> <a href="https://socratic.org/answers/402453" itemprop="url">Answer link</a> </div> </div> </div> </div> <div class="questionPageRight floatRight hidesWhenAnswerEditing"> <div class="questionPageRightMain"> <div class="relatedQuestions bordered"> <h5>Related questions</h5> <ul id="relatedQuestions"> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/what-is-the-molarity-of-200-ml-of-a-kcl-solution-that-reacts-completely-with-300"> what is the molarity of 20.0 ml of a KCl solution that reacts completely with 30.0 ml of a 0.400... </a> </div> </li> <li class="relatedQuestionItem"> <div class="questionLink"> <a class="relatedQuestionLink" href="/questions/how-can-molarity-and-osmolarity-be-calculated-from-mv"> How can molarity and osmolarity be calculated from mass per unit volume? 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What mass of sodium chloride is required in the following scenario?

A #350.00*L# volume of #NaCl(aq)# is required at #4.315*mol*L^-1# concentration. What mass of solute is required?