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| sample = """ | |
| [1]: https://baike.baidu.com/item/%E8%B4%A8%E8%83%BD%E6%96%B9%E7%A8%8B/1884527 "质能方程（质能方程式）_百度百科" | |
| [2]: https://www.zhihu.com/question/348249281 "如何理解质能方程 E＝mc²？ - 知乎" | |
| [3]: https://zhuanlan.zhihu.com/p/32597385 "质能方程的推导与理解 - 知乎 - 知乎专栏" | |
| 你好，这是必应。质能方程是描述质量与能量之间的当量关系的方程[^1^][1]。用tex格式，质能方程可以写成$$E=mc^2$$，其中$E$是能量，$m$是质量，$c$是光速[^2^][2] [^3^][3]。 | |
| """ | |
| import re | |
| def preprocess_newbing_out(s): | |
| pattern = r'\^(\d+)\^' # 匹配^数字^ | |
| pattern2 = r'\[(\d+)\]' # 匹配^数字^ | |
| sub = lambda m: '\['+m.group(1)+'\]' # 将匹配到的数字作为替换值 | |
| result = re.sub(pattern, sub, s) # 替换操作 | |
| if '[1]' in result: | |
| result += '<br/><hr style="border-top: dotted 1px #44ac5c;"><br/><small>' + "<br/>".join([re.sub(pattern2, sub, r) for r in result.split('\n') if r.startswith('[')]) + '</small>' | |
| return result | |
| def close_up_code_segment_during_stream(gpt_reply): | |
| """ | |
| 在gpt输出代码的中途（输出了前面的```，但还没输出完后面的```），补上后面的``` | |
| Args: | |
| gpt_reply (str): GPT模型返回的回复字符串。 | |
| Returns: | |
| str: 返回一个新的字符串，将输出代码片段的“后面的```”补上。 | |
| """ | |
| if '```' not in gpt_reply: | |
| return gpt_reply | |
| if gpt_reply.endswith('```'): | |
| return gpt_reply | |
| # 排除了以上两个情况，我们 | |
| segments = gpt_reply.split('```') | |
| n_mark = len(segments) - 1 | |
| if n_mark % 2 == 1: | |
| # print('输出代码片段中！') | |
| return gpt_reply+'\n```' | |
| else: | |
| return gpt_reply | |
| import markdown | |
| from latex2mathml.converter import convert as tex2mathml | |
| from functools import wraps, lru_cache | |
| def markdown_convertion(txt): | |
| """ | |
| 将Markdown格式的文本转换为HTML格式。如果包含数学公式，则先将公式转换为HTML格式。 | |
| """ | |
| pre = '<div class="markdown-body">' | |
| suf = '</div>' | |
| if txt.startswith(pre) and txt.endswith(suf): | |
| # print('警告，输入了已经经过转化的字符串，二次转化可能出问题') | |
| return txt # 已经被转化过，不需要再次转化 | |
| markdown_extension_configs = { | |
| 'mdx_math': { | |
| 'enable_dollar_delimiter': True, | |
| 'use_gitlab_delimiters': False, | |
| }, | |
| } | |
| find_equation_pattern = r'<script type="math/tex(?:.*?)>(.*?)</script>' | |
| def tex2mathml_catch_exception(content, *args, **kwargs): | |
| try: | |
| content = tex2mathml(content, *args, **kwargs) | |
| except: | |
| content = content | |
| return content | |
| def replace_math_no_render(match): | |
| content = match.group(1) | |
| if 'mode=display' in match.group(0): | |
| content = content.replace('\n', '</br>') | |
| return f"<font color=\"#00FF00\">$$</font><font color=\"#FF00FF\">{content}</font><font color=\"#00FF00\">$$</font>" | |
| else: | |
| return f"<font color=\"#00FF00\">$</font><font color=\"#FF00FF\">{content}</font><font color=\"#00FF00\">$</font>" | |
| def replace_math_render(match): | |
| content = match.group(1) | |
| if 'mode=display' in match.group(0): | |
| if '\\begin{aligned}' in content: | |
| content = content.replace('\\begin{aligned}', '\\begin{array}') | |
| content = content.replace('\\end{aligned}', '\\end{array}') | |
| content = content.replace('&', ' ') | |
| content = tex2mathml_catch_exception(content, display="block") | |
| return content | |
| else: | |
| return tex2mathml_catch_exception(content) | |
| def markdown_bug_hunt(content): | |
| """ | |
| 解决一个mdx_math的bug（单$包裹begin命令时多余<script>） | |
| """ | |
| content = content.replace('<script type="math/tex">\n<script type="math/tex; mode=display">', '<script type="math/tex; mode=display">') | |
| content = content.replace('</script>\n</script>', '</script>') | |
| return content | |
| if ('$' in txt) and ('```' not in txt): # 有$标识的公式符号，且没有代码段```的标识 | |
| # convert everything to html format | |
| split = markdown.markdown(text='---') | |
| convert_stage_1 = markdown.markdown(text=txt, extensions=['mdx_math', 'fenced_code', 'tables', 'sane_lists'], extension_configs=markdown_extension_configs) | |
| convert_stage_1 = markdown_bug_hunt(convert_stage_1) | |
| # re.DOTALL: Make the '.' special character match any character at all, including a newline; without this flag, '.' will match anything except a newline. Corresponds to the inline flag (?s). | |
| # 1. convert to easy-to-copy tex (do not render math) | |
| convert_stage_2_1, n = re.subn(find_equation_pattern, replace_math_no_render, convert_stage_1, flags=re.DOTALL) | |
| # 2. convert to rendered equation | |
| convert_stage_2_2, n = re.subn(find_equation_pattern, replace_math_render, convert_stage_1, flags=re.DOTALL) | |
| # cat them together | |
| return pre + convert_stage_2_1 + f'{split}' + convert_stage_2_2 + suf | |
| else: | |
| return pre + markdown.markdown(txt, extensions=['fenced_code', 'codehilite', 'tables', 'sane_lists']) + suf | |
| sample = preprocess_newbing_out(sample) | |
| sample = close_up_code_segment_during_stream(sample) | |
| sample = markdown_convertion(sample) | |
| with open('tmp.html', 'w', encoding='utf8') as f: | |
| f.write(""" | |
| <head> | |
| <title>My Website</title> | |
| <link rel="stylesheet" type="text/css" href="style.css"> | |
| </head> | |
| """) | |
| f.write(sample) | |