premise
stringlengths 923
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| hypothesis
stringlengths 11
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| label
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values |
|---|---|---|
Lester is not ugly.
Baird is not helpless.
Baird is uninterested.
Horace is not helpless.
Lester is not powerful.
Alston is realistic.
Lester is helpless.
Cuthbert is not realistic.
Cuthbert is not ugly.
Horace is not realistic.
Quinn is realistic.
Matthew is helpless.It can be concluded that Baird is powerful and Matthew is not sane once knowing that Lester is not uninterested.
If there is at least one people who is uninterested, then Baird is realistic.
Horace being not realistic or Matthew being not sane implies that Lester is not powerful.
Cuthbert being not helpless is equivalent to Alston being realistic.
It can be concluded that Quinn is ugly once knowing that Matthew is not realistic and Baird is not uninterested.
Alston being not helpless or Alston being not realistic implies that Lester is not ugly.
If someone is not uninterested, then he is not ugly, and vice versa.
If someone is not sane or he is helpless, then he is not uninterested.
Alston being helpless and Quinn being sane imply that Cuthbert is ugly.
Someone who is not uninterested is always both ugly and powerful.
If there is at least one people who is helpless or realistic, then Cuthbert is not ugly.
Someone is helpless and ugly if and only if he is not sane. | Cuthbert is ugly. | self_contradiction |
Lester is not ugly.
Baird is not helpless.
Baird is uninterested.
Horace is not helpless.
Lester is not powerful.
Alston is realistic.
Lester is helpless.
Cuthbert is not realistic.
Cuthbert is not ugly.
Horace is not realistic.
Quinn is realistic.
Matthew is helpless.It can be concluded that Baird is powerful and Matthew is not sane once knowing that Lester is not uninterested.
If there is at least one people who is uninterested, then Baird is realistic.
Horace being not realistic or Matthew being not sane implies that Lester is not powerful.
Cuthbert being not helpless is equivalent to Alston being realistic.
It can be concluded that Quinn is ugly once knowing that Matthew is not realistic and Baird is not uninterested.
Alston being not helpless or Alston being not realistic implies that Lester is not ugly.
If someone is not uninterested, then he is not ugly, and vice versa.
If someone is not sane or he is helpless, then he is not uninterested.
Alston being helpless and Quinn being sane imply that Cuthbert is ugly.
Someone who is not uninterested is always both ugly and powerful.
If there is at least one people who is helpless or realistic, then Cuthbert is not ugly.
Someone is helpless and ugly if and only if he is not sane. | Lester is sane. | contradiction |
Lester is not ugly.
Baird is not helpless.
Baird is uninterested.
Horace is not helpless.
Lester is not powerful.
Alston is realistic.
Lester is helpless.
Cuthbert is not realistic.
Cuthbert is not ugly.
Horace is not realistic.
Quinn is realistic.
Matthew is helpless.It can be concluded that Baird is powerful and Matthew is not sane once knowing that Lester is not uninterested.
If there is at least one people who is uninterested, then Baird is realistic.
Horace being not realistic or Matthew being not sane implies that Lester is not powerful.
Cuthbert being not helpless is equivalent to Alston being realistic.
It can be concluded that Quinn is ugly once knowing that Matthew is not realistic and Baird is not uninterested.
Alston being not helpless or Alston being not realistic implies that Lester is not ugly.
If someone is not uninterested, then he is not ugly, and vice versa.
If someone is not sane or he is helpless, then he is not uninterested.
Alston being helpless and Quinn being sane imply that Cuthbert is ugly.
Someone who is not uninterested is always both ugly and powerful.
If there is at least one people who is helpless or realistic, then Cuthbert is not ugly.
Someone is helpless and ugly if and only if he is not sane. | Lester is not powerful. | self_contradiction |
Lester is not ugly.
Baird is not helpless.
Baird is uninterested.
Horace is not helpless.
Lester is not powerful.
Alston is realistic.
Lester is helpless.
Cuthbert is not realistic.
Cuthbert is not ugly.
Horace is not realistic.
Quinn is realistic.
Matthew is helpless.It can be concluded that Baird is powerful and Matthew is not sane once knowing that Lester is not uninterested.
If there is at least one people who is uninterested, then Baird is realistic.
Horace being not realistic or Matthew being not sane implies that Lester is not powerful.
Cuthbert being not helpless is equivalent to Alston being realistic.
It can be concluded that Quinn is ugly once knowing that Matthew is not realistic and Baird is not uninterested.
Alston being not helpless or Alston being not realistic implies that Lester is not ugly.
If someone is not uninterested, then he is not ugly, and vice versa.
If someone is not sane or he is helpless, then he is not uninterested.
Alston being helpless and Quinn being sane imply that Cuthbert is ugly.
Someone who is not uninterested is always both ugly and powerful.
If there is at least one people who is helpless or realistic, then Cuthbert is not ugly.
Someone is helpless and ugly if and only if he is not sane. | Lester is not uninterested. | entailment |
Lester is not ugly.
Baird is not helpless.
Baird is uninterested.
Horace is not helpless.
Lester is not powerful.
Alston is realistic.
Lester is helpless.
Cuthbert is not realistic.
Cuthbert is not ugly.
Horace is not realistic.
Quinn is realistic.
Matthew is helpless.It can be concluded that Baird is powerful and Matthew is not sane once knowing that Lester is not uninterested.
If there is at least one people who is uninterested, then Baird is realistic.
Horace being not realistic or Matthew being not sane implies that Lester is not powerful.
Cuthbert being not helpless is equivalent to Alston being realistic.
It can be concluded that Quinn is ugly once knowing that Matthew is not realistic and Baird is not uninterested.
Alston being not helpless or Alston being not realistic implies that Lester is not ugly.
If someone is not uninterested, then he is not ugly, and vice versa.
If someone is not sane or he is helpless, then he is not uninterested.
Alston being helpless and Quinn being sane imply that Cuthbert is ugly.
Someone who is not uninterested is always both ugly and powerful.
If there is at least one people who is helpless or realistic, then Cuthbert is not ugly.
Someone is helpless and ugly if and only if he is not sane. | Quinn is realistic. | entailment |
Lester is not ugly.
Baird is not helpless.
Baird is uninterested.
Horace is not helpless.
Lester is not powerful.
Alston is realistic.
Lester is helpless.
Cuthbert is not realistic.
Cuthbert is not ugly.
Horace is not realistic.
Quinn is realistic.
Matthew is helpless.It can be concluded that Baird is powerful and Matthew is not sane once knowing that Lester is not uninterested.
If there is at least one people who is uninterested, then Baird is realistic.
Horace being not realistic or Matthew being not sane implies that Lester is not powerful.
Cuthbert being not helpless is equivalent to Alston being realistic.
It can be concluded that Quinn is ugly once knowing that Matthew is not realistic and Baird is not uninterested.
Alston being not helpless or Alston being not realistic implies that Lester is not ugly.
If someone is not uninterested, then he is not ugly, and vice versa.
If someone is not sane or he is helpless, then he is not uninterested.
Alston being helpless and Quinn being sane imply that Cuthbert is ugly.
Someone who is not uninterested is always both ugly and powerful.
If there is at least one people who is helpless or realistic, then Cuthbert is not ugly.
Someone is helpless and ugly if and only if he is not sane. | Cuthbert is not sane. | neutral |
Lester is not ugly.
Baird is not helpless.
Baird is uninterested.
Horace is not helpless.
Lester is not powerful.
Alston is realistic.
Lester is helpless.
Cuthbert is not realistic.
Cuthbert is not ugly.
Horace is not realistic.
Quinn is realistic.
Matthew is helpless.It can be concluded that Baird is powerful and Matthew is not sane once knowing that Lester is not uninterested.
If there is at least one people who is uninterested, then Baird is realistic.
Horace being not realistic or Matthew being not sane implies that Lester is not powerful.
Cuthbert being not helpless is equivalent to Alston being realistic.
It can be concluded that Quinn is ugly once knowing that Matthew is not realistic and Baird is not uninterested.
Alston being not helpless or Alston being not realistic implies that Lester is not ugly.
If someone is not uninterested, then he is not ugly, and vice versa.
If someone is not sane or he is helpless, then he is not uninterested.
Alston being helpless and Quinn being sane imply that Cuthbert is ugly.
Someone who is not uninterested is always both ugly and powerful.
If there is at least one people who is helpless or realistic, then Cuthbert is not ugly.
Someone is helpless and ugly if and only if he is not sane. | Matthew is helpless. | entailment |
Lester is not ugly.
Baird is not helpless.
Baird is uninterested.
Horace is not helpless.
Lester is not powerful.
Alston is realistic.
Lester is helpless.
Cuthbert is not realistic.
Cuthbert is not ugly.
Horace is not realistic.
Quinn is realistic.
Matthew is helpless.It can be concluded that Baird is powerful and Matthew is not sane once knowing that Lester is not uninterested.
If there is at least one people who is uninterested, then Baird is realistic.
Horace being not realistic or Matthew being not sane implies that Lester is not powerful.
Cuthbert being not helpless is equivalent to Alston being realistic.
It can be concluded that Quinn is ugly once knowing that Matthew is not realistic and Baird is not uninterested.
Alston being not helpless or Alston being not realistic implies that Lester is not ugly.
If someone is not uninterested, then he is not ugly, and vice versa.
If someone is not sane or he is helpless, then he is not uninterested.
Alston being helpless and Quinn being sane imply that Cuthbert is ugly.
Someone who is not uninterested is always both ugly and powerful.
If there is at least one people who is helpless or realistic, then Cuthbert is not ugly.
Someone is helpless and ugly if and only if he is not sane. | Lester is not helpless. | contradiction |
Lester is not ugly.
Baird is not helpless.
Baird is uninterested.
Horace is not helpless.
Lester is not powerful.
Alston is realistic.
Lester is helpless.
Cuthbert is not realistic.
Cuthbert is not ugly.
Horace is not realistic.
Quinn is realistic.
Matthew is helpless.It can be concluded that Baird is powerful and Matthew is not sane once knowing that Lester is not uninterested.
If there is at least one people who is uninterested, then Baird is realistic.
Horace being not realistic or Matthew being not sane implies that Lester is not powerful.
Cuthbert being not helpless is equivalent to Alston being realistic.
It can be concluded that Quinn is ugly once knowing that Matthew is not realistic and Baird is not uninterested.
Alston being not helpless or Alston being not realistic implies that Lester is not ugly.
If someone is not uninterested, then he is not ugly, and vice versa.
If someone is not sane or he is helpless, then he is not uninterested.
Alston being helpless and Quinn being sane imply that Cuthbert is ugly.
Someone who is not uninterested is always both ugly and powerful.
If there is at least one people who is helpless or realistic, then Cuthbert is not ugly.
Someone is helpless and ugly if and only if he is not sane. | Alston is realistic. | entailment |
Lester is not ugly.
Baird is not helpless.
Baird is uninterested.
Horace is not helpless.
Lester is not powerful.
Alston is realistic.
Lester is helpless.
Cuthbert is not realistic.
Cuthbert is not ugly.
Horace is not realistic.
Quinn is realistic.
Matthew is helpless.It can be concluded that Baird is powerful and Matthew is not sane once knowing that Lester is not uninterested.
If there is at least one people who is uninterested, then Baird is realistic.
Horace being not realistic or Matthew being not sane implies that Lester is not powerful.
Cuthbert being not helpless is equivalent to Alston being realistic.
It can be concluded that Quinn is ugly once knowing that Matthew is not realistic and Baird is not uninterested.
Alston being not helpless or Alston being not realistic implies that Lester is not ugly.
If someone is not uninterested, then he is not ugly, and vice versa.
If someone is not sane or he is helpless, then he is not uninterested.
Alston being helpless and Quinn being sane imply that Cuthbert is ugly.
Someone who is not uninterested is always both ugly and powerful.
If there is at least one people who is helpless or realistic, then Cuthbert is not ugly.
Someone is helpless and ugly if and only if he is not sane. | Quinn is not realistic. | contradiction |
Lester is not ugly.
Baird is not helpless.
Baird is uninterested.
Horace is not helpless.
Lester is not powerful.
Alston is realistic.
Lester is helpless.
Cuthbert is not realistic.
Cuthbert is not ugly.
Horace is not realistic.
Quinn is realistic.
Matthew is helpless.It can be concluded that Baird is powerful and Matthew is not sane once knowing that Lester is not uninterested.
If there is at least one people who is uninterested, then Baird is realistic.
Horace being not realistic or Matthew being not sane implies that Lester is not powerful.
Cuthbert being not helpless is equivalent to Alston being realistic.
It can be concluded that Quinn is ugly once knowing that Matthew is not realistic and Baird is not uninterested.
Alston being not helpless or Alston being not realistic implies that Lester is not ugly.
If someone is not uninterested, then he is not ugly, and vice versa.
If someone is not sane or he is helpless, then he is not uninterested.
Alston being helpless and Quinn being sane imply that Cuthbert is ugly.
Someone who is not uninterested is always both ugly and powerful.
If there is at least one people who is helpless or realistic, then Cuthbert is not ugly.
Someone is helpless and ugly if and only if he is not sane. | Lester is powerful. | self_contradiction |
Lester is not ugly.
Baird is not helpless.
Baird is uninterested.
Horace is not helpless.
Lester is not powerful.
Alston is realistic.
Lester is helpless.
Cuthbert is not realistic.
Cuthbert is not ugly.
Horace is not realistic.
Quinn is realistic.
Matthew is helpless.It can be concluded that Baird is powerful and Matthew is not sane once knowing that Lester is not uninterested.
If there is at least one people who is uninterested, then Baird is realistic.
Horace being not realistic or Matthew being not sane implies that Lester is not powerful.
Cuthbert being not helpless is equivalent to Alston being realistic.
It can be concluded that Quinn is ugly once knowing that Matthew is not realistic and Baird is not uninterested.
Alston being not helpless or Alston being not realistic implies that Lester is not ugly.
If someone is not uninterested, then he is not ugly, and vice versa.
If someone is not sane or he is helpless, then he is not uninterested.
Alston being helpless and Quinn being sane imply that Cuthbert is ugly.
Someone who is not uninterested is always both ugly and powerful.
If there is at least one people who is helpless or realistic, then Cuthbert is not ugly.
Someone is helpless and ugly if and only if he is not sane. | Matthew is not ugly. | self_contradiction |
Lester is not ugly.
Baird is not helpless.
Baird is uninterested.
Horace is not helpless.
Lester is not powerful.
Alston is realistic.
Lester is helpless.
Cuthbert is not realistic.
Cuthbert is not ugly.
Horace is not realistic.
Quinn is realistic.
Matthew is helpless.It can be concluded that Baird is powerful and Matthew is not sane once knowing that Lester is not uninterested.
If there is at least one people who is uninterested, then Baird is realistic.
Horace being not realistic or Matthew being not sane implies that Lester is not powerful.
Cuthbert being not helpless is equivalent to Alston being realistic.
It can be concluded that Quinn is ugly once knowing that Matthew is not realistic and Baird is not uninterested.
Alston being not helpless or Alston being not realistic implies that Lester is not ugly.
If someone is not uninterested, then he is not ugly, and vice versa.
If someone is not sane or he is helpless, then he is not uninterested.
Alston being helpless and Quinn being sane imply that Cuthbert is ugly.
Someone who is not uninterested is always both ugly and powerful.
If there is at least one people who is helpless or realistic, then Cuthbert is not ugly.
Someone is helpless and ugly if and only if he is not sane. | Cuthbert is sane. | neutral |
Lester is not ugly.
Baird is not helpless.
Baird is uninterested.
Horace is not helpless.
Lester is not powerful.
Alston is realistic.
Lester is helpless.
Cuthbert is not realistic.
Cuthbert is not ugly.
Horace is not realistic.
Quinn is realistic.
Matthew is helpless.It can be concluded that Baird is powerful and Matthew is not sane once knowing that Lester is not uninterested.
If there is at least one people who is uninterested, then Baird is realistic.
Horace being not realistic or Matthew being not sane implies that Lester is not powerful.
Cuthbert being not helpless is equivalent to Alston being realistic.
It can be concluded that Quinn is ugly once knowing that Matthew is not realistic and Baird is not uninterested.
Alston being not helpless or Alston being not realistic implies that Lester is not ugly.
If someone is not uninterested, then he is not ugly, and vice versa.
If someone is not sane or he is helpless, then he is not uninterested.
Alston being helpless and Quinn being sane imply that Cuthbert is ugly.
Someone who is not uninterested is always both ugly and powerful.
If there is at least one people who is helpless or realistic, then Cuthbert is not ugly.
Someone is helpless and ugly if and only if he is not sane. | Horace is powerful. | neutral |
Lester is not ugly.
Baird is not helpless.
Baird is uninterested.
Horace is not helpless.
Lester is not powerful.
Alston is realistic.
Lester is helpless.
Cuthbert is not realistic.
Cuthbert is not ugly.
Horace is not realistic.
Quinn is realistic.
Matthew is helpless.It can be concluded that Baird is powerful and Matthew is not sane once knowing that Lester is not uninterested.
If there is at least one people who is uninterested, then Baird is realistic.
Horace being not realistic or Matthew being not sane implies that Lester is not powerful.
Cuthbert being not helpless is equivalent to Alston being realistic.
It can be concluded that Quinn is ugly once knowing that Matthew is not realistic and Baird is not uninterested.
Alston being not helpless or Alston being not realistic implies that Lester is not ugly.
If someone is not uninterested, then he is not ugly, and vice versa.
If someone is not sane or he is helpless, then he is not uninterested.
Alston being helpless and Quinn being sane imply that Cuthbert is ugly.
Someone who is not uninterested is always both ugly and powerful.
If there is at least one people who is helpless or realistic, then Cuthbert is not ugly.
Someone is helpless and ugly if and only if he is not sane. | Cuthbert is helpless. | contradiction |
Lester is not ugly.
Baird is not helpless.
Baird is uninterested.
Horace is not helpless.
Lester is not powerful.
Alston is realistic.
Lester is helpless.
Cuthbert is not realistic.
Cuthbert is not ugly.
Horace is not realistic.
Quinn is realistic.
Matthew is helpless.It can be concluded that Baird is powerful and Matthew is not sane once knowing that Lester is not uninterested.
If there is at least one people who is uninterested, then Baird is realistic.
Horace being not realistic or Matthew being not sane implies that Lester is not powerful.
Cuthbert being not helpless is equivalent to Alston being realistic.
It can be concluded that Quinn is ugly once knowing that Matthew is not realistic and Baird is not uninterested.
Alston being not helpless or Alston being not realistic implies that Lester is not ugly.
If someone is not uninterested, then he is not ugly, and vice versa.
If someone is not sane or he is helpless, then he is not uninterested.
Alston being helpless and Quinn being sane imply that Cuthbert is ugly.
Someone who is not uninterested is always both ugly and powerful.
If there is at least one people who is helpless or realistic, then Cuthbert is not ugly.
Someone is helpless and ugly if and only if he is not sane. | Matthew is realistic. | neutral |
Lester is not ugly.
Baird is not helpless.
Baird is uninterested.
Horace is not helpless.
Lester is not powerful.
Alston is realistic.
Lester is helpless.
Cuthbert is not realistic.
Cuthbert is not ugly.
Horace is not realistic.
Quinn is realistic.
Matthew is helpless.It can be concluded that Baird is powerful and Matthew is not sane once knowing that Lester is not uninterested.
If there is at least one people who is uninterested, then Baird is realistic.
Horace being not realistic or Matthew being not sane implies that Lester is not powerful.
Cuthbert being not helpless is equivalent to Alston being realistic.
It can be concluded that Quinn is ugly once knowing that Matthew is not realistic and Baird is not uninterested.
Alston being not helpless or Alston being not realistic implies that Lester is not ugly.
If someone is not uninterested, then he is not ugly, and vice versa.
If someone is not sane or he is helpless, then he is not uninterested.
Alston being helpless and Quinn being sane imply that Cuthbert is ugly.
Someone who is not uninterested is always both ugly and powerful.
If there is at least one people who is helpless or realistic, then Cuthbert is not ugly.
Someone is helpless and ugly if and only if he is not sane. | Matthew is uninterested. | contradiction |
Lester is not ugly.
Baird is not helpless.
Baird is uninterested.
Horace is not helpless.
Lester is not powerful.
Alston is realistic.
Lester is helpless.
Cuthbert is not realistic.
Cuthbert is not ugly.
Horace is not realistic.
Quinn is realistic.
Matthew is helpless.It can be concluded that Baird is powerful and Matthew is not sane once knowing that Lester is not uninterested.
If there is at least one people who is uninterested, then Baird is realistic.
Horace being not realistic or Matthew being not sane implies that Lester is not powerful.
Cuthbert being not helpless is equivalent to Alston being realistic.
It can be concluded that Quinn is ugly once knowing that Matthew is not realistic and Baird is not uninterested.
Alston being not helpless or Alston being not realistic implies that Lester is not ugly.
If someone is not uninterested, then he is not ugly, and vice versa.
If someone is not sane or he is helpless, then he is not uninterested.
Alston being helpless and Quinn being sane imply that Cuthbert is ugly.
Someone who is not uninterested is always both ugly and powerful.
If there is at least one people who is helpless or realistic, then Cuthbert is not ugly.
Someone is helpless and ugly if and only if he is not sane. | Lester is not ugly. | self_contradiction |
Lester is not ugly.
Baird is not helpless.
Baird is uninterested.
Horace is not helpless.
Lester is not powerful.
Alston is realistic.
Lester is helpless.
Cuthbert is not realistic.
Cuthbert is not ugly.
Horace is not realistic.
Quinn is realistic.
Matthew is helpless.It can be concluded that Baird is powerful and Matthew is not sane once knowing that Lester is not uninterested.
If there is at least one people who is uninterested, then Baird is realistic.
Horace being not realistic or Matthew being not sane implies that Lester is not powerful.
Cuthbert being not helpless is equivalent to Alston being realistic.
It can be concluded that Quinn is ugly once knowing that Matthew is not realistic and Baird is not uninterested.
Alston being not helpless or Alston being not realistic implies that Lester is not ugly.
If someone is not uninterested, then he is not ugly, and vice versa.
If someone is not sane or he is helpless, then he is not uninterested.
Alston being helpless and Quinn being sane imply that Cuthbert is ugly.
Someone who is not uninterested is always both ugly and powerful.
If there is at least one people who is helpless or realistic, then Cuthbert is not ugly.
Someone is helpless and ugly if and only if he is not sane. | Quinn is not sane. | neutral |
Lester is not ugly.
Baird is not helpless.
Baird is uninterested.
Horace is not helpless.
Lester is not powerful.
Alston is realistic.
Lester is helpless.
Cuthbert is not realistic.
Cuthbert is not ugly.
Horace is not realistic.
Quinn is realistic.
Matthew is helpless.It can be concluded that Baird is powerful and Matthew is not sane once knowing that Lester is not uninterested.
If there is at least one people who is uninterested, then Baird is realistic.
Horace being not realistic or Matthew being not sane implies that Lester is not powerful.
Cuthbert being not helpless is equivalent to Alston being realistic.
It can be concluded that Quinn is ugly once knowing that Matthew is not realistic and Baird is not uninterested.
Alston being not helpless or Alston being not realistic implies that Lester is not ugly.
If someone is not uninterested, then he is not ugly, and vice versa.
If someone is not sane or he is helpless, then he is not uninterested.
Alston being helpless and Quinn being sane imply that Cuthbert is ugly.
Someone who is not uninterested is always both ugly and powerful.
If there is at least one people who is helpless or realistic, then Cuthbert is not ugly.
Someone is helpless and ugly if and only if he is not sane. | Horace is not realistic. | entailment |
Ryan is skinny.
Connell is not mental.
Channing is not uninterested.
Luna is mental.
Brian is crazy.
Luna is uninterested.
Ryan is not curious.
Brian is not curious.
Melville is not uninterested.
Melville is mental.
Hardy is not uninterested.
Connell is skinny.Someone being mental is equivalent to being skinny.
If someone is mental or he is crazy, then he is not sufficient.
As long as someone is uninterested, he is not skinny and not sufficient.
If Connell is not uninterested and Melville is not mental, then Connell is not skinny.
As long as someone is crazy and uninterested, he is not sufficient and curious.
Melville being not sufficient implies that Brian is not mental.
If Connell is skinny, then Ryan is uninterested, and vice versa.
It can be concluded that Channing is not uninterested once knowing that Melville is not crazy or Brian is not mental.
If someone is curious, then he is both not mental and not crazy.
If someone is both skinny and not crazy, then he is sufficient.
Connell being not mental implies that Brian is not curious.
If Melville is uninterested or Luna is crazy, then Brian is not curious. | Brian is not mental. | entailment |
Ryan is skinny.
Connell is not mental.
Channing is not uninterested.
Luna is mental.
Brian is crazy.
Luna is uninterested.
Ryan is not curious.
Brian is not curious.
Melville is not uninterested.
Melville is mental.
Hardy is not uninterested.
Connell is skinny.Someone being mental is equivalent to being skinny.
If someone is mental or he is crazy, then he is not sufficient.
As long as someone is uninterested, he is not skinny and not sufficient.
If Connell is not uninterested and Melville is not mental, then Connell is not skinny.
As long as someone is crazy and uninterested, he is not sufficient and curious.
Melville being not sufficient implies that Brian is not mental.
If Connell is skinny, then Ryan is uninterested, and vice versa.
It can be concluded that Channing is not uninterested once knowing that Melville is not crazy or Brian is not mental.
If someone is curious, then he is both not mental and not crazy.
If someone is both skinny and not crazy, then he is sufficient.
Connell being not mental implies that Brian is not curious.
If Melville is uninterested or Luna is crazy, then Brian is not curious. | Channing is not uninterested. | entailment |
Ryan is skinny.
Connell is not mental.
Channing is not uninterested.
Luna is mental.
Brian is crazy.
Luna is uninterested.
Ryan is not curious.
Brian is not curious.
Melville is not uninterested.
Melville is mental.
Hardy is not uninterested.
Connell is skinny.Someone being mental is equivalent to being skinny.
If someone is mental or he is crazy, then he is not sufficient.
As long as someone is uninterested, he is not skinny and not sufficient.
If Connell is not uninterested and Melville is not mental, then Connell is not skinny.
As long as someone is crazy and uninterested, he is not sufficient and curious.
Melville being not sufficient implies that Brian is not mental.
If Connell is skinny, then Ryan is uninterested, and vice versa.
It can be concluded that Channing is not uninterested once knowing that Melville is not crazy or Brian is not mental.
If someone is curious, then he is both not mental and not crazy.
If someone is both skinny and not crazy, then he is sufficient.
Connell being not mental implies that Brian is not curious.
If Melville is uninterested or Luna is crazy, then Brian is not curious. | Melville is crazy. | neutral |
Ryan is skinny.
Connell is not mental.
Channing is not uninterested.
Luna is mental.
Brian is crazy.
Luna is uninterested.
Ryan is not curious.
Brian is not curious.
Melville is not uninterested.
Melville is mental.
Hardy is not uninterested.
Connell is skinny.Someone being mental is equivalent to being skinny.
If someone is mental or he is crazy, then he is not sufficient.
As long as someone is uninterested, he is not skinny and not sufficient.
If Connell is not uninterested and Melville is not mental, then Connell is not skinny.
As long as someone is crazy and uninterested, he is not sufficient and curious.
Melville being not sufficient implies that Brian is not mental.
If Connell is skinny, then Ryan is uninterested, and vice versa.
It can be concluded that Channing is not uninterested once knowing that Melville is not crazy or Brian is not mental.
If someone is curious, then he is both not mental and not crazy.
If someone is both skinny and not crazy, then he is sufficient.
Connell being not mental implies that Brian is not curious.
If Melville is uninterested or Luna is crazy, then Brian is not curious. | Connell is not mental. | self_contradiction |
Ryan is skinny.
Connell is not mental.
Channing is not uninterested.
Luna is mental.
Brian is crazy.
Luna is uninterested.
Ryan is not curious.
Brian is not curious.
Melville is not uninterested.
Melville is mental.
Hardy is not uninterested.
Connell is skinny.Someone being mental is equivalent to being skinny.
If someone is mental or he is crazy, then he is not sufficient.
As long as someone is uninterested, he is not skinny and not sufficient.
If Connell is not uninterested and Melville is not mental, then Connell is not skinny.
As long as someone is crazy and uninterested, he is not sufficient and curious.
Melville being not sufficient implies that Brian is not mental.
If Connell is skinny, then Ryan is uninterested, and vice versa.
It can be concluded that Channing is not uninterested once knowing that Melville is not crazy or Brian is not mental.
If someone is curious, then he is both not mental and not crazy.
If someone is both skinny and not crazy, then he is sufficient.
Connell being not mental implies that Brian is not curious.
If Melville is uninterested or Luna is crazy, then Brian is not curious. | Hardy is not uninterested. | entailment |
Ryan is skinny.
Connell is not mental.
Channing is not uninterested.
Luna is mental.
Brian is crazy.
Luna is uninterested.
Ryan is not curious.
Brian is not curious.
Melville is not uninterested.
Melville is mental.
Hardy is not uninterested.
Connell is skinny.Someone being mental is equivalent to being skinny.
If someone is mental or he is crazy, then he is not sufficient.
As long as someone is uninterested, he is not skinny and not sufficient.
If Connell is not uninterested and Melville is not mental, then Connell is not skinny.
As long as someone is crazy and uninterested, he is not sufficient and curious.
Melville being not sufficient implies that Brian is not mental.
If Connell is skinny, then Ryan is uninterested, and vice versa.
It can be concluded that Channing is not uninterested once knowing that Melville is not crazy or Brian is not mental.
If someone is curious, then he is both not mental and not crazy.
If someone is both skinny and not crazy, then he is sufficient.
Connell being not mental implies that Brian is not curious.
If Melville is uninterested or Luna is crazy, then Brian is not curious. | Channing is not sufficient. | neutral |
Ryan is skinny.
Connell is not mental.
Channing is not uninterested.
Luna is mental.
Brian is crazy.
Luna is uninterested.
Ryan is not curious.
Brian is not curious.
Melville is not uninterested.
Melville is mental.
Hardy is not uninterested.
Connell is skinny.Someone being mental is equivalent to being skinny.
If someone is mental or he is crazy, then he is not sufficient.
As long as someone is uninterested, he is not skinny and not sufficient.
If Connell is not uninterested and Melville is not mental, then Connell is not skinny.
As long as someone is crazy and uninterested, he is not sufficient and curious.
Melville being not sufficient implies that Brian is not mental.
If Connell is skinny, then Ryan is uninterested, and vice versa.
It can be concluded that Channing is not uninterested once knowing that Melville is not crazy or Brian is not mental.
If someone is curious, then he is both not mental and not crazy.
If someone is both skinny and not crazy, then he is sufficient.
Connell being not mental implies that Brian is not curious.
If Melville is uninterested or Luna is crazy, then Brian is not curious. | Luna is sufficient. | contradiction |
Ryan is skinny.
Connell is not mental.
Channing is not uninterested.
Luna is mental.
Brian is crazy.
Luna is uninterested.
Ryan is not curious.
Brian is not curious.
Melville is not uninterested.
Melville is mental.
Hardy is not uninterested.
Connell is skinny.Someone being mental is equivalent to being skinny.
If someone is mental or he is crazy, then he is not sufficient.
As long as someone is uninterested, he is not skinny and not sufficient.
If Connell is not uninterested and Melville is not mental, then Connell is not skinny.
As long as someone is crazy and uninterested, he is not sufficient and curious.
Melville being not sufficient implies that Brian is not mental.
If Connell is skinny, then Ryan is uninterested, and vice versa.
It can be concluded that Channing is not uninterested once knowing that Melville is not crazy or Brian is not mental.
If someone is curious, then he is both not mental and not crazy.
If someone is both skinny and not crazy, then he is sufficient.
Connell being not mental implies that Brian is not curious.
If Melville is uninterested or Luna is crazy, then Brian is not curious. | Connell is mental. | self_contradiction |
Ryan is skinny.
Connell is not mental.
Channing is not uninterested.
Luna is mental.
Brian is crazy.
Luna is uninterested.
Ryan is not curious.
Brian is not curious.
Melville is not uninterested.
Melville is mental.
Hardy is not uninterested.
Connell is skinny.Someone being mental is equivalent to being skinny.
If someone is mental or he is crazy, then he is not sufficient.
As long as someone is uninterested, he is not skinny and not sufficient.
If Connell is not uninterested and Melville is not mental, then Connell is not skinny.
As long as someone is crazy and uninterested, he is not sufficient and curious.
Melville being not sufficient implies that Brian is not mental.
If Connell is skinny, then Ryan is uninterested, and vice versa.
It can be concluded that Channing is not uninterested once knowing that Melville is not crazy or Brian is not mental.
If someone is curious, then he is both not mental and not crazy.
If someone is both skinny and not crazy, then he is sufficient.
Connell being not mental implies that Brian is not curious.
If Melville is uninterested or Luna is crazy, then Brian is not curious. | Brian is sufficient. | contradiction |
Ryan is skinny.
Connell is not mental.
Channing is not uninterested.
Luna is mental.
Brian is crazy.
Luna is uninterested.
Ryan is not curious.
Brian is not curious.
Melville is not uninterested.
Melville is mental.
Hardy is not uninterested.
Connell is skinny.Someone being mental is equivalent to being skinny.
If someone is mental or he is crazy, then he is not sufficient.
As long as someone is uninterested, he is not skinny and not sufficient.
If Connell is not uninterested and Melville is not mental, then Connell is not skinny.
As long as someone is crazy and uninterested, he is not sufficient and curious.
Melville being not sufficient implies that Brian is not mental.
If Connell is skinny, then Ryan is uninterested, and vice versa.
It can be concluded that Channing is not uninterested once knowing that Melville is not crazy or Brian is not mental.
If someone is curious, then he is both not mental and not crazy.
If someone is both skinny and not crazy, then he is sufficient.
Connell being not mental implies that Brian is not curious.
If Melville is uninterested or Luna is crazy, then Brian is not curious. | Ryan is uninterested. | entailment |
Ryan is skinny.
Connell is not mental.
Channing is not uninterested.
Luna is mental.
Brian is crazy.
Luna is uninterested.
Ryan is not curious.
Brian is not curious.
Melville is not uninterested.
Melville is mental.
Hardy is not uninterested.
Connell is skinny.Someone being mental is equivalent to being skinny.
If someone is mental or he is crazy, then he is not sufficient.
As long as someone is uninterested, he is not skinny and not sufficient.
If Connell is not uninterested and Melville is not mental, then Connell is not skinny.
As long as someone is crazy and uninterested, he is not sufficient and curious.
Melville being not sufficient implies that Brian is not mental.
If Connell is skinny, then Ryan is uninterested, and vice versa.
It can be concluded that Channing is not uninterested once knowing that Melville is not crazy or Brian is not mental.
If someone is curious, then he is both not mental and not crazy.
If someone is both skinny and not crazy, then he is sufficient.
Connell being not mental implies that Brian is not curious.
If Melville is uninterested or Luna is crazy, then Brian is not curious. | Brian is not skinny. | neutral |
Ryan is skinny.
Connell is not mental.
Channing is not uninterested.
Luna is mental.
Brian is crazy.
Luna is uninterested.
Ryan is not curious.
Brian is not curious.
Melville is not uninterested.
Melville is mental.
Hardy is not uninterested.
Connell is skinny.Someone being mental is equivalent to being skinny.
If someone is mental or he is crazy, then he is not sufficient.
As long as someone is uninterested, he is not skinny and not sufficient.
If Connell is not uninterested and Melville is not mental, then Connell is not skinny.
As long as someone is crazy and uninterested, he is not sufficient and curious.
Melville being not sufficient implies that Brian is not mental.
If Connell is skinny, then Ryan is uninterested, and vice versa.
It can be concluded that Channing is not uninterested once knowing that Melville is not crazy or Brian is not mental.
If someone is curious, then he is both not mental and not crazy.
If someone is both skinny and not crazy, then he is sufficient.
Connell being not mental implies that Brian is not curious.
If Melville is uninterested or Luna is crazy, then Brian is not curious. | Melville is not crazy. | neutral |
Ryan is skinny.
Connell is not mental.
Channing is not uninterested.
Luna is mental.
Brian is crazy.
Luna is uninterested.
Ryan is not curious.
Brian is not curious.
Melville is not uninterested.
Melville is mental.
Hardy is not uninterested.
Connell is skinny.Someone being mental is equivalent to being skinny.
If someone is mental or he is crazy, then he is not sufficient.
As long as someone is uninterested, he is not skinny and not sufficient.
If Connell is not uninterested and Melville is not mental, then Connell is not skinny.
As long as someone is crazy and uninterested, he is not sufficient and curious.
Melville being not sufficient implies that Brian is not mental.
If Connell is skinny, then Ryan is uninterested, and vice versa.
It can be concluded that Channing is not uninterested once knowing that Melville is not crazy or Brian is not mental.
If someone is curious, then he is both not mental and not crazy.
If someone is both skinny and not crazy, then he is sufficient.
Connell being not mental implies that Brian is not curious.
If Melville is uninterested or Luna is crazy, then Brian is not curious. | Ryan is not skinny. | self_contradiction |
Ryan is skinny.
Connell is not mental.
Channing is not uninterested.
Luna is mental.
Brian is crazy.
Luna is uninterested.
Ryan is not curious.
Brian is not curious.
Melville is not uninterested.
Melville is mental.
Hardy is not uninterested.
Connell is skinny.Someone being mental is equivalent to being skinny.
If someone is mental or he is crazy, then he is not sufficient.
As long as someone is uninterested, he is not skinny and not sufficient.
If Connell is not uninterested and Melville is not mental, then Connell is not skinny.
As long as someone is crazy and uninterested, he is not sufficient and curious.
Melville being not sufficient implies that Brian is not mental.
If Connell is skinny, then Ryan is uninterested, and vice versa.
It can be concluded that Channing is not uninterested once knowing that Melville is not crazy or Brian is not mental.
If someone is curious, then he is both not mental and not crazy.
If someone is both skinny and not crazy, then he is sufficient.
Connell being not mental implies that Brian is not curious.
If Melville is uninterested or Luna is crazy, then Brian is not curious. | Hardy is crazy. | neutral |
Ryan is skinny.
Connell is not mental.
Channing is not uninterested.
Luna is mental.
Brian is crazy.
Luna is uninterested.
Ryan is not curious.
Brian is not curious.
Melville is not uninterested.
Melville is mental.
Hardy is not uninterested.
Connell is skinny.Someone being mental is equivalent to being skinny.
If someone is mental or he is crazy, then he is not sufficient.
As long as someone is uninterested, he is not skinny and not sufficient.
If Connell is not uninterested and Melville is not mental, then Connell is not skinny.
As long as someone is crazy and uninterested, he is not sufficient and curious.
Melville being not sufficient implies that Brian is not mental.
If Connell is skinny, then Ryan is uninterested, and vice versa.
It can be concluded that Channing is not uninterested once knowing that Melville is not crazy or Brian is not mental.
If someone is curious, then he is both not mental and not crazy.
If someone is both skinny and not crazy, then he is sufficient.
Connell being not mental implies that Brian is not curious.
If Melville is uninterested or Luna is crazy, then Brian is not curious. | Ryan is not uninterested. | contradiction |
Ryan is skinny.
Connell is not mental.
Channing is not uninterested.
Luna is mental.
Brian is crazy.
Luna is uninterested.
Ryan is not curious.
Brian is not curious.
Melville is not uninterested.
Melville is mental.
Hardy is not uninterested.
Connell is skinny.Someone being mental is equivalent to being skinny.
If someone is mental or he is crazy, then he is not sufficient.
As long as someone is uninterested, he is not skinny and not sufficient.
If Connell is not uninterested and Melville is not mental, then Connell is not skinny.
As long as someone is crazy and uninterested, he is not sufficient and curious.
Melville being not sufficient implies that Brian is not mental.
If Connell is skinny, then Ryan is uninterested, and vice versa.
It can be concluded that Channing is not uninterested once knowing that Melville is not crazy or Brian is not mental.
If someone is curious, then he is both not mental and not crazy.
If someone is both skinny and not crazy, then he is sufficient.
Connell being not mental implies that Brian is not curious.
If Melville is uninterested or Luna is crazy, then Brian is not curious. | Luna is skinny. | self_contradiction |
Ryan is skinny.
Connell is not mental.
Channing is not uninterested.
Luna is mental.
Brian is crazy.
Luna is uninterested.
Ryan is not curious.
Brian is not curious.
Melville is not uninterested.
Melville is mental.
Hardy is not uninterested.
Connell is skinny.Someone being mental is equivalent to being skinny.
If someone is mental or he is crazy, then he is not sufficient.
As long as someone is uninterested, he is not skinny and not sufficient.
If Connell is not uninterested and Melville is not mental, then Connell is not skinny.
As long as someone is crazy and uninterested, he is not sufficient and curious.
Melville being not sufficient implies that Brian is not mental.
If Connell is skinny, then Ryan is uninterested, and vice versa.
It can be concluded that Channing is not uninterested once knowing that Melville is not crazy or Brian is not mental.
If someone is curious, then he is both not mental and not crazy.
If someone is both skinny and not crazy, then he is sufficient.
Connell being not mental implies that Brian is not curious.
If Melville is uninterested or Luna is crazy, then Brian is not curious. | Ryan is skinny. | self_contradiction |
Ryan is skinny.
Connell is not mental.
Channing is not uninterested.
Luna is mental.
Brian is crazy.
Luna is uninterested.
Ryan is not curious.
Brian is not curious.
Melville is not uninterested.
Melville is mental.
Hardy is not uninterested.
Connell is skinny.Someone being mental is equivalent to being skinny.
If someone is mental or he is crazy, then he is not sufficient.
As long as someone is uninterested, he is not skinny and not sufficient.
If Connell is not uninterested and Melville is not mental, then Connell is not skinny.
As long as someone is crazy and uninterested, he is not sufficient and curious.
Melville being not sufficient implies that Brian is not mental.
If Connell is skinny, then Ryan is uninterested, and vice versa.
It can be concluded that Channing is not uninterested once knowing that Melville is not crazy or Brian is not mental.
If someone is curious, then he is both not mental and not crazy.
If someone is both skinny and not crazy, then he is sufficient.
Connell being not mental implies that Brian is not curious.
If Melville is uninterested or Luna is crazy, then Brian is not curious. | Melville is not skinny. | contradiction |
Ryan is skinny.
Connell is not mental.
Channing is not uninterested.
Luna is mental.
Brian is crazy.
Luna is uninterested.
Ryan is not curious.
Brian is not curious.
Melville is not uninterested.
Melville is mental.
Hardy is not uninterested.
Connell is skinny.Someone being mental is equivalent to being skinny.
If someone is mental or he is crazy, then he is not sufficient.
As long as someone is uninterested, he is not skinny and not sufficient.
If Connell is not uninterested and Melville is not mental, then Connell is not skinny.
As long as someone is crazy and uninterested, he is not sufficient and curious.
Melville being not sufficient implies that Brian is not mental.
If Connell is skinny, then Ryan is uninterested, and vice versa.
It can be concluded that Channing is not uninterested once knowing that Melville is not crazy or Brian is not mental.
If someone is curious, then he is both not mental and not crazy.
If someone is both skinny and not crazy, then he is sufficient.
Connell being not mental implies that Brian is not curious.
If Melville is uninterested or Luna is crazy, then Brian is not curious. | Melville is sufficient. | contradiction |
Ryan is skinny.
Connell is not mental.
Channing is not uninterested.
Luna is mental.
Brian is crazy.
Luna is uninterested.
Ryan is not curious.
Brian is not curious.
Melville is not uninterested.
Melville is mental.
Hardy is not uninterested.
Connell is skinny.Someone being mental is equivalent to being skinny.
If someone is mental or he is crazy, then he is not sufficient.
As long as someone is uninterested, he is not skinny and not sufficient.
If Connell is not uninterested and Melville is not mental, then Connell is not skinny.
As long as someone is crazy and uninterested, he is not sufficient and curious.
Melville being not sufficient implies that Brian is not mental.
If Connell is skinny, then Ryan is uninterested, and vice versa.
It can be concluded that Channing is not uninterested once knowing that Melville is not crazy or Brian is not mental.
If someone is curious, then he is both not mental and not crazy.
If someone is both skinny and not crazy, then he is sufficient.
Connell being not mental implies that Brian is not curious.
If Melville is uninterested or Luna is crazy, then Brian is not curious. | Melville is skinny. | entailment |
Chester is not pink.
Carroll is not shy.
Chester is shy.
Chester is boring.
Chester is splendid.
Kyle is not pink.
Deborah is not shy.
Quinn is splendid.
Sandy is successful.
Carroll is not splendid.
Kyle is not intellectual.
Kyle is boring.Chester is not shy if and only if Sandy is successful.
Deborah is not shy if and only if Quinn is not pink.
Uriah being not pink is equivalent to Deborah being not shy and Sandy being intellectual.
If there is at least one people who is pink, then Chester is successful.
Someone being not successful is equivalent to being not pink.
If someone is both shy and splendid, then he is boring.
It can be concluded that Sandy is intellectual once knowing that Uriah is not successful or Sandy is boring.
Someone being both boring and pink is equivalent to being not shy and splendid.
It can be concluded that Sandy is shy and Uriah is not boring once knowing that Kyle is pink and Deborah is not splendid.
If there is at least one people who is not successful, then Quinn is pink.
Someone is not successful and not intellectual if and only if he is boring and shy.
Sandy being not successful and Quinn being not boring imply that Sandy is not splendid. | Quinn is not successful. | entailment |
Chester is not pink.
Carroll is not shy.
Chester is shy.
Chester is boring.
Chester is splendid.
Kyle is not pink.
Deborah is not shy.
Quinn is splendid.
Sandy is successful.
Carroll is not splendid.
Kyle is not intellectual.
Kyle is boring.Chester is not shy if and only if Sandy is successful.
Deborah is not shy if and only if Quinn is not pink.
Uriah being not pink is equivalent to Deborah being not shy and Sandy being intellectual.
If there is at least one people who is pink, then Chester is successful.
Someone being not successful is equivalent to being not pink.
If someone is both shy and splendid, then he is boring.
It can be concluded that Sandy is intellectual once knowing that Uriah is not successful or Sandy is boring.
Someone being both boring and pink is equivalent to being not shy and splendid.
It can be concluded that Sandy is shy and Uriah is not boring once knowing that Kyle is pink and Deborah is not splendid.
If there is at least one people who is not successful, then Quinn is pink.
Someone is not successful and not intellectual if and only if he is boring and shy.
Sandy being not successful and Quinn being not boring imply that Sandy is not splendid. | Sandy is not successful. | contradiction |
Chester is not pink.
Carroll is not shy.
Chester is shy.
Chester is boring.
Chester is splendid.
Kyle is not pink.
Deborah is not shy.
Quinn is splendid.
Sandy is successful.
Carroll is not splendid.
Kyle is not intellectual.
Kyle is boring.Chester is not shy if and only if Sandy is successful.
Deborah is not shy if and only if Quinn is not pink.
Uriah being not pink is equivalent to Deborah being not shy and Sandy being intellectual.
If there is at least one people who is pink, then Chester is successful.
Someone being not successful is equivalent to being not pink.
If someone is both shy and splendid, then he is boring.
It can be concluded that Sandy is intellectual once knowing that Uriah is not successful or Sandy is boring.
Someone being both boring and pink is equivalent to being not shy and splendid.
It can be concluded that Sandy is shy and Uriah is not boring once knowing that Kyle is pink and Deborah is not splendid.
If there is at least one people who is not successful, then Quinn is pink.
Someone is not successful and not intellectual if and only if he is boring and shy.
Sandy being not successful and Quinn being not boring imply that Sandy is not splendid. | Chester is not intellectual. | entailment |
Chester is not pink.
Carroll is not shy.
Chester is shy.
Chester is boring.
Chester is splendid.
Kyle is not pink.
Deborah is not shy.
Quinn is splendid.
Sandy is successful.
Carroll is not splendid.
Kyle is not intellectual.
Kyle is boring.Chester is not shy if and only if Sandy is successful.
Deborah is not shy if and only if Quinn is not pink.
Uriah being not pink is equivalent to Deborah being not shy and Sandy being intellectual.
If there is at least one people who is pink, then Chester is successful.
Someone being not successful is equivalent to being not pink.
If someone is both shy and splendid, then he is boring.
It can be concluded that Sandy is intellectual once knowing that Uriah is not successful or Sandy is boring.
Someone being both boring and pink is equivalent to being not shy and splendid.
It can be concluded that Sandy is shy and Uriah is not boring once knowing that Kyle is pink and Deborah is not splendid.
If there is at least one people who is not successful, then Quinn is pink.
Someone is not successful and not intellectual if and only if he is boring and shy.
Sandy being not successful and Quinn being not boring imply that Sandy is not splendid. | Chester is not boring. | contradiction |
Chester is not pink.
Carroll is not shy.
Chester is shy.
Chester is boring.
Chester is splendid.
Kyle is not pink.
Deborah is not shy.
Quinn is splendid.
Sandy is successful.
Carroll is not splendid.
Kyle is not intellectual.
Kyle is boring.Chester is not shy if and only if Sandy is successful.
Deborah is not shy if and only if Quinn is not pink.
Uriah being not pink is equivalent to Deborah being not shy and Sandy being intellectual.
If there is at least one people who is pink, then Chester is successful.
Someone being not successful is equivalent to being not pink.
If someone is both shy and splendid, then he is boring.
It can be concluded that Sandy is intellectual once knowing that Uriah is not successful or Sandy is boring.
Someone being both boring and pink is equivalent to being not shy and splendid.
It can be concluded that Sandy is shy and Uriah is not boring once knowing that Kyle is pink and Deborah is not splendid.
If there is at least one people who is not successful, then Quinn is pink.
Someone is not successful and not intellectual if and only if he is boring and shy.
Sandy being not successful and Quinn being not boring imply that Sandy is not splendid. | Sandy is successful. | entailment |
Chester is not pink.
Carroll is not shy.
Chester is shy.
Chester is boring.
Chester is splendid.
Kyle is not pink.
Deborah is not shy.
Quinn is splendid.
Sandy is successful.
Carroll is not splendid.
Kyle is not intellectual.
Kyle is boring.Chester is not shy if and only if Sandy is successful.
Deborah is not shy if and only if Quinn is not pink.
Uriah being not pink is equivalent to Deborah being not shy and Sandy being intellectual.
If there is at least one people who is pink, then Chester is successful.
Someone being not successful is equivalent to being not pink.
If someone is both shy and splendid, then he is boring.
It can be concluded that Sandy is intellectual once knowing that Uriah is not successful or Sandy is boring.
Someone being both boring and pink is equivalent to being not shy and splendid.
It can be concluded that Sandy is shy and Uriah is not boring once knowing that Kyle is pink and Deborah is not splendid.
If there is at least one people who is not successful, then Quinn is pink.
Someone is not successful and not intellectual if and only if he is boring and shy.
Sandy being not successful and Quinn being not boring imply that Sandy is not splendid. | Kyle is splendid. | neutral |
Chester is not pink.
Carroll is not shy.
Chester is shy.
Chester is boring.
Chester is splendid.
Kyle is not pink.
Deborah is not shy.
Quinn is splendid.
Sandy is successful.
Carroll is not splendid.
Kyle is not intellectual.
Kyle is boring.Chester is not shy if and only if Sandy is successful.
Deborah is not shy if and only if Quinn is not pink.
Uriah being not pink is equivalent to Deborah being not shy and Sandy being intellectual.
If there is at least one people who is pink, then Chester is successful.
Someone being not successful is equivalent to being not pink.
If someone is both shy and splendid, then he is boring.
It can be concluded that Sandy is intellectual once knowing that Uriah is not successful or Sandy is boring.
Someone being both boring and pink is equivalent to being not shy and splendid.
It can be concluded that Sandy is shy and Uriah is not boring once knowing that Kyle is pink and Deborah is not splendid.
If there is at least one people who is not successful, then Quinn is pink.
Someone is not successful and not intellectual if and only if he is boring and shy.
Sandy being not successful and Quinn being not boring imply that Sandy is not splendid. | Uriah is pink. | neutral |
Chester is not pink.
Carroll is not shy.
Chester is shy.
Chester is boring.
Chester is splendid.
Kyle is not pink.
Deborah is not shy.
Quinn is splendid.
Sandy is successful.
Carroll is not splendid.
Kyle is not intellectual.
Kyle is boring.Chester is not shy if and only if Sandy is successful.
Deborah is not shy if and only if Quinn is not pink.
Uriah being not pink is equivalent to Deborah being not shy and Sandy being intellectual.
If there is at least one people who is pink, then Chester is successful.
Someone being not successful is equivalent to being not pink.
If someone is both shy and splendid, then he is boring.
It can be concluded that Sandy is intellectual once knowing that Uriah is not successful or Sandy is boring.
Someone being both boring and pink is equivalent to being not shy and splendid.
It can be concluded that Sandy is shy and Uriah is not boring once knowing that Kyle is pink and Deborah is not splendid.
If there is at least one people who is not successful, then Quinn is pink.
Someone is not successful and not intellectual if and only if he is boring and shy.
Sandy being not successful and Quinn being not boring imply that Sandy is not splendid. | Quinn is shy. | neutral |
Chester is not pink.
Carroll is not shy.
Chester is shy.
Chester is boring.
Chester is splendid.
Kyle is not pink.
Deborah is not shy.
Quinn is splendid.
Sandy is successful.
Carroll is not splendid.
Kyle is not intellectual.
Kyle is boring.Chester is not shy if and only if Sandy is successful.
Deborah is not shy if and only if Quinn is not pink.
Uriah being not pink is equivalent to Deborah being not shy and Sandy being intellectual.
If there is at least one people who is pink, then Chester is successful.
Someone being not successful is equivalent to being not pink.
If someone is both shy and splendid, then he is boring.
It can be concluded that Sandy is intellectual once knowing that Uriah is not successful or Sandy is boring.
Someone being both boring and pink is equivalent to being not shy and splendid.
It can be concluded that Sandy is shy and Uriah is not boring once knowing that Kyle is pink and Deborah is not splendid.
If there is at least one people who is not successful, then Quinn is pink.
Someone is not successful and not intellectual if and only if he is boring and shy.
Sandy being not successful and Quinn being not boring imply that Sandy is not splendid. | Chester is shy. | self_contradiction |
Chester is not pink.
Carroll is not shy.
Chester is shy.
Chester is boring.
Chester is splendid.
Kyle is not pink.
Deborah is not shy.
Quinn is splendid.
Sandy is successful.
Carroll is not splendid.
Kyle is not intellectual.
Kyle is boring.Chester is not shy if and only if Sandy is successful.
Deborah is not shy if and only if Quinn is not pink.
Uriah being not pink is equivalent to Deborah being not shy and Sandy being intellectual.
If there is at least one people who is pink, then Chester is successful.
Someone being not successful is equivalent to being not pink.
If someone is both shy and splendid, then he is boring.
It can be concluded that Sandy is intellectual once knowing that Uriah is not successful or Sandy is boring.
Someone being both boring and pink is equivalent to being not shy and splendid.
It can be concluded that Sandy is shy and Uriah is not boring once knowing that Kyle is pink and Deborah is not splendid.
If there is at least one people who is not successful, then Quinn is pink.
Someone is not successful and not intellectual if and only if he is boring and shy.
Sandy being not successful and Quinn being not boring imply that Sandy is not splendid. | Carroll is boring. | neutral |
Chester is not pink.
Carroll is not shy.
Chester is shy.
Chester is boring.
Chester is splendid.
Kyle is not pink.
Deborah is not shy.
Quinn is splendid.
Sandy is successful.
Carroll is not splendid.
Kyle is not intellectual.
Kyle is boring.Chester is not shy if and only if Sandy is successful.
Deborah is not shy if and only if Quinn is not pink.
Uriah being not pink is equivalent to Deborah being not shy and Sandy being intellectual.
If there is at least one people who is pink, then Chester is successful.
Someone being not successful is equivalent to being not pink.
If someone is both shy and splendid, then he is boring.
It can be concluded that Sandy is intellectual once knowing that Uriah is not successful or Sandy is boring.
Someone being both boring and pink is equivalent to being not shy and splendid.
It can be concluded that Sandy is shy and Uriah is not boring once knowing that Kyle is pink and Deborah is not splendid.
If there is at least one people who is not successful, then Quinn is pink.
Someone is not successful and not intellectual if and only if he is boring and shy.
Sandy being not successful and Quinn being not boring imply that Sandy is not splendid. | Kyle is shy. | entailment |
Chester is not pink.
Carroll is not shy.
Chester is shy.
Chester is boring.
Chester is splendid.
Kyle is not pink.
Deborah is not shy.
Quinn is splendid.
Sandy is successful.
Carroll is not splendid.
Kyle is not intellectual.
Kyle is boring.Chester is not shy if and only if Sandy is successful.
Deborah is not shy if and only if Quinn is not pink.
Uriah being not pink is equivalent to Deborah being not shy and Sandy being intellectual.
If there is at least one people who is pink, then Chester is successful.
Someone being not successful is equivalent to being not pink.
If someone is both shy and splendid, then he is boring.
It can be concluded that Sandy is intellectual once knowing that Uriah is not successful or Sandy is boring.
Someone being both boring and pink is equivalent to being not shy and splendid.
It can be concluded that Sandy is shy and Uriah is not boring once knowing that Kyle is pink and Deborah is not splendid.
If there is at least one people who is not successful, then Quinn is pink.
Someone is not successful and not intellectual if and only if he is boring and shy.
Sandy being not successful and Quinn being not boring imply that Sandy is not splendid. | Deborah is shy. | contradiction |
Chester is not pink.
Carroll is not shy.
Chester is shy.
Chester is boring.
Chester is splendid.
Kyle is not pink.
Deborah is not shy.
Quinn is splendid.
Sandy is successful.
Carroll is not splendid.
Kyle is not intellectual.
Kyle is boring.Chester is not shy if and only if Sandy is successful.
Deborah is not shy if and only if Quinn is not pink.
Uriah being not pink is equivalent to Deborah being not shy and Sandy being intellectual.
If there is at least one people who is pink, then Chester is successful.
Someone being not successful is equivalent to being not pink.
If someone is both shy and splendid, then he is boring.
It can be concluded that Sandy is intellectual once knowing that Uriah is not successful or Sandy is boring.
Someone being both boring and pink is equivalent to being not shy and splendid.
It can be concluded that Sandy is shy and Uriah is not boring once knowing that Kyle is pink and Deborah is not splendid.
If there is at least one people who is not successful, then Quinn is pink.
Someone is not successful and not intellectual if and only if he is boring and shy.
Sandy being not successful and Quinn being not boring imply that Sandy is not splendid. | Carroll is not shy. | entailment |
Chester is not pink.
Carroll is not shy.
Chester is shy.
Chester is boring.
Chester is splendid.
Kyle is not pink.
Deborah is not shy.
Quinn is splendid.
Sandy is successful.
Carroll is not splendid.
Kyle is not intellectual.
Kyle is boring.Chester is not shy if and only if Sandy is successful.
Deborah is not shy if and only if Quinn is not pink.
Uriah being not pink is equivalent to Deborah being not shy and Sandy being intellectual.
If there is at least one people who is pink, then Chester is successful.
Someone being not successful is equivalent to being not pink.
If someone is both shy and splendid, then he is boring.
It can be concluded that Sandy is intellectual once knowing that Uriah is not successful or Sandy is boring.
Someone being both boring and pink is equivalent to being not shy and splendid.
It can be concluded that Sandy is shy and Uriah is not boring once knowing that Kyle is pink and Deborah is not splendid.
If there is at least one people who is not successful, then Quinn is pink.
Someone is not successful and not intellectual if and only if he is boring and shy.
Sandy being not successful and Quinn being not boring imply that Sandy is not splendid. | Quinn is pink. | self_contradiction |
Chester is not pink.
Carroll is not shy.
Chester is shy.
Chester is boring.
Chester is splendid.
Kyle is not pink.
Deborah is not shy.
Quinn is splendid.
Sandy is successful.
Carroll is not splendid.
Kyle is not intellectual.
Kyle is boring.Chester is not shy if and only if Sandy is successful.
Deborah is not shy if and only if Quinn is not pink.
Uriah being not pink is equivalent to Deborah being not shy and Sandy being intellectual.
If there is at least one people who is pink, then Chester is successful.
Someone being not successful is equivalent to being not pink.
If someone is both shy and splendid, then he is boring.
It can be concluded that Sandy is intellectual once knowing that Uriah is not successful or Sandy is boring.
Someone being both boring and pink is equivalent to being not shy and splendid.
It can be concluded that Sandy is shy and Uriah is not boring once knowing that Kyle is pink and Deborah is not splendid.
If there is at least one people who is not successful, then Quinn is pink.
Someone is not successful and not intellectual if and only if he is boring and shy.
Sandy being not successful and Quinn being not boring imply that Sandy is not splendid. | Kyle is successful. | contradiction |
Chester is not pink.
Carroll is not shy.
Chester is shy.
Chester is boring.
Chester is splendid.
Kyle is not pink.
Deborah is not shy.
Quinn is splendid.
Sandy is successful.
Carroll is not splendid.
Kyle is not intellectual.
Kyle is boring.Chester is not shy if and only if Sandy is successful.
Deborah is not shy if and only if Quinn is not pink.
Uriah being not pink is equivalent to Deborah being not shy and Sandy being intellectual.
If there is at least one people who is pink, then Chester is successful.
Someone being not successful is equivalent to being not pink.
If someone is both shy and splendid, then he is boring.
It can be concluded that Sandy is intellectual once knowing that Uriah is not successful or Sandy is boring.
Someone being both boring and pink is equivalent to being not shy and splendid.
It can be concluded that Sandy is shy and Uriah is not boring once knowing that Kyle is pink and Deborah is not splendid.
If there is at least one people who is not successful, then Quinn is pink.
Someone is not successful and not intellectual if and only if he is boring and shy.
Sandy being not successful and Quinn being not boring imply that Sandy is not splendid. | Quinn is not pink. | self_contradiction |
Chester is not pink.
Carroll is not shy.
Chester is shy.
Chester is boring.
Chester is splendid.
Kyle is not pink.
Deborah is not shy.
Quinn is splendid.
Sandy is successful.
Carroll is not splendid.
Kyle is not intellectual.
Kyle is boring.Chester is not shy if and only if Sandy is successful.
Deborah is not shy if and only if Quinn is not pink.
Uriah being not pink is equivalent to Deborah being not shy and Sandy being intellectual.
If there is at least one people who is pink, then Chester is successful.
Someone being not successful is equivalent to being not pink.
If someone is both shy and splendid, then he is boring.
It can be concluded that Sandy is intellectual once knowing that Uriah is not successful or Sandy is boring.
Someone being both boring and pink is equivalent to being not shy and splendid.
It can be concluded that Sandy is shy and Uriah is not boring once knowing that Kyle is pink and Deborah is not splendid.
If there is at least one people who is not successful, then Quinn is pink.
Someone is not successful and not intellectual if and only if he is boring and shy.
Sandy being not successful and Quinn being not boring imply that Sandy is not splendid. | Chester is successful. | self_contradiction |
Chester is not pink.
Carroll is not shy.
Chester is shy.
Chester is boring.
Chester is splendid.
Kyle is not pink.
Deborah is not shy.
Quinn is splendid.
Sandy is successful.
Carroll is not splendid.
Kyle is not intellectual.
Kyle is boring.Chester is not shy if and only if Sandy is successful.
Deborah is not shy if and only if Quinn is not pink.
Uriah being not pink is equivalent to Deborah being not shy and Sandy being intellectual.
If there is at least one people who is pink, then Chester is successful.
Someone being not successful is equivalent to being not pink.
If someone is both shy and splendid, then he is boring.
It can be concluded that Sandy is intellectual once knowing that Uriah is not successful or Sandy is boring.
Someone being both boring and pink is equivalent to being not shy and splendid.
It can be concluded that Sandy is shy and Uriah is not boring once knowing that Kyle is pink and Deborah is not splendid.
If there is at least one people who is not successful, then Quinn is pink.
Someone is not successful and not intellectual if and only if he is boring and shy.
Sandy being not successful and Quinn being not boring imply that Sandy is not splendid. | Kyle is not boring. | contradiction |
Chester is not pink.
Carroll is not shy.
Chester is shy.
Chester is boring.
Chester is splendid.
Kyle is not pink.
Deborah is not shy.
Quinn is splendid.
Sandy is successful.
Carroll is not splendid.
Kyle is not intellectual.
Kyle is boring.Chester is not shy if and only if Sandy is successful.
Deborah is not shy if and only if Quinn is not pink.
Uriah being not pink is equivalent to Deborah being not shy and Sandy being intellectual.
If there is at least one people who is pink, then Chester is successful.
Someone being not successful is equivalent to being not pink.
If someone is both shy and splendid, then he is boring.
It can be concluded that Sandy is intellectual once knowing that Uriah is not successful or Sandy is boring.
Someone being both boring and pink is equivalent to being not shy and splendid.
It can be concluded that Sandy is shy and Uriah is not boring once knowing that Kyle is pink and Deborah is not splendid.
If there is at least one people who is not successful, then Quinn is pink.
Someone is not successful and not intellectual if and only if he is boring and shy.
Sandy being not successful and Quinn being not boring imply that Sandy is not splendid. | Chester is pink. | self_contradiction |
Chester is not pink.
Carroll is not shy.
Chester is shy.
Chester is boring.
Chester is splendid.
Kyle is not pink.
Deborah is not shy.
Quinn is splendid.
Sandy is successful.
Carroll is not splendid.
Kyle is not intellectual.
Kyle is boring.Chester is not shy if and only if Sandy is successful.
Deborah is not shy if and only if Quinn is not pink.
Uriah being not pink is equivalent to Deborah being not shy and Sandy being intellectual.
If there is at least one people who is pink, then Chester is successful.
Someone being not successful is equivalent to being not pink.
If someone is both shy and splendid, then he is boring.
It can be concluded that Sandy is intellectual once knowing that Uriah is not successful or Sandy is boring.
Someone being both boring and pink is equivalent to being not shy and splendid.
It can be concluded that Sandy is shy and Uriah is not boring once knowing that Kyle is pink and Deborah is not splendid.
If there is at least one people who is not successful, then Quinn is pink.
Someone is not successful and not intellectual if and only if he is boring and shy.
Sandy being not successful and Quinn being not boring imply that Sandy is not splendid. | Carroll is not pink. | neutral |
Casper is not famous.
Morris is worried.
Trent is not yellow.
Olaf is not yellow.
Trent is red.
Jerry is not worried.
Sherlock is mental.
Casper is yellow.
Morris is famous.
Jerry is not mental.
Morris is red.
Olaf is red.Someone being both not yellow and mental is equivalent to being not homely.
If Jerry is not famous or Jerry is worried, then Morris is not homely.
Jerry being famous is equivalent to Liam being not worried and Liam being not homely.
Sherlock is famous if and only if Jerry is red and Morris is mental.
If there is someone who is not yellow, then Olaf is worried and Olaf is not mental.
If Liam is famous, then Casper is mental.
Someone who is red is always yellow.
If someone is not worried or famous, then he is homely.
If there is at least one people who is both famous and not yellow, then Sherlock is red.
Someone being famous is equivalent to being not worried.
Olaf being not homely or Casper being not mental implies that Morris is red.
Sherlock is famous if and only if Morris is red. | Liam is not mental. | contradiction |
Casper is not famous.
Morris is worried.
Trent is not yellow.
Olaf is not yellow.
Trent is red.
Jerry is not worried.
Sherlock is mental.
Casper is yellow.
Morris is famous.
Jerry is not mental.
Morris is red.
Olaf is red.Someone being both not yellow and mental is equivalent to being not homely.
If Jerry is not famous or Jerry is worried, then Morris is not homely.
Jerry being famous is equivalent to Liam being not worried and Liam being not homely.
Sherlock is famous if and only if Jerry is red and Morris is mental.
If there is someone who is not yellow, then Olaf is worried and Olaf is not mental.
If Liam is famous, then Casper is mental.
Someone who is red is always yellow.
If someone is not worried or famous, then he is homely.
If there is at least one people who is both famous and not yellow, then Sherlock is red.
Someone being famous is equivalent to being not worried.
Olaf being not homely or Casper being not mental implies that Morris is red.
Sherlock is famous if and only if Morris is red. | Morris is worried. | self_contradiction |
Casper is not famous.
Morris is worried.
Trent is not yellow.
Olaf is not yellow.
Trent is red.
Jerry is not worried.
Sherlock is mental.
Casper is yellow.
Morris is famous.
Jerry is not mental.
Morris is red.
Olaf is red.Someone being both not yellow and mental is equivalent to being not homely.
If Jerry is not famous or Jerry is worried, then Morris is not homely.
Jerry being famous is equivalent to Liam being not worried and Liam being not homely.
Sherlock is famous if and only if Jerry is red and Morris is mental.
If there is someone who is not yellow, then Olaf is worried and Olaf is not mental.
If Liam is famous, then Casper is mental.
Someone who is red is always yellow.
If someone is not worried or famous, then he is homely.
If there is at least one people who is both famous and not yellow, then Sherlock is red.
Someone being famous is equivalent to being not worried.
Olaf being not homely or Casper being not mental implies that Morris is red.
Sherlock is famous if and only if Morris is red. | Liam is not red. | neutral |
Casper is not famous.
Morris is worried.
Trent is not yellow.
Olaf is not yellow.
Trent is red.
Jerry is not worried.
Sherlock is mental.
Casper is yellow.
Morris is famous.
Jerry is not mental.
Morris is red.
Olaf is red.Someone being both not yellow and mental is equivalent to being not homely.
If Jerry is not famous or Jerry is worried, then Morris is not homely.
Jerry being famous is equivalent to Liam being not worried and Liam being not homely.
Sherlock is famous if and only if Jerry is red and Morris is mental.
If there is someone who is not yellow, then Olaf is worried and Olaf is not mental.
If Liam is famous, then Casper is mental.
Someone who is red is always yellow.
If someone is not worried or famous, then he is homely.
If there is at least one people who is both famous and not yellow, then Sherlock is red.
Someone being famous is equivalent to being not worried.
Olaf being not homely or Casper being not mental implies that Morris is red.
Sherlock is famous if and only if Morris is red. | Olaf is not red. | contradiction |
Casper is not famous.
Morris is worried.
Trent is not yellow.
Olaf is not yellow.
Trent is red.
Jerry is not worried.
Sherlock is mental.
Casper is yellow.
Morris is famous.
Jerry is not mental.
Morris is red.
Olaf is red.Someone being both not yellow and mental is equivalent to being not homely.
If Jerry is not famous or Jerry is worried, then Morris is not homely.
Jerry being famous is equivalent to Liam being not worried and Liam being not homely.
Sherlock is famous if and only if Jerry is red and Morris is mental.
If there is someone who is not yellow, then Olaf is worried and Olaf is not mental.
If Liam is famous, then Casper is mental.
Someone who is red is always yellow.
If someone is not worried or famous, then he is homely.
If there is at least one people who is both famous and not yellow, then Sherlock is red.
Someone being famous is equivalent to being not worried.
Olaf being not homely or Casper being not mental implies that Morris is red.
Sherlock is famous if and only if Morris is red. | Trent is worried. | neutral |
Casper is not famous.
Morris is worried.
Trent is not yellow.
Olaf is not yellow.
Trent is red.
Jerry is not worried.
Sherlock is mental.
Casper is yellow.
Morris is famous.
Jerry is not mental.
Morris is red.
Olaf is red.Someone being both not yellow and mental is equivalent to being not homely.
If Jerry is not famous or Jerry is worried, then Morris is not homely.
Jerry being famous is equivalent to Liam being not worried and Liam being not homely.
Sherlock is famous if and only if Jerry is red and Morris is mental.
If there is someone who is not yellow, then Olaf is worried and Olaf is not mental.
If Liam is famous, then Casper is mental.
Someone who is red is always yellow.
If someone is not worried or famous, then he is homely.
If there is at least one people who is both famous and not yellow, then Sherlock is red.
Someone being famous is equivalent to being not worried.
Olaf being not homely or Casper being not mental implies that Morris is red.
Sherlock is famous if and only if Morris is red. | Sherlock is famous. | entailment |
Casper is not famous.
Morris is worried.
Trent is not yellow.
Olaf is not yellow.
Trent is red.
Jerry is not worried.
Sherlock is mental.
Casper is yellow.
Morris is famous.
Jerry is not mental.
Morris is red.
Olaf is red.Someone being both not yellow and mental is equivalent to being not homely.
If Jerry is not famous or Jerry is worried, then Morris is not homely.
Jerry being famous is equivalent to Liam being not worried and Liam being not homely.
Sherlock is famous if and only if Jerry is red and Morris is mental.
If there is someone who is not yellow, then Olaf is worried and Olaf is not mental.
If Liam is famous, then Casper is mental.
Someone who is red is always yellow.
If someone is not worried or famous, then he is homely.
If there is at least one people who is both famous and not yellow, then Sherlock is red.
Someone being famous is equivalent to being not worried.
Olaf being not homely or Casper being not mental implies that Morris is red.
Sherlock is famous if and only if Morris is red. | Sherlock is homely. | entailment |
Casper is not famous.
Morris is worried.
Trent is not yellow.
Olaf is not yellow.
Trent is red.
Jerry is not worried.
Sherlock is mental.
Casper is yellow.
Morris is famous.
Jerry is not mental.
Morris is red.
Olaf is red.Someone being both not yellow and mental is equivalent to being not homely.
If Jerry is not famous or Jerry is worried, then Morris is not homely.
Jerry being famous is equivalent to Liam being not worried and Liam being not homely.
Sherlock is famous if and only if Jerry is red and Morris is mental.
If there is someone who is not yellow, then Olaf is worried and Olaf is not mental.
If Liam is famous, then Casper is mental.
Someone who is red is always yellow.
If someone is not worried or famous, then he is homely.
If there is at least one people who is both famous and not yellow, then Sherlock is red.
Someone being famous is equivalent to being not worried.
Olaf being not homely or Casper being not mental implies that Morris is red.
Sherlock is famous if and only if Morris is red. | Liam is not famous. | contradiction |
Casper is not famous.
Morris is worried.
Trent is not yellow.
Olaf is not yellow.
Trent is red.
Jerry is not worried.
Sherlock is mental.
Casper is yellow.
Morris is famous.
Jerry is not mental.
Morris is red.
Olaf is red.Someone being both not yellow and mental is equivalent to being not homely.
If Jerry is not famous or Jerry is worried, then Morris is not homely.
Jerry being famous is equivalent to Liam being not worried and Liam being not homely.
Sherlock is famous if and only if Jerry is red and Morris is mental.
If there is someone who is not yellow, then Olaf is worried and Olaf is not mental.
If Liam is famous, then Casper is mental.
Someone who is red is always yellow.
If someone is not worried or famous, then he is homely.
If there is at least one people who is both famous and not yellow, then Sherlock is red.
Someone being famous is equivalent to being not worried.
Olaf being not homely or Casper being not mental implies that Morris is red.
Sherlock is famous if and only if Morris is red. | Casper is mental. | entailment |
Casper is not famous.
Morris is worried.
Trent is not yellow.
Olaf is not yellow.
Trent is red.
Jerry is not worried.
Sherlock is mental.
Casper is yellow.
Morris is famous.
Jerry is not mental.
Morris is red.
Olaf is red.Someone being both not yellow and mental is equivalent to being not homely.
If Jerry is not famous or Jerry is worried, then Morris is not homely.
Jerry being famous is equivalent to Liam being not worried and Liam being not homely.
Sherlock is famous if and only if Jerry is red and Morris is mental.
If there is someone who is not yellow, then Olaf is worried and Olaf is not mental.
If Liam is famous, then Casper is mental.
Someone who is red is always yellow.
If someone is not worried or famous, then he is homely.
If there is at least one people who is both famous and not yellow, then Sherlock is red.
Someone being famous is equivalent to being not worried.
Olaf being not homely or Casper being not mental implies that Morris is red.
Sherlock is famous if and only if Morris is red. | Olaf is not yellow. | self_contradiction |
Casper is not famous.
Morris is worried.
Trent is not yellow.
Olaf is not yellow.
Trent is red.
Jerry is not worried.
Sherlock is mental.
Casper is yellow.
Morris is famous.
Jerry is not mental.
Morris is red.
Olaf is red.Someone being both not yellow and mental is equivalent to being not homely.
If Jerry is not famous or Jerry is worried, then Morris is not homely.
Jerry being famous is equivalent to Liam being not worried and Liam being not homely.
Sherlock is famous if and only if Jerry is red and Morris is mental.
If there is someone who is not yellow, then Olaf is worried and Olaf is not mental.
If Liam is famous, then Casper is mental.
Someone who is red is always yellow.
If someone is not worried or famous, then he is homely.
If there is at least one people who is both famous and not yellow, then Sherlock is red.
Someone being famous is equivalent to being not worried.
Olaf being not homely or Casper being not mental implies that Morris is red.
Sherlock is famous if and only if Morris is red. | Trent is not yellow. | self_contradiction |
Casper is not famous.
Morris is worried.
Trent is not yellow.
Olaf is not yellow.
Trent is red.
Jerry is not worried.
Sherlock is mental.
Casper is yellow.
Morris is famous.
Jerry is not mental.
Morris is red.
Olaf is red.Someone being both not yellow and mental is equivalent to being not homely.
If Jerry is not famous or Jerry is worried, then Morris is not homely.
Jerry being famous is equivalent to Liam being not worried and Liam being not homely.
Sherlock is famous if and only if Jerry is red and Morris is mental.
If there is someone who is not yellow, then Olaf is worried and Olaf is not mental.
If Liam is famous, then Casper is mental.
Someone who is red is always yellow.
If someone is not worried or famous, then he is homely.
If there is at least one people who is both famous and not yellow, then Sherlock is red.
Someone being famous is equivalent to being not worried.
Olaf being not homely or Casper being not mental implies that Morris is red.
Sherlock is famous if and only if Morris is red. | Trent is not homely. | neutral |
Casper is not famous.
Morris is worried.
Trent is not yellow.
Olaf is not yellow.
Trent is red.
Jerry is not worried.
Sherlock is mental.
Casper is yellow.
Morris is famous.
Jerry is not mental.
Morris is red.
Olaf is red.Someone being both not yellow and mental is equivalent to being not homely.
If Jerry is not famous or Jerry is worried, then Morris is not homely.
Jerry being famous is equivalent to Liam being not worried and Liam being not homely.
Sherlock is famous if and only if Jerry is red and Morris is mental.
If there is someone who is not yellow, then Olaf is worried and Olaf is not mental.
If Liam is famous, then Casper is mental.
Someone who is red is always yellow.
If someone is not worried or famous, then he is homely.
If there is at least one people who is both famous and not yellow, then Sherlock is red.
Someone being famous is equivalent to being not worried.
Olaf being not homely or Casper being not mental implies that Morris is red.
Sherlock is famous if and only if Morris is red. | Liam is homely. | self_contradiction |
Casper is not famous.
Morris is worried.
Trent is not yellow.
Olaf is not yellow.
Trent is red.
Jerry is not worried.
Sherlock is mental.
Casper is yellow.
Morris is famous.
Jerry is not mental.
Morris is red.
Olaf is red.Someone being both not yellow and mental is equivalent to being not homely.
If Jerry is not famous or Jerry is worried, then Morris is not homely.
Jerry being famous is equivalent to Liam being not worried and Liam being not homely.
Sherlock is famous if and only if Jerry is red and Morris is mental.
If there is someone who is not yellow, then Olaf is worried and Olaf is not mental.
If Liam is famous, then Casper is mental.
Someone who is red is always yellow.
If someone is not worried or famous, then he is homely.
If there is at least one people who is both famous and not yellow, then Sherlock is red.
Someone being famous is equivalent to being not worried.
Olaf being not homely or Casper being not mental implies that Morris is red.
Sherlock is famous if and only if Morris is red. | Morris is not mental. | contradiction |
Casper is not famous.
Morris is worried.
Trent is not yellow.
Olaf is not yellow.
Trent is red.
Jerry is not worried.
Sherlock is mental.
Casper is yellow.
Morris is famous.
Jerry is not mental.
Morris is red.
Olaf is red.Someone being both not yellow and mental is equivalent to being not homely.
If Jerry is not famous or Jerry is worried, then Morris is not homely.
Jerry being famous is equivalent to Liam being not worried and Liam being not homely.
Sherlock is famous if and only if Jerry is red and Morris is mental.
If there is someone who is not yellow, then Olaf is worried and Olaf is not mental.
If Liam is famous, then Casper is mental.
Someone who is red is always yellow.
If someone is not worried or famous, then he is homely.
If there is at least one people who is both famous and not yellow, then Sherlock is red.
Someone being famous is equivalent to being not worried.
Olaf being not homely or Casper being not mental implies that Morris is red.
Sherlock is famous if and only if Morris is red. | Jerry is homely. | entailment |
Casper is not famous.
Morris is worried.
Trent is not yellow.
Olaf is not yellow.
Trent is red.
Jerry is not worried.
Sherlock is mental.
Casper is yellow.
Morris is famous.
Jerry is not mental.
Morris is red.
Olaf is red.Someone being both not yellow and mental is equivalent to being not homely.
If Jerry is not famous or Jerry is worried, then Morris is not homely.
Jerry being famous is equivalent to Liam being not worried and Liam being not homely.
Sherlock is famous if and only if Jerry is red and Morris is mental.
If there is someone who is not yellow, then Olaf is worried and Olaf is not mental.
If Liam is famous, then Casper is mental.
Someone who is red is always yellow.
If someone is not worried or famous, then he is homely.
If there is at least one people who is both famous and not yellow, then Sherlock is red.
Someone being famous is equivalent to being not worried.
Olaf being not homely or Casper being not mental implies that Morris is red.
Sherlock is famous if and only if Morris is red. | Olaf is not famous. | neutral |
Casper is not famous.
Morris is worried.
Trent is not yellow.
Olaf is not yellow.
Trent is red.
Jerry is not worried.
Sherlock is mental.
Casper is yellow.
Morris is famous.
Jerry is not mental.
Morris is red.
Olaf is red.Someone being both not yellow and mental is equivalent to being not homely.
If Jerry is not famous or Jerry is worried, then Morris is not homely.
Jerry being famous is equivalent to Liam being not worried and Liam being not homely.
Sherlock is famous if and only if Jerry is red and Morris is mental.
If there is someone who is not yellow, then Olaf is worried and Olaf is not mental.
If Liam is famous, then Casper is mental.
Someone who is red is always yellow.
If someone is not worried or famous, then he is homely.
If there is at least one people who is both famous and not yellow, then Sherlock is red.
Someone being famous is equivalent to being not worried.
Olaf being not homely or Casper being not mental implies that Morris is red.
Sherlock is famous if and only if Morris is red. | Olaf is yellow. | self_contradiction |
Casper is not famous.
Morris is worried.
Trent is not yellow.
Olaf is not yellow.
Trent is red.
Jerry is not worried.
Sherlock is mental.
Casper is yellow.
Morris is famous.
Jerry is not mental.
Morris is red.
Olaf is red.Someone being both not yellow and mental is equivalent to being not homely.
If Jerry is not famous or Jerry is worried, then Morris is not homely.
Jerry being famous is equivalent to Liam being not worried and Liam being not homely.
Sherlock is famous if and only if Jerry is red and Morris is mental.
If there is someone who is not yellow, then Olaf is worried and Olaf is not mental.
If Liam is famous, then Casper is mental.
Someone who is red is always yellow.
If someone is not worried or famous, then he is homely.
If there is at least one people who is both famous and not yellow, then Sherlock is red.
Someone being famous is equivalent to being not worried.
Olaf being not homely or Casper being not mental implies that Morris is red.
Sherlock is famous if and only if Morris is red. | Liam is not yellow. | entailment |
Casper is not famous.
Morris is worried.
Trent is not yellow.
Olaf is not yellow.
Trent is red.
Jerry is not worried.
Sherlock is mental.
Casper is yellow.
Morris is famous.
Jerry is not mental.
Morris is red.
Olaf is red.Someone being both not yellow and mental is equivalent to being not homely.
If Jerry is not famous or Jerry is worried, then Morris is not homely.
Jerry being famous is equivalent to Liam being not worried and Liam being not homely.
Sherlock is famous if and only if Jerry is red and Morris is mental.
If there is someone who is not yellow, then Olaf is worried and Olaf is not mental.
If Liam is famous, then Casper is mental.
Someone who is red is always yellow.
If someone is not worried or famous, then he is homely.
If there is at least one people who is both famous and not yellow, then Sherlock is red.
Someone being famous is equivalent to being not worried.
Olaf being not homely or Casper being not mental implies that Morris is red.
Sherlock is famous if and only if Morris is red. | Casper is not yellow. | contradiction |
Casper is not famous.
Morris is worried.
Trent is not yellow.
Olaf is not yellow.
Trent is red.
Jerry is not worried.
Sherlock is mental.
Casper is yellow.
Morris is famous.
Jerry is not mental.
Morris is red.
Olaf is red.Someone being both not yellow and mental is equivalent to being not homely.
If Jerry is not famous or Jerry is worried, then Morris is not homely.
Jerry being famous is equivalent to Liam being not worried and Liam being not homely.
Sherlock is famous if and only if Jerry is red and Morris is mental.
If there is someone who is not yellow, then Olaf is worried and Olaf is not mental.
If Liam is famous, then Casper is mental.
Someone who is red is always yellow.
If someone is not worried or famous, then he is homely.
If there is at least one people who is both famous and not yellow, then Sherlock is red.
Someone being famous is equivalent to being not worried.
Olaf being not homely or Casper being not mental implies that Morris is red.
Sherlock is famous if and only if Morris is red. | Casper is not worried. | neutral |
Justin is weak.
Miranda is perfect.
Sherman is remarkable.
Miranda is popular.
Morton is not perfect.
Sherman is perfect.
Bryant is not nice.
Kimberly is not weak.
Bryant is hard-working.
Miranda is not hard-working.
Jorge is not weak.
Sherman is weak.If someone is nice, then he is remarkable, and vice versa.
If Bryant is weak, then Kimberly is hard-working, and vice versa.
If someone who is hard-working is also not perfect, then he is not popular.
If there is at least one people who is both not remarkable and weak, then Sherman is nice.
If someone is nice or he is not weak, then he is not popular.
It can be concluded that Kimberly is hard-working once knowing that Justin is not remarkable.
If someone is not nice, then he is not hard-working.
If Jorge is not popular, then Kimberly is not hard-working.
Bryant is popular if and only if Jorge is hard-working.
If someone is not weak and popular, then he is not hard-working, and vice versa.
If Miranda is not nice, then Sherman is not remarkable and Kimberly is not popular.
If someone is perfect and not remarkable, then he is both not nice and hard-working, and vice versa. | Sherman is remarkable. | entailment |
Justin is weak.
Miranda is perfect.
Sherman is remarkable.
Miranda is popular.
Morton is not perfect.
Sherman is perfect.
Bryant is not nice.
Kimberly is not weak.
Bryant is hard-working.
Miranda is not hard-working.
Jorge is not weak.
Sherman is weak.If someone is nice, then he is remarkable, and vice versa.
If Bryant is weak, then Kimberly is hard-working, and vice versa.
If someone who is hard-working is also not perfect, then he is not popular.
If there is at least one people who is both not remarkable and weak, then Sherman is nice.
If someone is nice or he is not weak, then he is not popular.
It can be concluded that Kimberly is hard-working once knowing that Justin is not remarkable.
If someone is not nice, then he is not hard-working.
If Jorge is not popular, then Kimberly is not hard-working.
Bryant is popular if and only if Jorge is hard-working.
If someone is not weak and popular, then he is not hard-working, and vice versa.
If Miranda is not nice, then Sherman is not remarkable and Kimberly is not popular.
If someone is perfect and not remarkable, then he is both not nice and hard-working, and vice versa. | Jorge is nice. | neutral |
Justin is weak.
Miranda is perfect.
Sherman is remarkable.
Miranda is popular.
Morton is not perfect.
Sherman is perfect.
Bryant is not nice.
Kimberly is not weak.
Bryant is hard-working.
Miranda is not hard-working.
Jorge is not weak.
Sherman is weak.If someone is nice, then he is remarkable, and vice versa.
If Bryant is weak, then Kimberly is hard-working, and vice versa.
If someone who is hard-working is also not perfect, then he is not popular.
If there is at least one people who is both not remarkable and weak, then Sherman is nice.
If someone is nice or he is not weak, then he is not popular.
It can be concluded that Kimberly is hard-working once knowing that Justin is not remarkable.
If someone is not nice, then he is not hard-working.
If Jorge is not popular, then Kimberly is not hard-working.
Bryant is popular if and only if Jorge is hard-working.
If someone is not weak and popular, then he is not hard-working, and vice versa.
If Miranda is not nice, then Sherman is not remarkable and Kimberly is not popular.
If someone is perfect and not remarkable, then he is both not nice and hard-working, and vice versa. | Miranda is popular. | self_contradiction |
Justin is weak.
Miranda is perfect.
Sherman is remarkable.
Miranda is popular.
Morton is not perfect.
Sherman is perfect.
Bryant is not nice.
Kimberly is not weak.
Bryant is hard-working.
Miranda is not hard-working.
Jorge is not weak.
Sherman is weak.If someone is nice, then he is remarkable, and vice versa.
If Bryant is weak, then Kimberly is hard-working, and vice versa.
If someone who is hard-working is also not perfect, then he is not popular.
If there is at least one people who is both not remarkable and weak, then Sherman is nice.
If someone is nice or he is not weak, then he is not popular.
It can be concluded that Kimberly is hard-working once knowing that Justin is not remarkable.
If someone is not nice, then he is not hard-working.
If Jorge is not popular, then Kimberly is not hard-working.
Bryant is popular if and only if Jorge is hard-working.
If someone is not weak and popular, then he is not hard-working, and vice versa.
If Miranda is not nice, then Sherman is not remarkable and Kimberly is not popular.
If someone is perfect and not remarkable, then he is both not nice and hard-working, and vice versa. | Kimberly is not popular. | self_contradiction |
Justin is weak.
Miranda is perfect.
Sherman is remarkable.
Miranda is popular.
Morton is not perfect.
Sherman is perfect.
Bryant is not nice.
Kimberly is not weak.
Bryant is hard-working.
Miranda is not hard-working.
Jorge is not weak.
Sherman is weak.If someone is nice, then he is remarkable, and vice versa.
If Bryant is weak, then Kimberly is hard-working, and vice versa.
If someone who is hard-working is also not perfect, then he is not popular.
If there is at least one people who is both not remarkable and weak, then Sherman is nice.
If someone is nice or he is not weak, then he is not popular.
It can be concluded that Kimberly is hard-working once knowing that Justin is not remarkable.
If someone is not nice, then he is not hard-working.
If Jorge is not popular, then Kimberly is not hard-working.
Bryant is popular if and only if Jorge is hard-working.
If someone is not weak and popular, then he is not hard-working, and vice versa.
If Miranda is not nice, then Sherman is not remarkable and Kimberly is not popular.
If someone is perfect and not remarkable, then he is both not nice and hard-working, and vice versa. | Bryant is not popular. | self_contradiction |
Justin is weak.
Miranda is perfect.
Sherman is remarkable.
Miranda is popular.
Morton is not perfect.
Sherman is perfect.
Bryant is not nice.
Kimberly is not weak.
Bryant is hard-working.
Miranda is not hard-working.
Jorge is not weak.
Sherman is weak.If someone is nice, then he is remarkable, and vice versa.
If Bryant is weak, then Kimberly is hard-working, and vice versa.
If someone who is hard-working is also not perfect, then he is not popular.
If there is at least one people who is both not remarkable and weak, then Sherman is nice.
If someone is nice or he is not weak, then he is not popular.
It can be concluded that Kimberly is hard-working once knowing that Justin is not remarkable.
If someone is not nice, then he is not hard-working.
If Jorge is not popular, then Kimberly is not hard-working.
Bryant is popular if and only if Jorge is hard-working.
If someone is not weak and popular, then he is not hard-working, and vice versa.
If Miranda is not nice, then Sherman is not remarkable and Kimberly is not popular.
If someone is perfect and not remarkable, then he is both not nice and hard-working, and vice versa. | Justin is nice. | neutral |
Justin is weak.
Miranda is perfect.
Sherman is remarkable.
Miranda is popular.
Morton is not perfect.
Sherman is perfect.
Bryant is not nice.
Kimberly is not weak.
Bryant is hard-working.
Miranda is not hard-working.
Jorge is not weak.
Sherman is weak.If someone is nice, then he is remarkable, and vice versa.
If Bryant is weak, then Kimberly is hard-working, and vice versa.
If someone who is hard-working is also not perfect, then he is not popular.
If there is at least one people who is both not remarkable and weak, then Sherman is nice.
If someone is nice or he is not weak, then he is not popular.
It can be concluded that Kimberly is hard-working once knowing that Justin is not remarkable.
If someone is not nice, then he is not hard-working.
If Jorge is not popular, then Kimberly is not hard-working.
Bryant is popular if and only if Jorge is hard-working.
If someone is not weak and popular, then he is not hard-working, and vice versa.
If Miranda is not nice, then Sherman is not remarkable and Kimberly is not popular.
If someone is perfect and not remarkable, then he is both not nice and hard-working, and vice versa. | Kimberly is popular. | self_contradiction |
Justin is weak.
Miranda is perfect.
Sherman is remarkable.
Miranda is popular.
Morton is not perfect.
Sherman is perfect.
Bryant is not nice.
Kimberly is not weak.
Bryant is hard-working.
Miranda is not hard-working.
Jorge is not weak.
Sherman is weak.If someone is nice, then he is remarkable, and vice versa.
If Bryant is weak, then Kimberly is hard-working, and vice versa.
If someone who is hard-working is also not perfect, then he is not popular.
If there is at least one people who is both not remarkable and weak, then Sherman is nice.
If someone is nice or he is not weak, then he is not popular.
It can be concluded that Kimberly is hard-working once knowing that Justin is not remarkable.
If someone is not nice, then he is not hard-working.
If Jorge is not popular, then Kimberly is not hard-working.
Bryant is popular if and only if Jorge is hard-working.
If someone is not weak and popular, then he is not hard-working, and vice versa.
If Miranda is not nice, then Sherman is not remarkable and Kimberly is not popular.
If someone is perfect and not remarkable, then he is both not nice and hard-working, and vice versa. | Justin is not weak. | contradiction |
Justin is weak.
Miranda is perfect.
Sherman is remarkable.
Miranda is popular.
Morton is not perfect.
Sherman is perfect.
Bryant is not nice.
Kimberly is not weak.
Bryant is hard-working.
Miranda is not hard-working.
Jorge is not weak.
Sherman is weak.If someone is nice, then he is remarkable, and vice versa.
If Bryant is weak, then Kimberly is hard-working, and vice versa.
If someone who is hard-working is also not perfect, then he is not popular.
If there is at least one people who is both not remarkable and weak, then Sherman is nice.
If someone is nice or he is not weak, then he is not popular.
It can be concluded that Kimberly is hard-working once knowing that Justin is not remarkable.
If someone is not nice, then he is not hard-working.
If Jorge is not popular, then Kimberly is not hard-working.
Bryant is popular if and only if Jorge is hard-working.
If someone is not weak and popular, then he is not hard-working, and vice versa.
If Miranda is not nice, then Sherman is not remarkable and Kimberly is not popular.
If someone is perfect and not remarkable, then he is both not nice and hard-working, and vice versa. | Jorge is remarkable. | neutral |
Justin is weak.
Miranda is perfect.
Sherman is remarkable.
Miranda is popular.
Morton is not perfect.
Sherman is perfect.
Bryant is not nice.
Kimberly is not weak.
Bryant is hard-working.
Miranda is not hard-working.
Jorge is not weak.
Sherman is weak.If someone is nice, then he is remarkable, and vice versa.
If Bryant is weak, then Kimberly is hard-working, and vice versa.
If someone who is hard-working is also not perfect, then he is not popular.
If there is at least one people who is both not remarkable and weak, then Sherman is nice.
If someone is nice or he is not weak, then he is not popular.
It can be concluded that Kimberly is hard-working once knowing that Justin is not remarkable.
If someone is not nice, then he is not hard-working.
If Jorge is not popular, then Kimberly is not hard-working.
Bryant is popular if and only if Jorge is hard-working.
If someone is not weak and popular, then he is not hard-working, and vice versa.
If Miranda is not nice, then Sherman is not remarkable and Kimberly is not popular.
If someone is perfect and not remarkable, then he is both not nice and hard-working, and vice versa. | Kimberly is remarkable. | neutral |
Justin is weak.
Miranda is perfect.
Sherman is remarkable.
Miranda is popular.
Morton is not perfect.
Sherman is perfect.
Bryant is not nice.
Kimberly is not weak.
Bryant is hard-working.
Miranda is not hard-working.
Jorge is not weak.
Sherman is weak.If someone is nice, then he is remarkable, and vice versa.
If Bryant is weak, then Kimberly is hard-working, and vice versa.
If someone who is hard-working is also not perfect, then he is not popular.
If there is at least one people who is both not remarkable and weak, then Sherman is nice.
If someone is nice or he is not weak, then he is not popular.
It can be concluded that Kimberly is hard-working once knowing that Justin is not remarkable.
If someone is not nice, then he is not hard-working.
If Jorge is not popular, then Kimberly is not hard-working.
Bryant is popular if and only if Jorge is hard-working.
If someone is not weak and popular, then he is not hard-working, and vice versa.
If Miranda is not nice, then Sherman is not remarkable and Kimberly is not popular.
If someone is perfect and not remarkable, then he is both not nice and hard-working, and vice versa. | Sherman is weak. | entailment |
Justin is weak.
Miranda is perfect.
Sherman is remarkable.
Miranda is popular.
Morton is not perfect.
Sherman is perfect.
Bryant is not nice.
Kimberly is not weak.
Bryant is hard-working.
Miranda is not hard-working.
Jorge is not weak.
Sherman is weak.If someone is nice, then he is remarkable, and vice versa.
If Bryant is weak, then Kimberly is hard-working, and vice versa.
If someone who is hard-working is also not perfect, then he is not popular.
If there is at least one people who is both not remarkable and weak, then Sherman is nice.
If someone is nice or he is not weak, then he is not popular.
It can be concluded that Kimberly is hard-working once knowing that Justin is not remarkable.
If someone is not nice, then he is not hard-working.
If Jorge is not popular, then Kimberly is not hard-working.
Bryant is popular if and only if Jorge is hard-working.
If someone is not weak and popular, then he is not hard-working, and vice versa.
If Miranda is not nice, then Sherman is not remarkable and Kimberly is not popular.
If someone is perfect and not remarkable, then he is both not nice and hard-working, and vice versa. | Kimberly is not hard-working. | entailment |
Justin is weak.
Miranda is perfect.
Sherman is remarkable.
Miranda is popular.
Morton is not perfect.
Sherman is perfect.
Bryant is not nice.
Kimberly is not weak.
Bryant is hard-working.
Miranda is not hard-working.
Jorge is not weak.
Sherman is weak.If someone is nice, then he is remarkable, and vice versa.
If Bryant is weak, then Kimberly is hard-working, and vice versa.
If someone who is hard-working is also not perfect, then he is not popular.
If there is at least one people who is both not remarkable and weak, then Sherman is nice.
If someone is nice or he is not weak, then he is not popular.
It can be concluded that Kimberly is hard-working once knowing that Justin is not remarkable.
If someone is not nice, then he is not hard-working.
If Jorge is not popular, then Kimberly is not hard-working.
Bryant is popular if and only if Jorge is hard-working.
If someone is not weak and popular, then he is not hard-working, and vice versa.
If Miranda is not nice, then Sherman is not remarkable and Kimberly is not popular.
If someone is perfect and not remarkable, then he is both not nice and hard-working, and vice versa. | Miranda is hard-working. | contradiction |
Justin is weak.
Miranda is perfect.
Sherman is remarkable.
Miranda is popular.
Morton is not perfect.
Sherman is perfect.
Bryant is not nice.
Kimberly is not weak.
Bryant is hard-working.
Miranda is not hard-working.
Jorge is not weak.
Sherman is weak.If someone is nice, then he is remarkable, and vice versa.
If Bryant is weak, then Kimberly is hard-working, and vice versa.
If someone who is hard-working is also not perfect, then he is not popular.
If there is at least one people who is both not remarkable and weak, then Sherman is nice.
If someone is nice or he is not weak, then he is not popular.
It can be concluded that Kimberly is hard-working once knowing that Justin is not remarkable.
If someone is not nice, then he is not hard-working.
If Jorge is not popular, then Kimberly is not hard-working.
Bryant is popular if and only if Jorge is hard-working.
If someone is not weak and popular, then he is not hard-working, and vice versa.
If Miranda is not nice, then Sherman is not remarkable and Kimberly is not popular.
If someone is perfect and not remarkable, then he is both not nice and hard-working, and vice versa. | Miranda is not perfect. | contradiction |
Justin is weak.
Miranda is perfect.
Sherman is remarkable.
Miranda is popular.
Morton is not perfect.
Sherman is perfect.
Bryant is not nice.
Kimberly is not weak.
Bryant is hard-working.
Miranda is not hard-working.
Jorge is not weak.
Sherman is weak.If someone is nice, then he is remarkable, and vice versa.
If Bryant is weak, then Kimberly is hard-working, and vice versa.
If someone who is hard-working is also not perfect, then he is not popular.
If there is at least one people who is both not remarkable and weak, then Sherman is nice.
If someone is nice or he is not weak, then he is not popular.
It can be concluded that Kimberly is hard-working once knowing that Justin is not remarkable.
If someone is not nice, then he is not hard-working.
If Jorge is not popular, then Kimberly is not hard-working.
Bryant is popular if and only if Jorge is hard-working.
If someone is not weak and popular, then he is not hard-working, and vice versa.
If Miranda is not nice, then Sherman is not remarkable and Kimberly is not popular.
If someone is perfect and not remarkable, then he is both not nice and hard-working, and vice versa. | Sherman is nice. | entailment |
Justin is weak.
Miranda is perfect.
Sherman is remarkable.
Miranda is popular.
Morton is not perfect.
Sherman is perfect.
Bryant is not nice.
Kimberly is not weak.
Bryant is hard-working.
Miranda is not hard-working.
Jorge is not weak.
Sherman is weak.If someone is nice, then he is remarkable, and vice versa.
If Bryant is weak, then Kimberly is hard-working, and vice versa.
If someone who is hard-working is also not perfect, then he is not popular.
If there is at least one people who is both not remarkable and weak, then Sherman is nice.
If someone is nice or he is not weak, then he is not popular.
It can be concluded that Kimberly is hard-working once knowing that Justin is not remarkable.
If someone is not nice, then he is not hard-working.
If Jorge is not popular, then Kimberly is not hard-working.
Bryant is popular if and only if Jorge is hard-working.
If someone is not weak and popular, then he is not hard-working, and vice versa.
If Miranda is not nice, then Sherman is not remarkable and Kimberly is not popular.
If someone is perfect and not remarkable, then he is both not nice and hard-working, and vice versa. | Miranda is not hard-working. | entailment |
Justin is weak.
Miranda is perfect.
Sherman is remarkable.
Miranda is popular.
Morton is not perfect.
Sherman is perfect.
Bryant is not nice.
Kimberly is not weak.
Bryant is hard-working.
Miranda is not hard-working.
Jorge is not weak.
Sherman is weak.If someone is nice, then he is remarkable, and vice versa.
If Bryant is weak, then Kimberly is hard-working, and vice versa.
If someone who is hard-working is also not perfect, then he is not popular.
If there is at least one people who is both not remarkable and weak, then Sherman is nice.
If someone is nice or he is not weak, then he is not popular.
It can be concluded that Kimberly is hard-working once knowing that Justin is not remarkable.
If someone is not nice, then he is not hard-working.
If Jorge is not popular, then Kimberly is not hard-working.
Bryant is popular if and only if Jorge is hard-working.
If someone is not weak and popular, then he is not hard-working, and vice versa.
If Miranda is not nice, then Sherman is not remarkable and Kimberly is not popular.
If someone is perfect and not remarkable, then he is both not nice and hard-working, and vice versa. | Bryant is popular. | self_contradiction |
Justin is weak.
Miranda is perfect.
Sherman is remarkable.
Miranda is popular.
Morton is not perfect.
Sherman is perfect.
Bryant is not nice.
Kimberly is not weak.
Bryant is hard-working.
Miranda is not hard-working.
Jorge is not weak.
Sherman is weak.If someone is nice, then he is remarkable, and vice versa.
If Bryant is weak, then Kimberly is hard-working, and vice versa.
If someone who is hard-working is also not perfect, then he is not popular.
If there is at least one people who is both not remarkable and weak, then Sherman is nice.
If someone is nice or he is not weak, then he is not popular.
It can be concluded that Kimberly is hard-working once knowing that Justin is not remarkable.
If someone is not nice, then he is not hard-working.
If Jorge is not popular, then Kimberly is not hard-working.
Bryant is popular if and only if Jorge is hard-working.
If someone is not weak and popular, then he is not hard-working, and vice versa.
If Miranda is not nice, then Sherman is not remarkable and Kimberly is not popular.
If someone is perfect and not remarkable, then he is both not nice and hard-working, and vice versa. | Kimberly is hard-working. | contradiction |
Justin is weak.
Miranda is perfect.
Sherman is remarkable.
Miranda is popular.
Morton is not perfect.
Sherman is perfect.
Bryant is not nice.
Kimberly is not weak.
Bryant is hard-working.
Miranda is not hard-working.
Jorge is not weak.
Sherman is weak.If someone is nice, then he is remarkable, and vice versa.
If Bryant is weak, then Kimberly is hard-working, and vice versa.
If someone who is hard-working is also not perfect, then he is not popular.
If there is at least one people who is both not remarkable and weak, then Sherman is nice.
If someone is nice or he is not weak, then he is not popular.
It can be concluded that Kimberly is hard-working once knowing that Justin is not remarkable.
If someone is not nice, then he is not hard-working.
If Jorge is not popular, then Kimberly is not hard-working.
Bryant is popular if and only if Jorge is hard-working.
If someone is not weak and popular, then he is not hard-working, and vice versa.
If Miranda is not nice, then Sherman is not remarkable and Kimberly is not popular.
If someone is perfect and not remarkable, then he is both not nice and hard-working, and vice versa. | Sherman is not perfect. | contradiction |
Justin is weak.
Miranda is perfect.
Sherman is remarkable.
Miranda is popular.
Morton is not perfect.
Sherman is perfect.
Bryant is not nice.
Kimberly is not weak.
Bryant is hard-working.
Miranda is not hard-working.
Jorge is not weak.
Sherman is weak.If someone is nice, then he is remarkable, and vice versa.
If Bryant is weak, then Kimberly is hard-working, and vice versa.
If someone who is hard-working is also not perfect, then he is not popular.
If there is at least one people who is both not remarkable and weak, then Sherman is nice.
If someone is nice or he is not weak, then he is not popular.
It can be concluded that Kimberly is hard-working once knowing that Justin is not remarkable.
If someone is not nice, then he is not hard-working.
If Jorge is not popular, then Kimberly is not hard-working.
Bryant is popular if and only if Jorge is hard-working.
If someone is not weak and popular, then he is not hard-working, and vice versa.
If Miranda is not nice, then Sherman is not remarkable and Kimberly is not popular.
If someone is perfect and not remarkable, then he is both not nice and hard-working, and vice versa. | Kimberly is nice. | neutral |
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