recursal/Fanatic-Fandom huggingface dataset:
10: Macrophages IV

**10: Macrophages IV** is the tenth level of the game.

## Description

*The enviroment of this challenge is less friendly than the previous one. Can you nevertheless get 300 cells?*

*This requires some serious optimization of your cells. Note that all challenges do not have to be solved to progress in the game.*

## Solution

There are several elements to the solution:

1. Create a phagocyte in Mode 1, make sure it makes adhesion and split it into M2 and M3;
2. Make M2 a flagellocyte and increase its split mass to the available maximum to make less flagellocyte/make sure it does not break up as long as possible;
3. Make M3 a phagocyte, make it split into M3 and M1;
4. Select M3 and make sure the split angle is 30%, while Child 1 split angle is aligned with the flagellocyte direction (e.g. 330 degrees), make Child 2 point to the opposite direction (e.g. 120 degrees);
5. Make phagocyte split mass 1.66 Ng to make phagocytes split faster and make cytoskeleton to 0.75 to decrease the limited resource consumption;
6. Go to Microscope and incubate to grow more food, then freeze and put in all 30 cells, then observe.

 Other
David Harbour

**David Harbour** (nacido el 10 de abril de 1974) es un actor de nacionalidad estadounidense. Él interpretó a Jim Hopper en la serie *Stranger Things*.

## Biografía

Harbour es nativo de Nueva York y posee una doble licenciatura en Drama e Italiano de la universidad Dartmouth College. Comenzó su carrera en el teatro y debutó en Broadway con la versión de 1999 de *The Rainmaker*. Posteriormente estuvo nominado a los Tony por interpretar el personaje de Nick en la versión de 2005 de *¿Quién teme a Virginia Woolf?*, de Edward Albee. Recientemente ha protagonizado junto a Al Pacino la versión de 2012/2013 de *Éxito a cualquier precio*, de David Mamet. Entre sus trabajos en Broadway también se incluyen *El mercader de Venecia*, también con Al Pacino; la trilogía teatral de Tom Stoppard, *The Coast of Utopia*, en la que se incluyen las obras *Voyage*, *Shipwreck* y *Salvage*; y *The Invention of Love*, también de Stoppard. Además, participó en la obra ajena a Broadway de Lanford Wilson, *The Fifth of July* y en el estreno mundial de *Time Stands Still*, de Donald Margulies, en el teatro Geffen de Los Ángeles.

### Vida Privada

Anteriormente salió con la actriz Julia Stiles de 2011 a 2012, quien apareció con él en la serie *Blue*, además de en la película *Between Us*.
List of all Standard Smart Swimmers

This article is for the list of all Standard Smart Swimmers. For the species itself, see Standard Smart Swimmer.

## Pooping Smart Swimmer

Pooping smart swimmers are similar to Smart Swimmers, but what makes it special is, they have a mechanism called "Pooping". They possess two stereocytes; one to poop and one to hatch other smart swimmers. From their name, that is why they poop.

### The Poop

The poop use 2 modes, first being a phagocyte. That, being a phagocyte will first collect food from hatched poop. When it hatches, it will make 2 brown lipocytes. The reason why they poop is because they usually poop for predators to eat them. Although this is a waste of nutrients, it's still good for luring predators. The poop are brown.
Buoyocyte

The Buoyocyte is an intermediate cell that is unlocked after completing "Countermeasure". It has the ability to change its density.

## Description

The nucleus of the Buoyocyte is off-centered, and there appears to be a vacuole within, giving it the appearance of smiling. Depending on the density setting, it can float or sink. Inside the vacuole, there are spiky spots. Closer inspection of the vacuole reveals that it looks to be sucking the spiky patches. The spiky spots will be squashed by the top of the vacuole, making them smaller.

### Cell-specific settings

Density: A higher density makes the cell sink, while a lower density makes it float. This can be programmed with signal substance dependence, making this cell compatible with Senseocytes, Stereocytes and Neurocytes.

## Trivia

* It appears to be smiling
* It is completely useless if gravity is off
* If you zoom in, the bubbles are spiky.
* It is impossible to set the Buoyocyte density to a fixed value between 0.00 and 0.03, or between -0.03 and 0.00, using the in-game genome editor. A value of exactly 0 is allowed, however.
* The bubbles and the stuff inside the vacuole is actually a seperate liquid.
Maggot

This is a stub or is otherwise incomplete, you can help by making it bigger. You can edit this page here.

## Cell stats

### Defence

N/A

The Fly Maggot (Musca domestica) is a species of parasitic larva that is not capable of metamorphosis into an adult fly. These larvae are weak and cannot defend themselves from predators, as they are also much slow and possess no Keratinocytes, which could cost them their lives. Maggots like to live in large colonies of them, always sticking together, although some of their brethren may be devoured by the Rhinoceros Maggot, a stronger and more dangerous maggot that can protect itself and has decided to unfortunately prey on Maggots alone, its only food source besides nutrients. Maggots feed on the nutrients on substrates while using their head to steer them towards food sources, thus keeping them alive and in healthy condition. It is best to have these guys live in a plate size of 2.0 and nutrient max equal 7000, allowing many to coexist and thrive, without starving each other for food.

## Appearance

Maggots are invasive parasites that do resemble real-life maggots with many of their similarities in traits and appearance. Maggots possess a brown Stereocyte head, the brain of their body, and this allows them to control movement through their Flagellocytes. Every Maggot has 8 legs (their Flagellocytes), needing these extra pairs for speed, although Maggots still move way slower than their predator. They also have 8 Phagocytes which collects the food that the Stereocyte finds and a singular Photocyte at their abdomen to serve as a secondary food producer during hard times like; famine, desertification and low-nutrient environments.

## Behaviour

Maggots have a slow, sluggish behaviour, being quite lazy and gluttonous eaters, loving to eat as much as they possibly can before other Maggots snatch their nutrients away from them. Maggots cannot protect their food from others, not willingly wanting to share, but due to their lack of equipment to be able to fend themselves or their food off, they will have to retreat their food to the others, whether they like it or not. Maggots also can't run away from their predators, since their brain was created to only find and eat food, not to also multitask in running away, and even if it tried to run away, its predators are much faster than it, making an easy snack out of it.

## Trivia

* Fly Maggots are very similar to real life Maggots and resemble them almost perfectly.
* They work well in large colonies (minimum 10).
* They are preyed on by the Rhinoceros Maggot.
* Maggots have a shorter, yet faster cousin, the Grubb.

## Gallery

A lone MaggotA Maggot being devoured by a Rhinoceros Maggot nymph.A large colony of Maggots living together (19 individuals)
62: Avoidance

**62: Avoidance** is the sixty-second level of the game.

## Description

*"Can you make a species reproduce to 150 cells while keeping the inital cell count lo for 100 h?"*

## Substrate

A plate with a mine cell on the center of it.

### Substrate Settings

* Maximum cell count: 1000
* Petri dish diameter: 1.0 mm
* Substrate viscosity: 60.000
* Dynamic friction: 0.000
* Static friction: 0.000
* Salinity: 0.800
* Light amount: 2
* Light range: 2
Foreign species

Foreign species are terms of species that cannot be built, or impossible to build in the genome editor. A foreign species example is a Stone Coral, that used glueocytes as its structure and used virocytes to infect it to the body. The Basic Tree was also a foreign species.

Foreign species could not hybridize.
Cell tag

**Cell tags** are used for categorizing cells on the substrate. They can be seen through the cell diagnostics tool. A cell can only have one tag.

## List of cell tags

* **User cell**: Used for cells placed by the player.
* **Challenge cell**: Used for cells that are part of a challenge substrate. When a challenge substrate is opened in the experimental lab, all challenge cells become user cells.
* **Contamination cell**: Cells from contamination option.
* **Hybrid cell**: Used for cells that result from Gamete reproduction between user cells and challenge cells, or when at least one of the Gametes is a hybrid cell.
* **Infected user cell**: Used for user cells that was infected by a Virocyte.
* **Infected challenge cell**: Used for challenge cells that was infected by a Virocyte.
* **Infected contamination cell**: Used for contamination cells that was infected by a Virocyte.
.substrate file

Substrate data is stored in **.substrate files**.

## Format

The first four bytes are `AC ED 00 05`, which indicates the start of a Java stream format. Then, the next 2 bytes are `77 XX`, where `77` indicates that it is the beginning of a data block and, and `XX` indicates the block's length. Following that is the substrate version, the most recent of which is 95 (`00 00 00 5f`), in which the data follows as such:

**Substrate info:**

* **4 bytes (int)** - Substrate version (95)
* **8 bytes (double)** - Substrate age
* **4 bytes (int)** - Cell count
* **Environment info:**
	+ **4 bytes (int)** - Environment version (95)
	+ **8 bytes (double)** - Nutrient rate
	+ **8 bytes (double)** - Nutrient chunk size
	+ **8 bytes (double)** - Radiation level
	+ **8 bytes (double)** - Light amount
	+ **8 bytes (double)** - Light direction change
	+ **8 bytes (double)** - Light range
	+ **8 bytes (double)** - Substrate viscosity
	+ **4 bytes (int)** - Number of cell types (18)
	+ **1 byte each (booleans)** - Whether the gene pool contains (in order): phagocytes, flagellocytes, photocytes, devorocytes, lipocytes, keratinocytes, buoyocytes, glueocytes, virocytes, nitrocytes, stereocytes, senseocytes, myocytes, neurocytes, secrocytes, stemocytes, gametes, ciliocytes
	+ **1 byte (boolean)** - Contaminate with random cells
	+ **8 bytes (double)** - Gravity
	+ **8 bytes (double)** - Density
	+ **8 bytes (double)** - Density gradient
	+ **1 byte (boolean)** - Kill cells at edge
	+ **8 bytes (double)** - Nitrate amount
	+ **4 bytes (int)** - Max cell count
	+ **4 bytes (int)** - Max food count
	+ **8 bytes (double)** - Substrate diameter
	+ **8 bytes (double)** - Dynamic friction
	+ **8 bytes (double)** - Static friction
	+ **1 byte (boolean)** - Only point mutations
	+ **4 bytes (float)** - Salinity
	+ **1 byte (boolean)** - Cell aging
	+ **8 bytes (double)** - Nutrient lumpiness
	+ **8 bytes (double)** - Nutrient lump size
	+ **1 byte (boolean)** - Mobile food
	+ **4 bytes (float)** - Nutrient coating

This data is then followed by GZip compressed data which contains information about cells (which includes information about their genome stored in the same format as genome files) and nutrients present on the substrate.

## External links

* https://github.com/Davido101/substrate.py/blob/main/substrate.py - a genome reader made by Labyrinth.
* https://docs.oracle.com/javase/8/docs/platform/serialization/spec/protocol.html
49: Nervous

**49: Nervous** is the fourtyninth level of the game.

## Description

"Our field biologists have found a tiny organism that exhhibits a defence behaviour when subject to a certain stimulus. Can you figure out what the stimulus is?"

### Substrate Settings

* Maximum cell count: 1000
* Petri dish diameter: 1.0 mm
* Substrate viscosity: 0.000
* Dynamic friction: 0.000
* Static friction: 0.000
* Salinity: 0.3
* Light amount: 0.6
* Light range: 1

## Solution

Incubate first.

Set the blue color and green into 0, while the red color is max.

Then press the center hole. If there are pink colors splitting, it means you win.

## Trivia

* This is a very simple level containing colors.
44: Paleogenetics

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Reason: The description.

**44: Paleogenetics** is the fourtyfourth level of the game.

## Description

This ancient green organism was found living in an acidic lake. Archaeologists have the same lake found microscopic fossils of a-now-extinct-predator species thought to once live off these green creatures. To corrorborate this theory we would like to see if there are some traces of their interaction left in the genome of the green species. To test our theory we have placed a synthetic predator species on this substrate to see if some protective mechanism can be awoken from the depths of the green swimmers genome. That didn't happen.

Upon inspection of the genome we have found that a recent mutation has taken a shortcut, the M3 cells no longer split to M5,M6 but it splits to M3,M4. Perhaps this mutation proliferated as a result of the extinction of the predator. Anyway, can you-without inserting a keratinocyte-restore the old behavior and see what the species do in this synthetic environment?

If you get 400 cells without actually in-troducing a keratinocyte then we have comfirmed that this species has genes to protect itself from predator? and thus the fossil predators were most likely once living off of this organism.

## Substrate

Three devorocyte lakes and a bunch of gamete swimmers.

### Substrate Settings

* Maximum cell count: 1000
* Petri dish diameter: 1.0 mm
* Substrate viscosity: 30
* Dynamic friction: 0.000
* Static friction: 0.000
* Salinity: 0.300
* Light amount: 1.000
* Light range: 1.000

## Solution

In Paleogenetics, you need to get the green organisms to get better protection from the devorocytes. You may wonder how we do this because there isn't any visible way they could get protection other than huge numbers. How do we do this? We need to load their genome from the plate and change some splitting values. What it does is that it causes the other organism's keratinocytes to appear again in some way that not even I understand. Now I'll explain how to design it. First, select one of the green initial cells and then load it from the microscope into the genome tab. Then go to M3 and change it's children modes to M5 and M6. Make sure you do that step or else it wont work. Now all you need to do is change the cell's color to something not green to make it easier to tell which ones have the genes you want (you don't have to do that) and then insert! After a while, what should've happened was that most of the surviving cells are the ones that have either blue cells or keratinocytes and that you completed the challenge!
Challenge Solutions/44: Paleogenetics

This page contains player-made solutions of 44: Paleogenetics.

## PotatoDoesCode's solution

   In Paleogenetics, you need to get the green organisms to get better protection from the devorocytes. You may wonder how we do this because there isn't any visible way they could get protection other than huge numbers. How do we do this? We need to load their genome from the plate and change some splitting values. What it does is that it causes the other organism's keratinocytes to appear again in some way that not even I understand. Now I'll explain how to design it. First, select one of the green initial cells and then load it from the microscope into the genome tab. Then go to M3 and change it's children modes to M5 and M6. Make sure you do that step or else it wont work. Now all you need to do is change the cell's color to something not green to make it easier to tell which ones have the genes you want (you don't have to do that) and then insert! After a while, what should've happened was that most of the surviving cells are the ones that have either blue cells or keratinocytes and that you completed the challenge!
Crossbow Ant

A Queen Crossbow ant wandering for food.

## Description

Crossbow ants are big swimming insects that push algae with their noses. Crossbow ants are green and dark green with light green coloration, and they are both fast. The Crossbow ant gets its name from its crossbow-shaped snout. Because the Crossbow ant's crossbow noses are friendly, they do not pierce but rather push through cells. They collect food, so they are not nutrientovores because they only eat one type of food. The Queen ant and the Worker ant are the two types of Crossbow Ants. These forms work together to scavenge for resources. They do not work with each other, but they reproduce each other. They help push the algae to the position they want to. They do not have stingers. It's Crossbow part are long.

## Functions

### The Queen

The queen is a seven-celled species with four flagellocytes that is extremely rapid. It has a long-crossbow nose that enables it to collect a large amount of food. Because of the strong adhesin connection between the noses, the Crossbow nose also helps the queen to push algae. It has eggs that hatch Worker Crossbow ants, but the queen doesn't do anything other than collect food. They are not nutrientovores because they simply gather nutrients. They are larger than the majority of worker ants.

### The Worker

Worker ants are the Queen's daughters who scavenge for food. They are slightly slower than Queen ants due to their weight. Unfortunately, worker crossbow ants do not hatch queens. Workers are swift species with a nose that might also force other cells away. Queens and Workers are nearly identical, thus they should have the same structure. The only difference is that it has two flagellocytes rather than four. They may kind of support their queens and collect food. Workers also work hard to push any object it appears in its eyes.

## Gallery

A mysterious Algae they exploredA Crossbow Ant worker wandering around towards foodA Crossbow Ant queen reproducing Crossbow WorkersA Crossbow ant Habitat.The “mysterious algae” they lately wandered on.A queen and a worker.
Doryfish

Two doryfishes scavenging for nutrients

## Description

Doryfish (Blue tang) is a nutrientovorous smart swimmer fish that lives in petri dishes with little nutrients. The Doryfish, The Bobbit Worm and the Coral was made by Noirmancer Steeletto in a substrate named Bobbit Worm Aquarium.

Doryfish have Lipocyte eggs that only hatch when it is given enough nutrients from the parent. They are based off regal blue tangs, which live in coral reefs and in the open ocean. They get their name from their similar resemblance to Dory and Blue Tangs from a very famous movie.

Doryfish are composed of 12 Cells. They have yellow tails, blue bodies and black heads. They have 3 Flagellocytes, 3 Buoyocytes, 2 Stereocytes & 1 Senseocyte, 1 Neurocyte, 1 Myocyte and 1 Phagocyte.

## Preference

For a Doryfish to survive, their habitat must be:

1. Low nutrients or more
2. No mobile food
3. No light sources
4. Gravity and Density must be enabled.

Also, a Doryfish can coexist with other species, including predators and other swimmers that feed on the nutrients on the petri-dish.

## Stages of Life

A Doryfish starts life as a blue lipocyte egg. It has to be fed to be able to hatch into an adult.

1. Stage 1: The egg splits into two white lipocytes which split again to form two more blue stemocytes.
2. Stage 2: The embryo splits and there is a black lipocyte, a glueocyte, three blue stemocytes and a yellow nitrocyte.
3. Stage 3: The child splits again, the head, the body and the tail start forming. Then, the fish finally reaches its final form.
4. Stage 4: The fully-grown adult then finally grows two flagellocytes on its sides, to help with navigation towards food.
5. Stage 5: Another blue egg is attached to the body of the adult fish and then the life process starts all over again.

## Trivia

* This fish has three flagellocytes, two blue ones act as fins and a yellow one acts as a tail.
* It can sense food and predators, making it very smart and it can also sense walls and avoid them.
* It is based of Dory, the fun-loving and forgetful fish, from Finding Nemo & Finding Dory.

## Gallery

Two DoryfishesDoryfish EmbryoDoryfish Egg
60: Extermination

**60: Extermination** is the sixtyth level of the game.

## Description

*"Some mine-laying organism is living on this plate. Can you give them a taste of their own medicine and leave the plate clean afterwards?"*

### Substrate Settings

* Maximum cell count: 800
* Petri dish diameter: 1.0 mm
* Substrate viscosity: 6.000
* Nutrient rate: 10.000
* Nutrient chunk size: 0.300
* Salinity: 0.100

## Trivia

* This is the first level to use the mine species.

 Other
29: Floaters III

**29: Floaters III** is the twenty-ninth level of the game.

## Description

*"Can you figure out what substrate this is and get 450 cells to live on it?"*

## Solution

Floaters III is like Floaters II, except with no nitrates and some density gradient. Here, we can basically use the Floaters II solution to solve this challenge, obviously making sure to add nitrocytes in the genome. Before you follow along, I recommend you read the Floaters II solution so you can then edit onto it. Now, let's start designing! First, make M1's child 2 be M7 instead of M3. Have M3 be an nitrocyte with a split angle of 90 degrees. Make it's child 1 M3 and it's child 2 M8. M3 is the bouyocyte so we won't need to worry about it, but M8 should be a nitrocyte that can't split. Next, make sure M4's (the other form) child 2 be M9. Have M9 be a nitrocyte once again and make it split into M10 and M6 making sure to also set its split angle to 90 degrees. Make sure M10 is a nitrocyte that can't split. Finally, insert M1 into the plate! You should see that your genome is capable of reproducing even with the extremly low substrate nitrates. Incubate for some time, and what should happen is that the petri dish is now populated, and you completed the challenge!
Milipede

For the shorter and bigger counterpart, see Centipede.

## Description

The ***milipede*** is an organism engineered by Bwisialo, with contributions from Alast. It is a long, photosynthetic nematode that uses "feet" to crawl along the surface of the plate. It has a lipocyte as it's head. The ***millipede*** can evolve using light.

## Distribution

It lives in environments with light at its maximum, a low viscosity level, high salinity, and with dynamic friction.

## Cell stats

### Health

Each segments has 4 cells. The head has 1 lipocyte.
Keratinosecrcyte

In order to classify cells, go **here**.

It's name is very CONFUSING. But what it makes it like that?

It is this: Keratinocyte + secrocyte.

It is a type of cell thing, and it grows secrocytes to move. Also, it uses it's secrocytes to sslow down predators, and they are very small. When they have

more of this, they will dig. It takes about 60 hours to tak

## Cell stats

### Defence

22

e to dig, because of the big size. The more it has, the more i big.

Predators will stay here for a long time because it generates infinite amoun of secrocytes, and powered by light.

photo is overpopulated.

Crazed version here
Challenge Solutions/25: Mosh pit

This page contains player-made solutions of 25: Mosh pit.

## Devorocyte 89's solution

This only consists of 2 modes.

Let M1 phagocyte split into M2 ciliocyte and M3 phagocyte with adhesin on. Child 2 angle is 45 degrees. M2 won't split, and M2 has left movement speed and right movement speed max. M3 splits M3 phagocyte and M1 phagocyte. Now place it on the substrate. It should slowly reproduce to 300 cells.
Challenge Solutions/Scarce Conditions I, II, and III

In all Scarce Conditions challenges, there is food scattered sparsely around the plate, making it impossible for normal organisms to survive. How do we solve these? The key to all three is to use stereocytes. If we make the different stereocyte signals trigger different flagellocytes, then we can get an organism go to where food is on its own. Let's see how we make the genome. First, set M1 to be a lipocyte at slightly lower than default split mass. Have it split into M2 and M3 with maximum adhesin stiffness. Next, set both M2 and M3 to be lipocytes with a split angle of 90 degrees, minimum split mass, and maximum adhesin stiffness. For M2, make its child 1 angle 315 degrees and child 2 angle 300 degrees. Then for M3, set its child 1 angle to 330 degrees and child 2 angle to 315 degrees. Make M2 split into M4 and M5, and also make M3 split into M6 and M7. For now prevent M4, M5, M6, and M7 from splitting to make it easier to work with. Keep M7 as a phagocyte but have M6 be a flagellocyte. Also have M4 be a stereocyte and M5 be a flagellocyte. Now let's tune the stereocyte settings. Set it's sense to food and have an output around 20.00. It doesn't matter the signal type as long as the flagellocytes can use it. Next, set the right flagellocyte's "a" value to around 0.76 and a "b" value a little bit greater than 0. Do the same thing for the left flagellocyte but with a negated "a" value around -0.76. If you're trying to solve Scarce Conditions III, I recommend you reduce the nutrient priority of the flagellocytes by a little bit. Now we can get to reproduction. Set the stereocyte's split mass to what you think is around default and have it's child 1 be M1. Make sure to set the stereocyte's max connections to 3 to prevent making new M1 cells while there is already one connected to it. Again, if you're trying to solve Scarce Conditions III, I recommend cranking the nutrient priority by a little. Finally, we can insert M1 into the substrate! But before we do that, make sure M1's children don't keep adhesin otherwise the any M1 that splits while connected to your organism will wind up developing while still being connected. After you do that quick change, insert M1 into the plate! After a little while, what should've happened was that there was a lot of surviving cells on the plate, and you completed the challenge!
Immune flagellate

**Immune flagellates** are any flagellates in the class **Immunoflagellia**. The main characteristic that distinguish from the other flagellates is they're consisting of Keratinocyte, a cell that can protect another cells.

The immune flagellates evolved from normal flagellate to protect themselves from the predators or dangerous cells like Virocytes or Devorocytes.

The class have only two species, *Phagomunia saterskogis* and *Photomunia saterskogis*

## Classification

**Order Immunoflagellia**

* Family Phagoimmunae
	+ Genus Phagomunia
		- *Phagomunia saterskogis*
* Family Photoimmunae
	+ Genus Photomunia
		- *Photomunia saterskogis*
About (tab)

The about page in cell lab.

Version 103

Game created by Petter Säterskog.

Challenges designed by Alast, bwisialo, Nayus and Petter.

In case you get stuck:

Forum Wiki Youtube

Cell Lab is provided as a completly free app. There are no payments for features and no ads. If you would like to show your appreciation to the developer, consider donaring an amount of your choice below. A combination of buttons can be used.

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15: Macrophages V

**15: Macrophages V** is the fiftheenth level of the game.

## Description

*Cells now die when they reach the edge of the substrate. Can you make a species maintaining a cell count above 150 for 100 h?*

## Substrate

* Same as the "Macrophages III".
* Cell will die when reach the edge.

## Solution

 Other

* →
* Hint

Click a Tab to reveal the Hint.

Having trouble solving some of the challenges and need some inspiration? Let evolution do the job for you! Go to the "Experiment" tab of the main menu and choose "New plate". Try to make an environment similar to the environment of the Macrophages III challenge and put the solution you had for that exercise in it (you can save and load genomes in the genome editor).

Now start the simulation and you should have some cells multiplying in the environment. Then check "Kill cells at edge" and the number of cells should start declining. If you now increase the radiation level from 0 to slightly above 0 the cells will start mutating and soon you will have morecells than you started with since they have adapted to their environment. Hopefully you will be able to see a way to solve this exercise from studying their behavior!
34: Infection

**34: Infection** is the thirty-fourth level of the game.

## Description

"The Virocyte is a cell infected with a virus. If aanother cell touches this cell it risks also getting infected. This is very much how a virus works in nature. Which part of the genome gets copied is specified by the "Virus copy from" property in the genome editor. Note that not only the genes for one mode are copied but also the genes for the modes of 2 generations of descendants. So a maximum of 1+2+4 modes of the host genome are copied to the newly infected cell. In this challenge you are supposed to kill all inital cells by infecting them with a virus and leave the substrate clean."

### Substrate Settings

* Maximum cell count: 8000
* Petri dish diameter: 1.0 mm
* Substrate viscosity: 0.000
* Dynamic friction: 0.000
* Static friction: 0.000
* Salinity: 0.3
* Light amount: 0.6
* Light range: 0.2

## Solution

* →
* Hint

Click a Tab to reveal the Hint.

Tap on a cell under the microscope and press "Load" in the Genome editor and select "Load from microscope" to inspect the organisms living on this substrate before designing a virus.

## Trivia

* This is the first level featuring the virocyte.
Cyanide control system

A Cyanide Control System is a cell that drains cyanide from cells around it. Creating one is quite simple:

1. Choose a cell that you want to be your cyanide control system.

2. Set Split Angle so that it does not shift when it splits.

3. Set Split Ratio so that one of the daughter cells dies instantly.

4. Make sure that Keep Adhesins is on.

5. Set Split mass to minimum.

If your cell detaches from the organism, either change the split angle or reverse the Split Ratio.
Functions

The cell types can be classified into 4 different classifications depending on their functions:

**Nutrition Cells** **Neuron Cells** **Aggressive Cells** **Movement Cells**

Neuron Cells are called Signal senders.

Aggresive cells are called Energy stealers.

Movement cells are called Movers

Nutrition cells are called Food eater
Gun

A gun is a organism that I created (I'm not the owner of the game), I dont know how I made it.

In order to classify cells, go here.

## How It Works

It consists of a Flagellocyte and a Phagocyte, the Phagocyte makes a child which then becomes a Flagellocyte and swims forward like the bullet, then the Phagocyte makes another child like the gun is reloading and the cycle starts again.

## Trivia

* It can place "Traps" (which are just normal phagocytes multiplying, it looks like it places them but in reality it is the traps mutating)
Lipase

This is a stub or is otherwise incomplete, you can help by making it bigger. You can edit this page here.

Lipase is a type of chemical along with the other chemical: HCN (also known as Hydrogen Cyanide). However, it is not a type of toxin. It is a type of chemical that does injury damage to cells if exposed for too long. It can turn coated nutrient pieces into normal nutrient pieces. It is the head of 40: Digestion. It can be emitted by the Secrocyte.
Cell cycle/Cycles

FL - Flaggelocyte

ST - Sterocyte

NI - Nitrocyte

SN - Sensocyte

LP - Lipocyte

GM - Gamete

MY - Myocyte

NE - neurocyte

BU - Buyocyte

DV - Devorocyte

PT - Photocyte

KT - Keratinocyte

Life cycle loop: yes

### Immune flagellate

M1 PG > M2 FL M3 PG > M3 PG (CHILD ANGLE 2 45) > M4 KT (CELL WONT SPLIT) M5 PG > M5 PG M1 PG

Life cycle loop: yes
Lizard

## Description

### Information

**Common Pickle Lizard (Muries ascalabotes)** is a species of microscopic lizard in the family Microstilidae. They are tiny lizards with dark green colour, short bodies and long tails. They usually filter feed and don't prey on other species. Although these species are capable of surviving attacks from predators, they can be wiped out and become extinct by an invasive species of **Pinktail, also known as Pinkensis invadis**. These species of Pinktail are capable of wiping out any competition they have by overwhelming their competitors with immense numbers, which keeps the competitors from eating, which will result in the enemy dying. For the Pickle Lizards, these Pinktails are dangerous and can cause serious damage to the ecosystem. Pickle Lizards prefer not to live alongside competitors as they will eat up every nutrient on the substrate. One way that Pickle Lizards can counter these invasions is by spraying secrocytes with Food Smell. This way, they can trick the invaders, but it also comes at the cost of them also being tricked by their own defense protocols, making them look stupid. Once a Pickle Lizard reaches adulthood, they start mass reproduction and this causes their population to explode after 700 h of playtime. Because their tails are long and heavier, their legs have to be faster, which comes at the cost of energy, but getting energy is super easy and it doesn't effect the whole organism itself. Pickle Lizards are fairly fast but they aren't the fastest animal. Predators that are lighter and can speed-boost could easily outrun Pickle Lizards. Most of the time, these reptiles spend their lives trying to find food and reproducing.

### Anatomy

Pickle Lizards have 4 Flagellocytes, 3 Phagocytes, 3 Ciliocytes, 2 Photocytes, 1 Stereocyte & 1 Lipocyte.

### Regeneration

Pickle Lizards have a unique ability, Regeneration. Pickle Lizards are capable of regenerating limbs, including their tails. If their tails are cut off from the body, it will regenerate completely, so they can withstand any injury. If the part that regenerates their body is destroyed, they cannot regrow their limbs, which could have fatal consequences.

## Trivia

* Pickle Lizards reproduce without a mate.
* Pickle Lizards are fast creatures
* The Genus, Muries, has several species, including Muries ascalabotes & **Muries scalpturio, the Clawed Pickle Lizard**

## Dropbox

https://www.dropbox.com/s/igqq5vondcl8hpz/Reptile%20Lizard%20Substrate.substrate?dl=0
32: Symbiosis

**32: Symbiosis** is the thirtysecond level of the game.

## Description

"Most plants in the legume family live in the legume family live in symbiosis with nitrogen fixating bacteria called rhizobia living in their root systems. The bacteria provides nitrogen to the plants while the plants provide nutrients to the bacteria. On this substrate we have a couple of very tiny plants of the legume family. Unfortunately their rhizobia was killed by a virus and the plants as a result have stopped growing due to lack of nitrogen. Can you design some new organisms to take the role of the rhizobia?"

### Substrate Settings

* Maximum cell count: 1000
* Petri dish diameter: 1.0 mm
* Substrate viscosity: 30.000
* Dynamic friction: 0.000
* Static friction: 0.000
* Salinity: 0.6
* Light amount: 2.000
* Light range: 2.000

## Solution

M1 phagocyte - make adhesin, child 1 M2 flagellocyte and child 2 M3 gluocyte placed between the columns closer to the one on the right

M2 flagellocyte - increase split mass so it doesn't split

M3 gluocyte - child 1 doesn't keep adhesin, M3 gluocyte splits into M4 phagocyte and M5 nitrocyte

M4 phagocyte - increase nutrient priority to 3,16, makes adhesin child 1 M6 gluocyte and child 2 M2 flagellocyte, both child 1 and 2 angles set to 180 degrees, child 2 doesn't keep adhesin

M5 nitrocyte

M6 gluocyte - makes adhesin, splits into child 1 M5 nitrocyte and M4 phagocyte

## Trivia

* A level with a story.

 Other
52: Scarce Conditions II

**52: Scarce Conditions II** is the fifytytwoth level of the game.

## Description

"Can you make a species survive here without using the Myocyte?"

Same plate.

## Solution

In all Scarce Conditions challenges, there is food scattered sparsely around the plate, making it impossible for normal organisms to survive. How do we solve these? The key to all three is to use stereocytes. If we make the different stereocyte signals trigger different flagellocytes, then we can get an organism go to where food is on its own. Let's see how we make the genome. First, set M1 to be a lipocyte at slightly lower than default split mass. Have it split into M2 and M3 with maximum adhesin stiffness. Next, set both M2 and M3 to be lipocytes with a split angle of 90 degrees, minimum split mass, and maximum adhesin stiffness. For M2, make its child 1 angle 315 degrees and child 2 angle 300 degrees. Then for M3, set its child 1 angle to 330 degrees and child 2 angle to 315 degrees. Make M2 split into M4 and M5, and also make M3 split into M6 and M7. For now prevent M4, M5, M6, and M7 from splitting to make it easier to work with. Keep M7 as a phagocyte but have M6 be a flagellocyte. Also have M4 be a stereocyte and M5 be a flagellocyte. Now let's tune the stereocyte settings. Set it's sense to food and have an output around 20.00. It doesn't matter the signal type as long as the flagellocytes can use it. Next, set the right flagellocyte's "a" value to around 0.76 and a "b" value a little bit greater than 0. Do the same thing for the left flagellocyte but with a negated "a" value around -0.76. If you're trying to solve Scarce Conditions III, I recommend you reduce the nutrient priority of the flagellocytes by a little bit. Now we can get to reproduction. Set the stereocyte's split mass to what you think is around default and have it's child 1 be M1. Make sure to set the stereocyte's max connections to 3 to prevent making new M1 cells while there is already one connected to it. Again, if you're trying to solve Scarce Conditions III, I recommend cranking the nutrient priority by a little. Finally, we can insert M1 into the substrate! But before we do that, make sure M1's children don't keep adhesin otherwise the any M1 that splits while connected to your organism will wind up developing while still being connected. After you do that quick change, insert M1 into the plate! After a little while, what should've happened was that there was a lot of surviving cells on the plate, and you completed the challenge!

## Trivia

First level featuring the stereocyte.
66: Desert II

**66: Desert** is the sixtysixth level of the game, and the very last level.

## Description

"Same plate but now 600 cells.""

Same plate.

## Solution

In Desert, the substrate is very dry and food is sparsely populated. Desert II is the same challenge but with a higher goal. Sounds difficult, right? It's not as difficult as you may think it is. Let's look at how we design the genome. First, set M1 to be a lipocyte at default split mass with maximum adhesin stiffness and set child 1 to M2 and child 2 to be M3. Next, set both children of M1 to be a lipocyte at minimum split mass and max adhesin stiffness. Only this time, set M3's split angle to 90 degrees. Now, set M2's children to be M4 and M5 as well as M3's to be M6 and M7. Set M4 to be a neurocyte set the oscillator preset settings to: 2 adhesin connections, channel 1 to 2, and period 1.75 h. Next, set M5's split angle to 90 degrees and make it a lipocyte with minimum split mass. Have it split into M9 and M9. Now, set M9 to be a myocyte that receives S1 and makes negative contractions as well as receiving S2 for positive lift. Then prevent M7 from splitting and keep it as a phagocyte while M6 should be a lipocyte again with minimum split mass and maximum adhesin stiffness. Have M6 split into M7 and M8 with the child 2 angle (M8 is child 2) at 270 degrees so it make another phagocyte and a new lipocyte facing forward with the same settings we repeated. Now have M8 split into M10 and M7. Make sure that child 1 is M10 and not M7! Make M10 a glueocyte with the same lipocyte settings (except for the adhesin.) Set its split angle to 30 degrees, split ratio to 90/10, and child 1 angle to 330 degrees. Have child 1 be M11 as a stereocyte. This is how it will survive better. Make sure M11 doesn't split first. Now, set M11 to sense food with a not-to-high output and have the output signal be S3 to prevent it interfering with the myocyte's contracting and lifting. Select M9 (the myocytes) and set the input to S3 with the A value to something a little higher than 1.00. Finally, have M4's (the neurocyte) child 1 be M1 with maybe child 1 angle being 90 degrees. For more efficiency, check the "Mirror" checkbox for child 2. Before you insert, make sure for M1 that both of its children don't keep adhesin. Now, insert M1 into the plate! If you put the temperature on Incubate, you should see your genome surviving! After a while, what should've happened that the plate as many cells in it and you completed the challenge!
Chlorous booster

The **Chlorous booster** is a 3-cell organism, its 2x as fast as a normal flagellate due to it having 2 Flagellocytes.

In order to classify cells, go here.

It can divide into 3 cells, and lives in nutrients 1.5x lower than a normal flagellate.

## Tutorial

Make m1 split to m2 and m3. Make m3 split to m1 and m3. Make m2 split to m4 and m4. Make m4 not able to split and is a flagellocyte. If it dies because the tail is obstructed/blocked off then alter in m1's m2`s child angles and make it to look like this. Then last of all. Give it any color (you don't have to do this) , and put it in the petri dish.
Gilled Snake

## Description

Gilled Snakes are slithering Paleobranchians which have evolved to live in environments totally lacking of nitrates  Like Sirens, it adds body segments to its own. They really aren't neotenic and it seems to be green. Gilled Snakes have even highers cells, with over 68 cells. A newborn gilled snake is a non-segmented Gilled Snake. Gilled snakes get their name from their length and the presence of nitrocytes. It cannot reproduce, but it can add body segments to it's own. Gilled snakes as well as Gilled swimmers are related.

## Hybrids

Gilled Snakes could make hybrids with gilled swimmers. However, they could add body segments. Gilled Snakes also could make hybrids, but they are conjoined. Gilled snakes with cotton swimmers are the hardest to make hybrids with all these paleobranchians. However, hybrids between fox-eared salamanders are possible but not smart. All of these hybrids except for the Fox-Eared Salamander would add body segments.

## Download

https://www.dropbox.com/s/rmgajr4i6fwsihm/gilled%20snake.substrate?dl=0
Cyanide

**Cyanide**, currently known in-game as **HCN** (short for **Hydrogen cyanide**), is a poisonous chemical from Secrocytes. It kills cells over time if exposed for too long. Cells in direct contact to a cyanide Secrocyte will turn red and die quickly. However, since cell injury causes cells to turn green, the end result is that cells poisoned with cyanide will commonly turn yellow or orange. Like other substances, (nutrients, signal substances, etc.) cyanide will diffuse through adhesins when a cell splits. Like nitrate, it is equally distributed to daughter cells no matter what the split ratio is. This allows for simple cyanide control systems. Besides killing them, cyanide does not appear to have any other effect on cells. Keratinocytes protect cells in direct contact from cyanide only if the cells that need protection are connected to Keratinocytes. Cyanide can kill Keratinocytes if there at least one Secrocyte connected to the cell that connects to Keratinocyte.
Lipocyte Eggs

Lipocyte eggs are eggs that are produced from species.

The species will lay an egg and the lipocyte egg will hatch.

It has many colors like white, red or more.

Usually, species are connected to the eggs, not just drop them.

For protected species, the egg is vunerable to cyanide, devorocytes, lipase and protease.

Egg could hatch and get detached from the cell that made the egg. Almost all eggs have "keep adhesin" checkbox off and adhesin stiffnesss max. Some eggs are not vunerable to devorocyte attacks, while almost can.
24: Sterilization

**24: Sterilization** is the twentyfourth level of the game.

## Description

"You need to kill all cells on this substrate but lost your bottle of sterilizer, you have to think of something else."

### Substrate Settings

* Maximum cell count: 800
* Petri dish diameter: 1.0 mm
* Substrate viscosity: 30.000
* Dynamic friction: 0.000
* Static friction: 0.000
* Salinity: 1
* Light amount: 1.5
* Light range: 0.4
Clubbedfish

## Description

### Defence

It's flagellocytes are the ones only not protected, while the front and tail are protected.

**Clubbedfish** are smart swimmers that feed on sunlight as a baby and when they grow into an adult, they feed on food particles. They live in nutrient-rich petri-dishes. They are related to Smell Spike Swimmers.

These smart swimmers have Lipocyte eggs and will hatch once it receives enough nutrients from the parent. If the lipocyte egg is detached from the parent before it can even hatch, then it will slowly lose nutrients and die. Once the egg has enough nutrients to grow into an adult, it splits itself from the parent and regrows into another adult.

They are called Clubbedfish because their tail has a devorocyte as a spike club to fend off against enemies. Like armoured animals, most of their cells are attached to the middle, which protects the cell from being eaten. It does have weak spots though. They are vulnerable to attacks at the flagellocytes, since they aren't connected to a keratinocyte.

## Preference

For a Clubbedfish to survive, their habitat should be:

1. High nutrients
2. Have a few to no cells.
3. No mobile food
4. No predators
5. No rivals such as other species that feed on food particles.

The Clubbedfish is fairly smart and can detect food but it doesn't run from walls and it can't run away from predators, since the only thing it can sense of food.

## Stages of Life

It begins life as a reddish-brown lipocyte egg.

1. The egg splits into a green and pink photocyte. The pink is the body and the green is the tail.
2. It becomes twice the length and the tail is two cells long, so is the body.
3. The swimmer is now 7 cells. The tail has fully-grown, the body has grown the left swimmer and the head has begun forming.
4. The swimmer is now 9 cells and is a fully-grown adult. The tail is complete, the body is completed and has grown the right swimmer and the middle part of the body is a stereocyte, which will now enable the smart swimmer to be able to sense food and track it. The head is completed and it is ready to start creating a new egg for the next generation, as you can see from the picture.
5. The swimmer has grown an egg that is attached to its head, meaning it is now 10 cells in total.

## Trivia

* It is a smart swimmer and can only sense food
* It was based of an Ankylosaurus.
* This fish resembles the extinct group of fish, known as Placoderms, which had included giants such as Dunkleosteus (or Browurag), Titanichthys and Arthrodira.

A Clubbedfish.A Clubbedfish egg.
9: Macrophages III

**9: Macrophages III** is the ninth level of the game and the third level that uses the *Macrophages* title.

## Description

*We are going to try to use your new cell, the Flagellocyte, for this challenge. This cell can not gain energy from the enviroment, but it can swim! Note that this cell immediately dies if attached to another cell such that the flagellum is obstructed.*

*The viscosity of this substrate is higher than in the previous "Macrophages" challenge. Can you nevertheless make a species multiply to 420 cells?*

## Substrate

* Higher viscosity than in the previous "Macrophages" challenge.
* No light

## Solution

* →
* Hint
* Spoiler

Click a Tab to reveal the Hint.

To solve this challenge, you will need your organism's life cycle to include three different modes.

Ticking "Contaminate with random cells" in experimental mode and running for a little while might give you some ideas on how to solve this challenge.

Have mode 1 split to mode 2 and 3
Have mode 3 split to 3 and 1
Let mode 1 and 3 be Phagocytes and mode 2 Flagellocyte
Tick "Make Adhesin" for mode 1

Note that this is one among many different ways to solve this challenge.

## Trivia

* It is the first level to featuring Flagellocyte.

 Other