Comprehensive Destruction

Comprehensive Destruction is a way of measuring the volume of how precise and concentrated an attack is and equates to how much energy equivalence there is to destroy something. Here is the methods of destruction in order from least to most destructive:

The example values uses here is for regular Rock:

* **Minor Fragmentation** = 8 j/cm³ (usually an object that is just cracked, or snaps in two or three but not very small pieces relatively or remains together)
* **Fragmentation** = 69 j/cm³ (usually as an object that breaks apart as large/medium identifiable pieces, breaking down to more than few)
* **Violent Fragmentation** = 120 j/cm³ (usually when an object breaks up into smaller but distinguishable pieces such as hand size at least)
* **Pulverization** = 214.35 j/cm³ (usually when an object is reduced to powder or pure dust, small particulates of matter (*In extremely rare cases, it can have some insignificant debris so long as it does not fill the entire volume*), where dust usually falls if there is no wind to pick it up)
* **Liquefaction** = 2000 j/kg/°C (usually when an object (solid usually) is melted or turned to a liquid substance)
* **Vaporization** = 25700 j/cm³ (usually when an object is reduced to a gaseous substance or shows visible vapor (*In extremely rare cases, it can have some insignificant debris so long as it does not fill the entire volume*) unlike dust which as a gaseous state (*vapor, steam, smoke, etc.*) which rises, likely destruction down to molecules at high end)
* **Atomization** = 30852.2 j/cc (Only used when either stated or visibly proven that it is none of the above without atoms, usually when nothing remains besides particles)
* **Sub-Atomization** = 5.403E13 (j/cc) (Only used when either stated or visibly proven that it is none of the above, without particles usually when nothing truly remains)

We don't apply this to Destruction power as it is just a power to have certain types of effects, unless it can be applied to calculable feats.

Here is a lists of other values for destruction of other materials, and another with more with MPa or psi.

## Notes

For some cases in the Destruction Values of Fragmentation to Pulverization, we sometimes use Shearing Strength and Compression Strength of materials to determine the amount of Joules per cubic centimeters. where as Shearing strength is the material's ability to be cut without breaking, and compression strength is the material's ability to be compressed without breaking (here is a link for such values with MPa (Megapascals)).

* 1 MPa = 1 J/cc = 1\*10^6 N/m^2

When trying to find the exact values, they can be related to different terms when looking at MPa values:

* Fragmentation = Shear Strength
* Violent Fragmentation = High-End Shear Strength or below Compressive Strength
* Pulverization = usually High-End Compressive Strength
* Vaporization = using Enthalpy of Vaporization of materials
	1. Usually to find the J/cc value, you would need to find the boiling point (Celsius) of the material, the Heat of Fusion (Joules/mol), the Heat of Vaporization (Joules/mol) and the Molar Heat Capacity (J/(mol\*C))
	2. Then you need to find Molar Mass of the material (g/mol), then you need to convert the later three values to (*Joules/grams*) & (*Joules/grams\*Celcius*).
	3. Then using the Specific Heat Equation, we do (*mass of material g*)(*Molar Heat Capacity J/grams\*C*)(*Boiling point Celcius - temperature of area Celcius*) = *Joules.*
	4. Then using the Latent Heat Equation, we find the (*Heat of Fusion J/g*)(*mass of material g*) + (*heat of vaporization J/g*)(*mass of material g*) = Joules
	5. Add both Specific Heat Energy (#3) and Latent Heat Energy (#4) and divide by 1 cubic centimetre to get (*J/cc*)
* Atomization: Requiring the Enthalpy of Atomization of materials
	1. To get the energy, you would need:
		1. Density (*g/cm^3***)**
		2. Molar Mass
			1. Atomic mass (*u*)
			2. Molar Mass Constant (*1 gram/mol*)
				1. Make sure to separate the atomic structure by the elements and the constant increases with more atoms, ex. Water (H2O) = H (1 gram/mol) / 2O (2 gram/mol)
			3. Molar Mass (*Atomic Mass \* by Molar Mass Constant*)
				1. If you find the Molar Mass for more than one atoms in a molecular, add them together to get the total, ex Water = H + 2O
		3. Enthalpy of Atomization (kJ/mol)
			1. Same thing as with above (#2.2), add together the different element values with the additional atoms.
	2. Then you must divide Enthalphy of Atomization (kJ/mol) with Molar Mass (g/mol) to find Joules per grams (*J/g*)
	3. Then multiply the answer (#2) with the density of material (g/cm^3) to find the final results (J/cc)

There are other values for other materials.

Sometimes, concepts above can be muddled in their exact meaning and/or showings, such as Vaporization can mean either the break down of an object's entire chemical bonds or reducing a substance to a gaseous one. There are cases where even when said to be vaporized, the target is broken down to their particles.

Another way of doing it is with these two links in a specific order when you find the value of a material to convert

* convert from GPa to J/m^3
* convert J/m^3 to J/cm^3