Data upload

.gitignore

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+__pycache__/

README.md

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+---
+configs:
+- config_name: final_dataset
+  data_files: "data/final_dataset.csv"
+- config_name: evaluation_dataset
+  data_files: "data/evaluation_dataset.csv"
+- config_name: testset
+  data_files: "data/testset.csv"
+- config_name: train
+  data_files: "data/train.csv"
+---
+
+# Socratic benchmark

data/manual_evaluation_dialogues.csv

@@ -0,0 +1,994 @@
+original_text,problem,bug_code,bug_desc,bug_fixes,unit_tests,id,original_text_for_feedback,conversation
+"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>Can you explain what infinite recursion means?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+User: I believe it is line 7, because that is the line that is executed when `n` is larger than 2.
+Assistant: That is correct. Assume that the input `n` is 3, so the initial function call is `fibonacci(3)`. Can you tell me what is the first thing that happens in line 7 in this case?
+	<alt>Correct. So, when `fibonacci(n)` is evaluated, if n is larger than 2, line 7 is executed. What is the first thing that happens on line 7?
+	<alt>Correct. According to the problem description, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`, as you do on line 7?
+User: Well, the function is called recursively to compute `fibonacci(3)`.
+	<alt>Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`.
+	<alt>Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`. Oh, this is because I used the wrong parameters for the recursive calls. Let me fix it...
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 1) + fibonacci(n - 2)
+
+</code>
+	<alt>The call `fibonacci(n)`.
+Assistant: So, when you call `fibonacci(3)`, the code gets to line 7 where the first thing that happens is a new call to `fibonacci(3)`. What do you think happens when this new `fibonacci(3)` call is executed, line by line?
+	<alt>Do you see now why infinite recursion happens?
+	<alt>So, when you call `fibonacci(3)`, eventually it gets to line 7 where `fibonacci(3)` is called again. Do you see now why infinite recursion happens?
+User: Well, since n is 3, line 7 is executed again, which means that `fibonacci(3)` is evaluated again. I think I got it, `fibonacci(n)` calls itself recursively with the same parameter `n`, which leads to infinite recursion. I made mistake, I should have added the previous Fibonacci numbers, which are those at positions `n - 2` and `n - 1`. Let me try it... it works!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 2) + fibonacci(n - 1)
+
+</code>
+Assistant: Great, your program now works as expected!
+User: Thank you so much!
+Assistant: You are welcome!
+</dialogue>","Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```","def fibonacci(n):
+   if n <= 0:
+       return ""OOPS""
+   elif n == 1 or n == 2:
+       return 1
+   else:
+       return fibonacci(n) + fibonacci(n-1)",`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.,Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.,"assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55",0_5_fibonacci,"<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return ""OOPS""
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+","{'system': '<problem>\nCreate a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:\n-  \'OOPS\', if `n` is less than or equal to 0 \n- `1`  if `n` is equal to `1`\n- `1` if `n` is equal to `2`\n- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....\n## Example Cases:\n```\nfibonacci(-3) => \'OOPS\'\nfibonacci(0) => \'OOPS\'\nfibonacci(1) =>1\nfibonacci(2) => 1\nfibonacci(5) => 5\nfibonacci(10) => 55\n```\n</problem>\n<bug_code>\n1. def fibonacci(n):\n2.    if n <= 0:\n3.        return ""OOPS""\n4.    elif n == 1 or n == 2:\n5.        return 1\n6.    else:\n7.        return fibonacci(n) + fibonacci(n-1)\n</bug_code>\n<bug_desc>\n`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.\n</bug_desc>\n<bug_fixes>\nReplace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.\n</bug_fixes>\n<unit_tests>\nassert fibonacci(0) == \'OOPS\'\nassert fibonacci(1) == 1\nassert fibonacci(2) == 1\nassert fibonacci(5) == 5\nassert fibonacci(-3) == \'OOPS\'\nassert fibonacci(10) == 55\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?'}, {'role': 'assistant', 'content': 'I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?', 'alt': ['According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?', 'According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?', 'Can you explain what infinite recursion means?', 'Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?', ""Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?"", 'Can you explain what a recursive function is? When do we call a function recursive?', 'According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?']}, {'role': 'user', 'content': 'I believe it is line 7, because that is the line that is executed when `n` is larger than 2.'}, {'role': 'assistant', 'content': 'That is correct. Assume that the input `n` is 3, so the initial function call is `fibonacci(3)`. Can you tell me what is the first thing that happens in line 7 in this case?', 'alt': ['Correct. So, when `fibonacci(n)` is evaluated, if n is larger than 2, line 7 is executed. What is the first thing that happens on line 7?', 'Correct. According to the problem description, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`, as you do on line 7?']}, {'role': 'user', 'content': 'Well, the function is called recursively to compute `fibonacci(3)`.\n```python\n1. def fibonacci(n):\n2.    if n <= 0:\n3.        return ""OOPS""\n4.    elif n == 1 or n == 2:\n5.        return 1\n6.    else:\n7.        return fibonacci(n - 1) + fibonacci(n - 2)\n```', 'alt': ['Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`.', 'Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`. Oh, this is because I used the wrong parameters for the recursive calls. Let me fix it...', 'The call `fibonacci(n)`.']}, {'role': 'assistant', 'content': 'So, when you call `fibonacci(3)`, the code gets to line 7 where the first thing that happens is a new call to `fibonacci(3)`. What do you think happens when this new `fibonacci(3)` call is executed, line by line?', 'alt': ['Do you see now why infinite recursion happens?', 'So, when you call `fibonacci(3)`, eventually it gets to line 7 where `fibonacci(3)` is called again. Do you see now why infinite recursion happens?']}, {'role': 'user', 'content': 'Well, since n is 3, line 7 is executed again, which means that `fibonacci(3)` is evaluated again. I think I got it, `fibonacci(n)` calls itself recursively with the same parameter `n`, which leads to infinite recursion. I made mistake, I should have added the previous Fibonacci numbers, which are those at positions `n - 2` and `n - 1`. Let me try it... it works!\n```python\n1. def fibonacci(n):\n2.    if n <= 0:\n3.        return ""OOPS""\n4.    elif n == 1 or n == 2:\n5.        return 1\n6.    else:\n7.        return fibonacci(n - 2) + fibonacci(n - 1)\n```'}, {'role': 'assistant', 'content': 'Great, your program now works as expected!'}, {'role': 'user', 'content': 'Thank you so much!'}, {'role': 'assistant', 'content': 'You are welcome!'}]}"
+"<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+</bug_code>
+<bug_desc>
+The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.
+</bug_desc>
+<bug_fixes>
+Insert a line following line 4, with one indentation containing `return len(seq)` 
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I seem to be having some issues with this function I am trying to implement. It sometimes returns `None` instead of an output. 
+Assistant: What inputs have you tried? When do you get `None`?
+	<alt>Do you notice a pattern with the cases that produce `None`?
+	<alt>When do you notice `None` as the output?
+	<alt>What inputs have you tried? When do you get `None`?
+	<alt>It seems that your function may be returning nothing in certain cases. Can you think of a case where this might happen?
+User: I tried a lot of examples. One that worked correctly was `search(-2, [-1, 57, 65])`, but I got `None` when I tried `search(80, [-1, 57, 65])`.
+	<alt>I tried a few different ones. It looks like answers are only incorrect when `x` is really big relative to the numbers in the list
+	<alt>It seems like I get the wrong answer when `x` is bigger than all the existing list elements
+Assistant: Interesting. Can you walk me through what `search(80, [-1, 57, 65])` looks like at each line of your code? What would you expect as the output?
+	<alt>Compare and contrast the successful example `search(-2, [-1, 57, 65])` with the failing example `search(80, [-1, 57, 65])` where your function returns None. Does anything about `x` and `seq` in these examples stand out to you?
+	<alt>What do you expect your code to return when `x` is bigger than the `seq` elements?
+User: Sure! So, first, we iterate through the list elements. At each element, we check if `x` is less than or equal to it. In that case, we would want to insert at that index, so we return the index.
+Assistant: What happens if `x` is not less than or equal to any element?
+	<alt>What does your code do if `x` is greater than all of the elements in `seq`?
+User: I guess it doesn't return anything. I should add a case for that. Now that I've modified it, it seems to work!
+<code>
+ def search(x, seq):    
+  for i in range(len(seq)):
+    if x <= seq[i]:
+      return i
+  return len(seq)
+
+</code>
+Assistant: Good work. Let me know if you have any other questions.
+User: Thanks!
+</dialogue>","Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```","def search(x, seq):
+ for i in range(len(seq)):
+   if x <= seq[i]:
+     return i",The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.,"Insert a line following line 4, with one indentation containing `return len(seq)`","assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3",15_45_sequential_search,"<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+</bug_code>
+<bug_desc>
+The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.
+</bug_desc>
+<bug_fixes>
+Insert a line following line 4, with one indentation containing `return len(seq)` 
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+","{'system': '<problem>\nWrite a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.\n## Example Cases:\n```\nsearch(5, [-1, 5, 8, 10, 12]) => 1\nsearch(-2, [-1, 57, 65]) => 0\nsearch(0, [-120, 60, 78, 100]) => 1\nsearch(77, [-100, -50, 5, 44, 66, 76, 99]) => 6\nsearch(55, [-99, -2, 0]) => 3\n```\n</problem>\n<bug_code>\n1. def search(x, seq):\n2.  for i in range(len(seq)):\n3.    if x <= seq[i]:\n4.      return i\n</bug_code>\n<bug_desc>\nThe function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.\n</bug_desc>\n<bug_fixes>\nInsert a line following line 4, with one indentation containing `return len(seq)` \n</bug_fixes>\n<unit_tests>\nassert search(5, [-1, 5, 8, 10, 12]) == 1\nassert search(-2, [-1, 57, 65]) == 0\nassert search(0, [-120, 60, 78, 100]) == 1\nassert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6\nassert search(55, [-99, -2, 0]) == 3\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I seem to be having some issues with this function I am trying to implement. It sometimes returns `None` instead of an output.'}, {'role': 'assistant', 'content': 'What inputs have you tried? When do you get `None`?', 'alt': ['Do you notice a pattern with the cases that produce `None`?', 'When do you notice `None` as the output?', 'What inputs have you tried? When do you get `None`?', 'It seems that your function may be returning nothing in certain cases. Can you think of a case where this might happen?']}, {'role': 'user', 'content': 'I tried a lot of examples. One that worked correctly was `search(-2, [-1, 57, 65])`, but I got `None` when I tried `search(80, [-1, 57, 65])`.', 'alt': ['I tried a few different ones. It looks like answers are only incorrect when `x` is really big relative to the numbers in the list', 'It seems like I get the wrong answer when `x` is bigger than all the existing list elements']}, {'role': 'assistant', 'content': 'Interesting. Can you walk me through what `search(80, [-1, 57, 65])` looks like at each line of your code? What would you expect as the output?', 'alt': ['Compare and contrast the successful example `search(-2, [-1, 57, 65])` with the failing example `search(80, [-1, 57, 65])` where your function returns None. Does anything about `x` and `seq` in these examples stand out to you?', 'What do you expect your code to return when `x` is bigger than the `seq` elements?']}, {'role': 'user', 'content': 'Sure! So, first, we iterate through the list elements. At each element, we check if `x` is less than or equal to it. In that case, we would want to insert at that index, so we return the index.'}, {'role': 'assistant', 'content': 'What happens if `x` is not less than or equal to any element?', 'alt': ['What does your code do if `x` is greater than all of the elements in `seq`?']}, {'role': 'user', 'content': ""I guess it doesn't return anything. I should add a case for that. Now that I've modified it, it seems to work!\n```python\n def search(x, seq):    \n  for i in range(len(seq)):\n    if x <= seq[i]:\n      return i\n  return len(seq)\n```""}, {'role': 'assistant', 'content': 'Good work. Let me know if you have any other questions.'}, {'role': 'user', 'content': 'Thanks!'}]}"
+"<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Can you tell me the role of the variable `start`?
+User: In lines 2 and 3, we initialize the variables `max_len` and `start` with 0. The variable `pos` will be calculated as `s.find(t, 0) = 4`, which is the position of the first occurrence of `ca` (string `t`) in `abracadabra` (string `s`). Then, because `pos` is not -1, the variable `crt_str` is assigned the substring `s[0:4]`, which is `abra`. On line 7, `max_len` is calculated as `max(4, 0) = 4`. Then on line 9, `pos` is recalculated as `s.find(t, 0)`... Ah, I see the problem, I forgot to update the variable `start`, let me do that. It works now, thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: You're welcome!
+</dialogue>","Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```","def substr_len(s, t):
+   max_len = 0
+   start = 0
+   pos = s.find(t, start)
+   while pos != -1:
+       crt_str = s[start:pos]
+       max_len = max(len(crt_str), max_len)        
+
+       pos = s.find(t, start)
+   
+   last_str = s[start:]
+   max_len = max(len(last_str), max_len)
+
+   return max_len","The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.",On line 8 insert the code `start = pos + len(t)`.,"assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11",16_56_substring_length,"<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11
+</unit_tests>
+","{'system': '<problem>\nWrite a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.\n## Example Cases:\n```\nsubstr_len(""abracadabra"", ""ca"") => 5\nsubstr_len(""I love Python"", ""Py"") => 7\nsubstr_len(""contest"", ""test"") => 3\nsubstr_len(""icey ice"", ""ice"") => 2\nsubstr_len(""icey ice cream"", ""ice"") => 6\nsubstr_len(""abracadabra"", ""abba"") => 11\n```\n</problem>\n<bug_code>\n1. def substr_len(s, t):\n2.    max_len = 0\n3.    start = 0\n4.    pos = s.find(t, start)\n5.    while pos != -1:\n6.        crt_str = s[start:pos]\n7.        max_len = max(len(crt_str), max_len)        \n8.\n9.        pos = s.find(t, start)\n10.    \n11.    last_str = s[start:]\n12.    max_len = max(len(last_str), max_len)\n13.\n14.    return max_len\n</bug_code>\n<bug_desc>\nThe value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.\n</bug_desc>\n<bug_fixes>\nOn line 8 insert the code `start = pos + len(t)`.\n</bug_fixes>\nOn line 11 insert a new line with `ind += len(t)`.\n</bug_fixes>\n<unit_tests>\nassert substr_len(""abracadabra"", ""ca"") == 5\nassert substr_len(""I love Python"", ""Py"") == 7\nassert substr_len(""contest"", ""test"") == 3\nassert substr_len(""icey ice"", ""ice"") == 2\nassert substr_len(""icey ice cream"", ""ice"") == 6\nassert substr_len(""abracadabra"", ""abba"") == 11\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! My code does not stop and I do not understand why, can you help?'}, {'role': 'assistant', 'content': ""Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?"", 'alt': ['Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.', 'Sure. Can you tell me the role of the variable `start`?']}, {'role': 'user', 'content': 'In lines 2 and 3, we initialize the variables `max_len` and `start` with 0. The variable `pos` will be calculated as `s.find(t, 0) = 4`, which is the position of the first occurrence of `ca` (string `t`) in `abracadabra` (string `s`). Then, because `pos` is not -1, the variable `crt_str` is assigned the substring `s[0:4]`, which is `abra`. On line 7, `max_len` is calculated as `max(4, 0) = 4`. Then on line 9, `pos` is recalculated as `s.find(t, 0)`... Ah, I see the problem, I forgot to update the variable `start`, let me do that. It works now, thank you!\n```python\n1. def substr_len(s, t):\n2.    max_len = 0\n3.    start = 0\n4.    pos = s.find(t, start)\n5.    while pos != -1:\n6.        crt_str = s[start:pos]\n7.        max_len = max(len(crt_str), max_len)        \n8.        start = pos + len(t)\n9.        pos = s.find(t, start)\n10.    \n11.    last_str = s[start:]\n12.    max_len = max(len(last_str), max_len)\n13.\n14.    return max_len\n```'}, {'role': 'assistant', 'content': ""You're welcome!""}]}"
+"<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: `max_len` is a variable that stores the maximum length found so far, initialized with 0.  `start` stores the starting position in the input string `s` that we want to search for `t`, also initialized with 0. `pos` stores the position in the string `s` where the other string `t` is found. Inside the while loop, I have `crt_str` which stores the actual substring found between consecutive occurrences or `t` in `s`, with its length stored in `crt_len`. This substring is always between `start` and the current value of `pos`, which requires `start to be updated to contain the index right after the current occurrence of `t`.
+Assistant: Very good. So, you are saying then that the maximum length substring should be one of the strings computed in `crt_str` that are found between consecutive occurrences of `t` in `s`. Looking at test example 1, what is the correct maximum length substring and does it appear between consecutive occurrences or 'ca' in the input string?
+	<alt>Good. Do you think the maximum length substring always appears between consecutive occurrences of the string `t`?
+	<alt>Very good. If the maximum length substring appeared at the end of the string `s`, would your code extract it in `crt_str`?
+	<alt>Good. Can you tell me what is the last value that is assigned to `start` before `pos` becomes -1 and what is the substring of `s` that starts at that position?
+User: Ah, I see now. The maximum substring should be ""dabra"", which is between the last occurrence of `t` and the end of the string. I should have checked for substrings that end at the end of `s`, let me do that ... It works now! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.       max_len = last_len
+17.    
+18.    return max_len
+
+</code>
+Assistant: You're welcome, glad I could be of help!
+</dialogue>","Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```","def substr_len(s, t):
+   max_len = 0
+   start = 0
+   pos = s.find(t, start)
+   while pos != -1:
+       crt_str = s[start:pos]
+       crt_len = len(crt_str)
+       if crt_len > max_len:
+           max_len = crt_len
+       start = pos + len(t)
+       pos = s.find(t, start)
+   return max_len","The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.","After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```","assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11",16_46_substring_length,"<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.
+## Example Cases:
+```
+substr_len(""abracadabra"", ""ca"") => 5
+substr_len(""I love Python"", ""Py"") => 7
+substr_len(""contest"", ""test"") => 3
+substr_len(""icey ice"", ""ice"") => 2
+substr_len(""icey ice cream"", ""ice"") => 6
+substr_len(""abracadabra"", ""abba"") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len(""abracadabra"", ""ca"") == 5
+assert substr_len(""I love Python"", ""Py"") == 7
+assert substr_len(""contest"", ""test"") == 3
+assert substr_len(""icey ice"", ""ice"") == 2
+assert substr_len(""icey ice cream"", ""ice"") == 6
+assert substr_len(""abracadabra"", ""abba"") == 11
+</unit_tests>
+","{'system': '<problem>\nWrite a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = ""abracadabra""` and `t = ""ca""`, then the longest substring of `s` that does not contain `t` is `""dabra""`, so the function should return 5.\n## Example Cases:\n```\nsubstr_len(""abracadabra"", ""ca"") => 5\nsubstr_len(""I love Python"", ""Py"") => 7\nsubstr_len(""contest"", ""test"") => 3\nsubstr_len(""icey ice"", ""ice"") => 2\nsubstr_len(""icey ice cream"", ""ice"") => 6\nsubstr_len(""abracadabra"", ""abba"") => 11\n```\n</problem>\n<bug_code>\n1. def substr_len(s, t):\n2.    max_len = 0\n3.    start = 0\n4.    pos = s.find(t, start)\n5.    while pos != -1:\n6.        crt_str = s[start:pos]\n7.        crt_len = len(crt_str)\n8.        if crt_len > max_len:\n9.            max_len = crt_len\n10.        start = pos + len(t)\n11.        pos = s.find(t, start)\n12.    return max_len\n</bug_code>\n<bug_desc>\nThe code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.\n</bug_desc>\n<bug_fixes>\nAfter line 11, insert the following outside the while loop scope:\n```py\nlast_str = s[start:]\nlast_len = len(last_str)\nif last_len > max_len:\n       max_len = last_len\n```\n</bug_fixes>\n<unit_tests>\nassert substr_len(""abracadabra"", ""ca"") == 5\nassert substr_len(""I love Python"", ""Py"") == 7\nassert substr_len(""contest"", ""test"") == 3\nassert substr_len(""icey ice"", ""ice"") == 2\nassert substr_len(""icey ice cream"", ""ice"") == 6\nassert substr_len(""abracadabra"", ""abba"") == 11\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?'}, {'role': 'assistant', 'content': 'I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?', 'alt': ['Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?', 'Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?', 'Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?', ""Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?"", 'Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?', 'Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?']}, {'role': 'user', 'content': '`max_len` is a variable that stores the maximum length found so far, initialized with 0.  `start` stores the starting position in the input string `s` that we want to search for `t`, also initialized with 0. `pos` stores the position in the string `s` where the other string `t` is found. Inside the while loop, I have `crt_str` which stores the actual substring found between consecutive occurrences or `t` in `s`, with its length stored in `crt_len`. This substring is always between `start` and the current value of `pos`, which requires `start to be updated to contain the index right after the current occurrence of `t`.'}, {'role': 'assistant', 'content': ""Very good. So, you are saying then that the maximum length substring should be one of the strings computed in `crt_str` that are found between consecutive occurrences of `t` in `s`. Looking at test example 1, what is the correct maximum length substring and does it appear between consecutive occurrences or 'ca' in the input string?"", 'alt': ['Good. Do you think the maximum length substring always appears between consecutive occurrences of the string `t`?', 'Very good. If the maximum length substring appeared at the end of the string `s`, would your code extract it in `crt_str`?', 'Good. Can you tell me what is the last value that is assigned to `start` before `pos` becomes -1 and what is the substring of `s` that starts at that position?']}, {'role': 'user', 'content': 'Ah, I see now. The maximum substring should be ""dabra"", which is between the last occurrence of `t` and the end of the string. I should have checked for substrings that end at the end of `s`, let me do that ... It works now! Thank you!\n```python\n1. def substr_len(s, t):\n2.    max_len = 0\n3.    start = 0\n4.    pos = s.find(t, start)\n5.    while pos != -1:\n6.        crt_str = s[start:pos]\n7.        crt_len = len(crt_str)\n8.        if crt_len > max_len:\n9.            max_len = crt_len\n10.        start = pos + len(t)\n11.        pos = s.find(t, start)\n12.    \n13.    last_str = s[start:]\n14.    last_len = len(last_str)\n15.    if last_len > max_len:\n16.       max_len = last_len\n17.    \n18.    return max_len\n```'}, {'role': 'assistant', 'content': ""You're welcome, glad I could be of help!""}]}"
+"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.        return newNums
+</bug_code>
+<bug_desc>
+On line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.
+</bug_desc>
+<bug_fixes>
+Remove a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help, I'm stuck.
+Assistant: What should your code be doing?
+	<alt>Which test cases (if any) are failing?
+	<alt>What are you stuck on?
+	<alt>Can you explain your code line by line, given that `nums` is `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`?
+User: Right now, it's only returning the first number in the list, not all of them.
+	<alt>It's only passing the second test case.
+Assistant: Okay, let's look at your loop. Do you see anything that could be causing it to end early?
+	<alt>Have you checked the loop and how many times it iterates?
+	<alt>Let's add a print statement into your for loop that prints `i` and then execute it. What do you observe?
+	<alt>What do you think might cause your function to return a list with one element instead of multiple elements?
+	<alt>Let's use the debugger and step through the function while tracking the values of `i` and `newNums`. What do you observe?
+	<alt>What do you think is causing the lists not to include all the numbers?
+	<alt>Look at line 3, is it iterating through the whole list?
+User: No I do not. I'm iterating through the whole list of numbers.
+	<alt>I don't know, how could I find out?
+	<alt>Oh, I see, the return statement is in the wrong place.
+Assistant: Let's verify this by tracing the code in the loop. Can you tell me what line 3 does?
+	<alt>What can cause a function to end early?
+	<alt>What forces a loop to end?
+User: Line 3 starts the loop, and it iterates through everything in `nums`.
+Assistant: Good, then what happens?
+	<alt>Yes, you are right. Next, you have your if-statement. Is there anything in the if-statement that could make a loop end early?
+	<alt>Think back to what you know about functions. What makes them end early?
+	<alt>Think back to what you know about loops, what can make them stop?
+User: The if statement starts on line 4, it checks if the number is even.
+Assistant: Do you see anything on line 4 that could cause the function to return a list with one element instead of multiple elements?
+	<alt>Do you notice anything on line 4 that causes the function to end early?
+	<alt>Do you notice anything on line 4 that causes the for loop to end?
+User: I don't see anything that can cause that problem.
+	<alt>I see! The return statement after the if-statement is indented too much!
+Assistant: Okay, so what happens next on line 6?
+User: It returns the list.
+	<alt>I get it! It's returning after every iteration!
+	<alt>It's returning too soon.
+Assistant: When should it return the list?
+	<alt>Would a return statement end a loop?
+	<alt>Would a return statement cause the function to terminate early?
+	<alt>Is there anything on this line that would cause the loop or the function to end early?
+	<alt>When does your return statement execute?
+User: It should return the list when it finishes all the numbers.
+Assistant: Look at line 6, what level of indentation is the list on?
+	<alt>Think back to what you have learned about indentation, how does that control the order of actions in a loop?
+	<alt>Can the return statement end the loop early?
+User: I see, I'm indenting too much! It's returning the list as part of the loop, not after it. Let me change the indentation of the return statement.
+<code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.    return newNums
+
+</code>
+Assistant: What does it return now, after you changed the indentation of the return statement?
+User: It works properly! Thank you! Now the return statement executes after the for loop iterates through all the elements in `nums`.
+Assistant: You're welcome. Let me know if I can be of any further assistance.
+</dialogue>","Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```","def returnOdd(nums):
+   newNums = []
+   for i in nums:
+       if i % 2 != 0:
+           newNums.append(i)
+       return newNums","On line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.",Remove a tab indentation before `return newNums` on line 6.,"assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]",4_26_removing_even_numbers,"<problem>
+Create a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.
+
+## Example Cases:
+```
+returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]
+returnOdd([2, 4, 6, 8, 10]) => []
+returnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]
+returnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]
+```
+</problem>
+<bug_code>
+1. def returnOdd(nums):
+2.    newNums = []
+3.    for i in nums:
+4.        if i % 2 != 0:
+5.            newNums.append(i)
+6.        return newNums
+</bug_code>
+<bug_desc>
+On line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.
+</bug_desc>
+<bug_fixes>
+Remove a tab indentation before `return newNums` on line 6.
+</bug_fixes>
+<unit_tests>
+assert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]
+assert returnOdd([2, 4, 6, 8, 10]) == []
+assert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]
+assert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]
+</unit_tests>
+","{'system': '<problem>\nCreate a method `returnOdd(nums:List[int]) -> List[int]` that accepts a list `nums`. It should filter out all the even integers from the list `nums` and return a new list that contains only the odd integers from the original list.\n\n## Example Cases:\n```\nreturnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) => [1, 3, 5, 7, 9]\nreturnOdd([2, 4, 6, 8, 10]) => []\nreturnOdd([1, 3, 5, 7, 9]) => [1, 3, 5, 7, 9]\nreturnOdd([-76, -92, 9, -1, 7, 10]) => [9, -1, 7]\n```\n</problem>\n<bug_code>\n1. def returnOdd(nums):\n2.    newNums = []\n3.    for i in nums:\n4.        if i % 2 != 0:\n5.            newNums.append(i)\n6.        return newNums\n</bug_code>\n<bug_desc>\nOn line 6, the function returns the array `newNums` after the first iteration of the for loop. Consequently, the function returns `newNums` containing up to 1 odd value from `nums` instead of returning `newNums` containing all the odd values in `nums`.\n</bug_desc>\n<bug_fixes>\nRemove a tab indentation before `return newNums` on line 6.\n</bug_fixes>\n<unit_tests>\nassert returnOdd([1, 2, 3, 4, 5, 6, 7, 8, 9, 10]) == [1, 3, 5, 7, 9]\nassert returnOdd([2, 4, 6, 8, 10]) == []\nassert returnOdd([1, 3, 5, 7, 9]) == [1, 3, 5, 7, 9]\nassert returnOdd([-76, -92, 9, -1, 7, 10]) == [9, -1, 7]\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': ""Help, I'm stuck.""}, {'role': 'assistant', 'content': 'What should your code be doing?', 'alt': ['Which test cases (if any) are failing?', 'What are you stuck on?', 'Can you explain your code line by line, given that `nums` is `[1, 2, 3, 4, 5, 6, 7, 8, 9, 10]`?']}, {'role': 'user', 'content': ""Right now, it's only returning the first number in the list, not all of them."", 'alt': [""It's only passing the second test case.""]}, {'role': 'assistant', 'content': ""Okay, let's look at your loop. Do you see anything that could be causing it to end early?"", 'alt': ['Have you checked the loop and how many times it iterates?', ""Let's add a print statement into your for loop that prints `i` and then execute it. What do you observe?"", 'What do you think might cause your function to return a list with one element instead of multiple elements?', ""Let's use the debugger and step through the function while tracking the values of `i` and `newNums`. What do you observe?"", 'What do you think is causing the lists not to include all the numbers?', 'Look at line 3, is it iterating through the whole list?']}, {'role': 'user', 'content': ""No I do not. I'm iterating through the whole list of numbers."", 'alt': [""I don't know, how could I find out?"", 'Oh, I see, the return statement is in the wrong place.']}, {'role': 'assistant', 'content': ""Let's verify this by tracing the code in the loop. Can you tell me what line 3 does?"", 'alt': ['What can cause a function to end early?', 'What forces a loop to end?']}, {'role': 'user', 'content': 'Line 3 starts the loop, and it iterates through everything in `nums`.'}, {'role': 'assistant', 'content': 'Good, then what happens?', 'alt': ['Yes, you are right. Next, you have your if-statement. Is there anything in the if-statement that could make a loop end early?', 'Think back to what you know about functions. What makes them end early?', 'Think back to what you know about loops, what can make them stop?']}, {'role': 'user', 'content': 'The if statement starts on line 4, it checks if the number is even.'}, {'role': 'assistant', 'content': 'Do you see anything on line 4 that could cause the function to return a list with one element instead of multiple elements?', 'alt': ['Do you notice anything on line 4 that causes the function to end early?', 'Do you notice anything on line 4 that causes the for loop to end?']}, {'role': 'user', 'content': ""I don't see anything that can cause that problem."", 'alt': ['I see! The return statement after the if-statement is indented too much!']}, {'role': 'assistant', 'content': 'Okay, so what happens next on line 6?'}, {'role': 'user', 'content': 'It returns the list.', 'alt': [""I get it! It's returning after every iteration!"", ""It's returning too soon.""]}, {'role': 'assistant', 'content': 'When should it return the list?', 'alt': ['Would a return statement end a loop?', 'Would a return statement cause the function to terminate early?', 'Is there anything on this line that would cause the loop or the function to end early?', 'When does your return statement execute?']}, {'role': 'user', 'content': 'It should return the list when it finishes all the numbers.'}, {'role': 'assistant', 'content': 'Look at line 6, what level of indentation is the list on?', 'alt': ['Think back to what you have learned about indentation, how does that control the order of actions in a loop?', 'Can the return statement end the loop early?']}, {'role': 'user', 'content': ""I see, I'm indenting too much! It's returning the list as part of the loop, not after it. Let me change the indentation of the return statement.\n```python\n1. def returnOdd(nums):\n2.    newNums = []\n3.    for i in nums:\n4.        if i % 2 != 0:\n5.            newNums.append(i)\n6.    return newNums\n```""}, {'role': 'assistant', 'content': 'What does it return now, after you changed the indentation of the return statement?'}, {'role': 'user', 'content': 'It works properly! Thank you! Now the return statement executes after the for loop iterates through all the elements in `nums`.'}, {'role': 'assistant', 'content': ""You're welcome. Let me know if I can be of any further assistance.""}]}"
+"<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples > children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</bug_code>
+<bug_desc>
+The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.
+</bug_desc>
+<bug_fixes>
+Replace `apples > children` with `apples >= children` on line 3.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My function fails two test cases and I do not understand why, can you help?
+Assistant: Sure. Do you see anything special about the test cases it fails, compared to the ones where it works well?
+	<alt>Sure, I can help. Let's consider the third test case where `apples = 100` and `children = 100`. Can you manually run through the code and explain what happens, line by line?
+	<alt>Sure. Let's consider the third test case where `apples = 100` and `children = 100`. What is the number returned by your function?
+	<alt>Sure. Can you explain to me what you are trying to do with the while loop?
+	<alt>Sure. Can you tell me what the loop condition `apples > children` is there for?
+	<alt>Sure. Can you explain your code to me, what is supposed to do, line by line?
+User: It fails on test cases 1 and 3 and works well for cases 2 and 4. One thing that is different between them is that when it fails the number of apples is divisible by the number of children.
+	<alt>It fails on test cases 1 and 3 and works well for cases 2 and 4, but I don't see what is different between them.
+Assistant: Exactly. Now, in these cases, how is the number computed by your function, when compared to the correct output?
+	<alt>Exactly. Now, looking at your code, can you figure out why it returns the wrong number when `apples` is divisible by `children`? You might want to consider an actual example, such as test case number 3.
+	<alt>Exactly. Now, let's say that `apples = k * children`, which means that the function should return the value `k`. How many times does the while loop iterate in your code?
+User: It is 1 less than the correct number.
+Assistant: Correct. Looking at your code, this means that the while loop needs to iterate one more time in order to produce the correct value for `i`. Can you see what condition makes it stop iterating too early?
+	<alt>Correct. Looking at your code, can you figure out why when `apples` is divisible by `children` the function outputs 1 less than the correct number?
+User: Ah, I see, it stops when `apples` is equal to `children`, but it should iterate for that too. Let me fix that ... it works now, thank you!
+<code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples >= children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</code>
+Assistant: You're welcome, glad I could be of help!
+</dialogue>","Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```","def split_apples(apples, children):
+   i = 0
+   while apples > 0 and apples > children:
+       apples = apples - children
+       i += 1
+   return i","The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.",Replace `apples > children` with `apples >= children` on line 3.,"assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0",58_59_splitting_apples,"<problem>
+Write a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.
+
+## Example Cases:
+```
+split_apples(10, 2) => 5
+split_apples(7, 2) => 3
+split_apples(100, 100) => 1
+split_apples(1, 2) => 0
+```
+</problem>
+<bug_code>
+1. def split_apples(apples, children):
+2.    i = 0
+3.    while apples > 0 and apples > children:
+4.        apples = apples - children
+5.        i += 1
+6.    return i
+</bug_code>
+<bug_desc>
+The while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.
+</bug_desc>
+<bug_fixes>
+Replace `apples > children` with `apples >= children` on line 3.
+</bug_fixes>
+<unit_tests>
+assert split_apples(10, 2) == 5
+assert split_apples(7, 2) == 3
+assert split_apples(100, 100) == 1
+assert split_apples(1, 2) == 0
+</unit_tests>
+","{'system': '<problem>\nWrite a method `split_apples(apples:int, children:int) ->int` that takes in an amount of apples and a number of children. The function should distribute `apples` evenly across all `children`. The function should return the whole number of apples each child will get after distributing the apples evenly. Assume that both `apples` and `children` are positive whole numbers.\n\n## Example Cases:\n```\nsplit_apples(10, 2) => 5\nsplit_apples(7, 2) => 3\nsplit_apples(100, 100) => 1\nsplit_apples(1, 2) => 0\n```\n</problem>\n<bug_code>\n1. def split_apples(apples, children):\n2.    i = 0\n3.    while apples > 0 and apples > children:\n4.        apples = apples - children\n5.        i += 1\n6.    return i\n</bug_code>\n<bug_desc>\nThe while loop exits early when `apples` are divisible by `children`. Consequently, the function has an off-by-one error when `apples` is divisible by `children`.\n</bug_desc>\n<bug_fixes>\nReplace `apples > children` with `apples >= children` on line 3.\n</bug_fixes>\n<unit_tests>\nassert split_apples(10, 2) == 5\nassert split_apples(7, 2) == 3\nassert split_apples(100, 100) == 1\nassert split_apples(1, 2) == 0\n</unit_tests>\n<stu_desc>\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! My function fails two test cases and I do not understand why, can you help?'}, {'role': 'assistant', 'content': 'Sure. Do you see anything special about the test cases it fails, compared to the ones where it works well?', 'alt': [""Sure, I can help. Let's consider the third test case where `apples = 100` and `children = 100`. Can you manually run through the code and explain what happens, line by line?"", ""Sure. Let's consider the third test case where `apples = 100` and `children = 100`. What is the number returned by your function?"", 'Sure. Can you explain to me what you are trying to do with the while loop?', 'Sure. Can you tell me what the loop condition `apples > children` is there for?', 'Sure. Can you explain your code to me, what is supposed to do, line by line?']}, {'role': 'user', 'content': 'It fails on test cases 1 and 3 and works well for cases 2 and 4. One thing that is different between them is that when it fails the number of apples is divisible by the number of children.', 'alt': [""It fails on test cases 1 and 3 and works well for cases 2 and 4, but I don't see what is different between them.""]}, {'role': 'assistant', 'content': 'Exactly. Now, in these cases, how is the number computed by your function, when compared to the correct output?', 'alt': ['Exactly. Now, looking at your code, can you figure out why it returns the wrong number when `apples` is divisible by `children`? You might want to consider an actual example, such as test case number 3.', ""Exactly. Now, let's say that `apples = k * children`, which means that the function should return the value `k`. How many times does the while loop iterate in your code?""]}, {'role': 'user', 'content': 'It is 1 less than the correct number.'}, {'role': 'assistant', 'content': 'Correct. Looking at your code, this means that the while loop needs to iterate one more time in order to produce the correct value for `i`. Can you see what condition makes it stop iterating too early?', 'alt': ['Correct. Looking at your code, can you figure out why when `apples` is divisible by `children` the function outputs 1 less than the correct number?']}, {'role': 'user', 'content': 'Ah, I see, it stops when `apples` is equal to `children`, but it should iterate for that too. Let me fix that ... it works now, thank you!\n```python\n1. def split_apples(apples, children):\n2.    i = 0\n3.    while apples > 0 and apples >= children:\n4.        apples = apples - children\n5.        i += 1\n6.    return i\n```'}, {'role': 'assistant', 'content': ""You're welcome, glad I could be of help!""}]}"
+"<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value `None`.
+
+
+## Example Cases:
+```
+turn_clockwise(""N"") => ""E""
+turn_clockwise(""W"") => ""N""
+turn_clockwise(""S"") => ""W""
+turn_clockwise(""E"") => ""S""
+turn_clockwise(42) => None
+turn_clockwise(""rubbish"") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == ""N"":
+3.        print (""E"")
+4.    elif compass_point == ""E"":
+5.        print (""S"")
+6.    elif compass_point == ""S"":
+7.        print (""W"")
+8.    elif compass_point == ""W"":
+9.        print (""N"")
+10.    else:
+11.        print (""None"")
+</bug_code>
+<bug_desc>
+The function prints the strings ""N"", ""E"", ""S"", ""W"", and ""None"". Consequently, the function returns `None` for all cases of `compass_point` instead of returning the appropriate strings.
+</bug_desc>
+<bug_fixes>
+Replace all the print statements `print (""E"")`, `print (""S"")`, `print (""W"")`, `print (""N"")`, `print(""None"")` with the return statements `return ""E""`, `return ""S""`, `return ""W""`, `return ""N""`, `return ""None""` on lines 3, 5, 7, 9, and 11 respectively.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise(""N"") == ""E""
+assert turn_clockwise(""W"") == ""N"" 
+assert turn_clockwise(""S"") == ""W""
+assert turn_clockwise(""E"") == ""S""
+assert turn_clockwise(42) == None
+assert turn_clockwise(""rubbish"") == None
+</unit_tests>
+<stu_desc>
+
+
+</stu_desc>
+<dialogue>
+User: Hi! I have a problem. My code does not generate the right result and I cannot figure that out.
+Assistant: Hi! Let's take a look at your code. Could you explain how your code works?
+	<alt>Hi! What makes you think that your program is not working properly?
+	<alt>Can you give me an example where your code does not return the correct result?
+	<alt>I see. Let’s run your code with the function call `store = turn_clockwise(""N"")` then print `store` and observe the output in the terminal. What do you see?
+	<alt>I see. Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?
+User: Ok. My code gets the current `compass_point` and prints the next one.
+Assistant: What do you see as your output in the terminal and what are you passing as `compass_point`?
+	<alt>What makes the result incorrect? Can you give me an example including what you are passing in as `compass_point` and what you observe in the terminal?
+User: When I pass in `""N""` as `compass_point`. I see `""E""` printed in the terminal. That's strange since my output is printed correctly, but my program does not pass any of the tests.
+Assistant: What does a unit test need from a function to ensure that the function works properly?
+	<alt>Ah. How did you determine whether your function is correct?
+	<alt>I see. Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?
+	<alt>Is printing the same as returning a value?
+	<alt>Say you want to store the output of your function into a variable, what would you need to do?
+	<alt>What do you think a function needs to pass along its output to say get stored in a variable?
+User: It probably needs the value outputted by the function. My function outputs `""E""` in the terminal when I pass in `""N""` to it. The output is correct, so I am really confused.
+	<alt>I don't understand the question. Can you tell me more about unit tests?
+Assistant: Correct. So would you be able to store the value outputted by the function into say a variable?
+	<alt>Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?
+	<alt>Is printing the same as returning a value?
+User: Hypothetically yes. I should be able to store it in a variable. I have not tried though.
+Assistant: Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?
+	<alt>Let’s run your code with the function call `store = turn_clockwise(""N"")` then print `store` and observe the output in the terminal. What do you see?
+User: Ah I think, it would be `""E""` in `store`. 
+Assistant: Let’s try it and then print `store`. What do you observe in your terminal?
+User: Hmm... I see `None`. That’s really strange.
+
+<code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == ""N"":
+3.        print (""E"")
+4.    elif compass_point == ""E"":
+5.        print (""S"")
+6.    elif compass_point == ""S"":
+7.        print (""W"")
+8.    elif compass_point == ""W"":
+9.        print (""N"")
+10.    else:
+11.        print (""None"")
+12. store = turn_clockwise(""N"")
+13. print(store)
+
+</code>
+
+Assistant: What do you think the function needs to have in order to give its output to the variable?
+	<alt>Do you recall, which reserved word in Python is used to return the output for a function back to a variable?
+User: Ah! I think it might be `return`. Let me try that.
+<code>
+def turn_clockwise(compass_point):
+    if compass_point == ""N"":
+        return ""E""
+    elif compass_point == ""E"":
+        return ""S""
+    elif compass_point == ""S"":
+        return ""W""
+    elif compass_point == ""W"":
+        return ""N""
+    else:
+        return None
+		
+</code>
+	<alt>I’m not really sure.
+Assistant: Very good.
+	<alt>Very good. Is there a way for you to simplify your code?
+User: Thank you so much!
+Assistant: You’re welcome! Let me know if I can be of any further help.
+</dialogue>","The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value `None`.
+
+
+## Example Cases:
+```
+turn_clockwise(""N"") => ""E""
+turn_clockwise(""W"") => ""N""
+turn_clockwise(""S"") => ""W""
+turn_clockwise(""E"") => ""S""
+turn_clockwise(42) => None
+turn_clockwise(""rubbish"") => None
+```","def turn_clockwise(compass_point):
+   if compass_point == ""N"":
+       print (""E"")
+   elif compass_point == ""E"":
+       print (""S"")
+   elif compass_point == ""S"":
+       print (""W"")
+   elif compass_point == ""W"":
+       print (""N"")
+   else:
+       print (""None"")","The function prints the strings ""N"", ""E"", ""S"", ""W"", and ""None"". Consequently, the function returns `None` for all cases of `compass_point` instead of returning the appropriate strings.","Replace all the print statements `print (""E"")`, `print (""S"")`, `print (""W"")`, `print (""N"")`, `print(""None"")` with the return statements `return ""E""`, `return ""S""`, `return ""W""`, `return ""N""`, `return ""None""` on lines 3, 5, 7, 9, and 11 respectively.","assert turn_clockwise(""N"") == ""E""
+assert turn_clockwise(""W"") == ""N"" 
+assert turn_clockwise(""S"") == ""W""
+assert turn_clockwise(""E"") == ""S""
+assert turn_clockwise(42) == None
+assert turn_clockwise(""rubbish"") == None",6_33_turning_clockwise,"<problem>
+The four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that's distinct from the four compass points listed earlier, return the value `None`.
+
+
+## Example Cases:
+```
+turn_clockwise(""N"") => ""E""
+turn_clockwise(""W"") => ""N""
+turn_clockwise(""S"") => ""W""
+turn_clockwise(""E"") => ""S""
+turn_clockwise(42) => None
+turn_clockwise(""rubbish"") => None
+```
+</problem>
+<bug_code>
+1. def turn_clockwise(compass_point):
+2.    if compass_point == ""N"":
+3.        print (""E"")
+4.    elif compass_point == ""E"":
+5.        print (""S"")
+6.    elif compass_point == ""S"":
+7.        print (""W"")
+8.    elif compass_point == ""W"":
+9.        print (""N"")
+10.    else:
+11.        print (""None"")
+</bug_code>
+<bug_desc>
+The function prints the strings ""N"", ""E"", ""S"", ""W"", and ""None"". Consequently, the function returns `None` for all cases of `compass_point` instead of returning the appropriate strings.
+</bug_desc>
+<bug_fixes>
+Replace all the print statements `print (""E"")`, `print (""S"")`, `print (""W"")`, `print (""N"")`, `print(""None"")` with the return statements `return ""E""`, `return ""S""`, `return ""W""`, `return ""N""`, `return ""None""` on lines 3, 5, 7, 9, and 11 respectively.
+</bug_fixes>
+<unit_tests>
+assert turn_clockwise(""N"") == ""E""
+assert turn_clockwise(""W"") == ""N"" 
+assert turn_clockwise(""S"") == ""W""
+assert turn_clockwise(""E"") == ""S""
+assert turn_clockwise(42) == None
+assert turn_clockwise(""rubbish"") == None
+</unit_tests>
+","{'system': '\ufeff<problem>\nThe four compass points can be abbreviated by single-letter strings as “N”, “E”, “S”, and “W”. Write a function `turn_clockwise (compass_point:str)` that takes one of these four compass points as its parameter, and returns the next compass point in the clockwise direction. If `compass_point` has another value that\'s distinct from the four compass points listed earlier, return the value `None`.\n\n\n## Example Cases:\n```\nturn_clockwise(""N"") => ""E""\nturn_clockwise(""W"") => ""N""\nturn_clockwise(""S"") => ""W""\nturn_clockwise(""E"") => ""S""\nturn_clockwise(42) => None\nturn_clockwise(""rubbish"") => None\n```\n</problem>\n<bug_code>\n1. def turn_clockwise(compass_point):\n2.    if compass_point == ""N"":\n3.        print (""E"")\n4.    elif compass_point == ""E"":\n5.        print (""S"")\n6.    elif compass_point == ""S"":\n7.        print (""W"")\n8.    elif compass_point == ""W"":\n9.        print (""N"")\n10.    else:\n11.        print (""None"")\n</bug_code>\n<bug_desc>\nThe function prints the strings ""N"", ""E"", ""S"", ""W"", and ""None"". Consequently, the function returns `None` for all cases of `compass_point` instead of returning the appropriate strings.\n</bug_desc>\n<bug_fixes>\nReplace all the print statements `print (""E"")`, `print (""S"")`, `print (""W"")`, `print (""N"")`, `print(""None"")` with the return statements `return ""E""`, `return ""S""`, `return ""W""`, `return ""N""`, `return ""None""` on lines 3, 5, 7, 9, and 11 respectively.\n</bug_fixes>\n<unit_tests>\nassert turn_clockwise(""N"") == ""E""\nassert turn_clockwise(""W"") == ""N"" \nassert turn_clockwise(""S"") == ""W""\nassert turn_clockwise(""E"") == ""S""\nassert turn_clockwise(42) == None\nassert turn_clockwise(""rubbish"") == None\n</unit_tests>\n<stu_desc>\n\n\n</stu_desc>', 'messages': [{'role': 'user', 'content': 'Hi! I have a problem. My code does not generate the right result and I cannot figure that out.'}, {'role': 'assistant', 'content': ""Hi! Let's take a look at your code. Could you explain how your code works?"", 'alt': ['Hi! What makes you think that your program is not working properly?', 'Can you give me an example where your code does not return the correct result?', 'I see. Let’s run your code with the function call `store = turn_clockwise(""N"")` then print `store` and observe the output in the terminal. What do you see?', 'I see. Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?']}, {'role': 'user', 'content': 'Ok. My code gets the current `compass_point` and prints the next one.'}, {'role': 'assistant', 'content': 'What do you see as your output in the terminal and what are you passing as `compass_point`?', 'alt': ['What makes the result incorrect? Can you give me an example including what you are passing in as `compass_point` and what you observe in the terminal?']}, {'role': 'user', 'content': 'When I pass in `""N""` as `compass_point`. I see `""E""` printed in the terminal. That\'s strange since my output is printed correctly, but my program does not pass any of the tests.'}, {'role': 'assistant', 'content': 'What does a unit test need from a function to ensure that the function works properly?', 'alt': ['Ah. How did you determine whether your function is correct?', 'I see. Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?', 'Is printing the same as returning a value?', 'Say you want to store the output of your function into a variable, what would you need to do?', 'What do you think a function needs to pass along its output to say get stored in a variable?']}, {'role': 'user', 'content': 'It probably needs the value outputted by the function. My function outputs `""E""` in the terminal when I pass in `""N""` to it. The output is correct, so I am really confused.', 'alt': [""I don't understand the question. Can you tell me more about unit tests?""]}, {'role': 'assistant', 'content': 'Correct. So would you be able to store the value outputted by the function into say a variable?', 'alt': ['Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?', 'Is printing the same as returning a value?']}, {'role': 'user', 'content': 'Hypothetically yes. I should be able to store it in a variable. I have not tried though.'}, {'role': 'assistant', 'content': 'Suppose we run your code with the function call `store = turn_clockwise(""N"")`. What do you think the value of `store` will be after execution?', 'alt': ['Let’s run your code with the function call `store = turn_clockwise(""N"")` then print `store` and observe the output in the terminal. What do you see?']}, {'role': 'user', 'content': 'Ah I think, it would be `""E""` in `store`.'}, {'role': 'assistant', 'content': 'Let’s try it and then print `store`. What do you observe in your terminal?'}, {'role': 'user', 'content': 'Hmm... I see `None`. That’s really strange.\n\n```python\n1. def turn_clockwise(compass_point):\n2.    if compass_point == ""N"":\n3.        print (""E"")\n4.    elif compass_point == ""E"":\n5.        print (""S"")\n6.    elif compass_point == ""S"":\n7.        print (""W"")\n8.    elif compass_point == ""W"":\n9.        print (""N"")\n10.    else:\n11.        print (""None"")\n12. store = turn_clockwise(""N"")\n13. print(store)\n```'}, {'role': 'assistant', 'content': 'What do you think the function needs to have in order to give its output to the variable?', 'alt': ['Do you recall, which reserved word in Python is used to return the output for a function back to a variable?']}, {'role': 'user', 'content': 'Ah! I think it might be `return`. Let me try that.\n```python\ndef turn_clockwise(compass_point):\n    if compass_point == ""N"":\n        return ""E""\n    elif compass_point == ""E"":\n        return ""S""\n    elif compass_point == ""S"":\n        return ""W""\n    elif compass_point == ""W"":\n        return ""N""\n    else:\n        return None\n\t\t\n```', 'alt': ['I’m not really sure.']}, {'role': 'assistant', 'content': 'Very good.', 'alt': ['Very good. Is there a way for you to simplify your code?']}, {'role': 'user', 'content': 'Thank you so much!'}, {'role': 'assistant', 'content': 'You’re welcome! Let me know if I can be of any further help.'}]}"

data/raw/v2_sigcse/evaluation_dataset/0_0_fibonacci_conversational_thread_1.txt

@@ -0,0 +1,119 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+The student has a misconception about for loop ranges. The student also struggles to explain their code. The student knows how to use the debugger.
+</stu_desc>
+<dialogue>
+User: Hey, I really need help. This function is not returning the correct number.
+Assistant: I'll be happy to help you. What happens when you pass 5 as `count` to the function `fibonacci(5)`?
+	<alt>Happy to help. Can you give me an example of your function returning an incorrect number?
+	<alt>Sure. Can you list the first 5 numbers in the Fibonacci sequence?
+	<alt>Can you describe what your code does line by line?
+User: When I run the function with `n` as 5 the output is 8 instead of 5.
+Assistant: I see. What do you think might be the cause of this?
+	<alt>Can you describe your for loop on line 11?
+	<alt>Can you walk me through the steps your function takes to generate the Fibonacci sequence?
+	<alt>Can you identify any issues with the loop that generates the Fibonacci sequence?
+	<alt>Which part of your code do you suspect of causing this issue?
+User: I guess maybe the problem is that `a` is set to 0 not 1? I am not really sure.
+	<alt>I am not sure. Can you help?
+	<alt>I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return.
+Assistant: Let's focus on the loop. Can you describe what your for loop is doing on line 11?
+	<alt>Can you describe how many times the for loop iterates on line 11?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+User: The loop iterates depending on the value of `n`. Not really sure what else to say here.
+	<alt>Not really sure how to describe it.
+	<alt>It loops `n` times
+	<alt>The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.
+Assistant: Can you describe how many times the for loop iterates on line 11?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+User: The for loop loops from 1 until value of `n` for `n - 1` times
+Assistant: Let's verify that.  How can we monitor the value of  `i` during the loop?
+	<alt>How can we verify that?
+	<alt>Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration to verify that. After executing the code what do you notice?
+	<alt>To verify let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>Let's verify that.  How can we monitor the values of `a`, `b`, and `i` during the loop?
+User: I can use the debugger perhaps.
+	<alt>I can add print statements.
+	<alt>I'm not really sure can you suggest a way?
+Assistant: Let's first examine the values of `i`. How many times in total does the for loop iterate?
+User: Using the debugger I notice that the for loop iterates 5 times when `n` is  5 and the values of `n` range from 0 to 4 or `n - 1`. I thought it loops from 1 to `n`.
+Assistant: If your for loop is iterating more than you expected how might that impact the returned value?
+	<alt>Good. Let's go through the debugger again and track `a`, `b`, and `i` at each iteration. What do you notice?
+User: If it iterates one more time than I expected then it might be going to the next Fibonacci term in the sequence. So in our case 8 as opposed to 5!
+	<alt>Not really sure, maybe need to step through it to see how it affects the returned term.
+Assistant: Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+	<alt>Good. What should you do now to return the correct Fibonacci number?
+User: I think I should edit the range of the loop to iterate one less time. Let me edit my code.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n - 1):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: Good work. Have you tried your code on all the example cases to make sure it works properly?
+User: Yes all looks good! Thank you so much!
+Assistant: You are welcome. Let me know if I can be of any further assistance.
+User: Thank you!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/0_0_fibonacci_conversational_thread_2.txt

@@ -0,0 +1,141 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey, I really need help. This function is not returning the correct number.
+Assistant: I'll be happy to help you. What happens when you pass 5 as `count` to the function `fibonacci(5)`?
+	<alt>Happy to help. Can you give me an example of your function returning an incorrect number?
+	<alt>Sure. Can you list the first 5 numbers in the Fibonacci sequence?
+	<alt>Can you describe what your code does line by line?
+User: When I run the function with `n` as 5 the output is 8 instead of 5.
+Assistant: I see. What do you think might be the cause of this?
+	<alt>Can you describe your for loop on line 11?
+	<alt>Can you walk me through the steps your function takes to generate the Fibonacci sequence?
+	<alt>Can you identify any issues with the loop that generates the Fibonacci sequence?
+	<alt>Which part of your code do you suspect of causing this issue?
+User: I guess maybe the problem is that `a` is set to `0` not `1`? I am not really sure.
+	<alt>I am not sure. Can you help?
+	<alt>I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return.
+Assistant: Let's focus on the loop. Can you describe what your for loop is doing on line 11?
+	<alt>Can you describe how many times the for loop iterates on line 11?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+User: The loop iterates depending on the value of `n`. Not really sure what else to say here.
+	<alt>Not really sure how to describe it.
+	<alt>It loops `n` times
+	<alt>The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.
+Assistant: Can you describe how many times the for loop iterates on line 11?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+User: The for loop loops from 1 until value of `n` for `n - 1` times
+Assistant: Let's verify that.  How can we monitor the value of  `i` during the loop?
+	<alt>How can we verify that?
+	<alt>Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration to verify that. After executing the code what do you notice?
+	<alt>To verify let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>Let's verify that.  How can we monitor the values of `a`, `b`, and `i` during the loop?
+User: I'm not really sure can you suggest a way?
+	<alt>I can add print statements.
+	<alt>I can use the debugger perhaps.
+Assistant: Have you thought about adding a print statement to print the value of `i` at each iteration?
+	<alt>Have you considered using the debugger to track the value of `i` at each iteration?
+User: Ah yes good idea. Let me do that.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      print(i)
+13.      temp = b
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Let's examine the values of `i`. How many times in total does the for loop iterate?
+User: Observing the terminal output, I notice that the for loop iterates 5 times when `n` is  5 and the values of `n` range from 0 to 4 or `n - 1`. I thought it loops from 1 to `n`.
+Assistant: If your for loop is iterating more than you expected how might that impact the returned value?
+	<alt>Good. Let's go through the debugger again and track `a`, `b`, and `i` at each iteration. What do you notice?
+User: If it iterates one more time than I expected then it might be going to the next Fibonacci term in the sequence. So in our case 8 as opposed to 5!
+	<alt>Not really sure, maybe need to step through it to see how it affects the returned term.
+Assistant: Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+	<alt>Good. What should you do now to return the correct Fibonacci number?
+User: I think I should edit the range of the loop to iterate one less time and remove the print statement. Let me edit my code.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n - 1):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: Good work. Have you tried your code on all the example cases to make sure it works properly?
+User: Yes all looks correct! Thank you so much!
+Assistant: You are welcome. Let me know if I can be of any further assistance.
+User: Thank you!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/0_0_fibonacci_conversational_thread_3.txt

@@ -0,0 +1,199 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey, I really need help. This function is not returning the correct number.
+Assistant: I'll be happy to help you. What happens when you pass 5 as `count` to the function `fibonacci(5)`?
+	<alt>Happy to help. Can you give me an example of your function returning an incorrect number?
+	<alt>Sure. Can you list the first 5 numbers in the Fibonacci sequence?
+	<alt>Can you describe what your code does line by line?
+User: When I run the function with `n` as 5 the output is 8 instead of 5.
+Assistant: I see. What do you think might be the cause of this?
+	<alt>Can you describe your for loop on line 11?
+	<alt>Can you walk me through the steps your function takes to generate the Fibonacci sequence?
+	<alt>Can you identify any issues with the loop that generates the Fibonacci sequence?
+	<alt>Which part of your code do you suspect of causing this issue?
+User: I guess maybe the problem is that `a` is set to 0, not 1? I am not really sure.
+	<alt>I am not sure. Can you help?
+	<alt>I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return.
+Assistant: Let's focus on the loop. Can you describe what your for loop is doing on line 11?
+	<alt>Can you describe how many times the for loop iterates on line 11?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+User: The loop iterates depending on the value of `n`. Not really sure what else to say here.
+	<alt>Not really sure how to describe it.
+	<alt>It loops `n` times
+	<alt>The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.
+Assistant: Can you describe how many times the for loop iterates on line 11?
+	<alt>How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+	<alt>Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+User: The for loop loops from 1 until value of `n` for `n - 1` times
+Assistant: Let's verify that.  How can we monitor the value of  `i` during the loop?
+	<alt>How can we verify that?
+	<alt>Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration to verify that. After executing the code what do you notice?
+	<alt>To verify let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>Let's verify that.  How can we monitor the values of `a`, `b`, and `i` during the loop?
+User: I'm not really sure can you suggest a way?
+	<alt>I can add print statements.
+	<alt>I can use the debugger perhaps.
+Assistant: Have you thought about adding a print statement to print the value of `i` at each iteration?
+	<alt>Have you considered using the debugger to track the value of `i` at each iteration?
+User: Ah yes good idea. Let me do that. 
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      print(n)
+13.      temp = b
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Let's examine the values of `i`. How many times in total does the for loop iterate?
+User: Observing the terminal output, I notice that `i` is always 5 when `n` is 5. That doesn't make sense.
+Assistant: Are you sure that you are looking at the values of `i`? Examine line 12.
+	<alt>What variable are you printing on line 12?
+User: Oh whoops! Let me fix that.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      print(i)
+13.      temp = b
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Let's look at the terminal output. How many times does the for loop iterate?
+User: Observing the terminal output, I notice that the for loop iterates 5 times when `n` is  5, and the values of `n` range from 0 to 4 or `n - 1`.
+Assistant: Good. Can you identify other variables that might be important for us to track to identify the issue?
+	<alt>Let's add a print statement to print the values of `a`, `b` as well at each iteration to verify that. After executing the code what do you notice?
+	<alt>Let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>What would happen to the returned Fibonacci term if the for loop iterates 6 times?
+User: I think it would be good to track the variables `a` and `b` since I return `b` in the end and `a` is used to compute `b`.
+Assistant: Good. What do you think would be a good way for us to track the values of `a` and `b`?
+	<alt>Let's add a print statement to print the values of `a`, `b` as well at each iteration to verify that. After executing the code what do you notice?
+	<alt>Let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+User: I think I can add a print statement for these variables inside the for loop!
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      print(f"a: {a}\tb: {b}\t i: {i}")
+13.      temp = b
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Good. What do you observe about the values of `b` as the loop iterates?
+User: Hm, it seems like it is creating the Fibonacci sequence in the correct order. I don't notice anything off.
+Assistant: What do you notice about the last value of `b`?
+User: Oh! It's 8 which is what I am returning instead of 5! But why is that?
+Assistant: How was `b` computed in the final iteration of the for loop?
+User: I think `b` was 5 and `a` was 3 so  `b = 3 + 5` which is 8. Not sure how to get it to return 5 though.
+Assistant: What would happen to the returned Fibonacci sequence if the for loop iterates 6 times?
+	<alt>Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+User: Hm. I think it would `b = 5 + 8` which is 13 the next number in the Fibonacci sequence.
+Assistant: Do you notice a relationship between the number of for loop iterations and the Fibonacci term returned?
+User: Yes! I do think that the more the loop iterates the larger the Fibonacci term is returned. Maybe my for loop is iterating more than it should.
+Assistant: Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+User: I think I should edit the range of the loop to iterate one less time. Let me edit my code and remove my print statement.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: Good work. Have you tried your code on all the example cases to make sure it works properly?
+User: Yes all is correct thank you so much!
+Assistant: You are welcome. Let me know if I can help with anything else!
+User: Thank you so much!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/0_0_fibonacci_socratic_dialogue.txt

@@ -0,0 +1,158 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(0, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 11, the for loop iterates `n` times. Consequently, the function returns the (n+1)th term of the Fibonacci sequence instead of the nth term, as the loop generates one additional term beyond the desired nth term.
+</bug_desc>
+<bug_fixes>
+Replace `range(0, n)` with `range(1, n)` on line 11.
+Replace `range(0, n)` with `range(0, n - 1)` on line 11.
+Replace `range(0, n)` with `range(2, n + 1)` on line 11.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+The student is a beginner to an intermediate programmer who is familiar with basic programming concepts but may still struggle with some details, such as loop iteration.
+</stu_desc>
+<dialogue>
+User: Hey, I really need help. This function is not returning the correct number.
+Assistant: I'll be happy to help you. What happens when you call `fibonacci(5)`?
+	<alt>Happy to help. Can you give me an example of your function returning an incorrect number?
+	<alt>Sure. Can you list the first 5 numbers in the Fibonacci sequence?
+	<alt>Can you describe what your code does line by line?
+User: When I run the function with `n` as 5 the output is 8 instead of 5.
+Assistant: I see. What do you think might be the cause of this?
+	<alt>Can you describe your for loop on line 11?
+	<alt>Can you walk me through the steps your function takes to generate the Fibonacci sequence?
+	<alt>Can you identify any issues with the loop that generates the Fibonacci sequence?
+	<alt>Which part of your code do you suspect of causing this issue?
+User: I think the cause of this is probably the for loop since that's the only place where I compute `b`, the value that I return.
+	<alt>I am not sure. Can you help?
+	<alt>I guess maybe the problem is that `a` is set to 0 not 1? I am not really sure.
+Assistant: Good. Can you explain your for loop on line 11?
+	<alt>What specifically about your for loop on line 11 might be causing the issue?
+	<alt>Good. Can you describe how many times the for loop iterates on line 11?
+	<alt>Good. How many iterations does the for loop go through and what are the values of `a` and `b` in each iteration?
+	<alt>Good. What variables used in the for loop on line 11 should we pay attention to identify the issue?
+	<alt>Good. Can you take a closer look at the range of your for loop and think about how it might be affecting the result?
+User: The for loop loops from 0 until value of `n - 1`. In each iteration of the for loop, the loop computes a new Fibonacci number by adding the last two Fibonacci numbers together. This newly computed Fibonacci number is stored in `b` while the previous Fibonacci number (which was stored in `b` before the computation) is now stored in `a`.
+	<alt>It loops `n` times
+	<alt>Not really sure how to describe it.
+Assistant: Good, let's examine the loop together. How can we monitor the values of `a`, `b`, and `i` during the loop?
+	<alt>What are the values of `a` and `b` in each iteration?
+	<alt>What variables used in the for loop on line 11 should we pay attention to identify the issue?
+	<alt>Let's step through the function using the debugger and track `a`, `b`, and `i` at each iteration. What do you notice?
+	<alt>Let's add a print statement to print the values of `a`, `b`, and `i` after each iteration. After executing the code what do you notice?
+User: I'm not really sure can you suggest a way?
+	<alt>I can use the debugger!
+	<alt>I can add print statements.
+Assistant: Have you considered inserting a print statement after line 12 to output the 3 variables?
+	<alt>Have you considered using the debugger?
+User: Aha! Good idea! Perfect let me do that.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.   b = 1
+11.   for i in range(0, n):
+12.      temp = b
+13.      print(f"a: {a}\tb: {b}\t i: {i}")
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Let's look at the outputs what do you observe?
+User: I observe that `b` starts at 1 and `a` at  0 in the first iteration. `a` basically stores the value of `b` in the previous iteration.  Ultimately, at  `i = 0` `b = 0 + 1` then  at `i = 1` it is `b = 1 + 1` then at `i = 2` it is `b = 1 + 2` then at `i = 3` it is `b = 2 + 3` and at last  when `i = 4` it is `b = 3 + 5` returning 8.
+	<alt>It seems like the for loop is iterating one extra time. we want it to stop at `i = 3` where `b` is 5.
+	<alt>Hm, it seems like it is creating the Fibonacci sequence in the correct order. I don't notice anything off.
+Assistant: What do you notice about the value of `b`? Does it ever hold the correct Fibonacci term?
+	<alt>Good. Can you identify the point at which the loop should stop to get the correct Fibonacci number?
+User: We would want the for loop to stop at `i = 3` and return `b` as 5, but it iterates one more time since `3 <  5` which is the value of `n`.
+Assistant: Good observation. Can you think of a way to modify your for loop so that it returns the correct Fibonacci term?
+	<alt>Good. What should you do now to return the correct Fibonacci number?
+User: I think I should edit the range of the loop to iterate one less time. Let me edit my code.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b
+13.      print(f"a: {a}\tb: {b}\t i: {i}")
+14.      b = a + b
+15.      a = temp
+16.    return b
+
+</code>
+Assistant: Good work. Don't forget to remove the print statement!
+User: Ah yes! Thank you so much for your help!
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.     a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b
+13.      b = a + b
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: You are welcome. Let me know if you have any further questions.
+User: Thanks again! Goodbye!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/0_2_fibonacci_conversational_thread_1.txt

@@ -0,0 +1,91 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n < 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 2, the function only checks if `n` is less than `0` and then returns `OOPS`. When `n` is 0 the function returns `1` which is incorrect. The function should instead return `'OOPS'` when `n` is equal to `0`. 
+</bug_desc>
+<bug_fixes>
+Replace `if n < 0` with `if n <= 0` on line 2.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello. I need help with my code.
+	<alt>Hello! I need help on this my code is failing the first test case.
+Assistant: Let's start with a warm-up question. Consider the statement `x = 0`. What is the value of `y` in the following statement: `y = 1 if x < 0 else 0`?
+	<alt>Can you walk me through your code step by step given that `n` is 0?
+	<alt>Do you observe anything different about the first test case that might cause your code to output an incorrect result when compared with the rest of the test cases?
+	<alt>Can you describe the issue you are facing? Is your code failing any test cases?
+	<alt>Let's look at the `fibonacci` problem description. Given that `n` is 0. What should the `fibonacci` function return?
+User: Hm... I've never seen assignment being done like this before. I presume it would be a compiler error?
+	<alt>I think the value of `y` will be 0 because `x` is 0 and 0 < 0 is `False` so `else 0` will execute.
+Assistant: Let's verify that. Can you open a Python terminal and type in `x = 0` then on a new line `y = 1 if x < 0 else 0`. What do you observe?
+User: Ah. It works! I learned something new today.
+Assistant: What do you think the value of `y` is?
+User: I think the value of `y` will be 0 because `x` is 0 and 0 < 0 is `False` so `else 0` will execute.
+Assistant: Good. Let's look at your `fibonacci` function. Given that `n` is 0. Can you walk me through your code step by step?
+	<alt>Let's verify that. Can you print `y`? What do you observe?
+	<alt>Good. Let's look at your `fibonacci` function. Given that `n` is 0. What does the if statement on line 2 evaluate to?
+	<alt>Good. Let's look at the `fibonacci` problem description. Given that `n` is 0. What should the `fibonacci` function return?
+User: On line 2 `n < 0` evaluates to `False`, additionally the if statement conditions evaluate to `False` on lines 4 and 6, so it goes to line 9 the for loop on line 11 does not execute. So it returns 1 instead of "OOPS". I see the issue is the condition on line 2. Let me fix it.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+
+</code>
+Assistant: Good. Did you try running your code through all the test cases?
+User: Yes. Thank you very much for your help!
+Assistant: You're welcome.
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/0_2_fibonacci_socratic_dialogue.txt

@@ -0,0 +1,78 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.  if n < 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+</bug_code>
+<bug_desc>
+On line 2, the function only checks if `n` is less than `0` and then returns `OOPS`. When `n` is 0 the function returns `1` which is incorrect. The function should instead return `'OOPS'` when `n` is equal to `0`. 
+</bug_desc>
+<bug_fixes>
+Replace `if n < 0` with `if n <= 0` on line 2.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I need help on this my code is failing the first test case.
+	<alt>Hello. I need help with my code.
+Assistant: Can you walk me through your code step by step given that `n` is 0?
+	<alt>Let's start with a warm-up question. Consider the statement `x = 0`. What is the value of `y` in the following statement: `y = 1 if x < 0 else 0`?
+	<alt>Do you observe anything different about the first test case that might cause your code to output an incorrect result when compared with the rest of the test cases?
+User: `n < 0` evaluates to `False`, additionally the if statement conditions evaluate to `False` on lines 4 and 6, so it goes to line 9 the for loop on line 11 does not execute. So it returns 1 instead of "OOPS". I see the issue is the condition on line 2. Let me fix it.
+<code>
+1. def fibonacci(n):
+2.  if n <= 0:
+3.    return "OOPS"
+4.  elif n == 1:
+5.    return 1
+6.  elif n == 2:
+7.    return 1
+8.  else:
+9.    a = 0
+10.    b = 1
+11.    for i in range(1, n):
+12.      temp = b 
+13.      b = a + b 
+14.      a = temp
+15.    return b
+</code>
+Assistant: Good. Did you try it for all the unit tests?
+User: Yes I have. Thank you so much for your help!
+Assistant: You're welcome!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/0_5_fibonacci_conversational_thread_1.txt

@@ -0,0 +1,79 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>Can you explain what infinite recursion means?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+User: The previous two positions.
+	<alt>The numbers at positions n - 1 and n - 2.
+	<alt>The numbers at positions n - 1 and n - 2. Ah, now I see, I made a mistake on line 7, I used the wrong positions there. Let me fix it... It works now, thank you!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n-1) + fibonacci(n-2)
+
+</code>
+Assistant: Correct. Since the current position is `n`, what are the previous two positions?
+	<alt>That is correct. Looking at your code, does it really add the Fibonacci numbers at the previous two positions?
+User: Ah, now I see what the problem is. The code on line 7 adds the number at the current position, instead of positions `n - 1` and `n - 2`. Let me fix that... it works! Thank you!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 1) + fibonacci(n - 2)
+</code>
+Assistant: You are welcome, happy to help.
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/0_5_fibonacci_conversational_thread_2.txt

@@ -0,0 +1,84 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: Can you explain what infinite recursion means?
+	<alt>I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+User: Infinite recursion means that the function calls itself without ever stopping.
+	<alt>I am not sure, can you explain infinite recursion to me?
+Assistant: Correct. Where in the code does the function call itself?
+	<alt>Good. Given that the problem is caused by the function calling itself forever, where in the code do you think the problem is?
+User: It is on line 7.
+Assistant: Correct. There are two recursive calls there, can you figure out which of them leads to infinite recursion?
+	<alt>Correct. So, when the function is called as `fibonacci(n)`, if it gets to line 7 it calls `fibonacci(n)` again, and if that is completed it then calls `fibonacci(n - 1)`. Do you see why this leads to infinite recursion?
+User: Ah, I see. It is the call to `fibonacci(n)`, because `fibonacci(n)`calls `fibonacci(n)`which will again call `fibonacci(n)`, forever.
+	<alt>Ah, I see, it is the call to `fibonacci(n)`. I made a mistake, I should have called fibonacci for `n - 1` and `n - 2`. Let me do that ... it works! Thank you!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 2) + fibonacci(n - 1)
+</code>
+Assistant: Good! That means the code on line 7 is not correct. Can you look at the problem description to see how the Fibonacci number at position `n` needs to be computed and fix your code?
+	<alt>Good! Can you fix the code in line 7 so that it implements what is in the problem description?
+User: Ah, I see now, the previous two numbers are at positions `n - 1` and `n - 2`. Let me fix that... it works now! Thank you!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 1) + fibonacci(n - 2)
+</code>
+Assistant: You are welcome!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/0_5_fibonacci_conversational_thread_3.txt

@@ -0,0 +1,65 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+	<alt>I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>Can you explain what infinite recursion means?
+User: We get the Fibonacci number for `n + 1`. Ah, I see what the problem is, I used the wrong inputs in the recursive calls. Let me fix that... it works, it passes all the tests now. Thank you!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 2) + fibonacci(n - 1)
+</code>
+	<alt>We get the Fibonacci number for `n + 1`.
+Assistant: You're welcome!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/0_5_fibonacci_socratic_dialogue.txt

@@ -0,0 +1,88 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n) + fibonacci(n-1)
+</bug_code>
+<bug_desc>
+`fibonacci(n)` calls `fibonacci(n)` on line 7 with the same argument `n` which leads to infinite recursion and consequently a runtime error is thrown.
+</bug_desc>
+<bug_fixes>
+Replace `fibonacci(n) + fibonacci(n-1)` with `fibonacci(n-1) + fibonacci(n-2)` on line 7.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code returns a runtime error about infinite recursion, whenever I give it an input number greater than 2. Can you help?
+Assistant: I assume this means you tried it with values 1 and 2 for the input `n` and it worked. Given this, which line in the code do you think is responsible for the runtime error?
+	<alt>According to the problem description, the nth number in the Fibonacci sequence should be equal to the sum of Fibonacci numbers at what positions?
+	<alt>According to the definition of Fibonacci numbers given in the problem description, how is the number at position `n` computed?
+	<alt>Can you explain what infinite recursion means?
+	<alt>Assume that the input `n` is 3. Can you tell me what the code does in this case, by going over it line by line?
+	<alt>Given the error is about 'infinite recursion', can you tell me where recursion happens in your code?
+	<alt>Can you explain what a recursive function is? When do we call a function recursive?
+	<alt>According to the problem description, every Fibonacci number is the sum of the previous two numbers in the sequence. Therefore, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`?
+User: I believe it is line 7, because that is the line that is executed when `n` is larger than 2.
+Assistant: That is correct. Assume that the input `n` is 3, so the initial function call is `fibonacci(3)`. Can you tell me what is the first thing that happens in line 7 in this case?
+	<alt>Correct. So, when `fibonacci(n)` is evaluated, if n is larger than 2, line 7 is executed. What is the first thing that happens on line 7?
+	<alt>Correct. According to the problem description, what Fibonacci number do you get if you add the numbers at positions `n` and `n - 1`, as you do on line 7?
+User: Well, the function is called recursively to compute `fibonacci(3)`.
+	<alt>Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`.
+	<alt>Well, the function is called recursively to compute `fibonacci(3)`. Ah, I see now! When `n` is 3,  `fibonacci(3)` calls itself again on line 7 with the same value 3, and this leads to an infinite number of calls to `fibonacci(3)`. Oh, this is because I used the wrong parameters for the recursive calls. Let me fix it...
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 1) + fibonacci(n - 2)
+
+</code>
+	<alt>The call `fibonacci(n)`.
+Assistant: So, when you call `fibonacci(3)`, the code gets to line 7 where the first thing that happens is a new call to `fibonacci(3)`. What do you think happens when this new `fibonacci(3)` call is executed, line by line?
+	<alt>Do you see now why infinite recursion happens?
+	<alt>So, when you call `fibonacci(3)`, eventually it gets to line 7 where `fibonacci(3)` is called again. Do you see now why infinite recursion happens?
+User: Well, since n is 3, line 7 is executed again, which means that `fibonacci(3)` is evaluated again. I think I got it, `fibonacci(n)` calls itself recursively with the same parameter `n`, which leads to infinite recursion. I made mistake, I should have added the previous Fibonacci numbers, which are those at positions `n - 2` and `n - 1`. Let me try it... it works!
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    else:
+7.        return fibonacci(n - 2) + fibonacci(n - 1)
+
+</code>
+Assistant: Great, your program now works as expected!
+User: Thank you so much!
+Assistant: You are welcome!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/0_6_fibonacci_conversational_thread_1.txt

@@ -0,0 +1,82 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 and n == 2:
+5.        return 1
+6.    elif n > 2:
+7.        a = 1
+8.        b = 1
+9.        for i in range(3, n+1):
+10.            c = a + b
+11.            a = b
+12.            b = c
+13.        return b
+</bug_code>
+<bug_desc>
+On line 4, the function checks whether `n` is equal to `1` and `2` at the same time, which is not possible. Consequently, the function will never return `1` as specified by the instructions.
+</bug_desc>
+<bug_fixes>
+Replace `and` with `or` on line 4.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, my program passes all test cases except the second and third. Can you help?
+Assistant: Hi! Sure, what does the problem description say about these two cases?
+	<alt>Hi! Sure, what is the value of `n` in these two cases?
+	<alt>Hi! Sure, these two cases are exception cases according to the problem description. Where have you handled this exception?
+	<alt>Hi! Sure, what is the output supposed to be for each of these cases?
+User: It says to return 1 when `n` is equal to `1` and when `n` is equal to `2`
+Assistant: So will it return `1` when `n` is only equal to `1`?
+	<alt>Will `n` ever be `1` and `2` at the same time?
+User: No, it looks like it will return `1` only when `n` is `1` and `2`.
+Assistant: Will that ever happen?
+	<alt>Is that what you are supposed to do according to the instructions?
+User: No, `n` can be either `1` or `2`, but never both `1` and `2`.
+Assistant: Correct! How do you check if `n` is `1` or `2` instead of both `1` and `2`?
+User: Will it look like this?
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    elif n > 2:
+7.        a = 1
+8.        b = 1
+9.        for i in range(3, n+1):
+10.            c = a + b
+11.            a = b
+12.            b = c
+13.        return b
+</code>
+Assistant: Correct, do you now see the difference between `or` and `and`?
+User: I see it now, `and` evaluates to true only when both cases are correct. But `or` evaluates to true if either of the cases are correct. Thank you for your help!
+Assistant: That is right, you are welcome!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/0_6_fibonacci_socratic_dialogue.txt

@@ -0,0 +1,88 @@
+<problem>
+Create a function `fibonacci(n:int)` that takes in a parameter `n`, an integer representing the number of terms in the Fibonacci sequence to generate, and returns:
+-  'OOPS', if `n` is less than or equal to 0 
+- `1`  if `n` is equal to `1`
+- `1` if `n` is equal to `2`
+- Otherwise, return the nth term of the Fibonacci sequence. A Fibonacci sequence is a sequence in which every number is the sum of the previous two numbers in the sequence. Example Fibonacci sequence: 1, 1, 2, 3, 5, 8, 13, 21, 34, 55 ....
+## Example Cases:
+```
+fibonacci(-3) => 'OOPS'
+fibonacci(0) => 'OOPS'
+fibonacci(1) =>1
+fibonacci(2) => 1
+fibonacci(5) => 5
+fibonacci(10) => 55
+```
+</problem>
+<bug_code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 and n == 2:
+5.        return 1
+6.    elif n > 2:
+7.        a = 1
+8.        b = 1
+9.        for i in range(3, n+1):
+10.            c = a + b
+11.            a = b
+12.            b = c
+13.        return b
+</bug_code>
+<bug_desc>
+On line 4, the function checks whether `n` is equal to `1` and `2` at the same time, which is not possible. Consequently, the function will never return `1` as specified by the instructions.
+</bug_desc>
+<bug_fixes>
+Replace `and` with `or` on line 4.
+</bug_fixes>
+<unit_tests>
+assert fibonacci(0) == 'OOPS'
+assert fibonacci(1) == 1
+assert fibonacci(2) == 1
+assert fibonacci(5) == 5
+assert fibonacci(-3) == 'OOPS'
+assert fibonacci(10) == 55
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi, my program passes all test cases except the second and third. Can you help?
+Assistant: Hi! Sure, what does the problem description say about these two cases?
+	<alt>Hi! Sure, what is the value of `n` in these two cases?
+	<alt>Hi! Sure, these two cases are exception cases according to the problem description. Where have you handled this exception?
+	<alt>Hi! Sure, what is the output supposed to be for each of these cases?
+User: I am not sure, how can I find that?
+	<alt>It says to return `1` when `n` is equal to `1` and when `n` is equal to `2`
+Assistant: What are the values of `n` for these two cases?
+	<alt>There are 3 exceptional cases according to the problem description. Do these two test cases fall under any of those exceptions?
+User: In the second test case, the value of `n` is `1` and in the third case `n` is `2`.
+Assistant: Correct, what are we supposed to return for these values of `n`?
+User: We are supposed to return `1`, and I handled these cases on lines 4 and 5.
+Assistant: Ok, when does line 4 evaluate to true?
+	<alt>Ok, for what value of `n` will line 5 be executed?
+User: It evaluates to true if `n` is `1` and if it is `2`
+Assistant: Will the value of `n` ever be `1` and `2` at the same time?
+User: No, it can be either `1` or `2`, but never both at the same time.
+	<alt>No, I see that it has to be either `1` or `2` instead of `1` and `2`. Is that the error?
+Assistant: Correct! It is either `1` OR `2`, does your if statement check for that?
+User: Oh, I see it now! Looks like my if statement will be true only when `n` is `1` and `2`, instead of when `n` is `1` or `2`. Will this be the correct approach?
+<code>
+1. def fibonacci(n):
+2.    if n <= 0:
+3.        return "OOPS"
+4.    elif n == 1 or n == 2:
+5.        return 1
+6.    elif n > 2:
+7.        a = 1
+8.        b = 1
+9.        for i in range(3, n+1):
+10.            c = a + b
+11.            a = b
+12.            b = c
+13.        return b
+</code>
+Assistant: That looks great! It now returns `1` when `n` is either `1` or `2`.
+User: Thank you for explaining the difference between `or` and `and`!
+Assistant: You're welcome!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/10_39_xnglxsh_conversational_thread_1.txt

@@ -0,0 +1,90 @@
+<problem>
+Create a method `toxNGLXSH(sen:str) -> str` that converts an English sentence to xNGLXSH in which every lowercase vowel is replaced with 'X', each uppercase vowel is replaced with 'x', every lowercase consonant is replaced with its uppercase version, and every uppercase consonant is replaced with its lowercase version.
+
+## Example Cases:
+```
+toxNGLXSH('English') => 'xNGLXSH'
+toxNGLXSH('hello there!') => 'HXLLX THXRX!'
+toxNGLXSH("My name is John!") => 'mY NXMX XS jXHN!'
+toxNGLXSH('To be or not to be!') => 'tX BX XR NXT TX BX!'
+toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') => 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+```
+</problem>
+<bug_code>
+1. def toxNGLXSH(sen):
+2.  vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
+3.  for i in vowels:
+4.      if i.islower():
+5.           sen.replace(i, "x")
+6.      else:
+7.           sen.replace(i, "X")
+8.  sen.swapcase()
+9.  return sen
+</bug_code>
+<bug_desc>
+On lines 5, 7, and 8, the calls `sen.replace` and `sen.swapcase` leave `sen` unchanged, because strings are immutable in Python. Consequently, the function returns `sen` as it is.
+</bug_desc>
+<bug_fixes>
+Replace `sen.swapcase()` with `sen = sen.swapcase()` on line 8 and on lines 5 and 7 change `sen.replace` to `sen = sen.replace`.
+</bug_fixes>
+<unit_tests>
+assert toxNGLXSH('English') == 'xNGLXSH'
+assert toxNGLXSH('hello there!') == 'HXLLX THXRX!'
+assert toxNGLXSH("My name is John!") == 'mY NXMX XS jXHN!'
+assert toxNGLXSH('To be or not to be!') == 'tX BX XR NXT TX BX!'
+assert toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') == 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I wrote a lot of code and nothing is working.
+Assistant: I'm here to help. Can you describe the problem you are having?
+     <alt>Can you walk me through your code line by line?
+     <alt>Let's start with a simple example. What is the output of your code when you run it with the input "English"?
+     <alt>What does the `.replace()` method do?
+     <alt>What does the `.swapcase()` method do?
+User: I wrote a lot of code that makes sense, but my input sentence isn't changing at all. It is the same sentence that I started with. What do I do?
+Assistant: What are some reasons it could be staying the same?
+     <alt>What does the `.replace()` method do and does it modify the original string?
+     <alt>What does the `.swapcase()` method do and does it modify the original string?
+User: I could have an issue in the for loop or the control flow where somehow none of the methods are actually being called. Otherwise, there might be an issue with the methods I'm using.
+	<alt>If I was using the string methods incorrectly or if I was using the wrong ones, it might not work.
+Assistant: Let's test each of these separately. How can you check whether the methods are being called?
+User: One way I could check this is by adding `print` statements right before the methods to make sure I'm reaching those parts of the code. It looks like I'm reaching each part, but the sentence isn't changing. I think I'm not using these methods properly.
+<code>
+ def toxNGLXSH(sen):
+  vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
+  for i in vowels:
+      if i.islower():
+           print("here1", sen)
+           sen.replace(i, "x")
+      else:
+           print("here2", sen)
+           sen.replace(i, "X")
+  print("here3", sen)
+  sen.swapcase()
+  return sen
+
+</code>
+Assistant: Is there an easy way to modify your code to verify whether your code is modifying the original string?
+     <alt>What makes you think that you are using the methods incorrectly?
+     <alt>Have you considered printing the output of the method calls to see if they are changing the string, for example, `print(sen.replace(i, "x"))`?
+     <alt>Have you considered assigning the output of the method calls to a variable?
+     <alt>Where can you learn more about how `.replace()` and `.swapcase()` work and how they are used?
+User: Hm, I guess I can just assign `sen` the output of the method calls, in case they don't do in-place changes. That works!
+     <alt>I could also just print the output of the method calls to see if they are changing the string.
+<code>
+ def toxNGLXSH(sen):
+  vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
+  for i in vowels:
+      if i.islower():
+           sen = sen.replace(i, "x")
+      else:
+           sen = sen.replace(i, "X")
+  sen = sen.swapcase()
+  return sen
+
+</code>
+Assistant: Great! let me know if you need more help.
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/10_39_xnglxsh_socratic_dialogue.txt

@@ -0,0 +1,75 @@
+<problem>
+Create a method `toxNGLXSH(sen:str) -> str` that converts an English sentence to xNGLXSH in which every lowercase vowel is replaced with 'X', each uppercase vowel is replaced with 'x', every lowercase consonant is replaced with its uppercase version, and every uppercase consonant is replaced with its lowercase version.
+
+## Example Cases:
+```
+toxNGLXSH('English') => 'xNGLXSH'
+toxNGLXSH('hello there!') => 'HXLLX THXRX!'
+toxNGLXSH("My name is John!") => 'mY NXMX XS jXHN!'
+toxNGLXSH('To be or not to be!') => 'tX BX XR NXT TX BX!'
+toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') => 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+```
+</problem>
+<bug_code>
+1. def toxNGLXSH(sen):
+2.  vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
+3.  for i in vowels:
+4.      if i.islower():
+5.           sen.replace(i, "x")
+6.      else:
+7.           sen.replace(i, "X")
+8.  sen.swapcase()
+9.  return sen
+</bug_code>
+<bug_desc>
+On lines 5, 7, and 8, the calls `sen.replace` and `sen.swapcase` leave `sen` unchanged, because strings are immutable in Python. Consequently, the function returns `sen` as it is.
+</bug_desc>
+<bug_fixes>
+Replace `sen.swapcase()` with `sen = sen.swapcase()` on line 8 and on lines 5 and 7 change `sen.replace` to `sen = sen.replace`.
+</bug_fixes>
+<unit_tests>
+assert toxNGLXSH('English') == 'xNGLXSH'
+assert toxNGLXSH('hello there!') == 'HXLLX THXRX!'
+assert toxNGLXSH("My name is John!") == 'mY NXMX XS jXHN!'
+assert toxNGLXSH('To be or not to be!') == 'tX BX XR NXT TX BX!'
+assert toxNGLXSH('The quick brown fox jumped over the lazy rabbit.') == 'tHX QXXCK BRXWN FXX JXMPXD XVXR THX LXZY RXBBXT.'
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I wrote a lot of code and nothing is working.
+Assistant: I'm here to help. Can you describe the problem you are having?
+     <alt>Can you walk me through your code line by line?
+     <alt>Let's start with a simple example. What is the output of your code when you run it with the input "English"?
+     <alt>What does the `.replace()` method do?
+     <alt>What does the `.swapcase()` method do?
+User: I wrote a lot of code that makes sense, but my input sentence isn't changing at all. It is the same sentence that I started with. What do I do?
+Assistant: What are some reasons it could be staying the same?
+     <alt>What does the `.replace()` method do and does it modify the original string?
+     <alt>What does the `.swapcase()` method do and does it modify the original string?
+User: If I was using the string methods incorrectly or if I was using the wrong ones, it might not work.
+	<alt>I could have an issue in the for loop or the control flow where somehow none of the methods are actually being called. Otherwise, there might be an issue with the methods I'm using.
+Assistant: Let's open up the Python terminal and try running `sen = "To"` and then `sen.replace("o", "X")`. What do you observe?
+     <alt>Let's open up the Python terminal and try running `sen = "English"` and then `sen.swapcase()`. What do you observe?
+User: Ok, I tried that, and it looks like it returns the modified string I expect `TX`.
+     <alt>Ok, I tried that, and it looks like it returns the modified string I want `x` when I run it but after that when I print `sen` after that it shows `To` again. Maybe this means that the change is being applied, but not stored anywhere. I will assign the output of the string methods to `sen`.
+Assistant: Good. Now let's try running `sen = sen.replace("o", "X")` and then `print(sen)`. What do you observe?
+     <alt>Good. Now let's try running `sen = sen.swapcase()` and then `print(sen)`. What do you observe?
+User: Ah. It looks like the string methods don't modify the original string. They return a new string with the changes applied. I need to assign the output of the string methods to `sen` so that the changes are saved. Let me try that.
+<code>
+def toxNGLXSH(sen):
+  vowels = ["a", "e", "i", "o", "u", "A", "E", "I", "O", "U"]
+  for i in vowels:
+      if i.islower():
+           sen = sen.replace(i, "x")
+      else:
+           sen = sen.replace(i, "X")
+  sen = sen.swapcase()
+  return sen
+
+</code>
+Assistant: That looks good! Why do you think it worked?
+User: It looks like applying the method to a variable doesn't save the output anywhere. I guess they create new strings instead of modifying the original string. We need to assign it to the original variable so that the new output is saved.
+Assistant: Good work!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/11_40_palindrome_conversational_thread_1.txt

@@ -0,0 +1,68 @@
+<problem>
+Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome("racecar") => True
+is_palindrome("hello") => False
+is_palindrome("hannah") => True
+is_palindrome("firetruck") => False
+is_palindrome("nice") => False
+is_palindrome("") => True
+```
+</problem>
+<bug_code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string = string:
+6.    return True
+7.  else:
+8.    return False
+</bug_code>
+<bug_desc>
+On line 5, the function throws a syntax error.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on line 5.
+</bug_fixes>
+<unit_tests>
+assert is_palindrome("racecar") == True
+assert is_palindrome("hello") == False
+assert is_palindrome("hannah") == True
+assert is_palindrome("firetruck") == False
+assert is_palindrome("nice") == False
+assert is_palindrome("") == True
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey! I have a compiler error here.
+Assistant: Ok, what error do you see?
+	<alt>Let's start with a warm-up exercise. How do you assign a value of 1 to a variable `x`?
+	<alt>What line is the compiler error pointing towards?
+User: It's giving me an error on my equality operator use.
+Assistant: I see. How do you assign a value of 1 to a variable `x`?
+	<alt>How do you assign an empty string to the variable `rev_string`?
+	<alt>How would you check if two  variables `x` and `y` are equivalent?
+	<alt>Can you recall what the assignment operator is?
+User: I use the `=` operator.
+Assistant: What are you trying to do in line 5?
+	<alt>How would you check if  two variables `x` and `y` are equivalent?
+User: Ah I see the problem now. I should use `==` instead of equals to check for equality. Let me edit my code.
+	<alt>I am trying to check if `rev_string` is equal to `string`.
+<code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string == string:
+6.    return True
+7.  else:
+8.    return False
+
+</code>
+Assistant: Looks good! Does it pass all the test cases now?
+User: Yes it does! Thank you so much!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/11_40_palindrome_conversational_thread_2.txt

@@ -0,0 +1,94 @@
+<problem>
+Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome("racecar") => True
+is_palindrome("hello") => False
+is_palindrome("hannah") => True
+is_palindrome("firetruck") => False
+is_palindrome("nice") => False
+is_palindrome("") => True
+```
+</problem>
+<bug_code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string = string:
+6.    return True
+7.  else:
+8.    return False
+</bug_code>
+<bug_desc>
+On line 5, the function throws a syntax error.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on line 5. 
+</bug_fixes>
+<unit_tests>
+assert is_palindrome("racecar") == True
+assert is_palindrome("hello") == False
+assert is_palindrome("hannah") == True
+assert is_palindrome("firetruck") == False
+assert is_palindrome("nice") == False
+assert is_palindrome("") == True
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm really stuck.
+Assistant: Okay, what do you think the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Is the code running?
+	<alt>Which part of the prompt are you working on?
+User: I don't know, it isn't running!
+	<alt>The code won't compile, so it isn't doing any of the test cases.
+	<alt>I'm not sure why it won't run, I've done all the steps in the prompt.
+Assistant: Let's go through it step by step and figure out why it won't run. Do you see any problems on line 1?
+	<alt>Let's go through it step by step and figure out why it won't run. What is the most complicated part of the code?
+	<alt>Is there anything in the prompt that you haven't added yet?
+User: No, I don't see any problems on line 1.
+Assistant: What does line 2 do?
+	<alt>Let's look at the loop on line 3, what does it do?
+	<alt>Examine the if statement on line 5, what happens during that part?
+User: Line 2 makes a variable called rev_string and sets it to an empty string.
+Assistant: Very good, let's look at the for loop next, do you see anything that would cause a problem running the code there?
+	<alt>Great, let's check the if-statement next, is there anything that could cause a problem there?
+	<alt>What operator indicates that is what is happening on line 2?
+User: I don't see any issues with the for-loop.
+Assistant: What does the for-loop do?
+	<alt>Okay, let's check the if-statement next, is there anything that could cause a problem there?
+	<alt>What is happening on the line inside the loop?
+User: It reverses the string by adding letters one at a time to an empty string.
+Assistant: Very good, let's look at the if-statement now. Do you see any problems with it?
+User: I don't see any problems.
+	<alt>Oh! I see it, I'm using the wrong operator on line 5!
+Assistant: Let's look at the first line of the if-statement, what is it supposed to be doing?
+	<alt>Let's look at the first line of the if-statement, what is being checked on this line?
+	<alt>Let's look at the first line of the if-statement, what operator is being used here?
+	<alt>Check the documentation, do you see any problems with your comparison?
+User: It's supposed to compare the input string with the reversed string.
+	<alt>Oh! I'm assigning string to rev_string!
+Assistant: Check that line carefully, what exactly is happening in line 5?
+	<alt>Let's look at the first line of the if-statement, what operator is being used here?
+	<alt>Check the documentation, do you see any problems with your comparison?
+	<alt>Check the documentation, what operator is used for comparison of two strings?
+User: Oh! I'm assigning string to rev_string instead of comparing them!
+Assistant: Very good, so what is the correct operator to use there?
+	<alt>What operator is used for comparison of two strings?
+<code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string == string:
+6.    return True
+7.  else:
+8.    return False
+</code>
+User: I've fixed it!
+Assistant: Great, does it pass all test cases?
+User: Yes it does! Thank you.
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/11_40_palindrome_conversational_thread_3.txt

@@ -0,0 +1,100 @@
+<problem>
+Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome("racecar") => True
+is_palindrome("hello") => False
+is_palindrome("hannah") => True
+is_palindrome("firetruck") => False
+is_palindrome("nice") => False
+is_palindrome("") => True
+```
+</problem>
+<bug_code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string = string:
+6.    return True
+7.  else:
+8.    return False
+</bug_code>
+<bug_desc>
+On line 5, the function throws a syntax error.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on line 5. 
+</bug_fixes>
+<unit_tests>
+assert is_palindrome("racecar") == True
+assert is_palindrome("hello") == False
+assert is_palindrome("hannah") == True
+assert is_palindrome("firetruck") == False
+assert is_palindrome("nice") == False
+assert is_palindrome("") == True
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Help! I'm really stuck.
+Assistant: Okay, what do you think the problem is?
+	<alt>Are any of the test cases passing?
+	<alt>Is the code running?
+	<alt>Which part of the prompt are you working on?
+	<alt>Let's start with a warm-up exercise. How do you assign a value of 1 to a variable `x`?
+	<alt>What line is the compiler error pointing towards?
+User: I don't know, it isn't running!
+	<alt>The code won't compile, so it isn't doing any of the test cases.
+	<alt>I'm not sure why it won't run, I've done all the steps in the prompt.
+Assistant: Let's go through it step by step and figure out why it won't run. Do you see any problems on line 1?
+	<alt>Let's go through it step by step and figure out why it won't run. What is the most complicated part of the code?
+	<alt>Is there anything in the prompt that you haven't completed yet?
+	<alt>I see. How do you assign a value of 1 to a variable `x`?
+	<alt>How do you assign an empty string to the variable `rev_string`?
+	<alt>How would you check if two  variables `x` and `y` are equivalent?
+	<alt>Can you recall what the assignment operator is?
+User: No, I don't see any problems on line 1.
+Assistant: What does line 2 do?
+	<alt>Let's look at the loop on line 3, what does it do?
+	<alt>Examine the if statement on line 5, what happens during that part?
+User: Line 2 makes a variable called rev_string and sets it to an empty string.
+Assistant: Very good, let's look at the for loop next, do you see anything that would cause a problem running the code there?
+	<alt>Great, let's check the if-statement next, is there anything that could cause a problem there?
+	<alt>What operator indicates that is what is happening on line 2?
+User: I don't see any issues with the for-loop.
+Assistant: What does the for-loop do?
+	<alt>Okay, let's check the if-statement next, is there anything that could cause a problem there?
+	<alt>What is happening on the line inside the loop?
+User: It reverses the string by adding letters one at a time to an empty string.
+Assistant: Very good, let's look at the if-statement now. Do you see any problems with it?
+User: I don't see any problems.
+	<alt>Oh! I see it, I'm using the wrong operator on line 5!
+Assistant: Let's look at the first line of the if-statement, what is it supposed to be doing?
+	<alt>Let's look at the first line of the if-statement, what is being checked on this line?
+	<alt>Let's look at the first line of the if-statement, what operator is being used here?
+	<alt>Check the documentation, do you see any problems with your comparison?
+User: It's supposed to compare the input string with the reversed string.
+	<alt>Oh! I'm assigning string to rev_string!
+Assistant: Check that line carefully, what exactly is happening in line 5?
+	<alt>Let's look at the first line of the if-statement, what operator is being used here?
+	<alt>Check the documentation, do you see any problems with your comparison?
+	<alt>Check the documentation, what operator is used for comparison of two strings?
+User: Oh! I'm assigning string to rev_string instead of comparing them!
+Assistant: Very good, so what is the correct operator to use there?
+	<alt>What operator is used for comparison of two strings?
+<code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string == string:
+6.    return True
+7.  else:
+8.    return False
+</code>
+User: I've fixed it!
+Assistant: Great, does it pass all test cases?
+User: Yes it does! Thank you.
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/11_40_palindrome_socratic_dialogue.txt

@@ -0,0 +1,73 @@
+<problem>
+Write a function called `is_palindrome(string:str) -> bool` that returns True if the string is a palindrome and False otherwise. A palindrome is a string that is the same when read forwards and backwards.
+## Example Cases:
+```
+is_palindrome("racecar") => True
+is_palindrome("hello") => False
+is_palindrome("hannah") => True
+is_palindrome("firetruck") => False
+is_palindrome("nice") => False
+is_palindrome("") => True
+```
+</problem>
+<bug_code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string = string:
+6.    return True
+7.  else:
+8.    return False
+</bug_code>
+<bug_desc>
+On line 5, the function throws a syntax error.
+</bug_desc>
+<bug_fixes>
+Replace `=` with `==` on line 5.
+</bug_fixes>
+<unit_tests>
+assert is_palindrome("racecar") == True
+assert is_palindrome("hello") == False
+assert is_palindrome("hannah") == True
+assert is_palindrome("firetruck") == False
+assert is_palindrome("nice") == False
+assert is_palindrome("") == True
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hey! I have a compiler error here.
+Assistant: Ok, what error do you see?
+	<alt>Let's start with a warm-up exercise. How do you assign a value of 1 to a variable `x`?
+	<alt>What line is the compiler error pointing towards?
+User: It's giving me an error on my equality operator use.
+Assistant: I see. How do you assign a value of 1 to a variable `x`?
+	<alt>How do you assign an empty string to the variable `rev_string`?
+	<alt>How would you check if two  variables `x` and `y` are equivalent?
+	<alt>Can you recall what the assignment operator is?
+User: I use the `=` operator.
+Assistant: What are you trying to do in line 5?
+	<alt>How would you check if  two variables `x` and `y` are equivalent?
+User: I am trying to check if `rev_string` is equal to `string`
+	<alt>Ah I see so I should use `==` instead of equals to check for equality. Let me edit my code.
+Assistant: You used `=` for variable assignment. Shouldn't there be a different operator for equality?
+	<alt>Let's check the documentation. What is the operator for equality?
+	<alt>Are you sure that `=` checks for equality? How can we verify that?
+	<alt>If we were to assume that `=` checks for equality, would that be consistent with the error you noticed?
+User: I thought that they were for both purposes but after checking, I think the `==` operator is used to check for equality in Python.
+<code>
+1. def is_palindrome(string):
+2.  rev_string = ''
+3.  for i in string:
+4.    rev_string = i + rev_string
+5.  if rev_string == string:
+6.    return True
+7.  else:
+8.    return False
+
+</code>
+Assistant: Looks good!
+User: Thank you so much!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/12_41_reversing_a_list_conversational_thread_1.txt

@@ -0,0 +1,68 @@
+<problem>
+Write a function `reverse_list(lst:List[any]) -> List[any]` that returns `lst` in reverse order.
+## Example Cases:
+```
+reverse_list([1, 2, 3]) => [3, 2, 1]
+reverse_list([1, 2, 3, 4, 5]) => [5, 4, 3, 2, 1]
+reverse_list([]) => []
+reverse_list(["Hi", "Hello", "Goodbye"]) => ["Goodbye", "Hello", "Hi"]
+```
+</problem>
+<bug_code>
+1. def reverse_list(lst):
+2.    return lst[-1:]
+</bug_code>
+<bug_desc>
+On line 2, the way the slice operator is used creates a list containing only the last element in `lst` instead of a list containing all the elements of `lst` in reverse order.
+</bug_desc>
+<bug_fixes>
+Replace `return lst[-1:]` with `return lst[::-1]` on line 2.
+</bug_fixes>
+<unit_tests>
+assert reverse_list([1, 2, 3]) == [3, 2, 1]
+assert reverse_list([1, 2, 3, 4, 5]) == [5, 4, 3, 2, 1]
+assert reverse_list([]) == []
+assert reverse_list(["Hi", "Hello", "Goodbye"]) == ["Goodbye", "Hello", "Hi"]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm trying to reverse the elements of a list but it's not working.
+Assistant: Can you describe how you're trying to reverse the list?
+	<alt>Can you describe the problem you're having in more detail?
+	<alt>Let's start with a simple example. What do you expect the output of `reverse_list([1, 2, 3])` to do?
+	<alt>Let's start with a warm-up question. What does the slicing operator `[-1:]` do?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+	<alt>Where can you learn more about how to reverse a list?
+User: Sure, I used the `[-1:]` slicing operator.
+Assistant: Can you describe what the `[-1:]` slicing operator does?
+	<alt>How do you think this reverses the list?
+	<alt>Do you notice a pattern in your function's outputs?
+	<alt>How does slicing work in Python?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+User: The `[-1:]` slicing operator should return a list in reverse order.
+	<alt>I think it should return a list in reverse order but it's returning the last element of the list instead.
+Assistant: What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+	<alt>Let's run your code through all the test cases. Do you notice a pattern in your function's outputs?
+	<alt>Let's open the terminal and run `[1, 2, 3][-1:]`. What do you observe?
+	<alt>Let's start with a simpler problem. How can you obtain the first element of the list `a = [1, 2, 3]`?
+User: It returns `[3]` instead of `[3, 2, 1]`. Hm... it seems to be returning the last element of the list instead of the whole list in reverse order.
+Assistant: Good. Say you have an array `a = [1, 2, 3]`. How can you obtain every other element? So, `[1, 3]`?
+	<alt>Let's start with a simple problem. How can you obtain the first element of the list `a = [1, 2, 3]`?
+	<alt>Good. So where can you learn more about how to reverse a list?
+	<alt>Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+User: For an input list `a`, we can get every other element by using `a[::2]`. So `a[::2]` should return `[1, 3]`.
+Assistant: Good. Given that `[-1:]` returns the last element in the list, how do we combine using `::` with `[-1:]` to get every element in reverse order?
+	<alt>Good. So where can you learn more about how to reverse a list?
+	<alt>Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+	<alt>Good. `::2` gives us every other element and `[-1:]` gives us the last element. How can we get every element in reverse order?
+User: Oh, I see. We can just get every element of the list in increments of -1. So `a[::-1]`. I'll update my code. It looks like it's working now
+<code>
+ def reverse_list(lst):
+    return lst[::-1]
+
+</code>
+Assistant: Great! Let me know if you run into any other problems!
+User: Thanks!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/12_41_reversing_a_list_socratic_dialogue.txt

@@ -0,0 +1,59 @@
+<problem>
+Write a function `reverse_list(lst:List[any]) -> List[any]` that returns `lst` in reverse order.
+## Example Cases:
+```
+reverse_list([1, 2, 3]) => [3, 2, 1]
+reverse_list([1, 2, 3, 4, 5]) => [5, 4, 3, 2, 1]
+reverse_list([]) => []
+reverse_list(["Hi", "Hello", "Goodbye"]) => ["Goodbye", "Hello", "Hi"]
+```
+</problem>
+<bug_code>
+1. def reverse_list(lst):
+2.    return lst[-1:]
+</bug_code>
+<bug_desc>
+On line 2, the way the slice operator is used creates a list containing only the last element in `lst` instead of a list containing all the elements of `lst` in reverse order.
+</bug_desc>
+<bug_fixes>
+Replace `return lst[-1:]` with `return lst[::-1]` on line 2.
+</bug_fixes>
+<unit_tests>
+assert reverse_list([1, 2, 3]) == [3, 2, 1]
+assert reverse_list([1, 2, 3, 4, 5]) == [5, 4, 3, 2, 1]
+assert reverse_list([]) == []
+assert reverse_list(["Hi", "Hello", "Goodbye"]) == ["Goodbye", "Hello", "Hi"]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I'm trying to reverse the elements of a list but it's not working.
+Assistant: Can you describe how you're trying to reverse the list?
+	<alt>Can you describe the problem you're having in more detail?
+	<alt>Let's start with a simple example. What do you expect the output of `reverse_list([1, 2, 3])` to do?
+	<alt>Let's start with a warm-up question. What does the slicing operator `[-1:]` do?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+	<alt>Where can you learn more about how to reverse a list?
+User: Sure, I used the `[-1:]` slicing operator.
+Assistant: Can you describe what the `[-1:]` slicing operator does?
+	<alt>How do you think this reverses the list?
+	<alt>Do you notice a pattern in your function's outputs?
+	<alt>How does slicing work in Python?
+	<alt>What happens when you run `reverse_list([1, 2, 3])`? What do you observe?
+User: I think it should return a list in reverse order but it's returning the last element of the list instead.
+	<alt>The `[-1:]` slicing operator should return a list in reverse order.
+Assistant: Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+	<alt>Let's start with a simple problem. How can you obtain the first element of the list `a = [1, 2, 3]`?
+	<alt>Good. So where can you learn more about how to reverse a list?
+	<alt>Good. Let's visit the Python documentation about slicing. Do you notice anything about reversing a list?
+    <alt>Good. Say you have an array `a = [1, 2, 3]`. How can you obtain every other element? So, `[1, 3]`?
+User: I see. Got it. I think I need to use the `[::-1]` slicing operator or I can use the `reversed()` method. I'll update my code. It looks like it's working now.
+<code>
+ def reverse_list(lst):
+    return lst[::-1]
+
+</code>
+Assistant: Great! Let me know if you run into any other problems!
+User: Thanks!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/13_42_limit_conversational_thread_1.txt

@@ -0,0 +1,71 @@
+<problem>
+Write a method `limitFinder(lst: List[int], limit: int) -> List[int]` that takes a list of numbers and a limit and returns a list of all the numbers in the list that are less than the limit.
+## Example Cases:
+```
+limitFinder([1, 2, 3, 4, 5], 3) => [1, 2]
+limitFinder([1, 5, 4, 3, 5], 6) => [1, 2, 3, 4, 5]
+limitFinder([100, 2, 145, 3,8], 0) => []
+limitFinder([-1, -3, -4, -2, -5], -3) => [-4, -5]
+limitFinder([], 0) => []
+```
+</problem>
+<bug_code>
+1. def limitFinder(lst, limit):
+2.  lst2 = []
+3.  for i in lst2:
+4.    if i < limit:
+5.      lst2.append(i)
+6.  return lst2
+</bug_code>
+<bug_desc>
+On line 3, the for loop attempts iterating through `lst2` which is empty. Consequently, the for loop does not iterate and the function returns an empty list.
+</bug_desc>
+<bug_fixes>
+Replace `lst2` with `lst` on line 3.
+</bug_fixes>
+<unit_tests>
+assert limitFinder([1, 2, 3, 4, 5], 3) == [1, 2]
+assert limitFinder([1, 5, 4, 3, 5], 6) == [1, 2, 3, 4, 5]
+assert limitFinder([100, 2, 145, 3,8], 0) == []
+assert limitFinder([-1, -3, -4, -2, -5], -3) == [-4, -5]
+assert limitFinder([], 0) == []
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My program seems to always return an empty list instead of a list of numbers, can you help?
+Assistant: Sure. Can you walk me through what each line does?
+	<alt>Sure. Can you tell me which list are you supposed to find the numbers from?
+	<alt>Sure, can you explain what line 3 does?
+	<alt>Sure. It looks like your for-loop is never executed. Do you know why?
+User: Line 2 - creates an empty list `lst2`, which will eventually store all the numbers that are less than the limit.
+Assistant: Ok, what about the next line?
+User: Line 3 - loops through all the numbers in `lst2`
+	<alt>It looks like line 3 loops through the wrong list! Is that the issue here?
+Assistant: How many times will the for loop execute?
+	<alt>Will the for loop ever be executed?
+	<alt>Is `lst2` empty?
+	<alt>Is that the list that you want to loop through?
+User: It will be executed the length of the `lst2` times.
+	<alt>It will execute 0 times because `lst2` is empty.
+	<alt>How do I find that out?
+Assistant: What is the length of `lst2`?
+	<alt>Is `lst2` the list that you want to loop over?
+User: It is 0, so does that mean the for loop is never executed?
+	<alt>It is 0, should I loop over `lst` instead?
+Assistant: Correct, how would you fix your for loop now?
+User: Should I be looping over `lst` instead?
+Assistant: Yes, what does the new code look like?
+	<alt>Yes.
+User: This code works, thank you!
+<code>
+1. def limitFinder(lst, limit):
+2.  lst2 = []
+3.  for i in lst:
+4.    if i < limit:
+5.      lst2.append(i)
+6.  return lst2
+</code>
+Assistant: You are welcome!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/13_42_limit_socratic_dialogue.txt

@@ -0,0 +1,65 @@
+<problem>
+Write a method `limitFinder(lst: List[int], limit: int) -> List[int]` that takes a list of numbers and a limit and returns a list of all the numbers in the list that are less than the limit.
+## Example Cases:
+```
+limitFinder([1, 2, 3, 4, 5], 3) => [1, 2]
+limitFinder([1, 5, 4, 3, 5], 6) => [1, 2, 3, 4, 5]
+limitFinder([100, 2, 145, 3,8], 0) => []
+limitFinder([-1, -3, -4, -2, -5], -3) => [-4, -5]
+limitFinder([], 0) => []
+```
+</problem>
+<bug_code>
+1. def limitFinder(lst, limit):
+2.  lst2 = []
+3.  for i in lst2:
+4.    if i < limit:
+5.      lst2.append(i)
+6.  return lst2
+</bug_code>
+<bug_desc>
+On line 3, the for loop attempts iterating through `lst2` which is empty. Consequently, the for loop does not iterate and the function returns an empty list.
+</bug_desc>
+<bug_fixes>
+Replace `lst2` with `lst` on line 3.
+</bug_fixes>
+<unit_tests>
+assert limitFinder([1, 2, 3, 4, 5], 3) == [1, 2]
+assert limitFinder([1, 5, 4, 3, 5], 6) == [1, 2, 3, 4, 5]
+assert limitFinder([100, 2, 145, 3,8], 0) == []
+assert limitFinder([-1, -3, -4, -2, -5], -3) == [-4, -5]
+assert limitFinder([], 0) == []
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My program seems to always return an empty list instead of a list of numbers, can you help?
+Assistant: Sure. Can you walk me through what each line does?
+	<alt>Sure. Can you tell me which list are you supposed to find the numbers from?
+	<alt>Sure, can you explain what line 3 does?
+	<alt>Sure. It looks like your for-loop is never executed. Do you know why?
+User: Line 2 - creates an empty list `lst2`, which will eventually store all the numbers that are less than the limit.
+Assistant: Ok, what about the next line?
+User: Line 3 - loops through all the numbers in `lst2`
+	<alt>It looks like line 3 loops through the wrong list! Is that the issue here?
+Assistant: How many numbers are in `lst2`?
+	<alt>Will the for loop ever be executed?
+	<alt>Is `lst2` empty?
+	<alt>How many times will the for loop execute?
+	<alt>Is that the list that you want to loop through?
+User: `Oh I see, `lst2` is empty, so the for loop is never executed.
+Assistant: Correct, how would you fix your for loop now?
+User: Should I be looping over `lst` instead?
+Assistant: Yes, what does the new code look like?
+User: This code works, thank you!
+<code>
+1. def limitFinder(lst, limit):
+2.  lst2 = []
+3.  for i in lst:
+4.    if i < limit:
+5.      lst2.append(i)
+6.  return lst2
+</code>
+Assistant: You are welcome!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/14_43_used_twice_conversational_thread_1.txt

@@ -0,0 +1,87 @@
+<problem>
+Write a function `isTwice(string:str, char:str) -> bool` that returns `True` if the character `char` appears exactly twice in the string `string`. Otherwise, it returns `False`.
+## Example Cases:
+```
+isTwice("hello", "l") => True
+isTwice("hello", "o") => False
+isTwice("hello", "h") => False
+isTwice("", "e") => False
+isTwice("I'm a string!", " ") => True
+isTwice("Hey, I'm a string!", " ") => False
+```
+</problem>
+<bug_code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return true
+9.  else:
+10.    return false
+</bug_code>
+<bug_desc>
+On line 8, the function throws a NameError since `true` is not a boolean value.
+</bug_desc>
+<bug_fixes>
+Replace `true` with `True` and `false` with `False` on lines 8 and 10.
+</bug_fixes>
+<unit_tests>
+assert isTwice("hello", "l") == True
+assert isTwice("hello", "o") == False
+assert isTwice("hello", "h") == False
+assert isTwice("", "e") == False
+assert isTwice("I'm a string!", " ") == True
+assert isTwice("Hey, I'm a string!", " ") == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! This code isn't working. Can you help?
+Assistant: Let's talk about boolean variables. Can you explain the difference between a boolean variable with the value of `False` versus a string variable with the value `"False"` is?
+	<alt>First, let's analyze how your program is behaving and why. Can you describe the issue that you are facing?
+	<alt>It seems that you have a `NameError` error in your code. Are you able to find where this error is?
+	<alt>Let's start with a warm-up question. What are the two possible values of a boolean variable in Python?
+User: Well, boolean and Strings are different data types. Booleans have a true or false value, and Strings are just written words.
+	<alt>a boolean true is written like `bool = True`, whereas a String variable is written as str = "True."
+	<alt>I don't think there is a difference. I think both boolean "true" and String "true" looks the same when you write the code. For example, str = true and bool = true.
+Assistant: Let's try an example. How would you declare a string variable "str" and initialize it to the value "true?"
+	<alt>What are the two possible values of a boolean variable in Python?
+User: String str = "true";
+	<alt>Wouldn't you want to use a boolean variable for that instead?
+	<alt>String str = true;
+	<alt>str = true
+	<alt>String str = True;
+Assistant: That's right! Now, how would you declare a boolean variable `bool` and initialize it to false?
+User: boolean bool = false;
+	<alt>boolean bool = False;
+	<alt>boolean bool = "False";
+	<alt>I don't see that we are using boolean variables in the code.
+Assistant: Programming languages are very sensitive to syntax. For example, String variables require the use of quotations around their input. Can you think of any similar constraints to boolean inputs?
+	<alt>Try looking at the Python documentation. Can you find the section where they describe the use of Boolean variables? How does it compare to what you wrote here?
+	<alt>Let's try that in the Python terminal. What happens when you type `bool = false`?
+User: Oh, I see. I was writing `bool = true` when I should have been writing `bool = True`. I am missing a capitalization.
+	<alt>I should be using 0 and 1 instead of false and true.
+	<alt>I can't think of any constraints.
+Assistant: Good! Can you find where you made this mistake in your code?
+	<alt>How can you edit your code to fix this error?
+User: Yes, I found it. I'm going to show you the changed code now.
+<code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return True
+9.  else:
+10.    return False
+
+</code>
+Assistant: Good work! Looks like you did it.
+User: Thank you!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/14_43_used_twice_socratic_dialogue.txt

@@ -0,0 +1,83 @@
+<problem>
+Write a function `isTwice(string:str, char:str) -> bool` that returns `True` if the character `char` appears exactly twice in the string `string`. Otherwise, it returns `False`.
+## Example Cases:
+```
+isTwice("hello", "l") => True
+isTwice("hello", "o") => False
+isTwice("hello", "h") => False
+isTwice("", "e") => False
+isTwice("I'm a string!", " ") => True
+isTwice("Hey, I'm a string!", " ") => False
+```
+</problem>
+<bug_code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return true
+9.  else:
+10.    return false
+</bug_code>
+<bug_desc>
+On line 8, the function throws a NameError since `true` is not a boolean value.
+</bug_desc>
+<bug_fixes>
+Replace `true` with `True` and `false` with `False` on lines 8 and 10.
+</bug_fixes>
+<unit_tests>
+assert isTwice("hello", "l") == True
+assert isTwice("hello", "o") == False
+assert isTwice("hello", "h") == False
+assert isTwice("", "e") == False
+assert isTwice("I'm a string!", " ") == True
+assert isTwice("Hey, I'm a string!", " ") == False
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I wrote this code and it isn't working. can you help me?
+Assistant: First, let's analyze how your program is behaving and why. Can you describe the issue that you are facing?
+	<alt>It seems that you have a `NameError` error in your code. Are you able to find where this error is?
+	<alt>Let's talk about boolean variables. Can you explain the difference between a boolean variable with the value of `False` versus a string variable with the value `"False"` is?
+	<alt>Let's start with a warm-up question. What are the two possible values of a boolean variable in Python?
+User: I have a syntax error. My code won't even compile.
+	<alt>I think it's a runtime error because it just stopped running.
+	<alt>Can you tell me what the different types of errors are? I don't remember.
+	<alt>It's a logic error, I think. That's the one that is the result of a grammatical error, right?
+Assistant: I see! Let's try to solve a simpler problem. Can you write a code snippet of assigning `True` to a boolean variable called 'var'?
+	<alt>Can you write a code snippet of assigning `False` to a boolean variable called 'var'?
+	<alt>Where is the syntax error located in your code? You look for the line number.
+	<alt>How do you know that it is a syntax error? What are the different types of errors?
+User: `var = True`
+	<alt>`var = true`
+	<alt>var = 1
+	<alt>var = "True"
+Assistant: That's right. Is this what you wrote in your code on line 8?
+	<alt>That's right. Can you look back at where you use boolean variables and see if you used the correct syntax?
+	<alt>Can you point out in your code where you use boolean variables?
+User: No it isn't. I see. Well... the is not a boolean variable anymore. The value you assign to the code determines what kind of data type it is. Since I did not write 'True' in this exact format, I imagine that the program had interpreted the value as a variable that hasn't been initialized instead.
+	<alt>The code would get a syntax error and it wouldn't run.
+	<alt>I'm not sure what you are asking.
+Assistant: That's right! How can you modify your `isTwice` function now to fix this error?
+User: Oh! I found it! I was returning all lowercase True and False values! I will fix it.
+<code>
+1. def isTwice(str, chr):
+2.  count = 0
+3.  for i in str:
+4.    if i == chr:
+5.      count+=1
+6.
+7.  if count >= 2:
+8.    return True
+9.  else:
+10.    return False
+
+</code>
+Assistant: Looks like it works now. Good job!
+User: Thanks!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/15_44_sequential_search_conversational_thread_1.txt

@@ -0,0 +1,68 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?
+Assistant: Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?
+	<alt>Sure. Can you tell me if you notice any difference between the first test case and the other test cases?
+	<alt>Sure. In the first test case, can you explain why the correct return value should be 1?
+	<alt>Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through the if on line 3?
+User: We should return the index of `x` in `seq`.
+Assistant: Good. How do you find the index of `x` in a list `seq`?
+	<alt>Good. Now, looking at your code, does it ever return an index `i` such that the element at that index is equal to `x`?
+	<alt>Good. If the current index is `i`, how do you determine if the element at position `i` in the list `seq` is equal to `x`?
+User: I go through all possible indexes, starting at 0, and check of `seq[i]` is equal to `x`.
+Assistant: Good. Can you add code to do that?
+User: Let me try... I did it and it works now. Thank you!
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x == seq[i]:
+4.      return i
+5.    if x < seq[i]:
+6.      return i
+7.  return len(seq)
+
+</code>
+	<alt>I did it, and now the first test case works well, but the others don't work anymore.
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x == seq[i]:
+4.      return i
+5.  return len(seq)
+
+</code>
+Assistant: You're welcome, happy to help!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/15_44_sequential_search_conversational_thread_2.txt

@@ -0,0 +1,54 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?
+Assistant: Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?
+	<alt>Sure. Can you tell me if you notice any difference between the first test case and the other test cases?
+	<alt>Sure. In the first test case, can you explain why the correct return value should be 1?
+	<alt>Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through the if on line 3?
+User: We should return the index of `x` in `seq`.
+Assistant: Good. Now, looking at your code, does it ever return an index `i` such that the element at that index is equal to `x`?
+	<alt>Good. How do you find the index of `x` in a list `seq`?
+	<alt>Good. If the current index is `i`, how do you determine if the element at position `i` in the list `seq` is equal to `x`?
+User: Oh, it always returns a position where `seq[i] > x`. I think I need to also test for equality, let me do that... It works now, thank you!
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+5.  return len(seq)
+
+</code>
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/15_44_sequential_search_conversational_thread_3.txt

@@ -0,0 +1,55 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?
+Assistant: Sure. In the first test case, can you explain why the correct return value should be 1?
+	<alt>Sure. Can you tell me if you notice any difference between the first test case and the other test cases?
+	<alt>Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?
+	<alt>Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through the if on line 3?
+User: Because the element at position 1 is equal to 5, and according to the problem description whenever the number is present in the input list we should return its position.
+Assistant: Good. Now, can you tell me what happens in your code for test example 1 when `i` takes the value 1? Start with line 3.
+	<alt>Good. Does your code ever test if the number `x` is present in the list?
+	<alt>Good. How can you determine, using code in Python, if a number `x` is present in a list `seq`?
+User: When `i` is 1, `seq[1]` is equal to 5. On line 3, since 5 is not less than 5, this means that line 4 is not executed, so we go back to line `2` where `i` is assigned the next value of 2. Ah, now I understand where the problem is,  I should have tested for equality too, let me do that ... It works now! Thank you!
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+5.  return len(seq)
+
+</code>
+Assistant: You are welcome!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/15_44_sequential_search_socratic_dialogue.txt

@@ -0,0 +1,54 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x < seq[i]:
+4.      return i
+5.  return len(seq)
+</bug_code>
+<bug_desc>
+On line 3, the function only checks if `x` is less than `seq[i]` and then returns the index `i` where `x` should be inserted. When `x` is in `seq` at position `i`, the function returns the next index `i + 1` instead of the current index `i`.
+</bug_desc>
+<bug_fixes>
+Replace `<` with `<=` on line 3
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code passes all tests but the first one, and I cannot figure out what's wrong. Can you help?
+Assistant: Sure. In the first test case, can you explain why the correct returned value should be 1?
+	<alt>Sure. Can you tell me if you notice any difference between the first test case and the other test cases?
+	<alt>Sure. In the first test case, the input `x` is an element in the list `seq`. According to the problem description, what needs to be returned when `x` is an element of `seq`?
+	<alt>Sure. Let's consider the first test case, when the input `x` is 5 and the list `seq` has the value `[-1, 5, 8, 10, 12]`. When `i` takes the value 1 in line 2, what is the value of `seq[i],` and what happens when we run through `if` on line 3?
+User: The correct answer is 1 because 5 is found at position 1 in the input list.
+Assistant: Good. So the input element `x = 5` is present at some position `i = 1` in the list `seq`. Does your code check for this?
+	<alt>Good. What does your code do when position `i = 1`?
+User: Ah, I see now. I should also check if `seq[i]` is equal to `x`. Let me do that... It works now, thank you!
+<code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+5.  return len(seq)
+
+</code>
+Assistant: You're welcome, glad I could help.
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/15_45_sequential_search_conversational_thead_1.txt

@@ -0,0 +1,61 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+</bug_code>
+<bug_desc>
+The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.
+</bug_desc>
+<bug_fixes>
+Insert a line following line 4, with one indentation containing `return len(seq)` 
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I seem to be having some issues with this function I am trying to implement. It sometimes returns `None` instead of an output. 
+Assistant: Can you walk me through how your function handles some simple examples? For example, `search(5, [-1, 5, 8, 10, 12])`.
+	<alt>Do you notice a pattern with the cases that produce `None`?
+	<alt>When do you notice `None` as the output?
+	<alt>What inputs have you tried? When do you get `None`?
+	<alt>It seems that your function may be returning nothing in certain cases. Can you think of a case where this might happen?
+User: For that example, I get an output of 1. I first iterate through the elements in the list and check when the 5 is less than or equal to the current element, which happens at index 1. 
+	<alt>This just gives an output of 1
+Assistant: I see. What happens when you have a larger `x` value? Try `search(20, [-1, 5, 8, 10, 12])`.
+	<alt>I see. What about when your `x` is not less than or equal to any elements?
+	<alt>That seems right. How do you deal with negative numbers and numbers greater than all the list elements?
+	<alt>Good. Is there a case where your function might not return anything?
+User: For that, my code seems to return `None`. I use the same procedure and iterate through the list element. Oh, I see. Since 20 is greater than all the current list elements, I never get to the `return`
+Assistant: It looks like you just need to handle that other case then. What's a good answer to return when `x` is greater than all the existing elements?
+	<alt>Where would you want to insert an element that is larger than all the current ones?
+	<alt>What's a good place to insert 20 in the example I gave you?
+User: I think I should put it at the end of the list. I'll update the code and see if it works.
+<code>
+ def search(x, seq):
+  for i in range(len(seq)):
+    if x <= seq[i]:
+      return i
+  return len(seq)
+
+</code>
+Assistant: Looks like it works! Let me know if you need more help
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/15_45_sequential_search_socratic_dialogue.txt

@@ -0,0 +1,61 @@
+<problem>
+Write a function `search(x: int, seq: List[int]) -> int` that returns the index of the first occurrence of `x` in `seq`. If `x` is not in `seq`, return the index where `x` should be inserted to keep `seq` sorted. Assume that `seq` is sorted in ascending order.
+## Example Cases:
+```
+search(5, [-1, 5, 8, 10, 12]) => 1
+search(-2, [-1, 57, 65]) => 0
+search(0, [-120, 60, 78, 100]) => 1
+search(77, [-100, -50, 5, 44, 66, 76, 99]) => 6
+search(55, [-99, -2, 0]) => 3
+```
+</problem>
+<bug_code>
+1. def search(x, seq):
+2.  for i in range(len(seq)):
+3.    if x <= seq[i]:
+4.      return i
+</bug_code>
+<bug_desc>
+The function returns `None` when `x` is greater than all of the elements in `seq` instead of returning the index indicating that `x` should be inserted at the end of the array.
+</bug_desc>
+<bug_fixes>
+Insert a line following line 4, with one indentation containing `return len(seq)` 
+</bug_fixes>
+<unit_tests>
+assert search(5, [-1, 5, 8, 10, 12]) == 1
+assert search(-2, [-1, 57, 65]) == 0
+assert search(0, [-120, 60, 78, 100]) == 1
+assert search(77, [-100, -50, 5, 44, 66, 76, 99] ) == 6
+assert search(55, [-99, -2, 0]) == 3
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I seem to be having some issues with this function I am trying to implement. It sometimes returns `None` instead of an output. 
+Assistant: What inputs have you tried? When do you get `None`?
+	<alt>Do you notice a pattern with the cases that produce `None`?
+	<alt>When do you notice `None` as the output?
+	<alt>What inputs have you tried? When do you get `None`?
+	<alt>It seems that your function may be returning nothing in certain cases. Can you think of a case where this might happen?
+User: I tried a lot of examples. One that worked correctly was `search(-2, [-1, 57, 65])`, but I got `None` when I tried `search(80, [-1, 57, 65])`.
+	<alt>I tried a few different ones. It looks like answers are only incorrect when `x` is really big relative to the numbers in the list
+	<alt>It seems like I get the wrong answer when `x` is bigger than all the existing list elements
+Assistant: Interesting. Can you walk me through what `search(80, [-1, 57, 65])` looks like at each line of your code? What would you expect as the output?
+	<alt>Compare and contrast the successful example `search(-2, [-1, 57, 65])` with the failing example `search(80, [-1, 57, 65])` where your function returns None. Does anything about `x` and `seq` in these examples stand out to you?
+	<alt>What do you expect your code to return when `x` is bigger than the `seq` elements?
+User: Sure! So, first, we iterate through the list elements. At each element, we check if `x` is less than or equal to it. In that case, we would want to insert at that index, so we return the index.
+Assistant: What happens if `x` is not less than or equal to any element?
+	<alt>What does your code do if `x` is greater than all of the elements in `seq`?
+User: I guess it doesn't return anything. I should add a case for that. Now that I've modified it, it seems to work!
+<code>
+ def search(x, seq):    
+  for i in range(len(seq)):
+    if x <= seq[i]:
+      return i
+  return len(seq)
+
+</code>
+Assistant: Good work. Let me know if you have any other questions.
+User: Thanks!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/16_46_substring_length_conversational_thread_1.txt

@@ -0,0 +1,108 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: I don't know what the code finds as the longest substring, how can I determine that?
+	<alt>The longest substring is 'dabra' and I think this is also what my code finds.
+Assistant: Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)` and run your code on the first test example?
+	<alt>Can you add a new variable `max_str` that is updated with `crt_str` every time the `max_len` is updated in the if clause? Then print its value right before returning from the function.
+User: OK ... I did that. The code finds only the substring `abra`. Ah, now I see what the problem is, the maximum substring should be 'dabra'.
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        print('crt_str = ', crt_str)
+8.        crt_len = len(crt_str)
+9.        if crt_len > max_len:
+10.            max_len = crt_len
+11.        start = pos + len(t)
+12.        pos = s.find(t, start)
+13.    return max_len
+14.
+15.substr_len("abracadabra", "ca")
+
+</code>
+Assistant: That's correct. Can you now change your code so that is also considers the substring 'dabra'?
+	<alt>That's correct. What variable in your code stores the position where 'dabra' starts in `s`, and where does it end?
+User: OK. I think I need to look at the substring that starts at the last value of `start` and ends at the end of the string. Let me do that... It works now, thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.        
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.        max_len = last_len
+17.    
+18.    return max_len
+
+</code>
+	<alt>Not sure how to do that, can you help?
+Assistant: That's great! Glad I could help.
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/16_46_substring_length_conversational_thread_2.txt

@@ -0,0 +1,110 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: I don't know what the code finds as the longest substring, how can I determine that?
+	<alt>The longest substring is 'dabra' and I think this is also what my code finds.
+Assistant: Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)` and run your code on the first test example?
+	<alt>Can you add a new variable `max_str` that is updated with `crt_str` every time the `max_len` is updated in the if clause? Then print its value right before returning from the function.
+User: OK ... I did that. The code finds only the substring `abra`. Ah, now I see what the problem is, the maximum substring should be 'dabra'.
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        print('crt_str = ', crt_str)
+8.        crt_len = len(crt_str)
+9.        if crt_len > max_len:
+10.            max_len = crt_len
+11.        start = pos + len(t)
+12.        pos = s.find(t, start)
+13.    return max_len
+14.
+15.substr_len("abracadabra", "ca")
+
+</code>
+Assistant: That's correct. What variable in your code stores the position where 'dabra' starts in `s`, and where does it end?
+	<alt>That's correct. Can you now change your code so that is also considers the substring 'dabra'?
+User: I think it is the variable `start`, right before `pos` becomes -1. It should end where `s` ends.
+	<alt>I don't know, how can I find that?
+Assistant: Great. Now that you know where it starts and where it ends, can you add code that extracts this substring and looks at its length too?
+User: I did that, and it works now! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.        
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.        max_len = last_len
+17.
+18.    return max_len
+
+</code>
+Assistant: You're welcome, happy to help!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/16_46_substring_length_conversational_thread_3.txt

@@ -0,0 +1,117 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: I don't know what the code finds as the longest substring, how can I determine that?
+	<alt>The longest substring is 'dabra' and I think this is also what my code finds.
+Assistant: Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)` and run your code on the first test example?
+	<alt>Can you add a new variable `max_str` that is updated with `crt_str` every time the `max_len` is updated in the if clause? Then print its value right before returning from the function.
+User: OK ... I did that. The code finds only the substring `abra`. Ah, now I see what the problem is, the maximum substring should be 'dabra'.
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        print('crt_str = ', crt_str)
+8.        crt_len = len(crt_str)
+9.        if crt_len > max_len:
+10.            max_len = crt_len
+11.        start = pos + len(t)
+12.        pos = s.find(t, start)
+13.    return max_len
+14.
+15.substr_len("abracadabra", "ca")
+
+</code>
+Assistant: That's correct. What variable in your code stores the position where 'dabra' starts in `s`, and where does it end?
+	<alt>That's correct. Can you now change your code so that is also considers the substring 'dabra'?
+User: I don't know, how can I find that?
+	<alt>I think it is the variable `start`, right before `pos` becomes -1. It should end where `s` ends.
+Assistant: If you look at the test example, 'dabra' appears right after the last occurrence of `ca`. Which variable in your code computes that position?
+	<alt>Can you tell me what the variable `start` is supposed to do and how it is computed?
+	<alt>Which variable in your code computes the index right after the last occurrence of the string `t`?
+User: So it must be the sum between where `ca` starts, which is in `pos` and the length of `ca`, that is what `start` does.
+Assistant: Correct. Now, where does 'dabra' end?
+	<alt>Correct. Can you now write code to extract the string 'dabra' and consider it when computing the maximum length?
+User: It ends at the end of the input string `s`.
+Assistant: Correct. So it starts at the last value of `start` and ends at `len(s)`. Can you now write code to extract the string 'dabra' and consider it when computing the maximum length?
+User: Ok, I did that and it works now. Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.        
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.        max_len = last_len
+17.
+18.    return max_len
+
+</code>
+Assistant: Great, glad that I could be of help!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/16_46_substring_length_socratic_dialogue.txt

@@ -0,0 +1,87 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    return max_len
+</bug_code>
+<bug_desc>
+The code does not check for the case when the longest substring is at the end of the string, therefore it fails on test examples 1 and 5.
+</bug_desc>
+<bug_fixes>
+After line 11, insert the following outside the while loop scope:
+```py
+last_str = s[start:]
+last_len = len(last_str)
+if last_len > max_len:
+       max_len = last_len
+```
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I need help with my code, it does not work on some test examples such as the first one, and I do not understand why. Can you help?
+Assistant: I would be happy to. First, can you walk me through your code and explain what each variable is supposed to do?
+	<alt>Sure. Using the input for the first test example, can you go through your code line by line and show the values calculated for each variable?
+	<alt>Sure. Looking at the first test example, what is the longest substring your code finds and what is the correct substring?
+	<alt>Sure. Can you list all the correct longest substrings for the test examples and see if you notice anything special about test examples 1 and 5 on which your code returns the wrong result?
+	<alt>Sure. Inside the while block, right after line 6, can you include a print statement `print('crt_str = ', crt_str)`, run your code on the first test example, and see if you notice anything useful or missing about the strings extracted by your code?
+	<alt>Sure. Do you notice anything different about test examples 1 and 5 on which your code does not work?
+	<alt>Sure. Looking at the first test example, what is the correct longest substring and is there any variable in your code that stores that string at some point during its execution?
+User: `max_len` is a variable that stores the maximum length found so far, initialized with 0.  `start` stores the starting position in the input string `s` that we want to search for `t`, also initialized with 0. `pos` stores the position in the string `s` where the other string `t` is found. Inside the while loop, I have `crt_str` which stores the actual substring found between consecutive occurrences or `t` in `s`, with its length stored in `crt_len`. This substring is always between `start` and the current value of `pos`, which requires `start to be updated to contain the index right after the current occurrence of `t`.
+Assistant: Very good. So, you are saying then that the maximum length substring should be one of the strings computed in `crt_str` that are found between consecutive occurrences of `t` in `s`. Looking at test example 1, what is the correct maximum length substring and does it appear between consecutive occurrences or 'ca' in the input string?
+	<alt>Good. Do you think the maximum length substring always appears between consecutive occurrences of the string `t`?
+	<alt>Very good. If the maximum length substring appeared at the end of the string `s`, would your code extract it in `crt_str`?
+	<alt>Good. Can you tell me what is the last value that is assigned to `start` before `pos` becomes -1 and what is the substring of `s` that starts at that position?
+User: Ah, I see now. The maximum substring should be "dabra", which is between the last occurrence of `t` and the end of the string. I should have checked for substrings that end at the end of `s`, let me do that ... It works now! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        crt_len = len(crt_str)
+8.        if crt_len > max_len:
+9.            max_len = crt_len
+10.        start = pos + len(t)
+11.        pos = s.find(t, start)
+12.    
+13.    last_str = s[start:]
+14.    last_len = len(last_str)
+15.    if last_len > max_len:
+16.       max_len = last_len
+17.    
+18.    return max_len
+
+</code>
+Assistant: You're welcome, glad I could be of help!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/16_56_substring_length_conversational_thread_1.txt

@@ -0,0 +1,77 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Can you tell me the role of the variable `start`?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+User: `start` is supposed to indicate the position in `s` where we want to start searching for the next occurrence of `t`. Initially, we start searching from the start of the string, therefore it is initialized with 0.
+Assistant: OK. So, after you find the first occurrence of `t` at position `pos` in `s`, where do you want to start searching for the next occurrence of `t`?
+	<alt>OK. So the first value of `start` is 0, what is the next value of `start`?
+	<alt>OK. Can you run your code manually on the first test example and tell me what are the values that `start` takes in each iteration of the while loop?
+	<alt>OK. Does `start` ever change inside the while loop?
+User: Ah, I see the problem, I forgot to change `start` inside the while loop. Let me do that ... it works now. Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: Great, happy to help!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/16_56_substring_length_conversational_thread_2.txt

@@ -0,0 +1,77 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Can you tell me the role of the variable `start`?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+User: `start` is supposed to indicate the position in `s` where we want to start searching for the next occurrence of `t`. Initially, we start searching from the start of the string, therefore it is initialized with 0.
+Assistant: OK. Can you run your code manually on the first test example and tell me what are the values that `start` takes in each iteration of the while loop?
+	<alt>OK. So the first value of `start` is 0, what is the next value of `start`?
+	<alt>OK. So, after you find the first occurrence of `t` at position `pos` in `s`, where do you want to start searching for the next occurrence of `t`?
+	<alt>OK. Does `start` ever change inside the while loop?
+User: First, `start` is initialized with 0. Then `pos` becomes 4, then ... ah, I forgot to update `start` inside the loop. Let me try to fix that ... it works! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: You are welcome!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/16_56_substring_length_conversational_thread_3.txt

@@ -0,0 +1,77 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Can you tell me the role of the variable `start`?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+User: `start` is supposed to indicate the position in `s` where we want to start searching for the next occurrence of `t`. Initially, we start searching from the start of the string, therefore it is initialized with 0.
+Assistant: OK. Does `start` ever change inside the while loop?
+	<alt>OK. So the first value of `start` is 0, what is the next value of `start`?
+	<alt>OK. So, after you find the first occurrence of `t` at position `pos` in `s`, where do you want to start searching for the next occurrence of `t`?
+	<alt>OK. Can you run your code manually on the first test example and tell me what are the values that `start` takes in each iteration of the while loop?
+User: Ah, it doesn't! It stays equal to 0, which means that `pos` does not change either. Let me fix that... it works! Thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: You are welcome!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/16_56_substring_length_socratic_dialogue.txt

@@ -0,0 +1,72 @@
+<problem>
+Write a function `substr_len(s: str, t: str) -> int` that takes as input a string `s` and a non-empty string `t` and returns the length of the longest substring of `s` that does not contain `t`. For example, if `s = "abracadabra"` and `t = "ca"`, then the longest substring of `s` that does not contain `t` is `"dabra"`, so the function should return 5.
+## Example Cases:
+```
+substr_len("abracadabra", "ca") => 5
+substr_len("I love Python", "Py") => 7
+substr_len("contest", "test") => 3
+substr_len("icey ice", "ice") => 2
+substr_len("icey ice cream", "ice") => 6
+substr_len("abracadabra", "abba") => 11
+```
+</problem>
+<bug_code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+</bug_code>
+<bug_desc>
+The value of `start` never changes inside the while loop, thus `pos` which is computed based on `start` never changes either. Consequently, the while loop on line 5 never stops.
+</bug_desc>
+<bug_fixes>
+On line 8 insert the code `start = pos + len(t)`.
+</bug_fixes>
+On line 11 insert a new line with `ind += len(t)`.
+</bug_fixes>
+<unit_tests>
+assert substr_len("abracadabra", "ca") == 5
+assert substr_len("I love Python", "Py") == 7
+assert substr_len("contest", "test") == 3
+assert substr_len("icey ice", "ice") == 2
+assert substr_len("icey ice cream", "ice") == 6
+assert substr_len("abracadabra", "abba") == 11
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! My code does not stop and I do not understand why, can you help?
+Assistant: Sure. Let's assume the code runs on the first test example, can you run it manually for me line by line and show the value of each variable until you are done with one iteration of the while loop?
+	<alt>Sure. Can you explain to me what your code is supposed to do, line by line? Explain the role of each variable.
+	<alt>Sure. Can you tell me the role of the variable `start`?
+User: In lines 2 and 3, we initialize the variables `max_len` and `start` with 0. The variable `pos` will be calculated as `s.find(t, 0) = 4`, which is the position of the first occurrence of `ca` (string `t`) in `abracadabra` (string `s`). Then, because `pos` is not -1, the variable `crt_str` is assigned the substring `s[0:4]`, which is `abra`. On line 7, `max_len` is calculated as `max(4, 0) = 4`. Then on line 9, `pos` is recalculated as `s.find(t, 0)`... Ah, I see the problem, I forgot to update the variable `start`, let me do that. It works now, thank you!
+<code>
+1. def substr_len(s, t):
+2.    max_len = 0
+3.    start = 0
+4.    pos = s.find(t, start)
+5.    while pos != -1:
+6.        crt_str = s[start:pos]
+7.        max_len = max(len(crt_str), max_len)        
+8.        start = pos + len(t)
+9.        pos = s.find(t, start)
+10.    
+11.    last_str = s[start:]
+12.    max_len = max(len(last_str), max_len)
+13.
+14.    return max_len
+
+</code>
+Assistant: You're welcome!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/17_47_topk_socratic_dialogue.txt

@@ -0,0 +1,95 @@
+<problem>
+Write a function `top_k(lst: List[int], k: int) -> List[int]` that returns the top k largest elements in the list. You can assume that k is always smaller than the length of the list.
+## Example Cases:
+```
+top_k([1, 2, 3, 4, 5], 3) => [5, 4, 3]
+top_k([-1, -2, -3, -4, -5], 3) => [-1, -2, -3]
+top_k([], 0) => []
+top_k([550, 750, 3000, 2000, 1000], 3) => [3000, 2000, 1000]
+top_k([555, 777, 555, -1, 0], 3) => [777, 555, 555]
+```
+</problem>
+<bug_code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.pop(max(lst))
+6.    return result
+</bug_code>
+<bug_desc>
+The function removes the element at index `max(lst)` instead of removing an element equal to `max(lst)`. Consequently, the function throws an IndexError on line 5 when a removed value in `lst` is greater than the length of `lst`.
+</bug_desc>
+<bug_fixes>
+On line 5, replace `lst.pop(max(lst))` with `lst.remove(max(lst))`
+</bug_fixes>
+<unit_tests>
+assert top_k([1, 2, 3, 4, 5], 3) == [5, 4, 3]
+assert top_k([-1, -2, -3, -4, -5], 3) == [-1, -2, -3]
+assert top_k([], 0) == []
+assert top_k([550, 750, 3000, 2000, 1000], 3) == [3000, 2000, 1000]
+assert top_k([555, 777, 555, -1, 0], 3) == [777, 555, 555]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi. I am confused. My code doesn’t seem to work. Can you help?
+Assistant: Hello. Sure, let's see. Do you know what might be the issue?
+User: I think the problem is with the `.pop()` method. It seems to have issues with indexing.
+	<alt>When I use the `.pop()` method, I get an IndexError on some inputs.
+	<alt>For some inputs, I get an error and other inputs don't produce the right answer.
+Assistant: Ok, no worries. Let's review your code line by line. Could you please explain it to me?
+	<alt>Let's start with a simple example. What is the output of the following code snippet: `top_k([1, 2, 3, 4, 5], 3)`?
+	<alt>Let's start with a warm-up question. What does the `.pop()` method do?
+	<alt>Let's start with a warm-up question. What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?
+	<alt>Could you please explain what line 5 in your code does?
+	<alt>Let’s look into the Python documentation. Can you describe what the `.pop()` method does?
+User: Sure. First, I create an empty list where I will save the numbers from the given list. Then I add a for-loop and set the number of iterations it makes to K, which is the number of values the output list must contain. After that, I search for the maximum value in the given list. Once the value is found, I add it to the empty list I created earlier and then remove the value from the given list.
+Assistant: Good. What can you do right now to debug your code and diagnose what might be causing the problem?
+User: Hm… The problem is in the `.pop()` method. I can try debugging it by printing the given list to see how it is affected and the `max(lst)` to see what the `.pop()` method receives as the input. So printing the `max(lst)` command results in the maximum value of the given list. When I try executing the `.pop()` method, it raises an error. I am not sure what I am doing wrong.
+	<alt>I could try a more simple input and print out the max and the full list to see how it is processed. When I use the input `[0, 1]`, It seems to work, but when using `[1]`, it throws an error. I think it is removing elements by index and not by value, maybe I should use a different deletion method.
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        print(max(lst))
+6.        lst.pop(max(lst))
+7.        print(lst)
+8.    return result
+
+</code>
+Assistant: Are there other ways of debugging the `.pop()` method?
+	<alt>What happens if you use a different input value for the `top_k()` function?
+	<alt>Have you considered using the debugger?
+	<alt>What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?
+User: Hm... I probably could use a different value as the input for this method. So using 1 as the input value worked. The `.pop()` method seems to remove the value that has the index value of 1 in the given list. This is not what I was expecting from this method. What should I do?
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        print(lst)
+6.        lst.pop(1)
+7.        print(lst)
+8.    return result 
+
+</code>
+Assistant: Perhaps there are other solutions you can use aside from `.pop()`?
+	<alt>Where can we learn more about other list methods that can help us remove elements from an array?
+	<alt>I would suggest checking Python documentation. Perhaps you will be able to find useful information there?
+User: I think but I can't remember them...
+Assistant: I would suggest checking Python documentation. Perhaps you will be able to find useful information there?
+User: Ok. Oh I see, I used the wrong method. I should use `.remove()` instead. Aha! It works now. I removed the print statements also.
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.remove(max(lst))
+6.    return result
+
+</code>
+Assistant: Great! Please let me know if you need help with anything else.
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/17_47_topk_socratic_thread_1.txt

@@ -0,0 +1,76 @@
+<problem>
+Write a function `top_k(lst: List[int], k: int) -> List[int]` that returns the top k largest elements in the list. You can assume that k is always smaller than the length of the list.
+## Example Cases:
+```
+top_k([1, 2, 3, 4, 5], 3) => [5, 4, 3]
+top_k([-1, -2, -3, -4, -5], 3) => [-1, -2, -3]
+top_k([], 0) => []
+top_k([550, 750, 3000, 2000, 1000], 3) => [3000, 2000, 1000]
+top_k([555, 777, 555, -1, 0], 3) => [777, 555, 555]
+```
+</problem>
+<bug_code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.pop(max(lst))
+6.    return result
+</bug_code>
+<bug_desc>
+The function removes the element at index `max(lst)` instead of removing an element equal to `max(lst)`. Consequently, the function throws an IndexError on line 5 when a removed value in `lst` is greater than the length of `lst`.
+</bug_desc>
+<bug_fixes>
+On line 5, replace `lst.pop(max(lst))` with `lst.remove(max(lst))`
+</bug_fixes>
+<unit_tests>
+assert top_k([1, 2, 3, 4, 5], 3) == [5, 4, 3]
+assert top_k([-1, -2, -3, -4, -5], 3) == [-1, -2, -3]
+assert top_k([], 0) == []
+assert top_k([550, 750, 3000, 2000, 1000], 3) == [3000, 2000, 1000]
+assert top_k([555, 777, 555, -1, 0], 3) == [777, 555, 555]
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi. I am confused. My code doesn’t seem to work. Can you help?
+Assistant: Hello. Sure, let's see. Do you know what might be the issue?
+User: I think the problem is with the `.pop()` method. It seems to have issues with indexing.
+	<alt>When I use the `.pop()` method, I get an IndexError on some inputs.
+	<alt>For some inputs, I get an error and other inputs don't produce the right answer.
+Assistant: Ok, no worries. Let's review your code line by line. Could you please explain it to me?
+	<alt>Let's start with a simple example. What is the output of the following code snippet: `top_k([1, 2, 3, 4, 5], 3)`?
+	<alt>Let's start with a warm-up question. What does the `.pop()` method do?
+	<alt>Let's start with a warm-up question. What do you think the output of the following code snippet will be: `[1, 5, 3, 4, 2].pop(5)`?
+	<alt>Could you please explain what line 5 in your code does?
+	<alt>Let’s look into the Python documentation. Can you describe what the `.pop()` method does?
+User: Sure. First, I create an empty list where I will save the numbers from the given list. Then I add a for-loop and set the number of iterations it makes to K, which is the number of values the output list must contain. After that, I search for the maximum value in the given list. Once the value is found, I add it to the empty list I created earlier and then remove the value from the given list.
+Assistant: Good. What can you do right now to debug your code and diagnose what might be causing the problem?
+User: I could try a more simple input and print out the max and the full list to see how it is processed. When I use the input `[0,1]`, It seems to work, but `[1]`, it throws an error. 
+	<alt>Hm… The problem is in the `.pop()` method. I can try debugging it by printing the given list to see how it is affected and the `max(lst)` to see what the `.pop()` method receives as the input. So printing the `max(lst)` command results in the maximum value of the given list. When I try executing the `.pop()` method, it raises an error. I am not sure what I am doing wrong.
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        print(max(lst))
+6.        lst.pop(max(lst))
+7.        print(lst)
+8.    return result 
+
+</code>
+Assistant: What does that tell you about the `.pop()` method?
+	<alt>What conclusion can you draw from examining the output of the `.pop()` method?
+User: I think it is removing by index and not value, maybe I should use a different deletion method. I'll try `.remove()`. It works!
+<code>
+1. def top_k(lst, k):
+2.    result = []
+3.    for i in range(k):
+4.        result.append(max(lst))
+5.        lst.remove(max(lst))
+6.    return result
+
+</code>
+Assistant: Great! Glad to help
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/18_48_password_validator_conversational_thread_1.txt

@@ -0,0 +1,89 @@
+<problem>
+Create a function `validate_or_add_password(menu_choice:str, password:str, passwords_dict:Dict[str,any]) -> str` that validates or adds a password. This function takes three parameters:
+* `menu_choice (str)`: either 'v' for validate or 'a' for add password
+* `password (str)`: the password to be validated or added
+* `passwords_dict (Dict[str,any])`: a dictionary containing the passwords
+
+The function returns a string "Welcome!" if the password is found in the dictionary and menu_choice is 'v'. If the password is not found in the dictionary, the function returns "I don't know you.". If menu_choice is 'a', the function adds the password to the dictionary and returns "Password added!". If the password is already in the dictionary, the function returns "Password already exists!".
+## Example Cases:
+```
+passwords_dict = {1: "abc123", 2: "qwerty", 3: "password"}
+validate_or_add_password("v", "abc123", passwords_dict) => "Welcome!"
+validate_or_add_password("v", "xyz789", passwords_dict) => "I don't know you."
+validate_or_add_password("a", "abc123", passwords_dict) => "Password already exists!"
+validate_or_add_password("a", "newpass", passwords_dict) => "Password added!"
+passwords_dict[4] => "newpass"
+validate_or_add_password("a", "newpass", passwords_dict) => "Password already exists!"
+```
+</problem>
+<bug_code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == "v":
+3.        if password in passwords_dict.values():
+4.            return "Welcome!"
+5.        else:
+6.            return "I don't know you."
+7.    elif menu_choice == "a":
+8.        if password in passwords_dict.values():
+9.            return "Password already exists!"
+10.        else:
+11.            return "Password added!"
+</bug_code>
+<bug_desc>
+The function does not add `password` to `passwords_dict` as specified in the instructions.
+</bug_desc>
+<bug_fixes>
+After line 10 insert the following inside the `else` scope: `passwords_dict[len(passwords_dict) + 1] = password`
+</bug_fixes>
+<unit_tests>
+passwords_dict = {1: "abc123", 2: "qwerty", 3: "password"}
+assert validate_or_add_password("v", "abc123", passwords_dict) == "Welcome!"
+assert validate_or_add_password("v", "xyz789", passwords_dict) == "I don't know you."
+assert validate_or_add_password("a", "abc123", passwords_dict) == "Password already exists!"
+assert validate_or_add_password("a", "newpass", passwords_dict) == "Password added!"
+assert passwords_dict[4] == "newpass"
+assert validate_or_add_password("a", "newpass", passwords_dict) == "Password already exists!"
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: I need help with this code. It's throwing a `KeyError`. I'm not sure why.
+	<alt>Hello. I need help with my code.
+Assistant: Let's look through the Python documentation together. What does the error `KeyError: 4` mean and why does it occur?
+	<alt>Let's go through the problem description together. What is the function `validate_or_add_password` supposed to do when `menu_choice` is `"a"`?
+	<alt>Let's look through the Python documentation together. What does the error `KeyError: 4` mean and why does it occur?
+	<alt>What does `KeyError` typically mean and why does it occur?
+	<alt>Let's look at the example cases, where do you see `4` being used as a key?
+	<alt>Let's try to reproduce this error. Open the Python terminal and run, `d  = {'a': 1}` then, run `print(d['b'])`. What do you observe?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+	<alt>Which parameter in the `validate_or_add_password` function is a data structure that uses keys?
+	<alt>Can you walk me through what your code does line by line when `menu_choice` is `"a"`?
+User: After looking into the Python documentation, the `KeyError` seems to be caused by trying to access a dictionary using a key that does not exist. I wonder if this relates to adding a new password.
+Assistant: Good hypothesis. Can you walk me through what your code does line by line when `menu_choice` is `"a"`?
+	<alt>Good. Let's look through the example cases together. What do you think might be causing the `KeyError`?
+	<alt>Good. Which test case do you think is causing the `KeyError`?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+User: Certainly. So when `menu_choice` is `"a"` we go to line 8, we check if  `password` is already stored in `passwords_dict`. If so, the function returns "Password already exists!" otherwise it returns "Password added!".
+Assistant: Good. Let's go through the problem description together. What is the function `validate_or_add_password` supposed to do when `menu_choice` is `"a"`?
+	<alt>According to the problem description, what do you need to do with `password` if `menu_choice` is `"a"`?
+User: Oh. It is supposed to add `password` to `passwords_dict` and then return "Password added!". Let me edit my code.
+<code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == "v":
+3.        if password in passwords_dict.values():
+4.            return "Welcome!"
+5.        else:
+6.            return "I don't know you."
+7.    elif menu_choice == "a":
+8.        if password in passwords_dict.values():
+9.            return "Password already exists!"
+10.        else:
+11.            passwords_dict[len(passwords_dict) + 1] = password
+12.            return "Password added!"
+
+</code>
+Assistant: Good. Have you tried your code on all the example cases?
+User: Yes. It works correctly! Thank you for helping me today!
+Assistant: You're welcome. Let me know if I can be of any further assistance in the future.
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/18_48_password_validator_socratic_dialogue.txt

@@ -0,0 +1,90 @@
+<problem>
+Create a function `validate_or_add_password(menu_choice:str, password:str, passwords_dict:Dict[str,any]) -> str` that validates or adds a password. This function takes three parameters:
+* `menu_choice (str)`: either 'v' for validate or 'a' for add password
+* `password (str)`: the password to be validated or added
+* `passwords_dict (Dict[str,any])`: a dictionary containing the passwords
+
+The function returns a string "Welcome!" if the password is found in the dictionary and menu_choice is 'v'. If the password is not found in the dictionary, the function returns "I don't know you.". If menu_choice is 'a', the function adds the password to the dictionary and returns "Password added!". If the password is already in the dictionary, the function returns "Password already exists!".
+## Example Cases:
+```
+passwords_dict = {1: "abc123", 2: "qwerty", 3: "password"}
+validate_or_add_password("v", "abc123", passwords_dict) => "Welcome!"
+validate_or_add_password("v", "xyz789", passwords_dict) => "I don't know you."
+validate_or_add_password("a", "abc123", passwords_dict) => "Password already exists!"
+validate_or_add_password("a", "newpass", passwords_dict) => "Password added!"
+passwords_dict[4] => "newpass"
+validate_or_add_password("a", "newpass", passwords_dict) => "Password already exists!"
+```
+</problem>
+<bug_code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == "v":
+3.        if password in passwords_dict.values():
+4.            return "Welcome!"
+5.        else:
+6.            return "I don't know you."
+7.    elif menu_choice == "a":
+8.        if password in passwords_dict.values():
+9.            return "Password already exists!"
+10.        else:
+11.            return "Password added!"
+</bug_code>
+<bug_desc>
+The function does not add `password` to `passwords_dict` as specified in the instructions.
+</bug_desc>
+<bug_fixes>
+After line 10 insert the following inside the `else` scope: `passwords_dict[len(passwords_dict) + 1] = password`
+</bug_fixes>
+<unit_tests>
+passwords_dict = {1: "abc123", 2: "qwerty", 3: "password"}
+assert validate_or_add_password("v", "abc123", passwords_dict) == "Welcome!"
+assert validate_or_add_password("v", "xyz789", passwords_dict) == "I don't know you."
+assert validate_or_add_password("a", "abc123", passwords_dict) == "Password already exists!"
+assert validate_or_add_password("a", "newpass", passwords_dict) == "Password added!"
+assert passwords_dict[4] == "newpass"
+assert validate_or_add_password("a", "newpass", passwords_dict) == "Password already exists!"
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello. I need help with my code.
+	<alt>I need help with this code. It's throwing a `KeyError`. I'm not sure why.
+Assistant: Can you describe the issue you are experiencing?
+	<alt>Can you walk me through what your code does line by line when `menu_choice` is `"a"`?
+	<alt>Let's go through the problem description together. What is the function `validate_or_add_password` supposed to do when `menu_choice` is `"a"`?
+User: I am getting a `KeyError: 4`. Not really sure why.
+	<alt>My terminal is printing `KeyError: 4`. I think it's failing a test case perhaps.
+Assistant: Let's look through the Python documentation together. What does the error `KeyError: 4` mean and why does it occur?
+	<alt>What does `KeyError` typically mean and why does it occur?
+	<alt>Let's look at the example cases, where do you see `4` being used as a key?
+	<alt>Let's try to reproduce this error. Open the Python terminal and run, `d  = {'a': 1}` then, run `print(d['b'])`. What do you observe?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+	<alt>Which parameter in the `validate_or_add_password` function is a data structure that uses keys?
+User: After looking into the Python documentation, the `KeyError` seems to be caused by trying to access a dictionary using a key that does not exist.
+Assistant: Good. Let's look through the example cases together. What do you think might be causing the `KeyError`?
+	<alt>Good. Which test case do you think is causing the `KeyError`?
+	<alt>Let's look at your error again. What line is throwing the `KeyError`?
+User: Ah found it. In the example cases, line 18 is trying to access the value using the key 4 `passwords_dict[4] == "newpass"`. However, `passwords_dict` is initialized to `passwords_dict = {1: "abc123", 2: "qwerty", 3: "password"}` and does not have 4 as a key.
+	<alt>Ah found it. In the example cases, this line is trying to access the value using the key 4 `passwords_dict[4] == "newpass"` after calling `validate_or_add_password("a", "newpass", passwords_dict)` in an attempt to add "newpass" as a password.
+Assistant: Good. What is the statement right before line 18 attempting to do?
+User: Oh! I get it now! This example case is testing whether my function adds `"newpass"` to `passwords_dict`. I don't think I do that. I thought I just need to print "Password added!". Let me edit my code to ensure that it adds `password` to `passwords_dict` in this case.
+<code>
+1. def validate_or_add_password(menu_choice, password, passwords_dict):
+2.    if menu_choice == "v":
+3.        if password in passwords_dict.values():
+4.            return "Welcome!"
+5.        else:
+6.            return "I don't know you."
+7.    elif menu_choice == "a":
+8.        if password in passwords_dict.values():
+9.            return "Password already exists!"
+10.        else:
+11.            passwords_dict[len(passwords_dict) + 1] = password
+12.            return "Password added!"
+
+</code>
+Assistant: Good. Does your code pass all the example cases?
+User: Yes it does thank you for your help. I learned more about `KeyError`s today.
+Assistant: You're welcome to let me know if I can be of any further assistance.
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/19_49_word_counter_conversational_thread_1.txt

@@ -0,0 +1,77 @@
+<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words(" This is a sentence ")` returns 4. 
+## Example Cases:
+```
+count_words("hello world") => 2
+count_words("hello    world") => 2
+count_words("This is a sentence") => 4
+count_words("I love Python") => 3
+count_words("") => 0
+count_words(" ") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for i in range(1, len(sentence)):
+5.        if sentence[i] == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    if not space_mode:
+12.        words +=1
+13.    return words
+</bug_code>
+<bug_desc>
+On line 4, the for loop skips over the first character in the string `sentence`. Consequently, the function can miss counting a word if the first character in `sentence` is a word.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `(1, len(sentence))` with `(len(sentence)):`
+On line 4, replace `(1, len(sentence))` with `(0, len(sentence)):`
+</bug_fixes>
+<unit_tests>
+assert count_words("hello world") == 2
+assert count_words("hello    world") == 2
+assert count_words("This is a sentence") == 4
+assert count_words("I love Python") == 3
+assert count_words("") == 0
+assert count_words(" ") == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having a problem with this programming problem. My count seems off.
+Assistant: Did you try running your code? If so, is there a pattern you notice between the output of your code and what the answer should be?
+	<alt>Are there specific inputs that give you the wrong answer or is it always wrong?
+	<alt>Off in what way?
+User: Yes! My output seems to be 1 less than it should be.
+	<alt>My output is sometimes correct and sometimes lower than it should be
+Assistant: Does this happen with all inputs or just some inputs?
+User: I only seem to notice it on sentences that begin with "I" or "A", so I guess one-letter words.
+	<alt>It only happens with sentences that start with short words, it seems.
+	<alt>I thought it was working properly, but I just checked the sentence "I walked the dog" and the output was wrong.
+Assistant: Can you check how your function handles the beginning of the input? It seems like the issue might be there.
+	<alt>It only happens with sentences that start with short words, it seems.
+	<alt>Where do you count your first word?.
+User: Oh, I see. I'm missing the first index when I loop. I guess I never put in the base case.
+<code>
+ def count_words(sentence):
+    words = 0
+    space_mode = True
+    for i in range(len(sentence)):
+        if sentence[i] == ' ':
+            if not space_mode:
+                words += 1
+            space_mode = True
+        else:
+            space_mode = False
+    if not space_mode:
+        words +=1
+    return words
+</code>
+Assistant: Great!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/19_49_word_counter_socratic_dialogue.txt

@@ -0,0 +1,77 @@
+<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words(" This is a sentence ")` returns 4. 
+## Example Cases:
+```
+count_words("hello world") => 2
+count_words("hello    world") => 2
+count_words("This is a sentence") => 4
+count_words("I love Python") => 3
+count_words("") => 0
+count_words(" ") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for i in range(1, len(sentence)):
+5.        if sentence[i] == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    if not space_mode:
+12.        words +=1
+13.    return words
+</bug_code>
+<bug_desc>
+On line 4, the for loop skips over the first character in the string `sentence`. Consequently, the function can miss counting a word if the first character in `sentence` is a word.
+</bug_desc>
+<bug_fixes>
+On line 4, replace `(1, len(sentence))` with `(len(sentence)):`
+On line 4, replace `(1, len(sentence))` with `(0, len(sentence)):`
+</bug_fixes>
+<unit_tests>
+assert count_words("hello world") == 2
+assert count_words("hello    world") == 2
+assert count_words("This is a sentence") == 4
+assert count_words("I love Python") == 3
+assert count_words("") == 0
+assert count_words(" ") == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hello! I am having a problem with this programming problem. My count seems off.
+Assistant: Did you try running your code? If so, is there a pattern you notice between the output of your code and what the answer should be?
+	<alt>Are there specific inputs that give you the wrong answer or is it always wrong?
+	<alt>Off in what way?
+User: Yes! My output seems to be 1 less than it should be.
+	<alt>My output is sometimes correct and sometimes lower than it should be
+Assistant: Does this happen with all inputs or just some inputs?
+User: I only seem to notice it on sentences that begin with "I" or "A", so I guess one-letter words.
+	<alt>It only happens with sentences that start with short words, it seems.
+	<alt>I thought it was working properly, but I just checked the sentence "I walked the dog" and the output was wrong.
+Assistant: Can you check how your function handles the beginning of the input? It seems like the issue might be there.
+	<alt>It only happens with sentences that start with short words, it seems.
+	<alt>Where do you count your first word?
+User: Oh, I see. I'm missing the first index when I loop. I guess I never put in the base case.
+<code>
+ def count_words(sentence):
+    words = 0
+    space_mode = True
+    for i in range(len(sentence)):
+        if sentence[i] == ' ':
+            if not space_mode:
+                words += 1
+            space_mode = True
+        else:
+            space_mode = False
+    if not space_mode:
+        words +=1
+    return words
+</code>
+Assistant: Great!
+</dialogue>

data/raw/v2_sigcse/evaluation_dataset/19_50_word_counter_conversational_thread_1.txt

@@ -0,0 +1,84 @@
+<problem>
+Write a function `count_words(sentence: str) -> int` that returns the number of words in the sentence. A word is a maximal sequence of characters that does not contain spaces. For example, `count_words(" This is a sentence ")` returns 4. 
+## Example Cases:
+```
+count_words("hello world") => 2
+count_words("hello    world") => 2
+count_words("This is a sentence") => 4
+count_words("I love Python") => 3
+count_words("") => 0
+count_words(" ") => 0
+```
+</problem>
+<bug_code>
+1. def count_words(sentence):
+2.    words = 0
+3.    space_mode = True
+4.    for c in sentence:
+5.        if c == ' ':
+6.            if not space_mode:
+7.                words += 1
+8.            space_mode = True
+9.        else:
+10.            space_mode = False
+11.    return words
+</bug_code>
+<bug_desc>
+There is an off-by-one error where the last word in `sentence` is not counted when `sentence` ends with a non-space token.
+</bug_desc>
+<bug_fixes>
+Insert the following after line 10 outside the scope of the for loop:
+```py
+if not space_mode:
+     words +=1
+```
+</bug_fixes>
+<unit_tests>
+assert count_words("hello world") == 2
+assert count_words("hello    world") == 2
+assert count_words("This is a sentence") == 4
+assert count_words("I love Python") == 3
+assert count_words("") == 0
+assert count_words(" ") == 0
+</unit_tests>
+<stu_desc>
+
+</stu_desc>
+<dialogue>
+User: Hi! I'm writing some code to count words and it doesn't seem to be working
+Assistant: What seems to be the issue?
+    <alt>Let's walk through your code line by line. Can you explain what your code does?
+    <alt>When you run your code, what do you observe?
+User: My output counts are off by one
+Assistant: Does this happen with all inputs?
+	<alt>Hm, ok. Can you walk me through your code?
+    <alt>Can you give me an example input where this happens? Include what you expect and what you get.
+User: It's happened with all the inputs so far, but I'm not sure if it would happen with all of them
+Assistant: Can you try perturbing the inputs? Maybe add characters before or after.
+    <alt>What happens when you run `count_words("hello world ")`?
+    <alt>How does your function handle trailing whitespace?
+    <alt>Can you describe to me how you are counting words?
+    <alt>Does your loop count the last word in the sentence?
+User: It's still the same if I had numbers or non-letter characters after and before
+Assistant: Have you tried adding whitespace?
+    <alt>What happens when you run `count_words("hello world ")`?
+User: Huh, weird. When I pass the input "hello world ", the answer is correct, but it is wrong without the whitespace at the end.
+Assistant: How does your function handle trailing whitespace?
+User: I see now, I'm not counting the last word unless a space follows it. I'll amend my code to handle this. It looks like it works!
+<code>
+ def count_words(sentence):
+    words = 0
+    space_mode = True
+    for c in sentence:
+        if c == ' ':
+            if not space_mode:
+                words += 1
+            space_mode = True
+        else:
+            space_mode = False
+    if not space_mode:
+        words +=1
+    return words
+</code>
+Assistant: Happy to help!
+</dialogue>